What is gain in acousitcs?
364223
gain is the first step on the preamp of a sound mixer, you will see the gain control knob as the first knob on top for each channel on a sound mixer.\n\ngain also reffers to the amount of valume, for example i would say "i need more gain" when i'm asking for more valume.
947068
Don't give up too easily on the sound wave thing.  Graphic equalization.  Sound is measured in hertz (Hz) & Kilo Hertz (KHz), Kilo being the metric measure for 100.  Start with the low tones - long wavelengths, low number of hertz.  Move up the tone scale. As the tones get higher pitched the smaller the wave lengths - increased number of hertz. Super highs, like cymbals are in the kilohertz range and so on.  It's an everyday thing that everyone can relate to .  When you hear a siren go by the tone is lower as it approches and higher, faster, as it passes you and back to lower tones as the object receeds.  Good luck.
524937
look here\nhttp://education.yahoo.com/reference/weights_and_measures/index?p=volume
805783
db = 10* log (I2/I1)\n40 = 10*log (I2/I1)\n4 = log (I2;I1)\n\nI2/I1 = 10^4;  the anwer is 10,000 times as intense.\n\nNOTE  in answer to the responses below, if the statement says "intensity" that means the POWER level of the sound,  not the pressure amplitude.  (See the reference).  Therefore the factor of 10 is correct.\n\nQuote: "When referring to measurements of power or intensity it is:\n10log(I1/I2)"\n\nAlso, 0db is an arbitrary reference level, and does not mean zero intensity or ampltude.  In acoustics, 0db refers to a pressure amplitude of 10 micropascals.\n\nIn electrical circuits you have to state whether you are referring to power db or voltage db (BOTH are used).  For example, in rating the output of a power amplifier, the ratings are given in power db, but for a voltage amplifier, they are in voltage db.\n\nEDIT AGAIN, final statement:  it is true that if you measure sound with a SPL meter, the db is 20log(I1/I2).  That is because an SPL meter is a Sound Pressure Level meter.
42153
To explain this, I would have to use many words, so here's a website to sum it up for you:\nhttp://electronics.howstuffworks.com/speaker.htm
83113
Yes the answer is correct. It allows the perception of space. In reality when you hear any sound, you hear the sound that is directly comming to your ears from the source plus the one that is gettind reflected from surrounding objects. It is the Algebraic or Angular or phaser or vector sum of the total. because the all reflected sound waves are not necessarily in the same phase as that of each other.\n\nWhen we produce same sound in home theatre system, from different speakers, but with phase differance from each other, it gives you the Spatial effect, resulting in you feeing like sitting in a large auditorium.\n\nAudio engineers have invented many peciliar combinations of phase differances and weight of each phase to produce vivid sound effects.
107543
I assume you're the webmaster. In W2K you've got a neat utility called SOUND RECORDER (sndrec32.exe), open your background music file, goto EFFECTS select INCREASE VOLUME BY 25%. That ought to do it.
292273
Sound intensity is variously defined as amplitude or displacement (Ref. 1) or power per unit area (ref. 2).\nIf you mean a displacement ratio of 10000, then decibels difference = 20 * log10(10000) = 80 dB for a new total of 160 dB.\nIf you mean a power ratio of 10000, then decibels difference = 10 * log10(10000) = 40 dB for a new total of 120 dB.
91950
To gain control = commandeer,\n\nbut to adjust the gain control= adjust the volume.
930646
You probably want alpha, the common base current gain. In general, current gain is designated "beta," "alpha," or "gamma," for transistors connected in the common emitter, common base, or common collector configurations, respectively.  Beta = di(c)/di(b), the rate of change of collector current with respect to change in base current.  Alpha =di(c)/di(e), rate of change of collector current with respect to change in emitter current.  Gamma = di(e)/di(b), rate of change of emitter current with respect to change in base current.  Also, alpha = (beta)/(beta - 1), beta = (alpha)/(alpha - 1), and gamma = beta + 1.  For a detailed explanation, check out : http://www.tpub.com/neets/book7/25f.htm\n\nAnother possible answer: "amplification factor" for any amplifier circuit, regardless of configuration, or whether it uses tubes, BJTs, FETs, etc, refers to its voltage gain, dv(out)/dv(in), the change in output voltage with respect to a change in input voltage.
906307
From wikipedia:\n\nFor sound intensity, I0 is typically chosen to be 10^−12 W/m2, which is roughly the threshold of hearing. When this choice is made, the units are said to be "dB SIL". For sound power, P0 is typically chosen to be 10^−12 W, and the units are then "dB SWL".\n\nThe value of 56.0 db is derived from the formula\n\ndb = 10*log(I/I0)\n\nFor 56 db, I/I0 = 10^5.6  From the above reference,  I0 = 10^-12 W/m^2;  Therefore I = 10^5.6*10^-12 = 10^-6.4 W/m^2\n\nSince the distance from the source was given in your problem, perhaps it meant "power level" rather than "intensity level".  If that is the case, you would figure the power using the formula\ndb = 10*log(P/P0), just as above, except that P0 is 10^-12 watts.  To get intensity at point A, divide by the spherical area at that point A = 4πr^2, where r = 3.8m
913737
In physics it is acoustics.
888141
For starters, human's by nature are visual learners. This can be explained further by looking into Evolutionary Theory. Although, most of our teaching is completed using lecture, auditory input, most learners are visual learners first and auditory learners second. The audio visual classroom aids give visual learners the stimlus that helps them retain the information. Adding to that the auditory aspect, they can then connect the two forms of communication to allow for the best possible learning outcome. AV aids have greatly enhanced learning for visual learners, who struggled with "getting it" through the traditional auditory instruction/approach.
66925
recieve sound waves and transfer them from the air to the small bones in the ear which change them into electrical signals.
290478
I'm not quite sure, but I think it has to do with replicating sound waves.  It will create reverbrations, or echoes, if you will, on a recording system.  That will simulate the effect of having the state of the art equipment in recording studios.\n\nI got this from the site posted below.\nAcoustic Mirror™\nTake sound processing to a new level with the Acoustic Mirror™. Don't settle for the unnatural effects of artificial reverb units when you add reverberation to your sound files. With Acoustic Mirror you'll add the acoustical coloration of real environments and sound-altering devices to your recordings.\nAcoustic Mirror is the ideal software solution for audio recording studios, mixing and mastering engineers, motion picture and television producers, game developers, and multimedia content creators. You'll expand your creative potential with Acoustic Mirror's extensive library of impulse responses. We collected these extremely high-quality acoustic signatures by measuring many diverse environments over hundreds of hours. Apply our responses to your recordings, or create your own. The result is professional stereo imaging and realism that is uncanny.
186454
Two sound waves of equal frequency have a constant phase relationship so there is a constant amount of reinforcement or cancellation.  If the frequencies differ, the relative phase repeatedly varies between cancellation and reinforcement (total cancellation and reinforcement if the amplitudes are equal) at a rate equal to the difference in frequency.  The resulting sound has an apparent pitch between the two frequencies if they are close enough, or is heard as two frequencies if not, and is "amplitude modulated".  If the amplitudes are high enough, distortion in the ear results in perception of a third frequency ("difference frequency") at the modulation rate.
904995
An attenuater reduces the amout of volume through a medium such as wire or pipe. by a specific amount of decibles per foot. A volume control is an attenuator. There is also a power ratio. for every 3 db in reduction the power is reduced by half.