algebra maths problem sum?
149352
If it takes 5 people t days to do the house, then each day, 1/t of the house is painted.  If 5 people paint 1/t part of the house, then the rate at which each person paints 1/5t part of the house per day.  If 6 people take t - 8 days to paint the house, then each day 1/t-8 part of the job is done.  Since there are 6 people, each person paints 1/6(t-8) part of the house.  If we assume that each painter works at the same rate, then 1/5t = 1/6(t-8).  If we take reciprocals we get 5t = 6(t-8) and t = 48 for 5 people and 40 days for 6 people.
84611
Check this website:\nhttp://mathworld.wolfram.com/Addition-MultiplicationMagicSquare.html
531205
2 + 2 = 4\n\nthats all I got
780960
I also have difficulty typing this thypes of math problems.  First, simplify the ax^2+bx+c parts in the first half to (x+c)(x+c) looking things first.  So...\n\n[(x-3)(x-1)]} is the first part.  With the bottom of the second half, divide by 3, so that you get 3(x+1).  Now line everything up like so...\n\n(x+1)(x+3)(x-3)\n_____________\n3(x-3)(x-1)(x+1)\n\nNow do the cancellations and you get the right answer...\n(x+3)\n____\n3\n\nSorry for not working to convention, but it was easier to type it that way.
878947
Sum of roots = 4, product = -7.\n\nNotice the first answer would give a positive product, so it's ruled out since the product is negative.  One of the others is ruled out too -- I'm sure you can figure out which.\n\nOf the two choices remaining, only one of them could give a positive sum, so it's the answer.\n\nPS  I'm sure you can do it from this, but if not, email h_chalker@yahoo.com.au\n\nPPS  I've just looked at Katya's answer.  She's right, except that it doesn't factorise, so you'd have to fall back on a graphing calculator, but that's unnecessary when you can use the simple logic I've outlined.
51473
x+3  This is the right answer, because there is no =s sign in the problem.\n\n3x+9-2x-6\nx+3
128596
im great with algebra, ive been doing it for the past 4 years now non stop, email me and ill be more than happy to show you how to do it step by step and answer you questions\nzinger_38@yahoo.com
616179
here are the general steps you want to take when approaching these math problems\n\n1.) check for the greatest common factor\n2.) write out your parenthesis\n3.) since it's a squared problem, fill in the x's\n4.) write out your + & - signs\n5.) list the multiplication factors for the last term\n6.) plug in factors that will lead to the correct product\n\nwe'll start with #1 to get a better idea\n\n1.) -x^2+5x+24\n\n1. there is no greatest common factor\n2. write out your parenthesis\n\n(    )(    )\n3. fill in the x's\n\n( x   )(x   )\n\n4. fill in + or - signs\n\n-since we're dealing with -x^2 we know that one of the x's need to be + and the other one -\n\n(x   )(-x   )\n\n-since our last term is positive we know that either both the #'s are + or both of them are -\n\n(x-  )(-x-  )\n\nor\n\n(x+  )(-x+  )\n\n\n\n5.  list the multiplication factors for the last term\n\n24\n\n1*24=24\n2*12=24\n3*8=24\n4*6=24\n\n6. plug in factors that will lead to the correct product\n\n(x-8)(-x-3)=-x^2+5x+24\n\n**now, with a little more practice, you'll be able to figure these out faster...here are the answers to the rest of the problems\n\n2. (x-12)(x-12)\n3. (x-9)(x-12)\n4. 2(x^2-8x+16)=2(x-4)(x-4)\n5. 3(x^2-6x+72)=3(x-12)(x+6)
804510
3x^2+6x+5x+10\n(3x+5)(x+2)
263286
the problem you presented above can be represented as,\n\n(8x^8/2x^2) + (16x^6/2x^2) - (12x^3/2x^2)\n\nthen you can simply divide each of the term\nyou'll get\n\n4x^6 + 8x^4 - 6x
1022192
i have  a book about algebra..... and some website...see if they could help u
771776
http://mathforum.org/dr.math/\n\nThis is Ask Dr. Math, a website that can offer help for general math through Algebra and beyond. There are other good websites for math out online, type in keywords,  homework  math help and see all that you come up with. Eventually you will find one that can walk you through most problems. Good luck.
680155
i'd love to help but i'm having trouble with it myself\n\nuse ur math textbook it will have it unless ur math book say algebra and is red ( that my alg. book and it doesn't help) \n\nSRY good luck
598076
Sorry a12b13n5! - I think you are wrong on this one\n\nq +14 =8q + 8x7 (multplying out the brackets)\nq + 14 = 8q + 56 \nq - 8q = 56 - 14 (seperating the 'q's and numbers)\n\n-7q = 42\n\nthen devide by -7 to get\nq = -6\n\nto check\n-6 + 14 = 8 = 8(-6+1) = 8(1) = 8
283992
Simple algebra question:\n\na^2 + (a+1)^2 + (a+2)^2 = (a+3)^2 + (a+4)^2\n\nMultiply everything out getting...\n\na^2 + (a^2+2a+1) + (a^2+4a+1) = (a^2+6a+9) + (a^2+8a+16)\n\nAdd like terms on each side...\n\n3a^2 + 6a + 5 = 2a^2 + 14a + 25\n\nAll terms to the left...\n\na^2 - 8a - 20 = 0\n\nFactor into...\n\n(a-10)(a+2) = 0\n\nSolutions are a=10, or a=-2.  Since a has to be a positive integer, a=10.\n\n10,11,12,13,14 are your answers.\n\n\nCHECK:  \n\n10^2 + 11^2 + 12^2 =? 13^2 + 14^2\n\n100 + 121 + 144 =? 169 + 196\n\n365 = 365.
201475
Do the math or at least show us the factors to get the sum and then we can decide whether or not it's true.  You can't get a sum without addends right?
703752
simply subtract 7 from both sides. This leave you with\n\nx<_3