in math what is perimeter, area, and how do you draw a pentagon?
609947
Perimeter is the sum of the sides.  For example, if you have a 4 cm x 6 cm rectangle, you would add the 2 sides of 4 cm with the 2 sides of 6 cm to get 20 cm.  So the perimeter is 20 cm.\n\nFor area, it depends on the object you have.  If you have a kind of rectangle, you'd multiply the length times the width to get the area.  For a triangle, you'd multiply the base and the  height, then divide it by 2.\n\nTo see a drawing of a pentagon, go here:\n\nhttp://en.wikipedia.org/wiki/Pentagon
646607
Volume is for a solid, and a pentagon is a flat shape.  Do you mean area?  And have you given us all the information.  This obviously isn't a regular pentagon because two of the sides are not equal...  What are we missing?\n\nIf you mean a pentagonal solid, I suppose you could mean the area of the base is 60 sq cm and the height is 8 cm?  In this case it is just the area of the base times the height, or 480 cubic cm.  Don't forget to express the Volume in cubic cm. (cm^3).\n\nOn the other hand, if you are given the *perimeter* of the base being 60 cm and you assume a regular pentagon, then you have a different question....\n\nHere each side is 12.  The formula for the area of a regular pentagon is:\n\nA = 1.720s^2\n\nPlugging in 12 cm, you get:\n\nA = 1.720(144) = 247.68 sq. cm.\n\nMultiply the area of the base by the height (8 cm) to get your final volume:\n\nV = 247.68 * 8 \nV = 1981.44 cubic cm \n\nAgain don't forget the cubic on the units.
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There are two ways to measure the area of a shaded figure. The third is by integral calculus.\n\nMethod 1. \n\nStep 1. Draw the figure on a graph paper by choosing suitable scales in x and y axes.\nStep 2. Count the small squares that are shaded. If a square is not whole, then count it as one if it is greater than half a square. Skip it if it is less than half. And of course, two halves make a whole.\nStep 3. Convert it to area by multiplying the number of squares with area of 1 square.\n\nMethod 2.\nCase 1:\nIf the figure is a polygon, draw diagonals from from corner points and break it down to triangles.\nNow, the area of triangles can be calculated mainly by two formulae.\n\nArea of a triangle = (1/2) base * altitude\n= square root of [s(s-a)(s-b)(s-c)] \n\nThe second formula is very useful and practised in surveying. Here, a,b, and c are the three sides of a triangle; and s is the semi-perimeter i.e. s=(1/2)(a+b+c)\n\nCase 2:\nIf the boundary of the figure is curved, the the matter is a bit harder. If it is a circle or a part of a circle, use formula: area= pi*r squared; pi is approximately 3.1416..  Or else, you have to replace the curve by a straight line such that the area remains the same by eye.\n\nBy integral calculus, area can be found by using table of formula.
850259
here:http://www.cut-the-knot.org/Curriculum/Geometry/AreaOfParallelogram.shtml
948147
pentagon, doesn't matter the length of each side\n5-sided is pentagon
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The first area to be defined was the obvious one of a rectangle.  The number of squares of unit size that would fill up a rectangle is clearly the number of such squares that fit in a row across one dimension of the rectangle, times the number of such rows needed.  Since each square has a length and width of one unit, it's easy to see that the length x width = area of a rectangle.\n\nA rectangle can be divided into two right triangles of equal size.  Hence, the area of a right triangle is 1/2 x length x width, only in triangles we call those things base and height.  Now, any arbitrary triangle can be broken up into two right triangles.  Doing so, it's easy to show that the area of *any* triangle is 1/2 x base x height, where the height is defined as the perpendicular distance from the line containing the base to the opposite vertex.  Similar techniques using triangles can be used to find the area of other regular polygons. \n\nThe area of things like circles can be computed from integral calculus, although I suspect there is probably a geometric method to find the area of a circle as well.\n\nThe area of figures bounded by more complex functions than straight lines and circles is found using integral calculus.
