On a nautical chart, what is the small number below the large number in depth soundings?
490701
One is in meters the other is in fathoms (2 yards or 1.83 meters). A fathom is an old English nautical unit of measurement
756047
When its actual length is at least a number plus a half but less than the next higher number.
1110962
Mu,\n\ni.e. The question is incomplete, part of the ship will be above water, part below, depending on the exact nature of the ship and the position of the ladder a differing amount of steps will be visible when it is floating.
875881
what size boat are we talking about?
227503
To be in scientific notation, the decimal point which is now at the right end of the number must be moved to the left until it is after the first non-zero digit.  That takes five place moves for the decimal point.  This number of moves, 5, becomes the exponent of 10.  The extra zeros after the decimal point are dropped (unless the 200,000 is accurate to the ones place).  So your answer is 2 x 10^5.
792914
Yep.  If you put a 1000 ton boat in the ocean, the level rises just as if you put 1000 tons of salt water in the ocean.  Don't try to measure it though.
925623
1.10\n\nthat's the nearest ten ...look..\n\n1.11 take away 1...would be 1.10...and that's the nearest 10 and if it was 1.45 the nearest ten would be 1.50..because when you come to a 5 you always round up not down.\n\n1.63 would be 1.60 because 1.60 is nearest to 63 than 70 would be.\n\n2.67 would be ..2.70 because it's nearest to 70.\n\nHope that's clear enough?
712115
A map's scale is a ratio that relates a unit of measure on a map to some number of the same units of measure on the earth's surface.\n For instance, a map scale of 1:25,000, tells us that 1 unit of measure represents 25,000 of the same units on the earth's surface. One inch on the map represents 25,000 inches on the earth's surface. meters or yards or kilometers or miles, respectively, on the earth's surface.
792624
An absolute chart lists numbers that have relationships that are measurable in an exact way. \n\n4 miles is always twice as long as 2 miles.\n\nA relative chart lists numbers that have a relation that is not measurable in an exacting manner.\n\n10 degress celsius is not twice as hot as 5 degress celsius.
765094
Looks like the first answerer has no idea of what you're asking.\n I'll walk you through the math.\n1 atmosphere is equal to 1.01325 bars\nYou get a 1 atm change for every 33 feet in depth. We also have to take into account 1 atm already present at the surface. \n So:\nLets convert the bars to atm's\n20  divided by 1.01325 = 19. 738465 and change.\n That gives you your number of atmospheres equivalent to 20 bars.\n Subtract 1 atm for surface air pressure. This leaves you with 18.738465 atmosphere's to find the depth.\n We know that 1 atm is approx 33 feet in a column of water so \n18.738465 X 33 = 618.369345 feet\n There you go. To get a 20 Bar pressure, you need to be at 618 feet. approximately. Pretty dark down there.\n\nEdit to muddiver.\n \n Appendix C of the USN divers manual contains phone numbers for NOAA and the experimental diving unit, nothing but phone numbers. :)\n What you are referring to is in chapter 2 2-12 table 2-10 and the numbers actually are 33.9139 FW  and 33.066 FSW to a bar in there. I used the standard recreational scuba numbers in my calculations above as they're used more widely and 33 (the accepted standard) is an easier number for everyone to remember and rounded the numbers for the same reason. Also, you forgot to include surface air pressure in your result. That induced an error of an extra atm or 33 feet deeper than the actual result really is. Fine for ultra conservative deco schedules but not the answer he was going for.\n I own the book by the way. :)
461036
http://geography.about.com/cs/countries/a/numbercountries.htm
1116088
You need to know the length of a line if you want to know the amount that it departs or its longitude. \n\nIf you want to know where on the globe that is... its someplace between seattle, washington and portland, oregon
495045
When you are rounding a number to two significant figures first simply write the first digit (5) and then look at the third digit. If it is above or equal to 5 then incrase the second digit. If the third digit is below 5 then keep the second digit is kept the same.\n\nThe remaining digits are then just replaced by '0'\n\nIn this case O is below 5 so the second digit is kept the same. The remaining digits are then replaced by zeros. Thus we get 5200\n\nThis is a rather an irrational approach to it. Rather when rounding to two significant figures the want you to choose between two values of which one is closer to the given one. In this case they essentially want you to determine whether or not 5206 is closer to 5200 or 5300. Thus if you had to 'simplify' the number, which would give less error!
845231
I love this page. It help me a lot on my paperworks.\ngood source.\n\nhttp://bodc.ac.uk/data/online_delivery/international_sea_level/\n\nand you might need this (glossary) in guiding youte short froms\nhttp://www.bodc.ac.uk/help_and_hints/glossary_and_acronyms/
281745
Navigation with trig uses the basic principals of the patagorean theorem (a squared + b squared = c squared), sin (pronounced sine), cosin (pronounced co-sine), and tan (tangent).  If you remember the helpful hint SOH CAH TOA (pronounced so-cah-toe-uh) it will help you to remember sin = opposite over hypotenuse, cosin = adjacent over hypotenuse, and tan = opposite over adjacent.  These refer to the sides of a traingle.  Draw a right trinagle (that is a traingle with a right angle in it).  To find any one of the angles, you use what I described above (if you know the length of the sides).  You can mix the equations up and solve for any part of it that is unknown if you know the other two.  Now, back to your question...  A navigator will usually have a chart (map) with a scale on it (measurement on the paper).  With this he / she can tell the distance between any two points, thus giving the length of the side of a traingle.  If they do this from a couple of different points, it is called "triangulation".  Now they have the "triangle", they use the stuff above to figure out the angles, distances or whatever.  Finally, they use a formula of distance = rate x time (D=RT) and variations of it (T=D/R, and R=D/T).  Let's say the navigator want to know how long it will take to get from point A to point B.  They use what I've described above to measure the distance (D), and they know how fast they are traveling (with a speedometer or airspeed indicator, etc).  Now they can use T=D/R to figure out how long it will take to get there.  In "old" times, the accuracy of charts and maps was not quite up to par, so they used the "stars" as thier maps.  these were "known" quantities, with specific angles to the horiozon (which remained fixed).  The device they used was called a "sextant".  This gave them a reading of the angle.  They would also used an hourglass for time, and a specially-made board with a rope with knots in it.  As they let out the board and it hit the water, they would "time" how many knots passed through thier fingers.  This gave them "rate" (or speed).  Using what I described above, they could figure out the rest.  Hope this helped.
273577
Go to Carl's Sail Calculator.  It allows you to do side by side comparisons of  various attributes and ratio's for most production sailboats.  It includes hull speed, capsize ratio, sail area to displacement, displacement to LWL.  Detailed explanation for all ratios is included.\n\nJust go to http://www.image-ination.com/sailcalc.html\n\nFair winds and following seas buddy.
110772
0.58 (with a horizontal bar right above the 58)