(r+8)^2=r^2+16^2....work out PLEASE!!!?
547879
(r+8)(r+8)=r^2 + 256\nr^2 + 16r + 64 = r^2 +256\n16r = 192\nr = 12
76669
a=8\nb=-6\nc=-9\n\nx= -b + or - square root of {b^2-4(ac)} all over 2a\n\nx= 6 + or - square root of {36 - 4(8)(-9)} all over 16\n\n = 6 + or - square root of 324 all over 16\n\n (6+18) divided by 16= 3/2\n (6-18) divided by 16= -3/4\n\nso, x= 3/2 or -3/4\n\nthere you go. hope this helps
814891
a^2 - 2ab + b^2 = (a - b) ^2\n\nthen...\n\n(a - b)^2 / (a + b) = (a -b) (a - b) / (a + b)
814352
(12x^2 +16x) - (12x-7)- (4x-5)\n12x^2 +16x -12x +7 -4x +5\n\n12x^2+12\n\nthat is what I got....\nI think you might be able to put 12 on the other side of the = sign and turn it into 12x^2 = -12 and then since both sides have 12 in common you can divide both sides by 12 and you will have x^2 = -1 then you can add 1 to both sides and you will have x^2 +1 but I think I'm getting off track by that point....it's been a while since I had to do this stuff.
825318
(a^2 -2ab + b^2) = (a-b)(a-b) = (a-b)^2\nYou cannot cancel anything, so \n(a^2 -2ab + b^2)/(a+b) does not simplify.\n\nYou may wish to write it as (a-b)^2 /(a+b)
937830
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today
988729
(a + b)^2 = a^2 + 2ab + b^2\n\nso\n\n(a + 1)^2 = a^2 + 2a + 1\n(a - 1)^2 = a^2 - 2a + 1\n\n\n\nFermat:\n\nIf a = 2^(n-1) then\n(a + 1)^2 = (2^(n-1) + 1)^2\n = (2^(n-1))^2 + 2(2^(n-1)) + 1\n =( 2^(n-1)^2 ) + (2^n + 1)\n\n\n\nMersenne:\n\n(2^n - 1) + (2^(n-1) - 1)^2 =\n = 2^n - 1 + (2^(n-1))^2 - 2(2^(n-1)) + 1)\n = 2^n - 1 + (2^(n-1))^2 - 2^n + 1\n = (2^(n-1))^2\n = ( (2^(n-1) - 1) + 1 )^2
784622
16x^2 - 4x - 2\n= (4x)^2 -(4x)- 2\n= {(4x)^2 - 1} - (4x+1)\n={(4x+1)(4x-1)} - (4x+1)\n=(4x+1)(4x-2)\n= 2*(4x+1)(2x-1)
965936
use pythagorean theorem.\n\na^2 + b^2 = c^2\n\npluggin in\n\na^2 + 4^2 = 11^2\n\na^2 + 16 = 121\n\nSolve for a\n\na^2 = 105\n\na = sqrt(105)\n\na = 10.247
945218
[(x^2)^2]^2\n\n(x^2 -4x +4)^2\n\nmultiply      x^2  (x^2 -4x +4)^  = x^4 -4x^3 +4x^2\n\nmultiply     -4x (x^2 -4x +4)^    = -4x^3 +16x^2 -16x\n\nmultiply     4  (x^2 -4x +4)^      =  4x^2 -16x +16\n__________________________________________\n\nthe answer should be                 x^4 -8x^3 +24x^2 -32x +16\n\ni hope that helped
800533
Well dear Kristi \n\nthe answer is \n( 9r - 2s )^2 \n{ as you know ( a - b )^2 = a^2 -2ab+ b^2 \n81r^2 - 36rs + 4s^2\na = 9r , b = 2s , so \na^2 = (9r)^2 = 81r^2 \nb^2 = (2s)^2 = 4s^2 \n-2ab = (-2)(9r)(2s) = -36rs  } \n\nGood Luck Darling
788940
Dear friend,\n\nYour product is \n\n-5*(x^2) + 8*x -10*x + 16 =\n                           \n-5*(x^2) - 2*x + 16
984964
a^2 + b^2 = c^2 <---- This you should know.\na^2 + a^2 = c^2 <---- isosceles, so a = b\n2 (a^2) = c^2\nsqrt (2 * a^2) = c\nsqrt (2) * sqrt (a^2) = c\nsqrt (2) * a = c\n\nSubstitute 8cm for a and you'll find c.
735754
just plug the numbers in.  if y=8, and x=2, \nits 8=a(2^2)\nso 8=a(4)\nso a=2.\nhope that helps!
344768
Nooooooooooo\n\na^2-81=\na^2-9^2=\n(a-9)(a+9)\n\n(if you don't believe\n multiply (a-9)(a+9)=a^2-9a+9a-81=a^2-81)\n\nthe formula is a^2-b^2=(a-b)(a+b)\n\n(a-9)^2=\na^2-18a+81\n\nhere the formula is (a-b)^2=a^2-2ab+b^2\n\n(you can simply check it by multiplying\n(a-9)^=(a-9)(a-9)=a^2-9a-9a+81=a^2-18a+81)\n\nand you must see the difference between \na^2-81 and a^2-18a+81, it's quite obvious.
815860
Hello Dear \n\n- Take " √ " of eachsides\n√16y^2 =  √ 25 \n± (4y = 5)\ny = ± 5/4\n\nGood Luck dear.
1004368
x^4+y^4+8>= 8xy? \n\nI redid the proof using the Am-Gm inequality.\nUsing Am-Gm\nlet x^4=(x²)² & y^4=(y²)²\n((x²)²+ (y²)²)/2 >= sqrt{(x²*y²)²} =>\n\n((x²)²+ (y²)²)>= 2*x²*y²\n\n((x²)²+ (y²)²)+8>= 2*x²*y²+8\nUsing Am-Gm again on 2*x²*y²+8 =>\n(2*x²*y²+8)/2>=sqrt(2*x²*y²*8) =>\n(2*x²*y²+8)>= 2*sqrt(16*x²*y²) =>\n(2*x²*y²+8)>= 2*4*x*y=8xy\nSince x^4+y^4+8>= (2*x²*y²+8) &\n(2*x²*y²+8)>=8*x*y\nthen x^4+y^4+8>= 8xy. \nend of proof using the Am-Gm twice