between what 2 consecutive integers is the square root of 432 and how do i figure it out?
458909
You can goto http://www.math.com 's square root calculator and figure out that it is about 20.78 so since an integer is a decimal-less number the answer would be between 20 and 21.\n\nShort of using the sqrt function of a calculator if you know that 20 squared is 400 and that is close to 43 you might then try squaring 21 and get 441 then realize 432's sqrt must be between 20 and 21.
107941
64(sqrt7*sqrt5)/4*sqrt7\n(64/4=16 and sqrt7 is cancelled)\ntherefore, the answer is 16*sqrt5
925404
OK, let's see.\n\nIt's an arithmetic sequence, so the difference between consecutive terms is a constant.  The first term is 1, so we can express each term as:\n\nx(i) = 1 + k*(i-1), i = 1, 2, 3, ....\n\nNext the problem says that the 2nd, 10th, and 34th terms are the first three terms in a geometric sequence.  That means that the ratio of the 10th term to the 2nd term must be the same as the ratio of the 34th term to the 10th, because when you divide any two terms of a geometric sequence, you get the same constant.\n\ni(2) = 1 + 1*k\ni(10) = 1 + 9*k\ni(34) = 1 + 33*k\n\nSo we said i(10)/i(2) must equal i(34)/i(10):\n\n1+9k    1+33k\n-------- = --------\n1+1k      1+9k\n\nCross multiplying: (1+9k)^2 = (1+1k)(1+33k).\n\nThen 1 + 18k + 81k^2 = 1 + 34k + 33k^2.\n\nPutting it all on the left side, 48k^2 - 16k = 0, or 16k(3k - 1) = 0.\n\nSo either k = 0 (not interesting) or k = 1/3.\n\nTherefore the arithmetic sequence must be:\n\n1, 1 1/3, 1 2/3, 2, 2 1/3, 2 2/3, 3, 3 1/3, ....\n\nThe second term is 1 1/3.  The 10th term is 4 (1 + 3 * 1/3).  The 34th term is 12 (1 + 33 * 1/3).  So the geometric progression would be:\n\n4/3, 4, 12, 48, 192, .....
537920
It's rough, but what I would do is find the difference between the two routes on either side of the number (Wait for the example!)  and count until you get to it, then make a fraction. \n\nEXAMPLE:\nfind square root of 2.\n\n2 is between 1 and 4.\n\nit's 1 past 4 and there are 3 numbers between the two.  So root 2 is approxamately 1 1/3.  The 1 is from the first number between one and 4, and the 3 is because there's 3 numbers between 1 and 4.  It's confusing, and it's not a good estimate, but it works if you understand it.
1135721
Consecutive numbers just means that they follow one right after the other, like 7, 8, 9. etc.\nConsecutive odd numbers 9, 11, 13, etc.\nIf your first odd number is n, then to get to the next odd number you have to add 2 to it, so it is n + 2, the next odd number after that is (n + 2) + 2 or n + 4, etc.\n\nSo, for your question n + (n + 2) = 48\n                                        2n + 2 = 48\n                                               2n = 46\n                                                 n = 23\nIf n = 23, then n + 2 = 25.\nThe numbers are 23 and 25.
105888
square root(pi) = 1.77245385
302292
There's no solution.\n\nIf you're evil, you could argue that 102 - 78 is an answer ;)\n\nEDIT : Confirmed no solution with Telraam (http://members.chello.nl/g.de.blaauw/telraam.html). Allowing square roots gives (8*(2+.10))/.7 as a potential answer.
770326
If you are allowed to head into the realm of complex/imaginary numbers, you could factor out a sqrt(-1) and replace it with a lowercase i.\n\nsqrt(-24) = sqrt(4) x sqrt(6) x sqrt(-1)\nsqrt(-24) = ± 2 sqrt(6) i
54004
11\n\n\n11 multiplied by 11 equals 121. So, the square root of 121 is 11.
1060817
Square Root:\n\nSQRT(1839472)=1356.271\n\nSQRT(75639)=275.0255\n\nSum:\n\nSQRT(1839472) + SQRT(75639)\n\n= 1631.2964 (ans)
243752
Well, the definition of a square root has been explained pretty well.  The square root of 4 is 2.  sqrt(9)=3.  sqrt(2)=sqrt(2).  This is in simplist form becuase you cannot write sqrt(2) in a finite decimal expansion.\nHow to Simplify:\n\nConsider sqrt(99).\n99=11*9.\nso, sqrt(99)=sqrt(11*9)=sqrt(11)*sqrt(9)=sqrt(11)*3\nThe steps to follow are as described:\n1) try to break down the number being considered into its prime factors.  In this case: 11,3,3\n2)  look at those factors.  Are any of them perfect squares?  In our case, 9 is 3*3.\n3)  Use this property: sqrt(a*b)=sqrt(a)*sqrt(b) to break thye original number up into an irreducible number and a perfect square if possible.\n\nSome notes:\nThis is not possible if the number does not reduced to perfect squares.  For example: 143=11*13 neither of which are perfect squares so we are stuck here and sqrt(143) is in simplist form.  Hope this helps.
747566
-1.4172^2=\n\n-1.4172 times -1.4172.\n\nA negative times a negative is always positive, so you just multiply them together to get a positive value.  When you do so, you get a number a little larger than 2.  The square root of two (the number that, when multiplied by itself, equals 2) is about 1.414.... Your number is slightly larger, so the answer will be slightly larger than 2.\n\nHope this helps.
942253
the answer is -3x square root of 2
992834
u r probably working on order of operations, this might help:\nPlease (parantheses)\nExcuse (exponents)\nMy  (multiplication)\nDear (division)\nAunt (addition)\nSally (subtraction)\n\n1. 7000 x 400000 = 2800000000\n2.  1/144 = x^2 so x = +/- 1/12\n3.  -3 +/- the square root of 2\n4.  5t^4 - 7t^3 + 6t -2\n5.  4x^4 - 16x^2 +16
981873
-7 and -sqrt49\n\nYou can not take a square root of a negative number. Well, you can, but it's called an imaginary number because it can't actually exist.
180491
two consecutive even integers are 2n and 2n+2\n(2n)^2 + (2n+2)^2 = 100\n4n^2 + 4n^2 + 8n + 4 =100\n8n^2+8n=96\nn^2 + n = 12\nn^2 +n -12 = 0\nn = [-1+-sqrt(1+48)]/2 = [-1+-7]/2= -4 or 3\n\nIf n=3 then numbers are 2n = 6 and 2n+2= 6+2= 8\n6 and 8.\n\nIf n= -4\nThen 2n = -8 and 2n+2= -8+2= -6\n\n-6 and -8.
634605
Mathematicians have designated a special number 'i' which is equal to the square root of minus 1. Then, it follows that i2 = -1. To determine the square root of a negative number (-16 for example), take the square root of the absolute value of the number (square root of 16 = 4) and then multiply it by 'i'. So, the square root of -16 is 4i.\nAs a double check, we can square 4i (4*4 = 16 and i*i =-1), producing -16.\nAll negative square roots are called "imaginary numbers" (now you know where that letter 'i' comes from).