BUDGET of Matrix Word Problem?
827269
good question. would like 10 points if no-one else answers please.
836161
Perhaps you can explain to everyone why you can not do this in google as I just did?\n\n\nPDF] BREADTH-FIRST SEARCH IN THE EIGHT QUEENS PROBLEM C K Yuen and M D ...File Format: PDF/Adobe Acrobat\nThe Eight Queens Problem is a familiar example in programming and algorithm textbooks . Usually, the given solution applies depth-first search with ...\nportal.acm.org/ft_gateway.cfm?id=185019&type=pdf - Similar pages \n\nWeb Resources Guide for Chapter 9Animations of breadth-first search and depth-first search can be found at the ... You can generate all the solutions to the n-queens problem in section 9.4. ...\nwww.mhhe.com/math/advmath/rosen/r5/student/ch09/weblinks.html - 44k - Cached - Similar pages \n\nEight Queens PlusThis is an extension of the "Eight Queens" problem: "Place 8 queens on a ... Here's the recursive depth first Search procedure that finds all 92 solutions: ...\nwww.delphiforfun.org/Programs/EightQueensPlus.htm - 19k - Cached - Similar pages \n\nDictionary of Algorithms, Data Structures, and ProblemsProblems include traveling salesman and Byzantine generals. ... Very Fast Substring Search Algorithm, Communications of the ACM, 33(8):132-142, August 1998. ...\nwww.nist.gov/dads/ - 88k - Cached - Similar pages
36600
MMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM\nMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM\nMMMMMMMMMMMMMMMMMMMMMMMMMMMCCXXXVI\n\nor cMCCXXXVI\n\ndepending on wich calculator you use =)\n\ni guess LOVECAT was right ...
75512
hey champ(Anirudh) !! what happened... so many errors in ur code?\ni hv'nt done much.. just removed the errors.. \nwell ur code was just like an error removing question... that v used to solve in the boards!  i loved solving those easy pickings!!\n\nanyways.. heres the exact code.. \n\n\n#include<iostream.h>\n#include<conio.h>  //for clrscr() & getch()\n\nvoid main()\n{\nclrscr();         //optional\nint array[10],i,least,greatest;\n\n//Input Numbers\ncout<<" Input 10 numbers separated by spaces  : &#92;n";\nfor(i=0;i<10;++i)\n   {\ncin>>array[i];\n   }\n\ngreatest=least=array[0];\n\nfor(i=1;i<10;++i)\n   {\nif(array[i]>greatest)\n     greatest=array[i];\nif(array[i]<least)\n   least=array[i];\n   }\ncout<<"&#92;nLeast in the list is "<<least;\ncout<<"&#92;nGreatest in the list is "<<greatest;\ngetch();//optional\n}
738212
you need to set up a matrix equation.  \nthe rows should look like this:\n\n1      ,   -2    ,     1    ,      / -8\n3      ,   -3    ,    -2    ,     /-5\n-2     ,   -3     ,    3      ,    /5\n\nOnce you set this up follow the rules of matrices to get this to a unit matrix.  Once you have done this the three numbers on the right will become your answers for x, y and z.  x being which ever row has the 1 in the first column.  y being which ever row has the 1 in the second column.  z being which ever row has the 1 in the third column.
867789
Try starting with a proportion. Let K be the cost we are looking for.\n\nb / x = K / y\n\nNow solve for K.\n\nK = by / x
1126894
This normally means that you are going to be using Gaussian (or Gauss-Jordan) reduction, where ther eare three "moves" that are allowed.\n\n1) You can switch any two rows in the matrix.\n2) You can multiply any row in the matrix by a non-zero scalar.\n3) You can add a multiple of one row to another.\n\nUsing these three "moves," the goal is to reduce the matrix into a usable form (the echelon form, for example).
1062782
you should use matlab.
364344
emmmmmm\n\nd. its not a fuction of x in terms of y explicitly. It needs to be rearranged
226493
This is a question of how many ways can 26 letters be assembled, if they can each be used m times, and the word produced is n characters long. Without specifying the number of times each letter can be used, and the limit on how many letters can be in each word, there is no way to solve the problem.
480863
There's something missing in that hint, there must still be an 'n' in there somewhere.\n\nTo work out the general formula:\n\nThe number of 2*2 matrices is (n-1)(m-1). The number of 2*3 is (n-1)(m-2). The number of 2*4 is (n-1)(m-3)... and so on until you reach (n-1)(1) = (n-1)(m-(m-1))\n\nSo the total number of 2 * j matrices is\nSigma(j = 1) { (n-1)(m-j) }\n\nThen the number of 3 * j matrices is\nSigma(j = 1) { (n-2)(m-j) }\n\nAnd so on, up to\nSigma(j = 1) { (1)(m-j) }\n\nThe sum of all these gives the number of i * j matrices as:\n\nSigma(i=1 to n-1)Sigma(j=1 to m-1) {(n-i)(m-j)}
73219
Anyone with matrix background
338547
Seems like you have a type-o just above line 13.  in your declaration of  the Matrix class.  should be a single c in the word 'class'.\n\nIf you aren't already, you may want to consider using an IDE like netbeans which will catch simple  syntax errors like this for you before compiling.\n\nhope this helps.
