how do you solve 3/7 + 2/m and 3/n - 3/10?
821528
Before I can do anything you're going to have to tell me what they are equal to.
811523
(0 -7)/(-9-4) = -7/-13 = m = 7/13\n0 = 7/13(-9) + b ----> b = -63/13 \n\ny = 7/13x - 63/13
874116
-7,-10,-13 by putting n= 1 2 and 3
210403
8x-5x+3=x-7+10\n8x-5x+3-x=-7+10\n8x-5x-x=-7+10-3\n3x-x=3-3\n2x=0
516434
Okay first of all you write it like this...\n(3.5-1.666~)/1.333~\nUsing fractions is easier in this case, so here it is.\n7/2-5/3= 21/6-10/6=11/6 division by a fraction is multiplication by the inverse, so multiply 11/6 by 3/4 and you get 33/24, which can be reduced to 11/8 (eleven-eigths)\n\nBy the way, it's spelled "parenthesis"
683580
y^2 + 7y + 3y + 21\ny^2 + (7 + 3)y + 21\ny^2 + 10y + 21\n(y + 7)*(y + 3)
553445
42/15  /  7/3=\n\n42/15 * 3/7=\n\n[42*3]/[7*15]=\n\n[6*7*3]/[7*3*5]=\n\n6/5
712251
3p/7 = 4/5\n\nMultiply both sides times 7\n3p/7 * 7 = 4/5 * 7\n3p = 28/5\n\nMultiply both sides times 5\n3p * 5 = 28/5 * 5\n15p = 28\n\nDivide both sides by 15\n15p / 15 = 28 / 15\np = 28/15 \n\nCHECK YOUR ANSWER\n3(28/15) times 5=28\n7 times 4=28\nit is the correct answer\n\n\ngo to WWW.MATH.COM for homework help =)
437783
1) 1, 2, 3 and 6\n2) 1, 2, 2m\n3) 1\n4) 1, 3\n\n5) 5/9 (55/99) > (45/99) 5/11\n6) 2/3 (8/12) < (9/12) 3/4\n7) 4/5 (32/40) < (35/40) 7/8\n8) 1/3 (4/12) = (4/12) 4/12
969498
You need to find a common denominator for each one.\n(7x+3)/x\n\n(40c+18z)/(15cz)\n\n(8+21)/6y = 29/6y
846396
3(2s-3)=-(7-s)\n6s-9 = -7+s\n5s=2\ns=2/5
20617
5m-2n (m=-3, n=-2)\n= 5*(-3) - 2*(-2)\n= -15 - (-4)\n= -15 + 4\n= -11\n\nfor m= -3 and n= -2, 5m-2n = -11
435646
You must first find the lowest common denominator, then then multiply each top by the same  and then add. Example\n3/5 + 1/2 = 6/10 + 5/10 = 11/10 or 1 1/10
820171
First change them to improper fractions to do this multiply the whole number by the denominator so in 3 and 7/8 you would take 3 times 8, once you got that you would add it to the numerator so\n\n3x8=24\n7+24=31\n\nso you have 31/8 for the first fraction\n\nrepeat this step for the second\n2x10=20\n20+9=29\n\nthe second is 29/10\n\nNow you must fine the lowest common denominator for both fractions, which means find a number both 8 and 10 divide into evenly. Both go into 40 evenly, so you want the denominator to be 40 on both fractions, to do this multiply the top and bottom of each so that the denominator is 40 so for the first fraction, 31/8 you would multiply both the top and bottom by 5.\n\n(31/8)x5=155/40\nand the second fraction\n(29/10)x4=116/40\n\nnow you can subtract them\n\n(155/40)-(116/40)=39/40
308039
[3x/(5x+15)][(7x+21)/3]\n= [3x/(5(x+3))][7(x+3)/3]\nCancel the 3's and the (x+3)'s\n= [x/5][7/1]\n= 7x/5
741076
1/x+3/x+2=7\nMultiply by x getting:\n1+3+2x =7x\n4-5x =0\n0x* -5x +4 =0\n\n7/2x+2/x-1=4\nMultiply by 2x getting:\n7 +4 -2x =8x\n11-10x = 0\n0x* -10x +11 = 0\n\nx*+7x+2=2x+4\nx* +7x -2x +2 -4=0\nx* +5x -2 = 0\n\n4x*-3x=2x*+7 \n4x* -2x*-3x -7 =0\n2x*-3x-7 =0\n\n2x+3/x-1=x/4\nMultiply by x getting:\n2x* +3 -2x = x*/4\n2x* - x*/4 -2x +2=0\n2.25x* -2x +2 = 0\n\nThere, its done simply by multiplying and transposing terms to get what you want. You can move any term from one side of the equation to the other as long as you change its sign fro minus to plus or plus to minus.
838340
2m - 3(9m + 1) = 7m + 4(7 + 5m)\n2m - (27m + 3) = 7m + (28 + 20m)\n2m -27m -3 =7m +28 +20m\n- 25m - 3 = 27m + 28\n- 25m - 27m = 28 + 3\n- 52m = 31\n52m = -31\nm = - 31/52