At the raffle , Yvonne won 50 nickels and dimes. Thier value was $4.30. How many nickels and dimes are there?
138815
36 dimes ($3.60), 14 nickels (70¢)\n\nI did it via guess and check. =)
819747
8 total shoes were dropped on the floor.\n\nEmily grabs 1. We are now down to 7 shoes on the floor. 1 of them is the match with Emily and 6 are not.\n\n6/7 is the chance its not the matching shoe.\n\nGood Luck!
90859
3 quarters = 75 cents\n2 dimes = 20 cents\n1 nickel = 5 cents\n\n75 + 20 + 5 = 100 cents, or 1 dollar\n\n1 dollar + 4 dollars = 5 dollars\n\n5/2 = 2.50\n\nSo she has two and a half dollars, or two dollars and 50 cents --- $2.50
311209
You have approximately $18.14. \n\nA penny has a mass of 2.5g. Ten pounds is 4.536 kg. This means you have 1,814 pennies. When you divide this by one hundren, you get $18.14.
635973
p + 5n + 10d + 25q = 100\np + n + d + q = 50.\n\nSubtracting, we get\n\n   4n + 9d + 24q = 50\n\nq can't be more than 2.  If it is two, then 4n + 9d = 2, which is not possible, so q can be at most 1.\n\nIf q=1, then:\n\n   4n + 9d = 50-24 = 26\n\nThis has one solution, n=d=2.  So p=50-q-n-d =45 gives us: \n\n45 pennies, 2 nickels, two dimes, and a quarter.\n\nIf q=0, then 4n + 9d = 50.\n\nWe see that 50-9d is divisible by four, which only occurs if d is even and not divisible by four.  That gives us d=2,6,...  But d<6 (or n is negative.)  So d=2, n=8, which yields the solution:\n\n   40 pennies, 8 nickels, 2 dimes, zero quarters.
836465
5 DOLLA!  \n\nI don't know :(
852289
1.  Let x = numer of nickels and y = number of quarters\n(1) x + y = 20\n(2) 5x + 25y =400 (multiplied by 100 to get rid of decimal)\n-5x - 5y = -100 ((1) multiplied by -5)\n20y = 300\ny = 15 quarters\nx = 20 - 15 = 5 nickels\n\n2.  Same method as 1.\nlet x = no. of $12 seats, y = no.of $6 eats\nx + y = 30,000\n12x + 6y = 228,000\n. 6x + 6y = 180,000\n6x = 48,000\nx = 8,000\ny = 30,000 - 8,000\ny = 22,000
878065
.28 = 1 quarter and 3 pennies\n.28 = 2 dimes 1 nickel and 3 pennies\n.28 = 1 dime 3 nickels and 3 pennies\n.28 = 5 nickels and 3 pennies\n.28 = 2 dimes and 8 pennies\n.28 = 1 dime 2 nickels and 8 pennies\n.28 = 1 dime 1 nickel and 13 pennies\n.28 = 1 dimes and 18 pennies\n.28 = 4 nickels and 8 pennies\n.28 = 3 nickels and 13 pennies\n.28 = 2 nickels and 18 pennies\n.28 = 1 nickel and 23 pennies\n.28 = 28 pennies\n\ntotal 13 ways to mack change for .28.
819558
Theres 7 choices for the first digit, 6 more for the second .. 2 for the sixth. So 7*6*5*4*3*2 = 5040.
814894
About a dollar, not a nickel! lol.\n\nI'll trade u, pennys are not that important anymore.\n\nE-mail me.\n\nI collect pennys and stuff, so i know the value.\nI have a total of 20 dollars in pennys.
259226
here's one with coins that was on one of the worksheets i have:\n\nlet's say, for example, that you have $8.75 in dimes and quarters and there are 65 coins. how many dimes and quarters are there?\n\nso there would be 2 equations:\nd+q=65 (which is how many coins there are)\n\nand\n\n10d+25q=875 (how much money there is in dimes and quarters)\n\nfrom there, you'd solve it up and down like\n\n 10d+25q=875\n+  d+  q= 65 (Multiply by 10)\n---------------------------\n 10d+25q  =875\n+(-10d-10q=-650)\n-----------------------\n       15q= 225\n         q=15\n\nthen you plug in 15 for q for one of the equations.\n\n15+d=65\n65-15=50\nd=50\n\nyou'd have 50 dimes and 15 quarters. (i hope)\n\ni also hoped this helped ^^;
772903
Paula has twice as much money as Don. Together they have $105. How much does Paula have?\n\nP = 2D\nP/2 = D\n\nP + D = 105\nP + P/2 = 105\n\nSeventy two divided by a number is six. Find the number.\n\n72/X = 6\n\nJill's mother was 27 when Jill was born. The sum of their ages is now 51. How old is Jill?\n\nJill's mom is now 27 + J\n\nThe sum is 27 + J + J = 51\n\n\nThe product of a number and 18 is 270. Find the number.\n\n18X = 270\n\nThe sum of x and its square is equal to y times z.\n\nx + x^2 = yz\n\n\nTwice a increased by the cube of a equals b.\n\n2a + a^3 = b
811932
1     $58.50\n\n2     $23.20\n\n3     $38.25\n\n4     $75.60
817306
Number of dimes = x\nNumber of nickels = x + 7\nNumber of quarters = 40 - x - (x + 7) = 40 -7 -2x = 33 -2x\n\n10x + 5(x +7) + 25(33 -2x) = 405\n10x + 5x + 35 + 825 - 50x = 405\n825  + 35 - 405 = 50x - 10 x - 5 x\n455 = 35 x\nx = 455/35 = 13\nNumber of dimes = 13\nNumber of nickels = 20\nNumber of quarters = 7\n\nCheck: Does 13 * 10 + 20 * 5 + 7 * 25 = 405?\n\n130 + 100 + 175 = 405, so the answer is correct.
833257
1. There are a total of 11 coins \nA. 2/11\nB. 0\nC. 6/11\n\n2. \nA. there are 2 possibilities (5,6) and (6,5) out of 36 poswsibilities (6*6).\n1/18\n\nB. 6 possibilities: (1,6) (2,5) (3,4) (4,3) (5,2) (6,1)\n6/36 = 1/6\n\nC. There are no possibilites, the Max sum of two numbers can be 12 (two sixes)\n0\n\n\nGood luck.
719127
Well you got a quarter and a nickel.  Because one of the coins is not a nickel, it is a quarter.  So the other one is a nickel.  Hehehe.... Good one.
210388
10 nickels =  .50      - 1.00\n2 quarters =  .50      -\n\n\n4 dimes       =.40\n1 quarters    =.25\n7 nickels     =.35\n\n2 quarters 10 nickels\n1 quarter 4 dimes 7 nickels\n8 dimes 4 nickels