maths terms - grade 8 - algebra?
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Megami of Nekro is mostly correct, but I will try to clarify the situation a bit. \n\n1. factorize, or factor\n\nIf you have an algebraic expression that can be described as the product of some simpler expressions, to rewrite the expression as this product is to factorize it. \n\nSuppose you want to factorize the polynomial x^2 -3*x. In the case of polynomials of some degree, we regard polynomials of lower degree as simpler. In this case, the polynomial x^2-3*x is of degree 2, because the biggest power of x is 2 (the x^2 term). The lower degree polynomials in this case are of degree 0, called numbers, and of degree 1, called monomials. We can write the polynomial x^2-3*x as the product of lower order polynomials in the following way:\n\nx^2-3*x=x(x-3)\n\nThe two monomials x and (x-3) are factors of the polynomial x^2-3*x, and by expressing the polynomial as a product of two lower order polynomials, we have "factorized it" or "factored it". \n\n\nHere is another one:\n\nx^4+2x^2+1 is factorized as \n(x^2+1)(x^2+1)\n\nWith grade 8 mathematics, you cannot go any farther than this. We replaced a 4th degree polynomial with the product of its two factors, two 2nd degree polynomials (remember, we have decided that lower degree polynomials are simpler)\n\n\nAside: It is also interesting to note that one can factor whole numbers sometimes into a product of smaller whole numbers, which we regard as simpler. Therefore, \n\n10=5*2\n\nand 24=2*2*2*3\n\nThis is also called factoring. Numbers that can be expressed this way are called composite numbers. Numbers that cannot be expressed this way are called prime numbers (the real definition is slightly more complicated: you can look it up).\n\n2. Expand\n\nTo expand an expression is usually the opposite of factorizing. You multiply all the parts of the expression, at least as much as you can, using the distributive law, etc. \n\nIn the case of the expression x(x-3), we multiply our two monomials and return to the polynomial x^2-3*x:\n\nx(x-3)=x^2-3*x\n\nHere is another example. To expand\n\nx*(y-2)*(z+5)*y\n\nwe just multiply these factors together, \n\n x*(y-2)*(z+5)*y=\n(xy-2x)*(zy+5y)=\nxzy^2+5xy^2-2xzy-10xy\n\n\n\n3. Simplify\n\nThere is some ambiguity about what it means to simplify an expression. Computer algebra programs that simplify expressions sometimes use one definition of the simplest expression, and sometimes another. It all really depends on what shows up the features you are more interested in at the time. \n\nUsually to simplify an expression you have to do things like:\n\na. add up any like terms\n\nTo simplify  5x + 2y+ 2x+3+4, we add the terms with just numbers in them, and add the terms with just xs in them:\n\n5x + 2y+ 2x+3+4=7x+2y+7\n\nb. Multiply any numbers that can be multiplied\n\n5*2*x+2+y simplified is usually 10x+y+2\n\nc. Usually, when one simplifies an expression, the big powers are presented first, and the small powers follow (or sometimes vice versa).\n\nx+x^3+x^2 can be simplified as either \n\nx^3+x^2+x or x+x^2+x^3, depending on taste, the needs of the moment, etc.\n\n\nd. Usually when simplifying, any numbers or polynomials in ratios that can be divided will be\n\nSo 10/6 is often simplified as 5/3\n\nAnd (x^2-3*x)/x is often simplified as x-3\n\nHopefully that should get you started.
