On logic chips is VDD or VSS positive voltages? talking about CMOS. Please only answer if you actually know!?
481354
Vdd (Voltage Drain Drain)    - Positive\nVss (Voltage Source Source)  - Common, ground
263992
Here the concept is U'll decide the logic 1 nad 0 based on  spin of electrons...currently HP is working on it...if they come up with big result, it'll b a revolutionary change n da VLSI industry
960408
http://www.eas.asu.edu/~holbert/ece201/kvl.html
244997
An operational amplyfier has a gain of one.Thetrefore it is very ussefull in logic circuitry.
663500
Both, check your CMOS settings.
843449
maybe this would help\nhttp://encarta.msn.com/encnet/refpages/search.aspx?q=semiconductors
501730
Try http://www.asic-world.com/digital/boolean.html for a beginning.  I would start with basic boolean math.  That often will help you simplify a large logic circuit down to something you can build.
717058
yes. There's always a possibility that during the flash process you'll lose power in your neighborhood and render the chip unuseable.  What features do you need in the BIOS that you're hoping to add? If you don't know, then I don't reccomend flashing.
1085280
The most recent issue of IEEE transactions (2006, v.14, issue 4) is devoted to VLSI. The major specialization areas it cites are: systems specifications, design and partitioning, high performance computing and communication systems, neural networks, wafer-scale integration and multichip module systems and their applications.\n\nBesides the articles in this journal, there are a number of websites detailing VLSI conferences, journals, and professiona organizations. I would look through these sources for "State of the Industry" reports. Wikipedia and IEEE maintain a list of up-to-date links: http://en.wikipedia.org/wiki/Very-large-scale_integration\nhttp://www.ieee.org/portal/pages/society/eds/technical_committees/vlsi/links.html
369710
TTL (Transistor-Transistor Logic) is a name for type of logic circuits which are constructed using the bipolar transistors. \n\nIn general the bipolar transistors such as the NPN and PNP transistors are current operated devices. In these types of transistors, when used for digital logic circuits, typically the input voltage is applied across the Base-Emitter junction. As a result of this a small base current is produced in that junction. This small base current is magnified by the transistor's current gain factor B(called Beta), resulting in a large amount of collector-emitter current. This is basiclly how a TTL switch works.\n\nThe TTL family of circuits are generally very fast, but this speed comes at the cost of higher power dissipation. Also, a typical TTL logic gate circuit requires multiple transistors and other passive components such as resistors. This results in lower number of gates that can be put on an IC built using TTL family.\n\nThe CMOS(Complimentary Metal Oxide Semiconductor) family of logic circuits are buit using Metal Oxide Semiconductor(MOS) Field Effect Transistors (FET). These types of transistors are voltage operated devices. A typical CMOS logic gate circuit can be constructed using as little as two MOSFET transistors (A CMOS Inverter) resulting in a much higher density of logic gates that can be put on an IC.\n\nAlso, CMOS gates use much much lower power to operate compared to the TTL gates because no resistors are required to build such circuits.\n\nCMOS logic also allows much higher operating voltages compared to the TTL family.\n\nOne drawback of CMOS family is that they are slower than the TTL family, however these days this may no longer be true.
33167
A CMOS inverter consists of one N-channel transistor connected to ground, and one P channel transistor connected to Vdd. Their gate pins are tied together and used as the input, and their third pins are tied together and used as the output (See the picture below for details). These transistors act like switches, controlled by the input.\n\nWhen the input is high (Vdd), it turns on the N-channel transistor and turns off the P-channel transistor. This causes the voltage at the output to be low, because the N-channel transistor is switched on, connecting the output to the ground.\n\nWhen the input is low, just the opposite happens.
940120
Not necessarily! \n\nOutput is usually measured in watts at the speaker connections, not volts.\n\nThe Line-out "standard" is 1v peak-to-peak on most systems except those designed to drive many speakers, (like restaurant background music), which are usually either 75v or 150v to avoid "line loss" in large systems with long runs, which then use special transformers at each speaker to convert back for the speakers.
759091
------/:=====:x:=====:&#92;-----@-------\nL     2Wy                Int             2Wy           Load          N\n\n(Does this answer your question??)\n\nL=Live, 2Wy is a 2 way light switch, int is an intermediate switch, and @ is a light??\n\nConfused?? (never heard of tunnel switching!!?)
592245
The MSI K8N Diamond Plus Motherboard has memory voltage specifications from 2.6V-3.2V adjustable in increments of 0.05V.  It is not likely that the memory, regardless of type, will operate below the minimum of 2.6V since the memory must be matched to the chipset on the motherboard.  Generally, a motherboard chipset will not support both normal DDR and DDR2 type of memory because of the clocking strategy used to control memory access.  In other words, don't try to install DDR2 memory in a system that uses normal DDR or you may encounter system stability problems.
169792
A typical output has a transistor that pulls the output to ground when the output is 0 and a pull up resistor or transistor that drives the output high when the output is 1.\n\nHowever, there are two cases where this might not be desirable. Suppose we have an inverter that we want to use to turn on a 12V light. Sure, you could use a transistor or other switch to do that, but why not use an open collector inverter. This inverter only has the "low side" transistor. So the output is either 0 or floating. If the chip can handle 12V on the input, you can use it to directly turn the light on (it will be on with the output low). The 12V supply would go to the bulb and the other side of the bulb would go to the open collector output.\n\nThe other reason to do this is when you want to drive a lot of outputs into one input. For example, suppose I'm building a CPU. I have an input that causes a register to write its content to the bus. Further, suppose there are 10 reasons you might want to do this. The obvious way is to have a 10 input "OR" gate so that when any of these 10 things occur, the register gets the signal. But an easier way is to make the input active low. Tie a pull up resistor to the input and then drive it with 10 open collector gates. When no one wants to make the register write, the outputs all float and the resistor holds the input high (no action). If any output goes low (or multiple outputs, for that matter), the input goes low and the action occurs. This is often known as wired-OR.\n\nYou might find The Art of Electronics useful. You can read my review of this fine book at http://www.wd5gnr.com/books.htm (I didn't write it, BTW).
698161
No, the voltages are different
120823
This is a 18-pin microcontroller to control the moving display in 7X60 matrix of LEDs. this is programable.\n\nyou can get more in formation from here. this is manual of this prodct..\n\nhttp://www.zilog.com/docs/z8/appnotes/an_msgdisp.pdf\n\nplease check