Does a RF signal affect the sound in which it's carrying in a anyway(as it travels to its receiver)?
99864
An AM signal contains a band of frequencys twice as wide as the maxium "sound" frequency that it carries. When the wave travels a long distance through the ionisphere , say 5000 miles, the diferent frequences of the signal can be adsorbed different amounts causeing "selective fadeing" and distortion. How bad the distortion is depends on the condition of the ionisphere, which depends on how many sunspots the sun has and on wheather there is a solar storm in progress.
741475
Good question.\nNo. If you are travelling faster than the speed of sound (faster than Mach 1), you can not hear an echo of the sounds that you make.\n\nIn order to hear an echo, the sound must travel from your location, bounce off something, and return to you. \n\nIf you are travelling faster than Mach 1, all of the sound that you make is behind you. Whether it bounces or not, it can not come back to you, because once it's behind you it can't catch up with you.\n\nHere's an interesting thought: \nIf you subsequently slow down to less than Mach 1, then the sounds that you made while travelling faster than Mach 1 will start catching up with you. When you hear those sounds, they will not be echos in the sense of "sound that BOUNCED back to you." But you would experience the same effect as an echo (a sound that emanated from you, and later reached your ears).
149621
maybe you need to clean the pickup (reader of your plaver or your earpiece/speaker is not connected well
674033
the chassis wont distort the reading. you need to be encompassed in a diamagnetic material for distortion.
77677
Each device operates at a different frequency, just like a video card operating at 65mhtz, or a faster one at 72 mhtz. If one is operating at a different frequency (cant see it with the naked eye) then it will show up as a distortion. Just like having two music notes that are not harmonious with each other they cause distortion or in the parady given a bad chord.
441296
In certain low volume and high speed circuits, transistors will always have their places. ALthough their are now many more radio chips.\nMIKE
530967
Like that of a intercome system. Your voice is amplified and sent down the signal wire (Tip - old technology). The common wire (Ring).
224941
0ft/s. Sound doesn't propagate in vacuum
394921
Sound does not travel in a vacuum.
28532
The pickups are small magnets.  Wires are wrapped around the base of the magnets, with an inlet and an outlet.  When the strings vibrate, the metal moving through a magnetic field induces a change in the magnetic field (since the magnets magnetize the strings themselves, and a moving magnetic field induces a current in a nearby conductor--see faraday's principle of inductance).  The current will oscillate with the frequency of the string--this gives the frequency of the sound.
384214
Yes, there will be sound quality loss.
693154
Only if they are at the same distance from the station and the same atmospheric conditions. The farther the receiver, the longer it takes for the signal to be received.
387292
No, it doesn't damage the voice box...it has a different density, thus sound travels faster in helium
665563
If the frequency remains the same, the larger the amplitude, the more energy.  This is from basic observation of an AM radio signal - silence, not much change to the carrier, but the louder the signal being transmitted, the larger amplitude of the signal.
844853
Glass generally has not much effect on the radio frequencies.  It is the other material like metal that reduces the range.  It will not strengthen the signal by any means though.\n\nIt is not harmful.
122343
yes, according to this the volume doubles.  I would assume that the volume is directly related to the speed but I could be wrong.
405837
You need to have recorded the power over a range of frequencies and ploted the Output over the Input. If the chirp signal can be extrapolated into its freqency components possibly you can compare the output to this, otherwise a new set of data points are required.