if a balloon travels in a  straight line will it travel the same way as the 45 degrees?
108121
This question makes absolutely no sense and is in dire need of clarification.
104839
When an object is launched under the influence of only a uniform gravitational force field, it is said to follow a projectile motion. Under ideal condition, the path it traces is parabolic. There is catch here – if the initial velocity is equal or more than the escape velocity then the object will simply vanish into space i.e. leave earth!\n\nImagine if the launch angle from the horizontal is “theta” and initial velocity is “U” then you can easily compute vertical (Uv) and horizontal (Uh) components of it. The Uv will be equal to U x Sin(theta) and Uh will be equal to U x Cos(theta). Now by using Uv you can compute the max height it will reach and the total time it will take to go up and return to ground. With this round trip time in hand, you can easily compute the max horizontal distance it will cover before hitting the ground.\n\nAll these calculation assume ideal conditions like no wind resistance etc.
44361
Wind direction/resistance would be a factor, but if we disregard the wind and the planes are running at the same airspeed, the one heading westward would theoretically have a shorter flight.  This is because the Earth's rotation is eastward.  So as the plane flies westward toward it's destination, that city is also moving eastward toward the plane.  The opposite is true for the plane heading eastward.  It's destination is also moving eastward away from the plane.  While there wouldn't be much difference, the westward plane should make the flight a little more quickly.
922775
If everything were lined up exactly inline and marble 1 hits 2 which hits 3, then both marbles 2 and 3 would move together at the same rate as marble 1.    (1~~>2~~>3)   You have probably seen that demonstrated with the newton's pendulum toy that has 5 chrome balls hanging by strings.   When you pull 1 of the balls back and let it swing into the other 4, 1 ball swings off the other end.  2 balls cause 2 to swing off the other end.\n\nIn your experiment, the 1st marble will hit the other 2 and release all of it's energy.  They will then go at the same rate as the first marble.\n\nV1 = 0\nV2 = 15.5 in a direction 60 degrees off to left.\nV3 = 15.5 in a direction 60 degrees off to the right.
90462
The wind always blows in the same general direction.  It usually blows from west to east, except between 30 degrees N. and S. of the equator. There, it blows from east to west.
430468
First of all the distance is 20 METERS and not 20 METERS/SECOND. Also the unit of acceleration is m/sec*sec and not m/sec.\n\nNow, there are both horizontal and vertical speeds. Also the position is a vector that has both a horizontal factor and a vertical factor.\n\nTo find the horizontal speed:\nInitial speed: 0 m/sec.\nAcceleration: 5m/s^2\n=> Speed2 = Speed1 + Acc.* Time\n=> After 1 sec. speed= 0 + 1*5=5m/s\n=>After 2 secinds speed = 0 + 2*5= 10m/sec.\n\nTo find the vertical speed:\nInitial speed: 0 m/sec.\nAcceleration: -9.8m/s^2 [acceleration due to gravity]\n=> Speed2 = Speed1 + Acc.* Time\n=> After 1 sec. speed= 0 - 1*9.8=-9.8m/s\n=>After 2 seconds speed = 0 - 2*9.8= -19.6m/sec.\n\nTo find the horizontal position:\nDisplacement = (initial speed) * time + 0.5*acc.*time^2\n=> after 1 sec. displacement = 0 + 0.5*5 * 1 = 2.5 m\n=> position = 2.5 meters to the right of the initial horizontal position of the balloon\n\n=> after 2 seconds displacement = 0 + 0.5*5* 4 = 10 m\n=> position = 10 meters to the right of the initial horizontal position of the balloon\n\n\nTo find the vertical position:\nDisplacement = (initial speed) * time + 0.5*acc.*time^2\n=> after 1 sec. displacement = 0 + 0.5*-9.8 * 1 = -4.9 m\n=> position = 20[initial position] - 4.9 = 15.1 meters above the ground\n\n=> after 2 seconds displacement = 0 + 0.5*-9.8 * 4 = -19.6 m\n=> position = 20[initial position] - 19.6 = 0.4 meters above the ground
971582
it is one way (always +)\nwhereas other dims are 2 way (like + and -)\ni.e. distance=+50 km or -50 km\nbut time is always flowing in + direction
803366
Well, you know that 180 degrees is a straight line.  90 degrees is perfectly square (well, one corner of a square anyway.)  45 degrees is half of 45 degrees - it's a common angle to see in geometry class.\n\nTry using your protractor to draw out some common angles that will help you eyeball - 180, 90, 45, 75, 30, 10, etc.  Study these to help your estimation skills.  Best of luck!
