How do you factor 36x^3-84x^2+49x?
612346
Fact or out the x. This leaves 36x^2-84x+49 which is a perfect square (6x-7) so it facotrs to:\n\nx(6x-7)(6x-7)
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
801272
x³y - 3x²y - 10xy --- Take x and y out of each term...\nxy(x² -3x - 10) --- Factor the x² - 3x - 10\nxy(x - 5)(x + 2)\n\n*Note: To show exponents, such as x², use the ^ key (such as x^2). This expression looks like you basiclly wrote:\n3xy - 6xy - 10xy
930643
factor:\n\n(2x^2+x-6)/(2x+4)=\n\n(2x-3)(x+2) / 2(x+2)\n\nthe (x+2)s cancel out leaving\n\n(2x-3)/2
117019
I have been able to simplify it till:\n\n358x^2-450x divide 115x^2-130x\n\nYou can discuss if I am not getting the thing and if you need help on my email:\ntalhaiba@yahoo.com
175207
Next time use ^2 instead of typing out "to the 2". Anyway, write it in standard form, so that the variables are in descending order.\n\n14w^3 + 49w^2 - 8w - 28\n\nYou can't factor this. If it was 7w instead of 8w, then you could factor out a 7 by dividing all the coefficients by 7 and pulling it outside the parentheses. Alternatively, you could factor the first two terms separately from the second two:\n\n7w^2(2w + 7) - 4(2w + 7)\n\nNow it's in a great form for factoring. Group them.\n\n(2w+7)(7w^2-4)\n\n---\n\nDo the same thing for the second example.\n\n44t^3 - 4t^2 + 66t - 6\n\nFor this one, you can factor out a 2.\n\n2(22t^3 - 2t^2 + 33t - 3)\n\nOr, again, you can factor the terms separately:\n\n4t^2(11t - 1) + 6(11t - 1)\n\nGroup.\n\n(11t-1)(4t^2+6)\n\n\n\nHope this helped.
179350
ok well u gotta do long division for this. but first you need to find a factor. theres some theorem or rule or somethin that sayz, basically check all the numbers that are factors of the last number. so the last number is -12. factors are +-1, +-2, +-3, +-4, +-6. so put each one into the equation for x  and eventually, 1 of them will make the equation =0. so i think 1 works. so that means the factor is x-1. now u do long division.\n\nso first you ignore the -1 and u just see what do u multiply x by to get x^4. and its x^3. and then you multiply the whole   (x-1) by x^3   and subtract it from your equation. and then bring down the next term. and repeat it and you should not get a remainder.\n\n....................x^3 - 2x^2 - 11x + 12\n(x-1)...%...(x^4 - 3x^3 - 9x^2 + 23x - 12)\n.............x^4 - x^3\n\n...............0 -2x^3 - 9x^2\n.................-2x^3 + 2x^2\n\n...................0   -11x^2 + 23x\n.......................-11x^2 + 11x\n\n........................0     + 12x - 12\n.................................0 + 0\n\nand so there. your first factor is (x-1) and now u gotta repeat the same thing for your quotient. which is  \nx^3 - 2x^2 - 11x + 12.  so 1 works here again. which basically means (x-1) factors out twice.    so divide again\n\n....................x^2 - x - 12\n(x-1)...%...(x^3 - 2x^2 - 11x + 12)\n.............x^3 - x^2\n\n..................-x^2 - 11x\n..................-x^2 + x\n\n........................-12x + 12\n........................-12x + 12\n\nand now u have a quadratic equation x^2 - x - 12. which isnt that hard to solve. 2 numbers that add to -1 and multiply to -12  is just -4 and 3. so (x-4)(x+3)\n\nso the whole equation = (x-1)^2 (x-4)(x+3)    so the   zeros   are  1, 4, -3\n\nhope u get it. let meknow if u need more help. laterz
