What is the formula for the CO compound?
363430
Carbon with 3 bonds to oxygen\n\nC-O\n\nwith 3 of the - signs\n\nIt makes carbon monoxide
844628
a) 53.4\n34gCO  x 1mol CO/28gCO x 2molCO2/2molCO x44gCO2/1molCO2 = 53.4gCO2\nThe 2 moles CO cancel the 2 moles CO2 (from the balanced equation).
412530
1) H3COCH3 (or C2H6O) + 3O2 (g) --> 2CO2 (g) + 3H2O (g)\n2) HNO2 (aq) + NaOH (aq) <--> NaNO2 (aq) + H2O (l)\n3) 2K+ + Cr2O7(2-) + Fe(NO3)2 + 2H+ <--> CrO4(-) + Fe3+ + 2K+ + 2NO3(-) \n4) Na3PO4 + NH4NO3 = No reaction, all soluble salts.\n5) 2HCl (aq) + Na2S (s) --> 2NaCl (aq) + H2S (g)
859471
1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 9.630 g x (12 / 44) = 2.626 g\nhydrogen: 4.928 g x (2 / 18) = 0.548 g\noxygen: 4.055 - 2.626 - .548 = 0.881 g\n\n2) convert to moles.\ncarbon: 2.626 / 12 = 0.219 mol\nhydrogen: 0.548 / 1 = 0.548 mol\noxygen: 0.881 / 16 = 0.0551 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.219 / 0.0551 = 4\nhydrogen: 0.548  / 0.0551 = 10\noxygen: 0.0551 / 0.0551 = 1\n\nThe empirical formula of the substance is (C4H10O)n\nThe atomic masses add up to 74, which is also the molar mass of the compound. Therefore n=1 and we find C4H10O
363082
2Ag+ + CO_33-2 -> Ag_2CO_3
697475
1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 7.849 g x (12 / 44) = 2.141 g\nhydrogen: 3.213 g x (2 / 18) = 0.357 g\noxygen: 3.215 - 2.141 - .357 = 0.717 g\n\n2) convert to moles.\ncarbon: 2.141 / 12 = 0.178 mol\nhydrogen: 0.357 / 1 = 0.357 mol\noxygen: 0.717 / 16 = 0.0448 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.178 / 0.0448 = 4\nhydrogen: 0.357  / 0.0448 = 8\noxygen: 0.0448 / 0.0448 = 1\n\nThe empirical formula of the substance is (C4H8O)n\nThe atomic masses add up to 72, which is also the molar mass of the compound. Therefore n=1 and we find C4H8O
15061
K2Cr2O7 + 2Pb(C2H3O2)2 + H2O --> 2PbCrO4 + 2HC2H3O2 + 2KC2H3O2
36042
n-hexanoic acid\n\nThere are a LOT of compounds with that chemical formula.  Check chemfinder.com for more.
813421
Na2CO3(aq) + MgCl2(aq) --> 2NaCl(aq) + MgCO3(aq)
844087
Giving just a number means you learned nothing and just received a correct answer by doing no work.  Here's how it's done.\n\nStep 1:  Write the balanced equation.\n\n(2)C2H6 + (7)O2 ---> (4)CO2 + (6)H2O\n\n*The numbers in parentheses, (), are the coefficients in front of the compounds.\n\nStep 2:  Convert grams of C2H6 to moles of C2H6.  This is done by dividing 172gC2H6 by 30gC2H6 (the molar mass of C2H6).  The answer you get is, 5.73mol C2H6.\n\nStep 3:  Use the balanced equation to go from moles of C2H6 to moles of O2.  This will be done by the following:\n\n5.73moles C2H6 x 7mol O2 / 2mol C2H6 to leave you with, 20.1mol O2.\n\nStep 4:  Use the ideal gas equation to solve for the volume of O2.\n\nP = .9869atm\nV = ?\nn = 20.1mol O2\nR = .08206 L atm / K mol\nT = 285K\n\nThe answer you will get by solving for V and plugging all the numbers in and canceling your units will be, 476.3L O2.\n\nFinal Step:  Convert from L to m^3.  The conversion factor is:\n\n1m^3 = 1000L, therefore you will take 476.3L O2 and divide by 1000, to get .4763 m^3 O2.  This is your final answer.
