what is the greatest common factor of the following monomials? 15t^2 and 60st?
406228
I could be wrong but is it 15t.   They each have one t in common.  60 and 15 are both divisible by 15.\n\nTake the time to really think about these problems before posting them all on the internet.  It's better to have all the answers than to find someone else that does.\n\nGood luck with your math homework.  ;)
32760
You can use the AC Method to answer this question:\n\nFirst, rewrite the expression so it's in the form Ax^2 + Bx + C where A,B, and C are constants (numbers)\n\n16x^2 + 8x - 15\n\nThere's no common factors we could take out first, so...\n\nMultiply A x C, which in this case is 16 x -15 or -240.  Then look for factors of this number that add up to B.  You're looking for two numbers that fill in the blanks below:\n__ x __ = -240\n__ + __ = 8\n\nPrime facorization will help give you some ideas, or make an ordered list of numbers that multiply to -240.  \n240 and -1\n120 and -2\n80 and -3\n60 and -4\n48 and -5\n40 and -6\n30 and -8\n24 and -10\n20 and -12\n\nSee how the last pair of numbers satisfies the conditions?\n\nRewrite your polynomial, substituting the 2 values in for B to have 4 terms:\n\n16x^2 + 20x - 12x -15\n\nThen factor by grouping\n(16x^2 - 12x) + (20x - 15)\n4x (4x - 3) + 5 (4x - 3)\n(4x + 5)(4x - 3)\n\nThis method works for most polynomials of the form Ax^2 + By + C!  \n\nYou can check your answer of (4x + 5)(4x - 3) by using the FOIL method and see that it does work.\n\nGood luck!
757059
Your first two are right.  Some notes:\n\n1.  If you don't already know, you can find the GCF by factoring the numbers and taking the factors they have in common.  In this case, they only have 1 as a common factor.  You can find the LCM by taking the factors and multiplying the highest powers of each multiple.  In this case, you are simply multiplying all three numbers together.  If the GCF of two or more numbers is 1, then the LCM is the product of those numbers.\n\n2.  Yes, though you can type |6-8| by holding SHIFT and pressing the slash key (by the ENTER key).\n\n3.  Multiply through and combine like terms (assuming x squared in the second part):\n2(4x^2 - 3x + 2) - 3(x^2 - 5x - 8) =\n8x^2 - 6x + 4 - 3x^2 + 15x + 24 =\n5x^2 + 9x + 28\nThis cannot be factored any more.\n\n4.  Solve for V by multiplying through and getting V by itself:\n6(V - 2) - 4(V + 3) = 10-42\n6V - 12 - 4V -12 = -32\n2V - 24 = -32 \n2V = -8 (add 24 to both sides)\nV = -4 (divide both sides by 2)\n\n5.  You never want to leave a radical in the denominator.  So, the expression, 3/√x, is not the correct form.  You can get rid of the radical by multiplying by the square root of x for both the numerator and the denominator:\n3/√x * √x/√x (since √x/√x = 1)\n= 3√x / √x√x\n= 3√x / (√x)^2 \n= 3√x / x\n\nNow, the radical is in the numerator and not the denominator.
282430
do u mean greatest common factor
930308
x=[2+/-rt(4+60)]/2\n=[2+/-8]/2\n=-3 or 5\nso the factors are\n(x+3)(x-5)
308266
This factors into (x-5)(x+3)(2x-1)\nFind factors of p and q where p=15 and q=2\nFactors of 15: (positive and negative) 1,3,5,15\nFactors of 2: (positive and negative) 1,2\nPossible rational factors are p/q\np/q = (positive and negative) 1,3,5,15,1/2,3/2,5/2,15/2\nTest these numbers until you find one that works.\n5 works because\n2(5)^3-5(5)^2-28(5)+15=0\nNow use long division or synthetic division to get the others.
702912
150:350  divide terms by common factors\n15:35\n3:7
923846
Answer 1:\n59, 61 and 67 are all the primes between 55 and 70\n\nAnswer 2:\nThe Greatest Common Factor of 8 and 3 is 1. It can never be higher than 80. Even if it's the LCM you want, the answer is 24. Maybe you typed the 8 by mistake.\n\nAnswer 3:\nWhile searching for common multiples of two different primes, multiply the two and search for the product's multiple.\n7*5 = 35\nWe need a multiple of 35 between 150?\nOOps! What do you mean between 150?
372976
yes u can\nt^2(s^4-4)is the factored form\nt^2 is the highest common factor\n\n\n75x^2 - 147y^2\n3 is the common factor\n3(25x^2-49y^2)\n3(5x^2-7y^2)(5x^2+7y^2) is the factored form of 75x^2 - 147y^2
422347
2\n\n60 minutes to a hour\n2x60 = 120
875190
Perform a prime factorization of each number:\n16 = 2 x 2 x 2 x 2\n36 = 2 x 2 x 3 x 3\n\nTo find the lowest common multiple, you need to take each prime factor, enough to cover both numbers.  In other words you need four of the 2s and two of the 3s.\n\nLCM(16, 36) = 2 x 2 x 2 x 2 x 3 x 3\nLCM(16, 36) = 144\n\nThe other people might be thinking greatest common factor, but even that answer is wrong since the GCF(16, 36) is 4, not 2.
753025
a.2xy(-15x^2y^4+8x^2-5y^2)/-4xy^3\n(-1/2y^2)(-15x^y^4+8x^2-5y^2)\n\nb.2+160-64\n=98
6182
You can use what is called the Master Product Method to factor this and other quadratic trinomials.\n\nFor something of the form ax^2 + bx + c, the master product is a*c.  In this example, a is 2, b is -5 and c is 2, so the master product is 2*2 = 4.  Now you must find two numbers which multiply to give you the master product of 4, but add to give the middle coefficient of -5.\n\nThis requires a bit of trial and error, but you should be able to quickly discover that the numbers -1 and -4 will work since -1*-4 = 4 and -1+-4 = -5.  Now you rewrite the the entire trinomial replacing the middle term -5x with the equivalent -1x - 4x:\n\n    2x^2 - 5x + 2\n= 2x^2 - 1x - 4x + 2\n\nWe factor by grouping the first pair and last pair together and pulling out what's common to each pair:\n\n= (2x^2 - 1x) + (-4x + 2)\n= x(2x - 1) -2(2x - 1)\n\nNotice that (2x-1) appears in the factorization of both pairs.  We finish by factoring out the (2x-1) to get\n\n= (x - 2)(2x -1)
767501
242*160=38,720 cogs\n38,720/64=605(not divisible\nby 242,160,64 or 22) therefore,\nsame cogs cannot coincide\n38,720/22=1760(not divisible by\n242 or 64) therefore same cogs\ncannot coinside\n\ntherefore,minimum revolutions required\nto get back to original position\n=160\n\ni hope that this helps
1029303
if you are asking for the factors,it is\n(x-15y)*(x+15y)
944629
you need two numbers. you cannot get a Greatest Common factor with one number\n\nClick on the URL below for additional information concerning Greatest common factor.\n\nwww.brainpop.com/math/problemsolving/greatestcommonfactor\n\nwww.math.com/school/subject1/lessons/S1U3L2GL.html
84308
Let's go ahead and make factor trees:\n3y^3 = 3 * y * y * y\nand\n24y^3 = 3 * 2 * 2 * 2 * y * y * y\nWe can now see which factors are common to both terms.\nThey both have a 3, and three y's in common.\nSo, we know that the gcf will be 3 * y * y * y or 3y^3.\nHope this helps :-)