word problems..math? algebra 2? help please!?
829190
4.5Km. The equation is simple assuming X Km first leg. we have 12-X as the second  leg. So time taken in each leg X/9 and (X-12)/10 resp. The sum of which is the total time of 1.25 Hrs. So\n(x/9)+((12-X)/10)=1.25. Solve the simpe linear equation to get X=4.5Km
1181037
You will find the worksheets at the website of http://www.algebra.com. This website is a free site. You can also pose Maths. questions there and will get answers at the cost of $0 (zero dollar).\n\nI am a free tutor there and you may see my lessons and solutions to problems at\nhttp://www.algebra.com/tutors/aboutme.mpl?userid=psbhowmick\n\nYou will find the worksheets at\nhttp://www.edhelper.com/algebra.htm
950092
Do a Yahoo search.  Enter "Homework help, math."  There are bunches of web sites.  Good luck.
795656
The first thing you should remember is the phrase PEMDAS.  This is shorthand for parenthesis, exponents, multiplication/division, and addition/subtraction.  This is the order of operations in math.  You should solve all equations in this order.  So for the first one, you should first distribute (multiply) -7 with (3-3x).  After that combine like terms, i got 25x -30; you can also factor that to be 5(5x-6).  The same steps apply for the rest of the problems.  I hope it helps.
855129
Word problems like this can be hard.  Everybody has problems with them sometimes.\n\nIt does help to draw it out.  So you draw a little rectangle like this:\n ______________\n|                            |\n|                            |\n|______________|\n\n2 of the sides are 120 m and the other 2 are 150 m.  So you take 2 times each of these numbers and add them together:\n2(120) + 2(150)\n\nThat's your perimeter, in meters.  Now if your poles are 2 m apart, you don't need one for every meter you get in your answer, you only need 1 every 2 meters.  So you divide your answer by 2, and that gets your number of poles you need to put around the field.
727324
I wish you the best of luck, I know how hard algebra is. Here are a couple of websites that will hopefully help:\n\nhttp://www.algebrahelp.com/\nhttp://www.math.com/homeworkhelp/Algebra.html\nhttp://www.purplemath.com/\nhttp://www.helpalgebra.com/\nhttp://www.algebra.com/\nhttp://www.mathleague.com/help/algebra/algebra.htm\nhttp://www.freemathhelp.com/algebra-help.html\nhttp://www.gomath.com/algebra.html\nhttp://archives.math.utk.edu/topics/algebra.html
1127430
try this one http://www.algebrahelp.com/
873410
1.  (x + 9)(x - 9)\n2.  (t + 2)(t - 2)\n3.  (b + 12)(b - 12)
189233
The problem with this type of algebra problem is that it's hard to know the syntax (grammar) of the problem if it's just written out in words. For example, is it 2x - 9, all over x, or is x the denominator only for 9? It's confusing!So in the future, to make it clear, use brackets like this:\n\n****IF I am reading your problem CORRECTLY****, I would write it as:\n(((2x-(9/x))^2)-4) - (((x-(7/x))^2)-4) = ?\n\nBut put aside the whole brackets thing for a minute. \n\nNow, normally, it helps to break down the math probelem into parts, but it looks like you're learning to do exponents. If this is the case, you must have learned that exponents allow you to work certain problems quicker without having to break down the problem into small parts and solving them seperately. To remember what those exponent rules are, try both the links at the bottom of this post. You'll use exponent rules all through your life, so know them!
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
893957
well darling ;\nimagine this like that\n\ny^2 + ( a+b)y + ab \nyou need to find " a+b " & " ab" \nin our function \na+b = 16 & ab = 64 \n( y + a)( y + b) \n( y + 8 ) ( y + 8)\n{ ' 8 + 8 = 16 '   &  ' 8 * 8 = 64 ' }\nso\n( y + 8)^2\n\nGood Luck sweetheart.
898860
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
298555
If it's math you can get some pretty good help at math.com. going to google for extra practice in pretty much anything. edhelper has worksheets you can print.
1089643
http://www.algebra.com
706993
Try reviewing your class notes and looking through your text book. Im sure that the answer you need is there. It might take a bit of thought to figure out how to do these problems! Take the time to figure it out, it will be worth it in the long run!
509467
1: x<12\n2: x>257\n3: x>42\n4: x>84\n5: x>25\n6: x>179\n7: x<8\n8: x>577\n9: x<113
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}