How can I find the surface area of the Seven World Wonders? How do you find the surface area of a STATUE?
105290
tricky question... you could probably get a fair approximation by looking at a computer model of the wonders and having the computer determine the surface area based on how much mesh is required to cover the model.\n\nIRL I would probably just take a model and see how much paint is required to cover the surface, that should give you a good estimate.
33746
This gets asked daily....\nThe 7 wonders of the ancient world:\n\n    * The Great Pyramid of Giza\n      It is the one and only Ancient Wonder which does not require a description by early historians and poets. It is the one and only Ancient Wonder that does not need speculations concerning its appearance, size, and shape. It is the oldest, yet it is the only surviving of the Seven Ancient Wonders. It is the Great Pyramid of Giza.\n\n    * The Hanging Gardens of Babylon\n      Some stories indicate the Hanging Gardens towered hundreds of feet into the air, but archaeological explorations indicate a more modest, but still impressive, height.\n\n    * The Statue of Zeus at Olympia\n      This is a statue of the God in whose honor the Ancient Olympic games were held. It was located on the land that gave its very name to the Olympics. At the time of the games, wars stopped, and athletes came from Asia Minor, Syria, Egypt, and Sicily to celebrate the Olympics and to worship their king of Gods: Zeus.\n\n    * The Colossus of Rhodes\n      The island of Rhodes was an important economic centre in the ancient world. It is located off the southwestern tip of Asia Minor where the Aegean Sea meets the Mediterranean. The capitol city, also named Rhodes, was built in 408 B.C\n\n\n\n    * The Temple of Artemis at Ephesus\n      Eight hundred years after its destruction, the magnificent Temple of Artemis at Ephesus, one of the Seven Wonders of the Ancient World, had been completely forgotten by the people of the town that had once held it in such pride…\n\n    * The Mausoleum at Halicarnassus\n      The Mausoleum at Halicarnassus is the burial place of an ancient king. Yet the Mausoleum is different - so different from the Pyramid that it earned its reputation - and a spot within the list - for other reasons. Geographically, it is closer to the Temple of Artemis... And it was the beauty of the tomb rather than its size that fascinated its visitors for years.\n\n    * The Pharos of Alexandria (The Lighthouse of Alexandria)\n      Of the Seven Wonders of the Ancient World, only one had a practical use in addition to its architectural elegance: The Lighthouse of Alexandria. For sailors, it ensured a safe return to the Great Harbor. For architects, it meant even more: it was the tallest building on Earth. And for scientists, it was the mysterious mirror that fascinated them most... The mirror which reflection could be seen more than 50 km (35 miles) off-shore.\n\nOf those, opnly the Pyramids remain today.\n\nThere are more modern wonders:\n\n\n\n* Great Pyramid of Giza\n* Great Wall of China\n* Taj Mahal\n* Serengeti Migration\n* Galapagos Islands\n* Grand Canyon\n* Machu Picchu\n\nModern world:\n* Channel Tunnel\n* CN Tower\n* Empire State Building\n* Golden Gate Bridge\n* Itaipu Dam\n* Netherlands' Tidal Defences\n* Panama Canal\n\nNatural wonders:\n* Grand Canyon\n* Great Barrier Reef\n* Harbor of Rio de Janeiro\n* Mount Everest\n* Northern Lights\n* Paricutín volcano\n* Victoria Falls\n\nUnderwater wonders:\nPalau\nBelize Barrier Reef\nGreat Barrier Reef\nDeep-Sea Vents\nGalapagos Islands\nLake Baikal\nNorthern Red Sea
515325
A cube has 6 square sides and the surface area of the original cube is 6 m^2 or 6x(1000mm)^2 = 6 million mm^2\n\nSince there are 1000 mm in a m, "crushing" the cube results in (1000)^3 = a billion little cubes and each little cube has a surface area of 6mm^2. So the surface area of all the little cubes added together is 6 billion mm^2\n\nThe surface area has increased by a factor of 6 billion over 6 million = 1000
113754
Listed in order of their construction, the seven wonders are—\n\n    * the Great Pyramid of Giza\n    * the Hanging Gardens of Babylon\n    * the Statue of Zeus at Olympia\n    * the Temple of Artemis at Ephesus\n    * the Mausoleum of Maussollos at Halicarnassus\n    * the Colossus of Rhodes\n    * the Lighthouse of Alexandria
315840
Surface Area of a Cylinder = 2 pi r 2 + 2 pi r h\n\n(h is the height of the cylinder, r is the radius of the top) \n\nSurface Area = Areas of top and bottom +Area of the side \n\nSurface Area = 2(Area of top) + (perimeter of top)* height \n\nSurface Area = 2(pi r 2) + (2 pi r)* h \n\nIn words, the easiest way is to think of a can. The surface area is the areas of all the parts needed to cover the can. That's the top, the bottom, and the paper label that wraps around the middle. \n\nYou can find the area of the top (or the bottom). That's the formula for area of a circle (pi r2). Since there is both a top and a bottom, that gets multiplied by two. \n\nThe side is like the label of the can. If you peel it off and lay it flat it will be a rectangle. The area of a rectangle is the product of the two sides. One side is the height of the can, the other side is the perimeter of the circle, since the label wraps once around the can. So the area of the rectangle is (2 pi r)* h. \n\nAdd those two parts together and you have the formula for the surface area of a cylinder. \n\nSurface Area = 2(pi r 2) + (2 pi r)* h
193173
Listed in order of their construction, the seven wonders are—\n\nthe Great Pyramid of Giza \nthe Hanging Gardens of Babylon \nthe Statue of Zeus at Olympia \nthe Temple of Artemis at Ephesus \nthe Mausoleum of Maussollos at Halicarnassus \nthe Colossus of Rhodes \nthe Lighthouse of Alexandria
192399
In the front?  You have to consider the whole cube to find volume.  Volume = base area * height  You could find the surface area of one side, but you'd need to know the side length.
