Find the slope of the line going thru the pair of points: (3-7),(615)?
407918
(3,-7)(6,15)\nm = (y2 - y1)/(x2 - x1)\n\nm = (15 - (-7))/(6 - 3)\nm = (15 + 7)/3\nm = (22/3)\n\nANS : (22/3)
903023
M (-7, -3) is the midpoint of segment PQ and the coordinates of Q are (6, -3).\nLet the co-ordinates of P be (x,y).\nThen, (-7,-3) = ((x+6)/2, (y-3)/2)\n=>(x+6)/2 => -7 , (y-3)/2 = -3\n=>(x+6) => -14 , (y-3) = -6\n=>x => -14-6 , y = -6+3\n=>x => -20 , y = -3\n\nSo, co-ordinates of point p are (-20, -3)\n\nAll the best
32903
if you are given points (ex. (2,1) and (3,5) you can use this formula:\nm (slope) = y2-y1 / x2-x1\nso: 5 - 1 / 3-2 = 4/-1 or -4\n\nif you are given the equation of a line you can use this:\nx - ay = b\ny = -x + b / -a\nex.x-3y = 15\n-3y = -x + 15\ny = x/3 + 15\nso the slope is:\nx/3 = 1/3\nm(slope) = 1/3\nalways look for the coefficient of x and that is the slope.\n\nyou can also use this when you are given an angle:\nm (slope) = tan alpha
35268
slope = (-4-(-6))/(-2-0)\nslope = -1
89344
Use the two given points:\n(x1=7, y1=5) and (x2=-1, y2=1/5)\nand the "two point equation":\ny-y1 = ((y2-y1) / (x2-x1)) * (x - x1)\nto get started on this problem.\n\ny-[5]=(([1/5]-[5]) / ([-1]-[7])) * (x-[7])\ny-5=((-24/5)/(-8))*(x-7)\ny-5=(3/5)*(x-7)\n\nNow put the equation into the "slope intercept" form of y = mx+b.\n\ny-5=(3/5)*x - (21/5)\ny=(3/5)*x - (46/5)\n\nThe slope = 3/5\nThe intercept = -46/5
819556
Hey, here's the setup for these types of problems.\nYou want the equation in the form of y = mx + b\nsince we know that x = 2, y = -7, and m = -1/5, we can plug these values into that equation to find the equation of the line that passes through the desired point. SO:\n-7 = (-1/5)(2) + b\n-7 = (-2/5) + b\nb = (-7)+(2/5)\nb = -33/5\nso the equation for the line is:\ny = (-1/5)x - (33/5)\n\nhope that helps!!
754086
the slope will be (0 + 9) / (-8 +7) = 9/-1 = -9 --> m = -9\n\nnow take a point and plug it in to the formula y = mx + b.\n0 = -9(-8) + b ---> b = -72\n\nnow your done. y = -9x - 72
316654
The midpoint of that segment is (3, -2) - all you do is take the average of the x coordinates and the average of the y coordinates.\n\nThe slope of that segment is found by\n\nm = (y2 - y1)/(x2 - x1)\n= (1 - (-5))/(4 - 2)\n= 6/2\n= 3\n\nSince you're looking for a line perpendicular to this one, take the slope, invert it, and change the sign.  So the slope of the new line will be -1/3.\n\nNow you have a point and a slope for the new point: m = -1/3, and point (3, -2).  Use the point-slope formula to find the equation of the line:\n\ny - y1 = m(x - x1)\ny - (-2) = (-1/3)(x - 3)\ny + 2 = (-1/3)x + 1\ny = (-1/3)x - 1
877049
use the slope formula.\n\ny sub 2 minus y sub 1 divided by x sub 2 minus y sub 1\n\nthen you get 1-5 divided by 0-2\n\nthen you get -4 divided by -2\n\nthe answer is 2
851755
the slope of the line can be figured out with a simple formula.  If the question gives you two points all you have to do is plug into the formula delta y over delta x.  this means take the two y coordinates and subtract them from each other and divide that by the same thingy with the x coordinates. \nFor example. ( 0, 0) and ( 1, 2) What is the slope between those two points?\njust do (2 - 0 ) over ( 1 - 0 ) = 2/1 = slope of 2\n\nThe other method is to draw a line between the two points and count the boxes (on graph paper)  you first count to the left then up. so it would be starting from (0,0), you count 2 boxes to the left, then 1 up.  that would be 2/1 which is slope of 2.
729746
you solved it right, since the line BC never goes up/down(the y-coordinate never changed, graph it and you'll see) the slope is 0. and 0/7=0, so you're right.\nit would be impossible if you got 7/0, because you can't divide by 0.
1164791
y=mx+b\n2=2(3)+b..... (in this you know the slope is 2 b/c the line is parallel.\n2=6+b\n-4=b...... (so now you will want to write your equation for your line)\n\ny=2x-4..... (DONE!)
1075301
find the slope, m, of your line (-2/3 in this case). \n\nThe slope of any perpendicular line will be -1/m (3/2 in this case).\n\nSo for any real number b,\n. . . . . . . y = (-1/m)x + b = (3/2)x + b\nis the equation of a line perpendicular to the original line.
516608
I hope this helps you solve these types of problems. \nThere is only one straight line that you can draw that passes through both points. The equation of this line will be in the form y = mx + b where m is the slope (rise/run) and b is the y "intercept"(the value of y when x = 0) \nTo find the equation you must find both m and b.\nm = rise/run \nThe rise is the difference between the values of y for the two points = 1 - (-6) = 7\nThe run is the difference between the values of x for the two points = 3 - (-2) = 5\nSo the slope m = 7/5.\nSo we have y = (7/5)x + b. But we still need to find b.\nTo do this, you plug in the values of x and y for either one of your two points. We'll use 3,1. So we have:\n 1 = (7/5)3 + b and so b = 1- (21/5) = -16/5. This means the line crosses the y axis at y = -16/5\nWe now have the equation to the line:\ny = (7/5)x - 16/5
791058
The slope-intercept form for a line is y=mx+b, wherem is the slope and b is the y-intercept. Comparing this form to y=7x+3, you see that m=7 (the slope) and b=3 (the y-intercept).
371794
slope = (-1-2)/(-1-0) = -3/-1 = 3
194347
9x-6y+7=0  You change this to\n\n-6y=-9x-7  so it is in y=mx+b form.\n\nNext you divide by -6\n\ny=(9/6)x+(7/6)\n\n7/6 is your y intercept. (1.6666...)\nand 9/6 is your slope.  (1.5)\n\nTo find the x intercept you put 0 in for y\n\n0=(9/6)x+(7/6)\n(-7/6)=(9/6)x\n-7=9x\n-7/9=x\n\n-0.777...=x intercept