What is the unit of electrical energy??
362669
Kilowatt-hour is the commercial unit of electrical energy. Joule is the S.I. unit. Kilowatt-hour is the energy consumed when an appliance with one kilowatt rating is used for an hour. It is 3.6 x e6 J.
819211
Only 70% of the power flux reaches the surface ot the earth.\nThe electric field is defined a Newton per unit charge..\nThe power flux from the sun is really radiation power its Usually measured in Joules per second per meter^2. \nVolt per meter is = to force per unit distance. Its resulting units are kg /sec^2. which is not equal to joules/sec/meter^2.
521519
Kinetic energy is the form of energy that involves mass in motion.\n\nE - energy, in ergs\n=\nm - mass, in grams times\nc^2 - the speed of light, in meters per second (300,000,000), squared.\n\nTake one gram of matter and convert it entirely into energy.  It will equal:\n300,000,000 x 300,000,000 or\n90,000,000,000,000,000 (9 x 10^16) ergs.\n\nAn erg is a very small unit of energy; on the other hand, that's a helluva lot of ergs.  By my very rough calculations, the energy from 1 gram of mass would power a million 100-watt lightbulbs for 1 second, or one lightbulb for 3 years.\n\n(1 watt-hour=36,000,000,000 ergs. 1 joule=10,000,000 ergs.  1 horsepower-hour=26,845,000,000,000 ergs. 1 calorie=41,868,000 ergs.)
1115839
No, the electron's charge is not its energy content, the charge is the charge which is a fundamental quantity (and the same for all electrons.) The volt is not a unit of force, it is a unit of electrical potential, with units of J/C (joules/coulomb). A volt represents a potential difference that will impart one joule of energy to one coulomb of charge passing through it. An electron volt is a unit of energy, defined as the amount of energy imparted to one electron passing through a potential difference of one volt. Since the electron's charge is −1.60217653*10^-19 C, the energy so imparted is equal to 1.60217653*10^-19 J.
802656
I suppose w = watt and c is coulomb \nI'm calculating with SI-Unit\n[W]/[C] = [V*A*]/[C] = [V*(C/s)]/[C] = [V/s] \nV= volt, A= ampere, s= time.\nthat is the best I can do for you, but I think you have been writing somthing wrong in your question.
848039
Depends on the system of units.\n\nIn SI all forms of energy are measured in Joules.\n\nThe Joule is a derived unit not a fundamental one - 1 Joule = 1 kilgramme metre^2/second^2.
168724
There is a relationship between power P, voltage V and current I. This relationship is best summarised by this formula: \n\nP=IV.\n\nCurrent is something else entirely. It is the rate at which electrical charge flows. The standard unit for charge is the Coulomb, and the standard unit for current is the Ampere.\n\nVoltage is the “push” that excites the electrons in a conductor and makes them flow (as current). Voltage is measured in volts and can be thought of as the potential for charge to do work. \n\npower, electric, energy dissipated in an electrical or electronic circuit or device per unit of time. The electrical energy supplied by a current to an appliance enables it to do work or provide some other form of energy such as light or heat. Electric power is usually measured in Watts
795841
1 calorie = 4.184 Joules\n1 Joule = 1 watt-second, so\n1calorie (C) = 4.184 w-s\n(100 C/hr)(1 hr/3600 s)(4.184 w-s/C) =\n0.11622... watts
771080
joules is energy...im dumb
285663
The next power of 10 smaller than nano (E-9) in SI units is pico (E-12).\n\nHowever, if your talking in terms of length, there is a unit called the "Ångström" which is 1E-10 meters.  This unit is sometimes seen when describing the size of atoms or chemical bonds.
124587
I am going to take a guess and say the moon.\n\nNo, I am kidding, it's the Sun\n\nSolar energy can be converted in to electricity and heat.
204153
You should distinguish between power and engergy. A watt or kilowatt is a unit of power. It does not make sense to associate a cost with a unit of power, as you also need to know how much time was spent absorbing this power.\n\nEnergy on the other hand (with units like the kilowatt-hour or the joule) does incorporate information about time. A kilowatt-hour of energy, for example, would be enough energy to provide 1 kilowatt of power over a period of 1 hour. Energy costs about 5-8 cents per kilowatt-hour.
655289
The units of:\n[Power] = Watts\n[Current] = Amps\n[Time] = Seconds\n[Energy] = Joules\n     \n      also\n\n[Energy] = kWh\n\n1kWh = 3.6 X10^6 Joules\n\nPower = Current X Voltage\n\nEnergy = Power X Time \n\nAfter performing the previous calculation, the units of energy must be converted from Joules to kWh, since electric companies charge in dollar per kWh.\n\n\n$ = Energy (measured in kWh) * Cost of energy in Dollars per kWh\n\nUsually, the cost of electric energy is in the neighborhood of $0.05 and $0.10 per kWh.
739842
To work this out you must find out the power rating (in watts). Most of the time this information is written on the appliance. For example a standard electric kettle may use 1300 watts. \n\nElectricity is sold in units of 1000 watts per hour. For example if you use 10 100w light bulbs for an hour it will cost you 1000watts or 1 unit of Electricity\n\nYou will have to find your power rating on your appliance then compare an hour of usage of that appliance with the price of 1 unit of power (1 Kilowatt per hour)
1104990
E = mc2 is one of the most famous equations, even to non-physicists, and which states a relationship between energy (E), in whatever form, and mass (m). In this formula, c², the square of the speed of light in a vacuum, is the conversion factor required to formally convert from units of mass to units of energy, i.e. the energy per unit mass. In unit specific terms, E (joules) = M (kilograms) multiplied by (299792458 m/s)2.
577335
The SI unit: calorie (cal)
618379
all SI derived units can be expressed in a combination of SI base units:\nlength -- meter (m)\nmass -- kilogram (kg)\ntime -- second (s) \nelectric current -- ampere (A) \nthermodynamic temperature -- kelvin (K) \namount of substance -- mole (mol) \nluminous intensity -- candela (cd) \n\nExamples:\nUnit of force: Newton -- N = kg·m/s²\n\nUnit of power: Watt -- W = Joule/second = Ampere·Volt = Ampere·Ohm² = Volt²/Ohm = kg·m²/s³\n\nUnit of electrical potential: Volt = Joule/Coulumb = Joule/Ampere·second = Watt/Ampere = kg·m²/A·s³\n\nConductance: 1/Ohm = Ampere/Volt = A²·s³/kg·m²