Algebra help PLEASE....?
831884
When you use functional notation, you put whatever is in the parentheses in the place of x in the original function.\n\nSo if f(x) = 3x\n\nf(x+1) = 3(x+1) = 3x+3\n\nIf f(x) = 2x\n\n3 + f(x + 4) = 3 + 2(x+4) = 3 + 2x + 8 = 2x + 11\n\nHope that helps.
128596
im great with algebra, ive been doing it for the past 4 years now non stop, email me and ill be more than happy to show you how to do it step by step and answer you questions\nzinger_38@yahoo.com
842934
Ok, first you must get the -8 and the x/-2 out of parentheses, so u just multiply them both by one. So then is -8 * x / -2. First, you do -8 * x, which is -8x. The problem then becomes -8x / 2. In this step, just don't mind the negative or the x and just put them back in at the end. So you're really just doing 8 / 2, which is 4. You must put the - and the x back in, so the answer is -4x. Ta Da!
1089643
http://www.algebra.com
576570
algebra...usually (well i do) set up a equation for everything, and solve for the variable. If u need help u can always get help in www.algebra.com .....
778763
1) (a - b)(x - y)\n2) (x^9 + y^3)(x^9 - y^3)\n3) (6x + 5)(x + 8)\n4) (x - 9)(x - 7)
1000586
# 1    \n(x+1)*(x+6)=x2 +x+6x+6=x2 +7x +6\n#2\n(y-6)*(y-5)= y2-5y-6y+30= y2-11y+30\n#3\n(a-2) * (a+10)=a2 +10a-2a -20= a2  +8a -20\n#4\n(x-1) *(x+1)= x2 -x+x -1= x2 - 1
833830
1. Evaluate 3x^2 + 5x - 8 when:\n\na) x = 2\n3(2)^2 + 5(2) - 8\n3(4) + 10 - 8\n12 + 10 - 8\n22 - 8\n14 \n\nb) x = -3\n3(-3)^2 + 5(-3) - 8\n3(9) -15 - 8\n27 - 15 - 8\n12 - 8\n4\n\nc) x = 0.62\n3(0.62)^2 + 5(0.62) - 8\n3(0.3844) + 3.1 - 8\n1.1532 + 3.1 - 8\n-3.7468\n\n2. Simplify: 4x - 3x^2 + 2x - x^2\ncollect like terms\n4x + 2x - 3x^2 - x^2 \n6x - 4x^2\n2x(3 - 2x)\n\n3. Simpilfy: (5 x 6^2 - 5 x 3^2)/( 3 + 2)\nUsing BODMAS or PEMDAS\nWe treat the problems in the brackets first\n{(5 x 6^2 - 5 x 3^2)}/(3 + 2)\n\nIn here we treat the multiplications first\n{(5 X 36) - (5 X 9)}/(3 + 2)\n(180 - 45)/5\n135/5\n= 27
845742
-2(x+1) + 4 = 6(x-2) + 8\n-2x - 2 + 4 = 6x - 12 + 8\n-2x + 2 = 6x - 4\n-2x = 6x -4 -2\n-2x = 6x - 6\n-2x -6x = -6\n-8x = -6\n8x = 6 (The minus signs cancel each other out)\nx = 6/8\nx = 3/4
919864
1.  ax + xb\n2.  21x^3 + 24x*2y\n3.  24x^2 + 31x + 10\n4.  24x^2 - 8x - 6\n5.  40x^3 + 66x^2 + 38x + 6\n6.  x^2 - 1\n7.  x^3 - 8
705997
2x+1\n------- =\nx\n\n(2x+1)(x - 2)(4x + 3)\n-------------------------- =\nx(x - 2)(4x + 3)\n\n8x³ - 6x² - 17x - 6\n-------------------------- =\n4x³ - 5x² - 6x\n\n8x³ - 10x² - 12x + 4x² - 5x - 6\n------------------- ----------------- =\n4x³ - 5x² - 6x\n\n...... 4x² - 5x - 6\n2 + ----------------\n..... 4x³ - 5x² - 6x
896553
4x^2+8x-x-2\n(4x-1)(x+2)
123892
3(x – 2)^2 – 3(x – 2) – 6\n3((x-2)^2 - (x-2) -2)\n3(x^2-4x+4-x+2-2)\n3(x^2-5x+4)\n\n3(x-4)(x-1)\n\nYay!!
864870
http://purplemath.com/modules/index.htm\n\nis an awesome resource for all kinds of algebra topics, even ones you may have forgotten and need to brush up on.\n\nTake a look at that one.\nUMRmathmajor
1039099
This is the answer i got when i worked out the problem\n1. You have to distribute the (x + 2) & (x + 1)....you do the by using the FOIL method....Firsts Outsides Insides Last and you get: x + 2 = x^2 + 3x + 2\n\n2. Get rid of the 2 on the left side by subtracting it on the right side and you end up with : x = x^2 + 3x\n\n3. Now you can move the x on the left to the right side too so you have: 0 = x^2 + 2x\n\n4. Pull out and x leaving you with 0= x (x+2)\n\n5. x = 0 and x = -2\n\nMy algebra is rusty but I think this is how it's done.
139621
Ran into a little difficulty, I can't find my math editor.\n\nBut here goes:\nx = (-b +,- SQRT(b^2 - 4ac))/2a\na = 3, b = -5, c = 2;\nx = (-(-5) +,- SQRT(25 - 24))/ 6\nx = (5 + 1) / 6; x = (5 - 1) / 6\nx = (1, 2/3)\nThis would have looked a lot better if I had my math editor!!!\n\nClarification: I solved your quadratic equation using the quadratic formula.\n\nMashi below simplified your quadratic equation, which you don't need the quadratic formula to do. Substitute the values of x I obtained by solving into the simplified equation, they will equal 0
872966
1.) 3 &#92;/ x+2 - 4 = 3\nif you mean\n3 sqrt( x+2) -4 =3,\nthen\n3 sqrt(x+2) =7\nsqrt(x+2) = 7/3\nx+2 = 49/9\nx=49/9 -2\n\n2.) &#92;/ x+3 - &#92;/2x-8 = 1\nsqrt(x+3) -sqrt(2x-8) =1\nsqrt(x+3) = sqrt(2x-8) +1\nx+3 = 2x-8 +2 sqrt(2x-8) +1\n-x + 10 = 2 sqrt(2x-8)\nx^2 -20x + 100 = 4 ( 2x-8)\nx^2 - 28x  +132 =0\n'