how do you make a java statement in such a way that when you type 529, it displays five hundred twenty-nine?
818063
I'll help you if you try to write the code and have problems debugging it.\n\nYou should do your homework, not ask people to do it for you.\n\nBut if you pay me, I send you the code.
91787
Unfortunately, no. You'll need to parse the integer from the String entered in the text field. You can use JTextArea or JTextPane or even JPasswordField. To compare the values you'd either want to use a JButton at the bottom (for the user to click once he/she is finished entering text) and then parse an integer out of it.  View the sources below (especially the API) to view the different subclasses of the different types of text components in Swing. If you need help parsing the integer out of it, then let me know and I'll tell you how to do that (if I'm on, so don't count on it ;). Good luck!
810525
Move the decimal two places to the left.\n.3455
605693
Consider holding down the Alt key whilst typing 253 on the numeric keypad - it would make this easier to read:\n4r²-25s²/2r²+3rs-20s\nor should it be:\n4r²-25s²/(2r²)+3rs-20s\nor:\n4r²-25s²\n--------\n2r²+3rs-20s
316466
Another answerer gave an example, but I thought it\nmight help to explain it to.\n\nFor any large (or small) number, move the decimal\npoint to just after the first non-zero digit (so\nthat you end up with a number between 1 and 10.\nThen specify the number of digits that the decimal\nwas moved using the "times 10 to the something power"\nnotation.\n\nFor example, 123 would be "1.23 X 10^2"\nOr .00023 would be "2.3 X 10^-4" \n\n(where "^" means "to the power of")
734599
kbhit will return a integer to you, go to asciitable.com to find out what des each interger corresponds to what key.\n\ngood luck
864444
♪ALT 13♫\nalt 14\nHold down the ALT button and push 13 or 14 on the numpad
639299
you left out...\n\nsix thousand, seven hundred and forty. That is another option. But usually an address such as that would be said as \n\nsixty seven forty (67/40)
770189
Number will have to be the actual number it is working it out from..and it might not work as a long and definately not an integer.\n\nNumber as String\nOdd as Long (or Integer)\nEven as Long ( or Integer)\n\nIf Not (Number <1 or Number > 10) Then\nNumber = Number / 2\nIf InStr(Number, ".5") then\nOdd = Odd + 1\nElse\nEven = Even + 1\nEnd If\nEnd If\nMe.Print "Odd: " & Odd & " - " & "Even: " & Even
816710
Create an outer for loop that will loop from 7 down to 0, with a step of 2.\n\nCreate one inner loops.\n\nThe inner loop should take the value of i, place it in another variable and count down to 0.\nThen print out the dollar signs for each iteration of this loop.
846187
if you are using a "while" or "do while" loop\n\nwhile ((x1 - x0) > 0.001)\n{\n//your code here\n}\n\nor you can do this\n\ndo\n{\n//your code here\n}\nwhile ((x1 - x0) > 0.001);
339901
To validate text input converted to a int try this:\n\ntry {\n    String s = new JTextField().getText(); // The user enters text in the text field\n    int value = Integer.parseInt(s);\n}\ncatch(NumberFormatException ex) { // Invalid input, not a number\n    ex.printStackTrace();\n}\n\nHope this helps
926416
your getting a little anxious in your coding:\ntry changing the section below:\n\ncout << "Enter a number Negative, Positve, or Zero.";\ncout << '&#92;n';\ncin >> num;\n\nif (num > 0)\n{\n    pos(num);\n}\nelse if (num < 0)\n{\n  neg(num);\n}\nelse\n{\n  zero(num);\n}
347575
By adding a single line to the first '+' you can make it into a '4'. So...\n\n545 + 5 = 550
580667
Type ' the the number\nlike this\n'12345678901234567890\n\nand it will entered as it is..\n\nXLMan
1045723
It means a number between 5 and 200.  You might have to round to the nearest number if it doesn't take decimals.
195411
26*26*26*10*10*10 = 17,576,000\n\nRemember there are 26 letters in alphabet, so you have 26 choices for your first 3 digits. And you have 10 digits to choose from (0-9) for your last 3 digits.  Just multiply them together.