the length of a rectangular dog pen is 3times as long as its width /width is 8yards how many yards to finish?
115396
that makes no sense\nthe length is 24 yards though, and the area is 192 square yards..
673346
Think of a "foot ruler" (12 inches) - three (3) of those would equal 1 yard (that would be 36 inches or a "yard stick").  So if you are given 65 feet that would equal 21.6666 (or perhaps 21 and 2/3d) yards.  Divide 65 feet by 3 feet.
335828
The radius is half the diameter.\nThe diameter is twice the radius.\nd = 2r\n8 = 2r\nr = 8/2\nr = 4 inches
604460
Assume that the length is y cm.  Then the width is (y-3) cm.\nTo find the area, multiply length by width : y x (y-3).  But this is equal to 54 cm^2.\n\nSo, y x (y-3) = 54\n    y^2 - 3y  = 54\n    y^2 - 3y - 54 = 0\n\nSolving for y (using any method at your disposal (formula, completing the square, factoring), y = 9 or -6.  Obviously, -6 cannot be a side.  That leaves us with the length being 9 cm.  If the width is 3 cm less, that will be 6 cm.\n\nYou did ask for it to be explained.
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.
860533
long sides are 24ft and short sides are 9ft.\n\nArea = width x lenth\n216 = 24 x 9\n\nDimensions 24+24+9+9 = 66
541651
1meter=1.93613298yards\n1 yard=.9144 meters\nTherefore\n1 meter square=1.195990046yard square\n1 yard square=.83612736 meter square
688339
Let's say w is the width of the rectangle.  Then, the length will be w+5.  We know the perimeter is 58, and we know that the rectangle has two sides of length w, and two sides of length (w+5).  So...\n\n2w + 2(w+5)=58\n2w + 2w + 10 = 58\n4w + 10 = 58\n4w = 58 - 10\nw = (58-10)/4\nw=48/4\nw=12, the width of the rectangle.\n\nSince the length=w+5, the length is 17.
689736
11 year olds answer: i learned this in school a week ago, 36 inches since there are 3 feet in a yard and 12 inches in a foot, 1 yard=3 feet=36 INCHES! DUH!!!!!!!!
860398
Let W be the width of the pen (2 fences perpendicular to the barn).\nLet L be the length of the pen (1 fence parallel to the barn).\n\nWe know that 2W + L = 144\nSolve for L:\nL = 144 - 2W\n\nNow create a function for the area:\nArea = W * L\nArea = W (144 - 2W)\nArea = -2W² + 144W\n\nIf you take the first derivative and set it to zero you get:\n-4W + 144 = 0\n4W = 144\nW = 36\n\nThus the area will be maximized when the width is 36 and the length is 72.
906875
The trick is turning the word problem into equations.\n(Key: length = l; width = w)\n\nThey tell you the length is 3 feet more than twice the width, so:\nl = 2w + 3\n\nThen they tell you the perimeter (which is twice the width and twice the length) is 36, so:\n2l + 2w = 36\n\nYou should be able to take it from there.
879408
120(yards)x40(yards)=4800 square yards\n\nmultiply numbers first \nArea=length x width=120x40=4800\nmultiply the names, if the same, (convert to the same if the names differ) here we have the same names-- yards x yards = square yards\nif you have a question with (yards) x (yards) x (yards)=you get an answer in (cubic yards) and so on.  Good luck in math and thank you for asking.
225849
12 inches in 1 foot.\n3 feet in 1 yard.\n12 * 3 = 36 inches
598751
L=length w=width\n\nSo L=3w\n\nThe formula for perimeter is 2L+2W=P\nNow, you just plug in the variables and solve\n\n2(3W)+2W=64 --multiply 2 time 3W\n6W+2W=64    --add 6W and 2W\n8W=64    --Divide 8 on each side\nW=8\n\nWidth is 8 units\n\n--hope that helped
664383
ok...realize there are 12 inches in a foot and 3 feet in a yard\n\nso 1 yard * 3 feet/yard = 3feet\nso 3feet * 12 in/foot = 36 inches\n\npretty cool right!!\n\nhope this helped\n\nmatttlocke
804994
Let the Length of the side of the rectangle be x and the length of the side of the triangle is L\n\nThen when the rectangle is inscribed it is symmetrically placed (otherwise you would not get a rectangle). So the distance from its base vertices to the vertices of the triangle are each ½(L - x)\n\nThus the width of the rectangle = ½(L - x) tan 60°\n= √(3)/2 * (L - x)\n\nThus the area of the rectangle A = length * width\n= x * √(3)/2 * (L - x)\n= √(3)/2 * (Lx - x²)\n\ndA/dx = √(3)/2 * (L - 2x)\n= 0 for stationary points\nWhence L - 2x = 0 ie x = ½L\nd²A/dx² = -√(3) < 0 for all x Thus the curve is always concave down So the stationary point is a maximum.\n\nThus the length of the rectangle is ½L and the width is √(3)L/4\n(and its area is √(3)L²/8)
47718
So you've got an eight-sided figure and each side is 72-feet.  If you draw horizontal and vertical lines from each vertex (the angles where sides meet) to the other side of the octagon, you'll see that the octagon can be split up into one large square (in the center), four rectangles (up, down, left and right), and four triangles (in the corners).  You following me?  Get out a pencil and get to it!  Okay.  So what are lengths of your square's sides?  You'll note that the square has 72-foot sides, just like the original octagon.  Since you know how to find the area of the square, you're on your way.\n\nNext.  you have four rectangles, each with a length of 72-feet, but the short end - the width, how do we figure out the width of the rectangle?  Okay.  Look at your triangles.  Each triangle has one side of 72 feet - the side which is the outside of the octagon - and then two equal sides - it's an isosceles triangle with a 90-degree angle.\n\nOkay, time to call on pythagoras.  Pythagorean theorem states that a^2 + b^2 = c^2.  What that means is this: If you take the length of sides a and b (the ones we don't know) and square them, and add them together, the answer will be 72-squared (side C).  Too bad I'm not there with you to make this part easier to understand.  We know that a and b are equal in this case because our triangle is isosceles.  Therefore, 2x^2 is equal to 72^2.  This gives us a messy equation wherein our answer is, x is ROUGHLY equal to 51 feet.\n\nSo.  You have a square with sides 72 feet long.  You have 4 rectangles each with length 72 and width 51.  You have 4 triangles each with base 51 feet and height 72 feet.  You know that squares and rectangles have an area equal to length times width, and triangles have an area equal to one-half base times height.\n\nCalculate the area for your 9 figures and add them together.  THAT will be the square footage of your octagon.\n\nWhat... did you think I was going to do it ALL for you?