find the midpoint between (4,2) and (8, -1)?
816256
(4,2) (8, -1)\n\nAdd the x values together and divide by 2\n4 + 8 = 12\n12 / 2 = 6\n6 is your midpoint x value\n\nAdd the y values togethr and divide by 2\n2 -1 = 1\n1 / 2 = 1/2 or .5\n1/2 is your midpoint y value\n\nSo your midpoint will be (6, 1/2)
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
913982
Replace x with -2:\n4(-2)+y=10\n-8+y=10\n\nAdd 8 to both sides:\ny=18\n\nThe ordered pair is (-2,18)\n\nThe ordered pair means to find the x and y values.\n\nCheck:\n4(-2)+18=10\n-8+18=10\n10=10
387063
X=[-(30y-433)]/1232\nY=[-(1232x-433)]/30
1148035
Division, if you do not know how to divide can be done easily.\n\nTake the problem 32 divided by 8.  You would divide this out the long way.  The easiest way might be to subtract 8 until you get to zero.   You notice it take you 4 times of subtracting 8 to get to zero.  So your answer would be 4.
1113295
(1, 2, 3,4) or (-1, -2, -3, -4) or (1, 2, -3, -4) or (1, -2, -3, 4)\nYou also have\n(-1, -2, 3, 4), (-1, 2, -3, 4), (-1, 2, 3, -4), and (1, -2, 3, -4)\nSo there are 8 possibilities.\nEach having a probability of 1/8 or occurring.\nFor (1,2,3,4) and (-1,2,-3,4), the prob. of an even natural number is 2/4 = 1/2\nMultiply this by 1/8 to get the conditional prob.\n(1/2)(1/8) = 1/16\nFor each of the following: (1,2,-3,-4), (1,-2,-3,4), (-1, -2, 3, 4), and (-1, 2, 3, -4), the prob. of an even natural number is 1/4\n(1/4)(1/8) = 1/32\nFor (-1,-2,-3,-4) and (1,-2,3,-4), the prob. of an even natural number is 0.\n0(1/8) = 0\nAdd all these together.\n2(1/16) + 4(1/32) + 2(0)\n= 1/8 + 1/8\n= 2/8\n= 1/4\nThis doesn't match your solution, but you can see if this makes any sense to you.
1131526
median wud join A to mid pt of BC.\nmid pt of BC = (x2 + x3)/2  ,  (y2 + y3)/2\n\nlike this v hav 2 medians. (x1,y1) to  ( (x2+x3)/2 , (y2+y3)/2 ) \nand (x2,y2) to  ( (x1+x3)/2 , (y1+y3)/2 )\n\n\nnow 2 medians intersect in d ratio 2:1.\n\nby section formula: 2 get pt of intersetion;\n\n\n\n[ 2 {(x2+x3)/2} + x1  ] / (2 + 1)  and [ 2 {(Y2+y3)/2} + y1  ] / (2 + 1)\ni.e\n\n(x1 + x2+ x3)/3, (y1 + y2 + y3)/3
697523
For any line through 2 points (x-x1)/(y-y1)=(x2-x1)/(y2-y1); thus (x-0)/(y+5)=(8-0)/(9+5) or\nx=(y+5)*4/7 or 7x-4y-20=0 or 4y-7x+20=0 or y=1.75x-5 all are the same!
759679
heres copied direcly from my calculator to yours...\nmake two programs\nprgm mid:\nInput "X1:",A\nInput "Y1:",B\nInput "X2:",C\nInput "Y2:",D\nClrHome\nDisp " Midpoint, X=",(C+A)/2\nOutput(3,12,"Y=")\nDisp (B+D)/2\nDelVar A\nDelVar B\nDelVar C\nDelVar D\nOutput(1,1," ")\n\nprmn dist\nInput "X1:",A\nInput "Y1:",B\nInput "X2:",C\nInput "Y2:",D\nClrHome\nDisp "DIST="\nDisp root((C-A)2+(D-B)2)*****\nDelVar A\nDelVar B\nDelVar C\nDelVar D\nOutput(1,1," ")\n\nnote: in the distance one\nreplace root with the squareroot function and 2 with squared
829618
1.find the midpoint of BC usingthe midpoint formula\n(x1+x2/2,y1+y2/2) say (x,y)\n2.find the slope os BC using theformula \ny2/y1/x2-x1 say m\n3.the slope of the perpendicular bisector will be the negative inverse of this -1/m\n4. now use the point (x,y) and slope (-1/m) and find the equation of the perpendicular bisector
1149797
The first one is (-5, 3). I don't remember how to do the others.
293623
(y(1)-y(2))/(x(1)-x(2)) =\n(3-(-2))/(3-8) =\n(5)/(-5) =\n-1
413913
x=0,2,3,4 and y=1,-1,0,3
51216
x = [-(-4) +/- root((-4)^2 - 4x1x(-5))]/2x1\n  = (4 +/- 6)/2\n  = 5 or -1
367471
Add the x coordinates together and divide by 2.\nAdd the y coordinates together and divide by 2.\n(8+16)/2 = 12\n(3+7)/2 = 5\nMidpoint = (12,5)
414223
(x/2)-4=8\n(x/2)=12\nx=24
747439
(5)(5)-2(5)(-4)+(-4)(-4)\n=25-(-40)+(16)\n=25+40+16\n=81\n\nDon't forget that (-)(-)=(+) and (-)(+)=(-).\n\nGood luck!