ok on this one we have to use the formula for binomial squared to multiply the problem is (6x+5)^?
142158
Use the FOIL method, since this is really (6x+5)(6x+5)\n\nFirst terms (6x)(6x)=36x^2 +\nOutside terms (6x)(5)=30x +\nInside terms (5)(6x)=30x +\nLast terms (5)(5)=25\n\nFor a total of  36x^2 + 60x + 25
447887
You probably mean\np(x) = 2x^4 +5x^3 – 3x^2 -2x -6\nThe answer is e) Both b,d\nbecause when you multiply the factors you should get the original expression and (x+3)(2x^3 –x^2 -2)= 2x^4 +5x^3 – 3x^2 -2x -6\nThis was quickly seen because you need x^4 which is only obtainable by x multiplied by x^3 in your problem :)\nHope this helps
140804
6x(2x+y-5)=12x^2+6xy-30x
204269
isolate one of the radicals, then square both sides.\nhere you get 2x+3=5x-6.......3x=9.......x=3\n\nworst case is sqrt(something) + something = sqrt(something)\n\nhere you'd isolate a radical, square both sides, clean up the equation, isolate the remaining radical, square both sides, and finish.  AND CHECK YOUR ANSWERS.  when you square both sides, "extraneous" solutions sneak in that might have you, back in the original equation, taking the square root of something negative.\n\nexample:  sqrt(3x+3) + 1 = sqrt(5x+6)\n....... (3x+3)+2*sqrt(3x+3)+1=(5x+6) ..... left side is a binomial\n.........2*sqrt(3x+3) = 2x+2\n...........sqrt(3x+3) = x+1\n...............(3x+3) = x^2+2x+1 ....... right side is a binomial\n....................0 = x^2-x-2 ......... and it factors!\n....................0 = (x-2)(x+1)\n....................0 = (x-2) so x=2\nor .................0 = (x+1) so x=-1\n\nnow check: sqrt(3*2+3)+1 =? sqrt(5*2+6)\n.............sqrt(9) + 1 =? sqrt(16)\n...................3 + 1 = 4.............yes.\n\n..........sqrt(3*-1+3)+1 = sqrt(5*-1+6)\n...............sqrt(0)+1 = sqrt(1)\n.......................1 = 1 ............yes\n\nsigh.  when I wrote it the equal signs lined up.
97164
5 x squared would just be 5x^2\n\nx^-2  =  1/x^2\n\nSo, y negative 6 exponent  =  1/y^6
816805
i doubt u got it right. this is how u do it:\n\nfirst u group them \n\n(x³-3x²)+(4x-12)\n\nthen simplify each binomial\n\nx²(x-3)+4(x-3)\n\nthen since (x-3) are the same on both of them u group them together\n\n(x²+4)(x-3)\n\nand there u have it
984158
The general approach is to move the x's to one side of the equation and the numbers to the other side, then solve for x. In your example:\n\n5x - 6 = 4x -+ 8\nFirst step: move 4x to left side. Since you can subtract the same amount from both sides of an equation the detailed step looks like this:\n5x - 6 - 4x = 4x + 8 - 4x\nor, in short form,\n5x - 4x - 6 = 8\n\nThen, move the 6 to the other side by adding 6 to both sides:\n5x - 4x - 6 + 6 = 8 + 6\nor, in short form:\n5x - 4x = 8 + 6\n\nThen, reduce both sides of the equation:\nx = 14\n\nHope this helps!
