Can you continuously simulate acceleration with a moving elevator as at the earth surface?
482492
So long as there is rate of change of motion
227420
Assuming that it could be done, that the tunnel wouldn't be filled with magma, that the earth were not rotating, and that we made the tunnel into a vacuum, then the ball would fall from one end of the earth to the center while accelerating with non-constant acceleration, then continue to the other side of the earth but slowing down as it fell up with non-constant acceleration.  This is called simple harmonic motion and it would continue for ever.  If the tube was not a vacuum then the ball would initially speed up.  But as the gravitational pull the ball felt weakened and the air resistance increased (due to increases in air pressures at increasing depths) the ball would slow down.  In the end the ball would stop at the center of the earth.  If the earth were allowed to spin during this experiment, then unless the hole were drilled from the north pole to the south pole, conservation of angular momentum would cause the ball to crash into the sides of the tunnel as it fell and friction would cause it to slow until it came to a stop at the center of the earth.
150657
gravity is highest at the centre of the earth. so you will be accelerating towards the centre.since there is no resistence (assume so that there is no air), you would not stop at the centre due to inertia of motion and continue to go beyond the centre to teh other side. but due to increasing pull on you, you will turn back and continue to oscillate about the center of the earth.\n\nits good for theory but humanly imposible
870325
I suggest you build an anti-gravity lifter device that is able to float in the air without anything supporting it.\n\nhttp://www.amazing1.com/grav.htm
1038631
Yes, you can.\n\nIf you were at a high altitude in a fighter jet and you pointed the nose toward the ground and hit the afterburners you would be accelerating toward the ground at an acceleration much greater than that of gravity.
455809
Nope.  There has never been a demonstration of such ability under controlled circumstances.  If anyone thinks they can do it, why don't you contact James Randi and make yourself a quick million dollars.
816694
hi \nbasic formula to be used here is f=ma\nhere we have 2 scenarios elevator going up(against gravity of earth denoted by 'g' which is constant eual to 9.8 or lets say 10m/s ^2.\nnow when elevator is going up means it has to defy gravity and go up which means there has to be more force to accomplish\nhence we use f=70 x (g+a)\nwhich is f= 70 x(10+3)=910N\nwhile the elevator is moving down it doesnt need to defy gravity and hence the force required to accomplish this will be much less\nhence we use f=70x (g-a)\nwhich is f=70x(10-3)=490N\n\nis the elevator is standing still then \nf=m x a\nwhich is f= 70 x 3 = 210n
133048
Hello, \n\nThis problem is a bit more involved than you might initially think. There are 4 major considerations you must take into account. First, the acceleration is dependant on the angle of the hill at any given time. Therefore, acceleration is NOT constant, rather fluctuating with the incline. Second, the wind resistance is NOT constant by any means. It increases exponentially with the speed of the sled. Third, the force of the kinetic friction is not constant either. While the coefficient of friction does increase somewhat with speed (you could use an average for this), you cannot neglect the increase in friction when the sled goes around a corner. As you know, the friction is based on the normal force of the sled. At 90mph, the centripetal acceleration around a curve is V^2/r (V=velocity, r is radius of corner) which becomes quite considerable, even though steel on ice only has a kinetic coefficient between .01 - .05. \n\nNow that I have bored you out of your mind, the full equation would look something like this (I’m writing everything longhand so you know what I’m talking about)\nSum of the forces = mass x gravity x sin(angle of hill) – [(coefficient of friction) x mass x gravity x cos(angle of hill) – mass x velocity ^2 / radius of curve] – (Force of air drag)\n\nNotice the term included to account for curves: – mass x velocity ^2 / radius of curve\nDrops to zero when they are going in a straight line (r = infinity). \n\nTo find your acceleration (at a specific point in time), you simply divide everything by the mass of the sled and there you go!\n\nPS. don't take physics advice from dental students ;P
535733
no. you would accelerate to the centre then decelerate to almost the other side. then repeat traveling a bit less each time till you finally come to rest in the middle.
641758
A better question is why do we feel ourselves moving on a lift or bus.\n\nOnly accelerations can be felt, not motion at a constant velocity. Einstein showed that motion at a constant velocity doesn't even have any meaning unless it is measured "relative" to some "stationary" observer, and even "stationary" has no meaning. But enough of that.\n\nEinstein also showed that acceleration is the same as gravity in that they can both be felt, and cannot be distinguished from each other unless you can look out a window. If you are in a closed box with no window, you cannot tell if you in a gravitational field or are accelerating.\n\nWhen a bus is traveling at a "constant" velocity, you in it are actually being accelerated in all different directions all the time as the bus bounces around. If the bus was traveling on a perfectly smooth surface at constant velocity, and had no windows, with no accelerations of any kind, you would not know you were moving.\n\nSame with the lift. You can feel only the accelerations up or down. If the lift is traveling perfectly smoothly at constant velocity with no accelerations, you would feel nothing, except that the pressure in your ears would tell you whether you are going up or down.
939350
The height of the plane does not affect the acceleration, only the angle.\n\nAcceleration will be constant as long as the force acting on it is constant. The force contributing to acceleration (gravity) is constant.
1883
Let me give you a chance to answer this question yourself with these two yes/no questions: Do you have to adjust your feet in order to stay in one spot for a long time (having to shuffle your feet to put them back in the correct spot as the earth moves under you?)\n\nOr has your house/appartment building ever slid off its foundation beause the earth moved under it?\n\nWhatever answer you choose, yes or no, that's the answer to your question, for the same reasons.
745294
In a vacuum above a perfectly flat surface, the answer is no. (The ideal model situation)  However, no situation is ideal.\n\nI would say, in most cases, the vertical velocity of an object in freefall would noy be significantly affected by the horzontal velocity.\n\nIf the object is travelling fast enough for air resistance to significantly affect it, then the question becomes much more complex.  At even faster speeds the curvature of the Earth will be significant.\n\nIf the object is a baseball in an ordinary baseball game, unless it is a pitched curve ball, the horizontal velocity is insignificant.
761342
We did something like this in my physics lab with an Atwood machine.  It was a pully with weights hanging from it.  I can't exactly remember how it worked, but maybe this will inspire you.  We also did something with an air track and these two masses colliding and we'd see which one would go in which diretcion.  You need a nearly frictionless surface, like an air hockey table or ice slab.
1090022
theoretically, you would oscillate back and forth until friction slowed you down enough to come to a rest at the center of the earth.  it could be six flags newest attraction!
306816
B.  The acceleration is towards the Earth and the force is constant.
256104
Read Newton's 3rd law of motion.\nAlso, use F=ma to figure out your acceleration.