What is the domain and range for the given graph?
413913
x=0,2,3,4 and y=1,-1,0,3
799995
range can have two different meanings:\n\n  1. in a set of numbers, range is the difference of the largest number and the smallest number\n  2. in a function, such as domain and range, range refers to the output or y
893324
domain:  from - infinity to + infinity  (that's for x)\n\nrange: 0 to infinity (for y)\n\ny = |x+4|
863968
-3x^2+24x-49\ndy/dx=-6x +24\n-6x+24 =0, so x=4 \n\nSo the max occurs when x=4. ( We know it is a max because the coefficient of x^2 is negative.)\nso the max is -3(4^2) +2*4-49 = -48 +8 -49= -89\nThis means that the range (possible values of y) is all the real numbers =< -89 . Because -89 is the max value. In interval notation this is - infinity <y<= -89.\n\nThe graph is a parabola which is increasing upward until it hits the max when x = 4 and then decreases forever\nThus f(x) is increasing over the interval - infinity <x<4  and it is decreasing over the interval 4<x< + infinity. At x =4, f(x) is neither increasing or decreasing.\n\nThe vertex is located at (4, -89)\n\nSince f(x) is never positive, it never crosses the x-axis and thus has no real roots. The two roots are imaginary.\n\nI think that covers all your questions.
812091
On 1 graph you could put age(x) and height(y).....and on another graph, you could probably put age(x) and weight(y)......I think :)
995228
Domain:  All the values of x that provides a defined value of y.  In the equation above if we plug 0 or less than 0 for x, we get an undefined answer.  Thus the domain is x>0.  \n\nIntercepts:  To find intercepts we plug y equal to zero and then solve for x.  So, lnx/x = 0\n                          lnx = 0\n                             x = 1\nThus the intercept point is (x,y) = (1, 0)\n\nAsymptotes:  An asymptote is a straight or curved line which a curve will approach, but never touch.  By looking at the graph of lnx/x, we can conclude that the graph approaches y = 0 but never actually touches 0.  So, the asymptotes is y = 0.  \n\nCritical point:  In mathematics, a critical point (or critical number) is a point on the domain of a function where the derivative is equal to zero. It is also called a stationary point.  Derivative of above function is: \n                        dy/dx = [(x)(1/x)-lnx](x^2)\n                           0 = (1-lnx)/(x^2)\n                           0 = 1-lnx\n                           1 = lnx\n                            x = e\nSo, the critical point is x = e.
980349
Domain:  all real numbers\nRange:  [2, positive infinity]   (all real numbers from 2 to positive infinity)
668045
The only finite region bounded by those graphs is between the only two points at which they intersect, (0, 0) and (1, 1). f(x, y) = x + y is a plane x + y - z = 0 that passes through the origin. Note that in R, y=x^2 is below y=x with respect to the x-axis.\nNow that we have our bearings, we simply decide the boundary of our region and integrate over it. We are integrating from x=0 to x=1 and from y=x^2 to y=x the form x + y dy dx.\nIntegrating with respect to y first, we get the form xy + (y^2)/2 evaluated from y=x^2 to y=x which is (3/2)x^2 - x^3 - (x^4)/2. Integrating this form with respect to x gets us (1/2)x^3 - (x^4)/4 - (x^5)/10 evaluated from x=0 to x=1, which is just 1/2 - 1/4 - 1/10 = 3/20.
795982
∫_0_2 g(t) dt = 5\n\n(a)\ny= ∫_0_4 g(t/2) dt\nlet t/2 =x ; so dt = 2dx; and the range becomes x:0 to 2\nso, y= ∫_0_2 g(x) 2 dx = 2  ∫_0_2 g(x) dx = 2 * 5 = 10\n\n(b)\ny= ∫_0_2 g(2-t) dt\nlet 2-t=x; so dt = -dx; range becomes x:2 to 0\ny= - - ∫_0_2 g(x) dx = 5
727463
A graph is a way to visually show the relationship of different numerical values - there are lots of different types of graphs:  Pie, line, area, bar, etc.\n\nCheck out this site:\n\nhttp://nces.ed.gov/nceskids/createagraph/
493069
First :\nSince f is continuous over its domain (R),\ndf/dx = 5 x^4 +2 > 0 for every x\nSo f is an increasing function over its domain\nHence for every value of y their exist a unique value of x\nHence f has an inverse and one-one function\n3- Use function graph to graph f-1 as you mentioned\n(df^-1/dx) (2)= the slope of the tangent to f-1 at x=2\n6- (1,2)\n7- 7\n8- 1/7
788027
The graph is a V.  From the 0,0 draw a line with slope = 1 to the right of the y axis and draw a line with slope = -1 to the right of the y axis.  For y<|x|.  All you have to do is shade in the area below the V.  If y>|X|, all you have to do is shade in the area above the V.  Less than, shade below; greater than, shade above.  That should answer all the questions you've submitted.\n\nAnd no, absolute values do not form parabolas.  Some do, not all.  Like y = sqrt[|x-1|].  This forms 2 graphs each going away from each other.\nNice going NerdyKid.  You're not a nerd, you're a dork.
979117
From a table -- see which y-value corresponds to x=0\nFrom a graph -- see where the graph crosses the y-axis\nFrom an equation -- get the equation in y=mx+b form; the y-interecept is b
952602
This is what always helps me.\n\nA function is a machine.\n\nThe domain is everything you can put into the machine so that it doesn't break.\n\nThe range is everything you can get out of the machine.\n\nIn the case of your function, there's only one possible value of x that will "break" the function, in the sense that you'd get an infinite answer.  That value is x=0, because then you'd have 9/0 + 7, and 9/0 is infinity.\n\nSo the range is {x | x is not equal to 0}.\n\nAssuming that you meant 9/x + 7, rather than 9/(x+7).  If you meant the latter, x cannot be equal to -7.
838358
i can't give you the answer but i used my ti-83 and i can tell you the points of the graph...\n(1,0) (2,4) (3,8) (4,0)\n\nHope this helps
1071351
domain is the spread for the x values\nrange is the spread for values\nrelation is like a function that ties y to x.\n\nExample: Let  y = sqrt(x)\nas we know that x cannot have negative values but it can have values of 0 or any positive number\nSo, your domain is [0,infinity) or any numbers above 0 and including 0.\nIf x is 0 then y is 0 and if x is a huge number then y is a huge number. Since square roots do not give negative answers, y value can never be negative. So, your range becomes 0 to infinity or [0, infinity)
337327
assign value for your x-variable...say -10, -5, 0, 5, 10 and repesent it in a graph form...