what is the circumference of a bus wheel?
398730
22" WHEEL AT 50 MPH =???
906258
Amiya\n\nThe busbar sizing is the easiest of all in electrical engineering\n\nYou will need to understand the basis\nThe bus bar sizing is limited by the allowable current desity in the copper bar\n\nIf you want to size for a 1000A current, then you will take the 99.99% pure copper as the bar material. The current density allowable depends on the ambient temperature and the ventilation system adapted inside the panel. However upon assuming a reasonable local values for it, just devide the current by the current density of copper, you will get the allowable copper area of cross section\n\nfollowed by this, you can find out the cross sectional availability of the copper bars. If one is not meeting your area, you can stack two similar bars. You can not stack two different sizes of bars due to their difference in resistances. \n\nI think this background is just enough for the basics.\n\nLet us go to specifics.\n\nDo you want to design manually or using a software?\n\nManual designing is outbid by software.\n\nTry the free software below. I just tried to download and checked the operation of the software. It works excellent. I recommend you to try this.\n\nhttp://www.cda.org.uk/download/d11.exe\n\nStill if you insist for a manual calculation, Pl download the link below\n\nhttp://www.socomec.fr/documentation/documents/Catec-gb.pdf\n\nCheck the last page for busbar designing\n\n\nIf you find my answer fitting to your question,\nJust rate my answer. I will get 10 points for the best answer. This will take me to level 2 in yahoo answers. I can help answering others more effectively at higher levels.\n\nGood Luck\n\nGood Luck.\n\nHope i have solved your problem
228405
When you see a size like 16" or 20" or 24" this refers to the wheel diameter. So you would measure the diameter of the wheel.\n\nThe other measurement is frame size -  this tyically is the length of the tube the seat post slides into. \n\nHope this helps
837429
ok, 7.5 width = fattest part of the board (nose) when you're measuring side to side. Bearings are the part in the wheel that lets them spin, there on the inside of the wheel. YOU NEED BEARINGS. When you get the trucks, put the big nut (otherwise known as the "kingpin") facing inwards, or toward the middle. If you don't put them in the middle you will try to turn and basically die. When measuring a board, measure what looks like the fattest part of the board from side to side. Which should be from about 7 to 8 inches. When measuring length measure from the nose to the tail. Hope this helps!
763400
Circumference = 2*PI * r\n\nTherfore : Circumference / r = 2 * PI \n\nPI is nominally equal to 3.14
881999
It is half the size of a full circle.\n\nArea of a full circle = pi r²\nArea of a semi-circle = (pi r²) / 2\n\nIf you mean the perimeter, it would be half the circumference, but you'd have to add the diameter as the length of the flat side.\n\nCircumference of a full circle = pi d\nPerimeter of a semicircle = (pi d)/2 + d
1024156
Circumference is 25,000 miles.  the diameter is about 7,950 miles, just under 8,000 miles (the earth isn't quite a sphere, it is a little pudgy at the equator, so the diameter varies slightly for our "oblique spheroid" which isn't a perfect sphere).
160871
Divide 34 by PI...that will give you the diameter.\n\nDiameter = Circumference / PI
894020
Here's a method to measure pi.  You'll need a greasy marker, a wheel, and a flat surface to roll it on.\n\nMark a spot on the wheel with the marker.\n\nRoll the wheel on the floor long enough for the mark on the wheel will make two marks on the floor.\n\nMeasure the distance between the two marks on the floor - that's the circumference of the wheel.\n\nMeasure the diameter of the wheel.\n\nPi is the ratio between the circumference and the diameter.  Voilà!  Of course, this is subject to measurement error but you should get a pretty good approximation.
256350
a wheel of radius 7 in. can travel 2 circumferences in 2 revolutions.\n\nCircumference is:\nC = 2(pi)(r)\nC = 2(pi)(7 in)\nC = 14pi in.\nTherefore,\n2C = 28pi in. or 87.9646 in.\n\n1.\nC = 2(pi)(r)\nsolve for r(radius)\nr = C/2pi\nSince you know the circumference, simply substitute:\nr = 120cm/2pi\nr = 60/pi cm or 19.0986 cm\n\n2.\nA = aP/2\na = apothem\nP = perimeter\n\nGet the perimeter:\nP = 5(23.8 cm) = 119 cm\nto get the apothem, get a half of the measure of an int. angle of a regular pentagon:\n54degrees\nUsing trigonometry:\ntan 54 = a/(half of side)\na = (11.9tan 54) cm\nThus, area is\nA = aP/2\nA = 11.9tan 54 cm * 119 cm/2\nA = 11.9²*(tan 54)*5 cm² \nA = 708.05 tan 54 cm² or 974.5472 cm²\n\n3.\nUse the formula again, but this time solve for a:\nA = aP/2\n2A = aP\na = 2A/P\nP = 8(20 ft)\nP = 160 ft\na = 2(690ft²)/160ft\na = 69/8 ft\na = 8.625 ft\n\nHope this helps ^_^
554627
the circumference of a circle can be calculated by using the formula:\n circumference of circle=2*pie*r\n where pie=22/7;it is equal to 3.1415;\n r=radius of the circle.\nThanks.
736264
Manhole covers must be a minimum of 22 in (56 cm) in diameter, but can be as much as 60 in (1.5 m) in diameter.  Without knowing the specific diameter, we won't be able to give you the circumference.\n\nIf you do have a diameter, though, the circumference is:\nC = pi * diameter.\n\nUsing the numbers above, the circumference of a manhole cover will be between 69 inches and 189 inches.
333495
The scale would tell you that.  For example a hot wheels car is 1:64 so 1 inch on the hot wheel is 64 inches on the real car.
41743
It's "circumference", and it's the boundry of a circular area, and actually, it's not that hard. \n\nThe circumference is the length of the outside boundry of a circle expressed as 2*pi*r ("pi" = the pi constant, sometimes abreviated as 3.14 and "r" is the radius or half of the distance across the circle. You can also do simply ). It's the length you'd get if you were to wrap a string around a balloon and measure it.
137248
Here's one:\n\nhttp://www.wheelmax.com/Wheels/bsa/bsa.htm
814785
bikesdirect.com has guidelines on the size.
426870
I picture an axle with one wheel bigger than the other for this problem. Since they're not spinning, wheel A has to cover the same amount of distance wheel B covers in the same amount of time.\n\nWheel A has radius 12cm and rotates at 35 radians/second:\n12 cm * 35 rad/sec = 420 cm / sec.\n\nWheel B must also cover 420 cm each second. So we work backwards:\n\n(420 cm / sec) / 17 cm = 24.7 rad / sec\n\nSo you're right, B is the correct answer.