I need this equation balancing!!!?
462663
C4H9OH + 6O2 --> 4CO2 + 5H2O
244823
The amount (A) will be doubling, so substitute "2P" in for A. Then you can drop the "P" from each side by division and solve for t.\n\nA = Pe^(rt)\n2P = Pe^(rt)\n2 = e^(rt)\nln 2 = (rt) ln e\nln 2 = .054t (ln e = 1)\n(ln 2)/.054 = t\n(approx.) 12.836 = t\n\nDoes that sound correct? (It's been awhile since I've done these kinds of problems.)
339198
2x0 = 0\nIt'll be the same as today... :P
691296
use that at equilibrium : n.p = ni^2\nand from charge neutrality: \n\nn + NA = p + ND
741999
whats the equation or formula u need help with?
1178298
Read this: http://en.wikipedia.org/wiki/Linear_equations
115650
--5 2 0 1 -----  F L O W\n--4 2 0 1 -----  B L O W\n--1 0 2 5 -----  W O L F\n-------------------------\n1 0 4 2 7 ----- N O B L E\n\nBut still N and W value are coming same...does this problem have solution. If you have then can you please send the answer to my mail id hssiddhu@yahoo.com
268703
Use the overall rate equation: rate = k[A]^x[B]^y...\n1) define for rate1 and rate 2 with the appropriate concentrations.\n2) divide both sides (e.g. rate1/rate2 = ...\nNote that this cancels k\n3) Solve for x, y, ...  These are your respective orders.\n4) Add x, y, ...  This is your overall order.\n\nYou can get the value of k by:\n5) Plug in values of x, y, ... to either rate1 or rate2 equation.\n5) Solve for k.
1166133
Multiply both sides by R+r\nI(R+r) = E\nDistribute the I\nIR + Rr = E\nSubtract IR form each side\nRr = E - IR\nDivide both sides by R\nr = (E-IR)/R
17656
Best technique is to look for where it is unbalanced and change it so it is balanced. Repeat until it is balanced.\n\neg. We need 2 hydrogen here on the left, so go for:\n\nMg + 2HCl -> MgCl + H2\n\nNow we need another 2 as we have 2 Cl on the left and one of the right.\n\nMg + 2HCl -> 2MgCl + H2\n\nNow we need to have 2 Mg on the left as we have 2 Mg on the right. So we get:\n\n2Mg + 2HCl -> 2MgCl + H2\n\nAll balanced so that is the answer.
515516
goto purple math.com it will hopefully help you
957682
half it then times it by 2! that will give u the answer
1154468
make a common denominator\n\na/b - c/d = a*d/b*d - c*b/d*b = (a*d-c*b)/b*d
778184
PV=nRT\n\nn is doubled.\nT, V same.\nR is constant\n\n=>P has to be doubled to validate the eqn.
677826
1) is already balanced... to be more precise\n2C2H6 + 7O2 --> 4 C02 + 6H2O\n\n2) Fe2O3 + (3)H2SO4 --> Fe2(SO4)3 + (3)H2O
238182
p1    p2\n--- = ---\nq1    q2\n\n 5     2\n--- = ---\n 2    q2\n\nCross multiply,\n\n4/5
957775
Ca(OH)2 + CO2 --> C(OH) + CaO\n\nIs unbalanced..