202502
The answer is very basic. Start with chemical names.  Carbon dioxide is made from carbon and oxygen. Carbon is called C, and Oxygen is called O. If you have two atoms of O, and one atom of C, then you have Carbon dioxide. The shorthand notaion for this is CO2. Don't be afraid of chemical formulas, but bring yourself to be comfortable with them, so you don't freak when you have to do a problem like this:\n__H4C + __O4Fe---->__HCO + __Fe. (this is balancing equations, but they're easy, once you learn to decode what chemical equations are trying to tell you )\n\nOn this website, just look at the ones that are relevant:\nhttp://www.ukrocketry.co.uk/forum/index.php?s=e26325e497d951d76619a79a0ad64ae7&showtopic=381\n\n\n\n\n\nThis si a segment on this from my school textbook: (sorry, its kinda long)\nA molecule or compound consists of at least two atoms that are chemically bonded. The chemical formula of a molecule or compound states how many atoms of each element are in one of its molecules. This formula is similar to an algebraic formula in its use of symbols. The description of a compound with numbers and symbols is called a chemical formula. Some formulae can be quite complex.\n\nQuestions you may have are:\n\nWhat are chemical compounds? \nWhat is the numbering system in a chemical formula? \nHow do you designate complex compounds? \nThis lesson will explain the basics of chemical formulas. \n\nChemical compounds\nA molecule is the chemical combination of two or more atoms. They can be of the same element, such as in the oxygen molecule (O2) or different as in the water molecule (H2O)\n\nA compound is a molecule that is made up of at least two different elements. The water molecule is a compound. When atoms of different elements combine to form a compound, the result is a new substance that has different properties than the original elements. A good example is when the poisonous green chlorine gas is combined with the explosive metal sodium to form the white salt crystals we use in our food.\n\nThe study of Chemistry is mainly interested in the formation of chemical compounds, since there are so many possible combinations of elements.\n\nChemical formulas\nChemical formulas (or more correctly: formulae) are designations of molecules and compounds in shorthand notation, similar to that used in Algebra.\n\nElements can be written as abbreviations or in a shorthand notation. For example, He denotes helium, Fe denotes iron, and Cl denotes chlorine. A chemical formula is writing the elements of a compound, using their abbreviations.\n\nThe combination of two or more elements to form a molecule is designated by writing their abbreviations next to each other. For example carbon monoxide is written as CO. The order in which the elements are written is typically alphabetical, but there are a number of exceptions for historical reasons and to clarify the geometry of the molecule.\n\nIf there is more than one atom of a type in the molecule, the formula shows it by a small number after the symbol. For example, water is H2O, which means there are 2 atoms of hydrogen and one atom of oxygen in the molecule. Carbon dioxide is CO2, which means there is one atom of carbon and two atoms of oxygen in the molecule.\n\nTo show the number of molecules, a full sized number is located in front of the molecule. For example 4 molecules of carbon dioxide is designated as:\n\n4CO2\n\nThis means there are a total of 4 C atoms and 8 O atoms in the combination. A way to remember this—taken from Algebra—is to think of it as 4 x (CO2).\n\nComplex formulae\nJust as in Algebra, you can use parentheses to separate parts in a complex formula. One example is the formula for nitroglycerin, a highly explosive substance.\n\nC3H5(NO3)3\n\nThis formula shows that nitroglycerin consists of 3 atoms of C, 5 atoms of H and then 3 molecules of NO3. If the parentheses were not used, you might have a formula like:\n\nC3H5N3O9\n\nThe number of atoms for each el
407297
I2O5 + 5CO --> 5CO2 + I2
728397
You need to first balance the equation.\n\n2CO + O2 --> 2CO2\n\nUsing this you find the answer to be D.
200262
mono = 1\ndi = 2\ntri = 3\ntetra = 4\npent = 5\nhex = 6\nhept = 7\noct = 8\nnon = 9\n\nnonmetals:\nif there is no prefix for the first element, it is assumes to be one.\nTHe ening of the anion (the second one listed) is changed to -ide.\n\ncarbon - 1 \noxygen - 2\nCO2  <---The number is a subscript, but you cant do that on here\n\nPhosphorous - 1\nIodine - 3\nPI3\n\nHydrogen - 2\nOxygen - 1  (it should be monoxide)\nH2O\n\nHope that helps you.  Don't feel bad; you can't know what you haven't learned.
195778
1.  C(s)+O2--> CO2(g) - 393.5 kj\n2.  H2(g)+1/2 O2(g)--> H20 -285.8 kj\n3.  2C2H2(g)+5O(g)-->4CO2(g)+2H2O(... -2598.8\nCALCULATE the value for the reaction 2C+H2-->C2H2\n\nFirst balance eqn 3 with 5O2 (g) then reverse it so that you have 2C2H2(g) on the RHS. Of course, you will change the sign of the eqn as well. Now halve it so you have one C2H2 instead of 2. Let's call the new eqn number 4\n\nSecond, double the 1st eqn. Let's call it eqn 5\n\nLastly, add eqns 3, 4 and 5:\n\n4 2CO2(g)+H2O --> C2H2(g)+5O2(g) +1299.4 kJmol-1\n5 2C(s)+ 2O2--> 2CO2(g) -787.0 kJmol-1\n3 H2(g)+1/2 O2(g)--> H20 -285.8 kj\n----------------------------------------------\n  2C(s)+ H2(g) --> C2H2(g) + 226.6 kJmol-1
792910
This is not a complete equation. The products will be NaNO3 +  CaCO3\n\nBalance numbers:\n\n1,1,2,1
760322
1. Get the empirical formula of the compound,\nAssume 100g of the compound and get their number of moles.\n\nC: 65.45g/ 12g/mol = 5.454 mol\nH: 5.49g/ 1g/mol = 5.49 mol\nO: 29.06g/ 16g/mol = 1.816 mol\n\nDivide results by the smallest number of moles. You'll get: 3C, 3H, and 1O. Your empirical formula then is C3H3O.\n\n2. Determine the molar mass of the compound using this equation: MM = gRT/PV.\nMM = (4.13g * 62.3637  L·mmHg /K·mol * 294.3K) / (2508.6 mmHg * 0.183L) \nMM = 165.11 g/mol\n\n3. Determine molecular formula by identifying multiplier of the empirical formula C3H3O to get MM of 165.11g/mol.\n\n(3*12)x + (3*1)x + (1*16)x = 165.11\n36x + 3x + 16x = 165.11\n55x = 165.11\nx = 3\n\nHence, your molecular formula is C9H9O3.