Write the equation of the line passing through (-3,-5) and (3,0).?
816165
equation of the line is:\n(y-0)/(x-3) = (0 - (-5))/(3-(-3))\n \ny/(x-3) = 5/6\n\n6y = 5x - 15\n\n5x - 6y -15 = 0
265237
3s = -6\ndivide each side by 3\ns = -2
30454
say the line is y= ax + b\nsubstitute the (x,y)= (3,-11), (-1,9)\n\n-11= 3a+b......(1)\n9= -a+b.......(2)\nsubtract (2) from (1)\n\n-11-9= (3a+b)-(-a+b)\n-20= 4a\na=-5\nsubstitute this back into (2)\n9=5+b\nb=4\n\nie the original equation is y=-5x+4\n\nThe answer is D. but u left "x" out
77431
Any linear combination of x, y and a scalar when is put equal to 0 gives the equation of a line: that is "a term in x + a term in y + a number = 0" is a line.\n\nSo write a line whatsoever's equation:\n\nfor example (but you change it, please)\n\n4x -2y - 5 =0\n\nNow if you multiply all the terms for the same factor, you get an equivalent equation so you get a coincident (= the same) line:\nfor exemple, let's simply change all the signs:\n-4x +2y +5 =0 is always the same line\n\nAnd you can build infinite equations of the same line in this way\n\nP.S. = remember NEVER choose 0 as a multiplicator!
785524
y = 3x-5\n\nx^2 +(3x-5)^2 = 25\nx^2 + 9x^2 -30x + 25 = 25\n10x^2 -30x = 0\n10x(x-3) = 0\n\nso x = 0 or x = 3\n\nWhen x = 0 y = -5\n\nWhen x = 3  y = 4
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
945033
Derivative is y=cos x -5. Substituting in 0 gives you the slope -4. Now plug in the coordinates (0,3) to get the line, which is y=-4x+3
775693
y= -3x +5\n y= -4x -1  subtract\n0=x+6    subtract 6\nx=-6\nsubstitute\ny=-3(-6)+5\ny=18+5=23\nsolution is (-6,23)\n\ncheck \n23=-4(-6)-1\n23=24-1
394124
y=5\nx=-2/3\n\nSame method as the other one.
491966
Negative plus negative is ALWAYS negative.\n(-5) + (-3) = -8\n\nNegative minus negative may be negative, positive, or zero.\n(-5) - (-3) = (-5) + 3 = -2\n(-5) - (-5) = (-5) + 5 = 0\n(-5) - (-8) = (-5) + 8 = 3\n\nNegative plus positive works the same as negative minus negative. See the examples above.
330638
5/X+1<-2\n-1\n5/X<-3\n*X\n5<-3X\n/-3\n-5/3<X
54462
(3x+5)/wz \n(3*4+5)/(-1*5)\n(15+5) / (-1*5) \n20/-5 = -4
674651
put it in standard form :\n\ny < -1/2x + 3/2 \nand \ny > 2/3x + 2\n\nthen you know the first line passes thru the y axis at 3/2 and the second at 2\n\nthe slopes are -1/2 and 2/3 .... then shade below the line on the first one cuz y is less than .\n\nthen shade above the second line because y is greater than
1151668
The x-coordinate decreased by 4 - (-2) = 6 and the y-coordinate decreased by 2 - 0 = 2\n-3 - 6 = -9\n5 - 2 = 3\nAnswer: Q'(-9,3)
1149797
The first one is (-5, 3). I don't remember how to do the others.
232213
I'll do the fourth problem.\n\n-3x< -6  or x+5< -2\n\nfirst deal with one half- \n-3x< -6 (now divide by -3)\nx>2 (when you divide by a negative the sign is reversed)\n\nthen the second half- \nx+5<-2 (get x alone, so subtract five from each side)\nx< -7\n\nso you have:\n2 < x  or  x < -7\n\nto graph this there is a line with an arrow to the left of the first slash and another line to the right of the second slash\n\n<-----/-------0--/-->\n____-7______2
350403
Equation of a line:  y = mx + b\n\nm = 3 (slope)\ny = -4 (y-intercept)\n\ntherefore:  y = 3x - 4 \n\nCrosses x-axis at y = -4 (0,-4)\nCrosses y-axis at x = 4/3 (4/3,0)