Find the GCF of each set of monomials 12, 90?
460136
Actually the best way to find greatest common factor is to prime factorize. \n\nThe prime factorization of 12 is:\n2^2 x 3\n\nThe prime factorization of 90 is: \n2 x 3^2 x 5\n\nThe most shared numbers in each of those prime factorizations is one 2 and one 3. \n\nMultiply these two numbers:\n\n2x3=6\n\n6 is the greatest common factor.
627684
C=5/9(F-32)\nF=(9/5)C +32
872177
Coefficients are:  1  1  3
852407
To show your work, you list the factors of 3 and 9. Then find the greatest factor they both have in common.\n\n3: 1, 3\n9: 1, 3, 9\n\nThe GCF (Greatest Common Factor) is 3. Both 3 and 9 have 3 as a factor and it's greater than any other factors.
1150392
No problem, i just finished a calc3 course in college.\n\nYour problem is the same as 125 * (6x^2 + 5x + 7)^(-1/3)\nYou have to use the chain rule so you get\n125 * (-1/3) * (12x + 5) * (6x^2 +5x + 7)^(-4/3)\n\nthen you can simplify how you like from there
917618
Since you're dividing two monomials with the same base (x), you subtract the exponents so the answer is x^6. \n\nHope this helps ;-)
777032
Since there are too many numbers to list, here's a program to do it for you:\nhttp://wims.unice.fr/wims/en_tool~algebra~factor.html
92952
(8x+3)(4x+3)\n32x2+24x+24x+9\n32x2+48x+9
25946
=3fg*(f^2g)+3fg*5f-3fg*4\n=3(f^(1+2g))*g+15(f^2)g-12fg
742127
= (x^12)/12 - (8x^11)/11 + (5x^10)/2 - (10x^9)/3 - (15x^8)/4 + 24x^7 - 49x^6 + 60x^5 - (195x^4)/4 + (80x^3)/3 - (19x^2)/2 + 2x + C
14639
Assuming your first statement is correct, then\nA. g(c) = c/231\n\nIf c = 231, g(c)=1,\nIf c = 462, g(c)=2,\netc.
276464
(1x12)+(2x11)+(3x10)+(4x9)+\n(5x8)+(6x7)+(7x6)+(8x5)+\n(9x4)+(10x3)+(11x2)+(12x1)\n=12+22+30+36+40+42+42+\n40+36+30+22+12=364\n\n\n364 gifts
1123203
You can multiply and divide them easier.\n\nfifth root of 2x times 2x^20\n           -or-\n2x^(1/5) times 2x^20
902613
I just plugged this into my calculator.\n\n[1, 0, 2, 0, 2, 0 | 0\n0, 1, -3, 0, -2, 0 | 0\n0, 0, 0, 1, -1, 0 | 0\n0, 0, 0, 0, 0, 1 | 0\n0, 0, 0, 0, 0, 0 | 1 ]\n\nTake it however you want.
57233
4100\n\nbut most people while adding they calculate 90 as 900 and give the result as 5000!!!!
386935
42 = 2 * 3 * 7\n60 = 2 * 2 * 3 * 5\n\nSo, the GCF consists of the common ones, which are 2 * 3 = 6.
439000
Since you cannot factor any binomial to form a monomial, the only factoring you can do is by "common monomial factoring". After that, cancel like factors, but if there are no common factors, that means you cannot factor it anymore.\nExample:\n\n(3x - 3)/(2x - 2)\nyou can get common monomial factors for each:\n3(x - 1)/2(x - 1)\ncancel the common factors\n3/2\n\n(4x² - 6x)/(2x + 10)\n= 2x(2x - 3)/2(x + 5)\n= x(2x - 3)/(x + 5)\n\n(x + 3)/(x + 5)\n---> this cannot be simplified anymore\n\n^_^