how do i do heat loads for a reboiler?
108765
hi there,\nits like, you need to know the temp and the mass flow rate of the bottom product of the distillation column. also you need to know the boiling point of the bottom product. the mass flow rate depends on your design calculation. temp of the bottom product you should already know. and boiling point of the bottom product is readily availble.\n\nnow use m.cp.dt to find heat required to raise the temp of the product to its boiling point. where cp is the specific heat capacity of the bottom product and is available in handbooks or sometimes expressed as functions of temperature itself. and dt stands for differnce of boiling point of bottom product and the current temp of the bottom product.call this value as h1 (say).\n\nnow you know the latent heat of vapourisation of the bottom product again refer to data handbooks for the values. multiply this by the mass flow rate. and this is the heat required to vapourise the bottoms. lets call this h2 (say)\n\nnow h1+h2, gives you the heat load for the reboiler. use this heat load to calculate the steam requirement etc...\nyou can mail me sanjaykumar_16@yahoo.com for any clarifications.
686769
Heat it with a torch and bend it back.
243301
Reinstall the burner's drivers, also check for an update at a website for the company that made the burner
848677
I am a HVAC trainer in the USA, and as such I have to explain how to calculate what amounts of energy it takes to do a certain heating jobs.  Looking at your question, I am of the impression that you are asking how much energy it takes to bring the temperature of 100 gallons of water from 74deg F to 90deg F.  I will explain  how to do this calculation, plus ask and answer a question that I feel might be more appropriate to an application. \n\nMost HVAC technicians define a BTU as the amount of heat energy it takes to raise one pound of water one degree Fahrenheit.  Tables will state that there are approximately 8.34 pounds of water in one gallon of water.  Taking this information, we can calculate that there are 834 pounds of water in 100 gallons of water (100 * 8.34 = 834).   So, if we raised 100 gallons of water 1deg F, we will have put 834 BTU’s into that water.  The temperature difference you talk about is equal to the difference between 74deg and 90deg which is 16deg F (90 – 74 = 16).  If one degree requires 834 BTU’s, then 16 degrees will require 16 times that amount, or 13,344 BTU’s (834 * 16 = 13,344).\n\nNow for the real issue, if you have a flow of water entering the slab at 90deg F, and it comes out of the slab at 76deg F, and if the flow rate is …… lets say 8 gallons per minute, than how much energy is the water putting into the slab?  To answer this, we use the same concept as above except we figure the flow rate in pounds per hour and multiply that times the temperature difference.  The process goes like this: (8 gallons per minute) * (8.34 pounds per gallon) * (60 minutes per hour) = 4003.2 pounds per hour.  Now multiply the pounds per hour flow rate times the temperature difference, and we get the energy going into the slab (4003.2 * 16 = 64051.2 BTU’s per hour).  So, the heat pump would have to have a capacity of a little over 5 tons (1 ton is 12,000 BTU per hour) to meet that load. \n\nNow, the energy one puts into a slab should be based on the heat loss of the structure.  It might be that you only have to put 18,000 BTU’s into the slab to offset the heat loss.  The flow rate and temperature difference can be adjusted based on the heat loss.
1032301
Fan, then chicken wire, then hay, then chicken wire.\nMake the hay and wire the same size square as the fan.\nThe hay should be about 6" thick.\nPlastic pipe with 3/64 holes every 6" across the top of the hay.\nConnect a hose to 1 end and cap the other.\nTurn on water little by little until you get a trickle from the holes.\nTurn on the fan.\nSwamp cooler!
109915
switch from heat to ice back and forth
587092
Insulate the rod with a good insulator. (Styrofoam for instance). Get a source of measured heat.(electric heater with known wattage).Get two temperature measuring instruments.(  cu-constantan thermocouples).Get a stop watch.Measure the cross sectional area of the rod by appropriate scales.Measure the length of the rod.\n\nUse the equation: Q=k*(T1-T2)/dt, where\nQ=Btu, T=temperature at one end of the rod, t=time\n\nbe careful with the units.\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\nElectric
774220
Go to go ogle web site and type Heat Transfer u will get abundant information about the process OK babe bye.
