If you dive from a 3 ft diving block and enter the water at 4 ft from the base of the wall.  How far do you?
821134
One does not dive in a straight line, unless one is diving straight down. The effect of gravity causes the body to accelerate in the vertical direction, while (ignoring wind resistance and the curvature of the earth) one travels at a constant speed in the horizontal direction.\n\nSo this become a question of the length of the parabolic curve that you follow in travelling from the diving block to the water. This will be slightly greater than the 5-foot straight-line distance to the landing point (the splash point).\n\nIf you are studying calculus, write an expression for the path that the body follows, and apply the following formula: \ndistance = Integral (sqrt(1 + (dy/dx)^2) dx)\n\nRegarding your followup question:\nIf you're assuming that everything is a straight line, you just ratio everything up (using the concept of similar triangles), so the answer is 6/5 of 3 feet.\nIf you're using calculus, you need to use the concepts in the explanation above, and eventually use algebra to solve for the height of the platform.
695604
The only way I can see this being done is to have a piston or other way to separate the water and air; otherwise, the air will simply bubble up through the water.\n\nAssuming there is a piston or other separation device and the water will overflow at the top, the initial pressure needed to begin the displacement of the water is the height of the water in inches  times its density in pounds per cubic inch. Taking the density of water as 62.4 pounds per cubic foot and converting to pounds per cubic inch the density becomes .036111. The height is of course 100 ft time 12 inches per foot or 1200 inches. This yields an initial pressure of 1200 time .036111 or 43.33 psi. As the piston moves upward, the required pressure will decrease directly in proportion to its height or .4333 psi per 12 inches of rise.
751591
Probably from 6 to 10 feet., if the drop is feet first, and you don't get the air or wind knocked out of you when you hit. I was about that size on my first hi dive jump. Although they usually measure it in meters. Chances are, when you look at it from that height, you may decide otherwise unless provoked by someone in a dare! the distance after about 30' doesn't change as the speed rate of fall will be the same.
421847
4000 / (16 x 8 / 144 ) = 4500, you need 4500 blocks. That was a really easy question, I can't believe all the people above got it wrong. People! you need to convert the face of the block in ft²! 16 x 8 = 128 square inches = 0.88 square feet; hence, one block is equal to 0.88 ft². C'mon now, on this one I deserve the best answer.
857138
1ft. = 0.305m\n\n120m. x (1/0.305) = 393.44ft
689078
Yes, commercial oilfield divers regularly work at that depth and deeper. It has become fashionable for amatuer scuba divers to exceed 300' also, though the equipment and minimal back-up they have make this a risky enterprise.\n\nRight now, as you read this there will be an oilfield diver working offshore Brazil in 1,400... yes 1,400 feet of water!
790550
l = 3w - 2\n\nP = 2(l + w)\n\n44 = 2((3w - 2) + w)\n44 = 2(3w - 2 + w)\n44 = 2(4w - 2)\n44 = 4(2w - 1)\n2w - 1 = 11\n2w = 12\nw = 6\n\nl = 3w - 2\nl = 3(6) - 2 = 18 - 2 = 16\n\nANS : \n\nWidth = 6ft\nLength = 16 feet
1053798
Exhaling before attempting to descend underwater is simply a matter of allowing the body to displace less water (your chest area will be smaller), thus resulting in a negative state of buoyancy, and you sink.\nTry this to see for yourself. Next time you are in a pool, go to the deep end. Take a deep breath and do not move. Then slowly start to exhale. You will start to descend. The more air you exhale, the more you will find yourself going underwater. Of course only do this if you are comfortable in the water, and can recover from an out of breath state. \nHope this answers your question?!?!
1144865
Underwater cave diving
1119837
First divide up the initial velocity into its horizontal and vertical components.\nV is the initial velocity of 40 m/s.\nTheta is the launch angle of 37 degrees above the horizon.\nV_x_i and V_y_i are the horizontal and vertical components of the initial velocity respectively.\n\nV_x_i = V * cos(theta) = 40 * cos (37) = 31.95 m/s\nV_y_i = V * sin(theta) = 40 * sin (37) = 24.07 m/s\n\nAlthough the vertical component of the object's velocity will change as the object experiences gravitational acceleration toward the ground, neglecting air resistance, the horizontal component of velocity can be treated as a constant.\n\nV_x = V_x_i = 31.95 m/s\nV_y = V_y_i  - g*t\nwhere t is the time after the object is launched and g is the gravitational acceleration experienced by the object (g = 9.81 m/s^2).\n\nIf the fence which the object hits is 128 meters away (in the +X direction), then the object (traveling at 31.95 m/s in the +X direction) will hit it at about 4.01 seconds after launch.\n\nBy taking this value (4.01 s) and plugging it in for t in the below shown equation to solve for the distance relative to the initial launch height the object has traveled,\nd = V_y_i * t + 1/2 (g)t^2\none can calculate that the object is at a height of about 17.65 meters above its original launch height.\n\nSo I calculate the impact height to be 17.65 meters.
438161
Send down a SCUBA diver to look!  Just kidding.  Your idea to pump out the well and see what happens sounds good.  If you have a camcorder, you could tie it to a rope and lower it to the bottom to have a peek like in the movie Volcano.
1045735
well, since a 4-kilo shot weights slightly more (8.8 lbs vs. 8 pounds), I guess it would be less than 40', maybe 37' or 38' feet...
756848
Bob was travelling at 9.5 meters/sec when he started his jump. To gain maximum range he needed to jump at a perfect 45 degree angle. If he had done so, his initial velocity vertically would have been 9.5 /sqrt(2) = 6.72 meters/sec. His maximum height would occur at time t where 6.72-gt = 0.\n9.78t = 6.72\nt = 6.72/9.78 = 0.687 secs\n\nAfter that he would fall for another 0.687 secs till he hit the ground for a total of 2(0.697) = 1.37 secs\n\nIn this time, he would have traveled (6.72)(1.37) meters horizontally or 9.23 meters.\n\nSo his jump of 8.90 meters was 0.33 meters short of perfection.\n\nNote that air resistance (which is pretty important in reality) would have the effect of making the maximum achievable jump shorter than 9.23 meters. So his jump was better than it appeared..
519509
Depends if you want to come up again or not. It's not swimming down that's the problem.\n\nIf you're not bothered about coming up, you should dive over the Marianas Trench which reaches 10,911m down (not sure how accuracy to a metre is guaranteed!).\n\nFree diving has various categories and records, but the absolute maximum at the moment is held by Austrian diver Herbert Nitsch. On 2 October 2005 he dived to a depth of 172 m (564 feet).\n\nCurrently, the world record for scuba diving is just over 1000ft.  On June 13, 2005 Nuno Gomes, a 52-year-old civil engineer from South Africa, descended to a depth of 1,044 feet in the Red Sea. May be a later record now. I find it amazing how little depth we can go to when you imagine how small a 1000ft hill really is, about a 100 storey building.
49247
if its more than 4 inches thik
517312
300 meters (or 1000 feet) is about as far as a human being can go without the aid of a vessel. Dive depth records are a little over 300 m.\n\nThe Eiffel Tower is 300 meters tall, which is not very far at all considering how deep the ocean goes. The ruins of the Titanic, for example, are at a depth of 3,800 meters (which is about 2.5 miles). The pressure at that depth is over three tons per square inch - enough to crush you in an instant!
63833
50 feet or about 2-3 seconds