what is the emperical formula of magnesium oxide?
106182
Actually its MgO. Magnesium is a bivalent metal Mg(2+) and Oxygen has a charge of O(2-) so they form a very strong 1:1 bond.
713170
K2CrO4 +Pb(NO3)2 ---> PbCrO4(s)  + 2KNO3\n\nNice yellow ppt.
387120
You're close.  To find out how much uranium oxide is formed you have to determine how many moles of each starting material you have available and which is the limiting reagent.\n\nU + O2-> UO2\n\nMoles U = grams U/molecular weight = 100g/238.03g/mol\n=0.42moles uranium\n\nMoles O2 = grams O2/molecular weight = 37.2g/32g/mol\n=0.156moles O2\n\nFrom the chemical equation; 1 mole U + 1 mole O2 yeilds 1 mole UO2.  So from the above calculations we can see that the amount of O2 is limiting.  Thus the number of moles of UO2 formed must be equivalent to the #moles O2 (because it's limiting).  You can then calculate the grams of UO2:\n\ng UO2= moles UO2 formed * molecular weight UO2\ng UO2 = 0.156moles * 270.03g/mol\ng UO2 = 42.12g\n\n\nTo fully oxidize 100g of uranium, the number of moles of oxygen gas would have to be equivalent to the # of moles uranium.\n\nFrom the calculations above, we know that 100g U= 0.42 moles\n\nSo the # moles O2 required for complete oxidation is 0.42 moles.  Therefore the number of grams O2 can be calculated by using the molecular weight of O2:\n\ngrams O2= #moles O2* molecular weight O2\ngrams O2= 0.42* 32g/mol= 13.44grams O2 required
1036462
Calcium oxide is component of one calcium atom and one oxygen atom. Therefore, if two of the atoms are combined together, they shall have the combined number of protons.\nCalcum Oxide has 28 protons and 28 electrons.
123634
http://members.aol.com/oelaineo/formulas.html
884578
Electron configuration of Magnesium:\n[Ne] 3s2\n\nThus it has 2 valence electrons.
846447
http://www.bbc.co.uk/schools/gcsebitesize/chemistry/classifyingmaterials/formulae_and_equationsrev4.shtml
850100
I'll do one for you and then you can try the rest.\n\nMagnesium has 12 electrons, so follow your filling order. Each s orbital holds to electrons and each p orbital holds 6, so its:\n\n1s2 2s2 2p6 3s2\n\nIt has 2 electrons in its outer shell so to have a full outer shell it will lose 2 therefore the common ion It forms is Mg2+
74307
The permanganate is reduced to Mn2+ and the oxalate is oxidized to CO2.\n\n2 MnO4- +  5 C2O42-  +  16 H+ =  2 Mn2+  +  10 CO2  +  8 H2O\n\nYou obviously know enough to ask the question so I'm assuming you can maneuver the numeric placements appropriately.  This forum does not allow me to sub or super set characters.
980544
1) MgCO3\n2) AlF3\n3) BF3\n4) NH4F\n5) SnO2\n6) HCL\n7) Ca(OH)2\n8) Na2S\n9) K2SO3\n\n1) do yo mean PbCl2? then Lead (II) Chloride\n2) Lithium Bromide\n3) Potassium Sulfate\n4) Megnesium Hydroxide\n5) don't know\n6) Hydrogen Nitrate\n7) Barium Phosphate\n8) Carbon Monoxide\n9) Copper Brimide\n10) Ammonium Chloride\n11) Tin (II) Hydroxide\n12) Calcium Nitrogide\n13) Strontium Oxide\n14) Tetraiodide prefix for 9 and oxide\n\nFe^+2\nNi^2\nAg^+1
763345
Let's say you want to know what is the formula of Aluminum oxide.\n\nYou know that oxides always have a negative 2 charge and Aluminum is always a positive 3 charge.  So if you have 2 positive 3 charges that would be a positive 6, and if you had 3 negative 2 charges that would be a negative 6 and that would allow the charges to cancel out to a zero.\n\nSo the formula would be Al2O3 for aluminum oxide.\n\nIn other words, the criss cross method of determining the formula uses the charge of the opposite ion to determine how many atoms to use.  It criss crosses.
729584
1)SO2, the sulfur, when it burns in air reacts with the O to form SO2. When Mg burns in air it reacts with the O and the N in the air and forms both MgO and Mg3O2. The product SO2 is a gas and MgO and Mg3O2 is a solid.\n\n2)It is ionic. Ionic bonds form between a + ion and a - ion. Na is + and F is -.\n\n3)P with O is covalent. Both elements are negative ions so they share. You need a + and a - to be ionic.\n\n4)No! Lots and lots of liquids. Some solids also.\n\n5)O and S are in the same groups because they both have 2 electrons in their outer shells. P and S are next to each other because they both have the same number of energy levels (3).\n\nGet an "A".
977270
first you need a balanced equation.\n\n2Mg+O2===>2MgO\n\nNext convert everything given to mols.\n\n10.000 g Mg X 1 mol Mg / 24.30 g Mg (NOTE: this number is from the periodic table of the Elements) = 0.4115 mol Mg\n\n5.267 g O2 X 1 mol O2/ 32.00 g O2 (this is the molar mass of O2)= 0.1646 mol O2\n\nAt this point pick one of the mols you calculated.\n\n0.1646 mol O2 X 2 mol Mg (from balanced equation) / 1 mol O2 (from balanced equation)(for every 2 mol of Mg there is 1 mol of O2)= 0.3292 mol Mg needed to react with all of O2\n\nSince more Mg is available then needed (0.4115 mol > 0.3292 mol) this implies that O2 is the limiting factor. \n\nUse the limiting factor (O2) to get the mass of the MgO\n\n0.1646 mol O2 X 2 mol MgO / 1 mol O2= 0.3292 mol MgO\n\n0.3292 mol MgO X 40.30 g MgO/ 1 mol MgO = 13.27 g MgO\n\nessentially for all the other ones you are doing the same thing as before but with different numbers.
734862
HgO ------> Hg + O2 at about 400 C\n\nMg + CuCl2 ---------->  MgCl2 + Cu(solid)\n\nMg, being higly electropositive than Cu, replaces Cu.
782516
a) 3SiO2 +2 Al --->3 Si + 2Al2O3\n\nb)AgNO3 +HCl---> AgCl +HNO3\n\nc) Mg + CuSO4 ---> MgSO4 + Cu\n\nd) Pb(NO3)4 +4 NaI --->4 NaNO3 + PbI4 (s)
867158
2Mg+O2-->2MgO\n2MgO+2H2o---->2Mg(OH)2
290781
MgSO4(s) + 2HCL(aq) ---> H2SO4(aq) + MgCl2 (aq)