what is a factor in mathmatics?
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in a multiplication problem:\n\n2 x 3 = 6\n\n2 & 3 are factors, 6 is the product
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Prime Factors\nIn number theory, the prime factors of a positive integer are the prime numbers that divide into that integer exactly, without leaving a remainder. I have made a table listing the prime factors for numbers up to 10.(It could be expanded to 2000).  To find the prime factors for larger numbers try the Prime Factor Calculator. \nn Prime\nFactors \n1 1 \n2 Prime Number \n3 Prime Number \n4 2x2 \n5 Prime Number \n6 2x3 \n7 Prime Number \n       8 = 2x2x2  (This the the Prime number of 8)\n9 3x3 \n10 2x5 \n\n\nHope that helped
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why don't you get a piece of paper and make a factor tree?\nlearn something yourself.
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first, factor out the 4..4[3x^2 -xy -14y^2].  now you need factors of the coeffecients...factors of 3 are (1,3)..factors of 14 are(1,2,7,14).  Now multiply in a way to get -1 for the coeffecient of the middle term.\n4[(3x-7y)(x+2y)].  When you use your foil method, you get the origional equation.
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(x+7)(x+3)\n(x-11)(x+2)\nforget this one.  its AC factoring though\nthis ones AC too
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(x+3)(x^2-x+4)/(x+3) common factor\n\nmultiply by x+3\n\nx^2-x+4
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2x is the largest possible factor, leaving:\n2x(4x^2-5x-7)
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Look in your text book under "factoring polynomials"... or you could try this web site that explains this fairly thoroughly...\n\nhttp://faculty.ed.umuc.edu/~swalsh/Math%20Articles/Factoring.html
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if you are asking for the factors,it is\n(x-15y)*(x+15y)
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ok... it's greatest common denominator would be:\n     w x^2 y^4\nSo you take that as a factor of the expression\n\nw x^2 y^4 (w^5 x - y^3)\n\nCynthia
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You need to determine 2 numbers that add to -11 (the x term) and multiply to -60 (the numerical term).  You can do it by formula, or by a little trial-and-error.\n\nThe answers are -15 and 4, so the equation factors:\nx^2 - 11x - 60 = 0\n(x - 15)(x + 4) = 0\n\nIn order for the total to be zero, at least one of the factors must be zero.  So your solutions are x = 15 (which makes the first factor zero) and x = -4 (which makes the second factor zero).
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factors of 24\n1, 2, 3, 4, 6, 8, 12, 24
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factors\n1=1\n2=2x1\n3=3x1\n4=2x2=4x1\n5=5x1\n6=3x2=6x1\n7=7x1\n8=2x2x2=4x2\n9=3x3=9x1\n10=5x2=10x1\nMultiples\n\n1=1,2,3,4,5,6.......\n2=2,4,6,8,10,\n3=3,6,9,12,15\n4=4,8,12,16\n5=5,10,15,20\n6=6,12,18,24\n7=7,14,21,28\n8=8,16,24,32\n9=9,18,27,36\n10=10,20,30,40
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This question! Isn't it under mathmatics? LOL!
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Well it depends on the problem specifically, but usually you have to find the ratio of "two corresponding lengths in two similar geometric figures."(mathworlds)  Actually that is what the scale factor is.
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The factor common to the first 2 terms in #1 is 3x^4 because both terms are divisible by that (take the GCF of the numbers in front, and the lower of the two exponents).\n\nFor the second pair, the common factor is 4\n\nSo you'd get 3x^4(3x + 2) - 4(3x - 2) if you have to actually factor them\n\nProblem 2, the common factor of the first 2 terms is 4x^3 and for the second pair, 1.\n\nSo you'd get 4x^3(5x + 4) - 1(5x + 4)  which becomes\n\n(4x^3 - 1)(5x + 4).
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A factor is something which is multiplied to a number. So reducing by a factor of 2 means "the opposite of multiplying by 2" - that is dividing by 2. Hope that helps...