Identify the x and y intercept of the parola y=x^2 +4x + 1?
142395
well heres the deal, to find the intercepts you need to plug in zero for the other variable\n\ny intercept : (0,y)\nx intercept : (x,0)\n\nso plug 0 in for x as the first part states and get the y intercept\n\nthen plug zero in for y as the second part states and get the x intercept. NOTE: you will need to use the quadratic formula\n\nany questiosn e-mail me\nmatttlocke@yahoo.com
41570
A parabola with its base at 0,1.  Go to http://www.coolmath.com/graphit/ Enter x^2+1 and see it for yourself!  :)
845468
Y-intercepts :   .5\n\nX-intercept:   1\n\nAssymptote at x = 2
845966
There are several ways to do this, but since you mention y-intercept, we'll go that way.\n\nYou should know the formula y = mx + b.  In that formula "m" is the slope.  You are given a point (x,y).  Plug in all three of those numbers, and solve for "b".  Here you'd have\n12 = 2*4 + b\n12 = 8 + b\n4 = b\n"b" is the y-intercept, which here is 4.\n\nGo back and plug "m" and "b" into the formula.\nYour answer is y = 2x + 4.
887097
y=1 is a straight line parallel to x axis\nx=(-1/4) is a straight line parallel to y axis
523941
x intercept y=4 (0,4)\n(plug 0 in for x and solve)\ny intercept x=20/3 (20/3,0)\n(plug 0 in for y and solve)
645941
4x + y >= 4\ny >= -4x +4\n\n-------\ny = 0\n0 >= -4x + 4\nx = 1\n-------\nx = 0 \ny >= 0 + 4\ny = 4\n-------\n\n\nTherefore, shade the region above the line.\n\nTwo points on the line are:\nx-intercept: (0, 4)\ny-intercept: (1, 0)
618527
i'm not gonna solve it...but tell u how to solve it.\n\n-x intercept of vertex : -b/2a\n-y intercept of vertex : f(-b/2a)\n-for direction of opening find f(0)\n-i guess the axis of symmetry is the middle point of something. i cant remember that something.\n-find the relationship urself
238720
So we can find the x-intercept(s)
491455
(x^2+4x+1)/(x-2) = x+2+3/(x-2)\n\nx  : x^2+4x+1-x^2-2x =2x+1\n2  : 2x+1 -2x-4 =3
864283
According to the y=mx+b equation, b = y-intercept.\n\n-4 is b, which is the y intercept.  When x=0, y=-4.\n(0,-4)\n\nThe x-intercept is the value of y when x is zero.\n0 = 4x - 4\n4 = 4x\nx=1\nThus when y=0, x=1. (1,0)
930270
Well done, you have already done the hard work. The number in front of the x is the slope ie -2/13 and the other number is the y co ordinate of the y intercept ie (0 , 5/13). Another way to find the y intercept is to substitute zero for x and solve for y, or alternately substitute zero for y to find the x intercept.
819736
x intercept is when y=0\n\nso this would be x=3\n\n3^2 - 3 -6=0\n9-3-6=0\nso x intercept is 3\n\nproof:\n0= x^2 - x - 6\n6 = x ( x-1)\n6 = 3 (3-1)\n6 = 3 * 2\n6=6
937981
Your goal here is to solve for a, b, and c.  We can easily do this with the facts that we're given.\n\ny-intercept is 2: This means that when x=0, f(0) = 2\n\nso f(0) = b * a^(0) + c = 2\nb + c = 2 (since a^0 = 1)\n\nHorizontal asymptote is y = -2.  Remember that for exponential functions, the horizontal asymptote is always the horizontal shift, which is the constant next to the term containing the expontential.  Thus, in our case, c is the horizontal shift, so \n\nc = -2\n\nCombining this with b+c=2 (which is what we solved for earlier), substituting c=-2 in there yields:\n\nb+(-2) = 2, so b=4.\n\nb=4 and c = -2, so if we plug it back into f(x), we get\n\nf(x) = 4*a^x - 2\n\nPasses through the point (1,4) means we plug in 1 for x and 4 for f(x), to get:\n\n4 = 4*a^(1) - 2, or\n4 = 4a - 2\n6 = 4a\n3/2 = a\n\nNow we have a, b, and c.  The final answer is then:\n\nf(x) = 4*(3/2)^x - 2
780055
1/x + y\n______\nx + y\n\nMultiply the top and bottom by x\n= \n1 + xy\n______\nx^2 + xy\n\n\n(x-1)/x divided by ((x^2 -1)/(x+4)\n= (x-1)/x times (x+4)/(x^2 -1)\nFactor x^2 -1 = (x-1)(x+1)\nYou can cancel the (x-1)'s leaving you with\n(x+4)/[x(x+1)]\n\nNote:  For the first problem, if you meant\n1/(x+y)\n______\nx + y\nthen the answer is 1/(x+y)^2
195576
Y = U + VX^2\nVX^2 = Y - U\nX^2 = (Y-U)/V\nX = sqrt ( (Y-U)/V )
413913
x=0,2,3,4 and y=1,-1,0,3