can someone help me solve this equation: 3/x+5= 3/3x-2?
140957
find ur LCD (least common denominator) which is (X+5)(3x-2)\n\nmultiply ur values on top by what their corresponding denominators dont have\n\n3/x+5 doesnt have 3x-2 in the denominator so u multiply 3 by 3x-2 = 9x-6\n\n3/3x-2 doesnt have x+5 in the denominator so u multiply 3 by x+5 = 3x+15\n\nyou can set those equal to each other cuz the denominators cross out... so u have 9x-6 = 3x+15\n\nfrom there i hope u know what to do\n\nthere is another way by cross multiplying but i think this way is kinda easier and well actually theyre basically the same thing\n\no well, hope this helped
836174
3/5x= - 21\n\n5(3/5x) = 5 ( - 21)\n\n3x + - 105\n\n3x/3 =  105/3\n\nx = - 35\n\nThe answer is x =  - 35\n\nInsert the x value into the equation\n\n- - - - - - - - - - - - - - - - - - - -\n\nCheck\n\n\n3/5 x = - 21\n\n3/5( - 35) = - 21\n\n- 105/5 = - 21\n\n- 21 = - 21\n\n- - - - - - - - - - - - - - - - - - -\n\n2/3x + 8/3 = 20/3\n\n3(2/3x) + 3(8/3) = 3(20/3)\n\n2x + 8 = 20\n\n2x + 8 - 8 = 20 - 8\n\n2x = 12\n\n2x/2 = 12/2\n\nx = 6\n\nThe answer is x = 6\n\nInsert the x value into the equation\n\n- - - - - - - - - - - - - - - - - - - - - - - - \n\nCheck\n\n2/3x + 8/3 = 20/3\n\n2/3(6) + 8/3 = 20/3\n\n12/3 + 2.666666667 = 6.666666667\n\n4 + 2.666666667 = 6.666666667\n\n6.666666667 = 6.666666667\n\n- - - - - - - s-\n\nc/ -7 = 12\n\n- 7 (c/-7 = - 7(12)\n\nc = -  84\n\nThe answer is c = - 84\n\nInsert the c value into the equation\n\n- - - - - - - - - - - - -\n\nCheck\n\nc/-7 = 12\n\n- 84 / - 7 = 12\n\n12 = 12\n\n- - - - - - - - -s-
1119698
5 > x+1/-3 > 0\n5 > x-1/3 > 0\n5 1/3 > x > 1/3
943154
3= 1/2x+3\n\n>>>>1/2x=0,>>>x=0\n\ni hope that this helps
817206
1/2x+2/3=5/6\n1/2x=5/6-2/3\n1/2x=(5-4)/6\nx=2(1/6)\nx=1/3
763285
3b/8-5=2\n3b/8=2+5\n3b=8(2+5)\n3b=8x7\n3b=56\nb=56/3\nb=18 2/3
205091
Solve (2/3)x+(3/4)=(5/6) for x.\n(2/3)x+(3/4)=(5/6)\nx=1/8\n-----\nPlug in 1/8 for x in your other equation.\ny=2-(3/4)x\ny=2-(3/4)(1/8)\ny=61/32\n-----\nx=1/8 y=61/32\n(1/8, 61/32)\n\nI have a hunch that this is your math homework, so please use the process above to help you through the rest of your assignment instead of cheating.
