how do we convert standard form numbers to whole numbers?
478724
0.7 * 10^2 or 0.7 E+2 in some calculators,\n\nmeans that you must take your decimal (0.7 in this case) and shift the point a number of times as the exponent says (in this case 2) to the right if it is positive (like in this case) and to the left if it's negative.\n\nIn this case you must move the point two steps right: \nfrom 0.7 to 7.0 (first step) and then to 70. (final answer)\n\nAnother couple of exemples:\n\n.35 E-6 (or 0.35 * 10^-6)\nyou must move the point six steps left:\n0.00000035\n\n0.445 E+10 (or 0.445 * 10^10) \nyou must move the point 10 steps right:\n4450000000.
74472
Use ToString() with a format, like ToString("#.00"), as in...\n\nDim test As Double\ntest = 0\nSystem.Console.WriteLine(test.ToString("#.00"))
975293
TO_NUMBER: converts a character value expressing a number to a number datatype.\n\nSyntax: \nTO_NUMBER(char)\n\nExample:\nUPDATE <tablename> SET salary = salary + TO_NUMBER(SUBSTR('$100',2,3));\n\nOutput:\n10 rows updated.\n____________________________________-\nTO_CHAR: converts a value of a number datatype to a character datatype, using the optional format string. TO_CHAR() accepts a number(n) and a numeric format(fmt) in which the number has to appear. If fmt is omitted, 'n' is converted to a char value exactly long enough to hold all significant digits.\n\nSyntax:\nTO_CHAR (n[,fmt])\n\nExample:\nSELECT TO_CHAR(17145,'$099,999') "Char" FROM DUAL;\n\nOutput:\nChar\n- - - - - - - - - - - -\n$017,145\n\n[Look, I've given u the examples from my previously done queries, if u find any difficulty, u can mail me].
274854
The difficult thing here is reading and writing the numbers. They must be transformed from ASCII and then the result transformed back to ASCII.I found a program that calculates the sum of 2 numbers.I hope it helps.
668527
Using Roman numerals!  Twelve would be\n\nXII\n\nIf you cut that in half using a horizontal line, the top half looks like VII, which is 7.
369365
move the decimal point to the left 9 spaces.\n.000000004.
480629
Whole numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, and so on.\nThe whole numbers that are less than 6 (x<6) are\n{0,1,2,3,4,5}
314000
since they are all stored as binary all you need to do is display the results as either octal or decimal.\n//**************************************\n//INCLUDE files for :Convert Hex,dec,oct\n//**************************************\n#include <iostream.h>\n#include <conio.h> //for clrscr() & getche()func\n#include <stdlib.h> // for exit() function...\n//**************************************\n// Name: Convert Hex,dec,oct\n// Description:Converts an inputed number to Hex, dec, or oct.\nThe code was mainly written for education purposes.\n// By: Vagabond\n//\n//\n// Inputs:Inputs are from a main menu screen\n//\n// Returns:None\n//\n//Assumes:None\n//\n//Side Effects:None\n//This code is copyrighted and has limited warranties.\n//Please see http://www.Planet-Source-Code.com/xq/ASP/txtCodeId.10360/lngWId.3/qx/vb/scripts/ShowCode.htm\n//for details.\n//**************************************\n\n//****************************************************************************//\n// //\n// Program Name : ConvDec.cpp //\n// //\n// Programmer : Vagabond//\n//: Novice C++ //\n// //\n// Description : The user is asked to input a number in either Hex, Octal or //\n//Decimal, which is then converted to Hex, Octal & Decimal. //\n//The user can exit the program from the MAIN MENU or by//\n//the Escape key after each convertion.//\n// //\n//Compiler : Borland Turbo C++ v4.5.//\n// Date : 16/03/2006 //\n// //\n//****************************************************************************//\n#include <iostream.h>\n#include <conio.h>// for clrscr() & getche() functions...\n#include <stdlib.h> // for exit() function...\nconst int ESC = 27; // Used for escape sequince\nint main()\n\n\n    {\n    int key = 0;\n    int choise = 0;\n    long number;\n    while(key != ESC)\n\n\n        {\n        cout << "Choose Your Number Base&#92;n";\n        cout << "&#92;n&#92;t1. Hexadecimal.";\n        cout << "&#92;n&#92;t2. Octal.";\n        cout << "&#92;n&#92;t3. Decimal.";\n        cout << "&#92;n&#92;t4. Exit.