what is the distance between any 2 latitudes?
362323
Given the latitudes and longitudes of two places on earth, the distance between them:\nD = R * arccos{cos(long1-long2) * cos(lat1) * cos(lat2) + sin(lat1) * sin(lat2)}. \nhttp://www.cs.cmu.edu/~mws/lld.html \n\nbut if tou don't want to make the calculation, in next pages they determine the distance between two points on the earth given their latitudes and longitudes:\nhttp://www.export911.com/convert/distaCaIc.htm\nhttp://jan.ucc.nau.edu/~cvm/latlongdist.html
737744
In order to answer this question you need to know Winconsin's latitude.\nFor Wisconsin its latitude depends where you are there but it will change between 42°30'N to 47°3'N.\n\nThe midpoint between the equator and the pole is 45°.  \n\nSo if you are in south Wisconsin with a latitude < 45° you are closer to the equator than the pole.  \n\nIf you are in north Wisconsin with a latitude above 45° you are closer to the north pole.
1148398
the shortest distance between two points
809286
lat. 52.764248 deg,  lon -0.885651 deg.    is what i got.  maybe this helps
1058510
(1) Latitude is an imaginary line that runs east and west and connects points of equal latitude on the globe. \n\n(2) The equator marks 0° latitude and makes a great circle that encompasses the Earth at its broadest width.\n\n(3)  All other lines of latitude are parallel to the equator and form smaller circles.
798910
We know that the distance betwen two points is {(sqrt)(x1-x2)^2+(ya-y2)^2}\nBy the problem\n{(sqrt)(2+10)^2+(y-13)^2=13\n{(sqrt)(144+y^2-26y+169=13\n144+y^2-26y+169=169     [squaring both sides}\ny^2-26y+144=0\n(y-18)(y-8)=0      [factorising y^2-26y+144]\ntherefore y=18 or 8
835850
49 degrees N latitude
560119
Bethany's method isn't going to work cos 2 triangles are needed, not one. If that method is used, we'll obtain an answer close to 340km, which is obviously incorrect.\n\nSo, draw a straight line down from the moon, and a horizontal line cutting through both cities, such that these 2 lines form a right angle where they meet. Let this point be known as M.\n\nSince the angle of elevation of the second city is higher, this means that the second city is closer to the moon. So let the distance between the second city and point M be x.\n\nFrom here, we can use the laws of sine/cosine/tangent to construct the following equations:\nopposite = (x) x tan52.743\nopposite = (x + 398) x tan52.6997\n\nBoth eqns share the same "opposite", so they can be equated:\n1.314733352x = 1.312673378x + 522.4440045\nx = 253616\n\nx + 398 = 254014\n\nDistance from moon to first city = cos52.6997 x 254014\n                                 = 153,931km
172928
To find the distance between two points:\n\nSubtract the two first coordinates and square this answer (multiply it by itself)\n\nThen subtract the two second coordinates and square this answer\n\nAdd the two squared answers and do the square root of this sum\n\nThat's the distance\n\nSo, for (3,-2) and (-2, 10)...\n\n3 - -2 = 5, 5 squared is 25\n\n-2 - 10 is -12 squared is 144\n\n144+25=169\n\nsqrt (169) = 13\n\nSo the distance is 13
681007
If you mean the latitude, then it's 41.873712° N (+41.873712°).\n\nIf you mean the magnetic declination, then it's currently\n14°15'W changing by 0°3'E/year.
66035
Well suppose you want to find antipodal positions on the earth. The earth is only approximately a sphere (it is actually closer to an oblate spheroid), so the mathematical definition of an antipodal point on the earth does not quite hold. \n\nIf one location on earth is at 23 degrees North latitude, and 10 degrees West longitude, the antipodal point will be at 23 degrees South latitude, and 190 degrees West longitude (but 190 degrees West longitude will be more often called 170 degrees East longitude). \n\nThat is, just add 180 degrees to the longitude, and switch the North latitude to South latitude (or vice versa).
