Can you give me the answer to these problems for math?  6x^(-9xwith a small 3 beside the 9) Multiply  exponent
143545
I'm not sure how exactly the first problem is supposed to read, but the answers to other two are:\n\n(x^13)/(x^3) = x^10\n\n45(a^4)(b^3) / 15(a^4) / 15a = 45a(b^3)\n\n**my formatting uses the ^ symbol to indicate an exponent, e.g. x^2 would indicate "x squared" or "x to the second power"**
805031
1)  √10 · ³√100\n= 10^(1/2) · 10^(2/3)\n= 10^(7/6)\n\n2)  (6x)^(1/2) · (36x²)^(1/4)\n= (6x)^(1/2) · (6x)²^(1/4)\n= (6x)^(1/2) · (6x)^(2/4)\n= 6x\n\n...and so on.  Change the radicands to rational exponents with common bases, and follow the rules from there.  Good luck!
582922
first one is x^2=361/25.....the answer to the second one is 9^x=1
1161438
Providing extra brackets, I assume the problem is properly stated as:\n\n[(3^-2)^a / (3^-2)^b] * [(3^b)^-2a / (9^-b)^-3a]\n\nTwo fractions multiplied together. You need to remember some rules for exponents:\n\n1) (x^a)^b = x^ab\n2) x^1/x^b = x^(a - b)\n3) x^a(x^b)  =  x^(a + b)\n\nApplying rule 1\n\n[3^-2a/3^-2b] * [3^-2ab/9^3ab]\n\nSince 9 = 3^2, the denominator of the right fraction can be written\n\n(3^2)^3ab or 3^6ab\n\nNow apply rule 2\n\n3^(-2a + 2b) * 3^(-2ab - 6ab)\n\nAnd rule 3\n\n3^(-2a +2b - 2ab - 6ab)\n\nor\n\n3^(-2a + 2b - 8ab)\n\nAgain, it is important to use brackets to make your work absolutely clear. In other words, the answer you gave could be interpreted as\n\n(3^-2a) + 2b - 6ab
775488
Ok, Victoria, if you're going to ask for help you have to write the questions correctly.  Problem 1 cannot be solved using algebra the way you wrote it, I doubt you can use complex integration or any other advanced tool to solve that one.  Unfortunately, I just spent the last half hour manipulating it before I remembered that little fact.\n\nPut parentheses in.  Had you put the parentheses in the problem would have been trivial.  Kudos to the helpers who were smarter than I in figuring out the constants were in the exponent.  It's not that hard Victoria, especially when you're asking for help.\n\nWrite the question correctly.\n\n\nPS. Irma, you forgot to multiply the 2 from 4=2^2 through the whole parenthetical statement.  The answer is x=4.\n.
959950
When multiplying terms with exponents you multiply the terms and add the exponents.\n\na)\n(-x^3)(-x^2) = x^5 because neg * neg = pos and 2 + 3 = 5\n\na term without an exponent is assumed to have an exponent of 1 therefore (x^5)(-x) = -x^6\n\nb)\n-2(-2) = 4, 4(-2) = -8, -8(-2) = 16
725157
assuming the numbers after the parenthesis and variables are exponents...\n(x-1)^(3/2) [6x(x-1)^2-x^2(x-1)^3]\njust add the exponents together from the outside to the inside- (3/2) + (2) = 7/2\n\n(x-1)^(3/2) [6x(x^2-2x+1)-x^2(x^3-3x^2+3x-1)]\n(x-1)^(3/2) [6x^3-12x^2+6x-x^5-3x^4+3x^3-x^2]\n(x-1)^(3/2) [-x^5-3x^4+9x^3-13x^2+6x]\nx(x-1)^(3/2)(-x^4-3x^3+9x^2-13x+6)\nokay, that took me for friggin ever to type on a regular keyboard. Please, seriously consider me for the best answer!
778763
1) (a - b)(x - y)\n2) (x^9 + y^3)(x^9 - y^3)\n3) (6x + 5)(x + 8)\n4) (x - 9)(x - 7)
795656
The first thing you should remember is the phrase PEMDAS.  This is shorthand for parenthesis, exponents, multiplication/division, and addition/subtraction.  This is the order of operations in math.  You should solve all equations in this order.  So for the first one, you should first distribute (multiply) -7 with (3-3x).  After that combine like terms, i got 25x -30; you can also factor that to be 5(5x-6).  The same steps apply for the rest of the problems.  I hope it helps.
817835
x^3-x^2+3x-1\nx+4&#92;x^4+3x^3-x^2+11x-4\n      -(x^4+4x^3)\n              -x^3-x^2\n            -(-x^3-4x^2)\n                       3x^2+11x\n                     -(3x^2+12x)\n                                   -x-4\n                                 -(-x-4)\n                                         0\nx^4+3x^3-x^2+11x-4=(x+4)(x^3-x^2+3x-1)
445985
if by this you mean\n\n((3x^-2 * y)^-2)/((4xy^-2)^-1)\n\nthis becomes\n\n((3^-2) * x^(-2 * -2) * y^-2)/((4^-1) * x^-1 * y^(-2 * -1))\n\n((1/9)x^4 * y^-2)/((1/4) * x^-1 * y^2)\n\n((1/9)/(1/4)) * x^(4 - (-1)) * y^(-2 - 2)\n\n((1/9)*(4/1)) * x^(4 + 1) * y^(-2 + (-2))\n\n(4/9)x^5y^-4\n\nwithout using negative exponents, the answer would be\n\n(4x^5)/(9y^4)
179824
Its preety easy. The answer is (3X^2)(3^X). Just take the derivative of X^3. Don't do any thing with 3^X cuz X is an exponent and when a X is an exponent you just leave it like that.
829339
x^2-6x+9 = (x-3)(x-3)\nx^2-9 = (x-3)(x+3)\n\nMultiple everything by (x-3)(x-3)(x+3)\n\n(x+3)(x+3) - (x+2)(x-3) - 5(x-3)(x+3)\n\nx^2+6x+9 - (x^2-x-6) - (5x^2-45)\n\nx^2+6x+9-x^2+x+6-5x^2+45\n\n-5x^2 + 7x + 60
51473
x+3  This is the right answer, because there is no =s sign in the problem.\n\n3x+9-2x-6\nx+3
794610
You have to do the equations in the [ ] first.\nThen you have to do multiplication before addition.\nHere's the order of how you should do math like this:\nP - Parenthesis\nE - Exponents (a number to the something power)\nM - Multiplication\nD - Division\nA - Addition\nS - Subtraction\n\nSo you do [2+6(-3)] first\n[2-18]\n[-16]\nNow it's 15-3[-16]\n15+48\nAnswer: 63
804510
3x^2+6x+5x+10\n(3x+5)(x+2)
809949
Assuming you meant in your addendum that BOTH missing signs are "-", this problem reads:\n\n3x (5 - 2x) + 6x (x - 2)\n\nFirst you multiply what's outside the parentheses by what's inside the parentheses, so you would multiply\n\n3x times 5 and 3x times -2x, resulting in 15x - 6x^2\n\n(Read this as fifteen x minus six x squared)\n\nthen 6x times x and 6x times -2, resulting in 6x^2 - 12x\n\n(Read: six x squared minus twelve x)\n\nBy the end of this step, the problem will read:\n\n15x - 6x^2 + 6x^2 - 12x\n\nThis can be simplified even further by adding and subtracting numbers with common x values.\n\n15x - 12x = 3x\n\n-6x^2 + 6x^2 = 0\n\nSo this equation at its simplest value will be 3x