How would I do this in java?
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This is an identical java code for your C++ code,\n\n1. create a filename, say HelloWorld.java,\n\n2. Write in following codes,\n\npublic class HelloWorld\n{\n      public static void main (String args[])\n      {\n           System.out.println("Hello World");\n      }\n}\n\n3. Save it and compile it. Then open the class file using java.
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Something like this maybe:\n\n Runtime.getRuntime().exec("C:" + pathSeparator +\n"jdk1.3.1" + pathSeparator + "bin" + pathSeparator + "javac.exe " + file);  } catch(Exception e)  { e.printStackTrace();  }  }  }
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Type O or Offset <enter>\nClick on Object to be offset <enter>\nType in distance to offset <enter>\nClick on side to offset \nGame over!!!!
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Hi, as of everyprogramming languge. You can input commandline arguments. In java's main method. So this is how you would do your thing:\n\n\n/**\n* This is the main method in your class\n* In this example we will get all parametres \n* and input them in the array list\n*/\npublic static void main(String[] args) {\n\n// Lets initialize the arraylist\nList mylist = new ArrayList();\n\n// Lets input the commandline arguments in the array list\nfor (int i = 0; i < args.length ; i++) {\n\n// Add to ArrayList\nmylist.add(args[i]);\n\n}\n\n// Now we finished loading all\n// the arguments in the arraylist\n// Now lets  Print the list...\n\n// Lets make a Iterator for mylist\nIterator i = mylist.iterator();\n\n// Lets traverse the List\nwhile (i.hasNext()) {\nSystem.out.println(i.next());\n}\n\n// We are done!!\nSystem.out.println("Hope I helped!!! Enjoy :D");\n}
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In Java, "dynamically" is the *only* way to create\nan instance of a class (since unlike C++, it does\nnot allow static or stack-based objects).  Sample\nsyntax is:\n\n    Rectangle rectOne = new Rectangle(originOne, 100, 200);
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Java will not be able to perform such an operation in a straightforward manner, as it is not a Windows-specific language. You will have to write a DLL in Visual Basic / Visual C++ that makes calls to the Windows API to manipulate the Windows Registry (search the Microsoft Knowledge Base for tips here), then use JNI to make calls to your DLL from a Java program. Good luck!\n\nHowever here are some articles offering some additional information.\n\n\nhttp://www.bayequities.com/tech/Products/jreg_key.shtml\nhttp://www.gledix.com/regtoolkit for commercial apps
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Like this:\n\nConsole.Write( "This " );\nConsole.Write( "is on a single line." )\n\nConsole.WriteLine( "" );\nConsole.WriteLine( "This is on a different line" );\nConsole.WriteLine( "This is too!" );
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It is not complicated refer the link below \n\nhttp://www.onjava.com/pub/a/onjava/2003/06/11/jsp_progressbars.html\n\nIt has a sample code that will help u
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You first need to import the class (or classes) and then you will be able to use their methods or  create objects with those classes.\n\nexample: import java.util.*
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The first is a Java Class called Main.\n\nThe second is the constructor for this class. This is what isused to basically set the class up and make an instance of it.\n\nThe third is a method called main which takes in a string array which you have named args. You could call args whatever you want, its juts a general name most coders put on it. It has a modifier which is static and is public so other classes can invoke it. The main method is what is looked for by the java compiler at run time when you execute the program.\nSo a class may look like this:\n\npublic class Main\n{\npublic String greeting;\n\n public Main()\n{\ngreeting = "hello"\n}\n\npublic static void main(String[] args)\n{\nSystem.out.println(args[0]);\nSystem.out.println(greeting);\n}\n}\n\nThis would result in the value stored at args[0] being printed out. Then "hello" printed out on a new line.\nThe args are the arguments that you pass to your program. Most programs take in strings or ints.
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import java.io.IOException;\n\npublic class PosNeg {\n\npublic static void main(String[] args) {\n\nint [] wNumbers;\nwNumbers = new int[5];\nchar c = ' ';\n\nfor (int i=0;i<5;i++) {\nSystem.out.print("Enter the #"+i+": ");\ntry {\nwNumbers[i]=System.in.read()-48;\nif (wNumbers[i]<0)\nwNumbers[i]=(System.in.read()-48)*-1;\nwhile (System.in.read()!='&#92;n'){\n}\n} catch (IOException e) {\ne.printStackTrace();\n}\nSystem.out.print("The number you entered is ");\nif (Math.abs(wNumbers[i])!=wNumbers[i])\n   System.out.println("negative.");\n else\n   System.out.println("positive.");\n}\n}\n}
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In JavaScript you can do it. In Java you cannot, unless perhaps you typeset a char to a byte to an int. But that's not what you mean, is it?\n\nYou need to use at least one method.\n\nEdit:\nOf course, what the people who answered below me don't realize is that everything is in a method ("function" in other languages). Perhaps you want to write your own method to convert strings to numbers... it's still part of a method.\n\nBut why would you want to do that when there are parseInt and valueOf?\nRead down from http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Integer.html#parseInt(java.lang.String)
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Check up the java online tutorial from sun:-\nhttp://java.sun.com/docs/books/tutorial/\n\nYou can also check the following sites for other java related documents / ebooks:-\nhttp://www.freecomputerbooks.com/\nhttp://33367.com/
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Check out Socket programming in java.  It's pretty straight forward.\nhttp://www.javaworld.com/javaworld/jw-12-1996/jw-12-sockets.html
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visit this site\n\nhttp://java.sun.com/learning/tutorial/
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Here is a few loop methods you can use...\nBe sure you have a text box named TextBox1\n\neach will be devided with.\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\n\nDim X As Integer=0\nDim U As Integer=TextBox1.Text\n\nDo Untill X = U\nMsgBox X\nX=(X+1)\nLoop\n\n~~~~~~~~~~~OR~~~~~~~~~~~~~~\nDim X As Integer\nFor X = 0 To TextBox1.Text\nMsgBox X\nNext
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import java.util.*;\npublic class HelloWorld {   \n   public static Stack stack=new Stack(); \npublic static void main(String[] args) {\n   try {\n   String s="this is java string reverse ";\n   reverseString(s);\n   System.out.println("the reversed string value is ");\n   for(int i=stack.size()-1;i>=0;i--){\n   System.out.print(stack.get(i));\n   }\n       } \n   catch (Exception e) {\n            e.printStackTrace();\n       }\n    }\n   public static void reverseString(String s) throws Exception{\n      StringTokenizer temp=new StringTokenizer(s);\n   if(temp.hasMoreTokens()){\n   String s1=temp.nextToken();\n   stack.push(s1+" ");  \n   reverseString(s.substring(s1.length()+1));\n   }\n   else{\n   return;\n   }     \n   }  \n   \n}