Need more help with math 6 grad 3 problems questions plz help?
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All squares are rectangles,\nall parallelograms are quadrilaterls\nand all squares are parallelograms
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try this web site http://www.aaamath.com/grade6.html
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here are the general steps you want to take when approaching these math problems\n\n1.) check for the greatest common factor\n2.) write out your parenthesis\n3.) since it's a squared problem, fill in the x's\n4.) write out your + & - signs\n5.) list the multiplication factors for the last term\n6.) plug in factors that will lead to the correct product\n\nwe'll start with #1 to get a better idea\n\n1.) -x^2+5x+24\n\n1. there is no greatest common factor\n2. write out your parenthesis\n\n(    )(    )\n3. fill in the x's\n\n( x   )(x   )\n\n4. fill in + or - signs\n\n-since we're dealing with -x^2 we know that one of the x's need to be + and the other one -\n\n(x   )(-x   )\n\n-since our last term is positive we know that either both the #'s are + or both of them are -\n\n(x-  )(-x-  )\n\nor\n\n(x+  )(-x+  )\n\n\n\n5.  list the multiplication factors for the last term\n\n24\n\n1*24=24\n2*12=24\n3*8=24\n4*6=24\n\n6. plug in factors that will lead to the correct product\n\n(x-8)(-x-3)=-x^2+5x+24\n\n**now, with a little more practice, you'll be able to figure these out faster...here are the answers to the rest of the problems\n\n2. (x-12)(x-12)\n3. (x-9)(x-12)\n4. 2(x^2-8x+16)=2(x-4)(x-4)\n5. 3(x^2-6x+72)=3(x-12)(x+6)
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(1) add row#1*6 from row#2, then from row#3\nthat is [–6+1*6, –47+6*6, -2+1*6] for row#2\nthat is [-6+1*6, -41+6*6, 2+1*6] for row#3\nthus:\n1……6……1       \n0…..-11…..4\n0……-5…..8\n(2) add row#2*(-5/11) from row#3\nthat is [0, -5+(-5)*(-5/11), 8+4*(-5/11)] for row#3 \nthus:\n1……6……1       \n0…...-11…..4\n0……0….68/11\nto check the result multiply main diagonal: 1*(-11)*(68/11)=-68
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Replace x with 6\n6^2 - 2(6) + k = 0\n36 - 12 + k = 0\n24 + k = 0\nk = -24\nThe other root is -24/6 = -4
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Problem 1: Find an exponential function of the form f(x)=ba^x+c with y-intercept 2, horizontal asymptote y=-2, that passes through the point P(1,4). \n\nYou find the y-intercept by replacing x with zero, which gives f(x) [which is y on the graph] = 2, so b + c = 2 (since a^0 = 1)\n\nThe horizontal asymptote is y = c, so c = -2.  That means b must be [you figure it out]\nNow it is y = 4a^x - 2.  This must be true when x=1 and y=4.\nSo 4 = [you figure it out; answer deleted due to complaint from below]\n\n\nProb. 3.  What is the amount in the account if $500 is invested for 10 years at the annual rate of 5% compounded continuously? \n  Just plug in the values.\nA = 500 e^(.05 x 10)\n\n[answer deleted]
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Here you go! I hope this helps you out. I copied what some other guy said, he was mean about it.  :)\n\nArt B = 2x3 = 6 points\nHist A = 3 x4 = 12 points\nSci C = 4x2 = 8 points\nMath B = 3x3 = 9 points\nLab A = 1 x 4 = 4 points\n\nTotal points = 39\nTotal credits 13\n39/13=3.0\nGPA = 3.0
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1.) Ms. Jordan 275 / 2500 = 0.11 \n     0.11  x  100 = 11%\n\n2.) 900 students x 1.07 = 963 students .\n\n3.) Virus Scan  300 sec / 0.40 = 750 sec for 100%\n\n4.) Gasoline... 8882 / 0.85 = 10,449 BBLs per day.\n\n5.) Jerry's new salary is\n     18,500 x 1.105 = $ 20,442.50\n\n6.) Chen's Investment wound up being \n     6400 x 0.918 = $ 5875.20\n\nHave a nice day,\nZahbudar
