Factor these equations. If they're prime say prime.?
827502
1.6a^2b^2(1+3ab)\n\n2.(y-4)(y-1)\n\n3.(2b-1)(b+7)\n\n4.3(x^2-9y^2)\n=3(x+3y)(x-3y)
352698
7 & 103\n\nYou can go here to find the prime factors for any number:\nhttp://www.acme.com/software/factor/
842037
We need to factor the equation down. This involves finding the roots of the equation. This will look like:\n\n(ax+b)(cx+d) = 12x^2-31x+20 = 0\n\nBecause the final term is positive and the middle term is negative, my first hunch is to have b = -4 and d = -5. By doing so, the equation looks like:\n\n(ax-4)(cx-5) = 12x^2-31x+20 = 0\n\nThe factors needed for 12x^2 could be 2 and 6 or 3 and 4. We should test each combination to see that they work out. The factoring ends up looking like this:\n\n(3x-4)(4x-5) = 0\n\nNow all that remains is to solve for x in each set of parentheses. If the first term is zero, then\n\n3x-4 = 0\nx = 4/3\n\nIf the second is zero, then\n\n4x-5 = 0\nx = 5/4\n\nThus, x = 5/4, 4/3
18182
2x^2 + 5x + 20x + 50\n2x^2 + 25x + 50
631080
You can noy factor it out... it makes it easier to figure out when you put it into lowest terms... so it would be \n\n   x^2+7x-25..... so you cant factor it.
565133
We start by factoring the polynomial.  A little trial and error (testing the factors of 2, which is the constant term) reveals that 2 is a root.  So, we know that (x-2) is a factor.\n\nDividing the polynomial by (x-2) using synthetic division, we find the other factor is 6x^2+x-1.  This can be factored as (3x-1) (2x+1).\n\nSo, the equation, in factored form, is\n(x-2)(3x-1)(2x+1)=0\n\nSo, the roots are x=2, x=1/3, and x=-1/2.
607601
I think you set the equation to zero then you have to factor it.  Go to the link below if you wanna know how to do it. OR look your your math book.
752879
ok re arranged the second question so that the 6 is factored out so its x= such and such then sub the x equals such and such into the first equation and solve then do the same thing to Y in the second equation
777394
factor out 4b\n\n4b(b-2)= 0\n\nb = 2, 0\n\ngoodluck ^_^
865396
Prime factorization is basically simplifying a number into its prime factors.  A numerical example would help.\n\nHere's how you would simplify 100 into a prime factorization:\n\n100 = \n4*25 (these aren't prime numbers yet, thus factor again)\n2*2*5*5\n\nSince 2 and 5 are prime numbers, this is the prime factorization.  \n\n----------\n\nHope this helps
899336
84, without even needing to check. That is 2*2*3*7, which gives 3 prime factors. You can't get 4, since 2*3*5*7 is too big.
652953
I got:\n1. 6x^2 - 36x +48\n2. 6x + 22
959197
I have factored it please refer to.\n\nFrom this solution can be found
1053403
Write it as:\n2x^2-4x+3x-6\n=2x[x-2]+3[x-2]\n=[2x+3][x-2]\nSimple middle-term factorisation!!!
1156185
You know the first term is x^2 so you can write:\n(x     )(x     )\nYou know that the second term is -4x:\nIf factors are of the form (x+A)(x+B) then  Ax+Bx = -4x\nYou also know that the last term is -5, so A*B=-5\n\nJust find the values of A and B that satisfy these equations:\nAx+Bx = -4x\nA*B = -5\n\nA = -5 and B = 1\n\nNOW that we have the factors\n(x-5)(x+1)=0\nTo get 0 either section of the left hand side can be 0, so solve both cases:\nCASE 1:\nx-5 =0\nx = 5\nCASE 2:\nx+1=0\nx=-1\n\nANSWER x=5 or x=-1
807869
the prime factorization can be figured out by repeatedly dividing the number by a prime number.\n for example 12\n 12 divided by 2 = 6,   6 divided by 2= 3,  3 divided by 3= 1\n the answer is 1.\ni hope this was helpful.
962713
624/2 = 312\n312/2 = 156\n156/2 = 78\n78/2 = 39\n39/3 = 13\nThe prime factors are 2, 3 and 13\nThe prime factorization is 2^4 * 3 * 13