Help: can you help me come up with a formula for the number of regions?
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With three points you form a triangle, with four points a quadrilateral. Regions "outside" the polygon are equal to the number of sides (the number of points). The number of regions inside the polygon is the interesting number.\n\nFor two points, there are no regions "inside" the polygon.\nFor three points, there is one region inside the polygon.\nFor four points, there are four regions inside.
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4 thousands\n5 hundreds\n6 tens\n9 units\n8 tenths\n2 hundreths\n3 thousanths
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4 from asia, 14 from europe, 5 from africa, 4 from south america and 4 from north america and central america also 1 from oceania (some teams consist of 2 countries making 32 total countries)
156026
You can go to the CIA world factbook they will give you the list of countries.  Scroll down and bingo get the number of countries.  Hope this helps.
122975
The answer is six.\n\nHouston, New Orleans, Arizona, Detroit, Jacksonville and Cleveland.
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7\nNorth America\nSouth America\nAfrica\nAntartica\nAsia\nAustralia\nEurope
554315
First pick what you want your area to be.\nLet A = 100.\nThe first one is easy, just let it be a square with all side lengths of 10\nNow pick two other numbers that when you multiply them you get 100.\n4 times 25 = 100\nA rectangle with width 4 and length 25.\nKeep picking more\n2*50 = 100\nwidth = 2 and length = 50\nYou can find more.\nAlso, you don't have to use 100, just pick any number you want for the area.
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USe the function "CountIF"\n\ne-mail me for more details
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32 teams.\n\n14 teams from Europe, 5 teams from South Africa, 4 teams from North America, 4 teams from South America, 4 teams from Asia and 1 team from Oceania.
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87,857,473\nhttp://education.yahoo.com/reference/factbook/rp/popula.html
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Formula of area 'A' of any regular 'n'-sided polygon of each side 'a' is\nA = 0.25*n*a^2*cot(pi/n)\n\nPut a=10 and n=6 in this formula.\nA = 0.25*6*10^2*cot(pi/6)\n  = 150*sqrt(3)   [since cot(pi/6) = sqrt(3)]\n  = 259.8 sq units
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Diameter is two times the radius.\n\nThey may want you to calculate the mean (average), median, or mode of the 12 values.\n\nIt would be best if you would give more details.
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Worldwide\n8.3 Million\n\nU.S.\n2.5 Million
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Count the stars in a specific size region (say 1 minute square) and then multiply by the number of total regions that would cover the sky...\n\nHowever, this only counts stars visible to the naked eye and only works if you pick a region with an average density of stars.\n\nJust say it is "billions and billions" and leave it at that...
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Not sure how many you need, but here are the first few:\n2,3,5,7,11,13,17,19,23,29,31, 37,41,43,47,53,59,61,67, 71,73,79,83,89,97,101
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By Most Accounts, 193 is the Correct Answer\nA very frequent geographical question is "How many countries are in the world?." Different numbers pop up when one inquires or reads about the number of countries in the world. Each source you use often yields a different answer.
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2,3,1 (nothing goes there) ,6\n\nHope it helps :]