Assume the denominator x of a fraction is greater than numerator 2x-5. Find fracs  num and denom are + integer
824496
The numerator is 2x - 5 and the denominator is x.\n\nWe want x > 2x - 5, subject to the condition that both x and 2x - 5 are positive integers.\n\nFirst, solve for x.\n\nx > 2x - 5\n-x > -5\nx < 5\n\nx must be less than 5. Because of the requirements of the problem, x must be greater than 0. x must also be an integer.\n\nIf x = 4: (2*4 - 5)/ 4 = 3/4\nIf x = 3: (2*3 - 5) / 3 = 1/3\nIf x = 2: (2*2 - 5) / 2 = -1/2.\n\nx = 2 doesn't work, because the numerator is negative.\n\nPut another way, we have an additional constraint that:\n\n2x - 5 > 0\n2x > 5\nx > 5/2.\n\nTo be an integer that satisfies all of these condtions, x can be equal to 3 or 4.\n\nTo recap, the fractions are 3/4 (if x = 4) and 1/3 (if x = 3).
791629
If x = original number\nand\nR1= remainder of x/3\nR2= remainder of x/5\nR3= remainder of x/7\n\nThen  x = (R2 * 21) + (R3 * 15) - (R1 * 35)\n\nSo for your example of 26:\nR1 = 2\nR2 = 1\nR3 = 5\n\nX = (1 * 21) + (5 * 15) - (2 * 35)\n   = 21 + 75 - 70\n   = 26\n\nNotice how the remainder of one number relates to the multiple of the other two. Also, I think you need to start at 7 instead of 3, because there will be fractions and no remainders for the numbers less than 7.\n\nEDIT:\n\nIf you look at the formula again, you will see that it works for your example, also!  =)\n\nBe careful where you plug in your numbers; they aren't in order.
843552
For the first equation, you take half the denominator (34) to get 17.  So take half the numerator (12) to get 6.\n\n12 ... 6\n--- = ---\n34 .. 17\n\nFor the second equation, you multiply the numerator (2) by 4 to get 8.  So the denominator should multiply by 4 to get 36.  In other words, it must be 9.\n\n2 .... 8\n-- = ---\n9 ... 36\n\nYou can also do these by cross multiplying:\n1) 34x = 12 * 17\nx = 12 * 17 / 34\nx = 12 * 1 / 2\nx = 12 / 2\nx = 6\n\n2) 8x = 2 * 36\n8x = 72\nx = 72 / 8\nx = 9
677314
To do this, you do (2/3) / (1/5). You must flip the denomiator fraction over and change the operation to multiplication. So... that would be (2/3) * (5/1) which would be 10/3.
139386
(X-c) here represents the number you are going to devide with. c can take any value here.\nLet you have to devide with (x-5) , then c will be 5.\nAnd if you have to devide with (x+10) then c will be -10. As (x-(-10))=(x+10).\nThe remaider therum says, If you devide a polynomial, P(x) by (x-c) then the remainder will be P(c).\nIf you want a proof of this theorum,\nlet, the divisor of divison of P(x) by (x-c) is A and remainder is B.\nSo P(x)=A*(x-c)+B.\nSo P(c)=A*(c-c)+b\nor, B=P(c) which is the remainder, I hope this will clear your concept.
867004
For this equation:\n2 then 1 over 5 equals to 11 over 5\n\nin "2 then 1 over 5" 2 is the whole number, 1 is the numerator, and 5 is the denominator.\n\nMultiply the denominator (5) by the whole number (2) then add the numerator (1).  This number (11) becomes the new numerator.  Keep the original denominator (5).\n\nin 16 then 2 over 3 equals 50 over 3\n\nMultiply the denominator (3) by the whole number (16) then add the numerator (2).  This number (50) becomes the new numerator.  Keep the original denominator (3).\n\nhope that helps.\n\nmari
890923
To find the common denominator between fractions simply multiply the denominators and this is the common denominator.\n\nHowever this number may be large so try and find a number that all denominators will divide into evenly.\n\nHope this helps.
46798
if (1/x) + 2= (c/2)\n--------------------------------\n\n1/x = (c/2) - 2\n----------------------\nx = 1/((c/2) - 2)\n       (OR)\nx = ((c/2)-2)^-1\n-----------------------
537832
(x/x-2)-(x+1/x)=8/(x^2-2x)\n[x(x)-(x-2)(x+1)]/[x(x-2)]=8/[x(x-2)]\nx^2-(x^2-2x+x-2)=8\nx^2-x^2+x+2=8\nx=8-2=6
427245
You can only take the log of numbers that are positive, so\n\nx^2 + 6x + 5 > 0\n\nSo (x+5)(x+1) > 0\n\nSo x would have to be greater than -1 and less than -5.
40442
(2/X+5)+(3/X+4)=(2x/x^2+9x+20)\n\nX = -.341296
602043
I haven't done partial fractions in a while, so you might want to check this: \n1/(x+3) - 2/(x+3)^2 + 5/(x-7)
965696
Two add two fractions, the denominators must be equal.\n\nThe first step is to convert the addend that is a mixed number (an integer plus a proper fraction) into an improper fraction. Do this by multiplying the integer part by the denominator and then add the numerator of the fraction.\n\nExpress the result as an improper fraction (fraction with value greater than 1) whose numerator is the sum you just calculated and whose denominator is the same as the denominator of the fraction part of the mixed number.\n\nFor example: 2/3 + 4 2/5 = 2/3 + 22/5\n\nNext, find the least common denominator of these two fractions, the smallest integer that contains both denominators as factors. For the example above, this is 15. Multiple both terms by (3*5)/15, which equals 1, and therefore does not change the value of the fraction:\n\n(2/3) * (3*5)/(15) = 10/15 (the 3's "cancel out" since 3/3 = 1)\n(22/5) * (3*5)/(15) = 66/15 (the 5's "cancel out" since 5/5 = 1)\n\nNow add 10/15 + 66/15 by adding the numerators and keeping the same denominator: 76/15.\n\nFinally, express this improper fraction as a mixed number by dividing: 5 1/15
674900
When you have (a+b+c)/d, you can separate the terms of the numerator like so a/d + b/d + c/d.  If I do that and simplify, I get:\nx - (6/5) - (3/x).
65994
it would actually be by a factor of 16... since both masses are doubled, so the numerator increases by a factor of 4, and the denomonator is halved, so then the denomonator is actually r^2 so you have to square 1/2 giving 1/4. so that means that you have 4/(1/4) which is just 4 x 4 or 16.
50236
let the number be x\n\n1/(x-5) = 4 (1/2x)\n=> 1/(x-5) = 2/x\n=> x = 2x-10\n=> -x = -10\n=> x = 10\n\nthe number is 10.
538653
Just put each number in for x and see what the answer is.  Example : -11/2 + 75 = -5.5 + 75 = $69.50 a unit.