HARD Challenge Question!!!?
821062
I think you are supposed to assume the minimum velocity possible, which means tossed at a 45 degree angle. Otherwise he could throw it farther by using the same velocity at 45 degrees.\n\nvelocity = v, y velocity at time t = v/sqrt(2) - 10t so y velocity is 0 at \n\nt = v/(10sqrt(2))\nIn time 2t the distance travelled is 96.90, so\n\n96.90 = 2tv/sqrt(2)\n\nThese are 2 equations with 2 unknowns, solve for t and v (there may be a careless mistake in the details since I did this fast, but the technique will work)
461845
challenge = provocare...
263164
I won 10 points!\n\nThis is pretty easy. Try to stump me with harder ones.
617115
It's 'butt-munch' you dillwad...\n\nLook it up, it's not that hard. Do your own homework!
970878
OOOOOOOOOh i LUV LUVLUVLUV challenge 24!!!! ok her are some ideas:\n7,2,2,1=(7-1)(2+2)\n6,8,2,1=(8/4)(6*1)              ***All taken from Challenge 24 cards\n3,3,6,2=(3+3)(6-2)                     (single digit)\n9,2,5,1=(9-1)(5-2)\n~* ah what the heck i dont have time to finish this. I'llget back to you later, soon. and for future reference, DO buy challenge 24 cardsand so you can use them often. the only annoying thing is, it doesnt come w/anser key u have to figure it out yourself:(
871692
ELUSIVE-\n*sorry jus needed the points!
966057
well well..the second time i see the same question!!\nshow some of ur work buddy.. ur a degree student and u dont simply put the questions on others..u wud never pass that way...\nso prove that u have tried ur best to solve this problem..show some coding that u have made!
176413
Great puzzle, took me awhile to make it to f=1, g=4. The letters are from a-i: 9,8,7,2,6,1,4,5,3.\n\nPlugged in this is: (9 * 87 + 2/6) / (14 + 5/3) or (783 + 1/3) / (15 + 2/3) which equals 50.\n\nAnswer logged Sunday, March 12th, 3:20 pm with no other valid answers yet. Sorry to have to write that, but I've seen people change their answers too many times in the past.
24167
5\n\nC'mon man make it harder.
1065918
To get your answers, imagine what has to happen.  \n\na) First, you have to pick 1 of the 4 white balls out of the 12 balls there.\n\n2nd, you have to pick 1 of the 3 white balls left out of the 11 balls there.\n\nSo, in order to get a red and then a red, you need to get 4 out of 12 followed by 3 out of 11 or 4/12 times 3/11 or 12/132 = 1/22.\n\nb) First, how many ways can 5 people line up?  5!.  How many ways are correct (assuming they all have different names, only 1).  So, the prob is 1/5! or 1/120.
117477
Tough one ... these websites should help, or at least give you some ideas ...  good luck!!
78308
Real World/Road Rules Challenges
88228
alright... whats the word u want the answer to this riddle to be? Hunger! yay 2 points for answering a question lol, sry, but thats a tricky one
828134
this is very hard to answer, please try yourself
689151
New puzzle: Three words.\n\nY_u ~  nee_ ~  Je_e_!
450313
10 percoset should do the trick\nThis is a joke....just in case you are dumb enough to try it.lol
775790
pretty tough question.