How do I factor 90x^3+6x^2-12x?
364629
I am sorry that I can't explain how, but the steps and the answer is here... (6x)(5x+2)(3x-1)\n\n90x^3+6x^2-12x \n6 (15x^3+x^2-2x)\n6x (15x^2+x-2)\n(6x) (5x+2)(3x-1)\n\nTo check 5x*3x=15x^2, 2*3x=6x, 5x*-1=-5x,2*-1=-2, so\n15x^2+6x-5x-2, take out 5x out of 6x and you get 1x.\n\nThen multiply 6x across the whole formula.
835153
.more kids homework... factoring?\n1. rewrite the middle term as the sum of two terms and then factor completely 15x^2 -21x +6\n\n3(5x^2-7x+2)\n3(5x^2-5x-2x+2)\n3(5x-2)(x-1)\n\n2. rewrite the middle term as the sum of two terms and then facto by grouping. x^2 - 14x +45 \n\nx^2-9x-5x+45\n(x-9)(x-5)\n\n3. rerewrite the middle term as the sum of two terms and then facto by grouping x^2 + 19x +90\n\nx^2-10x+9x+90\n(x+10)(x+9)\n\n4. rewrite the middle term as the sum of two terms and then facto by grouping x^2 -2x -63\n\nx^2-9x+7x-63\n(x-9)(x+7)\n\n5.solve x^2 = -6x\n\nx=-6
827041
Obviously 1 isn't worth trying because 90 is so much bigger than the other terms, but you should check that\nP(2) = 0, and so\nP(x) = (x - 2)(x^3 + x^2 - 21x - 45)\n[You know how to do long division to get this?]\nSub -3 in the second factor and find\nP(-3) = 0\nand so x + 3 is a factor, and then\nP(x) = (x - 2)(x + 3)(x^2 -2x  -15)\nand you should be able to finish it from there.
786976
16x^2 + 12x\n\nIn order to solve, you would need an equal sign.  I think maybe you mean finding the zeros?\n\nFirst we would need to factor it.  We could pull an x and a 4 out of each.\n\n4x(4x + 3)\n\nWe get two factors.\n4x\n4x + 3\n\nThen we set each factor equal to 0 to find the zeros of the equation.\n\n4x = 0\nx = 0\n\n4x + 3 = 0\n4x = -3\nx = -3/4\n\nOur zeros are 0 and -3/4.\n\nI hope I helped. :)
767628
I'm assuming you want to factor this\n\n5z^2 + 4z -12 = (5z -6)(z+2)
944695
12 * (3-e^-3x)^3 *  e^-3x
843398
6x(x-3y)-3(6x^2-xy) = 6x^2-18xy-18x^2+3xy=-12x^2-15xy ans.
528350
(5x + 4)(6x + 4)\n30x^2 + 20x + 24x + 16\n30x^2 + 44x + 16\nANS : 16
786382
x^2-6x+9=3+9\n(x-3)^2=+/-rt12\nx-3=+/-2rt3\nx=3+/-2rt3\n\n2.2(x^2+5x)=-11\n2(x^2+5x+25/4-25/4)=-11\n2(x+5/2)^2-25/2=-22/2\n2(x+5/2)^2=3/2\n(x+5/2)^2=3/4\nx+5/2=+/-(rt3)/2\nx=-5/2+/-(rt3)/2\n=1/2[-5+/-rt3]
930308
x=[2+/-rt(4+60)]/2\n=[2+/-8]/2\n=-3 or 5\nso the factors are\n(x+3)(x-5)
263286
the problem you presented above can be represented as,\n\n(8x^8/2x^2) + (16x^6/2x^2) - (12x^3/2x^2)\n\nthen you can simply divide each of the term\nyou'll get\n\n4x^6 + 8x^4 - 6x
614345
(x+10)(x-10)\n(x-4)(x²+4x+16)\n(x+w)(x²-wx+w²)\n\nUnfortunately you just have to memorize the formulas.  There is no other way to figure out the factoring of the cubic expressions.
10610
X^2-9X+18\n\nShort and simple just factor it FOIL
898442
You just factor\n(2x-1)(x-2)=0\nx=2, 1/2
774014
2^3+2*2^2-3(2)-10=8+8- 6 -10 =0\nTherefore x-2 is a factor of the given polynomial
895527
2x^2-8x+3x-12\n2x(x-4)+3(x-4)\n2x+3 = 0 or x-4= 0\nx = -3/2 or x = 4\n\n2x^2+10x-72\n2x^2+18x-8x-72\n2x(x+9)-8(x+9)\nx = 4 or x = -9\n\nx^2+6x-x-6\nx-1 = 0 or x+6 = 0\nx = 1 or x = -6
92952
(8x+3)(4x+3)\n32x2+24x+24x+9\n32x2+48x+9