grace has 16 jelly beans in her pocket. she has 8 red, 4 green,4 blue ones. what is the minimum#of times get?
487566
To be absolutely sure she has one of each color (I'm assuming she's blind, she must take out 13 jelly beans.\n\nIf she got all 8 red in her first eight tries, then all green in her next four, she would have to get a blue one on her thriteenth try.
695512
Answers choices are:\n     1, 4, 3, 2, 2,\n      3, 1, 4, 2, 1,\n      1, 1, 4, 2, 1\n      3, 2, 3, 4, 1\n      3, 4, 1, 2, 4
1065104
You have 3 bananas, 2 lemons, 4 apples and 5 oranges.  Instead of saying all that you simply say that you have 14 pieces of fruit.  That is a basic way that we use summation notation in our daily lives.
641571
7 IS UNSATISFACTORY AS A SOLUTION (3B, 4G) because girls will have 3 brothers not 2 and boys will have 4 sisters not three. It needs to be expressed as "each child has five brothers and sisters", and the answer is then 6.
471834
aren't u missing a number there on the last row???\n\nin that case... i would say...\n\n9 11 13 15 17 19....
37938
not that many!!!!\nhow old are u?\nhow old is she?
32421
42\n\nhow many times is this going to be asked?
748483
The answer is 119\n\nTake 2 at a time end up with 1 (59 times=118 one left)\nTake 3 at a time end up with 2 (39 times=117 two left)\nTake 4 at a time end up with 3 (29times =116 three left)\nTake 5 at a time end up with 4 (23times=115 four left) \nTake 6 at a time end up with 5 (19times=114 five left)\nTake 7 at a time end up with 0 (17times=119 o left)\n\nI am dead sure this time = ]\n\nThe trick is look at 5 at a time. there is 4 left this means the last digit must be 9. So look at all possible answer of 7s that ends with 9 and work it out from that!!!!!!!!!!
17092
1..2..3..CRUNCH! the anwer is 3.\n\nThe world may never know.\n\nBut its actually around 200 licks http://www.tootsie.com/memoriesLicksMachine.html
469710
she has another cookie in her pocket?
577048
depends you take away 3 and give it to whom? if to u keep it to urself then you have 5...if you eat the 3 then you have two...if you take the three away and leave the two you have 3...now im confused!
177069
Answer:\nThere are 11 yellow marbles and 5 blue marbles.\n\nProof:\nLet "n" be the total number of marbles.\nLet "r" be the number of red marbles.\nLet "y" be the number of yellow marbles.\nLet "b" be the number of blue marbles.\nWe are told that the total number of marbles is 30:\nn = 30\nwe are told that there are 14 red marbles:\nr = 14\nand we are told that there are 6 fewer blue marbles than yellow marbles:\nb = y-6\n\nTherefore\nn = r + y + b\n30 = 14 + y + b\n30 - 14 = y + b\n16 = y + b\n16 = y + (y-6) (Express b as a function of y)\n16 = 2y - 6\n22 = 2y\n11 = y\n\nNow solve for b:\nb = (y-6) = 11-6 = 5
124726
He couldn't squash a jelly bean between 85 and 86 because they are opposite sides of the same page.\n\nHe could squash a chocolate bar between 90 and 91 because they are facing pages.\n\nNext question - what is the proper punishment for his desecration of MY FAVORITE BOOK!!!
345437
Wait, I'm confused. Are we saying: 90 Red Balls, 90 Blue Balls, 90 White Balls, 10 Multicolored Balls? If that is the case, and you are asking how many must be taken to guarantee that there will be at least 10 of one variety, then the answer is 37. It is possible to pick 9 of each of the four varieties. The next ball would therefore guarantee at least 10 of the same type.\n\nADDED:\nSo then, it's 30 Red, 30 Blue, 30 White, and 10 Multicolor? Then the answer is still 37, for the reason I described before. Unless...are those 10 other balls all the same? Do you mean 10 balls with mixed colors on them, or 10 balls, each a different, random color, but not red, blue, or white? Because if that's the case, it's 38. It is possible to pick 9 of each of the three colors, and all 10 balls of different colors, and you would then have 37. The next ball (38th) would have to be the 10th of either red, blue or white.
833053
with 4 kids, there are 2^4=16 possible combinations, including the order.  Since there's only one way to get all girls p=1/16.  For other combinations you have to do some counting since \nTwo boys and two girls can happen like so:\nggbb \ngbgb, \nbbgg, \nbgbg, \nbggb, \ngbbg, \n\nnote that there are  4 choose 2 = 6 of these.  (binomial coeff)\n\nEach of these is 1/16 and there's 6 of them so 6*(1/16) = 6/16.
171898
9!!\n\nsuppose he took out 4 from the green and for from the blue, noe he has to take at least one to ensure he has a blue one...
407313
If you had 11111111111111 apples, and I took 9999999 apples away from you, you would have 11111101111112 apples.  My question is where would you get 11111111111111 apples, and then what would I use to carry 9999999 apples away?  regardless, if you were willing to part with that many apples I would have plenty of cider, jam, jelly, pies, turnovers, applesauce, apple juice, and happy teachers!