A rock has a mass of 1.2 kg. If the rock is hung on a meter stick at the 5cm mark and the meter stick is .?
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Part (a): \n   Given three values (Mrock = 1.2 kg, Xrock = 5 cm, Xstand = 14 cm), and we need to solve for one unknown (Mstick).  To clarify, Mrock means mass of rock, and Xrock means position of the rock on the meter stick.\n   Since you're being tested on this concept, I'll assume you know the equation for torque: T = Force x Lever arm.  We will also use the concept of Static Equilibrium, which is a fancy term that means that nothing is moving.  Since this system is in static equilibrium, we can use the equation T(clockwise) = T(counterclockwise), using the stand as our pivot point (14 cm).\n   To find clockwise torque, we need to find the Lever arm from the center of mass to the pivot point.  The center of mass is located at 50 cm, and the pivot point is at 14 cm, so our lever arm is 50 cm - 14 cm = 36 cm.  T(clockwise) = Mstick * g * 36 cm  (It's okay to use units of cm in this problem because it cancels out in the end.)\n   If the rock is hung from a massless string, we can assume that the force on the meter stick from the string, which is the tension in the string, is equal to Mrock * g.\n   Counterclockwise torque: Lever arm = 14 cm - 5 cm = 9 cm.  Torque(counterclockwise) = Mrock * g * 9 cm (plug in numbers later to simplify calculation)\n   Torque(counterclockwise) = Torque(clockwise) ==>  Mrock * g * 9 cm = Mstick * g * 36 cm  ==> g's cancel, manipulate equation to get: Mstick = (9 cm / 36 cm) * 1.2 kg = 0.3 kg\n\nPart (b):\n   Since the stand is not causing the meter stick to accelerate upwards, it must be exerting a force upward equal to the force the meter stick exerts downward.  The total force from the meter stick is equal to (Mstick * g) + (Mrock * g) ===>  (Mstick + Mrock) * g ===>  1.5 kg * 9.8 m/s^2  ===> 14.7 N\n   I hope this helps (I'm a physics major...this should be a reliable answer)
202303
i will assume that you just asked how to find the mass of an object using a meter rule \nif that was the question it is simple\ntake the meter rule and hang it in such a way that it is in equilibrium i.e the scale is hanging horizontally\n\nknown hang the known mass on one side and hang the other mass on the other side\narrange in such a way that it is in equilibrium\nnow find the ditance of the known and the unknown mass from the position where the meter scale is tied and let it be a & b\n\nnow using the Principle Of Moments\n\nM*a=m*b\n\nhope it was helpful
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U can a measure the mass of an object accurately using a Physical Balance.\nUnit of mass is kg in SI unit ysstem.\nMore accurate ways of measuring mass is done now.\n\nU can calculate it's weight by a formulae:\nW=mg.\nW-Wieght\nm-mass\ng-aceleration due to gravity (9.8 ms^-2)
87964
1 kilogram is equal to 2.2 (2.20462) pounds.\nSo for each kilos you times it with 2.2
28535
Well, look at the units. The first one is a distance divided by a time; speed. The second one is in the units of energy (in the MKS unit system) the Joule. The "KE" also says to me that it isn't just any energy but, kinetic energy -- the energy that something has because it is moving.\n\nFrom these two bits of information you can deduce the mass of the object (if that's what you're talking about) in question.\n\nA very basic kinematic equation is the one that describes the relationship between the mass, velocity, and kinetic energy of something in motion.\n\nKE = 1/2 * mass * velocity^2\n\nsolving for the mass would be:\n\nmass = (2*KE)/(v^2)\n\nWhich is in the neighborhood of 2000 kg.\n\nhope that helps.
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Assuming the blocks were made from the same batch of iron, they would have the same density. So a 2-kg block of solid iron would have twice as much mass, weight, volume, and potential energy (if the block are the same distance off the ground).
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metric system\n1 kg= 1000 ml\n1 gm= 1000 mg
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convert them to kilograms
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F = KM1M2/r^2\n\nwhere K is the constant, M1 and M2 are the magnetic moments, and r is the distance between them.
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1m/0.4m = x/5m\n0.4x = 5\nx = 12.5
606827
The mass of the earth is 5,974,200,000,000,000,000,000,000 kg\nQuite heavy really.
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F = m*a \n\nm = 2 kg (two masses; two strings)\na = gravitational constant which happens to be 9.81 m/s^2 on the surface of the earth (or 32.2 ft/s^2 in EE units)\n\nsum the forces in the y-direction:\n\nT = F = 2 * m * a = 2 N\n\n(assuming massless strings)
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1 kilogram = 2.20462262 pounds\n1 meter = 3.2808399 foot
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On earth, mass and weight are equivalent, but in physics, it's more correct to use mass (since sometimes objects in physics problems are not on earth!)\n\nSo if the object weighs 1 kg, you can use 1 kg as its mass. One newton is the force needed to accelerate 1 kg (mass) at a rate of 1 meter per second^2.
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Weight:  2,223 kg  \nHeight:  5.3 meters \n\nInfo from site linked below.
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1 km = 1000 metres\n1 metre = 0.001 km
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The stone is a unit of mass in the Imperial system of weights and measures used in the United Kingdom, Ireland, and most Commonwealth countries. It is equal to 14 pounds or 6.35029318 kilograms.