how do i solve this- solve for x  3(x-1) +2x = 5x -6 - x?
492288
x=\n3x-3+2x=5x-6-x\n3x+2x-5x+x=-6+3\n1x=-3\nx=-3&#92;1\nx=-3
957282
|3(x + 1) + 6| =18\nie |3x + 9| = 18\nwhence |x + 3| = 6\nThere are 2 different methods to solve such an equation\n\nOne is to use the definition that\n|N| = N if N ≥ 0\nand = -N if N < 0\n\nThe other is to use the propety that |N|² = N²\n\nMethod 1\nSo x + 3 = ±6\nWhence x = -9 or 3\n\nMethod 2\n|x + 3|² = 6²\nie x² + 6x + 9 = 36\nx² + 6x - 27 = 0\n(x + 9)(x - 3) = 0\nx = -9 or 3
869535
5x+8+3x-5=6x-3\n8x+3=6x-3 (combine like terms)\n2x=-6 (subtract 6x, subtract 3)\nx=-3 (divide by 2)
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
892382
To solve the first one, divide each part of the first equation by two, so 2x-3y=-13; since -2x+3y = 13, adding the two equations gives 0x+0y=0.  No help.  Try substitution.\nFrom the first equation, 4x = 6y-26; x = 1.5y - 6.5\nsubstitute into the second equation -2(1.5y-6.5) + 3y = 13; -3y +13 + 3y = 13; 13=13.  Still no help.\nBoth equations are equivalent; the line that represents them is the solution.\n\nProblem two:\nSubtract equation 2 from equation 1.\n3x-3x+2y-3 = 6 - y\n2y-3 = 6-y\n3y = 9\ny = 3\n3x+6=6\nx=0\nchecking\n3x+3=y=3\n3x=0\nx=0
979201
First of all, solve both equations. So the first would be..\n\n3(2x+1)>5-2x \n     6x+3>5-2x (add 2x to both sides)\n         8x>2 (take 3 from both sides)\n           x>0.25 (divide both sides by 8)\n\nThe second would be..\n\n2x^2-7x+3>0\n4x^2-14x+6>0 (multiply both sides by 2)\n(2x-6)(2x-1)>0 (factorisation)\n \nReplacing > with =..\n\n2x-6=0,      2x-1=0\nx=3,                 x=0.5\n\nSo to satisfy both criteria, x must be greater than 0.25, greater than 0.5 and greater than 3. \n\nSo the answer is that x > 3.
734642
(3x + 10) -5x = 6x-50\n(3x+10) - 11x = -50\n3x-11x = - 60\n-8x = -60\nx=7.5
918458
Look at it this way:\n(-1)*(6x + 6x) = (-1)*(12x) = -12x
191567
Please use parentheses to explain the problem more effectively. Assuming the problem as,\n\n(x-1)/2x + x/(x+3)\n\nThe solution can be,\n\n(3x^2+2x-3)/(2x^2+6)
731670
(-4x3 + 3x2 - 5) + (x2 - 5x + 6) =\n-4x3 + 3x2 - 5 + x2 - 5x + 6 =\n-4x3 + 4x2 - 5x + 1
846617
You would set your two equations equal to each other to solve:\n\ny = 2x-6\ny = x² + 5x + 6\n\nSo, 2x-6 = x² + 5x + 6\n\nSubtract 2x from both sides:\n\n-6 = x² + 3x + 6\n\nAdd 6 to both sides:\n\n0 = x² + 3x + 12\n\nNow you can factor or use quadratic formula to solve for x.  (I don't see any way that this can be factored, unfortunately, so we'll have to use the ol' quadratic formula.)\n\nx = [ -3 ± √ (3*3 - 4*1*12) ] ÷ 2*1 = \n\n[ -3 ± √ (-39) ] ÷ 2\n\nThis equation has complex roots, but no real roots.  Therefore in your real plane these two graphs do not intersect.\n\n.
895527
2x^2-8x+3x-12\n2x(x-4)+3(x-4)\n2x+3 = 0 or x-4= 0\nx = -3/2 or x = 4\n\n2x^2+10x-72\n2x^2+18x-8x-72\n2x(x+9)-8(x+9)\nx = 4 or x = -9\n\nx^2+6x-x-6\nx-1 = 0 or x+6 = 0\nx = 1 or x = -6
214212
Hi, here's how ya do the problem:\n\n-5x+y=6\n\ny=5x+6 (move -5x over by adding the opposite)\n\nSo then you substitute it into the problem\n3x-2y=3 so that it looks like\n\n3x-2(5x+6)=3\n\nNext distribute the -2\n3x-10x-12=3\n\nand solve\n-7x-12=3\n-7x=15\nx=2.14\n\nThen you substitute 2.14 into either equation to figure out y\n-5(2.14)+y=6\n-10.70+y=6\ny=16.7\n\nHope this helps!
751294
3(2x+4)=6(x+2)\n6(x+2)=6(x+2)\ninfinite solutions
896236
First expand the brackets, collect like terms and simplify.\n\n(-2x^2 + 5x - 1) - (3x^2 - 4x - 6)\n= -2x^2 + 5x - 1 - 3x^2 + 4x + 6\n= (-2 - 3)x^2 + (5 + 4)x + (-1 + 6)\n= -5x^2 + 9x + 5
921258
5x - 15\n3x -  9 \n\n5 ( x - 3 )\n3 ( x - 3 )  = 5/3\n\nx^2+7x+10\nx^2+11x+30\n\n( x + 5 ) ( x + 2 )\n( x + 5 ) ( x + 6 )   =   (x+2)/(x+6)
846363
3x² + 6 + 10 - (3x² - 8x - 5)\n\n3x² + 6x + 10 - 3x² + 8x + 5\n\n3x² - 3x² + 6x + 8x + 10 + 5\n\n0 + 14x + 15\n\n14x + 15\n\nThe answer is 14x + 15\n\n- - - - - - -s-