what has 1nitrogen 5carbon and 8 hydrogen?
486317
This might not make much sense, but I think it might be\n2,4-Cyclohexadiene with an ammonia substituent.
859471
1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 9.630 g x (12 / 44) = 2.626 g\nhydrogen: 4.928 g x (2 / 18) = 0.548 g\noxygen: 4.055 - 2.626 - .548 = 0.881 g\n\n2) convert to moles.\ncarbon: 2.626 / 12 = 0.219 mol\nhydrogen: 0.548 / 1 = 0.548 mol\noxygen: 0.881 / 16 = 0.0551 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.219 / 0.0551 = 4\nhydrogen: 0.548  / 0.0551 = 10\noxygen: 0.0551 / 0.0551 = 1\n\nThe empirical formula of the substance is (C4H10O)n\nThe atomic masses add up to 74, which is also the molar mass of the compound. Therefore n=1 and we find C4H10O
149051
nitrogen, probably helium and hydrogen too.
552184
C3H8 + 5O2 = 3CO2 + 4H2O\n\n1 mole of propane is required.\n\nCheck:\nC: 3 on both sides\nH: 8 on both sides\nO: 10 on both sides
762215
Noble Gases:  He, Ar, Ne, Xe\nHalogens:  F2, Cl2, Br2, I2, At2\nOthers:  N2, O2
179135
Methane has a structure of four hydrogens attached to a carbon
759497
1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 7.432 g x (12 / 44) = 2.027 g\nhydrogen: 4.057 g x (2 / 18) = 0.451 g\noxygen: 3.383 - 2.027 - .451 = 0.905 g\n\n2) convert to moles.\ncarbon: 2.027 / 12 = 0.169 mol\nhydrogen: 0.451 / 1 = 0.451 mol\noxygen: 0.905 / 16 = 0.0566 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.169 / 0.0566 = 3\nhydrogen: 0.451  / 0.0566 = 8\noxygen: 0.0566 / 0.0566 = 1\n\nThe empirical formula of the substance is (C3H8O)n\nThe atomic masses add up to 60, which is also the molar mass of the compound. Therefore n=1 and we find C3H8O
873492
oxygen 21%\nnitrogen 78%\nco2 0.03%\nrest - inert gas and water vapours
292657
Neon - it's inert and remains monoatomic ; whereas carbon, boron and fluorine combine with other elements to form compuonds.
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N2: about 78%\nO2: about 21%\nAr: about 0.9%\nMisc.--includes CO2, nitrogen oxides, SO2, Xe, Kr, Ne, etc: about 0.1%
1082622
it is composed of 4 bases, each of which are composed of carbon, hydrogen, nitrogen, oxygen, and phosphorus
166454
I can supply you said chemicals.\n(C2H5NH)(CH3)C6H3OH \nPlease contact me by email: halsliu@gmail.com
875637
it is a mixture of hydrocarbons containing few carbons. octane is one constituent
750464
My chemistry is pretty rusty, but let's see.\n\nI'll assume that you have an infinite amt of O2, and that you have 68.12 grams of NH3.\n\nThe equation isn't balanced, so you need to do that first (you have 3 hydrogens on one side, but two on the other).  Balance to get:\n\n2(NH3) + (2.5)(O2) --> 2NO + 3(H20)\n\n4(NH3) + 5(O2) --> 4NO + 6(H20)\n\nNow, given that you have 68.12 grams of NH3, you need to convert this into moles of NH3, as Stoichiometry deals with molar ratios.  To get the conversion ratio, look at the periodic table.  Under each element, there should be an atomic mass.  For oxygen is 16.something, Hydrogen 1.008 ( i think ).  Find it for N and H.  (this is where I get hazy on the math).  I believe: take 3 * atomic mass of hydrogen + atomic mass of nitrogen, let's call it M  (it should be in grams/mole)  So to get moles, multiply 68.12 * (1/M).  \n\nNow, our equation above shows that for every 4 moles of NH3, we get 6 of H20.  # moles NH3 * (6/4) = # moles of H20.  Now, do the reverse operation of H20 to get how many grams is produced.  H20 has an atomic mass of something like 18.016.  So, # moles H20 * 18.016 = # grams H20\n\n\nI hope that's somewhat correct, and if not, leads you in the right direction at least
883737
Hydrogen gas molecules, H2
693067
Water, nitrogen and carbon.
875727
Octane is an alkane with the chemical formula C8H18. It has 18 isomers.