what is the molecular formula for glucose?
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C  H   O\n.6  12   6\n\nWITHOUT DECIMAL POINT
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Polysaccharides are relatively complex carbohydrates.\nThey are polymers (Polymer is a generic term used to describe a very long molecule consisting of structural units and repeating units connected by covalent chemical bonds) made up of many monosaccharides joined together by glycosidic linkages. They are therefore very large, often branched, molecules. They tend to be amorphous, insoluble in water, and have no sweet taste.\nCarbohydrates are chemical compounds that contain oxygen, hydrogen, and carbon atoms. They consist of monosaccharide sugars of varying chain lengths and that have the general chemical formula Cn(H2O)n or are derivatives of such.
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http://www.rpi.edu/dept/bcbp/molbiochem/MBWeb/mb1/part2/sugar.htm\n\nSimple web search
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Glucose, Fructose, Maltose
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Sugar is sucrose, a molecule composed of 12 atoms of carbon, 22 atoms of hydrogen, and 11 atoms of oxygen (C12H22O11). \nThe 1st link is just general info, the 2nd may give you an idea for an experiment.
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This time we use oxygen to burn the sugar:\n\nSugar + Oxygen = Carbon Dioxide + Water + Energy\n\nUsing glucose:\nC_6H_12O_6 + 6 O_2 -> 6 CO_2 + 6H_2O + Energy
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Start with 2.948g K2Cr2O7. End with how many mL. K=39, Cr=52, O=16, K2Cr2O7=294. Multiply by 1molK2Cr2O7/294gK2Cr2O7. The gK2Cr2O7 cancel, leaving molK2Cr2O7. Multiply by 1000mLK2Cr2O7/0.5molK2Cr2O7. This comes from 0.5M, which means 0.5 mol in 1000mL. The molK2Cr2O7 cancel, leaving mL solution to be evaporated.\n\nStart with 45mL NaCl, end with gNaCl. Na=23, Cl=35.5, NaCl=58.5. Multiply by 0.125molNaCl/1000mLNaCl. This comes from 0.125M. The mLNaCl cancel, leaving molNaCl. Multiply by 58.5gNaCl/1molNaCl. The molNaCl cancel, leaving the gNaCl that is the answer.\n\nStart with 100g glucose, G. End with L of G. C=12, H=1, O=16, C6H12O6=180. Multiply by 1molG/180gG. The gG cancel, leaving molG. Multiply by 1L G/0.5molG. This comes from 0.5M G. molG cancel, leaving L of G. Which is the answer.
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The formula for water is H2O i.e. there are 2 atoms of hydrogen and one atom of oxygen. Its molecular weight is 18 g/mol .
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IF it is of a disaccharide, both being 6 carbon sugars, such as in the case of sucrose (i thinking glucose and mannose? or gluc and fruc?) and their are 12 Carbons, than essentially 12 CO2 molecules, thus D would be the answer.
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Glycerin molecule is made of three carbon atoms (C), two hydrogen atoms (H), and three alcoholic hydroxyl groups (-OH). The chemical formula is C3H8O3.
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Carbohydrates: include sugars and their polymers. They include monosaccharides disaccharides, and polysaccharides. The monosaccharide is a monomer, the disaccharide is a polymer,and the polysaccharides are macromolecules.\n \nMonosaccharides: The basic formula (CH2O)\nExamples: triose sugars, 3 carbons, glyceraldehyde and dihydroxyacetone; pentose sugars. 5 carbons. ribose, deoxyribose, and ribulose; hexose sugars, 6 carbons, glucose, galactose, and fructose.\n     \n\n \n \nDisaccharides: These are double sugars with the formula C12H22O11. Notice that one molecule of water is missing from the formula. The covalent bond holding the two monomers together is called a 1-4 or 1-2 glycoside linkage. Examples: sucrose = glucose + fructose. maltose = glucose + glucose, and lactose = glucose + galactose.\n \n     \n\n \nPolysaccharides: The basic formula is ( C6H10O5)n . These are macromolecules capable of acting as structural or storage molecules.\n \nStorage Polysaccharides: Starch is a plant storage polysaccharide that is composed entirely of glucose joined by @1-4 glycoside linkages. amylose is the simplest form of starch. amylopectin is more complex and is branched. Glycogen is an animal starch stored in the liver and muscles of vertebrates. It is more highly branched than amylopectin.\n \nStructural Polysaccharides: Cellulose and chitin are examples of structural polysaccharides.\nCellulose is the most abundant organic compound on earth. It is made of glucose, like starch, but they differ in the type of 1-4 linkage. Instead of an @ linkage as in starch cellulose contains a B 1-4 linkage.\nThis causes the polysaccharide to take on a step arrangement and not a linear one like in starch.\nEnzymes find it difficult to brake the B 1-4 linkage.
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Glucose = Ethanol + Carbon Dioxide + Energy\n\nC6H12O6= 2C2H5OH +2CO2 + Energy
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Becasue if you take the constituent atoms of a carbohydrate molecule and break them down, you could put them together to form water and carbon.\n\nFor example, sucrose -- C12H22O11 -- could be broken down into 12 atoms of carbon and 11 molecules of water.
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You're right. The empirical formula is (CH3)x. The molar mass of (CH3)x is:\n\n(12 + 3*1)x = 15x\n\nSo:\n\n15x = 30, x = 2\n\nAnd the molecular formula is:\n\nC2H6    (CH3-CH3 : ethane)
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Hopefully by "Stoichiometry Concept Map" you want to know the route you take from a given point A to point B.\nBasic "MAP" :\n\nGrams of Substance A divided by molar mass of A ===> Moles of A times the coefficients of A and B from balanced equation to get moles of substance B===> Moles of substance B times molar mass of substance B ===> Grams of substance B\n\nExample:  How many grams of water produced in the oxidation of 1.00 g of glucose (C6H12O6)\nThe balanced equation is:\n\nC6H12O6(s) + 6 O2(g) ----> 6 CO2(g) + 6 H2O(l)\n\nSubstance A = Glucose\nSubstance B = Water\n\nOkay to solve lets convert 1 g of glucose into moles by dividing 1.00 g by C6H12O6 mol weight of 180.0 g/mol\n\n1.00g/180.0g/mol = 5.56 * 10^-3 mol\n\nNow multiply by 6/1 because the coefficient in front of glucose is 1, so put one in the denominator, the coefficient in front of the water is 6, so put six in the numerator.\n\n(5.56 * 10^-3 mol * (6/1)) = 3.33 * 10^-2 mol of H2O \n\nNow take that result and multiply it by the molar mass of Substance B\n\n(3.33 * 10^-2 mol *(18.0g/mol)) = 0.600g of H2O\n\nSo your final answer is 0.600 grams of H20 is produced when 1.00 gram of glucose is oxidized.
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250x.05=12.5grams of glucose
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Starch is a polymer of carbohydrates, so it doesnt have a set molecular formula- The individual units are CH, CH2, or CH3, depending on the number of carbon bonds on each carbon.