What is the difference between a NEMA 5-20R and NEMA 5-20L outlet?
360965
the "L" indicates a twist-lock recptacle that prevents the cord from being kicked out. MIKE
22663
Either above ground or below you have loss dependent on the length of travel.  It is more efficient to run at higher voltages, that is why there are step up transformers at the beginning of long runs and step down transformers from the main lines to the house lines.\n\nSome loss occurs as a result of heat energy
257792
When it says that it's 120VAC, it means that it's designed to run on power from the wall.  It's not designed for a low voltage (12V) situation.  The amperage measures at what current it might start malfunctioning.  Since a relay is a sort of switch, it's not a question of that much power being dissipated in the device.  (If it was generating 1200 W, it would be as hot as a toaster).
456654
For the three contacts in a plug which are detailed below.\n\nLive\nThe live contact carries alternating current. The voltage varies by country, as set by national regulations and industry standards. In a few cases (older installations in Scandinavian countries, the outputs of British 110 V building site isolation transformers and probably a few other cases) both main conductors may be live, either being two phases from a three-phase system or being from a single-phase transformer with centre-tapped output. Some plug/socket combinations are designed in a way that a plug can be inserted only one possible way — this is referred to as a polarised plug (not to be confused with positive and negative polarity). Others allow the plug to be inserted with live and neutral either way round — this is referred to as an unpolarised plug. Furthermore even if live and neutral can only mate one way round it may be common to wire them without regard for which is which.\n\n\nNeutral\nThe neutral contact is in most (but not all) cases referenced to the earth. Except under fault conditions it generally does not pose a danger, but is nevertheless treated as live in most installation practices.\n\nThe main danger that can be posed by the neutral is it has a non-null voltage (possibly as high as the voltage on the mains line) after a broken neutral cable in the wiring. Neutral and earth (ground) are strongly related (see Ground (power)) and are usually connected at some point. However extra connections between the Neutral and the Ground must not be made unless the relevant jurisdiction's regulations allow it.\n\n\nEarth\nThe earth contact is only intended to carry current when connected to equipment that has developed an insulation fault (except for EMI/RFI filters which do cause a small current down the earth). If a bare live wire or live component in a device gets loose and touches the metal casing of the appliance, somebody touching the case may receive an electric shock. In many countries devices with metal cases must have the case connected to the ground connection. This reduces but does not eliminate the voltage present on the case relative to earth and metalwork connected to the earthing system.\n\nWhen the neutral is directly connected to the earth as part of the wiring system (a TN system) a fault to earth is a short circuit and therefore provided the wiring is done correctly the circuit breaker will open, or the fuse will blow. In the case of an indirect connection (via the body of the earth) between the earth and the neutral (a TT system) the resistance of the path is much higher and therefore a residual-current device (RCD) must normally be used to disconnect the fault.\n\nThe neutral core could in theory be used as a ground, but this would be dangerous if the core broke, so this is not normally used in building wiring or portable appliances. It is, however, used in some other situations with special precautions. For instance, in Switzerland, sockets in houses with the old two wire installation have the ground and neutral contacts connected together, probably supposing, that the professionally maintained house installation is much more reliable than plugged-in device. Also using the neutral as a ground prevents the use of RCDs.
255532
Its the same jack, rj48 is used for T1 or PRI lines etc & uses all the 8 copper lines if i remeber right. Where as rj45 uses 4 & is designed for ethernet
1028004
Window units run off of 110 voltage x 2 = 220 voltage. Central air runs off 220 voltage. Central air circulates much better than window units. I'd opt for central air.
