a man hlding a stone is in a boat in a pond he drops the stone into the lake..what hapens to the level ofwater
613245
x is greater than y. when the rock is on the boat, it displaced water equal to its weight. when its in the water, it displaces water equal to its volume. the rock's density is greater than that of water. so more weight than volume equals more water displaced while its on the boat which means the level is higher.
478249
You weigh one stone and multiply that by 10.\n\nOne stone=14 lbs.\n\n14x10=140.\n\nThe person weighs 140 lbs.
530819
Com'on people, you should know this.\n\nPut in the ice cube slowly, some water spills out, most of the ice is under water (about 92% due to lower density).  Ice melts in time and the water level drops very slightly due to: 1) water temperature drops a bit (higher density, lower volume), 2)evaporation.
778473
Since the stone did not gain any potential energy, the energy is stored in the slingshot bands\n=F*d\n=30*.2\n=6\n\nAssume all of the energy gets transferred to the stone's kinetic energy in 20 cm\n\n1/2 *m*v^2\nset equal to potential and solve for v\n\n=15.5 m/s\n\nj
169646
The water pressure t a given depth is give as the weight of the water above that depth divided by the area it is being applied.\n\nSo imagine a column of water extending from the top of the lake down the depth.  Calculate the volume of this column of water then using the density of water (1 grams / mL) find the mass.  The take the mass of the water and find its weight (W = mg).  The weight it is the force exerted by the water, but pressure is the force of the water divided by the area it is applied.  So divide the force by the area of the base.\n\nEDIT:\nI see you added the density of water (even though I think my density [1 g/cc] is better).  I will leave you to do your own homework.\n[I also refuse to work with such an ugly unit, I prefer metric]
740680
D. spillting of water\n\n100%
1025160
I'm not sure why you asked twice, however, i'll try for a best answer on both of them lol.\n\nIf i understand your situation correctly, you have a pond (with no inlet or outlet), a boat with no leaks floating in the pond, and ice inside the boat.\n\nThe water level of the pond will not change at all as the ice melts. The water level in the pond would only change if mass were added or removed from the boat. A boat displaces an amount of water equal to the total weight of that boat. A change in ice melting from ice to water does not change its weight. Therefore no change.
495414
125% the density of water.
74937
there is salt in the water
684832
one you find in a pond shop
580754
i haven't done this in a while.\n\nThe volume of the reservoir is equal to (1/2)*(height)*("base")*length.  the reservoir is a rectangular prism with the "base" being the distance across the surface of the water.  We are given the shape of the full volume so we can scale down to the level of the water to find what the volume in the reservoir at its current level.\n\nif you think about the cross-section of the volume, and use half of that forming a right triangle, we can determine the ratio of the surface (the "base") to the height (water depth).  In this case, it is (40/2)/(20*sqrt(3)) or 1/sqrt(3).  so ("base"/2)/(height) = 1/sqrt(3)  and then "base" = (2*height)/sqrt(3).\n\nsubstitute that into the volume equation so that\nvolume = [(height^2)*length]/sqrt(3) or literally,\nV = [(h^2)*L]/sqrt(3).  differentiate with respect to time,\n(dV/dt) = [2*h*(dh/dt)*L]/sqrt(3) and substitute the numbers in:\ndV/dt = 200 - 50 = 150\nh = 10*sqrt(3)\nL = 450\nand solve for dh/dt which is the rate of change of the water level in yds/hour.  these are odd units, you might want to change to inches/hour.\n\ni did it this way and got 1/60 yds/hr or 0.6 inches/hr.\n\nbut again it has been a long time....
929781
What kind of stone?\n.
606896
The water level will go down when you throw the body in.  Try it in your sink.  Fill your sink with water and float a bowl (boat) in it.  Then, fill the bowl with silver wear (body and rocks) or anything more dense than water.  Mark where the water level is on the side of the sink.  Now, take the silver wear out, and put it in the water so it falls to the bottom of the sink.  You will notice that the water level went down.  When the silver was in the bowl, it displaced much more water than when it was at the bottom of the sink.  Therefore, the body will displace more water when it is inside the boat than when it falls into the water.
1078409
Someone with the ability to make & pilot a boat. :P
1022856
A water gauge would have been used. A hosepipe fitted both ends with glass rod, filled with coloured water, and of course it would be level
248368
In order to crack stone bricks loose.\n\nThey first carved the desired shape into large stones at a quarry, then they firmly inserted DRY wooden wedges inside the carvings. Then they soaked it in water.\n\nThis caused the wedges to expand as it absorbed water and it broke the stones loose.
742795
The water provides resistance.