If A < B and B < C; what can be said about A's relationship to C?
817396
Since B is in the middle, lets set B as 0 for example purposes.  A would be any negative number (A<B) and C would be any positive number (B<C).  Since there are no 'or equal to' symbols, A<C.  This is true for all possilbe cases.
649445
1.D\n2.B\n3.B\n4.A\nright?
533029
Let's call :\n(a) : x + 2y < 3\n(b) : 2x - 3y < 6\n\nWith the 1st one:\nx + 2y < 3\n<=> 2x + 4y < 6 \n\nThe 2nd one is 2x - 3y < 6\nThat means : \n(a) - (b)\n<=> 4y - (-3y) < 0 \nor 7y < 0 \nor y < 0\n\nWe have also: 2x - 3y < 6 <=> (2/3).2x - (2/3).3y < (2/3).6\n<=> (4/3)x -  2y < 4\nThat means:\n(a) + (b)\n<=> x + (4/3)x < 7\n<=> (7/3)x < 7\n<=> x < 3\n\nSo : x < 3 and y < 0
281098
p(ab) usually means the probability that a occurs AND b occurs.  by contrast p(a|b) means the probability a occurs GIVEN THAT b has occurred.
894883
I'm going to guess that you meant to ask:\n\n"if x->t and t->z, then x-> z."\n\nI.e. The statements "if x, then t" and "if t, then z" imply that "if x, then z".\n\nThis is a logical rule of inference called "hypothetical syllogism".\n\nA classic example of it is:\n\nSocrates is a philosopher.  All philosophers are human.  Therefore, Socrates is human.\n\nHope that's what you wanted.
296681
either A, B, or AB is possible
48168
D. If a variable some times equal to its both of the bounds, it will be mentioned or written as [a,b] generally called as values between a and b inclusive of a and b both, as per the case mentioned here, the variable can take any value between a and b inclusive of a, so a<= variable < b written as [a,b[
71105
C is the logical answer...
664969
What you are saying is that A, B and C either always tell the truth, or always lie.\n\nLet's assume that A is telling the truth (in family T) when he says "either I belong or B belongs to a different family from the other two".\n\nWe already are assuming that A is in T (truthtellers).  So that would mean that B is in the family of F (liars).  We can't determine if C is in T or F because in either case, the statement could be true.\n\nOn the other hand, A could be lying (F family) and then his statement would have to be false.  So that would mean that B is in the F family also.  Again we can't tell what family C is in.\n\nSo the possible combinations are:\n\nABC: TFT\nABC: TFF\nABC: FFT\nABC: FFF\n\nThe best we can tell from this information then is that B must be in the F family (liars).  You can't tell anything about A or C without additional statements.\n\nAnswer: B is in the family of liars (F)
1060440
I'm assuming that C' means not-C, rather than another variable.\n\nABC+ABD+C'D\n= ABC + ABD(C+C') + C'D\n= ABC + ABCD + ABC'D + C'D\n= ABC(1+D) + C'D(AB+1)\n= 1ABC + 1C'D\n= ABC + C'D\n\nWrite out the truth table and you can easily see that this is the case.
691129
<> means 'not equal to'\n\nThe C/C++ equivalent is != \n\n a <> b : means 'a is not equal to b'\n 5 <> 6 : gives the value True\n 5 <> 5 : gives the value False
1155894
If you mean like A, B, AB, O ... yes.
6232
B dont mean B\nB may be BB or OB\nand A mean AA or OA\nso the baby may come OO in one case \nif she is OB and he is OA\nthe baby may be\n\nOO=O \nOA=A\nOB=B\nAB
854360
S=(c-b)/(b-a)\nSb-Sa-c+b=0\nc=Sb-Sa+b\nc=S(b-a)+b\nHowever you like it.
1120942
A=  C - B divided by (x + y).\nB= C - A divided by (x + y).\nC= A*x + B*y\n\n* = multiply
415746
conditional statement and its inverse
807646
Ok, this is where MATH comes in. It's called variables. Youneed to plug in NAMES. A is your signifigant other B is their Ex. using this formula I was able to understand the question. Now, understanding the question, I can answer it! (aren't I smart? LOL!) Well, I'd have to get the whole story. It would REALLY upset be because I'd really care for A, obviously. So after A told me the whole story, then I would be able to apologize. Since B was already out of the picture it wouldnt' be an issue. I would warn A that he probably shouldn't be talking to B anymore but that any other B's that he knew, that I should be with him so they didnt' get any ideas.