answer this physics question plz...?
400015
By newron's ii law\nMa=F-f\nf=10-10*0.6\nf=4 N\nf= -4 i (vector notation)
50475
A)come on, the weight of the man is just his mass times gravity.\nB)this sounds like a torque problem, you need to know where on the beam the man is standing... since the beam is in equilibrium, you know that the sum of all torque is 0. 9im going to use T for torque because i cant get the greek letter i usually use) T=Fr (force times the distance from the pivit point) so all torques directed up minus all torques directed down equal 0. so that means all torques pointing up equal all torques pointing down. ok, so that means that:\n Tbeam + Tman = Tcable.\n and the cable is at an angle so it would actually be FrsinX instead of just Fr.  so now since the beam is uniform, we say that it's weight is in the center, so r is half of the length of the beam. so\n Tbeam=Fr=(288)(2.6) and now we convert the mass of the man to newtons, just multiplying by gravity(which im rounding to 10 because i dont feel like getting a calculator) and getting 750 Newtons. so that means\n Tman=Fr=750r. this has to stay as r because you didnt tell me where on the beam the man is standing. it probably indicate's where he's standing on your diagram. r would be the distance between the wall and the man because we're making the wall our pivot point, because if the end with the cable was our pivot point, everything there(including the cable) would be 0 because it would be 0m away from the pivot point, so we couldnt solve for Ft... so you'll have to plug in the "r" for the man yourself.  and Tcable=FrsinX=F(5.2)sin67 where F is the force of tension which is what you are solving for overall, r is 5.2 because the cable is 5.2m (the length of the beam) away from the pivot point. so now, we plug into what i told you before(Tbeam + Tman = Tcable.) which is true because the beam is in equilibrium. so \n\nTbeam + Tman = Tcable\nFr    + Fr   = FrsinX\n(288)(2.6) + (750)(r) = F(5.20)sin67\n\nplugging in the r which should be on your diagram, you can solve for F whichi is the tension in the cable.
762251
If 2 billiard balls of mass m (ma and mb) are perfectly elastic and ball A approaches from the left with velocity 2 m/s and hits ball B which has velocity 1 m/s, and is also going to the right, what's the status after the collision. \n\nA is going to the right with velocity 1 m/s and B is going to the right with velocity 2 m/s.\n\nma*2 m/s + mb*1 m/s = ma*1m/s + mb*2m/s\nmomentum is conserved
210676
Use free body diagram to balance the forces and u can derive the equation of motion \nIf u want i can give u full derivation.\n"::
946901
these questions are wierd, hard and confusing. u should ask your science teacher for help better luck on your next question. good luck
574012
I've alread answered two of your questiions in my last answer....\n\nIn this one, the guys above are correct - however, I'd try working it out for myself if I was you. Your tutor will soon realise something is wrong if you are giving answers to a subject you don't understand. Read the chapter, ask you teacher if you need more help. Learn Newtonian mechanics for yourself.
53841
The last poster needs to have his dynamic physics retaught, or stop trying to sound like an engineer.\n\nThe first mistake, is identifying newtons = force x distance.  This is actually a measure of work or energy and measured in joules.  The second mistake identifying force as being measured in joules.  Force is measured in Newtons.  Since it was Isaac Newton in the second law of motion that defined Force.\n\nYour question cannot really be answered without more information.  What is the direction of motion, horizontally or vertically?  \n\nVerically?  Then 150 lbs of force.  Pounds were once used to measure force.  If you want to use metric, convert the 150 lbs to kilograms, multiply by 9.8 and then you must exert at least this much force in Newtons to overcome the force of gravity.  150 lbs is 68.04 kg.\n\nHorizontally, what type of surface?  Determine the coefficient of friction, and multiply it by the mass in kilograms.  Then this is the amount of force you need to exert to overcome the force of friction.  There are two types of friction, static and dynamic.  In other words it takes more force to move an object at rest, but once the object is in motion it takes less force to keep it move (opposing the dynamic force of friction).\n\nWatts by the way is a measurement of power, which is energy derived by time, Power = dE/dt.  Joules per second.
573522
kinetic energy is 1/2 mv² so it depends on mass and velocity
1166211
I do not know you that well yet...............\n\n\nHow about a physics question or something challenging?
905559
This seems more like a physics question than a chemistry question.  I would try posting this in the physics section- someone will be able to help you there!
422460
please explain this question.
1014316
would you like to supply me with some formulas? im out of grade 12 physics and i forgot most of the formulas. trust me from experience, just plug numbers into a formula and things will work\n\nF=mg = ma\nFk=μkN\na= vf^2 - vi^2 / 2d
35590
I concur with previous answerer. The acceleration is 1.5 m/s^2. Rearrange Newton's Second Law, to solve for the acceleration. Then, substitute what you know.
761452
Here is a great site that thoroughly explains it:\nhttp://www.howstuffworks.com/question524.htm
835410
You need to get your units in a consistent form.  I suggest changing the velocity of the electron to 2.5E6 m/s so when you divide it into c-----------WAIT A MINUTE!-----Yor formula is NOT right, because you're dividing a speed by a speed, which will give a dimensionless answer.  Wavelength is a LENGTH, so the answer must come out that way.  I forget the formula you're refering to, but what you've typed isn't it................
660156
http://www.physlink.com/education/askexperts/ae25.cfm
950875
plsmake ur question clear.im not able 2 understand it