What are the steeps involved in preparing a 0.530 M copper (II) acetate solution, Cu(CH3CO2)2 ?
822325
a) Find some Acetic Acid (CH3COOH)\nb) Find some Copper (II) Hydroxide (Cu(OH)2)\nc) Add to form Cu(CH3CO2)2 + 2H2O\n\nWithout the volume or the number of moles, preparation of a 0.530M can be done several ways. \n\n2CH3COOH + Cu(OH)2 --> Cu(CH3CO2)2 + 2H2O\n\nUsing 1L:\n0.530 mol of Cu(CH3CO2)2 means 1.060 mol of CH3COOH\n\n1.060 / 0.5L = 2.120M\n\n0.530 mol of Cu(CH3CO2)2 means 0.530 mol of Cu(OH)2\n\n0.530 / 0.5L = 1.060M\n\nSo mix 500mL of 2.120M Acetic Acid with 500mL of 1.060M Copper (II) Hydroxide.\n\nN.B. Being a weak acid, acetic acid will not fully react with copper hydroxide, and hence the actual molarity requiredmay be higher.
958410
1.\nMn(s) + SnCl2(aq) --> MnCl2(aq) + Sn(s)\nCr(s) + 2HBr(aq) --> CrBr2(aq) + H2(g)\nCo(s) + CaBr2(aq) --> N.R\n2Al(s) + 3Ni(NO3)2(aq) --> 2Al(NO3)3(aq) + 3Ni(s)\n\n2.\nMg + 2AgNO3 --> Mg(NO3)2 + 2Ag\nmole of Ag = 3.580 / 108 = 0.033 mole\nmole of AgNO3 = 0.033 mole = 33 mmole\nmolarity of AgNO3 = 33 / 50 = 0.66 M\n\n3.\na.soluble\nb.soluble\nc.soluble\nd.insoluble\ne.soluble\nf.soluble\ng.insoluble in water, soluble in acid\nh.soluble\n\n4.\n3NaOH(aq) + Fe(ClO4)3(aq) --> Fe(OH)3(s) + 3NaClO4(aq)\n3Na+ + 3OH- + Fe3+ + 3ClO4- --> Fe(OH)3 + 3Na+ + 3ClO4-\nFe3+ + 3OH- --> Fe(OH)3\n(NH4)2SO4(aq) + Pb(NO3)2(aq) --> PbSO4(s) + 2NH4NO3(aq)\n2NH4+ + SO42- + Pb2+ + 2NO3- --> PbSO4 + 2NH4+ + 2NO3-\nPb2+ + SO42- --> PbSO4\n\nHope it helps\npeace\nvixklen
857898
2Al + 3*(CuO) -> Al2O3 + 3*Cu\n\nI2 + 2*(Na2S2O3) -> 2*(NaI) + Na2S4O6\n\nI2 + 5*(Cl2) -> 2*(ICl5)
416566
CH3COOH is an acid (systematic name is ethanoic acid, more commonly known as acetic acid, which is found in vinegar)\n\nSince metal + acid --> hydrogen + salt: \n2Al + 6CH3COOH --> 2Al(CH3COO)3 + 3H2
221298
2.5% copper, 97.5% zinc
1053722
Here's are a few:\nhttp://www.science-house.org/learn/CountertopChem/exp25.html\nhttp://www.chymist.com/copper%20silver%20gold%20expl.pdf\nhttp://chemlearn.chem.indiana.edu/demos/15-7%20TheGold1.htm
355760
It's [Cu(NH3)6]2+ or hexaamine copper (II)
445522
Acetic acid (HC2H3O2, or CH3COOH). Vinegar.
497218
Some quick help now\n1. Brass is a solid solution; copper is the solvent and zinc is the solute it is also an alloy so it may get you 6 as well. \n2. A bottle or can of a soft drink unopened is LeChatelier's Principle. It is at stasis until it is opened, thus the volume is larger and the equilibrium is disturbed until it gets back to equilibrium by outgassing the CO2.\n3. Take salt and sugar and mix them together. Large state of entropy. Hard to unmix them. \n5. Volatile solid: mothballs - naptha. Viscuous liquid - container of car engine oil\n7. That is a mole of something. Water H2O - 2 Hydrogens + 1 oxygen  (2 X 1.00 + 1X 15.999 = 18 atomic mass units) = 18 amus expressed as grams = 18 grams has 1 mole 18 grams of water is 18 ccs. So get something that holds 18 ccs or 18 mls of water. Small bottle.
920228
CuSO4•5H20\nThe dot notation denotes the hydrate.
707894
Cu 2+ ClO3 1-\n\nCu(ClO3)2
372026
CuSO4·5H2O(s) → CuSO4(s) + 5H2O(g)
801118
CuCl2 + 2NH4OH --> Cu(OH)2 + 2NH4Cl\n\nCu(OH)2 (s) + 4NH3 (aq)     ----->     Cu(NH3)4^2+
139382
First, you dissolve your compound in the solvent in which is is most soluable (perhaps THF or methylene chloride).  Then you very carefully use a pipette to layer the solvent in which it is not soluable on top (perhaps diethyl ether or pentane).  You need to add the second solvent slowly and carefully.  Let the solvent run down the side of the container.  Obviously the top solvent needs to be less dense than the bottom one.  You then let the container sit undisturbed on the bench or in the freezer away from any vibrations until crystals form.  As the upper solvent diffuses into the lower solvent, you compound will become less soluable until it falls out.  The first solution should be as close to saturated as possible.
799504
FeS + 2HBr --> FeBr2 + H2S\nFe2+ + S2- + 2H+ + 2Br- --> Fe2+ + 2Br- + H2S\n2H+ + S2- --> H2S\n\nK2CO3 + CuCl2 --> 2KCl + CuCO3\n2K+ + CO32- + Cu2+ + 2Cl- --> 2K+ + 2Cl- + CuCO3\nCu2+ + CO32- --> CuCO3\n\npeace\nvixklen
211591
Ca3PO4 and CuOH\n\n^^those are the answers
929071
2C18H18 + 45 O2 --->  36 CO2 + 18 H2O\n3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O