xpand and simplify (x+4)(x-1)(3x+2) ?
610650
Getting other people to do your homework is not a good way of helping you out, sadly.
811666
cross multiplying\n(x-4)(x+4)<x(x-5)\nx^2-16<x^2-5x\nadding 5x-x^2\n5x-16<0\nadding 16\n5x<16\ndividing by 5\nx<16/5\nx<3 1/5
685308
(3x + 6/4(x^2)) (x + 2/16(x))\ntake out x\n=x(3 + 3/2(x)).x(1 + 1/8)\n=9/8(x^2)(3 + 3/2(x))\ncan simplify d numbers still.
593331
x + 3 = x (x + 3)\n\nx + 3 = x^2 + 3x\n\nx^2 + 2x = 3\n\nx = 1 or -3
245933
(4x+3)(x-1)=0\n\nx= -3/4, x=1
798648
(x+3)(x^2+2x+4)\n\nStart by taking the first term in the first parenthesis and multiplying it by each term in the second parenthesis:\n\nx*x^2 + x*2x + x*4 = x^3 + 2x^2 + 4x\n\nNow take the second term and multiply it by each term in the second parenthesis:\n\n3*x^2 + 3*2x + 3*4 = 3x^2 + 6x +12\n\nNow add all of that together\n\nx^3 + 2x^2 + 4x + 3x^2 + 6x +12\n\nand combine terms\n\nx^3 + 5x^2 + 10x +12
846663
(x+3)(x-1)\n\n x= -3\nx=1
51216
x = [-(-4) +/- root((-4)^2 - 4x1x(-5))]/2x1\n  = (4 +/- 6)/2\n  = 5 or -1
985787
this is\n\nx^4+ 4\n= (x^2)^2 + 2^2\nadd and subtract 4x^2\n= (x^2)+2(x^2)*2 + 2^2 - 4x^2\n= (x^2+2)^2 - (2x)^2\n= (x^2+2x+2)(x^2-2x+2)
789893
x+4(2x+1)=3( x-2)+10x : x=2.5\n\nI like to work with x
119559
its (x+2)(3x+1) now thats rite lol
920343
(4/3)[x^3/(2-x)]^(1/3)\n[(2-x)(3)x^2-x^3(-1)]/\n(2-x)^2=\n\n 4x[1/(2-x)]^(1/3)\n[3x^2(2-x)+x^3]/\n3(2-x)^2
859715
1) 4-3x<_8+x\n4+8<_x+3x\n12<_4x\n3<_x or x in the interval [3,plus infinity)\n\n2) 3x-3>-x+1\n3x+x>1+3\n4x>4\nx>1 or x in the interval (1, plus infinity)\n\n3) 3(x-1)_<4x\n3x-3<_4x\n-3<_x or x in the interval [-3, plus infinity)\n\n4)1/2x<x+1\n-1<x/2\n-2<x or x in the interval (-2, plus infinity)\n\n5)-1/2x>1-x\nx/2>1\nx>2 or x in the interval (2, plus infinity)
602540
x + 3 >  8 ==> x >  8 - 3  ==> x > 5\nx - 4 < -2 ==> x < -2 + 4 ==> x < 2\n\nAnswer... not possible.
196269
i took this question to mean as:\n\n[11/ (4-x)] + [2x/ (16-x^2)]\n\nso, what you do first is to multiply addends by (-1/-1), which is still equal to one, and won't make a difference, except to change the signs.\n\nso it would look like\n\n[-11/ (x-4)] + [-2x/ (x^2 - 16 )]\n\nsimplify to:\n\n[-11 / (x-4) ] + [ -2x / (x+4) (x-4) ]\n\ncombine the elements:\n\n[(x+4) + (-2x)]/ [(x+4) (x-4)]\n\nto make \n\n[(x+4-2x)]/ [(x+4) (x-4)]\n[(-x+4)]/ [(x+4) (x-4)]\n[-(x-4)]/ [(x+4) (x-4)]\n\nand the simplest would be:\n\n-1 / (x+4)\n\n hope this helps. :D
157812
[x^2/4][2(log(x) - 1) log(x) + 1]
110508
(x^2+5) / (x^3+15-2x^2+1)^2\non [0,1]