what are the equations of these two lines?Put the answer in slope intercept form?
372923
2 basic things understood make this kind of question easy.\n\n1st, parallel lines have the same slope; perpendicular lines have "negative reciprocal" slope. \n\n2nd, when the equation is in standard form, Ax + By = C, the slope \nis -(A/B), and the intercept is C/B.\n\nso in problem A. any line perpendicular to -6x - 7y = 22 will start out \n7x - 6y = C, and we get C by plugging in the coordinates of the point the line has to go through.\nso 7(1) - 6(7) = -35.  that makes the equation 7x - 6y = -35.  slope is 7/6, intercept is 35/6, so slope/intercept equation is y = (7/6)x + 35/6.\n\nparallel is even easier, because the A and B don't change.  the new equation starts out -7x - 5y = C, and we plug in the point:\n -7(2) - 5(-8) = 26, so we get -7x - 5y = 26, where slope is -(7/5) and intercept is -26/5, so slope/intercept form is y = -(7/5)x - 26/5.\n\nThere's nothing wrong with standard form, but teachers like to make you keep changing form to practice basic algebra.
930270
Well done, you have already done the hard work. The number in front of the x is the slope ie -2/13 and the other number is the y co ordinate of the y intercept ie (0 , 5/13). Another way to find the y intercept is to substitute zero for x and solve for y, or alternately substitute zero for y to find the x intercept.
791058
The slope-intercept form for a line is y=mx+b, wherem is the slope and b is the y-intercept. Comparing this form to y=7x+3, you see that m=7 (the slope) and b=3 (the y-intercept).
783146
slope of the second line is  3/2  ( y=3/2 x - 5 )\n\nso slope of the 1st line -2/3\n\ny=-2/3 x + b, plug in ( 2, -1) to solve for b\n\n-1 = -4/3 + b\n\nb=1/3\n\nso eq of the first line is y=-2/3 x + 1/3\n\n or                                  3y=-2x + 1
105029
slope: 1; intercept: 2\n\nslope: -1; intercept: -3\n\nslope: -5/4; intercept: 20\n\ny = mx + b, where m, the coefficient of "x" is the slope and "b" is the y-intercept.  If you solve the equations for y it's pretty easy to figure out both.\n\nHope that helps.
246990
(7,5) and (11,9)\n\nlet them be (x1,y1) and (x2,y2)\n\nslope of line is (y2-y1)/(x2-x1)\n\nthus slope is (9-5)/(11-7) = 4/4 = 1\n\nequation of line is given by the formulae\n\n(y-y1)=slope*(x-x1)\nor\n(y-y2)=slope*(x-x2)\n\nso equation can be...\n\n(y-5)=1*(x-7) that is x-y=2\n\nor\n\n(y-9)=1*(x-11) that is x-y=2\n\nsee its the same in both cases !\n\nthe required equation is x-y=2 !!!
869778
IN SLOPE INTERCEPT FORM\ny = 7/8 x - 8\nhttp://www.pen.k12.va.us/Div/Winchester/jhhs/math/lessons/algebra/grapha.jpg\nThis is a graph... Put it in PAINT and figure out slope and y intercept.\n\nPS please award best answer
910261
Slope = m\n= y2-y1&#92;x2-x1 \n= -4-6/-3-2\n = -10&#92;-5\n=2\n\nnote: / means divided by\n\nthe slope of y= 2&#92;3x-4 is 2&#92;3
704179
An equation in slope-intercept form is y = mx + b\nIn the equation, m = slope and b = y-intercept\n\nUsing the equation given\ny=-3/2x+6\ny = mx + b\n\nWe know that the slope is -3/2.  That would be m.\nWe know the y-intercept is 6.  That would be b.\n\nNow we have to find the x-intercept.\n\nTo get the x-intercept, we will set y = 0 and solve the equation for x.\ny=-3/2x+6\nSubstitute 0 for y\n0=-3/2x+6\nAdd 3/2x to both sides\n3/2x = 6\nMultiply both sides by 2/3\n2/3*3/2x = 6*2/3\nx = 4\nThe x-intercept is 4.\n\nSlope =  -3/2. \ny-intercept = 6.\nx-intercept = 4.
