help...i have a math test tommorow and i do not understand box plots (A.K.A box and whisker plots) ...?
365486
the whisker on the left side is the lowest number in your set of data, and the one on the right side is the highest number. put the numbers in order from greatest to least and then you can find the boxes. if you have the numbers 12,10,52,1,26,9,45,13,38,36,and 8 for example, you would put them like: 1, 8, 9, 10, 12, 13, 26, 36, 38, 45, 52 then you find the median which is 13 and that is the line that you put in the middle of the graph. next you find the medians of all the numbers on the right of 13 which is 38. this number has a line on the right side of the middle. next you do the same thing for the numbers on the left which would be 9. put this on a number line and youre done!
491451
Ask your school's academic advisor. Judging by the class title this could just be basic math, but every school puts something different in basic math. So I cannot tell you anything.
578001
choose 5 numbers for x lets say 4,9,16,25,and 36\nfill them in for x\ny=4,y=9....\ny=2sqrt(4), y=2sqrt(9)....\nyour plots would be x and the answer for y
715220
yep, here they are, are you doing a pri=oject? i might be doing the same one.\n\nhttp://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=mathcom&s1=graphs&s2=equations&s3=basic\n\nhttp://www.webgraphing.com/plotting_advanced.jsp
129594
A stem and leaf plot is a chart where you put data in order from least to greatest.\n\n(Ages of 10 College Students (13, 18, 18, 19, 20, 21, 24, 25, 28, 30)\nFor example:\n1 / (the / should be a straight line) 3, 8, 8, 9\n2 / 0, 1, 4, 5, 8\n3 /0\n\nThen, on the side, you put a key. For this example it would be, 1/3=13.
184617
Did a teacher tell you this and now you wonder?  Or is this a mathematical riddle?\n\nIf the former, I don't see the inconsistency.  If the latter, I can't wait for the punchline.
527923
Draw a scatter-plot. In short draw a graph of y against x.\nIf the graph show linear relationship, u may continue. If the graph is not linear(or curvilinear) ignore the questions as regression model is  only for linear model.\n\nSince u didn't include datas, i can only gives u equations\n\n\nQ1....\nthe mean for the number of years a teacher has taught \n    =  (∑ x)/n\n\n \nthe mean for the students' average course grade \n    =  (∑ y)/n\n\nQ2....\nthe variance for the number of years a teacher has taught \n     s²=[ ∑ (xi – mean for x value) ² ]/(n-1)\n\nthe variance for the students' average course grade\n     s²=[ ∑ (yi – mean for y value) ² ]/(n-1)\n\n\nQ3....\nthe standard deviation(s)\ns= √variance for the number of years a teacher has taught\n\ns= √variance for the students' average course grade\n\nQ4....\nthe z-score for the number of years a teacher has taught\n= (observed value of x-mean for x value)/ the standard deviation of x value\n\nthe z-score for the students' average course grade\n= (observed value of y-mean for y value)/ the standard deviation of y value.\n\nobserved value means u must calculate for each value one by one.\n\nQ5.....\nThe correlation coefficent(r)\n=1/(n-1) X  ∑(xi-mean value for x / s for x value)(yi- mean value for y)\n\ns stands for standard deviation and X is times and n is sample size\n\nThe equation looks quite tough isn't it? Normally we calculated r².\n\nr²= (SSTO-SSE)/SSTO\n\nwhere SSE = sum of squared errors\n          = ∑(yi-predicted value of y)²\n\nthe predicted value is base on the least square line( u have to draw a graph that has the sum of ( yi-predicted value of y) is smaller than any other line.) \n\n  \n     SSTO = sum of squares total\n          = ∑(yi-the mean for y value)²\n\nAfter u find r², find r by √r²\n      \nThe value of r always between -1 and +1\n#If u get value for r outside that range, means u have made some mistakes in calculation.