how do solve: 2x^2 = 64?
141530
Steps:\n1) Divide by 2\nx^2=32\n2)Find square root\nx=sq.rt.32\n3)Simplify Radical\nx=sq.rt.(2)(16)\nANSWER:\nx=4+sq.rt.2\n\n*=times
836453
a^24b^24\njust multiply the exponents\n\nhope thie helps!!!
18182
2x^2 + 5x + 20x + 50\n2x^2 + 25x + 50
784942
2x + 2x - 12 = 52\n\n4x = 64\n\nx = 16\n\n\nAloha
832845
you need to add +1\nso that the equation can be represented as a perfect square\nx^2 - 2x + 1 = (x - 1) (x - 1) = (x - 1)^2\n\nthis is called solving by perfecting the square\nto do this, make sure that the coefficient of the first term is 1.\nThen, divide the coefficient of the middle term by 2,\nthen square the whole thing.\n\nIn this case, the coefficient of the middle term is -2\n-2 / 2 = -1\n(-1)^2 = +1
117585
4 and 64\nSQRT4 = 2\nSQRT64 = 8\n8 + 2 = 10\n64 - 4 = 60
825795
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
954896
x^2 + -2x = 5   Isolate the x^2 and x terms.\n\nx^2 + -2x = 5   Divide both sides of the equation by 1, which is the a-coefficient.\n\nx^2 + -2x + (-2/2)^2 = 5 + (-2/2)^2   Add half of the b-coefficient squared. In this equation that value is (-2/2)^2, and can be simplified to 1.\n\n(x + -2/2)^2 = 5 + (-2/2)^2   Write the x^2 and x terms side as a perfect square binomial.\n\n(x + -2/2)^2 = 5 + 1   Simplify the other side (simplify fractions).\n\n(x + -2/2)^2 = 6   Simplify the other side (combine numbers/fractions).\n\nSQRT[(x + -2/2)^2] = {+,-}SQRT[6]   Find the square root of both sides.\n\nWhen you combine and solve you'll get\n\nx = -1 plus or minus SQRT[6]
783870
7x^2+16x over (x-2)(x+2)(x+3)
678157
2x^2(1-2x)=0\n\nx=0\nx= (1/2)
781653
Eliminate the y to get\n2-x^2=2x+4\nx^2+2x+2=0\nusing quadratic formula\n(-2+-sqrt(4-4*2))/2\nwe see there are no real roots: the two functions do not intersect\nx= -1+-i
1123203
You can multiply and divide them easier.\n\nfifth root of 2x times 2x^20\n           -or-\n2x^(1/5) times 2x^20
959661
if by this you mean\n\nx^2 - 2x - 2 = 0\n\nx^2 - 2x = 2\nx^2 - 2x + 1 = 3\n(x - 1)^2 = 3\nx - 1 = sqrt(3)\nx = 1 ± sqrt(3)\n\n-------------------------\n\nbut if you mean\n\n7x^2 - 2x - 2 = 0\n7x^2 - 2x = 2\nx^2 - (2/7)x = (2/7)\nx^2 - (2/7)x + (1/49) = (63/49)\n(x - (1/7))^2 = (9/7)\nx - (1/7) = (3/7)sqrt(7)\nx = (1/7) ± (3/7)sqrt(7)\nx = (1/7)(1 ± 3sqrt(7))
796530
x/16 = 40/64\nmultiply both sides by 16\nx = 40/4\nx = 10
699210
Just plug in the numbers and solve for s...\ns=6^2-4^2\n    -----------\n       2(2)\ns=36-16\n     -------\n         4\n\ns=20/4\ns=5
59552
we have \nx^2 -84x+1764=0\nit's equation of second degree\nsolution x=42
508570
First you factor the like terms\np^2(2p+1)-49(2p+1)=0\nThen combine like terms\n(p^2-49)(2p+1)=0\nthen set each one equal to zero and solve\np=7, and negative 7     p=-1/2