an equilateral parallelogram.?
358372
its square with all sides and angles equal
792270
Hi I assume you mean an unsymmetrical item. I also assume you want a best fit. I have done similar things on a computer but not by hand. The computer finds three point most distant from the centroid and uses these points as pivots for three orthogonal planes. Not sure of the rest.
785873
M.C. Escher has already done a number of drawings based on the hyperbolic plane, based on Henri Poincaire's method of representing the entire hyperbolic plane.  Check this out: \n\nhttp://www.sciencenews.org/articles/20030830/mathtrek.asp
387286
Karnaugh map:\n\nCheck out the following link which will help.
943665
this is impossible to answer, there are many shapes that could be made this way.  do you have any other information like right angles or angles at corners?
889089
hi\nthe details which you gave have the answer for this question.\n\nangle E= angle C and angle A= angle B and DA=DB\n\nfrom this given data i will not assume that the triangles are equilateral, I will prove they are.\n\ncalculating the area of the 2 triangles with the formula (1/2)*base*height we can prove these 2 triangles are congruent and AC=BE\n\nsince the angle E=angle C and DA=DB then DB and DA must be the sides opposite these angles E and C respectively. \nhence  the line drawn(at angle of 90 degrees to base DB) from angle E to DB and line drawn(at and angle of 90 degrees to DA) from angle C to DA must be of equal magnitude (otherwise the angles cant be equal and/or sides cant be equal) ,  \n\nhence the length of this line drawn which is called as the height of the triangle is proved to be equal\n\nnow calculating the area with above formula (1/2)*base*height\nheights of 2 triangles are proved to be equal equal and bases are \ngiven to be equal hence areas of these 2 triangles must be equal.\n\nwhen area of 2 trianlges are equal and 2 sets of angles are equal and one side is equal then the 2 triangles must be absolutely congruent. hence AC must be equal to BE
951551
A line that runs parallel to the Y axis.
671808
4 sides and corners in a square
493884
In any quadrilateral the sum of the angles is 360 degrees.  Its an axiom that has been proven.  It's similar to the axiom that all angles in a triangle add up to 180.\n\nNote: the pattern is:\n3 angles = 180\n4 angles = 360\n5 angles = 540\n6 angles = 720\n7 angles = 900\netc.\n\nAnother fact about parallelograms is that the opposite sides have the same lengths and the opposite angles have the same measure.  This also means that two consecutive angles will add up to 180 (since the other pair must be equal and the total must be 360, as noted before).
858717
oblique, obilisque shape
729594
Rhombus and square (c)\n\n\nThis can be proved using geometry, analytic geometry, etc.  But it is the case.  Surprisingly, a general reactangle and parallelograms don't have perpendicular diagonals.\n\nGeneral kites do, and a rhombus is a kite with all equal sides.  A square can be thought of as a type and rhombus and rectangle, or just a rhombus when each angle is 90 degrees.  Then it makes sense that it would have perpendicular diagonals.
464335
I normally hate referring people to wikipedia articles, since it is so often inaccurate, but this one is quite good (link is below).  If you scroll down, there is a table that gives just what you're looking for.\n\n2x2 grid: 288 possible solutions\n3x3 grid: 6.7*10^21 possible solutions!
659736
Not a site, but I suggest you invest in something called Mathcad.\nTeach, please note, it is a site not a sight! Unless you were 'looking' for the answer... sorry!
771697
Try Google or Yahoo.  You'll find worked examples there.  I think it needs diagrams to understand; they and the accompanying explanations are too complex to attempt to reproduce here.
60892
A rectangle...equillateral means all equal sides, equiangular means all equal angles\n\nthe rectangle has all equal angles, 90 degress but teh sides are different, if the sides were the same it woudl be a square\n\na rhombus has equal sides but not necessarily equal angles\n\na parallelogram does not have to have equal angles or equal sides, it needs to have to sets of equal opposite angles and equal opposite sides\n\nhope this helps!!
657713
The area of a parallelogram is b × h, where b is the length of the base of the parallelogram, and h is the corresponding height.   \n\nHence, as per measurements given area of the parallelogram  would be 6 X 8 = 48 inches  and dividing it by two (to get half) gives us 24 Therefore the area of half of the parallelogram would be 24 sq.in.
1142827
You don't give a feasible region. However, only one of your answers actually satisfies z=6x+10y. That should solve your problem.