math trivias please!!! i nid the best now!   TnX!?
818905
The concept of representing complex numbers as a vector in cartesian plane coordinates was developed by a Norwegian surveyor, Caspar Wessel.
1003302
The official site only lists back to 1996, so you might try posting a message here\nhttp://www.mathlinks.ro/Forum/forum-314-50-50.html\nor, email mathcamp and ask them mc-info@mathcamp.org
30751
The Edifier has it right, but darned if I can follow the notation. You really need to see this written out like a textbook to understand what's going on.\n\nClick the link below in "sources" to see the answer hosted at my website www.calculus-help.com. Right now, Yahoo! answers, as far as I can tell, doesn't allow graphics, which makes it tricky to answer ANY math questions.\n\nPlease don't post math answers, guys, if the poster knows the answer but can't get there, and you get something completely different.
709282
Quick Math-Mind Games
29868
http://www.bymath.com\n\nand this is my weblog it is new but it will been good in future http://bymath.blogfa.conm\nDont forget comment!!!
116787
Euclid! Come and help us please!!
582286
How much do I care for this trivia?\nThanks for the 2 points!
195396
What's with the ... ? Is that a space for a number, are you supposed to guess whether to use the + or the x ? I don't get it, I think I'm gonna cry :~(
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
145326
i'm good at math, but what exactly is the quustion??? there isn't any... what is it, a equation?\nany way you can post it to sciences and mathematics > mathematics, im sure someone there can help you...\n\n>>>ok one minute i'm working on it...\n\n>>>there you go:\nlets do the first: (x-3)(x-1)(x+2)\nfirst we open the last two parentheses as in usual opening, and the (x-3) remains as it is. we get (x-3)[x^2+2x-x-2]\nequals (x-3)(x^2+x-2) then we open the two parentheses left. first we multiply by the first member (x) then the second (-3). then we get:\nx*x^2+x*x+x*(-2)-3*x^2-3*x-3*(-2)\nx^3 + x^2 - 2x -3x^2 -3x + 6\nand finally:\nx^3 -2x^2 -5x + 6\n\nthe second is the same way, i'm doing it, good luck :)\n\n>>>the second: (x-5)(x+1)(x-2)\nfirst we open the last two parentheses as in usual opening, and the (x-5) remains as it is. we get (x-5)[x^2-2x+x-2]\nequals (x-5)(x^2-x-2) then we open the two parentheses left. first we multiply by the first member (x) then the second (-5). then we get:\nx*x^2+x*(-x)+x*(-2)-5*x^2-5*(-x)-5*(-2)\nx^3 -x^2 -2x -5x^2 +5x +10\nand finally:\nx^3 -6x^2 +3x + 10\n\ni hope i helped...\n\n>>>oh i leave the first one to the last because i have to leave one of the three, and it really doesn't matter which one i leave. for example on the first i left the first parenthese (x-3)[(x-1)(x+2)] but i could leave the last [(x-3)(x-1)](x+2) or the middle (x-1)[(x-3)(x+2)] and i'd still get the same answer. i have to leave one of the three bcuz i can't open them all together, it's complicated and hard, and by opening two ane leave one it becomes much easier.
604123
I figured it out... the answer is 1/(13*(2-3x))\nIf you need an explanation tell me
176413
Great puzzle, took me awhile to make it to f=1, g=4. The letters are from a-i: 9,8,7,2,6,1,4,5,3.\n\nPlugged in this is: (9 * 87 + 2/6) / (14 + 5/3) or (783 + 1/3) / (15 + 2/3) which equals 50.\n\nAnswer logged Sunday, March 12th, 3:20 pm with no other valid answers yet. Sorry to have to write that, but I've seen people change their answers too many times in the past.
441947
pentagon DUH! lol sry (Hexagon is SIX!)im in geometry rite now so yea
1066393
do math problems it does the trick everytime!!!
502657
Try this link and read it all the way through.  It's short.\n\nhttp://mathcentral.uregina.ca/qq/database/QQ.09.00/tom3.html\n\nThis link is better:\n\nhttp://mathforum.org/library/drmath/view/56760.html\n\nJust scroll down.
405561
X  = Nothing \nor X  = 24th letter of the English Alphabet.\n\nAm I too clever or do I get the 10 points for being a smart ass?
1135008
This question! Isn't it under mathmatics? LOL!