The answer will SHOCK you!if you have a paper(very big),How many time you have to ply  to arrive to moon?
606391
42\n\n\nAdditional Details\n\nchange km into mm\nand put 0.1 times 2 in to you calculator\nand count the times you press = till you get pass da number\n\nyippy 10 pt for me
980339
Of course, that won't help you figure out how high it is in the sky each night at a specific time if you are trying to fill in a moon observing lab that you failed to do.  \n\nI will help you this much: the moon rises 50 minutes later each night (about 12 degrees further east at the same time each night) and is more or less directly overhead at midnight when it is full.  If you figure out where it should be at a particular time each night, you deserve credit for the lab.
283146
you could make it in one second or beyond 12 hours depending on where you are, excluding flight delays at al. it should not actually take long enough to measure in days, unless you are travelling by boat/ship
22701
Cool problem.\n\n6908.9 feet when the diameter is 25".\n\nThe formula is:\nL = (X^2+8*X)*49.26108,  \nwhere L is the length of paper remaining in feet, and X is the measure from the core out in inches\n\n\nIt's not simply a number times the measure because an inch near the core is not the same amount of paper as an inch near the edge.\n\nIt's important to realize that any formula will be an approximation.  You can't be very precise when measuring the size of the roll, and the size of the core is not always going to be exactly the same.  And the paper may be tighter near the core than on the outside.  Also, based on the info given, the thickness of the paper is actually .005314528".\n\n\nThere are a couple ways to approach this.  The easiest way, which happens not to be very intuitive, is to correlate the area of the cross-section with the length of paper.\n\nIf you want to follow this, draw two concentric circles - one representing the core, and the other representing the paper around the core.\n\nThe radius of the larger circle is X+4 inches.\nThe radius of the smaller circle is 4 inches.\n\nThe area of the donut area (representing the paper) is π*(X+4)^2-π*16 = π*((X+4)^2-16) = π*(X^2+8*X) square inches\n(In case the font is not clear in the browser, "π" is pi=3.141593.)\n\nLength x thickness = area of cross section\n(For this purpose, I'm assuming that the area of the cross section for a given amount of paper is the same whether it's rolled around a core, or it's cut into sheets and stacked.)\n\nWhen X=21 inches, Length = 30,000 feet = 360,000 inches\n\n(360,000 inches)*thickness = 3.141593 * (21^2+8*21)\nSo, thickness = .005314528 inches\n\nTo derive the formula:\n(Length in feet)*(12 inches/foot)*thickness=area of cross-section\n\nL*(12 in/ft)*(.005314528 in)=3.141593*(X^2+8*X)\n\nSolve for L:\nL=(X^2+8*X)*49.26108\nL is in feet, X is in inches.\n\n\nThe question asked how many feet when the diameter is 25".  \nX=8.5\nL=(8.5^2+8*8.5)*49.26108 = 6908.9 ft.
1138773
1 fold = 2 sheets\n2 folds = 4 sheets\n3 folds = 8 sheets\n4 folds = 16 sheets\n5 folds = 32 sheets\n6 folds = 64 sheets\n7 folds = 128 sheets\n8 folds = 256 sheets\n\nThe average thickness of a regular copy paper ranges from 0.05 to 0.10 millimeters. \n\nSo, at 6 folds, we are looking at 64 x 0.05 = 3.2 mm\n\nAt 7 folds, we are looking at 128 x 0.05 = 6.4 mm\n\nAnd at 8 folds, we are looking at 258 x 0.05 = 12.8 mm\n\nSo, bending a stack of paper from 3.2 mm to 6.4 mm on the 7th fold could well be the limit as at the 8th fold, it becomes much harder to fold from 6.4 mm to 12.8 mm.
180356
How far is it from Earth to the moon?\nIt is about 250,000 miles from Earth to the moon.
929971
it is liter on the moon you will wal later on the moon you my not all polp are diffft
1040803
Explain how a 600 yard wide rock could cause the 2,160 mile wide Moon to wobble, without touching it? It'd be like throwing a golf ball at a bus and expecting it to tip it over....\n\nIt doesn't matter what the moon does as far as wobbling and spinning, it's gravity isnt affected (unless it breaks up) and therefore the end result means zip to us. We may just get to see the far side!
579572
The thickness of the paper increases with ever fold 2 times. And so with  2 to the power of 7 times it  becomes 128 times thicker and makes it impossible to retain the shape of paper and makes it hard to fold it exactly half.
788671
You might as well ask how to get to the moon?\nThere are twenty main titles before you can start choosing the detail?
234969
Print a paper that looks like this.\n\n\nDate:______________\n\nStart Time:______________\nEnd Time:_______________\n\nDuration:____________
793088
Assuming that it is possible:\n\nThickness = 2^100 * thickness of 1 sheet\n≈1.27 X 10^30 * thickness of 1 sheet\n\nIf thickness of sheet = 0.2 mm\nThickness = 2.54  X 10^29 mm (= 10^28 inches)\n= 2.54 x 10^23 km (≈ 1.58 x 10^23 miles)(which is an awefully long way!!!!\n\n(1 light year ≈ 9.47 x 10^15 km so this distance is 2.68 x 10^7 light years)
131167
Ah! that happens like one time per some 100 years!!!\nAnd besides, it will 75% chance hit the ocean! And no tsunami! And, the moon is a shield. It protects 15% of the hits! And theres a 5% chance that it will hit near you. So its a -5% chance you will "get scared" of a metor hitting Earth. I did the math!
488119
depends on how big it is when it enters the atmosphere
604730
Jumbo jets travel at about 900 km/hr, and the moon is 384400 km from earth, so it would take about 18 days to get to the moon going that fast.\n\nHowever, jumbo jets work under the principles of lift propulsion, which requires air.  Since there is no air between the earth and the moon, the jet would be doomed shortly after takeoff.
68494
No. On the moon, you would "weigh" about 1/6 what you do on earth.  Although that's a much lower number, it's still not close enough to zero that you could escape the moon's gravitational pull simply by jumping.
464783
The paper is out, because of wind resistance, leaving only the small and big rocks.  Refering to the 11th century-actually, Newton's law was supplanted some years ago, and we know that the acceleration due to gravity is determined by the combined gravitational forces of both objects.  Assuming an exactly equal shape and an exactly equal density of the two rocks, the larger would fall more rapidly, because of the involvement of it's own gravity.  If we assume, for example, that the small rock is the size of a baseball, and the big rock is the size of, oh...the moon, then the big rock will fall quite a bit faster (the combined gravity will be greater, because of greater mass).  As the large rock gets smaller, the gravity will decrease.  However, no matter how close in size the two rocks, there will be some difference.  It would not be easily measurable at anything less that a few million tons, but it would still be there.\nNewton was likely the greatest genius that ever lived...but we have moved beyond him in a lot of areas, including our understanding of gravity-