how do you make a double line graph?
405166
Try this:\nhttp://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut9_bar.htm
100190
plot these coordinates:\n(0,0),(22.5,-1),(45,0),(67.5,1),(360,0), etc., etc.\n\nconnect them together in a curve and you'll have it.\n\nsine graphs are a series of curved lines. they start at zero, go up to one, go down to zero, go down to -1, and go up to 0 again.\n\nthe negative in front of the sine means that the graph is reflected along the x-axis. so that the 0, 1, 0, -1, 0 sequence is switched to 0, -1, 0, 1, 0.\n\nthe 4 in front of the x means that the normal period for the graph to make a complete curve is divided by for. so instead of the graph following the sequence every 90 degrees, it is done every 22.5 degrees.
635075
Graph X=-4 with dotted lines\n\nthen color everything below the line.
927797
http://www.pdfpad.com/graphpaper/\n\nGood Luck
600405
Generally, making an x,y chart helps plot your points. From there, you make a line.
538540
format>paragraph>look for line spacing and select double
1144569
for graphing, dee-dee-dee
701765
create the chart and then right click on one of the bars...\n\nselect "format data series"\n\nclick on "Options" and make the gap width a larger number\n\ntada
770341
You need to get y by itself.\n\nadd -3x to both sides so you get 2y> 3x+4\nnow divide 2 --> y>3/2x+2\n\ngraph that as you would if it were y=3/2x+2\n(starting at 2 on the y axis. then move up 3 points, and 2 to the right.)\n\nMake sure your line is DOTTED. It is only solid if the inequalilty is less/greater than or equal to.\n\nto check which side is to be shaded, plot points on both sides. try (0,0) if the line doesn't cross through that.\n\n:)\n\nIf the answer is correct, shade the region where (0,0) or the coordinates that work are.
442406
Make a table of values.  Then plot the points.  Your graph should be a "V" shape (not a parabola which is U shaped)---whether upright, sideways, or downwards.
661921
On your number line, go one third of the way between 0 and 1 and put your point on the 0 side of one third.  If you are using graph paper, make three lines equal one unit so that each line it one third unit apart.  This way will make one third be the first line past the number 0.
1137018
There's no way that Excel can create multiple y-axes like that.  Your best bet is to create the graph and use your drawing tools to create the extra y-axes.
731311
I use GrafEq for my graphs, you could give it a try at http://www.peda.com/grafeq/
985180
Pick 2 numbers for X, then plug them into your equation to get F(X), which is the Y value. Then you have the equations and put them onto your graph.\n\nTo plot the function, put your Y-intercept in (-3) then from there use the slope (-1/2) to plot other points. On the function, if you did it right you should come across your points that you made.\n\nHope this helps. Good Luck!!
709666
Use a graph paper. Vector normally given in the form of (i,j). Right now, assume your graph x-axis is your value of 'i' and y-axis is your value of 'j' plot them in and you will get it.\n\nRemember to size your scale as you do it in a normal mathematical way so that your whole vector line will be on 1 piece of graph paper.
1144014
draw a picture of the graph over the specified interval.  divide the graph into vertical rectangles.  the area under the curve will be the sum of the areas of the rectangles.  saying that youve made "n" rectangles, the only way to get the exact area is to find the sum for the limit as n approaches infinity.  work from that concept.  if you already knew that, or need more help or something, email me and i can give you more steps and a much more detailed description.  that would take a really long time though so im gonna see if this helps first.
487850
Right click on the line and select 'Add trendline'. Then select Linear and then click OK.