wether balloons burst at an altitude of 27.5km. what is the altitude in meters? ___meters?
398742
"km" means "kilometers", an aggregation of prefix "kilo-" and "meters". "kilo" means 1000. So 27.5 km is 27.5 thousand meters, or 27,500 meters.
809952
if your balloon were super super to the highest level so so so so so so so so so so so so so so so very very very very very strong.... as in... that it would survive at like zero pressure, your helium filled balloon would reach the outer space...\notherwise, it would'nt even reach the middle of the atmosphere..
841719
sorry for laughing but I know everything can be used with math. Those rockets, how long is goes up, where it lands the wind , angle bla/bla
945010
Equatorial gravity 3.69 m/s2\n(0.376g)
882711
a)\nRate = Distance/time = (24000 ft)/(20 min) = 1200 ft/min\n\nb)\nTo write A(t), you know that the max. value is 24000 and the plane descends at a constant, linear rate of 1200 ft/min.  Thus, you can write a linear equation of this model:\n\nA(t) = 24000 - 1200t, where t = time (in minutes)\n\nPlugging in 0 (at initial time), the height is 24000 feet, which matches the fact in the problem.\n\nc)\nThough linear functions have infinite ranges and domains, this problem is limited to the realism of the problem.  The range is only limited from the maximium value (24000 ft) to the ground (0 ft).  You can't have a negative value for altitude because that would not make sense in the problem.  The domain is limited to the time in air (20 min).  You can't have a negative time and time after 20 min is irrelevant because the plane has already landed.  Summarizing:\n\nDomain: 0 <= t <= 20\nRange: 0 <= A(t) <= 24000\n\n--------\n\nHope this helps
1144696
gravity and air resistance.
302444
sound-330m/s in air medium\nlight-299,297km/s
218928
I don't think there is an altitude limit... in any case I don't think you are going above 4000 meters... they should be ok...
960920
0.07896 km\n153 mm\n0.578  km
824167
The radius is actually 2/3 of the altitude.  Try that
481154
2 km = 2000m\n2000m = 200000cm
644088
1 meter = 3.2808399 feet,,,\n  so u can multiply 1,000 to the above given value that is \n\n3280.8399 feet.\n\n\nhave a nice time ;)
404977
Hahahahahahaha, how amusing the previous anwers are.\n\nThe balloon would continue to rise in the atmosphere until it reached a height where the pressure inside the balloon was equal to the pressure outside the balloon...then it would remain at the same height, moving in the wind, maybe slightly up and down due to thermals...until it burst !
77860
hey, didnt i answer something very similar to this for you? you need to do F=ma so 43000000N/2100000kg then you get an acceleration, but then you have to subtract gravity from this because thats the acceleration produced by the rocket but there is still gravity pulling with 9.8 m/s^2 in the opposite direction. so just do (43000000/2100000) - 9.8, and that's your answer :)
379193
it has nothing to do with the air in the atmosphere its the air that fills the balloon up. when its hot the ballon goes up as it cools it goes down
429348
2000 km distance?\n\n2000 km altitude?\n\nif u r asking about distance, mine is 2700 km. we manage.\nbut i should say that we work in the same area, so we have many events to meet at during the year
665350
As the volume is constant,\n(P/T)initial = (P/T) final\n1/(25+273.15) = P/(50+273.15)\nP = 1.084 atm\n\n(Taking the pressure of the initial gas was 1 atm.