what would happen if the moon had a greater centripetal force than the earth?
817352
It shouldn't have no impact on the earth.\n\nGravity is all that keeps us pulled together and it is only dependandt on MASS. If the moon's mass is constant (which I believe it is) it will not matter if it spins 100 times faster, or just halts on it's axis.
371595
approx 19 miles/second.\n\nAny force from centripetal acceleration you might feel would be more than compensated by the gravitational attractions from the Sun and Earth themselves.\n\nIt might be a measureable amount, but just barely.
856254
The attractive force of the "magnet earth" is much smaller than it's gravitational force. In fact it's negligibly small. Proof: put an iron object on the table, like a knife. Despite it being much more closer to the earth than the moon, it will not budge.
1027284
because the sun's gravitational pull is much greater than the earth's...same reason the moon goes around the earth and not the other way around
1069387
Yes, they would weigh a little more at the poles.\n\nThe Earth is not exactly spherical but rather is a little bit like a "squashed" sphere, with the radius at the equator slightly larger than the radius at the poles (this shape can be explained by the effect of centripetal acceleration on the material that makes up the Earth, exactly as described above). This has the effect of slightly increasing your weight at the poles (since you are close to the centre of the Earth and the gravitational force depends on distance) and slightly decreasing it at the equator.
901606
It spins roughly at the speed it orbits earth. I believe there is a slight "wobble" in the spin which enables astronomers to see about 3/4 of the moon over time. \nIf it spun at the same speed as the earth, the spin would have no effect on earth, but it would cause the moon to get hot inside because of the tidal effect. \nThe tidal effect acts like a brake.
1028524
The force would be 1/4 what it is now (since gravity follows an inverse-square of distance law). As it is, moon's gravity has next to no effect on our weight on earth, so weight change would be unnoticable. The main effect would be on the tides. Rather than being the primary determinant of tide height, as it is now, the moon would be a secondary influence and the sun would be the primary. This would reduce tidal heights by (very roughly) one half.
196388
Neither.  Considering there is still a WHOLE lot of gravity on the moon compared to other places, it would most likely stay on the ground, but it would not get absorbed.  The pull of Earth would keep it there on the surface.  It could freeze or boil, depending on the time you are on the moon and where you are on it.
537473
There is something to this.  The net angular momentum of the Earth-Moon system is such that it is fairly stable to the small torques introduced by other planets.  For instance, the orientation of Mars' rotational axis is believed to have changed dramatically over time.  This is shown with numerical models. \n\nThe moon is moving farther away from the earth.  Angular momentum  is transfered by tides.  The tidal bulge of the Earth remains oriented towards the moon.  The earth rotates under this bulge and drags it forward a bit. The gravity of the bulge itself then pulls the moon ahead in its orbit some.  The net effect is the earth's rotation slows, and moon moves to a slightly larger orbit.\n\nAt some point, the Moon's orbital period will be the same length as the Earth's rotational period and the Earth and moon will be tidally locked to one another. \n\nRegardless, the entire system will still have a lot of angular momentum and the Earth will be fairly immune to significant changes to the obliquity of its rotation.
364195
None of us would have to worry about what we going to do the next day because we would all be dead.\n\nWhat would happen if the Earth stopped spinning?\nThe probability for such an event is practically zero in the next few billion years. If the Earth stopped spinning suddenly, the atmosphere would still be in motion with the Earth's original 1100 mile per hour rotation speed at the equator. All of the land masses would be scoured clean of anything not attached to bedrock. This means rocks, topsoil, trees, buildings, your pet dog, and so on, would be swept away into the atmosphere. \n\nIf the process happened gradually over billions of years, the situation would be very different, and it is this possibility which is the most likely as the constant torquing of the Sun and Moon upon the Earth finally reaches it's conclusion. If the rotation period slowed to 1 rotation every 365 days a condition called 'sun synchronous', every spot in the Earth would have permanent daytime or nighttime all year long. This is similar to the situation on the Moon where for 2 weeks the front-side is illuminated by the Sun, and for 2 weeks the back side is illuminated. This situation for the Earth is not the condition of 'stopped' rotation, but it is as close as the laws of physics will let the Earth get. \n\n \n\nIf it stopped spinning completely...not even once every 365 days, you would get 1/2 year daylight and 1/2 year nightime. During daytime for 6 months, the surface temperature would depend on your latitude, being far hotter that it is now at the equator than at the poles where the light rays are more slanted and heating efficiency is lower. This long-term temperature gradient would alter the atmospheric wind circulation pattern so that the air would move from the equator to the poles rather than in wind systems parallel to the equator like they are now. The yearly change in the Sun's position in the sky would now be just its seasonal motion up and down the sky towards the south due to the orbit of the Earth and its axial tilt. As you moved along constant lines of Earth latitude, you would see the elevation of the Sun increase or decrease in the sky just as we now see the elevation of the Sun change from a single point on the Earth due to the Earth's daily rotation. \n\nFor example, if you were at a latitude of +24 degrees North in the Summer and at a longitude where the Sun was exactly overhead, it would slide gradually to the horizon as Fall approached, but since the Sun has moved 90 degrees in its orbit, it would now be due west. Then as we approach Winter, you would now be located on the dark side of the Earth, and would have to travel in longitude to a location 180 degrees around the Earth to see the Sun 1/2 way up the sky because in the Winter, the Sun is 48 degrees south of its summer location in the sky. It's a little confusing, but if you use a globe of the Earth and orient it the right way, you can see how all this works out. \n\nAs for other effects, presumably the magnetic field of the Earth is generated by a dynamo effect that involves its rotation. If the Earth stopped rotating, it's magnetic field would no longer be regenerated and it would decay away to some low, residual value due to the very small component which is 'fossilized' in its iron-rich rocks. There would be no more 'northern lights' and the Van Allen radiation belts would probably vanish, as would our protection from cosmic rays and other high-energy particles. This is a significant biohazard.
