wat r da different kinds of a quadrilateral?
830003
i don;t know all of them, but here are a few:\n-rectangle\n-square\n-rhombus\n-parallelogram\n-kite\n-trapezoid\n-and closed abject with four sides!\n-cyclic quaDrilateral     \n-cyclic-inscriptable \n\ncheck out the site dr. math for more info on quadrilaterals!
773761
I believe the answer is biconvex and elliptical.
302415
Sphere\nCylinder\nCone\nWedge
639731
a rhombus is a polygon with 4 equal sides, so YES, a rhombus can be a square
99265
I asked that same question to my teacher last time. She told me that I have to Seperated the shape into different common shapes. (for example like lets say I wanted to seperate a "square" into some common shapes I could turn it into two seperate triangles or four different triangles. Well Just try to use the formulas you know for the areas of the different disected figures you get.
948147
pentagon, doesn't matter the length of each side\n5-sided is pentagon
967111
Square and regular hexagon together \n\nEach decagon is surrounded on each alternate side by a square and a hexagon\n\nAlternately instead of the regular hexagon you could put 6 equilateral triangles tesselated into a regular hexagon or a combination of hexagons and equilateral triangles.
397113
sphere, elliptic, plane, euclidean, pseudosphere, hyperbolic
689719
The mode of presentation of data in the question is not sufficient to draw a single quadrilateral, there are two such quadrilaterals and hence two different answers.\n\nFIRST ANSWER: \nEqual sides i.e. sides of length 5*sqrt(2) are adjacent.\nLet the quadrilateral be ABCD. Then AB = BC = 5*sqrt(2), CD = 6, <DAB and <ABC are right angles. Drop a perpendicular to side AD from C intersecting AD at P.\n\nTotal area = area of rectangle ABCP + area of triangle CPD\n= [5*sqrt(2) x 5*sqrt(2)] + [0.5*{5*sqrt(2)-6}*5*sqrt(2)]\n= 50 + 3.7868 sq units\n= 53.7868 sq units\n\nSECOND ANSWER: \nEqual sides i.e. sides of length 5*sqrt(2) are opposite to each other.\nLet the quadrilateral be ABCD. Then AB = CD = 5*sqrt(2), BC = 6, <BCD and <ABC are right angles. \nClearly, quadrilateral ABCD is a rectangle. \nSo area = product of lengths of adjacent sides = AB x BC = 5*sqrt(2) x 6\n= 42.4264 sq units
774873
False for all quadrilaterals.\nBut all squares and isosceles trapezoids can be inscribed in a circle.
322061
Square- four equal, parallel sides, all right angles\nRectangle-four parallel sides, not necessarily all equal, with four right angles\nTrapezoid- one pair of parallel sides\nRhombus- all sides parallel, but not at right angles
219885
triangle- 3side\nquadrilateral- 4side\npentagon- 5side\nhexagon- 6side\nheptagon- 7side\noctagon- 8side\nnonagon- 9side\ndecagon- 10side\ndodecagon- 12side\nicosagon- 20side
507349
In geometry, a rectangle is defined as a quadrilateral polygon in which all four angles are right angles.\n\nFrom this definition, it follows that a rectangle has two pairs of opposite sides of equal length; that is, a rectangle is a parallelogram. A square is a special kind of rectangle where all four sides have equal length; that is, a square is both a rectangle and a rhombus. A rectangle that is not a square is colloquially known as an oblong.\n\nOf the two opposite pairs of sides in a rectangle, the length of the longer side is called the length of the rectangle, and the length of the shorter side is called the width. The area of a rectangle is the product of its length and its width; in symbols, A = lw. For example, the area of a rectangle with a length of 5 and a width of 4 would be 20, because 5 × 4 = 20. See the picture above right.
198751
http://www.ilovemaths.com/3conics.htm\n\nhttp://www.math2.org/math/algebra/conics.htm\n\nhttp://www.krellinst.org/UCES/archive/resources/conics/\n\nhttp://jwilson.coe.uga.edu/emt669/Student.Folders/Jones.June/conics/conics.html\n\nand listen to class.
1096150
To determine if it is a parallelogram:\nIf a quadrilateral has one pair of opposite sides which are parallel and equal in length, then the figure is a parallelogram.\n\nTo determine if it is a rectangle:\nIf a parallelogram has two pairs of opposite sides which are parallel and equal in length, then the figure is a rectangle.\n\nGraph the points and determine the distance between the points, or, in your case, two points have an X of 0 and two have X of 3\n\nBetween the (0, 2) and (0, 6), there is a distance of 4\nBetween the (3, -2) and (3,2) there is a distance of 4\n\nBetween the (0,6) and (3, 2) there is a distance of 3 horizontally.\nBetween the (0,2) and (3, -2) there is a distance of 3 horizontally.\n\nYour figure has two pairs of opposite sides that are equal in length and parallel.  You have a rectangle.
249214
An equilateral parallelogram:  Rhombus\nAn equilateral and equiangular parallelogram:  Square
809433
1.rectangle\n\n2.trapezoid