to write a C program on counting votes of each candidate?
817175
Isn't C really old?  What about C++?
1077694
I suggest you visit a site like www.sourceforge.org or www.programmersheaven.com. There are many open-source, game projects written in C.
917519
call the board of elections
115468
Here's the pseudo code - code it in any language you want - \n1. Find length of word, say N.\n2. i = 0, flag = 0\n3. Repeat following step till i <= N/2\n4. If ith letter is not equal to (N-i)th letter, set flag to 1 and exit loop.\n5. If flag = 0, word is a palindrome.
773524
In every race there are mistakes made in the vote counting. Either a machine malfunctioned or ballots were miscounted. It just happens. And when a vote is as close as these two are, it is just natural to check for those mistakes.
653726
I think it should be a certain amount of votes per phone number, like 5 or 10. That way, if people in the same household have different opinions they can all have a vote. Although it's easier said than done, I don't think AI will ever change the voting process.
423398
here...I'll tell you what to write and you write it...\n\n/* outline the program */\n\n// void main()...etc..\n\n/* define your variables */\n/* you'll need a pair of char pointers */\n/* and some numbers to hold converted values */\n\n\n/* input the first binary as a string */\n\n/* input the second binary as a string */\n\n/* convert them to decimal */\n\n/* add them */\n\n/* fprintf them */\n\n/* end program */\n\n\nthat's all.\nI write all my programs in commented logic first then fill in the blanks so that it does what I meant.  When I'm done, the program follows the flow and is already commented for the next person to follow.
1127766
61 Million votes\n\nThat's how.
207892
I'm not going to write any code for you, but I've got some ideas.\n\nIf you don't care whether the program uses real words, then implementation should be pretty easy.\n\nFirst, for each sentence, have the program decide how many words should be in the sentence. Then, for each word, have the program decide how many letters should be in the word. The program should alternate between consonants and vowels in order to ensure that the gibberish is still pronouncable. The program could also have a set probability for inserting parenthesis or commas, perhaps 1 in 7 for a comma and 1 in 40 for parenthesis. Be sure that the first word in the sentence begins with a capital letter. At the end of the sentence, the program should decide whether to end with a period, question mark, or exclamation point. You can then repeat for however many random sentences you would like.\n\nNow, if you want the program to use REAL words, you'll have to do a bit more work. First, you'll need a list of words, a "dictionary" so to speak. This will need to contain a lot of information if you want to make sentences using real words. You'll need information about its part of speech (noun, verb, adjective, adverb, interjection, etc.), gender (masculine, feminine, neuter), if the word is a verb whether it has any irregular forms or whether the verb is transitive or intransitive, if the word is a noun whether it has irregular plurals (e.g. "datum" and "data", or "goose" and "geese") or whether it's a proper noun none, some, or all of the time, if the word is an adjective whether it can be made into an adverb by adding -ly, and basically information for any other question that might come up when making a sentence. That's probably more than enough work right there. BUT, once that's taken care of, the program can use the random number generator along with the rules of grammer to make a sentence "framework", then simply select random words of the right part of speech to "fill in the blanks". For example:\n\n(?article?) (?adjective?) (noun) (?adverb?) (verb) (?article?) (?adjective?) (?noun?)\n\nThe question marks indicate optional parts of speech for such a framework sentence. The program might make sentences like the following:\n\nA blue apricot graciously impregnates the tall monkeys.\nThe car likes reality.\nBarns reluctently hold a safe hose.\nA baby vomits.\n\nIf you get really advanced, you can create other "sentence frameworks":\n\n(?article?) (?adjective?) (noun) was (?adverb?) (verb-past_participle) ?by? (?article?) (?adjective?) (?noun-posessive?) (?article?) (?adjective?) (?noun?)\n\nA velvet god was almost smashed by the delicious boss's happy dollars.\nMatthew was totally x-rayed by butter.\nA red vending machine was inflated by pride.\nThe rediculous baseballs were swallowed.\n\nIn conclusion, you'll have to apply all of your linguistic knowledge and problem solving skills -- not to mention a lot of time -- on this one. Actually it sounds like something I'd like to try. E-mail me if you're interested.
