Can someone help me with my Algebra 2 homewok?
103303
All it is, is solving a function within a function.\nThe first thing you need to do is take the g(x) function and plug 3 in for X. The answer you get is 15  (if I read your equation correctly. I read it as: 2x squared - 3)\nSo now thats you know g(x) = 15 you plug 15 in for your X in the function f(x). You get: 49. That's you answer.\n\nNote: If I read your equation incorrectly then just follow these steps:\n1. Solve the Function g(x)\n2. Take that answer and plug it into the Function f(x)\n3. Viola! Your answer.\n4. Check out my homework help question, to see if you can help me. :P
510279
Jimbo, you gave up too soon......\n\nV = L*W*H = L*W*x in this problem\n\nV = (6-2x)*(4-2x)*x\n\nV  oila!
1142710
Use this formula, you can find millions of them\n\nL x W = 2(L + W)\n\nuse any number for L and solve for W
695328
(1) add row#1*6 from row#2, then from row#3\nthat is [–6+1*6, –47+6*6, -2+1*6] for row#2\nthat is [-6+1*6, -41+6*6, 2+1*6] for row#3\nthus:\n1……6……1       \n0…..-11…..4\n0……-5…..8\n(2) add row#2*(-5/11) from row#3\nthat is [0, -5+(-5)*(-5/11), 8+4*(-5/11)] for row#3 \nthus:\n1……6……1       \n0…...-11…..4\n0……0….68/11\nto check the result multiply main diagonal: 1*(-11)*(68/11)=-68
880421
2.8-3w=46-w\n2.8=46+2w\n-43.2=2w\nw= -21.6
106436
I followed bugzpodder's advice.  Here's the formula I came up with. \n\n - 778728 - 121373345554191121 / 217945728000 * n^4 + 1298728131310487 / 1009008000 * n^3 + 670835515657 / 360360 * n + 2210058967013 / 12830400 * n^5 - 113499324114761 / 2874009600 * n^6 + 8961501223669 / 1306368000 * n^7 - 66868104743317 / 73156608000 * n^8 + 85853565361 / 914457600 * n^9 - 121097474346419 / 60540480 * n^2 - 27139677827 / 3657830400 * n^10 + 1792199 / 4009500 * n^11 - 1158076427 / 57480192000 * n^12 + 12283303 / 18681062400 * n^13 - 7672127 / 523069747200 * n^14 + 261523 / 1307674368000 * n^15 - 13147 / 10461394944000 * n^16\n\nCheers
701654
Instead of memorizing all the equations,understand how they are derived.Try to do it yourself.If you can't go to someone who knows for help.
740569
1) L = 4W\nA = LW = 20\nSubstitute L = 4W to get 20 = 4W x W\n20 = 4W^2, divide both sides by 4 to get\n5 = W^2, take square root of both sides to get W\nW = √5\n\n20 = L x W\n20 = L x √5, divide both sides by √5 to get L\nL = 20/√5 or, when rationalized, 4√5\nFinal answer:\nL = 4√5 and W = √5\n\n----\n\n2) L = W + 4\nA = 6 = L x W, substitute L = W + 4 to get\n6 = (W + 4) x W\n6 = W^2 + 4W, substract 6 from both sides to get\n0 = W^2 + 4W - 6\nThis is not easily factored, so you'd have to use the quadratic equation to solve for W. Once you have W, just plug that in to L = W +4 to get the L value. Good luck!
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
515516
goto purple math.com it will hopefully help you
175207
Next time use ^2 instead of typing out "to the 2". Anyway, write it in standard form, so that the variables are in descending order.\n\n14w^3 + 49w^2 - 8w - 28\n\nYou can't factor this. If it was 7w instead of 8w, then you could factor out a 7 by dividing all the coefficients by 7 and pulling it outside the parentheses. Alternatively, you could factor the first two terms separately from the second two:\n\n7w^2(2w + 7) - 4(2w + 7)\n\nNow it's in a great form for factoring. Group them.\n\n(2w+7)(7w^2-4)\n\n---\n\nDo the same thing for the second example.\n\n44t^3 - 4t^2 + 66t - 6\n\nFor this one, you can factor out a 2.\n\n2(22t^3 - 2t^2 + 33t - 3)\n\nOr, again, you can factor the terms separately:\n\n4t^2(11t - 1) + 6(11t - 1)\n\nGroup.\n\n(11t-1)(4t^2+6)\n\n\n\nHope this helped.
610160
http://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/\n\nhttp://www.math.armstrong.edu/MathTutorial/
330568
ask a question! I can help! maybe... yeah, pretty sure I can, I'm in Algebra 2!
998009
You need to use the distributive property where:\n8(4w+x-6y)=\n8(4w)+8(x)-8(6y)=       \n32w+8x-48y
791337
1) (1/2 i+2bj) - (bi-b^2 j) + ((7/2 +b)i-bj) = 4i+20j\n\nNow separate the equation into two equations.\n\n1/2 i - bi + (7/2 + b)i = 4 i\n2bj + b^2 j - bj = 20j\n\ni and j are no longer needed so get rid of them too\n\n1/2 - b + 7/2 + b = 4 => 0 = 0 (Not a big help)\n2b + b^2 - b = 20 \n\nb^2 + b - 20 = 0\n\nTime for the quadratic formula.\n\nb = (-1 +- sqrt(1 + 80)) / 2 = -1/2 +- 9/2 = -5, 4\n\n2) x = 1/2 i+2bj\n\nBasically you need to find where b makes the length of the vector equal to one. The Pythagorean Theorem helps here.\n\n(1/2)^2 + (2b)^2 = 1^2\nb = sqrt(3/4) / 2
128596
im great with algebra, ive been doing it for the past 4 years now non stop, email me and ill be more than happy to show you how to do it step by step and answer you questions\nzinger_38@yahoo.com
676730
Opening brackets \nLHS=SinA+ SinA. TanA+ CosA+ CosA.CotA\n=SinA+Sin^2A/CosA+CosA+Cos^2A/SinA\nGrouping\n=(SinA+Cos^2A/SinA)+(CosA+Sin^2A?CosA)\n=(Sin^2A+Cos^2)/sinA+(Cos^2A+Sin^2A)/CosA\n=1/sinA+1/CosA\n=SecA+CosecA\n\nEasy Pesy