What does Delta P mean, in terms of fluid power?
476471
It probably means change in pressure.  It is possible that they are refering to change in power though.  I would need the equation to be certain.
1168897
It depends on the pressure pump and the resistance of the pipe.\nSee http://docs.bentley.com/en/HMFlowMaster/FlowMasterHelp-06-02.html
1105154
pressure is: \n p(density)gh / gc =y(specific weight)h\nflow of liquid flowing inside the pipeline is:\n use the bernoulli equation:\n [p1/p(density)g  +  v1^2/2g  +  z1]  =  [p2/p(density)g  +  v2^2/2g  +  z2  +  hf]\n\nnote: p(density) is rho and y(specific weight) ir gamma.
799401
Darcy's Formula is the general equation for flow of fluids. I was going to list it here, but the notation would be too difficult to express in this format.\n\nFind a copy of the book Flow of Fluids Through Valves, Fittings, and Pipe, Technical paper No. 410 by Crane Valves North America
792853
The pressure of a fluid colum is P = (rho) * g * h\n\nYou know that for P = 1 atm and (rho)*g corresponding to Hg, h = 785 mm.\n\nNow change to H20. (rho) is 1/14 of the previous value, g is the same, P is the same, so h must be 14x greater.\n\n--> h = 14 * 785 = 10990 mm.
746288
On these equations D is for Delta :\n\nDh = De +pDV (definition of enthalpy)\npDV = R DT (equation of state)\nDh = Cp DT  (definition of enthalpy)\nWith first law of thermodinamics :\nDe = Dq +Dw = Dq ) Cv DT\n\nSo Cp DT = Cv DT + RDT\n\nSo Cp = Cv +R  so Cp always greater than Cv \n\n :
412802
p=F/A \n\nSo, you have the pressure of the atmosphere pluss the weight of the water above you.  Which is usually figured as a cylinder.  Hope that helps.
947873
The simple reason is that Hydraulics utilizes fluid as opposed to Pneumatics (air) although both are referred to as "fluid power" , the liquid normally oil used in hydraulics is simply uncompressible. SO THE FLUID is essentially stronger than STEEL when a pump pushes the oil to a device like a cylinder, imagine the fluid being a solid BAR of STEEL say 6 inches in diameter, it is literally like pushing a bar of steel.  \n\nHeavy equipment say could normally operate at say 2500 PSI out of the pump,  since the pump pressure is essetially regulated, it is simply a matter of selecting the desired force and sizing say the cylinder (for instance) appropriatey.\nSince:\nForce = Pressure (pump pressure) times Area (of the cylinder)\n\nThe forces are absolutely staggering with a quarter of a million pounds force off a 10" cylinder at 2500 psi pump output.  the chart below may not have been converted properly, but if you work the equations,  you will see that the incompressibility of the fluid is the secret to limitless amounts of power.  Usually safety is the only limiting concern with hydraulics as it is easy to die working close to anything with such reserve and speed.\n\n\nCylinder bore                                                       Force at 2500 psi \n\n2"                                                7,850 lbs\n3"                                              17,663 lbs\n4"                                                     31,400 lbs\n5"                                                   49,063 lbs\n6"                                                    70,650 lbs\n7"                                                       96,163 lbs\n8"                                                125,600 lbs\n9"                                                 158,963 lbs\n10"                                                     258,750lbs\n\nPneumatics are faster usually, BUT NEVER as powerful due to the compressible nature of air.
307366
If you have a small hydraulic piston pump where the cylinder has an area of say one square inch and you can drive its piston with a force of say 100 Lbs (using a lever arm), the pump will produce a hydraulic pressure of 100 PSI (pounds per square inch).  If the hydraulic fluid is delivered to a larger cylinder and piston (hydraulic ram) it will produce a force equal to the area of the larger piston time the supplied pressure.  If the larger piston has an area of say 10 square inches, the force will be 10 (square  inches) x 100 (pounds per square inch) = 1,000 pounds.  If you pushed down on the jack handle with 10 pounds of force, using its leverage, your 10 pounds of force has been magnified to 1,000 pounds of force (enough to lift one car tire off the road?)  A tiny check valve allows you to jack up the car with successive pump strokes by preventing backflow of tthe hydraulic fluid.  When you want to let the car down you (twist the handle?) open a bypass valve around the check valve.
906145
the manning number is used when calculating the flow of a fluid, ie water, through a pipe.  It usually refers to the resistance of the pipe and what it does to the water.  The rougher the surface, the higher the number.  A CMP has a manning of .023, but a RCP is .013
914748
The funny looking S thing is an integral sign, the p stands for pressure and the dV stands for a little change in volume.\nIt sounds like the work performed by something expanding at constant pressure.  The work is the amount of energy used.
358448
specific heat? that would be represented by Cp.\nHowever if you are using delta H then it would either be: delta H (fus) which is the enthalpy of fusion, used in problems concerning melting point (indicating a state change from solid to liquid)\nOr it could be delta H (vap) which is the enthalpy of vaporization, used in problems concerning a boiling point (indicating a state change from liquid to gas)\n\nHeat calculations are done using the formulas:\nq=m x (delta T) Cp <-- Used when there is a temperature change, but no state change\ng= m x (delta H fus) <-- Used for state changes from solid to liquid\nq= m x (delta h vap) <-- Used for state changes from liquid to gas
416798
105W\n\nA transformer changes the voltage, but inversely alters the current to the same degree. Therefore, using P=VI, the power is always the same.
423881
true - high sustained pressure and a signifigant distance to any pressure disturbance or variation
684406
Fluids at rest and in motion have different pressures and different equation. Energy is being created in motion so energy is being lost as heat.
765689
Yes you are right to subtract the water pressure from the total pressure.\n\nThen use p1v1/t1 = p2v2/t2\n\nSTP is p2v2/t2\n\nSTP = 1 atm and 0C or 273K\n\nSolve for V2.\n\nKeep units the same on both sides!
762826
Hydraulic machines work on Pascals principle.\nAccording to it the pressure exerted on a confined fluid is tranmitted equally and undiminshed in all directions.\nSo we can apply a small force on a large area and that pressure is transmitted throughout the fluid.\nThis pressure can be used to lift relatively large load(or force) by making it act on a small area of cross-section on the platform of the machine.\nPascals Principle is : P1=P2\nor\nF1/A1=F2/A2