b^2+7b+6=0? m^2+10m+21=0? n^2+3n-4=0? a^2+2x-8=0? a^2+3a-10=0? b^2+7b-8=0? y^2+6y-27=0? m^2-6m+5=0?
469080
1.(b+1)(b+6)=0           2.(m+3)(m+7)=0\n   (b+1)=) or (b+6)=0       (m+3) =0 or (M+7)=0\n    b=-1 or b=-6             m=-3   or  m=-7\n\n3.(n+1)(n-4)=0           4.(a-2)(a+4)=0\n   (n+1)=0 or (n-4)=0       a=2 or a =-4\n    n=-1  or n=4\n\n5.(a-2)(a+5)=0            6.(b-1)(b+8)=0\n   a=2  or a=-5              b=1 or b=-8\n\n7. (y-3)(y+9)=27          8. (m-1)(m-5)=0\n   y=3 or y=-9                m=1 or m=5\n\nnext time I'll give answer for the first three,the rest try it yourself or else you won't learn!!!!\n\nOKAY?
1106166
I used the quadratic formula\n\na = 5\nb = -7\nc= = -1\n\n-(-7) +- sqrt[ (-7^2 - 4(5)(-1)]\n----------------------------------------\n             2(5)\n\n7 +- sqrt [ 49 - (-20)]\n---------------------------\n             10\n\n7 +- sqrt [69]\n------------------\n         10\n\n\nFor your second problem, one of the solutions is -1/3.  The other is also 4\n\nfrom (11+13) / 6 = 4 or yours (11-13) / 6 = -1/3
134065
Your statement translates to the following algebraic equation.\na+b=a-b=a*b\nSolving a+b=a-b, we get b = 0; \nSubstituting b=0 and solving a+b=a*b, we get a = 0;\nSo the two numbers are zeroes.
91468
there should be 2 answers\n3m^2 + 18m =0\n(3m+0)(m+6)=0\nso m=0/3=0 or m=-6
424288
1. y2+6y+8 = (y+4)(y+2)\n2. x2+7x+12 = (x+4)(x+3)\n3. z2+2z-24 = (z-4)(z+6)\n4. x2+7x+10 = (x+2)(x+5)
1174116
8x^2 -5 -3x^2 + 7\n8x^2 - 3x^2 -5 + 7\n5x^2 + 2
610613
In 6ab + 4a + 3b + 2, we group the first 2 terms and the last 2 terms:\n\n6ab + 4a + 3b + 2 =\n(6ab + 4a) + (3b + 2)\nthen factor out the common factor 2a in (6ab + 4a)\n(Note: to factor out is the same as dividing each term with the common factor)\n\nwe get:\n2a(3b + 2) + (3b + 2)\nNotice that in each term of the above we have a common factor of (3b + 2)\nBy dividing each term by (3b + 2) or factoring out (3b + 2) we have:\n(3b + 2)(2a + 1)
508006
x^2 + 4bx + 2b=0\n(x+2b)^2 - 4b^2 + 2b = 0\n(x+2b)^2 = 4b^2 - 2b\n(x+2b) = SQRT(4b^2 - 2b)\nx = [SQRT(4b^2 - 2b)]-2b\n\n3x^2 -bx +1=0\n3(x^2 - (b/3)x + (1/3)) = 0\nx^2 - (b/3)x + (1/3) = 0\n(x-(b/6))^2 -(b/6)^2 + (1/3) = 0\n(x-(b/6))^2 = (b/6)^2 - (1/3)\nx-(b/6) = SQRT[b^2/36 - 12/36]\nx-(b/6) = [SQRT{^2 - 12)] / 6\nx = {[SQRT{^2 - 12)]+b} / 6\n\nb^2x^2 - 2bx + c^2= 0\n(bx)^2 - 2(bx) + c^2 = 0\n(bx-1)^2 - 1 + c^2 = 0\n(bx-1)^2 = 1 - c^2\nbx-1 = SQRT(1-c^2)\nbx = SQRT(1-c^2)+1\nx = [SQRT(1-c^2)+1]/b
924424
The equations:\n(a+b)^2=a^2+2ab+b^2\nA^2-B^2=(A+B)(A-B)\nJames Chan's solutions were right.
814891
a^2 - 2ab + b^2 = (a - b) ^2\n\nthen...\n\n(a - b)^2 / (a + b) = (a -b) (a - b) / (a + b)
694839
(y+4)(y+4)-2y -11=0\ny^2 +8y + 16 -2y -11 =0\ny^2 +6y +5=0\n(y+5)(y+1)=0\ny=-5, x=-1 , and   y=-1, x=3\n\nCheck with y=-5\n(-1)^2 -2(-5) = 1+10=11  OK\n\nCheck with y=-1\n3^2 -2(-1) = 9+2=11  OK
912242
2-10x=3x^2+3x-7x-7\n2-10x=3x^2-4x-7\n0=3x^2+6x-9\n0=3(x^2+2x-3)\n0=(x+3)(x-1)\nx=-3 and 1
627033
6y + 3 = -4y^2\n4y^2 + 6y + 3 = 0\n\na=4, b=6, c=3\n\ny = -b+-SQRT(b2-4ac) / 2a\ny = -6+-SQRT[36-(4)(4)(3)] / [(2)(4)]\ny = -6+-SQRT[-12] / 8\n\nBut SQRT[-12] is not possible, unless we are looking for imaginary values, then:\n\ny = -6/8 +- SQRT[-12]/8\ny = -3/4 +- [2SQRT3]i/ 8\ny = -3/4 + [(SQRT3)/4]i or -3/4 - [(SQRT3)/4]i
86546
(3y+1)(-2)+y\n-6y-3+y\n-5y-3\n\n12s+(7-s)2\n12s+14-2s\n10s+14\n\n7x-3x(x+1)\n7x-3x^2-3x\n-3x^2+4x\n\n3t(t-5)+6t^2\n3t^2-15t+6t^2\n9t^2-15t\n\n4w^2-w(2w-3)\n4w^2-2w^2+3w\n2w^2+3w
744314
multiply everything by b and (b-3)  ....... then you will get\n\n2b+7b-9=0\n\n(2b+9)*(b-1)=0\n\nso b= -9/2 or 1
275079
1) m= (2-4)/(2-5) = -2/-3 = 2/3\n2) m= (1-1)/ (-8+9) = 0/1 = 0
776052
3*5b= 15b      \n3*-7= -21\n 15b-21=-7+b\n15b-b-21=-7\n15-b=-7+21\n14b=14\nb=14/14\nb=1