What are 0-level data flow diagrams?
150617
Level 0 DFD is a one process diagram which summarises the inputs and the outputs of the system under consideration. This is called the context diagram. It contains only a single process linking all the External Entities - no data stores are included at this level.
1187479
The first item listed at the search\n\nhttp://www.google.com/search?q=example+data+flow+design\n\nwas\n\nhttp://www.cems.uwe.ac.uk/~tdrewry/dfds.htm\n\nseemed like a decent starting point.
526760
go to the source - The Art of Computer Programming by Donald Knuth.  It is the bible of data structures.
808315
I havn't done it mysqlf but a good place to start is with the TI-83 SDK and the documentation. The headers and required includes usually have a lot of information on how they can be used and often have a brief tutorial/starter project to build off of.
820522
"Decision control"? I hope, you mean "flow control"... the decisions, hopefully, are still under the programmer's control.\nI hope, you don't expect ALL the flow control structures explained... They are fairly self-explanatory, and there are tons of books  on the subject.\nI'll explain a couple to you here:\n- goto keyword is used to implement non-sequentual execution paths - like conditional statements or loops.\nfor example:\nL1: cin>>s;\n      if cin.eof() goto L2;\n      cout << s;\n      goto L1;\n\n- Long jump is similar to goto, but can be used to implement "jumps" accross code segments. Useful to implement function calls or so called exceptions.\nFor example:\nstring error_message = 0;\nvoid *ret = 0;\nL1: if (!error_message) longjmp (L2);\nabort (error_message);\n...\nL3: cin >> s;\nif cin.bad() goto L4;\ncout<<s;\ngoto L3;\nL4: error_message = "Read error"; \nlongjmp(L1);
735575
Try this one -\nhttp://www.datapigtechnologies.com/
1176200
The Windows Serial Port Programming Handbook\n\nby Laurie Kelly, Ying Bai
206633
I dont know if this will help but try these sites listed...\n\n\nhttp://gcc.gnu.org/\n\nhttp://www.goosee.com/x86/index.html
1002521
.MODEL small\ncr equ 0ah\nlf equ 0dh\nEOSTR equ '$'\n.stack 200h\n\n.data\ne db 'Enter the elements(0 to quit) :: '\n  db cr,lf,eostr\ns db 'The sorted elements are ::   '\n  db cr,lf,eostr\ntemp db 0\ncnt db 0\ntt db 0\nn  db 0\nnum db ?\n\n.code\ngetnum  proc near\n        ;push bx\n        mov temp,0\nscan:\n        mov ah,00h\n        int 16h\n        cmp al,13\n        jz  endscan\n\n        mov ah,0Eh\n        int 10h\n        sub al,30h\n\n        mov cl,al\n        mov al,temp\n        mov ah,0\n        mov bl,10\n        mul bl\n        add al,cl\n        mov temp,al\n        call scan\nendscan:\n        mov ah,0Eh\n        mov al,' '\n        int 10h\n        mov ah,0Eh\n        mov al,' '\n        int 10h\n        mov al,temp\n        ;pop bx\n        ret\ngetnum  endp\n\n\n\ndisp    proc near\n        ;push bx\n        mov bl,100\n        mov ch,1\nshow:\n        cmp bl,0\n        jz enddisp\n        cmp al,0\n        jnz n_zero\n        mov al,'0'\n        mov ah,0Eh\n        int 10h\n        mov al,0\n        jmp skip\nn_zero:\n        cmp ch,0\n        jz calc\n        cmp al,bl\n        jb  skip\ncalc:\n        mov ch,0\n        mov ah,0\n        div bl\n        mov cl,ah\n        add al,30h\n        mov ah,0Eh\n        int 10h\n        mov al,cl\n        jmp skip\nskip:\n        mov temp,al\n        mov al,bl\n        mov ah,0\n        mov bl,10\n        div bl\n        mov bl,al\n        mov al,temp\n        call show\n\nenddisp:\n        mov ah,0Eh\n        mov al,' '\n        int 10h\n        mov ah,0Eh\n        mov al,' '\n        int 10h\n        ;pop bx\n        ret\ndisp    endp\n\n\n\nstart:\n        mov ax,@data\n        mov ds,ax\n        mov dx,offset e\n        mov ah,9h\n        int 21h\n        mov bx,0\nread:\n        push bx\n        call getnum\n        pop bx\n        mov offset num[bx],al\n        inc bx\n        cmp al,0\n        