What Are All The Factors Of 250???
824398
First do a prime factorization:\n250 / 2 = 125\n125 / 5 = 25\n25 / 5 = 5\n5 / 5 = 1\n\nSo 250 = 2 x 5 x 5 x 5\n\nNow do all the combinations:\n1 = 1\n2 = 2\n5 = 5\n2 x 5 = 10\n5 x 5 = 25\n2 x 5 x 5 = 50\n5 x 5 x 5 = 125\n2 x 5 x 5 x 5 = 250\n\nSo the positive factors of 250 are:\n1, 2, 5, 10, 25, 50, 125, 250\n\n(Note: Technically -1, -2, -5, -10, -25, -50, -125 and -250 are factors too but I assume they only want positive factors.)
52919
in many cases, you need innovative thinking.. Consider this:\n\n250*844 = 250*(4*411) = (250*4)*411 = 1000*411 = 411000\n251*844 = (250+1)*844 = 250*844 + 1*844 = 411000 + 844 = 411844\n\n37*123 = 37*3*41 = 111*41 = (100+10+1)*41 = 4100+410+41 = 4551\n\nsometimes, do not oversimplify...\n105*598 = (100+5)(600-2) = 100*600 - 100*2 + 5*600 - 5*2 = 60000 - 200 + 3000 -10 = 62890 (not good)\n\n105*598 = 105*(600-2) = 63000 - 210 = 62890 (better)\n\nThe key is, you have gotta practice a lot.\nFor example, when I see 111*41, I wrrite down in a peice of paper like this:\n\n(* = space)\n41**\n*41*\n**41\n----\n4554
287987
3,000,000\n\n\nIf you mean 5,250,000 is the 35% of an amout you don't know... and you wanna know how much is the 20% of this unknown amount... then it's 3,000,000.
330778
100.\n\nIf 5 are defective in 250, then 20 will be defective in 1000.  If 20 are defective in 1000, then 100 will be defective in 5000.
780226
lets take the common multiple 210\n15,35,21 and 2 are the factors\nI was thinking of 105 but only 15.35.21 come to my mind
598359
approx 50 - 75\n\nit depends
235594
83.3, 41.6, 41.6\n\n5000 / 5 = 1000 / 4 = 250 / 3 = 83.333 / 2 = 41.666 / 1 = 41.666
27190
250\n\nSteps:\n176% = 1.76\n\n440/1.76 = 250
676245
Dat depends on a whole lot of factors
831410
factors of 32 are 1, 2, 4, 8, 16, 32\nfactors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, 80\n\nGreatest common factor is 16.
859764
I'll do the first one.  The others are the same\n\nSQRT(250*y^6) = SQRT(250) * SQRT(y^6)\n= SQRT(25)*SQRT(10)*y3\n= 5*SQRT(10)*y^3
572405
This is the way you find them all\n100 = 1 x 100 = 2 x 50 = 4 x 25 = 5 x 20 = 10 x 10\nFind yourself the dividers of 360 and 300.
255534
5^2 = 25\n100^2 = 10,000\n15^2 = 225\n\nso 25 + (10,000*225) = 2,250,025\n\nor did you mean\n\n(25 + 10,000) * 225 = 2,255,625
627277
(^^you forgot 41)\n25\n\n2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97
271143
Is that 2 times n cubed?  If it is, the answer is n = 5.\n\n250 = 2*n^3\nn^3 = 250/2  = 125\nn = cube root of 125 = 5\n\nto check, 5 x 5 x 5 = 25 x 5 = 125
486669
It depends on where or what city, up to 250K.
958614
#1.)-----------------------------------\n  \n25b^ -20by + 4y^\n\nMultiply 1st and 3rd term together to get 100b^y^.\n\nFactor 100b^y^ into two factors whose sum = the middle term of -20by.\n\n1by   X 100by\n2by   X 50by\n4by   X 25by\n5by   X 20by\n10by X 10 by   ....................BINGO!\n\n-10by + (-10by) = - 20by   &   (-10by)(-10by) = 100by\n\nThis is a really kewl factor by grouping trick, I LOVE it!\n\nBring down the first term of: (25b^)\n\nNext, write the SMALLER of the two factors 1st.  Followed by the LARGER of the two factors.  In this case, they're both the same, so it doesn't matter which one goes first: (-10by)\n\nFinally, bring down the third term of: (+4y^)\n\n25b^ -10by -10by + 4y^\n\nNow, lets factor by grouping! \nFactor out the GCFs.\nGCF#1 = 5b\nGCF#2 = -2y\n\n(25b^ -10by) + (-10by +4y^)\n5b(5b - 2y) -2y(5b - 2y)\n\nGCF#3 = (5b - 2y)\n\n(5b - 2y)(5b - 2y)\n\nSimplifies further as: (5b - 2y)^   ....Whatdayaknow?! \n.......................................................................................................It's a Perfect Square Trinomial.\n\n#2.)------------------------------------------------------------------\n\n100 - 9b^\n\nAh, the difference of two perfect squares.\n\n---------------------------------------------\n\nFORMULA:\na^ - b^ = (a-b)(a+b)\n\n---------------------------------\n\nSOLUTION:\n100 - 9b^\n(10)^ - (3b)^\n\n-----------------------\n\nANSWER:\n(10-3b)(10+3b)