what is the diametre of a circle whose circumference is 18.85 m?
406577
it's approximately 6 m.\n\nthe formula that relates diameter and circumference is:\n\nCircumference = pi * diameter\n\n18.85 = 3.14 * d\n\n18.85/3.14 = d\n\n6.00 = d  <-- answer
510334
x = a*sin(ang)\ny = b*cos(ang)\n\nang goes from 0 to 360 degress, a and b determine how oval it is (if a=b it is a circle)
525428
The circumference of the circle with radius of 1 m:\nd = 2*pi*r = 6.28 meters.\n\nThe time t = 1.35 seconds\n\nYou get the velocity by dividing the travelled distance by the time interval:\nv = d/t = 4.65 m/s
563113
radius is half of the diameter.\n\nyou can use the circumference equation; c = pi x d\n\nd = 2r so then c = pi x 2r\nc / pi = 2r\nc / pi / 2 = r
1031322
Perimeter of a circle = 2 *pi* radius or = pi *diameter\n\nFrom your picture the diameter of that semicircle = 8 \n\nso the perimeter of the circle = 8 * pi\n\nperimeter of semicircle (half circle) = 8*pi / 2 = 4* pi\n\nAlso, you can find the radius of the circle = diameter/2 = 8/2= 4\n\nThe Width of that rectangular = 1+ radius = 1+4 = 5\n\nThe two bottom short edges = the length of the rectangular - diameter of the semicircle = 10-8=2\n \nThe perimeter of the shaded area = Length of the rectangular + 2 * width  +  two bottom short edges + perimeter of the  semicircle = 10+2*5+2+4*pi=22 + 4* pi\n\nthe answer is a.\n\nHave fun !
1033128
Rewrite the equation as y=9/x. If we take one point on that curve and rotate it around the axis, the circle generated has a circumference of 18π/x and an area of  81π/x² (2πr and πr², respectively). Each of these circles is as an infinitesimally thin slice of the entire solid of revolution, and so we can find the surface area and volume of it by integrating the circumference and area of these circles, respectively. Thus the surface area of the entire curve is (n→∞)lim (1, n)∫18π/x dx (that should be read as "the limit as in approaches infinity of the definite integral from 1 to n of 18 pi over x with respect to x"). The antiderivative of 18π/x is 18π ln (x) and thus the by the fundamental theorem of calculus, (n→∞)lim (1, n)∫18π/x dx= (n→∞)lim (18π ln (n) - 18π ln (1)). Since the limit of ln n as n→∞ is ∞, the surface area is infinite.\n\nRepeating for the volume: the volume is (n→∞)lim (1, n)∫81π/x² dx . Our antiderivative is then -81π/x, and so the final volume is (n→∞)lim -81π/n - (-81π/1). Since the limit of 1/n as n→∞ is zero, the first term in this expression is zero, thus the final answer is - (-81π/1) or simply 81π.
634060
The length of one side of the rectangle can be related to the Circumference of the circle.\nTo get the perimeter of a circle, called the circumference of the circle, one simply has to multiply 2 times pi (about 3.14) times the radius of the particular circle. \nThe circumference of a circle can be calculated from its diameter using the formula:\nc = πd\nOr, substituting the radius for the diameter:\nc = 2πr\nWhere r is the radius and d is the diameter of the circle, and π (the Greek letter pi) is the constant 3.141 592 653 589 793...
56018
the circumference of the earth\nat the equator is 24,902 mi / 40,076 km.
716884
The circumference is equal to pi*diameter\nTaking pi to be 22/7(approx),\n22d/7 = 20\n22d = 20*7\n22d = 140\nd = 140/22\nd = 70/11 miles\nd = 6.3636363636... miles\nd = 6.36 miles (approx)
234569
The diametre of earth at the equator is about 12756 km (7926 mi). And at the poles it is 12713 km (7899 mi).\nThat is 43 km (27 mi) less than the equatorial diameter.
929196
I feel the question should be what is the circumference of earth -\nIt is -\nThe average radius of the Earth is 3,959 miles (6,374 kilometers).\nThe equitorial diameter of the Earth (distance from one side of the Earth to the other at the equator) is about 7,926 miles.\n\nThe ratio of the circumference to the diameter of a circle (circumference/diameter) \nis written as the symbol pi. \nPi is approximately 3.141592.\n3.14159265\n3.1415926535\n\nTherefore, to determine the circumference from the diameter given above:\nequitorial diameter x 3.141592 = equitorial circumference\n| |\n7,926 x 3.141592 = 24,900\n| |\nThe earth has a circumference of approximately 24,900 miles.\n\n\nMore precisely the circumference of the earth (or distance around earth)\nat the equator is 24,902 mi / 40,076 km. \n\nso the answer is 24,902 miles or 40,076 kms.
367152
its the distance between the centre point of a circle to any point along the edge.\n\nAlso its half the diameter. and it can be calculated from the circumference by dividing circumference by 2 pi.
593161
Simply use the corresponding equations. The circumference of a circle is Pi times the diameter and the area of a circle is Pi/4 times the diameter squared.\nThus doubling the diameter doubles the circumference, and quadruples the area.
335828
The radius is half the diameter.\nThe diameter is twice the radius.\nd = 2r\n8 = 2r\nr = 8/2\nr = 4 inches
69500
The circumference of the earth at the equator is 24,902 mi / 40,076 km.
803983
First ... assume an average diameter (or radius) for the planet.\n\nThe average radius normally given is 3963.1 miles (6378 km).\n\nCircumference of a circle = 2 * pi * r = pi * d\n\nCircumference = (2) * (3.14159) * (3963.1) = 24900.9 miles\n... which is approximately 40074 km.
237156
Pi * r^2\n\n(Pi R Squared)\n\nwhere R is the radius (which is also equivalent to half the diameter)