Factor completely. 3(x – 2)^2 – 3(x – 2) – 6?
140487
3(x-2)^2 - 3(x-2) - 6\n\n= 3[(x-2)^2 - (x-2) - 2]\n\n= 3[(x-2){(x-2) - 1} - 2]\n\n= 3[(x-2)(x-3) - 2]\n\n= 3[x^2 - 5x + 6 - 2]\n\n= 3[x^2 - 5x + 4]\n\n= 3(You should solve the next step as this is ur home work and dont make this a habit.)
1138309
I hope you are trying to say x+2 = (2/3)(2x-1)..if it is correct then\n\n3(x+2) = 2(2x-1) --> 3x+6 = 4x - 2 --> 6+2 = 4x-3x --> 8 = x
636732
8x^2y^3+5y^2 when "FACTORED COMPLETELY"=\n\ny^2 (8yx^2+5). \n\nThis should be right. My dad is a complete genius and he did this in like 2 seconds. I double checked it on my calculator too by plugging in numbers, so I can assure you he's right.\n\nHope this helps! Have a nice day :)
859126
The best way to do this is to MULTIPLY every term by the COMMON DENOMINATOR of ALL FRACTIONS\n\nFor example\n\n3/x + 2/3 = 5/3x\n\nMultiply every term by 3x\n\nyou get 9 + 2x = 5,....\n\nit never fails....for example\n\n3/x + 2/3 = x/6....common denomoinator is 6x...so multiply every term by 6x\n\n18 + 4x = x^2.... x^2-4x-18=0 ..... then you use the quadratic formula to factor etc..
774014
2^3+2*2^2-3(2)-10=8+8- 6 -10 =0\nTherefore x-2 is a factor of the given polynomial
276641
f(x)=3x^2-2x+8 for x=6\n\nf(6)=3*(6^2)-2*6+8\nf(6)=3*(36)-12+8\nf(6)=108-12+8\nf(6)=104
123892
3(x – 2)^2 – 3(x – 2) – 6\n3((x-2)^2 - (x-2) -2)\n3(x^2-4x+4-x+2-2)\n3(x^2-5x+4)\n\n3(x-4)(x-1)\n\nYay!!
685308
(3x + 6/4(x^2)) (x + 2/16(x))\ntake out x\n=x(3 + 3/2(x)).x(1 + 1/8)\n=9/8(x^2)(3 + 3/2(x))\ncan simplify d numbers still.
745882
C is correct but not complete... only the 3 is factored out... the real answer would be:\n\n3(x-1)(x+4)
919554
Factor out 3.\n3(x^2+2x+1)=0\n3(x+1)^2=0\nThe only answer then is x=-1 to make the expression equal 0.
222653
x+6(x^2)= 12\nx+6x^2  = 12\n6x^2+x-12=0\n(2x+3)*(3x-4)=0\n2x+3=0 3x-4=0\n2x=-3  3x=4\nx=-3/2 x=4/3
798514
do you mean 6x([1/2]x^2)?\nif so 3x^3\nor 6x(1/(2x^2))?\nthen its 3x^-1
149556
4x^3+36x^2+32x----using common factor which in this case would be 4x so, 4x(x^2+9x+8) and then u use guessing method \nand the complete factorization would be 4x(x+8)(x+1).
517819
start pulling out common factors\n\n2 (x^3 + 27)\n\n2(x^3 + 3^3)
764068
2x - 2 = x^2 - 4x + 3\nSet one side equal to 0\n0 = x^2 - 6x + 5\nFactor\n0 = (x - 5)(x - 1)\nSet each factor equal to 0\n0 = x - 5              0 = x - 1\nSolve\n5 = x                  1 = x
725157
assuming the numbers after the parenthesis and variables are exponents...\n(x-1)^(3/2) [6x(x-1)^2-x^2(x-1)^3]\njust add the exponents together from the outside to the inside- (3/2) + (2) = 7/2\n\n(x-1)^(3/2) [6x(x^2-2x+1)-x^2(x^3-3x^2+3x-1)]\n(x-1)^(3/2) [6x^3-12x^2+6x-x^5-3x^4+3x^3-x^2]\n(x-1)^(3/2) [-x^5-3x^4+9x^3-13x^2+6x]\nx(x-1)^(3/2)(-x^4-3x^3+9x^2-13x+6)\nokay, that took me for friggin ever to type on a regular keyboard. Please, seriously consider me for the best answer!
254834
if you use quadratic formula you get the factors of \n\nx= ( ( 3 +/- square rt.(5) ) / -6 )