what are two examples of incomplete dominance & give the genotypes & phenotypes?
149035
I assume you asked about autosomal incomplete dominant.  Generally speaking, let's say R is dominant allele for red color and r is the recessive allele for white color.  Incomplete dominant means that when parents RR and rr have offspring Rr, their color will be pink instead of red or white.  It's different from co-dominant which you can use the ABO blood type as an example with people who have AB blood type as an example of codominant.
952198
Recessive genetic traits
560142
One of each pair is derived from either parents. Also due to the diploid nature of chromosomes genotypes as homozygous dominant, homozygous recessive and heterozygous can be found. Thus a recessive character can be avoided to the maximum.
872996
Genetic dominance is the tendency for offspring to have one characteristic over another. This is due to the way alleles work. Alleles are alternative forms of a gene.\n\nThere are recessive alleles, and dominant alleles, and at times two alleles might be codominant. At such times, neither allele dominates over the other, and an intermediate characteristic is expressed in the phenotype (the physical expression of the characteristic).\n\nExample : Blood Group\nThere are three types of alleles : A, B, and O. O is recessive, but A and B are equally dominant. So A with O becomes A, B with O becomes B, but A with B is AB.\n\nExample : Antirrhinum flower\nThere are two colour types : Red and white. But the alleles for both types are codominant, and the result is pink.
591863
The answer is "b"\n\nAssuming the dwarf characteristic is recessive, since about half of the offspring were dwarf, that means that half the offspring have to by homozygous for the dwarf genotype (tt).  The only way to get that is to cross the Tt and tt.  Thus you get half the offspring being Tt (tall) and half being tt (dwarf).  If you cross a homozygous dominant (TT) with anything else, all the offspring will be tall, because all will carry at least 1 "T" gene.  If you cross "Tt" and Tt" then you get 1/4 TT (tall), 1/2 Tt (tall), and 1/4 tt (dwarf).
940033
Let's take the Blue eyes - brown eyes example.  Brown is the dominant trait, so we'll use the capital B letter.  Blue is the recessive trait, so we'll use the b letter.  A person with blue eyes has the genotype bb (got a b from dad and a b from mom).  A person with brown eyes can be homozygous BB (got B from dad and B from mom) or heterozygous Bb (got B from one parent and b from the other parent).\nA first generation usually starts with pure breeds, so both homozygous.  We'll have BB and bb as the starting parents.  Those parents produce gametes in their gonads.  Let's say that mom has blue eyes and dad has brown eyes.  All her eggs will have the b gene as all dad's spermatozoids will have the B gene.  If you want to make the Punnett square, you'll find that all babies will have 100% probability to be Bb\n____|__B__|__B__\n__b_|_Bb__|_Bb__\n__b_|_Bb__|_Bb__\nThe second generation is made by taking two of those offspring and crossing them.  First, you have to find out what alleles will be in the gametes.  Half of the eggs will be b and half will be B.  Also, half of the spermatozoids will be B and half will be b.  In the Punnett square you'll have.\n____|__B__|__b__\n__B_|_BB_|_Bb_\n__b_|_Bb__|_bb__\nHere, the babies will have 25% chance to have blue eyes (bb) and 75% chance to have brown eyes (25% homozygotous BB and 50% heterozygotous Bb).
697063
All of the offspring will be hetrozygious for tall (Tt) \n\nDominant Traits tall  colored seed coats axial flowers green pea pods inflated pea pods yellow peas round peas \nRecessive Traits short white seed coats terminal flowers yellow pea pods constricted pea pods green peas wrinkled peas \n    Remember that cells have pairs of chromosomes.  Each chromosome in a pair contains genes for the same characteristics.  Thus in Mendel's pea plants each cell in the plants contained two chromosomes which each held a gene to determine whether the plant was tall or short.  The genes on the chromosomes are called alleles.  Each allele or gene is either dominant or recessive.  A dominant allele will be used in transcription instead of the recessive allele.  In other words, if there is a chromosome with a dominant gene and a chromosome with a recessive gene, then the dominant gene will decide the characteristic for the plant.  As in the chart above genes standing for tall plants dominate over genes standing for short plants.  Alleles are denoted with a letter.  We will use "t" for tall for our example.  "T" means that there is a dominant allele and "t" means that there is a recessive allele. \nTerms needed to proceed: \n\nPhenotype - the way an organisms genes express themselves; either short, tall, green, etc (physical type). \nGenotype - the gene type of an organism; the alleles of a certain characteristic:  TT, Tt, tt. \nTT - means that the chromosomes that carry the alleles for a certain characteristic both have a dominant gene. \nTt - means that one of the chromosomes of a pair has a dominant gene while the other has a recessive gene for the certain characteristic. \ntt - means that the chromosomes that carry the alleles for a certain characteristic both have a recessive gene.\nIn Mendel's experiment he crossed a tall pea plant with a short pea plant:  TT    tt \nThe offspring were plants with a tall phenotype and with a dominant allele and a recessive trait:   Tt     Tt \n\nWhen these plants self-pollinated themselves they crossed a Tt cell and a Tt cell.  This resulted in plants with the genotype (gene type) of  TT   Tt   tt.
