what are the values of A,B,C,D,E, and F ?
829703
I did check the above answerers answers, and they are wrong :P\na,b,c,d,e,f = 1,2,5,5,4,6.\nYou could go and solve this by the usual elimination methods, but for something this large its far better to use a calculator or online solver. Google for 'simultaneous equation solver' and you'll find  heaps.\n(Just to confirm above answers are wrong: for those numbers you get 4a + b + 5d + 2e + 3f = 69, not 57.)
682720
I'm not sure if you mean from the set of {a,b,c,d,e} or all letters:\n\nIf only from the set {a,b,c,d,e}:\n\nIn the first case, you have 5 choices for the first letter, 4 choices for the second letter and 3 choices for the third.  The reason you have less choices is that you have already used a letter or two.\n\nStated as permutations this is:\nP(5,3) = 5 x 4 x 3 = 60 permutations.\n\nFor the second case, this is a simple permutation.  You have 5 choices for the first letter, 5 for the second and 5 for the third.  \n\n5^3 = 5 x 5 x 5 = 125 permutations.\n\nIf you mean for all letters of the alphabet:\n\nIn the first case, you have 26 choices for the first letter, 25 choices for the second letter and 24 choices for the third.\n\nStated as permutations this is:\nP(26,3) = 26 x 25 x 24 = 15,600 permutations.\n\nFor the second case, you have 26 choices for the first letter, 26 for the second and 26 for the third.  \n\n26^3 = 26 x 26 x 26 = 17,576 permutations.
303297
1. d\n2. a\n3. d\n4. b\n5. b
944583
a) [O 2-]\nb) [ I - ]\nc) [Na+]\nd) [Al 3+]\ne) [Ni 2+]\nf) [Mg 2+]
961485
1 V\n2 C\n3 vc\n4 vc\n5 c\n6 c\n7 v\n8 vc
160639
good 0, 3, 7, 4\n\n    bad 2, 9, 5\n\n    neutral 1, 8, 6
371319
The answer is d), i.e. "c"\n\n\na/b = b/c = c/d = d/e = x\n\na = x.b\nb = x.c\nc = x.d\nd = x.e\n\na = x.x.x.x.e = x^4.e\nb = x.x.x.e = x^3.e\nc = x.x.e = x^2.e\nd = x.e = x^1.e\ne = x^0.e\n\nabcde = (x^4.e).(x^3.e).(x^2.e).(x^1.e).(x^0.e)\n\nabcde = x^10.e^5\n\n(abcde)^(1/5) = (x^10.e^5)^(1/5)\n\n(abcde)^(1/5) = x^2.e\n\n(abcde)^(1/5) = c
898860
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
723554
b, c, d and e\n\nonly 17 can be....(8+9)
1184666
(1) C\n   B = D + 2\n   M = B + 4\n   M = ( D + 2 ) + 4\n   M = D + 6\n\n(2) E\n   B = 2H\n   M = B + 6\n   M = ( 2H ) + 6\n   M = 2H + 6\n\n(3) D\n   12 bulbs / x minutes\n   12 bulbs / ( x minutes ( 1 hours / 60 minutes ) )\n   12 (60) bulbs / x ( 1 hour )\n   ( 2 (12) (60) ) bulbs / x ( 2 hours )\n\n(4) D\n   Stop 1: x\n   Stop 2: x + y\n   Stop 3: ( x + y ) / 3\n   Stop 4: ( ( x + y ) / 3 ) + 2 = ( x + y + 6 ) / 3
462416
9. B\n10. B\n11. It's 0.3455\n12. C
397785
All of A, B, C, and D are animals, I'm pretty sure.  \n\nYou seem to be missing E though...
217542
1. c\n2. d\n3. e\n4. b\n5. a\nIts been a few years since I took biology but I thought I could take a shot at your question.  Hope the answers are right:)
760269
"d" is the answer.\n\nGet an "A".
1164142
F=O \n\nbut if E=MC2 then F=ND3\n\nthen F=ND3, \nsince ND is just [(M+1)(C+1)] \nthen \nF=({[(M+1)(C+1)]}3)\n\n\nOr you could say that\nF=E+1
692268
1. c\n2. c\n3. c\n4. c\n5. c
902899
#1  c:10\n#2  d:-57\n#3  b: 26\n#4  1:O\n#5 n/a \n#6  a:BMSK \n#7  d:9599\n#8  a:e\n#9  c:41\n\ni hope that this helps