For sperically diverging waves, intensity is proportional to which of the following?
606263
1/r^2\n\nIf you ask why, think of intensity as a flux given by \n\nFlux =  Total flow / (cross sectional area)\n\nNow the wave diverges spherically, but the total flow remains constant, owing to conservation laws. \n\nSo flux = Total flow / (Surface area of the sphere)\n\nNote that the total area of the sphere = 4*pi*r^2. \n\nThat gives you the r^2 term in the denominator. \n\nThis is nothing but a demonstration of the inverse squared law, which is much a part of classical theories of gravitation (Newton's law), electrostatics(Coulomb's law) and of the theory of sound intensity.
428587
Depending on the kind of lens - diverging or converging - it either concentrates light on a point (converging), or its sends light out as if it _came_ from a focal point on the other side.\n\nfor more information, look here:\nhttp://en.wikipedia.org/wiki/Optics
667863
Vertical interval\ndifference in altitiude between observer and target (or point of burst)
839609
Curl, divergence, gradient.
593131
The incident ray is perpendicular to the surface of reflection.\nThen one has the least distance case.
729175
A wave with y-values going from 1 to -1. An x-intercept exists at pi/2
800734
Speed of waves = wavelength X frequency of waves.
948797
convection, advection and radiation
845549
The most typical example of this kind of waves are the sound waves, propagating in any medium. If no sound the density of medium d=constant through out the whole volume. If sound then d1=d+delta means compression, d2=d-delta rarefaction. If d1 & d2 alternate along the path of the wave with certain period we can describe it in terms of sine/cosine, delta being its amplitude. The alternation of d1/d2 occurs because of inertia of medium molecules.
823430
the buoyancy of the object and its volume.
217609
light intensity is maximum at the source and dies down over distance, this can be explained with wave theory of light. so a medium in which light travels faster is where light looses intensity faster. but that is relative to another medium. because in any medium light is the fastest travelling thing. it may not be 'c' but fastest possible. \nso i conclude nothing :D
4461
Transverse electromagnetic waves (light,microwaves etc), the cosinewave shape is the same as calling something sinusoidal.\n\nSoundwave amplitudes can be sinusoidal.\n\nThe swing of a pendulum, simple harmonic motion.\n\nsinusoidal functions are solutions to many differential equations we find in nature.\n\nwaves on strings!
1101763
Well....moving water has a different refractive index to still water. So if you can monitor the intensity of color using the color of the light from still water you will see a change in the color when the water is moving. It is then possible to see that movement in the water is taking place. \nThe speed of movement maybe be also indexed as a change in refractive index. \nSo, it would be possible to run some controlled experiments and determine convection of water in some form of useful units.
90314
Check out these sites. Or just google your topic.\n\nhttp://www.physicsclassroom.com/Class/waves/U10L3b.html\nhttp://www.bbc.co.uk/schools/gcsebitesize/physics/waves/reflectionrefractionanddiffractionrev1.shtml\nhttp://physics.bu.edu/~duffy/PY106/Reflection.html
72824
Wave length is often represented by the Greek lower case letter lambda (your stick figure).  Replace that in your equation with "wavelength" or W until it makes sense then substitute lambda back into the equation.  It is just a shorthand notation that scientists have agreed upon (and nothing very magic).  See the link for more.  Good luck.
65598
I think it would be more kinetic than potential since an ocean wave is always in motion.\n\nHaving said that, here's what research shows:\nWave motion is highest at the surface and diminishes exponentially with depth; however, wave energy is also present as pressure waves in deeper water.\n\nThe potential energy of a set of waves is proportional to wave height squared times wave period (the time between wave crests). Longer period waves have relatively longer wavelengths and move faster. The potential energy is equal to the kinetic energy (that can be expended). Wave power is expressed in kilowatts per meter (at a location such as a shoreline).\n\nThe formula below shows how wave power can be calculated. Excluding waves created by major storms, the largest waves are about 15 meters high and have a period of about 15 seconds. According to the formula, such waves carry about 1700 kilowatts of potential energy across each meter of wavefront. A good wave power location will have an average flux much less than this: perhaps about 50 kw/m.\n\nFormula: Energy (in kw/m) = k H2 T ~ 0.5 H2 T, \nwhere k = constant, H = wave height (crest to trough) in meters, and T = wave period (crest to crest) in seconds.
209361
yeah, the guy was right, it's position and momentum, not energy and momentum. \n\nSee, if everything is a wave, it has a frequency spectrum associated with it (look up Fourier analysis). If something has one specific frequency only, then you can measure the frequency perfectly; the frequency gets you the wavelength, the wavelength gets you the momentum. But by definition, a wave at a single pure frequency extends to infinity in both directions, so you have no information about position. \n\nOn the other hand, if the wave looks like a single peak, you can calculate the position very nicely, but the frequency makeup (Fourier analysis) of a single peak contains an infinite number of frequencies, therefore an infinite number of momenta. \n\nFrom frequency /Fourier analysis, it's sort of obvious that the tighter you get the frequency/momentum, the wider the position spreads, and vice versa. No way you can specify a single frequency at a single point. (you can kind of see this intuitively; imagine a little chunk of a waveform, like just the tip of one peak; you can see the position precisely, but it's hard to estimate the frequency).