What the location point of Bermunda Triangle in latitude and longitude?
405983
Back in the 1970s, before "The X-Files" made alien rectal probes the preferred departure point from consensus reality, there was the Bermuda Triangle.\n\nThe Bermuda Triangle (aka the Devil's Triangle) is a three-sided zone in the Atlantic Ocean stretching approximately from Miami, Fla., to Bermuda to San Juan, Puerto Rico.\n\nPlanes, boats and people go in to the Bermuda Triangle, and some of them don't go out. This in itself is not particularly remarkable. There are many places in the world which have the ethereal and mystical quality known in scientific circles as "being very dangerous."\n\nNo, the Triangle's claim to fame is pretty much centered around the particular penchant for the aforementioned boats and planes to disappear without a trace. No wreckage, no bodies, no survivors. Just "bye-bye to reality"... Which is the mantra we must utter before delving into the Triangle ourselves.\n\nThe historical root of the Bermuda Triangle legend dates back the time that superstitious Europeans first hit the Atlantic Ocean in their flimsy little boats. Columbus, sailing the ocean blue in (you guessed it) 1492, ran into a strange oceanic phenomenon known as the Sargasso Sea, which is not coincidentally located in the center of the triangle.\n\nThe Sargasso Sea was a large floating mass of seaweed that no one had ever seen the like of. It looked dangerous and entangling but was relatively innocuous in practice. Hordes of eels migrate there every year to mate and die, which also looked more dangerous than it actually was.\n\nA legend of eerie splendiferous danger arose around the region of the Sargasso Sea, what with the tangling and eel-death-screwing. A diary entry from Columbus citing a light on the horizon has been expanded into a full-bore rectal probe chariot of fire by Triangle enthusiasts, but it's frankly underwhelming.\n\nThe next major incident chalked up to the Triangle's nefarious influence is the mysterious case of the Marie Celeste. In 1872, the Marie Celeste was found abandoned, as if the crew and passengers had very suddenly leapt up from their chairs and abandoned ship, leaving meals half-eaten and card games half-played.\n\nWhat is especially mysterious about the case of the Marie Celeste is how it ever got attached to the Bermuda Triangle, since it set sail from New York and was discovered derelict in the Azores, which in scientific terms is "nowhere fuckin' close to" the Bermuda Triangle.\n\nThe modern version of the Bermuda Triangle story sprang not from the muck-covered, eel-spunk sea, but from the otherwise innocuous-seeming air. In 1945, the infamous Flight 19 set out on a training mission in the "triangle."\n\nThere were five Avenger bombers in Flight 19. A radio transmission indicated that the planes encountered problems with their compasses. The weather was reported to be inclement. The mission was never heard from again. A rescue plane sent out to look for the missing pilots was subsequently also lost without a trace.\n\nNow, all this in itself is not particularly remarkable. Given the state of aerodynamic technology at the time and the weather conditions, the concept that the planes crashed at sea is basically sound. The failure to find any wreckage, while noteworthy, is also not especially profound, given that things tend to sink into the ocean, which is (in scientific terms) "very, very deep."\n\nOver the next several years, various other planes and boats disappeared in the region, while other reported odd phenomena such as compasses going nuts. People occasionally reported seeing lights and spooky smoke.\n\nAll this made for the seeds of a nice, local ghost story, but not one of the great supernatural mysteries of our time. To elevate any single set of data to legendary status, one of two things is required: A genuine and profound mystery, or some one person who is willing to say there is a genuine and profound myster
275807
According to the Macquarie Atlas, Palermo is 38.07N 13,21 East. The CIA World Factbook confirms this location.
464463
Just set your reference point by yourself. Everywhere can be North in space.
906820
The Bermuda Triangle, also known as the Devil's Triangle, is a geographical area in the Atlantic Ocean approximately triangular in shape and is famous for its supposed paranormal activities. The Bermuda Triangle is an approximate equilateral triangle with its three corners roughly defined by the islands of Bermuda (one corner) and Puerto Rico near its capital city San Juan (another corner), and near Miami, Florida (a third corner), giving it an area of nearly half a million square miles (1.2 million km²). (Other shapes have been proposed as well as dimensions and borders—see the map at the right and its legend.)\n\nThere are many claims of paranormal activity within the Triangle, especially the inexplicable disappearance of ships and aircraft, or of their crews. Other common claims made of the region are that the laws of physics do not operate here as they do elsewhere, or that extraterrestrial beings are responsible for the disappearances
333415
Compass headings are figured in degrees clockwise from north.  First leg was 30 nm heading 270°.  The east/west part of the trip is 30 cos 270 = -30, the north/south part is 30 sin 270 = 0.  Second leg is 10 nm heading 15°.  east/west part is 10 sin 15 = 2.59, north/south part is 10 cos 15 = 9.66.  Add the 2 legs in separate parts.  You are now at a position 9.66 nm north and 27.41 nm west of port.  divide n/s by e/w to get the tangent of the angle: 9.66/27.41 = 0.3524 = tan 19.4°.  If you make a sketch while doing all this, the 19.4° is your reference angle in the northwest quadrant, so the compass heading from port to your position is 289.4°.  You could also write that as N 70.6° W.\n\nBelieve me, this is a whole lot simpler than navigating in 3 dimensions -- 4, actually, because your home planet isn't going to stay where you left it.
