What is the unit of Kinetic Energy  ?
398556
A joule which is broken down into kg*(meters/second)^2\n\n(^2 means squared)\n\nAlso, 1 calorie = 4.184 joules.
602803
The theoretical physics equation E = mc2 states a relationship between energy (E), in whatever form, and mass (m). In this formula, c², the square of the speed of light in vacuum, is the conversion factor required to formally convert from units of mass to units of energy, i.e. the energy per unit mass. In unit specific terms, E (Joules) = M (kilograms) · (299792458 m/s) 2.
880131
Newtons are the SI unit of force.\n\nForce may also be measured in joules per centimeter, pounds force, atomic units of force, and several other units.
28535
Well, look at the units. The first one is a distance divided by a time; speed. The second one is in the units of energy (in the MKS unit system) the Joule. The "KE" also says to me that it isn't just any energy but, kinetic energy -- the energy that something has because it is moving.\n\nFrom these two bits of information you can deduce the mass of the object (if that's what you're talking about) in question.\n\nA very basic kinematic equation is the one that describes the relationship between the mass, velocity, and kinetic energy of something in motion.\n\nKE = 1/2 * mass * velocity^2\n\nsolving for the mass would be:\n\nmass = (2*KE)/(v^2)\n\nWhich is in the neighborhood of 2000 kg.\n\nhope that helps.
1030224
The answer in SI units is 1200 joules or 1.2 kilojoules. the definition of a joule is one watt second. in Calories, or English units, which shouldn't really be used with watts as it mixes systems of measurements, is 286.806883 calories or 0.286806883 kilo calories.
262268
KE = 1/2 m v^2, so if the velocity remains constant, the kinetic energy and mass are directly proportional.
283905
Kinetic Energy describes the amount of energy an object has by virtue of it hasving some non-zero mass and traveling at some speed.\nKE= 1/2 mv^2\n\nPotential Energy describes the energy that could be gained by that object if it was not at that potential.  It is not really accurate to say that potential energy is energy at rest since it is very possible for moving objects to have potential energy.\nA good example would be a rock sitting on a cliff.  That rock has some potential gravitiational energy since it is sitting some height above the ground (the bottom of the cliff).  The potential energy equals the amount of energy needed to put that rock up there in the first place and the amount of energy which could be gained if the rock falls down from the cliff.  As the rock is falling, before it hits the ground, the rock has some fraction of its potential energy converted into kinetic, in other words it has both at the same time.\nThere are many forms of potential energy, gravitational potential energy being the most commonly described.\ngravitational PE = mgh
694512
Work, power and energy all have the same units of measurement in SI scale
955569
(I)fundamental units:  those units which are the quantities which are independent of each other. All other quantities may be expressed in these units. It turns out that the number of fundamental units is 7. They are:\n(a)length (metre; m)\n(b)mass (kilogram, kg)\n(c)time (second, s)\n(d)luminous intensity (candela, cd)\n(e)electric intensity (ampere, A)\n(f)amount of substance (mole, mol)\n(g)thermodynamic temperature (Kelvin, K)
164623
They're just different units for energy\n\n1 calorie = 0.0041868 kilojoule
290784
Energy is directly proportinal to the square of velocity as you know (Kinetic Energy)\nas far as the velocity of a wave is concerned it wavelength * frequency\nso it has to be either frequency or wavelength,the choice is left to you\nif u asked me i had rather choose to go with frequency
895448
Kinetic energy can be expressed as\n\nKE = 0.5*m*v^2\n\nDoubling the kinetic energy requires increasing the speed by the square root of 2. Where doubling the speed increases the energy by a factor of 4.
1104990
E = mc2 is one of the most famous equations, even to non-physicists, and which states a relationship between energy (E), in whatever form, and mass (m). In this formula, c², the square of the speed of light in a vacuum, is the conversion factor required to formally convert from units of mass to units of energy, i.e. the energy per unit mass. In unit specific terms, E (joules) = M (kilograms) multiplied by (299792458 m/s)2.
394789
1kcal (or big "C" calorie) is equal to 4.19kJ (4.19x10^3J).  They are not the same thing.  The calorie was a unit made up before energy was fully understood and is the amount of heat needed to raise the temperature of 1g of water by 1 degree celcius (from 14.5 to 15.5 degrees celcius), whereas the joule is the SI unit for energy.
72896
Newtons is the unit for measure of force
1028188
This is a very good question.  Basically, the reason that we say kW and do not say kW/hr, is that calories and British Thermal Units (BTUs) are units of ENERGY, while the Watt is a unit of POWER.  The unit of time is already incorporated in the Watt.\n\nPOWER is defined as the rate at which WORK is done.  WORK is, in general, a transfer of ENERGY.  So POWER is the rate at which ENERGY is transfered from one object (or system) to another.\n\nThe capacity of a burner is stated in terms of POWER, that is, the rate at which it can transfer energy from the fuel (chemical potential energy) to the objects being heated.\n\nA Watt is defined as 1 Joule / second, (the Joule (J) is the basic SI unit of ENERGY).  1 Watt (again, a unit of POWER) is therefore equivalent to 3600 J/hr, since there are 60*60 = 3600 seconds in one hour.\n\n-------------------------\n\nFor your example, the power rating of the burner is 30kW.\n\nPower = 30kW = (30,000 W)*[(3600 J/hr)/(1 W)] = 108,000,000 J/hr = 108MJ/hr\n\nWe now use two conversion factors:\n\n1 kilocalorie = 4184 joules\n1 BTU = 1055.056 joules\n\nUsing these equivalencies, we can calculate the power in kcal/hr or BTU/hr:\n\n(108,000,000 J/hr)*[(1 kcal)/(4184 J)] = 25,812.6 kcal/hr\n       (this is pretty close to 25,800 kcal/hr stated on the burner)\n\n(108,000,000 J/hr)*[(1 BTU)/(1055.05585 J)] = 102,364.2 BTU/hr\n\n-------------------------\n\nYou stated that you are using Natural Gas with calorific value 40MJ/m^3.  (I found 38MJ/m^3 on Wikipedia, but this rounds to 40, so I'll go with your number for the example.)\n\nWe have:\n40MJ/m^3 = 9560.2 kcal/m^3  (using the above conversion factor)\n\nSo the consumption of Natural Gas is\n\n(25,812.6 kcal/hr)/(9560.2 kcal/m^3) = 2.7 m^3/hr\n\n(This rounds up to 3 m^3/hr, so your answer above is correct.)\n\nPlease note that 40MJ/m^3 is NOT equal to 11 kW/m^3, because the former is an ENERGY density, and the latter is a POWER density.\n\nHowever, 40MJ/m^3  IS approximately equal to 11 kWH/m^3, which I assume is what you meant to write.\n\nUsing this method gives the same answer:\n\n(30 kW) / (11 kWH/m^3) = 2.7 m^3/hr  (approx. 3 m^3/hr)\n\nAlso, as a matter of notation, the term "LPG" (Liquid Petroleum Gas) is typically used for either Propane or Butane in liquid form, NOT for Natural Gas.\n\nI hope this explanation is helpful for you.
71275
Heat is the kinetic energy of molecular motion. The molecules of a hot object are in rapid motion; the hotter, the higher the average speed and the greater the thermal energy. If the object is gaseous the motion consists of free-path travel and collisions with other molecules. If it is liquid the paths between collisions are shorter, and if solid the motion is vibrational with no secular movement.