can you help with my math problem?
817408
weigh 6 coins for the first time, 3 on each sides.  If the two sides balance, then weight the remaining two coins, and you find the heavier one.  If the two sides no balance, take the 3 coins that is heavier, take out two coins from the heavier side and put them on the scale.  If the two coins weight the same, then the 3rd one is the heavier one.  If the two coins doesn't weight the same, you could easy find the heavier one.
520168
Try this:\n\nhttp://www.algebra.com/
957682
half it then times it by 2! that will give u the answer
360833
first remember that -(-x) means +x.\nthe problem is now -1/2 - 2/3 + 1/3\n\nto add or subtract froctions you need a common denominator. so choose 6\nthe proble is now -3/6 - 4/6 + 2/6\n\nadd or subtract the numerators. that answer is -5\nthe answer to this problem is -5/6
263286
the problem you presented above can be represented as,\n\n(8x^8/2x^2) + (16x^6/2x^2) - (12x^3/2x^2)\n\nthen you can simply divide each of the term\nyou'll get\n\n4x^6 + 8x^4 - 6x
934652
So let's say the problem looks like this\n\n   11\nx 12\n--------\n        <-----the answer from 11*2\n       <------answer from 11*1\n\nfirst hide the 1 from the 12 and work out the problem as 11*2\nthen work on multiplying the 1 with 11 but make sure you start putting your answer down below your first answer and the answer starts in the column that is below the 1 from the 12.\n\nfinally when the two answers are found, you can add them and get your final answer. SOOO here's what it looks like\n\n      11\n   x  12\n--------------\n           22    (this is from 11x2)\n +  11       (this is from 11 x1)\n------------\n     132 = final answer!
915953
Please, learn arithmetic.\n\n12
1076304
(1) 1.3\n(4) 4\n(5) Right\n(6) 0\n(7) 0\n(8)0\n(9)12
538653
Just put each number in for x and see what the answer is.  Example : -11/2 + 75 = -5.5 + 75 = $69.50 a unit.
787725
To solve a problem like that:\n\n2x-3+4x = 10 (i'm not sure if this is your answer but I'm using it as an example)\n\nFirst combine the x's on the left side to get 6x-3 = 10\n\nThen add 3 to both sides to cancel the 3 on the left side.  You will not have 6x = 10.\n\nDivide both sides by 6 to isolate the x.  You will now have x = 10/6 (or 5/3)
859897
***************\nQUESTION 1\n***************\nOn the first question, we first have to find the equation that we will be solving for.  \n\nAssume that x is one integer.\nWe know that x+1 is the other integer because they are consecutive.\n\nSo we now put the wording into an equation\n1/3(x + (x+1)) = x - 5\n\nNow we solve the equation\n1/3(2x + 1) = x - 5\n2/3x + 1/3 = x - 5\n16/3 = 1/3x\n16 = x\n17 = x + 1\n\nOur two integers are 16 and 17.\n\nNow we check our answer.\n1/3 of 33 = 11 & 16 - 5 = 11 We are good! :)\n\n\n***************\nQUESTION 2\n***************\nEvery hour, Amy and Randy together walked 3.6 + 4.2 km apart from each other.\n\n3.6 + 4.2 = 7.8\n\nSo, every hour they will be 7.8 more km apart from each other.  We only want 10 minutes though, and there are 60 minutes in an hour. To get how far apart they will be in 10 minutes, we take:\n7.8 * 10/60 = 1.3\n\nRandy and Amy will be 1.3 km apart after 10 minutes.\n\nWe are done! :)
851464
that is a really simple question, so if you have a calculator you should be able to get it, otherwise, it is your homework and I refuse to give you an answer to your homework. I would actually HELP you to get the answer if you asked for HELP doing it.\n\n-EA
37738
try sosmath.com  they helped me before. if they don't have the answer you are looking for they have a list of links to tons of other math sites.  \n\nand there probably is someone on your campus that can help as well.  One on one help is always best...\n\nGood luck!
653946
1 4\n2 15\n4 2\n5 100\n6 3\n7 15\n8 10\n9 10\n10 33\n11 -45\n12 2\n13 500\n14 5\n15 200
858552
Have you tried these?  Surely you've been told that division by 0 isn't possible, so there's your answer for 7.  I'm not doing any others on Yahoo answers (too many at once), but if you really need help and are willing to do as much as possible for yourself I'll help you if you email h_chalker@yahoo.com.au, but nasty Maths teachers like me won't just hand you 7 answers on a plate!
437783
1) 1, 2, 3 and 6\n2) 1, 2, 2m\n3) 1\n4) 1, 3\n\n5) 5/9 (55/99) > (45/99) 5/11\n6) 2/3 (8/12) < (9/12) 3/4\n7) 4/5 (32/40) < (35/40) 7/8\n8) 1/3 (4/12) = (4/12) 4/12
268888
I think I can do this one...I'll get right back to you when I figure it out... *grabs a pen and paper...and also tries to figure out why people are answering, saying simply that they can't or won't answer your question*\n\nEDIT...k, here's what I got...not sure if I understood what your question was asking, so I may be mistaken...\n\nm=h(x)-2x\nk=(2-3h(x))/6x