proove that 2=3., clue--start with 0=0?
489740
let 0=0\n   then a^2-a^2=(a-a)(a+a)\n  then a(a-a)=(a-a)(a+a)\nthen a=2a\nthen 1=2\nthen 2=3
82888
1) Y=0\n\n2) X=0\n\n3) X=17 & Y=1
854837
Show it's a zero just means you sub x = -3 in the polynomial and get the result zero.  If that happens, you can divide the polynomial by \nx -(-3),  i.e. x + 3, and then find the zeros of the remaining expression.  Want to do it yourself?  Good.  Then don't scroll down to see what I've done.\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n-3      2     5     -6    -9\n\n              -6       3      9\n\n         2    -1     -3      0\n\nP(x) = (x + 3)(2x^2 - x - 3)\n       =  (x + 3)(x + 1)(2x - 3)\n\nZeros are -3, -1, 3/2
923617
First, factor out 3x from the equation, so 0= 3x(x^2-2x-3).\n\nThen, factor the polynomial in the parenthesis, so 0= 3x(x-3)(x+1)\n\nAfter that, use the zero product property to set each part of the the equation to zero, so 0=3x, 0=x-3, and 0=x+1.\n\nSolve these three to get x=0, x=3, and x=-1, respectively.
367158
(0! + 0! + 0! + 0! + 0!)!\n\n\n0^0 is undefined.
68748
uhm, ZERO!  0x2=0  what, did you fail basic math?
754459
3x^2-5X-2=0 \n(3x+1)(x-2)=0\n3x+1=0\n x=-1/3\n\nx-2=0\nx=2
898312
x can be zero to make the whole equation 0\n\n(2x-5) = 0...x = 5/2 plug it in and it does work\n\n(3x+9) = 0...x = -3 (but no negative reals)? so i guess that doesn't count?
1119411
1. Add 3 to both sides to set equal to zero, then factor to get something that adds to three and multiplies to 28---7 and -4\n(x-4)(x+7) = 0\nx=4, 7\n\n2. Add 4 to both sides to set equal to zero, then factor to get something that adds to 2 and multiplies to -15---5 and -3\n(x+5)(x-3) = 0\nx = -5, 3
211777
n=3\nl=1\nm sub l =1,0, or -1\nm sub s = + or - 1/2
884616
Possible .X....Y\noutcome\nHHHH......3....3\nHHHT......3....2\nHHTH......2....2\nHTHH......2....2\nHHTT......2....1\nHTHT......2....1\nHTTH......1....1\nHTTT......1....0\nTHHH......2....3\nTHHT......2....2\nTHTH......1....2\nTTHH......1....2\nTHTT......1....1\nTTHT......1....1\nTTTH......0....1\nTTTT......0....0\n\nHence,\nP(X=3,Y=3)=1/16\nP(X=3,Y=2)=1/16\nP(X=3,Y=1)=0\nP(X=3,Y=0)=0\nP(X=2,Y=3)=1/16\nP(X=2,Y=2)=3/16\nP(X=2,Y=1)=2/16\nP(X=2,Y=0)=0\nP(X=1,Y=3)=0\nP(X=1,Y=2)=2/16\nP(X=1,Y=1)=3/16\nP(X=1,Y=0)=1/16\nP(X=0,Y=3)=0\nP(X=0,Y=2)=0\nP(X=0,Y=1)=1/16\nP(X=0,Y=0)=1/16\n\n.................JOINT PROBABILITY DISTRIBUTION OF x & y\n\n........0.1....2.3.....|P(X=x)   \n...&#92;Y|__________|\n..X&#92;.|..........................|\n..__|..........................|\n....0|1/16.1/16.0.0.....|2/16\n......|..........................|\n....1|1/16.3/16.2/16.0|2/16\n......|..........................|\n....2|0.2/16.3/16.1/16|6/16\n......|..........................|\n....3|0....0..1/16..1/16|2/16\n......|..........................|\nP(Y=y)|2/16.6/16.6/16.2/16|1\n\nfOR 2nd part we have to find \nP(X=3|Y=1)=P(X=3,Y=1)/P(Y=1)=0\nP(X=2|Y=1)=P(X=2,Y=1)/P(Y=1)=(2/16)/(6/16)=1/3\nP(X=1|Y=1)=P(X=1,Y=1)/P(Y=1)=(3/16)/(6/16)=1/2\nP(X=0|Y=1)=P(X=0,Y=1)/P(Y=1)=(1/16)/(6/16)=1/6\nHence\n      conditonal probability distritribution of X given Y=1\n......X...|0.1.2.3..|TOTAL\n.....___|_______|_____\nP(X=x)|0.1/3.1/2.1/6.|1\n\nForget about those (.........)s. They are provided so that the tables do not collapse.
339198
2x0 = 0\nIt'll be the same as today... :P
730496
iteration1: a = 3, b = 2\niteration2: a = 13, b = 8\niteration3: a = 51, b = 30\nloop exit:  a = 81, b = 30 // condition a = a + b executed before exit
887323
1 4 2 5 3\n\nBut it's cyclical, so the sequence is 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 ... and so on.\nYou can start anywhere in the sequence. The first answer you received is correct, but that person chose to start with 3 instead of 1.
834770
3x^2-x-4=0\n=> 3x^2-4x+3x-4=0\n=> x(3x-4)+1(3x-4)=0\n=>(3x-4)(x+1)=0\nTherefore,either 3x-4=0 or x+1=0\nIf 3x-4=0,then x=4/3,and \nif x+1=0,then x=-1\nTherefore, x=4/3 or -1 ans
241669
Y=x^3(x+2)(3x-1)\n we have three possibility for x\nx^3=0 than X=0\nx+2=0 than X=-2\n3x-1=0 than x=1/3\n\nso the answer is a
877357
#1\n\nt=0 or -3\n\n#2\n\np^2 - (1/4)^2 which is p^2 - 1/16