In hydrolysis of haloalkanes, is OH the nucleophile of H20 if u are using aqueous silver nitrate and ethanol?
156987
OH- is not substituted in haloalkanes using water it is done using NaOH and KOH.\nRX + NaOH--->ROH +NaX\nHalo arenes can be converted to phenols using water if they contain many electron withdrawing groups like NO2+.(eg)picric acid.\n2,4,6 Trinitro chloro benzene + H2O--->picric acid \n                                     (2,4,6 trinitro phenol
382458
H2 + Cl2 -> 2HCl\n2Ag + H2S -> Ag2S + H2 \nCH4 + 2O2 -> CO2 + 2H2O\n2HgO -> 2Hg + O2\n3Fe + 4H2O -> Fe3O4 + 4H2
876773
The first reaction is simply wrong.  Nitrous acid does not ionize to nitrate.\n\nThe second reaction is a precipitation reaction, showing the net ionic equation.  The compound is ionic.\n\nThe third reaction is an example of SN2 displacement, not elimination.  Only single bonds are formed.
68089
With chemicals like NaBH4 you ought to say which solvent you mean. I will assume slightly alcaline water, adding OH(1-) to the equation:\n\nAg(1+) + 1 electron -> Ag (+-0)\n\nBH4(1-) -> "B(3+)" + "4 H(1+)" + 8 electrons.\n\nBoth the resulting hydrogen and the boron need hydroxide ions to remain in the solution, one each for every positive charge above. \n\nMultiply the silver equation by 8 to balance the electrons in the redox reaction.\n\nThis yields:\n\n8 AgNO3 + NaBH4 + 7 OH(1-) -> 8 Ag + 8 NO3(1-) + 4 H2O + H3BO3 + Na(1+)\n\nIf you need to write the result as neutral salts, add more sodium ions for the hydroxide.
457637
Aluminum Nitrate, Al(NO3)3, since, in a neutralization you take off any acidic hydrogen's, and any hydroxyls, and you combine the remaining ions in a way that the product molecule has no net charge. So\n Al(OH)3=Al(+3) + 3OH(-) \n HNO3 = H(+) + NO3(-)\nThe H(+) ions and OH(-) ions combine to form water, and each Al(+3) ion combines with 3 NO3(-) ions to produce Al(NO3)3 \n\nFormic acid (CHOOH) and sodium hydroxide(NaOH) produce Sodium formate, CHOONa, for the same reason as above.\n\nNote: The other H in Formic Acid is non-acidic, and so is not replaced by Na
638948
The reaction NaOCl + NH3 = NH2Cl + NaOH is very easy even cold. The reaction NH2Cl + NH3 + NaOH = N2H4 + NaCl + H2O is not so easy as it requires heating to boiling or close to it.\n\nHere's the link: http://www.sciencemadness.org/talk/post.php?action=reply&fid=2&tid=1128&repquote=20454
868179
2Rb + 2 H20 --> 2RbOH + H2
339232
Yes, the reaction would spontaneously occur because Sn is higher on the activity series than Ag.\n\nSn(s) + 2AgNO3(aq) => Sn(NO3)2(aq) + 2 Ag(s)\nThe net ionic is\nSn(s) + 2Ag+(aq) => Sn+2(aq) + 2 Ag(s)\n\nI don't remember the oxidation number for Sn.  2 sounds about right.\n\nIt would turn a silver nitrate solution to a tin nitrate solution, and you'd see metallic silver precipitate out.
290781
MgSO4(s) + 2HCL(aq) ---> H2SO4(aq) + MgCl2 (aq)
215604
C6H12O6(s) ---H2SO4--> 6C(s) + 6H2O(in H2SO4 solu.) + Heat
311033
H2SO4 - H20 = SO3\n\nAnyhydride is the removal of the atoms of water, therefore leaving Sulphur Trioxide.
713470
fatty acids and alcohol esters are easy, they just need:\n\n1. Heat\n2. Acid catalyst (often PTSA or sulfuric acid)\n2. Vacuum\n3. Nitrogen sparge\n\nthe alcohol group will react with the hydrogen on the fatty acid producing water, if the water is not remove, the bond will be hydrolyzed, which is why the vacuum is required to strip out the formed water.
813911
HBr ---> H(+) + Br(-)\nH2SO3 ---> H(+) + HSO3(-)\nCH3-COOH ---> H(+) + CH3-COO(-)
942020
We've to get this clear first. Water is a polar solvent, gasoline is a non-polar solvent. By the principal of like-dissolves-like, polar molecules will dissolve in water, for example, NaCl; while non-polar molecules will dissolve in gasoline, for example, fats, phosholipids, alkanes, alkenes etc.\n\nFor the question you've asked,\nChloroform is a polar compund because Cl draws electrons from the carbon center and making Cl atoms have a higher concerntration of electrons. Hydrogen atoms in water carry a partially positive charge and hence are attracted to Cl molecule. Hence it is soluble in water.\n\nNa2SO4 is soluble in water. This is because it is actually 2 Na+ ions attached to SO4(2-) ions. Na+ ions get attracted to oxygen atoms in water which has a partially negative charge and SO4(2-) ions gets attracted to hydrogen atoms in water which has a partially positive charge.\n\nKCL is soluble in water because Cl atoms draws electrons from K. Follow the same reasoning as chloroform.\n\nFor BaSO4, it is insoluble in water. Only barium nitrate dissolves in water. Other barium salts do not.\n\nHope this helps! =)
745017
Your question isn't really complete - the NaOH needs someting to react with.\n\nFor example:\n\nNaOH is used with lipids to make soap.\n\nNaOH + HCl -> H2O + NaCl
245442
Wait...not mixed with H2O? As in, molten liquid ammonia and molten liquid sodium sulfate? In that case no reaction. But with water, then:\n\n2NH3 + Na2SO4 + 2H2O --> (NH4)2SO4 + 2NaOH
262916
4 OH-(aq) --->  O2(g) + 2H2O(l) + 4e-