X^2(100^x-x100^x-20(100^x)=0?
404608
that is incomplete because you are missing one parenthesis. But x=0 is a correct answer.
489740
let 0=0\n   then a^2-a^2=(a-a)(a+a)\n  then a(a-a)=(a-a)(a+a)\nthen a=2a\nthen 1=2\nthen 2=3
759773
Let x be the larger number\nLet x - 100 be the smaller number\nThe difference between the two is 100.\n\nThe product would be x(x-100) = x² - 100x.\n\nIf you take the derivative, you get 2x - 100.\n\nSet this to zero:\n2x - 100 = 0\n2x = 100\nx = 50\n\nAlternatively, if you aren't familiar with calculus, turn the equation into vertex form for a parabola.  Do this by completing the square:\nx² - 100x = 0\n\nTake the coefficient on the x-term (-100), divide it by 2 (-50), and square it (2500).  Add this to both sides:\nx² - 100x + 2500 = 2500\n(x - 50)² = 2500\n(x - 50)² - 2500 = 0\n\nThis is vertex form a(x - h)² - k = 0 and the vertex will be at the point x = h or x = 50.\n\nSo either way you figure it, the numbers are 50 and -50.  The product is -2500 which is minimum.
148612
(A-B)^2=A^2-2AB+B^2\nThen\n(3/5)x= 2*x*N\nThen N=3/10\n\n(x-3/10)^2\nx^2-3/5x+9/100
708801
The answer is 10\n\nMultiply 5 times 20 and take the square root of that.\n\nMultiplication and Square Roots can be done in either order.
805031
1)  √10 · ³√100\n= 10^(1/2) · 10^(2/3)\n= 10^(7/6)\n\n2)  (6x)^(1/2) · (36x²)^(1/4)\n= (6x)^(1/2) · (6x)²^(1/4)\n= (6x)^(1/2) · (6x)^(2/4)\n= 6x\n\n...and so on.  Change the radicands to rational exponents with common bases, and follow the rules from there.  Good luck!
860864
x^2-20=0\n    +20=+20\nx^2=20\nif x squared minus 20 equals zero, you have to add 20 to both sides. Now, you have "x" on one side of the equals sign and a number on the other
207106
x^2-3=-2\nx^2=-2+3\nx^2= 1\nx=1\n\n1^2+-3+2=0
921698
let the base be x\narea=1/2*x*[5^2-(x/2)^2]\n       =1/2x[25-x^2/4]\ndA/dx=1/2[x(-1/2x)+(25-x^2/4)]\nsetting it to zero\n1/4x^2=-x^2/4+25\nx^2/2=25\nx^2=50/3\nx=5rt(2/3)\nh=rt(25-50/12)\n=rt250/12\n=5/2rt(10/3)\narea=(1/2)5rt(2/3)(5/2)rt(10/3)\n=25/4rt(20/9)\n=25/12rt20\nx=10/rt3\narea=1/2*10/rt3*200/12
720251
(a+b)^100 \n= a^100 + 100C1*a^99*b + 100C2*a^98*b^2 + ....... + b^100\n\n(a-b)^100\n= a^100 - 100C1*a^99*b + 100C2*a^98*b^2 - ....... + b^100\n\nTherefore (a+b)^100 + (a-b)^100 = \n2*[a^100 + 100C2*a^98*b^2 + 100C4*a^96*b^4 + ..... + b^100]\n\nClearly there are 51 terms in total irrespective of the values of 'a' and 'b'. [Here a = 8, b = 2*sqrt(5)]
922587
ok\nf(x) = 20 - x\nf(0) = 20 - 0 = 20\nf(2) = 20 - 2 = 18\nf(4) = 20 - 4 = 16\nf(8) = 20 - 8 = 12
590233
Hint:\nDo a simple substitution u = x-5\nWhich means x = u + 5\n\nYou should get\n\n(2/5)(x-5)^(5/2) + 2(x-5)^(3/2) + C
762440
Just split it into parts - when is x-x^2<0, and when is it >0?\nThat bit has roots 0 and 1, so it is positive between 0 and 1, negative everywhere else.\n\nThus, ∫(x=-1 to x=0) (x^2-x) dx + ∫(x=0 to x=1) (x-x^2) dx + ∫(x=1 to x=3) (x^2 - x) dx\n\n= [(1/3 x^3 - 1/2 x^2) from -1 to 0] + [(1/2 x^2 - 1/3 x^3) from 0 to 1] + [(1/3 x^3 - 1/2 x^2) from 1 to 3]\n= (0- -5/6) + (1/6 - 0) + (9/2 - -1/6)\n= 17/3.
87424
For negative exponents, make a fraction of 1 over whatever the base number is.  Then raise the denominator to the positive of your exponent.\n\nIn this case 10^(-2) would be 1/10^2 (read "1 over ten squared) so the answer is 1/100\n\nSome other examples:\n\n2^-5 = 1/(2^5)\n\n4^(-1/2) = 1/(4^1/2) or 1/sqrt4
13640
24X^4-10X^3-1062X^2+3190X+1124=0
14221
If X = -100\nThen X + 25 = -75\n-4X = 400\nand -75 > 400 is false
187658
it's defined \n\n0^0=0