my teacher asked the antilog of a no. to the base e. what i did is use the no. as exponents of e. am i wrong?
812767
The logarithm is the mathematical operation that is the inverse of exponentiation, so you were not wrong.\n\nFor  y = log(base b)(x)\nThe inverse of a logarithm is called an antilogarithm or antilog; thus, x is the antilog of y in the base b. \ni.e x = b^y\n\nSimillarly in a prticular case of natural logarithm (base e)\n\nFor  y = log(base e)(x)\nx is the antilog of y in the base e. \ni.e x = e^y.\n\nI hope, I answere your question.
1061702
every time i've asked a teacher this, they've told me that its an even number.  The only reason i can come up with is that it is found between  two odd numbers. (-1 and 1)
643228
This is unclear.  Use the symbol ^ when using exponents.\nDo you mean?\n(6x10^12)^12 times (3.2x10^8) divided by [(1.6x10^7)^3 times 10^2]?
944851
Actually, while the other answers are probably what your teacher was looking for, your mistake may have been due to the ambiguity of her wording.\n\nThere's a reason we use parenthesis in math - to make it clear what the order of operations should be, because y + 3^2 is different than (y + 3)^2. Her statement could be read both ways, and taken literally, your answer is correct. Take the question to another math teacher in your school, and ask them if it seems ambiguous to them - if they say yes, take it up with your teacher.
478724
0.7 * 10^2 or 0.7 E+2 in some calculators,\n\nmeans that you must take your decimal (0.7 in this case) and shift the point a number of times as the exponent says (in this case 2) to the right if it is positive (like in this case) and to the left if it's negative.\n\nIn this case you must move the point two steps right: \nfrom 0.7 to 7.0 (first step) and then to 70. (final answer)\n\nAnother couple of exemples:\n\n.35 E-6 (or 0.35 * 10^-6)\nyou must move the point six steps left:\n0.00000035\n\n0.445 E+10 (or 0.445 * 10^10) \nyou must move the point 10 steps right:\n4450000000.
932114
So you have the formula, and you have the number to plug into it. Are you confused about how to deal with the exponents? \n\nIntensity = 5.4 x 10-10, so\n\nd= 10 * log( 5.4 x 10-10/ 10-12)\nd= 10 * log(5.4 / 10-2 )  \nd= 10 * log(540)\n\nd= 10 * 2.732                        note it is a base 10 log!!\nd= 27.32
64293
No, it is not true that is e^n a transcendental number for all values of n.\n\nConsider the value n=0.\n\ne^0=1, and 1 is a rational number.\n\nSome mathematicians include zero in N, the set of natural numbers, and some do not. If you exclude zero as a possible value for n, then the answer to your question will be different.
535346
I'm not sure if this is the whole question, but I will interpret it as if it ended with a ) in place of the [exp...\n\n9(x^3)N - 12(x^4)(N^2) - 9(x^2)N
141990
(assuming the second 2 is an exponent) 2*2*2*7*5*g*h*h \nyou really should learn to do this if you are ever going to get through school though
144487
the answer is exponents.
760330
First let me assert that \n  log(base b)(a)=1/log(base a)(b) as follows:\n\n let log(base a)b=z\n   a^z=b\n   a=b^(1/z)  . Now sub back for z giving\n   a=b^(1/log(base a)(b))  and convert to log form of base b\n 1)   log(base b)(a)=1/log(base a)(b)  \n\n Now follow this: \n    let  log(base c)(x)=y\n        c^y=x   Now take log(base a) of both sides\n    ylog(base a)c=log(base a)x  and  sub back for y\n log(base a)x  = log(base c)x{log(base a)c} and\n use 1) to convert log(base a)c giving\n   2)  log(base a)x  = log(base c)x/{log(base c)a.\n\n     Lastly, into 2)  substitute X^3+1 for x,  4 for a and 10 for c\n\nand we have \n  log(base 4)(x^3+1)  = log(base 10)(x^3+1)/{log(base 10)4}
580659
Ok, first, its not 1/y^2.  It's 1/y^5.  \n\ny*y*y*y*y\n-------------\n(y*y*y*y*y*y*y*y*y*y)\n\n\n= 1\n-----------------\ny*y*y*y*y\n\n\n= 1\n----------\ny^5\n\nAnd you write it just like that so as to keep the exponents positive.
275631
One way to see this is to write x^(1-x) as exp((1-x)ln x) and use the chain rule. Only one person has the correct answer, art_colls. The power rule *does not apply* since the exponent is a function also!
232907
I would reword it as this:\n\nHowever, I am not good at math.\n\nHope this helps!
29143
It is called a caret.  You can use it to indicate an exponent or a superscript if the software you are using does not have the ability to make superscripts. \nEx: E=mc^2 (Einstein's famous equation relating mass and energy)
330547
#include<math.h>\nthen, pow(10,i)\nwill give the antilog of i.
519118
you use the 10^x key\n\nthe antilog of -4.82 \n= 10^(-4.82) = 1.514 * 10^(-5) = 0.00001514\n\ntype in -4.82 and hit the 10^x key (it's usually right above the log key, which mean you hit the 2nd function key then log)