i wanna know the structere of (h4p2o6) .it is a compound from phosphorus acids?
460898
Hypophosphoric acid, H4P2O6, is a tetra basic acid, prepared from NaClO2 and red phosphorous. As to its structure, I don't know, but just try arranging all the atoms in that compound in such a way as to satisfy all their valencies.
845828
Here you go...\n\nhttp://home.planet.nl/~skok/techniques/laboratory/pka_pkb.html
143362
Yes, Zaphod is correct.\n\nYou should write, ATP and ADP - all capital letters.\nThe (P)i is sometimes written just as Pi - the letter'i' is a subscript. In this context the (P)i indicates an inorganic phosphate group.\n\nSo, adenosine TRIphosphate is hydrolysed into adenosine DIphosphate + an inorganic phosphate molecule. The interesting thing about this hydrolysis is that lots of energy is released when this particular bond is broken. This terminal phosphate bond is often described as a 'high-energy' bond.\nThe 'high-energy' bond is indicatd in diagrams as: Adenosine-P-P~P for ATP.
761702
PH3: Phosphine\nAg2SO3: Silver Phosphite\nFeCO3: Iron(II) Carbonate\nN2O4: Dinitrogen tetroxide\nPb(OH)2: Lead(II) Hydroxide
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Sure.  "Studies on the interaction of U(VI) with living cells, spores, heat-killed cells, and decomposed cells of Bacillus sphaericus by time-resolved laser fluorescence spectroscopy show that different phosphate complexes are formed. Using fresh intact cells, the U(VI) is bound to organo-phosphate groups of the bacterial cells. With increasing age of the samples, the cells begin to lyse. During this process, inorganic phosphate is released and a uranyl phosphate precipitate is formed. The characterization of the released phosphate species by Raman spectroscopy and the uranyl phosphate complexes by time-resolved laser-induced fluorescence spectroscopy (TRLFS) has shown that the bacteria release H2PO4- during decomposition which leads to the formation of UO2(H2PO4)2."
112589
If you are talking of iron(III) phosphate, then it should be FePO4. For iron(II) phosphate, it should be Fe3(PO4)2. Both are possible but iron(III) phosphate is more thermodynamically stable.
264737
Dissolve the following in 800ml distilled H2O.\n8g of NaCl\n0.2g of KCl\n1.44g of Na2HPO4\n0.24g of KH2PO4\nAdjust pH to 7.4 or 7.6 with HCl.\nAdjust volume to 1L with additional distilled H2O.
291992
A nucleotide is a chemical compound that consists of a heterocyclic base, a sugar, and one or more phosphate groups. The base is connected to the sugar via glycosidic bonds and the sugar to the phosphates via phospho-diesther bonds.
1082622
it is composed of 4 bases, each of which are composed of carbon, hydrogen, nitrogen, oxygen, and phosphorus
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http://en.wikipedia.org/wiki/PH
473164
You have to make sure all the elements on each side of the equation are equivalent. \n\n4 PH3 + 8 O2 = P4O10 + 6 H2O\n\n\nThus each side of the equation has total:\n4 Phosphorus\n16 Oxygen\n12 Hydrogen
479762
I assume you are talking about the formula and not the structure.\n\nThe molecular formula is C6H5NO5P\n\nStructure (if in case you want it too) is as follows:\n\nDraw a benzene ring (phenyl group) minus 1 hydrogen (C6H5). To the Carbon without the hydrogen, attach a Hydroxyl group (-OH). On the other Carbon positions, whether it is the ortho positions, meta positions, or para position, erase the hydrogen and attach a nitrate group (-NO2). On the Oxygen with the double bond to Nitrogen on the Nitrate group, erase one of the bonds and attach this bond to the phosphate group (-PO3).\n\nI'm not sure if you are talking about a nitro-phospho bond or a hydroxy-phosphate bond, but the difference is only 1 hydrogen.
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Phosphorus forms only oxy-hydroxides, like phosphoric acid (H3PO4), which could be written as PO(OH)3. There will always be one H2O less than theoretically possible.
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I think you answered your own question.\n\nHydrogen atoms will bond then detach when ADP is formed.  It has to do with the valence electrons and the bonds created.  \n\nThe two outermost phosphates in ATP are held to the rest of the molecule by high-energy phosphoanhydride bonds and are readily transferred. Water can be added to ATP to form ADP and inorganic phosphate (Pi). This hydrolysis of the terminal phosphate of ATP yields between 11 and 13 kcal/mole of usable energy, depending on the intracellular conditions. The large negative delta G of this reaction arises from a number of factors. Release of the terminal phosphate group removes an unfavorable repulsion between adjacent negative charges; in addition, the inorganic phosphate ion (Pi) released is stabilized by resonance and by favorable hydrogen-bond formation with water. The formation of ATP from ADP and Pi reverses the hydrolysis reaction, and it requires a coupling of this energetically unfavorable reaction to an even more favorable one.
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2 M HCl\n\nHCl is a strong acid and acids have pH less than 7\n\nH3PO4 is a weak acid\n\nNH3 is a base\n\nNaOH is a base
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Silicon (a metalloid), Oxygen, Hydrogen, Phosphorus
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well, i do not know if this is correct but I'll give it a bash.\n\nfor your sulphuric acid there it undergoes a single H dissociation to create the HSO4- conjugate base (well i suppose technically it's amphoteric but for my purposes that doesn't matter) this is an extremely stable ion since it is resonance stabilised.  Thus it resists accepting back the proton and it resists losing it's other proton, because in doing so it would lose a degree of it's resonance.\n\nIn the group 2 hydroxides mentioned they obviously have ionic bonds and not covalent therefore they cannot have have resonance structures.  The reason they lose both hydroxides or none would be if the enthalpy of solution, that is if the polarity of the water molecule and the other factors of electron affinity/ionisation is strong enough to break the M--OH bond then it will do so twice and there is no way to stabilise a single dissocation product.\n\ni think.