What is the balanced chemical reaction between nitric acid and copper and gives a salt Cu(NO3)2?
366358
reaction of conc HNO3 at high temperatures with Cu:\nCu + 4HNO3 = Cu(NO3)2 + 2H2O + 2NO2\n\nreaction of dil HNO3 at ordinary temp with Cu:\n3Cu + 8HNO3 = 3Cu(NO3)2 + 4H2O + 2NO
394775
2Cu(NO3)2 ----> 2CuO + 4NO2 + O2\nOBSERVATION: brown, choking fumes of NO2 evolved; black solid i.e CuO settles at the bottom\n\n2FeSO4 ----> Fe2O3 + SO2 + SO3 \nOBSERVATION: white fumes of SO3 evolved and reddish brown solid i.e. Fe2O3 formed\n\nEDIT: The above equation for iron(II)sulphate may be a supposed characteristic for its thermal decomposition relating to that of copper(II)nitrate above, but Chaos, O2 will not be evolved here, because SO3 will not get reduced to O2, even on strong heating.
888667
Cu2S + 12HNO3 -> Cu(NO3)2 + CuSO4 + 10NO2 + 6H2O\n\nThere you go.
105132
3 Sn(NO3)4 + 4 AlCl3 --> 4 Al(NO3)3 + 3 SnCl4
759463
Atomic masses\nCu - 63.546g/mol\nN - 14.007g/mol\nO - 15.999g/mol\n\nmolar mass of Cu(NO3)2 - 187.554g/mol\n\nno of moles in 2.35x10^3g = 12.53
903862
Sorry Voyager. Copper is not so reactive a metal that it will react with sulphuric acid.\nYou need either solid copper (II) carbonate or solid copper (II) oxide for the salt.\nSince it is a sulphate, sulphuric acid is used together with the solid.\nHeat the acid so that the reaction can proceed at a faster rate. Add solid till no more will react (no bubbles of gas produced, and the solid remains insoluble). This is to ensure that all the acid is used up. Filter to remove unreacted solid and heat the filtrate, which is the copper (II) sulphate solution, till saturated (approximately 1/3 to half the original volume left would be a good gauge). Let the hot saturated copper (II) sulphate solution cool and after some days, when the excess water evaporates off, you should get hydrated copper (II) sulphate crystals.\nDo not heat till dryness as this will evaporate off the water of crystallization needed for the blue copper (II) sulphate crystals to form. Without the water of crystallization, you would get anhydrous copper (II) sulphate powder (white) and not the blue crystals.\n\nHope this helps :)
327756
like the 1st guy said, u need the coordination number. if the no. of ligands is 6 (as copper has a tendency to form octahedral complexes) its Cu(NH3)6
978387
You should have gotten elemental copper via the following equation:\n\n3CuCl2 + 2Al ---> 3Cu + 2AlCl3\n\nThe water is not part of the reaction.
221298
2.5% copper, 97.5% zinc
934206
2\nthe reaction is\nCa(OH)2+2HNO3=2H2O+Ca(NO3)2
734862
HgO ------> Hg + O2 at about 400 C\n\nMg + CuCl2 ---------->  MgCl2 + Cu(solid)\n\nMg, being higly electropositive than Cu, replaces Cu.
854997
CuS + H2SO4 ===> H2S + CuSO4
577084
Acid + base = salt + water.\n\nUnbalanced eqn is: Al(OH)3 + H2CO3 --> Al2(CO3)3 + H2O
770385
FeCl3+3NaOH>>Fe(OH)3+3NaCl
136146
The 1st answer is wrong. The reaction is\n\nNa2CO3(aq) + SrCl2 (aq)--> 2NaCl (aq) +SrCO3 (s)
792118
As copper is more reactive than silver it will give up its two electrons to silver ions so when is really happening is:-\n\n2Ag+  + Cu → Cu++ + 2Ag\n\n(The nitrate ions (NO3‾) are passive)
471526
I suspect that the product is AlSO4.\n\nI'm thinking that the Al swaps with the Cu.  That would leave a free Cu+ which might displace the H from H20 and form either CuOH or CuO, either one of which would probably produce H2.  \n\nSo, I guess you would first get CuOH and AlOH, as intermediate reactions.\n\nI think the equation is:\n\n                          NaCl (goes over the arrow)\n6CuSO4 + 4Al + 12H2O ---------------> 2Al2(SO4)3 + 6Cu(OH)2 + 6H2