Synthesis of hydroxamates?
473805
take a carboxylic acid and couple under normal conditions with an O-alkylated/acylated hydroxylamine.\n\nBy normal conditions, I mean normal peptide coupling conditions usined EDC, DIC/HOBt, CDI, PyBOP, PyBrOP, TBTU etc etc etc
717741
I'll talk through it, since I can't draw structures.  Presumably, this is an acid catalyzed process.  The first step is protonation of the oxygen on acetone.  This creates a more electrophilic carbonyl.  One of the hydroxyls of the starting material will attack the carbonyl carbon, generating a hemiacetal.  Protonation of the hydroxyl of this hemiacetal, followed by elimination of water with assistance from the lone pairs on the neighboring oxygen will generate an oxonium ion suited for another nucleophilic attack by the other hydroxyl of the hydrobenzoin.  A final proton transfer will generate the acetal.
835717
Hmmm.. I'm not trying to be stingy, but I still prefer using Yahoo! Answer since that there is a bunch of good chemist in this community, to asking for a help from there.\n\n\npeace\nvixklen
688017
2-hexanol. Look at the link, I think this is what you want.
555664
The formula could be (C6H12OH)n, in which case it could be synthesised from the corresponding aldehyde. Expensiveness depends on how much and how pure of a product you want.
771931
Starting material:\nCH3CH2CHBrCH2Br ?\n\nProduct wanted:\nCH3CH2CH2CH=CHCH3 ?  Cis or Trans?\n\nIf the starting material is 1,2 Dibromobutane, then treating it with base (eg. NaNH2) will give:\n\n CH3CH2CHBr–CH2Br   +   base   ——>  CH3CH2CH=CHBr   +   base   ——>  CH3CH2C≡CH\n\nIf this is done with excess NaNH2 in liquid ammonia or dry diethyl ether, then the sodium salt will be produced:\n\n(CH3CH2C≡C)- Na+\n\n(CH3CH2C≡C)- Na+ + BrCH2CH3  ——>  CH3CH2C≡CCH2CH3 \n\nCH3CH2C≡CCH2CH3 when heated gives the more stable compound CH3CH2CH2C≡CCH3  (this is 2-hexyne).  The path will be different from here depending on if you want a cis or trans product.  A controlled catalytic addition (Lindlar catalyst) of H2 will give the Cis form.  Na in liquid ammonia will give the Trans.\n\nThere might be an easier way, but this path is a classic.
488364
Chemexper.com its super cool , type in the name of the compound and it will give you a ton of info about the thing you are looking at. I order chemicals off of it but it was really useful in researching for my Ochem labs as well.
24037
Synthesis of Two Potential Inhibitors of para-Aminobenzoic Acid Synthase.
96717
See link\n\nhttp://chemistry.about.com/cs/howtos/ht/buildavolcano.htm
1176089
http://www.akrochem.com/pdfs/sulfenamides/X-BBTS.pdf\n\nWeb search BBTS and butyl for more information
283215
[Cu(NH3)4]SO4*H2O (s) + 2HCl(aq) --->\n\nCu(NH3)4 +2 (aq) + H2SO4(aq) + H2O(l) + 2Cl-(aq)
817601
try the local chemist....
564230
This is a selective way to produce cupper of cupper hydroxides by leaching hydroxide and elecrtowinnig as:\nCu(OH)2(s) = Cu+2(aq) + 2 OH–(aq) \nCu+2(aq) + 4 NH3(aq) = Cu(NH3)4+2(aq)\n\nand [Cu(NH3)4]2+ is better agent than [Cu(H2O)6]2+ in (aq) solutions for this.
750030
1. Iron (III) Hydroxide\n2. Ammonium Iodide\n3. Aluminum Hydroxide\n4. Sodium Carbonate\nThis site also has many others and is a great place to confirm your answers!\nhttp://www.quia.com/jg/125193list.html\nGood luck!
341863
ammonium nitrate and aluminum hydroxide\n\nNH4NO3 + Al(OH)3\n\nThe aluminum hydroxide is insoluble when formed and will precipitate out of the solution as a solid powder.
