If U have two coins that equal .30 cents, & one of them is not a nickel... what  coins do u have?
408806
A quarter ( not a nickel ) and a nickel
96391
Maximize the nickels (since they have the smallest value, it takes the most of them to make up the value you want) and use 1 each of nickels and dimes.\n\neg. $1.00 = .25 + .10 + .65\n         1 quarter, 1 dime, 13 nickels\n\n\n$15,348.30= .25 + .10 + 15,347.95\n         1 quarter, 1 dime, 306,959 nickels :)\n\nOr, for a formula, subtract $0.35 (the value of 1 quarter and 1 nickel) from the amount, then divide by $0.05.  This is the number of nickels you need, add 2 to get the total number of coins.
121136
need 1 more coin to show heads...\n\n4 possibilities. \n-Both coins have heads (25%)\n-1st coin has a head (25%)\n-2nd coin has a head (25%)\n- both coin has a tail (25%)\n\nadd em up.. 50%
1105093
A nickle and a quarter, you said one of them is not a nickle true statement because one of them is a quarter.
905802
Equivalent sets for 35 cents might be 7 nickels OR 3 dimes and 1 nickel.\n\nfor $6.92 might be 27 quarters, 1 dime, and 7 pennies\n\nand of course the possibilities are many for each
977563
You need to give us a problem, but let's say the problem was:\n\nYou have ten coins (dimes or nickels) and they add up to 65 cents...\n\nYou could guess that you have 5 dimes and 5 nickels:\nGuess:\n5 dimes, 5 nickels\nCheck\n75 cents <-- too high\n\nSo try guessing 4 dimes and 6 nickels:\nGuess:\n4 dimes, 6 nickels\nCheck:\n70 cents <-- still too high\n\nFinally try guessing 3 dimes and 7 nickels:\nGuess:\n3 dimes, 7 nickels:\nCheck\n65 cents <-- correct answer.
113666
You can type in a good description of the coin, it's likely that someone out there has another one just like it.  Otherwise, take it to a coin shop.
199752
1 cent is the value of 1 penny.\n1 dollar is the value of 1 dollar.\n\n1 penny = 1 cent = 0.01 dollars\n1 nickel = 5 cents = 0.05 dollars\n1 dime = 10 cents = 0.10 dollars\n1 quarter = 25 cents = 0.25 dollars\n\nThere are a couple more rare or obscure coins such as the 50 cent piece (not made anymore), and the dollar coin (many unpopular and thus little used versions of this).
809813
Seen this riddle at least 2 times already... getting old.... \n\nanswer is the other coin is the nickle and the first one is a quarter...
123028
13 nickels\n5 pennies\n3 dimes
927660
Hi, \n\nThey way to do this problem is to be careful in the way you set up your equations. \n\nD= dimes\nQ= Quarters\nN = Nickels\n\nSince there are twice as many dimes as quarters, you'd have to multiply the number of quarters by 2 to get it to equal the number of dimes. \n\n2Q = D \n\nSimilarly, if there are two more nickels than quarters, you'd have to add 2 to the number of quarters to get the number of Nickels\n\nQ + 2 = N\n\nNow, The total value (the number of each coin times the value of the coin.) is $7.60\n\n(0.25)Q + (0.1)D + (0.05)N = $7.60\n\nNow you have three equations with three unknowns. Now all you have to do is isolate variables, and substitute. \n\nHope that helps, \nMatt
957112
The answer was A..       dime, nickel and quarter or something like that.
874004
Start with no pennies:\n1 quarter\n2 dimes, 1 nickel\n1 dime, 3 nickels\n5 nickels\n\nNow try 5 pennies:\n2 dimes, 5 pennies\n1 dimes, 2 nickels, 5 pennies\n4 nickels, 5 pennies\n\nNow try 10 pennies\n1 dime, 1 nickel, 10 pennies\n3 nickels, 10 pennies\n\nThen 15 pennies\n1 dime, 15 pennies\n2 nickels, 15 pennies\n\nAnd 20 pennies:\n1 nickel, 20 pennies\n\nFinally:\n25 pennies
880748
Because the other coin is. You have two coins and logically speaking, one is not a dime but the other is
876730
A quarter and a nickel.\n\nONE of them is not a nickel...its a quarter!
656748
1 cent.\n\nOBTW US coinage does not include "pennies".  They are "cents".
766627
The only combinations that add up to 50 cents or more are:\n6 dimes\n5 dimes, 1 nickel\n5 dimes, 1 penny\n4 dimes, 2 nickels\n\n6 dimes:\nThere are C(12, 6) ways to pick six coins = 924.  Only one of these combinations is 6 dimes = 1 way.\n\n5 dimes, 1 nickel\nThere are C(6,5) ways to pick the dimes and C(4,1) ways to pick the nickel.  6 * 4 = 24 ways.\n\n5 dimes, 1 penny\nThere are C(6,5) ways to pick the dimes and C(2,1) ways to pick the penny.  6 * 2 = 12 ways.\n\n4 dimes, 2 nickels\nThere are C(6,4) ways to pick the dimes and C(4,2) ways to pick the nickels.  15 * 6 = 90 ways.\n\nThat's 1 + 24 + 12 + 90 combinations (127)\n\nAll told you have a chance of 127/924 or approximately 13.74%