simplify by dividing n^3-27/n-3?
831325
Factor the numerator.\nn^3 - 27 is a difference of cubes.\nn^3 - 27\n= n^3 - 3^3\n= (n-3)(n^2 + 3n + 9)\nYou can cancel the (n-3)'s leaving you with\nn^2 + 3n + 9
1103929
(x^3+x^2-11x-15)/(x+3)\n= (x^3+3x^2-2x^2-6x-5x-15)/(x+3)\n={ x^2(x+3)-2x(x+3)-5(x+3)}/(x+3)\n={(x+3)(x^2-2x-5)}/(x+3)\n=x^2-2x-5\n\nThis should do. but on further simplification you will get \n   x^2 -2x -5\n={x^2 -1 -6^(1/2)}{x^2 -1 +6^(1/2)}
912076
Divide numerator and denominator by 9... your answer is:\n1/3\n\nYou can't reduce this any further.
514501
It's not really a problem as much as a simplification; there's no = sign.  Anyway, simplified I get 8w^3 + 4w^2.  I got that by multiplying your original problem by \n(-2w-1)/(-2w-1).  That gets rid of the fraction in the denominator and reduces the numerals in the numerator down.
387063
X=[-(30y-433)]/1232\nY=[-(1232x-433)]/30
947283
You can do this using "synthetic division"\n....... ______________________\nx - 5 ) x^4 - 0x^3 - 3x^2 + 0x + 6\n\nI'm going to simplify this leaving out the x-terms and only showing the coefficients, but just imagine they are there:\n\n.............. 1 . 5 .22 110\n1 -5 ) 1 . 0 .-3 . 0 . 6\n......... 1. -5\n......... ------\n.............. 5 .-3\n.............. 5 -25\n.............. -------\n................... 22. 0\n....... ........... 22 -110\n....... ............----------\n....... ........ ........ 110  6\n....... ........ ........ 110 -550\n....... ........ ........ ------------\n....... ........ ........ ....... 556\n\nSo if I did it correctly the answer should be:\n1 5 22 110 remainder 556\n\nThis equates to:\n(x^3 + 5x^2 + 22x + 110) + 556/(x-5)
912865
bring the a's to one side... u then get 9a = 27 ... divide and answer is a = 3
903769
You can cross-cancel, and then multiply ... at least I think that's what it's called. \n\nLet's say you have the problem 27/4 x 16/9. Looks somewhat large at first, but you can make it really simple. The 9 and 27 can be reduced, because 9 is a factor of both of those numbers. Take 9 out of each and you get 3/4 x 16/1. Then you can take 4 out of the 16 and the 4. You're left with the problem 3/1 x 4/1, which equals 12/1. That reduces to 12.\n\nA long-looking problem that can be easily simplified. Hope that helps.
83153
There are a couple of ways to work this out, I will take the easiest to explain.\n\n(x-3)(x^3+3x^2+9x+27) Can be rewritten as:\n\n(x)(x^3+3x^2+9x+27)+(-3)(x^3+3x^2+9x+27) Now, multiply those out.\n\nx^4+3x^3+9x^2+27x-3x^3-9x^2-27x-81 Now, sort by like powers of x\n\nx^4+3x^3-3x^3+9x^2-9x^2+27x-27x-81 Simplify\n\nx^4-81
503803
3p > 21 + 6\n now adD 21+6 on the right hand side\nthis will give u 27\n3p > 27\nnow this will give u 27 divided by (/) 3\np > 27/3\np> 9\nthe answer is : p>9
780298
first u distribute the - to the stuff in the parenthesis so you have\n7x^2-3+x^2\nthen combine like terms\n8x^2-3
1001958
just go straight across.\n\nlike:  3/8 x 2/3 = 6/24 which simplifies to 1/4\n\nBecause on the top: 3x2=6 and on the bottom: 8x3=24\nThen 6 goes into itself once and into 24 four times: 1/4
924341
(6 + 7) * (4-2) = 26\n(14-5) / 3 = 3\n27 / (4+5) - 1 = 2\n6 * (7+2) - 1 = 53
486697
You do not need to use logs.\n27 can be written in base 3\n27 = 3^3\nTherefore,\n27^4 = (3^3)^4\nMultiply the exponents to get\n27^4 = 3^12\nThus, your equation is not\n3^x = 3^12\nWhenever the bases are the same, then the exponents are equal.\nTherefore,\nx = 12
949707
What you want to do is progress till the x is the only thing on one side of the equation; so\n\nget the 7 on the other side by adding 7 to each side of the equation:\n3x-7+7=26+7; this comes out to \n3x=33\n\nstill with me?   you have to do the same thing to both sides of the equation to keep it equal, so since you had to add seven to get rid of minus seven, you also have to add seven to the other side.\n\nnow you have  3x=33 and you need to get rid of the 3 multiplier, so now you will divide each side of the equation by 3:\n3x /3=33/3, or\nx=11\n\nto check for accuracy, just plug your answer, 11, back into the original equation and make sure it works:\n3times11  -7= 26.    \n\nsee? it's not so hard when you take it step by step.  in a little while you'll be solving these in your head.\n\nblessings!\ncryllie
964858
That just means that keep it in the square root instead of simplifying it.\nEx: Keep it as square root of 2 instead of 1.414\n\nSo if you're finding the square root of 27, for example.  You can split up 27 into 9*3.  Square root of 9 is 3, but 3 is not a perfect square.  So your answer would be : 3 square root of 3.  Instead of 5.196
968455
The ans is:\n\n27(26^4)\n\n26^4 + 26^5 = 26^4(1+26) => 27(26^4)