writing an equation of a line that has each pair of intercepts?
468700
I'll calculate these, but I'll apologize now to those others who might already be doing this if I post my replies after yours.....\n\n1. x-intercept:2,y-intercept 1\nx-int = 2 at point (2, 0) = (x1, y1)\ny-int = 1 at point (0, 1) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (1-0)/(0-2)\nm = -1/2\n\ny = mx + b (now, b is the y-intercept)\ny = (-1/2)x + 1\n\ny = (-1/2)x + 1 (substitute other point for verification)\n0 = (-1/2)*(2) + 1\n0 = 0\n\ny = (-1/2)x + 1\n\n------------------------------------------------------------\n2. x-intercept:5, y intercept 5\nx-int = 5 at point (5, 0) = (x1, y1)\ny-int = 5 at point (0, 5) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (5-0)/(0-5)\nm = -1\n\ny = mx + b (now, b is the y-intercept)\ny = -x + 5\n\ny = -x + 5 (substitute other point for verification)\n0 = (-1)*(5) + 5\n0 = 0\n\ny = -x + 5\n\n------------------------------------------------------------\n3. x-intercept:-4,y-intercept -1 \nx-int = -4 at point (-4, 0) = (x1, y1)\ny-int = -1 at point (0, -1) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (-1-0)/(0-(-4))\nm = -1/4\n\ny = mx + b (now, b is the y-intercept)\ny = (-1/4)x - 1\n\ny = (-1/4)x - 1 (substitute other point for verification)\n0 = (-1/4)*(-4) - 1\n0 = 0\n\ny = (-1/4)x - 1
375327
Where x = 0, the line intercepts the y-axis:\n\n1. 5x-2y =10 \n2y = 5x - 10\ny = (5/2)x - 5 \ny-int = (0, -5)\n\n2. 2y+7x =14\n2y = -7x + 14\ny = (-7/2)x + 7\ny-int = (0, 7)\n\n3. x=3\nHas no y-intercept\n\n4. 1/2x-2y=8\n2y = (1/2)x - 8\ny = (1/4)x - 4\ny-int = (0, -4)
147089
y intercept: (0,4)\nx intercept: (3,0)
564627
change the equation to slope intercept form\nsolve the equations for y\nx+2y=3\n2y= 3- x\ny= -x/2 + 3/2\nDo the same thing for the other formula\nthe form is\ny = mx + b\nAfter that just plug in numbers for x to get y
346120
The equation of a line in slope-intercept form is given by \ny=mx+b where m is the slope and b is the y-intercept.\nAll you have to do is plug the numbers in.\nso the equation is y=9x-3
30454
say the line is y= ax + b\nsubstitute the (x,y)= (3,-11), (-1,9)\n\n-11= 3a+b......(1)\n9= -a+b.......(2)\nsubtract (2) from (1)\n\n-11-9= (3a+b)-(-a+b)\n-20= 4a\na=-5\nsubstitute this back into (2)\n9=5+b\nb=4\n\nie the original equation is y=-5x+4\n\nThe answer is D. but u left "x" out
341751
Using pt. slope equation:\n\nY=mX+B where m=slope = 2/3, b=intercept, in this case = 0,\n\nY = 2/3 * x + 0\n\ny=2x/3.\n\n3y=2x\n3y-2x = 0.\n2x-3y=0
317632
slope = 1/5\ny-intercept = 2\nx intercept = -10
341565
Well, first, write it in standard form (y=mx+b).\n\ny = -3x + 0\n\nThe m in the equation is the slope of the line, and the b is the y-intercept. \n\nSlope = -3\ny-Intercept = 0\n\nFor another example, y = 5x + 3 would have a slope of 5 and a y-intercept of 3.\n\n\nHope this helped.
955089
y-2x=2\ny=2(x+1)\nx intercept(-1,0)\ny intercept(0,2)
937748
there are a couple of ways to do this, but I think the easiest is to find the slope and since you know the y-intercept, use that formula.\n\nm= (-4-0)/(0-12)\n\nm=-4/-12\nm=1/3\n\ny=(1/3)x -4
523941
x intercept y=4 (0,4)\n(plug 0 in for x and solve)\ny intercept x=20/3 (20/3,0)\n(plug 0 in for y and solve)
610726
there is a solution, all x,y that satisfy this equation:\ny = 4 - 2x\n\nwhich is a straight line with intercepts (0,4) & (2,0)\n\nIt has an infinite amount of solutions. To be able to solve for actual numbers, you need as many equations as you have variables.
645941
4x + y >= 4\ny >= -4x +4\n\n-------\ny = 0\n0 >= -4x + 4\nx = 1\n-------\nx = 0 \ny >= 0 + 4\ny = 4\n-------\n\n\nTherefore, shade the region above the line.\n\nTwo points on the line are:\nx-intercept: (0, 4)\ny-intercept: (1, 0)
89344
Use the two given points:\n(x1=7, y1=5) and (x2=-1, y2=1/5)\nand the "two point equation":\ny-y1 = ((y2-y1) / (x2-x1)) * (x - x1)\nto get started on this problem.\n\ny-[5]=(([1/5]-[5]) / ([-1]-[7])) * (x-[7])\ny-5=((-24/5)/(-8))*(x-7)\ny-5=(3/5)*(x-7)\n\nNow put the equation into the "slope intercept" form of y = mx+b.\n\ny-5=(3/5)*x - (21/5)\ny=(3/5)*x - (46/5)\n\nThe slope = 3/5\nThe intercept = -46/5
771990
y = mx + b is the slope intercept form, where m = slope\n\nso 2 is the slope in your example\n\nWith any equation for a line, there are 2 variables, x and y, representing the position on the x and y axis.  Given any line equation, you can manipulate it to get it into slope intercept form (y = mx + b), and m will be your slope.\n\nThe y-intercept is where the line crosses the y-axis (or where x = 0).  As you can see, if you put x = 0 in the equation, you will get:\n\ny = 0x + b\ny = b\n\nso when x = 0, y = b.\n\nHope this helps! :)
444240
-y=2-x\n\ny=x-2\n\nslope is 1\ny intercept is (0,-2)