If the temperature today is 0 degrees, than if tommorow is twice colder, how many degrees will it be tommorow?
408175
O degrees is really meaningless in that formula, unless you are using Kelvin.  In which case, zero is as cold as it could theoretically get. So I get it is a bogus question all around.\n\nNow if you qualified the question with day one the temp was x degrees (where x is positive), day two is zero degrees.  What temp. would it be if day three were twice as cold.  the formula would look something like this\n\nt=-x\n\nSo if day one was 10 degrees, day 3 would be -10.  That's really pushing the use of the temperature meanings though.
454506
100 degrees celcius\n212 degrees Fahrenheit
21392
So it depends on whether your question is in Fahrenheit or Centigrade (aka Celsius). If it is in degrees Fahrenheit you need to convert to Rankine, divide by two, and then convert back to Fahrenheit:\n0 Fahrenheit = 459.67 Rankine; twice as cold = 229.835 Rankine; 229.835 Rankine = -229.835 Degrees Fahrenheit which is your answer.\n\nIf, however, you are for some reason using metric, then you convert Centigrade (Celsius) to Kelvin, Divide by two, and convert back to Centigrade.\nSo: 0 Centigrade = 275.15K; twice as cold = 136.575K, converting back to centigrade you get -136.575 Centigrade which is your answer utilizing metric units.
165958
No. Absolute Zero is 459 degrees below zero Fahrenheit. \n\nTemperature is dependent on the rate of oscillation in molecules. At Absolute Zero the oscillations are as low as they can get.
412780
freezing: 0 C,  32 F\nboiling: 100 C, 212 F
642382
a) If 4 C is the temperature at 12 00 and -3 at 18 00 , the difference is 4 - (-3) = 7 C.\n\nb) It became warmer between 10 00 and 12 00 ( by 4C) and 14 00 and 16 00 (by 26 C) and also between 18 00 and 20 00 (by 1C).
344359
It depends what you mean by "twice as cold".  Without any further direction given, I would probably move to an absolute scale (Kelvin, in this case), and cut it in half.  The reason for this is that 0 Kelvin is "absolute zero", where there is no heat at all.\n\nK = C + 273\n\nThis would give:\n\n0C = 273K\n\n273K/2 = 136.5K\n\n136.5K = -136.5C\n\nSo I would say -136.5 degrees centigrade.\n\nTo be honest, I've never heard of weather getting that cold before...
576652
I hope this would help you:\n\nLow Temperature:     -270° F (-170° C)\nAverage Temperature: -185° C \nHigh Temperature: 700°F (350°C)
1109243
Are you serious? Every possible temperature is in both Fahrenheit and Celsius whether it's hot or cold. Depends where you live if you use F or C.
385457
In F, it's -459.39, in kelvin, it's zero, in celsius it's -273
847984
IT'S 32 F SO THAT IS 0 C
90071
That would depend on your latitude.  At 90 degrees N in January, the sun is below the horizon so it would be zero degrees per hour whereas at 90 degrees south when the sun is never setting but moving in a circle in the sky, it would be 15 degrees per hour.\n\nThere is no easy formula to figure out the number of degrees per hour at a given latitude.
177742
i think the answer would be 10 degrees. i am a junior in high school and am in precalculus. \nif you take 730 and subtract 360...you get 370 degrees\nif you subtract 360 again...you get 10 degrees.
426622
temperature differences
481420
first, 1 degree celcius is NOT 32 degrees fahrenheit. ZERO degrees celcius is 32 degrees fahrenheit, but niether here nor there....\n\nnth term will be \n\n(n) + (n-1) + 31. \n\nso if its the first term, then\n(1) + (0) + (31) = 32.....or for the 2nd\n(2) + (2-1) + (31) = 34\n(3) + (3-1) + (31) = 36\n(4) + (4-1) + (31) = 38  .....  and so on. \n\nso for the "42nd" term\n\n(42) + (42-1) + (31) = 114\n\nso for the Nth term\n\n(N) + (N-1) + (31) = .....
483791
0°C = 32°F\nSo instead of going with 0°C, go with 32°F, so that would be 32 * 2 = 64°F or about 18°C\n\nBut if you are talking about 0°F, which is about -18°C, double that and you get -32°F\n\nSo you either get about 18°C or -32°F
702247
1) 31.750 degrees\n2) 30.964 degrees\n3) 23.629 degrees\n4) 7.765 feet