What about (5r^2)(-4r^-3)?
825103
No, you add exponents when you multiply, so you would have\n5*(-4)r^(2-3) = \n-20r^-1 = -20/r
838051
5(x – 2)^2 = 3\n(x – 2)^2 =3/5\nx -2 =+- sqrt(3/5)\nx=2+- sqrt(3/5)
96233
+5,+12, -5, -12, +3.3
871981
3 to the 5th power\nor 3*3*3*3*3
931130
-4(x+3)>=20    &     x-5< -2\n-4x-12  >= 20    &     x < 5-2\n-4x  >=  20+12   &    x < 3\n-4x >=  32      &    x < 3\nx >= -8   &  x< 3\n-8  <=  x  <  3\n(x lies between -8 and 3)
821366
2.7*10^-5\n7.041*10^5
770383
-4(3a+4b)= -12\n3(4a-5b)= -16\n\n-12a-16b= 48\n12a-15b= -48\n\n-b=0\nb=0\n\n3a+4(0)= -12\n3a= -12\na= -4\n\ncheck: 3(-4)+4(0)= -12
958505
x={-(-4) (+/-)√[(-4)^2 - 4(1)(-5)]}/(2(1))\n x= 4(+-)6/2\n x=5,   x=-1\n\nCheck:\n with x=5,  5^2-4(5)-5=25-20-5=0  OK\n with x=-1   (-1)^2 -4(-1) -5 = 1+4-5=0  OK
590233
Hint:\nDo a simple substitution u = x-5\nWhich means x = u + 5\n\nYou should get\n\n(2/5)(x-5)^(5/2) + 2(x-5)^(3/2) + C
948937
(-3,-3);(-2,0);(-1,1);\n(0,0);(1,-3)
491966
Negative plus negative is ALWAYS negative.\n(-5) + (-3) = -8\n\nNegative minus negative may be negative, positive, or zero.\n(-5) - (-3) = (-5) + 3 = -2\n(-5) - (-5) = (-5) + 5 = 0\n(-5) - (-8) = (-5) + 8 = 3\n\nNegative plus positive works the same as negative minus negative. See the examples above.
829601
8r^3(8-π) \n64r^3-8πr^3\n(2r)^3(8-π)
701733
4r^2 -8r+3= 0\n\ntwo numbers that add to -8 and multiple to (3*4)= 12 \n\nwhich is -6 and -2\n\nso 4r^2 -2r-6r+3\n\n2r(2r-1) - 3( 2r-1)\n\n2r-3 = 0 and 2r-1= 0\n\nr= 3/2 and r= 1/2
952689
5x+3y+z+5w=-2\n3x+2y+2z+4w=2\n2x+4y+3z-3w=-11\n4x-3y-2z+2w=-3\n\n=>\n5     3     1     5   I  -2\n3     2     2     4   I   2\n2     4     3    -3   I  -11 \n4    -3    -2     2   I  -3\n\nR4 - (4/5)*R1 , R3 - (2/5)*R1 and R2 - (3/5)*R1 will give\n\n5.0000    3.0000    1.0000    5.0000   -2.0000\n         0    0.2000    1.4000    1.0000    3.2000\n         0    2.8000    2.6000   -5.0000  -10.2000\n         0   -5.4000   -2.8000   -2.0000   -1.4000\n\nR4 - (-5.4/0.2)*R2 , R3 - (-5.2/0.2)*R2 will give\n\n5.0000    3.0000    1.0000    5.0000   -2.0000\n         0    0.2000    1.4000    1.0000    3.2000\n         0    0.0000  -17.0000  -19.0000  -55.0000\n         0    0.0000   35.0000   25.0000   85.0000\n\nR4 - (-37/17)R3 will give\n\n5.0000   3.0000    1.0000    5.0000   -2.0000\n         0   0.2000    1.4000    1.0000    3.2000\n         0   0.0000  -17.0000  -19.0000  -55.0000\n         0   0.0000    0.0000  -14.1176  -28.2353\n\nR4 / -14.1176 will give\n\n5.0000    3.0000    1.0000    5.0000   -2.0000\n         0    0.2000    1.4000    1.0000    3.2000\n         0    0.0000  -17.0000  -19.0000  -55.0000\n         0    0.0000    0.0000    1.0000    2.0000\n\nR3 - (-19)R4 will give\n\n    5.0000    3.0000    1.0000    5.0000   -2.0000\n         0    0.2000    1.4000    1.0000    3.2000\n         0   -0.0000  -17.0000         0  -17.0000\n         0    0.0000   -0.0000    1.0000    2.0000\n\nR3 /(-17) will give\n\n5.0000    3.0000    