Write the steps you would take to solve this equation?
374296
First, simplify [a(b+c)=ab+ac]\n +8x -8 +3x = -8x\nSecond, combine like terms on each side [ax+bx=(a+b)x]\n +11x - 8 = -8x\nThird, isolate a variable [if a=b, then a+c = b+c]\n 19x - 8 = 0\n 19x = 8\nFourth, eliminate coefficient [if a=b, c =/= 0; a/c = b/c]\n x = 8/19\nFinally, evaluate.\n 8([8/19]-1) + 3(8/19) = -8(8/19)\n 8(-11/19) + (24/19) = -64/19\n -88/19 + 24/19 = -64/19\n True
596087
This is very straightforward. Which step are you having trouble with? The same goes for your other question.
444216
Write the Kc and the Kp\n\nChange PV=nRT to P/RT=(n/V) to P/RT=(concentration) note n/V is concentration.\n\n\nSubstitute P/RT for each concentration in the Kc.  You will see the Kp in the equation with extra R's and T's.  Finaih solving.
704941
The second equation can be rewritten as:\n3x + 2y = -1\nMultiply both sides by 2\n6x + 4y = -2\n6x + 5y = -7 (this is the first equation)\nSubtract the first equation from the second one.\ny = -5\nNow, plug the y = -5 into the second equation:\n3x +2(-5) = -1\n3x - 10 = -1\n3x = 9\nx = 3\nSo your solution is x = 3 and y = -5
164045
What do you want a step by step set of instructions or a balanced equation?\n\n2C6H5OH + NaOCL = 2C6H50 + NaCl + H2O
728397
You need to first balance the equation.\n\n2CO + O2 --> 2CO2\n\nUsing this you find the answer to be D.
969755
Relax\n\n1)) (5x + 7) + (x - 2) = 5x + 7 + x - 2 = 5x + x + 7 - 2 = 6x + 5\n\n2)) 2 X length + 2 X height = perimeter\n\n  (2 X x) + (2 X (x - 3)) = per = 2x + (2x - 6) = cir = 2x + 2x - 6\n\n  perimeter = 4x - 6,   or 2 ( 2x - 3)\n\n3)) same as # 2;\n\n  2 X (t + 5) + 2 X 2t = 2t + 10 + 4t = 2t + 4t + 10 = 6t + 10 = per\n\n4)) (t - 5) - (3t - 1) = t - 5 - 3t + 1 = t - 3t - 5 + 1 = -2t -4\n\n  or -2 (t + 2)
886265
gotta put the equation into y=mx+b first\ny= 1/3x - 1\n\nperpendicular would be y = -3x (+ or - any #)
858168
1. 14x^2 +21x\n\na good way to start would be to factor out any common terms:\n\n7(2x^2 + 3x)\n\n7x(2x + 3)
835153
.more kids homework... factoring?\n1. rewrite the middle term as the sum of two terms and then factor completely 15x^2 -21x +6\n\n3(5x^2-7x+2)\n3(5x^2-5x-2x+2)\n3(5x-2)(x-1)\n\n2. rewrite the middle term as the sum of two terms and then facto by grouping. x^2 - 14x +45 \n\nx^2-9x-5x+45\n(x-9)(x-5)\n\n3. rerewrite the middle term as the sum of two terms and then facto by grouping x^2 + 19x +90\n\nx^2-10x+9x+90\n(x+10)(x+9)\n\n4. rewrite the middle term as the sum of two terms and then facto by grouping x^2 -2x -63\n\nx^2-9x+7x-63\n(x-9)(x+7)\n\n5.solve x^2 = -6x\n\nx=-6
490656
Make Y=0\nyou have to have m and x though to solve b\nExample:\nY=mx+b\n0=3(4)+b\n0=12+b\n -12 on both sides of equal sign\n-12=b\nhope this helped!
77049
first you have to tell us what you're solving for.(either x or y).\nIf you want to combine like terms u have to add 2y+2y you get 4y,then you try 4y+4x = ?.\nBut you forgot what is equal to if you're solving \nfor the letter x or y
369017
Set one equation equal to one of the variables, then insert it into the other equation and solve for the second variable.  then insert that variable into the original equation.\n\nx+y=5 or x=5-y\nx+2y=6\n\nput x=5-y into the second equation\n\n5-y+2y=6 \n\nnow solve for y\n\ny=1\n\nput this back into one of the original equations\n\nx+1=5\n\nx=4
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
850884
using chain rule and product rule\n\ny'= 3x^(2)*tan(4x)\n         +4x^(3)*sec^(2)(4x)\n  = x^2(3tan(4x)+4x*sec^(2)(4x) \n\ni hope that this helps
758594
2. The equation is (y-y1)/(y1-y2)=(x-x1)/(x1-x2)\n=>(y+2)(-2-0)=(x+1)(-1-0)\n=>(y+2)(-2)=(x+1)(-1)\n=>-y-2=-2x-2\n=>-y+2x=0=> 2x-y=0 which is the required equn.\n3.The equation is (y-4)(4+4)=(x-0)/(0-4)\n=>y-4/8 =x/-4\n=>8x=-4y+16  or,8x+4y-16=0  o4 2x+y-4=0 is the reqd.equation\n4.the eqn. is (y+3)/(-3-3)= (x+2)/(-2-0)\n=>(y+3)/-6=(x+2)/-2\n=>-6x-12=-2y-6\n=>-8x+2y-6=0 or,-4x+y-4=0 which is the equired equation
607838
where is the rest of the equation?\n\n2x+5-x+3x+2-2x+5x-3x+8-4x+2+1x\n\nCollect like terms:\n\n2x-x+3x-2x+5x-3x-4x+1x+5+2+8+2\n\nRelocate the terms:\n\n1x+2x+3x+5x-x-2x-3x-4x+5+2+8+2 = 37\n\nAdd like terms:\n\n11x - 10x + 17 = 37\n\nNow, subtract all terms and solve from there.\n\nx + 17 = 37\nx = 20