How would you describe a waterfall?
112400
*Pondering a long time on this* My visual description would be http://en.wikipedia.org/wiki/Image:Escher_Waterfall.jpg\n\nScientifically, A waterfall is usually a geological formation resulting from water, often in the form of a stream (or river) flowing over an erosion-resistant rock formation that forms a sudden break in elevation. Some waterfalls form in mountain environments where erosion is rapid and stream courses may be subject to sudden and catastrophic change. In such cases, the waterfall may not be the end product of many years of water action over a region, but rather the result of relatively sudden geological processes such as thrust faults or volcanic action. Waterfalls may also be artificial.\nGreat waterfall info at http://en.wikipedia.org/wiki/Waterfall\n\nMy personal description, absolutely lovely...
450525
It rains\nthe rain collects and then either:\n\nsoaks into the ground and comes out later\nflows into a river then the sea\n\nAt some point it evaporates and forms clouds\n\nthen it rains...\n\nsee above!
796975
hills, mountains, creeks, streams or lakes
104013
river\n\nn : a large natural stream of water (larger than a creek); \n\nIf it didn't have water, I don't think it would be called a river.
457243
octagon\nholy water\nsilence
908662
good one... like there is Tsunami...a low pressure area in water body.Why there is no air movement.\nThere may be a little movement which is not highly noticeable.
386591
I took my first SkyDive in Nagamibie northern Victoria in November last year.\n\nExhilarating would be a good word to describe it.\n\nLike falling with the initial rush tat you get when falling off or jumping off something, but never finding the ground. Truly awesome!!!\n\nI would recommend it to everyone because once the shoot opens, the scenery is beautiful and everything is completely silent. Such a beautiful experience.
380715
Rain.  you are describing the dewpoint.
1172183
waterfall model\n\nThis is the most common and classic of life cycle models, also referred to as a linear-sequential life cycle model.  It is very simple to understand and use.  In a waterfall model, each phase must be completed in its entirety before the next phase can begin.  At the end of each phase, a review takes place to determine if the project is on the right path and whether or not to continue or discard the project.  Unlike in the general model, phases do not overlap in a waterfall model\n\nAdvantages\n\nSimple and easy to use. \nEasy to manage due to the rigidity of the model – each phase has specific deliverables and a review process. \nPhases are processed and completed one at a time. \nWorks well for smaller projects where requirements are very well understood.\nDisadvantages\n\nAdjusting scope during the life cycle can kill a project \nNo working software is produced until late during the life cycle. \nHigh amounts of risk and uncertainty. \nPoor model for complex and object-oriented projects. \nPoor model for long and ongoing projects. \nPoor model where requirements are at a moderate to high risk of changing.\n\nV-Shaped Model\n\nJust like the waterfall model, the V-Shaped life cycle is a sequential path of execution of processes.  Each phase must be completed before the next phase begins.  Testing is emphasized in this model more so than the waterfall model though.  The testing procedures are developed early in the life cycle before any coding is done, during each of the phases preceding implementation.\n\nRequirements begin the life cycle model just like the waterfall model.  Before development is started, a system test plan is created.  The test plan focuses on meeting the functionality specified in the requirements gathering.\n\nThe high-level design phase focuses on system architecture and design.  An integration test plan is created in this phase as well in order to test the pieces of the software systems ability to work together.\n\nThe low-level design phase is where the actual software components are designed, and unit tests are created in this phase as well.\n\nThe implementation phase is, again, where all coding takes place.  Once coding is complete, the path of execution continues up the right side of the V where the test plans developed earlier are now put to use.\n\nAdvantages\n\nSimple and easy to use. \nEach phase has specific deliverables. \nHigher chance of success over the waterfall model due to the development of test plans early on during the life cycle. \nWorks well for small projects where requirements are easily understood.\nDisadvantages\n\nVery rigid, like the waterfall model. \nLittle flexibility and adjusting scope is difficult and expensive. \nSoftware is developed during the implementation phase, so no early prototypes of the software are produced. \nModel doesn’t provide a clear path for problems found during testing phases.
