find the domain of log(x-4)(x+3)?
406468
D = {x | x < -3 U x > 4 }
519118
you use the 10^x key\n\nthe antilog of -4.82 \n= 10^(-4.82) = 1.514 * 10^(-5) = 0.00001514\n\ntype in -4.82 and hit the 10^x key (it's usually right above the log key, which mean you hit the 2nd function key then log)
942101
start by seperating y, u then have y=3x/2+3 then plug in the domain, or the numbers u are givin\nu'll have 0, 1.5, 3, 6, 7.5
807860
Yes, though don't forget the y on the second log:\n\nlogb x^2/3 + logb y^3/4\n\nAlso, if you would have had:\nlogb x^2/3 / y^3/4 it would equal logb x^2/3 - logb y^3/4\n\nlog rules are just like exponent rules: multiplication = addition and division = subtraction
584413
log(x-4) - log(3x-10) = log(1/x)\nlog((x-4)/(3x-10)) = log(1/x)\n(x-4)/(3x-10) = 1/x\nx(x-4) = 3x-10\nx^2 - 4x - 3x + 10 = 0\nx^2 - 7x + 10 = 0\n(x-2)(x-5) = 0\n\nx = 2 or x = 5.\n\nedit: Sorry, ervin is right.  I thought I had checked, but apparently I wasn't careful enough.  The only solution is x=5 since you cannot take the log of negative numbers.
958049
[Log(11)3 - 7]/0.35 = x\n\nRead: Log base 11 of 3 minus 7 all divided by 0.35 equals x
338108
A Natural log. It is expressed as: ln()\nFor example: ln(e^2) = 2
437664
The secret is to understand some of the rules of logarithms and adjust translate the numbers to make your lob easier.\n\nThe rules:\nlog(a*b) = log(a) + log(b)\nlog(a/b) = log(a)- log(b)\nlog(a^n)=nlog(a)\n\nIf I understand your problem:\n\nx= [(86400)*sqrt(365.25)]/[ (.079)^11]\n\nso log(x) = log [.....]\n\n     = log(86400)+log(356.25^.5) - log(0.79^11)\n     = log(86400)+.5*log(356.25) - 11*log(0.79)\n\nuse log tables to get the logs and add them up to get the log of x.  Use the tables again to find x.\n\nYou can make other approximations, i.e., 356.25 is close to 19^2 (=361)\nand 86400 is close to 300^2 (=90000) and continue from there.  \n\nHope that helps.
968058
Type 1.16 log / 4 / 1.0125 log =\nThis is 3 approximately (2.9869...)\n\nTh.
100388
This is due to a property of log which is that :\nlog(ab)=log(a)+log(b)\nRemark that this is true when well defined (for eg you can't write log(-1*-3)=log(-1)+log(-3) )\n\nSo here, you have log(x^2)=log(x)+log(x)\n\nTherefore, there are no diff. except that log(x^2) exists for all x in R&#92;{0} and 2log(x) is defined for all x strictly positive.
916994
(log x)^3 = log (x^9)\n(log x)^3 = 9 log x\n(log x)^2 = 9\nlog x = +/- 3\nx = 10^3 = 1000  or x = 10^-3 = .001
754397
ln(x+3) - ln(x) = ln[(x+3)/3]\n\n2ln(2) = ln(2²) = ln4\n\nSo, if ln[(x+3)/x)] = ln4, then\n\n(x+3)/x = 4, or\n\nx+3 = 4x, or \n\nx = 3x, or x = 1\n\nI used the properties of logs to help me solve this.  I think you tried to make it too hard on yourself (which is very easy to do when dealing with the hated logarithms!).  Also, you brought e into it when you didn't really need to.  Since we had ln(x) = ln(y), essentially, then from there we can conclude that x=y without bringing e into play.  Anyhoo, here's the log properties I used in this solution.  (I use the word log but it applies to ln as well.):\n\nlog(a) - log(b) = log(a/b)\n\nrlog(a) = log(a^r)\n\nHope that helped!\n\n~ ♥ ~
978473
log(10) = 1, so \n3 = 3log(10) = log(10^3) = log(1000)\n\n2log(2) = log(2^2) = log(4)\n\n3 - 2log(2)\n= log(1000) - log(4)\n= log(1000/4)\n= log(250)\n\nI used the following properties:\n1) log(x^n) = n log(x)\n2) log(a) - log(b) = log(a/b)
262377
a sum of logs is the log of the product, so\nlog4 (x-3) + log4 (x+3)=2\nlog4 [(x-3)(x+3)] = 2...........then by definition of log\n(x-3)(x+3)=4^2\nx^2-9=16\nx^2=25\nx= ±5.........but we can't use -5 because that would make x-3=-8 and log of a negative is not defined for real numbers,\n\nso x=5
693908
Logs are just equivalent to power statements. \nlog_a (b) = c means a^c = b.\nSo that equation just means x^2 = 2x-3.\nNow thats just a quadratic;\nx^2 - 2x + 3 = 0\nHowever that has no real roots. So there are no such values of x. But hopefully you get the idea.
627488
you can change the base...\nln x = (log2 (x))(ln 2)
658763
Take the logarithm of both sides:\n\nlog a^a = log 2\n\nThen use the rule log (x^y) = y log x\n\nso a log a = log 2\n\nUnfortunately from here we can only solve numerically. Look at the graph of a log a and make approximations.\n\nThough not expressible using elementary functions, the actual answer is defined by the Lambert's W function and reads: log 2 / (LambertW (log 2)), which is roughly 1.5596. More about the W function and what it's used for below.