how to seperate buprenorphine HCI from Naloxone HCI dihydrate ?
480845
The two should be separable by HPLC
415884
Check this link:\n\nhttp://72.14.203.104/search?q=cache:Hb_4_LKfVd4J:www.hydrogen.energy.gov/pdfs/progress05/vi_b_1_wu.pdf+how+to+make+sodium+borohydride%3F&hl=en&gl=in&ct=clnk&cd=7&client=firefox-a
171036
You would need hypo. The chemicals involved are too risky to handle without expert supervision.
233245
It depends on the type of alcohol and whether its single component or multicomponent based. if it is simple and short chain alcohol (low boiling pt) by simple distillation it can be separated.  If there are mixture of alcohols and long chained then you need to convert them into ester/salt, which would ease the separation process.
993248
HCI hydrogen chloride \nto make HCI u have to mix Sulfuric Acid and Sodium
10922
poke a hole in one of the eyes of the coconut and drain the liquid.  Put it in a couple of plastic bags and give it a whack over a hard rock, it will crack and seperate
56345
Check on it at www.erowid.com.  Not sure if they have an entire recipe, but it's worth a try.
812044
1. Xanax = Alprazolam\n2. Dilaudid = Hydromorphone\n3. Vistaril = Hydroxyzine Pamoate\n4. Lodine = Etodolac\n5. Neurontin = Gabapentin
304001
I suggest that you create a supersaturated solution first. Reason being that the more highly saturated the solution, the better the formation of the crystal and the larger the end product. This can easily be done by heating your solvent to a very high temperature and stiring in copious amounts of whatever is going to make up your crystal. Lower the heat as it goes and you should idealy end up with a very viscous solution, not so much of a liquid but more to the kind of stuff you get when you mix a bit of cornstarch with water. Thereafter dump everything in a beaker or bowl and suspend a thin wax thread in the solution itself. Cover up the bowl and leave to set for a few days. If you have done it correctly you should see a very nice, large crystal forming. Just a note though, don't let the thread touch the bottom of the bowl or even any thing other than the solution, or your crystal will be lopsided
1150323
Methcathinone can be synthesized by oxidation of (pseudo)ephedrine with (di)chromate salts, or via Jones reagent.Here is the synthesis via Jones reagent:\nOxidizing the Alcohol to a Ketone\n1.068 grams (just over 1 gram) CrO3 are added to 0.92ml H2SO4, and distilled water is added to bring the total volume to 4ml. 2 grams of pseudoephedrine are dissolved in 20ml acetone, and cooled in an ice bath. The Jones reagant is slowly added to the pseudoephedrine, dropwise and with stirring. The mixture becomes a reddish brown.Since we used just about the exact number of molecules required, and under very mild conditions, the reaction will proceed slowly, but very smoothly. Just let the ice melt and the stirred solution warm over night.\nExtracting the Ketone\nAbout 12-18 hours later the reaction is complete, the color is now a very dark green. We now have to neutarlize and extract our ketone. Add about 20mL of water, and chill in an ice bath. Dropwise and with stirring add about 1 gram of lye (Sodium Hydroxide - NaOH) in a solution with as little water as possible (highly concentrated). Check the pH regularly, and stop at pH=12. The now basic solution is shaken with 50ml of toluene. Allow to stand and two layers will form. The ketone will move into the toluene layer. Let the mix settle and remove the acetone/toluene/ketone and put it aside. Add another 50mL portion of toluene to the aqueous (water-based) portion, shake, filter (which breaks the emulsion and removes some chromium salts), and remove and put aside the toluene. Ensure that pH is still 12, and repeat again with another 50mL portion of toluene.Combine the three toluene extractions and evaporate them with a hair dryer. The result is the impure ketone of pseudoephedrine, also know as methcathinione or ephedrone.We used very gentle oxidation, neutralization, extraction, and evaporation conditions. Shortcuts can be used (no ice, evaporate with some heat, etc.), but good lab practice is never to stress the substrate needlessly. So we were careful.The raw "dirty" methcathinone weighs about 1.7 grams.It is purified by adding just enough tolene to redissolve it. Some particles will not dissolve, and are left in the drying dish. The toluene is filtered to remove any additional particles, poured back into the separation funnel and shaken with an equal amount of distilled water. This removes any small amount of water solubles. The toluene is put into a clean dish and dried once again. The impurities are more soluble in acetone than the ephedrone, so a very small amout of acetone is added, and sloshed around. Pour this off into the waste (original green mix). What's left is a little over 1 gram (about 60% yield) of relatively pure, slightly off-white methcathinone.\nBetter chemists can expect a much higher yield. This is a general procedure. The example given -Pseudoephedrine or Ephedrine to Methcatinone - is for illustrative purposes only. Oxidizing cold pills is illegal, and makes a lousy drug anyway
456308
helll no!...naicin and about 3 gallons of h2o! will do the trick...good luck!
463474
Ice, ibuprofin and rest. Nothing else you can do. You might want to wrap it also just for the stability.
1025535
Take two plastic cups.  Perforate both cup bottoms and insert graphite rods.  Invert two glass jars over the cup bottoms so that the ends of the graphite rods are nearly sealed.  Then connect the ends of graphite on the open end of the cups with wires to a 6V battery (check that the batteries are fresh!).    Disconnect wire-battery connection till later.\n\nhen, prepare an electrolyte solution in a PLASTIC tub. Here, there are two options.  One is a solution of NaCl and the other is dilute H2SO4.  I tried NaCl before, but it gives a generally low yield.  Never tried H2SO4.  From what I heard, I recommend you use that- but use DILUTE H2SO4 (careful not to touch any).   Always make sure (either) solution is warm, so that electrolyte will be surely distributed.  \n\nFinally, lower the cups+jars in such a way that the water goes up 2/3 of the way up the jars (the graphite rods should be completely submerged).    Then, reconnect wire-battery and wait... until water levels drop dramatically (takes a long time).  Your anode (negative terminal) jar contains 02. while your cathode (positive terminal) jar contains H2.  Check presence of O2 by putting a smoldering splint into  the (still) inverted jar- it will reignite.  Check presence of H2 by bringing lit splint into the (still) inverted jar- it will go 'pop'.\n\nHope this works for you.
516829
Preparative HPLC should do the trick.  Try a search at these to see if an exact procedure might be on the web.\n\n\nhttp://www.scienceresearch.com/search/\n\nhttp://www.scirus.com/srsapp/
402174
You can Use Dean and Stark Apparatus To Separate them \n\nAlso one Source i m providing you which involve the separation using PTC\n\nRefer it \n\nhttp://www.ptcorganics.com/Top10PTC.pdf
145494
Gatorade or Pedialyte.
318573
The reaction between Hydrochloric acid and Sodium Hydroxide is as follows,\n\nHCl + NaOH --> NaCl + H2O\n\nYou can see that there is a 1:1 ration between the number of moles of HCl needed to completely reacted with NaOH.\n\nSince you are given both a volume and concentration of the NaOH solution, you should be easily able to calculate the number of moles of NaOH availible.\n# mole = volume * concentration\n# moles = .1 Liters * .25 moles/L = .025 moles of NaOH\n\nIf you know you have .025 moles of NaOH, you know you need .025 moles of HCl to react it completely.\n\nIf you know that you have a .15 mole/Liter solution of HCl, you can calculate the volume required to get .025 moles lie this,\nLiters = moles / oncentration\nLiters = .025 moles / .15 moles/Liter = .01667 Liters or about 167 mL of solution.\n\n\nNext time do your own homework.