What algebra property of real numbers is if 3x=15 then 15=3x?
464936
Commutative operation.
819535
sqrt(x) - sqrt(3x + 3) = 1\nsqrt(x) = sqrt(3x + 3) + 1\n\nsquare both sides\n\nx = (sqrt(3x + 3) + 1)^2\nx = (sqrt(3x + 3) + 1)(sqrt(3x + 3) + 1)\nx = (3x + 3) + sqrt(3x + 3) + sqrt(3x + 3) + 1\nx = 3x + 3 + 2sqrt(3x + 3) + 1\nx = 3x + 4 + 2sqrt(3x + 3)\n\n-2x - 4 = 2sqrt(3x + 3)\n-x - 2 = sqrt(3x + 3)\n\nsquare both sides\n\n(-x - 2)^2 = 3x + 3\n(-x - 2)(-x - 2) = 3x + 3\nx^2 + 2x + 2x + 4 = 3x + 3\nx^2 + 4x + 4 = 3x + 3\nx^2 + x + 1 = 0\n\nx = (-b ± sqrt(b^2 - 4ac))/(2a)\n\nx = (-1 ± sqrt(1^2 - 4(1)(1)))/(2(1))\nx = (-1 ± sqrt(1 - 4))/2\nx = (-1 ± sqrt(-3))/2\n\nx = (1/2)(-1 ± isqrt(3))\n\nThere are no real solutions.
795252
Let a and b be any two real numbers. Consider the number x defined by\n\nx = ab + (-a)(b) + (-a)(-b).\n\nWe can write\nx = ab + (-a)[ (b) + (-b) ]       (factor out -a)\n  = ab + (-a)(0)\n  = ab + 0\n  = ab.\n\nAlso,\nx = [ a + (-a) ]b + (-a)(-b)      (factor out b)\n  = 0 * b + (-a)(-b)\n  = 0 + (-a)(-b)\n  = (-a)(-b).\n\nSo we have\n      x = ab\nand\n      x = (-a)(-b)\n\nHence, by the transitivity of equality, we have\n\n      ab = (-a)(-b).
843360
get the x's on one side and the numbers on the other.\n\nto do that -- perform the opposite operation to each part you want to move on BOTH sides of the equation ..\n\n3x + 3 = 15 - x\n3x (+ x) +3 = 15 - x (+ x)  ---- adding x to both sides\n4x + 3 = 15\n4x + 3 (- 3) = 15 (- 3) ---- subtract 3 from both sides\n4x = 12\n\nI'll bet you can do the last operation in your head ... just divide by 4 and you have your answer to x!
773850
Tip:  If the sum of the coefficients of the polynom are zero, then x =1 is a zero of the polynom.\n\nx = 1\nIf you need more roots do the synthetic divisiona and then use the quadratic formula.
168603
easy if that is the question\n2x+3x=5\nsince they have the same variable\nadd them \n5x=5\nthen divide by 5(no. to reduce the variable with 1 as its coefficient) \nx=1\n\nlonger method\n\n2(x)+3(x)=5\nby distributive property we know that (2+3)x=2(x)+3(x)\nthen: \n(2+3)x=5\n(5)x=5 divide by 5 \nx=1
635376
3 goes into 16 5 times\n5 times 3 is 15\n16 - 15 = 1\n16/3 = 5&1/3
854860
(3x - a)(x - 2)(x - 7) = \n(3x - a)(x^2 - 7x - 2x + 14) = \n(3x - a)(x^2 - 9x + 14) = \n3x^3 - 27x^2 + 42x - ax^2 + 18ax - 14a\n3x^3 + (-27 - a)x^2 + (42 + 18a)x - 14a\n\n3x^3 - 32x^2 + 81\n\nso\n\n(-27 - a)x^2 + (42 + 18a)x - 14a = -32x^2 + 81\n(-27 + 32 - a)x^2 + (42 + 18a)x + (-14a - 81) = 0\n(5 - a)x^2 + (42 + 18a)x - (14a + 81) = 0\n(-a + 5)x^2 + (18a + 42)x - (14a + 81) = 0\n-(a - 5)x^2 + (18a + 42)x - (14a + 81) = 0\n\nx = (-b ± sqrt(b^2 - 4ac))/(2a)\n\nx = (-(18a + 42) ± sqrt((18a + 42)^2 - 4(-(a - 5)(-(14a + 81)))/(2(-(a - 5))\n\nx = (-(18a + 42) ± sqrt(((18a + 42)(18a + 42)) - 4(a - 5)(14a + 81)))/(-2(a - 5))\n\nx = (-(18a + 42) ± sqrt((324a^2 + 756a + 756a + 1764) - 4(14a^2 + 81a - 70a - 405))) / (-2(a - 5))\n\nx = (-(18a + 42) ± sqrt(324a^2 + 1512a + 1764 - 4(14a^2 + 9a - 405))) / (-2(a - 5))\n\nx = (-(18a + 42) ± sqrt(324a^2 + 1512a + 1764 - 56a^2 - 36a + 1620))) / (-2(a - 5))\n\nx = (-(18a + 42) ± sqrt(268a^2 + 1476a + 3384)) / (-2(a - 5))\n\nx = (-6(3a + 14) ± sqrt(4(67a^2 + 369a + 846)))/(-2(a - 5))\n\nx = (-6(3a + 14) ± 2sqrt(67a^2 + 369a + 846)) / (-2(a - 5))\n\nx = (3(3a + 14) ± sqrt(67a^2 + 369a + 846))/(a - 5)\n\nUnless you mistyped something, 3x^3 - 32x^2 + 81 does not factor into (3x - a)(x - 2)(x - 7)\n\n--------------------------------------------------------------------------------\n\nx^3 - x^2 + 16x - 16\n(x^3 - x^2) + (16x - 16)\nx^2(x - 1) + 16(x - 1)\n(x^2 + 16)(x - 1)\n\nif you were to take this further, then\n\n(x - 4i)(x + 4i)(x - 1)
490279
5x + 3y = 16    \n(-)  2x + 3y = 1\n------------------------\n     3x      = 15\n\nx = 5\ny = -3\n\nSolution Set = { (5, -3) }\n\n\nx + 5y = 10  &  -2x - 10y = -20   is one and the same.\ni.e., they have to be cnsistent.
119559
its (x+2)(3x+1) now thats rite lol
1103929
(x^3+x^2-11x-15)/(x+3)\n= (x^3+3x^2-2x^2-6x-5x-15)/(x+3)\n={ x^2(x+3)-2x(x+3)-5(x+3)}/(x+3)\n={(x+3)(x^2-2x-5)}/(x+3)\n=x^2-2x-5\n\nThis should do. but on further simplification you will get \n   x^2 -2x -5\n={x^2 -1 -6^(1/2)}{x^2 -1 +6^(1/2)}
913301
i think its 15 cause 5x3=15
1153869
Well, if the perimeter (thats all the way around the outside or all three sides together is 35, then you can add up the three sides and they should equal 35\n\n3x-5 + 2x-3 + 15-x = 35\n\na little algerbracadabra :  3x+2x-x-5-3+15=35\n\nthen  4x=28\nand x=7\n\nso , put 7 back in for x for each of the sides and you get\n3(7)-5=16\n2(7)-3=11\n15-(7)=8\n\ndouble check just to be sure 16+11+8=35\n\nhurrah \nkeep at it\nmath is power
969851
Basically there're 2 approaches to this problem:\n\n1. Factoring -- easy but NOT applicable to ALL problems.\nAfter factoring, it becomes:\n(5x+1)(3x+5)=0 (cuz 15=5*3, 5=1*5, and 28=5*5+3*1)\ntherefore either 5x+1=0 or 3x+5=0\nthen the two real roots are:\nx=-1/5, -5/3\n\n2. Quadratic formula -- general & reliable but more work. \nAssuming u know the formula (if not look it up in ur math book), just go head and plug in all corresponding coefficients of the original equation (here a=15, b=28, c=5), yields:\nx=(-28+/-square root of (28^2-4*15*5))/(2*15)=-1/5, -5/3\nwhich gives u exactly the same answers as method 1.\n\nHope these make sense to u.. GoOd Luck!..^^
923617
First, factor out 3x from the equation, so 0= 3x(x^2-2x-3).\n\nThen, factor the polynomial in the parenthesis, so 0= 3x(x-3)(x+1)\n\nAfter that, use the zero product property to set each part of the the equation to zero, so 0=3x, 0=x-3, and 0=x+1.\n\nSolve these three to get x=0, x=3, and x=-1, respectively.
58450
use the distributive property (poor u, u seem to be having a lot of trouble with your math homework tonight!! hope this helps:)\n\nthe property states that a(b+c)=ab+ac, basically you take the "a" and multiply it by the other 2, or distribute it.  say a=2, b=3, and c=1.  your equation would be 2(3+1) and, using the distributive property, make it become 6+2 which equals 8.  so its the same when your using x.  3(-4x+7)= -12x+21!!! yay!! hope this helped!
941643
3/(5x)=-4\n3=-20x\n-3/20 = x\n-0.15 =x