Math question on averaging weight?
829781
Add 115 and 110 together (225). Take this number and subrtact it from  [179 multiplied by 9]. Then take that number and divide it by seven.\n\nYou should get 198 pounds for all 7 men.
73747
if the weight of the person is measured on Earth to be equal to 85 N then the mass is to be equal to \n\nm = F/a = 85/9.8 = 8.67 Kg\n\nif the weighting is taken on the moon then the mass is equal to \n\nm = 85 / 1.67 = 50.9 Kg
383531
========\n\nApparently purity, calculation or measurement errors have been there.\n\nYou repeated the thrice from the same solution to get an average.\n\nTry another solution.
805324
Part a)\n\nVf^2 = Vi^2 + 2 * a * d\na = (Vf^2 - Vi^2) / (2 * d) = -4,489/162 = -26.7 m/s^2\nm = 220*10^3 / 9.81 = 22,426 kg\nF = m*a = -598,777 N\n\nW = F * d = 50,297,245 J\n\nPart b)\n\nF (from above) = 598,777 N\n\nI hope this helps!
312896
The 2 are unrelated ... if you have a weight for the product per m2 then you would multiply that by the m2 to get a weight.
718152
weight equals mass times acceleration due to gravity
524937
look here\nhttp://education.yahoo.com/reference/weights_and_measures/index?p=volume
794045
we have F= G*M*m/r^2  and F=weight\n\nwhen M=M and r= r/2 then F=G*M*m/ (r/2)^2\n\ntherefore F(new)= 4*F and hence new weight is 4 times.\n\nthis is due to change in the value of g(acceleration due to gravity)\n\nsince F=mg= G*M*m/r^2   and hence only g is effected\n\nand hence weight also changes mass remainig same.
131445
Torque is force*distance.\n\nFind the weight of the person (M*g) = 89kg *9.81m/s^2 \nM*g= 873.09 Newtons\n\nthere is a 1:3 lever arm there--> 4cm/12cm\nThe muscle is having to exert a force of 3*873.09N or 2619N\n\nThe torque around the pivot is 2619N @ 4cm (or .04m)\n2619N * .04m = 104.77N*m\n\nYour question says you want to "find the torque" yet you ask for the "forces pushing up".  Make sure you know which one you need.
261755
Keep in mind that what you're doing when you add the logs is multiplying the ratios.  Then dividing by 3 takes the cube root of that.  So averaging the values is the arithmetic average and averaging the logs is the geometric average.  Which one is fits what you're doing best?  You'll have to figure that out.  I'd guess the geometric average based on the formula you've given.
96684
About 3300 lbs - \nYou convert it and at least you'll do some of your homework.
70889
convert to Newtons from mN, then divide by gravity because F=mg. so you get .00000780/9.8
348023
weigh 3 in one and 3 in the other:\n\nif they are equal:\nweigh each of the other 2 in one pan each. One will be lighter, voila\n\nIf they are different:\ntake the lighter set of 3, weigh one in one pan and one in the other and hold one aside.  If one is lighter, voila, if they are equal it's the one set aside.\n\nthat's the whole thing in 2 weighings
908586
GB >= 0.6*(CS + GB)\n\n"cushion" variable U introduced : \n\nU >= 0 \nGB + U = 0.6 * (CS + GB)
153995
F=m*a\na=F/m = 3.5 x 10^7N/(2.0x10^6kg) = 17.5 m/s^2 or 1.8g
1081095
Consider an animal weighing 100 kg. If all his dimensions suddenly are multiplied by two, than it's volume and weight will be multiplied by 2x2x2 = 2^3. This argument results already in L(W) scaling as W^0.333. Close enough.
769928
T = 2pisqrt(l/g)\nl = g(T/(2pi))^2 = 9.80(1.0/(2pi))^2 = 0.25 m\n\n(The object's weight is irrelevant for small oscillations.)