What is Mars size compared to Earth?
478701
Equatorial diameter 6,804.9 km (4228.4 Miles)\n(0.533 Earths)\nPolar diameter 6,754.8 km (4197.2 Miles)\n(0.531 Earths)\nOblateness 0.007 36\nSurface area 1.448×108 km2 (55.907 Million Square Miles)\n(0.284 Earths)\n\n\n"Mars-5-inch-thing" Sure... but in which category of questions are we?
218700
Do mean "difference" or "distance"?\n\nIf it's difference, well, Venus is the 2nd planet from the sun, Mars is the 4th planet from the sun, and Jupiter is the 5th planet from the sun.\n\nVenus is a rocky planet just slightly smaller than earth with a hot, dense, atmosphere.\nMars is a rocky planet just over half the diameter of earth with a cold, atmosphere with a pressure of about 1/10 that of earth.\nJupiter is a gas giant that could contain many earths.\n\nI'm guessing that your question has more to do with the distances between the orbits of the planets rather than the actual distances between the planets because the distance between the planets can vary greatly depending on where each is it's orbit.\n\nThe site linke below has the distances in astronomical units and kilometers (km) from the sun for the orbits of each planet.  Maybe from that you can figure out the answer to your question.
256634
Size and connection to the planet(under the water) but mainly size
418513
0.38 that of earth's\n\nhttp://www.amnh.org/rose/mars/pl2.html
884418
I think your facts of science need to be updated.\n\nMars orbit is 1.5 AU (about 145 million miles)  from the Sun. \n\nThe Earth is 93 million miles away from the Sun.  At its closest, Mars is about 50 million miles away, and we have sent many probes to Mars without the need for "infinit (sic) energy"\n\nA manned Mars mission is well within human ability.
21355
Equatorial Diameter: 7937 miles\nPolar Diameter: 7900 miles\n\nThe equatorial diameter is greater because the Earth is  spinning on it's axis (at about 1000 mph at the equator) which greats a centrifugal force pulling away from the center of the planet. This effectively lessens the gravitational pull at the equator and the equatorial regions of the planet bulge out.\n\nYou'll also find some other interesting solar system data at the site below.
960922
Mars \nThe planet that is fourth outward from the Sun. Mars has a mean heliocentric distance (semimajor axis) of 1.524 astronomical units, equivalent to 141.6 × 106 mi (227.9 × 106 km). Its orbital eccentricity of 0.093, one of the largest of the major planets, causes the distance between Mars and the Sun to vary from 128 × 106 mi (207 × 106 km) at perihelion to 155 × 106 mi (249 × 106 km) at aphelion. The mean diameter of Mars is 4212 mi (6780 km), or about 53% that of the Earth. The planet has a mass of 7.08 × 1020 tons (6.42 × 1023 kg), about 11% of Earth's. The sidereal rotation period is 24h 37m 22.7s, corresponding to a mean solar day of 24h 39m 35.2s.\n\nMars appears to the unaided eye as a bright, slightly reddish star. Having a mean (synodic) period between oppositions of 780 days, Mars is in conjunction with the Sun every other year. Viewed through a telescope, Mars usually appears as a bright reddish disk marked by complex, semipermanent dark regions and variable white polar caps.\n\nInterior\n\nAccurate measurements of the planet's gravitational field made by orbiting spacecraft have shown that Mars has a dense core and thus is differentiated into a core, mantle, and crust. The crust, composed of silicate rocks, enriched in silicon and aluminum and deficient in magnesium, is believed to be about 30 mi (50 km) thick. Over geologic time, partial melting of the crust or upper mantle has caused lower-density materials to float to the surface, creating the observed lava plains and volcanic structures.\n\nAt present Mars does not have a global magnetic field of appreciable strength. However, early in its history Mars must have had a more substantial magnetic field, because its near-surface rocks exhibit strong remanent magnetism. See also Rock magnetism.\n\nGeology\n\nThe Martian surface has been modified extensively by the processes of impact cratering, volcanism, faulting, and fluvial erosion. The terrain in the southern hemisphere is very heavily cratered and thus quite old, having formed some 3.8 × 109 years ago. Much of it stands 1–2 mi (1–4 km) higher than the planet's mean radius. By contrast, the northern hemisphere is dominated by vast, lava-covered plains with relatively few impact craters and an average elevation of about 3 mi (5 km) below the mean radius.\n\nThe Tharsis rise, or bulge, is an uplifted portion of the surface that stands several kilometers above the mean elevation of the planet. Most of Mars's tectonic features are associated with Tharsis, which affects approximately one-quarter of the entire surface.\n\nThe Martian surface exhibits several enormous shield volcanoes. The largest and perhaps the youngest is Olympus Mons, which is nearly 370 mi (600 km) across at its base and stands approximately 16 mi (26 km) above the surrounding terrain. Three other large shield volcanoes, Ascraeus Mons, Pavonis Mons, and Arsia Mons, lie along the nearby Tharsis rise. In shape and structure the Martian shield volcanoes bear a strong resemblance to their Hawaiian counterparts. At the summit of each shield is a complex of calderas, collapsed craterlike features that were once vents for lava.\n\nPerhaps the most spectacular features on the Martian surface are the huge canyons located primarily in the equatorial regions. Valles Marineris, actually a system of canyons, extends for over 3000 mi (5000 km) along the equatorial belt. In places, the canyon complex is as much as 300 mi (500 km) wide and drops to more than 4 mi (6 km) below the surrounding surface. Dwarfing the Earth's Grand Canyon, Valles Marineris is comparable in size to the great East African Rift Valley. In general, the walls of the canyon are precipitous, have well-defined edges, and show evidence of slumping and landslide activity (Fig. 1).\n\n\nAn image from the Mars Global Surveyor resolves features as small as 20 ft (6 m) in a 10-km-wide portion of Coprates Chasma, which is located in the middle of Mars's vast
1043193
Venus is closer to the Earth than Mars is.
