how to dionize the water nad how to measure the resistance of the water?
459127
First, it is spelled "deionize". \n\nde = remove\nion = charged particle\n\nSo, you are removing in ions from the water. An ion is a charged particle.  Sodium ion, Na+ or Chloride, Cl- are the most common ions in water. But you do not want them in your water in high concentration, so you deionize it.\n\nThe process is best performed in two steps.  First you would boil the water and capture the steam, allow the steam to turn back into liquid water, then repeat the process.\n\nBut this process only gets you so far. If you want the water to be truly deionized, and able to be used in a chemistry lab you will need to run it thru a resin chamber.\n\nResin or resin beads are very very small plastic like beads that have microscopic tunnels running thru them. Then inside of the tunnels have molecules that attract ions. Or type of resin will attact the positive ions another type will attract negative ions. All resin chambers have both types of resin.\n\nRob
415302
You need to use Pythagorean theorem.\nMeasure the lenght of the lotus plant which is above the water.(X)\nBend the plant to any one side until it is just submerged under the surface of water.\nMeasure the Dist. between the initial and final positions of the plant(Y)(i.e. the initial position and final position where it is submerged)\n\nLet the actual lenght be L.\nThen (L x L) = (Y x Y) + (L - X)(L - X)
742159
So lets roll...\n\nmathematically, set it up as follows:\n\nLet x = the number of kg of water @ 82degC that must be added\n\nEnergy = m * c * T\n(m = mass, c = specific heat of water, T = tempearature)\n\nNeglecting convective and radiation heat losses:\n\n (x kg)*c*(82 C) + (0.2kg)*c*(14 C) = (x + 0.2 kg) *c*(36 C)\n\ndividing by c and re-arranging:\n\n82x + 2.8 = 36x + 7.2\n\nx = 0.096 kg
928824
If we consider the volume of water is known.(If not known then use graduated cylinder and find the volume)\nMass of water can be calculated using following formula:\n\nDensity(ρ)=mass(m)/volume(V) , where\nρ is the object's density (measured in kilograms per cubic meter) \nm is the object's total mass (measured in kilograms) \nV is the object's total volume (measured in cubic meters) \n(Temp (°C)/ Density (g/cm3) \n30/ 0.9957 \n20 /0.9982 \n10 /0.9997 \n0 /0.9998 \n−10/ 0.9982 \n−20 /0.9935 \n−30/ 0.9839 )
905607
make a little "boat" that you can add weights to and float it in the different liquids.  Gradually add weight to the boat in each liquid to see how much it can hold before it sinks.  The more weight the boat can hold, the greater the density of the liquid!\n\nThis is basically a poor-man's hydrometer.
966711
The volume of the water in the cup at any moment is:\n\nV = (1/3) pi [ (Rw)^2 + (1)Rw + (1)^2 ] \n   = (1/3) pi [ (Rw)^2 + Rw + 1 ] h\n\nRw = Radius of upper part of water\nh = height of water\n\nRw / h = 2 / 6\n\n6 Rw = 2 h\n\nRw = 1/3 h\n\nSubstitute in to the volume equation\n\nV = (1/3) pi [ (1/9) h^2 + (1/3) h + 1] h\n = (1/3) pi [ (1/9) h^3 + (1/3) h^2 + h ]\n\ndV / dt  = (1/3) pi [ (1/3) h^2 + (2/3) h + 1] (dh / dt)\n\nSolve for dh /dt  and plug in the values h=4 and dV/dt = 3
470314
the specific gravity of water is 1.
88784
when the salt in in the water, it contribute ions in the water. and ions will conduct the electricity. the salt tester will test the electricity in the water, therefore, the salt compound will be measured
860053
measure the cold water temp and take a large amout of cold water than hot water and mix them .\nuse the realation mhot (Thot - T2) = mcold(T2 - Tcold)\nwhere:\nmhot = amount of hot water , Thot = hot water temp\nmcold = amount of cold water , Tcold = cold water temp.\nT2 = the temp. of water after mix.\n(considering the specific heat of water constant at this range of temp.)
11917
measure the height of the water in bucket or sink you're putting the model in BEFORE you put the model in.  Then put the model in and remeasure the water height.  Use the height and the dimensions of the vessel (bucket, sink, etc.) to calculate the volume of water that's displaced.  Using a perfectly circular or square vessel will be ideal.
701356
I think you mean OSMOSIS?\n\n1) go to www.google.com\n2) enter osmosis in the text box\n3) click the search button\n4) read
519141
you can measure the volume if you are very quick.\n\ntake a scaled glass, preferably one used in labs with a scale in mm3 or cm3, pour some water in it and read on the scale the volume of water.\nThen put the pretzel in the water and quickly read again the scale. \nThe volume of the pretzel is the difference between the second reading and the first one.\nDo it fast because the pretzel may absorb water. Or paint the pretzel with nail polish to be waterproof! :-)\n\nThe surface area is more difficult, but you can use a millimeter paper to have an approximate value. Put the pretzel on it, and draw around carefully the shape. Then count how many little squares are inside the contour lines, and multiply it with the area of one little square (= 1 mm2) :-)))\n\nHave fun!!!
751939
you can either do the math, look it up on a chart or go here:\n\nhttp://leebrewery.com/hydromet.htm\n\nand use the java-calculator.
574365
i use to work in several water treament facilities. a flow meter is calibrated with the rising and lowering of the water level. the best flow meter utilizes a float inside a pipe that is slightly larger than the float.go to www.grainger.com. they have pictures of a few flow meters
548154
Use a water level:  \nTake a long piece of hosepipe, put a short length of clear tube in each end.  \nFill with water and with a friend lay the pipe along the ground with the open ends (with the clear tube pointing upwards).\nThe water in the clear tubes at each end will be at the same height.
203892
Distill the water. The WATER comes out of the tubes, not the salt.\n    As for testing, just drink a little of it. Do you *LIKE* it?\nNo? Well you better make sure that you don't put it back in the same cup you used for collection.\nOK the water will still pass an electric current through it if it has any impurities. Completely pure water will not.\nUnless you use more than around one volt, in which case the bubbles you see escaping will be hydrogen and oxygen. That means you've gone too far with the testing part.
742795
The water provides resistance.