what is the aproximate are of a segment of a circle with a height 6 m and the lenght of the chord is 20 m?
407600
The area of the segment is given by\n\nA = r^2[theta - sin(theta)]/2\n\nSo we need theta, which is the angle that contains the chord, and the radius of the circle.\n\nThe radius of the circle is given by\n\nr = (c^2 + 4h^2)/(8h)\n= (20^2 + 4(6)^2)/(8*6)\n= (400 + 144)/48\n= 11.3 m\n\ntheta is given by\n\ntheta = 2 arcsin(c/[2r])\n= 2 arcsin(20/[2(11.3)])\n= 2.17 radians\n\nSo\n\nA = r^2[theta - sin(theta)]/2\n= (11.3)^2[2.17 - sin(2.17)]/2\n= 85.92 m^2
876382
Area = (1/2) Base x Height.\n\nBase is x, because you can choose any side as base.  All are equal.\n\nThe Height (h), half of Base (0.5x), and one Side(x) form a right angled triangle.\n\nh/x = sin 60 = sqrt (3)/2\n\nh = (sqrt(3)/2)x.\n\nArea = (1/2)x (sqrt(3)/2)x\n=sqrt(3)*x^2/4
207955
u need more info than just the length, but here is something which might help u are speaking of ovals( called ellipses in math)\n\n\nwell the formula for them is\n\n\n(x^2)/a^2  +  (y^2)/b^2  =1\n\nwhere a and b are half of the major and minor axis , you only know 1 of these meassures, thats not enough sorry chap, wish i could help, but i think no one can, with only that info
234891
I'm assuming that you are going to wrap the sheet to form a cone. \n\nTo simplify things, let x be the radius of the semicircle.\nThe circumfrence of the full circle is 2(pi)x, so the length of the semicircle arc is (pi)x. When you wrap the semicircle to form a cone, the base of the cone will have circumfrence of (pi)x, so its radius is x/2. The cone you get will have a sloping side of length x.\n\nThe volume of the cone is (pi)(r^2)h/3.\n\nThe height of the cone is third side of the triangle formed by the sloping side of the code (length x) and a radius of the base (x/2), so its length is sqrt(x^2 - (x/2)^2) = (x)sqrt(3)/2.\n\nSo the volume is ((pi)((x/2)^2)(x)sqrt(3)/2)/3 = \n\n((pi)((x^3)sqrt(3))/24 \n\nSubstituting x = 140mm  = 14 cm you have:\n\n((pi)((14^3)sqrt(3))/24 = 622.1 cc\n\n(Check arthmetic)
357131
It is a problem in long division with a remainder. You need to simply divide the whole integers (everything before the decimal point) and keep the remainder as the inches.  Thus your problem becomes 20 feet and 6 inches, you can check your answer by reversing the problem.  In 20 feet there are 20 times 12 inches, or 240 inches with 6.138 inches left over.  Thus the answer is 20 feet and 6 inches (rounding to whole inches as in your example). \n\n-LOVE YOUR NIEGHBOR AS YOURSELF
406577
it's approximately 6 m.\n\nthe formula that relates diameter and circumference is:\n\nCircumference = pi * diameter\n\n18.85 = 3.14 * d\n\n18.85/3.14 = d\n\n6.00 = d  <-- answer
503124
first split the triangle in half. \nfind the height of the triangle (with the 12cm side as base)\n\n7^2 - 6^2 = (height)^2\nheight = 3.61\n\nUse formula\n\nArea = (0.5) (height)(base)\n     = (0.5) (3.61)(12)\n     = 21.66 cm squared
711751
Draw the chord. Observe that , unless it goes thru the center of the circle, that it splits the circle into a large part and a smaller part. Now construct a perpendicular bisector on the chord. Note\nthat it's length to the edge of the circle on the larger part is greater than the radius else it would be on the smaller part. \nAlso the distance to the edge in the smaller part is less than\nthe radius. So somewhere on the perpendicular bisector the\ndistance to the edge is equal to the radius. At any\npoint on the bisector draw a pair of lines to the end points of the chord. They make a pair of congruent triangles by S.A.S. therefore the lines are of equal length. At some point the lengths must be equal to the length of the radius. The only place that can be is at the center.
110565
>>>> what is the altitude of a right triangle?\n\nI have several here, and I am at 12 metres above sea level.\nSeriously, you haven’t provided enough information. You need at minimum the length of 2 sides or a side and an angle as well as the orientation to be able to calculate height (altitude).\n\n>>>>>>if the equation is d=2r what is the d and the r what exectly \n>>>>>>>am I finding with this equation \n\nd = diameter. r= radius. You are finding either how far it is from one side of a circle to another (d), or how far it is form the edge of a circle to the centre (r).
