How do you solve a square root if it does not have one?
460425
The square root of 18 is not 6 it's 4.24264069\n\nThe square root of 36 is 6.
156166
that's easy.\nD=b^2-4ac\nx1= [-b-sqrt(D)]/2a\nx2= [-b+sqrt(D)]/2a\n-------------------\na,b,c are the coeficients (ax^2+bx+c=0) so a=1, b=3, c=-5;\nsqrt is square root
832801
Completing the square involves adding constants to both sides of your equation so you have a form:\n\n(x - a)^2 = b\n\nOnce you get this form, you can take the square root of both sides:\n\nx - a = sqrt(b)\n\nx = a + sqrt(b) \n\nSince a square root can be either positive or negative, it is just as correct to write:\n\nx = a - sqrt(b)\n\nNow, back to the original "perfect square"\n\n(x - a)^2 = b\n\nExpanding this out:\n\nx^2 - 2*a + a^2 = b\n\nMoving b to the other side:\n\nx^2 - 2*a + a^2 - b = 0\n\nYour equation is 2*x^2 - x - 2 = 0\n\nForst thing is to get plain x^2, so divide by 2:\n\nx^2 - (1/2) * x - 1 = 0\n\nNow from the form above, a = 1/.4 because 2*a = (1/2)*x\nNext, look at the constant term: \n \n-1 = a^2 - b\n-1 = (1/4)^2 - b\n\nSolving for b: b = 17/16\n\nSo your perfect square equation is:\n\n(x - 1/4)^2 = 17/16\n\nSolving for x:\n\nx - 1/4 = sqrt(17/16)\n\nx = 1/4 + sqrt(17/16)\nx = 1/4 - sqrt(17/16)\n\nSimplifying slightly:\n\nx = (1 + sqrt(17))/4\nx = (1 - sqrt(17))/4
1175507
square root of 2\n\nif 2 = x^(x^(x^...))\n\nthen 2 = x^ 2\n or x = √2\n\n[i hope you were truthful about the first answer gets the points....]\n\n\nI have an interesting follow up question however.  What if the quantity equals 4?  Then 4 = x^4 or x = 4^(1/4) = 2^(1/2) = √2 !!!  \n\nSo.. √2^(√2^(√2^(√2^...))) = 2 and √2^(√2^(√2^(√2^...))) = 4\nso...  2 = 4\nHow can this be??!!!!!\n(obviously its not.  where's the flaw?)
546400
D=square root ((x1-x2)^2 + (y1-y2)^2)
597652
The square root of 1 is 1.\nsqrt(6.6) = 2.569\nsqrt(15) = 3.873
670743
There is no square root of -1.
701990
Okay, this is corny, but say you were arranging a number of something on a table, and you wanted to make a square. You would take the square root of however many you have, and then you would know how many to put in the first row, and you could just line up each column after that to match. Or, if you wanted to stack them in a cube, you would take the cube root.
89471
idk wat the square root is.... the square root of a negative is not a negative though... a negative times a negative is a positive.... also, this is the 4th ? i have answered of urs
801012
inverse square root of a number say"x" is\nx^[-(1/2)]
1152199
It doesn't have a square root. A square root has to be an exact number (no decimals). Because it means that it is whatever that number is squared. ex: 100=10^2(10 squared). If it's a decimal number that goes on forever, it's impossible to square it because it's kinda infinite.
596727
Figure out what other number times itself equals your number.  That's its square root.
412542
x = -b +(or)- sqrt(b^2 - 4ac)\n    -------------------------\n               2a
583216
you can't add the two. If the numbers under the radical are different they can't be added. You can use a calculator and find the decimal answers and add those, or just leave it as an addition problem.\n\nTo prove it, the square root of two is about  1.414, the square root of six is about 2.449. the sum is 3.863, however the square root of 8 is 2.828, so they aren't equal.\n\nIt's not possible to have the exact form because they can't be added. It's simplified as the equation root two + root 6
283638
sqrt(25)=5 or -5. To verify it:\n\n5*5=25 checks\n-5*-5=25 checks\n\nboth work.\n\nan important thing to remember while square-rooting a number is that the root can be both positive or negative, as two negatives multiply up to a positive.
1147786
x - sqrt(x) = 0\nx = sqrt(x)\nx^2 = x\nx(x-1) = 0\nx = 0,1\n\nBoth check.
709225
Finding the square root\n\nClick on the URL below for additional information concerning finding the roots without a caculator\n\nwww.nist.gov/dads/HTML/squareRoot.html \n\nwww.homeschoolmath.net/teaching/square-root-algorithm.php \n\n- - - - - - -s-