ADesignSurfaceOfABaloonis 2cmWide WhenTheBaloonHolds 41cm^3airHowMuchAirDoesTheBaloonHoldWhenThedesignis10cm w
485421
well u need to consider the formula of finding the wolume of a sphere. formula is 4/3*pi*r*r*r. so when the balloon is 2cm wide it has a radius,r, of 1cm. so v=kr*r*r. when the design is changed to a width of 10cm. the radius is now 5cm hence going under an increase of 5. the new radius is 5 times the first radius. so the nex volume=k5*5*5*r*r*r=125*k*r. so the new volume is 125*41=5125. (i have a query with the problem though since it did not follow the formula, 4/3*pi*r*r*r does not equal 41. usually a balloon even though is not a perfect circle is considered to follow this formula. if the balloon you are talking about is not a sphere shaped ballon then i would undersatnd why the formula does not apply and in that case the explanation i gave would be inacurate. check on that before you take my answer as right. i just gave you what i think is right based on what i understood of the problem. good luck.)
445986
Just multiply the three numbers together - length * width * height.
389991
height times the base area. divided by three.
784249
Sides on a fifty pence piece
921006
Area = πab where a and b are the semi-major and semi-minor axis length
940435
Width is 52cms & height 88 cms
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.
67968
It is similar to calculating the area. \n\nIt is a product of Length and Width (L x W).
374839
273\nMultiply .42 by 650
317924
See previous answer--\n\nGives vertical height as rt27\n\nTherefore 1/2*6*rt27 is area of one side\n\nBase is 6*6 = 36
799188
The time should be about 3 sec, so you have bad input data.  The height you calculated IS correct for 37.88 sec
737308
I agree, your resolution isn't correct. Adjust and rescan. If that doesn't work send it to me and I'll see what I can do. amateur_designs@yahoo.com
765616
Since the volume is 1000, \npi*(r^2)*h = 1000, and so you can express h in terms of r.\n\nCall the cost per sq cm of the wall 1 unit.  Then the cost of the ends is 2 unit per sq cm.  Apply the areas, and get\ncost of wall = 2*pi*r*h  =  (sub in the expression you got above for h in terms of r)\nCost of ends = 2*pi*(r^2) * 2\n\nWrite f(r) for total cost, and as usual differentiate etc to find minimum value of r.  Obviously r and h must both be positive, and that's the only restriction on the domains.  Hope you can do it yourself from here.  You need the exercise and I don't.
191332
Find the dementions and multiply.
440360
1000CM^2 = 10000000mm^2
1079085
use this formula\n55x54x53x52x51/120
1111648
200 x 200\n\nor\n\n40, 000 colors