Which point is NOT a solution of y>or= to -2x + 5 ?
101123
(3, -3)\n\n-3 ?>= -2(3) + 5\n-3 ?>= -6 + 5\n-3 ?>= -1 (not true)\n\nIf you don't want to "plug and chug" all the points individually into the equation, you could draw up a graph and plot each point, and then draw the line for the equation. The solution set for the equation will be the shaded area to the right of the line, including the line itself.
23387
aY + b = c\n=> aY = c-b\n=> Y = (c-b)/a\n\nin this case:\n5 - 2Y = 7\n\na= -2\nb= 5\nc= 7\n\n=> Y = (7-5)/(-2)\n=> Y = -1
859504
(x-7)(x-5)\nso x= +7, or +5
908083
Tried to do it algebraically, that was a booger.\n\nI plugged that into mathematica and it gave me an error normally generated when the inverse of a function is needed to represent a solution and the solution variable occurs in more than one argument of that function.\n\nThat one might not have a solution?
369017
Set one equation equal to one of the variables, then insert it into the other equation and solve for the second variable.  then insert that variable into the original equation.\n\nx+y=5 or x=5-y\nx+2y=6\n\nput x=5-y into the second equation\n\n5-y+2y=6 \n\nnow solve for y\n\ny=1\n\nput this back into one of the original equations\n\nx+1=5\n\nx=4
855361
2x^2 - 9x - 5=0\n(2x+1)(x-5)=0\n2x+1=0\nx=-1/2\nx-5=0\nx=5\n\nroots are \nx=5, -1/2
985205
y = 2x^2 - 5    is a graph of parabola.\n\n-------------------------------------\n\nWhen x = # ,  this is an equation of a VERTICAL line.\n\nSimilarly,  when "x" is squared, "y" is to the power of one,\nthe parabola is a VERTICAL parabola. \n\nSo, now, we have established that the above equation is a VERTICAL parabola.\n\n-----------------------------------------\n\nA VERTICAL parabola is symmetric with respect to the y-axis, regardless of which direction the parabola opens (up or down).\n\n-----------------------------------------\n\nANSWER: This parabolic equation is symmetric with respect to the y-axis.
1027274
2x^2 - 2y^2 = 2(x^2 -y^2) = 2(x-y)(x+y)\n-2x^2 + 2xy = -2x(x-y)\nx^2 + xy = x(x+y)\n2(x-y)(x+y)/[-2x(x -y)]/[x(x+y)]\n= 2(x-y)(x+y)/[-2x(x-y)(x)(x+y)]\n= -1/x^2
79472
x = (1/3)y + 2\n-2x - y = 1\n\nTake the first equation, and plug its value of x into the second eq.\n\n-2[(1/3)y+2] - y = 1\n\nSimplify\n\n(-2/3)y - 4 - y = 1\n\n(-2/3)y - y = 5\n\n(-5/3)y = 5\n\ny = -3\n\nUsing the value of y, solve for x.\n\nx = (1/3)(-3) + 2\nx = (-1) + 2\nx = 1\n\nSo, the ANSWER is x=1 & y=-3
96194
Yes you are on the right track...Sort of.  \n\nSay you plug in any number for x.  We'll use 5\n\n-3(5)+y=-15\n-15+y=-15\n\nNow add 15 from the left to cancel the negative 15.  Then add 15 to the right to make the equation:\n\ny=0\n\nSo if x=5 and y=0 then your points will be (5,0)\n\nSay you have your original equation again\n-3x+y=-15\n\nNow plugin for x any number.  We'll use 1.\n\n-3(1)+y=-15\n-3+y=-15\n\nNow add 3 to the left to cancel out the negative 3 and add 3 to the right to make:\n\ny=-12\n\nSo x=1 and y=-12   (1,-12)\n\nHope that helps
664485
nope \n5x+5y\n\nthe 4y and -4y cancel each other out
1136858
y + 1 = 2y + 5\nSubtracting y on both sides\n1 = y + 5\nsubtracting 1 on both sides\n0 = y + 4\nTherefore y = -4
850894
2x-3y=5 ….multiply by 1\n                           x+2y=-l .... multiply by -2\n\n                                       2x-3y=5 \n                                      -2x-4y=2 …..add two equations\n                                      ------------\n                                        -7y= 7\n                                          y=-1\n\n substitute y=-1 in the second equation coz it is easier in order to get the x value\n\nx+2y=-1\nx-2=-1\nx=1\n\nSo the solution is (1,-1)
488491
U could do y=-2x+5 or you could do y=-7x (I luv math)
293623
(y(1)-y(2))/(x(1)-x(2)) =\n(3-(-2))/(3-8) =\n(5)/(-5) =\n-1
1025833
y = -x^2 + 4x + 5\n\nx = (-b/2a)\nx = (-4)/(2(-1))\nx = (-4)/(-2)\nx = 2\n\ny = -(2)^2 + 4(2) + 5\ny = -4 + 8 + 5\ny = 4 + 5\ny = 9\n\nVertex : (2,9)\nAxis of symmetry is x = 2
1103883
Y=X^5-X^-3+X^2\nY'=5X^4+3X^-4+2X\nY''=20X^3-12X^-5+2