physic question? piease write the way of solution.?
461302
So far, you have a starting position and an ending position.  If this were a physics question, you'd also need numbers like the mass of the ball and the initial launch velocity.\n\nIn general the equation of motion is given by\n\ns = s0 + v0t + at^2\n\nwhere you need or have the final position (which we have), initial position (which we have), initial speed (which we're looking for, gravity (a known constant), and the time in flight (which we can find using other equations).  Generally, things will go up and down parabolically, not in a straight line, so we need more information about this to answer your question.\n\nNow if you're just looking at a straight line path, then you can use some trig to find at least the angle to the ball (you can't find the speed if you're assuming straight line travel).  In this case, if the person is 1.7 m, and he is standing 5.8 m from the basket that is 3.05 m away, you have a right triangle where the horizontal leg is 5.8 m and the vertical leg is 4.1 m (the difference between the height of the basket and the player, assuming that the ball is thrown from 1.7 m above the ground).  Using the tangent function, you can find that angle:\n\ntan x = opposite side / adjacent side\n= 4.1 / 5.8\n= 0.7069\nx = 35.26 degrees\n\nBut again, laws of motion dictate that the ball follow a parabola to the basket.  But at least we can say that the launch angle has to be at least 35.26 degrees.
460952
Two hundred quattuordecillions\n\nCan be written using scientific notation as 2.0 x 10^47
1132678
Directions how to do this can be found in the text book.\n\nDo your own homework!
179131
Try this:\nhttp://kr.cs.ait.ac.th/~radok/physics/f3.htm
948228
D =M/V\n\nM=DV\n\nV=M/D
187220
W=F*d,  d=W/F,  d=600J/400N = 1.5m
364905
Use Charles' Law\n\nLet V initial = V\nLet T initial = T\n\nLet V final = V'\nLet T final = T'\n\n\nV/T = V'/T'\n\nSolve for V' you might have to convert from mL to L though.
663213
I am sorry I can not provide you with an answer to your question. However it might help you get more answers if you put this question in again but put it in the Science and Mathmatics section. Under Physics. I think there are more people willing to help you out there!
569320
v=vo + at\nv=0 + (9.8)(8)\nv=78.4\n\ny=1/2(vo + v)t\ny=1/2(78.4)(8)\ny=1/2(627.2)\ny=313.6m\n\nB
798267
This is a Hess' Law problem.\n\nThe strategy I like to teach for these is to get the biggest thing you need first then get rid of the biggest thing you don't need next.  So we want to get the 2 N2O5 first then get rid of the resulting 4 HNO3.\n\nUse -2 times the first eq to get your 2 N2O5, -4 times the third to get rid of your 4 HNO3, finally -2 times the second to get rid of the water:\n\n2 N2O5 + 2H2O > 4 HNO3   -152.4 kJ\n4 HNO3              >  2 N2 + 6 O2 + 2 H2  +696.0 kJ\nO2 + 2H2           >   2 H2O  -572 kJ\n\nEverything cancels properly to get the desired equation, and delta H is -28.4 kJ.
786456
a) 2900 * (54 + 0.29 v)\nb) 9 * 2900/v\nc) 2900 * (54 + 0.29 v + 9/v)\nv = 5.57
1116027
Find the potential energy PE=m*g*h\nEquate it to the energy equation\nMass*Height*accln due to gravity=Rise in temp.*Mass*Sp.Heat Cap.\nCancelling mass from both sides and rearranging the equation.\nRise in temp=Height*accln due to gravity/Sp heat capacity\n                    =(200*9.81/5.04*10^2) C
976575
Hi Mark, I will answer your question if you answer mine first.\nWhy are you asking this question, it seems like a lot of people in school are trying to take the easy way out of a physics or math problem.\nWill answer if you are not doing said above!\nCheers, Susie
977303
maybe what your teacher is trying to say here is the body temperature. now search for that answer. it's your homework.
969486
I just helped someone else with their physics question, so I'm alittle tired of it.  But, I suggest you make an equation sheet...physics is all about equations.  So, if you have a piece of paper with your equations, all you have to do is look at the sheet and plug things in...
180516
Well, P * V = n * R * t\nRight side is equal before and after changin` pressure.\nSo, P1 * V1 = P2 * V2\nP1 = 1.01 kPa ;\nV1 = 458 mL ;\nV2 = 477 mL.\nP2 = (P1 * V1)/V2\nP2 = (1.01 kPa * 458 mL)/477mL\nP2 = 0.97 kPa\n\nP.S. You didn't have to say how much is the temperature, it doesn't mather.
200995
by electrolisis\nH2O------>H2+O2\ni.e by passing electric current