Negative radius...is it possible?
481336
well, ok, i see lots of complicated answers...but here is the answer in simple terms\n\nthe radius measures teh distance from the center to its boundry...it doesnt matter what the coordinates of teh boundry are because we have to use the distance formula to find it which is\n\nd = sqrt[(x-x1)^2 +(y-y1)^2]\n\nso from this equation (x1,y1) is the origin (0,0)\n\nso you really have\n\nradius = d = sqrt[x^2 + y^2]\n\nso whatever point you choose the distance must be positive because any numbers squared then added will be positive.\n\nso you would claim, well what if the center wasnt at the origin, well the only difference would be that you would use the original distance equation i mentioned.\n\nSo we can say that all distance (according to the distance equation) must be positive, try it with any points you like, it will always be positive.  Due to the distance equation always being positive, all radii must be positive.\n\nhope this helps\n\nmatttlocke\n\nPS\nand for everyone who says distance cant be negative...they lie\n\nthe magnitude of direction can never be negative the negative does imply direction.  for example, on the number line, we have points -5, and 5, the distance of both of those points from 0 is 5, but if we were plot each point they would be going in opposite directions, and we know this due to the negative sign\n\nso the distance formula means that the distance will always be positive, the negative does tell you direction, ask any mathematician (im working on that) or a physicist and they will tell you the same thing.\n\nBut, a negative and positive radius mean the same thing because the boundry of the circle will intersect all the points at whatever the measure of the radius is in all directions, so i spose you could look at it as negative, but it doesnt really matter.  This would all hold in any 'n' dimension.
840317
if it is a true arch the length would equal the diameter,\nso radius would be half the diameter (length)
702351
I think you are looking too much into it, but here we go. \n\nIf you have the equation x^2 and say we pick points x= -1, and 1. \n\nWhen you plug the x's into the equation you will get a positive answer. This is why whenever the exponent is even, it will always bounce off the x- axis, because there is no way for it to go negative.\n\nfor the second question, say we take x^2 and plug in the same points above.\n\n-1 ^ 3 gives you -1. This would mean that ever x = -# will have a negative y value which means it will cross the x- axis\n\nTry it with more equations and you will understand
1147597
Is that the same principle as two negatives making a positive?\nThen the answer would be yes.
456296
Multiply a negative times a negative and you will get a postive answer.
991890
Try the 2-2 pattern. it's the best way. The 3 is done with that criss-cross pattern, but the 2-2 allows you to continue the circle, just make it have a big radius
962268
The range is the largest minus the smallest, or 12-3\nmean & std dev.:\nx, f, r,rf, fr^2\n3, 1, -4, -4, 16\n4, , -3, ,\n5, , -2, ,\n6, 1, -1, -1, 1\n7, 1, 0, 0, 0\n8,  , 1, ,\n9,  , 2, ,\n10, 1, 3, +3, 9\n11 , , 4, ,\n12, 1, 5, +5, 25\nsums,,,,,,,,3, 53\nm = 7+3/5 = 7.6\nσ ≈ √(53/5) ≈ 3.2558\nTechnically, \nσ = √((4.4² + 1.6² + 0.6² + 4.6² + 2.4²/5)\nσ = 3.1369
710762
If you mean 6 raised to the power of negative pi, that would be 6 raised to the power of -3.1416. That computed to 0.0036. Used a scientific calculator, but you could do it with logarithms also.
1059357
Thats why they asked theoretically.\n\nsame radius as the solar system\n1267650600228229401496703205376 kms\n\nOf which you allready knew, otherwise u would not be asking
1056342
Hint, try to work out the radius!  Do your homework yourself.
622196
bc when u have 2 and you take 4 away from it, you are negative 2--- think of it like this: 2-4=-2
461076
the value of the expression increases.\n\nUmm don't think so cuz negative numbers are real numbers and a negative number wouldnt make sense.
998200
Polar\nits use to converse from dimensional to polar.\nexp\n(3,4) --> (5;53)\nits mean 5 for radius and 53degree
483398
r u 4 r3al ?!! \n\nwhat mapping ? what equasion?  deckard maybe ? \n\nmore info please.
875283
You differentiated and found it has relative min at x=1/3?  but if you differentiate again you find second deriv is\n54x - 1/(x^2), and I think this goes from \nnegative when x<1/cuberoot(54) to positive when it's greater, so that means it has an inflection.  Also means it's concave down when \nx<1/cuberoot(54), so the answer must be 5, not 2.  Unless I made a mistake!\n\nPS  Dave is wrong about 1.  Domain is all positive real numbers, because lnx is undefined for 0 and neg.
165372
S= Radius * Alpha Angle\nAlpha Angle needs to be in radians\n\nSo, Radius= S/Alpha Angle (in Radians)
575459
Sorry but I don't quite understand your qn.\nCan you make it clearer?\n\n(to ozert:\ncos A and sin A could be negative values if tan A is in Quadrant 3)