410440
Assuming life on earth still existed and that water\ncould still be found (not all frozen), the tides \nwould be smaller, because the Moon influences the\ntides about 90% but the other 10% influence comes\nfrom the Sun's gravitational force... That's why\nthe tides are higher at New Moon and Full Moon, \nbecause both the Moon and Sun are pulling along\nthe same line, whereas at first quarter and last\nquarter Moon, the tides are relatively lower, \nsince the Sun and Moon's gravitation somewhat\ncancells each other out
830124
Nothin would happen.\nIf you consider two bodies the earth (name it E) and a large mass (m). \ninitially M rests on E. and you lift mass M. the force used to lift it will also act on E.\nAlso if you consider the mass M and E. as a system force exerted on dropping M would be internal and since internal forces do not cause acc. the Earth will not get unbalanced.\n\nThats good for us isn't it...
1104955
due to a transfer of Earth's rotational momentum to the Moon's orbital momentum as tidal friction slows the Earth's rotation. That increase in the Moon's speed is causing it to slowly recede from Earth (about 4 cm per year), increasing its orbital period and the length of a month as well. \nTo picture what is happening, imagine yourself riding a bicycle on a track built around a Merry-go-Round. You are riding in the same direction that it is turning. If you have a lasso and rope one of the horses, you would gain speed and the Merry-Go-Round would lose some. In this analogy, you and your bike represent the Moon, the Merry-Go-Round is the rotating Earth, and your lasso is gravity. In orbital mechanics, a gain in speed results in a higher orbit. \n\nThe slowing rotation of the Earth results in a longer day as well as a longer month. Once the length of a day equals the length of a month, the tidal friction mechanism will cease. (ie. Once your speed on the track matches the speed of the horses, you can't gain any more speed with your lasso trick.) That's been projected to happen once the day and month both equal about 47 (current) days, billions of years in the future. If the Earth and Moon still exist, the Moon's distance will have increased to about 135% of its current value. \n\nThe tides, chiefly caused by the Moon's gravitational attraction and the orbiting of Earth and Moon about a common point, act as a brake to slow down the earth's rotation. The nearer tidal bulge, which carries the greater effect, runs slightly out of alignment of the Moon overhead; the gravitational interaction between it and the Moon serves to speed up the Moon in its orbit even as it slows down the earth's rotation. As it speeds up, the Moon moves to a higher orbit. \n\nThe effectiveness of this tidal brake on the earth's rotation strongly depends on the configuration of the oceans. Thus, we should inquire as to whether the current arrangement is an average value or not. \n\nThe present rate of tidal dissipation is anomalously high because the tidal force is close to a resonance in the response function of the oceans; a more realistic calculation shows that dissipation must have been much smaller in the past and that 4.5 billion years ago the moon was well outside the Roche limit, at a distance of at least thirtyeight earth radii
150657
gravity is highest at the centre of the earth. so you will be accelerating towards the centre.since there is no resistence (assume so that there is no air), you would not stop at the centre due to inertia of motion and continue to go beyond the centre to teh other side. but due to increasing pull on you, you will turn back and continue to oscillate about the center of the earth.\n\nits good for theory but humanly imposible
364601
If that direction were opposite the direction of the \nearth's rotation, I think the answer is theoretically yes.\nIn reality there's not enough mass of people relative to the mass of the earth to have any effect.
422733
yes it would affect the earth because it would disrupt our tides and all of our weather would either become very extreme or nonexistent also we wouldn't have a moon for any one else to visit and then we wouldn't be able to go to anywhere but the earth .
1040803
Explain how a 600 yard wide rock could cause the 2,160 mile wide Moon to wobble, without touching it? It'd be like throwing a golf ball at a bus and expecting it to tip it over....\n\nIt doesn't matter what the moon does as far as wobbling and spinning, it's gravity isnt affected (unless it breaks up) and therefore the end result means zip to us. We may just get to see the far side!