how can i find the perimeter and area of a box?
813209
perimeter= 4(L+W+H)\narea= length times the width times the height
891853
let the side of thesquares be x cm\nlength of the box=(100-2x)\nand width=(60-2x)\nvolume=(100-2x)(60-2x)(x)\n(6000-320x+4x^2)x\n=4x^3-320x^2+6000x=0\ndV/dx=12x^2-640x+6000=0\n4(3x^2-160x+1500)=0\nsolve for x
172067
Perimeter is the distance around a figure. The area is the amount of space inside the shape. Good luck!
511828
I want to point out first that the formula for perimeter of a circle is (pi)d or 2(pi)r, not (pi)r^2- (pi)r^2 is for the area!\n\nAnyway, P= (pi)d\n         = 8pi\nDivide that by two since it's just a half circle\n         =4pi\nAdd 8 to that, and there you have it, the perimeter!\n\nFinal Answer- 4pi+8 or 20.56cm^2
800206
The 400 feet of fencing forms the perimeter P of the rectangular area.  The perimeter of a rectangle is P = 2*W + 2*L.  The area of a rectangle is A = L*W.  Take either the W or L from the perimeter equation and solve for it in terms of the other.  For example. 2*W = P - 2*L, or W = (P - 2*L)/2.  Put this expression for W into the area formula\n\nA = L*(P - 2*L)/2\n\nA = P*L/2 - L^2\n\nTo maximize area, take the derivative of A with respect to L to get\n\nA' = P/2 - 2*L  and set it equal to zero\n\nP/2 - 2*L = 0, or  L = P/4;  This gives you the length of the area.  You can get the width from the perimiter formula W = (P-2*L)/2;\nPutting in L = P/4 gives W = (P - P/2)/2 = P*(1-.5)/2 = P/4.\n\nNotice that L = W = P/4; in other words the maximum area rectangle is a square.
87402
a: width\nb: length\nperimeter = 2 x (a+b)= 420 ---> a+b = 210\nwe need to find max (a x b)\n\na= 210-b ---> area = a x b = b x (210-b) = 210 - b2 = - b2 + 210b = - b2 + 2 x 105 x b - 105squared + 105squared\n= - (b2 - 2 x 105 x b + 105squared) + 105 squared\n= - (b - 105)squared + 11025\n\nSince (b - 105) squared is always >= 0,\n - (b - 105)squared is always <= 0\n  - (b - 105)squared + 11025 is always  <= 11025\n\nthe largest area will be 11025 squared feet. This happens when - (b - 105)squared = 0, which means b = 105.\n\na = 210 - b = 105\n\n\nthe shortest way is to say that a rectangle has the largest area when it's a square, so each side would be 420/4 = 105.
558451
The are of a triangle can be found out by this formula...\nsquare root over s(s-a)(s-b)(s-c)\nwhere s=a+b+c&#92;2...\nWhere a, b and c are the sides..\nso i guess u can find the side and then find the perimeter..\nLolz...\nU calculate it urself
182640
I'm not sure if this is what you're asking, but if...\nd = length\nd-3 = width\n\nthen the area is d(d-3), a.k.a. d^2 - 3d .\n\nHope this helps!
378913
Do you mean like an object that has a semi-circle on one end?\n\nIf yes, you can find the area of the semi-circle by figuring the area of the entire circle and dividing by half. Then you just find the area of the rectangular portion and add the two answers.
804335
Call the side of the square you cut out x, then the box you make will have a square base of side (24 - 2x) and the height will be x. \n\nThe area of this box is then (24 - 2x)^2*x = 2x*(12 - x)^2. Call this a function of x, and we need to find the maximum.\n\n2x^3 -48x^2 + 288x = f(x)\n\n6x^2 - 96x + 288 = f'(x) = 0\n\nx^2 - 16x + 48 = 0\n\n(x - 12)(x - 4) = 0\n\nSo this has the 2 answers x = 12 and x = 4.\n\nx = 12 gives a minimum (volume = 0), so x = 4 is a maximum,  1024\n---------------\nI just looked at the above answers. JimBurnel made a careless error, the volume should be x(24 - 2x)^2, not x(24 - 2x). The rest of his logic is right, but the equation is wrong.\n\nAnd Paritosh Vasava assumes by "largest" you want surface area, I assume you mean volume. Of course the largest surface area comes when the squares you cut out are of size 0, your box is then 24*24*0, area = 576, volume = 0.
440894
go to this website and try to understand how to get the area of the shade region \n\nhttp://www.algebralab.org/lessons/lesson.aspx?file=Geometry_AreaPerCricle.xml\n\ngood luck
912405
Let x be the radius of the semicircle, then the rectangle has base 2r and height h.  The total perimeter of the window is\n\npi*r + 2r + 2h = 20. \n\nSo h = (20 - pi*r - 2r) / 2\n\nThe area is (pi*r^2)/2 + 2rh.  Replace h with the above so that the area is a function of r.  Differentiate to find the maximum.
164837
Perimeter = (2*L) + (2*W)\nArea = L*W\n\nFor example, if P=30 and A=50, L could be 5 and W could be 10.\n\nBut this might also work...\n\n((2*L) + (2*W))/Perimeter = 1 = (L*W)/Area\n\nFrom there, you can multiply both sides by the area (and/)or the perimeter to eliminate one of the fractions.  Just massage the numbers around a bit until the answer jumps out at you.
140062
L x W = Area\n\nCheater
103731
The area and perimeter would both be found using the same formula as finding it for a rectangle. Because the angles and lengths must be equal to be a parallegram if you cut off the angled part (trianle) from one end and put it on the other you would have a regular rectangle.\n\n2l+2h = perimeter\nl*w = area\n\nDo it the easy way!!!
493708
the formula for the area of any regular shape is \n(pa)/2, so there is no multipling the base by 2 involved.\np=perimeter\na=apothem
897940
perimeter = 2 * (length + width)\n\nfor square, length = width..\n\nso, perimeter = 2 * (2 * length) = 4 * length\n\ngiven, 4 * length = 104\nso, length = 26\n\nso, each side is 26 cm long.