Solution composition...?
827418
First, you have to calculate the mass of each component by multiplying their volumes by their densities.  You should now have weights for the ethanol and for the water.\nNext, calculate the number of moles of each solvent by dividing those weights by their atomic weights.\n\nNow you can begin answering the questions.  Molarity is defined as the number of moles of a substance per liter of solution.  The total volume of the solution, due to the assumption that the volumes are additive, is 100 ml + 200 ml, giving you 300 ml or 0.3 liters.  So, to get the molarity with respect to ethanol, divide the number of moles of ethanol by 0.3 L.\n\nMolality is the number of moles per kilogram of solvent.  Do exactly the same as above, except this time, you have to calculate the total Kg of solvent instead of the total volume of solvent.  You have to add the mass of ethanol and the mass of water you have calculated from the volumes and the densities.  That's your total mass but don't forget to divide by 1000 to get Kg.  Then you calculate the molality of ethanol by dividing the number of moles of ethanol by the weight of your total solution in Kg.\n\nThe mass percent of ethanol would be the mass of ethanol divided by the total mass of the solution multiplied by 100%.  This is just like any other percentage calculation.\n\nThe mole fraction of ethanol can be calculated by dividing the number of moles of ethanol by the sum of the moles of ethanol and water.\n\nGood luck.
877634
Any acid, for example:\n\nHCl + H2O  --> Cl- + H3O+
1107804
if i recall correctly you are mixing two (or more) substances together, generally liquid, and solids form and precipitate out of solution.  (basically some solid chunks form from the mixture of the liquid)
851560
solution...Bicarbonate and sodium. :)
715878
Solution is the mixture of a solvent and a solute ,where the solute dissolves in the solvent.
138848
Here is one example ,\n\nAgNO3(aq) + NaCl(aq)-> AgCl(s)white precipitate + NaNO3(aq)
831216
Cu (s) + Pb(NO3)2 (aq) ---------> No Reaction. \nCopper will not replace lead.\n\nreaction VI in the attached link.
857082
1.  Split up the elements and give them their original charges\n\nAg +\nNO3 -\nK +\nBr -\n\n2.  Combine an element with an element that they were not with, putting them side by side will help\n\nAg + with Br -\nNO3 - with K +\n\n3. So now you have 2 new compounds\n\nAgBr & KNO3-\n\n4.  Their should be a chart in your book that tells you which compound would be the precipitate but i don't think their is a precipitate for this reaction'\n\nso both will dissolve in a solution
592402
I agree with the first poster on C and E, but I'm not sure if A is also.  A solute dissolving in a solvent seems like a chemical process to me, but I don't remember for sure.
1051035
1-. NaCl + H2O Sodium Chloride ( table salt )\n2-. NaSO3 +2 H2O Sodium Sulfate ( or sulfite I always forget which is the 3 and which is the 4 )\n3-. NaC2H3O2 + H2O ( I'm guessing.  You will want to check your periodic table for the charges on this one )\n4-.NH4Cl + H2O.  Ammonium Chloride\n5-.NSO2 + 3H2O\n6-. not sure\n\nI presume you are working salt solutions.  Ammonia was never my strong suit. I'm positive about the first two.
897586
X2O\n\nExamples:\nH2O => Water
352910
yeeaaahhh....Mix 'em!!!  YYUUUMMMMMMYYYYYY!!!!!!!!!!!\n\n:)  :)
327703
The amount is diluted by a factor of 25.  So the resulting solution would have a concentration of 11.6M divided by 25 or \nor 0.464M.
1117999
First make a chemical equation, balance it, and find a mole ratio.  Use that ratio and the above information to solve the problem.
663581
NH4NO2 --------------> N2 + 2H20 \n\nYOU NEED TO HEAT THE SOLUTION IN ORDER TO DECOMPOSE THE COMPOUND \n \nHOPE THIS HELPS
990586
You cant.\nThe key word here being "completely".\n\nNo matter how insoluble a given precipitate is, it is always soluble to some, very minor, degree.\n\nHowever, by choosing to precipitate a compound with a very low, practically zero, solubility, the ion is (for all intensive purposes) removed from solution.\nWhen dealing with such low-low solubilities, the Ksp value for the compound becomes important...the lower the Ksp, the lower the solubility.
1121888
Well you got C3H3Br + CH3S,  I'd guess something like ethane and bromosulfide.. C2H6 + BrS..