Train A is travelin 27m n train B is travelin 48m. 780m takes a train 2 get across. In wut pt will they crash?
602319
27+48=75\n780/75=10.4\n75/60=1.25\n1/1.25=0.8\n0.8*60=48\n\nThey would crash in 10.4 hours, or 271.8 miles away from the starting point of train A. The trains cover 1.25 miles in total for one minute. They take 0.8 minutes, or 48 seconds, to travel one mile.
104070
Heather leaves a town at 2 p.m., going 56 mph, traveling east. Erin leaves the same town at the same time going 64 mph, traveling in the same direction. What time of day will it be when Erin is 72 miles ahead of Heather?\n============================================================\n\nHeather's distance = 56x\nErin's distance = 64x\nx = hours traveled\n\nThe distance between them at any time can be expressed as a simple equation:\n\nd = 64x - 56x\nd = 8x\n\nYou want to find "x" when d = 72 miles:\n\n8x = 72\nx = 9 hours\n\n2:00 p.m. + 9 hours = 11:00 p.m.
590410
Emergency on the way home. An adult trying to take a child. The child may fall and need help up. The child may see another child injured. Are you the parent of the child?
735262
1.  The key here is to understand how far the two trains have traveled in total during the first 3 hours.  We are told that the two trains started 500 miles apart, and 3 hours later are now 80 miles apart.  Thus they traveled 420 miles in total. \n\nIf you let x represent the rate of speed that the Freight train is traveling, and x+20 represent the rate of speed that the Passenger train is traveling, you can set the following algebric equation:\n\n3 hrs * x mi/hr  + 3 hrs * ( 20 + x ) mi/hr = 420\n 3x + 60 + 3x = 420\n6x = 360\nx =60 mi/hr.\nx+20 = 80 mi/hr.\n\n2.  The key is too figure out the total number of employees needed to break even.  Regardless of how many employees you have, we are told that it costs $2000 per day to run the factory.  In addition to that  we are told that for each employee, we must pay him or her $300.  These are the total costs for the operation.\n\nOn the other hand, we are told that each employee can produce $500 in revenue each day.\n\nThus, we need to create an algebric equation where the total costs = the total revenue\n\nLet x represent the number of workers, and set up the following algebric equation:\n\nCosts = Revenue\n\n$2000 (Fixed Costs) + $300 * x (Variable Costs) = $500 * x\n\n2000 + 300x = 500x\n2000 = 200x\n10 = x\n\nYou will need 10 workers to break even, and the total gross value of ball bearings produced will be 10 * $500 or $5000.\n\nHope that I have cleared things up for you!
543583
Use the pythagorean theorum.  Train One is the left leg, train 2 is the right leg, and the distance between them is the hypotenuse.  Since they only traveled an hour, their speed is irrelevant.  That triangle gives the formula of (x+10)^2 + x^2 = 71^2\n\nWork it out from there.  X will equal the distance that the second train traveled, and since they traveled for an hour, that is the magnitude of its speed as well.
729421
OK what you need to remember about any problem like this is the formula Distance Traveled=Rate of Travel * Length of Time Traveled, (D=R * T).  As long as you have two of those values, you can calculate the third.  You know the distance, and you know the rate or travel.  To calculate the Time, you get it by itself on one side of the equation.  Divide both sides of the equation by R (rate), like this:\n      D = R * T\ndivide both sides by R\n     D / R = (R * T) /R\nthe R's on the right side will divide out and leave you with\n     D / R = T\nNow you plug in the values for D and R\nFor train A\n     D = 1000 (miles)\n     R = 125 (mph)\nso  T= 1000/125 = 8 hours\nYou know the time is expressed in hours, because your units divide out just like numbers do.  Your are taking miles and dividing them by miles per hour, and that leaves you with hours.\nIf you add in the stops the train makes (2 stops, 15 minutes each) you would add 30 minutes, or 0.5 hours to the total time, it takes Train A 8.5 hours to go from Station 1 to Station 2.\n\nDoing the same thing with Train B...\nT = D / R\nT = 1000 / 100  (Train B is travelling the same distance, 1000 miles, and travelling at 100mph.)\nSolve the equation and you get T = 10 hours, and adding in one stop of 15 minutes (or .25 hours), you get 10.25 hours.\n\nSo, Train A gets there first.  Even if Train B doesn't make it's stop until near the very end of the run, Train A gets to the station in 8.5 hours, and even without any stops, at 100 mph, Train B is still 1.75 hours out of the station at that point.\n\nIt's a useful formula to learn and understand, you can apply in many different situations.\n\nGood luck.
1060398
Two airplanes are both travelling along linear courses, at fixed speeds.  Both will pass over a specific place.  At the same time, one plane is 500 miles east of the place; the other plane is 300 miles south of the place.  If the east plane travels at 500 mph, what speed must the other plane travel at to collide with the first?\n\n--keep in mind I've created a 3D system here--\nSet the point of collision at the origin (0,0). Now we have:\nx=500-500t\ny=300-nt.\nWe're looking for n.\nWe know that t=t in order for them to collide. \nNow solve for x=0 to find out when (the value of t) the first plane reaches the place of collision.  t=1.\nPlace y=0 and t=1 to solve for n.\nn=300mph.\n\nYou have to make your own graph.
