2x + 3y =1, 5x +3y =16,  /  x + 5y =10,  -2x  - 10y = -20?
490279
5x + 3y = 16    \n(-)  2x + 3y = 1\n------------------------\n     3x      = 15\n\nx = 5\ny = -3\n\nSolution Set = { (5, -3) }\n\n\nx + 5y = 10  &  -2x - 10y = -20   is one and the same.\ni.e., they have to be cnsistent.
54462
(3x+5)/wz \n(3*4+5)/(-1*5)\n(15+5) / (-1*5) \n20/-5 = -4
574841
-2(x+10)=3(2x-4)\n-2x-20 = 6x-12\n-2x = 6x+8\n-8x = 8\nx = -1
753426
X2   5x - 4y = 1\n10x -8y =2\n-10x + 8y = -3\n-------------------------\n  0=-1                NO SOLUTION
191645
3x+y=5 ----(1)\nx-2y=11----(2)\n\nfrom eqn (1)\ny=5-3x-----(3)\nNow substituting value of y in eqn (2) we get \nx-2(5-3x)=11\n7x-10=11\n7x=21\ntherfore x=3\nNow substituting value of x in eqn (3) we get \ny=5-3(3)\ntherefore y=-4\n\nX=3,Y=-4
639859
its simple..see\n\n2x + 3y = 1 -------- 1st expression\n5x + 3y = 16 ------- 2nd expression\n\nnow..first take 1st expression\n\nStep 1: 2x + 3y = 1\n        2x = 1 - 3y\n        x = (1 - 3y) / 2  -------- this is value of x\n\nnow..take 2nd expression\n\nStep 2: 5x + 3y = 16\n        5(1 - 3y) / 2 + 3y = 16  ---here put the value of x\n        2.5(1 - 3y) + 3y = 16\n        2.5 - 7.5y + 3y = 16\n        2.5 - 16 = 7.5y - 3y\n        -13.5 = 4.5y\n        y = -13.5 / 4.5\n        y = -3 ------ this is value of y\n\nNow again put the value of y in the 1st expression\n\nStep 3: 2x + 3y = 1\n        2x + 3(-3) = 1\n        2x - 9 = 1\n        2x = 1 + 9\n         2x = 10\n         x = 10 / 2\n         x = 5\n\nSo, final value of x = 5 and value of y = -3 \n\nHope ya understand ;-)
701107
4x +y = 16   ;2x + 3y = 24      Multiply the 2nd with -2, that gives -4x -6y = -48    Add the two:   0x - 5y = -32  \nDivision by -5 gives  y = 6,4\nInsert this value into the first equation:   4x + 6,4 = 16\n4x = 9,6 ;    x = 2,4\n\nNumber 2 is even easier:\nMultiply the first equation by 2 and add the equations.\n24x + 2y = 50    plus   8x - 2y = 14  gives  32x = 64; x = 2\nYou can now choose:  24 + y = 25  or  16 - 2y = 14\n(That you get when you replace in the original equations \nx by 2)  Anyhow you'll find   y = 1
866437
Let one side be 'x', second will be 'x + 5 ' third will be  ( x+5) - 3\nx  + x + 5 + ( x + 5 ) - 3 = 16
805693
#1\n4x+1+3=0\n4x+4=0\n4x=-4\nx=-1\n\n#2\n2y+7+4=y\n2y+11=y\ny=-11
631059
3y+5=y-25\n2y+5=-25\n2y=-30\ny=-15\n\nSee, you just use inverse operations.\n\n4n-5=2n+3\n2n-5=3\n2n=8\nn=4\n\nSo your answers are y=-15 and n=4. I hope that helped!
850894
2x-3y=5 ….multiply by 1\n                           x+2y=-l .... multiply by -2\n\n                                       2x-3y=5 \n                                      -2x-4y=2 …..add two equations\n                                      ------------\n                                        -7y= 7\n                                          y=-1\n\n substitute y=-1 in the second equation coz it is easier in order to get the x value\n\nx+2y=-1\nx-2=-1\nx=1\n\nSo the solution is (1,-1)
846702
-x + 2y = 18\n x + 8y = -38\n\nadd up these two lines\n\n0x+ 10y = -20\ny= -20/10 = -2\n\nx + 8(-2) = -38\nx - 16 = -38\n\n\nx=-22\ny=-2
599677
i know how 2 do this.\n4x+2y=2\n x-2y=8\n---------\n5x   =10\n5x=10\nx=10/5\nx=2.\nsubstitute x=2 in any1 of the equations.\nlet us take x-2y=8.\n  2-2y=8\n  -2y=8-2\n  -2y=6\n    y=6/-2\n    y=-3.\n therefore ur x=2 nd y=-3.
789893
x+4(2x+1)=3( x-2)+10x : x=2.5\n\nI like to work with x
1119268
okay first take x/5 + y/5 = 3 and times everything by 3 so you have 3x/5 + 3y/5=9 now times everything by 5 so you have 3x + 3y = 45 (notice the 5's on left side cancel when u mulitiply) now take \n3x + 3y = 45 and subtract the other equation from it which is 3x + y = 13 so it looks like this \n  3x + 3y = 45\n -3x -   y  =-13 which gives you \n  2y = 32 divide by 2 to get \n y=16 substitute this value of y in second equation ( 3x + y = 13)\nso you have 3x + 16 = 13 subtract 16 from both sides and you will have 3x = -3 divide by there and it gives you x = -1 now plug in both of you values x and y into one of the equations i say the second one because it's much easier but anyways when you plug it in the second one you get 3(-1) + 16 = 13 is this true and the answer is yes therefore it is solved correctly\n\nEDIT: Doin it again with a little more detail for my own sake lol\nEquation 1=  x/5 + y/5 = 3\nEquation 2=  3x + y = 13\n\n(x/5 + y/5 = 3) mulitiply everything in the ( ) by 3\n(3x/5 + 3y/5 = 9) multiply everything in the ( ) by 5\n3x + 3y = 45 notice the fives on the left side cancel\nNow subtract Equation 2 from 3x + 3y = 45\n   3x + 3y = 45\n   -3x - y= -13 so this will give you\n 0x + 2y = 32 divide by 2\n          y = 16 Substitute your y value into equation 2\n3x + y = 13 so you have instead 3x + 16 = 13 subtract 16 from both sides 3x = -3 divide both sides by 3 so you have x = -1 now plug in your x and y values into equation 2\n3(-1) + 16 = 13; -3 + 16 = 13; 16 - 3 = 13 which is correct therefore the solutions are correct
316989
2x-5=3x+6\n2x=3x+6+5\n2x=3x=11\n-x=11\n\nx=-11
516161
x-y+3x-5y+3=0\n\n4x - 6y + 3 = 0\n\n4x + 3 = 6y\n\n2x/3 + 1/2 = y