Algebra problem, please help!?
827600
Let the time of the appointment be t in hours, with now being time zero.  Then in the first case, she travels a distance of 66t kilometers.  In the second case, she travels 90(t - 2/3) kilometers, because 40 minutes is 2/3 hours.  Just solve the algebraic equations 66t = 90(t - 2/3) for t, and then evaluate either of the distance expressions.
872966
1.) 3 &#92;/ x+2 - 4 = 3\nif you mean\n3 sqrt( x+2) -4 =3,\nthen\n3 sqrt(x+2) =7\nsqrt(x+2) = 7/3\nx+2 = 49/9\nx=49/9 -2\n\n2.) &#92;/ x+3 - &#92;/2x-8 = 1\nsqrt(x+3) -sqrt(2x-8) =1\nsqrt(x+3) = sqrt(2x-8) +1\nx+3 = 2x-8 +2 sqrt(2x-8) +1\n-x + 10 = 2 sqrt(2x-8)\nx^2 -20x + 100 = 4 ( 2x-8)\nx^2 - 28x  +132 =0\n'
342762
x2+5x-2x-10\n\n*answer*\n\nx2+3x-10
955298
The KEY to solving any algebra problem, as I tell my students, is to get your unknown variable all by itself on one side of the equal sign.\n\nYou do this by "undoing" everyingthing that's being done to it right now.  And you "undo" the easy stuff first, like addition and subtraction, and then the more complicated stuff like multiplication and division.\n\nSo if you're adding 3 to X, then you would subtract 3.  And remember, what you do to one side of the equal sign, you MUST do to the other, so you would need to subtract 3 from both sides in my example.
896553
4x^2+8x-x-2\n(4x-1)(x+2)
123892
3(x – 2)^2 – 3(x – 2) – 6\n3((x-2)^2 - (x-2) -2)\n3(x^2-4x+4-x+2-2)\n3(x^2-5x+4)\n\n3(x-4)(x-1)\n\nYay!!
819891
2(x-6)=3x\n\n1.Distribute the 2 to the X and the 6. \n2x-12=3x\n\n2. Subtract the 2x from the left side and subtract it from 3x\n-12 = 1x\n\n3.flip the problem so it looks pretty!\nx = -12\n\nYour Welcome :D
945604
1.adding-2f-7\n-6f-2f+7-7<2f-2f-9-7\n-8f<-16\ndividing by -8\nx>2\n\n2.5/8g-4>2/3g+6\nadding 4\n5/8g>2/3g+10\nmultiplying by 24\n15g>16g+240\nadding -16g\n-g>240\ndividing by -1\ng<-240\n\n3.sum incomplete\n\n4.-2 1/9d+3/5<-3 2/9d-4 2/5\n-19/9d+3/5<-29/9d-22/5\nmultiplying by45\n-95d+27<-145d-198\nadding 145d\n50d+27<-198\nadding -27\n50d<-225\ndividng by 50\nd<-5 1/2
51473
x+3  This is the right answer, because there is no =s sign in the problem.\n\n3x+9-2x-6\nx+3
1063248
To solve correctly, distribute two to x and -2, add four to both sides, and divide both sides by x:\n\n2(x - 2) = x + 3\n2x - 4 = x + 3\n2x = x + 7\nx = 7\n\nThe error that was made was trying to simply remove the parentheses instead of actually distributing 2 to both of its contents.\n\n-----\n\nIf this is not what you meant and I have read it backwards, this is the other interpretation:\n\n-----\n\nTo solve correctly, add two to both sides, then divide both sides by x:\n\n2x - 2 = x + 3\n2x = x + 5\nx = 5\n\nThe error that was made was trying to change 2x [2 times x] into 2(x - 2) [2 times the difference of x and 2]. This is not allowed.
779257
put x=6ab/(a+b)in the eq(x+3a)/(x-3a) + (x+3b)/(x-3b).\nthen you get(9ab+3a^2/3ab-3a^2)+(9ab+3b^2/3ab-3b^2)\nby bringing the common values out in numerator and denominator and cancelling the them we get\n(3b+a/b-a ) +(3a+b/a-b)\nso the answer is 2
321475
*(2x/(x^2-4)) + (5/2-x) - (1/2+x)\n*(2x/(x^2-4)) + (5/2-x)((2+x)/(2+x)) - (1/2+x)((2-x)/(2-x))\n*(2x/(x^2-4)) + (10+5x)/(4-x^2) - (2-x)/(4-x^2)\n*(2x/(x^2-4)) + (8+6x)/(4-x^2)\n\nyou should be able to get it from there
921810
2(4x+7)=2x-4\ndistribute\n8x+14=2x-4\n-2x from feach side\n6x+14=-4\n-14 from each side\n6x=-18\ndivide by 6\nx=-3\nand the next one\n-2(18-3y)=7y+2y\ndistribue and add light terms\n-36+6y=9y\nsubtract 6y from each side\n-36=3y\ndivide by 3\n-12=y\n:) welcome
940135
Use factoring.\nx2-2x-8=0\n(x-4)(x+2)=0\nso\nx-4=0 and x+2=0\nsolve\nx=4 and x=-2
131300
-8x+2=26\nsubtract 2 from both sides.\n-8x=24\ndivide both sides by -8\nx=-3
537832
(x/x-2)-(x+1/x)=8/(x^2-2x)\n[x(x)-(x-2)(x+1)]/[x(x-2)]=8/[x(x-2)]\nx^2-(x^2-2x+x-2)=8\nx^2-x^2+x+2=8\nx=8-2=6
5554
Solving the problem stepwise -\n(x - 8 ) ( x - 2 )\n= x(x-2) - 8(x-2)\n=x^2-2x-8x+2\n=x^2-10x+2\n\nThese two sites will help you for the concepts.