The measures of the angles of a quadrilateral are x, x, x+15*, and x+45*; x=?
367886
x = 75 degrees\n\nSince all the angles must add to 360 degrees\n\n4x + 15 + 45 = 360\n\n4x = 300\n\nx = 75
857791
Without a picture or more information, your question isn't answerable, but I'm guessing that angles x and a are parts of a right angle, in which case the answer would be 41 degrees (49 + x = 90).
884011
The sum of the measures of the EXTERIOR angles is always 360.  So subtract 162 from 180 to get an exterior angle (18) then divide 360 by 18 to see how many sides.
454825
We can do this 2 different ways.\n\nFirst: Use the Pythagorean Theorem. Since all angles are right angles, the diagonal (measure from corner to corner) is the hypotenuse of the right triangle formed.\n\nBy the Pythagorean Theorem, 10^2 + 10^2 =x^2, where x=diagonal\n\nx^2=200\nx=sqrt(200)\nx=10 sqrt 2\n\n2nd way: use 45-45-90 Triangles\n\nWhen you draw any diagonal in a square, you get a 45-45-90 degree right triangle. This is because the 2 sides are the same, so the 2 base angles must be also. The top is 90, so the others must be 45 and 45 to equal each other.\n\nThe sides to a 45-45-90 right triangle are always in the ratio 1:1: sqrt(2) where sqrt(2) is the hypotenuse.\n\nYou know that the sides are 10 feet. Therefore the hypotenuse is 10 sqrt2 feet
952714
x is 50 degrees. in an equilateral triangle all angles r same, so each angle is 60 because all angles in a triangle equal 180.\n\nc=x+10\n60=x+10\n-10   -10\n50=x
765889
1. All angles are equal\n2. All angles are less than 180° \n3. Size of each angle = (180 - 360/n)° where n = number of sides
1029303
if you are asking for the factors,it is\n(x-15y)*(x+15y)
954217
The sum of the angles of a rectangle is always 360 degrees. Four angles of 90 degrees each; you will always get 360 anyway you add them up. \n\nReminds me of 360 degrees in a circle. Full circle.
185786
Measure one side of a rectangle, then an adjacient one.  Multiply them together.  A = B * H
86738
The angles all add up to 180 degrees.\n\nIf you know the lengths of all the sides you can use the "Law of Tangents" to find all the angles.  This is advanced geometry and Trigonometry, so rather than type, I am including a link to a pretty good explanation.\n\nhttp://answers.google.com/answers/threadview?id=38131
922959
____2x^2_+x_-15_____________\nx-2)  2x^3-3x^2-17x+30     \n       \n         2x^3-4x^2\n                  \n                 x^2-17x+30\n                 \n                 x^2 - 2x\n                        -15x + 30\n\nAbove tries to show the working\n\ndivides (2x^3-3x^2-17x+30) by (x-2)\n(same idea as ordinary division except the base is x , not 10)\n\nanswer is (2x^2+x-15) which = (x+3)(2x-5)\nworking:\nif 2x^2+x-15=0\nx = (-1 +/- sqrt(121))/4  "(-b+/-sqrt(b^2-4ac))/(2a) formula"\nx= -3 or x = 5/2\ntry it : (x+3)(2x-5) = 2x^2+x-15\n\nso the zeroes of (2x^3-3x^2-17x+30) =0 are\n2,-3,(5/2)\n\nthe zeroes of  (2x^2+x-15) = 0 are\n-3 and (5/2)\n\nif (2x^2+x-15) is graphed, it crosses \ny=0 (x axis) at x = -3 and x=(5/2)\n\nif the cubic is graphed, it has the \nzeroes 2,-3,(5/2)\n\nthe zeroes of\n(2x^3-3x^2-17x+30)/(x-2) are -3,(5/2)\nbut i think\n(2x^3-3x^2-17x+30)/(x-2) is \nundefined at x = 2
1021896
the squareroot of 2 over 2.  angle a must equal 45 degrees.\nnote- the answer may also appear as 1 over the squareroot of two.
723712
One way to solve this is to draw it on graph paper and count up the squares.  Howevr, I think I have a solution that doesn't resort to graphing:\n\nThe units 15 and 42 have a common divisor of 3.  So, if the diagonal starts at (0,0), it will also intersect (5,14) and (10,28).  Therefore, we can reduce this problem to testing a 5 by 14 rectangle and multplying by 3.\n\nFor the 5 by 14 rectangle, since this diagonal won't hit any vertices of the unit squares, just figure you will pass through 14 squares as you make your way across, and you will move up 4 squares.  So, 4 + 14 = 18 squares.  \n\nMultiple by 3 to get your answer for the 15 by 42 rectangle: 18 * 3 = 54.
768077
180 - 135 = 45\nNow divide 360 by 45\n360/45 = 120/15\n            = 8\nThe polygon is a regular octagon.
914112
It's usually called a quadrilateral, and the total of the internal angles of a convex quadrilateral is 360º.\n\nTo figure the sum of the internal angles of any convex polygon, the formula is (n-2)*180º, so a pentagon (five sides) has 540º, a hexagon (six sides) has 720º and so forth.
473359
DEepnds on the shape. If it's a quadrilateral then it's 25 m. If it's a triangle, then it's 15 m. But that's only if all the shapes are regular (all sides and angles the same).
463511
Use the double angle identities.