I need to help my wife with a math problem, again. Any help is much appreciated!!!!?
487186
A hexagon is made up of six equilateral triangles -- triangles with equal sides.  You need to split the triangles in half, in which case you'll get 12 right-triangles.\n\nDraw a diagram!\n\nIf the hypotenuse of the right triangle is x, one of the other sides is x/2 (because you split an equilateral triangle in half) and the other side is half 1.875.  You can calculate x using Pythagoras's Theorem ("the square of the hypotenuse ...).  The width of the screw at the widest point is 2*x.\n\nTo solve (B), it should be enough to draw another diagram.  You just need to allow for the screw head and the walls of the socket.
490047
I think a calculator would be great for this one! It sounds perfect for a math wiz to try...Good luck! MayMay
278729
http://www.aaamath.com/ There you go!! Hope that helps.
502657
Try this link and read it all the way through.  It's short.\n\nhttp://mathcentral.uregina.ca/qq/database/QQ.09.00/tom3.html\n\nThis link is better:\n\nhttp://mathforum.org/library/drmath/view/56760.html\n\nJust scroll down.
1094108
Use a calculator and raise it to the 1/3 power.\nDon't try to do it by hand...
662213
Anyone can give you the answer, but try here next time you need help with conversion or any other kind of math: \n\n\nhttp://www.gateways2learning.com/BasicMath/BasicMath.htm\n\nGood luck..................
190553
Yeah, I know what you mean. Read my answer to your first question, too, b/c maybe another teacher might be a better match for you as a tutor.  My daughter is having the same problem as you right now, her teacher is so boring she is killing the class slowly and surely. Used to be my son could tutor her, but he is in college now. I can't help b/c you kids are doing math I never ever heard of.  She tells me that you can go to some websites that give math help, if you google the math term you don't understand.  Good luck and don't give up, please?
937830
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today
537199
got to math.com, click on calculators and click on solve equations.....it'll do the math for ya
298555
If it's math you can get some pretty good help at math.com. going to google for extra practice in pretty much anything. edhelper has worksheets you can print.
1102335
I may be barking completely up the wrong tree here. Are you comparing one ratio with another?\n\nIn the first, there are 45 parts, in the second there are 19.\n\nMost math problems have a glimmer of sense about them, in that when you hit upon the right way to solve them or what they are really asking, the calculation is quite easy.  I was expecting the number of total parts in each expression to be an easy multiple of each other, which they are not.\n\nIf you are expected to apply the first ratio to the 18 side of the second, that looks a little more reasonable (45 and 18 are both multiples of 9.)\n\nDoes that help without seeming to? (Also I understand you to mean 'factor' and 'easy')
538111
yeah.....!!!! just calculate it!!! lol
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
151115
Would you please type your entire math question the way it is presented in your book? Your description is not enough for anyone to answer you correctly. Thanks!
813078
P(2 are women) = \nP(1st is woman) * P(2nd is woman) = \n6/10 * 5/9 = 30/90 = 0.333\n\nP(at least 1 is woman) =\n1 - P(both are men) =\n1 - P(1st is man)*P(2nd is man) = \n1 - (4/10)*(3/9) =\n1 - 12/90 =\n78/90 = 0.867\n\nI'm a little rusty on my "given that..." types of problems, and I'd hate to possibly steer you wrong on your remaining two questions.  But let me just say that I *THINK* the P of your 3rd question is 5/9; and I think the P of the 4th question is the same as the P of your 3rd question.\n\n~ ♥ ~
213586
Lazy gal!!!calculate it once more..
806420
Go to their website and you might be able to get the answers. Or if you have the book, they have all of the odd answers in the back of the book.  (Or if you have an older sibling who's really good at math, they can help a lot!)