how do find the domain and range of this y=4/7x-13?
144380
You got it quite confusing! Did you mean\n(a) y=4/7x-13 or (b) y=4/(7x-13) ??\n\n(a)\n\ny = 4/7x - 13    (-13 is not on the denominator!)\nThe range is the set of all possible values of y and\nthe domain is the set of all possible values of x, but a denominator cannot have a value of 0, so 7x cannot be 0\nand x cannot be 0.\n\nDomain={x/x E R, x is not equal to 0}\nTo get the range, solve for x in terms of y.\n\ny=4/7x-13\n7xy = 4 - 91x\n7xy + 91x = 4\n7x(y + 13) = 4\nx = 4/(7(y + 13))\n\n7(y + 13) cannot be equal to 0, so\n(y + 13) is not equal to 0 \ntherefore, y is not equal to -13\n\nRange={y/y E R, y is not equal to -13}\n\n(b)\n\nUsing the same procedure, you will get\n\nDomain={x/x E R, x is not equal to 13/7)\nRange={y/y E R, y is not equal to 0}\n\nc",
1171377
Divide each side by 12 to isolate the variable.\n12y/12=132/12\nYou end up with y=11.
226809
it is all of the "y" values that you calculate from the domain ("x" values)
143223
a) (6x-7y)(6x+7y)\nb) y(4xy-7)\nc) (x-8)(x+3)
1119164
3x-4y-1=0\n\ndistance=4.8
1055471
You need to graph this function. \nIt is a line.\ny = (x^2)^ 1/2 - 16 \ny = x - 16\nx = 0, y = -16, \nx = 16, y = 0
952602
This is what always helps me.\n\nA function is a machine.\n\nThe domain is everything you can put into the machine so that it doesn't break.\n\nThe range is everything you can get out of the machine.\n\nIn the case of your function, there's only one possible value of x that will "break" the function, in the sense that you'd get an infinite answer.  That value is x=0, because then you'd have 9/0 + 7, and 9/0 is infinity.\n\nSo the range is {x | x is not equal to 0}.\n\nAssuming that you meant 9/x + 7, rather than 9/(x+7).  If you meant the latter, x cannot be equal to -7.
516734
y= -x+4 is x=4 y=3.87
423719
If your parabola is the standard y = ax^2 + bx + c, your domain should be all real x.  Since you mentioned that it opens up, your range goes to infinity.  Since your axis of symmetry is at (2, -1), your vertex is at (2, -1) and your lower y-bound is -1.\n\nBTW, the axis of symmetry is a line of the form x = 2, if I'm interpreting your information correctly.  The vertex of a parabola always lies on the axis of symmetry, which is why I assumed that your lower y-bound is -1 in finding the range.
764937
I think the best answer would\nbe to give y in terms of x.\nThis is :\ny = (6302869x^2 - 384932345355.22x - 59096) / (231689354x + 23431653.57948)
1049371
The Domains are    4, -4, -8,and 14. Or, the x values.
937748
there are a couple of ways to do this, but I think the easiest is to find the slope and since you know the y-intercept, use that formula.\n\nm= (-4-0)/(0-12)\n\nm=-4/-12\nm=1/3\n\ny=(1/3)x -4
535506
If on a TI-83:\n1) Put the equation into Y=\n2) Click 2nd+Window (Tblset) to select the start of the table and the intervals\n3) Click 2nd+Graph (Table)
840687
Well, y=x/(x-1).\nSO, y(x-1)=x, or yx-y=x.\nSo, yx-x=y, or x(y-1)=y, so x=y/(y-1).\nSo, that means y is any real number except 1.\nSo, the range is any real number except 1.
727286
you basically have to factor the whole problem out, i.e:\n\nthe given equation factors out to:\n\n(x-4)(x+4)\n\nSo the domain is all real numbers except 4 and -4. This is so, because when x is either 4 or -4 the equation is equal to zero.
1121129
Domain = all x-values included in the function\nRange = all y-values included in the function\n\nBoth will be written as an inequality.  Here's an example:\n\ny = square root(x-3) + 2\n\nGraph this equation on your calucluator or sketch a graph by hand by plugging in x coordinates starting with 3.  The vertex of this graph is at (3, 2).  Therefore, the domain is:\n\nx is greater than or equal to 3\n\nThe range is:\n\ny is greater than or equal to 2.\n\nIt really helps to visualize the problem when doing these problems.\n\nGood luck!
893495
T = F*d = I*alpha\n\nI = (1/3)*M*d^2\n\nIn both cases, d is the distance from the axis to "the outer edge of one pane",  "as shown in the drawing".