How do u find the square root of a number, please help?
596727
Figure out what other number times itself equals your number.  That's its square root.
1137789
Here are some of the things you can do to a whole number!\nNote: These can be done using a calculator\n\n1)\nAlso get the number next to it. (e.g. if you chose 5, get 6)\nmultiply them.\nmultiply the result by 4.\nadd 1.\nget the square root of it.\nSubtract 1.\nDivide by 2.\nThe result is the original number!\n\n2)\nSquare your number.\nAdd twice the original number\nAdd 1\nGet the square root\nSubtract 1.\nThe result is the original number!\n\n3)\nSquare your number.\nAdd 6 timesthe original number\nAdd 9\nGet the square root\nSubtract 3.\nThe result is the original number!\n\n4)\nSquare your number.\nMultiply by 4.\nAdd twelve times the original number\nAdd 9\nGet the square root\nSubtract 3.\nDivide by 2.\nThe result is the original number!\n\n5)\nNote: Here, you must choose a single digit whole number.\nmultiply it by 37.\nAdd the digits of the result.\nContinue adding the digits of the result until you get a single-digit result.\n(e.g. 5 x 37 = 185, \n1 + 8 + 5 = 14, \n1 + 4 = 5)\nThe result is the original number!\n\n\n6)\nAlso get the next two consecutive whole numbers.\nmultiply the first and the third.\nsubtract the square of the middle term.\nThe answer is always 1!\n\n7)\n(note: you must choose here a 3-digit whole number)\nmultiply it by 7\nmultiply it by 11\nmultiply it by 13\nThe result is the number repeated!\n\n8)\nnote: you must choose a single-digit whole number\nAdd 3\nMultiply by 2\nsubtract 1\nMultiply by 5\nAdd 580\nRemove the tens digit of the result.\nThe result is always 65.\n\nFrom here, you will no longer choose a number\n9)\n9 x 9 + 7 = 88\n9 x 98 + 6 = 888\n9 x 987 + 5 = 8888\n9 x 9876 + 4 = 88888\n9 x 98765 + 3 = 888888\n9 x 987654 + 2 = 8888888\n9 x 9876543 + 1 = 88888888\n9 x 98765432 + 0 = 888888888\n\n10)\n1/7 = 0.142857 142857 142857 ...\n2/7 = 0.285714 285714 285714 ...\n3/7 = 0.428571 428571 428571 ...\n4/7 = 0.571428 571428 571428 ...\n5/7 = 0.714285 714285 714285 ...\n6/7 = 0.857142 857142 857142 ...\nNotice that each is a repeating pattern of 142857\n\n^_^
154621
If you mean 100 inside a square root symbol, the answer is 10.  However, if you mean the true square roots (as opposed the result of the square root function) the answer is 10 or -10.
623537
a times the square root of 2\n\na squared + b squared = c squared \n\nwhere a and b are the legs and c is the hypotenuse\n\nso if the legs are both a it's a squared plus a squared = c squared\n\n\nso 2*(a squared)=c squared\n\nso to find c you take the squared root of each side\n\nc = a times the square root of two
1122465
Just plug in 1 for x.\n√(1-1) = √0 = 0
24161
The square root of a negative number is an imaginary one.  The square root of -1 is known as i.  Negative square roots work out like positive ones, only with the i, so SqRoot(-4) = 2i and SqRoot(-64) = 8i.
546400
D=square root ((x1-x2)^2 + (y1-y2)^2)
544837
I squared the 7 to start with and got 49.  I am also only showing the addition version, you can do the subtraction later yourself.\n\n(-7 + sqrt(49 - 4(9)(-1)))/2(9)\n(-7 + sqrt(49 - -36))/18\n(-7 + sqrt(49 + 36))/18\n(-7 + sqrt(85))/18\n\nand I think that that is it.  You cannot simplify the square root.
51084
Just as the reciprocal of the number 2 is 1/2, or 0.5, the reciprocal of the square root of 2 is the square root of 1/2.  This is represented numerically as 0.707106781186...  Try it again, this time using numbers which will yield whole-number results.  For example, take the number 64.  The reciprocal of 64 is 1/64 or 0.015625.  The square root of 64 is 8, and the reciprocal of 8 is 1/8 or 0.125.  Note that the square root of 0.015625 is 0.125.
21852
Square Root of negative 11\n= √-11\n= √(11 * (-1))\n= √(11 * i                       since √-1 = i.\n= 3.31662479035539984911493273i
256504
because 56 is not an even root the best answer is=\n(n-squareroot of 56)(n+squareroot of 56). \nThe square root of 56 is 7.48331477355 if you need the exact number, but that's messy.
484362
Square root of 81 ...
1175507
square root of 2\n\nif 2 = x^(x^(x^...))\n\nthen 2 = x^ 2\n or x = √2\n\n[i hope you were truthful about the first answer gets the points....]\n\n\nI have an interesting follow up question however.  What if the quantity equals 4?  Then 4 = x^4 or x = 4^(1/4) = 2^(1/2) = √2 !!!  \n\nSo.. √2^(√2^(√2^(√2^...))) = 2 and √2^(√2^(√2^(√2^...))) = 4\nso...  2 = 4\nHow can this be??!!!!!\n(obviously its not.  where's the flaw?)
998294
square root of 13 is the answer
766787
If this is a problem in a math class, the answer provided by abcde12345 is correct. He shows you the technique to simplify it, which is to multiply numerator and denominator by the "conjugate" of the denominator (which just means you change the sign of the square root part, so you get (3 - sqrt(5)).\n\nIf this is a problem in physics or some other class, and all you need is a value, then follow the suggestion of some others who recommend using a calculator.
358881
http://www.nist.gov/dads/HTML/squareRoot.html\nhttp://www.math.com/students/calculators/source/square-root.htm\n\nI hope it will help
737774
You figure the square root of each number separately...you've probably learned that in class alredy (how to do that)...then you take reach result, and multiply them together for your final answer.\n\nUse your textbook for reference...good luck!