if an object of any mass is thrown up at any velocity,what happens before it comes down?
457512
It stopes before comes down
805410
Let me ask you a question. \n\n If I shot a bullet straight up, and then dropped a feather..  would the falling object move faster than the one going upwards?
59102
If the bullet is fired in the horizontel direction, both object will reach ground at the same time.. because they are reaching ground due to vertical gravitational acceleration only which is same for both.\n\nBut if the bullet is fired in the downward direction and at an angle downwards, it will reach grounf first because it is having a initial velocity as well whereas the initial velocity for the other object is zero.. The reverse holds true if the bullet is fired upwards.
730176
All of these questions can be answered using Newton's 2nd Law:\n\n"The rate of change of momentum of a body is proportional to the resultant force acting on the body and is in the same direction."\n\nThus, if a box has a net force of 0 N, it will not accelerate. This means that its velocity will not change. Note that this DOES NOT necessarily mean that its velocity is 0, just that the velocity is not changing.\n\nIf the box has a net force of 15 N, then it will accelerate in the direction of the applied force. Note that the magnitude of the acceleration is dependant upon the mass of the box.\n\nSo, to answer your two questions:\n\nA) Yes, it will have constant velocity.\n\nB) Yes, the box will accelerate.
287006
Terminal Velocity.  It depends on the weight of the object because it is based on gravity.  If there is force applied to the object then it could travel faster for moments then gravity would slow it down.
546523
Well according to Relativity Theory it is known that an Object of Mass (M) travelling at Velocity (V) would have a Change in Mass: ie\n        \n          Mass at Velocity (V)  = ( Rest Mass) / sqrt(1-(V^2/C^2) ) \n\nTherefore if we replace C^2 by V^2 then the Whole Equation becomes Infinite. in other Words You cannot Travel at the Speed of Light, because according to Physics an Object cannot have Infinite Mass.
860846
Force = 60 N.\nMass = 3 kg\nTime = 10 s\n\nAn object's change in momentum, Δp equals the Impulse, I on the object. I = ∫F dt = Ft. \n\nΔp = I = Ft = (60 N) * 10 s = 600 Ns\n\nAssuming the object started at rest,\np (initial) = mv = (3 kg) (0 m/s) = 0 Ns\nΔp = 600 Ns\np (final) = 600 Ns\n\np (final) = mv = (3 kg) * v(final)\nv(final) = (600 Ns) / (3 kg) = 200 m/s\nΔv = v(final) - v (initial) = 200 m/s - 0 m/s = 200 m/s\n\nThe object's change in momentum was 600 Ns (kg * m/s).\nThe object's change in velocity, assuming it started from rest, was 200 m/s.
1054120
Assuming you meant to say "100 meters per second",\nyes, the object would.\n\nAfter the object is released it undergoes a fairly constant acceleration downward as its Kinetic Energy is converted into gravitational Potential Energy.  After the object reaches its highest point and begins to fall back down again (assuming no air resistance), all of the PE it gained on the way up is converted back into KE so when it gets back its original starting height, it has the same speed as when it left.\nThe law of conservation of energy at work.
756287
Yes, Kaplan is correct.  While the ball is being thrown it is accelerating (not necessarily at 15 m/s2) up to a velocity of 15 m/s.  Once the ball is released the only force acting on it is gravity at -9.8 m/s2.
1131554
Yes. \n\n(All of the following bars air resistance.)\n\nA trajectory would be the path that it follows. If an object has no initial velocity, it would fall straight down.\n\nBut say it did have an initial velocity. Let's say you threw a football. Does the football ever stop in mid-flight and fall straight down? No; it has an initial velocity, a sideways trajectory. If something has an initial velocity sideways, it's trajectory will look like an upside down parabola (ie y= - x^2) once gravity is applied.\n\nHope that helps.
985453
When it's falling and reaches a velocity where the force from drag is equal to the force from gravity. Simply put, it doesn't speed up any more.
