How do you find the greatest common factor?
487301
There's another way if you're calculating the gcf of just two numbers... for example, 960 and 144. Start off by dividing the larger of the two by the smaller..\n960/144=> Quotient=6 Remainder=96\nNow, divide the divisor of the previous step by the remainder.\n144/96=> Quotient=1 Remainder=48\nContinue till your remainder is 0.\n96/48=> Quotient=2 Remainder=0\nThe last divisor, i.e. 48, is the GCF.\n\nAnother example...\n1890 and 168\n1890/168=> q=11 r=42\n168/42=> q=4 r=0\nSo the GCF is 42.
317079
GCF=greatest common factor is the no that is the gteatest factor of two or more no is the GCF \n\nEX) 12=1,2,3,4,6,12\n    30=1,2,3,5,6,10,15,30\n\nAs you can see 6 is the greatest in here that is common with 12 and 30
25946
=3fg*(f^2g)+3fg*5f-3fg*4\n=3(f^(1+2g))*g+15(f^2)g-12fg
844236
As stated, this is not true. The number a has to be the greatest common divisor of b and c. For example, 12=2*6 and 18=2*9, but there are not n and m so that 12*n+18*m=2. The GCD of 12 and 18 is 6, and you *can* write 6=12*(-1)+18*1.
916424
The answers:\n\nLCM=9000\nGCF=50\n\nThe explanations:\n\nTo do these types of questions, break each number down into its prime factors:\n\n450 = 2*3*3*5*5\n1000=2*2*2*5*5*5\n\nNow the LCM will be product of all the prime factors in 450 and 1000 altogether: 2*2*2*3*3*5*5*5 = 9000\n\nThe GCF will be the product of the prime factors which occur in BOTH 450 and 1000: 2*5*5 = 50\n\nHope that helps.
924243
(q - 6h)(g - 6h) \n= q(g - 6h) - 6h(g - 6h)\n= gq - 6hq - 6gh + 36h² (-6h x -6h = +36hh = +36h²)\n\n8q²j - 12g³hj \n= 2 x 2 x 2 x q x q x j - 2 x 2 x 3 x g x g x g x h x j\n= 2 x 2 x j x (2 x q x q - 3 x g x g x g x h)\n= 4j(2q² - 3g³h)  (The common factors in each part are the multiplier, the remaining factors are what are left inside the parentheses ... and always remember that 1 is always a factor of any number .. see example below)\n\n5g²h - 10g³h²\n= 5 x g x g x h - 2 x 5 x g x g x g x h x h\n= 5 x g x g x h x (1 - 2 x g x h)\n= 5g²h(1 - 2gh) (because 5g²h x 1 = 5g²h)
737839
NO. its 105\n35*3=105\n15*7=105\n\nNOT 70\n35*2=70\n15*4.666666666666666666666666666=70\n\n5 is the GCF
84308
Let's go ahead and make factor trees:\n3y^3 = 3 * y * y * y\nand\n24y^3 = 3 * 2 * 2 * 2 * y * y * y\nWe can now see which factors are common to both terms.\nThey both have a 3, and three y's in common.\nSo, we know that the gcf will be 3 * y * y * y or 3y^3.\nHope this helps :-)
986340
You look for the greatest common factor(gcf), and then divide each number by the gcf.\nExample:  The ratio of 4 to10 can be simplified because both are divisible by 2.\n4/2 = 2 and 10/2 = 5\nThe simplified ratio is 2 to 5.
