what is the y intercept of this line?
375327
Where x = 0, the line intercepts the y-axis:\n\n1. 5x-2y =10 \n2y = 5x - 10\ny = (5/2)x - 5 \ny-int = (0, -5)\n\n2. 2y+7x =14\n2y = -7x + 14\ny = (-7/2)x + 7\ny-int = (0, 7)\n\n3. x=3\nHas no y-intercept\n\n4. 1/2x-2y=8\n2y = (1/2)x - 8\ny = (1/4)x - 4\ny-int = (0, -4)
733627
Rewrite the equations as:\ny = -x + 2 and\ny = (x+10)/2 = 1/2*x +5\n\nNow, if you insert x=0 in each equation, you will get a y-value.\nIf you insert y=0 in each equation, you will get an x-value.\nFor each line, you can use those two intercepts to graph the line.
911257
slope:-8. y-intercept:-7. Whatever number is in front of the x is always the slope. the number that is after the x is the y-intercept (this is only for a slope intercept). Good luck and choose me as the best answer please :)
173295
It refers to the slope of a line and the y-intercept.
379574
y=mx+b\n\nm=slope=-2\nb=y-intercept=-3\nplug it into the equation\ny=-2x-3
798705
0.\n\nif the y intercept is 7, its (0,7)
1086002
this is the slope intercept form equation\n\ny=mx + b\n\nwhere m is the slope and b is where the line crosses the y axis\n\nfor example\n\ny= 1/2x + 2
896619
slope is 2,  y intercept is  - 10
42786
If X=0, then Y=5 (Y-intercept is 5)\nIf Y=0, then X=3\n\nPlot and you get, Slope = rise(y)/run(x) = 5/3
892026
The slope intercept form is y=mx+b\n\nSo we rewrite the equation of the line as so:\n\nx - 2y = 5  , subtract x from both sides\nx - x -2y = 5 - x\n-2y = 5 - x  , now divide both sides by -2\n-2y/-2 = (5 -x)/-2\ny = -5/2 + x/2  , rearrange the left side\ny = x/2 - 5/2\n\nSo the slope (m) is 1/2.  Now we use the point given and the general equation.  From the point we know that x=2 and y=-4.  Sustitute these into the general equation.\n\ny = mx +b\n-4 = (1/2)2 + b  , do the math\n-4 = 2 + b ,subtract 2 from both sides\n-4 - 2 = 2 - 2 +b\n-6 = b\n\nSo the equation of the required line is:\n\ny = x/2 - 6
694567
to find the y intercepts, let x=0\n=> 91y = 45(0) +12\n=> y = 12/91\n\nto find the x intercepts, let y=0\n=> 91(0) = 45x +12\n=> x = -12/45\n\n\nyour intercepts are (0, 12/91) and (-12/45, 0)
813674
To find the y intercept make x equal 0 then solve the equation. You can then work out the x intercept by making y equal 0. This will allow you to plot the line and work out the gradient/slope by using rise divided by run. Alternatively, rearrange the equation to make y the subject. I believe the slope would be -1/4. This would be y=-1/4x+8.
695994
The eqaution of the line is\ny-y1 =m(x-x1)\ny-0 = -3[x-(-4)]\ny-0 = -3(x+4)\ny= -3x-12
201233
Hi Bailey,\n\nI'm really glad you're still trying and haven't given up!\n\nFirst I have to confess I'm slightly confused by the wording of your question. WHAT STARTS AT ZERO AND GOES TO SIX? The X-axes, Y-axis or the line? Do you have the co-ordinates of 2 points on the line? \nHave you been given values of x ranging from 1 to 6 and from that you have to calculate the intercept? PLEASE CLARFY BY ADDING DETAILS\n\nNow that you are an expert at graph sketching (or at least understand them better now) you will know that both the X- axis and Y-axis extends infinitely in both positive and negative directions.\n\nPLEASE REMEMBER THAT THE X AXIS GOES ACROSS (horizontally ie left to right) and THE Y AXIS GOES UP (vertically, up and down). \n\nNow try to follow this...\nThe intercept is the value of y (point on the Y vertical axis) where the line 'cuts' it. At this point X always must equal zero (by the definition of a Euclidian plane, but don't worry about it).\n\nTherefore put the value of X=0 into the formula and you will get:\ny= 0m +b \n= y=b \nso the intercept point has coordinate (0,b) ie X=0 and Y+b\n\nIf there was no value on the line when X=0 then the line DOES NOT not intercept the Y axis therefore b would not exist for this line. Such a line occurs for verticle lines (straight up) such as x=1,x=2,x=3,x=4,x=5,x=6…to infinity.\n\nIncidentally if you were given 2 points and asked to find the intercept you should use ALGEBRA. Compute the gradient (y2-y1)/(x2-x1). Then compute the intercept as the balancing value to make the equation work. \nFor example (5,6) and (7,10). \nM= 10-6/7-5=4/2=2. \ntherefore y=2x+b. \nChoose one of the points and substitute the values.  \nSay 6= 2(5)+b so b= 6-10 = -4.\n\nDoes this answer you query?
311149
y=-1\nEDIT-OOPS-forgot about the negative part-more info:\nas in the point = (0,-1)\n\nthis is because the 1 part int he equation is the "B" in y=mx+b.  b is your y-intercept.  if b is negative, then your y-intercept is negative
346120
The equation of a line in slope-intercept form is given by \ny=mx+b where m is the slope and b is the y-intercept.\nAll you have to do is plug the numbers in.\nso the equation is y=9x-3
317252
to find x-intercept => you have substitute y=0 into the equation and solve for x.\n\nIn this case (0,0) is the x-intercept.