x + (2.7336)y = 5.48814 <---- solve for y and x?
142014
Dear One,\nit seems to me that you do not need parentheses when you multiply a number with y, but you may need a second formula to solve the values of both, x and y. \n\nIs something missing, or, may be, it is a different kind of math than I am used to?\n\nThe value as is for x would be (as I understand it)\n\nx +2.7336y = 5.48814\n\nIn algebra you treat both sides of an equation like you would treat an old fashion scale to keep it in balance, treating both sides alike. \n\nIf you want to isolate x on the left side, you have to get rid of the 2.7336y by subtracting it. \n\nHowever, to keep the scale in balance, you have to subtract it on both sides:\n\nx +2.7336y -2.7336y = 5.48814 -2.7336y\n\n+2.7336y -2.7336y is of course 0, and you can cross both out on the left. You get\n\nx = 5.48814 -2.7336y\n\nIf you now had another formula for x, you could place that result in this formula for x. And would get the value for y.\n\nHere ends my "math tooth."\n\nDid it help at all?\nCordially, India.Magica
338519
If you remove x completely (because you already know it's equal to 9), you have:\n\n4y = 9\n \nor 9/4 which is 2.25
394124
y=5\nx=-2/3\n\nSame method as the other one.
1160088
(1.02)^n = 2, solve for n....ln2 / ln1.02 ~ 35 years
743387
Working above is good until this step:\n\n2 + 0.8x >0.9(x + 6)\n2 + 0.8x >0.9x + 5.4)\n0.1x > -3.4 ← Symbol error in this line\n\nShould read 0.1x < -3.4\nie x < -34
1186783
You can't really solve it - all you can get is x+y=31.54875
769640
Solve one equation for x (or y), then substitute that value into the other equation.\n\nExample:  x-2y=5, so x=2y+5\n\nNow substitute this for x in "5x-2y=5"\n\n5(2y+5) - 2y = 5\n\n10y + 25 - 2y = 5\n\n8y = -20\n\ny = -20/8 = -5/2\n\nPut this value for y back into your first equation to solve for x:\n\nx = 2y + 5\nx = 2(-5/2) + 5\nx = -5+5\nx = 0\n\nANSWER: x=0, y=-5/2
399118
y-int= (0,-5)\nx-int= (-1.2,0)
934111
X + Y = 1\nX = 1 - Y\nsubstitute\n63x + 65y = 63.5\n63(1-y) +65y = 63.5\n63 - 63y +65y = 63.5\n63+2Y=63.5\n2Y=.5\nY=.25\nX= 1-.25\nX= .75
1081089
[ (50000 x 2.4)+(25000 x .8) ] / (50000+250000)=1.8\n\nThe remainder of the info in the problem is not necessary.
821374
The two numbers we'll call x and y.  Let's set up equations to model the situation:\n\n\nx+y=38\nx-y=14\n\nSolving the second one for x,\nx=y+14\n\nPlug this into the first equation for x and get:\n\n(y+14)+y=36\n2y+14=36\n2y=36-14\n2y=22\ny=11\n\nx-y=14\nx-11=14\nx=14+11\nx=25\n\nThe two numbers are 11 and 25.\n\nHope this helps.
160067
When you substitute with y=x^(1/6), you're assuming :\nI) x>0 (which should be put as a starting condition)\nII) y>0 . This is to be considered after solving the 2nd degree equation, as you get a fake solution y= -3 that you must reject as non-acceptable.\n\nThe only acceptable solution is x= 1/64
231399
You have vf1=1.73 and that should be vf2 instead.\n\nvf2=1.73 and then you solve for vf1=3.45\n\nvf1+5vf2=12.1\n2vf1-4vf2=0 so vf1=4/2vf2 or vf1=2vf2\nIf you substitue vf1 from the first equation with 2vf2 instead, this gives you\n\n2vf2+5vf2=12.1 or 7vf2=12.1 and solving for vf2 gives you 1.73, which you have correct\n\nthen, we already decided that vf1=2vf2, so\n\n2 * 1.73 = 3.46 = vf1
58270
x*y=90\nx=2.5y\n\nSubstitute 2.5y in for x:\n(2.5y)*y=90\n2.5yy=90\n2.5/2.5 yy=90/2.5\nyy=36\ny^2=36\nSquareroot(y^2)=squareroot(36)\ny=36\n\nplug-in y:\nx*6=90\n(also known as 6x=90, as is normally written that way)\nx*6/6=90/6\nx=15\n\nThus, 6 and 15\n\ny=15
886597
Y+X=10^26\nX*.02=Y\n\nSo:\n51X/50=10^26\nX=5*10^27/51\nY=10^26/51
274368
y=62.98\n\nYou just divide 522.734 by 8.3...
369017
Set one equation equal to one of the variables, then insert it into the other equation and solve for the second variable.  then insert that variable into the original equation.\n\nx+y=5 or x=5-y\nx+2y=6\n\nput x=5-y into the second equation\n\n5-y+2y=6 \n\nnow solve for y\n\ny=1\n\nput this back into one of the original equations\n\nx+1=5\n\nx=4