Finding the slope of the line passing through (3, 2)  (3,9)?
471084
undefined, because 3-3 = 0
1101719
Step 1: Find the slope of the line x-2y = 2.  Call it m. \n\nStep 2: Find the derivative f'(x) of the function f(x) = (x-1)/(x+1).\n\nStep 3: Find all values of x where f'(x) = m.\n\nStep 4: For each such value, find its corresponding y-coordinate by setting y=f(x), and then find the equation of the line that goes through that point with slope m.\n\nGood luck!
911563
Here's 2 examples:\n\n1.) Given point (2,2) and (3,3), find the function.\nStep 1: Find the slope.\nSlope = rise/run = (y2 - y1) / (x2 - x1) \n(3 - 2) / (3 - 2) = 1/1 = 1.\n\nStep 2: Given the slope, find the y intercept by trying to find a point (0, y) that fits the 2 points above, and the slope given.\nUse the slope formula: rise / run = 1\n(2 - y) / (2 - 0) = 1 = (2 - y) / 2 \n2 = 2 - y\n-y = 0\ny = 0\ny intercept = 0, 0\n\nStep 3: Once you have the slope, you can write it in slope intercept form:\ny = mx + b \nm = slope, b = y intercept\ny = 1x + 0, or y = x.\n\n2.) (a harder one) Given point (1,4) and (-3, 2), find the function.\nStep 1: Find the slope.\nm = rise/run = (y2 - y1) / (x2 - x1) \n(4 - 2) / (1 - -3) = 2/4 = 1/2 = .5\n\nStep 2: Given the slope, find the y intercept at (0, y)\nm = rise / run = 1/2\n(4 - y) / (1 - 0) = 1/2 = (4 - y) / 1 \n4 - y = 1/2\n-y = -3.5\ny = 3.5\ny intercept = 0, 3.5\n\nStep 3: Write it in slope intercept form:\ny = mx + b \ny = .5x + 3.5
858135
m = (9-(-1))/(-2-3) = 10/-5 = -2\n\n-1 = -2(3) + b\nb = -1 + 6\nb = 5\n\n\nf(x)= -2x + 5\n\n\nYou got the slope sign reversed.  Be careful about that.  Otherwise, it's correct!
1066076
ok first set up the problem according to y=mx+b:\n3y+2x+6=0\n- you want to get y by itself so you subtract 2x+6 from both sides (or add -2x-6)\n- you should get 3y= -2x-6\n-then divide by 3(or multiply by 1/3)on both sides\n- you should get y=-2/3x-2 and since m = your slope then the slope is -2/3\n:D\nI LOVE MATH!!!!!!!!
600555
y = mx + b\n\n"m" is the slope, which is the rise over the run.  y2-y1 / x2/1 = (1-3)/(3-2) = -2/1\nSo, m = -2\n\nPlug in a set of coordinates to find b...\n3 = -2(2) + b\nb = 7\n\nSo, the equation is y = -2x + 7\n\nIn yout case, you want it as Ax+By+C = 0\nThis would be 2x + y - 7 = 0
706345
slope = -5-1 / -2-(-3) = -6/1 = -6\ny-1=-6(x+3)\n.
674651
put it in standard form :\n\ny < -1/2x + 3/2 \nand \ny > 2/3x + 2\n\nthen you know the first line passes thru the y axis at 3/2 and the second at 2\n\nthe slopes are -1/2 and 2/3 .... then shade below the line on the first one cuz y is less than .\n\nthen shade above the second line because y is greater than
408060
To find the slope, you always have to set the equation as y=mx+b.  That equation is called the slope-intercept form.  "m" is the slope and b is the y-intercept.\nNow, to find the slope, try to get y alone.\n1. Subtract 2x from both sides.  You'll get: -8y=-2x+7\n2. Divide both sides by -8.  You'll get: y=(1/4)x+(-7/8)\nSo, the equation is y=(1/4)x-(7/8) and the slope is (1/4).
161144
equation of slope is (y2-y1)/(x2-x1)\n\n(8,-2) means x1=8 and y1=-2\n(3,5) means x2=3 and y2=5\n\nso slope= (5-(-2))/(3-8)\n=7/-5\n\nso slope= -7/5
1121252
slope = m\nperpendicular slope = (-1)/m\n\nslope = (y2-y1)/(x2-x1)\nslope = (2-5)/(4-2)\nslope = -3/2\n\nperpendicular slope = 2/3
134706
I'd plot the points and figure out the slope (vertical change/horizontal change).  In this case, it would be -1 [2 / -2].  Then trace out the line to see at what point it crosses the Y axis.  In this case, it would be -2.  Then plus those numbers in the the equation "Y = (slope)X + (intersection of Y axis)"  So, if I'm not mistaken, the solution should be "Y = -X - 2".
258618
This is what I wrote for a very close question to this one. Just ignore the graphing part. I didn't feel like doing the question right now, but this is the way to do it:\n\n"If you need the tangent, take the derivative of the function at the specific point, which will give you the slope. Since you have taken the derivative at some specific point (a,f(a)) you also have a point. Now use the point-slope form to figure out the equation. Then simply get a graph paper and graph it.\n\nExample: f(x)=3tan(2x)\n\nf'(x)=6[sec(2x)]^2 (I assume you can take derivatives.)\n\nYou have a point (a,f(a))\n\nNow use the point-slope form: y-f(a)=f'(x)(x-a)\ny-3tan(2a)=6[sec(2a)]^2*(x-a) is the answer in this case. \n\nOr in function form: y=6[sec(2a)]^2*(x-a)+3tan(2a)\n\nTo graph it, find 2 points on the equation, then draw a straight line between them. That is your tangent."
744864
although Question is little vague, i understand that u want to find slope of a line ???\n\nsay coordinatyes of A and B are (x1,y1) and (x2,y2)\n\nThe Slope of line m= (y1-y2)/(x1-x2)
941588
Identify the slope of each line and compare the values.\nIf the slopes are the same then they are parallel.\nIf the slopes give a value of -1 when multiplied together, then they are perpendicular.\nIf the slopes differ from that about, then they are neither.\n\nBring the y value to a unit value of one.\n(1) Slope 6∙4 and 6∙4, so it's parallel.\n(2) Slope ½ and ? , second equation is unclear.\nThe slopes are probably 3/2 and -3/2, if so, then they are perpendicular.\n(3) Slope -1/3 and 1/3, so the lines are perpendicular.
850944
You have 2 points, (x1,y1) and (x2,y2) and you want to find the equation of the line that goes through these points.\n\nThe first thing you want to do is find the slope.\nslope is rise/run so m = (y1-y2)/(x1-x2)\n\nFor slope intercept form , y = mx + b\nwhere m is the slope, and b is the y intercept\nnow that you have found the slope, you can solve for b, the y intercept by plugging in your value for m and one of the given points, either (x1,y1) or (x2,y2).\n\nFor point slope form,  y - K = m(x - H)\nm is the slope, and   (H,K) is a point that the line passes through.\nSince you have already calculated the slope, m, for the slope intercept form, you're already almost done. All you have to do is plug in the point (x1,y1) or (x2,y2). In your question, you are asked for the point slope form of just point (6,2).
1164791
y=mx+b\n2=2(3)+b..... (in this you know the slope is 2 b/c the line is parallel.\n2=6+b\n-4=b...... (so now you will want to write your equation for your line)\n\ny=2x-4..... (DONE!)