suppose that the following people want to a camp: 27 boys, 15 city children, 27 men, 21 noncity boys,?
153320
27 boys - 21 noncity boys = 6 city boys.\n18 city males - 6 city boys = 12 city men.\n27 men - 12 city men = 15 noncity men.\n\n15 noncity men + 21 noncity boys + 21 noncity females = 57 noncity people.\n\n57 noncity people + 42 city people = 99 people.
124643
all depends on your location and how many kids you want to tke care of.
641571
7 IS UNSATISFACTORY AS A SOLUTION (3B, 4G) because girls will have 3 brothers not 2 and boys will have 4 sisters not three. It needs to be expressed as "each child has five brothers and sisters", and the answer is then 6.
530167
Water slide theme park like the Atlantis in the Bahamas,get the kids and the parents will follow.Like the parents and kids going to separate summer camps together.Have a package that they can be separated for a couple of days and together for a couple before going back home.\nIf you're hiring,I'm a carpenter/home builder that would definitely relocate there.
835888
Basing this on rough statistics you'd be looking at a maximum current population of about 60 million, give or take a million.  That is of course assuming that all other aspects remain the same.
607618
There are a lot of boys and a lot of girls in grades 7-12. This sounds more like a homework assignment that you are trying to get us to do for you. Good luck with your research.
1006209
Children 10+ and adults          60-100\n\nWell conditoned athletes         40-60
706840
So what about the millions that are already there. As a matter of fact all of the muslims involved in the bus bombings were native born. Are you suggesting they be put in camps or something. Before offering silly questions think about it, okay??
194085
In the experiment of choosing a committee of 6 from a group of 8 women and 7 men,\n\nTotal no. of possible choices \n= no. of ways in which the 6 members of the committee can be chosen from the total 15\n==> n = C(15,6)\n==> n = 15*14*13*12*11*10/6*5*4*3*2*1\n==> n = 7*13*11*5\n==> n = 5005\n\nLet "A" be the event of choosing the committee with 3 women and 3 men\n\nFor Event "A"\n\n---------- Men----Women---Total\nAvailable---8-------7------15\nTo Choose---3-------3-------6\nChoices----C(8,3)-C(7,3)--C(15,6)\n\nNo. of favorable choices\n= (no. of ways in which the 3 men can be chosen from the total 8) * (no. of ways in which the 3 wommen can be chosen from the total 7) \n==> m(a) = C(8,3) * C(7,3)\n==> m(a) = 8*7*6/3*2*1 * 7*6*5/3*2*1\n==> m(a) = 8*7 * 7*5\n==> m(a) = 1960\n\nProbabilty of choosing the committe with 3 women and 3 men \n==> Probability of occurance of event "A" = m(a)/n\n==> P(A) = 1960/5005\n==> P(A) = 392/1001\n\n\nhttp://www.futureaccountant.com/probability/study-notes/\n\nhttp://www.schoolingkids.com/
209520
It all depends on the number of children and their sex. If you have two, one boy one girl than you will get a three bedroom. If you have two boys or two girls than you will most likely get a two bedroom.
205196
11 players\n1 goelkeeper\n10 field players
1043419
None.\n\nThey are either men, dead, or too young
766162
My main objection is that these people are being housed in a sweet Caribbean tourist vacation spot rather that being hung from lamposts in NY and DC.  My suggestion for housing them would be that their ashes be used as filler for urinal cakes.  The urinal cakes would be used exclusively in the boys bathrooms of elementary schools, so that they could be with the apocryphal "72 virgins."
138694
each child can be a male or a female \ntherefore the total no of events possible is 2^6=64\n\nthe question says that you should have atleast 3 girls \ni.e there can be three, four ,five or all six girls .\n\nthe number of ways of choosing 3,4,5,6 girls from 6 children is the sum\n6C3 + 6C4 + 6C5 + 6C6 (here C stands for combinations )\n\ni,e\n\n(6*5*4)/(3*2*1) + (6*5*4*3)/(4*3*2*1) + (6*5*4*3*2)/(5*4*3*2*1) + 1\nthis reduces to \n20+15+6+1\n=42\n\ntherefore the probability is \n42/64
930557
Either we have BBBGGG or GGGBBB. In both cases, there are 3! ways of arranging boys, and 3! ways of arranging girls. So 3!*3!*2 = 72.
1180468
3 helpers and Charles will start the trip so collectively they are having 4*5=20 dayz supply.\n\nAfter day one: one helper will start back with one supply for himself, leaving 15 for other three (20 - 4 -1)\nAfter day two: second helper will start back with two for himself,\nleaving 10 for other two(15- 3 -2)\nAfter day three: third helper will start back with three for himself leaving 5 for Charles (10 - 2 - 3)\nWith these 5 supplies Charles can cross the desert.\n\nThis is the minimum possible result, you can have any number more than that.
527572
you got the right answer already.\n\nit's 50%.  Doesn't matter if you have 75 girls, it's still 50% chance that the next one will be a boy.