ezplain how you would determine the slope of the equation 2x-8y=7?
408060
To find the slope, you always have to set the equation as y=mx+b.  That equation is called the slope-intercept form.  "m" is the slope and b is the y-intercept.\nNow, to find the slope, try to get y alone.\n1. Subtract 2x from both sides.  You'll get: -8y=-2x+7\n2. Divide both sides by -8.  You'll get: y=(1/4)x+(-7/8)\nSo, the equation is y=(1/4)x-(7/8) and the slope is (1/4).
246990
(7,5) and (11,9)\n\nlet them be (x1,y1) and (x2,y2)\n\nslope of line is (y2-y1)/(x2-x1)\n\nthus slope is (9-5)/(11-7) = 4/4 = 1\n\nequation of line is given by the formulae\n\n(y-y1)=slope*(x-x1)\nor\n(y-y2)=slope*(x-x2)\n\nso equation can be...\n\n(y-5)=1*(x-7) that is x-y=2\n\nor\n\n(y-9)=1*(x-11) that is x-y=2\n\nsee its the same in both cases !\n\nthe required equation is x-y=2 !!!
334051
from x + 8y = 2\nwe get x = 2 - 8y\nsubstituting in the other equation, we get\n3( 2 - 8y ) + 3y = 2\n=> 6 - 24y + 3y = 2\ncollecting like terms:\n=> -21y = -4\n=> y = 4/21
314638
7\n\ny-2x=5x\n\ny-2x+2x=5x+2x\n\ny=5x+2x\n\ny=7x\n\n7=slope
362052
4x-2y = 0  (add 2y to both sides of the equation)\n4x = 2y (divide both sides by 2)\n2x = y\n\nThis equation describes a line of slope 2 and a y-intercept at the origin.\n\nLet me know if you need more information.
190156
2x+5y=6------(1)\nx+y=7--------(2)\n\n(2) x 2; 2x+2y=14----(3)\n\n(1) - (3);\n3y=-8\ny=-8/3\n\nReplace y=-8/3 into (2)\nx+(-8/3)=7\nx-8/3=7\nx=7+8/3\nx=29/3\n\nConclusion: x=29/3 and y=-8/3
903764
2x - 8y = 3\nadd 8y to both sides and subtract 3 from both sides\n2x - 3 = 8y\ndivide both sides by 8\n(x/4) - (3/8) = y\n\nANSWER\n(x/4) - (3/8) = y
749030
y = m (x-x1) + y1\nm=slope (so m=2)\nx1 and y1 are the coordinates. Just plug your numbers in and expand the m(x-x1) part.
143223
a) (6x-7y)(6x+7y)\nb) y(4xy-7)\nc) (x-8)(x+3)
746165
Remember the fomula...\n\ny = mx + b\n\nm = Slope\n\nb = Y-intercept\n\nx and y = points\n\nSo plug everything in...\n\n1 = 4(2) + b\nMulitply\n1 = 8 + b\nSubtract 8 on each side\n-7 = b\n\ny = 4x - 7
985362
x-4y+4=12\n\nyou want to get it in y= mx + b form \n\nso switch the 4y and the 12 \n\nx + 4 -12 = 4y\nx - 8 = 4y\n\nnow divide by 4\n\n(1/4)x -2 = y\n\nso the slope is 1/4 and it crosses the y axis at -2\n\nsome points are \n(0, -2)\n(-4, -3)\n(-8, -4)\n(4, -1)\n(8, 0)\n(12, 1)\n\nhope this helped\nbest of luck
144604
The last answer was close.\n\nYou get y by itself, so you get\n\n7y= -2x + 5 \ny = -2/7x + 5/7\nso the slope of the perpendicular line is the negative reciprocal so it is \n7/2
772016
x1 >= .2(x1 + x2)\nx1 >= .2x1 + .2x2\nSubtract .2x1 from each side\n.8x1 >= .2x2\nDivide both sides by .2\n4x1 >= x2\nx2 <= 4x1\nNow, assuming x1 is on the horizontal axis (x) and x2 is the vertical axis (y), then\n1) Place a dot at (0,0).  This is the y-intercept.\n2) The slope is 4.  Starting at the point (0,0), move up 4 and to the right by 1.  Place a dot there.\n3) Connect the two points with a straight line.\n4) The graph will be shaded below the line.\nI found this by picking any point that is not on the line.\nFor instance, the point (1,0) is not on the line.\n(1,0) means x1 = 1 and x2 = 0\nx2 <= 4x1\n0 <= 4  Since this is true, you shade the side of the line where this point lies.
274298
Use implicit differentiation to find dy/dx. Standard differentiation rules apply, except when you differentiate a term with a "y" in it you must tack on a dy/dx, so:\n\n2x+8y(dy/dx)=0\ndy/dx = -x/4y\n\nThe tangent line intersects the ellipse at (x1,y1), so the slope of the tangent line will be -x1/(4*y1).\n\nWe can also compute the slope of the tangent line by plugging the two points (-5,0) and (x1,y1) into the standard slope formula m = delta(y)/delta(x) and get that the slope of the tangent line is y1/(x1+5). Since these expressions both describe the slope of the tangent line, they must be equal, so\n-x1/(4*y1)=y1/(x1+5)\nx1^2+5*x1=-4*y1^2\nx1^2+4*y1^2+5*x1=0\n\nSince (x1,y1) is a point on the ellipse, it must satisfy the equation of the ellipse, so x1^2+4*y1^2=5. Substituting this in to x1^2+4*y1^2+5*x1=0 gives us 5+5*x1=0, and x1=-1. At this point, there are actually two y1 values that will satisfy the equation of the ellipse, y1 could be either plus or minus 1 (get these by letting x=-1 in the original equation of the ellipse), and so there are actually two points on the ellipse where the tangent line passes through (-5,0), and those points are (-1,1) and (-1,-1).
1066076
ok first set up the problem according to y=mx+b:\n3y+2x+6=0\n- you want to get y by itself so you subtract 2x+6 from both sides (or add -2x-6)\n- you should get 3y= -2x-6\n-then divide by 3(or multiply by 1/3)on both sides\n- you should get y=-2/3x-2 and since m = your slope then the slope is -2/3\n:D\nI LOVE MATH!!!!!!!!
741586
set y=0\nsolve quadratic eqn\nquadratic eqn\n\n-7 +- (49-16)^.5\n-------------------\n2\n= (-7 +- 33^.5)/2
496285
slope m = (2-5)/(5--2) = -3/7\n5=-3/7*2+b\n5+6/7 = b = 35/7+6/7=41/7\n\ny =-3/7x+41/7