will objects at different sizes fall at the same speed?
148681
Only objects of the same mass (Weight) fall at the same speed. Objects of different size (Shape) can fall at different speeds.
771396
Because gravity is the same - so it has the same effect on both objects.  The larger object will strike the ground with a greater force, but both objects will accelerate at the same rate.
200103
If there is no wind speed, no other gravitational pulls present, no magnetic interference, and you throw it perfectly perpendicular up, then it will fall at the same place.\n\nIf you are riding in the passenger seat of a car going 20 mph, and you throw a ball out your window straight out, the ball will have an initial forward speed of 20mph.\n\nThe same concept applies in your question.  Let's say when you look up, the earth is rotating to the left.  When you throw the ball in the air, its initial direction will go a little to the left, but you won't notice it cause you are going a little to the left as well.\n\nHopefully that helps a little bit.  It's a little hard to explain without pictures.
642685
Ummm.... relativity doesn't have anything to do with it.\n\nBoth objects, regardless of their mass, are pulled toward Earth by the exact same gravitational force, and therefor are accelerated in exactly the same way (9.8 m/s^2) Thus they fall at the same rate.
84559
Both marbles will hit the ground at the same time, but one will roll along farther.\n\nIn short, the vertical force from gravity is the same for both marbles.  The one hit sideways just has an additional horizontal velocity in addition to its vertical acceleration.
895183
In the absence of friction, they would fall at exactly the same rate. In the real world, assuming the balls are the same size (which means the lighter ball is less dense) the heavier ball would be faster, because the drag would be similar but the driving force (the weight) would be different.\n\nThe reason they'd travel at the same speed when friction is neglected, is exactly the same reason they free-fall at the same speed; gravitational acceleration is uniform. Placing them on a ramp (or roller coaster track) simply dilutes the effect based on the sine of the angle to horizontal.
1108579
NO!!!\n\n\nThey dont fall with the same velocity, \n\nThere is a maximum /terminal velocity an object can attain while moving in a fluid. (in our case - air).\n\nAnother force acts on bullet in a direction opposite to that of g. \n\nThis force = 6 * pi * n * r * v \n\nr - radius of object,\nn - coeff of viscocity\nv - terminal velocity.\n\n\nThus the velocity with which the bullet will return to earth would be much less. (but still large enough )
171753
oldhippypaul is right, the correct statement is "both corks are subject to the same buoyant force". The explanation is that, if they´re identical,they weigh the same. Since there in balance (i.e., there not sinking or emerging) the bouyant force must equal thre weight and, therefore is fhe same.
1030122
Both would actually fall at the same speed in the absence of air resistance.  Therefore, the apple would fall faster.  \n\nHowever, on the moon, when the astronauts dropped a feather and a bowling ball, they hit the ground at the same time.  \n\nIt would seem that the bowling ball should fall faster since gravity is pulling on it with more force.  But, with the more mass, comes more inertia, which meas it resists being pulled more than the feather.  So, the feather is pulled less, but it resists less as well, so because of that, they will fall at the same time.  The relationship between the force of pull and the object's inertial compensates exactly so that all objects fall at the same rate.
857884
If, by "gravitational acceleration," you mean the acceleration of gravity, g, then the answer is that air resistance has no effect.  But you probably mean the acceleration of an object due to gravity.  If you drop an object, it accelerates downward, initially with an acceleration of g, ie, 9.81 m/s^2 or 32.2 ft/s^2.  But as soon as it is moving, the air striking its surface exerts a force on it that opposes its fall.  That force increases with the square of the object's velocity; in other words, if the velocity is, say, 10 m/s, the force on it due to air resistance will be 4 times what it was at 5 m/s.  The object will continue to accelerate, but its acceleration will continually decrease.  Finally, when the force on it due to air resistance is equal to the force of the gravitational attraction, it will reach a constant velocity.  That's what's called "terminal velocity."  If there is no air resistance, mass has no effect on the object's acceleration.  However, a more massive object will reach a higher terminal velocity than a less massive one, if both experience the same air resistance.  In other words, a sphere made of lead will accelerate faster and reach a higher velocity than one made of aluminum, if they're the same diameter and have the same surface properties.
863911
Because not everything is the same size & mass and going at the same speed, etc. Those attributes... vary.
321959
they would fall at the same time unless there is a force acting upon one of the weight...
308763
that depends on the shape and mass of the body falling, the shape affects air resistance, which determins terminal velocity, if there were no air resistance then terminal velocity would never be reached and it woudl be alot different. the mass matters becaseu the force of gravity, mg, has to equal the force of air restance, which increases with speed, \nant's, who's mass is very small, reach terminal velocity at 3 inches, dropping them from 50 feet is like dropping them from 3 inches, \n\nin most humans' i would say no, but it all depends.
759333
all object fall 4.9m after 1 sec\n\nX=1/2(9.8m/s^2)(2s)^2\nx=19.6m\n\nx=(1/2)(9.8m/s^2)(3s)^2\nx=44.1m
404829
the only thing that leads to the misconception that heavier things fall faster is most likely due to air resistance. In a vacuum, all objects fall under the same acceleration/gravity.
101463
that depends on the material's specific gravity\nweight in kg = specific gravity * volume in ltrs
879264
'Large' and 'small' probably refer to the masses of the balls, rather than the sizes. Assume one ball (with mass m1) is initially directly above the other (mass m2), and both are dropped at the same time from rest (with a slight vertical space between the two).\n\nThe lower ball hits first, bounces up and collides with the upper ball near the ground. The two  have about the same speed v = sqrt(2gH) going into this collision because both balls have fallen from approximately the same height. If the two masses were equal, then both would simply reverse direction, the top ball going upward at speed v and the bottom ball going down (for the second time) and immediately up at the same speed v --> both balls would continue up at the same speeds to the original height H.\n\nNow suppose the masses are slightly different with m2 > m1. Then the initial and final velocities (taking the upward direction as positive) for the collision are respectively:\n\nv1 = -v\nv2 = v\n\nand:\n\nv1 = v + x1\nv2 = -v + x2 \n\nwhere x1,x2 << v. Energy and momentum conservation require that:\n\n(m2-m1)v = m1(v + x1) + m2(-v + x2)\n(m1+m2)v^2 = m1(v + x1)^2 + m2(-v + x2)^2 \n= m1(v^2 + 2vx1) + m2(v^2 - 2vx2) (Approximately)\n-->\n2(m2-m1)v = m1x1 + m2x2\n0 = 2m1vx1 - 2m2vx2\n-->\nx1 = (m2/m1 - 1)v\nx2 = (1 - m1/m2)v\n\nSo the top (lighter) ball ends up with a higher speed (m2/m1)v and the lower (heavier) ball ends up with the lower speed (m1/m2)v. This is reflected by the one bouncing higher than H and the other lower than H.\n \nThere can't be more than one collision since the top ball comes out of the first (and only) collision with a higher speed than the bottom ball so the latter can never catch up to it. If the mass ratio were reversed (heavier ball on top) the situation would be much more complicated since there could be multiple collisions.