What should you do to understand trigonometry???
483588
Trignometry could be made interestingly easy.\nUnderstand the basics:\nThe longest side of triangle is hypotenuse.\nThe side of the triangle opposite the angle(your angle) is the perpendicular.\nthe remaining side is called the base.\n\nsine theta=perpendicular/hypotenuse\ncosine theta=base/hypotenuse\ntangent theta=sine theta/cos theta=perpendicular/base\n\nAll other formulas are based on these relationships.\nlike sine square theta+cosine square theta=1 etc.
1128929
First off......do you know how to do basic trigonometry and use Snell's Law?  If you do, then I'll walk you through it.  Write me at fortitudinousskeptic@yahoo.com\nIf you don't know trig and Snell's law I'm not going to try to explain it.  I'm not that motivated.
717403
There is only 2 ways to know an angle\n1. Know the other two angles \n2. know the length of 2 sides\nSince you don't know the other two angles, you need to use one of your trig functions, the only way to do this is to memorize the tables for sin, cos and tan for as many angles as you can manage, and then use your memorized chart once you figure out what ratio you are using.
733210
You basically have 2 options. Use a protractor and measure them (The internal angles total 180 degrees).\n\nThe other option is using the trig functions (Sin, cos and tan), however you must have some info on the triangle eg. length of sides to apply any of these.
209404
trigonometry is the study of angles in one or several triangles. it is a little like geometry, in the sense that it deals with shapes, but it also has characteristics similar to algebra and basic number functions. it's not too difficult once you learn how to work a scientific calculator.
466401
Trigonometry is hard to do in you head, so start out by making a drawing. You have two buildings A (tall) and B (short) - Draw them far apart, not like this:\n\nA         B\n|         \n|         \n|    \n|         |\n|         |\n|         |\n|         |\n\nNow draw one line from the top of A to the top of B - this is the angle of depression of the top and it is 46 degrees. That is, if you drew a straight, horizontal line across the top of building A, the angle between that line and the line joining the top of A to the top of B is 46 degress.\n\nSimilarly, draw a line from the top of A to the *bottom* of B - this is the angle of depression of the bottom and it is 77 degrees. That is, the angle between the horizontal line across the top of A, and the line between top of A and bottom of B is 77 degrees.\n\nNow can you find out the angle between the line from A-top to B-top, and the line from A-top to B-bottom? (It's very important for you to draw this!) Let's put this value aside for a minute. \n\nLooking at your drawing, can you see that you know the value for *part* of the angle between the horizontal line across A's top and length of building A? What is that part you know? Now, see how the line across A's top and length of A make a right angle? So how many degrees in a right angle? So if you know the total of that angle, and part of that angle, how do you get the other part? **Notice that this part we're trying to get is actually the angle between the line A-top to *B*-bottom, and the line A-top to *A*-bottom. \n\nYou should also notice that now we have two triangles:\nTriangle 1: A-top to B-bottom to A-bottom. Solve this triangle for line A-bottom to B-bottom for distance between the two buildings.\nTriangle 2: A-top to B-top to B-bottom. Solve this triangle for line B-top to B-bottom for height of building. \n\nDon't forget, we have two important angles that will help solve these two triangles!
908924
Because of (one of) the definition(s) of sin and cos.\nWhich is: take a unit circle, and draw in any radius at some angle theta. Then sin theta = the y value, and cos theta = the x value. Those are obviously less than 1.\n\nOr you could just take a typical right angled triangle - the length of the opposite/adjacent sides are always less than the length of the hypotenuse.
756840
cosx=tanx\ncosx=sinx/cosx\ncos^2(x)=sinx\n1-sin^2(x)=sinx    {pythagoras}\nsin^2(x)+sinx-1=0\nuse quadratic formula\nsinx=(-1+or-sqrt(5))/2\n=0.6180339888\nor -1.6180339888\nsine has to lie between +/-1\nsinx= 0.6180339888\nx=arcsin(0.6180339888)\n  =38.17270763\n+ve value for sine lies in 1st and 2nd\nquadrants \ntherefore,x=38.17270763 degrees or\n141.8272924 degrees\n\nthese two values were checked in the \noriginal equation and were found \nto be correct\n\ni hope that this helps
862258
I am taking College Algebra with Trigonometry and that is hard, so I know Calculus is real hard. That is a hard question to figure out.
