simply tell me , what speed is this planet of ours traveling in orbit around the sun, i assume we are travelli
465183
Earth's speed changes from time to time.  The average is 29.783 kilometers/second or 107,218 kilometers/hour.
128891
Are you on the same planet as us?
537517
The speed at which the earth spins varies upon your latitudinal location on the planet. If you're standing at the north pole, the speed is almost zero but at the equator, where the circumference of the earth is greatest, the speed is about 1,038 miles per hour (1,670 kph). The mid-latitudes of the U.S. and Europe speed along at 700 to 900 mph (1125 to 1450 kph).
982746
It rotates around its axis every 23 hours and 56 minutes. The circumference of the equator is 40,075 km. That means the equator is moving at a speed of 1674 km/h. The atmosphere moves with the ground, which is why we're not blasted into space by 1000 mph winds.\n\nIt revolves around the Sun every 365.24 days ata radius of about 150 million kilometres. That makes its orbital speed 108,000 km/h.
406821
Dan's result seems extremely low and the reason is that when he converted metres to inches he divided instead of multiplying so his final answer needs to be multiplied by about 1600.\n\nI don't think the earth's rotational speed around its own axis is relevant. I am unclear which Dan has taken, this or the earth's orbital speed around the sun.\n\nIf the radius of the Earth's orbit is 93 million miles, then the circumference of the orbit (assuming a circle for simplicity) is 2 pi r or 6.28 x 93 x 10^6 miles. In a fortnight (14 days out of 365) the earth will travel 14/ 365 ths of that distance (ignoring leap years for simplicity) and with 8 furlongs to a mile, that is\n\n8 x 14/365 x 6,28 x 93 x 10^6 f per f\n\nFor an approximate result, say 93 divides into 365 4 times, and divide the 4 into the 8 to leave\n\n28 x 6,28 x 10^6 furlongs per fortnight\n\n= approx 1.75 x 10^8 furlongs/fortnight\n\nOf course the sun itself is moving at about ten miles a second in the direction of Alpha Herculis, but that too is irrelevant to the calculation as is the rotational velocity of the earth on its own axis.
1085566
The earth's approx circumference at equator is 24,800 miles.  It takes about one day for it to spin around once.  So, at the equator one would be zipping right along at approx 1,000mph.  It gets slower the further north or south of the equator you go since the "circle" of latitudes gets smaller.  So, do we move fast? We do, but since we are part of the gravity well created by the earth, its spin is our frame of reference and relative to us we are not accelerating out of it.  Gravity and accelerated motion are covariant (thanks to Einstein) and an internal observer cannot tell one from the other.  Just like going along in a car.  If the car could travel extremely smoothly enough and you could not see any external input--like out the windows, unless it changed direction or speed i.e. its velocity by undergoing acceleration, you would never know you were moving. Think about it you can only really tell you're moving along by the road vibrations in the vehicle and by seeing things going by outside the windows.  You only feel "moved" if it turns or speeds up/brakes.
25250
I found what you may be looking for at the website below.  Here it is...\n\nFirst it should be known that the Earth's orbit around the Sun is elliptical, not perfectly circular, so the Earth-Sun distance is changing as we speak just from the Earth traveling in its orbit around the Sun.  \n\nIs the orbit itself changing? Well, there are some long-period oscillations, but those are very small, and don't imply that we're systematically moving towards or away from the Sun. \n\nThere is an effect which is making us move very slowly away from the Sun. That is the tidal interaction between the Sun and the Earth. This slows down the rotation of the Sun, and pushes the Earth farther away from the Sun. You can read more about tides, as they relate to the Earth-Moon system. The principle for the Sun-Earth system should be the same. But how big of an effect is this? It turns out that the yearly increase in the distance between the Earth and the Sun from this effect is only about one micrometer (a millionth of a meter, or a ten thousandth of a centimeter). So this is a *very* tiny effect. \n\nThere is another effect which is also small, but somewhat bigger than the tidal effect. The Sun is powered by nuclear fusion, which means the Sun is continuously transforming a small part of its mass into energy. As the mass of the Sun goes down, our orbit gets proportionally bigger. However, over the entire main sequence lifetime of the Sun (about 10 billion years), the Sun will only lose about 0.1% of its mass, which means that the Earth should move out by just ~150,000 km (small compared to the total Earth-Sun distance of ~150,000,000 km). If we assume that the Sun's rate of nuclear fusion today is the same as the average rate over those 10 billion years (a bold assumption, but it should give us a rough idea of the answer), then we're moving away from the Sun at the rate of ~1.5 cm (less than an inch) a year. I probably don't even need to mention that this is so small that we don't have to worry about freezing.\n\n:)\nPeace!
711345
Earth orbits in a counterclock wise direction around the sun.\nIt takes approximately 365.25 days do orbit around the sun.\nThe gravitational forces between the sun and earth and the resulting centripetal and centrufugal forces makes the earth go around.
239445
This is due to relative velocity. It's a great concept...it's the same concept which applies to you sitting at your desk..believe it or not...the earth you are situated on is revolving at the rate of once everyday..but do you feel it?? Nope...that is because you are revolving with it at the same speed. The formula for relative velocity is Vu-Vo where Vu is your speed and Vo is the speed of the other car..since they are the same, you subtract and voila..you get zero..therefore the car appears to be moving at zero speed in your vision. Check out relative velocity on GOogle..its a fun topic and your question is the fundamental base to relativity...Wow huh??\n\nGood luck.\n\nAyerhs\n\nPS: it is most definitely not because they have it on cruise control..I mean they could if they wanted but thats not the reason that they seen stationary to you.
739905
Which velocity? The Eath is spinning at a rate of 1 revolution/ 24 hours (about 18 miles per second) and whizzing around the Sun at about 66,600 mph. Also the Eath is moving with the entire galaxy through space.
504216
1,038 mph at the equator\n\n66,600+ mph around the sun\n\n486,000 mph around the center of the Milky Way galaxy\n\n1,332,000 mph through the universe\n\nSpeed is a relative matter depending upon your perspective!
783382
no the fourth planet from the sun.put me on best answer please!\n\nHappy Trails ♥!
754826
The distance required for the asteroid to travel around the sun = \n\n2PI *radius.....Radius R = 632 million kilometers\nThe orbiting circle for the asteroid is 3968.96 million kilometers\n\nDividing by the time it takes the asteroid to orbit a whole orbit around the sun, we should get the velocity\n\n3968.96 / 8.6485 million kilometers per year.\n\nOne million kilometers multiplied by 10^9  converts to meters\nOne year is = 365*24*3600 = seconds \n\nBy converting the Kilometers to meters and the years to seconds you should get:\n\n1257312021 / 11364129 = \n\n14552 meters per seconds approximately\n\nYou should double check the divisions and multiplication.
407005
I'd say 17000-19000 miles per hour.\n\nIts at a inclined geo-stationary orbit probably.
333459
The Earth orbits the sun at an average speed of 67,000 mph in a counterclockwise direction when viewed from above it's North Pole.
541450
The diameter of the Earth's orbit around the Sun is about 300,000,000 kilometers
1052164
Ask those living in other planets!