To reenter-ate from the previous question and make this simple, how many (mA) are in one volt ?
474963
Two completely different units.  Amps measure current (flow).  Volts measure voltage.  Voltage= current x resistance.
151356
Converting Amps to Volts at fixed wattage\n\nThe conversion of Amps to Volts is governed by the equation Volts = Watts/Amps\n\nFor Example, 48 watts / 12 Amps = 4 Volts\n\nExplanation\n\nAmps are how many electrons flow past a certain point per second. Volts is a measure of how much force that each electron is under. Think of water in a hose. A gallon a minute (think amps) just dribbles out if it is under low pressure (think voltage). But if you restrict the end of the hose, letting the pressure build up, the water can have more power (like watts), even though it is still only one gallon a minute. In fact the power can grow enormous as the pressure builds, to the point that a water knife can cut a sheet of glass. In the same manner as the voltage is increased a small amount of current can turn into a lot of watts.
491209
175.76 Amperes...\nusing m=z*i*t\nz=63.546/96500\nt=24*60*60\nm=10*1000
387680
Ok...you guys got this all wrong.  Voltage doesn't travel.\nThis is simple:\n\nSeries:\nAll series stuff see the same current\n\nParallel:\nAll parallel stuff see the same voltage
1100598
voltage = current x resistance\nE = I x R  It IS Ohm's law. An easy way to remember the formula and it's configurations is to draw a circle and divide it in half horizontally. Above the line write "E". In the lower half divide the semicircle vertically and write "I" on the left, "R" on the right. It should look something like this:\n                                                     E\n                                                   I    R\nNow just cover up the one you need. and either divide, or multiply.
238179
Resistance=Voltage/Amperes
219811
!WARNING!\nFirst before I even answer your question.  I just like to warn you that if your actually attempting a stunt like this be very careful.  Connecting 100 AA Batteries(1.25V) in series will produce 125 Volts.  Be very careful with it!\n\nAnswer:\nThe SI units of the electric field are volts per meter.\nThe equation for an electric field is: (E=V/r)\nWhere E=Electric Field, V=Voltage, r=distance from point.\nSo a higher electric field means two things: Higher voltage, or less distance. In order for you to get the highest voltage connect the batteries in series as follows:\n\nConnection: \nYou would need to connect the battery in series as follows to get the highest voltage. \n Bat1  Bat2  Bat3  Bat4  Bat5  Bat6      Bat100\n[- +]o[- +]o[- +]o[- +]o[- +]o[- +]o....[- +]o\n\n\nWhy:\nThe electric field is dependent on the voltage and distance. Increasing voltage will directly increase the electric field.  Decreasing distance will increase the electric field. Look at the equation above. E=V/r\n\nAnother way to think of it:\nThink of Voltage as pressure. And a ball as an point charge(electron).  Suppose you have a water hose and a ball.  You have to use the water hose to move the ball around.  If your too far away from the ball, the water will not reach the ball and the ball won't move.  The same thing happens in electric field.  The electric field is too far from the electron to make it move.  Now suppose you increase the pressure on the water hose.  Because of the increased pressure(Voltage) the water will shoot further and hit the ball, thus moving it.  If your very close to the ball you can use the water pressure(Voltage) to move the ball faster.
734859
Divide by the voltage and multiply by 1000.\n\nIf you are working with 3 phase power, divide again by sqrt(3)
974255
About plus and minus ten percent. That makes it 108 minimum and 132 maximum volts.\n\nMost appliances are designed to expect this range.
682439
I believe Volt is just the name of the unit for EMF, like meter is the name of the unit for length.
783633
YOU ARE ASKING A QUESTION THAT IS ANSWERED BY SOLVING THE EQUATION (E=IR) OR OHMS LAW. IF YOU GIVE ME TWO OF THE  UNKNOWNS THE EQUATION CAN BE SOLVED FOR A NUMERIC ANSWER.   LETS ASSUME THE VOLTAGE(E) IS 100VOLTS.  THEN THE CURRENT(IR1) WOULD BE (100VOLTS/110 OHMS) E1/R1 OR 0.909 AMPS.\nTHE SITE BELOW GIVE A LENGTHY DESCRIPTION OF THE SIMPLE CONCEPT AND JUST SEARCHING "OHMS LAW" WILL YIELD DOZENS MORE. YOU WILL FIND THAT THE VOLTAGE APPLIED TO EACH RESISTOR IS THE SAME AND THE AMPERES THROUGH EACH RESISTOR IS INVERSELY PROPORTIONAL TO THE RESISTANCE.
662856
First answer said convert Joules in electron volts and then compute. You don't need to convert to eV; just divide joules by potential difference (volts) to get 5 coulombs.
892848
One of the most frequently used is E=IR    ;E =voltage    I=current   R= resistance. U can change this every way depending on the unknown.\n    Good luck
1050051
Technically, you don't convert mA into VA in any AC circuit!  One is a measure of current flow, the other is a measure of power.\n\nNow if you want to figure out the power of the transformer, simply multiply the amperage by the voltage.\n\nP = 12V X 800mA = 12V X 0.8A = 9.6 VA or 9.6 watts.\n\nNow you can think of the power in terms of VARs (volt amp reactive), but those are typically used in where you have either a(an) inductive and/or capacitive load and use imaginary numbers to solve such problems.
1129109
0.004vi = (1.110 + 0.004)vf\n\n(1/2)(1.114)vf^2 = (0.220)(1.114g)(0.300)\n\nvf^2 = 2g(0.220)(0.300)\n\nI think you should be able to do the rest...
713107
range/amount\n\nrange = 120 mV (90mv - (-30mV))\namount = 2^16 = 64*1024\n\nplug-n-chug
899661
This will take a few steps.\n\nStep 1.  Find the equivalent resisitance of the 12 and 4 ohm\nresitor.  Reqv = R1(R2)/(R1+R2) = 12x4/16 = 3\n\nSo you have a 3 ohm and 7 ohm resistor in series.  This gives\na circuit current of V/Rtotal = 20/10 = 2amp\n\n\nNow the voltage drop across the 7ohm resitor is 7x2 = 14 volts\nand the voltage drop across the equival 3ohm resitor is 3x2 = 6 volts.\n\nThis 6 volts is across the 12 ohm resitor, so the current\nthrougth it is V/R = 6/12 = .5