if you go 25mph how long wolud it take to get from the north of california to the south. include breaks too.?
153213
You wouldn't make it.  The constant reckless driving charges for driving too slow would make you eventually loose your license.
17281
The answer is 15 to 45 miles per hour
947787
In this equation, you have a right triangle.  After 3 hours, the first car has traveled 150 km south and the 2nd car ahs traveled 210 km west.  You can find the between these two cars at 3 hours by using the Pythagorean Theorem since you have a right triangle.\n\nDistance = sqrt(150^2+210^2) = 258.07 km\n\nThe general form of the Pythagorean Theorem is:\n\na^2 + b^2 = c^2, where:\n\na = distance of car 1\nb = distance of car 2\nc = distance between cars.\n\nTake the derivative to find how the rates are related to one another.  Take the derivative with respect to time:\n\n2a(da/dt) + 2b(db/dt) = 2c(dc/dt)\n\nIn this problem, we are looking for dc/dt.  These are our known values:\n\na = 150 km\nb = 210 km\nc = 258.07 km\nda/dt = 50 km/hr\ndb/dt = 70km/hr\n\nPlugging these values for the equation above, solve for dc/dt:\n\ndc/dt = [2a(da/dt) + 2b(db/dt)]/[2c] ------->\n\n[(2*150*50) + (2*210*70)]/(2*258.07)\n\nTherefore, dc/dt = 86.02 km/hr.  Now change to km/sec:\n\n(86.02 km / 1 hr)(1 hr / 60 min)(1 min / 60 sec) = 0.024 km/sec\n\n-----------\n\nHope this helps
870630
Its 6870mi from Atlanta to Tokyo. If your West coast, take off about 1 to 2000 mi, and if your in Hawaii you should know already...
325281
OK, this is a simple unit conversion problem, buddy. First, get your measurements into similar units: in this case, change your minutes into hours (1 hr/60 min). You'll end up with.\n\n(40 km/h * .5 h) + (60 km/h * .25 h)\n\nThe hours will cancel out, and you'll be left with the kilometers.\n\n20 km + 15 km = 35 km\n\nIn this instance, the direction of travel doesn't matter: the question asks the distance traveled, not how far away from the point of origin you are.
694191
S = southbound speed\nN = northbound speed\nd = distance\nx = time from 8am\nS(x) + N(x-1) = d\n\nS*2 + N*1 = 500  => N = 500 - 2S\nS*3 + N*2 = 850 = 3S + (1000 -4S) = 1000 - S\nS = 150, N = 200
205365
Let r = the rate on the country roads.  Then r-9 is the freeway rate since he travels 9 mph slower there.  The formula needed is d=rt, or in another form t = d/r where t = time, d = distance and r = rate.  Since both have the same t, \n\n20/r = 15 (r-9)\n\ncross multiply to get 20r - 180 = 15r\n\nadd 180 to both sides and subtract 15r from both sides to get\n\n5r = 180   Divide by 5 to get\n\nr = 36.  So he goes 36 mph on the side roads.
1024302
Cruising Range:\nLand at 25 MPH: 300 Miles\nWater at 2600 RPM: 7 Hours\nCruising Speed:\nLand: 20 to 30 MPH\nWater: 6 MPH\nMaximum Speed Forward:\nLand: 45 MPH\nWater: 8.2 MPH\nMaximum Speed Reverse:\nLand: 12 MPH\nWater: 4.5 MPH
36001
A: 56 mph x 1.5 hours = 84 miles\n\n\nB: Distance = 100 total miles - 84 miles = 16 miles.\nTime = 30 minutes = 0.5 hours.\n\nAverage speed = 16 miles / 0.5 hours = 32 miles per hour.\n\n\nC: Total trip miles = 100 miles\nTotal time = 2 hours (1 hour 30 minutes for first leg, 30 minutes for final leg)\n\nAverage speed = 100 miles / 2 hours = 50 miles per hour.