1118263
yup yup. just put your hand blocking the bolt from fully recocking but let it recock close to full. this will stop the sear from catching the bolt assembly and it will go full auto or just jam the sear down
470685
You must calculate difference of enthalpy between first and second condition.  Enthalpy depends on  temperature and pressure.And it can be find from thermodynamic tables.\n\nI accept 1 bar for water's pressure \n\n1 bar and 20 degree water's enthalpy = 84 kj/kg \n1 bar and 55 degree water's enthalpy = 104,725 kj/kg \n\ndifferent between inlet enthalpy and outlet enthalpy = 104,725-84 = 20 kj / kg (this heat necessary to increase of 1 kg water's degree from 20 C to 55 C ) \n\namount of water = 6000 lt = 6 m3\nspecific density of water which is at 20 C and 1 bar = 0,0010017 m3/kg\nmass of water = 6 / 0,0010017 = 5990 kg \n\ntotal heat requirement = 5990 kg x 20 kj/kg = 119800 kj \n\nXXX if this proses time is 1 hour then \n\npower or capacity of boiler for perfect situation ( perfect situation = no losses and boiler effiency 100 %) = 119800 / 3600 second = 33,2 kw \nif boiler effiency = 85 % then \nreal capacity of boiler for proces time is 1 hour = 33,2 x (100/ 85) = 39,05 kw \n\nXXX if this proses time is a half hour then \n\npower or capacity of boiler for perfect situation ( perfect situation = no losses and boiler effiency 100 %) = 119800 / 1800 second = 66,55 kw \nif boiler effiency = 85 % then \nreal capacity of boiler for proces time is 1 hour = 66,55 x (100/ 85) = 78,3 kw \n\nif you want to calculate capacity of boiler ,  first you must know proses time and pressure.
101358
I think the only pratical way ot do this will be to distill the kerosene.\n\nBut be aware that you are probably breaking the law by doing so. The colouration is added to make it comply with safety laws.
341747
first vapour it all if there is no rubber monomer vaporize then try a distilation tower with hysys if u want i can simulate it for u?
810269
You don't.  You use a Dutch oven.  First, dig a pit about twice the size of your oven and twice as deep.  Line it with good stone or brick - firebrick if you plan on doing this with any frequency.  Then build a fire in your pit using well-seasoned hardwood like oak, walnut, cherry or pecan.  When you have a good heap of coals, scoop out all but about an inch of coals and place your Dutch oven with the turkey inside in the pit.  Shovel coals back inside, around the Dutch oven, which of course should have the lid on.  Then place a cover over the pit, which will not rest directly on the Dutch oven lid.  Cover that with a layer of dirt to seal the whole thing.  Then go do other things for about five hours.  Come back, carefully uncover the cooking pit, lift out the Dutch oven and check to see whether the turkey is done.  It should, if you've done all that I told you to, be done to perfection.  But ya know what - I had to experiment a couple times before I got it right, so if this is your first time, be sure you have a "plan B" if the turkey has to go back in the Dutch oven and back into the pit for awhile longer.  Heh - my "plan B" was to serve dessert first!  Hey, it worked...just don't forget to make sure there're still plenty of hot coals if it does have to go back in the pit a bit longer...and let it sit another hour before checking again.  Good luck!
672653
Use a moist heating pad.
881168
Use the fire to heat water in a container to boiling. Pipe it to a steam driven compressor to compress refrigerent to cool the ice chest. Don't forget the condenser, evaporator and expansion valve.
914327
A fired heater will probably be the cheapest way.  You could try electric heaters (you can buy the elements from water heaters at appliance repair shops - they use 240V), but the electricity cost will probably be more than for the fuel (if you were thinking gas/petrol, maybe propane or natural gas will be cheaper).  I also don't know if I'd be comfortable putting electric elements in 3500 gallons of biodiesel - I've seen a few kitchen fires, and burning oil is never pleasant.\n\nYou could also consider solar heating - it would be cheaper in the long run, but any efficient installation would have to involve heating panels, piping, pumps, and a lot of water.  You could try painting your tank black, but that probably won't work very well unless you live in the desert or high plains.
266808
Create an electromagnet by coiling the wire around the steel rod and attatching the wire to the power supply (put the ammeter in the circuit somewhere (in series). Use the retort stands to hold the weighing scales above the electromagnet. Place the 6 magnets in the weighing scale whilie the power supply is off. See what the weight of the magnets is. switch the power on and see whether there is any change in the weight. try repeating this a few times using different currents (measured on the ammeter). 100grams=approx 1Newton of force