if a daddy bull eats 3 bails of hay and a baby bull eats 1 bail of hay how many does a mama bull eat?
607245
Sounds like you have a transsexual cow there to me. Just dont try to mil it or the cream is gonna be really thick
509336
cheetah eats herbivore who east grass.\n\ngrass <-herbivore <-carnivore
732116
theres only 3\n\nsex food power
187660
We had a cow give 104 pounds, but they don't hold to that very long.  Many people who have better hay for their cows and feed more grain probably see 100-125 pounds a day on average.  Many cows realistically give 40-95 pounds.
492607
The calf weighs about two and a half tonnes and is around 7 m in length.\nI don't know if that helps but it can give you a good idea.
689838
Divide 278 by four to get the number of horses, then subract that number of horses from the heads to get the number of ostriches. MAke sense? If it doesn't email me. \n\nR u sure you have the number of hooves right?????? Cause ostriches don't have hooves but there is a remainder of 2 did u mean feet? if u meant feet then...\n\nummm...\n\nOOOO i no.... 123 horses and 0 ostriches! works don't it?
110844
chickens-5 cents, goats-1 dollar and cows-5 dollars\nLet a = number of chickens\nb = number of goats\nc = number of cows\n(1)a + b + c = 100\n(2)0.05a + 1(b) + 5c = 100\nSubtracting (2) from (1), we get\n0.95a - 4c = 0\n4c = 0.95a\n400c = 95a\n80c =19a\nc = 19a/80\nSince we're dealing with whole numbers, and 0<a<100 so the only possible value for a (chickens) is 80. By substituting, c (cows) will be 19, leaving b (goats) to be 1.\nAnswer:\n80 chickens = $4\n1 goat = $1\n19 cows = $95\n\n100 animals = $100
890512
If you are talking about cost, it depends on what kind of hay.  I live in Texas and we pay in excess of $6 per bail.  If your talking about weight, I would say a square bail is anywhere from 30# and up.  Depends on how tight it is packed.
345957
What are the number of puppies you have chosen ?\n\nTry this site for help\n\nhttp://www.futureaccountant.com/probability/
892129
this question depends on the brown hamster. if its BB crossed with the white (must be bb) then you will get all brown offspring.  However if the brown parent is Bb, the the offspring will be 1:1.  Two white offspring and two brown offspring.
925459
Sorry its Six -- One more to hold the Container below the udder to collect the milk !!! Ha Ha Ha ...too funny !! I liked it ! LOL !!
710730
1.Let the no.of boys in the family be x+1\nTherefore,each boy has x brothers(excluding the boy himself)  and x sisters\nSo the number of girls in the family is x\nTherefore each girl has x-1 sisters(excluding herslef,of course) and as assumed x+1 brothers\nBut by the problem,\n(x-1)=(x+1)/2\n+.2x-2=x+1\n2x-x=1+2\n+.x=3\nTherefore there are 3 sosters amd 4 boys in the family and the no. of children is 7.\nso A is correct\n2>Let the no. of children who lost 1 teddybear each be x\nTherefore,the no of children who lost two teddy bears each is 32-x\nAccording to the problem\nx+2(32-x)56\n=>x+64-2x=56 \nor x=8\nTherefore,8 children lost one teddy bear each\nA is correct
292525
several classes (100 students)of 6th graders went on a field trip to the zoo. 1/5 of them went to c the monkeys. 1/2 of them visited the penguins. 1/4 went 2 c the bats. and the rest went to the snack bar. how many students went to the snack bar? if u hav a heart. u will help \n\nwell...i got 5 students went to the snack bar...\n1/5 of 100=20\n1/2 of 100=50\n1/4 of 100=25\nso \n  20+50+25=95\n  100-95=5 students\n~Brendon
52825
Depending on their age and the amount of work they might be doing, and adult Clydesdale may eat 25 to 50 pounds of hay and 2 to 10 pounds of grain or other supplements.
1056611
Take the cow first, leaving the coyote and bale of hay.\nCome back, take hay across. \nTake cow back.\nTake coyote across. Coyote and hay again.\nCome back alone.\nGet cow and take it to opposite shore. Ta-da!
809519
Well, let's see.\n\n18 = b + s + c,  where b means bird(chicken)\n\ntotal number of legs:\nLt = 2b+4s+4c, right?\n\nLt = 3Ht +10 , total legs 10 more than 3 times number of heads\n\nI'd assume each animal only has one head, thus Ht = 18\n\nLt = 3*18+10 = 64\n\nLike most problems of this sort you must find integer solutions.\n\n18 = b + s + c\n74 = 2b + 4s + 4s\n\nA trial and error procedure is effective.  \nstart at \nb=s=c=6, -> Lt = 12+24+24 = 60, need more legs!\nb,s,c\n5,7,6, -> Lt = 10+28+24 = 62,\n4,7,7 -> Lt = 8+28+28 = 64 <------------- bingo\n\nNote that you can freely shift sheep and cows as long as the total is 14.  So, there are other solutions:\n\n4,14,0 -> Lt=8+56 =64....no cows.....
94656
F F F\n\nHere if you look at each of these sideways from a distance, you have a sheep, goat, and cow. Enjoy.