balance equation with 4:1 ratio - 4 copper : 1 silver?
612968
I hope you mean this...\n\n8Cu + 2AgNO3 -> 2Ag + CU(NO3)2 + 7Cu
825401
First of all I assume  Na2Co3 should be Na2CO3.\n\nFe(CO)5 + 4NaOH = Na2Fe(CO)4 + Na2CO3+ 2H2O\n\nFirst, balance out the metals (Na and Fe) then C, which was already balanced. Then I chose to balance out H and which automatically balanced out O.
342141
ok well, the equation is balanced so you need equal moles of Ag and Cl to make the products. They give you the concentration and volume of Ag, so you can find the amount of moles by multiplying 0.104mol/L * 0.0272L = 0.0028288 mols of Ag. so 0.0028288 mols of Cl were there originally. and you have the volume of water, so you divide moles by volume and you get the concentration. 0.0028288 mols/0.025L = 0.113152 M. \n\nanother way to do it is the easy way, use c1v1 = c2v2. you have c1 = 0.104M, v1 = 27.2mL, v2 = 25mL, so you can find c2. you dont have to worry about units in this case so its easier. \n\nhope this helped. let me know if u need more help. laterz
748872
Cu2+ (aq)  +  Zn (s) -->  Cu (s) + Zn2+ (aq)
738281
I have forgotten all the chemical formulas & whatnot... but I'm going to do this assuming that I'm right for the following:\n\n(note that if i get any of these wrong you'll have to make appropriate changes, this is just to show you HOW to do this)\nCu = Copper\nS = Sulfur\nCuS2 = Copper Sulfide\n\nSo first step is to balance the equation\n\nCu + 2S -> CuS2\n\nso then you can set up a problem like this:\n\n0.90 mol Cu * 1 mol CuS2  = # mol copper sulfide yielded\n(this is because there was 1 mole of Copper in 1 mole of CuS2.. so if CuS2 is not the correct formula change the "1 mol CuS2" accordinginly)\n\n\nThen add up the # of grams in 1 mol of copper sulfide\n\ndo that by taking the # of grams in 1 mol of copper + the number of grams in 2 mol of sulfur (again, this is just assuming that copper sulfide IS CuS2).  Once you've gotten that figure, multiply it by the number found from the earlier problem (# mol copper sulfide yielded).  This gives you the amount of grams.  To change this number to kilograms, divide it by 1000.
106704
If you go to a search engine, like google, you can just type in "balancing chemical equations" and it will give you tons of info. We were doing this in chemistry a few weeks ago, and thats how I found alot of help online. \n\nGood luck!!
5345
The common ratio is 1/4 or .25
1079619
First of all, we can estimate what the answer is going to be.  About half of all silver is 1 dalton too light, that means that the other half must be 1 dalton too heavy.  So we are looking for an answer of around 108.9.  \n\n(.5184)(106.9051) + (1-.5184)x = 107.9\n\nAnd you solve for X, which I get to be 109.0, which is what we predicted.
792118
As copper is more reactive than silver it will give up its two electrons to silver ions so when is really happening is:-\n\n2Ag+  + Cu → Cu++ + 2Ag\n\n(The nitrate ions (NO3‾) are passive)
821643
Copper is more reactive than silver, hence displacement of silver occurs.\nCu (s) + 2AgNO3 (aq) --> 2Ag (s) + Cu(NO3)2 (aq)\n\nSum of the coefficients? 6...\n\nHope this helps :)
283215
[Cu(NH3)4]SO4*H2O (s) + 2HCl(aq) --->\n\nCu(NH3)4 +2 (aq) + H2SO4(aq) + H2O(l) + 2Cl-(aq)
880619
Let x be the amount (in grams) of the 25% copper alloy, and\nlet y be the amount of the 50% copper alloy.\nThen,\n.25x + .50y = .45(1000) and\nx + y = 1000.\n\nSo, y = 1000-x \nthen\n.25x + .50y = .45(1000)\n.25x + .50(1000-x)=450\n.25x + 500 - .50x = 450\n(.25-.50)x +500 = 450\n-.25x = -50 (multiply both sides by -1)\n.25x = 50 (multiply both sides by 4)\nx=200, then substitute x in to the x + y = 1000 equation\n200 + y = 1000\nso y = 800.  and make sure to label each grams of the appropriate % copper alloy.
483467
First rewrite the equation such that it becomes \n4w/1 - gu/5 = u/4\n\nThen, change the denominator to 20. it'll become \n80w - 4gu = 5u\n\nShift all the u terms over the left and leave the rest on the right.\n-4gu-5u = -80w\n\nchange the signs by taking out the minus sign\n- (4gu + 5u) = -(80w)\n4gu + 5u = 80w\n\ntake out the common u term\nu (4g + 5)= 80w\n\ndivide 80w by 4g+5 and you will get\nu = 80w/ 4g + 5\n\nand that's the answer! hope this helps.\n\n* note: when making smth the subject of formula, the subject itself cannot appear in formula. e.g it should be u = 80w/ 4g + 5 NOT u= 80wg-4gu (or smth to this extent) as the u term  appears in the formula.
867817
25cm3 of a 4M solution of CuSO4 contains 25/1000 x 4 M CuSO4 = 0.1M\n\n! mole of CuSO4 weighs 160g (Cu = 64 + S=32  + O4 = 64)\n\nSo   0.1 Mole weighs  16g. This is how much anhydrous solid is needed. \nHowever copper sulphate usually comes as crystals and 1 mole of this weighs 250g ( + 5H20 = 90) so to make a 0.1 molar solution from crystals you need 25g CuSO4. 5H2O
734862
HgO ------> Hg + O2 at about 400 C\n\nMg + CuCl2 ---------->  MgCl2 + Cu(solid)\n\nMg, being higly electropositive than Cu, replaces Cu.
148175
The correct balanced equation is:\n2ZnS + 3O2 --> 2ZnO + 2SO2\nThis is BALANCED\nMr chemistry teacher, you didnt balance your equation,...and i'm in the ninth grade
320739
Based on what you have given us, there are no coefficients in front of any of the compounds/elements, so the ratio would be 1:1:1.\n\nI'm guessing that you didn't provide all the information need, though.\n\nGenerally these questions give you a reaction that you must first balance to determine the mole ratios.