why zinc not form zn-zn bond?
372962
zinc metal cells form a mettalic lattice wherein the atoms form mettalic bonds - which are not as strong as chemical bonds - from oxidation
454861
Zn + 2HCl---> zncl2 + H2\nIt is a displacement reaction. Zinc is more reactive then Hydrogen and is capable of displacing it from Hydrogen Chloride.
296542
when a bond is formed, some electrons don't participate in that because of hybrid levels, thats why there are some electrons left known as lone pair, they are never single, they are a pair of opposite spin.
729609
In covalent bonds, elements actually lose and gain electrons to other elements in the compound.  Polar bonds are covalent bonds that don't require hybridization, and Non-Polar bonds do require hybridization.  Ionic bonds occur when elements share an electron but do not lose it.  Therefore, you can tell that NaCl is ionic because Sodium has an extra electron and Chlorine needs one, so Sodium shares it's electron with Chlorine, forming a very strong bond.  Ionic bonds, however are broken by Polar-Bonded liquids such as water, which is why NaCl dissolves.
151391
Zinc Oxide\n\nGood source on the properties of Zinc Oxide:\nhttp://www.chemicalland21.com/industrialchem/inorganic/ZINC%20OXIDE.htm
637163
False.\n\nIonic bonds form when 1 or more electrons from one atom are transferred to the electron cloud of another atom.  Leaving one with a net positive charge while the other has a net negative charge.  These two opposing charges will be attracted to each other, resulting in an ionic bond.
853078
Composition\nCopper Plated Zinc\n\n2.5% Cu\nBalance Zn\n-----------------\nWeight 2.500 g \n---------------------\nDiameter 0.750 in.\n19.05 mm\n---------------\nThickness 1.55 mm
844424
In a single replacement reaction, an uncombined element (such as zinc, Zn) reacts with a compound (e.g., hydrochloric acid, HCl), taking the place of one of the elements in the compound (hydrogen, H, in this case). the result is a compound that includes the formerly uncombined element (zinc chloride, ZnCl2) and an element that was part of the former compound but got replaced (hydrogen, which is now in gas form, H2).\n\nTo balance the equation, you need to Cl's for each Zn, so you put one Zn and 2 HCls on the left and see what comes out on the right:\n\nZn + 2 HCl  ->  ZnCl2 + H2\n\nZinc replaced hydrogen. Single replacement reaction.\n\nIn a double replacement reaction, you have two compounds, and the elements "change partners."\nExample: Zinc Carbonate (ZnCO3) and Hydrochloric Acid (HCl)\n\nThe most powerful oxidizing agent in the combination (Cl) will combine with the most powerful reducing agent (Zn). This leaves the less powerful oxidizing agent (carbonate, CO3) to combine with the less powerful reducing agent (H). Again, we will need to Cls for each Zn, so the equation balances as follows:\n\nZnCO3 + 2 HCl  ->  ZnCl2 + H2CO3\n\nZinc has replaced hydrogen, and hydrogen has replaced zinc.\nAlso, chlorine has replaced carbonate, and carbonate has replaced chlorine.\n\nResult: double replacement.
218524
In Ionic bond, elements looses or gains electron(s) and become ions and the electrostatic potential of these ions bind them\n\nIn covalent, the participating elements are bound by sharing electrons between them.
958264
Search the web for zinc and read the fact sheet - it offers a lot of information.  Good luck - hope you find the answers you're looking for.
709959
No, the zinc ion has a positive charge because it is transition metal (+2 charge) but the sulfide ion has a negative charge (-2 charge). If you wanted, there could be a compound of Zinc Sulfide, since zinc is a metal and sulfide is a nonmetal.
247406
hope this helps...\n\nZinc sulfide\n\nMolecular Formula: ZnS \n\nMolecular Weight: 97.5 g/mol
618961
6 moles of hydrochloric acid will react at a faster rate than 1 mole of hydrochloric acid because the solution will not dilute as fast as the smaller amount of acid- more acid to react with the Zinc.\n\nSounds good to me...
882235
In an electrolytic cell you can plate most any metal that doesn't quickly react with the solvent and its solutes.  The force of the copper ions gaining electrons at a negative charged zinc electrode is certainly possible.\n\nSince the copper would receive two electrons and go from a +2 to a zero oxidation state, you would say that it is being reduced.
737924
You can figure it out.\n\nIf a neutral atom of zinc has an atomic number of 30, and a mass number of 65, then it has 30 protons, 35 neutrons, and 30 electrons.\n\nProtons and neutrons are found in the nucleus.\nSo, draw a circle. Write "30p+" and "35 n" inside it.\nThis represents the nucleus.\n\nIn Bohr's model, electrons orbit the nucleus at specific energy levels. The first level holds up to 2 electrons.\nThe second holds up to 8.\nThe third holds up to 8.\nThe fourth holds up to 18.\nWe use dots to represent electrons.\n\nDraw a ring around the nucleus.\nAdd two dots to the ring, usually at noon and 6:00.\n\nDraw another ring around the first one.  Draw eight dots: two at noon, two at 3:00, two at 6:00, and two at 9:00.\n\nContinue adding rings and electrons.\nYou should end up with twelve dots in the outermost ring.\n\n(Which doesn't correspond with the  Lewis diagram for zinc, but that's  another story....)
195781
None. "A more active metal will displace a less active metal from a solution of its salt." Copper and lead are both less active than zinc. Obviously, zinc won't displace itself from zinc sulfate.
951188
4. How many grams of zinc chloride can be formed from the reaction of 7.96 grams of zinc with excess HCL?\n\nZn + 2HCl → ZnCl2 + H2\n\n1 mole Zn produces 1 mole ZnCl2\nTherefore 65.7g Zn produces (65.7 + 2 x 35.5)g ZnCl2\nie ~65.7g Zn produces ~136.7g ZnCl2\nSo 7.96g Zn produces ~7. 96 x 136.7/65.7g ZnCl2\nie ~ 16.6g ZnCl2\n\n5. How many kilograms of copper sulfide could be formed from the reaction of 1.80 mol of copper with excess sulfur.\n\nCu + S → CuS\n\nSop 1 mole Cu produces 1 mole CuS\nTherefore 1.8 mole Cu produces 1.8 mole CuS\n1 mol CuS weighs ~(63.5 + 32.1)g = 95.6g\nSo 1.8 mol CuS weighs ~ 1.8 x 95.6g ≈ 172.1g = 0.1721kg\n\n6. If Copper(one) sulfide is partially roasted in air (reaction with 02), copper(one) sulfite is formed. Subsequently upon heating, the copper sulfite thermally decomposes to copper (one) oxide and sulfur dioxide. Write balanced chemical equations for these 2 reactions\n\nCu2S + 3O2 → Cu2SO3\nCu2SO3 → Cu2O + SO2