how rockets get slefpropelled in space??
461281
The above answers are pretty much correct, but no one has really given you a direct answer.\n\nSpaceship propulsion is quite simple in essentials, just remember that momentum is always conserved.\n\nMomentum of ship in direction x = Momentum of gas exhaust from engine in opposite direction (-x)\n\nThe total momentum of the exhaust is equal and opposite to the momentum of the spacecraft.
646077
I've built a model rocket with a M80 in the nose cone.  The fuse was placed directly in the end of the motor which normally launches the parachute.  When the second stage motor ended, it lit the fuse on the M80 and it blew up - simple and reliable.  But it was launched straight up and reached its apogee at 500 feet before exploding - (it was actually one the happiest moments in my life because we had worked hard on a number of launches building up to this final successful launch).\n\nI'd suggest getting some experience launching vertically first (it's safer and you won't trash your $$ electronics every launch)  Just make sure the center of pressure is behind the center of gravity so it doesn't go unstable.  You CAN have a lot of fun launching model rockets vertically. \n\nLaunching a rocket horizontally is really risky (I've done it before and I wouldn't want to do it again), especially if there is wind (rocket will track into the wind).  If a single fin falls off (because the glue broke), the missile will go unstable and it may come back at you! (no kidding)  \n\nThe electronics/servos the home hobbyist is likely to buy or build is unlikely to have the control response speed to prevent the rocket from going unstable - it takes thousands of dollars (and an engineering degree) to build and test a stable model rocket that can fly horizontally under any kind of control - even nation-states have a difficult time doing this, not to mention the potential liability you (or your parents) will have. (fire, injury, whathaveyou) \n\nIf you're really interested in building horizontal flying missles, it would be better if you enrolled in an aeronautical program in college to learn how to do it.  You could get paid for doing stuff like this if you got your degree and went to work for General Dynamics or Boeing doing cruise missile design.
912321
Are you sure those are really rockets?  There are not that many launched, you know, and the tend to go up quite quickly so unless you are down range from a rocket launch pad, you probably never seen a rocket.\n\nI tend to have a hunch that what you are talking about can be contrails from high altitude airliners.  If this is so, and then they can be in all directions (while rockets are essentially launched towards the east to get an extra nude from the earth's rotation) this is not smoke, it is just the engine exhaust, a mix of carbon dioxide and water vapor from the combustion of hydrocarbon fuel, that cools in the very chilly air at those altitude (10000 m and above).  The ice crystals form and look just like a cloud that can dissipate at varying rate depending on how humid it is up there.
682353
It works like this...\n\nA satellite is launched into space at a very specific angle.  It is carried to a specific height and gravity keeps it where they want it the same way it keeps the moon in check.  The object is in a continuous state of free fall but it doesn't fall from the sky (OK, when they get the math wrong some do fall from the sky.) because of it's inertial mass.  The inertial mass (newtons 2nd law) causes the satellite to move away from the earth and out into space... the gravity of the earth keeps pulling it down so that it can't get away.   \n\nLemme see if I can clarify.  draw a circle, better yet, get an orange, apple, round object.  The satellite is a few hundred miles above the earth... now get a pencil, pen, ruler, whatever.  put the orange on a desk and hold the pencil over top of the orange earth.  make sure it is pointing side to side and not straight up above our earth.  This is the path of the satellite when there is no gravity, it wants to go in a straight line away from the planet... You can see that it would get further away from the surface the more it moves away from the center.\n___\n.O\n\nEarth's gravity pulls it back toward the earth, counteracting the satellites natural motion, and when all the math is figured out you can keep it at an exact height above the earth and if your really good you can make it geosynchronous (always over the same spot)
262383
It requires enough thrust to escape Earth's Gravity. \n\nIt is said that a spacecraft uses more than 70% of the fuel on board in the first 20 minutes of the mission just to be able to "enter space", i.e. escape Earth's powerful gravitational pull.
1721
If you start a fire in zero gravity then (as long as it is not against the wall of the space craft) it will burn as a sphere.  The fire needs oxygen so will expand, however, as it expands more heat is lost, and the fire may go out.\n\nSo it would be a hot, glowing sphere that expands and then goes out.\n\nOf course if it is contact with the wall or something then the nature of the fire depend on the fuels available, etc.
1023626
the science between the movement of a rocket ship is governed in the third law (i think). The law of action and reaction.\nactually the air acts as a friction. but in space the rocket will fly faster because space is frictionless, due to no air.\nthe flame coming out from its butt's side is opposite to where the rocket is moving.\nthe flame is going < < < = = = \nwhile the movement of the rocket is = = = > > >\nLaw of action and reaction.
