to get  specific gravity of an object (metal) 48gms, do I weigh in air and then weigh in 48 mls of water?
613715
First find the volume of the object, i.e metal, by placing it in water and then u know the amount of water displaced.\nIf it displaces half the water than it's weight, then u know that it's specific gravity is twice that of water.
70889
convert to Newtons from mN, then divide by gravity because F=mg. so you get .00000780/9.8
995159
Use the atomic weights of the individual elements, and add them together.  For instance, if I had water, H2O:\n\nH - 1.01 g * 2 = 2.02 g\nO - 16.00 g\n\nSo the molar mass of H2O would be 18.02 g/mol.\n\nIf I wanted to convert from grams to moles, I would divide the grams by the molar mass.  Grams cancels out to be left with moles.\n\nIf I wanted to convert from moles to grams, I would multiply the moles times the molar mass.  Moles would then cancel out to be left with grams.
344788
hey man, dont worry ill help. first of all our given:\nh=280m\nsg=1.03\ngc=9.7m/s^2\n\nreq'd Pressure(absolute)\n----------------------------------------------\nsol'n:\nfor DENSITY of subs:\nformula\nSpecific Gravity=density of subs/density of water\ndensity of subs=1.03 x 1000(density for water)\ndensity of subs=1030 kg/m^3\n\nFOR PRESSURE GAGE:\nP(gage)=Vh\nP(gage)=density x gravitational constant x height\nP(gage)=1030 x 9.7 x 280\nP(gage)=2,797,480 Pa\n\nFOR PRESSURE ABSOLUTE:\nP(abs)=P(gage) - P(atm)\n\nwhy minus? bec. the submarine is pressurized, meaning its vacuumed\n\nP(abs)=2,797,480 Pa - 1atm(101.325x10^3 Pa)\nP(abs)=2,696,155 Pa\n\nconvert Pa to Kpa\n=2,696,480 /1000\n=2,696.155 Kpa\n\nconvert to bar\n=2696.155kPa x (1.01325 bar / 101.325 kPa)\n=26.96155 bar\n\ndont mind the others, they dont even know how to answer this simple question. They just want to earn points!
973894
float as mercury has a density of about 13.6gm/cc and iron much lesser 7.85gm/cc. Mass is immaterial as  in a sufficient quantity of mercury even a 1000000000000kg iron ball will float
810641
Use Archimedes's buoyancy principal.  The weight outside represents the response of mass to the Earth's gravity.  The weight in water represents the displaced water's weight.  Use the ratio to get the answer.  HINT: if you convert to mass, the answer almost gives itself away.\nThe displaced water has a well known density.  That density will give the volume of the both the displaced water and the object displacing it.
606521
Try this:\n\nhttp://education.yahoo.com/reference/weights_and_measures/
1044460
There are many different ways of doing this:\n\nUsing some sort of scale that will tell you "this has a mass of 357 grams"\nUsing a balance - place the object you want to find the mass of on one side, place masses of known weight on the other until the two sides balance.\nIf you know the density, you can immerse it in a liquid, measure the volume of liquid that is displaced, and then find the mass based on that.
836848
first you'll start with Q=m*c*delta t to get the total energy of the aluminum. divide the grams of aluminum by its molar weight and then use Q=m*c*delta t where the Q's are the same, c for the water is 4.18 J/gC and then solve for the mass. good luck!
182763
mrcury...cause mercury has more specific gravity than a steel and water, meaning to say mercury will settle down and steel will float on it ...i think water has 1 s.g and mercury has 13.6 s.g. not sure bout steel...
90516
This can be done with a density gradient column.  It is made of 2 fluids that are carefully mixed so that the density of the mixture varies from the top of the container to the bottom.  An object will then come to rest where its density matches the mixture.  This is actually a very accurate way of determining the density of materials.  However, over time the fluids in the column mix by diffusion and will eventually cause the suspended objects to sink or float.
734516
Easy.  \n\nYou have q = mass * specific heat * change in temp.\n\nFind the specific heat of water and your set.  Q is joules so you need to convert.
572696
density of pure water is 62.4 lbs/sq ft.\n\nSo, load = dAgh\n\nor A = 40000/(62.4*5*32) = 4.01 sq ft.
976396
1 G, I dont see how it can be zero otherwise it would float off!\n\nOK call me an idiot...I have just read the other answers lol
1006390
You need to know the density of whatever it is you want to convert.  1 ml of water at 4 degrees C is has a mass of 1 g or 1000 mg.  To convert any other liquid you must multiply by the specific gravity or density.
588958
the weight will be according 2 density of the material \n\nfor example for water 1  liter wighs 1 kg
92955
The mass of an object is NOT the same as the weight. \n\nWeigh the object. In the avoirdupois system the weight is in pounds. In the metric system, the weight is in newtons. \n\nDivide the weight by the local acceleration of gravity (roughly 9.8 m/sec^2 for the metric system, and 32 ft/sec^2 for the avoirdupois system). The result is the mass of the system. In the metric system, the unit of mass is the kilogram. In the avoirdupois system, the unit of mass is the slug. \n\nThe local acceleration can vary from location to location on the earth, so one way to estimate the local acceleration is by using an object of known mass. Weigh the known mass, and divide its weight by the known mass to find an estimate of the local acceleration. \n\nThere are many other methods for finding the mass including multiplying the volume of the object by its density. The volume can be found by measuring it, or submerging the object in water (or other liquid) and measuring the amount of displaced water (or liquid).\n\nGravitational mass is the same as inertial mass, for unknown reasons, so one could also devise methods that estimate inertial mass. For example, one could measure the centrifugal force on a string attached to the object while it is being spun (by introducing a spring in between, and measuring the stretch of the spring, for example). One could stage an elastic impact between the object and another object of known mass, and knowing the velocities before and after impact, compute the mass of the object. \n\nThere are many many other methods one could use.