Can someone show how to work these algebra problems? Didn't see any examples like them.?
825005
66 divided by 400 will give the percentage\n\n12,000 - 10,920 = X\nX divided by 12,000 will give rate of decrease
807552
ok first you have to distribute on each side, remember to watch the (-) (+) signs.\n\n- 4 (x + 2) - 11 = 2 (- 2x -3) - 13\n_________________________\n  -8x + (-8) - 11= - 4x -6 - 13\n\nnow that you are done distributing the 4 and 2, you must start isolating the X's, I like the x on the left, and so will work it that way. it makes no difference though....if you like it on the right, that is fine too. so I will start with the 4, and remember whatever you do to one side you must do to the other. \n\n    -8x + (- 8) - 11 = -4x - 6 - 13\n    +4x                     +4x\n__________________________\n     -4x + (-8) -11= - 6 -13\n\nremembering you cannot subtract with positive and negative numbers  so be careful of the signs and change/change the subtraction to plus signs. so let's do that next.\n\n  -4x + (-8)  + (-11)= -6 + (-13 )\n\nnow that you have changed the signs as above, do the operations on both sides.\n\n   -4x + (-19) = (-19)\n\nnow yo umust further isolate the X, so move the (-19) from left to right, again what you do to one side you must do to the other.\n\n    -4x + (-19) = (-19)\n             +19     + 19\n________________\n              -4x  = 0\n\nnow divide out the  -4, which into zero is zero, therefore x= 0, thus any number plugged in for the x would result in an "x=0" answer. \n\nhope this helped, for more help ask yahoo answers, or try www.purplemath.com, it is a great math site!
571127
Try going to this website. The will explain it step by step and you can ask all the math questions you want. www.algebra.com
362703
Free Video lessons!   \nForum/Help Center  Ask for help and help others \nand much more\nhttp://www.algebra.com/
424681
substituiting your values you get (the values you gave are not very clear, can't make out whether positive or negative.\nAssuming all values are positive...)\ny-2 = 2(x-5)\ny-2 = 2x -10\n2x -y - 8 =0  is of the form ax + by + c =0
488305
Just do a search for "algebra." You'll find a lot of web sites, including:\nhttp://mathworld.wolfram.com/topics/Algebra.html\nhttp://www.purplemath.com/\nhttp://www.algebrahelp.com/
953940
Hi again \n\nY = √2x – 3 \n2x – 3 = y ²\nX =( y ² + 3 )/ 2\nf –¹ (x)  =( y ² + 3 )/ 2  =>   f –¹ (x)  = (x ² + 3 )/ 2   &  x ≥ 0 \n\nGood Luck \n try to solve them yourslef again if you got wrong , am sure you can solve them correctly , if you just try your best
851212
hmm im not quite in college yet, but i hope to be help.\ndo you know the values for f, h, v, and a?\nif you do, id substitute it in.\nthen square both sides. \nand then solve.
189233
The problem with this type of algebra problem is that it's hard to know the syntax (grammar) of the problem if it's just written out in words. For example, is it 2x - 9, all over x, or is x the denominator only for 9? It's confusing!So in the future, to make it clear, use brackets like this:\n\n****IF I am reading your problem CORRECTLY****, I would write it as:\n(((2x-(9/x))^2)-4) - (((x-(7/x))^2)-4) = ?\n\nBut put aside the whole brackets thing for a minute. \n\nNow, normally, it helps to break down the math probelem into parts, but it looks like you're learning to do exponents. If this is the case, you must have learned that exponents allow you to work certain problems quicker without having to break down the problem into small parts and solving them seperately. To remember what those exponent rules are, try both the links at the bottom of this post. You'll use exponent rules all through your life, so know them!
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You will find the worksheets at the website of http://www.algebra.com. This website is a free site. You can also pose Maths. questions there and will get answers at the cost of $0 (zero dollar).\n\nI am a free tutor there and you may see my lessons and solutions to problems at\nhttp://www.algebra.com/tutors/aboutme.mpl?userid=psbhowmick\n\nYou will find the worksheets at\nhttp://www.edhelper.com/algebra.htm
38332
(x-2)/(x^2-2x-15)+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(-2-x)(x+3)/(x-5)(x+3)\n\n[(x-2) + (x+3)(-2-x)] / [(x+3)(x-5)]\n\nANSWER :\n(x^2+4x+8)/((x+3)(5-x))
795656
The first thing you should remember is the phrase PEMDAS.  This is shorthand for parenthesis, exponents, multiplication/division, and addition/subtraction.  This is the order of operations in math.  You should solve all equations in this order.  So for the first one, you should first distribute (multiply) -7 with (3-3x).  After that combine like terms, i got 25x -30; you can also factor that to be 5(5x-6).  The same steps apply for the rest of the problems.  I hope it helps.
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
778763
1) (a - b)(x - y)\n2) (x^9 + y^3)(x^9 - y^3)\n3) (6x + 5)(x + 8)\n4) (x - 9)(x - 7)
873100
Here you go!\n\nhttp://www.math.com/homeworkhelp/Algebra.html
967876
1) 2a^3 - 13a^2b + 11ab^2 + 14b^3\n\n2) (2a-4b) (4a^2+8ab+16b^2)\n\n3)  (b-8)(b-1)=0\n      b=8   or    b=1\n\n4) 4m^3 - 26m^2 - 14m=0\n2m(2m^2 - 13m - 7)=0\n2m=0  or  2m^2 - 13m -7=0\nm=0  or    (2m+1)(m-7)=0\n                  m=-0.5   or  m=7\n\n so the final answer is m=0 and m=-0.5 and m=7
626330
1) 2x^2 + 3 = x\n2x^2 - x + 3\n\nQuadratic formula:\n[1 +/- sqrt(1-4*2*3)]/(2*2)\n[1 +/- sqrt(-23)]/4\n\nx= 1/4 + sqrt(23)/4 * i\nor\nx= 1/4 - sqrt(23)/4 * i\n\n2) (2m - 7)^2 - 2(2m - 7) - 24 = 0\nSay X = 2m-7\nSo: x^2 - 2x - 24 = 0\n(x-6)(x+4)=0\nx=6,-4\n\n2m-7=6\nm=13/2\n\nor\n\n2m-7=-4\nm=3/2