equation question...?
473153
Frequency is in Hertz which is cycles/second, and the period is the length of each cycle in seconds, so they are related.\n\nThe wavelength is 2.69 m/cycle and speed of sound is 346m/s.  So divide the second by the first to get cycles per second -- look at the units and see what you have to do to get cycles on top and seconds on the bottom, and cancel out meters.\n\n346/2.69 = 128.6 Hz\n\nThe period is the inverse of this, seconds/cycle \n\n1/128.6 = 0.00777 seconds
331292
See the other postings of this question.  The equation is\n\nhttp://members.aol.com/logan20/elecspon.html
978944
The equation is 258.30 X 1.09. Incase you don't have a calculator, it's $281.55
728397
You need to first balance the equation.\n\n2CO + O2 --> 2CO2\n\nUsing this you find the answer to be D.
505936
What exactly are you supposed to do with this equation?  Are you suppose to graph it, find solutions, factor or what?  You need to be more specific.
928663
Are you asking for help or an answer?\n\nTake any 2 equations and multiply all of the terms or one or both by numbers that will make one of the terms in each equation have the same coefficient. Now subtract one from the other and the term will disappear. Now take the resulting equation and do the same with it against the third. Keep doing this until you are down to one term and solve for the variable. Now substitute the variable into the equation and solve for the other variables.
538044
hmmm...very tough one!\n\nill sovle by the formula!\n       _________\n-b +- V (b^2)-4ab\n------------------\n       2a\n       _________\n-10 +-V 100+512\n------------------\n       2\n\n       _________\n-10 +-V 612\n------------------\n       2\n\n-10 +- 24.7\n------------\n     2\n\n14.7/2\n\n34.7/2\n\n(7.35, 17.35)
758594
2. The equation is (y-y1)/(y1-y2)=(x-x1)/(x1-x2)\n=>(y+2)(-2-0)=(x+1)(-1-0)\n=>(y+2)(-2)=(x+1)(-1)\n=>-y-2=-2x-2\n=>-y+2x=0=> 2x-y=0 which is the required equn.\n3.The equation is (y-4)(4+4)=(x-0)/(0-4)\n=>y-4/8 =x/-4\n=>8x=-4y+16  or,8x+4y-16=0  o4 2x+y-4=0 is the reqd.equation\n4.the eqn. is (y+3)/(-3-3)= (x+2)/(-2-0)\n=>(y+3)/-6=(x+2)/-2\n=>-6x-12=-2y-6\n=>-8x+2y-6=0 or,-4x+y-4=0 which is the equired equation
961595
umm..are you missing an equals sign somewhere or am i really dumb? how do you figure out what x is unless you have both sides of the equation?
893013
is it x-3/x+2 or (x-3)/(x+2)?\n\nlets assume the second one\n\n2x(x+2)/(x+2)=x-3\nx+2 cancels out\n\n2x=x-3\nx=-3
285662
to find an equation.......\n\ny=mx+b\n\nm=slope \nb=y-intercept
852286
if it x - 4x/(x+1) = 4/(x+1)\nthen x(x+1) - 4x = 4\nor x^2-3x + 4 = 0\n\nthis is quadratic and so 2 solutions so Megan is right\n\nyou do not have tro evaluate
561262
u jammed the equation together.\ndo u mean\n6x^3 + ( 6/x - 2 * x^2 - x/3x2 - 3x + 3)\nits really hard to see ur question. can u write it out with spaces...\nhurry up i am waiting... lol
779257
put x=6ab/(a+b)in the eq(x+3a)/(x-3a) + (x+3b)/(x-3b).\nthen you get(9ab+3a^2/3ab-3a^2)+(9ab+3b^2/3ab-3b^2)\nby bringing the common values out in numerator and denominator and cancelling the them we get\n(3b+a/b-a ) +(3a+b/a-b)\nso the answer is 2
904672
let u = x^2 + 1, then you have du = 2xdx, => dx = 1/2x du,\n\nsubstitute back you are on the way  to solve it
178765
multiple both sides of equation by x to give\n\n2x     -     1x      =    1x\n---         ---          ---\n3            x            5x\n\nwhich resolves to:\n\n2/3x -1 = 1/5\n2/3x = 1 + 1/5 = 1.2\nx=(1.2 *3)/2 = 1.8
891679
I assume your x is in the denominator, but the -c is not.\n\nOriginal equation:\na / (bx) - c = 0\n\nAdd c to both sides:\na / (bx) = c\n\nMultiply both sides by bx:\na = cbx\n\nDivide both sides by bc:\na / (bc) = x\n\nx = a / (bc)