what is the mathematics behind bobsleding?
155762
The angle and speed. Have you watched coll runnings? You should its a g8 bobsleighing movie!
115763
Gravity states that if you drop 2 things at the same time, regardless of weight they would hit at the same time. Yet a larger mass rolling down a hill will gain more speed. Just watch the difference in speed from the skeleton & bobsled teams.
706663
The idea is that all forces at the nodes (connecting points) are balanced. Draw the two free body diagrams.\n\nLeft point:\nFx\n0=-T1cos53+T2cos11\nFy\n0=T1sin53-T2sin11-57\nRight point:\nFx\n0=-T2cos11+T3cos42\nFy\n0=T2sin11+T3sin42-W2\n\nBy inspection we see only the first 2 eqns are required. Solve the system:\n0=-T1cos53+T2cos11\n0=T1sin53-T2sin11-57\n\nT1=83.62 N\n{=}8.5 kg
655705
MATHEMATICS\n\n(MAT HE MAT ICS)
141117
The need for speed in a bobsled and luge dates back to at least 800 AD. Dangerously fast, bobsleds -- with two- or four-person teams -- were born from the toboggan as well as other early sleds used for transportation in snowy climates. The word "bobsled" comes from the fact that early sleds bounced, or "bobbed," while speeding downhill. \n\nIndividual racers plunged headfirst down the bobsled course on the ominously named "skeleton" sleds, steering with their head and shoulders. This is different from the luge (French for "sleigh"), on which one or two riders race lying down, feet first. Evidence of the luge dates back 1,200 years to Norway, where small sleds were first used as both vehicles and toys.
49314
Sorry, but with the time you spent typing these questions you could of looked them up in your physics book or googled them.  Sometimes getting others to do your leg work isn't always the best answer to a problem.  Good Luck in your new class!
573729
An alternative method:\nThe times taken by A, B and C to complete one lap around the track would be 10/7, 10/8 and 10/9 mins, respectively. Now we just need the LCM of these three to find out when they will all catch up with each other. \n\nThis turns out to be 10 mins.
103207
i got to say figure skating,bobsled,skelaton, luge, curling
702361
ok biker bike, here we go.\n\nacc.= g = 9.8 m/s2, (any object moving in air will have this acc. or retardation)\n\nb) we apply formula\ns=ut + 1/2at^2\nu=20\nt=4\ns=20*4 + 1/2 *9.8 *4*4\n  =158.4 m\n\nc) v=u + at\n  therefore, t= v-u/a\n                   =50-20/9.8\n                   =3 seconds (approx)
832950
Well use Newtons second law. The sum of all Forces = mass times acceleration\nF = m*a\nIn the x direction the only force is friction, and the mass is the skier. The force is negative because it is slowing down the skier.\n-25 = 6*a\na = -25/6 = -4.2\n\nNow  The change in velocity is the constant acceleration times the time. \n(v - v0) = at.\n(v -v0) = -4.2 m/s^2 *20 s = -84 m/s\n\nThis is a very ridiculous problem. Most skiers are about 10 times as massive, and a speed of 84m/s is equal to 190 miles per hour.
60345
Website for the Jamaican Bobsled team:\n\nhttp://www.jamaicanbobsled.com/content.html\n\nSeems that they still exist (or did in 2002).
167280
I like the figure skating, bobsledding, downhill skiing.  My favorite though is curling, since it's the only sport I can do.
844533
from what I remember conservation of momentum states that: \nm1v1=m2v2\nwhere in this case, m1= mass of the astronaut\nm2=mass of the sat.\nv1= unknown\nv2=speed of the sat.\n\nyou can find the speed by solving the above equation for v1:\nv1=m2v2/m1\n\nFrom there, once you have the speed you can calculate the distance by multiplying the speed (v1) times the time (7.5 s) given in the problem.
82489
So you love sleds.  Good news!  Skeleting is one part sled, one part you!  (That is, if you're interested in driving a one-person sled down an ice track at top speeds of 80 mph!)  What makes the sport different from luge is that you're face first, stomach-side facing the ice.  After you make that running start and jump on board your sled, I can imagine it would feel a lot like it's just you and your helmet facing a narrow track of hard, hard ice.  You still interested?\n\nIt's the oldest known sledding sport, actually.  Hailing from St. Moritz, Switzerland, when the Cresta run was built in 1884.  In 1928 and 1948, the Olympics were held in St. Moritz, so they included this oddball Skeleton sport!  ...but it wasn't actually permanently added (or I guess considered anything but crazy?) until 2002.  Maybe that's because those X-Games couldn't possibly be worse?  Best,\n\n`k.
769260
Use mgh for the pendulum at rest at the highest point, ( in other words at one end)\n\nm = mass of the "bobble" at the end of the pendulum\n\ng = force due to gravity\n\nh = height of bobble above where it is at the centre\n\nthe mgh above is the potential energy of the bobble due to its height (it is at rest for a moment as it changes direction.\n\nAt the centre it no longer has any potential energy, as it is at its lowest point and potential energy is due to height.\n\nAll its energy at the centre is kinetic energy\n\nthis is 1/2 m v^2\n\nsince energy is neither created nor destroyed ( at least for the purposes of questions like this)\n\nmgh = 1/2mv^2\n\nDivide each side by m (that gets rid of the bobble).\n\nThe question will have told you the height (or enough about the circle for you to find it)\n\nIt's not a very clear diagram.  It looks to me as if the height is 50cm = 1/2 metre\n\ngood luck!
783093
49 N will slide the penguin, taking g=10 the penguin masses 7kg and the sled 6kg. to get 49N on the penguin it needs to be accelerated at 7m/sec/sec sideways and to do this the sled need to see a force of 13*7 N in excess of 13N so I would estimate that a bit less than 14*7N will do the job.
481524
Sports is a pretty easy way to explain physics of all sorts...  \n\nEnergy to heat (of exertion)...\n\nKinetic energy of the vaulter/gymnast being transferred into the spins, jump, landing...\n\nPotential energy meets kinteic energy: football (U.S.) linemen\n\nCircular forces (centrifugal/centrifical) / angular momentum: a speed skater around a corner\n\nEffect of friction/gravity/force on object with specific mass: skiing\n\nTransfer of kinetic energy: golf club to ball, kick to ball,\n\nKinetic meets kinetic: baseball meets bat - net sum of energy of bat in positive direction + energy if ball in negative direction = distance/height ball travels.  Same with volleyball\n\nAcceleration/deceleration of gravity: balls making arc \n\nHowever, you say you want to "analyze a problem with sports" - do you need quantitative examples or just be able to explain all the forces at work with one particular problem?