&#92;n&#92;t";\n        cin >> choise;\n        switch(choise)\n\n\n            {\n            case 1: clrscr();\n             cout << "Enter a Hex number: ";\n             cin >> hex >> number;\n             cout << "&#92;n value in octal = "\n             << oct << number << endl;\n             cout << " value in decimal = "\n             << dec << number << endl;\n             break;\n            case 2: clrscr();\n             cout << "Enter a Octal number: ";\n             cin >> oct >> number;\n             cout << "&#92;nvalue in hex = "\n             << hex << number << endl;\n             cout << " value in decimal = "\n             << dec << number << endl;\n             break;\n            case 3: clrscr();\n             cout << "Enter a dec number: ";\n             cin >> dec >> number;\n             cout << "&#92;n value in octal = "\n             << oct << number << endl;\n             cout << "value in hex = "\n             << hex << number << endl;\n             break;\n            case 4: clrscr();\n             cout << "Program terminated by user...";\n             exit(0);\n             break; //Unreachable code.... \n            default : clrscr();\n             cout << "ERROR ~ Invalid selection&#92;n&#92;n";\n             break;\n            }\n            cout << "Press any key to continue or 'Esc' to exit";\n            key = getche();\n            clrscr();\n            }\n            cout << "Program terminated by user...";\n            return 0;\n
220005
Use a string. Calculate the first 16 digits, then put them into a string and subtract that number from your value and then use it as though its scientific notation. For example\n3.141592653589793 is the first 16 digits. So convert that to a string and then multiply your deriving value by 1,000,000,000,000,000 and start again. Then strip out the decimal and append to the string\n"2384626433832795"\nand then\n"0288419716939937", "5105820974944592", "3078164062862089",\n"9862803482534211", etc. \n\nThis should allow you a very large item.\n\n\nThe other option I can think of is declare an array 5 or 10 digits each and then store the numbers in there. That might work.\n\n\nEither way, good luck!
974244
Its just the whole numbers!\n0000\n0001\n0002\n0003\netc.\nup to\n9999\nremembering that if the number has less than 3 digits, you need to add the appropriate number of zeroes at the beginning.\n(i.e,. 23 would be 0023 and 456 would be 0456)\n(why anyone would want to 'prove' this or generate them in excel is beyond me. its a fabulous waste of time, unless you needed to print them out.) But if so,maybe you dont have excel:\n0000 0001 0002 0003 0004 0005 0006 0007 0008 0009 0010 0011 0012 0013 0014 0015 0016 0017 0018 0019 0020 0021 0022 0023 0024 0025 0026 0027 0028 0029 0030 0031 0032 0033 0034 0035 0036 0037 0038 0039 0040 0041 0042 0043 0044 0045 0046 0047 0048 0049 0050 0051 0052 0053 0054 0055 0056 0057 0058 0059 0060 0061 0062 0063 0064 0065 0066 0067 0068 0069 0070 0071 0072 0073 0074 0075 0076 0077 0078 0079 0080 0081 0082 0083 0084 0085 0086 0087 0088 0089 0090 0091 0092 0093 0094 0095 0096 0097 0098 0099 0100 0101 0102 0103 0104 0105 0106 0107 0108 0109 0110 0111 0112 0113 0114 0115 0116 0117 0118 0119 0120 0121 0122 0123 0124 0125 0126 0127 0128 0129 0130 0131 0132 0133 0134 0135 0136 0137 0138 0139 0140 0141 0142 0143 0144 0145 0146 0147 0148 0149 0150 0151 0152 0153 0154 0155 0156 0157 0158 0159 0160 0161 0162 0163 0164 0165 0166 0167 0168 0169 0170 0171 0172 0173 0174 0175 0176 0177 0178 0179 0180 0181 0182 0183 0184 0185 0186 0187 0188 0189 0190 0191 0192 0193 0194 0195 0196 0197 0198 0199 0200 0201 0202 0203 0204 0205 0206 0207 0208 0209 0210 0211 0212 0213 0214 0215 0216 0217 0218 0219 0220 0221 0222 0223 0224 0225 0226 0227 0228 0229 0230 0231 0232 0233 0234 0235 0236 0237 0238 0239 0240 0241 0242 0243 0244 0245 0246 0247 0248 0249 0250 0251 0252 0253 0254 0255 0256 0257 0258 0259 0260 