please help with this equation!?
595646
Make this into a equation\nit takes $20 + $0.50 x (x being the number of treats)\nThe second equation is 1.50x to get the profit\nnow you set them equal to each other and solve for the intersection point
929562
∫ax(2 -x)dx\n= ∫(2ax - ax²)dx\n= 2a * ½x² - a * ⅓x³ + c\n= ax² - ⅓ax³ + c
647266
(Ok, by the way, this is not a linear equation. A linear equation is when the equation includes "x" and "y")\n\nBefore you can get the answer, you have to obviously solve it. \nSo for this equation, you want to get the variable alone; to one side. Now looking at the equation, everything isn't simplified. The left side is, you can not do anything with "x" and "-15"...Though, on the right side, there are like terms (expressions/terms that can be simplified)..."x" and "2x" become 3x. See 1x (1x is same as x) plus 2x equals 3x. So now your equation is x-15=3x+1 Now that everything is simplifed, you can solve it. As I said, get the variable to one side. Usually, the variable is on the left side of the equation, but it doesn't really matter which side its on...So to get x alone from the left side, you have to do what to get rid of NEGATIVE 15?...Do the opposite, POSTIVE 15, which then cancel each other out and x will be left alone. However when you add 15 to the left side, you have to add 15 to the right side. So adding 15 to the right side, 3x+1+15= 3x+16...Now the equation should be x=3x+16. So now, you have to get the 3x from the right side to the left side. How do you get sixteen alone? You minus 3x from both sides. The right side will result with having just 16 as the other side will have -2x. The equation is ow -2x=16. Again, get x alone. And how to do that is divide -2 to both sides. So -2x divided by -2 is 1x or just x and 16 divided by -2 is -8. At the end you should have x=-8\n\nHere's the work:\nx-15=x+2x+1\nx-15=3x+1\nx-15+15=3x+1+15\nx=3x+16\nx=3x+16-3x\nx-3x=16\n-2x=16\n-2x/-2=16/-2\nx=-8\n\nAnd the "check" works too(when you plug in -8 as x)\n\nx-15=x+2x+1\n-8-15=-8+2(-8)+1\n-23=-8-16+1\n-23=-23
888367
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
1001971
[(16x*2-25) / (24x*2-30x)] / [(8x*2-2x-15) / (6x*2-7x-3)]\n= [(16x*2-25) / (24x*2-30x)] [(6x*2-7x-3) / (8x*2-2x-15)\n= [(16x*2-25) (6x*2-7x-30] / [(24x*2-30x) (8x*2-2x-15)]\n= [(4x-5) (4x+5) (3x+1) (2x-3)] / [(6x) (4x-5) (4x+5) (2x-3)]\n= (3x+1) / 6x
1117062
if ur just solving that equation...u dont need to switch the sign.....\nwatch (im not gonna have the equal sign on the bottom takes too long). \n\nx-1<-3\n(add one to both sides now)\nx<-2\n\nthers ur answer
956102
Here is the equation\n\n(246,92)U ---> (4,2)He + (242,90)Th + 2Gamma
842934
Ok, first you must get the -8 and the x/-2 out of parentheses, so u just multiply them both by one. So then is -8 * x / -2. First, you do -8 * x, which is -8x. The problem then becomes -8x / 2. In this step, just don't mind the negative or the x and just put them back in at the end. So you're really just doing 8 / 2, which is 4. You must put the - and the x back in, so the answer is -4x. Ta Da!
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
412953
An equation that is incorrect.
990847
isolate the variable\n\n-7x+1+8x=x+1\n-7x+8x=x\nx=x\nx=1\n\nthe answer is c) 1\nnow give me 10 points please!!!
714589
x/(x+3) - 2(x-1)/(x+3)(x+2)\n\nx(x+2) - 2 (x-1)\n--------------------\n   (x+3) (x+2)\n\n\nx^2 +2\n----------\n(x+3)(x+2)
736379
for this just substitute for x and y in eqn and see if LHS=RHS\nLHS=4\nRHS=(-1/2)(-3)-5/2\n=3/2-5/2\n=-2/2\n=-1\nnot = RHS\nso pt. not on line
437832
Homework.\n\nSuppose a1*x+a2*Tx+..+am*T^(m-1)x=0.\n\nApply T^(m-1) to get a1=0.\nApply T^(m-2) to get a2=0, etc.
891679
I assume your x is in the denominator, but the -c is not.\n\nOriginal equation:\na / (bx) - c = 0\n\nAdd c to both sides:\na / (bx) = c\n\nMultiply both sides by bx:\na = cbx\n\nDivide both sides by bc:\na / (bc) = x\n\nx = a / (bc)
73319
the earlier equation is not balanced.\nCaO + 2HCl --------> CaCl2 + H2O
605867
(x^2)/2 - 3(x^(3/2))/(3/2) + c = (x^2)/2 - 2x^(3/2) + c