1118569
43° 01'N  89°48'W according to someone who has identified it on Google Earth....but they could be wrong.\n\nhttp://www.caveofthemounds.com/    but it seems they may be right after all
429766
Assuming you meant just north of the equator as the belly button lies just above the wasit, and you mean at 0deg longitude as its at the front and in the middle of the body it would be the town of Tema which is found in Ghana.  The nearest big city though is Accra also in Ghana.\n\nBoth very beautiful cities...you should all go there someday....If you do also spend some time on the Gold Coast in Winneba and Saltpond.  You'll then understand why we have all been put on this earth.
447967
latitude 63° 45' and longitude 68° 30' west
513176
Try http://googleearth.com\nMaster.
66035
Well suppose you want to find antipodal positions on the earth. The earth is only approximately a sphere (it is actually closer to an oblate spheroid), so the mathematical definition of an antipodal point on the earth does not quite hold. \n\nIf one location on earth is at 23 degrees North latitude, and 10 degrees West longitude, the antipodal point will be at 23 degrees South latitude, and 190 degrees West longitude (but 190 degrees West longitude will be more often called 170 degrees East longitude). \n\nThat is, just add 180 degrees to the longitude, and switch the North latitude to South latitude (or vice versa).
634409
Cool! But if the map is on my back, how can i see the coordinates and point them out?
89430
Bermuda Triangle\n\n     also known as the Devil's Triangle and the Limbo of the Lost, a geographical area of about 3,900,000 sq km (1,500,000 sq mi), between Bermuda, Puerto Rico, and Melbourne in Florida (located 55°W to 85°W and 30°N to 40°N), in which there have been numerous unexplained disappearances of ships and aircraft.
180915
Latitude 19° 24′-19° 03′ N \nLongitude 98° 57′-99° 22′ W
350658
Country: South Africa (Free State province).\n(Latitude : -29 13' 00'' Longitude : 26 50' 00'') \nLanguage: Setswana/Sesetho.\nMeaning: Mountain at night.
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The orthocentre of a triangle is the point where all the altitudes meet\n\nSo if you have ΔABC one altitude is the line through A perpendicular to BC, another is the line through B perpendicular to AC and the last is the line through C perpendicular to AB\n\nUse these facts with the coordinates of A, B, and C and the slopes of AB, AC and BC (Find where two altitudes meet and if you are correct that point will also lie on the 3rd altitude)\n\neg Find the orthocentre of the ΔABC where A ≡(1, -3), B ≡(-1, -5), C ≡(3, 1)\n\nSlope AB = Δy/Δx\n= 2/(2) \n= 1\n\nSlope of perpendicular = -1 (-1 * 1 = -1)\nAltitude to AB goes through C\nSo equation of altitude of form y = -x + b\n(3, 1) lies on altitude\nTherefore 1 = - 3 + b\nb = 4\nThus altitude through C is y = -x + 4\nie x + y = 4 ............... (1)\n\nSlope AC = Δy/Δx\n= 4/2\n= 2\n\nSlope of perpendicular = -1/2 (2 * -1/2 = -1)\nAltitude to AC goes through B\nSo equation of altitude of form y = -1/2 x + b\n(-1, -5) lies on altitude\nTherefore -5 = -1/2 * -1 + b\nb = -11/2\nThus altitude through C is y = -1/2 x - 11/2\nie x + 2y = -11 ............... (2)\n\nSlope BC = Δy/Δx\n= 6/(4) \n= 3/2\n\nSlope of perpendicular = -2/3 (3/2 * -2/3 = -1)\nAltitude to BC goes through A\nSo equation of altitude of form y = -2/3 x + b\n(1, -3) lies on altitude\nTherefore -3 = -2/3 * 1 + b\nb = -7/3\nThus altitude through C is y = -2/3 x - 7/3\nie 2x + 3y = -7 ............... (3)\n\nie we have:\n x + y = 4 ................. (1)\n x + 2y = -11 .................. (2)\n2x + 3y = -7 ............... (3)\n\nEquation (2) - equation (1)\ny = -15\nFrom equation (1) x = 19\n\nCheck in equation (2) \nx + 2y = 19 + -30 = -11 YESSSSSSSSS!!!!!!!!!!!!!\n\nCheck in equation (3) to ensure that this point lies on this altiude also\n2x + 3y = 38 + -45 = -7 YESSSSSSSSS!!!!!!!!!!!!!\n\nSo the orthocentre of ΔABC is (19, -15)
706052
Jefferson City, Missouri\n\n  I found it to be 38 degree latitude
117735
Use the Pythagorean theorem (twice).  The ray from the top light to the observer's eye is a straight line that just grazes the surface of the earth.  One right triangle has the following 3 sides: center of earth (COE) to surface (a known quantity), COE to top light (also known) and distance from tower to graze point (unknown).  The right angle is at the graze point.  Set up the other triangle similarly for the observer's eye, solve for the 2 unknowns, then sum them.