How many 9s are between 0 and 100?
455486
20 (9,19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98,99)
1026835
96 + 95 + 97 + 99 = 387\n99 + 99 + 98 + 90 = 386\n\nThe first set is larger.\n\n(Note: It is unnecessary to divide by 4 to get the average in this problem because there are the same number of terms in each set.)
462416
9. B\n10. B\n11. It's 0.3455\n12. C
1121383
36\n95\n1080\n1080\n1080
1169470
792\n\n1 thru 9 = 9 digits\n10 thru 99 = 180 digits (90 numbers with 2 digits each)\n100 thru 300 = 603 digits (201 numbers with 3 digits each)\nTOTAL = 792
537104
Nine (9) - before 10 and after 11\nOne (1) - before 2 and after 0\nOne (1) - before 2 and after 0
1044971
A billion has 9 zeroes.
358099
0.43 & 0.0062\n\nDivide by 100
183810
If the domain is [100,999], you have 999-100+1=900 numbers to try.  If you divide a number by both 7 and 8, you can simply divide the number by 7*8=56 instead (I'm not sure if I can explain why this might be true.)  Basically, this means you have a 1/56 chance of a number having a remainder of 4 for both 7 and 8. 900 * 1/56 = 16.071, but since you can't have a part of a number that is a match, you can round that off to 16.
429263
basic numbers are numbers 0-9
706980
Zero is in the Hundreds position. \n\nTwo is in the Thousands, \nOne is in the Tens position,\nNine is in the Ones position.\n\nOnce you move to the right of the decimal, it is:\n\nFour in the Tenths position,\nSix  in the Hundredths position,\nand Three is in the Thousandths position.
432272
11 :)\n\nstart counting:\n1, 2, 3, .... 10, 11, .... 19, 20, 21, ..............89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100
1011386
I tried and I found that 100! is perfectly divisible by 350 as 350=2*5*5*7=50*7.\n\n100!= 100*99*98*97!\nnow 100 is divisible by 50 and 98 is divisible by 7.\n\nSo the least number is 1.
310292
one divided by 8 multiply 100
658003
5050\n\nIf you add the numbers like this\n (1 + 100) + (2 + 99) + (3 + 98) + . . . . + (50 + 51) = ?\nthen each set adds up to 101 and there are 50 sets of numbers, so 101*50=5050
501472
Minimum of nine. 100 divided by 9 equals 11.1......%\n\n4 times 11.1 equals 44.4 rounds to 44\n5 times 11.1 equals 55.5 rounds to 56\n\n\nDid anyone who posted after me actually take the time to read this analysis?\n\nOne more time:\nRounding to the nearest integer the possible solutions with total votes no higher than 100 are:\n4 5\n7 9\n8 10\n11 14\n12 15\n14 18\n15 19\n16 20\n17 22\n18 23\n19 24\n20 25\n21 27\n22 28\n23 29\n24 30\n24 31\n25 32\n26 33\n27 34\n27 35\n28 35\n28 36\n29 37\n30 38\n31 39\n31 40\n32 40\n32 41\n33 42\n34 43\n34 44\n35 44\n35 45\n36 45\n36 46\n37 47\n37 48\n38 48\n38 49\n39 49\n39 50\n40 50\n40 51\n41 52\n42 53\n42 54\n43 54\n43 55\n44 55\n44 56
480763
9999 = MMMMMMMMMCMXCIX\n\nExplaining:\n\nsince 1000=M\nand 100=C\nalso 10=X as you mentioned\nand  1=I\nThen 9999=9*1000(that is 9 M's)\n          +900 (that is 1000-100=CM)\n          +90 (that is 100-10=XC)\n          +9 (that is 10-1=IX)\n\nNote:In Roman Numerals; symbol represnts small No. to the rigt of Larger one is to be added while to the left of it is to be subtracted (Example: I=1 V=5 then 6=VI while 4=IV).