How many different ways can you make one dollar with 21 coins.  US.?
602150
There are 20 nickels in a dollar, so we know we are going to have to resort to pennies.\n\nLet's try 20 pennies... Hmm, no single coin makes 80 cents, so that won't work.\n\nOkay let's try 15 pennies.  Now we need 6 coins to make 85 cents:\n1 half-dollar, 1 quarter, 3 nickels... no good only 5 coins\n1 half-dollar, 1 quarter, 1 dime, 1 nickel... no good, 4 coins\n1 half-dollar, 3 dimes, 1 nickel... 5 coins\n1 half-dollar, 2 dimes, 3 nickels -- YES!\n\n3 quarters, 1 dime... bad, 4 coins\n3 quarters, 2 nickels... bad, 5 coins\n\n2 quarters, 3 dimes, 1 nickel -- YES!\n2 quarters, 2 dimes, 3 nickels... bad, 7 coins\n\n1 quarter, 6 dimes... bad\n\nOkay let's try 10 pennies.  Now we need 11 coins to make 90 cents:\n1 half-dollar, 1 quarter, 3 nickels... bad\n3 quarters, 3 nickels... bad\n2 quarters, 8 nickels... bad\n1 quarter, 6 dimes, 1 nickel... bad\n1 quarter, 3 dimes, 7 nickels... eleven coins -- YES!\n9 dimes... bad\n7 dimes, 4 nickels... eleven coins -- YES!\n\nOkay let's try 5 pennies.  Now we need 16 coins to make 95 cents:\n\n1 half-dollar, 9 nickels... bad\n3 quarters, 4 nickels... bad\n2 quarters, 9 nickels... bad\n1 quarter, 14 nickels... bad\n9 dimes, 1 nickel... bad\n3 dimes, 13 nickels... 16 coins -- YES!\n\nSo the answers are:\n1 half-dollar, 2 dimes, 3 nickels, 15 pennies\n2 quarters, 3 dimes, 1 nickel, 15 pennies\n1 quarter, 3 dimes, 7 nickels, 10 pennies\n7 dimes, 4 nickels, 10 pennies\n3 dimes, 13 nickels, 5 pennies\n\nThere are FIVE (5) ways to make one dollar with 21 coins!
372189
You can't. There are no $2 coins
877044
$1.19 - 3 quarters, 4 nickels, 4 pennies\n\nThe people above me who have changed there answers are cheats and should be reported as such !
500049
Hey.. Try Google calculator..\n\n25 U.S. dollars = 13.2534592\n\nhttp://www.google.com/search?q=25+dollars+in+sterling&btnG=Google+Search
208226
A dollar is 100 cents (pennies).  Consequently, a half dollar is 50 cents and a quarter dollar is 25 cents.\n\n.0296 x 1 dollar is about 3 cents which is 3% of a dollar - not enough to buy a piece of gum.\n.0018 x 1 dollar is much less than a single penny - basically nothing.\n\nWhat is your currency? I assume it is not US dollars so it might help you better understand if you convert .03 dollars into your money.  Try: http://www.xe.com/ucc/
515499
one dollar.\n\non 26th you got 1 dollar, so on 25th you got \n (1+1)/2=1\nsimilarly, on 24th ,23rd etc, you got only one dollar. \n\n(God, that's cheating, allowance should go higher!!!!!)
939247
No, but you can work it out on paper. I know because I did it once. You have five letters, so there should be 25 combinations, Of course, as two letters are the same that would make it 20. I think. Just give it a go. It's always more fun to work these tings out yourself.
532805
There is no missing dollar. You can't add them together that way. $25, the right price, plus the $2 the dishonest bellhop kept, plus the three $1's each man got, equals $30.
