what does the waveform of a non inverting amplifier look like?
828980
Depends on what the amplifier is configured as. Integrating, differentiating, ect. But a non inverting amplifier output will have the same polarity as the incoming signal in general.
249045
Ripple current is that which is not filtered. The best way to determine is to view using an oscillosope. The ripple is oscillating above the DC level.\nWithout viewing the circuit it is hard to determine if you are ontract or not.\nPossibly the current into the cap is 26amps, but I have a hard time believeing there is 6 amps of ripple. That's about 25% of your total current. \nUsually it is less than 5%.
1010149
Winamp Free Edition 5.23 I think. i just updated it some days earlier.\n\nI hope this will help you!
292420
Yes.  Convert the discrete time signal to a series of impulses.  Send the impulses through a digital to analog converter.  Send the output of the D/A through a low pass filter.  \n\nOppenheim describes the characteristics of an ideal reconstruction filter.  See pages 197-201.
372456
To measure ohms, DCV, ACV, Amps or what????
399669
Do you mean for a transistor (or even a valve) circuit?\n\nVOLTS on x axis, AMPS on y axis, Plot on x-axis full voltage at zero current through the device, even if the device could not actually do that.  Calculate what full current would be through load resistor with zero voltage across the device and plot on y-axis (again even though the device might never do that, the load resistor governs what voltage remains across the device at any given current).\n\nThe chosen bias current or voltage will determine the no-signal "Q-point" somewhere along this line. Any signal altering the bias will move the volts/current  up & down the diagonal load-line you drew.\n\nHowever, to complicate the matter, the ac load line may not be on the dc load line you drew.  You calculated this on the basis of a resistor dropping the supply voltage. You could have a reactive (eg capacitative) load.\nThe Q-point is the same, but the signal will operate up and down a line through the Q-point.  The line will have a gradient according to the net impedance of the load.\n\nHope this helps.\n\nPLEASE NOTE I HAVE EDITED x- AND y- AXIS SINCE THE ORIGINAL.
556680
http://en.wikipedia.org/wiki/Modulation_index
45092
You first have to represent your wave as a function. Let's say your wave has maximum and minimum aplitudes of 2 and -2 respectively, and a period of 10 seconds. The square of your function would be \nx^2 (t)= 2^2.\n\nMathematically, the squared signal is x^2 (t) and the "mean squared" signal is the integral of s^2(t) over an entire period, divided by the period. Finally, the "root mean squared" is the square root of this final result. \n\nIt's hard to put in the integrals and square roots in this text only format, so check out the website.
956319
The op-amp is basically a differential amplifier having a large voltage gain, very high input impedance and low output impedance. The op-amp has a "inverting" or (-) input and "noninverting" or (+) input and a single output. The op-amp is usually powered by a dual polarity power supply in the range of +/- 5 volts to +/- 15 volts.\n\nOne of the most common applications of this device is the propagation of sound, like a line driver for your stereo. The signal from an external source is very low-powered ... the operational amplifier is used to boost the signal to where it can "drive" the speaker to reproduce the sound.\n\nAnywhere a signal needs to be boosted - and distortion minimized - you can find an op-amp configuration of some sort.
487229
If your amplifier or receiver has a "phono" input, then you do not need a preamp.  If it does not have this input, then you will need a preamp, also known as a "step-up" amplifier.  You can probably find one of these on eBay, or at Radio Shack.  The electrical output from your phono cartridge is very low, and requires a boost so the signal from your LP's can be heard.
966403
It depends on the application.\nDr. Boye's requirement for the VCO was that it produced 5 distinct types of audio signal waveforms: square, sawtooth, triangle, sine and a pulsed sine wave that had a duty cycle of 3 seconds on and 3 seconds off. \nhttp://www.phy.davidson.edu/instrumentation/VCO.htm
607576
If the input jack is an effects send/return it might be a TRS style input. This will allow you to use one TRS cable to run the complete loop. If is only an input, it may be used for inserting other pre amp type units. Ex. cd player, drum machine, sample loops etc.If there is only one input on the front of the unit, just run the mono output of the delay pedal to the input. If the delay pedal is already mono, just go straight to the amp. Jim
159857
this si not a physics question. this is a basic IC that perhaps still and certainly at one time was available at radio shack. the ic 741 behaves as ANY op amp and it is electronics 101.......happy homeworking.
669972
Its impossible design unless you narrow the criteria.\n\nFor example, one needs to know the following\ninput impedance\ninput level\ndesired gain\nallowable phase shift\nbandwidth 3db points\nbandwidth skirts\nallowable THD\npower requirements, unipolar/bipolar\noutput impedance\noutput drive capability\nslew rate\nand many more....\n\nA simple inverting op amp will easily amplify 500Hz signals as well as everything else. If you want something you can play with, check out Linear Technology's or Microchip's website and their filter designer software. Most of it is spice based, and it can give you some ideas, but until you breadboard it, they are just ideas on paper.
1115202
http://www.dbpoweramp.com/codec-central-wma.htm\nits great!!!!!!!!!!!!!\nhave fun
797986
This is a very simple circuit.\nhttp://www.rason.org/Projects/fmkeyer/fmkeyer.htm
416476
You need some way to clip the signal, using a diode of some sort.  Simply R L and C cannot generate a square wave using AC voltage.