is there any  analytical answer for this serie?
149972
Bessell(1,2)/Bessell(0,2) = 0+1/(1+1/(2+1/(3+...
316975
there is no concrete answer
160587
In each triple, the difference between the 2nd and 3rd terms is > 0 so \n\n1 + 1/2 - 1/3 + 1/4 + 1/5 -1/6 + 1/7 > 1 + 1/4 + 1/7 + 1/10 + ...\n\nThe nth term of the series on the right is 1/(3n+1) > 1/(3n+3n) = (1/6) x (1/n)  which is going to diverge.
144611
You might find this paper useful\nhttp://arxiv.org/abs/math-ph/0106027
688944
View source of the that page.\nYou will see the formulas.
435388
damnt i should have paid attention calculus...\n\nlet pam...pam...breat....dimension......carry the one.....as x approaches zero......carry  the two....hold on...\n\nthis could take a while.
1045615
click on the below link, and choose any one of the results. I would advise reading at least 3 of them to get a feel for theory before choosing one of the walkthroughs.\n\nBest of luck to you!
620893
The best way to work this out would be to plot a speed time graph for the information.\n\nOr you could express it as a simultaneous equation.
477263
There are several cases where it can be solved.  There are a few solutions to cases of the circularly restricted 3-body problem, and situations where one of the bodies is of "zero" mass can be solved, but there is no general analytic solution to this problem.
875583
Also, If 0<a<1, this series converges because eventually each term becomes zero.  So its sum would not be infinity.  Right?
815668
You have not provided adequate information about the quation to find an answer.\n\n\nBTW, it's "Ramanujan"
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
313965
This approaches infinity as n approaches infinity.  To demonstrate, I'll show you something even smaller that sums to infinity.\n\n1 + 1/2 + 1/4 + 1/4 + 1/8 [4 times] + 1/16 [8 times]...\n\nThis is equal to 1 + 1/2 + 1/2 + 1/2 + 1/2.....which "goes to infinity.  \n\nSince each term my this series is equal to or smaller then your series (1/4 + 1/4 < 1/3 + 1/4, and 1/8 + 1/8 + 1/8 + 1/8 < 1/5 + 1/6 + 1/7 + 1/8, and so on), and my series approches infinity, your series must approach infinity, too!
635766
Even the answer is not clear!
492690
S(I)+3f (g)--> SF (g)\n..........2...........6
50930
I know it.\nIts one more than the Infinity.\nIf you know the value of infinity then substitute it and you'll get the answer.
310352
Spoiler warning!\n\nSolution is given in the source links below.