If Zane earned $5040 in interest for the year, how much does Zane invested at 9%?
359252
The last two answerers have missed the point that a fifth of Zane's money is invested at the lower rate of 6%,\n\nThink of it this way. $ 48,000 @ 9% = $4,320.\n\nThe last 720 dollars could be earned by £12,000 @ 6% or by two-thirds of that ($8,000) @ one-and-a-half times the interest (9%).\n\nIf the lot were invested @ 9% he only needs a capital of $56,000, but given a fifth is invested @ 6%, he needs $60,000 capital to generate the same interest.
361168
$1860\n\n31000 dividend by 100 muliply by 6
1042143
a. 10.9\n\n\nusing Gordon's dividend growht discount model, which is Dividends / (discount rate - growth), we see that:\n\n$1.80 (10.9% - 7%) = $46.15.\n\nof course, you have to use algebra to back into x, which was the 10.9%.
383391
$1,558.20\n\nDont ask me how, I used a financial calculator\n\nN = 10\nI = 9\nPV = 10,000\nFV = 0
487839
Need to know how much you invested at what interest rate first.
171884
There is not enough information in your question to determine what it is you are trying to find out.\n\nDo you mean to get your $30 back? If it is a dividend of $3 once a year then you would get your money back after ten years.
894001
Answer - $104.89\n\nReason:\nHere the rate of return is 9 % = .09 and our cash flow is a constant C = 9.44. Plug those into the PRESENT VALUE INTEREST FACTOR FOR ANNUITIES equation, which is:\n\nPV = C * (1-((1/(1+R))^n))/R\n\nHere n = infinity, since the security has no maturity, and will pay out as long as its in business. So\n\nPV = 9.44 * (1-(1/(1.09))^(inf.))/.09\n\nNotice 1/1.09 ~ .9174311, which is less than one. Multiplying a number less than 1 by itself an infinite amount of times will result in an infinately small number, extermely close to zero. So\n\nPV = 9.44 * (1-0)/.09\n\nPV = 9.44/.09\n\nPV = 104.888888 ~ 104.89\n\nNOTE: If you paid more for this security, your implied rate of return would be less than 9 %. Conversely, if you paid less for this security, your implied rate of return would be more than 9 %.\n\nI hope this cleared things up.\n\nRunner
846247
$65.36\n\n$76*0.86% = $65.36
882219
at 1.313% amount is 9.76\nat (100 - 1.313) 98.687 ----- ?\n\nmultiply 9.76 and 98.687 and divide it by 1.313 add the answer and 9.76 that will be the princliple
617540
18600 one year, compounded semiannually @7.5%\n\n=\n\n18600 *1.0375^2\n\n$20021.16\n\n\n\nsecond ques.\n\nx * 1.38 <=230\nx <=203/1.38\nx <=166.67\nmax price  = 166/67
214693
The annual return would be (1 + MonthlyRate)^12 - 1 (where ^12 means to the 12th power).  Componding monthly.\n\nSo, if you had a 1.0% monthly return, that would be 12.683% annual return.
953772
You can't actually hold 2.43 or 23.13 shares, it should be 2 shares and 23 shares.\n\nBut to answer you question, you would have lost 32.19% on your yahoo investment, but gained 16.24% on your google investment
940587
1. 50 x (.35)=17.5  \nExplanation %=((part of)/whole )x100\nso part of=whole (%/100)\n2. 40 (.82)=32.8 (33)\nSame as above\n\n3. (1.75 -1.5)/1.5=.166 16.6%\nExplanation again %=((part of)/whole )x100\nIn this case the original whole is 1.5 \n\n4. (12000-8500)/12000=.291 0r 29.1%\nIn this case the original whole is 12000 \n\n5. 20/1.75=11.43\nHere is a bit tricky x(1+%/100)=the new whole (interesting term ha?) or the original whole + increase = the new whole :)\n\n6.2000(1+.04) (1+.04)=2163.2 (made a mistake earlier)\n\n\nyear 1  principal + % or earned interest (1)\nyear 2  principal + % or earned interest (1) +(principal + % or earned interest (1) %)
803511
It assuming the 9% is an annual rate and simple interest with no payments until the end of the six months, then the interest due is $292.50.
280771
the rule says that\n\nif the interest rate is x %, then your investment would approximately double in 72/x years.\n\nfor example, if the interest rate is 9%, it would take approximately 8 years to double the value of your initial investment.\n\nThis rule is more accurate if the interest rate is small. You might prove it mathematically. It's very easy to prove it.
875073
Problem 1: If a piece of real estate purchased for $75,000 in 1998 appreciates at the rate of 6% per year, then its value t years after the purchase will be f(t)=75,000(1.06^t). According to this model, by how much will the value of this piece of property increase between the years of 2005 and 2008? \n\nf=75000*1.06^3=89326.20\nincrease=89326.20-75000=$14,326.20\n\nProblem 2: The amount A in an account after t years of an initial principle P invested at an annual rate r compounded continuously is given by A=Pe^rt where r is expressed as a decimal. What is the amount in the account if $500 is invested for 10 years at the annual rate of 5% compounded continuously?\n\n500*e^.05*10=500*e^.5=$824.36\n\n\n\nProblem 3: Find the number log5(1/5). \n-1
285276
Simple:  $250,000 X 3 X 4.3 divided by 12 X 100.\n\nThe answer above this one can't be right:  it's more than 400%.