How do you find the equaion when you are given the points and the slope?
412013
Slope = rise over run\n\nrise = y1 - y2\n\nrun = x1 - x2\n\nexample...  slope of line from (1,1) to (10,5)\n\nrise = 1-5  = -4\nrun  = 1-10 = -9\n\nrise/run = -4/-9 = 4/9\n\nM (slope) = 4/9\n\nPART 2:\n\nperpendicular lines will have inverse slopes...\n\nfor the line above... the inverse slope is -9/4.  Instead of rising 4 for even run of 9, it will fall 9 for even run of 4.\n\nNegitive slopes go down in respect to left to right, positive slopes go up from left to right.\n\nParrellel lines will have the exact same slope.\n\nPART 3:\n\nHorizontal lines have slopes of 0/10 (10 can be replaced by any number)... this works out to be a slope of 0 (zero) for any horizontal line.\n\nVertical lines have no slope (not zero!)  you simply put no slope for any answers asking about the slope of a vertical line.  Going back to the rise/run equation... rise = 10 (can be any number)... run = 0... any number divided by ZERO is impossible... thus there is no slope.
826422
Find the slope of the line that connects those points.
97021
Using the points you can work out the slope. That is 0.\nThen use one set of points and the slope to work out the equation of a line formula which is:   \n         y-y1=m(x-x1)\nm is the slope \n       y+4=0(x-11)\n       y+4=0\n       y=-4
454789
y=mx+b\n\n"m" is the slope, and "b" is the y axis. Best wishes in your studies!
856807
Yes that will be correct because after you isolate the (y) in other words put it in slope inercect form it would be \ny=2x+4 \nm=2\nb=4
917007
Well, you need two points to define a line (or one point and a slope).  There are infinitely many lines through the point (7,5).  So just pick one:\n\ny=x-2\ny=2x-9\ny=3x-16\ny=4x-23\n...
929126
The first thing you want to do is find the slope. That is, the change in Y over the change in X (Rise over Run). Each of these points are in the cartisian coordiante system, thus (3,-7) and (-5,2) are of the form (x,y). So lets find the slope!\n(y1-y2)/(x1-x2)\nUsing (3,-7) and (-5,2)\n(-7-2)/(3+5)=(-9/8)\nYour slope is (-9/8)\nNext to find the intercepts you use the equation of slope intercept form, Y=mX+b where X and Y are points, m is the slope and b is the y intercept. We know the slope and some points so we need to solve for b., the y intercept. Lets use the point (-5,2).\n2=-5(-9/8)+b\n2=(45/8)+b\n(-29/8)=b\nSo the point for the y intercept is (0,-29/8)\nNow we want to find what x is when y is zero for the x intercept. \nAgain use Y=mX+b but this time we know what b is. Set y=0. \n0=X(-9/8)+-29/8\n29/8=X(-9/8)\n29/-9=X\nThus, the x intercepts is (29/-9,0)
1088871
50 because if you rearrange it in the format of y=mx+b with m being the slope it would equal to 50 in your case
845789
the formula equation for point-slope form is:  y-y1= m(x-x1)...the person that answer b4 me is a dipsh*t......\n\nall u need to do now is substitute (plug-in) the given info....\n\ny-5= m(x+4)\n\nto find m (slope)...well f*ck it, ill do it for you...\n\nm=-3/10\n\nTHEREFORE:  the final point slope equation that passes thru (-4,5) and (6,2) is..... y-5= -3/10(x+4)\n\n\nyour welcome
1106036
Rise over run, or (y2-y1)/(x2-x1).  If your first point was (x1,y1) and your second point (x2,y2), then it's easy:\n\n[8 - (-4)] / [14 - 10] = (8+4)/(14-10) = 12/4 = 3\n\nThe slope of the line is 3.
194847
Im not gonna give u the answer, coz u wont learn otherwise, but i can tell you how to solve it...\n\nWell, remember that the standard equation for a line is \n\ny = mx + c\n\nwhere m is the slope of the line... Now, there is a relation between the slopes of two lines if they are parallel, look it up yourself...\n\nSo u have the slope of the line whose equation u need to find... U also have a point thru which it passes... Another representation of the equation of a line is...\n\ny - y1 = m(x - x1)\n\nwhere x,y are the variables for the eqn, m is the slope of the line, and x1, y1 are the (x,y) co-ordinates of a point thru which the line passes...\n\nYouve got all the stuff, throw it in, and wolla...
743965
If you can find the slope, you use the formula\n\ny - y1 = m(x-x1) where y and x are in general and y1 and x1 are the x and y values from ONE point. Pick either, it doesn't matter. So...\n\nThe slope is -2.\n\ny - 8 = -2 (x - - 2)\n\ny-8 = -2x - 4\n\ny = -2x + 4
706345
slope = -5-1 / -2-(-3) = -6/1 = -6\ny-1=-6(x+3)\n.
963751
find the first derivative for the curve, and then substitute the x coordinate for the slope at that point.\n\nfor example, for the graph y = x^2, the first derivative is 2x. to find the slope at where x = 1, sub x = 1 into 2x and the slope at that point is 2.\n\nalternatively, draw a tangent to the point where u want to find the point slope and the slope of the tangent is the point slope. note that this method's accuracy depends on how accurately you draw your tangent
35268
slope = (-4-(-6))/(-2-0)\nslope = -1
746991
the slope is 4\nwhen an equation is in standard form:\ny=mx+b\nm (which is the coefficient of x) is the slope
1101719
Step 1: Find the slope of the line x-2y = 2.  Call it m. \n\nStep 2: Find the derivative f'(x) of the function f(x) = (x-1)/(x+1).\n\nStep 3: Find all values of x where f'(x) = m.\n\nStep 4: For each such value, find its corresponding y-coordinate by setting y=f(x), and then find the equation of the line that goes through that point with slope m.\n\nGood luck!