How do you calculate resonance in a tube?
404818
Wave length and frequency are inversions.\n\nThe average speed of sound is 343 meters per second.\n\nA 1 meter wavelength then would be a frequency of 1/343 hertz.\n\nA tube will produce most easily a wavelength equal to it's length.  It can also produce a wave length of twice it's length.\n\nAll other tones will be some division of these lengths.\n\nA 12 meter tube would produce wave lengths of 24m (twice the tube) 12m (equal), 6m (half), 4m (a third), 3m (a quarter), 2m (a sixth) etc.  They will all will be completely divisible into the tube.\n\nThat makes frequencies of 12/343 Hz, etc.
315859
you got Ohm law : Ur=R*i(where i stands for current) and what's more, for the coil we have Ul=-L*di/dt . And for the condenser we have C*Uc=q and i = dq/dt.Now you have a differential equation with only one variable i.\n note: if the circuit is parallel then U should be a constant , in this case you shuold use U instead of i.Goodluck
379771
http://www.mikeholt.com/mojonewsarchive/EC-HTML/HTML/WyeTransformerCalculations~20030916.htm
388634
Inductive reactance can be calculated using this formula: XL = 2πfL\n\nGood Luck
799770
Sounds like a heat transfer question.  If so it depends on how the tube is being used.  \n\nFor a single pipe exposed to heat transfer to air, the outer diameter is used to determine the surface area.  For shell and tube exchangers they have charts for making the determination based on the tube configuration and baffling.
892848
One of the most frequently used is E=IR    ;E =voltage    I=current   R= resistance. U can change this every way depending on the unknown.\n    Good luck
1017019
you have to \n\n1. Determine the lengthy upto which the helical reinforcement is to be provided Let=L\n2. Determine the pitch =X\n3. Determine Y=L/X\n4.LENGTH OF HELICAL REINFORCEMENT=Y*3.1415*(SQRT  ( X SQ + D SQ ) )  WHERE D IS DIA OF HELICAL REINF.IN MM
810714
the velocity of fluid flow is proportional to area.\nfind the total area of one 4 mm tube compared to 2  mm tubes.  Here is a hint, they wont be the same.
899661
This will take a few steps.\n\nStep 1.  Find the equivalent resisitance of the 12 and 4 ohm\nresitor.  Reqv = R1(R2)/(R1+R2) = 12x4/16 = 3\n\nSo you have a 3 ohm and 7 ohm resistor in series.  This gives\na circuit current of V/Rtotal = 20/10 = 2amp\n\n\nNow the voltage drop across the 7ohm resitor is 7x2 = 14 volts\nand the voltage drop across the equival 3ohm resitor is 3x2 = 6 volts.\n\nThis 6 volts is across the 12 ohm resitor, so the current\nthrougth it is V/R = 6/12 = .5
638457
its the rhythm \nin physics it is called Resonance\ncheers
763289
You need to post some details - then I can post an answer...\n\nIn general, P = V*I = V^2/Z\nso calculate the complex impedance Z (= R+jX)\nthen take the real component of the complex power.
604852
Here are a couple of web sites that approach this in different ways. \n\nhttp://www.circletrack.com/techarticles/84199/\n\nhttp://www.diracdelta.co.uk/science/source/e/n/engine%20excitation%20mechanisms/source.html\n\nHope these help.
869184
You will find all details with calculation and experiment on:\nhttp://www.jgp.org/cgi/reprint/1/4/387.pdf
314766
For A), use the Poisson distribution. M. Poisson was a French mathematician whose name also happens to mean "fish" in French. To those who disagreed with him, M. Poisson said, "One man's meat is another man's Poisson!" \n\nIf you tested 20 tubes many times, on average 4 of them would last more than 500 hours (.20 of 20). The formula you need for the probability of exactly 5 lasting more than 500 hours is\n\nP(5) = e^-4 * (4^5/5!)\n\nThis is not so hard to compute. 4^5 is 1024, and 5! is 120. So we have\n\nP(5) = e^-4 * 1024/120\n\nP(5) = 0.018 * 1024/120 = .156\n\nFor B), I don't whether (1 - x) is in the exponent or is a factor of multiplication. Please clarify with parentheses or asterisks.\n\nf(x) = Ax^[2 * (1 - x)] ?\n\nor\n\nf(x) = A * (1 - x) * x^2 ?\n\nI see that math girl is using the latter, wherein (1 - x) is a factor of the multiplication. In that case, I agree with her that A = 12, for the reason she gives that the integral from 0 to 1 is equal to 1. She gives you the expression for the integral so you should be able to find the value of it over the interval 1/3 to 1/2. If not, choose this answer as best and ask me to integrate your expression from 1/3 to 1/2 for you.
430403
i presume you have the energy values for the different levels?\n\nif so you use the equation E=hc/lamda to find the wavelength for each energy transition in the series.\n\nThe red line will be about 575nm and the purple line will be about 375nm.
164646
You mean a 'frequency of 5.10^12Hz'\n\nCan you work it out yourself?:\n\nRemember that the speed (v) of the wave is 3×10^8 m/s,\nand that the wavelength is given by v/f\n\n[Edit: Darn, Kirchwey - don't do Glow's homework for her! ;-) ]
856026
Use the gas law\nPV=nRT