finding out how much soil will fit into a planter?
472982
a planter is the shape of a cone, but with the pointy end of the cone cut off.  if you know the formula for finding the volume of a cone, use it to figure out the volume of the cone that would be made if the planter did have the pointy end, then subtract the volume of the pointy end from the total volume, and that will leave you with thte volume of the planter
485446
I guess no one ever heard of a seedling except you and I.  A 7 inch plant isn't likely to be too large for that pot, but you may want to repot it if you eventually want it to get large.  A small (especially shallow) pot can stunt or deform the root system that will allow it to get big.\n\nIf it is your goal to eventually plant it in a much larger pot or outside, I'd say go ahead and repot it.  I'd keep the soil about the same, just make sure the soil is somewaht loose and has some organic matter in it and you should be alright.\n\nNurseries often grow 4 to 6 foot tall trees in whats called a #5 or 5 gallon pot.  It is slightly smaller than a 5 gallon pail.
421882
2" = 1/6 ft, so 60x20x(1/6) or (60x20)/6 will tell you how many cubic feet of sand you need.  However, these are both expressions.  To make an equation, you would write something like: \nV=60 ft x 20 ft x 1/6 ft \nwhere V is the volume of sand needed.\n\nIt works out to 200 cubic feet, by the way :)\n\nThe two previous answers are basically right except that volume can be expressed in neither square feet nor yards.  These are measures of area and distances, respectively.\n\nnotsomuch77 is right that you can convert from feet to yards by multiplying by 1/3.  However, to convert from _cubic_ feet to _cubic_ yards, you have to muliply by (1/3)^3, which is 1/27.  Basically, you have to muliply each length by 1/3, and when you do it three times it's the same as muliplying the whole thing by 1/27.
931375
Imagine the fence completley surrounding the garden:\nthen 2l+2w = 160  where l=length and w=width\nso w = 80-l\nalso area, a=lw = 80l - l^2\nfor max area da/dl=0\nda/dl = 80 - 2l\nthis is equal to zero when l=40 ft\nso w=40 ft\nand area = 1600 ft^2\n(nb the fence would be 40ft long on 3 sides and 30ft long on one side leaving room for a 10ft gate - using 150ft of fence)
333658
BOXES not BOXS...FULL not FILL\n1) multiply the dimensions of boxes\n2) take the percentage of remaining space as a decimal\n         Ex: 100-13=87 = .87\n3) multiply the number from 1 with the number from 2\n\n4259.52 Cubic Inches\nPlus\n4723.20 Cubic Inches\nPlus\n3801.60 Cubic Inches\n\nTotal: 12,784.32 Cubic Inches of remaining space
682836
You need to do a heat load calculation on your house to determine your heating and cooling needs. Then you size your heat pump equipment. where ever you get the equipment from should be able to tell you diameter and length of tube. You need to decide how much room you have for the installation. If your room is unlimited go with larger tube and 2 pipe system. What type of soil do you have? You can save some time and effort by using different installation methods.
929557
TOTAL SOIL AMOUNT  minus   INORGANIC CONTENT = ORGANIC CONTENT
855633
They do not need a lot of water.  Replace the soil with cactus soil from any garden centre, and give it a nice sized pot. Mine are always doubling in size, I split one a couple of weeks ago and got nineteen plants from it, which I threw away because nobody wanted one, shame innit.
998008
You can't convert them without knowing how much topsoil weighs, I'm afraid - and that will depend on how wet it is, etc.\n\nAlternatively, how big are the bags?
389337
Try this website; it has several links:\nhttp://www.answers.com/main/ntquery?s=Methods+of+soil+testing&gwp=11&ver=1.0.2.84&method=2
290493
Hole \nThe “hole’’ must be 41/4 inches (108 mm) in diameter and at least 4 inches (101.6 mm) deep. If a lining is used, it must be sunk at least 1 inch (25.4 mm) below the putting green surface unless the nature of the soil makes it impracticable to do so; its outer diameter must not exceed 41/4 inches (108 mm).
571378
1 half acre = 21,780 square feet\n\nSource: Google\n\nJust type in the conversion :)
538639
I am assuming you mean something like a round flower pot, where the base is smaller than the top.  You are saying the bottom has a diameter of 17 inches and the top has a diameter of 34 inches, with a height of 34 inches (not the slant).\n\nIs this correct?  I've also heard this called a truncated cone.  The formulas for volume is given below:\n\nHeight: h\nRadius of bases: r, R\nVolume: V\n\nV = Pi(R^2+rR+r^2)h/3\n\nSo plugging in your values (don't forget to cut the diameters in half to get radii):\n\nh = 34\nr = 8.5\nR = 17\n\nV = Pi(17^2+(8.5)(17)+8.5^2) 34 / 3\nV = Pi(289 + 144.5 + 72.25) 34/3\nV = Pi(505.75)34/3\nV = Pi(505.74)(10.333)\nV = Pi(5731.833)\nV = 18007 cubic inches
551690
T= L + 2B\n\nT is total surface area\nL is Perimeter x Height\nB is base area
415302
You need to use Pythagorean theorem.\nMeasure the lenght of the lotus plant which is above the water.(X)\nBend the plant to any one side until it is just submerged under the surface of water.\nMeasure the Dist. between the initial and final positions of the plant(Y)(i.e. the initial position and final position where it is submerged)\n\nLet the actual lenght be L.\nThen (L x L) = (Y x Y) + (L - X)(L - X)
367722
Part a)\n\nx = width\ny = length\n2x + 2y = 1000, so y = 500 - x\n\nA = xy = x(500 - x) = 500x - x^2\n\nb)  x should be positive (and small enough to fit the plot of land that he is planting the garden in)\n\nc)  If one corner is at the coordinates (0,0), the opposite corner is at (x,y) as defined above.\n\nd)  A = 500x - x^2\n\nCalculus Solution:\n\ndA/dx = 500 - 2x\nWhen 500 - 2x = 0, the area is a maximum.  Here, x = 250 and y = 250, so the maximum area is 62,500 square yards.\n\nNon-calculus Solution:\n\nGraph the equation A = 500x - x^2.  You can see that the parabola crosses the x-axis at x = 0 and at x = 500.  By symmetry, you know that the peak of the parabola must be half-way between 0 and 500 at x = 250.  When x = 250, A = 62,500, which is the maximum area.
724686
Start with what you know:\narea = 60 inches^2\nheight = 12 inches\n\nNeed to find base\nStart with known equation\nA = 1/2*b*h\nsolve for b = 2*A / h = 2 * 60 / 12 = 10 inches\n\nNow you know the base solve for the new height given the new area.\nArea = 60+20 = 80 inches^2\nh = 2*A / b = 2*80 / 10 = 16 inches\nso the new height is 16 inches\n\nCheck A = 1/2 * 10 * 16 = 80 inches^2