what is the answer to 5√1/25, and how do you do it?  show me in steps plz?
372531
first simplify the square root of 1/25.\nthe square root of 1 is one, and the square root of 25 is 5.  that leaves it to 1/5.  then multiply 5 to it - 5 X 1/5 = 1.\ngood luck!
657080
(x + 1)^2 = 25\nx + 1 = -5 or 5\nx = -6 or 4\n\n---------------------\n\nx^2 + 4x + 4 = 16\nx^2 + 4x - 12 = 0\n(x + 6)(x - 2) = 0\nx = -6 or 2\n\n----------------------\n\nx^2 - 14x + 49 = 13\nx^2 - 14x + 36 = 0\n\nx = (-b ± sqrt(b^2 - 4ac))/2a\nx = (-(-14) ± sqrt((-14)^2 - 4(1)(36)))/2(1)\nx = (14 ± sqrt(196 - 144))/2\nx = (14 ± sqrt(52))/2\nx = (14 ± sqrt(4 * 13))/2\nx = (14 ± 2sqrt(13))/2\nx = 7 ± sqrt(13)
770190
x² / √(1-x) \n= x² √(1-x)/(1 - x)\n= (-1 + 1 - x²)√(1-x)/(1 - x)\n= (1 - x²)√(1-x)/(1 - x) - √(1-x)/(1 - x)\n= (1 + x)√(1-x) - √(1-x)/(1 - x)\n= x√(1-x) + √(1-x) - 1/√(1-x)\n\nSo ∫x² / √(1-x) . dx\n= ∫[x√(1-x) + √(1-x) - 1/√(1-x)] . dx\n\nNow ∫x√(1-x)dx \n= x * -1 * 2/3 (√(1-x)³ - ∫[-1 * 2/3 (√(1-x)³ . 1)dx\n= -2x/3 * √(1-x)³ + 2/3∫(√(1-x)³ dx\n= -2x/3 * √(1-x)³ + 2/3*2/5 * -1 * √((1-x)^5)\n= -2x/3 * √(1-x)³ - 4/15 * √((1-x)^5)\n\n∫√(1-x) dx = \n\n∫1/√(1-x) dx = -2 *√(1-x)\n\nSo ∫x² / √(1-x) . dx\n= ∫[x√(1-x) + √(1-x) - 1/√(1-x)] . dx\n=  -2x/3 * √(1-x)³ - 4/15 * √((1-x)^5) - 2/3 * √(1-x)³ + 2 *√(1-x) + c\n= - 4/15 * √((1-x)^5) -2/3 (x + 1)√(1-x)³ + 2 *√(1-x)  + c
64026
55/5 - 5 = 6\n\nClever, no?\n\n... The answer above only works in one equation if you add the parentheses (5x5 + 5)/5 = 6. Take them out and you have 5x5+5/5 = 25+1 = 26.
896906
The strategy is to reduce the number of square roots by repeatedly squaring and rearranging:\n\nSquare\n\n     11 - 2 √11√10 + 10 < 6 - 2 √6√5 + 5\n\nRearrange\n\n     5 <  √11√10 - √6√5\n\nSquare\n\n     25 < 110 - 2 √11√10 √6√5 + 30\n\nRearrange\n\n     2 √11√10 √6√5 < 115\n\nSimplify\n\n     4 √3√11 < 23\n\nSquare\n\n     4² × 3 × 11 < 23²\n\n     528 < 529\n\nwhich is true.\n\nNote that all steps are reversible because both sides of the "<" are positive. For example, √11 - √10 > 0. Else you get into trouble "proving" that 1 < -2 from 1² < (-2)² !!!
