translate into an algebraic equation . Let x represent the number 4 times the sum of twice a number and 1 is 3
114500
the way u phrased that doesnt necessarily make sense. x= 2n+1 is 3   ....something along those lines. your wording confused me...my name is my messenegr msg me there and i can try and help
1062413
Okay, it says 'product' first so you know you're going to be multiplying something.\n\n"3 less than twice of x"\nWhat's twice of x? 2x\nWhat's three less than that? 2x - 3\n\nI'm not sure what you mean when you say "2 more than the quantity times x" because are you referring to (2x - 3) as the quantity, or the quantity of x?\n\nWell, if you mean the quantity is 2x - 3...\nthen 2 more than that is just (2x - 3) + 2 = 2x - 1\nYour product would be (2x - 3)(2x - 1) = 4x^2 - 8x + 3\n\nIf you mean the quantity of x...\nthen two more than that is just 2 + x\nYour product would be (2x - 3)(x + 2) = 2x^2 + x - 6\n\nI hope this helps.
985294
you just keep on deriving.\n\nI find it easier to split things into exponents.\n\nI am assuming your question goes\n\n(1/(2x))  - 4 = g(x)\nor\n\n(1/2)*x^-1     - 4 = g(x)\n\ndifferentiate once\n\ng'(x) = -(1/2) * x^-2 \ng''(x) = -2 * (-1/2) * x^-3  = x^-3\ng'''(x) = -3 * x^-4  =  -3/(x^-4)  **ans**\n\nPlug 3 into this... bah\n\nFor reference please use parenthesis to make your problem clearer for us. I just solved the whole thing using the wrong g(x).\n\n\n===!using the correct g(x) which should be g(x) =1 / (2x -4)===\n\ng(x) = 1 / (2x -4) = (2x - 4)^-1  don't forget the chain rule\n\ng'(x) = -1*2*(2x - 4)^-2 = -2 * (2x -4)^-2    chain rule again\n\ng''(x) = -2*-2*2*(2x -4)^-3 = 8*(2x -4)^-3    chain rule again\n\ng'''(x) = -3*2*8(2x - 4)^-4 = -48 * (2x -4)^-4\n\ng'''(x) = -48/[(2x -4)^4]\ng'''(3) = -48 * (6 -4)^-4 = -48/ (2^4) = -48/16   = ***real ans***\n\ng'''(3) = -3
1142915
The equation would look like:\n9 * (2X - 3) = X - 4 so \n18X - 27 = X - 4\n17X - 27 = -4\n17X = 23\nX = 23/17\nX = 1.35
771358
3x + 4 < x + 8\n2x < 4\nx < 2\n\n{x | x < 2}
1123152
let 1st no. be x\n......2nd.....be x+2 <--becuz its even no.\n......3rd......be x+4 <-- same reason\n\n2((x+2)+(x+4)) = 3x + 34\n2(2x + 6) = 3x + 34\n4x + 12 = 3x + 34\nx = 34 - 12\ntherefore, \nx = 22\n\nso 1st number is 22,\n2nd is 22 + 2 = 24\n3rd is 22 + 4 = 26\n\n=)
597439
=[(4+3x)/x] + (2/3)[(5+3x)/x]\n=[(4+3x)/x] + [(10+6x)/3x]\n=[(12+9x+10x+6x)/3x]\n=[(15x+22)/3x]
703525
when you write an equation, all you have to do is, put "n" in for the number or "a number" which you don't know.  So the sum of 8 times(multiplied by) "a number(N)" and(plus) 7 is(equals) twice(two times) "the number"(N)\n\n8xN+7=2xN
508029
The equation is:\n(x+a+b+c)^2 = 2x^2+(x+a)^2-(x+b)^2-(x+c)^2\nA simple rearrangement yields\n(x+a+b+c)^2 - x^2 = (x+a)^2-(x+b)^2 + x^2-(x+c)^2\nFactorize using the identity a^2-b^2=(a+b)(a-b)\n(x+a+b+c+x)(x+a+b+c-x) = (x+a+x+b)(x+a-x-b) + (x+x+c)(x-x-c)\nwhich can be written as\n(2x+a+b+c)(a+b+c) = (2x+a+b)(a-b)-c(2x+c)\n==> 2x(a+b+c)+(a+b+c)^2 = 2x(a-b)+(a-b)(a+b)-2xc-c^2\n==> 2x(a+b+c-a+b+c) = (a+b+c)^2 + a^2-b^2-c^2\n==> 4x(b+c) = a^2+b^2+c^2+2ab+2bc+2ca+a^2-b^2-c^2\n            = 2(a^2+ab+bc+ca) = 2(a+b)(c+a)\n==> x = (a+b)(c+a)/[2*(b+c)]
151739
algebra is the solution of equations like the above.  Let the "what" be expressed as w.  Then the question becomes\n\n  w * 3 = 4/3\n\nNow how do we solve this for w.  The trick is to operate on both sides of the equation the same function.  The caveat is that the function applied must have an inverse.  In this case multiply both sides by (1/3).\n\n(1/3)*3*w = (1/3)*(4/3)\n\nNow since 1/3 is multiplicative inverse of 3, the result is 1, and since 1 is the multiplicative identity, the result of the left hand side is w.  For the right hand side just do the multiplication\n\nw = 4/9\n\nThus 4/9 multiplied by 3 equals 4/3.
