If you take 1 and / by 3 and then * the answer by 3, why can't you get back the original 1 as a whole?
482881
Ummmmmmmmm... no, yours is a calculator error ;)  if you divide an apple into 3 parts you can put them back together... you just have a serious logic issue ;)
1007006
add or subtract 1\n\nor else subtract the S at the begining of Seven
595633
When you are dividing by something you are trying to find out how many of a certain amount (say, 3) is in another amount (say, 12). The result for my example, is of course 4, since 3 goes into the number 12 four times.\n\nNow the number 0 is nothing, literally. So if you're dividing into, say 12, you're wondering how much nothing is in 12. That's just not possible, because 12 is all "something".\n\nI hope that's clear enough...I tried.\n\nEdit: The guy above me is wrong.
628270
Can't be...any age divided by 1 wouldn't leave a remainder...if you eliminated '1' from the equation, it would be 61
891258
Try 1 ÷ 3\n\n1/3 = 0.33333.....\n\n~ ♥ ~
882621
My old math teacher showed me this.\n\nSince A=B, then A-B=0, and you can't divide by 0
98782
Just substituting x for 0 yields -9/-3 = 3.  This is not the indeterminate form 0/0 hence the limit is obtained by substitution, ie the answer is 3.
1027973
the 3rd one is correct, but I get -(3+b)/b+2 and 2 for the first 2
845113
Since the "If" part isn't true, it nulls the rest of the question. Some people may not have caught it the first time around because they may not now how to multiply correctly without electronic help.
674900
When you have (a+b+c)/d, you can separate the terms of the numerator like so a/d + b/d + c/d.  If I do that and simplify, I get:\nx - (6/5) - (3/x).
471544
Technically it is 3\n\nMultiplication/division always comes before addition/subtraction, so that question becomes half of two (1) plus 2 (1+2=3).\n\nIf you were to bracket the (2+2) on the other hand, then the equation would become half of (2+2) = half of 4 = 2\n\n\nEdit: Haha, cheers aphanes.
131932
it cant but .99 repeating is equal 2 one!!!! o unless u do a number 2 the 0th power \nex. (5^0)+(2+2)
168776
The construction of negative numbers and rational numbers is much more complex than you think. So 3 over -1 is not an arithmetic operation and using the rules of abstract mathematics it can easily be seen it is true.
499912
So far you have been given the easy conversion(a\nnon repeating decimal). Now let's go to the next\nlevel. Suppose your decimal repeats. For example,\n.3... , the ellipsis(...) means the 3 goes on forever.\nPut the 3 in the numerator and a number in the\ndenominator with as many 9's as there are digits in the\nrepeating part of the decimal. In this case. just one 9.\nSo the answer is 3/9 which equals 1/3 as you would\nexpect. How about .45...  , which means the "45" repeats.\nThe answer is 45/99 which is reduced to 5/11.
732725
the denominator should not be zero\nso 3(x+1) should not be zero\nx+1 should not be zero\nx should not be -1
559152
are u sure its not supposed to be the other way around. Cuz that would make a little more sense.\n\nBut if not, then it would probably be:\n1 + ((4s squared - 11) / (s to the 4 - 3s squared -11))\n1 the quotient. the rest the remainder.
705864
Alright, don't listen to the above post...\n\nGrade 12 here, answering questions all day for mere fun.\n\n12)\ny - 3 = -1/3 (x + 4)\n\nEXPLAINED\n\nadd 3 to both sides\ny = -1/3 (x + 4) + 3\n\nexpand 1/3(x + 4) \n= x * 1/3 + 4 * -1/3\n= x/3 + 4/3\ny = -1/3x - 4/3 + 3\n\nTo add -4/3 and 3, use 3 = 9/3\ny = -1/3x - 4/3 + 9/3\ny = -1/3x + 5/3\n\nTrue, my bad. I originally added 4/3 instread of -4/3\n\n\n16)\n(-2, -1) (4, -4)\n\nm = Dy / Dx\nm = ((-1) - (-4)) / ((-2) - (4))\nm = 3 / -6\nm = -1/2\n\ny = mx + b\n(-1) = -1/2(-2) + b\n-1 = 1 + b\n-1 - 1 = b\n-2 = b\n\ny = -1/2x - 2\n\nCHECK\ny = -1/2(4) - 2\ny = -2 - 2\ny = -4\nTherefore it works.\n\n18)\n(0, 0) (2, 3)\n\nm = Dy / Dx\nm = ((3) - (0)) / ((2) - (0))\nm = 3/2\n\nb = 0\n\ny = mx + b\ny = (3/2)x + 0\ny = (3/2)x\n\nNote, the lower post copied my answers