the perimeter of a square is 36cm. what are the lengths of each side? __cm?  solve the problem?
480278
That's an easy one.....lets see... 36 times 3.14 gives about 100....divided by 3 gives about 30 times 3 is 90 divide by 10 gives 9cm ! Peace of cake !
463854
The perimeter is twice the sum of the length and the width. Given the ratio of length to width, the perimeter is necessarily eight times the width. Therefore the width is eight and the length is twenty four.
48612
Let r be the radius of the circle and s the length of the square's sides.\ncircle perimeter=2*pi*r, square perimeter=4*s\n2*pi*r=4*s => s=pi*r/2\ncircle area=pi*r^2, square area=s^2\ns^2=(pi*r/2)^2=pi^2*r^2/4\nBut pi<4 => pi^2*r^2/4<pi*r^2 => square area < circle area
1077978
23 on the small side.\n\nIf the small side is x, then the long side is 5x.  That makes the perimeter x+x+5x+5x or 12x.\n\n12x=276\nx=276/12\nx=23\n\nThere for the rectangle is 23cmX115cm.
979599
L = length\nW = width\n\nLW = Area\n1) LW = 35\n\n2L + 2W = Perimeter\n2) 2L + 2W = 27\n\nSolve equation 1 for L and substitute into equation 2\n\nLW = 35\nL = 35/W\n\n2L + 2W = 27\n2(35/W) + 2W = 27\n70/W + 2W = 27\n70 + 2W^2 = 27W\n2W^2 - 27W + 70 = 0\n(2W - 7)(W - 10) = 0\nW = 7/2, 10\n\nL = 35/W\n\nIf W = 3.5, L = 10 and if W = 10, L = 3.5\n\nAssume L is longer than W: L = 10, W = 3.5
35250
Perimeter = a+b+c\n\nThis is the answer your maths teacher will be looking for.
832240
We know that the width is 5 yards, and that the length is double that, we can deduce that the length is 5x2=10.  So the rectangle is 5x10.\n\nThis means that the perimeter is 5x2+10x2=30 yards.  Since there are two sides length wise, and two width wise.\n\nThe area is the length times the width, 5x10=50 square yards.\n\nAgain, if you want to grow as a person you need to solve these yourself.  The time it took you to copy all these questions onto Yahoo! you should have been able to answer them yourself.  If you don't know how, you should be asking your teacher to explain them and give you extra tuition.
1108873
Here's the process you would use to solve the problem.\n\nFirst, you need to know that an isosceles triangle has two equal sides.\n\nTherefore, you have two variables in the problem\n                    x = length of leg (there are two of these)\n                    y = length of base\n\nWe know that "the length of one of the equal lengths of an isosceles triangle is 8 cm les than 4 times the length of the base."  Therefore, we can write "x" in terms of "y":\n\n                    x = 4y - 8\n\nFurthermore, we know that the perimeter is 29 cm.  Now we can set up an algebraic expression to solve for "x."\n\n2x + y = 29   (initial equation)\n2(4y-8) + y = 29 (substitution)\ny = 5 (solved)\n\nWe have the length of the base ("y").  Now we can solve for the length of one of the equal legs.  Remember from above that\n\nx = 4y - 8\nx = 4(5) - 8\nx = 12\n\nSolved!\n\nIf you are still confused, draw an isosceles triangle to visualize the problem.  Label the base "y" and the two legs "x."
851184
If sides means the sum of all four, none of the above :\n\n24/4=6cm.\n\n6*6=36 cm.^2\n\nIf sides means each side, than 24*24=576 cm. ^2
732742
awnser :length =18feet\n\np=2L+2W\n60=2L+24\n-24     -24\n36=2L\ndivide by 2\n18=L
896075
Do you mean what is the area of a square with sides (width and length) of 6 meters?\n\nIf so it is just 6m x 6m = 36 sq. meters.  (Remember area is sq. units and is given by the formula width times length.)\n\nOn the other hand, if you are asking for the dimensions of a rectangle with an area of 6 sq. meters, there is no single answer.  It could be 1 x 6, 2 x 3, 1½ x 4, ½ x 12, etc.
778352
.............6\n........______\n....../.|...........|&#92;\n...../..|...........|..&#92; 2\n..../_|_____|__&#92;\n\n\nThe triangle on the right is a 30-60-90, so the shorter side must be 2/1 = 1.  So the length of the bottom part is 6+1+1 or 8.  The height must be 1√3, so the area is 1/2(6+8)√3 = 7√3.\n\nGopal screwed up when he did 2*2cos60.  That's 2*2*1/2 = 2, not 4.
895737
Imagine a square that is 6 inches across on each side.\n\nThat's the simplest example.\n\nAny rectangle where the length and width have a product of 36 works also.  It can be 9 inches on one side and 4 on another.  It could even be 1 inch wide and 36 inches long (much like a yardstick).\n\nBut it's not just rectangles.  The area of a circle is pi (approx. 3.14) times the square of the radius.  So, a circle with 3.4 inches for a radius is about 36 square inches.
976501
You mean "one less."\n\nCall the base x.\nThen each leg is 2x-1.\nAnd the perimeter is x + (2x-1) + (2x-1), which equals 18.\n\nJust solve for x and you can calculate the lengths of the sides.
755315
1) Do you mean equilateral or scalene?  You can only answer this if it is a regular, equilateral (all sides the same).\n\nLet S be the length of one side.  Then the perimeter is given by the formula\nPerimeter = 3S = 74 cm.\n3S = 74\n\nDivide both sides by 3:\nS = 74/3\nS = 24 2/3 cm\n\nEach side of the equilaterlal triangle is 24 2/3 cm.\n\n2) The perimeter of a rectangle is 2(W + L) = 48 cm\nYou are also told that the width is 1/3 the length.  In other words:\n3W = L\nPerimeter = 2(W + 3W)\nPerimeter = 2(4W)\n48 = 8W\nW = 6 cm\nL = 3W = 3(6) = 18 cm.\n\nSo the width is 6 cm, the length is 18 cm.\n\n3) A regular hexagon has six sides that are all the same.\nThe formula for the perimeter is 6S = 96 cm.\n6S = 96\n\nDivide both sides by 6:\nS = 96 / 6\nS = 12 cm\n\nSo each side of the regular hexagon is 12 cm.
915466
Let a and b the lengths of the sides of the rectangle (with a the side with the semi-circle).\nThe perimeter is 2b+a(pi/2+1)=16, and the area ab+pi/8*a^2. Substituting b in the area (from the perimeter equation), the area is 8a-a^2*(1/2+pi/8). \nSetting the derivative to 0, we have a=32/(4+pi). Then b comes from the perimeter constraint as b=8*(1-(2+pi)/(4+pi)).\nNumerically this gives a=4.48, b=2.24 and an area of 17.92
65434
The question is WRONG. If you have length =6 and width =7, P=26 and A=42.