A triangle has three verices A(11,1), B(3,6),and C(3,-4).  Which two angles of  the triangle ABC are congruent
456084
angle b and angle c.\nthey are both on the same line of the x- axis and collide at a central point with respect to A.
367069
Given: \n1) a right triangle\n2) hypotenuse = 2\n3) the other two angles are 70 and 20 degrees\n\nFind:\nLengths of the remaining sides\n\nNote: \nWe have to be more specific here.\n\nLet:\na = side opposite the 70 degree angle (side adj. 20 degrees)\nb = side opposite the 20 degree angle (side adj. 70 degrees)\nc = hypotenuse = 2\n\nSolution:\n\n1) For side a:\n\nsin 70 = opp./hyp. = a/c\nTherefore, a = csin70 = 2sin70 = 1.88 ANSWER\nOR\ncos 20 = adj./hyp. = a/c\nTherefore, a = ccos20 = 2cos20 = 1.88 ANSWER\n\n2) For side b:\n\ncos 70 = adj./hyp. = b/c\nTherefore, b = ccos70 = 2cos70 = 0.68 ANSWER\nOR\nsin 20 = opp./hyp. = b/c\nTherefore, b = csin20 = 2sin20 = 0.68 ANSWER\nOR\nPythagorean Theorem: a^2 + b^2 = c^2\nb^2 = c^2 - a^2\nb^2 = 2^2 - 1.88^2\nb^2 = 0.4656\nTherefore:\nb = 0.68 ANSWER
493884
In any quadrilateral the sum of the angles is 360 degrees.  Its an axiom that has been proven.  It's similar to the axiom that all angles in a triangle add up to 180.\n\nNote: the pattern is:\n3 angles = 180\n4 angles = 360\n5 angles = 540\n6 angles = 720\n7 angles = 900\netc.\n\nAnother fact about parallelograms is that the opposite sides have the same lengths and the opposite angles have the same measure.  This also means that two consecutive angles will add up to 180 (since the other pair must be equal and the total must be 360, as noted before).
673009
Not all triangles are congruent.
1131094
Conclusion: If two sides of a triangle are congruent then the third side is also congruent.\nFirst you would state the 2 bottom given statements. then the third will be the conclusion I gave you.\n\nYou could also use the SAS congruency to show that two triangles are congruent. If the triangles are congruent then BC is congruent to DF.\nTHERE IS ALSO THE CPCTC.
765889
1. All angles are equal\n2. All angles are less than 180° \n3. Size of each angle = (180 - 360/n)° where n = number of sides
588232
1.to create a triangle whose sum of the angles is more than 180 degree.\n2. making a triangle whose hypotneuse is the smallest side.\n3.making an equilateral triangle whose angles are more than 60 degree each.\n3.2intersecting lines perpendicular to 2 other intersecting line cant be parallel to each other.\nETC.....
1010584
Just think....\n\nA triangle (3 sides) always totals 180 degrees\nA quadrilateral (4 sides) always totals 360 degrees\nA pentagon (5) will total 540 degrees\n\nSo, the angles, A, will always equal 180 degrees per side, for each side (N) after the first 2.\n\nIn other words,   A = 180 * (N-2)\n\nif A is 32040, then 32040 = 180 * (N-2)\n\nN - 2 = 178\n\nN = 180
1114001
c = 108 degrees\nyou can find this since A + B + c = 180\nA=B+C+72\nThensubstitute to get A + A + A + 72 = 180\n3A + 72 = 180\nA = 36 so then C= 108
722736
the angles are just unknown if i get you correctly.\nthere are sin, cos, and tan proportions you can work out to find the rest. i think you only need three of the measurements to work out the rest of the triangle, like 2 sides and an angle or 2 angles and a side.  not positive.
986577
a) "Suppose Triangle ABC and Triangle DEF are congruent."\nb) "Suppose there exists a line segment with at least two right bisectors."\nc) "Suppose there is an isosceles triangle for which the angles opposite two of its congruent sides are not congruent."\nd) "Suppose there is a line segment with at least two midpoints."\ne) "Suppose there are two intersecting lines such that opposite angles are not congruent."\nf) "Suppose AB is not equal to CD."
107799
a right angle triangle can be complmentary and so can 2 acute triangles, these two can also be congruent.
980809
4 rules\n1.two sides and the included angles of the two triangles equal\n2.2 angles and a side of one triangle equal to 2 angles and a side of theothrtriangle\n3.3 sides of one equal tothe three sides of theother\n4.in 2 right angled triangles if the  hypotenuses and a side of each are equal
930936
Use the fact that the sum of the angles of a triangle add up to 180 degrees. Let A, B, C be the angles of the triangle. The m<A + m<B + m<C =180. If you know m<A and m<B, you can find m<C.\n\nWhen I write m<A, I mean the measure of angle A, not m is less than A.
833343
Let the triangle be ABC\n\nAB = BC\n\nso angle C = angle A (opposite angle of equal sides)\n\nAB = CA\nso angle C = angle B\n\nso all angles are same\nso equiangular
628857
Not a, since the congruent sides could be adjacent sides.\n\nNot b, because that would be a trapezoid.\n\nDefinitely c - there's a way to prove this using properties of parallel lines, interior angles, and triangles.\n\nMaybe d, since congruent diagonals means that your angles could be right angles, but it also could mean that you have an isosceles trapezoid.\n\nBisecting diagonals always means that your quadrilateral is a parallelogram.  Congruent diagonals can also yield a parallelogram, albeit a specialized one - a rectangle.  Now if you have diagonals that both bisect each other and are congruent, then you have a square.
914532
Let the trianglas be ABC & BCD\nAD forms 2 triangles, ABD & ACD\nAB=AC since ABC is isisceles\nBC+BD since BCD is isosceles.\nangle ABC=angle ACB\nangle DBC=angls DCB so angls ABD=angle ACD so ABD is congruent to ACD by SAS\n\ncall the point where AD crosses BC E\n\nso both vertex angles are bisected.\nlook at ABC.\nAE bisects BAC & AE is a commin side for BAE & CAE.\nsince AB=AC, the triangles are congruent by SAS\ntherefore BE=CE\n& angle AEB= angle AEC which are supplements so they must be right angles.\nQED