64square root of 35 divide by 4 square root of 7?
107941
64(sqrt7*sqrt5)/4*sqrt7\n(64/4=16 and sqrt7 is cancelled)\ntherefore, the answer is 16*sqrt5
1037006
I am guessing 168 Ft. This doesn't seem right to me, and I'm not sure if I did it the correct way:\n\n                       7 \n*                      7 \n=             ----------\n                      49 \n ------------------------------         \n                       24 \n*                     24 \n=             ----------\n                     576 \n-------------------------------         \n                      49 \n*                    576 \n=             ----------\n                   28224 \n-------------------------------         \n                   28224 \nsquare root\n                     168
959978
use pythagorean thereom a^2 + b^2 = c^2. (c being teh longest side or the hypotenuse) the two legs are a and b. so you have the sq rt of 169. (sqrt of 12^2 + 5^2) which is 13
974343
√50 + √72 - √8\n√(25*2) + √(36*2) - √(4*2)\n√25√2 + √36√2 - √4√2\n5√2 + 6√2 - 2√2\n9√2
753032
7x - 4 = the number that is four less than seven times x
875144
you have to take the square root of each side, then just simplyfy\n\nx = 1.2472191289247
648650
Sometimes dealing with radicals is easier if you can recognize square roots.  If not, it sometimes helps to factor out the number to the point where you have pairs of numbers under a radical.  If you have sqrt(16), that's really sqrt(4*4).  Since you have a pair of 4s under a radical, you can take them out and write one 4 on the outside.  So for 4sqrt(16) you'd end up with 4*4, or 16.\n\nIt's not always that clean though - sometimes you'll have something leftover under the radical.  Take sqrt(125) for example.  sqrt(125) = sqrt(5*5*5).  Since you have a pair of 5s, take two out and put one on the outside the radical.  So sqrt(125) = 5sqrt(5), since you still have a 5 under the radical and no pair to get it out.\n\nLook at something like sqrt(248).  That's really sqrt(2*2*2*31).  A pair of 2s come out, and you still have a 2*31 inside.  So that equals 2sqrt(62).\n\nIt may take some practice.  I used to teach it by factoring out and pulling pairs out, but eventually you'll be able to see square roots and see that sqrt(200) = 10sqrt(2) by noting that sqrt(200) = sqrt(100*2) = sqrt(100)*sqrt(2) = 10sqrt(2).
393848
√7.99=2.82666 so it's between 2 and 3.\nyou can think about it as 7.99 being between 4 ( which is 2 squared) and 9 (which is 3 squared).\nDid you mean 7.99 or -7.99 because if you have meant -7.99 than its square root is not a real number so it cannot be between integers.
1087500
Just to complete to previous answer, in case it isn't clear:\n\nTo make it a perfect square you add (-b/2a)^2 to both sides.\nAs noted: \n(-7/2)^2 = 49/4\n\nStarting with:\nx^2 + 7x = -12\n\nAdd 49/4 to both sides:\nx^2 + 7x + 49/4 = 49/4 - 12 = 1/4\n\nFactor the perfect square:\n(x + 7/2)^2 = 1/4\n\nNow take the square root of both sides remembering that there are two roots (+ and -):\nx + 7/2 = +/- 1/2\n\nSo there are two equations\nx + 7/2 = 1/2  or x + 7/2 = -1/2\n\nSo x = -3  or x = -4
373728
Some folks seem to have forgotten this is a quadratic, and they have two (2) roots!\n\n(x - 7)^2 = 64\n\nx - 7 = ± 8 (take the square root of both sides)\n\nso \n\nx = 7 + 8 = 15 \n\nor \n\nx = 7 - 8 = -1\n\nyou could expand this out and use the quadratic equation to solve it as well:\n\nx^2 - 14x + 49 = 64\n\nx^2 -14x - 15 = 0  a = 1 b = -14  c = -15\n\nthe rest is left to the student as an exercise. :^)
879678
The first thing to do is to find the factors of the number you're taking the root of.\nFor example, teh factors of 24 include 2*12, 3*8, and 4*6.\nSince four is a perfect square (2^2), we'll use that set of factors.\nSo:\nsqrt(24)= sqrt(4*6)= sqrt(4)*sqrt(6)= 2sqrt(6)\n\nSame with sqrt(18):\n18=9*2\n9=3^2\nsqrt(18)= sqrt(9)*sqrt(2)= 3sqrt(2)\n\nsqrt(3) +sqrt(3) can only be reduced by realizing that it's\n2*sqrt(3), which could be the sqrt(12). THis is because you can take the two under the radical by squaring it. so  you get sqrt (2^2+3)= sqrt(12), but technically 2sqrt(3) is more reduced.\n\nsqrt(27)=3 sqrt(3)\nsqrt(12)= 2 sqrt(3)\nso 3sqrt(3) + 2sqrt(3) = 5sqrt(3)\nin this case, you're treating the sqrt(3) sort of like it was a variable. think of 3x +2x = 5x
276368
convert the fractions so they have common denominators:\n\n4/7 = 20/35; 2/5 = 14/35\n\n20/35 + 14/35 = 34/35
1006110
42 - 7 * 2^2 + 3 * sqrt(25)\n= 42 - 7*4 + 3*5\n= 42 - 28 + 15\n= 29
545599
subract 32 then divide by 1.8 (or mulitply by 5/9 --- same thing)
792411
put y = 7 and x =4 and solve for c\nwe get 7 = 16+c or c = -9
141530
Steps:\n1) Divide by 2\nx^2=32\n2)Find square root\nx=sq.rt.32\n3)Simplify Radical\nx=sq.rt.(2)(16)\nANSWER:\nx=4+sq.rt.2\n\n*=times
700498
Is something missing here? If you just want 4*sqrt(81)\nthe answer is 4*9 = 36