Three sums and relationships?
486619
As long as you are secure with each other and love each other it shouldn't be a problem as long as you can leave jealousy behind and remember that it is a pleasure thing and not a relationship in the making.  It is just for the pleasure, intense pleasure.  If there are any feelings that you are getting more out of it than you should be, don't get involved.  Stay in control.
264696
Explain "Why borrow" first.  you cant give more than what you have  so, if you have less but are forced to give you first  have to borrow from your neighbor.\n\nWhen your neighbor lends to you  he becomes one less.\n\nFirst only give sums where no zeros are involved  once this concept is reinforced  go a step further that  zero has to borrow from his neighbor and then lend to its neighbor.\n\nUse pebbles  or some other objects   in heaps  for units and tens so that  it becomes a practical problem instead of dry sums.\n\nAll the very best.
221696
Addition!  aka the sum of 3 and 5 is 8.
795675
3 + 6(9+9)\n\nP.S. i DONT wan a date with u.
1146358
I’m not seeing how this is solvable.  I’m getting two possible answers.\n\nBut here’s how you should work the problem.  \n\nFirst of all, I think you pretty much have to assume that the x,y < 10.\n\nSo we know that Bill can’t tell what his two numbers are just by looking at the product.  As it turns out, there are very few products that allow this to happen: they are 12,16,18,24,36.  So you factor out all the number pairs that would make those products, and the sums are 7,8 (twice), 9, 10(twice), 11(twice), 12, and 13.\n\nSo we know that Albert is seeing one of those sums.  If he sees 7, then he knows that the only way for his numbers to add up to 7, and multiply up to either 12, 16, 18, 24, or 36 is for the numbers to be 3 and 4.  But he says nothing.  Therefore, he isn’t seeing 7.  Neither is he seeing 9, 12 or 13, for the same reason.  So, now we know the sum must be either 8,10, or 11.  And now Bill knows that.\n\nSo, if Bill were seeing 12 as the product, he would know that the numbers were 2 and 6, since they add up to 8.  But he says nothing, so he’s not seeing 12.  Likewise, if he were seeing 18, he would know that the numbers have to be 2 and 9.  But he doesn’t, so he’s not seeing 18, and he can’t be seeing 36 either.  So that means he must be seeing either 16 or 24.\n\nAnd now Albert knows this, so either Albert is seeing a sum of 8, and knows that the numbers are 4 and 4, or he’s seeing 11, and the numbers are 3 and 8.  I just don’t know how to eliminate either of those options.
542977
every relationship has to have three Cs.commitment,communication and compromise.\neither its love marriage or arrange marriage,that is immaterial.but for the success of marriage these three Cs are indispensable.
44177
I'm sorry, but I don't think that you have actually asked a question here, or perhaps you have left off some very pertinent information. Unless you just wanted the above statement to be explained.\n\nIn this instance, the universe of discourse just means all the points contained in the set S = (p(x,y)), which is all the possible combinations of x = 1,2,3 and y = 1,2,3. For example, (1,3) and (2,2) and (3,1) would all be points contained in the universe of discourse for p(x,y).
420710
I know it has already been answered but I"ll take a chance with something different. Ok 3 to the third power plus two would be 3 to the fifth power which is 243.\n :)
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
1027973
the 3rd one is correct, but I get -(3+b)/b+2 and 2 for the first 2
872177
Coefficients are:  1  1  3
916534
21, 34  Yes it's called the Fibonacci series.  Each number is the sum of the previous two.\n\nWhat I don't understand is as a result of asking a valid question to expand your knowledge, so many people gave you such rude replys.\n\nI hope this helps, have a good day.
939729
Just "pair up" the terms.\n\n1 + (5-3) + (9-7) + (13-11) + ... + (2001-1999)\n\n1 + 2 + 2 + 2 + .... + 2 = 1 + 2 * 500 = 1001
759105
False... y has to be 2...\n(3,2) is a solution, but not (3,1).
761362
(x+2) + (x+3) + 17 = 2[x + (x+1)]\n\nD. none of these\n\nAlso, the end of the question is imprecise - sum of the two (greatest or smallest)?
846122
Three words MONEY   MONEY   MONEY
284339
When you have one thing, it does nothing. When you have two things, they act one each one equally. But, when you have three things, they have a dynamic relationship when the three forces are allways acting in different ways.