what is the mass of a nickel.?
603614
The mass of a nickel is a 5.02 g. Its density is 8.90 g/mL!\n\nI hope I'm first!
730167
Very close to the mass of a proton.  It is about 1.6749 x 10^-27 kg, 1 u, or 939.57 MeV/c^2.
885270
Atomic number\n 8\n \nAtomic mass\n 15.999 g.mol -1\n \nElectronegativity according to Pauling\n 3.5\n \nDensity\n 1.429 kg/m3 at 20°C\n \nMelting point\n -219 °C\n \nBoiling point\n -183 °C\n \nVanderwaals radius \n 0.074 nm\n \nIonic radius\n 0.14 nm (-2)\n \nIsotopes\n 4\n \nElectronic shell \n [ He ] 2s 2 2p 4\n \nEnergy of first ionisation\n 1314 kJ.mol -1\n \nEnergy of second ionisation\n 3388 kJ.mol -1\n \nEnergy of third ionisation\n 5300 kJ.mol -1\n \nDiscovered by\n Joseph Priestly in 1774
428368
(m)\n\nOne kilo equals 2.2 pounds
1080952
mass, volume and temperature.
871516
mass of the object\nforce of the magnet in a magnetic field\nthe object's own interference with the magnet
1021893
Weight of US coins:  \n\nPenny Standard weight 2.5 grams\nNickel Standard weight 5.0 grams\nDime Standard weight 2.268 grams\nQuarter Standard weight 5.670 grams\n\nSo, you would only need 1/5 of a nickel to weigh a gram.
304984
I would need more information to help you answer that question.\n\nWhat is the mass of the metal being used? What was the original temperature of the metal?\n\nThe formula you need is:\n\nq = mc(Tf - Ti)\n\nq = energy change\nm = mass\nc = specific heat\nTf - Ti = change in temperature
311209
You have approximately $18.14. \n\nA penny has a mass of 2.5g. Ten pounds is 4.536 kg. This means you have 1,814 pennies. When you divide this by one hundren, you get $18.14.
636056
one coin is not a nickel. the other one is. the answer is a quarter and a nickel
612107
a. 2k+ = .20moles , SO42-=.10moles\n\nb.Fe3+=.10moles,3NO3-= .30moles\n\nc.2Al3+=.20moles,3SO42-=.30moles\n\nd. Ni2+=.10moles,SO42-=.10moles
835018
about 3000 kilo J\nit depends on the atom
836906
I had to read about this in order to answer your question at this web site:\n\nhttp://home.um.edu.mt/chemistry/CH230/2.Analytical/CP210a.PDF\n\nSo, two moles of DMG combines with each Ni++ ion.\n\n(0.2145 g Ni)* (1 mole Ni/58.71 g Ni) = 3.65*10^-3 mole Ni\n\nIf what you tell me is correct that DMG is 116.1194 then the Ni complex which loses 2 H+ for the Ni++ has a molecular wt of\n172.8134 (please double check)\n\n(3.65*10^-3 mole Ni)* (172.8134 g/mole) = 0.6314 g\n\nplease check for errors
991058
mass =concentration\n-------\nvolume
824559
Mass is measured in grams.
699905
mass initial = Mi\nmass final = Mf\n\nMass growth = Mf - Mi\nPercent growth = Mf/Mi * 100
666681
1/2 * mass * velocity^2.