why we require motor to pump water to overhead tank ? and not for while drawing towards ground floor?
827110
In order to lift the water from ground level (or below) to a certain height it has to be supplied with some energy so that it moves against the gravitational pull of the earths  gravitational force.\n                                 \n                               So here a motor acts as a device which imparts energy to the fluid(water) so that it moves to a certain height.the two  most important pumps used to pump water are centrifugal pump and recipricating pump.in a reciprocating pump there will be  a piston and a cylinder where  in the piston moves inside the cylinder whereas in centrifugal pump there will be an impeller inside  a casing which rotates and inside it and imparts energy to the fluid so that it moves up.the impeller is rotated by connecting it to the motor.hence a pump is required to lift the water.\n\n                       But pump and motor are not required for drawing water because here,the water is moving in the direction of the earths gravitational   pull.here the weight of the fluid and the direction of gravitational pull are in the same direction.so the fluid will fall under its own weight.so a pump is not required.
87578
P = EI (Power equals voltage E times current I)\n\nMany electrical properties can be explained as analogous to water flow.  For example, a transformer "transforms" high voltage and low current into low voltage and high current, keeping the power constant (except for minor losses) at full load.\n\nThis would be equivalent to a high pressure water pump supplying low water flow to the primary winding and taking out high water flow at low pressure from the secondary winding to drive a low pressure water turbine.\n\nYou could represent the transformer core as a hollow square of wood or even thick cardboard.  On one side wrap say ten turns of thin clear plastic tube around the core to represent the primary (first) winding.  On the other side wrap say five turns of larger diameter plastic tube around the core to represent the secondary (second) winding.  Fill the primary tubing with water and red food coloring to represent "hot" high voltage and the secondary tubing with water and blue food coloring to represent "cooler" low voltage.\n\nThe explanation of course is that the high voltage primary winding will have more windings of thin tube (similar to more thinner copper wire windings) because the current will be less than in the secondary winding.\n\nThere will be less windings for the secondary coil using larger tubing because the current will be higher at low pressure.\n\nSupply the secondary tube with a shut off valve (or clip) to represent the fact that there will be no current unless the circuit is open.  In the formula, if current is zero power is also zero (on both sides of the transformer).\n\nYou can represent the pump and turbine with pictures (or drawings) of same but it would not be impossible to rig an actual pump and turbine, just not necessary to "see" what is happening.\n\nThe turbine can use up more and more power until the maximum power of the primary winding is reached but not more.  The magnet of the core will be "saturated at full power."\n\nThe rest is explaining magnetic flux in the core and how it is produced by the primary winding and cuts through the wires of the secondary to produce voltage and current if there is a load.  Each winding of a coil adds to the effect.  A transformer with equal primary and secondary windings would have the same voltage and current under load.  I believe that the phase would shift 180 degrees because of lead/lag.   Good luck.
1028078
With only pipes, no motors or whatever, you are only going to be able to use a siphon system, which will only allow you to lift the water if the eventual destination of the water is BELOW the start point.  A siphon won't lift water from the bottom of a well to the top, but in can lift water from one reservoir, over a wall, to a tank below or something like that.  \n\nAlso, bear in mind that suction of any kind can only raise water about 33 feet.  After that, the weight of the water in the pipe will be too much for the suction.  That's why the pump for a well is located at the bottom of a well, so it pushes the water up rather than pulling the water out from the top.  For this reason, a siphon can't work if it has to lift more than 33 feet.\n\nThere is another possibility - a pump based on a fluidyne Stirling engine.  Here's a link or two, you should be able to find more:\nhttp://www.fieldlines.com/story/2004/12/9/41413/0938\nhttp://www.maxpie.de/Fluidyne.htm  (in German, but has great pitures)
297405
Depends on your application.\n\nPump water from a shallow (less than 20ft)or deep (greater than 20ft) well?\nHow much volume(gpm) and pressure(psi) are you looking for?\nBased on standard house current at 110VAC or off of a car battery(12V) and how long do you plan to have this pump running (few minutes at a time or hr's or day's on end)?\n\nYour question can be simple or a major under taking. \n\nA simple pump, using an old washmachine pump and motor you can come up with a basic pump. This will work on a shallow application, meaning the pump can't draw water from a resavoir being very deep, maybe a few feet. \nA sump pump is also a very shallow well type, works from a jet principle, but can't deliver a lot of pressure 10-15psi for a short period of time.\n\nWater wells which are deep, > 30ft, usually have the pump submerged into the water which then pushes the water out vs drawing the water up.\nSome of the older pumps were of a piston design, inefficient compared todays jet pump standards.\n\nOtherwise an electric moter and a mechanical pump.
132657
You may need to change the foundation for the new motor to correct its height so that the pump and motor shaft centerlines are correct.  You will need a flexible coupling that accomodates different sized pump and motor shafts.  The speed and power rating of the new motor should be consistent with the needs of the pump.