963798
front stagnation point\nhttp://www.fluidmech.net/tutorials/raindrops/drop_flow.htm\nhttp://www.fluidmech.net/tutorials/raindrops/raindrop.htm
466575
Topography is the word you want. Combine Topography with river and throw it into a search engine and things like this Wikipedia article should fall out.  Happy hunting.
819058
lady in d water\ndonny darco\nland of d dead\nultraviolet\nd hills have eyes\n\n2 name a few
997459
Good answer mofu.   Local convention is the determining factor though - whoever grew up next to said watercourse will have a conventional way of talking about it, regardless of anyone's "definition".   In Scotland there are lots of rivers that the local Brazilian population regards as miniscule little streams.   In Brazil there are rivers that I would say are virtually the sea.
63593
When it rains and the rain hits mountains or other materials it cannot sink through small trickles appear in the direction of the downslope. The trickles come together eventually and pour looser materials with them (such as sand or loose earth for example). Eventually they can form a big enough stream to be a river. When a river runs with high speed it tends to have a straighter path, but if it becomes wide and slow it starts bend like a serpentine.
500930
Rain: Water pouring out of the sky.\n\nDrizzle: Very small water droplets which barely show up on your clothes.\n\nMist: A foggy watery cloud in the morning.
1149687
pouring,sprinkling,flooding?????????????? acid.
702956
Okay I think the other 2 answers you already had when I started this misunderstood your question so I'll get it right for you.\n\nTwo things happen in the 16 seconds.\n1. rock falls s meters\n2. sound travels back up s meters from water surface to well opening\n\nFirst let's deal with the #1 part, the rock's fall.  For this let's use a variable called t1 for time.\n\nWe need to use this formula: s = (v1)(t) + ½(a)(t)²\ns = displacement, v1 = initial velocity, t=time, a=acceleration\n\nSince the rock is dropped it has no initial velocity.  Let down be positive.\n\ns = (v1)(t1) + ½(a)(t1)²\ns = (0)(t1) + ½(a)(t1)²\ns = ½(a)(t1)²\n\nOkay so we figured out what we can in this step about t1.  Now let's go to step 2 and see what we can figure out about t2.\n\nThe sound travelled from the water up to the well opening (s meters) in some amount of time we don't know yet (t2).  We can describe the sound's movement with this formula:\n\ns = (v)(t) (we use this because the sound is not accelerating)\n\ns = displacement, v = velocity, t = time\n\nNow let's use our variables (t2, our s) and use v2 for the sound's velocity and see what we can put together with the sound.\n\ns = (v2)(t2)\n\nOkay so we know something about the sound and rock now, let's gather what we found and look at it.\n\n1. s = ½(a)(t1)²\n2. s = (v2)(t2)\n\nThere is something else we know too and can write down as an equation.  We know that the time it took for the rock to hit the water and the time it took for the sound of the splash to travel back up to the opening add up to a total of 16 seconds.  So we can write it as:\n\nt1 + t2 = 16s (let's isolate the t2 and call it equation 3)\n3. t2 = 16 - t1\n\nSo all together we have:\n\n1. s = ½(a)(t1)²\n2. s = (v2)(t2)\n3. t2 = 16 - t1\n\nWe have enough equations now to solve for the number of variables we have.  Start by substituting t2 from #3 into #2 to get equation #4.\n\n4. s = (v2)(16 - t1)\n\nNow set 1. and 4. equal to each other (because they are both s so they are equal so we can do that)\n\n(v2)(16 - t1) = ½(a)(t1)²       (expand it out now)\n\n16(v2)-(t1)(v2) = ½(a)(t1²)\n\nNow put in what we know (v2 = 345m/s, a = 9.8m/s)\n\n16(345)-(t1)(345) = 4.9(t1²)   (move it all to one side and it should look familiar)\n\n4.9t1²+345t1-5520=0  (it's a quadratic equation and we can solve those, stick it in your calculator)\n\nt1 solves to\nt1 = 13.436\nor\nt1 = -83.844 (forget this one, the rock didn't hit before you dropped it)\n\nSo t1 = 13.436m (we only know this to 2 significant digits)\n\nNow we can finally solve for s by using equation #1\n1. s = ½(a)(t1)²\ns = ½(9.8)(13.436)²\ns = 884.57m (only to two sig. digits)\n\ns = 880 meters