How do find the surface area of a partially filled sphere?
814140
The surface area of a sphere is 4 pi r^2 or 12.57 r^2.\nThe area of a curved surface of a spherical segment of height h, and radius of sphere r is equal to  2 pi r h\nSo, the area a=2 pi r h
549577
The formula for surface area of a sphere is \nA = 4*pi(r^2)\n64 pi = 4*pi(r^2)\nwhich means r^2 = 16 or r = 4\nVolume of a sphere is \nV = (4/3)*pi (r^3)\nV = (4/3)*pi (4^3)\nV = (4/3)*pi (64)\nV = (256/3)*pi
315840
Surface Area of a Cylinder = 2 pi r 2 + 2 pi r h\n\n(h is the height of the cylinder, r is the radius of the top) \n\nSurface Area = Areas of top and bottom +Area of the side \n\nSurface Area = 2(Area of top) + (perimeter of top)* height \n\nSurface Area = 2(pi r 2) + (2 pi r)* h \n\nIn words, the easiest way is to think of a can. The surface area is the areas of all the parts needed to cover the can. That's the top, the bottom, and the paper label that wraps around the middle. \n\nYou can find the area of the top (or the bottom). That's the formula for area of a circle (pi r2). Since there is both a top and a bottom, that gets multiplied by two. \n\nThe side is like the label of the can. If you peel it off and lay it flat it will be a rectangle. The area of a rectangle is the product of the two sides. One side is the height of the can, the other side is the perimeter of the circle, since the label wraps once around the can. So the area of the rectangle is (2 pi r)* h. \n\nAdd those two parts together and you have the formula for the surface area of a cylinder. \n\nSurface Area = 2(pi r 2) + (2 pi r)* h
820928
I am guessing that you want to know how big one of the sections are, so that's what I will try to determine.\n\nThe first step is to find the surface area of the hemisphere with a radius of 18 meters:\nThe surface area of a sphere, with r as the radius, is: A = (4)(π)(r²). Since this is a hemisphere, we can divide the expression equal to the surface area by 2, leaving us: A = (2)(π)(r²).\nA = 2(π)(18²) = 2(π)(324) = 648(π)\n\nSince we know that the surface area of the hemisphere is 648π m², we can divide this by 12 to find out the surface area of one of the sections:\n648π / 12 = 54π meters² ≈ 169.65 meters²
918429
use the formulas your given\nto find the volume of the cylinder\nthen pretend the semi hemi on  the top is a sphere find the volume and multiply by 1/2\n\nadd two totals to find volume
586130
surface area = 3bh, where b is length of side, and h is the height dropped normally from center to any of the sides\n\nvolume = 6 times volumeof each triamgle, formed by all 3 diagonals
1175861
Area of Semicircle = (PI * R * R)/2\n\nAns. = 2.262 sq. cm
730124
1. volume = h*2*pi*r^2 =1000 so r^2= 1000/2/pi/h\n\nsurface area = 2*pi*(h+2*r^2)\nsurface area / volume = (h+2*r^2)/h/r^2 \n=1/r^2+2/h  = 2*pi*h/1000+2/h  which is a minimum when h is about 17.84  [(1000/pi)^0.5]
250763
you split it into 2 ,a cone and a cylinder. first u need the slanting height of the cone and you find this by pythagorus theory for triangles ie L2 = h2 + r2, so height=6(found by subtracting the 15 from 21) radius=10 (20/2)therefore L2=6x6+10x10=136 therefore L =sqr root of 136 =11.6 surface area is A=pi*r*L\npi=3.142 so 3.142*10*11.6 = 364.5sq ft now the cylinder the surface area of a cylinder is circumference × h, or 2πr × h\nso 2*3.142*10*15 =942.6 so 942.6+364.5=1307.1 sq ft to find quantity of tins 1307.1/250=5.2 so they need 6 full tins you must check the formulas and calculations as I may have made a mistake ok
653555
Not considering the spheric harmonic of high orders I would have to tell you that my physics spirit tell the surface area  is what counts and there you could have k0.2Pi.R=2Pi <=>k0=1/R\nk1=1/(2R), k2=1/(distance of the 3 points more away from each other)........................
809750
Ratio of what?\nSurface area?\nVolume?\n\nI will go with volume.\n\nassume radius of sphere is = 1\n\nsphere = 4/3pi\ncylinder = 2pi\ncone = 2/3 pi\n\neat the pi's (get rid of them) and multiply what's left by 1.5\n\nSphere:Cylinder:Cone = 2:3:1\n\nI hope that helps
894074
Assuming the drop of water is a sphere or close to one...\n\nvolume of a Sphere = (4/3) * pi * radius^3\n\nTo find the volume of a drop, measure out a small volume of water into a graduated cylinder.\nUse a dropper to take drops and deposit them into another container.  Count the number of drops needed to empty the measured water.\nvolume of drop = measured volume / number of drops
1178530
Surface Area of a Cylinder = 2 pi r 2 + 2 pi r h\n\n\nr=radius\nh=height\n\nnote: the 2 after the 2 pi r is a square
196800
Surface area. Seriously. 8D
921006
Area = πab where a and b are the semi-major and semi-minor axis length
549797
enclose the ireegular shape with a rectangle and find the empty spaces. then subtract that with the area of the enclosed rectangle to get ur answer.
522898
Imagine you unraveled the cylinder, the middle would turn into a rectangle, right? so to find the surface area, take the height of the cylinder and multiply it by the circumference of the circles at the bases, then add in the area of the circles. Circumference is 2(pi)r and area is (pi)r^2.