Under what conditions does the AFN equation gives satisfactory predictions?
103485
How would the following items affect the AFN? \n\n    * Higher dividend payout ratio?\n          o Increase AFN: Less retained earnings.\n    * Higher profit margin?\n          o Decrease AFN: Higher profits, more retained earnings.\n    * Higher capital intensity ratio?\n          o Increase AFN: Need more assets for given sales.\n    * Pay suppliers in 60 days, rather than 30 days?\n          o Decrease AFN: Trade creditors supply more capital (i.e., L*/S0 increases).
501994
http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/posfe.html#c3\n\nThe link above may be of some help. Input the values you want or need.
152635
You program the data in to a calculator (like a TI-83), graph, and model the data points using an exponential profile.  It will then give you the form of the equation that best fits your data points in the form of a*e^(b*x), which you can then graph over your data points.  In your case, "b" should be negative to indicate decay.
437661
This requires the use of doppler shift formula for a moving source and stationary observer:\n\nf = f0 ( v / ( v + u ) )\n\nf0 = actual frequency = 5\nv = speed of wave = 20\nu = relative velocity of source away from observer = -10\n(since travelling toward)\n\nf = observed frequency = 10 Hz\n\nNow velocity = v = fl = frequency * wavelength\n\nso wavlength l = v / f = 20 / 10 = 2m
1074016
Detailed information as well as equations are available on the following page : \n\nhttp://www.jwave.vt.edu/crcd/kriz/modules/module06/formulation/edge_formulation.html
243814
although the equation is not complete and therefore the full answer can not be given. i believe this equation will need to be differentiated using the product of a product rule.
671842
Lamda = h/p\ntherefore p = h/lamda\nnow lamda = c/n (n= frequency) and (c = velocity of light   as photons travel at the speed of light)\ntherefore p = hn/c.\nAll conditions satisfied without the use of mass
144611
You might find this paper useful\nhttp://arxiv.org/abs/math-ph/0106027
731401
Correct.\nD. when delta G is positive the reaction is non-spontaneous
882001
Your equation f=wl/c is wrong. It should be f*wl = c. In that case\nf'*wl' =  f(1 + (v cos theta/c)) *  wl(1- (v cos theta/c)) = \nf * wl * (1 - (v cos theta/c)^2) = f * wl = c\nas long as v/c is much smaller than 1
129909
You might find the following informative:\nhttp://www2.mtroyal.ab.ca/~igilborn/admn1382/regression/theory/part_b.htm
880998
aff. means positive, of course it works.  once in effect it is permanent unless clearly stated differently
962180
http://www.mcponline.org/cgi/content/abstract/3/4/327
766444
time to the minus one.\n\nDo a dimensional analaysis on a rate equation to confirm this.
586314
ñ = n - iκ\n\nHere, n is the refractive index indicating the phase velocity as above, while κ is called the extinction coefficient, which indicates the amount of absorption loss when the electromagnetic wave propagates through the material. Both n and κ are dependent on the frequency (wavelength).
1138290
Look up stuff like Arrhenius equations. I don't have my phys chem text book to hand.\n\nFor part two, I think it's D, as I'm fairly certain it's not any of the others.
1125729
The index-of-reaction equation (i.r.e.): dF/dtZ = kZ(l - βF)m is compared with a generalized Prout-Tompkins equation (g.P.T.e.): dF/dt = kn(l - βF)y With the boundary condition F = 0, t = 0 the equations are equivalent for z = 2 or m = 0 or β ≤ 1 and the i.r.e, is closely approximated by the g.P.T.e. for other values of the parameters by use of the following approximation ∫(1- F)-m dF ≈ AF(1-BF)5 The parameter s is a function of m. Both A and B are close to unity for 1/3 < m < 3. The i.r.e. is recommended as being more useful than the g.P.T.e. because the i.r.e. has a better theoretical basis and because it is more readily integrated and fitted to experimental data.