program for inverse function on ti83plus. Can it be done?
613944
the ti83 does have the solver program. it's under MATH and is the nhumber zero
797737
Ok, take your equation \nf(x) = 2x^2 - 10\n\nreplace f(x) with y\n\ny = 2x^2 - 10\n\nswap y and x\n\nx = 2y^2 - 10\n\nsolve for y\nto do this first add 10 to both sides\n\nx + 10 = 2y^2\n\ndivide both sides by 2\n\n(1/2)x + 5 = y^2\n\ntake the sqaure root of both sides\n\nsqrt((1/2)x + 5) = y\n\nchange y to f(x)^-1 [the inverse function notation]\n\nf(x)^-1 = sqrt((1/2)x + 5)\n\nhope this helps
997106
It is possible to numerically calculate integrals on an 83, but it takes the calculater some time because it literally adds up the area under the curve. You have to plot the function in the y =. Then press CALC (2nd TRACE), choose option 7, enter the lower limit, enter the upper limit. The TI-83 only does definate integrals.
260093
Here it is:-\n\n/* Convert.cpp */\n/* Display the reverse of the input */\n/* By Senthil */\n\n#include <iostream.h>\n#include <conio.h>\n#include <string.h>\n\nvoid main()\n{\nchar inp[10];\nint cnt = 0, ex = 0;\nclrscr();\n\ncout<<"Enter some characters (max limit 10) : ";\ncin>>inp;\n\ncnt = strlen(inp);\ncnt--;\nfor(ex = 0;ex != cnt;ex++,cnt--)\n{\ninp[ex] = inp[cnt];\n}\ncout<<"The reverse of the string is : "<<inp;\ngetch();\n}
446101
switch the y and x\n\nx = 2y - 3\n\nThen solve for y\n\nx + 3 = 2y\n\n(x+3)/2 = y\n\nnow you have the inverse.
714975
There are many such programs available:\n\n   http://www.google.com/search?q=graphing%20functions%20plot%20save\nhttp://dir.yahoo.com/Business_and_Economy/Business_to_Business/Scientific/Software/Mathematics/Calculators/Titles/\n\nSome are commercial, while others are free such as:\n\nhttp://www.c-lunch.org/~jwozniak/wg/main.html\n\nor the long-standing (and excellent) GnuPlot:\n\nhttp://www.gnuplot.info/\n\nThough GnuPlot is not GUI-based.
458677
There's a very explicit algorithm which explains\nhow to handle number, operators (including left\nor right precedence), functions, etc. on the \nWikipedia site for RPN (see reference #1).\n\nMostly, it's very straight-forward.  If it's an operand\n(ie. a number), then push it on the stack.  If it's an\noperator, then pop off as many operands are needed and\nevaluate.\n\nBut do look at the full algorithm for the details.\n\nOh yeah, for a full-blown implementation, see the source\ncode to the Unix "dc" (desk calculator) program.  The\nSolaris source is at reference #2.
372526
some calculators can do this\n\nmathematica software will do it
443117
well ive got a TI-83, but i don't think there'e much differnce b/w the two\nI think you go to "mode" and find "Pol" click enter and uve got it.
567979
inverse of f(x) is (x-1)/2\n\nworking:\nlet inverse of f(x) be y\n       2x+1  = y\n       2x    = y-1\n        x    = (y-1)/2\nthus, inverse of f(x)= (x-1)/2
10353
nobody can inerse this function\ninstead u can draw its graph or calculate the derivate of the inverse by the relation\n(f^-1)'(y)=1/f'(x)
716277
To find the inverse of a function you simply interchange the x and y and solve for y.\n\ny = 2x - 1\n\nso to find the inverse we say\n\nx = 2y - 1\n\nnow solve for y\n\nx + 1 = 2y\n\n(x + 1)/2 = y   \n\ntherefore the inverse of y = 2x - 1 is  y = (x + 1)/2
243068
Let f inverse (12) = a,\nthen f(a) = 12 (because if f(x) = y, then f inverse(y) = x)\nThat is,\n12 = a + 2^a\nNow solve for a to get a = 3.15\nUsing a graphing calculator would be the easiest (and probably the best) way to get the answer of 3.15
952581
http://planetmath.org/?op=getobj&from=objects&id=3808
858418
Click ON\nClick PRGM\nSelect NEW tab and hit ENTER\n\nTo select DISP and PROMPT:\n Hit PRGM when creating or editing a program,\n Select Tab I/O and you will see you selection\n\nTo get the arrow, click STO-> just to the left of 1\n\n\nThis is the Program: (or the one I use)\n\n:Disp "AX^2+BX+C"\n\n:Prompt A\n:Prompt B\n:Prompt C\n:(-B+*square root*(B^2-4AC))/(2A)->D\n:(-B-*square root*(B^2-4AC))/(2A)->E\n:Disp D\n:Disp E\n\nTo run program, go to the main screen, click PRGM, select your program, hit ENTER, input values for A, B, and C, hit ENTER and you result will show your two possible answers.
918506
Here is your answer - the normalcdf function is used:\nhttp://webserver3.lanecc.edu/math/staff/ShellabD/calculatorCentralFolder/TI-83NormCDF&Invnorm.html
142496
There are a number of available tools in the following website:\n\nhttp://www.functionx.com/