What would be the answer to this system: y> or less than -3x + 2 then y < 2x + 2 ?
142748
GO RIGHT HERE GIRL...\nhttp://www.shodor.org/interactivate/activities/sketcher/\nTHIS WILL GRAPH ANYTHING ONLINE
895237
you do not get specific values, there are infinite number of solutions for each equations\n\n2x + y = 9, y= -2x + 9\n\n-x - y = - 8, y=-x+8\n\n- 3x + 4y = 2, y = 3x/4 - 1/2\n\n- 2x - y = - 3, y= -2x +3\n`
241669
Y=x^3(x+2)(3x-1)\n we have three possibility for x\nx^3=0 than X=0\nx+2=0 than X=-2\n3x-1=0 than x=1/3\n\nso the answer is a
504744
4. \nquad 1 = (x,y)\nquad 2 = (-x,y)\nquad 3 = (-x,-y)\nquad 4 = (x,-y)
869140
Just graph it like an equality, and then your answer is everything either above (>) or below (<) the line.  For example, in the last inequality, the answer is everything above the line y = -2, not including the line itself.
586962
(6y^2-3y)(y+7)-->(2y)(y-1)(y+7)\nif that helps
861275
x(y-1) = 2y + 3\n\nxy - x = 2y + 3\nxy - 2y = x + 3\n(x - 2) = (x + 3) / y\n y = (x + 3) / (x -2)
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
956578
x^2+3x-y=c\n2x +3 -y'=0\ny'= 2x +3\n\n(remember y^0=1)!
756805
x<2   (-infinity,2)\nx>3   (3, infinity)\nx<2 see first interval\nx>-2 (-2,infinity)
848687
This answer refers to the problem of y>x^2-2x+3 or verbally\n    y is greater than x squared minus 2 times x plus three\n\nThis problem can be solved through direct substitution.\nYou need to remember that your ordered pairs are in the form of (x,y)\n\nLet's substitute in (1,4).  We know that x=1 and y=4:\n\n4 > 1^2 - 2(1) +3\n4 > (1)(1) -2(1) +3\n4 > 1 - 2 + 3\n4 > -1 +3\n4 > 2            \n\nsince this is true, the correct answer should be:  c  (1,4)\n\nHope this helps!
759105
False... y has to be 2...\n(3,2) is a solution, but not (3,1).
699429
c'mon dude, these are easy.\n\nAdd second to first.\n\n2x = 2, x = 1, therefore y = -2.
674651
put it in standard form :\n\ny < -1/2x + 3/2 \nand \ny > 2/3x + 2\n\nthen you know the first line passes thru the y axis at 3/2 and the second at 2\n\nthe slopes are -1/2 and 2/3 .... then shade below the line on the first one cuz y is less than .\n\nthen shade above the second line because y is greater than
771358
3x + 4 < x + 8\n2x < 4\nx < 2\n\n{x | x < 2}
417188
y=Asin(2x)+Bcos(2x)+(x/4)\n\nNow you get to determine why.
411757
since y=+-(x)^(3/2) Range [0,oo[\nnP=(n,n*n^1/2) and x_n/y_n= [(n^1/2^)/n]=n^-1/2