999585
I knew it as I did the activity.Draw a circle an divide it into 8 equal parts.It should be equal.Then cut it and stick such that the tip of one cone is up and the other is down.See that the edges stick each other close together.Do it until you finish all the 8 parts.\nNow you needed some concentration.You can see that it forms a parallelogram.Now area of parallelogram=base*height and the circumference of circle=Pi*2*radius.The base of the diagram is half the circumference that is Pi*radius,and the height will be the radius.You will also notice that Area of parallelogram=Area of circle.Therefore,Base*height=Pi *Radius *radius.so, now you have got pi*radius square.\nHope you like my answer.
720465
ANSWER: 643.241 sq mm\n\nEXPLANATION:\nLet the radius of the inner circle (black portion) = r\nand that of the outer circle = R.\nAlso let the eccentricity = e.\n\nOn y-axis of the crosshair\nR - 5 = sqrt(r^2 - e^2)\nSquaring both sides\n(R-5)^2 = (r^2-e^2)___________(1)\n\nNow consider the x-axis of the crosshair,\n2R - 2r = 9\nor R - r = 9/2\nor R = 9/2 + r ___________(2)\n\nBut e = (difference of radii) \nSo e = R-r = 9/2 _________(3)\n\nSubstituting R from eqn(2) and e from eqn(3) in eqn(1)\n(r+9/2-5)^2 = r^2-(9/2)^2\nor (r-1/2)^2 = r^2-81/4\nor r^2-r+1/4 = r^2-81/4\nor r = 81/4 + 1/4 = 41/2\n\nThen R = r+9/2 = 41/2+9/2 = 50/2 = 25\n\nNow, area of the white region \n= (Area of outer circle) - (Area of inner circle)\n= (pi*R^2) - (pi*r^2)\n= pi*(R^2 - r^2)\n= pi*{25^2 - (41/2)^2}\n= 643.24 sq mm
1124334
two circles, in parallel planes with the line connecting their centers forming right-angles with each plane in all directions. ... and the walls comprising the set of line segments one of whose end points is on one circel and the other end point on the other circle withe the property that the segments at each point on circle(A) is the minimum distance to circle(B).\n\n.. or, since you use the word "cylinder" in the question:\n\na cylinder, each of whose end-faces is a circle.
316497
If a curve in n dimensions is given parametrically as:\n\n( f1(s), f2(s), ..., fn(s) ) for a <= s <= b\n\nthen you can approximate the arc length by dividing the domain [a,b] into many small pieces a = s0, s1, s2, ..., sk = b and summing the lengths of the chords (secants? straight line segments. whatever) between s_{i} and s_{i+1}.\n\nThe length of the curve is defined as the least upper bound of all such sums (if that set has an upper bound).\n\nUnder suitable hypotheses you can compute this as the definite integral of ``ds'' as s varies from a to b, using the Euclidean rule\n\n(ds)^2 = (df1(s)/ds)^2 + ... + (dfn(s)/ds)^2\n\ni.e., your length is the definite integral from a to b of the square root of the sum of the squares of the derivative of each coordinate function.\n\nFor example for a circle of radius one at the origin parameterized as ( cos(t), sin(t) ) as t varies from a = 0 to b = 2 pi you get ... 2 pi ... which is what you would expect.  :-)  :-)\n\nOr for the arc length of ( (s^3)/3 - s, s^2 ) from s = 5 to s = 8 the length is the integral from 5 to 8 of\n\nsqrt( (deriv (s^3)/3 - s w.r.t. s)^2 + (deriv s^2 w.r.t. s)^2 ) ds\n\n= sqrt( (s^2 - 1)^2 + (2s)^2 ) ds\n= sqrt( s^4 - 2s^2 + 1 + 4s^2 ) ds\n= sqrt( s^4 + 2s^2 + 1 ) ds\n= (s^2 + 1) ds\n\ni.e., integral from s=5 to s=8 of (s^2 + 1) ds.
318225
20.408941666666663 or 20 feet and 4 inches
5380
the answer to your question is simple..first find the equation for the circumference of a circle which would be 2 times pi times radius..which gives you the answer 29.516 if you round to the nearest 10th your answer would be 29.5cm
965204
Pythagorean Theorem\n\nc²  = √a ² = b²\n\nc²  = √(20)² + (15)²\n\nc² = √400 + 225\n\nc² = √625\n\nc = 25\n\nThe answer is c = 25\n\nThe length os the hypotenus is 25 cm\n\n- - - - - -s-
450988
The angle is 36 degrees (10%). The chord length is 30.901699 cm = 2*50*cos(90-36/2) cm.