i need to know something about some math!!and reducing to the lowest #?
407989
Just cross of like terms in the numerator and the denominator and see what is left.  like in the first problem the numerator and the denominator share two two's and a 3, so by crossing them off you are left with 4/7.  You can do that since 2/2 is one, and likewise with other similar fractions, and when you multiply by one you always get the same fraction.
352166
8\ntake away o from top and you're left with o on bottom - half - nothing\nor i guess 10 could work, too (or any double digit ending in 0) take away the first number and you're left with 0
955082
I think you just take the numbers and plug them in where the letters are and find your result.  Ie.  every time you see an a in the question, write -2 instead and then work it out...
912076
Divide numerator and denominator by 9... your answer is:\n1/3\n\nYou can't reduce this any further.
277190
1 + 49; 2 + 48; etc. Just match the next highest with the next lowest.
927294
mean (add all numbers together and divide by the amount of numbers) - 6\nmedian (middle number when ordered from least to greatest) - 7\nmode (the number that appears the most) - 9\nrange (lowest number subtracted from highest number) - 8
831476
rearrange the numbers from the least to the greastest\n83,85,85,88,89,89,90\n\n88 is the median
302338
take away the percent sign, move decimal 2 to the left.ie: 25% = .25\noops... sorry, reverse that.
531494
Ask your teacher.\n\nBut usually, you are supposed to simplify.
832646
I'm sorry, but how could you not know this?\nThis is basic elementary math and if you don't know how to round you are in trouble.\nIt's 0.1 by the way
1066492
x = -4\n10points thank u!
981364
Gopal has the correct answer! \n\nSo... becareful with some other results... and... never use:\n0.833 instead of 5/6... it's a mistake!\n\nFinished Algebra with 19!
1082141
divide. multiply. subtract. bring down
962762
Here is how to reverse a number - it doesn't matter how many digits.\nYou'll have to figure out the rest of your program yourself - there isn't much left anyway.\n\nint reverse (int n)\n{\n   int r = 0;\n   for (;n>0;n/=10) r=r*10+n%10;\n   return r;\n}
605811
As Lauren said, it's 1/x.\n\nMemorize this. It will be very useful.
1062332
52\n\n52+\n59+\n64+\n68+\n77\n==320\n\n320 = x + (x-9) + (x-13) + (x-18) + (x-25)\n320 = 5x -65\n385 = 5x\n77 = x\n\nx-25= lowest #\n77-25 = 52
95584
I rember doing something like this: you had to take the int you store the input in, and divide it by ten with the mod operator (%), and store it in a new int.  Since the mod operator divides the two numbers, and then returns the remainder, that will separate your last number.  For example:\n\nSay the input is 4321, and you have it stored in int input;\n\nint first_num = input % 10;\n\nthis takes your value in input, divides it by 10, then takes the remainder and stores it in first_num.  In this case, first_num should now equal 1.  \n\nAfter that, you have to shorten your input from 4321 to 432 by dividing (regular dividing this time) it by ten, and storing it in another new int.  (Since int can't have any decimals, dividing by ten just shortens it by the first number).  Then you do the whole thing over until you have all four numbers in separate ints, and then output them to separate lines.  \n\nHope that's clear enough--it's hard to explain this stuff so it's easy to understand.  Good Luck!