4x - 2y = 0 how do you do this?
362052
4x-2y = 0  (add 2y to both sides of the equation)\n4x = 2y (divide both sides by 2)\n2x = y\n\nThis equation describes a line of slope 2 and a y-intercept at the origin.\n\nLet me know if you need more information.
1144396
you would take the 2x-4y=3 and solve for a variable, such as x=(3-4y)/3   you now have what x equals and you sub that into the other equation so you now have 2[(3-4y)/3]-3y=0 and you should be able to solve that equation
898442
You just factor\n(2x-1)(x-2)=0\nx=2, 1/2
940135
Use factoring.\nx2-2x-8=0\n(x-4)(x+2)=0\nso\nx-4=0 and x+2=0\nsolve\nx=4 and x=-2
271990
x^2-2xy+4xz-8yz=\n(x^2-2xy) + (4xz-8yz)=\nx(x-2y) +4z(x-2y)=\n(x-2y)(x+4z)
222015
5x - 2y = 4  (1)\n2x + 3y = 13 (2)\nmul. eq.(1) by 2: 2 (5x - 2y = 4)\n                    10x - 4y = 8\n\nmul. eq.(2) by 5: 5 (2x +  3y = 13)\n                    10x + 15y = 65\n\nsubtract: 10x -  4y =  8\n      (-) 10x + 15y =  65\n          ________________\n               -19y =  -57 \n                  y =  -57/-19\n                  y =  3\n\nsubstitute value of y to any of the eqs.\n\nSubstituting to eq. (1):\n\n    5x - 2y   = 4   \n    5x - 2(3) = 4\n    5x - 6    = 4\n    5x              = 4 + 6\n    5x              = 10\n     x              = 10/5\n     x              = 2\n\nso, x = 2\n    y = 3\n\nto check, substitute values of x and y to any of the two equations:\n    for eq. (1),\n\n    5x   - 2y   = 4   \n    5(2) - 2(3) = 4\n      10 - 6    = 4\n\n    for eq. (2),\n\n    2x   + 3y   = 13\n    2(2) + 3(3) = 13\n      4  + 9    = 13
940849
2x + 4y = -6\nX - 3y = 7 multiply by two\n\n2x + 4y = -6\n2x - 6y = 14\n{subtract equation 2 from equation 1}\n\n2x - 2x + 4y - (-6y) = -6 - 14\n10 y = -20 divide by 10\ny = -2\n\n\nplug into a equation \n2x - 6(-2)  = 14\n2x + 12 = 14\n2x = 2\nx = 1\n\nx = 1, y = 2
835073
okay well\n\n1) combine two to figure out the first variable\nx-2y+z=4\n-x+2y+3z=-4\nso 4z=0; z=0\nthen figure out the next variable with a different set of equations\nlike and multiply so the ys will cancel [take Zs out cause zero]\nx-2y+z=4\n2(2x+y)=6\n\ntherefore\nx-2y=4\n4x+2y=6\n5x=10\nx=2\n\nthen substitute for y\n\n-x+2y=-4\n-2+2y=-4\n2y=-2\ny=-1\n\nso y=-1, x=2, z=0\n\n\ncontinue the process with the rest.
712820
write them so they can be added top to bottom (i.e. line up the x's, y's, and constants):\n\n4x + 2y = -4\nx - 2y = -3  (we need to rearrange the original equation here to line things up)\n\nnow add top to bottom:\n\n(4x)+(x)  +  (2y)+(-2y)  =  (-4)+(-3)\n5x + 0 = -7\n5x = -7\nx = -7/5\n\nnow plug x in to either equation to solve for y:\n\n2y = -7/5 + 3\n2y = -22/3\ny = -22/6 = -11/3\n\nHope this helps :)
679397
y = 0.5x-4 \n\nor similarly\n\nx= 2y +8
905206
8x - 2 = 3x - 2\n8x = 3x\n5x = 0\nx = 0
931393
GIVEN:\n\n0.4x - 0.1y = 5 \n6.4x + 0.4y = 60\n\nSTEP 1:  Multiply the first equation by 4 to get the following:  (because notice that 0.1 * 4 = 0.4, and we will be able to cancel our y's out and solve for x)\n\n1.6x - 0.4y = 20\n6.4x + 0.4y = 60\n\nSTEP 2:  Add the two equations together, to get one equation with our x variable only:\n\n1.6x - 0.4y = 20\n6.4x + 0.4y = 60\n-----------------------\n8.0x + 0y = 80\n\nSTEP 3:  Divide both sides by 8 to solve for x:\n\nx = 10\n\nSTEP 4:  Substitute this value for x into either one of your original 2 equations to solve for y:\n\n0.4x - 0.1y = 5\n0.4(10) - 0.1y = 5\n4 - 0.1y = 5\n-0.1y = 1\n0.1y = -1\ny = -10\n\nFINAL STEP:  Your answers are x = 10, y = -10\n\nHope that helped!\n\n~ ♥ ~
1070975
4x^2+8x-1=0 when x=.118 or -2.118\n\nTherefore 4y^3-17y+6=4.000 or 4.001
861681
subtract 1st equation from the second:\n  8y^2=32\nso y^2=4, and y = +/- 2\n\nplug back into 1st equation:\n4x^2+4=4\n\n4x^2=0\nx=0
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
720107
4x -12y =5...........(1)\n-x +3y = -1..........(2)\n\nMultiplying eq.(2) by 4 and add with eq.(1)\n(4x -12y =5) + (-4x +12y = -4)=\n0 = 1\nwhich is invalid.
1178709
y'=2x-2\n\nif =0 then:\n0=2x-2\n2x=2\nx=1