can we break up the H20 molecule into smaller sizes?
400308
Didn't you just ask this?\n\nThe H2O molecule can be broken into component atoms (H and O) under the right conditions, yes.  Smaller than that and you'll need a heat source like the Sun to create a plasma, which breaks the atomic nucleii into protons, neutrons, and smaller particles.\n\nOtherwise, H2O can form H+ and OH- ions, or H2 and O2 gas.
710756
Say away from H20 and LIGHT
854398
When the two glucose molecules join, two hydrogen and one oxygen atoms are released, so I think the answer to your question is that the larger molecule is the maltose and the smaller is water (H2O).\n\nHope this helps - now get on with your homework!!  ;-)
180938
ex: 2 hydrogen atoms and 1 oxygen atom combine to create 1 molecule of H20(a chemical change).
231898
There are a few isomers possible.\n\nEssentially there are two C's double-bonded, with either 2H's off one C and 2Br's off the other C.\nOr 1H and 1Br off each C
882835
Probably carbon latice structures, like buckeyballs or nanotubes.  These could then contain the smaller compounds that are doing the desired work.
968424
divert a huge Ice Comet into the planet?\n\nOr truck a metric butt-ton of hydrogen and oxygen there (frozen of course to bring the most amount in the smallest space) and burn the hydrogen with the oxygen to create seas of nice H20
234679
It would slightly lower the melting point since the introduction of the food coloring molecules disrupts the hydrogen bonding network of H20 molecules
310547
because when oxygen and hydrogen are put together into the compound H20, they become a substance completely different from either oxygen or hydrogen, and take on new characteristics
1057280
both cohesion and polarity of H20
924166
yes u can. use the equation E = hf where E is the energy and h is the planck constant. once u find f which is the frequecy...insert into equation velocity = wavelength x frequency...assuming u noe the velocity of the hydrogen!! :)\nOH but by the way since ur answer is in kj/mol u need to convert it to kj with the avogadro number which i forget...i'm sure u can find out!
525685
You can approach this is one of two ways:\n\n1)  By analogy with H2O (because O and S are both in the same group)\n\n2) From first principles ie octet rule, Lewis diagram, hybridisation, shape. \n\nNow S has 6 electrons in outer shell, while H has 1 each, therefore, S will share 1 e- from each H to complete its octet and each H will share an e- with S so H (which is too small to have 8e-s in outer shell) will have a full outer shell. So S is now covalently bonded to to H atoms, accounting for 4 e-s, with 2 non-bonding pairs. That makes 4 pairs of electrons around S all together, so hybridisation is sp3. Shape is tetrahedral minus two vertices ie bent (just like H2O).\n\nI hope this helps.
224679
No, because you can always make something smaller. Although lengths shorter that the Planck length (1.62e-35 meters) don't make physical sense.
1147215
Suppose we have pure HTO and DTO. The molecular masses are 20 and 21 compared to 18 for H2O. The density is therefore 20/18 = 1.111 g/cm3 and 21 / 18 = 1.167 g/cm3 respectively.
602846
<H1>big</H1>  <H6>small</H6>
311126
I'm not exactly sure what you're talking about, but yes, water can be separated into hydrogen gas (H2) and oxygen gas(O2). It's the following redox reaction.\n\nreduction: 2e- + 2H+ + H2O --> H2 + H2O\noxidation: 2H2O --> O2 + 4H+ + 4e-\n\nMultiply the reduction reaction by two and add the two together to get the final reaction.\n\n2H2O --> 2H2 + O2\n\nThe hydrogen goes down from a +1 state to a 0 state, and the oxygen goes up from a -2 state to a 0 state.
804090
ooo this will be fun!\n\nok..\nA)\n2.207g of H2O MW. 18.0\nmol = weight of sample (g) / molar weight (g/mol) (n=m/M)\nn = 2.207 / 18\nn = 0.1226 moles of H2O\n\nnow, since there is 2 hydrogens in H2O, then when the molecule is broken down, there is twice as many moles of hydrogen then the overall molecule,\ntherefore,\n\n2x 0.1226 = 0.2452 moles of H.\n\ndetermining number of moles of CO2 is also helpful,\n4.313g, n = 4.313 / (12.01 + 16 +16) = 0.0980moles\napprox, 5(moles H2O) :  4(moles CO2)\n\nB) \nworking the number of moles of this compound will be useful:\nn = 1.816 / 74.122 = 0.0245 moles, which is 1/10 of the moles of H produced. (or 1:5 of the moles produced of water)\n\nif you think about it, the reaction is something like this:\nCH2 + O2 --> CO2 + H2O\nclearly the above doesn't make sense, because 1) it isn't balanced, and 2) the reactant needs a higher molecular wt.. now thinking about it, the following can be deteremined:\nand from the ratio of moles found above:\n       1     : (excess):  4        :    5\nC4H10 + 13/2O2 --> 4CO2 + 5H2O\n\nnow, I amoung most allow fractions in equations, but if you don't, multiply through by 2.\n2C4H10 + 13O2 --> 8CO2 + 10H2O\n\nnow, you want the empirical forumla,\ntherefore,\ndivide by highest common factor,\nC2H5 \n\nthe empircal fomula is just a ratio and doesn't make huge sense, as the formula for an alkane is CnH2n+2\nhope that makes sense :)