Newton's third law of motion?
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Ya it actually verifies the Newton's laws.\n\n>> As per Newton's 1st law of motion, an object continues \nto be in its of rest or of uniform motion unless acted \nupon by an external force.\nIn that ad, the objects were in rest but when some object\nacted upon them, they came to motion.
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newtons are the unit of force.  the second law of motion says that F=ma, where F is the force, m is the mass and a is the acceleration of the mass.   so, you need to know the acceleration!\n\nif you are talking about an object on earth, then the acceleration is "g", which is 9.8 m/s^2.  so multiply the mass times that acceleration to get the force with which gravity pulls on that object, in newtons.
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A force at its most simplistic is a push or a pull. According to Newton's laws of motion, when something is at rest or travelling at constant velocity, there is NO force acting on it. \n\nNewton's second law states that Force = mass x acceleration which means that a force causes a _change_ in velocity (acceleration). So for continuing motion, there is only a force when there is acceleration.
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This is not Newtons third law. the two forces you mentioned does not form action reaction pair. they act on the same body. Newtons third law in this case is : action : force of gravity exerted by the earth on the book , reaction : force of gravity on earth by the book. and action : normal force on the book by the table , reaction : force exerted by the book on the table in the downward direction
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From..umm.. one of newton's laws (I don't remember which one now):\nSum of forces=mass*acceleration\nwe want to find the acceleration\n\ntwo forces apply on the mass, weight and friction\nforce due weight= mass * gravity * sin(25)\n                           = 22 * 9.8 * sin (25) = 91.12 N\n\nforce due friction= mass * gravity * cos(25) * fric. const.\n                           = 22 * 9.8 * cos (25) * 0.2 = 39.1N\n\nback to newton's law:\n-force due weight-force due friction= mass * acceleration\n\n(negative signs because forces act opposite to movement)\n\n-91.12-39.1=22*acc.\nacc.= (-91.12-39.1)/22 = -5.92 m/s2\n\nfrom the third law of straight motion under constant acceleration:\n(final velocity)^2 = (initial velocity)^2 +2 * acc. * distance\n\nwe want to find distance\nfinal velocity=0 (mass stops and reverse it's direction)\ninitial velocity= 3.9 m/s\nacc.= -5.92 m/s2\n\n0 = 15.21 + 2 * (-5.92) * dist\ndist. = -15.21/(2 * -5.92) = 1.28 m\n\nhope i didn't make any mistakes.
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A body in motion stays at that same velocity unless acted on by an outside force (Newton's laws of motion). So the sum of the forces acting on the book is zero since the velocity is constant. Since you are applying a one newton force in the horizontal direction, and friction is the only other force acting on it in the horizontal direction, the force due to friction must be one newton in a direction opposite to the force you are applying.
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* 1 Newton's first law: law of inertia\n* 2 Newton's second law: An applied force is equal     to the rate of change of momentum.\n* 3 Newton's third law: law of reciprocal actions\n\nClick the link and read all about it.
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ahh, good theory problem...\nlet's see, there's energy, friction, force (normal, tension, as well as the other ones mentioned), gravitation, mass, pendulum motion, gotta be more that I've missed, but no doubt someone'll be here to correct me.
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Third law\n    To every action (force applied) there is an equal and opposite reaction (equal force applied in the opposite direction).\n    Another way of stating Newton's third law, an interaction between two objects, is that, if object A exerts a force on object B, object B will exert the same magnitude force on A, but in the opposite direction.
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If an object is moving at a constant velocity, then the acceleration of that object is zero (acceleration is the measure of how fast the velocity is changing, if the velocity is unchanging, acceleration must be zero). By Newton's Second Law, if the acceleration of an object is zero, the net force on that object must also be zero.\n\nNewton's First Law also mentions this concept. Once an object is in motion it'll keep moving at the same velocity forever unless a force acts on that object. Now there must be some force acting on the object initially to get it moving, but once it's moving you can cut off all the forces on the object and it'll go forever (not really a practical experiment though since there are always forces like friction and gravity that cause the motion to stop).
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I concur with previous answerer. The acceleration is 1.5 m/s^2. Rearrange Newton's Second Law, to solve for the acceleration. Then, substitute what you know.
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Forces occur in pairs. Newtons third law.\nIf this is the case the forces exist as equal and opposite.\n [Fo ]=[-Fi]\nNet force = Fo minus Fi= zero!\n  Moving forces can be directional and vectorial.\nAlso they change continueously during the motion till they Atenuate at the end of their cycle.To identify the force you have to identify the power that has cause the motion of the mass and the direction of interaction. The power causing the motion is always equal to the magnetude of the force multiplied by the the speed that the force moves.\n\nCurvilenear motion indicates that the power of two moving masses interact and cause the two masses to move around a common pivot point. Thus the masses are locked together into an orbit forming a composite mass structure.In that case the moving masses experience a curved path.\nThan you have to understand what is  a circle. A circle consists of an infinite integral of short straight lines, and each straight line having different direction.\n\nDont feel bad if you cant fully understand why. . I dont find it easy myself.
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Haha whats with all these answers, if you know basic physics, One of Newtons laws of motion is that:\n\n"for an object that is stationary or travelling at constant velocity, no force acts."\n\nso you ask what is the force?\nthere is no resultant force, the driving force and resistance are equal and cancel each other out.\n\n\nAnd additionally the basic equation to find force is:\nF=ma (force = mass x accelleration), this is evidence that an accelleration needs to be taking place for a force to act.\n\nLets say you want the force for a 50kg object accellerating at 3ms-2. F=ma  ->  F=50x3 ->  F=150N.\n\nNow lets say you want the force for a 50kg object travelling at constant velocity, no accelleration.\nF=ma  ->  F=50x0  ->  F=0N\n\n\nThere you go, wasnt that easy
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Newtons, or sometimes kilograms
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In kinematics, the 3rd time derivative of position x(t) (x'''(t)) gives the rate of change of acceleration with respect to time (da(t)/dt). It is also known as jerk. This quantity is relevant in the context of problems involving rockets that have a mass that changes with time.
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well figure out the net force with F=ma and just subtract. like just say 93 x .26 is the net force, the force thats acually being used for motion. so you subtract this from 36 to see what force is opposing this. so the total equation is:\n36 - (93 x .26)