905767
You are making it needlessly hard on yourself.  The planet has the same mass as the earth, and someone on it weight the same as on earth, therefore the surface of the planet is the same distance from its center as the earth radius, i.e. this planet has the same dimension as earth.\nSo, the radius of the planet is 6,372.797 km, same as earth's.\nYou don't need to compute anything.  The orbital velocity of the planet has nothing to do with it.\nIf the weight was different, you only need to scale it remembering that the weight would vary as an inverse of the square of the radius.
664924
The average distance from Mars to the Sun is 1.52369 astronomical units.  One astronomical unit (AU, the average distance from the Sun to the Earth) is 1.49597870E11 meters.\n\nConverting those numbers, then, means that Mars is:\n\n1.52369 * 1.4959787E11 meters = 2.27941E11 meters, or, converting into English units:\n\n141,635,833 miles (on average -- remember that the orbits of the planets around the sun are not circular, but elliptical)
106913
i'm pretty sure that it's either 3 times greater or 9 times greater coz the gravity on mars is more than that of earth.\nbut i cant decide which one of them is the right one.
123187
Humans will probably live on Mars at some point, though it would probably be only temporary.  Now let's look at the problems.\nThe biggest problem would be making Mars a suitable environment for human life.  Terraforming the planet to give it a similar atmosphere as Earth would take thousands of years, if not longer.  The other option would be to build colonies.  And even then there's the question of what to do about gravity.  Because the gravity on Mars is less than that of Earth humans would have a difficult time maintaining muscle mass and bone density.  So, some sort of solution would need to be found.\nNext, let's face it, Mars is terribly far away and has little to offer, except maybe some frozen water.  And being so far away from Earth would probably be very problematic.  It is much more likely that in the future, if humans are to live in space, they'll live in self-sustained space colonies orbiting the Earth.
1130891
Equatorial circumference of the earth is 40,075.2 km which is\n40,075,200,000mm\nMeridional circumference of the earth is 40,007.86 km wich is\n40,000,786,000mm
774696
probably in planet mars
665122
mass of Earth = 5.9742 × 1024 kilograms
1175686
This can be solved in several different ways.  One of course is by calculus, by developing a formula for the surface area of a "slice" of the remainder of the sphere and integrating it about a rotated axis, or something similar.  Another is by digging for the rather obscure formula for the "volume of the endcaps of a sphere" and subtracting two of those and the volume of a cylinder from the volume of the original sphere (and discovering that many of the terms will cancel out nicely).\n\nThe easiest method, however, is via the use of simple logic.  Unfortunately, this method also requires one more "given" in order for it to be valid, though this given is not an unreasonable one:  There must be a single, real answer (or more specifically, a unique answer on the real number line).  Such an assumption would be folly in a practical (real-world) context, since without some form of proof, one should never immediately assume that this is the case.  Perhaps there are multiple answers, or there is no answer at all?  But as luck would have it, there actually is one answer, and it may be derived logically due to its unique existence.  (*thumbs nose at any philosophers who may be reading*)\n\nSolution:\n\nLet R be the radius of the cylinder drilled into the sphere.  If and only if there is a single, real answer, then that answer would still be the same no matter the value of R... even if R=0.  Thus, the answer is the volume of a sphere of radius 3 (diameter 6), or 36*pi cubic units.\n\n(Yes, the volume is always the same, whether the original sphere were the size of a basketball, or the size of a planet.)\n\nIt's a surprising answer, along the lines of the more familiar puzzle: "If the Earth were a perfect sphere and a band were placed snugly about its equator, and then one more meter were added to the length of the band and it were stretched so that all points along it were equidistant from the surface of the Earth, how far above the Earth would the band rise?"  Many are surprised to find that the size of the Earth plays absolutely no part in the equation, and that the "rise" is exactly the same if the sphere were basketball-sized or, umm... Earth-sized (with a circumference greater than 40,000,000 meters).  It rises exactly the radius of a circle with a 1-meter circumference: 1 / (2*pi) meters.
65671
The Mean Density of Mars is: 3.934 g/cm3