need to find out how to find the area of a square?
140062
L x W = Area\n\nCheater
357923
Six times the length of one side squared. The area of a square is the s^2 and a cube has six sides.
522898
Imagine you unraveled the cylinder, the middle would turn into a rectangle, right? so to find the surface area, take the height of the cylinder and multiply it by the circumference of the circles at the bases, then add in the area of the circles. Circumference is 2(pi)r and area is (pi)r^2.
741830
the ratio is 1:2 or 1/2\n\noh, by the way it goes like this:\n\nassuming the length of each side of square A is a, then the area is a^2.\n\nsince, the vertices of the smaller square (A) is the midpoint of the sides of the big square(B), using the diagonal of square A, we can find the sides of the bigger square.\n\nThe diagonal is a*squareroot of 2, in which when we square to get the area ===>  gives us 2a^2.\nThus, the ratio is between Square A' area (a^2) and B's area (2a^2) is 1:2 or 1/2
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A square is a quadrilateral (4-sided polygon) with sides of equal length, all joined at 90-degree (also called "right") angles to each other.\n\nSince the square has area, it is definitely the area within the lines that constitutes the square, not the lines themselves.
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The first area to be defined was the obvious one of a rectangle.  The number of squares of unit size that would fill up a rectangle is clearly the number of such squares that fit in a row across one dimension of the rectangle, times the number of such rows needed.  Since each square has a length and width of one unit, it's easy to see that the length x width = area of a rectangle.\n\nA rectangle can be divided into two right triangles of equal size.  Hence, the area of a right triangle is 1/2 x length x width, only in triangles we call those things base and height.  Now, any arbitrary triangle can be broken up into two right triangles.  Doing so, it's easy to show that the area of *any* triangle is 1/2 x base x height, where the height is defined as the perpendicular distance from the line containing the base to the opposite vertex.  Similar techniques using triangles can be used to find the area of other regular polygons. \n\nThe area of things like circles can be computed from integral calculus, although I suspect there is probably a geometric method to find the area of a circle as well.\n\nThe area of figures bounded by more complex functions than straight lines and circles is found using integral calculus.
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The area of a triangle can be found by multiplying the base times the one-half the height.\n\nIf a triangle has a base of length 6 inches and a height of 4 inches, its area is 6*2=12 square inches
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Do you mean like an object that has a semi-circle on one end?\n\nIf yes, you can find the area of the semi-circle by figuring the area of the entire circle and dividing by half. Then you just find the area of the rectangular portion and add the two answers.
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are the circles inside the square?\nif they are...\none side of the square is 8m\nso you divide that by two since there two circles side by side.\ndiameter of circle = 4m and you half this to get radius which is 2m. \nTo get area of a circle use pi.\nArea of circle =pi x radius squared\n                      = pi x 4
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It depends on what shape you want to know the area.\n\nSimple shapes have formulas. (such as a circle's area is Pi*r*r)\n\nComplex shapes which have pattern.(you know the equation of lines that form the shape), calculus is used to find the area.\n\nIf a shape is not ordinary. You should draw lines to grid it and count the area square by square.\n\n-Hope this would help-
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Area = Pi times the radius squared (A=pr2)\nIf you need to know how to find the radius, go here:\n\nhttp://math.about.com/library/blcircle.htm
53126
area = 1/2 x base x height
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Do you know how to find the area of a square?  What does the term "square base" mean to you?\n\nArea of a square = side*side\n\nedge=side
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use pythagorean thereom a^2 + b^2 = c^2. (c being teh longest side or the hypotenuse) the two legs are a and b. so you have the sq rt of 169. (sqrt of 12^2 + 5^2) which is 13
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Area of a square = L * L\n\nArea of A = x * x ..........(1)\nArea of B = y *y  ..........(2)\n  \n y = x -1               ..........(3)\n\nA = 4 * B              ...........(4)\n\nSubstitute (1) & (2) into (4) gives:\n\nx^2 = 4 y^2           ...........(5)\n\nSub. (3) into (5)\n\nx^2 = 4 (x-1) ^2\n\nSolve:\n\nx^2 = 4( x^2 -2x +1)\nx^2 = 4x^2 -8x +4\nOr\n\n3x^2 - 8x +4 =0\n\nSecond order eq.\n\nx1,x2= [+8 +- Sqr(8^2 - 4*3*4)]/(2*3)\n\nx1,x2 = [8+-4]/6\n\nx1 = 2   &  x2 = 4/6\n\nThen\ny1 = 2-1 =1   & y2 = 4/6 -1 = -2/6 ( illogical )\n\nthen\n\nx= 2  and y = 1
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You can do all these in google. For the first one, type in "4 square metres in square cm", and it tells you the exact answer. Do the same for the others. \nYou can then work out any others by yourself without needing to ask :)
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Area = Length x Width\n\nArea = 2 ft x 5 ft\n   ''    = 10 sq. ft