Solve the equation: 6(x+4) - (6x +24 = 0?
414064
6(x+4)-(6x+24)=0\n\n6x+24-6x-24=0\n\n0=0\n\nso the equation actually doesn't depend on the value of x.\nzero is always zero for whatever x you put in equation\n\nthe answer: all real numbers
293335
8+9+6+(1+2+3+4+5+7)^0 = 24\n\nX^(0) = 1
1060834
(5x+2)/3 -(2x+4)/6 = -4/3\n\nMultiply everything by 6:\n\n10x + 4 - (2x+4) = -8\n10x + 4 - 2x - 4 = -8\n8x = -8\nx = -1
13640
24X^4-10X^3-1062X^2+3190X+1124=0
338536
3(6) + 7 = 24\n18 + 7 = 24\n\n25 = 24\n\nNo.
929178
4(-2)² + 8(-2) + 3(-2) + 6\n= 4(4) - 16 - 6 + 6\n= 16 - 16 + 6 - 6 = 0
611607
Usually these types of problems would have -4x where you have -4.  Assuming that's the case...\n\nMultiply the top row by 4.  That comes out 4x + 12y = 68\n\nAdd this to the bottom row.  That is 0x + 14y = 84\n\nor just 14y = 84\n\nDivide both sides by 14 and get y = 6\n\nPlug this in to either equation to get x:\nx + 3(6) = 17\nx + 18 = 17\nx = -1\n\nCheck in other equation: -4(-1) + 2(6) = 16\n4 + 12 = 16 check\n\nHope that helps
139064
i think i know how to do it, one minute...\nhey is it 7k-14/(2k-6)(k-4) -6K+18/(2K-6)(K-4) = K+4/(2K-6)(K-4)\nor (7k-14)/(2k-6)(k-4) -(6K+18)/(2K-6)(K-4) = (K+4)/(2K-6)(K-4)\ni added parenthesses\n\n>>>ok so that's what you need to do:\nlet's say (2k-6)(k+4) = X\nso you get:\n7k -14/X -6k +18/X = k +4/X\n7k -6k -k = 4/X +14/X +18/X\n0k = 0X\n0 = 0*(2k-6)(k-4)\n=> every k will give us a legal equation!\n\ni really hope it's true, have u got the answer?
784568
18-6x= -8x+4\n14-6x= -8x\n14= -2x\nx= -7
781242
No,\n\n6-x=24\n6-x-6=24-6\n-x = 18\n\nx= -18
275027
Solve for y in the first equation and then substitute into the second equation.\n4x + 2y = 0  Subtract 4x from each side\n2y = -4x  Divide both sides by 2\ny = -2x\nSubstitute -2x for y in the equation 6x + 3y = 0\n6x + 3(-2x) = 0\n6x - 6x = 0\n0 = 0\nThis means there are infinitely many solutions of the form (x,y) where x is any real number and y = -2x.\nTherefore, the answer is\n(x,-2x), where x is any real number.
290738
12x+3-26=6x+1\n\n=> 6x-24=0 => x = 4
898616
abc(-24a^2b+43c)/6abc\n=(1/6)(-24a^2b+43c)
774101
6+4x=3x+2\n4x-3x=2-6\n1x=-4\nx= -4
786009
-2(x-3) + 4(x+7)\n-2x+6   +4x+28\n2x+34
754366
You need to use the quadratic equation as it is not factorable into rational expressions.\nThe form of the equation is:\nax^2 + bx + c = 0 \nSo in your case,\na = -2, b = 6, c = -3\nand the solution is:\nx = [ -b ± √(b^2 - 4ac) ] / (2a)\n\nso substitute and reduce.\n\nx = [ -6 ± √(6^2 - 4(-2)(-3)) ] / (2(-2))\n\nx = [ -6 ± √(36 - 24) ] / (-4)\n\n= [ -6 ± √12 ] / (-4)\n= [ -6 ± 2√3 ] / (-4) \n= (3 ± √3)/2
845742
-2(x+1) + 4 = 6(x-2) + 8\n-2x - 2 + 4 = 6x - 12 + 8\n-2x + 2 = 6x - 4\n-2x = 6x -4 -2\n-2x = 6x - 6\n-2x -6x = -6\n-8x = -6\n8x = 6 (The minus signs cancel each other out)\nx = 6/8\nx = 3/4