how do u find the height of a triangle?
598737
I wish I remembered terms for this stuff.\nFind the length of the base, divide that by two.\nUse this number to find the length of a line drawn from the point of the triangle to the base. Congrats, that number is the height.\nTriangle ABC.\nLength from point A to C is 3.\nFrom A to B is 4.\nSo B to C is 5.\nTake the base, we'll say line AC, and divide that by 2, so you get 1.5.\nUse that number, now, as the length from A to D.\nSo, 1.5 squared plus 4 squared is 18.25. Square root of 18.25 is 4.27, so your height is 4.27.\nPythagorean Theorem.\nA^2 + B^2 = C^2
190089
use heron's formula: \nArea=SQRT(s(s-a)(s-b)(s-c)), \nwhere s=(a+b+c)/2 or perimeter/2. \n\nyou only need to know the sides of the triangles. \nfrom (0,9) to (4,6), the distnace is a=5\nfrom (0,9) to (-1,12) the distance is b=sqrt(10)~3.16\nfrom (4,6) to (-1,12) the distance is c=sqrt(61)~7.81\n\nso, s=(5+3.16+7.81)/2=7.985\n\nplugging these 4 numbers into the formula gives \nSQRT(7.985(7.985-5) (7.985-3.16) (7.985-7.81))=4.486\n\nso the area is approximately 4.486
722736
the angles are just unknown if i get you correctly.\nthere are sin, cos, and tan proportions you can work out to find the rest. i think you only need three of the measurements to work out the rest of the triangle, like 2 sides and an angle or 2 angles and a side.  not positive.
168445
first find a vicinity plan. \nget a straw(in sodas) and a triangle\nstand on a specific location with the distance of X from the building.\nmake sure to know your height.\ncreate a transit by putting the straw along the hypoteneous of your 45x45 triangle.\nlook through the straw (try to see the zenith of the building) and measure the angle of depression.\nthen, simply apply the law of sines and cosines etc etc.\nthis will not give you exact building height but an instant approximation. this can also be used in finding approximate height of towers, canyons, mountains, and volcanoes.
457596
Surface area:\nCylinder(lateral):2 times pie times radius times height\ncylinder(total): 2 times pie times radiuse times height + 2 times pie radius squared\nTriangular prism(total): find the area of every side and add all together to get surface area(hint:area of a triangle=1/2bh or bh/2)\nCone(lateral):pie times radius times length\nCone(total):pie times radius times length + pie squared\npyramid(total):find area of ever side and add all together \narea of a triangle=1/2bh bottom of the pyramid is length times width
1017799
V = area of base times height\nheight = 14\nbase = 3*3*pi = 9pi\nV = 14*9pi\nV = 126pi\nV = 395.8
23271
The area of a triangle can be found by multiplying the base times the one-half the height.\n\nIf a triangle has a base of length 6 inches and a height of 4 inches, its area is 6*2=12 square inches
38263
5.196 (3 times root 3)\nDive the triangle into 3 equal triangles.  Then divide each one of those triangles into 2 triangles.  The hypotnuse of each triangle has a length of 2, and by trig. (it is a 30-60-90 triangle) the base has a length of the square root of 3 and the height is 1. Area of a triangle =(base times height)/2=(radical 3)/2.  There are 6 smaller triangles total, so multiply the area by 6=total area=3 times radical 3 (5.196)\nHope this helps, it would be a lot easier if I had a picture that I could post and it would make more sense.
644806
if the triangle is a regular triangle\n\na = (1/2)bh\n\na = (1/2)(6)(6 * sin60)\n\na = (1/2)(6)(3√3)\n\na = 9√3 = 15.588\n\n\nfor a regular polygon, \narea = (n*t^2) / (4*tan(π/n))\n\nwhere n = number of sides & t = length of side
416512
Here, you will need to use tan(angle) = opposite over adjacent twice.\nDraw a diagram showing two right angled triangles, one with an angle of 23 degrees, the other with an angle of 50 degrees. Both triangles should have their adjacent side (in the diagram i drew!) as 55 ft.\n\nYou then find the opposite side of each triangle and add them together to get the total height of the building.\n\nSo the height is 55tan(50) + 55tan(23) and the answer is in ft.
436114
well, you could be an architect and be using a 30-60-90 triangle and you needed to know a particular side of it. you can use x times the square root of 3, x being the shorter leg, to find the length of the longer leg.
