How do I balance this chemical equation CH3COOH+NaHCO3=CO2+H2O+NaCO3?
605005
NaHCO3(s) + CH3COOH(aq) → CH3COONa(aq) + CO2(g) + H2O(l) \nThis is the real chemical reaction.
824141
Start off with the original equation\n\nCaCO3(s) + HCl(aq) --> CaCl2(aq) + CO2(g) + H2O\n\n\nStart off by making the Ca equal on both sides, which is fortunately already done\n\nThen make the Cl equal on both sides by putting a 2 in front of HCL\nCaCO3(s) + 2HCl --> CaCl2(aq) + CO2(g) + H2O\n\nThen make the C's on both sides equal, which again, is already done\n\nNext make the O's equal on both sides, which yet again is already done.\n\nFinally you make the H's equal on both sides, which is done also. \n\nSo the answer to this whole question is to put a 2 in front of the HCl. (I'm guessing you meant to put CaCl2 instead of CaC12 in the products)\n\nThat was easy.
1175985
Balance the Carbons first, then the hydrogens, and lastly the oxygens:\nC3H8 + ?O2 --> 3CO2 + 4H2O\n(balances carbon and hydrogen)\nthen:\nC3H8 + 5O2 --> 3CO2 +4H2O (final answer)
551370
Well, the equation is..\nCH3COOH + NaHCO3 ----> CH3COONa (Sodium Acetate) + H2CO3 (Carbonic Acid) \n(or)\nCH3COOH + NaHCO3 ----> CH3COONa (Sodium Acetate) + H2O (Water) + CO2 (Carbon-dioxide)\n\nSo you might have noticed the equation is already balanced. It is a double-displacement reaction. So the sides are already balanced.\nHope this helps.\n\nOne small note...I don't think there is a compound such as NaCO3. The valency of CO3(^-2) ion is 2, so it has to combine with two Sodiums (two positive charges to neutralise its two negative charges) unless the compound one of the above users mentioned is NaCO3-.\n\nrule wid style n luv@vinny
764101
In all reactions one uses that 2 OH -> H2O + O, the split of oxygen goes to create the ion. Finally balance the equation:\n \nSO3 + 2 NaOH -> Na2SO4 + H2O\n\nCO2 + 2 KOH -> K2CO3 + H2O \n\nSO2 + Ba(OH)2 -> BaSO3 + H2O
195778
1.  C(s)+O2--> CO2(g) - 393.5 kj\n2.  H2(g)+1/2 O2(g)--> H20 -285.8 kj\n3.  2C2H2(g)+5O(g)-->4CO2(g)+2H2O(... -2598.8\nCALCULATE the value for the reaction 2C+H2-->C2H2\n\nFirst balance eqn 3 with 5O2 (g) then reverse it so that you have 2C2H2(g) on the RHS. Of course, you will change the sign of the eqn as well. Now halve it so you have one C2H2 instead of 2. Let's call the new eqn number 4\n\nSecond, double the 1st eqn. Let's call it eqn 5\n\nLastly, add eqns 3, 4 and 5:\n\n4 2CO2(g)+H2O --> C2H2(g)+5O2(g) +1299.4 kJmol-1\n5 2C(s)+ 2O2--> 2CO2(g) -787.0 kJmol-1\n3 H2(g)+1/2 O2(g)--> H20 -285.8 kj\n----------------------------------------------\n  2C(s)+ H2(g) --> C2H2(g) + 226.6 kJmol-1
73319
the earlier equation is not balanced.\nCaO + 2HCl --------> CaCl2 + H2O
748691
CH3COOH, remember the CO2 comes from the sodium carbonate so your question is poorly worded.
839194
The balanced equation is\n\nH3PO4 + 3KOH ----> K3PO4 + 3H2O\n\nApart from using the rule to balance this, you can also view this in this way, H3PO4, when dissolved in solution, gives 3H+ and 1PO43-, while KOH when dissolved in solution gives 1K+ and 1OH-. OH- and H+ always neutralize each other to give water. Therefore, you need 3 OH- to neutralize the 3H+ from the acid. Work out the balance, you get the above equation.\n\nGenerally, number of atom and particles can be found by first finding the number of moles. Number of moles by definition is the mass of the substance divided by the molecular weight. For example, total number of mole in 12 g of C is \n12 / 12 = 1 mole\n\nWithin each mole, there are always a finite number of UNIT, which can be in the form of atom, molecule, or ion. This special number is called the Avogadro constant, and has a value of 6.02e23.\n\nFor example, 1 mole of C has 6.02e23 carbon atom.\n\nHowever, for 1 mole of H2, there are 6.02e23 H2 MOLECULE!!! because every two H atoms are bond together to form a more stable molecule. To find the total number of atom, you know each H2 molecule has 2 atom, so the total number of atom in this case is 2*6.02e23 or 12.04e23 atom.\n\nUsing the relationship\n\n# mole = mass/ molecular weight\n\nYou get mass = # mole * molecular weight
830338
H2CO3 + 2KOH ===> K2CO3 + H2O\n2HNO3 + Ca(OH)2 ===> Ca(NO3)2 + 2H2O
684663
Maybe I'm wrong but I don't see a solution.  Not enough oxygen to complete that reaction.  Dod you have a typo somewhere?\nIf water is on the left then:\n  CH3COOH + 2 H2O + 8 NaCO3  =  8 NaHCO3 + 2 CO2
132050
oh shit.ok\nn2h2+(ch3)2n2h2+3n2o4 = 5n2 + 6co2 + 5h2
929071
2C18H18 + 45 O2 --->  36 CO2 + 18 H2O\n3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O
606155
NaOH + HCl ---> NaCl + H20
839940
1. 2C6H6 + 15O2 --> 12CO2 + 6HOH\n\n2. C12H22O11 + 12O2 --> 12CO2 + 11HOH\n\n3. CH3COCH3 + 4O2 --> 3CO2 + 3HOH\n\n4. C2H5OC2H5 + 6O2 --> 4CO2 + 5HOH\n\n5. C4H9OH + 6O2 --> 4CO2 + 5HOH
957775
Ca(OH)2 + CO2 --> C(OH) + CaO\n\nIs unbalanced..
700313
NaOH + K+ = Na+ + KOH