Each of the digits 1,1,2,3,3,4,6 is written on a separate card.?
403642
just remeber, if you want to know if any number is divisible by 4 just check to see if the last two digets are divisible by 4... that should greatly help in solving this problem\n\nNow if you would please, stop asking all of your homework questions
789066
Firstly, it has to start with either a 1 or a 2, and end with a 2 or a 6. So we just take each case one at a time.\n1..2: that leaves 23556, so there are 5!/2! ways, ie 60 ways.\n1..6: that leaves 22355, so there are 5!/(2!2!) ways, ie 30 ways.\n2..2: that leaves 13556, so there are 5!/2! ways, ie 60 ways.\n2..6: that leaves 12355, so there are 5!/2! ways, ie 60 ways.\n\nNote that in each case there are 5! ways of arranging the other 5 numbers, but we need to divide by 2 if there is a pair of repeated numbers.\nThat gives a total of 210.\n\n(note that both of the other answers given so far are wrong - its not 360, because that person has forgotten they have to be even; and its not 120. They counted 2x2 possibilities for the first and last digits which is correct, but one of those cases already uses both 2s, so you *don't* want to divide by 2 in the end for that particular case (you're not counting them twice are you!)\nTheres really no other way of doing it than splitting them into cases like I did.
1038063
If there was only one digit, there would be 10 (0-9)\nTwo digits, 100 (00-99)\nThree digits, 1000 (000-999)\n\nHey, there might be a pattern here\n\nSo 10 digits, 10,000,000,000 (0000000000-9999999999)
165298
100 - You only have 1 choice for the first digit (7) times 10 choices for the second digit (0 thru 9) times 10 choices for the third digit (0 thru 9). 1 X 10 X 10 = 100. Another way of looking at it is your choices are from 700 thru 799, which is 100 choices.
645487
1 - the initial 1\n11 - all numbers from phrase "previous has 1 digit 1"\n21 - all numbers from phrase "previous has 2 digit 1"\n1211 - all numbers from phrase "previous has 1 digit 2, then 1 digit 1"\n111221 - all numbers from phrase "previous has 1 digit 1, then 1 digit 2, then 2 digits 1"\n312211 - all numbers from phrase "previous has 3 digits 1, then 2 digits 2, then 1 digit 1"\n13112221 - all numbers from phrase "previous has 1 digit 3, then 1 digit 1, then 2 digits 2, then 2 digits 1"\n\nSo, the next will be\n\n1113213211 - all numbers from phrase "previous has 1 digit 1, then 1 digit 3, then 2 digits 1, then 3 digits 2, then 1 digit 1"\n31131211131221\n13211311123113112211\n11131221133112132113212221\nand so on
939342
7 digits..\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\nin a bank account
947933
The answer is 4.\n11 is eleven, which has 6 letters, so the next number is 6.\n6 is six, which has 3 letters, so the next number is 3.\n3 is three, which has 5 letters, so the next number is 5.\n5 is five, which has 4 letters, so the next number is 4.\n4 is four, which has 4 letters, so the next number is 4. It's all 4's from there!\n\nBy the way, 4 is the only number that has the same number of letters as its value, and if you start this sequence at any whole number, you will end up at four! Just a tidbit I knew! ^_^
901184
It reads 618 in the 1987 SLG row on the back of the card, it should read .618 and in a smaller text.\n\nonequesti0n
342459
Since there are seven ones, it will count up to 7 and then back down - 1234567654321.\n\n 1111111\nx1111111\n-------------\n0000001111111\n0000011111110\n0000111111100\n0001111111000\n0011111110000\n0111111100000\n1111111000000\n-------------\n1234567654321
247655
0,1,1,5,7,11,13,13,21,23,27.......
638209
1, 2, 3, 6, 7, 14, 21, 42
136789
That's an extremely good question. \n\nThe answer is simple. Before that, i will explain what your question means to those who don't get. Well, it means that we must get 24 using 1,3,4 and 6 any number of times however involving operations +,-,* and / only once. \n\n  Then, the answer is very simple :\n\n  {[(6*6)/(3-1)]+[6]}  =  24\n\n---------------------------------------------------------\nWOKRING :\n\n {[(6*6)/(3-1)]+[6]}   =  {[(36)/(2)]+[6]}\n                       =  18 + 6\n                       =  24\n\n----------------------------------------------------------\n\nI hope you post more questions like these. They evoke a lot of thought. I hope the solution serves th purpose.
741355
There are a few ways to find this, but the answer depends on whether we can repeat numbers in the combination and if the order matters.  \n\nIf we cannot repeat numbers and order matters:\n# combinations = 9*8*7*6*5*4 = 60480\nThere are 9 choices for the first digit, 8 for the second (because one is already taken), and so on.  We multiply the choices for each digit to find the total number of choices.\n\nIf we can repeat numbers and order matters:\n# combinations = 9^6 = 531441\nThere are 9 choices for each of the six digits.\n\nIf we cannot repeat numbers and order does not matter:\n# combinations = 9!/(6!*3!) = 84
339616
There are 12 face cards.\nThere are 26 red cards.\nThere are 6 face cards that are red.\n12+26-6 = 32\n32/52\n= 8/13
448118
Oh jeeze, are you serious LOL.......ok lets say: 999,349,843,928,999,344,576,345,768,324,999 gazilliontrillionbazillion........
827303
a(n) = a(n-1) + sum of digits of a(n-1)  \n \n25, 32, 37, 47, 58, 71, 79\n\nNext is 79 + 16 = 95.
920768
One solution is\n0, 2, 4, 6, 8, 10, 12, 1, 3, 5, 7, 9, 11\nBut there is a huge variety of solutions\n\nSorry Chris I did not copy so here is another\n\n0, 11, 5, 2, 9, 3, 1, 4, 10, 7, 12, 6, 8