what is the water viscosity at 45°C?
603098
Viscosity of water at 40°C = 653.2 micropascal-seconds\nViscosity of water at 50°C = 547.0 micropascal-seconds\n\nThe value at 45°C is about 600 micropascal-seconds
470314
the specific gravity of water is 1.
193114
watertemps of 60 and better
74375
45 Degrees = an Acute Angle of an Isosceles Right Triangle
791970
Use the Gay-Lussac gas law: V/T is constant. Note that T here is the temperature in Kelvin, not in Celsius. Luckily 27 C = 300 K
941617
The Specific Gravity of water is 1
976635
Don't even worry about the rock yet. The ball takes a certain time to drop 45m vertically and in that time it goes 30m horizontally. Air resistance is negligible so the horizontal velocity is constant. In the vertical direction, the ball starts motionless and accelerates and 9.81 m/s^2.\n\nTime to fall 45m\n45 = (1/2)(9.81)t^2\nt = 3.0289s\n\nhorizontal velocity:\n30 = 3.0289*v\nv = 9.9m/s
489685
Near about\n50 μΩcm\nat 20°C.
780066
V = nRT/P\nV = (25g/44g/mol)(0.08206Latm/molK)(298K)/1atm\nV = 138.9 L
763787
For the temperature of 277K (4 degrees Celsius) it is 1000kg/m^3, so it is 1kg/dm^3 (dm^3 is one liter), 1g/cm^3 (cm^3 is one milliliter). 4 degrees Celsius is the temperature of the highest density of water.
760588
Above is correct for G, with reference to water surface .... G is zero at final moment when student touches the water.\n\nFor E its zero at intial moment but not at final. Infact it is max at final moment coz that's where the extension is max.\n\nK is zero both at final n intial moments becoz at both times speed or velocity magnitude is zero, hence no KE
68502
3.6 J ml-1 (°C)-1; at a haematocrit of 45 %
700759
Let \nQ = volume flow rate in Litre/sec, \nD = diameter of the nozzle in cm and \nV = velocity of water in metre/sec. \n\nThen,  V = (40*Q)/ [pi*(D^2)]\n\nwhere pi = 3.14
1143445
Water has a density maxima at 4C
801823
Quantity of energy lost by the water:\n\nQ = (m)(deltaT)(c)\n    = (50.0g)(2.00 C)(4.18 JK-1g-1)\n    = 418 J\n\nSince the water got colder, the reaction was endothermic, and the enthalpy change for the reaction is +418 J.
944167
PV=nRT\nV = nRT/P\nV = (114g/44g/mol)(0.08206L-atm/mol-K)(28+273K)/0.987atm\nV = 64.84L or 0.0648 m^3
68568
Density of water at 4 degree celsius is taken as  constant 1.This is because density of water at 4 degree celsius is maximum.And at this temperature 1cc of water weighs 1 gm.