the perimeter of a rectangle is 64 cm. the length is 3 times as long as the width. find the length and width?
463854
The perimeter is twice the sum of the length and the width. Given the ratio of length to width, the perimeter is necessarily eight times the width. Therefore the width is eight and the length is twenty four.
678410
Let y = the length of the base and x = the length of one of the equal legs.\nThe perimeter is the sum of all of the sides, so \nP = x + x + y or P = 2x + y\nThe leg is 8 less than 4 times the base translates into\nx = 4y - 8\nNow\nP = 2x + y\n29 = 2(4y-8) + y\n29 = 8y - 16 + y\n45 = 9y\ny = 45/9\ny = 5\nYou're looking for the length of the equal legs, so you need to find x.\nx = 4y-8\nx = 4(5) - 8\nx = 12cm
775763
Let the sides of the rectangle be x and y.\n\nWe have xy = 1000.\n\nThe perimeter of the rectangle is 2x + 2y.\n\nUsing the area equations, solve for y in terms of x:\n\ny = 1000/x\n\nThis gives a perimeter equation P(x):\n\nP(x) = 2x + 2000/x.\nP(x) = 2x + 2000x^(-1)\n\nTake P'(x) and set it equal to 0:\n\nP'(x) = 2 - 2000x^(-2) = 0\n\n2 - 2000x^(-2) = 0\n2 = 2000x^(-2)\n2x^2 = 2000\nx^2 = 1000\nx = sqrt(1000)\nx = 31.622 m.\n\nThe rectangle is a square having side length 31.622 m. The perimeter is 124.491 m
71096
let area be A\nwidth be W\nlength be L\nnow area of rectangle is = length * breadth \n    A = L * B\n  L = A/B\n L = 3x (squared) +14x+8 / x+4\n   = (3x+2)(x+4) / (x+4)\n   = 3x+2
906875
The trick is turning the word problem into equations.\n(Key: length = l; width = w)\n\nThey tell you the length is 3 feet more than twice the width, so:\nl = 2w + 3\n\nThen they tell you the perimeter (which is twice the width and twice the length) is 36, so:\n2l + 2w = 36\n\nYou should be able to take it from there.
816989
2 * (l + w) = perimeter of rectangle\nl * w       = area of rectangle\nPerimeter of rectangle = Area in sqr units\n=> 2 * (l +w) = l * w\n=> 2*l + 2*w = l*w\n=> 18 + 2 * (x+1) = 9 * ( x +1 ) since l = 9 and w = x + 1\n=> 18 + 2x + 2 = 9x +9\n=>  11 = 7x\nHence x = 11/7
65434
The question is WRONG. If you have length =6 and width =7, P=26 and A=42.
838640
The perimeter is the measure of all of the sides added together.  If you have a square, the sides are all equal.  So, 3+3+3+3= 12 OR 3x4=12.  The answer is D.
979599
L = length\nW = width\n\nLW = Area\n1) LW = 35\n\n2L + 2W = Perimeter\n2) 2L + 2W = 27\n\nSolve equation 1 for L and substitute into equation 2\n\nLW = 35\nL = 35/W\n\n2L + 2W = 27\n2(35/W) + 2W = 27\n70/W + 2W = 27\n70 + 2W^2 = 27W\n2W^2 - 27W + 70 = 0\n(2W - 7)(W - 10) = 0\nW = 7/2, 10\n\nL = 35/W\n\nIf W = 3.5, L = 10 and if W = 10, L = 3.5\n\nAssume L is longer than W: L = 10, W = 3.5
852685
The area of a rectangle is length * width.  The length is defined in terms of the width.  You know the area, but not the width, so call the width x.  The length is then 2x + 3.\n\nTherefore, you can set up the problem like this:\n\n(2x + 3) * x = 44\n\nMultiply out the x and move the 44 over to get this:\n\n2x^2 + 3x - 44 = 0\n\nThis should look familiar, and you should know how to solve this.  I got:\n\n(2x + 11)(x - 4) = 0\n\nwhich leads to:\n\n2x + 11 = 0           \n2x = -11          \nx = -11/2\n\n x - 4 = 0\n x = 4\n\nNow, you have two answers.  However, only one makes sense, as it is impossible to have a negative width.  Therefore, you can disregard x = -11/2, leaving x = 4 as the width.  You can then substitute x into 2x + 3 to get 2(4) + 3 = 11.\n\nAs a check:\n\n4 * 11 = 44\n\nTherefore, this is a good answer.
975485
H*W= area\nheight times width\n\none side has a height of 8 and its width is 9 thus the area would be 72
813209
perimeter= 4(L+W+H)\narea= length times the width times the height
259191
Perimeter\ntwo sides are 8 and the other two sides are 16. \n\n8 times 2 is 16 and 16 times 2 is 32. \n\n16+32= 48(unit) \n\n                Area\njust multiply them:) \n\n8 times 16= 128(unit) squared\n\nDoes that help?
528659
This is simple algebra. I'll use P for perimeter, and L and W for length and width.\n\nWe know that 2L + 2W = P = 94. Also, 2W + 3 = L.\n\nSo, put these equations together and solve.\n\nL - 2W = 3\n2L + 2W = 94\n\nAfter solving, you get L = 97/3 and W = 44/3.
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.
511828
I want to point out first that the formula for perimeter of a circle is (pi)d or 2(pi)r, not (pi)r^2- (pi)r^2 is for the area!\n\nAnyway, P= (pi)d\n         = 8pi\nDivide that by two since it's just a half circle\n         =4pi\nAdd 8 to that, and there you have it, the perimeter!\n\nFinal Answer- 4pi+8 or 20.56cm^2
832240
We know that the width is 5 yards, and that the length is double that, we can deduce that the length is 5x2=10.  So the rectangle is 5x10.\n\nThis means that the perimeter is 5x2+10x2=30 yards.  Since there are two sides length wise, and two width wise.\n\nThe area is the length times the width, 5x10=50 square yards.\n\nAgain, if you want to grow as a person you need to solve these yourself.  The time it took you to copy all these questions onto Yahoo! you should have been able to answer them yourself.  If you don't know how, you should be asking your teacher to explain them and give you extra tuition.