how do you take root 6T6?
412294
Instead of singing songs about famous routes,\n\ndo...\n e raised to the (one half times the natural log of 6T6)\n\nThis is equivalent to root 6T6, but being the scenic route, it involves no kicks.
2106
i am gonna give u the best rootkit remover in the world accepted by proffesionals also. go and download it and its super simple. heres the link-\n\nhttp://www.f-secure.com/blacklight/try.shtml
959605
hello,\ntally 5.4 duplicate or original, but dont need of dat older version, u hav recent versions of 7 n above, if not even d version of 6.2 will suffice..but duplicates can never give u full functionality. as on considering the tally 6.2 version even duplicates or downloaded from any site, like for free, its supportive featuring for educational purpose. or may extend to somewat more...not much..if dis gonna be ur personal use, not for any shop or major functional activities, its enuf...
165911
No. but y do u want 2 go 4 previous version when the latest is available n it offers great deal of features.....versions below 6.0 wont run....so u could either try 6.0 or try the latest one.....i have version 6.0 if you want you post the request at this place itself....
685444
Go to control panel and then User accounts.\n\nThere should be an option for it.
210490
x^3 + x^2 - 4x + 6\n\nif roots are -3 and 1+i, and integer coefficients are needed, then 1-i must be another root,\n\nSo,  (x+3)(x-(1+i))(x-(1-i)) is the solution.  Steps to multiply out are:\n\n[Original]\n(x+3)(x-(1+i))(x-(i-i))     \n[FOIL on last two terms]\n(x+3)(x^2-x(1+i)-x(1-i)+(1+i)(1-i))  \n[Multiply terms of FOIL expansion]\n(x+3)(x^2-x-ix-x+ix+1+i-i-i^2)\n[Cancel terms]\n(x+3)(x^2-2x+1-i^2)\n[i^2 => -1 substitution]\n(x+3)(x^2-2x+2)\n[Perform FOIL]\nx^3-2x^2+2x+3x^2-6x+6\n[Reduce terms]\nx^3+x^2-4x+6\n\nSomebody please check my work and reasoning on this.  Been a while since I took a math class...  \n\nSir Jekshun, check your middle term again.  -1-i would be the assumed root using that term.
934434
2 options:\n-1-\nuse the driver provided at link beneath;\nas a veteran of kind of Linux (started w/ 5.x) i can't think of anything unmanageable in the install instructions, but your mileage may wary :-"\n\n-2- option is to upgrade your kernel to 2.6.18 (or higher)\nthe easiest (sic) way to do this is to upgrade to (Open-)SuSE 10.1 :-? :-??\nconsidering that the driver included in 2.6.18 has limited functionality, this would still be the easy solution but only to be considered if you really don't want to try to install the GPL driver.\nupgrading your 10.0 kernel manually to 2.6.18 would be way more complicated.
769101
= 6 + root(8/2)\n= 6 + root(4)\n= 6 + 2\n= 8
1070445
Go to:\n\nTools\nOptions\nMail format
663212
hey  try \nmount /dev/cdrom  /mnt\n\nyou need to  either define a mount point or need to  keep it in /etc/fstab so that at bootup tiume it takes up the mount point automatically.\n\nlet me know if any more issues.\nkshounish@yahoo.com
181936
go to www.vcdhelp.com\nlook up the guides\nthere you see  the root folder set up on a dvd dics
706596
You'd have to use the chain rule for the square root, then the quotient rule for what's inside.\n\nf ' (x) = (1/2) [(2x³ - 7) / (4x + 1)]^(-1/2) times the derivative of the radicand.\nFor that, the quotient rule gives:\n[6x²(4x + 1) - 4(2x³ - 7)] / (4x + 1)²\n\nThere's most likely some simplifying to be done, but that should get you on the right path.\n\nGood luck!
891439
you can log on to the rtr using hyperterm and then press ctrl + b to enter rommon mode change the boot mode to 0X2142, reload the rtr.\nenter priv mode copy startup to running config\nchange the pswd\nreset the config register to normal 0x2102\nsave running config to startup\nreload\nand u r done with password reset\nthen if u wish, u may erase the flash.\n\nCommands\nctrl + b\nconfig-register 0x2142\nreload\nena\ncopy start run\nena pas cisco\ncopy run start\nconfig-register 0x2102\nreload\n\nCheers !!
149847
you could try typing "man mount"\n\nor, mount -t vfat /dev/whatever_the_partition_is /mnt
880244
Logon to\nhttp://bt.custhelp.com/cgi-bin/bt.cfg/php/enduser/cci/bt_homepage.php?p_sid=6SMS-7mi\nand request CD
355812
You can't.\nIt was initialized a long long time back.
62450
go to www.oldversion.com  thats what i did because the new version always logs me out. follow the links, you will find it :)