when a charged particle moving inside a transverse electric field then the path traced by it is?
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When an object is thrown from a top of a tower in a horizontal direction, it is having a horizontal uniform motion and an accelerated downward motion due to the gravitational force. The path is a parabola.\n\nSimilarly, the charged particle is having a uniform motion and an accelerated motion due to the electrical force perpendicular to the uniform motion.  \n\nTherefore, the path is a parabola.
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the law states that if a wire with length L carries a current i, then a magnetic field is induced...  the magnetic field b (at a point r away) should be induced.... \n\nthe vector notations like dL (hat) and r (hat) are important because the direction of your induced magnetic field is determined using vecor algebra.... you can use the right thumb rule for that too.... the direction of the induced magnetic field  depends on the direction of your current that pass through the wire...\n\nnotice the magnetic field (look at the formula) is a vector quantity since length vector is crossed to the displacement vector....\n(vector cross vector is vector\nand vector dot vector is scalar)
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C.....because of the inductive effect, the charge will pass on to the other neutral body inductively.
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An equipotential surface of an electrostatic field is given by:\n\nE = -∇Φ\n\nwhere φ(x,y,z) is the scalar field representing the electric potential at a given point. The symbol ∇represent the derivative of the scalar field Φ which results in a vector field that is called the gradient.\n\nSo for example, the electrostatic field of a point charge q is given by:\n\nE = (kq/r^2) ř\n\nwhere k is Coulomb's constant, and is = 1/4πε\nε is the Permittivity of free space\nand ř is the unit vector in the radial direction in polar coordinates\n\nHere we see that the equipotential surface of the electrostatic field of a point charge are "spheres" surrounding the charge q, and its strength decreases by 1/r^2. At some distance r from the charge q, the electrostatic field E has the same strength everywhere on the surface of the sphere.
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I'm assuming that the current is not changing with time other than the initial turn-on transient.\n\nWhen the current has reached a steady state (didn't say reached zero, but some final state), you are in the area of electromagnetics called electro/magnetostatics and the magnetic and electric fields are uncoupled. For the situation that you describe (I'm assuming no stationary charges external to the wire), the Electric Field Density is zero.\n\nYou might be tempted to use Gauss' Law to find the Electric Field from an individual electron as it moved down the wire, but the summation at any particular point in space from all charges moving in the wire will sum to zero.\n\nWhen the current is first turned on you will have a changing magnetic field and therefore an electric field. However, that electric field will die away rapidly.
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Colloquially, a trajectory is the path in space followed by a body. Such a body can be a projectile, for example. Strictly speaking trajectory refers only to that portion of the path during which the body undergoes a transient movement between practically stationary or repetitive motions or until the body eventually stops moving. In a wider sense it also includes the meaning of orbit - the path of a planet, an asteroid or comet, for example. A trajectory can be described mathematically by the geometry of the path or as the position of the object over time.\nclick here:http://en.wikipedia.org/w/index.php?title=Projectile_motion&redirect=no\nhttp://en.wikipedia.org/wiki/Trajectory
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I think they're looking for "wave" too.\n\nBut the answer could also be "charged."  The electron beam is focused using magnets;  this can be done because a moving charged particle has a magnetic field, and thus can be manipulated by external magnetic fields.
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According to the Lorentz Force law:\n\nForce=q[E + v x B]\n\nso if there's no Electric field it will just be q(v x B) where q is the charge of the particle
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I hope you are familiar with atomic theory if not get familiar and come back to this. as an electron moves it creates a wake much like a boat moving through water this wake is called a magnetic line of force. if a nother electron is encountered by this wake it will be influenced by it like a surfer on a wave. an electromagnetic fiel is the area of influence of these waves. in most materials the electrons are moving in many different directions, hence the sum field is random and weak. however if most of the electrons are coerced into a uniform movement the individual lines become coherent and combine to provide a polarised field with a stronger magnetic influence moving this fiel across an object will cause the electrons in it to surf and produce an electric current. however these surfing electrons will produce a magnetic field that is the opposite of the field they are surfing on.
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A field or flux field
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In physics, the Lorentz force is the force exerted on a charged particle in an electromagnetic field. The particle will experience a force due to electric field of qE, and due to the magnetic field qv × B. Combined they give the Lorentz force equation (or law):\n\n F= q(E + v x B)\nwhere\n\nF is the force (in newtons) \nE is the electric field (in volts per meter) \nB is the magnetic field (in webers per square meter, or equivalently, teslas) \nq is the electric charge of the particle (in coulombs) \nv is the instantaneous velocity of the particle (in meters per second) \nand × is the cross product. \nThus a positively charged particle will be accelerated in the same linear orientation as the E field, but will curve perpendicularly to the B field according to the right-hand rule.
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Your question is interesting BUT reversed !\n\nIt is the the transverse and longitudinal waves of electricity and magnetism that CAUSE light NOT the reverse.\n\nAccording to electromagnetic theory as proposed by Maxwell, a moving electric charge will "induce" a perpendicular magnetic wave which will then induce a perpendicular electric wave and so forth.\n\nOur retinas percieve this phenomena as LIGHT.
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In physics, a magnetic field is an entity produced by moving electric charges (electric currents) that exerts a force on other moving charges. (The quantum-mechanical spin of a particle produces magnetic fields and is acted on by them as though it were a current; this accounts for the fields produced by "permanent" ferromagnets.) A magnetic field is a vector field: it associates with every point in space a (pseudo-)vector that may vary in time. The direction of the field is the equilibrium direction of a compass needle placed in the field.
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The reality of the situation is the electron doesn't orbit around the nucleus like the earth orbits around the sun.  \n\nThe electron is in what is called the "electron cloud."  You can only say that the electron is at a certain place with a certain probability: not certainty.  \n\nTherefore, there is no way to visualize how the electron moves about the nucleus.
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As we know that current also has a electric and magnetic field i.e is also electromagnetic in nature.\nWhat happens is that the electric and magnetic fields of current in a path offering resistance radiate these fields strong enough for them to propogate.\n\nkaran
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Answer is a) that a positive test charge would move.\n\nElectric field lines from an isolated charge move towards the negative charge , that is outwars from an isolated positive charge and inwards from an isolated negative charge that means if a positive test charge is released it will move along the electric field line , that is positive to negative.  So a) is the correct answer.\n\nThis pic will help you visualize it :\nhttp://buphy.bu.edu/~duffy/PY106/2e.GIF\n\nHave a nice day.\n☺☺☺\n\nCheck out this link for further clarification .
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After you obtained the flux by gauss formula, if you use it to find E then this E is not total net E and is the one produced by the charge inside.\n\nIn order to finding total E for a fixed point, you can suppose more gauss surfaces for other charge, or you can change the surface to contain other points, or you use other solutions than gauss.