how do i rewrite the following without an exponent (8/9)^ -1?
467447
9/8\n\nRaising a nonzero number to the -1 power produces its reciprocal.\n\n    a^−1 = 1/a\n\nThus:\n\n    a^−n = (a^n)^−1 = 1/a^n\n\nRaising 0 to a negative power would imply division by 0, and so is undefined.\n\nA negative integer exponent can also be seen as repeated division by the base. Thus 3^−5 = 1 ÷ 3 ÷ 3 ÷ 3 ÷ 3 ÷ 3 = 1/243 = 1/3^5.
1137023
(2x-9)(2x+9)\n\na guess... its been a long time since I did that stuff
985807
Remember:  a negative exponent means an inverse.  So:\n\n(8x)^-3 = 64\n\n(8x)^3 = 1/64\n\n8x = 1/4\n\nx = 1/32
799160
(2^(1/2))(2^(1/4))(2^(1/8))(2^(1/16)...\n=2^(1/2 + 1/4 + 1/8 + 1/16 +...)\n=2^1
557964
Wouldn't it be something like:\n\n2x(8) + 8s     to get rid of the denominator\n\n16x + 8s\n\nThat is as far as I think you could simplify it, because each has different variables and you can't combine something with different variables.
131932
it cant but .99 repeating is equal 2 one!!!! o unless u do a number 2 the 0th power \nex. (5^0)+(2+2)
985516
(8x^4 + x^2 + 9)/x^4\n= 8x^4/x^4 + x^2 / x^4 + 9/x^4\n= 8 + 1/x^2 + 9/x^4 \nor 8 + x^-2 + 9x^-4
110508
(x^2+5) / (x^3+15-2x^2+1)^2\non [0,1]
197247
its impossible because there needs to be either one less sign or one more number look:\n\nin a the order:\n2 * 4 - 6 + 8 /\n              ^there is an extra sign!!
886343
1/9(x-1)^9 evaluated from 0 to 2.\n\n1/9(1)^9 - 1/9(-1)^9 = 1/9 + 1/9 = 2/9\n\nIf I didn't screw up.
889816
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
178588
Rearrange as (-7)(-11) m^(-6) m^(-4) u^(-4). Then combine the two coefficients into 77, and add exponents for the same base m, to get m^(-10). The final result is \n77 m^(-10) u^(-4). By the way, you should ask your teacher or consult the book to see if exponents should be made positive. In that case write the answer as 77 / [m^10 u^4].
358921
(9^9)!\n\ni.e. factorial of 9 to the power 9\n\n\n\n\n\n\n--- ► λ ◄
400429
10^9, or 1,000,000,000
352749
By the chain rule:\n[e^(3x^(2)-7x)]*(6x-7)
365902
(.8+.9)/(1+.8*.9)=.98837c
743387
Working above is good until this step:\n\n2 + 0.8x >0.9(x + 6)\n2 + 0.8x >0.9x + 5.4)\n0.1x > -3.4 ← Symbol error in this line\n\nShould read 0.1x < -3.4\nie x < -34