what is the area of a parallelogram with base 21 cm, side lenght 22 cm, and height 20 cm.?
401461
permitter would be 83 cm\narea would be 415 cmXsq
714329
Area = pi*r^2 = pi*3^2 = 9pi. Thats 28.27 square feet, approx.
551690
T= L + 2B\n\nT is total surface area\nL is Perimeter x Height\nB is base area
53126
area = 1/2 x base x height
884235
Base is the dimension along the bottom of the object.\n\nHowever, your equation only applies to parallelograms.
241144
to calculate the area of a 2-dimensional space you always multiply length x width, or in this case height\n\nC
320776
The area S of a triangle is S = ½bh, where b is the length of any side of the triangle (the base) and h (the altitude) is the perpendicular distance between the base and the vertex not on the base.
189870
answer depends on arrangement.  \n\nSA = area of top + bottom + left side + right + front + back.\nif 1x1x24, SA = 24+24+24+24+1+1 = 98 sq cm, \nif 1x2x12, SA = 24+24+12+12+2+2 = 76 sq cm,\nif 1x3x8, SA = 24+24+8+8+3+3 = 70 sq cm,\nif 1x4x6, SA = 24+24+6+6+4+4 = 68 sq cm,\nif 2x2x6, SA = 12+12+12+12+4+4 = 56 sq cm,\nif 2x3x4, SA = 12+12+8+8+6+6 = 52 sq cm.\n\nnotice how the SA gets smaller as the arrangement becomes more compact.
1057756
lets say length= L\nwidth=W\nperimeter=P=22=2L+2W\nL=W+7\n\n22=2(W+7)+2W\n22=4W+14\n8=4W\n2=W\n9=L
235455
Area = 225 sq. cm = (15)^2\nPerimeter = 4*15 = 60 cm\n\nP*6 = 360 cm = 4x cm\nx = length of side = 90cm\nArea = 90^2 = 8100 sq. cm\n\nArea increased (6)^2 times, or 36 times.\n\n(225 * 36 = 8100)
789377
Pi by diameter\n( 22 / 7 ) X diameter
196800
Surface area. Seriously. 8D
65434
The question is WRONG. If you have length =6 and width =7, P=26 and A=42.
136459
Find the factors of 56 (or all the possible measures of sides that would equal an area of 56). \n2 and 28\n4 and 14\n7 and 8\n\nThen add 2l + 2w to get the perimeters.\n2(2) + 2(28) = 60\n2(4) + 2(14) = 38\n2(7) + 2(8) = 30\n\nSo the least perimeter would be 30 cm.
826650
area =\n\nx^2 + 2x\n\ncost ($) =\n \n( x^2 + 2x ) * 20\n\n_
952353
The curved surface area is 2*pi*r*h\n\nor 2*3.142*27*12 sq cms\n\nand 2*3.142*17*35 sq mms\n\nyou can do the rest
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.