(a62 - 2ab + b^2)/a+b?
825318
(a^2 -2ab + b^2) = (a-b)(a-b) = (a-b)^2\nYou cannot cancel anything, so \n(a^2 -2ab + b^2)/(a+b) does not simplify.\n\nYou may wish to write it as (a-b)^2 /(a+b)
778361
x=\n\n -b +/- SQRT (bSQ-4ac\n-------------------------------\n              2a\n\nwhereas: a(x)SQ+b(x)+c=number\n\nproblem: xSQ+2x+3=6\n\na=1\nb=2\nc=3\n\n-2 +/- SQRT (2SQ+4*1*3)\n-----------------------------------\n                 2*1\n\n2SQ=4\n4*1*3=12\n2*1=2\n4+12=16\nSQRT16=4\n\n-2+4\n------\n   2\n\n-2+4=2\n\n2/2=1\n\n-2-4\n------\n  2\n\n-2-4= -6\n\n-6/2= -3\n\nx= 1 AND -3
831044
2x² - 10a\n\n2a(a - 5)\n\nThe answer is 2a(a - 5)\n\n- - - - - - - -s-
817461
a^4 - b^4\n\n= (a^2 + b^2)(a^2 - b^2)\n\n= (a^2 + b^2)(a + b)(a - b)
94804
2\n\n6 - 2(2)\n6 - 4 = 2
538044
hmmm...very tough one!\n\nill sovle by the formula!\n       _________\n-b +- V (b^2)-4ab\n------------------\n       2a\n       _________\n-10 +-V 100+512\n------------------\n       2\n\n       _________\n-10 +-V 612\n------------------\n       2\n\n-10 +- 24.7\n------------\n     2\n\n14.7/2\n\n34.7/2\n\n(7.35, 17.35)
917375
b^2 + 6b -16 = 0\n(b+8)(b-2)=0\nb+8=0\nb=-8\n\nb-2=0\nb=2
339354
(2x + b) * (a + 3c)\n\n\nsteps:\n2ax + 6xc + ba + 3bc \n1) group first two, and last two\n(2ax + 6xc) + (ba + 3bc)\n\n2) factor out 2x from the first, and then b from the second group\n2x*(a + 3c) +  b*(a + 3c)\n\n3) since (a + 3c) is common, combine 2x and b\n(2x + b)*(a + 3c)
534750
1/2 + 1/2b + 2b^2 + 6bc + c^2\n\n(1/4b)(1/4b) + 4bc + (bc)(bc)\n1/2 + 1/4b +1/4b + b^2 +4bc + b^2 + c^2 + 2bc\n1/2 + 1/2 + 2b^2 + 6bc + c^2\n\nI think this is right... email me if I'm wrong?
706305
R^2=A^2+B^2 -2(A*B)cos(180-acute angle)
798164
A = 3ax + 4by - 2ay - 6bx\n= 3x.(a - 2b) - 2y.(a - 2b)\n= (3x - 2y).(a - 2b)\n\nB = 2ax - 2by + ay - 4bx\n= 2x.(a - 2b) + y.(a - 2b)\n= (2x + y).(a - 2b)\n\nA/B = (3x - 2y).(a-2b) / [(2x + y).(a - 2b)]\n= (3x - 2y) / (2x + y)
331279
what does a^2ba^3ab^3b =a^6b^5 or a*a*a*a*a*a*b*b*b*b*b
426775
b = 2g - 10\ng = (b + 10)/2
1046507
[2x/(x+3)(x-3)]*[(x-3)/4(x)]\ncancelling 2 and x-3 we will get\n=x/(x+3)2(x)\nsimplify we will get\n=x/(2x^2+6x)
412542
x = -b +(or)- sqrt(b^2 - 4ac)\n    -------------------------\n               2a
551906
Add each equation\nA + B = 3x^2 + 2x - 2\nA - B = -x^2 + 4x - 8\n2A = 2x^2 + 6x - 10\nDivide each side by 2\nA = x^2 + 3x - 5\nNow plug into one of the original equations to get B\nB = 3x^2 + 2x - 2 - (x^2 + 3x - 5)\nB = 2x^2 - x + 3
483173
((6p - 18)/(9p)) / ((3p - 9)/(p^2 + 2p))\n((6(p - 3))/3(3p)) / ((3(p - 3))/(p(p + 2)))\n((2(p - 3))/(3p)) / ((3(p - 3))/(p(p + 2)))\n((2(p - 3))/(3p)) * ((p(p + 2))/(3(p - 3))\n(2p(p - 3)(p + 2))/((9p)(p - 3))\n(2p(p + 2))/(9p)\n(2(p + 2))/9\n(2p + 4)/9