Find the GCF for 21, 35, and 70?
594665
21+7*3\n35=7*5\n70=7*5*2\n\nthe only thing in all 3 is 7 so the GCF=7
985975
take - common\n -(y^2-9y+20)\n-(y^2-5y-4y+20)\n-(y(y-5)-4(y-5))\n-(y-4)(y-5)
811163
(2 * 20) - 35 + 5 = 10
592014
a 30\nb 40\nc 50\nd 20
852407
To show your work, you list the factors of 3 and 9. Then find the greatest factor they both have in common.\n\n3: 1, 3\n9: 1, 3, 9\n\nThe GCF (Greatest Common Factor) is 3. Both 3 and 9 have 3 as a factor and it's greater than any other factors.
780226
lets take the common multiple 210\n15,35,21 and 2 are the factors\nI was thinking of 105 but only 15.35.21 come to my mind
275881
Mr Wonderful is right.  the quick common denominator is 65*26= 1690, but the numbers have a common factor of 13.  divide 1690/13=130.\n\na simpler example: given 8 and 12, QCD = 96, but GCF = 4, so LCD = 96/4 = 24.
893476
It is \n[(35x1.50)+(15x1.75)+(20x2.25)]/70=\n123.75/70=\n1.77
873982
c to f:\nn*1.8; add 32\n\nf to c:\nn-32; multiply by 0.5555
830021
35(2/3) - 39(4/7)\n(70/3) - (156/7) = 22/21\n\nANSWER\n22/21 miles
728450
G=(T+Mf)/M \ncross-multiply\nGM = T + Mf\nGM - Mf = T\nfactor out the M\nM(G - f) = T\nM = T(G-f)\n\nANSWER\nM = T(G-f)
389726
Unfortunatly, you will have to list the factors of each and then find the common and then the greatest common factor (GCF). \n\nIf you know the rules for finding factors it helps:\n\n2: goes into even numbers\n3: add the digits together and if the sum is divisible by 3 then the 2 digit number is (example 45: 4+5=9 and 9 is divisible by 3 so 45 is, too)\n5: all numbers that have a 0 or 5 in the one's place\n \nGood luck!
200143
Answering...\n\nSteps:\n1. Determine tha numbers/variables that are common to both terms.\n2. Use the greatest of these factors (GCF).\n3. Factor out the GCF.\n4. What are left, put them inside the parenthesis.\n\nTherefore:\n1. Common factor: 2\n2. GCF: 2\n3. and...\n4. 2(6y^2 - 5) ANSWER
957103
9 = 3*3, and 21 = 3*7, so common multiples must have at least two factors of 3, and one factor of 7; ie they must be a multiple of 3*3*7 = 63. Theres only one - 63.\n\nOr you could just list multiples of 21: 21,42,63,84. Only one is a multiple of 9.
487301
There's another way if you're calculating the gcf of just two numbers... for example, 960 and 144. Start off by dividing the larger of the two by the smaller..\n960/144=> Quotient=6 Remainder=96\nNow, divide the divisor of the previous step by the remainder.\n144/96=> Quotient=1 Remainder=48\nContinue till your remainder is 0.\n96/48=> Quotient=2 Remainder=0\nThe last divisor, i.e. 48, is the GCF.\n\nAnother example...\n1890 and 168\n1890/168=> q=11 r=42\n168/42=> q=4 r=0\nSo the GCF is 42.
985783
Here's how you do these.\n\nTake one number and figure out all the numbers that evenly divide into your number. Write those down. Do the same for the other.\n\nFor 52... 1, 2, 4, 13, 26, 52\n\nFor 135... 1, 3, 5, 9, 15, 27, 45, 135\n\nLook at what numbers they have in common. In this case, they only have 1 in common. To find the GCF, find the largest number they had in common. In this case, it's one.\n\nHope that helped,\nUMRmathmajor
948171
If s, r, and j are the numbers of CDs each has,\n\ns = 2j-1\n\nr = j + 53\n\ns - 25 = j + 25\n\nReplace the s in the third equation with 2j - 1 from the first.  Solve for j.  Then plug this in to get r and s.