what is the kinetic energy resulting from the movement of particles? thanks?
148295
the formula is\n\nKE = 1/2(mv^2)\n\nwhere m is mass in kilograms, v is velocity in meters/second.\n\nBy the phrasing of your question, perhaps what you meant is the WORK involved in moving (essentially, accelerating) a particle. Work is a measurement of how much energy is added or subtracted from a system and can be evaluated thus:\n\nW = dKE\n\nwhere d = delta, which is normally represented by a triangle. It means "the difference" in Kinetic Energy (KE) and can be measured thus:\n\nW = KE(0) - KE(1)\n\nWhere the number in parantheses represent subscripts. Thus KE(0) is the initial amount of kinetic energy before any change occurs, and KE(1) is the amount of kinetic energy after the change occurs. The difference equals the amount of work done on the particle.\n\nWork is measured in Joules (Newtons * Meters). It is a scalar, not a vector (it does not indicate direction, only a value), so it should always be positive. [not entirely sure about this part]\n\nYou can also measure work if you know the force applied to an object and the distance during it was applied.\n\nW = F*D\n\nWhere Force is measured in Newtons (mass * acceleration) and distance is measured in meters.\n\nI only had a C in physics, so if I've got something wrong here, feel free to point it out...
686704
The increase of the gravitational energy (m1+m2)gh is the loss of kinetic enery m(v^2)/2.\nThe bullet gets the same speed as the bob.\nUse conservation of momentum.
167143
Start with formula for total energy (the derivation of this is pretty awful and requires lots of diagrams to explain it)\n\nSo total energy is g*m*c^2 [g is gamma factor 1/sqrt(1 - V^2/c^2)]\n\nThe kinetic energy is total energy minus internal energy of particle = g*m*c^2 - m*c^2 (1)\n\nNow expand the gamma factor as a binomial series:\n\ng = 1/sqrt(1 - V^2/c^2) = 1 + (v^2/2*c^2) + ...\n\nsubstitute this into the above equation (1) and you get\n\nkinetic energy = m*c^2(1 + v^2/2*c^2) - m*c^2\n\n= 1/2*m*v^2\n\n(This is an approximation - so this only applies for low velocities. For relativistic velocities use formula (1) or expand the binomial expression to higher degrees of 'v')
533718
The particles must collide with sufficient energy (i.e. be moving with sufficient velocity) and they must collide with the proper orientation to form a new bond. They must overcome the activation energy plateau in order to react.
838178
The answer should be A.\n\nAverage kinetic energy of a substance is related to the speed of the particles moving in it and the temperature of the substance.\n\nAs the particles in the a substance moves faster, the average kinetic energy of the substance increases.  So does the temperature.\n\nWhen a substance changes phase, the temperature will remain constant.  This means that the average kinetic energy is also constant during this process.  Hence, B is wrong.\n\nWhen thermal energy is being transferred out of the substance, one could understand it as taking out some particles out of the substance.  So what is changed here?  I would think that the total kinetic energy is being changed, since some particles have been taken away.  But the taking away of the particles would not affect the speed of the remaining particles.  The AVERAGE kinetic energy should remain unchanged.  Hence, C is also wrong.
837367
Kinetic Energy\nKinetic energy is the energy of motion. An object which has motion - whether it be vertical or horizontal motion - has kinetic energy. There are many forms of kinetic energy - vibrational (the energy due to vibrational motion), rotational (the energy due to rotational motion), and translational (the energy due to motion from one location to another). To keep matters simple, we will focus upon translational kinetic energy. The amount of translational kinetic energy (from here on, the phrase kinetic energy will refer to translational kinetic energy) which an object has depends upon two variables: the mass (m) of the object and the speed (v) of the object. The following equation is used to represent the kinetic energy (KE) of an object.\n                     \nke=1/2*m*v^2\n\nwhere m = mass of object\n\nv = speed of object
770931
yes the kinetic velocity is incresed....due to the phase change...this is why we give energy for the liquid to vapourise to increase the energy of each molecule and seperate them ...for the motion to be faster
446643
The movement of an electron from one place to another.
