2 different committees of 5 are to be formed from a group of 10 people.?
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once we chose 5 persons for one committe then other committe members get fixed.\n\nThe 5 members can be chosen in 10C5 ways = 10*9*8*7*6/120\nor 6*7*6 or 252 ways
407874
coming together (No pun intended)
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sharing suggestions,\n\nsharing burdens,\n\ngive and take..\n\nbetween 2 or more parties in the organisation or group ;)
377107
Working together to achieve one common goal.
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Consult "Roberts Rules of Order" the standard for running meetings and committees.  \n\nShould be available at library; some resources at link below:
795663
Jesi has the right answer...\n\nIf there were ten, how would they reach decisions without the possibility of a tie vote? There are nine.
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1) keep "people" the same; balance "minutes" \noperation: solve this proportion\n\nprevious sheets : NEW SHEETS = previous minutes : new minutes\n\nNEW SHEETS = previous sheets * new minutes / previous minutes\n\nNEW SHEETS = 2 * 10 / 5 = 2*2 = 4\n\nat this point you know that 2 people can work 4 sheets in 10 minutes.\n\nNow keep minutes the same. Balance sheets with a proportion:\n\nNEW PEOPLE : old people = new sheets : old sheets\n\nNEW PEOPLE = old people * new sheets / old sheets\n\nNEW PEOPLE = 2 * 20 / 4 = 2 * 5 = 10\n\n10 is the answer
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Count the total number of groups:\n9 choose 5 = 9*8*7*6/(4*3*2*1) = 9*2*7 = 126.\n\nb) Count the number of groups where 3 women where chosen and 2 men.\n(4 choose 3) * (5 choose 2) = 4 * 10 = 40.\n\nThe prob that a random committee has exactly 3 women = 40/126\n\nc) If there were no women then the number of ways this can happen is:\n(4 choose 0) * (5 choose 5).  As you could probably already see, there is only 1 way to have a committe of 5 men and 0 women.  The prob = 1/126.\n\nf) >=3 women is the same as saying 3 or 4 women as 4 women is the most you can have.\n\n(4 choose 3)*(5 choose 2) + (4 choose 4) * (5 choose 1)=\n4*10 + 1*5 = 45.  Prob = 45/126.
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27 ways to pick the first person in the group\n26 ways to pick the second\n25 ways to pick the third\n24 ways to pick the fourth\n23 ways to pick the fifth.\n\nHowever, order is irrelevant, so we need to divide by 5!.\n\nThis is 27 choose 5\n= 27 x 26 x 25 x 24 x 23 / 120 \n= 80,730 ways
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just make a list of all the people you want to be involved.  send out an email to all, inviting their ideas on a certain subject.  \n\nyou could make a Yahoo! group, to help with the administration.
603121
A party or group (not a party as in having a good time) this group would be like one within a government.
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well if the men are abc and women are def, then  the arrangement is like adbecf  right?  so   man a is "flanked" by d and f, and man a could also be "flanked" by de or ef so theres 3 different ways man a could sit. for each of these, there are 2 positions the other 2 men could sit in. \n\nso basically its 1 of these:\nadbecf\nadcebf\naebdcf\naecdbf\nafbdce\nafcdbe    \nit doesnt matter which seats they sit on, cuz that will make each man be "flanked" with the same women so u cant have that. all that matters is their order.\nthe answer is c. i hope this makes sense.
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It would take the 15 people 4 hours to do 50 papers (half the time for half the work).\n\nSince there are only 2/5 of the people, the time taken will be 5/2 as long, or 10 hours.
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if there were 12 groups each with 1 cheerleader in....you will have 12 groups
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If you are only concerned about the ways that you can place the 15 women between the 10 men, then you have 9 positions to place the 15 women.  (You don't have to worry about the arrangements for the men since there has to be one in between there is only one way to arrange.) These are the ways to do it (regardless of order).\n\na) 1 1 1 1 1 1 1 1 7\nb) 1 1 1 1 1 1 1 2 6\nc) 1 1 1 1 1 1 1 3 5\nd) 1 1 1 1 1 1 1 4 4\ne) 1 1 1 1 1 1 2 2 5\nf) 1 1 1 1 1 1 2 3 4\ng) 1 1 1 1 1 1 3 3 3\nh) 1 1 1 1 1 2 2 2 4\ni) 1 1 1 1 1 2 2 3 3\nj) 1 1 1 1 2 2 2 2 3\nk) 1 1 1 2 2 2 2 2 2\n\nNow to rearrange these, you would have to use the multinomial coefficient.  You have to use this because you have repeats: For example in a), you can switch two 1's around and get the same result, but moving the 7 will give you a different result.\n\nFor a), there are 9!/8!1! = 9 ways to arrange.\nFor b) and c), there are 9!/7!1!1! = 72 ways to arrange.\nFor d), 9!/7!2! = 36 ways.\nFor e), 9!/6!2!1! = 252 ways.\nFor f), 9!/6!1!1!1! = 504 ways.\nFor g), 9!/6!3! = 84 ways.\nFor h), 9!/5!3!1! = 504 ways.\nFor i), 9!/5!2!2! = 756 ways.\nFor j), 9!/4!4!1! = 630 ways.\nFor k), 9!/3!6! = 84 ways.\n\nSo in total, there are 9 + 72 + 72 + 36 + 252 + 504 + 504 + 84 + 756 + 630 + 84 = 3003 ways to place the 15 women between the 10 men.\n\nNow if after that you want to know how many ways there are to arrange if you do make a difference between men and between women, then multiply by the number of ways to arrange the men and women.\n\n3003*10!*15! = 14,250,102,106,034,995,200,000 ways.\n\nNotice this is less than the number of ways to arrange all 25 people regardless of gender.  That would have been 25! = 15,511,210,043,330,985,984,000,000.
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20- read below\n\nCommittees are not mentioned in the Constitution, but they are an important part of our law-making process. The first Congress adopted a committee system to handle all of the many tasks given to the new American government by the Constitution.\n\nCommittees are like teams that study national problems. They help Congress organize its workload, report progress, and suggest solutions to the challenges that face the nation. They propose laws that are debated and voted on by the whole House.\n\nWhat are congressional standing committees and why are they necessary?\nStanding committees are permanent committees. When Congress was first formed, temporary committees helped legislators organize their work into different categories. As the number of laws proposed increased, standing committees replaced temporary ones. Today the congressional standing committees are permanent panels made up of Members of the House or Senate that make and debate laws for different areas of public policy. Each committee has jurisdiction over a certain area, for example health, education, the environment and foreign affairs. \nThe U.S. House of Representatives has 20 standing committees. In the 109th Congress, these committees were named: Agriculture, Appropriations, Armed Services, Budget, Education and the Workforce, Energy and Commerce, Financial Services, Government Reform, Homeland Security, House Administration, International Relations, Judiciary, Resources, Rules, Science, Small Business, Standards of Official Conduct, Transportation and Infrastructure, Veterans Affairs, and Ways and Means.
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11 players\n1 goelkeeper\n10 field players