Another equation, please?
824963
Given:  BX/D = CE/F\n\nFind:  "X"\n\nSolution:\nBX/D = CE/F\n(B/D)(X) = CE/F\n(D/B)(B/D)(X) = (D/B)(CE/F)\n(1)(X) = CDE/BF\n\nAnswer:\nX = CDE over BF  or  X = CDE/BF
429488
If you have two unknowns (i.e. x, y) then you must have two equations to solve for x and y. You only have one equation, unless I missed something.
539943
x+y........e=mc2..........2+2
1084156
The answer to that is a line.  If you want a unique solution to a two-variable problem, you need two equations.
247965
infinite values for both,\nits caus u cant solve two variables with just one equation
154380
I posted these sources earlier to someone else who was looking for math help.\n\nGood Luck!!
197333
i think \nx = 2664.173
1145097
kinda of hard to answer not beaing able to see the whole equation
561262
u jammed the equation together.\ndo u mean\n6x^3 + ( 6/x - 2 * x^2 - x/3x2 - 3x + 3)\nits really hard to see ur question. can u write it out with spaces...\nhurry up i am waiting... lol
281150
Next time just type your math equation into Google and it will do the math for you.\n\n15
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
629091
Sorry, but the formulas do not present well here.  Cannot discern operations.
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
165476
How about (a+c)/(b+d)  ? more interesting!!\n\nbtw this only work when a/b != c/d
838286
well Honestly dear Megan i don't think its correct , coz equation should have ONE " = " \n\nit must be something like this \n-4r ² ± 21r=r+13\n\nGood Luck
106013
y = -2x + 8\n\nsolve it yourself