Solve by elimination 3x-2y=-8 3y-21=9x Show your answer please thanks?
379982
For the second equation, move the 9x to the left side and the -21 to the right side\n3y - 21 = 9x becomes\n-9x + 3y = 21\nRight the equations, so that one is right below the other one.\n3x - 2y = -8\n-9x + 3y = 21\nYou can cancel out the x's by multiplying the top equation by 3\n3(3x - 2y) = 3(-8) becomes\n9x - 6y = -24\nNow you have\n9x - 6y = -24\n-9x + 3y = 21\nAdd the two equations together\n-3y = -3\nThus, y = -1\nTo find x, replace y with -1 in either one of the original equations.\nYou will find that x = -2\nAnswer: (-2,-1)
769967
removing the brackets\n18+3y=4y-16-y\nsimplifying\n18+3y=3y-16\nadding 16\n34+3y=3y\nadding -3y\n34=0\nwhich is absurd\nso the equation cannot be solved
162979
From y=-3x-3 and y=x+5 you have -3x-3=x+5 so\n-3x-x=5+3\n-4x=8\nx=-2\nNow y=x+5=-2+5=3\nThe solution is (-2,3).
239058
You have to solve for one and substitue into the other...\n\nLets solve for x...\n\n2x + 3y = 40 \n2x = 40 - 3y\nx = (40 - 3y)/2\n\nThen Substitute in the other.\n-2x + 2y = 20\n-2(40 - 3y)/2 + 2y = 20  (the 2's in the first set cancel becaue 2/2 = 1 so...\n-(40-3y) + 2y = 20  (then distribute the -)\n-40 + 3y + 2y = 20 (combine like terms)\n5y = 60\ny =12\n\nThen sub y into the equation to find x\n\n 2x + 3y = 40 \n2x + 36 = 40\n2x = 4\nx=2\n\nDouble Check in the other equation...\n-2x + 2y = 20\n-2(2) + 2(12) = 20\n-4 + 24 = 20\n20 = 20 These equal so x=2 and y=12!
549969
x=-y-9\n3(-y-9)-y=-7\n-3y-27-y=-7\n-4y-27=-7\n-4y=-20\ny=5\nx+5=-9\nx=-14
892382
To solve the first one, divide each part of the first equation by two, so 2x-3y=-13; since -2x+3y = 13, adding the two equations gives 0x+0y=0.  No help.  Try substitution.\nFrom the first equation, 4x = 6y-26; x = 1.5y - 6.5\nsubstitute into the second equation -2(1.5y-6.5) + 3y = 13; -3y +13 + 3y = 13; 13=13.  Still no help.\nBoth equations are equivalent; the line that represents them is the solution.\n\nProblem two:\nSubtract equation 2 from equation 1.\n3x-3x+2y-3 = 6 - y\n2y-3 = 6-y\n3y = 9\ny = 3\n3x+6=6\nx=0\nchecking\n3x+3=y=3\n3x=0\nx=0
871743
Since we're given y = x+8, let's solve the first equation for x by plugging in y.\n\n3x*3y=y*x^2+96 <==> 3x*3(x+8)=(x+8)*x^2+96\nMove everything to one side and expand.\n(x+8)*x^2+96-3x*3(x+8) = 0\nx^3+8x^2 -9x^2 -24x + 96 = 0\nx^3 - x^2 -24x + 96 = 0\n\nThis is easiest solved by plugging in to the solver of a graphic calculator. Once you get values for x, plug in to y = x + 8 and you have values for y.
275027
Solve for y in the first equation and then substitute into the second equation.\n4x + 2y = 0  Subtract 4x from each side\n2y = -4x  Divide both sides by 2\ny = -2x\nSubstitute -2x for y in the equation 6x + 3y = 0\n6x + 3(-2x) = 0\n6x - 6x = 0\n0 = 0\nThis means there are infinitely many solutions of the form (x,y) where x is any real number and y = -2x.\nTherefore, the answer is\n(x,-2x), where x is any real number.
232592
2x = 3y - 4y + 5 - 2\n2x = -y + 3\n2x + y = 3
860215
6x - 2y = 8 dividing both sides by 2 we get => 3x - y = 4 -----(1)\n3x + 7y = - 4 -----(2)\n(1) - (2) => 3x - y - 3x - 7y = 4 - (-4)\n-8y = 8 and y= -1\nso x = 1
984033
2x+3y=4\n4x+3y=-36\nsubtracting\n-2x=40\ndividing by -2\nx=-20\nsobstituting\n-40+3y=4\nadding 40\n3y=44\ny=44/3
409430
12x - 16y = 8\n9x - 12y = 6\n\n12x - 16y = 8\n-16y = -12x + 8\ny = (3/4)x - (1/2)\n\n9x - 12y = 6\n-12y = -9x + 6\ny = (3/4)x - (1/2)\n\nANS : 3.) (t,(3/4)t - (1/2))\n\nThats if i understand you correctly.
247328
wrtie the eqations as \n3x-2y=-8      \n9x-3y=-21\nmutliply first equation by 3\n9x-18y=-72\n9x-3y=-21\nnow deduct first equation from 2\nu get \ny=25.5\nu can calculate x now\nbut kid see one thing never ask direct questions see solved examples fom the book and then try solving the question by ur own \ngetting the solution will not help u to score in examination\ncheeeeers
309995
do this\n9x-3/4y=1  move 9x to other side\n3/4y=-9x+1 get rid of 3/4, by7 multiplying everything by 4/3\ny=-9x*4/3 +1*4/3\ny=-12x+4/3
1008519
Solve the first one for x:  x = 3\nSolve the second one for y:\n7x - 5y = 8\n7(3) - 5y = 8\n21 - 5y = 8\n-5y = -13\ny = 13/5\n\nCheck it:\n3-3 = 0 ---> OK\n7(3) - 5(13/5) = 21 - 13 = 8 --->OK\n\nDone.  Hope this helps!
689072
5x + 3y = 16 ------ equation 1\n\n2x + 3y = 1 ------- equation 2\n2x = 1 - 3y\nLet x = (1-3y) / 2 \n\nReplace x with y in equation 1, and solve y\n\n5 [ (1-3y) / 2 ] + 3y = 16\n5 (1-3y) + 6y = 32\n5 - 15y + 6y = 32\n9y = -27\ny = -3\n\nReplace the value of y to solve x\n \ntherefore x = [ 1 - 3(-3) ] / 2\nx = 10/2 = 5\n\nYou can try and solve the other pair of system using the same basis as above.
900384
suppose 2x-4=y then your equation is:\n\ny^2-4y-21=0 by solving this equation:\n\ny=(4(+-) (4^2-4*(-21))^0.5)/2 = (4(+-) 10)/2\ny1=7 and y2= -3 now\n\n2x-4= 7 then x1=11/2\n2x-4= -3 then x2=1/2