How do you simplify the square root of 2700x5y7z-5?
594505
what the ....................
685997
u should write it like\n7.52*10^-4
283638
sqrt(25)=5 or -5. To verify it:\n\n5*5=25 checks\n-5*-5=25 checks\n\nboth work.\n\nan important thing to remember while square-rooting a number is that the root can be both positive or negative, as two negatives multiply up to a positive.
1095338
2^5/2=square root(2^5)=square root(32)=5.66\n\n2^6/2=square root(2^6)=square root(64)=8
1121270
This one can't be simplified further uness you just write\nsqrt{5+3sqrt{3}}.\n\nOn the other hand, sqrt{7+4sqrt{3}} can be rewritten as 2+sqrt{3}. Making such simplifications is not easy in general.
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
1060817
Square Root:\n\nSQRT(1839472)=1356.271\n\nSQRT(75639)=275.0255\n\nSum:\n\nSQRT(1839472) + SQRT(75639)\n\n= 1631.2964 (ans)
84518
If the directions are to simplify, then what you have to do when multiplying square roots is to multiply the coefficients (numbers in front of the variables) and add the exponents of each variable.  Then if possible simplify the new coefficient (here, that won't be possible). Finally, if any exponent is 2 or higher, put one of that variable outside the square root for every 2 that the exponent has.  So if it is x^7 under the square root, x^3 goes outside and x is left inside.  For y^4, y^2 goes outside and no y is left inside.  I hope that makes sense and you can figure it out from here.
765445
(1) sqrt(7a)Xsqrt3=sqrt(7aX3)=sqrt(21a)\n(2)sqrt(5a)Xsqrt(15a)\n=sqrt(5aX15a)\n=sqrt(75a^2)\n=sqrt(25X3Xa^2)\n=5a)sqrt)3\n(3)sqrt3(sqrt5-sqrt3)\n=sqrt(15)-3\n(4)(sqrt2+3)(sqrt2-7)\n=2+3(sqrt)2-7(sqrt)2-21\n=-19-4(sqrt)2
1001971
[(16x*2-25) / (24x*2-30x)] / [(8x*2-2x-15) / (6x*2-7x-3)]\n= [(16x*2-25) / (24x*2-30x)] [(6x*2-7x-3) / (8x*2-2x-15)\n= [(16x*2-25) (6x*2-7x-30] / [(24x*2-30x) (8x*2-2x-15)]\n= [(4x-5) (4x+5) (3x+1) (2x-3)] / [(6x) (4x-5) (4x+5) (2x-3)]\n= (3x+1) / 6x
972013
2*root(5/7) - 3*root(7/5)\n\nFirst we notice we can distribute the root throughout the fractions, and rewrite our equation\n\n2*(root5 / root7) - 3*(root7 / root5)\n\nTo get rid of the radical denominators, we can multiply through by the denominators. So we multiply through by root5*root7\n\n2*root5*root7*(root5/root7) - 3*root5*root7*(root7/root5)\n\nWe see that the denominators cancel with their respective partners, and the numerators are squared. Thus the roots all dissapear and we are left with:\n\n2*5 - 3*7\n= 10 - 21\n= -11
927974
Multiply the coefficients and then add and subtract the exponents for the like bases. \n(7x^3y^-5)(4xy^3)= 28x^(3+1)y^(-5+3)= 28x^4y^-2
1174116
8x^2 -5 -3x^2 + 7\n8x^2 - 3x^2 -5 + 7\n5x^2 + 2
917114
√45x^6y^7=√(3x^3y^3)^2*5y=3x^3y^3√5y
283762
If your question is 2√(x+5)=√(x+45), then:\nStep 1.  Take the square root of both sides.  You'll get 4x+20√(x)+25=x+45\nStep 2.  Move the numbers and variables until √(x) is by itself.  You'll get √(x)=(3x-25)/(-20)\nStep 3.  Square boths sites to get: x=(9x^2 -150x +625)/(40)\nStep 4.  Multiply both sides by 40.  You'll get: 40x=(9x^2 -150x +625)\nStep 5.  Subtract 40x:  0=(9x^2 -190x +625)\nStep 6.  x=17.034 and 4.077
708801
The answer is 10\n\nMultiply 5 times 20 and take the square root of that.\n\nMultiplication and Square Roots can be done in either order.
964858
That just means that keep it in the square root instead of simplifying it.\nEx: Keep it as square root of 2 instead of 1.414\n\nSo if you're finding the square root of 27, for example.  You can split up 27 into 9*3.  Square root of 9 is 3, but 3 is not a perfect square.  So your answer would be : 3 square root of 3.  Instead of 5.196