Can you answer this number puzzle?
398903
71+43=29+85  that one was easy.
957682
half it then times it by 2! that will give u the answer
942547
Can you please check you haven't made a mistake somewhere? I have just calculated (with 99% certainty) that there are no solutions to those equations with those restrictions.\n\nEdit - OK, I assumed you made exactly one mistake. By removing each possible word and trying to solve it, I discovered that removing 'SIGH' was the only option that gave an answer.\nt 1\nh 8\na 3\nn 7\nk 6\ns 5\ng 9\ni 4\nv 2\nwhere SIGH = 26, not 25. Then THANKSGIVING = 65.\n\nThat was actually a cooler puzzle that the original, assuming you made one mistake :)
956405
something is wrong w/ your puzzle, because if you look in the fourth column, there are two 2s.\n\n* thanks for fixing it,  below are the number in the shape of the sudoku puzzle \n8 6 9 5 4 1 2 3 7\n2 3 1 6 7 8 4 5 9\n4 5 7 2 9 3 6 1 8\n6 1 4 8 3 2 9 7 5\n7 9 5 4 1 6 8 2 3\n3 2 8 9 5 7 1 4 6\n1 8 2 7 6 5 3 9 4\n5 4 6 3 2 9 7 8 1\n9 7 3 1 8 4 5 6 2
1046657
1+1 = 2 OR if you watched A hitch-hikers guide to the galaxy the answer would be 42.
57033
the answer is 3 because a-b|a-b & a-b|a so a-b|b
868097
-\naside from 1,\n2,3,4,6,12
920549
3   7    14 16  25\n11 20  23  2   9\n22  4    6    15 18\n10 13  17  24 1\n19  21  5    8   12
593943
1) The sum of the positive 3-digit odd integers = 101 + 103 + 105 + ... + 995 + 997 + 999.  Adding the first of these to the last, we get 101 + 999 = 1100.  Adding the second of these to the next to last, we get 103 + 997 = 1100.  This pattern keeps repeating until 549 + 551 = 1100.  The question then becomes, how many of these 1100's do we have?  We have one for 101, 103, 105, ..., 549 (the later numbers share their 1100's with these).  How many numbers are in the set 101, 103, 105, ..., 549?  Well, there are 449 numbers in 101, 102, 103, ..., 549.  Since there is one more odd number than even number, we must have 225 odd numbers and 224 even numbers.  Thus, there are 225 odd numbers in the set 101, 103, 105, ..., 549.  Thus, we have 225 1100's to add together.\n\n225 * 1100 = 247500.\n\n\n\n2) This time we wish to add the numbers of the set 10, 11, 13, 14, ..., 94, 95, 97, 98.  Adding the first to the last we get 10 + 98 = 108.  Adding the second to the second to last we get 11 + 97 = 108.  The pattern keeps repeating until we get 53 + 55 = 108.  How many 108's do we have?  Well, we have one for 10, 11, 13, 14, 16, 17, ..., 52, 53 (again, the later numbers share their 108's with these).  How many numbers are in this set?  In the set 10, 11, 12, 13, ..., 52, 53, there are 44 numbers.  The multiples of three range from 12 to 51--from 3*4 to 3*17.  Thus, there are 14 multiples of three in this range.  This means that there are 30 numbers in the set 10, 11, 13, 14, 16, 17, ..., 52, 53.  Thus, we have 30 108's to add together.\n\n30 * 108 = 3240.\n\n\n\n3) Here, I am assuming that the raise of 10% also applies to the previous year's raise and not just to the "principal" of $18000.  Thus, I am assuming a compound raise instead of 5 simple raises.\n\nDuring the first year, you make $18000.  During the second year, you make 18000 * 1.1 = $19800.  During the third year, you make 19800 * 1.1 = $21780.  During the fourth year, you make 21780 * 1.1 = $23958.  Finally, during the fifth year, you make 23958 * 1.1 = $26353.80.\n\nGood luck.
907310
5\n\n1s,2s,2px,2py,2pz
124188
1398\n\nEasy way:\nRound 399 to 400 (+1)\nRound 999 to 1000 (+1)\nAdd 1000+400=\n1400\nSubtract the two you added.\n1398
1069170
13212211\n\nJust counting numers in the previous number.\n\n'm i right??
853291
4 is the answer. Here's how:\n4 appears after a break of two numbers, so the number that follows 40 must be 4
1092764
4+4 will = 1\n\nThe logic is the answers are going down from five only in odd numbers thus the answer is 1.
263164
I won 10 points!\n\nThis is pretty easy. Try to stump me with harder ones.
73869
1,100 \n And here's the answer in romen numerals:\n\nMC\n\nWhoop-a-de-Doo!
176413
Great puzzle, took me awhile to make it to f=1, g=4. The letters are from a-i: 9,8,7,2,6,1,4,5,3.\n\nPlugged in this is: (9 * 87 + 2/6) / (14 + 5/3) or (783 + 1/3) / (15 + 2/3) which equals 50.\n\nAnswer logged Sunday, March 12th, 3:20 pm with no other valid answers yet. Sorry to have to write that, but I've seen people change their answers too many times in the past.