I need to compare answers for algebra equations?
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1. 4x+3y=4 solve for y, then find slope and y intercept:\n\n4x + 3y = 4\n3y = -4x + 4\ny= -(4/3)x + (4/3)\nY-intercept is 4/3\nSlope is -4/3\n\n2. Write an equation in the form of y=mx+b of the line that is discribed. y intercept is -4 and the line is parallel to the line whose equation is 2x+y=8\n\nThe line whose equation is 2x + y = 8 is written y = -2x + 8 in slope-intercept form.\n\nThe parallel line with y-intercept 4 is:\n\ny = -2x + 4\n\n3. write the point-slope form of the line of the ordered pairs then use the point-slope form of equation (-2,-5) and (6,-5).\n\nThe slope is 0.\n\nThe point-slope form of the line is:\n\ny = 0x -5 = -5\n\n\n4.  Write an equation for each line in point-slope form of equation and slop-int. passing through (-4,2) and perpendicular to the line whose equation is 3x - 2y + -5 = 0\n\nFirst, rewrite 3x - 2y + -5 = 0 as \ny = (3/2)x -(5/2)\nThe perpendicular line has slope -2/3.\n\nThe point-slope form of the line with slope -2/3 passing trhough (-4,2) is:\n\ny - 2 = -(2/3)(x + 4)\n\nThe slope intercept form of the line with slope -2/3 passing trhough (-4,2) is:\n\ny - 2 = -(2/3)x - 8/3\ny = -(2/3)x - 2/3
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http://www.gateways2learning.com/Algebra/Algebra.htm\n\nAlso try here.......\n\nYou may want to reconsider having it solve the answer for you, always know how to do the breakdown, it will help you to know "how" to go about it when you take a test.\n\nGood luck.....................
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It has been a long time, here are suggestions:\n1. 5x^3 + 11x^2 + 3x + 1  \n2. 4x^3 - 13x^2 - 8x + 7 \n3. 2x^4 - x^3\n4. 21x^2 + 26 x + 8
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purplemath.com is good, and so is coolmath.com/algebra
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Ask Dr. Math is my favorite.  You can also try Mathworld, though I usually find that I leave it more confused than when I entered.
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It's a variable comparison question\n\nax-3x+5=a+b\na(x-1)-3x+5=b\na(x-1)+5=b+3x\nax-a+5=b+3x\n\nnow comparing variables on both side of the equation\n\nwe get a=3\nn a+b=5\n\ntherefore,b=2
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go on\nwww.hotmath.com
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You should "cancel out". If you are saying what I think you're saying, then that's what you should do. Narrow it down until you have the answer. For example:\n\nx -10=2 + 2x   : This is your algebraic equation.\n\nYou should subtract 2 from each side, to get rid, or "cancel out" the 2. You get this:\n\nx-8= 2x\n\nNow you want to narrow down the x value so it just equals x. Subtract x from both sides.\n\n-8 = x\n\nTa da! There's a simple algabraic equation. If you have any questions, or if I was unclear, feel free to send me a message.
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Just do a search for "algebra." You'll find a lot of web sites, including:\nhttp://mathworld.wolfram.com/topics/Algebra.html\nhttp://www.purplemath.com/\nhttp://www.algebrahelp.com/
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www.hotmath.com\nhlps me all the time XD
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First of all, solve both equations. So the first would be..\n\n3(2x+1)>5-2x \n     6x+3>5-2x (add 2x to both sides)\n         8x>2 (take 3 from both sides)\n           x>0.25 (divide both sides by 8)\n\nThe second would be..\n\n2x^2-7x+3>0\n4x^2-14x+6>0 (multiply both sides by 2)\n(2x-6)(2x-1)>0 (factorisation)\n \nReplacing > with =..\n\n2x-6=0,      2x-1=0\nx=3,                 x=0.5\n\nSo to satisfy both criteria, x must be greater than 0.25, greater than 0.5 and greater than 3. \n\nSo the answer is that x > 3.
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check out www.quickmath.com\n\nAlmost everything is there.
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Look for a mathematic answer book
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There are several simple rules for re-arranging and solving equations.  It would be in your best interest to try and learn them, they aren't very hard.
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Look up "Algebra Solved 2005" or "algebrator", these two programs not only solve problems, but they give step by step solutions for understanding. they have tutorials and practice test. I went from knowing none to fairly advanced in a few weeks.
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If you're taking the course through a bricks-and-mortar college, see if the college has math tutors available.  \nIf you're taking the course online or your school does not have tutors, there are websites online with free worksheets to help you with troubling concepts. Try one of the following or search google for "algebra help":\n\nhttp://www.algebrahelp.com/lessons/\nhttp://www.algebra.com/\nhttp://www.purplemath.com/\n\nIf it's really troubling you and worksheets just aren't cutting it, try purchasing a game from Best Buy or another computer store that focuses on Algebra skills.  They really do help.
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hey there is a good website to check your work \nits www.webmath.com i use it all the time