How many rectangles are in a 5 by 4 rectangle (contains 20 small rectangles)?
397805
This problem is certainly tractable, you just need to\nfind a consistent/methodical way of counting the\nrectangles -- without missing any and without counting\nany of them multiple times.\n\nThe way I chose is to define each rectangle as being\ndefined by the square in the upper left corner and the\nsquare in the lower right corner.  Consider the following\nsimplified 2x3 case (where each square is labelled by\nits X and Y coordinates:\n\n0,0     0,1   0,2\n1,0     1,1   1,2\n\n\nThis 2X3 example has the following rectangles starting\nat 0,0.  Remember, each rectangle is defined by the\nsquare in its upper left and the square in the lower right:\n0,0   0,0\n0,0   0,1\n0,0   0,2\n0,0   1,0\n0,0   1,1\n0,0   1,2\n\nThen it also has the set anchored in the upper left by 0,1:\n0,1   0,1\n0,1   0,2\n0,1   1,1\n0,1   1,2\n\nThen it has the set anchored in the upper left by 0,2:\n0,2   0,2\n0,2   1,2\n\nThen those anchored by 1,0:\n1,0   1,0\n1,0   1,1\n1,0   1,2\n\nThose anchored by 1,1:\n1,1   1,1\n1,1   1,2\n\nAnd finally those anchored by 1,2:\n1,2   1,2\n\n\nRewriting the matrix another way, showing how many\nrectangles are anchored by each location in the matrix:\n\n2x3    2x2   2,1\n1x3    1x2   1x1\n\n\nand then doing the math:\n\n6      4     2\n3      2     1\n\nfor a total of 6+4+2+3+2+1 = 18\n\n\nDoing the same analysys for a 4x5 gives:\n\n4x5   4x4   4x3   4x2  4x1\n3x5   3x4   3x3   3x2  3x1\n2x5   2x4   2x3   2x2  2x1\n1x5   1x4   1x3   1x2  1x1\n\nor rewriting after doing the multiplication:\n\n20    16    12    8    4\n15    12     9    6    3\n10     8     6    4    2\n 5     4     3    2    1\n\nAdding up the columns gives:\n\n50    40    30   20   10\n\nFor a total of 50+40+30+20+10 = 150 total rectangles
810960
Easy. 40 divided by 2 is 20. Take half of 40.  OR 40x0.5
766270
im assumuing you mean a rectangle? If it was a square itd be 400, if its a rectangle its 80l-l^2
331831
The dimesnions of the rectangle are 14 feet by 34 feet.\n\nYou know that the perimeter is 96 feet and that each long side is 20 feet more than the short sides.\n\nAs there are 2 long sides the total length of both these sides must be 40 feet more than the total length of the 2 short sides (20 x 2 = 40).\n\nIf all the sides were the same length as the short sides then the rectangle would have a perimeter of 56 feet (we know it's 96 feet to start with and that the additional length on the two long sides is 40 feet and 96 - 40 = 56).\n\nEach side would therefore be 14 feet long since 56 divided by 4 = 14.\n\nNow that we know the length of the short sides all we need to do is add 20 to get the length of the long sides, 14 + 20 = 34.\n\nTo check it you can add 14 + 14 (the two short sides) + 34 + 34 (the two long sides) = 96.\n\nI hope that makes sense, it's 1:25AM here and I'm getting tired.
515192
If it's a square, (60 x 60) then probably 8.\nIf it's a circle (r=60) then probably 10.\nIf it's a cirlce (d=60) then probably 6
218079
A square is a rectangle, because by definition, a rectangle is any four sided shape with four right angles.  A rectangle can be a square when all four sides are equal, but not all rectangles are squares.\n\nHope this helps!
909688
5 x {(24 - 19) x [(25 + 23) ÷ 12 - (9 - 7)]}\n\n5 x {5 x [48 ÷ 12 - 2]}\n\n5 x { 5 x [ 4 - 2]}\n\n5 x { 5 x [ 2] }\n\n5 x { 10 }\n\n50\n\nThe answer is 50\n\n- - - - - - - - - -s-
8869
I made an applet that solves any 24 problem, so I got the answer easily.\n5*(5-1/5)=24
359093
Square and Rectangle= lenght*height\ntriangle=base*height divided by 2
927623
The perimeter of a rectangle is the sum of all 4 sides, i.e. twice the width plus twice the length.\nP = 2W + 2L\n120 = 2W + 2(40), from substituting what we know\n120 = 2W + 80\n120 - 80 = 2W + 80 - 80\n40 = 2W\n40 / 2 = 2W / 2\n20 = W\nThe table is 20 inches wide.
890237
4x10 , 8x5 it amounts to 4ft x10ft
608232
Rec first  8 X 4 = 32\n32 X 16 = 512  this is Area of rectangle.\n\nCircles pi X r^2 = Area\n3.14159 X 8 X 8 = 201\n\n512 - (2 X 201) = shaded area\n109.87 = shaded area\n\nOK ?
899361
4 pieces.\n\n12 * 2 is 24\nand 24/6 is 4
576115
20 divided by 4 equals 5.
283369
The perimeter of the square is 50 units\n\nThere are 5 rectangles that means the ratio of length to width has to be 5 to 1\nTherefore since each rectangle has a 5 to 1 ratio and a perimeter of 30 they are all 12.5 units by 2.5 units. (12.5 x 2 is 25, 2.5 x 2 is 5, 25 + 5 = 30)\nThe length of each side of the square is 12.5. 12.5 x 4 is 50 units
3477
64 squares of 1x1, 49 squares of 2x2, 36 squares of 3x3, 25 squares of 4x4, 16 of 5x5, 9 of 6x6, 4 of 7x7, 1 of 8x8 - 204, at least [in case I missed something :-) ]
1077978
23 on the small side.\n\nIf the small side is x, then the long side is 5x.  That makes the perimeter x+x+5x+5x or 12x.\n\n12x=276\nx=276/12\nx=23\n\nThere for the rectangle is 23cmX115cm.