there is a hutch with some rabbitsin each of the rabbits sits in a corner and can c 3 rabbits how many r there
412888
Wow, what school do you go to?????  Maybe they ought to teach you how to write.....
233027
There are 8! different arrangements (permutations) of the 8 friends.\n\nThere are 4! different arrangements of the 4 boys.\n\nThere are 5 different locations where the leftmost boy can sit when the 4 boys sit together.\n\nTherefore, there are 5*4! (or 5!) arrangements of the boys where all the boys sit together.  But there are also 4! arrangements of the 4 girls in the remaining slots.  So there are 5!*4! arrangements where the 4 boys sit together.\n\nSince there are 8! arrangements overall, the probability of all boys sitting together is (5!*4!)/8!.\n\nSimilarly, if the boys sit to the left and the girls sit to the right, then the probability is (4!*4!)/8!.\n\nInterestingly, this last answer is also the same probability as boy-girl-boy-girl-boy-girl-boy-girl and also the probability of girl-boy-girl-boy-girl-boy-girl-boy.  Therefore, the probability of alternating seats is (2*4!*4!)/8!.\n\nRecall that n! (read n-factorial) is n*(n-1)*(n-2)*...*3*2*1.
70246
2 cats, 2 dogs, 2 hens
421086
At the end there are 8 x 13 = 104 guppies.\nHalf of it came from Benny. Then Alice had 52\nBefore she had 11 more.\nSo she started with 52 + 11 = 63 guppies.
518990
perhaps you should improve your question to get improved answers, but based on what you have asked, I would assume it's a simple probability box situation, and the answer would be 7! which equals 5040.\n\nYou have seven books, and seven possible places\n\n{1} {2} {3} {4} {5} {6} {7}\n\nyou can arrange those in 7 different places, ie:\n\nin your first row, you can have either books 1-7, in row two you can either have books 1-7, less the book you already included, this gives the following breakdown:\n\n7 options (any book any where)\n6 options (any remaining book anywhere)\n5 options (any remaining book anywhere)\n4 options (any remaining book anywhere)\n3 options (any remaining book anywhere)\n2 options (any remaining book anywhere)\n1 option (remaining book only has one place)\n\nTherefore:\n\n7*6*5*4*3*2*1 = 7! = 5040.
973728
There are 6 men. Each man is carrying 6 baskets. Each basket contains 6 cats, each cat has 6 kittens. How many Legs are there all together?
118749
None because a woodchuck can't chuck wood. Heres one for you:\n\nWillie went to Williamsburg because his wallaby was wobbling and his wife was worried. How many w's are there in all?\n\nThe answer is none. There is no w in all.
667073
Let x = number of boys and \ny = number of dogs, then\nx + y = 40 and\n2x + 4y = 100\nDivide the second equation by two and then subtract it from the first\nx + y = 40\nx + 2y = 50\n-y = -10\ny = 10\nx + y = 40\nx + 10 = 40\nx = 30\n30 boys, 10 dogs
30747
2 cubes have 16 corners (since each cube has 8 corners)\n\na cylinder doesn't have any corners
1139646
small game. rabbits, small birds.
822575
buy a tape that has the rabbit in destress sounds on it from bass pro lay it down in a field make a blind you can hide behind . foxes coyotes will come out of the wood work looking for a free meal. i had a ball shotting them
708865
1.  Yes\n2.  Yes, 3 cats, 2 dogs, Yes\n3.  Dogs\n4.  No\n5.  No\n6.  False\nAge - 44
966876
Because some of them are called rabbits. You know, like Catholics.\n\nWord.
739475
A simple 8!\n\n8 choices for the first horse\n7 choices for the 2nd horse\n6 choices for the 3rd...\n...\n2 choices for the 7th horse\n1 choice for the last horse\n\n8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40,320 ways\n\nThis assumes that left and right arrangements are different.
1081057
You have to feed your rabbit three times a day, don't forget.  And give him some warm milk sometimes.\n\nGoats are different....\n\nWait, what was the question?
696944
It depends on what kind you have.  I used to have 4 different rabbits... The himalayan ones are really nice but really freaky looking! If you want one, that's the one I'd suggest!
835178
x+y=74\n2x+4y=196\n2x+2y=148\nsubtracting\n2y=48\ny=24\nsub x=50\nso 50 humans and 24 horses