Can you help me with this formula?
825337
NO! you have to replace V2 with given volumes:\nP = (V1P1)/V2\nP = (4 x 1)/3 \nP = 4/3 \n\nNow do the same thing for V2= 2. V2= 1 , V2= 5 and V2= 25
1001971
[(16x*2-25) / (24x*2-30x)] / [(8x*2-2x-15) / (6x*2-7x-3)]\n= [(16x*2-25) / (24x*2-30x)] [(6x*2-7x-3) / (8x*2-2x-15)\n= [(16x*2-25) (6x*2-7x-30] / [(24x*2-30x) (8x*2-2x-15)]\n= [(4x-5) (4x+5) (3x+1) (2x-3)] / [(6x) (4x-5) (4x+5) (2x-3)]\n= (3x+1) / 6x
565612
Take all the terms that include H to one side.\n\nS - 2LW = 2LH + 2WH.\n\nNow, factor out the H from the right side to get:\n\nS - 2LW = (2L + 2W)*H.\n\nNow, divide both sides by what it takes to leave H by itself.  In this case, get rid of the (2L + 2W)\n\n(S - 2LW)/(2L + 2W) = H
917250
I'm going off memory here so be sure to check this.  I think the formula is the same, but the structure may be different.  Just trying to point you in the right direction.
1114869
Here's a formula on this webpage you can use
747676
2C12H22O11 +24O2 ---> 24CO2 +22H2O\na)F\nb)F\nc)T\nd)F\ne)T\nf)T
904934
2HNO3 + Mg(OH)2 -->Mg(NO3)2 +2H20\n\n2H+(aq) + 2NO3-(aq) + Mg+(aq) + 2(OH)-(aq) -->Mg+(aq) + 2(NO3)-(aq) +2H20(l)\n\n2+(aq) + 2(OH)-(aq) --> 2H20(l)
89652
The formula involves complex maths calculations. Ask some maths professor.
635193
Drop me your email. I will do one and send it to you. Easier than explaining...just look at my formulas...will only take a minute...really...\n\nCheck your email\n\nIs what I gave you what you want?
943847
You must do your own homework. Here is a site that can answer questions about formulas that will enable you to do your own work. \nmathforum.org/dr.math
1132678
Directions how to do this can be found in the text book.\n\nDo your own homework!
238182
p1    p2\n--- = ---\nq1    q2\n\n 5     2\n--- = ---\n 2    q2\n\nCross multiply,\n\n4/5
1079085
use this formula\n55x54x53x52x51/120
971390
{3XY^2M/1}-{2M/[X^-1Y^-1]^2\n+{[4X^2Y^2]/M^-1}-\n(3X^(3Y)^(3M)^-1/(XYM)^-2
844650
I am putting some example:\nThe formula is actually put in the fields below relults so remove the " to operate.\n\nItemRateQtyResultFormula\nBread1510150"+ d2 * c2"\nBread 22510250"+ d3 * c3"\n\nTotal400"=sum(e2:e3)"
564798
Ba(NO3)2 + Na2CO3-->BaCO3 +2NaNO3\n\nto do a double displacement follow this formula\n\nAB + CD --> AD + CB
703752
simply subtract 7 from both sides. This leave you with\n\nx<_3