what is difference between the addition of even numbers below 2006 and the addition of odd numbers below 2006?
373133
odd numbers added to another odd number will always equal an even number.
1033912
It's actually pretty easy.  When you take a number, jumble around it's digits and then subract the new number from the old, you are always going to get a difference divisible by 9.  Since 9 divides the sum of the digits of all numbers divisible by 9, then nine divides the sum of the digits of the difference.  When you give all but one of the digits (and knowing that the last one is not 0), the computer just takes the sum of the digits you gave it, and subtracts it from a multiple of 9 (so that the remainder is between 1 and 9).  The number that you picked will always be the remainder.
1093659
Or is it this:\n300+20+4\n400+60+7\n100+10+1\n800+90\n60+8\n1000+600+50+4
624572
Your question does not make sense, but the multiplication sign and the addition sign are not always interchangable. Life is not fair, life is  B!TC#
1081387
here is one\n024331\nassuming that the 2&3 numbers are the only evens\nassuming only one one\nassuming  2&3 numbers are not same numbers\nassuming only one set of repeating numbers\nalso 024551, 024771, 024991, 026331, 026551, 026771, 026991, 028331, 028551, 028771, 028991, 042331, 042551, 042771, 042991, 046331, 046551, 046771, 046991, and so on.
203784
In an odd-number base the number x is odd if Q(x) is odd, and even if Q(x) is even.\n\nIn an even base the number is odd if the last digit is odd, and even if the last digit is even.
876511
not adding in for the extra partal days each year 31536000\n\nadding in for the extra partal days each year 31556926.08
280437
Based on minimal search, you may have an illegal form.\n\nYYYYDD would give you 200617\nYYYYDY would give you 2006Fri\nYYYYDDD might give you nothing, might give you 2006DDD, or 200617D or 2006017.\n\nIn cases like this, try the emperical method. Test it and see what you get.
713733
Problem 1: in 2005, t=2005-1998=7\nin 2008, t=2008-1998=10\namt property appreciates by between 2005 and 2008\n= f(10) -f(7)\n=75,000(1.06^10) - 75,000(1.06^7)\nfind the answer by typing the above into a calculator\n\nI don't really understand problem 2. What are you trying to find?\n\nI'm thinking it could be either P or r:\nTo find P: A=Pe^rt\ne^rt=A/P\nIn(e^rt)=In(A/P)\nrt = In(A/P)\nr = [In(A/P)]/t\n\nTo find P:\nP = A / [e^rt]\n\nI hope these were helpful.
984379
It's when you make mistake in addition. But I won't say the sum can't be put correctly but It can be made correct by changing the sign You could change the sign from + to - . Now can I have my ten points ? Please ???!
265044
2k = 2000\n2k3 = 2003\n\nUsed to represent years. Started using after Y2K bug.
1155709
all odd numbers? but i dunno any other significance
628648
None. The two numbers have no common factors, bar -1. You mean exactly (with no remainder) not evenly.
991923
For the first one, 4<-2<6 does become -2>x>-3 (you do have to flip the signs) and yes, it is still an "And" statement, just in reverse (or in other words, -2>x>-3 is the exact same thing as -3<x<-2). For the second one, you don't actually have to multiply by 10, but you should get the same answer either way. I got 0.84<x<1.76.
501034
It's unknown! Here's a couple links if you haven't looked at them already.\n\nhttp://mathworld.wolfram.com/OddPerfectNumber.html\n\nhttp://en.wikipedia.org/wiki/Perfect_number#Odd_perfect_numbers
451598
You do add first, in a manner of speaking.  Addition and subtraction are of equal importance because subtraction is the addition of negative numbers.  The problem could equally look like this:\n\n5145 + (-16) + 311 + (-19)\n\nIf the problem was performed adding the middle numbers first, you are actually adding 311 and NEGATIVE 16.  If instead you add 311 and 16, then subtract that number, you would be making the 311 a negative as well.  It would look like this:\n\n5145 - (16 + 311) - 19\n\nand result in this:\n\n5145 - 16 - 311 - 19\n\nwhich was not the original problem.\n\nFinal answer: 5421
1028919
B.\n\nBut it is not actually correct.  %'s are generally figured on a standard 360 day calendar year, this problem uses 365