In HVAC cooling load calculation, For High rise buildings how they r calculating.?
361569
It includes the number of air handlers being used, and the use of each room.  For example, equipment rooms have specific cooling requirements.  Generally, it depends on the total build-up area.
547543
When you say you want to design a chiller, I assume you mean the process design not the mechanical design. \n\nThe amount of heat being transferred is a given based on the process requirements. \n\nSince this is a BKU the shell side temperature both in and out will be the temperature of the refrigerant "bath" therefore the LMTD calculation is pretty straight forward.\n\nThe inlet and outlet temperatures on the tube side are also process design requirement and fixed by the process. \n\nThe actual materials of construction have very little to do with the actual sizing of the exchanger. Knowing the overall heat transfer coefficient is more a factor of the boiling liquid on the shell side and any condensing on the tube side. Velocity through the tubes is also a main factor.\n\nThe actual calculations are a trial and error method, because of this there are many computer programs to do the calculation for you. To attempt to provide a set of useful sample calculations on this site is not possible. You have to assume a tube size, number of tubes, tube length, tube arrangement, tube spacing and an acceptable pressure on the tube side.
958888
Use the formula:\nQ (heat) = Cp (Heat Capacity) * delta T (Change in Temperature)
187066
The rule of thumb is 1 ton for about 1000 SqFt. I will say at least a 1.5 Ton unit, especially if you are planning to add more space to your house. I am not sure what kind of heating you are using but there is split systems with heat pumps and other options to accomodate your heating too. Call your York agents, they will help you out.
363092
Well I'm not going to do the calculation for you but you can.\n\nDo a web search and you'll find dozens of sites to help you if you don't have a fluid flow handbook.
497419
The location of AC supply vents is strictly a matter of what is simpliest, easiest and cheapiest for the HVAC contractor. \n\nNo matter where you put them, the air from the AC is cooler that any other air in the room and will tend to go to the floor. So no matter when you have the vent the cooler air ends up in the same place.\n\nThe same story for air in the heating season. Except in reverse because warmer air rises.
177044
use the fmla.... Q=msT\n\nwhere Q is the quantity of heat required, m is mass, s is specific heat capacity of water, T is the temperature difference. i dont hav a calculator with me now, u do the computations plz...
827251
V = πr²h\nA (top & bottom) = πr²\nEnd Area = 2πr²\nLateral Area = 2πrh\nCost of tube = 2πrhC, C being cost per unit area\nCost of ends = 2πr²C*1.2\nTotal cost, P = 2πC(1.2r² + rh)\nh = V/πr², so\nP = 2πC(1.2r² + rV/πr²)\nP = 2πC(1.2r² + V/πr)\ndP/dr = 2πC(2.4r - V/πr²) = 0 for max or min, so\n2.4r = V/πr²\nr³ = V/2.4π\nr³ = 5/2.4π\nr = 0.872"\nh = 5/π0.872²\nh = 2.093"\n\nCheck:\nC(2.4*π0.872² + 10/0.872) = 17.201050C\nC(2.4*π0.87² + 10/0.87) = 17.201444C (+0.000394)\nC(2.4*π0.874² + 10/0.874) = 17.201137C (+0.000087)
322338
Some general overhead allocation methods are ratios based on:\n\nHeadcount \nArea occupied (sq ft)\nTime usage\n\nThe method usually depends on the type of cost. For example Utilities (electricity) would probably be based on area occupied as a percent of total area; whereas Liability Insurance would probably be based on headcount.\n\nHope that helps
975129
A square foot calculation would work, but you'd need to know the approx. cost per square foot of the building...  and the square footage per floor.  It'd cost more in a seismically active area because you'd need more structurally.  \n\nMaybe you could use $150/sq. ft. as a safe (high) number.  That's a construction cost for just the shell.  \n\nCheck this link http://www.manhattan-institute.org/html/cr_39.htm that says, "The physical cost of construction for high-rise apartment buildings in Manhattan ranges from $150 to $200 per square foot"\n\nHope that helps!
897593
If you are doing this in terms of the system,\n\nsince the system is losing energy (delivers heat) then the amount of energy is "-1275 J".  The surrounding add heat (perform work on) to the system, so the amount of energy is "+855".  The internal energy of the system is the sum of the energy loss and the work done to the system, so -1275 J + 855 J = -420 J.\n\nIf you are doing this problem in terms of the surroundings, the all the signs are reversed and you should end up with +420 J.
256725
I agree that I believe this to be a heat transfer equation however it seems that something is missing.  From the gut I would think that it is a way to calculate heat loss through something like a double-paned window.
644717
Rearranging the equation watts=volts*amps to solve for amps gives:\namps=watts/volts\nFor example, 1,200 watt hair dryer on the regular household voltage of 120V uses 10 amps.\nBe aware that your A/C may run on 220V or 240V, so check the data plate before calculating.\n\nAlso be aware that inductive devices like the electric motors in your A/C may have a power factor other than 1, but I would ignore that if I were you, because I find it confusing. If you don't want to ignore power factor, here are a couple of links.
542138
The general formula to calculate the heat loss is\n\nQ=m*cv*(t2-t1)\n\nQ is the heat loss\ncv is the specific volume at constant volume(if it is a constant volume process)otherwise use cp(specific heat at constant pressure)\n\nt2 is the external temperature\nt1 is the internal temperature
921703
Just let the units tell you what to do.  H=mass* T*sp heat.  with T in K
584010
E = 1/2 M x v^2 x F x H \n \nWhere v is the velocity of the load hitting the surface and H is the time period in which the frequency continues.
1017637
I will assume you want to find the sq ft of a house or building. You just multiply the length by the width. If the build has several different dimentions you will have to figure each area seperately and then add up the totals.