Formula in computing Cubage Box Measurement?
403625
94,752 cubic centimetres
804606
For cubic measure:  L x W x H = CI / 231 = G\nL = Length\nW = Width\nH = Height\nCI = Cubic Inches (Volume)\nG = Gallons\nMeasure the Length, Width, and Height in Inches.\n231 Cubic Inches to one Gallon.\nConvert Volume to Cubic Inches\nLength x Width x Height  = Cubic Inches  / 231 = Gallons\n\nFor Right cylinder measure: Pi x r'2 x H = CI / 231 = G\nPi = 3.14159\nr = radius (half of diameter) '2 = squared\nH = Height (or length)\nCI = Cubic Inches (Volume)\nConvert Volume to Cubic Inches. \nPi x r squared x H = CI / 231 = gallons
602189
u can go www.webmath.com, its pretty good. \nu can also ask on answers. \ni.e. 1cm = 10mm\n1m = 100cm or 1m = 1000mm\n1m = 3ft\n1ft = 12in \netc... hope it helps!
525014
Let's make this very simple.\n\nTo measure the volume of a cylinder, you find the diameter of the interior portion of the cylinder.  Take that number and divide by two...that's your radius (r).  Now measure the height of the interior of your cylinder...that's your height (h).\n\nNow, take the radius (r) and the height (h) and plug them into the formula below:\n\nV = π*(r)*(r)*(h)\n\n(π equals roughly 3.1516)\n\nNow if your answer is in cubic inches, multiply V by .0036 for British gallons or .00433 for US gallons (yes, they are different).  If V is in cubic centimeters, multiply by .00022 (British) or .00026 (US).\n\nI don't know how to make it any clearer...good luck.
755525
OK, first let's try to get that into a mathematical statement.  The volume can be given as yx^2, since the box is square, and the cost is 8x^2 for the top and bottom (4 cents times two sides), and 4xy for the sides (1 cent times four sides).  So the problem can be stated mathematically as yx^2 = 6912, c = 8x^2 + 4xy, minimize c.\n\nThe next step, I guess, would be to rearrange the equation to eliminate one variable and solve for c in terms of the other.  So say y = 6912/x^2, then c = 8x^2 + (4*6912)x/x^2.  That simplifies to c = 8x^2 + 27648x^-1.  Now we have c in terms of x.\n\nThe next step is to find the value of x for which c is minimized.  You don't say what math class you're in but the only way I know how to do this is with calculus, so I assume you are that advanced.  First you have to take the derivative of the function.  So the derivative of 8x^2 +27648x^-1 is 16x -27648x^-2.\n\nNext, find all points for which c' = 0.  Set 16x = 27648/x^2.  X = 1728/x^2.  x^3 = 1728.  x = 3_/1728 = 12.  So the only local min/max is at x = 12.\n\nNow, you would ordinarily compare the value of the function at the local min/max with the value at the boundaries, but since this function is undefined at the boundaries,we can assume that x = 12 is the answer.  \n\nGoing back to the first equation, yx^2 = 6912.  That means 144y = 6912.  y = 48.\n\nThe answer is (12, 48).
808987
lets say we have text1 as the meter textbox and text2 as the centimeter textbox as the simplest conversion example:\nsub text1 change\ntext2.text = str(val(text1) * 100)\nend sub\nso when you type a value in the meter box, it will multiply it by 100 and show the result in the centimeter box.
864388
some formulas that can help :\nhttp://www.eskridgeinc.com/support/formulas.html
477060
8X11\n\nThink about two boxes.  The outer box is 11X14.  The inner box is smaller, so you subtract.  You have to subtract 3 inches in each direction, so 11-3=8, and 14-3=11.
61304
Thy this website out: http://www.convertit.com/Go/ConvertIt/Measurement/Converter.ASP
861788
There is no accurate way to do this because too many variables are involved. You can do like I do though and run a series of tests and then average them.\n\nhttp://www.toast.net/
652379
It will be \n1, \n3, \n9 and \n27. \n\nAnd you can easily get all the measurement from it. I ve counted all that.
903949
Yes to the first question.\n\nYou have to do like this:\n(ai+bj+ck) ___\n\nIn the ___ you put the vetorial unit. Like: meters, cubic meters, newtons, m/s, etc.\n\n₢
102106
Volume is equal to legnth times width times height. The dimensions you gave are the length, width, and height. So all you do is multiply the dimensions together.\n\nVolume=6*10*4=60*4=240
191332
Find the dementions and multiply.
247410
There are different formulas for different shapes. This page has a list of them: http://www.math.com/tables/geometry/volumes.htm
969540
This problem has nothing to do with "volume", it deals with the surface area of the box.\n\n2 sides of the box measure 4.5 inches by 4 inches\n2 sides of the box measure 4.5 inches by 7 inches\n2 sides of the box measure 4 inches by 7 inches\n\nSo the surface area is going to equal:\n2(4.5 * 4) + 2(4.5 * 7) + 2(4 * 7) = 155 inches squared\n\nTo best cut the paper, you should make 13 in x 15 in sheets.
720092
While the answers above are correct, I will go a bit further.\n\nEstes rockets sells a nice tool for just this very job that will make your measurement fairly easy and accurate. It is called AltiTrak (TM).\n\nhttp://www.estesrockets.com/cgi-bin/products.cgi?view,296