Ratio of Joan to Ben's age is 3:2. 15 yrs ago, Ben was 3 times as old as Joan was then. How old are they now?
481629
This is only possible if Ben has been travelling at near the speed of light for the last 15 years and has only aged 3 years while back on earth Joan has aged 15 years \n\nHe was 9 and she was 3.\nNow he is 12 and she is 18.\n\nAlternatively his birthday is Feb 29th and the 15 years includes only 3 leap years, he is therefore only  3 birthdays older, while she has had 15 birthdays\n\nOr Ben comes from Planet Zog which takes 5 earth years to rotate around the Zoggian Sun. He started at age 9 Zog Years and Joan started at age 3 Earth Years. Now he is 12 Zoggian Years old and she has got the key of the door having just turned 18.\n\nOr he was 9 in 1991, she was 3. After 3 years he was diagnosed as having an incurable disease and was put into cryogenic deep-freeze until such time as a cure was found, thus he is 12 and frozen and she is 18 and warm.
1147092
28\n\nleap years (which have Feb.29-th) are all divisible by 4
367452
Your information is given in terms of how much Beatrice collected, so let her amount = b.  Then Amy collected four times as much, or 4b and Colin collected half as much, or b/2.  If b=1, then your ratio would be 4:1:1/2 and to get rid of the fraction in the ratio you can multiply them all by 2 and get 8:2:1\n\nNow to solve how much each person got, Amy + Beatrice + Colin = 44 and you need to weight it for how much each collected.  Remember that Amy = 4b and Colin=b/2\n\n4b + b + b/2 = 44 --- again, multiply through by 2 to get rid of the fraction\n8b + 2b + b = 88\n11b = 88\nb = 8\n\nSo Beatrice earned 8.  Amy was 4b, so Amy earned 32; Colin was b/2 so he earned 4.  Check and make sure that 8+32+4=44.
975887
My oldest lover was 20 years older that me and my youngest was 7 years difference.   I prefer 10 years older than me.  I'm 39.
1034112
None.  I had a classmate in law school who was in her 50s.  She had been a kindergarten teacher for 20+ years before that. One of her former students was in the group of law students a year behind us!
1186414
let the age of tony be x and sarah be y\nthen,\nfour years ago,\n(x-4)=5(y-4)\nx-4=5y-20\nx-5y= -16......................(1)\nafter two years,\n(x+2)=2(y+2)\nx+2=2y+4\nx-2y=2..........................(2)\nby subtracting eqn. (1) from (2),\n x -2y=2\n-x+5y=16\n--------------------\n3y=18\ny=6\nput value of y in eqn (2)\nx-2*6=2\nx=2+12\nx=14\ntherefore, the age of tony and sarah now are 14 and 6 respectively.
108823
The age of the OLDEST daughter should be 9.\n\nLet: \n\na= oldest daughter's age\nb and c = the two other daughters ages\nd = address of house across street  \n\nIf a*b*c=36, and a+b+c=d  then\n\nall possible ages combinations are:\n\n36, 1, 1   sum = 38\n18, 2, 1   sum = 21\n12, 3, 1   sum = 16\n9, 4, 1    sum = 14\n9, 2, 2    sum = 13\n6, 6, 1    sum = 13\n6, 3, 2    sum = 12\n4, 3, 3    sum = 10\n\nI used the logic of the Math Tutor website below.  If the guy says that the address across the street doesnt offer enough information, then it means that the confusion results from two of the sums having the identical address (13).  \n\nLooking at both of those sums (9+2+2, and 6+6+1), we infer that BECAUSE the man said he HAS an OLDEST daughter, the 6+6+1 possibly is excluded, because that would mean he had TWO equally oldest daughters.\n\nThe correct answer, then, would be 9.
381264
52.\n\nLOLOLOL\nno dude they are 39
854451
It's an algebra problem.\n\n\n2 * Teacher's Age = 3 * Student's Age\n\nSince the Teacher's Age = Student's Age + 15\nS will equal the student's age.\n2(S+15) = 3S \nWould be your equation.\n\nDistribute:\n2S + 30 = 3S\n\nSubtract 2S from both sides and you get:\nS = 30.\n\nThe student is 30 years old.  Since the teacher is 15 years older then the student, the teacher is 45 years old.\n\nWhy are people getting 15 and 30?  That's a 2:1 ration, not 3:2.
540886
According to the question the answer is 3
363296
He felt he was getting older. He wanted to start a family, where as Jen didn't. They split up. And voila! Jen gets knocked up. (Spite maybe?)
392833
The sister does not age at an exponential rate.\n\nBasically, the sister is seventeen years older than her brother, right?  She won't be twice as old as him forever--just that one year! \n\nAnother, easier, example:  older sister is 4, younger sister is 2.  The older sister is twice as old as the younger sister.  The next year, the younger sister will be 3, and the older sister will be 5.  Is the older sister still twice as old?  Of course not! \n\nSo, when the boy is 23, the sister will still be 17 years older.  23+17=40.\n\nThe "twice as old" thing is just there to confuse you.  The question could have easily read:  A boy is 17 years old and his sister is 17 years older than he.  When the boy is 23 years old, what will be the age of his sister.
8792
p(a)= prob of man to alive after 25 years\np(a')= prob of man to be dead after 25 years =\n1-p(a).\np(b)= prob of woman to be alive \np(b')= prob of woman to be dead = 1- p(b)\nso to be atleast one lives we have two cases \n1) man lives and woman dies \n2) man dies and woman lives \n\nso\np(atleast)= p(a)*p(b')+p(a')*p(b)\n          = 3/5*1/3+2/5*2/3\n          = 7/15(answer)
938437
Sue's age = s\nLea = s + 6\nJohn = 5 + (s + 6)\n\ns + (s+6) + (5 + [s+6]) = 41\nSince it's all addition you can basically remove the parenthesis:\ns+ s + 6 + 5 + s + 6 = 41\nCombine everything:\n3s + 17 = 41\nSubtract 17 from both sides:\n3s = 24\nDivide by 3 on both sides:\ns = 8\n\nCheck it out by filling in the ages:\nSue = 8\nLea is 6 years older than Sue = 14\nJon is 5 years older than Lea = 19\n8 + 14 + 19 = 41
397573
Myself 14 years.  Happy going.\nAjoke for your question.\nA couple is celebrating their 50th Wedding Anniversary.  All the 10 Children (all married and kids) are attending the celeberation.  Lot of rush and friends, drinks etc.  The oldman by the way is seeing all these 10 sons at a time now.  He finds one among them not resembling with all the other nine.  He was restless and still sipping a drink.  He thought of asking his wife and asked her, is (our) 10th child fathered by a diffrerent man, to which the wife replied Yes my dear.  The old man was very very upset and sipped more glass of drinks.  Some how he want to know who that person is maybe one of his friends he wants to know who, abnd once again went to his wife and asked, My dear darling wife can u tell me who is that man?  Again the wife replied "YOU MY DEAR".  \n\nMoral - Dont live for longer periods after marriage or else dont celeberate wedding anniversaries after 20 years.
341393
I think is 21. Next time do your homework. i could be wrong
852632
Given: Time 50 minutes ago was  4*50 min after 3 o'clock. T'ime now is 3 o'clock +4*50+50=3 o'clock+250min=\n3 o'clock+250/60=3 o'clock +4hrs and 10min or\n 10 min past 7 o'clock. It's now 1 hr and 10 min after 6 o'clock.