130012
There are a few things one should consider when engineering a busbar solution.  A general rule of thumb for sizing copper busbar used for 60 Hz applications is 1000 Amperes per square inch.  For example, 1/4" x 2" = 500 Amperes continuous.  If you'll be bolting busbars together, the general "overlap ampacity" rule of thumb is 200 Amperes per square inch of overlap.  These are the two basic rules for sizing copper busbar in most applications.  \n\nMore information is necessary to answer the question, such as frequency, maximum rated transformer current, desired heat rise, material type (copper / aluminum).  There are other things to consider besides conductor size such as, bracing the busbars to achieve the desired interrupting rating, insulating the busbar to achieve the proper BIL level, etc.\n\nBusbar engineering isn’t quite as simple as it looks and if done wrong, it could lead to severe injury or death.  This information is very general in nature, and consequently, is not applicable to every situation.  If you’ve never done this before, you should hire an experienced and qualified bus fabricator.  This information is very general in nature, and consequently, is not applicable to every situation.
399258
just put a limiting resistor. 60mA and 12V. Limiting resistor =R=(V-Vled)/I. assuming the extreme, 0V for Vled. R=12/6e-2=200ohm. that way the current will never exceed 60mA.
906258
Amiya\n\nThe busbar sizing is the easiest of all in electrical engineering\n\nYou will need to understand the basis\nThe bus bar sizing is limited by the allowable current desity in the copper bar\n\nIf you want to size for a 1000A current, then you will take the 99.99% pure copper as the bar material. The current density allowable depends on the ambient temperature and the ventilation system adapted inside the panel. However upon assuming a reasonable local values for it, just devide the current by the current density of copper, you will get the allowable copper area of cross section\n\nfollowed by this, you can find out the cross sectional availability of the copper bars. If one is not meeting your area, you can stack two similar bars. You can not stack two different sizes of bars due to their difference in resistances. \n\nI think this background is just enough for the basics.\n\nLet us go to specifics.\n\nDo you want to design manually or using a software?\n\nManual designing is outbid by software.\n\nTry the free software below. I just tried to download and checked the operation of the software. It works excellent. I recommend you to try this.\n\nhttp://www.cda.org.uk/download/d11.exe\n\nStill if you insist for a manual calculation, Pl download the link below\n\nhttp://www.socomec.fr/documentation/documents/Catec-gb.pdf\n\nCheck the last page for busbar designing\n\n\nIf you find my answer fitting to your question,\nJust rate my answer. I will get 10 points for the best answer. This will take me to level 2 in yahoo answers. I can help answering others more effectively at higher levels.\n\nGood Luck\n\nGood Luck.\n\nHope i have solved your problem
36655
potential difference\ndue to which the crrent flows  through the ends of the battery due 2 which appliances work on cell or a battery
297024
Nichrome (Nickel Chrome) wire is one of the more common alloys used as a heating element wire.\n\nIn a way it is correct that the higher the resistance, the more heat that will be generated.  Looking at Ohm's law, V = I * R and P = I * V.   P being power, which in a resistor is exhibited as heat.  P = I^2  * R  or P = V^2 / R\n\nWhat this is saying is that while although more resistance will produce more heat, you will also need to increase the voltage (which will increase the current) to get that heat.  So, more resistance is not the simple answer, you need to match the resistance with your electrical supply capabilities to optimize the heat output.\n\nIt would probably would be better to figure that the more current flowing through the resistor, the more resulting heat you will get.\n\nAs far as wire goes, a smaller diameter wire will have a higher resistance, and will get hotter using less current.  A larger wire will have a lower resistance and require more current to get as hot as the smaller wire.  But, again referring back to Ohm's law, the overall heat exhibited will be the result of figuring the power output for the wire (voltage multiplied by current).  The larger wire will be capable of a higher power output before it surcumbs to the heat and melts because it can carry a higher current.\n\nFor the sake of comparison, let's say that we have a short piece of thin wire and a longer piece of thick wire.  Because of the difference in lengths, they will have the same resistance.  If they are both subjected to the same electrical power supply (same volts, same amps), they will both produce the SAME amount of heat.  The smaller wire will have a higher heat DENSITY because it needs to produce the same thermal energy over a smaller area.  It will appear hotter because of this.  But, if both were used to heat water, they would in theory do exactly the same thing.
