Why space vehicle accelerates during take off  to escape for gravitational pull?
365720
Because there are two basic ways to leave the planet.  One is to achieve escape velocity.  Throw a ball up into the air, it goes up and then back down.  Throw is hadrer (faster), it goes higher and then comes back down.  If you could throw it hard (fast) enough it would not come back, it will have left the earth.\n\nNow this speed is really fast, and very few things could withstand suddenly being hurled skyward at the speed, not to mention the force it would take to do so.  That is why we launch things by applying continuous force to them.\n\nBy constantly pushing against the earth we can keep accelerating upward against the force of gravity, and manage to leave the planet at a more gradual rate of increasing speed.
404666
By the pull of earth's gravity
1139189
The earth is surrounded by air approximately up to 200 km.\n\nThe space is surrounding the earth in all direction.\n\n Any object thrown or moving with a speed of 11.2km/s (25053.7 miles /hour) will escape from the gravitational pull of earth and will not return to earth.\n\nIf the speed is less than this value, the object will move in a circular path around the earth.\n\nOur planes are moving very slowly compared to that speed. Therefore, they cannot escape into space. If they have a constant speed they will be circulating the earth with a particular radius around the earth. \n\nIf a plane is flying (with a constant speed) at a height h from the ground of a city, after certain hour it may fly over the ground of another city. For the people in that city the plane will be flying at the same height h.  Since the earth is a globe, through out the globe, the plane will be flying at the same height. The height from the ground increases if the speed of the plane increases.
949041
This problem relies on Newton's second law: F=ma\n\na. This question is not completely specified.  The mass of the rocket is then (F/a=m or 2.0E7/a).\n\nb. We first find the net force on the rocket and use the mass from the previous question. Now we compute the acceleration at liftoff (F/m=a or (25E6 - 2.0E7)/(2.0E7/a)).\n\nc. We derive a new formula by double integration on acceleration. \nintegrate(a dt) = at, integrate(at dt) = .5at^2. The sequence gives us acceleration -> speed -> displacement at time t. The rocket will be at velocity: +(25E6 - 2.0E7)/(2.0E7/a)(7*60) m/s and at displacement of: +.5((25E6 - 2.0E7)/(2.0E7/a))(7*60)^2 m.
605786
When a spacecraft is in orbit it needs no energy. That's the simple answer. However, you need to get it into orbit in the first place, and this means accelerating the object to the speed it needs to orbit the earth - around 18,000 mph. How much energy you need then depends on the mass of the object or spacecraft - this can be calculated from 1/2 mv^2. \n\nTo escape the earths gravity altogether the spacecraft needs to go faster, about 25,000 mph or 7 miles per second. So if you were going to Mars for example, once you achieve that speed you need no more energy.
701384
The present momentum of the spaceship is \np1 = 7600 * 125 = 950000 kgm/s.\nLet us say the momentum of the gas expelled is p2. Then\np2 / p1 = tan 30.\nHence, p2 = p1 tan 30 = 548482 kgm/s.\nThe mass of the gas expelled = p2 / v = 171.4 kg.\nThis is only an approximation because the mass of the space ship is changing during the expulsion of the gas. Also the gas is expelled perpendicular to the motion of the ship at all times, which will keep the tangential velocity constant. To take these into account, you should also know the mass rate at which the gas is being ejected. Since this is not given - and also since the mass of the gas is negligible as compared to the mass of the rocket, I suppose the approximation is justified.
215867
The ejection of water WILL effect the shuttles attitude (direction). Any mass accelerated out will have an equal and opposite force against the shuttle (Newton's laws). But as it happens, the on board gyroscope detects minor forces causing permutations to the craft and compensates with thrusters.
439960
According to the Bernelli principle it is because the ratio of high-speed wing over the TOP of the foil of the wing is not sufficient to generate lift.  Therefore gravity takes over and it falls back to earth.
703038
When it breaks loose it would remind you of the space shuttle taking off.\n\nCoach
330093
These answers are correct, in that inertia is only present during acceleration.   This is why countless designs to create gravity-like conditions on spacecraft don't work, because they try basing them on acceleration, which will not work when objects inside the craft appose each other in any way...IE, a person moves.  Now to get to what humans are confused about.  Gravity is not a force at all, but simply the consequence of the local slope of the universe, in a direction the human eye cannot see: time.  You stick to the floor not because gravity is pulling you down, but because that is the shortest distance between today and tomorrow.  In the mid 1950s, the Manhattan project had has its goals to crack the anti-gravity mystery.  Many publications were abundant during the early 50's.  By 1957, it completely stopped.  The Kinemassic Force field generator is probably the most known and only accepted anti-gravity generator ever created by humans.  This design has been arrived at by several scientists in the last 10 years.  When charged, the generator creates a gravitational field that is non-magnetic based.  Uses include artificial gravity, and propulsion.  This methodology is likely the future of space travel, and also disproves the Newtonian view of gravity in the universe.
