Identify the axis of symmetry, create a suitable table of values?
821185
I would complete the square first of all:\n\ny = x² - 4x = x² - 4x + 4 - 4 = (x-2)² - 4\n\nSo now your parabola's equation is in the format y = (x-a)² + b\n\nWhen it's in this format, you can easily tell the axis of symmetry, it's x=a.  So in our case, we see that our axis of symmetry is at x=2.\n\nTo get a table of values, just plug in various values of x to solve for y, as follows:\n\nx | y\n--------\n-1 | 5\n0 | 0\n1 | -3\n2 | -4\n3 | -3\n4 | 0\n5 | 5\n\netc.\n\nHope that helped!\n\n~ ♥ ~
538459
equal number of sides and equal measure of angles\n\n\nor at least thats what i remember from geometry!
728902
This can be done easily using a scientific calculator or there are many angular / decimal tables in Trig text books or many machinists handbooks or machinists guides.\n\nwww.industrialpress.com/en/tabid/63/Default.aspx
834801
the geometrical center and center of gravity match only for object that have symmetrical shape (around an axe or point: like a cylinder or sphere) and a constant density
638682
Domain ~ x values\nRange ~ y values\n\nYou have to work the function and figure them out.
942299
i cannot do this for you, but if it is e^(x^2) then it is going to be symmetric along the y axis right?\n\nso take the graph of e^u, where u=x^2, and do it from 0 to 9 (the square of 3) and then reflect that on the y axis and you have your answer. At u=0 the graph is going to equl to (0,1) and at 9 it will look like (9, e^9).  If you wanted to go from e^(x^2) from our e^u then it will just be squished (closer to the y axis at all points except 0), but you will still get a general feeling from what i said.\n\nalso i think it is possible you left out a negative in front of the x in which case the graph will look like the normal curve: http://www.uow.edu.au/student/attributes/statlit/modules/images/normal-curve-1.gif
102977
symetric designs, ratios from diagram to real material
829392
just a piont of view, but normally to divide something symmetrically you have to do it at the widest piont along the centre line. where as assymetricaly is off the centre line at a narrower piont and therefore not a symmetry,this only applies to poloygons and symmetric shapes.  hope this helps
442406
Make a table of values.  Then plot the points.  Your graph should be a "V" shape (not a parabola which is U shaped)---whether upright, sideways, or downwards.
608711
i think it's a parabola.. im not sure. u should try plotting it on a graph.. substitute  the x and y values and see what form comes out..
956580
In Excel you can graph the data and then add a trendline.  You can even have it display the equation for the trendline.  Some possible choices for fit are linear (line), exponential, polynomial of degree 2, 3, 4, 5, 6, etc.\n\nIf you give some sample data, I might be able to help further...
907364
Almost.  You would actually include the endpoints 0 and -3 (so you need to use a bracket instead of parentheses).\nD = [0, infinity)\nR = [-3, infinity)
608785
The same way you would measure your TV screen....diagonally
1017458
symetric properety...\n\n\nok heres why.....\n\n(pretend the equal signs are parallel line segments)\n\n===========================\n\n\ndo you see how you can split them dont the middle, thats called the symetric property
513263
Spiral, lenticular, elliptical and irregular\n\nSee the link
675746
by the number of sides and angles
691753
maybe a hexagonal prism http://en.wikipedia.org/wiki/Hexagonal_prism http://en.wikipedia.org/wiki/Prism_%28geometry%29