How to calculate short circuit rating of an extra high voltage cable?
367766
EHV insulation is based mainly on switching surge voltage.\nas the short circuit rating is calculated by using per unit impedance/reactance.reciprocal of the p.u value gives you short circuit rating.
177692
No matter what is the voltage rating, isolation or insulation is tested by using "MEGGER".\nThe value should be atleast above 1 Mega ohm in any case
279992
Copper's resistance increases by a factor of 0.0068 per degree C (ref.). This resistance increase is linear, not exponential. The formula is Resistance = R(initial) * [1 + alpha * (T(final) - T(initial)], where alpha is the temperature coefficient. Also note that self-heating due to any current flow will add to the ambient temperature effect, so power dissipation in a cable will be higher than what is calculated from resistance based on ambient temperature alone.
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The determining factor which makes a UPS (Uninterruptible Power Supply) suitable for a laser printer is the UPS Ratings.  Remember to protect your computer too because your laser printer will be rendered inneffective if you're computer is not working or has no power.\n\nCheck the packaging and see how the ratings are for the following:\n\n1. UL Rating: This is the Underwriters Laboratory test rating of approval for the device. The common rating for surge protectors is UL 1440 or higher. If the device you are looking at does not meet this specification, look for another device.\n \n2. Response Time: This is the time it takes for the device to react to a surge or power outage. Ten nanoseconds or less is the recommended time.\n\n3. Clamping Voltage: This is the point of protection where the device starts to function and senses when something is happening within the electrical circuits. The lower the voltage the better, usually 400 or less.\n \nThree way protection and extra jacks: This should be a given with today’s technology. For the surge protector to work, a 3-wire AC power connection must be used. "Cheater" adapters, which allow 3-wire appliances to be used with 2-wire outlets or extension cords, defeat the electrical ground connection and render most surge suppressors ineffective.\n\nRemember, being prepared for the disaster sometimes helps later on in the recovery. Do not forget to consistently backup your system. Have current data and files stored where you can recover them in case of a system failure. Always use a UPS to protect your computer not just your laser printer.
1091879
You DONT test continuity on HOT wires. The power must be off before making a continuity measurement. any meter will do then.
455603
If it's for a simple hobbyist application they need to know only the resistance value and its power rating.\n\nA full specification would also include:\n\ntolerance,  thermal coefficient,  maximum voltage.
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If the connector itself is shorting you might need to tape w/ electrical tape, but that maynot even work.\n\nSee if you can buy a replacement.\n\nUnless you mean it's the socket you plug the adapter into, then you're stuck. Unless it's still under warrentiy, then you should send it back for repairs
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The Thevinin equivalent of a DC circuit is merely a voltage source in series with a resistor.  The value of the voltage source is the open-circuit voltage and the value of the resistor is this voltage divided by the short-circuit current.  If you have the circuit diagram, you can calculate these values, or you can measure them.  Without more information there isn't more I can give you.
326286
Positive cable  = + = red cable. look for a plus + sine on the battery.
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You need to post some details - then I can post an answer...\n\nIn general, P = V*I = V^2/Z\nso calculate the complex impedance Z (= R+jX)\nthen take the real component of the complex power.
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Here is an interesting site about cables: http://web.anixter.com/Anixter/anixter.nsf/WCTechnicalHandbook/CableTypesandSelectionCriteria
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Kilowatts  Equations\nDirect Current  =        I x E/1000\nAC / 1phase 115v or 120v =I x E x PF/1000\nAC / 1phase 208,230, or 240v= I x E x PF/1000\nAC 3 phase All Voltages     =    I x E x 1.73/1000\n\nE = Voltage \nI = Amps \nPF = Power Factor
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Here's a link to the standard American Wire Guage table.  It has it all listed:\nhttp://www.eng.auburn.edu/~tdenney/ENGR1110/wireawg.html
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Use ACDSee Classic.\n\nhttp://www.download.com/3000-2192-1808446.html
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There are the two problems:\n1. Mechanical. The cable must be out of the way to prevent any mechanical damage or injury or even DEATH. \n2. Electrical. 1500 watts (~13.Amps at 120 Volts or 6.5A at 240 v could be better choice since a 6.5 A lesser wire gage can be used) will require at least a 10 gage (stranded) (or 14 gage for 6.5A) cable if you are running an inductive load (like motors). Resistive is more forgiving.\nThere is an easy way to estimate your circuit loading by placing a say 60w incandescent light bulb in series with you load at the end of your 500’ circuit and turning the load on. If the light dims and a lot you are in a little trouble. Do not test if your cable is coiled since as you realize you are adding inductance to the circuit.\n\nThis is an estimate. Consult electrical tables, licensed electrician  or equipment manufacturer for proper information.\n\nI hope it was useful.
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You need to use Ohm's law.\n  E=I x R  \n  E=Voltage. I=Current/Amps  R=Resistance/Ohms\n  E= 9voltsDC\n  I= 3amperes.\n  R= ?\n  So:\n  R = 9volt/3amp\n  R=  3ohms
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Assuming that we have 2 series resistors R1 and R2. And the voltage applied on them is V.\n\nTo get voltage applied on R1 (V1)= V * R1/(R1+R2)\nand so V2= V * R2/(R1+R2)