Find the quotient and remainder using synthetic division?
823706
2x^2 + 13x + 39 remainder 122\n\ndoes no one know what synthetic division is?  i suppose i only learned it last year...
842257
divide through\n\ny = [x^(3/2)]/3 - 2x^(1/2) -x^(-1/2)\n\nthen take the derivative\n\ndy/dx = [x^(1/2)]/2 - x^(-1/2) + [x^(-3/2)]/2\n\nthen put x^(3/2) in the denominator\n\ndy/dx = [1/x^(3/2)]*{ [x^2]/2 - x + 1/2 }\n\nwe take out the one half to find\n\ndy/dx = [1/2x^(3/2)] * [ x^2 - 2x + 1 ]\n\nwhich is the same as writing \n\ndy/dx = [1/2x^(3/2)] * (x - 1)^2\n\nor a = -1 and b = 2
907682
Divisor: 24\nDividend: 86\n86/ 24 = 3 remainder 14\n\nIn order to get the greatest quotient, your dividend must be as big as possible and divisor as small as possible so that you can get greatest possible quotient. Eg. compare 8/1 and 8/2. \n\n8/1 = 8\n8/2= 4 \nfrom this you can see that if your divisor increase in value, the quotient will decrease in value. \n\nE.g. 10/2, 12/2\n10/2= 5\n12/2= 6\nfrom this you can see that if your dividend increase in value, your quotient will also increase in value. \n\ntherefore, if you want to get greatest possible answer:\n- greatest possble dividend/ smallest possible divisor\n\nsmallest possible answer:\n- smallest possible dividend/ greatest possible divisor.
555590
Just multiply:\n(X/3)(3/4 x) -(x/3)(3/5) + (3/4)(3/4x) - (3/4)(3/5)\n\nand simplify from there
602043
I haven't done partial fractions in a while, so you might want to check this: \n1/(x+3) - 2/(x+3)^2 + 5/(x-7)
671751
DIvide both the numerator and denominator by -5*x*y^3 to get:\n\n3*x^2/4*y
113980
Use a calculator - numerator divided by denominator will give you the answer.
559152
are u sure its not supposed to be the other way around. Cuz that would make a little more sense.\n\nBut if not, then it would probably be:\n1 + ((4s squared - 11) / (s to the 4 - 3s squared -11))\n1 the quotient. the rest the remainder.
129645
You need to divide the numerator by the denominator.  The remainder is written as a fraction, with whatever you had left over as the numerator, and the number you are dividing by as the denominator.  For example, if you have 11/5, 5 will divide into 11 two times, leaving 1 left over, so the answer is\n\n11/5 = 2 1/5\n\nNote that if you had 10/5, the answer would have been just 2, i.e. a whole number.
920579
use synthetic  divsion method \ni think this link would help\nhttp://www.purplemath.com/modules/synthdiv.htm
762985
(b-4)/(b-4)(b+4) simplifies to 1/(b+4)\nrestrict denominator...bcannot equal 4 or -4
452826
If you set this up as a long division problem with x+1 on the outside and x^3 + 3x^2 - 2x + 7 inside and solve it like a long division problem, you will have x^2 + 2x - 4 on the top and a remainder of 11.  The remainder part is the leftover after the long division - no need to put it over x+1 (when you have 14 divided by 5, you have 2 remainder 4, not 2 remainder 4/5).
235381
in dividing fractions, you just multiply them by its reciprocal.\n\nso \n\n[(x+5) / (16x)]  * [ (4x ^2) / [(3x -2)] \n\nperform the operations: \n\n[ (x+5) / 4 ] * [ x / (3x-2) ]\n\nthe answer is:\n\n[x(x+5)] / [ 4(3x-2) ]
945604
1.adding-2f-7\n-6f-2f+7-7<2f-2f-9-7\n-8f<-16\ndividing by -8\nx>2\n\n2.5/8g-4>2/3g+6\nadding 4\n5/8g>2/3g+10\nmultiplying by 24\n15g>16g+240\nadding -16g\n-g>240\ndividing by -1\ng<-240\n\n3.sum incomplete\n\n4.-2 1/9d+3/5<-3 2/9d-4 2/5\n-19/9d+3/5<-29/9d-22/5\nmultiplying by45\n-95d+27<-145d-198\nadding 145d\n50d+27<-198\nadding -27\n50d<-225\ndividng by 50\nd<-5 1/2
161655
Divide the decimal number by 16.   Treat the division as an integer division.   \nWrite down the remainder (in hexadecimal). \nDivide the result again by 16.  Treat the division as an integer division.   \nRepeat step 2 and 3 until result is 0. \nThe hex value is the digit sequence of the remainders from the last to first. \ncheck here: http://www.permadi.com/tutorial/numDecToHex/
537832
(x/x-2)-(x+1/x)=8/(x^2-2x)\n[x(x)-(x-2)(x+1)]/[x(x-2)]=8/[x(x-2)]\nx^2-(x^2-2x+x-2)=8\nx^2-x^2+x+2=8\nx=8-2=6
866735
I believe you use the remainder theorem for this, which states that the remainder when a polynomial f(x) is divided by (x-k) is\nf(k)\n\nThus the remainder would be f(-1) = 11