how do you factor this?   2X² + 11X + 12   what would be the answer?
484892
(x+3)(2x+4) is incorrect.\n(x+3)(2x+4) = 2x^2 + 10x + 12\nSolution:\nMultiply the coefficient of the x^2 term with the constant.\n2(12) = 24\nYou are looking for factors of 24 that add the 11 (which is the coefficient of the x term).\n(3)(8) = 24\n3 + 8 = 11\nReplace 11x with 3x + 8x\n2x^2 + 11x + 12\n= 2x^2 + 3x + 8x + 12\nFactor by grouping\n(2x^2 + 3x) + (8x+12)\n= x(2x+3) + 4(2x+3)\n= (2x+3)(x+4)\nAnswer: (2x+3)(x+4)\nYou can easily check the answer by Foil.\n(2x+3)(x+4) = (2x)(x) + (2x)(4) + (3)(x) + (3)(4)\n= 2x^2 + 8x + 3x + 12\n= 2x^2 + 11x + 12
767628
I'm assuming you want to factor this\n\n5z^2 + 4z -12 = (5z -6)(z+2)
825795
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
769323
6 - 12x\n-or-\n-12x + 6\n\n-or-\n\n6(1-2x)\n\n...although that depends on whether you want the simplest expanded form or the simplest factored form.
71477
6x^2 + dx - 12 would need to factor into two binomials.  If you know that one is (2x - 3), then the first term of the other would have to be 3x, in order to make the 6x^2 term.  In order to get -12 as the constant term, we would multiply -3 x +4.  \n\nSo the other factor is (3x + 4)\n\nUsing the FOIL method for multiplying two binomials, we get\n(3x + 4)(2x - 3) \n= 6x^2 - 9x + 8x - 12\n= 6x^2 - x - 12\nSo d must be -1.
858168
1. 14x^2 +21x\n\na good way to start would be to factor out any common terms:\n\n7(2x^2 + 3x)\n\n7x(2x + 3)
485118
2x = 3x+11\n2x-3x = 11\n-1x = 11\nx = -11
814352
(12x^2 +16x) - (12x-7)- (4x-5)\n12x^2 +16x -12x +7 -4x +5\n\n12x^2+12\n\nthat is what I got....\nI think you might be able to put 12 on the other side of the = sign and turn it into 12x^2 = -12 and then since both sides have 12 in common you can divide both sides by 12 and you will have x^2 = -1 then you can add 1 to both sides and you will have x^2 +1 but I think I'm getting off track by that point....it's been a while since I had to do this stuff.
819891
2(x-6)=3x\n\n1.Distribute the 2 to the X and the 6. \n2x-12=3x\n\n2. Subtract the 2x from the left side and subtract it from 3x\n-12 = 1x\n\n3.flip the problem so it looks pretty!\nx = -12\n\nYour Welcome :D
954300
ok\nso its factoring.this is hella easy.10x+40 is 10(x+4)\nso the answer is 10(x+4)there you go
929375
simplify\n-12x -8 = 18x - 18\nadd 12x to both sides\n-12x +12x -8 = 18x +12x - 18\n-8 = 30x -18\nnow add 18 to both sides\n-8 + 18 = 30x - 18 + 18\n10 = 30x\ndivide both sides by 30 \nx = 1/3
311512
a comon factor is -3x\n-12x^4-3x=\n-3x*4x^3-3x*1=\n-3x(4x^3+1)
1085664
Good job!  You're halfway there!\n\nAs you are writing it out on your homework, underline the (4x+1) in each of the two terms.  That helps you see what you are factoring.\n\nFactoring out the (4x+1) from each term, you should get your final answer.\n\n=(5x + 4y)(4x+1)
911039
12x^2-10x-8\n=2(6x^2-5x-4)\nsplitting the middle term -5 into\n-8 and +3 so that the sum is -5 and\nthe product is -24\n=2(6x^2-8x+3x-4)\n=2(2x+1)(3x-4)
851885
You have :\n | x+4y   =12\n | 2x-3y  =6\n<=>\n | 2x+8y=24  \n | 2x-3y=6              \n<=>  \n | 11y=18\n | x+4y=12\n<=>\n | y=18/11\n | x=12-4(18/11)=60/11\n\nFinally, we have (x=60/11) and (y=18/11) .\n ^_^
469289
3x^2 = 12\n\nFirst, divide by three.\n\nx^2 = 4\n\nTake the square root.\n\nx = +2, -2
208740
EDIT: ** Baah. When I typed this answer I was first. Then at the end, I'm like the 3rd. Oh well..**\n\nThere are two ways. Which one is easier depends greatly on your thinking skills.\n\nYou can take the expression x2+7x+12 and assume it should break up in two factors:\n(x+ ? )(x+ ?)\nThen, search for two numbers that add up to the 7, but when multiplied equal 12.\nIt helps if you break down 12 into it's components, 12= 2*2*3. So, obviously, the answers could be:\n\n2 * (2*3) = 2 * 6 (but 2+6 is not =7)\n3 * (2*2) = 3 * 4, voila! 3+4 also = 7, so:\n\n(x+3)(x+4).\n\nThe second way could be just solving the cuadratic formula for second degree equations:\n\nb=(-b +/- SQRT(b2 - 4ac))/2a\n\nWhere ax2 + bx + c, so you'll have: a=1, b=7, c=12.\n\nReplace, then solve twice: Once for the + value of the SQRT, another for the - value of the SQRT. You should get something like:\n\nFirst run:\nx= -3\n\nSecond run:\nx= -4\n\nx=-3 is the same thing as (x+3)=0\nand \nx=-4 is also (x+4)=0\n\nNotice the two factors are precisely (x+3) and (x+4)?\n\nHope this helped..