what are the specific heat capacities of..?
358448
specific heat? that would be represented by Cp.\nHowever if you are using delta H then it would either be: delta H (fus) which is the enthalpy of fusion, used in problems concerning melting point (indicating a state change from solid to liquid)\nOr it could be delta H (vap) which is the enthalpy of vaporization, used in problems concerning a boiling point (indicating a state change from liquid to gas)\n\nHeat calculations are done using the formulas:\nq=m x (delta T) Cp <-- Used when there is a temperature change, but no state change\ng= m x (delta H fus) <-- Used for state changes from solid to liquid\nq= m x (delta h vap) <-- Used for state changes from liquid to gas
1003847
The study of heat and how it behaves.
977787
Are you asking about thermal conductivity or specific heat?\nAnd why are you not doing the research you should be doing:\nhttp://www.engineeringtoolbox.com/specific-heat-metals-d_152.html\nhttp://www.engineeringtoolbox.com/thermal-conductivity-metals-d_858.html
587798
Specific heat varies with changes of composition and temperature. The specific heat of a material can be calculated by hand or by using a process simulator.\n\nThe attached link can be used to obtain specific heat (and other properties) for a handful of pure components.\n\nBest wishes !
1137013
Thermal Properties Conditions \nTemp. (K) Pressure (Pa) \nMelting Temperature  1357.77 K   101325  \nBoiling Temperature  2835.15 K   101325  \nCritical Temperature  8280 K     \nFusion Enthalpy  208.7 J/g 0  101325  \nHeat Capacity  385 J/kg-K 298.15 more...  100000  \nThermal Conductivity 401 W/m-K 300 more...  101325
1128546
specific heat Q = mc(t2-t1)\nput everything in SI units..\nthen \n\n40,000= 500/1000 * c(68-20)\n40000=0.5* 48*c \nhence c= 40000/24= 1666.67 joules/kg oC.
751358
they have a high specific heat capacity,\nBecause it takes a lot of energy to make them increase in temperature.
360214
Regarding the heat capacity of neon, I was able to find the following information along with some other facts about neon at Dr. John Grohol's site, "Psych Central."\n\nNeon\nHeat Capacity: (25 °C) 20.786 J/(mol·K)\n\nIncluded below is the source link for this information, for more data about neon.\n\nHope this helps!
464223
'c' is the right answer.\nuse I law of thermo...\nU=Q-W\nU=Q-Q/4\nU=3Q/4\nBut U=n*C*T where n is moles,C is molar heat cap.for const volume.\nLet us assume that the heat absorbed during the process as\nQ=n* A*T\nwhere A can be defined as molar heat capacity for the process.\nso , n*C*T=3*n*A*T/4\nA=4C/3\nFor a diatomic gas C=5R/2(C=no.of degrees of freedom*R/2)\nA=4*5R/3*2\nA=10R/3
755161
The heat energy Q  that must be absorbed by a mass m with specific heat c raises the temperature of the mass from temperature T1 to temperature T2: \n\nQ = mc(T2-T1)\n\nThis assumes there are no other energy losses or gains to the system.
174082
you will need its specfic heat of coal by searching abt it.\nthe formula for calculating heat energy is\n\nq=m *c *(t2-t1)\n take SI units . the temperature differene is 200 and m is 1 kg of coal .if specific heat c is 1, then heat energy will be 200 joules/.
537035
Formula:  J = K*m*(T2-T1)\n\nSince both K & m are 1 for your problem, J = 125 Joules\n\nK is the specific heat defined as 1 for water.  Varies with other materials.  Also this formula is not strictly true for 1 liter unless you assume the 1 liter weighs 1 kg.  Liters are volume and the formula is for mass.
1175443
Temp (K)    viscosity (cp = 1mPa*s)\n1080                  1.030\n1100                  0.985\n1120                  0.944\n1140                  0.906\n1160                  0.870\n1180                  0.837\n1200                  0.907\n\nMore data at intermediate temperatures, as well as a parameterized equation for viscosity as a function of T are given in the source listed below.
1134140
Depends on the thermoconductive properties of a certain material. Copper for example will heat up or cool down very fast.
157547
The maximum possible coefficient of performance, B, can only happen in an ideal heat pump, or the Carnot heat pump. The formula for coefficient of performance is:\n\nB=Tl/(Th-Tl) where Tl is the low temperature and Th is the high temperature, both in kelvin.\n\nB= 266 K/(295 K - 266 K)\nB=9.17 is the maximum possible coefficient of performance.
223542
thermodynamic factors as well as the orientation and relative energies of the pi molecular orbitals involved.
295266
water\nits specific heat is 4.18 kJ/kg(degree)C\nits much more highthan any substance available.\nthats why its used in car radiators