539012
1/2 * sqrt(2x) = 5\n\nsqrt(2x) = 10\nsqrt(2x)^2 = 10^2\n2x = 100\nx = 50
907424
5x^2 and - 50x both can be divided by 5 soooo..do this\n\n5(x^2 - 10x) \n\nthen put a space to make in a quadratic equation.  Also, put the +129 on the outside of the paranthesis\n\n5(x^2 - 10x + __ ) + 129 - __\n\ntake half of 10 which is 5.  5^2 and put it in the blank spot\nREMEMBER PUT THE OPPOSITE OF WHAT YOU PUT IN THE QUADRATIC EQUATION ON THE OUTSIDE AND YOU NEED TO MULTIPLY THE OUTSIDE BY THE 5 IN FRONT OF THE EQUATION (25 * 5)= 125\n\nso you get\n5(x^2 - 10x + 25) +129 -  125\nthen factor\n\ny= 5(x - 5)^2 + 4
920470
The answer is:  4.47, and that's all there is to it!\n\nOk Vanessa, all you have to do is pull up your calculator (Start>Accessories).\nI am not suggesting you don't work it out in your head first: it's just basic. Check the answer on the calc, or, if you get stuck....go back.... to POWERS OF HIGH HOLY ROOTISM   SQUARE YOU KNOW, 1x1+(2x2)+2+(10-5)/1=       Simple:\n1+4+2+5/1=12
805031
1)  √10 · ³√100\n= 10^(1/2) · 10^(2/3)\n= 10^(7/6)\n\n2)  (6x)^(1/2) · (36x²)^(1/4)\n= (6x)^(1/2) · (6x)²^(1/4)\n= (6x)^(1/2) · (6x)^(2/4)\n= 6x\n\n...and so on.  Change the radicands to rational exponents with common bases, and follow the rules from there.  Good luck!
983331
a.\n\n   5 =            4 16/16\n - 2 5/16\n________________\n                   2  11/16
331369
a/5 = 6\nYou want to isolate the 'a'.  Move the 5 from the left side of the equal sign to the other side of the equal sign.  When you move it to the other side you invert it, so 1/5 (a/5 is essentially a*1/5) becomes 5/1, or just 5, and multiply by whatever is on that side of the equal sign.  So you get:\na/5 = 6\na * 1/5 = 6\na = 6 * 5/1 \na = 6 * 5\na = 30
493796
You have to do the Trick, meaning you take out the 5 and reapply it to the number without the variable (2). This leaves you with: 5(xsquared-3x-10)=0\n\nFactor what is inside the parenthesis and get: (x+2)(x-5)\n\nThen reapply the 3 into the equations (but only into the variables, because your doing the trick) and you get:\n(5x+2)(5x-5)=0\n\nThen, set both equations to 0 and solve.\nThe first equation:5x+2=0\nSubtract the 2 from both sides to get: 5x=-2\n\nNext, divide the 5 out of both sides to get: x=-2/5\n\nThe second equation: 5x-5=0\nAdd 5 to both sides to get: 5x=5\n\nNext, divide the 5 out of both sides to get: x=5/5 or x=1\n\nFINAL ANSWERS:\nx=-2/5\nx=1\n\nIf it's a word problem and you can only have one answer, elimate the one that doesn't make sense. For example, if they are asking for the height of something, you wouldn't pick the negative number.
907037
Re: ³√(5/2)\n\nIf you need an approximation it is (5/2)^(1/3) on your calculator (as stated above)\n\nIf you want it exactly then you can write it as ³√(5/2) (also as stated above)\n\nIf you want to express it exactl;y BUT with a rational denominator then:\n\n³√(5/2) = ³√5 / ³√2 * ³√(2²) / ³√(2²) \n= ³√20/³√(2³)\n= ½ ³√20
1000957
7/5.\n\n(2/5)^2 = 4/25, then divide by (1/5) to get 4/5.\n\nAs for the rest, it's (-2) * (-3) / 10 = 6/10 = 3/5.\n\n3/5 + 4/5 = 7/5.
693929
Your first question with the V's is unclear.\n\n√(10 - 6) / -5 √(10 + 7)\n√(4) / -5 √(17)\n√(4) / -5 √(4 * 4∙25)\n√(4) / -5 √(4) √(4∙25)\n 1 / -5 √(4∙25)
773372
-x/ sqrt (25-x^2)\nill explain it for ya\njust a chain rule problem\nthe equation is easy written as (25-x^2)^(1/2)\n(1/2) goes to (-1/2) dropping (25-x^2) to the denominator\nand multiplying by (1/2)\nnext times the numerator by the derivative of the inside (-2x)\nthe -2x and 1/2 make -x in the numerator\nleaving -x/(25-x^2)^(1/2) which is another way of what i typed for teh answer
767712
First you find the square root of both the numerator and the denominator which would end up being √5/√8. This would be a fine answer, but in my math classes teachers have had rules against keeping a radical in the denominator. so, to get rid of that multiply √5/√8 by √8/√8, which gives you √40/√64, or √40/8.