i cant remember: 4x+2y=8?
610726
there is a solution, all x,y that satisfy this equation:\ny = 4 - 2x\n\nwhich is a straight line with intercepts (0,4) & (2,0)\n\nIt has an infinite amount of solutions. To be able to solve for actual numbers, you need as many equations as you have variables.
409430
12x - 16y = 8\n9x - 12y = 6\n\n12x - 16y = 8\n-16y = -12x + 8\ny = (3/4)x - (1/2)\n\n9x - 12y = 6\n-12y = -9x + 6\ny = (3/4)x - (1/2)\n\nANS : 3.) (t,(3/4)t - (1/2))\n\nThats if i understand you correctly.
903764
2x - 8y = 3\nadd 8y to both sides and subtract 3 from both sides\n2x - 3 = 8y\ndivide both sides by 8\n(x/4) - (3/8) = y\n\nANSWER\n(x/4) - (3/8) = y
681236
Multiply each term in the first () by each term in the second ():\n\n2x times 2x = 4x^2\n2x times 1 = 2x\n-3 times 2x = -6x\n-3 times 1 = -3\n\nThen combine 2x and -6x\nAnswer: 4x^2 - 4x - 3
158233
X ?\n-8(0) + 4y = 48\n4y = 48\ny = 48/4\ny = 12\n\nY ?\n-8x + 4(0) = 48\n-8x = 48\nx = 48/-8\nx = -6\n\nSo: X int. = -6  y int. = 12
957836
4x+(-5y)+(-6x)+3y\n4x+(-6x)+(-5y)+3y\n=-2x-2y
123571
add the two equations on left hand side and right hand side\n\n3x - y + 5x + y = 4 + 4\n\n8x = 8\n\nx = 1\n\nput this into the first equation\n3(1) - y = 4\n-y = 4 - 3 = 1\ny = -1\n\nHence x= 1 y = -1\nconfirm it by checking the 2nd equation \n5(1) + (-1) = 4 \nCORRECT!
752254
Well, let's check if y=4.\nJust replace y with 4\n4(4) + 2(4) = 24\n16 + 8 = 24\n24 = 24 \nThis is equation is true, so you are correct.
708981
(4/x-8/y)/(24/xy)\n=(4y-8x/xy) * xy/24\n= 4(y-2x)/xy * xy/24\n=(y-2x)/6
940318
General principle:  if you have an equation (something with an equals sign in it), you can do anything you want as long as it's mathematically valid and you do it to both sides.  Do that, and you'll still have an equation.\n\n4y - 2x = 8\n\n4y - 2x + 2x = 8 + 2x\n\n4y = 8 + 2x because the -2x and +2x add to 0.\n\n4y = 2x + 8 because addition is commutative.  It doesn't matter what order you add them in.\n\nAt this point, we have 4y on one side of the equation and we're trying to get y by itself.  Obviously, we need to get rid of the 4.  We're currently multiplying by the 4, so we get rid of it by dividing by 4.\n\n4y/4 = (2x + 8)/4\n\ny = 2x/4 + 8/4 by the Distributive Property\n\ny = (1/2)x + 2\n\nSo, to write it as a function,\n\nf(x) = (1/2)x + 2
930601
put -2y=5-3x call it equation {1}\ncall 4x-5y=86 {2}\n\nmultiply all of the terms i {1} by 5\nmultiply all ot the terms in {2) by 2\nthis gives -10y=25-15x {3} &  8x-10y=172 {4}\nyou've got -10y in terms of x in {3}, so just put that into {4}  8x+25-15x=172, -7x=157, \nx = -172/7 sub in to {1} to get y \nman that was ablast from the past, haven't done that for years.
758567
2(2x-4)= x+4\n4x-8 = x+4\n4x-x = 8+4\n3x = 12\nx=4\n\n&\n\n4(x+3)+3= 5(x-4) + 5\n4x+12+3 = 5x-20+5\n4x+15 = 5x-15\n4x-5x = -15-15\n-x= -30\nx = 30\n\n&\n\nx+2= 4(5x-2)\nx+2 = 20x-8\n2+8=20x-x\n10 = 19x\n19x= 10\nx=10/19\n\n&\n\n21-3x = 4x+7\n21-7 = 4x+3x\n14=7x\n7x = 14\nx=14/7\nx=2
835686
4x^2 + 3y^2 = 4\n8x x' + 6y y' = 0\n8 x '' + 6 y'' = 0\n6y'' = -8x ''\ny '' = -4x / 3
861681
subtract 1st equation from the second:\n  8y^2=32\nso y^2=4, and y = +/- 2\n\nplug back into 1st equation:\n4x^2+4=4\n\n4x^2=0\nx=0
95804
You know that\n              1)3x+4y=12y\n              2)-2x+10=12y\nSo you can substitute 3x+4y for 12y in equation 2. Hence:\n              3)3x+4y=-2x+10\n                   5x=10-4y\n                    x=2-4y/5\nSubstitute this value for x into equation 1 and it becomes:\n              1)8y/5+6=12y\n                     y=15/26\nPlug this back into 3 and you get\n              3)x=2-(4/5)*(15/26)\n                x=20/13\nTherefore the answer to the system is (x,y)=(20/13,15/26)
160474
I supose u mean 1/4(4x-8)+3x=0\nThe answer is then very simple:\n\nx=1/2\nCheers
271990
x^2-2xy+4xz-8yz=\n(x^2-2xy) + (4xz-8yz)=\nx(x-2y) +4z(x-2y)=\n(x-2y)(x+4z)