mathamatical challenge!Find the value of y:?
400277
Ans is when y = p/2, assuming k is non-zero.\n\nThe growth rate is given by ky(p-y), with k and p being constant. Therefore this term describes an inverted parabola.\n\nThe highest point on an inverted parabola is its turning point, when it's gradient is zero.\n\nIf     G = ky(p-y)\nthen   G = kpy - ky^2             expanding the term\nso dG/dy = kp - 2ky               differentiate it to y\n           kp - 2ky = 0           at the turning point\n           kp       = 2ky\n            p       = 2y          divide out by k\n            p/2     = y
133024
y = 0.\n\nETA: That's if we're to assume that the value of x is constant between the equations.
1171377
Divide each side by 12 to isolate the variable.\n12y/12=132/12\nYou end up with y=11.
417188
y=Asin(2x)+Bcos(2x)+(x/4)\n\nNow you get to determine why.
399118
y-int= (0,-5)\nx-int= (-1.2,0)
699742
-(3x+y)(3x-y)\n-(9x^2-y^2)\ny^2-9x^2
518727
Multiply the first equation by 2.\n\nSubtract the second equation from the new first equation.\n\nSolve for y.\n\nTake your value for y and substitute it into the original first equation.\n\nSolve for x.
195576
Y = U + VX^2\nVX^2 = Y - U\nX^2 = (Y-U)/V\nX = sqrt ( (Y-U)/V )
948239
xy = y^½\n y = y^½ /x\n y = y^½*x^-½\n\ndy/dx = -½ y^½ x^ -3/2\ndy/dx = - [½ y^½ ]/x^+3/2\ndy/dx = - (y^½) / (2x^3/2)
896751
are you solving for y or n?
811806
If x is 2, then 8x is 16.\n\nIf y is 3, then 4y is 12.\n\n16-12 is 4.  :o)
240934
Solution: y = 9 - x or y = -x + 9\n\nHere are the steps I took:\nThe equation must equal y = mx + b, so we start with:\n1. x + 2y = 18\n2. x + y = 9 (Divide both sides by 2 to remove it from the "y")\n3. y = 9 - x (Subtract "x" from both sides)\n\nIn this type of equation in algebra, you have to produce steps to isolate the "y".
566070
0 = 2y + 2z\n\nz and y must be opposites and equal
1103883
Y=X^5-X^-3+X^2\nY'=5X^4+3X^-4+2X\nY''=20X^3-12X^-5+2
421674
y = (x mod 5) + 1.\n\nThough that does seem a bit like cheating :)
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
862692
y" + y = 1\n\n1=sin(x) + xcos(x)\n\nEquation should read 1=sin^2(x) + xcos^2(x)\nand x value is elements of real numbers.