A tough math question?
486296
s(n) =  [1-r^n]*a/(1-r) + [(1-n)r^n]*d/(1-r) + [1-r^(n-1)]*dr/(1-r)^2\nfor n > 0\n\ns(infinity) = (a + r(d-a))/(1-r)^2\nfor |r| < 1\n\nSee simulation\nhttp://www.geocities.com/derekcowley/public/agp.xls\n\nproof:\n\ncompute the difference equation:\ny(n) = [a + (n - 1)d]*r^(n-1) = a*r^(n-1) + (n-1)d*r^(n-1)\ny(n+1) = [a+nd]*r^n = a*r^n + nd*r^n = y(n)*r  + d*r^n\ny(n+1) = y(n)*r  + d*r^n\n\ngenerate the LTI discrete time system state space:\n\nx2(n) = r^(n-1)\nx2(n+1) = r*x2(n)\nx1(n+1) = r*x1(n) + d*x2(n) \nx1(1) = a\nx2(1) = r\n\nX(n+1) = A*X(n) + B*delta(n)\ny(n+1) = C*X(n)\n\nwhere A is a 2x2 matrix [r,d;0,r]\nB is column vector [a;r]\nC is a row vector [1,0]\ndelta(n) = 1 for n=0, 0 otherwise\n\nCompute the Z-transform:\n\nH(z) = C*[(zI-A)^(-1)]*B = a/(z-r) + dr/(z-r)^2\n\ncompute running sum:\n\nAccumulator U(z) = z/(z-1)\nS(z) = H(z)*U(z) = az/(z-1)(z-r) + drz/(z-1)(z-r)^2\n\nCompute partial sum (partial fraction expansion):\n\nS(z) = e/(z-1) + f/(z-r) + g/(z-r)^2\n\ne = a/(1-r) + dr/(1-r)^2\nf = -ar/(1-r) - dr/(1-r)^2\ng = -dr^2/(1-r)\n\nInverse Z-transform\n\ns(n) = e  + f*r^(n-1) + g*(n-1)r^(n-2) [n>0]\n= see top line above\n\nTo see a spectral analysis of the sequence based on pole/zero locations see\nhttp://www.geocities.com/derekcowley/public/agp2.xls\nYou will need the "Analysis ToolPak" add-in in Excel to properly see this file.
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Joel, you need some help.  This is one of the easiest questions I have ever heard!  You should know this, man!  You're gonna fail your test if you keep cheating on here and don't actually figure out how it works.  Good luck, brotha'\n\nL = -2 or L(x) = -2
165991
that is a good arithmatic question which many people get wrong. the answer would have to be 2
433833
the answer to your question is x=3(4,6)
184617
Did a teacher tell you this and now you wonder?  Or is this a mathematical riddle?\n\nIf the former, I don't see the inconsistency.  If the latter, I can't wait for the punchline.
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(sigh)... Req = R1 + R2 + ...\n\nReq = 5 + 3 = 8.\n\nYay, I win.
455115
ten points if you can figure this out first .. right?? \n\n\nANU!!
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
903397
You might try asking this question under "Mathematics."
60395
If this is a math question then anything is possible.
987327
Find a number X such that  2X = (X/2) + 99\n\nmultiply both sides by 2 to get  4X = X + 198\nsubtract X from both sides to get 3X = 198\ndivide both sides by 3 to get X = 66\n\ncheck work\n2*66 = 132\n66/2 + 99 = 132
604123
I figured it out... the answer is 1/(13*(2-3x))\nIf you need an explanation tell me
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
930279
Twice as long as it is from one to the middle!  How did I do?  This is the correct answer by the way.
852068
11\n\nany perfect square will have an odd number of factors
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kinda of hard to answer not beaing able to see the whole equation
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Wow... this one is tough! LOL!   ;-) \n\nGWB