how to reduce the given expressions into its simplest form?
818222
1.) (x^2y)/(xy) = ((x)(x)(y))/(x)(y) = (x/x)(y/y)(x) = (1)(1)(x) = x\n\n2.) (3(x-2)^2)/(6(x-2)^4) = ((3)(x-2)(x-2))/((3)(2)(x-2)(x-2)(x-2)^2)\n    *Now what can be "1" \n\n3.) There may be a type-o in the denom having the "+" sign, but if such the case, the expression is at it's simplest form.\n\n4.) Now for this think about factoring out a number and I think you'll see something that can be in its simplest form.
771358
3x + 4 < x + 8\n2x < 4\nx < 2\n\n{x | x < 2}
557964
Wouldn't it be something like:\n\n2x(8) + 8s     to get rid of the denominator\n\n16x + 8s\n\nThat is as far as I think you could simplify it, because each has different variables and you can't combine something with different variables.
907364
Almost.  You would actually include the endpoints 0 and -3 (so you need to use a bracket instead of parentheses).\nD = [0, infinity)\nR = [-3, infinity)
597439
=[(4+3x)/x] + (2/3)[(5+3x)/x]\n=[(4+3x)/x] + [(10+6x)/3x]\n=[(12+9x+10x+6x)/3x]\n=[(15x+22)/3x]
944361
Assuming you have declared all the variables in your equation, you can put this code in a procedure or function:\n\nelongation := P * L / A * E;
978426
for example:\n\n-1 < 2\nthen\n1 > -2\n\nanother:\n x < -5\nthen\n-x > 5\n\n-2 x > 9\nx< -9/2\n\ns
81883
Details of the algorithm for conversion along with\nsource program written in C can be found at.\nhttp://www.codepedia.com/1/Art_Expressions_p1\n\nA good short article on this topic.\nhttp://www.cs.man.ac.uk/~pjj/cs2121/fix.html
18182
2x^2 + 5x + 20x + 50\n2x^2 + 25x + 50
52040
number = ereg_replace ("^[0]+","",number);\n\nyahoo deletes my dollar signs\n\n^=start at beginning\n[0]+ delete all 0s
868097
-\naside from 1,\n2,3,4,6,12
1053464
if you want to simplify it \n\nit is 3x - 4x + 4 = -x + 4
614783
Multiply each by 4, then try to reduce.
618071
simplify to f(x)=(sqrt(x-2)(x-3))/(x-4)(x+5)\nthen sub in 1/x\nto get (sqrt(1/x -2)(1/x -3))/(1/x -4)(1/x +5)
1068964
simplify expression: -2(y+3)+6(y+1)\n\nsimply distribute then add.
902613
I just plugged this into my calculator.\n\n[1, 0, 2, 0, 2, 0 | 0\n0, 1, -3, 0, -2, 0 | 0\n0, 0, 0, 1, -1, 0 | 0\n0, 0, 0, 0, 0, 1 | 0\n0, 0, 0, 0, 0, 0 | 1 ]\n\nTake it however you want.
798195
Don't be scared by all the words.  You just have to remove brackets and parentheses from\n2[x+(x+10)+(x+2(10))] \n\nand then collect the terms -- you should get 6x+60.\n\nThe last part just means do it again with 15 replacing 10.