How do they get ice to freeze sideways on the luge track, and do they resurface it between runs and if so how?
153508
They use a fine mist spray and build the ice up a fraction of an inch at a time.  It is time consuming but works really well.
141256
Clapper Skates are used in the Speed Skating but sideways ski jumping? That's a new one on me.
971810
If the water is already frozen and you remove more heat, all you will get is colder ice.  Otherwise, we need to know at what point is it at in the latent heat of fusion.
51698
Here is a try section the area off with wood trenches covered with plastic  so the excess water goes into the trench waterhose that section down. It should freeze over in the right weather. (Make sure the plastic is tight so when laying it place the wood blocks on top of it.
892217
take the ball out of the bottom of the mouse and clean the runners, they get crap stuck round them. just scrape it with your finger nail and blow it out.
384592
when you pour water on the ice, the ice has layer of water around it, but its still really cold. when the new water stays next to it, the ice cube freezes the water around it, if two ice cubes are touching, they will freeze the water between them and stick to eachother
270183
Those are soooo painful and frustrating.  They may never go away completely.  All you can do is to rest, use lots of ice and stretch plenty before running.  I developed them a few years ago and they have not left yet.
111671
This is your lucky day!  I used to teach skating lessons back when people skated on 4 wheelers.  I'm assuming they still come equipped with a rubber toe stop on the front.  The first thing to learn is to drag the toe stop behind you while skating forward and slowly bring yourself to a stop.  Once you've mastered this, you'll realize how geeky it is.\n\nThe next thing to do is to learn how to skate backwards.  Starting at a standstill with your toes pointed together, force your feet apart in an outwards motion and then bring them back together again.  Sort of like doing an hourglass over and over.  This will get you going in a backwards motion.  To stop, simply lean forward on both toe stops.  It's fun when you're going fast.\n\nAs you become better, you'll learn how to stop without the toe stops when you're skating forward.  One way is to drag one foot behind the other in a sort of t-shape.  So instead of dragging the toe stop, you're dragging the inner front and rear wheel of the skate that's stopping you.\n\nEventually, you'll learn how to stop much the way skiers do, by turning both skates sideways and catching the inner edge of the right foot and the outer edge of the left foot at the same time.
814294
Since no energy is lost to friction or any other forces, this problem can be solved using energy methods. The energy in the compressed spring is simply:\n\nEs = 1/2 * k * x²\n\nAs the spring expands, it does work on the ice cube to speed it up. However, not all of the energy in the compressed spring is converted into kinetic energy of the ice cube. Note that gravity will pull the ice cube down the ramp according to the equation:\n\nF = m*g*sin(theta)\n\nThe energy imparted from the spring to the cube will be equal to the spring energy MINUS the work done against gravity. YOU HAVE TO TAKE INTO ACCOUNT THE NEGATIVE WORK DONE BY GRAVITY! This work is:\n\nW = F * x\n\nW = m*g*sin(theta) * x\n\nTherefore, the net energy imparted to the ice cube by the spring is simply:\n\nKE = Es - W\n\nKE = 1/2 * k * x² - m*g*sin(theta) * x\n\nThis is the kinetic energy of the cube after leaving the spring. Since no other forces are present, once the ice cube reaches its maximum height, its potential energy will be equal to its initial kinetic energy:\n\nPE = KE = 1/2 * k * x² - m*g*sin(theta) * x\n\nPotential energy is simply:\n\nPE = m*g*h\n\nm*g*h = 1/2 * k * x² - m*g*sin(theta) * x\n\nwhereh is the height of the block above the surface. Using simple trigonometry:\n\nh = L sin (theta)\n\nwhere L is the distance the ice cube travels up the slope after leaving the spring. Substituting this expression into the potential energy relation provides:\n\nm*g*L sin (theta) = 1/2 * k * x² - m*g*sin(theta) * x\n\nSolving for L:\n\nL = (1/2 * k * x² - m*g*sin(theta) * x) / (m*g*sin(theta))\n\nFinally, substituting all of the known values yields the answer:\n\nL = [(.5)(23 N/m)(.12 m)² - (.053 kg)(.12 m)(9.81 m/s²)sin(35°)] / [(.053 kg)(9.81 m/s²)sin(35°)]\n\nL = .4353 m\n\nThe ice cube will travel 43.53 cm up the ramp after leaving the spring. Hope that makes it clear! :)
657783
water won't expand the ICE will. otherwise its not frozzen...I'm sorry that was nit picky. *hides in corner*
660432
Cold water is the best in this situation. Ice is too cold and can damage the surrounding area.
700792
ICE..keep the ice on it for a while trust it works FAST
1088911
Freeze it in a block of ice....
116261
I think what you're thinking of is the depth of the grind - otherwise known as "Radius of Hollow" (or ROH). The deeper the hollow, the more grab you'll have on the ice.  The shallower, the easier it will be to glide.  ROH is typically anywhere from 1/2" to 5/16", but most shops I know of grind at 3/8"
886324
Think of it like this, if you have a car on ice, there is no friction. The wheels will spin, but the car won't go anywhere. If you have a car on pavement, the wheels spin and the car moves. This is  because the friction where the wheel is touching the pavement doesn't move. Instead,the wheel to rotates and the next part of the wheel touches the pavement and 'doesn't move'.\n\nHope that makes sense. I was never all that good with physics.
66867
Don't...It will kill the grass where you have the ice.\nWe did this several years ago, and it took three years of seeding, and weeding to get it fixed!!
84470
track took some rain this weekend. It was probably sealed and will be speed biased. play front runners