whats the average power delivered in RLC paralell circuit?
361838
The average power delivered in an RLC circuit is simply equal to the voltage across the circuit elements (which are the same) multiplied by the current through the resistor i.e P (power) = IV = I*I*R where I = current, V = voltage and R = resistance of resistor.
254996
If PC power supply is 300 watts,during 12 hours,it consumes 3600 watts ( 3.6 kilowatts) or less
892848
One of the most frequently used is E=IR    ;E =voltage    I=current   R= resistance. U can change this every way depending on the unknown.\n    Good luck
525922
Before you can answer this you need at lease to variables. You have the voltage of 1.5 vdc. You will need Amp the clock pulls. Wattage = Volts X Amps.
612298
up to 10 trillion watts
870052
Full example and circuit diagram on http://www.padre.ca/house/multiplier_example_web.pdf
324733
lol here you go... this question is asked all the time in wwiionlines/CSF \n\nfirst look at how much stuff this power supply will be feeding... \n\nhere is a rule of thumb \n\nno less then 500W for a gaming computer\n\nno less then 18A in each (if more then one) 12V+ rail. \n\nno less then 79% efficency\n\nalso take a look at the DB rating of the psu \n\ni have a Enermax 600W Sli noisetaker \n\n600W Peak \n38A 12V+ rail(s)\n96% Effiecncy \n31Db at normal operation
1165747
Nothing is for free.  Peripherals you put inside your computer take certain amount of power.   Motherboard, keyboard, mouse, graphics card, hard drive, cd drive, and etc. etc. all require certain amount of power.\n\nThe issue with have a good power supply isn't about speed.  It's about stability.  Your power supply is in charge of converting the AC current from the wall to DC.  An ideal power supply will provide stable DC current with very little ripple current.   Ripple current is the deviating fluctuation that is present in all DC current provided by a power supply.\n\nAnd it is possible to have too much wattage but only in extreme cases.  Electronic device like power supplies work with tolerance levels usually given in percentages.  So two different rated power supplies built with 5% tolerance will have different tolerances.  With a lot of power you lose a precision.  With precision you use a certain amount of power.  (Analogy would be fidelity and power in audio terms.)
544626
The 6800 is not a power hog like some cards.\n300w should be enough to meet the requirements for the card,\nhowever if you have several devices being powered ie; dvd Rom, CD burner, multiple HDD's etc. You may want to go to 400w +.\n\nBottom line: It should be OK. even though the official min. wattage is 350w
1026240
less than 0.3  for power sations\n0.5ohm for substation\n1 to 2 for homes
99832
i believe it is around 9.5%.\n\nBecause Efficiency = O/p Power / Input power * 100.\n\nOutput is the given one \n= 4 * 104 J/min * 3 * 60 min = 74880 J \nInput is  = 75 * 1076 * 9.8 J ( mgh - mg * 0 = Potential energey) \nthefore, eff. is 9.5%\n\nplease reply at autoprash90@yahoo.co.in
1064803
http://www.epanorama.net/circuits/parallel_output.html
542559
Motherboard manual here:\nhttp://www.emachineupgraders.info/dir1/motherboards/socket478/imperial_downloads.shtml\n The model came with a 250W power supply\nhttp://store.ramplus.com/atatrebe25at.html
272928
The normal maximum for a 9 pin 'D' type sub miniature connector is 1 amp per contact, however the typical serial I/O chip is only designed to deliver 50mA per output pin.\nThe Maximum out voltage for RS232c is + 12v & -12v, although normally there is a 'dead' area between +3v ab -3v to absorb noise on the lines, some higher quality devices will work with a dead area as low as +1v & -1v.
972428
C=80uF\nV=Voc1.5 volts\nI=Isc=5.0 amps (assuming short circuit current)\n\nSo thevnin's theorem implies the \nRth = Voc/Isc = 1.5/5 = 0.3ohms\n\nSo the circuit is an RL circuit,\n\nTime constant T = RC = 0.3*80uF = 24us\n\nNow you can use that formula for charging
429859
Take a look at...\nhttp://www.ampercom.com/download/RScript%20User%20Guide%201.0.pdf
75746
You'll need to provide a little more information in order to have your question answered properly.  AC or DC? Input voltage?  Fixed or variable output voltage? If variable, over what range? If fixed, what is the desired output voltage?  Output current?  How critical is the load regulation?\n\nAs you can see, the answer to your simple question can be a bit complicated :)