write the slope-intercept from of the equation of a line passing through (3,-2) with slope 1/2?
477914
slope= mx+b\nslope=1/2x\nequation= y=1/2x-3.5\ny-int: -3.5
907088
The slope is 1/3 and the point is (-2, -4).
128403
general equation of a line with slope m and y-intercept c is \n\ny = mx + c ....... (1)\n\nsay this line is parallel to 2x+3y+4=0 which means the slopes of two lines are equal\n\nso, m = -2/3  [-(x-coefficient/y-coefficient)]\n\nand c = 6 (given) \n\nsubstituting m and c in (1) \n\nrequired equation is y = -(2/3)x + 6\n\n=> 2x+3y-18=0
124756
slope intercept formula is y=mx +b to find b subsitute in for y,m, and x.  so 1 = -2(0) + b.   1 = 0 + b so b = 1 then your equation would be y=-2x + 1.
927388
y=mx+b\n\njust rearrange it so you get b as your intercept..\n\nin this case y=-1/4x +3, so the slope is -1/4, and the intercept is 3
829794
The standard equation for slope-intercept form is y=mx+b. m is the slope and b is the y-coordinate of the vertical (y) intercept\n\n-2x=y+3       Original equation\n\ny=-2x-3        Rewritten in S-I form\n\nm= -2, b= -3\n\nThis means that the graph of the funtion is a line through the y-axis at the point (0, -3) with a slope of (-2)
890222
for (0,2),(4,0) the slope is -1/2\nfor (-2,0),(4,0) the slope is 0
934552
Rearrange the equation so that you get it in the form of the equation of a straight line, that is in the form y = ax +b.\n\nYou get 2y = -x -2\n\nDivide through by 2 anf you get:\n\ny = -x/2 -1\n\nthe -x/2 term is -1/2 times x, so compare this with the equation of a straight line and you see that a = -1/2.  b is -1.\n\na is the slope or gradient of the line so the answer is -1/2.  Not that it has aminus sign so that tells you it slopes upwards from RIGHT to Left.\n\nb is the intercept on th y axis.  So the line crosses the y axis at y = -1.
306531
First, the slope is (delta y)/(delta X) = (-3)/2) = -3/2\n\nthe y intercept is +6  (interpolating back from \n(6,-3) ,(4,0),(2,3), (0,6)\n\nso the equation is Y=-3/2 X + 6\n\ngo from there and you have your answer.
704179
An equation in slope-intercept form is y = mx + b\nIn the equation, m = slope and b = y-intercept\n\nUsing the equation given\ny=-3/2x+6\ny = mx + b\n\nWe know that the slope is -3/2.  That would be m.\nWe know the y-intercept is 6.  That would be b.\n\nNow we have to find the x-intercept.\n\nTo get the x-intercept, we will set y = 0 and solve the equation for x.\ny=-3/2x+6\nSubstitute 0 for y\n0=-3/2x+6\nAdd 3/2x to both sides\n3/2x = 6\nMultiply both sides by 2/3\n2/3*3/2x = 6*2/3\nx = 4\nThe x-intercept is 4.\n\nSlope =  -3/2. \ny-intercept = 6.\nx-intercept = 4.
147089
y intercept: (0,4)\nx intercept: (3,0)
850944
You have 2 points, (x1,y1) and (x2,y2) and you want to find the equation of the line that goes through these points.\n\nThe first thing you want to do is find the slope.\nslope is rise/run so m = (y1-y2)/(x1-x2)\n\nFor slope intercept form , y = mx + b\nwhere m is the slope, and b is the y intercept\nnow that you have found the slope, you can solve for b, the y intercept by plugging in your value for m and one of the given points, either (x1,y1) or (x2,y2).\n\nFor point slope form,  y - K = m(x - H)\nm is the slope, and   (H,K) is a point that the line passes through.\nSince you have already calculated the slope, m, for the slope intercept form, you're already almost done. All you have to do is plug in the point (x1,y1) or (x2,y2). In your question, you are asked for the point slope form of just point (6,2).
502566
it's the slope-intercept form of the equation for a line.
942649
The slope is 3 and the y-intercept is -6
787261
Let the 2 points be (x1,y1)  and  (x2,y2)\n\neqn of line s given by\n\n(y-y1)/(y2-y1) = (x-x1)/(x2-x1)\n\nwhere  (y2-y1)/(x2-x1) is the slope of line
925887
Hopefully you know how to solve one part of it. Slope intercept form is Y= M x+B. First find the slope, using 2 set of coordinates, that formula is Y2-Y1 over X2-X1. that will be your M.  Then find your Y intercept. then plug it in to that formula above. I hope i was of some help. Don't put your life on this i did it in the beginning of the school year.  I may have the M and the B switched.
3669
This is for math right? If so:\n\nThe slope-intercept form is:\n\ny = mx + b\n\ny = value on the y-axis\nm = slope\nx = value on the x-axis\nb = y-axis intercept\n\nThe slope-intercept form gives the equation for a straight line.