how do you solve:  (2x^-2y^3)^2(-4x^2y^-6)/6x^9y^3   thanks?
150867
Your question makes no sense. There is no equal sign. What do you want to solve for? Why so many powers (a^b means a to the power of b)?
1124767
9a*a+6a-4b*b+1\n= (9a^2+6a+1)-4b^2\n=(3a+1)^2-(2b)^2\n=(3a+2b+1)(3a-2b+1)
617827
3x^3y^2z^4\n\nbecause you divide the exponents by 4, but do the fourth root of the coefficient 81
1002101
factor 9x^2y^2-9y^2\n9y^2(x^2-1)\n9y^2(x+1)(x-1)
709461
2x^2-6x+3\nuse this formula\n-b+or-root b^2-4ac/2a\nIn this case \na=2   b=-6    c=3\njust substitute this value in above formula\nYour answer must be\n3+root3/2     3-root3/2
810055
x^2 - 2x + y^2 + 2y + 2 = 16\n\nx^2 - 2x + 1  + y^2 + 2y + 1 = 16\n(x - 1)^2 + (y+1)^2 = 16\n\nCenter = (1, -1)\nRadius = sqrt(16) = 4
586962
(6y^2-3y)(y+7)-->(2y)(y-1)(y+7)\nif that helps
905134
2x - 3y - 6 = 0\n\n2x - 3y - 6 + 6 = 0 + 6\n\n2x - 3y = 6\n\n2x - 3y + 3y = 6 + 3y\n\n2x = 6 +3y\n\n2x/2 = 6= 3y/ 2\n\nx =  6 + 3y/2\n\n- - - - - - - - - -s-
232592
2x = 3y - 4y + 5 - 2\n2x = -y + 3\n2x + y = 3
541499
2x(x-5)-3(2x+1)\n2x^2-10x-6x-3\n2x^2-16x-3
1091081
64x^6 - 576x^5/y^2 + 2160x^4/y^4 - 4320x^3/y^6 + 4860x^2/y^8\n- 2916x/y^10 + 729/y^12\nIt's the same as mine except I put the y's in the denominator...but that doesn't matter.
287717
-4y^+8y+3y^2-6\n-4y(y^2-2)+3(y^2-2)\n(-4y+3)(y^2-2)\n\ndoes that make sense?
928756
m^6-n^6=(m^3+n^3)(m^3-n^3)\n(m^2-n^2)(m^4+m^2n^2+n^4)\nm^4-n^4=(m^2+n^2)(m^2-n^2)\nplugging in\nm^6-n^6/m^4-n^4\n=(m^4+m^2n^2+n^4)/(m^2+n^2)
1148686
(2y-8)(y-4)\n\n2y^2-8y-8y+32\n\n2y^2-8y^2+32
812732
2^(4x) - 4(2^(2x)) - 12 = 0\n\nFirst, note that 2^(4x) is equal to (2^(2x))^2\n\n(2^(2x))^2 - 4(2^(2x)) - 12 = 0\n\nThen, solve it like a quadratic.  Let y = 2^2x and you get:\n\ny^2 - 4y - 12 = 0\n(y - 6) (y + 2) = 0\n\ny = 6\ny = -2\n\nSubstitute y = 2^(2x) back to get\n\n2^(2x) = 6\n2^(2x) = -2\n\nYou can throw away the second equation because you can neve get a negative result from 2^(2x).  So we just deal with the first one.\n\n2^(2x) = 6\nConvert to logarithmic form\n\nlog[base 2](6) = 2x\nx = log[base 2](6) / 2\n\nThat can be simplified even more, but I'll leave that assignment up to you.
829339
x^2-6x+9 = (x-3)(x-3)\nx^2-9 = (x-3)(x+3)\n\nMultiple everything by (x-3)(x-3)(x+3)\n\n(x+3)(x+3) - (x+2)(x-3) - 5(x-3)(x+3)\n\nx^2+6x+9 - (x^2-x-6) - (5x^2-45)\n\nx^2+6x+9-x^2+x+6-5x^2+45\n\n-5x^2 + 7x + 60
817835
x^3-x^2+3x-1\nx+4&#92;x^4+3x^3-x^2+11x-4\n      -(x^4+4x^3)\n              -x^3-x^2\n            -(-x^3-4x^2)\n                       3x^2+11x\n                     -(3x^2+12x)\n                                   -x-4\n                                 -(-x-4)\n                                         0\nx^4+3x^3-x^2+11x-4=(x+4)(x^3-x^2+3x-1)