how many seconds are there in a year?
402818
31,536,000 in a normal year or 31,622,400 in a leap year.\n\nStrictly speaking the answer is usually 31,536,001 in a year and 31,622,401 in a leap year because most years there's a 'leap second' added and very occasionally there are 2 leap seconds added.
458563
Leap years only occur in years that can evenly be divided by 4.  \n\n2004\n2008\n2012\n2016\n2020\n2024\n2028
523376
Ok-An average  year is 365.2425 days = 8,765.82 hours = 525,949.2 minutes = 31,556,952 seconds. Multiplied by 2004 years =63240131808 seconds.  We have been through an additional 135 days =11664000 seconds. Plus 8 hours and 45 minutes = 31500.  Grand total = 63251827308 seconds, approximately. About 63 and a quarter billion seconds, give or take\n\nEdit- Long before 0000 (or 1 ad) there had been incredibly insightful plays written, multiple histories, and giant library at Alexandria, filled with human knowledge, trigonometry devised, the average circumference of the world calculated.  After the fall of the Roman Empire, we did not catch back up to the knowledge of 1 AD for over a thousand years...a long way from not knowing how to speak or read.
771065
Yes there is a better way than counting.\nBecause you have a leap year every four years, you can say that there are 365.25 days per year, as long as you deal in years that are multiples of four (which I will be doing). \n\nSo,  that means there are 52 + (1.25/7) weeks per year. \nThis is the same as 52 + (5/28) weeks per year. \nAs a top heavy fraction, this is 1461/28 weeks per year, and therefore there are 1461 weeks in 28 years. This is relevant because it is an exact number of weeks, the actual number 1461 doesn’t matter. This means that exactly 28 years ago, on 6 November, it was a Monday like it is today.\nSo, 6 November 1978 was a Monday.\n6 November 1950 was a Monday.\n6 November 1922 was a Monday.\n6 November 1894 was a Monday.\n\nWe have slightly overshot now, so we need to add on years. (I did this because it is easier to add than subtract, plus 1894 is closer to 1907 than 1922.)\nIn 4 years there are 208 weeks and 5 days (I found this by multiplying 52 + (1.25/7) by 4 to get 208 + (5/7) which is equivalent to 208 weeks and 5 days.)\n\nSo, 208 weeks after 6 November 1894, the date is 1 November 1898, also a Monday (because it’s an exact number of weeks later). 5 days later, it is a Saturday, on 6 November 1898.\nYou use the same process to find that it is a Thursday on 6 November 1902, and that it was a Tuesday on 6 November 1906.\n\nSince neither 1907 nor 1907 was a leap year (1904 and 1908 were), 365 days later it will be 6 November 1907.\n365 days is 52 weeks and 1 day. So, 52 weeks later, it is a Tuesday and the date is 5 November 1907, and the next day is 6 November 1907, and it’s a Wednesday.\n\nSo on 6 November 1907, it was a Wednesday.\n\nActually there is a slight problem with this method, because 1900 was not actually a leap year, but in this case it did not matter because the date is after 1900. You would have to adjust it very slightly for dates before 1900.
20659
yes you would have 60 sec per minute x 60 minutes per hour x 24 hours per day x 365 days per year x 65 years. = 2,049,840,000 seconds
708889
"The number of days in 1000 years is 1000 times 365, plus 250, minus 10, plus either 2 or 3, depending on which 1000 years we're talking about (there are 25 leap years in every century.  \n  \nThat would give us either 365242 or 365243 days in 1000 years. \n\nThere are 24 hours in each of those days, 60 minutes in each of  those hours, and 60 seconds in each of those minutes: \n\nTotal seconds: 315,569,088,000
852208
Sorry but milleniums are measured in years. there are 1000 years in a millenium.
797954
Only one at a time, genrally once a day. Around 1500 over a lifetime !
51580
Not quite. Years divisible by 100 are not leap years unless they are also divisible by 400. 2000 was a leap year, 2100 won't be a leap year.\n\nSo every 400 years you get 97 leap years, slightly less that 1/4.
646609
186,000 miles per second\n             11,160,000 miles per minute\n            669,600,000 miles per hour\n         16,070,400,000 miles per day\n      5,869,713,600,000 miles per year\n146,742,840,000,000,000 miles in 25,000 light years\nThat is some 146 quadrillion, 742 trillion, 840 billion miles
41539
36525 days (incling leap years)\n2191500 hours\n131490000 minutes\n7889400000 seconds\nwhich is one less second than we will have this century so use that extra second wisly by spending time with your family/friends/and learning a new language.
562130
An earth year (Gregorian calendar) is 365.2425 days \n= 31,556,952 seconds.\n\nA jovian year (one orbit of Jupiter around the sun) is 11.86 earth years.\n= 374,265,450 seconds.
789176
I'll take a simpler interpretation of the question and say one second is "calculated" to be 1/86400th of a day, where 86400 is the product of 24 hours times 60 minutes/hour times 60 seconds/minute. Problem is that the day (say from local noon to local noon by measuring the sun's highest point in the sky) is not constant throughout the year, so it was decided to use the average day looking over the whole year. \nFor very precise timings of experiments in the laboratory, one needs a very good pendulum or something else that oscillates or vibrates at a very constant frequency; then you can work back to what fraction of a day or how many seconds something takes. \nIn modern times cesium atoms provided the constant well defined measurable frequency, and scientists agreed to "define" one second as some number of these oscillations (9,192,631,770). Now when the earth decides to rotate at a different rate, scientists add leap seconds instead of redefining the second every year. \nLately the reliability of the cesium atom has been questioned, and since the speed of light (in vacuum) is defined as a fundamental "constant", the second can indeed be defined as how long it takes light to go some distance (299,792,458 meters), but that seems circular to me because I see a meter defined as how far light goes in 1/299,792,458 of a second.
769896
Seven wrong answers so far.  Apply a method similar to that described by Inquirer (the 7th answer) to find all 48 times this happens every day.\n\nThe other correct answer is 'none', since my digital clock doesn't have hands.
899482
You do 365 days times 24 hours, times 60 minutes, times 60 seconds.  So:\n\n1 year = 365 days\n1 day = 24 hours\n365 days = 8760 hours\n1 hour = 60 minutes\n8760 hours = 525600 minutes\n1 minute = 60 seconds\n525600 minutes = 31536000 seconds\n\n365 x 24 x 60 x 60 = 31536000
638017
start with the easy ones... all of 2007 and 2008 (a leap year), so that is 365 + 366 = 731\n\nnow for 2009, 31 + 28 + 3 = 62\n\nfor this year, if you include the 20th you have 12 + 30 + 31 + 31 + 30 + 31 + 30 + 31 = 226\n\n731 + 226 + 62 = 1019 (take off one day if you dont count the 20th)
1064894
365 days/year * 24 hours/day * 60 min/hour * 60 sec/min = 31536000 secs/year\n\nFor a leap year\n366 days/year * 24 hours/day * 60 min/hour * 60 sec/min = 31622400 secs/year\n\nSome would be tempted to give this answer:\n365.24219907407407407407407407407 days/year * 24 hours/day * 60 min/hour * 60 sec/min = 31556926 secs/year, however a calendar year does not contain partial days. Leap years are used to make up for the missing parts of the day.