the transitions to level n=1 are called Lyman seried..?
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they are within the visble range;\nThe series of lines in the hydrogen spectrum associated with transitions to or from the first energy level or ground state. It lies in the ultraviolet (Lyman-alpha at 1215.67 Å; Lyman-beta at 1026 Å) with a series limit is at 912 Å. The He II Lyman lines have almost exactly one-quarter the wavelength of their hydrogen equivalent (He II Lyman-beta, 303.78 Å; He II Lyman limit, 227 Å.)
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http://submarine.dyndns.org/~tofu702/Science/Physics_Book/PhysicsBookFull.pdf\n\nInduced absorption and stimulated emission in the ground state of a three-level atom\nC Mavroyannis 1992 Quantum Opt. 4 145-150   doi:10.1088/0954-8998/4/3/001\n\n   \n     PDF (237 KB) | References | Articles citing this article \n  \n   \n\nC Mavroyannis\nSci. Inst. for Molecular Sci., Nat. Res. Council of Canada, Ottawa, Ont., Canada\nAbstract. Studies the competition between absorption and stimulated emission induced by two laser fields at low intensities interacting on a two-photon resonance with a three-level atom. The induced spectrum into the ground state consists of a peak whose height and asymmetry depend strongly on the detuning. The spectra arising from the emission of a laser photon by the excited state consists of two peaks describing stimulated emission and induced absorption, respectively, where the former dominates the latter for small values of the Rabi frequencies but for higher ones, they cancel each other out. \n\nPrint publication: Issue 3 (June 1992)\n\n\nPDF (237 KB) | References | Articles citing this article
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The first two columns (the H and  Be columns) have electrons in the s sublevel. The other tall columns (B to He) have electrons in the p sublevel. The transition elements all have electrons in the d sublevel, and the inner transitions have electrons in the f sublevel. Atomic size increases from left to right because the elements all have the same number of energy levels, but the number of protons are increasing. Therefore, the pull on the electrons is stronger, and the electrons are pulled in more, making the size of the atom smaller. The atomic size increases going down a group because the number of energy levels increases going down a group. Thus the electrons on those outer levels are not as affected by the protons' positive charge.
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You can use the Rydberg formula, which relates the reciprocal of the wavelength of the photon absorbed or emitted to the squares of the reciprocals of the principal quantum numbers.\n\n1/wavelength = R(1/n_l^2 - 1/n_u^2)\n\nSo, for the listed values of n, \n\nA.  1/w = R(1/ 2^2 - 1/4^2) = 0.1875R\nB.  1/w = -0.75R\nC.  1/w = 0.21R\nD.  1/w = -0.04861R\n\nSince energy and frequency are proportional to 1/wavelength,\nlooks like the order is D, A, C, B.
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The diagonal rule is a method for determining the order in which electrons fill sublevels of energy levels of atoms when doing electron configurations.
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"Somewhat stable" energy level. The length of time an electron can be expected to reside in a metastable energy level (lifetime) is much greater than the time it can be expected to reside in other excited states. The lifetime to a metastable state is typically 10-3 seconds while the lifetime for other excited states is typically 10-8 seconds.\n\nAnswer to second question can be found in the definition of a Laser. \n\nAn acronym of Light Amplification by Stimulated Emission of Radiation. A laser is a cavity that has mirrors at the ends and is filled with lasable material such as crystal, glass, liquid, gas, or dye. These materials must have atoms, ions, or molecules capable of being excited to a metastable state by light, electric discharge, or other stimulus. The transition from this metastable state back to the normal ground state is accompanied by the emission of photons that form a coherent beam.\n\nSo my take on it?  Metastable energy levels are required for electrons to emit photons,  and being that metastable energies are more stable than other excited levels, they are more useful in industrial applications.  So Lasers use this phenomenon to project a beam of photons that are still particles.
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Below are some links with some cool diagrams.  I'm not sure if it's specifically what you wanted though.  The second link has some really cool information about spectral transitions in a LASER.
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n = 1,2,.....\n l = 0, 1, 2..... n-1\nm = -l, -(l-1)\n\nThe labels  are called quantum numbers, and made their debut in Sommerfeld's elliptical orbit model. They correspond to certain classical features of the orbit: \n\nn= sr. root of (semi major axis)\nl = orbital angular momentum\nm = orientation of the orbit
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try these sites: http://www.phy.ornl.gov/astrophysics/data/cf88/\n\nhttp://www.llnl.gov/science_on_lasers/07AstSpace/AS-F_Ther.html\n\nhttp://arxiv.org/abs/astro-ph/9801028\n\nI hope this helps....\n\nDon
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The first energy level is the atoms ground state, electrons will not release any phtons from this level since they are stable at this point.\n\nJust because an electron is in thr 7th level does not mean that it will release 7 photons to return to its ground state.  The electron could release 7 photons and jump 1 level each time, that is possible, but not required.  It is also possible that the electron release just 1 photon carrying a lot of energy and jump down all 7 levels at once.  The number of energy levels the electron jumps down depends on the energy it releases in the photon, or vice-versa, the energy it releases in a photon determines how many levels it jumps down.
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Yes and no.\n\nIt is homogenous in a very large scale, but not so in a small scale.\nSmall equals to a few thousand light years.\n\nDont understand what u mean by level.\n\nTry to ask your question carefully\nLove to tell you, but dont know what you want.
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Vault - level 4 or 5\nFloor - level 4 or 5\nBeam - level 4 or 5\nWhat about bars? Hope I helped!
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for example:\n\nCl-1: has 18 electrons = 17+1\nif u are talking about simple configuration: then ok:\nelectron config: 2,8,8\n\nif u want the SPDF configuration: then:\n1s2 2s2 2p6 3s2 3p6
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See if this helps.\n\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/atomic/hund.html
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http://www.illc.uva.nl/dip/past-lectures/dip100904.pdf
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if we assume that the following reaction occured\n\nA(l)----->A(g)\n\n[that means no A is not a polymer in liquid phase, the only thing occured  is the evaporation],\n\ntry plot ln(P) against 1/T, most likely you will have a straight line and the slope is - delta H/R, please notice the sign.
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energy levels/orbitals