1081174
I assume the equation is:\n\n4/(x+3) = 6/(4-x)\n\nFirst cross multiply (denominator on left to numerator on right and denominator right to numerator on left) \n\n4(4-x) = 6(x+3)\n16-4x = 6x+18\n\nCombine like terms, x's on one side, numbers on the other\n\n16-18 = 6x+4x\n-2 = 10x\n\nDivide both sides by 10 to isolate the x\n\n-2/10 = 10x/10\n-2/10 = x\n-1/5  = x\n\nThat's it!  Have fun!
1063248
To solve correctly, distribute two to x and -2, add four to both sides, and divide both sides by x:\n\n2(x - 2) = x + 3\n2x - 4 = x + 3\n2x = x + 7\nx = 7\n\nThe error that was made was trying to simply remove the parentheses instead of actually distributing 2 to both of its contents.\n\n-----\n\nIf this is not what you meant and I have read it backwards, this is the other interpretation:\n\n-----\n\nTo solve correctly, add two to both sides, then divide both sides by x:\n\n2x - 2 = x + 3\n2x = x + 5\nx = 5\n\nThe error that was made was trying to change 2x [2 times x] into 2(x - 2) [2 times the difference of x and 2]. This is not allowed.
1009395
4x + (x + 2) ....... 4x + 2 is 4 times a number plus 2 and it's incorrect
433833
the answer to your question is x=3(4,6)
598932
Replace y in the first expression by the value from the second.  You get:\n8x - 4(2x - 4) = 16\n\nNow simplify:\n8x - 4*2x - 4*-4 = 16\nthat's four times minus four...\n8x - 8x - -16 =16\n16 = 16\nThis holds for any value of x.\nThis has occurred because the two expressions are the same!\nIf you divide the first expression by 4, you get:\n2x - y = 4\nnow make y the subject (add y to both sides, then take 4..)\n2x - 4 = y\n\nIf you were to substitute your solution into the second expression, you would have:\n-1 = 2*3 - 4   clearly this is not a solution...\n\nIf x were 3 then y would be 2*3-4 = 2\n\nI hope the explanation above is of some use!
605879
(x+3)(x+12)(x+2)(x+8)= [(x+3)(x+8)][(x+12)(x+2)]\n                     = (x^2+11x+24)*(x^2+14x+24)\nlet t=x^2+24+(25X)&#92;2 . \nSo we have: x^2+11x+24=t-(3x)&#92;2 and x^2+14x+24=t+(3x)&#92;2                                 \nso the equation becomes: [t-(3x)&#92;2][t+(3x)&#92;2] = 4x^2\n                    <-->t^2-(9x^2)&#92;4=4x^2  \n                    <-->t^2=(25x^2)&#92;4\n                    <-->t=(5x)&#92;2 or t=-(5x)&#92;2\n                    <-->x^2+10x+24=0 or x^2+15x+24=0\ncontinue by yourself
665603
you put (x+2) in for x in the equation first\n\n((x+2)^3)+(2(x+2)^2)-4\n\nthen simplify \n\nx^3 + 8x^2 + 20x + 12\n\nand multiply the entire thing by 3\n\n3(x^3 + 8x^2 + 20x + 12)\n\n3x^3 + 24x^2 + 60x + 36