How do you find the original temperature?
141221
The original water temp is 25C, as was given in the problem... I'm assuming you meant to ask what was the initial temp of the water that was added, which isn't too hard. Here goes.\nQ(heat)= m(mass) x c(specific heat) x delta T(change in temp)\nso Q = (150g)(4.something J/gC-look it up)(25C-14C)\nBecause of conservation of energy and assuming ideal insulation, the heat LOST by the 150g of water during the mixing is equal to the heat GAINED by the 200g of water. So, once you have Q, rearrange the equation to look like [delta T] = Q/mc = Q/(200g)(c)\nThat will give you the temperature difference between 14C and the 200g of water's initial temp. Delta T should come out as being positive, since the temp is going up. \nWhen you have more complex mixtures of things with different specific heats and add processes and changes, the math becomes a lot more of a headache but the same basic principles apply just the same.
744550
One way is the reverse of going from celsius to fahrenheit! To find what 10c is in f you would take 10 and multiply by 2, then add 30 to get 50 fahrenheit. Do the reverse to answer your question! Let's say that its 82 f, to get c you would -30 from 82=52,then divide by 2, giving you 26celsius. Hope this helps.
827524
Easier compared to one with a higher heat capacity:\n\nH/(m*Cp) = (delta T), where m is the mass of the object, H is the heat that must be added (or removed) to raise (or lower) its temperature, delta T is its change in temperature, and Cp is its heat capacity. From the above formula, you can see that larger values of Cp result in small temp. changes, for the same heat amount.
420756
Tc = (5/9)*(Tf-32); Tc = temperature in degrees Celsius, Tf = temperature in degrees Fahrenheit\n\nfrom http://www.condoconcepts.com/convers.htm\n\nor\n\nA calculator helps here. \n\nTo convert Fahrenheit to Celsius, subtract 32 degrees and divide by 1.8. To convert Celsius to Fahrenheit, multiply by 1.8 and add 32 degrees. \n\nhttp://www.sciencebob.com/lab/q-c-f.html
571004
C=(100.7-32)*100/180=38.16\nANS: 38.16°C
812605
°F = (9/5)*°C + 32\n\nSo\n\n°F = (9/5)*(37.8) + 32 = 100.04 °F
921703
Just let the units tell you what to do.  H=mass* T*sp heat.  with T in K
676662
What did you use to measure the activation energy?\nYou probably used a thermometer which was probably marked to 0.1 degrees. That means that your measurements are probably accurate to 0.05 degrees. Reactant temp may be measured as 25.1 (+/- 0.05) so this means that the temp could be 25.05 or 25.15.\nDo the same for the transition state.\nDraw small vertical bars through each point, e.g for reactants the bar would go from 25.05 to 25.15, with the cross in the middle.\n\nI can't remember the formula, but errors are a lot more pronounced on small measurements. It may be something like the difference between the highest and lowest possible values divided by the recorded value, all multiplied by 100.
111333
Begin by subtracting 32 from the Fahrenheit number. \nDivide the answer by 9. \nThen multiply that answer by 5.
569322
Use the ideal gas law \n\nPV/T = constant for the final and initial states.
921632
PV = NRT, solve for N, note that T is absolute temperature in kelvins
863200
Use the equation Q=mc(delta)T.\n36.8 = .006*130*(Tf - 32)\nSolve the equation for final Temperature and you get 79 degrees Celsius
684353
P1V1T2=P2V2T1 \n\nRemember to express  temperature in Kelvin (with pressure in Pascals and volume in m^3)
907651
Just add first two and absolute value of third... answer 2 degree C.\nIf the values are the temperature level after the change... net change is from level 1.1 to minus 1.9 ...so net cgange is 1.1+1.9=3 deg C.\n Exact Wording of question is important.
1125139
15 + 68 = difference in temperature
615198
use the formula q=m*s*(t2-t1) where q is energy in heat,m is mass in grams,s is specific heat in joules/gram celsius,t1 is initial temp,t2 is final temp.\nsubstituting in formula,\n42,000=900*4.186*(t2-35)\nt2 works out to be 46.14 celsius.\nhope this helps.
883310
At temperatures above 220 K the rxn would be spontaneous. To determine spontaneity, first determine the delta G value by using the formula deltaG=deltaH-Tdelta S. Now find out what temperature value would make the delta G negative which would indicate a spontaneous rxn, and in this case it is spontaneous above 220 K.