energy in harmonic motion?
458950
if  cud be just more specific...?
816137
a) v^2-u^2=2as\n    v^2-52.4^2=2*(-9.8)*28.5\nv^2= 2745.8-558.6\n     =2187.2\nv=46.76m/s\n\nKinetic Energy=1/2mv^2\n                     =1/2*46.9*46.76^2\n                      =51,290 Joules\n\nb)height=28.5-5.06=23.44m\n\nv^2-u^2=2as\n\nv^2-52.4^2=2*(-9.8)*23.44\nv^2=2745.8-459.42\n     =2286.4\nv=47.8m/s
712458
Simple harmonic motion can be described by a sinusoidal function\n\nX(t) = X0*sin(w*t)\n\nwhere X0 is the amplitude of the motion, w is the angular frequency, and t is time. Given this expression for the time dependence of the displacement, the velocity is expressed as\n\nV(t) = X0*w*cos(w*t)\n\nand the acceleration can be written as\n\nA(t) = -X0*w^2*sin(w*t).\n\nBased on these expressions, the maximum velocity is\n\nVm = X0*w\n\nand the maximum acceleration is\n\nAm = X0*w^2\n\nThe angular frequency w is\n\nw = 2*pi*f\n\nwhere the linear frequency for this problem is f = 4940 /min. Be sure to convert to the proper units to get the answers in the form you need.
816057
again ... conservation of (mechanical only here) energy\n\npot energy = kin energy\n\nmgh = 1/2 m V^2\n\nso V = sqrt(2gh) -- see mass irrelevant\n\nV = sqrt(2*9.8*8.53) = 12.9 m/s\n\ng=9.8m/s^2 is the acceleration due to gravity\n\ng=10m/s^2 is not a bad approximation
822266
Conservation of energy:  KE=PE\n1/2*Mb*Vb^2= (Mb+Mw)*g*h\nVb^2=2*(Mb+Mw)*g*h/Mb\nVb^2=2*(0.01+2)*10*0.1/0.01\nVb^2=402\nVb=20.05 m/s
958996
initial energy : (mv^2)/2 = (0.047*56^2)/2 = 73.696 J\nfinal energy : mgh +KE= 0.047*9.81*17 + KE = 73.696\n\nKE = 73.696 - 7.83819 = 65.85781 = (mv^2)/2\nv = squareroot(KE*2/m)\nv= 52.94 m/s
538402
No because of Kinetic energy.\n\nLesson 1: Basic Terminology and Concepts\nKinetic Energy\nKinetic energy is the energy of motion. An object which has motion - whether it be vertical or horizontal motion - has kinetic energy. There are many forms of kinetic energy - vibrational (the energy due to vibrational motion), rotational (the energy due to rotational motion), and translational (the energy due to motion from one location to another). To keep matters simple, we will focus upon translational kinetic energy. The amount of translational kinetic energy (from here on, the phrase kinetic energy will refer to translational kinetic energy) which an object has depends upon two variables: the mass (m) of the object and the speed (v) of the object. The following equation is used to represent the kinetic energy (KE) of an object.
396443
This is an excellent question and is quite tedious for a large number of particles, but there have been some papers written on this question. See http://www.geom.uiuc.edu/docs/forum/hoops_links/energy.html for an interesting aside, http://tracer.lcc.uma.es/problems/thomson/thomson.html for some illustration and http://lanl.arxiv.org/find/grp_q-bio,grp_cs,grp_physics,grp_math,grp_nlin/1/all:+AND+problem+Thomson/0/1/0/all/0/1 for the actual mathematics.
916458
Kinetic energy is energy in motion and potential energy is energy at rest.
90286
There are four kind of energy: \n1. Gravity\n2. Electromagnetic\n3. Weak atomic Energies\n4. Strong atomic Energies
870625
each of the particles would have 1/2 the energy of the spring, 30 j each.  They would move at different speeds, c moves slower than d, but energy 1/2 mv^2 would be the same.
1037424
evenly distributed energy
641698
The total amount of energy in a closed system remains constant.\nThis, however, was found to be untrue. It was later substituted for the conservation of Mass-Energy.\nThis was also disproven. In fact, if a tiny bit of energy is "borrowed" from nothing for a really short amount of time, it can create mass according to the equation:\nE*t = h/(2*pi) = 1.06*10^-34 Js\nOf course, for our pruposes, the conservation of energy works.
827543
The equations involved are:\na) freq*wavelength = velocity of wave\nb) energy of radiation E = h*freq, where h is Plank's constant.\nYou can work out from these that the choice should be a.
950937
You're in luck.  I teach physics and I know exactly how to answer this question (it's based on the work-energy principle).  It's pretty simple, really.  But it would be best if we discussed it by messenger.  Yahoo Messenger me, my ID is\nfortitudinousskeptic\n\n- Kevin
676957
E = 1/2 M V^2 where V is the velocity.  Either we need to know the distance of travel of the load or the speed of the vibrating load.\n\nA load  hitting the surface 3 times a second going back and forth 1 ft each way will exert greater energy than a load traveling only 1 inch 3 times a second.\n\nTherefore, if the distance of travel is "d"\nE= 1/2 [M (df)^2]
150677
(The total energy) = (kinetic energy) +(potential energy)\n\nAt the start, most of the energy is potential energy. \n\nAs you slide down, then the potential energy decreases and the kinetic energy increases. \n\nThere is some energy dissipated by friction, that turns into heat. But without friction, the total energy at the bottom of the slide is the same as it was at the top of the slide.