what is a vertical intercept?
104027
The points where a line crosses the vertical and horizontal axes are known as the vertical and horizontal intercepts. (These points are often referred to as the x-intercept and the y-intercept.) Given a linear function f(x) = mx + b,
1092839
y=0 is the x-intercept\n\nso 5(0)-3x+4=0\n\n-3x=-4\n\nx = 4/3\n\nx-int = (4/3 , 0)
411240
you get vertical asymptote when denominator of a fraction hits zero. so \nx=0 for 3/2x\nx=-1 and x=3 for (x/(x+1)(x-3))\nand so on
885688
slope m=(y1-y2)/(x1-x2)\n          m=(1--1)/(3-3)\n          m=2/0    which gives us a singularity,\nthat is, a vertical line.
1187323
I prefer vertical, what the hell was the question again?
849823
set x=0 to get the y intercept and \ny=0 to get the x intercept\nin this case\nsetting x=0\ny-1=9\ny=10\nso y intercept=(0.10)\nsetting y=0\n-1=(x-3)^2\nx-3=rt(-1)\nx imaginary\nso no x intercepts
689040
longitudes are vertical and latitudes horizontal
887226
x,y intercepts are\n9-y=+/-(x-2)^2\ny intercept bysetting x=0 will be (0,9)\nx intercept by setting y=0\n9=+/-(x-2)^2\nx-2=3x=5\nx-2=-3\nx=-1\nx intercepts(-1,0) and (5,0)\nvertex=(2,9)
112219
m = 2\nb = 4\n\nThus, your line's equation is y = 2x + 4\n\nThe x-intercept occurs where the line crosses the x-axis, which is also where y = 0. Substituting 0 for y in the above equation:\n\n0 = 2x + 4\n-4 = 2x\n-2 = x (x-intercept)
937981
Your goal here is to solve for a, b, and c.  We can easily do this with the facts that we're given.\n\ny-intercept is 2: This means that when x=0, f(0) = 2\n\nso f(0) = b * a^(0) + c = 2\nb + c = 2 (since a^0 = 1)\n\nHorizontal asymptote is y = -2.  Remember that for exponential functions, the horizontal asymptote is always the horizontal shift, which is the constant next to the term containing the expontential.  Thus, in our case, c is the horizontal shift, so \n\nc = -2\n\nCombining this with b+c=2 (which is what we solved for earlier), substituting c=-2 in there yields:\n\nb+(-2) = 2, so b=4.\n\nb=4 and c = -2, so if we plug it back into f(x), we get\n\nf(x) = 4*a^x - 2\n\nPasses through the point (1,4) means we plug in 1 for x and 4 for f(x), to get:\n\n4 = 4*a^(1) - 2, or\n4 = 4a - 2\n6 = 4a\n3/2 = a\n\nNow we have a, b, and c.  The final answer is then:\n\nf(x) = 4*(3/2)^x - 2
882681
y intercept is the value that results when you put in x = 0.\nx intercept is the value that results when you put in y = 0.\n\nTo find the y intercept, plug in x = 0:\ny = -3(0)² - 12(0) + 7\ny = 0 - 0 + 7\ny = 7\n\nTo find the x intercept, plug in y = 0\n0 = -3x² - 12x + 7\n\nUsing the quadratic formula:\nx = [ -b ± sqrt(b² - 4ac) ] / 2a\n\nx = [ -(-12) ± sqrt((-12)² - 4(-3)(7)) ] / 2(-3)\nx = [ 12 ± sqrt(144 + 84) ] / -6\nx = [ 12 ± sqrt(228) ] / -6\nx = [ 12 ± 2(sqrt(57) ] / -6\n\nSo there are two x intercepts:\nx = -2 ± (sqrt(57) / 3)\nx ≈0.517 or x ≈ -4.517
279640
If you have an equation that is Y=__X-__ or Y=__X+__, then the second space is the Y-intercept and the first space is the slope.\n\nSo, for your equation, Y=3X-5, 5 is the Y-intercept, and 3 is the slope.  The Y-intercept is where the line crosses the Y axis, which is 5.  So, on the Y axis (which is X=0), count up 5 spots and that is your intercept --> (0,5).\n\nThen you have to use the slope, which remember is the number in the space before the X --> 3.  3 is the same as the fraction 3/1, and in the fraction of a slope, the top (numerator) is how many spaces up or down you move from the original point, and the bottom number is how many spaces you move left or right from the original point.  So, your first point being (0,5), move up 3 and to the right 1 (up and right because both 3 and 1 are positive).  You should be at (3,6).  \n\nMaking an input/output chart makes plotting your graph a lot easier.  Make a chart with two rows, the top row being X and the bottom row being Y.  To the left of your chart, label X and label Y.  (So that you remember your slope, I would write X --> 3, Y --> 1).  Put your intercept point (0,5) in the chart: 0 to the right of X and 5 to the right of Y.  Now you can see that you just add the slope!  0+3=3 and 5+1=6.  So, your next point is (3,6)!  From there, keep going to the right, adding as you go.  Add another 3 to 3 and another 1 to 6.\n\nGood luck!
918456
domain\nall real x\nx intercept\nputting y=0\n0=x+rt{x]\n-x=rtx\nx^2=x\nx(x-1)=0\nx=0 or 1\nx intercept=(0,0) and (1,0)\ny intercept\nsetting x=0\ny=0\ny intercept=(0,0)\nno symmetry exhibited
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
142602
This is truly a sad question, what is the school teaching you? To come to the yahoo answers board to get answers.\n\nSlope intercept form is y=mx+b\nWhich means you have to solve for the y variable on one side.\n\nThe manipulation of variables is as follows.\nsubtract 2x from both sides\n\nDivide through both sides by -3\n\nPlace the resulting form into the y = mx + b form
523941
x intercept y=4 (0,4)\n(plug 0 in for x and solve)\ny intercept x=20/3 (20/3,0)\n(plug 0 in for y and solve)
618527
i'm not gonna solve it...but tell u how to solve it.\n\n-x intercept of vertex : -b/2a\n-y intercept of vertex : f(-b/2a)\n-for direction of opening find f(0)\n-i guess the axis of symmetry is the middle point of something. i cant remember that something.\n-find the relationship urself