Can you balance this chemical equation and tell me what type of reaction it is: H2O2 (aq) + MnO2 =  O2 + H2O (
116069
The balance is :\n\n     H2O2(aq) -> O2(g) + 2H+(ag) + 2e-\n MnO2(s) + 4H+(aq)  +  2e-  ->  Mn2+(aq)  + 2H2O\n \n Combine the two half-reactions and cancel on both sides yield the     complete balance equation.\n\n MnO2(s) + H2O2(aq) + 2H+(aq) -> Mn2+(aq) + O2(g) + 2H2O\n\n this is an oxidation-reduction reaction\ntype  decomposition reaction.
744922
HClO2 + Ba(OH)2 -> BaClO2 + H2O\n\n2(NH4)3PO4 + 3Ca(NO3)2 -> 6(NH4)(NO3) + Ca3(PO4)2\n\nFinished and balanced.
904934
2HNO3 + Mg(OH)2 -->Mg(NO3)2 +2H20\n\n2H+(aq) + 2NO3-(aq) + Mg+(aq) + 2(OH)-(aq) -->Mg+(aq) + 2(NO3)-(aq) +2H20(l)\n\n2+(aq) + 2(OH)-(aq) --> 2H20(l)
868500
Oxidation :\n\nCu > Cu+2 + 2e-\n\nReduction :\n\n2H+ + e- + NO3- > NO2 + H2O\n\nMultiply the 2nd equation by 2, you get the complete balanced redox equation :\n\nCu + 4H+ + 2NO3- > 2NO2 + 2H2O + Cu+2
651011
H2O2 + OC(NH2)2 -> HCOOH + NH4OH -> NH4(HCOO)
942601
2 (OH-) minus 2 e- = H2O + [O]....we have removed the a e- from each hydroxide(OH-) to give H20 and [O], this [O] shown in square brackets denotes nascent oxygen, which is produced during the reaction, this combines with another nascent oxygen to give us oxygen molecule O2\n\nhence a better reaction would be multiiplies the above by 2 \n\n4 (OH-) minus 4 e- = 2H2O + O2 balanced!
129663
Please do your own home work.\n\nI suspect you are missing a symbol, it probably should be,\nN2O4  <==>  2NO2\n\nThink about how each of the changes will effect the equilibrium of the reaction.
617758
Actually, all you need is:\n\n2 H2O2 ======> 2 H2O + O2\n\nif you have water on both sides of the equation, they "cancel" out.  Just like in algebra:\n\na + b = a + c  is the same as b = c
73319
the earlier equation is not balanced.\nCaO + 2HCl --------> CaCl2 + H2O
748741
2K + I2 -> 2KI\n\nBa + S -> BaS\n\nMgBr2 + MnI6 -> No Reaction\n\nC7H16 + H2O -> No Reaction\n\n2KI + Br2 -> 2KBr + I2
883220
H2+O2-->H2O\nNaOH+HCl-->NaCl+H2O\nKOH-->(on heating,deomposition)K2O+H2O\ni guess this is what u want\nand i f u didn't get it i am sorry......
825248
Basically it is\n\n2 H2O2 -> O2 +2 H2O,\n\nwith catalase written above the reaction arrow.\n\nA more detailed formula would show intermediary reactions of H2O2 with catalase, and then how catalase returns to the original state giving up O2 and H2O.
867182
6HCl +3 I2 + KClO3 --->6 ICl+ KCl + 3H2O\n\n\nMnO4 - +2 NO2- +4 H+ ---> Mn2+2 NO3- +2 H2O
677826
1) is already balanced... to be more precise\n2C2H6 + 7O2 --> 4 C02 + 6H2O\n\n2) Fe2O3 + (3)H2SO4 --> Fe2(SO4)3 + (3)H2O
918374
Fe2O3 -- Fe+O2\n\nthis is the balanced form\n\n2(Fe2O3)--- 4Fe+3O2\nwithout the parentheses
766259
4 NH3 + 3 O2 ---> 2 N2 + 6 H20
683249
Oh, come on, it doesn't get any easier than this!\n\nSnO2 + 2H2 --> Sn + 2H2O\n\nAbove is balanced. 1 Sn on both sides, 2 O on both sides and 4 H on both sides.\nYou need to work a little harder on these yourself.