Help math question!!!?
823152
-3/5 + 8/35\nYou need a common denominator.\nSince 5 goes into 35 evenly, the common denominator will be 35.\n5*7 = 35, so wee need to multiply the top and bottom of the first fraction by 7\n-3/5 (7/7) = (-3*7)/(5*7) = -21/35\nNow we can add the numerators.\n-3/5 + 8/35\n= -21/35 + 8/35\n= (-21+8)/35\n= -13/35
920470
The answer is:  4.47, and that's all there is to it!\n\nOk Vanessa, all you have to do is pull up your calculator (Start>Accessories).\nI am not suggesting you don't work it out in your head first: it's just basic. Check the answer on the calc, or, if you get stuck....go back.... to POWERS OF HIGH HOLY ROOTISM   SQUARE YOU KNOW, 1x1+(2x2)+2+(10-5)/1=       Simple:\n1+4+2+5/1=12
891258
Try 1 ÷ 3\n\n1/3 = 0.33333.....\n\n~ ♥ ~
865538
i would guess this is 3rd or 4th grade?\n\nyou could use a calculator of course . . .\n\nto show your work, you need to do it on paper\n\ngood luck!
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
708585
What sort of help do you need with fractions? It depends. Or you can try math.com\n\nYou have to look a little to actually find what youre looking for, but mostly its good \n\nHope this helps!  :)
60599
This is not an equation.  Its garbage.  Both side of the equation have to equal each other.\n-35=.000075 this does not compute
777951
Tackling the problem bit-by-bit:\n\nFirst, let x = the larger number\nlet y = the smaller number\n\nYou can write out an equation to show their relationship of "difference" by:\nx - y = 68\n\nNext, you write out the equation to show their quotient relationship by:\nx/y = 5\nwhich gives:\nx = 5y\n\nNow plug x = 5y into the "difference" equation:\n(5y) - y = 68\nwhich gives\n4y = 68\nwhich gives \ny = 17\n\nNow plug y = 17 into the "difference" equation:\nx - 17 = 68\nx = 85
1142924
It's a math question...lol backatcha
218316
Thats funny.  Tell me another one.\n\nMaybe its like 5-2=2\n\n\nlol
233465
A.) (4*3) / (11*10) = 0.10909090909090909090909090909091\nB.) (7*6) / (11*10) = 0.38181818181818181818181818181818\nC.) this can be treated in 3 cases:\n\n(i) both defective (similar to letter A)\n    (4*3) / (11*10) = 0.10909090909090909090909090909091\n\n(ii) first is defective second is not\n    (4*7) / (11*10) = 0.25454545454545454545454545454545\n\n(iii) first is not defective second is\n    (7*4) / (11*10) = 0.25454545454545454545454545454545\n\nTake the sum of the 3 cases and you'll get 0.61818181818181818181818181818091
969084
OMG a math riddle I cant seem to answer!!!! :-)  Awesome. I cant sleep because now i want to knwo the anwer. And so i continue to try and solve it.\n\nBest i can come up with is 113  or 240 or 50-something..\nAlso maybe another number in the 100-n-teens\n\nI did find a 1-3-4 pattern aasuming the next number in 1-3-4-1 was a 3 but was unsure of how to continue it. (its1230 in the moring here)\n\nAnd again another possible patter 1-3-4-8 next number would be 16.\n\nI know some may not even know how I came up with these, but I love math and I love a challenge. I have been trying to find any possible correlation in the numbers that I can. \n\nHope someone figures it out. I know I cant wait to see the answer.
947480
Do your own homework . \n\nI'll help you anyway since you probably haven't done your homework in ages.\n\n\n1.3\n2.$234,896\n3.$625\n4.$2.00\n5.$10.00
779807
Yiu would first decide how many decimal places you are going to consider.  The usual is 3.  Then work it from there...;
609300
This is more of a word problem or a riddle than a math problem.\n\nThe answer is 7 (SEVEN).  Remove its first letter and it becomes EVEN!
53373
Here are a few sites you can check out:\nhttp://www.freemathhelp.com/\nhttp://www.mathgoodies.com/\n\nHope these sites can help you..
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}