wld plse show me step by step how to rite eqation with this line & pt & make it parlel to line (6,-7) 3x-5y=7?
818056
3x - 5y = 7\n5y = 3x - 7\ny = (3/5)x -7/5\nA line parallel to it is y = (3/5)x + b\n(6 , -7) on it, so -7 = (3/5)*6 + b\n-35 = 18 + 5b\n5b = -53 and b = -53/5\nThe wished line is y = (3/5)x - 53/5 or\n5y = 3x -53\n\nTh
736379
for this just substitute for x and y in eqn and see if LHS=RHS\nLHS=4\nRHS=(-1/2)(-3)-5/2\n=3/2-5/2\n=-2/2\n=-1\nnot = RHS\nso pt. not on line
748360
Regroup and add.  You got the 5n, so you should be able to get the other part!\n\nn + n - 1 + n - 2 + n + 7 + n - 11 = \nn + n + n + n + n - 1 - 2 + 7 - 11 =\n5n - 7\n\nNotice that -1 -2 - 11 = -14, add 7 to it and you get -7\n\nNRT
232213
I'll do the fourth problem.\n\n-3x< -6  or x+5< -2\n\nfirst deal with one half- \n-3x< -6 (now divide by -3)\nx>2 (when you divide by a negative the sign is reversed)\n\nthen the second half- \nx+5<-2 (get x alone, so subtract five from each side)\nx< -7\n\nso you have:\n2 < x  or  x < -7\n\nto graph this there is a line with an arrow to the left of the first slash and another line to the right of the second slash\n\n<-----/-------0--/-->\n____-7______2
1149797
The first one is (-5, 3). I don't remember how to do the others.
534868
7\nbecause\n6m+5=47\n.....-5 -5\n   6m=42 (divide each side by 6 and u get 7 {42/6 =7)
740076
First solve for y.\n3x - 5y = 7\nSubtract 3x from each side\n-5y = -3x + 7\nDivide everything by -5\ny = (3/5)x - 7/5\nThe slope is m = 3/5\nSInce the new line is parallel to the given line, that means the slope will be the same.  Use your given point to find the  line\ny - (-7) = (3/5)(x-6)\ny + 7 = (3/5)x - 18/5\ny = (3/5)x - 18/5 - 7\ny = (3/5)x - 53/5
373486
10y - 3 = -10 + 6y\n    + 3 =  +3 <-- subtract 3 from both sides  \n-------------------\n10y = -7 + 6y\n-6y =    - 6y <-- subtract 6y from both sides\n---------------\n4y = -7\n--   --\n4  =  4 <-- divide both sides by 4\n\ny = -7/4
965314
Not sure why u can't do these yourself but 1) = -360 \n2) -12\n3)-56.8\n4)-45\n5)1328\n6)-144\n7)-.5\n8)25\n9)11\n Those should be right
655321
set the lines equal to each other\n3x+4 = -2x-11\n5x+4 = -11\n5x = -15\nx = -3\nthen plug into either equation to find y\n\ny = -2(-3)-11\ny = 6-11\ny = -5\ntherefore the point of intersection is (-3,-5)\n\ntosmith
564317
Start as Jim Valentinojr stated:\n\n-1   0  -2 |  -6\n 1   4  -3 | -31\n 5   1  -1 | -28\n\nNow, do row and column operations as he stated until the first element of each row is a "1" and everything below is a "0."\n\nYou will have something that will look like:\n\n1  0  0 | 4\n0  1  0 | 2\n0  0  1 | 3\n\nThen, look at the columns the "1's" are in.  In the bottom row, 1 is in the z column, so the solution in this example is z = 3, y = 2, x = 4.
822034
You're NOT dumb!  Everyone has different skills.  Thought you were going to send me a note when you got stuck??  I took alg II twice!\n\n1.  simply switch it to s=1-2t.  Now put that first one into the second , for s, which will give you the value of t when you solve it.  Plug in t's value into either and that will give you s.\n\n2.  do the same way\n\n3.  P=120\n     L=3w\n     P=L times W\n\n4/5:  take the number on the outside and multiply each number inside the (), then combine.\n\n7/8:  isolate the variable (letter) and get it just on one side
496037
-3x + 5y = 8\nx + 2y = 1\n\n(-3x + 5y) + (x + 2y) = 8 + 1\n-3x + 5y + x + 2y = 9\n-2x + 7y = 9\n\n7y = 2x + 9\ny = (2/7)x + (9/7)\n\nx + 2y = 1\nx + 2((2/7)x + (9/7)) = 1\nx + (4/7)x + (18/7) = 1\n7x + 4x + 18 = 7\n11x + 18 = 7\n11x = -11\nx = -1\n\ny = (2/7)x + (9/7)\ny = (2/7)(-1) + (9/7)\ny = (-2 + 9)/7\ny = (7/7)\ny = 1\n\nx = -1\ny = 1
49155
first. ALWAYS start with the inner parentheses and work outward. \n\nSo removing the parentheses we get:\n\n-30x+9 + 30x-30 = x -7\n\nWe can combine the x's on the left side and the numbers. -30x + 30x is zero, so:\n\n-21 = x - 7\n\nWe need to get rid of the -7, so we add 7 to both sides\n\n-21+7 = x -7 + 7\n\nso -14 = x
766449
(-x/4+ 5/6) * 12 < (4x/3 +2) * 12 (mulitply both sides by 12)\n\n-3x +10 < 16x + 24\n\n-3x-16x +10-10 < 16x-16x + 24-10 (move all variables and numbers to one side)\n\n-19x< 14 (divide both sides by 19)\n\nx < -14/19\n\n* means times\n\n(-n/5 + 6) * 5 > n *5 (multiply both sides by 5)\n\n-n + 30 > 5n\n\n-n + n +30 > 5n +n (move all varialbes to one side)\n\n30 > 6n (divide both sides by 6)\n\n5>n
331369
a/5 = 6\nYou want to isolate the 'a'.  Move the 5 from the left side of the equal sign to the other side of the equal sign.  When you move it to the other side you invert it, so 1/5 (a/5 is essentially a*1/5) becomes 5/1, or just 5, and multiply by whatever is on that side of the equal sign.  So you get:\na/5 = 6\na * 1/5 = 6\na = 6 * 5/1 \na = 6 * 5\na = 30
101541
This is kinda wierd without drawing it out, but I'll try to explain and you can come up with the picture.\n\n1)  Start Program\n2)  Accept Input\n3)  Add 1 to counter\n4)  If counter is not equal to 3; go to #2\n5)  If N2 > N3, do #6-8; if not, go to #9\n6)  Move N3 to a hold field\n7)  Move N2 to N3\n8)  Move the hold field to N2\n9)  if N1 > N2, do #6-8 with the N1 & N2 replacing each other\n10) if N2 > N3, do #6-8\n11) print them