698592
The acceleration due to gravity is independent of the mass of the object.\n\n The speed of any mass thrown up will decreases by an amount 9.8 m/s per second. \n\nIf the initial speed is u, then its kinetic energy is ½ m u u. Its potential energy is zero.\n\nThe total energy is½ m u u + zero = ½ m u u.\n\nAs it goes up its kinetic energy decreases whereas its potential energy increases keeping the total energy same.\n\nWhen it goes up through ‘h’ meter,  its total energy is [ ½ m u u + mgh].\n\n[ ½ m u u + mgh] = ½ m v v.\n\nm u u + 2mgh = m v v. \n\nCancelling m on both sides,\n\nu u + 2gh = v v\n\nThus we have the familiar equation vv = uu + 2gh.\n\nWhen the ball reaches 9 m its speed becomes zero.\n\nHence,  v v = 2 x 9.8 x 9\n\nSolving we get v = 13. 3 m/s . \n\nThe speed with which it is thrown up is 13. 3 m/s.\n\nWhen the height is 8 m, now having known the initial speed we use the same equation for solving for uu.\nvv = uu + 2gh\n\n13.3 x 13.3 = uu + 2 x 9.8 x 8 .\n\nSolving for u, we get  u u = 196 or u = 4.43 m/s.\n\nThe problem can be viewed in other way.\n\nWhen the ball is at its heighest point namely at 9m its potential energy is mgh. where h is 9m\n\nWhen it falls through one meter its kinetic enery increases and potetial energy decreases , keeping the total energy as the same.\n\nmg x 9 = ½  m vv + mg x 8.\n\nOr mg ( 9-8) = ½  mvv \n\ng x 1 = v  v/2\n\n2 g = v v. \n\nv v = 2 x 9.8 = 19.6 (m/s)^2. \n\nv = 4.43 m/s.\n\n Note that the mass gets cancelled and hence we need not know the mass of the ball.
709444
Acceleration on any free falling object is always equal to the force of gravity, which is 9.8m/s^2.\n\nSince acceleration is a vector quantity, it can be denoted as positive or negative. In this case, since the object is moving downwar and not up, acceleration would be negative and so equal to -9.8m/s^2.\n\nGood luck.
823412
Velocity (or speed) defines the time it takes to cover a distance from point a to point b.\n\nV=d/t  >\nV (velocity)\nd (distance in meters)\nt (time in segonds)\nm/s (meters per segonds)\n\nAcceleration is a variation in the velocity, wether it increases OR decreases.\n\nie: gravity on earth has an acceleration of \n-9.98m/s  (notice the minus)  so if an object is falling down on earth it will accelerate towards the ground because the object is subject to that force of gravity, \nif it is thrown up it will slow down as it goes up because the same force of gravity affects the speed of the object, when it has slowed down completely it has reached 0m/s and will start to fall again and accelerate untill it reaches a surface that will stop it from falling further (ground, floor, your hand, etc)\n\nThe formula for acceleration is:\n\na= V1-V2/t \n\nor acceleration = initial velocity-final velocity divided by time.\nif it had an initial velocity that is different from the final velocity there was an acceleration, (or change in velocity).
655182
For maybe a half a second. The ball will initially go as fast as the car, but, because the mass of the ball has so less mass in comparison to the car, it will quickly lose momentum and slow down and fall to the ground.
1151411
Objects of different mass do fall at the same speed, but air resistance hinders this fact.  For example, if you drop a bowling ball and a feather at the same time on the Earth, obviously the bowling ball falls faster. \n\nHowever, on the moon, when the astronauts dropped a feather and a bowling ball, they hit the ground at the same time. \n\nIt would seem that the bowling ball should fall faster since gravity is pulling on it with more force. But, with the more mass, comes more inertia, which meas it resists being pulled more than the feather. So, the feather is pulled less, but it resists less as well, so because of that, they will fall at the same time. The relationship between the force of pull and the object's inertial compensates exactly so that all objects fall at the same rate.
404829
the only thing that leads to the misconception that heavier things fall faster is most likely due to air resistance. In a vacuum, all objects fall under the same acceleration/gravity.