help me with some repeating fractions and the rules to tell if the fraction repeats.?
484592
I don't know the rule... I don't even think there is one you jsut divide the fraction and see if it repeats... But to change a decimal into a fraction (if you can round the fraction to the hundreths-the first 2 numbers after the decimal-) but multiply the decimal by onehundred and then try to reduce...
538734
It's just like long division... but it is hard to show in text form here.\n\nLet's start with the second one, since it is simpler:\n\n2x^2 + 6x - 5 / 2x - 4\n\nWrite it as you would for long division:\n\n```````` ____________\n2x - 4 ) 2x^2 + 6x - 5\n\nStart with the first couple terms.  How many times does 2x-4 go into 2x^2 + 6x.  It goes in once (times x), with a remainder of 2.\n\n```````` _______1x____\n2x - 4 ) 2x^2 + 6x - 5\n`````````-` 2x^2 - 4x\n`````````----------------------\n````````````````````10x - 5\n\nAnd how many times does 2x-4 go into 10x-5... 5 times.\n\n```````` _______1x_+5_\n2x - 4 ) 2x^2 + 6x - 5\n`````````-` 2x^2 - 4x\n`````````----------------------\n````````````````````10x - 5\n``````````````````-`10x -20\n`````````----------------------\n```````````````````````````15\n\nSo the answer is x + 5 with a remainder of 15/(2x-4)\n\nTry the first on your own... it doesn't even have a remainder...\n\nHere's some hints:\n\nx + 11 ) 3 x^3 + 35 x^2 + 19 x - 33\n\nIgnoring x for a moment\n\n1 11 ) 3 35 19 -33\n\nFirst one goes in 3 times\n\n1 11 ) 3 35 19 -33\n```````- 3 33\n```````-----------------\n`````````````2 19\n\nNext goes in 2 times\n\n1 11 ) 3 35 19 -33\n```````- 3 33\n```````-----------------\n`````````````2 19\n```````````- 2 22\n```````-----------------\n```````````````-3 -33\n\nThis one goes in -3 times\n\n1 11 ) 3 35 19 -33\n```````- 3 33\n```````-----------------\n`````````````2 19\n```````````- 2 22\n```````-----------------\n```````````````-3 -33\n`````````````- -3 -33\n```````-----------------\n````````````````````0\n\nPut x back in you have 3x^2 + 2x - 3
199971
Since when you multiply the top and bottom of fractions by the same number, you can find a common denominator for them. For example, 1/2 of a pie is the same as 2/4 or 3/6 of a pie. When you multiply 4/7 by 5/5, you get 20/35. Do the same thing for 2/5. Then you have 20/35 + 10/35. Add the 20 and then 10, and you get 30/35. Then that can be divided on top and bottom of 5 to get 6/7, which is your ANSWER! :)
885296
6 2/3 / 10=\n\n20/3 /10=\n\n20/3*1/10=\n\n2/3 or .66666666666666 repeating or .6 repeating
779807
Yiu would first decide how many decimal places you are going to consider.  The usual is 3.  Then work it from there...;
975151
The previous responders have given you the answer for a terminating decimal. (That means a decimal that has a certain number of decimal places, and then all the rest of it is zeroes. For example, .9187 is a terminating decimal, which could be extended with zeroes as .918700000000000000000....)\n\nBut you may be asking about repeating decimals. These are more interesting. Here's how you convert them to fractions.\n\nIf there is only a single digit that repeats (such as .3333333333....), you take that digit and put it over 9:\n.3333333333.... = 3/9 = 1/3. (Note that you should put the fraction in lowest terms (1/3, in this case) after you put the digit over 9.)\n\nIf there are 2 digits that repeat, you put them over 99. For example, .636363636363636363.... = 63/99 = 7/11.\n\nAnd if there are lots of digits that repeat, you put them over the same number of 9's. For example, .71237123712371237123.... = 7123/9999.\n\nThere are other tricks, such as a decimal that doesn't repeat until after the first few decimal places (e.g., .7633333...), but the above rules should handle most of the situations you encounter.
857564
If this is for a statistics course, chances are you are allowed to run out 22.8 times.  If you must round, 23 would be more correct, but as answers never come out to integers in statistics, my guess is that you are to put the decimals.
318849
Ok, first you turn them into improper fractions.\n4 3/4 turns into 19/4\n2 1/12 turns into 25/12\n1 1/8 turns into 9/8\n\nThey all have to have the same denominator which would be 24. 19/4 turns into 114/24. 25/12 would be 50/24. 9/8 would be 27/24. Now they all have the same denominator you add them to get 191/24 which is the same as 7&23/24.
