How do i compute the volumne of a cylinder?
478313
V = h*pi*r^2\n\nThere h - height\nr - radius of foundation\nV - volume
29575
well, the formula for the volume of a cone is 1/3 * base * height.\n\nthe trick to doing this is to find the volume of the large cone, then subtract the volume of the small cone.  what's leftover will be the tumbler-shaped volume.  plug in numbers for the height and base for both the large and small cones, and then subtract. voila!
894074
Assuming the drop of water is a sphere or close to one...\n\nvolume of a Sphere = (4/3) * pi * radius^3\n\nTo find the volume of a drop, measure out a small volume of water into a graduated cylinder.\nUse a dropper to take drops and deposit them into another container.  Count the number of drops needed to empty the measured water.\nvolume of drop = measured volume / number of drops
180975
1.  Measure a gumball and calculate its volume.  Measure the cylinder and calculate its volume; multiply by 0.7; divide by the gumball volume.\n\n2. Count the number of gumballs vertically in the cylinder; this is h.  Count the number of gumballs around the circumference; divide by 3.14; divide by 2; this is r.  The number of gumballs is 3.14 x r^2 / h.
963784
tau = I*(alpha) where tau is the torque\nand alpha is the angular accelleration, \nI is the moment of Inertia = 0.5M*R^2 (for a cylinder)\nTau = r*F = 0.16m*40N \n6.4 = M*(0.0256)*90rad/s\nHence M = [6.4]/(0.0256*90)\nM = 2.78kg
804606
For cubic measure:  L x W x H = CI / 231 = G\nL = Length\nW = Width\nH = Height\nCI = Cubic Inches (Volume)\nG = Gallons\nMeasure the Length, Width, and Height in Inches.\n231 Cubic Inches to one Gallon.\nConvert Volume to Cubic Inches\nLength x Width x Height  = Cubic Inches  / 231 = Gallons\n\nFor Right cylinder measure: Pi x r'2 x H = CI / 231 = G\nPi = 3.14159\nr = radius (half of diameter) '2 = squared\nH = Height (or length)\nCI = Cubic Inches (Volume)\nConvert Volume to Cubic Inches. \nPi x r squared x H = CI / 231 = gallons
464437
Here is instructions on finding the volume of any prisim.\n\nhttp://www.math.com/school/subject3/lessons/S3U4L2DP.html
889350
to compute for the maximum height, the vertical component of the velocity is needed.\nSo Vy = 49sin30\n      Vy = 24.5m/s\n\nto solve for the max. height use the formula\nVy = sqrt(2*g*h)\nh=(V^2)/(2*g) = [(24.5m/s)^2]/(2*9.81m/s2)\nhmax = 30.594 m
969061
The only thing you need to figure that out is the height of the (i presume) circular cup. Just estimate it as a cylinder, or use some simple calculus to add a sloped cup.\n\nAnyways, the volume of a cylinder is pi*r^2 * h. or A * h  where A is the surface of the water.\n\nThe next problem is converting fl. oz to a volume in terms of distance measurements. I find this easiest to do in metric units, although if you spend some time you can figure it out in oz.\n\nso 1 US fluid ounce = 29.5735297 ml\n\n1 ml = 1 cubic cm.\n\nthus\n\n16 US fluid ounces = 473.176475 ml = 473.18 cubic centimeters.\n\n473.18 = A * h.\n\nSimply put in the height in centimeters and you've got the area.\n\nI don't know of any statistics about the average car cup holder dimensions although if you take a guess and imagine the one in your car, i'm sure it'll be close.
618423
A cylinder is round, therefore the largest diameter would be 7. The depth of the box is 2, so the height of the cylinder would be 2. the volume of a cylinder is found by multiplying the height of the cylinder by the area of its top (pi r squared). Now get back to your homework.
762991
Volume = pi * r^2 * h\n\nwhere\nr is the radius\nand\nh is the height\n\nFor example:\nr = 0.9m\nh = 1.2m\nvolume = 3.14159 * 0.9 * 0.9 * 1.2 = 3.0536 cubic metres or 3053.6 litres\n\n_
1129109
0.004vi = (1.110 + 0.004)vf\n\n(1/2)(1.114)vf^2 = (0.220)(1.114g)(0.300)\n\nvf^2 = 2g(0.220)(0.300)\n\nI think you should be able to do the rest...
529099
V = 2*pi[Integral r*f(x)]... where r is the radius of the cylinder... usually x\n\nSince ur integrating about x = -1...... the radius is x+1, yes x+1\n...if about the y-axis... the radius of the cylinder is just the x-coordinate or x-units... but since -1 is 1 unit from the y=axis.... the radius is x=1.......\n\nV = 2*pi[Integral (x+1)*f(x)]\nV = 2*pi[Integral (x+1)*(3x-x^2)]\nV = 2*pi[Integral -x^3+2x^2+3x]\nV = 2*pi[Integral -x^4/4+2x^3/3+3x^2/2]\nfrom 0 to 3\n\nV = 2*pi[45/4] = 45*pi/2
466950
Volume = Area x height\nArea = r x r x pi\npi is approximated by the fraction 22/7\nTherefore Volume of cylinder = 4 x4 x 22/7 x7 = 352 units^3
540563
weigh the graduated cylinder full with water.\ninvert the cylinder (still full) in a tub of water.\nblow bubbles into the cyliner to find the volume of the air you blew in.\nremove and reweigh the cyliner.\n\nit may be a little tricky, but it's not too bad.
358957
Volume = pi * r^2 * h\n\nr is 1/2 the radius of the drilled hole = (D'/2)\nh is equivalent to the diameter of the original cylinder = D
676849
Cylinder = PI r^2 x 6 r = 6PI r^3\nBalls = 4/3 x PI r^3 x 3 = 4 PI r^3\nratio = 4 PI r^3 / 6 PI r^3 = 4/6\n\nRatio = 2/3 of the space is used by the balls.