12 people come to u`r home, u have 1 bagel how can u cut the bagel in to 12 Pisces u can only cut it 3 times??
465409
keep it together, cut it in half, the stack the halves.  then cut it twice.  you will have 3 stacks of 4
929308
take a knife and cut 4 times thru the circle and u end up with 8 pie wedges...then line the wedges up-----<<<<<<<<------like that and cut thru on the dashed line, the fifth cut, giving u 16 wedges...not very mathematical but it works
1176573
21\nLets do this problem in reverse order.\nAfter giving 1/3 to her brother she is left with 6.\nThat means she has 2/3 of what she had.\nthat means she had 3*6/2 = 9 raisins before she gave it to her brother.\nNow add one she ate. So 10.\nNow she gave half to her sister that means she had 20.\nAdd 1 which she ate before that... so 21.
937250
PROBLEM 1:\nBobby is 3 years old.  His sister Nancy is four more than six times as old as Bobby.  How old is Nancy?\n\nPROBLEM 2:\nThe pizza parlor cuts large pizzas into 6 slices and small pizzas into 4 slices.  If Ryan buys 3 large pizzas and a small pizza, how many total slices will he have?\n\nPROBLEM 3:\nThere are 3 hexagons and a square drawn on a piece of paper.  How many total sides are there?\n\nPROBLEM 4:\nWhat is the base-10 equivalent of 34 base-6?\n\nPROBLEM 5:\nAdult tickets are $6 each and child tickets are $4 each.  How much will it cost for a family of 3 adults and 1 child?
577048
depends you take away 3 and give it to whom? if to u keep it to urself then you have 5...if you eat the 3 then you have two...if you take the three away and leave the two you have 3...now im confused!
106335
81 because you take the first number of them both first you take the 8 and put it in front and then you take the 1 and you put them together and what do you have 81! (please pick me it took me forever to write that out.)
1152243
I think it's 16 because of the math involved, you cut 16 in half and get 8, cut that in half you get 4, cut that in half and get 2, then a final winner.  Try doing that with 15 or 18
1046122
They are in a star formation.\n\n--------*\n *----*---*----*\n----*-------*\n--------*\n--*-----------*\n\nFive lines can be formed, with four people in each line.
993677
Well, if we consider that a pie is a 3 dimensional object we could first take 2 lines (cuts) perpendicular through the center on the top of the pie to cut it into 4 slices.  From there we could move to the side if the pie and cut evenly through it horizontally thus cutting each of the 4 pieces into a top and a bottom piece.  4 x 2 = 8.  I want dibs on the top 4 pieces...someone else can have the bottom mostly crust pieces!!  :-p
512917
13!8!/20!\n\nyour group sizes r, 2 4 6 8\n\nwithout any restriction of who goes together, u have this many choices: 20C2*18C4*14C6----A\n\nwith restriction of 7 ppl must goes together, u have this many choices: 13*12C6*6C4-----B\n\nThe prob of getting 7 ppl in a group is A/B. u do the algebra and u will get 13!8!/20!\n\n\nreasoning:\nfor 7 ppl to be in a group, the group must take at least 7 person. there is only one group that can do so. Taking the 7 ppl as one entity that must be allocated together, u have only left with 14 objects/persons to arrange. After the group for 8 take the group of 7 ppl, it can still take one and it has 13 choices from the remaining people.\n\nafter choosing the group of 8, u r left with 12 ppl to pick for the group of 6, 4 and 2 and the number of choices are, 12C6*6C4*2C2\n\nso, the total number of possibility would be 1*13*12C6*6C4*2C2.\n\n\n\n\n\n\n"....with restriction of 7 ppl must goes together, u have this many choices: 13*12C6*6C4-----B....."\n\nthis is because, in the special case of that 7 particulat person must be in a group, u group them together to form one. so, how, u only have 14 objects to allocate to groups. get it? since group of 7 can only go into the group that can fit 8 person... so, it's possibility is 1.\n\nAfter that, since the group of 8 has been filled up by the 7 person, u have one place in it left, and 13 ppl to choose from to fill it. hence, 13.\n\nthen, for the remaining of the task, u simply choose out of 12 people for your 6, 4, and 2 men groups.\n\n\n\nso, u have 1x13x12C6x6C4x2C2 to forming THIS(with 7 particular person in one group) type of group.\n\nthe prob(forming THIS group)=(number of way to form THIS type of group)/(number of way to form ANY type of group)\n\nget it?\n\n\n\n\nI'm glad u really wanna know. most ppl got the answer and they r satisfied. too bad i m not good at explaining. contact me if u need more help.\n\n\n\n\n\n\noh, sorry. u misunderstood me. yes, u r perfectly right. there r 13 ppl left after u allocate the 7 ppl to the "8" group. What i was saying was... b4 u do that, u have 14 "person".... one of them being a group of 7 people. sorry for confusing u. And from what u said, yes, u got the idea right.
519523
try cutting it up into squares and triangles
277836
multiply together the number of different possible combinations.  As the guy above me said, there are four times of toppings times the number of cheese choices times the weight of meat times the bun choices times anything else you can think of.
964273
If you number the tpopping from 1 to 8, you can have the following combinations of different toppings (numbered for simplicity):\n1) 1, 2, 3\n2) 1, 2, 4\n3) 1, 2, 5\n4) 1, 2, 6\n5) 1, 2, 7\n6) 1, 2, 8\n7) 1, 3, 4\n8) 1, 3, 5\n9) 1, 3, 6\n10) 1, 3, 7\n11) 1, 3, 8\n12) 1, 4, 5\n13) 1, 4, 6\n14) 1, 4, 7\n15) 1, 4, 8\n16) 1, 5, 6\n17) 1, 5, 7\n18) 1, 5, 8\n19) 1, 6, 7\n20) 1, 6, 8\n21) 1, 7, 8\n22) 2, 3, 4\n23) 2, 3, 5\n24) 2, 3, 6\n25) 2, 3, 7\n26) 2, 3, 8\n27) 2, 4, 5\n28) 2, 4, 6\n29) 2, 4, 7\n30) 2, 4, 8\n31) 2, 5, 6\n32) 2, 5, 7\n33) 2, 5, 8\n34) 2, 6, 7\n35) 2, 6, 8\n36) 2, 7, 8\n37) 3, 4, 5\n38) 3, 4, 6\n39) 3, 4, 7\n40) 3, 4, 8\n41) 3, 5, 6\n42) 3, 5, 7\n43) 3, 5, 8\n44) 3, 6, 7\n45) 3, 6, 8\n46) 3, 7, 8\n47) 4, 5, 6\n48) 4, 5, 7\n49) 4, 5, 8\n50) 4, 6, 7\n51) 4, 6, 8\n52) 4, 7, 8\n53) 5, 6, 7\n54) 5, 6, 8\n55) 5, 7, 8\n56) 6, 7, 8\n\nThis means that there are 56 different topping combinations. Since there are 3 types of pizza, 168 (which is 56 * 3) is the number of different pizzas you can choose from here.\n\nAnswer: 168 different pizza type and topping posibilities.
450313
10 percoset should do the trick\nThis is a joke....just in case you are dumb enough to try it.lol
545283
there are two groups of 2 people , so take those 2 people as 1 unit. so there are total 8 units.\nthus number of ways to be arranged is 8! , that is 40320.
22496
only 14\n\nthe last one need not to be cut.
821077
once we chose 5 persons for one committe then other committe members get fixed.\n\nThe 5 members can be chosen in 10C5 ways = 10*9*8*7*6/120\nor 6*7*6 or 252 ways