basic Math with LOGIC........?
463098
Think as follows.\n\n1 is 5^1 = 5\n\n2 is 5^2 = 25\n\n3 is 5^3 = 125\n\n4 is 5^4 = 625\n\nSee the pattern?, For the nth row is 5^n.\n\nHence, for what you wanted,\n\n5 is 5^5 = 3125\n\nAnd buddy, I always think before answering... :)\n\nRegards
70409
Go back to math class and figure it out!
467967
this is probably not a perfect answer but this site may give you some clues.\n\nhttp://www.gomath.com/Questions/question.php?question=4751\n\naltrnatively type 'prove v*v = 2gr*r/s+v0*v0-2gr' into a search engine and see what comes up.
95441
math with a bunch of letters and numbers
328795
1 + 1 = whatever you want to make.
733649
(4)/(x+7) + (x+3)/(x+7)\n=(4 + (x+3))/(x+7)\n=(4 + x + 3)/(x+7)\n=( x +7)/(x+7)\n=1
987327
Find a number X such that  2X = (X/2) + 99\n\nmultiply both sides by 2 to get  4X = X + 198\nsubtract X from both sides to get 3X = 198\ndivide both sides by 3 to get X = 66\n\ncheck work\n2*66 = 132\n66/2 + 99 = 132
868541
the truth about this is find the right formula for this equasion, then set it with ur need of what space you put it in to example : =sum(a1:a28)
684946
find whole (integer) number a,b, and c such that a^3+b^3=c^3.\nDon't remember the answer anymore,but it should be easy - all numbers were less that 10.
961595
umm..are you missing an equals sign somewhere or am i really dumb? how do you figure out what x is unless you have both sides of the equation?
530853
So where's that starting point?  Either we start (yesterday) with Mary having $785.63 we subtract $57. and $125. for 603.63.  Then we add $57.25 for a total of 660.88 (B) \nOR\nwe start we $785.63 (today) anb subtract $57. and $125 for $603.63 (C).  The $57.25 doesn't matter cause Mary did that yesterday....
751280
multiplication\n\n\nDoug
495947
i am intrigued by your idea of LOGIC!!! interesting
863581
You have a couple of typos, I think.  As for the "proof", dividing by x - y is dividing by zero.  That is a no-no.  (In other words, a * 0 = b * 0 does not imply a = b.)
214223
I can explain this with simple mathematics..\nLet the number u choose be 'x'.\nNow double the'x' and adding 12 gives us:\n2x + 12.\nDividing this expression by 2 gives us:\nx + 6.\nSubect the no. u thought i.e. 'x' from this and what u get is 6.\nAm I correct Ma'am?
501730
Try http://www.asic-world.com/digital/boolean.html for a beginning.  I would start with basic boolean math.  That often will help you simplify a large logic circuit down to something you can build.
732332
1/(1*2) = 1/2\n1/(1*2) + 1/(2*3) = 1/2 + 1/6 = 2/3\n1/(1*2) + .... + 1/(3*4) = 2/3 + 1/12 = 3/4\n\nA pattern is starting to appear eh??\n\nLets see:\n\n1/(1*2) + .... + 1/(4*5) = 3/4 + 1/20 = 4/5 Yesssssssssssss!!\n\nSo I suggest that 1/(1*2) + 1/(2*3) + ..... + 1/(99*100) = 99/100\n\n(See also Scott's formal proof above\n\nHe has based it on the fact that 1/[(n - 1)n] = 1/(n - 1) - 1/n\n\nie 1/4*5 = 1/4 - 1/5)