By what number should (-4) raised to the power 5 be divided to get the quotient 4 raised to the power -2?
146483
-4 ^7= -16384. they are wrong  it is not 1/16\n\n-4^5/x = 4^-2 \ncross multiply\n-4^5=x/16\nthen cross mutiply again\n-4^5*16= -4^7 =x
24322
2.4 (n - 1) = 12\n->(n-1)=12/2.4\n->(n-1)=120/24\n->(n-1)=5\n->n=6\n\nKeep Asking
18481
firt you work the problem in the parentheses. that would be (2*-5)+ 4. that would make it -10+4. that equals -6. then you take that and multiply it by -5. that gives you a positive 30
879678
The first thing to do is to find the factors of the number you're taking the root of.\nFor example, teh factors of 24 include 2*12, 3*8, and 4*6.\nSince four is a perfect square (2^2), we'll use that set of factors.\nSo:\nsqrt(24)= sqrt(4*6)= sqrt(4)*sqrt(6)= 2sqrt(6)\n\nSame with sqrt(18):\n18=9*2\n9=3^2\nsqrt(18)= sqrt(9)*sqrt(2)= 3sqrt(2)\n\nsqrt(3) +sqrt(3) can only be reduced by realizing that it's\n2*sqrt(3), which could be the sqrt(12). THis is because you can take the two under the radical by squaring it. so  you get sqrt (2^2+3)= sqrt(12), but technically 2sqrt(3) is more reduced.\n\nsqrt(27)=3 sqrt(3)\nsqrt(12)= 2 sqrt(3)\nso 3sqrt(3) + 2sqrt(3) = 5sqrt(3)\nin this case, you're treating the sqrt(3) sort of like it was a variable. think of 3x +2x = 5x
958505
x={-(-4) (+/-)√[(-4)^2 - 4(1)(-5)]}/(2(1))\n x= 4(+-)6/2\n x=5,   x=-1\n\nCheck:\n with x=5,  5^2-4(5)-5=25-20-5=0  OK\n with x=-1   (-1)^2 -4(-1) -5 = 1+4-5=0  OK
801068
-4(-1)^2 - 3(-1)\n-4(1) - -3\n-4 + 3\n= - 1
716170
since 2 is a root you take (x-2)*(x-2) and -3 is one also so you multiply (x+3) now you know it is a fifth degree so you need two more so you can take (4x^2+1) and multiply\n(x-2)(x-2)(x+3)(4X^2+1) you do the algebra
438101
Yes, in order to get a negative number after a positive number of multiplications or divisions, you must have the imaginary root of -1, or i. So if A x A x A x A equals a negative number, than A must be a real number with i.  In this case, it's  2 to the fourth power, or 16, and since it's -2, therefore it must be 16i.
858963
The answer is actually much more complex than one would think! The correct answer though is ...\n\n((2^n)(n-.5)!)/(2(.5!))\n\nThat looks kind of messy, so in English that is "2 to the n times n minus 1 half factorial over 2 times 1 half factorial."\n\nPlugging in 1,3,5,7 for n on a graphing calculator, we get 1,3,15,105, which are the correct first four terms in the sequence.
737484
5^-2 = (1/5)^2 = (1/5)*(1/5) = (1*1)/(5*5) = 1/25
81890
it's not factored completely if you leave it as a^2-25 so the proper answer is 5(a-5)(a+5)
1008674
You got it right so far. But next...to multiply by 1/4...is the same thing as dividing by 4. So take 4x^2/4=x^2 and then -4/4=-1...so you get x^2-1...make sense? I hope I helped...God bless.
559152
are u sure its not supposed to be the other way around. Cuz that would make a little more sense.\n\nBut if not, then it would probably be:\n1 + ((4s squared - 11) / (s to the 4 - 3s squared -11))\n1 the quotient. the rest the remainder.
1086560
f(-2) = 5. What's so difficult about this question?
225094
Either X with the upper value -4, or 1/x to the fourth power.
552485
(4)(1)(-10)=\n(4)(1)=4(-10)=-40
1149797
The first one is (-5, 3). I don't remember how to do the others.