what is the answer answer of n-4>10?
818735
This is just like a normal equation with equal sign instead of the >\n\nn-4>10\nso\nn>10+4\nn>14\n\nAs n >14, n must be 15 if n is a interger
793566
10 - 7 = 3\n\ntherefore 3 x 4 (for the 1/4) = 12\n the number is 12
144204
-10\n\nand to prove it -10 x -10 x -10 = -1000
397565
Multiply 5/4 by 4 and you get 5.  Therefore your answer is 4.
214070
If using modulo is permitted,\n\n3 + 7 - (8 % 4)\n= 3 + 7 - 0\n= 10
800297
15(-10) +4x = -x +10(-10)\n5 +4x(-4x)= -x+(-4x)\n5= -5x\nx= -1\n\n4(2x - 6) = x + 2\n8x (-x)- 24= x (-x) + 2\n7x - 24 (+24)= 2(+24)\n7x =26\nx = 3.7\n\n2(x+5) + 1 = 3 (x - 1) + 4\n2x+10 +1=3x-3+4\n2x+11=3x+1\n10=x\n\n- 3n + 12 + n = 22 \n-2n +12 = 22\n-2n= 10\nn= -5
459843
The answer should be 64350/184756 or 34.8%\nIs that what you have?\n\nTo solve this problem you will need a function called "choose", often written as C.\n\n20C10 means "given 20 items, how many possible combinations of 10 are there?".  If there are 20 questions and the teacher chooses 10 of them, then there are 20C10 possible combinations of questions on the test.\n\n20C10 is solved by 20!/[(10!)(20-10)!]\n\nThe solution to the problem is (15C8)*(5C2)/(20C10).\n\nThere are (15C8)*(5C2) possible combinations of 8 (out of the 15) questions that you do know and 2 (out of the 5) questions that you don't know.\n\n"Choose" functions are very long calculations so you should not be expected to do them by hand.  On a TI graphing calculator, use the nCr option under the MATH/PRB menu.
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
904593
.. |10 - 4x|\n---------------- > 3\n|x² - 7x +10| \n\nSo \n\nNow |10 - 4x| = 10 - 4x for 10 - 4x ≥ 0 ie x ≤ 2.5\nand = -(10 - 4x) for 10 - 4x < 0 ie x > 2.5\n\nAlso 3|x² - 7x +10| = 3(x² - 7x +10)  for x² - 7x +10 ≥ 0 ie x ≤ 2 and x ≥ 5\nand = -3(x² - 7x +10) for x² - 7x +10 < 0 ie 2 < x < 5\n\nFind points of intertsection:\n\nWhen x < 2\n10 - 4x = 3(x² - 7x +10)\n3x² - 17x +20 = 0\n(x - 4)(3x - 5) = 0\nOnly solution in domain is x = 5/3\n\nWhen 2 < x ≤ 2.5\n10 - 4x = -3(x² - 7x +10)\nSo 3x² - 25x + 40 = 0\nx = (25 ± √(625 - 480)/6\nOnly solution in domain is x = (25 - √(145))/6 (≈ 2.160)\n\nWhen 2.5 ≤ x < 5\n4x - 10 = -3(x² - 7x +10)\nSo 3x² - 17x +20 = 0\n(x - 4)(3x - 5) = 0\nOnly solution in the domain is x = 4\n\nWhen x > 5\n4x - 10 = 3(x² - 7x +10)\nSo3x² - 25x + 40 = 0\nx = (25 ± √(625 - 480)/6\nOnly solution in domain is x = (25 + √(145))/6 (≈ 6.174)\n\nSo \n.. |10 - 4x|\n---------------- > 3 occurs when |10 - 4x| > 3|x² - 7x +10|\n|x² - 7x +10|\n\nand this is when 5/3 < x < (25 - √(145))/6 \nand when 4 < x < (25 + √(145))/6\n\nWHHHOOOOOOOOPPPSSS YESSSSSSSSSSSSS asymptotes!! at 2 and 5!! so x cannot be 2 or 5\n\n5/3 < x < 2, 2 < x < (25 - √(145))/6, 4 < x < 5, 5 < x < (25 + √(145))/6 (although you can always argue that any number > -∞ and ignore the discontinuities)
391551
1/2(12) + 4 = 6 + 4 = 10
833237
so far, so good\n\nn!/(n-4)! = 56 [n!/(n-2)!] \n\nmultiply both sides by (n-2)!/n!\n\n[n!(n-2)!] / [n!(n-4)!] = 56\n\n(n-2)! / (n-4)! = 56\n\n(n-2)(n-3) = 56\n\nYou could multiply this out and solve the quadratic, in which case you will get one positive and one negative root, or if you remember that 56 = 8*7, then that quickly leads to n = 10
447627
a + 4a where a = 2 ?\n\nif so, then...\n\n2 + (4)2\n\n2 + 8\n\n10\n\nThe answer is 10.
401032
If your asking number mine is 10
474041
The most obvious answer is 6 (as described above).\n\nBut here's another option...\n\nThe correct answer to "10" could be 2.\nIn the case of the password for "eight" being 4, it could be the number of letters in the word "eight" minue one (5-1=4).\nTherefore, the answer to "10" would be 3-1=2.
874116
-7,-10,-13 by putting n= 1 2 and 3
814515
a = 33\n\n- - - - - -\n\na - 13\n\n33 - 13\n\n20\n\nThe answer is 20\n\n- - - - - - - - -s-
1099830
27\n\n(+7 -4 +8 -3 +9 -2 +10)