914755
your equation must be like x^2-3x-6 and your trying to factor this\n\n2 numbers say a and b must multiply to make -6 and add to make -3 so a*b=-3 and a+b=-6\n but i can't think on any that fits this criteria so you must use the quadratic equation\n\nx= [-b +-squareroot(b^2-4ac)]/2a\nwhere a=1 b=-3 and c=-6\nx= 3+-squareroot(9-4(1)(-6))/2\n\nx=(3+squareroot(33))/2 and x= 3-squareroot(33)/2\n\nin decimals x=4.3723 and x=-1.3723
815517
OK First you take out the common factor which is y. After you have done that.you have (y^2-12y+36). After this, it becomes simple factoring. The answer is\ny(y-6)(y-6)\nor also known as y(y-6)^2
219588
3x^3 + 2x^2 + x - 6\n= 3x^3 + 5x^2 - 3x^2 + 6x - 5x - 6\n= x(3x^2 + 5x + 6) - 1(3x^2 + 5x + 6)\n= (3x^2 + 5x + 6)(x - 1) \n\nThe factors are : (3x^2 + 5x + 6) and (x - 1) \n\nAlternatively, using polynomial division : \n(3x^3 + 2x^2 + x - 6) divided by (x-1) yeilds \n(3x^2 + 5x + 6)
494989
It seems that many people here don't realize that your equation is 3x^2 - 6x + 9.\n\n3 is the basic factor to get 3*(x^2 - 2x + 3)\n\nIf you are allowed to use imaginary numbers (where i = sqrt(-1)) then,\n\n3*[x - 1 + i*sqrt(2)][x - 1 - i*sqrt(2)]
863644
take out 4x first\n4x(x2-6x+8)\n4x(x-4)(x-2)
289855
First factor out the x: x(x^2 + 2x - 63)\n\nThen FOIL:  x(x+9)(x-7)
940636
Multiply both everything by 60\n60(4/3)(3x-2) - 60(3/5)(4x-3) = 60(11/60) + 60(3x)\n80(3x-2) - 36(4x-3) = 11 + 180x\n240x - 160 - 144x + 108 = 11 + 180x\n96x - 52 = 11 + 180x\n-63 = 84x\n-63/84 = x\n-3/4 = x
770441
take 2(x-2) as common factor\n\n= 2(x-2)((x+3) + (x-3))\n= 2(x-2)(2x)\n=4x^2-8x
836052
You can start by factorizing 3x^4 from everything\nm(x) = 3x^4 (2x^3 + 5x^2 - 3x - 3)\n\nI think there's something wrong with your problem, none of the possible roots given by the Ruffini's rule are working. Perhaps, if instead of 6x^7 + 15x^6 - 9x^5 - 9x^4 it was 15x^7 + 15x^6 - 9x^5 - 9x^4, then it could be factorized very nicely in\nm(x) = 3x^4 (x+1)(5x^2-3) \nor if instead you wrote 6x^7 + 6x^6 - 9x^5 - 9x^4 then it'd factorized to\nm(x) = 3x^4 (x+1)(2x^2-3)
715426
x^4 + 5x^3 - 30 / x^2 - 3\n\nThe important thing is that, especially with division, polynomials need place value so 0 coefficients apply.\n\nRewrite as follows\n\nx^4 + 5x^3  + 0x^2 + 0x - 30 / x^2 + 0x - 3\n\n.................... x² + 5x + 3\n................. ____________________\nx² + 0x - 3 )x^4 + 5x³ + 0x² + 0x - 30\n.................. x^4 + 0x³ - 3x²\n.................  ------------------ .....↓\n........................... 5x³ + 3x² + 0x\n........................... 5x³ + 0x² - 15x\n........................... ------------------ ....↓\n.................................... 3x² + 15x - 30\n..................... ............... 3x² + 0x - 9\n.................................... ------------------\n....................... ................... 15x - 21\n\nSo x^4 + 5x³  - 30 = (x²  - 3)(x² + 5x + 3) + 15x - 21\n(Or quotient is x² + 5x + 3 and the remainder is 15x - 21)