can you please help me to solve this..?
362556
MaX is right except for one thing:\nsqrt(cos^2(x)) is not equal to cos(x), but is equal to abs(cos(x)).\n\nHence the answer is:\nintegral(0,32pi/3, sqrt(2)*abs(cosx))\n=sqrt(2) * (21*integral(0,pi/2,cosx) + integral(pi/3,pi/2,cosx))\n= sqrt(2) * (21 + sin(pi/2) - sin(pi/3))\n= sqrt(2) * (21 + 1 - 0.5)\n= sqrt(2) * 21.5\n=30.40559...
302292
There's no solution.\n\nIf you're evil, you could argue that 102 - 78 is an answer ;)\n\nEDIT : Confirmed no solution with Telraam (http://members.chello.nl/g.de.blaauw/telraam.html). Allowing square roots gives (8*(2+.10))/.7 as a potential answer.
263164
I won 10 points!\n\nThis is pretty easy. Try to stump me with harder ones.
782406
°oO****Oo°°oO****Oo°°oO****Oo°\n\n\n 4 ∫[g(x)] g'(x) dx = 4 x 1/2g(x)² +c = 2g(x)²+c\n\nits the first suggestion that u made but i think you forgot the number 4...\n\n\n°oO~<<_P~'*'_ I~'*'_M~'*'_O~'*'~L _~'*'_A>>~Oo°
423306
None.\n\n1,186\n2,93\n3,62\n6,31\n\nPost the original problem. Maybe you've done something wrong.
881442
It is false no solution\n\nLook at \n Example 5:  on this site\n http://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut14_solve.htm\n \nWhere did our variable, y, go???  It disappeared on us.  Also note how we ended up with a FALSE statement, 0 is not equal to 11.  This does not mean that y = 11 or y = 0.  \nWhenever your variable drops out AND you end up with a false statement, then after all of your hard work, there is NO SOLUTION. \n\nSo, the answer is no solution.
815405
Sorry, but I don't think there is a way. You can mail this question to danuitti(who has 2180 best answers and appears at the top). He is a genius and he will most certainly find a solution. Good Luck!
540489
wow... looks like you got quite the problem there.  ... and no one really answered your question either.  Hope you find what you're looking for.
925629
polyeig(-5,-2,4,2) \n\nwill solve the equasion.  To learn about interpelations type:\n\nhelp interp1
54459
I agree with you. V!\n\nBTW, wrong forum.  Try the math forum under "Science and Math."  And this isn't Jeopardy, so try giving a question to get an answer.
103215
With this given data, it is not possible\n\nalthough the area is totalling to be 70 for both cases (7*10 and two pieces of 8*8 + 1*6) but with one division only, this is not possible\n\nPLEASE DO LET ME KNOW IF THERE IS SOME SOLUTION (i found it very interesting)
898860
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
196036
If you divide 2 to the second equation, you will notice that it is identical to the first one, so they are dependent to each other, and there are infinitely many solutions to this problem.\n\n^_^
522868
Take it to someone who knows what they are doing. \n\nWe've answered this question about 8 times for you. \n\nBring it to me, and I'll fix it for you - only if you quit posting the same question.
908277
* * * * * * * . I have encrypted the answer for you so that only you can see it and the rest of the readers can't solve it yet. This way your question isn't dead but you know I know the answer. Howzzat!?
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
890832
Gary, that's a good one, but one mistake...\nyou said that a=b, thus you cannot divide by (a-b) b/c that equals zero, and you cant divide by zero.