The reaction between an aldehyde and a ketone, catalysed by a base, is known as:?
613304
Well, an aldehyde can react with a ketone under either mildly acidic or alkaline conditions to form an aldol (or beta-hydroxy aldehyde), in a process called an "Aldol condensation".
146289
Primary and secondary alcohols react with PCC ('Pyridinium chloride) to form an alhehyde (primary) or a ketone (secondary). The reaction is a softened form of chromium oxidation chemistry. The reaction was discovered in the group of the famous chemist E.J. Corey. The disadvantage is that PCC is toxic and green alternatives to this reaction are definately desired. (C&E news recently reported a non-Tin Barton reduction of an alcohol to an alkyl group, but I digress)
877933
Hold a match up to it, and I suspect it will under go oxidation!! Do you mean under certain experimental conditions???\n\n----------\nOK. Here's a link that explains it nicely - but basically the trick is to realize that oxidation can mean the loss of a proton (i.e. hydrogen ion, or H+). The carbon atom that has the oxygen double bonded to it has that electronegative oxygen sucking electron density away from it, making it slightly positive in charge. So on the aldehyde, which has a hydrogen bonded to that same carbon atom, the slightly positive carbon atom is quite happy to give up the proton (i.e. oxidation). Remember like charges repel to help understand this. Another way to think about this is that considering  the oxygen, carbon and hydrogen atoms, the oxygen is the most electronegative, and the hydrogen the least electronegative. So the electrons will tend to be attracted to the oxygen the most and the hydrogen the least. So you've got this positive hydrogen atom sitting there, and it is very easy to be plucked off as a proton.\n\nThe ketone doesn't have a hydrogen bonded to that carbon atom, so it is relatively inert.
182435
Well, there are a lot.\n\nSubstiution:\n\nR-OH + SOCl2 ---> R-Cl\n\nElimination\n        \nR-R'-OH ---->  R=R' + H20 (with an acid catalyst and heat)\n\nReduction:\n\nR-OH ---> R-CH3 (Barton Reduction)\n\nOxidation:\n\nR-OH ---> R-COOH\nR-OH ---> R=O\n\nThen alcohols can act as nucleophiles, so there is a another set of reactions. But I've listened enough, imho.
302954
the previous reaction will provide 0% yield of n-heptyl benzene.  it'll all isomerize to the 2-heptyl, not "some of." Friedel-Craft is the right reaction, but you want acylation not alkylation with heptanoic acid (acid chloride, or prepare in situ).  then reduce the resulting ketone by any of a zillion ways ... zinc/HCl being the classic.\n\nand where did you get the idea that the longer the synthesis the better? that's just nutty.
741409
Its an acid base reaction. The baking soda (sodium bicarbonate) is a base and neutralizes the acid in the vinegar (acetic acid) and releases carbon dioxide in the process.\nHere is the reaction :\nNaHCO3 + CH3COOH ———> NaCH3COO- + H2O + CO2
417838
The chemical compound formaldehyde (also known as methanal), is a gas with a pungent smell. It is the simplest aldehyde. Its chemical formula is H2CO. Formaldehyde was first synthesized by the Russian chemist Aleksandr Butlerov in 1859. it is readily soluble in water, and it is most commonly sold as a 37% solution in water called by trade names such as formalin or formol.
663295
Chemistry relating to Carbon derivatives.
215729
K2IC4H6 + HNO3 ---  K2HI + NO3C4H6
899857
A solid that is formed by a chemical reaction.
364809
hey do u mean bases in chem.? well if it is in chem, then a base is not an alkali! a base is a compound which reacts with the hydronium ions of an acid to give salt and water only. they are insoluble in water but an alkali is soluble in water. Hence all alkali's are bases but all bases are not alkali's. eg of a base Cuo and of an alkali KoH
986422
A ketone solvent contains the carbonyl (C=O) group e.g. acetone or propanone.  If one of the groups coming off the carbonyl is an H then it is an aldehyde instead.  \nAn ester solvent contains the ester -O-(C=O)- group e.g. ethyl acetate.
128824
NaBH4 functions as BH4-, which donates a hydride (a hydrogen with a negative charge) to the aldehyde or ketone that you're working with. The product is a sodium salt/alkoxide. Water or HCl (acid) will protonate the alkoxide to generate the alcohol that you need. \n\nThe gas formed was probably hydrogen, from when the HCl reacted with the Sodium borohydride.
102941
I believe it was catalase.  It comes from the term to catalyse which means to speed up or destroy.  Calalyses are not used up in chemical reactions just like enzymes.
836698
The greater the Kb value is, the stronger the base.  Just think about what Kb means.  On the left side of the equilibrium is the base, on the right side is the conjugate acid, meaning the base has reacted.  The stronger the base, the more it will react, the more the reaction will proceed to the right, the greater Kb will be.\n\nSo.....\n\nC > E > B > A > D
867786
Let's take potassium representing group 1.  All the others will do the same thing.  Here is the reaction:\n\n2K(s) + 2HCl(aq) --> 2KCl(aq) + H2(g)\n\nThe reaction for group 2 will be similar.  Let's take calcium  representing group 2:\n\nCa(s) + 2HCl(aq) → CaCl2(aq) + H2(g)\n\nHope this helps.
460627
The keto is in equilibrium with the enol form. In the enol form, the stereogenic carbon assumes sp2 hybridisation and so loses optical activity.