How many acres do would I need to open a Driving Range that is 400 yards deep and 50 yards wide?
404957
An acre is about 4000 square yards. A driving range that is 400 by 50 is 20,000 square yards. Therefore, you need about 5 acres.
362618
How deep?  If you're pouring concrete or spreading gravel, you have to know how deep.  A cubic yard will cover 54 sq ft 6 inches deep, but it will cover 81 sq ft 4 inches deep.
100367
It would not be easy that is for sure. There are many saftey regulations you have to follow and many precautions to take. If you are planning on an outdoor shooting range I think it is around 500 yds of clear space for the range plus a clear back field for lousy shots. The expense is great also but in the southern and westurn part of the U.S. It has been proven to pay for itself.
662020
50' x 50' will give 2500 sq ft.
686286
I don't know about West Virginia, but in Texas you can't shoot with in 100 yards of a house.  In other words, we have six acres but there are some house around so we can't shoot here.  We can go down the road where there are no houses and shoot all we want.
510542
16.5 to 17 yards. It all depends on how far it needs to go. The further it needs to go the closer it is to 17 yards for trajectory reasons.
96755
Easy. Just use proportions. \nx = the height of the object\n12 / 28 or 3 /7 = 720 / x\ncross multiply\n3x = 5040\n x = 1680" = 560 yards
36471
Draw a rectangle to represent the lot. Lable the long side 240 and the short side 180.\nNow draw a smaller rectangle inside it so that it is the same distance from the large rectangle.\nLabel the distance between them (the lawn) as x.\n\nYou know the area of the small rectangle is its height times its width. If the height of the large rectangle is 180, then the height of the small rectangle will be 180 minus two strips of lawn or (180 - 2x). The width of the small rectangle will be 240 minus two strips of lawn or (240 - 2x).\nThe area of the small rectangle will be Width x Height or (180-2x)(240-2x).\n\nSince the area of the lawn is equal to the area of the factory, the area of the factory has to be half the area of the whole lot or 1/2x180x240 = 21600, so\n\n(180-2x)(240-2x) = 21600\n\nFactor out some 2's to make the number smaller and we have\n2(90-x)2(120-x) = 21600\n(90-x)(120-x) = 5400\nor\nx^2 - 210x + 10800 - 5400 = 0\nx^2 - 210x + 5400 = 0\nfacto\n(x-180)(x-30) = 0 solutions 180 and 30.\nSince 180 is not a viable solution the only possible one is 30.
923353
Its really hard to say because all courses are different lengths and widths, but a fair average would be in the area of 6,500,000 sq yards.\n\nA golf course would consume about the same area as a football stadium with surrounding parking lots.\n\nThis would make a golf course about 2 sq miles.
625704
Your best bet is to measure out 40 yards and just do it!
1025168
That is a great idea.  I shoot at one regularly.  There is allot of money to be made in it.   The down side is you will need a large amount of land and the throwers are expensive for automatic throwers.  plus the little extras like golf carts for older shooters and people to go around and load the auto throwers.  plus insurance in case of accidents.
423674
I know this sounds stupid, but it depends on the size of the lots.\n\nA developer can make them whatever size he wants, but most are between 1/4 to 1/2 acre.  1/3 acre lots are pretty much standard here.
199571
8,364 ft (2,550 m) or 2,788 yards
782936
Convert to sq.ft. first:\n\n132 yd * 132 yd = \n\n396 ft * 396 ft =\n\n156,816 ft ²\n\nNow divide by 43,560, since 1 acre = 43,560 ft ²\n\n156,816 ÷ 43,560 = 3.60\n\n(My answer is exactly half of yours)\n\n~ ♥ ~
5461
One acre = 43,560 square feet, or 4,840 square yards.
1165042
the perfect distance is 25 yards.  this will give you an idea on how much drop your gun has.  at 50 yards you can dicover if you are pulling.
673346
Think of a "foot ruler" (12 inches) - three (3) of those would equal 1 yard (that would be 36 inches or a "yard stick").  So if you are given 65 feet that would equal 21.6666 (or perhaps 21 and 2/3d) yards.  Divide 65 feet by 3 feet.