How do you figure this on a scientific calculator?
817907
The formula for population growth is P(n) = P(0)*(1+r)^n, where r is the fractional growth per year, n=no of years, P(0) is the starting value.  To solve for r, take log of both sides to get\n\nlog[P(n)] = log[P(0)] +n*log(1+r)\n\nThen log(1+r) = {log[P(n)] - log[P(0)]}/n = log[P(n)/P(0)]/n\n\nRaise both sides to the power of 10\n\n1+r = 10^{log[P(n)/P(0)]/n}\n\nr = 10^{log[P(n)/P(0)]/n} - 1\n\nSo enter P(n), divide by P(0), take log of the quotient.  Divide this by n and take 10 to the power of this result, then subtract 1.
406596
no idea...but I think you use the formula (Gravitational constant x mass 1 x mass 2) / distance squared
619240
u can even use calculus to find this out
212435
I do not have a scientific calculator at the moment, but maybe i can borrow yours ;)
392568
Yes you can. Its not scientific and it is really ugly, but it gets the job done.\n\nTo find it, just go to add content and type in the search box "calculator". You should be able to find it.
840437
Well, I can see that one possible solution is r = 0, and my calculator says the other answer is r = 0.0809394063, so hopefully that helps...
89652
The formula involves complex maths calculations. Ask some maths professor.
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.
412953
An equation that is incorrect.
731527
r=3, h=5, pi=3.14159.\n\nJust plug these into the formula and you're set.
937830
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today
889683
There is, it is called Standarad Deviation, if you have a decent Scientific Calculator it shouyld show how to use it.
955082
I think you just take the numbers and plug them in where the letters are and find your result.  Ie.  every time you see an a in the question, write -2 instead and then work it out...
714084
plug in cos^-1(30/50) in a calculator\nto get cos^-1 just hit 2nd cos
888394
Every time that we move the decimal point to the left, we are dividing a number by 10. we can make up for this by decreasing the power of the exponent by 1.\n\nEvery time that we move the decimal point to the right, we are multiplying a number by 10. we can make up for this by increasing the power of the exponent.\n\n\n.0035 x 10^15 = 3.5 x 10^12\n.002 x 10^17 = 2 x 10^14\n\n7000 x 10^33 = 7 x 10^36\n\nWhen multiplying two scientific notation numbers, like\n\n(a x 10^b) * (c x 10^d)\n\nmultiply a and c, and add b and d. Use the sum as the exponent of the product.\n\nSo:\n\n(3.5 x 10^12) * (2 x 10^14) = 7 x 10^26\n\nNow we can divide.\n\nWhen dividing two scientific notation numbers, like\n\n(a x 10^b) / (c x 10^d)\n\ndivide a by  c, and subtract d from b. Use the difference as the exponent of the product.\n\nSo:\n\n(7 x 10^26) / (7 x 10^36) = 1 x 10^(-10)
197333
i think \nx = 2664.173
737774
You figure the square root of each number separately...you've probably learned that in class alredy (how to do that)...then you take reach result, and multiply them together for your final answer.\n\nUse your textbook for reference...good luck!