I have a question about a math problem can any one figure it out with me?
613149
Firtly 1 And 2  cross the bridge and 1 takes flashlight back.Time Spent=2+1=3 then 3 and 4 cross the bridge amd 2 takes flashlight back.Time Spent 10+2=12.And now 1 and 2 can cross the bridge.Time Spent=2.Total time spent=3+12+2=17.
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.
703752
simply subtract 7 from both sides. This leave you with\n\nx<_3
894923
i know a good mathematical riddle, but i wont even bother telling it here, you example has nothing to do with your question, your assumption is false, people dont do that.
23893
There IS a solution:\n\n1x - .15x = 680\n\n.85x = 680\n\n.85x/.85 = 680/.85\n\nx = 800\n\nThere you go!!!
1081089
[ (50000 x 2.4)+(25000 x .8) ] / (50000+250000)=1.8\n\nThe remainder of the info in the problem is not necessary.
103215
With this given data, it is not possible\n\nalthough the area is totalling to be 70 for both cases (7*10 and two pieces of 8*8 + 1*6) but with one division only, this is not possible\n\nPLEASE DO LET ME KNOW IF THERE IS SOME SOLUTION (i found it very interesting)
154380
I posted these sources earlier to someone else who was looking for math help.\n\nGood Luck!!
37738
try sosmath.com  they helped me before. if they don't have the answer you are looking for they have a list of links to tons of other math sites.  \n\nand there probably is someone on your campus that can help as well.  One on one help is always best...\n\nGood luck!
591960
Don't you have a calculater?\n1 000 000 * 1 000 000 = 1 000 000 000 000
511709
Here is a link you may find helpful.\n\nhttp://www.math.buffalo.edu/mad/00.INDEXmad.html
243812
At most shouldn't it take only 13 minutes?  If 1 & 2 cross together, then they will take 3 minutes, and if 3 & 4 cross together, they will need 10 minutes.  10 + 3 = 13.\n\nMaybe I don't really understand the question??
686219
1,24 24,1 2,12 12,2 3,8 8,3 4,6 6,4 -1,-24 -24,-1 -2,-12   \n-12,-2 -3,-8 -8,-3 -4,-6 -6,-4 and if x and y don't have to be intergers, there are basicly an infaninte number of possibilitys, such as 1/2,48 1/3,72 1/4,96..... so on, and the negatives. I hope x and y must be intergers, or you're stuck. easiest way is to graph it, or put like y=24/x or x=24/y. Not much help, but it's right.
893957
well darling ;\nimagine this like that\n\ny^2 + ( a+b)y + ab \nyou need to find " a+b " & " ab" \nin our function \na+b = 16 & ab = 64 \n( y + a)( y + b) \n( y + 8 ) ( y + 8)\n{ ' 8 + 8 = 16 '   &  ' 8 * 8 = 64 ' }\nso\n( y + 8)^2\n\nGood Luck sweetheart.
422460
please explain this question.
903397
You might try asking this question under "Mathematics."
192062
Maybe this link will help:\nhttp://www.mathinvestigations.com/