Plant cell diagram-I can't find the chromosomes-labled.?
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I jsut did the same project with my 13 year old son.\nThis is what we used\n\nhttp://www.enchantedlearning.com/subjects/plants/cell/anatomy.GIF\n\nwe had to make a model
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One way I remembered was to draw a picture and label the parts of the cell.  I would draw a new picture over and over again until I could do it without looking for help anymore.\n\nThis website is good.  It gives you the information then it tests you on it:  http://teachertech.rice.edu/Participants/dawsonm/cells/partsframw.htm
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i did this, i used a ball of styrofome( er however you spell that) for the whole cell, and a smaller ball for the nucleus. then i just found a buncha little things for everything else. i used toothpicks with little tags on the end to label the parts
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Let's assume you want a human example.\nHuman cells have 46 chromosomes.\n\nIn Meiosis 1:\nProphase 1- chromosomes replicate, join with homologous pairs to become tetrads.\n--46 chromosomes paired, 23 tetrads, and 92 chromatids\nMetaphase 1- same numbers as prophase\nAnaphase 1: 46 chromosomes (double stranded), 92 chromatids\nTelophase 1: end: 23 chromosomes (double stranded), 46 chromatids per cell\n\nProphase 2: same as Telophase 1\nMetaphase 2: same as Telophase 1\nAnaphase 2: 46 chromosomes, zero chromatids\nTelophase 2: end: 23 chromosomes per cell.
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I don't like your teacher.  I think he/she is looking for B. genes, but then he/she should not have put chromosomes as an alternative choice.  Mendel's theory of independent assortment was only true because the genes he studied were on separate chromosomes.  It could be argued that what he was actually studying was chromosomal inheritance.
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Karyotype\n,\n\n Karyogram of human male using Giemsa staining.A karyotype is a standardized arrangement of all the chromosomes of a cell. In normal diploid organisms, autosomal chromosomes are present in two identical copies, although polyploid cells have multiple copies of chromosomes and haploid cells have single copies. The chromosomes are arranged and displayed (often on a photo) in a standard format known as an idiogram: in pairs, ordered by size and position of centromere for chromosomes of the same size. Karyotypes are used to study chromosomal aberrations, and may be used to determine other macroscopically visible aspects of an individual's genotype, such as sex. In order to be able to see the chromosomes and determine their size and internal pattern, they are chemically labelled with a dye ("stained"). The pattern of individual chromosomes is called chromosome banding, whereas the study of whole sets of chromosomes is known as karyology.\n\nNormal human karyotypes contain 22 pairs of autosomal chromosomes and one pair of sex chromosomes. Normal karyotypes for women contain two X chromosomes and are denoted 46,XX; men have both an X and a Y chromosome denoted 46,XY. However, some individuals have other karyotypes with added or missing sex chromosomes, including 47,XYY, 47,XXY, 47,XXX and 45,X. The karyotype 45,Y does not occur, as an embryo without an X chromosome cannot survive.
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cell wall yes.  chloroplasts no.  cytoplasm in both   i am positive.
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http://www.seedbiology.de/structure.asp
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In prophase, the cromatids have condensed into chromosomes, sister cromatids joined together at the centrmere (the structure looks like an X).  These chromosomes can be seen with a light microscope as well.  So, if you see X-shaped chromosomes that aren't lined up in any order, the cell is in prophase.\n\nIn metaphase, the chromosomes line up at the equatorial plane of the cell still in the X-shaped chromosome form.  \n\nIn anaphase, the sister chromatids separate at the centromere and start heading towards opposite poles of the cell.  The DNA is in bundled chromatid form.
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As there are many species of cacti, chromosome number may vary. An article I found suggests that many cacti have a chromosome number of 22.\n\nPDF] Números cromosomáticos para las Cactaceae del ParaguayFile Format: PDF/Adobe Acrobat - View as HTML\nChromosome numbers and polyploidy in certain. Cactaceae. Cactus and Succulent Jour., 25 (5):141-143. • (2n=22) Lambrou, M. & W. Till. 1993. ...\nwww.ub.es/botanica/cromopar/citogenetica.pdf -
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http://images.search.yahoo.com/search/images?p=meiosis&fr=FP-tab-img-t&toggle=1&cop=&ei=UTF-8
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(m)\n\nCloning of Plant Cells and Manipulation of Plant Genes\nPlant cells exhibit a variety of characteristics that distinguish them from animal cells. These characteristics include the presence of a large central vacuole and a cell wall, and the absence of entioles, which play a role in mitosis, meiosis, and cell division. Along with these physical differences, another factor distinguishes plant cells from animal cells, which is of great significance to the scientist interested in biotechnology: Many varieties of full-grown adult plants can regenerate from single, modified plant cells called protoplasts - plant cells whose cell walls have been removed by enzymatic digestion. More specifically, when some species of plant cells are subjected to the removal of the cell wall by enzymatic treatment, they respond by synthesizing a new cell wall and eventually undergoing a series of cell divisions and developmental processes that result in the formation of a new adult plant. That adult plant can be said to have been cloned from a single cell of a parent plant. \nPlants that can be cloned with relative ease include carrots, tomatoes, potatoes, petunias, and cabbage, to name only a few. The capability to grow a whole plant from a single cell means that researchers can engage in the genetic manipulation of the cell, let the cell develop into a completely mature plant, and examine the whole spectrum of physical and growth effects of the genetic manipulation within a relatively short period of time. Such a process is far more straightforward than the parallel process in animal cells, which cannot be cloned into full-grown adults. Therefore, the results of any genetic manipulation are usually easier to examine in plants than in animals.
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First, note the word "true-breeding".  That indicates each plant is homozygous for all those traits, which means that you don't have to worry about that plant being het for any of those genes.  And it means that they only make a single kind of gamete with regard to thsoe 4 genes.\n\nTechnically, these loci might all be linked to each other, you would need F2 data to know for sure.  But you are supposed to assume that four traits are controlled by 4 genes.\n\nNow, since the parents were homozygous for all their genotypes, the offspring will all be identical, they will all be het for those genotypes.  And which ever phenotype they are, that's the dominant one for that trait.  So purple, green, terminal, and yellow are the dominant phenotypes.\n\nAnd there are 16 different gametes to be made, because there are 4 genes (presumably) and each is het in the F1.\n\nThe only way for an F2 to show all 4 recessive phenotypes would be for it to get a gamete from each parent taht also had all four recessive alleles.  So 1 in16 gametes will fit the bill, so the odds of getting that gamete from on parent is 1 in 16, the odds of getting it from the other parent is 1/16, so the odds of getting it from both is 1/256.
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none\n\n\nyou start with one pair of homologous chromosomes in prophase I of meiosis I.  at metaphase I, these homologues line up across the metaphase plate, and at anaphase, they seperate so that one homologue goes to one pole, and the other homologue goes to the other pole.  after cytokinesis at the end of telophase I, you have one homologue in each cell...that homologue then goes through meiosis II, and at metaphase II, that homologue lines up at the metaphase plate with each sister chromatid facing each pole, and the chromosome is "pulled apart".  Anaphase II pulls the sister chromatids to each pole, and cytokinesis splits the one cell into two....two cells, each containing one sister chromatid of a homologous pair. (although in some text books this is refered to as a single homologue)
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1. Prophase 2. Metaphase 3. Anaphase 4.Teleohase
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Hi midnight, check out this site.  It should be of some help.  No diagrams, but plenty of text information.  Hope this helps.  Good luck.
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try this http://www.accessexcellence.org/RC/VL/GG/diagram.html\nAll the best !!