what is the NMR shift of NO2?
414105
I presume you asking for the N15 shift since there is no proton or carbon.  There is variability of the shift depending on it's environment (is it aliphatic or aromatic?)
1006740
The equilibrium constant for this reaction is given by:\n\n[NO]^2/([N2]*[O2]) = 6.91*10^-4\n\nYou also know, from mass balance, that:\n\n[NO] + 2*[N2] = 2*0.75 mol/L \nand\n[NO] + 2*[O2] = 2*2.4 mol/L\n\n (i.e., the total concentration of nitrogen and oxygen atoms doesn't change in this system -- the number of nitrogen atoms at equilibrium after the gasses react must be the same as the number of atoms you started with)\n\nYou now have three equations in three unknowns ([NO], [O2], and [N2]).  These three unknowns are the concentrations of the gases at equilibrium.  \n\nTo solve these equations, we can rewrite the mass-balance equations as:\n\n[N2] = 0.75 - 0.5*[NO]\n[O2] = 2.4 - 0.5*[NO]\n\nsubstitute these into the equilbrium constant equation to eliminate [N2] and [O2]:\n\n[NO]^2/((0.75 - 0.5*[NO])*(2.4 - 0.5*[NO])) = 6.91*10^-4\n\n[NO]^2/{1.8-1.575*[NO]+0.25*[NO]^2} = 6.91*10^-4\n\n[NO]^2 = 0.0012438 -0.001088325*[NO] +0.00017275*[NO]^2\n\n0 = 0.0012438 - 0.001088325*[NO] - 0.99982725*[NO]^2\n\nUse the quadratic formula to solve for [NO].  In general, there will be two roots, but only one will be physically meaningful.\n\n[NO] = -0.03582 or 0.03473.  Obviously, only the positive root has a physical meaning, so at equilibrium [NO] = 0.03473 mol/L\n\nSubstitute this into the mass-balance equations to get the concentrations of [O2] and [N2]:\n\n[N2] = 0.75 - 0.5*0.03474 = 0.73263 mol/L\n[O2] = 2.4 -  0.5*0.03474 = 2.38263 mol/L\n\nYou can check these results by plugging them back into the equilibrium constant equation to make sure everything agrees:\n\n0.03473^2/[0.73263*2.38263] ?= 6.91*10^4\n\n6.91*10^-4 = 6.91*10^-4  Check!
501957
In each technique you are looking at different spin 1/2 nuclei.\n\nIn general, 1H NMR spectra are much more sensitive, 1H NMR spectra can be aquired much more quickly than 13C, and overall 1H NMR spectra are much more useful for structural determination than 13C. \n\nAn important fact about 1H spectra is that you will see spin coupling between protons three bonds away due to hyperfine interactions. This is what actually provides information about how the atoms in a molecule are connected. Further, 1H spectra are always acquired in a way that the area under a peak is proportional to the number of protons in that particular chemical environment. This can also be very helpful in structure determination.\n\n13C NMR is less useful for several reasons. First, it's not very sensitive. While you can easily acquire a 1H spectrum in 2-3 minutes, 13C spectra routinely require several hours. \n\nTo partially overcome this, a NOE transfer from 1H - 13C is routinely used. This greatly increases the sensitivity of 13C nuclei near 1H nuclei, but doesn't change the\nsensitivity of 13C nuclei far from 1H nuclei. This causes two problems.\n\nThe first problem is that you can no longer integrate the areas under the peaks to find out the relative number of 13C in that position. Although there are ways of avoiding this problem, those techniques usually require days to acquire a spectrum instead of a few hours. \n\nThe second problem is that the farther a 13C nucleus is from a 1H nucleus, the weaker its signal will be. In some cases, if a 13C nucleus is a long ways away from a 1H and has a long relaxation time, it can essentially disappear from the spectrum. This is particularly true for carbonyl groups, and it can be very annoying when analyzing a 13C spectrum.\n\nAnother major problem with 13C is that the natural abundance of 13C is so low that essentially all 13C atoms are surrounded by 12C atoms. The means that you don't see the same spin coupling with neighboring nuclei that you can see with a 1H spectrum. As a result, you really don't have any information at all about how your 13C atoms are bonded together.\n\nIn practice, chemists use 1H NMR all the time. 13C NMR is sometimes used, but due to the drawbacks discussed about it generally isn't very helpful and is only used for journal which require 13C spectra of new compounds.
