How to solve an equation divide by 0?
601672
Okay, Lets just assume that you are dividing something by (n-3). Whether you are right or not doesn't matter, since you believe you are right, and I'm too lazy to check it out on my own.\n\nWhen n=3, your solution will be undefined. If you were trying to graph this, there would be an open circle around n=3. It would not - *NOT* - be infinite.\n\nNow, if you feel you are SUPPOSED to get an answer for every number you plug in, then I would go back and re-check your algebra, because if you *KNOW* you are supposed to get an answer, then something went awry with the algebra.
848441
If you are solving for t and if the problem is supposed to be\n 0=16*(t^2)+80t, then t = 0 and/or -5. If the problem is supposed to be 0=(16t)^2+80t, then t = 0 and/or -5/16. To solve the problem, you just factor out a t, which implies that t is equal to zero, then set the rest of it equal to zero and solve for t.
814311
The issue lies in the fact that the original equation is 0=0.\n\nThen, if you put in any value for x, you are dividing by 0 which as we all know, is a "no no."
911592
Factorize!\n4x (x^2-9) = 0\n4x (x+3) (x-3)\n\nyour solution is \nX = 0\nx= -3\nx= 3
749096
Solve the inequality the same way you would any other equation. Just remember that when dividing or multiplying by a negative number you have to flip the inequality.
784758
x^2+x+1=0\nx^2+2(1/2)x+1=0\nX^2+2(1/2)x+(1/2)^2+1-(1/2)^2=0\n(x+1/2)^2+3/4=0\n(x+1/2)^2=-3/4\nx=-1/2+/-√(3/4) i=-1/2+/-√3 * i/2
1137788
Nope, 0/0 could be 1 but it could also be anything else.   Division is the opposite of multiplication and 0 times anything at all, even infinity, is still zero.
1178709
y'=2x-2\n\nif =0 then:\n0=2x-2\n2x=2\nx=1
831674
1. replace x with -3, calculate and see if you get 0\n2. divide by (x+3) and solve the remaining quadratic equation
786976
16x^2 + 12x\n\nIn order to solve, you would need an equal sign.  I think maybe you mean finding the zeros?\n\nFirst we would need to factor it.  We could pull an x and a 4 out of each.\n\n4x(4x + 3)\n\nWe get two factors.\n4x\n4x + 3\n\nThen we set each factor equal to 0 to find the zeros of the equation.\n\n4x = 0\nx = 0\n\n4x + 3 = 0\n4x = -3\nx = -3/4\n\nOur zeros are 0 and -3/4.\n\nI hope I helped. :)
189562
This is not simply a quirk of our usual number system: in any number system that satisfies certain basic properties such as distributivity and associativity, 0 multiplied by anything will give 0. So if you start with any non-zero number x, there cannot be any number which when multiplied by 0 gives you x, so there can be no answer to the question "what is x divided by 0". Mathematicians say that "division by 0 is undefined", meaning there is no way to define an answer to the question in any reasonable or consistent manner.
882621
My old math teacher showed me this.\n\nSince A=B, then A-B=0, and you can't divide by 0
113980
Use a calculator - numerator divided by denominator will give you the answer.
1148035
Division, if you do not know how to divide can be done easily.\n\nTake the problem 32 divided by 8.  You would divide this out the long way.  The easiest way might be to subtract 8 until you get to zero.   You notice it take you 4 times of subtracting 8 to get to zero.  So your answer would be 4.
508570
First you factor the like terms\np^2(2p+1)-49(2p+1)=0\nThen combine like terms\n(p^2-49)(2p+1)=0\nthen set each one equal to zero and solve\np=7, and negative 7     p=-1/2
789094
divide by x^2\n6(x^2+(1/x^2))+ (x)+(1/x)+10 = 0\nput x+(1/x)= t\n\nthen solve for t and then solve for x\nyou'll find that there are no roots.!
1119654
(a+b)(a-b)=b(a-b),\nhere you want divide both sides by a-b,\nbut this is not accepted,\nbecause a-b=0 (as you have assumed that a=b)\nDivision by 0 is not defined.\nDividing both sides by 0 is your mistake.