Pulley at table saw arbor is 2.5". Motor turns at 3450rpm. what size pulley do I need to turn blade at 4000rpm
145461
since pulley size vs. rpm is linear, you can just use a simple relation. 2.5/3450 = ?/4000
376771
check your timing first at idle speed, vacuum advance unhooked from the distributor and plugged off. \n8-14 degrees, usually i set it at 11-12.\nrev up motor to 3000 - 3500, check it again. now should be at 32-38 degrees, this is called total advance. now-\nwatch the smoothness of the way it moves on its way up to 3500, it should advance quick at first, then slower the more rpm, but smoothly and not erratic or jerky or all over the place. best way to get total - use a timing light that has a dial or a way to measure degrees so you dial the mark back to 0 on the light and read the #. that is the # of degrees. if you dont have one, go to the local speed shop and get a strip of timing tape. that will let you watch the #s better if all you have is an old scholl light.\nhope this helps.
240802
I agree with the first answer and I'll add alittle to it. If it is stock for stock and the 396 is a HP car motor then it will be faster. If you are going to be building one of these motors then the Sky's the limit. You can get a larger displacement from the 396 and will have more torque but for the money you can get more HP out of the 400. Just be aware that you cannot bore the 400 out as large as you can the 396 and there is no replacement for displacement.
572355
I can pull a tractor even with one horse power motor. Or less. I will use a pulley with mechanical advantage.
903919
Generator sizing becomes more difficult when electric motors are involved, due to their large starting demand.  Typically, there are two motor styles: CODE G requires 3 times running watts to start, and CODE L requires 5 to 6 times running watts to start.\n\nIt is not practical to think that all loads will start at the same time.  Nor is it practical to size a generator using all starting watts for all selected motors, as some motor loads will already be running (or OFF), when others are ready to start.  As you can see, it can be difficult to exactly size a generator for a group of specific loads, as they are constantly changing in their "ON" or "OFF" cycle.  Always try to limit your load selections to the bare essential items.\n\nTO FIND:\n1 PHASE KW = V * A * PF / 1000\n3 PHASE KW = V * A * 1.73 * 0.8 / 1000\n1 PHASE KVA = V * A * 1000\n3 PHASE KVA = V * A * 1.73 / 1000\nMOTOR - REQD 1 PHASE KW = ( MOTOR HP) * (EFF)\nMOTOR - REQD 3 PHASE KW = (HP) * (0.746) * (EFF)\nMOTOR - REQD 1 PHASE KVA = (MOTOR HP) * (EFF) * (0.8)\nMOTOR - REQD 3 PHASE KVA = (HP) * (0.746) * (EFF) * (0.8)\n1 PHASE PF = 3 PHASE PF = KW / KVA\n1 PHASE AMPS = (KW * 1000) / (VOLTS * PF) =  KVA * 1000 / VOLTS\n3 PHASE AMPS = (KW * 1000) / (1.73 * VOLTS * PF) = (KVA * 1000) / (1.73 * VOLTS)\n \nREQUIRED PRIME MOVER (ENGINE) HORSE POWER\n KW / (GENERATOR EFF. X .746)\n \nFREQUENCY (HERTZ)\n NUMBER OF POLES X R.P.M / 120\n \n ~ ~\nEXAMPLES IN GENERATOR SIZING FOR LARGE ELECTRIC MOTORS \n\nAll AC electric motors require large amounts of electric power to start up, due to it's starting winding. After approximately 3/4 - 1-1/2 seconds, the starting winding drops out, and the running winding continues, at a much lower power demand.  A generator must be sized to handle the load of the starting winding.\n\nSizing a generator for three phase motor starting LRA : \nThe formula is: Motor HP x KVA per HP x (1000 / (Volts x 1.73)) = LRA. \nGiven the size of your machines, estimate KVA/HP at approximately 6.\nTherefore, for 11 kW ... LRA = 134.6 = 135 amps. Generator must produce this current at 380 V, so (1.73 * V * A * 0.8 / 1000) = KW = 71.\nSimilarly, for 15 kW .... LRA = 184 A and KW = 97.\n\nBOTH SINGLE PHASE AND THREE PHASE MOTOR SIZING EXAMPLES ARE BASED ON INFORMATION IN NATIONAL ELECTRICAL CODE HANDBOOK, ARTICLE 430.7 AND IS INTENDED FOR MAXIMUM VOLTAGE DIP OF 25% UPON INITIAL MOTOR START-UP.  IF 35% VOLTAGE DIP IS ALLOWABLE, REDUCE LRA, THEREFORE KW SIZE, BY 25% (LRA or KW X .75). IT IS NOT RECOMMENDED TO CHOOSE ANY GENERATOR KW SIZING THAT YIELDS MORE THAN 35% VOLTAGE DIP.\n\nStarting more than one motor, at one time: make a list of all motors, totaling all running watts.  Calculate the starting demand when the largest motor is started while all others are running.  Add the largest motor starting watts, to the running watts of all smaller motors already running.
460746
I did my manufacturing technology in my university which requires us to produce an item from lathe and milling machine manually. \n\nSo based on my experience: If you wish to do taper, you need to check the tools availability which come together with the machine. Some are basic (need a lot of experience to use) while others are designed to meet a lot of requirement (it can specifies the angle of taper, depth of cut, shape of taper etc).\n\nMy advise: Check the tool first. Then learn how to use.
