if it is a 20 min ride to the rink,if for every 5 min,2 miles were covered ,how many miles is it all together?
485266
Divide 20 by 5 to see how many 5 minute increments are in the trip, then multiply by 2 for the miles covered.\n\n20/5 = 4*2=8
942078
This is Geography? miles = 20(hrs_up+10/60)=60hrs_up\n200/60=40hrs_up\nhrs_up=5/60 hours \ndistance = 60*5/60 = 5 miles
487924
If you're talking about JUST the sweater (uniform), 5 seconds.\n\nOK, seriously... I don't know how you other guys can do it in 3-5 minutes!!!  When I was your age (oh God, I promised I'd never say that), I could do it in 7 minutes, TOPS.  Usually I would take 25-30 minutes.  2-3 minutes per skate, 5-10 minutes of locker/game talk, 10 minutes for pads/breezers/sweater, 5 minutes for tape and misc crap.\n\nBut now for my leagues, I try to put on half of my stuff before I leave the house.\n\nGoalies - double it.  Whatever it is, double it.  If you have 25 lbs of gear, double it.  If it takes you 2 minutes to piss, double it.
522298
look there's a 1&#92;6 because there are 2 hours(120 minutes)\n20 minutes is just 1&#92;6 of 120 minutes. is simple
569860
The official size of the rink is 200 feet long and 85 feet wide. The corners are rounded in the arc of a circle having a radius of 28 feet.
757576
To solve this problem, you need to find the time the bus needed to travel the 200 miles.  You should divide this problem into 3 intervals:\n\n1) 150 MPH for first 50 miles\n2) 125 MPH for 2 minutes\n3) 150 MPH for reaminder of trip\n\nFor interval 1, we need to caclulate the time taken to travel 50 miles:\n\n(50 miles)(1 hour / 150 miles) = 1/3 hour = 20 min\n\nFor interval 2, we needed to calculate the distance traveled in order to solve for interval 3:\n\n(125 miles / 1 hour)(2/60 hour) = 25/6 miles\n\nNow, we can find the # of miles for interval 3:\n\n# miles = 200 - (50 + 25/6) = 875/6 miles \n\nNow we can find the time needed to travel this distance:\n\n(875/6 miles)(1 hour / 150 miles) = 35/36 hour (around58 min)\n\n---------\n\nTo find average speed, you need to take [total distance/ time].  therefore,\n\navg. speed = [200 miles]/[(1/3) + (1/30) + (35/36) hr] ------->\n\n149.38 miles per hour\n\n------------\n\nHope this helps
723417
eh, forwards...playing the whole game...about 4 miles?...mids...6-7....defenders (depending on how bad your mids are) about 5....goalies about...50 feet
742241
The second problem is easier than the first problem, so I'll tackle it first.\n\nLet's imagine that the trip is 120 miles. The distance doesn't matter if the average rates are as given above.\n\nIt takes 3 hours to travel 120 miles at 40 miles per hour.\nIt takes 2 hours to travel 120 miles at 60 miles per hour.\n\nSo it took 5 hours to travel a total of 240 miles.\n\nThis is an average rate of 48 miles per hour.\n\nI'll work on the first problem and hopefully I'll get back to you.\n\nUPDATE\n\nI think I have the first problem solved as well. It involves an infinite series! Call the people involved A and B.\n\nThe probability that A wins on the first toss is 1/2.\n\nIf A doesn't win on the first toss, then the probability that B wins on the second toss is also 1/2. But this only happens in 1/2 of all games. (In the other half, A won on the first toss.)\n\nIf B doesn't win on the second toss, the the probability that A wins on the third toss is also 1/2. But this only happens in 1/4 of all games (In half the other games, A won on the first toss. In half the remaining games - 1/4 of all games, B won on the second toss.\n\nFollowing this logic, A wins:\n\n1/2 + 1/4(1/2) + 1/16(1/2) + 1/64(1/2) + ...\n\nof all games.\n\nB wins:\n\n1/2(1/2) + 1/8(1/2) + 1/32(1/2) + ...\n\nof all games.\n\nLooking again at A, we have:\n\n1/2(1 + 1/4 + 1/16 + 1/64 + ...)\n\nThe term in parentheses is an infinite series having initial term 1 and ratio 1/4.\n\nThe sum of an infinite series having ratio whose absolute value is less than 1 is equal to:\n\na/(1 - r)\n\nWith a = 1, and r = 1/4, the sum = 4/3. So:\n\n1/2(1 + 1/4 + 1/16 + 1/64 + ...) = 1/2 * 4/3 = 2/3\n\nLooking again at B, we have:\n\n1/2(1/2 + 1/8 + 1/32 + 1/128 + ...)\n\nThis sum should be half of the sum of the infinite series in A.\n\nWith a = 1/2 and r = 1/4, a/(1 -r) = 2/3\n\nSo:\n\n1/2(1/2 + 1/8 + 1/32 + 1/128 + ...) = 1/2 * 2/3 = 1/3.\n\nA should win 2/3 of the time, and B should win 1/3 of the time. There is an advantage to going first!
910005
.8 *10= 8\n\nso the question is at a speed of 18 miles per hour how long would it take to run 8 miles. \n\n18 miles / 60 minutes = .3 miles per minute\n8 miles / .3 miles per minute = 26.667 minutes
104070
Heather leaves a town at 2 p.m., going 56 mph, traveling east. Erin leaves the same town at the same time going 64 mph, traveling in the same direction. What time of day will it be when Erin is 72 miles ahead of Heather?\n============================================================\n\nHeather's distance = 56x\nErin's distance = 64x\nx = hours traveled\n\nThe distance between them at any time can be expressed as a simple equation:\n\nd = 64x - 56x\nd = 8x\n\nYou want to find "x" when d = 72 miles:\n\n8x = 72\nx = 9 hours\n\n2:00 p.m. + 9 hours = 11:00 p.m.
100012
A would take 22 minutes to get to 15 miles and 32 minutes to get to 20 miles. Unfortunately, there's insufficient information to be precise on B's journey. Did he spin off before the start?.. or at which point en route? Guessing it, I would say A arrived at 15 miles and at the 20 miles point first. NB. I have had to make certain assumptions in your question to arrive at this answer (eg I asumed A slows down to 40mph after 4 miles?)
930279
Twice as long as it is from one to the middle!  How did I do?  This is the correct answer by the way.
735212
I'm going to use minutes instead of hours.\nWe know that on the first trip, D = 120S (D=distance, S=Speed of first trip).\nWe know that one the second trip, D = 90(S+6).\n\nTherefore 120S = 90S + 540, or 30S = 540, and S = 18kph.\nTherefore the distance is 36 kilometers.\nChecking, 24(1.5) for the second trip also = 36.
1001541
260 miles.\n\nFrom the half-hour difference we can find the length of the hill:\n\nt = d/v, t2-t1 = d (1/v2 - 1/v1)\nd= .5/(1/72-1/90) = 180\n\nThis takes 2 hours at 90 mph, so the other hour covers 80 miles.\n180+80=260
736136
6.6_ miles (the _ means repeating).\n\nhttp://www.google.ca/search?hl=en&q=10*%282%2F3%29&btnG=Google+Search&meta=
90024
Most NHl rinks are 200 feet long by 85 feet wide but some are slightly different.\n\nInternational rinks are wider by about 10 feet but I am not 100% sure of the exact dimensions.
799226
They travelled a total of 476 miles in 4 hours.  So together they are travelling (476/4) mph or 119 mph.\n\nSo you have two equations:\nJ + S = 119\nJ - S = 5\n\n2J = 124\nJ = 62 mph\nS = 57 mph