how long will take to reach moon through rocket?
486518
According to Wikipedia, Apollo 11 took five days to reach the moon: they took off on July 16th, 1969, and reached the moon on July 21st, 1969.\n\nLater missions took as little as 3 days to complete.
25248
First of all, there is no fixed end to the atmosphere: it gradually fades away to the density of interplanetary space.  However, the effective "top" of the atmosphere is often taken to be 60 miles (100 km), the altitude at which a (typical) unpowered satellite could make one orbit before air drag slowed it and caused it to fall.\nTo reach this altitude only requires that an object be headed upward, no matter how slowly.  To move upward requires that the object have some force propeling it which is at least slightly greater than the force of gravity pulling it down.  This force of gravity lessens with altitude, which is why a rocket needs a lot of power to take off, but little to maneuver in orbit.  Thus there is no minimum speed needed to reach the "top" of the atmosphere.\nHowever, the orbital velocity needed to stay in orbit is that velocity which just equals the downward pull of gravity, so orbital speed depends on the altitude of the satellite: it goes down with altitude.  (For example, at a typical low-orbit altitude of a couple hundred miles or so, the speed is around 17,000 miles per hour and the orbital period for one orbit is around an hour and a half; the Moon, 238,000 miles away, moves about 2000 mph and takes 28 days to orbit once. For mathematical details, see references on Kepler's Laws.
969045
Are you taking into account the radius of the moon? The equations you've provided treat "r" as the distance between the centers of mass of each object. Therefore:\n\nr = radius of the moon + distance from it's surface\n\nr = 1785 km + 111 km\n\nr = 1,896,000 m\n\nSubstituting this into your equations provides:\n\nT = 2*pi*sqrt((1896000)^3/(6.674x10^-11 * 7.3x10^22))\n\nT = 7431.6 s = 123.9 min\n\nAdditionally:\n\nV = sqrt((6.674x10^-11 * 7.3x10^22) / 1896000)\n\nV = 1603 m/s\n\nHope that clears things up a bit! :)
546510
Here is a quick page of info for ya. Hopes this helps.\n\nhttp://teacher.scholastic.com/researchtools/articlearchives/space/moon.htm
980237
Since its a manned flight, the space craft being heavier, it would take at least eight months or more. However, like correctly pointed out by Christoph... N, it would be a very painful ride for the space passenger. The radiations and the athropy of the muscles & bones would cause a lot of discomfort.
7693
The question is about the lunar sidereal period.  It is 27.32166 days, as a casual web search reveals.
1162301
The Moon is Earth's only natural satellite. It has no formal name other than "The Moon", although in English it is occasionally called Luna (Latin for moon), or Selene (Greek for moon), to distinguish it from the generic "moon" (natural satellites of other planets are also called moons). Its symbol is a crescent. The terms lunar, selene/seleno-, and -cynthion (from the Lunar deities Selene and Cynthia) refer to the Moon (aposelene, selenocentric, pericynthion, etc.).\n\nThe average distance from the Moon to the Earth is 384,403 kilometers (238,857 miles). The Moon's diameter is 3,476 kilometres (2,160 mi). Reflected sunlight from the Moon's surface reaches Earth in 1.3 seconds (at the speed of light).\n\nThe first man-made object to land on the Moon was Luna 2 in 1959, the first photographs of the otherwise occluded far side of the Moon were made by Luna 3 in the same year, and the first people to land on the Moon came aboard Apollo 11 in 1969.
1016108
The moon is moving away from the Earth at about 3.8 cm per year.  At this rate, it is calculated that the moon will be far enough away from the Earth not to cover the sun in slightly less than 600 million years.
883966
Okay, here you are.\n\nAlex's rocket:\n\nDistance: 900 feet \nRate: 112.5 f/s\nTime: 8 seconds\n\nKeesha's rocket:\n\nDistance: 900 feet\nTime: 5 seconds\nRate: 180 f/s
320843
The actual time of travel from Saturn to the Earth will vary depending on the geometries of the two planets in their orbits, but will be between about 75 minutes and about 92 minutes.
645338
With or without stopping to ask for directions?\n\nIf the moon is (on average) 185,000 miles away and you drive 70 miles an hour, you'll get there in about 2600 hours, or somewhere around 110 days.\n\nRemember the moon is also moving, so you'll have to aim for the point in space where the moon will be when you get there ... and you'd better be going faster than 70 mph when you get there because the Moon won't wait up -- it's revolving around the Earth much faster than that.
999749
nothing... your car nowadays have a more complicated computer system then that lunar module.  I hope your asking about the first one that land on the moon
280025
The moon spins on its axis in the same amount of time it takes to complete one orbit around the earth. That is why the same side of the moon is  always facing earth 29 days 12 hours 44 minutes according to my American Heritage Dictionary's first definition of "moon".
357890
It takes the Moon 27.322 days to go around the Earth once. Because of this motion, the Moon appears to move about 13° against the stars each day, or about one-half degree per hour. If you watch the Moon over the course of several hours one night, you will notice that its position among the stars will change by a few degrees.
198137
The average distance from the Moon to the Earth is 384,403 kilometers (238,857 miles). The Moon's diameter is 3,476 kilometers (2,160 miles).
699914
It would go a LONG ways before it hit the lunar surface, since there's no aerodynamic friction loss since there's no atmosphere.\n\nBullets are self contained and will project a bullet without an atmosphere.\n\nThe Moon's escape velocity is considerable lower than that of Earth, at 2.38 km/s vs. 11.19 km/s, but most guns available to the public have muzzle velocities of not more than 0.350 km/s\n\n\nhttp://en.wikipedia.org/wiki/Earth\nhttp://en.wikipedia.org/wiki/Moon\nhttp://en.wikipedia.org/wiki/Muzzle_velocity
1145075
In order to send a satellite around the moon it would take a lot stronger rockets than currently used to bring them into orbit. Geostationary orbit is at a mere 36000km altitude, 1/11 of the distance to the moon. Satellites brought into geostationary don't have to overcome the escape velocity of earth.\n\nAny launch anomaly that could send a satellite around the moon has sufficient fuel and power left to send it into the wanted orbit.