Please help me with this calc im so confused?
829349
Take the derivitive of your equation with respect to t\nd(9x^2+16y^2)/dt = 18x dx/dt + 32y dy/dt = 0\n\nThey give you dx/dt = 4y.\nSubstitute this in the above equation and then solve for dy/dt.\n\nThe maximum dy/dt will be pretty easy to find from the equation you get.
805613
Since this is a slice of a sphere, it makes sense to do things all in sperical coordinates.  From your limits, that is what you are doing. All of your limits look fine.  All that remains is to convert the funciot to spherical coordinates using:\n\nx = p*sin(phi)*cos(theta)\ny = p*sin(phi)*sin(theta)\n\nAnd use- a differential volume of dv = p^2 * sin(phi) * dp dphi dtheta\n\nAfter integration I get:\n\n(R^4)/4 * (atan(4/3) - 4/25) ( 3*sin(b) + cos(b) - 3)\n\nWhere R = 25, b = atan(sqrt(277/123))
921398
I just taught this section today to my calc students.  You start by finding the first and second derivative.  I recommend looking in your book for an example.  Your book probably has something like this towards the front of the section.  It would be too long winded to write everything down here.  If you don't have your book on you, the web page below has problems that you can do and then check your answer.\n\nhttp://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/graphingdirectory/Graphing.html
380004
I don't understand.  Can you explain the problem a little better?
1150392
No problem, i just finished a calc3 course in college.\n\nYour problem is the same as 125 * (6x^2 + 5x + 7)^(-1/3)\nYou have to use the chain rule so you get\n125 * (-1/3) * (12x + 5) * (6x^2 +5x + 7)^(-4/3)\n\nthen you can simplify how you like from there
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.
750604
As Stuart has said above, you need to use the product rule to work this out.  The product rule states:\n\nthe derivative of f(x)g(x) is f(x)g'(x) + f'(x)g(x)\n\nSo, when you differentiate sinx wrtx you get cos and when you differentiate 2x wrtx you get 2.  Plugging these into the formula above you get:\n\n(f(x)g(x))'=2x(cosx)+2(sinx)\n                =2xcosx + 2sinx\n\nHope that this is helpful!
744903
1)\n\ntan^2(x) = sec^2(x) - 1\n\nSo the integral of sec^2(x) + 4 = tan(x) + 4x\n\n2)\n\ncsc(x) = 1/sin(x)\n\nthe integral is then of 1+sin(x)/cos^2(x).\nlet u = cos(x) then du = -sinx dx.\nso the integral is x+sec(x).\n\n3)\n\nlet u = cos(2x+1) then du = -(1/2)sin(2x+1) dx.\n\nso the integral is of -(1/2)/u^2 = 2/u = (1/2)/cos(2x+1) = sec(2x+1)/2\n\nSteve
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
859250
integral = x*tan(x)+ln(sec(x))  (use integration by parts with du = sec^2(x) and v = x).\n\ng'(x) = f(x), so a, c, e and g are true (b is true if f is continuous)\n\nSteve
659256
I don't understand the question. Can you please type it over so I can understand it? Thanks
60599
This is not an equation.  Its garbage.  Both side of the equation have to equal each other.\n-35=.000075 this does not compute
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
796906
too complicated to type it up, sorry. look up what other ways can sec^2x  be written, and start substituing those in. good luck
1132678
Directions how to do this can be found in the text book.\n\nDo your own homework!
923039
email me, calcu_lust@yahoo.com, i'll write out a nice solution.\n\nEdit: Go to my website, and aforementioned nice solution is typed out as a .pdf for you to download, with all the correct symbols and such:\nhttp://geocities.com/calcu_lust/yahooans.pdf
87883
First write y as a product instead of a quotient:\n\n(2+x)*(2-3x)^(-1)\n\nNow you should be able to do this. \nUse 2+x as your f and (2-3x)^(-1) as your g. \nYou will have to use the chain rule to find g'.