815399
First take a look on Quick-sort algo-based program :\n\n// Prog: QUICKSORT (RECURSIVE)\n#include<stdio.h>\n#include<conio.h>\n\nvoid quickrec(int *,int,int);      // declaration of function protoype\n\nvoid main()\n{\n  int x[30],n,i;\n  clrscr();\n  printf(" Enter total no. of elements ");\n  scanf("%d",&n);\n  printf(" Enter %d elements ",n);\n  for(i=0;i<n;i++)\n  scanf("%d",&x[i]);\n  quickrec(x,0,n-1);\n  printf(" After sorting get :&#92;n ");\n  for(i=0;i<n;i++)\n  printf(" %d",x[i]);\n  getch();\n}\n\nvoid quickrec(int x[],int lb,int ub)\n{\n  int pivot;\n  if(ub<lb)\n    return;\n  else\n  {\n  pivot=partition(x,lb,ub);\n  quickrec(x,lb,pivot-1);                 // These two\n  quickrec(x,pivot+1,ub);                 // are recursive calls.\n  }\n}\n\nint partition(int x[],int lb,int ub)\n{\n  int a,up,down,temp;\n  up=ub;\n  down=lb;\n  a=x[lb];\n  while(down<up)\n  {\n     while(x[down]<=a && down<ub)\n     down++;\n     while(x[up]>a)\n     up--;\n     if(down<up)\n     {\n       temp=x[down];\n       x[down]=x[up];\n       x[up]=temp;\n     }\n  }\n  temp=x[lb];\n  x[lb]=x[up];\n  x[up]=temp;\n  return up;\n}\n\n- - - - - - - - - - -- - - --- - -- - - -- -- - -- - - -- - - - -- \nNow coming to ur question. Mark '0' as 'down' and '6' as 'up' [bcoz array starts from position '0' & extends to '6', since there're 7 elements]. Again, a=10. Since, x[down]<=a condition is satisfied, down++ occurs. Now, 'down' points to 19. As 7<10, so x[up]>a condition is not satisfied, so up-- doesn't occur. Now, since down<up, so x[down] and x[up] are exchanged. Now arrangement is {10,7,2,17,3,11,7,19}. Again this loop'll be executed... thus at final step in 1st partition-stage u'll get {3,7,2,10,17,11,19}. Just follow the program & apply it on this. Go through the book on Data-Structures by Tanenbaum. There u'll ge step-by-step worked-out examples.
81883
Details of the algorithm for conversion along with\nsource program written in C can be found at.\nhttp://www.codepedia.com/1/Art_Expressions_p1\n\nA good short article on this topic.\nhttp://www.cs.man.ac.uk/~pjj/cs2121/fix.html
1049228
This site comes directly from Major League Baseball.\nAll leading vote-getters are listed at the bottom of the page.\nThey also list dates for updating the counts.
864102
There is no set number.  A list of nominees goes to the voters, and only those who receive a 75% vote are elected.
1019358
Here's 17 different implementations. Take your pick...\nhttp://www.planetsourcecode.com/vb/scripts/BrowseCategoryOrSearchResults.asp?txtCriteria=Tic+Tac+Toe&blnWorldDropDownUsed=TRUE&txtMaxNumberOfEntriesPerPage=10&blnResetAllVariables=TRUE&lngWId=10&optSort=Alphabetical
917997
Simply loop through the list of numbers and compute:\n\n'number' modulo '2'\n\nIn C, that would be:\n\nnumber % 2\n\nA modulus of 2 would return a '1' for odd numbers, and '0' for even numbers (since even numbers divide by 2 with no remainder, and odd numbers divide by 2 with a remainder of 1).\n\nExample:\n\nint index;\nint numArray[25];\n\n...(store the 25 numbers in the array)...\n\nfor(index = 0; index < 25; index++) {\n     if(numArray[i] % 2) {\n          printf("%d&#92;n", numArray[i]);\n     }\n}
876424
Use this site: http://www.vote411.org/pollingplacebystate.php
509939
count the politicians