According to newton's II law of motion that is F=ma?
146790
Photons do not just have a very small, negligible mass, they have zero mass.\nA photon does however have momentum due to the fact that it is traveling at the speed of light.\n\nYou cannot apply a force to a massless object, therefore, Newtons 2nd law is of no use here.\n\nIt might also help to remember that a photon is just one way to look at the nature of light.  Not only is light a particle, it is also a wave, an electromagnetic wave, and you surely cannot apply a force to a wave.\n\nhttp://math.ucr.edu/home/baez/physics/ParticleAndNuclear/photon_mass.html
1044611
F = Gm1m2/ r^2\nF = ma  \na = v/t\nv = d/t\na =d/t^2 \nF = m d/t^2  = Gm1m2/ d^2\nm  = (m1 + m2)\nF = (m1 + m2) d/t^2 = Gm1m2 /d^2\nd/m2t^2 + d/m1t^2 = G/d^2\nd/m2 + d/m1 = Gt^2/d^2\nSQRT{ (1/G) d^2 (d/m2 +d/m1)} = t
903133
From what I learned in physics class, the force you are speaking of is measured in Newtons.
718152
weight equals mass times acceleration due to gravity
118764
Newtons 2nd Law,\nForce = mass * acceleration\n\nIf you have two masses (m1 & m2) that accelerate at the same rate,\nF1 = m1*a --> a = F1 / m1\nF2 = m2*a --> a = F2 / m2\n\nset both acclerations equal to eachother, solve for the ratio,\nF1/m1 = F2/m2\nF1 = F2 * m1 / m2 --> F1/F2 = m1/m2\n\nSo the ratio of Force 1 (F1) to Force 2 (F2) must equal the ratio of mass 1 (m1) to mass 2 (m2) in order for both to accelerate equally.
1001657
V= V(i) + AT Initial velocity plus acceleratin x Time\n\n\n   = V(i) + (F/m)T     Acceleration = Force/ Mass\n\nNote  use same system of units
883415
according to newton's second law, F=ma\nso, initially, let the force be F1, mass be m1 and the acceleration be a1\nthe final force is F2, mass is m2 and the accleration is a2\nF1=m1a1 and F2=m2a2\nas the force is decreased by a factor of 3.7, F2=F1/3.7\nand since the mass is decreased by a factor of 2.6, m2=m1/2.6\nF1/F2=m1a1/m2a2\nso, 3.7=2.6*a1/a2\nbut a1=8m/s^2\nso, a2=2.6*8/3.7\nso, a2=5.62m/s^2\nthis is the new acceleration
475727
the answer to the first question is 5 m/s.\nF=ma; a=F/m=200N/40kg=5m/s\nthe second answer is 1m/s.\nF=ma; a=F/m=2N/2kg=1m/s\nthe third answer is 1:4.\nF=ma; m=F/a\n(1) M=f/a=F/a=m\n(2) M=f/a=4F/a=4m
727100
Remember Newton's second law:  F = ma.  You can rearrange that to read a = F/m.  So the original acceleration was equal to the original force divided by the original mass.  After the adjustments, you have a2 = 3.3F/2.5m.  Therefore, a2 = (3.3/2.5)a, or 1.32a.  The original acceleration was 6 m/s^2, so the new acceleration is (6*1.32) or 7.92 m/s^2.
566394
Newton's second law is \nforce = mass x acceleration\n\nHow about this? Two men were walking on a hill when they see a bar of chocolate at the bottom. Both are eager to get it. The first man, a skinny little guy of 120 lbs, trips and begins rolling down the hill. The second man, a fatty of 250 lbs, trips at the same time and begins rolling down the hill. Because the fat man has more mass, he is able to produce more force to accelerate himself down the hill faster than the skinny man. The happy fat man reaches the bottom of the hill first, and eats the chocolate.\n\nIllustrations shouldn't be too hard.
