Hz, Wave, and frequency physics hw?
818497
1) 4.2cycles/41.4s = X/1s\nX=0.101Hz\n\n2)40cycles/84s = X/1s\nX=0.476Hz
970598
Try this website for information on transverse and longitudinal waves:\n\nhttp://www.kettering.edu/~drussell/Demos/waves/wavemotion.html
821940
Electromagnetic waves move at a fixed speed, the speed of light: 299,792,458 metres per second.\n\nFor example, lets say the speed of light is 1 m/s and a length of string represents a how far the wave has travelled in a second... 1 meters.... it doesn't matter what the frequency is that's as fast as it can go.\n\nThe higher the frequency (more cycles), the shorter the wavelength in the 1 meter length of string.\nso\n1 hz = 1 wavelength per meter (wavelength = 1 m)\n2 hz = 2 wavelengths per meter (wavelength = 0.5 m)
1123630
1) 10 full wave-length passed by 120 sec so the wave period is 12 sec. f=1/T so f=0.083333 Hz\n2) First of all, light speed=3 x 10^8 m/s.\nSecondly, f=v/lambda\n(where v=light speed and lambda=wave-length)\nso f=3X10^8 / 6.6 x10^(-7)=4.5454 x 10^14 Hz (approx. 4500 GHz = Giga Hertz)
827543
The equations involved are:\na) freq*wavelength = velocity of wave\nb) energy of radiation E = h*freq, where h is Plank's constant.\nYou can work out from these that the choice should be a.
1160585
4 Hertz = 4 times per second
763829
I'm not familiar with that particular book, but the differential equations of simple harmonic motion are interesting.  You can make the system as complex as you like.  I've studied SHM in both maths and physics.  I simulated SH oscillators with operational amplifiers; in other words an analogue computer.  First you simulate a frictionless pendulum, then you introduce friction so the oscillations die away, then you introduce forcing terms of various frequencies to see what happens; like pushing a child on a swing.  If you're really clever, you can introduce hysteresis (delay), and extra degrees of freedom (flexible joints in the pendulum), and vary the Q of the system (how sharply you can tune it to the resonant frequency).  It's about the most open-ended project I ever saw.  I did it in second-year physics.  At its simplest, it's just sixth form maths, but you can turn it into an impossibly complex exercise in chaotic systems if you're clever.
924166
yes u can. use the equation E = hf where E is the energy and h is the planck constant. once u find f which is the frequecy...insert into equation velocity = wavelength x frequency...assuming u noe the velocity of the hydrogen!! :)\nOH but by the way since ur answer is in kj/mol u need to convert it to kj with the avogadro number which i forget...i'm sure u can find out!
744417
My answer assume that you have a good knowledge of integral calculus. If it's not the case, then use a soft like Matlab...\n\nNotations :  I will use SIGMA for the 1 to infinite sum and INTEGRAL for the integral between -T/2 and T/2.\n\nIf you consider a periodic signal x(t) with a T = 1/f0 period, its Fourier development is :\n\nx(t) = a0/2 + SYGMA[k=1 -> infinite]  (ak*cos(2*PI*f0*t)) +  SYGMA[k=1 -> infinite] (bk*sin*(2*PI*f0*t))\n\nwhere f0 = 1/T is the fundamental frequency  of the signal, a0/2 the mean value and ak, bk are the Fourier coefficients in cosinus and sinus.\n\nThe Fourier coefficients are calculated like this :\n\nak = 2/T * INTEGRAL[-T/2 -> T/2] (x(t)*cos(2*PI*k*f0*t) dt)    for k >= 0\n\nbk = 2/T * INTEGRAL[-T/2 -> T/2] (x(t)*sin(2*PI*k*f0*t) dt)     for k >= 1      \n\nAfter developpement, you will find the values  of all a and b coefficients in function of k.\n\nI hope this will help :)
1044821
Frequency 2Hz\n\nTime period = 1/2 s\n\nAmplitude = 10 cm.
303175
go to this site:\nhttp://en.wikipedia.org/wiki/Sine_wave
126863
The RF waves emanating from an antenna are generated by the movement of electrical charges in the antenna. Electromagnetic waves can be characterized by a wavelength and a frequency. The wavelength is the distance covered by one complete cycle of the electromagnetic wave, while the frequency is the number of electromagnetic waves passing a given point in one second. The frequency of an RF signal is usually expressed in terms of a unit called the "hertz" (abbreviated "Hz"). One Hz equals one cycle per second. One megahertz ("MHz") equals one million cycles per second.
78772
Off the top of my head:\n\nFlow rate, pressure, viscosity, temperature, rate, calorimetry, optics, nuclear phys., tension, stress & strain, surface tension, acoustics, magnetism, elctricity.
937514
wavelength = speed of light / frequency\nfrequency = speed of light / wavelength\nf = (3*10^8 m/s) / (615*10^-9 m)\nf = 4.878*10^14 Hz\n\nwavelength = planck's constant * speed of light / energy\nenergy = planck's constant * speed of light / wavelength\nE = (6.626*10^-34 J*s) * (3*10^8 m/s) / (615*10^-9 m)\nE = 3.232*10^-19 J
146531
This site is constructed well and has a high level of detail (up to degree level).\n\n\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
283860
Frequency = speed of light/wavelength.\n\nMake sure you keep the units straight when performing the calculations or it may not make sense.\n\nSo for your problem its (3 x 10^17 )/200 = 1.5 x 10^15 Hz
49259
c = yf\n\nc = speed of light (3 x 10^8 m/s)\ny = wavelength\nf = frequency\n\n==> f = c/y\n\n==> f = 3 x 10^8 m/s / 0.032 m \n\nf = 9.38 x 10^9 Hz\n\n-or-\n\nf = 9.38 GHz\n\n:)