how can i get the molecular weights of coconut oil, sunflower oil, balm oil, groundnut oil....?
98572
Since vegetable oils are not pure materials, they will have varying molecular weights depending on the specific mixture of a sample of the oil.  I would recommend using Chemfinder.com and free MSDS resources on the internet to gather data.\n\nFor example, Chemfinder.com lists lauric acid as the primary ingredient of coconut oil.  Lauric acid has a molecular weight of 200.  This may be good enough for your purposes.
810837
Just remember glucose (C6H12O6). Then using the basics of balancing any chemical equation you can figure out the rest of it.
363124
detlaH=H(products) - H(Reactants)\n\n200KJ/mol
132596
if I understand the question:\nto go from cal/gK to cal/gC you'd convert the temp from K to C. that's simply subtract 273. degrees C = degrees K - 273.\nif you're trying to go from j/kg to j/mol you need to know the identity of the substance you're talking about. specifically you must know the molecular weight of the substance. first convert kg to grams(multiply by 1000) then divide by the M Wt of the compound.
239887
You can use Aldrich, which will give you a sample spectra of the compound. It would be very useful for identification based on a comparison of the fingerprint region (<900 cm-1)\n\nAny Organic book worth its salt will have typical vibrational frequencies. You can also do a yahoo search to get them.
491381
Fat=9.1KJ per mole\nProtein=5.4 KJ per mole\nCarbohydrates= 4.2 KJ per mole
852232
Pv = nRT\nn = m/M (M Molecular weight)\nPV = (m/M)RT\nP = (m/V)RT/M\nPM/RT = m/v = Density.\nPlug the numbers, watch the units and get the density.\n\nOh a numerical answer, yes, ...42.
83605
go to www.chemfinder.camsoft.com you can find that and so much more
807944
Confection Sunflower Kernel\nNutrient Composition per 1 oz. (28.35 grams)\n\nNutrient Amount(1) %DV(2) \n\nCalories 168 -- \nProtein (grams) 6 12% \nFat (grams) 14.5 24% \nSaturated fat (grams) 2 10% \nMonounsaturated fat (grams) 2.3 -- \nPolyunsaturated fat (grams) 9.7 -- \nCarbohydrate (grams) 6.5 2.1% \nFiber (grams) 3 12% \nCalcium (milligrams) 25 2.3% \nIron (milligrams) 1.2 6.4% \nMagnesium (milligrams) 36 9% \nPhosphorus (milligrams) 323 32% \nPotassium (milligrams) 137 4% \nSodium (milligrams) 116 4.7% \nZinc (milligrams) 1.5 10% \nCopper (milligrams) 0.5 25% \nManganese (milligrams) 0.59 --(3) \nSelenium (milligrams) 22 31% \nVitamin C (milligrams) 0.3 0.5% \nThiamin (milligrams) 0.091 6% \nRiboflavin (milligrams) 0.079 5% \nNiacin (milligrams) 1.171 6% \nPantothenic Acid (milligrams) 1.968 20% \nVitamin B6 (milligrams) 0.225 11% \nFolate (micrograms) 66 17% \nVitamin B12 (micrograms) 0 0% \nVitamin A (IU) 3 0% \nVitamin E (mg_ATE) 11.3 84%(4)
242955
very little to find on that, its hard to find for purchase too, but I did find this http://www.treelight.com/health/nutrition/CoconutOil.html
389126
You don't have to 'get' equivalent weights of substances, its very simple to calculate them.\n\nFirst of all, you need to calculate the molecular wt or know the atomic wt of the compound or element you're dealing with.\n\nThe general formula for the equivalent wt of a compound is \n\nEquivalent weight = Atomic or molecular wt/ x\n\nx has different definitions in different contexts:\n\nIf for an element, x is the valency\n\nEg- E.W. of magnesium = 24/2 = 12\n\nIf for an ion, x is the number of units of charge\n\nEg- E.W. of Al+3 ion = 27/3 = 9\n\nIf for a compund, x is the total amount of formal charge present on the cation/anion, i.e. the number of ions multiplied by the charge on each radical.\n\nEg- For NaCl, the value of x would be 1\n    For MgSO4, the value of x would be 2\n    For AlCl3, the value of x would be 3\n    For Ba3(PO4)2, it would be 6,...\n\nIf for an acid, x is the basicity(no. of ionizable H+ ions)\n\nEg - 1 for HCl, 2 for H2SO4,..\n\nThe same applies for a base, x is the no. of ionizable OH- ions.\n\nNow for KMnO4 (acidified or not),\n\nThe molecular wt is 39+55+64 = 158\n\nThe value of x is 1\nSo the E.W. is 158/1 = 158\n\nHowever, if you are interested in the E.W. of Mn in KMnO4, which is more relevant in redox reactions(using acidified KMnO4), calculate the oxidation state of Mn first. It comes out to be +7.\n\nSo the E.W. is 55/7
474909
Petroleum Products Yielded from \nOne 55 Gal. Barrel of Crude, 2004\nProduct Gallons\n\nFinished Motor Gasoline 19.65\nDistillate Fuel Oil 10.03\nKero-Type Jet Fuel4.07\nResidual Fuel Oil1.72\nStill Gas 1.85\nPetroleum Coke2.18\nLiquefied Refinery Gas1.68\nAsphalt and Road Oil1.34\nNaptha for Feedstocks0.67\nOther Oils for Feedstocks 0.55\nLubricants0.46\nSpecial Naphthas0.13\nKerosene0.17\nMiscellaneous Products 0.17\nFinished Aviation Gasoline0.04\nWaxes0.04\n\nTotal44.77
437270
According to this website that information is not readily available:\n\nhttp://www.newdirectionsaromatics.com/lican-p-289.html\n\nand this one:\n\nhttp://www.wellnaturally.com/essential_oils/lican_oil.html
980626
ChemDraw from CambridgeSoft Corporation may be help you. Look at www.cambridgesoft.com
794558
http://web.indstate.edu/thcme/mwking/lipids.html\n\nGood Luck!!!
778176
Use the periodic table of the elements.  The "weights" are in grams per mol.  Just use algebra and solve for the number of mols.  Then you know how many atoms there are by the number of mols which is a definite number.
28731
The molecular mass of a substance (less accurately called molecular weight and abbreviated as MW) is the mass of one molecule of that substance, relative to the unified atomic mass unit u (equal to 1/12 the mass of one atom of carbon-12).\n\nThe molecular mass can be calculated as the sum of the atomic masses of all the atoms of any one molecule. The molecular mass can also be measured directly using mass spectrometry. In mass spectrometry, the molecular mass of a small molecule (< ~200 atoms of a given element) is exact, that is, the sum of the most common isotopes of each element. Of larger molecules, it is average, or calculated using the elemental mass number or the periodic table, since there is likely to be a statistical distribution of atoms representing the isotopes throughout the molecule.