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http://thesaurus.maths.org/mmkb/entry.html?action=entryById&id=3206\n\nhttp://mathforum.org/library/drmath/view/51899.html\n\nhttp://www-staff.mcs.uts.edu.au/~don/pubs/solving.html\n\nhttp://thesaurus.maths.org/mmkb/entry.html?action=entryById&id=3206
833246
More than one answer.\n\n(a) (8/ [8-3-3]) ! = 4! = 24\n\n(b) 8 / (3 - [8/3]) = 24 \n\n(c) In base-9 maths:\n8 + 8 + 3 + 3 = 2 (9s) + 4 units = 24\n\n(d) In base-11 maths:\n3^3 - 8/8 = 2 (11s) + 4 units = 24\n\n(e) In base-12 maths:\n3^3 + 8/8 = 2 (12s) + 4 units = 24\n\n(f) In base-26 maths:\n8! / (8-3)! x 3! = (8 x 7 x 6) / 6 = 8 x 7 = 2 (26s) + 4 units = 24
655551
http://www.algebra.com/tutors/   \n \nwww.homeworkspot.com  \n\nmathforum.org  \n\nhttp://www.awesomelibrary.org/Classroom/Mathematics/Middle-High_School_Math/Middle-High_School_Math.html  \n\nHOPE THAT HELPS!!!!!! :-D
714807
don't take it personally. they're just joking around. it's all pretend. fun and games, y'know. algebra two is pretty tough. when are you gonna take algebra three?
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Try\n\nhttp://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/index.htm\n\nYou can also try http://www.helpalgebra.com\n\nGoodLuck!
91424
x*SQRT(8+3x)*SQRT(50-4)*2x^2?????\n\nYour statement can be expressed as different algebraic expressions.\n\nExample: The last statement, "2x squared" can be 2x^2 or (2x)^2.\n\nTry to write it in algebraic form with, paranthesis if needed.
825528
6x - 3 - 4 - 8x = x +2\n\nLike Terms\n\n-2x - 7 = x + 2\n\nAdd 7 on each side\n\n-2x = x + 9\n\nSubtract x on each side\n\n-3x = 9\n\nDivide by -3 on each side\n\nx = -3
780298
first u distribute the - to the stuff in the parenthesis so you have\n7x^2-3+x^2\nthen combine like terms\n8x^2-3
102673
If you can't get an answer here, try asking your Algebra teacher for extra help after school tomorrow.  It's sure to add to your grade that you asked for the help.
209884
This acronym helped me out a lot when trying to figure out algebra. PEMDAS (Please Excuse My Dear Aunt Sally) It shows you the order in which you solve the problem. First off you start with anything in parentheses. Then you solve the Exponents. Next comes Multiplying or Dividing. And finally you Add or Subtract. Hope this helps!
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Are you trying to factor?\n\n2^(x+1) * 8^(-x)\n\nYou can solve this by remembering that a negative exponent term in the numerator should go into the denominator as a positive exponent term. Remember also that y^(x+1) = y*y^(x)\nand that 2^(x+1) with 8^x means that for any number, x, there is one more "2" than there are "8"\n\nThis is easily a homework question. You'll have to complete it from here.
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http://www.algebrahelp.com\nhttp://www.factmonster.com\nhttp://www.mathisfun.com\nhttp://www.edhelper.com (can print free worksheets)\n\n(These should be helpful.  I teach 8th grade algebra)
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Some potentially useful vocabulary:\n\nThe answer of an addition is called a sum.\nThe answer of a subtraction is called a difference.\nThe answer of a multiplication is called a product.\nThe answer of a division is called a quotient.\n\nNow, the specific question you are asking... the format of the answer will depend on what it is you have learned. It could be:\n\nb [division symbol] 7\nb[division symbol]7 = ____\nb/7\nb/7=___\n\nor something else! Check your textbook/notes.
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1) -  Y-2x-8 = 0 - so Y=-2x-8\n2) -  Y^2 +8x=0 - (-2x-8)^2+8x=0 \n\n\n4x^2+32x+64+8x=0\n\n4x^2+40x+64=0 - so (4x+8)(x+8)=0 so x=-8 or 4x=-8, x=-2\n\nWhen x=-8, Y-2(-8)-8=0 so Y=-8    A=(-8,-8)\nWhen x=-2, Y-2(-2)-8=0 so Y=4     B=(-2,4)
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A-Arithmetic.\nL-Logic.\nG-geometric patterns.\nE-Exponent\nB-Binomial\nR-Right answers on algebra tests.\nA-The grade I'm gonna make on this acrostic.
605993
algebra is a broad topic. try to go back to ur notes and look for the formulas that your teacher has given to you. better to stick on what is in your notes and textbooks. try this also, ask someome who has taken this subject before...his information might help you...good luck.