word problem for 4(3x - 5) = 5(2x + 4)?
830557
Tom baked 4 batches of fairy cakes. Each batch consisted of x cakes. He put 3 cherries on top of each cake in the first batch, but couldn't resist taking off and eating 5 of them. He did the same again with the second batch, then the third, then the fourth! Meanwhile, Sarah baked 5 batches of fairy cakes, again with x cakes in each batch. She put 2 cherries on each cake and an extra two on the final one. She repeated this procedure with each of the batches. She managed to resist eating any at all! Tom and Sarah discovered that Tom's cakes had exactly the same number of cherries in total as Sarah's. Set up an equation for this.\n\nThen: \n\nNumber of cherries on Tom's cakes = 4(3x-5)\nNumber of cherries on Sarah's cakes=5(2x+4)\n\nBut number of cherries is equal so:\n\n4(3x-5)=5(2x+4)\n\nPhew!! I think that works!! Lol!
445798
4*(4/4+4)=\n4*(1+4)=\n4*5=\n20
1157065
(x+5)(2x^2+4x+2)\nx(2x^2+4x+2)+5(2x^2+4x+2)\n2x^3+4x^2+2x+10x^2+20x+10\n2x^3+14x^2+22x+10
124685
y= 2x + 5 y= 6x + 1\ny=y\n2x+5=6x+1\n4=4x\n1=x\ny=2(1)+5=7
866437
Let one side be 'x', second will be 'x + 5 ' third will be  ( x+5) - 3\nx  + x + 5 + ( x + 5 ) - 3 = 16
560796
x = 4/5 + 1 3/8\nx = 4/5 + 11/8\nx = 32/40 + 55/40\nx = 87/40\nx = 2 7/40
19885
(5) x (2x^2-3x+5) I think
447443
Ok...you have to solve two equations\n\nFIRST ONE\n\nif (8-4x) < 5\n\nthen (8-4x-5) < 0 (by subtracting 5 from both sides of the equation)\n\nthus (3-4x) < 0 (obviously)\n\nso 3 < 4x (by adding 4x to both sides of the equation)\n\nso 4x > 3\n\nso......... x > 3/4\n\nSECOND ONE\n\nif -(8-4x) < 5\n\nthen -8+4x < 5 (obviously...see that -*- = +)\n\nthen -8+4x-5 < 0 (by subtracting 5 from both sides of the equation)\n\nso -13+4x < 0 (obviously)\n\nand 4x < 13 (by adding 13 to both sides of the equation)\n\nso......x < 13/4\n\nFINAL ANSWER IS.......(3/4 < x < 13/4)
630233
(4/x+2)+3-4/x = (2/x-3)+3-4/x\n5 = 2/x-4/x\nx(5) = x(2/x-4/x)\n5x = 2-4 = -2\n(5x)/5 = (-2)/5 = -0.4\nx = -2/5 = -0.4
771836
Simple substitution.\n\n5(3) - 2(2) + 4(4)\n15 - 4 + 16\n27
1053464
if you want to simplify it \n\nit is 3x - 4x + 4 = -x + 4
733063
5x^2-35x+3x-21\n5x^2-32x-21
472975
Replace x with 4 and y with 5.  If the resulting statement is true, then it is a solution.  If it is not true, then it is not a solution.\n5x +3y = 35\n5(4) + 3(5) = 35\n20 + 15 = 35\n35 = 35\nThis is true, so (4,5) is a solution.\n(There is no need to solve for y.  You can solve for y, but this just adds additional work.)
227193
∫[(2x^4) - (4/x^5)]dx=\n\n∫(2x^4)dx - ∫(4/x^5)dx=\n\n2∫x^4dx - 4∫[x^(-5)]dx=\n\n2*[x^5/5] - 4*[x^-4/-4]=\n\n(2/5)x^5 + x^-4 + C=\n\n(2/5)x^5 + 1/x^4 + C
666753
3/x-4 = 5/x\ncross multiply:\n 3x= 5x-20\n-5x -5x\n\n-2x=-20\ndivide -2 on each side x=10
222015
5x - 2y = 4  (1)\n2x + 3y = 13 (2)\nmul. eq.(1) by 2: 2 (5x - 2y = 4)\n                    10x - 4y = 8\n\nmul. eq.(2) by 5: 5 (2x +  3y = 13)\n                    10x + 15y = 65\n\nsubtract: 10x -  4y =  8\n      (-) 10x + 15y =  65\n          ________________\n               -19y =  -57 \n                  y =  -57/-19\n                  y =  3\n\nsubstitute value of y to any of the eqs.\n\nSubstituting to eq. (1):\n\n    5x - 2y   = 4   \n    5x - 2(3) = 4\n    5x - 6    = 4\n    5x              = 4 + 6\n    5x              = 10\n     x              = 10/5\n     x              = 2\n\nso, x = 2\n    y = 3\n\nto check, substitute values of x and y to any of the two equations:\n    for eq. (1),\n\n    5x   - 2y   = 4   \n    5(2) - 2(3) = 4\n      10 - 6    = 4\n\n    for eq. (2),\n\n    2x   + 3y   = 13\n    2(2) + 3(3) = 13\n      4  + 9    = 13
216863
((4 * 4) / 4) - 4 + 4 = 4