How do I Calculate and graph the number of worker minutes needed for each additional croissant.?
470658
The above answer is basically correct.  Plug in a few more values, such as (21,1543.5), (22,1694), and so on for a few more values of the graph.
1083459
Use this formula:\n\nSn=n/2[t1+tn]\n\nwhere\nSn --> ur required sum\nn --> no. of terms in the given progression \nt1 --> first term (in ur case: 3)\ntn -->last term (in ur case: 803)
912176
Rate = 2 houses / (4 workers * 3 days)\nRate = 1/6 house per worker per day.\n\n3 workers * n days * 1/6 house/worker = 5 houses\nn = 5 * 6 / 3\nn = 30 / 3\nn = 10 days
713684
Try this:\n\nAnnualized hours / Number of work days in pay period =\nPer diem hours * Actual number of days to pay * Hourly average = Dollar amount of pay
1076827
4:00\n\nEST = CST + 1 hour
414725
t=time it takes in hours to do the job\nSusan does half the job in an hour\nJaime does a third\nThey have one job to do\nso 1/2t+1/3t=1\nfinding like denominators, we get\n3/6t+2/6t=1\n5/6t=1\n5t=6\nt=6/5\n\nThat's roughly 1 hour, 12 min
701612
For this you need to figure out the lowest common multiple of the 3 numbers:\n\nLCM(15, 28, 40)\n\nPrime factorization:\n15 = 3 x 5\n28 = 2 x 2 x 7\n40 = 2 x 2 x 2 x 5\n\nFiguring out the maximum number of time each number appears in each factorization you get:\nLCM = 2 x 2 x 2 x 3 x 5 x 7 = 840 minutes\n\n840 minutes / 60 minutes/hr = 14 hours\n\nIf they were together at 9 a.m. on Monday, they will be together again at 11 p.m. on Monday.\n\nThey will then be together every 14 hours after that...\n\n9 a.m. Monday\n11 p.m. Monday\n1 p.m. Tuesday\n3 a.m. Wednesday\n5 p.m. Wednesday\n7 a.m. Thursday\n9 p.m. Thursday\n11 a.m. Friday\n\nSo the time they will be together on Friday is 11 a.m.\n\nI sure feel sorry for the drivers that get absolutely no breaks at all and have to drive constantly for days on end.  :)
775593
Load the Analysis Toolpak add-in and then use this formula, it's shorter:\n\n=A1/GCD(A1, B1)&":"&B1/GCD(A1, B1)
474038
there are 60 seconds in a minute so if you have 27 minutes you multiply, 27 x 60 gives you 1620 seconds, divided by 18 seconds, gives your 90  there is a calculator located on your computer go to start, programs, accessories, calculator.... check out the answer for yourself... it's the best way to learn how to do the math
77604
I worked in a beef processing plant in the state of Washington, and they ran 250 head an hour through there.  Multiply that x 24 (plant operates 24 hours a day) x seven and you can get a pretty good idea.
204627
http://redcort.com/timeclock.html\n\nIf you are looking for a simple solution use a template for Microsoft Excel:\n\nhttp://office.microsoft.com/en-us/templates/TC011201441033.aspx
365741
I think all you have to do is plug in a few values for C to get a graph.  For example, try 0, 5, 10, 15, 20.  It's continuous so you can connect the dots.\n\n(0,0), (5,87.5), (10,350), (15,787.5), (20,1400)\n\nTotal labor for 20 is 1400.
289834
power tell u how many time to mutiply the orginal number \n\nfor example\n  y^2 = y time y\n  y^3 = y time y time y\n  .......
1121923
to see the production levels over a certain period of time
262244
Let H be the nunber of hens. Assume rate of food consumption per hen is equal for all hens. Then, if X days feed left at decision point and r is feed consumption per hen per day:\n\nSell: (H-75)*r*(X+20) is feed left\n\nBuy:  (H+100)*r*(X-15) is feed left\n\nSo (H-75)(X+20)= (H+100)(X-15)\n\nHe has to know how much feed he has to say what he says. So if we know X we can find H
1062962
so Joe is taking 20 hrs and Fred is taking 32 hours. If these two are to be given work, then 20/52% should be given to Fred and 32/52% should be given to Joe to get things done in time ( I mean both finishes at the same time)\n\nSo Joe's portion of work would be 64% and Fred wil do 36% work...\n\nsimple !
1132233
this question will require calcs using logarithm.\nhence will take time