what is the @ command in Unix?
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There is no command in standard Unix spelled "@";\nhowever:\n\n  - There is a standard command, spelled "at",\n    for executing batch jobs at a specified time.\n    (see manual page at reference 1)\n\n  - Anyone *could* create a command called "@"\n    simply by renaming or linking a command\n    to that name.
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/*\nOriginal Question:\nI am writing a C program in Solaris environment...if i\nwant to execute some system command i can do it using\nsystem("string to be executed")....but it accepts string\nonly. what if i want to pass some variables to system at\nrun time....suppose i was to use this commands at runtime\n"cat file1 file2 >file3"....how i wud pass the file names?\nany suggestions !  thnx in advance Amardeep Sidhu\n*/\n\n#include <stdlib.h>\n#include <stdio.h>\n\nint\nmain(int argc, char* argv[])\n{\n\n  /* First, get some values into variables */\n\n  char *str1 = "ls";\n  char *str2 = "-l";\n  char *str3 = "/tmp";\n\n  /* One common trick to using "system()" is */\n  /* to "sprintf()" the arguments into a buffer */\n  {\n    char buffer[100];\n    sprintf(buffer, "%s %s %s", str1, str2, str3);\n    system(buffer);\n  }\n\n  return 0;\n}
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eMule.\nhttp://www.emule-project.net/home/perl/general.cgi?l=1
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./<program name> is only and will only run programs in the dir that you are currently in.\n\n./ is the unix/linux/bsd command line for the current directory.  If you were in /home/username/dir01/dir02/dir03 and wanted a run a script from the dir02 dir, you would type ../<script name>.  The ../ means one dir down.  ../../ would put you in to dir01 and so on and so forth.\n\nThe ./ is also a security measure so files just don't get run accidently.  \n\nIn order to run mozilla, it has to be installed.  I would read your distro's web page on how to do that.  Many distro's have good wiki sites that will guide you through the process step by step.  Once there, you just need to run it from the location where it resides.\n\nJust type:\n\nwhereis mozilla \n\nIt should locate it for you and give you its full path.
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gethostbyip()  - thats a perl module right ???\n\nshould be able to pipe each line of the tail into a little perl program where you call the module subroutine and display it to the terminal . . . \n\ntail access.log | little_program.pl\n\n\nyou can forget the gethostbyip stuff and maybe just use the linux shell command\n\nnslookup host \n\n\n\nor something like that
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Start at their website, http://www.unix.org
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the command line prompt is known as your script prompt..\n\nfor example in unix its like $ or %
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if you google for unix commands you will find tons of tutorials on all the commands you will ever need. You could also just buy mac osx server sense thats a unix platform and much nicer to configure then the command line stuff.
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I tried in Command -Prompt in Windows XP, hope it is the same.\nI typed in [exit] (without the brackets).
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if u have linux..\nat command prompt press tab twice\nit will give u a list\nfor "how to" use it try:\n\nman [command]\n\nchange [command] with your command, it will give u a brief manual
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This should work\n% sh\nsh-2.05b$ a=`ls`\nsh-2.05b$ echo $a\na.c a.out bin conf data env sql src templates upgrade\n\nPutting a command (like ls) in backticks and assigning the same to a variable (like a) lets you store output in a variable for a shell script
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for the most part is shouldn't matter which you use.  ./, / , and nothing, all mean the same.  If the first two are used, you are explicitly telling your webserver to look in the current directy of execution for whatever file.  If no address is specified it defaults to look in the current directory.  \n\n../ means "look in the parent directory" so if our current directory is /usr/local  ../ would take us to /usr.  \n\n\nIdeally both of these switches are used for directory traversal.  Commonly used in command line interactions (linux & dos) eg: (DOS)--> cd ../
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Most Unixes have a 'useradd' or 'adduser' command. You need to be root to run it. Type 'man useradd' to have the manual, it goes like:\n   useradd -g <MainGroup> -G <otherGroups> user_name
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If I get your question right, this is what you want.\nYour perl file is actually some kind of a template where there are placeholder variables whose values will be known at run time from another file, and you need some way to replace the correct values in their correct places.\n\nI once had a similar requirement and I resolved it by writing another program (you can write this one in perl, I chose java) that takes the template you have and create a new perl script with the placeholder variables replaced with those in the other file.\n\nYou need to execute this newly generated file now.
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what command are you using? And what is the OS?\nIts hard to answer this question without those details!
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#!/usr/bin/perl -w\n\nuse strict;\n\nopen( INPUTFILE, "input.txt" ) ;\nmy $startCaptureLine = 10;\nmy $numLinesToCapture = 10;\nmy $curLine = 1;\nmy $capturedLines = "";\nforeach (<INPUTFILE>) {\nif( $curLine >= $startCaptureLine \n     and $curLine <= $startCaptureLine + $numLinesToCapture - 1 ) {\n$capturedLines .= $_ ;\n}\n++$curLine;\n\n}\nprint "$capturedLines";\n\nexit 0;
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http://home.att.net/~short.stop/freesoft/unix.htm