whatisthe answerfor b^2+5b-24?
142846
You get 2 factors that are (b plus or minus something) times (b plus or minus something). If the “sign” before the number at the end of the equation is negative, then you have one of the factors as (b plus something) times (b minus something). The two “somethings” multiplied equal 24. They could be 1x24, 2x12, 3x8, or 4x6. The “5b” in the middle shows you this: one of the missing numbers is 5 greater than the other. 3x8 works here. Since the sign of the “5b” in the middle is positive, the larger missing number is positive. Your answer is:\n(b+8)(b-3)\n\nCheck: first: b*b=b^2. b*8=8b. b*-3=-3b. 8*-3=-24.\nAdd these up and you get b^2 +8b –3b –24.\nb^2 +5b –24
924187
= 16ab/20ab^2\n= 4/5b // 16 and 20 can be reduced by 4, and an a and a b cancels out\n\n3*3*3*3*3 = 3^5\n3*3 = 3^2\n3^5/3^2 = 3^3\n= 3*3*3
732400
25u + 74 = 23 u + 92\nlet's move all the numbers without variables to the right side.\nSubtract 74 from both sides.\n25u +74 -74 = 23 u +92 -74\nremember that whatever you do to one side of the eqn you have to do to the other.\n25u = 23 u + 18\nnow let's move the u's to the same side.\nsubtract 23u from both sides.\n25u - 23u = 23u -23u +18\n2u = 18\ndivide both sides by 2\nu=9
502865
x^2-2x=24\n=> x^2-2x-24=0\n=> (x-6)*(x+4)=0\n=> x=6 and x=-4
774953
It's quite complicated.  The link given goes into detail about an inductive method of obtaining this.  If you just want the answer it is -\n\n(n^4 - 6n^3 + 23n^2 -18n + 24) / 24
966048
(3ab^2)(3ab)^2\n(3ab^2)(9a^2b^2)\n27a^3b^4
661698
2b^4(4-3b)=0\n\nb=0\nb= (4/3)
862819
5(2+b) - (a+3b)\n= 10+ 5b - a - 3b\n= 10 +2b -a
747439
(5)(5)-2(5)(-4)+(-4)(-4)\n=25-(-40)+(16)\n=25+40+16\n=81\n\nDon't forget that (-)(-)=(+) and (-)(+)=(-).\n\nGood luck!
528350
(5x + 4)(6x + 4)\n30x^2 + 20x + 24x + 16\n30x^2 + 44x + 16\nANS : 16
922859
sqrt(5a^2 b^5 / 7b)\nFirst cancel the b on bottom with one of the b's on top\n= sqrt(5a^2 b^4 / 7)\nRecall the property that sqrt(x/y) = sqrt(x) / sqrt(y)\nSo sqrt(5a^2 b^4 / 7)\n= sqrt(5a^2 b^4) / sqrt(7)\nMultiply the top and bottom by sqrt(7)\n= sqrt(35a^2 b^4) / 7\nThe square root of a^2 is a, and the square root of b^4 is b^2 (You just divide the exponents by 2).\nAnswer: ab^2 sqrt(35) / 7
919864
1.  ax + xb\n2.  21x^3 + 24x*2y\n3.  24x^2 + 31x + 10\n4.  24x^2 - 8x - 6\n5.  40x^3 + 66x^2 + 38x + 6\n6.  x^2 - 1\n7.  x^3 - 8
1031270
x^2 + 5 + 5x + x y +5y\n\nx^2 + xy + 5x + 5y + 5\n\nx(x+y) + 5(x+y) + 5\n\nx(x+y) + 5(x+y+1)       OR     (x+5)(x+y)+5\n\nCynthia
865942
b = 70sin55\n\nb = 57.34
19885
(5) x (2x^2-3x+5) I think
437556
[Xe] 4f^14  5d^4 6s^2
184147
5t(t^2+t-1)(t^3-t^2+2t+2)\nIts a long answer but it's CORRECT.