How do you determine whether two lines are parallel, perpendicular, or neither?
823070
Get the slopes of the two lines using the formula:\n(y2 - y1)/(x2-x1)\n\nIf the slopes are equal the lines are parallel\nIf the slopes multiply together to give -1 the lines are perpendicular\nIf the slopes do not meet these conditions they are neither\n\nHope this helps!
893759
Is a line perpendicular to it. The proof is easy.\nDraw a line not perpendicular to the straight line.\nCall this line L1.  Now draw a line perpendicular to the straight\nline. Call it L2. Note that you have a rt triangle with  sides made of L1 and a side from the intersection of L1 and the original line\nto the intersection of L2 and the original line and a hypotenuse which is L2. That makes L2 longer than L1 . So the shortest distance is necessarily perpendicular.
1078788
For any line length X, it can be divided into 7 equal parts like so:\nStart with your segment --we'll call it AB-- and at point A, draw a ray going towards the top of your paper.  Then, with your compass, mark off seven equidistant points, starting at A (put your compass on A, make a mark on the ray; put your compass on that mark, make another on the ray, etc.) Then, draw a segment from your 7th point to point B.  Then just draw 6 more parallel lines (constructing congruent arcs and such) and your segment AB is divided.
849182
2x-3y=6 is the same as y=2/3x-2\n\nso in order to be perpendicular to this line, you must have slope -3/2\n\ntherefore L has slope -3/2 and has y-intercept of (0,2).  so plug that into slope-intercept form\n\ny=(-3/2)x+2
823237
There is several way to solve the problem, but I think it is easies, to find the parametric representation, and then use, that the scalar-product of the orientations-vectors is zero, if the line are perpendicular, and the orientations-vectors is linear depended if parallel.\n\nL1:  y = -½x-3 => (x,y)= (1,-½)*t+(0,-3)\n4x-2y+5 = 0 <=> y=2x+5/2=>\nL2: (x,y) = (1,2)*t + (0+5/2)\n\nbecause (1,-½)*(1,2)=1-1=0 the lines are perpendicular
753784
Plumb in the vertical and square in the horizontal.\n\nYou can use a square or measurements to determine square in the horizontal plane.  Use plumb bob, or level to determine if it is perpendicular to the ground.  Not sure what you are trying to do.
218561
A parallel line must have the same slope.\nSo you just need to find slopes of the lines that  you have.\n1) 5y= -4x - 11\ny = -4/5x -11/5\nthe slope m = -4/5\n\n2) 4y= 5x-7\ny= 5/4x -7/4\nthe slope m = 5/4
354533
1. True. \n2. True.\n3. True.\n4. False. A parallelogram has no symmetry at all.\n5. True.
908381
Note that I am using properties of standard form of an equation of a line (Ax+By=C) below.\n\nslope of a line from an equation in standard form is -(A/B);\n\nso the slope of your original line is -3/2.  Slope of a line perpendicular is the opposite reciprocal of the slope, so 2/3. \n\nUsing -(A/B), the left side of the equation will be:\n\n2x-3y; to find the right side, plug the point in:\n\n2(3)-2(2) = 6-4 = 2\n\nSo, an equation is 2x - 3y = 2
96323
2 lines are parallel if their slopes are equal. 2 lines are perpendicular if the product of their slopes is -1 (or if the slope of one line is the negative reciprocal of the other)\nFrom your given, the slope of the first equation is 3/5\nusing y = mx + b (m is the slope)\nThe slope of the second equation is -5/3. Notice that their product is -1, so the lines are perpendicular.
655971
To find if the vectors are perpendicular, you should find the dot product.\n\n4*4 + 5*-2 + -3*2 = 16 - 10 - 6 = 0\n\nSince the dot product is 0, the vectors are perpendicular.\n\nTo find if they are parallel, you check if the vectors are multiples of each other.  Since they are perpendicular, though, this is unnecessary.
863511
Rule #1) If the slopes of the lines are the equal, then the lines are parallel.\n\nRule #2) If the slopes of the lines are the negative reciprocal of one another, then the lines are perpendicular.\n\nRule #3) If the slopes of the lines do not meet any of the above criteria, then they are regular intersecting lines.
77842
the equation of a line that is perpendicular to another line will have a slope that is an opposite reciprocal to the other line (ex: if the slope of a line is 1/2, the perpendicular line will have a slope of -2).
627294
When two lines cross, 4 angles are formed.  Let p be the point of intersection and move around p counterclockwise.  Call the angles w x y and z.  Note that x and y are supplementary, since they join to make one of the two lines.  Similarly, y and z are supplementary, as they join to make the other line.  Thus x+y = 180° and y+z = 180°.  This means x = z.  These are called vertical angles, on opposite sides of p.  By the same reasoning, w and y are vertical angles, and are congruent. \nWhen presented with vertical angles, one measurement determines everything.  If w is 50° then so is y, while x and z are 130°.  If w = 90° then all four angles are right angles.  In this case the lines are said to be perpendicular.
572729
When two lines are not perpendicular, the types of angles that can be formed are:\n\n(1) Acute - one of the angles formed by the two lines is less than 90 degrees.\n(2) Obtuse - one of the angles formed by the two lines is more than 90 degrees.\n(3) Straight - the two lines are somewhat inclined in the same direction\n(4) Reflex - one of the angles formed by the two lines is either greater than 180 degrees, whilst the other is less than 180 degrees (which the exception that the two lines form a 270 degree, and a 90 degree angle). This applied to angles of a revolution.
1060257
Lines that do not intersect are parallel or skew; lines that intersect are perpindicular or non-perpindicular.
1107584
|\n  | \n  |  A\n  |\n  |_______\n......B\n\nThis is what "A" perpendicular to "B" looks like.  I hope this helps!