If anyone is familiar with cryptology questions, can you help?
608095
If you substitute each letter for a letter three places earlier in the alphabet, so that D becomes A, E becomes B, etc., you get\nJOEYOUHAVEBEENGIVEPROBLEMNUMB...\nEURFINALEXAMBONUSPROBLEM
393385
This link will solve your problem, just download the utitlity.  \nNow you better rate my answer the best one since it does not include calling any one :)\n\nhttp://www.softpedia.com/get/Security/Decrypting-Decoding/Asterisk-Key.shtml
849772
Help us, help you. \nGive some context for the Trust SCC. What is it, what does it do.?\nOne other thing, does this belong in Mathematics? Or should it be somewhere else? \nOf course the answer to the first question will tell us the answer to the second.\nThanks!
966057
well well..the second time i see the same question!!\nshow some of ur work buddy.. ur a degree student and u dont simply put the questions on others..u wud never pass that way...\nso prove that u have tried ur best to solve this problem..show some coding that u have made!
640029
There's a good book by Simon Singh, titled The Code Book that goes through the entire history of cryptography and some of the background.  His website also has information and links on crypto theory.  If you're looking for the most up to date information, ie on elliptical cryptography though or RSA do a search on scholar.google.com for the actual papers.
286646
Try this: \nhttp://www.research.att.com/~njas/sequences/?q=3%2C3%2C4%2C5%2C7%2C8&sort=0&fmt=0&language=english&go=Search\n\nthere are several possible solutions, see what matches what you wanted
1154070
INTRO:\n\nC-\nC5-E5 (4x)\n\n   \ne:-------------|----------------------------|-------------|-5~-4~-2~-----8--7--5~--|-------|\nB:-------------|----------------------------|-------------|-6~-5~-3~-OR-10~-9~-7~--|-------|\nG:-------------|----------------------------|-------------|-5~-4~-2~----10~-9~-7~--|-------|  (2X)\nD:-------------|---0-2-3~~-2~~-0-2~-0-------|-------------|-------------10~-9~-7~--|-------|\nA:-3~~-0-------|-0---------------------xx---|-3~~-0-------|--------------8--7--5---|-----0-|\nE:-------3~~-0-|-----------------------xx---|-------3~~-0-|------------------------|-3~~---|\n\nFirst Stanza:\n\nC             em\nSige, pag kasama ka naman,\n          Am                    F\nKitang-kita ko ang ating kasiyahan\nC                  em\nSige, wag na nating pigilan\n   Am               F\nAt di magtatagal, tayo ay liligaya\n\nRefrain:\nem         Am            em   Am  \nOkey lang naman ang ating usapan\n              em   Am           F\nHindi na lang babalikan ang nakaraan\n         G\nAng nakaraan\n\nChorus:\nC                em\nAyos lang, basta't kasama \nAm(break)\nKonting alak lang,\n  F\nKahit walang pulutan\nC                em\nAng minsan, naaalala\nAm                         F\nDi magtatagal, tayo ay liligaya\n\nSecond Stanza: (do first stanza chords)\n\nSige, pagpatuloy niyo lang\nUnti-unting lunurin sa kasiyahan\nSige, pagpasensiyahan na lang\nMga pumipigil sa ating ligaya\n\n(Repeat Refrain)\n(Repeat Chorus)\n\n\nADLIB: Do Chorus chords\n\ne:--------------------------------------------------------------------------------------------------|\nB:--------------------------------------------------------------------------------------------------|\nG:----------------------------------------------------------------------------12--------------------|\nD:-10-------12-------14-------15-------14----12----12-------14-------15----------------15----14-----|\nA:----10-10----10-10----10-10----10-10----10----10----10-10----10-10----10-10----10-10----10--------|\nE:--------------------------------------------------------------------------------------------------|\n\ne:--------------------------------------------------------------------|\nB:----------------------------------------------------13-13s17-15~----|\nG:-------12-------12-------12-------12---12b~~~-12s14-----------------|\nD:-14h15----14-15----14-15----14-15-----------------------------------|\nA:--------------------------------------------------------------------|\nE:--------------------------------------------------------------------|\n\ne:----------12-15-12----------------------------12-15-12-------------------------------------------|\nB:----13-15----------13-15--(4x)-THEN-----13-15----------15p13h15br15-15---13----------------------|\nG:-12----------------------------------12-------------------------------------14-12-----12fb~~~~---|\nD:----------------------------------------------------------------------------------13-------------|\nA:-------------------------------------------------------------------------------------------------|\nE:-------------------------------------------------------------------------------------------------|\n\n(Repeat Refrain)\n(Repeat Chorus 2x)\n(intro)
734903
Sure... Once you hack this sentence, decipher it and tell me what it means, I will then help you.. \n\n14  Y0U C4N R34D TH15 Y0U R34LLY N33D TO G3T L41D\n\nGood Luck
171860
Sounds like a homework question, and someone is at a losss for ideas.
778809
For encryption there are some softwares available on the net , u can get them by searching the relevant word.\n\n  The word may be like this  "Edword+Osborme+Wikson"
1111079
Read "Applied Cryptography" by Bruce Schneier - It's a comprehensive academic survey of the field of Cryptography. \n\nIf you want to have real fun, why not take a look at Stephen Wiesner's work on 'quantum money', and the extension of the concept to 'quantum cryptography'. I'm sure you can Google up references!
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
396820
i think a transposition cipher cuz if u figure out one letter, you have figured out the rest. in a substitution cipher, a letter could be any letter and if you found one, you still would not know the others.
678621
I don't understand this question OR the first answer.......what is this......a secret language?
243995
Depends on how much you want to know. I found the following "scholarly" articles that may be of interest. These may be hard to read but you can at least try to obtain them from your library. I would suggest that you read the Nat(ure) Biotechnology article, some of the Nature publications are very prestigious and only publish very good research papers.\n\n1: Tanaka K, Okamoto A, Saito I. \nPublic-key system using DNA as a one-way function for key distribution.\nBiosystems. 2005 Jul;81(1):25-9. Epub 2005 Feb 25.\n\n2: Leier A, Richter C, Banzhaf W, Rauhe H. \nCryptography with DNA binary strands.\nBiosystems. 2000 Jun;57(1):13-22.\n\n3: Dove A.\nDNA cryptography.\nNat Biotechnol. 1999 Jul;17(7):625. No abstract available.\n\n4: Beaver D.\nComputing with DNA.\nJ Comput Biol. 1995 Spring;2(1):1-7.
776173
1) this operation is made up of two steps, that means the probablility of the whole operation = the multiplication of the probablility of every step\n a) probaility of a 1 from the first box = 1/6, the other box = 1/7 , so P(Both will be 1's) = 1/7 * 1/6\n\nb) p(Exactly one of the will be a 2) = 1/6 * 6/7 + 1/7 * 5/6 \n\nc) P(Both will be even) = 3/6 * 3/7 \nd) P( Exactly one of them will be even) = 3/6 *4/7 + 3/6 * 3/7\n\ne) P(At least one of them will be even) = 1- both of the odd = 1- (3/6 * 4/7)\n\n>> as for the sample space it would take me forever to write it down! sorry\n\n2) Not sure about this one\n3) a) 5%\n    b) 16% >> dont know wut details to include its just a law
779599
srikanthj is talking bullsheit he doesnt know anything lol what file in c drive then???i bet you the file is encrypted so you need to crack it using caesars cypher noob