(A) what is the passenger's true weight     (b) what is the passenger's apparent weight?
820987
Actual weight is the downward force exterted by the body.\nAparent weight is the upward force exerted by the body.\n\nUsually the apparent weight is equal to the actual weight but in your description you said that body is in flight which is an exceptional case.\n\nYou can use Newtons second law for solving this problem.\n\nAn example of apparent weight calculation for vertically moving body (and a nice reference) can be found on this page\n\nhttp://www.answers.com/topic/apparent-weight
487670
None. It takes no power to maintain that speed (on level ground, no friction). The object has kinetic energy (0.5 * m * v^2). Power was required to put it in motion and power can be recovered by decelerating it. If you do the math, the energy is 3551.86 ft-lb, equivalent to 1 horsepower for 6.458 seconds. Answer 1 neglected the fact that weight must be converted to mass by dividing by g, and energy is proportional to v^2.
8725
a) eleven minutes.\nb) eight minutes.
596583
Mass. I think.Depending on how strong the gravity is your mass changes.
1124515
Since the plane flies by producing thrust and thereby offsetting its weight, the weight in flying state is zero. The mass remains the same as it was on the ground.
943484
I expect that you have the data on stretch as a result of tension. \na) The object is just at rest. Tension, T = W = m*g.\n\nb) T = W + m*a\n\nc) Tmax = W + m*a
302472
ANSWER A)\n\nUsing F=mg...and because 12 litres of water has a mass of 12kg.\n\nF = (12 * 9.81) = 117.72 N\n______________\n\nANSWER B)\n\nthe total weight of the full bucket is 127.72 N (you know why)
596616
Depend on where you want to measure the weight.\n\nWeight = mg\n\nWhere m is the mass of the plane and g is the accelleration of free fall.\n\nTo measue the weight of the scale you would park it on an aeroscale which would tell you its mass.\n\nThe mass of the plane wll be the same everywhere.\n\nTo find the weight of the plane you multiply the mass of the plane and the gravitational field strength from where you are measuring it.  On the srface of the earth tjis is 9.81.  The weight will be in Newtons.\n\nWhen the plane is in flight to measure its weight you need to find out the gravitational field stenth at the hight at which the plane is flying.  Unless the plane is flying exceptionly high (Like in space) then 9 will also be 9.81.
86433
Assuming no external force, the obivous choice is 56.5g because the bouyant force is equal to mass*gravity
816930
I go with C. \n\na) Chickens don't fly very well.\nb)Water is denser than air, and mercury is denser than water. It's true.\nd)But, if the cat is drunk it won't land on it's feet.
975855
Hi Vicky! \nLet a=32deg, p=patient’s weight, then f1=p*sin(a) is the force pulling him down along the sheet & f2=p*cos(a) is the force pressing him to the sheet, so when k is coefficient of friction, then \nat the moment to start slipping from the bed f1=k*f2, thus k=tg(a). the more k the more “adhesive” the patient feels.
75785
All right, we have four unknowns: the weight of Person A's luggage (we'll call x), the weight of person B's luggage (we'll call y), the cost per pound of luggage that the Bullet-Train charges (we'll call C), and the weight of luggage that the Bullet Train doesn't charge for (this is what you're looking for; we'll call it W).  Using these variables we can set up four equations:\n\nFirst the total weight of the two passengers' luggage is 100 pounds\n\nx + y = 100\n\nWe also know that the two passengers' luggage together (deducting the complimentary weight) costs $12 + $8\n\n(x + y - 2z) * C = 12 + 8\n\nand if we only deduct the complimentary weight once\n\n(x + y - z) * C = 30  <-- this is if only one person carries the weight on the train.\n\nWe can combine these equations to get\n\nz * C = 10\n\nNow, we have two independent equations and four unknowns.\n\nNext, we split up the two passengers.\n\nSo the weight passenger A is carrying (x) minus the complimentary weight (z) times the cost per pound is the charge for passenger A ($12)\n\n(x - z) * C = 12\n\nSimilarly for Passenger B\n\n(y - z) * C = 8.\n\nNow you have everything you need.  If you solve the last two equations for C and set them equal to each other after inserting your expression for z * C, you'll have an equation with x and y only.  You then combine that equation with the very first, and you can solve for x and y.  Knowing those you can solve for C and z.\n\nIf you have any questions, e-mail me at FroggyJ5@yahoo.com\n\nAnswers : \n\nx = 55 lb.\ny = 45 lb.\nC = $0.4/lb.\nz = 25 lb.
63054
People inside the plane are still being pulled down by gravity with a force of m*g=9.8*m.  The airplane is also holding the people within it with a force of m*v^2/r=22.22*m.  So you've got a horizontal force and a vertical force.\n\n      22.22*m\n---------------------->\n|\n|9.8*m\n|\nV\n\nPeople are most comfortable when they are accelerated into their seats (not the window or ceiling), so the bank angle will be perpendicular to the sum of those two vectors.  Your result should be about 65 degrees (though the 5 isn't a significant digit-- you should be able to get the final answer on your own).\n\nBut oh those poor people!  They'll be accelerated to almost 3 gs!
438003
a) km\nb) cm\nc) mm\nd) cm\n\n(height is in cm on my license)
541033
Total weight the vehical or product is built for according to the mfg. specs.
115489
B.\n\nAll of the rest are false.
461030
For the first problem, you need a law of motion. (final velocity)^2=(initial velocity)^2+2*acceleration*displacement. Substituting, you get 0=30^2+2*a*20m and a=22.5 m/s^2. Now, we need to write a force equation: ma=Tension force-weight. To find the mass of the elevator and its load, divide its weight by gravity (9.8 m/s^2) to get about 16.3 kg. And you already calculated the net acceleration. Our force equation can now be rewritten as (16.3 kg)*(22.5 m/s^2)=Tension force-160N. The tension force is about 207N.\n\nFor each of the weight scenarios in the second problem, you know the net acceleration to be 30 m/s^2. You can also find the mass of the passenger by dividing his/her weight by gravity. With the force equation ma=(force of feet up)-(weight) with respect to the passenger, you can find the force of his/her feet. Here is the work for the first scenario.\n\n16N/(9.8 m/s^2)=1.63 kg\n1.63 kg*30 m/s^2=(force of feet)-16N\nForce of feet=64.9N\n\nAnswers for the second and third scenario:\nb) 2600N\nc) 260N