there is a number that is that is 5 times the sum of its digit .what is the number pl. HELP?
487980
Yes, 45 is one but there can be others.
296260
such a no. cannot exist but hey dude a great question lets look at it this way\nthe last digit of the given no. will be 6\nand the resulting no will be 4 times that no\nlast digit of 4*6 is 4 so the resulting nos last digit digit has to 4 \nthat would mean the first digit of the original no will  be 4\nso just as an eg let us consider the no. 46\n46*4 will be 184\nthat is the first digit will be 1(or 2 or 3 or 4 but never 6)\nthis will be followed by every no \nso u c such a no just canno exist
97133
7,248,000,000.\n\nLook at the digit of the place you want to round to.\n\n7,248,193,675.\n------^\nLook to the immediate right. If this digit is 4 or less, keep the digit of the place you want to round to the same and make everything else a zero. If this digit is 5 or more,   make the digit of the place you are rouding to 1 greater, and then make everything else a zero. It is like seeing whicho ne the number is closer to.
53602
You need to round off the number to 4 digits and use the proper exponent to reflect the entire number:\n\n1.496 x 10^11  Your first answer is correct.
717483
1\nbecause u have mentioned that 1=5 so 5=1 and it cant = 9
741904
You have a billion numbers from 000,000,000 to 999,999,999.  These are all the possible combinations of digits 0 to 9 at each position (units, tens, hundreds, thousands, tens of thousands etc... to hundreds of millions).\n\nYou have 100,000,000 numbers starting with a 0.\n100,000,000 starting with a 1.\netc...\n100,000,000 starting with a 9.\n\nSince 0+1+2+3+4+5+6+7+8+9=45, this means the sum of all first digits is 45 x 100,000,000 = 4,500,000,000.\n\nSimilarly you will find that the sum of alll second digits (tens of millions) is also 4.5 billion.  Same for third digits, etc... and for ninth digits(units).\n\nSo the sum of all digits from 0 to 999,999,999 is 9 times 45 billion = 40,500,000,000.\n\nYou need to add 1 for the number 1,000,000,000, so the answer is 40.5 billion + 1 = 40,500,000,001.
580667
Type ' the the number\nlike this\n'12345678901234567890\n\nand it will entered as it is..\n\nXLMan
1126030
If a five digit number times 9 is another five digit number, then that five digit number must be less than or equal to 11111.  For it to be a five digit number, it must also be >=10000.  So the first digit must be 1. Hence, the last digit must be 9.\n\nSo our number is:\n\n    N = 1XYZ9.\n\nWe also know, since N<=11111, that X=0 or 1.\n\nNote that 9*N + N = 10*N, so you can write this as the addition problem:\n\n1XYZ9 + 9ZYX1 = 1XYZ90.  \n\nLooking at the tens digit, we see we get a carry over of 1 from the 1s digits, so we know that X+Z+1 has last digit 9.  But since X=0 or 1, that means X+Z+1 = 9, or X+Z=8. In the 100s digit, Y+Y has last digit Z.  In the 1000s digit, X+Z we know is 8, but we might get a carry-over from Y+Y of 1.  So either Y=X+Z=8 or Y=X+Z+1=9.  Since Y is always greater than 5, Y+Y always does contribute a 1 to the 1000s digit, so Y=9.  Y+Y has last digit 8, which means Z=8 and X=0.  So our number can only be 10989.
61276
100101111\nThat is:\n256+32+8+4+2+1
603285
this is possible to figure out.  What it is a combination of numbers   i will do examples to keep it simple.   If your number was 00  or 000  then the answer was 9.  well its a pattern    if your number is 001 then the answer he came up with was 8.  well then if you had 002  then it was 7.  but also on the note if your number was 011 or some combination of this number then it was 8 also  because when you take 011 and add 0+1+1 you get 2 so it was 8.   the way it works is the numbers you type in it adds them together so there is a correlating number that goes with the answer that was added together.  so... if the numer added together was 0 then it was 9.  and the number added together was 1 then he came up with 8.  added together you got 2 then he said 7.  and just keep going ... 3 is 6,   4 is 5.    also on the same account    5 is 4,  6 is 3,   7 is 2,   8 is 1,  and 9 is 0.
43951
you have to look at the 4th decimal place and if it is 5 or greater then you must raise the 3rd place to the next digit, if teh 4th decimal is 4 or less then you keep the number the same\n\n2986.342
158116
500+999+5667788+\n86676768766876667667+\n8980980808890890+\n798798787897897978=\n87,484,548,535,589,140,000\n\nFor some reason, all your numbers did not display.  I couldn't display them with "copy and paste" to post an answer.  I had to right click on your question to get all the number form "properties."  Then I pasted them in Yahoo and got your answer above.
352166
8\ntake away o from top and you're left with o on bottom - half - nothing\nor i guess 10 could work, too (or any double digit ending in 0) take away the first number and you're left with 0
1055246
Some simple tests to try out first:\n\n1. is the last digit is 5? (divisible by 5)\n\n2. do the digits sum to a multiple of 3? (divisible by 3)\n\n3. add all the digits in even positions (2nd, 4th, etc)\n    add all the digits in odd positions (1st, 3rd, etc)\n    subtract the 2 numbers\n    is this a multiple of 11?\n    e.g. given 9581: (9+8) - (5+1) = 17-6 = 11\n\nIf the answer to any of these is "yes", you have a composite number.\n\nIf not, tought luck! you will have to try dividing it by all odd numbers from 3 to half of the number (well, actually square-root of the number)\n\nAs an aside: try researching the term "recursion"
860441
I'm going to start by assuming that numbers starting with 0, other than zero itself, don't count.  Normally, since there are two choices for any individual digit, the number of numbers possible for any number of digits (d) is 2^d.\n\nHowever, since 0 can't be the starting digit for any but the one-digit numbers, your choices are cut in half, which would be 2^(d-1).\n\nThus, your answer would be the sum of:\n2 + 2^1 + 2^2 +...+ 2^9\n\nInterestingly enough, you'll notice that this answer ends up being 2^10.
888908
The answer is 23475.\n\nLet's look at how I got there:\n\n\nThe first digit is a prime number:  2,3,5,7\n\nOne is not a prime, so anything starting with 1 is not actually an option.  There are two valid numbers, but one of them has repeating digits.\n\nGood.  That narrows it down a lot.\n\nThe third digit is twice the first digit:  Following from the numbers possible for the first digit, it's 4,6,10,or 14.  It obviously cannot be the last 2 since they are two digits.  That means it is either 4 or 6, and the first digit is 2 or 3.\n\nSo far we have\n2x4xx or\n3x6xx\n\nThe fourth digit is the third digit plus 3.  That's easy.  We now have\n2x47x or\n3x69x\n\nThe fifth digit is the difference between the first digit and the fourth digit.  7-2=5 and  9-3=6  We now have\n\n2x475 or\n3x696\n\nWait!  The second number has a repeated digit, 6.  It thus cannot be the number.\n\nLet's go on with option 1.  The second digit is the fifth digit minus the first digit.  5-2=3\n\nThe number is 23475.\n\n\nHope this helps.
952696
n + (n - 5) + (n + 6) \n3n + 1