define minimum circuit ampacity?
142477
Ampacity: Refers to the how much current a wire can safely carry. For example, a 12 gauge electrical copper wire can safely carry up to 20 amps.\n\nminimum ampacity is not really something that makes sense unless you are talking about the lowest safe maximum and calling that minimum. This might arise from various ways to calculate the safe maximum and then having to use the lowest one. \n\nThe definition above on the link in the sources is not always true for example. If a 12 gauge wire is used in a conduit with a bunch of others and the fill ratio (how much air versus how much wire) of that conduit is greater than the maximum allowed then the current limits on the wires are reduced based upon the amount the conduit is overfilled. Wires in high temperature environments can be a reason to derate them as well.
504604
Time constants in electronic circuits.
820591
Add the loads in amperes of each of the appliances on that circuit.  Make sure that the total is less than the ampere rating of the circuit breaker.  You should probably only use about 3/4 of the amperes the circuit breaker is rated for.  For example, a 20 Amp breaker should only be loaded with about 15 Amps.\n\nIf only the wattage of an appliance is given, divide the wattage by the voltage to obtain the amperes.  For example, a toaster may draw 1200 watts.  1200 watts / 120 V = 10 Amps.  A light bulb may draw 60 watts.  60 watts / 120 V = .5 Amps.
210547
power=voltage^2/resistance\nhigher power means lower resistance.
228080
Assuming a DC circuit: use Ohm's law, I=E/R and P=I*E or I=150 Volts /11 Ohms = 13.64 Amps and Watts = 13.64 Amps * 150 Volts * 24 hours or 49,090.9 Watthours or 49.091 kWh.
209317
The straight calculation is this:\nVolts X Amps = Watts(power)\n\n4.5 watts would be the answer.
739568
Three  terms you need to know are:\n\nVoltage- This is the "potential" to make current flow through \n                a wire.  (measured in volts)\nCurrent- This is the actual electrons or "electricity"  which \n               "flows" through the wire. (measured in amperes or amps)\nResistance- This is the quality of a substance which tends to \n                      allow or inhibit the flow of electricity.\n\nOne more term is power. This is measured in Watts and is \n given as 1 Watt=(1 volt)(1 amp)\n\nHere's how it works.  You put a voltage across a wire.\nYou decide the voltage.  It does not change.  The wire and bulb has "resistance" and only lets a certain amount or current flow.  The current flows through the bulb and lights the bulb.\n So both 100 watt bulbs and 40 watt bulbs have the same \n120v "voltage".  The difference  is that less current flows through the 40 watt bulb, so it is dimmer.\nRemember that power or "Watts" is current  times voltage.\nso lower wattage means lower current.\nThe question should be how much current does each bulb use.\nThe answer is: 100 watt-5/6 amp\n60 watt- 1/2 amp\n40 watt- 1/3 amp
879314
The amp is found by subtracting the maximum of the wave by the minimum of the wave, and dividing that number by 2.
502126
is it not that obviouse? WIRE LESS.
1086143
It's a law of electrical flow along a circuit.
130012
There are a few things one should consider when engineering a busbar solution.  A general rule of thumb for sizing copper busbar used for 60 Hz applications is 1000 Amperes per square inch.  For example, 1/4" x 2" = 500 Amperes continuous.  If you'll be bolting busbars together, the general "overlap ampacity" rule of thumb is 200 Amperes per square inch of overlap.  These are the two basic rules for sizing copper busbar in most applications.  \n\nMore information is necessary to answer the question, such as frequency, maximum rated transformer current, desired heat rise, material type (copper / aluminum).  There are other things to consider besides conductor size such as, bracing the busbars to achieve the desired interrupting rating, insulating the busbar to achieve the proper BIL level, etc.\n\nBusbar engineering isn’t quite as simple as it looks and if done wrong, it could lead to severe injury or death.  This information is very general in nature, and consequently, is not applicable to every situation.  If you’ve never done this before, you should hire an experienced and qualified bus fabricator.  This information is very general in nature, and consequently, is not applicable to every situation.
960408
http://www.eas.asu.edu/~holbert/ece201/kvl.html
688307
Well, 36 Watts tube means they can handle a maximum of 36 watts. If the circuit provides 40 Watts, it will most likely fry. However, just because it says 40W doesn't necessary mean the circuit will be shelling out 40W, but I'd say go and get a 40W tube just to be safe.
816414
Always the current. The voltage can be whatever.
1114398
d: Subjected to a small voltage.
485922
the minimum amount of energy required to start a reaction
238179
Resistance=Voltage/Amperes