What is 1 + 2 + 3 + 4 &#92; 2 x 100?
467350
500 if the division is for all four numbers \nor \n800 if the division is for four only.
720251
(a+b)^100 \n= a^100 + 100C1*a^99*b + 100C2*a^98*b^2 + ....... + b^100\n\n(a-b)^100\n= a^100 - 100C1*a^99*b + 100C2*a^98*b^2 - ....... + b^100\n\nTherefore (a+b)^100 + (a-b)^100 = \n2*[a^100 + 100C2*a^98*b^2 + 100C4*a^96*b^4 + ..... + b^100]\n\nClearly there are 51 terms in total irrespective of the values of 'a' and 'b'. [Here a = 8, b = 2*sqrt(5)]
131443
4! + 4! + 4! + 4! + 4
175474
1+2+3+4+5+6+7+8+9+10+..........+....
1093659
Or is it this:\n300+20+4\n400+60+7\n100+10+1\n800+90\n60+8\n1000+600+50+4
208112
use the order of operations, so first the multiplcation. so\n\n2 + 2 - 3 + 96/2\n\nThen divide by two\n\n2 + 2 - 3 + 48\n\nAdd the twos\n\n4 - 3 + 48\n\nSubtract\n\n1 + 48\n\nAdd and get\n\n49
987327
Find a number X such that  2X = (X/2) + 99\n\nmultiply both sides by 2 to get  4X = X + 198\nsubtract X from both sides to get 3X = 198\ndivide both sides by 3 to get X = 66\n\ncheck work\n2*66 = 132\n66/2 + 99 = 132
95089
1(1)+0(2)+1(4)+1(8)+1(16)+0(32)+0(64)+0(128)+1(256)=\n1+0+4+8+16+0+0+0+256=\n285
8373
(([(4+4+4).(4+4)]+4)/4)*(4+4)\n\n(4+(4*4)).([(4+4+4).(4+4)]+4)
315642
4\n\n1 + 1 + 1 + 1= 4
369170
same as everywhere\n1+1=2\n2+2=4
358099
0.43 & 0.0062\n\nDivide by 100
61276
100101111\nThat is:\n256+32+8+4+2+1
204914
I only need four 0.\nbinary:0!+0!+0!+0!=100
779437
(3,261 + 5) + (20 X 10) + (220 X 5)\n(3,266) + (200) + (1,100) = 4,566
127502
Several ways:\n\n(9 / 9) + 99 = 100\n99 / .99 = 100\n(9 / .9) * (9 / .9) = 100 \n\nhttp://www.iit.edu/~smart/acadyear/puzzles.htm
1126193
11,000 + 1,100 + 11.\n\n12,111.