Can someone Help me in vb?
150672
Two ways to do it.\n\n1) SQL - in the SQL statement in the OpenRecordSet statement, add a WHERE clause the searches only for records you are looking for.\n\n2) Loop through the returned recordset until you find the record you are looking for.\n\nSub OpenRecordsetX()\n\n   Dim wrkJet As Workspace\n   Dim wrkODBC As Workspace\n   Dim dbsNorthwind As Database\n   Dim conPubs As Connection\n   Dim rstTemp As Recordset\n   Dim rstTemp2 As Recordset\n\n   ' Open Microsoft Jet and ODBCDirect workspaces, Microsoft \n   ' Jet database, and ODBCDirect connection.\n   Set wrkJet = CreateWorkspace("", "admin", "", dbUseJet)\n   Set wrkODBC = CreateWorkspace("", "admin", "", dbUseODBC)\n   Set dbsNorthwind = wrkJet.OpenDatabase("Northwind.mdb")\n   Set conPubs = wrkODBC.OpenConnection("", , , _\n      "ODBC;DATABASE=pubs;UID=sa;PWD=;DSN=Publishers")\n\n   ' Open five different Recordset objects and display the \n   ' contents of each.\n\n   Debug.Print "Opening forward-only-type recordset " & _\n      "where the source is a QueryDef object..."\n   Set rstTemp = dbsNorthwind.OpenRecordset( _\n      "Ten Most Expensive Products", dbOpenForwardOnly)\n   OpenRecordsetOutput rstTemp\n\n   Debug.Print "Opening read-only dynaset-type " & _\n      "recordset where the source is an SQL statement..."\n   Set rstTemp = dbsNorthwind.OpenRecordset( _\n      "SELECT * FROM Employees", dbOpenDynaset, dbReadOnly)\n   OpenRecordsetOutput rstTemp\n\n   ' Use the Filter property to retrieve only certain \n   ' records with the next OpenRecordset call.\n   Debug.Print "Opening recordset from existing " & _\n      "Recordset object to filter records..."\n   rstTemp.Filter = "LastName >= 'M'"\n   Set rstTemp2 = rstTemp.OpenRecordset()\n   OpenRecordsetOutput rstTemp2\n\n   Debug.Print "Opening dynamic-type recordset from " & _\n      "an ODBC connection..."\n   Set rstTemp = conPubs.OpenRecordset( _\n      "SELECT * FROM stores", dbOpenDynamic)\n   OpenRecordsetOutput rstTemp\n\n   ' Use the StillExecuting property to determine when the \n   ' Recordset is ready for manipulation.\n   Debug.Print "Opening snapshot-type recordset based " & _\n      "on asynchronous query to ODBC connection..."\n   Set rstTemp = conPubs.OpenRecordset("publishers", _\n      dbOpenSnapshot, dbRunAsync)\n   Do While rstTemp.StillExecuting\n      Debug.Print "  [still executing...]"\n   Loop\n   OpenRecordsetOutput rstTemp\n\n   rstTemp.Close\n   dbsNorthwind.Close\n   conPubs.Close\n   wrkJet.Close\n   wrkODBC.Close\n\nEnd Sub\n\nSub OpenRecordsetOutput(rstOutput As Recordset)\n\n   ' Enumerate the specified Recordset object.\n   With rstOutput\n      Do While Not .EOF\n         Debug.Print , .Fields(0), .Fields(1)\n         .MoveNext\n      Loop\n   End With\n\nEnd Sub
816802
I have been through this several times here on Y! answers.\nI have the software you need.\n\nSend me your e-mail address to send it to you\n\nEnjoy my profile, I am VBAXLMan
540500
Here you go (requires VB.NET)\n\nhttp://www.codeproject.com/useritems/sudoku.asp
268014
There are function like GetChunk and AppendChunk that can be used for this purpose\nsee the detailed code here http://www.vb-helper.com/howto_database_picture.html
209872
I already answered this for you in your other thread, using Visual Basic. With a little effort, you ought to be able to convert one type of Basic to another. The languages are virtually identical.\n\nOnce again, what you need to do is create a function. Let's call it DozenBetType. It is going to take one argument: an integer: DozenBetType(someInteger)\n\nThe function is going to return:\n1 if the number passed to it is 1-12\n2 if the number is 13-24\n3 if the number is 25-36\n\nThen you can simply call the function on both the number guessed and the number your program has generated.\n\nFor example, if the number your program generated is declared as intResult, and the number the person guessed is declared as intGuess:\n\nif DozenBetType(intGuess) = DozenBetType(intResult) then they have won the bet, otherwise they have not. (A simple if-then-else statement\n\nIf you don't want to use a function, or if that's too complicated for you, you can declare two new variables: intDozenTypeResult, for the number your program generated and intDozenTypeGuess, for the number your user guessed.\n\nSet intDozenTypeResult to be 1 if the program's random number is between 1-12, set it to be 2 if the value is 13-24, set it to be 3 if the value is 25-36. \n\nDo the same thing for intDozenTypeGuess.\n\nThen, simply compare those two variables:\n\nIf intDozenTypeResult = intDozenTypeGuess then they have won, otherwise they have not (again, a simple if-then-else statement).\n\nPlease, don't create new threads for the same question. Just update your old question.
