citric acid sodium hydroxide reaction?
152537
Citric acid is a weak acid, while sodium hydroxide is a strong base. The sodium would fall off the hydroxide (because it's strong), so the reaction would be:\n\nHC6H7O7 + OH- --> H2O + C6H7O7
1070616
mix concetrated sulphuric acid to the sodium acetate, the reaction will produce acetic acid and sodium sulphate.\n\nif you take all the water out of the sodium acetate, you will end up with 100% pure acetic acid.\n\nH2SO4 + CH2COONa => CH3COOH + Na2SO4\n(unbalanced equation)
572470
a.  4H20 + 4NO2 + 02--------->4HNO3 + 2 H2O\n      Al(OH)3+ 3HCl------------> AlCl3+ 3H2O\nb. not sufficient as Al(OH)3 is 12/78 moles which is able to react with .462 moles of HCl and here we have .9444 moles of HCl\n\n9. it is done by equilliberium reaction\n and u written Na reaction with H2 to form hydride
745644
H3PO4 + 3NaOH ----> 3H2O + Na3PO4
972791
HCl + NH4OH → H2O + NH4Cl.\nThere would be heat given off, so you could verify that a reaction took place.\n\n2HCl + Ca(OH)2 → 2H2O + CaCl2\n\nedit: The steps for balanacing the reaction:\n1)We know the salt produced is CaCl2, so an acid with Cl is HCl and a base with Ca is Ca(OH)2. \n2) write the skeleton reaction:\nHCl + Ca(OH)2 → H2O + CaCl2\n3) there are 2 Cl's on the right side, but only 1 on the left. To balance this, place a 2 in front of HCl\n2HCl + Ca(OH)2 → H2O + CaCl2\n4) Now there are 4 H on the left and only 2 on the right, so, place a 2 in front of H2O.\n2HCl + Ca(OH)2 → 2H2O + CaCl2\n5) check with the other elements, each side has one Ca, and 2 O. It all works out ☺
797533
Providing that the H3C6H5O7 is citric acid, that balanced equation is:\n\nH3C6H5O7 (s) + 3 NaOH (aq) --> Na3C6H5O7 (aq) + 3 H2O (l)\n\nThe net ionic equation is:\n\n3 H+ (aq) + 3 (OH-) (aq) --> 3 H2O (l)
506202
Write out the balanced reaction which occurs.\n\nSince both NaOH and H2SO4 are strong electrolytes (strong base, strong acid), we can assume both dissassociate completely and the reaction produced Sodium Sulfate and water,\n\n2NaOH + H2SO4 --> 2H2O + Na2SO4\n\nFind limiting reactant in order to find which  will be left over (either NaOH or H2SO4).\nIn order to do this, you need to know both the concentrations of the NaOH and the H2SO4 in order to find the initial number of moles of each.\n\nOnce you know how many moles of either OH- or H+ are left over, you can then find the pH, or pOH like this,\n\npH = -log ([H+])\npOH = -log ([OH-])\n\npH + pOH = 14\n\n*Remember to take into account that the final volume of solution is the sum of the intial volumes of each othe reactant solutions when calculating pH.\n\nEDIT:\nYou know, it just occured to me, I dont know why I even brought up pH, that was not what the question was asking.  but everything I said still stands in order to calculate the molarity...you just dont have to go the one extra step and calculate the pH by taking the negative log of the molarity concentration of H+ ions.\n\nAlso, for all of you out there who are just given answers with not other explanation, it would be nice if you stated what the concentration was of....salt? NaOH?  H2SO4?\nBecause of this ommision, I would highly inclined to disreguard their answers as numerically incorrect as well.
588293
When an acid reacts with an alkali (base), neutralisation occurs as the pH of the mixture becomes neutral, pH=7. (Acidic: pH < 7, Basic: pH > 7).\n\nSo an example would be to react sulphuric acid with sodium hydroxide to form sodium sulphate (salt) and water.\n2NaOH + H2SO4 ---> Na2SO4 + 2H20\n\nAn ELEMENT that would neutralise sulphuric acid (i.e. make its pH 7) could be any metal.\n\ne.g. Mg + H2SO4 ---> MgSO4 + H2\n\nBut this is not called a neutralisation reaction.
3490
it's an organic acid\n\nhttp://en.wikipedia.org/wiki/Citric_acid
638948
The reaction NaOCl + NH3 = NH2Cl + NaOH is very easy even cold. The reaction NH2Cl + NH3 + NaOH = N2H4 + NaCl + H2O is not so easy as it requires heating to boiling or close to it.\n\nHere's the link: http://www.sciencemadness.org/talk/post.php?action=reply&fid=2&tid=1128&repquote=20454
806488
NaOH + H2O---> Na+   +   OH-   +H20\n\nThere is no reaction, but sodium hydroxide will ionize in the water. Actually the water will ionize also.
985537
Are you sure?  I do not believe NaOH is used in nylon synthesis.\n\nPerhaps you are referring to sodium hydride?  It is used in the production of nylon 6 (polycaprolactam).\n\nIf this is the case, then, sodium hydride is the initiator of the reaction. It reacts with caprolactam by extracting the amide hydrogen, to produce the sodium salt.
222097
OH-(aq) + HC2H3O2(aq)---> H2O(l) + C2H3O2-(aq)
921837
NaHCO3 --> Na+ + HCO3-\nCa(NO3)2 --> Ca(2+) + 2NO3-\nAl2(CO3)3 --> 2Al(+3) + 3CO3 (-2)
366185
phenolphthalein and dilute sodium hydroxide are both clear and will turn pink when mixed
53525
Sodium hydroxide is a very strong base, not an acid (the common name is lye).\nTriglycerides are fats, like beef tallow.  Mixing them and allowinging to react would produce Granny's lye soap.
411151
the reaction produces NaCl, which is white