I'm really confused about capacitors:?
457025
they discharge when there is no longer anything charging them. they charge because a voltage is put across them, which causes charges to collect on opposite sides. when the voltage is removed (or short cicuited) there is nothing forcing the opposite charges to opposite sides. the capacitor discharges because opposites attract, and these opposite charges are now free to cancel each other out.
532394
I have seen this problem with motherboard that had the capacitors across the power supply inputs go bad. Other possibilities are overheated processor, overloaded power supply, & misconfigured power schemes.
38072
because the capacitor impedence = 1/ jwc ... for the dc current .. the frequency is equal to zero .. and w = 2(bi)f ... > w=0 .. the impedence = 1/0 = infinity ... so it's considered as an open circuit for DC
969011
You might care to explain what some of the letters are, not all of them have much to do with electronics.\n\nR I guess here is resistance, but what of l m x and s?  Is l for inductance (I think not here), what of s? seconds?\n\nSome of these (all ?) are simpley equations (eg: c=q/E solve for E) would apply whatever C, ! and E stood for.\n\nIn this case if you gave C an arbitar value or 2, Q an arbitrary value of 6 ad E an arbitary value of 3, you would see that C (2) = q (6) / E (2).   So E would be Q/C\n\nThis is usually the I=v/r fourmal where I=current, v=voltage and r=resistance. R=v/I is also the same but the other way around. V=IR is valid also.\n\ny=mx+b?  what electrical formla is that? Again it is easy to solve but I can see nothing to with electronics here. Again try assigning sinple numbers to the letters so that the equation works - then you can re-arrange the sum so it still works:\n\nGive m, x and b a different value: 3, 4+ 5\n\nNow 3*4 +5  = 17\nso Y=17.\n\nNow you can play about with re-arranging your sum:   \n\n5 = 17   -    3 * 4 \n\n5 represents b, 17 represents Y, 3 represents m and 4 represents x\n\nSo swapping numbers for letters:    b=y-mx
644653
I thought a capacitor stored up charge in a dc circuit.  If it was ac then it would be charging and discharging 50 times a second - so it could not store a charge, but the current just switches through albeit in alternating directions..
475454
he discovered the capacitor and defined capacitance.\nhe gave the formula.\nCHARGE(Q)=C(capactiance)* voltage(v)\nthe unit for measuring capacitance of a capacitor is FARAD.\ncapacitor is a linear component that stores charge.\nit consist of two metal plates separated by a dielectric material eg->glass,mica,fibre..etc,\n\ncapacitance of a capacitor is 1 farad if it can store a charge of  1 coloumb when i volt of current flows through it.
810481
First make sure the capacitor is discharged.( Connect a large screwdriver across the terminals of the capacitor).\nUsing an analog ohmmeter set to the 100K or 1000K scale,connect its leads across the capacitor, the ohmmeter needle should make a fast movement upscale and, after a very short time, should start moving slowly downscale toward the "0" value.This shows a good capacitor.Hope this help.
569885
This is a good time to learn dimensional analysis.  It will come in handy for all of your physics courses.\n\nFirst, µ x M cancels one another leaving ohms x Farads\n\nOhm = volt/amp\n\ncharge = capacitance x voltage  so capacitance = coluomb/voltage\n\nOhm x Farad = volt/amp X coulomb/volt\n\nso the volt cancels leaving \n\nOhm x Farad = coulomb/amp\n\nAmp = coulomb/sec\n\nOhm x Farad = coulomb/(coulomb/sec)\n\n= (coulomb/1) x (sec/coulomb) = sec\n\nBy the way, Tau = RC is the timeconstant of an RC type circuit.. you remember for a cap charging it is I = V/R[exp (-t/RC)  RC is in units of time = sec\n\nI used to have to do this stuff all the time in my undergrad physics courses.
