There are 10 kinds of people: Those who can count in binary and those who can't?
102924
that's 2. 10= 2. so i'm on the people who can count in binary.
85625
(A) 1000 (B) 1011 (C) 11011011 (D)11001110 \n\nA \n\nIf you translate each group of 4 from binary to decimal you get\n1000 = 8\n1011 = 11\n1100 = 12\n1110 = 14\n\nSince binary coded decimals represent the decimal digits 0-9 the only one that can be correct is (A) 1000
627773
1,2,5,10,20,50,100.\n\nSo that's 7.
160639
good 0, 3, 7, 4\n\n    bad 2, 9, 5\n\n    neutral 1, 8, 6
899443
39 can be devided by 3 people.  Scary.  \n\nBut you get the jist of what is a prime and a square from the other posts.
1178327
there are too many to count!
731003
ok.. um..if i remember correctly you would multiply 10 (the number of digits possible) x 4 (the number of digits) that makes 10,000 different possiblitiies... can i name them? probably...but wow.. that's a lot of time and energy.
1032678
As many or as few as they choose...
1185451
Its the numbers 0 through 10 in alphabetical order.
821305
a) effective or not - 2 choices - binomial\nb) smoke or note - 2 choices -binomial\nc) answers could be 1,2,3,4,5,6 . . .therefore NOT binomial
1096668
What ten types? Oh God, I only know about one!!!
309344
The many U can count!
428515
Binary numbers use only one (1) and zero (0). \n\n10 in binary is 2 in decimal.\n11 in binary is 3 in decimal.\n110 in binary is 6 in decimal.\n\n(Decimal numbers are normal numbers.)
900956
If you include combinations with no people and all people, the answer is 32 ways.  2^5.\n\n{ } = 1\n{A}, {B}, {C}, {D}, {E} = 5\n{AB}, {AC}, {AD}, {AE}, {BC}, {BD}, {BE}, {CD}, {CE}, {DE} = 10\n{ABC}, {ABD}, {ABE}, {ACD}, {ACE}, {ADE}, {BCD}, {BCE}, {BDE}, {CDE} = 10\n{ABCD}, {ABCE}, {ABDE}, {ACDE}, {BCDE} = 5\n{ABCDE} = 1\n\nThat's a total of 32 ways.\n\nAnother way to look at is to think that each person can be included or excluded.  There are two ways to include/exclude person A, two ways to include/exclude person B, etc.  That's 2^5 = 32.\n\nThis all assumes that ordering doesn't matter (that a combination of person A and B is the same as person B and A).\n\n(Note: if no people in the set is considered invalid, just subtract 1 and get 31).
873766
Lots of choices:\n6 boys and 21 girls\n9 boys and 18 girls\n12 boys and 15 girls\n15 boys and 12 girls\n18 boys and 9 girls\n21 boys and 6 girls\n\nWithout another piece of information (such as there are 3 more girls than boys, or twice as many boys as girls) there is no way to get a unique answer.
601128
9 Nonuplet\n10 Decuplet\n12 Dodecuplet
121013
if it is in binary, 1 + 1 = 10