317632
slope = 1/5\ny-intercept = 2\nx intercept = -10
674651
put it in standard form :\n\ny < -1/2x + 3/2 \nand \ny > 2/3x + 2\n\nthen you know the first line passes thru the y axis at 3/2 and the second at 2\n\nthe slopes are -1/2 and 2/3 .... then shade below the line on the first one cuz y is less than .\n\nthen shade above the second line because y is greater than
771990
y = mx + b is the slope intercept form, where m = slope\n\nso 2 is the slope in your example\n\nWith any equation for a line, there are 2 variables, x and y, representing the position on the x and y axis.  Given any line equation, you can manipulate it to get it into slope intercept form (y = mx + b), and m will be your slope.\n\nThe y-intercept is where the line crosses the y-axis (or where x = 0).  As you can see, if you put x = 0 in the equation, you will get:\n\ny = 0x + b\ny = b\n\nso when x = 0, y = b.\n\nHope this helps! :)
905236
To write this in slope intercept form, we will put it in the form y=mx+b like you said.  \n\ny-6=0\n\nnow we add 6 to both sides and get\ny = 6\n\nFor slope intercept form, I always put the x in there.  No x in the equation is the same as 0x because 0 * x = 0.\n\ny = 0x + 6\n\nThis equation has a slope of 0.\n\nOn this equation, y will be equal to 6 no matter what x is.\n\nLet's do a few points to prove that this will be a horizontal line.\n\n(0,6)\n(1,6)\n(2,6)\n(3,6)\netc...\n\nIf you plot these points, you will see a horizontal line at 6.
957268
The slope should be 3 over 1 or +3(rise over run)and the x and y intercepts would both be 0  (0,0). \n\nThis can be found by using the equation y=mx+b or by using a graphing calculator. The graph of the line in this case crosses exactly where the x-axis and y-axis cross (0,0).
306531
First, the slope is (delta y)/(delta X) = (-3)/2) = -3/2\n\nthe y intercept is +6  (interpolating back from \n(6,-3) ,(4,0),(2,3), (0,6)\n\nso the equation is Y=-3/2 X + 6\n\ngo from there and you have your answer.
863359
Slope = rise over run\n\nrise is change in y, run is change in x\n\nso rise = 9 - 6 = 3\nrun = -1 - (-3) = 2\n\ntherefore slope = 3/2\n\nSo using the slope intercept form:\n\ny = mx + b\ny = 3/2x + b\n\nwe plug in either point to solve for b (the y-intercept):\n\n6 = (3/2)(-3) + b\n6 = -9/2 + b\nb = 6 + 9/2 = 10.5\n\ny = mx + b where m = 1.5 and b = 10.5\n\ny = 1.5x + 10.5
1090932
If you plot those two lines, the solution is the place where they cross each other (if they do)... but.. let's set them up in Slope-Intercept form:  y = mx + b, where m is the slope and b is the y-intercept.\n\n-6x - 7y = 65 ==> y = -(6x +65)/7 ==> y = -(6/7)x - 65/7\n\n4x + 3y = -35 ==> y = (-4x -35)/3 ==> y = -(4/3)x - 35/3\n\nsince the slopes are different, the lines WILL cross and there is only 1 solution (if they had been the same slope then either there would have been no solution or infinite solutions)\n\none way to find the solution.. \n\n-6x -7y = 65 ==> multiply equation by 2 ==> -12x -14y = 130\n4x + 3y = -35 ==> multiply equation by 3 ==> 12x + 9y = -105\nnow add the two equations to eliminate x ==> 0x -5y = 25\nor... solving -5y = 25 for y... you get y = -5\n\nnow plug this value into one of the equations and solve for x:\n\n4x + 3(-5) = -35 ==> 4x - 15 = -35 ==> 4x = -20 ==> x = -5\n\nso your solution is (-5, -5)