solve equation by add. method 2x+y=-4  -5x+3y=-1?
117592
Multiply the 1st equation by 3\n\n3 [ 2x + y = -4]\nthat gives.. 6x + 3y = -12\n\nsubtract the 2nd equation from this\n\n6x + 3y - (-5x + 3y ) = -12 - (-1)\n\n6x + 3y + 5x - 3y = -12 + 1\n\n11x = -11\n\nx = -1\n\nput this into 1st equation\n\n2(-1) + y = -4\n\n-2 + y = -4\n\ny = -4 + 2\n\ny = -2\n\n\nx = -1 & y = -2\n\nyou can check this with 2nd equation\n\n-5(-1) + 3(-2) = -1\n+5 - 6 = -1 . hence the solution x = -1 & y = -2 is CORRECT
474164
x=5x-y\n\nx-5x=-y\n\n-4x=-y\n\ndivide both sides by -4\n\n(-4/-4)x=(-y/-4)\n\n1x=(1/4)y\n\nx=y/4
714041
10x+4y+4\n\nor can be written as y= -2.5x-1
86546
(3y+1)(-2)+y\n-6y-3+y\n-5y-3\n\n12s+(7-s)2\n12s+14-2s\n10s+14\n\n7x-3x(x+1)\n7x-3x^2-3x\n-3x^2+4x\n\n3t(t-5)+6t^2\n3t^2-15t+6t^2\n9t^2-15t\n\n4w^2-w(2w-3)\n4w^2-2w^2+3w\n2w^2+3w
904136
if x+y = 5 and 2x+y =6, then x = 1 ( by subtracting two equations)\nif x =1, then y = 4\n\nthus x -y = 1-4 = - 3\n\ncool :)
892382
To solve the first one, divide each part of the first equation by two, so 2x-3y=-13; since -2x+3y = 13, adding the two equations gives 0x+0y=0.  No help.  Try substitution.\nFrom the first equation, 4x = 6y-26; x = 1.5y - 6.5\nsubstitute into the second equation -2(1.5y-6.5) + 3y = 13; -3y +13 + 3y = 13; 13=13.  Still no help.\nBoth equations are equivalent; the line that represents them is the solution.\n\nProblem two:\nSubtract equation 2 from equation 1.\n3x-3x+2y-3 = 6 - y\n2y-3 = 6-y\n3y = 9\ny = 3\n3x+6=6\nx=0\nchecking\n3x+3=y=3\n3x=0\nx=0
518063
Solving a system by addition involves simply adding the two equations together. First, however, you have to do a little prep work. Either the x's or the y's must be of the opposite sign. I'll show you how to do the y's first, because it is easier.\n\n5x-3y=13\n4x-3y=11\n\nThe y's need to be opposite. What is the simplest way to do so? Make one of the -3y's into a positive 3y. Thus, multiple one of the equations by -1.\n\n-1(5x-3y=13)\nbecomes\n-5x+3y=-13\n\nNow you have\n-5x+3y=-13\n4x-3y=11\n\n+3y + -3y = 0\n\nYou have just canceled out the y's.\n\nNow you have:\n-5x=-13\n4x=11\n\nAdd these together and you get:\n-x=-2\nThus, x=2\n\nNow you know x. Take either of the original equations, and substitute in your new x.\n\n5(2)-3y=13\n10-3y=13\n-3y=3\ny=-1\n\nThat's it! Hope I helped.
973940
A previous answer was incorrect. It is\n\n-4x(x+3y)(x-2y)
631059
3y+5=y-25\n2y+5=-25\n2y=-30\ny=-15\n\nSee, you just use inverse operations.\n\n4n-5=2n+3\n2n-5=3\n2n=8\nn=4\n\nSo your answers are y=-15 and n=4. I hope that helped!
718048
x + y = 3\n\nSolve for a variable.  I chose X.\nx+y = 3\n -y    -y\nx = 3 - y\n\nSubstitute the value of X in the first equation.\n2(3-y) + y = 4\nDistribute.\n6-2y+y = 4\nAdd like terms.\n6-y = 4\n-6    -6\n-y = -2\nmultiply by -1.\ny=2\n\nSince you know Y = 2, substitute that back into the second equation that you solved for X with.\nx + y = 3\nX + 2 = 3\n  -2    -2\nX = 1\n\nX = 1\nY = 2
599677
i know how 2 do this.\n4x+2y=2\n x-2y=8\n---------\n5x   =10\n5x=10\nx=10/5\nx=2.\nsubstitute x=2 in any1 of the equations.\nlet us take x-2y=8.\n  2-2y=8\n  -2y=8-2\n  -2y=6\n    y=6/-2\n    y=-3.\n therefore ur x=2 nd y=-3.
77049
first you have to tell us what you're solving for.(either x or y).\nIf you want to combine like terms u have to add 2y+2y you get 4y,then you try 4y+4x = ?.\nBut you forgot what is equal to if you're solving \nfor the letter x or y
226701
For the second equation, use x=-1+y or x = y-1, then substitute that for x in the first equation, and solve.\n\n5(y-1) - 2y = 10\n\nYou should be able to take it from there.  You really should do your own, or you won't do well on the test.
1136858
y + 1 = 2y + 5\nSubtracting y on both sides\n1 = y + 5\nsubtracting 1 on both sides\n0 = y + 4\nTherefore y = -4
895237
you do not get specific values, there are infinite number of solutions for each equations\n\n2x + y = 9, y= -2x + 9\n\n-x - y = - 8, y=-x+8\n\n- 3x + 4y = 2, y = 3x/4 - 1/2\n\n- 2x - y = - 3, y= -2x +3\n`
222015
5x - 2y = 4  (1)\n2x + 3y = 13 (2)\nmul. eq.(1) by 2: 2 (5x - 2y = 4)\n                    10x - 4y = 8\n\nmul. eq.(2) by 5: 5 (2x +  3y = 13)\n                    10x + 15y = 65\n\nsubtract: 10x -  4y =  8\n      (-) 10x + 15y =  65\n          ________________\n               -19y =  -57 \n                  y =  -57/-19\n                  y =  3\n\nsubstitute value of y to any of the eqs.\n\nSubstituting to eq. (1):\n\n    5x - 2y   = 4   \n    5x - 2(3) = 4\n    5x - 6    = 4\n    5x              = 4 + 6\n    5x              = 10\n     x              = 10/5\n     x              = 2\n\nso, x = 2\n    y = 3\n\nto check, substitute values of x and y to any of the two equations:\n    for eq. (1),\n\n    5x   - 2y   = 4   \n    5(2) - 2(3) = 4\n      10 - 6    = 4\n\n    for eq. (2),\n\n    2x   + 3y   = 13\n    2(2) + 3(3) = 13\n      4  + 9    = 13
923416
Sometimes I like math.  What you need to do is add 1 to both sides of the equation for x=3y-1\nyou will be left with (x+1)=3y you should then divide the 3 from both sides... afterwards you will have (x+1)divided by 3 equals y or (X+1)/3=y\nFor the other part x+2y=9 you should substitute (x+1)/3 for the "y"\nNow solve x + 2((x+1)/3)=9\nx+(2x/3) +(1/3)=9\ntake from there