voltage in a potatoe vs. a lemon.?
831480
Voltage is dependent on the metals you use. The lemon however will have a lower output resistance. Because of this with the same load you may see more voltage the the lemon. But no load voltage will be the same.
620945
Item List:\n\n1. Potato \n2. Plate \n3. 2 pennies \n4. 2 galvanized nails \n5. Three(3) 8 inch lengths insulated copper wire, each with 2 inches of the insulation stripped off one end \n\nHow to do it\n\nFirst, cut a potato in half and put the two halves on a plate so they stand on their flat ends. The plate is there to keep your table clean. Then, wrap the end of one piece of wire around a galvanized nail and wrap the end of a second piece of wire around a penny. Stick the nail and penny into one half of the potato so that they're not touching each other. Next, wrap the third piece of wire around the other penny and put it into the other half of the potato. Put the other nail into the second half of the potato, but this nail should not have wire wrapped around it. Now, connect the wire from the penny on the first half of the potato to the nail that has no wire on it in the second half of the potato. Finally, touch the free ends of the wires to the battery section of the item you are trying to power. One wire goes to the positive(+) connection and the other wire goes to the negative(-) connection.\n \nDoes it work? \n\nYou'll probably have to try connecting the wires to the item in different ways to get the energy to flow through it in the right direction. It's just like putting batteries into a clock; they have to go in the right way.
616704
pie   p power = i current x e voltage\n      e = i x r resistance
250297
1.Current in the 385.451 V circuit is bigger.\n\nGod is spelled B-I-G B-A-N-G\n\nPBrax@netscape.com
165079
The germanium diode have a forward voltage of .3 volts compared to the silicon diode with a forward voltage of .7 voltage.
829788
It depends on the voltage your discussing.  The simplest that comes to mind is two parallel diodes reverse connected.  Silicon diodes will clip at  1.4Vp-p and germanium clip at 0.8Vp-p. \nFor higher voltages  two series zener diodes reverse connected will give you a wide option of clipping voltages. \nIf you specify the clipping volts I can help more.
1116545
See sources for making a "lemon battery" or a "potato battery".  You'll probably need to hook several of these batteries together in parallel in order to get enough current to power an LCD, but it should be possible.  Alternatively, you can use pieces of copper and zinc sheet metal to increase the surface areas of the electrodes in each battery, which will increase the current produced by each battery.
745468
Easy!\nIf the input is the same(1.1kW) it depends on their performance.
775555
P = FD/t = 300*9.8*5/8 = 1837.5 Nm/sec = 1.8375 kw
980170
You aren't clear about whether the switch is on in both measurements.  If it is, then the voltage will be the same.  If not, then the voltage will be different because of the voltage drop across the internal resistance of the battery.
1114398
d: Subjected to a small voltage.
579021
I think you meant WATTS versus volts. You will need to inspect your power supply for that information.\n You need to check out he following website, for more info on what you will truly need 250W sounds a bit low by today's standards - http://www.jscustompcs.com/power_supply/
177692
No matter what is the voltage rating, isolation or insulation is tested by using "MEGGER".\nThe value should be atleast above 1 Mega ohm in any case
752024
When you copy and paste these, why don't you convert the "W"s into "ohms"?\n\nHey!  The guy who did your homework for you ("The Great One") gave three WRONG answers (as of 1930 MST 11-14.  He'll probably redo it after he reads this)...heh, heh, heh...
752495
Without knowing the actual load, it is impossible to pick the bet pot.  But I would guess that it would work well to us a 1.0 k-ohm pot.  Connect one end to the positive terminal and the other end to the negative terminal and the wiper to your load.  The pot will form a simple voltage divider that will run the full range of voltage and it will only draw 9 mA of current when no load is applied. (If 9mA is too much, choose a larger pot.  But the higher resistance may affect your load.)
210547
power=voltage^2/resistance\nhigher power means lower resistance.
221557
.01uF / 1210/ 50v/ avx /digikey.com/\nMIKE