837353
Without the stop they went 100 miles at 150 mph.  \n\nt = 100 / 150\nt = 2/3 hour = 40 minutes.\n\nBut they stopped for 1 minute, that makes 41 minutes or 41/60 hours.\n\nDetermining their average bus speed over the 100 miles:\n100 miles = r * 41/60\nr = 100 * 60/41\nr ≈ 146.341463 mph
481716
distance = 160miles\nave. speed = 50mph\n\n160/50 = 3.2 hours or 3hours and 12 minutes\n\nfor the guy to arrive at exactly 11:30am\n\n(11:30) - (3hours12minutes) = 8:18am\n\nANSWER: 8:18am
894408
A.\nThey drove more distance on the highway than in the city, which come from 2 reasons:\n\n1. They spent more time on the highway, viz. 50 min.  at 60mph this would be 50 miles.\n2. Their average speed on the highway was 60mph, and only 30mph in the city. For equal times, the distance difference will be at a rate of.60-30 = 30mph\nThe total difference between highway and city distances is 100 miles.  Of this, 50 miles are due to extra time on the highway.  So 50 miles are due to speed difference.  The time spent in the city is, therefore, 50/30 hrs = 100 mins.\n\nSo they spent 100mins in the city and 100+50 = 150 mins on the highway.  So total distance=\n30*100/60 + 60*150/60\n= 50 + 150\n=200 miles.\n\nB.\nAnother way. Let the distance travel led in city be x miles.  Distance traveled on highway = x + 100 miles.\ntime in city = x/30 hrs\ntime on highway = (x+100)/60 hrs.\n\ntime difference:\n(x+100)/60 - x/30 hrs\n= x + 100 - 2x mins\n=100 -x mins.\n\nbut we know this is 50. so\n100 - x = 50\n>>\nx = 100 - 50 = 50. (=distance in city)\n\ndistance on highway = 100 + x = 150.\n\nTotal distance = 50 + 150 = 200 miles.
714444
About 175km \n\nabout 2hours 29 minutes
162000
1791.8 miles\nApproximate Travel Time: 27 hours 33 mins
543890
It takes four hours to travel those 300 miles, not counting the stops, so the average speed is 75mph (300 divided by 4).\n\nWith the wind slowing it down, it would be traveling 65mph.  It would then take 4.615 hours in transit (300 divided by 65), which works out to 4 hours 37 minutes (60 minutes * .615 to get the fraction of an hour, plus the four hours).  Add the two half hour stops back in and the total time including stops is 5 hours 37 minutes.
1175600
They will meet when:\n\n4mph x Time = 3miles - 5mph x Time\n\nSo the answer is 0.33333 hours \n\nOr just 20 minutes.\n\n(not 27)
554409
As you can tell, there's not really enough info within the problem itself to solve it.  You'll need to get a map, atlas, or some internet source to determine how much of the 481 miles will be driven in Oregon, and how much in California.  I won't look that up for you, but let's pretend that it's 121 miles in Oregon, and the other 481-121=360 miles in Cali.\n\nAssuming you constantly maintain the speeds indicated, you can calculate the time it takes you for each leg of the trip by using the formula:\n\n   distance = speed x time\n\nOr, equivalently,\n\n   time = distance / speed\n\nSo, for the 121 miles in Oregon, over which you will be traveling 65 mph,\n\n   time = 121 miles / 65 mph = (approximately) 1.86 hours\n\nand for the 360 miles in California, over which you will be traveling 70 mph,\n\n   time = 360 miles / 70 mph = (approx.) 5.14 hours\n\nAltogether, then, you'd be traveling 1.86 + 5.14 = (approx.) 7.00 hours.\n\nIf you want to write that out as one long problem, you could write it this way:\n\nTotal Time = Time1 + Time 2\n           = Dist1/Speed1 + Dist2/Speed2\n           = 121 mi/65 mph + 360 mi/70 mph\n           ~ 1.86 hr + 5.14 hr\n           ~ 7.00 hr\n\nNow, don't forget, I picked the distance values, 121 and 360 miles, out of thin air.  You'll need to look them up and do the problem yourself.  But hopefully that should give you an idea of how.  Good luck!