"Heading"," Bearing" & radials  used in aircraft navigation measured  in respect to true north or mag north
493587
Magnetic North of course because they use compass.
716991
http://www.21stcenturysciencetech.com/articles/fall01/navigators/navigators.html\n\nIs that what you mean?
48460
Rocket Man is not correct.  The angle that measures an east-west position is called Right Ascension (R.A.).  Declination is an angle for a north-south position.  \n\nHowever since you use the term horizon you may mean azimuth which works in a similar way.  Due north is 0 degrees azimuth and increases in a clockwise direction (90 degrees is east and so on.).  Again you could mean altitude which is 0 degress at the horizon and goes up to the zenith (90 degrees) in any direction.
488481
True north would be a line from your position to the geographic north pole.\n\nMagnetic north is a line between your position and the northern magnetic pole.  \n\nSince the northern magnetic pole does NOT coincide with the geographic north pole (IIRC, it is somewhere in northern Canada), there is a difference between those two lines.  The magnitude of that difference depends on precisely where on the earth you are standing when you take your measurement.\n\nThat's why, on all good topographic maps, they have an indicator of both magnetic north and true north, so you can apply the appropriate correction to navigate with a compass.  Of course, global positioning systems are making that problem a non-issue (if you can "see" the satellites . . .).
629527
Pilots have to adjust their flight paths to compensate for the Coriolis effect.  This is something we can calculate.
1170794
you let the navy do the work for you!!!  check out this awesome altitude/azimuth calculator!\n\nhttp://aa.usno.navy.mil/data/docs/AltAz.html
38995
In this situation a compass needle will not point to anywhere on the dial very strongly - it will just wander around weakly with no real direction. Explorers now need GPS to determine the exact pole location; it shifts slightly every year.\n\nDC :-)
115436
With a Magnetometer. See below for more detail.
1121613
Check this one\nhttp://science.nasa.gov/Realtime/jtrack/3d/JTrack3D.html
481113
It depends on what kind of mount you have, it seems you either have a German equitorial or an altazimuth mount.\nIf you are leveling & alighning on polaris and the blank end has a reference mark & 0 deg. north on the scale is in the center of two tripod legs the zero faces south.
828817
I like the Suunto compass.  The KB-14 series compasses have a unique sighting arrangement so that you can shoot a bearing to better than half a degree -- far more accurately than any other compass I have ever seen.  But they are expensive -- they run about $100.
1100581
First there are 3 north poles. There is magnetic north which your compass will point to, There is the North Pole the earth rotates on and then there is North which would be the top of the earth as compare to the sun and its orbital plane. We can also refer to north based on the position of the galaxy and assigning one end as North and the other as south. North and south poles are used in navigation after the discovery of the compass needle always pointing north.
1132574
check this out:\n\nhttp://gpsinformation.net/
965618
compass or directional legend,.
112005
you need a map of where you are camipng to read a compass correctly.  to read a compass stand still untill the compass stops moving.  then read where you want to go 0 is north 90 is east 180 is south 270 is west and 360 is again north
805477
"Heading" confuses me, because I don't know what it means.  I assume you mean the plane went 150 miles in a direction 42 degrees west of north, then 105 miles in a direction 52 degrees west of north.  In other words, when he changed course, he went 10 more degrees toward the west.\n\nIf that's right, then he ended up\n\n150 cos 42 + 105 cos 52 = 176.1 miles north of his starting position, and\n\n150 sin 42 + 105 sin 52 = 183.1 miles west of the starting position.\n\nPutting them together, he ended up\n\nsqrt(176.1^2 + 183.1^2) = sqrt(64546) = 254 miles from his starting position.  (Answer)\n\nBecause that course change was so slight -- only ten degrees -- it's almost like he traveled in a straight line.  He flew 255 miles total, and ended up 254 miles away.  The course change only cost him one mile in total distance.
338257
a) vcenter = (m1*v1+m2+m2)/(m1+m2)\n\nb) v1 rel = v1 - v center\nv2 rel = v2 - v center\n\nremember velocity is a vector so you must keep track of magnitude and direction