What is the force of gravity in feet?
456275
9.81 m/s² or 32.2 ft/s²
368233
N is Newtons, a unit that measures force. For every 1kg of something, if it accelerates at 1 meter per second per second (m/s/s or meters per seconds squared), than there is a force of 1N acting on it.\n\nForce is calculated by multiplying the mass (not weight) with the acceleration. For example, if you are 75kg, than there is a force of 75kg X 9.8 m/s/s (acceleration due to gravity: roughly constant on Earth) = 735N pulling you down. BUT, there is a reaction force, in this case the NORMAL, pushing you back up at the same time and force. Therefore, the force pulling you down, 735N, take away the NORMAL, also 735N, and you will have a NET FORCE of 0N because you are stationary. \n\nSo in order to resist something pulling at 14N (ignoring air resistance, friction, etc), it needs to pull back 14N.
757859
haha, k  Draw a picture and draw a free-body diagram.\n\nI don't feel like busting out a paper/pencil  so I'll try it in my mind\n\nF(sub g) cos Theta  =  Mg cos(20 degrees)\n\nbecause the Normal force is equal to the y-component of gravity.\n\nTwo similar triangles, the incline and one which has the Force of gravity straight down, and the y compentn equal opposite of the normal force, and X component equal opposite to F\n\n\nlots of physics i'm skipping in my explanation tho
999791
Measurements. The acceleration of gravity is:\ng = G*m/R^2\nWhere G is the gravitational constant 6.67*10^-11 N*m^2/s^2, m is the mass of the planet, and R is the distance between yourself and the planet. For the surface of the Earth, m and R are approximately:\nMe = 5.97*10^24 kg\nRe = 6.38*10^6 m\nUsing this, you should get about 9.8 m/s^2.
983120
Assume superman's mass = m \n\nFriction force developed by shoes: (g = 9.8 m/s^2)\nFf = m * g * 0.9\n\nAcceleration from force:\nF = m * a\n\nEquate the forces such that F = Ff, solve for acceleration:\nm * a = m * g * 0.9\na = 8.82 (m/s^2)\n\nDetermine the time required to go 50 m:\nx = (1/2) * a * t^2\n50 = 0.5 * 8.82 * t^2\nt = 3.367 seconds\n\nTada!
814690
The forces on the person are\n\nSFx = 0 = N - Fc\nSFy = 0 = Fs - m*g\n\nwhere SFx and SFy are the sums of the forces in the x- and y-directions, respectively, N is the normal (to the wall) force, Fc = m*v^2/r is the centripetal force, Fs = u*N is the friction force, m is the mass, and g is the gravitational acceleration.\n\nThese equations say that\n\nN = Fc = m*v^2/r = m*w^2*r\nu*N = u*m*w^2*r = m*g\n\nwhere w = v/r is the angular speed. Solving for the coefficient of static friction gives\n\nu = g/(r*w^2)
1093836
Centrifugal force and gravity.
903133
From what I learned in physics class, the force you are speaking of is measured in Newtons.
632008
Gravity, its weight, friction\nThat's about it.
193077
Force=Mass x Acceleration\n\nSo Acceleration = Force/Mass\n\nHope this helps
481398
sum the forces in the direction that they are applied and it will be equal for a static object. \n\nRule of thumb on this one is that you have 100N down ward, then you need 100 N's up ward.\n\nGivens, legs are equal lengths, same material, and no angles to calculate.\n\n4 legs - 4 forces - each at 25 Newtons.  \n\nNow if you want to get fancy, break out the strain gauges and let us see what we really find.  But it helps if you have preformed a few material tests and experimenters first.
748344
Every particle has a gravitational force associated with itself. It the basic nature of the particle.\nThe force is given by : F = G(m1*m2)/r^2\nwhere G= Universal constant of Gravity.\nSince the earth is very huge, the force between 2 humans is negligible as compared to the each of them to earth
51910
Weight is a force, but when something is weighed you actually measure it's mass assuming you are in an environment in which the force of gravity is constant (i.e., you're at a fixed location <radius from the center> on a planet or massive planetary mass).\n\nof course, one's mass can be approximated by W=mg at fixed radii from such planetary masses (like the earth, a massive asteroid, a superdense star, whatever...) if the force of gravity, g, is known at that radius.\n\nThere are 2 possible variables here - mass and the force of gravity.  Which one do you know?  usually an approximation for g is given.  Which one do you measure, then...that would be mass.
324670
You exert more pressure per square inch if you stand on your toes, because your entire body weight is concentrated on about two square inches, rather than being spread out over something like 40 or more square inches if you're flat-footed. But it doesn't change the total force your body's weight exerts on the entire floor you're standing on. For example, standing on your toes or standing flat footed in an elevator will have no effect on how fast the elevator rises or falls.
939985
Well, yes, the gavity is pulling you down, and you are not moving. So you are subjected to an acceleration and are not moving.\nMind you, one can argue that the *resulting* force is zero, as the ground is reacting with an equal and opposite force to your weight; if you take it that way, to have an unbalanced force should result in motion.
820061
A gravitational field is generated by the Earth. Since our heads are further away from the Earth than our feet, they experience a gravitational effect slightly less than that experienced by our feet. Einstein showed that clocks at higher gravitational potential tick slower. Therefore when you walk your feet and head travel the same distance, but our heads do it in less time. Therefore since velocity = distance / time they must be travelling at a higher velocity than your feet.
225182
There are many systems of measurement for force, ft/lbs, newtons etc. you can define your own if you wish. what is it you are really asking?