Dimples is a dominant trait. A man heterozygous for dimples marries a woman with no dimples.?
364067
Genotype of Man- Aa\nGenotype of Woman- aa\nPossible genotypes- Aa or aa (heterozygous or homozygous recessive)\nPossible phenotypes- Dimples and No Dimples\nProbability- 50% or 2/4
416191
They are two VERY different creatures and the genetic research they are doing has recently shown that the X chromosome in men and the X chormosome in women is very differnt much to their surprise!\n\nIt is almost like we are two different species genetically.
374218
not an exact science. has to do with dominant and recessive genes. which ever the genes fit together will determine the output. Like Punnet Squares. Could be shorter, in the middle, or taller than both of you.
515090
dominant e.g. Aa, AA - Recessive -aa
962212
1. Pp (heterozygous)\n2. Both parents are heterozygous (Ff)\nSince both parents show intense freckles, it must be a dominant trait. In order to have non-freck. children, they both must be heterozygous. Ff x Ff ----> 3:1 ratio expected; frec. to non-freck.\n3a) All four blood groups are possible\n  b)25% possibility for each\n\nFor#3, do a Punnett square-   A i   x   B i
699803
There are two type of alleles: dominant and recessive.\n\nThe rule of dominance is basically that if dominant is present in the allele, the phenotype (appearance) will not show the recessive gene.\n\nIn Mendel's pea plant experiment, his dominant was purple flower  (PP) and recessive was white flower (pp). \nWhen he crossed purple with white, he got all purples, with genotype (gene) of Pp. Since purple is dominant and is present in genotype, the flower is purple.
738923
The heterozygous individual for both Huntingtons and PKU has a genotype of HhPp.  As for the individual without Huntingtons, but is heterozygous for PKU her genotype is hhPp.\n\nSo nce again, the first thing is to make out the different types gametes.  The first produces HP Hp hP hp spermatozoids and the second produces only hP and hp eggs.\n\nYour Punnett square will have two columns and four rows.\n____|__hP__|__hp_\nHP_|_HhPP_|_HhPp\nHp_|_HhPp_|_Hhpp\nhP_|_hhPP_|_hhPp\nhp_|_hhPp_|_hhpp\n\nThere you go.  All that is left to do is the interpretation of the 8 different possibilities.\n\nGood Luck!
639406
When Mendel began to scientifically analyze "heredity", he concluded that each parent (mother + father) donates an "allele" for a characteristic (trait) in question.\n\nA lettering system was used: Capital letters indicated that the allele is DOMINANT; lower-case letters indicate that the allele is RECESSIVE.  This is the case for 22 of the 23 chromosome pairs in humans.  The 23rd pair are called the sex chromosomes.  Females (mother) always donate an "X" allele; fathers can donate either an "X" or a "Y" allele.\n\nIf a person's genotype for their sex is "XX", this means two things.  1: Both X's are the same (in other words, X and X are identical).  Identical alleles are called HOMOZYGOUS.  2: A human who is "XX" is female.\n\nA human who is "XY" is male.  "X" allele and "Y" allele are DIFFERENT.  Thus, they called HETEROZYGOUS.  We refer to men as being "heterozygous" in that a male's SEX alleles, 'X' and 'Y' are different.\n\nLet us say "B" is the dominant allele for brown eyes, and "b" is the recessive allele that can result in blue eyes.  A person who is "Bb" is heterozygous (B is a different allele than b).  A person's who genotype is Bb is likely to have brown eyes.  A person who is "BB" is HOMOZYGOUS (1st B is identical to the 2nd B) and will definitely have brown eyes.  A person who is "bb" is HOMOZYGOUS (1st allele 'b' is identical to the 2nd allele, 'b') for the recessive allele; this person will have blue eyes.
33435
A condition in which both alleles of a gene pair in a heterozygote are fully expressed, with neither one being dominant or recessive to the other.
496136
Not that I'm aware of. This genetic condition involves the X and Y chromosomes, and not anything else.
782924
genetic predisposition
52176
Genetic predisposition.
399075
Yes.\n\nBoth colour blindness and hemophilia are X-linked, and recessive. This means that if you are male, you will have the trait (because you only have 1 X chromosome), but if you are female, you have to have the disease on both your X chromosomes.\n\nThe 'normal healthy woman' had to get a hemophilia-X from her father (since he only has 1 X) - call it X(h) - and he was *not* colourblind so the X(h) doesn't carry the colourblindness mutation.\n\nShe also *had* to get a colour-blind-X from her mother, since her mother has to have 2 copies in order to *be* colourblind - call it X(b). So, she is X(h) X(b).\n\nShe marries a colourblind but not hemophiliac man: he must be X(b)Y. No other option.\n\nThere are thus four different possible outcomes for their children:\n\nX(b) X(h) mates with X(b)Y:\n\nX(b) X(b) - colour blind daughter\nX(b) Y - colour blind son\nX(h) X(b) - normal daughter (but carries both recessive traits)\nX(h) Y - hemophiliac son\n\nHope that was clear enough! :)
386547
There are certain genetic characteristics related to each race. This just happens to be a dominant trait with black women, but of course there are exceptions. Every race has a variety of body types
118008
No. B'coz if a perosn is heterozygous for a trait, the person will express the dominant trait. And, so will a person homozygous (dominant allele) for that trait. Therefore, it's not possible to differentiate between the two unless one obtains their karyotype chart.
490031
Ok, here's how it works. It seems that you need genotypes. A homozygous trait is a trait that is both dominant and recessive. Therefore, the organism possesses the dominant trait. A heterozygous genotype is always dominant (dominant is dominant over recessive). For example, brown hair (B) is dominant over blond hair (b). a heterozygous person will be Hh, and will have brown hair even though both alleles are present.
305371
I think that is a dominant trait. No one in my family has a cleft chin but my nephew has a cleft chin like his dad (my brother-in-law).