to demonstrate linkage of two makers a and b by transformation, one needs to demonstrate that?
474656
If you are talking about bacteria such as E Coli, you need to demonstrate that the markers are close to each other. To do that you need to do mating involving the F factor and demonstrate that the linked genes transfere near to each other.  This was done in classical expts in the 40s and 50s.
912141
Here are two (see refs.). Note that the second one is a rotating 3-D model.
745993
There is a great animation that explains the experiments in detail (with pictures) on the Mendel site at http://www.mendel-museum.org/eng/1online/experiment.htm
54243
DO YOUR OWN HOMEWORK. I'll expect you to show YOUR work when you hand it in.
808145
I think you might have a paper-worthy idea here. Not sure, like the first poster, of the amount of support you'll find to back your theory up, but I do find the comparison appealing, and I've never thought of that before!\n\nHope you can draw the similarities without too much painful, fruitless research! Good luck!
693711
Two sides to the same coin.
447231
Aha, geometry!\n\nDraw a diagram and follow the steps below.\n\nThe trick is to show that the triangles DBE and \ntriangle DAF are similar.\n\nProof That triangles DBE and triangle DAF are similar.\n\nLet <ABC> donote angle ABC.\nWe need to show any two corresponding angles of these traingles are equal.\n\nFirst angle,\n<FDA> = <BDE>  because D,B,F collinear and D,E,A collinear.\n\nSecond angle,\n<DAF> = <DAC> because A,F,C collinear\n      = (pi) - <ACD> - <ADC> angles in triangle ACD\n      = (pi) - <ACD> - <ADC>  ...(1)\n\nNow, separately  manipulate,<ACD> and <ADC>.\n\n<ACD> = <ACB> + <BCD> splitting <ACD> with line CB\n      = <ACB> + <CAB>, tangent property <BCD> = <CAB> \n      = (pi) - <CBA>  angles in triangle ABC\n      = <ABE>  because C,B,E are all colinear\n\nNow, similarly\n\n<ADC> = <ADB> + <BDC> splitting <ADC> with line DB\n      = <ADB> + <BAD>, tangent property <BDC> = <BAD> \n      = (pi) - <ABD>  angles in triangle ABD\n         \nSubstituiting these two info into (1), we get,  \n\n<DAF> = (pi) - <ACD> - <ADC>\n      = (pi) - <ABE> - [ (pi) - <ABD> ]\n      = <ABD> - <ABE>\n      = <BDE> because BE splits <ABD> \n\nDone. In showing the triangle DAF and triangle DBE are similar.\n\nHence, by ratio for similar triangles,\n\n        DA/DF = DB/DE\n\nOr Rewriting we get\n \n      DA * DE = DB * DF\n\nProved.\n\nNot so difficult, was it. hehehe.\n\nRegards
524082
If you change something it is not a clone anymore. It has to be an exact copy to be a clone. Your a bit obsessed with cloning aren't you?
179367
the answer to the question deals with einstein's special theory of relativity.  the equations that show the actual relationships are known as the lorentz transformations.  check out the website for a depiction of the lorentz stuff.  wikipedia has a more detailed article on special relativity and the lorentz transformations too.
1134906
Here's a link to a PDF file I wrote consisting of all the steps involved (though not quick enough to beat the other two answerers...)\n\nhttp://prash4.esmartdesign.com/ans2.pdf
944972
you need to provide just a llliiiiiiitttttttlllleeee more information if you want a real answer.\n\nGlue....industrial, relationships, arts and crafts, molecular, ????
1088610
Maybe the missing link isn't so missing.
772930
how about the history of mass production..\nthe fact that some things now have interchangable parts. The evolution from being able to replace a part of something , like a car, and still use the product.\nThen introduce the new world of disposable products. like calculators and computers and how it has influenced a world who has to have it now and easy..\ngood luck
102346
Below is a link to a simplified tutorial.
226661
clone or twin or whatever.. it'll be inscest
162014
it's a technique in science where two players want to choose a strategy to maximise their own profit according to the strategies choosen by the competitor
783048
If this is a course that you are on, they will have written the case study in such a way that the main entities should be fairly obvious.  Work out who/what are the main entities and then see if you can form an Entity Relationship Diagram.  When you have this, work out the degree of the relationship (one to one, one to many, many to many) and correct any many to many relationships by introducing new entities and reworking the relations.\n\nAs to the attributes, that takes a bit of thinking through on your part but you need to establish entities first.