How do I Calculate and graph the total labor needed to produce up to 20 croissants.?
365741
I think all you have to do is plug in a few values for C to get a graph.  For example, try 0, 5, 10, 15, 20.  It's continuous so you can connect the dots.\n\n(0,0), (5,87.5), (10,350), (15,787.5), (20,1400)\n\nTotal labor for 20 is 1400.
765455
Given y=.55x+12.when x units produced\nkTherefore,y=.55X20+12\n=11+12\n=$23 (when 20 units produced)
714975
There are many such programs available:\n\n   http://www.google.com/search?q=graphing%20functions%20plot%20save\nhttp://dir.yahoo.com/Business_and_Economy/Business_to_Business/Scientific/Software/Mathematics/Calculators/Titles/\n\nSome are commercial, while others are free such as:\n\nhttp://www.c-lunch.org/~jwozniak/wg/main.html\n\nor the long-standing (and excellent) GnuPlot:\n\nhttp://www.gnuplot.info/\n\nThough GnuPlot is not GUI-based.
143759
Algebra is really a big subject. Maple or Mathematica may help. Especially graphs. They are easy and useful.\nI do have 2 examples of story problems which may help.\nSay you are to feed 16 animals each get the same biscuits, the dogs get 2 the cats get 1. You are given 25 biscuits. How many dogs,how many cats are there? \nYou realize all 16 get one so hand out 16. Now the cats have been fed and the remaining 9 biscuits must be for the dogs.\nIf Sally can make 3 salads in 1 hour and Mark can make 2. How long to make 1 salad if they work together?\nThink of cars and miles per hour. Sally's speed is 3/hr and Mark's 2/hr. The sum is 5/hour. Now you need hour/salad so invert. 1/5 of an hour to make one salad.
659736
Not a site, but I suggest you invest in something called Mathcad.\nTeach, please note, it is a site not a sight! Unless you were 'looking' for the answer... sorry!
623222
Search the state website. Not sure if you can find a pre made pie chart but you can always make your own using Microsoft office once you find the data you need.
1169800
work done 1.078 X 10^5\nheat is -0.292X10^5
183345
I think you have to make a histogram. Make the x axis be the values (make it in ranges though, like $340-$350, $350-$360, etc) and then put the number of people who thought it would be in that range  on the y axis and make a bar graph. this is called a histogram. you should get a bell curve around the actual value i think.\n\nother than this, i cant think of another way you could do it, but the way that you said is wrong (most likely).
708619
Please state the requirements of the mathematic's work project.\n\n- - - - - - - -s-
890672
use the idea that \ntime/ work  rate = (1) job\nfor instance,,,,,the hot water takes 4 min to fill a tub\n1/4 * time = 1 job\nin one hour...1 * 1/4 --> 1/4 full\nin 4 hours...4 * 1/4  --> 1 tubfull\n\ntherefore the formula would look something like this\n\nt/4 + t/3 = 1\nmult by lcd\n3t + 4t = 12\nt = 12/7\nt= 1/ 5/7 min
12198
building a straw structure so that it can support 20 stacked quarters
231014
Here's a great formula. One does the work in A days and the other in B days. The number of days they will do the job if they work together being N,\n\nN=(AB)/A+B\n\nSo, if the first do the job together: N=24/10=2.4\n\nAnd if the three of them do it: N=(2.4x2)/(2.4+2)=1.09 days approximately.
84748
production function Q = 6L -0.5L squared\nI'm basing this on Q = 6L - (0.5L squared)\nand not Q = (6L - 0.5L) squared\n\nI would have to assume the owner wants to have the maximum production, therefore that Q should be the highest number.\n\nWhen L = 1, Q = 5.75.  \nL = 2, Q = 11.  \nL = 3, Q = 15.76\nL = 4, Q = 20\nL = 5, Q = 23.75\nL = 6, Q = 27\nL = 7, Q = 29.75\nL = 8, Q = 32\nL = 9, Q = 33.75\nL = 10, Q = 35\nL = 11, Q = 35.75\nL = 12, Q = 36\nL = 13, Q = 35.75\nSo the correct answer is L (employees) = 12
894151
I think the way to approach this is to minimize the number of remaining (that is, unused) hours to zero.\n\nJob B jobs must be multiple of 10, e.g. 10 jobs = 7 hours exactly (no remainder). \n\nJob C jobs must be multiple of 5, e.g. 5 jobs = 127 hours exactly (no remainder).\n\nUsing this approach, if you did 60 jobs B and 10 jobs C, the hours = 60 * .7 = 42 hours + 10 * 25.4 = 254 hours, total = 296 hours exactly (no remainder).\n\nThis would yield a revenue of $10,465.24 \n\nWrong!\n\nHmmm - (I'm doing this in Excel with columns labeled:\n# of B jobs, # of C jobs, B hours, C hours, total hours, $B/hr, $C/hr, $B, $C, $total; then keeping total hours <= 296, what is max $total)\n\nBest answers using Excel:\n# of B jobs, # of C jobs, B hours, C hours, total exact hours, $B/hr, $C/hr, $B, $C, $total\n\n0,11,0.000,279.4,279.400,$35.51 $35.33 $0.00 $9,871.20 $9,871.20 all C\n\n422,0,295.400,0,295.400,$35.51 $35.33 $10,489.65 $0.00 $10,489.65 all B\n\n386,1,270.200,25.4,295.600,$35.51 $35.33 $9,594.80 $897.38 $10,492.18 \n\n23,11,16.100,279.4,295.500,$35.51 $35.33 $571.71 $9,871.20 $10,442.91 \n\n350,2,245.000,50.8,295.800,$35.51 $35.33 $8,699.95 $1,794.76 $10,494.71 \n\n314,3,219.800,76.2,296.000,$35.51 $35.33 $7,805.10 $2,692.15 $10,497.24 optimum\n\n277,4,193.900,101.6,295.500,$35.51 $35.33 $6,885.39 $3,589.53 $10,474.92 \n\n241,5,168.700,127,295.700,$35.51 $35.33 $5,990.54 $4,486.91 $10,477.45 \n\n60,10,42.000,254,296.000,$35.51 $35.33 $1,491.42 $8,973.82 $10,465.24 \n\nLooks like 314 B jobs and 3 C jobs win!\n\nI'm not sure how to put this in an optimization formula...\n\nHope this helps!
372526
some calculators can do this\n\nmathematica software will do it
1144014
draw a picture of the graph over the specified interval.  divide the graph into vertical rectangles.  the area under the curve will be the sum of the areas of the rectangles.  saying that youve made "n" rectangles, the only way to get the exact area is to find the sum for the limit as n approaches infinity.  work from that concept.  if you already knew that, or need more help or something, email me and i can give you more steps and a much more detailed description.  that would take a really long time though so im gonna see if this helps first.
466006
Pick a few easy points like pi/2, pi, 3pi/2, 2pi.  You know the period.  Then just graph it.