263065
40 pennies, 8 nickels, 2 dimes  \n\nor\n\n45 pennies, 1 quarter, 2 dimes, 2 nickels
259226
here's one with coins that was on one of the worksheets i have:\n\nlet's say, for example, that you have $8.75 in dimes and quarters and there are 65 coins. how many dimes and quarters are there?\n\nso there would be 2 equations:\nd+q=65 (which is how many coins there are)\n\nand\n\n10d+25q=875 (how much money there is in dimes and quarters)\n\nfrom there, you'd solve it up and down like\n\n 10d+25q=875\n+  d+  q= 65 (Multiply by 10)\n---------------------------\n 10d+25q  =875\n+(-10d-10q=-650)\n-----------------------\n       15q= 225\n         q=15\n\nthen you plug in 15 for q for one of the equations.\n\n15+d=65\n65-15=50\nd=50\n\nyou'd have 50 dimes and 15 quarters. (i hope)\n\ni also hoped this helped ^^;
729692
20 pennies\n15 pennies and a nickel\n10 pennies, two nickels\n10 pennies, one dime\n5 pennies, three nickels\n5 pennies, one nickel, one dime\n4 nickels\n2 nickels, one dime\n2 dimes
974209
Four pennies\nTwo Nickles\nOne Dime\nOne Quarter\nOne Half Dollar\n\nThough you really need one coin (a dollar coin) -- since you don't specify that it has to be paid for with exact change.
896257
1. \nLet n be the number of nickels\nLet d be the number of dimes\nLet q be the number of quarters\n\nNumber of coins is 30:\n#1) n + d + q = 30\n\nThere are twice as many nickels as quarters:\n#2) n = 2q\n\nTotal value of the coins is $3.35.  (Use the value in cents, rather than dollars).\n#3) 5n + 10d + 25q = 335\n\nThree equations and three unknowns...\n\nSubstitute #2 into #1:\nd + 3q = 30\nAnd into #3:\n10d + 35q = 335\n\nNow solve for d:\nd = 30 - 3q\n\nSubstitute into the last one:\n10(30 - 3q) + 35q = 335\n300 - 30q + 35q = 335\n5q = 35\nq = 7\n\nPlug q back into d = 30 - 3q:\nd = 30 - 3(7)\nd = 9\n\nPlug q back into n = 2q\nn = 2(7)\nn = 14\n\nSo you have 14 nickels, 9 dimes, 7 quarters\n\n(As a double check --> 0.70 + 0.90 + 1.75 = 3.35)\n\n2. \nKaren is Anthony (statement #3)\nSince Karen is Anthony, John must be Juliet (statement #1)\nBeth is not Cleopatra, so she must be Romeo (statement #4)\nThat leaves Dan to be Cleopatra.\n\nFinal result:\nKaren = Anthony\nJohn = Juliet\nBeth = Romeo\nDan = Cleopatra\n\nThose cross-dressing friends...
596652
I used to do that before I decided what a pain in the neck it was and took the 8-9% hit from going to the change machine at the market.\n\nI got a box top and raised the big flat side up with a book at an angle.  Then I counted out the coins and laid them in the groove made by the side of the box top, and marked the spot where the required amount ended,  and then pushed the wrapper along the coins, then scooped it up and tidied up and folded the ends down.  Repeat, but you don't have to count the coins anymore because you marked the spot where they ended for that amount.\n\nThere are gizmos you can buy that "count" the coins by allowing only so many in the various columns and then you can slip the wrapper along the columns....
789401
Let's see.\n\nTwo dimes and one nickel\nOne dime and three nickels\nFive nickels.\n\nYou can have five pennies in place of one nickel in any of the above sitiuations.\n\nSo you could have:\n\nTwo dimes and five pennies\nOne dime and two nickels and five pennies\nFour nickels and five pennies.\n\nBut once again, you can have five pennies in place of one nickel in any of the above sitiuations. (Now, D = dime, N = nickel, P = penny)\n\n1D, 1N, 10 P\n3N, 10P\n\nOne more time\n\n1D, 15P\n2N, 15P\n\nAnd again:\n\n1N, 20P\n\nOne last time\n\n25P\n\nI count 12 ways.
696335
You're buying digits.\nEach digit cost 5 cents.\n1 is one digit.\n21 consists of 2 digits.\n347 consists of 3 digits.
627773
1,2,5,10,20,50,100.\n\nSo that's 7.