2x-3y=12 and passes through (4,3)?
822663
What are you looking for?\nSlope?\ny=mx+b form?\nI will come back to read additional details.
218375
4x+2y=12\n2y=12-4x\ny=6-2x\n\ny=-2x+6\n\nfrom \ny=mx+b\n\nwhere M= slope\nb= intersept\ntherefore y intersept will be +6
724639
2x-4y = 3.8\n3x - y = 17.7\n\nmultiply second equation by -4 so that when u add them both u will cancel the y's...\n2x-4y = 3.8\n-12x+4y = -70.8\n\nnow add them..\n\n-10x = -67\n     x = 67/10 = 6.7\n\nnow plug this x in for any one of the original equations and solve for y....\n\n2(6.7) - 4y = 3.8\n\n13.4 - 4y = 3.8\n-4y = -9.6\n   y = -9.6/-4 = 2.4\n\nso the solution is (6.7,2.4)
117592
Multiply the 1st equation by 3\n\n3 [ 2x + y = -4]\nthat gives.. 6x + 3y = -12\n\nsubtract the 2nd equation from this\n\n6x + 3y - (-5x + 3y ) = -12 - (-1)\n\n6x + 3y + 5x - 3y = -12 + 1\n\n11x = -11\n\nx = -1\n\nput this into 1st equation\n\n2(-1) + y = -4\n\n-2 + y = -4\n\ny = -4 + 2\n\ny = -2\n\n\nx = -1 & y = -2\n\nyou can check this with 2nd equation\n\n-5(-1) + 3(-2) = -1\n+5 - 6 = -1 . hence the solution x = -1 & y = -2 is CORRECT
721099
4a + 3b = 4x4 + 3x(-4) = 16 - 12 = 4
561594
i think you wrote it down wrong, maybe it should just be 3x+4y=12 and then you solve for y.\n\nalso, i don't know what an in and out table is
684399
if x + y = 12 and y = 2x, then in the original equation, you can substitute 2x for y.\n\nx + 2x = 12\n\ncombine like terms\n\n3x = 12\n\ndivide both sides by 3\n\nx = 4\n\nbecause y = 2x, substitute x for 4.\n\ny = 2(4)\n\ny = 8
973940
A previous answer was incorrect. It is\n\n-4x(x+3y)(x-2y)
1070900
5x - 2y + 4 = 0 (i)\n3x + 2y + 12 = 0 (ii)\n(i) + (ii)\n\n8x + 16 = 0\n8x = -16\nwherefore x = -2\n\nsub x = -2 into eq (i)\n-10 - 2y + 4 = 0\n-6 = 2y\nwherefore y = -3\n\nx = -2 y = -3 wherefore your homework is done
903764
2x - 8y = 3\nadd 8y to both sides and subtract 3 from both sides\n2x - 3 = 8y\ndivide both sides by 8\n(x/4) - (3/8) = y\n\nANSWER\n(x/4) - (3/8) = y
27685
You have two equasions 2x=3y and y=2x+4\nYou're going to plug one equasion into the other; plug the y= into the  first equasion because the y is already by itself.\n2x=3(2x+4) (I plugged what y equaled into the y in the first equasion.\nThen you solve for x\n2x=3(2x+4)\n2x=6x+12\n-4x=12\nx=-3\nNow that you have solved for x, plug x back into the y='s equasion\ny=2x+4\ny=2(-3)+4\ny=-6+4\ny=-2
170337
numbers 3 and 4\n\nx(squared) is still an integer and xy/x=y, which is an integer
203610
b, that's just me doing it in my head.\n3y = -6x + 12\ny = -2x + 4\n\n3y = -6x + 36\ny = -2 + 12\n\nIt's been a while since I've been in a math class, did I do this right?
560506
that works... so does this:\n\n-2 x -1 x 1 x 2 x 3 = 12\n\n-2*-1=2\n2*1=2\n2*2=4\n4*3=12
817648
y=6\n\n3(y+4)=5y\n3y+12=5y\n12=2y\ny=6
1153940
x - 2 = 3x + 12\nx - 3x = 12 + 2\n-2x = 14\nx = -7
825795
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]