how do you solve:  find the slope of the line perpendicular to 2x - 7y = 5?
144604
The last answer was close.\n\nYou get y by itself, so you get\n\n7y= -2x + 5 \ny = -2/7x + 5/7\nso the slope of the perpendicular line is the negative reciprocal so it is \n7/2
1065375
5 = 7y - [4 + (3y - 2)]\n5 = 7y - (2 + 3y)\n5 = 4y - 2\n7 = 4y\ny = 7/4
450157
slope = (y2-y1)/(x2-x1)\n5= (k-4)/(2-3)\n5= (k-4)/(-1)\nk-4= (-1)*5\nk-4= -5\nk= 4-5\nso k= -1.\ni hope you understand they way I worked it out. If you have any more questions, pls feel free to ask me on: pinkieflava@yahoo.co.uk
1064341
Remeber that perpendicular lines have negative reciprocal slopes, so the slope of the line you are trying to find is 1/3 (that is the negative reciprocal of -3).  You know that the y intercept is 5, remember that slope intercept form is y = mx + b where m is slope and b is y intercept.  You know both of these things now, the m = 1/3 and the b = 5.  Your equation is y = 1/3x + 5.
218561
A parallel line must have the same slope.\nSo you just need to find slopes of the lines that  you have.\n1) 5y= -4x - 11\ny = -4/5x -11/5\nthe slope m = -4/5\n\n2) 4y= 5x-7\ny= 5/4x -7/4\nthe slope m = 5/4
247531
The general purpose straight line has the equation Y = mX.  If you know the slope (m) to get the equation of a line thru a given point, say (h,k) just substitute the slope for the m, (X-h) for the X, and (Y-k) for the Y.  E.g. a line with slope 2 thru (-5,7) has the equation (Y-7)=2(X+5).  Then do a little algebra to get the slope-intercept form;\nY=2X+17.\n\nIf slope is not given, but instead you have coordinates of two points, find the slope by dividing the difference between the Y coordinates of the points by that between the X coordinates.  It doesn't matter which point you subtract, as long as you do it the same way for both the X and Y coordinates.   Then use that slope with the coordinates of either one of the points as above to get the equation.\n\nIn the example given, you're apparently supposed to find a line thru (5,1) that intercepts the line Y=4X-7.  Any two lines will intercept somewhere, so two quick answers are X=5 or Y=-7!  You can substitute X=5 into the equation to get the point of intersection of the first: (5,13).  OR\n\nA line thru (5,1) parallel to the line y=4X-7 will have the same slope.  So its equation will be (Y-1)=4(X-5) or \nY=4X-19.\n\nA line thru (5,1) and perpendicular to the line y=4X-7 will have a slope that is the negative reciprocal of 4 = -1/4 or -0.25.  So its equation will be (Y-1)=(-0.25)(X-5) which simplifies to Y = -0.25X + 1.25 + 1 or Y = -0.25X + 2.25.\n\nThink about it.  Thinking always helps.  Yahoo won't be there for your tests.
826923
The easiest way to do this would be to put the equations into slope-intercept form and compare the slopes.  If the slopes are the same, the lines are parallel.  If the slopes are the negative reciprocals of each other (like 2/3 and -3/2), they are perpendicular.  If neither, then neither.\n\n3x + 6y = 30\nx + 2y = 10\n2y = -x + 10\ny = (-1/2)x + 5\n\nSlope:  -1/2\n\n4y + 2x = 9\n4y = -2x + 9\ny = (-1/2)x + 9/4\n\nSlope:  -1/2\n\nYour call here.
908156
slope of  6x – 3y=10 is: 6/3=2\nso slope of perpendicular line is: -1/2\nand the equation is:\ny+6 = -1/2 ( x -2) !
171467
They're perpendicular:\n5y+3x=15\n5y=-3x+15\ny=-3/5x+15/5\ny=-3/5x+3\n(y=mx+b)\nm -> slope, so: -3/5 versus -5/3 it's perpendicular
766938
Use the forumula     delta Y/ deltaX to find the slope of the given points\n\n4-2/ 0-4   = -2/4 =  -1/2\n\n\nSince the perpendicular line is the equation  y = -1/2x; the other equation has the slope of the negative reciprocal of -1/2x so the equation would be \n\ny= 2x+b\n\nthen plugin x and y in this equation and you get\n\nb= -4\n\nso the final equation would be y=2x-4\n\n   Thats it
194347
9x-6y+7=0  You change this to\n\n-6y=-9x-7  so it is in y=mx+b form.\n\nNext you divide by -6\n\ny=(9/6)x+(7/6)\n\n7/6 is your y intercept. (1.6666...)\nand 9/6 is your slope.  (1.5)\n\nTo find the x intercept you put 0 in for y\n\n0=(9/6)x+(7/6)\n(-7/6)=(9/6)x\n-7=9x\n-7/9=x\n\n-0.777...=x intercept
141598
If we break down 25x^2, we get 5x.\n\nIf we break down 49y^2, we get 7y.\n\nThe resulting equation is:\n\n(5x + 7y)(5x - 7y)\n\nSolve it from there.
850894
2x-3y=5 ….multiply by 1\n                           x+2y=-l .... multiply by -2\n\n                                       2x-3y=5 \n                                      -2x-4y=2 …..add two equations\n                                      ------------\n                                        -7y= 7\n                                          y=-1\n\n substitute y=-1 in the second equation coz it is easier in order to get the x value\n\nx+2y=-1\nx-2=-1\nx=1\n\nSo the solution is (1,-1)
823070
Get the slopes of the two lines using the formula:\n(y2 - y1)/(x2-x1)\n\nIf the slopes are equal the lines are parallel\nIf the slopes multiply together to give -1 the lines are perpendicular\nIf the slopes do not meet these conditions they are neither\n\nHope this helps!
314638
7\n\ny-2x=5x\n\ny-2x+2x=5x+2x\n\ny=5x+2x\n\ny=7x\n\n7=slope
974393
If you mean parallel to y=2x + 5, then the slope will be 2\n\nSo you need to use:\ny = 2x + b\n\nPlug in your point (-1, 4) and solve for b:\n4 = 2(-1) + b\n4 = -2 + b\nb = 6\n\nSo your line is:\ny = 2x + 6
523552
It's already in slope and y-intercept form...  y = mx + b, so slope (m) = 7, y-int (b) = 0