what would the complementary strand of DNA be for the following sequence of bases c t t a g g c t t a c c a th
107332
G pairs with C and A pairs with T, so its GAATCCGAATGGTA\n\nI assume the "h" at the end is a typo?\n__________________________________________\nsouthernserendipiti wrote:\n>>>What's the "th" at the end?\nI assumed it was a t and a typo : )
1182355
Remember this: \n\nRNA (A, U, G, C)\nDNA (T, A, C, G)\n\nDNA has sequence: T-C-A-T-C-G \nmRNA would be c) : A-G-U-A-G-C
290261
I assume you have some knowledge of transcription (DNA->RNA), basically they want to know how well you understand the process of translation (RNA-> protein).  Further I assume they give you a set of tRNAs taht you didn't include here.  You need the codon usage table and it various (slightly) depending on the organism.  \n\nThe first question starts with the result and asks you for the template.  Given an RNA, what was the complementary DNA that was used to encode it?  RNA transcription proceeds 5' to 3' (so does DNA synthesis - the only process that does obey this rule is the reverse translation of retroviruses, it proceeds 3' to 5').  Further, nucleic acids are always listed 5' to 3'.  So basically what you do is first find the complementary DNA base pair for the RNA nucleotide.  U pairs with A, A with T, C with G, and G with C.  I'll give the first six letters as an example.\n5' UACACC 3'\n3' ATGTGG 5'\nNow you have to flip the sequence over, to read it properly in the 5' to 3' orientation.  \nGGTGTA\n\nQ2)  Now that you know the template (GGTGTA), find it's complement.  Use the same process as above.\nGGTGTA\nCCACAT -> TACACC\n\nQ4)  The mRNA sequence is UACACCGGG...  The tRNA finds the first three bases (the first codon), and base pairs with it.  The tRNA has an amino acid coupled to it, and upon basepairing to mRNA this amino acid is released to form a growing polypeptide chain.  All you have to do is look at the codon UAC and figure out what amino acid it codes for.  \n\nUsing a codon usage table from humans, UAC codes for Tyr (tyrosine). ACC codes for Thr.  So the first two amino acids are Tyr-Thr (or YT in single letter abbreviation)
14935
its DNA it is a part of a gene which is a thing wich codes for something. it is a double stranded structure. its also called a polynucleotide.
216027
If you are doing PCR and you make a particular product using two primers A and B, the nested primers C and D will be within the sequence of the A and B product.  \n\nthe sequence will look like:\n\n. . . A. . . . C. . . . D. . . .B
181048
deoxyribo nucleic acid
374804
Consider a regular climbing ladder.  If the ladder was sawed in half by sawing each rung crosscut thru the middle than each half of the ladder would represent one  DNA strand.  Each new organism receives a single strand from each of it's parents.  The two strands join to make the new organism's double stranded DNA.  The rail or sides of the ladder would represent the sugar and phosphate link backbone of the DNA.  The sawed rung would represent the nucleic acid bases.  The bases are classified as either purines or pyrimidines.  The two purines are Adenine (A) and Guanine (G) which are similiar to the compound Purine.  The two pyrimidine bases are Thymine (T) and Cytosine (C) which are structured similiar to the compound Pyrimidine.  In RNA Thymidine is replaced by Uracil.  The collective term for these structures is "nitrogenous base".  Each base contains either/or hydrogen (h), nitrogen (n) and oxygen (o) atoms located on the structure where the "cut" would exhist on the sawed ladder rungs.  When these bases move close together there is an attraction between these atoms and a bridge forms called a hydrogen bond  or h-bond.Thymine has an o and a h.  Adenine has a h which is attracted to T's o and an n which is attracted to T' h. A and T always h-bond or pair.  Cytosine has an h,n,and o.  Guanine has two h's and an o.  one h on guanine is attracted to the o on cytosine, the other to the n.  The o is attracted to the h on cytosine.  Therefore C always pairs with G and is held together by three h-bonds, where A and T are paired by two h-bonds.  In total the h-bonds strongly bind the two DNA single strands together but one at a time they can be broken to seperate the strands much like a zipper opening link by link.  Since C always pairs with G their proportion is is always the same.  The same is true for A and T.  Each Dna single strand has what is called a 3' (three prime hydroxyl) and a 5' (five prime phosphate) end.  When the two single strands pair to form thd Double strand they Form with the 3' end of one strand joining at the 5' end of the other strand.  This is known as antiparallel since they are running in opposite directions.
