What is the equation for equipment cost and equipment capacity?
469887
for generators , we choose like this , if the load is 1 MW , then we choose two of 60-75% each , according to budget and power failure problems , also the life time for a machine to be considered for 12 yrs , 8-10% depreciation yearly
735262
1.  The key here is to understand how far the two trains have traveled in total during the first 3 hours.  We are told that the two trains started 500 miles apart, and 3 hours later are now 80 miles apart.  Thus they traveled 420 miles in total. \n\nIf you let x represent the rate of speed that the Freight train is traveling, and x+20 represent the rate of speed that the Passenger train is traveling, you can set the following algebric equation:\n\n3 hrs * x mi/hr  + 3 hrs * ( 20 + x ) mi/hr = 420\n 3x + 60 + 3x = 420\n6x = 360\nx =60 mi/hr.\nx+20 = 80 mi/hr.\n\n2.  The key is too figure out the total number of employees needed to break even.  Regardless of how many employees you have, we are told that it costs $2000 per day to run the factory.  In addition to that  we are told that for each employee, we must pay him or her $300.  These are the total costs for the operation.\n\nOn the other hand, we are told that each employee can produce $500 in revenue each day.\n\nThus, we need to create an algebric equation where the total costs = the total revenue\n\nLet x represent the number of workers, and set up the following algebric equation:\n\nCosts = Revenue\n\n$2000 (Fixed Costs) + $300 * x (Variable Costs) = $500 * x\n\n2000 + 300x = 500x\n2000 = 200x\n10 = x\n\nYou will need 10 workers to break even, and the total gross value of ball bearings produced will be 10 * $500 or $5000.\n\nHope that I have cleared things up for you!
710153
Usually psi (pounds per square inch).\n\nAloha
1006215
Use the formula d = rt (distance = rate * time)\n\n1) Train A: d = 40t\n\n2) Train B: d = 60(t - 1)  [left an hour later]\n\nthe answer is when the two distances are the same, so we set the two equations equal to each other\n\n40t = 60(t - 1)\n40t = 60t - 60\n60 = 20t\n3 = t   [3 hours]\n\nPut this result back into equation 1\n\nd = 40 * 3 = 120\n\nAnd we expect the same result in equation 2\n\nd = 60(3 - 1) = 60 * 2 = 120\n\nI provide this level of detail in case you need this level of help.
442883
alot of the areas are with the main distributers and equipment retailers.  you can go to any of the equipment web sites and they have tons of info you can get.
925743
This is pretty straightforward.\nFirst you have to write the formula fo rthe cost of the tank as a function of, say, its radius, r:\n\nThe volume of the cylinder is 100 cubic feet.\nIt is also pi*r^2 times the height, h\n\nso let's solve for h\n100=pi*r^2*h\nh = 100/(pi*r^2)\n\nnext, the cost:\nthe rectangle cost is 2.40*(h*2*pi*r),\nor 2.4*100/(pi*r^2)*2*pi*r\nor, simplifying, 480/r\nThe cost of the base and top are:\n1.50*2 pieces * pi*r^2\n\nSo the total cost is\n480/r+3*pi*r^2\n\nNow you need to differentiate this and find the roots, and make sure they are minima, not maxima!
476534
management is not only mathematics , it is also experience and knowledge .\nwhen you want to know the cost of your product , you have to use mathematics to calculate the manpower cost , machines cost and material cost .\nin the same time you have to give a price can make a competition with other companies and takes  costumer satisfaction .
309325
Since m*C*dT=Q;\n\nHeat capacity=135000 J/(5100 g*(31.5K - 18K))= 1.96 J/gK\n\n(K for Kelvin)
983451
I would suggest you check out the yellow pages for Houston, TX; Tulsa, OK you will find several manufacturers for heat exchangers, pressure vessels, tanks, heaters and pumps.\n\nAssuming you have sufficient definition of each item in terms of size, capacity, surface area, working pressure, materials of construction you should be able to get estimates of just about any piece of equipment you will need.\n\nI do not wish to discourage you but, if you don't have a process flow diagram with a heat and material balance for the plant you are going to have a very hard time developing a cost estimate using major equipment cost.
903174
An estimate of what what cost?
673977
Great question.\n\nLet S be the number of small gears produced, and L be the number of large gears.\n\nWe want to maximize\n\n25S + 10L \n\nsubject to the constraints.\n\nThe constraints are\n\n4S + L <= 24\nS + L <= 9\n\n5 small gears, 4 large gears, maximum profit $165.
1017997
The equations are wrongor insufficient. Post the correct data if you want me to help/ Alternately, you could also message me.
690047
do a GOOGLE or YAHOO search for what you've just asked ... I'm sure there is a company that has loaded this manual onto the internet but my guess is there would be a fee ...
1044477
the smaller tank is 900L and the bigger tank is 1200L\n\nTank 1 = T\nTank 2 = T+300\n\n(2/3) T = (1/2) (T+300)\n(2/3) T = (1/2) T + 150\n(4/6) T = (3/6) T + 150\n(1/6) T = 150\nT = 900
1089687
Try this calculator, you can answer any question like that
885631
Let us assume that we rent out x videos.\nTherefore, for the first video shop, the cost is 15+2.5x.\nFor the second video shop, the cost is 5+3x.\n\nLet us equate them so that the cost becomes equal.\n15+2.5x=5+3x.\n.5x=10\nx=20\nTherefore, you need to rent more than 20 videos from the first shop to make it more economical.
956051
it depends on the cost of the work being done