What can I compare the flow of 17 cubic feet/second of water with?  (i.e. a stream, a river, etc.)?
366638
More like a small creek,\n\nA small river (San Marcos River in TX) will record in excess of 200cfs\nwhile a large river (Potomac River in MD) will record over 100,000 cfs
58570
Density is measured by weight per unit of volume, such as the density of water is 62.4 pounds per cubic foot.\n\nViscosity is a measurement of the rate at which a liquid flows or more accurately, its resistance to flowing. Water has low viscosity, honey has high viscosity.
876223
The unit "cubic meters per second" is a measure of flow.\n\n100/40 = 2.5\n\nThus you can say, "The Gulf Stream current is two and one-half times faster than the Cromwell current."\n\nHope this helps!
133260
.68181818181818 etc. \n(a little more than 1/2 a foot per second)
632058
C\nTotal discharge of a (river) system is determined by its  total volume dividd by a time constant.  Just as a car has a speed (miles per hour), the discharge of a river has a volume per second (or day, or year, etc.), which measured in scientific units is cubic meters per second (m^3*s^-1). Thus, C is the closest answer, although it omits the needed time interval to describe a total flow.
251868
Depends on the level of elevation.  The higher elevations have less air pressure.  At sea level it's about fifteen pounds for every square inch.\n\nConversion to mph is about 31.07 mph or 546.83 inches per second.\n\nHere are some drag formulas\nhttp://carini.physics.indiana.edu/E105/drag-force.html
1011234
united states gallons per minute
791045
The volumetric flow rate is proportional to the pressure at the bottom (which is rho*gh, or density times gravity times fluid height) and to the area of the orifice (which is pi*r^2, where r is the radius, 1 mm = 0.001 m).  There is a valve constant involved, which you can assume is equal to 1 if you're not given additional information.
641447
The flow rate in CFM (cubic feet per minute) is often used for compressible gases.  Therefore it is usually also necessary to indicate the pressure and temperature.  For ratings of fans and blowers at atmospheric conditions, it may be assumed that standard temperature and pressure at sea level are intended and will be close enough for most application (except high on a mountain?).
128148
It would depend on the amounts (mass) of the water.\n\nedit:\nThe specific heat of water is not 1 [artless_man], it is 1 calorie per gram degress celcius, the units make all the difference.  Notice the lower case c in calorie.\nA "better" specific heat of water, using metric units, is 4.186 J / (gram * degree celsius).\n\nHowever, for this problem, you dont even need to know the specifc heats since both substances are water.
115707
It depends on the pressure and temperature of the water so the previous answer is limited to only one condition.
340597
there's not too much difference, other than  the density which causes the drag coefficient. however, water has surface tension, which may be slightly important in causing greater drag
611212
One litre of water can be contained in a cube 10cm on each side.\nSo if you have, say, a 10cm square-section piece of roof guttering and you have water flowing along it (filling it to the brim), then every 10 centimetres the water moves means a whole litre has passed any given point.  If the water is flowing at 1 metre per second, then that's 10 lots of 10 centimetres and the flow rate is therefore 10 litres per second.\n\nRivers aren't nearly as simple, because they are not nice neat square troughs and besides, there are other factors such as turbulence, viscosity etc to take into account.\nBut the general principle is the same; try to measure the area of the cross-section of the flow and multiply it by the speed of flow to get the volume of water passing through.
337691
if the question is: If it takes 3 hours to travel 24 miles downstream and 6 hours to travel UPstream, how fast is the current? then,\nlets call the travelling speed Vt and the current speed Vc\ndownstream we have Vt+Vc=24miles/3hours=8mph\nupstream we have Vt-Vc=24/6=4mph\nto solve the system of two equations we can add the equations and get 2Vt=12, Vt=6mph\nVc=8-6=6-4=2mph\nThe current is 2mph fast.
574365
i use to work in several water treament facilities. a flow meter is calibrated with the rising and lowering of the water level. the best flow meter utilizes a float inside a pipe that is slightly larger than the float.go to www.grainger.com. they have pictures of a few flow meters
864791
A.) 3.02891 seconds\nB.) 290.1 m/s\n\nTrust me... =)
900600
listen closely!\nhttp://www.flowgo.com/index.cfm?action=view&id=5809&scid=0