782037
I solved the problem by stating that P would travel distance d in time t\nd=20*t+.5*.3*t*t\n\nand Q would travel d+20 in time t\nt is the time to collision\n\nd+20=30*t\nd=30*t-20\nSubtract the equations and solve for t:\n\n0=.15*t*t-10t+20\nt=2.064 seconds\n(the second root is superfluous)\nd=41.9m\n\nWhich proves collision\n\nj
437647
Let's think about how to solve these and maybe that will help you with others,\n\n1. Christian makes the trip twice as fast as Eloise.  Therefore his trip would take half the time.  If his trip was three hours shorter, then 3 hours is half the time.  His trip was 3 hours, Eloises was 6 hours.  So if Christian traveled at 30 mph for 3 hours, and Eloise traveled at 15mph for 6 hours .. how far is that?\n\n[modified below with details for additional answers]\n2. Basically \n4mph x SomeTime = SomeDistance\n5mph x (Sometime-1 hour) = SomeDistance\n\nor, \nif 4x=y and 5(x-1)=y\nthen,\n4x=5x-5\n4x-5x=-5\n-x=-5\nx=5  (this is the SomeTime)\n\ngoing back to the first equation\n4mph x SomeTime = SomeDistance\n4mph x 5hours = 20 Miles\n\ndoublecheck with the second equation,\n5mph x (Sometime-1hour) = SomeDistance\n5mph x (5hours-1hour) = 5mph x 4hours = 20 miles\n\n\n3. If the fast freight was going 60mph for 6 hours (noon to 6pm), then the whole trip is how far? .. 360 miles.  If the slow freight takes 8 hours to go 360 miles, then what is the speed of the slow freight?  360mph/8m = 45 mph
418614
This problem can be described by:\n\ndistance from A to pt = distance from B to pt\ndistance from B to pt = distance from C to pt \n\nsqrt( (x-11)^2 + (y-1)^2 ) = sqrt( (x-3)^2 + (y-6)^2 )\nsqrt( (x-3)^2 + (y-6)^2  ) = sqrt( (x-3)^2 + (y-4)^2 )\n\n\n(x-11)^2 + (y-1)^2 = (x-3)^2 + (y-6)^2\n(x-3)^2 + (y-6)^2  = (x-3)^2 + (y-4)^2\nI think x=87/16 , y=1 is a solution
1054333
Hey, mammalboy. Get a clue. Trains are still used today but tracks don't run everywhere that roads go. Genius.
159138
about 1.5 hours - try www.thetrainline.com
770080
Let us call x the minutes hand on the clock.\nIf 0<x<=5, then it is train B. (5 minutes)\nIf 5<x<=12, then it is train A. (7 minutes)\nIf 12<x<= 24, then it is train A. (12 minutes)\nIf 24<x<= 25, then it is train B. (1 minute)\nIf 25<x<= 45, then it is train B. (20 minutes)\nIf 45<x<=48, then it is train A. (3 minutes)\nIf 48<x<=60, then it is train A. (12 minutes)\n\nWe add it up to get that for 34 of the minutes, he gets on A, and that for of the 26 minutes he gets on B. There are 60 minutes in an hour, so the probability is 34/60, which reduces to 17/30.
772558
Now there's some strange questions. I'll help as best I can. I hope I've understood the questions properly.\n\nQuestion 1) Bob will always win, assuming they play perfectly.\nIf Ann takes 1 matchstick, Bob should take 2. That leaves 3 left. Now whether Ann takes 1 or 2 from the remaining 3, Bob is left with 1 or 2, so he can take what's left and wins.\nIf Ann takes 2 matchsticks,  Bob should take 1. That also leaves 3 left, so again regardless of how many Ann takes from the 3 remaining ones, Bob can take what's left and win again.\n\nQuestion 2) The answer is 5.52pm.\nLets say the slow train moves at speed X. That means the fast train moves at speed 2.75X. This is because the fast one moves 2.75 times faster than the slow one (since it travels the same distance in 8 hours compared to the slow time of 22 hours, so it must be going 22/8 times faster).\nIn the time taken for the trains to meet, between them they have travelled the full distance. Therefore you can add their speeds together to calculate the relative approaching speed of the trains, which would be 2.75X + X = 3.75X.\nNow, the slow train travels at speed X and takes 22 hours to go the same distance. Therefore we can say that the time taken for the two trains to meet is 22X/3.75X, or 22/3.75, which is 5.8666.\nTo convert 0.8666 of an hour to minutes is simple - just multiply by 60. This gives 52.\n\nSo the total time taken is 5 hours 52 mins. \n\nTo put it another way:\nSpeed of train 1 = 2.75 times faster than train 2. So the speeds of the two trains together = 3.75 times faster than the slow train.\nThe slow train takes 22 hours to go the distance. Therefore the two trains together take 22/3.75 to do the same distance, which is 5.8666.\n\nI hope this helps :)
1172962
the train cuz u might still be alive and be dragged with the train but the building as soon as u hit the floor ur a goner
160887
The insect is inside the bus, and so is moving 5 mph relative to the bus (that is what you meant right?) so:\n\na. 5 mph\nb. 55 mph, since the insect is moving 5 mph faster than the bus\nc. makes no sense since they are moving relative to each other
913200
Both their accelerations will be the same and equal to the acceleration due to gravity, g=9.81 m/s/s...This is coz the only force acting on them is the force due to gravity