does 1+1 always equal 2?
820084
Steve G has the best answer so far.\n\nThe answer is "not necessarily".\n\nIn binary (ie base 2) 1+1 = 10\n\nHowever in binary 10 represents two, so although you don't write it with a '2' symbol it still means two units of something.  But if your computer counter was very small and could only deal with a single bit, then 1+1 would show up as 0.\n\nIn real world conditions (ie away from the special rules of mathematics) think about what happens when two rain drops meet.  You might think of that as 1+1 but you still have 1 (heavier) raindrop.\n\nThe point is that addition always works the same way in mathematics and 1 + 1 will always result in value 2 however it may be written in different ways.  BUT mathematical addition may not accurately reflect events in the real world that look like addition.\n\nAnother example would be putting two elementary particles in a container.  If the particles happen to be a positron and an electron, then you end up with ZERO elementary particles and a burst of energy.
5316
If it were plus, instead of times, the answer would be 1.\nAs it is, I don't recognize it.  Perhaps my math is a bit rusty...
357910
hello!!!!!!!!!! \n1+1 in binary is 10! it's not ten but one zero!!!
817933
2 + 1 = 3\n4 + 1 = 5\nTake the numerals out of the two equations above which are in the next equation 2+2=5.\nWe will get 2 & 5.Now take out the nos. which are similar in both the equations.now we will have 1,1,2,5.As we have 3 numerals in the final equation we will add up the smallest digits 1+1.Then we will have 2,2,5which also means 2+2=5.\n2+2=5 is equal to 2+1+3and 4+1+5\nA little confusing.\nI hope u understand.
685311
1=1\n2=2\n3=6\n\nYou are multiplying the last number of a line with the first number of the second line and writing it beside it. Its the same thing we do in cumulative addition.\n\n1-1\n2-2*1=2\n3-2*3=6\n\nThats how you get it.
619527
1st step: try for n = 1\n\nThen 1*2^1 = 2 and\n(1-1)*2^(1+1)+2 = 2\n\n2nd step: Assume true for n, show true for n+1.\n\nThen sum(i=1 to n) = (n-1)*2^(n+1)+2\nThen for n+1:\n\n(n-1)*2^(n+1)+2 + (n+1)2^(n+1)\n= (n-1 + n+1)2^(n+1)+2\n= 2n2^(n+1)+2\n= n2^(n+2)+2\n= ((n+1) - 1)*2^((n+1)+1) + 2\n\nThus it works.
328795
1 + 1 = whatever you want to make.
115335
4.\n\nThink about it... 1+1+1+1= 4\n1+1=2\n1+1+1= 3\n1+1+1+1=....4\nHence:\n\n1+1+1+1= 4\n\nor:\n\n3+1= 4\nand\n4+0= 4
166763
1+1=2 is an axiom - something that we consider being true without proving it.
1138309
I hope you are trying to say x+2 = (2/3)(2x-1)..if it is correct then\n\n3(x+2) = 2(2x-1) --> 3x+6 = 4x - 2 --> 6+2 = 4x-3x --> 8 = x
121013
if it is in binary, 1 + 1 = 10
759105
False... y has to be 2...\n(3,2) is a solution, but not (3,1).
531205
2 + 2 = 4\n\nthats all I got
1023705
2 + 2 / 2 =\n2 + 1 = 3
1019179
Yes, negative x positive always equals negative.  \n        negative x negative always equals negative\n        positive x positive always equals positive
924405
Is it possible to have 2 equal signs in a problem?\nI am only in algebra but I haven't seen one like that before.\nSorry I couldn't help.
496228
1 + 1 = 2 ... traditional addition\n\n1 + 1 = 10 ... addition, but in binary\n\n1 + 1 = 1 ... boolean algebra\n\n1 + 1 = 11 ... Concatenation; although, it's usually with strings rather than numbers.