z = 2d + 1/2yx^2 (solve for x)?
822825
z-2d=1/2yx^2\n2(z-2d)=yx^2\nx^2=(2/y)(z-2d)\nx=+/-rt[(2/y)(z-2d)]
764329
x(abs[x- (x^2)] (-1=2)\n\n:> peace\n.
896553
4x^2+8x-x-2\n(4x-1)(x+2)
906876
2cos^2x-1+1/2sinxcosx\n=2cos^2x/2sinxcosx\n=cosx/sinx\n=cotx
678157
2x^2(1-2x)=0\n\nx=0\nx= (1/2)
581691
if by this you mean\n\n((x^2)/2) - ((7x)/4) = (-3/2)\n\nMultiply everything by 4\n\n2x^2 - 7x = -6\n2x^2 - 7x + 6 = 0\n(x - 2)(2x - 3) = 0\nx = 2 or (3/2)\n\nANS : x = 2 or (3/2)
108506
y=az+(-6/49)\n(6/49)a+ya=z\n\nam i right or close i hope
830984
You have to first eliminate one variable from two of the equations which would leave two equations with two variables.\nThen eliminate one of those two variables to get one value.  Plug this in to get a second value; plug these in to get the third.\n\nFor example in your problem b, if you multiply the second row by -1 and add it to the first row, that would eliminate z\n\n(2x - 1y = 1)\n\nThen divide the third row by 2 and add it to the (original) first row, which also eliminates z\n\n(20x - 4y = 16)\n\nNow take those 2 rows, eliminate either x or y, and start plugging in
983933
(x+y+z)(x+y+z) = x^2 + y^2 + z^2 + 2xy + 2xz + 2yz = 1\n\n(1-x^2 - y^2 - z^2) = 2xy + 2xz + 2yz\n\n(1 - x^2 - y^2 - z^2) \n------------------------ = xy + xz + yz\n.............2\n\nClearly the left hand side is less than 1/2
677039
(1) { -2x-y-z=0\n(2) { -x-2y-z=0\n(3) { -x-y-2z=0\n\nLet's look at (2):\n-x-2y-z=0 => x=-2y-z\nNow at (3):\n-x-y-2z=0 => x=-y-2z\nNow we can see that\n-2y-z=-y-2z => *** y=z ***\n\nNow let's put these values into (1):\n-2x-y-z=0 => -2x-y-y=0 => -2x-2y=0 => 2x=-2y => *** x=-y ***\n\nFor now, we know that x=-y=-z\nLet's put all of what we know into (2), and express everything using 'x':\n-x-2y-z=0 => -x-(-2x)-(-x)=0 => -x+2x+x=0 => 2x=0 => *** x=0 ***\n\nThus, x=0 => y=-0=0 => z=0\nSo the only solution is (0,0,0).\n\nGood luck!
356024
x + y + z = t\n\nx +x% + y + y% + z + z% =\n[(100 + 1)( x + y + z)]% =\n101t% = t + t%. So\nx +x% + y + y% + z + z% = = t + t% or\nx% + y% + z% = t%
123389
distribute the x to all terms inside the equation\n\n2x^2-26x
201432
x=2 and y =2,\n\n2^2=2^2 and 2*2 = 2 + 2 =4
162589
x^2 + y^2 = z^2\n\ni don't feel like fiddling with my calculator right now.
1027362
(1+2)/2=3/2\n1+(2/2)=2
822539
first multiple everythingby x, then simplify and solve:\n\n1/x-2 = 3/x+3 =>\n\nx/x - 2x = 3x/x +3x =>\n\n1 - 2x = 3 + 3x =>\n\n-2  = x
423853
[2x^{2}+ 2x2y]+[2x2y+2x^{2}]+\n[6yz^{9}+3y^{2}9z^{8}]+\n[3y9z^{8}+y^{3}72z^{7}]\n\nthis is using z as the last term.  Based on what I used, I think a 3D parabola of sorts will emerge