\n#If u get r=1 or -1, it means that the relationship is perfectly linear and all data points fall on the same straight line.\n#r=+something means that when two varibles tend to increase together.(x increase, y increase)\n#r=0 means the best straight line is exactly horizontal\n\nQ6....\ni dont know about the coefficient of determination. Never heard such thing. Sorry.\n\nQ7....\nthe regression equation\n\ny-hat=b-nought  -  b-one   x\n\n  where    \nb-one = [∑(xi-the mean for x value)(yi-the mean for y value)]/  ∑(xi-the mean for x value)²\n\nb-nought = the mean for y value  -  b-one(the mean of x value)\n\nQ8....\n From y-hat=(b-nought)  -  (b-one) x\nJust simply substitude x=x1, therefore\n   predicted y = b-nought)  -  (b-one)x1\n\nQ9....\nI'm not sure about standard error of the estimate for predicting Y from X. But if if i'm not mistaken, the formula should be\n\nstandard error(s.e)= s/ [∑(yi-the mean for y value)²][b-one)\n\nwhere b-one=r(the standard deviation for x value)/(the standard deviation for y value)\n\nand s= √[SSE/(n-2)]\n\n\n\n\nGood luck
327897
This looks ok:\n\nhttp://www.wadsworth.com/psychology_d/templates/student_resources/workshops/stats_wrk.html\n\nor else just keep google-ing psychology+statistics.\n\nGood luck :-)
729152
Try  this site it looks good!\n\nhttp://www.dositey.com/mathk2.htm
610514
http://www.lessonplanspage.com/Math.htm
78968
A Punnett Square, for those unaware, is the box used for determing allel (trait) combination in genetics.  A 2x2 box is the most commonly seen.  I'll use this as my example:\nDraw a square. Inside, draw a plus sign, so that you get 4 identical squares inside the larger square.\nNow, we need two 'breeders.'  Let's say Dad has brown hair, with resessive blond; Bb.  Mom is the same way; Bb.\nAt the top of the square, write Dad's alleles (the big and little 'b')...one per column.  On the left side, place Mom's alleles...one per row.\nNow, multiply.\nIn the four squares, you should end up with the following:\n1 BB\n2 Bb\n1 bb\n\nWhat does this mean?\nIt means that if Mom and Dad have 4 kids, the odds are they will have 3 with brown hair and one blond.  (Hopefully Dad understands recessive alleles, or Mom might have some explaning to do.)\n\nWill every 4th kid be blond?  No.  But, each kid will have a 1 in 4 chance of being blond, and 3 in 4 chance of being brunette.
669810
Will these work for you?\n\nsorry...try this one  http://cybersleuth-kids.com/sleuth/Math/Math_Worksheets/Percent/index2.htm
762323
http://www.lbl.gov/abc/wallchart/teachersguide/pdf/Chap02.pdf\n\nHeRe Is A LiNk...EvErYtHiNg YoU NeEd To KnOw
160741
you dont need to enter data into L1 you can use any of the lists, as longs as you specify which one when you are setting up plots in 2nd y= you then type in what lists you are using and make sure you turn on the plot!
901017
I am a math major so I have taken every math class. Start with Elementary Statristics...it is not that bad mostly pie and bar graphs for the first half of the semester.
490047
I think a calculator would be great for this one! It sounds perfect for a math wiz to try...Good luck! MayMay
882047
I can't draw a diagram, but that would help.  So, picture the box and the corners.  Label the amount cut off (like the size) from each side x.  The new length on each side is going to be 11-2x or 14-2x (as there are two squares on each side).  These multiplied together (like a rectangle) form the area of 80.  Let's solve.\n\n(11-2x)(14-2x)=80\n\nExpand.\n\n154-50x+4x^2=80\n\nBring the 80 over\n\n4x^2-50x+74=0\n\nBring out the two\n\n2(x^2-25x+37)=0\n\nx is about 1.715 solving this equation.\n\nThere is actually another solution, somewhere around 10.8.  However, this is an unnecessary solution:  10.8*2 is obviously larger than both 11 and 14.  We can throw it out.  \n\nCheck that:\n\n(11-2(1.715))(14-2(1.715))=80\n\nThat's your answer.\n\nHope this helps.