If 6x^2 + 4x = y, y = z^2 - x .....?
104175
f=thanx\ng=for\nx=the\ny=two\nz=points\n\nTell your teacher you need some help with your algebra.
249039
6\n\nx^2 - 10 = 4x +2\nx^2 -4x - 12 = 0\n(x-6)(x+2) = 0\nx = 6 or x = -2\n The Positive # is 6
1093922
if y = 6-x\nthen you just put that in for y\n2x-3(6-x) = -2\n2x- 18 + 3x = -2\n5x - 18 = -2\n5x = -20\nx = -4
130563
I'm not positive (it's been awhile), but I think if you can solve the equation for y, then it does.  So you have:\nx^3y-2y=6\n= y(x^3-2)=6\n= y=(x^3-2)/6\nso if i'm right, the answer is yes.\nhope that helped!
60538
if [ -7x + x^2 =0 ]\nthe you will get y = 7/x
846794
2x/x^2 - 5x + 6 + 4/x - 2\n\nFirst we will simplify\n2x/x^2\n\nThe x on the top crosses out and the x^2 on the bottom becomes x.  We end up with 2/x.\n\n2/x - 5x + 6 + 4/x - 2\n\nNow we combine like terms.  All of the terms with just numbers will be added together.  Everything with something over x will be combined. \n\n(2/x + 4/x) - 5x + (6 - 2)\n\nWe have 6/x - 5x + 4\n\nNothing else can be combined so it is now in simplest form.
143223
a) (6x-7y)(6x+7y)\nb) y(4xy-7)\nc) (x-8)(x+3)
91777
y=-6\n4x+y=2\n\nsubstitute -6 for Y\n\n4x-6=2\nadd 6 to both sides\n\n4x=8\nDivide both sides by 4\n\n\nx=2\ny=-6 (taken from above)
424288
1. y2+6y+8 = (y+4)(y+2)\n2. x2+7x+12 = (x+4)(x+3)\n3. z2+2z-24 = (z-4)(z+6)\n4. x2+7x+10 = (x+2)(x+5)
66783
(x-2)^2=x\nor x^2 - 4x + 4=x\nor x^2 - 5x + 4=0\nor x^2 - 4x - x + 4=0\nor x(x-4) - 1(x-4)=0\nor (x-4)(x-1)=0\n.'. x=4 or x=1;
757614
4 (x^2 + 3X -4)\n4(x+4)(X-1)
931054
Group all elements with y together:\n\ny(x^2 + 6x +9) -x^2 + 2x + 3 = 0\n\nMove the rest to the other side:\n\ny(x+3)^2 = x^2 - 2x + 3 (1)\n\nx = -3 is obviously not the solution of this equation therefore we can divide both sides of (1) by (x+3)^2.\n\n(1) is equivalent to:\n\ny = (x^2 - 2x + 3) / (x+3)^2
896553
4x^2+8x-x-2\n(4x-1)(x+2)
766536
(x^4-y^4)\n=(x^2+y^2)(x^2-y^2)\n=(x^2+y^2)(x+y)(x-y)\n\n2.(x^4-1)\n=(x^2+1)(x^2-1)\n=(x^2+1)(x+1)(x-1)
817379
y=(x^2-3x)^2\ny=x^4-9x^2\nAnd then I'm confused.
1169467
y = x^2 + 5x - 3\n2y=3x - 2\n----------------\n2y = 2x^2 + 10x - 6\n2y = 3x - 2\n-----------------------\n    0 = 2x^2 + 7x - 4\n=>2x^2 + 7x - 4 =0\n=>2x^2 + 8x - x - 4 = 0\n=>2x(x + 4) -1(x+4) = 0\n=> (2x - 1)(x + 4) = 0\ntherefore 2x - 1 = 0 => x = 1/2 or \nx + 4 = 0 or x = -4\nx = - 4 or 1/2  \ngot it?
767628
I'm assuming you want to factor this\n\n5z^2 + 4z -12 = (5z -6)(z+2)