the formula for radius?
367152
its the distance between the centre point of a circle to any point along the edge.\n\nAlso its half the diameter. and it can be calculated from the circumference by dividing circumference by 2 pi.
860968
u can use the following formulas to find the radius\n1)Area of circle=pi.*(radius)^2\nwhen area is given plug in that value into this formula and u can get the radius\n2)radius=diameter/2\nwhen the diameter is given,find the radius by dividing the diameter by 2\n3)circumference=2*pi.*r\nwhen the circumference is given use the above formula to solve for the radius\n\nthere is no definite formula for the radius but depending the other value given u can solve for the radius.\nhope that helps!!!
1068729
i think n=6..\nyes this can be done..if you know the formula..\nof volume and surface arae of a hypersphere and also the form of gamma fucntion..\nhope you can do it yourself..i saw these two links and based on the formula given for volume and surface ares and the gamma fucntion expression its evident that n=6.\nHope you can figure it out yourself.\nvolume= pi^3/6 (radius =1 here)
598391
First find the area of the circle that is on the top or bottom of the cylinder. The area formula for a circle is \n\n"pi,r squared. That means multiply pi times the radius of the circle which you have to square first.\nThen you take the number that you get and multiply it by the height of the cylinder.\nGood luck.
47332
Find the radius from the diameter by dividing it by 2.  So r = 44000 miles\n\nSurface area of any sphere = 4 * pi * r * r\n\npi = 22/7\n \nPlug in the values and you will get the surface area of Jupiter.
563113
radius is half of the diameter.\n\nyou can use the circumference equation; c = pi x d\n\nd = 2r so then c = pi x 2r\nc / pi = 2r\nc / pi / 2 = r
549743
Area increases 4 times. Beacause Area of circle = PiR2.\n\nSo if R doubles then radius will be 2R.\n\nHence area will be Pi(2R)2. which results into\n\n4 Pi R2.
143664
radius= diameter/2\narea=(pi)(radius)^2\n\narea of an 18 inch pizza= (pi)(9)^2= 81(pi)\narea of a 14 inch pizza= (pi)(7)^2= 49(pi)\n\ndifference= 81pi-49pi= 32pi= 100.5 square inches
112213
area of a circle: pi*r^2\nCircumfence: 2*pi*r
601593
Circumference is the distance around a circle.  2 times pi ( which is about 3.14) times the radius (the distance from the center of the cirle to any side).  In formula form it looks like this C = 2*Pi*r.\n\nThe formula for area of a circle is A = Pi*r^2 ( also known as r squared)
303304
Use the well known formulas that relate the radius and diameter of a circle to its circumfrence.\n\nC = pi * D\nC = 2 * pi * R\n\nFor pi, you can use 3.14 or 22/7, or whatever value your teacher wants you to use.
480203
Area of a circle = pi*r^2\n\nr=radius os the circle
736798
So R=1.6*r; R for body, r for head; and H1=K1*R is the distance from body center to the feet, K1=0.8; and h=k*r is the distance from head center to the neck, k=0.9; Now neck radius p=sqrt(r^2-h^2) and p=sqrt(R^2-H2^2), H2=K2*R is distance from body center to the neck, K2 being unknown.  Find K2;  p^2 = r^2*(1-k^2) = R^2*(1-K2^2), hence (r/R)^2*(1-k^2)=1-K2^2 and K2 = sqrt(1-(1/1.6)^2*(1-0.9^2)) = 0.9622;\nNow head volume v=v0-v1, v0=(4/3)*pi*r^3, v1=(pi/3)*r^3*(2-3h/r+(h/r)^3) is head cut-off part; v = (pi/3)*r^3*(2+3h/r-(h/r)^3) = (pi/3)*r^3*(2+2.7-0.9^3)\nThe same for body volume V=V0-V1-V2, V=(pi/3)*(1.6*r)^3 * (4-{2-3*K1+K1^3} - {2-3*K2+K2^3});\nW=v+V=r^3*C is the whole volume! To plug in numbers to find C, OK?
237156
Pi * r^2\n\n(Pi R Squared)\n\nwhere R is the radius (which is also equivalent to half the diameter)
52227
area of a circle is Пr2. hit the П key (shift -> exp (if you have a casio)).  the radius is 9.  square the radius. 9x9=81 (Пx81 or Пx9x9 = 254.4690049 <- that is your answer)
410603
Well, one possibility is radius=3.3cm and height=8.3cm., this measure is proportional with a normal can. You have to remember that a can is a cylinder, so the dimensions must match with 3.141592*r^2 * h=280 - 285
430210
Volume of a shphere  = 4/3 * pi * R^3\n\nwhere pi = 3.142 (approx)\nand R is the radius