solve this exponential patern 1 32 81 64 25?
493502
6.\n\n1^6, 2^5, 3^4, 4^3, 5^2, 6^1.
324992
it = 5667766776600000, is this for you enjoy ment? :)
129538
The next number is 30651.\nIt has a recursion, a_n=a_(n-1)^2+2*a_(n-2).
604123
I figured it out... the answer is 1/(13*(2-3x))\nIf you need an explanation tell me
1168828
1237548*26636686+5567562356-46\n\n32969745048238
141990
(assuming the second 2 is an exponent) 2*2*2*7*5*g*h*h \nyou really should learn to do this if you are ever going to get through school though
968787
553.    343434, 686868\n\n554  42\n\n555  642, yes\n\n556  210\n\n557  42\n\n558  Sorry, you have to do proofs yourself\n\n559  987987^30
1157976
0000, 0001, 0002, 0003, 0004, 0005, 0006, 0007, 0008, 0009, 0010, 0011... etc, etc  untill u get to 9998, 9999\n\ntry it out, might take a long time but one combination will work :))
589850
e)\nSolve the eqn.\nG(k)=k^2-0.5k=-0.5\nk^2-0.5k+0.5=0\nk= (0.5+_sqrt(.25-2))/2\n0.25+-sqrt(-1.75) /2\nSince term inside sqrt is negative \nthere are no real solutions
283562
If you express the equation in exponential form:\n(x^2)^1458=2^x\nx^2916=2^x\n\nWhen solved for x:\nx=-0.9998 and 1.0002
829854
Use logarithms to bring exponents down where you can deal with them.  Since the natural log is base e, that's the way to go here.\n\ne^5x = 7\n\n5x = ln 7\n\nand solve from there.
836453
a^24b^24\njust multiply the exponents\n\nhope thie helps!!!
197333
i think \nx = 2664.173
1029640
36415\nprior to 1/1/05, use G0001
647999
21, 4^0 = 1, not 0\n\n0.32, 0.32, 1/3
816170
You have done some mistake while copying the problem.Please check it up.It may be 36l^2-36lq+9q^2 or something else.However I am doing ipresuming it to be 36l^2-36lq+9q^2\n\ngiven exp.=9(4l^2-4lq+q^2)\n=9{2l)^2-2.2l.q+(q)^2}\n=9(2l-q)^2\nThe answer may also be written as {3(2l-q)}^2 or (6l-3q)^2
115650
--5 2 0 1 -----  F L O W\n--4 2 0 1 -----  B L O W\n--1 0 2 5 -----  W O L F\n-------------------------\n1 0 4 2 7 ----- N O B L E\n\nBut still N and W value are coming same...does this problem have solution. If you have then can you please send the answer to my mail id hssiddhu@yahoo.com