R there formulas for 1=2?
607013
Another Method.\n\n-1 = -1\n\n-1/1 = 1/-1\n\nSquare root both sides,\n\nSQR(-1/1) = SQR (1/-1)\n\nExpanding,\n\nSQR(-1)/SQR(1) = SQR(1)/SQR(-1)\n\nSQR(-1)/1 = 1/SQR(-1)\n\nCross Multiply,\n\nSQR(-1)*SQR(-1) = 1\n\n(SQR(-1))^2 = 1\n\n-1 = 1\n\nDivide by 2 on both sides,\n\n-1/2 = 1/2\n\nAdd 3/2 to both sides,\n\n-1/2 + 3/2 = 1/2 + 3/2\n\n1 = 2 (ans)
626330
1) 2x^2 + 3 = x\n2x^2 - x + 3\n\nQuadratic formula:\n[1 +/- sqrt(1-4*2*3)]/(2*2)\n[1 +/- sqrt(-23)]/4\n\nx= 1/4 + sqrt(23)/4 * i\nor\nx= 1/4 - sqrt(23)/4 * i\n\n2) (2m - 7)^2 - 2(2m - 7) - 24 = 0\nSay X = 2m-7\nSo: x^2 - 2x - 24 = 0\n(x-6)(x+4)=0\nx=6,-4\n\n2m-7=6\nm=13/2\n\nor\n\n2m-7=-4\nm=3/2
799171
This is works like n-2^(n-2) \n1-1 = 1-2^(2-2) = 1-2^0 = 1-1\n3-2 = 3-2^(3-2) = 3-2^1 = 3-2\n5-8 = 5-2^(5-2) = 5-2^3 = 5-8\n7-x = 7-2^(7-2) = 7-2^5 = 7-32 \nThus x is 32.
674498
1+1=2. That's it. The answer for everything else would be simply 42
733305
M - 1 = D + 1\n2 * (D - 1) = M + 1\n\ncan you solve the rest as two equations with two variables?\nM = D + 2\n(2 * D) - 2 = M + 1\n \nM = D + 2 substitute into\n2 * D = M + 3\n\n2 * D = (D + 2) + 3\n\n2 * D = D + 5\n\nLooks like D = 5.\nSo M = D + 2 = 7\n\nDonkey has 5 and Mule has 7.\nCheck it out and see if it works.
504635
Good:\n\nIt is not possible to find the exact value of 'a' and 'b' by only one equation in the form of numbers.\n\nYou can find the value by letting values of 'a' or 'b' and by this a number of values will be determined.\n\nJust divide the whole equation by 'a' than a simple form will be obtained.
278006
Actually, there are two:\n\n0+0=0*0=0\n\nand\n\n2+2=2*2=4\n\nIn both instances, the sum equals the product.
282131
Note that although x1=x2 satisfy the equations but some distinct values for x1 and x2 can satisfy it too: \n\nsuppose x1 and x2 are distinct and so x1-x2 is not zero\nthen eq1 is:\n\n4(x1-x2)(x1+x2)-4(x1-x2)=0\n\n---> 4(x1+x2)-4=0\n---> x1+x2=1\n\nand eq2 is:\n\n-3(x1-x2)(x1+x2)(x1^2+x2^2)+2(x1-x2)(x1+x2)=0\n\nomit (x1-x2)\nand substitute x1 by 1-x2 to get:\n(1-x2)^2+x2^2=2/3\n\n---> x2=(3+-sqrt(3))/6\n\nso we have two values for x1 and x2 which satisfy the equation and x1 and x2 are distinct.
313786
r is 2/1 = 2\n\nformula for nth term in a*r^(n-1)\n\n24th term is 1(2^23) = 8388608\n\nSum of n terms is a(r^n -1)/(r-1)\n\nSum of 10 terms is 1(2^10 -1)/(2-1) = 1023\n\nIn all the formula 'a' is the first term i.e, 1
838286
well Honestly dear Megan i don't think its correct , coz equation should have ONE " = " \n\nit must be something like this \n-4r ² ± 21r=r+13\n\nGood Luck
1023685
1= 1/2 +1/2\n\nThat is two "1/2"s\n\nThat was easy.
238182
p1    p2\n--- = ---\nq1    q2\n\n 5     2\n--- = ---\n 2    q2\n\nCross multiply,\n\n4/5
411302
cos^2 (2x) is equal to 1-sin^2(2x), remember, sin^2(x)+cos^2(x)=1
776599
http://www.purplemath.com/modules/fcns2.htm
869887
If you have 2 equations, just solve for one variable for one of the equations. Take that equation and plug it into the same variable for the other equation. You will solve for that variable, and plug in that number to any of the 2 equations to solve for the other variable.
655260
2=-1=x\n2+1=x\nthere fore x =3
114499
Break it down into three sections determined by the points where the absolute values change sign.\n\nfor 2 < x, g(x) = (x-2) + (x+2) = 2x\n\nfor x < -2, g(x) = -(x-2) + (-(x + 2)) = -2x \n\nfor -2 < x < 2, g(x) = -(x-2) + (x+2) = 4