Factor this expression: 75b^2c^2+60bc^6?
600095
You can factor out 15bc^2\n15bc^2(5b + 4c^4)
148359
No true factored form.\n\na=8 b=6 c=8\nx= (-b +- squareroot[b^2-4ac])/2a\nx= (-6 +- squareroot[36-256])/16\nx= (-6 +- squareroot[-220])/16\nx= (-6 +- 2i{squareroot[55]})/16\nx= (-3 +- i{squareroot[55]})/8
970351
The formula is 10C7 (2x)^3 (2y)^7\n\nThis comes out 122880x^3y^7
142158
Use the FOIL method, since this is really (6x+5)(6x+5)\n\nFirst terms (6x)(6x)=36x^2 +\nOutside terms (6x)(5)=30x +\nInside terms (5)(6x)=30x +\nLast terms (5)(5)=25\n\nFor a total of  36x^2 + 60x + 25
211551
So easy using Cos32= 0.848048 which is the value of BC/12\ntherefore BC=10.2\nthe same for <A= 58 cos58=0.8299  which equals AC/12 = 6.4
397605
12-13b+b^2=(12-b)-(12b-b^2)\n  = (12-b)-(12-b)b\n  =(12-b)(1-b)\n\nThis might not be easy to see, so here is the general approach:\n  Cb^2 + Db + E = (b-B1)(b-B2)\nwhere B1 = (-D + sqr(D^2-4CE) ) /(2C)\n and B2 = (-D - sqr(...) ) /(2C)\n\nIf (D^2-4CE)<0, you cannot factor it.\n\nsqr is square root. In your case C=1, D=-13, E=12, so you get B1=12 and B2=1
181759
36 ;) it comes from (5x+6)^2 which expands to 25x^2+60x+36
830444
d.) 2m^2(6m^6+3m^4+7)
785437
3x^2-75 = 0\n3x^2 = 75\nx^2 = 25\nx = +/-5\n\nThese ones are fun since there are two solutions that you can easily find by taking square roots.  The factored form is:\n\n3(x-5)(x+5)\n\nHope this helps.
702912
150:350  divide terms by common factors\n15:35\n3:7
84658
i got it!\n\nit's 3(2c+7)(c-4d)(c+d)!!!!\n\n6c^3 + 21c^2 - 18dc^2 - 63cd - 24cd^2 - 84d^2\nfirst we take out factor 3:\n3(2c^3 + 7c^2 - 6dc^2 - 21cd - 8cd^2 - 28d^2)\nthen we take out (2c+7) from each pain inside the parenthesses:\n3[(2c+7)c^2 - (2c+7)3cd - (2c+7)4d^2)]\nwe take (2c+7) out:\n3(2c+7)[c^2 - 3cd - 4d^2]\nwe factor [c^2 - 3cd - 4d^2] trinomially:\nc^2 - 3cd - 4d^2 = (c-4d)(c+d)\nthen we get:\n3(2c+7)(c-4d)(c+d)\n\nam i right??\n\n:) yeah i didn't believe myself...\nbut if u really write down all your factors, it's much more easier to take them out. and it WAS fun :))
1099108
I think its 8a^4b^3+6a^3b^5-2a^3b^4
981693
i. c=630/x\n\nii. 900 + (c-2)(x-30)\n  900 + cx - 2x - 30c + 60\n  900 +630 -2x - 30c + 60\n  1590 - 2x - 30c
658148
given 4a^2-12ab+9b^2\n    =(2a)^2-2(2a)(3b)+(3a)^2\n    =(2a-3b)^2
967229
$$$67.50\n\nll you need to do is take 75*0.10=7.5\n\n75-7.5= 67.50
528285
From\n6a^2 + 12ab - 18b2\nFirst, we factor out the common factor 6 to obtain:\n\n6(a^2 + 2ab - 3b^2)\n\nsince, the third term is - (negative) our factors will have different signs;\n6(___ - ___  )(___ + ___).\n\nThe first term's coefficient is 1, whose only factor is 1, so our factors will look like this:\n6(a - ___)(a  + ___)\n\nThe third term is -3b^2, and its coefficient is -3, whose factors are (1, -3), (-1, 3). Of these we use the factors such that when added will give us 2 (which is the coefficient of the second term 2ab. So we choose (-1, 3)\n6(a - b)(a + 3b)
198742
28x^6 - 14x^4 + 35x\n(7x)*(4x^5 - 2x^3 + 5)