Can anyone explain how this deals with Newton's laws of motion?
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Ya it actually verifies the Newton's laws.\n\n>> As per Newton's 1st law of motion, an object continues \nto be in its of rest or of uniform motion unless acted \nupon by an external force.\nIn that ad, the objects were in rest but when some object\nacted upon them, they came to motion.
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this seems an easy question but most of the student get it wrong since it is so easy to mess up your mind. it was a part of an exercise for my University exams. it makes you realise what is going on with spring ...just consider it as a opposing force. the body will drop and will expirience g --> it will accelerate. at the same time it will also expirience the sping;s opposing force.\n\nit will accelerate till the force become equal. this is the importnat factor. weight will keep on accelerating the body till it is completely cancelled by the spring force.\n\nso when \nFs = Weight then Velocity is maximum. \nso kx =mg =>\n\nx = mg / k.  (at this displacement the velocity  will be maximum)\n\nat this specigic point due to the theorem of conservation of energy we get that.\n\nkinetic energy + sping stored energy = potential energy at the start.\n\nso \n1/2mu^2 = (m*g)^2 / k => (be carefull mass = 76.7/1000kg)\nU = \n\nU = sqrt (( m*g^2)/k)) => u = 0.361m/s 9\n\nIF THE ALGBRA IS CORRECT\n\nNOW AFTER THAT POINT the body will still travel due to inertia and the springs force  larger now than gravity wll slow it down and bring it at rest \nat that point all the potential energy (due to height difference) will be transfornmed to springs stored energy therefore,\n\n1/2 k xmax^2 = mgXmax =>\n\nXmax = 2*m*g / k =>\n\nXmax = 0.02658m \n\n\n( i am at work and i believe the algebra is correct. the main point is to realise where certain things happen.)
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There is no net force acting on it. When there is a net, or resultant force acting on an object it causes an acceleration. As in this case a terminal velocity has been reached, that is no further acceleration is occuring, the resultant force is zero.\n\nThis is represented in the equation known as Newton's Second Law, or in Applied Mathematics, Newton Two. The equation is:\n\nF = ma and it means Force = Mass x Acceleration where the units are:\n\nNewtons (N) = Kilograms (Kg) x Meters per Second (ms^-1).
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The first law of Newton is, “an object is at rest or in uniform motion till a force acts on it”\n\nHence first law tells us what a force is.\n\nA force is one which changes the state of rest or state of uniform speed.\n\nAll the three laws of motion are implicated in the given example.\n\nFirst of all let us assume that the cart with the blocks is moving toward the solid barrier with a constant speed.\n\nThough both the cart and blocks are moving, the blocks are rest with respect to the cart and vice versa.\n\nThe static frictional force between the blocks and cart is preventing the relative motion between the two.\n\nNewton’s first law explains this. \n\nIf there is no frictional force between the two, then there will be relative motion between the two.\n\n Now consider the motion of the two together. Both are moving toward the barrier with constant speed.\n\nThus both will be in a state of constant speed till a force acts on them.\n\n“The cart hits the barrier” means, “The cart exerts a force on the barrier”.\nBy Newton’s third law the barrier exerts an equal and opposite force.\n\nWe are not bothered about what happens to the barrier when the cart exerts a force on the barrier but we are concerned about the reaction force- that is the force exerted on the cart by the barrier.\n\nThe cart comes to rest because of this force. By Newton’s first law the state of motion of the cart is changed to state of rest. \n\nWhen we consider the motion of the block on the cart, initially before the collision of the cart with the barrier, there was no relative motion between the two.\n\nWhen the cart strikes the wall, the speed of the cart is reduced where as the speed of the block is still in the forward motion (toward the barrier).\n\nThere fore, the blocks will move forward toward the barrier. \n\nIf we assume that there is no friction, then the blocks will move forward and hit some portion on the cart and hence their speed is reduced and increased in the opposite direction and they do fell off the cart. This is also due to the external force and is as per Newton’s first law of motion.\n\nIf we take into account the action of force of friction, the situation becomes some what hard to explain in a simple manner.
