what is the rpm on a 50Hz 220V single phase motor ?
375458
Depends on the number of poles.\n\nThe speed of the AC motor is determined by the frequency of the AC supply and the number of poles in the stator winding, according to the relation:\n\nNs = 120F / p \nwhere\n\nNs = Synchronous speed, in revolutions per minute \nF = AC power frequency \np = Number of poles per phase winding \n\nTherefore for the above example:\n120*50/2 = 3000rpm  for 2 pole
731018
First convert rpm to rad/s:\n6500 rot/m x (2pi rad/rot) x (1m/60s)=680.68 rad/s\n\n\nangular acceleration (alpha)= [w(f)-w(o)]/t= \n  [0-680.68 rad/s]/3s=-226.89 rad/s^2
844881
if your dealing with simple power supplies that supply DC electronics is pretty simply to get them to run on 50Hz. the first pic is a 60Hz supply....\nhttp://aycu34.webshots.com/image/5353/2000360261420977563_rs.jpg\nall you need to do is add some more capacitance to prevent the ripple voltage from dropping...\nhttp://aycu26.webshots.com/image/4785/2000376600521609993_rs.jpg\n\nbut from the sounds of it, you are dealing with AC electronics. Im sorry I do not have an answer for that.
541088
I am supposing that you are looking for the specification of ISO 1548:\n\nAbstract.\nIncludes the requirements for these components for use in aircraft electrical systems having voltage and frequency characteristics conforming to ISO/R 222, at any ambient temperature from -65 to +85 degrees centigrade, and all altitudes from 0 to 24 000 m. Gives terminology, requirements for dimensions, current, voltage and breaking-capacity ratings, time/current characteristics and tests.\n\nYou can buy the whole text on the source site.
286486
Just divide the speed by the frequency. So you get a wavelength of 344/50,000=.00688m=6.88mm. The answer above is not correct because the frequency is 50kHz=50,000Hz.
496103
You could try this website http://www.parkermotion.com/products/Rotary_Servo_Motors__7061__30_32_80_567_29.html
1065081
high torque compared to single phase. For the same power output the size of three phase motor will be smaller and also it will be less costly.
268387
It should be,if this is the original motor, is 10w30, summer,10w40 or 50 winter(depending on your location). If it is a motor from the mid-80's or newer it it should be a 5 weight\n5 qts.
924875
50,000V\n\nOtherwise, if you use Kilo, you just use the K - eg: 50 KV
888482
Please contact your local professional service centre.  \nDo not scratch your head with V= I X R.\nIf you still want to do your self,  use single phase varioc.  \nvoltage from 0. \nNormally Fridge comes with 230 volts input in India, \nrest of the world, I don't know.
807450
For a wye-connected machine:\nThe phase voltage (measured between a-b, b-c, or a-c) is (SQRT(3))* the line voltage (a-n, b-n, or c-n). In this case, connect your invertor across a-n, b-n, c-n (this may mean breaking the "common" neutral connection).\n\nFor a delta-connected machine:\nThe phase voltage equals the line voltage. In this case, connect your invertor across a-b, b-c, and a-c.\n\nWhich polarity you choose for the three connections will determine rotation - make sure your resultant rotation matches that on the machine nameplate, or you'll likely burn it up due to insufficient cooling...
970916
110V 60hz\nhttp://en.wikipedia.org/wiki/List_of_countries_with_mains_power_plugs%2C_voltages_and_frequencies
796281
That all depends on what the application is. If you put 50 volts on the 40 volt capacitor it could potentially explode. Put if you only have 40 volts on it no difference.
188071
Correction to Ra.Ge's answer. 220 vac is the rms value; the peak is sqrt(2) * 220. (See ref.) But the power factor information is correct. Assuming the guess of a 0.9 PF is good, the power is 7920 watts and the total consumption is 6083 Kwh. I hope this beast isn't really drawing that power all the time. If you have the fan set to continuous running, the compressor might be running only intermittently which brings down the net consumption.
173271
In the motor and VFD variable frequency drive industry, the standard speak is Amps, which is replacing HP old school.\n\nYou must realize that in an industry in which the typical 3phase power is based on 480VAC.\n\nThis means when someone is sizing a motor for a specific application they speak of the Amps need to perform the task.\n\nThe drives (VFD) which I work on are typically between 10amp up to 3000amp. Usually, 480Vac, sometimes 600Vac or 690Vac.\nA drive which is rated at 690Vac, 705amp is 600Vac, 800amp for the same drive.\n\nYou need to know both, HP and Amp for the machines which you are interested in. That means what is the typical voltage for the area. USA vs Canada vs UK vs Asia They are all different. \n\nKeep in mind Amps are Amps regardless where you are. Heavy wire sizing is crucial.
491871
Many different resources are available to you. \nApproximately 3,220\n\nTop hit: See below.
119135
10mH is 10 milli-Henries.  A Henry is a measure of inductance, and is defined as L=di/dt.  Inductors resist changes in current flow.  You have to use calculus to get the equation for an RL (resistor-inductor) circuit, which is what you have.  You are subjecting an RL system to a step input of 10 V from a "voltage source."  See the more technical, long-winded explanation of inductance.\n\nThe second site actually shows you an animated plot of the exact ciruit you are interested in.  \n\nAs a note of interest, large iron core inductors were developed for power supply filters in Vacuum Tube radios and amplifiers.  They had huge inductances of 7H or more.  These days, everything is in microhenries or millihenries because the frequencies in today's electronic systems have gone past 1 gigahertz.  Inductors can act as frequency-dependent resistors.  \n\nThese days, one hugely popular use of an inductor is to store energy in a magnetic field for switching power supplies in conjunction with electrolytic capacitors and FET modulated drives.  Wound 60Hz transformers are quite expensive, large, and heat producing.  The days of linear power supplies with large iron core transformers have given way to tiny circuits with driving transistors, an inductor, and some capacitors.  Switching supplies running at 125kHz or more can use transformers with ferrite (powdered iron) cores and far fewer windings.  The higher frequency packs much more energy than a 60Hz electrical source.\n\nAs a point of interest, try to find an old computer power supply which should be very easy to get.  Open it up.  Look at the parts, and you will see a high frequency transformer, inductors, capacitors, and drive transistors with modulating chips.  The 120VAC from the wall is put through 4 diode rectifiers to make 169V DC with some high voltage capacitors.  This voltage is made available to be switched at relatively high freqencies into a powdered core transformer primary.  The Secondary makes high frequency AC voltage which is rectified and filtered with capacitors and/or inductors.  A voltage detector circuit, usually isolated from the high voltage DC side by an optical isolator, tells the modulating chip what the load is.  The modulator will then vary the duty cycle of the transistors at a constant frequency to move more power across the transformer.  Have fun with electronics!  I love it...