If a 2000pd car is traveling 75mph down a 5 mile stretch how long will it take to reach the 3 mile mark?
108141
2.4\n\n75 miles/60 minutes   =   3 miles/X minutes\n\nCross multiply and solve for x:\n\n75X = (60 * 3)\nX = 2.4\n\nThe weight of the car is not relevant.
1106658
About 18.5 miles per second. 66600 Mph
749145
10 days.  the pattern continues like this for four more days:\n\n200 miles\n1000\n200\n1200\n\nThat adds up to 5,000 in 10 days.\n\nGood luck, and keep studying! :-)
1003796
I have no idea but probably like 70 maybe 85mph.
778547
28 hours..6.5 mph\n\nnot difficult..10 miles the first hour\n                   3 miles the next hour\n\n13 miles in 2 hours therefore 6.5mph\n\n182/6.5=28
1061938
Just under 25,000 miles (24,902.4 if you need a more exact figure).
1024302
Cruising Range:\nLand at 25 MPH: 300 Miles\nWater at 2600 RPM: 7 Hours\nCruising Speed:\nLand: 20 to 30 MPH\nWater: 6 MPH\nMaximum Speed Forward:\nLand: 45 MPH\nWater: 8.2 MPH\nMaximum Speed Reverse:\nLand: 12 MPH\nWater: 4.5 MPH
107452
120mi / x mph = 120mi / (-2x mph) - 3hrs\n120/x = -120/(-2x) - 3\n120/x = (120 + 6x)/(2x)\n(2x)(120) = (x)(120 + 6x)\n240x = 6x^2 + 120x\n6x^2 - 120x = 0\nx^2 - 20x = 0\nx(x - 20) = 0\nx = 20\n\n20 mph
696298
1st way :-\ndistance = speed x time = 55 mph x 3 h = 165 m\n\n2nd way :-\ngiven that d = 55t , so on putting t = 3hrs , we get d = 165 m
712175
Distance = Rate * Time\n\nYour first question does not make sense.  you are telling us that they will streak around a 1.5 mile track at 15 mph for 15 minutes and then asking us how long it would take.  You just told us 15 minutes.\n\nif you want to know "how far would they have traveled in 15 minutes at a rate of 15 mph on a 1.5 mile track" you can find out by:\n\nthe answer is 3.75 miles.\n\nD=RT\nD = 15 miles per hour * 15 minutes\nfirst you have make sure you are using the same units for time, either use minutes or hour for both the rate and time.\n\nI chose to change the 15 minutes into hours which = 1/4 of an hour.  use a ratio:  of minutes to hours and reduce 15/60 = 1/4\n\nthen multiply  15 m/h * 1/4h and you end up with 3.75 miles.\n\nwhen you say 15 miles per hour it = 15miles/1 hour in fraction form.\n\nwhen you multiply 15 miles / 1 hour * 1 hour /4  you cancel out the hours units and you are left with only miles.\n\nIf you want to know how long it would take them to travel one time around the track:\n\nD = RT\nT= D/R\n\nTime = 1.5 miles / (15 miles / 1 hour)\n\nRemember when you divide fractions you invert the second one and them multiply them:\n\nTime = 1.5 miles * 1 hour / 15 miles\nmultiply and cnacel out the miles unit and you get:\n(1.5 * 1) / 15\n1.5/15\n= .1 hours\n\nchange .1 hours into minutes:\n1 hour = 60 minutes so:\n.1 * 60 = 6 minutes\n\nit takes them 6 minutes to do a lap, (which is crazy for someone that size)
814622
5 hours X 40 miles + 30 miles= 230 \n\n230/5= 46 miles per hour...is that right? yeah i think so
1001541
260 miles.\n\nFrom the half-hour difference we can find the length of the hill:\n\nt = d/v, t2-t1 = d (1/v2 - 1/v1)\nd= .5/(1/72-1/90) = 180\n\nThis takes 2 hours at 90 mph, so the other hour covers 80 miles.\n180+80=260
1071959
No, as a former truck driver I know that slowing down saves gas, I gained 1 mile per gallon by slowing down 7 miles per hour, just think if everybody did that, I know they would find another way to keep the prices high, but the point is it would help to go 55, it also makes a difference on driver fatigue and how 4 wheelers interact with you.
1182945
4 miles (give or take)\n\nyou basically work out how many miles the firetruck goes in 1 minute (which is .83 50/60) then multiply by the 5 mins travelling time. 5 x .83 = 4.16 miles...\n\nformula would be: (a/60) x b = c\n\nwhere:\n\na is the constant speed\nb is the time taken to arrive\nand\nc is the answer
220370
MINI COOPER: 0 to 60 in 6.6 sec./ 1 qt. mile in 15.2 sec./\nTOP SPEED 134 mph. BRAKING 70-0 mph in 155 feet./ FUEL ECONOMY 25 mpg-city.
844954
if it is speeding........3 years.
454473
Depends on how fast your going.  It's 794 million miles away!  So divide that by how fast you want to go and you'll know.