if -3 = -45/sqrx^2 - 1,   what i the value of x^2?
142254
-3 = -45/sqrx^2 - 1  :: multiply both sides by sqrt(x^2-1)\n\n-3*sqrt(x^2-1) = -45   :: divide both sides by -3\n\nsqrt(x^2-1) = 15 :: square both sides\n\n(sqrt(x^2-1))^2 = 15^2\n\nx^2 - 1 = 15^2  :: add 1 to both sides\nx^2 = 15^2 + 1\n\nx^2 = 226
10571
50 is right.\n{i^2 -(-1)^i | i=1,2,...}
21852
Square Root of negative 11\n= √-11\n= √(11 * (-1))\n= √(11 * i                       since √-1 = i.\n= 3.31662479035539984911493273i
469289
3x^2 = 12\n\nFirst, divide by three.\n\nx^2 = 4\n\nTake the square root.\n\nx = +2, -2
851434
-x^2 if x=-2\n-(-2)^2  \n-(4)\n-4
801012
inverse square root of a number say"x" is\nx^[-(1/2)]
215050
2x²-2x-3=0\n2(x²-x-3/2)=0\nx²-x-3/2=0\n\napply the quadratic formula\n=>a=1 b=-1 c=-3/2\n\n=>[-(-1) + or - √(-1)²-4(1)(-3/2) ]over 2(1)\n\n=>[1 + or - √1+6] over 2\n=>[1 + or - √7] over 2 [answer]
60538
if [ -7x + x^2 =0 ]\nthe you will get y = 7/x
830946
c)\n\n= x^3 + x^2 + x - x^2 - x -1\n= x^3 -1
970375
to SUBSTRACT a negative integer means to ADD the absolute value.\n\n-45 -(-34) = -45 +34 = -11\n\nokay ?
736337
2/x + 3 = 2\n2/x = -1\n-x = 2\nx = -2
52909
x= -1\ny= 3\n\nSimply substitute the x and y values in the equation.\nTherefore\n=(-1)+3*3\n=(-1)+9\n= 8
846663
(x+3)(x-1)\n\n x= -3\nx=1
295120
1.73\n\nproof\n3 squared = 1.73205080756887729....\nrounded\n1.73
794793
x = 3. Try entering it on your calculator.
1147786
x - sqrt(x) = 0\nx = sqrt(x)\nx^2 = x\nx(x-1) = 0\nx = 0,1\n\nBoth check.
816596
x-11=2(-7)\nx=11-14\nx=-3\n\nCheck:\n  -1/7 (-3-11)=(-1/7)(-14)=2 OK\n\nOr did you mean\n\n-1/(7(x-11))=2    Then\n-1=14(x-11)\nx=11 - 1/14\nx=10 13/14\n\nCheck:\n  -1/(7/-1/14))=14/7=2   OK