How do I dilute epinepherine 1:1000 to 1:100,000?
141691
This is a simple ratio conversion.  A 1:1000 dose is 100 times more concentrated than a 1:100,000 dose.  All you need to do is to mix one part 1:1000 Epi with one hundred parts of saline.  For example you take 1cc of 1:1000 Epi and add that to 100cc saline, or 0.1cc of 1:1000 Epi and add that to 10cc of saline.
710157
ANSWER: 0.482 M\n\n\nEXPLANATION:\n\nM = mol solute / L soln\n\nTherefore, you need to find the mol of solute and L of soln to find M.  \n\nTo find mol solute:\n10800mg Na(1g Na/1000mg Na)(1mol Na/22.99g Na) = 0.4698mol Na\n\nTo find L of soln:\n1kg soln(1000g soln/1kg soln)(1ml soln/1.025g soln)(1L soln/1000ml soln) = 0.9756L\n\nUsing the two values found plug in to M = mol solute / L soln\n\n0.4698mol Na / 0.9756L soln = 0.482 M
397236
1mg /L is called  "ppm" ---Parts per million\n\nie.,  1ppm solution having 1mg of solute in 1L solvent
485893
Check on the internet for the ratios used by comercial factories, then prepare a solution from glycol and water in the given proportion. That's all!!!
264737
Dissolve the following in 800ml distilled H2O.\n8g of NaCl\n0.2g of KCl\n1.44g of Na2HPO4\n0.24g of KH2PO4\nAdjust pH to 7.4 or 7.6 with HCl.\nAdjust volume to 1L with additional distilled H2O.
63545
use sodium hydrolic solution
944773
The dilution formula is:\n\n(M1 and V1 are the concentration and volume of the stock solution; M2 and V2 are the concentration and volume of final solution.  M1 and M2 should be in molarities; V1 and V2 should be liters, but it doesn't matter as long as they're the same units)\nM1V1 = M2V2\n(12.0 M)(V1) = (2.50 M)(250.0 mL)\nV1 = 52.1 mL\n\n(C)
864626
1) Calculate the initial concentration of the H+.\npH = - log [H+] = 2, therefore  [H+] = 10 ^ -2 mol / liter\n\n2) Calculate the dilution factor.\nWe want to change the concentration from 10 ^ -2 mol / liter to\n10 ^ -4 mol / liter. Therefore the dilution factor is 100.\n\n3) Calculate the amount of water to add.\nThe dilution factor is 100. We therefore want to have 100 x 14.5 ml = 1450 ml after dilution. We therefore have to add 1450 - 14.5 = 1435 ml of water
864884
1: You wouldn't measure a dry powder in milliliters.  You can't really know exactly how much water to add unless the know the mls the dissolved drug take up.  You could add 10mls then QS up to 15 mls once it dissolved in the orginal 10mls.\n\n2 If the total volume of 2 grams is 15mls.  Then 7.5 mls added to 50 mls of NS or D5W would be the answer.\n\n3.  If the total volume is 100 mls then 100ml/60 minutes= 1.66ml/min. Of course, you would set up the pump in mls/hr which in this case is 100ml/hr...duh.  If the total volume is 107.5 mls then 1.8mls/min.
168296
http://allergies.about.com/cs/treatment/a/aa040802a.htm\nA saline solution for irrigation is easy to make. To make an isotonic solution (one similar to the salt content of your bodily fluids), mix 1/4-teaspoon salt in an 8-ounce glass of warm water and add a pinch (1/4-tsp.) of baking soda. Discard any unused solution.\nYou may chose to use filtered or distilled water if your water contains a lot of chemicals. Table salt can be used, but many prefer to use non-iodized canning or pickling salt.\n\nIf you do not want to make your own solution, you can also purchase sterile saline at your local pharmacy or grocery store. You can find it in the contact lens care section of the store. The purchased solutions, however, do not contain baking soda. Using baking soda improves the mucus-solvent properties of the solution.\n\n\nhttp://www.flatrock.org.nz/topics/lifestyles/consumer_tips_for_salt_use.htm
237268
.001565mol / .075L = .021M NaCl
542164
0.2x+0.5(300-x) = 123\n0.2x+150-0.5x = 123\n-0.3x +150 = 123\n-0.3x = -27\nx= 90\nyou will need 90 gallons of 20% saline solutions and 210 gallons of 50% saline solution to obtain the mixture.\nHope this helps!!!
1102382
You can dissolve it in water. Upto 7.4 g dissolves in 100 mL of water.  This solution will be acidic.
77503
in a standard lab pipette it takes 20 drops approx. to make 1 ml....sooooo 1/20 of a ml
741771
0.5M = 500mM\nv x c=v'xc'\nv x 500 = 50 x 1\n0.1mL of the 0.5M solution diluted to 50mL will be 1mM
1000408
Simply purchase a marked dropper from any pharmacy; 5 ml \nequals one teaspoon as any mom can tell you.
904391
For 1 Liter:\n\n0.03 * 1000mls = 30mls\n\nSo add 30mls citric acid to 970mls of water