What is resistance and OHM's law?Whreas what is the relation between both these?
151570
ohm's law states that current throught a conductor is directly proportional to the voltage applied to it.\n\nso,  i oc V\n=> i = R*V where R is proportionality constant called resistance of the conductor. \n\nResistance of a material is the electrical property which opposes the flow of electrons or current.
731049
resistance is said to be one ohm if 1 ampere of current flows through the circuit across potential difference of 1volt  becuse resistance =voltage /current\na 1 ohm resistor gives obstruction to the current such that only 1A\ncurrent pass through it when potential difference is1V
402553
Your circuit diagram looks strange - some resistance are denoted in Volts. Hmm, anyway, otherwise it's rather simple. You got to use your formulaes for calculating resistance in a series and ohm's law V=IR. I hope I'm right - I last did physics in 1999.\n------------------------------------------------\n\nThe resistors are all in series, therefore:\nTotal Resistance = 33 + 23 + 2/I + 1/I + 43\n                 = 99 + 3/I Ohms\n\nUsing Ohms law, V = IR. Therefore:\n=> 100 = I . Total Resistance\n=> 100 = I (99 + 3/I)\n=> 100 = 99 I + 3\n=> I = 97/99 Amperes  --- ans\n\nSub. value for I into Total Resistance:\n=> Total Resistance = 99 + 3/(97/99)\n                    = 9900/97 Ohms (or 102.06 Ohms) --- ans \n\nUsing V=IR\n\nV(3) = potential difference from 100 V to when current I passes through the 33 Ohm resistor\n     = 100 - [(97/99 x 33)] \n     = 202/3 V or 67.33 V (The reading of V (3)'s galvanometer) --- ans.\n\nV(2) = potential difference from V(3) to when current I passes through the 23 Ohm resistor\n     = 202/3 - [(97/99 x 23)] \n     = 4435/99 V or 44.80 V (The reading of V (2)'s galvanometer) --- ans.\n\nV(1) = potential difference from V(2) to when current I passes through the 2V resistor\n     = 4435/99 - 2\n     = 4237/99 V or 42.80 V (The reading of V (1) galvanometer) --- ans.
774610
R1+R2=9\nR1R2/R1+R2=2\nR1R2=2(R1+R2)\n=18\nso the resistances are 3 ohms and 6 ohms resply.
100752
There are two relavent formulas,\nOhms Law: V = R*I\nwhere V is the voltage, R is the resistance, and I is the current.  Also,\nPower = V*I\n\nIf we know that power is 150 watts, then,\n150 = V * I,\nbut what is the current (I)?\n\nWe know the resistance is 95 ohms,\nV = 95*I --> I = V / 95\nSo plugging back into the power equation,\nP = V^2 / R \n150 = V^2 / 95 --> V = sqrt(150 * 95)\nso V = 119.4 volts --> 120 volts
1165503
For a steady state DC circiut P=EI \nwhere\nP=power in watts\nE= Potential in volts\nI=Current in amperes\n\nfrom Ohm's I=E/R\nwhere R = resistance in ohms\n\nsubstituting and solving for E we obtain\nE = SQRT (PR).\n\nSo what is the resistance of your circuit.
337085
Resistance in a wire is caused by ions in the wire getting in the way of electrons. This causes their drift velocity( the average velocity of an electron) to decrease so current (charge per second)decreases because fewer electrons go past a certain point per second. Things can affect resistance, such as \n-heat as if the wire is hot the ions vibrate more and so get in th way of electrons more, \n-thickness of the wire as when it is thicker there are more spaces for electrons to get through, \n-material of the wire as some is more conductive than others,\nlength of the wire as the longer the wire, the more times the free electrons will collide with other free electrons, and the ions making up the metal. Therefore, more energy is going to be lost in these collisions (as heat). \n try this site http://www.bbc.co.uk/schools/gcsebitesize/physics/electricity_and_magnetism/resistance_and_resistorsrev1.shtml
757379
Resistance is connected to conductance as resistivity is related to conductivity.\n  By ohm's law\n   J= E * condutivity\nor \n  J= E/resistivity\n Resistance=( resistivity X length) /  Cross Sectional Area
647967
The impedance of a circuit element is defined as the ratio of the phasor voltage across the element to the phasor current through the element.\n\nElectrical resistance is a measure of the degree to which an object opposes the passage of an electric current.
