What's the limit of:?
475495
JohnyBoy almost has it right.  When you multiply both numerator and denominator by sqrt(1+cosX), the numerator becomes    X sqrt(1+cosX)        , not X (1+cosX),\nThe rest is correct.  So the limit is sqrt(2).
429977
not more than \n\nor\n\nnot less than
1116129
As x tends to 0 [1/x] tends to infinity. So 2^[1/x] is 2^[infinity](almost). So the limit naturally becomes infinitely large.
812928
There's no (practical) limit.  Most likely, you'll run out of space before it becomes an issue.
1108029
dambit dont you just hate that limit thing?
973997
Constraints of limitation!  (Meaning - the limits other people place on you)\n\nI must say, using Answers! to get help or ideas is great!  However, using it to actually DO your homework... not such a great idea... remember, a lot of teachers get online and use this site - they might see a correlation between some questions being asked and the paper you turn in!  \n\nJust a hint!!!!
893324
domain:  from - infinity to + infinity  (that's for x)\n\nrange: 0 to infinity (for y)\n\ny = |x+4|
836747
2,3,1 (nothing goes there) ,6\n\nHope it helps :]
521593
Forty of course.\n\n=D
756805
x<2   (-infinity,2)\nx>3   (3, infinity)\nx<2 see first interval\nx>-2 (-2,infinity)
807703
Achieved Theoritical Upper Limit
211385
minus one of how many ever u can ask.. as u've just asked one!
1113449
I dont think that there is a limit.
497029
No, because the limit as x->2- is undefined.  The limit exists for x->2+.
1123620
<  Less Than\n> Greater Than
1081409
I assume you mean:\nlim n->infinity of (1+n)^(1/n)\nIn this case, the limit is one.\n\nHowever, if you do:\nlim n->infinity of (1+(1/n))^n\nit is equal to e, or 2.718.....\n\n:)
35745
I think your equation got cut off because of the word-length limit.  Try putting spaces between the expressions (and put the equation in the 'more details section' and post again).  All I got was 550=2.297904*(L^0.38)*(M^0.41)... The answer to this snippet of equation at least is:\nM = 1.0596x10^58 / L^.926829