(w+3)/4w / (w-3)/2w what are they talking about..........?
491746
If u could give the entire question i could solve it for u and i'm not jokin. its actually quite easy.Its basically\n\n(w+3)/4w * 2w/(w-3).So wat ud have is\n\n1/2( (w+3)/(w-3) )\n\nits xactly like sayin 2/4 = (2/1) / (4/1)
86546
(3y+1)(-2)+y\n-6y-3+y\n-5y-3\n\n12s+(7-s)2\n12s+14-2s\n10s+14\n\n7x-3x(x+1)\n7x-3x^2-3x\n-3x^2+4x\n\n3t(t-5)+6t^2\n3t^2-15t+6t^2\n9t^2-15t\n\n4w^2-w(2w-3)\n4w^2-2w^2+3w\n2w^2+3w
928253
w² = 16w\nSo w² - 16w = 0\nSo w(w - 16) = 0\nSo either w = 0 or w - 16 = 0\nTherefore w = 0, 16
889816
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
776941
-25 < 5(w + 3)\n-25< 5w +15\n-40< 5w\n-8<w\n\n-9q + 18 -3 > 6q\n15 > 15q\n1> q\n\n\n19 < 7 + 1/3k + 2 -2/3k\nmultiply by 3 to get rid of denominators\n57 < 21 +k +6 -2k\n30< -1k\ndivide by -1\n-30<k
538319
A -> B\nB -> C\n...\nT -> U\nYou (U) -> V\nV -> W\n\nSo, You -> V
600360
In w(w-4) there are two factors being multiplied.  One, as you know, is w-4.  The other is w.  To use the zero factor property, you set each factor equal to 0.  This means that you will set w equal to 0 as well as setting w-4 equal to 0.
589702
I think this means:\n\n(t^2 - 2t - 15)/(t-5) * (t+5)/(t+3)\n\nIf that's right, then\n\n(t^2 - 2t - 15)/(t-5) * (t+5)/(t+3) = (t-5)(t+3)/(t-5) * (t+5)/(t+3)\n= t+5
1025264
pls specify ur question, didnt quite understand it\n\nIf there is "OR" u have to add and if it is "And" u have to multiply.
971390
{3XY^2M/1}-{2M/[X^-1Y^-1]^2\n+{[4X^2Y^2]/M^-1}-\n(3X^(3Y)^(3M)^-1/(XYM)^-2
253154
l = length\nw = width\n\nl = 8w\n\nlw = 128\n(8w)(w) = 128\n8w² = 128\nw² = 16\nw = 4\nl = 8(4)\nl = 32\n\nWidth is 4 feet.
955805
That simplifies to 3[2x-1]>12\n\n[2x-1]>4\n\n2x-1>4    2x-1<-4\n\nx>5/2  or x<-3/2\n\nWhen you have absolute values, you have to look at both ends of the spectrum
25946
=3fg*(f^2g)+3fg*5f-3fg*4\n=3(f^(1+2g))*g+15(f^2)g-12fg
514501
It's not really a problem as much as a simplification; there's no = sign.  Anyway, simplified I get 8w^3 + 4w^2.  I got that by multiplying your original problem by \n(-2w-1)/(-2w-1).  That gets rid of the fraction in the denominator and reduces the numerals in the numerator down.
928980
u^4-2u^2v^2 +v^4 -2u^2w^2-2uvw^2-v^2w^2)
985090
l = 5+w\n\nl*w = 36\n\np = 2l + 2w
905618
(A) 3+2(x-1)\n\n3+2x+2\n2x+5\n\n(B) 5-2(x+3)\n\n5-2x-6\n-2x-1\n\n(C) 1+2(x-1)\n\n1+2x-2\n2x-1\n\n(D) 6-3(w-2)\n\n6-3w+6\n-3w+12