Help with nuclear equations Any Help will be Greatly Appreciated !!!!!!!!?
832260
A 60 over 28 Ni\nB 222 over 86 Rn\nC 0 over -1 e\nD 4 over 2 He\n\nMake sure all the subatomic particles balanced. Total number of nucleons (proton + neutron) and protons should be the same on both side of the equation.
64647
2x (G2 + M2 ---> 2GM)      DH=-280.0*2= -560.0 kJ\n2x (L + 2M2 ---> LM4)      DH=-350.0*2= -700.0 kJ\n   (L2G4 ---> 2L + 2 G2)   DH=122.0*(-1)=-122.0 kJ (change sign when flip over)\n\nAdd them together, we'll have:\n2G2 + 2L + 6M2 + L2G4 ---> 4GM + 2LM4 + 2L + 2G2\nthen cancel 2G2 and 2L on both side, we end up with:\nL2G4 + 6M2 ---> 2LM4 + 4GM\nthe enthalpy of this reaction is, therefore the sum of each enthalpies calculated above.\nDH=(-560.0) + (-700.0) + (-122.0)= -1382.0 kJ (exothermic process)\nhope that'll help!
732400
25u + 74 = 23 u + 92\nlet's move all the numbers without variables to the right side.\nSubtract 74 from both sides.\n25u +74 -74 = 23 u +92 -74\nremember that whatever you do to one side of the eqn you have to do to the other.\n25u = 23 u + 18\nnow let's move the u's to the same side.\nsubtract 23u from both sides.\n25u - 23u = 23u -23u +18\n2u = 18\ndivide both sides by 2\nu=9
109271
This is from Mr. Jeffy:\n\nIf you know that 60.4% of the naturally occuring isotopes have an atomic mass of 68.9257 amu, then you know that the other 39.6% much have an atomic mass such that the averge is 70.9249 amu.\nSo,\n(60.4% of 68.9257) + (39.6% of x) = 70.9249\nSo solve for x.\n============================================================\n\nI think he merely switched a couple of terms here, so I think the equation will look like this:\n\n(60.4% of 68.9257) + (39.6% of 70.9249) = x\n\nSolving:\n\n41.6311228 + 28.0862064 = (approx.) 69.72\n\nYou have gallium (Ga), my friend.
795345
Same number of protons\n\ndifferent number of neutrons
660043
1.) do your own homework\n2.) this is the computer forum, not high-school chemistry.  Next time post to the right furom.
703814
211_____207_____4\n      Bi  -->__Tl +____a    (a helium nucleus) \n83_______81_____2
792926
You got it right when saying the more N+P it has, the heavier it will be. But you forget one thing:\n\nPeriodic table is sorted by the number of protons, not their atomic weight. Atomic weight noted there is calculated on the base of the proportion of naturally occuring isotopes. I guess you know what an isotope is. They are nuclei having same amount of protons but differ in neutrons. \n\n99.6% argon are 40Ar18 whilst 93% Potassium are 39K19\nBoth has the same number of nucleon = 58. Small differences may apply because of the contribution of other isotopes.
844758
Using the Michaelis-Menten equation.\n\nMore details on teh attached link\n\nhttp://www.le.ac.uk/by/teach/biochemweb/tutorials/michment2print.html\n\nGood luck
1040448
ask your chem prof or tutor ..it's hard to explain over the internet!
212309
The half-lives will vary depending on the isotope.  Go to the library and look them up in "The Handbook of Chemistry and Physics" in the reference section.
469212
See if this helps.\n\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/atomic/hund.html
853922
These are the right ones:\n\n2K(s) + 2H2O(l) ---> 2KOH(aq) + H2(g)\nH2SO4(aq) + 2KOH(aq) ---> K2SO4(aq) + 2H2O(l)\nCa(OH)2(aq) + 2HCl(aq) ---> CaCl2(aq) + 2H2O(l)
580964
Gamma decay is probably the one you are after.\nTransitions in the energy levels of the nucleons is the process behind it.\nNuclear Magnetic Resonance is also a nuclear process and would make a better answer as the wavelength of radiation is much safer.
778260
You could also write an alpha particle as:\n\n(4,2)He\n\nand a beta particle as:\n\n(0,-1)e.\n\nThese notations are useful in nuclear reactions.
741999
whats the equation or formula u need help with?
497024
H2S---> 2 H^+ + S^2-\nK(eq) = \n[2H^+]^2 [S^2-]\n ---------------\n     [H2S]\n\nNH4+----> NH3  + H^+\nK(eq) =\n [H^+][NH3]\n       ------------\n         [NH4+]\n\nC6H5COOH----> C6H5COO-  + H+\n\nK(eq) = \n[H^+][C6H5COO-]\n        ---------------\n         [C6H5COOH]