I need to solve by completing the square:?
826907
ill write down the formula for finding the root of a quadratic equation :  ax^2 + bx + c = 0\nsolution: x = {-b +- sqrt(b^2 - 4ac) } / 2a\n\nequation x^2=5x + 2 can be written as :\n\nx^2 - 5x - 2 = 0\nhere a = 1 ; b = -5 ; c = -2 ;\nsimply apply the formula to find the value of x .\n\nx ={ -(-5)+-sqrt(25 - 4*-2) } /  2\nx ={ 5 +- sqrt(24+8) } / 2\nx = { 5 +- sqrt(33) } / 2\n\nThe second equation :\n\n4x^2 + 2x - 3 = 0\nhere a = 4 ; b = 2 ; c = -3\n\nx = {-2 +- sqrt( 4 - 4*4*-3) } / 2*4\nx = {-2 +- sqrt(4+48) } / 8\nx = { -2 +- sqrt(52) } /8\n\nsimplify the term inside the square root ,  52 = 13*4\nso 4 gets square rooted and\n\nx = { -2 +- 2 sqrt(13) } /8\n\ntake 2 common from the numerator and denominator and cancel them.\n\nx = 2{ -1 +- sqrt(13) } / 4*2\nx = { -1 +- sqrt(13) } / 4\n\nthats your answer.\n\nhave a nice day :)
671808
4 sides and corners in a square
860621
That means write a binomial that if squared gives you t^2 - t + some constant then subtract that constant to "complete" the square.\n\n(t - 1/2)^2 would be t^2 - t + 1/4 so you have\n\n[(t-1/2)^2 - 1/4 ]- 1 = 0\n\n(t-1/2)^2 - 5/4 = 0\n\n(t- 1/2)^2 = 5/4\n\nsq rt both sides\nt - 1/2 = +- sqrt(5)/2\n\nadd 1/2 to both sides\n\nt = 1/2 +- sqrt(5)/2
945218
[(x^2)^2]^2\n\n(x^2 -4x +4)^2\n\nmultiply      x^2  (x^2 -4x +4)^  = x^4 -4x^3 +4x^2\n\nmultiply     -4x (x^2 -4x +4)^    = -4x^3 +16x^2 -16x\n\nmultiply     4  (x^2 -4x +4)^      =  4x^2 -16x +16\n__________________________________________\n\nthe answer should be                 x^4 -8x^3 +24x^2 -32x +16\n\ni hope that helped
1170609
Completing the square isn't too bad. The first thing I have my students do is identify a, b, and c.\na=1 (this is good, it makes the problem even easier)\nb=-4 (this is VERY good, whenever b is even, it divides by 2, which makes our problem much easier)\nc=-5\n\nNow, the only steps for completing the square are to:\n\n1) Find b\n2) Take half of b\n3) Square that\n4) Add that number to (x^2 - 4x +      ) - 5\n\n1) b= -4\n2) half b is -2\n3) square that is +4\n4) Add that number to (x^2 - 4x + 4) - 5\n\nThe trick now is that you changed the problem by adding +4, so you minus it back out to keep things fair. We now have:\n\n(x^2 - 4x + 4) - 5 - 4 simplify to\n(x^2 - 4x + 4) - 9\n\nNow, we factor (x^2 - 4x + 4), which is easy.\n\nIt will always be (x     )(x     ), and the blank will always be the half b.\n\n(x - 2)(x - 2) - 9\n(x - 2)^2 - 9 = 0  to solve for x...add 9, then square root both sides.\n\n(x - 2) = sqrt (9)\n\n(x - 2) = +3 OR (x - 2) = -3, add 2 to both sides:\n\nx = +3 + 2 OR x = -3 + 2\n\nx = 5, or x = -1\n\nOnce you get the hang of completing the square, it is really easy. Plus, it is really nice because doing so puts your function in whats called vertex form, making it really easy to find the vertex, and then the shape of the graph.\n\nGood luck on the rest!!
330086
Completing the square:\n\nGet the x^2 term by itself\nx^2 + 7x/5 - 6/5 = 0\n\nMove the constant to the other side\nx^2 + 7x/5 = 6/5\n\nTake half of the constant for the x term and square it: half of 7/5 is 7/10, squared is 49/100.  Add this to both sides of the equation\n\nx^2 + 7x/5 + 49/100 = 6/5 + 49/100\nx^2 + 7x/5 + 49/100 = 169/100\n\nThe left side is a perfect square trinomial - factor it\n(x + 7/10)^2 = 169/100\n\nTake the square root of both sides and solve for x\nx + 7/10 = +/- 13/10\nx = -7/10 +/- 13/10\nx = 6/10 or -20/10\nx = 0.6 or -2
1087500
Just to complete to previous answer, in case it isn't clear:\n\nTo make it a perfect square you add (-b/2a)^2 to both sides.\nAs noted: \n(-7/2)^2 = 49/4\n\nStarting with:\nx^2 + 7x = -12\n\nAdd 49/4 to both sides:\nx^2 + 7x + 49/4 = 49/4 - 12 = 1/4\n\nFactor the perfect square:\n(x + 7/2)^2 = 1/4\n\nNow take the square root of both sides remembering that there are two roots (+ and -):\nx + 7/2 = +/- 1/2\n\nSo there are two equations\nx + 7/2 = 1/2  or x + 7/2 = -1/2\n\nSo x = -3  or x = -4
571026
Whenever you have the difference of two squares\n\nF^2-S^2\n\nit factors as\n\n(F-S)(F+S)\n\nMemorize that pattern and problems like this will be a breeze.
857194
These problems look as though they need factoring.\nThey are the difference between two squares.\n\nDefinition : a^2 - b^2 = (a - b)(a + b)\nMultiply out the right-hand side to see that this is true.\nSo you just take the square root of each term.\n\ny^2 - 7 = y^2 - [sqrt(7)]^2 =  [ y - sqrt(7) ] [ y + sqrt(7) ]\n\nz^2 - 36 = z^2 - 6^2 = (z - 6)(z + 6)
888367
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
87810
Perfect squares between 1 and 49 are:\n1*1=1,\n2*2=4,\n3*3=9,\n4*4=16,\n5*5=25,\n6*6=36,\n7*7=49,\ntherefore \n\n49 = 49\n\nOnly one term is needed
540085
(a-2)(a+2)  \n(difference of squares)
170337
numbers 3 and 4\n\nx(squared) is still an integer and xy/x=y, which is an integer
925629
polyeig(-5,-2,4,2) \n\nwill solve the equasion.  To learn about interpelations type:\n\nhelp interp1
942253
the answer is -3x square root of 2
837603
factor a 2 out of the first two terms\n2(x^2-x)-40\ncomplete the square\n2(x^2-x+1/4)-40-1/2\n2(x-1/2)^2-40.5\nthe vertex is at x=.5    y= -40.5
832845
you need to add +1\nso that the equation can be represented as a perfect square\nx^2 - 2x + 1 = (x - 1) (x - 1) = (x - 1)^2\n\nthis is called solving by perfecting the square\nto do this, make sure that the coefficient of the first term is 1.\nThen, divide the coefficient of the middle term by 2,\nthen square the whole thing.\n\nIn this case, the coefficient of the middle term is -2\n-2 / 2 = -1\n(-1)^2 = +1