A pair of ski tracks approach a tree, pass around it, then continue down, parallel.  How many explanations?
407401
thanbks .. for giveing me best answer at your questions .. :) do you have an  e-mail ? :)write it at the end of one of your questions :)
72227
Ski poles are usually used as a timing tool when linking turns. They also are good when on a flat surface for both propelling you forward and for stoping or holding on a slight incline where there is no room to turn ie. liftline. If they had no use then racers who have lots at stake would not use them. Also they can help you get leverage to get up after a fall
730795
Here are "drawings" or descriptions of all 11 trees:\n\n_ _ _ _ _ _\n\n_ _ _ _ L\n\n_ _ _ L _\n\n_ L _ L\n\n_ _ L L\n\nX _ _\n\n_ X _\n\nY  (where each of the three spokes consists of 2 edges)\n\n X.L\n\nA star with 5 spokes: one spoke consists of 2 edges:\n\n1-2 1-3 1-4 1-5 1-6 6-7\n\nA start with 6 spokes:\n\n1-2 1-3 1-4 1-5 1-6 1-7\n\nStart with the one tree with 0 edges. After drawing all the trees with n edges, add an extra edge to get all the trees with n+1 edges, removing any duplicates ("isomorphic" trees).
550744
If I'm reading your description right, I think your first boat is heading up and to the right ("direction N.68 degrees E") making an angle of 68 degrees with north, or 22 degrees with east.  And I think your second boat is headed directly east ("S.90 degrees E").  So I'm assuming that they form a triangle, with one angle being 22 degrees and another one being a 90 degree angle, since we're looking for the point where one boat will be directly south of the other.\n\nThe first boat traveled 12t miles so far.  The second boat left an hour later and traveled 16(t-1) miles.\n\nThe first boat's path turns out to be the hypotenuse of the triangle, and the second boat's path will be one of the adjacent legs to the 22 degree angle.  So we can set up an equation with trig identities:\n\ncos 22 = 16(t-1)/12t\n0.9272 = 4(t-1)/3t\n2.7816t = 4t - 4\n4 = 1.2184t\nt = 3.3 hours\n\nSo after 3.3 hours, one boat will be directly south of the other.\n\nFinding that distance can be done one of several ways: using the Pythagorean theorem, sine relationships, law of cosines, etc.  I'll use sine, since we're already doing trig.  After 3.3 hours, the northernmost boat will have traveled 39.6 miles.  The distance between the boats becomes our side opposite the 22 degree angle.  So,\n\nsin 22 = distance between/39.6\ndistance = 39.6sin 22\n= 14.83 miles\n\nNow if I read the angle wrong, then simply go back and change all the "22" angles to the correct one and recalculate.
796966
Marble 1 will stop dead, marble 2 and marble 3 will move off at 7.7.5 m/s 45 degree to the right and to the left.  If you could see their trails painted up in light, it would make a capital letter Y but with that upper portion being at a right angle.
161975
Stem Christie\nIs a Turn that is completed by skidding on both uphill edges. As the Turn is made, the downhill Ski is positioned parallel to the other Ski. Doing so will make both of your Skis parallel and point in the same direction after making the Turn. \n\nThe Stem Christie Turn got its name from Christiana, the former name of Oslo in Norway.\n\nIt is for more experienced skiiers rather than newbies.
937301
time when the car hit the pile of snow from 4 m\nt=√(2d/g)\nt=√(2*4/9.8)\nt= .903 sec\n\nx=vt\n12m=v(.903s)\nv= 13.28 m/s
886229
a average 400 meter track. so 1/2 the track is a 200 meters. usually starts at bend and ends in a straight way
426
i found myself picking up snowboarding faster than skiing. by picking up, i mean i felt ready to take on the more intermmediate/advanced runs after a day or two of the bunny slopes. one board and 2 turns (backside and frontside) was a lot less to deal with than 2 poles and 2 skis and limbs flailing around in different directions. moguls are harder on a snowboard and more fun on skis. flatter runs are more frustrating on a snowboard. getting off the ski lift seems easier on skis
202200
There is geometry involved in the patterns of the skates on the ice.  Physics involves math...the amount of friction and motion over the ice.
24594
Here's a quasi-logical answer:\nBy definition, two lines are parallel if they have the same slope (s1=s2) and they are perpendicular if the product of their slopes is -1 (s1*s2=-1)\n\nSo we have s1=s2 and s1*s2=-1\nTherefore s1^2=-1, so s1=s2=i=sqrt(-1)\nIn conclusion, any two lines y=ix+a and y=ix+b are both parallel and perpendicular at the same time.
941588
Identify the slope of each line and compare the values.\nIf the slopes are the same then they are parallel.\nIf the slopes give a value of -1 when multiplied together, then they are perpendicular.\nIf the slopes differ from that about, then they are neither.\n\nBring the y value to a unit value of one.\n(1) Slope 6∙4 and 6∙4, so it's parallel.\n(2) Slope ½ and ? , second equation is unclear.\nThe slopes are probably 3/2 and -3/2, if so, then they are perpendicular.\n(3) Slope -1/3 and 1/3, so the lines are perpendicular.
765877
I dont know if you'll get many answers in this forum... this is Winter Sports :)
952598
On the trunks of trees.  They stick out horizontally from the side of the trunk.
449007
It's not a gimmick, it's an illusion , the same as the mtatlic hill, you're going down but it looks lie uoi are going backwards,something to do with physics, ask the physic' pro's for the deep, lengthy answer, they're good!
98077
It's a ski style where the skis are like downhill skis, but the heel is detached like a cross country ski. \nThe technique is to go downhill but in a "telemark" position which is bending both knees and one foot is in front of the other... a bit like when those "flying" skiers land...\nSo the do slalom but instead of keeping both legs together they always use this position....\nNot to try in a very steep hill....
176743
The apple doesn't fall far from the tree\nhehehehe