AN EQUATION FOR A CIRCLE WITH THE CENTRE (0,0) AND THE RADIUS oF 10. ????
461911
The equation is (x-h)^2 + (y-k)^2 = r^2, \nwhere (h,k) is the center and r is the radius.\nTHe center is (0,0), so that means h = 0 and k = 0.\nThe radius is 10, so that means r = 10\nPlug these values into the equation.\n(x-0)^2 + (y-0)^2 = 10^2, which simplifies to\nx^2 + y^2 = 100
991890
Try the 2-2 pattern. it's the best way. The 3 is done with that criss-cross pattern, but the 2-2 allows you to continue the circle, just make it have a big radius
692007
its quite simple the radius is half way threw the circle so its the radius 3 squared which equals 9 and 9 times pi or 3.14 equals 88.7364 but u mite have to round it so if u round to a whole number it would be 89 but to the nearest tenth it would be 88.7
680200
Assuming this means a circle...\n\ndefn/:\n\nc=circurmfernce\nA=area\nr=radius\nd=diameter\npi=pi (~3.1415926...)\nd=2*r\n\nC=2*pi*r=d*pi\nA=pi*(r^2)...(area is pi*r squared...pie are squared-no there not their round).\nA=pi*(d^2)/4.\n\njust plug and chug...\n\nC=10*pi.\nA=25*pi.\n\nanswer:\n\nit's that simple
5380
the answer to your question is simple..first find the equation for the circumference of a circle which would be 2 times pi times radius..which gives you the answer 29.516 if you round to the nearest 10th your answer would be 29.5cm
788538
x^2+2x+y-10y+22=0\nis NOT a circle, there is a y^2 missing.\nthis is a parabola!!!! '\n\nbut if you meant\nx^2+2x+y^2 -10y+22=0\nthen\nx^2 + 2x +1 -1 + y^2 -10 y + 25 -25 + 22 =0\n(x+1)^2 + (y-5)^2 =4\n\nso center (-1,5) \nradius: 2 \n'
608708
The basic formula for a circle is (x-h)^2 + (y-k)^2 = r^2\n\n(h,k) would be the center (where x=h and where y=k), and the radius is the positive square root of r^2\n\nSo in your example, there is no h or k, so the center would be (0,0) and the radius would be the positive square root of 25, which is 5.
1180944
alright, ill tell you, but not without explaining it.  im giving you the benefit of the doubt that you are not just cheating on your homework :)\n\nthe standard equation of a circle, using only variables is\n(x-h)^2 + (y-k)^2 = r^2\nwhere the center is at (h,k) and the radius is r\n\nthat means that when you look at the equation youre given, the x coordinate of the center is whatever number is subtracted from the x\n\n(x+1) ---> (x- -1)  so  h = -1\n\nyou use the same process to determine "k", which is the y coordinate of the center\n\n(y+3) ---> (y- -3)  so  k = -3\n\nthat makes the center of the circle at (-1, -3)\n\n\nfinding the radius is also simple using the standard equation. here it is again, just for reference:\n(x-h)^2 + (y-k)^2 = r^2\n\nsee how you can use that to get this?\n9/4 = r^2\n\nso just take the square root of both sides . . .\nr = +/- 3/2\n\nbecause you took the square root, the 3/2 could technically be either positive or negative, but since youre talking about the radius of a circle and you can't have a negative distance, you only take the positive answer.\n\nso r=3/2
351138
You got it.\n\nThe equation of a circle in standard cartesian from is:\n\n(x-a)^2+(y-b)^2=r^2\n\nThe circle is centered at (a,b) and r is the radius. For you, (a,b) is (0,0) and your r^2 term is 49, hence your r is the square root of 49 which is 7.
149565
cool! I'll think about it\n\n---\n\nhere I am.\nUse the two perpenducular segments as a coordinate system with O on their intersection.\n\nSay: the 4-3 segment defines the x axis, and the 2-6 segment defines the y axis.\nYou know four points belonging to the circle: (-4;0),(0;-2),(3;0) and (0,6)\nThe center of the circle has the mean value between -4 and 3 as its x and the mean value between -2 and 6 as its y (property of chords: the center is on the chord's axis)\n\nso the center's coordinates are C(-1/2;2)\n\nNow you can easily calculate the distance between C and anyone of the four points you know to get the radius.\n\nThen finish finding the diameter\n\n----
577034
Since the radius is 44, you could go either 44 units left, right, up or down from the center and find a point on the circle itself.  So (44,0) would be one such point.  However, these points are not in a quadrant; they are on an axis.  All the other points would fit in the circle's equation, x^2 + y^2 = 44^2.  So pick a number for the x-coordinate, square it, subtract this from 44 squared, then do the square root.  That gives you the y-coordinate.
237156
Pi * r^2\n\n(Pi R Squared)\n\nwhere R is the radius (which is also equivalent to half the diameter)
401455
Sorry.  This is going to be a little rough, typing the answer.  Here it goes:  \n(x-2)2(squared)+ (y-4)2 (squared)= 25\n\nYou find the midpoint between the two points for the center.  You find the distance between the two points for the diameter and divide that in half for the radius which equals 5.  The center is (2,4).  You square the radius and that is what comes after the equals sign.\n\nThe guy who entered before me is wrong.  I promise.
625973
How to do this problem:\n1. Find the Radius. To do this, take the diameter and divide by two. This gives you a radius of 5.\n2. Because the Area of a circle is equal to Pi times the radius squared, and your teacher wants the answer in terms of pi, square the radius and get 25 pi.
23358
A=Pi*R^2, where A=area of the circle, R=radius of the circle. * stands for multiplication and ^ for exponent. so the formula for Pi would be Pi=A/R^2.\n\nAnother formula is L=2*Pi*R, where L=length of the circle, R=radius of the circle. so the formula would be Pi=L/2*R.\n\nAnd Pi is an irrational number, meaning that it has an infinity of numbers after the comma. It cannot be exactly calculated, only aproximized. Not even using the ultimate computers, because of a single fact: its memory is not infinite, unlike the number, so you cannot phisically represent it.
568696
rare gem's answer is right..given the radius you'll just need to compute for the area using the formula right?\n\nArea=(radius^2)(pi)\n    = (5)(5)(pi)
236956
pi times the radius squared