The graph of a polynomial function is far from the x-axis when x increases in value. True or false?
472136
False. For example: F(x)=x^2 increases for x>0.\n\nF(x)=x^3 always increases.
736099
plot the coordinates then do the vertical line test.  if the vertical line intersects more than two points on the graph then it is not a function.  each set of coordinates you have listed are functions (i free hand it with no graphing paper or calc) so forgive me if im wrong.  also refer to www.coolmath.com. it is a good site for breaking down math
140428
x\n\nthe answer below is just for voltage - see my graph above - it is quite accurate. here it is again, larger: X
761741
No. In fact, you shouldn't even be putting infinity anywhere on a normal graph of tan. The only way you can show that is by adding an asymptote and putting an arrow on the curve showing it goes to infinity.\nOn the y axis, just put a few numbers (1,2,3) to correspond to some x values. That way you can tell it is doubled correctly.
788027
The graph is a V.  From the 0,0 draw a line with slope = 1 to the right of the y axis and draw a line with slope = -1 to the right of the y axis.  For y<|x|.  All you have to do is shade in the area below the V.  If y>|X|, all you have to do is shade in the area above the V.  Less than, shade below; greater than, shade above.  That should answer all the questions you've submitted.\n\nAnd no, absolute values do not form parabolas.  Some do, not all.  Like y = sqrt[|x-1|].  This forms 2 graphs each going away from each other.\nNice going NerdyKid.  You're not a nerd, you're a dork.
579155
The first one isn't, because it's undefined when x=4 (assuming the (x-4) is the denominator, not just the x)\n\nThe second one is; it's a horizontal line with no breaks or holes.
82793
I can think of two possible things you're asking:\n\n1. Are you asking about continuity?\nIf so, then the curve is broken when the denominator of a function equals zero. Also, the curve will be broken if it has a vertical asymtote. That is, when the graph of the curve gets closer and closer to an x-value without ever getting to it (thus, the y-value approaches infinity). An example of a graph with a vertical asymtote is y=sin(x).\n\n[edit: oops, I meant tan(x) instead of sin(x)]\n\n2. Are you refering to graphing a domain/range with inequalities?\nIf so, then use a solid line when the answer includes the graph of the function. That is, your function has an equal sign (=), greater than or equal sign, or less than or equal sign. If your answer does not include the function, use a dashed line (for >, <, or not equal to sign).\nFor example:\ny=x would have a solid line.\ny (is not equal to) x would have a dashed line with all the rest of the area of your plot shaded.\ny>x would have a dashed line with everything above shaded.\ny (greater than or equal to) x would have a solid line with everything above shaded.
923293
1. If you pass a vertical line down the graph, and it only passes through the function once, then ya, it is function.  If it passes through more than once, then it is not a function.\n\n2. Isolate x
935707
x<0\nso for all values of x, x will be a negative. when you absolute x, the positive absolute will always be bigger than the negative x
476794
This graph helps us to show what happens when a quantity y is inversely proportional to another quantity x.\n\nAgain, it shows us that a computer algorithm implementing y=(1/x) for the order of efficiency of the algorithm..
205031
There will be a vertical asymptote at x=-2, assuming you meant to put "x+2" in parenthesis. When x values get increasingly closer to negaitve two from the right, the graph approaches infinity. When the x values approach -2 from the left, the graph approaches negative infinity.\n\nSimilarly, there is also a horizontal asymptote at y=3. As x approaches infinity, the graph approaches 3 (1/infinity + 3 = 3). Also, as x approaches negative infinity, the graph also approaches 3 (1/negative infinitive + 3 = 3).
958822
well, a square root function looks like...half of a bridge or an arc. it starts at (0,0) and gradually rises for infinity. there's your basic shape.  now i am not exactly sure on your equation, but if the +3 is INSIDE the squareroot, then you would shift the graph to the LEFT 3. (yes, the opposite) but if it is OUTSIDE the squareroot, then you would shift it UP 3.
853022
It should be a function because one x input value gives only one y output value. Try the vertical-line test. But the function does not have an inverse though.
791991
Given a(x^2) + bx + c as the quadratic the c determines the vertical shift of the graph. If c = 0 you get a parabola whose vertex touches (0,0). If c > 0 the graph shifts up to have a y-intercept of (0,c). If c <0 you get the same result but (0,c) falls below the x-axis.
637834
this is paralell to the x axis. It`s 7
978117
The graph of f(x) is a line, which means it can't have an asymptote.\n\ng(x) = log5(2x) should have a vertical asymptote x = 0.
448269
The domain is all real numbers x, except for x=0.\n\nYou just have to remember that the exponential function and all polynomial functions are defined on the entire real line, that is there domain is all real numbers. Therefore, the only problem that occurs is with the operation of division by x. Since you cannot divide by 0, x can never be 0. All other values are fine though.\n\nIN RESPONSE to what urtimud said below: sure you can take e^0, but if you let x=0 you are taking e^(-1/0) which is undefined. Therefore, x=0 is not in the domain of this real valued function. Note that e is being raised to the ((x^2-1)/x) power, because your screen may have chopped off that last part.