What happens when sodium reacts with hydrochloric acid? Na + Hcl = ?
138095
If we look at this partial equation, we can see that it most closely resembles a single displacement equation. Since Na is a metal and in group IA, it will have a +1 oxidation state when it combines. This means that it will combine with the Cl (with an oxidation number of -1) to form NaCl. The hydrogen is released as hydrogen gas (H2). The unbalanced equation is: \n\n                                                                        Na  +  HCl -->   NaCl  +   H2 \n\nInventorying both sides of the equation and adjusting the coefficients to balance, the equation becomes: \n\n                                                                        2 Na  + 2 HCl --> 2 NaCl  +  H2
806865
Na2SO4 + H2O\n\nYou always get a type of salt plus water in acid-base neutralization.
124995
Barium chloride is soluble in water. Generally we dont say a molecule is reacting when it dissolves. (Like when NaCl dissolves in water.) \nWhen barium chloride dissolves the following happens\n\nBaCl2+2H2O --> Ba(OH)2+2HCl \n\nThe solution becomes acidic due to the formation of HCl. Though there is a chemical change, these type of changes are   not said chemical reaction. Rather they are dissolving of ions due to hydration.
745017
Your question isn't really complete - the NaOH needs someting to react with.\n\nFor example:\n\nNaOH is used with lipids to make soap.\n\nNaOH + HCl -> H2O + NaCl
657714
NaOH + HCl --> NaCl + H20\n\nn(NaOH) = 1.00 x 32.6cm3\n        = 1.00 x 32.6 x 10^-6\n        = 3.26 x 10^-5  mol\n\nn(HCl) = 1.00 x 25cm3\n       = 1.00 x 25 x 10^-6\n       = 2.5 x 10^-5  mol\n\ntherefore, NaOH is in excess.. hence the final solution is alkaline, which means the pH is more than 7.\n\nDue to the limitation of my knowledge, i can't give you the exact pH value. Just hope that it will help you to continue solving...
34709
When an acid and a base are placed together, they react to neutralize the acid and base properties, producing a salt. The H(+) cation of the acid combines with the OH(-) anion of the base to form water. The compound formed by the cation of the base and the anion of the acid is called a salt:\n\n\nHCl + NaOH --> H2O + NaCl\n2NaOH + H2SO4 --> 2H2O + Na2SO4
813249
Let's take the HCl part first. Since HCl is an acid a solution of HCl contains lots of H+ ions. So when you add HCl the concentration of H+ ions increases making it more probable for H+ ions to colide and react with In- ions than before. To be more precise the reaction In- + H+ -> HIn will become more probable than before, so it will dominate over the HIn -> In- + H+ reaction until a new equilibrium is reached (equilibrium is characterized by the left to right and right to left reactions being equally probable). So in equilibrium the concentration of HIn will be higher after you have addeed HCl.\n\nIt's a very general equilibrium principle called leChateliers principle which comes into play here. The principle can be casted as follows: When you disturb an equilibrium (for instance by adding or removing one of the constituting components) the equilibrium will be shifted in a direction which tries to cancel the change. In this example: We add H+ and the equilibrium tries to remove some of the H+ ions again by shifting the equilibrium to the left (meaning that more H+ reacts with In- to get HIn).\n\nIf you add OH- instead the OH- will neutralize the H+ in the solution (acid + base gives water):\nH+ + OH- -> H2O\nso you are effectively removing H+ and according to leChateliers principle the equilibrium will try to create new H+ ions by shifting to the right (so you will have less HIn and more In- than before you added OH-). The microscopic explanation is again that removing H+ makes the reaction In- + H+ -> HIn less probable than before meaning that the reaction HIn -> In- + H+ will be dominating until a new equilibrium is reached so some HIn will effectively be turned into In-.\nHope this helps.
152537
Citric acid is a weak acid, while sodium hydroxide is a strong base. The sodium would fall off the hydroxide (because it's strong), so the reaction would be:\n\nHC6H7O7 + OH- --> H2O + C6H7O7
621533
NaOH ----------------> Na+   +   OH-\nFind the number of moles of NaOH\nMoles of NaOH = 0.10M * 0.150L = 0.015 moles\nSince the coefficients in fornt of NaOH, Na+ and OH- are all 1, therefore if 0.015 moles of NaOH disssociates, 0.015 moles of Na+ and 0.015 moles of OH- are produced.\n\nSimilarly we will work with HCl\nHCl --------------------> H+      +      Cl-\nMoles of HCL = 0.30M * 0.05L = 0.015 moles\nThis means the 0.015 moles of H+ will be produced\n\nSince H+ and OH- have equal amiunts, they will completely neutralize each other leaving the solution at neutral pH. Since the neutral pH is 7, therefore, the pH of this solution will be 7.
813911
HBr ---> H(+) + Br(-)\nH2SO3 ---> H(+) + HSO3(-)\nCH3-COOH ---> H(+) + CH3-COO(-)
170895
Sodion Hypochlorite and Sodium Thiosulfate?  Ive never heard of Na2(s2o3)2?!  Anyways heres the balanced equation:\n\n2NaOCl + Na2S2O3 ---> Na2S2O3 + 2NaOCl\n\nPretty straight forward I guess.  Double Replacement reaction.
885670
Get the chemical equation first:\nHCl + NaOH --> NaCl + H2O\n\nMoles of HCl used = (50/1000)dm3 X (1.0mol/dm3) = 0.05 mol\nMoles of NaOH used = (50/1000)dm3 x (1.0mol/dm3) = 0.05 mol\n\nFrom chemical equation, 1 mole of HCl needs 1 mole of NaOH for complete neutralization.\nFrom what you are given, you have the exact amount for complete neutralization (meaning, there is no excess reagents).\nFrom chemical equation again, 1 mole of HCl or NaOH produces 1 mole of water.\nThus you had exactly 0.05 mole of water produced here.\nHope this helps. :)
459842
Hydrochloric acid produces H plus and Cl - :2 ions per molecule\n\nWater self ionizes to produce H plus and OH minus : 2 ions\n\nCarbonic acid H2C03 can produce 2 H plus and one C03 two minus ions: 3 ions\n\nSodium hydroxide dissociates to give Na plus and OH minus: 2 ions\n\nCarbonic acid potentially forms the greatest number of ions per molecule\n\n\nCarbonic acid is formed of the greatest number of ions per molecule?
429906
Never trust materials science majors ...\n\n1. NaCl (s) --> Na+ (aq) + Cl- (aq)\n2. Ca (s) + 2H2O (l) --> Ca(OH)2 (s) + H2 (g)\n3. Ca(OH)2 (s) --> H2O (g) + CaO (s)
877634
Any acid, for example:\n\nHCl + H2O  --> Cl- + H3O+
788122
NaOH in thermometer will have chemical reaction with HCL thus the HCl temperature measured won't be accurate as chemical changes will take place. This reaction involves a base (NaOH) and an acid (HCl), so it's a neutralization reaction, which is a special type of double-displacement reaction.♥
755177
1. Make sure that HCl is standardized.\n2. Write the balance equation:\n\nCa(OH)2 + 2HCl ---> CaCl2 + 2H2O\n\n- this means that 1 mole of Ca(OH)2 reacts for every 2 moles of HCl\n\n3. Get the number of moles of HCl reacted by multiplying the volume used to react Ca(OH)2 by the actual concentration of HCl (value from standardization). Divide the result by 2 - and this is now your moles Ca(OH)2.\n\n4. Get the molar solubility of Ca(OH)2 by dividing its number of moles by its volume. Unit is in gram per liter.