How are x and y intercepts used in Algebra 2?
596471
X & Y is used to find a point on a graph.  X is the number across, and Y is the number up or down.\n\nThat's all I have.\n\nFYI, ur question is a little vague...
162736
x-y=5\nx/5-y/5=1\nhence x intercept [5,0] and y intercept [0,-5]
934552
Rearrange the equation so that you get it in the form of the equation of a straight line, that is in the form y = ax +b.\n\nYou get 2y = -x -2\n\nDivide through by 2 anf you get:\n\ny = -x/2 -1\n\nthe -x/2 term is -1/2 times x, so compare this with the equation of a straight line and you see that a = -1/2.  b is -1.\n\na is the slope or gradient of the line so the answer is -1/2.  Not that it has aminus sign so that tells you it slopes upwards from RIGHT to Left.\n\nb is the intercept on th y axis.  So the line crosses the y axis at y = -1.
725212
Yeah, make them graphable on your calc.\n\ny = 4-x\ny = 2x-2\n\nIf you want to solve, just set 4-x and 2x-2 equal to each other (since y must also be equal in both equations)\n\n4-x=2x-2\n3x=6\nx=2\n\n\n2+y=4\ny=2\n\nTheir intersection is (2,2)\n\nThe y-intercept of the first is 4, and the second is 2.\nThe slope for the first is -1, and the second is 2.\nThe x-intercept of the first is 4, and the second is 1.
763572
Hi!\n\nSo, what you are looking at is a linear equation.  You can tell this because there is only one instance of the variable x, and it is not raised to any power.  So, the graph will take the form of a line.\n\nAll linear equations take the form f(x) = mx + b\n\nWhere m is typically called the "slope" and b is called the "y-intercept".   The y-intercept is the point on the graph where the function intercepts the y-axis (the one that goes from top to bottom on the graph).  So, right away you can tell that the y-intercept in your equation is -5 (negative 5).  What this means is that the graph intercepts the y-axis at the -5, or in other words, there is a point on the graph at the location (0,-5).  You can put a dot there.\n\nThe next thing you need to see is the slope.  In you equation, the slope is -2 (negative 2).   Slope really means "rise over the run", or in other words, how much the graph rises for every point it goes to the right.  A slope of negative 2 means that for every increase in x of one unit, the y value decreases by negative 2.   \n\nSo, starting at the point (0,-5) which we determined above, go down 2 units and to the right one unit (putting you at the point (1,-7).  That's another point.  You can do it again and find the next point which is (2,-9) and put another point.  You now can put your ruler on the graph and draw the rest of it.\n\nIt's good to understand how this type of equation works.  You could have also made a table of x values and y values, and simply computed a series of y values for a series of x values (that you picked).  Then you could have drawn the graph also.  But understanding this type of equation will help you in the future.
201233
Hi Bailey,\n\nI'm really glad you're still trying and haven't given up!\n\nFirst I have to confess I'm slightly confused by the wording of your question. WHAT STARTS AT ZERO AND GOES TO SIX? The X-axes, Y-axis or the line? Do you have the co-ordinates of 2 points on the line? \nHave you been given values of x ranging from 1 to 6 and from that you have to calculate the intercept? PLEASE CLARFY BY ADDING DETAILS\n\nNow that you are an expert at graph sketching (or at least understand them better now) you will know that both the X- axis and Y-axis extends infinitely in both positive and negative directions.\n\nPLEASE REMEMBER THAT THE X AXIS GOES ACROSS (horizontally ie left to right) and THE Y AXIS GOES UP (vertically, up and down). \n\nNow try to follow this...\nThe intercept is the value of y (point on the Y vertical axis) where the line 'cuts' it. At this point X always must equal zero (by the definition of a Euclidian plane, but don't worry about it).\n\nTherefore put the value of X=0 into the formula and you will get:\ny= 0m +b \n= y=b \nso the intercept point has coordinate (0,b) ie X=0 and Y+b\n\nIf there was no value on the line when X=0 then the line DOES NOT not intercept the Y axis therefore b would not exist for this line. Such a line occurs for verticle lines (straight up) such as x=1,x=2,x=3,x=4,x=5,x=6…to infinity.\n\nIncidentally if you were given 2 points and asked to find the intercept you should use ALGEBRA. Compute the gradient (y2-y1)/(x2-x1). Then compute the intercept as the balancing value to make the equation work. \nFor example (5,6) and (7,10). \nM= 10-6/7-5=4/2=2. \ntherefore y=2x+b. \nChoose one of the points and substitute the values.  \nSay 6= 2(5)+b so b= 6-10 = -4.\n\nDoes this answer you query?
