help with is math problem?
815604
I suppose you need the speed:\nThe required fraction is : 392/s ft/s\n                                      = 49ft/s (simplified)\nThe speed is 49 fett per second.
332255
=IF(OR(AND(A1>=1,A1<=12),\n       AND(A1>=25,A1<=36)),1,\n   IF(OR(AND(A1>=13,A1<=24),\n         AND(A1>=37,A1<=48)),2,""))\n\n\n(make sure it's all on one line with no spaces)
113980
Use a calculator - numerator divided by denominator will give you the answer.
609208
hey try to think logically about the problem.. its really easy just too much words and it confuses you. so take a deep breath and then begin. take 25 % off of $375 and it will give you the answer..... im pretty sure about this but you cant trust me on those dog gone word problems, lol \ngood luck
840649
1.\nn | n + 20\n------------\n0 | 20\n1 | 21\n2 | 22\n3 | 23\n4 | 24\n\nn | 3n - 35\n-------------\n1 | -32 \n2 | -29 \n3 | -26 \n4 | -23
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
423306
None.\n\n1,186\n2,93\n3,62\n6,31\n\nPost the original problem. Maybe you've done something wrong.
148434
So, continuing with mr_w's excellent example, we have 4 equations in 4 unknowns. So you can set this up as a matrix-vector problem.  Define matrix M such that M * Number of games bought vector = Cost & total games vector.  Assigning the rows of M in order to the total cost, the PS3 and Xbox360 cost, the PS1 and Xbox360 cost, and the total number of games, \nM = \n70 150 300 450\n0 0 300 450\n70 0 0 450\n1 1 1 1\nNumber of games bought vector =\na\nb\nc\nd\nand Cost & total games vector =\n13910 12000 3050 54\nThe solution will find the values of a, b, c and d.\nWhen I ran the solution I ended up with noninteger values for each and the values checked with the problem statements.  I hope those values were mr_w's solution.
411481
Simple word problem.\n\nStep 1: Assign known quantities to variables:\n\nM = age of the man\nS = age of his son\n\nStep 2: Translate sentences in the word problem into equations:\n\nM = S + 32\nM - 10 = 3 * (S - 10)\n\nStep 3: Solve multiple equations:\n\nM - 10 = 3 * (S - 10)\n(S + 32) - 10 = 3 * (S - 10)\nS + 22 = 3S - 30\n52 = 2S\nS = 26\nM = 26 + 32 = 58\n\nThe man is currently 58\nHis son is currently 26
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
971892
no of customers=-50(0.25n)+1000\nwhere n is element of natural numbers
854451
It's an algebra problem.\n\n\n2 * Teacher's Age = 3 * Student's Age\n\nSince the Teacher's Age = Student's Age + 15\nS will equal the student's age.\n2(S+15) = 3S \nWould be your equation.\n\nDistribute:\n2S + 30 = 3S\n\nSubtract 2S from both sides and you get:\nS = 30.\n\nThe student is 30 years old.  Since the teacher is 15 years older then the student, the teacher is 45 years old.\n\nWhy are people getting 15 and 30?  That's a 2:1 ration, not 3:2.
763076
1st Problem:\n\nLet's see, if we sell 198 thousand candy bars, we are giving them away, which is terrific for volume, but bad for profit.    \n\nRevenue = x P(x), = 9x-(x^2/22)  differentiate to get 9-(2x/22) so x/11=9 x=99\n\nPrice would be  4.50
944317
Im guessing your solving for y... so make the problem 58=29Y.  Divide both sides by 29 and you get y=2
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
137681
Ok...\nI see what you are doing...\nYou merely substitute the number in for x...\nso the problem becomes 6-2*(-1)\n6+2\n8
540085
(a-2)(a+2)  \n(difference of squares)