light oe wavelenght 500nm in air enters a glass plate of refractive index. find  speed, frequency , wavelength
594770
Well we are not going to do your homework for you. But we will help you along. why not start out by writing down everything you know. they writing down what you need to find. Then look at your equations and find one that uses what you know to find one of the values you need to find.\n\nSo write it up and put it on here and we will help you along.
286486
Just divide the speed by the frequency. So you get a wavelength of 344/50,000=.00688m=6.88mm. The answer above is not correct because the frequency is 50kHz=50,000Hz.
61861
Refractive index of a material in respect to second = speed of light in second medium / speed of light in first medium\n\nand here\nfirst medium = air(since no other medium has been specified)\nsecond medium = water(given)\ntherefore\nrefractive index of water= speed of light in air/speed in water\n=3*10^8 / 2.25*10^8\n=4/3\n=1.333..\nhope u like the explanation
1131513
The refractive index of a material is the ratio of the velocity of light in free space to that in the material.\n\nThe speed of light in free space is the maximum value. Therefore the speed of light in any medium is always less than that of the speed of light in free space.\n\nTherefore refractive index of any material is always greater than one.\n\nIn a given material the refractive index changes for change of frequency of the light wave. The refractive index of violet (High frequency) light will be more than that of red (Low frequency) light.\n\nThe refractive index of a material is greater implies that the speed of light in it will be less. We call this material as optically denser than the material for which the refractive index is less. \n\nFor the same material the density varies with temperature and generally when the density increases the refractive index also increases.
925293
c = lambda x nu\n\nc is the speed of light 3.0 x 10^8 m/s\n\nlambda is the wavelength\n\nnu is the frequency
423752
When light travels through the glass prism, the electromagnetic wave(light) interacts with the atoms and atoms begin to act like tiny transmitters. the light radiated by atoms in the glass "interferes" with the "actual" light from the source\nto produce a "new wave" with its crests at the place where it should have been earlier(in your case where it should have been in future) if the glass had not been there.\nSo we say that the "phase velocity" of light has been increased(or reduced) inside glass by factor and that factor is (1/refractive index) . (i.e.) only the phase changes.if the phase of a wavefront was 5 radian then inside the material it would change to ,say,7 radian.\n        Thus "phase velocity" can be greater than c but the "group velocity" which can transmit information cannot exceed c. (i.e) if I shine light at an electron at a fixed distance and find the time taken by light to reach it and hence disturb it will be found equal to the time taken in the same experiment with the space between me and the electron filled with the medium.
49259
c = yf\n\nc = speed of light (3 x 10^8 m/s)\ny = wavelength\nf = frequency\n\n==> f = c/y\n\n==> f = 3 x 10^8 m/s / 0.032 m \n\nf = 9.38 x 10^9 Hz\n\n-or-\n\nf = 9.38 GHz\n\n:)
172843
force does NOT come into play here at all. the spped of light in a medium is depndant on the refractive index : C/C'= u'/u where u' is the refractive index of the medium. hence when it enters glass u increases hence speed of light dec.
807253
nu = c / lamda\n\nsolve for lamda - you want wavelength.\nc is the speed of light = 3 x 10^8 m/sec\nnu is your frequency = 3.2 e-2\n\nplug into the calculator: 9.375 e9 meters
910620
wave length = speed / frequency\n\n12 = 550 / f\nf = 550 / 12 = 45.8 Hz
698462
ok, you have the frequency and what you want is hte wavelength. You need this equation. The wavelength multipled by the frequency gives you the speed of light. (2.9979x10^8) \n\nThis will give you the answer and if you want to convert from m to nm, you have to know that the relationship is 10^9. There are 10^9 nm in one meter.
267763
The wavelength can be easily found from the formula C=F*L, where C is the speed, F is the frequency and L is the wavelenght. \n\nIn a vacuum, C=299792458 m / s, \n\nso L=C/(1Hz)=299792458 m , since 1 Hz= 1/s. \n\nIn other media, the speed C will be less, and the wavelength L will therefore be less.
777234
the wavelength will be speed/frequency=300000/100100000\n=0.002997002997002997002997002997003 kilometers \nin aproximation\n=2.997002997002997002997002997003 in meters\nor 3meters
737785
I'll let you do the calculation, but the equation you need is:\n\nE = hc/lambda \n\nwhere h is Planck's constant, c is the speed of light in m/s and lambda is the wavelength of the light (in meters). You can find the rest of the numbers in your text book, I'm sure...
571366
The index of refraction of a substance is equal to the ratio of the speed of light in a vacuum to the speed of light in the particular medium.\n\nn = c / v\n\nIf the ratio of c to v is 3 to 1.2, the the index of refraction must be 2.5\n\nn = 3/1.2 = 2.5
11469
the speed of light = 299 792 458 m / s
409297
ok here is the thing\nif you are trying to calculate the thickness of a piece of paper you will need some equpment. Even though there is a lot of room for human error you still can get a fair estimate. \n\nwhat you need is 2 extrememly smooth glass plates and a lineat light source say a laser pointer. \n\nput one glass plate on a table place your paper on the side of the glass and put the other glass plate on the top of the two so that you will get a wedge between the two glasses. \n\nnow point the laser pointer perpendicular to the bottom glass plate and place a screen for reflections. you will get multiple reflections. (btw you need to know the frequency of the light emitted from the pointer.)\n\nthis is the set up\nfor calculations do a little search on air wedge interference \n\ni dont think you will need refractive indexes since you are using the same glass\nwith a little algebra you can figure it out