How do i get the proper degree of freedom when doing a chi sqaured test?
477523
The no of degrees of freedom for a chi-square distribution ia n-1
557865
the chi distribution of an area is based on the degree/ tilt of your main door to where it faces (360 degrees). then calculate the chi distribution. easy.
691694
i like having the lines in my @ss read. i think it is more accurate than a plain old palm reading! try a rump reading, you'll be suprised to see how accurate they are.
873308
OK - I will try and explain it, but forgive me if I get myself confused...  hehehe\n\nFirst step - make a bell curve.  Put a mark in the center and label that "7 hours" - that's your mean.  Next, put three marks on either side of that middle point - those will be your standard deviation points.  For the points on the right, ADD 5.3 to the mean for the first one, then add 5.3 again for the 2nd, etc...  Points on the left side of the mean have the 5.3 SUBTRACTED.  (Am I still making sense?  lol)\n\nNow - the 68-95-99.7 rule says that 68% of the freshmen will fall into the area between the first line on EITHER side of the mean, 95% between the second lines and 99.7% between the third lines on either side of the mean.\n\nI think you should be able to figure it from there - I hope so...  Right now I am so confused I think I gave myself a headache!  lol\n\nGood luck!
231416
You do need a Chi-Square test (also known as contingency table)\nThe idea of the procedure, invented to test the effectiveness of medical treatments, is to prove whether or not a given treatment (say tv watching by age 3) has some effect over the symptoms (say ADD)\n\nConstruct a table like this:\n.......ADD..NOT ADD.....total\nTV<3...n11...n12.......n11+n12=r1\ntV>3\n,<6....n21...n22.......n21+n22=r2\ntv>6...n31...n32.......n31++n32=r3\n.......c1=...c2=\n...sum(nj1)..sum(nj2)..total\n\nConstruct\ndifij=(nij-ci*rj/total)^2\nthen X=sum(difij) distributes as a chi-square with cols*(rows-1) degrees of freedom.
318413
OOO, We did this project in IPC, except our was 20 meters -.-;;. You're ideal angle is 45 degrees. That usually gets you the farthest. It would be pretty smart to use elastic potential energy by using piece of bamboo or just a flexible stick (haha, flexible stick) or just a rubber band. Don't put anything on the egg. Our model was made with a giant rubber band that I found on the floor, and a little seat attached to the crossbow model. If your teacher is strict about a catapult model, your best bet would be to use the bamboo stick and research trebuchets.
123406
Try Chi square testing, it starts out complicated but once you understand it, it is way faster than punnett squares! You can find all kinds of stuff about it on the internet, it's a statistical analysis.
842761
The standardized and studentized version of x differ in such a way that the former requires parameters (that is, population mean and population variance) while the latter uses statistic (that is, sample mean and sample variance).\n\n\nstandardized\n\nz test = (x - mu)(sqrt of n)/sigma\nz test = (108 - 100)(sqrt of 4)/16\nz test = 1\n\nstudentized\n\nt test = (x - muo)(sqrt of n)/s\nt test = (108 - 100)(sqrt of 4)/12\nt test = 1.3333\n\n\nlast\nBetween the two curves with different degress of freedom, the one with the greater value approximate the standard noramal curve more closely.\nIn fact, if the degrees of freedom approach infinity, the resulting curve will be the standard normal curve.\n\nTherefore the one with degress of freedom of 20 approximate the standard normal curve more closely than with the value of 12.
