what is circumference of the outer and inner ring of horses in a carousel?
365090
if say Ri.. is the radius of the inner horse from the centre of the carousel and Ro is the radius of the outer horse from the centre of the carousel.\nGeneral equation for circumfrence is \nCircumfrence = 2 x Radius x Pi. (you have to know Pi)\n\nTherefore inner horse circumfrence (Ci) is\nCi= 2 x Ri x Pi.\nCo= 2 x Ro x Pi.
289682
circumference = pie times diameter\nradius is half of the diameter\n\nso if you have either the circumference or the diameter, you can figure it out.
5380
the answer to your question is simple..first find the equation for the circumference of a circle which would be 2 times pi times radius..which gives you the answer 29.516 if you round to the nearest 10th your answer would be 29.5cm
1102776
Horse - 47.50 mph\nZebra - 40.00 mph
443403
# Diameter: 165 ft (50 m)\n# Circumference: 518.1 ft (158 m)\n# Volume: 2,200,000 ft³ (62,000 m³)\n# Weight:15,520,000 lb (7,040,000 kg)\n# Triangle tiles:11,324\n# Area: 109,375 ft² (10,161 m²)\n# Highest point in attraction: 163 ft (50 m)\n# Average angle of descent: 20 degrees\n# Steepest angle of descent: 39 degrees
102323
let x=num of humans\nlet y=num of horses\n\n2x+4y=196\nx+y=74  -> x=74-y\n\n2(74-y)+4y=196\ny=24\nx=74-24=50\n\n50 humans and 24 horses
870435
The three questions you could have are:\n1. What is the diameter of the bicycle wheel?\n2. What is the radius of the bicycle wheel?\n3. What is the area of the bicycle wheel?\n\nKnowing that the equation for circumference is c=pi*radius (also c=2*pi*radius), you can solve for the first question by dividing the circumference by pi.\nNote: * = multiply  C= the distance 256.3cm\n\n1. 256.3cm/ pi = 81.5828... = approx. 81.58cm\n\nThe radius is half of the diameter and so:\n2. 81.58cm/2 = 40.79 cm\n\nFinally, the area of the circle can be found with the equation A = pi*(radius)^2\n3. Area= pi*(40.79cm)^2 = pi*(1663.8241) = 5227.05756...= approx. 5227.06cm^2\n\nHope this helps!  You could consider this solving backwards because you are continuously using information that is given or solved for and plugging the values back into different equations.
292092
Well if you know the name of the horse go to pedigreeonline.com it really helps or try aqha.com and look in the books on that web page hope it helps!!!!!\n~good luck~
711674
the circumference of a circle is the diameter * pi.\n\nor...\n\nC = d * 3.14
605474
According to official baseball rules, a baseball can have a circumference anywhere between 9 and 9.25 inches.  \n\nFrom the MLB website, rule 1.09:  \n\nThe ball shall be a sphere formed by yarn wound around a small core of cork, rubber or similar material, covered with two stripes of white horsehide or cowhide, tightly stitched together. It shall weigh not less than five nor more than 5 1/4 ounces avoirdupois and measure not less than nine nor more than 9 1/4 inches in circumference. \n\nA circumference of 9 inches corresponds to a radius of 1.432 in (= 3.638 cm) and a volume of 12.311 in^3 (= 201.733 cm^3).  (circumference = 2*pi*r, volume = 4/3 pi*r^3.)  A circumference of 9.25 inches corresponds to a radius of 1.472 in (=3.739 cm) and a volume of 13.365 in^3 (=219.016 cm^3).
992769
looking at the carousel horses on the merry go round.  They made me feel all fuzzy inside.  I loved Strawberry's too. I loved looking at my mom when she got all dolled up.. She looked beautiful.
940399
Short Circum. 20 3/4" \nLong Circum. 27 13/16"  \nLength 11 1/4" \nWeight 14-15 oz.
1187952
Here's everything you can possibly wanna know....\nhttp://www.angelfire.com/tx2/horsecorral/horseanatomy.html
512345
In humans, between 5 to 8 inches.
903470
r=sin 11θ for the smaller petals and r=Xsin11θ where X>1\nthis will give you your larger petals.
877852
Inertia with outstretched hands is represented as I_o\nInertia with wrapped hands is represented as I_w\nInertia of the body only is represented as I_b = 0.40\nm is the mass of the arms\nL is the length of the outstretched arms\nr is the radius\n\nI of a rod = (mL^2)/12\nI of a thin ring = mr^2\n\nI_o = I_b + (mL^2)/12\nI_o = 0.40 + (8.0*1.8^2)/12\nI_o = 2.56\n\nI_w = I_b + mr^2\nI_w = 0.40 + 8.0*0.25^2\nI_w = 0.90\n\nUsing conservation of angular momentum:\n\nI_w * speed_w = I_o * speed_o\n0.90 * speed_w = 2.56 * 0.40\nspeed_w = 1.14 rev/s
66459
http://www.totalfitnessfl.com/fit/North_Star_Dressage_Saddle_Wide_Tree_z42000_47282.php\nhttp://www.dressage-ext.com/ProductDetail.asp?KEY=3331\nhttp://www.mei.net/~equineline/Dressage%20Saddles.htm