what is the shearing strength of mild steel?
402913
well, I don't know about the testing, but for design, you use 0.4Fy as your shear strength. If you have 36 ksi steel, then you need 14.5 ksi to create a shear failure. Don't know if that works forpunching holes; it's probably less. Good question.
1097722
Steel is stronger, in both tensile and compressive strength. Chalk crumbles.
452629
The weight of steel you can find through density and volume.The density /specific weight of steel C 35 --0.0784 N/cc.\n\nCalculate the volume of the steel component and then multiply it with the density given above. Remember to take care of unit you are following.
803612
There are some charts on:\nhttp://www.krausco.biz/tonagechart.html\n\nwhich give a tonnage based on several factors. Once you have a method for actually calculating, you could check your answer against this site:\n\nexerpt:\n"RULE OF THUMB formula for making multiple bends on a press brake. For shape shown, in mild steel with radii equal to metal thickness unless otherwise noted.\n\nMultiply Metal Thickness by factor = Tons per Foot\n\nExample for bottom bending\n16ga (.062) Mild Steel. .062 x 150 = 9.3 tons per foot."\n\nHope this helps!
1094716
First of all you would find the first part of you question in the manual. The second part is documented in the Manual of STEEL CONSTRUCTION "Allowable Stress Design" Ninth Edition. and the third part is called an M.T.R. This is the birth compasition of the metal used to make the beam which gives you the carbon hardness and rating of that beam. \nGood luck,\nChris
93591
The rather loose grammar in use on Yahooanswers makes your question ambiguous.  Do you want to know what of what value stiff steel is? If so, the answer is obvious; the uses of steel in construction, consumer products, automobiles, etc. are myriad.\n\nIf you mean instead, what numerical value of "stiffness" does steel posses, there are several possible answers.  One would be the shear modulus of steel, which is a measure of how much a substance deforms when a shearing force is applied.  It is define as S= Shear stress/shear strain= F/A)/ (DEL X/h) where F is the force applied parallel to an object's fixed end, A is the area over which the force is applied, DEL x is the distance the object deforms, and h is the height of the object.  For steel, this is 8.4 x 10^10 Pascals.  Compare this to 2.5 x 10^10 Pascals for aluminum, and 14 x 10^10 Pa for tungsten.
803950
I  think you are talking about EN-8.\nA plain carbon steel suitable for use where a good degree wear resistance combined with toughness is required but without the expense of an alloy steel.\n\nTypical applications of EN8 include base plates for tools in plastic moulding and pressure casting dies, components for hand tools.\n\n\nSince 1988 a new series of 'mandatory' European standards (EN = Europaischen Normen) has been created, to replace national standards, such as BS, DIN, SS and NF, throughout 18 countries of Western Europe. EN are a part of the 'Single Market' legislation, designed to give equal opportunities for firms to compete throughout Europe, by harmonising the technical requirements between countries. The national standards bodies, of which BSI is one, are required to officially withdraw their national standards, when an EN is created with the same scope of application.\n\n\nA number of letters with there mechanical property identifiers are listed below\nLetter Steel Use Mechanical Property... \nS Structural Steel Minimum Yield Strength \nP Pressure Purposes Minimum Yield Strength \nL Line Pipe Minimum Yield Strength \nE Engineering Minimum Yield Strength \nB Reinforcing Steel Characteristic Yield Case \nY Pre-stressing Steel Minimum Yield Case \nR Rails Minimum Yield Case \nH High Strength Cold Rolled Minimum Yield Case \nD Flat Products for Cold Forming C, D or X followed by \ntwo numbers characterising steel \nT Tinmill Products Nominal Yield Case \nM Electrical Steel Number = 100 x specific loss in \nW/kg, "—" \nNumber = 100 x nom thick in mm \nLetter for type of steel (A,B,E,N,S or P) \n\nEN 8 IS an old standard. AISI-1040 is the equivalent. The new standard would be BS 970 080M40.
884549
mild steel square tube is mild steel square tube what else????\nLike round tubes which have round cross-sections this is just a square tube with square cross-section.
334754
Structural steel ASTM-A36 400 650   \nSteel, high strength alloy ASTM A-514 690 760   \nSteel, high tensile 1650 1860   \nSteel, Piano wire  2000   \n\nrest below
1115091
The best answer to this question would very long. The quick and dirty response is:\n\nCutting tools in metalwork apply a compressive force to the work piece. The compressive force overcomes the forces holding the atoms together and and the material begins to slip along planes of irregular crystal stucture. The effected zone is reffered to as the shear zone. \n\nAgain this is short answer. Probably raised more questions than it answered.
109020
1 and 3/4 inch round steel.095 wall. No soft steel or aluminum. Must be welded completely. No gaps
1163614
It is significantly stronger - it will not break nearly as easily as bronze\nAlso it will hold a finer edge than bronze.\nSo it makes a much better sword than bronze.
385650
ductility.  A ductile metal is easily shaped
701453
You can find it using the general bending formula as related to torsion (twisting) rather than bending.\n\nT/j = G/Theta x L = Shear stess/Radius\n \nThe folowing link explains much better than I can.\n\nhttp://www.freestudy.co.uk/c105.htm
923963
Traffic timing for this much weight is also considerable. A\n   building code shows that you might need 15 or more for\n   this area so titanium is probably out.  The core value of\n   bronzed steel is ok for the average busy building.  Size again\n   must be measurables ranging from 2.7 to 3.7 made in 20 foot\n   can be made in 35 precise.
896228
Let's see.. if the steel is thick, probably a lot of it
670653
There are specific eqn's used to determine the point at which an object will go "plastic" and then break. It is determinant on the radius and composition of the object. You have to look at youngs modulus and the tensile stress being applied to the object you are using. here is a table of some values for Youngs modulus and tensile stress: http://cougar.slvhs.slv.k12.ca.us/~pboomer/physicslectures/textass/tables7-8.jpg\n\nThe Young's modulus allows the behavior of a material under load to be calculated. For instance, it can be used to predict the amount a wire will extend under tension, or to predict the load at which a thin column will buckle under compression. Some calculations also require the use of other material properties, such as the shear modulus, density, or Poisson's ratio.\n\n\nLinear vs non-linear\n\nFor many materials, Young's modulus is a constant over a range of strains. Such materials are called linear, and are said to obey Hooke's law. Examples of linear materials include steel, carbon fiber, and glass. Rubber is a non-linear material.\n\nYou can find this kind of table for most household items, and since you are using fishing line there are different "tests" which will hold various ammts. of weight before breaking.. Ie. such as a 100 pound test will hold that mush weight as opposed to a 20 lb test which would break pretty easily. You could vary the test weight on various strings and by knowing the test you could predict at which time the string would break...