Exponent equation .25k^(3/8)=(.115)k?
365551
Just divide both sides of...\n\n.25k^(3/8) = .115k\n\nby k^(3/8), giving you...\n\n.25 = .115k^(5/8)\n\ndivide by .115...\n\n2.174 = k^(5/8)\n\ntake 2.174 to the 8th power, and the 5th root...\n\n2.174^(8/5) = k\n\nwhich means k = 3.464ish....\n\nThe first person was correct, but miscalculated the final answer...
776941
-25 < 5(w + 3)\n-25< 5w +15\n-40< 5w\n-8<w\n\n-9q + 18 -3 > 6q\n15 > 15q\n1> q\n\n\n19 < 7 + 1/3k + 2 -2/3k\nmultiply by 3 to get rid of denominators\n57 < 21 +k +6 -2k\n30< -1k\ndivide by -1\n-30<k
973521
=5.2*5.2*10^-5\n=27.04^10^-5\n=2.704*10^-4
471375
First, there is a difference between\n1) 3^x-5=27 and\n2) 3^(x-5)=27    1) means raise 3 to the x power, then\n\nsubtract 5 , 2) means subtract 5 from x and raise 3 to that power.\nCheck your original and be sure. In math, we're extremely\nand totally precise. It's part of the whole academic discipline. \n  About you log key : Calculators are different so you will have to experiment a little. Key in 10 then hit log. You\nmust get 1. For now ignore confusing issues with the use\nof ln, you don't need to know that. To make sure, key in\n100 and hit log. You must get 2.\n  No for anti log or inverse log experiment some more and/or get help. Key in 1 and punch your inverse log\nsequence or key. The answer must be 10. Again do it for 2.\nThe answer must be 100. When you have mastered that then\nproceed to the problem.\n Assume your problem is 1). Then add 5 to both sides of the equation giving you 3^x=32. Now solve\n x(log(3))=log(32)\nx=log(32)/log(3) \nTake the log of 32 giving 1.505  .\nTake the log of 3 giving .477  so\nx=1.505/.477 = 3.155\n\n If the problem was actually 2) then we have\n(x-5)(log(3))=log(27)\n(x-5)=log(27)/log(3) = 1.43/.477 = 3.00\nx=8
884053
The 8.198 part is called the mantissa.  The "5" in 10^5 is the exponent.  Shift the decimal in the mantissa the same number of places as the exponent.  Shift right for positive exponents, left for negative ones.\n\nSo, you have the right answer, 819,800.
927521
1/2bh\n1/2(8.5)(5.5)\n23.375
640221
8 = 2^3\n.125 = 1/8 = 8^(-1) = 2^(-3)\n8^x = .125\n(2^3)^x = 2^(-3)\n2^(3x) = 2^(-3)\nWhen the bases are the same, then the exponents are the same.\n3x = -3\nx = -1
1079532
2xy^2(3y^2)^(1/3)\n\ndivide the exponents by three, leave the remainder in the root.\nfind the lowest cubic factor in 24 (8=2^3) and take it out, leave the 3 in.
759262
The rules for simplifying integer exponents are pretty simple:\n\nhttp://en.wikipedia.org/wiki/Exponentiation
737484
5^-2 = (1/5)^2 = (1/5)*(1/5) = (1*1)/(5*5) = 1/25
1017358
K = a^2 * sqrt(3)/4\nK = 16^2 * sqrt(3)/4\nK = (256/4) * sqrt(3)\nK = 64sqrt(3)\n\nANS : 64sqrt(3)cm^2 or 108.8cm^2
784811
W=f x d\n25 x 1.5= 37.5j
232086
(5 cm^3)*(8.9)(g/cm^3) = 44.5 g
641969
log 35 = log (7 * 5) = log 7 + log 5\n\nlog 8 = log (2^3) = 3 log 2 = 3 * 0.3010\n\nlog 5 is already given isn't it. \n\nand by the way you have written the value of log 7 wrongly. the value that you have given is of log 3.
250535
Assuming the reaction is elementary:\n\nK = [03]^2/[02]^3\n\n1.8*10^-7 = [03]^2/0.0012^3\n\nSolving for [03], O3 concentration is 1.76*10^-8 M.  (Actually plus or minus, but the negative concentration is meaningless).
962658
3^2+4^2=5^2\n25=25\n\n3^3+4^3+5^3=6^3\n27+64+125 = 216\n\n4*2^4+7^4+8^4=?\n4*16+2401+4096=?\n64+6497=6561\n\nI don´t get the last part.
617827
3x^3y^2z^4\n\nbecause you divide the exponents by 4, but do the fourth root of the coefficient 81