1090885
the answer would be Y=2X^2+5 because you are changing the Y intercept.
930270
Well done, you have already done the hard work. The number in front of the x is the slope ie -2/13 and the other number is the y co ordinate of the y intercept ie (0 , 5/13). Another way to find the y intercept is to substitute zero for x and solve for y, or alternately substitute zero for y to find the x intercept.
920959
r(x)= x^3+8/x^2+4\n\nAssuming you mean r(x)= (x^3 + 8)/(x^2 + 4)\n= (x + 2)(x^2 - 2x + 4)/(x^2 + 4)\n\nWhen x = 0, r(x) = 8/4 = 2.\nSo it cuts the y- axis at (0, 2)\n\nr(x) = 0 when (x + 2)(x^2 - 2x + 4)/(x^2 + 4) = 0, ie when x = -2\n\nSo it cuts the x-axis at (-2, 0)\n\nie x-intercept is -2 and y-intercept is 2.
172343
the easiest way to find a y-intercept is to just plug in 0 for x.\n\nSo, you get:\ny-3=2(0-5)\ny-3=2(-5)\ny-3=-10\ny=-7
1169410
An x-intercept occurs where y = 0, so plug in 0 for y.\n\nx^2 + x - 6 = 0\n\nFactor the quadratic equation (reverse FOIL)\n\n(x + 3)(x - 2) = 0\n\nx = 2, -3
142602
This is truly a sad question, what is the school teaching you? To come to the yahoo answers board to get answers.\n\nSlope intercept form is y=mx+b\nWhich means you have to solve for the y variable on one side.\n\nThe manipulation of variables is as follows.\nsubtract 2x from both sides\n\nDivide through both sides by -3\n\nPlace the resulting form into the y = mx + b form
359675
y-intercept occurs when x=0\n\nSo, set x=0, and your equation becomes:\n    2(0) - y = 4\n\nor, because 2*0 = 0,\n    \n    y = -4 is your y-intercept.\n\nThe slope can be found by writing the equation in standard "y = mx + b" form, where "m" is the slope. In your example, that would be:\n\n    y = 2x - 4\n\nSo, the slope ("m") is 2.\n\nDone and done.
444240
-y=2-x\n\ny=x-2\n\nslope is 1\ny intercept is (0,-2)
918456
domain\nall real x\nx intercept\nputting y=0\n0=x+rt{x]\n-x=rtx\nx^2=x\nx(x-1)=0\nx=0 or 1\nx intercept=(0,0) and (1,0)\ny intercept\nsetting x=0\ny=0\ny intercept=(0,0)\nno symmetry exhibited
821928
I only see equalities... and what are you supposed to do with them?\n\nAssuming you need to graph them, first put them in terms of y:\n1) y = -x + 2\nThis has a slope of -1 (diagonal downward) and a y-intercept of 2.\n\n2) y = -2\nThis has no slope (horizontal line) and goes through the y-intercept of -2.\n\n3) y = x + 2\nThis has a slope of 1 (diagonal upward) and a y-intercept of 2.\n\nThe lines are shown in the attached diagram... Now what do you want to do with them?
618527
i'm not gonna solve it...but tell u how to solve it.\n\n-x intercept of vertex : -b/2a\n-y intercept of vertex : f(-b/2a)\n-for direction of opening find f(0)\n-i guess the axis of symmetry is the middle point of something. i cant remember that something.\n-find the relationship urself