612300
how basic??\nthere're about a million books on basic electronics..\nyou talking about engineering level basics?\nor layman basics?\nin any case.. check out wikipedia.org.. might help
119135
10mH is 10 milli-Henries.  A Henry is a measure of inductance, and is defined as L=di/dt.  Inductors resist changes in current flow.  You have to use calculus to get the equation for an RL (resistor-inductor) circuit, which is what you have.  You are subjecting an RL system to a step input of 10 V from a "voltage source."  See the more technical, long-winded explanation of inductance.\n\nThe second site actually shows you an animated plot of the exact ciruit you are interested in.  \n\nAs a note of interest, large iron core inductors were developed for power supply filters in Vacuum Tube radios and amplifiers.  They had huge inductances of 7H or more.  These days, everything is in microhenries or millihenries because the frequencies in today's electronic systems have gone past 1 gigahertz.  Inductors can act as frequency-dependent resistors.  \n\nThese days, one hugely popular use of an inductor is to store energy in a magnetic field for switching power supplies in conjunction with electrolytic capacitors and FET modulated drives.  Wound 60Hz transformers are quite expensive, large, and heat producing.  The days of linear power supplies with large iron core transformers have given way to tiny circuits with driving transistors, an inductor, and some capacitors.  Switching supplies running at 125kHz or more can use transformers with ferrite (powdered iron) cores and far fewer windings.  The higher frequency packs much more energy than a 60Hz electrical source.\n\nAs a point of interest, try to find an old computer power supply which should be very easy to get.  Open it up.  Look at the parts, and you will see a high frequency transformer, inductors, capacitors, and drive transistors with modulating chips.  The 120VAC from the wall is put through 4 diode rectifiers to make 169V DC with some high voltage capacitors.  This voltage is made available to be switched at relatively high freqencies into a powdered core transformer primary.  The Secondary makes high frequency AC voltage which is rectified and filtered with capacitors and/or inductors.  A voltage detector circuit, usually isolated from the high voltage DC side by an optical isolator, tells the modulating chip what the load is.  The modulator will then vary the duty cycle of the transistors at a constant frequency to move more power across the transformer.  Have fun with electronics!  I love it...
1035397
Polarized capacitors are useful for single direction systems. The gate only opens one way and the lead is always singular in its transfer of power. Because of this the power is at full when it crosses the board and the Resistance is must be manipulated to make sure the power does not overload the system. As an example, most of the older laser systems worked off a polarized capacitor, when activated the capacitor discharged and all the power drained to a single pole. Thus the laser would fire in one burst until the entire capacitor was discharged. \n\nNon-polarized or dual gated systems are omni directional and therefore omni systemic. Meaning the power flow can be multi directional, however because of the multi directional flow the power is decreased more quickly and dispersed over a wider area. Thus it cannot be as useful due to resistance across the board. However non-polarized capacitors work well within the atmosphere of amplifiers, and other more commercially accepted applications. However remember that all capacitors take time to recharge, and must be fully discharged before they can be recharged. Damage could occur when attempting to ram charge any kind of capacitor.
969269
Whether or not a motor needs a capacitor depends on the type of motor. There are at least 5 or 6 different types of single phase motor, some requiring capacitors, some not (pf correction aside).\n\nIt is likely that the device wired to the motor in the dishwasher is required where ever you use it. It is also usual for start capacitors to be mounted on the side of the motor but may not always be the case. A capacitor is normally cylindrical and will have a value in micro farad.\n\nTake a look at the link below and see if any of the options on it resemble what you have.\nhttp://www.tcf.com/TCFBlower/pdfs/engr_data/ED1100.pdf\n\nThey don't mention another type that is often used in domestic appliances but is clear to identify by the fact it has brushes and commutator, this type would not normally need any separate control\n\nI have even found a dc motor in a standard washing machine, obviously a dc motor requires some other circuitry to use on the mains. I don't know how common this would be to find since I don't take apart too many domestic appliances.
922607
You must have a wire not plugged in properly. Tighten them up. If you went by the book everything should be ok.
1174183
my advice is not to fiddle with the inside of that box... if you touch the capacitor, it will likely kill you... just buy a new one... when i got a replacement, it ran me $50..
1164919
you need to describe what you mean by "small" better.\nis it too small vertically, horizontally, or both?\nAlso, how good is your electronics background?\nDo you know how to discharge the CRT and large capacitors so you don't get zapped with 330 to 10,000 volts while attempting to repair it?\nYou also need to define "wavy" better.\nWith the tin amount of information you have given though, it sounds like the power supply is failing, but in which part is impossible to say.
797208
Not the easiest thing to explain via email but the best way to start is to understand clearly the function of the symbols shown in diagram. Once you understand what each item does find a starting point - usually the power supply and walk through it. ANother way is to get the corresponding termination diagram. I find them much easier to understand.
324170
the 20 ohm is shorted because the current can go through the switch without going through the reisistor. when it is closed, R =10+1 =11, V =3, Current = V/R = 3/11 amps\n\nbecause direct current cannot cross a capacitor, which is in cd. this is because a capacicotr is plates which are parallel and do not touch. obviously, if the plates do not touch, electricity cannot flow through them. alternating current can go through a capacitor, only because the capacitor keeps discharging