How do you change degrees celsus into degrees ferinhit?
483906
if you want a quick guess, use the rule of thumb, F=2*C+32\n\nif you want it exact, use the formula which is, F=1.8*C+32
1084272
double it and add 30 to the celsius temp and you get an rough farenheit temp-for example 30Celsius x 2=60+30=90Farenheit
111333
Begin by subtracting 32 from the Fahrenheit number. \nDivide the answer by 9. \nThen multiply that answer by 5.
759551
V1/T1 = V2/T2\n\nFirst convert temperature to Kelvin. 198+ 273 = 471\n\nNext plug into equation\n\n4.81 L / 471 K = 2.49 L / T2\nT2 = 243.8\nthen put it back into C 243.8 - 273 = -29.2 C
172716
To convert F to C and C to F you use the equation:\n\n  (F - 32)/ 180 = C/100\n            \nThen,   C = (F-32).100/180 = (F-32).5/9\n    \nAnd, F = (C . 180/100) + 32 = (C . 9/5) +32\n              \nIn your question: \n\nF = 40 . 9/5 +32 = 8 . 9 + 32 = 72 + 32 = 104
756155
Celsius to fahrenheit:\n(C*9) / 5 +32\nmultiply it by 9, then divide it by 5, then add 32.\n\nbackwards:\n((F) - 32  ) /9 *5\n\nthere are some converters on the web if you don't want to use the formula:\nwww.wbuf.noaa/gov/tempfc.htm
154145
Or you could do it yourself using the formulas F=9/5C+32 and C=5/9F-32.  1 degree Fahrenheit is 5/9 of 1 degree celsius (and vice versa) and you add or subtract 32 degrees because freezing is 32F and 0C.
21392
So it depends on whether your question is in Fahrenheit or Centigrade (aka Celsius). If it is in degrees Fahrenheit you need to convert to Rankine, divide by two, and then convert back to Fahrenheit:\n0 Fahrenheit = 459.67 Rankine; twice as cold = 229.835 Rankine; 229.835 Rankine = -229.835 Degrees Fahrenheit which is your answer.\n\nIf, however, you are for some reason using metric, then you convert Centigrade (Celsius) to Kelvin, Divide by two, and convert back to Centigrade.\nSo: 0 Centigrade = 275.15K; twice as cold = 136.575K, converting back to centigrade you get -136.575 Centigrade which is your answer utilizing metric units.
932464
F - 32 = (9/5) C \nF - 32 = (9/5)*1\nF = (9/5)+32\nF=(9+32*5)/5\nF=169/5\nF=33.8 degree ferhenite=1 degree centigrade\n\n2.\n25 degree centigrade= ? ferhenite\nF - 32 = (9/5) C \nF - 32 = (9/5)*25\nF - 32 = (9*25/5) \nF - 32 = 9*5\nF - 32 = 45\nF=45+32\nF=77 degree ferhenite=25 degree centigrade.
419278
Farenheit = (9/5) * Celcius + 32\n22C = 72F\n0C = 32F\n-40C = -40F\n\nvery confusing math, no? Easier (in my opinion) to memorize a few key temperatures!
311200
centigrade: 5/9 (F-32)example: 212F = .556 x (212 -32) = 100c\n\nFahrenheit: 9/5 (C+32) example: 100C = 1.8 x100 +32 =212f\n\ncentigrade and Fahrenheit equal at -40 degrees
151136
278K. In the Kelvin system, 0'C = 273K. Also, there is no "formula" for converting between celcius and kelvin. You just add or subtract. It's basically a shift of origin type of thing where you move the origin from 0 to 273.
33810
Here is the new and easy way to convert centigrade to Farenhiet and viceversa\n**************************\nIf your number is 'x' degrees (either C or F)\n\n1) Add 40 to the number --->  x+40\n2) Multiply by the factor 'Y'\n\n     Y= 5/9  if from Farenhiet to Celsius\n     Y= 9/5  if from Celsius to Farenheit\n\n     ie   ---> (x+40)*Y\n\n3) Subtract 40 from the resulting number.\n\n   -----> [(x+40)*Y] - 40\n\nand there you have it you have converted into the desired scale.\n\nTip to remember Y;-\n\nF-->C   lower  so  5/9\nC-->F   higher so  9/5\n\n********************************\nThere u have the best way of conversion.\n\nDanEengineer@yahoo.com
424227
take 32 degrees off the F, then divide by 1.8.  So for example lets say you have a F temp of 50.  Take 32 off that, which gives you 18.  Divide by 1.8, which gives you 10.  So 50 F is the same as 10 C.
600668
If it is 0 deg Centigrade i.e. 32 deg Farrenheit and double the cold i.e. 16 deg F mening -8.9 deg Centigrade
884756
Celsius=5/9(Fahrenheit-32).\n43F=6.111111111.........Celsius
819522
Look at this link and you can learn about converting at the end of site you can enter your number and check your answer http://www.csgnetwork.com/tempconv.html\n, but try anyway to do your homework by yourself, at the exam you will not have the yahoo answers to answer for you!