how do you solve?     2(x-6) = 3x      please include steps.?
819891
2(x-6)=3x\n\n1.Distribute the 2 to the X and the 6. \n2x-12=3x\n\n2. Subtract the 2x from the left side and subtract it from 3x\n-12 = 1x\n\n3.flip the problem so it looks pretty!\nx = -12\n\nYour Welcome :D
492288
x=\n3x-3+2x=5x-6-x\n3x+2x-5x+x=-6+3\n1x=-3\nx=-3&#92;1\nx=-3
214212
Hi, here's how ya do the problem:\n\n-5x+y=6\n\ny=5x+6 (move -5x over by adding the opposite)\n\nSo then you substitute it into the problem\n3x-2y=3 so that it looks like\n\n3x-2(5x+6)=3\n\nNext distribute the -2\n3x-10x-12=3\n\nand solve\n-7x-12=3\n-7x=15\nx=2.14\n\nThen you substitute 2.14 into either equation to figure out y\n-5(2.14)+y=6\n-10.70+y=6\ny=16.7\n\nHope this helps!
840645
1,2,3\n1+2+3=6\n1x2x3=6
770101
3ax+4by-2ay-6bx\n=3ax-6bx-2ay+4by\n=3x(a-2b)-2y(a-2b)\n=(3x-2y)(a-2b)\n2ax-2by+ay-4bx\n=2ax-4bx+ay-2by\n=2x(a-2b)+y(a-2b)\n=(2x+y)(a-2b)\nso 3ax+4by-2ay-6bx over2ax-2by+ay-4bx\n=3ax+4by-2ay-6bx /2ax-2by+ay-4bx\n=(3x-2y)(a-2b)/(2x+y)(a-2b)\n= (3x-2y)/(2x+y)
968475
(2x sqrt(2x)) (3 sqrt(5x))\n= (2x*3) (sqrt(2x*5x))\n= (6x) (sqrt(10x^2))\n= (6x) sqrt(x^2) sqrt(10)\n= (6x)(x) sqrt(10)\n= (6x^2) sqrt(10)
140487
3(x-2)^2 - 3(x-2) - 6\n\n= 3[(x-2)^2 - (x-2) - 2]\n\n= 3[(x-2){(x-2) - 1} - 2]\n\n= 3[(x-2)(x-3) - 2]\n\n= 3[x^2 - 5x + 6 - 2]\n\n= 3[x^2 - 5x + 4]\n\n= 3(You should solve the next step as this is ur home work and dont make this a habit.)
781088
Plug in 2 for x to determine this:\n\n3(2) + 5 = 6+5 = 11 ≠ 17\n\nTherefore 2 is not a solution.\n\n~ ♥ ~
129694
-6 <= 2x-4 < 8 |:2\n-3 <= x-2 < 4   |+2\n-1 <= x < 6 \nso, x is between -1 (included) and 6 (not included)
905206
8x - 2 = 3x - 2\n8x = 3x\n5x = 0\nx = 0
191567
Please use parentheses to explain the problem more effectively. Assuming the problem as,\n\n(x-1)/2x + x/(x+3)\n\nThe solution can be,\n\n(3x^2+2x-3)/(2x^2+6)
820806
-2x^2+6x-3=0\n=->2(x^2-3x+3/2)=0\n=>2(x^2-2x.3/2+3^2/2^2)-3/4=0\n=2(x+3/2)^2-(sqrt3/2)^2=0\n=>-2(x+3/2+sqrt3/2)(x+3/2-sqrt3/2)=0\nTherefore,x=-3/2-sqrt3/2 or -3/2+sqrt3/2
222653
x+6(x^2)= 12\nx+6x^2  = 12\n6x^2+x-12=0\n(2x+3)*(3x-4)=0\n2x+3=0 3x-4=0\n2x=-3  3x=4\nx=-3/2 x=4/3
897641
8-3x=4x-12+6\n-7x=-14\nx=2
863984
4x-3+2x=15\n4x+2x-3=15\n4x+2x=15+3\n6x=18\nx=18:6\nx=3\n\n4*3-3+2*3=15\n12-3+6=15\n9+6=15\n15=15 ...so x=3
1086105
2*(3x+1) = 3*(x-2)\n6x + 2 = 3x - 6\n6x - 3x = -6 -2\n3x = -8\nx = -2.6667\n\nSolve:\n\n2*(3*[2.6667] +1) = 3*([2.6667] - 2)\n2*(7) = 3*(4.6667)\n-14 = -14\n\ntherefore x = -2.6667
1012196
3(x+12)=x+2\n3x+36 =x+2\n2x+36=2\n2x=34\nx= 17