Waht are the possible genotypes of the parents of a child who has wavy hair (Hh)?
815304
Possible:\n\nHH x Hh\nHh x Hh\nHH x hh\n\nNot Possible:\n\nhh x hh\nHH x HH
259417
Yes it is. You'd be surprised at the recessive genes  a lot of black  folks have, so they may just look like the average person of African decent but they may have a lot of other genes from other groups dormant in their genetic code. So it is entirely possible that the child could have straight hair.
903731
How, why, how long, any other abnormalities, any other family members abnormal, what age....???\n\nNo one can possibly comment or reasonably respond to your question when you give no information.  \n\nYou need to spend another 5 points and really give people something to go on if you expect a helpful answer.
325168
I don't, but fyi Down's Syndrome is caused by trans-located chromosomes, a.k.a. non-disjunction.  It's likely there are some parents on Y!A with one.
1112767
If I'm reading you right . . . no, it's not genetic, but it CAN  be hereditary.  People can't teach their kids what they themselves don't know.  So it is a cycle.
61473
Well, being that blonde and red are submissive genes..one could say that in time, they will die out, or at least become rare, because even Asian people have a few blue/grey eyed children. \n Say B= brown (or black whatever).. and r=red. If a brown headed man(Br) has four children with a red headed woman(rr)..the odds or this:\nDad B  r\nMom r  r\n Meaning there is at least a 1 in four chance that the child will have red hair. As long as the submissive gene is there, the hair/eye color will be there. Even if both parents have Brown or Black hair. If both have the submissive gene for Red/ blonde. they have a 1 in 4 chance of having that color show in their children
775856
A)\n\nAs far as pod size, at least one parent must be homozygous for H, since all the offspring have one pod.  The other parent coudl have any genotype for that gene\n\nThe leaf shape is showing the 3:1 ratio characteristic of a dihybrind cross.  So both parents must be het at the leaf locus.\n\nB) is similar, since all the offspring have 3 pods, the parents must be homozygous for that recessive allele.  The other parent coudl have any genotype for that gene.\n\nThe 3:1 ratio of leaf shape shows that the parents must again both be het for the leaf shape locus.\n\nC)  If all the offspring show the dominant pheontype, one parent must be homozygous for the pod number, and one must be homozygous for the leaf shape.  Either the same parent is homozygous for both, or each is homozygous for one trait.  Again, if one parent is homozygous for a gene, the other parent coudl have any genotype at that locus.\n\nD)  The ratio of one-pod/3-pod is again, 3:1, so both parents must be het for that gene.  Since half the offspring have the dominant leaf shape, and half have the recessive leaf shape, that means that one parent must be homozygous for the recessive allel, and the other must be het.\n\ne) The ratio of one-pod/3-pod is closest to 3:1, so both parents must be het for that gene.  again, the ration is leaf shapes is closest to 1:1, so one parent must be homozygous recessive, the other het.\n\nBut the ratios aren't quite right, there's something non-Mendelian affecting the offspring here.
796672
OK, draw yourself up a nice big checkerboard with 16 squares! Down the left hand side, write beside each square the 4 possible gametes produced by 1 parent - for parents with the genotypes you have given above, the gametes produced are: AB, Ab, aB, ab - this is because each egg or sperm produced will have only half the number of genes of the parent (so ONE copy instead of 2) so that when the egg and sperm meet, they will have 2 copies of each and not more!!! So the gametes will have ONE copy of the 'A' gene (which may be either the dominant 'A' allele or recessive 'a' allele - half the gametes will get one type of allele and half the other) and the same goes for the 'B' gene, to produce the possible gamete types above. Then, along the top of your little checkerboard diagram, write above each of the 4 squares the 4 possible gamete types for the SECOND parent - which in your case, are the same as the first!\n\nNow - you want to fuse your eggs and sperm to produce offspring! Do this by combining the gamete genotype of 1 parent with that of the other in the box where they meet up - eg if your very top left-hand square has the genotype 'AB' above it, and 'AB' to the left of it, then the genotype of the offspring produced will be AABB - homozygous for both! And the square 2 down from the top, in most left column, might be combining the gametes 'Ab' with AB - producing offspring AABb, which is homozygous for gene 'A' but not for gene 'B'.... and so on and so forth for the rest of the squares!\nI WOULD RECOMMEND DRAWING UP THIS SQUARE TO SHOW YOUR WORKING - YOUR TEACHER WILL BE WANTING TO SEE THAT!\ndouble homozygotes are AABB, AAbb, aaBB, or aabb...
373156
according to genetics,if both parents are homozygous black(both of each parent's alleles or genotypes are the same),the odds are ALWAYS zero.eg:both parents' genotype is BB(B-black colour is the dominant while b-white colour is recessive)the children are ALL BB,so they are All black. \n\nif one parent is heterozygous(genotypes are different),same as above.eg:if the mother is BB & the father is Bb, 2 children are BB while the other 2 are Bb,which means All are black\n\n  if both parents are heterozygous the odds are i in every 4 children. eg:both parents are Bb, 1 child is BB-black , 2 children are Bb-black & 1 child is bb-white.\n\ni hope u have studied genetics in bio-if not,then ur lost!good luck!!!
777180
ive tried looking, they wont reveal any of that. I do believe it is hereditary though
388114
Perhaps you want a website that will take the pictures of both parents and somehow morph them?  The resulting photo will be more silly than a useful indication of what your offspring might look like.  Find a genetic planner and discuss the traits that you both possess, and you might figure out which traits are more likely to be dominant.  You can come up with educated guesses for hair and eye color, etc., but nothing more definitive than that.
393296
im 31 years old and have been wearing a hat every day (no kidding) since i was about 15 years old. no hair loss here. my father and grandfather have full heads of hair and i dont know if its hereditary. but ive still got lots of hair.
168370
I believe it is hereditary. But my sister and a good friend have successfully tried the following remedies.1)Ground contraceptive pills added to the shampoo. 2)Chopped onion added to the shampoo. 3)An infusion made with ash tree leaves.
962212
1. Pp (heterozygous)\n2. Both parents are heterozygous (Ff)\nSince both parents show intense freckles, it must be a dominant trait. In order to have non-freck. children, they both must be heterozygous. Ff x Ff ----> 3:1 ratio expected; frec. to non-freck.\n3a) All four blood groups are possible\n  b)25% possibility for each\n\nFor#3, do a Punnett square-   A i   x   B i
1033894
pedigree, crossface , masterlock , FU etc
508663
well it depends... it's a simple genetics case really... but it depends if your husband is Homozygous or Heterozygous dominant. If he is homozygous, this means he has two dominant alleles for brown hair... and your child will never have read hair, becuase his genes will be dominant over your red hair and recessive gene. However, if he is heterozygous with one dominant brown hair gene and the other a recessive gene, then there is a 50% chance of his recessive gene combining with your recessive gene. But it is only possibel to guess at what his genes are unless you go back to previous family generations, this is called genetic counselling, where people study your history to determine what genes you have.
125133
Genetic predisposition among other things.