How do you solve:4(9+6) two different ways?
147220
First you need to do 9 + 6 which equals 15 then multiply that by 4 and you would get 60. The second way that you would solve that is by distrubuting that means you multiply 4 x 9 which equals 36 then 4 x 6 which equals 24 and add them together 36 + 24 equals 60.
966048
(3ab^2)(3ab)^2\n(3ab^2)(9a^2b^2)\n27a^3b^4
500014
a. (x+9)(x-9)\nb.(t-2)(t+2)\nc. (b-12)(b+12)
67171
Use the distributive property:\n4*5x + 4*(-9) =24\n20x + -36 = 24\n      +36   +36\n20x = 60\n--------\n20    20\nx=3\nI realize you already have the answer but sometimes the path is more important than the destination...
8373
(([(4+4+4).(4+4)]+4)/4)*(4+4)\n\n(4+(4*4)).([(4+4+4).(4+4)]+4)
758829
a = 6 and b = 8\n6^2 + 8^2 = 36+64 = 100\n\nor a = 8 and b = 6\n8^2 + 6^2 = 64+36 = 100\n\nor a = 10 and b = 0\n10^2 + 0^2 = 100+0 = 100\n\nor a = 0 and b = 10\n0^2 + 10^2 = 0+100 = 100\n\nWithout any restrictions on a and b, there are infinitely many answers.
774020
3x^2(5x^2 – 2x + 6) – 2x(x^2 + 3x + 9)\n15x^4-6x^3+18x^2-2x^3-6x^2-18x\n15x^4-8x^3+12x^2-18x\nx(15x^3-8x^2+12x-18)
83408
6 because 6*7=42 and 6*9=54
873410
1.  (x + 9)(x - 9)\n2.  (t + 2)(t - 2)\n3.  (b + 12)(b - 12)
35579
5(x^4 -9) = 5(x^2 + 3) (x^2 - 3)
1106533
1) 6(x-4)(x-2)\n= 6(x^2 - 2x - 4x +8)\n= 6(x^2 - 6x + 8)\n= 6x^2 - 36x + 48\n\n2) (x+7)(x+4)-(x+3)(x+2)\n= (x^2 + 4x + 7x + 28) - (x^2 + 2x + 3x + 6)\n= (x^2 + 11x + 28) - (x^2 + 5x + 6)\n= x^2 + 11x + 28 - x^2 - 5x - 6\n= 6x + 22
347487
-6-9x=-9x-4\n-6=-4.....\nno solution?? whats so hard to that?
889893
2+7\n3+6\n9+0\n\nThat's it. They all add up to 9... I think that's what the question is asking.
636772
k=1/4 or k=2 or many more possibilities
957282
|3(x + 1) + 6| =18\nie |3x + 9| = 18\nwhence |x + 3| = 6\nThere are 2 different methods to solve such an equation\n\nOne is to use the definition that\n|N| = N if N ≥ 0\nand = -N if N < 0\n\nThe other is to use the propety that |N|² = N²\n\nMethod 1\nSo x + 3 = ±6\nWhence x = -9 or 3\n\nMethod 2\n|x + 3|² = 6²\nie x² + 6x + 9 = 36\nx² + 6x - 27 = 0\n(x + 9)(x - 3) = 0\nx = -9 or 3
954529
When solving these problems you want to simplify them on both sides of the equal signs as much as possible. first you plug in the number for the variable then you spread it out in the case of        3x(1+y)=9+z      you will plug in the numbers to get           (3(2))(1+4)=9+z    then 6(1+4)=9+z   then    6(5)=9+z  then 30=9+z  then you subtract the 9 from both sides  30-9=9+z-9  then you would get  21=z   i hope this helps you if you need more help teachers usually will if u ask
133517
the solutions is 7,8,3,2 or 7,6,5,2. The problem works with both sets of numbers.