How far is the line on the floor where the thrower stands from a regulation dart board?
461251
The dart board is hung so that the center of the bullseye is 1.74m (5'8") from the floor. The throwing line, which is also referred to as the oche (pronounced "ockey"), the ockey (mostly in America), or the toeline, is generally located 2.37m (7'9.25") from the face of the dartboard measured horizontally. This is the recognized world standard asset by the World Darts Federation and is played as such in most areas. However, there are variations in distance and some people play from 2.29m (7'6"), 2.44m (8') and as far as 2.74m (9').\n\nWhen hanging the board care must be taken to ensure that the floor does not slope away from the wall. If it does, the height of the bullseye will not be located the correct height from the floor in relationship to where the player is standing. If this is the case, the location of the dart board on the wall will have to be adjusted either up or down whichever the case may be.
1060647
3 pointer 23' 9'' on top and 22' on the sides\n\nFree throw is 15 feet.
500588
A regulation size pool table is 4 1/2 x 9 feet.
637941
3 feet and 2 1/2 inches
866826
7 feet 9 1/4 inches.  The Center of the Bullseye is 5 ft 8 in from the floor.  Have fun!!
604691
60 feet 6 inches in professional baseball\n\nlittle league is 46 feet
320279
Hello\n\nIf you want the best i suggest you to have a look http://www.brunswick-billiards.com/\n\ngood luck with ure new cue :)
1071927
The dart board is set up the way it is in order to make the game challenging. If 20's, 19's, and 18's were right beside each other, everyone would have a 60+ point-per-dart average. Putting the one and five beside the 20, forces you to be accurate.\n\nIt also gives an advantage to darters who think before throwing. Sometimes in a game of '01, there are two sections beside each other that will both be beneficial. For example, if you have 35 left (in a double out game), you throw for the 19/3 pies. Three leaves 32, and 19 leaves 16. The double 16 and double eight are right beside each other as well.
1069162
The bull is 5'8" from the floor, the front of the board is 7'9.25" from the throwing line (the oche), and if measured diagonally the bulls eye is 9'7 3/8" from the line.
81906
First Question:\nVertical and horizontal motion are independent from each other.  Use d=(v.i)(t)+(1/2)(a)(t)^2 to find the time that the dart is in the air.  d is distance(0.32m), v.i is the initial velocity(0.00m/s vertically since it was thrown exactly horizontally), a is acceleration (9.8m/s^2: gravity) and t is the time in seconds.  Now that you have the time, use that in the equation x=vt, where x is the horizontal distance (range) that you are asked to solve for, v is the velocity(11.8m/s), and t is the time that you just found.  The answer to the problem is the x variable in this equation.\n\nSecond Question:\nI have attempted this problem for about 40 minutes and I have tried every possible combination of variables and equations, but there is not enough information to solve it.  Therefore, I have to say that it is an impossible problem.  If you figure out how to solve it, please, send me an e-mail at the address I give later and tell me how to do it.\n\nThird Question:\nFirst, find the distance that the basket is from the launch point by subtracting the two.  Then, use (v.f)^2=(v.i)^2+(2)(a)(d), where v.f is the final velocity, v.i is the initial velocity, a is the acceleration (9.8m/s^2), and d is the distance which you just found.  To  get the ball to the basket, it only needs to go the exact distance to the basket, so the final velocity is 0.00m/s.  Use the previous equation to find the intial vertical velocity.  The use v.iy=(v)sin(angle), where v.iy is the initial vertical velocity and v is the initial angular velocity, to find the velocity the ball must be launched at for each angle.\n\nPlease send me an e-mail at bge1234@yahoo.com after you turn in your work and get the solution so that I can see how your teacher did it.  In particular, tell me how to do the second question.  My ways SHOULD work as long as you don't make any calculatory errors.  I hope this helps you.
993771
its about 120 inches!
329688
www.throwingmechanics.com
1009700
Most competition pools are about 3- 3.5 feet in the shallow end. I have never really had a problem doing a flip turn in this shallow of water. I personally have hit my head on the wall on both ends. so I would practice in a big open area before you do one in a meet. try open  turns to work your way into a closed turn!
361883
46'.  See the attached link for field layout.\n\nhttp://www.prm.nau.edu/prm423/little_league_field.htm
842002
4.92126 feet or 59.0551 inches
10457
According to the NBA.com web site, "A free throw line shall be drawn (2" wide) across each of the circles indicated in the court diagram. It shall be parallel to the end line and shall be 15' from the plane of the face of the backboard."\n\nSo 15 feet.
582988
A right-handed boomerang circles towards the left, a left-handed boomerang circles towards the right. Most sport boomerangs are in the range of 2.5 to about 4 ounces. the range on most of these is between 25 - 40 yards (or meters) \nA right or left handed boomerang can be thrown with either hand, but the flight direction will depend upon the boomerang, not the thrower. \nGrasp one wing of the boomerang nearly vertically so that the other wing points forward and the flat side is away from you. The other way works also, but this way is usually easier to learn. Holding the tip by just the end between your thumb and one or two fingers, launch the boomerang forward quickly while trying more for spin than for very much force. \nThe boomerang should flatten out on its own and arc around, sometimes coming to rest a little in front of the thrower or behind the thrower, but ideally should hover in gently allowing the thrower to catch it as a sort of "boomerang sandwich" between the thrower's hands. \nOne should not throw a returning boomerang level, like a flying disc. The boomerang will turn in the direction of the top of its airfoils, so if that direction happens to be up rather than to the side it may fly high enough that the landing causes damage to the boomerang or whatever it lands on.