How do I find out how many gallons of water can a big galvanized round tank hold?
361907
If the tank is a cylinder, the Volume is πr²h.  If you get the volume in cubic feet, multiply by 7.5 to get gallons.
215877
1 liter is a cubic decimeter. There are 1000 dm3 per m3, 264.17205 gallons per m3 and 3.7854118 liters per gallon.\n\nVolume can be calculated by the equation:\narea*height. So if you have a nice symmetrical tank just try to calculate its bottom (or top) area and then multiply with the height.\n\nArea is calculated with either:\nside*lenght of the tank for squares or for circles:\nradius^2*pi\n\nIf your tank is neither cylindrical nor cubical you may have your work cut out for you. Determine which shape it resembles the most.\nA sphere:\nV=(4*pi*r^3)/3\n\nA prism:\nV=B*h\nwhere h is height and B is the bottomarea of the parallell trapeze:\nB=(h*(a+b))/2\n\nFor a pyramid:\nV=(B*h)/3\n\nFor a straight circular cone:\nV=(pi*r^2*h)/3\n\nIf all else fails just fill that sucker with water (if it´s not a monstersized tank). You need to check it for leaks anyway. Weigh it empty and subtract that from the weight of the tank full. 1 liter (dm3)= 1 kg.
342773
Want to see something neat??\n\nType "19 gallons in cubic feet." into google.\n\nWorks for all kinds of conversions.
1044477
the smaller tank is 900L and the bigger tank is 1200L\n\nTank 1 = T\nTank 2 = T+300\n\n(2/3) T = (1/2) (T+300)\n(2/3) T = (1/2) T + 150\n(4/6) T = (3/6) T + 150\n(1/6) T = 150\nT = 900
1038988
You need to look up ASTM A120. That is the standard for galvanized pipe.
1161603
40000 pounds...8 lbs. per gal.
384987
Too few details... you need to disclose base area of tank, shape of it (is your tank cylindrical, spherical, cuboid, pyramid, etc).\n\nBUT, assuming it's a cuboid OR cylindrical (meaning has a round base and sides aren't tapered),\n\nif 210 barrels is 6 feet tall,\nthen 210 barrels => (6 x 12) inches\n     210 => 72 inches\nso   210/2.1 => 72/2.1\n     100 => 720/21 inches\n          = 34 6/21 inches\n          = 2 feet 10 6/21 inches\n          approx 2 feet 10.3 inches
708850
Water weighs 8.34 pounds per gallon\n\n1 cubic feet of volume holds 7.5 gallons of water\n\nfind the cubic feet volume of the tank (LxWxH) which is 30 \n\nthen multipy the cubic feet by the 7.5 which is 225 pounds.  Pretty heavy huh:)
83803
If you set this up as a series of fractions, you can make the units cancel out until you get to the desired unit.\n\n600T x 1c/16T -- the tablespoons cancel, and you have 37.5 cups.  Then just keep going this way\n\n600T x 1c/16T x 1pint/2c x 1quart/2pint x 1gal/4quart\n\nMultiply across the top and across the bottom.  All the units cancel out except for gallons, so you are left with (600/256)gallons, or 2.34 gallons.
8752
On average, around 12 or more gallons (3/4 of body weight).
960633
Capaticy is 15 gallons\n 3/4 of the capacity is full\n\n so 15 x (3/4) = 11.25 gallons is in the tank\n it will take 15 - 11.25 = 3.75 gallons to fill up.
1062578
I don't know who on this answer thinks they are smart, but no one got the same answer so that means that it is possible that one of you has a clue and the rest are babbling dumb-azzes.\n\nI have a 20x40 inground pool that hold a little under 35,000 gallons  based on that I would just guess that yours is around 15,000
803330
i got the same answer \nusing the equation PV / RT = n, i found the number of moles of the tank, which is 264.  Then using the same equation find the balloon, which i got was .138 moles.  Then divide and i got 1.91*10^3 balloons
1008144
Manufacturer and date of\nVisual inspection date\nHydrostate test dates\nSize of tank\nTank capacity
639676
You can do this with some math.  I'm assuming 12 feet is the diameter.  So the radius would be half that, or 6 feet.  2.5 feet (30 inches) is the height.\n\nThe volume of a cylinder is the area of the circle, times the height.\n\nV = pi r^2 h\n\nSo the volume is 3.14159 x 36 x 2.5\nThis is approximately 282.743339 cubic feet.\n\nOne cubic foot holds 7.48051945 US gallons, so you multiply 282.74 x 7.48 to get around 2,115 gallons.\n\nIncidentally, a gallon of water weighs 8.34 lbs, so you are talking about 17,639 lbs or nearly 9 tons of water!!!  Be sure the sides and the base are well constructed.
695589
Solve for the smallest tank, witha volume of 10,000 m^3 \n\nSurface area of the tank would be\n(height of the tank x circumference of the tank) + piR^2 \n\nvolume of the tank = 10000m^3 \nh*piR^2\n\nAs you change the values of H and R to get you volume the surface area will change. Solve for a minimum value.\n\nThe dimensions of the small tank then determines the radius of the hemisphere that it would take to hold that tank.
811969
The rate at which they will work:\nX/30 + X /45- X/90, where X is equal to the tank volume per minute.\n(3+2-1)X/90= 4 X /90. That is the combined capacity= X/22.5.\nTherefore it will take 22 and half minutes to fill up the tank.