help me please with this topic from trignometry?
608164
I hope that this will help: \nsin(70) = 0.7739,sin(110) = -0.0442,sin(47) = 0.1236,sin(133) = 0.8689, sin(69) = -0.1148,\nsin(111) = -0.8645,cos(70) = 0.6333, cos(110) = -0.9990,cos(47) = -0.9923,cos(133) = 0.4948,\ncos(69) = 0.9933, cos(111) = -0.5025
875835
OD=E*d*C\n\nWhere OD=optical density\nE the molar extinction coefficient\nd the length of the path of the light through the solution (width of the cuvette)\nC the concentration in mole/L of the solute.\n\nYou need d and C as well to get E.\nThis is a fair approximation especially for student problems.\n\nIn reality if you wanted to find E, you would do a standard curve by measuring the OD of samples of known concentration.\nThen you would use linear regression to find the equation of the curve and from its slope you would calculate E (slope=E*d)\n\nA good standard curve and thus accurate calculation requires care to ensure the accuracy of the standards, several points (ideally 9 at least) and being within the linear are of the method.\nThe region of highest accuracy is 0.2-0.8. You can go even below or above this range (though not above 1.0) but this is the range where the photometric error is minimal.
873172
u can get them with the help of second and higher derivatives.\ninflection point is there where the second derivative is zero.
202236
Maybe this site can help\nhttp://drwilliampmartin.tripod.com/classm.html
545673
there are lots of medical devices taking ideas from trigonometry.\none simple example is hip prostheses..the angle at which it should be designed implanted and all are decided by trignometric techniques. I can give you more examples if you r really interested
49314
Sorry, but with the time you spent typing these questions you could of looked them up in your physics book or googled them.  Sometimes getting others to do your leg work isn't always the best answer to a problem.  Good Luck in your new class!
921273
Let x be the distance of the man from spotlight on ground. Let his shadow on wall be s. Then we have, x/10 = 2/s, by similarity of triangles. or  s = -x/20 if we see that as x increases s decreases. \n\nThis gives ds/dt = -(1/20).(dx/dt) = -.06 m/s independent of x. so the Shadow decreases at this rate even when the man is 3m from wall or x = 7 m
880627
Do you mean verifying trig identities?\n\nTry: ask dr math\n\nIf you have a specific trig question, write back.\n\nGuido
1032932
mass, length, time, current, luminous intensity and solid angle steradians r fundamental. Rest all can b expressed by these alone.\n\nDarren G - missed d last 1.\n\nSo ur ans is option D
527822
What's your sine? Oops. I seem to be going off on a tangent. I can't function without you. I don't know Y, but you remind me of my X. It's plane to see that we'd make a great ordered pair, if you get by point. I'm not line. I really have no axis to grind. I've tried every angle I can think of to get this right. I don't mean to be obtuse, but I think we're complementary.
858889
QUESTION 1:\n\nAsk yourself: WHICH TRIG FUNCTION IS OPPOSITE OVER ADJACENT?  IT IS THE TANGENT FUNCTION, RIGHT?\n\nThe bottom of the tree is 25 feet away from a point that measures 30 degrees from ground level to the top of the tree.\n\nAnswer: tan30degrees = x/25feet...choice 1.\n\nNotice that they are NOT asking you to solve for x.  Get it?  \n\nQUESTION 2:\n\nYou need to write the given equation 3x - 2y = 12 in the y =mx + b\nform.\n\nLet's do that right now.\n\nWe have:\n\n3x - 2y = 12 \n\nI will subtract -3x from both sides of the equation.\n\nWe get:\n\n-2y = -3x + 12...See what I did?  \n\nNext:\n\nDivide BOTH sides of the equation by -2 to find the value of y.\n\nWe get this:\n\ny = (-3x + 12)/-2\n\nWe can reduce the equation to this:\n\ny = 3/2 (x) - 6\n\nSlope is 3/2 and the y-intercept is -6.\n\nFinal answer: choice 1\n\nGuido
717702
This should help you a lot.\n\nhttp://home.earthlink.net/~drbobshields/DO.html
501273
Didn't got the question do you want the solution for all the problems of goodman's Introduction to Fourier optics book? Well I do not think I have them any more if you want a specific problem I can help you. I can even try to get a chapter solution for you. Just tell me each one, I can try to get it for you, I do not garantee but I think I may have a way to got them just send me an email (I have a yahoo email). If you have the solutions and you don't understand tell me each problem I can do it in more detail probably, not garantee at 100% but at a good 90% .
577147
This article answers your question.\n\nhttp://www.hhmi.org/cgi-bin/askascientist/highlight.pl?kw=&file=answers%2Fgeneral%2Fans_043.html
1128929
First off......do you know how to do basic trigonometry and use Snell's Law?  If you do, then I'll walk you through it.  Write me at fortitudinousskeptic@yahoo.com\nIf you don't know trig and Snell's law I'm not going to try to explain it.  I'm not that motivated.
460547
This looks close enough to the techniques used to show that the roots are close to the critical line. The actual estimates are difficult, though, and nobody has been able to actually give a proof using these techniques (obviously). Go ahead and try it. Perhaps you can see through to a proof. If so, you will be famous. If not, you will have learned somthing.
398594
You may be talkig about a square, sine, and sawtooth (triangle) waveforms. They look like their names imply on an oscilloscope. They have no special significance other than they are descriptive of the type of AC wave they describe. It is like asking what are the different colors and what are their significance?