What is the difference between the mean and the average?
469807
nothing, mean is just a different word for average.  the median and mode have different meanings though.  the median is the number right in the middle of all the data, the range is the lowest number to the higest number in the data, and the mode is the number that occurs most often.\n\n"bradsgranny" down there is COMPLETEY wrong, the MODE, like i said, is the number that occurs most often, not the mean...people should check their sources before they write something that is entirely WRONG.
374019
Sorry your answer was wrong.\nMean can be less than median also as median is not affected by extreme numbers at its both ends while mean is.\n\ne.g. find mean and median of following data.\n     1, 3, 5, 9, 18, 180\n\nhere your answer for mean will come to\n               36\n\nwhile if you find median for it then it will come to\n            7\n\nIn this example mean was greater than median.\n\ne.g. -180, 18, 5, 3, 1, 9\nhere your mean is -24\n\nwhile your median is 4.\n\nSo from both example you can say that\n\nnone of them is always greater than other one nor it is always smaller than other one.
557393
No. A mean is an average, so the only time the maximum velocity would equal the mean velocity is if the velocity was constant (unchanging).
800575
There are three averages, you need two, the mode+median, the other one is the mean.  \n\nThe median is the middle of the data, so just arrange the data in order from least to greatest and cross out ones from either side one by one, but you're left with two in the middle, just take the average of 9 and 15, you get 12, which is your median.  \n\nThe mode is the value that appears most in a set of data, in the first set 9 appears the most, thrice, so it's the mode.  \n\nIn the second set no number appears more frequently than the others so there is no mode.  \n\nHope this helps!!
704942
Range is the highest minus the lowest number of your data (in the above example, 15 -1 = 14 would be the range)\nThe mean is the average of all your data\nTo find the median yo have to order all the numbers and the central one is the median, for example, 1 4 5 6 6 7 8 9 11 12 15\n7 is the median because is in the middle.\nThe mode is the one that repeats the most in the serie, in the same example 6 would be the mode...\nThere are some formulas for more complex set of data, if you need them let me know..
107133
You have all the information you need.\n\nThe Mean is the same as the average. It's just another term for a simple average. So it's $7500\n\nThe standard error of the mean is the standard deviation divided by the square root of the number of samples. So it's just $650 divided by 10, or 65.
935926
It means that there is a large gap in the middle of the data set with one or a small ammount of entries being grossly larger than the majority of the set:\n   the set 1,2,3,4,30 has a mean of 8 and a median of 3\n   the set 20,22,28,32,33,34,64,68,71 has a mean of 49 and \n   a median of 33
926282
on average, what was the question
360360
The average value of a function is given by\n\n(1/(b-a)) S f(x) dx, evaluated from a to b.\n\nSo for this question, the average will be given by\n\n(1/(4-0)) S 8+4e^-2t+te^-2t dt = (1/4)[8t - 2e^(-2t) + S te^-2t dt]\n\nLet u = e^(-t)\ndu =  -e^(-t) dt\n\nSo, S te^-2t dt = - S u^2 du\n= (-u^3)/3\n= -e^(-3t)/3\n\nSo your answer then becomes\n\n(1/4)[8t - 2e^(-2t) - e^(-3t)/3] = 2t - (1/2)e^(-2t) - e^(-3t)/12\n\nEvaluating from 0 to 4,\n= 2(4) - (1/2)e^(-2(4)) - e^(-3(4))/12 - [2(0) - (1/2)e^(-2(0)) - e^(-3(0))/12]\n= 8 - (1/2)e^(-8) - e^(-12)/12 + 1/2 + 1/12\n= 8 5/12 - (1/2)e^(-8) - e^(-12)/12\n~ $8.42
122943
Yes. What you're talking about is the adjustment of the MEDIAN (definition below). Because "good" and "bad" are relative ("good" is simply BETTER than what "isn't good") but "normal" is what is average, your expectation for what normal days are will rise when you experience a lot of good days. When you encounter what USED to be a "normal" day, it is now "not as good as the current normal day" and therefore bad. Confused? Good.
