show the answer and steps for this problem 2n -3 =5n -18?
411709
we did it at primary school but I see someone did it wrong :))
91468
there should be 2 answers\n3m^2 + 18m =0\n(3m+0)(m+6)=0\nso m=0/3=0 or m=-6
261181
assuming that 2x+5=0, then I deny that solution. The Pair(3,-5) workes for 6y-8=-54 only.
904822
Hello Dear Blue \n\n2x^3+8x^2 - 5x + 5 ÷ x-2\n\n▪ Step1\n( 2x^2 ) ( x-2 ) = 2x^3 - 4x^2 ; { let Q1 = 2x^2 }\n2x^3+8x^2 - 5x + 5 - ( 2x^3 - 4x^2 ) = \n2x^3+8x^2 - 5x + 5 - 2x^3 + 4x^2 = +12x^2 - 5x + 5 {remainder} \n\n▪ Step 2\n+12x^2 - 5x + 5 ÷ x - 2 \n(x - 2) (12x) = 12x^2 - 24x ; { let Q2 = +12x }\n+12x^2 - 5x + 5 - ( 12x^2 - 24x  ) =\n+12x^2 - 5x + 5 - 12x^2 + 24x = +19x +5 {remainder}\n\n▪ Step 3 \n19x +5 ÷ x -2\n(x -2) (+19) = +19x - 38; { let Q3 = +19}\n19x +5  - (+19x - 38) =\n19x +5  -19x + 38 = +43 {remainder}\n\n▪ Step 4\nSum Q1, Q2, Q3\nQ1 + Q2 + Q3\n2x^2 +12x +19\n\nSo;\n(2x^3+8x^2-5x+5) ÷ (x - 2)    = >\n\nQ(x) OR quotient = 2x^2 +12x +19 \nR(x) OR Remainder is + 43 \n\nGood Luck dear.
908426
Plug in each of the four answers.  The only one that works is (2), because you get\n\n | 3 (-2/3) - 3 | = 5\n | -2 - 3 | = 5\n | -5 | = 5\n 5 = 5
232592
2x = 3y - 4y + 5 - 2\n2x = -y + 3\n2x + y = 3
445500
(18)(-3)=(-11)r\n-54=(-11)r\n54/11=r
487838
1) Assuming an aritmetic sequence\n\nbn = b1 + (n-1)d \nletting b3=a1 = 20, then b7=a5 = 32, and b25 = b23\na5 = a1 + (5-1)d\n32 = 20 + (5-1)d\n32 = 20 + 4d\n12 = 4d\n3 = d\n\nb25 = a23 = 20 + (23-1)*3\nb25 = 20 + 22*3\nb25 = 20 + 66\nb25 = 86\n=====================================================\n2)\na75 = a1 + (75-1)d; d=-3\n\na75 = 5 + (75-1)*-3\na75 = 5 + 74*-3\na75 = 5 + -222\na75 = -217\n\nSn = n/2(a1+an)\nS75 = 75/2(5 + -217)\nS75 = 75/2(-212)\nS75 = -7950\n===================================================\n3) ????\n\na5 = 5*5 - 4 = 21\na15 = 5*15 - 4 = 71\na25 = 5*25 - 4 = 121\n\nOR MAYBE\n\na1 = 5*1 - 4\na1 = 5 - 4\na1 = 1\na30 = 5*30 - 4\na30 = 150 - 4\na30 = 146\n\nSn = n/2(a1+an)\nS30 = 30/2(1 + 146)\nS30 = 30/2(147)\nS30 = 2205\n================================================\n4)\n\nrth term is nCr-1m^n-(r-1)k^r-1\n\n5th term =\n4C4m^4-(5-1)k^5-1\n4C4 = 1\n\n5th term = k^4
675569
(2n-14)(2) = 12 + -n\n4n - 28 = 12 - n\n5n = 40\nn = 8
810900
Multiplying eqn no 1 by 3 and subtracting it from eqn.no2,w get \ny-2z=5........(eqn.no4)\nmultiplying equn. no.1 by 2 and adding it with eqn. no.3,we get\n3y-5z=6.......(eqn. no 5)\nmultiplying eqn, no(.4)by 3 and subtracting it from eqn. no.(5),w get  z= -9\nPutting the value of z in eqn. (4),we get\ny+18=5\nTherefore  y=5-18= -13\nPutting the value of y and z in equation no.1,we get\nx-26+9=3\n=>x=3+26-9=20\nTherefore,x=20,y=5 and z= -9   ans.
789310
Notice the first equation only involves x.\nx - 5 = 6\nAdd 5 to both sides\nx = 11\nNow replace x with 11 in the second equation\n3(11) - 2y = 5\n33 - 2y = 5\n-2y = 5 - 33\n-2y = -28\ny = -28/-2\ny = 14\nAnswer: (11,14)
621649
(3x-18)  = 7+4x+64\n-18-7-64 = 4x-3x\n-23-64   = x\nx = -89
146936
(32 + 18 - 45 x 3) / 5 - 7 x 2 = ?\n\n-31
433211
This is simple-\n3Mg(S) + N2(G) (2 is subscript) Yields (arrow) Mg3N2(S)
1139003
(n/(n - 3)) + (5/(2n - 6))\n(n/(n - 3)) + (5/(2(n - 3)))\nMultiply everything by 2(n - 3)\n(2n + 5)/(2n - 6)
153400
i believe it would be '-9'\nn=5 \n-3-(5-1)(1.5)\n-3-(4*1.5)\n-3-6\n-9
483173
((6p - 18)/(9p)) / ((3p - 9)/(p^2 + 2p))\n((6(p - 3))/3(3p)) / ((3(p - 3))/(p(p + 2)))\n((2(p - 3))/(3p)) / ((3(p - 3))/(p(p + 2)))\n((2(p - 3))/(3p)) * ((p(p + 2))/(3(p - 3))\n(2p(p - 3)(p + 2))/((9p)(p - 3))\n(2p(p + 2))/(9p)\n(2(p + 2))/9\n(2p + 4)/9