A 12-kg hammer strikes a nail at a velocity of 8.5m/s?
820117
The impulse is the change in momentum.  The hammer initially has a linear momentum of 12kg * 8.5 m/s = 102 N*sec.  Its final speed is 0 m/s, so its final momentum is 0 N*sec.  The change in momentum = impulse = 102 N*s.\n\nThe average force accompanying a change in momentum is given by the impulse divided by the time over which the impulse is delivered.  In this case, F  = 102 N*sec/0.008 sec = 12750 N.
567093
9 mm Luger Parabellum\n\n* 7.5 g (115 gr) Full Metal Jacket: 1280 ft/s (390 m/s) \n* 8.0 g (124 gr) Full Metal Jacket: 1180 ft/s (360 m/s)
946178
During a smash with a hammer two end of a metal show a potential difference. That is piezo electricity.\nDuring the smash electrons are displaced.\n\nTh
8312
Muzzle velocity: 2,800 feet (853 meters) per second
825317
with hammer and chisel
1155452
Only impulse (force x duration, or the quantity of momentum transferred to the pin) is calculable from the data, not force by itself, which is variable in time and not directly meaningful.\n\nIf the moving object has mass M and velocity V, and the object being struck has mass m, then assuming the collision is elastic and all motion is in the forward direction (all these assumptions are at least approximately true for the bowling ball and pin) then the impulse is:\n\nImpulse = 2*M*m*V/(M+m)\n\nEach pound value must be divided by g to get proper units of mass, so this is:\n\n=(g/g^2)*[2*16*3.5/19.5]*V = 5.74*(V/g)\n\nSince:\n\nV/g = 23mph/(32ft/sec^2) = 1.05 seconds \n\nthe result is:\n\n6 pound-seconds\n\nIt's the equivalent of 6 pounds acting for 1 second, or 1 pound acting for 6 seconds, or etc..
927051
The given final speed doesn't seem to compute. I get 14.8 m/s. \nMa*Va + Mb*Vb = (Ma+Mb)*Vf \nis the formula that applies to show conservation of momentum in a completely inelastic collision, which is what you have. The only explanation I could suspect is some cargo was spilled. \n\nTo continue the assignment - kinetic energy is given by\n(1/2)*m*v^2\nThere is no requirement that all the original kinetic energy be measurable as kinetic energy after a completely inelastic collision. But you should be able to point to where the missing energy went. Some of the energy probably went into cart damage. Perhaps the cargo slid around.
702948
asume that it is free fall that is initial speed is zero\n\nv = u+at = 0 + 9.8 * 5 = 49 m /sec\n\nit is independent of weight of stone
816469
well F=mv/t given: m=78kg, v=24m/s, t=60s\n\nF=78(24)/60=31.2N
62656
When it hits something.
775555
P = FD/t = 300*9.8*5/8 = 1837.5 Nm/sec = 1.8375 kw
229948
TO CRACK IT...HIT IT WITH A BIG HAMMER
335020
hit it with a hammer....
751049
First find Vo:  Vo^2 = Rg/sin(28)  Where R = range & 8 = theta\n\nUsing your numbers, Vo = 41.523 m/s\n\nImpulse = change in momentum ----> Ft = mVo---> F = mVo/t\n\nSo, F = (.0431kg*41.523m/s)/.00438sec = 408.59 N\n\nVoila!
756774
P=P (momentum before = momentum after)\nmv=mv\n(55kg)(4.6m/s) = (230kg)v\nv= ((55kg)(4.6m/s))230kg\nv=1.1m/s
748368
first get the time from the horizontal motion  t = .51 / 1.2 s (uniform motion, no acceleration here)\n\nthen use h = 1/2gt^2 for the vertical motion (with initial velocity zero)
817632
c: 8cm.\n\njust look at the units!\n\n200N/2500N/m = .08 m\n\n.08m is 8cm.