Imagionary zeros and GCF?
824137
1. 2 or 0\nGCF= greatest common factor?\n2. 12x\n3. 2x\n\nnotation for power is 2^5
1092588
actually, a googolplex is NOT 1 with 100 zeros. That's a googol. A googolplex is 10^(10^100) or 10^googol and can not be written as zeros as it would take more ink then there is matter in the universe to write.
892605
(constant)/(2^n) when n->infinity => the limit is 0(zero)\n\nPS\nNot to be a a stickler for rules but is this really laptop related ? :))
1065017
I'm writing up a proof right now that this is not possible.\n\nCheck out the pdf at:\nhttp://www.geocities.com/euleratuo/
362894
Division by zero is undefined.
26155
You should use scientific notation to describe this number. Correctly expressed, this number is 1*10^n where n is the number of zeros you typed. (I don't know how many zeros follow the ...)
707641
another zero would be the conjugate of the one you know,\nthen try the rational zeros test, or even syn div
894466
Uh...one and one-fourth degrees below zero.  (Is this a trick question?)
945266
Does 0.9999999999999999999999999....(continued) = 1.0\n\nA great topic in maths which will actually interest people because the above statement is true.
241288
What goes wrong is the loss of information.  All _n_ divided by zero goes into the same "infinite quality".\n\nIt is possible to admit different infinite numbers; this is Robinson's approach with "nonstandard analysis", and then there are a myriad of choices as what to admit and what to disallow.  If you take that approach, it is still easier to disallow n/0 as undefined, and permit other "zeroes" where n/d is defined, where d is one of those classes of zeroes.\n\nIt is exactly equivalent, however, to the following:\nlim(d->0) n/d.  In this case the limit doesn't exist, but there are other "zero approaching denomenators" where the limit does exist.  One very important one:\n\nlim(d->0) sin(d)/d = 1
600360
In w(w-4) there are two factors being multiplied.  One, as you know, is w-4.  The other is w.  To use the zero factor property, you set each factor equal to 0.  This means that you will set w equal to 0 as well as setting w-4 equal to 0.
624780
No way, Common Multiple is infinite series which keeps on increases. Hence there is no limit on multiples, ie GCM doent exist,...
49698
your variable m stays for "miles".\nYou thus just have to put 295 instead of m and do the exact reckoning: 0.05*295 + 30  14.75 + 30 = 44.75\n\nNow choose from the options the one which is closest to your number: 45\n\nIn this way you cannot do wrong
866033
1 followed by 10^50 zeros\n\nSince a googolplex (notice it's googol, not google like the search engine) is a 1 followed by 10^100 zeros, the square root of that is just half the exponents; just like sq.rt. of x^2n = x^n.\n\n~ ♥ ~
561184
a)\ni: s may not be zero, as m/s would be undefined\nii: s=m/(x-z)\nx may not equal z, or you'd be dividing by zero again...\niii: x=z+m/s\nas part i, s may not be zero\n\nb) √(x²-4) may not be zero, so x may not be ± 2\nfurther, if -2<x<2, then √(x²-4) will be a complex number, so for both T and A to be real, x would have to be greater than 2 or less than -2...\n\nif the subject is changed to x:\nx=√[(A/T)²+4]\nthen T can't be zero
907364
Almost.  You would actually include the endpoints 0 and -3 (so you need to use a bracket instead of parentheses).\nD = [0, infinity)\nR = [-3, infinity)
460848
no there doesnt. If you solve the congruences one at a time and use your solution for the previous congruence in the next one, you will eventually get the colution 1 congruent to 0 (mod7) which is obviously impossible