how to split a long string to substrings?
465084
string alpha="AAAABBBBAAAA"\n\nstring one=alpha.substring(0,4)\nstring b=alpha.substring(4,4)\nstring three=alpha.substring(8,4)\n\ni hav used substring which is valid in java,c,c++,visual basic,c#.
790123
$input = "I went to the park today and it suddenly";\n$input = trim( $input ); // trim whitespace\n\nif ( strlen( $input ) > 39 )\n{\n  $input = substr( $input, 0, 36 );\n  $input .= '...';\n}
226715
The short answer is you can't.  The long answer (below) is a work around.\n\nYou can't actually convert from long to short and back again.  There are a fixed number (often 255) of possible symbols (letters digits punctuation etc) in most characters.\n\nIf you try to compress the string, usually some data has to be lost.  Some techniques like hoffman coding can help a bit, but not much in your case.  You might find a way to store 10 or 12 characters but not much more.\n\nLong answer.\nCreate a table of the long strings with an 8 character key field.  Store the key field in the database instead of the long string.  When you need to display the long string, you look up the 8 character key in your table to find the matching, original string.
220856
Try winrar and execute the command WIZARD in Tools menu... and specify the blocj's size in which the want to split your file.
923590
If it's a standard .sql file, you should be able to split it. This would break transactions, but depending on the statements in the file this may not be an issue.
522101
void RemoveWhiteSpaces(char *string) {\nchar * bch;\nchar newstr[80];\n// Get the first whitespace\nbch = strtok (string,' ');\n\nwhile (*bch != '&#92;0')\n{\n  if(string != ' ') {\n   strcat(newstr,bch);\n  }\n  *bch++;\n}\n\nreturn 0;\n}\n\n\nI guess, I am not gonna give you the hwole answer, maybe I did :) But here it is, hope you the best.. Some stuff need work
137760
Object\n\n1) enclose it in braces\nString [] apple = {"a", "b", "c"};\n\n2) read it into what?  Array?  ArrayList?  I can do it in four lines...\nString line;\nBufferedReader br = new BufferedReader(new FileReader("build.xml"));\nwhile ((line = br.readLine()) != null) {/*do something here*/}\nbr.close();\n\n3) string.replace\nString banana = "This'is'a'test";\nSystem.out.println(banana.replace("'", ""));\n\n(In case that's hard to read - the method is "replace" openparin doublequote singlequote doublequote comma doublequote doublequote closeparin)
76546
How about using the char array that is the input string, converting to uppercase, then using the chars as indexes into your substitution array of chars? Use the ASCII table to help you.\n\nchar subst_array[] = {'Z', 'Y', 'X', ...};\n\nconversion to uppercase: if (char > 90) char -= 32;\n\nfor (i = 0; i < strlen(input_string); i++)\n  input_string[i] = subst_array[input_string[i] - 65];\n\ncout << input_string;
419166
under linux or cygwin use the split command.\n\nRoxio CD software will handle it for you. \n   search help under split or size to find more about it.
540992
HOW LONG IS A LENGHT OF STRING?
10333
Use Filter and Label. You can set them to be sorted automatically by Subject, From, To, Has the words, Doesn't have, but not by Size
363476
There's not enough information, what type of list, I don't think you mean an Enumerated List, and into what type of split, are you talking about linked lists, or something like indexing using trees to navigate or manage keys?
103786
You could do something like:\n\n\nDim captionString As String\nDim numEntries As Integer\nDim ctr As Integer\nnumEntries = 0\n\nFor ctr = 1 to Len(txt.text)\n    If (Mid(txt.Text, ctr, 1) = "a") Then\n        If (numEntries > 0) Then\n            captionString = captionString & ","\n        End If\n        captionString = captionString & ctr\n        numEntries = numEntries + 1\n    End If\nNext ctr\nLabel1.Caption = captionString\n\nThe idea is that everything inside the For...Next loop is done at each position of the string, and so you build up the string to put in the caption of Label1.
860018
first, yahoooooo answers does not handle long lines of code, I had to view source, then extract \nSystem.out.println( testtring.replaceAll( \n     "href&#92;&#92;s*?=&#92;&#92;s*?&#92;";(.*?)&#92;",\n     "$1"));\n\nbefore I realized you shouldn't be using replaceall at all! you want to match not replace.
129786
var fileName =\nlocation.pathname.substring (location.pathname.lastIndexOf ('/')+1)\nalert(fileName);
424535
your getting a user input for first and last name seperated by a space. use the strtok() function to extract the strings on either side of the space. then print it in the format you want.
928881
how longs a bit of string