how can we measure force?
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The standard procedure it to do a midichlorian count.
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The unit of force is the Newton (N).\n\n1 newton is defined as the force needed to accelerate a 1kg object at 1m/s*2.(from Newton's 2nd Law of Motion: F = ma)   \n\nSometimes it is given in its base units as kgm/s*2
53841
The last poster needs to have his dynamic physics retaught, or stop trying to sound like an engineer.\n\nThe first mistake, is identifying newtons = force x distance.  This is actually a measure of work or energy and measured in joules.  The second mistake identifying force as being measured in joules.  Force is measured in Newtons.  Since it was Isaac Newton in the second law of motion that defined Force.\n\nYour question cannot really be answered without more information.  What is the direction of motion, horizontally or vertically?  \n\nVerically?  Then 150 lbs of force.  Pounds were once used to measure force.  If you want to use metric, convert the 150 lbs to kilograms, multiply by 9.8 and then you must exert at least this much force in Newtons to overcome the force of gravity.  150 lbs is 68.04 kg.\n\nHorizontally, what type of surface?  Determine the coefficient of friction, and multiply it by the mass in kilograms.  Then this is the amount of force you need to exert to overcome the force of friction.  There are two types of friction, static and dynamic.  In other words it takes more force to move an object at rest, but once the object is in motion it takes less force to keep it move (opposing the dynamic force of friction).\n\nWatts by the way is a measurement of power, which is energy derived by time, Power = dE/dt.  Joules per second.
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Mass interacting with gravity
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Measure the weight of 1 cup of sand and figure it from there.\n\n :-)
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Force - Newtons\nMass - Kilograms\nAcceleration - metres per second
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The magnitude of a force is measured in newtons(N)
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The measure of force of gravity on an object(6 letters)\n--weight\n\nA unit that measures force(6 letters)\n--Newton\n\nthe rate of changein velocity(12 letters)\n--Acceleration\n\na chnage in position in a certain amount of time \nm_t_ _ n\n--Motion\n\nacceleration is 9.8 meters/sec/sec \n_ _ _ v _t_\n--Gravity\n\na force that is opposite to the direction of motion\n[_]_ _ _ t _ _ _\n--Friction
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The force of gravity of one object on another is given by the equation\nF = (GMm)/r^2\n\nWhere G is the universal gravitational constant, M is the mass of one object, m is the mass of the other, and r is the distance between the two.\n\nYou can see that the greater the mass of the two objects, the stronger the force of one on the other is.\n\nIn short, things that are more massive get a better tug.
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depends on the direction of the force
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Newtons, or sometimes kilograms
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In physics, a force is anything that causes a body with mass to accelerate. The net (or resultant) force is the sum of all the different forces acting on a body.\n\nForce is a vector quantity defined as the rate of change of momentum induced by the force, and therefore has a direction associated. The SI unit for force is the newton.
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opposite force being applied
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Two approaches that I can think of from a non-physicist.\n\n1. Simply a marker over how far back it physically recoils; or\n2. A spring scale fixed to a point that measures the peak force pulling back against it (you could also use a G meter if available).\n\nGood luck
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1) Measureing the height of ants in order to fit them out in a    tuxedo for the beetles wedding\n2) Disprove that individual atoms can be measured by using a micrometer (the best experiments sometimes don't support a theory but disprove it)\n3) Measuring toilet paper thickness to see if soft and thick is better than thin and strong.\n\nSafety when using a micrometer is paramount. Never, ever put your head inside the jaws of a micrometer unless it is less than the width of the jaws.
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since its you science homework the answer your more than likely looking for is Newton meter, now its up to you to find out what you can on it
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Read Newton's 3rd law of motion.\nAlso, use F=ma to figure out your acceleration.