area of triangle help!!!!?
816398
The area of a triangle is given by the formula:\nA = 1/2 b * h\n\nLet b = h + 2\nA = 40\n\nSo:\n40 = 1/2 (h + 2)h\n40 = (h² + 2h)/2\n80 = h² + 2h\nh² + 2h - 80 = 0\n(h + 10)(h - 8) = 0\n\nh + 10 = 0\nor\nh - 8 = 0\n\nh = -10 \nor\nh = 8\n\nBut negative numbers don't make sense for lengths, so there is one answer:\n\nThe height = 8 ft\nThe base = 10 ft
926515
Let x be the length for the square and 14-x for the triangle.\n\nThe area of the square is (x/4)^2 = (x^2)/16.\n\nThe height of the triangle is sqrt(3)(14-x)/6 and the base of the triangle is (14-x)/3, so the area of the triangle is\n\n1/2 bh = [(14-x)/6] [sqrt(3)(14-x)/6] = (14-x)^2 sqrt(3)/36\n\nTotal area A = (x^2)/16 + (14-x)^2 sqrt(3)/36\n\nA = [9x^2 + 4(x^2 - 28x + 196) sqrt(3)] / 144\n\nA = [(9 + 4 sqrt 3) x^2 - (112 sqrt 3) x + (784 sqrt 3)] / 144\n\ndA/dx = [2(9 + 4 sqrt 3) x - (112 sqrt 3)] / 144 = 0\n\n(9 + 4 sqrt 3) x = 56 sqrt 3\n\nx = (56 sqrt 3) / (9 + 4 sqrt 3) = 6.0895 meters  (Answer)\n\nThe area of the square is 2.32 m^2.  The area of the triangle is 3.01 m^2, and the total area is 5.33 m^2.
353664
find the area of the cross section.... then times the area by the length... that is of course if it's a prism
458187
find the area of the base and multiply it by the height\n\n(1/2)*b*h1*h2  for a triangular prism h1 is height of the triangle, h2 is the height of the prism\n\npi*(r^2)*h for cylinder, h is height, r is radius of the base
135768
Area = Pi times the radius squared (A=pr2)\nIf you need to know how to find the radius, go here:\n\nhttp://math.about.com/library/blcircle.htm
558451
The are of a triangle can be found out by this formula...\nsquare root over s(s-a)(s-b)(s-c)\nwhere s=a+b+c&#92;2...\nWhere a, b and c are the sides..\nso i guess u can find the side and then find the perimeter..\nLolz...\nU calculate it urself
323670
measure each diagonal, come up with the area of one triangle X it by 4, then work out the area of the base simple!
991928
Assuming you mean a regular hexagon, then with the 30-60-90 relationship, you should get that half the length of a side is 2.\n\nSo, the area of that yellow triangle in the link below is\n.5 * 2 * 2 * sqrt(3) = 2 * sqrt(3)\n\nThere are 12 triangles, so the area is 24 * sqrt (3).
