How could i write an equation in slope-intercept form for a line that passes y= -1/2x + 4; ( -3, 5 )?
145572
Your question is quite vague, and so with your previous question. That is why I have to make an assumption. Please see my solution to your other question.\n\nFor this particular question, if:\n1. The line passes thru y = (1/2)x + 4 & (-3,5)...NO PARTICULAR EQUATION.\n2. The line is parallel to y = (1/2)x + 4 & passes thru \n(-3,5)...SEE SOLUTION A.\n3. The line is perpendicular to y = (1/2)x + 4 & passes \nthru (-3,5)...SEE SOLUTION B.\n\nSOLUTION A: PARALLEL LINE\ny = mx + b ==> equation in slope-intercept form.\nm = slope = 1/2 = same slope as the parallel line.\nb = y-intercept\n\nSolving for b, use the point (-3,5):\ny = mx + b\n5 = (1/2)(-3) + b\n5 = -3/2 + b\nb = 5 + 3/2\nb = 10/2 + 3/2\nb = 13/2\n\nTherefore, equation of line is:\n\ny = mx + b\ny = (1/2)x + 13/2  ANSWER\n\n-------------------------------\nSOLUTION B: PERPENDICULAR LINE\ny = mx + b\nm = slope = -2 = negative reciprocal of the \nperpendicular line\nb = y-intercept\n\nSolving for b, use the point (-3,5):\ny = mx + b\n5 = -2(-3) + b\n5 = 6 + b\nb = 5 - 6 \nb = -1\n\nTherefore, equation of the line is:\n\ny = mx + b\ny = -2x + (-1)\n\ny = -2x - 1  ANSWER
88214
y+3 = (-8/3)(x-3)\ny = (-8/3)(x-3) - 3\ny = (-8/3)x + 8 - 3\nTherefore, y = (-8/3)x + 5 would be the equation satisfying the mentioned conditions in slope-intercept form.
698987
Another form of the equation is the point-slope form. If you have two points, find the slope.\n\nm = (a2-b2)/(a1-b1) for points (a1,a2) and (b1,b2)\n\n  Then take one point (a1,a2) and plug it into the following:\n\n(y-a2) = m(x-a1)\n\nIt actually turns out to be the slope intercept form, but if your teacher will accept that form than it is easier since you can just leave it like that.
350403
Equation of a line:  y = mx + b\n\nm = 3 (slope)\ny = -4 (y-intercept)\n\ntherefore:  y = 3x - 4 \n\nCrosses x-axis at y = -4 (0,-4)\nCrosses y-axis at x = 4/3 (4/3,0)
1092839
y=0 is the x-intercept\n\nso 5(0)-3x+4=0\n\n-3x=-4\n\nx = 4/3\n\nx-int = (4/3 , 0)
953419
The slope intercept form of the line is \n\ny = mx + b where m = slope and b = y-intercept\n\nSince (5, -3) lies on the line then\n\n-3 = 5m + b\n\nie 5m + b - 3 = o\n\nSo any line in which m = (3 - b)/5\n\neg b = -2, m = 1 So y = x - 2\nb = 8, m = -1 So y = 8 - x ....... and so forth\n\nGraphing m against b would give all the values of m, b that satisfy the given condition.
845966
There are several ways to do this, but since you mention y-intercept, we'll go that way.\n\nYou should know the formula y = mx + b.  In that formula "m" is the slope.  You are given a point (x,y).  Plug in all three of those numbers, and solve for "b".  Here you'd have\n12 = 2*4 + b\n12 = 8 + b\n4 = b\n"b" is the y-intercept, which here is 4.\n\nGo back and plug "m" and "b" into the formula.\nYour answer is y = 2x + 4.
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
42786
If X=0, then Y=5 (Y-intercept is 5)\nIf Y=0, then X=3\n\nPlot and you get, Slope = rise(y)/run(x) = 5/3
974393
If you mean parallel to y=2x + 5, then the slope will be 2\n\nSo you need to use:\ny = 2x + b\n\nPlug in your point (-1, 4) and solve for b:\n4 = 2(-1) + b\n4 = -2 + b\nb = 6\n\nSo your line is:\ny = 2x + 6
560706
You need to get the y alone on one side of the equation. Subtract 5x from both sides and you get:\n-3y=-5x-3\nDivide each variable by -3 to get:\ny=(5/3)x+1\nNow you can graph using this equation.\nThe y-intercept is 1 and the slope is 5/3.\nHope this helps.
389930
Write the equation in the point-slope form, then substitute 0 for x and solve for y.  That is the y-intercept.
105029
slope: 1; intercept: 2\n\nslope: -1; intercept: -3\n\nslope: -5/4; intercept: 20\n\ny = mx + b, where m, the coefficient of "x" is the slope and "b" is the y-intercept.  If you solve the equations for y it's pretty easy to figure out both.\n\nHope that helps.
35268
slope = (-4-(-6))/(-2-0)\nslope = -1
765225
First put the first equation into slope-intercept form or:\n\ny = mx +b\n\nm = slope,  and b = y-intercept\n\n-3x -3y = 2\n+3x        +3x\n\n-3y = 3x + 2\n/-3     /-3\n\ny = -x + 2/3\n\nSo, your slope for the first equation is:\n\nm = -1\n\nTo have a line parallel to the first line, the slopes must equal.\n\n\n\nUse Point-Slope form.\n\ny - y1 = m ( x - x1)\n\nSince you are using the point (-3, -4)\n\ny1 = -4\n\nx1 = -3\n\nSo your new equation will be:\n\ny - -4 = -1 ( x - -3)\n\n(remember the slope must be the same)\n(a minus a negative = a positive)\ny + 4 = -1(x + 3)\n\ny +4 = -x -3\n   -4         -4\n\ny = -x -7\n\nor you can put it back into standard form ( Ax + By = C)\n\nx + y = -7
937748
there are a couple of ways to do this, but I think the easiest is to find the slope and since you know the y-intercept, use that formula.\n\nm= (-4-0)/(0-12)\n\nm=-4/-12\nm=1/3\n\ny=(1/3)x -4
341751
Using pt. slope equation:\n\nY=mX+B where m=slope = 2/3, b=intercept, in this case = 0,\n\nY = 2/3 * x + 0\n\ny=2x/3.\n\n3y=2x\n3y-2x = 0.\n2x-3y=0