Is normal force or gravity stronger when an object is on an incline?
815959
Normal force can be thought of as the force required by a surface to hold an object up.If the surface is horizontal the normal force is equal and opposite the gravitational force as this is the maximum. When the surface is on an incline the normal force is going to be the mass*g*cos(theta) and as the cos(theta) approaches 90 degress the normal force decreases to zero. So the maximum is when the plane is horizontal and the cos 0 equals 1 and decreases to 0 as the angle of the plane increases. \n\nNot to confuse the issue though, the normal force does not have to be derived from gravitational force on an object. an example is pushing on a wall with your hand. the force that the wall exerts back on your hand is the normal force. \n\nThe normal force derives its name from vectors and the force is always normal to the plane on which something is acting regardless of whether the force is a result of gravity or of pushing or pulling on a wall or any combinations using a sum of the forces.
939535
Sorry, but you'll need to give a little more information. How are the pulleys and weights arranged? Just a little picture would help.\n\nTypically, pulleys, weights, tensions and accelerations are extensions of the block on an incline problem except the pulleys are providing the force vector direction change.\n\nIt might help to think of the problem as a sum of vectors and look for where their vector sum lies.
48086
Sometimes, you weigh less, gravity's pull does not change, doy!
1170472
You've got a couple of strange answers so far.  Look, the formula written above is correct, the mass of the earth is basically the same, but the mass of your surroundings isn't the same.  The pull of gravity is less the higher your elevation, greater the lower the altitude.  If you're on land with higher density, you'll have a greater pull then on land with a lower density.  Pretty much everywhere on land gravity isn't even, out in the middle of the ocean, it's very close to even.  But, keep in mind, these differences are pretty much negligible.  The only way to be able to measure the difference is with scientific equipment.  Actually, it's common practice to measure gravitational anomalies under ice sheets to gleam information about the formations underneath.
919106
They all involve friction, but I think you mean which has the most force due to friction, right? :-&#92;  If so, I believe the answer is that they are all the same.\n\nIn simple situations, the frictional force created by sliding two surfaces against eachother is given by:\n\nf = u * N\n\nWhere u (mu) is the frictional coefficient (an experimentally-determined constant) and N is the normal force, which is mg (mass times accelleration of gravity) if the surface isn't tilted.\n\nSo, assuming the frictional coefficient is the same for all sides of the book, there is no reason why changing the sides would make a difference.
770512
The total force on the block is mg sin (theta). The mg cos (theta) and force normal cancel out. Since there is no friction, the only force, again, is only mg sin (theta). \n\nThis is obvious if you consider that there is a force mg, and break it down into components, the solution should seem obvious.
655647
Force is a vector and it can be -ve.\n\nThrow a ball up. If you take its displacement upwards to be +ve then the gravity pulling it down is in the opp. direction and hence -ve. Thus the force acting on it is -ve.\n\nIts all a question of taking references.
376523
it depends on the angle of ur effort. lets say there u are trying to move a cart. if u push the way u will push ur mower, one component of ur force will be downwards, thus effectively pushing the cart down and thus increasing the frictional force . but if u pull the cart this force will not be downwards but upwards and hence the frictional force will be reduced. so its better to pull.
