ok if the problem is y= -5 - 17 I know the slope is -5 but would the y intercept be 17 or -17 and would x=-3.4
102256
the problem simplifies to y=-23 which has a slope of 0 and the y intercept at -23
560706
You need to get the y alone on one side of the equation. Subtract 5x from both sides and you get:\n-3y=-5x-3\nDivide each variable by -3 to get:\ny=(5/3)x+1\nNow you can graph using this equation.\nThe y-intercept is 1 and the slope is 5/3.\nHope this helps.
197787
y = 3/5x+q (q is free to choose) is parallel to y = 3/5x-5\nEach has the same slope: 3/5\ny = -5/3x+r (r is free to choose) is perpendicular to it,\nso its slope is -5/3
306531
First, the slope is (delta y)/(delta X) = (-3)/2) = -3/2\n\nthe y intercept is +6  (interpolating back from \n(6,-3) ,(4,0),(2,3), (0,6)\n\nso the equation is Y=-3/2 X + 6\n\ngo from there and you have your answer.
416338
As halibori says, you can use a graphing calculator and see where the lines cross.   I use a different machine, the one between my ears.   \n\nIf you add the two equations, the +3y in the first cancels the -3y in the second, leaving the equation  4x + x = -8 - 17, or 5x = -25.   This one's easy since the only unknown is x, and we see that x = -5.   Now\nwe can go back to the first equation, plug in the value -5 instead of x, and it becomes\n-20 -3y = -8, or -3y = 12, so we have that y = -4.
64774
Since the slope is higher, the line would be steeper. Y-intercept is still 5. X-intercept would change: the equation y=2x+5 has an x-intercept of -2.5, while the equation y=4x+5 has an x-intercept of -1.25.
753590
Basically, its a straight line going through (1,3), with gradient, m=-3. we have y=mx+c. putting the point (1,3) into here, \n\n3=(-3)(1)+c, so c=6, which is the y-intercept. so the line equation is,\n\ny=-3x + 6, which is a straight line with y-intercept at y=6. the line will be sloping downwards since the gradient (m) is negative. if you plot a few values of x and y which satisfy the equation you can see the line. to check axis intercepts, put y=0 for the x-intercept and x=0 for the y-intercept.
665061
have the equation in slope intercept form except with a greater then or equal to sign or less then or equal to sign\nexample:  Y > Mx + B  then solve it like you would a normal slope intercept equation by solving for x... start by adding or subtracting b to Y and then divide the slope which is Mx from both sides and then you will get your x answer the greater or less then sign will change if the answer is negative it will face the opposite way from which it was if postive answer it won't change....... hope this helps......
897596
If y = -5 + 3,  then y = -2 and the rest is easy, but when you started to solve it, you were working off of y = -5x +3.\n\nIf it is y = -5 + 3, then y = -2 and x = 1.1\n\nIf it is y = -5x +3, then the next step is to either check the original problem for where you misread it or write null set as the answer.  6 does not equal 7 hence the correct values for x and y are not real numbers...
949123
2x + 5y = 15\n\nSo 5y = 15 - 2x\n\nSo y = 3 - 0.4x\n\n3 is the intercept. -0.4 is the slope
272963
The y-intercept is moved to 6 on the y axis from -5.  Also, the slope changes to 5/1 (5 up, 1 right) from 2/1 (2 up, 1 right), creating a sharper increase in the line.
724767
This cannot be done since if it's perpendicular to y = -3, which is a horizontal line, it would be a vertical line and vertical lines have no slope.\n\nPS Its equation would be x = 1
162736
x-y=5\nx/5-y/5=1\nhence x intercept [5,0] and y intercept [0,-5]
925887
Hopefully you know how to solve one part of it. Slope intercept form is Y= M x+B. First find the slope, using 2 set of coordinates, that formula is Y2-Y1 over X2-X1. that will be your M.  Then find your Y intercept. then plug it in to that formula above. I hope i was of some help. Don't put your life on this i did it in the beginning of the school year.  I may have the M and the B switched.
892026
The slope intercept form is y=mx+b\n\nSo we rewrite the equation of the line as so:\n\nx - 2y = 5  , subtract x from both sides\nx - x -2y = 5 - x\n-2y = 5 - x  , now divide both sides by -2\n-2y/-2 = (5 -x)/-2\ny = -5/2 + x/2  , rearrange the left side\ny = x/2 - 5/2\n\nSo the slope (m) is 1/2.  Now we use the point given and the general equation.  From the point we know that x=2 and y=-4.  Sustitute these into the general equation.\n\ny = mx +b\n-4 = (1/2)2 + b  , do the math\n-4 = 2 + b ,subtract 2 from both sides\n-4 - 2 = 2 - 2 +b\n-6 = b\n\nSo the equation of the required line is:\n\ny = x/2 - 6
1105412
Assuming it is a linear interpolation, you can graph the two points, draw a line and then figure out what x = 26 will give you for y...\n\nYou can also do it mathematically by figuring the equation of the line.  You have a rise of 3 (subtract y-coordinates, 7-4) and a run of 20 (subtract x coordinates, 40-20).  So the slope is 3/20.\n\nNext you have to figure out where it will intersect the y-axis.  That's the point where x = 0.  We already know that for every 20 points (in x) there's a change of 3 (in y), so going backwards 20 points, there would be a drop of 3 points.  In other words, going back from (20,4) you get to (0,1).  So the y-intercept is 1.\n\nPutting this into slope-intercept form (y = mx + b) you have:\ny = (3/20)x + 1\n\nDouble check by putting in x = 20 and x = 40, you should get y = 4 and y = 7.\n\nNow just plug in x = 26 and see what you get for y:\ny = (3/20)26 + 1\ny = 78/20 + 1\ny = 3.9 + 1\ny = 4.9\n\nAnd that is your answer using linear interpolation.  For the point 26, you would get 4.9.\n\nAnother way to do it is to just use just the slope.  You know the slope is 3/20.\nFrom 20 to 26 is 6 points.\n6 x 3/20 = 9/10 = 0.9.\n\nThis means that at 26, it will be 0.9 more than at 20.\nSo adding 4 + 0.9 you get 4.9, just like before.\n\nFor the point 26, you would get 4.9.
877049
use the slope formula.\n\ny sub 2 minus y sub 1 divided by x sub 2 minus y sub 1\n\nthen you get 1-5 divided by 0-2\n\nthen you get -4 divided by -2\n\nthe answer is 2