The angle of the sun?
823839
Step 1: find a place where the horizon is at the same altitude above sea level as the place you are standing. Standing on the coast or a boat, looking out to sea is best.\nStep 2: Look South from the northern hemisphere and north from the southern hemisphere\nStep 3: Take the reading at 12 noon (no Day Light Saving allowed.)
618473
It's relative to the plane of the Earth's orbit around the Sun, called the Ecliptic.
676514
The sun DOES rotate! It also revolves.
509207
Yes. You can use sine or cosine to determine the angle.\n\nSine x = Opposite / Hypotonuse\nSin x=5/13\nSin x=.38\nx=22.6*\n\nCosine x = Adjacent / Hypotonuse\nCos x=12/13\nCos x=.92\nx=22.6*
95409
When we're on equinoxes, ie, mid spring and mid fall, the sun is travelling on a path where its altitude at noon = your lattitude. \n\nSo lets take Montreal for example, at almost a 45 degree lattitude. Imagine a line drawn across the sky so that the highest point the sun is at is 45 degrees.\n\nLets move to summer. The angle the sun will be at, during noon on the longest day (the solstice) will be 45 + 23.5 degrees (the tilt of the earth) = 68.5 degrees.\n\nNow during winter, the sun will only climb to 45 - 23.5 = 21.5 degrees.\n\nif you've drawn these lines, you'll notice that the winter line is extremely shorter than the summer line - the amount of time the sun is above the horizon is shorter because you've dropped the arc line significantly, covering up more of the sun's path.\n\nI hope I've conveyed this adequately - the only way to properly see this is to picture it.
954514
umm just make them perpendicular to the sun.  wait till like 1 pm and put a pencil standing up on your panels and adjust the panel until there is no shadow. it is then perpendicular
248579
cause in Ur position the sun is not completely vertical , in which all times the vertical rays have the greater effect , so we will tilt it in a degree to make the rays vertical approximately to Ur panel
799966
the external angle\n\ni hope that this helps
737740
Follow ditz's advice (make a diagram) as you read these directions for solving the 4 problems:\n\n1. assuming that the sun is a point source and the earth's surface is flat:\nangle = arctan (6.25/10.1)\n\n2. assuming that the string forms a straight line, and that the end of the string is on the ground:\nsqrt(50^2 - 30^2)\n\n3. arccos (1.75/4)\n\n4. 30 cos (75 degrees)
94125
Eratosthenes knew that on the summer solstice at local noon on the Tropic of Cancer, the Sun would appear at the zenith, directly overhead — though Syene was in fact slightly north of the tropic.\n\nHe also knew, from measurement, that in his hometown of Alexandria, the angle of elevation of the Sun would be 7° south of the zenith at the same time. Assuming that Alexandria was due north of Syene- Alexandria is in fact on a more westerly longitude- he concluded that the distance from Alexandria to Syene must be 7/360 of the total circumference of the Earth.\n\nThe distance between the cities was known from caravan travellings to be about 5,000 stadia.\n\nThere were some errors in this calculation although today we can use his method using correct measurements. Syene is not exactly on the Tropic of Cancer, and is not directly south of Alexandria; nor is the Sun at infinite distance. (Eratosthenes knew the latter, but we are not told he corrected for it.) More seriously, angles in antiquity could be measured only to degrees or quarter-degrees, and measurement of overland distances was worse. He established a final value of 700 stadia per degree, which implies a circumference of 252,000 stadia. The exact size of the stadion he used is no longer known (the common Attic stadion was about 185 m), but it is generally believed that Eratosthenes' value corresponds to between 39,690 km and 46,620 km. The circumference of the Earth around the poles is now measured at around 40,008 km. Eratosthenes' method was used by Posidonius about 150 years later.
359151
No.  The angle between the sun and the moon as viewed from the earth is 180 degrees for the full moon pahse.  This means that the full moon and the sun are always on opposite sides of the earth.\n\nSince the moon is not always "in plane" with the sun, and your horizon is not perfect, it may be possible on occasion, depending on the geography of the horizon, and one's latitute to see the full moon rising as the sun is setting, or to see the full moon setting as the sun is rising.
59746
the sun weighs approximatly 2.0 * 10^30 kg\n\nto abisdad2004's answer i believe the site has a typo, they probably meant to the 30th power
278956
This has been asked and answered many times before:\n\nhttp://answers.yahoo.com/search/search_result;_ylt=Amylv82zdJRUVkmYew.javjpy6IX?p=temperature+of+the+sun
232256
Same direction as the Sun and the Moon, to the west.\n\n---Addition----\nChristina has a good point. If you were close to one of the poles, the stars would be just turning around and you could not tell if it is west or east direction.
450988
The angle is 36 degrees (10%). The chord length is 30.901699 cm = 2*50*cos(90-36/2) cm.
872347
The axial F-S-F angles is 173 degrees and the equatorial F-S-F angle is 101.4 degrees.\n\nThe sites below has a good diagrams and additional information:
705867
First, the Earth's Equator is tilted at 23-odd degrees to the plane of its orbit; second, the Earth is slightly flattened at the poles; and third, the Earth is spinning.  These have no effect around the time of the equinoxes.  However, at the solstices, the gradient of the Sun's gravitational field across the Earth's diameter causes the daytime equatorial bulge to be attracted more strongly than the nighttime equatorial bulge, so there is a torque apparently trying to pull the spin axis more upright relative to the orbit.  But, like a spinning top, angular momentum means that the effect is to push it sideways instead.  The tilt stays at 23-odd degrees, but the axis "precesses" and describes a great cone in a period of about 26,000 years.