How, without taking pencil off the paper, draw 3x4 points by drawing five straight lines,  end up at startpoin
359013
i dont know     i just dont know
977003
Draw a straight line .now plot three points S,T and R on it ,taking ST=3.8 cm and TR=1.4 cm.\nWrite the distances 38 in betweenS and T and 14 between Tand R.your sketch is complete.\nNow ,rite the followin unde the sketch:-\nSR=ST+TR=38+14=52.
30239
You can't just draw one? It's 10 boxes across the top and down the side, starting with 0 and going to 9 (and no, the corner doesn't share both sides). All you need are a pen and a ruler.
941144
haha I've always wondered this too. There is no way as far as I know. I just type 'divided by' or put a space so I can draw it after I've printed it.
681515
1)you can try drawing the lines using a flexible ruler (i am not too sure about the name),\n2)you can try plotting more points before drawing the line,\n3)you can practice drawing the line in one go without hesitating or stopping. (visualize the whole line you want to draw before you start then go for it- do it fast) - this may help to steady your hand.\n\nbut most of all practice makes perfect unless you can use the computer to plot the graph for you.
295856
You have to draw the lines and mark the points.\nIf Cp has a 90 degree angle with the line you just draw and crosses it right in the middle, then you have graphic proof that it is the perpendicular (which means it has a 90 degree angle) bisector (which means that it splits another line in two halfs).
1171108
The farmer planted his trees in a star pattern.\n\nIf you draw a star, place a tree at the 5 points of the star and at each place where the lines cross.
497181
You only need two points to determine a line.\nYou should use three just to make sure you don't make a mistake.\nPick two values of x and find the corresponding values for y.\nThis one is pretty simple.\nLet x = 0, then y = 0 (since y = x)\nLet x = 1, then y = 1\nLet x = -3, then y = -3.\nPlot these points on the graph and connect them with a straight line.
817425
(a) By drawing the points on a graph sheet, Midpoint is determined as (11,16)\n\n(b) Again by drawing on a graph sheet, by using Hypotenuse theorem; \nRadius = Longest side of right angled triangle \n            = square root of (4^2+5^2) \n            = square root of (16+25) \n            = square root of (41) \n            = 41^0.5 \n            = 6.4
96194
Yes you are on the right track...Sort of.  \n\nSay you plug in any number for x.  We'll use 5\n\n-3(5)+y=-15\n-15+y=-15\n\nNow add 15 from the left to cancel the negative 15.  Then add 15 to the right to make the equation:\n\ny=0\n\nSo if x=5 and y=0 then your points will be (5,0)\n\nSay you have your original equation again\n-3x+y=-15\n\nNow plugin for x any number.  We'll use 1.\n\n-3(1)+y=-15\n-3+y=-15\n\nNow add 3 to the left to cancel out the negative 3 and add 3 to the right to make:\n\ny=-12\n\nSo x=1 and y=-12   (1,-12)\n\nHope that helps
451332
The same way I use a pen.
1112375
Create a new blank image.\nClick on the Draw icon.\nNow click on the Tools Palette and set up the line as required.\nThe colour of the line will be the Foreground solid colour.\n\nClick and hold the mouse to start drawing your line.  Drag to where you want the line to end.\nYou will be able to adjust this once it is done.\nThe Layer Palette is good for selecting the line.\n\nOnce you are happy with the one line just copy and paste as new layer to repeat.  Then just drag into position.
1027994
if you are asking .. how to sketch an eclipse ... take two verticies (two spots some distance apart left to right on a page) ... and using a compass play with intersecting the radius' of different lengths ... you will find that if you pick the one of equal length as the distance from the vertices ... you will get an intersection of the two radius' from the original vertices ... then playing with the new found radius' ... you will be able to place arcs on the ajoining vertices to creat the other two arcs and blend them together creating an approximate elipse ... a french curve help too
248595
I was going to say graph paper to. Then you can keep a straight line. Very simple solution. If your talking about bigger graphs then it would be a good idea to sketch the drawings at the job and bring them back to a drawing table if thats what your looking to do.
232213
I'll do the fourth problem.\n\n-3x< -6  or x+5< -2\n\nfirst deal with one half- \n-3x< -6 (now divide by -3)\nx>2 (when you divide by a negative the sign is reversed)\n\nthen the second half- \nx+5<-2 (get x alone, so subtract five from each side)\nx< -7\n\nso you have:\n2 < x  or  x < -7\n\nto graph this there is a line with an arrow to the left of the first slash and another line to the right of the second slash\n\n<-----/-------0--/-->\n____-7______2
504740
After several attempts, it seems that it is rather impossible.  If you start in the bottom corner, you can get all but 3 squares rather easily.  If you're careful, you can have 1 remaining if you start diagonal to the corner.\n\nWhat are you trying to do this for?  Is it a website?  I'd love to try it again.
856650
This isn't the answer, but it might spark something in your mind for an answer.  If you needed to make 5 lines, with 5 trees, using a total of 19 trees, you could make a square with a diaganal line running through it.  I'll keep trying to think of another way.  May we inquire where the question came from?\n\n.1...2...3....4...5\n.6..............7...8\n.9........10......11\n12..13...........14\n15..16.17.18.19