how to calculate the 10th order root from a given number?
138197
Using what tool?\n\nInternet access?  Use Google Calculator -- see http://www.google.com/features.html#calculator\n\nPencil and paper?  Try iterations of Newton's method.\n\nCalculator?  Get a rough estimate by hitting the sqrt key ten times, subtract one, divide by ten, add one, then hit the "x squared" key ten times.\n\nLog tables?  Look up the logarithm, divide by ten, find antilogarithm.\n\nCalculator with x^y button?  Raise to the 0.1 power.\n\nCalculator with e^x and ln buttons?  Take ln, divide by ten, take e^x.\n\nC compiler?  Include <math.h> and use the pow function.\n\nJava?  Use Math.pow.\n\nFORTRAN or Perl?  Use x ** 0.1.
706596
You'd have to use the chain rule for the square root, then the quotient rule for what's inside.\n\nf ' (x) = (1/2) [(2x³ - 7) / (4x + 1)]^(-1/2) times the derivative of the radicand.\nFor that, the quotient rule gives:\n[6x²(4x + 1) - 4(2x³ - 7)] / (4x + 1)²\n\nThere's most likely some simplifying to be done, but that should get you on the right path.\n\nGood luck!
928231
8x-10x > -11-1\n\n-2x > -12\n\nx < 6
805031
1)  √10 · ³√100\n= 10^(1/2) · 10^(2/3)\n= 10^(7/6)\n\n2)  (6x)^(1/2) · (36x²)^(1/4)\n= (6x)^(1/2) · (6x)²^(1/4)\n= (6x)^(1/2) · (6x)^(2/4)\n= 6x\n\n...and so on.  Change the radicands to rational exponents with common bases, and follow the rules from there.  Good luck!
228116
The easiest way to find a square root is to use a calculator, but you can do it without one. Here’s one way, using 12 as an example of the squared number:\n\n   1. Pick a number that when squared, comes close to (but is less than) the number whose square root you’re finding: 3 × 3 = 9. This is a better choice than 4: 4 × 4 = 16\n   2. Divide the number you’re finding the square root of (12) by the number you squared (3) in step 1: 12 ÷ 3 = 4\n   3. Average the closest square root (3) and the answer of step 2 (4): 3 + 4 = 7. 7 ÷ 2 = 3.5\n   4. Square the average to see how close the number is to 12:\n\n3.5 × 3.5 = 12.25—Close, but not close enough!\n\nRepeat steps 2 and 3 until the number squared is very close to 12:\n\nDivide: 12 ÷ 3.5 = 3.43\n\nAverage: 3.5 + 3.43 = 6.935\n\n6.935 ÷ 2 = 3.465\n\n3.465 × 3.465 = 12.006, close enough!
737774
You figure the square root of each number separately...you've probably learned that in class alredy (how to do that)...then you take reach result, and multiply them together for your final answer.\n\nUse your textbook for reference...good luck!
908850
Memorize the table of powers of 2 from 0 to 10 or 16.\n\nIf you have a zero don't do nothing. If you have a one add the power of 2 for the position (position starts from zero).\n\nFor example:\n\n10\nfirst zero add nothing.  1 in position 1. so 2^1 = 2\nSo 10 = 2\n\n110\nposition 0. its a zero adds nothing.\nposition 1. 2^1 adds 2\nposition 2. 2^2 adds 4\n\n110 = 6
913982
Replace x with -2:\n4(-2)+y=10\n-8+y=10\n\nAdd 8 to both sides:\ny=18\n\nThe ordered pair is (-2,18)\n\nThe ordered pair means to find the x and y values.\n\nCheck:\n4(-2)+18=10\n-8+18=10\n10=10
920470
The answer is:  4.47, and that's all there is to it!\n\nOk Vanessa, all you have to do is pull up your calculator (Start>Accessories).\nI am not suggesting you don't work it out in your head first: it's just basic. Check the answer on the calc, or, if you get stuck....go back.... to POWERS OF HIGH HOLY ROOTISM   SQUARE YOU KNOW, 1x1+(2x2)+2+(10-5)/1=       Simple:\n1+4+2+5/1=12
426775
b = 2g - 10\ng = (b + 10)/2
604216
In an ordered pair, the first number stands for the x value and the second number stands for the y value.  \n\nTaking the first ordered pair you have (5,?), you know that the x value is 5.  So you plug 5 into the equation where it says x.  \n\n2(5)+y=10.  Now solve as a regular algebraic equation\n10+y=10  \ny=0\n\nNext one: (?,10).  This time you know the y value, so you plug the 10 into the y value and you have \n\n2x+10=10   Solve algebraically. \n2x=0, \nx=0.\n\nI will leave the last two for you to figure out, although I'm sure others will be posting it.\n\nI hope this helped you to understand HOW to do it...\n\nGood Luck.
