I need to solve this sentence:A trapezoid is ________ a parallelogram.?
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Whoever is requiring you to solve this sentence probably wants you to write "not".  There's a mild conflict between the community of mathematicians and the community of elementary educators about whether the definition of trapezoid should include parallelograms.\n\nAs a mathematician, it seems that a parallelogram or even rectangle should be counted as a trapezoid, because everything true about trapezoids is also true about them.  Also when you use the Trapezoid Rule for approximating integrals, it would be foolish to say "and Rectangle Rule", to handle the flat case.\n\nI'm not entirely clear on the educator's argument, some nebulous idea about how children should view them as being essentially different things.  Since trapezoids don't have much application in mathematics, this debate has gone unnoticed by most.  However in every textbook on geometry I've seen they insist on forcing this unpleasant definition down pupil's throats by having test questions like the above.\n\nAnyway I want you to get a good grade so write "not".   It's not your teacher's fault.  :/
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Wow, that last person used way too much stuff.\n\nDraw in one diagonal of parallelogram ABCD, say BD.  You have congruent angles ABD and BDC, ADB and DBC because they are alternate interior angles and BD is congruent to itself.  The two triangles are congruent (ASA) which makes the parts you want congruent by CPCTC.
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A hexakaidecagon (hexadecagon).\n\nFor the rest of the polygon questions you'll have, try the link below:
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a) "Suppose Triangle ABC and Triangle DEF are congruent."\nb) "Suppose there exists a line segment with at least two right bisectors."\nc) "Suppose there is an isosceles triangle for which the angles opposite two of its congruent sides are not congruent."\nd) "Suppose there is a line segment with at least two midpoints."\ne) "Suppose there are two intersecting lines such that opposite angles are not congruent."\nf) "Suppose AB is not equal to CD."
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In any quadrilateral the sum of the angles is 360 degrees.  Its an axiom that has been proven.  It's similar to the axiom that all angles in a triangle add up to 180.\n\nNote: the pattern is:\n3 angles = 180\n4 angles = 360\n5 angles = 540\n6 angles = 720\n7 angles = 900\netc.\n\nAnother fact about parallelograms is that the opposite sides have the same lengths and the opposite angles have the same measure.  This also means that two consecutive angles will add up to 180 (since the other pair must be equal and the total must be 360, as noted before).
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Strange parabola.\n\nBring the form to x = a(y-h)^2 + k\nThe vertex is (h,k).\nThe directrix will be x = k - m\nwhere m = 1/(4a)
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Hi Dear Ruth ; \n\n{ as you know Sum ( angles of trapezoid) = 360\nif ' a ' & ' b ' & ' c ' & ' d ' are angles of trapezoid so \na + b + c + d = 360 } ....\n\n▪ Step 1 \na = 6x - 4   , b = 5x + 1 , c = 4x  , d = 3x + 3\nas , a + b + c + d = 360 so ;\n6x - 4 + 5x + 1 + 4x + 3x + 3 = 360\n[ 6x + 5x + 4x + 3x  ] + [ -4 + 1 + 3 ] = 360\n18x + 0 = 360 \nx = 360 / 14\nx = 20 \n\n▪ Step 2\nas x = 20 \na = 6x - 4  ; 6(20) - 4 = 116 \nb = 5x + 1 ; 5(20) + 1 = 101\nc = 4x ; 4(20) = 80 \nd = 3x + 3 ; 3(20) + 3 = 63\nso we have ;\na = 116 ; b = 101 , c = 80 , d = 63 \n\nGood Luck dear ♣
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a trapazoid has 2 parallel sides and two non parallel sides.\n\nArea=( 1/2 sum of the parallel sides) * height\n\nremember the height must be the perpendicular height.\ni.e the height perpendicular to the parallel sides
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to find areas of parallelograms use the formula: \n\nA = base×height.
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"d" is the answer.\n\nGet an "A".
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Are you talkin about a trapezium or a trapezoid.\nif its a trapezium,here's how : \nlet the height be "h".\ndrop two perpendiculars equal to h on the base.the lengths b&#92;w the perps.is 6 units.therefore the rest of the length is 10.each individual length to the left of the perp is 5 units.\nin the triangle with the diagonal,the side adjacent to the angle with the base and diagonal is 6+5=11\ntherefore the angle is cos^-1(11/12)=a\ntherefore tan a=h/11\ntherefore h=11tan a\nanswer is height,h=4.795831523
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A rectangle...equillateral means all equal sides, equiangular means all equal angles\n\nthe rectangle has all equal angles, 90 degress but teh sides are different, if the sides were the same it woudl be a square\n\na rhombus has equal sides but not necessarily equal angles\n\na parallelogram does not have to have equal angles or equal sides, it needs to have to sets of equal opposite angles and equal opposite sides\n\nhope this helps!!
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No. The diagonals of a parallelogram bisect each other, but they don't bisect the angles.
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Sounds like they are looking for a *right* trapezoid.  \n\nYou can't just say trapezoid, because that doesn't require the shape to have any right angles.  A picture of a right trapezoid is given below:\n\n(Note: with their clues, it could actually be any polygon with at least 4 sides.  For example it could be a five sided polygon, with a couple right angles and one set of parallel sides.  (You know, the little house with a pointy roof we all drew when we were little)... and there are other shapes too.\n\nBut for this question, I'd go with *right* trapezoid.
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No - if a trapezoid has 3 congruent sides, the fourth side will also have to be congruent in order for you to close the shape.  In this case, your trapezoid will be a square.\n\nBy definition, a trapezoid has to have one pair of opposite sides that are parallel.  If you try to construct a trapezoid with three congruent sides, the fourth side will have to be the same length - try it with pencils or popsicle sticks to see.  If you do, remember, one pair of sides HAS to be parallel.\n\nA trapezoid can have 2 congruent sides - as long as they are adjacent (i.e. a side and a top).  If the opposite sides are congruent, then you'll end up with a parallelogram.
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Hi,\nThe answer is C.\n\nYou could make a ray-diagram and see for yourself...
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To determine if it is a parallelogram:\nIf a quadrilateral has one pair of opposite sides which are parallel and equal in length, then the figure is a parallelogram.\n\nTo determine if it is a rectangle:\nIf a parallelogram has two pairs of opposite sides which are parallel and equal in length, then the figure is a rectangle.\n\nGraph the points and determine the distance between the points, or, in your case, two points have an X of 0 and two have X of 3\n\nBetween the (0, 2) and (0, 6), there is a distance of 4\nBetween the (3, -2) and (3,2) there is a distance of 4\n\nBetween the (0,6) and (3, 2) there is a distance of 3 horizontally.\nBetween the (0,2) and (3, -2) there is a distance of 3 horizontally.\n\nYour figure has two pairs of opposite sides that are equal in length and parallel.  You have a rectangle.