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The rate of change of momentum of a body is proportional to the resultant force acting on the body and is in the same direction.\n\nIn an exact original 1792 translation (from Latin) Newton's Second Law of Motion reads:\n\nLAW II: The alteration of motion is ever proportional to the motive force impressed; and is made in the direction of the right line in which that force is impressed. — If a force generates a motion, a double force will generate double the motion, a triple force triple the motion, whether that force be impressed altogether and at once, or gradually and successively. And this motion (being always directed the same way with the generating force), if the body moved before, is added to or subtracted from the former motion, according as they directly conspire with or are directly contrary to each other; or obliquely joined, when they are oblique, so as to produce a new motion compounded from the determination of both.\n\nNewton here is basically saying that the rate of change in the momentum of an object is directly proportional to the amount of force exerted upon the object. He also states that the change in direction of momentum is determined by the angle from which the force is applied.\n\nHowever, it must be remembered that for Newton, mass was constant and independent of velocity. To take "motion" (motu) as meaning momentum gives a false impression of what Newton believed. Since he took mass as constant (part of the constant of proportionality) it can, in modern notation, be taken to the left of the derivative as . If  is dependent on velocity (and thus indirectly upon time) as we would now hold, then  has to be included in the derivative, giving  or .\n\nUsing momentum in the terminology (which would never have occurred to Newton) is a latter-day revision of the law to bring it into correspondence with special relativity.\n\nInterestingly, Newton is restating in his further explanation another prior idea of Galileo, what we call today the Galilean transformation or the addition of velocities.\n\nAn interesting fact when studying Newton's Laws of Motion from the Principia is that Newton himself does not explicitly write formulae for his laws which was common in scientific writings of that time period. In fact, it is today commonly added when stating Newton's second law that Newton has said, "and inversely proportional to the mass of the object." This however is not found in Newton's second law as directly translated above. In fact, the idea of mass is not introduced until the third law.\n\nIn mathematical terms, the differential equation can be written as:\n\n \nwhere  is force,  is mass,  is velocity,  is time and  is the constant of proportionality. The product of the mass and velocity is the momentum of the object.\n\nIf mass of an object in question is known to be constant and using the definition of acceleration, this differential equation can be rewritten as:\n\n \nwhere  is the acceleration.\n\nUsing only SI Units for the definition of Newton, the constant of proportionality is unity (1). Hence:\n\n \nHowever, it has been a common convention to describe Newton's second law in the mathematical formula  where  is Force,  is acceleration and  is mass. This is actually a combination of laws two and three of Newton expressed in a very useful form. This formula in this form did not even begin to be used until the 18th century, after Newton's death, but it is implicit in his laws.
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Since the piece of cheese is at rest. and no net force is acting. by Newton's First Law of Motion, it would continue in its initial 'state of motion'  which is rest here (since it was initially at rest) ....all other choices would violate the law!. got it dear!
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k ill try to help u  even though i dont condone cheating. i just know how it is to not understand something and its due in a few hours and it sucks. just remember, nobody will be able to help u on the exam.\n\nso 1. \na. acceleration is change in velocity divided by time. \nsince it started from rest, initial velocity is 0 and then final velocity is given as 25.3 m/s. and the time is given as 0.59s. so to get acceleration   you would do  \na =  Vf-Vi / t\n  =  25.3 - 0 / 0.59\n  = 42.88......