Solve By Substitution b=2a+2   5b-9a=12?
410550
5(2a+2) - 9a = 12\n10a + 10 - 9a = 12\n10 + 10a - 9a = 12\n10 + a = 12\n10 + a - 10 = 12 - 10\na = 2\n\n\nb = 2(2)+2\nb = 4+2\nb = 6
279682
14a^2 + 5a + 3\n\n[Add the terms which have same degree]\n\n[6a^2 + 8a^2 = 14 a^2\n2a + 3a = 5a\n1+2 = 3]
814891
a^2 - 2ab + b^2 = (a - b) ^2\n\nthen...\n\n(a - b)^2 / (a + b) = (a -b) (a - b) / (a + b)
801397
equation (2)*2\n6x-4y+8z=12\n9x+4y-z=0\nadding\n15x+7z=12    (4)\n(1)*2\n18x+8y-2z=0\n6x-8y-3z=3\nadding\n24x-5z=3        (5)\n(4)*5        75x+35z=60\n(5)*7      168x+35z=21\nadding     243x=81\nx=1/3\nsubstituting\n8-5z=3\n-5z=-5\nz=1\nsub\n3+4y-1=0\n4y=-2\ny=-1/2\nsolution set{1/3,-1/2,1}
130465
we need at least 12 terms\nSn = (n/2)*[2a1 + (n-1)d]\nin our series a1=11 and d=5. we need to find an n so that Sn>450:\n(n/2)*[2*11 + (n-1)5] = 450  /multiply equation by 2\nn*[22 + 5n - 5] = 900\nn*[5n + 17] = 900\n5n^2 + 17n - 900 = 0\nn1 = 11.82\nn2 = -6.92   /irrelevant\nwe want Sn to be greater then 450, and n has to be integer so the answer is n=12\nS12 = (12/2)*[2*11 + (12-1)*5]\nS12 = 6*[2*11 +11*5]\nS12 = 6*11*7 = 462 > 450
924424
The equations:\n(a+b)^2=a^2+2ab+b^2\nA^2-B^2=(A+B)(A-B)\nJames Chan's solutions were right.
139883
(a+b)(a-b) \n= a^2 - ab + ba - b^2\n= a^2 - b^2 -ab +ab\n= a^2 - b^2
337108
6b + 24a + 45\n= 3*2*b + 3*8*a + 3*15\n= 3(2b + 8a + 15)
847698
Are you looking for help on how to do these so that you can do them on your own, or are you just here looking for answers? \n\nb² - 3b - 10 = (b-5)(b+2)\n\n15x³ - 29x² + 8x =\nx(15x² - 29x + 8) =\nx(5x-8)(3x-1)\n\na² - b² + 9a - 9b =\n(a+b)(a-b) + 9(a-b) = \n(a+b+9)(a-b)\n\n-5b + 35 =\n-5(b+7)
793289
Replace m with 2n in the second equation\n2(2n) + 2n = 12\n4n + 2n = 12\n6n = 12\nn = 12/6 = 2\n\nm = 2n = 2(2) = 4\n\nAnswer: m = 4 and n = 2
38366
I think this is the answer\n\na^2-2ab-b^2\n-a^2(b-b^2)\n= -a^2
893823
Use the quadratic equation \n\nt = -b + or - sqr(b^2 - 4ac)/2a\n\nyour equation is already in the form:\n\nat^2 + bt + c = 0\n\njust plug in the variables and solve for t twice
62277
first, distribute the 2a to the things in the parentheses:\n\n5a + (2a * 5 - 2a * b)\n\nthen, follow pemdas:\n\n5a + 10a - 2ab\n\nwhich equals:\n\n15a - 2ab
590233
Hint:\nDo a simple substitution u = x-5\nWhich means x = u + 5\n\nYou should get\n\n(2/5)(x-5)^(5/2) + 2(x-5)^(3/2) + C
893931
m = 2\n\nb = -1\nso just substitute               these values in your equation\n\ny = mx + b\nthen you'll have\n\ny = 2x -1
4959
=8(y^3)z + 12(y^2)(z^2) - 20y^2
777394
factor out 4b\n\n4b(b-2)= 0\n\nb = 2, 0\n\ngoodluck ^_^