Partial Fraction plz solve?
602043
I haven't done partial fractions in a while, so you might want to check this: \n1/(x+3) - 2/(x+3)^2 + 5/(x-7)
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
68882
1) yes, this is correct as written.  Not sure what else you need? \n2) 10/14?\n3) 2 (1 is not a factor)\n4) -6(x+1)\n5) 5 1/4 or 21/4 (same thing)\n6) 1 4/9
423596
1/14 X 100% = 7%\n\nu r right
28370
x(x-3)/x(x+2) divided by (x-3)(x-2)/(x-2)(x+2)\nfrom first fraction curtail x \nfrom second fraction curtail (x-2) and we have\n(x-3)/(x+2) divided by (x-3)/(x+2), which is 1\nx^2 - 5x + 6 = (x-2)(x-3)\nx^2 - 4 = (x -2)(x+2)
841476
When you retry the problem remember to move only yout z^-2 up don't move the 4 that is a constant in the denominator. \n\nyou should get this . (12x^5z^3/30x^7y^7) * (15x^2z^10/4y^3)\n\nremember to simplify as best you can prior to multiplying.\n\ntry from here and let me know what you get.
891258
Try 1 ÷ 3\n\n1/3 = 0.33333.....\n\n~ ♥ ~
982041
Well dear\n\n-If the first root is " α " and the second roots is " α + 3"  so have  \n▪x ² - (α + β) + α β = 0 \n▪( x - α )(x - β ) = 0 \n-b/a = α+ β  \n&\nc/a = α β\nso we have ; \nc/a = m/4  \n-b/a = - ( -16) / 4 = 4 \nα + α + 3 = 4 , 2α + 3 = 4 \nα = 1/2  ,  β = 3 1/2 \n2 /a = α β  =>  m/4 =  1/2 * 7/2  , m = 7\n\nGood Luck dear
770136
P = Ae^rt\nP = 100e^(.2*52)\nP = 100 * 32824.21\nP = 3282421
620534
First, take the partial derivitives...\n\nSo, the partial with respect to x is...\n\n2xy^3z^6\n\nAnd the partial with respect to y is...\n\n3x^2y^2z^6\n\nAnd the partial with respect to z is...\n\n6x^2y^3z^5\n\nThis gives you the gradient...\n\n(2xy^3z^6, 3x^2y^2z^6, 6x^2y^3z^5)\n\nIn which you plug in the point...which simplifies to...\n\n(-2, 3, -6)\n\n...So this is a vector...so it should be denoted\n\n<2, 3, -6>\n\nTo find the magnitude of this vector, simply take the root of the sum of the squares...\n\nsqrt(4 + 9 + 36) which = sqrt(49) = 7\n\nCake :)
743185
1. 2/.25\n\n2. 1/4\n3.26/51 and1/4\n\n4.1/6\n1/2
443446
S (x^2-4x) / (x^3-6x^2) dx\n\nlet u = x^3-6x^2\nthen du = 3x^2-12x\n\nS (x^2-4x) / (x^3-6x^2) dx = (1/3) du/u\n= (1/3) ln u + C\n= (1/3) ln (x^3-6x^2) + C\n\nAnswer B.
361025
Here, you need the exercise. Show how\n1/(x^2-1) + 1/(x+1) = x/(x^2-1)\nSimple enough fraction. And it's free.
269746
Make 2 7/15 an improper fraction, flip it over to its reciprical and mulitply the two.\n\nBoy...I hope I got that.  *bits fingernails*
901005
Use the following equation and solve:\n\nP1V1/T1=P2V2/T2\n\nT2=P2V2T1/P1V1\n\nalso note the significant figures!!!!
766790
1. 5m^2 - 15mp - 2mr - 6pr <-- Impossible to factor by grouping. It needs to be either, exactly one of the signs needs to be reversed.\n\n2. 6-3x-2y+xy\n(6 - 3x) - (2y - xy)\n3(2 - x) - y(2 - x)\n(3 - y)(2 - x)
837423
ilurb is correct, alternatively you could multiply both side by 2 to clear the fraction\n\n2y - 10 = x + 4\n\n2y = x + 14\n\ny = (1/2)x + 7\n\neither way you get the same answer.