what should we do if we have two numbers for the median?
493498
all the above answers are correct, but here's an example:\n\ngiven: 15,18,12,21,11,17\n\nin order: 11,12,15,17,18,21\n\nnow originally, the median would be the two numbers, 15 and 17.  but the median is only one number, or in this case, the average between the two middle numbers, 15 and 17.  so:\n\n(15+17)/2 = 16\n\nso the median's 16 - yay.
399290
It depends on the circumstance. Could you give some background to the question? \n\nIf you take a Gaussian normal random distribution and expand the sample size, the median and the mean would both remain unchanged. This question is missing something. Could you clarify?
703752
simply subtract 7 from both sides. This leave you with\n\nx<_3
271009
first of all salaries, especially in america are not normally distributed. Yet in a hypothetical sense, you could use any of them in a normal distribution because they would be approximately the same. but mean is sensitive to outliers or extremes in data, whereas median and mode is not.
1165756
Mean is the average, when adding all numbers then dividing by the amount of numbers given.\n\nMedian is the numbers in the middle average - 8
434108
in the first one the median is 3/4 cuz it stands right in the middle\nthe mean is 2\nas about the second one:\n10x+5(12-x)=100\n10x+60-5x=100\n5x=40\nx=8\n8 ten dollar bills\n4 five dollar biils
472192
To elaborate further, your mode does tell you what the most common value in your data is, but, like the median, it's a somewhat arbitrary value.  For example, take the data set 1,2,2,3,7.  Both the mode and the median are 2, and the mean is 3.  Now take the data set 1,2,2,25,50.  Again, the mode and the median are both 2, but the mean is now 16.  Now, say that second data set represents the number of shark attacks that have happened in the past 5 years off the coast of a beachfront property you're thinking about buying.  I'd much rather know the mean number of shark attacks, not the mode or the median, wouldn't you?
205444
median is given by P(X<median)=0.5, while percentile 90% is given by P(X<P90)=0.90.\nwith those two equations, since gamma has two parameters, you can solve for them.
921908
1\n\njust do a little bit of trial you will see that the smaller number you use it nears 1.
627711
1,10,10,14,17,20\n\nmean = sum of items / number of items = 72/6 = 12\nmedian = middle value, or mean of two middle values if there is an even number of items\nso in this case median = (10+14)/2 = 12\nmode = most frequently occurring = 10
628648
None. The two numbers have no common factors, bar -1. You mean exactly (with no remainder) not evenly.
810881
Arrange your sequence of numbers from the smallest to largest...\n\nthen the middle number in your sequence is your median\n\nit's simple as that.\n\nfor example\n\nA.   6, 7, 10, 4, 9\n\nRearrange to\n\n4, 6, 7, 9, 10\n\nThe middle number in the sequence is 7 as you can see\n\nSimple :D\n\nhope it helps
226471
get it sorted 1st, \nthen get the differences of adjacent number pairs, \nget the min of this differences
374019
Sorry your answer was wrong.\nMean can be less than median also as median is not affected by extreme numbers at its both ends while mean is.\n\ne.g. find mean and median of following data.\n     1, 3, 5, 9, 18, 180\n\nhere your answer for mean will come to\n               36\n\nwhile if you find median for it then it will come to\n            7\n\nIn this example mean was greater than median.\n\ne.g. -180, 18, 5, 3, 1, 9\nhere your mean is -24\n\nwhile your median is 4.\n\nSo from both example you can say that\n\nnone of them is always greater than other one nor it is always smaller than other one.
898911
Take the average of the absolute value of each of the numbers minus the mean...\n\n( |2.44-2.23| + |3.54-2.23| + |1.37 - 2.23|  + |1.5 - 2.23| + |2.3-2.23| )/5
944997
you divide or multiply by a negative numberand the sign of inequality flips
269746
Make 2 7/15 an improper fraction, flip it over to its reciprical and mulitply the two.\n\nBoy...I hope I got that.  *bits fingernails*