Graphing using Basic shapes and shifting?
819957
Start with a graph of:\nf(x) = x\n\nThat's a straight line going through the origin with a slope of 1.  It should look like a 45 degree angle if you draw it correctly.\n\nNow to transform this to:\nf(x) = | x |\n\nYou have to think of each value smaller than 0.  Rather than -1, for example, you'll have 1.  Rather than -2, you'll have 2, etc.  This is like "mirroring" the graph that is below the x-axis so that it is above the x-axis.\n\nThis results in a "V" shape.  A slope of -1 down to the origin, then a slope of 1 from the origin.\n\nFinally:\nf(x) = | x | - 2\n\nFor every value that results, you now subtract 2.  For example, x = 0, gives -2, rather than 0.  This is true for every point x, making every point y smaller by 2.  It would look like you shifted the whole graph down 2 units.\n\nSo it would be "V" like before, but it would go down at a slope of -1, cross the x-axis at -2, and continue to (0, -2).  Then it would slope up (m=1) through the x-axis at 2 and continue upward.\n\nYou can go to the first link and type 'abs(x) - 2' in the box.  The resulting graph is shown as the 2nd link.
34052
I do not know a preprogrammed utility to do this, but can point you in the direction that you might need to go.  See the reference below for the math and an on-line converter:
727314
From y = x2 to y = x2 - 6 is: shift the graph 6 units 'down'.\nFrom y = x2 to (x + 5)^2 is: shift the graph 5 units 'to the left'.\n\nTh
321282
GIMP (GNU Image Manipulation Program) will let you do that quite nicely. You can find it at http://www.gimp.org
70364
Well, it would depend what graphics toolkit you're using, what operating system, etc. It would probably involve:\n\n1. creating a window\n2. creating a canvas or drawing area\n3. creating all the elements of a clock on the canvas.\n\nThe "hard" part is 3, where you probably have to use trigonometry to turn your circular clock coordinates into the usual cartesian coordinates.
1989
I assume you are talking about vector analysis.  The graphical method would be drawing the vectors head to tail and to scale. and then drawing in the resultant and using your ruler and protractor to measure the displacement and angle.
630158
Since you don't want to subdivide (subdivision with chi-square is perfectly valid BTW) you could try a Tukey's HSD. However if you are doing this by hand it will probably be faster to subdivide.
409326
I haven't used this, but it looks fairly simple (as opposed to the professional mapping products):\n\nhttp://www.smartdraw.com/specials/geography.asp?type=12195&id=12195\n\nGood luck
1153250
I dont know how a Grapher works, but your can first draw 12 edges and then fill them\nAssume one vertice to be the origin and then start drawing the edges in X Y Z co-ordinate axis.\nPlot the following points and join for a solid with sides 3,4,5.\n0,0,0\n3,0,0\n0,4,0\n0,0,5\n0,4,5\n3,4,0\n3,0,5\n3,4,5\n\nYou have 8 vertices. Join to get 12 edges. Your solid is ready.\nYou can substitute your required lengths instead of 3,4,5
298247
Select your data. You have already entered your data, right?\n\nPull down the "insert" menu to "chart". Choose "line", choose the particular line graph you like best. Hold down the sample bar to see if the graph looks the way you expect it to. If you aren't making any changes, you can pretty much click "next" until you get a chance to click "finish".
554451
you can use Microsoft Spread Sheet or Excell add all the data and it will make you all kinds of graphs
953641
I can only say so much because those equations are too long for two in the morning. Not that it matters; I just won't be retyping them. But you certainly need a bunch of random things for this. First, you need a variable -- a char, probably, since you don't care about any input beyond that. I don't know what the compare thing is going to output, but that'll come.\n\nI suggest an array for the old and new charts.\n\nGeez, what's the syntax? int oldchart[11], or something? I'm getting too used to Java. Anyway. Since you're going in increments of 5 from 0 to 50, you'll have a 0, 5, 10, ... 45, 50 -- that is, 11 different speeds, right? So you'll need an array for the old chart and an array for the new chart, both with a size of 11. Do you get where I'm going?\n\nCalculating the chart takes a bit more thinking. We'll ignore the actual process of getting input for the moment and just deal with filling it in. I'll suggest a method, and explain afterwards:\n\nint speed;\nfor(int i = 0; i < 11; i++)\n{\n   speed = i*5;\n   oldchart[i] = <calculate wind chill>;\n}\n\nThe same thing could be applies to the newchart array. The index, i, will go from 0 to 10, matching the indexes of the array, right? Since you're going by increments of 5, the speed for slot i will be i*5. That takes you from 0 to 50.\n\nSo after you pull that off for the old and new, you've got charts saved in the variables. Printing them is kind of similar to what happened above -- you use a loop to output what's in the array, using i*5 for the speed.\n\nNow, granted, you could combine this and the above step so you wouldn't need the arrays at all--you'd just recalculate and print every time. But I find it easier to organize my thoughts by going a way that deals with one issue at a time... It depends on what you prefer at this point.\n\nfor(int i = 0; i < 11; i++)\n{\n   speed = i*5;\n   cout << "Speed: "<< speed << " Wind Chill: " << oldarray[i] << endl;\n}\n\nLet's see...\n\nDisplaying the menu is easy--just use cout << "your menu stuff" << endl;\nInput is a bit stranger, I think. For something like this, just use a cin and check afterwards if it's right. Um, let's see... I'll give this to you in pseudocode--you should be able to work out the actual stuff.\n\nwhile ( the user doesn't want to exit )\n//this is just a logic thing -- if the user is done, then what?\n{\n     take the user's input;\n\n     if the input is 'o' or 'O'\n     {\n          calculate and print the old chart\n     }\n\n     else if the input is 'n' or 'N'\n     {\n          calculate and print the new chart\n     }\n\n     else if the input is 'c' or 'C'\n     {\n          calculate and print both the old and new charts (?) (whatever compare does)\n     }\n\n     else if the user wants to exit\n     {\n          end the program (usu. with return 0 or something of that nature)\n     }\n\n     else the user's input was bad\n}\n\nMind that for this to go well, you'd have to mind a few issues -- as I wrote above, if the user doesn't enter what you expect them to. Also, you'd have to deal with a case where the user decided to print charts before entering data into the old or new charts. For that, you should give the temperature a default value, like 0, so the charts can still be calculated.\n\nYou can see that I wrote in a calculation for every print, which is what I was saying before with it not being necessary. You could technically use the for loop I gave for printing but just replace the reference to the array with the calculation for the wind chill.\n\n...Don't know if I covered all of it, but I should be getting to bed. ^^;
927797
http://www.pdfpad.com/graphpaper/\n\nGood Luck
775797
http://www.coolmath.com/graphit/
295508
A graphing calculator has very few pixels, so all the graphing calculator has to do is plug in a finite amount of values into the equation and illuminate a finite amount of pixels. The fast custom processor and memory banks make this seem almost instantaneous.\nSimple home computer software graphs curves by evaluating the equation at some finite amount of points, and connecting those points with lines (or simple polygons for surfaces). Professional software such as Mathematica uses more advanced algorithms to render curves and surfaces.
799961
google's sketchup.  It's free and easy to use!
215568
It's called morphing.  There is a software out there called Morpheus that will do it. It should be really easy to find