If I wanted 1 cm width of diamond, in 590 meters squared how much would it cost me?
146191
Same as above, and there is missing info anyway. How much would 1 unit* of this cost?\n\n*unit, because the question is messed up. <_<
751869
First, we need to find the partial derivatives of cost with respect to length and width.\n\nC = 10LW + 640(1/W + 1/L)\ndC/dL = 10W - 640 * (1/L^2)\ndC/dW = 10L - 640 * (1/W^2)\n\nThe minimum of cost will occur where the above partial derivatives are equal to 0.\n\n10W - 640 * (1/L^2) = 0\n10W = 640 * (1/L^2)\nW(L^2) = 64\n\n10L - 640 * (1/W^2) = 0\n10L = 640 * (1/W^2)\nL(W^2) = 64\n\nSo we have 2 equations which both need to be true at minimum cost\n\nW(L^2) = 64 and L(W^2) = 64\nL = 64/(WL) and W = 64/(WL)\n\nSo W and L must be the same\n\nW(W^2) = W^3 = 64\nW = L = 4 meters\nH = 2 cubic meters / (4 * 4 square meters) = 0.125 meters\n\nNote that the given equation is correct, Gary needs to substitute\nhw = 2/l and hl = 2/w to get the final result...
547564
Estimate it=use about 70 sq meters, as supplied by Mars, and figure 1.5 candies per centimeter long, and 2 per centimeter high-so 6 candies per cubic cm. I would estimate about 5, though, because I dont think they are as small as I estimated.  So at 1 million cub cm/cub M, that would get you about 5 X 1 million, X 70, or about 350 million.  Because they are oblate spheroids, they would pack slightly tighter than the flat rectangular boxes, so I'd add a fudge factor of about 20%.  Say anything from a low end of about 200 million to a high end of about 500 million.
841638
4.00751601 × 10^9 centimeters
385689
You want arc length or straight line?\n\n934.59 nm\n\naccording to the reference below.
1048004
Instead of just telling you the answer, I will tell you how to get the answer:\n\n7% is comprable to 0.07 therefore, if you multiply 12,900 by 0.07, you will find your answer which like most of your responses state is 903.
229617
http://jewelry.about.com/cs/diamondclarity/a/judge_clarity.htm\nnot sure about the tool but here's a site to teach you how to evaluate diamond.
765616
Since the volume is 1000, \npi*(r^2)*h = 1000, and so you can express h in terms of r.\n\nCall the cost per sq cm of the wall 1 unit.  Then the cost of the ends is 2 unit per sq cm.  Apply the areas, and get\ncost of wall = 2*pi*r*h  =  (sub in the expression you got above for h in terms of r)\nCost of ends = 2*pi*(r^2) * 2\n\nWrite f(r) for total cost, and as usual differentiate etc to find minimum value of r.  Obviously r and h must both be positive, and that's the only restriction on the domains.  Hope you can do it yourself from here.  You need the exercise and I don't.
956016
You can do all these in google. For the first one, type in "4 square metres in square cm", and it tells you the exact answer. Do the same for the others. \nYou can then work out any others by yourself without needing to ask :)
306931
http://www.digitaldutch.com/unitconverter/\n\nhas a converter for unit conversion.\n\n1 foot = 30.48 cm\n\n154cm = 5.052feet
871718
This would depend on the site and amount of work to be carried out, mail me at shaun@sdhinternet.co.uk with the  details and will let you know what the cost would be
705154
9cm3\n\n9x9x9=729!!!!!
1054722
Approx\nUS$30,000- 45,900
861097
We want to minimize cost, so find out what the cost function is:\n\nCost = cost of (top + bottom) +  cost of side\n= (1.2 * 2 Pi r^2) + (0.4 * 2 Pi r h)\n= 2.4 Pi r^2 + 0.8 Pi r h\n\nSince the Volume is 500 ml = 500 cubic cm = 0.0005 cubic m,\n\nVolume = Pi r^2 h\n0.0005 = Pi r^2 h\nSo h = 0.0005/(Pi r^2)\n\nSubsititue h in the cost function\n\nCost = 2.4 Pi r^2 + 0.8 Pi r (0.0005/(Pi r^2))\nC = 2.4 Pi r^2 + 0.0004/r\n\nTo minimize we need to differentiate and then set the derivative to 0\n\ndC/dr = 4.8 Pi r - 0.0004/r^2\n\nSet dC/dr = 0\n\n4.8 Pi r - 0.0004/r^2 = 0\n4.8 Pi r^3 - 0.0004 = 0\nr = 0.0298 m\n\nand h = 0.0005/(Pi r^2) = 0.179 m\n\nTherefore, to minimize the cost the radius must be 2.98 cm and the height must be 17.9 cm.
802410
rfamilymember is right and so is his method for getting the answer. It's $113.33\n\nJust multiply this by 0.075 to check. (That's 7.5 hundredths, in other words,7.5 per cent.)
439597
41 - 24 carats in solid gold\n\nMy mom loves doing these, but i'm not so good...
360089
949,04\n\nYou can type the following as a search in g**gle:\n\n$1689 in gbp\n\nIt does all sorts of computations and conversions for you. Curency conversions, miles to kilometers, plain arithmatic, etc.