How can I use KCl + Iodine to get KI?
829643
Not without a reducing agent that will turn iodine into iodide, and then you will have to get rid of that reducing agent.\n\nI guess if KI is unavailable you'd better look for another titrable reducing agent to react with the bleach, e.g. Fe2SO4 solution.
442899
Manganese and manganese dioxide. Also potassium iodide does a good job.
764442
2KClO3(s) --> 2KCl(s) + 3O2(g)\n\nmole of KClO3 = 0.263 / 122.6 = 2.145 mmole\nmole of O2 = 2.145 * 3 / 2 = 3.217 mmole\nvolume of O2 over water:\nP * V = n * R * T\n0.948 atm * V = 3.217 * 10^-3 * 0.082 * 294\nV = 0.081 litre\n\npeace\nvixklen
82368
U get precipitate of Lead Iodide. The reaction is already mentioned!!!!\n\nPb(NO3)2 (aq) + 2KI (aq) --> 2KNO3 (aq) + PbI2 (s)
1185900
H2SO4 + 2KOH --> K2SO4 + 2H2O
117753
Okay you have a choice between Potassium oxalate (K2C2O4 ) and Sodium Iodide (NaI). \n\nPotassium oxalate is highly soluble (30g/100g) and sodium iodide is even more soluble(184 g/100 ml).\n\nWithout knowing the reactants it is almost impossible to predict a product, especially with two choices. Given those two products, I would expect it to be K2C2O4, but that is just a guess. What was in the solution?
505651
Hi and be blessed, I teach HapKiDo a corean martial art of self defense in the country of Panama and have been teaching this art for 29 years. The study of Chi or Ki as is called in Korean (Corean) is very interesting because it is a development that helps you besides increase the inner energy or life force, very important to learn it from a qualified teacher. \n\nThe best way to lear and increase your Ki is by breading and the best way is by inhaling slow and deep with out hearing the breath in your nose and exhale the same way out the mouth. It can be done in 4 basic ways: standing, seated, laying down or walking. \n\nYou must be patient ! To learn to increase the inner energy is a development thing so no rush. With time you will feel the Ki flow in your body, it is not a magic thing since all persons have Ki it is not an aout of this wold thing it is just some thing a person doing this activity dailly and with patience.\n\nAt first one must balance the breath. This means that the inhale and exhale must take the same length in time for example start wit 3 or 4 seconds inhale and balance the same exhaling and once this happens continue incresing the time span but make sure it feals confortable as you do this training since it really is not dangerous to do but it is a sencible thing to work with and it is true that doing it wrong can hert you like drinking water incorrectly.\n\nThis can be learned in HapKiDo, AiKiDo, TaiChi, Ki Gong or Chi Kung/Gong etc. Were ever you find the place and how to know if you found it is by doing this activity in a relaxful way ! Good luck.
650634
http://www.iogkf.com/
639819
depends on the concentration of Fe2+, if your KMnO4 is more concentrate then you use less to get to equilibrium, but you want a concentration so you can find the right amount easily, otherwise if you let a drop through the burette and turns out it's way too much you don't get accurate results
867182
6HCl +3 I2 + KClO3 --->6 ICl+ KCl + 3H2O\n\n\nMnO4 - +2 NO2- +4 H+ ---> Mn2+2 NO3- +2 H2O
924875
50,000V\n\nOtherwise, if you use Kilo, you just use the K - eg: 50 KV
433948
According to the MSDS for KCl,\nits solubility at 0 degrees C is 28.1 g/100 g of water
890618
You could work out that in I2O7, the iodine is in a +7 oxidation state, so it can't go any higher.\nSimilarly, in Cl- it is -1, and it can't go any lower.
407297
I2O5 + 5CO --> 5CO2 + I2
1054522
Can't see what the matches might be for, but you could quite easily make nitrogen iodide with the iodine, which is a very unstable explosive.
414222
For each, you have to calculate the number of moles needed from the volume and the final molarity:\n\nFor potassium iodine:\nV= 400ml= 0.4L\nM= 0.2M= 0.2 moles/L\n\n#moles KI required = 0.4L * 0.2moles/L= 0.08moles KI\n\nYou can then calculate the mass of KI needed by using the #moles calculated above and the molecular weight of KI\n\nMW of KI= 166 g/mole\n\n# grams KI required = 0.08 moles KI required * 166g/mole\n# grams KI required = 13.28g KI required\n\nYou calculate the answer for FeCl3 in the same manner.  I think you can handle it from here.
1100942
Heat it.   Iodine sublimates (goes from solid to gas) at 100 and something celsius.  If you cool the iodine vapour you can collect the solid iodine crystals.