sq ft of a 30 foot diameter circle pleeeeeease?
471852
Area of a circle = pi*r^2 and the radius is half of the diameter, so 15 feet in this case. (15 feet)*(15 feet)*3.14 = 706.5 feet^2\n\nSo about 706.5 square feet.
360732
Right.  I'm not sure what the question is, but let's assume that the space we are talking about is a rectangle, and you have to figure out what the dimensions are.  Well, the perimeter, 26, is the distance around the space which has the area of 36, which for the sake of argument, we will assume is square feet.  What times what equals 36?  9 x 4, right?  So, it's possible, but not certain that we are looking at a rectangle whose dimensions are 9 feet by 4 feet.  To prove this, remember that a rectangle has four sides.  If our assumptions are correct, it has two sides of 9 feet and two of 4 feet, right? So then,  9 + 9 + 4 + 4 = 26.  It would seem that this is the right answer.  \n\nOf course 12 times 3 also equals 36.  But this time, if we substitute the 12 and the 3 as the dimensions, we would get a perimeter of 30 feet, obviously the wrong answer.  Looks like you have a rectangular space that is 9 by 4 feet.\n\nI hope this helps and that I haven't just muddied the water further.
725266
12 x 16, that will equal square feet (192)\njust measure length times width to calculate square footage
991890
Try the 2-2 pattern. it's the best way. The 3 is done with that criss-cross pattern, but the 2-2 allows you to continue the circle, just make it have a big radius
974140
Multiply the two numbers together, then divide that total by 144.\n\nsample:  12in. x 24in. = 288sq in.\n                288sq. in. / 144sq. in. = 2 sq ft.\n                 144 is the number of sq inches in a square foot
145526
Length times width. A square measuring 2 feet by 2 feet is four square feet.
63808
30' feet deep by 160' wide...
1075072
The maximum area would be a circle. If it has to be a rectangle a square would be the highest area. So divide 50 by 4 and you get 12.5 and that will be the largest. It is a square 12.5 feet per side.
914474
well from my understanding there is 360 degrees in the circumference of a circle so divide that by 12 and you get 30 so every 30 degrees mark it.\nI hope i am not to wrong here!\n\nUnless its bigger but you can draw it down to fit that scale, that's not hard.
1048814
If the circles are concentric, just subtract the area of the smaller circle from the larger circle:\n\nArea of small:  6*6*pi\nArea of large:  9*9*pi\n\nDifference of areas = 81*pi   -    36*pi  =  45*pi = 45 * 3.14159  = \n\n141.37 square units
240663
Since you didn't say anything about the length of the tube or strips, I assume you're aligning the unknown longest side with the unknown length of the tube.\nThe largest square that can fit in this circle is that with sides of 3*Sqrt(2)", so you can fit 4 in width-wise and 22 in by thickness for a total of 88 strips. But there's some space left over on the sides. You can squeeze in 4 more strips on the side of the lengthwise strips for a total of 92 strips.\nBut there's more space in the tube outside the square which can hold even more wood.
163044
DIVIDE SQ INCHES BY 12 AND YOU GET SQ FEET
949995
check out www.mscdirect.com\nthey dont have 30x30 but they do have 36x24
505953
36.65 sq ft = 36 sq ft + 93.6 sq in\n\nYou multiply 0.65 sq ft x 144 to get sq in, because as you already used it, 144 sq in = 1 sq ft
935174
Let the length be x ft and the width be y ft\n\n2x + 2y = 300\nie x + y = 150\nThus y = 150 - x\n\nArea = xy\n=x(150 - x)\n= 150x - x²\n\nVertex of this parabola occurs when x = -b/2a and at this point Area is maximum as the parabola is concave down. (a < 0)\n\nie x = (-150)/(-2)\n= 75\n\nWhen x = 75 y = 75 so it should be square with sides 75 ft\n\nWhen x = 75, Area = 150*75 - 75² = 5625 sq ft\n\nSo the maximum area occurs when the length (and width) are 75 ft and it equals 5625 sq ft
915242
The area of a circle is calculated by multiplying pi (3.1415926) by the radius squared.  If you want it in square feet, make sure that you measure the radius in feet as well.
981841
area of the base times the height.