how many protons are in a calcium oxide molecule?
116277
the chemical formula is CaO. So total no. of electrons are \nequal to sum of electrons in Ca and O. \nElectrons in Ca = 20\nElectrons in O  = 8\nSo total electrons = 28\nsince no. of electrons is equal to that of protons,\nHence answer is = 28
1118024
Acidic \n\nbelow 6 acidic above 7 basic
106971
13. And I believe you mean 13 electrons. 13 protons, 22 neutrons, and 13 electrons. The atomic number is the number of protons in the nucleus.
727510
it does not have to end with the s, and in the case of calcium, which has 20 electrons, the ground state would have the configuration ending in 3d2, because it is the lower energy state, see the link it is pretty cool\n\nhttp://www.webelements.com/webelements/elements/text/Ca/econ.html
986414
Start by balancing the equation:\n2Ca3(PO4)2 (s) + 6H2SO4 (aq)-----> 6CaSO4 (s) + 4H3PO4(aq)\n\nThen figure out the molar masses of each of the reactants:\nCa3(PO4)2 = 3(40.078) + 2(30.973762) + 8(15.9994) = 310.176724\n\nH2SO4 = 2(1.00794) + 32.065 + 4(15.9994) = 98.07848\n\nDivide each of your known masses of reactants by its respective molar mass to determine how many moles of each you have, and divide this number by the coefficient (the number in front) of the reactant to determine how many "parts" of each you have:\n(1000/310.176724)/2 = 1.612 parts 2Ca3(PO4)2\n(980/98.07848)/6 = 1.665 parts 6H2SO4\n\nTake the smaller number (since once you run out of one reactant, the reaction is over) and figure out how many moles of calcium sulfate and phosphoric acid you'll produce:\n(1.612)(6)(40.078 + 32.065 + 4(15.9994)) = 1316.7518832g CaSO4\n\n(1.612)(4)(3(1.00794) + 30.973762 + 4(15.9994)) = 631.872933536g H3PO4\n\nSince the total mass of reactants and products needs to be the same, you can check your (er, my) work by totalling up both sides:\n(1.612)(2)(310.176724) + (1.612)(6)(98.07848) = 1948.625g\n1316.7518832 + 631.872933536 = 1948.625g
783799
wait a minute.....i know this one.........calcium doesn't have multiple ionic charges so there's only Calcium (I) or just plain calcium.\nCaCl \nUnlike iron and copper and others calcium only has one ionic charge\n\nYou don't use prefixes with ionic compounds, however you do\n with molecular compunds\nGO COWBOYS!!!!!!!!!!!!!!!!! in your face indy 9-1
674948
HF + H2O => F + H3O+\nNH4+ + H2O => NH3 + H3O+\nH2CO3 + H2O => HCO3- + H3O+\nHNO2 + H2O => NO2 + H3O+\n\nbasically, the oxonium ion is formed in each one, when a proton is donated to water.
279663
Well, Sulfuric acid is a diprotic acid. The first proton is a strong acid, and the second proton is a fairly strong weak acid.\n\nBecause it's a strong acid, there will be 18 M of H3O+ ions.\n\n-log(18) = -1.255\n\nTo the correct number of significant figures, the pH is -1.26.\n\nEDIT: dr_futuredentist is very wrong. The second hydrogen\ndoes not dissociate fully at all.
739878
I am not sure what you are asking but the answer could be a monoatomic ion. The positive being a cation and the negative being an anion.\n\nYou might ask over at http://forums.mychemistrytutor.com though.
802465
carboxylic acid, as represented by -(C=O)-OH. For more info, check the source.
286893
proton radius = 2 x 10^(-16)m\nelectron radius = 2.817940285 x 10^(-15)m
757438
CaC2 + 2 H2O ---> Ca(OH)2 + HCCH
921680
Calcium and Strontium
205870
CaCO3(s) + 2HC2H3O2(aq)-> Ca(C2H3O2)2(aq) + H2O(l) + CO2(g)
311037
It's an organic acid having a\n\nO=C-OH group; the H of the -OH group is the proton source, \n\nthus: -O(-) H(+).\n\np.s. In aqueous solution. The fourth carbon bond is not drawn.
73319
the earlier equation is not balanced.\nCaO + 2HCl --------> CaCl2 + H2O
290781
MgSO4(s) + 2HCL(aq) ---> H2SO4(aq) + MgCl2 (aq)