208438
There is a delightful article by the late Dr. John Kenny on that, back a few years ago, looking at the formulae for surface area and volumes of spheres; I'll see if I can find it for you--it's in my files SOMEWHERE--and give you the reference, and the formulae he generated. It turns out that they're not precisely the same as what you've got--but not terribly far from it.\n\nAs I said, I'll see if I can find it, and I'll get you the reference and the formulae.\n\nAbout 9pm CST...\n\nOK, here is the formulae, done the best I can on this thing...\n\n\nFor a sphere of dimension 2*k, radius R\n\nVolume: (pi^k)*(R^(2*k))/k!\n\nFor a sphere of dimension 2*k + 1 and radius R\n\nVolume:\n(2^(2*k+1))*k!*(pi^k)* (R^(2*k+1))/(2*k+1)!\n\n\nTo get the surface areas for each of these, all you do is differentiate with respect to R...\n\nAs I said, it was a little more complex than you thought--the surface areas come out a little bit differently for odd and even numbered dimensions.  I do not recall why, frankly.
210461
It all depends on the shape you are trying to measure. Different shapes use different equations.\n\nSurface area is generally quite easy. you just work out the area of each side and add them all up. Try this site: http://www.bbc.co.uk/schools/gcsebitesize/maths/shape/arearev3.shtml\n\nVolume is a little more difficult. There are some good examples of working out volumes of different shapes here: http://www.bbc.co.uk/schools/gcsebitesize/maths/shapeih/areaandvolumerev3.shtml
1033784
A cube has 6 square faces so divide the surface area by six = 81 sq. cm\n\nThe area of a suare is s^2 so so you have to get the suqre root of 81 sq. cm = 9 cm\n\nVolume of a cube is s^3 so raise 9 to the third power  9^3 = 729 cu. cm ---->volume of the cube
483551
The official list only goes up to seven:\n\n1. Great Pyramid of Giza\n2. Hanging Gardens of Babylon\n3. Statue of Zeus at Olympia\n4. Temple of Artemis at Ephesus\n5. Mausoleum of Maussollos at Halicarnassus\n6. Colossus of Rhodes\n7. Lighthouse of Alexandria\n\nThere are of course, many debates even about this list. Some people want to include more recent wonders, others want multiple lists (natural, underwater, modern, etc.)\n\nSo, if you are looking for the 8th wonder, it can be whatever you like friend!
422511
if u kno the base and height.. then area= (base x height)/2\n\nif the triangle is scalar,\nthen :\n\nfirst find s, using hero's formula\n\ns= (a+b+c)/2   .... where a,b,c are the sides of triangle.\n\nthen , area = squareroot(s x (s-a) x (s-b) x (s-c)
1106432
Diameter == 10.\nRadius == 5.\nCenter == (1,7)\n\nMethod: use Pythagorean Theorem.
573929
You only need to know the length of one side to compute the area of a regular(every-side-equal) pentagon.\n\nIF S is the length of one side, then use this formula:\n\nArea = S squared x 1.72\n\nFor S = 8 ft., Area = 64 x 1.72 = 110 square ft.\n\nWhich makes sense since will it obviously be greater than 8^2 = 64 and less than 12^2 = 144
250763
you split it into 2 ,a cone and a cylinder. first u need the slanting height of the cone and you find this by pythagorus theory for triangles ie L2 = h2 + r2, so height=6(found by subtracting the 15 from 21) radius=10 (20/2)therefore L2=6x6+10x10=136 therefore L =sqr root of 136 =11.6 surface area is A=pi*r*L\npi=3.142 so 3.142*10*11.6 = 364.5sq ft now the cylinder the surface area of a cylinder is circumference × h, or 2πr × h\nso 2*3.142*10*15 =942.6 so 942.6+364.5=1307.1 sq ft to find quantity of tins 1307.1/250=5.2 so they need 6 full tins you must check the formulas and calculations as I may have made a mistake ok
1017799
V = area of base times height\nheight = 14\nbase = 3*3*pi = 9pi\nV = 14*9pi\nV = 126pi\nV = 395.8
901347
You could use the formula for surface area of a sphere to solve this.\n\nUsing google, I found the diameter of the earth is 12756.3 km, which is equal to 41,851,378 ft.  So the radius is 20,925,689 ft.\n\nThe formula for surface area of a sphere is 4pi r².\n\nSo the square feet covering the earth is 4pi(20,925,689)² square feet.  \n\nThis is approx. equal to 5.5026 * 10^15 square feet.\n\n~ ♥ ~