What is the product (x-a)(x-b)(x-c)...(x-z) equal to?
398761
the product contains the expression (x-x) which = 0 thus the product is 0
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
406322
q*(x,y,z)X(a,b,c) = q(yc - zb, az - xc, xb - ya). In your case, B is (0, 0, -1.2) so you have -5nC(-1.2y, 1.2x, 0) = (-3.6*10^(-7), 7.6*10^(-7), 0) which is a trivial system of equations.
704948
Taking x common from (x^2 - ax)/x , we get x(x - a) /x which gives us (x-a). Now, (x + a)(x - a) gives us (x^2 - a^2)
565951
the answer is zero b'coz at the end, X-X is equal to zero.
894584
y(x-1) = z\n\n(x-1) = z / y\n\nx = ((z/y)+1)\n\n\nthe middle one.
927
aX + b = cX + d\n=> aX - cX = d-b\n=> (a-c)X = d-b\n=> X = (d-b)/(a-c)\n\nin this case:\n5(x -3) = 2x +6\n=> 5x -15 = 2x +6\na= 5\nb= -15\nc= 2\nd= 6\n\n=> x= (6+15)/(5-2)\n=> x= 21/3\n=> x= 7
729005
a.xa+xb\nb.21x^3+24x^2y\nc.3x(8x+5)+2(8x+5)\n=24x^2+15x+16x+10\n=24x^2+31x+10\nd.4x(2x+1)-6(2x+1)\n=8x^2+4x-12x-6\n=8x^2-8x-6\ne.8x(5x^2+7x+3)+2(5x^2+7x+3)\n=40x^3+56x^2+24x+10x^2+14x+6\n=40x^3+66x^2+38x+6\nf.x^2-1\ng.x(x^2+2x+4)-2(x^2+2x+4)\n=x^3+2x^2+4x-2x^2-4x-8\n=x^3-8
387602
1 = b\n2 = d\n3 = d\n4 = c\n5 = c\n\n4/5
339354
(2x + b) * (a + 3c)\n\n\nsteps:\n2ax + 6xc + ba + 3bc \n1) group first two, and last two\n(2ax + 6xc) + (ba + 3bc)\n\n2) factor out 2x from the first, and then b from the second group\n2x*(a + 3c) +  b*(a + 3c)\n\n3) since (a + 3c) is common, combine 2x and b\n(2x + b)*(a + 3c)
672754
Take out the five so you have:\nx^2 + 8 + 16\nthen you can change that to\n(x + 4)^2 b/c you have to find a number that is the product of the a and c and the sum of b\nwhere you have: ax^2 + bx + c
973940
A previous answer was incorrect. It is\n\n-4x(x+3y)(x-2y)
587091
Xn = (Xn-1 + Xn-2)/2\nThen X2 = (X1 + X0)/2 = (a+b)/2.\nX3 = (X2 + X1)/2 = [(a+b)/2 + b]/2 = (a+3b)/4\nX4 = (X3 + X2)/2 = [(a+3b)/4 + (a+b)/2]/2 = (3a+5b)/8
975217
Line AC = 6, line BC= 2x+2, line AB=x+1\nSo 2x + 2 = 6\n2x = 4\nx = 2 <-- option C
983933
(x+y+z)(x+y+z) = x^2 + y^2 + z^2 + 2xy + 2xz + 2yz = 1\n\n(1-x^2 - y^2 - z^2) = 2xy + 2xz + 2yz\n\n(1 - x^2 - y^2 - z^2) \n------------------------ = xy + xz + yz\n.............2\n\nClearly the left hand side is less than 1/2
448387
4b(5 - a) - 3c(5 - a)\n= (5 - a)(4b - 3c)\n\nThe answer is D. Since both have the factor (5 - a), you factor it out, and what's left is (4b - 3c).
1051508
Your equation would look like x^2-ax+b.  Which means when you solve the equation you would two answers one of which will contain a plus sign other will contain a minus sign since the middle term is negative.  Thus the answer is C.