\n\nb. the force is equal to mass x acceleration. since you know the mass and acceleration, you just multiply them and you get F = 38421.69... N. \n\nc. you have to find the normal force in this case, which is the force that opposes gravity. like upward force. so in this case, gravity is acting on the driver and force of gravity is equal to mass x 9.8 = 666.4 N. and that means the normal force is 666.4N (since he is not moving up or down the total vertical force = 0)\n\n2. ok well in this case, you know the initial velocity is 0, the distance is 404m and the time is 4.944s. if its constant acceleration, you could assume that the average velocity is just Vi+Vf/2. so if thatz average velocity, then distance = average velocity x time\n     404 = 4.944s  x  (0+Vf)/2\n 404 x 2 / 4.944 = Vf\nVf = 163.43........m/s\n\nthe acceleration would just be Vf-Vi/t. and since you know Vf now  you just do   a = 163.43-0/4.944\na = 33.056....m/s^2\n\n3. ok well acceleration is 9.8m/s^2 (gravity)     distance is 9.7m. initial velocity is 0m/s. so this time, you have to solve 2 equations. the first one is the acceleration equation. a = Vf-Vi / t = Vf / t = 9.8\n9.8 = Vf/t\nVf = 9.8t\nand the other one is the distance = t  x  Vi+Vf/2   average velocity one. \n9.7 = t x Vf / 2\n19.4 = Vf x t\n19.4 = (9.8t) x t\n19.4 = 9.8t^2\nt^2 = 1.979...\nt = 1.406....s\n\nnow that you know the time, you find the Vf by putting it in any of those 2 equations. Vf = 9.8t = 9.8 (1.406)\nVf = 13.788... m/s\n\npart b. so in this case, you use the initial velocity as the one u just found (the velocity of the swimmer at the surface of the water)   so Vi = 13.788m/s\nand Vf = 0    since they come to a stop. and d = 2m\nso you have to find the acceleration. first you need to find the time by using the average velocity equation.\nd = t x Vi+Vf/2\n2m = t x (0+13.788)/2\n4 = 13.788t\nt = 0.29s\nnow that you know the time, you have to find acceleration\na = Vf-Vi/t\n  = 0-13.788 / 0.29\na = -47.5286m/s^2    its negative because its downwards and up is positive in our case. so the force = mass x acceleration and you just got acceleration and her mass is 65kg so you just multiply by 65kg to get F = 3089.36N\n\n\n4. well F = ma and you have the force. when they say it weighs this much newtons, then it means  use gravitational acceleration which is 9.8. so 2350N = m x 9.8m/s^2\nm = 2350/9.8\nm = 239.79kg\n\ni hope you actually understand this stuff. try to do your homework by yourself   dont take advantage of this site. youll just end up screwing yourself over. and if u dont get anythin, let me know and ill try to help
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Newton's First Law of Motion:\nI. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.  \n\nThis we recognize as essentially Galileo's concept of inertia, and this is often termed simply the "Law of Inertia". \n\nNewton's Second Law of Motion:\nII. The relationship between an object's mass m, its acceleration a, and the applied force F is F = ma. Acceleration and force are vectors (as indicated by their symbols being displayed in slant bold font); in this law the direction of the force vector is the same as the direction of the acceleration vector.  \n\nThis is the most powerful of Newton's three Laws, because it allows quantitative calculations of dynamics: how do velocities change when forces are applied. Notice the fundamental difference between Newton's 2nd Law and the dynamics of Aristotle: according to Newton, a force causes only a change in velocity (an acceleration); it does not maintain the velocity as Aristotle held. \n\nThis is sometimes summarized by saying that under Newton, F = ma, but under Aristotle F = mv, where v is the velocity. Thus, according to Aristotle there is only a velocity if there is a force, but according to Newton an object with a certain velocity maintains that velocity unless a force acts on it to cause an acceleration (that is, a change in the velocity). As we have noted earlier in conjunction with the discussion of Galileo, Aristotle's view seems to be more in accord with common sense, but that is because of a failure to appreciate the role played by frictional forces. Once account is taken of all forces acting in a given situation it is the dynamics of Galileo and Newton, not of Aristotle, that are found to be in accord with the observations. \n\nNewton's Third Law of Motion:\nIII. For every action there is an equal and opposite reaction.  \n\nThis law is exemplified by what happens if we step off a boat onto the bank of a lake: as we move in the direction of the shore, the boat tends to move in the opposite direction (leaving us facedown in the water, if we aren't careful!).
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Newton's Laws of Motion:\n\nI. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.  \n\nII. The relationship between an object's mass m, its acceleration a, and the applied force F is F = ma. Acceleration and force are vectors (as indicated by their symbols being displayed in slant bold font); in this law the direction of the force vector is the same as the direction of the acceleration vector.  \n\nIII. For every action there is an equal and opposite reaction.
