how long does it take to count to one trillion?
815662
At one number per second, it would take you 11, 570,000 days, or about 31709 years.\n\neven at 10 per second you would need 3170 years, so, being a mere human, you couldn't do it.\n\nWill
286402
It's actually plenty of time. Count with the clock for like three minutes. Yipe! it's longer than you think. When you're in pain, 60 seconds is an eternity. It's plenty of time. Unless you're a bomb technician :0)
1017128
i'm positive it takes as long as it has accurately been calculated to be.
1014006
The answer to your question is "it depends on where you are."\n\nIn the USA, One Billion is equal to 1000 Million -- that is it is 1,000,000,000.\n\nHowever, in some countries, a Billion is equal to a million million -- 1,000,000,000,000.  \n\nThat means that in those countries a Billion is equal to a thousand US Billions -- which is called a Trillion in the US.
1011935
Which one?  They're not all the same you know.\n\nLet's say 400,000 years for safe\n\nOK ok,\n\nr = 30 trillion miles\nC = 2πr\nOrbit length = 188.5 trillion miles\nPluto orbits at something like 2 km/sec which translates to 5369 mph.  Let's divide that by 4 for silly [Outer objects travel slower than inner objects].  That's 1342 mph.  Dividing...\n140,461,997 hours.  16,023 earth years.
606654
PRecisely 365.24 days. Every four years we have a leap year, but to keep from getting ahead we skip the whole leap year thing once out of every hundred. We might have done so in 2000, I don't remember.
117381
Roughly 5.87 trillion miles
918131
Nine hundred ninety-nine trillion and one.  :)\n\nBut if you're asking what number comes after nine hundred ninety nine trillion, nine hundred ninety-nine billion, nine hundred ninety-nine thousand, nine hundred ninety-nine, I believe the answer is "one quadrillion".
815694
One trillionth of one trillionth of one second.
957782
One trillion has 12 zeros. Here are the names of what comes after that: \n15 - quadrillion \n18 - quintillion  \n21 - sextillion  \n24 - septillion  \n27 - octillion 1000  \n30 - nonillion  \n33 - decillion  \n36 - undecillion  \n39 - duodecillion  \n42 - tredecillion  \n45 - quattuordecillion \n48 - quindecillion  \n51 - sexdecillion  \n54 - septendecillion  \n57 - octodecillion  \n60 - novemdecillion  \n63 - vigintillion  \n66 - undecillion\n \nBut it doesn't stop there. By definition, infinite means never ending.
596572
that would be "one thousand"\n\n\nbecause one million times one thousand is one billion\n\n1 000 000 x 1000 = 1 000 000 000
21973
1000 times 1000 is a million.
235811
1,000,000.  A billion is a million thousand.
635940
A little over 9 years.\n\n(1.08)^9 = 1.999
743411
I will assume that the interest is simple and compounded annually, just to make the question easier.\n\nYou will reach $1million (US system) 97 years later, at the age of 115.  $1,035,358, actually.\n\nI used a simple formula with an Excel spreadsheet to figure this out.
555365
9-billion\n12-trillion\n15-quadrillion\n18-quintillion\n21-sextillion
1144278
Let's assume that you can count pretty quickly.  Say 10 numbers per second.  Let's assume that you start counting when you are born and count at a rate of 10 numbers per second until you die 100 years later.  that means you have counted 10*60*60*24*365.25*100=3,155,760,000 numbers.  That is pretty good.  Let's call this number N.  And note that 3^3=27, 3^(3^3)=3^27=7625597484987>2000*N.  So, you could count to 3^(3^3) if you had 2000 lifetimes to do so.\n\nNow let's look at graham's number:\n\n3^3=27\n3^^3=3^(3^3)\n3^^^3=3^^(3^^3), where 3^^n=3^(n^n)\n3^^^^3=3^^^(3^^^3), where 3^^^n=3^^(n^^n)\n\n3^^3>2000N\n3^^^3>>N (this means a hell of a lot bigger)\n3^^^^3>>>>>>>>>>>>>N\n\nbut 3^^^^3=g_1\n\ngraham's number is g_64 where g_n is defined recursively by\ng_1=3^^^^3 and g_n=3^^^. . .^^^3 where there are g_(n-1) ^ between the 3s.\n\nSo, if you had all the computers in the world counting from the Big Bang until now, you would probably have made it to about g_3 or maybe g_4 (if scientists are very wrong about how old the universe is).