Find an equation for the line with an undefined slope and passing through the point (-9, -4)?
610140
x=-9 because that means all xs on that line equal -9, making it a vertical line which means it is undefined.
734729
problem1\n\nsince you have said P (4,-5) is a point on the function, then the corresponding point will be (4,-5) .. :)\n\nproblem2\n\nfor a line having y intercept 3 will have following form\n\ny =mx+3\n\nwhere m is the slope of the line. Now it is said to be perpendicular to y =2/3x-4. So slope for this is 2/3\n\nsince slopes of two lines perpendicular to each other if multiplied yields -1\n\nm X 2/3 = -1\n\nor m = -3/2\n\nso the required line will be\n\ny = -3/2 x+3\n\nproblem3\n\nf(x) = 1/x^2 -2x-8\n\nto make the f(x0<0, let us try with some arbitary values of x\n\nif x = 1, f(x) = -9\nif x=2, f(x) = -11.75\nif x = 0, f(x) = infinite (due to 1/x^2)\nif x = -1, f(x) = -5\nif x= -2, f(x)= -3.75\nif x=-3, f(x) = -1.88889\nif x=-4, f(x) = 0.0625\n\nHope this helps
194847
Im not gonna give u the answer, coz u wont learn otherwise, but i can tell you how to solve it...\n\nWell, remember that the standard equation for a line is \n\ny = mx + c\n\nwhere m is the slope of the line... Now, there is a relation between the slopes of two lines if they are parallel, look it up yourself...\n\nSo u have the slope of the line whose equation u need to find... U also have a point thru which it passes... Another representation of the equation of a line is...\n\ny - y1 = m(x - x1)\n\nwhere x,y are the variables for the eqn, m is the slope of the line, and x1, y1 are the (x,y) co-ordinates of a point thru which the line passes...\n\nYouve got all the stuff, throw it in, and wolla...
729746
you solved it right, since the line BC never goes up/down(the y-coordinate never changed, graph it and you'll see) the slope is 0. and 0/7=0, so you're right.\nit would be impossible if you got 7/0, because you can't divide by 0.
858135
m = (9-(-1))/(-2-3) = 10/-5 = -2\n\n-1 = -2(3) + b\nb = -1 + 6\nb = 5\n\n\nf(x)= -2x + 5\n\n\nYou got the slope sign reversed.  Be careful about that.  Otherwise, it's correct!
498526
The value of y at the y-intercept (b), which is the point at which the line intersects the y-axis, is -9, and the slope (m) is -3. Following, the y=mx+b or slope-intercept form, the equation is y=-3x-9.
730934
First you have to find the equation of the line that contains these two points (9,1) and (5,5)\nI believe the easiest way to do that is to use slope and y-intercept form (y=mx+b) m= slope and b= y-intercept\n\nto find slope, m = rise/run\nrise = -4\nrun = 4\nrise / run = -1\n\nTo find y-intercept plug in a coordinate pair and use are found slope.( i used 5,5)\ny=mx+b  x= 5 y=5 m=-1 b =?\n5=(-1)(5) +b\n10 = b\n\nSo this is our equation of the two points\ny=-x +10 \n\nNow we can use this equation to find whether  (10,0) is on  the line: Substitute (10,0) and see if the equation is still valid\n\n 0 = (-1)(10) + 10\n 0 = 0 Yes (10,0) is on the same line as the other points
896619
slope is 2,  y intercept is  - 10
610276
points (3,2) and (-3,-10) belong to f and the equation for f is\ny-y1=[(y2-y1)/(x2-x1)]*[x-x1]\nwhere y1=2,y2=-10,x1=3,x2=-3\n\ny-2=[(-10-2)/(-3-3)]*[x-3]\n\ny-2=[-12/-6]{x-3]\n\ny-2=2[x-3]\n\ny=2+2x-6\n\ny=2x-4\n\nso the slope of f is 2\n\nsince g is perpendicular to f the slope is -1/2\n\nand equation would be\n\ny-9=-1/2(x+4)\n\ny=9-[1/2]x-2\n\ny=-(1/2)x+7\n\nso g(x)=-(1/2)+7
134706
I'd plot the points and figure out the slope (vertical change/horizontal change).  In this case, it would be -1 [2 / -2].  Then trace out the line to see at what point it crosses the Y axis.  In this case, it would be -2.  Then plus those numbers in the the equation "Y = (slope)X + (intersection of Y axis)"  So, if I'm not mistaken, the solution should be "Y = -X - 2".
626863
To find slope you start by choosing two points Ex: (1,2) and (5,6). You us the equation m(slope)=(y2-y1)/(x2-x1) Ex:(6-2)/(5-1)=4/4=1 The slope is one. To find the x-intercept you plug in Y=0 (zero) into the equation, and to find the y-intercept you plug in X=0 into the equation.
1161836
One way to write the equation of a line is\ny - y1 = m(x - x1)\nwhere m is the slope and (x1, y1) is a point on the line.\n\nGiven your information,\ny - 4 = -2(x - 1)\nThat is the point-slope form of the line.  This can be changed to slope-intercept form:\ny - 4 = -2x + 2\ny = 2x + 6
91103
x=-3 is the equation for the line.\n\ny=mx+b where m is slope and b is y-intercept.\n\nm=change in y/change in x= [(-3)-1]/[(-3)-(-3)]\nm=-4/0\nWhen you divide by zero the answer is undefined, so slope is undefined.\n\nOnly vertical lines have undefined slopes, so the equation for the line is x=-3. This means that no matter what value you pick for y, x will be equal to -3.
843812
slope= 1   y-int=0\nThis is an equation. You can cancel the -7 and you'll have y=x. If you remember from the equation y=mx+b, then you'll see that here your m=1 and your b=0
850699
y = mx + b  --> slope-intercept form\ny = 3x + b\nsubstituting point(4, 9)\n9 = 3(4) + b\n9 = 12 + b\nb = -3\n\ntherefore the equation is given by\ny = 3x - 3
736765
slope=1\ny=x+b\n-3=3+b\nb=-6\ny=x-6
323843
If every point on the line has the same x coordinate, the line would be vertical. The formula for slope is rise/run. The "run" part would be the change in the x coordinates. Since there is no change, "run"=0. Dividing by zero is undefined, so the line's slope is undefined (not zero). Only vertical lines have an undefined slope.\n\nAlso, try plotting points. Choose any x value, and you will see that if every point has that same value, the line will be vertical regardless of the y value.\n\nAlso notice and vertical lines are not functions as they do not pass the vertical line test.