Find the slope and distance between these two points?
604791
To find the slope, represented by m, you use the formula:  \n(the change in y)/(change in x)  \nor\n(y2-y1)/(x2-x1)\nSo for (2,-3) (4,5)  x1=2  x2=4  y1=-3  y2=5\n((5-(-3))/(4-2)=(5+3)/(4-2)=(8)/(2)=4\nso m=4\n\nTo find the distance, represented by d, use the formula:\nsquare root((x2-x1)^2 + (y2-y1)^2)\n\nfor (2,-3) (4,5) d= 8.25
253663
Slope is the "change in y" divided by the "change in x" (AKA "rise" over "run").\n\n(x1, y1) = (-2, 4)\n(x2, y2) = (2, -1)\n\nThus:\n\nm (slope) = "delta y"/"delta x" = rise/run\nm = (y2 - y1)/(x2 - x1)\nm = (-1 - 4)/(2 - (-2))\nm = -5/4\n\nrun = 4, rise = -5
877049
use the slope formula.\n\ny sub 2 minus y sub 1 divided by x sub 2 minus y sub 1\n\nthen you get 1-5 divided by 0-2\n\nthen you get -4 divided by -2\n\nthe answer is 2
554784
x=(1--2)  or (1+2)\ny=(5-3)\n\ny/x=slope\nx=3\ny=2\nslope is 2/3
843812
slope= 1   y-int=0\nThis is an equation. You can cancel the -7 and you'll have y=x. If you remember from the equation y=mx+b, then you'll see that here your m=1 and your b=0
736765
slope=1\ny=x+b\n-3=3+b\nb=-6\ny=x-6
1147518
distance between point A nad point B
1038364
Formula for linear slope is y=mx+b\n5y=10x-10\nDivide the 10x-10 and 5y  by 5 to get\ny=2x-2\n-21+7y=14\nAdd -21 to both sides to get\n7y=35 Hence y=5\nx=-5 The slope is undefined. IF you graph the line and take two coordinates and use the formulas (y2-y1)/(x2-x1) you get 0 at the bottom. Anything divided by 0 is undefined.\nY-5=2 is add the 5 to both sides to get y=7
155791
Here is a good page describing slope.\n\nhttp://mathforum.org/cgraph/cslope/slope.html
1121252
slope = m\nperpendicular slope = (-1)/m\n\nslope = (y2-y1)/(x2-x1)\nslope = (2-5)/(4-2)\nslope = -3/2\n\nperpendicular slope = 2/3
324454
I'll help :)\n\nSlope is calulated by taking the change in y over the change in x.  So (78-92)/(5-9)=  -14/-4 = 7/2\n\nThe slope is 7/2
787261
Let the 2 points be (x1,y1)  and  (x2,y2)\n\neqn of line s given by\n\n(y-y1)/(y2-y1) = (x-x1)/(x2-x1)\n\nwhere  (y2-y1)/(x2-x1) is the slope of line
408060
To find the slope, you always have to set the equation as y=mx+b.  That equation is called the slope-intercept form.  "m" is the slope and b is the y-intercept.\nNow, to find the slope, try to get y alone.\n1. Subtract 2x from both sides.  You'll get: -8y=-2x+7\n2. Divide both sides by -8.  You'll get: y=(1/4)x+(-7/8)\nSo, the equation is y=(1/4)x-(7/8) and the slope is (1/4).
751258
y' = 2x + 4\ny'(1) = 6 this is the slope.\ntangent: yt = 6x + b\n\ny(1) = 1 + 4 + 10 = 15\nyt(1) = y(1) = 15 = 6 + b ===> b = 9\n\nyt = 6x + 9
71640
you find to points on the line \nexample (2,5) and (1,6)\naight m= slope\nput the points in this simple equation\ny2-y1 (over) \nx2-x1\n\n6-5 over\n1-2\nwhich Equals  \n M= 1/ -1\nHoped it helped\nor try asking the teacher for help after school or at lunch
1101719
Step 1: Find the slope of the line x-2y = 2.  Call it m. \n\nStep 2: Find the derivative f'(x) of the function f(x) = (x-1)/(x+1).\n\nStep 3: Find all values of x where f'(x) = m.\n\nStep 4: For each such value, find its corresponding y-coordinate by setting y=f(x), and then find the equation of the line that goes through that point with slope m.\n\nGood luck!
1136213
if a line has the equation px+qy=r\nthen the slope of the line is -q/p