what is the coefficient of shrinkage in graphite casting ? in terms of percentage and volume.?
26943
It appears that the question period has expired.  If you have received an answer that meets your needs, please choose one of those as a 'best answer.'  If you haven't received a good answer for your question, you may want to consider the following,\n\n1) Re-post your question.  Newer questions get more activity on Yahoo! Answers than old ones.\n2) If you do re-post your question, consider why it wasn't answered the first time.  Could it be more specific?  Could it be worded better? Were there grammatical or spelling errors? Was it in the best category?\n\nIf it doesn't seem likely that re-posting your question will help you, then here's a listing of my favorite 'answer sites'.  Maybe one of them will help you.\n\nAnswers.com http://www.answers.com/\nBartleby http://www.bartleby.com/\nYahoo Reference http://education.yahoo.com/reference/\nHowStuffWorks http://www.howstuffworks.com/\nWikipedia http://en.wikipedia.org/wiki/Main_Page\n\nSince I really haven't answered your question, it is not necessary to give me any points.  Regards.
542138
The general formula to calculate the heat loss is\n\nQ=m*cv*(t2-t1)\n\nQ is the heat loss\ncv is the specific volume at constant volume(if it is a constant volume process)otherwise use cp(specific heat at constant pressure)\n\nt2 is the external temperature\nt1 is the internal temperature
271646
Silicon is essential to making of grey cast iron as opposed to white cast iron. Silicon causes the carbon to rapidly come out of solution as graphite, leaving a matrix of relatively pure, soft iron. Weak bonding between planes of graphite lead to a high activation energy for growth in that direction, resulting in thin, round flakes. This structure has several useful properties.\n\nThe metal expands slightly on solidifying as the graphite precipitates, resulting in sharp castings. The graphite content also offers good corrosion resistance.\n\nAlso A famous (and very large) example is the Iron Pillar of Delhi, erected by order of Kumara Gupta I around the year AD 400. However, unlike stainless steel, these artifacts owe their durability not to chromium, but to their high phosphorus content, which together with favorable local weather conditions promotes the formation of a solid protective passivation layer of iron oxides and phosphates, rather than the non-protective, cracked rust layer that develops on most ironwork.
1122699
Depends on what the molarity of the concentrated acid is and what the final concentration you want.\n\ntypical formula is: (final volume x final concentration) / initial concentration = initial volume
582418
put simply its complete bullshit... lol, solidification is just the slowing of atoms/molecules, sonce light ALWAYS (dont even go tehre with the whole medium thing, its always) travels at teh same speed... like i said before solidified light is bs. :-)
482888
I'm guessing that your question pertains to the series of standard solutions you would prepare using the stock solution and volumetric flasks/pipette.  \n\nYes, you can use the C1V1=C2V2 formula, however there's a more practical and faster method that can be arrived at through common sense.  That is the concept of dilution factor.  If you have a stock solution of .5M iron for instance and you wanted to make a .05M iron solution, just dilute the next solution by a factor of 10%.  One way this can be achieved is by taking 10 mL of this stock solution using a volumetric pipette and adding it to a 100 mL volumetric flask.  To lessen the sampling error, it's better to take a larger sample volume, but usually this becomes tedious since lab equipment can be limited.\n\nSo take the original x molarity stock solution.  And if your final desired concentration is y, then the dilution factor is\n\ny/x \n\nThis percentage, y/x, represents the volume percentage in the final solution, that is multiply y/x by the particular To Deliver volume of the volumetric flask, to determine how much volume of the stock solution you need.......place this solution into the volumetric flask with a volumetric pipette, and then dilute to the mark with the standard solvent.
500514
is the AT and GC proportions?\n\nfor example\n\n30% AT\n70% GC\n\nis the same as\n\n15% A\n15% T\n35% G\n35% C
981890
Reproduction detail\n1. use of finer sand, \n2. Hydrostatics of the molten metal \n3. same as in #2\n4.Hmmm?\n5.To avoid air voids :). \n6. Not enough water and the sand will crumble, too much water the medium will be too fluid or too much of steam will be produced during casting damaging the mold from inside out.
150301
Graphite is the most stable form of C. It has a gleaming appearenc and is quite brittle. It has a low elting point as well...
908586
GB >= 0.6*(CS + GB)\n\n"cushion" variable U introduced : \n\nU >= 0 \nGB + U = 0.6 * (CS + GB)
695323
Hi. From the web, they use the constant 'k' :    http://answers.yahoo.com/question/;_ylt=Aku8q5AETPeTKbquDgodzrYezKIX?link=answer&.crumb=xa6shFEtoH4&qid=20061103074030AA2hrrt&.done=http%253A%252F%252Fanswers.yahoo.com%252Fquestion%252Findex%253Fqid%253D20061103074030AA2hrrt\nThermal conductivity = heat flow rate × distance / (area × temperature difference).
1052478
The charring you are referring to is called "Remelt"\n   It is seen in the EDM process as well.\nI am unfamiliar with the material you are referring to.\n   Can you offer more information?
422875
U have not mentioned the gas gravity to determone deviation factor to have an exact answer...generally..taking z=1\npsia ( absolute value) will also be used \nPsc*Vsc/Tsc=PV/T\n\nso: Vsc/V=PTsc/PscT=53.1/T \n\nThis is the simplest correct answer.... make is easier but worse that the process is isothermal so\n\nVsc/V=102 --> 1cu ft at TVD= 102 SCF\n\nThe most exact solution can be provided if u want..with taking temperatire and deviation,composition in account
134473
The answer is obviously (A). The bar may shrink a little, but it can't disappear completely, as the options B, C and D imply!!\nHence, by process of elimination, the answer is (A). :-)
1161541
Ha ha :))\n\n\nlet's say x be the length of metal rod 1 in the final composite rod \n\n===> (31-x) is the length of matal 2 in composite rod \n\nalpha 1(coefficient of linear expansion for metal 1 )  = change in length /original length  *change in temp =6.35* 10.^-2/31*100\n=\n\nSimilary ,for metal 2\n\n\nalpha 2  = (3.20 * 10.^-2)/31*100\n\nFOR THE FINAL compsite  rod  \n\nx*alpha1 * change in temperature + (31-x)* alpha 2* change in temp = 5.55 * 10.^-2 \n\nchange in temp above eqn is same =100\n\n0.002x+(31-x)*0.0010=5.55*10.^-2\n\n0.001x=0.0245\n\nx= 24.500 cm of metal rod 1\n\n& (31-24.500) cm = 6.500 cm of metal rod 2\n\n\nTHE author below has made a mistake of leaving the orriginal length :\n\nThe eqn is:\n\ndl=alpha*original length*dT
1041556
The answer to your question is indeterminate, for several reasons\n1) This is a trade secret that competitors would like to know the answer to.  Hire a trade spy.\n2) What are the L x W x H dimensions of the product?. Costs will be determined by the size of the "bath" vessel required.\n3) The surface area-to-volume ratio will determine the melt-spread time, product cooling time required, etc.\n4) Is the production order for 1 ton per day? 2 tons? 10 tons?\n5) WHAT Clarity (letter) per WHAT Rating per WHAT GPS Standard (#) ?
1078399
i'm not very sure if this is what you're looking for, but for a closed system with constant temperature, pV=p'V'. since volume, V = pi x (diameter/2)^2 x length, with constant length of the pipe, we have V = k(diameter)^2, where k is constant. hence, pV=p'V' is rewritten as p(diameter)^2 = p'(diameter')^2, i.e. p'/p =(80/250)^2. the new pressure is 0.1024 the original pressure.