I just need help in explaining how to translate this word problem into equation so that I can do them.?
599170
For the value of t for which the height is 12, substitute 12 in for h, and solve for t.\n\nh = -16t^2 + 32t\n12 = -16t^2 + 32t\n16t^2 - 32t + 12 = 0\n4t^2 - 8t + 3 = 0\n(2t-3)(2t-1) = 0\nt=1.5s or t=0.5s\n\nThere are two answers: one is on the way up, and the other is on the way down.\n\nFor the second question, how long was he above 14 feet, you can do the same thing.\n\n14 = -16t^2 + 32t\n16t^2 - 32t + 14 = 0\n8t^2 - 16t + 7 = 0\n\nThis cannot be factored, but can be solved using the quadratic formula, giving the solutions:\nt = 1 + (sqrt2)/4\nt = 1 - (sqrt2)/4\n\nThese solutions again represent a value for on the way up and on the way down.  The difference between the two values is:\n\n2*(sqrt2)/4 = (sqrt2)/2 which is approx 0.707 s
840271
Make sure the order is maintained:\n\nAdd 1 to x: x + 1\n\nThen multiply by 6: (x + 1) * 6\n\nFor the other equation, divide by 6: x / 6\n\nThen subtact 1: (x / 6) - 1\n\nThe trick is to take your time and read the problem statement throroughly. Good luck.
872092
It is always understandable when a student feels overwhelmed by "word problems" because they are often presented in an intimidating manner.  If only they could be FUN again ... if YOU wrote the problem, I believe you might find it fun!  :-)\n\nBut let's allow ourselves some joy once we uncover all the unknowns in this problem.  Perhaps we'll get results from converting "written words" into "mathematical expressions."\n\nWhat's most important is that you understand the shape involved (think "shoe box") and how the "openings" are placed (think "windows" on three faces of the shoe box).  All the openings are understood to be identical.\n\nUsing only the letter X -- which stands for the length of an opening -- we can indeed come up with expressions for every other dimension of the container, as well as the openings.\n\nX = Opening LENGTH (given)\nX-2 = Opening HEIGHT ("length is 2 more than height")\n\n2X+8 = Container LENGTH ("8 more than twice X")\n3 = Container HEIGHT (given)\nX+2 = Container WIDTH ("2 more than length of opening")\n\nThe surface area of the container's sides (minus the three openings) is given as 300 square meters.  The equation is also given as 2 (sides) + 2 (front/back) + 2 (top/bottom) - 3 (openings), so let's just set these equal:\n\n300 = 2 (sides) + 2 (front/back) + 2 (top/bottom) - 3 (openings)\n\nAll we need to do is to write, and then substitute, expressions for the areas in parentheses.\n\nSide area = length * height = 3 (2X+8) = 6X + 24\nFront or back area = width * height = 3 * (X+2) = 3X + 6\nTop or bottom area = length * width = (2X+8) * (X+2)\n____________________________ = 2X^2 + 12X + 16\nOpening area = length * height = X (X-2) = X^2 - 2X\n\nTime to substitute:\n\n300 = 2 (6X+24) + 2 (3X+6) + 2 (2X^2+12X+16) - 3 (X^2-2X)\n\nNow that this (long) equation has been written, it is necessary to solve for X, since we need that value in order to calculate what the problem asks for:  The area of each element.\n\nCollect like terms:\n\n300 = 2 (6X+24) + 2 (3X+6) + 2 (2X^2+12X+16) - 3 (X^2-2X)\n300 = 12X + 48 + 6X + 12 + 4X^2 + 24X + 32 - 3X^2 + 6X\n300 = X^2 + 48X + 92\nX^2 + 48X - 208 = 0\n\nWhat we hope is that the trinomial on the right-hand side of this equation is able to be factored easily!  Does it?\nMy approach is to factor '-208' and see whether I can 'build' the linear term's coefficient ('48') from the factors.\n\n-208 = -2 * 104 = -2 * 2 * 52 = -2 * 2 * 2 * 26 = -2 * 2 * 2 * 2 * 13\n\nCan we group these factors into (one positive, one negative) numbers that produce 48 when added together?  Yes!\n\n(-2*2) + (2*2*13) = -4 + 52 = 48\n\nWe got lucky ... the '-4' and '52' provide the perfect pair of factors needed to create a 48 (through addition), so we can now factor.\n\n0 = (X-4)(X+52)\n\nThings are getting better still, because only one of the zeros (some call them 'roots') from the right-hand side will be positive.  The zeros are 4 and -52, and we will only choose the 4, since it represents a physical measurement of length (of an opening).\n\nWe can go back to the expressions above and substitute X=4.\n\nSide area = 6X + 24 = 6(4)+24 = 48 sq. m\nFront/back area = 3X + 6 = 3(4)+6 = 18 sq. m\nTop/bottom area = 2X^2+12X+16 = 2(4^2)+12(4)+16 = 96 sq. m\nOpening area = X^2 - 2X = 4^2-2(4) = 8 sq. m\n\nI hope this helps!
