Why do they call zero(0) an even number? What is the reason?
145210
They call ZERO an even number, who are they that mention like this?\n\nActually, odd numbers are start with 1, then 3, 5, etc., even numbers are start with 2, then 4, 6, etc.\n\nIf you check at the numbers system, then you can understand what meant by odd number, even number, negative number, natural number, whole number and others. \n\nSo, here the point is, ZERO actually is not a even number (the smaller even number start with 2), then there was no reason to tell you that why can call it an even number.
678148
VERY GOOD Question!!!\nI don't know, but i never thought abou it either.\n\nwell if you only need to write 0 i guess you don't write anything. and for like 10 you just write an x so i guess there is not a zero because you don't really need it.\n\ni hope i was help!
104840
Actually, as what I have learned, this equation is limitless because the numbers itself are limitless. The incredible fact about this is that in every number you substitute in "x", the answer is always "0".
230430
The square root of -1 has no relation to zero.  It requires an imaginary number.  Division by zero is, unfortunately for our number system, impossible.  You cannot cut something into zero pieces, and in fact the very statement makes no sense.
189562
This is not simply a quirk of our usual number system: in any number system that satisfies certain basic properties such as distributivity and associativity, 0 multiplied by anything will give 0. So if you start with any non-zero number x, there cannot be any number which when multiplied by 0 gives you x, so there can be no answer to the question "what is x divided by 0". Mathematicians say that "division by 0 is undefined", meaning there is no way to define an answer to the question in any reasonable or consistent manner.
81372
I don't mean to be rude, but none of the above answers are quite right, and some are actually quite wrong. 0/0 is not undefined, 0/0 is not always infinity, 0/0 never means "nothing" (in fact, it is used quite frequently in calculus), and although there is no general way to define 0/0, it most certainly can be defined given enough information in a problem.\n\nNormlparker had it closest, when discussing the nature of division. In other words, 10/2 means take 10 things and divide them into 2 equal groups; when you do, each of those groups will contain 5 things, so 10/2=5. Dividing by 0 doesn't conceptually make sense. You can't take 10 things and divide them into no groups. That answer is UNDEFINED. (Captial letters for vocabulary emphasis, not because I am yelling.)\n\nNow dividing 0 by 0 is a different issue, because you can surely take no things and make them into no groups. However, what's the size of those nonexistent groups? It's not infinity, nor is it undefined, as some previous posters have said. Dividing 0 by 0 is an INDETERMINATE value, and it's exactly as you said--it could equal just about anything.\n\nTake for instance the fraction (x^2+2x-3)/(x-1). If you plug x=1 into the fraction, you get 0/0, but the function is definitely not infinity when you get close to x=1. If you factor the numerator, the fraction becomes [(x+3)(x-1)]/(x-1). Cancel those common factors and you get x+3. In other words, this fraction (although undefined at x=1) gets very close to x+3=1+3=4. In this case, 0/0 is basically 4.\n\nTo be specific, a non-zero number divided by 0 approaches infinity (or negative infinity), but 0/0 can approach lots of things. However, ANYTHING divided by 0 is not a real number. \n\nWhen you took your equation (0)(0)=0 and divided both sides by one of the 0s on the left side, you actually violated a mathematical principle. Sure you can divide both sides of an equation by any number, as long as you are certain that number is not 0.\n\nSome of the most famous mathematical fallacies are based upon divideng by 0 in a sneaky way. You can prove lots of untrue things (such as 1=2) if you do that, and it's actually kind of fun. I used to do that once a year in my geometry classes to "prove" to my students all math was worthless, and as soon as they got excited, I showed them how I fooled them. They usually didn't care so much, but nerds like me think that kind of stuff is hilarious.\n\nHere are some other indeterminate values that can equal anything: (0)(infinity), 1^(infinity), (infinity)/(infinity).
57849
By definition, even numbers are all numbers that can be written as 2 times n where n is a whole number.\n\nOdd numbers are those that can be written as 2 times n + 1.\n\n0 = 2 times 0, so it is even.
