explain the nature of servo system damping.?
594945
Dashpots are often used to dampen a servo system.  They provide a resistance proportional to thrust that can avoid hunting.  The effect can be adjusted, however for large-scale production, it may be possible to find a suitable adjustment on a test stand and to provide fixed orifices for production models.
869627
http://en.wikipedia.org/wiki/Servomechanism
790328
A damper restricts the flow, and can be adjusted to let more through or less through.\n\nA valve will be opened or closed.\n\nThink of it in the same fashion as in an air conditioning system
44400
A control system is a device or set of devices that manage the behavior of other devices.A control system is an interconnection of components connected or related in such a manner as to command, direct, or regulate itself or another system.\n\nThere are two common types of controllers, with many variations and combinations: logic controls, and feedback or linear controls. There is also fuzzy logic, which attempts to combine the easy design of logic with the real-world utility of feedback controls.
487247
I believe you are talking about system type number?\n\nIt is the number of integrators (1/s) in the plant transfer function.\n\neg: the number of "s=0" roots in the denominator\n\nKnowing the system type, you can then easily calculate steady state error in the standard form closed-loop system for step, ramp, and parabolic inputs.
268125
just investigate for example ODE y"=-y and then add to the left part increasingly small non-linearity +c*y^2 and find solution of the first order of c - you will see how different modes interact with each other.
421929
This is a basic form of feed-back controller.  You create an "error" signal, based on the difference between a desired state, and a measured state.  In your example, this would be the distance the joint is from the target position.\n\nYou apply a gain to this error signal, to provide the driver signal to the actuator.  In the case of PD, two gains; one to the Difference (the error) and one to the change in the error, since the last measurement/control cycle.\n\nThe gains are not dimensionless, and in your example, assuming voltage controlled actuators, the dimensions of Gp are volts/meter.  The dimensions of Gd are volt seconds/meter.\n\nok?  For more, see the reference source below.
823386
Hi Alan the 1st!\nWe neglect the central aperture in CD, then inertia momentum is I=m*r^2/2 for any homogeneous disk, m=0.017kg, r=0.06m. Torq T=I*w’, w’ is angular acceleration, while w=w’*t, w=22 rad/s, t=0.88s, thus T=m*r^2*(w/t)/2, - plug in the proper numbers, be a good boy!
120526
Critically damped and overdamped oscillators have no overshoot and no oscillation; therefore no resonance.
137603
Consider  one small part of the dancing string:\nelastic energy <==> kinetic energy.\nThe sum of both is mechanical energy.\nIt is supposed to be constant.\n\nOnly the friction of the air damps the oscillations.\nMechanical energy ==> (friction) heat\nThat's all foulks!
115349
By definition a servo system includes feedback a Stepper motor however simply recieves a signal from a conroler and attampts to move to the proper postion. There is no feed back to determine weather this happened or not.
1047731
Assume dc/dz is constant, n(t=T)=-DA(dc/dz) T\nBut in reality dc/dz often changes.  Normally dc/dz should decrease with time.  If it is a close system, it will reach the equilibrium state.
734225
i just learned this in class... \nafter you enter your mass matix M,\nyour Dampening Matrix C\nand your Stiffness Matrix K\nyou take [K] - lamda [M]= (b) \nyou can type \n[Evals]=eigs(new)\nThese will also be the square of your natural frequencies.\nyour mode shapes are the eigvectors! fyi
709745
If I understand what you are asking, then what we do is that we find the equilibrium points for the PDEs and then we check for their stability.  We check whether they are asymptotically stable, unstable, or a saddle point (stable sometimes and unstable other times).\n\nStability can be checked by looking at the behavior of the differential equation (or the system of differential equations) in the neighborhood of the equilibrium point.\n\nOther than that, I am not sure what you mean.
615645
search \nMechatronics on google and you will get a lot of resources \nfew links\nwww.PMDcorp.com      High-precision single or multi-axis Includes user-friendly software\nStepper motor control?\nwww.teknic.com      Discussion of motion & I/O control: low-cost, reliable, easy expansion
312735
Try a damping circuit.
119821
With a sliding mass on a level surface and subject to kinetic friction, the friction force is constant in magnitude and opposite the motion direction.  The force magnitude is the normal force (in this case = weight) times the coefficient of friction.  With constant friction force, the power required to maintain a given velocity is proportional to the velocity.  (Thus if a car were subject to friction but not to air resistance, it would use the same energy per mile regardless of speed.)  When the driving force is removed the sliding mass undergoes a constant deceleration to zero velocity.  A greater mass will have the same deceleration as a lesser one.\nSome structures that have potential vibration problems use friction dampers instead of (or as well as) the more conventional viscous dampers whose retarding force is approximately proportional to speed rather than constant.  Friction dampers have the advantage of removing a constant amplitude of vibration with each oscillation cycle, as compared wih viscous dampers that  approach zero amplitude asymptotically.  Why a constant amplitude decrement?  Energy is proportional to peak amplitude squared (X^2).  With friction damping, d(Energy) therefore d(X^2) is proportional to X, thus d(X) is constant.