population density x miles from the center of an area is given by p(x)=350,000e^ -0.84x people per sq. mile?
396729
To solve this you need a sum function\nand it the\nSum of i, for x=1 to 2.5 (350,000e^-0.84x)\nNow this is not easily solvable, now I will assume that you have learned integrals, if not this is not going to make sense.  I do not remember the priciple name for what I am about to say, but we can take a finite sum and convert it to a definite integral, and the answer will be the same, so\ntake the definite integral from 1 to 2.5 of 350,000e^-0.84x dx\nThis is (350,000*e^-0.84x)/-0.84 from 1 to 2.5 (see source for how I solved this)\nSo following the rules for definite integrals we get,\np=(350,000*e^(-0.84*2.5)/-0.84)-(350,000*e^(-0.84*1)/-0.84)\n =((350,000*e^-2.1)/-0.84)-(350,000*e^-0.84)/-0.84)\n =(350,000*0.1225/-0.84)-(350,000*0.4317/-0.84)\n =(42859.7499/-0.84)-(151098.6832/-0.84)\n =-51,024-(-179,880)=230,904\nAssuming my math is right, which I now doubt, that's the answer I get, you might want to double check my integration using proper substitution, if you get the same answer turn it in as that
844021
5,984,685 miles² \n5280 ^2  sq ft/sq mi\n12 ^ 2 sq in / sq ft\n\nabout 2.4 * 10^16 sq inches
755101
Well area is equal to Radius squared times 2 pie(or22/7)\nSo you would have 35^2=1225 and then 1225*2*(22/7)=7700 inches for your area\n\nhope that helped
288560
area  155,959 square miles\n\npopulation 35,893,799 2004 estimate
373623
p = number of adults\nc = number of children\n\nthen there are p-c more adults than children
991151
0.001562506 square miles
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area := Πr2\ncircumference := Πd  ,  r=radius, d=diameter, Π=3.14128....
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828 miles.\n\n1x + 1.5x = 1380\n2.5x = 1380\nx = 552 (the second day)\n1.5x = 828 miles (the first day)
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33469 sq ft or a area that measures apprx 577' X 577'.  This math is based on the following information.\n\nTotal sq miles of US soil 3,537,441\n(this equals 98,618,195,174,400 sq feet)\n\nTotal US population as of july 2005 (est)\n 295,734,134\n\nThere - now you can sleep.
930776
I am making the assumpition that the points you are given form the probability density distribution curve p(x) for the random variable.   This means that P(a<x<b) is ∫[a to b)p(x)dx.  In this type of distribution  ∫[-∞ to +∞]p(x)dx = 1\n\nStart by plotting the distribution from the points given.  The probability of a point being within a range is the area under the curve within that range .  Use geometry to compute these areas: break up the figure into rectangles and triangles.  First get the full area, call that A (this should come out 1).  The width of the area you want is the limit of the values given; in case i, that would be the distance from x = 1 to the right-hand limit of the curve at x = 3, or ∆x = 2.\n\nTo show you how, here is the way to get the full curve area A:\n\nRectangle from (0,.3 to (3,.3): Base 3 height .3, area .9\nTriangle from (1,.3) to (1.5,.5) to (2,.3): Base 1, altitude (.5-.3) = .2, area = .5*1*.2 = .1\n\nTotal area = 1 (as it should).\n\nArea for P(x>1) rectangle base 2, height .3, area .6; triangle base 1 altitude .2, area .1, then P(x>1) = .7, the sum of the areas.\n\nFrom a probabiliy distribution, you cannot get the probability of a single value, only a range.\n\nYou will have to interpolate altitudes for points that do not coincide with the ones given.\n\nEDIT: I have made a drawing of the distribution if that will help.  Find it at http://img218.imageshack.us/img218/8930/distributionhg6.png
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for consolidated urban areas with at least urban density of 400 persons per square kilometer (or the nearly identical US defintion = 1,000 per square mile.\n\nNYC metro in the United States.\n3,353 square miles - (8,683 Sq Km)
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The question is a little faulty but I think I know what you meant.\n\nIf d is 30.5, then r is half that, 15.25.  You mean pi which is about 3.14.\n\nIf I use that value of pi, and r is 15.25, then area is pi r squared, or 3.14 x 15.25 x 15.25 which is 730.24625.\n\nUsing a better value of pi, I got 730.61664.
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dP/dt = 0.069762e^(0.011t) * 10^9\n\nSince I think the population should be in billions of people per year.
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Assumptions: \nPopulation = 6 billion\nDisplacement = 2.5 cu ft/person\nRadius of earth = 4000 mi\nWater coverage = 75% of earth surface\n\nSea level rise = [ 6E9*2.5/(4pi4000^2*5280^2) ] *.75 * 12 = \n                          ~42 millionths of  an inch.\n\nGive or take
15711
Total population in 2000\n 1,334,544\n\n453 square miles
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P(X)= 365/365 x 364/365 x 363/365\n    = 1 x 0.997 x 0.994\n    = 0.991
320809
If the population increases by 4% each year, at the end of the year the population will be 104% of the original population at the start of the year.\nSo, the population at the end of the year is 16016, which is 104% of the original.\nSo 100% would be the popluation at the start of the year.\nUsing ratio and algebra:\n16016/104 = x/100\nx = 100*16016/104\nTherefore, x = 15400.\nTherefore the popluation at the start of 2002 was 15400.\nDouble check by doing the question in reverse, now that you have the original popluation.\n\n4% of 15400 = 616\n\n15400 + 616 = 16016\n\nTherefore you can be sure that the original population at the start of the year was 15400.