what is the molecular formula of nitrophenol phosphate?
479762
I assume you are talking about the formula and not the structure.\n\nThe molecular formula is C6H5NO5P\n\nStructure (if in case you want it too) is as follows:\n\nDraw a benzene ring (phenyl group) minus 1 hydrogen (C6H5). To the Carbon without the hydrogen, attach a Hydroxyl group (-OH). On the other Carbon positions, whether it is the ortho positions, meta positions, or para position, erase the hydrogen and attach a nitrate group (-NO2). On the Oxygen with the double bond to Nitrogen on the Nitrate group, erase one of the bonds and attach this bond to the phosphate group (-PO3).\n\nI'm not sure if you are talking about a nitro-phospho bond or a hydroxy-phosphate bond, but the difference is only 1 hydrogen.
276161
click here to view IR spectra of ortho http://www.aist.go.jp/RIODB/SDBS/cgi-bin/cre_frame_disp.cgi?spectrum_type=ir&sdbsno=2650 and para http://www.aist.go.jp/RIODB/SDBS/cgi-bin/cre_frame_disp.cgi?spectrum_type=ir&sdbsno=2681 isomers of nitrophenol.\nIR spectroscopy is very much dependent on the polarity of a bond and also on the symmetry (and lack of symmetry) of the molecule or a group of atoms in a molecule. IR spectroscopy is very useful for differentiating the two isomers. I hope you find them.
613727
try:\nhttp://lb.chemie.uni-hamburg.de/static/data/50_zzk46n8n.html
6814
Calcium phosphate: 13 atoms (3 Ca, 2 P, 8 O)\n4 Aluminum Carbonate molecules: 56 atoms: (36 O, 12 C, 8 Al)\nLead Nitrate: 9 atoms (1 Pb, 2 N, 6 O)\nThe Or threw me off on on this one.  I'm assuming it's Cr.  If it is it would be-\n2 Ammonium Dichromate molecules: 38 atom (4 N, 16 H, 4 Cr, 14 O).\nIf you are adding all the atoms for all the molecules together you get 116 atoms.
929172
3Mg(NO3)2 + 2Na3PO4 => Mg3(PO4)2 (prec.) + 6NaNO3\n\nAqueous solution is assumed.  The magnesium phosphate is insoluble and precipitates out.  This is normally indicated with a downward arrow right after its formula, but no such symbol exists on this keyboard.
871578
http://www.olysun.com/Chem_121/Soln.html\n\n\ncc
47432
3AgC2H3O2 + Na3PO4 -----> Ag3PO4 + 3NaC2H3O2
769020
It sounds like an enzymatic assay for phosphatases. I did that myself a long time ago.\nIf I remember correctly 405 should be the wavelength at which you are measuring the absorbance, unless you mean that the value was 0.405\n\nYou need to make a standard curve: measure the absorbance for different samples of p-nitrophenol of known concentration (you prepare them yourself) and then do the plot absorbance vs concentration. You find the equation for the curve by linear regression and then you can use it to find out the concentration of p-nitrophenol in your samples. Be sure to have alkaline solutions in order to have practically all of the p-nitrophenyl molecules in the p-nitophenoxy form as the anionic form is yellow and the protonated colorless.\n\nThe exact math depend on the specifics of your experimental set-up.\n\nAs for the second question it is not very clear what you mean.
966082
1 - NH4OH\n2 - PbO\n3 - KBr\n4 - PCl5 (five)\n5 - Al(NO3)3\n6 - Ba3(PO4)2  (not sure)\n7 - C4H10\n8 - Sn(OH)4\n9 - NH4NO3\n10 - Li3P\n11 - Ba3ClO2   (not sure)\n12 - MgSO3
890894
C12H22O11+12O2-------12CO2+11H2O+E
748280
PH3:                           Phosphine\nAg2SO3:                    Silver Phosphite\nFeCO3:                      Iron(II) Carbonate\nN2O4:                        Dinitrogen tetroxide\nPb(OH)2:                   Lead(II) Hydroxide
393840
Methylbenzene - C7H8\n\nBenzaldehyde - C7H6O\n\nNitrobenzene - C6H5NO2
880087
De = 2\nHydrogen = H\nmono = 1\nOxide = Oxygen\nOxygen = O\nH2O
145093
The stock name for this compound is ammonium phosphate.  \nThis is an ionic compound, which means that it is named with the names of the ions.  The cation (the first ion, positively charged) is NH4+, which is called ammonium.  The anion (the second ion, negatively charged) is called phosphate, PO4(3-).  \nNote that because the entire compound must be neutral, there are three ammonium (+) ions to balance out one 3- PO4 ion.
62338
multiply 220 times 0.564 then divide by 31. That will give you the number of P atoms in the formula(the subscript). \nmultiply 220 times 0.436 then divide by 16. That will give you the number of O atoms.\nYou can do the same for problem two but use the right molecular mass and the right percents.
204385
H3PO3\n\nnot H3PO4, which is PhosphoRIC acid
385735
The molecular mass of p-nitrophenylphosphatase is 33 kDa.