word problem? please help?
490704
Let s = speed of the boat\n\n60 / (s - 10) = 140 / (s + 10)\n140(s - 10) = 60(s + 10)\n140s - 1400 = 60s + 600\n80s - 1400 = 600\n80s = 2000\ns = 2000 / 80\ns = 25\n\ncheck:\n60 miles at 15 mph = 4 hours\n140 miles at 35 mph = 4 hours\n\nThe answer is 25 mph.
478142
Hi there,\n\nIs it possiple you left out a P?\nThen the answer is PROGRAMME.\n\nHave fun puzzling! ;)
954030
Try on  the forums of wordreference.\n\nwww.wordreference.com
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
614837
I already posted this solution (or how to get it).  Do a search of yahoo answers....
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
706993
Try reviewing your class notes and looking through your text book. Im sure that the answer you need is there. It might take a bit of thought to figure out how to do these problems! Take the time to figure it out, it will be worth it in the long run!
349201
Write out the sample space:\nHHH, HHT, HTH, THH, HTT, THT, TTH, TTT.\n\nThere are 8 different possibilities - 2^3.\n\nTwo of the outcomes: HHH and TTT are all the same -\nProbability is 2/8 = 1/4 = .25.
347066
ok, i think one will be where you have to solve a word problem dealing with alegebra. One with number sentences that have a letter on one side of the problem and letters on both sides of the problem. i could be wrong, but i'm trying to help.
649445
1.D\n2.B\n3.B\n4.A\nright?
855129
Word problems like this can be hard.  Everybody has problems with them sometimes.\n\nIt does help to draw it out.  So you draw a little rectangle like this:\n ______________\n|                            |\n|                            |\n|______________|\n\n2 of the sides are 120 m and the other 2 are 150 m.  So you take 2 times each of these numbers and add them together:\n2(120) + 2(150)\n\nThat's your perimeter, in meters.  Now if your poles are 2 m apart, you don't need one for every meter you get in your answer, you only need 1 every 2 meters.  So you divide your answer by 2, and that gets your number of poles you need to put around the field.
906875
The trick is turning the word problem into equations.\n(Key: length = l; width = w)\n\nThey tell you the length is 3 feet more than twice the width, so:\nl = 2w + 3\n\nThen they tell you the perimeter (which is twice the width and twice the length) is 36, so:\n2l + 2w = 36\n\nYou should be able to take it from there.
261922
product\nprice\nplace\npromote
897586
X2O\n\nExamples:\nH2O => Water
88228
alright... whats the word u want the answer to this riddle to be? Hunger! yay 2 points for answering a question lol, sry, but thats a tricky one
165476
How about (a+c)/(b+d)  ? more interesting!!\n\nbtw this only work when a/b != c/d
1142710
Use this formula, you can find millions of them\n\nL x W = 2(L + W)\n\nuse any number for L and solve for W