Geomerty question? Help? EXAM tommorow!?
493708
the formula for the area of any regular shape is \n(pa)/2, so there is no multipling the base by 2 involved.\np=perimeter\na=apothem
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|\n  | \n  |  A\n  |\n  |_______\n......B\n\nThis is what "A" perpendicular to "B" looks like.  I hope this helps!
151334
there is a website called www.hotmath.com where they have some books that offer help on homework and explains how to do the problem step by step. \n\ni hope that may help you in geometry! \ndoctor math (google it) might help too
835259
I'll give you a hint and let you try to figure out the rest yourself (unless someone else tells you the exact answer). =)\n\nUse your trig identities:\n\ntan A = sinA/cosA\n\ncot A = 1/tanA or cot A = cosA/sinA
502657
Try this link and read it all the way through.  It's short.\n\nhttp://mathcentral.uregina.ca/qq/database/QQ.09.00/tom3.html\n\nThis link is better:\n\nhttp://mathforum.org/library/drmath/view/56760.html\n\nJust scroll down.
667922
Either use volumes of revolution or compare cross sections of the sphere and a cylinder with a couple of cones removed. The latter is how Archimedes did it.
1137727
I like the joke!  To play along, I define:\nr = metric r  and \nd = metric d\n\nV = (pi/3)*(d^2)*(3r - d)\n\nThis will work for the tank being any fraction of a sphere, not just 1/2
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This should help.\n\nhttp://www.geomatters.com/products/category.asp?CID=1
716347
Of three points, A,B,C\n Check the slope of A-B,  B-C, A-C.  If any of the slopes are the same, you have parallel lines and thus no triangle.  So, to do (2), do (4) first.\n  If you know the distance between A-B, B-C, A-C, you can calculate the area with the formula, so (5) also depends on (4).\n\n You write your own code.  yA isn't a site to do your homework, since if you don't do it yourself, you don't pass the class!
1017799
V = area of base times height\nheight = 14\nbase = 3*3*pi = 9pi\nV = 14*9pi\nV = 126pi\nV = 395.8
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Hope this helps\n\n\nhttp://argyll.epsb.ca/jreed/math9/strand3/triangle_congruent.htm\n\nhttp://mathforum.org/geopow/fullsolutions/102596.solutions.html or www.mathforum.org
863713
The only thing I remember about geometry is...a2 + b2 = c2.\n\nSomehow, I doubt that helps you.....sorry.
440894
go to this website and try to understand how to get the area of the shade region \n\nhttp://www.algebralab.org/lessons/lesson.aspx?file=Geometry_AreaPerCricle.xml\n\ngood luck
87753
Just add up the lengths of the three sides. Works for any triangle - wether it's equilateral, isosceles or obtuse.
175713
Your question is too complicated to appreciate the math in it, which is supposed to be the real beauty in the first place. Anyway, I have tried figuring it out and come with equations. I do not even want to try and begin substitution and end up with more complications. I just thought once you saw the relation, you would throw those 10 points my way.\n\nAssuming a to be sides of the squares of the prism and b to be the length of the rectangles, we know that the sum of all dimensions is 14a+5b. Now I do not even want to get started why you brought it the story of the equilateral triangle. You can just say the sum  of the dimensions is 61. Anyway, since any side of the trianle, as it is equiangular hence equilateral, is twice 14a+5b and 122, the sum of the dimensions will be 61. So your first equation is 14a+5b=61\n\nYou know the volume of the prism is the length X width X heiht = a x a x b = (a^2)b This is equal to the surface area. The surface area is the sum of all the areas on the prism and that is a^2+4ab. (How about you calculate how that came up?)\n\nSo there is your second equation, (a^2)b = a^2+4ab So then from 14a+5b=61, express a in terms of b or the other way around and plug it into the second equation and experience brutal complications and figure out what the variables are. I think you know it is too easy to calculate each dimension and area after that.
861159
You need to know the base and the height of the shapes. \n\ntrapeziod: average of two bases x height\nparallelogram: base x height\ntriangle: 1/2 x base x height\n\nOr if you know how to use the sin, cos, tan, then you only need to know a few sides to calculate the base and the heights.
99265
I asked that same question to my teacher last time. She told me that I have to Seperated the shape into different common shapes. (for example like lets say I wanted to seperate a "square" into some common shapes I could turn it into two seperate triangles or four different triangles. Well Just try to use the formulas you know for the areas of the different disected figures you get.