How do you build a solar heater to heat water in a styrofoam cup at least 3 degrees?
466868
try painting the cup black and setting it in the sun, perhaps setting it on a mirror
166194
About 350 watts heat is to be dissipated from an area of about 0.5 meter square and limiting surface temperature below 100 degree celsius.
678334
This is a bit complicated but you might try this....\n\nStart with a centralized heat source, preferably electrical, so it should remain fairly constant.  You will need three thermometers, each to be held in place by their own stands.  Place a block or bar of metal so that it does not quite touch the heat source, and in contact with its thermometer at the far end.  Place a wooden bowl with water (a metal or glass container would taint your study ) near the heat source with its thermometer just in the water.  Place your last thermometer the same distance from the heat source, thus testing the heat conductivity of air.  If you had access to more thermometers and stands, you could place them at various points in a line from the heat source.  You will notice that the last thermometer will by far have the lowest readings.
503195
what size are we talking here? small use some of that packing material and use a exacto (sp) knife to form, shape sides roof , put it together with something that won't melt the Styrofoam
1165181
It's been awhile since i've done this but i'll give it my best\n\nFirst off, the first energy you need to calculate is the energy needed to raise the temperature of ice to 0 degrees C. so...\n\n(12.37 g)(.48 cal/deg/g)(35 deg) = +207.816 cal\n\nWhen the ice changes to water you have a positive heat of fusion. So...\n\n(12.37 g)(80 cal/g) = 989.6 cal\n\nNext you have to raise the water temperature from 0 degrees C to 100 degrees C. So...\n\n(12.37 g)(1.0 cal/deg/g)(100 deg) = 1237 cal\n\nNext you have the positive heat of vaporization.\n\n(12.37 g)(540 cal/g) = 6679.9 cal\n\nNext once it is steam, you must raise the temperature from 100 degrees C to 146 degrees C. So...\n\n(12.37g)(.48 cal/deg/g)(46 deg) = 273.1296 cal.\n\nNow that you have the energy for each step add them together.\n\n207.816 + 989.6 + 1237 + 6679.9 + 273.1296 = 9387.45 cal\n\nI'm pretty confident in my breakdown but it defintely wouldn't hurt to have someone else check it
789204
Give the site below a try! Good luck.\n\n<This is for fun only. If you are actually trying to do this to heat your house or use for power, I don't think you can do that. You would need commercially made cells, but you could set up the system yourself.>
725257
Well that's a good one though, I suppose you can't do that. What you think is simple is too complicated. We have a lot of problems maintaining the  temperature as a constant. You simply cant stabilize it. It will keep oscillating. You can still do it, but they'll be expensive and hard. It all depends on the surrounding temperature, where you put it, what the jugs are made up of(material) and so on.  But, you can maintain the temperature within a certain range. Contact your thermodynamics teacher for assistance.
874138
if u want to make a good sciences project and u want it easy take a cup and add watter and then grab a piece of cardboard and and cover the glass and then turn the cup upside down and then the water wont fall ok
914327
A fired heater will probably be the cheapest way.  You could try electric heaters (you can buy the elements from water heaters at appliance repair shops - they use 240V), but the electricity cost will probably be more than for the fuel (if you were thinking gas/petrol, maybe propane or natural gas will be cheaper).  I also don't know if I'd be comfortable putting electric elements in 3500 gallons of biodiesel - I've seen a few kitchen fires, and burning oil is never pleasant.\n\nYou could also consider solar heating - it would be cheaper in the long run, but any efficient installation would have to involve heating panels, piping, pumps, and a lot of water.  You could try painting your tank black, but that probably won't work very well unless you live in the desert or high plains.
115623
Should be able to do it, as the water will boil at about 212 degrees and will keep the paper below its approx 450 degree flashpoint. The part of the bag not cooled by the water might burn though
505556
you have to look for it at the saturated watter boards or the saturated water graph, then the temperature will tbe the saturation temperature, according to my graph, the temperature would be...\n\n83.79ºC
867420
about heating maching bring a thick wire and wrap it around a spoon then the tips connect them into electric source (big one) dont do it alone it gets really hot ...ok\nabout the cooling machine i dont know
477927
my containers are hot
904712
Try this: http://worldwind.arc.nasa.gov/ it's made by Nasa and is hot!!
402260
couple of choises. pool heater or a pool heat pump. or even a solar heater. try this link and see if any would work for you.\n\nhttp://www.swimmingpoolsetc.com/poolheaters.htm\nhttp://www.swimmingpoolsetc.com/pool-heat-pumps.htm\nhttp://www.swimmingpoolsetc.com/solar-heater-ig-pools.htm\nhttp://www.swimmingpoolsetc.com/solar-heater-ag-pools.htm
830153
Well, you could use a turtle shell to boil the water. Cover the top with leaves and mud to seal it, leaving a hole for a bamboo vent to collect the steam. Using bamboo as tubing, that would also help the condensation, create long enough tubes to have the water condensate and then fall into another turtle shell or coconut shells.
1029936
A solar still big enough to supply the needs of one person is an incredibly small, compact package.  It does NOT have to heat the sea water to anywhere near the boiling point, only a few degrees above ambient temperature to where the rate of evaporation is sufficient to cause fresh water to collect on the inside of a clear plastic cover and trickle down into a gutter where it is collected for drinking.  This principle has been known and used for at least 300 years.\n\nHere's a sample of what you get googling "solar still":\nhttp://www.solaqua.com/solstilbas.html