what is the multiplicative inverse of the following equations?  |1 -1 1 |        |0 -2 1 |       |-2 -3 0 |?
370476
Solve the equation, the find the reciprocal, by putting 1 over the whole number to make a fraction, or by flipping fractions.
757845
x  y\n0 0\n1 -1/5\n-5 1
304206
the clue would be to simplify the equation  to \nlim {x +[-(x+1)+1]}/(x+1)\n x-->0 \nlim [x + 1 -x]/(x+1)\nx-->\nlim (1/(x+1)) =1\nx-->0
289224
(x+ [1+i*sqrt(3)]/2) * (x+[1-i*sqrt(3)]/2) = 0
757614
4 (x^2 + 3X -4)\n4(x+4)(X-1)
268383
2x^2+6x-1x-3\n2x(1x+3)-1(1x+3)=0\n(2x-1)(x+3)=0\nx=1/2 or -3
602488
1-x = -(x-1)\nx^3 - 1 = (x-1)(x^2+x+1)\nAnswer: -(x-1)(x^2+x+1)
1033116
A X = D\nX = A^(-1) D. (A inverse * D)\n Do it ur self.
892759
g(t)=1/3(t+2)^2-12 (1<t<4) \nDomain is 1 < t < 4\nRange is -9 < g(t) < 0\n\nSo for inverse\nt = 1/3((g^(-1)(t) + 2)² -12\nSo 3t = ((g^(-1)(t) + 2)² - 36\n((g^(-1)(t) + 2)² = 3t + 36\n(g^(-1)(t) + 2) = √(3t + 36) (NOTE: NOT -√(3t + 36))\n\nSo g^(-1)(t) = √(3t + 36) - 2\nDomain: -9 < t < 0\nRange: 1 < g^(-1)(t) < 4
878479
To find the inverse function switch the x's and y's\n\ny=x^2-3\nbecomes\nx=y^2-3\nand after simplifying\ny=+/-sqrt(x+3) -- don't forget the plus or minus, you need both for this one!
412551
-4x+16=-1-4x\n-4x+4x=-16-1\n0=-17\n\nthe answer is [a]0
304526
let a-x=u\nso, -dx=du\n\nthen ∫1/(a-x)^2dx= \n-∫1/[(u)^2]du=\n-∫u^(-2)du=\n\n-[u^(-2+1)]/(-2+1)=\n\n-u^(-1)/-1=\nu^(-1)=\n\n1/u + C=\n\n1/(a-x) + C
588927
easy.. -1 , -2 , 1,2,3.\n\n-1 x -2 =2\n2x2x3 = 12
541499
2x(x-5)-3(2x+1)\n2x^2-10x-6x-3\n2x^2-16x-3
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
916864
Ord(e^(4x)-1 -4x) ~ Ord(e^(4x) > Ord(x^2)\nThen:\n\nlim(e^(4x)-1 -4x)/x^2 {x--> oo} = oo\n\nRemember\n\nln x < x^a < e^x < x^x
1144405
1. multiplicative inverse for x is x^(-1) or 1/x\nx*x^(-1)=1\n\n\nexample: 1/5 is multiplicative inverse for 5 because\n5*[1/5]=1\n\n2. commutative law for addition is \na+b=b+a\n\nexample: 3+5 = 5+3\n(8=8)\n\ncommutative law for multiplication is ab=ba\n\nexample: 5*3=3*5\n(15=15)\n\n3. distributive property means a(b+c)=ab+ac\n\nexample: 5(1+3)=5*1+5*3=5+15=20.