247689
Use analytical trig (hint: sin function).  That should give you the answer you are looking for.
844759
Look at the various values of cosx when x = pi/2, pi, etc. (recall that pi/2 = 90 degrees).\n\nFrom looking at these values in my book, I see two values for x that will satisfy this equation:  x=pi/3, and x=pi\n\ncos pi/3 = 1/2\ncos 2pi/3 = -1/2\n\ncos pi = -1\ncos 2pi = 1\n\n~ ♥ ~
545074
The word "Trigonometry" is derived from two Greek words meaning measurement or solution of triangles. Trigonometry is a branch of mathematics that deals with the ratio between the sides of a right triangle and its angles. Trigonometry is used in surveying to determine heights and distances, in navigation to determine location and distances, and in fields like nondestructive testing for determining things such as the angle for reflection or refraction of an ultrasound wave.\n\nThere are three principle functions in trigonometry: sine A, cosine A, and tangent A where A is an angle. These are typically abbreviated for use in algebra to: sinA, cosA, and tanA. These terms are defined in terms of a right triangle. SinA is equal to the side opposite of the angle A (side a) divided by the hypotenuse of the triangle (side c). From the right triangle below, it can be seen that the value of angle A is directly linked to the ratio of side a and side c. In other words, if the length of side a is changed (and side c is not changed by the same amount), then angle A must change. When the division of the length of side a by side c is performed, the resulting value is directly related to angle A. The relationship between the decimal value of the ratio of the side and the angular value of angle A can be looked up in trigonometry tables or, as is more common these days, programmed into a scientific calculator. The relationship between angle A and the ratio of any two of the three sides can be determined by using either the Sin, Cos or Tan functions. CosA is equal to the side adjacent to the angle A divided by the hypotenuse and tanA is the sine divided by the cosine and is therefore the side opposite the angle divided by the side adjacent.
624769
You can use sin and cosine.
104581
It takes practice!  And its like a puzzle.  Just use the main trig identities as reference and a good math tutor.  Unfortunately, this place isn't the best place to ask that kind of question because we are limited by text explainations and trig identities need a lot more than that!
779945
1. cosθ=A*B / (|A|*|B|)=(1*5+0*2+3*6) / 5√ 26\n            =81.171\n\n2. assume the angle of vectors of a and b is "m"  \n   so cos m= a*b/(|a|*|b|)=0   because cos90=0\n   m=90...so it is a right triangle...\n   |a| and |b| are representing the right-angled sides of the triangle.\n   |a|=√17; |b|=√26\n   S=|a|*|b| / 2 =10.5\n\n3. P(1,3,5) to cylindrical coordinates.......\n                         r=√1+9 =√10....\n                         θ= tan^(-1)3=71.6\n                         z= 5 \n       In terms  of x , y , and z\n                         x= r.cosθ =√10*71.6 =226\n                         y= r.sinθ = 0.95*√10= 3\n                         z=5\n                        so its (226,3,5)\n            ditto, T 's doesn't have cylindrical coordinates \n                     S 's cylindrical coordinates is (0.6, -0.8, -10)\n  ......................(that's all i know..)
472052
ok so i assume you know the basic rules of trigonomerty for a triangle.\ni.e sinR = opposite/hypotenuse and cosR= adjacent/hypotenuse.\n\ndraw the triangle on a piece of paper.\nYou will see that sin R = ST/SR\n\n(where ST is the edge running from S to T and similarly SR is the edge running from Sto R)\n\nalso cos R= RT/SR\n\nso sinR^2 + cosR^2 = (ST)^2/(SR^2) + (RT)^2/(SR^2)\n\n= [(ST)^2 + (RT)^2]/(SR^2)\n\nNow we use pythagoras' theorem. I assume u know this? The sum of the squares of the two shorter sides of the triangle equals the square of the longer side (the hypotenuse)\n\nso (ST^2) + (RT)^2 = SR^2\n\nSO WE NOW HAVE\nsinR^2 + cosR^2 = SR^2/SR^2 = 1\n\nthere you go\n\n\nCANT E-MAIL YOU BACK WESTILE BECAUSE IT SAYS YOUR E-MAIL IS NOT VERIFIED
251440
memorize simple rules and try to derive the hard ones from simple ones and then to be fast then memorize the diffucult rules.Trigonometry is simple if you know basic El-Cebir well