I need help with this math problem please?
819914
Remember - a negative exponent is an inverse.  If all you are doing is multiplying and dividing, life is easy.\n\n(3a^-7 b^7)/(9a^7 b^-5)\n\nFirst, move the negatives from where they are to the other side of the miniscis:\n\n= (3 b^7 b^5)/(9 a^7 a^7)\n\n(You can verify this by rewriting, for instance, a^-7 as 1/a^7 and simplifying, but I promise you this works.)\n\nNow:  3/9 = 1/3\n\nb^7 b^5 = b^12\n\na^7 a^7 = a^14\n\nSo, b^12/(3 a^14) and we're done.\n\nIf there were addition and subtraction in the problem, then it gets an order of magnitude harder.  Then, there is no substitute for rewriting the negative exponents as reciprocals and simplifying from there.\n\nHope this helps.
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
111021
If you are sloving for X then anything greater than 2 will work. basically it is 6 time what (X) will be greater than 12. Well 6x2=12 so that won't work.
538653
Just put each number in for x and see what the answer is.  Example : -11/2 + 75 = -5.5 + 75 = $69.50 a unit.
103938
you have to solve p such that S=D=Q.\n\nfrom S, p=Q/10 -70\n\nput that instead of p into D equation, solve for Q\n\nthen use that Q to compute p=Q/10 -70
653946
1 4\n2 15\n4 2\n5 100\n6 3\n7 15\n8 10\n9 10\n10 33\n11 -45\n12 2\n13 500\n14 5\n15 200
641208
The best place to go for math help online that i found was \nhttp://www.math.com\nI hope its useful to you.  I know people on here can tell you the answers, but if you have a test to take, and want to really learn it, go there.
1076304
(1) 1.3\n(4) 4\n(5) Right\n(6) 0\n(7) 0\n(8)0\n(9)12
609300
This is more of a word problem or a riddle than a math problem.\n\nThe answer is 7 (SEVEN).  Remove its first letter and it becomes EVEN!
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
813994
the first one is (x+10)(x+8)\nand the second one is your second answer
511948
There are an infinite number of ordered pairs that would satisfy this equation. If you want to find a few of them, assign a value to x and then solve for y.
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
662213
Anyone can give you the answer, but try here next time you need help with conversion or any other kind of math: \n\n\nhttp://www.gateways2learning.com/BasicMath/BasicMath.htm\n\nGood luck..................
30019
28 - 7*2*2\n\n155 - 5*31
1074417
The answer is 10. \n\nIf you don't believe me, do the problem yourself and compare that with my answer.
937830
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today