someone rode for 20secs with 1.5m/s2 acc.for 2min.at const.speed and braked for 15secs and stopped.?
482401
Assume starts at Zero speed.\nMax speed is after 20 sec during which added 1.5m/s of speed each of these seconds.\nDistance during this phase d = Half a * (t squared)\nDistance during middle phase is  Max speed (as above) times 120 (NOT 2) seconds.\nDeceleration in third phase is Max speed (as above) divided by each of the 15 seconds it took to lose that speed. (If it does not work out as 4/3rds the acceleration, you have a problem!)\nDistance in the third phase is again d = Half a t^2  (Strictly speaking ut + 0.5at^2 with negative value of a, but no difference in this case as comes to a stop)\nDraw graph of speed v time (NB seconds - don't mix with minutes) find area by geometry.\nEdit - give you a clue - the distance is not 3900 and the deceleration is not 0.5 (nor even -0.5) as above.  Have you ever been tempted to give someone the wrong answer?
761829
I would think speeding.
359641
UMMM NO.  What kind of question is that????  If someone is moving that fast on you, you better be careful.
1076359
0-60 is around 2 secs, and the braking is almost as fast, so it should be around 4 secs.
402977
1st question: Answer is 10km/(2/3hr) = 10*3/2 km/hr, that is\n              15km/hr\n\n2nd question: Answer is 200m over 160s, that is:\n                    200m/160s = 1.25 m/s
231616
in a flat stable position it is broadly 120 miles per hour (takes about 10 seconds to get to that).  Head down (max track) you are nearer 200 mph =8-)
853764
he does has KE. if he doesn't , he wud be at rest in his seat if the brakes r applied suddenly. Observe this out from the bus. This's all bcoz of inertia of motion
403963
Sub 3hrs....he used to be a very good triathlete before he became a pro-cyclist.\n\nGo Lance!!!
671105
almost exactly, assuming someone on earth is doing the measurement. someone moving very fast would get a different result.
47765
If I were you, I would stay away from driving a fast vehicle. And get your brakes checked.
761782
He could have caused a major accident there fidgety.\nReminds me of the young man who is trying out his new sports car on a quiet country lane.There's no traffic about so he risks taking it up to 70mph,then 80mph, and then 90.He turns a corner and sees two old farmers standing in the middle of the road chatting.The man wrenches the wheel sideways,the car shoots up an embankment,flies into the air,and crashes in the middle of an adjacent field.One of the farmers turns to the other and says" That was lucky.I reckon we got out of that field in the nick of time."
694954
Variables: 150 rev/min  2.2h = 140 min \n(a) Difference in velocity (150 to 0) over difference in time (0 minutes to 140)\ndelta v / delta t   (150-0)/(0-140) = -1.0714 rev/min/min\nAcceleration is negative since it is slowing down.\n(b) during the slowdown? one less than the answer to (c)?\n(c) (v not times delta t) / acceleration absolute value  (150*140)/|-1.0741|  =  19553.07 revs\n(d) and (e) email if you really want, but this stuff should give you a start. Hope this isn't due for a couple days tho.
685470
the speed = distance/time
125221
20...in...unfortold amount of seconds...
926411
The stop distance is not an arithmetic progression (ie it is not 40m). It is in fact a geometric progression. The stop distance is a lot lot more. Truthfully, I don't know but if you were travelling at 120 kmh and there was a truck 40m (or even 60m) in front of you when the brakes locked; you'd be dead.
708458
Its probably 2pts.  Im not sure but it is a "moving violation"
554892
(m)\n\nRain falls at an average of seven miles per hour