What is the p-value for this case?
596511
z = (47-50)/(7/sqrt(40)) = -2.71\n\nSince this is a one sided test, then the p-value would be the area to the left of -2.71, which is 0.0034.  The answer is D.
247542
P(0) = -1 + 5(1) - 4(-1) - 8 = 0
623677
Analysis of variance or ANOVA checks for the variation contributed by teh population in question
705080
Every time you perform a hypothesis test, you have to find p-value. Since, this p-value will decide wether the hypothesis is true or not. And, when accepted or rejected at what percentage will it be accepted or rejected.\n\nI hope this is the answers your question.
1163562
really good or really bad, depending on how you want to look at it... and don't try telling me that wasn't a statistical answer!\n\np <0.0000001
629177
P(selecting a person at random and he has the symptom and is detected by the procedure)\n\n= P(patient having it) and P(detecting it using the procedure)\n\n= (0.5/100)*(98/100)\n= 0.0049\n\nBut if the person is not randomly selected and you are sure s/he has the problem and its just a matter of detecting it with the procedure, then Probability = (98/100) = 0.98
693338
since your P-value is large then you cannot reject Ho,
319924
It depends on the distribution.  Some probability distributions have multiple parameters (such as the mean and standard deviation for the Normal distribution).  Phi2 would be one parameter of the particular distribution used in the problem.
947255
Let X be mean fill of container. \n\nThe distribution is X~N(16, 1.5) i.e. it is normally distributed as stated in the question.\n\nWant to find P(X>17), so standardise.\nP(X>17) = P(Z>(17-16)/(1.5/2)) = P(Z>1.33)\n\nThen you look up your normal table. The answer is approximately 0.09.
522796
a) Sensitivity = P(Test + | Has disease), so out of the people who have the disease, 93.4% would test positive for it.\n\nSpecificity = P(Test - | Doesn't have disease), so out of the people who don't have the disease, 98.6% would test negative for it.\n\nb) This is again a Bayes' Rule problem\nP(T+|D) = 0.934\nP(T-|ND) = 0.968\nP(D) = 0.002\n\nP(D|T+) = P(D)P(T+|D)/(P(D)P(T+|D) + P(ND)P(T-|ND))\n= (0.002)(0.934)/(0.002(0.934) + 0.998(0.968))
907438
I could tell you the answer or I could give you an idea of what to consider when you do it yourself.\n\na) Binomial numbers and p = 0.7, q= 0.3 might help here.  You do not know the size of the population of the mailing list so you might need to make an assumption that it is large enough to assume a Normal distribution.  I think the central limit theorem might help here.\n\nb) Binomial theory, and conditional probabilities.  Look it up in your text book!  Again if the size of the population is large enough you might be able to simplify the problem.
856461
This would be a binomial.  Assuming that p=1/2 , equal probability of male or female.\n\nThen it's like 80 trials with success (male) or failure (female)\n\nAt least 30 male means that you have to add probs of 30, 31, 32, ...,80.  It's easier to add probs of 1,2,...,29 and subtract from 1.\n\n80 is a large enough number to use the normal approximation.\n\nFor the normal, the mean would be 80/2 = 40.  So, at least 30 is\n\n1-P(X<less than 30) \n\nconvert X to Z to use standard tables.
814472
p stands for probability and it is less than 0.1%
905517
I answered this question for jc yesterday!  Search for questions to find the answer.\n\n\nJust integrate p(x) along the rod.
887177
1. probabilty of getting a value that extreme in truth if the null hypothesis is true\n2. 1. null hypothesis is false \n    2. null hypothesis is true and there's another factor at work\n3. conclusion: it is likely that you should reject the null hypothesis\n4. wtf
508493
I've found that the Wikipedia articles on probability distributions are top notch and contain enough information for you to solve this problem on your own.\n\nHint: solve the algebraic expressions that relate mean and variance so you can express p or n as algebraic relationship of one another and then do some substitions.\n\nAt first I thought you needed to know p or n up-front however I realize that you have all the info you need to solve this problem algebraically.\n\nGood luck with your homework.
784392
Here is what i found.  I'm not sure how right this is, but you can check it out.  Good Luck with your testing.