2627
I could suggest several considerations.  First P=IE, that is Power equals the electrical current (I in Amperes) times the voltage (E in volts).  Current is like the flow of water in a pipe and voltage is like the pressure causing the water to flow.  If you use the water to drive a hydraulic piston (say to hoist an automobile for repair) you can use either a small piston and high pressure or a larger piston and lower pressure.  Which is more cost effective?\n\nIn the United States, electric power is delivered to neighborhoods using three wires (three phases) strung along telephone (power) poles.  Only two of the wires are led to a single residence but the neighborhood must use all three wires to balance load on the wires.  Within a house electricity passes from only one wire (phase) to ground or earth to light a lightbulb which uses 110 volts.  The clothes dryer that needs far more power is connected between two of the supply wires (two phase) and to ground to supply 220 volts.  A machine shop might connect a very large motor to all three supply wires to obtain even more power at 440 volts.\n\nSix volts or even 12 volts DC in an automobile circuit can be touched with little danger.  It is less dangerous to accidentally touch a 110 volt AC wire than a 220 volt source and 440 volts is most dangerous.\n\nTherefore, the selection of voltage depends in part on safety and then on the size of the job to be tackled and also economic factors.  The higher the required current, the larger the required wires using expensive copper.  Increasing the voltage reduces the needed current and reduces the needed copper to do a given job.  The higher the required voltage, the more expensive the required electrical insulation will be.  Engineers must determine the best trade off of many factors.
234860
See the fig in the web site. Instead of lifting the load through a vertical height 'h' we are moving the load through a longer distace 'l' along the plane.\nIn any machine work will be the same.\nWork is the product of force and distance.\nIf the load is moved vertically we would have done a work Wxh.\nBut in inclined plane we move the effort P through a distance l . Work done is Pxl\n But P x l = W x h \nSince l is greater than h, P is less than w.\nTherefore \nAn inclined plane reduces the effort force by increasing the distance through which the force is applied\n\nIn your choise the second and fourth answer is  wrong\nas  no  (ideal) machine can increase or reduce our work. In an inclined plane effort distance (length of the plane) is more than the height. Therefore the first one is correct.
379326
wells u can do without electricity but water i dont think can do with out without electricity do the things the hard way without water probably die...
114610
i agree with an intermediate tank , also u can use multistage centrifugal pump , with pipes greater at least one size specially for suction , ur hight is not critical , we can go to 250 m .
68500
Answer to the first part of thequestion;  \n\nConsider a water tank full of water.We connect a pump which pumps the water from the tank and delivers it again to the tank. \n The tank will never be empty and the water will be flowing continuously along the pipe connected to the pump and tank.\nIf the pipe connecting the pump and tank has an obstacle say a solid block of wood  which is somehow inserted into the pipe, then there will not be flow of water. But still the pipe and tank will have water but with out  any flow. \n Similarly in an electrical circuit electrons are like water in the tank ;the wire is like the pipe; the battery or cell or generator of electicity is like the pump in our example.\n Electrons flow from one end(tank) of the battery(pump) to the other end (tank) through the wire like water through the pipe.\n If one end of a wire is connected to the battery and the other end is left free,we have to imagine that the free end is further connected to the battery by an imaginary wire made of air.( The only matter that connects the free end to the battey is air) Just like water cannot flow through the wooden obstacle electrons cannot flow through air. Though the wire is full of electrons there will not be any flow of  electrons. \n\nAnswer to the second question,'Y dont they fall when they reach the end.\n\nThe wire is full of electrons even if there is no flow. We shall lift one end of the wire and let  the other end loose. It is natural to expect all the electrons in the wire to fall down due to gravity. But the electostatic force beeing very much stronger than the gravitational force keeps them within the wire. To remove them out we must apply a force atleast equal to the electostatic force. The function of the battery, in fact ,is  to provide such a force.
1055447
i no somebody who uses the motor out of an old washer and has water constantly pouring through it to use on his pond. all he does is turn it on to start with to get it going and let gravity do the rest.
970609
Hi. Usually to minimize pressure variations in a home's water system. Fire extinguishers, aerosol cans, Coleman stoves, etc. all use them to store potential energy.
3535
well, (heh),\n\nlifting a mass m of anything a height h against the force of gravity requires an amount of energy that is equal to E = mgh, where g is the acceleration of gravity - 9.8 m/s^2.  \n\nthe power comes from dividing by how long it takes to do this - power is energy / time.  so P = mgh/t.  that means the pump requires that much power to do so.\n\nso, if you decrease h in the above equation, the power goes down.  it is a linear relationship, so if you halve the height over which you are pumping, you halve the amount of power required.\n\nnote that this ignores the frictional nature of water, which is reasonable if the water is not moving very fast in the pump or pipes.  if it is, you have a more complicated problem.
489429
One which is not interrupted. This can be done with a reserve tank, for example, as in an "air hose". It can deliver a constant supply of air, from the reserve and then ,as the pressure begins to dissipate, the pump comes back on, keeping the supply constant. The pressure in the tank is maintained at a higher level than at the "regulated" out put.
1033172
Good Morning!  I saw your question and had to try this one.  A few years back I worked for Stanley Hydraulic Tools and the discharge pumps we sold we centrifugal pumps as well.   These pumps as yours are designed to move large volume not pressure. Closing the discharge side off should not damage the pump.....housing or impeller.  We had a hydraulic motor that spun the pump/impeller.  The hydraulic motor was constantly bathed in oil and even in a stall or a closed discharge valve situation the pump was protected.  I would encourage you to find out who the manufacturer of your pump assembly is and make this question out directly to them but I hope this in its self helps!  Hyway.
36968
Electric distribution uses the ground as a return leg of the circuit.  The voltage in your house, or in overhead lines, is held at a voltage above ground.  So you are completing a circuit.
1032050
You said the pipeline (suction or discharge?) was choking but did not say the pump was trouble. So why go to a gravity fed system? I would guess the pipes would continue to choke. The velocity might even be less in the gravity system and that could agravate the problem