what software can draw me a mathematical function such as cos(x) or even x+y=0?
372526
some calculators can do this\n\nmathematica software will do it
567245
simple x=r*cos(theta), y=r*sin(theta), r^2=x^2+y^2\nsubstitude, not hard
252184
Well, if you're using Microsoft Office, Excel provides many chart and graphic options.\nStatistical software also provide those functions, but they're really expensive.\nHere's a link for some software. Some are free, and others are shareware or have free demos that might serve you:\nhttp://dmoz.org/Science/Math/Software/Graphing/
832512
either square root or erauqs
206636
for (i=1,t=1,cosx=1;i<=n;++i)\n{\n  t=(-1)*(t*x*x)/((2*i)*(2*i-1);\n  cosx += t;\n}
882816
You can't do that on a calculator. What you can do is use the calculator to get the graph drawn then use your algebra to figure out where to shade. \nLooking at the graph, you know that it's a parabola with the vertex (4, -3). test the point (0,0) outside of the parabola.....\nsince you get\n0 is greater than or equal to 0 - 0 + 13\nsince that is a false mathematical statement, you know that you shade inside of the parabola....\nlets test a point inside/on the parabola and see, like (4, -3)\n- 3 is greater than or equal to 16 - 32 + 13\n-3 is greater than or equal to - 3\nthat is true so you now know to shade inside your parabola\nthat's how you do problems like that w/a calculator\nsince your calculator can do all of the operations, it's really easy
429405
go to your graphing calculator and hit the Y= button, then input your problem, it looks like an arch, that goes extremly high.. it starts on -3
676950
A few that come to mind at Euler, Maxima and Octave. Unfortunately, I don't think any of the free packages come close to Mathematica or Matlab, but maybe one of them will still meet your needs.
1011462
You have two ways to do it...\nOne... if you have to do it on a graph paper... \nthen.. put some values of x and solve for y and make a table... and then plot those points on graph\n\nOtherwise.. use graph plotting softwares.. like gnuplot (which is a free software).. define function as f(x)=2x (f(x) is equivalent to y here) and say plot f(x).. it will plot you the function.
87377
I am not sure what you actually want to do. Do you want a package that does calculus? Then what is wrong with Mathematica? \n\nI have used several different computer algebraic manipulators, like MACSYMA and REDUCE and MUMATH and SMP and so on. There are some advantages and disadvantages to each. But Mathematica is not a bad choice and is well supported.
351583
how about instead of (a+b)^4 you plot (x+y)^4?\n\nit's quite a funny 3D plot.\n\nLooks like a conehead balancing on his head.\n\nSeriously... draw a cone rounded off on the top and then flip the paper upside down and you'll get an approximation of (a+b)^4.
103447
In R^2 = (x-a)^2 + (y-b)^2, (a,b) are the (x,y) coordinates of the center of the circle.  If you literally want to draw the circle, set the distance between the compass points to R, put the center point on (a,b) and draw.  If you want to program a computer to draw it, you create a loop where theta (the angle) goes from 0 to 2pi (one full circle) in small steps.  Then at each step, turn on the pixel nearest to (a + R*cos(theta), b + R*sin(Theta)).
636329
I like to use GraphCalc, as it also includes live rotation of 3-D graphs. See http://www.graphcalc.com/ .
679535
The best way to approach this is to use logarithms & Euler's formula. \n\nWe know that the Euler's formula states:\n\nexp(ix)=cos(x)+i*sin(x)\n\nWe have to express 'i' in terms of the angle 'x' - to do this, we use argand diagram & find that 'i' is at an angle of 90 degrees (pi/2) to the Real axis. Hence, x=pi/2.\n\ni = exp(i*pi/2) = 0+(i*1) = i (which proves the last statement)\n\nNow, going back to the actual problem,\n\nA=i^i\n\nTake logarithm on both sides\n\nln(A)=i*ln(i)\n\nBut we have proved\n\nln(A)=i*ln(exp(i*pi/2))\n\nSince ln & exp are inverse of each other, they cancel out to give:\n\nln(A)=i*i*pi/2\nln(A)=-pi/2\nA=exp(-pi/2)\n\nThus, i^i = exp(-pi/2)
885716
cot(-x)cos(-x) + sin(-x) = -csc x\n\nLHS = cot(-x)cos(-x) + sin(-x)\n= cos(-x)/sin(-x) * cos(-x) + sin (-x)\n= cos²(-x)/sin(-x) + sin²(-x)/sin(-x)\n= (cos²(-x) + sin²(-x))/sin(-x)\n= 1/sin(-x)\n= 1/-sin(x)\n= -csc(x)\n= RHS
651097
yep corel draw 12\nfreehand 10\nms publisher.
41570
A parabola with its base at 0,1.  Go to http://www.coolmath.com/graphit/ Enter x^2+1 and see it for yourself!  :)