Graph -2x=y +3 using the slope-intercept form What is that?
829794
The standard equation for slope-intercept form is y=mx+b. m is the slope and b is the y-coordinate of the vertical (y) intercept\n\n-2x=y+3       Original equation\n\ny=-2x-3        Rewritten in S-I form\n\nm= -2, b= -3\n\nThis means that the graph of the funtion is a line through the y-axis at the point (0, -3) with a slope of (-2)
927388
y=mx+b\n\njust rearrange it so you get b as your intercept..\n\nin this case y=-1/4x +3, so the slope is -1/4, and the intercept is 3
620528
There are two equations there, not one.\n\nFor the first equation, plug the numbers on your X-axis into "x", calculate "y", then draw the points on your graph.  I'll get you started:\n\nx=0, y = -3\nx=1, y = -1\nx=2, y = 1\netc.\n\nThe second equation simply means that x = 1.5 and y = 3.  This is just a single dot on a graph.
964525
Y = mx + b\nWhere  m is the slope of the line ond\nb is the y intercept
1086002
this is the slope intercept form equation\n\ny=mx + b\n\nwhere m is the slope and b is where the line crosses the y axis\n\nfor example\n\ny= 1/2x + 2
394184
well, you really should do your own homework, but the answer is D. substitute 3 and 7 into the equation for the easy answer.......7=2(3)+1......but to know that, the equation is  y = mx + b. m designates the slope of the line, and b the y-intercept, that is b is the second coordinate of the point where the line crosses the y-axis
1163751
If you are given the slope(m) and a point on the line(x1, y1) you can write the equation of the line.\n\nYou take the y-intercept equation\ny =m*x + b and substitute x1 and y1 for x and y and get\ny1 = m*x1 + b    \nnow solve for b\nb = (y1-m*x1)\nsubstite b = (y1-m*x1) into the y-intercept equation\ny =m*x +(y1-m*x1)\nsubtract y1 from both sides of the equation\ny -y1 = m*x -m*x1\nbecomes the point-slope formula\ny -y1 =m*(x-x1)
861275
x(y-1) = 2y + 3\n\nxy - x = 2y + 3\nxy - 2y = x + 3\n(x - 2) = (x + 3) / y\n y = (x + 3) / (x -2)
225103
2y=2x+1 is the equation for a straight line having a slope of 1 and a y intercept point of 1/2. Y is then a function of the value of x or vice versa, whichever way you care to think about it.
953419
The slope intercept form of the line is \n\ny = mx + b where m = slope and b = y-intercept\n\nSince (5, -3) lies on the line then\n\n-3 = 5m + b\n\nie 5m + b - 3 = o\n\nSo any line in which m = (3 - b)/5\n\neg b = -2, m = 1 So y = x - 2\nb = 8, m = -1 So y = 8 - x ....... and so forth\n\nGraphing m against b would give all the values of m, b that satisfy the given condition.
523552
It's already in slope and y-intercept form...  y = mx + b, so slope (m) = 7, y-int (b) = 0
180320
Draw any line passing through origin. Its equation is y = mx and the slope ‘m’ is y/x.\n\nNow move the line up (or down) through a distance‘d’ with out changing the slope. The line cuts the y-axis at a distance d from the origin. This is y-intercept.\n\nThe x-coordinates of all the points on the line remain the same whereas all y-coordinates increase (or decrease) by‘d’. But the slope remains the same and x coordinates also remain the same. Therefore we give a correction to y coordinate to keep m constant.\n \nDenoting +d or -d by ‘b’, the slope of the new line’ ‘m’ is (y- b) /x. \n\nThus the equation of any line in slope intercept form is \n\nm =(y - b)/ x. or y = mx + b.
203791
The x-intercept is when the line crosses the x axis. When your equation's graph crosses the x axis, it means that y is zero at that point. right?\n\nSo to find the x-intercept you assume y=0 and solve for x.\n\nNow to find the y-intercept, it is when x=0. If you imagine it graphically, when it touches the Y-axis, X's value is zero.\n\nSo to find the y-intercept you assume x=0 and solve for y.\n\nExample: y= 3x-6\nx-interp: assume y=0\n      0= 3x -6      \n 3x = 6     \n x = 2\n\ny-interp: assume x=0 \n     y= 3*0 -6        \n          y= -6
873072
in an equation y = mx + b, m is always the slope and by is always the y-intercept\n\nx + 2y = 3\n2y = 3 - x\ny = (-1/2)x + (3/2)\nthe slope is -1/2 and the y-intercept is 3/2\n\n1/2x - 9 = 0\nwhere's the y?  this isnt an equation\n\ny = 3x - 2\nthe slope is 3 and the y-intercept is -2\n\ny + 4x = 8\ny = -4x + 8\nthe slope is -4 and the y-intercept is 8
857166
Slope intercept form is y=mx+b\n\nStandard form is Ax+By=C\nIn which A, B, and C are whole numbers.\nSo, you have y-4=-x+1.\ny-4(+4)=-x+1(+4)=\ny=-x+5=\nx+y=5\nThere's your answer.
771990
y = mx + b is the slope intercept form, where m = slope\n\nso 2 is the slope in your example\n\nWith any equation for a line, there are 2 variables, x and y, representing the position on the x and y axis.  Given any line equation, you can manipulate it to get it into slope intercept form (y = mx + b), and m will be your slope.\n\nThe y-intercept is where the line crosses the y-axis (or where x = 0).  As you can see, if you put x = 0 in the equation, you will get:\n\ny = 0x + b\ny = b\n\nso when x = 0, y = b.\n\nHope this helps! :)
653148
All equations for a line will have the form:\n\ny = mx + b,\n\nwhere x & y are coordinates, m is your slope, and b is your y-intercept.\n\nTherefore, substituting in your slope and y intercept, you get:\n\ny = -2/3x + 4\n\nThis equation can then be used to graph the line, since given any x, the corresponding y can be found. :)