If x has the value 5 and u reassign it with x="expr $x + 10" what is the new value of x?
366534
It completely depends on where you are using this formula, is it in Excel? A program? What language?\n\nWe need more info.
437083
It depends how you break down the equation.\n\nIf you're saying that X = 5 then...\n\nIf something is in brackets then it's treated as a separate sum so for example 3 x (2+2) is the same as 3 x 4.\n\nIf there's no mathematical symbol then multiplication is used, in the above example the equation could have been written as 3(2+2).\n\nIn your equation the first part is 2 + 3 which equals 5.\n\nYour equation now becomes 5 (45x-2)\n\n45x is the same as 45 x 5 which is 225\n\nYour equation now becomes 5 (225-2)\n\n225 - 2 is 223\n\nYour equation now becomes 5 (223) which is the same as 5 x 223 so THE ANSWER TO YOUR EQUATION WOULD BE 1115\n\nBut the equation could also be read as 2 plus 3 lots of 45x minus 2 in which case the answer is 671 but if this were the case the equation should be written as 2(3(45x-2))\n\nIf you're saying that the answer to the equation is 5 then... \n\nAnother way to read the equation is 2 +3 multipliied by (45 times x minus 2) and the whole lot multiplied by x equals 5.  In which case x = 0.356295
89230
x is age 5 years ago.  so x = 7.  age now is x + 5 = 12
121013
if it is in binary, 1 + 1 = 10
405561
X  = Nothing \nor X  = 24th letter of the English Alphabet.\n\nAm I too clever or do I get the 10 points for being a smart ass?
505528
With algebra you have to balance each side of the equals sign. You can only add or subtract like kinds (think of all the x numbers as apples and all the plain numbers as pears). You want to get all the pears on one side and all the apples on the other.  If you move a figure from one side to the other, you have to do the opposite - eg, moving +8 to the right side makes it -8 and so on.\n\n5x + 8 + 3x - x + 5 = 6x -3\n5x - 6x + 3x -x = -3 -5 -8\nx = -16\n\nTo check it, go back to your original equation and replace the x with -16 and work out both sides (which both come to -99) so you know you are correct when you say x = -16.\n\nHope this makes it a little clearer\n\nJust thought I should add an extra note as not sure how confused you are about algebra.  The thing to remember is that x just replaces an unknown number - you could use d, e, y, "fred" - anything, so 2x just means there are 2 lots of the unknown number (x), eg, 2 multiplied by x could just mean 2 multiplied by 3.  The point is to find out what the x is representing.  In the case of your question the x represents the unknown number -16, ie, x = -16.
928231
8x-10x > -11-1\n\n-2x > -12\n\nx < 6
590233
Hint:\nDo a simple substitution u = x-5\nWhich means x = u + 5\n\nYou should get\n\n(2/5)(x-5)^(5/2) + 2(x-5)^(3/2) + C
714579
P (X>=5) \n= 1 - [  P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4)] \n\nRandam sample of 100 days from the past 10 yrs... \nC(360*10, 100)
41587
If something is equal to other thing, then you can substitute that something with the other thing.\n\nExample:\n\nIf x = 2y\n\nthen in: x+ 3y = 5\n\nyou can substitute x by 2y\n\n2y + 3y = 5
599364
x^2 + x = x(x+1)\n\nIt can be simplified to x(x+1).
831559
x= 5\n\n21x+28=16x+40+13\n21x+28=16x+53\n      25=5x\n        5=x
734849
x+78 [greater than or equal to] 120\nx [greater than or equal to] 120-78\nx [greater than or equal to] 42
321878
The statement is true for all values of x.\n\nBasically, from negative infinity to positive infinity.\n\nIf you work out the equation:\n\nx+5-7 = x-7+5\nx-2 = x-2\nx = x
366161
well...after transfering the "+7" in the right of the equal sign and which becomes "-7"(the sign is changed from "+" to "-") we have on the left "2x" and on the right "24-7" which is "17". After this we divide "24" at "2" which comes from the "2x" in order to find "x" and the result is that "x=8,5" or "x equals 8,5".
145326
i'm good at math, but what exactly is the quustion??? there isn't any... what is it, a equation?\nany way you can post it to sciences and mathematics > mathematics, im sure someone there can help you...\n\n>>>ok one minute i'm working on it...\n\n>>>there you go:\nlets do the first: (x-3)(x-1)(x+2)\nfirst we open the last two parentheses as in usual opening, and the (x-3) remains as it is. we get (x-3)[x^2+2x-x-2]\nequals (x-3)(x^2+x-2) then we open the two parentheses left. first we multiply by the first member (x) then the second (-3). then we get:\nx*x^2+x*x+x*(-2)-3*x^2-3*x-3*(-2)\nx^3 + x^2 - 2x -3x^2 -3x + 6\nand finally:\nx^3 -2x^2 -5x + 6\n\nthe second is the same way, i'm doing it, good luck :)\n\n>>>the second: (x-5)(x+1)(x-2)\nfirst we open the last two parentheses as in usual opening, and the (x-5) remains as it is. we get (x-5)[x^2-2x+x-2]\nequals (x-5)(x^2-x-2) then we open the two parentheses left. first we multiply by the first member (x) then the second (-5). then we get:\nx*x^2+x*(-x)+x*(-2)-5*x^2-5*(-x)-5*(-2)\nx^3 -x^2 -2x -5x^2 +5x +10\nand finally:\nx^3 -6x^2 +3x + 10\n\ni hope i helped...\n\n>>>oh i leave the first one to the last because i have to leave one of the three, and it really doesn't matter which one i leave. for example on the first i left the first parenthese (x-3)[(x-1)(x+2)] but i could leave the last [(x-3)(x-1)](x+2) or the middle (x-1)[(x-3)(x+2)] and i'd still get the same answer. i have to leave one of the three bcuz i can't open them all together, it's complicated and hard, and by opening two ane leave one it becomes much easier.
329632
{x: x inequal to 2}\nor\n{x: x=/= 2}