Help, Hard problem...?
821093
Can someone help me with my precalculus problem? Can you please read the following problem and figure out the?\n\nCan someone help me with my precalculus problem? Can you please read the following problem and figure out the equation for me along with how you figure this out?\n\n\nA tsunami (commonly called a “tidal wave” because of its effect is like a rapid change in tide) is a fast moving ocean wave caused by an underwater earthquake. The water first goes down from its normal level then rises at an equal distance about its normal level, and finally returns to its normal level, the period is about 15 minutes.\n\nSuppose that a tsunami with an amplitude of 10 meters approaches pier Honolulu, where the normal depth of water is 9 meters.
900562
I'd suggest searching for such problems here on yahoo answers.  You can find out how to do it.
934101
what's the height?  you need the height to finish this problem\nwhat type of shape is it?  a cylinder? cone?\nbe specific or no one can help you
195201
i think u typed the question wrong, can u please correct it and if u have 2 unknowns, please give 2 equations, else u cant get a definite solution
1132678
Directions how to do this can be found in the text book.\n\nDo your own homework!
828134
this is very hard to answer, please try yourself
219160
hi,i can not answer your question but i am having the same problem and i can`t find anyone to help,\nwill someone help us????
435388
damnt i should have paid attention calculus...\n\nlet pam...pam...breat....dimension......carry the one.....as x approaches zero......carry  the two....hold on...\n\nthis could take a while.
625162
Try dictionary.com, m-w.com, or one of the thousand other good dictionary websites on the web, as for problems, try search on http://mathforum.org/
43253
Depending on what you need to solve, you need two angles and a side, or two sides and an angle. Hit me with an E-Mail if you are stuck with something.\n\nkeptcompany@yahoo.com
1020883
i am sure you can find a math tutor that will be happy to help you when you explain what the problem is.\n\nso what IS the problem, anyway?
1066144
Without the knowledge of where point e is, this problem is insolvable.\n\nI suspect, however, from a brief diagramming session, that you will need to solve for the length of ab using the Pythagorean Theorem, and set up similar triangles.
855129
Word problems like this can be hard.  Everybody has problems with them sometimes.\n\nIt does help to draw it out.  So you draw a little rectangle like this:\n ______________\n|                            |\n|                            |\n|______________|\n\n2 of the sides are 120 m and the other 2 are 150 m.  So you take 2 times each of these numbers and add them together:\n2(120) + 2(150)\n\nThat's your perimeter, in meters.  Now if your poles are 2 m apart, you don't need one for every meter you get in your answer, you only need 1 every 2 meters.  So you divide your answer by 2, and that gets your number of poles you need to put around the field.
1014316
would you like to supply me with some formulas? im out of grade 12 physics and i forgot most of the formulas. trust me from experience, just plug numbers into a formula and things will work\n\nF=mg = ma\nFk=μkN\na= vf^2 - vi^2 / 2d
430201
Its tricky work, i need digrams to explain to you so your better just following this link, I think it will help you out.
702610
I'll try to help... \n\nFirst, I'm going to leave out all the x-terms, but just imagine they are there:\n\n.................. ........ ......4/5 56/25 -156/125 -1028/625\n5 ... -4 ... 9 ) 4 ... 8 ... -8 ... 4 ... 1 ... -8\n................... 4 .-16/5 36/5\n...................------------------\n................... ......56/5 -76/5 4\n................... ......56/5 -224/25 504/25\n................... ......-------------- -----------\n................... ............. -156/25 -404/25 1\n................... ............. -156/25 624/125 -1404/125\n................... ............. ------------------- ----------------\n................... ............. ........... -1028/125 1529/125 -8\n................... ............. ........... -1028/125 4112/625 -9252/625\n................... ............. ........... ------------- --------------- --------------\n................... ............. ................. .......... 3553/625 4252/625\n\nIf I did it correctly (which there is no guarantee), I get the answer as:\n\n(4/5)x^3 + (56/25)x^2 - (156/125)x - 1028/625)\nwith a remainder of:\n[ (3553/625)x + 4252/625 ] / (5x^2 -4x+9)\n\nHowever, with all those fractions I probably made a mistake somewhere... your math teacher is a masochist!
18128
show her, tell her, draw a diagram. If she still isnt doing it right...well, your call. At least try to help her first.