Two airplanes leave ATL at 10:30am. 1 plane flies W at 320mph & the other flies E at 400mph.?
602259
after first hour they are 720 miles apart.(400+320=720).\n2700/720=3.75 so that tells you that in 3 hours and 45 minutes the planes would be 2700 miles apart. they left at 10:30 am so\n10:30 am + 3:45 = 2:15 pm.
184920
Time of flight.....\n\nsince the flight hasn't begun yet it is Time Minus 10, 9,8,7,6,5,4,3,2,1, liftoff \n\nT plus 1,2,3,4,etc..............................\n\nuntil touchdown when the flight is over and the clock stops
543583
Use the pythagorean theorum.  Train One is the left leg, train 2 is the right leg, and the distance between them is the hypotenuse.  Since they only traveled an hour, their speed is irrelevant.  That triangle gives the formula of (x+10)^2 + x^2 = 71^2\n\nWork it out from there.  X will equal the distance that the second train traveled, and since they traveled for an hour, that is the magnitude of its speed as well.
902644
A)  x = time going to Chicago\n     x+1 = time returning to Detroit\n\n   75 * x = distance to Chicago\n   60(x + 1) = distance returning\nSince the distances are equal\n 75x = 60(x + 1)\n 75x = 60x + 60\n 75x - 60x = 60\n  15x = 60\n  x = 4 hours\n x + 1 = 5 hours\n\nB)  a = speed of airplane\n      w = speed of wind\n     \n   3.5(a - w) = 630                    a - w = 630/3.5  a - w = 180\n     3 (a + w) = 630                   a + w = 630/3    a + w = 210\n\n       a - w + a + w = 180 + 210\n      2a = 390\n        a = 195mph plane speed\n\n       195 + w = 210\n         w = 210 - 195\n         w = 15 mph wind speed\n\nC)   w1 = weight at 4000 mi.\n       w2 = weight at 4000 + 550 mi.\n\n      160/(4000)(4000) = w2/(4550)(4550)\n\n        (4550 * 4550 )/(4000 * 4000)   * 160    = w2\n\n        At least you do the arithmetic from here\n\nD)  Same problem different name\n\n     p1/(L1)(L1)=p2/(L2)(L2)\n     p1(L2)(L2)/(L1)(L1) = p2\n\n     (1sec x 64cm x 64 cm)/(81 cm x 81 cm) = p2\n\n    Once again, you do the arithmetic
653251
http://www.usatoday.com/weather/resources/askjack/2003-05-06-lightning-airplanes_x.htm
857842
If flies slightly farther, but not significantly
317439
Depending on where you live, there are noise restrictions at certain times. So it's not like no planes fly at all, it all depends on the decibel output their engines make.
397449
In GA it was around 8:59am when the first plane hit
190148
Modeling the fly and two trains as particles,\nAnd taking the midpoint of trains as origin,\nthe equation of motion of trains are:\nx(t)=-30+18t\ny(t)=30-18t\nin kilometers respectively.\n\nThey collid when 18t=30,\nthat is at t=30/18=5/3 hours (100 minutes).\n\nThe distance traveled by the fly,\nWHICH IS FLYING AT SPEED 80 KMPH,\nin 5/3 hours is\n5 / 3 * 80 = 400/3 km\n\nThat is approximately 133.3 kilometers.
540627
Not an uncommon thing to see. The "sky" is laid out in compass points and most commercial air craft are assigned flight paths that are like "high ways" in the sky. Generally you will find those "trails" are on true points, 00%,45%,90% etc. The reason for the near perfect "X" is due to the vectors the two were heading on.
378732
how about the airlines?\n\n911 was the perfect example.\n\n2 planes leaving Boston 30Min's apart going to the same LA airport and both plans had a half a load.
925243
e is the correct answer\n\ncoplaner means all in the same plane. the magnitude of the three can result in a, b, or c.\n\nd is impossible
1116075
The two trains are moving towards each other at a speed of 25 mph each.  Thus at a speed of 50 mph relative to each other.  Since they started 100 miles apart, it will take them 2 hrs to reach each other.\n\nThey fly flew at a constant speed of 37 mph for 2 hrs.  Thus the fly flew 74 miles.
1107948
I have been across the Triangle many times in both boats and planes. I never observed anything different. There are many scheduled flights across it every day.  One of the reasons for so many stories is that there is such a huge amount of air and shipping traffic across this area.
412157
A plane would only have to travel at approx 1000mph to go around the Earth in 24 hours.  Some supersonic jets easily travel that fast.  Throw in time for slowdowns to meet with tankers and landings to refuel.  I believe that it can be done.  I'm surprised that the government didn't have the Sr71 attempt it during its career.
359184
There is no wind.  The conveyor belt isn't moving air to cause lift.  Just because the conveyor belt is moving the plane's wheels doesn't mean it will fly..   Point the plane the other way and it will.
977845
Put on a number plane with B initially at O (0. 0)\nTherefore A is initially at (-150, 0)\n\nNow A's position, t hours after midday, is (-150 + 35t, 0) and B's position is (0, 25t)\n\nSo t hours after midday \n\n|AB| = √[((-150 + 35t) - 0)² + (0 - 25t)²]\n= √[(22500 - 10500t + 1225t² + 625t²)\n= √(22500 - 10500t + 1850t²) \n\nVelocity of change = d(|AB|)/dt\n= 0.5 * (3700t - 10500) / √(22500 - 10500t + 1850t²)\n= 0.5 * (3700 * 4 - 10500) / √(22500 - 10500 * 4 + 1850 * 4²)\n= 0.5 * 4300 / √(10100)\n≈ 21.4 km/h