945134
On problem 5\n\n4X^2 + 5x - 6\n\nLook at your factors for a & c.\n4 has factors  1*4 and 2*2\n6 has factors  1*6 and 2*3.\nNow multiply the choices and find differences until a diff is 5.\n1,4 times 1,6 gives us 1-24 = -23\n1,4 times 6,1 gives us 6-4 = 2\n1,4 times 2,3 gives us 2-12 = -10  \n1,4 times 3,2 gives us 3-8 = -5..... (yea!!)\n\nUse those values in your answer 1,4 and 3,2 such that the 3 is multiplied by 1x and 2 is by the 4x.\n \n(4x-3)(x+2)\n-----------------------------------------------\nOn problem 7, \n9X^2 +12X + 4\nNote that we have positive signs on b & c.\n\nFactors of 9 are 1,9 and 3,3\nfactor of 4 are 1,4 and 2,2\nNow multiply the factors and find when the SUM is 12.\n1,9 times 1,4 leads to 1 + 36 = 37\n1,9 times 4,1 leads to 4 + 9 = 13\n3,3 times 1,4 leads to 3 + 12 = 15\n1,9 times 2,2 leads to 2 + 18 = 20\n3,3 times 2,2 leads to 6 + 6 = 12 (yea!!)\n\n(3X + 2)(3X + 2)\n\n-------------------------\nOn problem 9, \n12X^2 - 24X - 9\n\nwe have a negative c again so we will find differences between factor products until finding 24.\n\n12 factors into 1,12.....2,6.... and 3,4\n9 factors into 1,9 and 3,3\n\n1,12 times 1,9 leads to 1 - 108 = -107\n1,12 times 9,1 leads to 9 - 12 = -3\n1,12 times 3,3 leads to 3 - 36 = -33\n2,6  times 1,9 leads to 2 - 54 = -52\n2,6  times 9,1 leads to 18 - 6 = 12\n2,6  times 3,3 leads to 6 - 18 = -12\n3,4  times 1,9 leads to 3 - 36 = -33\n3,4  times 9,1 leads to 27 - 4 = 23\n3,4  times 3,3 leads to 9 - 12 = -3\n\nrats.   no solution
214212
Hi, here's how ya do the problem:\n\n-5x+y=6\n\ny=5x+6 (move -5x over by adding the opposite)\n\nSo then you substitute it into the problem\n3x-2y=3 so that it looks like\n\n3x-2(5x+6)=3\n\nNext distribute the -2\n3x-10x-12=3\n\nand solve\n-7x-12=3\n-7x=15\nx=2.14\n\nThen you substitute 2.14 into either equation to figure out y\n-5(2.14)+y=6\n-10.70+y=6\ny=16.7\n\nHope this helps!
1025264
pls specify ur question, didnt quite understand it\n\nIf there is "OR" u have to add and if it is "And" u have to multiply.
458594
you subtract like terms.  \n5x^2 - 9x^2 = -4x^2\n-3x - (-5x) = -3x+5x = 2x\n6 - (-3) = 6+3 = 9\n\nTherefore, the final answer is -4x^2 +2x +9
71477
6x^2 + dx - 12 would need to factor into two binomials.  If you know that one is (2x - 3), then the first term of the other would have to be 3x, in order to make the 6x^2 term.  In order to get -12 as the constant term, we would multiply -3 x +4.  \n\nSo the other factor is (3x + 4)\n\nUsing the FOIL method for multiplying two binomials, we get\n(3x + 4)(2x - 3) \n= 6x^2 - 9x + 8x - 12\n= 6x^2 - x - 12\nSo d must be -1.
1053054
Use the binomial.  I've already shown you how in a previous question.  And you already know that you need to use it.
902233
4-5-(-6)\n=4-5+6 = 10-5 = 5
293335
8+9+6+(1+2+3+4+5+7)^0 = 24\n\nX^(0) = 1
470305
Factoring is the "opposite" of FOILing.\n\nIf you had x^2 (which is x squared)\nx^2 + 5x + 6\n\nYou ask yourself:  What multiplies to 6?  (Write all the choices including negatives)\nThen, out of those choices, which one (and only one will work) adds to 5.  \n\nSo... 2 x 3 = 6  and -2 x -3 = 6\n2 + 3 = 5\n-2 + -3 = -5 \n\nSo, 2 and 3 add to 5 and mult. to 6.\n\nThen you write it in parenthesis keeping the signs.\n\nYou get (x + 2)(x + 3)\n\nHope that helps.  Good luck.
1053403
Write it as:\n2x^2-4x+3x-6\n=2x[x-2]+3[x-2]\n=[2x+3][x-2]\nSimple middle-term factorisation!!!