0261 0262 0263 0264 0265 0266 0267 0268 0269 0270 0271 0272 0273 0274 0275 0276 0277 0278 0279 0280 0281 0282 0283 0284 0285 0286 0287 0288 0289 0290 0291 0292 0293 0294 0295 0296 0297 0298 0299 0300 0301 0302 0303 0304 0305 0306 0307 0308 0309 0310 0311 0312 0313 0314 0315 0316 0317 0318 0319 0320 0321 0322 0323 0324 0325 0326 0327 0328 0329 0330 0331 0332 0333 0334 0335 0336 0337 0338 0339 0340 0341 0342 0343 0344 0345 0346 0347 0348 0349 0350 0351 0352 0353 0354 0355 0356 0357 0358 0359 0360 0361 0362 0363 0364 0365 0366 0367 0368 0369 0370 0371 0372 0373 0374 0375 0376 0377 0378 0379 0380 0381 0382 0383 0384 0385 0386 0387 0388 0389 0390 0391 0392 0393 0394 0395 0396 0397 0398 0399 0400 0401 0402 0403 0404 0405 0406 0407 0408 0409 0410 0411 0412 0413 0414 0415 0416 0417 0418 0419 0420 0421 0422 0423 0424 0425 0426 0427 0428 0429 0430 0431 0432 0433 0434 0435 0436 0437 0438 0439 0440 0441 0442 0443 0444 0445 0446 0447 0448 0449 0450 0451 0452 0453 0454 0455 0456 0457 0458 0459 0460 0461 0462 0463 0464 0465 0466 0467 0468 0469 0470 0471 0472 0473 0474 0475 0476 0477 0478 0479 0480 0481 0482 0483 0484 0485 0486 0487 0488 0489 0490 0491 0492 0493 0494 0495 0496 0497 0498 0499 0500 0501 0502 0503 0504 0505 0506 0507 0508 0509 0510 0511 0512 0513 0514 0515 0516 0517 0518 0519 0520 0521 0522 0523 0524 0525 0526 0527 0528 0529 0530 0531 0532 0533 0534 0535 0536 0537 0538 0539 0540 0541 0542 0543 0544 0545 0546 0547 0548 0549 0550 0551 0552 0553 0554 0555 0556 0557 0558 0559 0560 0561 0562 0563 0564 0565 0566 0567 0568 0569 0570 0571 0572 0573 0574 0575 0576 0577 0578 0579 0580 0581 0582 0583 0584 0585 0586 0587 0588 0589 0590 0591 0592 0593 0594 0595 0596 0597 0598 0599 0600 0601 0602 0603 0604 0605 0606 0607 0608 0609 0610 0611 0612 0613 0614 0615 0616 0617 0618 0619 0620 0621 0622 0623 0624 0625 0626 0627 0628 0629 0630 0631 0632 0633 0634 0635 0636 0637 0638 0639 0640 0641 0642 0643 0644 0645 0646 0647 0648 0649 0650 0651 0652 0653 0654 0655 0656 0657 0658 0659 0660 0661 0662 0663 0664 0665 0666 0667 0668 0669 0670 0671 0672 0673 0674 0675 0676 0677 0678 0679 0680 0681 0682 0683 0684 0685 0686 0687 0688 0689 0690 0691 0692 0693 0694 0695 0696 0697 0698 0699 0700 0701 0702 0703 0704 0705 0706 0707 0708 0709 0710 0711 0712
478761
100,000,000,000,001 or one could give it to you in scientifi notation with a rounding error 10.0 E13
997626
http://www.convertit.com/Go/ConvertIt/Reference/AMS55.ASP?Res=150\n\nhttp://www.math.sfu.ca/~cbm/aands/subj.htm\n\nhttp://clusterfie.epn.edu.ec/ibernal/html/CURSOS/AbrilAgosto06/Metodos/Libros/Fundamentals%20Of%20Numerical%20Computing%20-%201997%20-Wiley%20%20(By%20Laxxuss).pdf
1177242
I suggest http://www.oanda.com/convert/classic\nI've tried this many times, very easy and very helpful too.
623394
IsNumeric will tell you if a value being passed into it can be converted into a number, were you to try to run Decimal.Parse on it. You might use it like this:\n\nFunction Translate(Foo as String) As Decimal\n    if IsNumeric(Foo) = True then\n      Return Decimal.Parse(Foo)\n    Else\n      Return 0\n    End if\nEnd Function
49715
use bitwise operators. something like:\n\nnum_bits = 0;\nfor(i = 0; i < 32; i++) {\nif number & (1<<i) num_bits++;\n}\n\nnow num_bits holds the number of bits that were set in number. The "<<" operator does bit shifting. So "1<<i" equals a number that's all 0's except for a 1 at position i. If you bitwise and that with something, that tells you if that bit is set in the number. So we do this for each of the bits and add up the results.\n\nThis is assuming 32-bit integers. Adjust accordingly for 64-bit integers.
930497
find the standerd formula, rearrange it, and plug in the numbers
1002104
there is no direct way.  A way of doing it though, would be for exampe, if you have 45.385, take the 45 as the whole number, and what u are left with .385, do 1 devided by 0.385, which gives you 2.59, so 2.6 rounded, now just multiply both by 10, and VOILA! 45 10/26\n\nSo basicaly devide "1" by the decimal, and multiply by 10, and put 10 over that answer!\n\nhope that helped