need help in algebra?
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send me allur queries at rahul_sett1981@yahoo.com
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Not just algebra...but anything in this world looks hard until we understand/learn it. So dont worry. \n\nNow, to give you some help regarding algebra. I I have answered a similar question before. Somebody asked what's the best way to teach algebra. I have answered them with a helpful link (see the link below), where they have video lessons of algebra for free. A professor teaches you algebra from scratch and gives real-world examples from time to time. He makes it look so easy that you not only would find algebra easy but interesting too. Here is the link.\n\nhttp://64.78.42.182/free-ed/Math/Algebra/Algebra01_VidLect.asp
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The KEY to solving any algebra problem, as I tell my students, is to get your unknown variable all by itself on one side of the equal sign.\n\nYou do this by "undoing" everyingthing that's being done to it right now.  And you "undo" the easy stuff first, like addition and subtraction, and then the more complicated stuff like multiplication and division.\n\nSo if you're adding 3 to X, then you would subtract 3.  And remember, what you do to one side of the equal sign, you MUST do to the other, so you would need to subtract 3 from both sides in my example.
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got to math.com, click on calculators and click on solve equations.....it'll do the math for ya
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You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
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try http://www.webmath.com/\nit gives you help on math on almost any time of math.
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http://www.gateways2learning.com/Algebra/Algebra.htm\n\nAlso try here.......\n\nYou may want to reconsider having it solve the answer for you, always know how to do the breakdown, it will help you to know "how" to go about it when you take a test.\n\nGood luck.....................
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Well we are not going to do your homework for you. But we will help you along. why not start out by writing down everything you know. they writing down what you need to find. Then look at your equations and find one that uses what you know to find one of the values you need to find.\n\nSo write it up and put it on here and we will help you along.
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take out the x\nx(a-b)=6\nx=6/(a-b)
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Use the quadratic formula.\nx1 = 1\nx2 = -1/2
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http://www.algebrahelp.com/ I found this site very useful perhaps you should check it out http://www.algebrahelp.com/
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Go to http://www.glencoe.com/sec/math/algebra/algebra2/pdf/alg2_20.pdf
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Simple algebra question:\n\na^2 + (a+1)^2 + (a+2)^2 = (a+3)^2 + (a+4)^2\n\nMultiply everything out getting...\n\na^2 + (a^2+2a+1) + (a^2+4a+1) = (a^2+6a+9) + (a^2+8a+16)\n\nAdd like terms on each side...\n\n3a^2 + 6a + 5 = 2a^2 + 14a + 25\n\nAll terms to the left...\n\na^2 - 8a - 20 = 0\n\nFactor into...\n\n(a-10)(a+2) = 0\n\nSolutions are a=10, or a=-2.  Since a has to be a positive integer, a=10.\n\n10,11,12,13,14 are your answers.\n\n\nCHECK:  \n\n10^2 + 11^2 + 12^2 =? 13^2 + 14^2\n\n100 + 121 + 144 =? 169 + 196\n\n365 = 365.
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Try going to this website. The will explain it step by step and you can ask all the math questions you want. www.algebra.com
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http://education.yahoo.com/homework_help/math_help/
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I can help, I've taken College Algebra, Calc. I, Calc. II and I've also taken many other math courses, and I'm also studying to be a computer programmer, so if you need help you can contact me at assassin7262002@yahoo.com
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Here are a few sites you can check out:\nhttp://www.freemathhelp.com/\nhttp://www.mathgoodies.com/\n\nHope these sites can help you..