i need help with switching the greater than or less than sign in an equation with a negative integer?
408980
when playing with < and >\nif you multiply all the equation by -1 the sign < changes to >, and the sign > changes to <\nbut if you just switch the number on the other side the sign doesnt change\nin ur case :\n2x-y < 4 \nequals\n-y < -2x + 4\nif you multiply it with -1 it will become\ny > 2x - 4\n\nlike that. hope it helps :)
378781
-1*100\n-2*50\n-4*25\n-5*20\n-10*10\n~or~\n1*-100\n2*-50\n4*-25\n5*-20\n10*-10
14221
If X = -100\nThen X + 25 = -75\n-4X = 400\nand -75 > 400 is false
954015
I answered this question a few weeks ago. The answer is to draw a forward slash (/) through the equal (=) sign changing it to a not equal sign. This gives the true inequality\n5+5+5 not = 555.:
815621
-47+(-16) is the same as -47 - 16, which equals -63.\nWhen you subtract from a negative number, you are takeing more away from the negative, which will make it more negative.
770189
Number will have to be the actual number it is working it out from..and it might not work as a long and definately not an integer.\n\nNumber as String\nOdd as Long (or Integer)\nEven as Long ( or Integer)\n\nIf Not (Number <1 or Number > 10) Then\nNumber = Number / 2\nIf InStr(Number, ".5") then\nOdd = Odd + 1\nElse\nEven = Even + 1\nEnd If\nEnd If\nMe.Print "Odd: " & Odd & " - " & "Even: " & Even
218778
The answer is -1\n\nIn Algebra, anytime you subtract a number, you change the number following the minus sign into its inverse (negative to a posotive and positive to a negative) and then add.  Therefore, your problem becomes -12+11, giving an answer of -1.
785570
try substituting letters for numbers and vice versa
930501
There needs to be an "x" there somewhere.  If it were\n-4x + 7 > 15, you'd have \n-4x > 8\n  x < -2 (because you switch the sign when you divide by a negative)
759182
x+2>9\n .-2 .-2\n____\n|x>7|\n```````\nx-18<35\n +18 +18\n_____\n|x<53|\n`````````\n 30+x<16\n-30 . . -30\n_______\n|x < -14|\n```````````\nx-9.5<9.5\n +9.5 +9.5\n_____\n|x<19|\n`````````\nAnd when you graph the inequalities, just draw a number line and draw a dot(open) on the mark that shows your number. Then, if the variable is greater than your number, draw an arrow to the right, and if the variable is less than your number, draw an arrow to the left.\nLike, x<3 is:\n . -1 . . 0 . . 1 . . .2 . . .3 . . 4 . . .5. . .6 . . .7\n< =l===l===l===l===o---- l-------l-------l-------l-->\nThe "=====" is the graphing part, and the "----" is just the original number line. Make the "===" darker so you know where you drew the line. this only work is the inequality is "greater than" or "less than". If the inequality is "greater than or equal to" or "less than or equal to", than the dot should be closed, or solid.
102547
A begining and no ending: Positive Integers\nAn ending and no begining: Negative Integers
242385
when you multiply two negatives you get a positive because the negative signs cancell each other out
462143
When you add a positive number and a negative number, you actually subtract the two numbers, then choose the sign of the larger number for your answer.\n\nWhen you subtract a negative number from a positive number, the negative number becomes positive and you add the 2 numbers.\n\nWhen you subtract a positive number from a negative number, it becomes negative and you add the 2 numbers.
954759
The || signs represent absolute value. This is a term that means the distance of a number on a number line to zero. Absolute value is thus always positive. For example, |2| = 2 and |-2| = 2.\n\nFor equations where you are solving for a variable and one side is absolute value, you must solve the variable so it can equal both the negative and positive values. Using the example above, this means we have to set the equation so that x+3 equals both 4 and -4. This is because regardless of the negative or positive part, it will change into 4 because it is absolute value. Here is how you do it:\n     |x+3| = 4\nx+3=4\nx=1\nThats the normal way, as if there were no absolute value marks.\nBut we have to account for the negative part too:\nx+3=-4\nx=-7\n\nNow to prove this is true:\n         |x+3|=4\n|(1)+3|=4\n|4|=4\nThe negative too:\n|(-7)+3|=4\n|-4|=4\n\nI don't know how the second equation would work, partially because I don't know the full equation. Perhaps you meant |2b+9|=0 ? Otherwise, you can't do anything further. I hope I explained it well.
857932
This formula will put a minus sign in a second column's entry when the first column's entry is a minus or the positive value if positive.\nA1=first entry\nA2=second entry\nPut into A2:\n=IF(A1>0,A1,"-")
202107
Try this:\n=IF(A1>0,A1-(A1*0.1),A1) \nin cell C1. \n\nAlso, you didn't specify what happens when A1=0. If C1 = A1, then the above will work, if not, try this:\n=IF(A1>0,A1-(A1*0.1),IF(A1<0,A1,Zero Value))
769460
I think that you want x element of [-6,4)\n\nYou wanted closed on the left and open on the right, is that true?\n\nJust remember that for intervals:\nopen   ( )\nclosed [ ]\n\nAnd you can match them up: [-6,4)