If anyone could solve this math problem WITHOUT using calculus please tell me.Problem is in the details.?
148719
You just draw a graph yourself.\n\n! ain't gonna graph for you. Rather ! love calculus.
724027
sidharth has solved the problem correctly and given you the two values for x that satisfy the conditions of the problem.\n\nHowever, he didn't specify the POINTS on the curve.\nThey are (0,0) and (-2,-2).
1028166
i know how to derive tis equation by means of calculus but i'm not sure that it involves algebra. i can give u the calculus proof though.
191567
Please use parentheses to explain the problem more effectively. Assuming the problem as,\n\n(x-1)/2x + x/(x+3)\n\nThe solution can be,\n\n(3x^2+2x-3)/(2x^2+6)
1132233
this question will require calcs using logarithm.\nhence will take time
51150
UGH!!!  Thx for the effort (I was the one to post that question, as a part of a solution to another problem I found here on Yahoo! Answers.)  Incidentally, I made a mistake when simplifying the other problem and it should be xln(2)-2ln(x)-ln(86400) = 0\n\nI don't know any way to get rid of the ln(x) unless maybe it's using calculus techniques?  I'm just glad this problem is making other ppl trouble about it as much as I did :-).
978944
The equation is 258.30 X 1.09. Incase you don't have a calculator, it's $281.55
659736
Not a site, but I suggest you invest in something called Mathcad.\nTeach, please note, it is a site not a sight! Unless you were 'looking' for the answer... sorry!
765864
I'm unclear with the way you stated the problem. Am I looking for a implicit derivative. I'll check back to solve it.
619240
u can even use calculus to find this out
435388
damnt i should have paid attention calculus...\n\nlet pam...pam...breat....dimension......carry the one.....as x approaches zero......carry  the two....hold on...\n\nthis could take a while.
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
665576
x^2<4x\n\ncase 1: x<=0\nno solution\n\ncase 2: x>0\ndivide by x\nx<4\n\ntherfore the solutions are 0<x<4
755525
OK, first let's try to get that into a mathematical statement.  The volume can be given as yx^2, since the box is square, and the cost is 8x^2 for the top and bottom (4 cents times two sides), and 4xy for the sides (1 cent times four sides).  So the problem can be stated mathematically as yx^2 = 6912, c = 8x^2 + 4xy, minimize c.\n\nThe next step, I guess, would be to rearrange the equation to eliminate one variable and solve for c in terms of the other.  So say y = 6912/x^2, then c = 8x^2 + (4*6912)x/x^2.  That simplifies to c = 8x^2 + 27648x^-1.  Now we have c in terms of x.\n\nThe next step is to find the value of x for which c is minimized.  You don't say what math class you're in but the only way I know how to do this is with calculus, so I assume you are that advanced.  First you have to take the derivative of the function.  So the derivative of 8x^2 +27648x^-1 is 16x -27648x^-2.\n\nNext, find all points for which c' = 0.  Set 16x = 27648/x^2.  X = 1728/x^2.  x^3 = 1728.  x = 3_/1728 = 12.  So the only local min/max is at x = 12.\n\nNow, you would ordinarily compare the value of the function at the local min/max with the value at the boundaries, but since this function is undefined at the boundaries,we can assume that x = 12 is the answer.  \n\nGoing back to the first equation, yx^2 = 6912.  That means 144y = 6912.  y = 48.\n\nThe answer is (12, 48).
30751
The Edifier has it right, but darned if I can follow the notation. You really need to see this written out like a textbook to understand what's going on.\n\nClick the link below in "sources" to see the answer hosted at my website www.calculus-help.com. Right now, Yahoo! answers, as far as I can tell, doesn't allow graphics, which makes it tricky to answer ANY math questions.\n\nPlease don't post math answers, guys, if the poster knows the answer but can't get there, and you get something completely different.
137681
Ok...\nI see what you are doing...\nYou merely substitute the number in for x...\nso the problem becomes 6-2*(-1)\n6+2\n8
970181
1) This has no elementary solution\n2) This one, however, does have a solution, with the substitution e^x = tanu.  You are at the answer arctan(e^x)\n\nSteve