What is the area of a kite, geometry wise?
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I believe it would be one-half times the length of each diagonal.\n\nIn other words, if the diagonals are 4 & 6 the area would be:\n\nA = 1/2 * 4 * 6 = 12\n\nIf you don't know the diagonals, but you know the length of the sides, you could construct the diagonals and calculate their dimensions using the Pythagorean theorem:  c^2 = a^2 + b^2, and then solve from there.  Keep in mind that you'll have to do some extra geometric analysis to find the length of each leg of the right triangles that are created by the intersection of the diagonals before you can use the theorem.
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42.0 by 59.4 cm (2500 cm2)\n\nThe length of A series paper is 1.414 (square root of 2) times its width. This is done so that if you blow up or reduce to any other size in the range, the image shape is the same.\n\nThe area of A0 paper is 1 square metre\nSo A0 is 84.1 by 118.9 centimetres\n\nA1 is half the area of A0 (5000 cm2)\nSo A1 is 59.4 by 84.1 cm\n\nA2 is half the area of A1 (2500 cm2)\nSo A2 is 42.0 by 59.4 cm\n\nA3 is half the area of A2 (125  cm2)\nSo A3 is 29.7 by 42.0 cm\n\nA4 is half the area of A3 (625 cm2)\nSo A4 is 21.0 by 29.7 cm\n\nA5 is half the area of A4 (312.5 cm2)\nSo A5 is 14.8 by 21.0 cm\netc. etc.\n\n\np.s. sorry, greywolf, A4 is 29.7cm long not 9.7cm.\nand wiseguy, stick 4 pieces of A4 together, if you cut A4 in half, you get A5.
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Surface area. Seriously. 8D
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im a geo student, but i havent done proofs for a long time sorry. ok\n2. false, because squares are parallelograms with 4 congruent sides and 4 right angles, while kites have 2 pairs of congruent sides and only 1 pair of congruent angles that are NOT right angles\n3. false, because a rhombus is a parallelogram with 4 congruent sides, while a kite is any thing BUT a parallelogram. enuff said\n4. false, because kites are quadrilaterals with only two pairs of congruent sides, while the quadrilateral mentioned has 3 congruent sides\n5. false, for example- do trapezoids have 4 congruent sides, and 4 right angles, and is a parallelogram (characteristic of squares)? i think NOT\n6. read above- trapezoids are not parallelograms.
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Yes, follow the suggestion of x60157. In addition, if you can determine the:\n\n1. height ,h, of each triangle you can use the formula for area: A = 0.5bh where b = side prependicular to the height\n\n2. sides of the triangle, then this formula can be used:\nA = Sq. root of (s(s-a)(s-b)(s-c)) where a,b,c are the sides of each triangle; s = semi-perimeter = 0.5(a+b+c)
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kites as in the things you attach to strings or birds of prey
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Area = Length x Width\n\nArea = 2 ft x 5 ft\n   ''    = 10 sq. ft
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If your two figures have a ratio of similarity of 2:5, then each side of the smaller one is the side of the larger one times 2 and divided by 5.  This might lead you to believe that your area would be 100 times 2 and divided by 5 = 40.  This is, however, not the case.  If each side is times 2 and divided by 5, the total area is times 2 times 2 divided by 5 divided by 5. = 16\nThe best way to imagine this problem is by assuming your shape is a square.  How large is each side of the square if the area is 100 square units?  Each side must be 10 units, since 10 times 10 is 100 square units.  Now shrink each side by multiplying by 2 and dividing by 5.  Each side is now 4 units long.  How much area is your square?  4 times 4 is 16 square units!
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lol.\nfind formula for area of spiral.  subtract smaller from bigger.  sry no more help.
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Okay I will prove it.\n   there are 2 extreme cases of kite:\n  (i)when both sides become equal:\n      then it becomes a rhombus and area is .5*d1*d2\n  (ii) when one side is zero :\n      then it becomes a triangle and its area 1/2*b*h\nsatisfies the formula for kite (try drawing it)\n   Now the variation of area with the diff of sides is a smooth function must have a formula that satisfies both extremes. 1/2d1d2 satisfies the condition.\n   Assume that there is one more function satisfying the given criteria.It must have same value at all pts since area  \nis a unique entity.2 functions have the same graph and hence they must be identical.This proves that no other answer exists.
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15a) Ahh, lengths, areas, and volumes. Lengths are proportional to each other, areas are proportionatl to the square of the length, and volumes are proportional to the cube of the length.\n\na) The ratio of the area of the windscreen is ⅜^2\nb) The ratio of the capacities of their boots is ⅜^3\nc) The ratio of the widths is ⅜\nd) I suppose the model car has four wheels, just the original. It's a model, after all.\n\n15b) we are looking for a rectangle with area equal to 16. Let the width be w. Then the length is w + 6.\n\n16 = w(w + 6)\nw^2 + 6w -16 = 0\n(w + 8)(w - 2) = 0\n\nw = 2, and the length is 8. The area is 16.
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Area of what?\n\nRectangle = b×h\nSquare = l^2\nTrapezium = ½(l+b)h\nEllipse = πlb\nCircle = πr2 \nTriangle = ½b×h
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*\n1/2 base X altitude + area (triangle)\n\n\n45 square centimeters
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The area of an equilateral triangle is\nA = (1/4)sqrt(3) * a^2, where a is the length of the side.\nSince the triangle is equilateral, you know that the length of each side is 10/3.\nThe area is\nA = (1/4)sqrt(3) (10/3)^2\nA = (1/4)sqrt(3) (100/9)\nA = (25/9)sqrt(3)
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Long or wide?\nSingle line?\nDual line?\nQuad line?\nWhat kind?\nThere are many diffrent kites out on the market today,\nHere's a link to my friends shop, he can get just about\nanything you want.\nhttp://awindofchange.com/\nHis name is Kent, just tell him what your're looking for\nand he can help.\nTell him that you were sent to him by me "Powerkyter."
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go to this website and try to understand how to get the area of the shade region \n\nhttp://www.algebralab.org/lessons/lesson.aspx?file=Geometry_AreaPerCricle.xml\n\ngood luck
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The area of the rectangle is:\n A of rectangle = L X W = 12 x 8 = 96 sq in\n\nThe area of the triangle is:\nA of triangle = 1/2 (A)(B) = 1/2 (A)(32 in) where A is the altitude to the base B of the triangle.\n\nsince both areas are equal:\n96 sq. in = 1/2(A)(32 in)\n96 sq. in = A (16 in)\nA = (96 sq. in)/16 in\nA = 6 inches