What is the speed and the volume of the water flowing in the Gulf stream?
375342
The Gulf Stream is a strong warm ocean current, transporting as much heat as the annual output of 1 million power stations. It moves water at a rate of 30 million cubic meters per second off of Florida, increasing to 80 million cubic meters per second as it moves farther north. The volume of the Gulf Stream is far more water than all the water of all rivers that empty into the Atlantic combined (they barely total 0.6 million cubic meters per second.)\n\nHere's a cool heat image of the gulf stream (see URL below).
859051
water has density 1gm/ml. what ever is the volume in ml for water same is the mass in gms because density = mass/volume\n\n\ni hope it will help you out
851515
the easy answer is that it is less dense, but if you want the real answer, it is most dense at 4C, here is a graph\n\nhttp://www.piercecollege.edu/offices/weather/water.html
760588
Above is correct for G, with reference to water surface .... G is zero at final moment when student touches the water.\n\nFor E its zero at intial moment but not at final. Infact it is max at final moment coz that's where the extension is max.\n\nK is zero both at final n intial moments becoz at both times speed or velocity magnitude is zero, hence no KE
700759
Let \nQ = volume flow rate in Litre/sec, \nD = diameter of the nozzle in cm and \nV = velocity of water in metre/sec. \n\nThen,  V = (40*Q)/ [pi*(D^2)]\n\nwhere pi = 3.14
404074
the gulf stream makes the atlantic warmer
925754
At sea level, at a temperature of 21 °C (70 °F) and under normal atmospheric conditions, the speed of sound is 344 m/s (1238 km/h or 770 mph).
1105154
pressure is: \n p(density)gh / gc =y(specific weight)h\nflow of liquid flowing inside the pipeline is:\n use the bernoulli equation:\n [p1/p(density)g  +  v1^2/2g  +  z1]  =  [p2/p(density)g  +  v2^2/2g  +  z2  +  hf]\n\nnote: p(density) is rho and y(specific weight) ir gamma.
632058
C\nTotal discharge of a (river) system is determined by its  total volume dividd by a time constant.  Just as a car has a speed (miles per hour), the discharge of a river has a volume per second (or day, or year, etc.), which measured in scientific units is cubic meters per second (m^3*s^-1). Thus, C is the closest answer, although it omits the needed time interval to describe a total flow.
810751
The speed of sound in water (including seawater) depends on several factors, but most important is the the temperature of the water.  By measuring the time it takes for an acoustic signal to travel from a source to a receiver, one can determine the average temperature along the path followed by that sound signal. (Other factors that include sound velocity or travel time include salinity, pressure (i.e. pressure-induced changes in density), and ocean currents.)  By measuring the average temperature along many different paths, one can reconstruct a 3-dimensional "map" of the temperature distribution in the oceans.  \n\nBy following the changes in temperature over time, one can detect long-term changes in the temperature distribution and hence average temperatures of the oceans.
1101763
Well....moving water has a different refractive index to still water. So if you can monitor the intensity of color using the color of the light from still water you will see a change in the color when the water is moving. It is then possible to see that movement in the water is taking place. \nThe speed of movement maybe be also indexed as a change in refractive index. \nSo, it would be possible to run some controlled experiments and determine convection of water in some form of useful units.
982941
Fluid Pressure= weight density x (times) depth\n\nFl. p.= 10,000 kg/m^3(thats the weight density of water) x 15 m\n\nFl. p.= 150,000 m^2 (because one m cancels)\nHope this helps!
859177
Volumetric flow = velocity x cross-section area = 43cm/s x 2.0 cm2 = 86 cm3/s\n\nMass flow = Vol flow x density = 86 cm3/s x 1.0 g/cm3 = 86 g/s\n\nCapillary Velocity = Vol Flow / capillary cross-section = 86 cm3/s   /  3.1x10^3 cm2 = 0.028 cm/s
694233
Is it really so? On my opinion the only explanation of this phenomenon is Gulf-stream, that flows to the Northern semi-globe and brings much warmth from equatorial zone, while nothing like this exists in Southern semi-globe.
82511
hydrological AND hydrodynamical engineering
708432
Poiseuille's Law: dV/dt = (πR^4/8η)(∆P/L)\n\nWe're given\n\ndV = 490 cm^3 or 0.00049 m^3\ndt = 35 min or 2100 sec\nL = 2.5 cm or 0.025 m\n\nη - viscosity of water is 8.90 × 10-4 Pa•s or 8.90 × 10-3 dyne-sec/cm2at about 25°C.\n\nWe also have ∆p = ρg∆h\n\nρ is the density of pure water (1000 kg/m^3)\ng is the acceleration due to gravity (9.81 m/s^2)\n∆h is the height of the fluid column (we are given 0.8 m)\n\nHence, ∆p = (1000)(9.81)(0.8) = 7848 N/m^2\n\nNow we solve for D, the diameter of the needle, which is = 2R\n\nD = 2R = 2[(8ηLdV)/(π∆Pdt)]^-4\n\n= 2 [(8(8.90×10^-4)(0.025)(0.00049)) / ((3.147)(7848)(2100))]^(1/4)\n\n= 2(2.025 x 10^-4) = 4.05 x 10^-4 m or 0.405 mm
941617
The Specific Gravity of water is 1