how many earth years is one light year?
481585
An Earth year has about 10,000 calories per serving, while a light year has only about 5,000 calories.  Also, you age a lot less in a light year, but you dont really do as much...
850696
4.3 light years = 4.06802721 × 10^13 kilometers\n(40680272100000 km)
963687
There is no day of the year that has EXACTLY 12 hours of daylight and 12 hours of dark because no day is EXACTLY 24 hours long. A sidereal day is 23 hours, 56 minutes, 4.091 seconds long. On the equinoxes, we have approximately equal amounts of light and dark.
81010
Jupiter is way too close to be using light years.\n\nOne "Astronomical Unit" is the earth-sun distance and is approximately eight light minutes. Jupiter orbits at about five A.U. from the sun.  So even when Earth and Jupiter are at their most distant I would still expect that distance to be less than one light hour.
545233
870436 billion light years. If u disagree, go and measure it urself
235335
If it's the big picture you're looking at, a year is the time it takes for the earth to make one revolution around the sun. The earth is thought to be some 4 billion years old.\n\nA decade is ten years. A century is one hundred years. A millenium is one thousand years.
1155179
the universe is expanding at a rate of one tenth of the speed of light (speed of light is 300,000 km per second). Recent estimate tells that the Universe has a diameter of 13 billion light years.\n\n1 light year = 300,000X60X60X24X365 kilometers\n Now imagine how big the 13 billion light years would be...
424465
Actually there are 364 + 1/4 days in a year. This has to do with the time that our Earth takes to complete one erbit around Sun. Now we have an arbiterary time period called week which has 7 days. So we have a normal year of 7 x 52 = 364 days. This leaves us with one 1/4 day per year left unaccounted. To make up for it, we have a leap year (365 days, 29 days in February) every four years.
246225
Currently, the accepted view is that the universe is approximately 78 billion light-years in size. A light-year is the distance light travels in one year (a large number since light travels about 186,000 miles each second). To determine this, astronomers used the WMAP project. See the links to determine how this was accomplished, but only if you don't mind being confused (it is quite lengthy and quite confusing - even for an astronomer such as myself!).
333277
We've been measureing this quantity for a number of years, and we are getting better results all the time.  The best news is that the different techniques we have been using all agree that the distance is about 26,000 light years.
19452
"A light year is the distance light travels in one year: about 9.461 × 10^15 metres or about 5.879 × 10^12 miles."\n\nFor some context, it is 4.22 light years to Proxima Centauri, the nearest star outside the solar system.
25917
If you take leap years into consideration, the average year contains 525,948.766 minutes.  A year with just 365 days contains 525,600 minutes.
826958
First calculate how many seconds there are in a year.\n\n60 * 60 *24 * 365 = 31535000 seconds in a year.\n\nThen multiply that by how far light travels in one second (it's easier to use a scientific calculator and scientific notation.\n\n1.86 x 10 ^ 5  * 31535000 = about 5.86 X 10^12 miles\nThat would be 5 with 12 number places trailing it so....\n5,860,000,000,000 is pretty darn close to 5.88 trillion miles.  Now I know my calculation is slightly off.  Your teacher was probably looking for a leap year in the equation.  When multiplying by the # of days in a year, use 365.25 instead of 365.
954912
It averages between 91 and 94 million miles. You can check this by multiplying the speed of light (186,000 miles per second) by the time it takes light to reach the Earth (8 min, 16 sec.)\n\n30 NOV 06, 1711 hrs, GMT.
647693
lots :-)  Let me figure it out...\n\nFirst the number is spelled 'googol' and is equal to 10^100 (1 followed by 100 zeroes).\n\nA year nominally has 31,556,926 seconds (365.242199 days x 24 hours x 60 minutes x 60 seconds).  I used the number 365.242199 because that is how long it takes for the earth to go once around the sun... we round this to 365 and add an additional day every 4 years (with some exceptions 3 out of every 4 centuries, blah, blah, blah)...\n\nAnyway, I digress.  Back to the problem at hand.\n\n10 x 10^99 / 3.1556926 x 10^7 = (10/3.1556926) x 10^92\n\n3.16887646 × 10^92 years.  There is no English name for this word but it is *lots* like I said at the beginning.  :-)\n\nThe closest I can get to a name would be to use vigintillion (10^63) as a base and go from there...\n\n3.16887646 x 10^29 x 10^63 or\n\n316 x 10^27 x 10^63 +\n887 x 10^24 x 10^63 +\n646 x 10^21 x 10^63\n\nSo that would be:\n316 octillion-vigintillion, 887 septillion-vigintillion, 646 sextillion-vigintillion years\n\nOkay, a little more research and I found that my names were close but not exactly correct.  This number should be called:\n  \n316 octovigintillion 887 septenvigintillion 646 sexvigintillion years!
672104
It takes the earth approximately 365.25 days to orbit around the sun. A normal year is 365 days, then they add an extra day every four years when those four quarter days add up. However,they do not add the day on certain years, because it is just under a quarter of a day extra per year. So 2000 was NOT a leap year, for example.\n\nWe get "leap seconds"occasionally, too. It's all just trying to keep our artificial calendars in sync with the earth's orbit around the sun.
591913
Despite it sounding like time, light year measures distance.\nIt's the distance that light travels in space in one year, a very long distance.\n\n186000*365*24*3600 = 5.87 x 10^12 miles.