The amount of force needed to move an object depends on the objects?
466570
Mass.\n\nF=ma\n\nF is the force\nm is the mass\na is acceleration
390189
first you must know that where are you use this information ? \nif calculate of force per leg is very important , you must make a static model which is include all dimensions et. and you can calculate forces  with use most useful static rules. \nexample rules \ntotal moment = always zero (every point)  \ntotal forces any direction (x,y,z) = always zero \netc. \n\nif solution not important you can accept 25 N per leg
1059217
he value g=9.81 depends on the mass. Think about Newton's second law of motion: Force is equal to mass multiplied by acceleration. Commonly, in college, acceleration can be substituted by gravity in some special cases. So mass depends on gravity.
1036294
letter b is the answer.. because the weight of the object is approx. 627.20kg multiplied by 9.8(acceleration due to gravity) so the product is the force..
209689
mass in motion stays in motion unless disrupted by another force!
247359
Mass interacting with gravity
121693
cmon...dont u know basic physics...just calculate the resultant of these 2 forces\nanswer= [(132)^2 + (181)^2]^1/2\nif this makes sense!!
833368
find the force of her weight. \nthat should be the answer
955176
Force - Newtons\nMass - Kilograms\nAcceleration - metres per second
225182
There are many systems of measurement for force, ft/lbs, newtons etc. you can define your own if you wish. what is it you are really asking?
787229
Acceleration and Force are directly related. So the question is the same as asking for the position that gives 1/2 max force.\n\nSpring force and displacement are directly related. So the question is the same as asking for the displacement that is1/2 max displacement.
883840
The force due to friction (whether static or kinetic) is dependent on the appropriate coefficient of friction (static or kinetic), between the materials, and the mass of the object (which defines the NORMAL force between the two surfaces). \n\nBy the way, the coefficient of static friction is ALWAYS greater than for kinetic friction.\n \nNow, no matter what the surface area, the normal force will remain the same, since the mass remains the same. In other words, no matter what side you put the block on, the force due to static friction and the force due to kinetic friction will not change.\n\nHope this helps!
572487
Distribution of force over area.
912606
The simple answer is that the vector sum of the forces acting on an object must be zero if the object is to remain in "equilibrium" or in other words to have constant velocity.
782591
a)an object allways accelerates in the direction of the net force\n--- u dint tell us u had to do it as a well proven question or for basic understanding? never mind....if they ask u this in school then follow the explaination----\nby newtons first law of motion,...(i'm assuming u know it)...'unless and untill a force acts on it' ---so a body would move if adequate force was applied(that overcame its friction and inertia)\n\nas u know...forces cancel each other as well.\nthis happens according to the law of vectors.\nthus if two forces are acting in different directions, then the resultant force is always in another direction depending on how they cancel each other and according to their magnitude which is the resultant direction.\nso finally,...there be only one force left...with a particular direction and a particular magnitude....and now..applying newton's forst law of motion...it is proved that an object allways accelerates in the direction of the net force(newton's 2nd law states that force causes acceleration---u can also explain this by saying that,velocity changes hence acceleration occurs)\n\n\n(b)A lower net force is needed to accelerate an object from rest to 10m/s than is required to accelerate it from rest to 20m/s irrespective of the time take.-----\nthe answer is NO.\nwe have to take the time into consideration. if we  have to stop such a high speed in less time...then we have to apply a lot of force....remember---force causes acceleration..it causes a change per unit time...if u want more change per unit time...u have to apply more force\nso thats it
784877
How are they applied? Tangentially? In opposite direction? Or same?\nLet us assume oppo direc and on the border.\nThen net force=35N.\nTorque = r x F = I w\n=35x0.341= ''0.5'' m R^2\nR radius m mass\n ''Check if it is 0.5 only for a solid disk or cyliner about its axis.\n\nHope it helps
487670
None. It takes no power to maintain that speed (on level ground, no friction). The object has kinetic energy (0.5 * m * v^2). Power was required to put it in motion and power can be recovered by decelerating it. If you do the math, the energy is 3551.86 ft-lb, equivalent to 1 horsepower for 6.458 seconds. Answer 1 neglected the fact that weight must be converted to mass by dividing by g, and energy is proportional to v^2.