16y^2 =25 i need to factor this please help?
815860
Hello Dear \n\n- Take " √ " of eachsides\n√16y^2 =  √ 25 \n± (4y = 5)\ny = ± 5/4\n\nGood Luck dear.
631400
Factor out the y:\n\n(a-2) * y = c\n\nThen divide both sides by (a-2):\n\ny = c / (a-2)
924187
= 16ab/20ab^2\n= 4/5b // 16 and 20 can be reduced by 4, and an a and a b cancels out\n\n3*3*3*3*3 = 3^5\n3*3 = 3^2\n3^5/3^2 = 3^3\n= 3*3*3
334674
(y+2)^2/25 + (x-3)^2/16 = 1\n\n(y+2)^2/25 = 1 - (x-3)^2/16\n\n(y+2)/5 = (+/-)sqrt(1 - (x-3)^2/16)\n\ny+2 = (+/-)5sqrt(1 - (x-3)^2/16)\n\ny1 = -2 + 5sqrt(1 - (x-3)^2/16)\n\ny2 = -2 - 5sqrt(1 - (x-3)^2/16)\n\n\nOR\n\n\nSometimes, TI-84 and 83 calculators come pre-packaged with a conic sections application. Go in and it will ask for the values of a,b,h and k for the ellipse equation:\n\n(x-h)^2/a^2 + (y-k)^2/b^2 = 1\n\nInput the values, and it will do all the work for you.\nIf you don't have this application, just graph using 2 seperate functions.
81890
it's not factored completely if you leave it as a^2-25 so the proper answer is 5(a-5)(a+5)
305313
4x^3y^2-16y^3-9y=\ny(4x^3y-16y^2-9)
1079532
2xy^2(3y^2)^(1/3)\n\ndivide the exponents by three, leave the remainder in the root.\nfind the lowest cubic factor in 24 (8=2^3) and take it out, leave the 3 in.
913842
25x+75y-25z\nSum of all coefficients\n= 25+75-25\n=75
893957
well darling ;\nimagine this like that\n\ny^2 + ( a+b)y + ab \nyou need to find " a+b " & " ab" \nin our function \na+b = 16 & ab = 64 \n( y + a)( y + b) \n( y + 8 ) ( y + 8)\n{ ' 8 + 8 = 16 '   &  ' 8 * 8 = 64 ' }\nso\n( y + 8)^2\n\nGood Luck sweetheart.
746280
c^2 = 3^2 + 4^2\nc^2 = 9 + 16 = 25\nc = square root (25) = 5
689072
5x + 3y = 16 ------ equation 1\n\n2x + 3y = 1 ------- equation 2\n2x = 1 - 3y\nLet x = (1-3y) / 2 \n\nReplace x with y in equation 1, and solve y\n\n5 [ (1-3y) / 2 ] + 3y = 16\n5 (1-3y) + 6y = 32\n5 - 15y + 6y = 32\n9y = -27\ny = -3\n\nReplace the value of y to solve x\n \ntherefore x = [ 1 - 3(-3) ] / 2\nx = 10/2 = 5\n\nYou can try and solve the other pair of system using the same basis as above.
302953
5y(y^2 - 5xy - 14x^2)\n\nIf you're expanding, you get:\n\n5y^3 - 25xy^2 - 70yx^2\n\nIf you're factoring, you get:\n\n5y(y^2 + 2xy - 7xy - 14x^2)\n= 5y( y(y+2x) - 7x(y+2x) )\n= 5y(y + 2x)(y - 7x)
952496
Wasn't it 2/y^2-16 = 10/y^2+4y?\n\nIf so:\n\n2/y^2 - 16 = 10/y^2 + 4y\n10 (y^2 - 16) = 2 (y^2 + 4y)\n5 (y^2 - 16) = y^2 + 4y\n5y^2 - 80 = y^2 + 4y\n5y^2 - y^2 - 4y = 80\n4y^2 - 4y = 80\n4 (y^2 - y) = 80\ny^2 - y = 80/4\ny^2 - y = 20\ny^2 = 20 + y\n\nso now, we have this:\n\n2/y^2 - 16 = 10/y^2 + 4y (where we can replace y^2 with 20 + y)\n10 (y^2 - 16) = 2 (y^2 + 4y)\n10 (20 + y - 16) = 2 (20 + y + 4y)\n5 (20 + y - 16) = 20 + y + 4y\n100 + 5y - 80 = 20 + 5y\n20 + 5y = 20 + 5y
249211
Quickest way to solve it- take the first equation and square it, giving you \nx^2+y^2-2xy=25, while the other equation gives you\nx^2+y^2    =15\n\nSo xy = -5 (if that's not immediately obvious, take the difference of the two equations above and solve for xy).\n\nA word of advice on the side: there are certain quadratics that show up all the time on the SAT, such as (x+y)^2, (x-y)^2, and x^2-y^2. It's worth your while to become intimately familiar with these guys, so that you can expand and factor them immediately.
811806
If x is 2, then 8x is 16.\n\nIf y is 3, then 4y is 12.\n\n16-12 is 4.  :o)
586962
(6y^2-3y)(y+7)-->(2y)(y-1)(y+7)\nif that helps
679588
Multiply it out...\n2y+6y+24x-24y-6x\nThen combine\n-16y+18x OR\n18x-16y