Can someone convert ca. 21000 NL/hr to CFM? And tell me how. Thank you.?
611115
Do you mean ML/hr (mega litres per hour) OR nL/hr (nano litres per hour)?\n\n1 litre  = 0.035315 cubic feet and of course 60 min = 1 hour\n\nSo 1 ML/hr = 0.035315 x 10^6 / 60 = 588.6 cubic feet per min
759551
V1/T1 = V2/T2\n\nFirst convert temperature to Kelvin. 198+ 273 = 471\n\nNext plug into equation\n\n4.81 L / 471 K = 2.49 L / T2\nT2 = 243.8\nthen put it back into C 243.8 - 273 = -29.2 C
170709
Use the ideal gas law: PV=nRT where P is pressure in Pa, V is volume in meters cubed (m^3), n is amount in moles, T is temperature in Kelvin (K), and R is the ideal gas constant 8.314 J/mol K.\n\nSolving for V: V=nRT/P\nYou have to convert pressure from atm to Pa. The conversion factor is 1 atm = 101325 Pa\n\nV=(2.44 mol)(8.314 J/mol K)(343 K)/243180 Pa\n\nV=0.0286 m^3
788892
OF2 (~104), NF3(~107), CF4 (~109.5),  BF3 (120), BeF2(~180)
363092
Well I'm not going to do the calculation for you but you can.\n\nDo a web search and you'll find dozens of sites to help you if you don't have a fluid flow handbook.
489685
Near about\n50 μΩcm\nat 20°C.
273201
1 cu m/hr = 1,000/60 L/min = 100/6 L/min = 16.67 L/min\n\nTherefor, the tank will be filled up eventually.\n\n1/2 filled in 5,000/60 Min = 83.33 min\n10 Cu m = 10,000 Liter\n\nOther half in 5,000/43.33 = 115.39 Min\n\nTotal time = 198.72 min
323034
LFM * Area = CFM\n\nIf your booth has a 32" x 7 ft opening, then it's"\n\n2.67 * 7 * 100 = 1869 CFM
185993
About 450?  Do you mean 4500?  Go to Perma-cool's web site and they have a graph that tells you what cfm for the size of your engine.  I have a mustang with a 302 and it needs to be around 3000cfm.  I would imagine a 360 would need more.
379801
This website does all the work.  Just put in the values!  Good luck.  http://www.onlineconversion.com/temperature.htm
240210
To convert fahreheit temerature to celsius:\nsubtract 32\nmultiply by 5\ndivide by 9.\n\nI'll let you do the math.
208359
check out http://compensation.blr.com/compensation/employee_performance_evaluation_samples.cfm
775809
I believe the units of your supposed answer are wrong.  They should be kJ/mol and not kJ.\n\nHeat = m * Cp * DeltaT = 60 * 4.186 * (13.2 - 27.2) = - 3516 J\n\nThis heat is absorbed by 28.7 g of KI.  Per mole (MW(KI) = 166 g/mol), the heat will then be:\n\n28.7 g ===> 3516 J\n166 g ===> x\n\nx = 3516 * 166 / 28.7 = 20,340 J/mol = 20.3 kJ/mol
317109
Take table for R134a refrigerant:\n\na) delta s = entropy change\n--inlet for evaporator assuming 50%moisture= interpolate to get S \n@200kpa for R134a\n0       Sg   \n0.5     S\n1       Sf\nget Sg and Sf from table at 200kpa for R134a. \n \n--out for evaporator = Sg at 200Kpa (get from table) since it is sat vap.\n\nthe difference of both Sfg and Sg is the answer.\n\nb)  delta S = Q / T  where Q = 120 KJ and T = -5+273 = 268K\n\nc) add both a) and b) is the total entropy
969517
Use the clausius-clapeyron equation for this one.\n\nln (P/Po) = (delta H/R ) (1/To - 1/T)\n\nPo is one atm at To = 61.7 C based on the info in the question.  T is 36.2C.  This formula requires absolute temps, so convert to K.\n\nSo:\n\nln (P/1 atm) = 31400/8.314 (1/334.8K - 1/309.3K)\n\nIf I didn't fat finger the calculator P = 0.39 atm.\n\nHope it helps.
148738
Homework, huh?  Badly copied from the source.  Make it an answerable question, clean up the gibberish and try again.  For instance, 90 degrees phase lag at what frequency?  Sorry to be curmudgeonly, but this shouldn't be just about getting answers without understanding.  Anyway, here's a hint.  At 90 degrees, Xr=Xc, and RC=1/(2*pi*f).  For phase lag the R is in series and the C in shunt.
958888
Use the formula:\nQ (heat) = Cp (Heat Capacity) * delta T (Change in Temperature)