how high will a helium filled balloon float?
404977
Hahahahahahaha, how amusing the previous anwers are.\n\nThe balloon would continue to rise in the atmosphere until it reached a height where the pressure inside the balloon was equal to the pressure outside the balloon...then it would remain at the same height, moving in the wind, maybe slightly up and down due to thermals...until it burst !
941032
waterballoons, not only can you have more fun with them but they cant harm you. Once when i used a helium balloon, my voice was like that for half an hour!! it freaked me out! Waterballoons are simply fun.
687166
The air in the ball is less dense than the surrounding pool water so less dense things rise upwards like a balloon. Helium is lighter than the Oxygen/Nitrogen mix found in the atmosphere and it is exactly the same with the pool and the ball. And when you drop something in like a rock it sinks to the bottom because more dense objects fall through the more dense ones like rain. In a pool there's more water so it seems like the air is naturally on top but in rain there is more air so it's like a mix until the gravitational attraction/density problems are fixed.
898627
The idea is that the increase in hydrostatic pressure of the water will cause a decrease in volume of the balloon. You are told that the temperature of the ballon is constant so that you can make the assumption PV = constant = Pa Va, where Pa Va are the pressure and volume at atmospheric conditions.\n\nThe bouyant force is simply the weight of water displaced, and therefore is it proportional to the volume of the balloon. You can assume that the water is incompressible and therefore constant density.\n\nSo, saying that the bouyant force is 1/2.4 of the surface value means that the volume has decreased to Va/2.4.\n\nPa Va = Pb Vb; Vb = Va/2.4 --> Pb = 2.4 Pa.\nRemember that this means absolute pressure.\nThe absolute hydrostatic pressure in the water is:\nPw = Pa + (rho) g h\nwhere h is the depth below the surface.\nSo: 2.4 Pa = Pa + (rho) g h\nh = (1.4 Pa)/((rho) g)\nPa = 101 000 N/m^2\nrho = 1000 kg/m^3\ng = 9.8 m/s^2\nh = 14.4 m
1013381
This would be an awesome inexpensive experiment. as I believe that it does with respect to the diameter of the bubble gravity attraction should be increased with respect to surface area, however this experiment should be conducted in an environment free from draft and circulating air flow.
822839
The net force is the volume of the balloon times the density difference between air and hydrogen (∆d) times g. From archimedes principle: the bouyant force is dair*V*g, the weight of hydrogen is dhyd*V*g, so the net force is the difference, or (dair - dhyd)*V*g =∆d*V*g.   The volume of the baloon is (4/3)πr^3.\n\nr = cuberoot[3*F/(4π * ∆d * g)]\n\nThis comes out 4.89 m
282829
This is similar to asking why gravity doesn't affect boats. It does, but buoyancy keeps them above water. Similarly, if you push a hollow rubber ball down to the bottom of a pail of water and simply release it, it will pop back up to the surface.\nThe helium balloon is just being pushed up by the relatively higher air pressure under it. See the sources for a detailed calculation and a diagram of the pressure situation.
652657
Helium floats ,nitrogen will make it drop to the floor..
1127230
No, it's a nice idea though. As the balloon rises the pressure outside it will drop causing the gas inside the balloon to expand until eventually the balloon will pop. Sorry to burst your bubble as it where; I love the idea of space being filled with these multi coloured balloons though :))
535624
PV=nRT\n\nas the air is heated the average kinetic energy of the molecules increases. ie P increases.But V is constant. so some gas molecules escape through the bottom. Hence the density decreases and becomes lesss than that of surrounding air.Thus the balloon rises.
530907
you should observe an initial volume 1V, and xV when the balloon had rise, at sea level atm pres. is 1 and at x is 0.8, so you do\n 1V -  1\n xV - .8\nas all inverse proportions you do the math as follows\nxV =  1\n1V    0.8   \nx = 1/0.8\nx=1.25 which means 125%\nso volume increases by a 25%
937535
The helium is compressed when it is in the tank.  When it exits the tank, it expands in the balloons until it equalizes with atmospheric pressure.  Any gas can be compressed, as to occupy a smaller volume.  You can see this if you would take a plastic container fill it with air, and submerge it to the bottom of a swimming pool.  you would able to see that the container would deform because of the volume change of the container.
1184219
an extra floatation device for added safety
689832
The object must be less dense than the fluid to float, and more dense to sink.  If it is exactly equal density, then it can be suspended.
278863
if u really want to get an answer to this question, u need to be more through when asking it. hello? i mean seriously, we dont know anything around the experiment you are working on. so take the noncharged part of the balloon and put it next to the cereal and paper. what do u think will happen. something will and if you did it then you would know.
618509
fill water balloons with different amounts of water and drop them at the same height to see if they fall differently.  =)
449240
Atmospheric pressure will support a column of air about 10 metres high.   The exact height varies from day to day depending on atmospheric pressure; high and low pressure systems.   To start with, partly fill your container with coloured water, with the hole at the bottom submerged in more coloured water.   If there was no air in your transparent ball, it would need to be 10 metres in diameterfor you to see a boundary between the empty space at the top and the water column supported by the atmosphere pushing down on the liquid outside, but because you've trapped some air inside, this air pushes down on the water so the water isn't as high.