if it taks 5 people 7 days to dig a hole, how many days would it take 2 people to dig half a hole?
604909
No such thing. A half a hole is still a hole.
6869
5 days, while camping.
623290
It is because you are trying to make a round peg fit into a square hole.\n\n7 x 4 = 28 x 13 lunar months = 364 days, \nbut there are 365 days in a regular year. \nThen in order to fit into the Earth's rotation around the Sun every 4th year we have to add an extra day.\nPlus occasionally we have Leap seconds too.\nConfused?
805222
10*5+4*3+5*2.5=74.5\n74.5 man days=149\n1 man day=2\nmembers who worked for 3 days contributed 12*2=$24
881108
Wrong.\n\n3 weeks with Sundays is 21 days.\n\n3 weeks without is 18 days.\n\nSo you need to apply 21/18, not 24/21.\n\nEDIT: You said the house still has to be built in 3 weeks.  That's 18 days if they don't work on Sundays.  There aren't 3 "extra Sundays" anywhere because on the contrary, days are taken away.\n\nIt takes 35 workers to do it in 21 days.  Multiply by 21/18 and the result will be more than 35 - this accounts for the fact that you have fewer days.\n\nLook at it another way.  If 15 people build a house in 7 weeks, this means the house needs 15*7*7 = 735 man-days to build.\n\nNumber of people needed = 735 / number of days.\n\n3 full weeks (21 days) will take 735/21 = 35 people.\n\n40 people for 3 weeks with Sundays off (18 days) will only give you 40*18=720 man-days.  Not enough.\n\nFor 18 days, you need 735/18 = 41 people (rounded up to the next whole number - you can't hire a fraction of a person).
708636
10 workes finih half the road in 6 months\nletx workers finish the remaining half in 4 months\nthe equation\nx=6/4*10=15 workers\nadditional 5 workers
419226
Let a,b and c denote the number of days that A,B and C would respectively take to finish the work, working alone. \n\nNow A and B together do it in 8 days. \nHence in one day they finish 1/8 th of the work. \n1/a + 1/b = 1/8 ...........(I)\n\nB and C do it in 12 days. \nHence in one day they finish 1/12 th of the work. \n1/b + 1/c = 1/12 ..........(II)\n\nA alone does it in 16 days. \nHence in one day he finishes 1/16 th of the work. \n1/a= 1/16 => a = 16 .........(III)\n\nfrom (I) and (III), \n1/16 + 1/b = 1/8\n=> b = 16 .......(IV)\n\nFrom (II) and (IV), \n1/16 + 1/c = 1/12\n=> c = 48...... (V)\n\nNow, A and C together working in one day \nwould finish \n1/a + 1/c of the work\ni.e 1/16 + 1/48 of the work\ni.e 1/12th of the work. \n\nHence they would finish the work in 12 days.
590630
How about a bowl of water beneath it? Is that within the rules? Alternatively one of the other posters is planning to drill a hole through the centre of the planet, you could always use their hole, it wouldn't break then!
1103861
Monday.  Divide 100 by 7 = 14 with two days over.  Sunday - Monday.
821077
once we chose 5 persons for one committe then other committe members get fixed.\n\nThe 5 members can be chosen in 10C5 ways = 10*9*8*7*6/120\nor 6*7*6 or 252 ways
1070574
A couple days,\nmaybe even five, if they're behind schedule\nit depends on where you live
175769
1-2 days it depends on alot of factors like weather, colony size, ect.
307426
Let e = a standard unit of 1 man-hour per weekday effort\n3.5 e = effort made during 1 man-hour during the weekend\n\nSunday 2am +19 hours = Sunday 9pm\neffort = 3 men, 19 hours, weekend effort only = 3*19*3.5e = 199.5e\nto dig 12 m^3 = 12*(100/2.54)^3 cu.in. (about 700k)\n\ne (using shovel) in 1 man-hour (week-day) = (12*(100/2.54)^3 / 199.5) cu.in.\nwhich is roughly 4000 cu.in. (I'll do the exact math shortly)\n\nStarting at Saturday 5pm to dig 17 in. cubed with a tablespoon (1/5 the size)\n\n17 in. cubed is 17^3 cu.in. (somewhere less than 8000 cu.in.)\n\nNow, a standard tablespoon is maybe 9" long (so that puts the shovel just under 4 feet... so reality check on the shovel \n\nchecks out at least)... the question is, is the tablespoon (1/5)^3 the volume lifting capacity of the shovel?  let's assume \n\nyes... not as long, not as wide, not as deep... so let's use (1/5)^3 for the shoveling volume.\n\nthat means it takes 5^3 as much effort to dig the same cubic volume with a tablespoon as with the shovel.\n\nso this should put us somewhere at (8000/4000)*5^3 times the effort made to dig the first hole, in order to dig the second \n\nhole...or roughly 2*125 = man-hours... coronary time for the man\n\nIf the first 24 hours is at 3.5e efficiency, that's 84 man-hours done...\nthen he drops to half-efficiency on Sunday 5pm. 1.75e from 5pm-12am (7hours) = 12.25 man-hours done\nnow he's still at half-efficiency for the week... 24*5/2=60 per set of 5 weekdays\n\nuntil he's set for a coronary at ((17^3)/(12*(100/2.54)^3)/199.5))*(5^3) = 167.30911 man-hours\n\n84+12.25+60=156.25, so he needs another 11 or so man-hours at 3.5/2 efficiency on next Saturday, or 6.3194914 hours or\n\n1 week later Saturday 6:19:10am, just in time for the morning shift of the ER at the local hospital.
231014
Here's a great formula. One does the work in A days and the other in B days. The number of days they will do the job if they work together being N,\n\nN=(AB)/A+B\n\nSo, if the first do the job together: N=24/10=2.4\n\nAnd if the three of them do it: N=(2.4x2)/(2.4+2)=1.09 days approximately.
957682
half it then times it by 2! that will give u the answer
786232
You need to figure out how much of the job a man does in a day.\n\n3 men take 2 days to finish a job.  So 1 man would take 6 days.  Stated another way, a man finishes 1/6 of the job each day.\n\nIf you have 2 men, then they would finish 2 * 1/6 = 1/3 of the job in a day.\n\nThe answer is 1/3 of the box.
440649
First of all we need to find the volume of known canal.\nV=4*5.5*405\nV=8910(m^3)\n600 men can dig in half an hour. So they can dig \n8910*2=17820(m^3) in an hour.\nTherefore 1 man can dig 29.7(m^3) in an hour.\n2500 man can dig 29.7*2500=74250(m^3) in an hour.\n2500 man dig 74250*6=445500(m^3) in 6 hours.\n10*8*x=445500\nso x=5568.75 m