1.0000    5.0000   -2.0000\n         0    0.2000    1.4000    1.0000    3.2000\n         0    0.0000    1.0000    0.0000    1.0000\n         0    0.0000    0.0000    1.0000    2.0000\n\nR2- R4 will give\n\n5.0000    3.0000    1.0000    5.0000   -2.0000\n         0    0.2000    1.4000             0    1.2000\n         0    0.0000    1.0000             0    1.0000\n         0    0.0000    0.0000    1.0000    2.0000\n\nR2- (1.4)R3 will give\n\n5.0000    3.0000    1.0000    5.0000   -2.0000\n         0    0.2000    0.0000             0   -0.2000\n         0    0.0000    1.0000             0    1.0000\n         0    0.0000    0.0000    1.0000    2.0000\n\nR3 /(0.2) will give \n\n5.0000    3.0000    1.0000    5.0000   -2.0000\n         0    1.0000    0.0000             0   -1.0000\n         0    0.0000    1.0000             0    1.0000\n         0    0.0000    0.0000    1.0000    2.0000\n\nR1- 5R4 will give\n\n5.0000    3.0000    1.0000             0  -12.0000\n         0    1.0000    0.0000             0   -1.0000\n         0    0.0000    1.0000             0    1.0000\n         0    0.0000   -0.0000    1.0000    2.0000\n\nR1-R3 will give \n\n5.0000    3.0000             0             0  -13.0000\n         0    1.0000    0.0000             0   -1.0000\n         0    0.0000    1.0000             0    1.0000\n         0    0.0000   -0.0000    1.0000    2.0000\n\nR1-3R2 will give \n\n5.0000             0   -0.0000             0  -10.0000\n         0    1.0000    0.0000             0   -1.0000\n         0    0.0000    1.0000             0    1.0000\n         0    0.0000   -0.0000    1.0000    2.0000\n\nR1/5 will give \n1.0000             0   -0.0000             0   -2.0000\n         0    1.0000    0.0000             0   -1.0000\n         0    0.0000    1.0000             0    1.0000\n         0    0.0000   -0.0000    1.0000    2.0000\n\nAnd thats the final answer.\n\nSo, your answer is x=-2, y=-1,z=1, w=2\n\nVerification\na=\n     5     3     1     5\n     3     2     2     4\n     2     4     3    -3\n     4    -3    -2     2\nb= \n    -2\n     2\n   -11\n    -3\ninverse of a is\n\n    0.0250   -0.0250    0.1250    0.1750\n    0.4000   -0.4000    0.0000   -0.2000\n   -0.5125    0.6792    0.1042    0.0792\n    0.0375    0.1292   -0.1458   -0.0708\n\nThus,\ninv(a)*b = [-2 -1 1 2]'\n\nI hope i answered your question.\n\nAll the best
8794
5t+1>3t-13\n-> 5t-3t>-13-1\n-> 2t>-14\n-> t>-14/2\n-> t>-7\nKeep Asking
212399
move everything to one side...\n\nx^3+5x^2-x-5=0\n(x^2-1)(x+5)=0\n\nsolve each parenthesis\n\n1). x^2-1=0\nx^2=1\nx=+1 and -1\n\n2). x+5=0\nx=-5\n\nso the answers are 1, -1, -5
814005
the standard form for writing this is to start from the variable with the highest exponent...\n\n(3a^2+2a+5)-(a^2+a-6)=???\n\n3a^2+2a+5-a^2-a+6=???\n(distribute the negative sign (which is the minus operation for this case) to the second given)\n\n???=2a^2+a+11\n(add those that have the same variable, don't forget to consider the sign)