How many kilometers per liter will a car go if its engine is 25% efficient ...?
827623
F*m = μ*Joules→ m = .25*40000000/1000 = 10000m = 10 km
934537
1 UK gallon = 4.546 liters\nso 1/2 UK gallon would be 2.273 liters\n\nfor more conversion see http://www.translatorscafe.com/cafe/units-converter/fuel-consumption/c/
321421
0.215 kL = 215L\n(1kL = 1000L)
767490
enough vapour to run a car
800779
32h + 24c = 432  --> drove a total of 432 miles, need to find h and c, highway and city gallons.\n\nh + c = 16  ---> used 16 gallons\n\nUse substitution:  h = 16 - c\n\n32(16 - c) + 24c = 432\n\n512 - 32c + 24c = 432\n\nCombine like terms:\n\n512 - 8c = 432\n\n-8c = -80\n\nc = 10 gallons.  At 24 miles/gallon city, drove 240 miles in the city, \nso must have driven 432 - 240 = 192 miles on the highway.\n\nCheck your work:\n\n32(6) + 24(10) = 432.  (6 gallons on the highway)
481058
Retrofitting Older Model Year Carbureted Vehicles to get 50 Plus Miles Per Gallon With My Gasoline to Propane Converter, and then Donating Them to The Meals On Wheels Program , The Disabled American Veterans, Homeless Shelters, Etc. It can Only be A Hypothetical Dream Because By Law All Vehicles From 1996 To The Present Are Required to Run At 14.7 Parts of Air to 1 Part of Fuel. I've found A Way To Change That To 100 Parts Of Air to 1 Part of Fuel! But It Will Never be Marketed! I've Been to The US Patent Office, and Witnessed Firsthand How All Similar Units have been Kept off the Market, so don't even go There!And Now, with the EPA OBD II Law, That will never Change! If I'm Wrong, then how is it that Engines DO Run on Large, Expensive, Cumbersome Propane Tanks that are a Hassle to Set Up, and Refill? Petroleum, on a Molecular level is all the Same. It's only the Dispersal that's Different! My Hypothetical Dream Job, which will never Happen,,would be to Disprove Once and for all the Almighty 14.7 to 1 Air to Fuel Ratio, Reduce  Dependency on Imported Oil, and Reduce Air Pollution Caused by Vehicles!
860183
This is a momentum question.\n\nMomentum = mass x speed\n\nSo, the original momentum is contained solely withing the moving engine and equals 4 units of mass times 5 km/h.  This equals a 'momentum' of 20.\n\nThe final momentum equals the combined mass of the engine and freight car, which is 4 units plus 1 unit for a total of 5 units of mass.\n\nSo, if Momentum = mass x speed, then since our final momentum is 20 (the same as the original momentum) and our final mass is 5, then 20 = 5 x Speed\n\nDividing both sides by 5 yields a final speed of 4 km/h.\n\nBest wishes and good luck.
162289
My dad in Australia has converted his car to run on Liquid Petroleum Gas. It has halved his costs every time he fills his tank. See the link below for more info.
280551
There is not sufficient information to calculate efficiency. \n\nFor an engine you need the energy input and the energy output. Energy output divided by energy input times 100 gives you the efficiency. \n\nThe amount of fuel and its energy content will take care of the input. The output requires a dynamometer or some other means of measuring the energy output at the engine shaft
840998
there are basically 2 methods\n1) tank full to tank full:- Means fill it full --then drive around as much as you like-- note the millage--- fill it up to tank full again and see how many liters. now divide millage by liters of fuel to get the average\n2) tank empty to tank empty:- drive till the tank is empty, then fill it with say 5 liters and then again drive till tank empty and note the millage. divide millage by fuel filled that is 5 ltrs in this example.\nTry anyone that suits you and get back to us. Most people say No-1 suits them more.\nAnd BTW it took me more time guessing what you meant than actually answering.
782858
750 mi /(30 mi/gal) = 750/30 mi/(mi/gal)\n=25 mi*(gal/mi) =25 gal\n\nIn other words if you go 750 miles in a car that does 30 miles per gallon, you use 25 gallons of fuel.  Notice that you can divide the units (Miles and Gallons) just like you can divide the numbers.  When you have miles on the top and the bottom lines, they cancel each other out.
297496
I'm already half way there; a Vapor Chamber that converts Regular Pump Gasoline into Propane.The Problem is that it's Illegal to change anything on any Car from 1996 to the present, even if Emissions are Lowered, and Fuel Economy is Improved.100 parts of Air to 1 Part of Fuel, instead of 14.7 Parts of Air to 1 Part of Fuel, which is the Law! I've already built the Vaporizer Chamber, which is a Really Cool Gadget, and burning less Fuel would definitely make Life easier!
22306
based on the fastest acceleration..namely the 1/4 mile standard:\n\nThe 1968 Plymouth S/S Barracuda at 10.5 sec with 130 mph on the 1/4 mile speed\n\nfrom the standpoint of top end speed, earlier this year the Koenigsegg CC topped the McLaren F1's previous record hitting 245 mpg. Now there is a new dog on the field that claims 248...but is waiting validation apparently: The 2006 Bugatti Veyron \n\nYou'll like these links
559741
A divorce and a 2006 Toyota hybrid highlander limited"black"and i don't have to worry about gas i get anywhere between 32 and 38 MPG in a 7 passenger SUV it is the best.Thanks for reminding me! GOOD LUCK TO YOU!
919282
please make your question more understandable\n\nif it decreases from 30mph to 15mph over 75 metres then at this deceleration its logical to say it would take another 75metres to stop\nbut something tells me thats not the answer ! if you want me to do your homework at least have the decency to type in the full question.
1186504
A.   thermal efficiency=work done/total amount of heat taken= 3200/1.55x10^4= 0.206\n\nB.  heat discarded=heat taken-work done=15500-3200=12300 J\n \nC. Heat evolved= 15500 J\nthe mass of gasoline is heat/heat evolved per gm.\n=15500/46000\n= 0.3369\n\nD. power output = 63x 3200=201600 J
8203
i dont know the km. but ive been in a honda accord at 120 mph in neigborhood streets (120 in a quaretr mile is pretty fast) and ive been 160mph in my Honda CRX