what is structure padding in c programming language?
404314
C compiler allocates memory for a structure variable by \naligning to a word boundary.\nstruct ex\n{\nchar a;\nchar b;\n};\n the structure has only 2 bytes. So the compiler pads with 2 more bytes as a word is 4 bytes\nYou can also make the compiler not to use the padding
966909
I am assuming that all you want is that simple pattern drawn.\n\nFor a predefined size of the triangle LINELIMIT:\n\nint main() {\n  int head = 1. prev; line = 0, col = 0;\n\n  for (line = 0; line < LINELIMIT; line++) {\n    prev = head;\n    for (col = 0; col < line; col++) {\n      printf("%d ", prev);\n      prev *= 2;\n    }\n\n    printf("&#92;n");\n    head *= 2;\n  }\n\n  return 0;\n};
811310
Apart from the obvious:  how can I use functionnalities defined in it, I don't see what you are trying to find out.  \n\nanyway if that is what you need, this is done by placing this line at the top of your  .c file\n\n#include <graphic.h>\n\nOtherwise try to be more explicit about what you need
551498
I'm no "C" expert, but in Delphi this is a Windows system call, and I'm sure it will be a similar implementation in C; just alter the syntax as necessary...
199843
Sliding Window (sliding dictionary)\n\nThis method use a fixed length dictionary size to compress and the dictionary content is changing (FIFO - First In First Out) in cycle as it progressing. The size of the dictionary can be determined at the design time or at the run time (first have to go through source content at least once before determine the best size) that is depend on how the programmer want to achieve to get better result (smaller result size). \n\nEncoding:\nEg: dictionary size is 8 bytes.\nCode: \n(S) = Store as is.\n(Lxxx) = Length (xxx = total bytes).\n(CC) = Compression Code.\n(SPxxx) = Start Position (xxx = start at the position of dictionary
4787
If you can work in C++, there are many set \nimplementations available in the standard template\nlibrary.  However, if you're working in C, you\ncan add functional/useful sets using just a small number\nof bitwise and logical operations.\n\nThe basic idea is that a set will be a bit vector,\nand element "i" will be at position "1<<i".\nFor small sets (say, up to 32 or 64), you can\nhold the sets in a scalar variable.  For larger\nsets, you'd need to create an array of scalars and factor\nthat into the accessing code.\n\nWith no error checking, and just for illustration,\nI've included a trivial example of using "bit vector"\nsets in C:\n\n#include <stdio.h>\n\ntypedef long set_t;\n\n#define clear_set(x)          (x=0)\n#define set_element(e, x)     (x |= (1<<(e)))\n#define is_element(e, x)      ((1<<(e)) & x)\n#define sizeof_set            (sizeof(set_t)*8)\n\nint\nmain()\n{\n    int i;\n    set_t s;\n\n    clear_set(s);\n\n    set_element(5, s);\n    set_element(15, s);\n    set_element(25, s);\n\n    printf("The set consists of [");\n    for (i=0; i<sizeof_set; i++) {\n        if (is_element(i, s)) {\n            printf(" %d", i);\n        }\n    }\n    printf(" ]&#92;n");\n    return 0;\n}\n\nWhen compiled and executed, it demonstrates that\nit correctly created a set with elements 5, 15, and 25.\n\n$ cc set.c\n$ a.out\nThe set consists of [ 5 15 25 ]
966120
try this stuff... pls understand the logic...\n\n#include<stdio.h>\n\nint main()\n{\nint no,rem;\nscanf("%d",&no);\nwhile (no)\n{\nrem = no % 10;\nprintf("%d",rem);\nno = no / 10;\n}\n}
742648
