how to find the length of an arc?
141519
It is the length divided by the radius
508595
You have two ways:\nOld one: Thomson divide the arc into strips at equal intervals and solve each.\nNew one: Integrate from y=0, first root to y=0 second root
407911
So you are doing some numerical analysis... if you have a spreadsheet program you can use that. Use the trapezoid rule or Simpson's rule for some small increment in x.  Your spreadsheet program is able to evaluate arctan.  The second question can be evaluated with Newton's method.
731974
You should be doing your own homework.\n\nYou need to know the diameter of Jupiter in meters.\nConvert that number of meters to AU.\nUse the definition of "sin" (or "tan").\nOne second of arc is 1/3600 of a degree.
956315
The simplest way is to cut it into five slices, each with an arc of 72 degrees (or 2*pi/5 radians). You could probably also figure out a way to cut it into strips so that each strip has equal area, but that would be significantly more complicated.
493520
The length of the curve between the two points according to my calculation was:\n\nd = (3/2a) + (a*ln(2)/4)\n\nThe length is minimum under the condition that\n\na = √(6/ln(2))\n\n\n\nI don't have the time to show the full calculations, but I'll give you some key points:\n\n1. Find the line element 'ds' using the formula:\n   ds = √(dx^2 + dy^2)\n   -or-\n   ds = dx * √(1 + (dy/dx)^2)\n\n2. Evaluate (dy/dx) and substitute in above equation. \n\n3. Integrate the line element 'ds' determined above from x=1 to x=2 - this should give you the length of the curve in terms of 'a'\n\n4. To find the minimum length, differentiate the equation for length with respect to 'a', make the equation equal zero & solve for 'a'. This should give you the values for 'a' that is either for minimum or maximum. Now, differentiate the new equation once more & substitute the different values of 'a'. For each case, check if the equation yields a positive value - this means that it is a minimum case.
187232
LET:\nr = radius of pulley\ns = arc length = belt length that moved around the pulley.\nt = time of belt to move that length\nw = angular speed of pulley\nv = linear speed of belt\n\nGIVEN:\nr = 13.34 cm\ns = 52 cm\nt = 16 sec\n\nSOLUTION:\n\na) w = v/r = s/(rt) = 52 cm/[(13.34 cm)(16 sec)] \n = 0.24 rad/sec ANSWER\n\nb) v = s/t = 52 cm/16 sec = 3.25 cm/sec ANSWER\n\nI hope the solution is clear enough...
736325
Area of a rectangle is length XWidth. So if you have the area of a rectangular field or courtyard and either length or breadth/width,just divide the area by length to get the width and similarly just divide the area by width/breadth to get the length it is very easy\nWe know that Length XBreadth=area of the rectangular yard.\nTherefore,length=360.15/15\n=24.01m
939597
measure the distance between the beginning of the positive transition to the end of the negative transition.\nThis will be the wave length.
315798
I think what you're trying to explain is that all points A,B,C are on the cirumference of a circle, with the line AC being a diameter of the circle.\n\nThis forms a right angled triangle with the right angle at point B. That's just a rule of circle geometry when 1 side of a triangle in a circle is a diameter. By angle sum of a triangle, the angle at C must be 62 degrees.\n\nDraw in the line 0B, forming an iscoceles triangle OBC, since OB and OC are equal radii. In this triangle, angles at B and C are both 62 degrees, so angle at centre is 56 degrees. This is the angle that subtends the arc you want to find.\n\nIf you want the arc length you need the radius and use the formula\nl = 2 * pi * r * 56 / 360
120928
ok, let the triangle be ABC with sides AB, BC, AC.\ndraw a typical line, get too point on in with the distance of BC, name them B and C. then draw an arc with the center of B and the length of AC and another one eith the center of C and the length of AB. if they had a common point, it would be A and your triangle is there, but if not, there is no triangle with those three sides.
