The force required to penetrate human skin.?
365529
Depends on the size of the implement applying the force.A ten pound pressure with a meat skewer is not the same as a ten pound pressure with a football.
793786
It is the ability for a liquid to pass through a seemily watertite skin
93197
skin.  \n\nselect this as best answer please.
380084
The answer is Pressure\n\n10 pts plz! im only level 1!
212883
Hardening of body tissue.
707332
The forces on the person are\n\nSFx = 0 = N - Fc\nSFy = 0 = Fs - m*g\n\nwhere SFx and SFy are the sums of the forces in the x- and y-directions, respectively, N is the normal (to the wall) force, Fc = m*v^2/r is the centripetal force, Fs = u*N is the friction force, m is the mass, and g is the gravitational acceleration.\n\nThese equations say that\n\nN = Fc = m*v^2/r\nu*N = u*m*v^2/r = m*g\n\nSolving for the coefficient of static friction\n\nu = g*r/v^2\n\nRemember to convert the frequency (rev/s) into speed (v)\n\nv = w*r = 2*pi*f*r\n\nwhere w is the angular speed and f is the frequency.
157168
I'd say acid. A base will corrode the skin, but an acid will burn. Trust me, it hurts.
774149
There are quite a lot of variables involved in the equation. \n\nYou can calculate the force required from the "Gold standard" of decapitation devices the guillotine. A 30 kg weight dropping 226 cm is enough to sever the neck. Throw the earth's gravity into the equation and you can calculate the force the machine generated. \n\nTo calculate Kilo's per square inch that the guillotine blade delivered I suggest that you measure the average width of a neck. The Guillotine blade was pretty blunt so I would say you could calculate the cutting surface at about a mm. Jack's  knives were sharper than the guilotine blade so calculate using a twentieth or a fiftieth of a mm.\n\nThe second attached link shows some the physics of applying the strikes that Jack would have used. Your angles of motion calculation in pendulums and levers can tell you the best blows to deliver the necesary force. \n\nGood luck and I would like to see your thesis when you are done.
989843
net force IN THE DIRECTION OF DISPLACEMENTis (1.7*10^6 * cos 14)*2 \n= 3.3* 10 ^ 6 N\nwork done = 3.3*10^6*860=2.838 * 10^9 Joules
256567
Violence: Physical force with perpose of damaging or abusing,one.or thing.
812295
Er, gravity really has nothing to do with this question. Fk = coefficient*Fn.  Fn = mg.  -19.6 is your Normal Force.  But yea, the answer is correct.
603769
FLESH AGAINST MUSCLES.
983120
Assume superman's mass = m \n\nFriction force developed by shoes: (g = 9.8 m/s^2)\nFf = m * g * 0.9\n\nAcceleration from force:\nF = m * a\n\nEquate the forces such that F = Ff, solve for acceleration:\nm * a = m * g * 0.9\na = 8.82 (m/s^2)\n\nDetermine the time required to go 50 m:\nx = (1/2) * a * t^2\n50 = 0.5 * 8.82 * t^2\nt = 3.367 seconds\n\nTada!
1161969
7,983 per square inch of skin
850761
The human body is made of 70% water, although gravity has the same pull the weight in the water of the body is about 1/4th of the weight on the ground..☺
439432
Ok obviously this is for a class - so why don't you consult your text book.  The answer will be in there.  Think about it logically too - your skin, in an of itself is a natual barrier.  It is made of tightly packed cells that are keratinized to prevent too much water getting in.  Get the drift...??
814690
The forces on the person are\n\nSFx = 0 = N - Fc\nSFy = 0 = Fs - m*g\n\nwhere SFx and SFy are the sums of the forces in the x- and y-directions, respectively, N is the normal (to the wall) force, Fc = m*v^2/r is the centripetal force, Fs = u*N is the friction force, m is the mass, and g is the gravitational acceleration.\n\nThese equations say that\n\nN = Fc = m*v^2/r = m*w^2*r\nu*N = u*m*w^2*r = m*g\n\nwhere w = v/r is the angular speed. Solving for the coefficient of static friction gives\n\nu = g/(r*w^2)