whats the square route of: 1in; 6.6mm; 15yds?
597652
The square root of 1 is 1.\nsqrt(6.6) = 2.569\nsqrt(15) = 3.873
581862
6" is perfect.7" is OK. anything larger OUCH.\n2 finger thick is perfect. anything thicker OUCH>
710674
I hope by width you mean height.  If so then the answer is πr^2 * h\nso π15^2 * 60 \n\n13500π\n or \naprox.  42411.5
292640
1 in(2.54cm/1 in)(10 mm/1 cm)\n= 25.4 mm or 2.54 x 10^1 mm
398235
six inches\n\n\n\n\nLOL
855200
that sent me round in circles.\nhere have a link c if u find what u need.\n:)
527703
9 x 19mm. Capacity 15 + 1
602189
u can go www.webmath.com, its pretty good. \nu can also ask on answers. \ni.e. 1cm = 10mm\n1m = 100cm or 1m = 1000mm\n1m = 3ft\n1ft = 12in \netc... hope it helps!
726378
LW = A\n15W = 200\nw = 200/15 = 40/3\n\nThe diagonal will, along with one width leg and one length leg, form a right triangle.  Using the Pythagorean theorem, a^2 + b^2 = c^2, we can figure out the length of the diagonal:\n(15)^2 + (40/3)^2 = c^2\n225 + 8000/9 = c^2\n10025/9 = c^2\nc = (sqrt)(10025/9) = (sqrt 10025)/3 = 5(sqrt 401)/3
559136
SOMEANTHA is correct\n\nbut if you want a quickie answer for bigger numbers\nhere is a website that will do it for you\n\nhttp://www.onlineconversion.com/length_common.htm
929508
inner surface area of a conduit of inner diameter d and length l = pi*d*h\nherd d = 10mm= 0.01 m\nand h = 5m\nso inner surface area = pi*0.01*5\n= 0.157  m squared
976772
15 / 3.5 = 4 with remainder of 1\n\nTherefore the leftover piece is 1 meter long
690230
(160 x .065) + 160\n\nor\n\n160 x 1.065
647274
1/6 coz there r 6 sides on  a die  i dunno
100397
Exactly 14/16 of an inch
1124183
Hmmm. Six-inchers are pretty common. Buy them at well-equipped hardware stores or buy from machinist supply houses like McMaster-Carr. I guess you could saw an inch off.
732742
awnser :length =18feet\n\np=2L+2W\n60=2L+24\n-24     -24\n36=2L\ndivide by 2\n18=L