Electric energy travels in a closed circuit to light a bulb. How is the circuit affected if you open the switc
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A current flows means there is a motion of electrons in a particular direction (not random motion). In a circuit the electrons cannot accumulate at any point. So to have a current one needs a closed circuit. When the switch is open there is no current and thus no light. The elctrons move randomly without any effective direction of motion.
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At work we just got motion sensitive switches.  If there isn't any movement for so long, the lights turn themselves off.  Saves a bunch on electricity.  Of course they automatically turn themselves back on when we walk through.
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DC is Direct Current in which the electrons move in one direction through the wire all the time.\nAC is Alternating Current in which the electrons flow one way for a short time and then switch directions and flow the other way for a while.\nThe constant direction switching does not interfere with the work the electricity does if the devices using it are properly designed. Some devices, like incandescent light bulbs, work equally well with either type of current. Other types of devices, like transformers, depend on the constant switching to operate.
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A pendulum demonstrates the transfer of potential energy to kenitic energy.\n\nA light bulb demonstrates the transfer of electrical energy to light and heat.
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the is rotated in the magnet with the help of the wheels which are turned by the driver. this induces electricity to flow through the wire. this electricity is used to light the bulb.\nlook up electro magnetic induction.
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Firstly, electrical energy from the wall socket is transferred to the toaster.\nThis is the converted into heat energy by the filament.\nThere will also be some wasted heat and light energy.\nFinally, the spring will store spring potential energy when it is down, converted to kinetic energy as it rises, with a piece of toast hopefully!
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No. The filament is a part of the cicuit and when it is burned out, the circuit is broken and no current is flowing.
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The resistance of the coil which is connected to the D.C supply will add to other resistances in the circuit.\n\nNo voltage will be in the secondary.\n\nWhen the circuit is closed and opened there will be potential at the secondary.\n\nWhen the current is steady it will not work as a transformer
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Hi,\n\nThis is a RC circuit. And the following is the circuit diagram:\n\nGround --voltage supply --- switch --- R --- C --- Ground\nwhere R is 4.1k Ohm and C is 6uF\n\nFrom the given equation, apparently, the Capacitor is assumed to be uncharged (so voltage across capacitor V_C = 0V) before the switch is closed. When the switch is closed, the voltage across the R is maximum because V_C = 0V. So there is maximum current I_max = (V_supply - 0) /R. However, as the capacitor is charged, V_C increases and thus I reduces. That's why you have this equation:\n\nI = Imax e ^ -( t / RC)\n\nAnd by substituting I = 0.75 Imax, you can find that t = 0.00707 second = 7.07 milli second (ms)\n\nIf you still have more questions, please let us know\nhttp://www.kodkodkod.com/index_files/submitquestion.htm\n\nKodKodKod Learning Consulting
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Assuming the plates are also superconductors and the dielectric between them is vacuum, the only place for the energy to go is by electromagnetic radiation. The connecting superconducting wire will have inductance so you will have a resonant "tank" circuit with a very high "Q" factor. What you get is damped oscillations at the resonant frequency. Depending on dimensions, it could take a while for all the energy to radiate away, but radiate it will.
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When a magnet is passed through the centre of a coil of wire an electric current is produced in the wire. The energy comes from the movement of the magnet. Kinetic energy is converted into electrical energy and this is how electricity is generated in a generator. The reverse can also happen. Passing electricity through the electric coil in your cars starter motor will cause the magnet inside to move. Hence electrical energy is converted to kinetic energy and this energy turns the crankshaft of your car to get it started.
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well if i am not wrong.. they work on the principle of thermionic emission... \n\nnow wat happens is ... at the cathode end ( negatively charged) there is a metal bit.. called emitter  and at the anode end( positive terminal) another metal called the receiver. the tube is vacuated and filled with gas, in this case a halogen vapour. \n\nwat happens is when a potential is applied, when we switch it on, the cathode emits electrons.\nthese electrons pass thru the vapours and ionise them. when ionised these gases emit energy in the form of light..\n\nthis is the explanation in the most condensed form... equations make it complicated for understanding... \n\nhope i did justice to ur query
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Light bulb uses light waves.
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b) and c)\n\nthe transformer works in such a way that electric current flows through the secondary circuit only when the electric current in the primary circuit is changing.\n\nwhen you close the switch the electric current in the primary circuit suddenly rises from 0amp to some value\nwhich causes electric curent to flow through the secondary circuit\n\n.. b) is true\n\nwhen you open the switch the electric curent in the primary circuit changes from the maximum value to 0amps thus electric curent flows through the secondary.\n\n.. c) is true\n\nbut \n..a) is false\n\nsicne a battery is a dc source wich means that as long as the switch is closed it supplies a steady amount of electric current through the primary. thus ther will be no current through the secondary.
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Your question is confusing, but here I go.\n\nTo have zero current the circuit must be open.\nThat will give you the higher voltage.\nNow if you have a capacitor circuit, when you close the circuit will take some time to be zero current, while the capacitor charges.\nIn a inductor circuit the current is not possible to be zero because of the nature of the circuit, but will be near zero .\n\nIn a resistor circuit, the current never will be zero, the energy will become heat.\n\nso what are you trying to answer ???
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the electrical circuit?
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Radon 360 makes excellent points, but not all systems operate in that fashion and you will find different regulations in different countries (and unfortunately in different provinces or states.)\n\nMost systems in the European community operate with closed loops circuits and an open circuit is an alarm.  In the U.S. it's bass ackwards, most systems close the circuit on alarm or lower the resistance on an initiaing circuit to the "alarm threshold".  There are pros and cons to both ways.  If the circuit remaining closed is a "safe" condition, this if something is inadvertently shorted or if a fire melts the insulation and the conductors touch, placing a short on the circuit, the system will fail to function properly.  Conversely, on a system that needs a circuit closure to activate, then a cut wire, or one conductor melted away would prevent proper operation.\n\nOutput circuits, or indicating circuits are a whole new ballgame.  Obviously, you can't have a "short" or the units would not get the power they need to operate.\n\nBottom line, most all fire alarm systems supervise both the initiating and indicating circuits in some fashion.  In the United States, Class "B" circuits use an end of line resistor or other device that the main control panel is constantly looking for, if it doesn't see it, it faults.  Class "A" circuits return the wires to the panel in a redundant fashion to build a fault tolerance into the system.  Technically Class "A" and "B" are old terms that have been replaced with "Style B and D" and "Style Y and Z" for initiating and indicating circuits respectively.\n\nIn the end, most diagrams are based on the information provided by the fire alarm control panel's manufacturer.  Their manual outlines the type of circuits the system is expecting and show example layouts that can be used to generate a specific system.  Some even offer CAD files that can be downloaded to assit to this end.  \n\nIf you are looking to design a system, consult a professional.\n\nIf you want to learn more about it, feel free to contact me direct.