Question about ferson optics?
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Give Ferson optics a call\n\n5801 Gulf Tech Drive\nOcean Springs, MS 39564\n(228) 875-8146 Phone\n(228) 875-5947 Fax
1168909
Check out the University of Rochester in NY they also have a well known optics/laser program
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It's a great toy. A 60mm aperture (2.4") won't gather much light (which also determines the amount of detail you can make out at higher magnifications). Is this a refractor? Cheap models suffer from various distortions produced by inferior coatings, poor collimation, etc.\n\nYou can see a long way (moon, mars, stars, etc), but thre real question is how good the image is (fuzzy, dim, etc)\n\nTry the following website (page goes to a celestron 760 mm refractor - a decent instrument. Lots of description.)\n\nhttp://www.telescope.com/jump.jsp?itemID=116608&itemType=PRODUCT&path=1%2C2%2C4%2C13&KickerID=699&KICKER
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Screen savers help but i WOULD RECOMMEND antireflective coated lenses. Also get up and get away from the monster for breaks.  Better light  works the best.
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I did find 0.47 for the refraction index "http://www.robinwood.com/Catalog/Technical/Gen3DTuts/Gen3DPages/RefractionIndexList.html" but I I do not know at what wave lenght that I am not seeing probably for green or blue. I found another values has well following:\nhttp://engr.smu.edu/ee/smuphotonics/Modeig/pages/MISC/RNCRIM.DOC\nn=0.18+i*5.72 for 900nm (near infrared)\nn=0.08+i*4.98 for 827nm (red)\n\nI do think it changes a lot with the wavelenght that you input\n\nI do not now if you know what the i means but is the imaginary part of the refraction index it reflects the absorption that light will suffer in the metal. Gold has a metal behaves to the the light much has it behaves  the plasma ones it has free electrons. This explines 2 things the imaginary part and second the value that is minus then 1. the imaginary part is due to the current that are induced when the light incidates in the metals it creates a current that consequently creates an energy lost. (ohm`s theorem) second the efect that is minus then one reflects that the phase velocity seams to propagate at a velocity larger then the velocity of light in vacuum ( its a rouder normal stuff in plasmas if you want to know more tell me I can inform you). Atention this does not mean that the energy travels faster then c it just means the phase does. \n\nif you want me to tell you why is it faster then light it is a litle bit more complicated but if you insist tell me
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Mostly clarity, a well focused image across the whole field of view with well focussed crosshairs. Has he suggested a magnification? Does he want variable power? For fixed power I mostly go with 6x for hunting, higher magnification seems to make it slow to get the sight picture right and acquire the target. For variables something in the 2-7 to 4-12 range should do, 3-9 is the most popular (or was). I'd be interested to hear any alternative views on those. \n\nWaterproof and fogproof too, don't want to forget those. You need to ask if he want's glossy, matt or stainless too, it would be a shame to get him the wrong thing, if he's bothered.\n\nFor best brightness the objective diameter should be 7x the magnification, so a 4x28 gives a 7mm exit pupil, which means that the light it gives out can all be taken in through the pupil of an eye. If you have a 10x40 then the exit pupil is 4mm and only about half the pupil diameter of the human eye receives light. That's why we find funny numbers like 8x56, 6x42, 4x28 and also why a lot of sailing binoculars are 7x50. This is at the esoteric end of things though, focussed is much more important.\n\nCabelas is another Leupold stockist.
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ok here is the thing\nif you are trying to calculate the thickness of a piece of paper you will need some equpment. Even though there is a lot of room for human error you still can get a fair estimate. \n\nwhat you need is 2 extrememly smooth glass plates and a lineat light source say a laser pointer. \n\nput one glass plate on a table place your paper on the side of the glass and put the other glass plate on the top of the two so that you will get a wedge between the two glasses. \n\nnow point the laser pointer perpendicular to the bottom glass plate and place a screen for reflections. you will get multiple reflections. (btw you need to know the frequency of the light emitted from the pointer.)\n\nthis is the set up\nfor calculations do a little search on air wedge interference \n\ni dont think you will need refractive indexes since you are using the same glass\nwith a little algebra you can figure it out
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The outgoing intensity is found by applying the effective transmittance of each of the three polarizers, in order.  Assuming ideal polarizers:\n\n(I out) = (I in) * (50%) * (cos(24))^2 * (cos(45-24))^2\n\nso (I in) = (2.3 W/m^2) / (0.5) / (.834565) / (.871572) = 6.324032\n\nor about 6.324 W/m^2\n\nNote that this assumes the 45 degree angle is measured in the same rotation direction (e.g., both CCW) as the 24 degree angle.  If the 45 degree angle is measured in the other direction (e.g., CW rather than CCW), then the factor (cos(45-24))^2 should instead be (cos(45+24))^2, which would give the value of 42.918 W/m^2 for the intensity of the incident light.
