need help solving this: x-4 divided by 2x+4 all greater than or equal to 0?
146214
D.    X (greater or equal to) 4\n      2(-2)+4 = 0\nso (-infin, -2) U [4, infin)
1034880
That's a stupid question.  x can equal anything equal to or greater than 7 and still be correct.  Unless you asked the question wrong.  \ni.e. If x=9 then the problems answer would be: 24.  24 is greater than 20.  So it fits within the variables you have listed: "greater than or =20"  \nBut if x=6 then the product would be 18, less than 20 and outside the variables you have listed.  \nSo the answer, according to your variables, is x=7 or anything greater.
17048
= x^2 - 7x + 4x -28\n= x^2 - 3x - 28
811666
cross multiplying\n(x-4)(x+4)<x(x-5)\nx^2-16<x^2-5x\nadding 5x-x^2\n5x-16<0\nadding 16\n5x<16\ndividing by 5\nx<16/5\nx<3 1/5
834770
3x^2-x-4=0\n=> 3x^2-4x+3x-4=0\n=> x(3x-4)+1(3x-4)=0\n=>(3x-4)(x+1)=0\nTherefore,either 3x-4=0 or x+1=0\nIf 3x-4=0,then x=4/3,and \nif x+1=0,then x=-1\nTherefore, x=4/3 or -1 ans
712395
9x+5/(x-4)+(-7x)/(x-4)\n=9x+5-7x/(x-4)\n=(2x+5)/(x-4)
726744
x/ -4 + 5 = 1\nsubtract 5 from both sides\nx/ -4 = -4\nthen multiply both sides by -4\nx = 16
751318
x^2-x-6>0\nor, x^2-3x+2x-6>0\nor, x(x-3)+2(x-3)>0\nor, (x-3)(x+2)>0\nor x>3 and x<2\n\nhope this helps :)
156773
when x=3\na) 9\nb) 38\nc) 23\nd) 9\ne) 4 and 2/3\n\nwhen x=2\na) 7\nb) 30\nc) 17\nd) 7\ne) 6\n\nwhen x=1\na) 5\nb) 22\nc) 11\nd) 5\ne) 10\n\nwhen x=0\n\na) 3\nb) 14\nc) 5\nd) 3\ne) ERROR, can not divide by zero
961595
umm..are you missing an equals sign somewhere or am i really dumb? how do you figure out what x is unless you have both sides of the equation?
795059
You came up with x > -1 OR x < 7.  The "or" is key.  It can be less than 7, or  greater than -1.  There's no real number that doesn't fit the solution.\n\nFor the second one, you came up with x >= 0.8 AND x >= 2.  Similarly, the "and" is the key here.  Anything greater than or equal to 2 is going to be greater than 0.8, fulfilling both conditions.  The same cannot be said if the numbers are reversed.\n\nTo sum it up, if the problem has an "or" condition, every solution must solve at least one inequality.  If the condition is "and", every solution must solve ALL inequalities.
919399
6(x+4)-2x=-8\n6x+24-2x=-8\n6x-2x+24+8=0\n4x+32=0\n4x=-32\nx=-32/4\nx=-8
101082
(x-1)/4 > 3\nx-1 > 12\nx > 13
852286
if it x - 4x/(x+1) = 4/(x+1)\nthen x(x+1) - 4x = 4\nor x^2-3x + 4 = 0\n\nthis is quadratic and so 2 solutions so Megan is right\n\nyou do not have tro evaluate
803653
2x>-10\ndividing by 2\nx>-10/2\n=x>-5
894400
I'm not sure what you mean by ***, so I'll answer the second part of your question.\n\n-4x/-4x + 12/-4x = 1 - 3/x
914435
x > 5\n\n- - - - - -s-