how do you solve  six subtract twox when x   2?
156720
Well, let's see. First you start by multiplying the coefficient by the arc. Then you determine the ratio of the remainder to the cosine. When that has been calculated you LEARN BASIC ALGEBRA AND QUIT ASKING THIS FORUM FOR THE ANSWERS TO YOUR HOMEWORK!!!!
1060834
(5x+2)/3 -(2x+4)/6 = -4/3\n\nMultiply everything by 6:\n\n10x + 4 - (2x+4) = -8\n10x + 4 - 2x - 4 = -8\n8x = -8\nx = -1
734008
that means you multiply by the 2 first,  2 x X and 2 x 7\nso then you have  2x + 14= - 26      move your 14 to the other side by adding its opposite to both sides\n2x + 14 = - 26\n2x +14   +  - 14  = -26   +    -14\n\n2x =  -40\nthen divide both sides by 2\n2x/2    = -40/2\nx= -20
769323
6 - 12x\n-or-\n-12x + 6\n\n-or-\n\n6(1-2x)\n\n...although that depends on whether you want the simplest expanded form or the simplest factored form.
705997
2x+1\n------- =\nx\n\n(2x+1)(x - 2)(4x + 3)\n-------------------------- =\nx(x - 2)(4x + 3)\n\n8x³ - 6x² - 17x - 6\n-------------------------- =\n4x³ - 5x² - 6x\n\n8x³ - 10x² - 12x + 4x² - 5x - 6\n------------------- ----------------- =\n4x³ - 5x² - 6x\n\n...... 4x² - 5x - 6\n2 + ----------------\n..... 4x³ - 5x² - 6x
892797
okay so you start with:\n15-2n=6-n  ---> you subtract 6 from both sides\n-6       -6 \n-------------\n9-2n=-n ----> you then add 2n to each side\n +2n +2n\n-------------\n9=n
803653
2x>-10\ndividing by 2\nx>-10/2\n=x>-5
940135
Use factoring.\nx2-2x-8=0\n(x-4)(x+2)=0\nso\nx-4=0 and x+2=0\nsolve\nx=4 and x=-2
1138309
I hope you are trying to say x+2 = (2/3)(2x-1)..if it is correct then\n\n3(x+2) = 2(2x-1) --> 3x+6 = 4x - 2 --> 6+2 = 4x-3x --> 8 = x
743161
cross multiply\na/-6 = -3/2\n18 = 2a\na = 9
61956
try to follow\n\nx/2-10=a\na/2-4=b\nb/2-2=6\n\nsolve and substitue\nb=16\na=40\nx=100 --the original amount\n\nhope that helped
808787
2(x+4)-6=-6(x+4)-10\nadding 6\n2(x+4)=-6(x+4)-4\ndividing by 2\n(x+4)=-3(x+4)-2\nx+4=-3x-12-2\nx+4=-3x-14\nadding -4\nx=-3x-18\nadding 3x\n4x=-18\ndividing by 4\nx=-9/2
1019688
(x - 2)*3 = 6 + x\n\n3x - 6 = 6 + x\n\n2x = 12\n\nx = 6
794701
The first thing you have to do is group together like terms, and remember that since this is an equation, what you do to one side you have to do to the other side.  I'll show you this in steps.\n\n4x + 2x = 9x - 6  Group together like-terms on the left hand side to get\n6x = 9x - 6    Subtract 9x from both sides to get\n\n6x - 9x = -6   (at this point, note that the 9x on the right hand side disappeared.  This should happen, since subtract 9x would make 9x on the right hand side equal to zero).\n\nNow, group together like terms on the left hand side, to get\n-3x = -6\nSince our goal is to isolate x, we divide both sides by -3\n\n-3x/-3 = -6/-3\nx = 2
1133153
7 - 2[4-6+2x] - 8+ x=6\n\n7 - 2[-2+2x] - 8 +x =6\n7 + 4 - 4x - 8 + x =6\n3 - 3x = 6\nx = -1\n\nDon't listen to the math goober - plug the value in and check it.
949122
isolate the variable.\n\nfirst subtract 3 from both sides.\n2x=6\n\nisolate the variable further.  Divide each side by 2\nx=3
588927
easy.. -1 , -2 , 1,2,3.\n\n-1 x -2 =2\n2x2x3 = 12