Please tell me what is the CONJUGATE of ( 2ix - i ) and ( 1-2x )?
474735
If z = x+iy, then the complex conjugate of z is Z'= x-iy.\nIn your sum the conjugate of 2ix - i = i(2x-1).  The real component is zero and the imaginary component is 2x-1. Then the conjugate of 2ix - i must be i(1-2x).  Similarly, \nin (1-2x) the real component is 1-2x and the imaginary component is zero.  The complex conjugate is 1-2x.
1063806
Let G be a finite group and assume that for all x,y in G the equation\n\nx(yxy^{-1}) = (yxy^{-1})x\n\n this means actually that any element commutes with all its conjugates;;\n\nall conjugate elements commute could be something different.\n So can you clarify me?\n Or maybe it's all conjugates of an element commute ( between them).
920734
2xy(-15x^2y^4)+8x^2)-5/-4xy^3\n(-1/2)[-15x^2y^4+8x^2-5)/y^2\n(-1/2y^2)[-15x^2y^4+8x^2-5]
743387
Working above is good until this step:\n\n2 + 0.8x >0.9(x + 6)\n2 + 0.8x >0.9x + 5.4)\n0.1x > -3.4 ← Symbol error in this line\n\nShould read 0.1x < -3.4\nie x < -34
1024714
A1-B2; A2-B1\nC1-D2; C2-D1\nE1-F2; E2-F1\nG1-H2; G2-H1
10571
50 is right.\n{i^2 -(-1)^i | i=1,2,...}
821031
I=I1+I2; I1=int{for x=pi/6 until pi/2} of x*dx = x^2/2{for x=pi/6 until pi/2}= pi^2/9;\nI2=int{for x=pi/6 until pi/2}of  25*dx/(sinx)^2; \nLet t=tg(x), then 1/(sinx)^2=1/t^2+1 and dx=(1+t^2)*dt;\nI2=int{for t=1/sqrt(3) until +inf}of 25*t^(-2)*dt = -25/t = 25*sqrt(3)
557964
Wouldn't it be something like:\n\n2x(8) + 8s     to get rid of the denominator\n\n16x + 8s\n\nThat is as far as I think you could simplify it, because each has different variables and you can't combine something with different variables.
245176
u*(u-2)+v*(u-2)\n(u+v)*(u-2)
575490
I- + 2e- -------> I2\n\n4P + 3e-  -------------> P4\n\nthere ya go :)
433211
This is simple-\n3Mg(S) + N2(G) (2 is subscript) Yields (arrow) Mg3N2(S)
1154070
INTRO:\n\nC-\nC5-E5 (4x)\n\n   \ne:-------------|----------------------------|-------------|-5~-4~-2~-----8--7--5~--|-------|\nB:-------------|----------------------------|-------------|-6~-5~-3~-OR-10~-9~-7~--|-------|\nG:-------------|----------------------------|-------------|-5~-4~-2~----10~-9~-7~--|-------|  (2X)\nD:-------------|---0-2-3~~-2~~-0-2~-0-------|-------------|-------------10~-9~-7~--|-------|\nA:-3~~-0-------|-0---------------------xx---|-3~~-0-------|--------------8--7--5---|-----0-|\nE:-------3~~-0-|-----------------------xx---|-------3~~-0-|------------------------|-3~~---|\n\nFirst Stanza:\n\nC             em\nSige, pag kasama ka naman,\n          Am                    F\nKitang-kita ko ang ating kasiyahan\nC                  em\nSige, wag na nating pigilan\n   Am               F\nAt di magtatagal, tayo ay liligaya\n\nRefrain:\nem         Am            em   Am  \nOkey lang naman ang ating usapan\n              em   Am           F\nHindi na lang babalikan ang nakaraan\n         G\nAng nakaraan\n\nChorus:\nC                em\nAyos lang, basta't kasama \nAm(break)\nKonting alak lang,\n  F\nKahit walang pulutan\nC                em\nAng minsan, naaalala\nAm                         F\nDi magtatagal, tayo ay liligaya\n\nSecond Stanza: (do first stanza chords)\n\nSige, pagpatuloy niyo lang\nUnti-unting lunurin sa kasiyahan\nSige, pagpasensiyahan na lang\nMga pumipigil sa ating ligaya\n\n(Repeat Refrain)\n(Repeat Chorus)\n\n\nADLIB: Do Chorus chords\n\ne:--------------------------------------------------------------------------------------------------|\nB:--------------------------------------------------------------------------------------------------|\nG:----------------------------------------------------------------------------12--------------------|\nD:-10-------12-------14-------15-------14----12----12-------14-------15----------------15----14-----|\nA:----10-10----10-10----10-10----10-10----10----10----10-10----10-10----10-10----10-10----10--------|\nE:--------------------------------------------------------------------------------------------------|\n\ne:--------------------------------------------------------------------|\nB:----------------------------------------------------13-13s17-15~----|\nG:-------12-------12-------12-------12---12b~~~-12s14-----------------|\nD:-14h15----14-15----14-15----14-15-----------------------------------|\nA:--------------------------------------------------------------------|\nE:--------------------------------------------------------------------|\n\ne:----------12-15-12----------------------------12-15-12-------------------------------------------|\nB:----13-15----------13-15--(4x)-THEN-----13-15----------15p13h15br15-15---13----------------------|\nG:-12----------------------------------12-------------------------------------14-12-----12fb~~~~---|\nD:----------------------------------------------------------------------------------13-------------|\nA:-------------------------------------------------------------------------------------------------|\nE:-------------------------------------------------------------------------------------------------|\n\n(Repeat Refrain)\n(Repeat Chorus 2x)\n(intro)
796906
too complicated to type it up, sorry. look up what other ways can sec^2x  be written, and start substituing those in. good luck
746627
Cl2 + 2KI --> 2KCl + I2\n\nsingle replacement
871212
i2=i1R1/R2\ni1=R2i2/R1\n\nR1/R2=i2/i1\n\nR1/Rx = R2/R3\n(R1/R2)*R3=Rx\nRx=(i2/i1)*R3
732232
3x - 2 = 2x - 1\n\n3x - 2 - 2x = 2x - 1 - 2x\n\nx - 2 = - 1\n\nx - 2 + 2 = - 1 + 2\n\nx = 1\n\nThe answer is x = 1\n\nInsert the x value into the equation\n\n- - - - - - - - - - - - - - - - -\n\nCheck\n\n3x - 2 = 2x - 1\n\n3(1) - 2 = 2(1) - 1\n\n3 - 2 = 2 - 1\n\n1 = 1
809248
Just break it into parts. X=1x. X can be any other variable but the thing that matters is that all the variables are the same. 1x-.8x=.2x. Then .2x-2.9x= -2.7x. It simplifies down to -2.7x but there is know way to figure out what the value of X is. If the equation was x-.8x-2.9x=any thing a value for x would be possible to find but there is known and so there is no way to find the value of x on it's own.