444311
The area of a triangle is\n\n1/2 * Base * Height\n\nSo it the max base is 2 ft, and the max area is 20 ft^2, then the max height would have to be 20ft
340579
Find the area of the triangular base, then multiply that by (1/3) times height.\nThe formula is (1/3)*(area of base)*(height)\nSay the triangular base has base = 3 and height 4.\nArea of triangle = (1/2)(3)(4) = 6\nSay the height of the pyramid is 10.\nThe volume is  \n(1/3)(6)(10) = 20
890633
1. total area of a box of sides a,b,c is 2(ab+bc+ca)\na=4,b=3,c=6 => surface area = 108 sq.ft\n..\n2.Lateral area = pi*radius*slant ht\npi=3.1415,radius=2m(4m/2), slant ht=15m\nans is 188.49sq.metres\n..\n3.   volume of pyramid = (1/3)* height * base area\n= (1/3)* (6) * (6*6)\n= 72 cu.metre\n..\n4. lateral area of cylinder = 2*pi* radius* height\n=2*3.1415*12*60\n=4523.76cu. mm\n..\n5. total surface area = outer surface + inner surface + top surface + bottom surface\n= 2*pi*8*height + 2*pi*5*height + 2 times ( pi*(8-5)^2)\n[the last term is the sum of top and bottom surfaces which are circular rings]\nheight is not given :(
1086020
(Click on the link below for the diagram. Expand to get a clearer view)\n\nLet the point of intersection of altitude and base be P\n\nThe length BP and PC is x.\nThe length AB = AC = (40-x-x)/2 = 20-x\n\nThen we use pythagoras theorem to find x.\nx^2 + 8^2 = (20 - x)^ 2\n40x = 336\nx = 336/40 = 8.4\n\nHence the area of the triangle\n= 1/2(base*height)\n= 1/2(16.8*8)\n= 67.2
966422
The area of an equilateral triangle is\nA = (1/4)sqrt(3) * a^2, where a is the length of the side.\nSince the triangle is equilateral, you know that the length of each side is 10/3.\nThe area is\nA = (1/4)sqrt(3) (10/3)^2\nA = (1/4)sqrt(3) (100/9)\nA = (25/9)sqrt(3)
420090
If the x and y axis are forming two of the sides of the triangle, the truangle is right angled so the area of the triangle will be 1/2 * base * height\n\nThe line through (3,2) therefore has to meet the x axis and the y axis to complete the triangle shape. \n\nConsider the gradient of the line = -1. The line would cut the x axis at (5,0) and the y at (0,5), making the triangle 0.5 * 5 * 5 = 12.5 units squared\n\nConsider gradient = -a. We'd have intersects at (3-2/a,0) and (0,2-3/a). The area of the triangle would be:\n\n0.5 * (3-2/a) * (2-3/a)\n= 0.5 * (6 - 4/a - 9/a + 6/a²)\n= 0.5 * (6 - 13/a + 6/a²)\n= 0.5 * (6a² - 13a + 6) ---- (multiply everything by a²)\n\nNow solve for minimum a by differentiating:\n\nd/da = 0.5 * (12a - 13)\n\nReaches a minimum when d/da = 0 :\n\n0 = 6a - 6.5\n6.5 = 6a\na = 1.086666\n\nNow put that back into our area equation, we get:\n\n= 0.5 * (3-2/a) * (2-3/a)\n= 11.556\n-------------
880255
I can just give you a link to help you solve it.\n\nhttp://www.ticalc.org/pub/83plus/basic/math/geometry/
1138152
AB=BC=CD=DE=EA = 20g with which is g = ((V5) - 1)/2\nUse 3x Heron's formula for area of a triangle and sum the three.\nA = V{s(s-a)(s-b)(s-c)} while s=(a+b+c)/2\n\nABE = 200V{g(2g+1)} = BCD\nBDE = 100gV(4-g^2)\n\nABCDE = 400V{g(2g+1)} + 100gV(4-g^2)\nNow use g = ((V5) - 1)/2 or use g = 0.6180339.
175713
Your question is too complicated to appreciate the math in it, which is supposed to be the real beauty in the first place. Anyway, I have tried figuring it out and come with equations. I do not even want to try and begin substitution and end up with more complications. I just thought once you saw the relation, you would throw those 10 points my way.\n\nAssuming a to be sides of the squares of the prism and b to be the length of the rectangles, we know that the sum of all dimensions is 14a+5b. Now I do not even want to get started why you brought it the story of the equilateral triangle. You can just say the sum  of the dimensions is 61. Anyway, since any side of the trianle, as it is equiangular hence equilateral, is twice 14a+5b and 122, the sum of the dimensions will be 61. So your first equation is 14a+5b=61\n\nYou know the volume of the prism is the length X width X heiht = a x a x b = (a^2)b This is equal to the surface area. The surface area is the sum of all the areas on the prism and that is a^2+4ab. (How about you calculate how that came up?)\n\nSo there is your second equation, (a^2)b = a^2+4ab So then from 14a+5b=61, express a in terms of b or the other way around and plug it into the second equation and experience brutal complications and figure out what the variables are. I think you know it is too easy to calculate each dimension and area after that.