evaluate (15-5) divided [ (12 divided by 2 *2) -2] now i really don't have a clue.....?
147408
(15-5) divided [ (12 divided by 2 *2) -2]\n\n= (15-5)/[12/(2*2) - 2]\n= 10/[12/(2*2) - 2]\n= 10/[12/4 - 2]\n= 10/[3 - 2]\n= 10/1\n= 10
60538
if [ -7x + x^2 =0 ]\nthe you will get y = 7/x
321475
*(2x/(x^2-4)) + (5/2-x) - (1/2+x)\n*(2x/(x^2-4)) + (5/2-x)((2+x)/(2+x)) - (1/2+x)((2-x)/(2-x))\n*(2x/(x^2-4)) + (10+5x)/(4-x^2) - (2-x)/(4-x^2)\n*(2x/(x^2-4)) + (8+6x)/(4-x^2)\n\nyou should be able to get it from there
705901
Here is how you do it:\n(2,1) and (3,4) = [(2)(3) + (1)(4)]/(2)(1) - (3)(4)\n                        = (6 + 4)/(2-12)\n                        = 10/-10\n                        = -1\n\nTada
590233
Hint:\nDo a simple substitution u = x-5\nWhich means x = u + 5\n\nYou should get\n\n(2/5)(x-5)^(5/2) + 2(x-5)^(3/2) + C
1150392
No problem, i just finished a calc3 course in college.\n\nYour problem is the same as 125 * (6x^2 + 5x + 7)^(-1/3)\nYou have to use the chain rule so you get\n125 * (-1/3) * (12x + 5) * (6x^2 +5x + 7)^(-4/3)\n\nthen you can simplify how you like from there
895708
Order of operations: Parentheses Exponent Multiplication Division Addition Subtraction.\n\n2 - 2[4-9] ÷ (-5)\n2 - 2[-5] ÷ (-5)\n2 - [-10] ÷ (-5)  ~~ same as 2 + 10 ÷ (-5)\n2 + [-2]  ~~ same as 2 -2\n= 0\n\nI'd double check that if I were you; it's a bit early for me. :*)
766449
(-x/4+ 5/6) * 12 < (4x/3 +2) * 12 (mulitply both sides by 12)\n\n-3x +10 < 16x + 24\n\n-3x-16x +10-10 < 16x-16x + 24-10 (move all variables and numbers to one side)\n\n-19x< 14 (divide both sides by 19)\n\nx < -14/19\n\n* means times\n\n(-n/5 + 6) * 5 > n *5 (multiply both sides by 5)\n\n-n + 30 > 5n\n\n-n + n +30 > 5n +n (move all varialbes to one side)\n\n30 > 6n (divide both sides by 6)\n\n5>n
302848
Probably easier to show by example.\n4x2+8-:-4-1 (-:- = divide)\nmultiply any numbers first, then divide, then add and subtract.\n\nYou could add brackets in if that helps you.\n(4x2)+(8-:-4)-1 = 9
672142
it's\n[x(x+2)]/[x*x] -2/3x=\n\n[x+2]/x - 2/3x=\n\n[3[x+2]-2]/3x=\n\n[3x+4]/3x=\n\nx + [4/3]x
771836
Simple substitution.\n\n5(3) - 2(2) + 4(4)\n15 - 4 + 16\n27
8373
(([(4+4+4).(4+4)]+4)/4)*(4+4)\n\n(4+(4*4)).([(4+4+4).(4+4)]+4)
710907
too many ways to interpret this.  Restate using parentheses.\n\nI'm going to guess that the equation is\n2/(x - 2) + 15/(x^2 - 7x + 10) = 3/(x^2 - x - 12)\n2/(x - 2) + 15/(x - 2)(x - 5) = 3/(x - 4)(x + 3)\n(2(x-5) + 15)/(x - 2)(x - 5) = 3/(x - 4)(x + 3)\n(2x + 5)/(x - 2)(x - 5) = 3/(x - 4)(x + 3)\n(2x + 5)(x - 4)(x + 3) = 3(x - 2)(x - 5)\n(2x + 5)(x^2 - x - 12) = 3x^2 -21x + 30\n2x^3 - 2x^2 - 24x + 5x^2 - 5x - 60 = 3x^2 -21x + 30\n2x^3 + 3x^2 - 29x - 60 = 3x^2 -21x + 30\n2x^3 - 8x - 30 = 0\nx^3 - 4x - 15 = 0\n(x - 3)(x^2 + 3x + 5) = 0\nx = (-3 ± sqrt(9 -20))/2\nx = (3, (- 3 + j11)/2, (- 3 - j11)/2)\n\n....... x^2 + 3x  + 5\nx - 3)x^3......... - 4x - 15\n....... x^3 - 3x^2\n............ + 3x^2 - 4x\n............ + 3x^2 - 9x\n..... ..... ..... ..... . 5x - 15\n..... ..... ..... ..... . 5x - 15
1043865
I'm not sure why you have spaces between the number and the variables.\n2 = 2x + 1x + 2x + 10\n2 = 5x + 10\n-8 = 5x\nx = -8/5
54462
(3x+5)/wz \n(3*4+5)/(-1*5)\n(15+5) / (-1*5) \n20/-5 = -4
560506
that works... so does this:\n\n-2 x -1 x 1 x 2 x 3 = 12\n\n-2*-1=2\n2*1=2\n2*2=4\n4*3=12
96233
+5,+12, -5, -12, +3.3