I have a shape with 4 different sides and need to work out how many square meters?
460116
It depends what it looks like.\nWithout seeing the actual picture I cannot find the area.
837128
My husband and I just used geometry the other day to estimate how much tile to buy for our 2 bathrooms.  Our bathrooms have a lot of irregular spaces, so we had to measure the entire perimeter of each bathroom.  We then split the bathrooms into different geometric shapes to find the area.  We had to work our formulas for several squares, rectangles, and triangles.   Then we added them all together to come up with the square footage.  After that, we had to estimate how many 12 inch by 12 inch tiles we needed.  It was pretty tricky, but my husband is a math whiz, so it's easy for him.  He's an engineer, go figure...
48612
Let r be the radius of the circle and s the length of the square's sides.\ncircle perimeter=2*pi*r, square perimeter=4*s\n2*pi*r=4*s => s=pi*r/2\ncircle area=pi*r^2, square area=s^2\ns^2=(pi*r/2)^2=pi^2*r^2/4\nBut pi<4 => pi^2*r^2/4<pi*r^2 => square area < circle area
283369
The perimeter of the square is 50 units\n\nThere are 5 rectangles that means the ratio of length to width has to be 5 to 1\nTherefore since each rectangle has a 5 to 1 ratio and a perimeter of 30 they are all 12.5 units by 2.5 units. (12.5 x 2 is 25, 2.5 x 2 is 5, 25 + 5 = 30)\nThe length of each side of the square is 12.5. 12.5 x 4 is 50 units
47718
So you've got an eight-sided figure and each side is 72-feet.  If you draw horizontal and vertical lines from each vertex (the angles where sides meet) to the other side of the octagon, you'll see that the octagon can be split up into one large square (in the center), four rectangles (up, down, left and right), and four triangles (in the corners).  You following me?  Get out a pencil and get to it!  Okay.  So what are lengths of your square's sides?  You'll note that the square has 72-foot sides, just like the original octagon.  Since you know how to find the area of the square, you're on your way.\n\nNext.  you have four rectangles, each with a length of 72-feet, but the short end - the width, how do we figure out the width of the rectangle?  Okay.  Look at your triangles.  Each triangle has one side of 72 feet - the side which is the outside of the octagon - and then two equal sides - it's an isosceles triangle with a 90-degree angle.\n\nOkay, time to call on pythagoras.  Pythagorean theorem states that a^2 + b^2 = c^2.  What that means is this: If you take the length of sides a and b (the ones we don't know) and square them, and add them together, the answer will be 72-squared (side C).  Too bad I'm not there with you to make this part easier to understand.  We know that a and b are equal in this case because our triangle is isosceles.  Therefore, 2x^2 is equal to 72^2.  This gives us a messy equation wherein our answer is, x is ROUGHLY equal to 51 feet.\n\nSo.  You have a square with sides 72 feet long.  You have 4 rectangles each with length 72 and width 51.  You have 4 triangles each with base 51 feet and height 72 feet.  You know that squares and rectangles have an area equal to length times width, and triangles have an area equal to one-half base times height.\n\nCalculate the area for your 9 figures and add them together.  THAT will be the square footage of your octagon.\n\nWhat... did you think I was going to do it ALL for you?
955861
area: l*w = 256\n-> 4w*w = 256\n->w(sqaure) = 64\n->w=8 (width)\n->l = 4w = 4*8 = 32(length). \n\nThere you go.
336458
the sides are 2 units (3-1=2) \nand the ends are 10 units. (6-(-4)=10)\n\narea = side times end = 2*10 = 20\nperimeter = 2 * side + 2 * end = 2*2 + 2*10=4+20=24
594683
To find area you multiply the length times the width. It's pretty easy once you know
844420
Area of a rectangle formula\n\nA = LW\n\nA = 4 x 5\n\nA = 20 Square feet\n\nThe answer is A = 20\n\n- - - - - - - - - -s-
210461
It all depends on the shape you are trying to measure. Different shapes use different equations.\n\nSurface area is generally quite easy. you just work out the area of each side and add them all up. Try this site: http://www.bbc.co.uk/schools/gcsebitesize/maths/shape/arearev3.shtml\n\nVolume is a little more difficult. There are some good examples of working out volumes of different shapes here: http://www.bbc.co.uk/schools/gcsebitesize/maths/shapeih/areaandvolumerev3.shtml
327427
Each side would have length sqrt(3), so the area would be 3 m^2.
268407
Actually it depends on the layout of the meters.  If it is a true square, it would be 2x2 meters... so 2 meters wide.  It is also possible to have four square meters be 4x1 meters.\n\nMore information is needed.
907964
let l be the length and w be the width\n lw=111\n\nbut it has a margin so Area= (l-11cm)(w-4)\ndifferntiate\nbut we have 3 unknowns so we use the first ea lw=111\nl=111/w\n\nA=(111/w-11)(w-4)\n\ndA/dw= (111/w-11)+(w-4)(-111/w^2)=0\n\n111/w-444/w^2= 111/w-11\ncancel 111/w\n-444/w^2=-11\ncrossmultiply\nw^2=-444/-11\nw=6.4 cm\nl=111/6.4=17.3
87402
a: width\nb: length\nperimeter = 2 x (a+b)= 420 ---> a+b = 210\nwe need to find max (a x b)\n\na= 210-b ---> area = a x b = b x (210-b) = 210 - b2 = - b2 + 210b = - b2 + 2 x 105 x b - 105squared + 105squared\n= - (b2 - 2 x 105 x b + 105squared) + 105 squared\n= - (b - 105)squared + 11025\n\nSince (b - 105) squared is always >= 0,\n - (b - 105)squared is always <= 0\n  - (b - 105)squared + 11025 is always  <= 11025\n\nthe largest area will be 11025 squared feet. This happens when - (b - 105)squared = 0, which means b = 105.\n\na = 210 - b = 105\n\n\nthe shortest way is to say that a rectangle has the largest area when it's a square, so each side would be 420/4 = 105.
143210
fancy description of a rectangle.\n\nIf it had four congruent sides, it would be a square.
991928
Assuming you mean a regular hexagon, then with the 30-60-90 relationship, you should get that half the length of a side is 2.\n\nSo, the area of that yellow triangle in the link below is\n.5 * 2 * 2 * sqrt(3) = 2 * sqrt(3)\n\nThere are 12 triangles, so the area is 24 * sqrt (3).
897940
perimeter = 2 * (length + width)\n\nfor square, length = width..\n\nso, perimeter = 2 * (2 * length) = 4 * length\n\ngiven, 4 * length = 104\nso, length = 26\n\nso, each side is 26 cm long.