how do you factor x squared + 2xy+ y squared - 1?
602794
OK--x^2+2xy+y^2 factors to (x+y)^2. 1 is a perfect square so this is a difference between two squares. So the answer is (x+y)+1 and (x+y)-1. The parenthesis aren't necessary they are there so you can see it more easily. Now lets test. Let x=10 and y=2\n12 squared is 144 -1 is 143. If I am right the facotros are 10+2+1 or 13 and 12+2-1 which is 11. 13*11 is 143. Hope this helps.
1002101
factor 9x^2y^2-9y^2\n9y^2(x^2-1)\n9y^2(x+1)(x-1)
311407
are you trying to solve for x?\n\nFirst, find the factors for the equation.  (x+2)(x+1)\n\nCheck it to see if it's right.  x times x equals x squared. 1x plus 2x equals 3x. 2 times 1 equals 2.\n\nMake one of the parenthesis groups equal to zero.  For example, x+2 = 0   To solve this, x must equal -2.\n\nPut -2 back into the original equation and see if it works.\nNow make the parenthesis group equal to zero.  x+1=0  To solve this, x must equal -1.\n\nTherefore, the answer is using either -1 or -2 will make the equation zero.\n\nHope this helps.  ;)
343717
Let the factors be x and y, then\nxy = 15\nand x-y = 2\nSolve for x in x-y = 2 by adding y to both sides\nx = y+2\nSubstitute into xy = 15\n(y+2)y = 15\ny^2 + 2y - 15 = 0\nFactor\n(y-3)(y+5) = 0\ny equals 3 or -5.\nWe usually only talk about positive factors.\nAnswer: 3 and 5
708644
Use the quadratic formula.\nx1 = 1\nx2 = -1/2
906876
2cos^2x-1+1/2sinxcosx\n=2cos^2x/2sinxcosx\n=cosx/sinx\n=cotx
697620
x^2+y^2=(x+y)^2-2xy\nsubstituting\nx^2+y^2=3^2-2(1)\n            =9-2\n            =7\nx^2+y^2=7\nmy 10 pointsplease
10610
X^2-9X+18\n\nShort and simple just factor it FOIL
617264
Since each term has at least x in it, divide out the x by distributive property:\n\nx(x^2 - 4xy + 4y^2)\n\nThen factor the rest by FOIL:\n\nx(x-2y)(x-2y)
254834
if you use quadratic formula you get the factors of \n\nx= ( ( 3 +/- square rt.(5) ) / -6 )
259003
Use the quadratic formula.  It works everytime!\nx = (-b plus or minus sprt(b^2 - 4ac))/2\nwhere\nax^2 + bx + c = 0\nSome of these will factor, however not all of them will.
707539
x = (y^2 + 2y -1) / 2\ndx=ydy+dy\n1=(y + 1 )dy/dx\ndy/dx=1/(y+1)\nd2y/dx2 = -1 / (y+1)^2
753025
a.2xy(-15x^2y^4+8x^2-5y^2)/-4xy^3\n(-1/2y^2)(-15x^y^4+8x^2-5y^2)\n\nb.2+160-64\n=98
791199
(6x^2)/4x^2y-12xy(x^2+x-12)/3x^2+12x\n3/(2y)-4y/x(x^2+x-12)+12x\n=(3/2y)-(4x^2y-4xy+48y)/x+12x\n=[3x-2y(4x^2y-4xy+48y)+24x^2y]\n/2xy\n=[3x-8x^2y^2+8xy^2-96y^2\n+24x^2y]/2xy
848564
Substitute 2x-1 for y in the middle part, you get:\nx^2 + x -6(2x-1) = 2x-1\nThis you can reduce to a quadratic equation for x.
36762
Factor by grouping:\nx^2 (3x - 5) - 3 (3x - 5)\nAnswer: (3x - 5)(x^2 - 3)
549653
Subtract 2x from each side\n-y = 0 - 2x\nMultiply each side by -1\ny = 2x