ten examples of addition of polynomials?
142543
Polynomial= multiple terms, i.e. 3x^2+7x-3\nSo I suppose addition of them would be like\n(4x^2+7x-5)+(9x^2+9x+7+y)\n=4x^2+7x-5+9x^2+9x+7+y\n=13x^2+16x+2+y\nor\n(4x^2+7x-5)-(9x^2+9x+7+y)=\n(4x^2+7x-5)-1(9x^2+9x+7+y)=\n(4x^2+7x-5)+ (-1*(9x^2+9x+7+y))=\n(4x^2+7x-5)+(-9x^2-9x-7-y)=\n4x^2+7x-5-9x^2-9x-7-y=\n-5x^2-2x-12-y.\n\nMaybe now you can do your own.\nNote that these methods only work with adding/subtracting.
503153
(x+7)(x+3)\n(x-11)(x+2)\nforget this one.  its AC factoring though\nthis ones AC too
493502
6.\n\n1^6, 2^5, 3^4, 4^3, 5^2, 6^1.
913484
are you talking about a polynomial :\na + bx +cx^2 + dx^3 +...\n\nbecause those a,b,c,d... do not appear any where on the graph... you have to look at the intercepts and the extreama, and the inflection points to get any good idea about the shape of the graph
1178023
a*b is the same thing as adding a b's together. Here are a few examples:\n3*2 = 2+2+2 = 6\n2*3 = 3+3 = 6\n1*6 = 6\n6*1 = 1+1+1+1+1+1 = 6\n4*4 = 4+4+4+4 = 16\n9*9 = 9+9+9+9+9+9+9+9+9 = 81
1109323
The others are correct:  3x is one such example.\n\nIf you want to be pedantic about it, there are an infinite number of functions that fulfill this.  Just add any constant:\ny=3x+c.
651993
Here's the best I can do to help with the first one.\n   __x_+9___\nx-2)X^2+7x-2\n    x^2-2x\n    ------\n        9x-2\n        9x-18\n        -----\n           16\nFollow the example for the rest
593998
When you have a polynomial, the coefficients are integers.  For example:\n\nax^2 + bx + c = 0\n\nThis is the general formula for a second degree polynomial (x is to the 2, hence second degree).  In this case, a, b, and c are the integers.\n\nAlso, if you add other terms, such as x^3, they would also be multiplied by integers.
902478
wow its been a long time.. i use a calculator to do that now.. but here goes one thing i remember...\n\nlets say we have a polynomial like this\n\nx^2 -3x-10  and we need to factor it..\n\nwe take a look at what factors of -10 we could use that would add up to -3  in this case there are two way to get -10 (-2*5) or (2*-5)  if we add the two sets together one gives us -3 and the other gives us 3 so we can throw out the -2*5 terms.\n\nSo now we lay out the factors.... we need two x's to get x^2 so we need two x's in the first terms (remember FOIL?)\n\nlay the terms out so they give us the correct values\n\n(x+2)(x-5)  now we can use FOIL (firs, outer, inner, last) to check ourselves...\nX*X = x^2\nX*-5 = -5X\n2*x =2x\n2*-5=-10\n\nso we get [x^2] +[-5x] +[2x] +[-10]\nor x^2 -5x+2x-10\ncombine like terms now\n-5x+2x =-3x\n\nwhich gives us\nx^2-3x-10\n\nhope that helps
123892
3(x – 2)^2 – 3(x – 2) – 6\n3((x-2)^2 - (x-2) -2)\n3(x^2-4x+4-x+2-2)\n3(x^2-5x+4)\n\n3(x-4)(x-1)\n\nYay!!
804510
3x^2+6x+5x+10\n(3x+5)(x+2)
502428
#1. (x-5)(x+1)\n#2. (x-3)(x+2)
976290
There are lots of them.  The story of Fibonacci numbers is interesting.  Also, some background on the Pythagoreans:\n\nhttp://en.wikipedia.org/wiki/Portal:Mathematics
920768
One solution is\n0, 2, 4, 6, 8, 10, 12, 1, 3, 5, 7, 9, 11\nBut there is a huge variety of solutions\n\nSorry Chris I did not copy so here is another\n\n0, 11, 5, 2, 9, 3, 1, 4, 10, 7, 12, 6, 8
167287
= (lnx + lnx)-lny = 6+6-2 = 10
50866
It's a prime example of addition.
773695
Look in your text book under "factoring polynomials"... or you could try this web site that explains this fairly thoroughly...\n\nhttp://faculty.ed.umuc.edu/~swalsh/Math%20Articles/Factoring.html