Math Smarties....help me??
829325
Even if you didn't know how to do this algebraically, you could check each of the choices above and figure out the right answer. That's why multiple choice is a bad option for math questions. \n\nThat being said, here is how you would solve it.\n\nLet x be the height of the Washington Monument.  Since the Eiffel Tower is 497 feet taller, you can write the height as x + 497.\n\nNow, we are going to examine the case if each monument were 58 feet shorter.  With this scenario, we have\nHeight of Washington Monument  = x - 58\nHeight of Eiffel Tower = x + 497 – 58 = x + 439\n\nSince the new Eiffel Tower is twice the height of the new Washington Monument, you can write them as:\n2 * Washington = Eiffel\n2(x – 58) = x + 439\n\nNow, solve for x:\n2x – 116 = x + 439\nx = 555\n\nSo, we know that the height of the Washington Monument is 555 and that the height of the Eiffel Tower is 497 feet higher--or 1052.\n\nTest the answers.  \n1052 – 455 = 597 (satisfies the first condition)\n1052 – 58 = 994; 555 – 58 = 497\n497 * 2 = 994\n\nSo your heights are indeed 555 and 1052 (none of the above).
798960
1. Square everything in the first set of inequalities.\n\nIf 4 < sqrt(x) < 9, then 4^2 < [sqrt(x)]^2 < 9^2\n\nor, 16 < x < 81.\n\nAs a test, let's choose x = 64. I picked it because it has an easy square root.\n\nIf x = 64 (and note that 16 < 64 < 81), then sqrt(x) = 8, which is greater than 4 and less than 9.\n\n2. If the total cost of x apples is b cents, then the cost of 1 apple is b/x cents. x * b/x = b, which is indeed the cost of x apples according to the problem.\n\nIf 1 apple costs b/x cents, then y apples cost yb/x cents.\n\nAs a test, suppose that 5 apples cost 20 cents. (That is, x = 5, b = 20).  In this case, 1 apple costs 4 cents.\n\nHow much are 6 apples (Let's let y = 6). 6 apples would cost 24 cents.\n\nNow, what is yb/x?\n\n6*20/5 = 120/5 = 24.\n\nIn this case, it checks out. (It will for all cases, but one case doesn't actually prove that it works. It really only justifies it. But it is right :D)
859713
You should go to www.AAAMath.com  good luck
228388
Actually I had something to help you but x=0 which makes it pretty difficult.\n\nI guess you could try to talk about tomatoes or something.  Say Tom (X) has 1/2 the amount of tomatoes that Jill has, plus four.  Or in other words, if you take Jill's amount of tomatoes, multiply it by two, and take Tom's amount and multiply it by three, there total amount of tomatoes will equal 12.  How many tomatoes does Jill have?  How many does Tom have?
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
930340
PROBLEM 1:\n\nsqrt(x^3) = 8\n\nSquare both sides:\nx^3 = 64\n\nNow take the cuberoot of both sides:\nx = cuberoot(64)\n\nSolve:\nx = 4\n\nPROBLEM 2:\n\ncuberoot(x^2) =4 \n\nCube both sides:\nx^2 = 4^3\n\nSimplify:\nx^2 = 64\n\nTake the square root of both sides:\nx = ±8
37738
try sosmath.com  they helped me before. if they don't have the answer you are looking for they have a list of links to tons of other math sites.  \n\nand there probably is someone on your campus that can help as well.  One on one help is always best...\n\nGood luck!
1127430
try this one http://www.algebrahelp.com/
856067
1)1,8,27,64,125\n  x^3 = 1^3, 2^3, 3^3, 4^3, 5^3\n\n2)9, 13, 15, 19, 21, 25\n a(n)+ n-2 = {a(n-1) +a(n+1)}/2\n\n3)00001, 00011, 00101, 00111, 01001\n  1,3,5,7,9 in binary\n\n4)17,23,5,18,20,25,21,9,15,16\nok, your teacher is an ass for this one..  heres the breakdown\nq is the 17th letter, w is the 23 letter, e, r, t, y, u, i, o, p\nthe top row of a standard U.S. keyboard. i think i earned 10 points for that one alone\n\n\n5)\nFOUR\nF I V E\nN I N E\n\nR=0\nF=2\nI=3\nN=5\nE=6\nU=7\nV=8\nO=9\n\n2970 + 2386 = 5356\nDONE.  Hope this works for you
616179
here are the general steps you want to take when approaching these math problems\n\n1.) check for the greatest common factor\n2.) write out your parenthesis\n3.) since it's a squared problem, fill in the x's\n4.) write out your + & - signs\n5.) list the multiplication factors for the last term\n6.) plug in factors that will lead to the correct product\n\nwe'll start with #1 to get a better idea\n\n1.) -x^2+5x+24\n\n1. there is no greatest common factor\n2. write out your parenthesis\n\n(    )(    )\n3. fill in the x's\n\n( x   )(x   )\n\n4. fill in + or - signs\n\n-since we're dealing with -x^2 we know that one of the x's need to be + and the other one -\n\n(x   )(-x   )\n\n-since our last term is positive we know that either both the #'s are + or both of them are -\n\n(x-  )(-x-  )\n\nor\n\n(x+  )(-x+  )\n\n\n\n5.  list the multiplication factors for the last term\n\n24\n\n1*24=24\n2*12=24\n3*8=24\n4*6=24\n\n6. plug in factors that will lead to the correct product\n\n(x-8)(-x-3)=-x^2+5x+24\n\n**now, with a little more practice, you'll be able to figure these out faster...here are the answers to the rest of the problems\n\n2. (x-12)(x-12)\n3. (x-9)(x-12)\n4. 2(x^2-8x+16)=2(x-4)(x-4)\n5. 3(x^2-6x+72)=3(x-12)(x+6)
154380
I posted these sources earlier to someone else who was looking for math help.\n\nGood Luck!!
880255
I can just give you a link to help you solve it.\n\nhttp://www.ticalc.org/pub/83plus/basic/math/geometry/
737774
You figure the square root of each number separately...you've probably learned that in class alredy (how to do that)...then you take reach result, and multiply them together for your final answer.\n\nUse your textbook for reference...good luck!
233014
U R RIGHTT..HOW DID YA GET IT..PLZ CAN YA EXPLAIN..I'VE BEEN TRYING THIS PROBLEM FROM A LONGTIME.EVEN DE CALCULATOR SAYS ITZ "4"..I KNOW DE CALCULATORS WRONG TOO..PLZZ DO EXPLAIN IT TO ME ASAP
796176
If you go to Acessories on your desktop you should be able to find one there, however this link takes you to a calculator site which is very eay to use. \n\nhttp://www.math.com/students/calculators/source/basic.htm
91753
factorize\nx^2 + x = x(x+1)\n\nfactorize\nx^2 - 1 = .... (you should know)\n\n2 = 2 (!!!)\nTake the lcm of the three denominators (each different factor (=parenthesys) once and with the highest power)\n\nIt is 2x(x+1)(...)   (fill the dots)\n\n.....\n\nnow if you can't go on, you need to open your book again and study, or pay more attention at school at your math classes, and ask immediately for further explanation to your teacher when you feel you've not understood.\n\nGood work and good study
584912
http://www.algebrahelp.com/ I found this site very useful perhaps you should check it out http://www.algebrahelp.com/