What is the effect on an unbalanced force on and objecT?
819927
All objects react as if there were only a single force acting upon them. Let's say an object on your desk had a force of ten newtons pushing it to the east. Let's call that force positive 10 newtons. According to Newton's second law, it would accelerate (pick up speed) moving in an eastward direction. It had a single force acting upon it and since there was no opposing force we say that it was an unbalanced force. Now say the same object had another force of 10 newtons acting on it in a westward direction. Lets call that force negative 10 newtons. Now we have two forces and since they are equal but have opposite signs the algebraic sum is zero ([+10N] + [-10N] = 0). We now have balanced forces - equal but opposite. Remember I said that all objects react as if there were only one force acting upon them? Even though there are two forces acting in opposite directions on the object on your desk, that object reacts as if there were only one force acting upon it - a force of zero newtons. BTW, that sum force is called the resultant. So according to Newton's first law since a zero force is applied to the object it will remain at rest. In short, unbalanced forces result in movement, balanced forces don't.
359625
you have to balance it...
209689
mass in motion stays in motion unless disrupted by another force!
358800
The basic principle behind a Chinese steelyard balance is torque—or leverage, if you prefer.\n\nA symmetrical balance has the two weights equidistant from the point at which they are suspended (let’s call it the “fulcrum,” for simplicity’s sake):  when the weights are equal, the balance levels out.  But let’s say you’re trying to measure the weight of a two-pound object.  Then the balance will level out if you place a two pound weight equidistant from the fulcrum, or a one-pound weight half as far from the fulcrum, or a half-pound weight a quarter of the way from the fulcrum.\n\nThe steelyard balance puts the object to be wieghed at a specific distance from the fulcrum, then moves the known weight along the length of the opposite arm.  The ratio of the distances between the fulcrum gives the ratio of the two weights.\n\nThe link shows the best picture of one that I could find.\n\n\nRyan Wyatt\nRose Center for Earth & Space\nNew York, New York
912606
The simple answer is that the vector sum of the forces acting on an object must be zero if the object is to remain in "equilibrium" or in other words to have constant velocity.
261295
the force of gravity is one of the weakest (you can just see it's effects in a macroscale) that's because G is such a a small value... this Cavendish guy used a torsion balance to measure G ( a rod with two metal spheres at their ends).\n \nwhen you twisted the rod, then a torsional force is exert (..that force is proportional to the angle of rotation of the rod) ; He relate the angle of rotation and the quantity of torsional force ..then, he brought 2 lead spheres near the smaller ones (attached to the rod) ..because the force of gravity the larger spheres attract the smaller ones , twisting the rod ..then he measured how much..he knew F, and the masses of the metal spheres , then by Newton's formula F=Mm/d^2 ( he knew d ..the rod lenght) he determined G...the first experimental measure of G (maybe he didn't have a life :).\nI've found also this page that may help you, good luck
832148
You could just use the old force = (G*M*m)/r^2\nWhat is missing from the diagram is that the small weights were held by a long thin wire.  The wire formed a weak torsional spring.  If there were some gravitational force, it would cause the weights to twist the wire until the torque of the twisted wire matched the force of gravitation (times the radius).  He could measure the amount of twist by shining a light at a mirror attached to the weights and seeing how far the reflection moved.
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*is a center-directed force\n\n\nnot "*acts as an unbalanced force on the satellite" because, it is balanced by centrifugal force. \n\nnot "*changes the direction of the satellite" because direction is changed by only tangential forces and not the force acting towards center.
903133
From what I learned in physics class, the force you are speaking of is measured in Newtons.
813186
a counterbalancing force or system of forces.
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In one word: Balancing
552732
Interesting Question.. any way my answer is that u can balance anything on a needle, the only condition is that u should know the point at which the centre of gravity of that object is located... if u know the centre of gravity of earth then definately u can balance it on a needle... centre of gravity is nothing but a point where the weight of the object is concentrated.. For Example : A spinning top has its centre of gravity on the point which is touching the ground.. hope u have understood.
