A regular solid with 5 corners.?
396443
This is an excellent question and is quite tedious for a large number of particles, but there have been some papers written on this question. See http://www.geom.uiuc.edu/docs/forum/hoops_links/energy.html for an interesting aside, http://tracer.lcc.uma.es/problems/thomson/thomson.html for some illustration and http://lanl.arxiv.org/find/grp_q-bio,grp_cs,grp_physics,grp_math,grp_nlin/1/all:+AND+problem+Thomson/0/1/0/all/0/1 for the actual mathematics.
29941
You can't have a polygon of that size.  A polygon is an object with three or more straight sides.  One property of a polygon is that no one side can be longer than all the other sides added together.  You listed 6 dimensions, implying a six sided polygon.  But since one side is much longer than the other five together, this is not a real object.\n\nTry taking a yardstick and five toothpicks and put them together to make a polygon shape.  It won't work.\n\nIncidentally, even if you gave realistic dimensions, that's not enough information.  Consider this 6-sided object:\n._\n/ .&#92;\n&#92;_/\nand this one:\n||\n||\n||\n\nEven if the sides were all the same length, they have different areas because the angles are different.
223610
Basically, why isn't there a rotational symmetry for 5 cells in a circle? Because there is no way you can have a single elementary cell that repeats itself covering all of the plane.\n\nTry filling a sheet of paper completely with identical cells of even-sided triangles, squares (and diamond shapes) or hexagons: no problem. Trying to do so with any other regular polygon will leave gaps. Hence only rotations with 2, 3, 4 or 6 periods will result in a lattice.
9196
You want the VOLUME of the rectangular solid.\n(A "cube" is a solid with equal height, width, and depth - like a die.)\n\nThe volume = 15.5 * 10.5 * 9.375 = 1525.78125 cubic inches
747730
use Eulers formula\n\nF+ V = E+2\n\nhere F = faces = 8\nV = vertices =12\nE = edges = 18\n\ntherefore it is possible to construct the solid.\n\nit is a hexagonal cylinder
23529
that is one of the answers, if the length of one side is 5. Use the Phytagorous theorem.
494278
a trapezoid.\n   __\n  /__&#92;
950225
Let a side of the square be 'x' and a side of the pentagon be 'y'.\nFirst, is the pentagon a regular pentagon or a pentagon drawn at random? If it isn't regular, then the ratio is impossible to determine as each side of the pentagon can be different. So I'll assume that it's regular. In a regular pentagon, all the sides are equal.\nPerimeter of square = 4x\nPerimeter of regular pentagon = 5y\nFrom question,\n4x = 5y\n4x/y = 5\n4(x/y) = 5\nx/y = 5/4\nThe ratio of a side of a square to that of a side of the pentagon is 5:4.\nA side of the square must be larger than a side of the pentagon if the perimeters are equal.
1092713
triskaidecagon\n\nor a 13-sided polygon, haha.\n\nCheck the source for polygon names from 1-20 sides  :)
1052606
A minimum of 3 - where the three polygons are all equilateral triangles.\nIf they are all different, then a minimum of 5 - a regular pentagon.\n\nThe maximum number of sides which the largest polygon could have is ∞ that is a circle.\n\nThe limiting factor (assuming we are talking 2 dimensions) is that the sum of the internal angles does not exceed 360°.\nThe circle's internal angle approaches 180°. the other two regular polygons could be two squares or an equilateral triangle with either another triangle, a square or a regular pentagon.
566727
I'm afraid that with the given information, this would be impossible to determine. The only thing one could conclude from this information is that this polygon has an even number of sides. \n\nIt could be a square with sides of 3cm each\nIt could be a hexagon with sides of 2cm each\nIt could be an octagon with sides of 1.5cm each\nIt could be a decagon with sides of 1.2cm each\nIt could be a 12-gon with sides of 1cm each\n\nThe list is infinite unless you are given more specific information, such as the length of each side or the angles within the shape.
63969
A hexagon has 6 sides.
128133
A hexakaidecagon (hexadecagon).\n\nFor the rest of the polygon questions you'll have, try the link below:
416560
You should be able to picture it. Or at least, find a D+D player and look at a 12-sided die.\n\nOne half of this is a pentagon, surrounded on each of the 5 edges by other equal-sized pentagons.  The pentagon has 5 edges, and from each of the five corners is another edge which reaches to the 'equator' of the thing.  The bottom half is identical, with anoth 10 edges just like the flipside. Finally, around the 'equator', is another 5 edges.\n\n25 edges.  Don't need formulas, just good 3-D visualization skills.\n\nPS  It's 'polyhedron', by the way.  Polyhedra is plural.  Saying 'a polyhedra' is just like saying 'a women'.
140477
If it's only the front, and assuming it's rectangular, it's 30 x 30 =900. If it is not rectangular, information is not sufficient to tell.
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Sides on a fifty pence piece
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1.rectangle\n\n2.trapezoid