Trying to figure out odds.?
827228
Here's the real deal:\n\nBaltimore is a 4 point favorite. So if you want Baltimore and the score ends up Baltimore 24 Atlanta 20....That's a "Push" a Tie and NO money exchanges hands. For you to win betting on Baltimore they must win by 5 or more points. Atlanta is +4 Points, just the opposite. Add 4 points on Atlanta's final score to get your final score.\n\nThe over/under of 41.5 is combined points for the entire game. So if Baltimore wins 27-21 the total is 48 points and the OVER bets win, the under bets lose.
97799
i don't believe the person above me got the second part right.  he is right about the beginning - the first probability is 2/5:\n\npossible numbers to draw: 2 4 6 11 13 15\n\nso you can choose any of these six out of the fifteen given (6/15 = 2/5).  the next number you draw must be also a "winning" number.  BUT, you have to have an even number less than 7 AND an odd number greater than 10.  this gives us two scenarios:\n\nIF the first number picked was even and <7, then the possible numbers you can pick from are ONLY: 11 13 15, since picking another even number <7 will not meet your requirements.  this gives us a probablity of 3/14, since there are 3 "winning" numbers out of the 14 numbers left.\n\n\nIF the first number picked was odd and >10, then the possible numbers you can pick from are ONLY: 2 4 6, since picking another odd number >10 will not meet your requirements.  this gives us a probablity of 3/14, since there are 3 "winning" numbers out of the 14 numbers left.\n\nSO, finally, suppose you go with the first scenario.  the probability would be: (6/15)*(3/14) = 3/35  going with the second scenario will give you the same thing, 3/35.  thus adding these two, since you can have either scenario occur and still meet your requirements, gives you: 3/35+3/35 = 6/35.\n\nAnd that would be the odds: 6/35.
435037
try this site for help on probabiliity\n\nhttp://www.futureaccountant.com/probability/
176534
The results of a few lottery draws :)
152796
try this site...\n\nhttp://www.futureaccountant.com/probability/
513542
They have a 1 in 32 chance
852433
Fat chance on this site  :-)\n\n\n.
585757
The odds are based on the number of numbers you can select from.  For example, if the winning number is five numbers out of a total of 70, you have a chance of 1 in (70 x 69 x 68 x 67 x 66), since this is probability without replacement.  So the calculated odds are 1 in 1,452,361,680 in this example.\n\nAnd as for the answer that made fun of your use of commas, feel free to point out to him that his use of apostrophes was erroneous as well.  "comma's" was the word he used, and it really should have been "commas." :)
239442
You're picking the wrong numbers. listen carefully, i'll tell you the winning numbers for last week 4-23-26-31-40-51.\nNo just joking, its a good idea to have three of the numbers to be even numbers and three to be odd numbers, these hit almost all the time, other than that it's all luck.
90357
F- even and odds.  There are 3 even sides and 3 odd sides. So the likelihood is the same for both.
131088
try this site\n\nhttp://www.futureaccountant.com/probability/
85977
PLS GO TO A FORTUNETELLER!!!
765221
CASE 1:\nThe probability that 2 green balls are selected from box A:\n1/2 (chance of picking box A)\nChance of picking first ball green (3/6)\nChance of picking second ball green (2/5)\n\nSo the combined odds are: 1/2 x 3/6 x 2/5 = 1/4 x 2/5 = 1/10\n\nCASE 2:\nThe probability that 2 red balls are selected from box B:\n1/2 (chance of picking box B)\nChance of picking first ball red (4/9)\nChance of picking second ball red (3/8)\n\nSo the combined odds are: 1/2 x 4/9 x 3/8 = 12/72 = 1/6
469260
Wanna make a long term bet.
908589
Well, unfortunately, in order to have a good chance of winning the big prize, you'll probably have to spend more than the prize itself.  \n\nTo calculate the odds of winning, we start by finding the odds of getting one number.  In your scenario, it seems that there are 80 numbers, of which you've picked 40.  Neither the actual numbers themselves, nor the order they are selected makes any difference, since, presumably, each number has an equal chance of being picked.  For the first number, our odds are 40/80, or 1/2, since we have picked 40 numbers out of 80 total.  Not too bad, huh?\n\nWell, here's where it gets rough in a hurry.  We now need to get the second number.  The odds of us having this number have changed slightly, since one number is now off the board, to 39/79 (we have 39 numbers left, the board has 79 left).  This number must then be multiplied to the previous number, as only half of the situations have us selecting the first number correctly.  This comes out to 0.2468, or a little less than 1/4.\n\nContinuing along, each successive number has slightly decreasing odds, and must also be multiplied by the earlier odds as well.  So the odds on the third number are 40/80 * 39/79 * 38/78.  And so on, until we've calculated the odds of picking the 20th number (21/61) and multiplied it to the other 19 values.\n\nThe final value is a miniscule .00000003899, or 1 in 25.7 million.  By purchasing the second ticket, your odds increase to 2 in 25.7 million, with three tickets, the odds are 3 in 25.7 million, etc.  So to even have half a chance of winning, you will need to have a staggering 12.8 million tickets.  This may seem ridiculously high, but it's how lotteries, kenos, and other similar games of chance are able to do so well.\n\nHope this helps.
324600
The odds of winning are currently 7/1.  That is you will get seven times your stake back plus your stake if you were to back them to win.  Back them with Dareld Racing Bookmakers
148704
Here's a website that shows ALL the odds for every lottery game in OK:\nhttp://okc.about.com/gi/dynamic/offsite.htm?zi=1/XJ&sdn=okc&zu=http%3A%2F%2Fwww.lottery.ok.gov%2Findex.htm