What is the component form and magnitude of the indicated vector?
816839
(17-9)**2+(9-18)**2\n\nthen square root of it will,  give u magnitude
774120
Sure,\nYou are adding two vectors:\n\nV1 has magnitue 0.45 m/s and in the W direction (head of vector faces W) \n\nThe 2nd vector is has magnitude 0.35 m/s and 30 degrees E of N (or 60 degrees from +ve x-axis) and its tail is added to the head of the first). So the angle betwen the two vectors is 60 degrees.\n\nUse the SAS rule for finding the magnitude of the resultant vector\n\nc = sqrt(a^2+b^2 -2ab cos(theta))\n\nVr = sqrt((0.45)^2 +(0.35)^2 - 2*0.45*0.35 cos60)\n   = 0.409 m/sec \n\nThe direction of Vr is from the tail of the first vector to the head of the 2nd.\n\nTo determine the angle, A, bewteen Vr and the first vector use the sine law.\n\n0.409/sin60 = 0.35/sinA\n\nSinA = 0.74 and A= 47.8 degrees\n\nSo the direction of the craft is 90-47.8 = 42.2 degrees W of N
85418
dx/dt+ax=b :P\n\n\nmathematica had some online find-the-derivitive program, last I remember
332766
Force is a vector quantity as it has both magnitude (size) and direction.
1084380
Rectangular coordinates are component of the vector where the polar form gives all the information in a compact form. It helps to see the magnitude (how much) and phase (which way) versus having it seen as part of it is in this direction and the other part is the other. Sinusoidal and harmonic expression representation is easily described in the euler's identity/mathematics which translates to better visual representation in polar of the theory on hand.
1116580
Brian gave you the answer, but he didn't explain it thoroughly.\n\nPlace your vector at the origin of an x and y plane.  The x and y axes are perpendicular, so you can use the Pythagorean formula to get the magnitude which is the length of the hypotenuse of the right triangle formed by the points (0,0), (10,0), and (0,8). sqrt(10^2+8^2)\n\nNow you need direction which is the angle between the x axis and the vector. Since you have solved for all three lengths of the triangles sides, you can use any inverse trig function to find the angle.  Brian chose tangent.\n\nGood work, Brian!
889456
I'm not sure I understand the question, but if you want to translate the vector from its current position to the origin, then just add (4,-5) to its beginning and end points.\n The vector will now be pointing from the origin to (6,1).\nHope this helps.
1063540
This represents a plane that goes through the origin. It is perpendicular to the vector <1,1,1>.
1075810
Scalar has magnitude only; vector has both magnitude and direction.\n\nThe sum of two scalars A and B is the A+B; the sum of two vectors A and B is not equal to A and B, except when they are in the same directions.\n\nThe difference of two scalars A and B is A-B; the difference of two vectors A and B is not equal to A- B except when they are in a straight line.\n\nThere is only one product for two scalars a and B; but for vectors there are two products a dot B and a cross B.\n\nA scalar divided by a scalar is again a scalar; a vector divided by a vector is not a vector.
833474
What is what?? the magnitude?? the torque??\n\nfinish your questions
519602
Just draw the vectors\nMake sure you understand at what nagles they are\nr1 and r2 are inclined at 45 deg\nYou have asked only for magnitude\nJust apply the formula sqrt(4^2+2^2+2*4*2*cos 45)\nsqrt(16+4+16/sqrt(2))=5.595\nFor the difference part.Just reverse the sign for cos term\nyou get |r1-r2|=2.9472
4519
(4/3)*pi*r^3\n\n[four thirds pi r cubed]\n\ngood luck!
921006
Area = πab where a and b are the semi-major and semi-minor axis length
1095286
1.www.physics.uoguelph.ca/tutorials/vectors/vectors.html \n2.mathforum.org/~klotz/Vectors/vectors.html
980573
For the vertical component, you calculate SIN37 and then multiply by the lenght of the vector.\nIf the vector points down, it is a negative component.\n\nFor the horizontal component, you calculate COS37 and then multiply by the lenght of the vector.\nIf the vector points left, it is a negative component.
879746
Ek = 1/2.m.v2   (1/2 mass times velocity squared) - \n\nsorry can't do superscript on this site
874727
You need to sum the components. Let Fr, Fl, Fu, and Fd be to right, left, upward, and downward directed forces, respectively. Then\n\nFx = Fr - Fl\n\nand\n\nFy = Fu - Fd.\n\nThe right and upward directions are taken as the positive direction so that the minus sign indicates that the forces (Fl and Fd) are directed to the left and downward.\n\nThe magnitude of the resulting force is then computed as\n\nF = sqrt(Fx^2 + Fy^2)\n\nand the direction can be found from\n\ncos(q) = Fx/F\n\nUse some reasoning to be sure that the direction you compute is consistent with the orientation of the force components.