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http://en.wikipedia.org/wiki/Newton%27s_law_of_universal_gravitation
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Newtons 2nd Law,\nForce = mass * acceleration\n\nIf you have two masses (m1 & m2) that accelerate at the same rate,\nF1 = m1*a --> a = F1 / m1\nF2 = m2*a --> a = F2 / m2\n\nset both acclerations equal to eachother, solve for the ratio,\nF1/m1 = F2/m2\nF1 = F2 * m1 / m2 --> F1/F2 = m1/m2\n\nSo the ratio of Force 1 (F1) to Force 2 (F2) must equal the ratio of mass 1 (m1) to mass 2 (m2) in order for both to accelerate equally.
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I will give you a direction to solve the problem...\n\nFirst I will do the problem from a rectilinear formulation(using force, acceleration, velocity) then transfer it to a curvilinear formulation(using Torque, angular accelaration, angular velocity).\n\ngiven F=ma (or F=m(v/t) or more specifically F=m(dv/dt) or even more specifically F=d(mv)/dt).\nWhere F=force, m=mass, v=velocity, and t=time.\n\ngives you Ft=mv (conservation of energy=>conservation of momentum or the impulse-momentum equation).\n\nThis states that it will take a certain amount of force for a certian period of time to produce a certain change in velocity of an object assuming that the mass remains constant.\n\nTransmitting to curvilinear motion force becomes torque, v becomes rv(radius time velocity or w), mass becomes moment of inertia (or I) and t stays the same.
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Newton's Laws of motion.Everything continues in its state of rest or motion unless acted upon by an external unbalanced force.
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I am sure someone cleverer will come along and shoot holes in this but I think this has a lot to do with Newton's 3 Laws (Newton being a clever dead bloke).\n\nForce: When you kick your sister in the shin you are using force\nMass: If she is fat, she has lots of mass\nInertia: Being fat, she will not be able to chase you. She has inertia. \n( Example from - http://www.allworldknowledge.com/newton/index.html)\n\nSo you are on the train and you are moving - its worth remembering that gravity (the force which keeps you on the floor) only goes downward not along. You on the train are moving along and the 'force' of the train going along, keeps you going along. Get it?\n\nWell you're still going along, watching the world go by, and then you jump.\n\nBy jumping you're still going along with the direction of the train thats one force. But when you start coming down it's the gravity pulling you back, as another force. The train moving you along hasn't changed, you just have two forces one pulling you down (the jump) and one pulling you along (the train).\n\nSo you end up in exactly the same place. With a few miserable commuters.
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From what I learned in physics class, the force you are speaking of is measured in Newtons.
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I've alread answered two of your questiions in my last answer....\n\nIn this one, the guys above are correct - however, I'd try working it out for myself if I was you. Your tutor will soon realise something is wrong if you are giving answers to a subject you don't understand. Read the chapter, ask you teacher if you need more help. Learn Newtonian mechanics for yourself.
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a)an object allways accelerates in the direction of the net force\n--- u dint tell us u had to do it as a well proven question or for basic understanding? never mind....if they ask u this in school then follow the explaination----\nby newtons first law of motion,...(i'm assuming u know it)...'unless and untill a force acts on it' ---so a body would move if adequate force was applied(that overcame its friction and inertia)\n\nas u know...forces cancel each other as well.\nthis happens according to the law of vectors.\nthus if two forces are acting in different directions, then the resultant force is always in another direction depending on how they cancel each other and according to their magnitude which is the resultant direction.\nso finally,...there be only one force left...with a particular direction and a particular magnitude....and now..applying newton's forst law of motion...it is proved that an object allways accelerates in the direction of the net force(newton's 2nd law states that force causes acceleration---u can also explain this by saying that,velocity changes hence acceleration occurs)\n\n\n(b)A lower net force is needed to accelerate an object from rest to 10m/s than is required to accelerate it from rest to 20m/s irrespective of the time take.-----\nthe answer is NO.\nwe have to take the time into consideration. if we  have to stop such a high speed in less time...then we have to apply a lot of force....remember---force causes acceleration..it causes a change per unit time...if u want more change per unit time...u have to apply more force\nso thats it