How do you find "B" in the equation for graphing a line, "y = mx + b" ?
490656
Make Y=0\nyou have to have m and x though to solve b\nExample:\nY=mx+b\n0=3(4)+b\n0=12+b\n -12 on both sides of equal sign\n-12=b\nhope this helped!
63789
A line's equation is y=mx+b where m is the slope of the line and b is where it crosses the y-axis.  In this case, you need to simplify the equation down to make it into the y=mx+b format.  If you do this, you get y=10x-13.  So in this instance, the slope of the line is 10.
744864
although Question is little vague, i understand that u want to find slope of a line ???\n\nsay coordinatyes of A and B are (x1,y1) and (x2,y2)\n\nThe Slope of line m= (y1-y2)/(x1-x2)
954269
it is natural to write the equation of st.line as y=ax+b (now common form is y=mx+c; this has its own story!)\n\nso if x=0, y=b
704179
An equation in slope-intercept form is y = mx + b\nIn the equation, m = slope and b = y-intercept\n\nUsing the equation given\ny=-3/2x+6\ny = mx + b\n\nWe know that the slope is -3/2.  That would be m.\nWe know the y-intercept is 6.  That would be b.\n\nNow we have to find the x-intercept.\n\nTo get the x-intercept, we will set y = 0 and solve the equation for x.\ny=-3/2x+6\nSubstitute 0 for y\n0=-3/2x+6\nAdd 3/2x to both sides\n3/2x = 6\nMultiply both sides by 2/3\n2/3*3/2x = 6*2/3\nx = 4\nThe x-intercept is 4.\n\nSlope =  -3/2. \ny-intercept = 6.\nx-intercept = 4.
1016870
y = mx + b, where m = slope, and b = y-intercept\n\nYou have the variables Y, M, and X. So, let's find b:\n\n5 = (-2/5)(17) + b\n5 = -6.8+b\n11.8 = b\n\nYour equation would then be:\ny = -2/5x + 11.8
872809
If the equation is lineear, or a line like it sounds like, the equation is y=mx+b. m is the slope or ten. and b is the y-int. or -130, and you are done
94805
If you know how to find the slope of a line in the form y = mx + b, just write the equations of two lines with different slopes.  They will have to cross.  Graph each line and find the crossing point.  That's the answer.  Hint:  make the slope of one line be the y-intercept of the other line and vice versa.  Then they will cross at an exact point on the graph.
746165
Remember the fomula...\n\ny = mx + b\n\nm = Slope\n\nb = Y-intercept\n\nx and y = points\n\nSo plug everything in...\n\n1 = 4(2) + b\nMulitply\n1 = 8 + b\nSubtract 8 on each side\n-7 = b\n\ny = 4x - 7
540264
a linear equation is just x+y=a number, or y=x+a number.  It could also have a coefficient in front of x or y in either equation.  To graph it, either use the slope-intercept form, where you take y=x+a number, the coefficient in front of x is the slope, and the number after x is the y-intercept, so, you plot (0, the number) and use the slope to find another point, then draw your line.  The second is to find two or three points that fit the equation and plot them.  Just substitute a number in for x two or three times, find y each time, and plot those numbers, then draw a line through them.
578147
First, you'll move the 6x to the other side to create the equation y=mx+b.  M=Slope.  Divide by 5 to get Y by itself, then you're left with y=-6/5x+13.  So slope is...\n\n-6/5
3669
This is for math right? If so:\n\nThe slope-intercept form is:\n\ny = mx + b\n\ny = value on the y-axis\nm = slope\nx = value on the x-axis\nb = y-axis intercept\n\nThe slope-intercept form gives the equation for a straight line.
104788
Remember the slope-intercept form?\n\ny = mx + b.\n\ny = the y coordinate.\nx = the x coordinate.\nm = the slope.\nb = the y - intercept.\n\nyour equation is already in slope-intercept form. so all you need to do is match up your numbers with the y = mx + b.\n\nThe slope is -5.\nThe y - intercept is -17.\n\nHope that helps :)
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
311234
-2/3\n\nTo find the slope, rewrite the equation in the form y = mx + b\n\n3y = -2x + 6\ny = (-2/3)x + 2
284371
To solve this, you need to know how to write the equation of a line:\n\ny = mx + b\n\nYour math book should describe in detail how to derive this equation and what it means. Basically, m is the slope of the line and b is the y-intercept (the x coordinate where the line crosses the y-axis).\n\nYou can take the equation of the line given, y = 4x + 3, and figure these things out.\n\nm = 4 (the slope)\nb = 3 (the y-intercept)\nThis y-intercept can also be written as (0,3) being a point on the line.\n\nThe second part is to figure out the equation for a perpendicular line. First, the slope will always be -1/m. Therefore, the slope of your new line will be -1/4. What about the y intercept? We don't yet know this, but we do know a point on the line. What we can do is use the equation above, fill in the slope and the (x,y) coordinates, and solve for b.\n\ny = mx + b\nWe know: point (x,y) is (-1,3) and m = -1/4\n3 = 1/4 * (-1) + b\n3 = -1/4 + b\nb = 2 3/4\n\nHope that helps explain how to do these problems.\n\nEdit: Sorry, I had the point written backwards as (3,-1). I corrected the mistake. That's why it helps to write everything out!
379574
y=mx+b\n\nm=slope=-2\nb=y-intercept=-3\nplug it into the equation\ny=-2x-3