Young boy walks 150 meters due east and then turns around and walks 30 meters due west?
100221
The total distance is just the total amount that he walks. So 150 + 30 = 180 meters. Displacement is where he ends up from his original starting point. Since he went 150 meters east from his starting point but then turns around and walks 30 meters back. It's 150- 30 = 120 meters away from his original starting point.
1030354
At the equator, the earth is approx 24,000 in circumference.  So, how fast can you walk? That's how long it will take.  HINT:  Go to the North or South pole and walk around in a little circle, then you've gone "around" all the longitudes of the whole world in a few steps.
532708
its a kilometer...1000 meters
1172735
Orthodics and leg exercises. Maybe even specially made shoes to correct the direction of his feet.
661447
The difference in rates is 1 km/hr. So if they are moving in the same direction, the faster walker will be 5 km ahead at the end of 5 hours.\n\nThe sum of the distances traveled per hour is 11 km. So at the end of 5 hours of travel in opposite directions, they will be 55 km apart.
250619
be patient.  boys do it slower than girls and keep up with it, don't stop just because he did.  he'll come around and if he doesn't contact his pedi.
363019
depends on where he is movin
314851
150 meters = 492.125984 feet
333415
Compass headings are figured in degrees clockwise from north.  First leg was 30 nm heading 270°.  The east/west part of the trip is 30 cos 270 = -30, the north/south part is 30 sin 270 = 0.  Second leg is 10 nm heading 15°.  east/west part is 10 sin 15 = 2.59, north/south part is 10 cos 15 = 9.66.  Add the 2 legs in separate parts.  You are now at a position 9.66 nm north and 27.41 nm west of port.  divide n/s by e/w to get the tangent of the angle: 9.66/27.41 = 0.3524 = tan 19.4°.  If you make a sketch while doing all this, the 19.4° is your reference angle in the northwest quadrant, so the compass heading from port to your position is 289.4°.  You could also write that as N 70.6° W.\n\nBelieve me, this is a whole lot simpler than navigating in 3 dimensions -- 4, actually, because your home planet isn't going to stay where you left it.
1014751
some guy and really far
37837
Look left then right and finally left.Good Luck
732740
im curious how this helpful to both of us??\n\nlynns distance (neglect directions )is 20 km....but her displacement (a vector) is 2 km east....because going north 5 and them south 3 and south 2 later cancels out n/s distance and going 6 east but 4 west leaves with 2 east..draw it out\n\n\nthe UFO moved 10 km North, it moved 20 east but them 30 west, subtract to leave 10 West...so the TOTAL displacement is 20 km\n\nBUT use pythagorean for 2\n\n10^2+10^2=200, sqrt 200, leaves 14.14 km NW
732600
SRY!! Matt is going to a basketball game out of town. If he could travel 75mph, He would arrive one hour early. If he could travel 45mph he arrives one hour too Late. How far is Matt's trip\n\ndis=75*(time-1)\ndis=45*(time+1)\n\nthen\ndis= 225mile,    time=4hour
198059
I believe NEW is 406km east.\n\n928km-522km=406km \n\nPott is not a factor in this.
530622
Ok, first you want to see where they meet. To make this easier, advance train A for 5/6ths of an hour and see the problem in terms of when train B starts out. 65 x 5/6= 325/6\nkilometers. So the problem is the same only they start out at the same time over a distance of 600- 325/6 kilometer =\n545 5/6 kilometers.\n\nNow, they travel in the proportion of 65/105 kilometers per hour. So the distance till they meet will be in the same proportion. That is 545 5/6 x 65/105 = 212875/630 or about 338 kilometers for train A to travel. Since it travels at 65 kph, this means it travels for 5.2 hours from the new start time equal to B's which was 6:20 AM. Ends up being 11:32AM.
100012
A would take 22 minutes to get to 15 miles and 32 minutes to get to 20 miles. Unfortunately, there's insufficient information to be precise on B's journey. Did he spin off before the start?.. or at which point en route? Guessing it, I would say A arrived at 15 miles and at the 20 miles point first. NB. I have had to make certain assumptions in your question to arrive at this answer (eg I asumed A slows down to 40mph after 4 miles?)
1059801
scalar quantities are added like simple maths :\ne.g.1) 4pounds + 5pounds =9pounds\ne.g.2) 1cm + 6cm = 7cm\n\n\nVectors can be added! But not like above because they have directions associated.\ne.g.1)  You travel "5km North and then 2 Km South" means you actually travelled "3 km North".\n\ne.g.2) You travel "3km North and then 4Km East" means you actually travelled "5km NorthEast"\n\nThe motion of a resultant vector  is similar to e.g.2(above) - the motions is that it goes neither in North nor in East but in North East.\n\nCheck out the two links below, they are more appropriate examples.\n\nhttp://ergo.human.cornell.edu/DEA325notes/biomechfund.html\n\nhttp://www.wellesley.edu/Physics/phyllisflemingphysics/104_o_2dimmotion.html