Sorry, another geomerty queation? Help!!!?
471483
Your question is difficult to understand.  From what I make of it, here is my answer (and I could well be wrong)\n\nI assume x and y are angle measures (in degrees)\n\nBC=2(angle A)\n6y=2(2x)\n6y=4x  (eq. 1 to be referenced below)\n\nAB+BC+AC=360 degrees\n6y+6y+4x=360\nUsing (eq. 1)\n6y+6y+6y=360\ny=20\nx=6y/4=30
471036
Why do some questions not have answers? I guess that is what you mean. I went to answer one just a minute ago and it said I need help with my geometry but that was all it said. Now how can you answer that. If the question is really vulgar I don't answer them I figure someone will.
605515
It is not exactly round, just looks that way.\n\nSee webpage below for the correct shape.
521177
dimensions don't even come into it!  Dementions do, however.  'Oh momma', is the answer.  Glad to help! (I imagine elasticity may be crucial here)
127894
I can probably help u with it....I am in grade 10, skipped grades 9...reasonably good at Algebra and Trig, Geomerticaly retarded though T,T"\ndamnedatheist@gmail.com can help u
776007
If your two figures have a ratio of similarity of 2:5, then each side of the smaller one is the side of the larger one times 2 and divided by 5.  This might lead you to believe that your area would be 100 times 2 and divided by 5 = 40.  This is, however, not the case.  If each side is times 2 and divided by 5, the total area is times 2 times 2 divided by 5 divided by 5. = 16\nThe best way to imagine this problem is by assuming your shape is a square.  How large is each side of the square if the area is 100 square units?  Each side must be 10 units, since 10 times 10 is 100 square units.  Now shrink each side by multiplying by 2 and dividing by 5.  Each side is now 4 units long.  How much area is your square?  4 times 4 is 16 square units!
857307
I think I know why your not getting the right answer..... it's the physics thing.\n\nAny Geography questions.... anybody.... Oh well.\n\nBy the way, "Nameless", who shat in your corn flakes??
459931
a nine-sided polygon???  can't wait to see other answers...
33162
Check Out This Website!! \n\nGives You Examples And Everything!! \n\nhttp://www.mathleague.com/help/geometry/geometry.htm
247013
this is not so easy to answer without doing some work: usually, when you speak of tessellation, it's more likely to deal with symmetries.\n\nHere is a good site which has a couple of interesting articles and softwares on tessellations:\n\nhttp://www.scienceu.com \n(click on the "Geometry center" icon)\n\nAnyway, I'll think better about it: it's a good question.
824775
The Area of a triangle is half the area of a square. So take one verticy and take a 90degree line from that up to the other corner.\n\nOh cr@p I'm starting to forget it all now. Too long ago.\n\nIt's something like that.
151606
if all the lines are equal in every way (duplicate) then you can put a measurment (dimension) from the existing line to a datum or border whichever you choose and then put a callout like 3@12.00' (3 lines at 12.00 feet)in the dimensionwith a arrow pointing at the line.\n\njeff
54459
I agree with you. V!\n\nBTW, wrong forum.  Try the math forum under "Science and Math."  And this isn't Jeopardy, so try giving a question to get an answer.
837293
I haven't done one of these in quite a while. \n\nWhat would you differential element be?  How about r*(dtheta)*dr?\n\nthat sort of a ds*dr   where ds depends on the radius.  Try it! \n\nNote that without the sin theta you'd get the int rdthetadr with r 0 to R and theta 0 to 2pi  You'd get the correct area of a circle.\n\nTry the intergral, see if it makes sense.  Then sketch the figure and estimate it's area to compare.  My confidence is increasing as I write this.
943161
The faster way to solve this questions is using graphical method. Draw the respective triangles (choosing appropriate scale) and you will get answer.
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
934101
what's the height?  you need the height to finish this problem\nwhat type of shape is it?  a cylinder? cone?\nbe specific or no one can help you