what is the nuber for 9-1-1...i cant find it.?
99012
Well I kno you are being smart and I know you know it is 9-1-1 so I am sure that we would like it if you didnt ask questions that you already know the answer to. I am not trying to be mean but.....yeah.
491037
n91  rocks!!\n\njst got it
853927
999,999,999,999.9\n\nlol, how old are your kids/
124188
1398\n\nEasy way:\nRound 399 to 400 (+1)\nRound 999 to 1000 (+1)\nAdd 1000+400=\n1400\nSubtract the two you added.\n1398
1038063
If there was only one digit, there would be 10 (0-9)\nTwo digits, 100 (00-99)\nThree digits, 1000 (000-999)\n\nHey, there might be a pattern here\n\nSo 10 digits, 10,000,000,000 (0000000000-9999999999)
772023
1-1=3-3\n1(1-1)=3(1-1)\nBy ignoring (1-1)from the two sides\nthen:  1=3
408271
take the cube root of 729 u get 9
864681
numbers 1-12==they're always on the clock\n99/9=11
798483
Here it is:\n\n(98,42)Mo + (1,0)n ---> (99,42)Mo
889816
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
96075
you are talking about "Pascalles (not sure about spelling) Triangle." It goes 1,11,121,1331 and so on.
966095
are you asking for eleven and 1-ninth percent as a fraction?\n\nLets deal with the number first: \n11 1/9 is the same as 11 + 1/9.\nMultiply 11 by 9 to get 99/9 +1/9.\nso you get 100/9\n\nTo change to percent, you have to divide by 100. You can do this by multiplying the fractions\n(100/9) x (1/100) =100/900\n\nTo simplify: 1/9
429263
basic numbers are numbers 0-9
871673
So call the number\nB = {b_0,b_1,b_2,b_3,b_4,b_5,b_6,b_7,b_8,b_9}\n(this reverse indexing makes things easier).\n\nYou must have b_0 != 0, since you were told it was a ten-digit number. So b_0 is between 1 and 9.\nSo b_0 = 0 - (number of the b_i which are non-zero)\n\nAlso note that Sum_i=0..9 (b_i) = 10 since B has ten digits, and each b_i has to have a single value between 0..9\nHence Sum_i=1..9 (b_i) = (10 - b_0) for any particular choice of b_0\n\nTo prove the number is unique, see below:\n\nIt's easy to show 6210001000 is one possible answer.\nb_0 = 6 since there are six 0's in B\nb_1 = 2 since b_2, b_6 =1\nb_6 = 1 since b_0 = 6\nAll other b_i are 0 since there are no other non-zero b_i.\n\nTo prove the number is unique, the easiest way seems to be to show that the other b_0 between 1..5 and 7..9 are impossible by (proof by contradiction).\n\nb_0 = 9 is impossible since then b_9 must be 1, which gives a contradiction giving '9000000001', which only has 8 zeros, also b_1 must be 1, et.c\n\nb_0 = 8 gives '8000000010', but then b_1 must be 1, and it has one less zero, so that becomes '7100000100'...\nbut that has two ones, so b_1++, and b_2 must be 1, and you have again one less zero so b_0=6, giving '6210001000', which finally works.\n\nHarder to show that b_0 = 1..5 are impossible.\n\nLet's start from the opposite extreme, b_0=1.\nThen Sum_i=1..9 (b_i) = (10 - b_0) = 9\nThis constraint means each b_i can only be 0, 1 or 2.\nSince we set b_0=1, this means we have one zero and eight ones e.g. B='11111111110', doesn't matter where you put the 0. But that doesn't work since clearly b_1 must >=8, thus Sum_i=1..9 (b_i) = 8+7>9 which is a contradiction.\n\nIt should be trivial to crank out the cases b_0=2..4, maybe there is a more compact proof.
463357
number 9 or number 10
628648
None. The two numbers have no common factors, bar -1. You mean exactly (with no remainder) not evenly.
506057
What is the 1.4*10^-11 part ??????????????