Find the perfect square trinomial whose first two terms are x² – 3/5x?
148612
(A-B)^2=A^2-2AB+B^2\nThen\n(3/5)x= 2*x*N\nThen N=3/10\n\n(x-3/10)^2\nx^2-3/5x+9/100
513219
Perfect Squares\n\nEdit: First Four to be precise
723313
Yes\n\n(1-2)^2 = (3-2)^2\n\n3 is not equal to one\n\na and c do not have to be equal since the terms are squared. On removing the squares, you have to account for both +ve and -ve roots.
751318
x^2-x-6>0\nor, x^2-3x+2x-6>0\nor, x(x-3)+2(x-3)>0\nor, (x-3)(x+2)>0\nor x>3 and x<2\n\nhope this helps :)
733063
5x^2-35x+3x-21\n5x^2-32x-21
1047777
first x outside x inside x last\n(2x*5x) + (2x * -2) + (-5 * 5x) + (-5 * -2)=\n10x^2 + -4x + -25x + 10=\n10x^2 - 29x + 10
36762
Factor by grouping:\nx^2 (3x - 5) - 3 (3x - 5)\nAnswer: (3x - 5)(x^2 - 3)
863644
take out 4x first\n4x(x2-6x+8)\n4x(x-4)(x-2)
502428
#1. (x-5)(x+1)\n#2. (x-3)(x+2)
927818
2(x - 3) = 2\n\n2(x - 3) / 2 = 8 / 2\n\n(x - 3)² = 4\n\n√(x - 3)² = √4\n\nx - 3 = ± 2\n\nx - 3 + 3 = 3 ± 2\n\nx = 3 ± 2\n\n- - - - - - - - - \n\nSolving for ( + ) \n\nx = 3 + 2 \n\nX = 5\n\n- - - - - - - - - \n\nSolving for ( - )\n\nx = 3 - 2 \n\nx = 1\n\n- - - - - - - - -s-
533127
2*2*2*5*5 or 2to the third power times 5 to the second power
545883
(a^2  - 5) * (a^2  - 2)
712412
the first one is\ny= -3/2+3
832845
you need to add +1\nso that the equation can be represented as a perfect square\nx^2 - 2x + 1 = (x - 1) (x - 1) = (x - 1)^2\n\nthis is called solving by perfecting the square\nto do this, make sure that the coefficient of the first term is 1.\nThen, divide the coefficient of the middle term by 2,\nthen square the whole thing.\n\nIn this case, the coefficient of the middle term is -2\n-2 / 2 = -1\n(-1)^2 = +1
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
342762
x2+5x-2x-10\n\n*answer*\n\nx2+3x-10
845986
I dont know what you mean by the first half, but (x+2)(x+1) is simple.\n\n\nUse the FOIL method.\n\nFront\nOutside\nInside\nLast\n\nso\n\nFront\nX*X=X^2\n\nOutside\nX*1=X\n\nInside\n2*X=2X\n\nLast\n2*1=2\n\nSum them up\nX^2 + X + 2X + 2\n\nSimplify\nX^2 + 3X + 2