Does  fiber rope have a greater tensile strength than metal?
142000
ok first off i'd like to point out that the navy uses 3 things that fit into the general category you are talking about\nrope (line)\nSteel cable (wire rope)\nChain (chain)\n\nit depends on what you are using each for.  i'm assuming now that you mean to tie off to the pier?  if not then please note it in the add details section.\n\nok the navy uses lines and sometimes wire rope to tie off to the pier however it is almost exclusively lines.  now if you are asking if one is stronger than the other than it depends on the size and material you are  talking about.  generally here's the breakdown and i'm not going to type in all of the increments cuz i really don't feel like it.\n\nusuallly the navy uses nylon lines as opposed to polypropylene and manila (marline) now a days though they are now trying to switch to kevlar (i'll get to that later)\n\nthese are the break pounds ratings for line vs wire rope\n\n       nylon......wire rope\n1/2"   6400.......18700\n1"     25000......72800\n1 1/2" 53000......160000\n2"     92000......278000\n2 1/2" 140000.....424000\n\nacross the board the wire rope is stronger yes but now look at it this way.  the navy uses 2 1/2" lines to tie off ships to the pier at 140000 lbs the wire rope equivalent would be 1 1/2".  now per 100 feet the line weighs 149 lbs\nthe wire rope weighs 360 lbs  its a matter of being able to handle the lines a 360 lb line is just to bulky and heavy also the mooring operation is very complex and wire rope kinks and twists in ways that tend to make it not easy to handle.  thats just for beginners now you have getting underway.  if pearl harbor happened again you think you're going to want to mess with 360 lbs of wire rope in a big tanged mess in order to get underway.  NO  you cut the lines loose.  then you have the issue of lines doing what is known as PARTING.  this is where the line (line here meaning MOORING LINE be it line or rope) breaks.  with nylon line you can install what is known as a tattle tale.  it is a smaller piece of line that is spliced into the line as the line stretches (and it WILL) if it is going to part.  the tattletail's will pop first giving warning to relax the line quickly or get the hell out the way.  when a nylon line parts it whips back like a rubberband at faster than the speed of sound it WILL KILL PEOPLE if they are in the WRONG place at the WRONG TIME.  now a rope whan it parts.  first you won't know it's coming cus there is very little stretch to a rope so no tattletail. second if you tried to put in a tattletail it would weaken the rope. now here's the kicker when a rope parts.  it not only snaps back but it also becomes in escence a shrapnel grenade.  there is no right or wrong place to be when a rope parts. IT WILL GET YOU.  and if it doesn't kill you.  you AIN'T GONNA BE HAPPY! remember i mensioned KEVLAR Lines?\n\nthe navy is switching to them cuz A: they weigh about the same as the Nylon does B: they are stronger C: you can put a tattletail in them without weakening them and D: when they part they simply drop down into the water. they don't snap back and kill people.  this is of course just the basics i'm not mensioning the myriad other reasons like chemical exposure rust etc etc...
653336
Tensile strength is the limit of a material to withstand tensile stress without causing failure to the material. Tensile stress occurs when a object is subjected to forces that make the object EXPANDS. Opposite of tensile stress is compressive stress.\n\nCommon example of tensile stress is pulling a rubberband and if the stress is beyond its strength, then the rubberband will break.\n\nMeanwhile, flexural strength is the limit of a material to withstand flexural stress without failing. If an object is subjected to flexural stress, it will undergo both tension and compression behaviour because of bending moment. Flexural strength of a material will depend on either its tensile strength or compressive strength, whichever is lesser.\n\nMost common example of a flexural stress is by bending an eraser into a U shape. The upper surface of the eraser will be subjected to compressive stress while bottom surface will undergo tensile stress. If you bend it further, you may see the bottom surface of the eraser will start to crack, which indicates that it the stress exerted to it is beyond its flexural strength.
1118699
Fatigue testing is not limited to testing samples at 80% of max tensile strength. It is also done at 50 up to 90%.\n\nBefore you can answer the why of fatigue testing, you must have an understanding of dynamic loading.\n\nNot all loads are dead loads(loads that does not vary in intensity). Some loads like in machine parts are dynamic loads. Loads that varies as the parts inside the machine moves.\n\nLets say that the max tensile strength of a material is 100 ksi. If we apply a load of 90 ksi of course the material can withstand it. But if we load, unload, load, unload, and so on this 90 ksi load, at some number of repeated applications the material will fail. This is the goal of fatigue testing. To test the number of repeated loading at which a material fails.\n\nFatigue testing is usually given in % of max tensile strength  with accompanying number of repeated load applications. And usually to get the proper behaviour of the material you must have the number of samples used. The greater the number of samples the more credible is the result.
