Complete the ordered pairs for the equation 2x + y = 10 (5,?), (?,10), (?, -2), (0,?)?
486558
Easiest way to resolve this is to rearrange the equation for either x or y:\n\nx = (10-y)/2\n\ny = 10-2x\n\nSo if you already know y, then you use the first equation, and if you know x, then use the second.\n\nFor example, the first one would require using the second equation: y = 10 - 2 x 5 = 0, therefore first one is (5,0).\n\nThe next one would require using the first equation: x = (10 - 10) / 2 = 0, therefore the second one is (0, 10).
676814
First equation: sqrt[x] + y = a\nor sqrt[x] = a - y\nSquaring both sides\nx = (a - y)^2__________(1)\n\nSecond equation: x + sqrt[y] = b\nor sqrt[y] = b - x\nSquaring both sides\ny = (b - x)^2___________(2)\n\nSubstituting 'x' from eqn. (1) in eqn. (2)\ny = [b - (a - y)^2]^2\n  = [b - a^2 + 2*a*y - y^2]^2\n\nSo it is clear that you have to solve a 4-th order equation.\nIt is really tough.
599677
i know how 2 do this.\n4x+2y=2\n x-2y=8\n---------\n5x   =10\n5x=10\nx=10/5\nx=2.\nsubstitute x=2 in any1 of the equations.\nlet us take x-2y=8.\n  2-2y=8\n  -2y=8-2\n  -2y=6\n    y=6/-2\n    y=-3.\n therefore ur x=2 nd y=-3.
298404
4x+y=10\n\n6x-y=20 \n+y   +y\n_______\n6x = 20+y\n-20  -20\n6x-20 = y\n\nreplace 6x-20 in for y with the other equation\n\n4x+(6x-20)=10\n10x-20=10\n+20     +20\n10x=30\nx=3\n\nnow plug in 3 in the equation as x\n\n4x+y=10\n4(3)+y=10\n12+y=10\ny=-2\n\nso x=3 and y=-2\nI think\n_____________________________\nAnother way to do it is get y's alone and set them equal\n6x-20=10-4x\n10x-20=10\n10x=30\nx=3\nand then just plug in like what I did b4
714041
10x+4y+4\n\nor can be written as y= -2.5x-1
778763
1) (a - b)(x - y)\n2) (x^9 + y^3)(x^9 - y^3)\n3) (6x + 5)(x + 8)\n4) (x - 9)(x - 7)
1076564
What do you want to solve for? x? y? or do you want an ordered pair (x,y) that works (integers maybe?)
913334
x^2 + 2x + 7 Remainder 10\n\ni can add the steps if you don't think i did it by hand
733627
Rewrite the equations as:\ny = -x + 2 and\ny = (x+10)/2 = 1/2*x +5\n\nNow, if you insert x=0 in each equation, you will get a y-value.\nIf you insert y=0 in each equation, you will get an x-value.\nFor each line, you can use those two intercepts to graph the line.
699742
-(3x+y)(3x-y)\n-(9x^2-y^2)\ny^2-9x^2
86546
(3y+1)(-2)+y\n-6y-3+y\n-5y-3\n\n12s+(7-s)2\n12s+14-2s\n10s+14\n\n7x-3x(x+1)\n7x-3x^2-3x\n-3x^2+4x\n\n3t(t-5)+6t^2\n3t^2-15t+6t^2\n9t^2-15t\n\n4w^2-w(2w-3)\n4w^2-2w^2+3w\n2w^2+3w
1162328
1) -  Y-2x-8 = 0 - so Y=-2x-8\n2) -  Y^2 +8x=0 - (-2x-8)^2+8x=0 \n\n\n4x^2+32x+64+8x=0\n\n4x^2+40x+64=0 - so (4x+8)(x+8)=0 so x=-8 or 4x=-8, x=-2\n\nWhen x=-8, Y-2(-8)-8=0 so Y=-8    A=(-8,-8)\nWhen x=-2, Y-2(-2)-8=0 so Y=4     B=(-2,4)
413913
x=0,2,3,4 and y=1,-1,0,3
103832
Place one equation below the other and add:\nx-x elimates x\n-3y+2y = -y\n9+1 = 10\nso -y = 10\ny= -10\n\nso x --3*10 =9\nx=9-30\nx = -21
895237
you do not get specific values, there are infinite number of solutions for each equations\n\n2x + y = 9, y= -2x + 9\n\n-x - y = - 8, y=-x+8\n\n- 3x + 4y = 2, y = 3x/4 - 1/2\n\n- 2x - y = - 3, y= -2x +3\n`
704540
Add the two equations together: (2x+y)+(x-y) = 1+8, so 3x = 9, x = 3.  Then 2*3+y = 1 so y = -5.\n\nSteve
94721
y= 2x + 11 and y=-x + 5 \n\n2x + 11 = -x + 5\n3x + 11 = 5\n3x = -6\nx = -2\n\ny = -(-2) + 5\ny = 2 + 5\ny = 7\n\n(-2, 7)