x + 3 > 8 and x - 4  < -2?
602540
x + 3 >  8 ==> x >  8 - 3  ==> x > 5\nx - 4 < -2 ==> x < -2 + 4 ==> x < 2\n\nAnswer... not possible.
553161
(1+3)*2 = 8\n(3+8)*3 = 33\n(8+33)*4 = 164
302848
Probably easier to show by example.\n4x2+8-:-4-1 (-:- = divide)\nmultiply any numbers first, then divide, then add and subtract.\n\nYou could add brackets in if that helps you.\n(4x2)+(8-:-4)-1 = 9
1149923
(2,-4) if f(x) is defined for x=2
795059
You came up with x > -1 OR x < 7.  The "or" is key.  It can be less than 7, or  greater than -1.  There's no real number that doesn't fit the solution.\n\nFor the second one, you came up with x >= 0.8 AND x >= 2.  Similarly, the "and" is the key here.  Anything greater than or equal to 2 is going to be greater than 0.8, fulfilling both conditions.  The same cannot be said if the numbers are reversed.\n\nTo sum it up, if the problem has an "or" condition, every solution must solve at least one inequality.  If the condition is "and", every solution must solve ALL inequalities.
756805
x<2   (-infinity,2)\nx>3   (3, infinity)\nx<2 see first interval\nx>-2 (-2,infinity)
800627
x = 3/(x-2)\n\n=> x(x-2) = 3\n=> x^2 - 2x = 3\n=> x^2 - 2x - 3 = 0\n=> (x-3) (x+1) = 0\n\nEither x-3 = 0 => x=3\nOr x+1 = 0 => x=-1
807939
= (1 + 8x)*(1 - 8x) = 1 - 64*x^2\n\nAnd what do you say?
991923
For the first one, 4<-2<6 does become -2>x>-3 (you do have to flip the signs) and yes, it is still an "And" statement, just in reverse (or in other words, -2>x>-3 is the exact same thing as -3<x<-2). For the second one, you don't actually have to multiply by 10, but you should get the same answer either way. I got 0.84<x<1.76.
235841
A(8) = 1/2 (-3)* 8 -1 = -12-1=-13
533029
Let's call :\n(a) : x + 2y < 3\n(b) : 2x - 3y < 6\n\nWith the 1st one:\nx + 2y < 3\n<=> 2x + 4y < 6 \n\nThe 2nd one is 2x - 3y < 6\nThat means : \n(a) - (b)\n<=> 4y - (-3y) < 0 \nor 7y < 0 \nor y < 0\n\nWe have also: 2x - 3y < 6 <=> (2/3).2x - (2/3).3y < (2/3).6\n<=> (4/3)x -  2y < 4\nThat means:\n(a) + (b)\n<=> x + (4/3)x < 7\n<=> (7/3)x < 7\n<=> x < 3\n\nSo : x < 3 and y < 0
930501
There needs to be an "x" there somewhere.  If it were\n-4x + 7 > 15, you'd have \n-4x > 8\n  x < -2 (because you switch the sign when you divide by a negative)
879176
= x(x+3) + 4(x+3)\n= x^2 + 3x +4x + 12\n= x^2 +7x + 12
879052
x^2 - 8x + 16\n\n\nthe person above me said it is -x^2 but that is incorrect because -x * -x = x^2
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
41284
Wait, all the answers are wrong\n\nx^2+4>4\nThen x^2-4x+4>0\nthen (x-2)^2>0\nBut hey, (x-2)^>0 is always true expect when x=2 which equals zero. An square is always positive or 0.\nSo the answer will be any value but 2 or R-{2}\nthese are the evidence:\nPut them in original non equation\nx=0 then 4>0 which is true\nx=-1 then 1+4>-4 so 5>-4 which is true\nx=3 then 9+4>12 so 13>12\n but at x=2 then 8>8 which is incorrect
593331
x + 3 = x (x + 3)\n\nx + 3 = x^2 + 3x\n\nx^2 + 2x = 3\n\nx = 1 or -3