473864
Genotypes of man and woman : DdPp x DdPp\nPossible gametes of man and woman: DP Dp dP dp X DP Dp dP dp\nChildren: I guess its a dihybrid cross with 9:3:3:1 ratio of phenotypes since you have not mentioned the kind of inheritance.
969016
I believe that these questions  relate to the "Hardy-Weinberg equalibrium" for population genetics.\nP(purple/dominant)=700 or .7\nq(White/recess.)=300 or .3\nP+q= 100% or 1.00\nPlug these numbers into the quadratic equation:\nP squared + 2Pq + q squared  = 1.00\nnote: the 2Pq represents the hybrib condition\n\n#1 P=.7 , q =.3      Ans.  B\n#2  2(.7)(.3) = .42        Ans. ????\n#3      Ans. A ??\n#4  q = .0001 Ans. A\n#5 2(.9999)(.0001) = .00019   Ans.A
348504
Genotype of the man-Pp\nGenotype of the woman-Pp\nPossible genotypes of children-PP, 2Pp, pp\nPossible phenotypes of children-2 carriers, one that has it, one that is completly free of it\nProbability of PKU disease in their children-25%
190009
yeah like the first person says. it all depends because there are dominant and recesive genes or chromosomes or whatever, and i think green is dominant, but if you get get 2 blues they dominate over 1 green, i think that is how it works.
612642
brown is dominant, green and blue are recessive, therefore both parents have two copies of the gene for their eye color therefore they don't have a brown gene to pass on.
812959
A " dominant " gene only means that gene is expressed. Africans have no more dominant genes than anyone else. Are you confusing a dominant gene with a gene for dominance?
958482
The dominate gene, or trait is stronger than the recessive.\n\nSay your dad has brown eyes. Your mon has green.  (brown is the dominate gene)  You would have more brown in your eyes cause the brown gene is dominate (stronger)\n\nWill
871407
1. The trait must be genetic.\n\n2. There needs to be variation within the gene between different individuals (e.g. two or more alleles for a single gene).\n\n3. There needs to be differing fitness between alleles (e.g. one allele gives a reproductive advantage over another).
1177562
you're asking this question because the darker-skin pigment genes *do* tend to be dominant or co-dominant. the answer may go back to your father's parentage ... were his recent ancestors all latino? recessive genes can skip generations before showing up.
901637
Let B mean the genotype for dominant black fur and b mean the genotype for brown fur. \n\nRecall that when a gene is dominant, it is always expressed when  it is present. When a gene is recessive then it is ONLY expressed  when there is no alternative.\n\na) Pure black mice would have B1B2 and brown mice must be b1b2 because it is a recessive gene. (I've put in the numbers to act as subscripts so it makes more sense.) Crossing these, you would get offspring that inherit one gene from each parent.\nB1b1 ==> black\nB1b2 ==> black\nB2b1 ==> black\nB2b2 ==> black\n\nSo false because all the offspring from pure black and brown rats would be black. \n\nb) True. Pure black mice have BB. As both parents have BB then there's not a chance for bb to occur!\n\nc) False. Brown mice are always bb (recessive) so bb x bb can never result in Bb or BB. So offspring of 2 brown mice are always brown.\n\nd) Heterozygous black mice are Bb. So crossed with brown mouse bb (b1b2):\nBb1 ==> black\nbb1 ==> brown\nBb2 ==> black\nbb2 ==> brown\nSo you get equal numbers of black and brown offspring. True.