866043
Standard deviation is a measure of the "spread" or range of values in a collection of data.   Two sets of data can have the same average value, yet be very different in nature.  If most of the values are close to the average "deviating" only a little from that, the standard deviation is small.  If many values are very different from the average, the standard deviation is large.  If you were to take a sample from a collection of data, it is more likely to be near the average in value if the standard deviation of that collection is small.\n\nFor a more technical explanation and specific formulas see http://en.wikipedia.org/wiki/Standard_deviation
820283
To find the median you must first put your data in order from least to greatest.  The median is the number that appears in the middle.  If for some reason you have two pieces of data in the middle you find the mean of those two numbers.\n\nSlope is (y2 - y1)/(x2 - x1)
655920
The standard deviation is the square root of the variance. Now, the variance is the "average squared difference (distance) of each observation from the mean".\n \nLets think about it. You want a measure of how dispersed the data is, right? Well, suppose you have heights for your data and your trying to compare two groups. For example, you want to know if the height´s of New Yorkers vary more or less than the heights of Floridians. You are NOT trying to see which are taller.\n \nSo you can calculate the average height of each group and then see haw far away from this average each individual height is and then calculate the average distance from the average height. If everyone had the same height, the average distance would be ZERO, reflecting that the population´s height is very CONCENTRATED around its average.\n \nBut why do you use the squared difference? Because if you were to calculate the average of "x - average(x)" you would always get zero, so by squaring and taking the square, you always get a positive number (the distance is always positive).\n \nGot it?
74440
The Mean is the average.  You have 22 numbers; add them up and divide by two to get the mean.  In this case, that gives 87.38\n\nThe median is the "middle" value.  Since you have 22 numbers, 11 of them will be below the median, and 11 will be above.  In your case, the 11th biggest number is 87.9 and the 12th biggest number is 88.  The median could be anything in between, but is generally taken to be the average of these two- or 87.95\n\nThe mode is the most common value.  In your case, each value occurs only once, except for 91.7 which occurs twice.  Therfore, 91.7 is the mode\n\nUpper and lower quartiles are similar to the median; The lower quartile is the value below which 1/4 of your values lie, and the upper quartile is the value above which 1/4 of your values lie.  Since you have 22 numbers, the lower quartile is the value between the 5th and 6th largest numbers (82 and 83.6), and the upper quartile is the value between the 17th and 18th largest numbers (92.9 and 94.2).  That makes 82.8 and 93.55\n\nThe range is the minimum value to the maximum value, or {68 to 98.2}\n\nTo get the variance, first subtract the mean from each value.  Then, take the square of each of these new values.  Then, add up all these squares.  Finally, divide this sum by the number of values (22 in your case).  This should give a variance of 51.22 with your numbers.\nNOTE:  The above formula is for "population variance", and is generally used when your numbers represent an entire population.  If your numbers represent a sample of a population, you should use the "Sample Variance", which has the same formula except that you divide by the number of values minus one (21 in your case).  With your numbers, this should give a sample variance of 53.66.\n\nThe standard deviation is just the square root of the variance.  Like the variance, there is a "population standard deviation" (7.16 in your case) and a "sample standard deviation" (7.33 in your case)
187632
The relative average deviation is the average deviation divided by the average of the measurements....lol\n\nIf that doesn't help much, check out the link below.\n\nMatt
824818
OK, here goes:\n\nThe data could be\n7 9 10 12 12 13 14\n\nThe median (center number) is 12\nThe mode (most repeated number) is 12\nThe mean (average) is 11.\n\nThe point is that you need to look at all three measures to get a good idea of the data.\n\nHere's another set:\n1 3 10 12 12 19 20\nThis has the same measurements.\n\nIt is only when we look at things like the variance and std deviation that we can really see the difference between those two data sets.\n\nGood luck!
957340
The answer is C.\n\nHowever, do you know how to get the answer?\n\nThe mean is the average of all of the numbers. Add the four numbers you gave me and divide by 4. That is how you get your number. This is what teachers use to find your average for your school grade.\n\nSorry, im studying to be a teacher, I wanted to make sure you understood.