How do I transform variation into variation rate?
413275
The variation rate is not a percentage, but the variation over time. You can express the variation as a percentage: Value 2 - Value 1 divided by Value 1 gives you the percentage increase. It can be used as the rate of growth between the dates of V1 and V2 only, and only if you know the time interval.
458036
If I understand your question correctly, this should help:\n\nTotal Variance = (Actual Quantity x Actual Rate) - (Budgeted Quantity x Budgeted Rate)\n\nIf you get a positive number, the variance is unfavorable and if you get a negative number, the variance is favorable.  \n\nHope this helps!
1180637
I was answering another similar question, and I came across a website that has a downloadable sample spreadsheet for doing statistical distributions.  Play with this and see if it helps you out.
532639
I believe in a generalized fashion the equation for flow rate is:\n\nFlowrate = K*(cv)*((p)^.5)\n\nK = a variable to adjust for various fluids
729738
rate of change=dy/dx=slope
839113
rate of change of demand or supply
52711
shift or change\nfixed or immobile\nvector
617956
http://1accordion.net/tuning.html
1156399
This is a good question even for a statistician.\nThe problem is your set is small and I do not know what the deviation between samples is, however the repeatability and reproducibility information can bind the window \nthrough which the third value will fall through or perhaps even remain in.  \n\nLet me know.
61488
Change the pattern of the shot from wide to tight
902244
Since it is a direct variation we can use the formula\n\ny = k x\n\nSince we are given the ordered pair (2,4) we know y=4 when x=2. Plugging these values into the formula gives us\n\n4 = k(2)\n\nTo solve for k we divide both sides by 2 which gives us\n\nk = 2.\n\nIt would also be correct to set up the variation to be\n\nx = k y\n\nIn this case, we do the same procedures to find k. Plug in the known values for x and y to get that k = 1/2. Unless you are told which one to solve for either are correct. If you are given a multiple choice test I would think that only one could be a possible answer, unless you are first given the variation equation.
697514
Faster more efficient reproduction - no suurprises
928594
If you assume it's normal, then yeah, although I assume there is more data than you have given as you do not have the variance there, although you could treat this as a binomial distribution giving it mean 0.3, variance n0.3*0.7, although when calculating the confience interval you'll want to divide by n^2 for that variance.
861788
There is no accurate way to do this because too many variables are involved. You can do like I do though and run a series of tests and then average them.\n\nhttp://www.toast.net/
785620
You'll find the correct answer in www.onlineconversion.com.  Save it in your Favorites :)
1084985
The best I've found is a free converter - \nhttp://joshmadison.net/software/
695069
It's been a long time for me, but I'll give a shot at interpreting that wiki page for you.\n\nNatural process variation is a measurement of how much some measurable value varies during a process such as manufacturing.  It's not enough to just measure the average, because the average may be right on target, but the individual values may wander all over the place around that average ... and this may be unacceptable.  \n\nSo we need to measure how much this wanders.  Instead of the average, we measure the standard deviation (sigma), which I'm sure you are studying somewhere.\n\nWhile this is a concept from (SPC) statistical process control (like manufacturing), I've not seen it applied to biology.  (I hope it's not an accident that you posted this in the biology section ... when asking questions like this, you might want to give more background about what class you are taking, and how this came up.)   \n\nBut I can see an application to this to studying the basic concept of "variation" in biology, which is the fuel for evolution.  For example, we could measure the standard deviation for some trait like forearm length, or the beak lengths in a species of finch.