solve the following  linear equation: x - y = 4 / 3x + 2y= 7?
408462
to solve such a system in general, what you do is this: take the first equation, solve it for x treating y as you would a constant. In your case, this is x = 4 + y.\n\nThen, take your expression for x and substitute it everywhere you see x in the second equation; in your case you get 3 *(4+y) + 2y = 7.\n\nSolve this now 1-variable equation for y, once you find y (in this case, -1).\n\nSubstitute the value of y into either equation, and you get the value of x (3 in this case).
917321
x+y=2\n2x-y=0\n\nx=2-y\n2(2-y)-y=0\n\nX=2-y     \n4-3y=0   \n\nx=2-4/3\ny=4/3
965380
(x - 3)² + (y + 2)² = 4²\n(C): x² + y² - 6x + 4y - 3 = 0
770834
y=x+3\ny=2x-4\nfirst u need to replace the x+3 in place of y in the 2n equation to get this\nx+3=2x-4\nthen subract the x from both sides to get this\n3=x-4\nthen add 4 from both sides to get this\n7=x\nthen replace the 7 in one of the equations to get y to get this\ny=7+3\nthen you are going to get the anser like this\ny=10\nthe answer is (7,10)
900384
suppose 2x-4=y then your equation is:\n\ny^2-4y-21=0 by solving this equation:\n\ny=(4(+-) (4^2-4*(-21))^0.5)/2 = (4(+-) 10)/2\ny1=7 and y2= -3 now\n\n2x-4= 7 then x1=11/2\n2x-4= -3 then x2=1/2
586962
(6y^2-3y)(y+7)-->(2y)(y-1)(y+7)\nif that helps
714828
You need to solve one equation for x or y then substitute it into the other.  The equation easier to solve for is -3x + 4y = 2.\nAdd 3x to both sides and divide by 4 to get\ny = 2/4 + 3/4 x\n\nThen plug this in for y in the first equation\n\nx^2 + (2/4 + 3/4 x)^2 = 5\n\nx^2 + (1/2 + 3/4 x)(1/2 + 3/4 x) = 5\n\nx^2 + 1/4 + 3/8  x +  3/8 x + 9/16 x^2 = 5\n\nmultiply all by 16\n\n16x^2 + 4 + 6x + 6x + 9x^2 = 80\n\nCombine and move the 80 over\n\n25x^2 + 12x - 76 = 0\n\nFOIL: (x+2)(25x - 38) = 0\n\nso x = -2 or 38/25\n\nPlug these in to get y
95804
You know that\n              1)3x+4y=12y\n              2)-2x+10=12y\nSo you can substitute 3x+4y for 12y in equation 2. Hence:\n              3)3x+4y=-2x+10\n                   5x=10-4y\n                    x=2-4y/5\nSubstitute this value for x into equation 1 and it becomes:\n              1)8y/5+6=12y\n                     y=15/26\nPlug this back into 3 and you get\n              3)x=2-(4/5)*(15/26)\n                x=20/13\nTherefore the answer to the system is (x,y)=(20/13,15/26)
225766
Given, x = 1/2y + 4 ............(i)\n and   2y +3 x = 12 ............(ii)\nSoln.: Multiply both side by 2 in eqn. (i)\n      2x = y + 8\ni.e.  2x - y = 8\ni. e. 4x - 2y = 16....(iii), multiplying both the side by 2\nNow, add eqn. (ii) and (iii) above,\n (2y+3x)+ (4x-2y)= 12 + 16\ni.e. 7x = 28\ni.e. x = 28/7 = 4.Ans.\nNow putting the value of x = 4 in either of the eqn. above, find out the value of y. Say, put value of 'x' in eqn.(ii),\n2y + 3x = 12\n2y + 3x4 = 12\n2y + 12 = 12\n2y = 12-12 = 0\nSo, y = 0/2 = 0 Ans.
700548
So x4-5*y2*x2+4*y4=0; or (x^2-y^2)*(x^2-4y^2)=0; or (x-y)*(x+y)*(x-2y)*(x+2y)=0\nIt splits into independent linear equations: (a) y=x; (b) y=-x; (c) y=0.5*x; (d) y=-0.5*x;\nNow exclude (a) & (c); thus (x+y)*(x+2y)=0; did you mean it Don?
296060
5x-2y=7\n3x+4y=2\n\n5x-2y=7 (multiply this by 3)\n3x+4y=2 (multiply this by 5)\n\n15x-6y=21  (now subtract the bottom from\n15x+20y=10  the top)\n\n-26y-11 (y=.42 then substitute y in the problem)\n\n15x -6*.42=21 (then solve from there)
701107
4x +y = 16   ;2x + 3y = 24      Multiply the 2nd with -2, that gives -4x -6y = -48    Add the two:   0x - 5y = -32  \nDivision by -5 gives  y = 6,4\nInsert this value into the first equation:   4x + 6,4 = 16\n4x = 9,6 ;    x = 2,4\n\nNumber 2 is even easier:\nMultiply the first equation by 2 and add the equations.\n24x + 2y = 50    plus   8x - 2y = 14  gives  32x = 64; x = 2\nYou can now choose:  24 + y = 25  or  16 - 2y = 14\n(That you get when you replace in the original equations \nx by 2)  Anyhow you'll find   y = 1
490656
Make Y=0\nyou have to have m and x though to solve b\nExample:\nY=mx+b\n0=3(4)+b\n0=12+b\n -12 on both sides of equal sign\n-12=b\nhope this helped!
741586
set y=0\nsolve quadratic eqn\nquadratic eqn\n\n-7 +- (49-16)^.5\n-------------------\n2\n= (-7 +- 33^.5)/2
744326
yes!  \n\n2x-3y=7\n\n-2x from each side of the =\n\n-3y=-2x+7\n\n-3y/-3 and -2x+7/-3\n\ny=2/3x+-2.3\n\nGo to -2.3 on the Y-intercept\nThe slope is 2/3 (up 2, over 3)
715249
2x - y = 7...Equation A\n\nx + 4 = 8...Equation B\n\nWe can find x in Equation B by subtracting -4 from both sides.\n\nWe get this:  \n\nx = 8 - 4\n\nx = 4\n\nNext, plug 4 into Equation A to find the value of y.\n\n2(4) - y = 7\n\n8 - y = 7\n\n-y = 7-8\n\n-y = -1\n\nYou need to divide each side of the equation by -1 to find y.\n\nDoing this we get:\n\ny = -1/-1\n\ny = 1\n\nTo check if I am correct,\n\nplug your value for x and y into BOTH original equations to see if BOTH SIDES of BOTH equations are equal.\n\nGuido
698387
y= -(2/3)x^2 + (2/3)x + 4\n\n\n(P): y = ax^2 + bx + c\n\nPoints (0;4)  (-2;0)  (3;0) are element of (P)\n-->  4 = 0a + 0b + c --> c = 4\n0 = 4a - 2b + c\n0 = 9a + 3b + c\n\n--> 5a + 5b = 0 --> b = -a\n--> 4a + 2a + 4 = 0 --> a = -2/3,  b=2/3