how do you write the charge and discharge of a battery?
821830
You have to know with what kind of battery your starting.
792406
let the initial charge on the capasitor be q. Then for charging the equation is given by:\nQ=q(e)^(-t/T);  where e is base of natural log. 't' is the time and 'T' is time constant which is probably 1/(RC)\n\nfor discharging\nQ=q(1-(e)^(-t/T));\n\nnow the graph can be easily plotted by taking Q on 'y' axis and 'q' on x-axis.
1148859
Simple!\n\nJust a battery, resister, and the diode\n\nThe resister is determined by the size of the battery and the maximum allowable load on the diode. You have to have the diode specs to determine this.
652086
1. volts\n2. (b) negatively charged.\n3.  short.  Could also be "conductor," but the lack of control seems to indicate an unwanted short.\n4.  watt-hours.\n5.  \n6.  (a) The formula is P=V*V/R.  Where V is the voltage and R is the resistance.  So P=45*45/15=135 watts.  Actually the object is consumming the power, not producing it.\n    (b)  135*10 = 1350 watt-hours, or 1.35 kw-hr.\n    (c) 0.08*1.35 = $1.08\n7.  (a)  V=IR, so if the voltage is increased while the resistance is kept constant, then the current will also increase. (I=V/R)\n    (b)  If the resistance is increased and the voltage is kept constant, then the current has to decrease. (I=V/R)
194009
Connect all the positive terminals together, and then tie all the negative terminals together. The voltage of batteries wired in parallel is the same voltage as one of the individual cells. If they were hooked in SERIES, the the voltages of all the batteries would be added together to get the total battery combo voltage.
286535
Basically what it's saying is this:\n\nThose battery tester strips have a special ink which allows for the batteries charge to travel across it.  The more charge the battery has, the further it can travel.\n\nSo, when you test a battery, and it's charge is weak -- it's charge will only 'travel' partially across this special conductive ink.\n\nThe thermochromic and normal ink mentioned are largely for display/cosmetic purposes.  These basically allow you to see how far the charge has travelled across the conductive ink layer -- and thereby see that this battery is "good" or "bad".  \n\nHope that helps.
233940
A battery is a method of either STORING or GENERATING an electrical charge chemically. In generator type of battery usually (2) disimiliar metals provide the anode (+) and Cathode (-) of the battery an electrolyte solution causes a chemical reaction which destroys the anode and cathode as it produce an electrical charge. Examples of this type of battery are the carbon zinc battery, alkaline batteries etc. \nA storage battery stores an electric charge in the form of ions on plates in the battery this type of battery may use the same material for the anode and cathode and also uses an electrolyte material but it must be charged before it will "produce" an electrical charge. Examples or the lead acid, Nickel Cadmium, Lithium ion etc.
1559
Nope you really should not. Most batteries are lithium ion batteries that develop a memory over time. I learned that the hard way. I always left my laptop plugged in, and in a year my battery was completely dead. From what I know, you should do a complete cycle of the battery at least once a month. That means at least once a month, drain the battery to empty and charge it up again. Dont cycle too often though because that too shortens battery life spans... Soo just keep in moderation. Dont always leave it plugged in, but dont always rely only on your battery either.
964185
I sense that you have no clue what you're doing. Tell me I'm wrong.\n\nFor DC circuits, Ohm's law says: V = I * R, voltage equals current times resistance.\n\nYour circuit will consist of a battery (voltage source) and a load (resistance) plus the wires to connect them and the meter(s).\n\nIdeally you will test one battery at a time. That way the load will be identical (including the small resistance of the wires).\n\nBatteries typically have two ratings: voltage and capacity.\nVoltage is measured in volts and this decreases as the battery discharges. Capacity is measured in amp hours (current multiplied by time) which specifies how long the battery can deliver a current.\n\nAssuming the circuit resistance is constant (reasonable assumption for your purposes), when you connect the battery to the load, the voltage (independent variable) will cause a current (dependent variable) to flow. As the battery discharges, the voltage will decrease, and the current will correspondingly decrease. You will need a watch or timer as well. Time zero will be when you first connect the battery. Measure the battery voltage at that instant and at intervals. Depending on the load and how fast the battery discharges should determine how frequently you take measurements.\n\nmsg me when you have the data if you need help analyzing it.
1017031
violation of probation - battery is the original charge
500850
Rechargable batteries can only handle a certain number of charge discharge cycles so if you discharge the battery before charging it you will actually shorten the life of the battery as opposed to simply charging it when you get a chance.
924475
= 9u-10u + 6v = 6v - u
467003
You'll need, as the name may suggest, a voltmeter.  Also applicable is a multimeter - which you'd then set to voltmeter mode.\n\nAt which point you'd just put one contact on one one end of the battery, and one on the other, and see what the equipment reads.\n\nMy money's on 1.5V :)
383618
information is stored in 1's and 0's, binary,\nthis can be represented in +5 volts or 0 volts.\nmost computer memory is DRAM, it stores charges in little capacitors switched by transistors.\nif you take away power the numbers go away, discharge.\npermanent storange is on the hard drive, it stores info on magnetic media, like casssete tape, MIKE
511371
8,639,930 Joules\n\nEnergy is represented by units of Joules.\n\n1 Joule = 2.7778×10−4 watt-hour\n\nassume your battery can deliver 100 AMPS for 1 hour at 24 volts\n\n(24V x 100A) x 1 hour = 2400 Watt-Hour\n\n2400 W-H / 2.7778 x 10^(-4) = 8,639,930 Joules
1100598
voltage = current x resistance\nE = I x R  It IS Ohm's law. An easy way to remember the formula and it's configurations is to draw a circle and divide it in half horizontally. Above the line write "E". In the lower half divide the semicircle vertically and write "I" on the left, "R" on the right. It should look something like this:\n                                                     E\n                                                   I    R\nNow just cover up the one you need. and either divide, or multiply.
438317
What you are doing is building a battery, an acid based battery.  take a lemon, get a strip of copper and a strip of zinc from chemistry class, or use pennies and dimes.  insert the metal stips in opposite sides of the fruit and connect a wire to each strip.  with this you will get about a .5volts, take 2 or three and wire is series and you can light a small flashlight bulb or run a small motor.\n\nsee the following  http://www.hilaroad.com/camp/projects/lemon/lemon_battery.html