What is the relationship between numbers that have 13 as a demoninator?
157255
they r alwes divisible by 13....
556508
XD the number 666 represents the devil. Good Job, but for posting this question, you lost five points again? O.o
483474
How about this:\n\nhttp://en.wikipedia.org/wiki/13_%28number%29
256724
10 12 14 18\n\nbecause you are just 13
133903
You can put it as the last number, right after 2, because that would be the 13th number.\nOr it could be after the number 6. If you add all the numbers and divide by 13, you would get 6.
1069170
13212211\n\nJust counting numers in the previous number.\n\n'm i right??
365093
7.38461538    \nor\n7 5/13\nor\n7(+5)\n.\n.\n.\n.\n.
1117885
23\n\nAny number exactly divisible by three can be represented just using the three. Any number that yields a remainder of 1 when divided by three and is at least 13 can be represented as 13 plus some number of 3s. Any number that yields a remainder of two when divided by three and is at least 26 can be represented as 13+13+some number of threes. Because all numbers must have a remainder of either 0, 1, or 2 when divided by 3, all numbers at least 26 can be represented with one of these schemes. It is easily seen that adding the ability to include more than two 13s, or any number of sixes, adds no additional power to the system. Therefore, the greatest number not representable would be the largest number less than 26 and having a remainder of 2 when divided by three. This number is 23.
785946
mine is 132, 215, and 22. they are all special to me in some way! just people that are special to me. i transfigure their names to numbers!
324897
Could be 10,14,13. The odd terms differ by 3 (eg. 4-1,7-4), the even terms differ by 4.
349393
The "powers" often assigned to numbers come from old superstitions and folklore. \n\nThirteen is supposedly unlucky because there are thirteen witches in a coven, Judas was the thirteenth Apostle, etc.\n\nSeven is supposedly lucky because it appears frequently in the Bible, seven heavens, seven seals, etc.
41742
rt11guru said it.  here's another easy way.  write down the powers of two in *descending* order, starting with the one that is next smallest after your number.  for instance, the power of 2 that comes after 534 is 512 or 2^9.  so you write down this list of numbers:\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n\nthen go through and find the largest of these powers of 2 that is less than your number.  in this case, that is 512.  put a 1 underneath 512:\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n  1\n\nnow subtract that power of 2 from the number you started with.  534-512 = 24.  repeat the process.  find the largest power of 2 that is less than 24, which is 16.  put a 1 under that number:\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n   1  |        |        |      |      |  1  |    |    |    |\n\nnow subtract that power of 2 from your number.  24-16 = 8.  keep doing this until you've reached zero.  in this case it only requires one more step, because 8 - 8 = 0.  your table at the end should look like this:\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n   1  |        |        |      |      |  1  | 1 |    |    |\n\nnow, everywhere that is missing a 1, fill in a 0.  \n\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n   1  |   0   |   0   |  0  |  0  |  1  | 1 | 0 | 0 | 0\n\nthat sequence is your binary number.  in the case of 534, it is 1000011000.\n\n(sorry, this looks terrible.  can't format it properly in this yahoo window.  but, each one of those | in the bottom rows should line up with the | in the top row.)
5567
According to Wolfram Research, \n"An n-digit  number that is the sum of the nth powers of its digits  is called an n-narcissistic number. It is also sometimes known as an Armstrong number, perfect digital invariant (Madachy 1979), or plus perfect number.\n\nThe values obtained by summing the dth powers of the digits of a d-digit number n for n==1, 2, ... are 1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 2, 5, 10, 17, 26, ... (Sloane's A101337).\n\nThe smallest example other than the trivial 1-digit numbers is\n153==1^3+5^3+3^3.(1)\n\nThe first few are given by 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634, 8208, 9474, 54748, ... (Sloane's A005188). "
806319
I have a friend who "has" 13 but not over.\nHer name is Maryelizabeth.\nYes all one name.
738298
[k+2]=13\nk+2-2=13-2\n       k=11
122963
4 would be 16/4 and 8/2  - simply *2  the number and make sure the demonator - lower number is 2, or \nmultiply 4 of the number and make the lower number a 4.\nfor example\n20 would be 40/2 and 80/4 are improper.
1024248
There's a lot of good answers here, and some not so good (when I have more time I'll explain the real difference between a witch and a wizard....)\n\nHere's one possibility not yet mentioned: the Death card in a Tarot deck bears the roman numeral XIII. Thirteen.\n\nJust a suggestion.