In a vial of 5ML there are how many Minims?
400500
well,here is the answer:\n*1 ML = 15 Minims\n*5 ML = 15 * 5 = 75 Minims
220540
Here's a good chart to use\nhttp://www.simetric.co.uk/si_medical.htm\nTo answer your question there are 1000 mcg to 1 mg so 2.5 mg equals 2500 mcg
386514
Enter the smallest of the two. If B=12000 and C=12001 you would enter B...12000.
575750
This can be done using the formula M1V1=M2V2.  For example, if you have 2M HCl and wanted 2L of .5M HCl, then putting that into this equation as 2(V1)=(.5)(2).  Solve accordingly.  This is just an example.  This formula can be used in a variety of ways that all.  But, to make it to the desired you, a volumetric flask is needed in which water is added until the etched line on the flask to equal the preset volume of the flask.
657390
Pour each person one cup full, (two cups from each bottle), they now have had 300ml and each bottle has 200ml left. Empty one bottle into the cup, then pour from one bottle to the other until they're equal - 100 ml each. Let two people drink those, then then pour what was in the cup into the two bottles equally, another two 100ml measures!
639912
1 teaspoonful is 5 ml.  1 and 1/2 teaspoonful is 7.5ml. it is not possible to use a teaspoon to measure out 6.25ml. what you need is a measuring spoon/ syringe. most pharmacy would give them out for free.
354060
0.2 gal. or 25.6 fluid oz.
62542
I think this is a trick question. A volume of one cubic centimeter is the same as one milliliter.
69568
None, unless you pour something into it, then it is a measure of 1.5 oz. \n\nHope it is something yummy.
955266
1.3-.9=.4kg for half a bottle of oil no bottle so 1 bottle of oil with no bottle should wiegh .8kg so the bottle should wiegh.5kg
860910
Pour the liquid in the graduated cylinder and there will usually be mL markings along the side.  This measurement is volume
1012209
300mL\n    x.18\n_______\n\n   54.00 mL
1103878
1000 mls X (0.5/100) = 5 mls\n\nrabidcrayon: 0.05 would be 5% not 0.5%
164131
1 milliliter = 0.001 liters
780603
1. Put 8l in the 8l-jar - \n4l are left in the 12l-jar, 8l in the 8l-jar, the 5l-jar is empty \n\n2. Fill the 5l-jar with water from the 8l-jar -\n4l still in the 12l-jar, 3l left in the 8l-jar, 5l in the 5l-jar\n\n3. Empty the 5l-jar into the 12l-jar - \n9l in the 12l-jar already, 3l in the 8l-jar, 5l jar is empty\n\n4. Empty the 8l-jar into the 5l-jar (those 3l, you know ;) -\n9l in the 12l-jar still, 8l-jar is empty, 3l in the 5l-jar\n\n5. Fill the empty 8l-jar with water from the 12l-jar - \n1l left in the 12l-jar, 8l-jar is full (with 8l :), 3l in the 5l-jar still\n\n6. Pour 2l from the 8l-jar into the 5l-jar - this is easy, you just have to fill the 5l-jar :) -\n1l in the 12l-jar, 6l are left in the 8l-jar, 5l in the 5l-jar\n\nGUESS WHAT?\n\n7. Empty the 5l-jar into the 12l-jar - \n6l in the 12l-jar, 6l in the 8l-jar, 5l-jar is empty\n\n:)
931815
Your KCl example is a good one.  A 0.5 molar would have 1/2 mole/liter or 37.75g KCl in a liter. A 5% w/v KCl would be 50 g/liter; so the 5% is more concentrated.\n\nThe 2.5% w/v sodium bisulfate is 25g/liter and the .025M is 3 g/liter.\n\nIt all depends on the molecular mass.
371296
well seeing that the molarity of the two solution is a direct ratio of how many molecules there are in the solution, i think that the ration would be 0.15/0.20\n\nso assuming that the reation is 1 to 1 (i cant remember so if it isnt 1 to 1, then i'm wrong) then you would need 18.75 mL of the 0.200 M HCl