f = 9/5 c+32 please assist?
99752
well, if you needed the "comnversion of C---> F\n\nthan its simply\n\nC = 5/9(f-32)
812605
°F = (9/5)*°C + 32\n\nSo\n\n°F = (9/5)*(37.8) + 32 = 100.04 °F
172716
To convert F to C and C to F you use the equation:\n\n  (F - 32)/ 180 = C/100\n            \nThen,   C = (F-32).100/180 = (F-32).5/9\n    \nAnd, F = (C . 180/100) + 32 = (C . 9/5) +32\n              \nIn your question: \n\nF = 40 . 9/5 +32 = 8 . 9 + 32 = 72 + 32 = 104
896061
f(x)=16-5x\nf(-3)=16-5(-3)\n=16+15=31
785535
Multiply both sides by a. Then divide both sides by 9. You should get a=5.
874492
Here's what you have to do.\nReplace Q with 1.6x10^(-19)\nReplace C with 3.31x10^20\nReplace K with .49\nFor #1, replace x with 1.9\nF = (1.6x10^(-19)) (3.31x10^20) (.49) / (2(1+cosh(.49*1.9))\nEvaluate using a calculator.\n\nFor #2, replace F with 3 and solve for x.\n3 = (1.6x10^(-19)) (3.31x10^20) (.49) / (2(1+cosh(.49*x))\n3(2(1+cosh(.49*x)) = F = (1.6x10^(-19)) (3.31x10^20) (.49) \n6 + 6cosh(.49*x) = F = (1.6x10^(-19)) (3.31x10^20) (.49)\n6cosh(.49*x) = F = (1.6x10^(-19)) (3.31x10^20) (.49) - 6\ncosh(.49*x) = ((1.6x10^(-19)) (3.31x10^20) (.49) - 6) / 6\n.49*x = inverse cosh (((1.6x10^(-19)) (3.31x10^20) (.49) - 6) / 6)\nx = inverse cosh (((1.6x10^(-19)) (3.31x10^20) (.49) - 6) / 6) / .49
712395
9x+5/(x-4)+(-7x)/(x-4)\n=9x+5-7x/(x-4)\n=(2x+5)/(x-4)
285069
-40\n\nC = 5/9 * (F-32)\n\nPutting x as C and F,\n\n=> x = 5/9 * (x-32)\n=> 9x = 5x - 5*32\n=> 9x - 5x = -5*32\n=> 4x = -160\n=> x = -40\n\nHence they are equal at -40
901932
Fahrenheit formula\n\nInsert 39 ° into the formula\n\nF = 9/5C + 32\n\nF= 9/5(39) + 32\n\nF = 351/5 + 32\n\nF = 70.2 + 32\n\nF = 102.2\n\nThe answer is F = 102.2\n\n- - - - -s-
949276
hi dear xmixxdiam \n\n(7/20 + 3/5) - (3/8 x 4/9)\n● Part 1\n7/20 + 3/5\n- first take a common denominator and its ' 20 ' \n( 7 + 12 ) / 20 = 19 / 20 \n\n● Part 2\n3/8 * 4/9 = (3  / ( 4 * 2) ) * ( 4 / (3 * 3))\n- Now cancel " 3 " & " 4 " \n1/ 2 * 1/3 = 1/6\n\n● Part 3\n19 / 20 - 1 / 6 = ( 57 - 10 ) / 60 = 47 / 60 = 0.783 { bar over 3 } \n\nGood Luck Darling ♣
424227
take 32 degrees off the F, then divide by 1.8.  So for example lets say you have a F temp of 50.  Take 32 off that, which gives you 18.  Divide by 1.8, which gives you 10.  So 50 F is the same as 10 C.
740030
f = uN\n198 = u*(55*9.8)\nu = 0.367 for static\n\nf = uN\n175 = u*(55*9.8)\nu = 0.325 for kenetic
170756
To go from Celsius to Fahrenheit, take the temperature in Celsius, multiply by 9, divide by 5, then add 32.\n\nF = (9/5)C + 32
307116
f.w. divide by two\n\n95.21g/2 =47.61g
1086560
f(-2) = 5. What's so difficult about this question?
836547
f(x)=rtx+C\nf(1)=1+C=2\nso C=1\nf(1/4)=rt(1/4)+1=3/2
756998
f(g(x))= 4g(x) -5\n= 4(x/3) -5\n= 4x/3 -5\ns