the weight of the person higher in equator than the pole ,why?
489652
No, the opposite. A person is lighter at the equator because of the centrifugal force generated by the Earth's rotation.
794485
You are upside down... according to someone in Australia.\n\nThe Earth is a sphere and is constantly attracting you via gravity.  So no matter where you go it will always be pulling you towards the center.  As you travel around the globe "down" will always be toward the center of the Earth.
118984
It's often called a scaling law.  If you assume the giant is twice as tall as an average person and proportioned the same, his limbs will have 2^2 = 4 times the cross-sectional area but he will weigh 2^3 = 8 times as much.  Unit stress will be 8/4 or twice that of the average guy.  Crash!
845919
Gravity also decreases with altitude (since greater altitude means greater distance from the earth's centre). All other things being equal, an increase in altitude from sea level to the top of Mount Everest (8,850 metres) causes a weight decrease of about 0.28%. It is a common misconception that astronauts in orbit are weightless because they have flown high enough to "escape" the earth's gravity. In fact, at an altitude of 250 miles (roughly the height that the space shuttle flies) gravity is still nearly 90% as strong as at the earth's surface, and weightlessness actually occurs because orbiting objects are in free-fall.
64883
Up or away from the center of gravity.
327439
This is a common feature for persons born and broughtup in cold climate. People in Equatorial regions tolerate heat more for the same reason. There may be slight variation amongst individuals in tolerance to climatic issues. Nothing to worry.
928537
not at all, the material weight is just taking different forms, a person is a composition of something already here, there is not heavier planet.\n\n:> peace\n.
214499
It all has to do with altitude. The higher you are from the earth, the colder it gets. Air is also thinner.
1177145
You are right, that because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles. Try not to think of centripetal acceleration as a force though; what's really going on is that objects which are in motion like to go in a straight line and so it takes some force to make them go round in a circle. So some of the force of gravity is being used to make you go round in a circle at the equator (instead of flying off into space) while at the pole this is not needed.\n\nThis means that the centripetal acceletation at the equator is about 0.03 m/s2 (metres per seconds squared). Compare this to the acceleration due to gravity which is about 10 m/s2 and you can see how tiny an effect this is - you would weigh about 0.3% less at the equator than at the poles!
538503
Because the air is less dense the higher the altitude, there are less molecules available to retain heat. Therefore the heat of the sun dissipates more readily.
309044
Because of buoyant force acting against our weight. The amount of the bouyancy is decided by the Archimedes principle according to which the force acting on us in the upward direction is determined by the amount of water displaced by us which indeed is equal in volume to the volume of the submerged part of our body. \n\nThe buoyant force acts upward and balances our weight so that the net force acting on our body becomes 0 and we feel weightlessness.
302056
It all depends on whose point of view you are going from.  If you go from the person digging the hole, then they would say they are digging down.  If you go from someone at the North Pole, then they would say that the digger is going up.  Someone on the equator would say that the digger is goibng across.\n\nIt's all relative.
15807
If you define up as the direction towards the sky, and down as the direction a ball will fall when dropped, then there is no difference when you stand on the north pole, south pole or anywhere in between.\n\nThe Earth is spherical so Earth's gravity pulls in the same relative direction no matter where you are, down towards the center of the planet, so that makes down always towards your feet.\n\nAnd also since the Earth is spherical the sky will always be above your head, up. \n\nSo there is no difference in upside down or right-side up based on where you are on the Earth.
6855
Do NOT try to figure this out.\n\nHis bottom, which has more weight.\n\nPoetess777
190298
There is the factor of where the wind originated from and the rotation of the earth.  Think about it, how fast is the north pole spinning (pretty slow, it takes 24 hrs for the earth to revolve)?  At the equator, the ground spins at a very high speed, being as the ground is further from the axis of rotation.  \n\nAs an example, a high-altitude air-mass originates from near the equator and travels away from the equator. The ground is spinning slower as you move away from the equator, but the air-mass does not lose a lot of the speed it had when it was at the equator.  Thus it will be moving relative to the ground it is now above. Since the earth rotates in the eastern direction, the wind will travel from east to west (relative to the ground it is now above).  \n\nIf the wind came from a location away from the equator and moved towards the equator, it is moving slowly relative to the equator so it will appear to be travelling slower than the rotation of the ground below it.  As a result, it would move from east to west relative to the ground.\n\nThis is how phenomenon like that jet-stream work.  This effect is called the coriolis (if I spelled it right) effect.
418803
Theoretically, the gravity at the north pole should be higher.  The reason being: The earth is not a perfect sphere, even if you filled in all the oceans and leveled all the mountains.  This is because the earth's spin creates centripital force, which forces the earth out at the equator.  So, at the north pole, you would be closer the the earth's core, and therefore the center of it's gravity well.  The closer you are to the center of a gravity well, the more you weigh.  \n\nIF you are trying to find the exact strength, you could determine your distance from the north pole and amount of centripital force and gravatational force acting on your body at your lattitude, then subtract it from the gravatational force on you at the north pole, but I don't know how you'd do that.  FInd someone with a really fancy calculator.
887515
Please be warned - there are MANY incorrect responses above.\n\nThe theoretical answer to your theoretical question is that you would be weightless at the centre of the earth because the forces of attraction would exactly cancel out.\n\nTo address some of the errors above:\nYou would not be pulled apart because the mass of the earth is not enough.  Similarly, you are not pulled apart when standing ON the earth, even though the earth is pulling your feet more strongly than your head.  If the earth were enormously massive then you would be (it's called being spaghettified, although it ought to have a different name if you are the centre!).\n\nThe force of attraction does NOT increase as you get closer to the centre of the earth.  The responder is thinking about Newton's Law of Gravitation which applies to POINT masses.  If you apply it to a large body such as the earth then you find that only the sphere underneath you attracts - the rest of it cancels out.  ie The earth is roughly 6400km in radius.  If you are 5000km from the centre then you will feel the force of attraction of a 5000km radius sphere of the Earth at a distance of 5000km - the force of attraction of the remaining 1400km 'shell' exactly cancels out.\n\nYou would not 'feel' the force of the sun (any more than you do on the earth) since its force of attraction is providing the centripetal force required to move you in a circle around the sun.\n\nThe force of gravity is NOT caused by the rotation of the earth.  In fact, if the earth stopped rotating we would all be a little bit heavier since a part of the force of gravity is being used to provide the centripetal acceleration necessary to keep us spinning around once per day, with the earth (on the equator this amounts to about 0.3%).\n\nYou also ask about gravitons!!  How they work is a difficult question since they are theoretical!  According to classical Newtonian theory, gravity is simply a fundamental property of matter - matter attracts other matter and that's that.  Newton himself was always uncomfortable about the idea of "action at a distance" but even his genius could not solve the problem, given the limitations of the time that he lived in.  Along came Einstein and gave a solution - matter distorts the shape of space and the apparent force of gravity is actually simply the result of an object moving in the distorted space.  Think of a heavy ball on a rubber sheet and another ball moving along.  It does not 'know' about the heavy ball but it changes its path towards the ball because the surface on which it is rolling has been distorted.\n\nThe graviton is an attempt to explain the phenomenon of gravity without recourse to considering distortions of space-time.  Bodies with mass emit particles called gravitons.  They interact with other massive particles.  The degree of ineraction can be calculated and reasonably easily represented on a Feynman diagram.  Try an internet search.  Huge tanks full of washing up liquid have been built down abandoned deep mine shafts to try to detect these particles.  Some 'events' have been noted but they remain elusive, as far as I know.\n\nHope this goes some way to answering your interesting questions.