765235
Here you are:\n1. multiply the first equation by -1 to get\nN2 + O2 ---> 2NO  H= 180 kJ   {1}\n2. Sum the above equation with the second one:\n2NO + O2 ---> 2NO2 H= -112 kJ   {2}\n\nThe sum is\nN2 + 2O2 ---> 2NO2  (This is what you need)\nSo now sum the Hs for the rearenged equation {1} and the second equation {2}.  This will be the H for the equation you need\n\n-112 + 180 = 68 kJ.
943386
Here are two ways to get the same answer of -1.\n\nThe nitrogen in nitrate has a formal charge of +5, and the total charges on the bound oxygens is -6 (3@-2 each), so the net charge for nitrate is -1.\n\nDon't rely on the model of ammonia, NH3, with three bonds and a lone pair.  The nitrogen in nitrate has been oxidized to the extent that all five valence electrons are involved in making 5 bonds to the three oxygen atoms.  Since each oxygen is capable of two bonds, the result is that there is on average one extra charge for the NO3 "radical", or -1 net.\n\nHope this helps.
129663
Please do your own home work.\n\nI suspect you are missing a symbol, it probably should be,\nN2O4  <==>  2NO2\n\nThink about how each of the changes will effect the equilibrium of the reaction.
813754
O2, N2 and CO2.\n\nDon't understand the last part
769316
6.02 x 10^23 of NO2 molecules make 1 mol.\nThus\n4.65 x10^24 of NO2 molecules\n= 1/(6.02 x10^23) x 4.65x10^24\n= 7.724252492 mol of NO2.
744530
It is an electrophilic aromatic substitution reaction.  Because the -COO- acts as an electron withdrawing group to one phenyl group and a moderate electron donating group to the other pheny group the nitration will occur on the pheny group where the COO- is acting as an electron donating group.  The major product of the nitration will have the -NO2 in the para position because the ortho position is partially blocked by the large COPh group.\n\nI hope this helps!
150155
Carbon bound to Nitrogen by a triple bond.
683249
Oh, come on, it doesn't get any easier than this!\n\nSnO2 + 2H2 --> Sn + 2H2O\n\nAbove is balanced. 1 Sn on both sides, 2 O on both sides and 4 H on both sides.\nYou need to work a little harder on these yourself.
638067
Nitrogen\nAcetone chilled with dry ice (CO2)
480464
YOU WOULD HAVE TO USE THE BOND ENTHALPIES TO WORK OUT WHICH ONE. SEEING THOUGH N2 MAKES UP 78%OF THE EARTHS ATMOSPHERE ITS SEEMS VERY INERT SO MOST PEOPLE WOULD ASSUME THAT IS THE ONE
835111
4 NH3  +  5O2  --->  4 NO  +  6H2O\n2 NO  +  O2 ---> 2 NO2  +  N2O4\n3 NO2  +  H2O ---> 2 HNO3  +  NO
869414
NMR -  Nuclear Magnetic Resonance spectroscopy is an analytical chemistry technique used for determining the content and purity of a sample as well as its molecular structure......it is used to identify and confirm the structures of organic compounds.  The 1H (or proton) NMR is the most common, in which the number and type of protons can be determined using a NMR spectrometer, its related to the neighboring environment that each hydrogen experiences.  There is also 13C NMR which helps determine the environment surrounding the carbon atoms. there are also 2D NMR experiments that can be run.
933205
electron affinity\n\nas you are changing Cl2 ->2Cl-
172774
your formula refers to several different structures which of course would give different NMR spectra. It could be 2-bromo-X-methylpyridine where X is the 3,4,5 or 6 position or Bromoaniline, with the various positional isomers. If you don't know the name go to the sigma website and find the structure/name (it may even have the NMR).