what is the perimeter of a polygon at has 2 sides that each measure18 in. and three sides that equal 24 in.?
114428
seriously? okay: P = 2(18) + 3(24) = 36 + 72 = 108 in
136459
Find the factors of 56 (or all the possible measures of sides that would equal an area of 56). \n2 and 28\n4 and 14\n7 and 8\n\nThen add 2l + 2w to get the perimeters.\n2(2) + 2(28) = 60\n2(4) + 2(14) = 38\n2(7) + 2(8) = 30\n\nSo the least perimeter would be 30 cm.
904266
18x-6=24\n18x=30\nx=30/18\nx=15/9\nx=5/3
354025
the perimeter of a figure is the distance around the edge of the figure.  so in this case, the triangle is 6 in + 8 in + 10in = 24in.
976501
You mean "one less."\n\nCall the base x.\nThen each leg is 2x-1.\nAnd the perimeter is x + (2x-1) + (2x-1), which equals 18.\n\nJust solve for x and you can calculate the lengths of the sides.
47718
So you've got an eight-sided figure and each side is 72-feet.  If you draw horizontal and vertical lines from each vertex (the angles where sides meet) to the other side of the octagon, you'll see that the octagon can be split up into one large square (in the center), four rectangles (up, down, left and right), and four triangles (in the corners).  You following me?  Get out a pencil and get to it!  Okay.  So what are lengths of your square's sides?  You'll note that the square has 72-foot sides, just like the original octagon.  Since you know how to find the area of the square, you're on your way.\n\nNext.  you have four rectangles, each with a length of 72-feet, but the short end - the width, how do we figure out the width of the rectangle?  Okay.  Look at your triangles.  Each triangle has one side of 72 feet - the side which is the outside of the octagon - and then two equal sides - it's an isosceles triangle with a 90-degree angle.\n\nOkay, time to call on pythagoras.  Pythagorean theorem states that a^2 + b^2 = c^2.  What that means is this: If you take the length of sides a and b (the ones we don't know) and square them, and add them together, the answer will be 72-squared (side C).  Too bad I'm not there with you to make this part easier to understand.  We know that a and b are equal in this case because our triangle is isosceles.  Therefore, 2x^2 is equal to 72^2.  This gives us a messy equation wherein our answer is, x is ROUGHLY equal to 51 feet.\n\nSo.  You have a square with sides 72 feet long.  You have 4 rectangles each with length 72 and width 51.  You have 4 triangles each with base 51 feet and height 72 feet.  You know that squares and rectangles have an area equal to length times width, and triangles have an area equal to one-half base times height.\n\nCalculate the area for your 9 figures and add them together.  THAT will be the square footage of your octagon.\n\nWhat... did you think I was going to do it ALL for you?
794439
how many sides does the polygon have u have to find how many side polygon is it then online look up whats that shape total degree like triangle always = to 180 then u would do 108(5) subtract from the total degree of polygon
884011
The sum of the measures of the EXTERIOR angles is always 360.  So subtract 162 from 180 to get an exterior angle (18) then divide 360 by 18 to see how many sides.
467774
The area of the regular hexagon is given by:\n\nA = 2.598 s^2\n\nSo if the sides are 12 inches each;\n\nA = 2.598 (12 in)^2\n\nA = 374 in^2
636579
Okay, I got something really different, but it might be wrong, I used tangents and stuff to figure it out, and I assumed a dodecagon had 12 sides, but I might be wrong. Anyways, I got 38.4 for the perimeter, and 115.2 for the area.
688339
Let's say w is the width of the rectangle.  Then, the length will be w+5.  We know the perimeter is 58, and we know that the rectangle has two sides of length w, and two sides of length (w+5).  So...\n\n2w + 2(w+5)=58\n2w + 2w + 10 = 58\n4w + 10 = 58\n4w = 58 - 10\nw = (58-10)/4\nw=48/4\nw=12, the width of the rectangle.\n\nSince the length=w+5, the length is 17.
411731
The perimeter might be 14.0625. \n3+4+5+6+7 = 25 and the pentagons are similar. It is just a matter of proportions. \n(the perimeter of given)/ (perimeter you r tryin to find) = (area of given)/ (area given for the second pentagon)\n\nso in numbers it is (25/x)=(48/27) and you just solve for x because the pentagons are similiar.
724177
B)48\n\nFirst of all, you can quickly eliminate choices A and C because the number of tiles (or area of the rectangle) has to be greater than or equal to the perimeter.  Then just use guess and check to see what dimensions give you a perimeter of 38 and an area of 48 or 52.  You'll come up with 3 x 16.
283369
The perimeter of the square is 50 units\n\nThere are 5 rectangles that means the ratio of length to width has to be 5 to 1\nTherefore since each rectangle has a 5 to 1 ratio and a perimeter of 30 they are all 12.5 units by 2.5 units. (12.5 x 2 is 25, 2.5 x 2 is 5, 25 + 5 = 30)\nThe length of each side of the square is 12.5. 12.5 x 4 is 50 units
975962
Let n be the length of one of the equal sides.\nLet n + 3 be the length of the third side.\n\nThe sides are n, n and n + 3 respectively.\n\nn + n + (n + 3) = 27\n3n + 3 = 27\n3n = 24\nn = 8\n\nSo the sides are 8 cm, 8 cm and 11 cm respectively, for a total perimeter of 27 cm.
766258
The length of the wire must be (2x5)+(2x7)=24cm.  So each side of the triangle must be 24/3=8cm. long.
875314
Fisrt divide the regular octagon into 8 isosceles triangle. The resulting vertex angle would be 45 deg.\nDivide the isoscles into congruent right triangles with an angle of 22.5 deg, 67.5 deg and 90 deg.\nThe length of the sides opposite 22.5 deg would b equal to\nhypotenuse (radius of the circle) times sin 22.5 deg.l\nThat would be 6.046398231 cm.\nDoubling this value would result to the side of the octagon,\nand that is 12.09279646.\nMultiplying the side by 8, we get the final answer or the perimeter of the regular octagon inscribed in the circle.\nthe answer is\n96.7423717 cm.\n\nYou my use this formula for any regular octagon inscribed in a circle with radius x.\nP = 16x sine 22.5\nContact me if this is wrong.