5x-4y=1;(-8,2)answer is y=5/4x+12 how is this figured out for an equation in slope-intercept form?
110363
If you put an equation in the form:\n\ny = m*x + b\n\nthen, \n\nm = the slope\nb = the y-intercept.\n\nIf you look for a parallel line that passes through a given point, then you keep the slope the same, and solve for the slope:\n\n5x-4y = 1   -->  y = 5/4x - 1/4\nthe family of all parallel lines is\ny = 5/4x + b  (for any value of b).\n\nFor a line passing through (-8, 2), plug the numbers in and solve for b:\n2 = 5/4*(-8) + b\nb = 12\n\nSo y = 5/4x+12 is a line with slope 5/4, passing through the point (-8,2).
162736
x-y=5\nx/5-y/5=1\nhence x intercept [5,0] and y intercept [0,-5]
91777
y=-6\n4x+y=2\n\nsubstitute -6 for Y\n\n4x-6=2\nadd 6 to both sides\n\n4x=8\nDivide both sides by 4\n\n\nx=2\ny=-6 (taken from above)
881909
No, I don't think you are right.  I assume this is a system of simultaneous equations and you're trying to find a solution set.\n\n4x - 12y = 5\n-x + 3y = -1\n\nFirst, multiply the second equation by 4 on both sides, giving\n\n4x - 12y = 5\n-4x + 12y = -4\n\nNext, add the two equations, giving\n\n4x-4x +12y -12y = 5 -4\n0x + 0y = 1\n\nThere are no solutions (x,y) for which this is true, so the solution set is the empty set.\n\nTaking the solution set you've determined, (5,0), putting that into the first equation gives\n4*5 -12 * 0 = 5\n20 -0 = 5 or 20 = 5, which is not true, so (5,0) cannot possibly be a solution.\n\nYou've made several errors, as follows:\n\n4x-12y=5  OK\n-x+3y= -1 OK\n\n-x=3y+-1 NO!, should be -x = -3y + -1 or x = 3y +1\n4(3y+-1)-12y=5 OK\n12y+-4-12=5 NO!, should be 12y -4 -12y = 5 or -4 = 5 \n0y=1 I have no idea how you got this\ny=0 NO!, if 0y =1, y is not 0, there is no y such that 0y =1\n-x=12y+5  I have no idea how you got this\n-x=12(0)+5 I understand how you got this, but y does not equal 0\n-x=0+5 OK\n-x=-5 previously you had -x = 0 + 5 , which was wrong but if it was right, you should get x = -5, not -x = -5\n\nOMG
743965
If you can find the slope, you use the formula\n\ny - y1 = m(x-x1) where y and x are in general and y1 and x1 are the x and y values from ONE point. Pick either, it doesn't matter. So...\n\nThe slope is -2.\n\ny - 8 = -2 (x - - 2)\n\ny-8 = -2x - 4\n\ny = -2x + 4
599677
i know how 2 do this.\n4x+2y=2\n x-2y=8\n---------\n5x   =10\n5x=10\nx=10/5\nx=2.\nsubstitute x=2 in any1 of the equations.\nlet us take x-2y=8.\n  2-2y=8\n  -2y=8-2\n  -2y=6\n    y=6/-2\n    y=-3.\n therefore ur x=2 nd y=-3.
1137447
2 linear equations\n\n X  + 3Y - 1 = 0\n4X + 7Y + 5 = 0\n\nFROM (1)   4X + 12Y - 4 = 0\nFROM (2)   4X +  7Y + 5 = 0\n\nSUBTRACT\n                          5Y - 9 = 0\n\n                          5Y = 9\n\n                            Y = 1.8\n \n  FROM (1)      X + 5.4 - 1 = 0\n\n                        X + 4.4 =   0\n\n                        X =  -4.4
887085
First, I multiplied the first equation by 2 and the second one by -5 in order to make it easy for me to cancel out both x's.\n2(-5x+7y=-40)\n-5(-2x+4y=-16)\n\n-10x+14y=-80\n10x+-20y=80\n\nNow, you can actually cancel out the x's and the constants at the end.\n\n-6y=0\ny=0\n\nNow you plug y=0 into one of the equations to find x.\n\n-5x + 7(0) = -40\n-5x +0 = -40\n-5x = -40\nx = 8\n\n(0,8) is the answer.
70526
=((-4y)^2)/(10y-5)= (16y^2)/(10y-5)\nand if the equation is equal to zero then y=4i
304476
y = x^2-5x\n0 = x^2-5x\n\nx^2-5x = 0\n\nx(x-5) = 0\n\nx = 0 or x = 5\n\nx-intercepts : (0,0) and (5,0)\n\nANSWER : two
1013948
Standard form for a slope intercept equation is:\n\ny = mx + b\n\nwhere m is the slope and b is the y-intercept.  So, transforming:\n7x + 4y = 20\n4y = 20 - 7x\ny = (20 - 7x) / 4\ny = 5 - 7/4 x\ny = -7/4 x + 5\n\nAnd\n5x + 6y = 19\n6y = 19 - 5x\ny = (19-5x) / 6\ny = 19/6 - 5/6 x\ny = -5/6 x + 19/6
695016
4x + 3y =12, find y = 4\n4x+3*4=12\n4x+12=12\n4x=0\nx=0
959550
x-5y=4, therefore x=4+5y and you plug that into the other problem to get 4(4+5y)+8y=-5, 16+20y+8y=-5, 28y=-21, y=-21/28 or -3/4, then plug -3/4 into one of the equations for y and solve for x, although I'm afraid it's been to long for me to remember the answer to dependant, independant, etc.
1136858
y + 1 = 2y + 5\nSubtracting y on both sides\n1 = y + 5\nsubtracting 1 on both sides\n0 = y + 4\nTherefore y = -4
560706
You need to get the y alone on one side of the equation. Subtract 5x from both sides and you get:\n-3y=-5x-3\nDivide each variable by -3 to get:\ny=(5/3)x+1\nNow you can graph using this equation.\nThe y-intercept is 1 and the slope is 5/3.\nHope this helps.
856807
Yes that will be correct because after you isolate the (y) in other words put it in slope inercect form it would be \ny=2x+4 \nm=2\nb=4
951394
x+y=4\nx-y=8.5\n\nJust add the 2 equations\n\nit will result to this one:\n\n2x-0y=12.5\n2x=12.5\nx=6.25\n\nusing x, we could get the value of y.just choose from the 2 given equations where you  could substitute x.\n\nx+y=4\n6.25+y=4\ny= -2.25