-Solve the equation and find x?
108580
3x/5-5=13-3x\n3x/5+3x=13+5\n18/5x=18\n18 divided by 18/5x=5x\nx=5
741552
You have got it right.\nthe answer is\n\nf(x) = 3x
902011
Ha! You had an answer to that 10 min before you even asked :). Check your previous question.\nBy factoring x out we have \nx(12x^2 + 3x -42)=0\n\nx1=0 \nsee reference and use equations provided\nx2=14/8=7/4\nx3=-16/8=-2
763084
or solve equation for x and y components separately. \nfor x    0 +3+?=0 \nfor y    3+0 +?=0
794793
x = 3. Try entering it on your calculator.
744692
Consider the following equations:\n1)   2x + y = 4 \n  \n2)   x − y = −1 \n\nTo solve them simultaneously, first, you need to solve one equation with respect to one variable. Let's solve the first one:\n\n2x + y = 4  Rearranging, you get:\ny = 4 - 2x\nNow you know the value of y, so plug it into the second equation, like this:\n\nx − y = −1 Rearrange using the value for y that you determined above:\n\nx - (4 - 2x) = -1\nNow solve this equation, since it now has only one variable:\n\nx - 4 + 2x = -1\n3x = 4 - 1 = 3\nx = 1 Now that you have the real value for x, go back to the first equation and solve for the real value of y:\n\n2x + y = 4  \ny = 4 - 2x  we know x = 1 so, y = 4 - 2\ny = 2\n\nYou can prove these are the right answers by using them in the equations.
245933
(4x+3)(x-1)=0\n\nx= -3/4, x=1
317252
to find x-intercept => you have substitute y=0 into the equation and solve for x.\n\nIn this case (0,0) is the x-intercept.
518727
Multiply the first equation by 2.\n\nSubtract the second equation from the new first equation.\n\nSolve for y.\n\nTake your value for y and substitute it into the original first equation.\n\nSolve for x.
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
921129
x = 7 or 3\n\nTake the square root of each side of your equation, to get the following:\n\n| x-5 | = 2\n\nNotice I used absolute value signs, because either 2 or -2 squared will give us 4.\n\nSo, x-5 = 2 or x-5 = -2\n\nx-5 = 2 → x = 2+5 = 7\n\nx-5 = -2 → x = -2+5 = 3\n\nSo x=7 and x=3 are both solutions to your equation.\n\nHope that helped!\n\n~ ♥ ~
856711
because this has 2 unknowns it cannot be solved.\n\nbut I can write  x in terms of b\n\n2x = 13-b\nor x =(13-b)/2
66565
You cannot "solve" this because it is not an equation.  An equation has two parts that are joined by the symbol =.  However, in early pre-Algebra classes, they might ask you to simplify this, meaning, to write this expression so that the "x" only appears once with its coefficient and the rest of the numerical values are also combined.  For this, you add all of the coefficients of x (3+1 - invisible coefficient before the second appearance of x) to find that you have 4x.  Next, you add the -8 and 4, which you can then express as either adding negative four or as subtracting four (if you need help here, consider the number line, move eight spaces to the left of zero, then move four spaces to the right).  Thus, you can re-write the expression as 4x-4.  Look in your textbook before the problems for a better example of what exactly they are expecting you to do in that section.
893013
is it x-3/x+2 or (x-3)/(x+2)?\n\nlets assume the second one\n\n2x(x+2)/(x+2)=x-3\nx+2 cancels out\n\n2x=x-3\nx=-3
256883
This is a question containing 2 variables x and y. This can be solved either by knowing the value of one of the variables, or by means of simultaneous equations. (Using another equation containing the same two variables).\n\nThe answer to your current question can only be simplification of the equation.\n\ni.e\n\nxy-4x=1
93711
First, distribute the one.  Now you have x+3.  Then, distribute the two.  Now you have -2+3x.  So, now your equation reads:  x+3-2+3x.  Combine like terms.  x+3x = 4x, 3-2=1.  Now, you have 4x + 1 = 0.  Subtract the one.  Now, you have 4x = 1.  Now, divide by 4 to get the x by itself.  You're left with x = 1/4.
610726
there is a solution, all x,y that satisfy this equation:\ny = 4 - 2x\n\nwhich is a straight line with intercepts (0,4) & (2,0)\n\nIt has an infinite amount of solutions. To be able to solve for actual numbers, you need as many equations as you have variables.