Triangle has three sides,square four sides- what about a circle?
362519
2 sides, inside and outside.
328495
now, if you add that it has 4 sides and all right angles, you probably can pass that off as the definition of a rectangle.\n\notherwise you just have a parallelogram.
845226
If the square has an area of 36 sq. units, then each side is sqrt(36) or 6.  This means that the common side of the triangle is 6 units.  Since it is an equilateral triangle, then all three sides are 6 units, so the perimeter of the triangle is 6 * 3, or 18 units.
669147
number of sides, congurency?, size of angles, distinguishing characteristics
895737
Imagine a square that is 6 inches across on each side.\n\nThat's the simplest example.\n\nAny rectangle where the length and width have a product of 36 works also.  It can be 9 inches on one side and 4 on another.  It could even be 1 inch wide and 36 inches long (much like a yardstick).\n\nBut it's not just rectangles.  The area of a circle is pi (approx. 3.14) times the square of the radius.  So, a circle with 3.4 inches for a radius is about 36 square inches.
169610
three in a triangle, two in a square (but that will get you triangles, which means you can do an additional three inside them) and I am not sure about pentagons.
1010584
Just think....\n\nA triangle (3 sides) always totals 180 degrees\nA quadrilateral (4 sides) always totals 360 degrees\nA pentagon (5) will total 540 degrees\n\nSo, the angles, A, will always equal 180 degrees per side, for each side (N) after the first 2.\n\nIn other words,   A = 180 * (N-2)\n\nif A is 32040, then 32040 = 180 * (N-2)\n\nN - 2 = 178\n\nN = 180
204855
Looks to me like you are trying to figure out a "PERIMETER" rather than an "AREA".  If so, you need to ADD the lengths of all the sides together.  If you ARE looking for an area, it is simply Length x Width (for a rectangle or square), 1/2 the base x height (for a triangle), or Pi x radius squared (Pi is approximately =3.1415926) for a circle.  If the "shape" of the object you are trying to find the area of is irregular, then you must divide it up into these familiar shapes first, find EACH individual area, then add those areas together for the total area.
758662
For example, a square is inscribed if the square is inside a circle.  The four vertices of the square are touching the circle..\n\nThe square will be circumscribed if it will be outside the circle.  In this case the circle will be touching the square in four points on the sides.
830003
i don;t know all of them, but here are a few:\n-rectangle\n-square\n-rhombus\n-parallelogram\n-kite\n-trapezoid\n-and closed abject with four sides!\n-cyclic quaDrilateral     \n-cyclic-inscriptable \n\ncheck out the site dr. math for more info on quadrilaterals!
735084
a normal triangle has 3 sides. asking q just for fun?
776798
Every side of this triangle has a pair of ends and all the three pairs are cyclic. ie, if AB,BC & CA are the three sides of the given triangle , then the side AB has the ends (4,5),(1,1), BC has the ends  (1,1)and (-2,5) & CA has the pair of ends (4,5),(-2,5).\nBy simple inspection of these pairs we can find that the points C and A are at the same height from the abcissa hence parallel to it. By this we can conclude easily that the length of CA=6 units.\nFurther, to be an isocelous triangle in this case the point B should be on the mid line of CA, and it is normal to CA. The mid point of CA is three units away from its ends C&A. As CA is parallel to absissa we can clearly conclude that any point between (1,0)&(1,5) will be the vertex of an isosceles triangle. Here the point B is (1,1) on the said line. Thus proved that the given points form an isosceles triangle.\nWe alredy know that CA = 6\nAnd the other sides are equal to sqrt(4-1)^2 +(5-1)^2 = 5 units\nNow, we can find the area of this triangle by Heron's Formula \nie sqrt[8(8-6)(8-5)^2] =12 sq units
687079
An equilateral triangle is a regular polygon with three equilateral sides (sides measuring the same length) and three equiangular angles (angles that are the same measure) these being of 60 degrees.
898007
It is said that the area of a circle is Pi R square.  Pie are not square. Pie are round, cornbread are square.
748416
You can certainly inscribe a triangle inside a circle as shown in the attached picture... but I'm not sure what you mean by "fit".  There is obviously space left over because a triangle isn't the same shape as a circle...
172946
Hello Michelle. Firstly, the word is Sudoku. I agree with Mayflyish in that the information given does not seem to work. For a 4x4 puzzle you need four numbers, letters or symbols. Also there is no single middle box. Additionally, using the layout you suggest (i.e. triangles and squares in each corner) means that none of the inner four boxes could contain a circle, because all of the outer vertical and horizontal lines between the squares and triangles would have to contain a circle each. So, I think, you will find that the four inner boxes must contain triangles and squares.
980809
4 rules\n1.two sides and the included angles of the two triangles equal\n2.2 angles and a side of one triangle equal to 2 angles and a side of theothrtriangle\n3.3 sides of one equal tothe three sides of theother\n4.in 2 right angled triangles if the  hypotenuses and a side of each are equal