i need hlp wit homework the second lttr is an r and the ? is:wat is a relatedor derivd frm livngcont indetails
816705
Organic molecules are found in living things..and organic fits, try that.
161241
V = I * R = I1 * R1 = I2 * R2.\n\nI2 * R2 = I1 * R1\n\nI2 = (I1 * R1)/ R2\n\nR2 = 16 * R1\n\nI2 = (I1 * R1)/ (16 * R1)\n\nI2 = I1 / 16
887169
You're getting into logarithm.  If X/D = R^Y, then Y = log(X/D), where log is the logarithm in base R.
840090
P1V1 = nRT = P2V2\nP1/P2 = V2/V1
898860
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
554491
I LOVE U\n\nFirst line:\n= I [ (L+N)² - N(2L+N) ] O / L\n= I [ L² + 2LN + N² ) - ( 2LN + N² ) ] O / L\n= I [ L² ] O / L\n= I L O\n\nSecond line:\n= [(v+r)(v-r)][E/V(U³/U²)]  (Note: that is U^3/U^2)\n= [v² - r²] [E/V(U)]\n\nNow we know that we "r" (are) nothing without each other, so r = 0\n\n= [V²] [E/V(U)]\n= V E U\n\nAll together our equation is I LOVE U
483398
r u 4 r3al ?!! \n\nwhat mapping ? what equasion?  deckard maybe ? \n\nmore info please.
828677
∫sin(ln(t)) dt\n\n= ∫sin(ln(t)) d(t)/dt dt\n\n= tsin(ln(t)) - ∫t * 1/t cos(ln(t)) dt \n\n= tsin(ln(t)) - ∫ cos(ln(t)) dt \n\n= tsin(ln(t)) - ∫ cos(ln(t)) d(t)/dt dt \n\n= tsin(ln(t)) - (tcos(ln(t)) -∫ t * 1/t *-sin(ln(t)) dt)\n\n= tsin(ln(t)) - tcos(ln(t)) -∫sin(ln(t)) dt\n\nSo 2∫sin(ln(t)) dt = tsin(ln(t)) - tcos(ln(t))\n\nSo ∫sin(ln(t)) dt = t/2(sin(ln(t)) - cos(ln(t)))
724685
r-s = t\nadd s to both sides\nr = t+s
802256
this maybe helpful \n\n\n\nwww.springerlink.com/index/R617G25W81437Q01.pdf\n\nhttp://www.springerlink.com/index/R617G25W81437Q01.pdf
396330
Another homework question.
960662
ry +s = tx - m\nYou must leave y alone for indicate its value in terms of other variables.\n\nFirst of all you move the s to the other side or the = as shown: ry =tx- m - s (you change the sign of s)\n\nThen you move the r as follows: y=(tx-m-s)/r\n\nAnd thats it \n\nYou have a restriction because the r has to be different than 0 to avoid a division by zero.  So restriction is r different from zero.
809473
Scroll to the bottom for Homework Help: http://answerpool.com/6/ubb.x?a=cfrm&cdra=Y&s=669605981
245176
u*(u-2)+v*(u-2)\n(u+v)*(u-2)
424650
Not really enough information to help, so try this site:\n\nhttp://www.blc.edu/fac/rbuelow/calc/ex4-6.html\n\nit's the second problem down the page
888459
v(t)= -gt - ve(ln((m - rt)/m))\n\nx(t) = ∫v(t) dt\n\n= ∫[-gt - ve(ln((m - rt)/m))] dt (Note ∫lnu du = ulnu - u + k)\n\nLet u = (m - rt)/m Thus du = -r/m dt ie dt = -m/r du\n\nSo x(t) = -½gt² - ve*-m/r (u(lnu - 1) + c\n= mve/r [ (m - rt)/m * (ln((m - rt)/m)  - 1] - ½gt²\n= ve(m - rt)/r * (ln((m - rt)/m) - 1) - ½gt²\n\nIf g = 9.8 m/s^2, m = 30000 kg, r = 155 kg/s, and ve = 3000 m/s and t = 1 minute = 60 s\n\nx(60) = 3000 * (30000 - 155 * 60)/155 * (ln (30000 - 155 * 60)/155 - 1) - ½ * 9.8 * 60²\n\n≈ 138390 m\n\n= 138.39km
753296
|t - 78.3| ≤ 38.3\n\nSo either t -78.3 ≤ 38.3 whence t ≤ 116.6\nOR - (t - 78.3) ≤ 38.3\nwhence - t ≤ - 40 ie 40 ≤ t\n\nSo 40 ≤ t ≤ 116.6