Could someone graciously tell me what the answer to the algabraeic equation: y-3/5=(-6)?
358483
y-3/5=-6\nsubtract y from both sides\n-3/5=-6-y\nadd six to both sides\n6-3/5=-y\nfind a common denominator for 6/1 and 3/5\n30/5-3/5=-y\nsubtract 30/5-3/5\n27/5=-y\nsimplify 27/5\n5 2/5=-y\nmultiply both sides by a negative to get a positive y\n-5 2/5=y\ny=-5 2/5
394124
y=5\nx=-2/3\n\nSame method as the other one.
809836
-3(12) - [5(-4) - 2³]\n= -36 - (-20 - 8)\n= -36 - (-28)\n= -36 + 28\n= -8
932187
y = 3/2 (-4) -2 = -12/2 - 2 = -6 -2 =  -8\n\n(x,y) = (4,-8)
1088452
= -14a+28-4(6a-5)\n= -14a +28-24a+20\n= -38a+48
783104
(y-11) -(y+6)=6y\ny - 11 - y - 6 = 6y\ny - y - 6 - 11 = 6y\n0 - 17 = 6y\n6y = -17\ny = -17/6\nThe answer is D) -17 over 6
897596
If y = -5 + 3,  then y = -2 and the rest is easy, but when you started to solve it, you were working off of y = -5x +3.\n\nIf it is y = -5 + 3, then y = -2 and x = 1.1\n\nIf it is y = -5x +3, then the next step is to either check the original problem for where you misread it or write null set as the answer.  6 does not equal 7 hence the correct values for x and y are not real numbers...
373833
Use y = mx + b to find your equation.  m is -3, and you have an x and a y, so you can find b...\n\ny = mx + b\n5 = -3*2 + b\n5 = -6 + b\nb = 11\n\nSo your equation would be y = -3x + 11 (not listed in your answers - you may want to double check that).
978534
subtrac 3y and 4 from boside\ny^2-3y-4\nfactor\n(y-4)(y+1)\ny= 4 and -1
213207
(x^4 y^-2 / x^-3 y^5)^-1\n= (x^7 y^-7)^-1\n= (x^7 / y^7)^-1\n= y^7 / x^7\n= (y/x)^7
92773
First get the slope (m):\n(-3-(-3))/(-6-3)=0\nNow the y-int (b):\n-3= 0(3)+b\nso b=-3\nso your equation is \ny=0x-3 or simply\ny=-3\nYou could also just note that the two numbers -6 and 3 map to -3 so the only linear equation satisfying this would be a constant function at -3.  If you don't understand this last comment just ignore it!
817648
y=6\n\n3(y+4)=5y\n3y+12=5y\n12=2y\ny=6
439650
(y-6)(y-5)\n\n-6 and -5 add up to -11\n-6 and -5 multiply to 30
162979
From y=-3x-3 and y=x+5 you have -3x-3=x+5 so\n-3x-x=5+3\n-4x=8\nx=-2\nNow y=x+5=-2+5=3\nThe solution is (-2,3).
1056194
5x+3y+6=0\n\n5x = -3y - 6\n\n**  x = (-3y - 6)/5\n\nsubstitute for x in second equation:\n\n3x + 5y + 18 = 0\n\n3 * (-3y - 6)/5 + 5y + 18 = 0\n\n(-9y - 18)/5 + 5y + 18 = 0\n\n(-9y - 18)/5 + 25y/5 + 90/5 = 0\n\nmultiply both sides by 5:\n\n-9y - 18 + 25y + 90 = 0\n\n16y = -72\n\ny = -9/2 = -4.5\n\nsubstitute for y in the ** equation\n\nx = (-3 * -4.5 - 6)/5 = 7.5/5 = 1.5\n\nx = 1.5\ny = -4.5
580659
Ok, first, its not 1/y^2.  It's 1/y^5.  \n\ny*y*y*y*y\n-------------\n(y*y*y*y*y*y*y*y*y*y)\n\n\n= 1\n-----------------\ny*y*y*y*y\n\n\n= 1\n----------\ny^5\n\nAnd you write it just like that so as to keep the exponents positive.
795190
y = ax^3\n-5 = -8a, 5 = 8a, a = 5/8\n\nf(x) = (5/8)x^3