What is the molar heat capacity of neon?
360214
Regarding the heat capacity of neon, I was able to find the following information along with some other facts about neon at Dr. John Grohol's site, "Psych Central."\n\nNeon\nHeat Capacity: (25 °C) 20.786 J/(mol·K)\n\nIncluded below is the source link for this information, for more data about neon.\n\nHope this helps!
569971
This problem only has enough information if you assume it is an ideal gas.  In this case, PV=nRT is the equation of state.\n\nn and R are constants in this case, so PV/T must also be constant.  These values must also all be in absolute scales - the celcius must be converted to kelvin or any other scale based on absolute zero.  This means:\n\nP(i)V(i)/T(i)=P(f)V(f)/T(f)\nV(f)=T(f)P(i)V(i)/[P(f)T(i)]\n    =(250+273)K(740mmHg)(410mL)/[(680mmHg)(27+273)K]\n    =[523*740*410/(680*300)]mL\n    =777.83mL\n\nBy the significant digits you've presented, this can only be evaluated to any accuracy as 780mL.  (two significant digits)
509763
Try using the calculator at the webs site listed below. \nEthanol at 57.5 deg C has a heat of vaporization = 40.23 KJ/mole.\n\nThis web site has calculators for a number of other physical properties.\n\nBest wishes !
64340
Neon is the chemical element in the periodic table that has the symbol Ne and atomic number 10. A colorless nearly inert noble gas, neon gives a distinct reddish glow when used in vacuum discharge tubes and neon lamps and is found in air in trace amounts.\n\n\nNotable characteristics\nNeon is the second-lightest noble gas, glows reddish-orange in a vacuum discharge tube and has over 40 times the refrigerating capacity of liquid helium and three times that of liquid hydrogen (on a per unit volume basis). In most applications it is a less expensive refrigerant than helium. Neon has the most intense discharge at normal voltages and currents of all the rare gases.
569322
Use the ideal gas law \n\nPV/T = constant for the final and initial states.
526102
Neon is produced by almost all western nations, and is easily obtained from the liquification of air.\n\nAbaut 1 part in 65,000 of air is neon.
945210
Melting point: -77.7 C \nBoiling point: -33.3 C \nDensity: 0.6813 g/L, gas.\n\n At standard temperature and pressure, ammonia is a gas.
836131
The correct answer is 3 Nitrogen \n\n7 electrons as follows 1s2 2s2  2p3  . The sublevel 2p3 can theoretically contain  6 electrons and has only 3\n\n\nHelium and neon are noble gases. All the sublevels are filled\n\nBeryllium  has  4 electrons and  2 on shell K 2 and 2 on sublevel 2s complete
783249
Change it to 1.27 × 10^4\n\nYour value for Specific Heat of Zn is only 3 sigfigs, thus, your answer can only be up to 3 sigfigs.
512153
The mean van der Waals diameter of water has been reported as identical with that of isoelectronic neon (2.82 Å) [112]. Molecular model values and intermediate peak radial distribution data indicates however that it is somewhat greater (~3.2Å). The molecule is clearly not spherical, however, with about a ±5% variation in van der Waals diameter dependent on the axis chosen; approximately tetrahedrally placed slight indentations being apparent opposite the (putative) electron pairs.
910584
Try this site:\nwww.webelements.com\nit should be on there this is the site I used for my chemistry report(interview with an element) on Neon
580457
Standard enthalpy of formation of Barium oxide crystals at 298.16K (25°C) is -548.0 kJ/mole.  For gaseous/vaporous BaO, it is -112.0 kJ/mole
46596
Use mole concept. Heres how it's done:\n1)Neon's atomic number's 10 and it has acomplete orbit. therefore it's molecular formula is Ne.\n2)1 mole of Ne weighs 20.18g&i mole is 22.4 l\n3) use the following equation and then cross multiply:\n\n    22.4   litres    weigh          20.18 a.m.u\n     2     litres    weigh          x a.m.u.\n\nNow ur equation is 'x'= (2 X 20.18)22.4\nwhich is equal to 1.801 gms or a.m.u
820519
First write the balanced chemical equation:\n\nPb(NO3)2 + 2NaBr --->  PbBr2  +  2NaNO3 \n\nThen, find the total volume of the solution: 200mL + 200mL = 400mL \n\nFrom the density, the mass is:   density = mass/volume   mass = density * volume = 1.0 g/mL * 400 mL = 400 g\n\nQ = mC(Tf - Ti) ; where Q = heat released, m = mass of solution,, C = specific heat capacity, and (Tf - Ti) = change in temperature\n\nSo,  Q = 400g * 4.2 J/gK * (2.44 + 273)  (Since C is J/gKelvin, the temperature rise also has to be in Kelvin)\n\nQ = 462.5 KJoules\n\nHope this helps...
860331
NH4Cl has an enthalpy of solution of +14.8kJ/mol, meaning the reaction is endothermic.
808490
I hope you are EUR, because I'm not converting this....\nThe market price of pure neon gas is 165.30 € per cubic-decimeter in small quantities (<1 cu-dm),\nand about 2.81 € per cu-dm in large quantities (> 300 cu-dm).
834399
Your answer depends on the nature of your problem, so you'll want to give more info if you want a complete answer.  The specific heat capacity you use depends on which substance is being heated up or cooled off.  The mass will be the mass of the substance that is being heated up or cooled off.\n\nOne exception that frequently occurs is when you are dissolving a substance in water.  Most problems will assume that the solution has the density and specific heat capacity of pure water.  So in other words, if you dissolve 3 grams of ammonium chloride in 100 mL of water and watch the temperature go down, most instructors would want you to use a mass of 100 grams (instead of 103) and the specific heat capacity of water 1.00 cal/g C or 4.184 J/g C if you're working in joules.\n\nHope this helps...this is the best I can do without more info about the problem.