Give me an example of a wheel-and-axle and a pulley!!!?
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The old Model T Ford manufacturing plant. The wheels, axles and pulleys where positioned above the workers providing the energy for the respective operations to make the car.
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Look at how the forces break down. For block 1\n\nSFx = m1*a = F*cos(q) - T1\n\nwhere SFx is the sum of the forces in the x-direction, a is the acceleration, and T1 is the tension from the string. For block 2\n\nSFy = m2*a = T2 - m2*g\n\nwhere SFy is the sum of the forces in the y-direction, a is the acceleration, and T2 is the tension from the string. Considering the pulley now\n\nSt = I*a/r = r*T1 - r*T2\n\nwhere St is the sum of the torque, I is the moment of inertia of the pulley, r is the radius of the pulley. Combining these three equations will let you solve for the acceleration.\n\nI*a/r^2 = T1 - T2\n\nT1 = F*cos(q) - m1*a\nT2 = m2*a + m2*g\n\nso we have\n\nI*a/r^2 = F*cos(q) - m1*a - m2*a - m2*g\n\nwhich rearranges to\n\n(m1 + m2 + I/r^2)*a = F*cos(q) - m2*g\n\nSolving for a yields\n\na = (F*cos(q) - m2*g)/(m1 + m2 + I/r^2)
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Try the Machinist's Handbook - most libraries will have a copy.
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Here is one example...the bouncing ball. Just google that in and you get a bunch of results.
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The site listed below seems to have some nice web applets with  various kinematics applications and such.  I would (and did) search Google for "kinematics" to find the best. Specific searches such as "rotational motion", "Newton's laws", "1-D kinematics", "2-D kinematics", etc will yield more tuned results.
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here's a site with pics that might give you some ideas:\n\n\nhttp://www.physics.usyd.edu.au/competition/comp1998/comp98.html
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I FOUND IT!\n\nHere: http://www.eldritchpress.org/jwj/auto.htm
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This sounds like a homework assignment, so I am not going to put it in the format you requested.\n\nYes, the concept of work does explain all of that. Without pulleys, levers, and wedges, we would have to lift 2 ton metal pieces without the use of cranes. You would be so surprised on how many things depend on pulleys, levers, and wedges.\n\nJ.N.S
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Think of the wheels as spinning masses or revolving weights, in fact gyroscopes. \nEach wants to turn left or right while spinning but is constrained by it's axis,\nHowever both drift overtime.\nNow add another pair further back and wider apart, and this pair are not on the same line of travel.\nWith four wheels all wanting to drift the resultant direction becomes a straighter line.
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The two simplest pulley systems demonstrate the principles of their operation.  First if there is a single pulley overhead and you pull down to lift a load, you must pull with the same force as the weight of the load because oonly one rope pulls up on the load.  100 pound load = 100 pound pull.\n\nSecond, if the load is below you and you pull up on a rope connected to your own level through a pulley, you pull with a force one half the weight of the load because two ropes are pulling now up on the load.  100 pound load = 50 pounds pull + 50 pounds on fixed rope.\n\nThe overhead pulley required you to pull the rope say 10 feet to lift the load 10 feet; but the pulley below you required you to pull the rope 20 feet to lift the load 10 feet.\n\nYou can calculate more complicated pulley systems either by counting the number of ropes that are under tension that actually lift the load and dividing the load by that number or you can determine the length of rope you must pull to raise the load a given distance and use that ratio to determine your force vs the load weight.  you can do this by making sketches rather than actually setting up real pulleys, ropes and loads.  Good luck.
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We use wheels and axles for all kinds of cool stuff. Cars, trucks, bicycles, and trains all use wheels and axles. Also, gears, which are a lot like wheels and axles, are used in all kinds of machines. Pulleys are, too. Look at these Wikipedia pages if you need more information.
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The answer is  - (0.635 - 0.324)* r * g = 2.9 Nm.\n\n\nYour equation for torque and other things are correct.\n\nFor the system to be in equilibrium the NET torque must be zero.\n\nSuppose that 0.635 kg mass rotates the pulley in clockwise direction.\n\nThen the other mass 0.324kg will rotate the pulley in the anti-clockwise direction.\n\nTorque produced by 0.635 kg about the axis is F x r = 0.635*r*g. (Let us take clockwise rotation  as positive)\n\nTorque produced by 0.324 kg about the axis is F x r = - 0.324*r*g. (anticlockwise direction)\n\nThe net torque about the axis is (0.635 - 0.324)* r * g = 0.311*r*g. \n\nIf there is no friction, the pulley will rotate in the clockwise direction by the action of this torque\n\nIf the frictional torque acts opposite to this torque, then the net torque will be zero and the system will be in equilibrium.\n\nTherefore the frictional torque is - 0.311*r*g. (anticlockwise direction)\n\n\nSubstitute the value for r = 0.95 m and g = 9.8m/s^2\n\nThe frictional torque is 2.9 Nm.
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http://www.webmath.com/geo_cylinder.html\nif u want examples go to this link or find another link on yahoo
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All of the power from the motor goes to friction because they just let the wheel coast and burn up all the energy.  But, I'm sure that wasn't the intended answer for the problem\n\nYou need to make a few preliminary calculations:\nFirst you need the Inertia of the flywheel which you can find given the mass and radius of the wheel.\n\nThen you need to calculate the angular acceleration required to bring an object at rest up to 5.88 rad/s in 0.531 sec.  Using this, you can get the torque of the motor - friction.\n\nFinally, calculate the angular acceleration required to bring an object spinning at 5.88 rad/s down to rest in 26.8 revolutions.  Using this, you can get the torque of the friction by itself.\n\nAdd the second result from the first to get the torque of the motor.  Take the friction torque and divide by the motor torque times 100 to get percentage of friction.
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Lift, thrust, gravity, drag.
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A shovel or a backhoe! That's a machine not a 'loose girl'\n\nhttp://www.total-knowledge.com/~willyblues/
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What is what?? the magnitude?? the torque??\n\nfinish your questions