if the l=10', b=10'& h=1'. what is the quantity(cmt) of concrete has to be required & what is the formula?
456901
10'x10'x1'=100ft3= appro. 2.83m3
912780
Let x be the length of the corners.  Then the base will be (30 - 2x) by (30 - 2x) and the height will be x.\n\nYou want that to be a maximum, so create a formula for the volume, take the first derivative, set it to zero and you'll have the maximum.\n\nf(x) = x(30 - 2x)(30 - 2x)\nf(x) = x(900 -120x + 4x²)\nf(x) = 4x^3 - 120x² + 900x\n\nNow take the derivative\nf'(x)= 12x² - 240x + 900\n\nNow factor it:\nf'(x) = 12(x² - 20x + 75)\nf'(x) = 12(x - 5)(x - 15)\n\nAnd set it to zero:\n12(x - 5)(x -15) = 0\n\nSo x must be 5 or 15, but at x = 15, you have a minimum volume (0).  At x = 5 you have a maximum volume of 5 in x 20 in x 20 in = 2000 cu. in.
952904
A= (B*h)/2\nA=(10*15)/2\nA-=75
126589
The widely used Doyle Rule is (D - 4)^2 * L/16 \nThis would give (10-4)(10-4) * 12/16 = 36 * ¾ = 27.\n\nIf the 10 inches wide is the DIB (Diameter Inside the Bark), then a 12 foot log would yield 27 board feet.  See the chart listed below:
290650
There are several types of tests for testing the strength of concrete in various ways but the most common is the compressive testing.\n\nASTM C 31/ C31M-03 allows for three different sizes of cylinders (first number is diameter): 4"x8" (100mm x 200mm), 6" x 12" (150mm x 300mm), and 9" x 18" (225mm x 450mm). They have to be prepared in a very specific manner, they are to be filled in equal layers (the number of which dependent upon the cylinder size) and each layer rodded 25 times.  After the first layer all subsequent layers should have the rod break about 1" into the layer below it.  Here's the number of layers each size cylinder requires: 4"-2 layers, 6"- 3 layers, 9"- 4 layers.  On the top layer you have to heap it over the top before rodding and if it falls below the top you have to stop and add more concrete then continue rodding.  After that you strike the top off flat and put it in a safe place.\n\nFor compression testing of cylinders you'll refer to ASTM C 39/C 39M.  Basically you have to use either a steel cap with neoprene padding or a bonded cap that is messy and stinks to high heaven when being applied.  You have then zero the machine and start applying load.  You can either run a metered advance all the way or you can apply load at an increased rate up to 50% of the design strength.  The loading rate has to be between 20 psi/second and 50 psi/second.  Some bodies have a tighter requirement of say 35 psi/s +/- 7 psi/s.\n\nAs far as running the machine if it's digital you'll have a scale that says "pace deviation" you will want to put it on the zero there during the second half of the loading, be gentle in your adjustments otherwise you risk having one break with no warning.  Once you get it in the middle it should stay there till right before the cylinder goes, it will start moving to the minus side and lower the loading rate.  You are not supposed to continue adjusting it during this phase, you have to let the cylinder fail (or you can stop it right before it goes off the minus side of the scale to avoid having to clean up a mess).\n\nIf you're using a newer machine you can hit "stress" and it'll tell you the PSI or you'll have to divide the pounds of force applied by the area of the top of the cylinder (Pi r^2) to get the pounds per square inch.\n\nHow violent the concrete fails will be dependent upon the strength of the concrete.  A 4000 psi concrete doesn't make much sound... an 8000 or 9000 psi concrete sounds kinda like a gun going off and can send stuff flying across the room.  The machine i used this summer i blew the door off of on atleast 3 seperate occasions and on one of those it sent a good sized chunk of concrete flying about 15 feet across the room.
