A secant-secant angle is a central angle of the circle always, sometimes, or never?
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Sometimes but rarely. A secant is a line that crosses a circle at two points, creating a chord within the circle. For such an angle to also be a central angle, bith the chods must pass through the center of the circle, and be diameters.
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If you are given the arc length of s,\n\nThe angle may be found by\n\ns/(2*PI*r) * 360 degrees.
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Take a unit circle and a point p on the circle. Embed the circle to be centered at the origin on a Cartesian xy-plane. The cosine of p, cos(p), is the x-coordinate, or abscissa, of p. The sine of p is the y-coordinate. These functions are the projection functions for the unit circle. \nIt is common to give the points p on the 1-dimensional circle the coordinate referring to the arclength between p and the positive x-axis (as measured clockwise). Thus, the point (1, 0) on the unit circle is given the native coordinate (0), or 0 for short. Inversely, the point 0 in the unit circle has Cartesian coordinates (cos(0), sin(0)). Since the circumference of a circle is 2Pi, a point that is a quarter of the way around the circle from the positive x-axis is given the coordinate 2Pi/4 = Pi/2 and so forth. This system of coordinates is called radians and is the native way of measuring angles, as each angle has a unique radian measure. \nThis relationship can be seen by drawing a radius from the origin to mark the angle and assigning it the radian measure of wherever it intersects the unit circle. There are more analytical reasons as well, as you go on to study calculus.\nThe radius drawn above also gives the relationship between these circular projection functions, and the way one first encounters trigonometric functions, as ratios of the sides of right triangles. Now you should be able to visualize the triangles inside the unit circle (or any larger circle, dependent on the triangle's hypotenuse), and see why the trigonometric functions are cyclic in 2Pi, and derive some properties of the trigonometric functions that are not easily apparent from just looking at right triangles.\nThe tangent function is so named because it is the length of a certain tangent to the circle; a tangent drawn from the positive x-axis to where it meets an extended radius of the circle. You may be able to work out the equation tan(p) = sin(p)/cos(p) from the geometry involved. If you're familiar with the secant function, (1/cos(p)), you may want to know that it is a geometric secant as well. See the sources below for pictures.
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Angles are formed by two rays that begin at the same point or the union of two rays with a common endpoint, called the vertex\n\nThey are measured in \ndegrees (360 = complete circle), \nminutes ' (60 minutes in one degree) and \nseconds " (60 seconds in one minute)
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Center is a point. Therefore we can think any direction from a point.\n\nAny thing that is opposite to it in a given direction, is opposite to the center.
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Statements\n1) PT tangent to circle O, PAB is a secant.\nReason: Given\n2)Draw line TB\nreason: two points determine a line\n3) angle mtp is congruent to angle mtb\nreason: an angle bisector(line MT) bisects an angle into two congruent angles\n4) draw tangent XY that meets at point T and is parallel to line segment PB\nreason: a tangent may be drawn to one point of a circle\n5) angle mtb is congruent to angle pmt \nreason: when a transversal crosses two parallel lines the alternate interior angle formed are congruent\n6) angle mtp is congruent to angle pmt\nreason: i forgot the name of this theorom look it up(something like if x=y and y=z then x=z)\n7) triangle PMT is isoceles \nreason= converse of the base angles theorm\n\ni hope i was able to help somewhat, i tried to draw a diagram to the best of my ability with the given information. by the way i know there was another way to do the proff with circle properties but i think it was much easier to draw a tangent parallel to PB saved a lot of steps also. good luck!
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angle b and angle c.\nthey are both on the same line of the x- axis and collide at a central point with respect to A.
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There is a theorem (I think you remember it better). I just put it with my own words. Let points A, B, C & D belong to the same circle. Then the angle ABC=(Arc ADC)/2\nThus the Sum of 7 Arcs under 7 Angles will be = to 2pi radians, that means that the Sum of those Angles = pi radians, the main demand being they belong to the circle.
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Almost a coicle!\nEach side would subtend an anhle of slightly more than 1.5degrees so it is very close to a circle. I don't think it has any official name.
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coterminal is when you add and subtract 360 degrees from the terminal angle. too little info. sorry.
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SEC stands for secant, which is the ratio of the hypotenuse to the leg adjacent to the acute angle X.  So here, \n\nsec(x)= (sqrt 41)/4
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alright, ill tell you, but not without explaining it.  im giving you the benefit of the doubt that you are not just cheating on your homework :)\n\nthe standard equation of a circle, using only variables is\n(x-h)^2 + (y-k)^2 = r^2\nwhere the center is at (h,k) and the radius is r\n\nthat means that when you look at the equation youre given, the x coordinate of the center is whatever number is subtracted from the x\n\n(x+1) ---> (x- -1)  so  h = -1\n\nyou use the same process to determine "k", which is the y coordinate of the center\n\n(y+3) ---> (y- -3)  so  k = -3\n\nthat makes the center of the circle at (-1, -3)\n\n\nfinding the radius is also simple using the standard equation. here it is again, just for reference:\n(x-h)^2 + (y-k)^2 = r^2\n\nsee how you can use that to get this?\n9/4 = r^2\n\nso just take the square root of both sides . . .\nr = +/- 3/2\n\nbecause you took the square root, the 3/2 could technically be either positive or negative, but since youre talking about the radius of a circle and you can't have a negative distance, you only take the positive answer.\n\nso r=3/2
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Since O is the center, this problem becomes fairly straightforward.  First, assuming <BOA = 94 degrees (not sure which of the four angles at O is 94 degrees, but say it's <BOA.  This means that the arc from B to A is also 94 degrees.  And since the chord from A to C goes through the center, it means it is a diameter.  This means that the arc from A to C is 180 degrees (half of the circle).  So that means that the arc from B to C has to be 86 degrees (180 - 94, because part of that arc from A to B is 94, the rest must add up to 180).  So now you have to use what your teacher told you about when the angle is on the circle.  Namely, that the angle on the circle (the inscribed angle) is half of the arc measure (intercepted arc).  So if the arc measure is 86 degrees, the angle must be 43 degrees.\n\nEdit: I just saw that it was <COD, not <BOA, but they are congruent because the are vertical angles, so nothing changes.
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It is the (secant(x))^2; or you could write it as (cos(x))^(-2) or 1/(cos(x))^2.\n\nBut basically the secant squared is the most elegant answer.
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A circle is the locus of a point which moves in a plane in such a way that its distance from a given fixed point is always constant.\n         The fixed point is called the centre & the constant distance is called the radius of the circle.\n           \n          A circle with centre O & radius r is denoted by C(O,r) !!!
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For example, a square is inscribed if the square is inside a circle.  The four vertices of the square are touching the circle..\n\nThe square will be circumscribed if it will be outside the circle.  In this case the circle will be touching the square in four points on the sides.
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If the shape is a quadrilateral, the measures of its opposite angles WOULD add up to 180 degrees.  This is because the measure of an inscribed angle (an angle with vertex on the circle) is half the measure of its intercepted arc.  Between the two opposite angles, their combined arc is the whole circle which measures 360 degrees.  So the sum of the inscribed angles is half of that, or 180.