what is an equation of the line through (-1,1) and (2,3)?
486556
Remember you won't have Yahoo Answers to rely on when you take the test...\n\nIt is much better to learn *how* to do it yourself.  First you need to figure out the slope.  The slope is the rise over the run.  Rise is the difference between the y coordinates.  Run is the difference between the x coordinates.\n\nRise = y2-y1\n= 3 - 1\n= 2\n\nRun = x2-x1\n= 2 - -1\n= 3\n\nSo the slope is 2/3\n\nNext you need to figure out a point when x=0\n\nYou have one point (-1, 1)\nx = -1\ny = 1\n\nMoving over 1 unit you get to x = 0\nFor every unit you move over, you go up by the slope.\nSo y = 1 + 2/3\n\nThe point x = 0, y = 1 2/3 is the y-intercept.  (0, 1 2/3)\n\nNow you have all the information you need to write the equation in "slope intercept" form.\n\nJust remember the equation:\ny = mx + b\n\nm is the slope\nb is the y-intercept\n\nFrom what you have solved above:\nm = 2/3\nb = 1 2/3\n\nSo the equation of a line is:\ny = 2/3x + 1 2/3\n\nTo double check your work (which you should definitely do) plug in the two points you had originally:\n\n(-1,1)\nx = -1\ny = 2/3(-1) + 1 2/3\ny = -2/3 + 1 2/3\ny = 1\n(-1,1) Correct\n\n(2,3)\nx = 2\ny = 2/3(2) + 1 2/3\ny = 4/3 + 5/3\ny = 9/3\ny = 3\n(2,3)  Correct\n\nSo the equation is:\ny = 2/3 x + 1 2/3\n\nIn mixed fractions:\ny = 2/3x + 5/3
954933
y-y1 = m(x-x1)\nplug in values from one of the points......for example (4,1)\ny -1 = 1/2(x-4) distribute....\n\ny-1 = 1/2x - 2   add one to both sides\n\ny = 1/2x -1......equation of the line\n\nsince it is above the line....greater than.....so\ny > 1/2x-1.....is line dotted? or solid (then use symbol for > or =)
497181
You only need two points to determine a line.\nYou should use three just to make sure you don't make a mistake.\nPick two values of x and find the corresponding values for y.\nThis one is pretty simple.\nLet x = 0, then y = 0 (since y = x)\nLet x = 1, then y = 1\nLet x = -3, then y = -3.\nPlot these points on the graph and connect them with a straight line.
655260
2=-1=x\n2+1=x\nthere fore x =3
940096
You have z=2, and y-z=-3, so if you put the value of z in there you should have \ny - 2 = -3\nso y is -1\nNow, with the value of y, you can replace it in the x-y=4 equation\nx-(-1)=4\nso x=3\n\nYou were on the right track, you just stopped a bit short of the finish line.
758594
2. The equation is (y-y1)/(y1-y2)=(x-x1)/(x1-x2)\n=>(y+2)(-2-0)=(x+1)(-1-0)\n=>(y+2)(-2)=(x+1)(-1)\n=>-y-2=-2x-2\n=>-y+2x=0=> 2x-y=0 which is the required equn.\n3.The equation is (y-4)(4+4)=(x-0)/(0-4)\n=>y-4/8 =x/-4\n=>8x=-4y+16  or,8x+4y-16=0  o4 2x+y-4=0 is the reqd.equation\n4.the eqn. is (y+3)/(-3-3)= (x+2)/(-2-0)\n=>(y+3)/-6=(x+2)/-2\n=>-6x-12=-2y-6\n=>-8x+2y-6=0 or,-4x+y-4=0 which is the equired equation
509875
We use point slope to find the equation for the line:\n\ny - y1 = m(x - x1)         Initial Equation\ny - 7 = 3(x - 2)           substitute\ny - 7 = 3x - 6             distribute\ny = 3x + 1                 Add 7 to each side to solve for y\n\nNow that we have the equation for the line, we want to know where the line crosses the x axis.  That means we put 0 in for y and solve for x.\n\n0 = 3x + 1      Initial equation with 0 substituted for y\n-1 = 3x         Subtract one from each side\n-1/3 = x        Divide each side by 3.\n\nDone - the answer is (d) -1/3
706345
slope = -5-1 / -2-(-3) = -6/1 = -6\ny-1=-6(x+3)\n.
650764
Remember that i^2 is -1 so\n-3i+2(-1)-2+i=-4-2i
802801
i think -1; y=mx+b, "b" is the 3 and "m"(slope) is negative one.
871212
i2=i1R1/R2\ni1=R2i2/R1\n\nR1/R2=i2/i1\n\nR1/Rx = R2/R3\n(R1/R2)*R3=Rx\nRx=(i2/i1)*R3
935919
Please calm down. Now do you want the line between (2,0) and (-2,-2) The way I do it is to get the point vector solution of the line and eliminate t. The point is (2,0). The vector is <-2 - 2, -2 -0>. Just subtract the first coordinate from the second. So the vector is <-4, -2> \nNow set up the point vector equation describing the postion of the graph at time t.\nJust point + vector*t in component form.\nThe x-components: x = 2 - 4t \nThe ys: y = 0 - 2t\n\nThere, that is it. But some nasty professors don't like this form, so we'll eliminate t. We plug y = -2t into first equation and get x = 2 + 2y.\n2y = x - 2. y = x/2 -1.
743897
gradient of the new line is -1/4\nso y=- 1/4x-c\nso using (2,3) 3 = (-1/4*2)-c\n3 = -1/2 - c\n3 and1/2 = -c\nc = -3 and 1/2\n\nso equation of line is:\n\ny = -1/4x + 3.5\n\nco-ordinates of C:\n when y=0\n\nso 0 = -1/4x + 3.5\n-3.5 = -1/4x\n3.5 = 1/4x\n14=x\n\nso co-ordinates of C = (14,0)\n\nHope this helps
207106
x^2-3=-2\nx^2=-2+3\nx^2= 1\nx=1\n\n1^2+-3+2=0
1093431
what is d2 here..if its line what is its equation?
211777
n=3\nl=1\nm sub l =1,0, or -1\nm sub s = + or - 1/2
948937
(-3,-3);(-2,0);(-1,1);\n(0,0);(1,-3)