What would happen if you dropped a 1-kg rock from 1000 miles up unto the surface of a neutron star?
813411
Well, you couldn't, because my calculations tell me that if you get closer than about 5000 km. from a neutron star, the tidal forces, that is the difference between the gravity pull on your feet and your head, would stretch you out and kill you.  If you built a strong robotic vehicle that could get to within 1600 km of the surface, the rock would be pulled to powder by tidal forces before it hit the surface.  The bits would hit the surface at up to a third of the speed of light, 100 000 km/second, depending on the mass of the neutron star.  They'd get so hot on impact that they'd emit X-rays, which, as they climbed against the neutron star's gravity, would lose energy, and you'd see them from a safe distance as soft X-rays, UV and visible light.The amount of energy radiated would be about 10^15 joules; comparable to the Hiroshima bomb.  The mass of the neutron star would increase by about half a kilogramme or so.  The crust of a neutron star probably consists of iron or diamond, and your rock would end up as one of these.  It would be interesting to perform this experiment, from a safe distance, with a robot probe, on a neutron star within a whisker of collapsing into a black hole, to see what gives.
994321
I'm afraid it won't explode now.\nIt won't go and explode as a nova or super-nova unless something real bad happens and it gets a denser core.\nOur star won't explode until at least 5 billion years time, unless anything makes it do it.\nThe term nova means very large explosion. But our star won't explode it will widen with a little explosive force and all of it's gaseous surface and mid layers will blow off.\nOur star is an M class (G Medium class) a super-nova will only happen with L class stars (O Large class) + (M Small class) the M and S class have novas only when they collide it is likely to be explosive as the stars are young and hot.\nThe main course of nuclear fusion is:\nD+T=4He+1n or 3-2H+2-1H=4He-3.5MeV+1n-14.1/14.2MeV\nThe sun will not explode in at least 1 billion to 5 billion years!
784870
seems you have no clue what you are talking about...\nwhat do you mean by how big of a neutron star ??
861406
(1000kg is not a ton, it is called a tonne or metric ton)\n\nThe object of 1000kg will have a force of acceleration on it of about 9.8m/s² during its fall of 5m.\n\nTo find the kinetic energy Ek that it will have at the end of its fall you just need to find its gravitational potential energy at the beginning of the fall.  By the end of the fall all the gravitational potential energy will have turned into kinetic energy.\n\nUg=(m)(g)(h)\n\nUg is grav. potential energy, m is mass, g is acceleration due to gravity, h is height\n\nUg=(1000)(9.8)(5)\nUg=49,000 Joules\n\nSo our Ek is also 49,000 Joules.\n\nThe object will land on the earth with 49,000 Joules of kinetic energy.\n\nNear the earth's surface, the object will have a force towards the earth of \nf=ma\nf=(1000kg)(9.8m/s²)\nf=98,000N\n\nAt the time of impact the composition of the earth will determine how much force the 1 tonne mass imparts on the earth.  If it lands somewhere soft where it can dig in far its kinetic energy will be eaten more slowly because it is pushing on the earth with a smaller force, if it lands somewhere very hard then the Ek will be eaten up very quickly as it will decelerate very quickly by imparting a large force on the earth.
1179562
No effect. They're so far away their magnetic and gravitational fields have only the most infinitesimal influence on the Earth.
701207
it goes super nova and then a neutron star the rest of its life.  its life is also shorter because the increased gravity requires more nuclear fusion (and faster fuel consumption) to negate.
830124
Nothin would happen.\nIf you consider two bodies the earth (name it E) and a large mass (m). \ninitially M rests on E. and you lift mass M. the force used to lift it will also act on E.\nAlso if you consider the mass M and E. as a system force exerted on dropping M would be internal and since internal forces do not cause acc. the Earth will not get unbalanced.\n\nThats good for us isn't it...
509966
Ummm that's not a real question.\n\nBut, if that happened, you'd end up with someone standing on the earth who observed that small particle moving in a direction opposite the earth's rotation at a speed that could be calculated by:\n\n(radius of the earth)*6.28*(1/30-1/24)
366136
Not really - As it would travel at the speed of light (or the lack of) - but there would be a delay of a few picoseconds.....
619335
well if it were in a medium where it is obstructed by external forces,it would continue till the 0 point and stop... but when unobstructed it would keep travelling.
