How Do you Simplify (14-5i)+(-8+19i) and (7+3i)(7-3i)?
464606
Simplify: (14-5i)+(-8+19i)\n\nStrategy: Remove the ( ) and then combine the parts without an i (the "real" terms) and then combine the parts with an i (the "imaginary" terms). You are adding complex numbers in this problem.\n\nSolution:\n(14-5i)+(-8+19i)\n = 14 - 5i - 8 + 19i\n = 14 - 8 - 5i + 19i\n = 6 + 14i\n\n \nSimplify: (7+3i)(7-3i)\n\nStrategy: Remove the ( ) by applying the "FOIL" method (a.k.a. Distributive Property of Multiplication over Addition). We will also use the definition i^2 = -1 to complete the simplification. You are multiplying complex numbers in this problem.\n\nSolution: \n(7+3i)(7-3i)\n = 49 - 21i + 21i - 9i^2\n = 49 - 9i^2\n = 49 - 9(-1)\n = 49 + 9\n = 58\n\nNote: You may also write the answer in complex form (a + bi) as 58 + 0i.
1100896
17+22+8+8+2+20+26+15+18+13=149
572398
first multiply i by everything in the first bracket.\nso -8i * i + 3 * i + 2(2-5i)\n\nthen do same with 2nd bracket\nso -8i^2 + 3i + 2*2 - 5i*2\n= -8i^2 + 3i + 4 - 10i\n\nnow collect all the like terms\n-8i^2 + 3i - 10i + 4\n= -8i^2 - 7i + 4\n\nnow if i is the imaginary number i^2 would be -1.\nso it would be 8-7i +4 = 12-7i\n\nhope that helps. laterz
1157783
2 + 3i\n-2 - 3i\n\n\nNO FAIR YOU PEOPLE WHO ARE EDITING YOUR ANSWERS WITH THE CORRECT ONE \nI WAS FIRST, THANK YOU (MIKESGLOBAL & dhaval70\n YOU CHEAT)\n\nThank you for being honest dhaval70.\n\nboy i could go for a pint right now....
688567
1 + 2 = 3\n3 + 4 = 7\n7 + 6 = 13\n13+ 8 = 21\n21+ 10= 31\n31+ 12= 43
575490
I- + 2e- -------> I2\n\n4P + 3e-  -------------> P4\n\nthere ya go :)
747277
5a+6b-3a+b=?\nSimplified= (2a+7b=?)  or (2a = -7b) or (7b = -2a)\nThey are all the same\n\n15x-3y-7x-4y=?\nSimplified = (8x-7y=?)  or (8x = 7y) or (-8x = -7y)\n\n15m-17n-23m+25n=?\nSimplified -8m+8n=? or (8n=8m) or (n=m)
602540
x + 3 >  8 ==> x >  8 - 3  ==> x > 5\nx - 4 < -2 ==> x < -2 + 4 ==> x < 2\n\nAnswer... not possible.
8473
7t+15 > 3t-13\n4t > -28\nt > -7
913862
3x + 2y - 2z\n\n3(5) + 2(2) - 2(1)\n\n15 + 4 - 2\n\n19 - 2\n\n17\n\nThe answer is 17\n\n- - - - - - -s-
776941
-25 < 5(w + 3)\n-25< 5w +15\n-40< 5w\n-8<w\n\n-9q + 18 -3 > 6q\n15 > 15q\n1> q\n\n\n19 < 7 + 1/3k + 2 -2/3k\nmultiply by 3 to get rid of denominators\n57 < 21 +k +6 -2k\n30< -1k\ndivide by -1\n-30<k
596283
add them up like this \n4+2+(-3)+6+5+(-3)+(-2)+0+(-1)+(-4)+3\ndivide the result by 11 because that is how many numbers there are in your list.  That will be your answer!
771836
Simple substitution.\n\n5(3) - 2(2) + 4(4)\n15 - 4 + 16\n27
852547
You need to multiply by the reciprocal\n\nwhich gives you \nnumerator:  (s+t)15\ndenonimator:  5(2(s+t))\nThis will simplify to 15(s+t) over 10(s+t); which is 1.5
96233
+5,+12, -5, -12, +3.3
1007006
add or subtract 1\n\nor else subtract the S at the begining of Seven
555590
Just multiply:\n(X/3)(3/4 x) -(x/3)(3/5) + (3/4)(3/4x) - (3/4)(3/5)\n\nand simplify from there