programming code in c to copy a input file to a output file.?
406293
scanf reads from the input line and printf prints the information you give to the output line.
293992
Use TOBA (see link below)\n\nToba translates Java class files into C source code. This allows the construction of directly executable programs that avoid the overhead of interpretation.
1143912
There's no such site, as far as I'm aware.\nI don't think it's possible to convert from VB to C, because it would be too difficult (READ: impossible!) to do such a thing (they are too different programing languages, one is compiled, one interpreted...). You'd better try to understand the algorithm(s) in the programs and rewrite the code!
380729
cat the file into awk and then print out the fields you are interested in.\n\nFor example below code will print only first item on each line in myfile\n\ncat myfile | '{ print $1 }'
84237
Use Putfile:\n\nhttp://www.putfile.com/
898810
Browse directly to the file you want and right click on it. Then select copy. go back to C: drive and right click. Select Paste. It will copy that file over to the C: drive
1130146
C program? Do you mean the C language, or the C Drive?
129073
The code below will work.\n\nint main()\n{\nint aNum,i;\ncout<<"enter a number";\ncin>> aNum;\nfor(i=0;i<aNum;i++)\n{\nfor(j=0;j<=i;j++)//nested loop\ncout<<"*";// end of nested loop\ncout<<'&#92;n';\n}// end of outer loop\nreturn 0;\n}
742648
#include<stdio.h>\n#include<conio.h>\nvoid main()\n{\nint n=5,i,j;\nclrscr();\nfor(i=1;i<=2*n-2;i++)\n{\nprintf(" ");\n}\nprintf("1&#92;n");\nfor(i=2;i<=n-1;i++)\n{\nfor(j = 1;j<=(n-i)*2;j++)\nprintf(" ");\nfor(j = i;j<=2*i-1;j++)\n{\nprintf("%d ",j);\n}\nfor(j = 2*i-2;j>=i;j--)\n{\nprintf("%d ",j);\n}\nprintf("&#92;n");\n}\nfor(i = n;i<=2*n-1;i++)\nprintf("%d ",i);\nfor(i = 2*n-2;i>=n;i--)\nprintf("%d ",i);\ngetch();\n}
664249
After seeing this question asked many times (I still don't know why it keeps being asked), I decided to try it. My understanding is that you cant just open the source file and print it which would be the obvious way. Well, its much harder than it seems, but after several hours I did get some code to work. There is purposely "sloppy" or "poor" coding in it to get to work, but its the best I could do in a few hours time. \n\nI dont know if I want to share it though, because it was tuff.
253284
#include <stdio.h>\n\nint main(void) {\n\nint i, j, count; //C Sucks, wait till you take java\n\nfor(i=1; i<=1000; i++){&#92;&#92;goes through all numbers 1 to 1000\n    count=0;\n    for(j=2; j<i; j++)&#92;&#92;goes through all numbers 2 to i\n    {\n     if(i%j==0)&#92;&#92;checks to see if it i is evenly div. by i\n        count++;\n    }//nested for\n    if (count ==0)\n        printf("%d&#92;n", i);\n}//for\n\nreturn 0;\n}//main\n\n\n//Hope that helps!
348911
#include <stdio.h>\n#include <strings.h>\n\nint\nmain(int argc, char* argv[])\n{\n  char *token, *string = argv[1];\n  int count = 0;\n\n  while ((token=strtok(string, "&#92;t ")) != 0) {\n    count++;\n    string = 0;\n  }\n    \n  printf("String has %d words&#92;n", count);\n\n  return 0;\n}\n\n\nAnd to show that it works:\n\n$ cc cw.c\n\n$ a.out "this is a simple test"\nString has 5 words
231724
not really sure how to do that.. \nbut try using a splitting program to join it\nhjsplit is a good one that i use to split and it joins files too. \n\nhttp://www.pcworld.com/downloads/file_description/0,fid,20360,00.asp
252411
IN computer language ,everything need to be converted into machine level language. THen it is executed by the processor.\nIn your program also, 1st preprocessor directive include<stdio.h> defines the standard function like printf.\nmain is SPECIAL function  and print is standard input statement.\nCompile covert your source into machine level language. while linker link the files with macros,preprocessor directives. Run command execute the program..//this is abt windows.\nIN unix\ninstead of turboc, there is CC compiler. which compiles the code. while to run the program just type ./a.out\n\nso steps to doin uNIX are:\n\n1. vi filename.c\n2.cc fileaname.c\n3./a.out\n\n\nHi! what type of more detail u want? about execution in unix or programming in unix?or anything else..?
492415
try it on anoither comouter and transferring the file to anther comoputer
408732
To use the input the way you want... you have know how the c compiler gets the input... all output and input are first transferred from the i&#92;o device to a stream...so the input is  stored in a stream and the program gets its input from this stream...so if the user gives two chars as input... its stored in the stream... and after the program gets a char from the stream...the next char which is in the stream is taken as the next input... to avoid this you can use the function fflush();... this funtion erases the stream...
849879
here you go...\n(it'll work with up to 255 different disks, if you need more, you'll have to replace chars with ints)\n\nm1(char *a,b) {memove(b+1,b,strlen(b)+1); *b=*a; memmove(a+1,a, strlen(a);}\nm(char *a,b,c) {if (*a)  {m(a+1,b,c);m1(a,c);m(b,c,a);}