how do i find the angle of an obtuse triangle with only two sides?
816836
You need one more datum, either the third side or any angle.  If it were a right triangle, the right angle would comprise the third datum.
392786
you may be dealing with "right" triangles, but you don't identify the angle that is 90, so your question is bout impossible to answer. this type of question usually involves  \na squared + b squared = c squared (a^2 + b^2 = c^2) where a and b are the 'legs' of the triangle in question. (the two 'legs' of a right triangle make the 90 degree corner) :)
728290
The method is entirely dependent on what you know about the triangle in the first place.  If you know the 3 sides, you can use Steve's law for the altitude; ex: (alt to side c) = sqrt(4a^2b^2-(a^2+b^2-c^2)^2) / 2c\n\nIn general, the altitudes of a triangle intersect at a point called the orthocenter, whose location is described in detail at\nhttp://www.cut-the-knot.org/triangle/altitudes.shtml
826563
multiply the tangent of the given angle by the known side as long as it's not the sloping side (i.e. the hypotenuse). You will need a scientific calculator to do this. I am assuming of course that you are dealing with a right triangle. This will give you the other side of the triangle. Example:\n\nlets say you have side A of a right triangle and an angle of 30 degrees and A = 10. Take your scientific calculator press 30 and then the tan button depending on the type of caculator you have. Now multiply that result by 10 and you will get side B.\n\nSide C is found by A^2 + B^2 = C^2. take the square root for your answer.\n\nNow if the given angle is opposite the given side. Just calculate the angle of the given side by adding the given angle to 90 degrees and subtract the result from 180, and then multiply the tangent of the new new angle by the given side.\n\nTheoretically you can check the answer by multiplying the new side by the tangent of the new angle. You should in theory get the given side. But my trig is so rusty I may have forgotten more than  you will ever know. good luck.
942453
From symmetry, you have all the angles\n69 for two, and 180-69= 111 for the other two.\nUse the law of cosines: for triangle abc with opposing angles A,B,C we have the length of the 3rd side c for given a,b from:\n\nc = sqrt(a^2 +b^2 -2abcos(C))\n\nIn your case: a=4, b=6 and C = 69 so\n\nBD = sqrt(36+16-48(cos(69)) = 5.9\n\nFor C = 111 we have:\n\nAC = sqrt(36+16-48(cos(111))= 8.32
328129
just draw a triangle has right angle which dimensions 1,sqrt(3),and hypothenus 2. if you want it, i can send to you
278653
15: First you cut the triangle in half so the hypotenuse is 17 and the bottom leg is 8 (half of 16=8) and then use Pythagorean theorem so it would be 17^2 - 8^2 (=225) and take the square root of that (=15).\nGood luck on your midterm!
715400
Angle of line from horizontal position.
27656
I used the acronym sohcahtoa to remeber that sin=opp/hyp cos=adjacent/hyp and tan=opp/adj, so you have a angle you want to measure the degree of that angle, using the lengths of the sides of the triangle opposite, adjacent and hypotenuse and then using your calculater you divide the lengths and hit the button sin-1, cos-1 or tan-1 key, also cot=1/tan, hope that helps
161223
law of cosines : a^2 = b^2 + c^2 -2bc * cos(A)\nwhere a, b,c are side lengths and A is the angle oppisite side a.
901368
You need to take triangles with leg length 2-sqrt(2) from each corner. That is about 0.586".\n\nThe length of each side of the octagon will be 2 * sqrt(2) - 2. This is about 0.828"\n\nThis was calculated by setting the length of each leg of each triangle to x.\n\nhypotenuse = remaining side of square\n\nx * sqrt(2) = 2 - 2x. And then solve for x.
109605
Just use Cosinus Theorem: c^2=a^2+b^2-2abCos(gamma)\n1.\nc=sqrt(4+64-2*2*8*sqrt(3)/2))\nc=6.34\n\n2. Is not a right Triangle.. but anyway lets find the angle A:\n22^2=15^2+33^2-2*15*33*Cos(A)\nCos(A)=830/990\nA=ArcCos(83/99)\nA=33°1' 48.54"
881588
First, the isosceles triangle has sides of 10, 12, 12.  You can find the angle by law of cosines or, as I prefer, just divide the triangle into two right triangles.  The short side is 5 and the hypotnuese is 12 so the angle at G is arcsin(5/12) and the total angle FGA is twice that (since we split the original triangle in two) <FGA = 2*arcsin(5/12) = 49.249 deg.\n\nIf you make a pyramid, The radius of the hexagon (10 cm), the 12 cm side and the height form a right triangle so the height is:\n\nh = sqrt(12^2 - 10^2) = sqrt(44) = 6.633\n\nFinally, for the area, we need the height of the isosceles triangle which is the tjhird side of the right triangle in the first part. This height is:\n\nc = sqrt(12^2 - 5^2) = sqrt(119) = 10.909\n\nSo the area is: A = 3*10*sqrt(119) = 327.261
1021896
the squareroot of 2 over 2.  angle a must equal 45 degrees.\nnote- the answer may also appear as 1 over the squareroot of two.
302936
Without knowing the measurements of the sides, you can only figure this out if all sides of the polygon are equal in length. And this is how...\n\nSee, first you draw any polygon, except a triangle. So before doing it, you should know that all the angles of a triangle must add up to 180 degrees. (You can do it with a triangle too, but you would be using what you’re hoping to discover.) From the center of the polygon, draw a line to each vertex. This will create a number of triangles, inside the polygon, equal to its number of sides. Knowing that the angles inside each triangle must add up to 180 degrees, you simply multiply 180 by the number of triangles, which is also the number of sides. Then, realizing that the angles in the center of the polygon, which do not contribute to the angles of that polygon, form a complete circle, and therefore must add up to 360 degrees, you subtract 360 from the result. So the angles in any polygon must add up to 180x-360, or 180(x-2), where x is the number of sides. To find the measure of each angle, in a polygon where all sides and angles are equal, you divide that by the number of sides. The equation then works out to (180(x-2))/x.
722736
the angles are just unknown if i get you correctly.\nthere are sin, cos, and tan proportions you can work out to find the rest. i think you only need three of the measurements to work out the rest of the triangle, like 2 sides and an angle or 2 angles and a side.  not positive.
367687
an angle that is inside a circle or any other figure