Is it possible to convert mercury into gold by adding 1 electron that it lacks? If yes, how?
140269
Mecury doesn't "lack one electron".  What you would need to do is remove one proton from mercury to make it into gold, in some kind of nuclear reaction.  Now, while not impossible in theory, I don't know of any nuclear pathway to do it, and it would no doubt be prohibitively expensive to do if there were.
163107
Ok, so gold's symbol is Au, and it has an atomic mass of about 196.967. Therefore, there are 196.967 grams of Au for each mole of Au.\n\n2.15 mol Au(196.967g Au / 1 mol Au)= 423.47905 grams of Au\n   (2.15 moles of gold is 423.47905 grams)\n\n2.15 mol Au(6.023*10^23atoms Au / 1 mol Au)=1.2943*10^24atom\n    (You multiply the number of moles by Avagadro's number to get the number of atoms present for the number of moles)\n\nTo sum it up:\n   2.15 moles of Au is also:  423.47905 grams of gold \n                                    and\n                              1.2943*10^24atoms of gold \n\nhope that helps
341076
Yes, you can add Rhodium, Irridium and Palladium among others.\n\nBasically it's those elements that have the outer electron d-shell filled completely. They therefore interact weakly with other elements.
905246
Yes.  You just begin to take electrons away from the outermost, least stable orbitals.  In this case the first two electrons will come from the 4s2 shell, and then the one from the 3d.  This will leave you with just [Ar], which is a noble gas, and if you remember back to the beginning of chemistry, elements become ionic (gain or lose electrons) because they all wish to achieve this noble gas configuration.
691661
Gold plating is typically so thin unless you have a real lot of it it would not be worth the trouble.  A gold plated ring would probably contain less than 10 mg of gold - about 20 cents at $600 per ounce.  If you dissolve the entire jewelry in aqua regia (a mix of nitric acid and hydrochloric acid) and then neutralize, the gold can be precipitated either electrochemically or by a more active metal such as zinc.  Good luck.  A whole lot of mess and danger for a few dollars worth of gold.
759114
How to Melt Gold\n\nMelting gold is easy and fun, especially useful for casting gold items or pouring gold ingots from scrap gold or gold dust. \n\nSteps \nGet your scrap gold material \nPlace in crucible \nTurn on acetylene torch \nPoint at gold until melted \nUsing crucible tongs, pour into ingot mold or other shape (or bucket of water if making gold shot). \nCool gold piece, turn off torch and enjoy. \n\n\n\nTips \nA little flux always helps keep the gold liquid. \n\nDefine flux:\n. (Chem. & Metal.) Any substance or mixture used to promote the fusion of metals or minerals, as alkalies, borax, lime, fluorite.\n\n\nWarnings \nDon't burn yourself and wear welder's goggles. \n\n\n\nThings You'll Need \nHow to use an oxy-acetylene or oxy-propane torch.
27696
Gold is very nonreactive.  It will not dissolve once in your mouth (unlike the mercury compounds used in other dental work).  If it does not dissolve, it cannot poison you.
805536
Yes, then it is a called a cation.  The element still contains its protons and therefore gives the ion a positive charge.  \n\nHowever, the electron configuration of the element determines what ions you can make as the stability will drastically fall with the more electrons removed
380850
let's see if i can come up with 10 facts....\n\n\n1. you can change the color of gold by mixing it with an alloy (eg, white gold, rose gold)\n2. there is no such thing as white 24k gold.\n3. the higher the concentration of gold in a piece, the softer it is\n4.if you have a sheet of 24k gold, you can rip it like a piece of paper\n5. largest nugget of near-pure gold discovered was found in Australia. It produced 142 pounds of pure gold. \n6.scientists believe that there may be 70 million tons of gold dissolved in the ocean\n7. gold's chemical symbol is Au from the Latin word for gold, aurum. \n8. a lump of pure gold the size of a matchbox can be flattened into a sheet the size of a tennis court.\n9. absolutely pure gold is so soft that it can be molded with the hands.\n10. an ounce of gold can be stretched into a wire 50 miles long\n\n\n\n\nnot sure if they are "astounding" but there you go. 10 facts about gold.
