What is the median value of the following series? 4,6,8,3,9,10,10,1,5,7,12?
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7\n\norder them; if you have odd number of entries, take the middle one; if even - take average of two middle ones.\n\n\n\nand it's a statistics question
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A box-and-whisker plot can be useful for handling many data values. They allow people to explore data and to draw informal conclusions when two or more variables are present. It shows only certain statistics rather than all the data. Five-number summary is another name for the visual representations of the box-and-whisker plot. The five-number summary consists of the median, the quartiles, and the smallest and greatest values in the distribution. Immediate visuals of a box-and-whisker plot are the center, the spread, and the overall range of distribution.\n \n\n\nThe first step in constructing a box-and-whisker plot is to first find the median, thelower quartile and the upper quartile of a given set of data. Example: The following set of numbers are the amount of marbles fifteen different boys own (they are arranged from least to greatest).\n\n18 27 34 52 54 59 61 68 78 82 85 87 91 93 100\n \n\n\nFirst find the median. The median is the value exactly in the middle of an ordered set of numbers. *\n\n68 is the median\n\nNext, we consider only the values to the left of the median: 18 27 34 52 54 59 61. We now find the median of this set of numbers. Remember, the median is the value exactly in the middle oa an ordered set of numbers. Thus 52 is the median of the scores less than the median of all scores, and therefore is the lower quartile.\n\n52 is the lower quartile\n\nNow consider only the values to the right of the median: 78 82 85 87 91 93 100. We now find the median of this set of numbers. The median 87 is therefore called the upper quartile. \n\n87 is the upper quartile\n\n(*If you're finding the median in an ordered set with an even number of values, you must take the average of the two middle numbers. For example: 3, 5, 7, and 10. Add the two middle numbers. 5 + 7 = 12. Divided 12 by 2 to get the average. 12 / 2 = 6. Therefore 6 is the median for the ordered set of 3, 5, 7, and 10.)\n\nYou are now ready to find the interquartile range (IQR). The interquartile range is the difference between the upper quartile and the lower quartile. In our case the IQR = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values, it limits the range to the middle 50% of the values.\n\n35 is the interquartile range\n\nplease review these pages.
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Mode is the number that occurs most often in a series of numbers.\nExample: 1223444456677789\n4 is the mode\n\nMedian is the number that is right in the middle.\nExample: 123445677788899\n7 is the median
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8,6.12,18,10,1,4,21,8,12,7,15
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8\n9\n7\n4\n4\n5\n7\n7\n9\n8\n5\n4\n8\n8
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Could be 10,14,13. The odd terms differ by 3 (eg. 4-1,7-4), the even terms differ by 4.
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I agree with the other answers here - I define the median as the mean of the two central numbers (when you're stuck in this situation).  Or, add the two numbers together, and divide the result by 2.\n\nHowever, math books have their own way of doing things, and I would suggest that you look at your book, checking the example, and see the answer they give in that situation.  Then do the same type of thing in this problem.
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First we compute for x using the mean value of the given array, that is:\n4 = [ x + 3 + (4x-3) + (x+4) + (-16) + 9 + (x-4) ] / 7\n28 = 7x - 7\n28 + 7 = 7x\n35 = 7x\nx = 5.\n\nPlugging the value of x to the original array, the observations now become\n(5, 3, 17, 9, -16, 9,  1)\n\nSince median is the middle value of the arranged observations or values in the given array, that is, it is the value that divides the given array into two equal parts. Thus, we then sort the given array in ascending order, that is:\n(-16, 1, 3, 5, 9, 9, 17)\n\nBecause we have n = 7 observations (which is an odd number), the median is computed as the (n + 1)/2 th observation in the ordered array. If we use the ordered array, the median is the 4th observation, that is \nmedian = 5.\n\n---\n\nNOTE: In number theory, a number n is said to be an odd number if it is not divisible by 2. That is, there exists an integer, say k, such that n = 2k - 1.
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There are three medians in a triangle, not just one.\n\na) is your answer.
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The median is another word for the number that is the middle number. When there is an odd amount of numbers, the one in the middle is the median. When there isn't, you take the mean (average) of the two in the middle. With this set of numbers, since there is 11, the median is 9.\n\nHope that helps!
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Range is the highest minus the lowest number of your data (in the above example, 15 -1 = 14 would be the range)\nThe mean is the average of all your data\nTo find the median yo have to order all the numbers and the central one is the median, for example, 1 4 5 6 6 7 8 9 11 12 15\n7 is the median because is in the middle.\nThe mode is the one that repeats the most in the serie, in the same example 6 would be the mode...\nThere are some formulas for more complex set of data, if you need them let me know..
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Do you mean outliers? They're the numbers in your set that are completely different from the rest. Say you're looking at average salaries and your numbers are [ $1,000, $1,500, $1,000, $1,850, $1,650, $90,000, $2,000 ] $90,000 would be the outlier.\n\nMean is the average number. That is, all the items added up and divided by the number of items:\n($1,000+$1,500+$1,000+$1,850+$1,650+$90,000+$2,000)/7 \n\nThe mean is $14,142\n\nThe median is a number that separates the higher half of a sample distribution from the lower half. It is the middle value in a distribution, above and below which lie an equal number of values:\n\n1000, 1000, 1500, 1650, 1850, 2000, 90000\n\nSo the median is 1650\n\nIf you have two numbers as the median, you find the average of those two. (Add them up, divide by two.)\n\nThe range is the lowest number subtracted from the highest:\n90,000-1,000=8,000
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Arithmetic sequence:  1, 2, 3, 4, 5, 6, 7\nGeometric sequence:  1, 2, 4, 8, 16, 32, 64
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The first step to finding a median is arranging your numbers in order. In this case, it would be:\n109, 115, 119, 125, 142, 179\n\nThe number in the middle is the median. Since you have six humbers, there are two in the middle: 119, and 125. So, to find the median, you find the number between those 2 numbers, or 122.
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0!=1\n2!=2\n4!=24\n6!=720\n8!=40320\n10!=3628800
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Suppose you have a set of numbers:\n\n0, 1, 1, 2, 3, 4, 6, 8, 9, 11, 15\n\nThe median is the middle number when put in least to greatest: 4\n\nThis breaks your list into two halves: 0, 1, 1, 2, 3 and 6, 8, 9, 11, 15.  Your upper quartile is the median of the greater half: 9.  Likewise, your lower quartile is the median of the lower half: 1.\n\nIn the event you have two numbers for a median, take the average of the two and that becomes your median.  In the above example, if you only had 6, 8, 9, 11 for your upper half, your median would be the average of 8 and 9, or 8.5.\n\nAs for your second question (assuming that x belongs in the numerator):\n\n4/5 = (-9/4) - 7x/10\n4/5 + 9/4 = -7x/10\n16/20 + 45/20 = -7x/10\n61/20 = -7x/10\n61/2 = -7x\nx = -61/14
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6\n\nYou are putting the single digit numbers in alphebetical order:\neight, five, four, nine, one, seven, six, three, two, zero