GCSE Maths Question: Working out the mean...?
488742
(135*24+225*32+200*m) / (135+225+200) = m\n\n10440/560 + 200m/560-m = 0\n\n-360m/560 = -10440/560\n\nm = 10440/360 = 29\n\nHowever, I always make mistakes in those calculations...
111022
7\n\norder them; if you have odd number of entries, take the middle one; if even - take average of two middle ones.\n\n\n\nand it's a statistics question
873308
OK - I will try and explain it, but forgive me if I get myself confused...  hehehe\n\nFirst step - make a bell curve.  Put a mark in the center and label that "7 hours" - that's your mean.  Next, put three marks on either side of that middle point - those will be your standard deviation points.  For the points on the right, ADD 5.3 to the mean for the first one, then add 5.3 again for the 2nd, etc...  Points on the left side of the mean have the 5.3 SUBTRACTED.  (Am I still making sense?  lol)\n\nNow - the 68-95-99.7 rule says that 68% of the freshmen will fall into the area between the first line on EITHER side of the mean, 95% between the second lines and 99.7% between the third lines on either side of the mean.\n\nI think you should be able to figure it from there - I hope so...  Right now I am so confused I think I gave myself a headache!  lol\n\nGood luck!
323008
By calculationg it's mean. Add all the values of observations and then divide by the number of observations.\nThat's all!
107133
You have all the information you need.\n\nThe Mean is the same as the average. It's just another term for a simple average. So it's $7500\n\nThe standard error of the mean is the standard deviation divided by the square root of the number of samples. So it's just $650 divided by 10, or 65.
354866
The average value of a function is given by\n\n(1/(b-a)) S f(x) dx, evaluated from a to b (I'm using S as the integration symbol).\n\nSo for this question, the average will be given by\n\nVavg = (1/6-0) S e^t + te^(2t) dt\n= (1/6){e^t + [(e^2t)/2][t - (1/2)]}\n= (e^t)/6 + te^(2t)/12 - e^(2t)/24\n\nEvaluating from 0 to 6,\n= (e^6)/6 + 6e^(2(6))/12 - e^(2(6))/24 - {(e^0)/6 + 0e^(2(0))/12 - e^(2(0))/24}\n= (e^6)/6 + e^(12)/2 - e^(12)/24 - (1/6 - 1/24)\n= 74663\n\nI've been looking at your answers and the equation and either there's something missing in your equation or there's an answer missing somewhere.
275869
Using a property of proportions, the product of means is equal to the product of the extremes.\n12x = ?20\n? = 3x/5\n\nSince there are 2 variables, you cannot solve for an exact value for any, instead it will be a function (one-to-one correspondence)  \n\n\nHope this helps^_^
240821
Harmonic mean is a term between any two harmonic terms...\n\nThis term comes from a series of numbers (harmonic progression) whose reciprocals are in arithmetic progression...\n\nHow to get a harmonic mean?\n1. Change the harmonic progression into arithmetic progression by getting the reciprocal of each term.\n2. Determine the common difference, d.\n3. Add the difference to the preceding term.\n4. The reciprocal of the result will be the harmonic mean.\n\nEX: Harmonic Progression: 1, 1/4, 1/7, 1/x, 1/13...\nLet 1/x = harmonic mean between 1/7 and 1/13\nTo get x:\n\n1. Change to arithmetic progression.\n 1, 4, 7, x, 13...\n\n2. Determine the common difference, d.\nLet: a1 = 1st term = a1 = 1\n.....a2 = 2nd term = a1 + d = 1 + d = 4\n.....a3 = 3rd term = a1 + 2d = a2 + d = 4 + d = 7\n.....a4 = 4th term = a1 + 3d = a3 + d = 7 + d = x\n.....From: a2 = 1 + d = 4\n.....we have: d = 4 - 1 = 3\n\n3. Add the common difference to the preceding term. \n...Therefore: x = a4 = a3 + d = 7 + 3 = 10\n\n4. The reciprocal of the result will be the harmonic mean.\n..Therefore: 1/x = 1/10 = harmonic mean between 1/7 & 1/13\n\nHARMONIC PROGRESSION: 1, 1/4, 1/7, 1/10, 1/13...
1022203
The mean proportional is also known as geometric mean and is defined as (a1*a2*a3*...*an)^(1/n) for n numbers.\nTherefore for 2,3 and 4, the mean proportional is (2*3*4)^(1/3)\n=24^(1/3)\n=2.884
815467
1) two make-ups get 40 and 70\n2) make-ups get 68 (current mode)\n3) denote the score of one make-up student as x, write out the mean, set it equal to 58 and solve the equation (it is your homework, remember?)
890798
depends which average\n\nalthough probably the mean \n\nin order to do this you need to add up the 3 numbers and then divide by the amount of numbers\n\n13 + 9+ 8 = ?\n\nthen divide that total by 3\n\nfor the medium \n\nyou need to put the numbers in order so 8 9 13 and find the middle number\n\n\nthe other average is mode but you can only use this if there is more than one of the same number. It is the most common number
840800
The mode is the data point that appears the most often. From the problem statement, there's a single mode, 5. So, since there are 3 cards, then at least 2 of the cards must be 5. (If all 3 cards are different, then there would be 3 modes.)\n\nSo the cards are 5, 5, and x. (x could be 5 without changing the mode). Now, look at the mean. To find the mean, add up all the values, and divide by the number of values. So add 5 + 5 + x to get x + 10, and divide that by 3. That expression must equal 8.\n\nSo, you now have an equation to solve: (x + 10) / 3 = 8. Solve it as you normally would:\n\nmultiply both sides by 3 to get x + 10 = 24\nsubtract 10 from both sides to get x = 14.\n\nSo the 3 cards are 5, 5, and 14. The mode is 5, and the mean is (5 + 5 + 14) / 3 = 24 / 3 = 8.
892527
Take the average of each of the coordinates.\n\nx-mid = (0 - 0)/2 = 0\ny-mid = (4 - 0)/2 = 2\nz-mid = (0 - 4)/2 = -2\n\nmid (0, 2, -2)
592312
Sure you have learned it. It's addition. If the mean (average) must be in the middle (the third number) then the numbers are:\n\n15,16,17,18,19\n\nand sum is 5*17 or 85
846377
Mean (m) = 20.142857= 20.14\n\nMedian = 4th no. = 21\n\nxffx(x – m)(x-m)2\n12112-8.1478.4996\n17117-3.149.8596\n19119-1.141.2996\n211210.860.7396\n221221.863.4596\n241243.8614.8996\n261265.8634.3396\n71410.02143.0972\n  2                2\nS   =  (x  - x)   / f   = 143.0972 /7 = 20.44171\n        \n S (SD) = &#92;/ 20.44171 = 4.521251 = 4,52 Approx.
243975
Do your own homework. How do you expect to learn if you can't do it yourself?\n\n My appologies, I feel mean now.
924135
google ..... maths psychometric test book