how do i solve this fractional equation math problem?
612720
-2 = 1/(1+x)-3/(x-1)\nmultiply both sides by (x^2-1)=(x+1)*(x-1):\n\n-2(x^2-1)= x-1 -3(x+1) \n\nrearrange\n2x^2 - 2x - 6 = 0\ndivide by 2\nx^2 - x -3 =0\napply formula for quadratic equations\nx=(1 +/- sqrt(1+4*3))/2\n = 0.5 +/- sqrt(13)/2\n\n"+/-" means plus or minus (there are two solutions)\n"^2" means squared
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
725272
Take half of the coefficient of the x term, which comes to 7/2.\nSquare that, which comes to 49/4.\n(x + 7/2)^2 = x^2 +7x + 49/4
605867
(x^2)/2 - 3(x^(3/2))/(3/2) + c = (x^2)/2 - 2x^(3/2) + c
972013
2*root(5/7) - 3*root(7/5)\n\nFirst we notice we can distribute the root throughout the fractions, and rewrite our equation\n\n2*(root5 / root7) - 3*(root7 / root5)\n\nTo get rid of the radical denominators, we can multiply through by the denominators. So we multiply through by root5*root7\n\n2*root5*root7*(root5/root7) - 3*root5*root7*(root7/root5)\n\nWe see that the denominators cancel with their respective partners, and the numerators are squared. Thus the roots all dissapear and we are left with:\n\n2*5 - 3*7\n= 10 - 21\n= -11
394036
Try to solve the eqs with quad rule:\na*x^2 + b*x + c=0\nx=(-b +- Sqrt(b^2-4*a*c))/(2*a)\n\nx^2+2x+5=0 => Get two Complex answers, \nso no it can't be factorized.\n\nx^2+4x+5=0 => Get two Complex answers, \nso no it can't be factorized.\n\nx^2+4x+3=(x+3)*(x+1)=0; \nSo, yes, this can be factorized. \nSolutions are x=-3 and x= -1\n\nx^2+2x-3=(x+3)*(x-1)=0;\nSo, yes, this can be factorized. \nSols are x= -3 and x=1
943546
LCM of 2, x+1, x+2 is the product of the terms.  Express everything fractions with the LCM as the denominator.  Then solve.\n\n4(x+2) / 2(x+1)(x+2) + 6(x+1) / 2(x+1)(x+2) = 7(x+1)(x+2) / 2(x+1)(x+2)\n\nThen multiply everything by the denominator (LCM):\n4(x+2) + 6(x+1) = 7(x+1)(x + 2)\n\nMultiply out:\n4x + 8 + 6x + 6 = 7(x+1)(x+2)\n10x + 14 = 7(x+1)(x+2)\n10x + 14 = 7(x² + 3x + 2)\n10x + 14 = 7x² + 21x + 14\nPut it all on one side:\n7x² + 11x = 0\nx(7x + 11) = 0\n\nx = 0\nor\n7x + 11 = 0\n7x = -11\nx = -11/7\n\nSo x = 0 or x = -11/7
817789
I assume that you mean 1/(x+5) + 3/(x+4) = -1(x^2+9x+20)\n\nTaking the left hand side...we make one fraction by using a common denominator.\n\n[ 1(x+4) + 3(x+5) ] / (x+5)(x+4) = -1(x^2+9x+20)\n-->\n\n(4x+19)/(x^2 + 9x + 20) = -1(x^2+9x+20)\n\nEquating numerators since denominators are the same...\n\n4x + 19 = -1\n4x = -20\n\nx = -5\n\nPlease note that even though -5 solves the equation, when substituted back into the original equation, you will get undefined terms ( 1/0 = infinity) on both sides.
714160
x^2+6x+8/x^2-4-21 / x^2-4/x^2-7x\n=x^2 + 6x +(8/x^2) - 4 - (21/x^2) - (4/x^2) - 7x\n=x^2 + 6x -4 -7x +(8/x^2) - (21/x^2) - (4/x^2) \n=x^2 + 6x -4 -7x +[8-21-4]/x^2\n=x^2 + 6x -4 -7x -17/x^2\n=(x^2)*[x^2 - x -4  -17]/x^2\n=(x^2)*(x^2) - (x^2)*(x) -4*(x^2)  -17]/x^2\n=(x^4) - (x^3) - 4(x^2)x -17]/x^2
803154
first get a common denominator for the (1/x - 1/y):\n(1/x) - (1/y) = \nx/xy - y/yx = \nx-y/xy\n\nnow that we have 2 fractions in fraction form, we can reduce it to one fraction by multiplying the top with the bottom over the 2 middle sets:\n\nxy (x+y)\n-----------\nx-y (y-x)\n\n\nexpand or leave it as that
1163658
Use partial fraction decomposition.\nFactor the denominator.\ny^2 - y = y(y-1)\n1/(y^2 - y) = A/y + B/(y-1)\n1 = A(y-1) + By\nLet y = 0, then\n1 = A(-1) + 0\nA = -1\nLet y = 1, then\n1 = A(0) + B(1)\nB = 1\nThus,\n1/(y^2 - y) = -1/y + 1/(y-1)\nintegral of the above is\nAnswer: -ln(y) + ln(y-1) + C, where C is a constant.
