I need help with algebra.?
827005
It's linear alright. x = - 3/7. A little tricky because it's a line parallel to the y axis.
390719
so you have (1/2)a+a-(6/3)=4+(1/3)a\n\nadding like terms: (3/2)a-2=4+(1/3)a\n\nsubtract (1/3)a from (3/2)a and add two to both sides:\n(3/2-1/3)a=4+2\n(9/6-2/6)a=6\n(7/6)a=6\n\nnow solve and what do you get? :)
515516
goto purple math.com it will hopefully help you
561262
u jammed the equation together.\ndo u mean\n6x^3 + ( 6/x - 2 * x^2 - x/3x2 - 3x + 3)\nits really hard to see ur question. can u write it out with spaces...\nhurry up i am waiting... lol
919864
1.  ax + xb\n2.  21x^3 + 24x*2y\n3.  24x^2 + 31x + 10\n4.  24x^2 - 8x - 6\n5.  40x^3 + 66x^2 + 38x + 6\n6.  x^2 - 1\n7.  x^3 - 8
156840
Look up "Algebra Solved 2005" or "algebrator", these two programs not only solve problems, but they give step by step solutions for understanding. they have tutorials and practice test. I went from knowing none to fairly advanced in a few weeks.
1181037
You will find the worksheets at the website of http://www.algebra.com. This website is a free site. You can also pose Maths. questions there and will get answers at the cost of $0 (zero dollar).\n\nI am a free tutor there and you may see my lessons and solutions to problems at\nhttp://www.algebra.com/tutors/aboutme.mpl?userid=psbhowmick\n\nYou will find the worksheets at\nhttp://www.edhelper.com/algebra.htm
895063
Google the word algebra help.  Purple math is great, but there are other sites also.  I am sorry I do not have the names at the moment.
1046507
[2x/(x+3)(x-3)]*[(x-3)/4(x)]\ncancelling 2 and x-3 we will get\n=x/(x+3)2(x)\nsimplify we will get\n=x/(2x^2+6x)
551906
Add each equation\nA + B = 3x^2 + 2x - 2\nA - B = -x^2 + 4x - 8\n2A = 2x^2 + 6x - 10\nDivide each side by 2\nA = x^2 + 3x - 5\nNow plug into one of the original equations to get B\nB = 3x^2 + 2x - 2 - (x^2 + 3x - 5)\nB = 2x^2 - x + 3
837436
Your Algebra teacher is trying to kick your butt, right?  I have the answer:\n\nReorder the terms:\n3+64x+16x^2=0\n\nStart with the 16 - divide all numbers by 16\n\n3/16+64x/16+16x^2/16=0/16\n\nResults are:\n\n.1875+4x+ x^2=0\n\nNot done yet...Next, take out the .1875.\n\n.1875+(-.1875)+4x+x^2=0+.1875\n\nResults from this calculation:\n\n4x+x^2=-.1875\n\nThen, add a 4 into the equation\n\n4+4x+x^2=-.1875+4\n\nAdd like terms:\n\n4+4x+x^2=3.8125\n\nThen, you need to factor the problem out.\n\n(x+2)(x+2)=3.8125\n\nTake the square root of 3.8125\n\n=1.952562419\n\nAfter that, take one of the factors you created above and use the square root to arrive at the answer...one positive, one negative\n\n2 + x = 1.952562419\n\nx = 1.952562419 - 2\n\nx = -.0474437581\n\nand\n\n2 + x = -1.952562419\n\nx = -1.952562419 - 2\n\nx = -3.952562419\n\nx = (-.047437581, -3.952562419)\n\nYou might have to plot that on a graph.  You have just calculated a point of off the x axes...the horizontal line.\n\nHope that helps. Maybe someone can give you fewer steps.
501445
Try this website. http://www.webmath.com/index3.html
80315
If this is an algebra problem, they probably mean x/3 = (x+8)/7\n\nCross multiply to get 7x = 3x + 24 \n\nSubtract 3x from both sides to get 4x = 24\n\nDivide both sides by 4 to get x = 6\n\nCheck:  6/3 = 2; (6+8)/7 = 14/7 = 2
913123
I think you can try this website \nhttp://www.algebra-test.com \nhttp://www.algebraavenue.com\nhttp://www.algebra-online.com/algebra-equation.html \nhttp://www.algebrahelp.com\nhttp://www.algebra-net.com\nhttp://www.algebra-online.com/solve-algebra-equation.html\nhttp://www.algebrahelp.com/lessons/equationbasics/pgw.htm\nhttp://www.algebrasolver.com\nhttp://www.edhelper.com/algebra.htm\nhttp://www.math.com/students/worksheet/algebra_sp.htm
531494
Ask your teacher.\n\nBut usually, you are supposed to simplify.
272295
There's lots of help online. Try these web sites:\n\nhttp://www.algebrahelp.com/\nhttp://www.purplemath.com/\nhttp://www.sosmath.com/algebra/algebra.html\nhttp://www.helpalgebra.com/\n\nThere's even more. So start with these, and good luck!
330568
ask a question! I can help! maybe... yeah, pretty sure I can, I'm in Algebra 2!