128500
The object will follow a parabolic trajectory to the earth, as observed from outside the plane.  On the plane, it will appear to fall straight down in your (moving) frame of reference.  Air resistance will retard this motion, but it's magnitude depends on the drag coefficient of the object dropped and the medium in which it is falling.
613764
I assume you are wondering if the Earth's rotation will come into play here.  \n\nThe answer is yes.  This is the same as asking if a ball thrown in an airplane will land back in the person's hand.  Why is that so?  Everything in the plane is moving at the same speed, even the air molecules inside the cabin.  So, when the ball is thrown up, since it had the plane's speed before it was thrown, it will have that speed while going in the air, and since the air molecules are trucking along with everything else, they won't hinder the ball's motion.  \n\nIf you were to be able to watch the ball be thrown from outside the cabin, you would see the ball follow a curved parabolic path, where everyone in the cabin would see it go straight up and straight down.  You would see that curved path, because of the ball's horizontal motion due to the plane's speed.  Everyone inside wouldn't not see that, because they too are traveling with that same horizontal motion.\n\nSame thing applies here.  You share the same tangential speed as the Earth's surface, and so do all of the air molecules.  If you were able to jump for that long of time, you and everyone else around you would see you go straight up and straight down.  However, if you were being watched from space, you would follow a parabolic curve because of your tangential motion.
386243
yes the angle will affect trajectory and distance.  the best angle is 45 degrees
66389
Their navigation method relies on a light source at a great distance -- the sun or moon. If they are flying in a straight line, the angle between their direction of travel and the light source remains constant.\n\nWhen the light source is close, as they fly in a straight line, the angle changes. When they make a navigation correction, they start to circle the light source and spiral into it.\n\nTo see this, suppose at 8:00 tomorrow morning, you go out and walk keeping the sun 45 degrees to the left of your center. Since the sun is in the east, you will pretty much be walking southeast. You can go a long time before the movement of the sun causes you to change your course very much.\n\nThen find a lamp post, keeping it in a position 45 degrees left of center start walking. You won't get very far before you have to turn to your left to keep the lamp post at 45 degrees. As you continue to walk, you will spiral into the post.
439775
The plane is actually following the curvature of the earth, which only seems to look straight - exactly the way ships do.\nIF it would follow a geometrical straight line, it would actually increase altitude, leaving the sphere of the atmosphere, and make it look like a perpetuous climb (gain of altitude) to a LOCAL observer ...\nBut the so cold level-flight, is a question of keeping altitude, or keeping touch with a certain air pressure, which means a constant distance to the earths center of gravity, making the path a curve...\nSo, a plane is not flying a straight line - strict geometrically (and GLOBAL) speaking!
293083
45 degrees is the optimal angle to launch a projectile for maximum horizontal displacement.
145156
If you go in what you think is a straight line, no, you will never come to an end, or a wall, but it is very probable that you will actually be going in curves. Space is probably very warped, we already know that mass bends light.
706335
The density of helium is only one-seventh of the density of air at the same pressure, so when the balloon is stable, the other six-sevenths has to be accounted for by a combination of (i) the weight of the balloon fabric, and (ii) the tension in the balloon fabric keeping the helium at a higher pressure than the surrounding air.  There is no simple answer, but four miles would not surprise me.
795941
There is a little trick to this question, Alyssia. \nWe can try to use the ideal gas law to calculate the change in volume.\n P1V1 / T1 = P2V2 / T2  \n\nKeep in mind that temperature is absolute, not celsius, so T1 is 273.15 + 20 = 293.15 and T2 is 273.15 - 196 = 77.15\n\nSolving for the second volume, we get the equation V2 = V1 * P1/P2 * T2/T1.  \nSubstituting the given values we have V2 = 2.91 * 1/5.2 *  77.15/293.15\nTherefor the new volume might be .147 L.\n\nHowever, the balloon will loose all elasticity before reaching that temperature.  Therefor the actual starting and ending pressures of the gas INSIDE the ballon cannot truely have the same ratio as the starting and ending pressures outside the ballon.  For a real balloon, the answer is too difficult for me to calculate.  \n\nFor a theoretical balloon that keeps a constant elasticity, the answer is .147 L.