Ohmmeter Setting Question?
829816
the horseshoe is the greek letter omega and it is the unit for resistance.  \n200 = 200 ohms\n2000= 2000 ohms\n2000k = 2000000 ohms\nthe k means to take the number an multiply by 1000\nif you see an M that means to take that number and multiply by 1 million.
953043
Hi. Sounds like you puffed the LED. Most need a resistor to limit current.
96754
Im not really clear what you mean by settings but the best physical part swap for acceleration in ring and pinion swap to lower the final drive ratio which means the engine revs faster hope i could help
129024
ohm, or om is correct. om is supposedly the sound vibration when the universe was created
372456
To measure ohms, DCV, ACV, Amps or what????
941451
Probably nothing as long as the voltage is correct. I wonder -- how do you know you have 50hz?
435282
The top right is treble pickup volume.\nThe bottom right is treble pickup tone.\nThe top left is rhythm pickup volume.\nThe bottom left is rhythm pickup tone.\n\nWhen using both pickups(switch set in the middle) all 4 knobs work that way you can mix and match the tone and volume so if you want the treble pickup to have more presence, put the volume higher than the rhythm pickup etc.\n\nHope this helped.
272621
v=voltage\no=ohm\nm=milliammeter\n\na tester which test those mentioned aboved. don't use it in measuring resistance(ohms) when the circuit is still connected to a source (voltage)
1001225
"gods_my_ruler" obviously has NO IDEA what he is talking about.\nOf course you can, easily split H2O into H2 and O2 gas through a process known as "electrolysis".  Actually, 12 volts is way over the minimum voltage required to electrolysize water.\nYou will also, of course, need to use some form of electrolyte (commonly, "salt", or Na/K Hydroxide are popular choices) in order to help the water conduct electricity since pure water does will not conduct at all.\n\nBut you question was about controlling the current flow.\nI assume you are having problems with the current getting too high and overloading your power supply?\nFor starters, I would downgrade your power source to something with a little less voltage if possible.\nYou can also use combinations of small (on the order or just a few ohms or less) resistors wired in series/parallel in order to give you just the right resistance you are looking for in order to decrease the current through the cell.\n\nWithout more specifics about the problem you are having, that is about all the advice I can give for now.\n\nRemember, it is not the voltage that controls the H2 production rate, it is the current.\nAccording to Ohm's Law,\nV = R*I\nso a higher voltage (with a given resistance) does mean a higher current, but the same goal could be achieved with a lower voltage and much lower resistance.\n\n\nEDIT:\nIn reply to "kurticus1024",\n\nUsing a reostat or variable resistor would work to dynamically control the resistance in the circuit, and thus the current through the cell, however, most reostat which I am aware of have a high minimum resistance (i.e.  even when turned all the way to the minimum setting, they are far from zero ohms) so by doing this, you will be DRAMATICALLY increasing the resistance through the cell and intern virctually cutting your cuttent to just a few miliamps.  A few miliamps is fine for many common electrical components whcih the reostat was designed for but if you intend on produce Hydrogen, you are going to have to wait a VERY long time to get any sizeable amount.
1130014
V=IR\n\nWire 1:\n50 = 2 * R1 => R1 is 25 ohms\nCurrent = 2 amps\npower = V*I = 2*50 = 100 watts\n\nWire 2: \n100= 2* R2 => R2 = 50 ohms\nCurrent=2amps\npower = V*I = 100*2 = 200 watts\n\nare you looking for ratios when you say "compare" ?\nif yes: ratio of resistances is  1:2\nratio of currents is 1:1\nand ratio of power is 1:2
810481
First make sure the capacitor is discharged.( Connect a large screwdriver across the terminals of the capacitor).\nUsing an analog ohmmeter set to the 100K or 1000K scale,connect its leads across the capacitor, the ohmmeter needle should make a fast movement upscale and, after a very short time, should start moving slowly downscale toward the "0" value.This shows a good capacitor.Hope this help.
230873
Volt = I * R \nmeasure V and I or use the resistance  setting on an ohm meter. Use a fine mechanical pencil refill and subtract out the resistance on the meter leads. If more accuracy is needed there are milli ohms meters or make a resistor bridge.
774566
There are a couple of ways that I can think of right off hand.  They depend on what the surrounding circuitry is like.  \n \nRemember, a static discharge is a fairly high voltage arc.  So one possibility is to measure the resistance at the transistor and compare it to a known good board.  The low voltage used to measure the resistance shouldn't hurt anything, but like I pointed out, this depends on the circuitry.  One company I am familiar with used to do this to trouble shoot a circuit.  They had a whole list of resistance readings for various points in a circuit.  It was quite helpful.  \n  \nYou might also power the board and use a scope to measure wave forms.  Or even a DMM to measure voltages.  \n  \nAnother way is to use a curve tracer.  Again, depending on the circuitry.
399258
just put a limiting resistor. 60mA and 12V. Limiting resistor =R=(V-Vled)/I. assuming the extreme, 0V for Vled. R=12/6e-2=200ohm. that way the current will never exceed 60mA.
246763
difference? Resistance IS Ohms's law, thus the units for resistance are Ohms, from the guy's name.\n\nAnd Ohm's law is:\n\n     V = I R \nwhere V is voltage; I is current; R is resistance.\nor\n     E = (sigma) * J\nwhere E is electric field intensity; sigma is conductivity; and J is current density\n\nBoth are considered Ohm's Law, with the second equation considered as being more complete.
971626
Your question isn't clear.\n\nI suspect that what you mean is "how low can I go before I can't do what I want to with the motor".\n\nDepending on the inverter manufacturer, a typical limit is around 7 hertz. This is because reducing the frequency much lower will cause feedback issues and overheating (due to harmonics) in the drive. Also possible is the cycling frequency of the thyristors.\n\nMost applications will prefer low-end frequencies in excess of 12 hertz - to avoid possible tuning/torsional amplification with the structure to which the motor is mounted. No sense trying to run right on a structural resonance point!\n\nPracitacally speaking, there's also an upper limit on frequency as well, usually imposed by the motor design. Often, this is approximately at 2.2 times line frequency (133 hertz for 60 hertz systems, 110 hertz for 50 hertz systems).
81594
Use ohm's law (I=E/R); 2 AAs are 2.4 to ~3 volts depending on battery type, so 0.4 to 0.5 A.\nHOWEVER, if you measured the bulb's resistance cold, it will be higher when hot, so it will draw less current.