How we can calculate Short Circuit Impedance of an industrial plant with 33kv supply?
595239
Typing "short circuit program" into Google or Yahoo produces the following sites selling programs designed to calculate fault currents for power systems.\n\nhttp://www.bussmann.com/apen/software/s_circuit.asp\nhttp://www.elitesoft.com/web/electrical/elite_short_info.html\nhttp://www.easypower.com/short_circuit.html\nhttp://www.cai-engr.com/sc.htm\nhttp://www.durandassociates.com/Short_Circuit/short_circuit.html\n\nTake your pick...
887561
Use ACDSee Classic.\n\nhttp://www.download.com/3000-2192-1808446.html
827069
The meter should have some literature with it.\n\nWrite to the manufacturer and ask for it.
898940
You can find printable schematics on the page I've linked below.\n\nGood luck.
140136
Here's a study guide.  http://www.doctronics.co.uk/meter.htm
756481
Normally this is a "Restive" not voltage question/answer, and the proper neutral to ground = 2 Megg ohms (min.) this being incorporated in a residential application.\nHigher voltage in let us say a 3-phase utilization this # is on the low side. (assuming a.c. source. d.c. is a completely different animal!
679718
The deciding factor here would be the Utility Company Service Entrance. THAT cannot be rewired by you! The other two points ( Low side of transformer and Motor Windings) can easily be configured either way by simply rewiring the 3 windings on the motor, and the 3 windings on the output of the transformer.\n\nOptimum efficiency will be DELTA-DELTA-DELTA or STAR-STAR-STAR...Either way no 'ground loops' to cause loss.
1041136
Read in Detail at this site\nhttp://books.google.com/books?vid=ISBN0768917425&id=Ca58uytAJoAC&printsec=toc&dq=mechanical+engineering%3F+CIVIL+%26+ELECTRICAL%3F
815065
I tried to import a spreadheet for you but I coouldn't make it come through, if you email me I'll send it to you, like1m@yahoo.com  \n\nYou can fill in the two variables, just write it in excel and you will be able to calculate your values for voltage and current dependent on the resistance for any given values.  All answers here are correct as it is the basic premise of \nOhms law, but you asked for a chart.  You do need to know the resistance though.  The interrelation is such that for at a given voltage with infinate resistance there will be no current (flow), for that same voltage with minimum resistance there will be maximum current (flow) this would be referred to as a dead short and is comparable basically to welding. Either extreme is not normally practical unless you are turning the power "off" in one case or welding in the other (dead short).  Dependent on the requirement usually the interrelation is desired to be somewhere in the middle.  There is also the element of reactance which is slightly more dynamic that static resistance. but for now this is what your auto calc chart should look like....  \n\nInput ohms & volts to autocalc Amps\n\nInput OhmsInput VoltsI=V/R\n      200                     24                 0.12\n\nInput ohms & Amps to autocalc Volts\n\nInput OhmsInput AmpsV=I*R\n    200                     0.12                   24
1100598
voltage = current x resistance\nE = I x R  It IS Ohm's law. An easy way to remember the formula and it's configurations is to draw a circle and divide it in half horizontally. Above the line write "E". In the lower half divide the semicircle vertically and write "I" on the left, "R" on the right. It should look something like this:\n                                                     E\n                                                   I    R\nNow just cover up the one you need. and either divide, or multiply.
708021
The symbol for electrical load is Z called impedence.\n\nThis consists of the inducticve reactance, capacitative reactance and ohmic resistance.
864668
First, what is the input voltage and the desired output voltage?  Is the output voltage fixed, or do you need a range of adjustment (taps)?  Do you need isolation between the input and the output?  If not, an autotransformer (single winding) might be acceptable.  What is the frequency, and is it single phase, three phase Y, or three phase delta?\n\nNext, what is the power rating?  Small transformers are usually rated in output current, whereas larger transformers are rated in KVA.  This is the maximum load;  a smaller load would not be a problem.\n\nFinally, what are the mechanical factors?  Does it need to be hermetic or can it be open frame?  Do you want terminals or wire leads?  What shape and size?  What is the mounting?\n\nIt's not really that hard.  Usually you can browse through a catalog and find the transformer you need in minutes.
898015
Nominal= 36ohms\nTolerance=5% \nMultiply nominal by .05 , then add that figure to nominal for Max,.subtract it from nominal for Min.,,and study your ohm's LAW!! ;-)=
1028580
The website book section on AC circuits linked below is probably your best bet to get a full understanding of this topic.  Click on the power factor chapter; it is pretty good.\n\nNevertheless, my quick answers to your questions:\n\npower factor arise only in 3phase?\n** Nope.  It must be considered in both single and multiple phase AC circuits\n\ndifference between kW and kVA? \n** One is the unit for real power (kilo Watts) and the other is the unit for apparent power (kilo Volt-Amperes).  kVAR (kilo Volt-Amperes Reactive) is the unit for reactive power (basically power that is stored and released in inductive/capacitive loads).  Real power and reactive power sum up to equal apparent power (see the triangle diagram in the linked page).\n\nHow is the power factor caused?  What is the effects?\n** The power factor is the cosine of the impedance angle of your load (or the apparent power angle of the load, same thing).  Power factor varies between zero and one.  Where one indicates all real power (resistive impedance) and zero indicates all reactive power (inductive or capacitive impedance).  In between zero/one is a combination between the two.  Generally, we like to have a power factor near one; otherwise supplying power to large reactance loads can be wasteful and can lead to unsatisfactory voltage drops at the load.\n\npower_factor = cos(voltage_angle - current angle) = cos(impedance_angle)\n\nWhat is lead/lag/unity?\n** unity => pf = 1 (all resistive load, voltage and current in phase)\n** lagging => pf between 0 and 1 (corresponds to inductance in the load, current angle LESS than voltage angle)\n** leading => pf between 0 and 1 (corresponds to capacitance in the load, current angle GREATER than voltage angle)\n\nWe need the lead/lag distinction in power factor, otherwise we don't have any idea if we are talking about an inductive/capacitive load.\n\nHope that helps.
978617
Try this web page:\n\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/electronic/zenereg.html\n\nIt shows the basic circuit and has calculator to figure out component values.\n\nThere are much better solutions out there for a voltage regulators than zeners... such as the three terminal regulators like 78xx or LM317 types...
123471
Go to ThomasNet.com, which is a comprehensive directory of industrial manufacturers and suppliers. Searching for "electrical supplies" yield 6,379 results, and each result includes company description, contact information, website address. Browse through the results and contact the companies that you think would provide you with what you need.\n\nHope this helps
95109
This might help\n\nhttp://www.ttec.co.tt/consumertips/conserveelectricity/default.htm