What does y =? 2y-3+5+4y-10=3y-8+6y+12?
149255
2y-3+5+4y-10=3y-8+6y+12\n\n6y - 8 = 9y + 4\n\n-8 = 3y + 4\n\n-12 = 3y\n\ny = (-12/3)\n\nANSWER : y = -4
351633
4-y-2y=10\n4-3y=10\n-3y=6\ny=-2\n\nx=4-(-2)\nx=6
978183
y = 8\n\n2 + 3y\n\n2 + 3(8)\n\n2 + 24\n\n26\n\nThe answer is 26\n\n-- - - - - - - - - - - s-
298404
4x+y=10\n\n6x-y=20 \n+y   +y\n_______\n6x = 20+y\n-20  -20\n6x-20 = y\n\nreplace 6x-20 in for y with the other equation\n\n4x+(6x-20)=10\n10x-20=10\n+20     +20\n10x=30\nx=3\n\nnow plug in 3 in the equation as x\n\n4x+y=10\n4(3)+y=10\n12+y=10\ny=-2\n\nso x=3 and y=-2\nI think\n_____________________________\nAnother way to do it is get y's alone and set them equal\n6x-20=10-4x\n10x-20=10\n10x=30\nx=3\nand then just plug in like what I did b4
1103883
Y=X^5-X^-3+X^2\nY'=5X^4+3X^-4+2X\nY''=20X^3-12X^-5+2
1031270
x^2 + 5 + 5x + x y +5y\n\nx^2 + xy + 5x + 5y + 5\n\nx(x+y) + 5(x+y) + 5\n\nx(x+y) + 5(x+y+1)       OR     (x+5)(x+y)+5\n\nCynthia
940849
2x + 4y = -6\nX - 3y = 7 multiply by two\n\n2x + 4y = -6\n2x - 6y = 14\n{subtract equation 2 from equation 1}\n\n2x - 2x + 4y - (-6y) = -6 - 14\n10 y = -20 divide by 10\ny = -2\n\n\nplug into a equation \n2x - 6(-2)  = 14\n2x + 12 = 14\n2x = 2\nx = 1\n\nx = 1, y = 2
824262
well... imagine 2 functions\n\n2x + 3y = 5\n-2x + 2y = 10\n\nadd the two togather\n\n5y = 15\ny=3\n\nplug y into one of the first equations\n\n2x + 3y = 5\n2x + 3(3) = 5\n2x + 9 = 5\n2x = -4\nx = -2 and y = 3\n\nyou can check it with the other equation too\n\n-2x + 2y = 10\n-2(-2) + 2(3) = 10\n4 + 6 = 10\n10 = 10\n\nand the system is solved... \n\nx = -2 and y = 3
753426
X2   5x - 4y = 1\n10x -8y =2\n-10x + 8y = -3\n-------------------------\n  0=-1                NO SOLUTION
957836
4x+(-5y)+(-6x)+3y\n4x+(-6x)+(-5y)+3y\n=-2x-2y
124685
y= 2x + 5 y= 6x + 1\ny=y\n2x+5=6x+1\n4=4x\n1=x\ny=2(1)+5=7
203610
b, that's just me doing it in my head.\n3y = -6x + 12\ny = -2x + 4\n\n3y = -6x + 36\ny = -2 + 12\n\nIt's been a while since I've been in a math class, did I do this right?
1009010
y= 40-5x\ny=40-5(6)\ny=10\n10
683580
y^2 + 7y + 3y + 21\ny^2 + (7 + 3)y + 21\ny^2 + 10y + 21\n(y + 7)*(y + 3)
1169467
y = x^2 + 5x - 3\n2y=3x - 2\n----------------\n2y = 2x^2 + 10x - 6\n2y = 3x - 2\n-----------------------\n    0 = 2x^2 + 7x - 4\n=>2x^2 + 7x - 4 =0\n=>2x^2 + 8x - x - 4 = 0\n=>2x(x + 4) -1(x+4) = 0\n=> (2x - 1)(x + 4) = 0\ntherefore 2x - 1 = 0 => x = 1/2 or \nx + 4 = 0 or x = -4\nx = - 4 or 1/2  \ngot it?
728357
3x^2y^2(2y+3y)/3x^2y^2\n=5y
95804
You know that\n              1)3x+4y=12y\n              2)-2x+10=12y\nSo you can substitute 3x+4y for 12y in equation 2. Hence:\n              3)3x+4y=-2x+10\n                   5x=10-4y\n                    x=2-4y/5\nSubstitute this value for x into equation 1 and it becomes:\n              1)8y/5+6=12y\n                     y=15/26\nPlug this back into 3 and you get\n              3)x=2-(4/5)*(15/26)\n                x=20/13\nTherefore the answer to the system is (x,y)=(20/13,15/26)