483088
this is very easy, just use the pythagorean therom (i might spell it wrong) the formula is: a^2 + b^2 = c^2 (c is the length of the pipe)\n\n15^2 + 8^2 = c^2\n\n225 + 64 = c^2\n\n289 = c^2\n\n17 = c\n\nyou need 17 feet of pipe
529532
10 Litre = 10000 cm^3\n100 Litre = 100000 cm^3\n1000 Litre = 1000000 cm^3 \n\n1 m  = 100 cm\n1 m^3 = 1000000 cm^3\n\n10 Litre = 0.01 m^3\n100 Litre = 0.1 m^3\n1000 Litre = 1 m^3\n\nSo 1 cubic Metre would contain 1000 Litre
353215
I work in a hardware store, just as an introduction.  So I am cheating because I know the "rule of thumb" that has all the other factors in it like density and stuff.  Quickcrete (TM) says that an 80lb. bag of premixed concrete will do 2/3 of a cubic foot.  There are 27 cubic feet per cubic yard, so it takes about 40 80lb. bags per cubic yard (at a hardware store they just say "yard" and mean cubic yard).  One bag does one two foot deep fence post, not that anyone asked.
321421
0.215 kL = 215L\n(1kL = 1000L)
551690
T= L + 2B\n\nT is total surface area\nL is Perimeter x Height\nB is base area
1066290
First, you need the volume. The formula yields: V = pi rh/3 = 20000pi/3 cubic feet. Since it weighs 50 pounds per cubic foot, the ratio 50 lbs/ft.^3 = 1. So multiplying this to our volume equation, V = 20000pi/3 ft.^3 = 20000pi/3 ft.^3 * 50lbs/ft.^3 = 100000pi/3 lbs. The work function is (25-x)100000pi/3 = W(x). Integrate this result from x=0 to x=25, and you get the answer.
942561
Substitute the h with 180, so 180= -16t^2 + 112t. \n\nThen subtract 180 from both sides of the equation, so 0= -16t^2 +112t -180. \n\nThen factor out a -4 from the equation, so 0= -4(4t^2 -28t +45) \n\nThen divide both sides of the equation by -4, so 0= 4t^2 -28t+45.\n\nThen factor the equation so that 0= (2t-9)(2t-4)\n\nThen use the zero product property so 0= 2t-9 and 0=2t-5.\n\nSolve both and you get t= 5/2 and t=9/2. Remember, the original equation was a quadractic function, so there are two answers.\n\nThis means that the path of the arrow was a parabola, and it first reached a height of 180 ft. at 5/2 seconds, and after reaching its maximum height of 196 ft. at 7/2 seconds, fell to 180 feet again at 9/2 seconds.\n\nHope I got the math right!
529872
Easy H*D*W    H=Height D=Depth W=Width *= times\n\nUse the units cubed, if it is meters use m^3 as the unit of measurement
877088
E = hc/λ \nλ = 1.2 x 10^-10 m\nc = 3 x 10^8 m/s\nh = 6.626068 × 10^-34 m2 kg / s\n\nE = 6.626068 × 10-34 * 3 x 10^8 / 1.2 x 10^-10\n\nE = 1.7 x 10^-15 J.
909774
1. W = 5 ft, L = 13 ft\n2. W = 10 cm, L = 26 cm\n3. $1300
205124
That depends on how deep you want the concrete.  Multiply the desired depth (in feet) by 128,000 square feet, then divide by 27 (because there are 27 cubic feet in a cubic yard).
895472
Let's see, volume = length x width x height, so:\n\n80 ft x 12 ft x 1/2 ft = 960 x 1/2 = 480 cubic feet\n\nSince 3 feet = 1 yard, 1 cubic yard of concrete = 27 cubic feet, so:\n\n480/27 = 17.78 cubic yards is your answer\n\nFinding the surface area of the driveway is the same as finding the area of a rectangle, so:\n\nArea = length x width, so 80 ft x 12 ft = 960 square feet