what machenism is needed to extract electricity electrons from the electromagnetic waves ?
141754
Electromagnetic waves??? thats something ive never heard of before. how about posting the article or the website online? \n\ni do know that electricity can be "transmitted" by magnetism, via electromagnetic induction. according to faraday's law, a changing rate of magnetic flux linkage induces an electromotive force, and thus induces current on a conductor. check out faraday's law at wikipedia for more info dude...
139259
I'm not sure what you are asking.  Here are two possible answers:\n\nFirst:  E = h*nu\n\nIs the equation for the amount of quantized energy in light where h is Planck's constant, 6.626e-34 Joule seconds, and nu is the frequency in Hertz.\n\nThis determines the "raw" energy in the light.  As you know, going from electricity back to light varies in efficiency.  An electric light bulb requires much more electricity than a flourescent bulb to produce the same amount of light.\n\nSecond: hf = phi + Ek\n\nThis is the equation for the photoelectric effect, where electrons are ejected from a material being struck by light.  h is again Planck's constant and f is the frequency of the incident photon.  Phi is the amount of energy required to remove an electron from its binding and Ek is the kinetic energy observed.
889370
carbon has no free electrons available\nso it cannot conduct electricitys\nin case of germanium and si they have d orbits in the outer shell and they have greater mobility
513117
use a potato and two different metals as electrodes. The link will help you, do your own homework, or web searching atleast! it was the second link in google for g** sake!
1148142
Yes, but it is not as easy as detemining electron kinetic energy.  Cerenkov light comes easily from charged particles moving through a medium, but much less easily from uncharged particles with a non-zero magnetic moment, as the magnetic footprint is much smaller than the electrical footprint of a chared particle.  A magnetic particle will create cerenkov light, but it is weaker.  You'd also have to verify that the relationship between angle and velocity holds for magnetic objects, it's not trivially obvious to me that the angle must necessarily be the same.
508002
electricty is form of energy which is created by flow of positive charges(conventional assumption).but actually it is due to the flow ofelectrons inthe direction opposite to the flow of electricity.actually electrons do not travel with that speeed the electric field does the necessary.\n\nbut u have mentioned that matter particles cannot atttain the velocity comparable to that of light.\ni think its not correct\naccording to einstien's theory of relativity\nno particle in this universe is able to attain the velocity greater than that of light even same velocity for some.\nbut if the particle travels with a velocity comparable to that of light then the mass changes accordingly\nm=mo/sqrt(1-v^2/c^2)\nwhere mo is the rest mass of particle\nv is velocity of particle\nc is the velocity of light\nm is the mass of particle at velocity v
877117
That's depending on the domains you want to use that electricity, because there are a lot of ways to produce electricity as to consume it. In fact it is (and should be) very simple to produce electricity, as the way it is valued and used. \nThe only thing which separates the methods is  the QUANTITY of electric energy.\nIt's not the same thing to light up a flashlight bulb or LED,or to power a industrial electric engine (motor) for mechanical work. \nThe basic and most quantitative method is to use a generator (which , yes implies FERROUS ALLOYS) which have a magnetic core carbon-iron based, used as magnetic circuit (they conduct very well the magnetic field, but they are specially made to isolate the convective currents.\nThe idea is simple to use in various ways, thing is to pass one (electro)magnet in front of a coil with (without) ferrous core. You can imagine from here a lots of ways to put it or to make it work with something.\nFor instance instead of using common generator(alternators) you can take one coil and insert in side of the spirals a bar of permanent magnet and with alternative movements of back and forth you can get  electricity. The strongest the magnet, the strongest the electricity will be.\nFor easy lab electricity you can take some jucy fruits(apples,oranges, pineapples, etc) and insert in them two electrods with some distance with respect to each other, one made from zinc and other from copper. Colect the energy gathered by the potential differential, and voila:). \n\nFerroalloys generaly are giving A.C current, meaning thet's alternative and is not good for aparatus wich use Direct Current. But with this method you can get a direct current fairy easly. \nGood luck:)
267999
Light is an electromagnetic wave, like radio waves, governed by Maxwell's Equations:\n\nhttp://en.wikipedia.org/wiki/Maxwell%27s_equations\n\nThis means there are both electric and magnetic waves travelling together; one cannot exist without the other. The energy of the light trades back and forth between the electric and magnetic waves continuously. \n\nNeat thing to consider - metals are shiny because they are conductors! The electric field hits the metal and is cancelled out - a conductor won't allow a voltage difference between two points. The current which flows through the conductor creates a magnetic field which radiates away at 90 degrees to the source. That magnetic field collapses and creates an electric field... effectively, a new light beam! And that is how reflections work.\n\nNo conductor is perfect, of course, so some of that electric current in the surface of the conductor causes resistive heating. This is the reason why a fork left on a sunny picnic table will get a lot hotter than the surrounding air. \n\nFreakier still is that light has mass, which demonstrates that waves and fundamental forces seem to be carried by some sort of "messenger particle", though that's well outside the scope of this Electrical Engineer's theoretical physics training!
