explain how you got the answer for the mass of a nickel, and what is the mass of a computer disk please explai
609693
weight = mass * gravity\ntherefor\nmass = weight/gravity\n\nsorry naughty but you're wrong, if you go to the moon or jupiter you will have the same mass you have in earth but you'll have a different weight
761131
mass=90\nvolume=110.6\ndensity=mass/vo;ume=90/110.6=.814\n\nSince you didn't specify units, I can't put units on the answer. They are mass/volume or mass/l^3
26899
go to encarta.msn.com and search for keys mass/solid structure, surface Structure
587954
Measurements (In distance I'm assuming) would give you volume.\n\nMass / Volume = Density\n\nIf you have volume & density, you can rewrite the equation:\n\nMass = Volume * Density
849662
The moment of inertia of an object is given as:\n\nI = volume integral of (r² dm)\n\n(I have no good way of writing this, so check the wikipedia link below of more info). Wikipedia also has a list of moments of inertia, which I've included below. It provides the moment of inertia for a disk as:\n\nI = (1/2) * M * R²\n\nAs for calculating it step by step, note that if the mass is evenly distributed throughout the disk, then the density of the disk is equal to its mass divided by its volume:\n\nrho = M / (pi * R² * h)\n\nThe infintesimal dm can be expressed as:\n\ndm = rho * dV\n\ndm = M / (pi * R² * h) * r * d-theta * dr * h\n\ndm = M / (pi * R²) * r * d-theta * dr\n\nThus, the moment of inertia is given as:\n\nI = int(int(M / (pi * R²) * r^3, r=0..R),theta=0..2pi)\n\n(again, I don't have a good way to express this - its a double integral of M / (pi * R²) * r^3 * dr * d-theta, where r goes from 0 to R and theta goes from 0 to 2pi). This reduces to:\n\nI = int(M / (pi * R²) * r^3 * 2pi, r=0..R)\n\nI = M/(pi * R²) * (1/4)*R^4 * 2pi\n\nI = M/(R²) * (1/2)*R^4\n\nI = (1/2) * M * R²\n\nSo that's how you find the moment of inertia. Now, substituting your values into this expression provides:\n\nI = (1/2)(41 kg) (18.8 cm * 1 m/100 cm)²\n\nI = .7246 kg-m²\n\nThat's it! :)
358234
1 bit (b)\n\n1 byte (B) = 8 bits\n\n1 Kilobyte (K / KB) = 2^10 bytes = 1,024 bytes \n\n1 Megabyte (M / MB) = 2^20 bytes = 1,048,576 bytes \n\n1 Gigabyte (G / GB) = 2^30 bytes = 1,073,741,824 bytes \n\n1 Terabyte (T / TB) = 2^40 bytes = 1,099,511,627,776 bytes\n\n1 Petabyte (P / PB) = 2^50 bytes = 1,125,899,906,842,624 bytes\n\n1 Exabyte (E / EB) = 2^60 bytes = 1,152,921,504,606.846,976 bytes\n\n1 Zettabyte (Z / ZB) = 2^70 bytes = 1,180,591,620,717,411,303,424 bytes\n\n1 Yottabyte (Y / YB) = 2^80 bytes = 1,208,925,819,614,629,174,706,176 bytes
551638
there are many elements in the world.\nthe mass of the laptop is 5000 pounds.\nthe table there is a matter.\ni don't know what atom is
896963
if you added more details it would have helped you more.\ntheres a thousand megs in a gig so you should convert the gigs into megs.\nso for eg.if you had 24 megs and 1.5 gigs. you would say\n24 megs + 1500 megs (1.5gigs) = 1524\n\n if you meant you wanted to get more space on your computer you should get a new hard drive or  a removable hard drive\nif 1 gig equals 1024 then: 3 gig wouls be 3 times 1024 = x
267872
braxton_paul is a little mixed up.\n\nUsing an electronic scale accurate to 1/10 of a gram, I found the mass of a penny (from 2002) to be 2.5 grams.
836906
I had to read about this in order to answer your question at this web site:\n\nhttp://home.um.edu.mt/chemistry/CH230/2.Analytical/CP210a.PDF\n\nSo, two moles of DMG combines with each Ni++ ion.\n\n(0.2145 g Ni)* (1 mole Ni/58.71 g Ni) = 3.65*10^-3 mole Ni\n\nIf what you tell me is correct that DMG is 116.1194 then the Ni complex which loses 2 H+ for the Ni++ has a molecular wt of\n172.8134 (please double check)\n\n(3.65*10^-3 mole Ni)* (172.8134 g/mole) = 0.6314 g\n\nplease check for errors
74127
The 4.7 GB value is the amount of space in binary.\n\nIn decimal, it comes out to 4.38 GB, which is what the computer is displaying.\n\n\n1 GB equals 1073741824 bytes.
1138448
Look on a periodic table.\n\nIt should be listed below the atomic number as a decimal value.  The mass number is an average mass (in atomic mass units) of an element, based on different isotopes.  It equals the number of protons + the number of neutrons in the nucleus.
882485
1 Nickel = 5 c\n1 Dime = 10 c\n1 Quarter = 25 c\n5.50$ = 550 c\n\nAssume number of nickels = X\n\nThen number of quarters = X + 4\n\nThen number of dimes = total number of coins – (number of nickels + number of quarters) = 37 – (X + X + 4) = 33 – 2X\n\nnumber of dimes * dime value + number of nickels * nickel value + number of quarters * quarter value = Total value\n\n(33 – 2X) * 10 + X * 5 + (X + 4) * 25 = 550\n330 – 20X + 5X + 25X + 100 = 550\n10X + 430 = 550\n10X = 550 – 430\n10X = 120\nX = 120 / 10\nX = 12\n\nNumber of nickels = X = 12\nNumber of dimes = 33 – 2X = 33 – 2 * 12 = 9\nNumber of quarters = X + 4 = 16\n\n12 * 5c + 9 * 10c + 16 * 25c = 60c + 90c + 400c = 550 c = 5.50 $\n\n12 + 9 + 16 = 37 coins\n\nAnswer: Jo has 9 dimes :-)
449468
Take it to your bank and desposit it.  They'll hate you, but their legally obligated to take it, I hear.  That's what "all debts, public and private" means!\n\nAccording to the US Mint, a nickel weighs 5 grams even and a dime weighs 2.268 g.\n\n(Yes, purists, I know grams ain't weight, but "masses" ain't a word!)\n\nKeep in mind your numbers have only one significant digit!  (i.e., if you want better accuracy, I need numbers more accurate than "20" and "30".  How about "21.3" or something?)  Playing with the numbers gives us:\n\nNickels:  ~2000, or $100\nDimes:  ~4000, or $400
233618
1 mass\n2 magnitude of separation
1036388
Torque is given by the product of moment of Inertia and angular acceleration. \n  \nR - Radius = 13/2 inch =0.1651m\nMoment of inertia of the disc is ½ M R^2. = ½ x 15 x 0.1651 x 0.1651 \n=0.204435 kg m^2.\n\nAssuming that the disc is stopped in t seconds by the applied torque, the angular acceleration is 1800 x 2 x pi/ 60t radian per second^2 =188.49556/ t (radian per second^2)\n\nTorque = 0.204435 kg m^2 x 188.49556/ radian per second^2\n..............= 38.535/t Nm.
934281
I think ths question refers to the mass defect whcih is explained here: