How would you write and then add 323 AND 198 using ROMAN NUMERALS ?
410075
323 CCCXXIII\n198 IICC\n\nCCCXXIII+IICC\n=IICCCCCXXIII\n             =IIDXXIII\n             =DXXI\n\n323+198=521\n\nI  1\nV  5\nX  10\nL  50\nC  100\nD  500\nM  1000
699337
Ñ = alt 165\ná = alt 160\ní = alt 161\nó = alt 162\nú = alt 163\nñ = alt 164\nÑ = alt 165\n¿= alt 168\n\nÉ = alt 144\né = alt 130
33748
there are a few different ways.  the first is to write numbers alphabetically:  three four etc.  then changing them is easy. 3 4 etc.\n\nor if you have a cheap type calculator try typing in this sequence of numbers and turn it up side down:  5 5 3 7 8 0 0 8\n\nerr well thats numbers to lettres but its still funny!
774139
For this, the simplest method is to add the input and output up:\n16 + 82 = 98\n34 + 64 = 98\n47 + 51 = 98\n51 + 47 = 98\n63 + 35 = 98\n\nSince they all add up to the same amount, the function is a straight addition/subtraction function. Thus, the function is: r = 98 - a.
1115229
Just add them up using the calculator:\n1000 + 5999 + 9888 = 16887\n\nOr if you don't have a calculator:\n*111\n---------\n**1000\n+5999\n+9888\n=====\n16887\n=====
33055
count the decimal places.  line the numbers vertically, like they taught you in the second-grade.  add like-decimal places.  The answer is 100+200+100=400. Now add 400 to the other two numbers you gave us, and it should be pretty easy.
732400
25u + 74 = 23 u + 92\nlet's move all the numbers without variables to the right side.\nSubtract 74 from both sides.\n25u +74 -74 = 23 u +92 -74\nremember that whatever you do to one side of the eqn you have to do to the other.\n25u = 23 u + 18\nnow let's move the u's to the same side.\nsubtract 23u from both sides.\n25u - 23u = 23u -23u +18\n2u = 18\ndivide both sides by 2\nu=9
791300
Use the FOIL method; First, Outer, Inner, Last.\n\nFirst, n * n\n\nOuter, n * 5\n\nInner, n * 7\n\nLast 7 * 5.\n\nThen add them all together.\n\n22 NOV 06, 0420 hrs, GMT.
280927
let the first 3 digits of your number be x = abc and the last four digits be y =defg\n\nwhere a-g are the digits\n\nThe sequence of operations can be rewritten as:\n\n((x*80 + 1) * 250 + 2 * y - 250)/2\n\nIf you distribute the first 250 you get\n\n(20000x + 250 + 2y - 250)/2\n\nCancel the 250's\n\n(20000x+2y)/2\n\nDivide both elements of the numerator by two (distribute the 2)\n\n10000x + y\n\nSince x is a three digit number abc, abc * 10000 = abc0000\n\nSince y is a four digit number defg, 10000x + y = abcdefg.  \nThus we see using algebra that you end up with the same 7 digit number you started out with.
981844
2 +28 -65 +48 +99,002,456,486 +1 -87 -998\n= 99,002,455,415\nNote to other answerers:  If you hold your mouse over the string of characters, it will show everything.
635970
You mean Roman numerals? Here's an easy way to remember them:\n\nIt's Very eXciting, Linda Cried During Math (I V X L C D M).\n\nThen the values are 1 and 5 over and over again:\n1, 5, 10, 50, 100, 500, 1000\n\nSo you get I=1, V=5, X=10, L=50, C=100, D=500, M=1000\n\nIf a smaller number comes before a larger one, you subtract. (Example: IV=4)\n\nIf a smaller number comes AFTER a larger one, you add. (Example: VI=6)
359204
100 which is the binary equivalent of 4 if you are considering those 2 numbers to be added binary numbers
478761
100,000,000,000,001 or one could give it to you in scientifi notation with a rounding error 10.0 E13
668527
Using Roman numerals!  Twelve would be\n\nXII\n\nIf you cut that in half using a horizontal line, the top half looks like VII, which is 7.
1124460
Hold down the alt key and type the following 3-digit codes on the NUMBER PAD on the right:\n\ná = alt+160\né=alt+ 130\ní = alt+161\nó = alt+162\nú = alt + 163\nñ = alt + 164\nÑ = alt + 165\n\nAlso helpful:\n¿ = alt + 0191\n¡ = alt + 0161
1069170
13212211\n\nJust counting numers in the previous number.\n\n'm i right??
949998
For 22 * 11 add 2+2=4 and put it in between the orginal number.\n2 4 2\ni.e. 44 * 11 = 4+4=8 = 4 8 4\n\nFor 55 * 11 add 5+5=10 and put it in between the orginal number.\nFor this one, the tens place carrys over to the first digit.\n5+1 0 5 = 6 0 5\ni.e. 66*11 = 6+6=12 = 6+1 2 6 = 726\n\nAlso for 113 * 11 add the first 2 digits (11) + the last 2 digits (13) which 11+13 = 24 and put it between the first and last digit of the three digit number. 1 24 3\ni.e. 126 * 11   12 + 26 = 38 = 1 38 6\ni.e. 149 * 11   14 + 49 = 63 = 1 63 9\ni.e. 314 * 11   31 + 14 = 45 = 3 45 4\nFor this one, the hundred place carrys over to the first digit.\ni.e. 874 * 11   87 + 74 = 161 = 8+1 61 4 = 9 61 4\n\nAlso for 1126 * 11 add the first 2 digits (11) + the middle 2 digits (12) which 11+12 = 23 add the middle 2 digits (12) + the last 2 digits (26) which 12+26=38 and you can see 23 38 but omit the repeat digit in the middle (238) and put it between the first and last digit of the four digit number. 1 238 6\ni.e. 1342*11 = 13+34=47 and 34+42=76  47 76 = 476 = 1 476 2\ni.e. 1451*11 = 14+45=59 and 45+51=96  59 96 = 596 = 1 596 1\n\nThese get a little tricky but its easier than doing it the long way\ni.e. 3884*11 = 38+84=126 and 88+84=172 so you get\n\n3 _ _ _ 4\n1 2 6   \n_ 1 7 2\nHere you choose the larger number for the thousand and hundreds place and forget about the other but add the ten thousands place.\n4 2 7 2 4\n\n4992*11 = 49+92 = 148 and 99+92 = 191\n\n4 _ _ _ 2\n1 4 8\n_ 1 9 1\n5 4 9 1 2