Algebra:Find the y- and  x- intercepts of the line 4x+3x=12. Clearly label which is which.?
147089
y intercept: (0,4)\nx intercept: (3,0)
1032854
given the zeroes of y:\nif x = -4, 0 or 2, then y = 0.  Therefore it passes through\n(-4, 0)\n(0,0)\n(2,0)\n\nIn other words -4, 0 and 2 are x-intercepts of the polynomial.\n\nThe polynomial (3rd degree) can be expressed as:\ny = x³ + ax² + bx + c\nIt can also be expressed as\ny = (x - x1)(x - x2)(x - x3) \nwhere n is a constant.\n\nWhen you substitute x1 to the expression\ny = (x1 - x1)(x1 - x2)(x1 - x3)\ny = (0)(x1 - x2)(x1 - x3)\ny = 0\n\nTherefore, x1 is a zero\n\nThe same goes with x2 and x3. Therefore you can put the zeroes into our expression\n\ny = (x - (-4))(x - 0)(x - 2)\ny = (x + 4)(x)(x - 2)\ny = x(x + 4)(x - 2)\nor\ny = x(x² + 2x - 8)\ny = x³ + 2x² - 8x\n\nThat is your 3rd degree polynomial! Hope this helps^_^
341565
Well, first, write it in standard form (y=mx+b).\n\ny = -3x + 0\n\nThe m in the equation is the slope of the line, and the b is the y-intercept. \n\nSlope = -3\ny-Intercept = 0\n\nFor another example, y = 5x + 3 would have a slope of 5 and a y-intercept of 3.\n\n\nHope this helped.
170337
numbers 3 and 4\n\nx(squared) is still an integer and xy/x=y, which is an integer
416338
As halibori says, you can use a graphing calculator and see where the lines cross.   I use a different machine, the one between my ears.   \n\nIf you add the two equations, the +3y in the first cancels the -3y in the second, leaving the equation  4x + x = -8 - 17, or 5x = -25.   This one's easy since the only unknown is x, and we see that x = -5.   Now\nwe can go back to the first equation, plug in the value -5 instead of x, and it becomes\n-20 -3y = -8, or -3y = 12, so we have that y = -4.
66565
You cannot "solve" this because it is not an equation.  An equation has two parts that are joined by the symbol =.  However, in early pre-Algebra classes, they might ask you to simplify this, meaning, to write this expression so that the "x" only appears once with its coefficient and the rest of the numerical values are also combined.  For this, you add all of the coefficients of x (3+1 - invisible coefficient before the second appearance of x) to find that you have 4x.  Next, you add the -8 and 4, which you can then express as either adding negative four or as subtracting four (if you need help here, consider the number line, move eight spaces to the left of zero, then move four spaces to the right).  Thus, you can re-write the expression as 4x-4.  Look in your textbook before the problems for a better example of what exactly they are expecting you to do in that section.
695994
The eqaution of the line is\ny-y1 =m(x-x1)\ny-0 = -3[x-(-4)]\ny-0 = -3(x+4)\ny= -3x-12
845468
Y-intercepts :   .5\n\nX-intercept:   1\n\nAssymptote at x = 2
760751
a) i)  (0,3)\nThe y-intercept is when x=0, right?  So just plug in zero for x and get:\ny=(0)^2-4(0)+3\nWe get 3 since everything else is zero.\n\nii) (3,0) and (1,0)\nOkay, we have to find when the equation is zero for the x-intercepts.  So, set the equation equal to zero (y=0)\n0=x^2-4x+3\nYou can factor this, which is finding two things that, when multiplied together, form this equation.  The two factors are\n(x-3) and (x-1)  Our factored form is\n(x-3)(x-1)=0\nOne of them MUST equal zero for the whole thing to be zero since they are multiplied, but either one can equal zero.  So we have two possible x values: 3 and 1.  Those are the x-coordinates, the y coordinates are zero.\n\niii) (2,-1)\nThe vertex is halfway in between the roots, which are 3 and 1.  You can take the average of them:  (3+1)/2=4/2=2.  The x-coordinate of the vertex is 2.  Now plug that in:\n\n(2)^2-4(2)+3 = 4-8+3=-4+3=-1\nThe y-coordinate is -1.\n\n\nb) x=2\nThis is just a vertical line with the same value as the x-coordinate of the vertex (the line of symmetry goes through the vertex).  The line is x=2
394184
well, you really should do your own homework, but the answer is D. substitute 3 and 7 into the equation for the easy answer.......7=2(3)+1......but to know that, the equation is  y = mx + b. m designates the slope of the line, and b the y-intercept, that is b is the second coordinate of the point where the line crosses the y-axis
284371
To solve this, you need to know how to write the equation of a line:\n\ny = mx + b\n\nYour math book should describe in detail how to derive this equation and what it means. Basically, m is the slope of the line and b is the y-intercept (the x coordinate where the line crosses the y-axis).\n\nYou can take the equation of the line given, y = 4x + 3, and figure these things out.\n\nm = 4 (the slope)\nb = 3 (the y-intercept)\nThis y-intercept can also be written as (0,3) being a point on the line.\n\nThe second part is to figure out the equation for a perpendicular line. First, the slope will always be -1/m. Therefore, the slope of your new line will be -1/4. What about the y intercept? We don't yet know this, but we do know a point on the line. What we can do is use the equation above, fill in the slope and the (x,y) coordinates, and solve for b.\n\ny = mx + b\nWe know: point (x,y) is (-1,3) and m = -1/4\n3 = 1/4 * (-1) + b\n3 = -1/4 + b\nb = 2 3/4\n\nHope that helps explain how to do these problems.\n\nEdit: Sorry, I had the point written backwards as (3,-1). I corrected the mistake. That's why it helps to write everything out!
172343
the easiest way to find a y-intercept is to just plug in 0 for x.\n\nSo, you get:\ny-3=2(0-5)\ny-3=2(-5)\ny-3=-10\ny=-7
564627
change the equation to slope intercept form\nsolve the equations for y\nx+2y=3\n2y= 3- x\ny= -x/2 + 3/2\nDo the same thing for the other formula\nthe form is\ny = mx + b\nAfter that just plug in numbers for x to get y
610726
there is a solution, all x,y that satisfy this equation:\ny = 4 - 2x\n\nwhich is a straight line with intercepts (0,4) & (2,0)\n\nIt has an infinite amount of solutions. To be able to solve for actual numbers, you need as many equations as you have variables.
504744
4. \nquad 1 = (x,y)\nquad 2 = (-x,y)\nquad 3 = (-x,-y)\nquad 4 = (x,-y)
765225
First put the first equation into slope-intercept form or:\n\ny = mx +b\n\nm = slope,  and b = y-intercept\n\n-3x -3y = 2\n+3x        +3x\n\n-3y = 3x + 2\n/-3     /-3\n\ny = -x + 2/3\n\nSo, your slope for the first equation is:\n\nm = -1\n\nTo have a line parallel to the first line, the slopes must equal.\n\n\n\nUse Point-Slope form.\n\ny - y1 = m ( x - x1)\n\nSince you are using the point (-3, -4)\n\ny1 = -4\n\nx1 = -3\n\nSo your new equation will be:\n\ny - -4 = -1 ( x - -3)\n\n(remember the slope must be the same)\n(a minus a negative = a positive)\ny + 4 = -1(x + 3)\n\ny +4 = -x -3\n   -4         -4\n\ny = -x -7\n\nor you can put it back into standard form ( Ax + By = C)\n\nx + y = -7
811806
If x is 2, then 8x is 16.\n\nIf y is 3, then 4y is 12.\n\n16-12 is 4.  :o)