y = -1/2x + 3/2 How do I do this?
374950
Plug in x, solve for y as follows:\nIf x=0 then solve for y and get y= 3/2\nif x=10 y= -10/2+ 3/2 = -7/2\nCreate a graph using the horizontal as the x scale and the vertical as y.  Plot the above and you will see that it's a straight line.
91777
y=-6\n4x+y=2\n\nsubstitute -6 for Y\n\n4x-6=2\nadd 6 to both sides\n\n4x=8\nDivide both sides by 4\n\n\nx=2\ny=-6 (taken from above)
821178
x=-2 ,y=0     &      x=0 ,y=1  \n                     \n\nm=(1-0)/(0+2)\nm=1/2\n\ny=mx + c\n\ny=(1/2)x + c\n\nPut (0,1)\n\n1=(1/2)(0) + c\n\nc= 1\n\nEquation:\n\ny=(1/2)x + 1\n\n2y=x + 2             ANSWER...!!!
411757
since y=+-(x)^(3/2) Range [0,oo[\nnP=(n,n*n^1/2) and x_n/y_n= [(n^1/2^)/n]=n^-1/2
757845
x  y\n0 0\n1 -1/5\n-5 1
549653
Subtract 2x from each side\n-y = 0 - 2x\nMultiply each side by -1\ny = 2x
1163658
Use partial fraction decomposition.\nFactor the denominator.\ny^2 - y = y(y-1)\n1/(y^2 - y) = A/y + B/(y-1)\n1 = A(y-1) + By\nLet y = 0, then\n1 = A(-1) + 0\nA = -1\nLet y = 1, then\n1 = A(0) + B(1)\nB = 1\nThus,\n1/(y^2 - y) = -1/y + 1/(y-1)\nintegral of the above is\nAnswer: -ln(y) + ln(y-1) + C, where C is a constant.
135330
First you need to take the anti-derivative (integral) of the equation.\n\nSo, 1/3 (3x^3) - 2x + C = y (you always need to put in that constant when you integrate).\n\nSo, x^3 - 2x + C = 2 when x= -1... (-1)^3 - (-2) + C= 2...  \nSo, -1 + 2 + C= 2... 1 + C = 2... C=1...\n\nFinal answer: y= x^3 -2x +1
861275
x(y-1) = 2y + 3\n\nxy - x = 2y + 3\nxy - 2y = x + 3\n(x - 2) = (x + 3) / y\n y = (x + 3) / (x -2)
800260
4y+3=2y\n      3=-2y\n-1 1/2= y\n\n\nslope- 3
886265
gotta put the equation into y=mx+b first\ny= 1/3x - 1\n\nperpendicular would be y = -3x (+ or - any #)
679397
y = 0.5x-4 \n\nor similarly\n\nx= 2y +8
698387
y= -(2/3)x^2 + (2/3)x + 4\n\n\n(P): y = ax^2 + bx + c\n\nPoints (0;4)  (-2;0)  (3;0) are element of (P)\n-->  4 = 0a + 0b + c --> c = 4\n0 = 4a - 2b + c\n0 = 9a + 3b + c\n\n--> 5a + 5b = 0 --> b = -a\n--> 4a + 2a + 4 = 0 --> a = -2/3,  b=2/3
576742
ANSWER: y = 2; x = -1/5\n\nSOLUTION:\n\n1) First solve for y.  You can do this by adding the two equations together:\n\n5x - 2y = -5\ny - 5x = 3\n\nNotice that you have a positive 5x on the first equation, and a minus 5x on the second equation, so they both cancel out and you can re-write the equation as follows:\n\n- 2y = -5\n   y = 3\n\nAdd up these 2 equations and you get: \n\n- 1y = -2   or y =  2\n\n2) Then solve for x by replacing y with 2.  You can use any of the 2 equations from the problem.\n\n5x - 2(2) = -5\n\n5x - 4 = -5\n\n5x = -5 + 4\n\n5x = -1\n\nx = -1/5
701694
7x + y = 1 (subtract 7x from both sides)\ny = 1 - 7x\n\n3x + 2y = -9 (substitute in for y)\n3x + 2(1 - 7x) = -9\n3x + 2 - 14x = -9 (subtract 2 from both sides)\n-11x = -11\nx = 1\n\ny = 1 - 7x (substitute in for x)\ny = 1 - 7(1)\ny = 1 - 7\ny = -6\n\nAnswer: (1, -6)
927388
y=mx+b\n\njust rearrange it so you get b as your intercept..\n\nin this case y=-1/4x +3, so the slope is -1/4, and the intercept is 3
830587
y'=-x^(-1/2)\ny"=(-1/2)x^(-3/2)\n2x^2[(-1/2)x^(-3/2)]+3x[x^(-1/2)]-x^(-1)=0\n-x^(1/2)+3x^(1/2)-1/x=0\n2x^(1/2)-1/x=0\n2x(x^(1/2))-1=0\nx^(3/2)=-1/2\nx=(-1/2)^(2/3)\n\n\ni think thats correct... but who knows...>.<;;;\nis there an answer key???