2x^2-x-1=-1     What are the steps to reach x=1/2 or 0?
103674
2x^2 - x = 0  { by adding 1 to both sides }\nx^2 - (1/2)x = 0  { by dividing both sides by 2 }\nx (x - 1/2) = 0 { by factoring }\n\nsolves when either x = 0 or x = 1/2 . QED
895342
x^2-9x-x+9=0\n(x-9)(x-1)=0\nx=9 or x=1
851434
-x^2 if x=-2\n-(-2)^2  \n-(4)\n-4
581691
if by this you mean\n\n((x^2)/2) - ((7x)/4) = (-3/2)\n\nMultiply everything by 4\n\n2x^2 - 7x = -6\n2x^2 - 7x + 6 = 0\n(x - 2)(2x - 3) = 0\nx = 2 or (3/2)\n\nANS : x = 2 or (3/2)
1033116
A X = D\nX = A^(-1) D. (A inverse * D)\n Do it ur self.
786717
its 1\n\nsince i = (-1)^1/2\n\nso i^2 = (-1)^(2*(1/2))\n\nwhich is 1
71279
It'sa simple aquation...\n\nx-4/4-x = x-1-x = x-x-1 = 0-1 = -1
871243
X^-n = 1/(X^n)\nso\n(-8)^-1 = 1/(-8^1) = -1/8
572493
=x(x^3-2)\n--> x=0 or x=2^(1/3) or -2^(1/3)
940135
Use factoring.\nx2-2x-8=0\n(x-4)(x+2)=0\nso\nx-4=0 and x+2=0\nsolve\nx=4 and x=-2
676772
If you must factor, this is how it is done...\n\n2x^4 - 16x^2 = 0\nx^4 - 8x^2 = 0\nx^2(x^2 - 8) = 0\nx^2 = 0 and x^2 = 8\nx = 0 and x = +/-sqrt(8)\n\nThere...
441224
x - sqrt(x) = 0\nAdd sqrt(x) to each side\nx = sqrt(x)\nSquare each side\nx^2 = x \nSubtract x from each side\nx^2 - x = 0\nFactor x\nx(x-1) = 0\nx = 0 or x = 1\nCheck in orginal problem: x- sqrt(x) = 0\nFor x = 0\n0 - sqrt(0) = 0\n0 - 0 = 0 \n0 = 0\nFor x = 1\n1 - sqrt(1) = 0\n1 - 1 = 0\n0 = 0\nThus, the answers are \n0 and 1\n\nAlso, sqrt(x^2) = x is only tru if x is positive.\nsqrt(x^2) = |x| is true for any number.\nThat is, the square root of x^2 is equal to the absolute value of x.\n\nx^2 = 4 means x = -2 or x = 2
743971
change in x = 1-(-1) = 2\nchange in y = 0-0=0\n\ntotal change = sqrt(2^2 + 0^2)\n= sqrt 4\n= 2
560328
anything to the power of zero is one. so 1+1=2. Y=2. 2X2=4.
220918
2*x^2 - 3*x - 2 = 0 <=> x = -1/2 V x = 2 \n\n==> 2*x^2 - 3*x - 2 <=0 <=> x = [-1/2 , 2]
25136
1 = sqrt(1) = sqrt(-1*-1) = sqrt(-1)*sqrt(-1)=i*i = i^2 = -1\nSo 1 = -1.  Add 1 to both sides and 2 = 0.  Divide both sides by 2 and 1 = 0.
775457
multiplying by x\nx^2-5=4x\nx^2-4x-5=0\n(x-5)(x+1)=0\nx=5 or -1