Given 5x-3y=15, give the equation of 3 parallel lines?
111804
10x-6y=30(Multiplied by 2)\n15x-9y=45(Multiplied by 3)\n20x-12y=60(Multiplied by 4)
171467
They're perpendicular:\n5y+3x=15\n5y=-3x+15\ny=-3/5x+15/5\ny=-3/5x+3\n(y=mx+b)\nm -> slope, so: -3/5 versus -5/3 it's perpendicular
953271
if it is parallel the slope is 3 so the equation is\ny = 3x + b\nnow you just solve\n-2 = 3*2 + b\n\nfor b and that is your new y intercept and equation.
525451
5y -3y = 14 -3\n2y = 11\ny = 5.5\n\n5y -3y = 14 - 9\n2y = 5\ny = 2.5
349210
dy/dx = -(15cos(3/x)/2x^2) * (sin(3/x))^3/2
776052
3*5b= 15b      \n3*-7= -21\n 15b-21=-7+b\n15b-b-21=-7\n15-b=-7+21\n14b=14\nb=14/14\nb=1
946761
well to solve the first equation (its a line plot)\n3y+1[-1]=2x+16[-1]\n3y=2x+15\nif x=0, y=5 (y intercept)\nif y=0, x=-7.5 (x intercept)\n\nthe second line graph\n3y+5[+4]=2x\n3y+9=2x\nif x=0, y=-3\nif y=0, x=4.5\n\nNow, these lines are not equal, but do you have to plot both lines to prove? Your question is not clear.
740076
First solve for y.\n3x - 5y = 7\nSubtract 3x from each side\n-5y = -3x + 7\nDivide everything by -5\ny = (3/5)x - 7/5\nThe slope is m = 3/5\nSInce the new line is parallel to the given line, that means the slope will be the same.  Use your given point to find the  line\ny - (-7) = (3/5)(x-6)\ny + 7 = (3/5)x - 18/5\ny = (3/5)x - 18/5 - 7\ny = (3/5)x - 53/5
689072
5x + 3y = 16 ------ equation 1\n\n2x + 3y = 1 ------- equation 2\n2x = 1 - 3y\nLet x = (1-3y) / 2 \n\nReplace x with y in equation 1, and solve y\n\n5 [ (1-3y) / 2 ] + 3y = 16\n5 (1-3y) + 6y = 32\n5 - 15y + 6y = 32\n9y = -27\ny = -3\n\nReplace the value of y to solve x\n \ntherefore x = [ 1 - 3(-3) ] / 2\nx = 10/2 = 5\n\nYou can try and solve the other pair of system using the same basis as above.
843375
3x + 1 = 5x - 15\n16 = 2x\nx = 8
204479
[(5x^2-5x-30)/(45-15x)]*\n[(4x-12)/(6+x-x^2)]=\n\n[5(x-3)(x+2)/(5*(9-3x)]*\n[4(x-3)/(3-x)(x+2)]=\n\n[(x-3)(x+2)/3(3-x)]*\n[-4(3-x)/(3-x)(x+2)]=\n\n[(x+2)/-3]*[-4/(x+2)]=\n\n[-(x+2)/3]*[-4/(x+2)]=\n\n[-4(x+2)]/[-3(x+2)]=\n4/3
736590
7(5y+5x) = 105\nopen brackets first\n\n35y+35x=105\n\ndivide everything by 35\n\ny+x=3\n\nmake y the subject\n\ny=3-x
1052653
Given 3x - 2y = 5, if you follow the suggestion in the first answer and multiply it by 2 you get\n\n6x - 4y = 10\n\nand if you add this and the second equation you get\n\n0x + 0y = 17 or 0 = 17, indicating that there is no solution to this simultaneous pair.  Why, you might ask - if you solve each equation for y you get\n\ny = 3x/2 - 5/2  and\ny = 6x/4 + 7/4\n\nThe coefficient of x in the second equation reduces to 3/2, so these equations have the same slope and are therefore parallel.
166772
2x - 3y = 5        \n2x^2 + 3y^2 = 35 \n\n2x = 5 + 3y\nx = (5 + 3y)/2\n\n\n2 [(5 + 3y)/2]^2 = 5 + 3y\n2 [(25+30y+9y^2)/4] = 5 + 3y\n25+30y+9y^2 = 10+6y\n9y^2-24y+15=0\n(3y-3)(3y-5)=0\n\ny=1; y=5/3\n\nif y=1\n2x - 3(1) = 5\nx = 4\n\nif y = 5/3\n2x - 3(5/3) = 5\nx = 5
967269
1. Since 5y = 15x + 35, y = 3x + 7, and the slope is 3.\n\n2. Since 3x + y = 7, y = -3x + 7, and the slope is -3.
972476
........._______________\nx - 5 ) x³ - 3x² - 13x + 15 ( x²\n......... x³ - 5x²\n......... -------- ....↓\n............... 2x² - 13x ....... ( 2x\n............... 2x² - 10x\n............... ----------- ....↓ \n............... ....... -3x + 15. (-3\n............... ....... -3x + 15\n............... ....... -----------\n............... ....... -----------\n\nSo P(x) = x³ - 3x² - 13x + 15\n= (x - 5)(x² + 2x - 3)
135926
15 + 30 = 45\n45 x 3 = 135\n45 + 135 = 180