how to avoid classnotfound exception in java?
109898
Another tip - class names and file names are CASE SENSITIVE.  If you create a class "Apple", and refer to it as "apple", you won't find it at runtime.\n\n(I'm just beyond a novice at Java - hope this helps too - just vote for the other guy).
1089274
If the Die.java application is not compiled you will need to do so. It should compile as Die.class. Then just make sure that class file (Die.class) is located in the same directory as the Java file you are working on which references Die.class.  You should not need to import it if this is the case since it is not part of the Java API.
721905
This is a proper way to do exception...\n\npublic class AccountsNotFoundException extends Exception {\n\n    public AccountsNotFoundException () { }\n\n    public AccountsNotFoundException (String msg) {\n        super(msg);\n    } \n}\n\nAnd within the code you do this:\ntry {\naccount_list = bankDB.getAccounts(id);\n} catch (AccountsNotFoundException e) {\nERROR_MSG = "Account not Found!";\n}\n\n\nThis is a small bank application I have done... You could post your own messeages within it but please don't throw exceptions that are not cought!\n\n\n\nWhat your doing up there is throwing an exception which isn't caught! So it is improper!
277785
You first need to import the class (or classes) and then you will be able to use their methods or  create objects with those classes.\n\nexample: import java.util.*
64616
If your a biginar , dont confuse with these big answers, set the environment variable path to //jdk../bin  ,its not having its own id, u just type your program in an editor, and go to dos prompt, then compile and execute your java
760469
The most likely problem is that the applet was written using an API with methods that don't exist in the JVM class API being used by IE.  Update your browser Java Plugin to the latest and then try.
883565
If you know the package name (like in your example), then look at this:\nhttp://forum.java.sun.com/thread.jspa?threadID=341935&start=15\n\nTo get to that point from any given object, get the object's class, and then get the Package object.\n\nClass clazz = myObj.getClass();\nPackage package = clazz.getPackage();\nString packageName = package.getName();
1129097
This is easy.  You don't have a JVM (Java Virtual Machine).  You can't see the java applets.  Go to java.com or Sun Java and download a JVM.  Then change your settings to what it recommends at the sites Troubleshooting or FAQ page.
696919
http://www.java.com/en/download/help/index_error.xml\n\nhere is a site that may have an answer to your problem
462064
i use eclipse for my java programs.. its quite simple, and gives u the exact lines where errors start..\njgrasp too works well..\ngood luck
969657
Is the library class a final class? If it is not, suggest you create a new class that extend that library class and include this new class as an inner class in your class. \nCheck out 'Inner Class' for Java, that allows a class definition to be placed inside  another class.
169925
this is either a security setting or you dont have java installe (assuming the applet is java)
267757
that's a possibility, also make sure you have java installed.
621477
error is what u can't expect\nexception is u know that it may occur and try to catch it\nif (x>10)\nthrow exception xyz{"hello-desc"};\nELSE PRINT ("HELLO");\nU KNOW here WHEN to throw a msg\nerror\nis preucation u are taking because u don't want to stop the flow of ur application or come out of ur application or hanging the application
14263
If you have the JDK installed ( else its here : http://java.sun.com/j2ee/1.4/download.html#sdk )\nand your classpath set \n( add CLASSPATH variable in your environmnet variables - MY Comp rt click properties > Advanced> Environment Variable > new variable >\n\nVariable : CLASSPATH \nValue    : .; \n\nAlso set PATH : <path of your JDK bin folder>\n)\n\nNow write your program in notepad , open cmd, and type \njavac myfile.java \n\nthe filename = classname and is case specific.\nthen if it results in zero errors, \n\ntype:\n\njava myfile\n\nthat would run your program
370055
Something like this maybe:\n\n Runtime.getRuntime().exec("C:" + pathSeparator +\n"jdk1.3.1" + pathSeparator + "bin" + pathSeparator + "javac.exe " + file);  } catch(Exception e)  { e.printStackTrace();  }  }  }
52727
public class ABCImplentation implements ABC {\n  public void someMethod() throws Exception {\n  }\n}