How will you find the weight of an Aeroplane?
596616
Depend on where you want to measure the weight.\n\nWeight = mg\n\nWhere m is the mass of the plane and g is the accelleration of free fall.\n\nTo measue the weight of the scale you would park it on an aeroscale which would tell you its mass.\n\nThe mass of the plane wll be the same everywhere.\n\nTo find the weight of the plane you multiply the mass of the plane and the gravitational field strength from where you are measuring it.  On the srface of the earth tjis is 9.81.  The weight will be in Newtons.\n\nWhen the plane is in flight to measure its weight you need to find out the gravitational field stenth at the hight at which the plane is flying.  Unless the plane is flying exceptionly high (Like in space) then 9 will also be 9.81.
184329
mass of chopper=m\nm1=mass of air\nv=velocity of air\nt=time of acting of the force\nmgt=-m1v\nv=mgt/-m1
1081934
There are too many formulas to calculate that answer. You have to take in account for example, position of object to find potential energy, mass and the weight due to the gravitational force, also Force that is going to be exerted the object and the amount of that energy that will be lost. SO it is a lot to  find that out. But their is not one formula for it. Sorry, But if you do find out Let me know.
1046911
it will fall straight down , but appear to fall at an angle if observed from the plane
999871
if you know the weight of the metal used and then how much of it was used you could calculate it and the same for all the non metal parts
577532
How much does a penny weigh?  How much does the empty water bottle weigh?  Take total water bottle full of pennies minus empty water bottle weight, get result; then use that result and divide by individual penny weight and that should tell you how many pennies there are.  The divide that by 100 and will tell you dollar amount.  have fun finding a sensitive enough scale though.
606521
Try this:\n\nhttp://education.yahoo.com/reference/weights_and_measures/
325473
Measure the weight of 1 cup of sand and figure it from there.\n\n :-)
412802
p=F/A \n\nSo, you have the pressure of the atmosphere pluss the weight of the water above you.  Which is usually figured as a cylinder.  Hope that helps.
405919
http://en.wikipedia.org/wiki/Hundred_weight
341507
You mean find "g" as if you didn't know the constant? Okay.\n\nPretty simply really. Have the height measured that you're going to drop it from to where it's going to land (this will be your "h"). Make it a high one (one meter is enough). Measure the mass of the object (that's the "w"). Then when you do the experiment, time it. Start it at the instant you let it drop and stop it once it touches where ever it lands. That's enough information to find "g." Just solve for "g" then that would be the answer.\n\nActually, for an experiment, you should solve for "g" as a formula before you start doing anything else. So the formula would be like this:\n\ng = (2h)/[(t^2)(w)]\n\n(t^2 is "t squared")\n\nSo just have that formula then do the experiment: measure height of the drop, the mass of the object, then time it when you drop it (you need good reflexes when you drop it, as it falls fast).\n\nPS Penguins!!!
612424
I haven't done any physics problems for ages, but I'll give it a try.\n\nThe centripetal acceleration = V^2/R \n\nBut, because the acceleration due to gravity is about 9.8m/sec^2 and this is important to the answer, you first want to express V in m/sec;\n\nV = 360km/hr = 360,000m/3,600sec = 100m/sec.\n\nSo the centripetal acc. = (100m/sec)^2 /500m = 10000/500 = 20m/sec^2, which is about 20/9.8 = 2.04 g-forces. This force is always directed towards the center of rotation. \n(Note: if you were on a spinning wheel space station where gravitational forces were negligible, and it had a radius of 500m and had a tangential V of 100m/sec, and you were walking around the inside of the station at the 100m extremity, you would have the apparent weight of 2.04 gs)   \n\nAs far as his "weight" is concerned: if the seat of the plane measured his weight at different points around the loop then it would vary. \n\nAt the top of the loop: his recorded weight would be 70kg x (20-9.8)/9.8 = 72.86kg. This is because gravity is reducing the  weight. \n\nAt the bottom: it would be 70x(20+9.8)/9.8 = 212.86 kg\nThis is because gravity is adding to the weight.\n\nAt the mid-points gravity and the centripetal acc. would be perpendicular to each other and the recorded weight would simply be 70x20/9.8 = 142.86kg\n\nI hope that helps.
107381
I agree, your English is poor but I think you are asking:\n\nWhen flying in aeroplane, how much pressure is outside? \n\nThe exact outside pressure will depend on the altitude at which you are flying. At a common cruising altitude of  37,000 feet, the outside air pressure is about 3.2 psi. At sea level it is 14.7 psi.  \n\nWhy does it sometimes shake?\n\nFlying in an airplane through air is just like riding in a car along a bumpy dirt road or a ship across choppy open water. The air, while invisible, is very much like an ocean and is always in motion while the aircraft moves through it. The more turbulent the air mass, the more the plane will bouce or shake as it passes through it. At high speeds the air takes on fluid like properties around an aircraft. The oceans are not always calm and glassy and neither is the air which is a constant mass in motion. Just like a journey on the seas or a country road, you cannot always expect your journey to be completely smooth.
149116
Since the plane is horizontal normal force cancel weight so no force in vertical direction. No friction so no extra force in the horizontal direction.\nF = ma System: wagon\nFn + Fg + F1 + F2 = ma   \n(these are all vectors, except the m, but I can't type the arrow)\nF1 + F2 = ma (Fn + Fg = 0) (again, vectors)\nChoose the 45N as positive direction\n45 - 30 = 8a\n15 = 8a\na = 1.875 m/s^2 in the 45N force direction
51910
Weight is a force, but when something is weighed you actually measure it's mass assuming you are in an environment in which the force of gravity is constant (i.e., you're at a fixed location <radius from the center> on a planet or massive planetary mass).\n\nof course, one's mass can be approximated by W=mg at fixed radii from such planetary masses (like the earth, a massive asteroid, a superdense star, whatever...) if the force of gravity, g, is known at that radius.\n\nThere are 2 possible variables here - mass and the force of gravity.  Which one do you know?  usually an approximation for g is given.  Which one do you measure, then...that would be mass.
178900
I can't figure it out, my brain is slow tonight.\nHave x=air plane speed\nhave y=wind speed\nx+0=225\nso x=225\n225+y=300\n225-y=210\nFrom there I'm lost
383223
YOu may want to check with the FAA\n\nhttp://www.faa.gov/\n\nGood luck.