What happens to the level of the water when you do this?
606896
The water level will go down when you throw the body in.  Try it in your sink.  Fill your sink with water and float a bowl (boat) in it.  Then, fill the bowl with silver wear (body and rocks) or anything more dense than water.  Mark where the water level is on the side of the sink.  Now, take the silver wear out, and put it in the water so it falls to the bottom of the sink.  You will notice that the water level went down.  When the silver was in the bowl, it displaced much more water than when it was at the bottom of the sink.  Therefore, the body will displace more water when it is inside the boat than when it falls into the water.
580754
i haven't done this in a while.\n\nThe volume of the reservoir is equal to (1/2)*(height)*("base")*length.  the reservoir is a rectangular prism with the "base" being the distance across the surface of the water.  We are given the shape of the full volume so we can scale down to the level of the water to find what the volume in the reservoir at its current level.\n\nif you think about the cross-section of the volume, and use half of that forming a right triangle, we can determine the ratio of the surface (the "base") to the height (water depth).  In this case, it is (40/2)/(20*sqrt(3)) or 1/sqrt(3).  so ("base"/2)/(height) = 1/sqrt(3)  and then "base" = (2*height)/sqrt(3).\n\nsubstitute that into the volume equation so that\nvolume = [(height^2)*length]/sqrt(3) or literally,\nV = [(h^2)*L]/sqrt(3).  differentiate with respect to time,\n(dV/dt) = [2*h*(dh/dt)*L]/sqrt(3) and substitute the numbers in:\ndV/dt = 200 - 50 = 150\nh = 10*sqrt(3)\nL = 450\nand solve for dh/dt which is the rate of change of the water level in yds/hour.  these are odd units, you might want to change to inches/hour.\n\ni did it this way and got 1/60 yds/hr or 0.6 inches/hr.\n\nbut again it has been a long time....
56505
ok, well it depends on the container, what is in teh water, if teh container is filled with water to the top or if there is expansion room.  Also elevation, temperature and pressure (air pressrue) would have an impact because the container might just crack or explode
216556
The water must be given as initial push to go uphill. Once the flow is established, siphoning can occur.
152879
No, it will not.  The other answers to this question are on the right track, in that they point out that an object's density is the key thing in most situations, since if it is less dense than the fluid it is in, it will displace fluid equal to its weight before it is completely submerged, and hence float.\n\nBut in *this* problem, we are told from the outset that there is not enough water to be displaced.  Therefore, the object will displace all the water, all 1 lb. of it, and still not have displaced enough water to equal its weight.  Therefore, it will rest on the bottom, i.e. not float.
816334
your body is accelerating at the same rate of the car so no matter what you do, you will impact the water at 9.8 meters per second squared. that should kill you. the same happens in falling elevators. if you jump before it hits the bottom, you will break your legs or die.
644239
I'm assuming that you're referring to drowning with this question. The answer is none...the water is so salty that you cannot sink.
110991
The water comes from a point elevated far above the sink height (a reservoir in upstate NY).\n\nBecause its source is higher, the water will flow (downward)--even though the pipes might go 'up' a buiding. Its all about the conservation of energy laws you can learn about in physics.\n\nFrom the reservoir it is piped to the city, and it gets filtered and treated before it gets to the sink.\n\nThe sink valves hold it back until you open them, and let the force of the flow down your drain, where it goes out to the river.
444674
if you drop something in the water, it displaces water, and that displaced water moves other water, the rock going down in teh water pushes some up, which then pushes some down, and so on and so on.
611169
Base area x height of water.
65968
The water in the toilet is inside a "knee", basically an s-shaped combination of curved tubes. If the far side of the tube develops underpressure, some of the water will be pulled over into the far side, and water level will sink.\n\nPressure on the far side can oscillate. Usually the waste water system is connected to outside pressure via a separate chimney. On windy days, this chimney may act like a jet pump, reducing the inner pressure of the canalisation, so that water will be sucked into the falling side when the oscillation goes that way, lowering the water level.\n\nAnother possible source of oscillation are huge amounts of water flushed at once, moving down the tube pushing all the air below and leaving lower pressure above.\n\nBarometric pressure shouldn't really come into this, since canalisation and the open air are connected. However high or low the pressure, it ought to be the same inside the canalisation unless strong wind makes the chimneys act like jet pumps.\n\nNow, at which air pressures do you observe strong wind?
215319
Not sure, but if you drain yourself of approx 5 pints then you will loose alot of wieght.
694162
nothing, the air is probably underneath the fluid and the position change will reverse that allowing the air to escape.
65104
They probably pump it up and fill it. Lke allwater towers there are pipes going both up and down. Once filled though, they can leave it alone for awhile. Usually there are sensers inside that relay to a computer and alerts when the tower is getting low. In small towns I know sometimes they put too much water in and it isn't used. Thats why they sometimes flush it. But I would research the topic in an online enclycopedia.
516732
Well, the temperature doesn't matter. What does matter is the concentration of the water outside of you. It's osmosis/diffusion. You have water in your body and there's water outside of you; but the water outside gonna have a higher concentration that the water inside of you. This is when you take into consideration that the water outside of you  will include dirt(some salts) and other chemicals like from your soap or shampoo, which is why it's concentration is higher. The whole process of your fingers shriveling-up is because the water inside of you leaves your body in attempt to balance the concentration outside to equal yours.
265293
It is due to a change in the mass as the volume of water changes.
78350
When the metal enters the water, it begins losing heat to the water. At the same time the temperature of the water rises. This process continues until the temperature of the metal and the temperature of the water are equal st which point (30.6oC) no net flow of heat occurs. The heat lost by a gained system is given by (mass)(Specific heat)(change in temp.)First calculate the heat gained by the water, then calculate the specific heat of the metal.\n\nTemp rise in the water - \n   (change in temp) 30.6 - 25.0 = 4.4\n\nHeat gained by water - \n              \n   (185.0)    (4.184J)/(g oC)  (4.4) = 3.4*10 pwr3 J\n\nThe metal dropped into the water must have the same temp as the water (30.6)\n\nTemp drop by the metal - \n   (Change in temp) = 178-30.6 = 147.4\n           \n Specific heat = \n(heat)/(mass)(change in temp)\n\nSpecific heat of the metal =\n(3.4*10 pwr3)\n(36g)(147.4)\n             \n=0.640 J/g oC\n\nhope this helps. good luck