Need to purchase a field meter to measure % transmittance in water.  Like Hach DR/850?
358092
Check the Omega online catalog. They have an extensive supply of measuring devices for lab, process, and manufacturing uses. Customer service is top notch.\n\nwww.omega.com
925200
The scientific supply companies like VWR probably have them.\n\nI searched for "oxygen reduction potential electrode" and got a bunch of hits.  Try that.\n\nYou'll also need a meter to attach it to.  Many better pH meters can handle this kind of probe as well.
1162066
See if this meets your needs.\n\nhttp://www.fishingworks.com/tide_prediction_interval.cfm
777109
photogrammetric analytical instrument Auction\n\nhttp://cgi.ebay.com/TOPOGRAPHIC-HYDROGRAPHIC-SURVEYING-CD-8-more-3452p_W0QQitemZ230045806754QQihZ013QQcategoryZ26204QQcmdZViewItem\n\n:>peace
241018
= wind speed measurement over shore and water surface.\n\nclick link to read more...
438682
sure. go to a science store or look up schematics on the web.
169474
Measure the transmission of light through the test-tubes using two small identical solar cells and a single light source equidistant from the two tubes.  The voltage off the cells can be fed into vu-meters (one for each test-tube) and when the two vu-meters read the same, the two test-tube mixtures should be equally opaque.
1185872
I can think of two ways to measure the absorption and reflection coefficient of a material.  The first would only work with a polished surface.  First measure the intensity of a laser beam with a photodetector, then shoot the laser beam at the surface and aim the reflection at a photodetector.  Coefficient of reflection = transmitted intensity/initial intensity  (coefficient of absorption =1-reflection).  The other, harder way, which would work with any material, is to measure the heat gain in the target.\n\nFor this you're gonna want as small a piece of the target material you can get so that the laser still completely hits it.  Now attach a thermistor to the back of the target (again the smaller and thinner the target the better, ideal would be a foil just thick enough to be completely opaque).  Now shoot the laser at the target and measure the temperature as a function of time  It should be linear up until it starts radiating nearly as fast as it absorbs energy, so take points until it starts to level off and drop points after that.  Now find the specific heat of the thermistor-target apparatus by dipping it in water with a thermometer in it, using the initial and final temperature of the water, the volume of the water, and the initial temp of the apparatus, determine the heat it absorbed per degree it's temperature changed (this will actually give you specific heat*mass which is fine).  Now convert your temperature vs. time data to heat vs. time using the specific heat you determined (temp*(specific heat*mass)).  The slope of the line of best fit for this data will give you the rate it absorbed energy in watts.  Divide this by the lasers output in watts and you get the absorption coefficient.
1148898
For that quantity, check with Aquadynne. They may be able to help you:\n\nhttp://www.aquadyne.com.au/home.php
562654
Okay, I'll try this one -\n\nRun this experiment twice (or more times), each time with a piece of metal having different density.  The metal piece should be of adequate size (a sewing needle isn't going to do it), it needs to be big enough to significantly affect the temperature of the water.  You will need to know the mass of the metal (i.e., weigh it) and have a thermometer capable of reading from room temperature up through boiling or so.  Please note this is not going to give you a highly accurate answer, but can give you a ballpark idea (I'm guessing you're probably not doing this in a 500 million dollar lab).\n\nThe procedure:\n\n1)  Measure and record room temperature as T1.\n\n2)  Weigh the metal, call it M1.\n\n3)  Bring a known quantity of water (weigh it, or measure it and convert to weight, call it M2) to a temperature just short of boiling (say 180F to 200F, use the same temperature for each run of this experiment).  Record the temperature as T2, and remove the heat source (take it off the burner, etc.).\n\n4)  Drop in a metal piece at room temperature.  Allow a couple of minutes for heat to exchange.  Make sure you use \nthe same amount of time for each run of this experiment.\n\n5)  Measure and record the new temperature of the water as T3.\n\n6)  Repeat with your other metal samples.\n\nYou can now estimate the specific heat capacity for each metal.  It will not be super-accurate (heat escapes your system, and temperatures won't have completely equalized), but should give you some idea.  Just assume all temperatures did equalize and that no heat escaped for calculational purposes.\n\nSince (you are assuming) the heat which left the water went into the metal, then the product of mass, specific heat capacity, and temperature change should be the same for both the metal and the water (but in opposite directions).\n\nThis means that:\n\n(M1)(c1)(T3-T1) = (M2)(cw)(T2-T3)\n\nwhere c1 is the specific heat capacity of the metal, and cw is the specific heat capacity of water (look it up on Google to get the units you need).\n\nSolving this, you get:\n\n......(M2)(cw)(T2-T3)\nc1 = -----------------\n........(M1)(T3-T1)\n\n(sorry about the dots, I'm trying to keep everything aligned)\n\nRepeat the calculations for each of the metals.\n\nYou will need to calculate (or look up) the densities of each of the metals.  Then, graph density vs. the specific heat capacities you calculated, and see if your hypothesis is true.\n\nHave fun!
740110
there is a company called schrodinger, or something close t o that.\nthey make lasers measureing tools for the semiconductor and other industrues. they are in massachusetts.
751939
you can either do the math, look it up on a chart or go here:\n\nhttp://leebrewery.com/hydromet.htm\n\nand use the java-calculator.
64722
A radiometer does what you describe. \n\nhttp://store.sundancesolar.com/solrad.html\n\n\nDirections to build a simple radiometer:\n\nMake a radiometer to measure solar energy. Colour the paper side of a gum wrapper black and cut in four pieces. Stick the pieces to each side of a match stick with the shiny sides all facing the same way. Wrap a thread around a pencil and attach to the match stick. Suspend in the jar and place in a sunny location. The radiometer will turn as it absorbs energy.
550478
Refrective index water should be the same throught, provided that all the other conditions are the same throughout -- such as temperature, presense of impurity, etc.\n\nIts not the refrective index of water alone that determines whether light will be reflected or not or at what angle the light should be projected to be reflected. When you are talking about the surface of the water, you are really talking about the interface between water and air. When you are talking about "under the water", light is not changing media.
85778
EMF200 Gauss Meter \nRemote Infrared (IR) Thermometer \nmotion detector
372456
To measure ohms, DCV, ACV, Amps or what????
580603
stick it in a tank of water then measure the water displaced.archemedes law