1053942
depends on the type of metal
427198
I think I'm gonna look like I've got no clue whatsoever if I answer this one but, still, I'll give it a try risking my reputation. \n\nFirst of all, I didn't have a clue what you meant by a "buckyball", then I looked it up in a dictionary, now I know its a nickname for the C-60 Buckminsterfullerene. Thanks for adding one more word in my vocubulary (I desperately need a better vocubulary). \n\nNow, coming to your question, to determine the strengh of a rope made of C-60, umm.. I'll take a coward's way out by not going into the molecular constitution of the rope. As the physical strengh is an observable physical quantity, I'll solve the problem on a macroscopic scale. \nI'll hang a heavy mass with the help of the Carbon rope and will keep increasing the mass untill the rope ruptures.\nNow, I'll note down -\n1- The Weight (mass * acceleration due to gravity) that broke the rope.\n&\n2- The cross sectional area of the rope.\n\nNow, I'll just divide the Ultimate Weight by the cross sectional area of the rope to get the TENSILE STRENGTH of the rope.\n\nNow, I'll adopt the same procedure with the steel cable.\n\nI think, that way, we can easily compare the tensile strengths of the carbon & steel ropes.\n\nNow, to answer the second part, the density of the C-60 rope. Here too, I'll use a method that doesn't involve the molecular constitution of the rope (sorry again).-\nI'll use the Archimedes' Principle instead-\nLets first assign signs to the physical quantities-\nW = Weight of the Rope\nF = Buoyant force\nd1 = density of our rope\nd2 = density of the water (or the fluid in which you choose to immerse the rope)\nV1 = Volume of the rope\nV2 = Volume of water displaced by the rope.\ng = acceleration due to gravity\n\nTake the rope & put it into water (or any other fluid), now first see if it floats or gets submerged.\n\n\nIf it gets submerged, you can say that-\nW - F = (d1 - d2) * V1 * g \n(as the volume of the rope is equal to the volume of water displaced here)\nNow, knowing other quantites, we can calculate density of the rope!\n\nIf it floats-\nW = F\nd1 * V1 * g = d2 * V2 * g\n\nd1/d2 = V2/V1\n\nIf you take water as the fluid, d2 = 1000 kg/m^3
1019278
Titanium is NOT the strongest metal.  It is often thought of as the strongest but actually it has one of the highest strength to weight ratios.  I.e., for a metal that is so light-weight, it is extremely strong.  Typically it has a ultimate tensile strength of up to 170,000 psi.  Another unique property is that its strength does not deteriorate in high temperature applications. This makes it ideal for use in aerospace especially engine components. \nThere are many metals much stronger than this.  Two stainless steels that come to mind are 17-4PH and 15-5PH which can achieve Ftu of 180,000 to 200,000 psi through heat treatment.\nInconel 625 which is used in the aerospace industry, typically in the production of high-strength fasteners used in critical joints can achieve ultimate shear strengths of 220,000 psi.\nIntermediate alloy steels such as 5Cr-Mo-V has an Ftu of up to 280 ksi.  Also low alloy steel such as AISI 4130 used in aircraft landing gear has extremely high bearing strength, tensile and compression strength.
598430
Copper has a higher melting and boiling point and better electrical conductivity.\n\nIf you are a die caster, Zinc would be better because it can be easily pressure die-cast and hence better accuracy in the cast component with minimal metal removal for finishing.
352642
It makes a difference what the weight of the rope is, amonst other things.  This seems like an almost impossible problem to solve precisely.
255628
In the world of natural fibers, spider silk has long been recognized as the wonder\nfiber for its unique combination of high strength and rupture elongation. An earlier study\nindicated spider silk has strength as high as 1.75 GPa at a breaking elongation of over\n26%.[1,2]. With toughness more than three times that of aramid and industrial fibers,\nspider silk continues to attract the attention of fiber scientists and hobbyists alike. [3-1
718464
Everyone here, including the asker, is wrong.\n\nThe long rope will carry a greater load than the short one if the initial tension in each is the same.\n\nReason:  The long rope will DEFLECT more than the short, and the angle it makes with the horizontal will therefore be greater.  The greater the angle, the more upward load the rope will carry.\n\nTorque has NOTHING to do with this problem.  The nature of a rope is that is can ONLY support TENSION.  No bending (torque) allowed.\n\nI'll supply the equations in a while; I started scribbling them down, but they got a little hairy, and I wanted more time to sort them out so they're readable.  I like this problem; it's just that you assumed a particular answer was right a priori..........
