how do i calculate serum albumin using--C1V1=C2V...?
397904
C1 will be the original concentration of 10mg/cm3, V1 will be the 5 different volumes you are adding.  C2 will be unknown and V2 will be the 10cm3.  For example:\ntube 2...(10mg/cm3)(1cm3)=C2(10cm3)   C2=1mg/cm3
201711
well you use the ideal gas law pv=nrt. STP means temperature is 25 degrees = 298K and P=1atm = 101325Pa. you have 1g and to convert that to molar mass, you would divide by the molar mass so 1/28 (i think molar mass of N is 14?). so then you do v=nrt/p = 298 (8.314)/28 (101325) = somethin\n\nfor the CH4, you know the volume and temp and pressure. you have to find n. so you put V = 0.0172m^3 (cuz 1000L = 1m^3). and temp and pressure are same, so n=pv/rt. and  once you get n (number of mols) you convert it to mass by multiplying by the molar mass (i think 16) and you get some number.\n\nhope u get it, sorry i didnt do the calculations. let me know if u need more help or whatever. laterz
731363
If v^2 is proportional to Fc, then v^2 = k*Fc, where k is a constant.  For each of your values of v and Fc, calculate k = v^2/Fc;\n\nYou will get the following values for k:\n\n39.51, 37.97, 33.61, 32\n\nThese average to 35.77 and the standard deviation is about 10%, which would be considered a good fit and that the formula\n\nV^2 = 35.77*Fc fits those values pretty well.
650254
it is C as in use the formula for CI for one sample proprtion from your book(i better get the best answer choice cause this is the fifth one i am answering)\nand the above guy is a moron
446836
Concentation 1 x volume 1 = conc 2 x volume 2.\n\nYoure are probably using it to find total blood volume with a known volume of 'marker' albumin.  \nThe marker concentration x its volume = the concentration after dilution x the amount of diluent(the blood volume)
840090
P1V1 = nRT = P2V2\nP1/P2 = V2/V1
983043
A=ebc\n\nWhere A is absorbance (no units, since A = log10 P0 / P )\n\ne is the molar absorbtivity with units of L mol-1 cm-1,\n\nb is the path length of the sample - that is, the path length of the cuvette in which the sample is contained. We will express this measurement in centimetres.cm\n\nc is the concentration of the compound in solution, expressed in mol L-1\n\nNow, you know why there is no unit for "A".
780066
V = nRT/P\nV = (25g/44g/mol)(0.08206Latm/molK)(298K)/1atm\nV = 138.9 L
855087
Ca2+=[Ar]\nMg2+=[Ne]\nI-=[Xe]\nF-=[Ne]
839145
x=107.636\nequation is c1v1=c2v2 it is asking for ml so change 1.60 L to 1600ml and you get x*11=1600*0.740 solve for x.
944773
The dilution formula is:\n\n(M1 and V1 are the concentration and volume of the stock solution; M2 and V2 are the concentration and volume of final solution.  M1 and M2 should be in molarities; V1 and V2 should be liters, but it doesn't matter as long as they're the same units)\nM1V1 = M2V2\n(12.0 M)(V1) = (2.50 M)(250.0 mL)\nV1 = 52.1 mL\n\n(C)
862382
Ah yes, the classic Iron Thiocyanate complexation lab.\n\nTo determine the concentrations for the first part, you need to know the concentrations of the stock solutions and the final volume of the solution you made.  You can then use the formula:\n\nC1*V1 = C2*V2\n\nWhere C is concentration and V is volume.\n\nFor the second part, I'm not really sure what you did in your lab.  Usually you use the calibration curve you constructed from the first part to measure the concentrations in the second part.  There is alot of ugly calculations to be done in there.  Check your lab packet for more information.
482888
I'm guessing that your question pertains to the series of standard solutions you would prepare using the stock solution and volumetric flasks/pipette.  \n\nYes, you can use the C1V1=C2V2 formula, however there's a more practical and faster method that can be arrived at through common sense.  That is the concept of dilution factor.  If you have a stock solution of .5M iron for instance and you wanted to make a .05M iron solution, just dilute the next solution by a factor of 10%.  One way this can be achieved is by taking 10 mL of this stock solution using a volumetric pipette and adding it to a 100 mL volumetric flask.  To lessen the sampling error, it's better to take a larger sample volume, but usually this becomes tedious since lab equipment can be limited.\n\nSo take the original x molarity stock solution.  And if your final desired concentration is y, then the dilution factor is\n\ny/x \n\nThis percentage, y/x, represents the volume percentage in the final solution, that is multiply y/x by the particular To Deliver volume of the volumetric flask, to determine how much volume of the stock solution you need.......place this solution into the volumetric flask with a volumetric pipette, and then dilute to the mark with the standard solvent.
837288
Use the formula M1V1=M2V2\n\nThat is the first Molarity times the first volume are equal to the second Molarity times the second Voume.\n\n.2098M x70mL = .662M x V2\n\nSolve for V2.\n\n(.2098 X 70)/.622 = V2\n\nV2 = 23.61mL NaOH to titrate the solution to neutrality.
742488
C1V1=C2V2\n40%x100mL=25%xV2\n4000=25%xV2\n4000/25=V2   ((25%xV2)/25=V2)\n160=V2\nV2-V1=60\nshe should add 60 mL of water.
842874
C1V1 =  C2V2     thereafore C2  =  (C1*V1)/V2\n\nC1=3.58 * 10E-3  M\nV1=5.0 * 10E-3 dm3\n\nC2 = x M\nV2 = 2.5 * 10E-2\n\n\nC2 = (3.58*10E-3      X     5.0*10E-3) / 2.5*10E-2\n\nFinish off
338257
a) vcenter = (m1*v1+m2+m2)/(m1+m2)\n\nb) v1 rel = v1 - v center\nv2 rel = v2 - v center\n\nremember velocity is a vector so you must keep track of magnitude and direction