Multiply (p+2)p^4 - 2p^3 +3?
408254
p^5 +2p^4 -2p^3 + 3\n\nNote: P times P^4 is P^5, b/c when you multiply exponents, you add the exponential numbers.  Since P is really P^1, 1+4 = 5, giving you P^5.
216863
((4 * 4) / 4) - 4 + 4 = 4
681236
Multiply each term in the first () by each term in the second ():\n\n2x times 2x = 4x^2\n2x times 1 = 2x\n-3 times 2x = -6x\n-3 times 1 = -3\n\nThen combine 2x and -6x\nAnswer: 4x^2 - 4x - 3
346216
4p+9+(-7p)+2\n\nGroup the p's and the numbers\n\n(4p - 7p) + (9 + 2)\n\nSimplify\n\n(-3p) + (11)\n\nANSWER : -3p + 11
1053464
if you want to simplify it \n\nit is 3x - 4x + 4 = -x + 4
530727
138.12 divided by three multiply by 2
843483
using (x+y)^3 = x^3+3x^2y+3xy^2+y^3\n\nwe get (2a+b)^3 = 8a^3+12a^2b+6ab+b^3\n\n(ab+c)^3 = a^3b^3+3a^2b^2c+3abc^2 + c^3\n\n(6ab-c)^3 = 216a^3b^3-108a^2b^2c+18 abc^2 - c^3
219026
x^3+4x+1\n\n(3x^4+2x^3+12x^2+11x+2)=\n=(3x+2)*(x^3+4x+1)
1053403
Write it as:\n2x^2-4x+3x-6\n=2x[x-2]+3[x-2]\n=[2x+3][x-2]\nSimple middle-term factorisation!!!
720161
Yes, I can:\n4! + 4 \n=\n(4 x 3 x 2 x 1) + 4 = 28\n\n(BTW, 4squared + 4squared = 32)
944695
12 * (3-e^-3x)^3 *  e^-3x
665603
you put (x+2) in for x in the equation first\n\n((x+2)^3)+(2(x+2)^2)-4\n\nthen simplify \n\nx^3 + 8x^2 + 20x + 12\n\nand multiply the entire thing by 3\n\n3(x^3 + 8x^2 + 20x + 12)\n\n3x^3 + 24x^2 + 60x + 36
8373
(([(4+4+4).(4+4)]+4)/4)*(4+4)\n\n(4+(4*4)).([(4+4+4).(4+4)]+4)
531205
2 + 2 = 4\n\nthats all I got
695176
6x^2-3x-4x+2\n3x(2x-1)-2(2x-1)\n(2x-1)(3x-2)
87719
x^2 + 9x + 10x + 90\n\n(x + 9)(x + 10)
36273
(A^3 + B^3)=(A+B)(A^2 - AB + B^2)