How do you write an equation for your trend line?
102416
after you've drawn your trend line look for the y-intercept (b)...then choose another point on the line to calculate the slope (m)...y = mx + b is the equation of the line of best fit
34052
I do not know a preprogrammed utility to do this, but can point you in the direction that you might need to go.  See the reference below for the math and an on-line converter:
1163751
If you are given the slope(m) and a point on the line(x1, y1) you can write the equation of the line.\n\nYou take the y-intercept equation\ny =m*x + b and substitute x1 and y1 for x and y and get\ny1 = m*x1 + b    \nnow solve for b\nb = (y1-m*x1)\nsubstite b = (y1-m*x1) into the y-intercept equation\ny =m*x +(y1-m*x1)\nsubtract y1 from both sides of the equation\ny -y1 = m*x -m*x1\nbecomes the point-slope formula\ny -y1 =m*(x-x1)
917786
most statistics follow a pattern, whether it be linear, quadratic, or whatever. Once you have enough data to establish a pattern, you can accurately predict the remainder of the line.\n\nFor instance, you have a line that looks to be half a parabola. Once it starts going back up, you can be pretty certain of where it's going to be.
466006
Pick a few easy points like pi/2, pi, 3pi/2, 2pi.  You know the period.  Then just graph it.
955392
an analysis, or a graph/chart/plot
365741
I think all you have to do is plug in a few values for C to get a graph.  For example, try 0, 5, 10, 15, 20.  It's continuous so you can connect the dots.\n\n(0,0), (5,87.5), (10,350), (15,787.5), (20,1400)\n\nTotal labor for 20 is 1400.
610991
http://www.cc.ysu.edu/~dmsewell/hwp.cgi\n\nDo the chart.
158569
Here is a tutorial...you can change any of the parameters that you mentioned and look at the graph as it is made and changed...really cool if you ask me.\nhttp://www.analyzemath.com/logfunction/logfunction.html
688944
View source of the that page.\nYou will see the formulas.
620893
The best way to work this out would be to plot a speed time graph for the information.\n\nOr you could express it as a simultaneous equation.
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
974937
please complete the equation
445014
(a) just substitute:  C = 10X + 40, where X = number of units produced.\n\n(b) It's a straight line with horizontal axis X and vertical axis C.  So, plot (0,40) and say, (5,90) and draw a straight line.\n\n(c) It's a straight line also thru the origin with a slope of 50.  Here, the vertical axis is R but it's the same scale as the C.  The line will go thru the points (0,0) and (1,50).\n\n(d) On the graph, it will be where the two lines intersect (1,50) or set the two equations equal to each other and solve:\n  \n     50R = 10X = 40  and 40R = 40  so X = 1
279461
MINITAB is free for 30 days, provides a reasonable graphical interface and has some good statistical methods.\n\nAlternatively use the excel add-in Analysis ToolPak from the 'Tools->Add-ins' menu. Then click  Tools->Data Analysis and use one of the methods there. (Moving average / exponential smoothing & regression are good simple methods for forecasting)\n\nThe best software is probably ForecastX Wizzard but is very expensive
164074
alright, finally a question i can answer, ok first of all u need some bivariate data (meaning data in the first two lists). exponential regression is going to find the equation of the line that best fits the data. on my calc there is linear regression (straight line), quadratic regression (parabola looking thing), cubic regression (cubic looking thing), quartic regression (weird looking parabola), and ooo i see what ur talking about. hmm i think its like finding an equation of the line then looks like an exponential equation. and example of this is graphing y=2^x. try that and u'll see what i mean
547680
I guess you need this for stock market prices?\n\nLet R_i be the daily price variations in percent.\nM = average of R_i \nVar = average of ( (R_i - M)^2 )\nSD = square root of Var