what is the cubed root of 128x to the 5y to the 13?
102099
(128x)^(1/3)^(5y)^(13)=\n\nMultiply all the power\n\n(128x)^[1/3*5y*13]=\n(128x)^(65/3 y)
795110
use the Power function\n\n=power(100,1/7)\n(proof - the value you receive "1.93069....."^7 = 100)\n=power(x,1/y)\n\nx=the number you want to find the y root of\ny=the root power
386376
My computer gives me this 4 real results, there are two more Imaginary results.\n\n1) -1\n2) 1.8698\n3) -0.260\n4) -2.688\n\nImaginary roots are\n\n5) 1.039 + j1.40\n6) 1.039 - j1.40
475059
4\ncubed root of 8 is 2. squared is 4. \nOr 8 squared is 64, cubed root of that is 4.
408271
take the cube root of 729 u get 9
623996
2y is equal to thirteen
103512
Actually, there's no compelling reason to rewrite the 7th root of z-8 as the 7th root of z-2^3. Here's why:\n\n(1) z-8 is a binomial, so you have to consider the expression as a whole: (z-8). Even if you had the cube root of z-8, you couldn't rewrite it as z-2^3 and then pull the 2 outside the radical to get 2*cube root of (z-1). That's not allowed. If z and 8 were multiplied that's a different story; the cube root of 8z does equal 2 times the cube root of z. However, addition and subtraction means if anything gets simplified the whole chunk has to be simplified. For instance, the cube root of (z-8)^7 does equal z-8.\n\n(2) In order to simplify a seventh root, you need a value in the radical that can be generated by multiplying something by itself 6 times, such as 2*2*2*2*2*2*2=2^7=128. You could simplify 7th root of (128z) as 2*7th root of z.\n\nLong story short, writing 8 as 2^3 really isn't simplifying any more than writing z as z^1 is considered simplifying z. You cannot reduce or simplify the expression at all.
41742
rt11guru said it.  here's another easy way.  write down the powers of two in *descending* order, starting with the one that is next smallest after your number.  for instance, the power of 2 that comes after 534 is 512 or 2^9.  so you write down this list of numbers:\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n\nthen go through and find the largest of these powers of 2 that is less than your number.  in this case, that is 512.  put a 1 underneath 512:\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n  1\n\nnow subtract that power of 2 from the number you started with.  534-512 = 24.  repeat the process.  find the largest power of 2 that is less than 24, which is 16.  put a 1 under that number:\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n   1  |        |        |      |      |  1  |    |    |    |\n\nnow subtract that power of 2 from your number.  24-16 = 8.  keep doing this until you've reached zero.  in this case it only requires one more step, because 8 - 8 = 0.  your table at the end should look like this:\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n   1  |        |        |      |      |  1  | 1 |    |    |\n\nnow, everywhere that is missing a 1, fill in a 0.  \n\n\n512 | 256 | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1\n   1  |   0   |   0   |  0  |  0  |  1  | 1 | 0 | 0 | 0\n\nthat sequence is your binary number.  in the case of 534, it is 1000011000.\n\n(sorry, this looks terrible.  can't format it properly in this yahoo window.  but, each one of those | in the bottom rows should line up with the | in the top row.)
168190
If you were to have the equations just as they are then 5x-3y would equal 7 not 13.  And 4x-3y would equal 5 not 11.  So try putting in -1 as y, then it will work out as you have it originally written.
1012665
if the multiplication involves the same radical, (squarel root, cube root, etc.) then that is equal to the product of the radicals\nie sqrt(5) * sqrt (2) = sqrt(10).\n\nif they are different radicals, then it is more difficult. the only way is to change the radical to the same radical through manipulation of the number/radical.\n\nfor example 4 * sqrt (2) = sqrt (4^2) * sqrt (2) = sqrt (16) * sqrt (2) = sqrt(32).
942305
Okay. You have a few things that you have to consider.\n\nNegative exponents: moves it to the denominator\nFractional exponents: the denominator tells you what the root is, the numerator tells you what the root is rasied to\n\nSo: (x+1)^-2/3 rewritten would be:\n\n1/[cuberoot(x+1)^2]\n\nwhen x is seven you have\n1/[cuberoot(8)^2]\n1/[2^2]\n1/4
1146202
It would be 0.5^1/3 (cube root of 0.5) which is approximately equal to .7937
413500
2.8284271. For that to equal 8, x would have to be 2. 2 cubed is eight and the square root of that is 2.8284271. Another way to express that is 2^(3/2) = 2.8284271, or the "square root of two cubed".
737743
The positive square root is 11.  The cube root is about 4.946 (it's not an integer).
128709
fourth root of 625=100\n121=11\nroot 16&#92;169=0.0236686 \n\nIf you like math you should be doing this right know
8473
7t+15 > 3t-13\n4t > -28\nt > -7
125377
509.7 OR 5.097 X 10 TO THE THIRD POWER