How many extra inning baseball games are won by one run and how many are won by other amounts in a given year?
108916
You're probably going to have about 90% of extra inning games won by a margin of just one run.  Hope this helps!
1171482
tehre's a formula for it...\nit depends how much you run druing the game
1035104
x = total hits\ndoubles = 1/7 of x, or x/7\nhome runs = 12.5% of x or 0.125x\nsingles = 82\n\nx = x/7 + 0.125x + 82\nmultiply both sides by 7\n7x = x + 0.875x + 574\nsubtract x from both sides\n6x = 0.875x + 574\nsubtract 0.875x from both sides\n5.125x = 574\ndivide both sides by 5.125\nx = 112\n\nthe kid had 112 hits
539558
No.. a pitcher can only receive one or the other.  If he wins the game that means the team took the lead while he was the active pitcher, while a save can only be recorded when you enter the game with a lead intact.
1029100
It is 0, the runner must make it to first base safely without any other outs recorded to have any of the runs coun, very nice question, and the guy a few questions up read it wrong, two outs stop all preceding runs\n\n7.12 Unless two are out, the status of a following runner is not affected by a preceding runner's failure to touch or retouch a base. If, upon appeal, the preceding runner is the third out, no runners following him shall score. If such third out is the result of a force play, neither preceding nor following runners shall score.
497522
1)single\n2)double\n3)triple\n4)HR\n5)error\n6)wild pitch\n7)passed ball\n8)steal home\n9)balk\n\nkinda cheap to count the 4 different types of hits but I couldn't think of any other way to get 9. \n Squeeze play wouldn't work because with 2 outs you'd only need to get the out at first and inning is over and if he makes it to first then it's a single so it's no different.\n Sac Fly?  there are 2 outs though someone else already pointed that out.\n \nWhat about catcher's interference?  Does the man on third get a base or do you have to be forced to move to get to on that type of play?\n\nhmmm...that's all I can think of right now.
393089
The slugging percentage indicates the player’s ability to get extra-base base hits, such as doubles, triples, and home runs. The calculation for slugging percentage is the number of total bases achieved for all hits divided by the number of at bats. Slugging percentage tells you how many bases a player hits for each time at bat. \n\nTotal number of bases from hits (TB) divided by number of at bats (AB)\n\nTB = 1B + 2(2B) + 3(3B) + 4(HR) / AB
497751
The answer is six.\n\nOf the first five players to get a hit, two are thrown out on the bases and three are standing on the bases. The next batter hits the ball, but it touches one of the runners. The batter is credited with a hit (#6), but the runner is out, making three outs in the inning before a run scores.
405389
this is easy enough, these people are making it more difficult than it really is.\n\nIm not sure if your just talking about Earned Runs, or the ERA, which is the earned run average... so i will describe both.\n\na run is "earned" when the run is scored without the assistance of a fielding error.  so all runs are earned unless the runner has reached base by error, or a runner was allowed to score by error.  \n\nNow Earned Run Average (ERA) is figured out by dividing the amount of earned runs by the amount of innings pitched, then multiplying by 9 innings.  For Example...\n\nIf a starting pitcher pitches 5 innings, allowing 1 run... you take (1/5) and that equals 0.2.  Then you take 0.2 x 9 innings and get an era of 1.80 ERA.  \n\nHope that helped!
1174359
You could use a bunch of different measuring sticks.  Last year's NL East had the top four teams finish within 7 games of each other, while the West had the last place team only 15 games behind the division winner, the same as the 1996 NL Central.  The 1995 NL West (only 4 teams) had an 11 game gap between first and last, but that season was strike-shortened, as was 1994 when the 4 teams in the AL West were within 5 1/2 games of each other.  The 2004 AL West had the top three teams within 3 games of each other.\n\nIf we're only going to go back to the 3-division format in each league, those have been the closest races.
19393
If you mean how many handle a standard game, there are four. One at first base, one at second base, one at third and one calling the balls and strikes behind home plate. \n\nIf you want to know the total number of umpires working at any one time, that would be 60 per night as there are 30 MLB teams or a maximum of 15 games going on in a day.
1038421
slugging % is based on power.\n\nhomerun=4\ntriple=3\ndouble=2\nsingle=1\n\nadd the total bases then divide by the number of at -bats.\n\nNOTE:\n\nwalks, hbp, errors, sacs, and dropped 3rd strikes do NOT count as an "at-bat".
466860
162 per team in Major League Baseball\n\nThere are currently 30 teams in the MLB.  Since each game is played by exactly 2 teams assuming there are no rainouts that are not made up or forfeited games you would multiply 162 games per team by 30 teams and divide that product by 2 teams per game and even though the unit comes out to teams it is really games.\n\nThere are a total of 2430 games played in a regular season of the MLB.\n\nAny regular season ties that require a playoff will have that playoff game count as a regular season game.  So once in a while there are 2431 or 2432 games.\n\nIn 2005 there were 2430 regular season games played.\n\nIn 1995 the teams played a 144 game schedule due to a late spring training that was a result of the previous year's strike\n\nThe last year of 154 games per team was 1960.  That year there were 16 teams in MLB so that year there would have been a potential for 1232 games.  I manually counted them for you and came up with: 1232, they played all the regular season games that year.
1107229
The Major League Baseball season has been 162 games long for each team since 1961 (American League) and 1962 (National League). For the four-plus decades prior, the standard season length was 154 games. This page is about the evolution of the season schedule since Major League Baseball began.
1136682
It's kind of easy to figure out once you understand it. I still have to look back through an inning to figure it out.\n\nIf a runner reaches base because of an error than if that runner eventually scores, it is considered an unearned run.\n\nAlso, you have to imagine that that runner is out. Therefore, if there were two outs when the error happened, then any runs scored after that play would be unearned because you assume that the fielder would have fielded the ball cleanly and got the out.. No matter what.\n\nIf there are less than two outs, then at the end of the inning you look back and figure what would have happened if the runner had been out. \n\nThere are also errors that just allow a runner an extra base (like a throwing error on a play at the plate and the runner who hit the ball advances to second or third base because of the error).\n\nIn this case, you have to figure that the runner would still have been at the original base and then go through the inning and see if he would have scored.\n\nIt's a complicated thing, but if you understand it and have a scorebook in front of you, it's pretty easy to figure it out at the end of the inning.
547600
Easy enough:\n\nERA= (ER/IP)*9\n\nER = Earned Runs\nIP = Innings Pitched\nERA = average number of runs allowed per nine innings
476608
Earned Run Average--It is the average number of earned runs scored on a picticular picher in 9 innings.