How many diffrent 5-digit zip codes are possible if no gigit is repeated?
469878
10 * 9 * 8 * 7 * 6 = 30240 combinations
532000
How about 9! 51, 52, 55, 56, 57, 58, 59, 60, 61
582349
2,555,555,555,550,000,000,000,000,000\nthats 2 then ten 5s then sixteen 0s
177153
There is no flaw as long as you recognize that .99999 repeats forever.  If you were to end it at some point and subtract, then as a previous poster said, you'd actually get 8.99....1.  But since it repeats, there is always another 9 and so it works.\n\nAnd consider this - if .9999999repeating did NOT equal 1, then there would be another number between them.  What would that number be?\n\n~~~~~~~~~~~~~~~~~~~~\nNo, the number in question is not infinitessimal, it doesn't exist.  You can never get to the end of the string of nines to try and squeeze another number in there :)
228700
1.   The Zone Improvement Plan, otherwise known as ZIP code.\n2.   Telephone area codes.\n3.   Roman Numerals.\n4.   The Fibonacci sequence\n5.   Natural numbers: the positive (or if you prefer, non-negative) integers {1, 2, …}\n6.   Negative numbers,also known as integers\n7.   Rational numbers (fractions)\n8.   Irrational numbers (for example, the square root of 2)\n9.   Real numbers, which encompass both rational and irrational numbers.\n10.  Imaginary numbers, or complex numbers (such as the square root of -1 which is represented by the letter i).
1080209
check this out\nhttp://www.zipzoomfly.com/jsp/ProductDetail.jsp?ProductCode=252950
1064447
Area Codes or Zip Codes?\nType into your browser, Area Codes or the other.  It's free for all in the US.
1029989
The answer is 120 "lock combos" if I've understood your question.\n\nYou can't use a number twice, but different orders are allowed, but a combo must end in 0. So, for example, 2450 and 5240 are valid combo numbers. If that's the case, the answer is 120.\n\nYou must choose 3 distinct numbers in any order from the numbers 2 4 5 6 7 8. You then add a 0 on the end of these 3 to get a  valid 4 digit combo number. The number of ways of doing this is simply 6x5x4 = 120. Note, if digits could be used more than once it would 6x6x6 = 216.\nAs far as using formulas go, you would use the permutation formula: \n\nnPr = n!/(n-r)! In your case n= 6 and r = 3\n\n6P3 = 6x5x4 = 120
431988
The U.S. has tons of zip codes. It depends on what city or mail delivery area you live in.
939247
No, but you can work it out on paper. I know because I did it once. You have five letters, so there should be 25 combinations, Of course, as two letters are the same that would make it 20. I think. Just give it a go. It's always more fun to work these tings out yourself.
1081387
here is one\n024331\nassuming that the 2&3 numbers are the only evens\nassuming only one one\nassuming  2&3 numbers are not same numbers\nassuming only one set of repeating numbers\nalso 024551, 024771, 024991, 026331, 026551, 026771, 026991, 028331, 028551, 028771, 028991, 042331, 042551, 042771, 042991, 046331, 046551, 046771, 046991, and so on.
1093828
You can break down your set of valid passwords into:\n- X = Passwords with 5 alphanumeric chars\n- Y = Passwords with 6 alphanumeric chars\n- Z = Passwords with 7 alphanumeric chars\nNow how X, Y, and Z are disjoint sets, so if we can count the size of X, Y and Z separately, we just need to add the sizes to get the set of valid passwords.\n\nHow do we count X?  Each of the five characters of X can be one of 36 characters (10 numbers, and 26 characters).  So the total possible number is 36*36*36*36*36, since there are 36 "choices" for each location.  This is 36^5.\n\nSimilarly, we can count Y and Z to be 36^6 and 36^7.\n\nSo the total number of passwords is: 36^5+36^6+36^7.
164812
If it does not contain a decimal place I guess:\n5?
232325
the are 9 1-digit number; 90 2-digits number = 180 digits, we already have 189; 900 3-digit number=2700 digits; we have 2899 digits;\n\n9000 4-digit number= 36000 more digits; total=38,899; \nwe still have 40,000 - 38889 =1,111 digits to go, coming from 5-digit numbers. Dividing by 5, we need 222 5-digit numbers. Startingt from 10000, we are in 10221 and we have 222*5+38889 =39,999. So we need the FIRST digit of the next number (That number being 10,222) So the 40,000 digit of the series is 1.\nVery nice problem. Thanks
655775
USA postcodes, known in the US as Zip codes are five digits long and broadly run south to north in nine bands.  Zip codes starting with 0 or 1 are on the East Coast and Zip codes starting with 9 are on the West Coast.  In general within a band lower numbers are farther south.  So 98888 is way north of 90001.\n\nThe bands and the south to north numbering is not always followed, as the Zip Codes were designed to incorporate the old zone numbers that larger citys had.  So, Los Angeles, has zip codes starting 900xx, while San Diego, about a hundred miles south, has zip codes starting with 920xx.\n\nJust about any five digit number from 00001 to 99999 is likely to be a Zip Code.
606295
If you mean the phone code, it is 1.\nUS zip code???? ummmmmmmmm. naaaaaaaaaaaaaaah.
1159911
Here in Canada, the postal code goes as follows\nLetter-number-letter (space) number-letter-number\nfor example\nZ9Z 9Z9\n\nI believe in America it is a 5 number system\nBeverly Hills California...zip code is 90210