Serious Calc help please...I'm lost and I have a huge test tomorrow that I am studying for?
827251
V = πr²h\nA (top & bottom) = πr²\nEnd Area = 2πr²\nLateral Area = 2πrh\nCost of tube = 2πrhC, C being cost per unit area\nCost of ends = 2πr²C*1.2\nTotal cost, P = 2πC(1.2r² + rh)\nh = V/πr², so\nP = 2πC(1.2r² + rV/πr²)\nP = 2πC(1.2r² + V/πr)\ndP/dr = 2πC(2.4r - V/πr²) = 0 for max or min, so\n2.4r = V/πr²\nr³ = V/2.4π\nr³ = 5/2.4π\nr = 0.872"\nh = 5/π0.872²\nh = 2.093"\n\nCheck:\nC(2.4*π0.872² + 10/0.872) = 17.201050C\nC(2.4*π0.87² + 10/0.87) = 17.201444C (+0.000394)\nC(2.4*π0.874² + 10/0.874) = 17.201137C (+0.000087)
102673
If you can't get an answer here, try asking your Algebra teacher for extra help after school tomorrow.  It's sure to add to your grade that you asked for the help.
814337
This will help you out! \n\nhttp://www.webqc.org/mmcalc.php
706629
go on\nwww.hotmath.com
880047
I can find this on a TI-84+, is that how you want to get it or do you need an algebraic solution?
959479
all you need to do is go to www.webmath.com, it'll help u there!\n\nI always do my math problems to that site if ever i get stuck on something! It's helpful!
1084798
I've got a big exam tomorrow too, infact 4! I haven't revised for my maths or one of my physics but I revised loadsa past papers in the past month for my other physics. I went over them today to see which questions i couldn't do and tried to do them, or look at the definitions I need to know. I think if you just skim the stuff you need to define then you can work the rest out.
873308
OK - I will try and explain it, but forgive me if I get myself confused...  hehehe\n\nFirst step - make a bell curve.  Put a mark in the center and label that "7 hours" - that's your mean.  Next, put three marks on either side of that middle point - those will be your standard deviation points.  For the points on the right, ADD 5.3 to the mean for the first one, then add 5.3 again for the 2nd, etc...  Points on the left side of the mean have the 5.3 SUBTRACTED.  (Am I still making sense?  lol)\n\nNow - the 68-95-99.7 rule says that 68% of the freshmen will fall into the area between the first line on EITHER side of the mean, 95% between the second lines and 99.7% between the third lines on either side of the mean.\n\nI think you should be able to figure it from there - I hope so...  Right now I am so confused I think I gave myself a headache!  lol\n\nGood luck!
502657
Try this link and read it all the way through.  It's short.\n\nhttp://mathcentral.uregina.ca/qq/database/QQ.09.00/tom3.html\n\nThis link is better:\n\nhttp://mathforum.org/library/drmath/view/56760.html\n\nJust scroll down.
1039521
Dear Lord,\n\nPlease help me circle the wagons!  There is no parallel for my situation.  I'm surrounded by squares who will ace this test and I forgot to study a segment.  Be my ray of light, beaming through a kite of confusion.  Send down your angles to assist me.  I need points on this test.  Please, send me a sine.
862258
I am taking College Algebra with Trigonometry and that is hard, so I know Calculus is real hard. That is a hard question to figure out.
260828
Go to homeworkhelp.com and get a real live tutor. You chat with them and ask your question and they help you figure it out. Don't get too excited though because they don't give you the answer, straight up.
875394
Very understandable....I just posted a question about my pre-calculus homework and i didnt ask for the answer, i just need help finding how to get it....i'd like to know how to do it myself, i dont just want someone to tell me the answer....does me no good @ all!
35718
The biggest thing would be to review EVERYTHING that is graded and returned.  Really understand your mistakes and make corrections.  If you can't figure this out, get help on particular problems from your professor, another student or a website like dr. math (see sources).  \n\nThere are also a ton of great resources on the web, just search for "math help" or "statistics help".\n\nDrop in for your professor's office hours.\n\nMost of all, don't let yourself get behind.  In any math class, being clueless about one day might not seem so bad, but quickly leads to being clueless about what's been taught over a week, a month, the course... don't put yourself in that place.  Stay on top of homework and do corrections religiously.
202506
I can help, I've taken College Algebra, Calc. I, Calc. II and I've also taken many other math courses, and I'm also studying to be a computer programmer, so if you need help you can contact me at assassin7262002@yahoo.com
1029299
I just took Calculus this year.  And I apologize in advance, since Calculus is not my strong suit and it is especially difficult to explain without visuals.  So....\n\nTo find the relative min and max, you take the first derivative of the function.  You have to multiply the exponent by the coefficient and then subtract one from the exponent.  Therefore, the first derivative of the function is:\nf'(x) = -4x^2+2x+30\n\nThen, you set this equation equal to zero to find the relative mins and max.  What I like to do is use a graphing calculator to graph the equation of the first derivative.  See where the line crosses the x axis.  The points where the graph go from positive to negative are your rel. max, and the points where the graph goes from negative to positive are your rel. min.  For this one, your relative min is at x=-2.5, and your rel. max is at x=3.\n\nI'm not sure about this part, but I believe that the graph of the first derivative is also good for telling you how to find out where the graph is increasing and decreasing (I think).  Now, the graph of the first derivative is positive in between -2.5<x<3.   Which means that is where the original function is increasing.  \n\nNow on to the inflection points.  You find them by taking the second derivative.  Take the derivative of the derivative (see directions above).  The second derivative is\nf''(x) = -8x+2\n\nThe inflection points are where x=0 on the graph of the second derivative.  I think you're set.  \n\nAnyways, if this didn't help, a real teacher will do wonders with this problem and many others, I know mine did! (If you're reading this, thanks Mrs. C!)  Good Luck!
822034
You're NOT dumb!  Everyone has different skills.  Thought you were going to send me a note when you got stuck??  I took alg II twice!\n\n1.  simply switch it to s=1-2t.  Now put that first one into the second , for s, which will give you the value of t when you solve it.  Plug in t's value into either and that will give you s.\n\n2.  do the same way\n\n3.  P=120\n     L=3w\n     P=L times W\n\n4/5:  take the number on the outside and multiply each number inside the (), then combine.\n\n7/8:  isolate the variable (letter) and get it just on one side