A Chemistry Question!?
831776
A few are:\nMg, Zn, Al, Fe, and Cu.  They will dissolve at different rates according to the activity series of the metals.
831216
Cu (s) + Pb(NO3)2 (aq) ---------> No Reaction. \nCopper will not replace lead.\n\nreaction VI in the attached link.
518616
Check this out....\n\nhttp://www.sciencestuff.com/prod/Chem-Rgnts/C2043
1040448
ask your chem prof or tutor ..it's hard to explain over the internet!
2247
And this is chemistry how??
1081543
i find  your question, interesting but quite inexplicable .\n this is something new to me . I was not  very attentive in my chemistry studies ..\n\n My memory centre is all clogged up with other facts , just now ; \n this must be the reason for me , to draw a blank here\n \n i will go hang my head in shame .\n \n or hunt up that  answer,  LIT UP for all to see , on Google or some other wondrous search engine .\n\n good luck \n \n.
136146
The 1st answer is wrong. The reaction is\n\nNa2CO3(aq) + SrCl2 (aq)--> 2NaCl (aq) +SrCO3 (s)
167656
the correct answer is B. A is wrong b/c it isn't an oxidation reduction reaction. Looking at a table of solubility products will confirm the answer is B.
129663
Please do your own home work.\n\nI suspect you are missing a symbol, it probably should be,\nN2O4  <==>  2NO2\n\nThink about how each of the changes will effect the equilibrium of the reaction.
691513
Check that both sides of equation match. Here is an example:\n\n3 CH3CH2OH + 2 Cr2O7 2- + 16 H+ --> 3 CH3COOH + 4 Cr3+ + 11 H2O\n\nThere should be an equal amount of H, C, O, Cr in both sides of the equation. \nIt is sometimes difficult to know where to start balancing an equation. In such case you should try to find an element/molecule that does not appear in every molecule on the other side of the equation. Eg. when balancing this equation above, I first balance the number of Cr because it is on its own on the right side. Sometimes you just need to try and play with numbers for a while to find the right answer. Hope this helped...
381120
look it up on any periodic table - like the one linked below... good luck!
725621
6Rb(s)+N2(g)--->2Rb3N(s)
839410
This compound is an amine.  You can identify it by the NH2 (amine group) at the end.  You did a fair job with the structure considering the limits of the text here.  I am sure you realize that two of your carbons do not have the correct number of bonds.
733447
Br+H20--->HBr+O\n\nNi(II)O+H20--->Ni+H202\n\nKO2+H2O--->KOH + H2\n\nHope that helps.
539827
(a) 2 NaClO3 -> 2 NaCl + 3 O2\n\n(b) 3 MnCl2 + 2 Al -> 3 Mn + 2 AlCl3\n\n(c) C4H10 + 13/2 O2 -> 5 H20 + 4 CO2 \n                  or\n(c) 2 C4H10 + 13 O2 -> 10 H20 + 8 CO2\n\nBalancing is quite simple for these simple equations. You just have to see the left hand side pick up an element, see how many atoms of that element are there in it and multiply the R.H.S compound containing that element with a number which will be equal to no. of atoms in the l.h.s. Then again repeat the procedure by picking another element.....see it's quite difficult to explain you with writing aneways i hope it helps u :)
859386
Due to differences in chemical structures
78348
The answer has to do with symmetry of the molecule and hydrogen bonding.  That should get you going in the right direction