943006
The balance of forces acting on you: m*a=f1-f2; m is your mass, f1 is the force pulling you down the slope, f2 is force of friction, both being parallel to the slope incline. Thus f1=m*g*sin(b), f2=m*g*cos(b)*k, while g=9.8m/s^2, b=31deg, a=1.16m/s^2, m*g being your weight. Mind! While f1 is a vector parallel to the slope, the force m*g*cos(b) is normal to the slope and should not be taken into account unless friction be present. \nNow m*a=m*g*(sin(b)-k*cos(b)), hence k=(sinb-a/g)/cosb=0.46
881560
If you lift a 100 pound weight with only 50 pounds of force, the weight will remain on the floor because of inertial (it is pulling down more by gravity than you are pulling up).  Although you may be greatly exerting yourself, you have added no energy to the weight.  If you now lift with an upward force of 101 pounds, you overcome the downward force of the weight and it rises.  Importantly you are now adding potential energy to the weight.  Lift the weight one foot and you have added 100 foot-pounds of potential energy by doing work (force times a distance) on the weight.  We know that a pendulum can convert potential energy (height) to kinetic energy (motion) continuously until stopped by friction (that converts the energy to heat and sound, etc.).  Therefore, a body will remain at rest until you add energy to it and it will then remain in motion until the energy is removed again.  Energy is added when a force acts on the weight for a distance and energy is removed when the weight acts as a force moving a resistance a distance.  This is simple in a frictionless (ideal) system but in fact friction often applies a force to the weight removing its energy in the form of heat.  Hope that helps a little.
90527
Are you walking on an incline?  I recently read in a Health Magazine (Shape, maybe?) that when walking on an incline, if you are holding on to the bars in front of you, not only do you burn fewer calories, but you can cause abnormal strains on various leg muscle groups.  Better to go less of an incline and support your upper body naturally.
898411
The Cf will equal the tangent of the angle of the incline when the box first starts to move.\n\nSuggestion: Try each box several times and average the results for a more meaningful result.  Normally pressure does affect the Cf to a small degree, so you should see some difference using different boxes of the same weight or the same box with different masses.\n\nGood luck!
575083
lifting, pulling, exerting greater forces
12996
I can't draw a free-body-diagram here, so it's going to be somewhat more difficult to explain (a picture is worth 1000 words and all)...\n\nSince the block is moving at a constant velocity, we know that all the Forces are balanced.  this means that the Force of friction is equal to the force of gravity pulling the block down the incline.\n\nI'll write this as \nFf = uN  \n\nSince we know the angle of the slope, 25 degrees, we can break the Force of gravity into 2 components,  one that points down the incline (i'll refer to it as Fx) and one points the opposite direction (I'll refer to is as Fy) of the Normal vector N.\n\nIf you draw that triangle you notice the the hypotenuse has magnitude(length) of mg (mass times the gravitational constant.\n\nnow, lets use the sin & cos relationships to determine the length of the 2 components: Fx & Fy\n\nsin = opposite / hypotenuse\ncos= adjacent / hypotenuse.\n\nIf you look at the diagram, the opposite is Fx so\nsin 25 = Fx / mg \nFx = sin25 * mg \n\nand the adjacent is Fy so\ncos 25 = Fy / mg\nFy = cos25 * mg  \n\nagain since all force are in balance, \nFy = N \n\nand Fx = uN \nsin25 * mg = u * Fy \nsin25 * mg = u * cos25 * mg \nwhich reduces to\n\nsin25 / cos25 = u \nand \nfinally\nu = tan25 = ~.466
118752
The fricional force between an object and a surface is dependent on two things,\nthe coefficient of friction between the two surfaces and the normal force exerted by the surface on the object.\nIf you increase either of these, the frictional force is increased, likewise, if you decrease (or make zero) any of these, the frictional force is less (or zero).
788458
To understand this quandary you must look at a much bigger picture. since gravitational force is determined by an objects mass the earth actually exerts a much greater force on the object than the object exerts on the earth. Now this is where you must remember Newton's second law - if an unbalanced force acts on an object the object will accelerate in the direction of the force. The unbalanced force is the force of gravity the larger mass (earth in this case) exerts on the smaller object. The acceleration in the direction of the force is what we call gravity. It is true that the object exerts a reaction force but the maximum force it exerts is only the force of gravity it can generate based on it's mass. Since it weighs less it's force is not strong enough to move the earth.
60690
The amount of matter in an object is called its mass. The force of gravity is dependent on the amount of mass a body has. That means that the gravity on the Earth is greater than the gravity on the Moon, since the Earth has much more matter or mass than the Moon.