slope -2; y-intercept 5?
488491
U could do y=-2x+5 or you could do y=-7x (I luv math)
806897
First equation:\n4x + 2y = 10\n\nRearrange to get the y-term alone:\n2y = 10 - 4x\n\nDivide both sides by 2 to get it in slope-intercept form (y = mx + b):\ny = -2x + 5\n\nNow you can graph it by drawing a line through (0,5) as the y-intercept and have it go down at a slope of -2 through points (1,3), (2,1), (3,-1), etc.\n\nFor the second equation, draw a horizontal line for y = 4\n\nYou'll see they intersect at the point (½, 4).  I've attached a graph of the two lines...\n\nSo your solution is:\nx = 0.5 (or ½)\ny = 4
468700
I'll calculate these, but I'll apologize now to those others who might already be doing this if I post my replies after yours.....\n\n1. x-intercept:2,y-intercept 1\nx-int = 2 at point (2, 0) = (x1, y1)\ny-int = 1 at point (0, 1) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (1-0)/(0-2)\nm = -1/2\n\ny = mx + b (now, b is the y-intercept)\ny = (-1/2)x + 1\n\ny = (-1/2)x + 1 (substitute other point for verification)\n0 = (-1/2)*(2) + 1\n0 = 0\n\ny = (-1/2)x + 1\n\n------------------------------------------------------------\n2. x-intercept:5, y intercept 5\nx-int = 5 at point (5, 0) = (x1, y1)\ny-int = 5 at point (0, 5) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (5-0)/(0-5)\nm = -1\n\ny = mx + b (now, b is the y-intercept)\ny = -x + 5\n\ny = -x + 5 (substitute other point for verification)\n0 = (-1)*(5) + 5\n0 = 0\n\ny = -x + 5\n\n------------------------------------------------------------\n3. x-intercept:-4,y-intercept -1 \nx-int = -4 at point (-4, 0) = (x1, y1)\ny-int = -1 at point (0, -1) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (-1-0)/(0-(-4))\nm = -1/4\n\ny = mx + b (now, b is the y-intercept)\ny = (-1/4)x - 1\n\ny = (-1/4)x - 1 (substitute other point for verification)\n0 = (-1/4)*(-4) - 1\n0 = 0\n\ny = (-1/4)x - 1
950053
It is a line with a slope of 1/5 and a y-intercept of 1.
928485
First solve for y to find the slope.\n5x - 2y = 10\nSubtract 5x from each side\n-2y = -5x + 10\nDivide everything by -2\ny = (5/2)x - 5\nThe slope is m = 5/2\nSince you want a line that is parallel, that means the slope of the new line will be the same as the slope of the old line.\nUse your point to find the equation.\ny - (-5) = (5/2)(x -3)\ny + 5 = (5/2)x - 15/2\ny = (5/2)x -15/2 - 5\ny = (5/2)x - 25/2
929126
The first thing you want to do is find the slope. That is, the change in Y over the change in X (Rise over Run). Each of these points are in the cartisian coordiante system, thus (3,-7) and (-5,2) are of the form (x,y). So lets find the slope!\n(y1-y2)/(x1-x2)\nUsing (3,-7) and (-5,2)\n(-7-2)/(3+5)=(-9/8)\nYour slope is (-9/8)\nNext to find the intercepts you use the equation of slope intercept form, Y=mX+b where X and Y are points, m is the slope and b is the y intercept. We know the slope and some points so we need to solve for b., the y intercept. Lets use the point (-5,2).\n2=-5(-9/8)+b\n2=(45/8)+b\n(-29/8)=b\nSo the point for the y intercept is (0,-29/8)\nNow we want to find what x is when y is zero for the x intercept. \nAgain use Y=mX+b but this time we know what b is. Set y=0. \n0=X(-9/8)+-29/8\n29/8=X(-9/8)\n29/-9=X\nThus, the x intercepts is (29/-9,0)
89344
Use the two given points:\n(x1=7, y1=5) and (x2=-1, y2=1/5)\nand the "two point equation":\ny-y1 = ((y2-y1) / (x2-x1)) * (x - x1)\nto get started on this problem.\n\ny-[5]=(([1/5]-[5]) / ([-1]-[7])) * (x-[7])\ny-5=((-24/5)/(-8))*(x-7)\ny-5=(3/5)*(x-7)\n\nNow put the equation into the "slope intercept" form of y = mx+b.\n\ny-5=(3/5)*x - (21/5)\ny=(3/5)*x - (46/5)\n\nThe slope = 3/5\nThe intercept = -46/5
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
974393
If you mean parallel to y=2x + 5, then the slope will be 2\n\nSo you need to use:\ny = 2x + b\n\nPlug in your point (-1, 4) and solve for b:\n4 = 2(-1) + b\n4 = -2 + b\nb = 6\n\nSo your line is:\ny = 2x + 6
568116
It has no y intercept cuz its a vertical line.\nIt's slope would be undefined cuz when you try to find the slope the normal way using two points, say (-7,4) and      (-7,8), the slope would be (8-4)/(-7-(-7))=4/0 which is undefined
856807
Yes that will be correct because after you isolate the (y) in other words put it in slope inercect form it would be \ny=2x+4 \nm=2\nb=4
955089
y-2x=2\ny=2(x+1)\nx intercept(-1,0)\ny intercept(0,2)
844157
At x =0, y =5 is the y intercept.
707187
Given two points, (x1, y1) and (x2, y2), slope is (y2 - y1)/(x2 - x1):\n(1 - 6)/(-3 - 5) = -5/-8 = 5/8
391343
i think 2.\n\nRearrange the eqution to give x= (10-2y)/5\n\nX intercept occurs when y=0\n\nput 0 in place of y and solve the equation.\n\n(10-0)/5\n\ntherfore x = 2
756857
Any line parallel to x - 2y = 5 will have the same slope as x - 2y = 5. Therefore you must first find the slope of x - 2y = 5. To easily find the slope, you re-write the equation in the form y = mx + c where m is the slope.\n\nx - 2y = 5\n- 2y = -x + 5\ny = 1/2 x - 5/2\n\nOR \n\ny = 0.5x - 2.5\nThe slope is therefore 0.5\n\nGiven the point (2, -4) and slope 0.5\nthe equation is found as follows:\n\ny - (-4) = 0.5(x - 2)\ny + 4 = 0.5x - 1\ny = 0.5x - 1 - 4\ny = 0.5x - 5\n\nYou can re-write that equation in any form you like.
104788
Remember the slope-intercept form?\n\ny = mx + b.\n\ny = the y coordinate.\nx = the x coordinate.\nm = the slope.\nb = the y - intercept.\n\nyour equation is already in slope-intercept form. so all you need to do is match up your numbers with the y = mx + b.\n\nThe slope is -5.\nThe y - intercept is -17.\n\nHope that helps :)