What happens at the precise time the "unstoppable force" meets the "unmovable object"?
396138
a=F/m, lim x->inf x/x = 1. The object will accelerate.
39271
IT will happen in time.
885382
Short answer: The ball will touch because space can only be divided into bits of a certain small size and no smaller.\n\nMore Detail:\n\n"Is there a point where there is no such thing as half? (The ball is so close to the surface that to drop it another half-way would be impossible because it has to touch eventually.)"\n\nYou guessed right, space is not continuously divisible, you cannot keep going 1/2 way between one point and another point in space indefinitely.  Space is "quantized", or, comes in little chunks which are only so small and never smaller.  "Loop quantum gravity, string theory, and black hole thermodynamics all predict a quantized space-time with agreement on the order of magnitude."1. So, in our discretized(not infinitely divisible) space-time, you would run out of half-ways and the ball and surface would touch.  A second reason, in reality, that the ball and surface would touch is that things do not need to infinitely close (have 0 distance between them) to be "touching" (I explain this a little later).\n\nAlternatively, if you wish to consider this problem in a "general relativity" like universe, where space-time is a smooth and infinitely divisible continuum, then the answer to your question lies in considering what is happening when things "touch".\n\nEveryday matter is made of atoms with a nucleus in the middle and electrons which zip around the nucleus, surrounding it.  The outer physical boundary of something like a book or your hand or a ball is occupied mostly by electrons.  Electrons repel each other because they are of the same electric charge.  So when two objects come very close together, their outer boundaries will repel each other.  When you put a ball on a table or grab a coffee cup you and it are not really quite touching in that your matter is in direct contact, you are very nearly touching, but not quite, because you are both sheilded from each other by your outer layer of electrons.\n\nIf space-time were an infinitely divisible continuum with no such "smallest chunk" of space then you would eventually get close enough that the ball and surface would be "touching" just as much as things ever do touch.  The distance between things does not get to 0 when they touch, it's just very small, but not infinitely small.\n\nIf you wish to consider this problem in a further way, similar to the way you may have been considering it originally, then let us ignore our best physical evidence and the theories built from them and say that space-time is infinitely divisible; there is no such thing as a "smallest bit" of space.  Let us also assume, contrary to reality, that physical objects have static (unchanging and exactly defined in space) outer boundaries, such as a mathematical geometric shape might.\n\nIf this is the case, then your question was answered by Xeno in "Xeno's Paradox".\n\nyour question was considered by Xeno in a famous problem known as Xeno's 'Achilles and the Tortoise' Paradox, which can be rephrased:\n\n"Zeno's Paradox may be rephrased as follows. Suppose I wish to cross the room. First, of course, I must cover half the distance. Then, I must cover half the remaining distance. Then, I must cover half the remaining distance. Then I must cover half the remaining distance . . . and so on forever. The consequence is that I can never get to the other side of the room."2\n\nSo we have the idea that you can never get somewhere because no matter how close you get there is another bit of ground left to cover that is 1/2 as long as the one you covered since you last checked.  Remember, it is important that we are working with the assumption that we have been able to take infinite little hops at the end of this room crossing.\n\nLet's assume that we are correct in saying that taking an infinite number of hops, each 1/2 as long as the last, will never get us to th
993555
In a vacuum, both objects will land at the same time.
1013406
When one end of the unbreakable cable felt a tug, the force would be transfered along the cable to the satelite. When the cable is close enough the a blackhole, the acceleration at one end would cause the cable to break.. despite unbreakable. This is because the force cannot be transmitted fast enough along the cable... one end would be moving so fast while the other end barely felt the force yet and hence has not started moving.\n\nBlackhole is a very dense matter. So, it's straightforward to think that after the whole string is "in" the blackhole, they are condensed into very very dense form. However, is this so? Nobody can tell as known physical laws cannot be extended into this singularity in spacetime.\n\nIt might be a lame answer but I have to say it. The above situation cannot arise because there simply can be no unbreakable cable. Just like in QM... what if I know the velocity and position of an electron exactly. It's interesting to know what will happen, but QM tells us, u cannot know it. So, even though it is interesting to know it, it's beyond the domain of our universe. Yes, if it exist, it'll break the laws of logics in our universe..... but that's exactly why it does not exist..... because logic is consistent. Logic itself prevent such situation from arising. Know what I mean?\n\nAnyway, even if the cable is unbreakable... what about the part of the satellite it is tied to? Let's just imagine the cable and the satellite are unbreakable, then the blackhole would simply stretch the cable infinitely long without breaking it... allowing time for the force to "flow" thru the whole cable to accelerate the satellite. Is it reasonable to think of sth that can be stretch infinitely but would not break? Or u can set another rule that the cable cannot be stretched at all. This would then violate the rule of special relativity, that nothing can travel faster than the speed of light, as the force would be transfered to the satellite instantaneously.
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opposite force being applied
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Chuck Norris; it's the unstoppable force vs. the unmoveable object.
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Hi!  You are right.\nIf they have equal masses and are elastic then  b) it is going to happen. Why? well Vf= 2*Vcm-Vi. Where all are vectors and :\nVf= final speed;   Vcm=center of mass speed ;  Vi=initial speed.\nThus 0=2*Vcm-Vi => Vcm=V/2=(m1V1+m2V2)/(m1+m2)=\n=m1*Vi/(m1+m2)  => m1=m2.    \n  " a)" isn't possible because the total momentum must be preserved.\n          Hope it helps!
83052
Forces occur in pairs. Newtons third law.\nIf this is the case the forces exist as equal and opposite.\n [Fo ]=[-Fi]\nNet force = Fo minus Fi= zero!\n  Moving forces can be directional and vectorial.\nAlso they change continueously during the motion till they Atenuate at the end of their cycle.To identify the force you have to identify the power that has cause the motion of the mass and the direction of interaction. The power causing the motion is always equal to the magnetude of the force multiplied by the the speed that the force moves.\n\nCurvilenear motion indicates that the power of two moving masses interact and cause the two masses to move around a common pivot point. Thus the masses are locked together into an orbit forming a composite mass structure.In that case the moving masses experience a curved path.\nThan you have to understand what is  a circle. A circle consists of an infinite integral of short straight lines, and each straight line having different direction.\n\nDont feel bad if you cant fully understand why. . I dont find it easy myself.
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There cant be an unstoppable force or an immovable objet in nature, so their collision can only be imaginary.\neven if it happens one of them has to behave abnormally!!\nSo Either the force will be stopped or the object will move, either ways there will be deviation from nature!!\n\nIt is like asking is infinity < infinity +1 !!\nThink about it!!
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Finite but unbounded.
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as the table is frictionless a constant force will take it to infinity...... it will never stop....
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For every action there is an equal and opposite reaction.\n\nThe smaller object gets busted, as is your question.
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assume that just for 1 second gravity goes off and comes back, what will happen??? is it possible??? no funky answers please. genuine replies are appreciated.
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simple. 'every action has an equal and opposite reaction' remember that one? the unstoppable force will do a 180 degree turn and apply itself in the other direction.
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The answer has to be A.\nThe time will be the same because Gravitational force does not depend on the mass of the object, since they start with same velocities and accelerate with the same rate they must hit the ground at the same time.\n\nAnd it obviously has to be the same distance because if it wasn't then they would never hit the ground at the same time in the first place. That would happen because if 2 bodies start with the same speed and have the same acceleration but different displacements then their time has to be different.
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There is no such thing as an unbalanced force in physics because of Newton's Third Law: for every action, there is an equal and opposite reaction. So for every force that exists, there has to be an opposing force that balances it out.