If isobars are closer together, the steeper the pressure gradient that exists?
826600
Yes that's correct.  There is a big pressure change are you move form location to location across the isobars.
264933
try substracting atmospherical pressure, and then you have the in-gage pressure.
162429
As pressure increases, volume decreases.
888873
For most fluids, you would expect to see a negative gradient if you would plot the friction factor vs. 64 / Re ...top number is relative based on units or something.\n\nAre you sure you're plotting it correctly?  The friction factor should be decreasing as the velocity of the fluid in the pipe is increased.\n\nI'm rusty w/ my chen material so this is all I have for answer; for now.
786817
Anywhere there is a difference in pressure. Examples:\nLow pressure in a vaccum cleaner, higher pressure outside pushes the air into the cleaner. Different pressure in a house compared to outside, when you open a window the higher pressure flows to the lower pressure. Remember that it is always a push and never a suck. Science never sucks!
739951
Atmospheric bressure, the shorter the distance between the isobars indicates that a storm is brewing
423881
true - high sustained pressure and a signifigant distance to any pressure disturbance or variation
234246
I´m only gonna attemp thisbecause it´s kind of late and there´s a chance you´ll have to wait untill tomorow (and I guess you´re cramming). So if you don´t get anyother answers, pick and don´t let it go to waste)\n \nImagine you have a scalar function over R3, that is f(x,y,z). Pressure is a scalar - it is given by a number so there is no direction involved like with force.\n \nA pressure field can be defined as P = f(x,y,z) where the point (x,y,z) defines a point in space.\n \nA gradient, is a vector in space, that is, for a given point, e.g. (10, 20, 15), a gradient is a vector that could be (1, 5, -20). The thing is that the gradient points in the direction that you would have to follow if you were at (10, 20, 15) that would lead you to the maximum increase in the field (in this case, in presure). It also indicates the intensity of the increase (kind of like a derivative).\n \nAn example in the body can be given by the presure in the femur when you stand (on one leg). (These examples are acctually hard to give, because bio-mechanics is very complex; there is hidro-dinamics, flector moments etc. and few cases of hidro-statics or simple compression.) At the top end of it, it receives all the weigh of the body minus the weight of the leg. The pressure is that weight divided by the area of cross section at that point (extreme over simplification here). As you go down towards the middle of the femur, two things happen:\n1) the weight above the cross section increases;\n2) most important, the cross section reduces.\n \nSo we know that as you go down the pressure (force / area) increases. So the gradient along this part of the femur would be a vector pointing down.\n\nHope this was clear (and correct) enough.
404840
Bubble side goes down, smooth side up.
605725
If you think of pressure as being the weight of a column of air at sea level, lets just call that 760 for example, then the column would be shorter and not as heavy if you were on the top of a mountain and therefore would have a lower pressure, say 500 and out in space it would be almost 0.  In the reverse if the column were going below sea level, it would be even heavier and therefore the pressure would be greater than 760. The deeper you go the heavier or greater would be the pressure.
45731
when there is a low pressure system that brings all the air towards it
984213
http://en.wikipedia.org/wiki/Pressure_gradient_force\nhttp://en.wikipedia.org/wiki/Temperature_gradient\nHope this helps, good luck!
1147399
A long skinny cylinder is the preferred shape for high pressures.  But if you have a cylinder and a sphere with the same diameter and wall thickness, the sphere will have a slightly smaller hoop stress because theoretically there is no "hoop" in a sphere since the diameter is never a constant over any width of cross section.
569120
Isobars link locations with constant pressure, isotherms do the same for temperature
383444
No.  There's nowhere near enough pressure.  You need to go down about 50 meters before the bends can hit you upon surfacing.  Depending on your physicall fitness, you may even be able to go deeper.
497010
DUE TO SURFACE TENSION POSITIVE ANGLE OF CONTACT AND INTERNAL PRESSURE.
885093
If the inside is pressurized, the shape has to symmetrical in such a way, that will make the internal pressure distribute itself more or less equally. Else the can may burst where the pressure is more.\nAlso the shape has to have a logical design.\nFor the sake of argument, let us consider others shapes.\n\nSpherical:: well that's not possible. Not very easy to hold !!\nBut yeah, from the physics point of view, its the ideal.\n\nCube and Cuboid :: The corners present can cause unequal pressure distribution, also the strain present may give rise to corrosion.\n\nElliptical:: no comments !!