what is the equation of the line that has a slope of -3 and passes through the point(2,5)?
373833
Use y = mx + b to find your equation.  m is -3, and you have an x and a y, so you can find b...\n\ny = mx + b\n5 = -3*2 + b\n5 = -6 + b\nb = 11\n\nSo your equation would be y = -3x + 11 (not listed in your answers - you may want to double check that).
759094
the perpendicular slope is the negative inverse of the origional, meaning, once you change your equation into y=mx+b form, you flip your slope, and make it negative.\n\n-3y=1212-2x\ny=-404-(2/3)x\ny=-(2/3)x-404\n\nso the slope is -2/3. the perpendicular is 3/2.\n\nplug it in with the point:\n\n3=(3/2)(4)+b\nb=-3\n\ny=(3/2)x-3
845789
the formula equation for point-slope form is:  y-y1= m(x-x1)...the person that answer b4 me is a dipsh*t......\n\nall u need to do now is substitute (plug-in) the given info....\n\ny-5= m(x+4)\n\nto find m (slope)...well f*ck it, ill do it for you...\n\nm=-3/10\n\nTHEREFORE:  the final point slope equation that passes thru (-4,5) and (6,2) is..... y-5= -3/10(x+4)\n\n\nyour welcome
134706
I'd plot the points and figure out the slope (vertical change/horizontal change).  In this case, it would be -1 [2 / -2].  Then trace out the line to see at what point it crosses the Y axis.  In this case, it would be -2.  Then plus those numbers in the the equation "Y = (slope)X + (intersection of Y axis)"  So, if I'm not mistaken, the solution should be "Y = -X - 2".
751701
ok so the standard equation of a line is y = mx + b, so you want to get the second equation into that form:\n\n5y = 12- 3x\ny= 12/5-3/5X\nso the slope here is -3/5\n\nfor the set of two points:\nthe equation for a slope is (y2-y1)/(x2-x1) so:\n(7-3)/(4-2) = 4/2\n\nso 2 is greater than -3/5 therefore, the slope of the first line is larger
316654
The midpoint of that segment is (3, -2) - all you do is take the average of the x coordinates and the average of the y coordinates.\n\nThe slope of that segment is found by\n\nm = (y2 - y1)/(x2 - x1)\n= (1 - (-5))/(4 - 2)\n= 6/2\n= 3\n\nSince you're looking for a line perpendicular to this one, take the slope, invert it, and change the sign.  So the slope of the new line will be -1/3.\n\nNow you have a point and a slope for the new point: m = -1/3, and point (3, -2).  Use the point-slope formula to find the equation of the line:\n\ny - y1 = m(x - x1)\ny - (-2) = (-1/3)(x - 3)\ny + 2 = (-1/3)x + 1\ny = (-1/3)x - 1
701324
(y2 -y1)  / (x2 - x1)\n\n-5, -3        -5 , 2\nx1, y1       x2, y2 \n\ny's :  2-(-3) = 5       x's : -5 -(-5) = 0              (2 negatives = +)\n\nso  5/0  which means its undefined\n\nur teacher sux
162979
From y=-3x-3 and y=x+5 you have -3x-3=x+5 so\n-3x-x=5+3\n-4x=8\nx=-2\nNow y=x+5=-2+5=3\nThe solution is (-2,3).
477914
slope= mx+b\nslope=1/2x\nequation= y=1/2x-3.5\ny-int: -3.5
907088
The slope is 1/3 and the point is (-2, -4).
892026
The slope intercept form is y=mx+b\n\nSo we rewrite the equation of the line as so:\n\nx - 2y = 5  , subtract x from both sides\nx - x -2y = 5 - x\n-2y = 5 - x  , now divide both sides by -2\n-2y/-2 = (5 -x)/-2\ny = -5/2 + x/2  , rearrange the left side\ny = x/2 - 5/2\n\nSo the slope (m) is 1/2.  Now we use the point given and the general equation.  From the point we know that x=2 and y=-4.  Sustitute these into the general equation.\n\ny = mx +b\n-4 = (1/2)2 + b  , do the math\n-4 = 2 + b ,subtract 2 from both sides\n-4 - 2 = 2 - 2 +b\n-6 = b\n\nSo the equation of the required line is:\n\ny = x/2 - 6
1093431
what is d2 here..if its line what is its equation?
945033
Derivative is y=cos x -5. Substituting in 0 gives you the slope -4. Now plug in the coordinates (0,3) to get the line, which is y=-4x+3
71640
you find to points on the line \nexample (2,5) and (1,6)\naight m= slope\nput the points in this simple equation\ny2-y1 (over) \nx2-x1\n\n6-5 over\n1-2\nwhich Equals  \n M= 1/ -1\nHoped it helped\nor try asking the teacher for help after school or at lunch
740076
First solve for y.\n3x - 5y = 7\nSubtract 3x from each side\n-5y = -3x + 7\nDivide everything by -5\ny = (3/5)x - 7/5\nThe slope is m = 3/5\nSInce the new line is parallel to the given line, that means the slope will be the same.  Use your given point to find the  line\ny - (-7) = (3/5)(x-6)\ny + 7 = (3/5)x - 18/5\ny = (3/5)x - 18/5 - 7\ny = (3/5)x - 53/5
734729
problem1\n\nsince you have said P (4,-5) is a point on the function, then the corresponding point will be (4,-5) .. :)\n\nproblem2\n\nfor a line having y intercept 3 will have following form\n\ny =mx+3\n\nwhere m is the slope of the line. Now it is said to be perpendicular to y =2/3x-4. So slope for this is 2/3\n\nsince slopes of two lines perpendicular to each other if multiplied yields -1\n\nm X 2/3 = -1\n\nor m = -3/2\n\nso the required line will be\n\ny = -3/2 x+3\n\nproblem3\n\nf(x) = 1/x^2 -2x-8\n\nto make the f(x0<0, let us try with some arbitary values of x\n\nif x = 1, f(x) = -9\nif x=2, f(x) = -11.75\nif x = 0, f(x) = infinite (due to 1/x^2)\nif x = -1, f(x) = -5\nif x= -2, f(x)= -3.75\nif x=-3, f(x) = -1.88889\nif x=-4, f(x) = 0.0625\n\nHope this helps
707187
Given two points, (x1, y1) and (x2, y2), slope is (y2 - y1)/(x2 - x1):\n(1 - 6)/(-3 - 5) = -5/-8 = 5/8