how do i measure specific gravity of water?
470476
water weighs 8.345 lbs/gal.  Divide water weight lbs/gal by 8.345 and that's your answer.
1165265
its all to do with weight displacement and the volume of water
952124
1. The bouyant force of the water on the object is the difference in the reading, i.e. BF=(.0554-.0370)g\n                                   =0.0184gN\n\nBased on Archimedes' Principle, BF =Volume*Density of water displaced.\n \n0.018g=Volume*1000g\nVolume=.018/1000\n            =1.8*10^-5m3\n\n2. Density of Object=Mass/Volume\n                                =.0554/1.8*10^-5\n                                =3078kg/m3
864563
In part, specific gravity can be measured with a hydrometer.  You establish a range that the liquid displaces and let it bob until it comes to equalibrium.  This test can be measured at any temperature.  \n\nHowever, mass density is done in a container that is kept at a constant temprature.  The math is easy once the measurments are taken, but there is more time involved in setting up the test and bringing the whole thing to equalibrum
152321
1 gallon of water=8.33 pounds\n\n\nGallons into Pounds: Multiply the specific gravity of the liquid by 8.33* (weight in pounds of 1 gallon of water); then multiply this result by the number of gallons, to obtain the weight in pounds.
63147
Archimedes' principle states that the buoyant force experienced by a submerged object is equal to the weight of the liquid displaced by the object. Experimentally this appears in the fact that the submerged object apparently weighs less by an amount equal to the weight of the liquid displaced. The buoyant force can be expressed as:\n\nFb = W(air) - W(liquid) = dgv \n\nwhere d is the density of the liquid, g is the acceleration of gravity and v is the volume of the immersed object (or the immersed part of the body if it floats).
468283
Depends on the quantity of ice in the water, time you measure it at, etc. All depends on the precise details of the experiment.
457644
It does indeed have a higher specific gravity than fresh water.\n\nPure water has a specific gravity of 1000 kilograms per cubic meter\n\nSea water (in general) has a higher specific gravity, on average it is around 1026 kilograms per cubic meter
208900
Specific gravity.\n\nPure water has a density of 1 (the mass of 1 cubic centimetre of pure water is precisely 1 gramme), if something was twice as heavy as water (i.e. it has twice the mass) it would have a specific gravity of 2, 6 times as heavy and the SG would be 6.  If something was half as light as water it's SG would be 0.5 and so on.
1000766
The low technology approach is to use a densitometer.  This can be as simple as a hydrometer as used in the brewing industry to check for specific gravity (density).  From a measured density and a known volume and if you know the densities of both liquid components of a binary mixture you can work out the relative proportions of each using simultaneous equations and hence the concentration of one in the other.
142959
Well, actually you can.  If you know the specific volume of the material for which you wish to convert units, you can use volumetric measurements to determine mass.  Here's how you do it:\n\n# of grams * (specific volume, in L/gram) = # of liters\n\nSince specific volume isn't a very standard measure, you will probably need to convert from a measure of density (often in units of grams/cm^3).  Here's a more complete formula:\n\n# of grams * 1000 / (density in grams/cm^3) = # of liters.
613715
First find the volume of the object, i.e metal, by placing it in water and then u know the amount of water displaced.\nIf it displaces half the water than it's weight, then u know that it's specific gravity is twice that of water.
70735
The upthrust force equals the weight of the water displaced.\n\nIf d = density of the water,\nV = volume displaced,\ng = acceleration due to gravity,\n\nThe force of upthrust is,\nF = d*V*g
588958
the weight will be according 2 density of the material \n\nfor example for water 1  liter wighs 1 kg
120873
D= M/V\n\nIts a formula used to calulated to density (thinkness) of an object by dividing the Mass of an object by its volume. In this case, you can use the water displacement method that displaces (water) from its orignal volume by adding an object (marble). Using a balancer, measure and record the weight of graduated cylinder(ml), before and after the addition of water. Subtract the weight of the cylinder with water from the cyliner's weight and you will get the mass. You have to pay attention to how much the water displacement after adding the marble. record the volumes before and after (if ness). This will solve for volume. Once this is accomplished, you would have no problem finding the density.
963983
There are many ways to do this problem.  The best way to probably handle density, and perhaps mass even, is using Archimedes principle of buoyancy.  You can find a detailed discussion on www.wikipedia.com and search for Archimedes or buoyancy.  The main idea is that "the weight of the displaced fluid is directly proportional to the volume of the displaced fluid".  \n\ngood luck!
562654
Okay, I'll try this one -\n\nRun this experiment twice (or more times), each time with a piece of metal having different density.  The metal piece should be of adequate size (a sewing needle isn't going to do it), it needs to be big enough to significantly affect the temperature of the water.  You will need to know the mass of the metal (i.e., weigh it) and have a thermometer capable of reading from room temperature up through boiling or so.  Please note this is not going to give you a highly accurate answer, but can give you a ballpark idea (I'm guessing you're probably not doing this in a 500 million dollar lab).\n\nThe procedure:\n\n1)  Measure and record room temperature as T1.\n\n2)  Weigh the metal, call it M1.\n\n3)  Bring a known quantity of water (weigh it, or measure it and convert to weight, call it M2) to a temperature just short of boiling (say 180F to 200F, use the same temperature for each run of this experiment).  Record the temperature as T2, and remove the heat source (take it off the burner, etc.).\n\n4)  Drop in a metal piece at room temperature.  Allow a couple of minutes for heat to exchange.  Make sure you use \nthe same amount of time for each run of this experiment.\n\n5)  Measure and record the new temperature of the water as T3.\n\n6)  Repeat with your other metal samples.\n\nYou can now estimate the specific heat capacity for each metal.  It will not be super-accurate (heat escapes your system, and temperatures won't have completely equalized), but should give you some idea.  Just assume all temperatures did equalize and that no heat escaped for calculational purposes.\n\nSince (you are assuming) the heat which left the water went into the metal, then the product of mass, specific heat capacity, and temperature change should be the same for both the metal and the water (but in opposite directions).\n\nThis means that:\n\n(M1)(c1)(T3-T1) = (M2)(cw)(T2-T3)\n\nwhere c1 is the specific heat capacity of the metal, and cw is the specific heat capacity of water (look it up on Google to get the units you need).\n\nSolving this, you get:\n\n......(M2)(cw)(T2-T3)\nc1 = -----------------\n........(M1)(T3-T1)\n\n(sorry about the dots, I'm trying to keep everything aligned)\n\nRepeat the calculations for each of the metals.\n\nYou will need to calculate (or look up) the densities of each of the metals.  Then, graph density vs. the specific heat capacities you calculated, and see if your hypothesis is true.\n\nHave fun!