An array element is accessed by including its _____ in _____ after the array name. Please fill in the blanks.?
108407
an array element is access by including its INDEX in BRACKETS after the array name.
1053311
//created by vinyl21 for yahoo answers\n//gjfr77@yahoo.com\nimport java.io.*;\nclass matrix{\nint n,m;\nint a[][]=new int[100][100];\nint r[]=new int[10];\nint c[]=new int[10];\nDataInputStream d=new DataInputStream(System.in);\n\nvoid input() throws IOException{\nSystem.out.println("ENTER THE NO OF ROW");\nn=Integer.parseInt(d.readLine());\nSystem.out.println("ENTER THE NO OF COLUMN");\nm=Integer.parseInt(d.readLine());\n\nfor(int i=1;i<=n;i++){\nfor(int j=1;j<=m;j++){\nSystem.out.print("("+i+","+j+"):");\na[i][j]=Integer.parseInt(d.readLine());}}}\n\nvoid process(){\nfor(int i=1;i<=n;i++){\nfor(int j=1;j<=m;j++){\nr[i]+=a[i][j];}}\n\nfor(int j=1;j<=m;j++){\nfor(int i=1;i<=n;i++){\nc[j]+=a[i][j];}}\n}\n\nvoid display(){\nSystem.out.println("given matrix");\n\nfor(int i=1;i<=n;i++){\nfor(int j=1;j<=m;j++){\n\nSystem.out.print(a[i][j]+"&#92;t");\n\n}\nSystem.out.println("&#92;n");}\n\nSystem.out.println("row sum");\n\nfor(int i=1;i<=n;i++){\nfor(int j=1;j<=m;j++){\n\nSystem.out.print(a[i][j]);\nif(j<m)System.out.print("   +   ");\nelse System.out.print("   =   ");}\nSystem.out.println(r[i]);\nSystem.out.println();}\n\nSystem.out.println("column sum");\n\nfor(int i=1;i<=n;i++){\nfor(int j=1;j<=m;j++){\n\nSystem.out.print(a[i][j]+"&#92;t");}\n\nif(i<n){\nSystem.out.print("&#92;n");\nfor(int d=0;d<m;d++){System.out.print("+&#92;t");}\n}\nelse {System.out.print("&#92;n");\nfor(int d=0;d<m;d++){System.out.print("=&#92;t");}}\nif(i==n){System.out.println();\nfor(int k=1;k<=m;k++){\nSystem.out.print(c[k]+"&#92;t");}}\nSystem.out.println();}\n\n}\n\nvoid displaye() throws IOException{\nSystem.out.println("PRESS ANY KEY TO EXIT");\nString n=d.readLine();}\n\n\npublic static void main(String args[])throws IOException{\nmatrix k=new matrix();\nk.input();\nk.process();\nk.display();\nk.displaye();}}\n\n/*output\nI:&#92;>cd j\n\nI:&#92;j>cd bin\n\nI:&#92;j&#92;bin>java matrix\nENTER THE NO OF ROW\n3\nENTER THE NO OF COLUMN\n3\n(1,1):1\n(1,2):2\n(1,3):3\n(2,1):9\n(2,2):8\n(2,3):7\n(3,1):4\n(3,2):5\n(3,3):6\ngiven matrix\n1       2       3\n\n9       8       7\n\n4       5       6\n\nrow sum\n1   +   2   +   3   =   6\n\n9   +   8   +   7   =   24\n\n4   +   5   +   6   =   15\n\ncolumn sum\n1       2       3\n+       +       +\n9       8       7\n+       +       +\n4       5       6\n=       =       =\n14      15      16\nPRESS ANY KEY TO EXIT\n*/
965488
This operator(->) indexes into a structure to dereference a pointer inside.  So it is used when the target is a pointer.  The (.) operator is used when the variable inside is a sstandard named variable.
1047339
If this line is in your main method:\n\nObject[] object_array;\n\nYou have created an array of objects.
881644
Something like this:\n\nint **myArray;\nint s1,s2,i;\n\nprintf("Input row size: ");\nscanf("%d",&s1);\nprintf("Input column size: ");\nscanf("%d",&s2);\n\nmyArray[0] = malloc(s1*s2*sizeof(int));\nif (myArray[0] != NULL ) {\n  for (i = 0;i<s1,i++) {\n         myArray[i] = (i * s2) + myArray[0];\n  }\n}\n\nmyArray can then be used as normal\n\nmyArray[2][4] = 20;
659498
because you are using a pointer to load the array. you are actually writing outside of the array, but it isnt causing any problems (yet) because a[] is the last variable you are using.\n\ntry this to see what I mean. declare another int after a[]\nint a[]={1,4,2,5,6,3,7,8);\nint b;\nmake b = 0;\nwriting to a[8] means you overwritting the NULL terminator, but try writing to a[9] (a[9] = 12;), print out b, and see what it is. you should see that it is now 12.
