2 objects 1 unstoppable 1 unmovable collide what is the outcome?
141401
All motion is relative.
711513
Hi!  You are right.\nIf they have equal masses and are elastic then  b) it is going to happen. Why? well Vf= 2*Vcm-Vi. Where all are vectors and :\nVf= final speed;   Vcm=center of mass speed ;  Vi=initial speed.\nThus 0=2*Vcm-Vi => Vcm=V/2=(m1V1+m2V2)/(m1+m2)=\n=m1*Vi/(m1+m2)  => m1=m2.    \n  " a)" isn't possible because the total momentum must be preserved.\n          Hope it helps!
788625
This is a momentum question.  If the end result is comming to a halt, then then each vehicles' momentum was equal and opposite.  Momentun (M) = mass (m) * velocity (v),  therefore you are left needing to solve the equation m1*v1 = m2*v2...you can do the rest I hope....
125621
B) Increase\n\nThe difference in the two objects' velocities would be constant since that are both accelerating at the same rate, but the first object already had a higher initial velocity (from Object B' point of view).\n\nThe equation relating the distance traveled with respect to initial velocity, accelertion and time is,\nd = v_i * t + 1/2 a*t^2\nSo for both objects, after B is released the 1/2 a*t^2 part of the equation is the same, so we can ignore that part and focus on the v_i * t part.\nIf we start t=0 at the moment object B is released, object A's velocity is some non-zero number while B has no initial velocity.  So as time goes on, the distance between the 2 objects inceases.
170385
There seems to be a missing varible of time. Without a time contraint there is an infinite number of times these balls will touch. I am not sure the minimum distance from the wall though. I guess it would have to be at least smaller than the size of the small ball so the two would actually collide.
913200
Both their accelerations will be the same and equal to the acceleration due to gravity, g=9.81 m/s/s...This is coz the only force acting on them is the force due to gravity
59102
If the bullet is fired in the horizontel direction, both object will reach ground at the same time.. because they are reaching ground due to vertical gravitational acceleration only which is same for both.\n\nBut if the bullet is fired in the downward direction and at an angle downwards, it will reach grounf first because it is having a initial velocity as well whereas the initial velocity for the other object is zero.. The reverse holds true if the bullet is fired upwards.
776706
It depends on whether the objects are completely elastic, completely inelastic, or somewhere in between. And also, did they hit square and were the velocities both on the same line or did they get deflected at a new angle. I'll assume they hit square and their velocities were on a line - like they were on a track.\n\nElastic:\nMomentum before = momentum after\nMa*Va + Ma*Vb = Ma*Vb + Mb*Va\n\nInelastic:\nM*Va + M*Vb = 2M(Va+Vb)/2
827118
We can't use conservation of energy because this is an inelastic collision. Conservation of momentum does hold, so\n\nm1*u1 + m2*u2 = (m1+m2)*v\n\nu2 is zero. So \n\nv = m1*u1/(m1+m2) = .24 kg*u1/2.85 kg = .084*u1\n\nThe projectile's incident kinetic energy \nKEp = (1/2)*m1*u1^2 = 0.12*u1^2 joules\nThe final kinetic energy \nKEf = (1/2)*(m1+m2)*v^2 = 1.42*(.084*u1)^2 = .0100*u1^2 joules.\n\nPercentage = 100%*KEf/KEp
759986
both will have same weight mass
514545
By their definitions, you can't have both.\nIf a force is truly unstoppable, then no object is unmovable.\nIf an object is truly unmovable, then no force can be unstoppable.\n\nThen again, the force may just pass through the object the way neutrinos pass through the earth.
386584
Either 1. The cat will explode with confusion\nor 2. The cat will land on it's side\nor 3. The cat will split in half so that it's back lads one way and it's feet land the other lol.
322347
it is the collision of two preasure sysems and the difference of the tempeture
854225
The extent of damage sustained is directly proportional to the amount of energy consumed. If in case a) the stationary car is allowed to move after the collision, then case a) is where the original car sustains the LEAST damage. \n\nDue to conservation of momentum, in case c) the velocity of the two vehicles will be zero after the collision. So vehicle 1 will have lost all of its energy and the energy will be converted into deformation (damage).\n\nIn case b) the velocity of the car will also be zero after the collision, so all of its enery will be converted into damage also.\n\nSo, in case a) the car sustains the least damage, in cases b) and c) the car sustains the same amount of damage.\n\nI am only looking at the damage to ONE vehicle in each case, not the damage to all vehicles.
206468
In elastic collision, energy is not lost.\n\nmv2 + MV2 = mu2 + MU2\n(1055 + 690) * (2.15)2 = 1055u2 + 690U2\n\nalso mv+MV = mu + MU\n(1055 + 690) * 2.15 = 1055u + 690U\n\nYou have 2 equations with 2 variables, solve them.
771396
Because gravity is the same - so it has the same effect on both objects.  The larger object will strike the ground with a greater force, but both objects will accelerate at the same rate.
54780
Two possibilities: They would remain at the point of their meeting forever or the unstoppable force would disperse into smaller unstoppable forces and move on in different directions.