what is the correct meaning of " Y:(i=0i>xE'11=:e_y#a#?oe?.hlp8jklu.mgjap,e(p+>i*tf!"?
606057
" Y:(i=0i>xE'11=:e_y#a#?oe?.hlp8..
747950
It's many years since I did maths but shouldn't there be an = somewhere? And isn't there normally "y" too? I thought it would be fun to stretch my brain for a change but...Am I being obtuse?
846187
if you are using a "while" or "do while" loop\n\nwhile ((x1 - x0) > 0.001)\n{\n//your code here\n}\n\nor you can do this\n\ndo\n{\n//your code here\n}\nwhile ((x1 - x0) > 0.001);
367158
(0! + 0! + 0! + 0! + 0!)!\n\n\n0^0 is undefined.
743387
Working above is good until this step:\n\n2 + 0.8x >0.9(x + 6)\n2 + 0.8x >0.9x + 5.4)\n0.1x > -3.4 ← Symbol error in this line\n\nShould read 0.1x < -3.4\nie x < -34
534027
function f1(){\nvar e = 12.88;\n\nvar e1 = e + "";\n\nif(e1.indexOf(".") != -1){\nif(e1.substring(e1.indexOf(".")+1,e1.length).length >  2)\nalert (" Invalid");\nelse\nalert ("Valid  "+e1);\n}\n}\n\nTest with changing the Value of e to different numbers
130040
http://en.wikipedia.org/wiki/E_%28mathematical_constant%29\nfor the significance of e and how it is used, use this link
246299
h= (C*I/A+T/k)*z*log(.7*y)
339463
no its starts with a Y. the Y and y are differnt in the computer world.
838865
What language is this?  It looks like the result of a night of unbridled passion between C, C++, and Java!\n\nSo, you know that "x->y" is equivalent to "(*x).y", right? So, even though you never used . directly, it's apparently what the compiler is seeing. Of course, . can only be used with a struct, and it is complaining that you are using it with something that is not a struct. However, the error is confusing, since the problem is really caused by a problem with pointers.\n\n Consider b[10]  (and b[9]).  b is a pointer to blocks. The [ ] operator dereferences this pointer, so that b[10] has type block, not block *.  Since -> can only be used with pointers (block *), the compiler generates an error. \n\nThink carefully about what you want to do, draw a picture on paper, and make sure your types all make sense.  Good luck.
774675
the code for the prg is\n\nmain()\n{\nint no1,no2,min,max,i;\nscanf("%d %d", &no1,&no2);\nif (no1<no2)\n{\nmin=no1;\nmax=no2;\n}\nelse\n{\nmin=no2;\nmax=no1;\n}\n\nfor(i=min;i<=max;i++)\nprintf ("%d&#92;n",i);\n\n}
947162
Code:\nsyms x\n\ny= x^2 + sin(x) - erf(x)\n\ndy=diff(y,'x')\n\nSuggestion: read the help for sym/diff which is very different than a numerical diff like you are working with.
1136716
2r<22\nr<11\nAnswer= (-infinity,11)\n\n* don't have the infinity symbol on computer
1099552
x' € S - {x}\nworks fine...\n( replace the € by the usual "is an element of" symbol )
479514
It printed this for me 0♦8\n\nHope this Helps.\nGood Luck!!!
411757
since y=+-(x)^(3/2) Range [0,oo[\nnP=(n,n*n^1/2) and x_n/y_n= [(n^1/2^)/n]=n^-1/2
781563
y>(12-3x)/4\n\nSteps:\n\nmultiply the 12 on both sides\n3x+4y>12\n\nminus the 3x isolating the y variable\n4y>12-3x\n\ndivide by 4 on both sides to get y by itself\ny>(12-3x)/4 or...\n\nsimplified 3-(3x/4)