101-102=1   how can you make this problem true if you can only move one number?
151971
101 - 10^2 = 1... just raise the 2 up a bit.\n\nhope this helps :-)
347406
Dude, so simple.\n\nYou need to find a # that is the lowest multiple of both 3 and 2.\n\nSo 1/2 + 1/3 changes to X/6 + X/6\n\nTo find out the top # you do the same thing that you did w/ the bottom #\n\n1 x 3   1 x 2     3     2      5\n----- + -----  = --- + ---  = ---\n2 x 3   3 x 2     6     6      6\n\nHay, if I help som 1 cheet, than I show them how to the problem, ok?\n\nJackmac :P~
165298
100 - You only have 1 choice for the first digit (7) times 10 choices for the second digit (0 thru 9) times 10 choices for the third digit (0 thru 9). 1 X 10 X 10 = 100. Another way of looking at it is your choices are from 700 thru 799, which is 100 choices.
939267
Let x = "one number". \nThen, the "another number" is 2x.\n\nWhen the larger number is decreased by 10,\n\n2x - 10\n\nThe result is 2 greater than the smaller number\n\nx + 2\n\nTherefore,\n\n2x - 10 = x + 2, and\nx = 12.\n\nSo the two numbers are x and 2x, or 12 and 24.\n\nLet's put it back into the problem.\n\nOne number is twice another.  24 is twice 12.\nWhen the larger number is decreased by 10 (24 - 10 = 14), the result is 2 greater than the smaller number (2+12 = 14).  Therefore that's the answer!\n\nHappy solving!
956128
Simply multiply\n9 * 8 * 7 * 6\nBecause the first number can be 1-9 but not zero and the second number can be 1-9 but one number has already been used and so on and so forth.\nHope it helps.
842688
Think of a number between 1 & 10.\n-----3\n\nMultiply your number by 9.\n-------27\n\nAdd the digits of your answer. (if it was 23 then 2+3=5)\n---------9\n\nWhen done correctly you should be left with a single number. Now minus 5\n---4\n\nIf your number is 1 your the letter A. If it's 2 your the letter B. 3 your C. 4 your D 5 your E etc etc.\n--------------D\n\nGo to the next letter in the alphabet after yours.\n---------E\n\nChoose an animal beginning with that letter no birds or insects though!!!\n---------elephant\n\nHave you thought of one? I'm gonna try and guess it.... ***PHANELET***\nIf you can rearrange these letters to get your animal I got it right ;-)\n\n----------pretty good ;)
297664
Wrap-around, modular arithmetic.  If the sum exceeds 100, subtract 100 so the result is still 2-digit.  And when decoding, if the result goes negative, add 100.
1007006
add or subtract 1\n\nor else subtract the S at the begining of Seven
279409
Find every number between 101 and 999 that is divisible by 7 and then add them together.  Hmmm......like I really am going to do that.
858530
it is possible when X=33.02163079..... try it
136679
Useing a very fine metal blade that will contact the flat area of the shaft that the number wheels are mounted on, Just hold the shaft and rotate the wheel untill the new number you want to use is in the old position. You must prevent the shaft from rotating while changeing numbers.\nCaution.....do this just one wheel at a time or you will lock yourself out.     Any good locksmith can do it for you in seconds. These directions came with the case originally.....These are NOT secrets. By the way, the lock must be open at the time.
921908
1\n\njust do a little bit of trial you will see that the smaller number you use it nears 1.
49715
use bitwise operators. something like:\n\nnum_bits = 0;\nfor(i = 0; i < 32; i++) {\nif number & (1<<i) num_bits++;\n}\n\nnow num_bits holds the number of bits that were set in number. The "<<" operator does bit shifting. So "1<<i" equals a number that's all 0's except for a 1 at position i. If you bitwise and that with something, that tells you if that bit is set in the number. So we do this for each of the bits and add up the results.\n\nThis is assuming 32-bit integers. Adjust accordingly for 64-bit integers.
9961
0,1,1,2,3\n\nto get the next number add the previous 2 numbers
376319
Are you able to use any other numbers and operators?  If so this would be fairly easy.  Using only Three 8's and a subtraction symbol it is not possibe\n\nClosest example (8+8)/8-1=1
785224
An algorithm for solving this would be to divide up the digits and shuffle or switch them in the direction that makes them closer to correct (the "greedy algorithm").  That should work without too much trial and error.
1099193
I assume you mean you can only use the symbols and digits once to make it equal two.  In other words, use 1 2 3 4 ( + ) - and make it equal two.\n\nThat's easy!\n (4 + 1²) - 3 = 2\n\nHere are some other ways I can think of:\n4 + (1² - 3) = 2\n(4 - 3) + 1² = 2\n(1² + 4) - 3 = 2\n(-2 + 4) 1³ = 2\n1 + (4 - 3)² = 2\n1 + (3 - 4)² = 2 (since (-1)² = 1)\n2 ( -3^1 + 4) = 2 (imagine the 1 is a superscript 1st power)\n(2 + 4) 3^-1 = 2 (imagine the -1 is a superscript, so 3^-1 = 1/3)\n+2³ (4^-1) = 2 (-1 superscript, so 4^-1 = 1/4)\n2(+3) - 4^1 = 2 (imagine the 1 is a superscript again)\n(3 + 1^4) - 2 = 2 (imagine the 4 is a superscript 4th power)