a motor uses 825 N to list a load a distance of 5 m in 2.5 sec. what is the power nedeed?
595586
I got 1650. First I multiplyed 825 * 5, and then divided that by the time which was 2.5. The formula for power if I remember correctly is work divided by time. Work is equal to f times d. D is the distance and f is the force in Newtons.\n\nI think this is correct if I remembered how to do it the right way. :]
51664
1.35 x 10th\n\nI probably typed it wrong.  1.35 times 10 to the 10th power.
288780
From the following link, look for "Chapt22, Problem-24".\n\nThis problem is similar, except the speed is 10% instead of 11%. I'm sure you can use the same formulae though.\n\nhttp://www.jca.umbc.edu/~george/html/courses/phys112/2004fall/homework/04fall_phys112_hk8.pdf
340440
power is the amount of work done in unit time \nit is measured in Joules per second , dude
189249
totaly diferent motor
2752
A. Potential energy = Force * Distance\n     = (50 * 9.8) * 10\n     = 4900 J\nB. Power rating = Energy / time = 4900 / 5 = 980 Watts
1065117
You need the power factor of the motor. Since that is not known, we have to assume the PF. Let the PF be 0.85. Then,\n\nI = (8.5*1000)/( sqrt 3*415*0.85) = 13.9 =14 A. You can read the PF from the motor and adjust the result.
349215
mechanical power, P = Work done per unit time = W/t\n\nElectical Power P = current times potential difference = IV\n\nfor ohmic devices we can also use the substition from Ohm's law V = IR in the power formula above.
685470
the speed = distance/time
90631
energy because power wich is in mw multipiled by time wich is actualy in seconds or hour equals energy wicj is in joules
818883
Es = L*r*w (w=2piN) , N=600 rpm=10rps , L=9 \nEs = L*r*2pi*N) , N=10, L=9 \nEs = 9*0.18*2*3.14*10\nEs (Shaft Energy)= 101.734 Newton/second which is not a unit of power.\n\nPlease specify the units of r,Es,L=95 or 9 ?\nWhat is the unit of Ee? HP or KW?\nfurther you have given following data which are contradictory.\nPump Shaft Speed =1200 ?\nEe (Electrical Energy) = 67.2\nT = 1.62\nw (Rotational Speed)= 62.8
378804
Vf=Vi+At\n5=12+A*2.3\nA= -3.04348 m/s^2
696257
Energy given = energy absorbed\ntotal travel of pile driver h1 =4.00+0.11=4.11 m\nAssume the pile has no mass\nenergy given = mgh1 = 1900*9.81*4.11\nenergy absorbed= F * h2 = F * 0.11\nF * 0.11 = 1900 * 9.81 * 4.11\nF=696,420.82 N
35590
I concur with previous answerer. The acceleration is 1.5 m/s^2. Rearrange Newton's Second Law, to solve for the acceleration. Then, substitute what you know.
697169
The equation for power is:\n\nP = W / t\n\nwhere P is power, W is work and t is time. Assuming a perfectly efficient power harnessing system, the work provided is equal to the gravitational work done to pull the water down. \n\nA total of 2400 liters of water (2400 kg) is moved from a height of 20m down to a height of 0m, so:\n\nW = m * g * h\n\nW = (2400 kg)(9.81 m/s²)(20m)\n\nW = 470880 J\n\nThis work is provided over the course of 1 minute (60 second), so the power provided is:\n\nP = 470880 J / 60 s\n\nP = 7848 J/s = 7848 W\n\nFinally, 1 watt = 0.001 340, so 7848 W provides 10.52 hp.\n\nP = 10.52 hp\n\n\nHope that helps! :)
1102009
q = I t\nq = 2.5 C/s x 900 s = 2250 C = 2.3 kC\n\nP = 120 V x 2.5 A = 300 watt\nE = P x t\nE = 300 J/s x 900 s = 270 kJ
346550
kingbodonti is correct...\n\nPower in watts = Work in joules / time in seconds\n\nPower = 1,000 joules/50 seconds\n\nPower = 20 watts ANSWER