1187223
Well, a clear question would help. \n\nAre you trying to calculate the power that a certain material can withstand?   Or are you trying to calculate strength?
71861
Fiber optic cables offer two big advantages over traditional copper in a network:  they are immune to electromagntic interference, and they can run much much further than copper without needing repeaters.  The bigest two disadvantages to fiber are that they are more expensive, and that the standards are still evolving.\n\nBoth of those disadvantages are going away, though, meaning that I strongly believe fiber is going to completely replace copper eventually.  Right now, many companies are "future proofing" by running fiber along with copper in walls so that if they need to upgrade to fiber in the future, it is already part of thier structured network.  Also, major backbones, either running between campuses or even just between wings or floors of a building are now more and more fiber only, because it just makes sense when you're already paying so much money to set up the backbone.\n\nThe source below is a tutorial on my company's website giving more details about fiber.
936613
Of course, aluminum wins as it has the lowest density.  The passivating oxide film makes aluminum non-corrosive, which is a great comfort to the metallurists and structural engineers responsible for keeping these birds in flight, rather than cracked up over an ocean.
317200
more likely iron then steel
904960
It is the best for metal woods because of the trampoline effect. They use steel in all the other clubs except for titanium for drivers and in a few fairway metals. Steel is very strong but it has no spring-like effect. Titanium is lighter and and is a trampoline. If you hit a titanium club very lightly, it will go absolutely nowhere. If you hit steel lightly, it will go farther, just like a trampoline vs. solid ground.\n\n\nTitanium has taken the world of golf by storm. Manufacturers of some of the world’s top golf clubheads have chosen to use titanium as their chief ingredient in assembling space age, state-of-the-art components. But why is this? \n\nThere are many materials as strong if not stronger than titanium. So why is titanium the material of choice? Titanium is not only one of the “hardest” metals known to man but unlike these other hard materials, titanium is extremely lightweight. Because of these weight characteristics, manufacturing advances have enabled clubhead designers to build drivers of ever increasing size while not being inhibited by added clubhead weight. \n\nThree different types of titanium are used in the manufacturing of today’s clubheads: 9-6AL-4V, 15-3-3-3 and SP700. There are 3 characteristics that are used to gauge the quality of each type of titanium. Tensile strength represents the material’s resistance to breaking or cracking. The higher the value the more resistant the clubhead is to cracking. Elongation is the percentage each type of titanium will flex or spring upon impact. The higher the percentage, the more spring each metal will experience. HRC Hardness is fairly self-explanatory, exhibiting values that correspond to the metals hardness. The higher this figure, the less likely the metal will dent or become deformed upon use. \n\nWhen evaluating the types of titanium and the figures used to do so, clearly noted is the separation between 9-6AL-4V and 15-3-3-3 / SP700. A golfer should avoid the purchase and use of 9-6AL-4V as the minimal cost savings (typically $20 to $40) do not warrant the inferior playing characteristics. As one can surmise, a clubhead made with 9-6AL-4V is much more likely to crack or dent through continued use. In addition, the elongation percentage is not nearly as high as the others mentioned therefore, a golfer would not experience the potential gains in distance/yardage that he/she would if using either of the other titanium’s. \n\nTitanium’s 15-3-3-3 and SP700 offer tradeoffs when considering which may be better to seek when making your next purchase. 15-3-3-3 has the highest tensile strength of the 2 but a smaller elongation percentage. Meanwhile, SP700 still possesses considerable tensile strength but does add a few percentage points in the category of elongation. How does this translate? SP700, through its’ higher elongation figure, can impart more spring upon impact and thus deliver more energy to the golf ball thereby increasing distance. \n\nSo what are the trade off’s? Simply put—dollars for distance. Though this figure varies widely, the SP700 titanium is typically a bit more expensive than the 15-3-3-3, usually on the order of $20 - $40. This amount is oftentimes minimized by using SP700 strictly in the face of the driver head. Also, the higher one’s clubhead speed, the more realized benefit that could be realized from the increased spring effect of SP700. Golfers with a lower swing speed may not notice substantial yardage gains when comparing the two and therefore may not wish to pay this premium. Truly though, it is hard to go wrong with using either titanium as both offer such incredible playing characteristics, such vast improvements over stainless steel \n\n\nHope this helps.
1005037
Tensile strength depends mostly on the strength of the inter molecular bonds or inter particle bonds.\n\nMaterials with small grain size tend to have better bonds than those with large grain size
769099
Iron is stronger and steel of course is stronger still.  Further, iron corrodes only if not cared for.  Copper will form a patina over time even if cared for.