jnz read\n\n        mov ah,0Eh\n        mov al,10\n        int 10h\n        mov ah,0Eh\n        mov al,13\n        int 10h\n\ncount:\n        mov al,offset num[bx]\n        cmp al,0\n        jz endcount\n        inc n\n        inc bx\n        call count\nendcount:\n\nbubble:\n        mov bx,0\nsort:\n        mov al,offset num[bx]\n        mov dl,al\n        mov cx,bx\n        inc bx\n        mov al,offset num[bx]\n        cmp al,0\n        jz endsort\n        cmp dl,al\n        jb n_exch\n        mov tt,al\n        mov al,dl\n        mov offset num[bx],al\n        mov al,tt\n        mov bx,cx\n        mov offset num[bx],al\nn_exch:\n        call sort\nendsort:\n        inc cnt\n        mov al,n\n        cmp al,cnt\n        jnz bubble\n\n        mov dx,offset s\n        mov ah,9h\n        int 21h\n        mov bx,0\nsho_arr:\n        mov al,offset num[bx]\n        cmp al,0\n        jz endpr\n        push bx\n        call disp\n        pop bx\n        inc bx\n        call sho_arr\nendpr:\n        mov ax,4c00h\n        int 21h\n\n        end start
192550
Do you have a description of the actual datapath?   It's probably in the engineering manual for the chip.\n\nIf not, you'll have to design it:  Start with all the visible registers and figure out what is necessary to implement all of the instructions in the instruction set.   For example, if there's an instruction which adds the number in one register to the number in another register and places the result in a 3rd register, that pretty much defines PART of the data path.   You'll need to add to that the operations (complement, shift, subtract, ...) for all the other instructions.\n\nOnce you've done that, it should be pretty straightforward to write a C or C++ program to simulate it.
422073
UML is suited and u can effectively use microsoft visio.net for it :)
209333
no where.  Just the data pointers are deleted.
113769
It's an Entity Relationship diagram. It is a graphical representation of data models and is typically used when designing a database or other information system.
130888
Your question is worded and punctated a little akwardly so I'm not sure how well I can answer your question.  \n\nYou could try Microsoft Visio to draw a diagram, but that would depend on what kind of diagram you needed.  "hierarchy of data" is a little too broad a subject to answer this question effectively. \n\nI lead you to the Microsoft Visio 2003 homepage as my source.  Hopefully you can find what you need there.  Microsoft Visio can build all sorts of diagrams, such as a  networking lab, database relationship diagram, house floor plan, flowchart, electrical diagram, etc.\nIt is also compatibable with Microsoft Access, Visual Studio.NET and SQL Server so you should be able to link your diagram to a database easily.
154865
There is a free version of diagramming software, called "Dia" which is hosted on SourceForge.  If you are using Windows, they do have a Windows download as well.  The site contains the download links, FAQ and documentation if needed.\n\nAlternatively, there is another package (which has a free trial, but is commercial) called "SmartDraw", which can also be used if you only need to temporarily create diagrams.\n\nI've included the links to both below.
487486
#define QUEUE_EMPTY 2\n\n#define TRUE_EMPTY1\n#defineFALSE_EMPTY0\n\ntypedef struct node\n{\nint data;\nstruct node *link;\n} Queue;\n\n\nintDequeue(Queue **front, Queue **rear);\nintEmptyQueue(Queue **q);\n\nint Dequeue (Queue **front, Queue **rear)\n{\nint data;\n\nif (EmptyQueue (front))\n{\nprintf ("Queue Empty!&#92;n");\nexit (QUEUE_EMPTY);\n}\n\ndata = (*front)->data;\nif ((*front)->link == NULL)\n*front = *rear = NULL;\nelse\n*front = (*front)->link;\n\nreturn data;\n\n}\n\nint EmptyQueue (Queue **q)\n{\nif (*q == NULL)\nreturn TRUE_EMPTY;\n\nreturn FALSE_EMPTY;\n}
892614
you can use Siw, it's a system information tool, and free\n\nhttp://www.snapfiles.com/reviews/SIW/siw.html