How can I determine the equivalence point on a titration curve?
152408
Use excel to give delta y/delta x on the curve. Look for a point where this value (the derivative) shoots up in value. That's your point.
602416
http://www.scienceaid.co.uk/titration.html
813100
ΔH =ΣΔHf°prod-ΣΔHf°react
235402
See comment above.\n\nYou do need to do several trials at various concentrations though. You can then determine it through a linear regression.\n\nI also suggest that you consult a book on Analytical chemistry, because Beer's law has limitations. For example, it loses linearity at higher concentrations.
390546
I'll give you a hint.\n\nDelta G = Delta H - T Delta S\n\nUsing that formula, you can get 1\n\n(B) you can look up in any physical chemistry text:\n\nG(2) - G(1) = a formula I don't have available
778184
PV=nRT\n\nn is doubled.\nT, V same.\nR is constant\n\n=>P has to be doubled to validate the eqn.
466006
Pick a few easy points like pi/2, pi, 3pi/2, 2pi.  You know the period.  Then just graph it.
948423
You are going the wrong way.\nThe dissociation constant of a weak monoprotic acid is Ka. If you have a polyprotic acid then you have Ka1,Ka2,etc and more than one equivalence points.\n\nDo the plot, find the equivalence point, and then pKa=pH for 1/2 volume of base of that needed to reach the equivalence point.\nSince you have a weak acid you don't have the equivalence point at pH=7 but at higher pH (The equivalence point will be at the middle of the rising curve). \nThen Ka=10^-pKa\n\nYou can have a look at \n\nhttp://www.shodor.org/unchem/basic/ab/\n\nhttp://www.chemguide.co.uk/physical/acidbaseeqia/phcurves.html
980208
ok, im going to assume that you know (rho)(g)(h) = pressure\n\nlets label 4 points:\nA is at the bottom of the 1.28cm mark\nB is at the top of the 1.28cm mark\nC is at the bottom of the hl mark\nD is at the top of the hl mark\n\nNotice 2 things:\n1. the pressures at A on the right and the left must be the same\n2.if you removed the same amount of blue from both sides, hl would still be the same measurement (so lets remove it for calulations)\n\nnow the blue on the left side is of a height of 1.28+hl and the green on the right is 1.28\n\nat the top they are equal, so:\n2.25*g*(1.28+hl)=8.41*g*(1.28)\n2.25(1.28+hl)=8.41*1.28         g cancels from both sides\n2.25*1.28+2.25*hl=8.41*1.28\n2.88 + 2.25hl = 10.765\n2.25hl = 10.765 - 2.88=7.885\nhl = 7.885/2.25 = 3.50435.....cm
375635
Kp=Kc(RT)n\na.Kp=Kc(RT)-1/2\nb.Kp=KcRT\nc.Kp=KcRT\nd.Kp=Kc(RT)2
973794
moles = concentration* volume\n\nfind the moles of the substance with given concentration and volume\n\n\nwrite and balance the equation. determine the moles equivalence of every reactant then use the equation above
838358
i can't give you the answer but i used my ti-83 and i can tell you the points of the graph...\n(1,0) (2,4) (3,8) (4,0)\n\nHope this helps
72964
thats easy, just chaeck your points and click on the link. thaen look at the second chart and look at the 1st and 4th colums
754842
thats not so hard... all you have to do is titrate it against an acidic solution of known concentration that has a mole ratio of 1:1with sls. add a indicator ( phenolphthaleine) to find the endpoint and that should do it.
464799
I assume that you have an equation such as A and B react together to give C. Work out the molar ratios of each, i.e. is it 1 equivalent of A reacted with 1 equivalent of B to give 1 equivalent of C?\nAssuming it is a 1:1:1 ratio, then look at the amounts you actually reacted - chances are that you did not use 1 mole of each of the reactants. Work out the molar quantities of each reactant. (mass used/molecular weight of compound)\n\nIf you used 0.5 moles of each, then you would get 0.5moles of product and just convert this to a mass.\n\nIf one of the reactants is in excess, e.g. 0.5 moles of A and 0.8moles of B was used, ignore B because as there is only 0.5 moles of A you would only make a maximum of 0.5 moles of C.\n\nHope this helps
370091
"a" and "b" are characteristic constants of the electrode system. A plot of electrode potential versus the logarithm of current density is called the "Tafel plot" and the resulting straight line the "Tafel line." "b" is the "Tafel slope" that provides information about the mechanism of the reaction, and "a" provides information about the rate constant of the reaction. \nRigorously, the equation should be written using the absolute value of the current density and the ± sign for anodic and cathodic overpotentials, respectively. Also, the equation holds only for relatively high overpotentials, approximately 0.1 volt or higher. \nFor example:a plot of  h (greek alphabet not available,its "eta") vs. log of anodic current with a=0.5 (a is the cathodic electron transfer coefficient). The linear plot is of the Tafel equation. The slope b is 2.3RT/anF. The intercept at h=0 gives the exchange current density i0. This is known as a Tafel plot. With this we can calculate a and i0.
363124
detlaH=H(products) - H(Reactants)\n\n200KJ/mol