884841
The mercury probably doesn't have much value as it is probably impure and possibly contaminated being contained in a jar for an extended period of time. The most important concern is to NOT open the jar. Mercury is very poisonous and can be deadly in large amounts such as the one that you have. You should consult with someone to ensure that it is disposed of properly, and do not attempt to dispose of the metal yourself. So in short, the mercury isn't worth much, but it's such a large amount that you want to be very careful with it. Hope this helps!
178276
Gain one/two electron(s):\n\nIf an atom or ion acquires another electron in a chemical reaction, it has gained an electron.  ditto for two electrons.\nExample: S has 16 electrons.  If it gains one electron it becomes a S- ion.  If it gains two electrons, it becomes a S-2 ion.\n\nSteal one/two electrons:\nIf an atom or ion looses an electron in a chemical reaction, it had to go somewhere.  That "somewhere" will be to another atom/ion.  So, the receiving atom/ion could be said to have stolen the electron.  Same goes for reactions involving two electrons.\nExample: Na reacts with Cl to produce NaCl.  Cl "steals" an electron from Na, creating Na+ and a Cl- ions.\n\n"Never ever react electron"\nI have never ever heard this phrase.  Maybe it refers to a species (atom or ion) that does not participate in the reaction.  It's valence electron(s) would not react.
210537
mercury expands when heated.  not very much though, that's why it's in such a thin tube-- so the results are exaggerated, more visible, and more easily measured
327609
If I've understood what you're asking then:\nA\nCd(s) + Ag2+ -> Cd2+ + Ag(s) \n\nCadmium occurs at Anode and the Silver would deposit on the Cathode\n\nB (I hate Manganese equations and the partial above is incorrect)\n\nMnO2 + 4H+ + 2AgBr -> Mn2+ 2Br- + 2Ag + 2H2O\n\nMnO2 @ Anode\nAgBr @ Cathode\n\nC\n\n(PtCl4)2- + 4Ag -> Pt + 4AgCl \nAg @ anode\n(PtCl4)2- @ Cathode
712728
choose the noble gas that comes before the element.   in Mn(2+)'s case, that's Ar\n\nwrite the noble gas down in brackets, and continue on with the electron config. as normal\n\n[Ar}4s23d3\n\nFor O(2-), it turns into Neon so it would just be [Ne]
252020
From wikipedia:\n"a mythical substance that supposedly could turn inexpensive metals into gold and/or create an elixir that would make humans younger"
470003
First you need to compare the standard reduction potentials of each half-reaction. (See URL below if you don't have values.) The more positive value will be the reduction half-equation and must therefore be the cathode (and the positive terminal for a voltaic cell). The other half equation will be the oxidation half-equation, and must therefore be the anode (and the negative terminal). You need to reverse this equation. Before you can add the two half-equations together, you must ensure that each half-equation has the same number of electrons.\n\na) has a problem; it is not balanced. Either the silver atom on the right hand side should have a single positive charge OR there should be 2 electrons on the left hand side.\n\nb) The MnO2 reduction half-equation has a more positive value than AgBr reduction half-equation, therefore is the cathode etc ie\n\nReduction: MnO2 + 4H^+ + 2e^- = Mn^2+ + 4H2O (Cathode, +ve)\nOxidation: Ag + Br^- =  AgBr + e^-           (Anode, -ve)\n\nNow multiply the oxidation half-equation by 2 so that the number of electrons in each half equation is the same: \n\n2Ag + 2Br^- =  2AgBr + 2e^-\nMnO2 + 4H^+ + 2e^- = Mn^2+ + 4H2O \n---------------------------------\n2Ag + 2Br^- + MnO2 + 4H^+ =  2AgBr + Mn^2+ + 4H2O \n\nNote: the electrons cancel out.\n\nc)  i hope that the above will allow you to complete this one on you own.
689544
Na+ is missing an *electron*