Please how do i solve x^2-10x=0???????????????????????????????????????????????????????????????????????????????
609632
If you need to show your work than factor but other wise it is 0 and 10
98037
2. Take the square root of both sides, thereby negating the ^2 and giving 10. Then solve for 5x=10.
898700
x = 4 ==> (x - 4) = 0\nx = -2 ==> (x + 2) = 0\n(x - 4)(x + 2) = 0\nx^2 - 2x - 8 = 0
907934
2x(x - 2) = 3(x + 10)\n2x² - 4x = 3x + 30\n2x² - 7x - 30 = 0\n(2x + 5)(x - 6) = 0\nx = -5/2 or 6 ← option d
808574
4x^2-4x= -7\n4x^2-4x+7=0\nx=(4+/-√(4^2-4*4*7))/8\nx=(4+/-√(16-112))/8\nx=4+/-√(-96))/8\nx=(1/2)(1+/-√6 i)\nx=1/2+(1/2)√6 i\nx=1/2-(1/2)√6 i
610821
Easy...\n0 = 0\n\nadding -2 on both sides\n\n-2 = -2\n-> -3 + 1 = -6 + 4\n-> -2*3/2 + 1 = -4*3/2 + 4\n\nadding 9/4 on both sides..\n\n-> 9/4 -2*3/2 + 1 =9/4 -4*3/2 + 4\n->\n(3/2 - 1)^2 = (3/2 - 2)^2\n\ntaking +ve sqr root\n3/2 - 1 = 3/2 - 2\n\n-> 1= 2\nadding 1 on both sides\n2 = 3\n-> 1 + 1 =3
747917
add -100 x^2\n0=4x^4-98.5x^2\nx^2(4x^2-98.5)=0\nx^2=0 or 4x^2-98.5=0\n4x^2-98.5=0\nx^2=98.5/4\nx=+/-rt(98.5)/2\nso x=0 or +/-(rt98.5)/2
770687
x^2 + 10x = 7\n\nTake half the coefficient of x and square it:\n\n5^2 = 25\n\nAdd that to the equation:\n\nx^2 + 10x +25 = 7 + 25\n(x + 5)^2 = 32\n\nTake Sq. Rt. of both sides:\n\nx+5 = sqrt(32)\n\nx = sqrt(32) - 5\n\nsqrt(32) = + or - 4(sqrt(2) = + or - 5.65685425\n\nx = 0.657 or -10.657
508006
x^2 + 4bx + 2b=0\n(x+2b)^2 - 4b^2 + 2b = 0\n(x+2b)^2 = 4b^2 - 2b\n(x+2b) = SQRT(4b^2 - 2b)\nx = [SQRT(4b^2 - 2b)]-2b\n\n3x^2 -bx +1=0\n3(x^2 - (b/3)x + (1/3)) = 0\nx^2 - (b/3)x + (1/3) = 0\n(x-(b/6))^2 -(b/6)^2 + (1/3) = 0\n(x-(b/6))^2 = (b/6)^2 - (1/3)\nx-(b/6) = SQRT[b^2/36 - 12/36]\nx-(b/6) = [SQRT{^2 - 12)] / 6\nx = {[SQRT{^2 - 12)]+b} / 6\n\nb^2x^2 - 2bx + c^2= 0\n(bx)^2 - 2(bx) + c^2 = 0\n(bx-1)^2 - 1 + c^2 = 0\n(bx-1)^2 = 1 - c^2\nbx-1 = SQRT(1-c^2)\nbx = SQRT(1-c^2)+1\nx = [SQRT(1-c^2)+1]/b
1056888
2(x^2-4x)-1=\n2(x^2-4x+4) -8-1=\n2(x-2)^2-9
148117
25x^2 - 81x = 0\nx(25x - 81) = 0\nx = 0\n25x - 81 = 0\n25x = 81\nx = 81 / 25\n\nSo, x = 0 or x = 81/25.
917843
(x + i)(x - i)(x - 3 + i)(x - 3 - i) = 0\n\n(x^2 - i^2)[(x - 3)^2 - i^2] = 0\n\n(x^2 + 1)(x^2 - 6x + 9 + 1) = 0\n\nx^4 - 6x^3 + 10x^2 + x^2 - 6x + 10 = 0\n\nx^4 - 6x^3 + 11x^2 - 6x + 10 = 0   (Answer)
572493
=x(x^3-2)\n--> x=0 or x=2^(1/3) or -2^(1/3)
855294
x = 9 or -10\n\nTake the square root of both sides of your equation, to get the following:\n\n| x+1 | = 10\n\nNotice I used the absolute value signs around x+1 ... that's because x+1 can equal either 10 or -10.  Why?  Because 10² = 100 and so does (-10)² = 100.\n\nSo, continuing on with showing our work:\n\nx+1 = 10 or x+1 = -10\n\nx+1 = 10  → x = 10-1 = 9\nx+1 = -10 → x = -10-1 = -11\n\nHope that helped!\n\n~ ♥ ~
879495
so easy :\nx^2 - Sx + P = 0\n\nwhere, S is the sum of the roots and P is the Product of the Roots :\n\nS = 2+(sqrt)2 + 2-(sqrt)2 = 4\n\nP = [2+(sqrt)2][2-(sqrt)2]= 4-(2) = 2\n\n==> the equation is x^2 - 4x + 2 = 0\n\nhope this helps enjoy !!??!!
207106
x^2-3=-2\nx^2=-2+3\nx^2= 1\nx=1\n\n1^2+-3+2=0
902011
Ha! You had an answer to that 10 min before you even asked :). Check your previous question.\nBy factoring x out we have \nx(12x^2 + 3x -42)=0\n\nx1=0 \nsee reference and use equations provided\nx2=14/8=7/4\nx3=-16/8=-2