the volume of cube is given by v=s^3 find the lenghth of a side of cube if the volume is 729 cm^3?
408271
take the cube root of 729 u get 9
6863
Congrats on being so advanced in math.  That's great!\n\nVolume of cylinder = π x R x R x H = π x (R^2) x H\n\nA square has an area, not a volume.\nThe area of a square = S x S = S^2\n\nIf you meant the volume of a cube,\nthe volume = S x S x S = S^3
626725
First you need the area of a single face, to do this you need to multiply one side of the face (square) by another adjacent (next to) to the first, this will give you the area if a single face; then you just need to multiply that times six wich is the number of faces in a cube. Depending on the mesuring system that you are using, i.e. metric, standard, etc., you will end up with a number followed by cm.2 or ft.2, that "2" means that you are talking about area and not distance nor volume or any other; it avoids confussion.
875857
find what?...the dimensions of the box with the most volume?\n\nArea = w^2 + 4wh = 1100 cm^2\nh = (1100 - w^2 ) / 4w\n\nVolume = h w^2 =\nV = w^2 * (1100 - w^2 ) / 4w \nV = w (1100 - w^2 ) / 4\nV = 275w - (w^3)/4\ndV/dw = 275 - (3/4)w^2\nlet dV/dw = 0\n(3/4)w^2 = 275\n\nw = 19.15 cm\nh = 9.57 cm
594682
v=4/3pi x R^3\n4/3 pi x 512\n4.17 x 512\n2,138.21 mm-cubed
731102
consider the front face to be an A by A square that has depth length L.  The Volume of this rectangle would then be A*A*L.  since we know A + L =108. Then L = 108 - A.  Putting this into our volume formula we get 108A^2 - A^3.  In order to maximize A take the derivative and set it to zero.  So we have 216A - 3A^2 = 0.  This leads to A = 72 cm.  Then L would be 108 - 72 = 36cm.  The maximum volume would then be 72 * 72 * 36 = 186,624 cm^3
788320
If it's a cube, all sides have to be squares.\n\nIf the surface area of one side is 1, then the the length of each edge is also 1.\n\nThen, the diagonal of a side would be √(1² + 1²) = √2\n\nAnd, not sure if this is what you're asking, a diagonal connecting one corner of the cube to the opposite corner would have the diagonal of one side as a base, and an edge as the other side, so it would have length √(1+2) = √3
866689
at the vortex, the degree measure would be 45. at a cube's vertex, the degree measure is 90. so if it passes it (between the middle, of course) you have half of 90 degrees one each side.\n\n45
1001765
If d times d times d = p times p and p = 9,\nThen 9 x 9 = 81.  What is the cube root of 81? It is 4.3
637876
v=4/3 pi r^3 (four thirds x pi x (r cubed))
529963
The volume of a sphere is (4/3) pi r^3\n\nIf r is in meters than the volume is in cubic meters.\n\nFor r = 123,234,000 meters, the volume is \n\n2, 495, 343, 701, 035, 872, 000, 000, 000 pi\n\nor a little over\n\n7, 839, 353, 439, 355, 860, 807, 159, 721. 15 cubic meters\n\n(where the spaces keep Yahoo Answers from truncating the number and replacing the chopped off part with "...")\n\ni.e., approx.\n\n2.494E+24 pi or 7.839E+24 cubic meters
920811
The volume available in simple terms is Length (L) times Width (W) times Height (H).:: V=LxWxH\nMultiply this by the density of what is in the volume and you have the weight.\nExample: a one foot cube of steel (density 0.2833 lbs/in3)\n12x12x12x0.2833=489.54 lbs \nNOTE: watch your units
895037
surface area of a cube is 6a^2\nvolume=a^3\ntheir relation: V/SA = a/6\n\nif its cut into half, volume will be:\n(a/2) x a^2 = (a^3) / 2\nthe surface area will be 2a^2 + 4a(a/2) = 4a^2\nnow their relation: V/SA = a/8\n\nnote: crazy horse's answer went wrong when he assumed a halved cube has only two of its sides halved. in fact, it has its 4 sides halved.
726531
A=1/2bh is for the area of a triangle.\nV=s^3 is for the volume of a cube.
975485
H*W= area\nheight times width\n\none side has a height of 8 and its width is 9 thus the area would be 72
937032
I'm assuming:\nThe box has a square top and bottom.\nThe volume v is fixed.\nr is the length of a side of the top.\nh is the height of the box.\n\nv = r^2*h\nh = v/r^2\n\nThe surface area is a top and bottom both r x r and\nthe sides which are r x h.\n\nArea = 2*r^2 + 4*r*h = 2^r^2 + 4*r(v/r^2) = 2r^2 +4v/r\n\ndA/dr = 4r -4v/r^2\n\nSet to 0 and solve\n0 = 4r -4v/r^2\n\n0 = 4r^3 -4v\n0 = r^3 - v\nv = r^3, or  r = v^(1/3)\nThat means that the container is a cube.
63817
tsniperx\n2 months ago\n\nVolume of one block cube = 10cm*10cm*10cm = 1000cm^3\nVolume of two block cube = 2000 cm^3\nVolume of one sphere = (4/3)*pi*r^3 = (4/3)*pi*(5cm)^3\nVolume of one sphere= 523.59877 cm^3\n\nno spheres= Volume of clay / Volume of sphere= 2000cm^3 / 523.59877cm^3\nNo spheres must be integer = 3 spheres