Can anyone help me with my quantum mechanics assignment, please?
466161
time average means sum of hte probability density over a certain time interval divided by the time interval. and it will be a function of position since the wave function is a function of position AND time.\nso u have W(x,t) where W is the wave function and x is position t is time. you integrate it with respect to time from a starting time to an ending time (not that hard, its just integral of e^-iwt, i think) and then divide by the time interval. and ya. i dunno.\n\nhope that helps. let meknow if u need more help. later
1061308
Quite frankly I find it fascinating.  I haven't had the opportunity to study up as much as I'd like on the new ideas coming forth, but I would like to suggest a movie to you; it's called "What the *bleep* do we know?".  There are many credited scientists and mathematicians and other experts in their fields who discuss quantum mechanics in a way that your everyday Joe can understand.  Although a good chunk of it shows how the ideas relate back to the body/self.  Some of these ideas are portrayed in a "story" about a deaf photographer--which is an excellent idea, considering much of quantum mechanics deals with the idea of an "ultimate observer".   One warning, though; the movie does, at one point, all but mathematically dispel the notion of "God"...\n\nHope you like it!
635193
Drop me your email. I will do one and send it to you. Easier than explaining...just look at my formulas...will only take a minute...really...\n\nCheck your email\n\nIs what I gave you what you want?
836806
Are you referencing the time dependency of the Schroedinger equation?  Or are you implying quantization of time?
964345
by using de broglies wave eqtn u can solve it\nthe eqtn\nwavelength=h/mv\n\nm=h/(v*wavelength) for one atom\nbut for 1 mole(avogadro no.(N) of atoms)\nm=h*N/(v*wavelength)\n\nnow v=3*10^7 m.sec^-1 (1% of speed of light)\nh=6.625810^-34 J.sec\nwavelength=3.31*10^-3*10^-12 meters\nN=6.023*10^23\n\nnow by substituting above values\nm=4*10^-2 Kg =40gr\n\nThis is the atomic weight of Calcium
799202
for those questions, all you have to do is translate them into the equation\ncheck chemtutor.com for hellp, it explains it much clearer than i can
437983
I would reccomend a book called "Schroedinger's Cat" and another called "Schoedinger's Kittens".  Maybe they are the same book, but I read the latter.  It is an easy to read piece of literature about Quantum theory.  \n\nMy girlfriend also has encouraged me to read "Mr Tompkins in Paperback" which covers a wide variety of Science topics, including Quantum theory.  \n\nGood luck and have fun.
753727
Looks as though this is some kind of assignment. No? Maybe you ought to think it all through and provide your own answers. You can do it!!\n\nChow!!
610467
Go to your local physics professor. If you are correct, (s)he will no doubt help you to get it published. If you are incorrect, (s)he should be willing to show you where your math is off.
837785
hi\np=(qm)/n\ny=x+(b/m) or x+(bq/np)
501994
http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/posfe.html#c3\n\nThe link above may be of some help. Input the values you want or need.
834583
You can use the Rydberg formula, which relates the reciprocal of the wavelength of the photon absorbed or emitted to the squares of the reciprocals of the principal quantum numbers.\n\n1/wavelength = R(1/n_l^2 - 1/n_u^2)\n\nSo, for the listed values of n, \n\nA.  1/w = R(1/ 2^2 - 1/4^2) = 0.1875R\nB.  1/w = -0.75R\nC.  1/w = 0.21R\nD.  1/w = -0.04861R\n\nSince energy and frequency are proportional to 1/wavelength,\nlooks like the order is D, A, C, B.
34932
how about quantum information theory?  this encompasses some of the cool research that's going on currently, including quantum entanglement, teleportation and the 'quantum parallelism' that you get by using quantum bits in a superposition of states.  \n\nhttp://www.imaph.tu-bs.de/qi/concepts.html\nhttp://www.qubit.org/index.html\nhttp://plato.stanford.edu/entries/qt-entangle/\n\ngood luck!
1033843
e=mc^2\n\ne (energy)=m (mass) times c (the speed of light) squared
475865
It's quantum electro dynamics - QED for short
159765
Well i would be quite happy to take up the assignment,\nbut id like to get more info abt ur requirement.\nplz mail me if u are intrested\n\ncleptoshalom@yahoo.com
43146
Use Kirchoff's laws.  Read page at link then follow the link "example."\n\nhttp://www.pa.msu.edu/courses/1997spring/PHY232/lectures/kirchoff/kirchoff.html\n\n--- \nadded:\nwow! pjw, that UTex link is a cool online tutorial!