How many lines/cm must a grating have if there is to be no second-order spectrum for any visible wavelength?
465115
The equation is just for the angle of a particular wavelength. Not for resolution. Say 250nm,300nm look like 2 lines and not one. \nI think you want to look up diffraction limits. \nSimple experiment is to compare a CD rom and DVD see how they split wavelengths.
933542
No.  But it's wavelength decreases.\n\n\nDoug
977017
D) .diffraction grating, will split the light on the edges causing a rainbow effect on the edges of the objects
389650
microwaves have the longest wavelength of your three choices. Gamma rays have the shortest and ultraviolet waves are at the far end of the visible light spectrum and have a wavelength shorter than microwaves but longer than gamma rays.
470121
Try these answers:\n\nFor the first one, shortest is 0.0086 m, longest is 8.6 m.\nFor the second one, it should be 2.95 Hz
64215
almost certainly it would be in the visible region of the spectrum. after all it does have that pretty color!\nvisible region is roughly between 400-700 nanometers wavelength.
1065631
To convert between wavelength and frequency, recall the following equation, converting all units to meters:\n\nspeed = frequency * wavelength\n\nspeed of light is 3*10^8\nwavelength is 1150 = 1150 * (10^-9)\n\nso just divide and you shall conquer !\n\nHope this helps,\n\nJ
963067
Emission lines of different wavelength depending upon what is being studied.
712915
i have not heard of spectroscopy being used to determine the amounts of gases, but i guess you could by looking at how deep the colours are. If the colours are paleish = not alot,etc
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wavelength = speed of light (c) / frequency\n\nTypical frequency values for your examples are:\n\nMicrowave: 10^9Hz\nX-Rays: 10^17Hz\nRadio: 10^7Hz\nInfrared: 10^13Hz\n\nTherefore X-Rays have clearly the highest frequency, (and hence the shortest wavelength.)
251507
I'm not really sure what you're asking for, but I'd answer this question using Physics concepts.\n\nOK, we all know that the visible light spectrum lies between the wavelength of 700nm-400nm. (That's 700 nanometer-400nanometer). 700nm is the red part of the spectrum, and 400nm is the violet part of the spectrum.\n\nAccording to your colour spectrum (ROYGBIV), orange light has a larger wavelength than yellow light.
86731
The splitting and shift of a spectral line into several components in the presence of an electric field.
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Infrared is light that has a wavelength outside the bottom of the visible spectrum--it is essentially the "colour" that occurs before red (the lowest visible wavelength).\n\nThe invisible "light" that occurs at the top of the visible spectrum is ultraviolet.\n\nBoth of them can't be seen with the naked eye, but can alter the way the eyes perceive the other--visible--colours.
550292
If you mean by "broad band" the entire electromagnetic spectrum, visible light is a small bit (of the entire spectrum)that our eyes are able to detect.  As far as particular wavelengths/freqs and other cool info go see:\nhttp://imagine.gsfc.nasa.gov/docs/science/know_l1/emspectrum.html
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One of the beauties when using Fourier transforms, is the ability to work with a spectrum of modes and act on each of the components individually with a filter. By sampling the function over a period  with a finite number of values  , where  is the size of the sampling interval, the spectrum gets truncated at the shortest wavelength  called Nyquist critical wavelength: this corresponds to exactly 2 mesh points per wavelength, which does however not mean that shorter wavelengths  do not contribute to the Fourier coefficients (4.1#eq.1). Figure 4.3#fig.1 illustrates how they get aliased back into the lower components of the spectrum
1034520
Isn't black the absence of color? So there would be no wavelength to the color...
895120
The correct answer is 3.\nThe 1st spectral line is caused by the electron falling from state 2 to state1.  The 2nd line is caused by a shift from 3 to 2, and the third, a shift from 3 to 1.