369779
Latitude is used to measure how far north or south a location is, based on its distance from the equator, which is the imaginary line (or circle) that runs around the earth, equally distant from the north and the south poles. (The Equator gets its name from being EQUAL distance apart from the poles). \n\nFrom the Equator to the north pole, the distance is broken into 90 degrees of measurement, and likewise, from the Equator to the South Pole.\n\nWhile the Equator and other "lines of latitude" help measure  north-south location, the lines themselves extend in the east-west direction as they represent every point on the earth that is that distance from the equator. These lines are often called PARALLELS, because they are all parallel to the equator. You can have a parallel at any measure of latitude, such as the 10 degrees north parallel or the 42 degrees south parallel. \n\nSome parallels have special names. Besides the Equator, there are four parallels which have significance for the earth's rotation and seasons. In the northern hemisphere, the Tropic of Cancer is the line or circle of latitude that is 23.5 degrees north, and the Arctic Circle is 66.5 degrees north. In the southern hemisphere, the Tropic of Capricorn is 23.5 degrees south, and the Antarctic Circle is 66.5 degrees south. Because the earth's axis is at an angle to the sun, we have seasons, and these lines show where the sun's location will be or not be on particular seasonal changes. Use the first link to learn more about these lines.\n\nOther parallels have historical significance. When the Korean War ended in a stalemate, the country was divided into North and South Korea roughly along the 38th parallel (that means everything north of the 38 degrees north parallel belonged to North Korea, and everything south of  that parallel belonged to South Korea). In the 1800s, the 49th parallel (north) is what was used to determine the boundary between the United States and the British colony of Canada, west of the Great Lakes, and so most of the current US-Canada border is a line along the 49th parallel.\n\nAll lines (or circles) of latitude can be called parallels.
1183908
There is no such equation. \n\nThe post office keeps a database with the latitude and longitude of each post office -- each zip code. You can look up the latitudes and longitudes of the zip codes and use them to compute the distance. For a spherical earth:\n\nLet Lat1 and Lon1 be the latitude and longitude of the first post office. Let Lat2 and Lon2 be the latitude and longitude of the second post office. Then compute the angles:\n\ndLon = | Lon1 - Lon2 |   (make sure to account for any difference in the east- or west- of Greenwich longitudes)\n\nD = 2 arcsin[ sqroot{ sin^2((Lat2 - Lat1)/ 2)+ cos(Lat1) cos(Lat2) sin^2(dLon/2) } ]\n\nIf you computed D in radians, convert D from an angle to a distance (in miles) using the equation: \n\nMiles = D * 12450 / pi\n\nIf you computed D in degrees, use the equation:\n\nMiles = D * 69.167
44586
The earth is not a perfect sphere. It's slightly 'wider' than it is tall, so you could measure the circumference at the equator (24,901.55 miles or 40,075.16 kilometers). If you go through the south and north poles (24,859.82 miles or 40,008 km)
725888
Using Pythagoras' Theorem, with R, the radius of the earth, equal to 6400km, and assuming that your height is considerably less than R, then you find that the distance to the horizon is approximately 3.6km multiplied by the square root of the height above ground level.\n\nFor example, if you are roughly 2m tall then the distance, if you are standing at ground level will be 3.6x1.4 = 5km, roughly.  This is about 3 miles.\n\nIf you are 2m tall and standing on a cliff of 20m then you can see 3.6x4.7 = 17km or about 10.5 miles.\n\nHope this helps!
476223
The Earth rotates once in 24 hours, and its (equatorial) radius is 3,963 miles (6,378 km). As with the Moon, the rotational speed starts at zero at either geographic pole and increases as you head toward the equator, where it reaches its maximum of about 1038 mi/hr (1669 km/hr). At 45 degrees north or south latitude, the rotational speed is about 0.7 of this maximum speed.
476566
Conversions:\n\n1 statute (ordinary) mile = 5,280 feet\n1 nautical mile = 6,080 feet\n1 angular minute = 1 nautical mile along the equator\n1 degree = 60 angular minutes\n1 circumference = 360 degrees\n\nTherefore: \n\nCircumference = 360 x 60 x 1 x 6,080  feet\n\nCircumference = 131,328,000 feet ANSWER or\n\nCircumference = 131,328,000 feet/ 5,280 feet per mile\n\nCircumference = 24,873 statute miles ANSWER