How many rads/s is 45 rpm equivalent to?
100448
There are 2 x pi radians per revolution, by definition of radian.  So \n\n45 rev./min x 1 min/(60 s) x 2 PI rad/rev =4.71 rad/s
229898
it is exactly 299,792,458 meters per second\n\nor 299,792.458 km per second
1071909
roughly 11 meters per second, or 24 miles an hour.\n;o)
341657
OK, you are right, there are 2(pi) radians in a circle and spinning 10 times is 20 radians.\n\nYour angular velocity is the rate the mass (the clothespin?) spins within a given time. You give 10 revolutions in 5 seconds. or you can say 2 revolutions per second or 120 rpm (revs per minute). Multiply that by 2 to get radians per minute. \n\nAngular acceleration doesn't seem to be considered here since you say the mass has spun 10 times at a constant rate (or speed). So, in what you are asking, the length of the string (the radius of the circle of which the mass spins - your half a meter) Does not come into play here.
818883
Es = L*r*w (w=2piN) , N=600 rpm=10rps , L=9 \nEs = L*r*2pi*N) , N=10, L=9 \nEs = 9*0.18*2*3.14*10\nEs (Shaft Energy)= 101.734 Newton/second which is not a unit of power.\n\nPlease specify the units of r,Es,L=95 or 9 ?\nWhat is the unit of Ee? HP or KW?\nfurther you have given following data which are contradictory.\nPump Shaft Speed =1200 ?\nEe (Electrical Energy) = 67.2\nT = 1.62\nw (Rotational Speed)= 62.8
621554
45= 1/2(2x-x)\n45= 1/2(x)\n90=x
819223
If I understand correctly, one revolution of the disk is equal to one period.  You need to know the time (T) taken for one period.\n\nFrequency (f):\n f = 1/ T\n T = 1/ f\n T = 1/ 2200\n T = 0∙000 454 545....\n T ≈ 454∙454 µs\n\nAngular speed (w):\n w = Θ/ t\n w = 2π/ 454∙454 x 10^-6\n w = 6∙283 185 307.../ 454∙454 x 10^-6\n w = 13823∙007 68...\n w ≈ 13,823 rad/s\n\nIf the period is 20 for one cycle then:\n w ≈ 13,823 / 20 rad/s\n w ≈ 691∙15 rad/s
126757
45\nYou need a number that is the 2 power of a whole number and falls in that range.
439730
107.23 mph.  Do I get 10 pts?
1007024
distance equals rate times time\nThat is,\nd = rt\nd = 117 and t = 2.25\nSo we have\n117 = r(2.25) or\nr = 117/2.25\nr = 52 mph
1145904
52/700/80=Max write speed 5200 rpm\n700MB storage\n80 minutes music play\n40=Max write 40000rpm\nAny time you wish to have the best quality CD Burn, use a little slower speed than your burner supports.\nIn any event if you have a 40,000 ROM MAx Burner, and put a 52,000RPM CD, you should not have to change anything.
818461
45 (if you count today)
272252
Do you mean a certain rpm?\n\nrpm -i [name of rpm]
75525
a) 72.072 cm/sec^2\n\nb) 82.63 cm/sec^2
17281
The answer is 15 to 45 miles per hour
812026
a) There are 2pi radians in a revolutuion\nThe angular speed in radians pers sec is simply 2pi xRPS\nwhere RPS is the number of revolutions per sec (1RPS = 60RPM) \n\n2400x2pi /60 sec = 251.33 radians per sec\n\nb) The circumference = pi Dia =  23.562 in = 23.562/12 =1.9635ft\n The speed of the saw teeth is 2400/60 = 40 RPS (x 19635 ft) =78.54 ft/sec\n\nJust a note about angular speed:\nThe angular speed is the answer to the question: how many times does it rotate in a given amount of time? This can be expressed in radians per sec, RPS or RPM etc.\nThe speed of the teeth (or of some other point on the blade) is the answer to the question: What distance do the teeth travel in a given amount of time, for a given RPS, RPM etc.?\nIf you take a disk, or circular blade, and draw a radial line on it and then give the disk a certain RPM then the points on your line will have the same angular speed, since different points on the radial line will all travel 360 degrees(or 2 pi radians) every revolution. But the points will be travelling at different speeds. Points at the edge of the disk will have the greatest speed since they travel a greater distance (i.e. a greater circumference) per revolution than points which are closer to the center of the disk. So the teeth of the saw will have a greater speed than points on the blade which are closer to the center, but they all have the same angular speed.
1055461
45/360....THATS THE RATIO CZ THE WOLE CIRCLE SUBYENDS A 360 ANGLE WHILE THE ARC SUBTENDS A 45 ANGLE SO THE RATIO OF THE ARC TO CIRCUMFERENCE IS 45/360