The length of a rectangle is 3 times the width. If the perimeter of the rectangle is 64units wuts the width.?
598751
L=length w=width\n\nSo L=3w\n\nThe formula for perimeter is 2L+2W=P\nNow, you just plug in the variables and solve\n\n2(3W)+2W=64 --multiply 2 time 3W\n6W+2W=64    --add 6W and 2W\n8W=64    --Divide 8 on each side\nW=8\n\nWidth is 8 units\n\n--hope that helped
877246
The perimeter of the triangle is 48 so you divide that by 4 and the length of each side is 12 inches
360732
Right.  I'm not sure what the question is, but let's assume that the space we are talking about is a rectangle, and you have to figure out what the dimensions are.  Well, the perimeter, 26, is the distance around the space which has the area of 36, which for the sake of argument, we will assume is square feet.  What times what equals 36?  9 x 4, right?  So, it's possible, but not certain that we are looking at a rectangle whose dimensions are 9 feet by 4 feet.  To prove this, remember that a rectangle has four sides.  If our assumptions are correct, it has two sides of 9 feet and two of 4 feet, right? So then,  9 + 9 + 4 + 4 = 26.  It would seem that this is the right answer.  \n\nOf course 12 times 3 also equals 36.  But this time, if we substitute the 12 and the 3 as the dimensions, we would get a perimeter of 30 feet, obviously the wrong answer.  Looks like you have a rectangular space that is 9 by 4 feet.\n\nI hope this helps and that I haven't just muddied the water further.
35250
Perimeter = a+b+c\n\nThis is the answer your maths teacher will be looking for.
745313
Not enough information. If the rectangle is also a square, then the length of each side would be 32/4 = 8 cm. Letting x be the length of one of an arbitrary pair of sides and y represent the length of a side from the other pair, you do know of course that x and y must satisfy the equation 2x + 2y = 32 cm --> x + y = 16 cm. Since you have two unknowns but just one equation, there are uncountably infinite many possibilities for (x, y).
366751
make x the width, and solve the two equations (the one given, and the one assumed about the rectangle where l*w=A)
753977
Do you mean the perimeter? To find the perimeter of a rectangle, you will have to add up the lengths of each side.\n\nFor example, a rectangle with sides that are 2 feet and 4 feet long would have a perimeter of 2 + 2 + 4 + 4 = 12 feet
182640
I'm not sure if this is what you're asking, but if...\nd = length\nd-3 = width\n\nthen the area is d(d-3), a.k.a. d^2 - 3d .\n\nHope this helps!
191768
r u sure its not 40 m less, if it is here:\nLet w=width\n    w+40=length\nw(w+40)=21^2\nw^2+40w=441\nw^2+40w-441=0\n(w+49)(w-9)=0\nw=-49 or w=9\nthe width is 9 m and the length is 13 m
471423
The area of the rectangle is:\n A of rectangle = L X W = 12 x 8 = 96 sq in\n\nThe area of the triangle is:\nA of triangle = 1/2 (A)(B) = 1/2 (A)(32 in) where A is the altitude to the base B of the triangle.\n\nsince both areas are equal:\n96 sq. in = 1/2(A)(32 in)\n96 sq. in = A (16 in)\nA = (96 sq. in)/16 in\nA = 6 inches
935014
If the square has sides of 12, the perimeter of the square is 4x12 = 48 inches. This is the length of the wire.\n\nTo find out the sides of the equilateral triangle, divide 48 by 3, since the triangle has 3 equal sides.
865958
The perimeter is 8.32 Inches\n\nThe answer is 8.32 inch\n\n- - - - - - - s-
789618
a) 24 in.\n\nSince a square has four sides...  You must add six for each side (i.e. 6 + 6 + 6 + 6) to get perimeter.
876778
The triangle is a right triangle of sides 3,4,5.\nThe maximum rectangle occurs when a perpendicular is raised from the midpoint of the short side to the hypotenuse (side that equals 5) and then a perpendicular from point  to the side   that is of length 4. The dimensions of this rectangle are 2* 1.5 = 3 square units.
20276
If the area increases by 25%, it will be 80 square inches. \n\n64/4 = 16\n64+16 = 80\n\nTherefore, the length and width of the new rectangle will be any two numbers whose product is 80, 8 x 10 or 16 x 5 for example.
688339
Let's say w is the width of the rectangle.  Then, the length will be w+5.  We know the perimeter is 58, and we know that the rectangle has two sides of length w, and two sides of length (w+5).  So...\n\n2w + 2(w+5)=58\n2w + 2w + 10 = 58\n4w + 10 = 58\n4w = 58 - 10\nw = (58-10)/4\nw=48/4\nw=12, the width of the rectangle.\n\nSince the length=w+5, the length is 17.
826433
perimeter=4 times the side\n=4*64=256 foot