1119268
okay first take x/5 + y/5 = 3 and times everything by 3 so you have 3x/5 + 3y/5=9 now times everything by 5 so you have 3x + 3y = 45 (notice the 5's on left side cancel when u mulitiply) now take \n3x + 3y = 45 and subtract the other equation from it which is 3x + y = 13 so it looks like this \n  3x + 3y = 45\n -3x -   y  =-13 which gives you \n  2y = 32 divide by 2 to get \n y=16 substitute this value of y in second equation ( 3x + y = 13)\nso you have 3x + 16 = 13 subtract 16 from both sides and you will have 3x = -3 divide by there and it gives you x = -1 now plug in both of you values x and y into one of the equations i say the second one because it's much easier but anyways when you plug it in the second one you get 3(-1) + 16 = 13 is this true and the answer is yes therefore it is solved correctly\n\nEDIT: Doin it again with a little more detail for my own sake lol\nEquation 1=  x/5 + y/5 = 3\nEquation 2=  3x + y = 13\n\n(x/5 + y/5 = 3) mulitiply everything in the ( ) by 3\n(3x/5 + 3y/5 = 9) multiply everything in the ( ) by 5\n3x + 3y = 45 notice the fives on the left side cancel\nNow subtract Equation 2 from 3x + 3y = 45\n   3x + 3y = 45\n   -3x - y= -13 so this will give you\n 0x + 2y = 32 divide by 2\n          y = 16 Substitute your y value into equation 2\n3x + y = 13 so you have instead 3x + 16 = 13 subtract 16 from both sides 3x = -3 divide both sides by 3 so you have x = -1 now plug in your x and y values into equation 2\n3(-1) + 16 = 13; -3 + 16 = 13; 16 - 3 = 13 which is correct therefore the solutions are correct
1102849
gurl am not helping out with ur homework next time.\n f(x) =/x/ +3x +1\n       =x+3x+1\n       = 4x+1\n\n  f(x)=3x+/2x-5/\n       = 3x+2x-5\n       =5x-5\n\n  g(x)= /x/+/x-1/\n        = x+x-1\n        =2x-1\n\n  g(x)=3/x-2/ - /x+1/\n        =3(x-2) - x+1\n        =3x-6-x+1\n        =2x-5
555590
Just multiply:\n(X/3)(3/4 x) -(x/3)(3/5) + (3/4)(3/4x) - (3/4)(3/5)\n\nand simplify from there
36762
Factor by grouping:\nx^2 (3x - 5) - 3 (3x - 5)\nAnswer: (3x - 5)(x^2 - 3)
731670
(-4x3 + 3x2 - 5) + (x2 - 5x + 6) =\n-4x3 + 3x2 - 5 + x2 - 5x + 6 =\n-4x3 + 4x2 - 5x + 1
941643
3/(5x)=-4\n3=-20x\n-3/20 = x\n-0.15 =x
19796
3^2x - 5(3^(x+4)) = 0\n=> 3^2x = 5(3^(x+4))\n=> Ln(3^2x) = Ln(5(3^(x+4)))\n=> Ln(3^2x) = Ln5 + Ln(3^(x+4))\n=> 2xLn3 = Ln5 +(x+4)Ln3\n=> 2xLn3 = Ln5 +xLn3 +4Ln3\n=> xLn3 = Ln5 +4Ln3\n=> x = Ln5/Ln3 +4Ln3/Ln3\n=> x = Ln2 + 4
493796
You have to do the Trick, meaning you take out the 5 and reapply it to the number without the variable (2). This leaves you with: 5(xsquared-3x-10)=0\n\nFactor what is inside the parenthesis and get: (x+2)(x-5)\n\nThen reapply the 3 into the equations (but only into the variables, because your doing the trick) and you get:\n(5x+2)(5x-5)=0\n\nThen, set both equations to 0 and solve.\nThe first equation:5x+2=0\nSubtract the 2 from both sides to get: 5x=-2\n\nNext, divide the 5 out of both sides to get: x=-2/5\n\nThe second equation: 5x-5=0\nAdd 5 to both sides to get: 5x=5\n\nNext, divide the 5 out of both sides to get: x=5/5 or x=1\n\nFINAL ANSWERS:\nx=-2/5\nx=1\n\nIf it's a word problem and you can only have one answer, elimate the one that doesn't make sense. For example, if they are asking for the height of something, you wouldn't pick the negative number.
492288
x=\n3x-3+2x=5x-6-x\n3x+2x-5x+x=-6+3\n1x=-3\nx=-3&#92;1\nx=-3
790308
1.  5x + 7= 3x + 21\n     -3x       -3x\n     2x + 7 = 21\n           -7    -7\n     2x = 14\n     /2     /2\n        x = 7\n\n2.  3x - 2 (5-x) = -3(x-10) + 3x\n     3x - 10 - 2x = -3x + 30 + 3x\n     x - 10=30\n     x=40\n\n3.  5( x+1) = 3(2x +3) + 5\n     5x + 5 = 6x+9 + 5\n    5x+5=6x+14\n    5=x+14\n    x=-19