What is the air speed velocity of an unlaided swallow?
481337
i beleive according to the man in the castle a swallow had to beat it's wings 43 times every second in order to maintain air speed velocity. That's a european swallow by the way :
722598
This is one you have to be careful with. \n\nThe actual world record on a single breath underwater static apnea(unassisted)is 8min 58sec held by German freediver Tom Sietas. \n\nThis was the record David Blaine was going for but hell 7 mins is damn impressive! Especially in his condition.\n\nYou can read of record breaking times that exceed 15mins, however these records were only achieved by pre-breathing 100% oxygen and are not recognised by virtually all the freediving community (including AIDA - the largest international body).
748368
first get the time from the horizontal motion  t = .51 / 1.2 s (uniform motion, no acceleration here)\n\nthen use h = 1/2gt^2 for the vertical motion (with initial velocity zero)
22326
For the European Swallow, roughly 11 meters per second, or 24 miles per hour.
700759
Let \nQ = volume flow rate in Litre/sec, \nD = diameter of the nozzle in cm and \nV = velocity of water in metre/sec. \n\nThen,  V = (40*Q)/ [pi*(D^2)]\n\nwhere pi = 3.14
19187
From style.org, who has put far more time into this than I could ever do:\n\n"Although a definitive answer would of course require further measurements, published species-wide averages of wing length and body mass, initial Strouhal estimates based on those averages and cross-species comparisons, the Lund wind tunnel study of birds flying at a range of speeds, and revised Strouhal numbers based on that study all lead me to estimate that the average cruising airspeed velocity of an unladen European Swallow is roughly 11 meters per second, or 24 miles an hour."\n\nAccording to the article, kinematic data for the African swallow species is hard to come by, so as of right now the velocity of an African swallow is unknown.
1075806
I assume that you mean that the object is perpendicular to the velocity of the wind.\n\nConsider a flat plate, area A, against which a wind of speed v is blowing.  The air has a density of p.  All measurements are made in a consistent unit system of course.\n\nIn one second a mass of air will be brought to rest, this mass is given by A x p x v\n\nThe momentum change of this air is therefore A x p x v²\n\nwhich gives the force on the flat plate.  Your object will also have a drag coefficient (Cd) the more streamlined the object is the lower it's drag.  So the total force becomes:\n\nA x Cd x p x v²\n\nYou will have to look up the drag coefficient for your object in a text.
711801
About the same as an African swallow (not to be mixed with the European one)
888567
a) zero momentum, as velocity on top is zero. p=mv\n     p=0.100kg * Om/s\n\nb) Vf = Vi + at\n      0=15+(-10)t\n     t=1.5ec (to reach maximum height)\n\nDivide by 2 for halfway up .i.e 0.75ec\n\nVf = Vi + at\nO=15 + (-10)(0.75)\nVf = 7.5m/s\n\np=mv   (p = momemtum)\n\np = (0.100kg)(7.5m/s)\np = 0.75kg*m/s, upwards (Direction is important)
466291
The speed of sound varies depending on the material it is travelling through, the pressure, altitude and temperature.\n\nOn the assumption you're talking about air and that you're at sea level under normal atmospheric conditions then 340m/s would be the speed at 14 degrees C and 330m/s would be the speed at minus 1 degree C - so they're both right.
411961
DEpends upon the size of the persons throat.
60295
If you're referring to the Freight version, it's pretty slow, even without the normal 20-mosquito payload, no more than 35 knots. The Passenger Swallow, though, can manage 48 knots unladen (and, incidentally, nearly that fast laden, since it's only a two-poucher). \nHowever, you probably know that Swallow is planning to phase out their Passenger version, in much the way Pigeon Air did theirs (misguidedly, I think) in 1900 when they thought it was a money-loser. So get your thrill ride while you still can!
1127
What do you mean? An African or European swallow?
736825
The speed of a free falling bodies is independent to its mass when the air resistance is not considered.\n\nFormula\n\nVf=Vi + gt\nVf final velocity (what is asked)\nVi initial velocity ( equal to zero, free fall)\ng acceleration due to gravity (9.8 mper second squared)\nt time travel.\n\nVf = 0 + 9.8 * 5\nVf = 49 m/s
1050300
It was a swallow....\n\n\nArthur: The swallow may fly south with the sun or the house martin or the plover may seek warmer climes in winter, yet these are not strangers to our land? \nSoldier #1: Are you suggesting coconuts migrate? \nArthur: Not at all. They could be carried. \nSoldier #1: What? A swallow carrying a coconut? \nArthur: It could grip it by the husk! \nSoldier #1: It's not a question of where he grips it! It's a simple question of weight ratios! A five ounce bird could not carry a one pound coconut. \nArthur: Well, it doesn't matter. Will you go and tell your master that Arthur from the Court of Camelot is here? \nSoldier #1: Listen. In order to maintain air-speed velocity, a swallow needs to beat its wings forty-three times every second, right? \nArthur: Please! \nSoldier #1: Am I right? \nArthur: I'm not interested! \nSoldier #2: It could be carried by an African swallow! \nSoldier #1: Oh, yeah, an African swallow maybe, but not a European swallow. That's my point. \nSoldier #2: Oh, yeah, I agree with that. \nArthur: Will you ask your master if he wants to join my court at Camelot?! \nSoldier #1: But then of course a-- African swallows are non-migratory. \nSoldier #2: Oh, yeah... \nSoldier #1: So, they couldn't bring a coconut back anyway... \n[clop clop clop]\nSoldier #2: Wait a minute! Supposing two swallows carried it together? \nSoldier #1: No, they'd have to have it on a line. \nSoldier #2: Well, simple! They'd just use a strand of creeper! \nSoldier #1: What, held under the dorsal guiding feathers? \nSoldier #2: Well, why not?
484307
in air= 340m/s\nin water=1500m/s\nin solid=4500m/s
594819
Well it depends on several things.\n\nIf you mean how fast it chews down through the earth, on a mud rig 60ft or so every hour.  I dont know about air rigs, never worked on one of those.\n\nNow if you mean how fast the bit is actually spining, I'm not sure...I just know it it no fun to change