area of a triangle is 64 square meters and the base is one-half times the heigth. what is the triangles height
606374
Let h = height, then \nb = (1/2)h\nA = (1/2)bh\n64 = (1/2)(1/2)h*h\n64*4 = h^2\n256 = h^2\nh = 16
287728
Surface Area = [Base Area] +\n1/2 × Perimeter × [Side Length]\n\nVolume = 1/3 × [Base Area] × Height\n\nThe Surface Area has two parts: the area of the sides (the Lateral Area) and the area of the base (the Base Area). \n\nThe Base Area depends on the shape, there are different formulas for triangle, square, etc. \n\nBut the Lateral Area is surprisingly simple. Just multiply the perimeter by the side length and divide by 2. This is because the sides are always triangles and the triangle formula is base times height divided by 2
324878
I'm assuming you are asking for a formula to calculate the area when you just know the base (x) and not the height.  But, you need to know the height, even if the triangle is a right triangle.  To see this, imagine you had a right triangle standing on it's shortest side.  That shortest side would be your base, x.  Now stretch the triangle taller and taller.  The base length still stays the same, but the area inside the triangle grows and grows.  (And the triangle is still a right triange.) So, unless you know the height, you can't know the area.\n\nNow, what I'm guessing, is that your triangle might actually be not only a right triangle, but an isosceles triangle too, meaning that 2 of the sides are the same length.  And because it's a right triangle too, that means the two shorter sides (that connect at the right angle) are the same length.  So, your base and your height are the same length.\n\nIf this is true...\n\nlet x = length of base\nsince triangle is isosceles and right, height also = x\n\nSo the traditional formula becomes:\n1/2 BH = 1/2 x*x\n(sorry, can't figure out how to write "x squared" right now)\n\nHope that helps...
814915
Area = ½ ab SinC\n Area = ½(55)(29) Sin 61º\n Area = ½(1595) Sin 61º\n Area = 797∙5 Sin 61º\n Area = 797∙5(0∙874 619 707)\n Area = 697∙509 2165\n Area ≈ 697∙51 square units.
975485
H*W= area\nheight times width\n\none side has a height of 8 and its width is 9 thus the area would be 72
471423
The area of the rectangle is:\n A of rectangle = L X W = 12 x 8 = 96 sq in\n\nThe area of the triangle is:\nA of triangle = 1/2 (A)(B) = 1/2 (A)(32 in) where A is the altitude to the base B of the triangle.\n\nsince both areas are equal:\n96 sq. in = 1/2(A)(32 in)\n96 sq. in = A (16 in)\nA = (96 sq. in)/16 in\nA = 6 inches
644806
if the triangle is a regular triangle\n\na = (1/2)bh\n\na = (1/2)(6)(6 * sin60)\n\na = (1/2)(6)(3√3)\n\na = 9√3 = 15.588\n\n\nfor a regular polygon, \narea = (n*t^2) / (4*tan(π/n))\n\nwhere n = number of sides & t = length of side
684692
Question 20906\nSubmitted on 5/28/2002\n\nFind the area of a nonagon inscribed in a circle of radius 24cm.\n\nSolution 20906\n\nThe nonagon can be divided into nine congruent isosceles triangles. \nThe lengths of the sides are 24 cm and the vertex angle is 360/9 = 40.\nThe base of one triangle is\nB = 2 * 24 * sin (20)\nThe height of the triangle is\nh = 24 * cos (20)\nSo the area of one triangle is\nA = (1/2) * 2 * 24 * sin (20) * 24 * cos (20)\nA = 24^2 sin(20) cos(20)\nAnd the area of the nonagon is\n9 * 24^2 sin (20) cos (20)\n= 1666.1\n\n\nSubstitute in your 1 meter for the 24 centimeters and you'll get your answer.  I believe the answer should come out to somewhere around 3.353 m^2
254539
The sides of the initial right isosceles triangle are 1 and 1.  Therefore the area = 1 x 1 x 1/2 = 1/2.\n\nThe sides of the enlarged triangle are 8 and 8.  Therefore the area = 8 x 8 x 1/2 = 32\n\nDilation:\n\nAssuming the preimage is the smaller of the 2 images:\nThe are of the preimage = 1 therefore the sides of the preimage square is 1 by 1.\n\nIf the scale factor is 1/4 , then the sides of the image square is 4 by 4 therefore the area = 16 and the perimeter = 16 (4+4+4+4)\n\nInversely if the preimage is the larger of the 2 images, the size of the image sqaure is 1/4 by 1/4 and the area = 1/16 and the perimeter = 1 (1/4+1/4+1/4+1/4)
816398
The area of a triangle is given by the formula:\nA = 1/2 b * h\n\nLet b = h + 2\nA = 40\n\nSo:\n40 = 1/2 (h + 2)h\n40 = (h² + 2h)/2\n80 = h² + 2h\nh² + 2h - 80 = 0\n(h + 10)(h - 8) = 0\n\nh + 10 = 0\nor\nh - 8 = 0\n\nh = -10 \nor\nh = 8\n\nBut negative numbers don't make sense for lengths, so there is one answer:\n\nThe height = 8 ft\nThe base = 10 ft
851772
1/2 bh or bh over2.\nType triangle is inconsequential.\nb=base  h=height\nMeasure both, multiply, divide in half.