548985
This might help.\nhttp://www.dataq.com/develop/vb6.php?file=68\nor \nhttp://www.control.com/1026215375/index_html\nor\nhttp://www.experts-exchange.com/Programming/Wireless_Programming/GSM/Q_21005159.html
728764
Kindly go to www.allexperts.com\nChoose computing category. then Programming--Basic--Visual Basic\nYou can post your query there with one of the experts.\nThey will reply you free of charge
1122755
hi...................u will get complete information on vb.net . Just u have to search for VB.NET TUTORIAL   on yahoo.........hope i helped u in finding what u wanted.
1146521
Private Sub SomeObject_KeyDown(KeyCode As MSForms.ReturnInteger, Shift As Integer)    \n    If KeyCode = vbKeyLeft Then 'left arrow = vbKeyLeft = 37\n         Call cmdLeft_click\n    End If\nEnd Sub\n\nyou may want to try other events pending on the app you're working on
587532
Try searching for it at http://www.planet-source-code.com/vb
670070
 Dim frmName As String\n   \n frmName = "form2"\n   \n Select Case frmName\n  Case "form1"\n   Form1.Show\n  Case "form2"\n   Form2.Show\n  Case "form3"\n   Form3.Show\n  Case Else\n   MsgBox "Invalid form name"\n End Select\n\n***EDIT***\nIn VB, you can't convert a string object into a form object.  This is why String.Show doesn't work.  However, you can use a "select case" on the string and if the string matches the form name (i.e. form2), then show the form.\n\nAnother alternative is to loop through the forms collection until you find a form with the same name as your string.\n\nIn any case, if you create a project with 2 forms (called form1 and form2).  Add a button to form1 and paste the above code into the click event of the button.  When pressed, form2 will be displayed.
131688
Install VB 6.0 runtime on the machine that might solve the problem.\n\nFile: VBRun60sp4.exe
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> http://www.pcguide.com/vb/showthread.php?t=38363
453113
Just do this=Make an compent.\nstartComp\nmergeTIFFToVisualBasic\nendComp\nOr\nDesigner f-filebox ok-okbutton c-cancel o-options e-edit\nMerge TIFF to Visual Basic\nf\n\no  c  e  ok\n\nSurley,it maybe work.\nGood.
954444
Learn VB.Net. Its the best programming language today.
556841
Try Planet Source Code. Below are 52 examples (You probably should do your own homework, however...):\n\nhttp://www.planetsourcecode.com/vb/scripts/BrowseCategoryOrSearchResults.asp?blnWorldDropDownUsed=TRUE&txtMaxNumberOfEntriesPerPage=10&blnResetAllVariables=TRUE&optSort=Alphabetical&txtCriteria=Binary+Tree&lngWId=3
868999
sorry sohail but VB is something that can't be taught in a short time.\ntry going to tutorialized.com or just google it n find a good site.\n\nbe prepared for a looooooooooong journey of VB