How do I convert grams to liters?
142959
Well, actually you can.  If you know the specific volume of the material for which you wish to convert units, you can use volumetric measurements to determine mass.  Here's how you do it:\n\n# of grams * (specific volume, in L/gram) = # of liters\n\nSince specific volume isn't a very standard measure, you will probably need to convert from a measure of density (often in units of grams/cm^3).  Here's a more complete formula:\n\n# of grams * 1000 / (density in grams/cm^3) = # of liters.
798989
1) Calculate the mass of acid in 1 liter:\nIn one liter we have 0.01 mol = 1.321 gram\n\n2) Calculate the dilution factor:\nWe have to dilute by a factor 5/1.321 = 3.785..  \n\n3) Calculate the volume of the 5g/litre solution we have to dilute to obtain 100 ml:\nAs the dilution factor was 3.785, we need 100/3.785 = 26.42 ml of the original solution.
970837
Get the grams and moles and divide.
50047
For Cooking:\n1 teaspoon = 5 ml \n1 tablespoon = 15 ml\n30 ml = 1 fluid oz\n240 ml = 1 cup \n470 ml = 2 cups / 1 Pint\n28 grams = 1 oz. \n454 grams = 1 pound\n\nConversion:\n1 gram (g) = 15.43 grains\n1 fluid ounce (oz.) = 29.57 mL (30)
232453
480,000.0 mg /1000 = 480g, 0.80 L x 1000 = 800 ml, so 480g/800ml.  divide both sides by 800 = 0.6g/ml. m = milli = 1/1000. 1000 mL = 1 L, 1000 mg = 1g, 1000 meter = 1 kilo meter. Kilo = 1000.
251343
(5.5 grams/1 Liter)x(molar mass of glucose, arrange it so the grams cancel) = moles/Liter of glucose
842421
Recipe at:\nhttp://www.gisbornesc.vic.edu.au/home/jans/year9/polsh.htm\n\nYou'll have to convert the metric measurements into American by using your own brain or http://www.onlineconversion.com\n\nThere's a very basic method at this site, that doesn't involve chemicals, etc.\nhttp://ri.essortment.com/cleanandleath_rjmd.htm
616026
No conversion is necessary.  36 ug/l equals 36 ng/ml, the ratio is the same!
863742
http://www.translatum.gr/converter/measurements.php\n\nhttp://www.easysurf.cc/cnver7.htm
117205
The molecular weight of glucose is 120.\n120 grams of glucose in 1 liter of water is 1 molar.\ndivide 120 grams by 10^-9, mix that in 1 Liter if water and the result is 1nM. Multiply 120*10^-9 by 125 and dilute to 1L, thats 125nM. About 15mG glucose in 1ml H20.
543827
If you know the grams, which you do on one...its easy.  To find the grams from ml, you need to know the density.  Density is in grams/ml, so if the density was 2 g/ml and you had 4.5 ml, then you would have 9 grams.  So you take the grams and you need to find moles to calculate percent yield.  To do this, find the total molecular weight (for instance, water is 18 b/c of two H's which are 1 and one O which is 16).  When you have the grams and molecular weight, divide the grams by the molecular weight.  This will give you the moles, since the molecular weight is grams per mol.  Do this for every reagent or thing you use.  Whicever one has the lowest amount of moles is your limiting reagent because once that is gone, the reaction stops!  Now the theoretical yield is found by doing stoiciometry.  So whatever your limiting reagent is...that number is your theoretical yield for this problem.  Then weight the product when you are done, and find the amount of moles you have by oncve again dividing how many grams you have by the molecular weight.  Then divide that by your Theoretical yield and that is your percent yield!  Looks harder than it is.
746173
17.5 of what? gram ms, mg, kg, lb?\n\nby definition Molarity = atomic mass (gm)/1 liter\nMgCl2 – has (24.31 + (34.45)x2)=94.21\n\nso 1 mole of  MgCl2 = 94.21/1 liter\n\nSo since M=m/v\nassume  it is 17.5 gram ms in 2.5  Molar solution then \nv=m/(M x 2.5)=(17.5/94.21)/2.5=074=74 ml
851431
MASS / VOLUME\n that's way you measure it in g/mL
749394
divide the 15.8 g by the gfw ( molecular weight of Lithium chloride )
726654
For water, it's easy: 1mL=1g. For everything else, you need to know the density. Density is g/mL. So, if you have 3g of something that has a density of 6g/mL, you have 0.5mL of stuff.
188870
a scale or balence that uses grams
161453
you cannot directly convert liters to pounds without knowing the density of a substance. Once you know the substances density than it is a matter of conversion using like units from the density.