Finding the area of a grazing animal?
401927
In the first part of the question, the goat can graze in the area of half a circle (since it's bounded on one entire side by the fence) with a radius equivalent to the length of the rope.  Since the area of a circle is defined as being equal to pi*r^2, the area of grazing in this instance is half that:\n\nA=1/2*pi*r^2\nA=1/2*3.14* 50ft^2\nA= 3925 square ft\n\nIn the second part the grazing area is increased because the goat is no longer bounded fully by the fence.   The fence would only extend 25 feet to either side of the goat.  Thus the goat could expand it's grazing area another 1/2 circle on either side by wrapping around to the other side of the fence at each of the ends (it's best if you draw a picture for yourself to understand this visually). Each 1/2 circle would have a radius of 25ft (because that would be the freedom of the rope past the end of the fence.  Since there would be 1/2 of a circle for each of the sides (right and left), you can calculate the additional area the goat is allowed to graze using the following:\n\nA= area right half circle (radius 25ft) + area left half circle (radius 25ft)\nA= whole circle with radius 25ft\nA= pi*r^2\nA= 3.14*25ft^2\nA=1962.5 square feet\n\nRemember, this is the additional area the goat can graze with the smaller fence.  To get the total area with the smaller fence, add the additional area to the original area calculated in the first part to yeild:\n\nA= A long fence + A additional\nA= 3925 + 1962.5\nA= 5887.5 square feet\n\nHope this helps.
614012
Grazing.\nForestry.\nCultivation.
220777
use the following formula .. \n\ntotatal surface area = \n[(H/D)*4(pie)(0.5D*0.5D)] + [ (H-t)/(D-2t)*4(pie)*(0.5D-t)(0.5D-t)] + [(pie)(0.5D*0.5D)-(pie)(0.5D-t)(0.5D-t)]\n\nthis is considering D = tank diametere is from outer surface and not the cavity diameter \n\n\nouter surface area of cover = (H/D)*4*(pie)(0.5D*0.5D)\ninner surface area of cover = [(H-t)/(D-2t)*4*(pie)*(0.5D-t)(0.5D-t)] \n\nthe base line are = [(pie)(0.5D*0.5D)-(pie)(0.5D-t)(0.5D-t)]
838437
just divide any calculations made in \nsquare metres by 10,000 and you have\nyour area in hectares\n\ni hope that this helps
742940
The size of a deer track will help you to determine the size of the deer. As a deer grows, their feet will grow accordingly. Big mature bucks will leave big and deep tracks. In soft ground the dew claws will show on both bucks and does. Rounded tips on hoofs are a result of hoof wear usually due to rocky or other abrasive surfaces and has little to do with weather the deer is a buck or a doe. \n\nWhen analyzing deer tracks in shallow snow, look to see which deer are dragging their feet. It is believed that bucks drag their feet to conserve energy. In deeper snow all deer will drag their feet. Another trick for snow tracking is to watch for antler impressions in the snow. When a large buck is checking the trail for a doe in estrus, his horns will sometimes leave an impression in the snow. This will also show you how wide his antler spread is. \n\nOnce you have found a good track in the snow, you can follow it to find travel routes, feeding areas, watering areas and bedding areas. \n\nWhen a deer walks, they will place their back hoof in the track of their front hoof. If the second track falls slightly to the outside of the first, it is probably a doe because a doe's hind quarters are wider than her chest. The wider hind quarters of a doe are required for giving birth. If the second track falls slightly to the inside and short of the first track, then it is probably a buck track since a buck's chest is wider than his hind quarters and his body is longer. \n\nThis article has a helpful chart with it showing prints left by certain deer based on age and sex.
1175962
umm...you probably need to use something called a image map and define areas in it. Check the link below for more details.
910732
If you draw the outer line the goat can travel will have a shape of heart.\nThe largest area is = 5/6 * 3.14 * 45^2 + 2/3 * 3.14*15^2\n=5298.75+471=5769.75 sq.ft.
421910
Go to GoogleEarth.com
10445
So when the cowboys go find the heard of cows they can hear where they are. if they have 1000 acres of land just think how hard that will be finding cows. This way they can find them easier.
378913
Do you mean like an object that has a semi-circle on one end?\n\nIf yes, you can find the area of the semi-circle by figuring the area of the entire circle and dividing by half. Then you just find the area of the rectangular portion and add the two answers.
858344
I am assuming that your sheep pen must be rectangular, guessing from your use of length and width, and you are working with a set perimeter value.  In this case, your pen should be a square of length and width each equal to 1/4 of your total perimeter.  However, if you are free to maintain a pen of any shape, you get the most area per unit perimeter in a circle, of radius = 1/(2pi) times the perimeter.
1179666
The USDA website has a lot of great data that lists the cattle numbers according to the Agricultural census. Every farmer/rancher should know how many cattle they have! You can't manage what you don't measure! Ask the the ranches that make the most profit per animal.
320023
google just type the area in
1104045
Try  searching yahoo:beef cutting and butchering.
296045
Try looking it up on Galileo or EBSCOHost database.
1092038
google earth\n\nterraserver
484019
try aqha.com they might help you