try to answer this x+3 over 2 multiplied by x^2 minus x over x+3 equals to 21? show me your steps?
457401
((x+3)/2)((x^2-x)/x+3)=21\nMultiply the numerator and demoninators together\n[(x+3)(x^2-x)]/[2(x+3)]\nyou can cancel the x+3 out from the numerator and demominator\n(x^2-x)/2=21\ncross multiply\nx^2-x=42\nmove the 42 over\nx^2-x-42=0\nfactor\n(x-7)(x+6)=0\nx=7,-6\nPlug x in and see if it equals 21 and it does
574042
we need to multiply something by (x+1) so that the result would be x^2-1. but we know x^2-1 = (x-1)(x+1).\nso we have to multiply (x-1) with (x+1) to get x^2-1.
572480
breaking it apart, we have:\n\n(x+1)^3=(x+1)(x+1)(x+1)=\n(x^2 + 2x + 1)(x+1) =\n(x^3 + 3x^2 + 3x + 1) SO\n6(x+1)^3 = 6(x^3 + 3x^2 + 3x + 1) = 6x^3 + 18x^2 + 18x + 6\n\n(x+1)^2 = (x+1)(x+1)=\nx^2 + 2x + 1   SO\n-3(x+1)^2 = -3(x^2 + 2x + 1)=\n-3x^2 - 6x - 3\n\n4(x + 1) = 4x + 4\nand -9 stays the same.\n\nSo putting everything together, you have\n(6x^3 + 18x^2 + 18x + 6) + (-3x^2 - 6x - 3) + (4x + 4) - 9 \ncombine like terms and you get:\n6x^3 + (18x^2 -3x^2) + (18x - 6x + 4x) + (6 - 3 + 4 - 9)\n6x^3 + 15x^2 +  16x - 2\n\nWHEW!  That took me back to college pre-calc!
897152
let x = smaller number\n2x + 8 = larger number\n2(2x + 8) + 3x = 65\n4x + 16 + 3x = 65\n7x + 16 - 16 = 65 - 16\n7x = 49\n7x/7 = 49/7\nx =7
751626
01. -1/2(x+2) = 3 [given]\n\n(x+2) = -6 [multiply both sides by -6]\n\nx = -8 [subtract 2 from both sides]\n\n02. 1/5x = 10 [given]\n\nx = 50 [multiply both sides by 5]\n\n03. 3k = -6/7 [given]\n\n-21k = 6 [multiply both sides by -7]\n\nk = -6/21 [divide -21 on both sides]
798648
(x+3)(x^2+2x+4)\n\nStart by taking the first term in the first parenthesis and multiplying it by each term in the second parenthesis:\n\nx*x^2 + x*2x + x*4 = x^3 + 2x^2 + 4x\n\nNow take the second term and multiply it by each term in the second parenthesis:\n\n3*x^2 + 3*2x + 3*4 = 3x^2 + 6x +12\n\nNow add all of that together\n\nx^3 + 2x^2 + 4x + 3x^2 + 6x +12\n\nand combine terms\n\nx^3 + 5x^2 + 10x +12
1012196
3(x+12)=x+2\n3x+36 =x+2\n2x+36=2\n2x=34\nx= 17
944029
(x+2)/(x²-2) = (2)/(3-x)\nCross multiply\n(x+2)(3-x) = 2(x^2-2)\nSo -x² - x + 6 = 2x² -4\nSo 0 = 3x² + x - 10\n\nLooking for two numbers whose sum = +1 (ie b) and product = 3 * -10 = 30 (ie a*c) \nThese numbers are +6 and - 5\nSo + x = + 6x - 5x.\nSo 3x² + 6x - 5x - 10 = 0\n\n3x(x + 2) - 5( x + 2) = 0\n(3x - 5)(x + 2) = 0\nThus x = -2 or 5/3
1095585
The original equation:\n-2 ( x + 3 ) = 8\n\nMultiply the x and the 3 by -2:\n-2x - 6 = 8\n\nAdd 6 to both sides:\n-2x = 14\n\nDivide by -2:\nx = -7
