Displacement gyroscope....help?
831067
Any kind of spinning top is a gyroscope.  So building one is straight forward.  Not really sure what you mean about "displacement"?  Gyroscopes are to stop displacement but their size depends are what you can steady with the rotation of the gyroscope.
911903
Well, you could build a *relatively* simple circuit that simply cut the frequency in half, but then again, what kind of sensor are you dealing with?\n\nWhy do you want to tune it to a lower frequency? It is not simple to just shift a frequency, there are many things to take into account; input impedance, output impedance (both may be frequency dependent), signal amplitude, and required voltage swing.\nI would only attempt this if it was not a vital sensor I was messing with.
615645
search \nMechatronics on google and you will get a lot of resources \nfew links\nwww.PMDcorp.com      High-precision single or multi-axis Includes user-friendly software\nStepper motor control?\nwww.teknic.com      Discussion of motion & I/O control: low-cost, reliable, easy expansion
769928
T = 2pisqrt(l/g)\nl = g(T/(2pi))^2 = 9.80(1.0/(2pi))^2 = 0.25 m\n\n(The object's weight is irrelevant for small oscillations.)
423028
This may help:\n\nhttp://www.rdpslides.com/pptfaq/FAQ00143.htm
119218
For distance, just add the magnitudes of all distances the object travelled.\n\nfor displacement, us the formula\n\nd = sqrt ( d1^2+d2^2+2*d1*d2*cos(angle between d1 and d2) )
926220
Use a floating point, or gimbaled hydralic plates to adjust as needed. this is also a known Earthquake Resistant design.
906380
First problem: You have assumed all the mass of the meter stick is concentrated at the lower end; obviously, it is uniformly distributed along the length of the stick.  Assume that the mass is concentrated at the center; then, the length of the oscillator will be 0.865 meters, and the period should correspond.  There are some complications involving moment of inertia which I am ignoring.\nSecond problem: You may be solving for the wrong thing.  It looks like you are solving for the frequency of oscillation, rather than the maximum speed of motion.  Some careful work with units will help show you what is going on.
779107
my answer is not pricice but may help you>\nyou need 1- mic   2- miliampir-meter  ( or AVO-meter)\nput on mA position . connect microphone tow wire to the AVO-miter \ntalk now you'll see AVO-miter pointer moves or digilat nunber increes
373075
Acceleration= 10 rad/s2\n\nAngular vel w= 10 x t rad/s\n\nAngular displacement d= 10 x t^2 / 2  :(t squared)\n\nThey say that angular displacement is 150 rad in 5 seconds, this means in an interval between t and (t+5).\nd= 10 t^2 /2 \nd2-d1= 10/2 (t+5)^2 - 10/2 t^2 =150 rad\nt^2 + 10t + 25 - t^2 = 30\nt= 0.5 sec\n\nSo the wheel totates for 0.5 seconds before they start to count.  \n\nHope its clear enough.
1179150
if you can picture a gyro spinning, picture it spinning out of control. or take a quarter and drop it on a table and watch it before it stops moving. it's all about speed. the rate of inertial is so grate the human eye can not see and regulate it at the same time.
466855
usually a wheel, mounted so that it can spin about an axis in any direction. When spinning, the gyroscope has special properties. Many spinning objects exhibit some of these properties; the rotation of the earth about its axis gives it the properties of a huge gyroscope. Once a gyroscope starts to spin, it will resist changes in the orientation of its spin axis. For example, a spinning top resists toppling over, thus keeping its spin axis vertical. If a torque, or twisting force, is applied to the spin axis, the axis will not turn in the direction of the torque, but will instead move in a direction perpendicular to it. This motion is called precession. The wobbling motion of a spinning top is a simple example of precession. The torque that causes the wobbling is the weight of the top acting about its tapering point. The modern gyroscope was developed in the first half of the 19th cent. by the French physicist Jean B. L. Foucault, and its first notable use was in a visual demonstration of the earth's rotation. In the second half of the 19th cent., with the invention of the electrically driven rotor, its uses multiplied. It became possible to rotate the gyroscope's wheel at desired speeds without interfering with the precession. Large gyroscopes are used in ship stabilizers to counteract rolling. The gyroscope is the nucleus of most automatic steering systems, such as those used in airplanes, missiles, and torpedoes. It is also used in the gyrocompass, a directional instrument used on ships. Unaffected by magnetic variations, its spinning axis, when brought in line with the north-south axis of the earth, provides an accurate line of reference for navigation.\n\nAlso look at...\n\nhttp://en.wikipedia.org/wiki/Gyroscope
779861
Ok, here's how i think you do it\n\ncar displacement = 66*t where t is the time in seconds\n\nbaloon displacement = 15*t + 200\n\nso according pitagoras\n\nc^2 = 4356*t^2 + (15*t+200)^2\n\noperating you get\n\nc^2 = 4581*t^2 + 6000*t + 40000\n\nnow, deriving dc/dt you get\n\nVc = 3*(1527*t+1000)/(4581*t^2+6000*t+40000)^(1/2)\n\nso now you just subtitute t\n\nVc = 33.7 ft/s\n\nI hope this helps.
901648
put x=2 directly into the given equation to get value of x at t=2...the answer u get is the displacement\n\ndifferentiate the equation wrt time to get velocity equation and then differentiate the velocity equation to get acceleration equation\n\nin both cases put t=2 to get velocity and acceleration\n\nconvert the given equation in terms of sin\ncomparing the new equation with x=asin(wt+@)\nwhere a=amplitude\n          w=angular frequency\n          @=phase\n\nalso use equations w=2 x pi x f and T=1/f\nhere x denotes multiplication \nf=frequency \nT=period
437059
This web page provides some descriptions and drawings of both horizontal and vertical mechanical accelerometers.\nhttp://solomon.physics.sc.edu/~tedeschi/midway/tm/4Measurements.html\n\n"[A] ... protractor, string and weight ... can be used to measure the horizontal component of acceleration (horizontal accelerometer).\n...\nThe simplest vertical accelerometer is a spring scale. You can tape a weight to the hook and, holding the scale vertical, read off the weight under various conditions. The number of 'gs' you experience in a given situation is the scale reading in that situation divided by the scale reading when you are not moving."\n\nA mechanical accelerometer is just an accelerometer that does not use electronic components, such as a Micro-Electro-Mechanical System or MEMS.
924362
The answer to this depends on the specific equatorial mount you havve.  Different manufacturers will have different ways to do this.  The rings should be able to move on their stem, but not freely -- they should (if you don't touch them) follow the scope's motion.\n\nIn general, you want the RA and Decl rings to be adjustable so that you can calibrate then (or align, which might be a better word.).\n\nAfter aligning your polar axis closely, select a recognized star near the equator (+/- 30 degrees is fine), point the scope to it, and then adjust the RA ring to agree with the known right ascension of that star.  Similarly set the declination ring, and \nyou are all set.  \n\nIf the rings are too loose, then you need to check the scope directions (don't you hate that?) and see if there isn't a collet\nring or nut or setscrew or something to tighten it a bit.  It still should be moveable when you need to re-adjust the rings (each time you set up the scope you need to set the rings.
280904
Do a search for 'barometers'\n\nAll I got was 'potassium tetraiodomercurate(II)' but I have never heard of and have no idea if thats what you are looking for ;O)