Math Question (Geometric Sequences)?
399499
x=2 and A=5/8 so sub2 = 1 and 1/4\nFirst we solve for X\n20 * x^4 = 320\nx^4 = 16\nx = 2\n\nThen we solve for A\n2^5 * A = 20\n32 * A = 20\nA = 20/32\nA = 5/8\n\nThen we go back and plug it in to sub 2\n5/8 * 2 = 10/8 or 1 and 1/4
815660
Easy!!!\nYou're all wrong! it's not an arithmetic sequence! you have just put logic into it and just add & minus and use your common sense!!\n\nBut the pattern is a pythagorean triple!! so the answers are:\n\n√5 and 3612!!\n\nWhy?\nsimply because terms 1,2,3 form a pythagorean triple!\n\nCheck!\n(√5)² + 2² = 3² is the equation true?\n5 + 4 = 9\n9=9 TRUE!!!\n\nso the answer is √5\nnext terms!\n3 4 and 5\nCheck:\n3² + 4² = 5²\n9+16=25\n25=25 TRUE!!\n\nNext!\n5, 12, 13\nCheck:\n5²+12²=13²\n25+144= 169\n169=169 TRUE!\n\n\nNext!\n13,84,85\n\n13²+84²=85²\n169 + 7056 = 7225\n7225=7225 TRUE!\n\nLAST!!\n85,3612,3613\n\n85² + 3612²= 3613²\n7225 +13046544 = 13053769\n\n13053769 = 13053769  TRUE!!!\n\nSO the answers are!!\n\n√5 and 3612!\n\nThat's all!! ^_^!!
695801
I forgot too much about this stuff to prove convergence.  However, if you can take care of that side of things...\n\nKnowing that the sequence converges, then consecutive terms are nearly equal as n grows larger.  This means\n\nlim(n to inf)  X_(n+1) = X_n\n\n0.5(a+X_n) = X_n\n\nX_n = a.\n\nEDIT: I got something better, you can show that\n\nX_n = a/2 + a/4 + a/8 + ... + a/2^n + X_0/2^n\n\nwhere X_0 is the initial term.  Of course X_0/2^n converges to zero so you're left with a geometric series.
957591
line = 1 side\nparallel lines = 2 sides\ntriangle = 3 sides\nsquare/ rectangle = 4 sides\npentagon = 5 sides\nhexagon = 6 sides\nheptagon = 7 sides\noctagon = 8 sides\nnonagon = 9 sides\ndecagon = 10 sides\n\ni hope i have helped you.... good luck
664851
Dear, Your answers with complete explanation are below:\n\n1. Take any 2 terms, say 1/3 and 1/9.\nthe ratio is  = 1/3 / 1/9 = 1/3.\n\nSum of a geometric series to 'n' terms is given by:\nS(n) = a(r^n - 1)/(r - 1),\nwhere, \nS(n) = sum upto n terms\na= first term\nr=ration between 2 consecutive terms\nn= no. of terms\n\n2. Here,\n\nr= 1/3\nn= 10\na = 1.\n\nSo, S(10) = (3^10 - 1)x3 / 3^10 x 2.\nS(10) = 1.49997459 ~ 1.4999746\n\n3. Similarly, S(12) = 1.499997177\n\n4. If there are infinite terms in a geometric series, then its sum is = a/(1-r)\n\nHere this is = 1/(1-1/3) = 3/2 = 1.5\nSo, this series is always less than 1.5.
844539
1. An arithmetic sequence has a(sub 5)= -10 and a(sub 12) =18. Find a(sub 2) and a(sub 17)\n\nLet a(sub 1) = a and d = common difference.\nFor an AP:\na(sub n) = a + (n - 1)d\n\nSo a(sub 5) = a + 4d = -10 .... (1)\nand a(sub12) = a + 11d = 18 . (2)\nEquation (2) - equuation (1)\n7d = 28\nSo d = 4\nSo a = -26\na(sub 2) = a + d = -22\na(sub 17) = a + 16d = 38\n\n2. Find s(sub 4) for the geomtric sequence: \na(sub 1) = 5p, a(sub 2) = -10p\n\nLet a(sub 1) = a and common ratio be r\n\nFor a GP\na(sub n) = ar^(n-1)\n\na(sub 1) = a = 5p .......... (1)\na(sub 2) = ar =  -10p ..... (2)\nEquation (2)/equation (1)\nr = -2\n\nSo a(sub n) = 5p * (-2)^(n-1)\n\ns(sub n) = a(r^n - 1)/(r - 1)\n= 5p((-2)^n) - 1)/(-2 - 1)\n= -5p/3 ((-2)^n - 1)\n\nSo s(sub 4) = -5p/3 ((-2)^4 - 1)\n= -25p
1089657
1)Linear Sequences : ex. a=2n , n>=1:\n1,2,4,8,16,32,...\n\n2)Quadratic Sequences : ex. a=n^2 , n>=2:\n4,9,16,25,36,49,64,81,....\n\n3)Cubic Sequences : ex. a=n^3 , n>=2:\n8,27,125,.....\n\n4)Polynomial Sequences : ex. a=2^n , n>=0:\n1,2,4,8,16,32,64,128,....\n\n5)Factorial Sequences : ex. a=n! , n>=0:\n1,1,2,6,24,120,....\n\nAll the above are devided into 2 major types : finite and infinite sequences...
771405
40.\nhttp://www.research.att.com/~njas/sequences/b000602.txt
649237
you will get the answer for all sequences BEST WEBSITE \n\nhttp://pirate.shu.edu/projects/reals/numseq/sequence.html
149999
A regular n-gon has the centers of its inscribed and circumscribed circles the same point. If you draw segments from this center to each of the vertex, you will get n number of radii and n number of triangles, which are all congruent. Using derivation you will arrive at the conclusion that\nA = .5aP or A = .5ans where\nA is the area, a is the apothem, s is the side and P is the perimeter\na =2A/ns\nThe radius is acquired by\nsin [180degrees(n - 2)/n] = a/r\nr = a/sin[180degrees(n - 2)/n]
1017007
Ive noticed you were asking quite alot of these geometry questions. I think you should pay more attention in class and you wouldnt need to ask home work questions, and plus, just knowing the answer wont help, youll have to know how to do it, especially if this is for a final exam...
256555
The geometric mean of two numbers is the square root of their product.  So multiply 9 times 81 and do the square root of the answer.
17334
Geometric -- multiplying the previous term by 4
286004
What is the relationship between the items in the sequence? If you are adding the same thing over and over, it is arithmetic (2,4,6,8,10). If you are multiplying by the same thing over and over, it is geometric (2,4,8,16,32).
278116
1:C\n2:A\n3:D\n4:D\n5:A\n6:D
986577
a) "Suppose Triangle ABC and Triangle DEF are congruent."\nb) "Suppose there exists a line segment with at least two right bisectors."\nc) "Suppose there is an isosceles triangle for which the angles opposite two of its congruent sides are not congruent."\nd) "Suppose there is a line segment with at least two midpoints."\ne) "Suppose there are two intersecting lines such that opposite angles are not congruent."\nf) "Suppose AB is not equal to CD."
792610
Try these;\nhttp://www.mathleague.com/help/geometry/geometry.htm\nhttp://www.coolmath.com/home.htm\nhttp://www.ics.uci.edu/~eppstein/geom.html