879176
= x(x+3) + 4(x+3)\n= x^2 + 3x +4x + 12\n= x^2 +7x + 12
1138309
I hope you are trying to say x+2 = (2/3)(2x-1)..if it is correct then\n\n3(x+2) = 2(2x-1) --> 3x+6 = 4x - 2 --> 6+2 = 4x-3x --> 8 = x
705864
Alright, don't listen to the above post...\n\nGrade 12 here, answering questions all day for mere fun.\n\n12)\ny - 3 = -1/3 (x + 4)\n\nEXPLAINED\n\nadd 3 to both sides\ny = -1/3 (x + 4) + 3\n\nexpand 1/3(x + 4) \n= x * 1/3 + 4 * -1/3\n= x/3 + 4/3\ny = -1/3x - 4/3 + 3\n\nTo add -4/3 and 3, use 3 = 9/3\ny = -1/3x - 4/3 + 9/3\ny = -1/3x + 5/3\n\nTrue, my bad. I originally added 4/3 instread of -4/3\n\n\n16)\n(-2, -1) (4, -4)\n\nm = Dy / Dx\nm = ((-1) - (-4)) / ((-2) - (4))\nm = 3 / -6\nm = -1/2\n\ny = mx + b\n(-1) = -1/2(-2) + b\n-1 = 1 + b\n-1 - 1 = b\n-2 = b\n\ny = -1/2x - 2\n\nCHECK\ny = -1/2(4) - 2\ny = -2 - 2\ny = -4\nTherefore it works.\n\n18)\n(0, 0) (2, 3)\n\nm = Dy / Dx\nm = ((3) - (0)) / ((2) - (0))\nm = 3/2\n\nb = 0\n\ny = mx + b\ny = (3/2)x + 0\ny = (3/2)x\n\nNote, the lower post copied my answers
1047514
x^3 + 5x^2 - 8 divided by x -1 is:\n\nx^2 + 6x + 8\n\nor...\n(x + 2) (x + 4)\n\ndon't listen to byh. sorry I can't show you HOW to do the problem. I just couldn't figure out how to in type.
791629
If x = original number\nand\nR1= remainder of x/3\nR2= remainder of x/5\nR3= remainder of x/7\n\nThen  x = (R2 * 21) + (R3 * 15) - (R1 * 35)\n\nSo for your example of 26:\nR1 = 2\nR2 = 1\nR3 = 5\n\nX = (1 * 21) + (5 * 15) - (2 * 35)\n   = 21 + 75 - 70\n   = 26\n\nNotice how the remainder of one number relates to the multiple of the other two. Also, I think you need to start at 7 instead of 3, because there will be fractions and no remainders for the numbers less than 7.\n\nEDIT:\n\nIf you look at the formula again, you will see that it works for your example, also!  =)\n\nBe careful where you plug in your numbers; they aren't in order.
790277
ill give it a shot - im not sure , anyways i got 2 answers..\n\n(1st)\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6x = 2-4x\n\nx+4x+6x = 2+1\n\n11x = 3\n\nx = 3/11\n\n\n(2nd possible answer)\n\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6/x = 2-4/x\n\n-5 = -2/x\n\n-5x = -2\n\nx = -2+5\n\nx = 3
783870
7x^2+16x over (x-2)(x+2)(x+3)
1035131
i think you made an arithmetic error in the first step.\n\nstart with: |5x - 3| + 8 = 22\nthen subtract 8 from both sides, and you will get\n|5x-3| +8 - 8 = 22 - 8\n|5x-3|  = 14\nand not |5x - 3| = 24\n\nfrom there:\n|5x-3|  = 14\n5x-3 = 14 or 5x-3= -14\n5x-3+3=14+3  or 5x-3+3= -14+3\n5x = 17 or 5x = -11\nx = 17/5 or -11/5