I need to know what the set of numbers are called in a matrix. The word starts with the letter A.?
818446
It is called an ARRAY
756126
you need to do the following:\nT( (1,-1))= (0, 2) = -6 (1,-1) - 2 (-3,2)  so the first column of your matrix is:\n-6\n-2\n\nnow\nT ( (-3,2) ) = ( -1, -5) = 17 (1,-1) + 6 (-3,2), so the second column of your matrix is:\n17\n6\n\nwhen you put them together you get:\n-6 17\n-2 6\n'
954003
it is from a logic work sheet.  directions are find the next item in the pattern.  examples:  12321, 23432, 34543, 45654\na, z, b, y, c, x, d\ntam, tan, rib, rid, rat, raw, hip
772876
In order to decode the message, we interpret each pair of encoded numbers as a vector. There are 10 vectors:\n\n<8, 21>, <- 15, - 10>, <- 13, - 13>, <5, 10>, <5, 25>, <5, 19>, <- 1, 6>, <20, 40>, <- 18, - 18>, <1, 16>\n\nSince _RON corresponds to the vectors <0, 18>, <15, 14>, we know that:\n\nM<0, 18> = <-18, -18>\nM<15, 14> = <1, 16>\n\nWe know that for any 2×2 matrix M, the first column of M is M<1, 0> and the second is M<0, 1>. Thus, we need to find M<1, 0>. Fortunately, M is a linear transformation, so if there are constants a and b such that a<0, 18> + b<15, 14> = <1, 0>, then:\n\nM<1, 0> = M(a<0, 18> + b<15, 14>) = aM<0, 18> + bM<15, 14> = a<-18, -18> + b<1, 16>\n\nTo find a and b, we equate x and y components of the vectors, giving the system of equations:\n\n15b=1\n18a+14b=0\n\nWhich has the solution:\n\na = -7/135, b = 1/15\n\nSo M<1, 0> = -7/135<-18, -18> + 1/15<1, 16> = <1, 2>\n\nNow to find M<0, 1>. First we solve:\n\n15b=0\n18a+14b=1\n\nThe solution is:\n\na=1/18, d=0\n\nSo <0, 1> = 1/18<0, 18>, and:\n\nM<0, 1> = 1/18<-18, -18> = <-1, -1>\n\nThus M is the matrix:\n\n[1, -1]\n[2, -1]\n\nTo decode the message, we multiply every vector by M^-1, which is:\n\n[-1, 1]\n[-2, 1]\n\nThe decoded vectors are:\n\n<13, 5>, <5, 20>, <0, 13>, <5, 0>, <20, 15>, <14, 9>, <7, 8>, <20, 0>, <0, 18>, <15, 14>\n\nWhich spells out the message:\n\nMEET_ME_TONIGHT__RON
599681
It depends on exactly what you mean by a matrix. If you're talking about multi-dimensional or nested arrays in ActionScript, then here is a link to get you started...
