what is the limite of friability test?
405650
What do you want to fry?
1025820
There are no limits on the amount, but there are limits on what can be done with it.\n\nI can think of no reason why it should be limited.
892270
First of all, you need to actually guess what the limit will be. \nf(x) = (x+2)(x-2) / (x+2) = x-2 as long as x is not equal to -2, so a good guess would be -4, since its very close to -4 when x is very close to -2.\n\nLet ε>0. Choose δ=ε. Then if 0 < |x- -2| = |x+2| < δ, we have:\nf(x) = (x+2)(x-2)/(x+2) = x-2, since x isn't equal to -2.\nSo |f(x) - -4| = |x-2- -4| = |x+2| < δ = ε, as required.
828415
You restrict the domain of the function as necessary in order that it pass both the vertical and horizontal line test.  Once you do that, f^-1 exists.  For example, if f(x) = sinx, you can restrict its domain to (-pi/2, pi/2). This function will then pass both h & v line test, and its inverse will then exist.\n\nanother example - f(x) = x^2.  A parabola opening upward whose vertex is the origin, and fails the h-line test.  If you restrict domain to (>=0),  f^-1 will then exist.
663593
A unified family of goodness-of-fit tests is introduced and studied.\nThe new family of test statistics Sn(s) includes both the supremum\nversion of the Anderson-Darling statistic and the test statistic of\nBerk and Jones (1979) as special cases. The new family is based on\nphi-divergences somewhat analogously to the phi-divergence tests for\nmultinomial families introduced by Cressie and Read (1984), and is\nindexed by a real parameter s ∈ R: s = 2 gives the Anderson - Darling\ntest statistic, s = 1 gives the Berk-Jones test statistic, s = 1/2 gives\na new (Hellinger - distance type) statistic, s = 0 corresponds to the\n“reversed Berk-Jones” statistic studied by Jager and Wellner (2004),\nand s = −1 gives a “studentized” (or empirically weighted) version\nof the Anderson - Darling statistic. We also introduce corresponding\nintegral versions of the new statistics.\nWe show that the asymptotic null distribution theory of Jaeschke\n(1979) and Eicker (1979) for the Anderson-Darling statistic, and of\nBerk and Jones (1979) and Wellner and Koltchinskii (2003) for the\nBerk-Jones statistic, applies to the whole family of statistics Sn(s)\nwith s ∈ [−1, 2]. We also provide new finite-sample approximations\nto the null distributions and show how the new approximations can\nbe used to obtain accurate computation of quantiles.\nOn the side of power behavior, we show that for 0 < s < 1 and\nfixed alternatives the test statistics always converge almost surely to\ntheir corresponding natural parameter. For 1 < s < ∞ we provide\nnecessary and sufficient conditions on the alternative d.f. F for convergence\nto the corresponding natural parameter to hold, and show\nthat the “Poisson boundary” phenomena noted by Berk and Jones\nfor their statistic continues to hold for s ≥ 1 and s < 0 by identifying\nthe Poisson boundary distributions explicitly. We also briefly discuss\nfurther large deviation results and connections between the work of\nBerk and Jones (1979) and Groeneboom and Shorack (1981).\nWe extend the results of Donoho and Jin (2004) by showing that\nall our new tests for s ∈ [−1, 2] have the same “optimal detection\nboundary” for normal shift mixture alternatives as Tukey’s “highercriticism”\nstatistic and the Berk-Jones statistic.
742785
as x ->pi/4 (1-tan x) ->0 and sec x is not infinite(sqrt(2))\n\nso limit is product =0
833193
Informally, a function f has limit L at a point p when we can make the value of f as close to L as we want, by taking points close enough to p.\nlim     f(x) = L\nx-->p
834638
1. horizontal asymptotes : find the limit of fn as x--> infinity:\n\ndivide the fn's num and denom by highest i.e. x^2:\nr(x) = {x + (3)}/{1  - (4/x^2)}\nhence as x--> +-inf, r(x)---> +- inf\n\n2. vertical asymptote means find zeroes of denom:\nx^2-4=0\n(x+2)(x-2)=0\nhence x= 2 and x=-2 are the answers.
732858
in testing the hypothesis > is the right side, < is the left side, not equal to is a two tailed test....for whatever test your using find the critical value...if it is greater than the alpha reject otherwise fail to reject
888635
Let f(x) = 3x^4 - 25 + 5/4. Consider an arbitrary real valued x say x = c. We need to determine if the left-hand behavior and the right-hand behavior of the function f at x = c are the same or not. \n\nBecause f(x) is a polynomial function (of degree 4) on x, it follows that the function f is continuous on R (the set of real numbers).  So, if we take the limit on the left (and right) of x, we will get the same value for both sides. \n\nThat is, the behavior on the left (Left-hand Limit) will be: as x approaches  c from the left, we get f(x) approaches f(c) = 3c^4 - 25 + 5/4. Similarly, the behavior on the right (Right-hand Limit) will be: as x approaches c from the right, we also get f(x) approaches f(c) = 3c^4 - 25 + 5/4. \n\nTherefore, both the left and right-hand limit yields to f(c), i.e. as x approaches c, we always obtain f(c).\n\nHence, both left and right-hand behavior of f are the same for all real valued x.
267558
I have no idea what critical interval is, but in most sample tests a nice size for a preliminary theory test is from 200 to 500.  That will give you a nice idea of whether the theory is viable or not.  Then for the final sample try toget at least 1500.
47430
thats a good qeustion. i didnt know that there was a limit. just ask yahoo. they let you ask anything and they helped me once.
225035
Try 31545.  Leave off the 0.
922757
a) Can't sell more than 4, so 1*p(selling 1) + 2*p(selling 2) + 3p(selling 3) + 4p(selling4).\n\nb) Find the number n so that p(x>n) is less than 0.05 for a Poisson "vif" mean 3.
662623
the lowest acceptable limit as restricted by controlling parties\n\nA floor, or bottom, is the minimum allowable limit. An example of a floor occurs in underwriting. The issuing corporation will declare a minimum acceptable amount at which the investment bank can purchase the securities. This way the corporation ensures sufficient capital acquisition.
1154919
<1>...u know lim xsin(1/x)=lim (sin(1/x))/(1/x),and when x goes to infinity ,(1/x) goes to <0>....and we know that (sina)/a when <a> goes to <0> is 1...and here <a> is <1/x>...so it's limit is <1>
879179
There is no limit.\n\nYou can see this by approaching from two different directions, along the x-axis and along the y-axis.If x is zero and y->0, then the formula becomes:\n\n   (siny)^2/y^2\n\nSince sin y/y -> 1 as y->0, this also approaches 1 as y approaches zero.\n\nOn the other hand, if y=0, and x->0, then the formula becomes:\n\n    x^2/(2x^2)\n\nwhich has a limit of 1/2 as x->0.