Can you use the given doubling time to predict the population in 2010, 2060, and 2100?
815301
month population\n0 1000\n1 1200\n2 1440\n3 1728\n4 2074\n5 2488\n6 2986\n7 3583\n8 4300\n9 5160\n10 6192\n11 7430\n12 8916\n13 10699\n14 12839\n15 15407\n\n\nThe doubling time is 3.8 months (=x where 1.2^x=2);\nAssuming the population growth rate does not change, the population in 2010 (48 months away) will be \n2^(48/3.8)*1000=6,345,767 (estimated)\n1.2^48)=6,319,749 (calculated)\n\nFor 2060, number of months=54*12=648\n2^(648/3.8)*1000=2.155*10^54\n1.2^648*1000=2.039*10^54\n\nFor 2100 NUmber of months = 94*12=1128\n2^(1128/3.8)*1000=2.282*10^92\n1.2^1128*1000=2.072*10^92\n\nThus the doubling rule works quite well even for the distant future.
758583
dP/dt = 0.069762e^(0.011t) * 10^9\n\nSince I think the population should be in billions of people per year.
735975
I choose a time period in the future... by at least 1000 years.  So... perhaps 3506.  Why?  Just to see how it all shakes out.  1000 to 1500 years might be enough time for humans to actually overcome human nature and truly advance.
524563
The United States conducts a census every ten years.  The next one will be in 2010.
1025564
It depends on which 10 years.  If it has two leap years in it (like 2001-2010) it would have 315,532,800 seconds (60*60*24*3652).\nIf it has 3 leap years (like 2000-2009) it would have 315,619,200 seconds (60*60*24*3653)
1044100
I Don't know but maybe next millennium
959922
Probably the same as the Population.
1179086
how could we possibly predict  this?
51580
Not quite. Years divisible by 100 are not leap years unless they are also divisible by 400. 2000 was a leap year, 2100 won't be a leap year.\n\nSo every 400 years you get 97 leap years, slightly less that 1/4.
943178
A = A_(0)*exp(k*t) \n\nA represents the amount at a given time t.\n\nAo represents the initial amount of the growing entity.  Note that this is the amount when t = 0.\n\n\nk is a constant that represents the growth rate.  It is POSITIVE when talking in terms of exponential GROWTH.\n\n\nt is the amount of time that has past.  If the information for time is given in dates, you need to convert it to how much time has past since the initial time.  For example, if the model is set up at an initial year of 2000 and you need to find out what the value is in the year 2010, t would be 2010 - 2000 = 10 years.\n\nYou can use this formula to find any of its variables, depending on the information given and what is being asked in a problem.  For example, you may be given the values for Ao and t and you need to find the amount A after the given time.  Or, you may be given the final amount A and the initial amount Ao and you need to find the time t.\n\nSome examples of exponential growth are population growth and financial growth.  The information found, can help predict what a population for a city or colony would be in the future or what the value of your house is in ten years.  Or you can use it to find out how long it would take to get to a certain population or value on your house.
185308
harldy ever, check out wikipedias calendar stuff... it goes into the next few millenia
852208
Sorry but milleniums are measured in years. there are 1000 years in a millenium.
680571
POSSIBLE maybe in 2030
40369
U.S. and World Population Clocks - POPClocks\nPopulation Clocks\nU.S. 297,846,028\nWorld 6,489,395,497\n00:09 GMT (EST+5) Jan 05, 2006 \nNote: The U.S. POPClock is consistent with Census 2000 data and the most recent national population estimates.
426897
7 182 in 1990, 13 598 in 2001.\nNearly doubled in 10 years.
789712
Let x be the number of years.\nLet n be the amount of increase in people\nLet p be the initial population in year "0"\n\nf(x) = p + n(x/10)\n\nFor example, if you had 100,000 people, and it increases by 10,000 people every 10 years, your equation would be:\nf(x) = 100,000 + 10,000(x/10)\n\nThis can be simplified to an increase of 1,000 every year.\nf(x) = 100,000 + 1,000x
708889
"The number of days in 1000 years is 1000 times 365, plus 250, minus 10, plus either 2 or 3, depending on which 1000 years we're talking about (there are 25 leap years in every century.  \n  \nThat would give us either 365242 or 365243 days in 1000 years. \n\nThere are 24 hours in each of those days, 60 minutes in each of  those hours, and 60 seconds in each of those minutes: \n\nTotal seconds: 315,569,088,000