838640
The perimeter is the measure of all of the sides added together.  If you have a square, the sides are all equal.  So, 3+3+3+3= 12 OR 3x4=12.  The answer is D.
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the formula for the area of any regular shape is \n(pa)/2, so there is no multipling the base by 2 involved.\np=perimeter\na=apothem
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Why are you asking this again?  I just answered you.\n\nAgain:\nThere are "levels" to dimensioning.\n\nThe major dimensions are the overall height, width, depth of the whole object. \n\nThe next level down will sub-divide that major dimension to describe sub-components.\n\nAs example: Consider a house plan. \n* From one extreme side to the other extreme side is a MAJOR dimension (the overall width). \n* In between those extreme outer wall edges are interior walls that need to be located as well. So the next layer of dimensions (MINOR) still goes from one side to the other but pulls lots of dimensions from lots of walls. \n* Also, there are porches, corners for inset windows, etc Another MINOR level picks up those points.\n* And so on.\n\nIn your 3D drawing: \n* you only have 6 MAJOR dimensions to a cube shape anyway. Depending on how you rotate the drawing object, you see 3 of them and 3 will be hidden (back side).
921010
I'm going to focus on the usual non-euclidean geometry due to Lobachevsky. In that geometry, there are infinitely many lines parallel to a given line and through a given point. Squares (i.e. figures with 4 equal sides and 4 equal angles) don't have right angles. There is a pentagon with all right angles. The area of a triangle can be determined by the sum of the angles in the triangle (it is proportional to the difference of 180 degrees and the sum of the angles). There is a 'natural' unit of distance obtained from angles between parallel lines and perpendicular lines.
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i think you might mean what 2 dimensional figure has the greatest area in relation to its perimeter. in that case the circle has the greatest area of any shape with the same length perimiter.  so the answer is nothing.  if you take a rope and are asked to arange it into a closed shape with the most area, a perfect circle is the shape you'd use.
789618
a) 24 in.\n\nSince a square has four sides...  You must add six for each side (i.e. 6 + 6 + 6 + 6) to get perimeter.
35250
Perimeter = a+b+c\n\nThis is the answer your maths teacher will be looking for.
426495
It depends on what shape you want to know the area.\n\nSimple shapes have formulas. (such as a circle's area is Pi*r*r)\n\nComplex shapes which have pattern.(you know the equation of lines that form the shape), calculus is used to find the area.\n\nIf a shape is not ordinary. You should draw lines to grid it and count the area square by square.\n\n-Hope this would help-
978615
a polygon with 5 sides is a pentagon.\n\nthis has two right angles so it would look like the picture of a basic drawing of a house.   see the pic of the house attached.\n\nhttp://www.thestationerystudio.com/index.cfm/fuseaction/catalog.viewProduct/productId/5214
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You can draw a triangle with base of 6 and height of 8.\n\nAs the area of a triangle is one-half*base*height, as long as the product of your base and height is 48 units, use those dimensions for your triangle. For example, you could draw a right triangle with base of 6, height of 8, and hypotenuse of 10, but it doesn't *have* to be a right triangle. You can also draw an isoceles triangle with base of 6 and height of 8 - make your base, start your height line at the "3" mark, and then form the rest of the triangle by dropping two segments from the top of the "height" segment to each end of the "base" segment.
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Zeroth dimension = point\nFirst dimension = line\nSecond dimension = square\nThird dimension = cube\nFourth dimension = tesseract\nFifth dimension = decateron\n\nThe rests have names (I've lost the website), but what you are listing is the names of polygons (at least after the tesseract), all two-dimensional objects.\n\nA two dimensional object with:\n3 sides = triangle\n4 sides = square\n5 sides = pentagon\n6 sides = hexagon\n7 sides = heptagon\n8 sides = octagon\n9 sides = nonagon\n10 sides = decagon\n\nSee the below for the construction of the rest of the names: