what are the difference between kpa and kn/m3?
487941
It is exacly the same thing. They are both units of  pressure and 1 kpa=1 kn/m3.
610716
Kilometer is the answer. Kilo is a prefix that stands for 1000, and you know what a meter is. So a kilometer is 1000 meters.
375635
Kp=Kc(RT)n\na.Kp=Kc(RT)-1/2\nb.Kp=KcRT\nc.Kp=KcRT\nd.Kp=Kc(RT)2
962694
Tehe answer is:\nAg + HNO3 -> AgNO3 + H\nAgNO3 + KBr -> AgBr + KNO3
474374
Standard atmospheric pressure is 101 325 Pa = 101.325 kPa = 1013.25 hPa = 1013.25 mbar = 760 Torr. This definition is used for pneumatic fluid power (ISO R554), and in the aerospace (ISO 2533) and petroleum (ISO 5024) industries.
169390
kilo pascals a unit of pressure which is 1000 N/m^2
929836
v = b - u/k\nv - b = u/k\nk(v-b) = u
847153
PV = nRT  .... n/R = P/RT\n\n800 torr x (1.3158×10^−3 atm/1 torr) = 1.053 atm\n\nn/R = (1.053 atm)/(8.206 x 10^-2 L atm/Kmol  x 298 K)\nn/R = 0.043 mol/L\n\nNH3 mass is (14 + 1x3)=17 g/mol\n\ndensity = n/R but we need it in g/mL\nn/R = 0.043 mol/L x (17 g/mol NH3) x (1L/1000mL)\nn/R = 7.31 x 10^-4 g/mL
388597
KiloPascals\nInches of Mercury\nPounds per Square Inch\nAtmospheres\nMillibars\n\nAll of these are used as units to measure air pressure.\n\nStandard atmospheric pressure is usually measured as millibars. Like when you watch the Weather Channel...\n\n:)
538984
I would think it is related to the metric prefix "kilo-" meaning 1,000 and abbreviated "k".
849178
GPa and MPa (giga-pascal [1E9 pascals] and mega-pascal [1E6 pascals])  are metric units of stress. (6.89 Mpa = 1 ksi [1000 psi - pounds per square inch])(1 Pa = 1 newton / meter^2)\n\nUsually fibers are tested in 'tows' bundles of maybe 1000 fibers. In order to know what force they can sustain given a tensile strength you just multiply the tensile strength by the cross-sectional area of the fibers.
621097
kVp affects penetration and mAs is the quantity of x-ray, so if you don't have enough penetration, you are going to have MORE absorbed dose because less xray is actually getting through the body. If you increase FFD, this also gives you less penetration, giving more absorbed dose if you do not increase your kVp, and if you decrease collimation, you will have more scatter which will give you more absorbed dose. SO, in effect you have \nincrease kVp=decrease absorbed dose  \n    increase FFD=increase absorbed dose\n increase collimation=decrease in absorbed dose.  Hope this helps!
529951
Kilo Crypt-equivalent-operations Per Second
759238
just look at your units..that normally hleps\n\nhf ...kj / mole\n3.22 kJ / 6.02 Kj/mol =    x moles\nxmoles * 18 gram / mol.....  Thats your answer
363034
m = kn\nk = m/n\n\nk = 144/8\nk = 18\n\nANS : 18
28535
Well, look at the units. The first one is a distance divided by a time; speed. The second one is in the units of energy (in the MKS unit system) the Joule. The "KE" also says to me that it isn't just any energy but, kinetic energy -- the energy that something has because it is moving.\n\nFrom these two bits of information you can deduce the mass of the object (if that's what you're talking about) in question.\n\nA very basic kinematic equation is the one that describes the relationship between the mass, velocity, and kinetic energy of something in motion.\n\nKE = 1/2 * mass * velocity^2\n\nsolving for the mass would be:\n\nmass = (2*KE)/(v^2)\n\nWhich is in the neighborhood of 2000 kg.\n\nhope that helps.
1177648
Are you fixing a 1987 Mazda RX-7?  Hehe...  I really am curious to know what this conversion is for...  Is your lawnmower on the fritz?  Hehe.  \n\nFirst off, let me ask you if the unit bearing measurements in KMPH or KPH has any sort of "tachometer" on it...  Some tachometers show both KMPH and RPMS, but others don't.  If you're in a situation where your tach doesn't have one, uh....  You're probably gonna need to check with the Autoguru.  \n\nAccording to him, to calculate your RPMs, you must do the following:  \n\n1) If your Road Wheel diameter is 'D' meters, then its circumference would be '^D' ( using ^ as a symbol for 'pi'=3.14). \n\n2) Assume you are cruising in IV gear @ 60 kph and the Car has a 'final drive'/FDR ratio of 4:1 and the IV gear ratio/TGR of 0.9:1. \n\n3) Then the # of revolutions 'per minute' the Road wheel would make would be = 60/60 x 1000/3.14 x D. \n\n(Assuming 'D' to be = 0.50 meters, it'd be = 636.94 rpm. The figure of '1000' comes in to convert 'kph' into 'mph' and '60' to convert hrs into minutes.  [*That's the Metric System at work, for ya, kids!]) \n\n4) To get the Engine rpm now, we multiply 636.94 x FDR x TGR or 636.94 x 4 x 0 .9 which = 2293 rpm. \n\n5) For E-Rpm in any other gear, '0.9' would have to be replaced by the drive ratio of that gear viz 1.33 for III and so on.\n\nThis is pretty close to the real life example of a Maruti 800, which when "tacho'd" does 80 kph/~3000 rpm!\n\nI hope this helps you!  Good luck!