How many minutes would the energy taken to power up a typical lightbulb, light that lightbulb for when lit?
603667
Energy=Power X Time\ntherefore, time = Power/ Energy \n\nThe two formulas for power are: P=VI or P=I to the power of 2 Multipleied by R
35547
By definition, a watt is "the SI unit of power. Power is the rate at which work is done, or (equivalently) the rate at which energy is expended."\n\nA 50-watt bulb is expending energy at 1/2 the rate of a 100-watt bulb.\n\nSo - if both are shining (not "shinning") for the same amount of time, the 50-watt bulb would use 1/2 the energy of the 100-watt bulb.
1184666
(1) C\n   B = D + 2\n   M = B + 4\n   M = ( D + 2 ) + 4\n   M = D + 6\n\n(2) E\n   B = 2H\n   M = B + 6\n   M = ( 2H ) + 6\n   M = 2H + 6\n\n(3) D\n   12 bulbs / x minutes\n   12 bulbs / ( x minutes ( 1 hours / 60 minutes ) )\n   12 (60) bulbs / x ( 1 hour )\n   ( 2 (12) (60) ) bulbs / x ( 2 hours )\n\n(4) D\n   Stop 1: x\n   Stop 2: x + y\n   Stop 3: ( x + y ) / 3\n   Stop 4: ( ( x + y ) / 3 ) + 2 = ( x + y + 6 ) / 3
233283
a regular light bulb \nas apposed to a floresent
829486
Of course not; that would be akin to perpetual motion.  Of the energy used by a lamp, between 5% for an incandescent light bulb to nearly 30% for the best fluorescent tube ends up in usable visible light, and at the other end, the best (and quite costly) solar cells convert 18% of the light in electricity.  So, assuming ALL the light from the best lamp is directed to the best solar cell, you get power back at the rate of 5.4%.  It will get dark pretty quick...
866318
Savings = (Cost Conventional) - (Cost Efficient)\n\n(Cost Conventional) = (Energy Cost + Bulb Cost) x Period\n(Cost Efficient) = (Energy Cost + Bulb Cost) x Period\n\nConventional: 100 W * 0.08  $/kWh * 10000 h = 80.00\nOver the same period, number of bulbs = 10000/750 = 13.3\nSo, total cost = 80.00 + (14 * 0.42) = 85.88 (we can't buy a third of a bulb!)\n\nEfficient: 28 W * 0.08 $/kWh * 10000 h = 22.40\nNumber of bulbs = 10000/10000 = 1\nSo total cost = 22.40 + (1 * 17.00) = 39.40\n\nSavings = 85.88 - 39.40 = $ 46.48 (over a 10000 hour span).
1177158
I just watched something about this on Oprah today. There's these lightbulbs you can buy for about $10 each that have 10 times the life of regular lightbulbs and use up to 66% LESS energy. Also, RECYCLE, REDUCE, REUSE! Plant trees! Use as much recycled materials as you can! And spread the word! Let's all become environmentalists so we can save the Earth for our children and THEIR children! :)
165350
wattage of the bulb is important...prob not generating enough heat to make the 'lava' flow (wax).\n\nIt should show signs of flow within an hour...at least!
163728
Turning off a lightbulb is easy. Simply leave it in the box. It will remain off.
887711
Light IS energy...sorry I can only think of one...:(
661303
Lights in your car interior require little energy and are used rarely and in shorter time periods than most bulbs.  They do burn out though.  \n\nLEDs, the source of light for your cellphone (well, some phones), are much more energy efficient since the light is created from a different process compared to a bulb (light bulbs are essentially resistors that heat up and release light).  LEDs last 5-20 times longer than conventional bulbs, and thus are the future.
451714
Watts is a unit of energy. You probably have 100 watt light bulbs in your house. You probably also have 60 and 75 watt bulbs as 100 is pretty bright. If you are running and creating 100 watts you could power a 100 watt bulb--most peole can't do this for long. I don't remember what METS are, but it is some sort of power output also.
739842
To work this out you must find out the power rating (in watts). Most of the time this information is written on the appliance. For example a standard electric kettle may use 1300 watts. \n\nElectricity is sold in units of 1000 watts per hour. For example if you use 10 100w light bulbs for an hour it will cost you 1000watts or 1 unit of Electricity\n\nYou will have to find your power rating on your appliance then compare an hour of usage of that appliance with the price of 1 unit of power (1 Kilowatt per hour)
393843
b/c a constant amt. of electricity is going into it, and it will only get brighter if you add more electricity to it, or get a brighter bulb!
1043980
You can, but there is a danger of overheating and fire. Here's why.\n\nThe power of a light bulb in watts is determined by the equation P=V^2/R where V = voltage and R = resistance. The higher power (higher wattage) light bulbs actually have lower resistance, so they draw more current.\n\nThat same current must pass through the wires, socket, etc. These also have resistance. The greater the current that passes through the wire, socket, etc. generates heat from the equation P = I^2 * R.  So, if the current is doubled, there is 4 times as much heat that is generated by the wires, socket, etc.\n\nSockets and wires have different ratings depending on their ability to handle high current and heat. You may have seen ceramic light sockets - they provide better heat resistance that lightweight sockets with plastic that can melt.
413474
Electricity is charged by the kilowatt (1000 watts) hour.  A 60 watt bulb uses 60/1000 hr. That's .06 times price per KWH.
830736
It means a tube-light consumes 75 joules of energy per second.But usually a tube light conumes still less power. \n           1watt(W)=1joule/second.\nThe power of the tube... is only dependent on the materials used inside it and it does not depend on voltage applied,current supplied etc.Whatever may be the current supply,the power remains the same.only reqirement is we have to apply adequate voltage and current depending on the power of the tube light.