You have a cylinder, length = L, diameter = D. If you drill a hole perpendicular to the center line of?
358957
Volume = pi * r^2 * h\n\nr is 1/2 the radius of the drilled hole = (D'/2)\nh is equivalent to the diameter of the original cylinder = D
70150
so you have to find the surface area of a cylinder that is 35diameter and 40 ft tall. or \n((3.14)17.5^2)40)
917169
L = μ(0) μ(r) N^2 A/l\n\nwhere\n \nμ(0) is the permeability of free space (4π × 10-7 henrys per metre) \nμ(r) is the relative permeability of the core (dimensionless) \nN is the number of turns. \nA is the cross sectional area of the coil in square metres. \nl is the length of the coil in metres\n\nHere we assume that μ(r) = 1, since the solenoid doesn't enclose anything like a metal core. Then\n\nL = [μ(0) N^2 (πR^2)] / l, where R is the radius of the solenoid\n\n= [(4π × 10-^7)(2920)^2(π(0.005)^2)] / (0.1)\n\n= 8.44 × 10-^3 henries
116020
Volume = pi*r^2*h\n\nWhere pi = 3.14.159...\nr = raduis of cylinder in feet\nh = height of cylinder in feet
315845
Rule of thumb, 4 one thousands of an inch (0.004") per one inch of diameter of the cylinder bore. Example: three and a half inch bore would be 0.014".
863660
Use volume formula for a cylinder:\n\nV = pi r² h\n\nYou know r = d/2 = 18/2 = 9 ft.\n\nYou know h = 47 ft.\n\nSo, using 3.14 for pi as your question requests, you get the following:\n\nV = 3.14 * (9 ft.) ² * 47 ft.\n\n= 3.14 * 9 * 9 * 47 ft ³\n\n= 11,954 ft ³ (rounded)\n\nHope that helped!\n\n.
1142473
The volume of a cylinder equals the (area of the base)*height = π r2h
813209
perimeter= 4(L+W+H)\narea= length times the width times the height
938684
If you desire the external surface area of the pipe,\n\nA = pi*d*L\n\nMake sure d & L are in the same units and your answer will be in those units squared.\n\nIf you are looking for the internal cross sectional area:\n\nAc = (pi*d^2)/4
403060
(Front Diameter) / (Rear Diameter) = ratio of front to rear\nIn this way,\n10 / 4 = 2.5 = ratio of front to rear
26120
If the pressure's the same, then the change in volume would be "(3.61*A*X)/SQRT(Y) Where: A = Cross-sectional area of discharge\npipe in square inches\nX = Horizontal distances in inches\nY = Vertical distances in inches"
100213
Diameter will be 1 units\n\nCircumference =piD\nif Circumference =pi\nthen D=1
1124334
two circles, in parallel planes with the line connecting their centers forming right-angles with each plane in all directions. ... and the walls comprising the set of line segments one of whose end points is on one circel and the other end point on the other circle withe the property that the segments at each point on circle(A) is the minimum distance to circle(B).\n\n.. or, since you use the word "cylinder" in the question:\n\na cylinder, each of whose end-faces is a circle.
246604
The volume of a cylinder equals the area of the base times the height.  The area of the base equals pi times the radius squared.\n\nSo first you need to find out the area of the base. \nBase equals pi times radius squared.\npi = 3.14\nyour radius is 3 inches\nSquare your radius first.  3 squared = nine\nthen multiply by 3.14\nnine times 3.14 = 28.26\nNow, your base is 28.26\nSo multiply your base times your height.  Which would be \nBase = 28.26 inches x Height 6 inches = 169.56 cubic inches\nAnswer is 169.56 cubic inches
877827
Is that a single diameter?  Your statement is ambiguous.\n\nAssuming that it is, find the distance between those two points.  Halfway between the two points is the center
906875
The trick is turning the word problem into equations.\n(Key: length = l; width = w)\n\nThey tell you the length is 3 feet more than twice the width, so:\nl = 2w + 3\n\nThen they tell you the perimeter (which is twice the width and twice the length) is 36, so:\n2l + 2w = 36\n\nYou should be able to take it from there.
986706
You want to use a 23/32 .718 drill bit.\nStart by spot drilling with a 1/4 or so then drill with the .718 bit.