Is it thermodynamically feasible for elemental sulphur to react with oxygen to give sulphur trioxide?
611744
Under high heat or pressure, yes\nAt STP, no
167656
the correct answer is B. A is wrong b/c it isn't an oxidation reduction reaction. Looking at a table of solubility products will confirm the answer is B.
157730
I think FePO4 +O2 >>>>> Fe2O3 + PO2. balance it and solve it . n its simple stoichiometry.
170129
CuSO4 (s)  --H2O-->  Cu+2 (aq) + SO4-2 (aq)
729584
1)SO2, the sulfur, when it burns in air reacts with the O to form SO2. When Mg burns in air it reacts with the O and the N in the air and forms both MgO and Mg3O2. The product SO2 is a gas and MgO and Mg3O2 is a solid.\n\n2)It is ionic. Ionic bonds form between a + ion and a - ion. Na is + and F is -.\n\n3)P with O is covalent. Both elements are negative ions so they share. You need a + and a - to be ionic.\n\n4)No! Lots and lots of liquids. Some solids also.\n\n5)O and S are in the same groups because they both have 2 electrons in their outer shells. P and S are next to each other because they both have the same number of energy levels (3).\n\nGet an "A".
953209
Yes . but when the reaction begins, these temperatures will equilibrate\n\nIt is sometimes not possible to react if one compound is solid and the other is liquid
895580
Mercury(II) oxide decomposes into its elements when heated.\nThere is no way that you would know this unless you had been taught about thermal decomposition. So all you need to worry about is the correct formula of oxygen gas.\n\nTherefore 2HgO --> 2Hg + O2.
1158402
No. Think about connections. CH3-CH2-O-S-O3H. The ethyl must bind to an oxygen, not the hydrogen. [CH3CH2]- [HSO4]+ would seem to be the right "ionic" form, but these aren't ions.\n\nYou need to show that the hydrogen is on one side of the sulphur and the ethyl is on the other side, and each of them are connected through oxygens.
747354
A reversible reaction can go in both directions.\nAn irreversible reaction cannot.\n\nAn example of a chemical reaction that can go in both directions could be the reactions between rust, hydrogen and water.\nPassing hydrogen gas over rust yields iron and water.\nFe3O4(s) + 4H2(g) --> 3Fe(s) + 4H2O(g)\nBut passing steam over hot iron produces rust and hydrogen.\nFe3O4(s) + 4H2(g) <-- 3Fe(s) + 4H2O(g)\n\nMany oxidation reactions cannot reverse.  For example, burning charcoal on the BBQ will produce ash, CO, CO2 and heat.  However, you cannot use CO2 and ash to make charcoal.  This example is irreversable from a thermodyamic point of view.  Heat is generated from the reaction, yet heat cannot be used to go in the other direction.\n\nReversable thermodynamic processes usually involve a change of state.  You can add heat to change ice to water or water to steam.  Take heat away and you change water to ice.
1103908
you mean into a chloride?\neasy just add concentrated hydrochloric acid.the chloride will precipitate. and the sulfate will come out as hydrogen sulfide gas and water. maybe you need hydrogen to be passed in the mixture.\nna 2(so4)   + hcl  =      nacl   + h2s  + h2o
571388
Cu + 2H2S04 --> CuSO4 + SO2 + 2H20\n\nCu (copper) is oxidized, because it loses 2 electrons to enter into the +2 state.\n\nThe sulfuric acid is the oxidizing agent, because it oxidizes the copper and is itself reduced to form sulfur dioxide. (Compare the oxidation states. Half of it remains as SO4- because it takes 2 equivalents of H2SO4 to react with Cu, due to the mole to mole ratio.)\n\nI'd do this reaction in the fume hood, though. SO2 is an irritant to your lungs.
832783
e.g. of formula: Magnesium+oxygen=magnesium oxide\ne.g. of Mixture: Air\ne.g. of Compound: Magnesium oxide
320284
It is not possible.  Observe the chemical equation:\nAg2SO4(s) + AgNO3(s) --> Ag2SO4(s) + AgNO3(s)\n\nIn order for a substance to dissolve, it must be in an aqueous solution.
405797
heat the pure gas in a sealed tube in absence of air. it breaks up into its components. you've got solid yellow sulphur.
750179
NaCl2 + NaCO3 ==> NaCO3 + NaCl2 NOTE: these two reactants will not react because the reactants and the products are identical\n\nCu + O2 ==> CuO2   This is already balenced\nCuSO3 + Fe ==> FeSO3 + Cu   The charge is not given so procuts could be different\n\n2HCl + 2Zn ==> 2ZnCl + H2\nMnO2 + H2O2 ==> No reaction: similar to NaCl2+NaCo3\n\nGood luck
387221
B2O3(s)+Mg(s) yields MgO(s)+B(s)\nNotes: yields should be substituted with an arrow that is read as yields and in diboron trioxide the numbers are subscripts not superscripts.
893375
I think the reactants that you've listed my be wrong or balanced correctly to give a possible vanadium oxide.  Please check out: http://www.webelements.com/webelements/elements/text/V/key.html\n\nThis site lists all 5 possible vanadium oxides (right side half way down the page)\n\nThe most is likely is vanadium (III) oxide (aka vanadium oxide or\ndivanadium trioxide) but to produce two moles the reaction would be:\n\n4V + 3O2 --> 2 V2O3