can someone help me with this equation?
814242
Barium Hydroxide is a weak alkali which is not very soluble. If you try to neutralise it with dilute sulphuric acid you will get a precipitate of Barium sulphate. This means you won't be able to neutralise solid barium hydroxide just the solution. To neutralise either the solution or the solid use dilute hydrochloric acid.\nBa(OH)2  +  2HCl  =  BaCl2 +  2H2O\n\nIf you add carbonate ions CO3 2- to a solution of barium hydroxide Barium carbonate will be precipitated. Again carbonate ions (as in sodium carbonate solution) will not completely react with solid barium hydroxide.
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
244823
The amount (A) will be doubling, so substitute "2P" in for A. Then you can drop the "P" from each side by division and solve for t.\n\nA = Pe^(rt)\n2P = Pe^(rt)\n2 = e^(rt)\nln 2 = (rt) ln e\nln 2 = .054t (ln e = 1)\n(ln 2)/.054 = t\n(approx.) 12.836 = t\n\nDoes that sound correct? (It's been awhile since I've done these kinds of problems.)
814311
The issue lies in the fact that the original equation is 0=0.\n\nThen, if you put in any value for x, you are dividing by 0 which as we all know, is a "no no."
765864
I'm unclear with the way you stated the problem. Am I looking for a implicit derivative. I'll check back to solve it.
821450
go to a math website off yahoo. it should help.
798483
Here it is:\n\n(98,42)Mo + (1,0)n ---> (99,42)Mo
299918
This is a separable differential equation\ndP/dt = 4P^2 + tP^2\nFactor P^2 out from the left side\ndP/dt = p^2(4+t)\nDivide each side by P^2 and multiply each side by dt\ndp/P^2 = (4+t)dt\nNow integrate each side\n-1/P = 4t + (1/2)t^2 + C\nSolve for P and you will get\nP = -1/(4t + (1/2)t^2 + C)
1132678
Directions how to do this can be found in the text book.\n\nDo your own homework!
849885
I understand your frustration in receiving no Answer yet to this question, but since I do not have any direct knowledge of how to perform the calculation(s) you need ... I hope the link below serves you well.  It appears to explain the mathematics behind all the concepts you mention.
782406
°oO****Oo°°oO****Oo°°oO****Oo°\n\n\n 4 ∫[g(x)] g'(x) dx = 4 x 1/2g(x)² +c = 2g(x)²+c\n\nits the first suggestion that u made but i think you forgot the number 4...\n\n\n°oO~<<_P~'*'_ I~'*'_M~'*'_O~'*'~L _~'*'_A>>~Oo°
986332
y=ln[sec5x+tan5x]\ny'={1/[sec5x+tan5x]}[5sec5xtan5x+5sec^25x]\n=5sec5x[sec5x+tan5x]/[sec5x+tan5x]\n=5sec5x
931316
(-0.242+2.18-1.94)*10^-18\n=(-0.002)*10^-18
961595
umm..are you missing an equals sign somewhere or am i really dumb? how do you figure out what x is unless you have both sides of the equation?
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
978722
You can't, algebraically.  You have two equations and three variables.  Sorry.  You need one more equation, such as a = b.
492690
S(I)+3f (g)--> SF (g)\n..........2...........6