what is the graph of x=y2 ( i mean x equals y raised to power two) called?
608711
i think it's a parabola.. im not sure. u should try plotting it on a graph.. substitute  the x and y values and see what form comes out..
162293
On both equations, you have x^ but don't say what x was raised to. I'm assuming that it is x^2. Is this correct?
985205
y = 2x^2 - 5    is a graph of parabola.\n\n-------------------------------------\n\nWhen x = # ,  this is an equation of a VERTICAL line.\n\nSimilarly,  when "x" is squared, "y" is to the power of one,\nthe parabola is a VERTICAL parabola. \n\nSo, now, we have established that the above equation is a VERTICAL parabola.\n\n-----------------------------------------\n\nA VERTICAL parabola is symmetric with respect to the y-axis, regardless of which direction the parabola opens (up or down).\n\n-----------------------------------------\n\nANSWER: This parabolic equation is symmetric with respect to the y-axis.
548747
(x,y) (-x,y)is a refelction over y axis. I think...
476794
This graph helps us to show what happens when a quantity y is inversely proportional to another quantity x.\n\nAgain, it shows us that a computer algorithm implementing y=(1/x) for the order of efficiency of the algorithm..
918264
IF you mean like an ordered pair it is a point on a graph.  An example is:  (x,y)  so you can have (3,5)  or (-7,-88)  Otherwise I'm not sure what you're talking about.
637800
Try this website www.algebrahelp.com/calculators/equation/3dgraphing/pg2.htm
766536
(x^4-y^4)\n=(x^2+y^2)(x^2-y^2)\n=(x^2+y^2)(x+y)(x-y)\n\n2.(x^4-1)\n=(x^2+1)(x^2-1)\n=(x^2+1)(x+1)(x-1)
432398
y = -1/2 sin·­­­¹ pi x\nTo graph this, it is easier to rearrange to make x the subject, then turn the graph paper on its side and plot x as a function of y, just remember that y is now positive going left and x is positive going up.\n-2y = sin·­­­¹ pi x\nsin (-2y) = pi x\n1/pi sin (-2y) = x\n\nnow sin (-2y) = sin 2y   (check your trig properties)\n\nso we want to graph\nx = 1/pi sin 2y\n\nnow for the graph  y = a sin bx\nthe amplitude is a and the period is 2pi/b\nso the amplitude is 1/pi\nthe period is 2\n\nPlot your sin function along the y axis. Then turn the paper the right way up. Remember that to be a function, it can only have one value of y for each value of x, you only want a single half S shape, going from y = -.5 to .5, this way the graphs remains a 1 to 1 function.
958831
Draw the graph of y = x^3\nThe (x-1) part shifts the graph to the right by 1.\nThe +4 part shifts the graph up by 4.\n(0,0) lies on y = x^3\n(1,4) lies on y = (x-1)^3 + 4\nNote that the x-coordinate increased by 1 and the y-coordinate increased by 4.
891649
(y-3x) cannot be graphed because there is no equality...\nyou could graph y=3x... that would be a line that passes through (0,0) with a slope of 3
606971
Do they have the same slope?  If so:\n\n(Y2-B2)/X2 = (Y1-B1)/X1\n\nThis implies that they will either never intersect or be equal to each other. (ie, if B2=B1, they are the same, if B2=/=B1 they will never be equal.)\n\nOK, so you have updated the question.  Now if you multiply these two equations together you will notice that x will be 2nd degree and y will be second degree (ie, both will have a 2 as their largest exponent.)  Therefore, the graph will be one of a conic section.  Either and ellipse, a circle, a hyperbola, or a parabola depending upon the scalars a,b,c and A,B,C.  If you don't know how to tell when a conic section is a circle, ellipse, hyperbola, etc. then ask another question, or google it.  Hope this helps.
314146
Let y = arccosine x\nthen x = cos y\nfirst put a value for y and get the corresponding value of x\nDraw the graph
897937
Please click on and read from the following:\n\nhttp://www.answers.com/binomial%20theorem\n\nSpecifically:\n\n\n"In algebra, a formula for expansion of the binomial (x + y) raised to any positive integer power. A simple case is the expansion of (x + y)2, which is x2 + 2xy + y2. In general, the expression (x + y)n expands to the sum of (n + 1)terms in which the power of x decreases from n to 0 while the power of y increases from 0 to n in successive terms. The terms can be represented in factorial notation by the expression [n!/((n − r)!r!)]xn − ryr in which r takes on integer values from 0 to n."
201432
x=2 and y =2,\n\n2^2=2^2 and 2*2 = 2 + 2 =4
539943
x+y........e=mc2..........2+2
949784
y= (x^2 - 1)^2\nx^2-1=+/-√y\nx^2=1+/-√y\nx=+/-√(1+/-√y)