787272
There are no even odd numbers.  However, 2 is the only even prime number.  Is that what you meant?
1032037
it is any number smaller then 4, for example 3.99999 or 2, or 0.00001, BUT NOT zero itself!!! (0=0, and not 0<0)\n\nSo x<4 is WRONG, the answer is: \nx<4 AND x is not equal to 0\nBUT x CANNOT be a negative number either, as -1(-1-4)=5!!\n\nSo the final answer is: \nx<4 and x>0 --- any figure will match your condition\n\nThanks for the math!
8564
It looks to me that the integer part means that you take the integer that comes before the given number if the given number is not an integer thus 0 would be the correct answer.
238404
thanks 4 voting my answer as best but i didnt understand what u said\no divided by any no is always zero and with exception of zero where i guess it's not defined(aint that also zero iam not sure)
827218
Mathematics wouldn't be as advanced as it is today without the zero. This is because you may have noticed that 0 is very 'powerful' meaning that if for example i had the following expression:\n\n999999x8575x75238x652938x753928x7539042x34173x0\n\nthe answer would be 0. \nIt is this type of number that helps in simplifying alot of equations in calculus. Believe me, without the number 0, planes would not have been to fly!
692848
bcoz 0 is the additive identity and any number multipled by 0 gives 0.So operations using 0 are simpler and life becomes much more easier.
457166
This is a Frequently Asked Question. Following is my previous answer:\n\nThis question may be asked so frequently (along with the infamous 0.999...) because no concrete axioms or definitions are ever given for the real number system until one studies higher algebra or real analysis; it is assumed that everyone knows what a real number is until then. The proliferation of these questions show that this assumption is no good.\nFor the sake of conciseness, I will not define what a real number is here, as only the algebraic structure of the real numbers is necessary to answer this question. The algebraic structure of the real numbers is what we call a field. A field is an algebraic structure that follows a finite set of axioms. These axioms define what statements are true and false in this system based on the laws of logic. You can find the field axioms here: http://mathworld.wolfram.com/Field.html .\nEach line is preceded by "For all real numbers a, b and c, the following is true...". Note that the proper form of the additive identity and multiplicative identity is that it prescribes the existence of some number 1 and some number 0 such that the equations hold. These same numbers are then used to prescribe the existence of additive and multiplicative inverses.\nDivision a/b is just shorthand for a*(b^(-1)). So in your question, you are looking for 1*0^(-1). It is easy to show that there is no such number as 0^(-1) in any field. Suppose 0^(-1) exists.\nThen 0*0^(-1) = 1. But multiplying both sides by 0^(-1) gives 0 = 0^(-1), which means 0*0 = 0 = 1. This is obviously false.\nSuppose 0 = 1. 0*a = a for all numbers a. But 0*a = (1 + (-1))*a = a + (-a) = 0. Thus 0 is not equivalent to 1 and our sole assumption that 0^(-1) exists must be false. Thus the expression 1*0^(-1) is undefined in a field.\nProof by contradiction is very powerful for many types of statements.\nAs to the limit argument, note that you are evaluating a limit of the function f(x) = 1/x. As we approach 0 from the negative x-axis, this limit decreases without bound, but as we approach 0 along the positive x-axis, the limit increases without bound. Thus, the limit of f(x) at 0 does not exist, so f(0) remains undefined with no continuous way to complete it. The limit is not indeterminate for this function; it does not exist.\nWhile 1/0 is not defined in any number system, |1/0| is defined as positive infinity in extended number systems (which are not fields by the above argument) for various purposes. See http://mathworld.wolfram.com/AffinelyExtendedRealNumbers.html .
649881
4) n is even.\nStarting with an even number (0) and ending with an even number, means you have an odd number off roots.
510570
Because the exponet of both is an even number which is 2\n\nIf you divide by 8 you might get a .5 result.
579225
Division by zero is undefined, even if you divide zero into zero.\n\nhttp://en.wikipedia.org/wiki/Division_by_zero