Help with a math question....?
815927
You just asked this, and I just answered it.  :)\n\nThe answer is 72.\n\nClick link to see this problem solved.
662213
Anyone can give you the answer, but try here next time you need help with conversion or any other kind of math: \n\n\nhttp://www.gateways2learning.com/BasicMath/BasicMath.htm\n\nGood luck..................
939267
Let x = "one number". \nThen, the "another number" is 2x.\n\nWhen the larger number is decreased by 10,\n\n2x - 10\n\nThe result is 2 greater than the smaller number\n\nx + 2\n\nTherefore,\n\n2x - 10 = x + 2, and\nx = 12.\n\nSo the two numbers are x and 2x, or 12 and 24.\n\nLet's put it back into the problem.\n\nOne number is twice another.  24 is twice 12.\nWhen the larger number is decreased by 10 (24 - 10 = 14), the result is 2 greater than the smaller number (2+12 = 14).  Therefore that's the answer!\n\nHappy solving!
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.
422460
please explain this question.
347406
Dude, so simple.\n\nYou need to find a # that is the lowest multiple of both 3 and 2.\n\nSo 1/2 + 1/3 changes to X/6 + X/6\n\nTo find out the top # you do the same thing that you did w/ the bottom #\n\n1 x 3   1 x 2     3     2      5\n----- + -----  = --- + ---  = ---\n2 x 3   3 x 2     6     6      6\n\nHay, if I help som 1 cheet, than I show them how to the problem, ok?\n\nJackmac :P~
290027
9 - 48m^2 or 9(1-4m^2)\nthe 1 before the second set can be dropped, it's implied. Read it like this:\n(3*3)-(3(4m*4m))\n(9) - (3*16m^2)\n9-48m^2\nThen divide it all by the common 9\n9(1-4m^2) : That's your answer
320882
1 2 3 4 5 6 7 8\n<---[======)--->
520168
Try this:\n\nhttp://www.algebra.com/
984538
(2/6) / (4/9)\n1/3 * 9/4\n3/4
900166
-0.86602540378443864676372317075294
723713
- 8 < √40 < - 7\n\n-8 < √4 √10 < - 7\n\n-8 < 2 √10 < - 7\n\n-8 < 2 x 3.16227766 < - 7\n\n- 8 < 6.32455532 < - 7\n\nThis above  statement is FALSE\n\n- - - - - - - - - - - - - - - - - - - - - \n\n9 < √ 51 < 10\n\n9  < √1 √50 < 10\n\n9 < √1  √2 √25 < 10\n\n9 <  1 x 1,414213562 x 5 < 10\n\n9 < 7.071067812 < 10 \n\nThe above statement is  FALSE\n\n- - - - - -S-
708585
What sort of help do you need with fractions? It depends. Or you can try math.com\n\nYou have to look a little to actually find what youre looking for, but mostly its good \n\nHope this helps!  :)
950092
Do a Yahoo search.  Enter "Homework help, math."  There are bunches of web sites.  Good luck.
957682
half it then times it by 2! that will give u the answer
538044
hmmm...very tough one!\n\nill sovle by the formula!\n       _________\n-b +- V (b^2)-4ab\n------------------\n       2a\n       _________\n-10 +-V 100+512\n------------------\n       2\n\n       _________\n-10 +-V 612\n------------------\n       2\n\n-10 +- 24.7\n------------\n     2\n\n14.7/2\n\n34.7/2\n\n(7.35, 17.35)
909352
This question has been asked so many times!?!?!\n\nGood challenge question!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nSomeone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8