if the two bulb are connected to a 220-v line in series,through which bulb will there be the greater V drop?
116616
neither they are egual
749151
If the voltmeter is connected across the bulb, it measures the voltage drop (potential difference) across the bulb.. ie.. the voltage the bulb gets from the battery..\n\nIf theres only the light bulb in your circuit, then the entire voltage of the battery drops across the bulb... so the voltmeter will read 12V\n\nIf there is some other bulb or other appliance connected in series with this bulb, then voltage of the battery gets divided according to their resistances..\n\nIf there is a bulb in parallal with the bulb.. then both bulbs get 12V each because in parallel, the voltage remains the same\n\nGot It?
330950
actualy, i think they use the same voltage, but have a transformer on the batery to up the voltage to the needed amount. are you looking for the bulb, or a batery powered fixture. you use a standard bulb, you can find it anywhere florescant bulbs are sold. i have seen those fixtures at spencer's and places like that.
695376
The resistance of the filament of the lamp varies with temperature. When the filament is at room temperature the resistance is much lower than when it is white hot. \n\nCurrent = V/R. If the voltage is constant and the resistance increases, the current decreases.
1113253
Dude, \n\n   You have to reword your question. It really doesn't make much sense. Here's my interpretation of the question:\n\n"An AC voltage (230v/50Hz) is applied to a light bulb. If the frequency is reduced to 10Hz will the light flicker?"\n\nAnswer is yes. We do not see the 50Hz flicker, because of persistence of vision.
951468
There are a number of products on the market that will do what you want, and be certified and safe.\n\nMake sure you get a warm LED though: cool white LEDs produce a terrible colour of light.\n\nhttp://www.theledlight.com/120-VAC-LEDbulbs.html
655128
Assuming that we have 2 series resistors R1 and R2. And the voltage applied on them is V.\n\nTo get voltage applied on R1 (V1)= V * R1/(R1+R2)\nand so V2= V * R2/(R1+R2)
1082346
The "60 each" part of your question says you don't understand the most basic aspects of electricity.  Voltage is a measurement between two points.  Think of a 12V car battery.  It is 12 volts between the 2 terminals of the battery.  Another analogy:  two things that are 3 feet apart are 3 feet apart, not 1.5 feet each.\n\nDoubling 120 is 240, not 220, but I 220 is a commonly used number, like 110 for 120, but the standard voltages are 120 and 240.\n\nI think the point about doubling when you lose a neutral is talking about what is called a multiwire circuit.  The service into your house is the same, and some appliances like your dryer, have the same thing.  For a single phase case, a multiwire circuit has 2 phase (or hot) conductors and a neutral, with 120 volts between each phase and the neutral and 240 volts between the two phases.  This is created by a secondary winding on the utility transformer that is 240V, with a tap in the center which is grounded.  The tap is half way so it is 120V to each hot conductor.  If the neutral connection is lost, you still have 240V between the hot conductors, and all the 120V things in your house will be put in series.  For example, a couple light fixtures on 2 separate circuit breakers might be on the two opposite phases.  When the neutral is lost to the utility, there is still a connection of the neutral's of the lights, so you'll have the two lights in series and connected to 240V.  Each light will not have 240V though.  If the load on each phase were the same, removing the neutral will still leave 120V on each side.  That isn't likely, so one phase will get more than 120V (and generally cause damage) and the other phase will be less than 120V, and they will add to 240V.  It would be impossible for it to be so unbalanced that one phase would be 240V and the other would be 0.
927371
Voltage is analogous to the PRESSURE forcing water through a pipe, and electric current is analogous to the liquid FLOWRATE.  220 volts is twice the "electrical pressure" of 110 volts, so it would force twice as much electrical current (amperes) through an appliance as 110 volts would.\n\nAs other answerers have noted, the appliance plugs are usually designed so that you cannot do this by accident.
732838
If your referring to a black-out style outage where the issue was with a transformer, then there is no equation it is simply a outage where a piece of equipment called a transformer failed.  A transormer is simply a container with 2 coils of wire used to change or transform voltage from one level to another. If you have a power pole in your back yard , if you look at the top there is usually 1 or more "cannisters" with wires running from the power pole to the cannister to your house. That cannister is a transformer.  The power pole has anywhere from 2000-5000 volts on it and the transformer's job is to lower the voltage level down to either 240 VAC in europe and other countrys or 110 VAC here in the US.  This is called a step down transformer.  There are also others called step up transformers that raise the voltage from 110 up to levels as needed. \nNow, if that piece of equipment fails then no power can pass down the line and give you electricity in your house. If a large transformer that supplys power to the city fails,then that city (or portion of that city conected to that transformer) will receive no power until the transformer is fixed. \n\nFor a better explanation (or a clearer one ) read here:\nhttp://science.howstuffworks.com/power.htm
160858
WELL..IF YOU ARE GOING TO CHANGE A DISLEXIC TO ACCEPT ELECTRICITY OR A LIGHT BULB THEN YOU BETTER MAKE SURE EVERYTHING IS UP TO CODE...YOU WILL DEFINATELY NEED A 220 VOLT SERVICE CONNECTION..
250297
1.Current in the 385.451 V circuit is bigger.\n\nGod is spelled B-I-G B-A-N-G\n\nPBrax@netscape.com
530475
It depends on the rating of the breaker.  Common values for the maximum current in houshold lighting circuits are 15 and 20 amps.\n\nCurrent = power/voltage, so each 60 W bulb running on 110V draws 60W/110V = 0.545 amps.  You could run 27 of these on a 15 amp circuit and not blow the breaker (15 * 0.545 = 14.73 amps).  The 28th light would exceed allowable current.\n\nFor a 20 amp circuit, you could run 36 60W lights. (36*0.545amp = 19.64 amps)
718722
These are specially designed light bulbs that have had their light output calibrated to a standard source at NIST (or maybe some other standards organization). They must be operated at a specified voltage potential. They usually cost an arm and a leg, have a limited lifetime (the filament evaporates over time changing its characteristics and also plating the glass of the bulb with a thin film of metal) and are only as stable as the voltage/current supply you power it with. You must also take care to never touch the glass with bare skin or anything else that might deposit contaminants.\n\nYou also have to be very careful not to touch the glass with bare skin or any other contaminants.
929481
You need to wire them in parallel, with wire heavy enough for the total current and also have a battery that can deliver the current required at the voltage required without voltage drop.  You don't state the battery voltage or the lamp wattage, so I cant work it out for you!\n\n(I take it that you want EACH of the three bulbs to be as bright as one single one?)
702226
Its fault with the socket or the wiring. Check them out. You have not mentioned the voltage. Wattage matter in performance. Its only the Voltage & Ampere that matters for working.
215667
check ur connections and see if there are any loose wire or burnt bulbs