329175
I'm assuming your accessing it from another class? \n\nPrivate declaration stops this from occuring. You need to provide a public property ie.\n\nprivate _str as string = ""\nPublic Property etc as string\nGet\nreturn _str\nEnd Get\nSet(value as string)\n_str = value\nEnd Set\nEnd Property\n\nOtherwise if you are accessing a class-scope variable normally, you could do:-\n\nPublic class Class1\n Private Str as string = ""\n Private Sub New()\n   Str = "Hehehe"\n End Sub\nEnd Class\n\nQuestion wasn't clearly stated, but i think that should answer it...
227826
you can use redim function in VB to increase the size of array without loosing any data.it will increase the size of the array and persist your data existed in the array.\nlett me know us satisfied with the ans or need any clarification.
195396
What's with the ... ? Is that a space for a number, are you supposed to guess whether to use the + or the x ? I don't get it, I think I'm gonna cry :~(
818446
It is called an ARRAY
687702
A previous answer explained that "array subscripts get\ncompiled down to use pointer arithmetic".\n\nIt's not simply an implementation issue, but rather a\nlanguage definition issue.  Section 6.3.2.1 of the Ansi C\nstandard explains that except when used as the argument of\na "sizeof" or "&" operator, a reference of "array of type"\nis converted to reference of "pointer to type" which\npoints to the initial element of the array.\n\nTo use the example from the previous poster, "x[i]" is\n_defined_ to be *(x+i).\n\nTo extend the illustration (and to confuse your friends),\nconsider the following.  A character string reference is\nconverted to type "pointer to char", but since pointers\ncan be used in array context, you can reference one as\nfollows:\n\n    char c = "house"[3];\n\nBut as the other poster explained, since x[5] is \nsemantically equivalent to 5[x], the following is\nalso legal:\n\n\n    char c = 3["house"];\n\nThis, of course, equals the character value 's'.\n\n\nFinally, for those answering who are so young that \nthey think "C is the mother of all languages", you \nmight do a quick web search on the words "Fortran" \nand "Algol" :-)
578465
The easiest way to do this is to count back from the end of the array.\n\nFor instance, if an array has three values, \n$item[0], $item[1] and $item[2] then you can access the last with:\n$item[-1]... an easy way to reach it!
150130
this is pointer to invoking object in Javascript.\nSo you're passing current object for update to a function in your code. \nThere are also some alternate ways (document.form.xxx) to reference to current object, but this is simple and to the point when you just want to change the object from where you're making method invocation.
169151
int\nmain (void)\n{\nfor(i=0;i<10;i++){\nprintf("some thing output here %d", i)\n}\n}
980139
the way you store ur data.e.g. array,list,tree,queue
8215
"foo", "bar", and "foobar" are generally used as place holders by programmers; a way of saying "[insert your code/variable/constant/etc. here]".  Depending on the context in which you find it in the example code, you would replace "foo" in your own code with a function, a string literal, a variable, and so on.\n\nI haven't come across "_('foo')" in any of the PHP scripts I've looked at, though, but it seems unlikely (given PHP's rules of syntax) that it could represent a function or an escape sequence by itself; more than likely, it's meant to be replaced by something in your own code.
359046
#include <ctype.h>\n#include <stdio.h>\n#include <stdlib.h>\n\nstatic char *article[] = { "the","a", "one", "some", "any" };\nstatic char *noun   [] = { "boy","girl", "dog", "town", "car" };\nstatic char *verb   [] = { "drove","jumped", "ran", "walked", "skipped" };\nstatic char *prep   [] = { "to", "from", "over", "under", "on" };\n\nint\nmain()\n{\n  int asize = sizeof(article)/sizeof(article[0]);\n  int nsize = sizeof(noun)/sizeof(noun[0]);\n  int vsize = sizeof(verb)/sizeof(verb[0]);\n  int psize = sizeof(prep)/sizeof(prep[0]);\n\n  char buff[100];\n  for (int i=0; i<20; i++) {\n    (void)sprintf(buff, "%s %s %s %s %s %s.",\n      article[rand()%asize],\n      noun[rand()%nsize],\n      verb[rand()%vsize],\n      prep[rand()%psize],\n      article[rand()%asize],\n      noun[rand()%nsize]);\n    *buff = toupper(*buff);\n    (void)printf("%s&#92;n", buff);\n  }\n  return 0;\n}\n\n\n$ a.out\nSome town walked to a dog.\nThe car ran from any dog.\nAny boy drove under any town.\nOne girl jumped under the girl.\nOne car jumped to one girl.\nAny boy skipped over a dog.\nAny town jumped from some town.\nThe town ran from the town.\nOne car walked to any town.\nOne town ran over one boy.\nAny town jumped on the car.\nSome dog skipped from a boy.\nSome girl skipped over a boy.\nA car walked over some girl.\nThe car jumped from a girl.\nThe boy skipped on the town.\nAny car walked from one girl.\nAny dog ran to a town.\nA car jumped under some car.\nSome boy walked to the car.