If the C-weighting is used on a sound level meter, what will it read for a 2000 Hz sound at 40 dB?
460452
If this is your physics homework, I suggest you invest in a good text book.
719322
Sound is usually measured in decibels
464204
A frequency oscillator.
190160
Better or worse than what? I'm betting this is about a parallel-resonant L-C circuit. I don't know what the original load is, but the more you load down such a circuit (i.e., the lower the load resistance) the broader the resonance and the lower the gain and Q. This follows from a formula for Q, Q=R/sqrt(L/C) (see formula for Q_load in ref.) where w is the resonant frequency (rad/sec), R is resistance and C is capacitance.
216287
I think you're talking RF not audio and the given C value sounds just fine. We pretty much agree except for the decimal point, unless you are using a comma for the d.p.\nI get f = v/lambda = 299792458/5.7 = 5.259517E+07 Hz, \nw = 2*pi*f = 3.304652E+08 rad/s, and \nL = 1/(w^2*C) = 1/(1.092072E+17*1.9E-12) = 4.819422E-06 H or 4.819 uH.
850732
If you can measure the *frequency*, you know the wavelength.\n(As the wavelength is just the frequency divided by the speed of sound.)  I found a calculator that does this for you:\nhttp://www.sengpielaudio.com/calculator-wavelength.htm\n\nIdeally you would get an oscilloscope to measure the frequency.\n\nIf you don't have access to one, if you have a guitar tuner, you could measure the frequency (the tuner will tell you the pitch, say A#, and you can look up the frequency of that pitch in a music book).\n\nOr if you have a bunch of tuning forks or a pitch pipe, you could get an approximation.\n\nIf you have an ocilloscope, don't forget to get the precise speed of sound at your elevation (sound travels a bit faster at sea level, than if you live in, say, Denver).  (Note that the calculator link above gives you a place to enter the speed of sound where you live.)  If you're using a guitar tuner or tuning forks, they are only approximations anyway, so the exact speed of sound for your elevation won't make a difference.  \n\nP.S.  I found a reference to a sound analyzer you can get for your computer!  The software is free, but it needs a soundcard in your computer (which you probably have).  It uses the information from a microphone in your computer to give you the frequency and wavelength of the musical note.  It's kinda cheating if this is for a science-fair project ... but maybe this is what you want.\nhttp://www.relisoft.com/Freeware/freq.html
474712
At normal atmospheric pressure, the temperature dependence of the speed of a sound wave through air is approximated by the following equation:\n\nv = 331 m/s + (0.6 m/s/C)*T\nwhere T is the temperature of the air in degrees Celsius. Using this equation is used to determine the speed of a sound wave in air at a temperature of 20 degrees Celsius yields the following solution.\n\nv = 331 m/s + (0.6 m/s/C)*T \nv = 331 m/s + (0.6 m/s/C)*20 C\n\nv = 331 m/s + 12 m/s\n\nv = 343 m
930095
This question cannot be answered without knowledge of the order of the filter.\n\nEach order attentuates 20 dB/decade for frequencies above its pole.
804155
a) T = 0.5 sec\n\nb) freq = 1/T = 2 Hz\n\nc) w = 2pi*freq = 4 pi\n\nd) w^2 = k/m\nk = m*w^2 = 0.5*16 pi^2 = 8*pi^2\n\ne)  V_max = A*2*pi*f = 0.35*2*pi*2 = 1.4 pi m/sec\n\nf) A_max = A*(2*pi*f)^2 = 0.35*(2*pi*2)^2 = 5.6*pi^2 m/sec^2
416586
DeciBels below 1 Milliwatt) A measurement of power loss in decibels using 1 milliwatt as the reference point. A signal received at 1 milliwatt yields 0 dBm. A signal at .1 milliwatt is a loss of 10 dBm.\n\nOR\n\nDataBase Manager
746361
Paul's quite right -3.01(something) dB is half the power. It's based on the Bel (after Alexander Graham ) which is log10(some power / some other power) but is a bit of a big change (3 Bel is a factor of 1000) so people use the decibel (dB) which is 10*log10(P2/P1)\n30 dB =1000  -30 dB = 1/1000\n\nIn terms of your low pass filter, if P2 is the output power you get if you put a clean narrowband signal of power P1 and center frequency w into your filter then when 10*log10(P2/P1)~=-3,  w is your 3dB frequency.  \n\n\nGood luck
1152208
go to volume on your taskbar and check if its balanced in master volume diagram box
584175
This might be what you're looking for:\n\nhttp://www.speech.cs.cmu.edu/cgi-bin/cmudict/
1137756
probably somewhere in the 110-120 range
373527
Sorry to say but you will need a audio analyzer or oscilliscope to find the low end (drop off) and hi end (peak) of your system And the know how of reading both.
289044
The frequency range is generally accepted to be 20 Hz to 20,000 Hz. With the speed of sound = 334 m/s, 20 Hz has a wavelength of 16.7 m, 20,000 Hz a wavelength of 16.7 mm. (Ubergeek, the answerer in your link slipped a decimal place.)
1128179
I don't think there is a good way. You'd need to write code to filter the tone out of the microphone data, figure out the frequency, and give feedback to the user. It can be done, but it would be way more trouble than it's worth in any language I can think of. IMO you should just put up the $20 for a pocket tuner.