4 Algebra Questions. Please help me ok? Thanks?
832106
1) 1/-4<m/-4\nmultiply both sides by negative 4 and flip the inequality sign\n4>m.\n\n2) -1/8< or equal to n/-32\nmultiply both sides by negative 32 and flip the inequality sign\n4 greater than or equal to n\n\n3) x/-12>1/4\nmultiply both sides by negative 12 and flip the inequality sign\nx<-3\n\n4) -1/2x< or equal to 2\nmultiply both sides by negative 2 and flip the inequality sign\nx> or equal to -4
919864
1.  ax + xb\n2.  21x^3 + 24x*2y\n3.  24x^2 + 31x + 10\n4.  24x^2 - 8x - 6\n5.  40x^3 + 66x^2 + 38x + 6\n6.  x^2 - 1\n7.  x^3 - 8
680155
i'd love to help but i'm having trouble with it myself\n\nuse ur math textbook it will have it unless ur math book say algebra and is red ( that my alg. book and it doesn't help) \n\nSRY good luck
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
843058
1) 2.01 * 10^2\n\n2) 1.995 * 10^23\n\n3) 5.35 * 10^-4\n\n4) 3.8418 * 10^-7
921810
2(4x+7)=2x-4\ndistribute\n8x+14=2x-4\n-2x from feach side\n6x+14=-4\n-14 from each side\n6x=-18\ndivide by 6\nx=-3\nand the next one\n-2(18-3y)=7y+2y\ndistribue and add light terms\n-36+6y=9y\nsubtract 6y from each side\n-36=3y\ndivide by 3\n-12=y\n:) welcome
1100359
1)If it's an equation then solve it quadratically\n\n(X-3)= 0 or (X-3)= 0\n\ntherefore X= 3 (as the 3 moves to the other side making it positive)\n\n2)If you have to find the products ude the distributive law:\n\nXsquared -3X-3X+9\ntherefore the answer would be Xsquared -6X+9\n\nBut I'm sure you needed the Equation one so use my first answer and method.
872966
1.) 3 &#92;/ x+2 - 4 = 3\nif you mean\n3 sqrt( x+2) -4 =3,\nthen\n3 sqrt(x+2) =7\nsqrt(x+2) = 7/3\nx+2 = 49/9\nx=49/9 -2\n\n2.) &#92;/ x+3 - &#92;/2x-8 = 1\nsqrt(x+3) -sqrt(2x-8) =1\nsqrt(x+3) = sqrt(2x-8) +1\nx+3 = 2x-8 +2 sqrt(2x-8) +1\n-x + 10 = 2 sqrt(2x-8)\nx^2 -20x + 100 = 4 ( 2x-8)\nx^2 - 28x  +132 =0\n'
232213
I'll do the fourth problem.\n\n-3x< -6  or x+5< -2\n\nfirst deal with one half- \n-3x< -6 (now divide by -3)\nx>2 (when you divide by a negative the sign is reversed)\n\nthen the second half- \nx+5<-2 (get x alone, so subtract five from each side)\nx< -7\n\nso you have:\n2 < x  or  x < -7\n\nto graph this there is a line with an arrow to the left of the first slash and another line to the right of the second slash\n\n<-----/-------0--/-->\n____-7______2
68882
1) yes, this is correct as written.  Not sure what else you need? \n2) 10/14?\n3) 2 (1 is not a factor)\n4) -6(x+1)\n5) 5 1/4 or 21/4 (same thing)\n6) 1 4/9
1022192
i have  a book about algebra..... and some website...see if they could help u
1106533
1) 6(x-4)(x-2)\n= 6(x^2 - 2x - 4x +8)\n= 6(x^2 - 6x + 8)\n= 6x^2 - 36x + 48\n\n2) (x+7)(x+4)-(x+3)(x+2)\n= (x^2 + 4x + 7x + 28) - (x^2 + 2x + 3x + 6)\n= (x^2 + 11x + 28) - (x^2 + 5x + 6)\n= x^2 + 11x + 28 - x^2 - 5x - 6\n= 6x + 22
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
355004
1. a = b + 1 (Given, let a and b be two numbers such that a = b + 1)\n\n2. (a-b)*a = (a-b)*(b+1)\n\n3. a^2 - ab = ab + a - b^2 - b\n\n4. a^2 - ab - a = ab + a  - a - b^2 - b\n\n5. a*(a - b - 1) = b*(a - b - 1)\n\n6. a = b\n\n7. b + 1 = b\n\n8. Therefore, 1 = 0
821200
(x²+4x+4) / (2x-3) / (x²-4) / (2x²-7x+6)\n\nYou have 4 terms and three divisions, so it's a little unclear if you mean (a/b) / (c/d) or what.  I will try to help to the extent I can.\n\nLet's assume you mean:\n\n[ (x²+4x+4) / (2x-3) ] / [ (x²-4) / (2x²-7x+6) ]\n\nFactor your x² equations to see if you can cancel terms:\n\nx²+4x+4 = (x+2)(x+2)\nx²-4 = (x+2)(x-2)\n2x²-7x+6 = (2x-3)(x-2)\n\nWoohoo - things are looking good!  Now we can rewrite our original problem using these factors:\n\n[ (x²+4x+4) / (2x-3) ] / [ (x²-4) / (2x²-7x+6) ] = \n\n[ (x+2)(x+2) / (2x-3) ] / [ (x+2)(x-2) / (2x-3)(x-2) ] =\n \n[ (x+2)(x+2) / (2x-3) ] * [ (2x-3)(x-2) / (x+2)(x-2) ] =\n\nnotice we can cancel out three terms: (2x-3), (x-2) and (x+2)\n\n[ (x+2)(x+2) / (2x-3) ] * [ (2x-3)(x-2) / (x+2)(x-2) ] =\n\n(x+2)\n\nHope that helped!\n\n~ ♥ ~
909535
1) \n76>40+4c\n36>4c\nc<9\n\n2) 1500>100+17.5p\n1400>17.5p\np<80
303592
Yes, I can solve them.\n\nLike any other fractions, find a common denominator.  Though with (a) you can just multiply everything by 7x and simplify the equation to:\n\n21 + 1 = -14x\n\nYou can do the same with (c).  With (b) it's a little more complicated, and you have to find the common denominator of x and (x + 6).  I'll leave that for you.