Why do halogenoalkanes have higher density than alkanes?
114220
bcoz halogens ave a very high charge density and when u add dis 2 an alkene which has a set charge density it will increase, so it will b higher den a alkene
830546
The halogens can be found in column 17 of the Periodic Table.  They are called Group VII because they all have 7 electrons in their outer orbitals.\n\nThe lighter ones (Fluorine & Chlorine) are gases at room temperature.  Bromine is a liquid, while Iodine & Astatine are solids.  All tend to rapidly react by gaining an electron (they are good oxidizers).\n\nThe noble gases can be found in column 18 of the Periodic Table.  They are called Group VIII because they all have 8 electrons in their outer orbitals.\n\nHaving full outer orbitals, the noble gases usually do not react with other elements.  This is why they are sometimes called the Inert Gases.  Several compounds of Xenon and Fluorine and Oxygen have been make and studies, however.
484846
1. The freezing point of water and gasoline can be compared in terms of their intermolecular forces. The stronger the intermolecular forces of a substance, the higher the freezing point (as more energy is required to overcome those forces). Water has a low molecular weight and so has weak dispersion forces. Gasoline consists of long chained hydrocarbons with high molecular weights and so would have much stronger dispersion forces than water. Even though water has strong hydrogen bonding, the overall intermolecular forces in gasoline would be much stronger and so it would have a lower freezing point, that is, less than 0 degrees celsius. \n\n2. Freezing and melting are opposite processes. So if water freezes at 0 degrees celsius, then it must melt at 0 degrees celsius.
420827
high density - at least compared to air. this is why anything sinks in a fluid; rocks are higher in density than water or air so they sink, helium balloons are lower density than air so they float.
903371
I have a serious feeling that you haven't given us all the info.\nIf you know the density of HCl you can get the first one.\nBut we don't have enough info to even begin to tell you the relevance of the NaOH.   More info, or concentrate on your own homework...
97857
Yeah, it's the greatest electronegativity difference between the two atoms that are forming that bond.  In other words, it's the difference between how far away the two elements are from fluorine, the most electronegative element.  Diatomic molecules like Cl2 are very nonpolar because both Cl atoms are equidistant from fluorine, and HBr is more polar because Br is closer to fluorine than hydrogen.
134491
if you look at the sequence methane ethane propane butane pentane hexane heptane ... it goes from gas to liquid, as the molecules go heavier. now ethanol is lighter than hexane, so it is no wonder that somewhere there must be a point where alkanes have a lower boiling point than ethanol. exactly where is difficult to calculate from first principles but it must be somewhere. so why not at heptane.
1015522
Primarily volatility.  The shorter the alkane chain, the more volatile the compound.  Think of it as a distillation of a very complex mixture.  Isomerization of alkanes with similar volatilities is why petroleum "fractions" like gasoline will contain many different compounds.
376102
The Halogens are very, very reactive chemicals, and tend to hook up and form salts with the other elements rather than hanging around in a pure elemental form.  They tend to pick up extra charge very well which makes them prime candidates for bonding.
858619
The easiest way to approach problems like these, my friend, is to look at your alkyl halide first and then look at your nucleophile or base.\n\nT-butyl bromide is a tertiary halide.  Tertiary halides undergo E1 and SN1 reactions because of their ability to form a stable carbocation intermediate.  If you recall, tertiary carbocations are more stable than primary and secondary.\n\nYour -OCH3 is a strong base known as methoxide, the conjugate base of methanol.  Strong bases favor elimination reactions and thus the elimination product is your answer.
445447
1-chloropropane, because chlorine has a higher value of electronegativity.
463321
Alkanes have a C-C single sigma bond which is very strong and has a high bond dissociation energy to be broken. For this reason, alkanes only undergo free radical substitution reactions i.e they are only capable of substituting one or more of their H atoms with another atom, but they cannot undergo a complete change of structure, making them relatively inert as compared to alkenes.
998521
that is wrong!!!!\nthe values should have been the other way round!\nnow look:since ethane is a parafin we cannot discuss its prop\ncome to acetone. the central carbon is double bonded to an oxygen atom\nnow when an electrophile comes to this oxygen the bond attains polar character wth the oxygen having partial negative charge(grearter electronegativity), and the carbon having partial positive charge\nnow obviously the electrophile will go towards this oxygen atom, showin its basic character\nlook at the other way(the one described above)\nwhen the oxygen atom reduces the electron cloud density, the carbon atom is more strogly attached to the hydrogens which means that it cannot be released easily which once agains shows its basic character\nhence the values should have been the othr way round
244326
Saturated means that all the Carbon-Hydrogen bonds are 'single' bonds.  Thus, the previously double and triple bonded carbon-hydrogen atoms cannot not take anymore H atoms...they are saturated with them!\n\nStructure is very simple. They are pretty much straight floppy chains.  Think of a shoelace flopping around.\n\nSaturated hydrocarbons are in the 'ane' family of names.  Pentane, Octane, Butane, etc.\n\nProperties:  One great property is that they flop around a lot.  This makes them pass through tight spaces easier, and contribute to clogging far less than unsaturated hydrocarbons (double and triple bonds are rigid, and thus not floppy).  This floppyness is especially important for arteries.  Eat more unsaturated hydrocarbons (fats), get more clogged arteries.  Eat saturated (floppy), and they don't get stuck.\n\nUses:  One use is gasoline (Octane).  Straight-chain (saturated) burns more efficiently.\n\nHope this helps.
316023
intermolecular polarity and the fact that fluids dont compress the way gases do?
359119
look at column 7.  all of the densities appear there in grams/cm3.\n\nhttp://www.science.co.il/PTelements.asp
879801
Pentane\n\nIt depends on which compound has the strongest intermolecular forces. In the case of hydrocarbons the intermolecular forces that are present are dispersion forces.\nIn such cases:\n"The more branched a molecule is, the more "spherical" it is, and the smaller surface area it will have - since dispersion forces increase with surface area, the more branched molecules will have a lower boiling point. You may notice that the trend in the melting points is rather different - this is because the longer a branch is, the more potential it has to flop around and disrupt the regular crystalline lattice of frozen pentane, giving a liquid state."