can you represent 100 by using 9 ,9times?
373987
of cos!\n\n9*9 + 9 + 9 + 9/9 + (9-9)9
838732
000000 to 999999 --> 1 million combinations\n\n10 choices for the first digit\n10 choices for the second digit\n10 choices for the third digit\n10 choices for the fourth digit\n10 choices for the fifth digit\n10 choices for the sixth digit\n\n10 x 10 x 10 x 10 x 10 x 10 = 1 million\n\nHowever, if you disallow 0 as a starting digit then you have the following:\n\n*9* choices for the first digit (1-9)\n10 choices for the second digit (0-9)\n10 choices for the third digit (0-9)\n10 choices for the fourth digit (0-9)\n10 choices for the fifth digit (0-9)\n10 choices for the sixth digit (0-9)\n\n9 x 10 x 10 x 10 x 10 x 10 = 900,000
1126193
11,000 + 1,100 + 11.\n\n12,111.
678031
psbhowmick, 99 is divisible by 9, but 199 is not. You can't find the remainder simply by looking at the last 2 digits. For instance, the remainder of 22654785/19 is 2, not 9 as you suggest.\n\nDividing by 19, hmmm... the only shortcut I can think of is to use the mod function on your calcutor. Sorry.
731003
ok.. um..if i remember correctly you would multiply 10 (the number of digits possible) x 4 (the number of digits) that makes 10,000 different possiblitiies... can i name them? probably...but wow.. that's a lot of time and energy.
283337
FORTY\n+ TEN\n+ TEN\n--------\nSIXTY\n\n\n29786\n+ 850\n+ 850\n--------\n31486
857564
If this is for a statistics course, chances are you are allowed to run out 22.8 times.  If you must round, 23 would be more correct, but as answers never come out to integers in statistics, my guess is that you are to put the decimals.
880056
Easy way to remember...\n\n(1) the digits in the multiples of 9 also equal 9 when added together such as 18 (1+8=9) and 45 (4+5=9).\n\n(2) multiples of 9 less than 100 'reverse' half way thru (09 & 90, 18 & 81, 27 & 72, 36 & 63, etc.)\n\n(3) start with 09 and add 1 to the tens column and subtract 1 from the ones column. (09, 18, 27, 36, 45, etc)
376218
Not sure how many you need, but here are the first few:\n2,3,5,7,11,13,17,19,23,29,31, 37,41,43,47,53,59,61,67, 71,73,79,83,89,97,101
429263
basic numbers are numbers 0-9
15502
35\n  16\n+ 47\n____\n  98\n+  2\n____\n 100
474508
In the number: 495,703 the value of 9 is 9 X 10,000 = 90,000.\n\nActually IF I recall correctly (been a long time since 3rd grade math) the value is 10,000.\n\nI think this lesson is probably about learning the value placement in the positioning of numbers so that understanding big numbers becomes easier. But the wording of this question to a 3rd grader (AND some other people too) IS not easy to comprehend, so hopefully, I am telling this answer correctly.\n\nSounds like it's time for a parent/teacher conference.
917858
Only 1, 3, and 4 are allowable for the hundreds digit.  Anything goes for the rest.  So there are 3 choices for the hundreds digit, 5 choices for the tens digit since you can't use whatever you cose for the hundreds, and 4 choices left for the ones digit.\n\n3*5*4 = 60
887
I don't know about there being 9 but this site should help.
1169470
792\n\n1 thru 9 = 9 digits\n10 thru 99 = 180 digits (90 numbers with 2 digits each)\n100 thru 300 = 603 digits (201 numbers with 3 digits each)\nTOTAL = 792
633476
yes! wednesday = 23+5+14+5+19+4+1+25=100 [yea i have no life]\n\nsorry to ruin the whole 100% attitude thing... maybe that only works on wednesdays or something XP
290916
100...it's based on age