We know that exampl:3^2+4^2=5^2,3^3+4^3+5^3=6^3, For which integer k X1^5+X2^5+...+Xk^5=Y^5 has integer answes
816912
I think you need to make your question a bit more clear, but...\n\n1^5 + 2^5 + ... k^5 = (Y/X)^5
757614
4 (x^2 + 3X -4)\n4(x+4)(X-1)
1185809
1) 5^(4+11) = 5^15\n2)6^(6*3) = 6^18
133233
(1+1+1)! = 6 3 factorial is 6\n2+2+2 = 6\n3*3-3 = 6\nsquare root(4) + square root(4) + square root (4) = 6\n5 + 5/5 = 6\n6+6-6 = 6\n7 - 7/7 = 6\ncube root(8) + cube root(8) + cube root (8) = 6\n9+9 / square root(9) = 6
600301
x^3+x^2+2 = x^5+2\n\n(x^2+2)^2 = x^4+4\n\n(x^3+x^2+2)/[(x^2+2)^2] = (x^5+2)/(x^4+4) = (x+2)/4 = (x+1)/2
67692
(4X^3 +12X^2) + (12X +36)= 4X^2(X+3) + 12(X+3)\nX+3 is common.. hence we could write...\nas (X+3)(4X^2 + 12)= 4(x^2+3)(x+3)
1024215
1^3 + 6^3 +8^3 = 9^3\n\n3^3+10^3+18^3 = 19^3\n4^3+17^3+22^3 = 25^3\nthere's a lot!!!
934909
4/x + 5/y^2 =12\n(4y^2 + 5x)/(xy^2) = 12\n4y^2 + 5x = 12xy^2  (1)\n\n3/x + 7/y^2 =22\n(3y^2 + 7x)/(xy^2) = 22\n3y^2 + 7x = 22xy^2 (2)\n\n3 * (1)\n12y^2 + 15x = 36xy^2  (3)\n\n4 * (2)\n12y^2 + 28x = 88xy^2 (4)\n\n(4) - (3)\n13x = 52xy^2\nx = 4y^2\n1/4 = y^2\n(+-)1/2 = y\n\n4/x + 5/y^2 =12\n4/x + 5/(1/4) =12\n4/x + 20 = 12\n4/x = -8\n4/-8 = x\nx = -1/2\n\n\nx = -1/2, y = (+-)1/2
359082
there are 3, (since 5/3 *3 = 5)
389436
5x4+4+4+5+4/2\n=20+4+4+5+2\n=35
653967
a)  1/3^-3 = 3^3  = 27\n\nb)  3/5^-1 = 3*5 = 15\n\nc)  4a^-2b^-3 = 4/(a^2*b^3)\n\nd)  x^-2y^-3/z^-1 = z/(x^2*y^3)\n\ne)  x^6/x^2 = x^3  (I think this is what you wanted to ask, you left out the carets)\n\nf)  x^4y^2z/x^2y^4z^2 = x^2/(y^2*z)
219026
x^3+4x+1\n\n(3x^4+2x^3+12x^2+11x+2)=\n=(3x+2)*(x^3+4x+1)
565940
Let the numbers be x and y where y is the larger number.\nx:y = 3:5 => 5x=3y => x=(3/5)y --(1)\ny = 36+((1/2)(y-x)) --(2)\n\nSubstitute (1) into (2),\ny = 36+((1/2)(y-(3/5)y))\ny = 36+((1/2)(2/5)y)\ny = 36+(1/5)y\ny-(1/5)y = 36\n(4/5)y = 36\ny = 36/(4/5)\ny = 36*(5/4)\ny = 45\n\nSo x=(3/5)(45)=27\n\nCheck:\n- 27:45 = 3:5 okay\n- 36+((1/2)(45-27)) = 45 okay
853859
g(x) = x^5+5x^4+10x^3+10x^2+5x+1 = (x+1)^5\n`
746280
c^2 = 3^2 + 4^2\nc^2 = 9 + 16 = 25\nc = square root (25) = 5
798535
x^3 - x^2 + 5x + 5\n\n(x^3 - x^2) + (5x - 5)\n\nx^2(x - 1) + 5(x - 1)\n\nsince both x^2 and 5 have the same factor, you can factor it to\n\n(x^2 + 5)(x - 1)\n\nif you want, you can either leave it that way, or\n\n(x + sqrt(5i))(x - sqrt(5i))(x - 1)\n\nwhat you can probably just leave it as (x^2 + 5)(x - 1)\n\nyou can also try www.quickmath.com, click Factor under Algebra, then type in x^3 - x^2 + 5x - 5, then click enter. \n\nAnymore Questions Ask ME
36762
Factor by grouping:\nx^2 (3x - 5) - 3 (3x - 5)\nAnswer: (3x - 5)(x^2 - 3)