Width, length and depth?
820027
The usual convention will be Length, Width and Height.\nDepending on who you received the dimensions from it could be anything.
55911
Dimensions are simply attributes or modes.  Here's 3:\n\nCommunication.\nTravel.\nExpenditure.
669147
number of sides, congurency?, size of angles, distinguishing characteristics
1073502
Once again you will see that this is a rectangle.\nA = length times width\nA = 7*2\nA = 14
985823
Area = Length x Width\n\nArea = 2 ft x 5 ft\n   ''    = 10 sq. ft
65434
The question is WRONG. If you have length =6 and width =7, P=26 and A=42.
907028
Cubic length. For example cubic feet, cubic inches, cubic centimeters, cubic yards etc.
957319
Here's what you know:\narea: 131.2 cm^2\nwidth: 8 cm\narea formula: width x length\n\nSo you know width x length = 131.2\nYou know the width, so plug it in to get the solution
464398
Find the area.\nArea of a rectangle = length*width\n= 15*20\n= 300\n(2/3)(300) = 200\n300-200 = 100 square feet
948283
4 feet by 4 feet by 8 feet
170125
Engineering it the height width and depth of all components and and mechanicle functions factored in as well as electrical air and fluid movement and anything else related to it...........engineering is making somthing, design is is a picture of it........\nAuto cad is whats used instead of paper because you can use 3 dimensions (a box has 3 measurements height width and depth) its as simple as that,fluid movement is done through mathmatical equasions and so is the rest...I dont have all the info but thats what i know in a nutshell...Maybe you should look twards the internet for more information....College librarys/stores where they sell books will tell you more.......You dident answer my question on the drywall but thats fine..........
174731
Nor sure if I understand your question.  Are you looking for 3 dimensional and 2 dimensional shapes?\n\n2 dimensional\n-square\n-circle\n\n3 dimensional\n-cube\n-sphere
927242
volume = length x width x height
986859
Let: L=length, W=width, P=perimeter\n\nL=5+2W\n\nP=2L+2W, P=112\n2L+2W=112\nSubstituting L into the equation, we get:\n\n2(5+2W) +2W = 112\n10 + 4W + 2W = 112\n6W = 112-10\n6W = 102\nW = 17\n\nL = 5+2W\nL = 5+ (2*17)\nL = 39\n\nSo, the dimensions of the frame is 39 x 17 inches.
567514
let us assume that you are trying to measure a room :\n\nso you check linear lenghth in one side and then linear length in other side and let us call them as length and width \nassume: \nlength =12 ft\nwidth =10 ft\n\nthen area= length xwidth \nso \narea=12x10=120 square feet.\n\nlinear is  distance \nsquare feet is area.
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.
925174
Color, type, form, and so on...