a very hard sequence question?
482632
Multiply the last 2 terms together and then add 1.\nIf that is the pattern (looks like it is) then it should be 155, not 153.\nTo find the next 3 terms, just keep going. (You'll need a calculator with lots of digits).\n22 * 155 + 1 = 3411\n155 * 3411 + 1 = 528706\n3411 * 528706 + 1 = 1803416167
772626
The number is 41312432.\n\nThe "4" is in the 1st anf fifth space. 4_ _ _ _4_ _\nThe "1" is in the 2nd and 4rth space_1_ 1_ _ _ _\nThe "3" is in the 3rd and 7th space _ _ 3_ _ _3_\nThe "2" is in the 5th and 8th space_ _ _ _ 2 _ _2\n\nDon't know any way to show steps other than the way I did here...\n\nBTW the number 23421314 also satisfies the requirements.
1164476
The next number is 3. \nGoing by the number sequence and the number of letters per word in your question then that would be the next number. \nThe final number would be 3 as well.
1086560
f(-2) = 5. What's so difficult about this question?
797929
1 -> b\n2 -> e\n3 -> c\n4 -> d\n5 -> a\n6 -> f
723065
The sequence is the given series is *2 *3 *4 *5 *6and so on...so the answer is 720
320882
1 2 3 4 5 6 7 8\n<---[======)--->
394920
1) [1/x] <= 1/x, for all x>0\n2) [1/x] = 1/x, iff 1/x is an integer, so x=1/n for some integer n.\n3) [1/x] < 1/x, for all x != 1/n for any n (x>0).\n4) So, f(x) = [x*[1/x]] = [x*1/x] = [1] = 1 for all x=1/n for some integer n.\n5) Also, x*[1/x] < x*1/x = 1 for all x != 1/n for any n (x>0),\nthen f(x) = [x*[1/x]] = [<1] = 0 for all x != 1/n for any n (x>0).\n\nlim f(x)(x->a) = b, iff for ALL sequences {a_n->a} f(a_n)->b.\n\nLet's take 2 sequences:\n{a_n = 1/n} f(a_n)=1 for all n (see 4), so f(a_n)->1.\n{b_n = 2/(2*n+1)} f(b_n)=0 for all n (see 5), so f(b_n)->0.\nEasy to see that {a_n}->0, {b_n}->0.\n\nThus, there is NO limit of f(x) when x->0.\n\nPS: "iff" means "if and only if"
842276
1,2,3,4,6,8,12,16,24,48 \n\nlolz hope this helps :)
1059802
well that is an easy one.....\n\nIt is in alphabetical order
859715
1) 4-3x<_8+x\n4+8<_x+3x\n12<_4x\n3<_x or x in the interval [3,plus infinity)\n\n2) 3x-3>-x+1\n3x+x>1+3\n4x>4\nx>1 or x in the interval (1, plus infinity)\n\n3) 3(x-1)_<4x\n3x-3<_4x\n-3<_x or x in the interval [-3, plus infinity)\n\n4)1/2x<x+1\n-1<x/2\n-2<x or x in the interval (-2, plus infinity)\n\n5)-1/2x>1-x\nx/2>1\nx>2 or x in the interval (2, plus infinity)
759105
False... y has to be 2...\n(3,2) is a solution, but not (3,1).
602536
Don't believe your have a closed form of U(n). Perhaps, that's because you couldn't type the formula correctly.\n\nOnce you have the correct closed form of U(n), just try to see if you could find the limit as n approaches infinity, then you know whether the sequence converges or not.
1103012
35\n\nThe sequence is every even-indexed Fibbonacci number plus 1.  So from the original sequence whose value is the sum of the two previous numbers:\n\n0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, ...\n\nYou take every second number and add 1:\n\n2, 3, 6, 14, 35, 90, 234, ...
902613
I just plugged this into my calculator.\n\n[1, 0, 2, 0, 2, 0 | 0\n0, 1, -3, 0, -2, 0 | 0\n0, 0, 0, 1, -1, 0 | 0\n0, 0, 0, 0, 0, 1 | 0\n0, 0, 0, 0, 0, 0 | 1 ]\n\nTake it however you want.
786690
u can do it by\n(n/2)(a+l)\nwhere \nn is no. of terms\na is first term\nl is last term
326938
| | | | + - - - - -  = TEN\nthe question is really 4 lines + 5 lines = the words ten