when hydrocloric acid and sodium hydroxide are made into a salt what colour is it?
411151
the reaction produces NaCl, which is white
729728
Sodium Hydroxide----NaOH\n\nWhich is the same thing as lye.\nIt is commonly used in drain uncloging agents.
711078
Acid used is ethanoic acid, hence the salt produced is ethanoate (in this case, the exact salt is sodium ethanoate CH3COONa). Since this is an acid-base titration, products are salt and water.\nCH3COOH + NaOH --> CH3COONa + H2O
695381
A reaction between an acid and a metal oxide to form a salt and water as the only products.
217892
Apart from the precipitation reactions (AgCl and BaCO3 form insoluble compounds, although HCl will dissolve BaCO3), there is flame colouring for identifying the alkali and earth alkali metals (Na yellowish orange, Li reddish, Ba green), there are pH measurements (HCl acidic, NaOH and Na2CO3 basic, rest neutral), and you need to test an oxidant to identify the sugar solution. This ought to give you a matrix which gives only one possible identification for each test (with deionized water failing all tests).
283437
Sodium Hydroxide dissolves in water and dissassociated completely to form Sodium +1 and Hydroxide -1 ions in solution.\n\nNaOH --H2O--> Na+(aq) + OH-(aq)
794274
B, though its even more common as K2Cr2O7\n\nby coincidence, C, Na and H2 happen to be quite good reducing agents.
571970
Acid +Alkali =Salt + Water\nHence,\n\nNaOH + HCl = NaCl + H2O\n\nWhen litmus paper is dipped in NaOH solution it turns blue it means that NaOH is basic in nature.When HCl is added to NaOH The mixture becomes acidic and so the litmus paper turns red.The product you get after mixing both solutions is common salt and water so when this is heated the water evaporates and the salt is left back.This is a small experiment which you can do by adding salt to water and then heating it till the water gets completely evaporated.
655440
1)  Phenolphethelein  colourless in acid  red colour in alkali\n\n2)Litmus  red in acid and red in alkali\n\n3)Methyl Red red in acid  and yelow in alkali\n\n4)Methyl Orange- pink in acid and yellow in alkali
168285
Some elements have differing soluability depending on their oxidation state.  If the hydroxide of one oxidation state is insoluable but another oxidation state is soluable, then it would act as a test for oxidation state.\n\nAnother possible way for sodium hydroxide to act as a test for oxidation state is if the element in question has different colors in different oxidation states in basic pH.
706856
Acidic.\nBecause sodium nitrate is a salt solution, and is neutral. Since you are adding an acid to a neutral soution, the end reault will be an acidic mixture.
386284
The reaction Mg(OH)2 <--> Mg+2 + 2OH- will turn to the right when hydrochloric acid is added. This is because the acid eats away the hydroxides, and due to LeChatelier's principle, the equilibrium must shift to the right to account for this loss.\n\nAs for the Na2(EDTA), it will also shift to the right. The EDTA will form a complex with the magnesium ions, again, lowering the concentration of the Mg+2, so the equilibrium shifts to the right. Keep in mind that complex ions only form in molecules with empty d-orbitals.\n\nThis reaction is endothermic, like all dissolution (dissolving) reactions are. It takes energy to break the ions out of the crystal lattice structure.
464975
If you mean NaCl (letter L at the end instead of number one), then, yes, sodium chloride is an ionic compound. In solid form it is NaCl(s), commonly known as table salt.\n\nIn case you're wondering, the formula NaCl is actually considered a "formula unit" rather than a "molecule." In solid form, ionic compounds are 3-D matrices of ions. But when dissolved or solvated in water, the ions become free floating Na+ and Cl- ions rather than individual NaCl units. A formula unit simply shows the lowest whole-number ratio of cations (positively charged ions) to anions (negatively charged ions) given by the formula. Sodium chloride's cation to anion ratio is one sodium cation Na+ per chloride anion Cl-, or 1 to 1.\n\nBy way of contrast, the formula H2O (for water) represents a molecule, because each molecule of water is a distinct unit.
975374
Acids and Bases will cancel each other out when mixed in equal proportions and you will end up with Water and a Salt.  The salt will depend on what to substances you are mixing. \n\nFor example, if you mix Hydrochloric Acid (HCL) with Sodium Hydroxide (NAOH) in the proper MOL to MOL ratios you will end up with Water (H2O) and Sodium Chloride (NACL)
606155
NaOH + HCl ---> NaCl + H20
1087032
try Vogel's "Qualitative Inorganic Analysis", I'm pretty sure it has all the answers 4 u.\n\ndont care editions, but for 7th ed, ISBN is 0582218667\n\n****\nokey then, from Vogels\n\n1) when heated, lead nitrate decomposes to white solid lead oxide (PbO), brown gas (NO2) and oxygen gas. Brown gas decolorizes when contact with water. \n\n2) ammonia odur. ammonium compounds are all volatile towards heat and decomposes to ammonia and an acid but quickly recombine if the acid, in this case, hydrochloric acid, is a strong acid.\n\n3) anhydrate copper sulphate is white, hydrate copper sulphate is blue. I have no idea which one you actually heated. If it's anhydrate, no change; if hydrate, blue ---> white.\n\n4) blue precipitate forms initally, but resolve upon excess reagent, clear blue soln results due to the formation of copper complex [blue precipitate: Cu(OH)2*CuSO4, complex: [Cu(NH3)4]^2+]\n\n5) brown precipitates froms [Cu(OH)2], no change with excess reagents.\n\n6) metal-gray stipe (magnesium stipe) gains a redish brown color due to formation of copper metal. Possible decolorization of the soln (depends on how much magnesium u actually put in)\n\n7) volatile reaction, solid metal solves,ignitable gas is formed. (if phenolphthalein is added to water initally, soln becomes pink)
423114
Adding sulphuric acid and sodium hydroxide respectively??