can someone help me find the value of n:     n-1 1/2 =?
398720
n - 1 1/2 = 3\nAdd 1 1/2 to each side\nn = 3 + 1 1/2\nn = 4 1/2
431708
0/0=(1-1)/(1-1)=(1+1)*(1-1)/(1-1)=> 0/0=2\nor this:\n0/0=(4-4)/(2-2)=(2+2)*(2-2)/(2-2)=> 0/0=4\nor, maybe, this one:\n0/0=(9-9)/(3-3)=(3+3)*(3-3)/(3-3)=> 0/0=6\n.........and so one......\n\nhowever, it's not immpossible, just undefinied....
984623
It will be 1/(x^2)\n\nFor example\n\n(1/2)^2 = (1^2)/(2^2) = 1/ 4\n(1/3)^2 = (1^2)/(3^2) = 1/ 9\n(1/4)^2 = (1^2)/(4^2) = 1/16\n\nSo the result actually gets smaller even though you are squaring it
411757
since y=+-(x)^(3/2) Range [0,oo[\nnP=(n,n*n^1/2) and x_n/y_n= [(n^1/2^)/n]=n^-1/2
887594
Combine like terms, so n-2n = -n\n\nn - 2n = -14\n\n-n = -14\n\nn = 14\n\nPretty straightforward.  What part messed you up?  Let us know and I (we) will try to explain for you.\n\nNRT
734075
6(1/2)=3\n-2(1/2)=-1\n12(1/2)=6
919613
Divide 1 by 2/5 or \n1/(2/5) = 5/2
858963
The answer is actually much more complex than one would think! The correct answer though is ...\n\n((2^n)(n-.5)!)/(2(.5!))\n\nThat looks kind of messy, so in English that is "2 to the n times n minus 1 half factorial over 2 times 1 half factorial."\n\nPlugging in 1,3,5,7 for n on a graphing calculator, we get 1,3,15,105, which are the correct first four terms in the sequence.
984538
(2/6) / (4/9)\n1/3 * 9/4\n3/4
256280
divide by -4\n80,-20,5,-5/4,5/16,-5/64....\n{n, n/(-4)}
950045
Correct formula should be as follows:\n\nE = 1/2*I*w^2
427035
-x1 = 24000-x2\nx2 = 16000-x1\n\n-x1 = 24000-(16000-x1)\n-x1 = 24000-16000+x1 \n2x1 = - 8000\nx1 = - 4000\n\nx2 = 16000-(-4000)\nx2 = 20000
978426
for example:\n\n-1 < 2\nthen\n1 > -2\n\nanother:\n x < -5\nthen\n-x > 5\n\n-2 x > 9\nx< -9/2\n\ns
464039
Your equation would be:\n\n= ((1/p) - (1/q))/(1/pq)\n\n= ((q - p)/pq) * pq\n\n= q - p\n\nHope I am clear.
786717
its 1\n\nsince i = (-1)^1/2\n\nso i^2 = (-1)^(2*(1/2))\n\nwhich is 1
5300
(n+k-1) over (k) = (n+k-1) / (k)\n\n=> (n+k-1) / (k) = n/k +1 -1/k
799171
This is works like n-2^(n-2) \n1-1 = 1-2^(2-2) = 1-2^0 = 1-1\n3-2 = 3-2^(3-2) = 3-2^1 = 3-2\n5-8 = 5-2^(5-2) = 5-2^3 = 5-8\n7-x = 7-2^(7-2) = 7-2^5 = 7-32 \nThus x is 32.