square root is over 4x-3 then in the same equation =36?
488811
1. square both sides: 4x-3=1296\n2. add 3 to both sides: (4x-3)+3=1296+3; 4x=1299\n3. divide by 4: (4x)/4 = 1299/4;  x=324.75
483647
Here's how:  square root is the same as the 1/2 power.\n\nSqrt (9) = 9^(1/2) = 3\n\nCube root is same as 1/3 power.\n\nFourth root same as 1/4 power, etc.\n\nIf you have an exponent of 2/3, thet's the cube root squared.\nSo 8^(2/3) = (cube root of 8)^2 = 4
1128882
4*4+4+Sqrt(4) = 22, \n\nthis is 4*4 = 16\nplus 4 = 20\nplus the square root of 4, which is 2 = 22\n\nusing only the number four!
1012196
3(x+12)=x+2\n3x+36 =x+2\n2x+36=2\n2x=34\nx= 17
76669
a=8\nb=-6\nc=-9\n\nx= -b + or - square root of {b^2-4(ac)} all over 2a\n\nx= 6 + or - square root of {36 - 4(8)(-9)} all over 16\n\n = 6 + or - square root of 324 all over 16\n\n (6+18) divided by 16= 3/2\n (6-18) divided by 16= -3/4\n\nso, x= 3/2 or -3/4\n\nthere you go. hope this helps
424346
Yes and No at the same time.  \n\ns = 0\n6(8s-3) = 48s - 18\n48s - 18 = 48s - 18\n(48)(0) - 18 = (48)(0) - 18\n-18 = -18\n\nor\ns = 1\n6(8s-3) = 48s - 18\n48s - 18 = 48s - 18\n(48)(1) - 18 = (48)(1) - 18\n48 - 18 = 48 - 18\n30 = 30\n\nActually all real numbers will work becuase the equations are equal.
831094
36. >\n38. =\n40. >\n42. <\n44. <
890998
if s+2 = 38, s is equal to 38 -2 which is 36\n\nThe square root of 36 is 6\n\n6 / 6 is 1\n\n1 + 4167 is 4168\n\n 4168\n-  612\n-------\n3556\n\n3556 divided by 50 si the same as 355.6 divided by 5\n\n355.6 / 5 = 71.12\n\nSimple :-)
872966
1.) 3 &#92;/ x+2 - 4 = 3\nif you mean\n3 sqrt( x+2) -4 =3,\nthen\n3 sqrt(x+2) =7\nsqrt(x+2) = 7/3\nx+2 = 49/9\nx=49/9 -2\n\n2.) &#92;/ x+3 - &#92;/2x-8 = 1\nsqrt(x+3) -sqrt(2x-8) =1\nsqrt(x+3) = sqrt(2x-8) +1\nx+3 = 2x-8 +2 sqrt(2x-8) +1\n-x + 10 = 2 sqrt(2x-8)\nx^2 -20x + 100 = 4 ( 2x-8)\nx^2 - 28x  +132 =0\n'
699632
Example:\n4^x = 8\n\nThe technique here is we change both sides into the same base.  Since we know that 4 = 2² and 8 = 2³, then we can change the equation into\n2^2x = 2^3\n\nThen, since the bases are equal, then the exponents must also be equal.  Thus,\n2x = 3\n\nTherefore,\nx = 3/2.\n\n----------------------------\nThe thing here is to change both sides into the same base.\nAnother example:\n81^[x(x + 2)] = 1/3^(9 - 20x)\n\nWe change both bases: 81 = 3^4, 1/3 = 3^-1.  Thus,\n3^[4x(x + 2)] = 3^[-(9 - 20x)]\n\nWe then equate the exponents:\n4x(x + 2) = (20x - 9)\n\nWe distribute:\n4x² + 8x = 20x - 9\n\nWe transpose everything to the left\n4x² - 12x + 9 = 0\n\nWe factor out\n(2x - 3)² = 0\n\nSquare root both sides\n2x - 3 = 0\n\nWe transpose -3\n2x = 3\n\nDivide 2.  Therefore,\nx = 3/2\n\n--------------------------\nHere's another example:\n\n2^x = 3\n\nI know that it is VERY DIFFICULT to change 3 into a power of 2.  Here, we use another tool: the logarithm.  If you are already ready, you can inform me so that I can teach you that.  Please feel free to contact me.\n\nkevin!\n^_^
227387
D = 36 - (4)*(-2)*(-3)= 36- 24 = 12\nTwo real solutions.
296703
-3 + sqrt(2) or -(3 - sqrt(2))\nthats like saying\n\n-1x, 0x, 1x\n\nthe answer is problem found like this\n\n2x, 3x, 4x\n\nso i believe the answer is \n\n6 - 2sqrt(2), 9 - 3sqrt(2), 12 - 4sqrt(2)
535646
I think you mean 36 not 38 since\n\n4 = 4*3^0\n12 = 4*3^1\n36 = 4*3^2\n108 = 4*3^3\n324 = 4*3^4\n\nSo, if that's the case, it's 324.\n\nUPDATE: Kemmy, 1^3+1 = 2, not 4.
980949
sol: x^2-6x=3\ncoeff of x is 6, so divide it by 2 and square the no. i.e u get 3^2=9\nadd this no. on both sides of equation\nx^2-6x+9=3+9\nx^2-6x+9=12\n(x-3)^2=12\nx-3=+12^1/2 ,-12^1/2  (this is square root of 12)\nx=3+12^1/2,3-12^1/2
299363
Well, the square root is 27i, that makes it easy, cause 3X3X3 = 27, so 3 to the 6th is 729, and i X i is -1, so the sixth root of -729 is 3i.
751288
for the last one, if you're aking (x-3)^2= 36....\nsquare root both sides to get (x-3) = 6 and -(x-3)= 6\nthen for the (x-3) you add 3 to both sides to get x=9\nfor the -(x-3)=6 you distribute and get -x+3=6, the answer it x=-3\n\nso...... x= 9 or -3
880996
No.\nTo simplify SQR(108), break it down into\nSQR(36)*SQR(3)\nSince 36 is a perfect square, SQR(36) = 6\nSo the answer is 6*SQR(3).