6 cosh x is equal to the integral 6x^4+12x^3+24x^2+48x+96 dx.Find x.?
828746
6 cosh x = 6/5 x^5 + 3x^4 + 8x³ + 24x² + 96x + C\n\nIf C is not given, then x can be any real number.  That's all.\n\n^_^
790277
ill give it a shot - im not sure , anyways i got 2 answers..\n\n(1st)\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6x = 2-4x\n\nx+4x+6x = 2+1\n\n11x = 3\n\nx = 3/11\n\n\n(2nd possible answer)\n\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6/x = 2-4/x\n\n-5 = -2/x\n\n-5x = -2\n\nx = -2+5\n\nx = 3
1109407
-4(3-x) = 2(x+6) \n-12+4X=2X+12 use distributive property\n-12+4x-2x=2x-2x+12 move the variable x onto 1 side \n-12+12+2x=12+12 isolate the variable x\n2x=24\n(2x/2)=24/2\nx=12\n\nCheater!
479850
Firstly, we have to multiply all of the eqautions together.\n\nxy*yz*zx \n\n= 6*9*24 \n\n= (xyz)^2 \n\n= 1296\n\nNext step is to find the square root. (Let V = square root)\n\nV1296\n\n= 36\n\n= xyz
769323
6 - 12x\n-or-\n-12x + 6\n\n-or-\n\n6(1-2x)\n\n...although that depends on whether you want the simplest expanded form or the simplest factored form.
909143
take out the x\nx(a-b)=6\nx=6/(a-b)
827232
d/dx of rtx=1/2rtx\nd/dx of (6x^2)=12x\nd/dx of (x^2+1)^10\n=10(x^2+1)^9*2x\nd/dx of rtx(6x^2)(x^2+1)^10\nd/dx of rtx[(6x^2)(x^2+1)^10]\n+rtx*d/dx(6x^2)(x^2+1)^10\nd/dx of (6x^2)(x^2+1)^10\n=6x^2*d/dx(x^2+1)^10\n+(x^2+1)^10*d/dx of 6x^2\nrest i think you can complete
1042657
I think you mean 4x/((x+6)(x+6)) + 3/(x-6).  You need a common denominator.  In this case it will be (x+6)(x+6)(x-6).\n\nSo we get 4x(x-6) + 3(x+6)(x+6) as the new numerator.\nThis equals 4x^2-24x + 3x^2+36x+108 = 7x^2+12x+108.\n\nFinal answer: (7x^2+12x+108) / ((x+6)(x+6)(x-6))
685308
(3x + 6/4(x^2)) (x + 2/16(x))\ntake out x\n=x(3 + 3/2(x)).x(1 + 1/8)\n=9/8(x^2)(3 + 3/2(x))\ncan simplify d numbers still.
543539
No.\n\nX=24\n\nGet a common denominator and multiply it by all three terms -\n\nx/6*(48) - x/8*(48) = 1*(48)\n\nsimplified becomes:\n8x - 6x = 48\n2x = 48\nx = 24\n\nIf you substitute "24" for the "x", you'll see that this solution is correct:\n\n24/6 - 24/8 = 1\n4 - 3 = 1
980949
sol: x^2-6x=3\ncoeff of x is 6, so divide it by 2 and square the no. i.e u get 3^2=9\nadd this no. on both sides of equation\nx^2-6x+9=3+9\nx^2-6x+9=12\n(x-3)^2=12\nx-3=+12^1/2 ,-12^1/2  (this is square root of 12)\nx=3+12^1/2,3-12^1/2
536107
Is 24(x/12)+36(12-x/x) supposed to equal 32? (because then the answer would not be 32)\nor is x supposed to equal 32? (the answer still would not be 32)
1151870
this is a u sub problem\n\nlet u = sin(2x) than du = 2 cos 2x dx and than du/2 = cos(2x) dx\n\nnow subbing it in we get \n\nint(1/2 u^5 du)\n\nwhich is 1/2 x 1/6 u^6 = 1/12 sin^6(2x) + c
667337
x^2+5x-24 = 3x\nx^2+2x-24 = 0\n(x+6)(x-4)=0\nsoln: {-6,4}
966462
(6x^2)/(4x^2 y-12xy) * (x^2 + x - 12)/ (3x^2 + 12x)\n\nFirst, I would attempt to simplify if possible:\n2x(3x)/x(2xy-6y) * (x^2 + x - 12)/ (3x^2 + 12x )\n(3x) / (2xy - 6y) * (x^2 + x - 12)/ (3x^2 + 12x)\n\nRewrite to see if we can cross cancel:\n\n(3x)           (x^2 + x - 12)\n---------  *   -----------------\n(2xy-6y)    (3x)(x + 4x)\n\n1               (x^2 + x - 12)\n---------- *  -----------------\n(2xy-6y)     (x+4x)\n\nUnfoil the (x^2 + x -12 to see if we can further simplify\n\n(x^2 + x - 12) = (x -3)(x+4) so you will have:\n\n1             (x-3)(x+4)\n-------  *  --------------\n2y(x-3)      (x+4)\n\nBy simplification:\n\n1           (x-3)\n------   * ----------\n2y(x-3)     1\n\nBy Cross Cancel:\n1/2y
1098481
6(2x + 8) - 6 =0\n12x + 48 - 6 = 0\n12x + 42 = 0\n12x = -42\nx = -42/12\nx = -3.5
747790
(3*2) cos 3x * (2.5*2)cos 3x\n\nwhich is equal to=(6 cos 3x * 5 cos 3x)\n\nwhich is equal to=30cos^2 3x