Need help solving and identifying basic or acidic?
832121
Nope, :s sorry\n\nIts the same as before. The K(w) of water is 1.0 *10^-14\nK(w) = [H+][OH-]\n1.0*10^-14=[H+][2.8*10^-4]\n[H+]= 3.57*10^-11\n\npH=-log[H+]\n the pH is 10.4\n\nand pOH =-log[OH-] u have that in the ques\n\nHappy trails
394317
acids are sour and bases are bitter.\nacids turn blue litmus red and its the other way round in bases
810837
Just remember glucose (C6H12O6). Then using the basics of balancing any chemical equation you can figure out the rest of it.
20330
Go to this website and fill the Ph no. http://www.mp.bsnl.co.in/directory/ssasearch1.asp
618488
Look at their conjugate bases and whichever is more stable will have the weakest acid. PKA values are also easy to prove this becuase it is a realtion of the H+ content.
215160
http://www-ec.njit.edu/~skawinsk/chem243/chap11/chap11.htm\nthis may help–near the bottom
869137
2H3PO4 + 3Ba(OH)2 ---> 6H2O + Ba (PO4)2 +  2Ba
744922
HClO2 + Ba(OH)2 -> BaClO2 + H2O\n\n2(NH4)3PO4 + 3Ca(NO3)2 -> 6(NH4)(NO3) + Ca3(PO4)2\n\nFinished and balanced.
871537
It is not an redox or acid-base reaction. so you can't employ oxidation number method or ion-electron method. So the options you have left are the inspection method & algebraic method. Among them, I think this equation is way too simple to employ algebraic method.Why don't you employ the simple inspection method.\n\nC2H5OH-----------> Oh! BY THE WAY! WHAT IS HCO2. THERE IS NO SUCH COMPOUND AS THIS.\n\nHowever the possible products are:-\nC2H5OH----------------->CH3CHO + H2(Cu,300deg C)\nC2H5OH----------------->H2CCH2 + H2O(H2SO4,170 deg. C)\nC2H5OH----------------->C2H5OC2H5(H2SO4,140 deg. C)\nC2H5OH----------------->H2CCH2 + H2O(Al2O3,300 deg. C)\nC2H5OH----------------->H2CCH2 + H2O(H3PO4,250 deg. C)
1057509
below 7 is acidic\nabout 7 is neutral\nabove 7 is basic\n\nthe scale ranges from 0 - 14
951259
acid and base\nget red cabbage boil it but don't let the juice go to waste.. collect it\nget  some paper towel and dip it in the juice  pull it out and let it dry... pick it up and cut it in strips... now use it to measure if somethign is acid or base ... blue or green if its a base... red or orange if it's acid... \nthe hypothesis can be on finding out if any liquid is acid or base and the above is the procedure\ngood luck\nbtw a+ in 8th grade with this
1057594
I think this is how you do it:\nacid and base is measured in terms of pH and pOH. as you know, the H makes it acidic and the OH makes it basic, and if you mix an H and OH, you get water, which is to say it was neutralized.\nSo, let's say you have HBr with a pH of 4. You that pH is a measure of the concentration of H present in the mixture. So, to get the actual number you do -10ph, and you'll get a number like 10^-5 or something. So, to neutralize that many Hs, that's how many OH's you need. so, you'll need a pOH 4, which is the same thing is a pH of 10 (pOH = 14 - pH). \nhope that helps, good luck. and read the book, and do some of hte exercised in the book.
336053
Just by looking at any acid or base, its tough to guess. But still you can\n\n(1). Touch the solution with your fingers. If it is sticky like detergent, then its a base.\n(2) Acid smells "Sour" smell.. you remeber Vinegar smell?its acid smell\n\n(3) Open the cap of bottle inside the hood. If it is exibiting fumes then its a "Concentarted acid". If not then it may be a weak acid or a base. To confirm just touch with your fingers and see whether it id sticky or not.\n\n(4) If you have litmus paper then its so simple... if you have a blue litmus paper...which turns into red on treating with some solution then the solution is acid.. (Blue----Red---Acid   You can remeber this easily by first letters in each word..B--R--A)
43703
How about the red fountain experiment with acids and litmus solutions? mail me at pr4kane@yahoo.com for furhter details on it. u can try electroplating,bleaching by chlorine/so2,the brown ring test with sulphuric acid etc.
484565
Sounds like basic chemistry questions to me.\n\nAABBCAABD\n\nI think,
452992
Well first of all you have not given us all the information to be able to answer this buffer question.  We need to know the Ka (6.2x10-8)of the acid.  But the steps to perform the task.  Calculate how much of the acid is neutralized by the addition of the base.  Recalculate the equilibrium concentration of both the acid and base with the new acid value.  using Ka=[H+][Na2HPO4]/[NaH2PO4] solve for H+ and finally use pH=-log[H+].  Your final answer..pH=7.25
711408
I am not a chemistry student but I make this research for you and maybe it helps you http://www.chem.latech.edu/~deddy/chem104/104Antacid.htm\nhttp://www.chemcool.com/regents/acidsbasessalts/aim3.htm\n\njust copy those links and you should be on your way to solve ur problem.