How do you estimate the time in other planets in our solars system equating to earth's format.?
148755
These are open questions, that NASA and other space agencies are just working out.  \n\nTake Mars.  A martian day is 24 hours, 37 minutes.  A martian year is 687 earth days, or 669 martian days.  How does NASA keep track?  Mars has no prime meridian, no time zones, and no calendar.  So for now, they keep track of martian days, and kind of punt on the rest.  With a probe, like the Mars rover, the day it lands is called Sol 0, and each martian day after than was Sol 1, Sol 2, etc.  Each probe has its own starting point.  They didn't expect the rovers to run so long, so they didn't worry about months or years...they just count the days.\n\nSo what are they going to do when humans start spending time on Mars?  That is an open question they are still figuring out.  My guess is, since people won't exactly be running around outside, martian time will be largely irrelevant, and they will stick to earth time.\n\nIn the meantime, you can check out local martian time with this: \n\nhttp://www.giss.nasa.gov/tools/mars24/
511079
GALACTIC TIME references Earth's movement relative to the center of our galaxy, the Milky Way. Galactic time consists of the GALACTIC DAY--one revolution of Earth around the Sun relative to the galactic center--and the GALACTIC YEAR--time for Earth to make on revolution of the galactic center.
562130
An earth year (Gregorian calendar) is 365.2425 days \n= 31,556,952 seconds.\n\nA jovian year (one orbit of Jupiter around the sun) is 11.86 earth years.\n= 374,265,450 seconds.
540921
Go to this site.  Click on the time and you can convert to whatever time zone around the world you want.
868089
You can easily compute the Earth's angular speed by considering that the Earth makes little less than one complete round on itself in a day.\n\nThat "little less" accounts for the fact that, taking the Sun as reference, since in a year the Earth also makes a revolution around the Sun, that revolution adds up 1 day that shall not be counted.\n\nTherefore, the Eart's angular speed is 1-1/365 rounds/day.\nWhich is, in International Units: 1.154 x 10^(-5) rad/s.
1071518
Time And Relative Dimension (or Dimensions) In Space
533246
http://www.worldtimezones.com/
667841
It is based on the rotation on the earth. Explaining it is too much for a yahoo answer, so the following wikipedia articles will explain this. \n\nThe second wikipedia article explains the 'french' decimal time, in which units of time are divided into slots of 10 each. This is also a lenghtly but comprehensive answer.
882266
Using Kepler's laws (third law):\n\nThe ratio between the T*T and a*a*a is a constant for our Sun and it applies to all objects rotating around it. where T is the period and a is the average distance. \nSo:\nT2=T1*(a2/a1)^(3/2) ;  ^ is used for power \nT2=1year *[  (4.5*10^9)  /  (1.5*10^9)  ]^(3/2)\nT2=164.3 years     \nTo make sure...see the links
188774
http://www.worldtimezone.com/\n\nlook at the map and calculate it based on your time zone.
148254
Easy...\n\nWorld Time Clock\nhttp://www.timeanddate.com/worldclock/\n\nWorld Weather\nhttp://www.weather.com/common/welcomepage/world.html?from=globalnav
771253
Actually time is measured in multiples of 24.  It may have something to do with our angular measurement system.  The Earth rotates 360° every 24 hours.  Each hour represents 15° of angular rotation.  Each minute of time represents 15 minutes of angular rotation and each second of time represents 15 seconds of angular rotation.  As to where our time measurement system came from, I don't know, but it could probably be found out pretty easily by doing a few searches.\n\nCheck this link for books on the subject:\nhttp://books.google.com/books?q=origin+of+time+measurement&ots=V7_ssegXJ4&sa=X&oi=print&ct=title
84814
http://pweb.jps.net/~tgangale/mars/converter/calendar_clock.htm
105036
Earth revolves around this shinning star called a sun and it takes about 365 to 366 days to make a round trip around the sun.\n\n60 minutes and not 100 minutes --> Ever looked at a globe and the time zones? \n\nweek consists of 7 days --> Again with the Earth revolving around the sun.
842146
Well the earth orbit's the sun \n2AU * PI / year\n\nAn AU is the average distance of the Earth from the sun in it's orbit.  Although all orbit's are ellipses, the equation of a circle should approximate close enough.\n\n1AU =149.598×10^6 km.\n2AU = 299196000 km \n\nThe earth moves really fast so we should convert years into seconds.  The earth orbits the sun once about every 365.25 days (the .25 is why we have leap years).\n\n365.25 * 24 * 60 * 60 = 31557600 seconds.\n\nSo now all we must figure out to get the speed in km/sec we calculate \n(299196000 * PI) / 31557600\n=29.785280109497\n\nSo the Earth orbits the sun at a speed of 29.785280109497 km/sec.  That's pretty fast!\n\nWikipedia gives a max orbital speed of 29.783 km/sec and a min orbital speed of 29.291 km/sec, so my estimate was pretty darn close.
433636
Try this:\nhttp://www.timeanddate.com/worldclock/
1050320
Since there are 27 integer time zones (from GMT - 12 hours to GMT + 14 hours), there's no way the whole world can have the same date at the same time, because there will always be points that are more than 24 hours apart, and those points (at least) will be in different days.