how would i calculate the weight per one thousand feet of 0.0145'' diameter of aluminum?
457065
0.0145 diameter means Pi x 0.0145 square inches in cross section = 0.0455 square inches. Multiply this by 1000 ft (convert feet to inches by using 12000inches) gives you 546.6 cubic inches for the entire piece. The density of aluminum is\n2.70 grams per cubic centimeter, so you convert 546.6 cubic inches to cubic centimeters by multiplying by 16.387 giving a total of 8,957 grams altogether.
445906
10 times 10 times 10 1000\nyou could use a calculator alot easier
481398
sum the forces in the direction that they are applied and it will be equal for a static object. \n\nRule of thumb on this one is that you have 100N down ward, then you need 100 N's up ward.\n\nGivens, legs are equal lengths, same material, and no angles to calculate.\n\n4 legs - 4 forces - each at 25 Newtons.  \n\nNow if you want to get fancy, break out the strain gauges and let us see what we really find.  But it helps if you have preformed a few material tests and experimenters first.
289324
simple F=m*a\nm=0.8\na= the acceleration due to gravity (9.8 ms^2)\nWeight is 7.84 N\nthe conversion should be in your textbook from newtons to lbs and from lbs to oz
778176
Use the periodic table of the elements.  The "weights" are in grams per mol.  Just use algebra and solve for the number of mols.  Then you know how many atoms there are by the number of mols which is a definite number.
9559
You're talking about weight of steel tubing in lbs. per foot, which is\n10.6802   X  Wall Thickness X  ( Diameter - Wall Thickness ),\nand for Round Tubing it is 10.6802 x T x (OD - T), where OD is Outside Diameter. The websites I listed below just offer the formula, with no explanation for the constant, but I'll try to give it some explanation.\n\nThe constant must be related to the properties of the material in question, steel in our case, which is made of carbon and iron. The concentration of these depends on the application and it causes the weight to vary, consequently, the constant will vary also.\n\nThe 10.6802 must be the constant of weight (if we have to put a name on it) for commercial piping steel, and its units should be lbs/ft, so that you will get pounds in your result. I’m not a mechanics or materials engineer so I’m just putting the basics of material’s science to work here.\n\nI recommend you look in The Science & Engineering of Materials, by Donald R. Askeland, Pradeep P. Phulé, or any other materials book.
803612
There are some charts on:\nhttp://www.krausco.biz/tonagechart.html\n\nwhich give a tonnage based on several factors. Once you have a method for actually calculating, you could check your answer against this site:\n\nexerpt:\n"RULE OF THUMB formula for making multiple bends on a press brake. For shape shown, in mild steel with radii equal to metal thickness unless otherwise noted.\n\nMultiply Metal Thickness by factor = Tons per Foot\n\nExample for bottom bending\n16ga (.062) Mild Steel. .062 x 150 = 9.3 tons per foot."\n\nHope this helps!
884698
diameter = 2 times radius.\n10 ft radius = 20 feet diameter
419589
100 short tons(2000lb ea.)=200,000 pounds\n100 long tons(2240lb ea.)=244.000 pounds\n100 tonne(metric ton)(1000kg/1kg=2.204lb)=220,462 pounds
845900
Do to the increased weight (volume) I'd say 1/100th of 33 feet.
149897
Depends on the temperature. At a guess at melting point not that different from solid aluminum.
710153
Usually psi (pounds per square inch).\n\nAloha
804854
The density of glass is around 2.3 gm/cc or 0.85 lb/in^3.  To get the  pounds per square foot,  Multiply the thickness in inches by 12.  So a 1/8" thick piece weighs 1.5 pounds per square foot.
373349
Volume = 1/48 * 1*1 = 1/48 cu ft\ndensity = 480 pounds per cu ft\n\nmass = density*volume = 480* 1/48 lb = 10 lb
106773
depends on the acceleration of the airplane or object. this found by vector addition. example: if an airplane or a rocket is falling freely (god forbid) all the objects inside will have 0 weight.
861406
(1000kg is not a ton, it is called a tonne or metric ton)\n\nThe object of 1000kg will have a force of acceleration on it of about 9.8m/s² during its fall of 5m.\n\nTo find the kinetic energy Ek that it will have at the end of its fall you just need to find its gravitational potential energy at the beginning of the fall.  By the end of the fall all the gravitational potential energy will have turned into kinetic energy.\n\nUg=(m)(g)(h)\n\nUg is grav. potential energy, m is mass, g is acceleration due to gravity, h is height\n\nUg=(1000)(9.8)(5)\nUg=49,000 Joules\n\nSo our Ek is also 49,000 Joules.\n\nThe object will land on the earth with 49,000 Joules of kinetic energy.\n\nNear the earth's surface, the object will have a force towards the earth of \nf=ma\nf=(1000kg)(9.8m/s²)\nf=98,000N\n\nAt the time of impact the composition of the earth will determine how much force the 1 tonne mass imparts on the earth.  If it lands somewhere soft where it can dig in far its kinetic energy will be eaten more slowly because it is pushing on the earth with a smaller force, if it lands somewhere very hard then the Ek will be eaten up very quickly as it will decelerate very quickly by imparting a large force on the earth.
1017844
You need the thickness, or the "height" of the aluminum foil.  Your density equation states that aluminum is 2.70 g/cm^3.  You have all the information except the height.  So plug in the numbers:\n\n2.70 g/cm^3 = 2.04g all over 11.5 cm X 14.0 cm X h\n= 2.04 g / 161 X h cm\n2.70 h= 2.04 / 161\n2.70 h = 0.0127\nh = 0.0047 cm\n\nReplace answer for h and you'll find the answer is correct.