help me solve this cryptogram?
825205
It says:\n\nSCHOOL WILL BE CLOSED TODAY DUE TO SNOW, OR, UP, IF IT'S NOT SNOWING... PONSTERS! NOW HOW DO I TURN THIS OFF, SIS
752305
Find the error. It's impossible!\nCapital "F" and capital "I" and a "." or an"!".\nThe alphabet is just "a red herring"
512346
use the code\n\nfdsk/sjl000?434kl;.ffff\n;a;;ilekshj8888889423ds\ndsk223333.425fjlwkeds34\n;;;lkdkfjlkkkdsla992340\n\nyou have three seconds to do this.  If you do your computer will start printing money if you don't it will blow up
786886
Why didn't you just ask me?  You could have emailed and saved 5 points.\nMy solution did indeed contain a typographical error omitting the q from the value of m.\nAlso, I had amended the solution with a comment shortly after the question had been resolved.  (There was another small error as well.  It is very difficult sometimes typing and then proof-reading mathematical proofs in these Yahoo boxes, especially when they contain alot of special characters.)\n\nSee:\n\nhttp://answers.yahoo.com/question/index;_ylt=ApZ1XohHNUdL5xkBg8bXQEfsy6IX?qid=20061124162535AAURdJ5
120457
1) 4\n2) 15241578750190521
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
1157976
0000, 0001, 0002, 0003, 0004, 0005, 0006, 0007, 0008, 0009, 0010, 0011... etc, etc  untill u get to 9998, 9999\n\ntry it out, might take a long time but one combination will work :))
966925
There are 3 solutions for ABCDEFGHJ -\n\n2 6 7 8 3 5 1 4 9\n2 6 7 9 5 3 1 4 8\n6 7 8 4 1 3 2 5 9
1186498
In a hexagram shape, like so...\n\n----o----\no-o-o-o\n--o---o-\no-o-o-o\n----o----
500368
The links below have good info. The first briefly addresses your first question, and the second is a good brief history of the problem which provides some insight as to the difficulties encountered. I actually played around with this problem a little on an elementary level and it is interesting. Cheers.\n\nhttp://www.sciam.com/print_version.cfm?articleID=000DBA55-B698-1C71-9EB7809EC588F2D7\n\nhttp://www.geocities.com/fermatnow/flt/
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
675348
I agree with chapin4ever's answer.\nand the three digit number is the ASCII equivalent of the symbol.
912374
Okay, first you just have to pull out the letters for each slot:\n\n1. A, U, I\n2. O, N, D\n3. C, I, Y\n4. M\n5. A\n6. F, L, E, A\n7.\n8. A\n\nJust looking at these and rearranging a bit, I came up with "animalia," which fits the clue, as it is the name of one of the biological kingdoms.
280945
Go to Artimes Fowl's website and it'll decode it...try not to tell anyone.
923039
email me, calcu_lust@yahoo.com, i'll write out a nice solution.\n\nEdit: Go to my website, and aforementioned nice solution is typed out as a .pdf for you to download, with all the correct symbols and such:\nhttp://geocities.com/calcu_lust/yahooans.pdf
379690
See this webisite:\n\n"This is an essay I wrote for a mathematics essay prize. We had a number of possible topics to choose from and I choose cryptology, because I already had a passing interest in thanks to my attempts to code encryption algorithms for my computer programs. It won, by the way ;-). This is the original essay with a few corrected spelling mistakes (though there are probably some left)."\n\nLoads of info
772876
In order to decode the message, we interpret each pair of encoded numbers as a vector. There are 10 vectors:\n\n<8, 21>, <- 15, - 10>, <- 13, - 13>, <5, 10>, <5, 25>, <5, 19>, <- 1, 6>, <20, 40>, <- 18, - 18>, <1, 16>\n\nSince _RON corresponds to the vectors <0, 18>, <15, 14>, we know that:\n\nM<0, 18> = <-18, -18>\nM<15, 14> = <1, 16>\n\nWe know that for any 2×2 matrix M, the first column of M is M<1, 0> and the second is M<0, 1>. Thus, we need to find M<1, 0>. Fortunately, M is a linear transformation, so if there are constants a and b such that a<0, 18> + b<15, 14> = <1, 0>, then:\n\nM<1, 0> = M(a<0, 18> + b<15, 14>) = aM<0, 18> + bM<15, 14> = a<-18, -18> + b<1, 16>\n\nTo find a and b, we equate x and y components of the vectors, giving the system of equations:\n\n15b=1\n18a+14b=0\n\nWhich has the solution:\n\na = -7/135, b = 1/15\n\nSo M<1, 0> = -7/135<-18, -18> + 1/15<1, 16> = <1, 2>\n\nNow to find M<0, 1>. First we solve:\n\n15b=0\n18a+14b=1\n\nThe solution is:\n\na=1/18, d=0\n\nSo <0, 1> = 1/18<0, 18>, and:\n\nM<0, 1> = 1/18<-18, -18> = <-1, -1>\n\nThus M is the matrix:\n\n[1, -1]\n[2, -1]\n\nTo decode the message, we multiply every vector by M^-1, which is:\n\n[-1, 1]\n[-2, 1]\n\nThe decoded vectors are:\n\n<13, 5>, <5, 20>, <0, 13>, <5, 0>, <20, 15>, <14, 9>, <7, 8>, <20, 0>, <0, 18>, <15, 14>\n\nWhich spells out the message:\n\nMEET_ME_TONIGHT__RON