790653
In order to solve, you need a common denominator:\n2(sqrt(3/5)) - 5(sqrt (5/3))\n2(sqrt 3/sqrt 5) - 5 (sqrt 5/sqrt 3)\n2(sqrt3/sqrt3)(sqrt 3/sqrt 5) - 5(sqrt 5/sqrt 5)(sqrt 5/sqrt 3)\n2(3/sqrt 15) - 5(5/sqrt 15)\n6/sqrt 15 - 25/sqrt 15\n-19/sqrt 15
904672
let u = x^2 + 1, then you have du = 2xdx, => dx = 1/2x du,\n\nsubstitute back you are on the way  to solve it
712992
I will try to explain step by step....\n\nA) x-2/3 + x+3/4=5/6\nFirst you would place like terms together;\nx+x-2/3+3/4=5/6\nThen try to make all the denominators equal.  Do this by thinking of what the denominators can all go into.  In this case, they can all go into 12 using whole numbers.  Since multiplying by 1 doesn't change the value, you can do that by multiplying the top and bottom of each fraction by the same number.  \n  So the -2/3 would all be multiplied times 4/4 giving you -8/12.  The 3/4 would all be multiplied times 3/3 giving you 9/12.  The 5/6 would all be multiplied times 2/2, giving you 10/12.\n\nThe equation would now look like;\nx+x-8/12+9/12=10/12\n\nYou then combine like terms;\nx+x=2x\n-8/12+9/12= 1/12\nSo your equation is now;\n2x+1/12=10/12\n\nSubtract 1/12 from both sides;\n2x=9/12\n\nAnd divide by 2;\nx=4.5/12 or 9/24\n\n9/24=3/8\n\nSo, the answer to A would be x=3/8\n\nAs for B...I'm not to good at word problems, sorry :)\n\n\nAnd NS in line 3 of your work, it should be -8/12 because -2*4= -8 not 8
890045
1/2x - 1/2y = 2 - - - - - -Equation 1\n4/3 x + 5y = - 1- - - - - -Equation 2\n- - - - - - - - - - -\nMultiply equation 1 by - 8 and clear the fraction equation 2\n\n1/2x - 1/2y = 2\n\n-8(1/2x) - (-8)(1/2y) = - 8(2)\n\n- 8/2x - (-8/2y) = - 16\n\n- 4x + 4y = - 16. . . New equation 1\n\n- - - - - - - - -\n\n4/3x + 5y = - 1\n\n3(4/3x) + 3(5y) = 3(- 1)\n\n4y + 15y = - 3 . . .New equation 2\n\n- - - - - - - - - - - - -- \n\n- 4x + 4Y = - 16\n4x + 15y = - 3\n- - - - - - - - - - \n19y = - 19\n\n19y/19 = - 19/19\n\ny = - 1\n\nThe answer is y = - 1\n\nInsert the y value into equation 2\n\n- - - - - - - - - - - - - - - -\n\n4/3x + 5y = - 1\n\n4/3y + 5( - 1) = -1\n\n4/3x + (- 5) = - 1\n\n4/3x - 5 = - 1\n\n4/3x - 5 + 5 = - 1 + 5\n\n4/3x = 4\n\n3(4/3x) = 3(4)\n\n4x = 12\n\n4x/4 = 12/4\n\nx = 3\n\nThe answer is x = 3\n\nInsert the x value into equation 2\n\n- - - - - - - - - - -\n\nCheck for equation 2\n\n4/3x + 5y = - 1\n\n4/3(3) + 5( - 1) = - 1\n\n12/3 + (-5) = - 1\n\n4 - 5 = - 1\n\n- 1 = - 1\n\n- - - - - - - - - - - - - \n\nCheck for euation 1\n\n1/2x - 1/2y = 2\n\n1/2(3) - 1/2(- 1) = 2\n\n3/2 - (-1/2) = 2\n\n3/2 + 1/2 = 4\n\n4/2 = 2\n\n2 = 2\n\n- - - - - - - - - - - -\n\nThe solution set { 3, - 1 }\n\n- - - - - - - -s-
985930
The answer is 1/2. To solve it... use algebra. Use X to represent the unknown fraction. Turn the word problem into a numerical expression. It will look like this: 4(X/5) x X = 1/5.    the little x is times. simplify and you get 4X^2/5= 1/5. then simplify again and you get 4x^2=1 Then x^2= 1/4 then x=1/2 ta da!
696212
find the common denominator\nmultipy the top and bottom of the fraction so the denominators are equal and then add the numerator