What are consecutive Numbers?
402695
consecuitive numbers are numbers that come in a row or in a pattern.  1,2,3,4  consecutive numbers   2,4,6,8 consecutive numbers in the pattern y+2 understand?
47484
Y=X+1 (consecutive numbers)\n4Y=3X+23\n4(X+1)=3X+23\n4X+4=3X+23\n\nTherefore:\n\nX=19\nY=20
947933
The answer is 4.\n11 is eleven, which has 6 letters, so the next number is 6.\n6 is six, which has 3 letters, so the next number is 3.\n3 is three, which has 5 letters, so the next number is 5.\n5 is five, which has 4 letters, so the next number is 4.\n4 is four, which has 4 letters, so the next number is 4. It's all 4's from there!\n\nBy the way, 4 is the only number that has the same number of letters as its value, and if you start this sequence at any whole number, you will end up at four! Just a tidbit I knew! ^_^
1063322
three consecutive even integers are\nx, x+2 and x+4\n\nEquation is\n2((x+2)+(x+4)) = 6x - 12\n\nSolving for x\nx = 12\nSo, 12, 14 and 16
576839
7 consecutive times\n\n1999-2005
1172244
I don't know where this law of numbers came from....\n\nBut...\n\nMaybe what it should say is..."Any odd number with any given power can be expressed as a difference of one consecutive set of two perfect squares."...since that statement is true...\n\nThe difference between two consecutive squares is, in fact, the sequence of odd numbers.\n\nThis is interesting too, because all prime numbers will be included in this sequence, except for 2.
345220
Let x = first integer, then x+1 = second integer.\n(We use x and x+1 because consecutive integers always differ by one.)\nThree times the smaller means 3(x) = 3x\nThree times the smaller is added to four times the larger means add 4(x+1) to 3x\nThe result is 60 means to set it equal to 60.\n3x + 4(x+1) = 60\nDistribute the 4.\n3x + 4x + 4 = 60\nCombine 3x and 4x\n7x + 4 = 60\nSubtract 4 from each side.\n7x = 56 \nDivide both sides by 7\nx = 8\nThus, the integers are 8 and 9.
940770
smaller=x\nlarger=x+2 (consecutive even integers)\n\nx+2=2x-10\n12=x\n\nsmaller=12\nlarger=14
913215
The third answer (from samoht14) comes closest to answering this question.  From it you can see that you need to find a value of x so that 2*x + 1 is equal to the odd number.\n\nso, given an odd number, subtract 1 and halve the result to get x.\n\nThen x and x+1 are the numbers you want.\n\ne.g. for 37, \n36/2 =18 and so the consecutive integers are\n18 and 19.\n18 + 19 = 37
649881
4) n is even.\nStarting with an even number (0) and ending with an even number, means you have an odd number off roots.
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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49\n\n6 f the above numbers
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Let the numbers be n and n+1 (consecutive)\n\nthen the answer is 2n(n+1)\n\nYou know, I can tell you're really trying, (not just fishing for homework answers) because you didnt ask the whole question, just the part you needed help with setting up properly.\nGood Luck!
424362
Problem #1:  Four consecutive integers have sum of -34.  Let the first integer be x.  The next three must be x+1, x+2, and x+3.  This gives you the equation\n\n-34 = x + x+1 + x+2 + x+3\n-34 = 4x + 6\n-40 = 4x\nx = -10\n\nSo, the 4 consecutive integers are -10, -9, -8, and -7.\n\nProblem #2:  Again, four consecutive integers can be written as x, x+1, x+2, and x+3.  This time the equation is:\n\n4(x + x+3) = 24 + 6(x+2)\n4(2x + 3) = 24 + 6x + 12\n8x + 12 = 6x + 36\n2x = 24\nx = 12\n\nSo, the 4 integers are 12, 13, 14, and 15.  \n\nIt pays to check your answers:  The sum of the first and fourth is 12+15=27.  Four times this sum is 108.  6 times the third integer is 6*14=84.  108 is 24 greater than 84.
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differences between consecutive primes\n\n3-2 = 1\n5-3 = 2\n7-5 = 2\n11-7= 4\n13-11 = 2\n17-13 = 4\n19-17 = 2\n23-19 = 4\netc.
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The numbers give the next in the sequence, for example 3692 is 369*2 and that is 738 and so on.\n\n369 x 2 = 738 || 73 x 8 = 584 || 58 x 4 = 232 || 23 x 2 = 46\n\nYour final answer is 46.
943885
if you take the numbers one-by-one: 25! / ( (25-1)!*1! )\n\ncombination from n numbers taken by k:  n! / ( (n-k)!*k! )\n\nfor example:\n    -25 numbers, taken by 7: 25! / (18!*7!)\n    -25 numbers, taken by 4: 25!/ (21!*4!)
688342
There are 24 possibilities to have 3 consecutive letters.\nThe total possible ways of typing any 3 letters is 26^3.\nAnswer: 24/26^3 = 24/17576 = 3/2197 = .001365498407