193438
the 6^2 will divide out, and then you have to multiply the 2 with all the exponents on the inside....oh and r^0 is just one....so i think the answer would be t^-10 \nPS i just changed this answer, realized i made some stupid mistkae :-)
400015
By newron's ii law\nMa=F-f\nf=10-10*0.6\nf=4 N\nf= -4 i (vector notation)
962762
Here is how to reverse a number - it doesn't matter how many digits.\nYou'll have to figure out the rest of your program yourself - there isn't much left anyway.\n\nint reverse (int n)\n{\n   int r = 0;\n   for (;n>0;n/=10) r=r*10+n%10;\n   return r;\n}
1137789
Here are some of the things you can do to a whole number!\nNote: These can be done using a calculator\n\n1)\nAlso get the number next to it. (e.g. if you chose 5, get 6)\nmultiply them.\nmultiply the result by 4.\nadd 1.\nget the square root of it.\nSubtract 1.\nDivide by 2.\nThe result is the original number!\n\n2)\nSquare your number.\nAdd twice the original number\nAdd 1\nGet the square root\nSubtract 1.\nThe result is the original number!\n\n3)\nSquare your number.\nAdd 6 timesthe original number\nAdd 9\nGet the square root\nSubtract 3.\nThe result is the original number!\n\n4)\nSquare your number.\nMultiply by 4.\nAdd twelve times the original number\nAdd 9\nGet the square root\nSubtract 3.\nDivide by 2.\nThe result is the original number!\n\n5)\nNote: Here, you must choose a single digit whole number.\nmultiply it by 37.\nAdd the digits of the result.\nContinue adding the digits of the result until you get a single-digit result.\n(e.g. 5 x 37 = 185, \n1 + 8 + 5 = 14, \n1 + 4 = 5)\nThe result is the original number!\n\n\n6)\nAlso get the next two consecutive whole numbers.\nmultiply the first and the third.\nsubtract the square of the middle term.\nThe answer is always 1!\n\n7)\n(note: you must choose here a 3-digit whole number)\nmultiply it by 7\nmultiply it by 11\nmultiply it by 13\nThe result is the number repeated!\n\n8)\nnote: you must choose a single-digit whole number\nAdd 3\nMultiply by 2\nsubtract 1\nMultiply by 5\nAdd 580\nRemove the tens digit of the result.\nThe result is always 65.\n\nFrom here, you will no longer choose a number\n9)\n9 x 9 + 7 = 88\n9 x 98 + 6 = 888\n9 x 987 + 5 = 8888\n9 x 9876 + 4 = 88888\n9 x 98765 + 3 = 888888\n9 x 987654 + 2 = 8888888\n9 x 9876543 + 1 = 88888888\n9 x 98765432 + 0 = 888888888\n\n10)\n1/7 = 0.142857 142857 142857 ...\n2/7 = 0.285714 285714 285714 ...\n3/7 = 0.428571 428571 428571 ...\n4/7 = 0.571428 571428 571428 ...\n5/7 = 0.714285 714285 714285 ...\n6/7 = 0.857142 857142 857142 ...\nNotice that each is a repeating pattern of 142857\n\n^_^
153400
i believe it would be '-9'\nn=5 \n-3-(5-1)(1.5)\n-3-(4*1.5)\n-3-6\n-9
129538
The next number is 30651.\nIt has a recursion, a_n=a_(n-1)^2+2*a_(n-2).