Convert the melting point of iron metal to degrees Celsius.?
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That depends on the alloy of steel you are talking about. The term alloy is almost always used incorrectly these days, especially amongst bicyclists. They use the term to mean aluminum. What the term alloy really means is a mixture of metals, any kind of metals. Almost all metal used today is a mixture and therefore an alloy.\n\nMost steel has other metals added to tune its properties, like strength, corrosion resistance, or ease of fabrication. Steel is just the element iron that has been processed to control the amount of carbon. Iron, out of the ground, melts at around 1510 degrees C (2750°F). Steel often melts at around 1370 degrees C (2500°F).
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Gold's freezing point is 1064.58 degrees celsius.\n(This is the melting point and melting points are the same as freezing points.  Water, for example, melts at 0 degrees celsius but also freezes at 0 degrees celsius.)
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The frezing point (also the melting point) of Vanadium is 1910 degrees C (3470 degrees F).
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To convert Fahrenheit temperatures into Celsius:\nBegin by subtracting 32 from the Fahrenheit number. \nDivide the answer by 9. \nThen multiply that answer by 5.
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The temperature where the substance turns from a solid to a liquid. The melting temperature of ice is 31.9999 degrees Fahrenheit.\n\nThe melting point for gold would be much higher as it must be very hot for gold to turn to a liquid.
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Melting point 933.47 K\n(660.32 °C, 1220.58 °F)\n\nBoiling point 2792 K\n(2519 °C, 4566 °F)
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there are different tempuratures to melt gold and copper,for instance gold is a softer metal and it will melt before the copper.say the temp for melting gold is 1000 degrees,and copper is 1200 degrees,the gold will melt first.
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double it and add 30 to the celsius temp and you get an rough farenheit temp-for example 30Celsius x 2=60+30=90Farenheit
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Melting point 1811 K\n(1538 °C, 2800 °F)
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Q = m.s.ΔT\nHeat loss by the copper = heat gained by the metal.\nCopper (heat loss) = 200.0g x 0.38J/g.ºC x (195.5ºC-228.4ºC) = -2500.4J\ndivide the heat by the mass and ΔT of the metal to get the specific heat of the metal:\n2500.4J/(65.0g x (195.5ºC-18.3ºC)) = 0.2171 = 0.21 J/g.ºC (correct SF)
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You should find that under the ASTM Manual for steel. Your engineering department should have a copy, otherwise try finding it on line.
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Depends on the temperature. At a guess at melting point not that different from solid aluminum.
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d iron it is heated very hot and it melt
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To convert Fahrenheit to Celsius, subtract 32 degrees and divide by 1.8. To convert Celsius to Fahrenheit, multiply by 1.8 and add 32 degrees
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1) Calculate the heat needed to melt 100 grams of ice completely: \nMass of ice * Heat of Fusion\n100g * 333J/g = 33300 J\n\n2) Calculate the cooling we can obtain \nMass of water * specific heat of water * temperature loss\n180g * 4.2 J/g K * dT = 33300 J => dT = 44.0 degrees\n\nConclusion we need only to melt 100g * 30/44 = 68.1 gram of ice to cool down the water to zero degree. 31.9 grams of ice remains.\n\n3) 1) Calculate the heat needed to melt 50 grams of ice completely: \nMass of ice * Heat of Fusion\n50g * 333J/g = 16650 J\n\n4) Calculate the cooling we can obtain \nMass of water * specific heat of water * temperature loss\n180g * 4.2 J/g K * dT = 16650 J => dT = 22.0 degrees\n\n5) Calculate the average temperature of the water.\nAfter melting of the ice we have 50 g of water at 0C and 180 g of water at 30-22=8C. This average out to 6.3C
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100 degrees celcius\n212 degrees Fahrenheit
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Melting point -11°C (262.15 K) \nBoiling point 150.2°C (423.35 K)