i want to draw a funhouse that you see at the fair and include plane mirrors convex mirrors and concave mirror
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I think we might need more information to be helpful. Is it a plan view, section/elevation?
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I'd design one free for you if you'd link to my site.\nEmail me at adamfishercox@gmail.com
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I can design some for you if you have an idea, they are not generally available, but desiners like me want to help people out by making them.\n\nGoto gamefreakuk.conforums.com, signup and contact me (admin) and i will design one for you.
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maybe a hexagonal prism http://en.wikipedia.org/wiki/Hexagonal_prism http://en.wikipedia.org/wiki/Prism_%28geometry%29
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Try an app named OmniForm. It may be a little expensive, but it works like a charm.
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How about drawing a bunch of straight lines of differing length, from a fixed point, so that the tips create the image of an arc?
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M.C. Escher has already done a number of drawings based on the hyperbolic plane, based on Henri Poincaire's method of representing the entire hyperbolic plane.  Check this out: \n\nhttp://www.sciencenews.org/articles/20030830/mathtrek.asp
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http://sketchup.google.com/download.html
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You can make one on that game thing at Comedy Central's website, save it to your comp., & upload it as a pic on here.\n\nI ♥ SP too! =)
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Try these \nmypimpspace\nfreecodesource\nlayout-designer at vampire freaks
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i would go to the store and get a coloring book of somthing i like such as batman or hot wheels i did this when i painted my toolbox a couple years ago turned out great using a coloring book since they are perfect for tracing designs
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http://www.johnstonsarchive.net/spaceart/cylmaps.html
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Use clay and then you'll be able to form the 3d shapes
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playing around with mirrors....and light.....and lenses
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since your ddoing coordinate geometry you should at least tell what shape you're trying to get.\nI'm assuming it's a parallelogram so u should make it (1,8)
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Discounting rotations and mirror images, there is only one way to make a magic square using the digits 1 through 9.  \n\nFirst, we can prove the 5 has to go in the middle:\n\nLet the numbers in the top row from left to right be a, b, and c.  Let the numbers in the middle row from left to right be d, e, and f.  (Note e is the middle box.)  Let the numbers in the bottom row from left to right be g, h, and i.     \n\nWe know a + b + c = 15 and g + h + i = 15\n\nWe also know a + e + i = 15, b + e + h = 15, and c + e + g =15.  Therefore, (a + e + i) + (b + e + h) + (c + e + g) = 15 * 3 = 45.  We can rearrange this to (a + b + c) + (g + h + i) + 3e = 45.  Since a + b + c = 15 and g + h + i = 15, that reduces to 15 + 15 + 3e = 45, or 3e = 15.  Therefore e (the middle box) must equal 5.   \n\nKnowing the middle box is 5, try 9 in a corner and you'll notice a problem - the 6, 7 and 8 can't all be placed in the square without the row or column with the 9 exceeding 15.  So, the 9 has to occupy a side box.  Since we are discounting rotations and mirror images, we can arbitrarily select box b for the 9.  This forces the placement of the 1 in box h.   \n\nWith the 9 and 1 now placed, the 8 and 6 have to go in the row with the 1.  So, we'll put the 8 in box g and the 6 in box i.  (We still haven't done anything to create a second square if rotations and mirror images are discounted.)  That forces the placement of the final four numbers.
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unless you have actually seen one to know what it looks like, you could use some paper mache stuck over a balloon, stick some pipe cleaners in with it, get some bulgy eyes!!