an isosceles triangle has how many congruent sides and angles?
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An isosceles triangle is a triangle with (at least) two equal sides and two equal angles.\n\nhttp://mathworld.wolfram.com/IsoscelesTriangle.html
96075
you are talking about "Pascalles (not sure about spelling) Triangle." It goes 1,11,121,1331 and so on.
394622
A triangle in which all 3 sides are of different lenghts, with different angles.
610782
A circle has 360 degrees. Now imagine that from the icosagon you can make 20 equally-sized triangles. The angle made by each triangle is 360/20=18 degrees. The other two angles of each triangle are both 81 degrees.\n\nThe basic formula for the area of a triangle is 1/2 base x height. How do we find these? Well, imagine that from each of the 20 triangles we make two additional right triangles. In doing this we know several things:\n\n-The hypotenuse is equal to 6.5 cm (the radius).\n-The angles of the smaller triangle are now 9 degrees, 81 degrees, and 90 degrees.\n-The sine of 9 degrees is equal to the opposite side divided by the hypotenuse. If we multiply this value by 6.6 we get the length of the opposite side ("1/2 base").\n-The sine of 81 degrees multiplied by 6.5 gives us the "height".\n-Once you compute each value (1/2 base and height) you multiply them by each other and you get the area of the triangle.\n-Multiply the area of that triangle by 20, since you have 20 of them. Voila.
337862
go do your homework by yerself next time.\n\nBut becos im feeling nice today...\n\na triangle = 1 triangle , duh\na quadilateral can be divided into two triangles with vertices (points) all at the points of the quadilateral\n5 sided --> 3 triangles\n6 sided --> 4 triangles\n....\n12 sided --> 10 triangles\n1 triangle -->180 degrees\n10 triangles --> 1800 degrees
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The lenghth of the missing side is 20 in. because an isosceles triangle has only 2 alike sides so you multiply 26.5 X 2 and get 53in and then subtract 53in. from 73in. and get the 20in.
588232
1.to create a triangle whose sum of the angles is more than 180 degree.\n2. making a triangle whose hypotneuse is the smallest side.\n3.making an equilateral triangle whose angles are more than 60 degree each.\n3.2intersecting lines perpendicular to 2 other intersecting line cant be parallel to each other.\nETC.....
358118
In an equilateral traingle, all sides are equal and all three angles are 60 degrees.\n\nIn an isosceles triangle, two sides are equal and the two base angles of an isosceles triangle are equal to one another.\n\nThe other answer above refers to light reflected in a mirror or other reflecting surface/
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A nonagon can be broken into 9 isoceles triangles.\nThe vertex angles will be 360/9 = 40 degrees.\nThe two sides adjacent to the vertex have length 1 meter\nEach of the 9 triangles can be split into 2 right triangels with angles of 20 and 70 degrees.\nThe side opposite the 20 degree angle is sin(20) meters.\nThe side adjacent the 20 degree angle is cos(20) meters.\n\nEach of those triangles will have area (1/2)sin(20)cos(20 m^2\n\nThe total area of the 18 triagles combined is 9sin(20)cos(20).
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In all isosceles triangles if you drop a perp. line from the apex you will automatically bisect the base.\nThis done you will have 2 similar rt. angled triangles with base of 46.75 and hypotenuse of 49.25\nThe angle opp. the perp. is found by looking up the angle whose cosine is 46.75/49.25  = 0.9492  =  18.3*\nHence, other base angle is 18.3* making base angles sum of 36.6*\nSum of the angles of a triangle is 180*\nHence, Apex angle is 180 - 36.6  =  143.4*
63969
A hexagon has 6 sides.
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There are three cases:\n1) Side-Side-Side (SSS)\n2) Side-Angle-Side (SAS)\n3) Angle-Side-Angle (ASA)\nNote that Angle-Angle-Angle (AAA) does not guarantee two triangles are equal (congruent).  It does guarantee that they are similar.\nAlso, Angle-Angle-Side (AAS) does not mean the triangles are congruent.
71806
In an isosceles right triangle, sides a and b are equal and c is the hypotenuse.  Pythagorean's Theorum says that a^2 plus b^2 = c^2 for all right triangles.  here, a and b are equal, so you can say 2(a^2)=c^2.  If you want to solve for c, you find that c = a(rad2)
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Not a, since the congruent sides could be adjacent sides.\n\nNot b, because that would be a trapezoid.\n\nDefinitely c - there's a way to prove this using properties of parallel lines, interior angles, and triangles.\n\nMaybe d, since congruent diagonals means that your angles could be right angles, but it also could mean that you have an isosceles trapezoid.\n\nBisecting diagonals always means that your quadrilateral is a parallelogram.  Congruent diagonals can also yield a parallelogram, albeit a specialized one - a rectangle.  Now if you have diagonals that both bisect each other and are congruent, then you have a square.
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a) "Suppose Triangle ABC and Triangle DEF are congruent."\nb) "Suppose there exists a line segment with at least two right bisectors."\nc) "Suppose there is an isosceles triangle for which the angles opposite two of its congruent sides are not congruent."\nd) "Suppose there is a line segment with at least two midpoints."\ne) "Suppose there are two intersecting lines such that opposite angles are not congruent."\nf) "Suppose AB is not equal to CD."
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I think I'd start with 9 isosceles triangles.\n\nEach angle at the apex is 360 divided by 9 degrees\n\n=40degrees.\n\nThe other two angles are equal, so subtract 40 degs from 180 degs and halve what's left.\n\nEach base angle of the triangle = 70 degs.\n\nYou already have 40degs and the side opposite it (0.80m)\n\nSo you can use a over sinA = b over sinB to find the other two (equal) sides of the isosceles triangle.\n\nNow drop a perpendicular from the apex of the isosceles triangle to the (middle of) its base, forming two right angled triangles.\n\nEach of these triangles is half of the isosceles triangle.\n(remember the base of the right angled triangle is half the 0.80m)\n\nNow you can use \n\nsin = opp/hyp,  cos = adj/hyp,  tan = opp/adj to find the length of the perpendicular height.\n\nNearly there!\n\nArea of a triangle = half the base times perpendicular height \n\nWhen you've worked this out for one of the isosceles triangles, you just have to remember back in line one, that you are finding the area of 9 identical triangles, so you multiply the area of one by 9 to get the area of the nonagon.\n\nThis uses lots of fairly sinple steps, which you should be able to remember in an exam.  PS don't try to remember the order of the steps we used here, just have confidence that when you start, the solution will unfold for you.  If you wanted to practice, try it in a week with a different polygon!
39543
There are seven different (even if rotated, they're still different) ways to join the points together. Multiplied by 5, this gives 35 triangles total.