239058
You have to solve for one and substitue into the other...\n\nLets solve for x...\n\n2x + 3y = 40 \n2x = 40 - 3y\nx = (40 - 3y)/2\n\nThen Substitute in the other.\n-2x + 2y = 20\n-2(40 - 3y)/2 + 2y = 20  (the 2's in the first set cancel becaue 2/2 = 1 so...\n-(40-3y) + 2y = 20  (then distribute the -)\n-40 + 3y + 2y = 20 (combine like terms)\n5y = 60\ny =12\n\nThen sub y into the equation to find x\n\n 2x + 3y = 40 \n2x + 36 = 40\n2x = 4\nx=2\n\nDouble Check in the other equation...\n-2x + 2y = 20\n-2(2) + 2(12) = 20\n-4 + 24 = 20\n20 = 20 These equal so x=2 and y=12!
820052
I do not understand how the "problem" has to do with the question. But to answer the first part...\n\nThe cell should contain \n=POWER(number, power)\n\neg. =POWER(5, 2) would display 25\n\nA cubic root would look like this...\n=POWER(number, 1/3)
576570
algebra...usually (well i do) set up a equation for everything, and solve for the variable. If u need help u can always get help in www.algebra.com .....
1045152
You want to basically simplify the expression through taking out a common factor of each term in that expression:\n\nso 4 goes into both 4a and 16\nso 4(a+4) I believe would be the correct answer. \nDon't get mad if I'm wrong.
865937
w=x\nl=2x\n2w+2l=P\n2x+2(2x)=2\n2x+4x=2\n6x=2\nx= 1/3\n\nwidth is 1/3 and length is 2/3
780298
first u distribute the - to the stuff in the parenthesis so you have\n7x^2-3+x^2\nthen combine like terms\n8x^2-3
518727
Multiply the first equation by 2.\n\nSubtract the second equation from the new first equation.\n\nSolve for y.\n\nTake your value for y and substitute it into the original first equation.\n\nSolve for x.
589722
Step 1: Solve one equation for one variable in terms of the other.\nStep 2: Plug that into the other equation and solve for the second variable.\nStep 3: Plug the second variable into the first equation and solve for the first variable.
1087622
Use the explanation given in the last question you asked, and just put 12 in place of 4 from the previous problem.
701654
Instead of memorizing all the equations,understand how they are derived.Try to do it yourself.If you can't go to someone who knows for help.
934652
So let's say the problem looks like this\n\n   11\nx 12\n--------\n        <-----the answer from 11*2\n       <------answer from 11*1\n\nfirst hide the 1 from the 12 and work out the problem as 11*2\nthen work on multiplying the 1 with 11 but make sure you start putting your answer down below your first answer and the answer starts in the column that is below the 1 from the 12.\n\nfinally when the two answers are found, you can add them and get your final answer. SOOO here's what it looks like\n\n      11\n   x  12\n--------------\n           22    (this is from 11x2)\n +  11       (this is from 11 x1)\n------------\n     132 = final answer!
855129
Word problems like this can be hard.  Everybody has problems with them sometimes.\n\nIt does help to draw it out.  So you draw a little rectangle like this:\n ______________\n|                            |\n|                            |\n|______________|\n\n2 of the sides are 120 m and the other 2 are 150 m.  So you take 2 times each of these numbers and add them together:\n2(120) + 2(150)\n\nThat's your perimeter, in meters.  Now if your poles are 2 m apart, you don't need one for every meter you get in your answer, you only need 1 every 2 meters.  So you divide your answer by 2, and that gets your number of poles you need to put around the field.
969755
Relax\n\n1)) (5x + 7) + (x - 2) = 5x + 7 + x - 2 = 5x + x + 7 - 2 = 6x + 5\n\n2)) 2 X length + 2 X height = perimeter\n\n  (2 X x) + (2 X (x - 3)) = per = 2x + (2x - 6) = cir = 2x + 2x - 6\n\n  perimeter = 4x - 6,   or 2 ( 2x - 3)\n\n3)) same as # 2;\n\n  2 X (t + 5) + 2 X 2t = 2t + 10 + 4t = 2t + 4t + 10 = 6t + 10 = per\n\n4)) (t - 5) - (3t - 1) = t - 5 - 3t + 1 = t - 3t - 5 + 1 = -2t -4\n\n  or -2 (t + 2)
727014
start with the O... they are always -2\nsince there are 2, and the compound must balance...\nPb must be +4\n\nso you get +4 -2