807395
http://eta.physics.uoguelph.ca/tutorials/torque/Q.torque.inertia.html\n\ngives 2I=mr^2  so I = 163*0.306*0.306/2\n\nhttp://buphy.bu.edu/~duffy/py105/notes/AngularMo.html\n\ngives 2 * kinetic energy = Iw^2\n\nso KE at 1500rpm = I*4/2*pi^2*(1500/60)^2 joules - everything is frictionless so this is the work done in accelerating the flywheel to 1500 rpm\n\nyou can work out the KE at 1181 rpm and find the difference that was dissipated as heat.\n\nbest of luck - Mike
350925
The best way is to measure it in a machine shop.  I've measured my time in machining and found there are two important numbers to know: 1) how long it takes to remove a cubic cm of material, and 2) how long it takes to clean up and setup for the next machining operation.  \n\nThe first number (material removal rate) is surprisingly small - it takes longer than you might think to remove a cubic cm of material (my range in tool steel runs 0.1-1 cu. inch/hour; less in softer materials).\n\nThe second number may surprise you also - it takes hours to break down, clean up, and setup for the next machining job.  Eventually you will develop a rules for particular jobs, for example, to put a "slide" in a mold base takes about 40 hours (just to cut the slide, not including the cavity pins).\n\nIf you are in production, such as screw machines, the second number is less significant because you can distribute the cost over the volume of the production.\n\nTo simplify: the most efficient typical cutting tool in terms of material removal is the lathe, followed by the drill, then milling, then fine machining, then finish grinding.  To the extent you can use the more efficient tools to remove material, the quicker the work can be done.  The bigger and more robust machine tools can remove more cubic cm/hr, but generally you are stuck with the tools you have.\n\nThere are straightforward calculations for surface feet per minute machining speeds depending on tools and metal to be cut, but this information is not really conclusive in estimating machining costs because setup and finish machining take so much longer than the material removal rate would indicate.  Estimate finish machining cu. cm/hr to be 10 times longer than rough machining unless you have a reason to believe it is shorter.\n\nThe way to calculate the total machining cost is by using a worksheet with all the operations step-by-step, including setup & breakdown, with estimates for time at each step.  For the machining steps, if you have no estimate, use about 0.5 cubic cm/hour unless you have reason to think more can be removed.  If you think this is too slow, run a test first because it takes longer than you might think.  \n\nI would say to ask a machinist, but they won't tell you as they guard this information closely, because it is the core of their business.  This is why it is good if you keep track of how long each machining operation takes when you do it.\n\nOne machinist kept extremely detailed records on networked computers on the shop floor how long each operation took, so he knew exactly how long a job would take.  His competition didn't; he never took a job he would lose money on, while his competition did.  He is still in business - they are not.\n\nIn short, it is best to confirm/develop yourself with your own tools the actual times needed to create your machining costs - there is no shortcut.
268387
It should be,if this is the original motor, is 10w30, summer,10w40 or 50 winter(depending on your location). If it is a motor from the mid-80's or newer it it should be a 5 weight\n5 qts.
603284
Depends on the age of the motor.  You better check with Johnson, They have been making them leaner through the years.  It also depends on the oil you are using, they have different specs.  But if you gotta have an answer right now, you're probably safe using 40:1.
812026
a) There are 2pi radians in a revolutuion\nThe angular speed in radians pers sec is simply 2pi xRPS\nwhere RPS is the number of revolutions per sec (1RPS = 60RPM) \n\n2400x2pi /60 sec = 251.33 radians per sec\n\nb) The circumference = pi Dia =  23.562 in = 23.562/12 =1.9635ft\n The speed of the saw teeth is 2400/60 = 40 RPS (x 19635 ft) =78.54 ft/sec\n\nJust a note about angular speed:\nThe angular speed is the answer to the question: how many times does it rotate in a given amount of time? This can be expressed in radians per sec, RPS or RPM etc.\nThe speed of the teeth (or of some other point on the blade) is the answer to the question: What distance do the teeth travel in a given amount of time, for a given RPS, RPM etc.?\nIf you take a disk, or circular blade, and draw a radial line on it and then give the disk a certain RPM then the points on your line will have the same angular speed, since different points on the radial line will all travel 360 degrees(or 2 pi radians) every revolution. But the points will be travelling at different speeds. Points at the edge of the disk will have the greatest speed since they travel a greater distance (i.e. a greater circumference) per revolution than points which are closer to the center of the disk. So the teeth of the saw will have a greater speed than points on the blade which are closer to the center, but they all have the same angular speed.
424547
the 302 only ran from 68-69.\n\nthough you can make your own.\nthe 302 shares the same bore as a 350, but the stroke is 3.00" instead of 3.48", so you have to get an aftermarket crank with a 3' stroke. get the correct length pistons and rods and you have a 302.
422657
go to www.stoodyind.com  This site list all sizes for a specific metal thickness. They have a very complete chart showing everything you need to know about the cut. Psi, kerf, speed etc.
276460
Try Jass machine company:\nwww.jassmachco.com/nustep.htm\n                            Lyndell
189249
totaly diferent motor
896349
RPM=120*FREQUENCY/P\nRPM=120*50/4\nRPM=1500 RPM.\nnow you want to run motor on 60 hz supply and others parameters same,then\nRpm=120*60/4\nRpm=120*15\nRpm=1800.\nRpm will be increased by 20 %.\nIf the 60 hz is permitted , then you will get 20 % more production.\nWe have lost production what we have expected as we are using 50 hz supply system and machine which we have procured having capacity based on 60 hz capacity!
960139
a picture is worth 1000 words --> http://images.google.com/imgres?imgurl=http://www.metalwebnews.com/howto/bandsaw/sawl.gif&imgrefurl=http://www.metalwebnews.com/howto/bandsaw/saw1.html&h=1982&w=1286&sz=58&hl=en&start=11&tbnid=aPmSNNATpMeNGM:&tbnh=150&tbnw=97&prev=/images%3Fq%3DBand%2BSaw%26svnum%3D10%26hl%3Den%26lr%3D%26sa%3DG