How do you write the equation of a line that passes through point (-2,3) with a slope of -4?
827723
i am going to forward this link in the hopes that you can follow the steps for your particular problem. YOU MUST LEARN THIS!\n\ni want to see you score high on your SAT:\n\nhttp://www.terragon.com/tkobrien/algebra/topics/equationofline/equationofline.html
765225
First put the first equation into slope-intercept form or:\n\ny = mx +b\n\nm = slope,  and b = y-intercept\n\n-3x -3y = 2\n+3x        +3x\n\n-3y = 3x + 2\n/-3     /-3\n\ny = -x + 2/3\n\nSo, your slope for the first equation is:\n\nm = -1\n\nTo have a line parallel to the first line, the slopes must equal.\n\n\n\nUse Point-Slope form.\n\ny - y1 = m ( x - x1)\n\nSince you are using the point (-3, -4)\n\ny1 = -4\n\nx1 = -3\n\nSo your new equation will be:\n\ny - -4 = -1 ( x - -3)\n\n(remember the slope must be the same)\n(a minus a negative = a positive)\ny + 4 = -1(x + 3)\n\ny +4 = -x -3\n   -4         -4\n\ny = -x -7\n\nor you can put it back into standard form ( Ax + By = C)\n\nx + y = -7
32903
if you are given points (ex. (2,1) and (3,5) you can use this formula:\nm (slope) = y2-y1 / x2-x1\nso: 5 - 1 / 3-2 = 4/-1 or -4\n\nif you are given the equation of a line you can use this:\nx - ay = b\ny = -x + b / -a\nex.x-3y = 15\n-3y = -x + 15\ny = x/3 + 15\nso the slope is:\nx/3 = 1/3\nm(slope) = 1/3\nalways look for the coefficient of x and that is the slope.\n\nyou can also use this when you are given an angle:\nm (slope) = tan alpha
359276
1. 4x+3y=4 solve for y, then find slope and y intercept:\n\n4x + 3y = 4\n3y = -4x + 4\ny= -(4/3)x + (4/3)\nY-intercept is 4/3\nSlope is -4/3\n\n2. Write an equation in the form of y=mx+b of the line that is discribed. y intercept is -4 and the line is parallel to the line whose equation is 2x+y=8\n\nThe line whose equation is 2x + y = 8 is written y = -2x + 8 in slope-intercept form.\n\nThe parallel line with y-intercept 4 is:\n\ny = -2x + 4\n\n3. write the point-slope form of the line of the ordered pairs then use the point-slope form of equation (-2,-5) and (6,-5).\n\nThe slope is 0.\n\nThe point-slope form of the line is:\n\ny = 0x -5 = -5\n\n\n4.  Write an equation for each line in point-slope form of equation and slop-int. passing through (-4,2) and perpendicular to the line whose equation is 3x - 2y + -5 = 0\n\nFirst, rewrite 3x - 2y + -5 = 0 as \ny = (3/2)x -(5/2)\nThe perpendicular line has slope -2/3.\n\nThe point-slope form of the line with slope -2/3 passing trhough (-4,2) is:\n\ny - 2 = -(2/3)(x + 4)\n\nThe slope intercept form of the line with slope -2/3 passing trhough (-4,2) is:\n\ny - 2 = -(2/3)x - 8/3\ny = -(2/3)x - 2/3
322514
m1*m2=-1\n\nhold for the slope of two intersecting lines
866549
The slope of a line is defined as:\n\nm = (change in y) / (change in x)\n\nor:\n\nm = (y2 - y1) / (x2 - x1)\n\nGiven the points (-3, 3) and (0,-3) means:\n\nx1 = -3\nx2 = 0\ny1 = 3\ny2 = -3\n\nPlugging these numbers into the equation for m yields:\n\nm = (-3 - 3) / (0 - -3)\n\nm = (-3 - 3) / (0 + 3)\n\nm = (-6) / (3)\n\nm = -2\n\nNote that a slope of 0 means that there is no change in y, or that y1 = y2
766938
Use the forumula     delta Y/ deltaX to find the slope of the given points\n\n4-2/ 0-4   = -2/4 =  -1/2\n\n\nSince the perpendicular line is the equation  y = -1/2x; the other equation has the slope of the negative reciprocal of -1/2x so the equation would be \n\ny= 2x+b\n\nthen plugin x and y in this equation and you get\n\nb= -4\n\nso the final equation would be y=2x-4\n\n   Thats it
179699
The equation of a line is y=mx+c\nHere when x = 6, m = 4/3, y = -2\nTherefore c = y-mx = -2 - (4/3)*6 = -10\n\nHence y = (4/3)x-10\n\nHope this helps!
889514
slope of first line: (2-(-4))/ (5-3) = 6/2 =3\nslope of second line: ( -1 -5)/( -2-0) = -6/-2 = 3\nsince the slopes are equal that means that the 2 lines are parallel !
1124994
you can use the y=mx+b formula for a line.  \n\ny is the y-coordinate of a point\n\nm is the slope, x is the x-coordinate of a point\n\nb is the y-intercept (where the line touches or intercepts the y-axes).  \n\nsince you know the y intercept of the line (passes through origin, so it's 0), the value of b would be 0 and  you also know the slope of the line, which is two, the equation for the line would look like this.\n\ny=2x + 0 or y=2x\n\na point on the line would have coordinates that would fit the equation ---- y has to be two times x; x has to be 1/2 of y.\n\nhere are some points on this line: (0,0), (1,2), (-1,-2), (2,4), (-2,-4).\n\nhope that helped :)
917007
Well, you need two points to define a line (or one point and a slope).  There are infinitely many lines through the point (7,5).  So just pick one:\n\ny=x-2\ny=2x-9\ny=3x-16\ny=4x-23\n...
226683
The equation of the tangent at any point is f'(x)=3*(x^2).\n\nAt x=2, f'(2)=12, f(2)=8.\n\nSo the line has slope 12 and passes through the point (2,8).\n\ny - 8 = 12 * (x - 2) is the equation of the tangent line.
695994
The eqaution of the line is\ny-y1 =m(x-x1)\ny-0 = -3[x-(-4)]\ny-0 = -3(x+4)\ny= -3x-12
35268
slope = (-4-(-6))/(-2-0)\nslope = -1
97021
Using the points you can work out the slope. That is 0.\nThen use one set of points and the slope to work out the equation of a line formula which is:   \n         y-y1=m(x-x1)\nm is the slope \n       y+4=0(x-11)\n       y+4=0\n       y=-4
180320
Draw any line passing through origin. Its equation is y = mx and the slope ‘m’ is y/x.\n\nNow move the line up (or down) through a distance‘d’ with out changing the slope. The line cuts the y-axis at a distance d from the origin. This is y-intercept.\n\nThe x-coordinates of all the points on the line remain the same whereas all y-coordinates increase (or decrease) by‘d’. But the slope remains the same and x coordinates also remain the same. Therefore we give a correction to y coordinate to keep m constant.\n \nDenoting +d or -d by ‘b’, the slope of the new line’ ‘m’ is (y- b) /x. \n\nThus the equation of any line in slope intercept form is \n\nm =(y - b)/ x. or y = mx + b.
350403
Equation of a line:  y = mx + b\n\nm = 3 (slope)\ny = -4 (y-intercept)\n\ntherefore:  y = 3x - 4 \n\nCrosses x-axis at y = -4 (0,-4)\nCrosses y-axis at x = 4/3 (4/3,0)