How do u solve this 13-t=t-7 plz help!!!!!?
478454
13 - T = T - 7\n+7          +7\n20 - T = T\n+T           +T\n20= 2T\n/2   /2\n10 = T
931612
f^{-1}(y) = (y-42) / 7\ns
618786
see this 4^5$32@* ghh4$)--==Y7^6hnyntt%5$$%%44557 b7B7g77&765&yY\nis = to none, now happy
937830
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today
854810
Since benabean took the absolute difference in the periods, the value of K IS relevant; in fact, crucial to the solution.  My solution:\nTake the ratio of the 2 periods: T2/T1 = √(g1/g2) = 1.00095426\nMultiply this by the seconds in a day (86400)→ 86482.4\n\nSo, a difference of 82.4 sec lost per day.
753296
|t - 78.3| ≤ 38.3\n\nSo either t -78.3 ≤ 38.3 whence t ≤ 116.6\nOR - (t - 78.3) ≤ 38.3\nwhence - t ≤ - 40 ie 40 ≤ t\n\nSo 40 ≤ t ≤ 116.6
900395
Plug in -9.3 to see if it works out:\n\n12.8 - (-9.3) = 12.8 + 9.3 = 22.1 ≠ 3.5\n\nSo q = -9.3 is NOT a solution.
336054
T=RV \nT=4\nV=8\n 4=8R\n\nR = 4/8 = 0.5 = R
916037
We'll solve this in steps, to make it easier.\n\nt + 8 = -12\n\nSubtract 8 from both sides\nt=-20\n\nWe now know the value of t.  To find t+1, add 1 to the value of t.  This is the answer we are looking for.\nt+1=-20+1\nt+1=-19\n\n\n-19 is the answer.  Hope this helps.
440158
Since a = 9-t,\nThen 4(9-t) = 8t-12.\nThen 36-4t = 8t-12.\nThen 12t = 48.\nSo t = 4.\n\nThus a = 9-t = 9-4 = 5.
756828
The objective of this problem is to "solve for t" which means to isolate it on one side of the equation, hoping that only a number appears on the other side.\n\nBegin by distributing the (-6) factor through the left-hand side's other group of terms:\n\n-24 + 6t = 12t\n\n... being careful to let the two minus signs "cancel each other out" and become a + sign.\n\nNow, we hope to "collect like terms" -- that is, terms containing 't' -- on the right side.  Do so by subtracting 6t from both sides:\n\n-24 = 6t\n\nNow, finally, divide by the "coefficient of t" which is 6:\n\n-4 = t\n\nAnd there is your solution!\n\nMany teachers instruct you to "check your work" by substituting the "answer" back into the original problem, to make sure it is correct.  Let's do that here:\n\n(-6)(4-(-4) = 12(-4)?\n\nSimplify the left-hand slightly:\n\n-6 * (8) = -48?\n-48 = -48\n\nYes!  This yielded a true mathematical statement, hence our solution of t=-4 was correct all along.\n\nHope this helps!
144380
You got it quite confusing! Did you mean\n(a) y=4/7x-13 or (b) y=4/(7x-13) ??\n\n(a)\n\ny = 4/7x - 13    (-13 is not on the denominator!)\nThe range is the set of all possible values of y and\nthe domain is the set of all possible values of x, but a denominator cannot have a value of 0, so 7x cannot be 0\nand x cannot be 0.\n\nDomain={x/x E R, x is not equal to 0}\nTo get the range, solve for x in terms of y.\n\ny=4/7x-13\n7xy = 4 - 91x\n7xy + 91x = 4\n7x(y + 13) = 4\nx = 4/(7(y + 13))\n\n7(y + 13) cannot be equal to 0, so\n(y + 13) is not equal to 0 \ntherefore, y is not equal to -13\n\nRange={y/y E R, y is not equal to -13}\n\n(b)\n\nUsing the same procedure, you will get\n\nDomain={x/x E R, x is not equal to 13/7)\nRange={y/y E R, y is not equal to 0}\n\nc",
268911
since no one else will explain it, if u have 7a-5<9. then u have to add five to both sides to get rid of it on the left side. so that makes 7a<14. then to get a by it self, u have to divide both sides by 7. so u get a<2.
822034
You're NOT dumb!  Everyone has different skills.  Thought you were going to send me a note when you got stuck??  I took alg II twice!\n\n1.  simply switch it to s=1-2t.  Now put that first one into the second , for s, which will give you the value of t when you solve it.  Plug in t's value into either and that will give you s.\n\n2.  do the same way\n\n3.  P=120\n     L=3w\n     P=L times W\n\n4/5:  take the number on the outside and multiply each number inside the (), then combine.\n\n7/8:  isolate the variable (letter) and get it just on one side
282133
sqrt(t(sqrt(t(sqrt(t))))) = sqrt(t(sqrt(t(sqrt(t)))))\nsqrt(t(sqrt(t(sqrt(t))))) = sqrt(t(sqrt(t*t^(1/2))))\nsqrt(t(sqrt(t(sqrt(t))))) = sqrt(t(sqrt(t^(3/2)))) \nsqrt(t(sqrt(t(sqrt(t))))) = sqrt(t(t^(3/4)))\nsqrt(t(sqrt(t(sqrt(t))))) = sqrt(t^(7/4))\nsqrt(t(sqrt(t(sqrt(t))))) = t^(7/8)\n\nThe derivative of sqrt(t(sqrt(t(sqrt(t))))) = the derivative of t^(7/8), so:\n\n(t^(7/8))' = (7/8)*t^((7/8)-(8/8))\n(t^(7/8))' = (7/8)*t^(-1/8)
921632
PV = NRT, solve for N, note that T is absolute temperature in kelvins
1087652
Umm ... what's your equiation again?\n\nIt currently reads: T(n)=4T(n-1)-3T(n-2)-2n4^n+3n^2\n\nI have no idea what 2n4^n means. You should rewrite your equations in the "add details" section next time, cuz you have more space that way for parentheses.