899952
If you throw a ball across the room, it will stop accelerating as it leaves your hand.\n\nThe whole ball (including anything inside it) will carry on travelling according to the force you applied, but its direction will be altered by gravity (which is still pulling it downwards).\n\nThe shape it's flight makes is called a 'parabola', and this same shape happens whenever gravity stops an object from travelling upwards (even a purely vertical thrust will lead to some sideways movement; this is called 'Coriolis effect'), and makes it travel downwards instead.\n\nBecause the outside of the object is always travelling in the same direction as the objects inside it, they don't press on each other (their relative 'G' is zero). Because 'weight' is actually just relative pressure, the objects will seem weightless.\n\nThe American and Soviet 'vomit comets' are large transport aeroplanes with strengthened wing roots and a padded interior.\n\nThe pilot will first initiate a steep dive, and pull up out of this as if he is going to 'loop the loop'. Pulling up from a dive like this will press the passengers against the floor, so they seem heavier than normal; typically 3-4 times their normal weight (3-4G).\n\nAs the plane comes up from the dive, this extra 'G' will decrease, until it reaches zero, and the passengers feel 'weightless'. \n\nAt that point, the aeroplane is travelling upwards under the momentum of its own weight, like a roller coaster. If the pilot kept the engines accelerating, they would drive the plane upwards and press against the passengers, but by cutting the engines, the plane is left to rise like a thrown ball. It travels in a parabolic curve, but the passengers don't (they tend to bounce around in zigzags, perform somersaults for the camera, lose their sense of direction and start puking)\n\nAbout 40 seconds of weightlessness can be simulated in this way, because that's how long it takes for the plane to stop rising, and return to its downward dive speed. If it was left to dive for too long, pulling out of the dive would rip the wings off.\n\n(if that happened, the passengers would experience weightlessness (or very nearly; air resistance would slow the plane, but not them) all the way to the ground, but they wouldn't be able to tell us about it afterwards)
378440
carnival baloons reach a specific hieght at which they stop verical movement and start to float around losing gas and eventually coming down to earth. i dont know why hey stop movung up but my guess is that they stop when the thickness of air at that altitude is less than the density of helium.
78972
Very large rockets produce enough thrust to overcome the Earth's gravity. Eventually, they go so high up, that even with the rockets turned off, the Earth's gravity no longer pulls it back down.  Everytime you jump up, you're essentially 'leaving' the Earth's gravity, so think of it as 'jumping' with so much force that you keep going right into space.  Sorry for the watered-down explanation. You could probably get a more scientific responce by typing 'rocket propulsion' into a search engine.
1159027
...mass of the planet it is "escaping" from, and the mass of the rocket.\n\nIf there are other large objects close enough to exert a gravitational influence on the rocket, these may need to be factored in as well.
628522
Uses the gravitational pulll of the planet to speed up the object and also change its trajectory... Look at what they do with satilites that they send into deep space.
902957
Aerial.  Its from space.
361256
The liquid oxygen goes in the smaller, top tank inside the external tank.  To provide better stability in rockets, one should always put the densest (and heaviest) fuel at the top.\n\nThe propellant mixture in each SRB motor consists of an ammonium perchlorate (oxidizer, 69.6 % by weight), aluminum (fuel, 16 %), iron oxide (a catalyst, 0.4 %), a polymer (such as PBAN or HTPB - a binder that holds the mixture together, 12.04 %), and an epoxy curing agent (1.96 %).
104839
When an object is launched under the influence of only a uniform gravitational force field, it is said to follow a projectile motion. Under ideal condition, the path it traces is parabolic. There is catch here – if the initial velocity is equal or more than the escape velocity then the object will simply vanish into space i.e. leave earth!\n\nImagine if the launch angle from the horizontal is “theta” and initial velocity is “U” then you can easily compute vertical (Uv) and horizontal (Uh) components of it. The Uv will be equal to U x Sin(theta) and Uh will be equal to U x Cos(theta). Now by using Uv you can compute the max height it will reach and the total time it will take to go up and return to ground. With this round trip time in hand, you can easily compute the max horizontal distance it will cover before hitting the ground.\n\nAll these calculation assume ideal conditions like no wind resistance etc.
506920
You would agree that, the projectile motion is nothing but a trajectory. It is explained as, the path traced by an object in space.\n\nTherefore when we study the motion of a rocket in space, yes we can call it a projectile.
701384
The present momentum of the spaceship is \np1 = 7600 * 125 = 950000 kgm/s.\nLet us say the momentum of the gas expelled is p2. Then\np2 / p1 = tan 30.\nHence, p2 = p1 tan 30 = 548482 kgm/s.\nThe mass of the gas expelled = p2 / v = 171.4 kg.\nThis is only an approximation because the mass of the space ship is changing during the expulsion of the gas. Also the gas is expelled perpendicular to the motion of the ship at all times, which will keep the tangential velocity constant. To take these into account, you should also know the mass rate at which the gas is being ejected. Since this is not given - and also since the mass of the gas is negligible as compared to the mass of the rocket, I suppose the approximation is justified.