What is the relationship between angle of incidence and reflection depending on where the ball bounces?
395942
Well, gimme the address of the curator and I shall ask Ganguly to answer your question ;)
897839
The angular change ratio from the planar field
496012
javelin thrown at angles 30 and 60 will land in same spot because as per properties of projection if x is angle of projection then range for angles of projection x and 90-x will be same
882625
during the throwing motion the ball is accelerated in the opposite dirrection as gravity. once the ball leaves the hand of the thrower however, the acceleartion is constant, and is equal to that of gravity, g = 9.80 m/s^2
1075466
This phenomenon is call total internal reflection.\nThe theory explaining the phenomenon is detailed in most good physics optics textbooks.
444945
The maximum velocity of light is in air (strictly in vacuum).\n\nThe velocity is less in other medium.\n\nThe change in velocity from medium to medium is refraction.\n\nWhen light enters from medium 1 to medium 2, a potion of light is bounced back into the medium 1 and the remaining passes into medium 2 (Refracted). The bouncing back is reflection.\n\nThe proportion of reflection or refraction depends on the angle the ray makes at the point of incidence on the boundary.\n\nWhen light enters from glass (a medium of less velocity; optically denser medium) into air (a medium of more velocity; optically rarer medium) no portion of light is refracted (do not enter into air) at certain angles of incidences. The whole portion of light is bounced back into glass\n\nThey are TOTALLY AND INTERNALLY reflected.\n\nThere is no change in velocity and therefore total ilnternal reflection is not refraction,
609124
Reflection and refraction do not directly prove Huygen's Theorem, at least not in any way I'm familiar with. Diffraction patterns, such as those of single and double slits, are clear examples of Huygen's Theroem in action.\n(We haven't done wave optics yet)
520099
It's INCIDENT not INDICENT. And it's the Law of Reflection : the angle of incidence equals the angle of reflection. So, 40 degrees.
148730
I think it will not change. The reflected ray has to have the same angle. The ray passes through water and refelcts in the water. \nWhat changes is the direction of the ray coming from the air, and then going through the water, but this will not change the focal lenght. Focal lenght is just a matter of geometry of the mirror.
801331
CRITICAL ANGLE:  it is the minimum angle when total internal reflection starts: This means that the refracted ray is in the boundary between two materials (with different refraction index). It only happens if the ray is crossing from a medium with high index refraction to another with smaller index.\n\nThe Problem:\nn1: refraction index of air = 1.003\nn2: refraction index of plastic = ?\ntheta12: critical angle in plastic-air layers = 37.3°\nBy Snell:\nn2*sin(theta12) = n1*sin(90°)\nn2 = n1/sin(theta12) = 1.65\n\nNow:\nn3: refraction index of water = 1.33\nn2: refraction index of plastic = 1.65\ntheta23: critical angle in plastic-water layers = ?\nBy Snell:\nn2*sin(theta23) = n3*sin(90°)\ntheta23 = arcsin(n3/n2) = 53.7°
149736
A conver mirror is diverging in nature.Ligh rays incident at its extreme corners gets diverged following laws of reflection.Hence if we draw the diagram we can clearly understand that the reflected rays follow a wider path.While in case of a plane mirror the divergence is not so large.The credit to this can be given to the cuvature in convex mirror
273641
This wave behaviour is called reflection.\n\n- Constructive interference is when 2+ waves interact and create a wave that is stronger than any of the original interacting waves.\n\n- Diffraction is the tendency for waves to bend around corners.\n\n- Refraction is the bending of waves through a medium (say, water)\n\n- Reflection is the return of a wave in the original direction after bouncing off something (say, light bouncing off a mirror)
26908
When a basketball bounces there is a continuous conversion between Kinetic and Potential energies. \nAt maximum height of the bounce, Potential Energy (P.E.) is maximum and Kinetic Energy(K.E) is minimum or zero.At the floor level, K.E is maximum and P.E is minimum or zero. What is really relevant here is that the Total Energy of the system, E, which is the sum of K.E and P.E remains constant
646629
If the angle from the base is the same in the reflection as the angle from the base of your fan isosceles triangle then the angles are congruent.
696403
The outgoing intensity is found by applying the effective transmittance of each of the three polarizers, in order.  Assuming ideal polarizers:\n\n(I out) = (I in) * (50%) * (cos(24))^2 * (cos(45-24))^2\n\nso (I in) = (2.3 W/m^2) / (0.5) / (.834565) / (.871572) = 6.324032\n\nor about 6.324 W/m^2\n\nNote that this assumes the 45 degree angle is measured in the same rotation direction (e.g., both CCW) as the 24 degree angle.  If the 45 degree angle is measured in the other direction (e.g., CW rather than CCW), then the factor (cos(45-24))^2 should instead be (cos(45+24))^2, which would give the value of 42.918 W/m^2 for the intensity of the incident light.
112172
Only a limited answer:  For the special case where M = m, there are just 2 collisions.  After the first collision, V = 0 and v = V's initial value.  In the post-reflection collision the opposite exchange occurs.
507693
I'll get you started...\n\nFirst, determine how long the ball was in the air.  From that, determine the velocity at which the ball was thrown (the rate necessary, factoring in gravity's acceleration, to keep it airborne for that period of time).  Construct a vector using the velocity of the truck vs. the velocity of the ball to determine the angle.\n\nGood luck!