Y=MX+B---------- M=SLOPE   B= Y -INTERSEPT   MY IS IT "M" USED FOR SLOPe AND Y IS IS "B" FOR Y-INT.
402565
another good question for you is why did they use the variable x for the horizontal axis and why did they use the variable y for the vertical axis and the Z for the third dimension....well your answer is just to assign it some variable because it had to be assigned so there could be some order...if you take a multivariable calculus class you will see that there is no assigned order of the x,y and z axis' because it is all relative to how you are looking at it you just have to assign each one and generally the x and y axis' are orthogonal to the z axis....anyways m was probably just used because it is not used in other places so that is what they assigned it
953409
(3,7) (1,5)\n\n5-7/1-3=  -2/-2= 1 so that is your slope (1)\n\ny=mx+b....m= slope, and b= y intercept\n\ny=1x+b then plug in x and y from one of your coordinates\n\n7=1(3)+b\n7=3+b\n4=b\n\ny=1x+4\n\nthen you put it into standard form
523552
It's already in slope and y-intercept form...  y = mx + b, so slope (m) = 7, y-int (b) = 0
903667
2x-4y=0 is in standard form.  the same equation in slope-intercept form (y=mx+b) is y=1/2x where 1/2 is the slope (y/x or rise over run) and the y-intercept is 0 or at the point (0,0) (because there is no b).  it depends what you want to do with the equation as to what form you put it in.  what do you want to do with it?  what do the directions say?
247082
Yes because to find slope you need change in y and change in x (or whatever coordinate system you use).\n\nSince you have both two x's and two y's then you're set.\n\nUse this formula: Δy/Δx where Δ stands for "change in" or (y1 - y2)/(x1 - x2)\n\nUsing the coordinates listed:\n(-2 - -2)/(6 - -8)=\n(-2 + 2)/(6 + 8)=\n(0)/(14)\n\nSince '0' divided by anything is zero, your slope is zero.\n\nThis would be a line that is parallel to the x axis 2 units below the axis.
1066076
ok first set up the problem according to y=mx+b:\n3y+2x+6=0\n- you want to get y by itself so you subtract 2x+6 from both sides (or add -2x-6)\n- you should get 3y= -2x-6\n-then divide by 3(or multiply by 1/3)on both sides\n- you should get y=-2/3x-2 and since m = your slope then the slope is -2/3\n:D\nI LOVE MATH!!!!!!!!
855184
You don't, really.  y =  mx + b is the slope-intercept line equation, where m = slope and b = y-intercept (the place where x = 0).  I guess you could put both equations in this format, draw the resulting lines, and find where they converge (cross).  That would be easy to do on graph paper, but more difficult to show here.\n\nOne of the other ways to solve the equation system is to substitute one variable for the other.  To do this, you'd first need to put one of the equations in a format where a single variable is by itself on one side of the equation, like this:\ny = 2x - 2\n\nThen plug in the value on the right side of that equation instead of y in the first equation:\nx + (2x + 2) = 4\n3x + 2 = 4\n3x = 2\nx = 2/3\n\nThen plug that back into one of the equations and solve for y\n2/3 + y = 4\ny = 10/3\n\nThe point of convergence for the system is (2/3, 10/3)
456859
y = mx + b\n0 = 2m + 4\n2m = -4\nm = (-4/2)\nm = -2\n\ny = -2x + 4\n\nStandard form of this would be \n\n2x + y = 4
562373
y = mx + b\n\nm is the slope (rise over run).  You have two coordinates (x1,y1) and (x2,y2).  Rise is y2-y1, Run is x2-x1.  So in your example, Rise = 6, Run = -5.  Slope = Rise/Run or -6/5\n\ny = -6/5x + b\n\nb is the y-intercept.\n\nPlugging in one of your coordinate x=3, y=-5\n-5 = -(6/5)(3) + b\nSolve for b and you have\nb = -5 + 18/5\nb = -25/5 + 18/5\nb = -7/5\n\ny = -6/5x -7/5\n\nTo double check, let's put in the second coordinate of x = -2, y = 1\n\n1 = -6/5(-2) -7/5\n1 = 12/5 - 7/5\n1 = 5/5\n1 = 1\n\nThis is consistent, so there is your answer:\n\ny = -6/5x -7/5
836584
The form y = mx + b is called the "slope-intercept" form of an equation describing a straight line.\n\nIn this form, m is the slope (how much the y-value changes for each unit change of the x value) and b is the point along the y-axis where the line crosses it (where x-value is zero).\n\nSo, as m increases, the line bocomes closer to vertical and when m decreases, the line becomes closer to horizontal.\n\nSimilarly, when b increases the line's slope remains the same but the line moves up on the graph, while if b decreases then the line moves down.\n\nHere is a great website for playing with this form of a linear equation in slope-intercept form:
1016870
y = mx + b, where m = slope, and b = y-intercept\n\nYou have the variables Y, M, and X. So, let's find b:\n\n5 = (-2/5)(17) + b\n5 = -6.8+b\n11.8 = b\n\nYour equation would then be:\ny = -2/5x + 11.8
746165
Remember the fomula...\n\ny = mx + b\n\nm = Slope\n\nb = Y-intercept\n\nx and y = points\n\nSo plug everything in...\n\n1 = 4(2) + b\nMulitply\n1 = 8 + b\nSubtract 8 on each side\n-7 = b\n\ny = 4x - 7
736765
slope=1\ny=x+b\n-3=3+b\nb=-6\ny=x-6
948277
y = mx is the general equation for a straight line on cartesian coordinates. So F = ma is also similar with m as the slope, a as the independent variable and F as the dependent variable even though physically this makes no sense. So just plot it on the coordinate system now...\n\nAyerhs.
94805
If you know how to find the slope of a line in the form y = mx + b, just write the equations of two lines with different slopes.  They will have to cross.  Graph each line and find the crossing point.  That's the answer.  Hint:  make the slope of one line be the y-intercept of the other line and vice versa.  Then they will cross at an exact point on the graph.
104788
Remember the slope-intercept form?\n\ny = mx + b.\n\ny = the y coordinate.\nx = the x coordinate.\nm = the slope.\nb = the y - intercept.\n\nyour equation is already in slope-intercept form. so all you need to do is match up your numbers with the y = mx + b.\n\nThe slope is -5.\nThe y - intercept is -17.\n\nHope that helps :)
751258
y' = 2x + 4\ny'(1) = 6 this is the slope.\ntangent: yt = 6x + b\n\ny(1) = 1 + 4 + 10 = 15\nyt(1) = y(1) = 15 = 6 + b ===> b = 9\n\nyt = 6x + 9