How many unpaired electron would be found in the ground state of Vanadium?
814740
Look at the proton number, which is 23. That means the electron arrangement ends in 3d3 4s2.  Hund's Rule suggests that the 3d3 electrons go in separate orbitals before being forced to pair up, so a V atom has 3 unpaired electrons.
191934
Two in the first shell. 10 in the second shell. 10 in the third shell. 5 in the 4th shell for neutral Manganese. Mn 2+ is missing 2 electrons, so it would only have 3 in the outer shell. The rest will stay the same.\n\nHere's a cool interactive periodic table that may help you with your homework. \n\nhttp://www.webelements.com/\n\nYou can click on the the element you are interested in, then in the column on the left you can go to electronic properties and it will show you how the electrons are distributed. You can add or remove electrons to configure the electron arrangement of various ions of the substance you are interested in.
803831
14 of each\n\nhttp://www.webelements.com/webelements/elements/text/Ag/ionz.html
932025
You mean the Valence Shell Configuration?\n\nIt is easy to find this by simply looking at the Group # (these are the column numbers). \n\nElements in Group 1 all have 1 electron in their valence shell, Elements in group 2 have 2 and so on...\n'\nIf you mean how many shells there are then look at the Period #  this is the horizontal groups) the Period # corresponds with the number of electron shells.\n\nElements in Period 2 have 2 electron shells, elements in Period 3 have 3 and so on...
350793
The frezing point (also the melting point) of Vanadium is 1910 degrees C (3470 degrees F).
821637
1 break up the compuond into ions or ions and radicals in this case there are no radicals.\n2 place the charges of each ion to the upper right of the symbol and viola e.g. \nBa2+  Fl-
969429
92 protons and 92 electrons\nIsotopes have a different number of electrons
770837
1) 2\n2) 4\n3)17\n4) Ar\n5) 118\n6) metallic\n7) 92U239\n8) has its valence electron farther from the nucleus\n9) americium and curium\n10) Ne0\n11) 20\n12) neutrons\n13) 1\n14) 8\n15) +2\n16) hydrogen\n17) 18\n18) 17\n19) an ion\n20) proton
1010723
First the electron would have an sp1 configuration not np1.  As to which orbital it would revolve in...it doesn't matter.  The x, y, and z are just ways to distinquish the 3 different orbitals.  the point in the center is a null point.  the electrons do not actually travel through that spot.  Orbital configurations just define a volume where an electron might spend some of its time.  it could be found anywhere in the volume.
312552
A two-color three-photon ionization technique, using two pulsed dye lasers, was employed to explore the high-lying energy levels of U I. A number of new U I levels in the 34 290--35 120-cm/sup -1/ region was observed.^Uncertainty in the assignment of J values to some levels known from earlier studies was also reduced or removed.\n\nHUH? Is that what you want?\n\nEDIT\nAbstract. Two-colour resonance ionization spectroscopy was used for identification of 240 new levels of 238U in the energy range of 38 500 to 41 200 cm-1. A precision of +or-0.03 cm-1 (1 SD) for the energies was obtained by using laser-induced fluorescence signals of I2 for spectral calibration. The angular momentum quantum number, J, was uniquely assigned for 134 of these levels by using angular momentum selection rules. \n\nThats a little more specific\nAnd some more\n\nAbstract. Visible and infrared absorption measurements on the  ion in tetragonal zircon-type matrix  are reported and analysed in terms of the standard parametrization scheme. The observed 17 main peaks and a number of less intense lines have been assigned and fitted to most of the 32 allowed electric dipole transitions with the root mean square error equal to . The free-ion parameters obtained for the model Hamiltonian, , ,  and , as well as the corresponding crystal-field parameters, , , ,  and , agree fairly well with the initial theoretical estimations. The results are discussed in relation to the previous spectroscopic study on the scheelite-type matrix .
1089354
Whatever its atomic number is, would be the number of electrons. If it's an ion, then add for every negative value and subtract for every positive one.
937724
Mg has 12 electrons\nwe will fill them from lower orbitals to higher\none orbital needs 2 electrons to fill in\n1s : one orbital, 12 electrons: 2e\n2s : one orbital, 10 electrons : 2e\n2p : three orbitals, 8 electrons : 6e\n3s : one orbitals, 2 electrons : 2e\n\nSeveral rules govern the placement of electrons in orbitals (electron configuration). The first dictates that no two electrons in an atom may have the same set of values of quantum numbers (this is the Pauli exclusion principle). These quantum numbers include the three that define orbitals, as well as (the hitherto unmentioned) s. Thus, two electrons may occupy a single orbital, so long as they have different values of s. However, only two electrons, because of their spin, can be associated with each orbital.\n\nAdditionally, an electron always tries to occupy the lowest possible energy state. It is possible for it to occupy any orbital so long as it does not violate the Pauli exclusion principle, but if lower-energy orbitals are available, this condition is unstable. The electron will eventually lose energy (by releasing a photon) and drop into the lower orbital. Thus, electrons fill orbitals in the order specified by the energy sequence given above.\n\nSo you will have to fill the electrons that have the same spin\nevery two electrons of an orbital have different spin but two electrons of two orbital can have the same spin\n\nyou can use a rectangle to represent for an orbital, an arrow to stand for an electron,( up or down is the spin of that electron )\ngood luck
747161
Answer:  SIX electrons\n\nI drew a diagram for you: http://server6.theimagehosting.com/image.php?img=untitled.34c.JPG\n\nElectron Configuration of Fe: 1s2 2s2 2p6 3s2 3p6 4s2 3d6 \n\nExplanation:  As you can see in the electron configuration above, there are 6 electrons in 3d orbitals of Fe in its ground state.
811889
No concrete way to work it out. Groups one and two take positive charges equal to their group number (Mg2+, Li1+ etc). Groups 3, 4, 5, 6 and 7 ionise to a negative charge of 8 minus their group number (Cl1-, O2- etc), though 3, 4, and 5 tend to resist ionisation and are much more commonly found bonded covalently. The Transition elements ion charges are virtually impossible to predict without an extensive knowledge of d orbitals etc..
36176
its when there are unpaired electron orbitals
433486
A paramagnetic substance contains unpaired electrons and tend to move into a magnetic field.\n\nLiquid oxygen does not exist formally with a double bond linking the two oxygens (O=O).  This form only exists at higher temperatures.  When a liquid at -214 to -183oC it exists as a di-radical.  There is a single bond between each oxygen, and each oxygen holds a single electron in its p-orbital.  The presence of these single electrons impart the paramagnetism.\n\nLiquid oxygen is also a pale blue colour due to the unpaired electrons.
1072620
Actually it is not magnetic but paramagnetic. That is that it is attracted by the magnetic field but does not remain magnetic once it leaves the field. Gaseous oxygen is paramagnetic also but is moving too fast to be affected by the magnets. The reason that it is paramagnetic is because the oxygen molecule has two unpaired electrons. Electrons not only go around the atom in their orbitals, they also spin, which creates a magnetic field. Unpaired electrons spin in the same direction as each other, which increases the magnetic field effect. When the electron in an orbital become paired with another electron in that orbital, the new electron spins in the opposite direction and this cancels the effect of the first electron. Note that according to Valence Shell Electron Pair Repulsion theory (VSEPR), O2 has no unpaired electrons but according to Molecular Orbital (MO) theory it does have unpaired electrons. Since liquid O2 does stick to a magnet, MO theory is better at explaining the behavior.