Bruce discovered that the wishing well contained $9 in nickels and dimes and that there were 30 more dimes?
818311
Nickels = x\nDimes = x + 30\n\n900 = 10(x+30) + 5(x)\n900 = 10x + 300 + 5x\n900 = 15x + 300\n600 = 15x\nx = 40\n\nso, 40 nickels and 70 dimes
738254
39 cents up to the first ounce
789045
Let\nd = number of dimes\nq = number of quarters\nn = number of nickels\np = number of pennies\n.10d = value of dimes\n.25q = value of quarters\n.05n = value of nickels\n.01p = value of pennies\n\n\n\n\nWe have the following equations:\n\nKeinv has $6.45 in coins in his cash box. \n.10d + .25q + .05n + .01p = 6.45\n\nThe number of quarters is one less than twice the number of dimes. \nq = 2d - 1\n\nThe number of nickels is one less than twice the number of \nquarters. \nn = 2q - 1\n\nThe value of the pennies is the same as the value of \nthe nickels. \n.01p = .05n\n\n\n\nIn summary,\n(1) .10d + .25q + .05n + .01p = 6.45\n(2) q = 2d - 1\n(3) n = 2q - 1\n(4) .01p = .05n\n\nWe simplify these:\n(1) 10d + 25q + 5n + p = 645\n(2) q = 2d - 1\n(3) n = 2q - 1\n(4) p = 5n\n\nSubstitute (2) into (3)\nn = 2(2d - 1) - 1\nn = 4d - 2 - 1\nn = 4d - 3\n\nSubstitute this into (4)\np = 5(4d - 3)\np = 20d - 15\n\nSubstitute n and p into (1)\n10d + 25(2d - 1) + 5(4d - 3) + (20d - 15) = 645\n\nWe distribute\n10d + 50d - 25 + 20d - 15 + 20d - 15 = 645\n\nWe add the d's and the constants\n100d - 55 = 645\n\nWe transpose the constant to the right, and simplify\n100d = 700\n\nThus,\nd = 7\nq = 2d - 1 = 13\nn = 4d - 3 = 25\np = 20d - 15 = 125\n\nTherefore, Keinv has 7 dimes, 13 quarters, 25 nickels, and 125 pennies (having a total value of $6.45).\n^_^
628939
Easy. A penny and a 1972 dime that has a value of 29 cents. Another thing, get a life and think of something original.
1072155
this is dumb... where did the $9 come from?  Something cost $25 so there was $5 change.  Dad took $2 and so that leaves $3.  Which is $1 for each kid.
210388
10 nickels =  .50      - 1.00\n2 quarters =  .50      -\n\n\n4 dimes       =.40\n1 quarters    =.25\n7 nickels     =.35\n\n2 quarters 10 nickels\n1 quarter 4 dimes 7 nickels\n8 dimes 4 nickels
588899
7 dimes and 16 nickles because set x as dimes y as nickels x+y=23 10x+5y=150 so y=-x=23 and 10x-5x+115=150 so 5x=35 so x=7 and 7+y=23 so y=23-7 so y=7 so there is 7 dimes and 16 nickles
718899
The facts in this riddle are clear: There is an initial $30 charge. It should have been $25, so $5 must be returned and accounted for. $3 is given to the 3 friends, $2 is kept by the bellhop - there you have the $5. The trick to this riddle is that the addition and subtraction are done at the wrong times to misdirect your thinking - and quite successfully for most. Each of the 3 friends did indeed pay $9, not $10, and as far as the friends are concerned, they paid $27 for the night. But we know that the clerk will tell us that they were charged only $25 and when you add the $3 returned with the $2 kept by the bellhop, you come up with $30.
438930
he wished for more wishes. each time he wished for another wish
719127
Well you got a quarter and a nickel.  Because one of the coins is not a nickel, it is a quarter.  So the other one is a nickel.  Hehehe.... Good one.
1100579
thirty two cents before taxes.
789401
Let's see.\n\nTwo dimes and one nickel\nOne dime and three nickels\nFive nickels.\n\nYou can have five pennies in place of one nickel in any of the above sitiuations.\n\nSo you could have:\n\nTwo dimes and five pennies\nOne dime and two nickels and five pennies\nFour nickels and five pennies.\n\nBut once again, you can have five pennies in place of one nickel in any of the above sitiuations. (Now, D = dime, N = nickel, P = penny)\n\n1D, 1N, 10 P\n3N, 10P\n\nOne more time\n\n1D, 15P\n2N, 15P\n\nAnd again:\n\n1N, 20P\n\nOne last time\n\n25P\n\nI count 12 ways.
644334
there is no missing dollar\n\nthe three paid $30, and the clerk gave the bell hop $5 to give back, meaning they paid 25 for the room.  he gave each man $1, and kept 2 for himself.\n\n25 for room\n+3 returned\n+2 stolen\n=30\n\nOR\n\nthey each paid nine for the room, and got a dollar back from the bellhop\n\n9 x 3= 27 paid for the room\n3 x 1= 3 refunded\n27+3= 30
708058
6 pennies.\n3 dimes.\n8 nickles.\n\nLearn how to do your own homework :-P
669176
p=pennies, n=nickels, d=dimes\n3p= 3,  2p+1n=7,  2p+1d=12\n\n3n=15,  2n+1p=11,  2n+1d=20\n\n3d=30,  2d+1p=21,  2d+1n=25\n\n1p+1n+1d=16\nSorry, I could only come up with 10.  :)
12248
He bought 1 bull for $10, 9 cows for $45, and 90 calves for $45.\n\n1 + 9 + 90 = 100 animals\n$10 + $45 + $45 = $100.
197666
A penny is a thought asked for. Two pennies is one thought too many.