7(b-2);b=8  evaluate?
358924
7(b-2)\n7(8-2)\n56-14\n42
883494
take the length of the equal sides to be a,and the other side to be b\na=4b-8\n2a+b=29\nso 29-2a=b\nsubstitute for b\na=4(29-2a)-8\na=116-8a-8\na=116-8-8a\na=108-8a\n108=8a-a\n108=7a\na=15.428571428571428571428571428571(the 428571s repeat)
198100
7 / [8 2/5] = 7 / [42/5] = 7* 5/42= [7*5]/[7*6] = 5/6
295665
8 2/5 = [(8*5)+2]/5=42/5\n\n7/(42/5)= (7*5)/42= 35/42
700731
-7=9+(-8x)          Subtract 9 from both sides\n\n-16=-8x            Divid both sides by -8\n\nx=2
1027973
the 3rd one is correct, but I get -(3+b)/b+2 and 2 for the first 2
243986
2+2[24+(-4)+(10)]\n2+2[30]\n2+60\n62!
864795
8(t-2sqrt(a))(t+2sqrt(a))
263576
22+2 = 24\n8+8+8 = 24\n3^3-3 = 24
611894
8 to 3  (56 to 21 and divide by 7)
146936
(32 + 18 - 45 x 3) / 5 - 7 x 2 = ?\n\n-31
729543
-24+w+8=4\n-24+24+w+8-8=4+24-8\nw=20\n\nhope this helps!
550482
-2a(b+2)-6b=\nor\n-2(ab+2a+3b)
426775
b = 2g - 10\ng = (b + 10)/2
8473
7t+15 > 3t-13\n4t > -28\nt > -7
998009
You need to use the distributive property where:\n8(4w+x-6y)=\n8(4w)+8(x)-8(6y)=       \n32w+8x-48y
749939
Nobody can help you because it's false.\n\nLet a1 = 1, a2 = 4, b1 = 2, b2 = 3, and n = 7\nThen a1 + a2 = 5, b1 + b2 = 5\nBut a1*a2 = 4, while b1*b2 = 6.\n\nYou are talking about modular arithmetic, right?