Rank the energy of one photon of the following types of  Electromagnetic Waves in decreasing order?
609476
gamma rays\nvisible light\ninfrared light\nmicrowaves
681366
velocity = frequency*wavelength. velocity is constant, therefore decreasing the wavelength will increase the frequency.\n\nFor a photon E = hf (h = planck's constant, f = frequency) so a higher frequency will produce higher energy.
17746
electromagnetic energy (light) is converted to chemical energy, or rather chemical potential energy.
328045
Yes, a radio wave is an elecromagnetic wave just as light, X-rays, microwave, gamma rays, etc.  All carried by photons.  Radio waves are the least energetic, or longest wavelength, of the electromagnetic spectrum.  Sound waves, on the other hand, are like waves in water, or sand dunes-they are movements of atoms-air, in the case of sound-they are not carried by photons, do not go the speed of light, and are not electromagnetic.  All electromagneic waves go the speed of light, since they are carried by photons.  The only difference between a radio wave and a visible light wave in the frequency of the wave and the energy of the photon (both of which are integrated).
1033843
e=mc^2\n\ne (energy)=m (mass) times c (the speed of light) squared
133248
First, read more about the wave-particle duality. Yes, light is more than just a photon or a "single ray", it comes in waves. But the energy packets are in discrete bundles or quanta ---> which leads us into quantum mechanics. This all arose from the blackbody radiation problem, where radiation could be modelled as oscillators, thus Plancks constant is of units Joules*second or Energy per frequency. And as you said, if Plancks was energy per frequency, why isnt the energy of a photon numerically the same? You are implicitly assuming time is a non-factor or time is perfectly "1" second, but the light has a frequency characteristic to its color/wavelength. And once again, we're back at light is a photon AND a wave.
439976
lower wavelength is higher energy.  Planck's law holds that Energy equals a constant (Planck's constant or h) times frequency.  Frequency is inversely proportional to wavelength, so wavelength is inversely proportional to Energy.\n\nIn practical terms, I remember this because blue and ultraviolet light is higher energy than red and infrared.
355213
In y = A sin Bt, B is the frequency in radians/second, or B = 2pi*f, where f is the frequency in cycles/second, or Hertz.\n\nI assume by "c= 3 x 10^10", you're referring to the speed of light, which is 3*10^10 cm/sec.\n\nf = c / wavelength, so f = 3*10^10 cm/sec / (3*10^-10cm) = 3*10^20 cycles/sec or 3*10^20Hz.\n\nSo B = 2*pi*f = 2*pi*3*10^20 = 6*pi*10^20 radians/sec.  That's about 1.885*10^21 radians/sec.\n\nNote that these equations hold for all electromagnetic radiation, including radio waves, microwaves, IR, light, UV, X rays, and gamma rays.
139259
I'm not sure what you are asking.  Here are two possible answers:\n\nFirst:  E = h*nu\n\nIs the equation for the amount of quantized energy in light where h is Planck's constant, 6.626e-34 Joule seconds, and nu is the frequency in Hertz.\n\nThis determines the "raw" energy in the light.  As you know, going from electricity back to light varies in efficiency.  An electric light bulb requires much more electricity than a flourescent bulb to produce the same amount of light.\n\nSecond: hf = phi + Ek\n\nThis is the equation for the photoelectric effect, where electrons are ejected from a material being struck by light.  h is again Planck's constant and f is the frequency of the incident photon.  Phi is the amount of energy required to remove an electron from its binding and Ek is the kinetic energy observed.
932169
Gamma rays have the smallest wavelengths and the most energy on the electromagnetic spectrum. There isn't much physical difference between gamma rays and x-rays besides the fact that the gamma rays vibrate faster. They measure 10 to the negative power of 11 all the way to 10 to the negative power of 14 (meters). I hope I've answered your question. My knowledge of the electromagnetic spectrum only extends so far.
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1. magnetic field B\n\n2. relativistic mass at double light speed, as you see it's imaginary ;)\n\n10. relativistic kinetic energy\n\ncould only guess about the rest. i hate tensors.
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I'd say option B. Each photon contains one fragment of the image. But actually, there are no such things as photon particles. The "waves" that "photon particles" create are actually part of the photon themselves.
353533
If you could find a transition between an inverted state and a ground state of 1 joule, you could probably make a laser of that frequency. At this point, hard gamma rays are the limit we have done.
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Radio Waves\nInfrared light\nVisible Light\nGamma Rays
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Electromagnetic radiations or waves are propagating in space. Electromagnetic waves have electric and magnetic components, the electric field and the magnetic field oscillate at right angles to each other and to the direction of propagation.\nAs any other waves e.m. waves are characterized with  frequency (number of vibrations in one second), wavelenght (the distance from one crest to the next crest in the sinus wave) and radiant energy. \nThe range of the e.m. waves is called the electromagnetic spectrum. The highest frecvency and energy / the lowest wavelenght e.m. radiations are gamma rays (are shorter than the size of the nucleus in the atom) then X rays, ultraviolet radiations, visible light, infrared radiation (heat radiation), microwaves, and radiowaves which has the lowest frequency and longest wavelenght (can be several km long). We can see only the visible light, the other e.m. radiations are invisible to us. But they can have an effect on our organism. They have a lot of technical, medical and other use.\n\nfor more see >>\nhttp://en.wikipedia.org/wiki/Electromagnetic_radiation
216960
They are alll electromagnetic waves.  They all have different frequencies.  Radio waves have the lowest and gamma rays have the highest.
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i presume you have the energy values for the different levels?\n\nif so you use the equation E=hc/lamda to find the wavelength for each energy transition in the series.\n\nThe red line will be about 575nm and the purple line will be about 375nm.