which on of the following temperture is equal to 5' C?
151136
278K. In the Kelvin system, 0'C = 273K. Also, there is no "formula" for converting between celcius and kelvin. You just add or subtract. It's basically a shift of origin type of thing where you move the origin from 0 to 273.
826739
It is 240.8000208800021 degrees Fahrenheit.\nhttp://www.metric-conversions.org/temperature/celsius-to-fahrenheit.htm
563071
it would depend. twice as cold as the difference of that temp compared to the whet temp was that came befor it. so it yesterday was 5 degrees f then tomarrow will be -5 degrees f.
1127260
Fahrenheit  to Celsius °C = (°F – 32) / 1.8\nCelsius to Fahrenheit °F = °C × 1.8 + 32
820184
I think you should break things down and think of the question like this.\n\nThe heat for a process is 250.3J, Its doubled with the same temperrature difference, the temperature difference is 5C.
159190
Celsius times 9, then divide that number by 5. Add 32.\n\n10C X 9 = 90 / 5 = 18 + 32 = 50F
1136926
A simple solution is to mulitply the celsius temperature by 2 and then add 31 (32 - 1). It's not the exact science, but It will give you the right answer 97% of the time.
963644
Heat capacity = q/(delta)T\n\nC= 135J/(54°C-25°C)\nC= 135J/25°C\nC= 5.4 J/°C
546621
To convert Kelvin to Celsius  use this formula C = K - 273.  Therefore 422.35k - 273 = 149.35C.\n\nTo convert Celsius to Fahrenheit, the formula is F = (C x 9/5) + 32.  Therefore, 149.35C x 9/5 + 32 = 300.8F.
754332
The formulas for converting between degree Celsius and degree Fahrenheit are:\n\nF = (C * 9/5) + 32\nC = (F - 32) * 5/9\n\nTo find the temperature when both are equal, we use an old algebra trick and just set F = C and solve one of the equations.\n\nC = (C * 9/5) + 32\nC - (C * 9/5) = 32\n-4/5 * C = 32\nC = -32 * 5/4\nC = -40\n\nF = (F * 9/5) + 32\nF - (F * 9/5) = 32\n-4/5 * F = 32\nF = -32 * 5/4\nF = -40\n\nSo the temperature when both the Celsius and Fahrenheit scales are the same is -40 degrees.\n\nI really hope this wasn't your home work...
1140288
B. 93.3\n\nThis will help you:  http://www.onlineconversion.com/temperature.htm
99762
From Farenheit to Centigrade use this equation: \nTC=5/9(TF-32)\n\nFor vice versa use this:\nTF=9/5TC+32\nKinda hard to write formulas on a computer. Sorry.\nExample: the boiling point of water is 212 F. In centigrade it would be 5/9(212-32) ->5/9(180) =100 c
10501
From Fahrenheit = (value - 32) / 1.80\n\nor use http://www.csun.edu/~jmj2600/hw4.html
1007444
Used to convert celcius to fahrenheit and reverse.\n\nF = (9/5 *C) + 32\n\nYeah, I know the parentheses are redundant.\n\nAlso \n\nC = 5/9 * (F-32)\n\nJust to assure yourself and me that the equations are correct\n\n20 degrees Celcius is the same temperature as 68 degrees Fahrenheit.
923282
a) 98.5 L\nb) 0.000763 cg\nc) 57.0 m\nd) 9500 sec OR 9.50 * 10^3 sec\ne) 12.2 degrees C\nf) 0.00750 x 10^4 mm OR 7.50 * 10mm OR 75.0 mm\ng) 1760 mL or 1.76 * 10^3 mL\nh) 8.86 km
750705
212 F, 100 C,     373 K
412780
freezing: 0 C,  32 F\nboiling: 100 C, 212 F