Find the lenghts to the nearest tenth for CE & BCgiven that DE=18m AB=14m, BD=1 and AC=12m. ALso BC II DE.?.?
493661
ce + bc = 26\nbc = 18\nde = 8\nassuming that the total is to be 64 and equaled to an even amount... not sure how to figure this without the figure?
1094272
In your problem, (CE)(ED)=(AE)(EB). \n\nSubstituting, you get (6)(5)=(2)(EB)\nSimplifying, you get 30=2EB\nDividing 2 from each side, you get 15=EB\n\nEB is 15 units.\n\nFor proof of (CE)(ED)=(AE)(EB), connect CB, and AD,\nmeasure of angle BCD=1/2 the measure of arc BD\nmeasure of angle BAD=1/2 the measure of arc BD\nmeasure of angle ADC=1/2 the measure of arc AC\nmeasure of angle ABC=1/2 the measure of arc AC\nmeasure of angle BCD=measure of angle BAD\nmeasure of angle ADC=measure of angle ABC\nBy AA Similarity Theorem, \ntriangle CBE is similar to triangle DAE\nBy the definition of similarity,\nED/EB=AE/CE\nBy the cross product theorem,\n(CE)(ED)=(AE)(EB)
252742
I believe the bounds are where the numbers are deviated but still close. Say, in the problem, 11 cm is measured to the nearest centimeter. So, it may not be 11cm. It could be 10.6 cm, 11.3 cm, or even 10.51294803 cm. But they'll all be 11cm in the measurement. \n\nSo for the question, if it's asking for the minimum possible area:\nLet l be length and w be breadth. \n10.5 <= l < 11.5\n8.5 <= w < 9.5\nThe lower bound would be composed of the shortest length and breadth. \nA = 10.5(8.5) = 89.25 cm^2
299035
just like the person above (bree) says but you can further reduce the 18. \n\nx= 3c sqrt(2)
300929
r is probably 27 and t is 8. Here's my reasoning:\n\n18 * 18 * 18 = r * r * t\n5832/r = r * t\nLets factorize 5832\n5832 = 27 * 27 * 8\nAnd Since 27 > 8, it can be accepted as the solution.\n\nI don't know if this is the correct way of doing it. Anyway, in my opinion worth a shot.
850438
1 5/6- 11 3/6=2/6\n\ncorrect answer is A. 2/6 " shorter. or C. 2/6 " shorter\nDid you intend to repeat 2/6 in shorter?
233014
U R RIGHTT..HOW DID YA GET IT..PLZ CAN YA EXPLAIN..I'VE BEEN TRYING THIS PROBLEM FROM A LONGTIME.EVEN DE CALCULATOR SAYS ITZ "4"..I KNOW DE CALCULATORS WRONG TOO..PLZZ DO EXPLAIN IT TO ME ASAP
630777
18x = 18\n x = 1\n\nnow gimme me 10 pts
732742
awnser :length =18feet\n\np=2L+2W\n60=2L+24\n-24     -24\n36=2L\ndivide by 2\n18=L
474388
Okay, first, since the vector given for B is a unit vector, we know that the vector from the origin to B must be given by (some constant)*(2,-2,1)/3.  So, what you want to do is find the value of that constant such that |A-B|=10.  Do this by setting A-B=(6-2x/3, -2+2x/3, -4-x/3).  Then just find the length of that vector in terms of x, set it to 10, and solve for x.
1151145
Calculate acceleration a=(24-10)/16 = 14/16\nF=ma=1200*(14/16)=1050N
368833
10 - B.\n11 - A.\n12 - C.\n13 - B.\n14 - B.\n15 - B.\n16 - C.\n17 - C.\n18 - A.\n19 - A.\n20 - C.
129441
It's not possible.\n\nLet a be 20Rs, b be 10Rs, and c be 1Rs\n\na + b + c = 10\n20a + 10b + c = 50\n\nWe can get from these two 10b + 19c =150, or b = 15 - 1.9c\n\nBut no matter what positive integer you put for c, b won't be a positive integer.\n\nSo unless you have half-coins or something, No Solution.
622500
10 = c\n\n11 = c\n\n12 = b\n\n13 = c\n\n14 - not sure\n\n15 - not sure
943434
2(2.5b -9) +6b =7  distribute 2\n5b-18+6b=7   combine like terms\n11b-18=7   add 18\n11b=25   divide by 11\nb=25/11=2 3/11=2.273\n\n12y = 2y +40   subtract 2y\n10y=40   divide by 10\ny=4\n\n6(c +4) = 4c -18   distribute 6\n6c+24=4c-18    subtract 4c\n2c+24=-18    subtract 24\n2c=-42    divide by 2\nc=-21
774792
Let the length of side "b" be x ft.\nTherefore side a=2x and side c=2x+3\nAccording to the problem,\nx+2x+2x+3=93\n=>5x+3=93\n=>5x=93-3=90\n=>x=90/5=18\nTherefore.side a=2X18=36 and side c=36+3=39\nAnswer a=36ft. b=18 ft and c=39 ft
762351
make two equations    5m+6e=135 and 3m+4e=85....you want to cancel either m or e so multiply the first equation by -3 and the second by 5\n\n-15m-18e=-405 1st equation\n15m+20e=425 2nd equation subtract the two\n0+2e=20\n2e=20\ne=10  plug this into one of the original equations\n5m+6*10=135\n5m+60=135\n5m=75\nm=15