what is projectile motion?
104839
When an object is launched under the influence of only a uniform gravitational force field, it is said to follow a projectile motion. Under ideal condition, the path it traces is parabolic. There is catch here – if the initial velocity is equal or more than the escape velocity then the object will simply vanish into space i.e. leave earth!\n\nImagine if the launch angle from the horizontal is “theta” and initial velocity is “U” then you can easily compute vertical (Uv) and horizontal (Uh) components of it. The Uv will be equal to U x Sin(theta) and Uh will be equal to U x Cos(theta). Now by using Uv you can compute the max height it will reach and the total time it will take to go up and return to ground. With this round trip time in hand, you can easily compute the max horizontal distance it will cover before hitting the ground.\n\nAll these calculation assume ideal conditions like no wind resistance etc.
978760
Projectile Motion-  Examine the initial velocity and angle necessary to hit targets at different points.
6491
11.3 Km/sec at earth's surface (7 miles/sec)\n\nNOTE that escape velocity is the speed with which you would throw an object so that it does not fall back to earth. Rockets for example have constant propulsion and therefore do not need to travel with escape velocity to go into space.
810784
Colloquially, a trajectory is the path in space followed by a body. Such a body can be a projectile, for example. Strictly speaking trajectory refers only to that portion of the path during which the body undergoes a transient movement between practically stationary or repetitive motions or until the body eventually stops moving. In a wider sense it also includes the meaning of orbit - the path of a planet, an asteroid or comet, for example. A trajectory can be described mathematically by the geometry of the path or as the position of the object over time.\nclick here:http://en.wikipedia.org/w/index.php?title=Projectile_motion&redirect=no\nhttp://en.wikipedia.org/wiki/Trajectory
859137
first thing u should do is do draw the path of the projectile,  using only imagination, the ball will definetly fall down as it moves away from the table edge until it finally hits the floor.\n\nprojectile path is always parabolic, and the direction of the velocity vector is tangent to the path of the projectile at any point.\n\nat the initial state, the velocity vector was pointing left or right according to your assumption, but as the parabolic path falls down, the velocity vector points down with it, when the ball hits the floor the velocity vector will be perpendicular to the horizontal in the downward direction.\n\nso at 45 degrees downward, the velocity vector has two components, on in the horizontal V*cos(theta) and another downward V*sin(theta), to get how high the ball at this instant apply the same laws but use V*sin(theta) instead of V ,  and to find how far from the table use V*cos(theta) instead of V.\n\nhope this helped.
771568
Basically you have the right idea. Use momentum (mass x velocity) for the motion and the sudden change in speed and/or direction (acceleration) and you get force x time = kinetic energy trying to rip you apart or squash you like a bug.
763881
Take the x-axis as the line of action of the moving ball. and suppose the second ball moved at an angle theta wrt to the line of action with certain velocity that u need to find out. Now resolve the velocity components of both balls along x-axis and y-axis before and after collision. Now conserve the momentum along both x-axis and y-axis before and after collision. solve the equations and u will know all the unknowns.\n\nFor the second question find 'e' i.e. co-effecient of restitution and depending on the value it will be elastic or inelastic.
307841
One-dimensional motion is motion along a straight line, and cen be represented by four variables, velocity (v), time (t), displacement (x), and acceleration (a).  There are five equations that can solve for any unknown variable, assuming constant acceleration:\ndelta x=v(delta t)\ndelta v=a(delta t)\ndelta x=v initial*delta t + 0.5a(delta t)^2\ndelta x=v(delta t) - .5a(delta t)^2\nv^2=v inital^2 + 2a(delta x)\n\nAlso, keep in mind the derivative of displacement is velocity and the derivative of velocity is acceleration.  Likewise, the integral of acceleration is velocity and the integral of velocity is displacement.
728879
basketball. When you shoot the ball to make a basket, the force with which it is thrown, combats with gravity. This determines at what point the ball will start to fall towards the basket.
282533
Muzzle velocity is the speed of a projectile leaving the barrel of a gun.\n\nMeasured in feet per second. \n\nIt is used as a comparison between similar projectiles, such as ammunition for a gun.
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Here's how to solve this.\nThe velocity is a vector, and right-angle components of velocity operate independently.\nThe bullet is fired with 2000 ft/s horizontal velocity but zero vertical velocity. So you know the horizontal and vertical components of velocity at the instant the bullet leaves the barrel.\n\nHowever, once it leaves the gun's barrel, the bullet experiences no horizontal forces, but vertically it is acted upon by gravity.\n\nSo: 1) how long does it take for the bullet to fall 5 ft, starting with zero vertical velocity? (hint: s = 1/2 a t^2\n\n2) Once you figure out how long until the bullet hits the ground, then figure out how far the bullet has travelled horizontally during that time, given 2000 m/s initial horizontal velocity and no horizontal forces.\n\nDoes this help?
786994
velocity-height and horizontal movement. 11.2 km/s in order to escape earth's atmosphere (air provides resistance against movement) above 50 km and movement in horizontal direction so that the object falls perpetually towards the earths gravity centre.
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Displacement.  If you mean its change in position *divided* by the time it took, that would be its average velocity.
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Simple parabolic path formula \n\na hit ball is given a velocity v at and angle theta.\n\nAssuming no air resistance the balla travels through the air along its horizontal vector un abstructed, while acted on by gravity in the vertical direction.\n\nthe equation\n\nd=vt + 1/2gt^2 can be solved for d which will be the total vertical distance at time t, where t is the time at which the ball is the highest, lets say about 1/2 of the total time, g is the gravitational constant and v in the velocity in the vertical direction
1131554
Yes. \n\n(All of the following bars air resistance.)\n\nA trajectory would be the path that it follows. If an object has no initial velocity, it would fall straight down.\n\nBut say it did have an initial velocity. Let's say you threw a football. Does the football ever stop in mid-flight and fall straight down? No; it has an initial velocity, a sideways trajectory. If something has an initial velocity sideways, it's trajectory will look like an upside down parabola (ie y= - x^2) once gravity is applied.\n\nHope that helps.
1006189
Explain Newtons laws of motion.
73523
You just want me to do your science homework, don't you?  Somehow I suspect the answers are in your textbook, if you just look hard enough.  Okay, here we go.\n\nInertia is the tendency of an object to resist a change in its motion.  With intertia expressed as p.  Momentum increases if the mass or velocity increases.  Not sure where the final two sentences are going, or if you're looking for verbs or what.  Good luck.