Probability calculation; ready?
479518
The probability would be zero.  Since the angles of a triangle in this case would be considered a continuous random variable (meaning that the angle could be anything in the range of (0, 180)), the probability that you would find a triangle with an angle that is exactly 45 degrees is impossible.\n\nThis is analogous to finding a person who is exactly 6 feet tall.  You may find a person who is close to being 6 feet tall, but their height will always be off by a fraction of an inch.  Same is true with the triangles; you may be able to find a triangle that has an angle very close to 45 degrees, but that angle will always be off by a fraction of a degree.
365970
1/161\nTake the number of ways the event can occur divided by the total number of events.
664305
For that to happen, 1 must come on each dice.\n\nThus P(Sum is 2) = P(1 appears)*P(1 appears)\n\n=(1/6)^2 = 1/36
726292
I believe you just gave the probability of the favorable outcome: 3/5.  You need to phrase your question in clearer terms.  More Web 1.0, less Web 2.0.
887044
to calculate just time the total of first choice and the total of second choice or until the total of n choice.\nor you can try this: if you toss n coins total probability is 2^n\nif you toss n dice total probability is 6^n\n\nor if you wanna know the probability just arrange it and try this\nex: the probability if you take two alfabets from A - I are\nAA,AB,AC,ETC\nBA,BB,BC,ETC\nETC\n\n: )
906595
C.\nThis is a binomial probability problem.\nThe binomial formula says \nP(r out of n) = (nCr)(p^r)(q^(n-r)), where n is the number of trials (here 6 rolls), r is the number of successes (here 0, 1, 2, and 3 twos), p is the probability of success (here 1/6), and q is the probability of failure (here 5/6)\nYou need to plug in 0, 1, 2, and 3 for "r" into this formula.  If you do, you get:\nP(0 twos) = .3348979767\nP(1 two) = .401877572\nP(2 twos) = .200938786\nP(4 twos) = .05358367627\nYou add up these answers to get your final answer, about .9913
418035
Abby's answer is for getting exactly \nTTTTTTTTHH\n\nBut the same probability applies for\nHHTTTTTTTT\n\nand\n\nHTHTTTTTTT\n\nThere are C(10,2) ways the 8 tails and 2 heads can occur, so the correct answer is to multiply .5^10 * C(10,2)\n\nThis is the same as c(10,8)/ 2^10 as in the last answer.
735176
Probability is the measure of how likely an event is. Is is given by the formula: \nP = (The Number Of Ways an Event Can Occur) divided by (The Total Number Of Possible Outcomes) \n\n1) To find the probability for a pen to be selected from the first box, you write the number of pens over the total number of items in the box. So: \n\n2 (number of pens) / 10 ( total items in the box) \n\nwhich reduces to 1/5. \n\n2) To find the probabilty for a marker to be selected from the second box, you do the same thing. \n2 (markers) / 5 ( total items in the box) which cannot be reduced. \n\nThe answers are 1/5 and 2/5. \nHope this helps ;-)
696506
There are 10 different digits\nso p(x)=1/10=0.1\nwhere p(x) means the probability of number 'x' being selected.\neg probability of the number 3 being selected,\np(3) = 0.1
67102
43 out of 400.\nThere is 120*120 pairs of minuites within which in which they can arrive resturent. And to be within 3 minuite, the diffrence of this of this  two pair have to be 3 or less. If the first one of this is between 4 to 117, there will be 7 possibility of  second one.\nAnd teher will be 6 for 3 and 118, 5 for 2 and 119,and 4 for 1 and 120.\nso total possibolity is 114*8+6*2+5*2+4*2 that is 828\nSo the probability is 828/14400=43/200.
90357
F- even and odds.  There are 3 even sides and 3 odd sides. So the likelihood is the same for both.
560810
1)  I think you're missing a bit.\n\nGiven that P(W<=4)=0.825 then P(W>4) = 1-0.825 = 0.175\n\nThis is because all probabilities sum to 1.  So since <=4 annd >4 make up all teh possibilities the value could take - then they're total probabilties must be 1.\n\n2)  Expected value\nTo do these you simply have to multiply the probability by the value and total them up.\n\n+36,000×0.7 -6,000×0.3 = $23,400\n\n3)  Binomial\nYou have a bin(6, 1/6) as there are 6 trials and the probability of a success (ie getting a four) is 1/6.\n\nYou require the probability of 2 fours so just using the binomial formula P(X = x) = nCx × p^x × (1-p)^(n-x) you get:\n\nP(X = 2) = 6C2 × (1/6)² × (5/6)^4 = 0.2009\n\n4)  Binomial\n\nthis again is a binomial Bin(10, 0.33) - as we have 10 trials (students) and the probability of each one being a success (ie member of ethnic minority) is 0.33\n\nUse the formula above to get the probability of more than 6:\n\nP(X = 7) = 10C7 × 0.33^7 × 0.67^3 = 0.01538...\nP(X = 8) = \nP(X = 9) = \nP(X = 10) = \n\ntotalling these up gives the probability of more than 6.\nThen the probability of NOT more than 6, P(X <=6) = 1 - P(X>6) using the idea from 1.\n\n5)  The mean of teh binomial is just np (ie the number of trails time the probabilty of success).\n\nSo for your example where we have bin(6, 0.7) it will be 6×0.7 = 4.2 seeds germinating.
956234
26 different calculations.  duh!!!
257322
It's very simple. Every taster has to choose one out of 5 cups, so on every round the probability of a single taster choosing A is 1/5.\nSince the event is repeated 4 times independently, the overal probability will be 1/5 of 1/5 of 1/5 of 1/5.\nThat is, (1/5)^4 = 1/625.
540053
In the experiment of tossing a coin ten times.\nTotal number of possible choices = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 \n\n      = 1024 \n => n = 1024\n\nLet A be the event of getting number of heads is double the number of tails.\n\nFor event A\n------------\nNumber of favourable choices  =  Number of chances of getting heads is double the number of tailes.\n\n                  = No chances for occurance of event A\n                  = 0\n           =>  m  = 0\n\nProbablity of occurance of an event A =  Number of favourable choices / total number of possible choices\n     => P(A) =  m/n\n     => P(A) =  0/1024\n     => P(A) =  0\nTherefore the probability is zero.\n\n\n\nFor all about probabilty:\n\nhttp://www.futureaccountant.com
672123
The probability of A is 26%.  Probability of B is 42%.  Both A and B is 7%.  Probability of neither = 100% - [(26%+42%)-7%] = 39%.  Or in your format, 0.39.
95999
Don't you think you could have written this more clearly? \n\nIf there is a uniform distribution of the weight w being between 5 and 10, then each of these probabilities is equal:\n\nP5_6=P{5<=w<6}\nP6_7=P{6<= w<7}\nP7_8=P{7<=w<8}\nP8_9=P{8<=w<9}\nP9_10=P{9<=w<10} \n\nThe sum of these is 1, so \n\n1=P5_6+P6_7+P7_8+P8_9+P9_10, and\nP5_6=P6_7=P7_8-P8_9=P9_10\n\nso 1=5xP9_10, so P9_10=0.2\n\nThe probability is 0.2.