how do you use four eights to get 100?
457868
It's possible to get 100 using even THREE eights!\nAnd this is in DECIMAL, not binary base!\n\n100 = -log_8 (log_8 (sqrt(sqrt(...sqrt(8))))),\n\nwhere log_8 is logarithm in base 8\nand the number of square roots is 300.\n\nLet's prove it.\n\nA = sqrt(sqrt(...sqrt(8))) {300 roots} =\n= ((8^(1/2))^(1/2))...^(1/2) {300 powers} =\n= 8^(1/2 * 1/2 * ... * 1/2) {300 multiples} = \n= 8^(1/8 * 1/8 * ... * 1/8) {100 multiples} = \n= 8^(1/(8^100)) =\n= 8^(8^(-100)).\n\nlog_8 (A) =\n= log_8 8^(8^(-100)) =\n= 8^(-100).\n\nlog_8 (log_8 (A)) =\n= log_8 8^(-100) =\n= -100.\n\nHence, -log_8 (log_8 (sqrt(sqrt(...sqrt(8))))) = 100.\n\nQED\n\nYou can use forth eigth, for example, to change every one 8 in that formula to sqrt(8*8).
364224
multiply the numerators (top numbers) together put that number on top, multiply the denomonators (bottom) together, put that number on the bottom---   5/8 times 4/7 is 20/56
975052
888 + 88 + 8 + 8 + 8 = 1000\nThat's eight eights.
345970
Ok, I got it.  I recommend writing the numbers 1-12 and crossing them out as you use them.\n\nYou've got your 5,6,1,and 8 on the inside.  So on the upper row of four, 5+6=11, so you need 15 more to make 26.  The only numbers that are left where 2 add up to 15 are 12&3 or 11&4.  I tried 11&4 first and will just tell you it didn't work, so it's 12&3.  Now to decide which goes where.  If you put the 3 on the left, it lines up with the 1 making 4, and there's no other numbers that will add up to the required 22 - so 12 must go on the left and 3 on the right.\n\nNow you can see the line  from the bottom point up to the 3.  8+3=11, so you need 15 again, and the only choices left are the 11&4.  Put the 11 at the bottom point and the 4 between the 8&3.\n\nNow looking at the line that goes from 12 down to the 11 you have 12+1+11=24, so you must use the 2 here.  Now you have 7,9 & 10 left.\n\nLooking at the line with the 5&2, that makes 7, so you need 19.  The only way to get that is with the 10 & 9, but you don't know which goes where.  You DO know, though, that the only other point that is left gets the 7.  That's the bottom right point.\n\nThis made a line with 7,6,4 and the very top point.  7+6+4=17, so you need 9 at the top to make 26, which leaves the space for the 10 at the bottom left.\n\nIn order, from top to bottom/left to right you have\n\n9\n12,5,6,3\n2,4\n10,1,8,7\n11
317578
a warm up? as in ask u questions? i can do that. but the main way to do this is to multiply. as in if youre doing 98/7, then do the multiples of 7 until you get to 98, so do 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98     and then count the number.\n\nor if its more than 10x7, (70) then subtract 70 from it and count. so 98-70 = 28. and 28/7 = 4. and then answer is 10+4. you could also do this with 5x7, cuz those are easy numbers to do it with. \nso for an example, if you were doing like 174/3, first you could do 10x3 = 30, and then count out the multiples of 30 until it gets higher than 174.\nso 30, 60, 90, 120, 150 so that means if 3*50 = 150. if u subtract 150, you get 24. then do 24/3 and add it to 50. so its 8. so then 174/3 =58. and the multiples of 30 are just the multiples of 3, with a 0 added on the end. if the numbers are even bigger, than do multiples of 300, 3000 etc.\nso now questions for u to do\n\n1. 108/12\n2. 77/11\n3. 84/7\n4. 54/9\n5. 39/3\n6. 26/2\n7. 84/3\n8. 65/5\n9. 84/4\n10. 48/8\n\nhope this helps. laterz
974959
set a goal  time you want to run the 100 in and divide that buy 2 and pratice the 50 in that time or less and then run 200  and do the same work on starting blocks and form out of the blocks good luck
729543
-24+w+8=4\n-24+24+w+8-8=4+24-8\nw=20\n\nhope this helps!
611894
8 to 3  (56 to 21 and divide by 7)
183810
If the domain is [100,999], you have 999-100+1=900 numbers to try.  If you divide a number by both 7 and 8, you can simply divide the number by 7*8=56 instead (I'm not sure if I can explain why this might be true.)  Basically, this means you have a 1/56 chance of a number having a remainder of 4 for both 7 and 8. 900 * 1/56 = 16.071, but since you can't have a part of a number that is a match, you can round that off to 16.
1079568
Find the least common multiple for 4 and 8.  It is 8.\nMultiply everything by 8\n8(10x) - 8(1/4) = 8(9x) + 8(3/8)\n80x - 2 = 72x + 3\nSubtract 72 x from each side\n8x - 2 = 3\nAdd 2 to each side\n8x = 5\nDivide each side by 8\nx = 5/8
1174474
DIVIDE IT BY 100 TIMES THAT BY 20 AND THEN ADD THAT ONTO 12,590
996363
by add 888+88+8+8+8 =1000 got it
951171
Add them... 8+7+7+5+3+2+2= 34 and divided by 7\nYyou have 34/7=\nYou know 4x7= 28 so you need 6 more to reach 34\nso you have 4 and 6/7
1092560
888+ 88+ 8+ 8+ 8 = 1000\nComplete answer-\n1) [(8+8)/8] * [(8* 8* 8)- 8] - 8 = 1000\n\n2) (8888-888) / 8 = 1000 \n\n3) 8 [(8*8) + (8*8)] -8 -8 -8
572405
This is the way you find them all\n100 = 1 x 100 = 2 x 50 = 4 x 25 = 5 x 20 = 10 x 10\nFind yourself the dividers of 360 and 300.
376319
Are you able to use any other numbers and operators?  If so this would be fairly easy.  Using only Three 8's and a subtraction symbol it is not possibe\n\nClosest example (8+8)/8-1=1
584205
put 80 over 50 and set it equal to x/100\n\nx shoudl equal 160\n\ntherefore 160%