887598
Well a very very simplistic demonstration could be shown on a pool table.\n\nIf you shoot the cue ball at a stationary ball (let's call it the 8 ball) across the table, the cue ball has Kinetic Energy, where as, the 8 ball has only potential energy.  \n\nWhen the cue ball collides with the 8 ball, the kinetic energy will transfer from the cue ball to the 8 ball, sending the 8 ball in motion.  Now that the 8 ball is in motion it has Kinetic energy which is a change of form.  \n\nThe Law of Conservation of energy says that energy cannot be created.  So what does that mean?  It means that if the 8 ball is now in motion, it took energy from the cue ball, which means that the cue ball has now lost energy, and will be traveling slower, and if they hit at the right spot (since they are approximately equal in mass) the cue ball can even come to a complete stop upon collision.\n\nHope I didn't lose you!\n\n~~Tyler\n\n\nAlso, an easier example would be a monkey falling out of a tree.\n\nIf the monkey is sitting down eating a banana on the highest branch, he has Potential energy.  If he reaches for another banana and it's just out of his reach and he slips off of the branch, his potential energy is now being converted into kinetic energy.\n\nHopefully theres a pile of leaves on the ground.
217138
the particles move faster.
262268
KE = 1/2 m v^2, so if the velocity remains constant, the kinetic energy and mass are directly proportional.
247664
It's at the apex of the circle.\n\nThe total energy of the system is the sum of the kinetic energy, 1/2 mv^2, and the potential energy, mgh (where h is the height above the circle's lowest point).  At the bottom of the circle, all the energy is kinetic and the speed is highest; at the top, some of this energy has been stored as potential energy, according to this:\n\n1/2 m (v_bottom)^2 + 2mgr = 1/2 m (v_top)^2 \n\nThe actual value of the velocity is undetermined, as v_bottom can be as fast as you like.\n\n>>>EDIT:\n\nPoster above is completely right.  Whoops :)  That'll teach me to do this on scraps of paper at work...
405474
This is the rest energy of a particle. Energy equals mass times the speed of light in a vacuum squared. This expression became famous for its simplicity, even though it's not really all that practical. I read once that even at absolute zero particles will still have some motion. I'm not sure how one would go about proving that since it's impossible to get anything to a temperature of absolute zero. Anyway since there will always be some movement, the more practical version is:\n\nE = mc^2 /(sqrt(1 - v^2/c^2)), where v is the speed of the particle. (sqrt() is meant to mean the square root of the argument inside the parenthesis)\n\nIt's important to note that this is only true for a particle since you have to consider binding energies if you want to look at anything more complex.
897524
Kinetic energy is .5 * mass * velocity ^ 2\nSo the change in kinetic energy, or delta K.E, would be:\n\n.5 * mass * initial-velocity ^ 2 - .5 * mass * final-velocity ^ 2\n\nSince Kinetic Energy is lost, the initial velocity goes first.\n\nGood luck on your test!
538402
No because of Kinetic energy.\n\nLesson 1: Basic Terminology and Concepts\nKinetic Energy\nKinetic energy is the energy of motion. An object which has motion - whether it be vertical or horizontal motion - has kinetic energy. There are many forms of kinetic energy - vibrational (the energy due to vibrational motion), rotational (the energy due to rotational motion), and translational (the energy due to motion from one location to another). To keep matters simple, we will focus upon translational kinetic energy. The amount of translational kinetic energy (from here on, the phrase kinetic energy will refer to translational kinetic energy) which an object has depends upon two variables: the mass (m) of the object and the speed (v) of the object. The following equation is used to represent the kinetic energy (KE) of an object.
1131325
Maybe this can help...all you have to do is a search in Yahoo or Google...\n\nhttp://www.think-energy.com/ThinkEnergy/11-14/activities/EnergyTrans.aspx\n\nTry searching for "energy" or "kinetic energy"
393889
There is potential energy and kinetic energy.  Kinetic energy is the energy that something has from motion.  It's equation is E=1/2*m*v(squared) where m=mass and v=velocity.  For potential energy there are many forms.  Gravity E=mass*height*gravity, Electric and magnetic fields are potential energy.  And nuclear energy E=m*c(squared) which is the rest potential energy that anything with mass will have.  There is also energy from light E=h*nu, nu=frequency h=planck's constant.  There is also chemical potential energy which is the energy contained within molecules.