How to make a hologram in aluminium foil?
467081
A white light hologram is not aluminum foil.  It's a very high quality photograph.  The way the picture was taken is what makes it holographic.  The main thing for any hologram is that a LASER hits the photographic film and another copy of the same LASER hits the object you're photographing before going to the same film.  For a white light hologram they use a slit to eliminate vertical parallax.
615070
My guess would be to take a piece of paper and fringe the bottom. Like, cut it into little sections but don't cut them completely off. That's the only way I know to do it.
715337
I had to do the same thing.\n\nHere's what I did. it was real easy.\n\nGo to a craft store, get a plastic see through empty ball that you can take apart in halves. Then buy clear candle GEL. Get a wire for orbitals and beads for electrons.\n\nWhat you do is melt the candle gel in a pan until it is liquid, let it cool a little and pour it into half the ball, put your "orbitals" with the electrons in place on the gel, put the second half of the ball on, tape it shut and some tape and string to hang it up.\n\nIt takes about 5 minutes to make and is visible from all angles.
794316
one option is to freeze the water, shape it into a concave lens shape, polish it till its transparent, and use the disk like a magnifying glass on the match head.\n\ni saw this actually done on myth busters, although it didn't go very well
701866
The short answer:\n\nThe larger the hologram the larger the coherence length needed.\n\nThe holography setup can be thought of as a Michelson interferometer, since the superposition of the two split path lengths taken by the reference and object beams creates an interference pattern on the film plate\n\nFor the hologram to be created, the total path length difference between the object and reference beams must be less than the coherence length of the laser. If the path length were to deviate outside this length, then the phase would not be the same for an object ray and a corresponding reference beam ray. \n\nTherefore, as a general rule the maximum size of the object is limited to about L/N. \n\nWhere L is the length of your laser cavity. \nand N is the number of modes in your laser cavity.\n\nIn our experiment we have a HeNe laser cavity which is 40 cm operating with 3 modes. Thus our maximum object size is about 13 cm. \n\nWe can approximate the coherence length of the laser as L/N.
86452
I don't know for specific .. but here is a link for a 3d max tutorials ..they are helpful\nhttp://3dlinks.com/links.cfm?categoryid=13&subcategoryid=105
651090
There are a number of methods: the traditional powder method, magnetic powder, ninhydrin, fuming with super glue...  The best/easiest method is highly dependent on what kind of surface you're attempting to lift the print from.  You'd use one of the powders for glass, but it would be useless on paper; vice versa for ninhydrin.
805344
Here are some links to help you out http://inventors.about.com/library/inventors/bltelevision.htm\n\nGood Luck!!!
944867
You could duplicate the layer/objects and go to Objects > Transform > Reflect. Also, you could make an opacity mask overlay by making a black-to-white square and selecting both it and your object you want to mirror and in the transparency dialog click "Make Opacity Mask". With text you may need to use the "Make Outlines" feature at the bottom of the Objects list. I forget exactly where that is.\n\nI can help you specifically if you want (contact me through Yahoo Answers).
953676
Not yet...\nThe solution is to use Holographic projection.\nYour screen would be the same as a hologram, and, instead of showing a picture, would have to be "written" by "scattering vectors".  This, in theory, would allow you to see THROUGH the screen a scenery in 3D (behind!), providing the processor can trace scatering vectors fast enough.\nTo get it IN FRONT of the screen is more complex.\nLet's first get monitors "see through" in 3D!
349917
Cut out a cardboard circle, draw colors on that or glue the color wheel on it.\nPut a needle through the centre (as the axis) and use 2 forks to hold the needle.\n\nIf you need a lot of spin, tie a rope around the needle and pull
307244
I think you need to use a special cnc machine\n any way herein below some under considration useful sites\n\n•http://www.8bestsites.com/aluminum-extrusion/6/\n\n•http://www.maytecinc.com/\n\n•http://www.extrusions.com/005issue/htmls/ExtrusionAdvantages.htm\n\n•http://unisource-tech.com/Products_-_Unisource_Technolog/Aluminum_Extrusion_front_panel/aluminum_extrusion_front_panel.html\n\n•http://www.aeroext.com/\n\n•http://www.pennaluminum.com/extproc.asp\n\n•http://www.sati.com.tw/
470729
a good radar reflective surface has to be hard and flat, just like a ball bouncing back off a wall, you want the radar reflection to bounce back to the receiver with most of the strength that was sent out so you can get a good 'reflection'\nthe balloon is round so not a good reflective target, the aluminium is a metal so a good reflective material, it all depends on the line of sight as well. If the balloon was right in the middle of the radar beam width it might give of a weak sig? depends on the size of the balloon as well. A huge blimp of that material would give a better reflection than a normal size balloon. Hope this was a help.
409297
ok here is the thing\nif you are trying to calculate the thickness of a piece of paper you will need some equpment. Even though there is a lot of room for human error you still can get a fair estimate. \n\nwhat you need is 2 extrememly smooth glass plates and a lineat light source say a laser pointer. \n\nput one glass plate on a table place your paper on the side of the glass and put the other glass plate on the top of the two so that you will get a wedge between the two glasses. \n\nnow point the laser pointer perpendicular to the bottom glass plate and place a screen for reflections. you will get multiple reflections. (btw you need to know the frequency of the light emitted from the pointer.)\n\nthis is the set up\nfor calculations do a little search on air wedge interference \n\ni dont think you will need refractive indexes since you are using the same glass\nwith a little algebra you can figure it out
760371
1. The ratio of h to r is not dependent on the can being made of aluminium. The surface area is just a concept - it cannot be aluminium.\n\n2. Is a cube (assuming that no aluminium is used in forming the edges) \n\n3. You need to do this bit.\n\nFurther Investigation  - you need to do this bit , it looks as though if you limit your investigation to regular prisms that will be O.K., investigating cones would be impressive. \n\nIn so far as the wastage is concerned. If you find out what the area+wastage is for the optimally sized circular cylinders and compare with optimally sized hexagonal prisms then this may be sufficient?
240384
http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
943816
i want to make a system that gets mounter to the passenger front bumber of my car, so when im stuck in traffic and some _hole feel he deserves to drive in the emergency lane, the laser will burst a hole in his tire, and give him a reason to be in the emergency lane.  Some issues with this system is the timing of when to fire the laser, how much power the laser would be.  You dont want to accidentally fire at the wrong thing, so these issues must be addressed first.  I think thats pretty innovative.\n\nwhilst working on my M.E. senior design project, my sponsor (an artist) wanted to make a dynamic hologram depicting a full COLOR rainbow..  Yeah, I know...  It made for great jokes the entire year.