The cost in dollars of producing x units is C(x)=920+2x - .02x² + .00007x³. Find The marginal cost?
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If you can only produce an integer number of units, then the marginal cost will be C(x+1) - C(x), ie. if you are currently producing x units, how much more will it cost to produce the next unit? Since the cost of the next unit depends on how many units you have already produced, the marginal cost is itself a function of x.\n\nIf you can produce any real valued number of units, then the marginal cost will be the derivative of the cost function with respect to x, and is again a function of x.
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Cross multiply\n(x-2b)c = (x-2c)b  Multiply each side out using the distributive property\nxc - 2bc = xb - 2cb Since you are solving for x move all the terms that have an x to one side and all the terms that do not have an x to the other side.\nSo add 2bc to each side and subtract xb from each side\nxc - xb - 2bc + 2bc = xb - xb - 2bc + 2bc\nxc - xb = 0  Factor an x from the left side\nx(b-c) = 0\nEither x = 0 or b-c = 0\nso x = 0 or b = c\nIf b does not equal c then x must be zero.\nIf b does equal c, then x can be anything.\nAlso, note that b and c cannot equal zero because then you would be dividing by zero.  Dividing by zero is undefined.
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Your question is unclear, but this might help you.\n Total cost of products = No. of products x Price of products.\n\nIf there is more then one produce, say for example three different products then:\n Total cost = (No. of Product 1 x Cost 1) + (No. of Product 2 x Cost 2) + (No. of Product3 x Cost 3)
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Line AC = 6, line BC= 2x+2, line AB=x+1\nSo 2x + 2 = 6\n2x = 4\nx = 2 <-- option C
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cost of x apples=b cents\ncost of 1 apple=b/x\ncost of y apples(direct ratio)\nSO Y(B/X)CENTS
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Lets assume x as the cost of car\n\nThus total cost = 2000 + half of the cost\ni.e x = 2000 + (x/2)\nx - (x/2) = 2000\nx/2 = 2000\nthus x = 4000\n\nAlternatively,\n\na car costs 2000 plus half its cost thus 2000 is balance half cost and thus total cost is 2000*2 = 4000
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c'mon dude, these are easy.\n\nAdd second to first.\n\n2x = 2, x = 1, therefore y = -2.
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Jimbo, you gave up too soon......\n\nV = L*W*H = L*W*x in this problem\n\nV = (6-2x)*(4-2x)*x\n\nV  oila!
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For your first, |x - 3| > 10\n\nFor your second, if two cans of soda cost $1.40, how much would 7 cans cost?
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I would use substitution method on this one...\n\nFirst, break it up into the sum of 2 integrals...\n\nInt(cost/(1+sin^2t))dt + Int(-2sint/(1+cos^2t))dt\n\nFor the first integral let u = sint\n\ndu = cost\n\nThen you have an integral that you can evaluate ...\n\nInt(1/(1 + u^2)du = arctan(u)\n\nSubstitute cos(t) back in for u and you get arctan(cos(t)), evaluate that from 0 to pi/2.\n\nFollow the same reasoning for the 2nd one!
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(a) If marginal revenue is greater then the marginal cost, this signifies that variable costs for production of every subsequent unit are greater then additional revenue associated with it. Therefore, the company is either operating above the equilibrium point or is unable to reach it. As such, company should reduce the level of production to achieve the equilibrium point or stop producing at all. \n\nI would love to help you more on this assignment. If you need professional help - contact us at http://custom-writing.org/\nYour source for professionally written essays and A+ homework.
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set up 2 equations with 2 unknowns and solve\n\none equation will involve the total poundage\nx + y = 9\n\nthe other equation will  involve your  costs with oh say the Right Hand Side having 9 * .96 as its value\n\n.... i want you to think on your own so this is as far as i go :)
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if (1/x) + 2= (c/2)\n--------------------------------\n\n1/x = (c/2) - 2\n----------------------\nx = 1/((c/2) - 2)\n       (OR)\nx = ((c/2)-2)^-1\n-----------------------
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Cost to produce/market the product.\nGoing rate for similar products.
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The equation is 258.30 X 1.09. Incase you don't have a calculator, it's $281.55
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Here's the method (you can do the calculations yourself, surely).\nMaximize the profit xp(x) - C(x) over x: work out d/dx of the profit, set it equal to 0, and work out x. That's the optimum (profit-maximizing) quantity. Then put this x into the formula for p(x) = ... to work out the price. Finally, put this x into the formula for the profit: it is xp(x) - C(x) = ...
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Divide 950 by 5\nAnswer: $190