find the perimeter   5m 5m =?m?
473359
DEepnds on the shape. If it's a quadrilateral then it's 25 m. If it's a triangle, then it's 15 m. But that's only if all the shapes are regular (all sides and angles the same).
743282
Let x and y be the dimensions.  Then the perimeter is 2x+2y, and the area is xy = 1000.\n\nTo minimize the perimeter, set y = 1000/x and obtain the perimeter in terms of x alone,\n\n2x + 2000/x.\n\nTo minimize this, differentiate it, to get\n\n2 - 2000/x^2\n\nand set this equal to zero.  You get x = sqrt(1000), so y=1000/sqrt(1000)=sqrt(1000) as well, so the rectangle is actually a square.\n\nNote: to confirm that x=sqrt(1000) is a minimizer, not a maximizer, you can compute the second derivative, which is 4000/x^3, and see that it's positive, so this critical point is a minimizer.
534868
7\nbecause\n6m+5=47\n.....-5 -5\n   6m=42 (divide each side by 6 and u get 7 {42/6 =7)
753977
Do you mean the perimeter? To find the perimeter of a rectangle, you will have to add up the lengths of each side.\n\nFor example, a rectangle with sides that are 2 feet and 4 feet long would have a perimeter of 2 + 2 + 4 + 4 = 12 feet
115023
Imagine a `speed` x `time` chart. Plotting the data, we will have parallelogram whose area will the length the car walked between the two speeds.\n\nWe'll have, then, 30*((5.56+13.89)/2) = 291.75m
1077978
23 on the small side.\n\nIf the small side is x, then the long side is 5x.  That makes the perimeter x+x+5x+5x or 12x.\n\n12x=276\nx=276/12\nx=23\n\nThere for the rectangle is 23cmX115cm.
688339
Let's say w is the width of the rectangle.  Then, the length will be w+5.  We know the perimeter is 58, and we know that the rectangle has two sides of length w, and two sides of length (w+5).  So...\n\n2w + 2(w+5)=58\n2w + 2w + 10 = 58\n4w + 10 = 58\n4w = 58 - 10\nw = (58-10)/4\nw=48/4\nw=12, the width of the rectangle.\n\nSince the length=w+5, the length is 17.
35250
Perimeter = a+b+c\n\nThis is the answer your maths teacher will be looking for.
1169918
1 ->25000\n2cm ->2*25000cm=50000cm=500m\n\nans: b:500m
802049
The answer is (D).\n\nThe perimeter is 9x (just add up the 4 sides 2x+3x+3x+x to determine this) -- which eliminates (B) and (C) as a possible answer.\n\nThe area is 6x^2 -- which eliminates (A) as a possible answer, leaving only (D).\n\nLooks like you have a trapezoid, where the base is 2x, the sides are 3x each, and the top is x.  Draw straight lines down from your top to your base, so that your trapezoid is in 3 pieces:  a right triangle with base = x/2 and hypotenuse 3x, a rectangle x by 2x, and another right triangle with base = x/2 and hypotenuse 3x.  The area of the inner rectangle is 3x^2, and you can put the two triangles together to get another x by 2x rectangle for another 3x^2 area, or a total area of 6x^2.\n\nI hope that helped.\n\n~ ♥ ~
46001
you need to be more specific...\nbut technicaly the perimeter is the sum of all the sides...
1079204
Let's see . . . a meter is 39.37 inches so\n\n1 m = 39.37 in\n\nand you want to find 1.74 meters (which equals 1 m 74 cm) so\n\n(la ti do!)\n\n1/1.74=39.37/x\n\ncross-multiply to get\n\nx=39.37 X 1.74=68.5038 inches\n\nThere are twelve inches to a foot, so you would have\n\n5 feet (60 inches) + 8.5038 inches \n\nwhich is exactly 5 feet and 8.5038 inches, which equals 174 cm!
48612
Let r be the radius of the circle and s the length of the square's sides.\ncircle perimeter=2*pi*r, square perimeter=4*s\n2*pi*r=4*s => s=pi*r/2\ncircle area=pi*r^2, square area=s^2\ns^2=(pi*r/2)^2=pi^2*r^2/4\nBut pi<4 => pi^2*r^2/4<pi*r^2 => square area < circle area
598751
L=length w=width\n\nSo L=3w\n\nThe formula for perimeter is 2L+2W=P\nNow, you just plug in the variables and solve\n\n2(3W)+2W=64 --multiply 2 time 3W\n6W+2W=64    --add 6W and 2W\n8W=64    --Divide 8 on each side\nW=8\n\nWidth is 8 units\n\n--hope that helped
551690
T= L + 2B\n\nT is total surface area\nL is Perimeter x Height\nB is base area
1010902
This is  basic\nslope= m=(y2-y1)/(x2-x1)=(12-7)/(8-6)=5/2\nangle=arctan(5/2)
1071585
assume 0.1mm3\n6.02e22 mm3\n6.02e19 cm3 \n6.02e13 m3\n6.02e5 km3\nroughly 602,000 km3