could someone help me solve these word problems?
822270
Let's look at the rectangle problem:\n\nThe original is 12 x 8, for an area of 96.\n\nThe new rectanlge's sides are 3/4 the sides of the original, or 9 x 6 (since 9 is 3/4 of 12, and 6 is 3/4 of 8).  So the area of the new rectangle is 9*6 = 54.\n\nSo the ratio of the areas is 54/96 = 9/16 = (3/4)^2\n\nNotice that the ratio of the sides (new to old) = 3/4, and the ratio of the area (new to old) = (3/4)^2\n\n~ ~ ~ ~\n\nLet's look at the circles now.\n\nCircle 1 = radius 5\nArea = pi r² = 25pi\n\nCircle 2 = radius 15\nArea = pi r² = 225pi\n\nSo, when we multiply the radius by x, we are multiplying the area by x²\n\n~ ~ ~ ~\n\nIf every dimension of a 2-D figure is multiplied by k, then the areas can be expressed like this:\n\nFigure 1 Area = l * w = lw\n\nFigure 2 Area = lk * wk = lwkk = lwk²\n\nSo multiplying each side by k in a 2-D figure increases the area by k²  (that's k^2 in case you can't read the little 2)\n\n~ ~ ~ ~ \n\nIf every dimension of a 3-D figure is multiplied by k, then the volumes can be expressed like this:\n\nFigure 1 Volume = l * w * h = lwh\n\nFigure 2 Volume = lk * wk * hk = lwhkkk = lwhk³\n\nSo multiplying each side by k in a 3-D figure increases the volume by k³ (that's k^3 in case you can't read the little 3)\n\n~ ~ ~ ~ \n\nBeach ball volume = 100 in³\n\nLet r = radius of beach ball.  If we multiply the radius by 3, new radius is 3r, and the new volume is 4/3 * pi * (3r)³ = \n4/3 pi*27r³ = \n27 * 4/3 pi r³\n\nBut 4/3 pi r³ = 100 (our original beach ball), so 27 * 4/3 pi r³ = 2700 in^³.  (Notice this is 27 times our original ball, or 3³.)\n\n~ ~ ~ ~\n\nHope that helped you some!\n\n~ ♥ ~
443144
you should try this site http://www.oberlin.edu/physics/dstyer/SolvingProblems.html
1170886
problem\ninformation\nhypothosis\nexperiment\nrecording\nconclusion\n\njust remember pi herc (abbreviations) and it will be easy
836789
All this problems are solved using the equation:\n\nHeat = M * Cp * DeltaT\n\nPlug the numbers, check wich one is OK.  Oh, and watch the units.
347066
ok, i think one will be where you have to solve a word problem dealing with alegebra. One with number sentences that have a letter on one side of the problem and letters on both sides of the problem. i could be wrong, but i'm trying to help.
777129
Product\n\nPrice\n\npromotion\n\nplace\n\nWilliam
1097568
m0= A'B'C'D'\nm1= ABSENT\nm2=A'B'CD'\nm3=ABSENT\nm4=A'BC'D'\nm5= ABSENT\nm6= ABSENT\nm7= A'BCD\nm8=AB'C'D'\nm9= ABSENT\nm10= ABSENT\nm11= AB'CD\nm12=ABC'D'\nm13=ABSENT\nm14=ABCD'\nm15= ABSENT
263164
I won 10 points!\n\nThis is pretty easy. Try to stump me with harder ones.
937047
Well, there may be more solutions here than usual, but the first solution I see is:\n(3 L,5 L,8 L)\n(0/3,0/5,8/8)\n(0/3,5/5,3/8)\n(3/3,2/5,3/8)\n(0/3,2/5,6/8)\n(2/3,0/5,6/8)\n(2/3,5/5,1/8)\n(3/3,4/5,1/8)\n(0/3,4/5,4/8)
599042
I'll solve it for you. Send it over.\n\nstill\nshell\ngrill\ncliff\n give us a clue
263495
email me for solution
356852
respond, react, rejoin, counter, solve, satisfy, solution, key, resolution, remedy, fulfill, retort
903092
1) b)\n\n2) [H2O]^2 / 2[H2] [O2]\n  \n   [NO]^2 / [N2] [O2]\n\n3) b)\n\n4) b)
896358
Referring  to URL http://en.wikipedia.org/wiki/Word_problem might be of some help to you:\n\nThe term word problem has several meanings:\n\nFor a mathematical problem written without heavy reliance upon mathematical notation, see Word problem (mathematics education). \nFor the word problem for encodings of sets in mathematics and computer science, see word problem (mathematics). \nFor the word problem for groups, see word problem for groups
117050
These should do the trick,\nhttp://www.puzzledepot.com/wordfinder2/scrabble.html\nhttp://www.a2zwordfinder.com/\nhttp://www.wordfinder.co.uk/
706993
Try reviewing your class notes and looking through your text book. Im sure that the answer you need is there. It might take a bit of thought to figure out how to do these problems! Take the time to figure it out, it will be worth it in the long run!
625162
Try dictionary.com, m-w.com, or one of the thousand other good dictionary websites on the web, as for problems, try search on http://mathforum.org/