-3+l-10l=7..............          true or false?
820094
true ... the I-10I is always 10...as it is a modulus...so 10 - 3 = 7
285303
If you mean mg/100mL, then it should be the same thing, since 1 dL = 100 mL\n\nIf you mean mg/mL, then:\nMultiply through by ratios to cancel the units:\n\n[ ] mg/dL * [10 dL / 1 L] * [1 L / 1000 mL]=
2520
B\n-7-3=10\n-7+3=-4\n\ni dont know why everyone's giving you such complicated answers, ive taken plenty of algebra and calculus and you certainly don't need any of that for this... you just subtract and then add the two numbers from each choice in your head and see which ones give you what they're looking for...  start with adding up all the numbers, its easier, plus, choice b is the only one where the numbers even add to -4
810076
11^(0.35+7) = 3 this is a contradiction\n\nx=3 is a solution but the rest is just a mess.\n\nDo you have any idea of what you are doing?
723713
- 8 < √40 < - 7\n\n-8 < √4 √10 < - 7\n\n-8 < 2 √10 < - 7\n\n-8 < 2 x 3.16227766 < - 7\n\n- 8 < 6.32455532 < - 7\n\nThis above  statement is FALSE\n\n- - - - - - - - - - - - - - - - - - - - - \n\n9 < √ 51 < 10\n\n9  < √1 √50 < 10\n\n9 < √1  √2 √25 < 10\n\n9 <  1 x 1,414213562 x 5 < 10\n\n9 < 7.071067812 < 10 \n\nThe above statement is  FALSE\n\n- - - - - -S-
904593
.. |10 - 4x|\n---------------- > 3\n|x² - 7x +10| \n\nSo \n\nNow |10 - 4x| = 10 - 4x for 10 - 4x ≥ 0 ie x ≤ 2.5\nand = -(10 - 4x) for 10 - 4x < 0 ie x > 2.5\n\nAlso 3|x² - 7x +10| = 3(x² - 7x +10)  for x² - 7x +10 ≥ 0 ie x ≤ 2 and x ≥ 5\nand = -3(x² - 7x +10) for x² - 7x +10 < 0 ie 2 < x < 5\n\nFind points of intertsection:\n\nWhen x < 2\n10 - 4x = 3(x² - 7x +10)\n3x² - 17x +20 = 0\n(x - 4)(3x - 5) = 0\nOnly solution in domain is x = 5/3\n\nWhen 2 < x ≤ 2.5\n10 - 4x = -3(x² - 7x +10)\nSo 3x² - 25x + 40 = 0\nx = (25 ± √(625 - 480)/6\nOnly solution in domain is x = (25 - √(145))/6 (≈ 2.160)\n\nWhen 2.5 ≤ x < 5\n4x - 10 = -3(x² - 7x +10)\nSo 3x² - 17x +20 = 0\n(x - 4)(3x - 5) = 0\nOnly solution in the domain is x = 4\n\nWhen x > 5\n4x - 10 = 3(x² - 7x +10)\nSo3x² - 25x + 40 = 0\nx = (25 ± √(625 - 480)/6\nOnly solution in domain is x = (25 + √(145))/6 (≈ 6.174)\n\nSo \n.. |10 - 4x|\n---------------- > 3 occurs when |10 - 4x| > 3|x² - 7x +10|\n|x² - 7x +10|\n\nand this is when 5/3 < x < (25 - √(145))/6 \nand when 4 < x < (25 + √(145))/6\n\nWHHHOOOOOOOOPPPSSS YESSSSSSSSSSSSS asymptotes!! at 2 and 5!! so x cannot be 2 or 5\n\n5/3 < x < 2, 2 < x < (25 - √(145))/6, 4 < x < 5, 5 < x < (25 + √(145))/6 (although you can always argue that any number > -∞ and ignore the discontinuities)
45380
its simple ... 80*70*60 ... 10*0 = 0 !!\n\nright isnt it ??? :D
184988
One correction to Duane G's response. When you multiply the bottom by sqrt(3) you get sqrt(3) * sqrt(3) = 3, not 1. Therefore your final answer would be 2 * sqrt(6).
554677
-4 F\n\nReason:\n10 - 14 = -4
333624
(ln x)^7=(7*(lnx)^6)*(1/x)=7*(lnx)^6/x
784373
So long as the absolute value of the sum total of the 2 negative numbers is greater than the absolute value of the sum of the 2 positive numbers the answer should be negative.\n\nExample:\n    (-4)+(-3)+(+2)+(+1)=(-4)\nAbsolute value of (-4)+(-3)= |7|\nAbsolute value of (+2)+(+1)=|3|\n7>3 and 7 is negative so the answer is -4
1082282
B- = 2.7\nB = 3.0\nso its somewhere between B and B-
270378
-12 and 10 are both correct since\n\n-12 + 1 = -11 and | -11 | is 11\n\n10 + 1 = 11 and | 11 | is 11
168190
If you were to have the equations just as they are then 5x-3y would equal 7 not 13.  And 4x-3y would equal 5 not 11.  So try putting in -1 as y, then it will work out as you have it originally written.
481898
1dL = 10cL\n53dL = 530cL
949876
2e^(7-3x) = - 20\n\nDivide both sides by 2:\n\ne^(7-3x) = - 10\n\nTake the natural log of both sides:\n\nln e^(7-3x) = ln (- 10)\n\nAt this point you can say game over, undefined, because you can't take the log of a negative number.\n\nThere is no more work you can do.\n\nYou might want to be familiar with the graph of a basic log curve. If you look at the domain, you see that x values must be positive. Just for fun, let's pretend that your problem read (change to a positive 20):\n\n2e^(7-3x) =  20\n\nStill do the same as above, divide by 2:\n\ne^(7-3x) =  10\n\nThen take the natural log of both sides:\n\nln e^(7-3x) =  ln (10)\n\nln of e will just give you whatever exponent is there:\n\nso:\n\n7 - 3x = ln (10)\n\nA little algebra (subtract 7 from both sides):\n\n-3x = ln (10) - 7\n\nDivide by -3:\n\nx = [ln (10) - 7] / -3\n\nUsing logs is kind of abstract, but all you need to realize is that logs are just exponents, with many of the same properties. Practice makes perfect. Try more problems from the book, do them until you feel good about them!
624130
Shiv, you've got the answer wrong. When inserting y, you forgot the 2 in 10x+2y=7.\n\nJust ashu is also wrong, when you substract 10x from 10x (10x-10x) it become 0 not x.\n\nThe Correct answer is these two equations are unrelated, why? Since if you plot these 2 line equations, they will be paralel to each other. Proof of paralelness?\n\n10x + 2y = 7\n2y = -10x + 7\ny = -5x + 7\n\nit's gradient is -5, same as y = -5x + 3. Both of them has gradient -5 so they are paralel to each other. \n\nIf the lines is paralel, that means the lines don't intersect, so there is no cases where both x1 = x2 AND y1 = y2.