i need to graph y > 6x-2 and y < -3x+4 on the same line?
821475
graph both the graphs as though they were of equality and not inequality and after wards shade the relevant portion
809234
you would plot it on a graph at (0,5) \nor "y-int=5"
653148
All equations for a line will have the form:\n\ny = mx + b,\n\nwhere x & y are coordinates, m is your slope, and b is your y-intercept.\n\nTherefore, substituting in your slope and y intercept, you get:\n\ny = -2/3x + 4\n\nThis equation can then be used to graph the line, since given any x, the corresponding y can be found. :)
549653
Subtract 2x from each side\n-y = 0 - 2x\nMultiply each side by -1\ny = 2x
184282
y = 7\n\na horizontal line
975981
You need to pick another point that the line goes through and substitute it into that formula such as (3,6) put the x and y in the correct places.
291453
It shifts it.  If y = mx + b, b is the y-intercept (where the graph crosses the y-axis), and changing b would move the entire line up or down along the y axis.\n\nTry graphing these two lines by plotting points\n\ny = x\ny = x+3\n\nSee how the lines are parallel, but one is slightly higher than the other?
812734
The easiest way to graph this equation is to plug in 0 for x and get one point, then plug in 0 for y and get another, then draw the line that connects the two points.\n4(0) - 3y = 24\n-3y = 24\ny = -8\n(0, -8)\n\n4x -3(0) = 24\n4x = 24\nx = 6\n(6, 0)
939024
Draw yourself a cartesian graph, vertical line is the y axis, horizontal is the x axis.\n\npick points on the x axis like 1, 2, 3, etc.  plug thos values into the equation and solve for y. then pair the numbers, place points in the graph by taking the x value going straight up (or down if y is a negative number) and place the dot accross from the y value.  do this for each set of points then connect the dots with a line or a curve. for instance in your equationstart with x=1\n\ny= 7(1-5)(1-2)^4(1+.5)(1+2.5)^3\ny= 7(-4)(-1)^4(1.5)(3.5)^3\ny=7(-4)(1)(1.5)(42.875)\ny=-1800.75\n\nso in XY format the first point would go at (1, -1800.75)
789536
If you are supposed to do it by graph, then it's easy.  Just place the points on the graph (scaled, of course) and see when x=0, namely, when the line crosses the y-axis.  That will be your answer.  If you are looking for the formula way, here you go:\n\nm=(4-0)/(10-(-10)) = 4/20 = 1/5\n\n0 = 1/5(-10) + b\nb= 2\n\ny=x/5+2\n\nYour y-intercept, or f(0), is 2
958895
If you mean y = 2 - x then theabove answers are right.\n\nI'm wondering, though, if you might mean you have a graph of some function f(x) and want to draw a graph of the combined function g(x) = f(2 - x). If so you simply flip the original graph around the y axis (this gives you -x) and then shift the whole thing 2 to the right (this is the 2). You can check individual points if you want to make sure: g(2) = f(0), g(3) = f(-1), ...
770341
You need to get y by itself.\n\nadd -3x to both sides so you get 2y> 3x+4\nnow divide 2 --> y>3/2x+2\n\ngraph that as you would if it were y=3/2x+2\n(starting at 2 on the y axis. then move up 3 points, and 2 to the right.)\n\nMake sure your line is DOTTED. It is only solid if the inequalilty is less/greater than or equal to.\n\nto check which side is to be shaded, plot points on both sides. try (0,0) if the line doesn't cross through that.\n\n:)\n\nIf the answer is correct, shade the region where (0,0) or the coordinates that work are.
778580
Go to this link:\n\nhttp://www.coolmath.com/graphit/index.html\n\nYou can enter your equation and graph it.
1055471
You need to graph this function. \nIt is a line.\ny = (x^2)^ 1/2 - 16 \ny = x - 16\nx = 0, y = -16, \nx = 16, y = 0
712712
[on] [y=] [(] [x,t,o,n] [+] [2] [)] [/] [x,t,o,n] [enter] [5] [-] [2] [x,t,o,n] [enter] [(-)] [2] [x,t,o,n] [-] [3] [enter] [window] [(-)] [5] [enter] [5] [enter] [1] [enter] [(-)] [5] [enter] [5] [enter] [graph]\n\nYou should have on screen a vertical asymptote at x=0, horizontal asymptote at y=1, a curve going to negative infinity towards 0 on the left, a curve going to positive infinity towards 0 on the right, on the left tangent line y=-2x-3 touches point(-1,-1), and on the right tangent line y=5-2x touches point(1,3).
951551
A line that runs parallel to the Y axis.
470658
The above answer is basically correct.  Plug in a few more values, such as (21,1543.5), (22,1694), and so on for a few more values of the graph.