Mathematica's "Calculus WIZ"?
140162
Mathematica is to symbolic calculus what the calculator is to arithmetic.\n\nIt is an extremely powerful tool that if used correctly can relieve one from the tedium of having to sift through the bookkeeping of solving a problem.\n\nOn the other hand, using it as a crutch by someone who has not yet mastered the basics will be harming themselves by relying on something else to do the heavy lifting for you.\n\nSo short answer, if you are working on a project and have developed a complicated model to simulate a system, it will be useful where a hand solution would be difficult or impractical. If you are looking to solutions to your homework, you will be harming yourself.
113770
http://mathforum.org/library/drmath/sets/high_calculus.html\n\ngood luck...
221164
to get an extra credit, maybe?\n\n---\n\nseriously, I cannot figure out how you can study calculus without knowing limits: even if you only deal with numerical procedures, every iterative formula, or better, EVERY FORMULA (such as those used to find the roots of a non-linear equation, approximated integrals, derivatives and so on) needs a preventive study for convergence conditions: this involves limits!\n\nOne more step back: DERIVATIVE IS A LIMIT ! How can you apply it without knowing what it is?
66376
Absolutely. Wikipedia has a whole open source, online, calculus book,  http://en.wikibooks.org/wiki/Calculus.  Here you can find many examples of different calculus problems and their solutions.  Alternatively, the software program Maple is capable of solving many math problems including calculus problems.  Stick with Wikipedia's calculus book though if you want to learn calculus online.
875394
Very understandable....I just posted a question about my pre-calculus homework and i didnt ask for the answer, i just need help finding how to get it....i'd like to know how to do it myself, i dont just want someone to tell me the answer....does me no good @ all!
207651
http://mathworld.wolfram.com\nhttp://en.wikipedia.org/wiki/Mathematics
492613
Just do a google search.  Here are some:\nhttp://www.tucows.com/preview/216584\nhttp://www.filesland.com/software/pre-algebra.html\nhttp://www.adders.org/maths.htm\nhttp://freewarehome.com/bb/index.php?action=vthread&forum=3&topic=19
79903
Here is an excellent site:\nhttp://www.sosmath.com/calculus/calculus.html\n\nVery thorough explanations and examples provided.
908083
Tried to do it algebraically, that was a booger.\n\nI plugged that into mathematica and it gave me an error normally generated when the inverse of a function is needed to represent a solution and the solution variable occurs in more than one argument of that function.\n\nThat one might not have a solution?
147855
Try http://integrals.wolfram.com/
30751
The Edifier has it right, but darned if I can follow the notation. You really need to see this written out like a textbook to understand what's going on.\n\nClick the link below in "sources" to see the answer hosted at my website www.calculus-help.com. Right now, Yahoo! answers, as far as I can tell, doesn't allow graphics, which makes it tricky to answer ANY math questions.\n\nPlease don't post math answers, guys, if the poster knows the answer but can't get there, and you get something completely different.
438371
same thing as (8x^2+2x-2)^(3/2), right?\nso add one to the power\nmultiply by the inverse of that power\nand divide by the derivative of what's in the parenthesis on the left\ngot it?
176564
http://www.math.com/\nhttp://mathworld.wolfram.com/\nhttp://www.calculus-help.com/\nhttp://math.about.com/od/calculus/
880047
I can find this on a TI-84+, is that how you want to get it or do you need an algebraic solution?
785120
http://www.freemathhelp.com/forum/viewforum.php?f=9\nhttp://www.purplemath.com/modules/
183373
Try the inside cover of your Calculus book - it usually summarizes the rules for derivatives and some key integrals.
933478
Using the Wolfram Integrator:\nhttp://integrals.wolfram.com/index.jsp\n\nOne obtains\n1/10 sec(2x)tan^4(2x) + 2/15 sec(2x)tan^2(2x) + 4/15 tan(2x)\n\nUsing the other poster's logic - you get (u^2 + 1)^3