Someone teach me how to do this math problem...i know it's easy...it's been years since school?
409373
60x+60=180\n60x-60=180-60\n60x=120\n60x/60=120/60\nx=2
937830
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today
882621
My old math teacher showed me this.\n\nSince A=B, then A-B=0, and you can't divide by 0
893957
well darling ;\nimagine this like that\n\ny^2 + ( a+b)y + ab \nyou need to find " a+b " & " ab" \nin our function \na+b = 16 & ab = 64 \n( y + a)( y + b) \n( y + 8 ) ( y + 8)\n{ ' 8 + 8 = 16 '   &  ' 8 * 8 = 64 ' }\nso\n( y + 8)^2\n\nGood Luck sweetheart.
233014
U R RIGHTT..HOW DID YA GET IT..PLZ CAN YA EXPLAIN..I'VE BEEN TRYING THIS PROBLEM FROM A LONGTIME.EVEN DE CALCULATOR SAYS ITZ "4"..I KNOW DE CALCULATORS WRONG TOO..PLZZ DO EXPLAIN IT TO ME ASAP
959479
all you need to do is go to www.webmath.com, it'll help u there!\n\nI always do my math problems to that site if ever i get stuck on something! It's helpful!
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
1111502
okay here is what I think....still a little unclear\nx=9th grade\nx+8=8th grade\n3/4(x+8)=11th grade\n\nso...\nx+ x+8+ 3/4(x+8)=96\n\nx+x+8+3/4x+6=96\ncombine terms\n2 3/4x + 14=96\nsubtract 14 from both sides\n2 3/4x=82\ndivide each side by 2 3/4\nx=29 9/11\nthen round up\n9th grade =30\n8th grade =38\n11th grade=28 (actually it is28 1/2 but bc you can't have 1/2 of a person it is 28)
733739
do the multiplication first, then add the variables, then solve the equation by getting the variable to one side , remember, you move numbers by adding their opposite to both sides \n\n2(2.5b-9) + 6b=7\n5b - 18  +6b=7\n11b-18=7\n      +18  added to both side to move the -18\n11b=7 +18\n11b= 25\ndivide by -11 to both sides\nb=25/-11\n\nps: oops was that a .2 at the beggining? if so, the answer for the start would be \n.2(2.5b -9)\n.5b -.9
1183842
find the are  (base x height = area) and time that by 3........   OR  ........ take each of the length of the sides and times it by 3...
555699
I think I can help you with this one... I learned how to do it in Kindergarten.\n\nPull your head out of your ass and measure.\n\nGood Luck!
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
455504
I will explain a method that is the most easy on this planet, and a unique one.\n\nI will illustrate with the help of a simple example.\n\nEg. 4-2.\n\nDraw no. line as follows:\n\n<-6--5--4--3--2--1--0--1--2--3--4--5--6--7-->\n\nNumbers left to zero are negative integers\nand to the right are the positive ones.\n\nLocate 4 on this line. Now move 2 steps behind 4 as the operation to be carried out is subtraction.\n\nThis will give answer as 2. \n\nSimilarly for addition move the steps ahead.
832646
I'm sorry, but how could you not know this?\nThis is basic elementary math and if you don't know how to round you are in trouble.\nIt's 0.1 by the way
448711
51,336\n\nNext time just type your math problem into at google search and it will do the math for you!\n\nLink below.
888367
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
517123
It's hard to show it clearly here but the solution is actually:\n\n[-b±√(b²-4ac)]/2a\n\nthere will usually be two solutions!\nThe site below has it laid out more clearly...\n\n("invited" to leave school early.. 1974)