help dividing polynomials?
824178
You typed exponents just fine!\n\nx^3 - x^2 -x + 7 divided by x+1 is a "long division" type problem rather than factoring because x+1 doesn't go evenly into the polynomial\n\nThe answer is x^2 -2x + 1 + 6/x+1
1135639
(1 - a/b) divided by (a^2/b^2 - 1)\nGet a common denominator for 1 - a/b\n1 - a/b\n= b/b - a/b\n= (b-a)/b\nGet a common denominator for a^2/b^2 - 1\na^2/b^2 - 1 \n= a^2/b^2 - b^2/b^2\n= (a^2-b^2)/b^2\n= (a-b)(a+b)/b^2\n\n(b-a)/b divided by (a-b)(a+b)/b^2\n= (b-a)/b times b^2/[(a-b)(a+b)]\nCancel anything on the top with anything on the bottom.  Note that a-b = -(b-a).\nAnswer: -b/(a+b)
555590
Just multiply:\n(X/3)(3/4 x) -(x/3)(3/5) + (3/4)(3/4x) - (3/4)(3/5)\n\nand simplify from there
947283
You can do this using "synthetic division"\n....... ______________________\nx - 5 ) x^4 - 0x^3 - 3x^2 + 0x + 6\n\nI'm going to simplify this leaving out the x-terms and only showing the coefficients, but just imagine they are there:\n\n.............. 1 . 5 .22 110\n1 -5 ) 1 . 0 .-3 . 0 . 6\n......... 1. -5\n......... ------\n.............. 5 .-3\n.............. 5 -25\n.............. -------\n................... 22. 0\n....... ........... 22 -110\n....... ............----------\n....... ........ ........ 110  6\n....... ........ ........ 110 -550\n....... ........ ........ ------------\n....... ........ ........ ....... 556\n\nSo if I did it correctly the answer should be:\n1 5 22 110 remainder 556\n\nThis equates to:\n(x^3 + 5x^2 + 22x + 110) + 556/(x-5)
113980
Use a calculator - numerator divided by denominator will give you the answer.
562262
This is easy synthetic division, but you did not include a divisor. Anyway, you use each numbers co-efficients as the top numbers, leave a row, and then the bottom row, for the answer. The divisor must be x (variable) + or - (any number, say 1) \n(x+1) divide  (x^4 + x^3 + x^2 + x + 1).\ntake inverse of (x+1) integer: -1.\ndrop the first co-efficient and then divide co-efficients by this, 'bouncing' remainder into middle row. \n\nthe bottom row would be about 1/1/1/1 which you'd supplement on to the taken off variable, x.\nAbout This:\nx^3 +x^2 +x +1
894899
Horners' method of synthetic division is used to find the roots of polynomials. \nwe have to know one of the roots to proceed with this. we can check if 1or -1 are roots of the polynomial using some easy tricks. \n1) if the sum of all the coefficients is equal to 0, then 1 is a root\n2) if the sum of coefficients of even terms is equal to the sum of the coefficients of the odd terms, then -1 is a root.\nnow, for the first equation, we already know that -2 is a root, because the question is to find the quotient when the polynomial is divided by x+2. \nin synthetic division, u first put down a 0 beneath the first coefficient, ie., 3. now add these two. the result is 3. \nnow multiply 3 with the root, ie., -2. the result is -6. write this beneath the second coefficient, ie., 2. the result is -4 after addition. \nrepeat the same steps until u reach the last coefficient.\nnow next we write 8 below -1. result is 7.\nnext we write 7*-2 ie., -14 below 5. the result is -9.\nlastly, we write -9*-2=18 below . the result is 12, but the result should be zero.\nso, the given equation is not divisible by x+2.\n\ncoming to the second equation, follow the same procedure as above and u will get the resultant coefficients at each stage to be 2,6,22,61 respectively. so it is not divisible by 3
1039099
This is the answer i got when i worked out the problem\n1. You have to distribute the (x + 2) & (x + 1)....you do the by using the FOIL method....Firsts Outsides Insides Last and you get: x + 2 = x^2 + 3x + 2\n\n2. Get rid of the 2 on the left side by subtracting it on the right side and you end up with : x = x^2 + 3x\n\n3. Now you can move the x on the left to the right side too so you have: 0 = x^2 + 2x\n\n4. Pull out and x leaving you with 0= x (x+2)\n\n5. x = 0 and x = -2\n\nMy algebra is rusty but I think this is how it's done.
294579
First multiply p times the second polynomial.\np(p^4 - 2p^3 + 3) = p^5 - 2p^4 + 3p\nthen multiply 2 times the second polynomial.\n2(p^4 - 2p^3 + 3) = 2p^4 - 4p^3 + 6\nNow add these two together.\n\n(p^5 - 2p^4 + 3p) + (2p^4 - 4p^3 + 6)\n= p^5 - 4p^3 + 3p + 6
810284
i got 2x^2-x-3 R -4\n\nfirst divide 2x+5 into 4x^3+8x^2-11x-19 and you get 2x^2 then you subtract and your left with -2x^2-11x-19 and then you divide that by 2x+5 and you get -x add that to 2x^2 and you get 2x^2 - x then you subtract from your original and get -6x-19then divide 2x+5 into that and you get -3 ((2x^2-x-3)) multiply that by 2x+5 and you subtract from -6x-19 and you get -4 you cant divide 2x+5 into that so -4 is your remainder
208112
use the order of operations, so first the multiplcation. so\n\n2 + 2 - 3 + 96/2\n\nThen divide by two\n\n2 + 2 - 3 + 48\n\nAdd the twos\n\n4 - 3 + 48\n\nSubtract\n\n1 + 48\n\nAdd and get\n\n49
920343
(4/3)[x^3/(2-x)]^(1/3)\n[(2-x)(3)x^2-x^3(-1)]/\n(2-x)^2=\n\n 4x[1/(2-x)]^(1/3)\n[3x^2(2-x)+x^3]/\n3(2-x)^2
917477
where else?\n\nhttp://www.factoring-polynomials.com/
1154468
make a common denominator\n\na/b - c/d = a*d/b*d - c*b/d*b = (a*d-c*b)/b*d
66583
Polynomials are expressions involving x raised to a whole number power (exponent). Some examples are: \n\n\n\nIn this lesson we consider division of polynomials such as: \n and . \nThere are two ways to calculate a division of polynomials. One is long division and a second method is called synthetic division. Synthetic division can be used when the polynomial divisor such as x-2 has the highest power of x as 1 and the coefficient of x is also 1. Otherwise, such as , a long division process must be used. Both methods will be demonstrated. \n\nWe will now look at some examples showing how these two procedures are done
853619
There is a theorem related to polynomial divisions called the remainder theorem. Let p(x) be a polynomial of any degree. When it is divided by a linear polynomial of the form x - a, the remainder is p(a).\nAnswer 1:\nLet p(x) = x^5 - 3x^3 + x^2 - 3\nDivisor = x - 2\nHere, a = 2\np(2) = 2^5 - 3(2)^3 + 2^2 - 3\n= 32 - 24 + 4 - 3\n= 32 - 24 + 1\n= 8 + 1   \n= 9\n\nAnswer 2:\np(x) = x^5 - 3x^3 + x^2 - 3\nDivisor = x + 1\na = -1\np(-1) = (-1)^5 -3(-1)^3 + (-1)^2 - 3\n= -1 + 3 + 1 - 3\n= 0\n\nYou can check with actual division if you like. Looks like some of us have it wrong.
55565
Your computer has a calculator built in.  Failing that, try long division.  You're gonna have to learn how to do it anyway.\n\nSheesh.