If X can do a job in4days that Y can do in6,and Z can do in2,howlong would the job take if XYZ workedtogether?
115782
OK, let T be the time (in days) that the job takes.  You know that x can do one fourth of the job in a day, y can do a sixth, and z can do a half.  You have one job to do.  so the equation is set up:\n\n1/4T+1/2T+1/6T=1\n\n24 is a common denominator, so:\n6/24T+12/24T+4/24T=1\n\nNow add the fractions, you get:\n\n22/24T=1\n22T=24\nT=24/22, or 12/11 days (little better than 1 day)
496894
I don t think so .\nThey already had their day off last Monday and Tuesday !
725665
It depends on the program
786232
You need to figure out how much of the job a man does in a day.\n\n3 men take 2 days to finish a job.  So 1 man would take 6 days.  Stated another way, a man finishes 1/6 of the job each day.\n\nIf you have 2 men, then they would finish 2 * 1/6 = 1/3 of the job in a day.\n\nThe answer is 1/3 of the box.
641588
Depends on Qualifications.\n\nDOE - Depends on experience.
557994
It depends on how well you do on that particular day.
1052047
tools can b used 2 do a lot of works while a equipment is ment for a specific job
268467
it will probably take a day or two\nthank you
201899
If the other person works then 1. If you support them then 2
58601
It might, if you know how to work it ;)
541253
You can't generalize this. Every company, every hiring situation can be different. If they need someone ASAP, then they'll move quickly. If not, it could be days, it could be weeks.
917544
This type of problem is solved by finding the fraction of the job each, then both, can do in an hour.  If t = the hours for the faster person, she can do 1/t of the job in an hour, the slower can do 1/(t+2) of the job, and together they do 1/5 of the job in an hour.\n\nSo 1/t + 1/(t+2) = 1/5
399252
Like in the book of Job?
319866
WORK = force x distance  So you would need something the work would be done on. you would need to exert a force on it and someplace for it to go.
539329
yes , it would be possible and worth it. Depends on how strenuous your job is as well.....
244378
Here's a great formula. One does the work in A days and the other in B days. The number of days they will do the job if they work together being N,\n\nN=AB/A+B\n\nJim and Sue = (30x45)/30+45=18 minutes\n\nAll of them = (18x90)/18+90=15 minutes.... PS. 1 hr and 30 min is 90 minutes.\n\nThey can do the job in 15 minutes!
1062962
so Joe is taking 20 hrs and Fred is taking 32 hours. If these two are to be given work, then 20/52% should be given to Fred and 32/52% should be given to Joe to get things done in time ( I mean both finishes at the same time)\n\nSo Joe's portion of work would be 64% and Fred wil do 36% work...\n\nsimple !