If the distance from a converging lens to the objects is less than the focal length of the lens, image wil be?
414316
Hi,\nThe answer is C.\n\nYou could make a ray-diagram and see for yourself...
761501
If nothing else,you can use this but I am not positive.  "A telescope can refract images."
572843
focal lenth will definitely increase. because refractive index will decrease
241224
As best I recall, the focal length is equal to 2*the Radius of Curvature; 1/f = 1/o+1/i\n\nM= -{i/[o]}; thus, f=54; the image distance is 3 * the object distance; 3o + o = 54 cm; 4*[o] =54 ; [o]=13.5; the other object distance ? I can only find one; the sign on the image is distance is +; Magnification is - so it is "inverted"; or if o=-13.5, the second answer, I THINK, is found; with a +3 magnification; upright
283026
Focal length.\nThe distance from the lens to a point at which the light going through the lens will converge into a sigle point.\n\nAfter the light enters a lens straight on, the light is bent, causing the light to focus toward a signle point. After that point the image is turned upside down.
801074
Let x = distance of object from stronger source. If weaker source has strength S then stronger source has strength 3S.\n\nIllumination due to stronger source is 3S/x².\n\nIllumination due to weaker source is S/(12-x)².\n\nRequired to minimize the total illumination\n 3S/x² + S/(12-x)², or ignoring S, minimize \n\n          t(x) = 3/x² + 1/(12-x)².\n\nDo the usual t '(x) = 0 and check t '' > 0. After simplifying t '(x) = 0 get\n\n          3 (12 - x)³ = x³\n\nTake cube roots and simplify to get\n\n          x = 12 / [ 1 + 1 / 3^(1/3) ]\n\nand on further simplification\n\n          36 / ( 3 + 9^(1/3) ) = 7.086497 feet\n\nYou can check the answer using WIMS Function calculator and selecting "curve"
922899
Points to consider:\nFocal distance of mirror.\nMirror type: Flat, concave and convex.\nReflected index of silver coating.\nMagnification of image.\nGlass type.\nGlass colour.\nThickness of glass used.
583825
take above as :-\nm= -v/u = h'/h = 2h/h = 2\n-v/u = 2, v = -2u\ntake,\n1/f = 1/v + 1/u\n1/-50cm = 1/-2u + 1/u\n(-50) because focal length of concave mirror is always negative.\n\n\nnow, solve it get value of 'u'& you will get ur object distance.\nit must be less than 0.5 m as the image is erect & enlarged.
1058928
The medium of a lens is the material which it is made of.
309034
the magnifying of the lens: M = 4 and by definition \nM = -di/do\ndo is the distance from lens to object\ndi is the distance from lens to image\nso -di/do = 4 ---> di = -4do\nthe thin lenses equation:\n1/f = 1/do + 1/di\n1/f = 1/do + 1/(-4do)\n1/f = 1/do - 1/(4do) = 3/(4do)\nf = 4do/3 = (4*2.88 cm)/3\nf = 3.84 cm
608577
Depends on the shape of the object being measured.
620878
focal length = infinity\ncurvature  = 0
757629
It focuses an image on the retina so that you can see it.  The shape of the lens in the eye is controlled by muscles, so that the focal length can be adjusted to get sharp focus of both near and distant objects.  Errors in the shape of the lens can be corrected with eyeglasses.
423455
Yes, by placing a simple microscope close to the eye, the light rays which were diverging from the object are now diverging less or even convering a little before they reach the eye's lens. The far sighted observer's eye does not have to converge the light rays as much and their weaker focussing power is now sufficient to form a focussed image on the retina.
1163490
i'm assuming these are a convex and concave lenses ....hence the different dispersions ....forming a doublet will cause parallel light up to 2000 yards or optical infinity
703298
For a convex lens, a thinner lens will have a greater focal length because the length is mostly determined by the curvature of the lens.  Greater curvature gives shorter focal length.  A thin lens is almost flat, therefore doesn't have as much curvature.  Light striking the lens at a greater angle(more curvature) will refract more.
55444
10 meters 5 meters to the mirror and 5 meters back.and no it's not 5 meters the image you see is in fact 10 meters away that is why it's very hard to take pictures with a mirror in them and get it to turn out in foucuse becouse your dealing with two or more focal plains