554827
Well, I suppose you want a program that computes the trace of a matrix. The trace is simply the sum of the elements in the diagonol in a matrix. I won't show it to you with OOP since there's no reason to.\n\nint trace(int matrix[][],int numrows,int numcols) {\n\nint tracetotal = 0;\n\nif (numcols != numrows) {\nstd::cout<<"Error: Can't compute trace. Not square matrix.&#92;n";\nexit(1);\n}\n\nfor (int i = 0; i < numrows; i++) {\ntracetotal+=matrix[i][i];\n}\n\nreturn tracetotal;\n}
744408
Say a[i,j] are the elements of A. The definition of the determinant is:\n\ndetA = Sum over P: (-1)^P * a[1,P(1)] * a[2,P(2)]*...* a[n,P(n)]\n\nwhere the sum is over all permutations P of (1,2,...,n) and (-1)^P is -1,+1 for odd and even permutations respectively. (P(i) is the image of i under P).\n\nNow let's say (for example) that matrix B is created multiplying the second row by a constant c and adding it to the first row:\n\na[1,i] --> a[1,i]+c*a[2,i]\n\nThen the determinant of this new matrix will be:\n\ndetB = Sum over P:\n(-1)^P * (a[1,P(1)]+c*a[2,P(1)]) * a[2,P(2)]*...* a[n,P(n)]\n\n= det A +\nc * Sum over P: (-1)^P * a[2,P(1)] * a[2,P(2)]*...* a[n,P(n)]\n\nbut the last sum is zero, because for each permutation P there is exactly one other permutation differing only by a transposition T of (1,2)\n\nP' = PT , P = P'T\n\nand P and P' have opposite parity so the two terms generated by each of these n!/2 pairs cancel each other --> detB = detA
469735
The system of equations:\n[a11 a12 a13; a21 a22 a23]\n[1 -3 4; 2 3 1]\n\nPerforming indicated row operation:\n[a11 a12 a13; a21' a22' a23']\n[1 -3 4; -1 -6 3]\n\na21' = a11 - a21 = 1 - 2 = -1\na22' = a12 - a22 = -3 - 3 = -6\na23' = a13 - a23 = 4 - 1 = 3
554067
The identity matrix is a matrix that when multiplied to another matrix results in that same matrix. It is similar to the number 1 because 1 multiplied by any number gives the same number.\n\nThe identity matrix can be identified by the presence of 1s diagonally across it like a back slash. The rest of the numbers are 0.\n\ne.g.\n10\n01\n\n100\n010\n001\n\n...
438919
I dont know how to put this up here. I tried to put it in a nice format, but it would accept.\nBut you put the following in one matrix \n-2  6\n+2  2\n\nThen you put a * (multiply)\n\nThen you put the following in one more matrix\n\nx\ny\n\n\nThen put an ' = ' symbol\n\nThen put the following in a matrix\n\n40\n8
973911
It might be a little to high of a level but thesymbol for integers Z (in set theoy) comes from the german word for number.  Also, in cardinality of sets uses some hebrew letters.  Algebra is an Arabic word.  Our number system is called the Hindu-Arabic.  \n\nWikipedia has some good stuff on math history....\n\nOf course, lots of things are named for the developer.  Cartesian coordinate for Descarte.  Gaussian, or normal, distibution: the so-called bell curve.  Pythagoras...Fibonacci numbers...
537104
Nine (9) - before 10 and after 11\nOne (1) - before 2 and after 0\nOne (1) - before 2 and after 0
545976
R= red Y= yellow B= black;\n\n     R\n    Y Y\n   R B R\n  Y R Y Y \n R Y R Y R\n\n or if they are numbered\nput the ones <8 (1 to 7) instead of the reds (R) and the ones bigger then 8 in the yellow's place. The * will replace the Black (B).\n\nexample:\n\n          (1)\n       (9) (10)\n      (2) (8) (3)\n   (11) (4) (12) (13) \n  (5) (14) (6) (15) (7)
67428
It starts with an "A". I think you need to be a bit more specific.
590873
You have a 3*2 matrix, into which each cell can have either a 0 or a 1.  You have two choices - 0 or 1 - and you have six different places to put your choices (2*3 = 6).  To find the total number of matrices, you multiply each cell by every other cell.  In this case,\n\n2*2*2*2*2*2 = 64, which can also be written as 2^6 (2 to the 6th power) = 64\n\nFollowing this logic, to find the number of n*m matrices that have an entry of 0 or 1, you would again multiply every cell by every other cell.  In this case, using exponential notation only, since we don't know what n*m equals,\n\n2^(n*m) or 2 raised to power of n*m
619440
7 will be after five\nand eight will be after six.\n\nReason: The upper numbers in 'numerals' contains straight lines, the lower one contains curves.\nWell...
618738
I can't give you a definiton because I really didn't understand anything I read about matrices!!!  But here are a few links that may be helpful to you.