Obtuse Side Angle Side?
402447
No.\nYou have to find cos(100) and then multiply it by 24\ncos(100) = -.1736
808242
Yes. These are intriguing geometry problems. What is YOUR question? Be specific. Post ONE question and be specific about where you are stuck. Right now, this just looks like you want someone to DO your homework for you. But you wouldn't cheat on your homework like that, would you?\n\nHere's a hint -- supplemental angles add up to 180\n\nFor example, if one angle is 60 degrees, its supplement is 120
695430
There's not enough information to answer the question. We need to know at least one angle as well as the length of two sides.
584720
Emily - \n\nThat is going to depend on what angle you want the sin, cos, and tan for.  If yo'ure looking at angle M, \n\nsin = opposite leg (one that doesn't touch the angle) / hypotoduce (long leg... dont quote the spelling) = 10/17.2 = .5814\n\ncos (angle) = adjacent leg (short one touching the angle) / hypot (long leg) = 14/17.2\n\ntan (angle) = opposite leg / adjacent leg = 10/14 \n\nIF you were looking at another angle you would just adjust these to that angle.  For example, the sin of angle T is 14/17.2\n\nthe sin, cos, and tan of angle R are all undifined\n\nGood luck\n\nP.S. Cheer Up   http://img.photobucket.com/albums/v641/emilymiriam/emilyrainbow001.jpg
896517
See one point of view at
686639
just blow air through your nose when you are upside down\n\nwater should not go up while you are right side up
934709
Plot 3 points, connect them with lines. you get a triangle\n\nList most acute (sharp) angle 1st, most obtuse (blunt) angle last, and remaining one in the middle.\n\nIt looks like C will be the most obtuse
984859
internal rotation on shouldwer and elbow bent
846631
Construct meaning with a compass and straightedge? And by "adjacent" they're already at right angles? Just measure each side with the compass, move it so one leg is at the other corner, and draw a small arc approximately where the other leg extends. Do this for both sides, then the point of intersection is your missing point, and you can draw out the rectangle with the straightedge.\n\nIf the sides are not at 90 degrees, just turn one of them (measure one with the compass, draw a circle based on it, then take the two points of intersection and construct the perpendicular bisector, then take the point where that intersects....)
159884
It looks like a 90 degree angle:     |_
863293
In the opposite direction of the applied force or motion
784249
Sides on a fifty pence piece
153276
Reads the same upside down as right side up
206799
look on the oposite side as the front\ncmon use your head
373853
I think right angles are, because we just did that in my class and thats what i heared. good luck
98672
use the tangent ratio ( trig function ) or inverse tangent of (6/ (43/8)) OR iNV TANGENT (1.116) = 48.14 degrees and to get the other angle, just subtract it from 90 degrees or 41.86 degrees. hope it helps how I got it. go over the trig function or cohsahtoa rule
715400
Angle of line from horizontal position.