If you have a 45 RPM and side A has a 3 minute 30 sec. song in length in it. How many grooves r in the record?
821802
This is an old riddle.\n\nAssuming the record has two sides (A and B), the record has two grooves.  Each side has one continuous groove that spirals inward to the center.\n\nAs a side note, a 3.5 minute song on one side of a 45 RPM record would require 157.5 revolutions to play, so that one groove would spiral around 157.5 times.
125730
Dont know about the CD but I have the 45
1033681
ok this might be confusing but here it goes\n\n2 gigs is 2,147,483,648 bytes\na short music video is about 38,912,000 bytes\nso dividing these i got about 55 vidoes. its late so i might have missed a number.\ntried to help tho
894979
I'd say about 60 to 65, depending on the length of the songs. Most songs are about 4 minutes long, which is around 4MB, and suppose all your songs were exactly 4 minutes long, then you could fit 64 songs, but I assume you have longer/shorter songs, so maybye more or less than what I estimated
1120502
Here's something interesting I found on a website from Roxio:\n\nAbout 90+ minute CDs \n\nAccording to the official Red Book standard, the maximum playing time for an audio CD is 74 minutes. This specification has been stretched by everyone in the industry to support 80-minute audio CDs. However, anything over 80 minutes clearly violates the specification. Most CD players and CD recorders will therefore have problems reading or writing 90-minute discs. The following problems can occur: \n\n- CD player doesn't recognize the disc \n- CD head bounces out of the groove \n- CD player can't find tracks after 80 minutes \n- CD can't be copied \n- CD can't be read (90+ minute CDs use a very tight groove) \n- CD created may contain same sector number twice \n- CD created may contain a sector with a negative number \n\nMost of these problems will result in an unreadable CD. Worse, it is even possible that trying to record or play a 90+ minute CD could physically damage the CD player or recorder. WE THEREFORE STRONGLY RECOMMEND THAT YOU DO NOT USE 90+ MINUTE CDs!
107395
I am not sure what is happening, but here is a pretty simple suggestion.\n\nI would bring in a home style setup.  Remember that most studio equipment is high-end compared to the stuff most people have at home.\n\nCreate a track the way you normally do, and then play it on the home stereo you brought into the studio.  Now you have a comparison you can make in less than 30 minutes.\n\nWhen you make the first test recording, do it just like you have before.  For the second recoding, check the overdrive limit of the CD, and record this 2nd CD as high as possible without distortion.\n\nI hope this suggestion will help you.  My profile contains my email address, so if you experiment and are still having trouble you can write me.\n\nBest of luck,\nJeffrey
82903
A song's tem is it's Tempo
212066
30 mins = 3/4 page therefore you take 10 mins for every 1/4 of the page .. so one page = 40 mins ... so 6 pages = 6 x 40 = 240 mins = 4hr\n\n*edit*\n\nif you want to use fractions to find of one page do 30 x 4/3
244207
There's not enough room to give you an effective answer here.  Email me at mad4tunes@yahoo.com, with an explanation in the title, and I'll email you back with the brochure I put together on doing this.
678982
this is 100% correct\n\nhttp://www.mxtabs.net/tab_versions.php?path=Guitar,g,563,Green+Day,Good+Riddance+%28time+Of+Your+Life%29,234265
412968
70\n\ndivide 30 by a half equals 60
877000
if you are talking about blank cds that use uncompressed music(like when you get a cd and it says 80 min)\n\nyou get  700 mb =80 min so\n\n80/700=0.114285714 minutes in 1 mb.\n\n\nthat is not really the way to think about it for compressed music\n\nit all depends on the compression used and how much was gained by said compression.\n\n\nbut if i had to go by the average mp3 song I would say:\nthe average song is 3.5 mb in mp3 format and is about 3 to four min so I would say you can get about a minute of mp3 music in 1 mb on average.
559713
This related to music ,,, how? 2 pts here.
544479
The speed of sound: 340.29 m / s
150473
Are you trying to sell band equipment, or are you some kind of non English speaking DJ. If your "Drum and bass" is as disjointed as your English, wont it mess up the beat count.I can imagine it on a count of one to four.\nOne tw hree fou. Sorry dude but yur enlish is upallling.
493056
The tempo is different for each song.  I could make a generality, and say that most jazz songs in 3/4 time are around 135bpm (beats per minute), but that's hard to determine.  Some jazz songs are slower, and are played as low as 95bpm.  If you're looking for determine the tempo for a particular arrangment I would suggest getting a hold of a metronome, or this online metronome:\nhttp://www.metronomeonline.com/\n\nA metronome will be able to count out the beat for you, and you can sync it up with the jazz you're looking to play.  Hope this helps!
2556
You're really close! The answer is actually 1:03:11. You were off one minute because you forgot to borrow a minute from the 34 so you could subtract the seconds.