what is molar conductivity in electrochemistry?
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I think you can find everythin u are lookin for and more on this site.. good luck!!!http://www.tannerm.com/electrochem.htm
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Hi,\nHere you can find a table:\n\nhttp://www.physchem.co.za/Data/Electrode%20Potentials.htm
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Usually sintered material from a single type of crystal, such as CaF2 or ZrO2 (the latter used in the lambda cell of car catalysts). The ion conduction is a property of the crystals, not created through the ceramic accumulation.\n\nThe principle of conduction is that imperfections in the crystal - missing ions - get mobilized at sufficient temperature, so that the ions can be replaced from neighboring positions, making the gap migrate through the crystal along an electrical field gradient.
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The conductivity of aluminium is required. A detailed solution of the Heat equation (A pde) is necessary to get an accurate answer. In the absence of any simplifying assumptions, this problem is not trivial
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Without applying a potential, nothing.  The net voltage of the cell is less than zero (silver's oxidation is -0.80V, while aluminum's reduction is -1.68V).  Total voltage would be -2.48V, which is non-spontaneous.
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molality = moles of solute / kg of solvent.\n\n200 grams of water  = .2 kg of solvent.\n\n.3 molality = x moles / .2 kg\nsolve for the number of moles (x).\n\nThen multiply the number of moles by the Molar mess of Silver Nitrate and that is your answer.
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Electrolytes- compounds which when dissolved in water produce solutions that conduct an electric current. \n\nNonelectrolytes- compounds which when dissolved in water produce solutions that do not conduct an electric current.
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Go here to find out about  "MOLAR ENTHALPY"\n\nhttp://www.carolina.com/chemistry/activities/Determining_Molar_Enthalpy_of_Solution.pdf
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Water ability to conduct water depends on the total amount of dissolved solids  (TDS), thus, the electrical conductivity (EC) of water is an indirect measure of its dissolved constituents. Let's say you had your arms stretched out and your pool is really clean (very low TDS), depending on the circumstances, there may be different field strengths from one side of your body to another. In this case, your body becomes the conductor and, yes, you can be electrocuted.
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This may be what you are looking for:\n\nhttp://www.diva-portal.org/ntnu/abstract.xsql?dbid=104\n\nIt was the fifth entry in a search for "electrochemical MgO" in yahoo.
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Well, I'm not doing your homework for you, but Molarity is Moles per liter.  So that means you would have to change grams to moles, hopefully you know how to do that.
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NaNO2 in solution dissociates into Na+ and  NO2- because of its Ionic Bonding, and therefore the solution can be conductive.  All other molecules contain Covalent Bonding which cannot dissociate in solution therefore they cannot be conductive in solution.
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In an electrolytic cell you can plate most any metal that doesn't quickly react with the solvent and its solutes.  The force of the copper ions gaining electrons at a negative charged zinc electrode is certainly possible.\n\nSince the copper would receive two electrons and go from a +2 to a zero oxidation state, you would say that it is being reduced.
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The molarity of a solution is the number of moles of a substance per liter of solution.\n\nMolarity = moles/liter\n\nSo, if you know what your solute is, you need to calculate the number of moles you have by:'\n\nmoles = mass of solute/molecular weight of solute\n\nnumber of moles is then divided by the number of liters you have, and voila!  Molarity.\n\nExample:  40 grams of sodium chloride in 500 mL of water:\n\n40 gm NaCl/58.443 grams per mole = 0.6844 moles\n\n0.6844 moles/500 mL * 1000 mL/liter = 1.369 moles/liter  or the solution is 1.369 M sodium chloride in water.
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With chemicals like NaBH4 you ought to say which solvent you mean. I will assume slightly alcaline water, adding OH(1-) to the equation:\n\nAg(1+) + 1 electron -> Ag (+-0)\n\nBH4(1-) -> "B(3+)" + "4 H(1+)" + 8 electrons.\n\nBoth the resulting hydrogen and the boron need hydroxide ions to remain in the solution, one each for every positive charge above. \n\nMultiply the silver equation by 8 to balance the electrons in the redox reaction.\n\nThis yields:\n\n8 AgNO3 + NaBH4 + 7 OH(1-) -> 8 Ag + 8 NO3(1-) + 4 H2O + H3BO3 + Na(1+)\n\nIf you need to write the result as neutral salts, add more sodium ions for the hydroxide.
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The product of a neutrilization reaction is always water and a salt, so use that as a guide.  For part 2, use the units as a guide.  Hint M=molarity=mols/L
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here, you just use the ideal gas law, PV=nRT.  since molarity is equal to moles of solute per liters of solution, M=n/V, so P=MRT.\ntherefore,\nKp=Pco*Ph2o/(Ph2*Pco2)\n  =[CO]RT*[H2O]RT/ ([H2]RT*[CO2]RT)\nall the RT coefficients end up canceling out, so:\nKp=[CO][H2O]/[H2][CO2]\n  =Kc\nsince there were equal numbers of gas molecules on each side of the equation, Kp was equal to Kc.  as a general rule, Kp=Kc*(RT)^N, where N is the change in the number of gas molecules.