2343
If you mean plasma cutter, I can help.  A plasma cutter puts a high-frequency (RF) pulse from the copper tool tip to the metallic material to be cut.  This ionizes the air.  Then DC power is delivered to the arc.  The machine dumps a lot of power into the material, heating it up.  The small opening in the tip is for air which blows the molten material away.  In the case of aluminum, the air just pushes it out of the way.  In the case of steel, the air charge reacts with the iron to produce iron oxide, which further produces more heat than just the arc and helps cut the material.\n\nTraditional gas cutting with acetylene and Oxygen is similar, although i have never gas-cut aluminimum.  (?)  The oxy-acetylene is set up to heat the steel with a blue flame.  When a spot is melted through, you push the oxygen lever which lets a lot of oxygen out right onto the metal.  The ferrous (iron) material burns with the oxygen, cutting the steel.
120420
Assuming you mean photoelectric and not just solar heat cells: \nThe material (silicon ore = sand) is not the problem, the trouble is the apparatus needed to electrolyse and purify the material, and then apply it to suitable carriers.
634708
The process of recovering gold from electronics circuits is relatively simple, but also quite expensive to set up.\n\nEquipment required includes a DC power source capable of delivering several amperes of current at approximately 12 to 100 VDC.  ( A DC Arc Welding Power supply will work well here. )\n\nThen the material containing the gold to be extracted must be crushed.  Crushing multi-layer fiberglass circuit boards is difficult, but it must be done to expose as much of the gold as possible.\n\nA solution of water and some Gold Salt should be mixed.  Gold Sulfate is probably the cheapest, but it is STILL very expensive.  The solution should be in the range of 0.5 gram per litre.\n\nObtain a tank or container made of conductive metal.  Copper is best.  Place the crushed material in the tank,\nPour in the Gold Salt solution until crushed material is completely covered. Attach the POSITIVE anode of the power supply to the tank.  Attach the NEGATIVE cathode of the powersupply to a small piece of gold wire or gold goin or jewelry ( Just a seed to get the thing started . ) And immerse this negative lead in the solution, being careful NOT to let it touch the tank or the crushed material.\n\nTurn on the power...And walk way...The Gold from the crushed material will be 'deposited' on the Cathode gradually over time.  The more current you are able to safely supply without burning something up, the faster the process will be.
140269
Mecury doesn't "lack one electron".  What you would need to do is remove one proton from mercury to make it into gold, in some kind of nuclear reaction.  Now, while not impossible in theory, I don't know of any nuclear pathway to do it, and it would no doubt be prohibitively expensive to do if there were.
401395
Way to go Arbitrage!  Oh to funny guy- yeah we get that E=MC2  IS a formula- but if you really want to "get it" Check out Maxwells equations. It's a great time to be a science nerd with all this info pouring in now! Figure it out & go up one on Albert!
364875
Not sure what you mean, are you talking about using 2 different metals and generating electricity from a potato?
46381
Well electricity needs a path to travel in. Electricity can flow in wires, or other conductors, like a plasma, which consists of charged particles; that is, the electrons have been stripped off the atoms because they are so energetic, leaving just a seething collection of positive and negative particles (said to be "ionized"). In a lightning strike, a path of charged particles extends between the cloud and the ground, or some other object near the ground like a tree or a lightning rod or building (or sometimes between one cloud and another). The electricity in lightning follows this charged path. \n\nIf you can use a powerful laser or some other technique to form an ionized path in the air, then electricity can follow that ionized path, just like it does in lightning (or in Van de Graff generator experiments).
108122
http://science.howstuffworks.com/lightning.htm
413107
I will have to answer your question in two parts.\n\nElectrons in a piece of metal move around randomly with speeds of about 10^5 m/s. This is just the thermal velocity associated with the energy the electrons possess without any electric field present.\nWhen an electric field is applied, the electrons acquire a miniscule drift velocity. This velocity is miniscule compared to both the thermal velocity AND the speed of light.\nElectrons flowing as a current have speeds no where near the speed of light, whether you speak about the thermal or drift velocities.\n\nHOWEVER, the SIGNAL DOES travel close to the speed of light. Signal speeds are typically about 2/3 the speed of light. Just do a simple coaxial cable calculation to find a wave equation, and you can find the conduction speed.\nThe reason for this is that the Electric field applied can cause electrons ALL THROUGHOUT the circuit to move, and thus the speed of the signal is greater than the drift speed of the electrons.\n\nThe other answers are wrong in saying that ELECTRONS travel close to the speed of light.\nIt is correct to say that ELECTRICAL SIGNALS travel close to the speed of light, however.