70654
Here is an answer i found in physlink.com\n\n"Stars and Planets form as a result of the gravitational collapse of accreting material. Any net translational motion of that initial material is accelerated as its radius of rotation decreases. This is due to the same conservation of angular momentum principle that makes skaters and divers spin more rapidly when they bring their arms closer to their bodies. In its extreme, this effect can make collapsed neutron starts spin many times each second, creating the regular beat of pulsars as observed from Earth.\n\nOnce an initial spin was established for the Earth, the same conservation principle says that its angular momentum will continue unless it can be transferred to another object. With no significant frictional forces to allow that to happen, the Earth can continue to spin indefinitely without any further prodding."\n\nCourtesy:- http://www.physlink.com/Education/askexperts/ae201.cfm\n\n\nBy the way...The speed of rotational (of Earth) at the equator is about 1,000 miles per hour.
220257
Depends on the distance you are from it. Close to the surface it is 9.81 m/s^2.\nThe gravitational force (and therefore the acceleration) decreases as the square of the distance from the centre of the earth. The surface of the earth is about 4000 miles from the centre - so if you flew 4000 miles above the surface of the earth, out into space, the acceleration would be 1/4 that of the surface... or about 2.45 m/s^2.
627291
Nothing.  A warhead would have no effect, since it would be fryed, melted, crushed, and sucked into the black hole.  It wouldnt even make it past 10 feet before all of that happenes to it from a black hole.
537690
Technically you'd start digging up when you reached the centre of the core and entered the 'the half' whether you'd immediatly feel the shift is questionable... I think as you got right close to the centre of the earth your sense of up and down would weaken, so it wouldn't be until you'd got some way away that you'd feel like you were going up...and yes once you'd got up you would fall back down due to gravity. Think of the gravity as those like the force on those playground things you can spin in circle and the centrifugual force can be used to mkde you spin faster or slower as you hold yourself close in or furtehr out...the further out you are the more you feel the froce...the closer in the less obvious it is.\n\nEdit: 8928 the core is solid... your talking about the mantle in which even rocks are molten.
952325
You would not feel any change. You were weightless before the star 'appeared'. And once you come under the acceleration (you might call it deceleration), you would still be weightless in the reference system of the interior of your spacecraft. You would be subject to the same gravity of this star as your spacecraft, and would still be free-floating. \n\nEven if your spacecraft were exerting thrust, you would feel only the force of that thrust on your body. Assuming you are in a seat, the seat has to push you to keep you moving at the spacecraft's velocity. Even though the acceleration due to the star is presumably much higher than that of the thrust, all you feel is the relatively small thrust. It's because you fall equally with the spacecraft. Think back to the last time you were in an elevator and the cable broke.\n\nYou would notice only if you looked astern, or it started getting hot.
1007746
Any radiatioactive isotopes from the blast would have dispersed to near ambient levels in a very short distance.  Certainly in less then 500 miles.
918873
If it were posible for the neutronium to exist in a plane, then yes, I think so. However, neutronium is so dense that its own gravity will pull it into a sphere. If you got close enough to look at it, it would pull you in and you would be a (very thin) stain on the surface.\n\nNeutron stars are supposed to be made mostly of neutronium. If two collided or got close enough for their tides to pull one apart, then small pieces might be left. But neutronium is supposed to be very unstable. It is only its own gravity that binds the electrons and protons together so that they merge and lose their identities. \n\nFor very massive neutron stars (just short of being black holes, I guess) their inner layers are supposedly a quark-gluon soup. \n\nFor very small ones or pieces broken off, if that is possible, if there is not enough gravity to keep the particles together, the electrons and protons will regain their identities and the nuclear interctive forces will reassert themselves, and the mesons will begin to interact between the electrons and protons again,. What would happen is that the small piece of neutronium would erupt in a burst of energy and high energy particles. \n\nS/F writers like H. Beam Piper (in the 60's) postulated that we would learn to control nuclear forces like we learned to control electricity and have (what he called ) 'collapsium' plated spacecraft, where the outer shells of the electrons were in contact with the nuclei (what we would now call 'degenerate matter'.) Such a plating (a tiny fraction of an inch thick) would protect like several feet of lead shielding. It would also weigh more than many feet of lead shielding! (He also proposed that we would have antigravity by now.)\n\nTheoretically, a sphere of neutronium would be perfectly reflective, and the noted s/f author Larry Niven used that feature in his classic story There Is A Tide (1968, Galaxy magazine.)\n\n15 NOV 06, 1632 hrs, GMT.