In the four corners of  a street a man takes 80min for  each corner but for 1 corner he takes 1hour 20min why?
140361
80 mins and 1 hour and 20 mins is the same amount of time.
286517
It differs. From 90 feet a minute to 180 feet a minute.
374345
48 seconds / 4 people= 12 seconds
38833
We need to know how wide the road is. If it's a two lane road, it would only take about a second to cross.
334516
Well, 60 minutes = 3600 seconds\nIf he moves at 5 meters per second, he'll travel 18000 meters (5*3600) or 18 kilometers.
732600
SRY!! Matt is going to a basketball game out of town. If he could travel 75mph, He would arrive one hour early. If he could travel 45mph he arrives one hour too Late. How far is Matt's trip\n\ndis=75*(time-1)\ndis=45*(time+1)\n\nthen\ndis= 225mile,    time=4hour
66399
1 hour in some parts.
518996
He has to drive two miles (one mile up and one mile down) in two minutes.  He already took two minutes to get up the hill, so it is impossible for him to average 60 mph.
802160
Well you need a difference of two hours.  80 miles = 4 hours at 20 miles an hour and two hours at 40 miles an hour.  \n\n20 if the plane gets in at 8 and she leaves at 5 if she goes 20 miles an hour she will get there at 9 an hour late.  If she goes 40 miles an hour she get there at 7 an hour early!
1175600
They will meet when:\n\n4mph x Time = 3miles - 5mph x Time\n\nSo the answer is 0.33333 hours \n\nOr just 20 minutes.\n\n(not 27)
831693
Let x be the distance he walked.\n\ntime = distance/speed\n\nso time walked + time in truck = 10 hours\n\nx/5 + x/20 = 10\n\nmultiply by 20\n\n4x + x = 200\n5x = 200\nx= 40 km\n\nCheck - he spent 40/5 = 8 hrs walking out, and 40/20 = 2 hours walking back for a total of 10 hrs.
959794
Hi Jimmy\n\nA normal round played in a foursome would take roughtly 4 hours.\n\nYou could play alone and do it in about 2.5 hours but you would have to be moving pretty fast with no delays.\n\nLeon
243812
At most shouldn't it take only 13 minutes?  If 1 & 2 cross together, then they will take 3 minutes, and if 3 & 4 cross together, they will need 10 minutes.  10 + 3 = 13.\n\nMaybe I don't really understand the question??
83843
3 periods of 20 minutes
744614
They ran for 20 mph for 1 minute. In this time, they covered 1/3 of a mile. This means that for the other 9 2/3 miles, they ran at 35 mph.\nThis means their time for that part was 29/105 hours. Add in the 1 minute to get 29/105 + 1/60 to get 41/140 hours as their time. We take 10 divided by this to get their average speed, which is 1400/41 mph, which is approximately 34.14634146 mph.
1181326
Tim is right.  i just want to explain it further so you will understand.\n\nso the problem is we are looking for the time spent in both trips. lets call it "X". one is 1 hour longer than the other so we can call it "X + 1". \n\nif trip1 with a distance of 180 miles is taken in X with an additional 1 hour we can call this equation as 180 per X+1 or in mathematical form its 180/(X+1)\n\nif trip 2 with a distance of 135 miles is taken in X we can call it 135 per X or 135/X\n\nwe have now 2 equations 180/X+1 and 135/X\n\nsince the rates are the same we can say that the rate for 180/(X+1) is equal to rate for 135/X.  or in equational form it is\n180/(X+1)=135/X.\n\nWe now have a working equation.  If you notice, we are dealing with fractions and to equate it we need to transpose it using cross multiplication.  Cross multiplication is done by pairing the numerator of one side to the denominator of the other side and then proceed to multiplication.\n\nlooking at the working equation, we will pair 180 and X or 180X and another pair which is 135 and (X+1) or 135(X+1)\n\nnow we have a new working equation 135(X+1) = 180X\n\nto simplify 135(X+1) we multiply 135 with X and with 1. 135 and X is equal to 135X and 135 and 1 is equal to 135\n\nnow we have simplified the equation to 135X + 135 = 180X\n\nto get the value of X, we combine similar terms.  they are 135X and 180X.  We combine this by transposition.  Remember that in order not to change the value of the equation we must change the sign of what is moved to another side.  In this case i will move 180X to pair it with 135X and move 135 to the other side. so now we get 135X - 180X = -135\n\nwe simplify the like terms and we get -45X.\n\nnow we have -45X = -135\n\nbut we are only looking for X so we must eliminate -45 from the X.  identify the numerical coefficient of X which is -45 and devide it from the original. what you do to one side, you should also do it to the other.\n\n-45X/-45 = -135/-45 with this equation we can simplify it into\nX=3\n\nnow we have the value for X\n\nso one trip will be 3 and since another is 1 hour longer then it must 3 + 1 = 4\n\nheres the solution\n\n180/(X+1)    =      135/X\n135(X+1)     =      180X\n135X + 135   =    180X\n135X - 180X   =    -135  \n            -45X   =    -135\n         -45X/-45=    -135/-45\n                   X =  3\n          \n             X + 1 =  trip 2\n             3+1 = 4
573729
An alternative method:\nThe times taken by A, B and C to complete one lap around the track would be 10/7, 10/8 and 10/9 mins, respectively. Now we just need the LCM of these three to find out when they will all catch up with each other. \n\nThis turns out to be 10 mins.