In mathematics, there's another name for slant height , what is it? give ya a hint starts with H.?
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the slant height is called the 'hypotenuse' only if the polygon whose height you are getting is a  triangle.   but parallelograms do not have hypotenuse, only height. \n\nyou might also mean there are ten 'letters' in the answer.
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The area of a triangle is half base times height.\n\nCould you properly define the length of the base, height and hypotenuse?
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A cone and pyramid have one thing in common, the base area is proportional\nto the square of the height.  If you keep the angles and overall shape the\nsame and just increase the size (like a slight zoom of a camera lens), the\nbase area is some constant times the square of the height:  A=cH^2.  The "c"\nis a constant that will eventually divide out.  Also, the volume is\nproportional to the cube of the height:  V=kH^3.  We want to find out how k\nmust relate to c.\n\nConsider two cones with identical shapes: one has height H, one has height\nH+h.  "h" is extremely small.  If H were 10 meters, h would be a millimeter.\nThe base area and volume for the first are A1=cH^2 and V1=kH^3.  The other's\narea and volume are A2=c(H+h)^2 and V2=k(H+h)^3.\n\nIf we subtract the larger smaller volume from the larger volume, we get the\nvery thin sheet at the bottom.  If h is small enough, the thin sheet will\nhave area A1=cH^2 and height h.  The thin sheet will have a volume (cH^2)h.\nIf you don't say that h is very small, then the sheet will have a more\ncomplex volume formula.  We now have V2-V1=(cH^2)h.  Let's do the algebra:\nk(H+h)^3- kH^3=(cH^2)h\nkH^3+(3kH^2)h+(3kH)h^2+kh^3  -  kh^3  = (cH^2)h\n(3kH^2)h + (3kH)h^2 + kh^3 =(cH^2)h\n\nNow, the limits:\n\n"h" is tiny, so the second and third terms are extremely small compared to\nthe first.  They are like adding a penny to a million dollars.  They really\ndon't count enough to keep.  Limit theory lets us drop them under the\ncircumstances.  This yields:  (3kH^2)c=(cH^2)h.  Divide out common terms and\nget:  3k=c, or k=(1/3)c.  Put this in the original formula for volume:\nV=kH^3=(1/3)cH^3=(1/3)(cH^2)H=(1/3)AH.  Volume equals (1/3)Base area times
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The oblique answer is correct. As for the slanted 3-D rectangle, I believe you are referring to a parallelepiped: http://mathworld.wolfram.com/Parallelepiped.html .
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rectangle\n\nradius\n\nrhombus (a parallelogram with two equal acute angles, two equal obtuse angles, and four equal sides)\n\nradian (a unit of measure of an angle defined such that in a circle, the lenght of the portion of the circumferance between two lines that intersect at the midpoint at an angle of one radian is equal to the length of the radius)\n\nright (as in right angle, right triangle)\n\nregular\n\nrotation (as in rotational symmetry or rotational transformation)\n\nratio\n\nregion (as in the region inside a circle)
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SOHCAHTOA....geometry term Sine Opposite Over Hypotenuse,Cosine adjacent over hypotenuse, Tangent opposite Over Adjacent
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I should tell all answers above are wrong or doesn't have\nproper claim for it.\n\nEven though 1/3 pi r*r * h \nwhere h is the height of midpoint looks correct.
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Just remember SOH CAH TOA\n\nSin: opposite/hypotenuse\n\nCos: adjacent/hypotenuse\n\nTan: opposite/adjacent
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1/2 bh or bh over2.\nType triangle is inconsequential.\nb=base  h=height\nMeasure both, multiply, divide in half.
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A = base * height\n\nbase = 8\n\nslant height = 6\nto get the actuall height, we use trig\n\nthink of 6 as the hypotenuse\n\nsin 30 = height / slant height\n\nor height = sin30 * 6\n\nheight = 3\n\ntherefore area = 8 * 3 = 24
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Adjacent... means "next to."\n\nSOH CAH TOA!!! Someones doing trig!\n\nCosine = Adjacent / hypotenuse\n\nI just remember it because the angle your choosing is touching this side. The Adjacent side.
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Adjacent means  "next to"\n\nIn trigonometry (which you are calling maths), the term is used with respect to angles. When you consider the right angle in your figure above, "a" and "b" are the adjacent sides of the right angle (the 90 degree angle) and the side "c" is the hypotenuse and also the "opposite" side.
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do u mean angle or side? for side length you use the pithagorean theorem... a^2+b^2=c^2 ... yopu hace c, c=16, and a, a=9\nso ... 9^2+b^2=16^2......   b^2=16^2-9^2===175\nb= square root of 175 =13.2\nI
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when a body is in limiting equilibrium on an inclined plane then the inclination of the plane with the horizontal is called the angle of repose.it is denoted by greek letter alpha.tangent of alpha=mu<greek letter meaning coefficient of static friction.\n u might hav got it now tht its a term related to friction
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Slant 6, 318, 360, 400, 440? Which one?
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A parabola opening upward has the equation:\ny = a(x - h)² + k,\nwhere (h, k) is the vertex and a is the amplitude (the number of spaces up for one unit on either side of the vertex).\n\nIf you want a vertex of (-2, 0) and the same amplitude, it's:\ny = 2(x - (-2))² + (0), or\ny = 2(x + 2)².
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Good that you care to ask. The answer to this should be evident to you by integration (hope you have been introduced to calculus? If not, you will be this year.). \n\nI assume that you don't have much of a background.\n \nOK, let the cone be such that its height is H, base radius R. \n\nWhat you need to do is consider an infinitesimally thin section of the cone (a diagram should be so helpful here, unfortunately not possible) at height h from the bottom and of height (along the axis) 'dh', such that the radius of the section is a uniform 'r'. \n\n(Note that you have a uniform radius r to the section because you have chosen a very thin section of the cone.)\n\nNow, the surface area of the section considered is \n2*pi*r*dh*cosec x. (x is the cone half-angle)\n\nThe cosec term comes from basic trigonommetry, when you realise that the section is tilted and not exactly parallel to the axis. \n\nThe surface area  of the entire cone, indeed the curved surface area, is a summation of all such infinitesimal sections, each of surface area 2*pi*r*dh* cosec x \n(where r is the radius of each section). \n\nThis above sum can be found by \nintegrating 2*pi*r*dh*cosec x (that is a word in the language of calculus for finding out the sum of many small parts) over the entire height of the cone. \n\nalso realise that r = h tan x. \n\nso an integration of 2*pi*htan x*cosecx*dh gives us,\n\nCSA = 2*pi*sec x* (H^2/2)  \n    = pi*R* H (sec x/tan x)\n    = pi*R* H cosec x\n    = pi*R*L\n\nHope this satisfies.