363388
The total resistance is 12 + 8 + 6 = 26 ohms. In series the total resistance is the sum of individual resistors. Apply ohm's law V=IR, I = 20/26 Amperes. The voltage drop across each resistor is found by multiplying the current with the resistance of each resistor.
858072
Resistance is the property in an electrical circuit.\n\nAny wire will have some resistance to flow of charges.\n\nThe property that gives hindrance to flow of charges is called resistance.\n\nIf there is any obstacle to the flow of charges then the one which gives this obstacle is said to possess some resistance.\n\nThe resistance is related by this simple equation E = I R.\n\nOr R = E/I. \n\nE is the potential difference and I is the rate of flow of charges.\n\nThe resistance is zero only when I is infinity.\n\nThe resistance is less when I is great for small values of E.\n\nThe resistance is large when I is small for a value of E.\n\nThe potential difference between the ends of a battery is full to its maximum when it is not connected to any external circuit.\n\nThat is when the current is zero the potential difference across the battery is maximum. This maximum potential difference is called E.M.F of the battery\n\nConsider a battery of 2 Volt.\n\nWhen this is connected to a resistor of 2 Ohm the current we expect is 2/2 = 1 ampere. \n\nBut in practice this will not happen.\n\nThe current will be less than 1A. Suppose that the current is 0. 95 A.\n\nAt the same time if we measure the potential difference it will NOT be 2 volt but it will be only 1.9 volt. \n\nThus there is a loss of 0.1 volt.\n\nThe chemicals inside the battery produce this 0.1 volt opposing the 2 volt ( when there is no flow of charges inside the battery).\n\n\n \n\nReturning to the current consideration, we used a battery of 2 volt E.MF and a resistor of resistance 2 ohm. But the current is 0.95 A instead of 1 A.\n\nIf the total resistance were 2.105 ohm instead of 2 ohm , then the current in the circuit will be 2 / 2.105 = 0.95 A.\n\nThus we see that the battery is having some INTERNAL resistance of 0.105 ohm.\n\nThis resistance is due to the production of opposite emf of 0.1 volt to the actual emf of 2 volt (2- 01 = 1.9 V). The potential difference across the battery has reduced to 1.9V from 2 V.\n\nThus the resistance is only a property and there not be any resistor inside the battery.\n\nThis internal resistance is not a constant one and will vary according to the external resistances used in the circuit and other factors.
224197
Amps and volts, while correlated, are different characteristics of electricity. You can determine one from the other, but you can't convert one into the other.\n\nHaving said that, here's OHM's law: \n\nV=I x R, where V is volts, I is Amps and R is resistance.
304043
Because algebra skills are very lacking in most people. It's just to make sure that they know what the rearranged formula's look like. But you are right, those 2 laws are probably all you need to remember. P=IE is always true, but remember than Ohm's Law is only an approximation for materials that have a linear E vs R graph, such as metals at room temperature. Its not true for semiconductors and gas discharges.
1155349
Impedance is a bit different than resistance. Ideally Resistance will hold it's value no matter what frequency your working with, where Impedance is frequency depedent. inductors and capacitors have impedance where resistors have resistance (actually most resistors have a slight amount of impedance because they have a coil shape.).
210547
power=voltage^2/resistance\nhigher power means lower resistance.
609858
Its is the amount of resistance.  Same reason the wire in a lightbulb grows.  There is some level of electrical resistance, even in conductive materials.  The resistance creates heat and eventual combustion.
653976
You need to use Ohm's law.\n  E=I x R  \n  E=Voltage. I=Current/Amps  R=Resistance/Ohms\n  E= 9voltsDC\n  I= 3amperes.\n  R= ?\n  So:\n  R = 9volt/3amp\n  R=  3ohms