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Something is wrong with this question. I see it is 2 months old and would write directly if you allow email.\nI think the question should be about the object not the image. If the object is at the focal length of the lens, then the rays are parallel and easy to see with the eyes. The only image is on the inside of the eye.\nIt doesn't make sense to have length anywhere.
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I do hope this helps with your studys.\nIn optics, chromatic aberration is caused by a lens having a different refractive index for different wavelengths of light (the dispersion of the lens). The term "purple fringing" is commonly used in photography, although not all purple fringing can be attributed to chromatic aberration.\n\nLongitudinal and lateral chromatic aberration of a lens is seen as "fringes" of color around the image, because each color in the optical spectrum cannot be focused at a single common point on the optical axis.\n\nSince the focal length f of a lens is dependent on the refractive index n, different wavelengths of light will be focused on different positions. Chromatic aberration can be both longitudinal, in that different wavelengths are focused at a different distance from the lens; and transverse or lateral, in that different wavelengths are focused at different positions in the focal plane (because the magnification of the lens also varies with wavelength).\n\n Minimizing chromatic aberration.\nThere exists a point called the circle of least confusion, where chromatic aberration can be minimized. It can be further minimized by using an achromatic doublet or achromat in which two materials with differing dispersion (usually crown and flint glass) are bonded together to form a single lens. This reduces the amount of chromatic aberration over a certain range of wavelengths, though it does not produce perfect correction. By combining more than two lenses of different chemical composition, the degree of correction can be further increased, as seen in an apochromatic lens or apochromat.\n\nMany types of glass have been developed to reduce chromatic aberration, most notably, glasses containing fluorite. These hybridized glasses have a very low level of optical dispersion; only two compiled lenses made of these substances can yield a high level of correction.\n\n Chromatic aberration of a single lens causes different wavelengths of light to have differing focal lengths. For an achromatic doublet, visible wavelengths have approximately the same focal length. Diffractive optical element with complimentary dispersion properties to that of glass can be used to correct for color aberration. An achromatic doublet brings two wavelengths to a common focus, leaving ultraviolet and infrared uncorrected and out of focus.The use of achromats was an important step in the development of the optical microscope.\n\nAn alternative to achromatic doublets is the use of diffractive optical elements. Diffractive optical elements have complimentary dispersion characteristics to that of optical glasses and plastics. In the visible part of the spectrum, diffractives have an Abbe number of -3.5. Diffractive optical elements can be fabricated using diamond turning techniques.\n\nRead more about it at the following web site below.\n\nAs for the type writer question here is the answer to that.\nA typewriter is a mechanical, electromechanical, or electronic device with a set of "keys" that, when pressed, cause characters to be printed on a document, usually paper.\n\nIn the late 19th and the start of the 20th century a person who operated such a device was sometimes also called a typewriter but it then became more common to call the person a typist.\n\nFor much of the 20th Century, typewriters were indispensable tools in business offices and for many (if not most) professional writers. By the 1980s, however, word processor applications on personal computers largely overtook the tasks previously done with typewriters. However, typewriters are still popular in the developing world, and among some niche markets.\n\nAs of 2006, the following companies manufacture typewriters and accessories: Smith-Corona, Olivetti, Adler-Royal, Olympia, Brother, and Nakajima. Olivetti is the only western company to currently manufacture manual typewriters. All other current models are electronic.
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Light reflected from surfaces like a flat road or smooth water is generally horizontally polarized. This horizontally polarized light is blocked by the vertically oriented polarizers in the lenses.\n\nThe result: a reduction in annoying and sometimes dangerous glare.\n\nsee the link for a more scientific discussion on polarization
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deviation= (refractive index -1)*angle of prism\n\nif prism angle is small...\nand\ndependence of rf with wavelength is given by cauchy's formula\n\nrf= A/wavelength....  A is constant\n\nso dependence (deviation) proportional to [(1/wavelength) -1)]
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The glass is polished to a very smooth surface--any one of several means might be used, depending on what shape the mirror is supposed to be.\n\nThat done, an electrically conductive layer is applied, and metal is electroplated onto it.  On the whole, the electroplating is done slowly, because that produces a much better surface.\n\nSome mirrors, however, rely on a trick involving the index of refraction; put two layers together where their indexes of refraction have just the right relationship, and you get reflection.\n\nThe easiest trick, of course, is to take a material that will polarize light.  You take two layers of it, and rotate them so that they are trying to polarize light at right angles to each other (Say, one's twisting the light 45 degrees left, and the other layer is trying to take it 45 degrees right), slap 'em together and you have a mirror.\n\nIt is this last trick that is used to make the sunglasses you can see out of, but that look like mirrors to others trying to look in.
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LGP depends on the area of the objective lens/mirror.  Area depends on the square of the diameter.  So take the ratio of their diameters (express them both in the same units first!) and square that ratio - that will be your answer.
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LOL! Um take it to an optician. Be sure to pay him!
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the angle between the incident ray and the perpendicular to the reflecting or refracting surface at the point of incidence
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How about a polarized lens