If it took 6 seconds for the wave to pass, what wouldbe the wave's frecuency?
486866
If one wave equals one cycle, then the answer is:\n\nA. 6 Hz
108422
1 minute sounds about right.\n\na couple of moments is definately under 5 minutes.
231096
6 meters per second\n\n360 meters per minute\n\n21,600 meters per hour
401527
7 seconds or 3 seconds
44625
The speed of sound (at sea level) approximately is 340.29 m/s and can be used as a global estimate for the speed of sound for the purposes of this calculation.  That would mean that students measuring such a sound would need to be seperated by 340 meters to measure even a 1 second delay in sound propagation.  Additionally they would need to be able to perfectly synchronize the start of the sound event and the start of stopwatch event.  Making it even worse is the need to react with enough speed to stop the stopwatch upon reciept of the signal without significant reaction delay.\n\nThe experiment would be simply to accomplish with resources to control synchronization and detection equipment, but it would not be a low-budget, high-school type of experiment.
904901
Did you check the Wave Volume?
404818
Wave length and frequency are inversions.\n\nThe average speed of sound is 343 meters per second.\n\nA 1 meter wavelength then would be a frequency of 1/343 hertz.\n\nA tube will produce most easily a wavelength equal to it's length.  It can also produce a wave length of twice it's length.\n\nAll other tones will be some division of these lengths.\n\nA 12 meter tube would produce wave lengths of 24m (twice the tube) 12m (equal), 6m (half), 4m (a third), 3m (a quarter), 2m (a sixth) etc.  They will all will be completely divisible into the tube.\n\nThat makes frequencies of 12/343 Hz, etc.
694048
velocity is frequency times the wavelength\nso if the frequency decreases the velocity also will decrease
103569
Displacement.  If you mean its change in position *divided* by the time it took, that would be its average velocity.
506291
For the slower machine, it would take 3 times the length of time, 8*3=24min\n\nFor the faster machine, it would take 1.5 times, 8*1.5=12min
953838
1 second = 1 000 000 microseconds
789953
Measure the speed of sound by help of an echo, a stopwatch and a tape-measure. (depending on temperature it is about 430 m/s.\nRepeat your measurements at least 10x and have the average.\nGood luck\n\nTh
63833
50 feet or about 2-3 seconds
1093017
Your question is incomplete, part of it looks to be cut off.\n\nThis is just a guess, but the question almost seems like it is asking how long after the student claps his hands does he hear the eco bounce back off the wall.\nIn this case, one would need to know the speed of sound (or one could just estimate it to be about 340.29 m/s).\nSince speed is given as distance traveled per unit time, one can calculate the amount of time it would take something traveling at a given speed to be the distance traveled divided by the speed.  In this case with the sound, the sound traveled to the wall (165 meters) and back again (another 165 meters), for a total distance of 330 meters.
119936
You need to know the mass of the earth and it's natural freqeuncy. The answer is usually about 10 Hz. It goes "dong" at about ten times per second, as opposed to the human ear, which can start to detect "dong"s at 2000 Hz.
168920
This is ultrasonic, not electromagnetic, so C is irrelevant.  The equation is:\nF=V/L where V=sound velocity in water (~1475 m/s), F=frequency in Hz, L=wavelength (0.0003 m)\nResult is you need 4.9 MHz or higher.
421087
One up and other down with no crest in between implies, 'half wavelength is 4 m'.Therefore in 3 second distance travelled by the wave is 8m. Velocity is  Distance by time = 2.66 m/s.