How do I find the Equation of a line perpendicular to -1/3x-4y=2 passing throughp=(2,-4)?
460260
First you need to know that the slope of two perpendicular lines are negative reciprocals of each other.\n\nSo given your first line of -1/3x - 4y = 2, find the slope of this line by changing to the slope/intercept form.\n\ny = -1/12x + 2\n\nThe slope is -1/12, so the slope of a line perpendicular to this line has a slope of 12.\n\nNext it's easiest to use the point slope form of a line to write the new equation.  Given a point and the slope, the formula allows you to write the equation for the line.\n\ny - y1 = m(x - x1)\n\nwhere m is the slope and (x1, y1) are the coordinates you are given.\n\nIn this case\ny - (-4) = 12(x - 2)\n\nor y + 4 = 12(x - 2)
978534
subtrac 3y and 4 from boside\ny^2-3y-4\nfactor\n(y-4)(y+1)\ny= 4 and -1
96323
2 lines are parallel if their slopes are equal. 2 lines are perpendicular if the product of their slopes is -1 (or if the slope of one line is the negative reciprocal of the other)\nFrom your given, the slope of the first equation is 3/5\nusing y = mx + b (m is the slope)\nThe slope of the second equation is -5/3. Notice that their product is -1, so the lines are perpendicular.
1101023
First you must find the slope of the line with the points (6,3) and (7,7).  Slope equals Y1-Y2 / X1-X2.  So that equation with the numbers substituted is Slope equals 3-7 Divided by 6-7 or -4/-1 or 4.  That is a slope of four.  \n\nA perpendicular line's slope is the opposite reciprocal or -1/4.
179699
The equation of a line is y=mx+c\nHere when x = 6, m = 4/3, y = -2\nTherefore c = y-mx = -2 - (4/3)*6 = -10\n\nHence y = (4/3)x-10\n\nHope this helps!
734729
problem1\n\nsince you have said P (4,-5) is a point on the function, then the corresponding point will be (4,-5) .. :)\n\nproblem2\n\nfor a line having y intercept 3 will have following form\n\ny =mx+3\n\nwhere m is the slope of the line. Now it is said to be perpendicular to y =2/3x-4. So slope for this is 2/3\n\nsince slopes of two lines perpendicular to each other if multiplied yields -1\n\nm X 2/3 = -1\n\nor m = -3/2\n\nso the required line will be\n\ny = -3/2 x+3\n\nproblem3\n\nf(x) = 1/x^2 -2x-8\n\nto make the f(x0<0, let us try with some arbitary values of x\n\nif x = 1, f(x) = -9\nif x=2, f(x) = -11.75\nif x = 0, f(x) = infinite (due to 1/x^2)\nif x = -1, f(x) = -5\nif x= -2, f(x)= -3.75\nif x=-3, f(x) = -1.88889\nif x=-4, f(x) = 0.0625\n\nHope this helps
777827
y=-4x+k is the first line slope =-4= m\n \nsecond line has a slope-1/m=-1/-4=1/4\n\nsecond line : y=(1/4)*x+C , but C=0 because line passes through the origin\n\nline  is thus y=x/4\n\n\nsubstitute v+1 for y and v for x in this equation\n\nv+1=v/4\n\nv=-4/3
1134198
Slope of the given line AB= [2-3]/[-2-2]= 1/4\n\nSlope of the required line= -1/4.\n\nThe required equation y= (-1/4)*x + constant.\n\nInfact this is the equation for family of lines which met the above condition.
