analysis   2,3,4,15,16,_,_,_  what comes next?
362891
your answer is 255.  I believe it works something like this (look at the one integer gaps), remove them at one integer spaces (2,4) (3, 15) (4,16) what do these have in common?  Whats the next chain to follow?  4 is divisible by 2, step up 15 is divisible by 3, step up 16 is divisible by 4 step up and the next number divisible must be whatever is divisible by 15, the only answer which is given and fits that description is D 255.  I hope you can follow the logic :)  I dont see any relation where three numbers can be sequenced in relation here.  I know that next you could say 224 is divisible by 16 but there is nothing left after that for a third answer to form a chain with what is left to choose from (19 and 20)  Note also that by using this method the number which divides into 255 by 15 is in fact 17 to continue your string 15,16,17.
1027973
the 3rd one is correct, but I get -(3+b)/b+2 and 2 for the first 2
587245
If you have n events where the number of outcomes for the first event is p1 and the number of outcomes for the second event is p2 and so on up to the nth event (pn), then the number of total ways the event can occur is\n\n(p1)(p2)(p3)...(pn).
670785
series, or sequence no idea, just a guess, u need to explain it better.
873410
1.  (x + 9)(x - 9)\n2.  (t + 2)(t - 2)\n3.  (b + 12)(b - 12)
23639
I depends on what the last # is if it continues as a 1 then the answer is 3
893652
with 1q, 2 ways (0,1 n)\nwith 3d, 1 ways (0 n)\nwith 2d, 3 ways (0,1,2 n)\nwith 1d, 5 ways (0,1,2,3,4 n)\nwith 0d, 7 ways (0,1,2,3,4,5,6 n)\n\nTotal of 18 ways
597439
=[(4+3x)/x] + (2/3)[(5+3x)/x]\n=[(4+3x)/x] + [(10+6x)/3x]\n=[(12+9x+10x+6x)/3x]\n=[(15x+22)/3x]
512141
1/2, 2/4, 3/6, 4/8, 6/12, 7/14, 8/16 . . .
1125943
The order of operations are :\nParenthesis\nExponents\nMultiply\nDivide\nAdd\nSubtract
971669
1. 1s2 2s2 2p6 3s1\n2. 1s2 2s2 2p6 \n3. 1s2 2s2 2p4\n4. 1s2 2s2 2p6\n5. 1s2 2s2 2p6 3s2 3p6 3d7 4s2
465985
1 - D\n2 - B\n3 - C\n4 - C
376218
Not sure how many you need, but here are the first few:\n2,3,5,7,11,13,17,19,23,29,31, 37,41,43,47,53,59,61,67, 71,73,79,83,89,97,101
446786
11.\nT, H, E, A, L, P, H, A, B, E, T
868097
-\naside from 1,\n2,3,4,6,12
367516
here are the anwsers in order from top to bottom \n-T\n-T\n-F\n-F \nhope this helps
466757
1 1 2 3 5\nif last=1(the first number) \n   next=1(the second number)\n   temp= last+next=1+1=2(thethird number)\nthen\n    next=temp=2\n    last=next=1\n    temp=last+next=1+2=3(the fourth number)\nlike this way you can get all it's numbers