704342
You would first convert it to a fraction.\n\n.5555... = 5/9\n\nIn general, when you have a repeating decimal, just put the repeating portion over an equivalent number of nines.  So .5555... = 5/9\n\n(As another example, .1818... = 18/99 = 2/11, and .135135... = 135/999 = = 15/111 = 5/37)\n\nSo once you convert the repeating number to a fraction you have 30 5/9%\n\nIn words this is "thirty and five-ninths percent"
809434
First, ignore those negative signs for now, and calculate each mixed fraction as an improper fraction.\n\nThe technique:  denominator times whole number, plus numerator, while keeping the denominator.\n\n6 1/6 = 37/6  (6 x 6 = 36, plus 1 = 37)\n2 2/9 = 20/9  \n\nNow, add the negative signs and solve normally\n\n-37/6 - 20/9\n\n-111/18 - 40/18\n(-111-40)/18 = -151/18
959905
I understand what you are saying when you mention the permutations for 10 digits, but I think you're missing what it really means.  First, this isn't right to think of it this way to think about this.  Non-repeating doesn't mean that I can't find a string in the decimal expansion that's the same as an earlier string (for example, finding a piece 14159 later in pi isn't impossible).  What it means is that there is no point where the digits in pi *completely* repeat (i.e. it becomes something like 141591415914159.... on and on forever).  So you're right, it can include some kind of partial repeat, but non-repeating means it can't have a total repeat.\n\nYour comment about the permutations (not combinations) on the numbers {0,...,9} is right but it's used incorrectly also.  It's wrong because of what I mentioned above.  Basically it's assuming that once you pick a number you can't repeat it again in a 10 digit sequence, but that's clearly wrong (again, 14159 appears in pi, where 1 occurs twice).  So you have several right ideas here but you're combining them seomwhat incorrectly.\n\nHope this clears things up!!
882012
What you want to do is factor out the same values from the numerator and denominators.  \n\nThe order in which you factor these out does not matter, the key is to continue to factor them out until there is nothing else to factor out.\n\nFor example you can factor out a^8 by turning it into:\n\n36 * (a^8) * (b^4) * 1/2\nover\n27 * (a^8) * a * (b^6) * 1/3\n\nsince (a^8) over (a^8) = 1 you can cancel them out leaving you with:\n\n36 * (b^4) * 1/2\nover \n27 * a * (b^6) * 1/3\n\nwe do the same factoring for b where we can factor out a (b^4):\n\n36 * (b^4) * 1/2\nover \n27 * a * (b^4) * (b^2) * 1/3\n\ncanceling the (b^4)s we get:\n\n36 * 1/2\nover\n27 * a * (b^2) * 1/3\n\nYou can then further reduce the fraction by multiplying out the 36 * 1/2 and the 27 * 1/3:  leaving you with:\n\n18\nover \n9 * a * (b^2)\n\nAs you can see now you can factor out a multiple of 9 leaving you with:\n\n2\nover\na*b^2
407989
Just cross of like terms in the numerator and the denominator and see what is left.  like in the first problem the numerator and the denominator share two two's and a 3, so by crossing them off you are left with 4/7.  You can do that since 2/2 is one, and likewise with other similar fractions, and when you multiply by one you always get the same fraction.
708585
What sort of help do you need with fractions? It depends. Or you can try math.com\n\nYou have to look a little to actually find what youre looking for, but mostly its good \n\nHope this helps!  :)
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
961226
You find the fraction of a fraction by multiplying the top numbers and (separately) multiplying the bottom numbers.\n\nTherefore, the answer is 1/3 x 1/8, or 1 x1 over 3 x 8.  1 x1 = 1, and 3 x8 = 24, so you wind up with 1/24.\n\nWhen I first learned how to do this, I wanted to divide rather than multiply.  But you multiply the fractions, and, as I said, top numbers go with top numbers and bottoms with bottoms.  Good luck!!
66293
can you repeat numbers?\nif not\nfor the first digit you get 9 choices\nfor the second one 8\nfor the third 7\nand the forth 6\n\nso the total number is 9*8*7*6= 3024 combination\n\nif you can repeat numbers 9^4=6561\n\n(if you could use the zero, and were allowed to repeat numbers the answer would be 10^4=10000;that numbers from 0001 to 9999 and 0000, a total of 10,000 numbers)