Factor x(squared) + 18x + 80?
813994
the first one is (x+10)(x+8)\nand the second one is your second answer
92952
(8x+3)(4x+3)\n32x2+24x+24x+9\n32x2+48x+9
254834
if you use quadratic formula you get the factors of \n\nx= ( ( 3 +/- square rt.(5) ) / -6 )
418401
While looking for easier ways to do things with factors, I realized there might be a commonality between the left side and the right side.\n\nfactor a 2 out of the left side...\n2(17x-3.8) = (17x-3.8)(x+12.5)\n\ndivide both sides by (17x-3.8)...\n2 = x+12.5\n\nsubtract 12.5 from both sides...\n-10.5 = x\n\nAnd there you have it.  x = -10.5\n\n\nAnother possible approach would have been to do what the second answerer suggested, but use "completing the square" instead of the quadratic formula.
283601
1) First we move all the factors with x to one side, and the ones without x to the other.  Result will be:\n\n4x/3 - 2x + x = 3/2 + 1/5\n\n2)  Then, we factor out an x from the left side and get:\n\nx(4/3 - 2 + 1) = 3/2 + 1/5\n\n3)  Calculate the actual numbers on both sides\n\nx(4/3 - 6/3 + 3/3) = 15/10 + 2/10\nx(1/3) = 17/10\n\n4)  Divide both sides by 1/3 and get a final result of...\n\nx = (17/10)/(1/3)\nx = (10/17)*(3/1)\nx = 30/17\n\n5)  Comform that I PWN n00bs.  And... I'm pretty sure I pwn n00bs.  Therefor, we are done!  ^-^
779020
Just a number. Also, the answer is 3, not 37. You just have to substitute -1/3 where there is an x in the original.\n\nf(x) = 18x(squared) - 12x - 3\nf(-1/3) = 18 * (-1/3)^2 - 12 * ( -1/3) - 3\n                    18 * 1/9     + 4            - 3\n                             2 + 4 -3\n                                  3
846702
-x + 2y = 18\n x + 8y = -38\n\nadd up these two lines\n\n0x+ 10y = -20\ny= -20/10 = -2\n\nx + 8(-2) = -38\nx - 16 = -38\n\n\nx=-22\ny=-2
825488
18:30 = 24 : x\nx(18) = (30)(24)\nx = [(30)(24)]/18\nx = 720/18\nx = 40
1177677
shouldn't it be x^2??? if it IS x-squared, then sure, you could use the factorization method. \n\nit goes like this:  (6x + 1) (x - 1) = 0\n\ntherefore, x = -1/6 , 1
863644
take out 4x first\n4x(x2-6x+8)\n4x(x-4)(x-2)
922587
ok\nf(x) = 20 - x\nf(0) = 20 - 0 = 20\nf(2) = 20 - 2 = 18\nf(4) = 20 - 4 = 16\nf(8) = 20 - 8 = 12
225790
Well the answer is 1.5 but you should try working it out for yourself to try and get this answer and you probably need to show your working anyway.\n\nUse this quadratic formula (in the box)\n\nhttp://www.sosmath.com/algebra/factor/fac08/fac08.html
738486
8w-18 = 12w +14\n    +18           +18    add 18 on both sides\n\n    8w=12w + 32\n-12w   -12w          subtract 12w on both sides\n\n  -4w=32             solve for w\n   /-4    /-4\n\n   w= -8
438560
__5 _ , x____\n9 – x2 6x+ 18\nI'll take a shot at what I think you are asking.  Is it write each of these two fractions: 5 over 9 minus x squared, and x over 6x + 18?\n\nIf so, factor each denominator: (I'll use x^2 for x squared)\n9-x^2 = (3+x)(3-x)\n6x+18 = 6(x+3)\n\nNote: x+3 = 3+x, so...\n\nThey share a factor of (x+3) so the LCD is 6(x+3)(3-x)\n\nFirst fraction missing 6, so multiply top & bottom by 6\nSecond is missing (3-x) so multiply top & bottom by (3-x)\n\nFirst: 30 over (6(x+3)(3-x))\nSecond: (3x-x^2) over (6(x+3)(3-x))
310788
You need to factor everything, then cancel common factors.\n4x+8 factors as 4(x+2)\n6x-3x^2 factors as 3(2-x)\n3x^2-4x-4 factors as (3x+2)(x-2)\n9x^2-4 factors as (3x+2)(3x-2)\n\nCancel the (3x+2)'s, and the (x-2) can cancel with the (2-x) leaving a factor of -1.  The factors that are left are:\n[-4(x+2)]/[3(3x-2)].
928231
8x-10x > -11-1\n\n-2x > -12\n\nx < 6
636732
8x^2y^3+5y^2 when "FACTORED COMPLETELY"=\n\ny^2 (8yx^2+5). \n\nThis should be right. My dad is a complete genius and he did this in like 2 seconds. I double checked it on my calculator too by plugging in numbers, so I can assure you he's right.\n\nHope this helps! Have a nice day :)