Write in the form a + bi, the following division problem  1/(3 + 2i)?
830047
1/(3 + 2i)\n= 1/(3 + 2i) (3-2i)/(3 - 2i)\n= (3-2i)/ (9+4)\n= (3/13) - (2/13) i\n`
1109416
3/x  + 1    the way you put it..
797941
My Dear Aunt Sally is how I learned it.\n\nMultiplication Division Addition Subtraction
470404
((a^2 - b^2)/8a) X ((4a^3)/(a + b)^2))\n(4a^3(a^2 - b^2))/(8a(a + b)^2)\n((4a^3)/(8a)) * ((a^2 - b^2)/(a + b)^2)\n((a^(3 - 1))/2) * (((a - b)(a + b))/((a + b)(a + b)))\n((a^2)/2) * ((a - b)/(a + b))\n\nANS : ((a^2)(a - b))/(2(a + b))\n\nOn your problem, here is where you went wrong\n\nTo make it easier, you should had kept your problem in\n\n(4a^3(a - b))/(8a(a + b)) form, then had done this\n\n((4a^3)/(8a)) * ((a - b)/(a + b))\n\n(4/8)(a^(3 - 1))((a - b)/(a + b))\n(1/2)(a^2)((a - b)/(a + b))\n((a^2)(a - b))/(a + b)
695176
6x^2-3x-4x+2\n3x(2x-1)-2(2x-1)\n(2x-1)(3x-2)
395828
haha, but this does not work. you cannot mathematically divide by (a-b) because this quantity is equal to 0. (1-1)=0. Dividing by zero yields an indeterminate answer.
119559
its (x+2)(3x+1) now thats rite lol
972642
(A^2+2ab+b^2)/(a+b) + (a^2-b^2)/(a-b) + (a-b)/(a+b)/(a^2-b^2)/a+b)\n(a+b)^2/(a+b)+(a+b)(a-b)/(a-b)+ (a-b)/(a+b)*(a+b)/(a^2-b^2)\na+b+a+b+(a-b)/((a+b)(a-b))\n2a+2b+1/(a-b)\n\nif I got all the ( ) in the right places.
913289
You end up with a remainder, so it's not pretty, but you should be able to do long division and get:\n\n3x^2 - 4x + (16/3) - 23/(3*(3x+2))
1137023
(2x-9)(2x+9)\n\na guess... its been a long time since I did that stuff
572398
first multiply i by everything in the first bracket.\nso -8i * i + 3 * i + 2(2-5i)\n\nthen do same with 2nd bracket\nso -8i^2 + 3i + 2*2 - 5i*2\n= -8i^2 + 3i + 4 - 10i\n\nnow collect all the like terms\n-8i^2 + 3i - 10i + 4\n= -8i^2 - 7i + 4\n\nnow if i is the imaginary number i^2 would be -1.\nso it would be 8-7i +4 = 12-7i\n\nhope that helps. laterz
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
993955
Sorry, it would be easier to see if I could write the fractions normally...\n\n2(1/(h+1)  - 1) * 1/h\n\n2(1/(h+1)  - (h+1)/(h+1)) * 1/h\n\n2((1-h-1)/(h+1)) * 1/h\n\n2(-h/(h+1)) *1/h\n\nBring out the negative:\n\n(-2/h)*(h/(h+1))\n\nCancel out the h in the numerator with the one in the denominator.\nYou get -2/(h+1)
652728
a=b=i^(1/3)\ni=-1\nab+a^2b+ab^2 = [i^(1/3)*i^(1/3)] + [i^(2/3)*i^(1/3)] + [i^(1/3)*i^(2/3)]\n= [i^(2/3)] + i + i\n= -2+(-1)^(2/3)
386814
They are correct.  Observe the order of operations or PEMDAS\n\nParenthesis\nExponents\nMultiplication-Division\nAddition-Subtraction\n\nso first multiply   -89 * 658 =   -58562\nThen add 2   =                    -58560\nThen add 6   =                    -58554\nThen subtract 89 (or add -89) =   -58643
960799
BIMDAS BIMDAS BIMDAS!\nbrackets, indices, multiplication, division, addition, and then subtraction\n\nHence, do your 6.4 divided by 0.032 first.\nThen, do 3.34 add the answer from above.\n\nShould be 203.34
1119654
(a+b)(a-b)=b(a-b),\nhere you want divide both sides by a-b,\nbut this is not accepted,\nbecause a-b=0 (as you have assumed that a=b)\nDivision by 0 is not defined.\nDividing both sides by 0 is your mistake.