Find the volume, to the nearest tenth, of a pyramid that is 6 feet  tall and whose base is?
398958
The area of the equilateral triangle is:\n\nA = 0.433 s^2\n\nA = 0.433 (10 ft)^2\n\nA = 43.3 ft^2\n\nThe volume of the pyramid is:\n\nV = 1/3 A h\n\nV = 1/3 (43.3 ft^2) (6 ft)\n\nV = 86.6 ft^3
721975
Since each has eight edges it is a square pyramid\nAnd also the Lemght if the edge is given as 8 unit\nNow the altitude or axis of pyramid is sqrt(8^2+128)\nV(Volume)=1/3 * a^2 * height\nVolume of two pyramidas will be twice this that is 2V\nNow since we know the volume and base edge(a=8)\nwWe can find the axis by volume of pyr=1/3 * a^2 * axis\nconsidering a right triangle with axis and half of base making the right angle and slant height as hypotenuse you can find slant height using H^2=B^2+ALT^2\n\n\nWhile doing the problem dont calculate the values You can just fid an approximate value ad cancell terms thus making ita lot simple
155419
the base of a triangle times the height times 2\n\nb*h*2
9233
Find the dimensions of the base:\n36 - 4 - 4 = 28\n25 - 4 - 4 = 17\n\nSo the area of the base = 28 x 17 = 476\n\nThe height = 4\n\nSo the volume = 4 x 476 = 1904
1187142
maybe something like 7^(1/3) over 7^(1/2)\n\nthat's the same as the cube root of 7 over the square root of 7.\nTo solve it, you would just subtract the exponents and you'd get 1 over 7^(1/6)\n\nI hope that is what you are looking for.
18689
(-2,1) and (5,1) form the base.\nThe length of the base is 7.\n\nThe height is 5.\n\narea=5*7*(.5)=17.5
680192
The area of a triangle is 1/2 the base time the height.\n\nA=1/2bh\nA=1/2(10)(4)\nA=(5)(4)\nA=20 units^2
325762
Volume of pyramid = 1/3 x base area x height\nArea of trapezoid = 1/2 x sum of parallel sides x height\n1/3 x [1/2 x (20 + 28) x h] x 36 = 3168\n...\nh = 11 cm.
160337
square-based pyramid=\n1 squared base\n4 triangle shaped sides\n1 point at the top of the shape\n4 more at the bottom
503124
first split the triangle in half. \nfind the height of the triangle (with the 12cm side as base)\n\n7^2 - 6^2 = (height)^2\nheight = 3.61\n\nUse formula\n\nArea = (0.5) (height)(base)\n     = (0.5) (3.61)(12)\n     = 21.66 cm squared
563210
The volume of a pyramid is equal to one-third the base area multiplied by the height.\n\n\nImagine a step-pyramid made up of small square prisms with dimensions\na-by-a-by-b, arranged in square layers. If the layers are k-by-k for\nk = 1, 2, 3, ..., n, then the total volume of the step-pyramid is:\n\n   V = a^2*b*[1^2 + 2^2 + 3^2 + ... + n^2],\n     = a^2*b*n*(n + 1)*(2*n + 1)/6 (which can be proved by induction),\n     = a^2*b*n^3*(1/3 + 1/[2*n] + 1/[6*n^2]).\n\nNow, the height of the step-pyramid is h = b*n, and the area of the \nbase is:\n\n   B = a^2*n^2, \n\nso the volume is:\n\n   V = h*B*(1/3 + 1/[2*n] + 1/n^2).\n\nNow let n -> infinity, so the steps get smaller and smaller, and the\nvolume of the step-pyramid approaches the volume of the inscribed \npyramid. Then the right-hand side approaches h*B/3, as the volume V \napproaches the volume of the pyramid.\n\nThis same proof works for a pyramid with any polygonal base. For a \ncone, take a pyramid with a regular m-gon for a base, and let \nm -> infinity.\n\nThe base approaches a circle, and the pyramid approaches a cone, and \nthe formula V = h*B/3 still holds in the limit.\n\nThere is another proof, which cuts a rectangular solid into six pieces \nof equal volume, each of which is a triangular pyramid (or irregular\ntetrahedron). This proves that the volume of each is 1/6th the volume \nof the starting rectangular solid, and each has base of area 1/2 the \narea of one of the faces of the solid, and height equal to the \ndimension of the solid perpendicular to that face
879654
multiply the moles by the number 6.02 x 10^23.....altho it would be a very big and unmanageable number but thats how u find it
457596
Surface area:\nCylinder(lateral):2 times pie times radius times height\ncylinder(total): 2 times pie times radiuse times height + 2 times pie radius squared\nTriangular prism(total): find the area of every side and add all together to get surface area(hint:area of a triangle=1/2bh or bh/2)\nCone(lateral):pie times radius times length\nCone(total):pie times radius times length + pie squared\npyramid(total):find area of ever side and add all together \narea of a triangle=1/2bh bottom of the pyramid is length times width
865361
The formula is F=D²/16d\nWhere D is the diameter (10 feet) and d is the depth (5 feet)\nF = 100/80 = 1.25
770086
y=6x^2, When x = 0, y = 0 When x = 1, y = 6\n\nSince rotating about the x-axis\nV = π∫(from y = 0 to h) x² dy\n= π∫(from y = 0 to h) y/6 dy\n= πh²/12\n\nWhen h = 6 V = π*36/12\nSo volume in glass (at time t and height h) is given by\n\nV = π/12 * (36 - h²); 0 ≤ h ≤ 6\n\nSo dV/dh = π/12 * (-2h)\n= - πh/6\n\nNow dV/dt = dV/dh * dh/dt\n - ½ = - π*3/6 *dh/dt\ndh/dt = 1/π\n\nSo the level is dropping at 1/π (in/s)
193438
the 6^2 will divide out, and then you have to multiply the 2 with all the exponents on the inside....oh and r^0 is just one....so i think the answer would be t^-10 \nPS i just changed this answer, realized i made some stupid mistkae :-)
512055
2,800\n\nYour original solution is one tenth of a mL, so multiply that by ten to get the end volume.  Do the same thing with the number of particles: 280x10=2,800.