formula to figure gallons of water in round vessel.?
151746
Weigh it.  Each gallon weighs 10 pounds.
225482
Assuming that you mean a cylindrical tank, find its volume using the formula V=(pi)(r^2)(h).  To find the radius, plug the 12' circumference into the formula C=2(pi)(r).\n\nYou need to convert 38'5" to just feet.  \n\nConvert your answer, which will be in cubic feet, to gallons.  1 gallon=0.1336805 cubic feet.
486266
the formula for volume of a cylinder is V = h * pi * r^2.\nAlternatively, the surface area is A = h * pi * r * 2.\n\nSo, if you have either the surface area or the volume, you can calculate for the height.\n\nH = Volume / pi * r^2\nH = Area / pi * r * 2
856204
1. 285000 X 7.481 = 2132085 gal\n\n2.  I'm almost positive that this one is written incorrectly.\n\n3.  Use FOIL\n5x X 5x = 25x^2\n5x X 3 = 15x\n5x X 3 = 15x\n3 X 3 = 9\n25x^2 + 30x + 9\n\n4. w = 12/5x\nw = 900/y^2
966711
The volume of the water in the cup at any moment is:\n\nV = (1/3) pi [ (Rw)^2 + (1)Rw + (1)^2 ] \n   = (1/3) pi [ (Rw)^2 + Rw + 1 ] h\n\nRw = Radius of upper part of water\nh = height of water\n\nRw / h = 2 / 6\n\n6 Rw = 2 h\n\nRw = 1/3 h\n\nSubstitute in to the volume equation\n\nV = (1/3) pi [ (1/9) h^2 + (1/3) h + 1] h\n = (1/3) pi [ (1/9) h^3 + (1/3) h^2 + h ]\n\ndV / dt  = (1/3) pi [ (1/3) h^2 + (2/3) h + 1] (dh / dt)\n\nSolve for dh /dt  and plug in the values h=4 and dV/dt = 3
1107016
To find amount of water produced, first , we need to write a balanced equation for the reaction:  \n\n2H2 + O2 = 2H2O\n\nTo do any Stoechiometry calculations we need to change the grams to moles.\n\n1 g H2 * 1 mol/2.016 g = .496 moles of H2\n10 g O2 * 1 mol /32 g =.3125 moles \n\nThe ratio between H2 and H2O in the balance equation is 1:1\nOn the other hand, the ratio between O2 and H2O in the balanced equation is 1:2.  \nThat means we can make .496 moles of H2O from the given H2 and 03125*2 = .625 moles of H2O from the given O2.  In this case H2 is the limiting reactant since H2 will run out first. That means we can only make .496 moles of H2O from the given H2 and O2. \nNow we need to change the moles of H2O to grams.  \n.496 moles * 18.016 g/1 mol H2O = 8.936 grams.
708850
Water weighs 8.34 pounds per gallon\n\n1 cubic feet of volume holds 7.5 gallons of water\n\nfind the cubic feet volume of the tank (LxWxH) which is 30 \n\nthen multipy the cubic feet by the 7.5 which is 225 pounds.  Pretty heavy huh:)
804606
For cubic measure:  L x W x H = CI / 231 = G\nL = Length\nW = Width\nH = Height\nCI = Cubic Inches (Volume)\nG = Gallons\nMeasure the Length, Width, and Height in Inches.\n231 Cubic Inches to one Gallon.\nConvert Volume to Cubic Inches\nLength x Width x Height  = Cubic Inches  / 231 = Gallons\n\nFor Right cylinder measure: Pi x r'2 x H = CI / 231 = G\nPi = 3.14159\nr = radius (half of diameter) '2 = squared\nH = Height (or length)\nCI = Cubic Inches (Volume)\nConvert Volume to Cubic Inches. \nPi x r squared x H = CI / 231 = gallons
1031813
use the formula pi*r^2*h\nwhere pi=1.34\n r=radius (in inches)\n  h=height of cylinder (inches)
529872
Easy H*D*W    H=Height D=Depth W=Width *= times\n\nUse the units cubed, if it is meters use m^3 as the unit of measurement
518403
You make a container 16 cm by 3 cm (and 1 cm thick) and pour water inside. The weight of the water in gm is your answer.\n\nAnother method is to use Napier's Bones. Just sliding and matching the numbers.
28543
volume of a cylinder is pi*r^2*height:\npi * (1.5 ft) ^ 2 * (6 ft)\n42.4115008 ft^3\n\nso the volume of the cylinder is about 42.4115 cubic feet. There are about 7.48 gallons in a cubic foot, so: \n\n42.4115008 ft^3 * 7.48051945 gal/ft^3 = 317.260057 gal.\n\nSo a cylinder 6 feet tall with diameter of 3 feet can hold about 317.26 gallons of water.
220777
use the following formula .. \n\ntotatal surface area = \n[(H/D)*4(pie)(0.5D*0.5D)] + [ (H-t)/(D-2t)*4(pie)*(0.5D-t)(0.5D-t)] + [(pie)(0.5D*0.5D)-(pie)(0.5D-t)(0.5D-t)]\n\nthis is considering D = tank diametere is from outer surface and not the cavity diameter \n\n\nouter surface area of cover = (H/D)*4*(pie)(0.5D*0.5D)\ninner surface area of cover = [(H-t)/(D-2t)*4*(pie)*(0.5D-t)(0.5D-t)] \n\nthe base line are = [(pie)(0.5D*0.5D)-(pie)(0.5D-t)(0.5D-t)]
247410
There are different formulas for different shapes. This page has a list of them: http://www.math.com/tables/geometry/volumes.htm
920013
Let x be the amount of gallons you used:\n\nThere is a flat charge of $55 for the first 6,000 gallons.  So start with that.\n\nThen you need to add the excess charge.  The charge is 0.20 per gallon over 6000.  \n\nThe hard part is figuring out how to write the excess of 6000 gallons.  If I had used 7000, it would be 1000.  If I had used 8000, it would be 2000.  So in general, you would write (x - 6000).\n\nPutting it all together:\nWater bill = 55 + (x - 6000) * 0.20\n\nNow technically, you have two formulas.  You have one for amounts under 6000, and one for amounts over 6000.\n\nFor x <= 6000,\nf(x) = 55\n\nFor x > 6000\nf(x) = 55 + (x - 6000) * 0.20
11917
measure the height of the water in bucket or sink you're putting the model in BEFORE you put the model in.  Then put the model in and remeasure the water height.  Use the height and the dimensions of the vessel (bucket, sink, etc.) to calculate the volume of water that's displaced.  Using a perfectly circular or square vessel will be ideal.
289591
Volume = area x height\n\n3 inches = 0.25 foot\n\nArea = Pi x d'2 /4 = 3.1416 x 0.25 x 0.25 / 4\nArea = 0.0049\n\nVolume = Area x height\nVolume = 0.0049 x 10 = 0.4908 cubic feet\n \n1 cubic feet = 7.48 gallons  \n\nVolume in gallons = 0.4908 x 7.48 = 3.67 gallons