what is the minimum and maximum lengths of par 3,4 and 5's ?
482661
The USGA has issued guidelines \nThe current guidelines are these for men:\n\nPar 3 - Up to 250 yards\nPar 4 - 251 to 470 yards\nPar 5 - 471 yards to 690 yards\nPar 6 - 691 yards or more\n\nNow many holes may play longer or shorter than the posted yardage.  That is why they only have guidelines.  A lot of golf  courses have par 4's over 470 yards.
915221
- How many links should be strung together to form a chain?\n\nNumber of links = 54/0.5 = 108\nsd = 108 * 0.01 = 1.08\n\nSo mean length (μ) of 108 links = 54" with a sd (σ) of 1.08"\n\n- What proportion of the chains would meet BD's standards?\n\nz = (x - μ)/σ + 0.5\n= (54.25 - 54)/1.08 + 0.5\n= ~0.7315\n\nFrom a table of z-scores establish the proportion that would lie above the mean and double it for those that lie below the mean.\n\nP(-∞ to 0.7315) ≈ 0.617 (Ref Table 1)\nTherefore P (-0.7315 to 0.7315)\n≈ (0.617 - 0.5)*2\n= 0.117 *2\n= 0. 234\nie 23.4% of the chains will meet the standards and 76.6% of chains fail\n\n- Supposed BJ Company wished to reduce the proportion of chains that failed to meet Bridgestone’s standards to one third the current value to what value would they have to change the standard deviation of the length of the individual chain links?\n\nif only 1/3 fail (1/6 too long and 1/6 too short) then 2/3 pass and so want to establish z for p ≈ 0.5 + 0.333 = 0.833\n\nFrom table (See Ref 1)\nz ≈ 0.7975\n\nSo 0.7975 = (54.25 - 54)/σ + 0.5\n0.25/σ = 0.2975\nσ = 0.25/0.2975\n= 0.84 inches for the 108 links\n= 0.0039 inches per link
870849
Depending on the size 3-5 mph
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***********************************************************************\n\n18 holes on a golf course\n\n***********************************************************************
68097
do you mean things as far as max and mins, asymptotes and things like that?\n\nif you are a little more specific i can help you better, or e-mail me, it would be a little easier  matttlocke@yahoo.com
721808
If you are trying to make a triangle out of three equal lengths, all you do is devide 180 by 3.....and taddaaa you get your angles.\n\nIf does not matter how long each side is.
500492
The max is 14, if you start with less than 14 you can add clubs until you hit 14 during the round.  You can not share clubs, unless it's with a partner.  When you share clubs you cannot have more than 14 between the people sharing.  starting around knowing you have more than 14 clubs is DQ.  Not knowing is 2 strokes per hole with a max of 4 strokes.  Matach play loss of hole max 2.  That is how someone can be 4 holes ahead after only playing 2.  \n\n\n   a. Selection and Addition of Clubs\nThe player must start a stipulated round with not more than 14 clubs. He is limited to the clubs thus selected for that round except that, if he started with fewer than 14 clubs, he may add any number provided his total number does not exceed 14.\nThe addition of a club or clubs must not unduly delay play (Rule 6-7) and the player must not add or borrow any club selected for play by any other person playing on the course.\n b. Partners May Share Clubs\nPartners may share clubs, provided that the total number of clubs carried by the partners so sharing does not exceed 14.\nPENALTY FOR BREACH OF RULE 4-4a or b, \nREGARDLESS OF NUMBER OF EXCESS CLUBS CARRIED: \nMatch play ;— At the conclusion of the hole at which the breach is discovered, the state of the match is adjusted by deducting one hole for each hole at which a breach occurred. Maximum deduction per round: Two holes.\nStroke play — Two strokes for each hole at which any breach occurred; maximum penalty per round: Four strokes.\nBogey and par competitions — Penalties as in match play.\nStableford competitions — see Note 1 to Rule 32-1b. \n c. Excess Club Declared Out of Play\nAny club or clubs carried or used in breach of Rule 4-3a(iii) or Rule 4-4 must be declared out of play by the player to his opponent in match play or his marker or a fellow-competitor in stroke play immediately upon discovery that a breach has occurred. The player must not use the club or clubs for the remainder of the stipulated round. \nPenalty For Breach Of Rule 4-4c:\nDisqualification.\n\n\nQ. A player starts a round with 15 clubs. He discovers his error at the 2nd tee after his opponent or a fellow-competitor has played but before he has played. Does the player incur the maximum penalty of (a) deduction of two holes in match play or (b) four strokes in stroke play?\n\nA. No. Since the player has not started play of the 2nd hole, he incurs a penalty of (a) deduction of one hole in match play or (b) two strokes in stroke play.\n\n4-4a/12 Competitor Who Misplaces Putter Borrows Fellow-Competitor’s Putter\n\n\nQ. In stroke play, A, who had mistakenly left his putter at the previous green, borrows a putter from B, a fellow-competitor, and uses it. At the next tee, the Committee is advised of the situation. What is the ruling?\n\nA. A was not entitled to borrow a club selected for play by any other person on the course — Rule 4-4a. A incurs a penalty of two strokes for a breach of Rule 4-4a and must immediately declare B’s putter out of play as prescribed in Rule 4-4c. If A recovers his own putter, he may use it.\nB may have his putter returned to him and use it for the remainder of the round.\n\n4-4a/13 Player Practices with Another Player’s Club\n\n\nQ. A player starts a round with 14 clubs. Between the play of two holes he borrows another player’s putter and makes several practice putts on the putting green of the hole last played. What is the ruling?\n\nA. There is no penalty. Such practice putting is permitted by Rule 7-2. The borrowing of the putter does not breach Rule 4-4a since the putter was not used to make a stroke that counted in the player’s score. (Revised)\n\n4-4a/14 Player Carries Pieces of Broken Club\n\n\nQ. A player starts a round with 14 clubs as well as a club that had been broken into pieces prior to the start of the round, but had not yet been removed from his bag. What is the ruling?\n\nA. The Rules do not contemplate such a situation. In these circumstances, in equity
114574
there is no maximum. Minimum is 14.
200692
15,21,25,28,29,5,1,3,99,31
308532
The length of the touch line must be greater than the length of the goal line. \n\nLength: minimum 90 m (100 yds) maximum 120 m (130 yds) \n\nWidth: minimum 45 m (50 yds) maximum 90 m (100 yds) \n\nInternational Matches \n\nLength: minimum 100 m (110 yds) maximum 110 m (120 yds) \n\nWidth: minimum 64 m (70 yds) maximum 75 m (80 yds)
450313
10 percoset should do the trick\nThis is a joke....just in case you are dumb enough to try it.lol
15000
I always liked my strings as tight as possible but really it depends on how you play the game. Here's the general grid:\n\nStandard: 50-60\nMidsize: 55-65\nOversize: 60-70\nSuper Oversize: 60-70
256061
2 metres           4 secs \n4 metres           8 secs\n6 metres          12 secs        \ninto deep trouble 13 secs
1052669
I'm not sure - but did you know that most golf ball have between 300 and 450 dimples?
540454
Around 115 to 130 \nhere is some more into \nwww.gcbaa.org Golf course builders association
439151
there isn't any, but the longest that i know of are:\npar 3: 250\npar 4: 560\nPar 5: 650
1102885
No there is not a standard or rule about the height.  A have seem courses with a hole the requires a 12 to 15 foot pole.  The reason is the hole is so steep going up to the green, it requires a longer pols so you can see the flag.  The course I'm thinking about is on a Air Force base in San Antonio TX.