How do you draw a graph with with the x, y, and z axis (making it 3D)?
400474
yes we can draw 3d picture in graph\nstep1: draw x,y,z axis\nstep:2 locate the points  for what u has to draw .location can be done similsr to x,y mappings like(0,1,2),(1,1,3) etc......................\nstep :3 hence a 3d pic formed but no 3d effects on graph
718943
openGL is the best for 3-D drawing.
816484
You need to do two things:\n1. set your window\n2. program the equations.\n\n1. At the top there's a 'Window' button.  You can set window parameters there.  However, I'd recommend using the 'Zoon' button and chosing option 6: ZStandard.  This will give you a good window.   You can change it later.\n\n2. The top left button says 'Y='.  Press this and program equation 1 then 'enter'.  This put you down one line so that you can program equation 2.\n\nTo run press the upper right hand button 'Graph'.\n\nAlso, go to the Texas Instruments website for help and to download an users manual.
556436
If you can plot (X, Y) points on a graph-there is an easy way to show the shape of a very basic parabola. \n\nUse (0, 0) as the vertex, or the point where it bends.\n\nNow Use the process called an X, Y table (its how you will plot out the basic equation (or function) of your parabola. Use easy numbers such as 3, 2, 1, 0 -1, -2 -3. That is all you need.  Often 1, 0 and -1 will work fine. Simply put any of the "easy" numbers go in for X. Solve through for Y (if X is 2 in Y=Xsquared+1 than Y will be 5) (2,5)\n\nThe easiest is Y=X squared, but just rememeber that since  both positives AND negatives square as positives. You will have (-1, 1) (-2, 4) (-3, 9)\nand also (1,1) and (2,4) and (3,9)\n\n Say for Y=x squared +2\n\nYou will have a vertical shift upward. Remember (0,0) as you starting point, now go up the Y axis two points and use the same process you did in y=x sqaured\n\nRemember that what you figure out as a positive with a negative its always backwards. So Y=x squared-2 will start at (0, -2)\n\nIf you have y=-x squared instead of facing up like in y=x squared, it will face down. \n\nThere is this rule to remember as well:\n\ny=A(X +OR- B)+OR- C \nSorry the computer doesn't let me say "plus or minus" any better way.\n\n1. +/- A amplitude \n\nY=3x sqaured will fatter than Y=Xsquraed, Y= 1/3x squared will look skinnier. \n\nNegatives Open downward, positives open upward.\n\n2.+ or - B : phase shift\nnegatives addded to X in parenthesis  move to the right, positives added to X in parenthesis move to the left. \nDONT WORRY ABOUT THIS ONE AS MUCH. \n\n3. = or - C: Vertical shift \nIF a negative number is added after X, move it down\n\nIF a positive number is added after X, move it up\n\n\nI said it both geometrically and algeabraically. Email me at josh_rittinger@yahoo.com if you still need help.
89202
Hi again, just graph the three boundary lines and shade the correct sides.  This will give you a shaded triangle with vertices (2,3), (4,5), and (4,0)  [I think; I don't have graph paper handy].  The maximum and minimum values must occur at one of these 3 sets of coordinates.\n\nfor (2,3), 3x + y = 9\nfor (4,5), 3x + y = 17\nfor (4,0), 3x + y = 12\n\nSo 9 is the minimum value and 17 is the maximum.\n\nCheck it out yourself to be sure the graphs really intersected where I thought they did!
133824
do your own homework!\n\nx=4, y=2, z=3
891091
Yes, It is possible if we use x,y,z plane in plotting graphs. When using this method we should be very precise.\n\n3D model gives very spectacular graphs. There is algebraic expression for many 3D shapes e.g sphere, cones
333191
Consider the function f as mapping the points x of a set X to the points y of a set Y. Draw a horizontal line (the x axis) so that each point on the line represents an element of the set X. Draw a perpendicular line (the y axis) to intersect the x axis at the null point or zero. Each point on the y axis represents an element of the set Y. \n\nFor each x in X calculate the value of y= f(x) in Y. This gives a pair of co-ordinates (x,y). (Depending on the function, you may have more than on value of y for each x eg the function f(x)=square root of x will give + and - values.)\n\nFor any x on the x axis draw a line parallel to the y axis to intersect the x axis at x. Draw another line to intersect the y axis at the point y=f(x) and parallel to the x axis. Where these lines intersect is a point on your graph. The complete graph consists of all such points.\n\nWhere the set X is infinite (eg the set of real numbers) you cannot calculate the value of f(x) individually for every x but by calculating the values for a series of points at suitable intervals you will see a pattern emerging to the graph and you will be able to fill in the gaps by joining the (x,y) points, hopefully with a smooth and continuous line.
955476
i am assuming you want an x and y table.  just pick any x values, and plug them in to get a y value.  (go easy on yourself, pick easy values like 0 and 1)  make sure you throw in some negative numbers as well,  just to make sure you have got the main idea of graph.  if you are graphing this, just start at your vertex and then plot your points you just found-you have the right idea, just remember the number in the parentheses is OPPOSITE, so it would be to the RIGHT 3 down 7.
206626
Do you mean graph? Look in your math book. You take a pencil and you graph ordinarly basically.
1027994
if you are asking .. how to sketch an eclipse ... take two verticies (two spots some distance apart left to right on a page) ... and using a compass play with intersecting the radius' of different lengths ... you will find that if you pick the one of equal length as the distance from the vertices ... you will get an intersection of the two radius' from the original vertices ... then playing with the new found radius' ... you will be able to place arcs on the ajoining vertices to creat the other two arcs and blend them together creating an approximate elipse ... a french curve help too
1137018
There's no way that Excel can create multiple y-axes like that.  Your best bet is to create the graph and use your drawing tools to create the extra y-axes.
950608
get some graph paper. plug in numbers for x and calculate its equivalent y value. do that 5 times, and you should have your curved line. If not, use higher or lower numbers than you used the first time ( I like starting with 0) Then  draw a line perpendicular to the most bent part (aka axis of symmetry, aka cut the line in two so both sides of the new line look like mirror images), find 2 points on that cutting line, and there you go.
470658
The above answer is basically correct.  Plug in a few more values, such as (21,1543.5), (22,1694), and so on for a few more values of the graph.
731311
I use GrafEq for my graphs, you could give it a try at http://www.peda.com/grafeq/
384702
The first 3 are all straight lines, so you just need to get 2 points in each.\n1. y = |x| + 3 for x = 1 then y = 4, for x = 2 y = 5.\n\n2. y = 3/2x - 2 for x = 2 then y = 1, for x = 4 y = 4\n\n3. y = x - 5 for x = 5 y = 0 for x = 6 y = 1\n\nFor #4. This is a curve shaped like and upside down U that passes through 0,0, for all values of x, y will always be negaive.\n\nThe best way is to substitute values of x and get values of y and sketch.\n\nHope I was some help
497181
You only need two points to determine a line.\nYou should use three just to make sure you don't make a mistake.\nPick two values of x and find the corresponding values for y.\nThis one is pretty simple.\nLet x = 0, then y = 0 (since y = x)\nLet x = 1, then y = 1\nLet x = -3, then y = -3.\nPlot these points on the graph and connect them with a straight line.