Two objects attract each other gravitationally with a force of 2.5*10^-10 N when they are 0.25m apart...?
813425
F = GmM/r^2; where G is a constant, m and M are the two masses, and r is the distance between them.\n\nm + M = 4 kg; so m = 4 - M\n\nF = G(4 - M)M/(.25)^2 = 2.5*10^-10; where G = 6.67 × 10−11 N m^2 kg^−2 \n\nUse the above to solve for M, then m = 4 - M to find m.  \n\nAnd there you have it, you do the math.
856254
The attractive force of the "magnet earth" is much smaller than it's gravitational force. In fact it's negligibly small. Proof: put an iron object on the table, like a knife. Despite it being much more closer to the earth than the moon, it will not budge.
9301
ok, well the formula you need is:\n\nFg=Gm1m2/r^2\n\nwhere Fg is the force of gravitation, G is the universal gravitational constant(just a constant, you dont have to worry about it) m1 and m2 are the masses of the 2 objects, and r^2 is the distance between the two objects squared.\n(a) ok, so if r increases by 10 times, since r is squared, the denominator would actually increase by 100 times.  Since the denominator increases by 100 times, and the numerator stays the same, you're basically multiplying it by (1/100) so that means that you have to do the same thing to both sides, so you just multiply Fg by 1/100 so thats 500/100 so the answer is 5 newtons.  This makes sense because the farther objects get from each other, the less each other's gravity will affect them.\n\n(b) ok, now one of the m's, lets say m1 doubles.  The rest stays the same again, and this time its in the numerator, so you're just multipying the whole thing by 2, so the new force would be 1000 newtons.  This makes sense, because something with more mass would experience more gravitational force, for example, a person with more mass experiences a greater gravitational force with the earth, and therefore weighs more.
503782
If there were 2 planets, one would probably catch up with the other. The slightest difference in their orbital speeds would lead them to come together and either collide or start orbiting around a point in space between the 2 planets. When they got very close, they would be gravitationally attracted to each other. They would either merge into one planet under gravitional force, or the gravitional force of the larger one might slingshot the smaller one out of this orbit into one further away from or nearer to the sun.\n\nThe distance at which a planet orbits from the sun is dependent just on its speed, not its mass. If the 2 planets had substantially different speeds, they would orbit at different distances from the sun.
121693
cmon...dont u know basic physics...just calculate the resultant of these 2 forces\nanswer= [(132)^2 + (181)^2]^1/2\nif this makes sense!!
78189
I think you're asking about the relationship between distance and gravitational pull.\n\nGravitational pull weakens as the distance increases.  The farther you are away from an object, the weaker the gravitational pull will be.\n\nWe say that gravity is "inversely proportional" to distance - meaning as distance increases, gravity decreases, and as distance decreases, gravity increases.\n\nMore specificially, gravity is inversely proportional to the square of the distance - meaning that if the distance increases by a factor of 2, gravity decreases by a factor of 4, and if the distance increases by a factor of 3, gravity decreases by a factor of 9.
83044
The one with the lowest alititude will pass the one further away because the gravitational pull is stronger the closer an object is to earth.
968370
If the origin of the coordinate system is placed at the middle of the two particles positions are -r/2 and r/2. Two charges of the same sign will repell each other so the force has a positive sign and it's magnitude is given by (C Q^2) / (r^2) Where C is the Coulomb constant.
375266
Gravity is a force that accelerates two masses directly towards each other. In order for the masses to not simply crash into each other, one of the masses must have some nonzero velocity relative to the other mass that is not directed along the line between them. \nAssume one mass is larger than the other. It takes some time for the smaller mass to hit the larger mass under the pull of gravity. If we give the smaller mass a velocity perpendicular to the line between the two masses, the mass may "miss" the larger planet before it falls all the way to the surface, and continue to do so. The range of velocities can make this continual freefall take shapes from a perfect circle (the perfect tangential velocity, which has almost zero probability) to ellipses, and with high velocities from parabolas to hyperbolas.\nA velocity too small will simply increase the amount of time before the planets collide, these are spirals.
