what is 999 divided by 89???
816947
999 / 89 = 11.2247191\n\ndid you know that Google can act like a calculator?\n\nhttp://www.google.com/search?hl=en&lr=&safe=off&q=999+%2F+89&btnG=Search
210139
the only way to make 1991_1991 divisible by nine is to choose _ the missing number by 5\n\n199151991 is divisible by nine\n\nso 199151991 / nine =221 2 7999 \n\nSo there is 3 numbers not 4 in the first so i say\n0221 2 7999 x nine = 1991 5 1991
215950
almost ... its 1000 to 9999 \n\ni.e 9000 combinations :)\n\nAnother way to do this ... \n\nexcept the first digit all can have a 0 .. so the possible combinations are : \n\n9*10*10*10 = 9000\n\n( 9 possible digits can be put in the first and 10 in the 2 thru 4)
1072126
10000\n\nThat's counting 0000, 0001, 0002, all the way to 9999
203269
call 1 900 or something with 1 900
108568
Here are two fantastic ways:\n   \n  (8888 - 888) / 8 = 1000\n\nand\n\n  888 + 88 + 8 + 8 + 8 = 1000
1114070
It's 27 %.   Don't your calculators work?  9700 divided by 35800 is .27....   27%.
1115229
Just add them up using the calculator:\n1000 + 5999 + 9888 = 16887\n\nOr if you don't have a calculator:\n*111\n---------\n**1000\n+5999\n+9888\n=====\n16887\n=====
127502
Several ways:\n\n(9 / 9) + 99 = 100\n99 / .99 = 100\n(9 / .9) * (9 / .9) = 100 \n\nhttp://www.iit.edu/~smart/acadyear/puzzles.htm
1127621
Actually the above "proof" is misleading. \n\nx=0.999...99\n\n10x=9.999...90 (as anything x10 adds a zero to the end as the decimal place shifts, even if the number is infinite)\n\n9x=10x-x\n=9.999...90-0.999...99\n=8.999...81\n\nx=9x/9=8.999...81/9=0.999...99\n\nTherefore 0.999...99 does not equal 1....mathematics isn't independent of logic. Beware of those who try to make it so.
838732
000000 to 999999 --> 1 million combinations\n\n10 choices for the first digit\n10 choices for the second digit\n10 choices for the third digit\n10 choices for the fourth digit\n10 choices for the fifth digit\n10 choices for the sixth digit\n\n10 x 10 x 10 x 10 x 10 x 10 = 1 million\n\nHowever, if you disallow 0 as a starting digit then you have the following:\n\n*9* choices for the first digit (1-9)\n10 choices for the second digit (0-9)\n10 choices for the third digit (0-9)\n10 choices for the fourth digit (0-9)\n10 choices for the fifth digit (0-9)\n10 choices for the sixth digit (0-9)\n\n9 x 10 x 10 x 10 x 10 x 10 = 900,000
448118
Oh jeeze, are you serious LOL.......ok lets say: 999,349,843,928,999,344,576,345,768,324,999 gazilliontrillionbazillion........
179549
(y + 9) * (y + 9)\n\n9 and 9 add to be 18 and multiply to be 81.
271046
look at it this way:\n\n1/3 = .3333...\n2/3 = .6666...\n\nadd the two and you get \n\n3/3 = .9999...\nor, equivilently\n\n1 = .9999...\n\nso, looking at it that way, yes they are equivalent\n\nthe only reasone this works is because we could never add the .000....1 to the .999... to make it 1 because we never know where the last 9 occurs, infact there is no last 9, so we must conceed that they are equivilent.\n\nor, one could look at it as .999... converges to 1, no matter how close you say .999... has to be to 1 in order to say they are equivilent, .999... could be taken that many digits out so that the next digit would round it up to 1\n\nhope this was helpful\n\nmatttlocke
565436
simple!\n(8888-888)/8 = 1000\n\ncertainly I didn't copied rt11guru's answer.\nhere is another one\n\n888 + (8+8)*8 - 8 - 8 = 1000
1157976
0000, 0001, 0002, 0003, 0004, 0005, 0006, 0007, 0008, 0009, 0010, 0011... etc, etc  untill u get to 9998, 9999\n\ntry it out, might take a long time but one combination will work :))
481632
Replace m with 9.\nIf the resulting statement is true, then 9 is a solution.\nOtherwise, 9 is not a solution.\n8(9) + 7 = 91\n72 + 7 = 91\n79 = 91\nThis is false.\nThus, 9 is not a solution.