413902
A chromosome, cosisting of a strands of DNA, or Deoxy ribose nucleic acid, is composed of a double sided chain of proteins known as nucleic acids. These acids, Adenine, Guanine, Cytosine and Thiamine may bond with any other nucleic acid in the ribs of the "ladder" of the DNA strand, but can only bond in certain pairs to form the "steps" of the ladder. Guanine only bonds to Cytosine, and Thiamine only bonds to Adenine. In the RNA molecule, which consists of only one "rung" of the "ladder", Thiamine is replaced by Uracil. Sets of these nucleic acids are what determines the traits expressed, "phenotypically", in the organism.
563152
Restriction enzymes, also called restriction nucleases (EcoRI in this example) , surrounds the DNA molecule at the point it seeks(sequence GAATTC). It cuts one strand of the DNA double helix at one point and the second strand at a different, complementary point (between the G and the A base). The separated pieces have single stranded "sticky-ends," which allow the complementary pieces to combine. \n\nThe newly joined pieces are stabilized by DNA ligase.\n\nEcoRI, one of many restriction enzymes, is obtained from the bacteria Escherichia coli.
887935
The DNA is linked by the 4 bases G,C,A,T \nG and C pair together and A and T pair together they are held together by hydrogen bonds. G and C have 3 hydrogen bonds A and T have 2.\nThese form the double helix which is the DNA structure.
57795
DNA is a chain of chemical "building blocks", called "bases", of which there are four types: these can be abbreviated A, T, C, and G. Each base can only "pair up" with one single predetermined other base: A+T, T+A, C+G and G+C are the only possible combinations; that is, an "A" on one strand of double-stranded DNA will "mate" properly only with a "T" on the other, complementary strand;\n\nA= Adenine\nT=Thymine\nC=Cytosine\nG=Guanine\n\nI got this from wikipedia
905906
It takes three bases of DNA to make one codon.  So it would take three phosphates, three sugars and three of C,T,G,A.  Google DNA Codon table if you want to encode a codon for a specific amino acid.
153709
Units of information in DNA are stored as hydrogen bonds linking base pairs of amino acids including thymine, cytosine, adenine and guanine.  Each base can only be linked to a single complementary base, for example, A+T, T+A, C+G or G+C.  The order, or polarity, of each base pairing is important (meaningful) in this context.  Genetic information is determined by the sequence of base pairs forming a three-dimensional chain described as a double-helix.
843004
Use the standard Watson-Crick base pairing rules, with the change that A in DNA base pairs with U in the RNA. The anticodons in the tRNA will then base pair with the mRNA strand by the same base pairing rules:  G with C and A with U.
857765
In the monomer of DNA, the carbon number of deoxyribose sugar component (circular structured sugar with 5 Carbons) is marked as the first C binding to the Nitrogen base (A, T, G or C), and the 5th C binding to the phosphate group (PO4). \n\nThe 3' and 5' is called basing on the 3rd and 5th carbon in the deoxyribose molecules. DNA polymerization is like this: and individual monomer's phosphate group (which is bound to the 5th C) is added to the 3rd C of the previous monomer in the polymerized chain. The polymerization only occurs in this direction, no reverse direction (no addition of 3rd C of an individual monomer to the phosphate group bound to a monomer in a polymerized chain. That's why they say the DNA polymerization is in 5' to 3' direction.\n\nYou can go to this link to see a picture of the monomer structure and the polymerization: http://cmgm.stanford.edu/biochem/biochem201/Slides/DNA%20Structure/004%20DNA%20Covalent%20Structure.JPG
752227
Non-overlapping: Each triplet in DNA specifies one amino acid.  Each base is part of only one triplet, and is therefore involved in specifying only one amino acid \nEg.AUC CGA ACU AGC\nOverlapping code: as the code is read in blocks of three, it will only move up one base at a time, rather than three bases at a time, like the non-overlapping code\nEg. AUC UCC CCG CGA GAA AAC ACU CUA AGC \n\nOr to put it simply non-overlapping code means adjacent triplets do not share a base
691341
A DNA nucleotide ia made up of:\n1- phosphate \n2- deoxyribose sugar\n3- one of the 4 nitrogeneous bases: adenine, thymine, cytosine or guanine.