Does the process 2H+ --e.coli--> H20 occour anerobically or require O2?
151776
E. coli can not grow in H2.  This is why S. typhi kills off the E. coli in our intestines thus finding opportunity to infect. "Montazuna's Revenge."
1093422
([O2]^(O2 coefficient)*[H2]^(H2 coefficient))/\n[H2O2]^(H2O2 coefficient)
930110
Well, for starters, Temp is important for the catalytic effect, a low temp will slow the reaction, while too high a temp will kill the yeast.  Sugar is the food source for the yeast, so if there is not enough, the yeast wont divide as much.  Water is important of course to provide a comfortable anaerobic environment. Hope that helps you some.
152040
Aerobic bacteria uses O2 like all the other cells, in resparation, aka. break down of glucose. Anaerobic bacteria, cannot stand oxygen, because it is like a poison to them, they can get all of their energy from chemicals, such as sulphuric acid, from underwater volcano vents
875948
Water brakes down into h and o. 2H2O.....2H2 +O2.
410355
one mole of water formation will be as follows:\n\nH2 + (1/2) O2 -------> H2O + 68.3 Kcal.\n\nIts highly exothermic reaction.\nNow, if you want the reverse to happen, you need to give the same amount of energy to break the bonda between H and O
768548
Anaerobic respiration occurs without oxygen.  In yeast, it produces carbon dioxide and alcohol, in humans, it produces lactic acid and carbon dioxide.
927756
2H2O2 → 2H20 + 02 is the balanced equation for the above decomposition
866210
2NO+O2--->2NO2\n\nCaO+H2O--->Ca(OH)2\n\nCaCO3--->CaO+CO2
163942
food water air reproduction
745142
aerobic rxns use oxygen...anaerobic is w/o oxygen.
178868
glycolisis is an anaerobic process not required O2 to function, while the Krebs Cycle and electron transport occur in the walls of the mitochondria where oxygen is used and yielded. Further, glycolisis occurs in the cytoplasm, a place of little or no oxygen. \n\nThe next step in anaerobic cell respiration is fermentation it can be lactic in most animals or alcoholic in most plants
302323
Although the type of corrosion most of us are familiar with involves molecular oxygen, corrosion, in general, does *NOT* require the presence of free oxygen.  \n\nFor example, galvanic corrosion, which can occur when two dissimilar metals with different oxidation potentials are in electrical contact.  The less noble metal will form an anode, and be oxidized, while the more noble metal will form a cathode, where reduction reactions will occur.  In the absence of oxygen, reduction reactions like:\n\n  2H+ * 2e- -> H2(gas)\n\ncan occur.  This reaction is particularly important in acidic environments, (when the H+ concentration is high).  Such environments can develop in corrosion environments via hydrolysis reactions, e.g., \n\n  Fe3+ + 3H2O -> Fe(OH)3(solid) + 3H+\n\nwhere the Fe3+ ions are produced by the oxidation of iron metal, and Fe(OH)3 is the solid mineral "goethite", a major component of "rust".\n\nCorrosion can also be induced in the absence of free oxygen by the action of some species of bacteria. For example, there are bacteria that can reduce sulfate ions (SO4--) or nitrate ions (NO3-) to hydrogen sulfide (or metal sulfides) and molecular nitrogen.  To do so, they need to couple these reactions to a "source" of electrons, which can be a metal surface that is then oxidized (i.e., corroded). \n\n\nFinally, there are some metals that are themselves strong reductants -- so strong that they can reduce water.  Li, Mg, Na, and Al all have standard oxidation potentials that are lower than that of water, so they will react spontaneously (in the case of Li and Na, *violently*) with pure water (even water containing no free oxygen) to form metal ions or hydroxides and hydrogen gas.
860434
aerobic respiration requires oxygen, but oxidizes glucose completely to CO2 and water. Different text books have different values for the amount of ATP you get from a single molecule of glucose but it'll be somewhere in the 30-36 range.\n\nWithout oxygen available, the glucose can only be fermented. Yeast ferment glucose to ethanol and CO2.  In the process, a cell can produce only a net of 2 ATP  per moleucle of glucose used.
570402
Nothing...unless you light a match, then...BOOM!  In the case of Oxygen and Hydrogen, you'll get pure water afterwards...that should put out the fire you just started :)\n(Not really)
729117
You don't give the rate law, so it's impossible to tell. Suppose [H2O2] = concentration of H2O2 and [I-] = concentration of iodide. If rate = k[H2O2][I-], then the mechanism is one step. This means that both an H2O2 and an I- have to come together at the same time for the reaction to occur. If rate = k[H2O2], then it's a two-step process. This is because something has to happen to H2O2 in a slow, rate-limiting step, followed by the reaction of whatever with I-.
744647
C(3)H(8)+5O(2)=>3CO(2)+4H(2)O\nfuel+oxygen=>carbon dioxide+water\ncombustion \nbrackets-subscript