Solve using the addition principle. Graph and write set-builder notation for the answer.?
402424
f+12<18  Subtract 12 from each side.\nf < 6\nThus, the solution is all numbers less than 6.\n(-infinity,6) is called interval notation.\nSet builder notation:\n{f|f<6}\nSet builder notation is always enclosed in braces {}, and always starts out with f|\nThe vertical bar is read "such that"\nThus, {f|f<6} is read "f such that f is less than 6."\nAlso, the graph is a number line with a parenthesis, ), at 6 and then shaded to the left of 6.
40850
-3 <4x\n x < -3/4\n solution set : {- infinity ,.............,-3/4}
685420
x-y = 4\nx = 4 + y\nx-4 = y\n\nSo all pairs of the for (x, x-4).
695947
D\n\nEither is sufficient.  \n1) will lead to 2 equations,2 unknowns which yield a unique solution for x and y:  x=y+1, x+y=77, therefore x=39, y=38.  xy=1482 \n\n2) If the sum is 77 and x and y have the same tens digit, then there are two solutions for {x,y}, namely {38,39} and {39,38}, however the product xy is the same. xy=1482
421674
y = (x mod 5) + 1.\n\nThough that does seem a bit like cheating :)
548405
please dont hate math\nshow interest\nthen you do well\n\nFOIL\nFirst-Out-Inner-Last\n\nThis method is used for multiplying two binomials.\nsay (a+b)(x+y)\n\n( a + b ) (x + y)\n\nFirst------first terms in the two binomials. they are to be multiplied. so ax\nthen Outer a and y. so ay\nInner-----bx\nLast-----last terms in the binomials. so 'by'\nthen add all the terms.\nax+ay+bx+by\n\nyou may consult me
795656
The first thing you should remember is the phrase PEMDAS.  This is shorthand for parenthesis, exponents, multiplication/division, and addition/subtraction.  This is the order of operations in math.  You should solve all equations in this order.  So for the first one, you should first distribute (multiply) -7 with (3-3x).  After that combine like terms, i got 25x -30; you can also factor that to be 5(5x-6).  The same steps apply for the rest of the problems.  I hope it helps.
979117
From a table -- see which y-value corresponds to x=0\nFrom a graph -- see where the graph crosses the y-axis\nFrom an equation -- get the equation in y=mx+b form; the y-interecept is b
363348
Are we solving for x?
699742
-(3x+y)(3x-y)\n-(9x^2-y^2)\ny^2-9x^2
813994
the first one is (x+10)(x+8)\nand the second one is your second answer
67171
Use the distributive property:\n4*5x + 4*(-9) =24\n20x + -36 = 24\n      +36   +36\n20x = 60\n--------\n20    20\nx=3\nI realize you already have the answer but sometimes the path is more important than the destination...
945604
1.adding-2f-7\n-6f-2f+7-7<2f-2f-9-7\n-8f<-16\ndividing by -8\nx>2\n\n2.5/8g-4>2/3g+6\nadding 4\n5/8g>2/3g+10\nmultiplying by 24\n15g>16g+240\nadding -16g\n-g>240\ndividing by -1\ng<-240\n\n3.sum incomplete\n\n4.-2 1/9d+3/5<-3 2/9d-4 2/5\n-19/9d+3/5<-29/9d-22/5\nmultiplying by45\n-95d+27<-145d-198\nadding 145d\n50d+27<-198\nadding -27\n50d<-225\ndividng by 50\nd<-5 1/2
505936
What exactly are you supposed to do with this equation?  Are you suppose to graph it, find solutions, factor or what?  You need to be more specific.
1000586
# 1    \n(x+1)*(x+6)=x2 +x+6x+6=x2 +7x +6\n#2\n(y-6)*(y-5)= y2-5y-6y+30= y2-11y+30\n#3\n(a-2) * (a+10)=a2 +10a-2a -20= a2  +8a -20\n#4\n(x-1) *(x+1)= x2 -x+x -1= x2 - 1
731776
simple!!!\nthe answer is : 12x^2\nthe rule of addition intergers with exponents is simple.\nyou just add the whole number (that is 4+8) and then follow the integers (that is x^2)... get my point?\ni hope i have helped you with your assignment....
602540
x + 3 >  8 ==> x >  8 - 3  ==> x > 5\nx - 4 < -2 ==> x < -2 + 4 ==> x < 2\n\nAnswer... not possible.