First of all I am no good at chemistry. The names of the compounds FeS, NaCl, NaOH, and Pb(CN)2 all end in the
457655
Iron (II) SulfIDE\n\nSodium ChlorIDE\n\nSodium HydroxIDE\n\nand Lead...umm...something. *lol*\n\nThe answer is evidently (A). =D\n\n\n\nPS okay, so yea, someone already wrote what i wrote when i was typing it. sorry!
839410
This compound is an amine.  You can identify it by the NH2 (amine group) at the end.  You did a fair job with the structure considering the limits of the text here.  I am sure you realize that two of your carbons do not have the correct number of bonds.
864677
carbon monoxide = CO\nIron (II) Chlorate= Fe(ClO3)2\nLead (IV) oxide = PbO4\nNitric acid = HNO3\nSulfuric Acid = H2SO4\n\nall numbers are subscripts.
590452
(NH4)2 SO4  + (FeSO4)2 + 2H2O____(\nNH4)2SO4Fe2(SO4)3.24H2O\n\nAmmonium ferric sulphate
832296
A) Ag2O (s) >>> 2 Ag(s) + 1/2 O2 (g)\nB) Nickel (II) Carbonate >>>>>Nickel (II) Oxide + [Carbon Dioxide], NiCO3 -> NiO + CO2\nC) Ammonium Nitrate >>>>> Dinitrogen monoxide + Water,  \nC does not balance as is... but this does:\nNH3NO3 -> N2O +  1.5 H2O + 0.5 O2\n\n48) A) 2 HCl (aq) + Ca (OH)2 (aq) >>>> 2 H2O + CaCl2 (aq)\nB) 3 Ag2 SO4 (aq) + 2 AlCl3 (aq) >>>> 6 AgCl (s) + Al2(SO4)3 (aq) (silver chloride is a precipitate)\nC) H2C2O4 (aq) + 2 KOH (aq)>>>> 2 H2O + K2C2O4 (aq)\nD) CdBr2 (aq) + Na2S (Aq)>>> CdS(s) + 2 NaBr (aq) (Cadium sulfide is a precipitate)\n50 Write a Balanced equation for the complete combustion of each compound:\nA) Butene (C4H8): C4H8 + 6 O2 -> 4 CO2 + 4 H2O\nB) Octane (C8H18): C8H18 + 12.5 O2 -> 8 CO2 + 9 H2O\nC) glycerol (C3H8O3): C3H8O3 + 3.5 O2 -> 3 CO2 + 4 H2O\nD) Acetone (C3H6O): C3H6O + 4 O2 -> 3 CO2 + 3 H2O\n52: Complete these:\nA) Al (s) + H2SO4 (aq)>>>> AlSO4(aq) + H2(g)\nB) 2 HCl (aq) + Ba (OH)2 (aq)>>>> BaCl2 (aq) + 2 H2O\nC) Au (s) + 3 HCl (aq) >>>>> AuCl3(aq) + 1.5 H2 (g)\n54) EACH IS BALANCED BUT "INCORRECT", so correct these:\nA) Cl-2 + NaI(aq) >>> NaCl2(aq) + I-\nB) NH3(aq) >>> N- + H+3\nC) Na (s) + O2(g) >>NaO2(s)\nD) 2Mg (s) + H2SO4(aq) >>Mg2SO4(aq) + H2(g)\nE) MgCl2(aq) + Ca(OH)2(s) >>> Mg(OH)2(s) + CaCl2(aq)\nF) H2 (g) + Cl2 (g) >> H2Cl2 (g)
821226
1. sodium hypochlorite\n2. hydrogen chloride\n3. concentrated sulphuric acid\n4. oxidising it, for example with potassium manganate(VII).\n\nIf you've done the other 96, well done!
387399
Pb2+ + Cl- ---> PbCl2\n\nWe know that the lead in Pb(NO3)2 has to have a 2+ charge because a nitrate ion has a 1- charge, so two of them is a 2- charge.  The entire compound must have no charge, so a 2+ charge is assigned to the lead. \n\nBoth compounds Pb(NO3)2 and NaCl dissociate (they are both soluble), and because nitrate and Na+ ions are always soluble, they can be ignored in a net ionic equation.
748280
PH3:                           Phosphine\nAg2SO3:                    Silver Phosphite\nFeCO3:                      Iron(II) Carbonate\nN2O4:                        Dinitrogen tetroxide\nPb(OH)2:                   Lead(II) Hydroxide
64690
NA2SO4,KOH,AGCL,CA(NO3)2 ARE SOLUBLE.AND HG2BR2 AND CDS IS INSOLUBLE.
15061
K2Cr2O7 + 2Pb(C2H3O2)2 + H2O --> 2PbCrO4 + 2HC2H3O2 + 2KC2H3O2
599313
Refer to the electrohemical series (see source).  The answer depends on whether the conditions are such that iron is oxidized to Fe2+ or Fe3+.  In the case of iron metal being oxidized to Fe2+, the correct order is:\n\nMg, Zn, Fe, Sn, Pb
56554
While I don't particularly feel like doing the work for you, this site gives information on why all of the elements are named as they are.\n\nhttp://www.ktf-split.hr/periodni/en/
1051035
1-. NaCl + H2O Sodium Chloride ( table salt )\n2-. NaSO3 +2 H2O Sodium Sulfate ( or sulfite I always forget which is the 3 and which is the 4 )\n3-. NaC2H3O2 + H2O ( I'm guessing.  You will want to check your periodic table for the charges on this one )\n4-.NH4Cl + H2O.  Ammonium Chloride\n5-.NSO2 + 3H2O\n6-. not sure\n\nI presume you are working salt solutions.  Ammonia was never my strong suit. I'm positive about the first two.
913568
Zn(NO2)2; Co(HSO3)3; HgF; Al2(CO3)3; Cs2C2O4; Ba(ClO)2; SnBr2; Mg(HSO3)2.
964369
Huge order. Let's see how far it can be served.\n\n1. Monoatomic negative ions: take the element name (sometimes shortened) and add "-ide" (as in hydride, nitride, oxide, sulphide, phosphide, chloride...)\nPositive ions: element-name, charge (if several charges are possible), ion (sodium ion, iron II ion...)\n\n2. Polyatomic ions:\nComplexes with various ligands list the ligands and the central ion/atom.\nOxygen as ligands has its own nomenclature, depending on oxidation state. E.g. Sulphate, sulphite, perchlorate, chlorate, chlorite, hypochlorite...\n\n3. Binary molecular compounds: Halogen, oxygen and sulphur compounds usually have the correspondent "-ide" as if you had ionic compounds. Usually the more electropositive element is used as center.\n\n4. Acids: Oxygen acids have a similar nomenclature to oxygen ions.
761689
If Fe(OH)3 and NaOH get together they have no reason to combine. They are both hydroxides and sodium and iron are both metals. Although sodium hydroxide is a strong reagent, both metals want to give away electrons and there is no other reactant to give them to.
966082
1 - NH4OH\n2 - PbO\n3 - KBr\n4 - PCl5 (five)\n5 - Al(NO3)3\n6 - Ba3(PO4)2  (not sure)\n7 - C4H10\n8 - Sn(OH)4\n9 - NH4NO3\n10 - Li3P\n11 - Ba3ClO2   (not sure)\n12 - MgSO3