how long does a diffuison pump take to pump from atm into high vacuum?
463393
Firstly a diffusion pump can't pump from one atm. The system must be pumped down using a conventional pump first. The time it takes depends on many factors such as size and how long the system has been at atmospheric pressure and are there any leaks.
60954
It depends on usage. You know that there are two main things in pump, Head and Discharge, and we have a rating curve for these two parameter. If you want to send water to higher elevation, you can send less water (Decrease Discharge) and vise-versa.\n\nin normal case and normal usage, we have some pumps around 2 lit/sec for a very low high to around 2000 lit/sec. Pumps that are used in wells is around 30 to 50 lit/sec.\nBut I advice you to chose apropriate pump by rating curve.\nOne of the largest company in pump industries is KSB. You can find more information in their sites. Below:
413210
hi chuck, \n\n5300 lbs of pressure?  yikes!  hate to be working near that thing if it should blow!\n\nanyway the point of a bladder accumulator is to expand/contract thereby absorbing transient fluctuations in the pressure, right?  so i would expect you would want it to be somewhere near the middle of its range - too empty and it won't be full enough to compensate for pressure dips, and too full and it won't be able to expand to handle pressure spikes.  so somewhere near halfway i.e. 60% sounds reasonable to me.  \n\nthis is one of those things where a calculation of the pressure depends on a LOT of weird variables like the elastic constant of the bladder, the shape of it etc.  your best bet to get maximum damping is probably to just do an empirical trial and error sort of thing.\n\n200 Hz is well within the audible range of the human ear.  G3 on the piano (find middle A, go down an octave plus one white key - that's low G) is supposed to be tuned to 196 Hz, so your 200 cps hum should sound almost like low G.  depending on the amplitude of the pulses you could probably just listen to the pipes, or use a stethoscope if it's too quiet, and then vary the charge pressure looking for a minimum in the hum.\n\ngood luck!
989194
If you are talking about the limit on the suction side of a pump then the answer is about 34 feet. This is because due to atmospheric pressure that is all the water can be raised without the portion at the bottom of the column starting to vaporize. \n\n14.7 psia (atmospheric pressure) equals 33.9 feet of water.
439732
on my pool the vacuum hose sticks into a hole at the bottom of the skimmer box inside the pool. then the lid on top of the skimmer is pressed down into the water to the bottom of the box, now the only way the pump is going to get water is threw the vacuum hose. make sure that you fill the hose with water. place hose over the water return hole and fill, then place in skimmer hole
624128
his applies only to transfer pumps since we deliberate add a gas load to the chamber and measure the quantity of gas issuing from the mechanical pump's exhaust. The method works as long as the gas chosen is not condensable, not captured in the foreline trap, does not dissolve in oil and is present in sufficient quantity to be measured.\n\nIf the mechanical pump has gas ballast, make sure it is off. Note the chamber's steady state pressure under the gas load. Put a bubble flow meter on the pump's exhaust, and measure the flow rate in cc per sec at atmospheric pressure. Using the gas in = gas out (at constant chamber pressure) principle, the gas entering must equal the measured throughput. If more precise numbers are needed, measure the exhaust gas temperature and the barometric pressure and re-calculate the quantity of gas at STP with Boyle's and Charles' law combined:\n\n(P1 x V1) / T1 = (P2 x V2) / T2\n\nExample The measured flow of gas at the pump's exhaust is 2.3 atm cc per minute from a chamber at a measured pressure of 1.4 x 10-5 torr. The exhaust gas temperature is 32°C and the barometric pressure is 750 mm Hg. What is the (corrected) effective pumping speed from the chamber?\n\n2.3 atm cc per min = (2.3/60) atm cc per sec\n= (2.3/60) x (760/1000) torr.liter per sec\n= (2.3/60)x (760/1000) torr.liter per sec at 750 torr and 32 °C\n= (2.3/60) x (760/1000) x (750/760) x (273/305) torr.liter per sec at STP\n= 0.0257 torr.liter per sec\nEffective pumping speed\n= (0.0257/1.4x10-5) liter per sec\n= 1838 liter per sec
1104947
I think that you can go to sleep, with the water on medium pressure.  We have the same pool and it took about 6 hours to fill on high pressure.
779880
Depending of the flow rate and the definition of "high head" it could be a multistage centrifugal or a positive displacement pump. \n\nIf given only one choice then a positive displacement pump would be the likely choice but not necessarily the best choice. \n\nFor example: to pump 10 gallons a minute up to 1500 psig, a positive plunger pump would be the likely choice. However, to pump 1000 gpm up to 1000 psig, a multistage centrifugal would probably be the best choice.\n\nMore information is needed to make a good recommendation.
273013
Go to the link below and it has an online calculator for pump affinity laws.  \n\nThe one you are interested in is:\n\n(pressure at old speed)/(pressure at new speed) =\n\n(old speed/new speed)^2\n\nIncrease the speed (RPM) of the pump 10%, and the discharge pressure goes up 21%    \n( 1.10^2)
769857
I also use DVD Decrypter and it takes about 20-25 minutes.\n\nWhen I 1st started it took about an hour... it all depends on computer and DVD speed on your computer.
491824
plug in the numbers and solve\n\n3 atm x v = (0.0821) x (.0832) x (400 degrees K)\n\n3v = 2.732288\nV = 0.917626666666666
969517
Use the clausius-clapeyron equation for this one.\n\nln (P/Po) = (delta H/R ) (1/To - 1/T)\n\nPo is one atm at To = 61.7 C based on the info in the question.  T is 36.2C.  This formula requires absolute temps, so convert to K.\n\nSo:\n\nln (P/1 atm) = 31400/8.314 (1/334.8K - 1/309.3K)\n\nIf I didn't fat finger the calculator P = 0.39 atm.\n\nHope it helps.
114610
i agree with an intermediate tank , also u can use multistage centrifugal pump , with pipes greater at least one size specially for suction , ur hight is not critical , we can go to 250 m .
3535
well, (heh),\n\nlifting a mass m of anything a height h against the force of gravity requires an amount of energy that is equal to E = mgh, where g is the acceleration of gravity - 9.8 m/s^2.  \n\nthe power comes from dividing by how long it takes to do this - power is energy / time.  so P = mgh/t.  that means the pump requires that much power to do so.\n\nso, if you decrease h in the above equation, the power goes down.  it is a linear relationship, so if you halve the height over which you are pumping, you halve the amount of power required.\n\nnote that this ignores the frictional nature of water, which is reasonable if the water is not moving very fast in the pump or pipes.  if it is, you have a more complicated problem.
828458
Maybe a week. I had this done a long time ago and it didn't take long at all.
573941
first off if you have an above ground pool to operate the (litleman) aka bottom of the pool vacume you have to fill the vac hose with water the you take out the fiters basket and their is a hole when the filter is on you will feel some suction that is whear you hook up the vacume hose after it has been totaly imerged in water and it is filled with water but turn the filter off before sticking the vacume hose in the hole in the bottom of the skimmer where you just took the basket out the turn the pump on the vacume may get stuck and you may need to help in out a little. To add filter sand i can not give you adaquate instructions because all filters vary so some take more sand some take less sand. But i hope i helped you out.    \n\np.s if you need more help email me at efmc1101@yahoo.com or contact your local pool store
1074976
The output of the pump will be in psi's.There should be a pressure regulator on the pump with an adjustment screw.Screwing it in increases psi and out decreases psi.