214682
Always, always, always draw a picture if you are having trouble.  Or do an image-search to look at for reference.  Ok, here goes:\n\nA pyramid with a square base will have 4 equal triangular faces, leaning in to meet at a point.  First find the area of the base, that's the easiest.  It's width^2.  In this case, 15.5^2 = 240.25\n\nNow to find the area of one of the triangular faces.  The height of the pyramid is from the point at the top straight down to the center of the square.  If you were to go from this point out to the side, you would be drawing a line from the center of the square to the midpoint of the base of one of the triangular faces.\n\nSo you've created a right-triangle with a height that is the height of the pyramid (19.3), a base that is 1/2 the width of the square base (15.5/2 = 7.75), and solving for the hypotenuse will give you the "actual" height of one of the triangles (if you were to stand it up straight), otherwise knows as the slant height.\n\nUsing pythagorean theorem, 19.3^2 + 7.75^2 = c^2; c = approx 20.798, the height of one of the triangles.\n\nNow you have all the information you need to find the area of a triangle.  The formula for that is 1/2*base*height.  You just found the height, and the base will be the width of the square-base of your pyramid (again, try to picture it).\n\n1/2*15.5*20.798 = approx 161.1845\nThere are 4 of these, so 161.1845*4 = 644.738\nAdd that to the area of the square base, 240.25\n\n644.738 + 240.25 = 884.988 -- this is approximate since I rounded earlier.
599733
I believe it would be one-half times the length of each diagonal.\n\nIn other words, if the diagonals are 4 & 6 the area would be:\n\nA = 1/2 * 4 * 6 = 12\n\nIf you don't know the diagonals, but you know the length of the sides, you could construct the diagonals and calculate their dimensions using the Pythagorean theorem:  c^2 = a^2 + b^2, and then solve from there.  Keep in mind that you'll have to do some extra geometric analysis to find the length of each leg of the right triangles that are created by the intersection of the diagonals before you can use the theorem.
863802
area=(1/2)d1*d2\n=(1/2)*28*13\n=14*13\n=182 sft
779149
you can figure out the hypotenuse using the pythagorean theorem (a^2 + b^2 = c^2), so the hypotenuse is 10.\n\nAfter that, you just add up the areas of all the surfaces - For the triangles, its 6x8 divided by 2 = 24\n\nFor the rectangular faces, you do the following\n4x8 = 32\n4x6 = 24\n10x4 = 40\n\nAdd all these up and you get as surface area of 120.
604203
to find the surface area of a pyramid take 1/2 of the perimeter of the base times the slant height and add on the area of the base.  First lets find the area of the base with 3 sides of 17.32 each. You need more information for this, unless you have been taught some simple trig functions. To get the area of the base we need to know the height of this base(if it were standing up).If I use the tangent function I find that the height of the triangle is approximately 15 inches. So the area of the base is 1/2 times 17.32 times 15. I did the tangent of 60 degrees = the height of the triangle divided by 1/2 the side of the triangle.  I hope this helps solve the rest of the problem.
981841
area of the base times the height.