the name of a totally collapsed object (two words)?
828617
Although it's not an object in the usual sense, since it is of infinite mass and zero volume, the actual answer is a "singularity"----ONE WORD. This is what is found at the center of a black hole (which is probably the answer most people will give, bur the black hole "contains" the singularity, which is hence more densely compressed.
581807
D. Epicenter\nFinal answer.
990247
A sphere.  It has an inside and an outside.
78498
By unstoppable you mean un-deflectable?\n\nThe force would go thru the object.\n\nThat way the force continues unstopped and the object remains unmoved.
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Hi there,\n\nTry looking for "Klein space" (without the 's). You get for instance this page : http://www.mccallie.org/myates/The%20Shape%20of%20Space/Student%20Projects/group10.htm
812993
A blank one or a R/W one.\n\n///
578266
largest with all the ice\n\n2nd largest without all the ice
717854
something that cannot be explain
878219
your question is not clear. describe positions of the objects.
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I don't remember any term like this.\nI am in doubt that whether such term exists as for as Physics is concerned.
213526
QUESTION: WTF is that?
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It is called a ray.\nA ray is a half-infinite line with one end-point.
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I think I'm gonna look like I've got no clue whatsoever if I answer this one but, still, I'll give it a try risking my reputation. \n\nFirst of all, I didn't have a clue what you meant by a "buckyball", then I looked it up in a dictionary, now I know its a nickname for the C-60 Buckminsterfullerene. Thanks for adding one more word in my vocubulary (I desperately need a better vocubulary). \n\nNow, coming to your question, to determine the strengh of a rope made of C-60, umm.. I'll take a coward's way out by not going into the molecular constitution of the rope. As the physical strengh is an observable physical quantity, I'll solve the problem on a macroscopic scale. \nI'll hang a heavy mass with the help of the Carbon rope and will keep increasing the mass untill the rope ruptures.\nNow, I'll note down -\n1- The Weight (mass * acceleration due to gravity) that broke the rope.\n&\n2- The cross sectional area of the rope.\n\nNow, I'll just divide the Ultimate Weight by the cross sectional area of the rope to get the TENSILE STRENGTH of the rope.\n\nNow, I'll adopt the same procedure with the steel cable.\n\nI think, that way, we can easily compare the tensile strengths of the carbon & steel ropes.\n\nNow, to answer the second part, the density of the C-60 rope. Here too, I'll use a method that doesn't involve the molecular constitution of the rope (sorry again).-\nI'll use the Archimedes' Principle instead-\nLets first assign signs to the physical quantities-\nW = Weight of the Rope\nF = Buoyant force\nd1 = density of our rope\nd2 = density of the water (or the fluid in which you choose to immerse the rope)\nV1 = Volume of the rope\nV2 = Volume of water displaced by the rope.\ng = acceleration due to gravity\n\nTake the rope & put it into water (or any other fluid), now first see if it floats or gets submerged.\n\n\nIf it gets submerged, you can say that-\nW - F = (d1 - d2) * V1 * g \n(as the volume of the rope is equal to the volume of water displaced here)\nNow, knowing other quantites, we can calculate density of the rope!\n\nIf it floats-\nW = F\nd1 * V1 * g = d2 * V2 * g\n\nd1/d2 = V2/V1\n\nIf you take water as the fluid, d2 = 1000 kg/m^3
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my jigsaw has a framulator. Do your own homework.\nMIKE
674826
yea just dont break a window or something then it would be called break the object
295075
a plate folded like a prism
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gravity.\n\nany shape of mass that is not spherical is gravitationally unstable