Algebra!!! how to do???please tnx alot?
138946
but u can simplify it.\n1/2*a= a/2\nand b-1/3= lcd 3b-1/3\nhen the product of mean = product of extremes\nso multiply the numerator  of first and denominator of second\na*3=3a would be the numerator\nand 3b-1 * 2\nthat's 6b-2\nand the simplified form is 3a over 6b-2
151739
algebra is the solution of equations like the above.  Let the "what" be expressed as w.  Then the question becomes\n\n  w * 3 = 4/3\n\nNow how do we solve this for w.  The trick is to operate on both sides of the equation the same function.  The caveat is that the function applied must have an inverse.  In this case multiply both sides by (1/3).\n\n(1/3)*3*w = (1/3)*(4/3)\n\nNow since 1/3 is multiplicative inverse of 3, the result is 1, and since 1 is the multiplicative identity, the result of the left hand side is w.  For the right hand side just do the multiplication\n\nw = 4/9\n\nThus 4/9 multiplied by 3 equals 4/3.
921810
2(4x+7)=2x-4\ndistribute\n8x+14=2x-4\n-2x from feach side\n6x+14=-4\n-14 from each side\n6x=-18\ndivide by 6\nx=-3\nand the next one\n-2(18-3y)=7y+2y\ndistribue and add light terms\n-36+6y=9y\nsubtract 6y from each side\n-36=3y\ndivide by 3\n-12=y\n:) welcome
302848
Probably easier to show by example.\n4x2+8-:-4-1 (-:- = divide)\nmultiply any numbers first, then divide, then add and subtract.\n\nYou could add brackets in if that helps you.\n(4x2)+(8-:-4)-1 = 9
842934
Ok, first you must get the -8 and the x/-2 out of parentheses, so u just multiply them both by one. So then is -8 * x / -2. First, you do -8 * x, which is -8x. The problem then becomes -8x / 2. In this step, just don't mind the negative or the x and just put them back in at the end. So you're really just doing 8 / 2, which is 4. You must put the - and the x back in, so the answer is -4x. Ta Da!
1169576
Try:\n\nhttp://www.sosmath.com/cyberexam/algebra/q001/1/1.html\n\nhttp://www.math.com/practice/Algebra.html\n\nhttp://www.glencoe.com/sec/math/studytools/prealglblr.shtml \n\nhttp://www.syvum.com/squizzes/algebra/
680155
i'd love to help but i'm having trouble with it myself\n\nuse ur math textbook it will have it unless ur math book say algebra and is red ( that my alg. book and it doesn't help) \n\nSRY good luck
919864
1.  ax + xb\n2.  21x^3 + 24x*2y\n3.  24x^2 + 31x + 10\n4.  24x^2 - 8x - 6\n5.  40x^3 + 66x^2 + 38x + 6\n6.  x^2 - 1\n7.  x^3 - 8
825795
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
516699
its D!!\n\nA) 4+8X=0\n  -4   -4\n ----------\n   8X= -4\n  ---  ---\n   8    8\n\n   x= -4/8 or X= -1/2\n\n\n\nB) X= -1-X\n  +X    +X\n -----------\n  2X= -1\n ---  ---\n  2    2 \n\n  X= -1/2\n\n\n\nC) -2(x-2)=5     negative times(x) a negative is a positive\n   -2x+4  =5     negative times(x) a positive is a negative\n      -4  -4\n -------------\n   -2X= 1\n   --- ---\n   -2   -2\n\n     X= -1/2\n\n\nD)  -3X= 6\n    --- ---\n    -3   -3\n\n   X= -2\n\n\n\nits sad most ppl got this wrong?? is this Geometry?? or Algebra??
