Find the volume of a rectangular box that is 15cm by 25cm by 18cm?
825929
Multiply them together to get the volume in cubic cm...\n\nVolume = Width * Length * Height\nVolume =  15 x 25 x 18 = 6,750 cu. cm.
614589
width = 5 \nlength = 12
691993
density=mass/volume\n5.3=371/v\n0.014cm cubed=v\napproximately
948718
Width = 6 - 2x\nLength = 8 - 2x\nDepth = x\n\nVolume = x(6 - 2x)(8 - 2x)\n= 4x^3 - 28x^2 + 48x ← kindricko's work to here\n\nJust to add to kindricko's answer\n\nVolume is a positive quantity\nSo x cannot be negative or V will be negative\nSo the smallest value of x will be 0 (your graph will confirm this)\n\nAlso none of the dimensions of the box can be negative\nSo 6 - 2x cannot be less than 0 or even equal 0 (as then the box becomes a rectangle)\nie 6 - 2x > 0\nie x < 3\n\nSo the possible values for x lie in the domain\n0 < x < 3 and your graph should confirm this.\nNow somewhere in between the volume will reach a maximum.\nWhat is the value for x there, and so what is the maximum possible volume? (You can read this from your graph too if you draw it accurately enough)
747374
A rectangular prism is a box.\n\nSA (surface area) = 2 * l * w + 2 * h * w + 2 * l * h\n24 cm^2 = = 2 * l * w + 2 * h * w + 2 * l * h\n12 cm^2 = lw + hw + lh\n\nThe simplest prism that fits this would be a cube of 2 cm on a side:\n12 cm^2 = 2 * 2 + 2 * 2 + 2 * 2\n12 cm^2 = 4 + 4 + 4\n12 = 12
265577
LENGTH X WIDTH X HEIGHT DIVIDED BY 27
801034
Here's the answer: (I'm assuming the top of the box is counted in the area)---------   x = side of square base, h = height, S = surface area, P = perimeter length\n\nS = 2x^2 + 4xh\n\nP = 8x + 4h ---->  h = (P-8x)/4  Substituting,\n\nS = 2x^2 + 4*x*(P-8x)/4 = Px - 6x^2\n\nFor your particular case where P = 120 cm,\n\nS = (120x - 6x^2) cm^2
114649
Here's an idea.  Show them something that's pretty much flat and rectangular, such as piece of stiff carpet or a pad of paper.  Write on the board what the perimeter, area, and volume are.  Have them measure it with a tape measure and come up with the answers that you have.  They'll see that they just have to add for the perimeter but multiply for the area and volume.
783613
Area = length x width
875857
find what?...the dimensions of the box with the most volume?\n\nArea = w^2 + 4wh = 1100 cm^2\nh = (1100 - w^2 ) / 4w\n\nVolume = h w^2 =\nV = w^2 * (1100 - w^2 ) / 4w \nV = w (1100 - w^2 ) / 4\nV = 275w - (w^3)/4\ndV/dw = 275 - (3/4)w^2\nlet dV/dw = 0\n(3/4)w^2 = 275\n\nw = 19.15 cm\nh = 9.57 cm
882047
I can't draw a diagram, but that would help.  So, picture the box and the corners.  Label the amount cut off (like the size) from each side x.  The new length on each side is going to be 11-2x or 14-2x (as there are two squares on each side).  These multiplied together (like a rectangle) form the area of 80.  Let's solve.\n\n(11-2x)(14-2x)=80\n\nExpand.\n\n154-50x+4x^2=80\n\nBring the 80 over\n\n4x^2-50x+74=0\n\nBring out the two\n\n2(x^2-25x+37)=0\n\nx is about 1.715 solving this equation.\n\nThere is actually another solution, somewhere around 10.8.  However, this is an unnecessary solution:  10.8*2 is obviously larger than both 11 and 14.  We can throw it out.  \n\nCheck that:\n\n(11-2(1.715))(14-2(1.715))=80\n\nThat's your answer.\n\nHope this helps.
730124
1. volume = h*2*pi*r^2 =1000 so r^2= 1000/2/pi/h\n\nsurface area = 2*pi*(h+2*r^2)\nsurface area / volume = (h+2*r^2)/h/r^2 \n=1/r^2+2/h  = 2*pi*h/1000+2/h  which is a minimum when h is about 17.84  [(1000/pi)^0.5]
741778
This is not tricky at all. The volume is 1-1/2 cylinders of "height" 50,000 meters and radius 4 meters.\n\nThe formula for the volume of a cylinder is\n\nV = pi * r^2 * h
425258
volume = height X width x depth\nv = h x w x d\nv= 11 x 16 x 24\nv= 4224 inches^3 ( inches cubed )
783604
volume=pir^2h=1000\nsince there are two variables we need a minimum of two equations
202519
C'mon man, do your own homework else you'll never learn.\n\nVolume = height * width * depth\n20 = h * 2 * 2.5\n\n????
457143
20 boxes at $.75 equals $15.00\n25  boxes at $.40 equals $10.00\ntotal:  $25.00