how do you calculate fertilizer for turfgrass applications?
143681
yeah, what kunwarrara said
190048
After looking at some related websites, I assume you mean "topsoil by the cubic yard" when you say "topsoil by the yard" and "4 cubic yards" instead of "4 yards". \nYou need to know the density of the topsoil in order to change mass into volume, as density = mass/volume.\nAccording to the USGA specification, the bulk density of topsoil should be between 1.25 and 1.45 g/(cm^3). At sea level, 1 gram is about 2.205*10^(-3) pounds and 1 cm = 1.094*10^(-2) yards, so 1.35g/(cm^3) = 1.35g/(cm^3)*(2.205*10^(-3))pounds/gram*((1/(1.094*10^(-2))cm/yard)^3 = 2273 pounds/(yard^3).\nSo 4 cubic yards would be 4*2273 pounds.
707973
You have to start with a balanced equation.  The subscripts will give you the correct charge and a prefix will give you the right amount of atoms on each side of the equation.  Some elements, like O, F, and I are diatomic and come in pairs.
262763
The best way to figure out yardage is to stand on the 100 yard marker. Guess about a half way point where its 50 yards, and then say your inbetween the 50 and 100, your about 75, or say you inbetween the flag and the 50, about 25
692391
frut flog - golf turf
672778
If it is just about vertical infiltration, you can use Green-Ampht equation or simply Darcy's law if the soil is saturatted.\nThese require, soil properties such as porocity, field capacity, hydraulic conductivity and rainfall intensity.\n\nFor more realistic and regional studies, you can use \nWater balance method, Penman-montith method, \nThe above require all sorts of meteorologic information including solar radiation. The water balance method is much simpler but you need a long-time record. P=M method is very complex so you'll be better off to use HELP 3 model that kind of automates the process. This DOS based model can be downloaded at USGS website.
637181
I dont know the exact calculation but this site might be able to help you.\n\nhttp://www.fseric.demon.co.uk/skills/salinity.htm
871442
Agricultural chemistry includes the application of chemical fertilizer.\n\nWater quality.\n\nThis might help:\n\nChemistry Information from the Center for Food Safety and Applied Nutrition and FDA\n\nhttp://www.cfsan.fda.gov/~dms/chemist.html\n\nhttp://chemistry.about.com/library/weekly/aa082101a.htm\n\nhttp://en.wikipedia.org/wiki/Food_chemistry
329671
Hmm, you are in luck.  I am a biologist/chemist with a little ecology and botany knowledge and I might be able to help you out here.  But in the future, procrastination is not the answer.  Trust me, I know.\n\nAnywho, on with your project.  And, kudos to your teach.  He is getting you ready for college.  Lets see, you are wanting to germinate seeds.  It would be feasable to choose seeds with very quick germination times as probably you don't have a very long time to perform this experiment.  Some grasses will germinate in as little as 7 days.  With a little research, you can find your own seeds to use.  Next, you are going to have to decide what treatments you want to apply to each group.  And by each group, you need to have more than one "cup" of seeds, more like 4 or 5.  That is for replication.  By treatments, you could use things like adding different types of fertalizer in each group.  Use fertalizers that differ in the amount of phosphourus, nitrogen, and potassium (3 primary nutrients required by plants.)  Then, with multiple groups recieving the same kinds of fertalizer, vary the amount of sunlight (preferably artificial, like an incandesant lamp) and amount of water given.  What you will end up with is something like this:\n\nfertalizer A - 15 cups; each cup gets 1 tb of fertalizer\n      Cups 1-5 get 10mL of water and 12 hrs of "sunlight" daily\n      Cups 6-10 get 10mL of water and no "sunlight" daily\n      Cups 11-15 get no water and 12 hrs of "sunlight" daily\nRepeat this for say, 3 or 4 different types of fertalizer over a 10 to 15 day period.  Also, have 15 cups that follow the above procedure but get NO fertalizer.  After the 10 to 15 days, compare growth of the plants by measuring (probably in mm) the amount of growth produced.  \n\nBy performing a little research of your own and whatever plant seed you decide to use, you can base your hypothesis on how each fertalizer "should" affect your seeds and how much they "should" grow.\n\nFor example, lets say nitrogen is the main nutrient needed by grass.  Any of the fertalizers used that are low in nitrogen would not grow as much as the ones that get the nitrogen.  And those that do get the nitrogen, the ones that get water and sun will grow more than the others that get only sun or only water.  So, your hypothesis would be something like this:  The seeds that recieve adequate amounts of light, water, and nitrogen will have more growth after x amount of days than the other plants.  Then, you perform the experiment and see what you get.  \n\nGood luck on your experiment and if you remember, let me know what your teach thinks and what grade you get!
158796
I assume you know what osmosis is.\nIt would be nice to end up with enough results to plot a graph (LINE graph) so you will need at least four (more is better) solutions of different concentrations. Sucrose solution is usually used.\nUse a BIG potato so that all your samples are as similar as possible.\nThe easiest way to get uniform samples is to cut cylinders with a cork borer, then cut into 5mm disks.\nPut 10 discs into each solution.\nWeigh 10 discs before they are put in, then CAREFULLY blot them dry and reweigh them next day.\nCalculate the change in mass per gram of potato (you could expect some to gain, some to stay the same and some to lose so you will get some negative values).\nPlot a line graph of 'change in mass per gram of potato' AGAINST 'concentration of solution'.\nNow you must consider what the graph show you.
1111477
First you have to work out the number of moles or grams of the material you are making from the amoults you are using.\n\nWhen from the purifed form of the compound you have obtained the formula is\n\n% = A/B * 100%\n\nThere B is the theorical amoult in grams or moles you would produce at 100%\nand A is the amoult produced in grams or moles.\n\nNote make sure your calcurations are in one unit grams or\nmoles but not mixed.
444216
Write the Kc and the Kp\n\nChange PV=nRT to P/RT=(n/V) to P/RT=(concentration) note n/V is concentration.\n\n\nSubstitute P/RT for each concentration in the Kc.  You will see the Kp in the equation with extra R's and T's.  Finaih solving.
527802
N(Nitrogen), P(Phosphorus), K(Potassium)
695903
Depends on the industry.  No set formula that I know of.
273275
Well you can estimate COD by using K2Cr2O7. Add excess to the sample. Then titrate with FeSO4 to get the end point. Then run a blank titration. The difference in amount will give you the requred quantity of K2Cr2O7 required for the titration giving you the COD. The titation link is given below. \nThe method for COD is given in the second link. \nThanks\n\nHope to get voted the best!!
556576
Dig a hole. \nBurn it. \nUse it for fertilizer.
498327
Multiply the number of cubic feet by 7.481 to get the number of gallons (U.S.). \n\nThis formula applies to "liquid gallons", which are the kind commonly used today.