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1. 2\n\n2. 2a^2b\n\n3. 6xyz^2(2z-3y)\n\n4. 3a(4a-b+3ab^2)\n\n5.(d+2)(d+3)\n\n6.(x-9)(x-2)\n\n7. (4x-1)(x+3)\n\n8. (4b-9)(4b+9)\n\n9.(y+7)^2\n\n10. (2m+7n)^2
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goto purple math.com it will hopefully help you
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QUESTION 1:\n\nAsk yourself: WHICH TRIG FUNCTION IS OPPOSITE OVER ADJACENT?  IT IS THE TANGENT FUNCTION, RIGHT?\n\nThe bottom of the tree is 25 feet away from a point that measures 30 degrees from ground level to the top of the tree.\n\nAnswer: tan30degrees = x/25feet...choice 1.\n\nNotice that they are NOT asking you to solve for x.  Get it?  \n\nQUESTION 2:\n\nYou need to write the given equation 3x - 2y = 12 in the y =mx + b\nform.\n\nLet's do that right now.\n\nWe have:\n\n3x - 2y = 12 \n\nI will subtract -3x from both sides of the equation.\n\nWe get:\n\n-2y = -3x + 12...See what I did?  \n\nNext:\n\nDivide BOTH sides of the equation by -2 to find the value of y.\n\nWe get this:\n\ny = (-3x + 12)/-2\n\nWe can reduce the equation to this:\n\ny = 3/2 (x) - 6\n\nSlope is 3/2 and the y-intercept is -6.\n\nFinal answer: choice 1\n\nGuido
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1. An arithmetic sequence has a(sub 5)= -10 and a(sub 12) =18. Find a(sub 2) and a(sub 17)\n\nLet a(sub 1) = a and d = common difference.\nFor an AP:\na(sub n) = a + (n - 1)d\n\nSo a(sub 5) = a + 4d = -10 .... (1)\nand a(sub12) = a + 11d = 18 . (2)\nEquation (2) - equuation (1)\n7d = 28\nSo d = 4\nSo a = -26\na(sub 2) = a + d = -22\na(sub 17) = a + 16d = 38\n\n2. Find s(sub 4) for the geomtric sequence: \na(sub 1) = 5p, a(sub 2) = -10p\n\nLet a(sub 1) = a and common ratio be r\n\nFor a GP\na(sub n) = ar^(n-1)\n\na(sub 1) = a = 5p .......... (1)\na(sub 2) = ar =  -10p ..... (2)\nEquation (2)/equation (1)\nr = -2\n\nSo a(sub n) = 5p * (-2)^(n-1)\n\ns(sub n) = a(r^n - 1)/(r - 1)\n= 5p((-2)^n) - 1)/(-2 - 1)\n= -5p/3 ((-2)^n - 1)\n\nSo s(sub 4) = -5p/3 ((-2)^4 - 1)\n= -25p
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1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
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Answer 1:\n8y+6=3\n8y = 3-6\n8y = -3\ny = -3/8\n\nAnswer 2:\n3b+14=5b\n3b = 5b -14\n3b - 5b = -14\n-2b = -14\n2b = 14 (Minus signs cancel each other out)\nb = 14/2\nb = 7\n\nAnswer 3:\n4.5m-3=2m-0.5\n4.5m = 2m -0.5 + 3\n4.5m - 2m = 2.5\n2.5m = 2.5\nm = 2.5/2.5\nm = 1\n\nAnswer 4:\n7.3m-16=m+0.38\n7.3m = m + 0.38 + 16\n7.3m - m = 16.38\n6.3m = 16.38\nm = 16.38/6.3\nm = 2.6\n\nAnswer 5:\n18n+2n=6n+11.2\n20n = 6n + 11.2\n20n-6n = 11.2\n14n = 11.2\nn = 11.2/14\nn = 1.6/2\nn = 0.8
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1.6a^2b^2(1+3ab)\n\n2.(y-4)(y-1)\n\n3.(2b-1)(b+7)\n\n4.3(x^2-9y^2)\n=3(x+3y)(x-3y)
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1.adding-2f-7\n-6f-2f+7-7<2f-2f-9-7\n-8f<-16\ndividing by -8\nx>2\n\n2.5/8g-4>2/3g+6\nadding 4\n5/8g>2/3g+10\nmultiplying by 24\n15g>16g+240\nadding -16g\n-g>240\ndividing by -1\ng<-240\n\n3.sum incomplete\n\n4.-2 1/9d+3/5<-3 2/9d-4 2/5\n-19/9d+3/5<-29/9d-22/5\nmultiplying by45\n-95d+27<-145d-198\nadding 145d\n50d+27<-198\nadding -27\n50d<-225\ndividng by 50\nd<-5 1/2
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Not really enough information to help, so try this site:\n\nhttp://www.blc.edu/fac/rbuelow/calc/ex4-6.html\n\nit's the second problem down the page