893993
1.  Here you just divide both sides by 5 to get the x by itself\nand you get :\n5x<35\nx<7\n\n2. Divide both sides by 4\n4y>15\ny>15/4\n\n3.  Divide both sides by 16\n16y<64\ny<4\n\n4.  Divide both sides by a -18. Remember that you have to switch the equality sigh when you divide by a negative:\n-18y>-36\ny<2\n\n5. First, combine like terms (x):\n5x + 6x <-33\n11x<-33\nDivide both sides by 11:\nx<-3\n\n6. Combine like terms (y):\n-12>2y - 6y\n-12>-4y\nDivide by a -4. Remember to switch the equality sigh \n3<y\n\nHope that was helpful!
576570
algebra...usually (well i do) set up a equation for everything, and solve for the variable. If u need help u can always get help in www.algebra.com .....
681236
Multiply each term in the first () by each term in the second ():\n\n2x times 2x = 4x^2\n2x times 1 = 2x\n-3 times 2x = -6x\n-3 times 1 = -3\n\nThen combine 2x and -6x\nAnswer: 4x^2 - 4x - 3
953801
Get a tutor, get your parents to help you, read through the chapter in your Algebra book that you're currently doing, if your school has extra help with teachers go to the help sessions, study with your friends, form a study group, and do the extra practice problems for the current chapter in the back of your book for learning how to do the equations and stuff. I am also in your same grade doing Algebra 1 Honors. Hehe, I should take my own advice!
1079811
It *is* awfully hard to write algebra expressions on Yahoo Answers, isn't it? Oh well, we do what we can.\n\nAddressing your first question, let's write it out like a long division problem.  You'll have to imagine the horizontal bar above the larger polynomial, because I can't format it properly here:\n\nx^2 + 3x - 2  )  x^4 + x^3 - 5x^2 + 13x - 6\n\nOur first step is to look at the first term in each polynomial, and divide the smaller into the larger.  x^4 / x^2 = x^2, so the first term we write in our quotient (above the bar) is x^2.  You can write it directly above the x^4, if you wish, or above the 5x^2 term, your preference.\n\nNow, we're going to multiply that "partial quotient" by the entire divisor (x^2 + 3x - 2), which gives us x^4 + 3x^3 - 2x^2.  Write that "partial product" below the first three terms of the original dividend (x^4 + x^3 - 5x^2).  Our next step is to subtract the partial product: (x^4 + x^3 - 5x^2) - (x^4 + 3x^3 - 2x^2) = -2x^3 - 3x^2.  We then drop down the next term from the dividend, the 13x term, and repeat:\n\n-2x^3 / x^2 = -2x (add that term to our quotient)\n\n-2x * (x^2 + 3x - 2) = -2x^3 - 6x^2 + 4x\n\n(-2x^3 - 3x^2 + 13x) - (-2x^3 - 6x^2 + 4x) = 3x^2 + 9x\n\nFinally, we drop down the last term from the dividend, -6, and repeat once more.  I'm sorry that I can't write this out the way your math book can... I really hope Yahoo Answers creates some sort of way of inputting formulas, or at least monospacing text entry!\n\n3x^2 / x^2 = 3 (so we add a +3 term to our quotient)\n\n3 * (x^2 + 3x - 2) = 3x^2 + 9x - 6\n\n(3x^2 + 9x - 6) - (3x^2 + 9x - 6) = 0... no remainder!\n\nSo our final quotient is x^2 - 2x + 3, with no remainder.\n===\nNow, when doing the 2nd problem, you'll want to write the larger polynomial, the dividend, as x^4 - 3x^3 + 0x^2 + 6x - 5.  We incorporate that extra 0x^2 term so that we never find ourselves trying to subtract unlike terms.\n\nSorry there's no better way to write this out on Yahoo Answers.  Hope that helped anyway!
102673
If you can't get an answer here, try asking your Algebra teacher for extra help after school tomorrow.  It's sure to add to your grade that you asked for the help.
701654
Instead of memorizing all the equations,understand how they are derived.Try to do it yourself.If you can't go to someone who knows for help.