Any help with this math problem?
150640
Since D= (L^2 + w^2 + H^2)^1/2 then\nD^2 = L^2 + W^2 + H^2\nW^2 =  D^2 - L^2 - H^2\nW = (D^2 - L^2 - H^2)^(1/2)\nOR W = SQRT (D^2 - L^2 - H^2)\nNOW FOR L = 12, D= 13 AND H=3 YOU HAVE\nW= SQRT (169 - 144 -9) = SQRT (16) = 4
285246
hey this is the math section\nthere is an another section for this type of question\nu had better post it their 4 a better response
912865
bring the a's to one side... u then get 9a = 27 ... divide and answer is a = 3
30019
28 - 7*2*2\n\n155 - 5*31
828643
Here are some sites that might help:\n\nhttp://www.math.com/index.aspx\n\nThis one has lots of other links:\nhttp://www.sosmath.com/wwwsites.html
113980
Use a calculator - numerator divided by denominator will give you the answer.
192062
Maybe this link will help:\nhttp://www.mathinvestigations.com/
509467
1: x<12\n2: x>257\n3: x>42\n4: x>84\n5: x>25\n6: x>179\n7: x<8\n8: x>577\n9: x<113
908965
the answer is pi 3.14. use the pythagoran therom with x= pi(r2) then compensate for the remainder and it'll work itself out. If that doesn't work, try FOIL. first, outside, inside, last.
467967
this is probably not a perfect answer but this site may give you some clues.\n\nhttp://www.gomath.com/Questions/question.php?question=4751\n\naltrnatively type 'prove v*v = 2gr*r/s+v0*v0-2gr' into a search engine and see what comes up.
538111
yeah.....!!!! just calculate it!!! lol
329355
Try solving this one:\n\nDetermine all pairs of positive integers (a, b) such that\n\na^2/(2ab^2-b^3+1)\n\nis a positive integer.\n\nNote that in 2ab^2 just the b is squared.\n\nGood luck!
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
780025
x ≤ 5\n\n-- - - - - - -s-
137681
Ok...\nI see what you are doing...\nYou merely substitute the number in for x...\nso the problem becomes 6-2*(-1)\n6+2\n8
1067700
Let the numbers be n and n+1 (consecutive)\n\nthen the answer is 2n(n+1)\n\nYou know, I can tell you're really trying, (not just fishing for homework answers) because you didnt ask the whole question, just the part you needed help with setting up properly.\nGood Luck!
987327
Find a number X such that  2X = (X/2) + 99\n\nmultiply both sides by 2 to get  4X = X + 198\nsubtract X from both sides to get 3X = 198\ndivide both sides by 3 to get X = 66\n\ncheck work\n2*66 = 132\n66/2 + 99 = 132