1/2^x < 0.01 Why is the sign flipped ?
812981
1/2^x < 0.01 \nthen multiply both sides by 2^x\n1 < 0.01 2^x\nnow divide both sides by 0,01:\n1/ 0.01 < 2^x\n100 < 2^x\n~
832106
1) 1/-4<m/-4\nmultiply both sides by negative 4 and flip the inequality sign\n4>m.\n\n2) -1/8< or equal to n/-32\nmultiply both sides by negative 32 and flip the inequality sign\n4 greater than or equal to n\n\n3) x/-12>1/4\nmultiply both sides by negative 12 and flip the inequality sign\nx<-3\n\n4) -1/2x< or equal to 2\nmultiply both sides by negative 2 and flip the inequality sign\nx> or equal to -4
748852
yes the signs have just been changed\ntake -x+y=-2 and multiply by -1 on both sides\n \nyou get x-y=2 and since the same thing was done to both sides the equation is equivalent
957940
If the sign in front of the 4 is a single negative sign then the answer is x>4, because you change the sign when you divide by a negative number in an inequality. If the inequality is actually -(-4)<-16, then your answer is right.
514501
It's not really a problem as much as a simplification; there's no = sign.  Anyway, simplified I get 8w^3 + 4w^2.  I got that by multiplying your original problem by \n(-2w-1)/(-2w-1).  That gets rid of the fraction in the denominator and reduces the numerals in the numerator down.
821366
2.7*10^-5\n7.041*10^5
162293
On both equations, you have x^ but don't say what x was raised to. I'm assuming that it is x^2. Is this correct?
30751
The Edifier has it right, but darned if I can follow the notation. You really need to see this written out like a textbook to understand what's going on.\n\nClick the link below in "sources" to see the answer hosted at my website www.calculus-help.com. Right now, Yahoo! answers, as far as I can tell, doesn't allow graphics, which makes it tricky to answer ANY math questions.\n\nPlease don't post math answers, guys, if the poster knows the answer but can't get there, and you get something completely different.
312174
It seems undefined since for x <= 0 and x != odd number, x^x doesn't work out so well.  If it's x->0+, then it's just 1.
876541
something is wrong in the way the problem is stated\nboth the answers are wrong, according to me.\nif you differentiate -19800-50.01x  you will get -50.01 and that cannot be equated to zero
762698
The demoninator of the fractions are doubling.\n\nSo:\n\n1 1/2 1/4 1/8 1/16 1/32 1/64\n\n1/64 or 0.015625
1117062
if ur just solving that equation...u dont need to switch the sign.....\nwatch (im not gonna have the equal sign on the bottom takes too long). \n\nx-1<-3\n(add one to both sides now)\nx<-2\n\nthers ur answer
885973
EE/EB/HI  upside down on a calculator display.
6928
When both operands are numeric, ^ in Java is a bitwise exclusive OR (otherwise known as XOR).  In binary terms, 2^4 is the same as 00000010 XOR 00000100 which results in 00000110 (6).  This is unless the ^ operator is overloaded in which case you'd have to refer to the overloaded method for XOR.  If you are not familiar with XOR, XOR returns TRUE when both operands are not equal, and FALSE when both are equal.
735670
The 1 is in the 1000ths place:\n\nThere's no "1s" After the decimal. AFTER the decimal, it goes 10ths, 100ths, 1000ths, etc.\n\nUse this key for more problems you might have:\n1000s, 100s, 10s, 1s . 10ths, 100ths, 1000ths, etc
951210
ok...well 1/x becomes basically infinity as x gets really close to zero...so (1/x)/x woud be infinity/something really close to 0 which would make the value infinity\n\nso we have\n\ne-(1-x)^infinity\nwell...thats ok\n\ne-(1 - (basically zero))^infinity is\ne-1^infinity\nwhich is\ne-1\n\nso the limit as x approachs zero from the right is e-1 which is approximately 1.71828\n\nhope this helps\nmatttlocke
366161
well...after transfering the "+7" in the right of the equal sign and which becomes "-7"(the sign is changed from "+" to "-") we have on the left "2x" and on the right "24-7" which is "17". After this we divide "24" at "2" which comes from the "2x" in order to find "x" and the result is that "x=8,5" or "x equals 8,5".