what is the value of root of  -1?
493159
It does not have a real number value and is therefore defined as "i". i is an 'imaginary number'. The concept is a little too involved for me to be able to supply a complete answer describing imaginay numbers though. Hope that helps.
485166
The correct answer is d.\n\nf(1-x) will give a negative number for all positive 'x' values.\n\nbut squaring these negative number will always give a positive number i.e (-4)^2 = +16.\n\nTherefore in the equation f(x) = x^2(1-x)^2;\n\nYou can see that for all positive or negative numbers you will have a positive value. Again,\n\nLet x=5; Then 1-x = -4;\n\nFor the equation d.. 1-(-4) = 5. i.e the original number.\n\nHence, f(5) = 5^2 (-4)^2 = 25*16;\nAlso, f(-4) = (-4)^2 (5)^2 = 25*16;\n\nThus, for all values of x... Equation d is TRUE.
728155
Lots of great answers which deserve the 10 points, but a short-cut would be to use \nproduct of roots = -40\n\nThe product of (3 + i) and (3 - i) is 10, so the other root must be -4.\n\nOf course, the advantage of the other methods is that they check up that the given information is correct, whereas this method accepts the information that 3 + i is a root (so that 3 - i must be, too).
19513
This seems to be a popular question. There is no real number that is the square root of -1.  However, it turns out that it is useful to develop as set of numbers that allows the square root of -1.    This is called "i" as is known as an imaginary number.  The set of numbers that includes i is called the set of complex numbers.
325892
= 1-{1-[1-(0)]}\n= 1-{1-[1]}\n= 1-{0}\n= 1
491468
If by x1/2 you mean x^(1/2), and by -1-[x] you mean -1 minus the absolute value of x, then the composite function f o g is (-1-[x])^(1/2).\n\nWhat is unusual about this is that this function is not defined for any real number x.  The expression (-1-[x]) is always going to be negative, no matter what x is.  Raising this to the power of 1/2 is the same as taking the square root of it.  Since the square root of a negative number is not defined in the real number system, the domain is the empty set.
820030
i is define as sqrt(-1)\ntherfore  i*i=sqrt(-1)*sqrt(-1)= -1
958505
x={-(-4) (+/-)√[(-4)^2 - 4(1)(-5)]}/(2(1))\n x= 4(+-)6/2\n x=5,   x=-1\n\nCheck:\n with x=5,  5^2-4(5)-5=25-20-5=0  OK\n with x=-1   (-1)^2 -4(-1) -5 = 1+4-5=0  OK
482706
I think you mean find the cube root of -8/27:\n\nCube root of a negative is negative.\nCube root of 8 is 2\nCube root of 27 is 3\n\nSo the answer is -2/3
851434
-x^2 if x=-2\n-(-2)^2  \n-(4)\n-4
797702
Since there is no = sign in that equation, I assumne it should be equal to zero.  If that is the case then m= -1/8
466400
0 can't be in the domain.\nAlso, -1/2 cannot be in the domain because\n(-1/2)^(-1/2) = 1/sqrt(-1/2) which is not a real number\nI'm not sure exactly how to right this:\nThe domain is any real number except 0 and any number of the form (p/q), where p and q do not have any common factors and q is even and (p/q) is negative.\nIf (p/q) is negative and reduced and q is even, then you would be taking an even root of a negative number(which is never a real number).
559973
4i is the answer you seek,\nthe i is the square of -1 says any geek.\nThis is a abstract answer to solve your query,\nbut all negative roots include the 'i,' my deary.
70580
Well, I don't really understand you. This is the best I could.\n\nI think it is true. For example, the cube root of -8, which is x, is -2, which is y. y^3 is -8, which is x. So, yes, I think it's true.
593847
The answer is zero isn't it?  The square root of (7 squared) is 7.  If you minus 14 you get -7. Add another 7, brings you up to zero.
678825
The square root of -1\nis an imaginary 1\nit is depicted generally with a character 'i'\nif u want root of -2\nthen itd be i x root(2)\nor 1.414i
230430
The square root of -1 has no relation to zero.  It requires an imaginary number.  Division by zero is, unfortunately for our number system, impossible.  You cannot cut something into zero pieces, and in fact the very statement makes no sense.