Write an equation of the line that passes through the given point and has the given slope...?
819556
Hey, here's the setup for these types of problems.\nYou want the equation in the form of y = mx + b\nsince we know that x = 2, y = -7, and m = -1/5, we can plug these values into that equation to find the equation of the line that passes through the desired point. SO:\n-7 = (-1/5)(2) + b\n-7 = (-2/5) + b\nb = (-7)+(2/5)\nb = -33/5\nso the equation for the line is:\ny = (-1/5)x - (33/5)\n\nhope that helps!!
1163751
If you are given the slope(m) and a point on the line(x1, y1) you can write the equation of the line.\n\nYou take the y-intercept equation\ny =m*x + b and substitute x1 and y1 for x and y and get\ny1 = m*x1 + b    \nnow solve for b\nb = (y1-m*x1)\nsubstite b = (y1-m*x1) into the y-intercept equation\ny =m*x +(y1-m*x1)\nsubtract y1 from both sides of the equation\ny -y1 = m*x -m*x1\nbecomes the point-slope formula\ny -y1 =m*(x-x1)
911563
Here's 2 examples:\n\n1.) Given point (2,2) and (3,3), find the function.\nStep 1: Find the slope.\nSlope = rise/run = (y2 - y1) / (x2 - x1) \n(3 - 2) / (3 - 2) = 1/1 = 1.\n\nStep 2: Given the slope, find the y intercept by trying to find a point (0, y) that fits the 2 points above, and the slope given.\nUse the slope formula: rise / run = 1\n(2 - y) / (2 - 0) = 1 = (2 - y) / 2 \n2 = 2 - y\n-y = 0\ny = 0\ny intercept = 0, 0\n\nStep 3: Once you have the slope, you can write it in slope intercept form:\ny = mx + b \nm = slope, b = y intercept\ny = 1x + 0, or y = x.\n\n2.) (a harder one) Given point (1,4) and (-3, 2), find the function.\nStep 1: Find the slope.\nm = rise/run = (y2 - y1) / (x2 - x1) \n(4 - 2) / (1 - -3) = 2/4 = 1/2 = .5\n\nStep 2: Given the slope, find the y intercept at (0, y)\nm = rise / run = 1/2\n(4 - y) / (1 - 0) = 1/2 = (4 - y) / 1 \n4 - y = 1/2\n-y = -3.5\ny = 3.5\ny intercept = 0, 3.5\n\nStep 3: Write it in slope intercept form:\ny = mx + b \ny = .5x + 3.5
346120
The equation of a line in slope-intercept form is given by \ny=mx+b where m is the slope and b is the y-intercept.\nAll you have to do is plug the numbers in.\nso the equation is y=9x-3
180320
Draw any line passing through origin. Its equation is y = mx and the slope ‘m’ is y/x.\n\nNow move the line up (or down) through a distance‘d’ with out changing the slope. The line cuts the y-axis at a distance d from the origin. This is y-intercept.\n\nThe x-coordinates of all the points on the line remain the same whereas all y-coordinates increase (or decrease) by‘d’. But the slope remains the same and x coordinates also remain the same. Therefore we give a correction to y coordinate to keep m constant.\n \nDenoting +d or -d by ‘b’, the slope of the new line’ ‘m’ is (y- b) /x. \n\nThus the equation of any line in slope intercept form is \n\nm =(y - b)/ x. or y = mx + b.
920988
if the slope is undefined,the line will be parallel to the y axis and of the form x=k\ny-2=1/0(x+3)\n0(y-2)=x=3\nx+3=0\nx=-3
1136213
if a line has the equation px+qy=r\nthen the slope of the line is -q/p
1088418
Equation/Formula for Point slope equation is y = mx + b wherein b is the y intercept and m is the slope.\n\n1. y intercept = -3\n    slope = 4\n\n2. y intercept = 4\n    slope = -3\n\n3. y intercept = 0\n    slope = 3\n\n4. you must simplify this one. The solution is:\n\n(step by step)\n\nIsolate the y     4/5y = -1/2x + 1\ncancel the fraction beside y  (5/4)4/5y = -1/2x(5/4) + 1 (5/4)\nand then it becomes    y = -5/8x + 1 1/4\n\nso then the y intercept is = 1 1/4 (--one and one over four)\nand the slope is = -5/8\n\n*when looking for the slope, do not inclued the variable "x" in your answer :)\n\nI hope this helped :)
2767
The Pythagorean Theorem definitely: a^2+b^2=c^2 \n\nPoint slope form: y - y1 = m(x-x1) \nStandard y equation: y=mx+b\n...Sorry, cant think of any more. \nSee, the rest of the equations that i could give you are not the ones EVERYONE should know :)
528541
The slope is zero, it is a horizontal line.  The equation is y=-3.\n\ny=mx+b is the slope intercept form where m is the slope and b in the place where the line crosses the y axis.\n\nSlope is rise over run. The is the difference in y's over the distance in x's.
777827
y=-4x+k is the first line slope =-4= m\n \nsecond line has a slope-1/m=-1/-4=1/4\n\nsecond line : y=(1/4)*x+C , but C=0 because line passes through the origin\n\nline  is thus y=x/4\n\n\nsubstitute v+1 for y and v for x in this equation\n\nv+1=v/4\n\nv=-4/3
787000
slope is equivalent to dy/dx = y'\n y = x -1\ndy/dx = dx/dx -0\n dy/dx = 1\n   y' = 1\nTherefore the slope of the given equation is 1.
823070
Get the slopes of the two lines using the formula:\n(y2 - y1)/(x2-x1)\n\nIf the slopes are equal the lines are parallel\nIf the slopes multiply together to give -1 the lines are perpendicular\nIf the slopes do not meet these conditions they are neither\n\nHope this helps!
730934
First you have to find the equation of the line that contains these two points (9,1) and (5,5)\nI believe the easiest way to do that is to use slope and y-intercept form (y=mx+b) m= slope and b= y-intercept\n\nto find slope, m = rise/run\nrise = -4\nrun = 4\nrise / run = -1\n\nTo find y-intercept plug in a coordinate pair and use are found slope.( i used 5,5)\ny=mx+b  x= 5 y=5 m=-1 b =?\n5=(-1)(5) +b\n10 = b\n\nSo this is our equation of the two points\ny=-x +10 \n\nNow we can use this equation to find whether  (10,0) is on  the line: Substitute (10,0) and see if the equation is still valid\n\n 0 = (-1)(10) + 10\n 0 = 0 Yes (10,0) is on the same line as the other points
547413
On a graph, a line can have a slope. The slope is defined as how many spaces the line moves up or down divided by how many spaces the line moves left or right from any two given points. You may see it written as\n\nrise\n----\nrun\n\nOR\n\nchange in Y\n-----------\nchange in X\n\nOR\n\n{for the line through points (X1, Y1) and (X2, Y2)}\n\nY1-Y2\n-----\nX1-X2\n\n\nA line from upper right to lower left will have a positive slope.\nFrom upper left to lower right will have a negative slope.\nStraight up and down will have an undefined slope.\nLeft to right will have a slope of 0.\n\nHope this helped! Good luck!
927388
y=mx+b\n\njust rearrange it so you get b as your intercept..\n\nin this case y=-1/4x +3, so the slope is -1/4, and the intercept is 3
97021
Using the points you can work out the slope. That is 0.\nThen use one set of points and the slope to work out the equation of a line formula which is:   \n         y-y1=m(x-x1)\nm is the slope \n       y+4=0(x-11)\n       y+4=0\n       y=-4