297729
You are correct, but the effects are so insignificant, it doesnt nearly matter.\n\nAll object in the universe have a gravitational attraction to one another.\nTake the Earth and bowling ball example,\nThe Earth exerts a force on the bowling ball, and the bowling ball exerts a force on the Earth.  Both on these forces cause the other object to accelerate towards a common center of mass.  In the case of the Earth's gravitational force on the bowling ball, the force is huge in comparison to the bowling ball's force exerted on the Earth, so much so that we can easily neglect the 2nd force.\n\nLets look at some numbers.....\nIf we say the Earth has a mass of 5.9742 E24 kg and say we will say we have a very heavy bowling ball with a mass of 1000 kg, then we can calculate the gravitaional force between them if we know the distance.  Lets estimate their centers of mass are 6380 (~larger than radius of Earth), we can calculate the gravitational force to be,\nF_g = (G*M*m)/r^2\nF_g = 9789.58 Newtons, which would cause an acceleration of 9.7895 mm/s^2 for the bowling ball and a miniscule 1.63 E-21 m/s^2 for Earth.  To put that in perspective of just how slow acceleration is, if you were to accelerated you car from at a constant acceleration of 1.63 E-21 m/s^2, it would take you about 86500000000000 YEARS to go from 0 to 10 miles per hour!  I think for simplicity sake, Newton did all right.\n\nEDIT:\nYes, the bowling ball very much so does pull on the Earth.  How is the "universe" to know which object is suppose to be the planet and which is the bowling ball?  ALL objects in the universe have a gravititational attraction to ALL other objects.  The Earth pulls in the bowling ball, and the bowling ball pulls on the Earth.  There are 2 equal forces pointed in opposite directions, therefroe momentum is conserved (which is a physical LAW).
233618
1 mass\n2 magnitude of separation
408862
the force between the object and the earth is dependant on mass, but the acceleration of the object towards the earth is 9.81 meters&#92;second. (ignoring air resistance)\n\nforce = mass x acceleration
383007
Yes, the first part is true.  Why does that make tides more "believable"?  \n Any two gravitaionally-bound objects will orbit around a common center of gravity.  (which is closer to the more massive object).
976997
As objects move closer together, the gravitaional forces betwen them increase.  That is to say, the gravitational force is inversely proportional to the distance betwen the objects.\n\nA reduction of distance by a factor of 5 would mean a five fold increase in the gravitational force.
355325
Newtons, or sometimes kilograms
965826
L = 8pi G rho/c^4 is the definition of the cosmo constant L (1/m^2); where c = light speed and rho is the energy density of the known universe in a vacuum.\n\nF = GmM/r^2 is the equation for the attraction force F between two masses m and M, r distance apart.\n\nL was created by Einstein to make his equations come out right.  By that, he meant the universe should be spherical (not flat or saddle shaped).  His original results showed a flat universe, and he just "knew" that was wrong; so on came L to fix the shape problem.\n\nF was the result of experiments by Newton.  Through observation, he found that the attractive force between two bodies was proportional to the inverse square of the distance between them and to the product of the magnitudes of the two masses.  That is, F varies as (~) (mV/r^2).  \n\nWhenever there is a proportionality, as in F ~ mM/r^2, there has to be a constant of proportionality.  In this case Newton called it G; so that F ~ mM/r^2 becomes F = GmM/r^2 when the constant is inserted.\n\nThe G in both equations is the same constant.  But Sir Newton came upon it long before Einstein found it could be used in his equations and the calculation of L.  So there is no way that Newton (1642-1727) could know about Einstein's (1879-1955) use of it much later.
318297
The derivative of the potential function is the gravitational force.\n\nPotential(At distance r) = G*Mass/d\nForce = Derivative(Potential)\nForce(At distance r) = G*Mass/d^2\n\nWhere G is the gravitational constant and r is the distance from the center of the sphere.\n\nSo when you are considering 2 bodies of mass M & m we get the formula (GmM)/r^2.