D={x|x is a whole number and x < 6} give in roster form?
480629
Whole numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, and so on.\nThe whole numbers that are less than 6 (x<6) are\n{0,1,2,3,4,5}
780025
x ≤ 5\n\n-- - - - - - -s-
744474
x=2y\n\n-2 -4\n0 0\n1 2\n3 6
781242
No,\n\n6-x=24\n6-x-6=24-6\n-x = 18\n\nx= -18
165476
How about (a+c)/(b+d)  ? more interesting!!\n\nbtw this only work when a/b != c/d
918264
IF you mean like an ordered pair it is a point on a graph.  An example is:  (x,y)  so you can have (3,5)  or (-7,-88)  Otherwise I'm not sure what you're talking about.
101082
(x-1)/4 > 3\nx-1 > 12\nx > 13
402424
f+12<18  Subtract 12 from each side.\nf < 6\nThus, the solution is all numbers less than 6.\n(-infinity,6) is called interval notation.\nSet builder notation:\n{f|f<6}\nSet builder notation is always enclosed in braces {}, and always starts out with f|\nThe vertical bar is read "such that"\nThus, {f|f<6} is read "f such that f is less than 6."\nAlso, the graph is a number line with a parenthesis, ), at 6 and then shaded to the left of 6.
725157
assuming the numbers after the parenthesis and variables are exponents...\n(x-1)^(3/2) [6x(x-1)^2-x^2(x-1)^3]\njust add the exponents together from the outside to the inside- (3/2) + (2) = 7/2\n\n(x-1)^(3/2) [6x(x^2-2x+1)-x^2(x^3-3x^2+3x-1)]\n(x-1)^(3/2) [6x^3-12x^2+6x-x^5-3x^4+3x^3-x^2]\n(x-1)^(3/2) [-x^5-3x^4+9x^3-13x^2+6x]\nx(x-1)^(3/2)(-x^4-3x^3+9x^2-13x+6)\nokay, that took me for friggin ever to type on a regular keyboard. Please, seriously consider me for the best answer!
312174
It seems undefined since for x <= 0 and x != odd number, x^x doesn't work out so well.  If it's x->0+, then it's just 1.
803653
2x>-10\ndividing by 2\nx>-10/2\n=x>-5
918808
wouldnt it be like 3<x<-3 f(x)\nso like x would be 1 so it would be just f if you really want to simply that far done.
195396
What's with the ... ? Is that a space for a number, are you supposed to guess whether to use the + or the x ? I don't get it, I think I'm gonna cry :~(
1036177
sory i didnt get ur Q\ndo u mean 2x-6>x ?\nthen x is greater than 6
739570
d2 - =int(c2/10)\n\neasy
333624
(ln x)^7=(7*(lnx)^6)*(1/x)=7*(lnx)^6/x
1034880
That's a stupid question.  x can equal anything equal to or greater than 7 and still be correct.  Unless you asked the question wrong.  \ni.e. If x=9 then the problems answer would be: 24.  24 is greater than 20.  So it fits within the variables you have listed: "greater than or =20"  \nBut if x=6 then the product would be 18, less than 20 and outside the variables you have listed.  \nSo the answer, according to your variables, is x=7 or anything greater.