I need to know the angles of a right angled triangle where the lines either side of the 90degrees are 60 &120?
610337
phi1 = atan(60/120) = atan(0.5) = 26.57 degr\nphi2 = atan(120/60) = atan(2) = 63,43 degr
477225
Since angle in a semicircle is right, angle (APB) = 90 \n\n=> APB is right angle triangle with hypotenuse as AB = 10 cm and other side AP = 6 cm,\n\napplying Pythagoras theorem,\n\nBP^2 = AB^2 - AP^2 = 100-36 = 64 => BP = 8 cm
798165
If it's a right triangle, use the Pythagorean Theorem.\n\na^2 + b^2 = c^2\n\n\nA and B are the legs (the ones that touch the right angle), C is the hypotenuse which is opposite the right angle.\n\n10^2 + x^2 = 26\n\n100 + x^2 = 676\n\nx^2 = 576\n\nx = 24
245894
81 \nthe sum of all angles in any triangle = 180
1030296
for it to be a triangle the angles have to measure to 180, so if you have a 90 degree andlge off one, you could subtract 90 from that, take the remaining 90 and work with that, since you know your need a 1:1 of the legs , then you know you need an equal angle.. angle has to equal 90/2... and thats where i get stumped...\n      gl
889937
A triangle has 180 degrees.  a right angle is 90 degrees.  a triangle has 3 angles.
733210
You basically have 2 options. Use a protractor and measure them (The internal angles total 180 degrees).\n\nThe other option is using the trig functions (Sin, cos and tan), however you must have some info on the triangle eg. length of sides to apply any of these.
698661
[Note: < denotes angle]\n\n<A + <B +<C = 180 \n(Because, in a triangle, sum of the angles is 180)\n\n<B + <C = 180 - <A\n<B + <C = 180 - 40\n<B + <C = 140.......(1)\n\nBecause this is an isosceles triangle, AB = AC,  the angles opposite the equal sides are equal (congruent), \ntherefore <B = <C ........ (2)\n\nSubstituting value of <B from (2) to (1), we get:\n\n<C + <C = 140\n\n2 * <C = 140\n\n<C = 140/2 = 70\n\n<C is the angle opposite line AB, which is 70 degrees.
385473
x = angle\n90 - x = complement\n\nx = 4(90 - x)\nx = 360 - 4x\n5x = 360\nx = 72\ncomplement = 18\n\nThe solution checks out since 18*4=72.  So the angle is 72.
366178
Take the average between the side of an inscribed square\nand that of an inscribed hexagon. With a hexagon you\nget an isosceles triangle with base as a side and a 60\ndegree angle at the apex, leaving 120 degrees to be split\nbetween the equal pair which are then also each 60 degrees.\nSo you have an equilateral triangle whose base is equal\nto the radius of the circle and of course the base is a side\nwhich has a length of 1. \n  Now inscribe a square. There are now 4 isosceles\ntriangles with a 90 degree angle at the apex and a pair\nof 45's at the base. Draw an altitude from the apex, \nperpendicular to the base, thus bisecting the 90 at\nthe apex making another 90, 45, 45 triangle whose\nside is 1/2 the side of that of the square. The hypotenuse\nis a radius of the circle so the side of the last mentioned\ntriangle is 1/2^2 (.707). This makes the side of the\nsquare 1.414. So averaging 1 and 1.414 you get 1.207.\n Using trig we find the real answer to be 1.1755.\nSo the percentage of error is 2.67 percent from 1.207.\nI wouldn't win an engineering prize with that kind of\naccuracy, but I think I could build a pretty good\ncatapult.
534524
A nonagon can be broken into 9 isoceles triangles.\nThe vertex angles will be 360/9 = 40 degrees.\nThe two sides adjacent to the vertex have length 1 meter\nEach of the 9 triangles can be split into 2 right triangels with angles of 20 and 70 degrees.\nThe side opposite the 20 degree angle is sin(20) meters.\nThe side adjacent the 20 degree angle is cos(20) meters.\n\nEach of those triangles will have area (1/2)sin(20)cos(20 m^2\n\nThe total area of the 18 triagles combined is 9sin(20)cos(20).
865033
okay. so. there's a special set of rules for a 30-60-90 triangle.\n\nthe sides are proportional to each other by the ratio \n\nx : v/( 3)x : 2x\n\nwhere the v/ is the square root.\n\nthat means that the greatest angle corresponds to the greatest length.\n\nbecause the longest side is 7.5 meters, that means that is 2x.\n\ndivide by two for x, and that is the 30* length. (because its the smallest angle, therefore is opposite the smallest length)
563121
a right angled isosceles triangle\n\nplease give me 10 points now
544028
You have to have a right triangle.\nThen you figure out which is side is opposite or adjacent from the angle you need.
1104391
The angles in a triangle add up to 180, so the answer is b. 40 degrees.
536681
for this if you are looking for the angle you dont need the lengths of the sides.  A sail would be a right triangle therefore the largest angle would be 90 degrees.\nIf you are looking for the largest SIDE then you should use\nthe Pythagorean Theorem.  a^2 + b^2 = c^2
520768
First you need to find the slope of the line. Use the info from the slope (rise over run) to make a right triangle with hypotenuse is the line. Use inverse tangent on info from slope to find angle.