Chemistry Question: Charles Law?
826679
Let's assume that the flask is upside down in a water bath.\nAt 100 C, it contains some water (volume = x), and a volume of hot gas (VH).  When cooled to 0 C, the volume of the gas decreases, and some water (214 mL) is pulled into the flask. The volume of the cool gas is now VC. \n\nSome relationships to get you started:\n\nVH - x = 300 mL\nVH - VC = 214 mL\n\nCharles' Law\n\nVC / TC  =   VH / TH\n\nor\n\nTH /TC    =    VH / VC
949162
Nobody, actually.  The Ideal Gas Law is a summation of three separately discovered laws by three different chemists:\n\n- Boyle's Law is named after Robert Boyle who published it in 1662.\n- Gay-Lussac's Law is named after Joseph Louis Gay-Lussac, who discovered it in 1809.\n- Charles' Law was discoverd by Jacques Charles in 1787, but he never published it.  Instead, it was referenced and published by Gay-Lussac in 1802 as he was doing other work.\n\nPerhaps the reason why no specific scientist is given credit for the combined Ideal Gas Law is that so many were working on it at the same time.  It's been pointed out that Avogadro might have had a version of it, and that almost anyone could have derived it mathematically if they just sat down and did the right kind of problem.
598319
http://www.sbuniv.edu/~ggray/CHE3345/chp14.html\nhttp://web.odu.edu/sci/tisenhou/chem321/chap12/index.htm\n\nbest luck
660043
1.) do your own homework\n2.) this is the computer forum, not high-school chemistry.  Next time post to the right furom.
592683
rate law = k [A] raised to the power of m [B] raised to the power of n [C] raised to the power of p\n\nwhere k = rate constant\nC = catalyst\nm,n,p = indiviual orders\nm+n+p = over-all rate\n\nin your example,\nrate law = k [HCl] raised to the power of m\n\n[Mg], since it is a solid, will always be 1\nwhile the order m, must be experimentally determined.
677826
1) is already balanced... to be more precise\n2C2H6 + 7O2 --> 4 C02 + 6H2O\n\n2) Fe2O3 + (3)H2SO4 --> Fe2(SO4)3 + (3)H2O
718914
Hi utkarsh teri eng se pata chalta hai what could be ur level.\nanyways..\nu can take K C Sinha books, S L Loney books, and I A moron(i dont rem it exactly, may be its I E Moron ) for Calculus.\nFor Physical Chemistry \n1) sarin and sarin\n2) just that i remembered many but now its not comming to my mind.\ni hope that books be useful to u.
848535
http://i24.photobucket.com/albums/c16/ScurvyBC/img007.jpg\n\nI drew it for you and uploaded it.\nWe did this activity in AP Chem where we had to build the models and draw them, and the teacher graded it and this is right. Oh but I forgot to draw the brackets around it with the negative charge symbol, so dont forget that!
782945
I won't do your homework for you, but you should look here:\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/carcr.html#cc1\n\nGood luck. :)
964798
This is a chem, not bio question
72077
Charles' law: If the volume of a container increases, the temperature of the gas inside increases.  If the volume of a container decreases, the temperature of the gas inside decreases.  \nIf the volume of the container increases, then the gas molecules must move faster and impact the walls of the container more often.  Therefore, the temperature must increase as well.
700450
Letters A, B, D.\nIn not sure about C, its wording is tricky.\nIdeal gas law : PV = nRT\nReal gas law : (P + (a(n / V)^2)) * (v - nb) = nRT\nThe corrected pressure times the corrected volume.
739878
I am not sure what you are asking but the answer could be a monoatomic ion. The positive being a cation and the negative being an anion.\n\nYou might ask over at http://forums.mychemistrytutor.com though.
512622
Ca(OCl)2 as far as i rem being taught in chemistry....U should have paid attention in ur class.....
95816
i believe c is the answer - not 100%
1138288
What do you want to know?  He is considered the father of experimental chemistry.  He is credited with describing the Law of Conservation of Mass.
805169
alright...\nconsider the R.H.S.\nh2o has two o-h bonds which account for 2x467 and since thre are 2 mol. u get 2x2x467--------(1)\nco2 has two c=o bonds which account for 2x799 and since u hav 4 mol. u get\n4x2x799-------------(2)\naddin 1 and 2 u get 1868+6392=8260\nconsider the L.H.S.\nu hav in c2h2, two c-h bonds which account for 2x413--------(3)\nand one triple bond accounting for 1x839---------(4)\nnow u hav 2x(3+4)=2x(826+839)=3330------(5)\nand u hav 5x(o=o) which acc for 5x(495)=2475----(6)\naddin 5 and 6 u get 5805\ntherefore ur ans is 5805-8260=-2455\nand since u want for one mol of acetylene u get -1227.5 kj/mole