What is complementation test?
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Complementation Testing\nOccasionally, multiple mutations of a single wild type phenotype are observed. The appropriate genetic question to ask is whether any of the mutations are in a single gene, or whether each mutations represents one of the several genes necessary for a phenotype to be expressed. The simplest test to distinguish between the two possibilities is the complementation test. The test is simple to perform --- two mutants are crossed, and the F1 is analyzed. If th e F1 expresses the wild type phenotype, we conclude each mutation is in one of two possible genes necessary for the wild type phenotype. When it is shown that shown genetically that two (or more) genes control a phenotype, the genes are said to form a complementation group. Alternatively, if the F1 does not express the wild type phenotype, but rather a mutant phenotype, we conclude that both mutations occur in the same gene.\nThese two results can be explained by considering the importance of genes to phenotypic function. If two separate genes are involved, each mutant will have a lesion in one gene while maintaining a wild type copy of the second gene. When the F1 is produc ed, it will expresses the mutant allele of gene A and the wild type allele of gene B (each contributed by one of the mutant parents). The F1 will also express the wild type allele for gene A and the mutant allele for gene B (contributed by the other muta nt parent). Because the F1 is expressing both of the necessary wild type alleles, the wild type phenotype is observed. \n\nConversely, if the mutations are in the same gene, each homolog will express a mutant version of the gene in the F1. Without a normal functioning gene product in the individual, a mutant phenotype occurs. \n\nEye color in Drosphila is a good model to demonstrate the complementation test. A wide array of spontaneous mutations have been studied. These experiments demonstrated that five genes (white, ruby, vermillion, garnet and carnation) controlling ey e color reside within 60 cM of each other on the X chromosome. The dominant wild type allele for each gene produces the deep red eyes. The mutant alleles produce a different color. If mutants from any of these five genes are crossed, the F1 would expre ss deep red eye color (wild type phenotype). \n\nFive different alleles (buff, coral, apricot, white and cherry) are also known to exist for the white gene, each representing a mutation at a different position in the gene. If mutant flies for any of the five white alleles are crossed, the F1 offspring would have a mutant eye color. Therefore, two genes involved in the expression of a phenotype complement each other. But complementation bet ween two alleles of the same gene does not occur
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This test to quantify the inhibition of lipopolysaccharide (LPS) activity by serum with a turbidimetric Limulus amoebocyte lysate assay. Assays are performed in multiwell microplates, and turbidity is measured as the optical density at 380 nm with a microplate spectrophotometer. LPS potency is measured as the 50% maximal Limulus amoebocyte response (LR50) of LPS diluted with saline. By comparing LR50s in saline, LPSs from various species of bacteria are standardized against the U.S. Reference Standard Endotoxin, lot EC-5.  .   A positive correlation is found between standardized potency in saline and serum inhibition of the various LPSs tested.   The degree of inhibition of all types of LPS tested increased are found with increasing serum concentration.\nVR
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Red top (clot tube) chemistry general tests\nRed/Gray speckle (clot tube with separator layer) general chemistry tests also.\nBoth above spun in a centrifuge, tests run on serum or plasma.\nPurple cap (has anticoagulant) does red cell count, white cell count, sedimentation rate, ect all for a CBC. Complete Blood Count.\nGrey cap (has anticoagulant) blood sugar.\nTheres a wall chart on the BD website with a full product ID . System is called Vacutainer.\nhttp://www.bd.com/vacutainer/pdfs/plus_plastic_tubes_wallchart_tubeguide_VS5229.pdf
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no-its a totally different test.
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diagnostic test\n\nn : an assay conducted for diagnostic purposes
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You have to use the manual, otherwise you can't do this.  If you find the manual, email me and I can help you.  What test is this?
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Assuming a pure substance, (this method will not work on mixtures).  \n1. Dissolve in Carbon disulphide.  (The compound is now banned in schools)\n2. Allow to evaporate in a fume cupboard.\n3. The presence of yellow rhombic like crystals is a test for S.\n4. Melt a sample and do a MP test.\n5. Melt a few grammes and allow to cool in air.  Needle like crystals will be formed.
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Have you been tested for lupus?
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It's a simple test that tells whether an alcohol is primary secondary or tertiary by looking at the time required for a white ppt to form.
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E-rosette test\nn.\nA test to identify T cells by mixing purified human blood lymphocytes with serum and sheep red blood cells; rosettes of red blood cells form around human T cells on incubation.
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"Complements of" means somebody is giving you something or providing you with something.  Alternate ways of phrasing: "Please take this pen with our compliments," or "This is free complimentary pen".\n\nIn a letter, you'd use "With best compliments from".
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yes i just had a test on it
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What are they testing for?
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I think you mean double blind experiment. This is the test where both the person who administering the test and the person under the test do not know the answer.
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ELISA(Enzyme Linked Immuno Sorbent Assay)- a type of blood test to detect the antibodies to a suspected infecting organism.
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There are two parts to the interivew. A written and verbal test. Sorry.
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Molisch's Test is the reaction of 1-naphthol with carbohydrates in the presence of sulfuric acid.  Carbohydrates are oxidized in this system to furfural derivatives, which will condense with the naphthol to give a purple-colored dye.\n\nFehling's Test is for aldehydes.  Copper (II) sulfate and Rochelle's salt (potassium sodium tartrate) solutions are combined, which causes complexation of the copper with tartrate.  An aldehyde will reduce the copper (II) to copper (I), which will precipitate as Cu2O, a red solid.  Ketones do not react in this manner.