If a car is traveling at a speed of 60 mph, how many hours will it take for the car to travel n miles?
826951
n=60h,it's not a trick question, it's pure algebra.
427975
you multiply the # of KM by 0.6.\n\nex: If a car is traveling at 80 KM/hr, how fast is the car traveling in miles?\n\n80 km X 0.6 = 48 miles/hour.
735212
I'm going to use minutes instead of hours.\nWe know that on the first trip, D = 120S (D=distance, S=Speed of first trip).\nWe know that one the second trip, D = 90(S+6).\n\nTherefore 120S = 90S + 540, or 30S = 540, and S = 18kph.\nTherefore the distance is 36 kilometers.\nChecking, 24(1.5) for the second trip also = 36.
265901
average speed: total distance/total time\ntotal distance: 60 miles\ntotal time: 100 minutes = 1,6666666666666667 hour\naverage speed = 60 miles/1,6666666666666667 hour\naverage speed = 36 mph\n---------------------------------------------------\nvelocity is zero because man does not change of position
860357
65mi/hr equals 95.33ft/sec\nthe travel distance: 95.33ft/s*3s=285.99ft\nif 1 car equals 20ft then 285.99ft equals 14 cars and 6ft
851569
final speed=initial speed+(acceleration*time)\n=10+(30*30/60)\n=10+15\n=25km/h\nhope that helps..\ngood luck
602319
27+48=75\n780/75=10.4\n75/60=1.25\n1/1.25=0.8\n0.8*60=48\n\nThey would crash in 10.4 hours, or 271.8 miles away from the starting point of train A. The trains cover 1.25 miles in total for one minute. They take 0.8 minutes, or 48 seconds, to travel one mile.
94127
45 miles / 5 hours = 9mph\n45 miles /3 = 15 mph \n\n15mph - 9mph = 6 mph\nCurrent is 6 mph
103992
You need to know the speed of each car to answer the question. Assuming car 1 has a speed of s1 miles/hour and car 2 has a speed of s2 miles/hour. The time they will take to meet each other will be 8.5/(s1+s2). You can now substitute the values to arrive at the answer!
718292
40 miles per hour.  For instance if it is a 120 mile trip (one way) it will take 4 hours there, and 2 hours back.  \n\n6 hours for a 240 mile round trip.  6/240 is 40 mph.
554409
As you can tell, there's not really enough info within the problem itself to solve it.  You'll need to get a map, atlas, or some internet source to determine how much of the 481 miles will be driven in Oregon, and how much in California.  I won't look that up for you, but let's pretend that it's 121 miles in Oregon, and the other 481-121=360 miles in Cali.\n\nAssuming you constantly maintain the speeds indicated, you can calculate the time it takes you for each leg of the trip by using the formula:\n\n   distance = speed x time\n\nOr, equivalently,\n\n   time = distance / speed\n\nSo, for the 121 miles in Oregon, over which you will be traveling 65 mph,\n\n   time = 121 miles / 65 mph = (approximately) 1.86 hours\n\nand for the 360 miles in California, over which you will be traveling 70 mph,\n\n   time = 360 miles / 70 mph = (approx.) 5.14 hours\n\nAltogether, then, you'd be traveling 1.86 + 5.14 = (approx.) 7.00 hours.\n\nIf you want to write that out as one long problem, you could write it this way:\n\nTotal Time = Time1 + Time 2\n           = Dist1/Speed1 + Dist2/Speed2\n           = 121 mi/65 mph + 360 mi/70 mph\n           ~ 1.86 hr + 5.14 hr\n           ~ 7.00 hr\n\nNow, don't forget, I picked the distance values, 121 and 360 miles, out of thin air.  You'll need to look them up and do the problem yourself.  But hopefully that should give you an idea of how.  Good luck!
697994
Impossible.\n\nVariance is Time. To get the average of 60 mph for 2 milels journey, you must know the time.\n2 miles/time= 60 mph\ntime = 2/60 *60 = 2 mins\nsince at 1st mile the train has traveled at 30mph. It has already spent 2 mins. So, it's not possible to get average of 60mph.
426864
Roughly 3 ten-thousandths of a second.\n\nIf an object is travelling 60 mph, it moves at 1 mile or 5,280 ft/min.  60 seconds in an minute 5,280/60 = 88 ft per second.  12 inches in a foot = 1,056 inches per second.  2.76/1056 = approx. .00261 seconds.
715166
Distance is found to be the product of velocity and time.  E.G. if you travel at 60 MPH for 2 hours, you travelled (60 M/h) * (2 h).  The hours units cancel giving the answer as 120 miles.\n\nUsing this formula:\nd = v * t\n57 = v * 1.8, so v = 57/1.8 = 31 2/3 FPS.\nTo convert FPS to MPH,\n(31 2/3) * (60*60/5280) = 21.6 MPH.
652370
Okay, I've thought about this and it's not possible to determine the rate of acceleration from the given criteria.  It is an "average" of 60 miles per second, BUT how many miles in the first second compared to the number of miles in the final, fifth second?  If that is known, you can project MPH from seconds 6 to 10 or the additional 1/4 mile.  How do you calculate the rate of acceleration in your theory?  How fast is the vehicle traveling at each point of the 1/4 mile distance?
36001
A: 56 mph x 1.5 hours = 84 miles\n\n\nB: Distance = 100 total miles - 84 miles = 16 miles.\nTime = 30 minutes = 0.5 hours.\n\nAverage speed = 16 miles / 0.5 hours = 32 miles per hour.\n\n\nC: Total trip miles = 100 miles\nTotal time = 2 hours (1 hour 30 minutes for first leg, 30 minutes for final leg)\n\nAverage speed = 100 miles / 2 hours = 50 miles per hour.
1009103
We have a formula:\nSpeed = Distance / Time\nhere Time= Distance /Speed.==D/S\nD=100km in both cases\nS1= 125km/hr; S2= 80km/hr\n\nT1=D/S1==100/125 hrs === 4/5hrs===4/5*60mins= 48mins\nT2=D/S2==100/80 hrs ===5/4 hrs ===5/4*60 mins= 75mins\n\nTime saved = T2-T1==75-48=27 mins.\n\nIs this clear buddy