How do I solve this problem?  3x-5(3x-7)=2(x+9)+45?
477010
Remember Order of Operations - in this case, Parenthesis, then Add/Subtract.\n\n1.) First, we do the parenthesis:\n3x-5(3x-7)=2(x+9)+45\n3x-(15x-35)=(2x+18)+45\n\n2.) Next, we add/subtract from the parenthesis:\n3x-(15x-35)=(2x+18)+45\n-12x + 35 = 2x + 63\n\n3.) Then, we solve by subtraction and division:\n-12x + 35 = 2x + 63\n-12x - 2x = 63 - 35\n-14x = 28\nx = -2\n\nCheck:\n3(-2) - 5(3(-2)-7) = 2(-2+9)+45\n-6 - 5(-6-7) = 2(7) + 45\n-6 + 65 = 14 + 45\n59 = 59
935657
5x = -15          x = -3\n-4x = 36          x = -9\n12+n/2=18      n = 12\n-25 = 5 - 6x     x = 5\n2x + 3x = -45  x =-9\n7n--n=48        x = 8
1047159
3x+3x+2x+2x=70\n10X=70\nx= 70/10\nX=7\n\n3*7=21\n2*7=14\nthe length and width are 21,14
191645
3x+y=5 ----(1)\nx-2y=11----(2)\n\nfrom eqn (1)\ny=5-3x-----(3)\nNow substituting value of y in eqn (2) we get \nx-2(5-3x)=11\n7x-10=11\n7x=21\ntherfore x=3\nNow substituting value of x in eqn (3) we get \ny=5-3(3)\ntherefore y=-4\n\nX=3,Y=-4
169903
3x-5=5x-3\n3x=5x-3+5   (gets the numbers together)\n3x-5x=5x-5x+2   (gets the variables together)\n-2x=2\nx/-2=2/-2\nx=-1
1152335
Solve,\n\n3x = 2y - 5 ... (1)\n\ny - 5x = -1 ... (2)\n\nRearrange (2), we get,\n\ny = 5x - 1 ... (3)\n\nSubstitute (3) into (1)\n\n3x = 2(5x - 1) - 5\n\n3x = 10x - 2 - 5\n\n3x = 10x - 7\n\n10x - 3x = 7\n\n7x = 7\n\nx = 1 ... (4)\n\nSubstitute (4) into (3)\n\ny = 5(1) - 1\n\ny = 4 \n\nTherefore x = 1 and y = 4.
1035131
i think you made an arithmetic error in the first step.\n\nstart with: |5x - 3| + 8 = 22\nthen subtract 8 from both sides, and you will get\n|5x-3| +8 - 8 = 22 - 8\n|5x-3|  = 14\nand not |5x - 3| = 24\n\nfrom there:\n|5x-3|  = 14\n5x-3 = 14 or 5x-3= -14\n5x-3+3=14+3  or 5x-3+3= -14+3\n5x = 17 or 5x = -11\nx = 17/5 or -11/5
1068646
hmm see you can do it in simple way,\n\n(8x-3x) = (5x+ 3x)\ni.e.x ( 8-3) = x (5+3)\ni.e 5x = 8x\ni.e 5 = 8\n\nCheers
818056
3x - 5y = 7\n5y = 3x - 7\ny = (3/5)x -7/5\nA line parallel to it is y = (3/5)x + b\n(6 , -7) on it, so -7 = (3/5)*6 + b\n-35 = 18 + 5b\n5b = -53 and b = -53/5\nThe wished line is y = (3/5)x - 53/5 or\n5y = 3x -53\n\nTh
781088
Plug in 2 for x to determine this:\n\n3(2) + 5 = 6+5 = 11 ≠ 17\n\nTherefore 2 is not a solution.\n\n~ ♥ ~
810076
11^(0.35+7) = 3 this is a contradiction\n\nx=3 is a solution but the rest is just a mess.\n\nDo you have any idea of what you are doing?
908426
Plug in each of the four answers.  The only one that works is (2), because you get\n\n | 3 (-2/3) - 3 | = 5\n | -2 - 3 | = 5\n | -5 | = 5\n 5 = 5
974614
Simple. Get rid of the denominators on both sides by multiplying by the lowest common multiple (in this case, 8). So that would make the left side: 2(3x +7) and the right side: -x. Then just isolate and solve for x!
708030
5x + 7 = 6x\nSubtract 5x from each side\n7 = x\nAnswer: x = 7
308039
[3x/(5x+15)][(7x+21)/3]\n= [3x/(5(x+3))][7(x+3)/3]\nCancel the 3's and the (x+3)'s\n= [x/5][7/1]\n= 7x/5
1153869
Well, if the perimeter (thats all the way around the outside or all three sides together is 35, then you can add up the three sides and they should equal 35\n\n3x-5 + 2x-3 + 15-x = 35\n\na little algerbracadabra :  3x+2x-x-5-3+15=35\n\nthen  4x=28\nand x=7\n\nso , put 7 back in for x for each of the sides and you get\n3(7)-5=16\n2(7)-3=11\n15-(7)=8\n\ndouble check just to be sure 16+11+8=35\n\nhurrah \nkeep at it\nmath is power
975557
5x-3y=-12\n-3y=-5x-12\nmultiplying by -1\n3y=5x+12\nm=5/3\nb=12/3=4\n\n2.y=3x+5\n\n3.y+5/5+5=x+3/4+3\ny+5/10=x+3/7\nmultiplying by 70\n7(y+5)=10(x+3)\n7y+35=10x+30\nadding -7y\n35=10x-7y+30\nadding -35\n10x-7y-5=0