how can i calculate sqrt?
410829
The commonly taught method for computing square roots with pencil and paper can be found in the Wikipedia article, "Methods of computing square roots".\n\nScroll down to the heading "An exact long-division-like algorithm".
241586
Hello !\n\nA good question.\nSomething like:\n( round((sqrt(9!)) / 9 )  ) x (9/9)\n\n\n© ßogdan @ CyE CORP.
107783
sqrt(pi) ~= \n1.77245385090551602729\n8167483341145182797549\n4561223871282138077898\n5291128459103218137495\n0656738544665416226823\n6242825706662361528657\n2442260252509370960278\n7068462037698653105122\n8499251730289508262289\n3209537926796280017463\n9015351479720516700190\n1852340185854469744949\n1264031392177552590621\n6405419332500906398407\n6137334774751534336679\n8978936585183640879545\n1165161738760059067393\n4317913328098548462481\n8490205465485219561325\n1561647467515042738761\n0561079961271072100603\n7204448367236529661370\n8094323498831668424213\n8457096\n\nEnjoy!
833533
Go for calculator.\npress  number (z), press x^y, press 5 \nthen press x^y then press 0.3\ngotcha, u will get the answer
577034
Since the radius is 44, you could go either 44 units left, right, up or down from the center and find a point on the circle itself.  So (44,0) would be one such point.  However, these points are not in a quadrant; they are on an axis.  All the other points would fit in the circle's equation, x^2 + y^2 = 44^2.  So pick a number for the x-coordinate, square it, subtract this from 44 squared, then do the square root.  That gives you the y-coordinate.
105888
square root(pi) = 1.77245385
832512
either square root or erauqs
593752
log ( sqrt (x+ 1) *x^5)
959978
use pythagorean thereom a^2 + b^2 = c^2. (c being teh longest side or the hypotenuse) the two legs are a and b. so you have the sq rt of 169. (sqrt of 12^2 + 5^2) which is 13
138197
Using what tool?\n\nInternet access?  Use Google Calculator -- see http://www.google.com/features.html#calculator\n\nPencil and paper?  Try iterations of Newton's method.\n\nCalculator?  Get a rough estimate by hitting the sqrt key ten times, subtract one, divide by ten, add one, then hit the "x squared" key ten times.\n\nLog tables?  Look up the logarithm, divide by ten, find antilogarithm.\n\nCalculator with x^y button?  Raise to the 0.1 power.\n\nCalculator with e^x and ln buttons?  Take ln, divide by ten, take e^x.\n\nC compiler?  Include <math.h> and use the pow function.\n\nJava?  Use Math.pow.\n\nFORTRAN or Perl?  Use x ** 0.1.
978895
Can you use a square root symbol?  If so, sqrt(9) + 9 - 9
924905
Ah, the art of calculus, ive been a teacher for 23 years and ive seen questions related to this many of times. Its actually very easy. Take -598 divide it by -236 then press tan on your calculator. Then graph it with the points 6, -5 and you should get Y= -4584 + X then get X by its self and u get 4584 and put it to the 5th degree. Then square it. You should get the point -3.
1147786
x - sqrt(x) = 0\nx = sqrt(x)\nx^2 = x\nx(x-1) = 0\nx = 0,1\n\nBoth check.
807922
Here is how to do it:\n\nsqrt 500\nsqrt 100*5\n10 sqrt 5\n\nTherefore, you are correct.
203508
Two.\n\nYou can rewrite it as x^2 = 15 or x = sqrt(15)\n\nx solves to (rounded) 3.87 or -3.87
353701
sqrt(a^2 + b^2) = a + b\nSquare each side.\n[sqrt(a^2 + b^2)]^2 = (a+b)^2\na^2 + b^2 = a^2 + 2ab + b^2\nSubtract a^2 and b^2 from each side\n0 = 2ab  \nDivide both sides by 2\n0 = ab\nEither a = 0 or b = 0 or both equal 0.\nAnswer: a=0 and b > 0, or a > 0 and b=0, or a=0 and b=0\na or b can never be negative(even it one of them is zero).\n\nIn general, the equation \nsqrt(a^2 + b^2) = a + b \nis false.  However, it is true for certain values of a and b.
1157812
There is a method called the binary search method that will find the \nsquare root of any number N.  You'll need a calculator to do this \nmethod.\n\nThe first step is to pick a value you know to be too small the be the\nsquare root of Pi.  Call this value S (for small guess).  The next\nstep is to pick a value you know to be too large to be the square root\nof Pi.  Call this value L (for large value).\n\nThen since Pi = 3.14159.... we'll say S = 1, and L = 2.\n\nS = 1\nL = 2\n\nThen find S^2 and L^2 (S and L squared):\n\nS^2 = 1\nL^2 = 4\n\nWhich of these values is farther away from Pi? S^2 is farther away \nfrom Pi then L^2, so replace S with the average of S and L.  Now we \nhave:\n\nS = 1.5\nL = 2\n\nContinue the process:\n\nS^2 = 2.25\nL^2 = 4\n\nReplace the small value again since its square is farther away.\n\nS = 1.75\nL = 2\n\nGoes to:\n\nS^2 = 3.0625\nL^2 = 4\n\nReplace the large value now:\n\nS = 1.75\nL = 1.875\n\nGoes to:\n\nS^2 = 3.0625\nL^2 = 3.515625\n\nReplace the large value again:\n\nS = 1.75\nL = 1.8125\n\nGoes to:\n\nS^2 = 3.0625\nL^2 = 3.28515625\n\nAt which point we know to replace the large value again since its \nsquare is farther away then the small value's square.\n\nSo\n\nS = 1.75\nL = 1.78125\n\nAt this point we know the square root of Pi lies between 1.75 and \n1.78125. Continuing this process we can get finer and finer bounds for \nthe value of the sqaure root of Pi.  After a while we will see that \nthe square root of Pi equals 1.77245....  Since Pi is irrational we \ncan never get an exact answer and we have to settle for an \napproximation.\n\nHope this helps.\n\n-Doctor Steven,  The Math Forum\n Check out our web site!  http://mathforum.org/dr.math/   \n    \n\nI hope this helps you a little sorry if it does not!