594488
h^2=25\nh= (+-)5 (+-) very important!\n\n4g^3 -4g^2 -24g-throw away one g's you get:\n4g^2 -4g -24  divide by 4., you get\ng^2 -g -6 --- (g-3) (g+2)=0 --- g=3, g=-2\n\n15y^2 + y - 2=0\n(3y-1)(5y+2)=0\n3y-1=0 , 5y+2=0 ---- y= 1/3 , y= -2/5\n\nR^2 -6R +9\n(R-3)(R-3)=0\nR=3\n\nTHENNNNNNNNNNNNN\n\n3p(5p+2)(p-6)=0\n(15p^2 + 6p)(p-6)=0 LOOK: [15p^2 x p] and [15p^2 x (-6)]      AND  [6p x p] and [6p x -6] \n15p^3-  90 p^2 + 6 p^2 - 36p  =0\ndivide the equation by "p" you get-\n15p^2- 84p - 36=0 can be divided by 3, you get\n5p^2- 28p- 12=0\nfactorise- (5p-2)(p+2)=0\n5p-2=0, p+2=0\np= -2/5    or p= -2\n\n36L^2-12L+1=0\n(6L-1)(6L-1)=0\n6L-1=0 ---L= 1/6\n\n-10x^2  -29X  +10=0\ncant get the right answer- cuz it should be -10 not +10\nif -10- the answer should be\n(5x+2) (-2x-5) =0\n5x+2=0   -2x-5=0\nx= -2/5 and x=-5/2\n\nSay S as the size of garden \nlength- say 10S  and width   S\narea = 10S^2=144\nS^2=144/10 = 14.4\nS=3.79 m (i guess)\nperimeter = 3.79 +3.79 +3.79 +3.79=  15.179 m\n\nP/s: please check your answer- I like maths, but im a very careless lady.\nAnd also, I think the one who answers after me- has a better solution. I js missed doing these maths problems.. because i hadnt done it for years.. so, wanna work it out for fun.. Anyway, good luck.
93202
greatest common factor of 16,24 and 30\nfirst of all we have to factorize it\n16= 2*2*2*2\n24= 2*2*2*3\n30= 2*3*5\n\nso greatest common factor in this case is the greatest number, that 16,24 and 30 are divisible by it.\n\nso the only common number in all the three is "2" and it is also the greatest common factor because the numbers above don't have any other common factor\nGCF=2\n\nNow let us find the GCF (greatest common factor) of other numbers.\neg:  12,24,48\n\nfactorize it first\n12= 2*2*3\n24= 2*2*2*3\n48= 2*2*2*2*3\n\nthe common factors in all the three are two times two and one time three (look carefully)\nGCF= 2*2*3\nGCF= 12\nthat is the greatest common factor.\n\n1st answer gcf =2  and 2nd answer gcf=12
944629
you need two numbers. you cannot get a Greatest Common factor with one number\n\nClick on the URL below for additional information concerning Greatest common factor.\n\nwww.brainpop.com/math/problemsolving/greatestcommonfactor\n\nwww.math.com/school/subject1/lessons/S1U3L2GL.html
456039
C = 5(F - 32)/9\nK = P/2.2\n\nThe easiest place for all conversions is google. It has a built in calculator and converter that automatically gives you the results. Simply type in something like:\n\n30 degrees centigrade in fahrenheit\nor\n50 pounds in kilograms\nor even\n50 lb in kg
875098
Depends on the model...\n\nOn the Texas Instruments (TI) models, you would use the GCD function.\n\nGCD is found under MATH → NUM, arrow down to gcd( \nFrom the home screen, choose gcd(  followed by two numbers separated by a comma.\n \nNOTE:  gcd( accepts non-negative integers only and works with only two entries at a time.  If you need to figure the GCF or more than two numbers, do them a pair at a time.
770441
take 2(x-2) as common factor\n\n= 2(x-2)((x+3) + (x-3))\n= 2(x-2)(2x)\n=4x^2-8x
372976
yes u can\nt^2(s^4-4)is the factored form\nt^2 is the highest common factor\n\n\n75x^2 - 147y^2\n3 is the common factor\n3(25x^2-49y^2)\n3(5x^2-7y^2)(5x^2+7y^2) is the factored form of 75x^2 - 147y^2
906886
Basically you just need to look at each number and each letter separately.  See what factor the numbers have in common (for example 4 and 6 have 2 as their greatest common factor, leaving 2 and 3), then see what power the letters have in common (x² and x³ have an x² in common (leaving 1 and x), etc.\n\nJust distribute the common factors out in front and leave the rest inside parentheses.\n\nHere are a few examples from your son's problem sheet:\n4n + 6 --> you have to factor out a common 2 --> 2 (2n + 3)\n4x + 12x³ --> factor a common 4x --> 4x (1 + 3x²)\n3x + 15 --> common 3\n-6y² -3y³ --> common -3y²\netc.\n9c³+15c --> common 3c\nxy²+x²y --> common xy --> xy(y + x)\n\nI left some out, but I think you should be able to explain it to him now.