the base of a solid is a region in the first quadrant bounded by the x-axis, the y-axis, and the linex+2y=8.if
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If I'm picturing this right, your solid looks like a triangle when looking at it from the z direction, but like half a cone (albeit a slanted cone with a side perpendicular to the base) when looking at it from the x direction.  If so, then we can use an integral to find the volume.\n\nIf we take slices in the x direction, we're looking at the volume of a half of a cylinder.  Since the volume of a cylinder is pi*r^2*h, and the cross sections are only semicircles, the volume of our slices is really (1/2)pi*r^2*h.\n\nOur height h is dx, since we're slicing perpendicular to the x-axis.\n\nWe have a diameter for our circle given by the equation for the upper bound - x + 2y = 8.  Rewritten in slope-intercept form, we have y = -x/2 + 4.  Since we need the radius for our integral, we take half of this: y = -x/4 + 2.  So our integral becomes (using S as the integration symbol):\n\nV = S (1/2)pi*(-x/4 + 2)^2 dx\n\nAdditionally, we're evaluating from x = 0 to x = 8, the point where the line meets the x-axis.  So,\n\nV = (1/2)pi S [(x^2)/16 - x + 4] dx\n= (1/2)pi[(x^3)/48- (x^2)/2 + 4x]\n= pi[(x^3)/96 - (x^2)/4 + 2x]\n\nEvaluating from 0 to 8,\n= pi{[(8^3)/96 - (8^2)/4 + 2(8)] - [(0^3)/96 - (0^2)/4 + 2(0)]}\n= 16pi/3
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It is the coordinate system.  X plane is when y and z are constant, for example.
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the y axis depend on the x axis so if u were doing a graph the x axis would be at the bottom
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1. y-axis\n\n2. 2nd quadrant\n\n3. 2nd or 3rd quadrants\n\n4. 2x + 3y = 6 => y = 2 - (2/3)x\n\n5. x - 2y = 8 => y = (1/2)x - 4\n\n6. x - 3y = 4 => x = 4 + 3y\n   Only (a) is a solution\n\n7. y - 2x = -1 => y = -1 + 2x\n   (b), (c) are solutions
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-180 is just like 180 degrees (pi), so it's on the -1 position coordinate on the x-axis; between the 2nd and 3rd quadrant.
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considering both y values are -2 for A and C....\n\nwe know that a straight line exists between these two points, which means that it HAS to be 1 of the 4 sides.\n\ngiven that, the coordinates or K and L HAVE to be (3, infinity (EXCEPT -2)) and (-4, infinity (EXCEPT -2))
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Actually trapezoids are Bottom Edge + Top Edge X Height /2.  Or:\n\nH(B+T)\n------\n  2
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The points where a line crosses the vertical and horizontal axes are known as the vertical and horizontal intercepts. (These points are often referred to as the x-intercept and the y-intercept.) Given a linear function f(x) = mx + b,
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This represents a plane that goes through the origin. It is perpendicular to the vector <1,1,1>.
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It is a median of a trapezoid, not a midsegment because a midsegment is used for triangles.\n\nThe formula for getting the measurement of the median would be m=1/2(b1+b2)\n\nm is the median\nb1 is base 1\nb2 is base 2\n\nm=1/2(b1+b2)\n8=1/2(6+x)         [multiply both sides by 2]\n16=6+x\nx=10\n\nYou could use the formula of a median of a trapezoid to get the measurement of any of the bases with a median as one of the given.
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height times the base area. divided by three.
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90° < beta < 180° means 2nd quadrant.\nsin beta = 12/13 \nbeta=arcsine(12/13)=67.38° in the 1st quadrant\nor 180°-67.38°=112.62° in the 2nd.\n\ntan beta = 3/4 , sin beta < 0\nsin beta<0 means 3rd or 4th quadrant.\ntan beta>0 means 1st or 3rs quadrant so we are in the 3rd quadrant.\nbeta=arctan 3/4=36.87° in the 1st quadrant. or\n36.87°+180°=216.87° in the 3rd.
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measure each diagonal, come up with the area of one triangle X it by 4, then work out the area of the base simple!
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A parabola opening down with a max at the point 0,-2.  it will also be twice as wide as a standard parabola
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A=pi*x*y \n\nwhere x is small radius from centre to circumference and y is large radius from centre to circumference.
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y=1 is a straight line parallel to x axis\nx=(-1/4) is a straight line parallel to y axis
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In quadrant II, the x-coordinate is negative and the y-coordinate is positive.\nSo in which quadrant is the x-coordinate positive and the y-coordinate negative?  The fourth quadrant.\n\nCarla = z\nOdell = 3z\nKai = 3z - 8\nAdd everything together.\nz + 3z + 3z - 8 \n= 7z - 8  \n(B)