How to calculate the 3 phase electrical power consumed by any electrical equipment withot using power meter?
113827
if you are using 2 machines 90kW each for 24 hours then your energy consumption per day would simply be,\n\n90 kW x 24 hours = 2160 kwh\n\nand since you're using 2 machines then,\n\n2160 kwh x 2 = 4320 kwh per day for the two machines
349215
mechanical power, P = Work done per unit time = W/t\n\nElectical Power P = current times potential difference = IV\n\nfor ohmic devices we can also use the substition from Ohm's law V = IR in the power formula above.
997515
vernier callipers \nmeasuring weights\nmagnet bars\nIC tester\nvoltmeter\nammmeter\nenergy meter\nMultimeter\nDC Power Supply \nFunction Generator \nDigital Multimeter \nOscilloscope \npower wires\nBreadboard\nresitors \ncapacitors\nvoltage divider and current divider circuits
560205
Please refer this link \nhttp://www.sepialine.com/docs/html/Power%20Logic%20Connector%20Manual.htm
517654
Need to know the impedance of the solar panel to determine current.
1112798
An electric meter measures energy usage, not power.\n\nThe kilowatt is a unit of power (energy per unit time).\nA kilowatt hour is a unit of energy.\n\nThe question should either be asking for the speed of rotation of the disk if the energy usage is at 1 kW of power, or the unit should be changed to kWh instead.\n\nIt seems to reason that for every 1 kWh of enegry used, the metal disk on the "power meter" (really an energy meter) would go around once, but in reality, they might be designed a tad more complicated than this.
118710
The meter must measure the power you use (and must pay for) using the formula P = IE (power equals current (I) times voltage (E)).  To do so it must accurately dedect the line voltage and electrical current entering your house.  The meter contains an aluminum disk that you can see spinning fast or slow depending upon how many (or few) electrical devices you have turned on.  Inside the meter there are two coils of wire (one on top and one on the bottom of the disk).  One coil senses instaneous voltage that can vary (and even droop in a brownout).  The other coil detects all the current you are using, if any.  With your main circuit breaker open there will be none.  When there is both voltage and current flowing, magnetic eddies are produced that measure and integrate the power being used by spinning the aluminum disk (like a small motor) which is connected to a set of gears that turn the meter numerals.  See the link for an illustration and detailed explanation.  Good luck.
1112270
Look on your electric bill to find the billing rate.  It would be a simple calculation from there.
653976
You need to use Ohm's law.\n  E=I x R  \n  E=Voltage. I=Current/Amps  R=Resistance/Ohms\n  E= 9voltsDC\n  I= 3amperes.\n  R= ?\n  So:\n  R = 9volt/3amp\n  R=  3ohms
38597
P= work/time and work is = to force x distance so its 500x4 =2000joules\nand 2000/4 =500 watts
1187367
It is billed based on no. of units consumed.\n1 unit = 1 kilowatt hour\nThe meter works on the principle of electro-magnetic induction.\ni.e.,the revolving fluxes set up as  a result of loading sets up an alternating flux which links with the cu ring (that rotates in in meter) and induces an emf which causes a current to flow.the current flowing in the cu ring sets up its own flux and it opposes its cause. As a result the Cu.ring rotates. The unit is recorded based on the no. of revolutions made by the cu.ring
855117
It appears you are speaking of apparent power. \nTransformers are rated in VA (volt X amps) called apparent power. \nIn a DC circuit power is determined by multiplying voltage X current (E X I = P). In an AC circuit power is determined the same way only when voltage and current are in phase with each other which means they are rising and falling falling at the same time. \nWhen they rise and fall at slightlly different times the time difference is known as a phase angle and the cosine of this angle is also applied to the E X I =P formula making it E X I X the cosine of the angle. This formula is used to determines the TRUE POWER of the AC circuit or any transformer circuit. \nTo sum it up, the APPAREMT POWER is always volts X amps. The TRUE POWER is always VOLTS X AMPS X the cosine of the angle. \nThe angle becomes larger when inductors, motors and capacitance are part of the load circuit.
1040867
Using 3 phase current, it is possible to get 3 times the energy down the same wire - so it is much more efficient.  Each phase is 120 degrees out from the others, so the signal looks kind of like braided hair, when one phase is at the peak, the other two are crossing at 70%, one going up the other going down.  Once we get the energy to where we want to use it, then we can tap off the different phases for single phase use. \n\nI forget about the delta and wye stuff, it's been a while. \n\nCheers!
63042
Electric power has two components:\n\nActive power, which produces work.\nReactive power, which is needed to generate magnetic fields required for operation of inductive electrical equipment, but performs no useful work. \nActive power is measured in KW (1000 Watts) \nReactive power is measured in KVAR (1000 Volt-Amperes Reactive) \nTotal power is measured in KVA (1000 Volt-Amperes)\n\nPower Factor is the measure of the relationship between Active and Reactive power at the point of consumption.\n\ncheck out powerfactorhelp.com -- pretty clear and simplistic
80787
it shouldnt mater that much, 3 phase power fires one after another, if all three have the same voltage, amperage, and Hz. the only thing, that i can think of, is to make sure that they are cycling in order. DO NOT CONECT TO MOTOR, if the motor is conected and the wires are conected in the improper order, it will not run backwards, it will cause severe damage, as far as i know. runing backwards would only work in 2 Phase power, Maby. Be carefull when using multi-meters with 3 Phase power, i read on my meter that that source can be unpredictable and very dangerous. A good meter and good judgement can do a lot of help in this situation. I think that if you just guess and hook them all up, and be ready to turn it off quickly, then if it is incorect you just switch your b and c wires and it should work. if you have a meter i think that some power setups have the a and b lines at 115vac and c is higher, MABY! i do not know for sure how to discover for sure what they are, but i dont think that ossiliscopes are the corect tool for the job. good luck
511307
well you need the power factor as well, From O/P KW to I/P KW by I/P KW = O/P KW / Efficiency; I/P KVA = I/P KW / power factor; I/P Current = I/P KVA / (V3 x 480); V3 is a 3 phase motor is used. so simple.
681299
Power = Volt X amps\nP/v= I\n100/130 = .77 amps\nMIKE