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A bicycle is a wonderful example of an object that's unstable at rest, but stable in motion. My other favorite example is a broom balancing upside-down on the palm of your hand. Let's take a moment to look at the broom because it will help to understand the bicycle. \n\nWith the broom exactly centered above your motionless hand, nothing pushes it to one side and it balances. It's in equilibrium-it experiences no overall forces. In principle, it can stay that way indefinitely, but in practice it never does. The slightest shift of the broom's center of gravity to one side and over it goes. Any disturbance that shifts the broom away from equilibrium gives rise to forces that push the broom still farther from equilibrium, so the equilibrium is unstable. Any object that has no base of support-the polygon formed by its contact points with the ground-has an unstable equilibrium and tips over when disturbed. That instability stems from the fact that its center of gravity always descends when it's tipped and it releases gravitational potential energy as a result. Potential energy-energy stored in forces-is so intimately related to the forces themselves that whenever an object can release potential energy by heading in a certain direction, it naturally accelerates in that direction. \n\nSo the broom is unstable in your motionless hand. But if you move your hand, you can stabilize the broom. You do this by endlessly moving your hand under the broom's center of gravity. If the broom starts to tip to the left, you move its handle to the left to place that handle under the broom's shifted center of gravity. In that manner, you keep returning the broom to its equilibrium. Even though the equilibrium is naturally unstable, you keep helping it out and make it dynamically stable-stable in motion. \n\nNow let's shift to the bicycle. Like the broom, an upright but motionless bicycle is in an unstable equilibrium. If you're really skilled, you can balance it by shifting your weight around to keep the overall center of gravity above the wheels. However, there's a much easier way to balance the bicycle: drive forward! Once the bicycle is in forward motion, it steers automatically and places its wheels under the overall center of gravity. Unlike the broom example, where you have to think in order to push the handle under the center of gravity, the bicycle does this for you automatically. If the bicycle starts to fall over to the left, the front wheel steers left and the bicycle drives its wheels under the overall center of gravity. The bicycle returns to upright all by itself, even when you have no hands on the handlebars. \n\nThe automatic steering occurs for two reasons. First, there is gyroscopic precession that occurs when the spinning front wheel experiences torques from the ground. When the bicycle tips to the left, forces from the ground twist the spinning wheel so that its angular momentum shifts from leftward to rearward. This complicated precession effect causes the wheel to steer left toward the left. \n\nBut the more important source of automatic steering is that the tipped bicycle naturally flexes about its steering axis and turns its front wheel in the same direction as the tip. If you tip the bicycle left, the wheel pivots so as to steer the bicycle left. The fork and frame design are important to this effect. The tipped bicycle can reduce its gravitational potential energy by flexing and, as I mentioned above, this capacity to lower potential energy leads to forces that cause the tipped bicycle to flex. When you tip the bicycle to the left, it steers left and thus manages to reduce its gravitational potential energy-the bicycle's center of gravity descends slightly. Together with gyroscopic precession, this automatic steering makes the bicycle's wheels drive under the overall center of gravity so that the bicycle keeps returning to upright. So the forward-moving bicycle is like a broom w
693390
Gravity, centrifugal forces and centripetal forces
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Well, yes, the gavity is pulling you down, and you are not moving. So you are subjected to an acceleration and are not moving.\nMind you, one can argue that the *resulting* force is zero, as the ground is reacting with an equal and opposite force to your weight; if you take it that way, to have an unbalanced force should result in motion.
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The net force is 0 Newtons. The force of friction is 100N.\n\nThe key here is that\n1. No acceleration.\n2. Horizontal force only.\n\nThis means that the forces are balanced in the horizontal direction. The object isn't accelerating so net F = ma = 0.
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The force of gravity of one object on another is given by the equation\nF = (GMm)/r^2\n\nWhere G is the universal gravitational constant, M is the mass of one object, m is the mass of the other, and r is the distance between the two.\n\nYou can see that the greater the mass of the two objects, the stronger the force of one on the other is.\n\nIn short, things that are more massive get a better tug.