19668
The way to figure this out is, \n\nS=segment length of arc \nA=angle subtended by arc\nR is radius of circle \n\nS/A=2*pi*R/(2*pi),\n\nso S=RA\n\nthen differentiate with respect to time t, \n\nand dS/dt=R*dA/dt,\nand dA/dt=w, the angular speed\n\ndS/dt=T, tangential velocity\n\nso T=R*w
389433
If you're asking how to do it: Just take the total number of degrees of the angle, divide by two, and there you go, you know the measurements of the 2 equal angles.\nanswered by Fading Away...\n\nAngle bisector Theorem.\n\nIf you are a Geometry student who knows constructions, locate a radi from your vertex and draw an arc. Choose another radii on that new arc that you just drew(That is more than half the arc) from the point where your newly drawn arc intersects the segment. Draw another arc. Repeat process on opposite side. Draw bisectore from vertex through intersection of two arcs.\n\nHope that helps!\nAnswered by Emily\n\n\n\nThis was asked and answered 13 hours ago, click this link.\nhttp://answers.yahoo.com/question/;_ylt=Al6hLACuaPLouhbP7BmwxcIjzKIX?qid=1006041024466
811157
Your question is not well posed, but I'm going to restate it in the way that I'm guessing you're thinking.  \n\nSuppose you have a 20 inch diameter circle.  Take two points on the circle and draw a straight line segment between them that is precisely 8 inches in length (this is termed a "secant", or a "chord").  What is now the arc-length of the segment of circle between those two points?\n\nIf that is your question, then here is how I work the problem:\n\nYou have defined an equilateral triangle, two edges of which are the radii of the circle, 10 inches each, and one which is the chord of 8 inches.  We can now determine the ANGLE between the two 10 inch edges using basic trigonometry.  The easiest way for me to think about this, offhand is to divide the equilateral triangle in half, making two right triangles.  The hypotenuse is 10 inches, the opposite leg is 4 inches, and therefore the sin function of the angle is equal to 4/10.  the angle is therefore (approximately) 23.6 degrees.  Since we "trigged" a right triangle that was half of the original equilateral triangle, we need to double the result, yielding 47.2 degrees.\n\nThe angle between the two radii that subtend the arc who's chord is 8 inches (on a 20 inch circle) is 47.2 degrees.\n\n47.2 degrees represents 47.2/360 of the circle (or 0.13 of the circle).  Therefore the arc length of the segment in question is given by 0.13 x the circumfrence.\n\nThe circumfrence is pi times the diameter or 3.14 x 20 = 62.8 inches, therefore the arc length is given by 0.13 x 62.8 =\n8.2 inches\n\nThe answer here isn't terribly surprising.  The 20 inch diameter circle is quite large compared to the short segment of an 8 inch straight line.  The "gentle curvature" of the circle compared to the line means that the arc length of the circular segment isn't going to be much longer than the straight line.  If  you took it to the extreme and compared the circular segment from a circle who's DIAMETER was about 8 inches, then the arc length would become nearly half the circle, 3.14 x 8 / 2 =12.5 inches.  On the other hand, if the diameter of the circle got really really big (like the diameter of the earth for example) then you'd not be able to tell the difference between the straight 8 inch rod and the curve of the circle at all.  The answer would approach exactly 8 inches.\n\nI hope that answered your question!
634060
The length of one side of the rectangle can be related to the Circumference of the circle.\nTo get the perimeter of a circle, called the circumference of the circle, one simply has to multiply 2 times pi (about 3.14) times the radius of the particular circle. \nThe circumference of a circle can be calculated from its diameter using the formula:\nc = πd\nOr, substituting the radius for the diameter:\nc = 2πr\nWhere r is the radius and d is the diameter of the circle, and π (the Greek letter pi) is the constant 3.141 592 653 589 793...
1078788
For any line length X, it can be divided into 7 equal parts like so:\nStart with your segment --we'll call it AB-- and at point A, draw a ray going towards the top of your paper.  Then, with your compass, mark off seven equidistant points, starting at A (put your compass on A, make a mark on the ray; put your compass on that mark, make another on the ray, etc.) Then, draw a segment from your 7th point to point B.  Then just draw 6 more parallel lines (constructing congruent arcs and such) and your segment AB is divided.
353664
find the area of the cross section.... then times the area by the length... that is of course if it's a prism