(5/x+6)+(2/x^2+7x+6) = (3/x+1)........please help...........?
609345
The demoninator of the second term (x^2 + 7x + 6) can be factored to (x+6)(x+1), so multiply both sides by that value and watch the terms cancel out.  You get \n\n5(x+1) + 2 = 3(x+6)\n5x + 7 = 3x + 18\n2x = 11\nx = 5.5
346785
(x^2-5x+4)/(x^2-9) * \n(x^2+7x+12)/(x^2+3x-28)=\n\n[(x^2-5x+4)*(x^2+7x+12)]/\n[(x^2-9)*(x^2+3x-28)]=\n\n[(x^2-4x-x+4)*(x^2+4x+3x+12)]/\n[(x-3)(x+3)*(x^2+7x-4x-28)]=\n\n[(x(x-4)-(x-4))*(x(x+4+3(x+4)]/\n[(x-3)(x+3)*(x(x+7)-4(x+7)]=\n\n[(x-4)(x-1)*(x+4)(x+3)]/\n[(x-3)(x+3)*(x+7)*(x-4)]=\n\n[(x-1)(x+4)]/[(x-3)(x+7)]
556363
(8/x+2) + (8/2) = 5\n\n(8/x+2) + 4 = 5\n\nSubtract 4\n\n(8/x+2)=1\n\nMultiply x+2\n\n8= x+2\n\nSubtract 2\n\nx=6
40442
(2/X+5)+(3/X+4)=(2x/x^2+9x+20)\n\nX = -.341296
712395
9x+5/(x-4)+(-7x)/(x-4)\n=9x+5-7x/(x-4)\n=(2x+5)/(x-4)
581691
if by this you mean\n\n((x^2)/2) - ((7x)/4) = (-3/2)\n\nMultiply everything by 4\n\n2x^2 - 7x = -6\n2x^2 - 7x + 6 = 0\n(x - 2)(2x - 3) = 0\nx = 2 or (3/2)\n\nANS : x = 2 or (3/2)
781088
Plug in 2 for x to determine this:\n\n3(2) + 5 = 6+5 = 11 ≠ 17\n\nTherefore 2 is not a solution.\n\n~ ♥ ~
1060834
(5x+2)/3 -(2x+4)/6 = -4/3\n\nMultiply everything by 6:\n\n10x + 4 - (2x+4) = -8\n10x + 4 - 2x - 4 = -8\n8x = -8\nx = -1
168359
1/3 + 1/2 = 2/6 + 3/6 = 5/6
806157
it is \n(x/3x+1/3x)/(3/3x+x/3x)=\n=(x+1)/(x+3)
572480
breaking it apart, we have:\n\n(x+1)^3=(x+1)(x+1)(x+1)=\n(x^2 + 2x + 1)(x+1) =\n(x^3 + 3x^2 + 3x + 1) SO\n6(x+1)^3 = 6(x^3 + 3x^2 + 3x + 1) = 6x^3 + 18x^2 + 18x + 6\n\n(x+1)^2 = (x+1)(x+1)=\nx^2 + 2x + 1   SO\n-3(x+1)^2 = -3(x^2 + 2x + 1)=\n-3x^2 - 6x - 3\n\n4(x + 1) = 4x + 4\nand -9 stays the same.\n\nSo putting everything together, you have\n(6x^3 + 18x^2 + 18x + 6) + (-3x^2 - 6x - 3) + (4x + 4) - 9 \ncombine like terms and you get:\n6x^3 + (18x^2 -3x^2) + (18x - 6x + 4x) + (6 - 3 + 4 - 9)\n6x^3 + 15x^2 +  16x - 2\n\nWHEW!  That took me back to college pre-calc!
939068
Is this one problem?  If so, you can solve it like this:\n\n(a/b) / (c/d) = (a/b) * (d/c)\n\n~ ~ ~ ~ \n\n( (x² - 4) / x² ) / ( (x²+5x+6) / x ) = \n\n( (x² - 4) / x² ) * ( x / (x²+5x+6) ) = \n\n( (x² - 4) * x) ) / (x² * (x²+5x+6) ) = \n\n( (x² - 4)  / (x * (x²+5x+6) ) = \n\n{{ now notice you can factor your quadratic equations, to get the following }}\n\n(x+2)(x-2)  / (x * (x+2)(x+3) ) = \n\n(x-2) / (x(x+3))\n\nHope that helped!\n\n~ ♥ ~
934083
-3/4 x +5 = 2/5 x -7\n5+7= (3/4 +2/5) x\n      = (15+8)/20 x\n12  =23/20 x\nx= (20*12)/23=240/23\n\nif u mean -3/(4 x +5) =2/(5x -7)\nthat will be:\n-3(5 x-7) = 2(4 x +5)\n-15 x +21 = 8 x +10\n21-10=(8+15)x\n11 = 23 x\nx=11/23
1000586
# 1    \n(x+1)*(x+6)=x2 +x+6x+6=x2 +7x +6\n#2\n(y-6)*(y-5)= y2-5y-6y+30= y2-11y+30\n#3\n(a-2) * (a+10)=a2 +10a-2a -20= a2  +8a -20\n#4\n(x-1) *(x+1)= x2 -x+x -1= x2 - 1
1133153
7 - 2[4-6+2x] - 8+ x=6\n\n7 - 2[-2+2x] - 8 +x =6\n7 + 4 - 4x - 8 + x =6\n3 - 3x = 6\nx = -1\n\nDon't listen to the math goober - plug the value in and check it.
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
846363
3x² + 6 + 10 - (3x² - 8x - 5)\n\n3x² + 6x + 10 - 3x² + 8x + 5\n\n3x² - 3x² + 6x + 8x + 10 + 5\n\n0 + 14x + 15\n\n14x + 15\n\nThe answer is 14x + 15\n\n- - - - - - -s-