1159027
...mass of the planet it is "escaping" from, and the mass of the rocket.\n\nIf there are other large objects close enough to exert a gravitational influence on the rocket, these may need to be factored in as well.
351440
well ok. for part a, the acceleration is in the horizontal direction, because its moving horizontally. so the force is just mass x acceleration which is 70*6=420N. but thatz only in the horizontal direction.\n\nfor part b, you have to account for gravity. so gravity is pulling down at 9.45m/s^2, but youre accelerating upwards at 6m/s^2. so that means that youre overcoming the gravity and accelerating at 6m/s^2 MORE than the gravitational acceleration.\nso 9.45+6 = 15.45. this is your actual acceleration.\nso now you just do F=ma again and you get 70*15.45=1081.5N. \n\nhope this helps. let me know if you need more help. and this isnt thermodynamics.
618594
The thrust of the burning gasses out of the rear of the rock causes a force against the rocket. If the resulting force is more than the force of gravity, the rocket accelerates according to the formula A= F/M. Where M= the mass of the rocket and F=the net force of the burning gasses minus the force of gravity. As the rock rises, it looses mass due expending its burnt fuel. That causes it to accelerate faster. Also as it rises, the force of gravity becomes less increasing the net force impelling the rocket, thus causing it to accelerate faster.
368139
If the object has onboard power, then the speed is not really relevant to whether it will leave the atmosphere, just when. If you just fire an object upwards and it has no self-propulsion, however, then you need to calculate the change in gravitational potential energy (find out how far the atmosphere extends) and add the energy lost to air friction (this depends on velocity). Equate this to the object's initial kinetic energy and solve for initial velocity v. Your initial velocity will have to be larger than this.
365397
OK, relativity DOES NOT come into play here, because the velocities involved are not remotely high enough.\n\nYou are talking, it seems, about an object being projected up into the air and falling back to earth.  This must occur below escape velocity or it would leave the earth.  Relativistic speeds are far, far, far, far higher than that.  So, your question is in fact not related to relativity in any way, as much as you seem to think it is. SO I will answer your question 'normally'.\n\nWhen the object is projected upwards, it possesses a certain amount of kinetic energy whcih, as it rises, it converted into potential energy which increases with height.  When the KE finally runs out, the object will peak and as gravity, which exists by the way, will pull it down the PE will be converted back into KE and thus motion, in a downward direction in this case.\n\nAll I can say after this is to stand under it and maybe after it hits, you'll understand a little better.
36456
Thrust does not require air to "push off" of.  The propulsion is all based on Newton's laws: specifically, for every action there is an equal and opposite reaction.  If I push you with three lbs of force, I will also push myself back with three pounds of force.  From this, we can ultimately derive a conservation of momentum, which says that for me to issue a force onto an object and impart it with momentum, the force acting on me in the opposite direction will impart the same momentum.  Momentum is defined as the velocity times the mass.  So if a masive object exerts a force on a smaller object, the smaller object will go faster and the larger will go slower, but in the absense of other forces, they will have the same momentum.  When you fire a gun, the tiny bullet gets tremendous speed, while the much larger gun gets the same force but a much lower speed (what you would call "kick" in the gun.)\n\nthe same prinicple is at work in a space shuttle.  The products of combustion in the engine will be propelled backward at an enormous speed.  Though the shuttle is far larger, the force exerted forward on it is equal to the force exerted backward on the exhaust stream.  As the engine continues to fire, this force build up and up until the speed of the shuttle--unobstructed by wind resistence--can become enormous.
241909
The escape velocity is the minimum velocity an object needs to obtain in order to leave the surface of the Earth and never return, it will break free of the Earth's gravitational field forever.\nIt is not necesary to obtain escape velocity just to go into space.  While orbiting the Earth, you are most definatly still trapped within the Earth's gravitational field and you will eventually return to the surface.\n\nIf an object launched from the ground with an initial velocity lower than the escape velocity, the object will eventually (it may be take a very long time) return to the Earth and fall back down.