how an array of 5x46 can help you find the product of 5x46.?
480823
if your array is 5 wide by 46 long, then you just assign an incrementing value to each consecutive cell and you will find that the last cell (5,46) = 5 X 46.\nSee below:\n\n1,2,3,4,5,6,....44,45,46 -cell (1,46) = 1 X 46 = 46\n47,48,49,50,....90,91,92 -cell (2,46) = 2 X 46 = 92\n...\n...\n...228,229,230 - cell (5,46) = 5 X 46 = 230
842178
Start with the whole array as set Q.\nUse algorithm X to get the median M of Q.\nSet a = [size of Q]/2.\nIf a = k, stop; M is your answer.\nIf a > k, set Q = the values less than M, otherwise set Q = the values greater than M.\nRepeat.\n\nThis algorithm is a bit off because when [a > k], the comparison [a <=> k] is subsequently invalid.  But you get the gist of it.  Use X in a binary search mode.
632642
To solve this problem, you have to do ratios. Now, according to the image, do the ratio: small/long for one diagonal = small/long for the other diagonal. In this case, 6/10 = 5/x. Cross multiply to get 6x = 50. x = 50/6 or 25/3. I can't see the answer choices provided because they're so small but I can gurantee that the answer is 25/3, which i believe is c
306814
204 total.\nThe size breakdown is as follows:\n204 =1+4+9+16+25+36+49+64 = n(n+1)(2n+1)/6 when n=8 \n\n1 size 8x8\n4 size 7x7\n9 size 6x6\n16 size 5x5\n25 size 4x4\n36 size 3x3\n49 size 2x2\n64 size 1x1
818446
It is called an ARRAY
276464
(1x12)+(2x11)+(3x10)+(4x9)+\n(5x8)+(6x7)+(7x6)+(8x5)+\n(9x4)+(10x3)+(11x2)+(12x1)\n=12+22+30+36+40+42+42+\n40+36+30+22+12=364\n\n\n364 gifts
777975
6x-4=56\n6x=56+4\n6x=60\nx=60/6\nx=10
103215
With this given data, it is not possible\n\nalthough the area is totalling to be 70 for both cases (7*10 and two pieces of 8*8 + 1*6) but with one division only, this is not possible\n\nPLEASE DO LET ME KNOW IF THERE IS SOME SOLUTION (i found it very interesting)
332600
to find areas of parallelograms use the formula: \n\nA = base×height.
374444
100\n\n(10mm=1cm; 10x10=100)
359961
Find the areas of all 6 faces of the rectangular solid by muliplying each one's width by length.  Then add them together for the total surface area.  To find volume, multiply length by width by height.  The ratio will be the total surface area divided by the volume (or expressed as a fraction the total surface area over the volume).
799073
-4x + 10 = 6x - 40\n\n-----------------------------\n\n+4x to each side:\n\n(-4x +4x) +10 = (6x+4x) - 40\n10 = 10x - 40\n\n------------------------------\n\n+40 to each side:\n\n(10 + 40) = 10x (-40 + 40)\n50 = 10x\n\n------------------------------\n\nDivide each side by 10:\n\n50/10 = 10x/10\n5 = x\n\n------------------------------\n\nSo your answer is x = 5
1137110
first distribuit\n24x-6x=12x-36\nthen\n18x=12x-36\n-12x\n6x=-36\ndivide\nx=-6\n\nadd x\n-10>x+36\nsubtrack 36\n-46>x\nso\nx<-46
53856
are you guys still doing homework on Friday night?\nFind the common demoninator for the three numbers.\n2x3=6\n6x3=18\n2x9=18\nso 18 is the common denominator\n2x9=18\n9x2=18\n3x6=18\nWhat ever you do to the bottom, you also do to the top.\nNeed more help....\npinkstealth@yahoo.com
306958
60\n\n3x4=12\n\n12x5=60\n\nYou should review your algebra skills. A, B, and X are all variables, meaning they represent numbers. This problem tells you what the variables are, so you just substitute them in. Therefore Y=3x5x4
751280
multiplication\n\n\nDoug
706198
5*4*3 = 60\n\nExample:\nNow let's suppose we have 10 letters and want to make groupings of 4 letters. It's harder to list all those permutations. To find the number of four-letter permutations that we can make from 10 letters without repeated letters (10_P_4), we'd like to have a formula because there are 5040 such permutations and we don't want to write them all out! \n\nFor four-letter permutations, there are 10 possibilities for the first letter, 9 for the second, 8 for the third, and 7 for the last letter. We can find the total number of different four-letter permutations by multiplying 10 x 9 x 8 x 7 = 5040. This is part of a factorial \nhttp://mathforum.org/dr.math/faq/faq.comb.perm.html