What is happening in a water filled beaker after NaCl is added?
100560
By a particle diagram, do you mean a graph? If you do, then draw a graph with an X (time) and Y (concentration) axis. When you put NaCl into water, the concentration of NaCl will be 100%. But as time goes by, the NaCl molecules will be pulled away from each other by polar water molecules (NaCl concentration will decrease), causing the appearance of a Na concentration and a Cl concentration. These two concentrations will increase from zero. I believe the slope of the two latter elements will be (theoretically) the same. So basically you should have two lines (increasing NaCl line and one line (which actually includes the 2 separate lines for Na and Cl because they are the same) for Na and Cl crossing each other like an X.
571970
Acid +Alkali =Salt + Water\nHence,\n\nNaOH + HCl = NaCl + H2O\n\nWhen litmus paper is dipped in NaOH solution it turns blue it means that NaOH is basic in nature.When HCl is added to NaOH The mixture becomes acidic and so the litmus paper turns red.The product you get after mixing both solutions is common salt and water so when this is heated the water evaporates and the salt is left back.This is a small experiment which you can do by adding salt to water and then heating it till the water gets completely evaporated.
949292
NaCl - sodium chloride
16164
The instruction is not correct because the total volume yielded when you mix 100ml of concentrated solution and 900ml water will be somewhat less than 1000ml. The concentration will be slightly higher than 1.0M\n\nThe correct procedure is to take a 1l volumetric flask  and add the concentrated solution to about 800ml water, then fill up to the mark.
838918
Its a decomposition equation. In essence Sodium Chloride (salt) breaks down into the Sodium ion and the Chlorine Ion. Chances are it's talking about NaCl when it's an aqueous solution (a solution who's solvent is water)
506202
Write out the balanced reaction which occurs.\n\nSince both NaOH and H2SO4 are strong electrolytes (strong base, strong acid), we can assume both dissassociate completely and the reaction produced Sodium Sulfate and water,\n\n2NaOH + H2SO4 --> 2H2O + Na2SO4\n\nFind limiting reactant in order to find which  will be left over (either NaOH or H2SO4).\nIn order to do this, you need to know both the concentrations of the NaOH and the H2SO4 in order to find the initial number of moles of each.\n\nOnce you know how many moles of either OH- or H+ are left over, you can then find the pH, or pOH like this,\n\npH = -log ([H+])\npOH = -log ([OH-])\n\npH + pOH = 14\n\n*Remember to take into account that the final volume of solution is the sum of the intial volumes of each othe reactant solutions when calculating pH.\n\nEDIT:\nYou know, it just occured to me, I dont know why I even brought up pH, that was not what the question was asking.  but everything I said still stands in order to calculate the molarity...you just dont have to go the one extra step and calculate the pH by taking the negative log of the molarity concentration of H+ ions.\n\nAlso, for all of you out there who are just given answers with not other explanation, it would be nice if you stated what the concentration was of....salt? NaOH?  H2SO4?\nBecause of this ommision, I would highly inclined to disreguard their answers as numerically incorrect as well.
703543
Mmmm... Salt....\n\nYou will get a super-saturated solution. Like the sugar they use to make rock candy, salt dissolves better in hot water. Saturated means it has as much solute (salt, in your question) in it as will possibly dissolve, so a saturated solution at 60 degrees celsius has quite a lot of salt in it!\n\nAs the saturated solution goes back to normal temperatures, it eventually reaches the point where there is MORE salt in solution than would normally dissolve. This is called a super-saturated solution. It still looks like it did before, except saltier than normally possible.\n\nSeveral things can happen to a super-saturated solution as it cools. Either it appears unchanged, or crystals start to grow like when you are making rock candy. You would see crystals around the edges and on the sides and bottom of the container. Some substances like sodium nitrate are so soluable that they can crystalize all at once when disturbed, which looks like the solution instantly froze solid. Table salt does not normally do this, so just write that it would go from saturated to super-saturated and crystals would form.
386284
The reaction Mg(OH)2 <--> Mg+2 + 2OH- will turn to the right when hydrochloric acid is added. This is because the acid eats away the hydroxides, and due to LeChatelier's principle, the equilibrium must shift to the right to account for this loss.\n\nAs for the Na2(EDTA), it will also shift to the right. The EDTA will form a complex with the magnesium ions, again, lowering the concentration of the Mg+2, so the equilibrium shifts to the right. Keep in mind that complex ions only form in molecules with empty d-orbitals.\n\nThis reaction is endothermic, like all dissolution (dissolving) reactions are. It takes energy to break the ions out of the crystal lattice structure.
904474
Do not crush the rock salt as this will make the impurities harder to remove.\n\nDissolve the rock salt in very hot water and filter.  If the filtrate (the water that comes through the filter) is colored, then you might need to treat it with charcoal to remove these soluble impurities.\n\nOnce you have a clear solution, allow some of the water to evaporate until the solution becomes saturated.  A single seed crystal will start the formation of sodium chloride crystals from the solution.  Stirring will keep the crystals smaller, otherwise you can end up with one very large crystal of salt.\n\nThis crystallization process is what does the final purification.  The crystals formed will be almost pure sodium chloride.
895319
salty.\nHCl (aq) + NaOH (aq) -> NaCl (aq) + H2O (l)\nNaCl (sodium chloride) is the salt you put into your food.
1014526
salts only get into your tap water when there's a problem with your water softener.  it may be turned up too high.
828284
The first thing that happens is that it melts.  If you continue heating the molten salt, you will see bubbles appearing.  These are bubbles of oxygen:\n2 KClO3(l)   --->   3 O2(g)   +   2 KCl(l)\nThe main product left behind is potassium chloride, but I believe that you also get some potassium perchlorate (tetraoxochlorate(VII)), produced by disproportionation:\n4 KClO3(l)   --->   3 KClO4(l)   +   KCl(l)\n\nIt wouldn't surprise me if the reaction also produced very small amounts of oxides of chlorine, such as chlorine dioxide, ClO2.\n\nAllan Deeds.
415923
Yes, salt water is a sodium chloride solution with Na+ and Cl- ions. when two seperate condutors are immersed in the solution without contacting each other and a bulb or any electrical appliance is placed across the conductors the positive and negative ions migrate and conducts electricity.
1187925
You have two ionic substances, it will undergo a double displacement reaction.\nPb(C2H3O2)2 + 2 NaCl --> PbCl2 + 2 NaC2H3O2\n\nNow since Lead(II) acetate, Sodium chloride, and sodium acetate are soluble, they break up in water, and the net ionic equation is\nPb2+ + 2 Cl- --> PbCl2\n\nPbCl2 or Lead (II) chloride, is the precipitate formed, and it's generally yellowish.
729404
They yield K3PO4 and H2CO3.... Just switch the positive ion with the negative ion and make sure the charges cancel out to zero on each new salt.
668153
Add NaCl to Water to make a solution and then heat it.\nMeasure the increase in boiling point along with the molality.\nShow htat it is greater htan ht eoriginal water's boiling point.\nGiving the proof of the increase in boiling point and measure the Kb.
727503
The pH value would increase, by how much would depend on the volume and concentration of the sodium hydroxide used.\n\n2.0Molar would have a much greater effect than 0.1Molar in the same volumes added to your water.