561728
Grignard Synthesis of Benzoic Acid\n\n\nPreparation:  McMurry, sections 10.8 and 20.6.\n\nConversion of an organic halide into a Grignard reagent completely transforms the reactive character of the organic compound. Carbon bears partial positive charge when bonded to halogen but partial negative charge when the carbon is bonded to magnesium. The Grignard reagent is a very reactive nucleophile and base. \n\nIn this experiment you will make the Grignard reagent phenyl magnesium bromide; this reagent will then be treated with carbon dioxide to form benzoic acid. The sequence (Equation I) is explained in McMurry Sect 20.6.\n\n\nAs in any work, this experiment may not succeed the first time; be prepared to repeat it from the beginning. On the second try, you should be able to work much more efficiently and with more understanding. \n\n\nProcedure: Obtain a 150 mm piece of magnesium ribbon. Hold one end with forceps and with the other hand remove the residue on the ribbon by scraping it with a spatula, scissors or pliers to obtain a shiny surface. Cut at least 0.12 g of the shiny ribbon into 2-3 mm pieces (do not handle the pieces) and place on a folded piece of paper to obtain the mass on the balance. Transfer the magnesium pieces to the 5 mL conical vial, add the dry spin vane, add one small crystal of iodine and add 300 µL (0.3 mL) of anhydrous ether. Be prepared to add more ether as necessary to maintain the liquid level at a minimum of 300 µL.\n\nAssemble the rest of the apparatus as in Mayo, et al., Fig 3.24. Clamp the apparatus firmly to a stand.\n\nIn the hood, prepare a solution of 510 µL of bromobenzene in 700 µL of anhydrous ether in the 3 mL vial using the delivery pipettes provided. Cap this vial with a polyethylene top. \n\n(*Note:  Be certain the dry ice is ready before you initiate the reaction below.)\n\nDraw half of the bromobenzene solution into the syringe and insert the needle through the polyethylene cap in the Claisen head as in the figure. While stirring the mixture below, add 6-8 drops of the bromobenzene solution. Evidence of reaction is the formation of tiny bubbles. When the reaction has started, add the remainder of the bromobenzene solution slowly over 3-5 min. The temperature should be maintained at about 40 oC to allow gentle refluxing (Mayo, et al., p. 29) of the ether. To the 3 mL vial add an extra 300 µL of ether, then transfer this to the reaction via the syringe. Adjust the total volume to 3 mL with the addition of more anhydrous ether. Reflux the mixture for 10 minutes, then allow the gray-brown solution of the Grignard reagent to cool to room temperature. What do you observe?\n\nThe Dry Ice (at least 1.0 g) is added in small chunks to the Grignard solution. Note the reaction as this is added. To convert the C6H5C(=O)-OMgBr, to benzoic acid (last step, Equation I), use a pipet to VERY SLOWLY add 1 mL of 6 N HCl and again observe the result. Test the aqueous layer with pH paper; it should be acidic. Remove the ether by gently heating the vial for 5 minutes on the steam bath. Cap the vial, mark it and set it in your drawer until the next laboratory period. \n\nPreparation for the 2nd laboratory period:  The benzoic acid has been synthesized, but it must be purified. Water soluble magnesium salts are removed by extracting away the water layer; but, a number of organic side products remain with the benzoic acid.  These are side products of the Grignard reaction; small amounts of benzene are formed (Equation II), unreacted bromobenzene remains, and biphenyl, H5C6-C6H5, is formed from the reaction (Equation III). \n\nThe benzoic acid can be isolated from this mixture by taking advantage of its property as an acid. Only it can dissolve in aqueous NaOH (Equation IV) while the side products remain in the ether. After the ether-soluble side products have been removed, strong acid is again added to reverse this reaction in order to restore the benzoic acid.\n\nRecrystallization of the crude product in
814611
CdSo4+NH4OH ---->Cd(OH)2 + (NH4)2SO4