How many ballons can pepl fit in their stomach wen the balloon is full?
397559
It depends how many drugs you are trying to sneak into prison
810702
An idea would be, "Which gas could you fill a volleyball up with that would make it go better?" They you can have regular air, carbon dioxide, and helium. Then you make a hypothesis based on what you know, try one of them, and see if you were wrong.
180187
Nope. You couldn't fill anything. The balloon would just be empty. But why would you use a "hand pump" in space?
739747
p1v1=np2v2\nv2 = 4/3 pi 0.15^3 = 0.014137\nn----> no. of balloons\nputting values we get n = 679.03 so approx 679 balloons.\nhope this helps
801554
Assume spherical approximation for balloon:\n\nVolume of weather balloon at time, t is:\n\nV(t) = 4/3 pi r(t)^3\n\n(1).....dV(t)/dt = 4 pi r(t)^2 x dr(t)/dt  (chain rule)\n\nlet t be in minutes\n\nr(t)= .04t m,  that is (500/1000)*0.08*t m\n\nd r(t)/dt = .04m/min\n\nSo when r(t) = 90cm = .9m, we have from (1)\n\nd V(t)/dt = 4 pi (0.9)^2 x .04 m^3/min\n\n=0.4072 m^3/min
410065
Where are you going in that balloon?lol
536322
a tv program showed that approximately 2600 balloons filled with helium is needed to lift 20 kg child a few centimeters of the ground. (if i remember right, of course)
53886
Since the air inside the balloon is heated, the molucules are more active and therefore spread out. The weight of the air inside the ballon is less than the weight of the air that the ballon displaces.
804421
The higher the balloon goes in the atmosphere the less pressure on the balloon. This causes the helium to expand its volume. If the balloon was filled to capacity it would *pop* at higher altitudes.
173870
1.Since Volume is proportional to Temperature, it could also be written with a constant(k): V = k x T , V/T = k , k = 0.923L/ (25+273)K = 3.10x10^-3 L/K\n2.I'm not too sure about this one, but here is my best shot.\nUsing the ideal gas law PV=nRT, same Temp & Pressure, let Va be the volume of the first baloon and Vb be the volume of the second balloon. Va = 1.25Vb, Let na be the number of moles in baloon 'a' and nb be the number of moles in balloon 'b'.\n\nBalloon a: PVa = naRT\nBalloon b: PVb = nbRT\nsolve for P,T or R.\nThis case I solved for T:\nT = PVa/naR  & T = PVb/nbR, since same temp (or pressure or constant) which is PVa/naR = PVb/nbR. Divide by P & R, Va/na = Vb/nb\nVa x nb = Vb x na, Va = 1.25 Vb, @75%\n1.25(.75)Vb nb = 0.75Vb x na, divide by .75Vb\n1.25nb = na\nSo there is 25% more moles (or mass) in baloon A.
130096
aRjuN, you are wrong, because balls are round, spherical, and they leave space between them, that can't be occupied.\n\nThis problem is so hard, you almost can't solve it. It takes maybe millions of calculations to find the best way to put the balls inside a container, in order to fit as many balls as it could.
803330
i got the same answer \nusing the equation PV / RT = n, i found the number of moles of the tank, which is 264.  Then using the same equation find the balloon, which i got was .138 moles.  Then divide and i got 1.91*10^3 balloons
991569
Yes this is an important topic.\nthe amount is tiny really.\nwhy not try to blow up a balloon and never burst it then all th gas will be traped and not effect the environment\nx x x
116245
I am making the assumption that the balloon is inflated with helium.  The molecules of helium contract when they are cold and expand when they are hot.  So if you put the balloon in the refrigerator or outside on a winter day, it will become smaller.  Once you put the balloon back into a warm environment, it will expand back to it's original size.
363341
4 8 15 16 23 mega ball 42
831625
attache one's self to a bunch of helium ballons and see how high one can go.
93903
I would have two large, EXTREMELY LARGE balls attached with a rather large string or steel cable or whathaveya. I would throw one ball in space and BAM it goes on forever!\n\n~or two quote someone, until it hits something.