If torque is shown in amps, How can I convert Amps into lbs-ft?
366746
The answer is, you don't.  Torque isn't measured in amps unless it's the signal from some electronic transducer that measures the torque and outputs a signal for an electronic display/data recorder.  And if that were the case, you'd calibrate known torque values to the signal output.
748663
The answer hippoterr... gave you was OK till the last step. It's always is wise to check the units and see if they make sense. His result is in sec/rev.\n\n2 x Pi x11.5 / 30 = 2.4 He left out the units in the math part, but if you include them you see that the result is in sec/rev.\n\nUnit conversion can be confusing. A better way - you know you want it to be something per sec so start with:\n\n30 meter/sec. Then to convert to rev/sec multiply by 1, in a special form.\n\nIn the form 1 rev/(2 x Pi x11.5 meters). This = 1, right? The top and bottom are equivalent. So back to \n\n30 meter/sec * 1 rev/(2 x Pi x11.5 meters) = .415 rev/sec\n\nYou understand why weight/mass wasn't needed? It's the acceleration that results from the rotation,  and  a = F/m.
478844
1.0 Ton = 12 MBH\n\nI would get a confirmation on this though.
8174
1 kilowatt = 1.34102209 horsepower\n\nIf you want to convert anything, go to http://www.google.com/. Type in, for example, "convert 20 kilowatts to horsepower" and Google will do the conversion for you.
328811
power to weight ratio = power/weight.\n\nIn quoting it, you must give the units, e.g.\nhorsepower per ton, watts per pound, kilowatts per kilogram...
266330
let' see  one ton is 2000 pounds and there are 16 ounces to the pound so 2000 x 16 = ???? c'mon, you can do it, I have faith in you.
388172
Torque is the product of a force and a lever arm. We have the torque as .85 newton*meters. We can get the answer by a simple dimensional analysis. A newton is actually a kilogram*meter / second^2. We have the length and the mass. So we just need the angular acceleration. Divide .85 N m by .33 m (not 33 cm), then divide this result by .75 kg.\n\nThis gives 3.43 rad / sec^2 \nSo C is the correct answer.
21035
ya torque=f*d and since the distance is zero because the applied force is at the moment of inertia... Troque is zero! bahahaah oy i hate statics.. or physics.. same thing
61304
Thy this website out: http://www.convertit.com/Go/ConvertIt/Measurement/Converter.ASP
901138
There are several wrong answers in the preceding.\nThese are correct:\n\n(lbf) = (lbm) * (acceleration in g)\n(lbf) = (slugs) * (acceleration in ft/sec^2)\n\n1 g = 32.174 ft/sec^2\ncorrespondingly\n1 slug = 32.174 lbm\n\nIf you know acceleration in in/sec^2, the corresponding unit mass would be 12 slugs or 386.09 lbm. This unit does not have a popular name that I am aware of.\n\n1 lbm = .45359 kg\nAll conversions are approximate
290214
Its the standard measurement for torque like ft in leght/ it is how many pounds of pressure it can produce  /the chevy duramax diesal can produce 650 Lb-Ft of torque the best in it's calss/ these is one of the things that allows it to pull more easier
60438
vol=17*5*3 ft^3\nwt=2300lbs\ndesity=wt/vol=9.02 lbs/ft^3
1009332
Convert everything to inches, then multiply.  LxHxW.  They need to be the same units, though.
1051362
Unless you have a way to measure the output torque, any method you use will be an estimate. \n\nIf all you want is an estimate and there is a way to determine or estimate the load requirements of the driven equipment then you have a chance. \n\nAs an example:\n\nIf it is driving a 100 gpm water pump with a known efficiency and flow rate you can measure the differential head, then it is possible to estimate the load requirement of the pump and therefore the output of the motor. Be careful, efficiencies and flow rates can vary with head requirements.
161453
you cannot directly convert liters to pounds without knowing the density of a substance. Once you know the substances density than it is a matter of conversion using like units from the density.
920087
to solve your problem with minimal work, just bring your bike into a LBS and they should have the tool to take it out, shouldnt cost you a dollar or two, they might just do it for you for free! \n\nCheers
32262
Foot-pounds describe a force.\nUsually used to specify a turning force such as a lever.\nThe value is the distance multiplied by the weight.\nSo if you double the length of the lever, you will double the total turning force.