Im having trouble remembering how to bend electrical conduit?
826815
Conduit Bender. Take the measurements, allow for the arch, and bend.
234304
Try asking this question in the engineering section under math and science.  That is where I ask all of my technical questions.
1125882
The best thing to do is to use a table of wire gauge versus current and resistance.  The tables usually provide resistance per linear foot  so that for a given length of wire of a particular gauge, you can determine its resistance.  This is important because the wire's resistance combined with the current that your load draws will cause a voltage drop across the wire so that you do not have the same voltage at the load as you provided from your power source. This follows Ohm's law (  V = IR).  You should size the wire conservatively and follow local codes if this is for commercial or residential purposes.
762462
Do you mean the FEA program if so the most important factor and the one that i used to always get wrong is node number and separation. Try a simple shape with fixed point load and pivot. First try with 10000's of nodes then try with 100's then with just 2 or 3 dependent on shape the difference to the results are big. Node choice comes with experience which i am lacking!!
1111034
Perhaps the link will help a little.  If you bend a pipe or metal bar, some of the metal will be in tension (stretched) and some will be in compression (squeezed).  There is a neutral plane between the two conditions that is neither stretched nor squeezed.  Often the plane passes through the centroid of the pipe (or bar).  This is easy to find if the cross-section is regular (round, square, etc.) but more difficult to find if the area is irregular or of variable properties such as density.  The centroid is similar to the center of gravity for the shape.  Hope that helps a little.
759091
------/:=====:x:=====:&#92;-----@-------\nL     2Wy                Int             2Wy           Load          N\n\n(Does this answer your question??)\n\nL=Live, 2Wy is a 2 way light switch, int is an intermediate switch, and @ is a light??\n\nConfused?? (never heard of tunnel switching!!?)
471243
Mine is u-shaped. It goes in kind of like a corkscrew. The straight end starts things off, and then you twist to seat the rest of the stud. It feels weird (unpleasant, actually) until you've done it a few times and get used to the sensation.
24059
You can find detailed instuctions on buiding an epee test box at http://www.busybwebdesign.com/saskfencing/testbox.htm\nso there's really no need to reinvent the wheel there.\n\nas an alternative you can also use a multimeter to test the weapon in lieu of building something from scratch. Here's an example of one http://www.radioshack.com/product/index.jsp?productId=2103534&cp=&kw=multimeter&parentPage=search\n\nstart by setting the multimeter to OHMs (which measures resistence). insert the leads from the multimeter into the A and B socket holes. When the point is depressed, the needle on the multimeter should move to somewhere under 1 ohm. The needle should not move when the point is not depressed.\nTo test your wiring, remove 1 of the leads and place it against the blade. Depress the tip. If the needle moves, you either crossed your wires or the insulation on one of the wires is worn and the wire is touching the blade.
965440
Stick the metal end into the socket and twist it round and round until it is firmly in place.
294387
go to DIY sites about electrical. you must be an electrician to conduct electrical wiring. electrical current is an unforgiving. you ust know how to respect it...
688527
Do you have an Ace Hardware near you or another type of hardware store.  The people at Ace will help you and show you how to make it easy to thread.\nGood luck....
531867
I am typing this answer on a computer connected with a cat-5 cable to a LAN. You need to explain what "climping" is and what you are trying to do before anyone can help you with your problem.
291589
Use the node voltage method. Label each node with a voltage, then apply Kirchoff's current law at as many nodes as you need to generate enough equations to solve for any unknowns you have introduced.\n\nLet the node at the bottom of the circuit be ground, and then try to figure out the voltages at the other nodes relative to ground. Clearly the voltage at the node on the top will be 14V (I'll just call this V1) but no other voltages are apparent. So call the voltage at the node between R1, R3, and R4 Vx and the voltage at the node between R2, R3, and R5 Vy.\n\nNow that we have labeled all the node voltages, you can figure out every single current in the circuit in terms of V1, Vx, and Vy (using Ohms Law, the voltage drop across a resistor is equal to the resistance times the current in the direction of the voltage drop). For example, we know the current going down through R1 is (V1-Vx)/R1, the current going right through R3 is (Vx-Vy)/R3, etc. Now we just have to solve for the unknowns Vx and Vy.\n\nKirchoff's current law (KCL) says that the sum of the currents leaving a node is equal to zero. If we apply this law to the node with voltage Vx and the node with voltage Vy, we'll get a pair of equations that we can use to solve for Vx and Vy.\n\nApplying KCL at the node with voltage Vx should give you the following equation:\n\n(Vx-V1)/R1 + (Vx-Vy)/R3 + Vx/R4 = 0\n\nThe first term is the current going up through R1 (we already figured out the current going down through R1, but we want currents that are leaving node Vx so we had to flip the sign), the second term is the current going right through R3, and the final term is the current going down through R4.\n\nI'll leave it to you to figure out the equation for node Vy. Once you have that you'll have two equations and two unknowns and you can solve for everything. Once you have Vx and Vy, you can easily figure out a numerical value for any current in the circuit.\n\nBTW, the node-voltage method is pretty powerful and can solve most linear circuits. Check out the link below, it was written by an old EE prof of mine who is very thorough.
185952
a diode blocks current from flowing in a certain direction. current will flow from the non striped side to the striped side
800088
any good diy book will do or perhaps links on the internet.\n\nin the uk its all about getting a phase neutral and earth around each point.\nso for the sockets grab a reel of 2.5mm 2core and earth (so called because the earth doesnt have an extra layer of insultation) and take it round to each socket in a ring. usually fuse at 32A with a circuit breaker.\nfor an immersion heater fuse at 16A and take a single 2.5mm 2c and earth cable.\n\n(This starts getting a bit boring, go and buy a book)
595017
The first thing you need to do is to make sure that none of the light reflected from your body reaches the observer.   The observer would see a black object there (you).  So you must replace that light with the light that the observer would normally see if you were not there. So I would guess that you must bend the light that is coming from behind to bend around your body. \n\nHow you would do these things, I have no idea.
308771
well I guess I don't understand exactly what are you asking...so more details are needed...simple answer to your existing question as is....place the connector on the cable and insert the connector (cable in it) into the rj45 slot on the crimp tool and squeeze...but if your asking for pin out on the cable..then you need to specify rather you want a straight thru or cross over cable...you can use these sources as nice guides...Hope it answers your question what it is...