890883
1)One leg of a right triangle is 12 cm long. The diference between the other two sides is 2 cm.\nFind the sides of the triangle. (Pythagorean Theorem)\n\nWhat we can take from this problem is that one LEG is 12 cm long, while the other LEG is unknown (we will call it X) and the HYPOTENUSE -- the longest side of a right triangle -- is also unknown (we will designate it X+2, since it differs 2 cm from the unknown leg).\n\nSetting up Pythagorean Theorem as always:\n\n "Leg squared" + "Leg squared" = "Hypotenuse squared"\n\n  12^2 + x^2 = (x+2)^2\n\nExpanding:\n\n  144 + x^2 = x^2 + 4x + 4\n\nCollecting like terms:\n\n  4x = 140\n\nDivide by 4:\n\n   x = 35\n\nThe unknown leg is 35 cm, while the hypotenuse is 37.  Thus, we can also call the triplet (12,35,37) a "Pythagorean Triple" (of which there are infinitely many!).\n\n\n2) The hypotenuse of a right triangle is 58 cm long. The diference between the other two sides\nis 2 cm. Find the sides of the triangle. (Pythagorean Theorem\n\nIn this case, we know the hypotenuse, but do not know the lengths of the legs.  For convenience, we will again use the expressions X and (X+2) for each side's length.\n\nBy P.T.:\n\n x^2 + (x+2)^2 = 58^2\n\nExpanding:\n\n x^2 + x^2 + 4x + 4 = 3364\n\nCollect like terms:\n\n 2 x^2 + 4x - 3360 = 0\n\nDivide by the GCF (2):\n\n  x^2 + 2x - 1680 = 0\n\nCan we factor this trinomial easily?  We could, if we knew integer factors of -1680 (one positive, one negative) that combine to make 2.\n\nLuckily, -1680 can be factored into -2*2*2*2*3*5*7, and these can be grouped into two sets:\n      2*3*7 = 42\n -2*2*2*5 = -40\n\nFactor:\n\n (x+42) (x-40) = 0\n\nAlthough two solutions come from these factors (-42 and 40), we may only consider the positive answer, since lengths of triangle's legs are always positive!\n\n Therefore, x=40 (Leg 1), and Leg 2 is 42 cm.
1086020
(Click on the link below for the diagram. Expand to get a clearer view)\n\nLet the point of intersection of altitude and base be P\n\nThe length BP and PC is x.\nThe length AB = AC = (40-x-x)/2 = 20-x\n\nThen we use pythagoras theorem to find x.\nx^2 + 8^2 = (20 - x)^ 2\n40x = 336\nx = 336/40 = 8.4\n\nHence the area of the triangle\n= 1/2(base*height)\n= 1/2(16.8*8)\n= 67.2
209843
If you don't want to spend money, you can use mathmatics.\n\nAll you need is a tape measure and a protractor.\n\nDepending on how tall the tree is (just guess) measure about the same distance from the tree.\n\nyou. . . . Tree  (20 ft.) \n\nNow if you can imagine that you are a vertex of a right triangle, and the tree represents the other two vertices.  Bottom of the tree is one, and the top is the other.\n\nSit down in your spot and hold the protractor level wiith the ground.  From the center of the protractor, view the top of the tree and then wrrite down the angle you are viewing through to see the top of the tree.\n\nNow using trigonomerty you should be able to closely estimate the height of the tree.\n\n\nHeight = distance (you to the tree) multiplied by the SIN(angle from protractor).\n\n\nHere is a trig table you can refer to...\nhttp://wikisource.org/wiki/Trigonometric_functions_of_angles_0%C2%B0_to_90%C2%B0_by_degree
323670
measure each diagonal, come up with the area of one triangle X it by 4, then work out the area of the base simple!
856719
This is a good opportunity to learn some problem solving skills- When you're not sure what to do, try a very specific example, then try to do it in general terms. \n\nIn this example, suppose that we assume that the ladder has to touch the fence.  Drawing it out, we see "similar triangles".  What information do we need to compute the length of the ladder (the full hypotenuse)?  Try a specific example now.  Suppose the distance from the fence to the foot of the ladder is 1 unit.  In order to compute the hypotenuse, we need to figure out where the top of the ladder is (the height of the triangle), h.  Using similar triangles,  8/1 = h/5, so the height of the triangle must be 40.  Now the ladder must be the square root of 40^2+5^2.\n\nCan we do that in general?  Easy!  Replace the number 1 by the variable x.  Now write the height of the triangle in terms of x:\n\nx/8 = (4+x)/h  Solve for h.\n\nNow you have the base length, (4+x) and the height h in terms of x.  Now you can compute the hypotenuse.  Hint:  Minimize the hyptonuse squared, not the hypotenuse itself.  It's easier to differentiate.
803140
OK.. First of all it's an isosceles triangle.. thus the base is divided by the vertical line into two equal halves of 3 and 3 each.. \nNow just look at one triangle.. say the left one.. it is a right traingle (the vertical line is perpendicular to the base) having base of 3 and hypotenuse of 21. \nThus if the vertical height is 'h'     => h^2 + 3^2 = 21^2   (^2 means square.. ie power 2) \nsolving for h = (441 -9)^(1/2) = 20.78  (use a calculator)\nNow for theta..         Cos a = Base / hypotenuse \n                                 cos a = 3/21 = 1/7\n                                 a= cos^-1 (1/7)          (Cosine inverse)\n                                 a = 1.43 radians         (Use a calculator :-) )\nGuess thats it !!