#include<stdio.h>\n#include<conio.h>\nvoid main()\n{\nint n=5,i,j;\nclrscr();\nfor(i=1;i<=2*n-2;i++)\n{\nprintf(" ");\n}\nprintf("1&#92;n");\nfor(i=2;i<=n-1;i++)\n{\nfor(j = 1;j<=(n-i)*2;j++)\nprintf(" ");\nfor(j = i;j<=2*i-1;j++)\n{\nprintf("%d ",j);\n}\nfor(j = 2*i-2;j>=i;j--)\n{\nprintf("%d ",j);\n}\nprintf("&#92;n");\n}\nfor(i = n;i<=2*n-1;i++)\nprintf("%d ",i);\nfor(i = 2*n-2;i>=n;i--)\nprintf("%d ",i);\ngetch();\n}
522101
void RemoveWhiteSpaces(char *string) {\nchar * bch;\nchar newstr[80];\n// Get the first whitespace\nbch = strtok (string,' ');\n\nwhile (*bch != '&#92;0')\n{\n  if(string != ' ') {\n   strcat(newstr,bch);\n  }\n  *bch++;\n}\n\nreturn 0;\n}\n\n\nI guess, I am not gonna give you the hwole answer, maybe I did :) But here it is, hope you the best.. Some stuff need work
117995
There are five data types for C: void, integer, float, double, and char.\n\nvoid: associated with no data type \nint: integer \nfloat :floating-point number \ndouble :double precision floating-point number \nchar: character \n\n\n\nC++ defines two more: bool and wchar_t.\n\nbool: Boolean value, true or false \nwchar_t: wide character
253461
®\nuse ascii:\n\n\n<p>& # 1 7 4 ;</p>\nwithout the spaces
640784
In terms of the kernel itself, I believe it is mostly written in straight C code, with some in C++.  The same with the GNU utilities.\n\nYou can access the kernel source here: http://www.kernel.org/\n\nThe GNU utilities, which makes up most of the rest of what we think of as the "core" of Linux can be found here: http://www.gnu.org/
62287
the source code should be easy to work out and implement in C if you know the algorithm.\n\nfirst use the elementary transformations and equivalence of re and nfa to convert nfa. Then use the std techniques to convert the nfa to dfa.\n\nIf you use dynamically allocated nodes, it shouldn't be too difficult
242005
/*set up a struct like so:*/\n#include <stdlib.h>\n#include <stdio.h>\n\nint main()\n{\n\nstruct person\n{\n  char name[30], address[50];\n  int age,telephone;\n};\n\n/*variable of type persons*/\n struct person details;\n\n/*read*/\n printf("Name:");\n fgets(details.name, 30,stdin);\n\n printf("Address:");\n fgets(details.address,50,stdin);\n\n printf("Age:");\n scanf("%d",&(details.age));\n\n printf("Number:");\nscanf("%d",&(details.telephone));\n\n/*print*/\n printf("&#92;nprinting data");\nprintf("Name: %s",(details.name));\nprintf("Address: %s",(details.address));\nprintf("Age: %d&#92;n",(details.age));\nprintf("Number: %d&#92;n",(details.telephone));\n\nreturn 0;\n}\n\n\n/* subtle things to note, use fgets when someone might include a space in their input, but remember fgets will store the &#92;n character, so keep that in mind when printing it */
260093
Here it is:-\n\n/* Convert.cpp */\n/* Display the reverse of the input */\n/* By Senthil */\n\n#include <iostream.h>\n#include <conio.h>\n#include <string.h>\n\nvoid main()\n{\nchar inp[10];\nint cnt = 0, ex = 0;\nclrscr();\n\ncout<<"Enter some characters (max limit 10) : ";\ncin>>inp;\n\ncnt = strlen(inp);\ncnt--;\nfor(ex = 0;ex != cnt;ex++,cnt--)\n{\ninp[ex] = inp[cnt];\n}\ncout<<"The reverse of the string is : "<<inp;\ngetch();\n}
736284
change the memory module to huge while compile ur code. try simple codes like\n\nint main()\n{\nint *p;\np = (int *) malloc (sizeof(int));\nscanf("%d", &p);\nprintf("%d",*p);\n}\n\nu can find differ, i think...
261764
In C in even does not have to be called "pointer", it can be simply integer, depending of memory model. For example:\n\nint v = 0xCCCC;\n*((int*)v) = 0;\n\nClassical C has not strong type checks; in sais instead:\n\n- Do what you want to do if you know what and how. Everything is on your own.\n\nThat is the reason why C is so-called "low-lewel programming language"