332748
ok the simplest way is to hang a weight if some sort (key dog tag nail ect.) from a string held in your hand, now swing the weight in a circle eather way and think yes, now this direction of travel will be yes now go the oposit way and think no, this direction now will represent no, now for i don't know/ i will not answer, change direction to a back and forth motion so it swings tward you and away, \n\nnow all you have to do is think yes or no questions and remember the direction of travel\n\n\ngood luck
710256
You got the CG just right.  Your method might work with enough concentration., but I would look at making the angular momentum come to zero:\nL = Iω = (2.7*.325²  + 1.3*.675²) * 26rpm*2π/60 = 2.389 kg m²/s\n\nTo stop the movement the angular impulse must equal the - of the angular momentum:\n\nT * t = L→ T = L/t = 2.389/5.8 = .4118 Nm (ccw)
827431
when the probability is 0.2:\n\nP((β-12%)*Sqrt(n)/σ>=1.301)=20%\n1.301 is the T value under degree of freedom of 44 and α =10%\n\nI did not pay attention in leaasons of statistics, I dont know if it's correct.
248494
Ekta, it should be McNemar not McNerman.\n\nIt is the chisquare test for matched pairs. In a normal chisquare test you do the sum of  [(observed - expected)^2]/ expected and calculate the degrees of freedom. But in a matched chisquare analysis, the concordant pairs, that is a and d give no information, but only the discordant pairs are useful to us.\nHence, we have,\nChi square = (c-b)^2 / (b+c).\nThere is a continuity correction but I will not go into it. The degrees of freedom will again be 1.\n\nI hope you got what u meant to ask. If not, u can just comment further in this question and I will answer it.
878588
First, learn to recognize a 90 degree angle... that's like the corner of a square.\n\nAlso learn to recognize a 180 degree angle... that's a straight line.\n\nIf you imagine taking the corner of a square (a right angle) and dividing exactly in two, that would be a 45 degree angle.\n\nIf you imagine dividing it into three, that would be a 30 degree angle.\n\nEverything else you have to eyeball how the angle compares to 90 degrees.  For example, if the angle seems to be about 2/3 the way to 90 degrees, that is 2/3 * 90 = 60 degrees.
310004
find a better Statstic book, or use CHIDIST / CHIINV functions in MS-Excel. Or use this thing:\nhttp://www.georgetown.edu/faculty/ballc/webtools/web_chi.html\njust make sure it gives same numbers for lower df's as your table
84965
What you are describing is what some people like to refer to as Degrees of freedom.\n\nFor example in statics, there are 6 degrees of freedom;  The degrees of freedom in this case would be "movement in and rotation about all three axis.  However, not all six would be concidered a free mode.  Think of a wheel on a car.  The wheel can rotate about the transverse axis(how the car moves, and rotate about the vertical axis (this is how the car turns).  However the wheel could not move in any direction (relitive to the car) or rotate in the longitudinal axis (in normal condition).
980793
Your first inclination is wrong, therefore, your belief is correct.\nYou need to figure for x. \n\nDo this: execute the equation if x = 1, then 2, then 3, etc. You will start to see a pattern, at which point you should be able to rephrase the equation. (It's actually pretty simple - you will see).
463856
Gosh this is a bit vague - but I think you're referring to why we use 1/F when getting a lower confidence interval or doing a 2-sided test.\n\nThe definition of an F m,n-dsitribution is:\n\n[Chi-square(m)/ m] ÷ [Chi-square (n) / n]\n\nTherefore if we did 1 / Fm,n this would be:\n\n[Chi-square(n)/ n] ÷ [Chi-square (m) / m]\n\nSince "dividing by a fraction is the same as turning it over and mulitplying by it".\n\nSo suppose we want a lower 5% limit for F4,5, ie:\n\nP(F4,5 < ? ) = 0.05\n\nWe can invert both sides:\n\nP(1/F4,5 > 1/?) = 0.05\n\n(Note the sign changes, eg 2 < 3 but 1/2 > 1/3)\n\nBut using the result from earlier 1/F4,5 = F5,4:\n\nSO we now have:\n\nP(F5,4 > 1/?) = 0.05\n\nSo what we do is look at the upper 5% point in the F5,4 -tables which is 6.256.\n\nSo 1/? = 6.256\n\nHence ? = 1/6.256\n\nSo the shortcut rule is to get the value we do "one over the F distribution with the number swapped round"\n\nHope this helps.