115853
#include <iostream>\n#include <vector>\nusing namespace std;\n#define rep(i, n) for((i) = 0; (i) < (n); (i)++)\n#define rep2(i, k, n) for((i) = k; (i) < (n); (i)++)\nvoid f21();\nint n;\ndouble mat[100][100];\nint main()\n{\nwhile(true)\n{\ncin >> n;\nif(!n) break;\nmemset(mat, 0, sizeof(mat));\nf21();\n}\nreturn 0;\n}\n\nvoid f21()\n{\ncout << "****************************************" << endl;\ncout << "*          INVERSE OF MATRIX           *" << endl;\ncout << "****************************************" << endl;\n\ncout << "ORDER OF THE MATRIX: " << n << endl;\ncout << "ENTER ELEMENT ROW-WISE" << endl;\nint m = 2*n;\nint i, j, k;\nrep(i, n) {\nrep(j, n) {\ncin >> mat[i][j];\ncout <<"&#92;t";\nprintf("%5.3lf", mat[i][j]);\n}\nrep2(j, n, m) {\nif(i == (j-n)){\nmat[i][j] = 1;\ncontinue;\n}\nmat[i][j] = 0;\n}\ncout << endl;\n}\n\ncout << endl << "INVERSE MATRIX: " << endl;\ndouble pivot, comm;\nrep(i, n) {\npivot = mat[i][i];\nif(mat[i][i] == 0){\ncout << "DIVISION BY ZERO." <<endl;\nreturn;\n}\nrep(j, m) mat[i][j] = mat[i][j]/pivot;\nrep(j, n) {\nif(i == j) continue;\ncomm = mat[j][i];\nrep2(k, i, m) {\nmat[j][k] = mat[j][k] - (comm*mat[i][k]);\n}\n}\n}\n\nrep(i, n) {\nrep2(j, n, m) {\ncout <<"&#92;t";\nprintf("%6.4lf", mat[i][j]);\n}\ncout << endl;\n}\ncout << endl;\n}\n\n/*This is writen in C++ this will output the inverse of a Matrix\ninput:\n4\n1 2 3 4\n2 1 4 2\n2 5 7 12\n1 -1 3 11\n\n5\n1.173 -0.634 0 0 0\n-0.539 1.173 -0.634 0 0\n0 -0.539 1.173 -0.634 0\n0 0 -0.539 1.173 -0.634\n0 0 0 -0.539 1.173\n\n0\n*/
156986
First, I am not sure why you call this factoring. This is not factoring. \n\nThink of it this way. If each of the teams play each other once, there are G1=[N^2-N]/2 games. To see that this is true, just compute either \n\nN choose 2 = N!/[(N-2)!2!]=[N^2-N]/2 \n\nor \n\nmake a matrix with the N teams as both rows and columns. Every element of the matrix constitutes a game between two teams, one in the corresponding row and one in the corresponding column. One has to disregard the N diagonal elements, because a team cannot play itself, so there are a total of N^2-N games in the matrix, without the diagonal. Since this includes games when A plays B as well as B plays A, we have to divide by 2, to get again [N^2-N]/2.\n\nIf each of the teams play each other 2 times, there are G2=N^2-N games. To see this, just imagine the matrix of team-labelled columns and rows again, and subtract the diagonals again, so that both the games between A and B and between B and A are included, for a total of 2 games between each pair of teams. The number of elements in the matrix is N^2-N, ignoring the diagonal elements again. \n\nFor the teams to play each other 3 times, they can just play the one game schedule, and then the 2 game schedule, for a total of 3 times between each pair of teams, so:\n\nG3=G1+G2=(3/2)*[N^2-N]\n\nFor N=7, this is just 1.5*[49-7]=1.5*42=63.\n\nThere are 63 total games played.
876460
First of All, without the actual file, trouble shooting will be tough...\n\nAnyways,\nI had faced some calculation issues previously. It got solved when I created a fresh Pivot table in a new worksheet "afresh"... Though the Source data was same, the 2 PT's showed different summaries...\nTry it...\n\n\nTip / Info: \nAlso have a look at the Custom calculation of "Running Total", this can be useful for U as well...
677295
Something to do with COSTING. Try this,