what is a coefficient?
600578
not just in math but also in chemistry\n\nChem: 2OH\n\nMath: 2x
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the standard form is: Ax + By = C\n\nin your two equations you dont have any 'y' so you might have typed it wrong but if it is right then 'B' is 0.  \nthen combine like terms. this should leave you with Ax + (0)y = 0\n\n\nto determine 'x' and 'y'...\n\n             PART #1\n1. choose 'x' as zero\n a. this eliminates 'Ax'\n2. divide both sides by coefficient of 'y'\n a. this leaves y = C/B\n3. determine y\n\n             PART #2\n1. choose 'y' as zero\n a. this eliminates 'By'\n2. divide both sides by coefficient of 'x'\n a. this leaves y = C/A\n3. determine x\n\ni hope this helps!
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it's defined \n\n0^0=0
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The  exponent becomes a coefficient\n-1+2x lne\nln e=1\n-1+2x
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c.\n\nIn probability theory and statistics, the coefficient of variation (CV) is a measure of dispersion of a probability distribution. It is defined as the ratio of the standard deviation to the mean
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:equation when thing equally=0 \nEx:the proportion of negative=positive advantage & disadvantage copensated in its own value of property.anymore question??
156694
Then the coefficient of variation is .333
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Domain:  All the values of x that provides a defined value of y.  In the equation above if we plug 0 or less than 0 for x, we get an undefined answer.  Thus the domain is x>0.  \n\nIntercepts:  To find intercepts we plug y equal to zero and then solve for x.  So, lnx/x = 0\n                          lnx = 0\n                             x = 1\nThus the intercept point is (x,y) = (1, 0)\n\nAsymptotes:  An asymptote is a straight or curved line which a curve will approach, but never touch.  By looking at the graph of lnx/x, we can conclude that the graph approaches y = 0 but never actually touches 0.  So, the asymptotes is y = 0.  \n\nCritical point:  In mathematics, a critical point (or critical number) is a point on the domain of a function where the derivative is equal to zero. It is also called a stationary point.  Derivative of above function is: \n                        dy/dx = [(x)(1/x)-lnx](x^2)\n                           0 = (1-lnx)/(x^2)\n                           0 = 1-lnx\n                           1 = lnx\n                            x = e\nSo, the critical point is x = e.
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Domain ~ x values\nRange ~ y values\n\nYou have to work the function and figure them out.
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Friction is a theoretical coefficient used so that future results may be predicted.
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When your first term is x², you can look at the other two coefficients -- in this case -8 and +15.\n\nTo factor, look to see what two numbers when multiplied together will give you your last coefficient (+15) and when added together will give you your middle coefficient (-8).\n\nSo in your case, we see that we need two NEGATIVE numbers because 15 is positive and only two negs or two positives can give you a positive when multiplied.\n\nWe know that the two must be negative, because we need to get a negative 8 when we add them together.\n\nSo, we can see that +15 = -5 * -3\nand -8 = -5 - 3\n\nSo, our factorization is (x-5)(x-3).\n\nNotice we plugged in our -5 and -3 into (x__)(x__).\n\nHope that helped somewhat!\n\n.
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t=rho/(sqr((1-rho^2)/(n-2)))\nwhere:\n\nrho: correlation coefficient\nn: number of observations
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its a logarithmic integral.\ndifferentiation of log x is 1/x\ntherefore integration of 1/a-x is -log(a-x)+c\nnegative sign because coefficient of x is -1
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The answer to that is a line.  If you want a unique solution to a two-variable problem, you need two equations.
885905
Yes, and this is because of Binomial theorem.\n\nAccording to Binomial theorem\n(a+b)^n = sum(k=0 to k=n)[(a^k) * (b^(n-k))]\n\nSo, with each term in your expantion, we observe 3 things\n\n1. Power of one of the variable increases from zero to n.\n2. Power of remaining of the variable decreases from n to zero.\n3. The coefficient of each term from starting to last will have coefficient (n perm k), where n is the power of (a+b) on RHS and k is the number of the term you are evaluating.\n\nI hope this answers your question.\n\nAll the best.
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Assume there is a pair a_i, b_j with a non zero product.\nWrite fg= (a_i x^i + other terms) (b_j x^j + other terms) =\na_i b_j x^(i+j) is non zero.\n\nContradiction.
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pa·ram·e·ter    ( P )  Pronunciation Key  (p-rm-tr)\nn. \nMathematics. \nA constant in an equation that varies in other equations of the same general form, especially such a constant in the equation of a curve or surface that can be varied to represent a family of curves or surfaces. \nOne of a set of independent variables that express the coordinates of a point. \n\nOne of a set of measurable factors, such as temperature and pressure, that define a system and determine its behavior and are varied in an experiment. \nUsage Problem. A factor that restricts what is possible or what results: “all the parameters of shelterwhere people will live, what mode of housing they will choose, and how they will pay for it” (New York). \nA factor that determines a range of variations; a boundary: an experimental school that keeps expanding the parameters of its curriculum. \nStatistics. A quantity, such as a mean, that is calculated from data and describes a population. \nUsage Problem. A distinguishing characteristic or feature.