what is the graph of (x-4) + (y-3)=5?
101785
It's a curvy line with 3 bumps, the 2nd bump is higher than the 1st or 3rd, but the 3rd is kinda squished in.  Too bad you can't see my calculator.
1142461
1. x-y=5; y= x - 5\nAdd y to each side x - y + y = 5 + y, becomes x = 5 + y. Subtract 5 from each side, x - 5 = 5 - 5 + y, becomes x - 5 = y\n\nSolve the rest on your own
809836
-3(12) - [5(-4) - 2³]\n= -36 - (-20 - 8)\n= -36 - (-28)\n= -36 + 28\n= -8
124621
x-4y=-20\n=> -4y=-x-20\n=> 4y=x+20\n=> y=x/4+5 Ans.\nThanks.
921939
Good Evening\n\nI think we've been avoiding this question because we can't graph here... however to get you started, create an x|y chart for each line, plug in a couple of values, and connect the dots  (for a line you only need two points, but some books recommend finding three, so you can verify you didn't make a mistake somewhere)\n\nx+y = 8\nx|y\n----\n4|4\n3|5\n2|6\n\nx - y = -4\nx|y\n0|4\n1|5\n2|6\n\nGraph the two lines, and they should intersect at (2,6) since it appears in both of the charts...\n\n~i~
920205
.y = 6x + 5\n(0, ) \nx=0\nso y=5\n\n\n(3, )\nx=3, so y= 6(3) +5 =23
554784
x=(1--2)  or (1+2)\ny=(5-3)\n\ny/x=slope\nx=3\ny=2\nslope is 2/3
516161
x-y+3x-5y+3=0\n\n4x - 6y + 3 = 0\n\n4x + 3 = 6y\n\n2x/3 + 1/2 = y
474164
x=5x-y\n\nx-5x=-y\n\n-4x=-y\n\ndivide both sides by -4\n\n(-4/-4)x=(-y/-4)\n\n1x=(1/4)y\n\nx=y/4
361536
Let's call f(x) = x^2 - 4\n\nThe graph of f(x) = x^2 - 4 looks like a smile ( U )  with the graph passing the y - axis at -4.\n\nThe roots are at x = 2 and x = -2.  This can be found by solving for x^2 - 4 = 0\nx^2 - 4 = 0\n(x + 2)(x - 2) = 0\nso x + 2 = 0, or x - 2 = 0\nso x = -2 or x = 2\n\nsince you're int'ing from x = -1 to x = 3, you have to break up the int into\n[x = -1 to x = 2, where f(x) is negative and take the absolute value] \nand\n[x = 2 to x = 3, where f(x) is positive]\n\nso int of f(x)\n= x^3/3 - 4x + c\n\nso int of f(x) from x=-1 to x=3\n= {+ve value of int of f(x) from x = -1 to 2}\n                +\n  int of f(x) from x = 2 to 3\n\nSeparately\nint of f(x), x = -1 to 2\n= | (2^3)/3  - 4(2) - [((-1)^3)/3  - 4(-1)] |\n= | (8/3) - 8 - [(-1/3) + 4] |\n= | (8/3) - 8 + (1/3) - 4 |\n= | (9/3) - 12 |\n= | 3 - 12 |\n= | -9 |\n= 9\n\nint f(x), x = 2 to 3\n= (3^3)/3  - 4(3) - [(2^3)/3  - 4(2)]\n= 27/3 - 12 - [(8/3) - 8]\n= 9 - 12 - (8/3) + 8\n= 5 - (8/3)\n= 7/3 (or 2 1/3)\n\nAdd them together and you get:\n9 + 2 1/3\n= 11 1/3 which is appromixately 11.333_
416338
As halibori says, you can use a graphing calculator and see where the lines cross.   I use a different machine, the one between my ears.   \n\nIf you add the two equations, the +3y in the first cancels the -3y in the second, leaving the equation  4x + x = -8 - 17, or 5x = -25.   This one's easy since the only unknown is x, and we see that x = -5.   Now\nwe can go back to the first equation, plug in the value -5 instead of x, and it becomes\n-20 -3y = -8, or -3y = 12, so we have that y = -4.
94721
y= 2x + 11 and y=-x + 5 \n\n2x + 11 = -x + 5\n3x + 11 = 5\n3x = -6\nx = -2\n\ny = -(-2) + 5\ny = 2 + 5\ny = 7\n\n(-2, 7)
844157
At x =0, y =5 is the y intercept.
427569
Substitute into the standard slope intercept equation. (y = mX+b)\n\n-4=(3/5)2+b\n-4=(6/5)+b\nb=-4/(6/5) \nb=-10/3\n\nThe equation is y = (3/5)x - (10/3)
433833
the answer to your question is x=3(4,6)
67171
Use the distributive property:\n4*5x + 4*(-9) =24\n20x + -36 = 24\n      +36   +36\n20x = 60\n--------\n20    20\nx=3\nI realize you already have the answer but sometimes the path is more important than the destination...
96194
Yes you are on the right track...Sort of.  \n\nSay you plug in any number for x.  We'll use 5\n\n-3(5)+y=-15\n-15+y=-15\n\nNow add 15 from the left to cancel the negative 15.  Then add 15 to the right to make the equation:\n\ny=0\n\nSo if x=5 and y=0 then your points will be (5,0)\n\nSay you have your original equation again\n-3x+y=-15\n\nNow plugin for x any number.  We'll use 1.\n\n-3(1)+y=-15\n-3+y=-15\n\nNow add 3 to the left to cancel out the negative 3 and add 3 to the right to make:\n\ny=-12\n\nSo x=1 and y=-12   (1,-12)\n\nHope that helps