1006189
Explain Newtons laws of motion.
975303
Second Newton's Law:\nF-mg*Sin(b)-mg*Cos(b)*k=m*A\nb=21 degrees\nF=100 N, Sin(b)=0.35, Cos(b)=0.93, m=11.5 Kg, k=0.400\nTherefore:\n100-11.5*10*0.35-11.5*10*0.93*0.400=11.5*A\nA=0.12 m/s^2\nv(t)^2-v(t=0)^2=2*A*(x(t)-x(t=0))\nv(t=0)=1.5 m/s, x(t)-x(t=0)=4.05 m\nTherefore:\nv(t)=4.79 m/s\nEnd. Thank U... Ramin
494540
Haha whats with all these answers, if you know basic physics, One of Newtons laws of motion is that:\n\n"for an object that is stationary or travelling at constant velocity, no force acts."\n\nso you ask what is the force?\nthere is no resultant force, the driving force and resistance are equal and cancel each other out.\n\n\nAnd additionally the basic equation to find force is:\nF=ma (force = mass x accelleration), this is evidence that an accelleration needs to be taking place for a force to act.\n\nLets say you want the force for a 50kg object accellerating at 3ms-2. F=ma  ->  F=50x3 ->  F=150N.\n\nNow lets say you want the force for a 50kg object travelling at constant velocity, no accelleration.\nF=ma  ->  F=50x0  ->  F=0N\n\n\nThere you go, wasnt that easy
83305
I suppose the problem was already due so I'll finish it for you now.\n\nF=m*a\na=F/m= 2*10^6N/1.2*10^6kg = 1.67m/s^2 * g/9.81m/s^2 = 0.17g
49354
Newton's First Law of Motion:\nI. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.  \n\nThis we recognize as essentially Galileo's concept of inertia, and this is often termed simply the "Law of Inertia". \n\nNewton's Second Law of Motion:\nII. The relationship between an object's mass m, its acceleration a, and the applied force F is F = ma. Acceleration and force are vectors (as indicated by their symbols being displayed in slant bold font); in this law the direction of the force vector is the same as the direction of the acceleration vector.  \n\nThis is the most powerful of Newton's three Laws, because it allows quantitative calculations of dynamics: how do velocities change when forces are applied. Notice the fundamental difference between Newton's 2nd Law and the dynamics of Aristotle: according to Newton, a force causes only a change in velocity (an acceleration); it does not maintain the velocity as Aristotle held. \n\nThis is sometimes summarized by saying that under Newton, F = ma, but under Aristotle F = mv, where v is the velocity. Thus, according to Aristotle there is only a velocity if there is a force, but according to Newton an object with a certain velocity maintains that velocity unless a force acts on it to cause an acceleration (that is, a change in the velocity). As we have noted earlier in conjunction with the discussion of Galileo, Aristotle's view seems to be more in accord with common sense, but that is because of a failure to appreciate the role played by frictional forces. Once account is taken of all forces acting in a given situation it is the dynamics of Galileo and Newton, not of Aristotle, that are found to be in accord with the observations. \n\nNewton's Third Law of Motion:\nIII. For every action there is an equal and opposite reaction.  \n\nThis law is exemplified by what happens if we step off a boat onto the bank of a lake: as we move in the direction of the shore, the boat tends to move in the opposite direction (leaving us facedown in the water, if we aren't careful!).
252215
2nd Law of motion:  the net force = the time derivative of the momentum vector.
780140
The forces are equal and opposite, but your friend with twice your mass will accelerate at only half the rate you do.  Newton's Third Law of Motion specifies that any action (i.e., force) has an equal and opposite reaction, in this case the force with which your friend pushes on you when you push on him.  Newton's Second Law of Motion says that the rate of change of momentum is proportional to an applied force.  This is usually rendered F = ma, where F is force, m is mass, and a is acceleration.  As you can see, to keep F constant when m is doubled, a must be divided in half.