233128
y=-x+0.4\nm'=-1\nm=1 (perpendicular)\n\ny=x+b\n10=4+b\nb=6\nanswer: m=1, b=6\n\nm of 5x+5y=2 is -1 as you see, and multiplication of the slopes of two perpendicular lines equal to -1 therefore the slope of perpendecular line is +1
941588
Identify the slope of each line and compare the values.\nIf the slopes are the same then they are parallel.\nIf the slopes give a value of -1 when multiplied together, then they are perpendicular.\nIf the slopes differ from that about, then they are neither.\n\nBring the y value to a unit value of one.\n(1) Slope 6∙4 and 6∙4, so it's parallel.\n(2) Slope ½ and ? , second equation is unclear.\nThe slopes are probably 3/2 and -3/2, if so, then they are perpendicular.\n(3) Slope -1/3 and 1/3, so the lines are perpendicular.
961745
the slope of the line perpendicular to that line would be the inverse negative of the slope of x-3y = 8\n\n(x-8)/3 = y\n\nthe slope = x/3, so the perpendicular line has a slope of -3x\n\ny = mx + b\n\nm = -3\n\nx = 5\n\ny = -4\n\n-4 = -15 + b\n\nb = 11 \n\ny = -3x + 11
908156
slope of  6x – 3y=10 is: 6/3=2\nso slope of perpendicular line is: -1/2\nand the equation is:\ny+6 = -1/2 ( x -2) !
724767
This cannot be done since if it's perpendicular to y = -3, which is a horizontal line, it would be a vertical line and vertical lines have no slope.\n\nPS Its equation would be x = 1
341751
Using pt. slope equation:\n\nY=mX+B where m=slope = 2/3, b=intercept, in this case = 0,\n\nY = 2/3 * x + 0\n\ny=2x/3.\n\n3y=2x\n3y-2x = 0.\n2x-3y=0
829618
1.find the midpoint of BC usingthe midpoint formula\n(x1+x2/2,y1+y2/2) say (x,y)\n2.find the slope os BC using theformula \ny2/y1/x2-x1 say m\n3.the slope of the perpendicular bisector will be the negative inverse of this -1/m\n4. now use the point (x,y) and slope (-1/m) and find the equation of the perpendicular bisector
753792
You can find the slope of 2x - 3y = 12, call it m.  The line perpendicular to it will have slope -1/m.  Since you know the slope (-1/m) of your line and a point on it (2,8) you can solve to find the equation.\n\nSTEP 1 -- Find -1/m\n\n2x - 3y = 12\n-3y = -2x - 12\ny = 2/3 x - 4  << so m=2/3, and -1/m = -3/2\n\nSTEP 2 -- Use slope -3/2 and point (2,8) to find the equation\n\nRecall that (y-y0)=m(x-x0), so we get the following:\n\ny - 8 = -3/2 (x - 2)\ny - 8 = -3/2 x + 3\ny = -3/2 x + 11\n\nSo, the equation you are looking for is y = -3/2 x + 11\n\n~ ♥ ~
80737
sigh...you shouldn't wait this late to do your homework...and you should study more, but i'll show you how to do this one - hopefully it'll help you with the other ones you posted lol.\n\nyou know the line is 2x-3y=18\n\nfind the slope of this line since you'll use it later:\n\n2x-3y=18\n-3y=18-2x\ny=-6+(2/3)x\n\nthus the slope is 2/3, since in that equation, y=b+mx, m=2/3.\n\nnow the line you want to find is perpendicular to this.  meaning the slope is the negative reciprocal.\n\nnew slope = -1/m = -1/(2/3) = -3/2\n\nnow you found the new m.  plug this into the given slope-interceot form equation and you get:\n\ny=mx+b\ny=-(3/2)x+b\n\nnow since you know that this line passes through point (-1,8), plug these y and x values into the equation and solve for b:\n\ny=-(3/2)x+b\n8=-(3/2)(-1)+b\n8=3/2+b\nb=8-3/2\nb=16/2-3/2\nb=13/2\n\nnow plug b back into your equation and you get:\n\ny=-(3/2)x+b\ny=-(3/2)x+13/2\n\nwhich is your answer :)  now go try and solve the rest of your problems by yourself.\n\n[[edit]]\n\nand don't listen to the guy above me - he's wrong and i don't like beer.