math help? how to solve?
818580
are you doing your home work on Yahoo answers?
79472
x = (1/3)y + 2\n-2x - y = 1\n\nTake the first equation, and plug its value of x into the second eq.\n\n-2[(1/3)y+2] - y = 1\n\nSimplify\n\n(-2/3)y - 4 - y = 1\n\n(-2/3)y - y = 5\n\n(-5/3)y = 5\n\ny = -3\n\nUsing the value of y, solve for x.\n\nx = (1/3)(-3) + 2\nx = (-1) + 2\nx = 1\n\nSo, the ANSWER is x=1 & y=-3
1187525
well start by multiplying things out\n\n-8x+12=-8x+5\n-8x+8x+12=5\n0+12=5\nno solution?\n\n2x+3y=6\n2x=6-3y\nx=6/2-3y/2\nx=3-(3/2)y
974614
Simple. Get rid of the denominators on both sides by multiplying by the lowest common multiple (in this case, 8). So that would make the left side: 2(3x +7) and the right side: -x. Then just isolate and solve for x!
899125
Q : 7x + 4 = 15x + 36\n\nfirst, move '+4' to the right side of the equation.\nand you get:\n7x = 15x + 36 - 4\n\nsecond, move '15x' to the left side of the equation.\nand you get:\n7x - 15x = 36 - 4\n\nthird, do the subtraction.\nand you get:\n-8x = 32\n\nforth, change the the left side of the equation to positive and the right side to negative.\nand you get:\n8x = -32\n\nthen, divide -32 by 8 so that you get 'x' equals to ___.\nand you get:\nx = -32/8\n   = -4 [the answer]
511948
There are an infinite number of ordered pairs that would satisfy this equation. If you want to find a few of them, assign a value to x and then solve for y.
934652
So let's say the problem looks like this\n\n   11\nx 12\n--------\n        <-----the answer from 11*2\n       <------answer from 11*1\n\nfirst hide the 1 from the 12 and work out the problem as 11*2\nthen work on multiplying the 1 with 11 but make sure you start putting your answer down below your first answer and the answer starts in the column that is below the 1 from the 12.\n\nfinally when the two answers are found, you can add them and get your final answer. SOOO here's what it looks like\n\n      11\n   x  12\n--------------\n           22    (this is from 11x2)\n +  11       (this is from 11 x1)\n------------\n     132 = final answer!
1020883
i am sure you can find a math tutor that will be happy to help you when you explain what the problem is.\n\nso what IS the problem, anyway?
888367
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
447443
Ok...you have to solve two equations\n\nFIRST ONE\n\nif (8-4x) < 5\n\nthen (8-4x-5) < 0 (by subtracting 5 from both sides of the equation)\n\nthus (3-4x) < 0 (obviously)\n\nso 3 < 4x (by adding 4x to both sides of the equation)\n\nso 4x > 3\n\nso......... x > 3/4\n\nSECOND ONE\n\nif -(8-4x) < 5\n\nthen -8+4x < 5 (obviously...see that -*- = +)\n\nthen -8+4x-5 < 0 (by subtracting 5 from both sides of the equation)\n\nso -13+4x < 0 (obviously)\n\nand 4x < 13 (by adding 13 to both sides of the equation)\n\nso......x < 13/4\n\nFINAL ANSWER IS.......(3/4 < x < 13/4)
831674
1. replace x with -3, calculate and see if you get 0\n2. divide by (x+3) and solve the remaining quadratic equation
537199
got to math.com, click on calculators and click on solve equations.....it'll do the math for ya
727014
start with the O... they are always -2\nsince there are 2, and the compound must balance...\nPb must be +4\n\nso you get +4 -2
787725
To solve a problem like that:\n\n2x-3+4x = 10 (i'm not sure if this is your answer but I'm using it as an example)\n\nFirst combine the x's on the left side to get 6x-3 = 10\n\nThen add 3 to both sides to cancel the 3 on the left side.  You will not have 6x = 10.\n\nDivide both sides by 6 to isolate the x.  You will now have x = 10/6 (or 5/3)
345141
0 solutions!\n\nMove sqrt(x+8) on the other side and then raise by the power of 2. You will get\n\nx-4=4+4*sqrt(x+8)+x+8    (btw if there is a solution it has to be greater or equal to 4)\n\nthis is equivallent to \n\nsqrt(x+8)=-4\n\nWhich is impossible by the definition of sqrt(). It always has to be greater or equal to 0.
255958
Substitute 2 for x and solve for c.\n2^2-3(2)+c=0\nRemember do powers, then multiplication, then subtraction.
969755
Relax\n\n1)) (5x + 7) + (x - 2) = 5x + 7 + x - 2 = 5x + x + 7 - 2 = 6x + 5\n\n2)) 2 X length + 2 X height = perimeter\n\n  (2 X x) + (2 X (x - 3)) = per = 2x + (2x - 6) = cir = 2x + 2x - 6\n\n  perimeter = 4x - 6,   or 2 ( 2x - 3)\n\n3)) same as # 2;\n\n  2 X (t + 5) + 2 X 2t = 2t + 10 + 4t = 2t + 4t + 10 = 6t + 10 = per\n\n4)) (t - 5) - (3t - 1) = t - 5 - 3t + 1 = t - 3t - 5 + 1 = -2t -4\n\n  or -2 (t + 2)