Half Split Technique of problem solving?
822882
Split half technique is used when fault finding on an electrical circuit. If you have a supply and an earth, you would then check for voltage about half way along the circuit. If you had voltage, you would then pick a point about half way between your present position and earth. You would then repeat with half way of every subsequent haalf until you had located the break.
188200
I had trouble with the same thing. The best way, and it's worked till now in college, is to take the most complicated element used (i.e. CH3OOH + C2H3O9 ---> etc), figure out O's first since O is used the most. Then work backward using the 2nd most used element. You might get a non-reduced form of balancing, but you can check whats divisible (i.e.  4CH + 2 CH2H3O2 <---> 4 OH + 2 CH3; all divisible by 2 so it'd be 2, 1, 2, 1 respectively). See if this works, it's worked when I've helped other people in the past as well.
700389
1/2 half of 8 is 2.\nhalf of 8 is 4.\n1/2 of 4 is 2
810960
Easy. 40 divided by 2 is 20. Take half of 40.  OR 40x0.5
681497
Solve meaning???\n\nploting?\nfinding the focus etc.?\n\nbe specific
381290
I have an iterative method that is good for at least 80% of these types of problems.\n\nFirst, write down the series.\n\nNext, above the line you just wrote, write the difference between each pair of elements. In this case, it will be 1, 2, 4, 8, .... In this case, the answer is obvious - they are powers of two. The next one in the differences line should be 16, so the next on the original line should be 15+16=31. This will allow you to get any member in the sequence.\n\nIf the first order of differences doesn't give rise to a discernable pattern, try the differences of differences and so on.
1137735
use  brain\nif not  calculator
1018412
do you really want someone else to think for you?\nhmmm...well then...\nhere it goes...\n1. look in your math book...there are examples of how to do this problem...\n2. same answer as above!!!\n#3... same...\n\n#4!!!! remember Einstein solved "un-solve able" problems!!!
917224
Simply use correct order of operations\n\nparentheses\nexponents\nmult/division (from left to right)\naddition/subtraction (from left to right)
283228
Thinking about and cognitively manipulating events, things or concepts that are not in ones immediate presence or environment is abstract reasoning.\nTake a test here:\nhttp://www.testgrid.com.au/demo/sampleabstract.tg\n\nAn example might be an unfolded patterned box as the desired end point and 4 folded boxes off to the side. Your task would be to match which one of the 4 boxes is identical to the first. All of this on a printed page.
1102335
I may be barking completely up the wrong tree here. Are you comparing one ratio with another?\n\nIn the first, there are 45 parts, in the second there are 19.\n\nMost math problems have a glimmer of sense about them, in that when you hit upon the right way to solve them or what they are really asking, the calculation is quite easy.  I was expecting the number of total parts in each expression to be an easy multiple of each other, which they are not.\n\nIf you are expected to apply the first ratio to the 18 side of the second, that looks a little more reasonable (45 and 18 are both multiples of 9.)\n\nDoes that help without seeming to? (Also I understand you to mean 'factor' and 'easy')
951948
When I do word problems, I break it down into manageable chunks.  After reading the entire problem once to get a sense of what I'm dealing with, I re-read each sentence one at a time and try to write down in mathematical terms what each sentence is saying.  Often each sentence is only a portion of the overall equation, but I find if I tackle it like this, I can piece together the overall equation by looking at all the partial equations I got from each sentence.\n\nHope this helps a little.  Good luck!\n\n~ ♥ ~
934652
So let's say the problem looks like this\n\n   11\nx 12\n--------\n        <-----the answer from 11*2\n       <------answer from 11*1\n\nfirst hide the 1 from the 12 and work out the problem as 11*2\nthen work on multiplying the 1 with 11 but make sure you start putting your answer down below your first answer and the answer starts in the column that is below the 1 from the 12.\n\nfinally when the two answers are found, you can add them and get your final answer. SOOO here's what it looks like\n\n      11\n   x  12\n--------------\n           22    (this is from 11x2)\n +  11       (this is from 11 x1)\n------------\n     132 = final answer!
917544
This type of problem is solved by finding the fraction of the job each, then both, can do in an hour.  If t = the hours for the faster person, she can do 1/t of the job in an hour, the slower can do 1/(t+2) of the job, and together they do 1/5 of the job in an hour.\n\nSo 1/t + 1/(t+2) = 1/5
963940
Surely,you can do it.It reduces your head-ache of doing big multiplications and any proess which reduces your work-load but gives the correct answer is vaid.To tell you frankly,in higher classes,that is the procedure we follow to solve a problem in a quicker way.
269746
Make 2 7/15 an improper fraction, flip it over to its reciprical and mulitply the two.\n\nBoy...I hope I got that.  *bits fingernails*
465409
keep it together, cut it in half, the stack the halves.  then cut it twice.  you will have 3 stacks of 4