What is the displacement of a tapered bar length L under its own weight? Graph a displacement profile?
600829
We need a little more info.  How is the bar supported?  (Cantilever, simple at both ends, etc)\n\nAlso, how is it tapered?  (Height, width, diameter...)\n\nHow much is it tapered?  (Percent of taper parameter at small end)\n\nAll the above will make a huge difference not only in the actual displacement, but the form of the equation as well.
754995
Nicole I think that to understand what is to be done here I suggest to assume that a coordinate system be attached to one of the objects. I-don’t-remember-who says, but << any reference system at rest or moving with linear constant speed has no privilege with others the like>>.\n(x) m2=4kg is reference system #2, where v2=0, and m1=2kg is moving with speed v=8+12=20 ms, impact by m1 on m2 M1=m1*v=40kg*m/s\n(y) m1=2kg is reference system #1, where v1=0, and m2=4kg is moving with speed v=8+12=20 ms, impact by m2 on m1 M2=m2*v=80kg*m/s, so R=40/80=0.5
155791
Here is a good page describing slope.\n\nhttp://mathforum.org/cgraph/cslope/slope.html
93031
Check this out...\n\nhttp://home.inter.net/eds/paper/inchmetric.html
364905
Use Charles' Law\n\nLet V initial = V\nLet T initial = T\n\nLet V final = V'\nLet T final = T'\n\n\nV/T = V'/T'\n\nSolve for V' you might have to convert from mL to L though.
239996
Work done = force x distance moved by object i thinkin a straight line ,so ithink some conversion maybe needed.
651714
Homework?\nOK, only a hint. Consider a cylinder made of the circle and with a height dh. What is the volume of this cylinder? \n\nNow displace the cylinder along the path over dh, etc.
1053010
On a bisic model there are some basic questions:\n\n1: What is the velosity the item is to achieve to produce the results your are after. \n\n2: What mass are you allowed in you deisgn, as shaft design will need to be considered. \n\n3. What materials can withstand the velosity, and yet maintain you mass variable. \n\n4. Diameter is dependent on velocity, material,\n\nas far as buliding it... you must consider the G factor...dependent upon weather it is earth bound or space bound.
179742
Various springs (flat or helical) deflect linearly with load and resistance of certain wires (nichrome, etc.) varies linearly with length.  If your experiment allows or expects large deflections you may be able to combine the spring/resistors into a circuit that calibrates force/deflection/resistance-reading suitable for measurement on an ohmmeter or perhaps a strip chart recorder.  Good luck.
102977
symetric designs, ratios from diagram to real material
83027
Here's a link that might help you:  http://www.mebs.co.uk/deflection_fields.htm
701453
You can find it using the general bending formula as related to torsion (twisting) rather than bending.\n\nT/j = G/Theta x L = Shear stess/Radius\n \nThe folowing link explains much better than I can.\n\nhttp://www.freestudy.co.uk/c105.htm
676330
Displacement is a vector quantity.
481625
Yes, it is possible to find pressure drop per unit length from  some more information about density and viscosity of the fluid and roughness of the pipe. Any book on fluid dynamics gives the procedure.\n\nTheformula is:\nPr head = 2f(v^2/g)(N/D)\nwhere \nf= friction factor (generally found from a chart)\nv= average velocity of fluid \ng= conversion factor (having magnitude equal to std accln due to gravity)\nN= Equivaalent length\nD= diameter of pipe.\nYou have to follow some standard system to work out this problem (see standard reference)
370828
You get K by knowing that the parabola is centered in the middle of the span (where the sag is lowest). So\n\nk= y/x^2  = 143/640^2  = 3.5x10^-4\n\nFrom there use the path length equation to get the length of the cable. When you have that, multiply by 1.05 and work backwards for (b)
1111034
Perhaps the link will help a little.  If you bend a pipe or metal bar, some of the metal will be in tension (stretched) and some will be in compression (squeezed).  There is a neutral plane between the two conditions that is neither stretched nor squeezed.  Often the plane passes through the centroid of the pipe (or bar).  This is easy to find if the cross-section is regular (round, square, etc.) but more difficult to find if the area is irregular or of variable properties such as density.  The centroid is similar to the center of gravity for the shape.  Hope that helps a little.
564798
Ba(NO3)2 + Na2CO3-->BaCO3 +2NaNO3\n\nto do a double displacement follow this formula\n\nAB + CD --> AD + CB