how do u factor these problems 4x^3+36x^2+32x,-3x^2+27x-60, 25x^2-15xy+25y^2?
149556
4x^3+36x^2+32x----using common factor which in this case would be 4x so, 4x(x^2+9x+8) and then u use guessing method \nand the complete factorization would be 4x(x+8)(x+1).
757415
1) yes\n2) get rid of x factor, so -(x^3-1)/(x^2+1)\n3) You lost a negative, (2x+3)/(3-2x)\n4) Remove y factor: 7x/2y\n\nSteve
210100
Factor them out. \n2 = 2\n3 = 3\n4 = 2*2\n5 = 5\n6 = 3*2\nLowest common multiple = 2*2*3*5 = 60\nYou have 1 left over, so 60+1\n61.\n(2*30)+1, (3*20)+1, (4*15)+1, (5*12)+1, (6*10)+1
517819
start pulling out common factors\n\n2 (x^3 + 27)\n\n2(x^3 + 3^3)
18182
2x^2 + 5x + 20x + 50\n2x^2 + 25x + 50
1009982
a.   First multipy -2 times (x-4) to get -2x+8\nb.   Then 5-2x+8 to get -2x+13\nc.   then 3 times (-2x+13) to get -6x+39\nd.   then add 6x to both sides to get 39=8x+9\ne.   subtract 9 on both sides to get 30=8x\nf.   divide both sides by 8 to get x=(30/8) or (15/4)
774020
3x^2(5x^2 – 2x + 6) – 2x(x^2 + 3x + 9)\n15x^4-6x^3+18x^2-2x^3-6x^2-18x\n15x^4-8x^3+12x^2-18x\nx(15x^3-8x^2+12x-18)
696447
taking out common factors,the expression\n=3xy(4x-3x^4y-5y^3)/3xy\n=4x-3x^4y-5y^3
968026
I got   3(x² - 5x + 4) or 3( x - 4 )( x - 1 )\n\nLet me show you my work...\n\n3( x - 2 )² - 3(x - 2) - 6\n\nSimplify\n\n3( x -2 )( x - 2 ) - 3( x- 2 ) - 6\n\nDistribute\n\n3( x² - 4x + 4) - 3x + 6 - 6\n\nDistribute and Simplify\n\n3x² - 12x + 12 - 3x\n\nSimplify\n\n3x² - 15x + 12\n\nYou can now simplify by factoring out 3\n\n3(x² - 5x + 4)\nor\n3( x - 4 )( x - 1 )
801272
x³y - 3x²y - 10xy --- Take x and y out of each term...\nxy(x² -3x - 10) --- Factor the x² - 3x - 10\nxy(x - 5)(x + 2)\n\n*Note: To show exponents, such as x², use the ^ key (such as x^2). This expression looks like you basiclly wrote:\n3xy - 6xy - 10xy
571026
Whenever you have the difference of two squares\n\nF^2-S^2\n\nit factors as\n\n(F-S)(F+S)\n\nMemorize that pattern and problems like this will be a breeze.
371573
If i is a root, you may express it into x = i, a root of x^3 + i = 0.\nsince x = i, x - i = 0\nTherefore, x^3 + i has a root x - i. to get the other 2 factors, divide.\n(x^3 + i)/(x - i) = 0\nDivide it using long division, and you'll get\nx^2 + ix - 1 = 0\nActually, \nx^3 + i factors as (x - i)(x^2 + ix - 1) \ntherefore, \nx^2 + ix - 1 = 0\nuse the quadratic formula:\na = 1\nb = i\nc = -1\nx = [-b +or- sqrt(b^2 - 4ac)]/2a\nx = [-i +or- sqrt(i^2 - 4(1)(-1))]/2(1)\nx = [-i +or- sqrt(-1 + 4)/2\nx = (-i +or- sqrt -3)/2\nx = (-i +or- i sqrt3)/2\nTherefore, the other roots are\nx = (-i + i sqrt3)/2\nx = (-i - i sqrt3)/2\n\n^_^
835686
4x^2 + 3y^2 = 4\n8x x' + 6y y' = 0\n8 x '' + 6 y'' = 0\n6y'' = -8x ''\ny '' = -4x / 3
984033
2x+3y=4\n4x+3y=-36\nsubtracting\n-2x=40\ndividing by -2\nx=-20\nsobstituting\n-40+3y=4\nadding 40\n3y=44\ny=44/3
198742
28x^6 - 14x^4 + 35x\n(7x)*(4x^5 - 2x^3 + 5)
972476
........._______________\nx - 5 ) x³ - 3x² - 13x + 15 ( x²\n......... x³ - 5x²\n......... -------- ....↓\n............... 2x² - 13x ....... ( 2x\n............... 2x² - 10x\n............... ----------- ....↓ \n............... ....... -3x + 15. (-3\n............... ....... -3x + 15\n............... ....... -----------\n............... ....... -----------\n\nSo P(x) = x³ - 3x² - 13x + 15\n= (x - 5)(x² + 2x - 3)
911592
Factorize!\n4x (x^2-9) = 0\n4x (x+3) (x-3)\n\nyour solution is \nX = 0\nx= -3\nx= 3