how many possible combinations are there for a 3-dial master lock?
817139
10 digits ^ 3 dials = 10 * 10 * 10 = 1000 possibilities\n\n~ ♥ ~
761643
How many at a time?  You didn't say.\n\nThe number is an expression called  nCr, which is \nn!/((n-r)!r!), but it's pretty simple to think of it this way:\n\nI'll suppose you want them 3 at a time.  Then, for the first one, with 6 letters to choose from, write 6*5*4 on top (three factors because we want 3 letters) and 1*2*3 on the bottom\n6C3 = 6*5*4/(1*2*3)\n        = 20\n\nIf there had been 10 letters and we wanted to know the number of combinations 4 at a time, we would put four factors on top and bottom:\n10C4 = 10*9*8*7/(1*2*3*4)\n          = 210
920768
One solution is\n0, 2, 4, 6, 8, 10, 12, 1, 3, 5, 7, 9, 11\nBut there is a huge variety of solutions\n\nSorry Chris I did not copy so here is another\n\n0, 11, 5, 2, 9, 3, 1, 4, 10, 7, 12, 6, 8
378556
There are absolutley hundreds of thousands if not millions of identical keys in the world, simply because it is impossible to make every one unique.  For example, a certain brand of door lock has 5 pins, each of which can be at one of 5 different settings.  this means that for this brand there are only 3125 different keys made (5^5).  if for example they made 1 million locks last year that means that if you bought one of those locks there would be 320 identical locks also sold.\n\nobviously manufacturers make many more than a million locks in a year, so really the security provided by a lock is not provided by that lock being unique, but instead by the fact that it would be impractical to find one of the identical keys (think of a theif carrying three thousand keys to your door and trying each and every one of them to try and break in)
427494
The number of combinations is determined by multiplying the number of possible numbers of the first by the number of possible numbers of the second, third and last. If the any of the numbers could be used more than once, the answer would be 4 X 4 X 4 X 4 = 256. Since this problem says that the number can only be used once, then the number of possible choices for the first is 4, the second is only 3, the third is 2, and the last is only 1. So the way to arrive at 24 is 4 X 3 X 2 X 1. Maybe an example to make sure it is clear. If the first digit was 3, then the second could only be one of 5, 8, or 9. If the second was chosen as 5, then the third could only be one of 8 or 9. The last then could only be the one not selected as the third.
335957
eh not real sure but should have a key with  a blue Fn or simalar button that enables the alternate to other keys,  try holdin this button down and simultaneously pressing the corrosponding colored Num Lock button.  hope this helps
845925
If you problem, or part of it, is:\n\nHow many 8 digit numbers can be formed from this list of digits?\n8! / (3! * 2!)\nThe number combinations of digits has tobe reduced by 2! because of the 2 "6"s.\nThe number combinations of digits has tobe reduced by 3! because of the 3 "2"s\n.\nBut since the number cannot exceed 65,500; all larger numbers must be eliminated. Subtract the number of 8 digit numbers that can be produced from the list that start with "9". Likewise "7". Likewise "69", "67", "66", "659", ""657", and "656".\n\n\n\n(Try to state your problem clearly and completely.)
579803
this has some lock diagrams. hope it helps
88776
Are you looking for a set of 8 consecutive whole numbers that when you add 7 of them together in different combinations you receive those 3-digit responses?\n\nWell you've only listed 6 possibilities and only one of those is odd.\n\nStarting at 29 the lowest combination is 224 and the highest is 231.  Starting at 28 the lowest is 217.
1118957
The first number has to be (x+6) and the second number is (x).  There are four possible combinations: 6,0 (60); 7,1 (71); 8,2 (82); 9,3 (93).  60 plus 8 (68) does not equal 06, or 6.  71 plus 8 does not equal 17.  82 plus 8 does not equal 28.  93 plus 8 does not equal 39.\nUnfortunately, this problem is impossible.\nSorry I couldn't be of more help.
178600
A key that opens any lock
469878
10 * 9 * 8 * 7 * 6 = 30240 combinations
220007
The above answers are correct, assuming that one of the people with the second key would be available to open the second lock.  However, If it was not known if any 1 person would be available to open the lock, it would be nice for ANY two to be able to open the door.  \n\nIn this case, you would need 10 locks and 90 keys. Each person would get one key for each of 9 of the locks, excluding 1 (different) key / lock per person. Therefore, a single person could open 9 of the locks, but it would take any one of the other 9 people to open the last lock, ensuring that your conditions are always met.\n\nIn summary -\n10 locks\n9 keys per lock, total of 90 keys.
938348
There are many combinations. One of them is 1,2,3,4,5,16. Is there some specific property you wanted these six numbers to have?
791761
3483\n\nThe numbers correspond to the buttons on a telephone\n\n663 - ONE\n896 - TWO\n84733 - THREE\n3687 - FOUR\n3483 - FIVE
836747
2,3,1 (nothing goes there) ,6\n\nHope it helps :]
230780
1,2,3,4,5,6  Try those!  (Same odds as any other combination of numbers!)