how do you connect4x3 dots without retracing your previous dots?
366770
go across then down one and back across then down and across\n>-- meaning across the direction the arrow points\n|-- meaning go down one dot\n>****|\n|****<\n>**** and you're done
302670
You need to change the size of the "slice" to change the size.  Make sure the slice layer is showing, increase the size of the relevant slice making sure it doesn't overlap a different slice.  \n\n-HTH
128086
If you are talking about where the dots are placed, then you can place them in order, just make it logical. No particular way is "best."
531033
Draw it your self on x-y plane, then determine the coordinates
410933
Let 1 2 3 4 5 6 7 8 9 A B C D be the dots, with D in the middle. (You say 1 in the middle)\n\n1 2 3 4\n5 -- -- 6\n-- -D- --\n7 -- -- 8\n9 A B C\n\nIT CAN BE DONE WITH 5 LINE SEGMENTS AND DOESN'T NEED 6.\n\nConnect 7-5-1-2-3-4-D-9-A-B-C-8-6 in a Z-shape\n\nSo I think if it needs six lines, your question was meant to be regarding 16 dots, 4 of them in the middle. It would then be similar to your other question with 9 dots.\n\n1 2 3 4\n5 6 7 8\n9 A B C\nD E F G\n? -- -- !\n\nConnect 1-2-3-4-8-C-G-! and then proceed as for 9=dot problem, F-A-5-6-7-8-B-E-?-D-9. Six lines needed.\n\nGeneralising, an n x n square of n^2 dots will require 2n-2 lines. (for n>2)\n\nImagine a further 9 dots wrapped around the 16-dots as follows\n\nH I- J K L\n1 2 3 4 M\n5 6 7 8 N\n9 A B C 0\nD E F G P\n\nConnect G-F-E-D-0-5-1-H-I-J-K-L-  M-N-O-P and then proceed as for the 9-dot problem:\n\nC-7-2-3-4-M-8-B-E-A-6\n\nwhich is 8 lines.
921939
Good Evening\n\nI think we've been avoiding this question because we can't graph here... however to get you started, create an x|y chart for each line, plug in a couple of values, and connect the dots  (for a line you only need two points, but some books recommend finding three, so you can verify you didn't make a mistake somewhere)\n\nx+y = 8\nx|y\n----\n4|4\n3|5\n2|6\n\nx - y = -4\nx|y\n0|4\n1|5\n2|6\n\nGraph the two lines, and they should intersect at (2,6) since it appears in both of the charts...\n\n~i~
302837
Yes, you can, but the representation of the vectors is going to be position dependent. So you won't be able to add a vector at the origin and another vector at another point. You would first have to 'parallel transport' one vector to wherever the other is and then add them. This type of thing is usually done in more generality in differential geometry
661921
On your number line, go one third of the way between 0 and 1 and put your point on the 0 side of one third.  If you are using graph paper, make three lines equal one unit so that each line it one third unit apart.  This way will make one third be the first line past the number 0.
696922
Let's say it's like this:\n[1 2 3]\n[4 5 6]   } Pretend the whole thing is surrounded by two big\n[7 8 9]     brackets\n\n[9 8 7]\n[6 5 4] And that the top is multiplied by this\n[3 2 1]\n\n[1 2 3]------[9 8 7]   (I'm using---as spaces)\n[4 5 6]--X--[6 5 4] \n[7 8 9]------[3 2 1]\n Multiply the first number in row one of the 1st matrix by the first column of the 2nd matrix ( 9 6 3 ). Then multiply the second number in row one by the second column ( 8 5 2 ) and then 3rd number by the 3rd column ( 7 4 1 ). When you're done, you should have the first row of a newer giant matrix set up...\n\n[1(9) + 2(6) + 3(3)---1(8) + 2(5) + 3(2)---1(7) + 2(4) + 3(1)]\n\nNow, take the 2nd row of of the first matrix and multiply it the same way...(now you have the first and second rows I showed you)\n\n[1(9) + 2(6) + 3(3)---1(8) + 2(5) + 3(2)---1(7) + 2(4) + 3(1)]\n[4(9) + 5(6) + 6(3)---4(8) + 5(5) + 6(2)---4(7) + 5(4) + 6(1)]\n\nDo you notice a pattern? The column numbers that are multiplied are lined up right on top of each other... this will save you time in the future. The row numbers change, but you know they are always in the same order.\nNow, multiply the last row of the first matrix by the columns of the second matrix...(here is how the final matrix looks)\n\n[1(9) + 2(6) + 3(3)---1(8) + 2(5) + 3(2)---1(7) + 2(4) + 3(1)]\n[4(9) + 5(6) + 6(3)---4(8) + 5(5) + 6(2)---4(7) + 5(4) + 6(1)]\n[7(9) + 8(6) + 9(3)---7(8) + 8(5) + 9(2)---7(7) + 8(4) + 9(1)]\n\nNow, multiply the numbers...\n[9 + 12 + 9---8 + 10 + 6---7 + 8 + 3]\n[36 + 30 + 18---24 + 25 + 12---28 + 20 + 6]\n[63 + 48 + 27---56 + 40 + 18---49 + 32 + 9]\n\nAdd up the numbers to get the final resulting matrix...\n[30  24  18]\n[74  61  54]\n[111 114  90] \nP.S. Sorry I didn't use your numbers... this is the answer to the matrix I made up, but at least it shows you how to do it right? Hope this helps!!!
658966
I searched online and it looks like a program called VCDGear could do it. Check out the source link below and hopefully this will solve it for you.
409096
Use the line tool.  You can also use the rectangle tool and then transform the rectangle by hitting CTRL-T.  Move your cursor just outside the corner bounding box handle until it turns into the rotate cursor.  Rotate at will to create diagonals.
481919
It is impossible to trisect an arbitrary angle using only compass and straightedge (but bisection is possible). No there is no mathematical technique (i.e a theoretical construction technique to do so, even if impractical). It cannot be done exactly. The best that can be done is approximation. One can imagine, I suppose, a radial arm (our radius rotating about a fixed  point) whose rotation speed was controlled very precisely by a computer and the speed could be extremely slow and a laser could be used with a super accurate quartz timer to 'print' a dot at fixed intervals thus dividing an arbitrary angle as desired. Certainly, technologically feasible, but I haven't heard anything about it, and it would be a technological technique, not a mathematical "breakthrough".
125119
add them together and divide by 3
355118
download the pathes.\nchk if you have enough memory
661969
Adjust until the diagonals are equal.
452780
use some tape and make 4 x's in a box shape with another x in the middle. the hop on one foot hitting all x's as quick as you can moving from bottom x's to top x's then back down and that is one set. then switch feet. i usually time myself and do 5 set continually trying to always beat my time.
325009
Remember the connect the dots game as a child, with numbered dots?  By connecting the dots in sequence a picture shows up.  So by connecting the dots, everything becomes clear, you see the big picture.