what the anwer to square root of 81 times 3 plus 17 minus 12?
404426
sqrt(81) = 9\n\nso take 9 x 3 = 27\n\nthen 27 plus 17 = 44\n\nfinaly 44 - 12 = 32\n\nso your final answer is 32.
1159901
12sqrt(1/3) - sqrt(27)\nsqrt(1/3)\n= sqrt(1)/sqrt(3)\n= 1/sqrt(3)\n= sqrt(3)/3\n\nsqrt(27) = sqrt(9*3) = 3sqrt(3)\n\n12*sqrt(3)/3 - 3sqrt(3)\n= 4sqrt(3) - 3sqrt(3)\n= sqrt(3)
338371
sqare root of 9=3\n\n3+3+3+3=12\n\n12 cm
80992
You have to use the property that the square root of (ab) is equal to the square root of (a) times the square root of (b).  So the square root of 80 = the square root of (5) times the square root of (16).  The square root of 16 is 4, so you end up with the answer of 4 times the square root of 5.  Write it as 4 sqroot sign (5).
863385
First of all, if you meant, 3* i^17 - i^11\n\n3* i^17 - i^11\n\nHere is how I would do this.\n\ni^2 = -1\ni^4 = 1\ni^6 = -1\ni^8 = 1\ni^10 = -1\ni^12 = 1\ni^16 = -1\n\ni^17 = i^16 * i = -1*i = -i\ni^11 = i^10 * i = -1*i = -i\n\n3* i^17 - i^11\n3 * -i - -i\n-3i + i\n\nANSWER\n-2i\nor\n0 + -2i\n\n*********************\n\nIf you meant (3i)^17 - i^11, the answer is different.\n129140163 * i^17 - i^11\n129140163* -i - -i\n-129140163i + i\n\nANSWER\n-129140162i
146354
x square-12x-85\nI think?
227986
n is the set of all numbers grater than -27.\n\nsolve for equality\n-3n=81\n-3n/-3 = 81/-3 (divide by -3)\nn=-27\nthen inset the answer back into the equation \n-3*-27<81 is false : 87 = 87 being negative you need larger numbers for a smaller result so ... see first line
899814
2√72 + √32 - 4√18\n= 2(√8*√9) + (√8*√4) - 4 (√2*√9)\n= (2*3)√8 + 2√8 - (4*3)√2\n= 6(√2*√4) + 2(√2*√4) - 12√2\n= (6*2)√2 + (2*2)√2 - 12√2\n= 12√2 + 4√2 - 12√2\n= 4√2\n\nHope this helps.
1004150
-3x - 12x - 3 = 4 -12x + 20\n-15x - 3 = -12x + 24\n-27 = 3x\nx = -9
330312
the square ROOT is 18.574175621006709970985687682281
832512
either square root or erauqs
628836
I don't have the  symbol\n\nBut \nthe SQRT(44)  =  2 x SQRT(11)\nthe SQRT (18) =  3 x SQRT(2)\nthe SQRT (27) =  3 x SQRT(3)\nthe SQRT (200)= 10 x SQRT(2)
860580
just divide the inside by a perfect square (i.e. 4,9,16) and write it like this\n(this is the first problem you have)\nV(3X9) because 3X9=27\ntake the square root of the perfect square and move it to the outside\n3V3\nwhen you already have a number outside the radical, multiply it by the number you just simplified from the inside of the radical\n3V32\n3V(16X2)\n3X4V2\n12V2
1093038
no,12 has no perfect square root.it is an irrational number.but approxmiately the answer is 3.46....
460242
ur answer is [sqrt(3) - sqrt(7)].it can written as sqrt[x +/- 2*sqrt[y]] when x=a^2 + b^2 and y=a*b is equal to sqrt(a) +/- sqrt(b)
944695
12 * (3-e^-3x)^3 *  e^-3x
804695
If I got it, your problem is.........\n\n4+/- sq root -12\n_______________\n           2\n\n\n\nThen:   4+/- 2i sq root 3\n            _____________\n                  2\n\n\nSimplify to:    2+/-  i sq root 3