find the domain of the rational expression xsq.-9/(x-4)(x+2)?
481515
If that is x squared time -9 in the numerator then the answer would be all real numbers except 4 and -2 because the denominator cannot be 0.
270471
is the question\ny = √x +3\nor y =√(x+3)where both x and 3 are under the root\nFor the first one the domain would be x≥0\nfor the second one the domain would be x≥-3\n\nP.S. The expression under the sqrt cannot be negative.
1049371
The Domains are    4, -4, -8,and 14. Or, the x values.
46351
Sy   = |x| - x^2 + 2   \n     = (x^2/2) - (X^3/3) + 2X
110508
(x^2+5) / (x^3+15-2x^2+1)^2\non [0,1]
157955
9*9\n=(3^2)(3^2)\n=3^(2+2)\n=3^(4)\n=3*3*3*3\n=(3*3)*(3*3)\n=(9)(9)\n=1(9*9)\n=1(9+9+9+9+9+9+9+9+9)\n=1(18+18+18+18+9)\n=1(36+36+9)\n=1(72+9)\n=1(81)\n=1*81\n=81\nFINALLY, I GOT IT!\nThe answer to this complex rational algebraic problem is 81\n\nDuh!  ;-p
241586
Hello !\n\nA good question.\nSomething like:\n( round((sqrt(9!)) / 9 )  ) x (9/9)\n\n\n© ßogdan @ CyE CORP.
920343
(4/3)[x^3/(2-x)]^(1/3)\n[(2-x)(3)x^2-x^3(-1)]/\n(2-x)^2=\n\n 4x[1/(2-x)]^(1/3)\n[3x^2(2-x)+x^3]/\n3(2-x)^2
255082
by laplace\n   s^2f(s)-sf(0)+4f(s)-4f(0)+9f(s)=9
764329
x(abs[x- (x^2)] (-1=2)\n\n:> peace\n.
966048
(3ab^2)(3ab)^2\n(3ab^2)(9a^2b^2)\n27a^3b^4
689918
use  power rule and product rule\nf'(x)=[1/5]*5*x^4 + 2x(x^2-x-9)+ \n(x^2+9)(2x-1) + 0=\n\nx^4 + 2x^3 - 2x^2 -18x + 2x^3 - x^2 +18x -9 =\n\nx^4 + 4x^3 - 3x^2 -9
787164
is there a specific area that you need help with in rational numbers?  I guess you can use a site that i know of.  Here: \nwww.algebra-online.com\n^ after that put a slash and write: rational-numbers-1.htm\nthat might help you (:
3037
This is not presented as an equation, so the goal appears to be to combine the rational expression --> x+10 \nThat's all you can do with the question as it is written.
873410
1.  (x + 9)(x - 9)\n2.  (t + 2)(t - 2)\n3.  (b + 12)(b - 12)
40850
-3 <4x\n x < -3/4\n solution set : {- infinity ,.............,-3/4}
35579
5(x^4 -9) = 5(x^2 + 3) (x^2 - 3)