need cubic feet of a circular hole 30 feet wide and 6" deep?
141968
Since you have a circular hole you have to make the next operation:\n\nFirst multiply the diameter (wide) by PI (3.1415926535)^2 and divide the result by 4 (or multiply by half the wide  by pi^2 and don't divide by 4 it's the same result).\n\nThat's 30 feet by 9.8696044 and divided by 4 the result equals 74.02203300 square feet.\n\nThen multiply by 0.5 feet (that's 6") to get the volume (that's the cubic feet) and equals 37.01101650408 cu. feet.\n\nJust in case you need to know
1060977
you can buy a 6 foot extesnsion cable
949980
Go to B&Q and buy a grow bag, worked for me, Jim 7foot 6"
443794
30 degrees or pi/6 radians
65609
If you want to consider also rectangular rooms, your room may fit some of these possibilities:\n\n1) 11 x 25 (= exactly 275)\n2) 12 x 23 ( almost equal to 275)\n3) 13 x 21 ( almost equal to 275)\n4) 14 x 19,5 (almost equal to 275)\n5) 15 x 18,3 ( almost equal to 275)\n\nThese, added to your 16,6 x 16,6 should give you a good range of choices to which your room may fit.\n\nAlso to consider that the technical specifics of a technical device never exactly follow pure mathematics: so the 2200 cubic feet is always to be read "+ or - epsilon". That's why you don't need to bother to inch errors in your walls' lenght.
1051825
To cover it to a depth of 2 inches, you need just about 0.4 cubic feet of sand.  (Pi X D/2 X H)
948283
4 feet by 4 feet by 8 feet
220777
use the following formula .. \n\ntotatal surface area = \n[(H/D)*4(pie)(0.5D*0.5D)] + [ (H-t)/(D-2t)*4(pie)*(0.5D-t)(0.5D-t)] + [(pie)(0.5D*0.5D)-(pie)(0.5D-t)(0.5D-t)]\n\nthis is considering D = tank diametere is from outer surface and not the cavity diameter \n\n\nouter surface area of cover = (H/D)*4*(pie)(0.5D*0.5D)\ninner surface area of cover = [(H-t)/(D-2t)*4*(pie)*(0.5D-t)(0.5D-t)] \n\nthe base line are = [(pie)(0.5D*0.5D)-(pie)(0.5D-t)(0.5D-t)]
611578
C = pi times diameter\n\n  = 22/7 times 28 = 22 times 4 = 88 ft
587057
If your pen is round, then the circumference is about 157 feet.  Assuming you are building a fence of some kind, decide on how far apart you want to put your posts, how many 2x6's you need between posts, and don't forget to subtract the length of the gate from the original circumference.\n\nFor example, if you decide you need three 2x6's to a section, you want eight feet per section, and your gate is ten feet wide, you are looking at 147 feet of fence divided into 18 eight-foot sections (with an extra three feet to take care of...maybe a short section near the gate, or a small gate opposite the main gate). Multiply the 18 by three boards per section and you'll need 54 8-foot 2x6's (plus a ten-foot piece if you want to make that extra three feet into a short section).\n\n(of course you'll have to buy some posts, too...I'd recommend something in the 4x4 range...20 pieces in the above example...length determined by how high you want the fence, and how deep you want to dig to set the posts.)
882706
305m long by 33.5m wide
205124
That depends on how deep you want the concrete.  Multiply the desired depth (in feet) by 128,000 square feet, then divide by 27 (because there are 27 cubic feet in a cubic yard).
493858
this will be  169646.00329384883487698274269709 cubic inches
710873
The area of the sheet is 250*200=50000 cm^2, \nand area of the hole is 0.6*50000 = 30000 cm^2. \nArea of the hole is \n=(250-2*x)*(200-2*x) \n=50000-500*X-400*X+4*X^2\n=4*X^2-900*X+50000.\nArea of the hole is= 30000 cm^2. \nEQUATING above two, we have\n4*X^2-900*X+50000=30000\n4*X^2-900*X+20000=0\nX^2-225*X+12500=0\nx=-b+/-sqrt(b^2-4*a*c)/2*a\nx=225+/-sqrt(225^2-4*1*12500)/2*1\nx=225+/-sqrt(50625-50000)/2\nx=225+/-sqrt(625)/2\nx=225+/-(25)/2\nx=(225+25)/2 or x=225-25/2\nx=125 or x=100
569185
First off, just take the cube root (or use that x^y button on your calculator and raise the volume in question to the 0.3333333333 power). 1.8x10^6 cu ft would then be about 121 feet on a side.  Now, yourreal question is how big is 27,000 tons (I assume english units, not metric tons since you went to cubic feet).  That will depend on the density of the substance in question.  27,000 tons of water will take up more room than 27,000 tons of iron. The volume you gave gives a density of about 30lbs/cubic foot, which is about 1/2 the density of water.\n\nThis does sound like something hollow, like a boat, or maybe it is wood. That is a big block of wood. You gonna carve yourself an office building or something? A ten story cubic building is about that volume.
950995
208 feet by 208 feet.
264523
1 ft^3 = 7.48 gallons.  You will therefore need a box with an internal volume of 2.139 ft^3 (or 3696.257 cubic inches).\n\n12" x 14" x 22" will work.  OR 12" x 12" x 25.67"  OR ....