958791
I don't know but the only difference is that they have a better grip for when you insert it and that it's stronger (like SUPER tampons but not as big).\n\nhttp://www.playtexsport.com/
1132650
Responses without sources aren't answers, just opinions.\n\nA higher frequency results in a smaller lighter transformer (hence usually less expensive) for the same capacity.\n\nTo indiantrumpet: nice to see that you posted a verifiable source.
878570
If the 20A fuse is the size that is designed for the machine, then something is wrong with the machine.\n\nMost likely, either accumulated dirt, or worn out parts, or both, are causing the load on the motor to be much higher than designed. If you continue to operate the compressor in this way you will burn out the motor. I looked a little bit for on-line info about the compressor you mentioned but could not find it. If it is old, and replacement parts are not available, you may need to replace the compressor.\n\nOne possible transient cause could be a much lower than normal supply voltage - a brownout. If this is happening, the motor will draw more current and possibly blow the fuse. If this is the problem, the solution is to correct the power supply (if it is under your control) or to wait until it is normal again (if it is a utility supply).
809231
Ok then, one at a time\n\nwhy are the wires in a plug covered in flexible plastic? - its insulation to stop the individual strands of wire touching each other and causing a short circuit.\n\nwhy is brass used to make the pins in the plug? - 2 reasons, its a very good conductor of electricity and its very strong and resilient to being put in and taken out of the spring loaded metal strips that contact it in a plug.\n\nwhy is the earth pin longer than the others? - its a safety thing, the earth pin goes in first and you cant insert anything into the other two holes until it has - its to stop kids frying themselves if they shove stuff into the holes.\n\nwhy is thick cable used for some appliances and thin for others? - depends upon the amount of current it'll be carrying, a cable for an adaptor for a USB external drive say is thin because it uses a small amount of current, but your electric cooker uses tons, the wire has to be thicker to carry the amount of amperage travelling through it so that it doesn't overheat.\n\nwhat is the purpose of a fuse? - its in case of a power surge, it will blow if too much current passes through it, the fuse blows and not your expensive electrical items.\n\nHope that gave you all you needed to know.
702129
I've found a good site introducing and explaining the voltage and phase relationships between delta and wye 3 phase transformers. Try www.elec-toolbox.com/usefulinfo/xfmr-3ph.htm\nI hope that this proves useful for your research.
932280
When supplying a branch circuit with more than one live conductor, each live conductor must be protected by a breaker pole. To ensure that all live conductors are interrupted when any pole trips, a "common trip" breaker must be used. These may either contain two or three tripping mechanisms within one case, or for small breakers, may externally tie the poles together via their operating handles. Two pole common trip breakers are common on 120/240 volt systems where 240 volt loads (including major appliances or further distribution boards) span the two out-of-phase live wires. Three pole common trip breakers are typically used to supply three phase power to large motors or further distribution boards.\n\nMCB (Miniature Circuit Breaker)—rated current not more than 100 A. Trip characteristics normally not adjustable. Thermal or thermal-magnetic operation. \nThe overload relay  consists of a coil, a plunger, a dashpot, and a pair \nof switch contacts. The plunger is attached to a disk suspended in an oil-filled chamber (dashpot). The coil connects in series with an associated 440-volt motor supply circuit and the switch contacts are in a 115-volt start-and-run circuit for the motor. \n\nDuring normal operation, the magnetic flux induced by the coil is not great enough to cause an appreciable movement of the plunger. However, if an overload of sufficient magnitude and duration occurs, the increased current through the coil draws the plunger upward. \n\nWhen the plunger and disk reach the end of their upward travel, the normally closed contacts open in the 115-volt start-and-run circuit, de-energizing the motor contactor which opens the 440-volt motor supply circuit. With the motor circuit open, the overload relay plunger drops and the relay resets. \n\nSince the dashpot retards upward movement of the plunger disk, the circuit does not break instantaneously during an overload. Two conditions determine the delay time: (1) the size of the orifice in the plunger disk through which the oil must pass and (2) the magnitude of the overload (strength of the magnetic field).