solution for the Emperical formula...Help...?
820191
The empirical formula is derived from the mineral's structural (molecular) formula by using the published analysis of the mineral or deriving the analysis using basic rules.\nAtomic substitutions were analyzed by the following procedure if published analyses were not available. Adjustments were made to match the measured density with the calculated density if needed: \n(K,Na) = K0.75 Na0.25\n\n(K,Na,Cs)= K0.6 Na0.3 Cs0.1 \n\nRare Earth Elements (REE in formulae) were calculated based on the chondrite normalized abundances. This analysis used 144 for the REE atomic weight and 61 as the atomic number. \nSolid solution series minerals were calculated based on the mid-points of the accepted compositional range of the mineral..☺
855052
Come on now, what is the formula for this???  :)\n\n(V1 * T1)/P1  =  (V2 *T2)/P2\n\n(69L * 131)/2.85  = (xL * -37)/2.85\n\nNow, solve for 'x'?  Be sure to watch your units!!!!
603820
Well i cannot write the whole formula here but check the link below
515668
F = (m dot * V)e - (m dot * V)0 + (pe - p0) * Ae
620893
The best way to work this out would be to plot a speed time graph for the information.\n\nOr you could express it as a simultaneous equation.
437730
See http://members.aol.com/logan20/elecspon.html for the equation to use.
429835
ok, u have to use distance formula\n\nsqrt[(-4-(-7))^2+(c-7)^2]=5   \nsquare both sides\n[(-4-(-7))^2+(c-7)^2]=25      \nadd the stuff in the parentesies\n[(-3)^2+(c-7)^2]=25           \nexponents\n9+(c-7)^2=25                  \nsubtract from both sides\n(c-7)^2=16                    \nsquare root both sides\nc-7= +/-4                     \nadd to both sides\nc=11 or c=3
629091
Sorry, but the formulas do not present well here.  Cannot discern operations.
1154468
make a common denominator\n\na/b - c/d = a*d/b*d - c*b/d*b = (a*d-c*b)/b*d
764897
use derivative rule for exponential as\n\nd/dx(A exp(bx))=(A*b)*exp(bx)\n\nyou got hint. No more Spoon Feeding
782406
°oO****Oo°°oO****Oo°°oO****Oo°\n\n\n 4 ∫[g(x)] g'(x) dx = 4 x 1/2g(x)² +c = 2g(x)²+c\n\nits the first suggestion that u made but i think you forgot the number 4...\n\n\n°oO~<<_P~'*'_ I~'*'_M~'*'_O~'*'~L _~'*'_A>>~Oo°
66380
You have to use the formula -\nm1s1(t3-t1)=m2s2(t2-t3)\n=>191(4.184)(30.5-25)=38s2(192-30.5)\n=>s2=191(4.184)(5.5)/((38)(161.5)\n=>s2=0.716 J/g.k
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
603804
apply formula for it\nits easy
741999
whats the equation or formula u need help with?
844758
Using the Michaelis-Menten equation.\n\nMore details on teh attached link\n\nhttp://www.le.ac.uk/by/teach/biochemweb/tutorials/michment2print.html\n\nGood luck
243814
although the equation is not complete and therefore the full answer can not be given. i believe this equation will need to be differentiated using the product of a product rule.