what is the speed of T! and T3?
597450
t1 is a 1.5 megabyte\nt3 is 45 Meg.\n\nds0 is 56k\n\n1 ds0 = 1 phone line\n1 t1  = 24 phone lines multiplexed(combined) on 1 cable\n1 t3  = 28 t1's multiplexed(combined) on 1 cable\n1 t3  = 672 phone lines.\n\n1sts1 = the electrical equivalent of 1 T3\n3 sts1 ride on 1 OC3\n3 oc3's and 3 sts1's ride on 1 OC12.\nor 12 sts1's ride on 1 OC12\nor 4 OC3's ride on 1 oc12\n\nOC48 works the same as an OC12 or OC3.\nOC = optical carrier.  sts1's are electrical equivalents of a ds3(digital) signal.\n\nyour voice is converted from sound to analog(through/at your phone).  The analog is converted to digital(at your phone or at your Local Exchange Carrier).  The digital is converted into sts1 electrical and shipped from your from location to your calling to location on an Optical carrier.  then the reverse occurs.  the electrical signal is taken off the optical carrier, converted back to digital then back to analog which passes through a speaker providing sound.\n\nif you are wondering how it is carried over any of these methods remember that the sound is converted into 1's and 0's or on's and off's.  each part of a sound is represented by a different length of a 1 or 0 or on and off.  so a digital signal is either on or off as you make sound.  the electrical signal is either on or off for that same sound.  the fiber or light in an optical carrier too is either on or off.  different shades of light are multiplexed on a same line.  so while your conversation goes over as white, mine may go over as bright white.  converters at the other end look for those two shades and seperate them to the appropriate path.  since shades of color are near infinite, millions of calls can be placed over the same lines..\n\nindian smoke signals worked in the same way.  1 cloud = yes.  2 clouds = no, etc...\n\nget it?.
8794
5t+1>3t-13\n-> 5t-3t>-13-1\n-> 2t>-14\n-> t>-14/2\n-> t>-7\nKeep Asking
1011755
SPEED.\n\nF.M. IS LITTLE FASTER THAN M.F.
583057
You typically order T1's and T3's from an ISP if you want to use them for Internet access. The ISP then provisions one from a telephone company or digital circuit provider from your home/business to their closes POP (point of presense).\n\nBoth can be expensive (a T3 more so than a T1). For internet access you pay two costs (the telco cost for the physical circuit and the bandwidth/port charge to the ISP).\n\nA full-blown T1 is 1.536 Mbps (mega-bits per second)\nA full-blown T3 is 45Mbps\nEach can be fractionalized so you don't have to use the full port-speed.
815604
I suppose you need the speed:\nThe required fraction is : 392/s ft/s\n                                      = 49ft/s (simplified)\nThe speed is 49 fett per second.
340116
a) d= 0.5 * 9.8 * t^2 + Vi * t = 10 m\nFor t=1 sec:\nVi= 10 - 9.8*0.5 = 5.1 m/s \n\nb) g= (Vf-Vi)/ t\nFor t=1sec and Vi=5.1\nVf= 9.8+5.1= 14.9 m/s\n\nHope it is clear enough.
685470
the speed = distance/time
301328
Homework.\n\nLook at B=A. You should find something interesting about tr(A^tA).
496307
Tf = 9/5 Tc + 32\n\nor \n\nTf = (1.8)Tc + 32
589588
T1 = 2\n\nT2= 4\n\n>d= T2-T1\n=4-2\n2.\n\nT4= 8\n\nT3=6\n\n>d=T4-T3\n=8-6\n=2.\n\nGet it?
145998
Congrats! Now please vote me as best answer so I can reach lever 3 much faster.....!!!!!!!
623007
150 KB/s\n\n24X is 3600KB/s
159581
There is a simple answer and a much longer, more complicated answer.\n\nThe simple answer is that the T1 and T2 spins show different tissues more clearly.  On T2-weighted images, water is very bright.  On T1-weighted images, fat is very bright.\n\nI won't go into the physics of WHY that is.  It's not that important, except to us who get excited about it.  ;)
931765
1. d=t, any form of d=t+b would be parallel. b = any number. That is a line.\n\n2. d=t would also work here.\n\n3. Well if you go 60 MPH and you wnat to know how many miles a minute you can go convert using (60miles/hour)*(1hour/60minutes) and you get 1mile/minute. If you need feet, 1 mile is 5280 feet, so 5280 feet/minute
1006215
Use the formula d = rt (distance = rate * time)\n\n1) Train A: d = 40t\n\n2) Train B: d = 60(t - 1)  [left an hour later]\n\nthe answer is when the two distances are the same, so we set the two equations equal to each other\n\n40t = 60(t - 1)\n40t = 60t - 60\n60 = 20t\n3 = t   [3 hours]\n\nPut this result back into equation 1\n\nd = 40 * 3 = 120\n\nAnd we expect the same result in equation 2\n\nd = 60(3 - 1) = 60 * 2 = 120\n\nI provide this level of detail in case you need this level of help.
544479
The speed of sound: 340.29 m / s
636559
TNG Tech Manual lists it at 656 times the speed of light. This would also be the same for DS9 and Voyager, as these occur in approximately the same time frame. There is some as-yet-indeterminate algorithim to determine the difference in speeds; some say it's logarithmic, but I haven't seen it.\n\nTOS was much easier. According to the orig. ST tech manual, warp speed = (factor)-cubed * speed of light. Warp 1 = 1c (1^3), Warp 2 = 8c (2^3), Warp 3 = 27c (3^3), etc...