how would you know that all the angles in a parellalegram?
493884
In any quadrilateral the sum of the angles is 360 degrees.  Its an axiom that has been proven.  It's similar to the axiom that all angles in a triangle add up to 180.\n\nNote: the pattern is:\n3 angles = 180\n4 angles = 360\n5 angles = 540\n6 angles = 720\n7 angles = 900\netc.\n\nAnother fact about parallelograms is that the opposite sides have the same lengths and the opposite angles have the same measure.  This also means that two consecutive angles will add up to 180 (since the other pair must be equal and the total must be 360, as noted before).
454825
We can do this 2 different ways.\n\nFirst: Use the Pythagorean Theorem. Since all angles are right angles, the diagonal (measure from corner to corner) is the hypotenuse of the right triangle formed.\n\nBy the Pythagorean Theorem, 10^2 + 10^2 =x^2, where x=diagonal\n\nx^2=200\nx=sqrt(200)\nx=10 sqrt 2\n\n2nd way: use 45-45-90 Triangles\n\nWhen you draw any diagonal in a square, you get a 45-45-90 degree right triangle. This is because the 2 sides are the same, so the 2 base angles must be also. The top is 90, so the others must be 45 and 45 to equal each other.\n\nThe sides to a 45-45-90 right triangle are always in the ratio 1:1: sqrt(2) where sqrt(2) is the hypotenuse.\n\nYou know that the sides are 10 feet. Therefore the hypotenuse is 10 sqrt2 feet
140611
Complementary angles add up to 90 degrees.\nSupplementary angles add up to 180 degrees.\n\nJust think in alphabetical order: C comes before S, and 90 comes before 180.
583757
Your statement is incorrect.  It reads:\n\n"In the image below, there are right angles. How would I prove that they're right angles without a protractor in any triangle?"\n\nActually, it should read:\n\n"In the image below, there are some angles."\n\nAnything else is pure conjecture.  (That means a guess.)\n\nIf you would like us to say something about those angles, you need to tell us how the figure was constructed.  After you tell us that, and ask your question more clearly, your answer will be obtained in short order.\n\nedit...\n\nYou have added some text in your extra text file that doesn't help at all:\n\n"I know that these green points are right angles..."\n\nSo you think a point can also be an angle.  It will be a long time before you get someone (who knows and understands geometry) to agree with that.\n\nIf you start over and explain what you want to know, in correct terms, you may have a chance at getting an answer.
928764
You would just do 180-56 to equal 124 degrees\n\nsupplementary angles add up together to equal 180 degres or a straight line
302936
Without knowing the measurements of the sides, you can only figure this out if all sides of the polygon are equal in length. And this is how...\n\nSee, first you draw any polygon, except a triangle. So before doing it, you should know that all the angles of a triangle must add up to 180 degrees. (You can do it with a triangle too, but you would be using what you’re hoping to discover.) From the center of the polygon, draw a line to each vertex. This will create a number of triangles, inside the polygon, equal to its number of sides. Knowing that the angles inside each triangle must add up to 180 degrees, you simply multiply 180 by the number of triangles, which is also the number of sides. Then, realizing that the angles in the center of the polygon, which do not contribute to the angles of that polygon, form a complete circle, and therefore must add up to 360 degrees, you subtract 360 from the result. So the angles in any polygon must add up to 180x-360, or 180(x-2), where x is the number of sides. To find the measure of each angle, in a polygon where all sides and angles are equal, you divide that by the number of sides. The equation then works out to (180(x-2))/x.
606300
well, think about it- how many degrees are there in ALL triangles? \n\nif you know 2 angles, you only need one more. Let's say 2 angles were 44 and 72. The two angles combined are 44+72. If you know how many degrees there are overall, you would subtract how many you have from what you know needs to be there!
566727
I'm afraid that with the given information, this would be impossible to determine. The only thing one could conclude from this information is that this polygon has an even number of sides. \n\nIt could be a square with sides of 3cm each\nIt could be a hexagon with sides of 2cm each\nIt could be an octagon with sides of 1.5cm each\nIt could be a decagon with sides of 1.2cm each\nIt could be a 12-gon with sides of 1cm each\n\nThe list is infinite unless you are given more specific information, such as the length of each side or the angles within the shape.
628550
same angle degree, same lenght of a side.
1010584
Just think....\n\nA triangle (3 sides) always totals 180 degrees\nA quadrilateral (4 sides) always totals 360 degrees\nA pentagon (5) will total 540 degrees\n\nSo, the angles, A, will always equal 180 degrees per side, for each side (N) after the first 2.\n\nIn other words,   A = 180 * (N-2)\n\nif A is 32040, then 32040 = 180 * (N-2)\n\nN - 2 = 178\n\nN = 180
847510
Several ways. The first that comes to mind is to figure the area with Heron's formula (area = sqrt(s(s - a)(s - b)(s - c)), where s = (a + b + c)/2). The area can also be figured as 1/2 base times altitude, so you know the altitudes of the triangle. The altitudes give you right triangles where you know the hypotenuse (a side of the triangle), and a leg, so you can compute the trig functions of all the angles. Then the angles can be computed as arcsin or arccos of the angle (arcsin(altitude/side))
955408
the formula is half the height times the base.  But here's why:\n\nFirst consider a rectangle.  You know the surface to be height times width.  Now cut the rectangle in two pieces, along a diagonal.  You end up with two triangles. Furthermore, the sides of these triangles are the same, thus the triangles themselves are equal. The surface of each has to be half that of the surface of the rectangle.\n\nFor triangles with a right angle in them, you have proven 0.5*h*b to be correct.  But each triangle will work.  If you have a triangle without a right angle, you can always find a way to split it in two smaller triangles, each having a right angle, and process each part separately.\n\nYou could also cut a parallelogram in two equal parts (again: cut a diagonal) and end up with two equal triangles, not having a right angle.
559255
You're best bet is to think of them as an assembly of right angle parrellelagrams. Then each parrellelagram has a volumn of base x height x width. If they are not of that shape think of them as of that shape anyway.
713469
Can't u prove it ?\nuse simple geometrical angle laws.\n\nif we have a triangle : \nupside-- the inclined plane\ndownside--- the horizontal\nright side--- the gravitational force (vertical)\n\nDRAW IT........ as u know \n\nand then draw the perpendicual component on the plane     \n\nuse this: sum of the two angles inside the triangle    =180-90=90\n\nsum of angles at the gravitional point= 180-90=90 also\n\nu will prove the equality
185652
since your ddoing coordinate geometry you should at least tell what shape you're trying to get.\nI'm assuming it's a parallelogram so u should make it (1,8)
262981
All sides and angles are equal to a side and angle on another figure
87971
The area of a parallelogram is area = base x height. Now, drawing a diagonal of the parallelogram splits the shape into two congruent triangles. Therefore, each triangle will have an area equal to (1/2)base x height.\n\nThis is true for any triangle; that is, any triangle has a corresponding parallelogram associated with it, which can be cut in half.