How do you read these numbers?
816949
Angle measurement, which is the meaurement behind latitude and longitude (the angle being at the center of the earth) are measured in degrees to start with, but to get the measurement more precise, degrees are divided into minutes, and the minutes are divided into seconds.  (Nothing to do with time measurement, except that a degree has 60 minutes, and a minute has sixty seconds).  So 54 35' 45.6" reads 54 degrees, 35 minutes, 45.6 seconds.
1127163
you line up the decimal points and subtract from right to left.\nExample:\n\n  2.10\n- 1.25\n_____\n   .85
832637
your question does not make sense, the numbers are impossible
1124460
Hold down the alt key and type the following 3-digit codes on the NUMBER PAD on the right:\n\ná = alt+160\né=alt+ 130\ní = alt+161\nó = alt+162\nú = alt + 163\nñ = alt + 164\nÑ = alt + 165\n\nAlso helpful:\n¿ = alt + 0191\n¡ = alt + 0161
220005
Use a string. Calculate the first 16 digits, then put them into a string and subtract that number from your value and then use it as though its scientific notation. For example\n3.141592653589793 is the first 16 digits. So convert that to a string and then multiply your deriving value by 1,000,000,000,000,000 and start again. Then strip out the decimal and append to the string\n"2384626433832795"\nand then\n"0288419716939937", "5105820974944592", "3078164062862089",\n"9862803482534211", etc. \n\nThis should allow you a very large item.\n\n\nThe other option I can think of is declare an array 5 or 10 digits each and then store the numbers in there. That might work.\n\n\nEither way, good luck!
718467
go to the Format column, and then go to Cells...\nIn that box, pick TEXT. it will display your number exactly how it is written.
1149797
The first one is (-5, 3). I don't remember how to do the others.
1113487
I'm not sure anyone has "taught" you anything yet.\n\nThe "base" of a number system indicates how many different digits are used.  The base also tells us the first value that will need two digits to be expressed.  We normally use a base 10 numbering system--10 is the first two-digit number.\n\nOctal is a base 8 numbering system.  The numbers in octal (counting up) are 0, 1, 2, 3, 4, 5, 6, 7, 10, 11, 12, 13, 14, 15, 16, 17, 20, 21, ...  As you can see, there are only 8 different digits used in this numbering system.  (By the way, the largest two-digit number in octal is 77.  The next number is 100.)\n\nHexadecimal is a base 16 numbering system.  That means that 16 must be the first value that requires two digits, so we borrow letters of the alphabet to give us enough digits.  Counting up in hexadecimal looks like this:\n0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1A, 1B, 1C, 1D, 1E, 1F, 20, 21, 22, ...\nAs you keep going, you can have a value like EA--both of those are digits.  The biggest two-digit number in hexadecimal is FF--the next number after that is 100.\n\nHow do we think about numbers in these other systems?\n\nRemember that in our base 10 numbering system the first digit (on the right) is the "ones" digit, the next digit is the "tens" digit, the next is the "hundreds" digit, and so forth.  Notice that these are represented as powers of the base.  That is, the first digit is the 10^0 digit, so take the value here and multiply by 10^0.  The next column is the 10^1 column.  The next column is the 10^2 column.  The next would be the 10^3 column.\n\nThe same is true in the other systems.  In octal, the first digit (on the right) is the "ones" column (8^0).  The next column would be the "eights" column (8^1).  The next column would be the "sixty fours" column (8^2).  And so forth.  So the octal value 427 means that we have 4 sixty-fours, 2 eights, and 7 ones (the decimal value would be 279).\n\nIn hexadecimal, the first digit (on the right) is the "ones" column (16^0).  The second digit is the "sixteens" column (16^1).  The next column would be the "two hundred fifty-sixes" column (16^2).  So the hexadecimal value 2AB means that we have 2 of the sixteen squares, A sixteens, and B ones (the decimal equivalent would be 683).\n\nThis doesn't give you nice neat formulas for converting (but you didn't ask for that).  But does this help make sense of these numbering systems?\n\nThe reason these are used, by the way, is that they both relate nicely to the binary numbering system--which is what machines use.  In binary (base 2), there are only two digits--0 and 1--on and off--so switches operate in a binary world.  Instead of talking in binary, the digits are grouped.  Octal corresponds to groups of three binary digits, while hexadecimal corresponds to groups of four binary digits.
774551
If it reads 5x^4, it means 5 * x^4. If it read (5x)^4, then it would mean 5x * 5x * 5x * 5x.
470294
Press Alt and the numbers 164 = ñ\n\nPress Alt and the numbers 165 = Ñ
513070
The answer is 384.I just don't realise why you can't check it on the calculater
500278
THe kind with numbers. LOL
49819
Hold on....10....20......25.....29..30....25..29\n\n25
130987
These are usually trick questions.  For example, when you type a 2 on a cheap calculator and turn it upside down, it looks like a 5.  So 2-55 :: 6 - 99 (because 6 upside down is 9).  \n\nThe second one, 23-3983::32-? (3,839 , 3,994 , 4,874 , 9,599) ,unless you typed the answers wrong, is 9,599 because the first number is the sum of the digits of the second one.
671756
The base values are:\n\nI - 1\nV - 5\nX - 10\nL - 50\nC - 100\nD - 500\nM - 1000\n\nThese can be placed together so that consecutive numbers that are equal or smaller are added, but if a smaller number comes before a larger one, it is subtracted. So VI is 6, but IV is 4.\n\nLines can be placed over any of the letters to multiply them by 1000.
675348
I agree with chapin4ever's answer.\nand the three digit number is the ASCII equivalent of the symbol.
359942
If you mean, how do you check to see if the number is valid, here's a simple regular expression:\n\n"^[0-9]{3}&#92;-[0-9]{2}&#92;-[0-9]{4}$"\n\nThe above matches:\n\n000-00-0000\n\nit does NOT match:\n\n0000-00-000\n00-000-000\n000000000\n\nJust use a regular expression validator against that and you should get match / no match results.