How to measure dia-inch in piping works?
409033
a vernier caliper should do the trick.  it can measure the inner and outer diameter
878674
Use the micrometer caliper to measure the diameter of the copper wire. \nThe micrometer caliper is used to measure distances with more precision than a vernier caliper. It has a 0.5 mm pitch screw, this means that you read millimeters and half millimeters along the barrel. Every revolution of the ratchet knob will open the jaws a half millimeter. The sleeve is divided into 50 divisions corresponding to one hundredth of a millimeter (0.01 mm) each. To take a measurement place the object between the anvil and the spindle, grip the ratchet and turn until the object is lightly gripped, do not overtighten. The first part of the measurement is taken from the barrel, each division is 0.5 mm, note that the millimeters and half-millimeters are on opposite sides of the line. Next obtain the reading of the sleeve and add this value to the reading you obtained from the barrel. \n1. Obtain the reading when the surfaces of the anvil and the spindle are in contact. This is the zero reading of the micrometer caliper, it can be either positive or negative. Record the zero reading to 0.0001 cm.
751939
you can either do the math, look it up on a chart or go here:\n\nhttp://leebrewery.com/hydromet.htm\n\nand use the java-calculator.
175063
2.54 centimeters in an inch\n25.4 milimeters in an inch
748854
You are correct... just divide by 12, so 2.989E-8 slugs/in-s.  The only unit you are changing is the length.  I had no idea people used the slug/ft-s as a unit of viscosity.
1051954
All you need to do is know the density of water- not too difficult to find! THe psi necessary to support a column then must match the weight of that column. So, if a column is 1inch in area and Hinches high, if you know D the density of water per cubic inch in pounds, the height of the column in inches times this value is the psi needed.\n\nPressure psi=H*D\n\nThis also works for metric, just use cms and kgs as the base sizes.
1006839
if u recollect the equation,\n             resistance (r)= pl/A;\n        where p=specific resistivity\n                   l= length\n                   A= cross sectional area \n               Area = pie(3.414) * r2\n                  \n              but diameter is twic the radius.\nhence insulation thickness is dependent on pipe diameter.
579127
what is the diameter....? Just multiply the diameter times pi. (3.14)
389111
depends what you talking about. It can be in either inches or mm  There are other means of Caliber (see below)
481625
Yes, it is possible to find pressure drop per unit length from  some more information about density and viscosity of the fluid and roughness of the pipe. Any book on fluid dynamics gives the procedure.\n\nTheformula is:\nPr head = 2f(v^2/g)(N/D)\nwhere \nf= friction factor (generally found from a chart)\nv= average velocity of fluid \ng= conversion factor (having magnitude equal to std accln due to gravity)\nN= Equivaalent length\nD= diameter of pipe.\nYou have to follow some standard system to work out this problem (see standard reference)
503
That depends on what L and P are.  If you plug the permitter and length in, you can get width W.\n\nIf you want a formula that will yield W, it's: (P-2L)/2 = W
665408
Well you can look at it and measure the pitch, which is the longitudinal distance required for one revolution of a braid wire around the hose. Or you can measure it indirectly from the angle the wire makes to the longitudinal axis and the diameter of the hose, but it probably wouldn't be as accurate. The formula would be pitch = pi*diameter/tangent(braid angle).
1009332
Convert everything to inches, then multiply.  LxHxW.  They need to be the same units, though.
430786
The formula for the capacity or volume, V, of a cylinder is:\n\nV = Π(d^2)h/4\nwhere:\nΠ = 3.1416 (value up to 4 decimal places)\nd = diameter of the cylinder\nh = height of the cylinder\n\nSo, merely substitute the values that you have and you will get the capacity or volume of the cylinder. Just make sure to use similar unit of measures both for the diameter and the height.
137292
You didn't really give me too many options with this one.  Increase or increase?  I think I'll have to go with "increase."\nSeriously, if a pipet is dirty, most likely it is contaminated with a salt compound, which would contribute to the density of something you were measuring out with the pipet.
550617
Take a rope ( that doesn't elongate/stretch easily), wind round both pulleys (just the way belt goes)and mark one end where it touches the other. Measure this and the size in inches is the size of the belt. As to whether 'A' or 'B' or 'C', it is based on cross-section. The smallest is 'A'. I hope I am understood.
774461
Remember this magic number, 3.2808. Say for example 15 inch is 1.25feet. Divide it by 3.2808 gives u an accurate 0.381 number in metre. The use of the significant numbers is to prevent rounding off error.