What is the formula for finding the volume of rectangular prisms in cubic units?
613917
Height times Width times Length
888444
The volume unit would be a cubic unit as it is 3-dimensional. It would depend on the unit of measure in the equation.\n\nThe calculation for volume of a cylinder is (pi) * radius^2 [squared] * height.\n\nOr out in English "Pi times the radius squared times the height"
254189
cube = a 3  \n\nrectangular prism = a b c  \n\nirregular prism = b h  \n\ncylinder = b h = pi r 2 h  \n\npyramid = (1/3) b h  \n\ncone = (1/3) b h = 1/3 pi r 2 h  \n\nsphere = (4/3) pi r 3  \n\nellipsoid = (4/3) pi r1 r2 r3
1100142
area or volume???\n\narea = 2 (3.4 * 3 + 3*2.2 + 2.2*3.4 )\n in square meters.\n\nvolm = 3.4*3*2.2\nin cubic meters.\n\n\nI only edited bcoz ever1 is giving wrong ans for area. Correct area is 48.56 sq mtr. I dont understand how it can b 6.6\n\nvolm = 22.44 cubic mtr
559607
A rectangular prism is simply made up of 6 rectangles.  One pair of rectangles would be 3cm x 3cm (the ends).  The other 4 rectangles would be 3cm x 20cm.  So the total surface area would be the sum.\n\n3cm x 3cm = 9 sq. cm\n3cm x 20cm = 60 sq. cm\n\nSo 9 + 9 + 60 + 60 + 60 + 60 = 258 sq. cm.\n\nIn this case two of the dimensions were the same, but if the sides were h,w,l the total surface area would be:\n= hw + hw + hl + hl + lw + lw\n= 2hw + 2hl + 2lw\n= 2 (hw + hl + lw)\n\nIn your example:\n= 2 (3x3 + 3x20 + 3x20)\n= 2 (129)\n= 258 sq. cm.   (Don't forget the units are sq. cm)
173051
area is .001 X .001 = .00001 (the area per cube face) X 6 ( the number of faces on a cube)=.00006 cm squared.\nVolume is length times width times height, or .001 X .001 X .001 = .0000001 cm cubed\n\nso, .00006/.0000001 = 6/.001 = 6000.
4519
(4/3)*pi*r^3\n\n[four thirds pi r cubed]\n\ngood luck!
77442
It implies that the box is 10 square so each dimension is 10.  Volume of a cube = h x d x w , or in this case 10 x 10 x 10 = 1000
175713
Your question is too complicated to appreciate the math in it, which is supposed to be the real beauty in the first place. Anyway, I have tried figuring it out and come with equations. I do not even want to try and begin substitution and end up with more complications. I just thought once you saw the relation, you would throw those 10 points my way.\n\nAssuming a to be sides of the squares of the prism and b to be the length of the rectangles, we know that the sum of all dimensions is 14a+5b. Now I do not even want to get started why you brought it the story of the equilateral triangle. You can just say the sum  of the dimensions is 61. Anyway, since any side of the trianle, as it is equiangular hence equilateral, is twice 14a+5b and 122, the sum of the dimensions will be 61. So your first equation is 14a+5b=61\n\nYou know the volume of the prism is the length X width X heiht = a x a x b = (a^2)b This is equal to the surface area. The surface area is the sum of all the areas on the prism and that is a^2+4ab. (How about you calculate how that came up?)\n\nSo there is your second equation, (a^2)b = a^2+4ab So then from 14a+5b=61, express a in terms of b or the other way around and plug it into the second equation and experience brutal complications and figure out what the variables are. I think you know it is too easy to calculate each dimension and area after that.
281759
3454.3615403812755165920718499567 centimetres cubed
1127924
Area of rectangle = length x width \nArea of a circle = pi x R x R = pi R^2 where pi~3.14 and R - radius\nArea of an ellipse = pi x a x b see http://www.tpub.com/content/engineering/14069/css/14069_33.htm \n\nVolume = area of the base times hight\nVolume of a rectangular prism= area of rectangle x height = length x width x height\nVolume of a sphere = (4/3)pi x R x R x R = (4/3)pi x R^3\n \nCheck math tables or the web for equation of other geometric figures \n\nPercentage = 100 x (partial amount) / (total amount)\n\nHave fun
141014
The equation for vol depends on what he's taking the vol of i.e. square sphere etc. \n\nCommon equations for volume:\n\nA cube: s^3 = s*s*s (where s is the length of a side)\nA rectangular prism: l*w*h (length, width, height)\nA cylinder: PI*(r^2)*h (r = radius of circular face, h = distance between faces)\nA sphere: (4/3)*PI*(r^3) (r = radius of sphere) - (which is the first integral of the formula for Surface Area of a sphere\netc.\nmore volume defs @: http://en.wikipedia.org/wiki/Volume\n\nPI = 3.1415926535...\n\ndensity is represented by the symbol rho which looks like a p and the equation for it is p = (m/V) where m is mass and V is volume.
486266
the formula for volume of a cylinder is V = h * pi * r^2.\nAlternatively, the surface area is A = h * pi * r * 2.\n\nSo, if you have either the surface area or the volume, you can calculate for the height.\n\nH = Volume / pi * r^2\nH = Area / pi * r * 2
606307
Suppose you have a rectangular box.\nThe length is 3 more than the height.  The width is twice as long as the height.\nWhat is the volume of the box?
121103
The formula for the volume of a pyramid is V = (1/3)Ah\nwhere A is the area of the base, h is the height, and V is the volume \nof the pyramid.
955408
the formula is half the height times the base.  But here's why:\n\nFirst consider a rectangle.  You know the surface to be height times width.  Now cut the rectangle in two pieces, along a diagonal.  You end up with two triangles. Furthermore, the sides of these triangles are the same, thus the triangles themselves are equal. The surface of each has to be half that of the surface of the rectangle.\n\nFor triangles with a right angle in them, you have proven 0.5*h*b to be correct.  But each triangle will work.  If you have a triangle without a right angle, you can always find a way to split it in two smaller triangles, each having a right angle, and process each part separately.\n\nYou could also cut a parallelogram in two equal parts (again: cut a diagonal) and end up with two equal triangles, not having a right angle.
916691
The closer you get to a cube shape (i.e., width=length=height) the better.\n\n**************\n\nOoops. You're right, it's deceptive. While a cube maximizes the volume for a GIVEN area, in this problem we decrease the total area the more we cut from the sheet. So, you need to express the volume of the cube in terms of the heights of the sides.\n\nI did a quick re-calc, and decided that the squares (i.e, the height of the resulting sides) should be 1/3 m.\n\nGood question!