i have eight 8's equal to 1000. give your solution?
108568
Here are two fantastic ways:\n   \n  (8888 - 888) / 8 = 1000\n\nand\n\n  888 + 88 + 8 + 8 + 8 = 1000
932821
adding 2x+3\n8x=24\ndividing by 8\nx=3
285803
It is\n\n   888\n  +088\n  +008\n  +008\n  +008\n --------\n  = 1000\n --------
1081089
[ (50000 x 2.4)+(25000 x .8) ] / (50000+250000)=1.8\n\nThe remainder of the info in the problem is not necessary.
1143015
8(8X8+8X8)-8-8-8=1000\n\n-unpredicktaboh-
362147
8 X 11=88\n\n88 X 154 = 13552\n\n13552 +76= 13628\n\n13628 -3 = 13625\n\n13625 + 7= 13632\n\nTHERE THERE ALL BETTER
813994
the first one is (x+10)(x+8)\nand the second one is your second answer
23893
There IS a solution:\n\n1x - .15x = 680\n\n.85x = 680\n\n.85x/.85 = 680/.85\n\nx = 800\n\nThere you go!!!
889891
~..-8,-6,-4,-2,0,2,4,6,8
469878
10 * 9 * 8 * 7 * 6 = 30240 combinations
928231
8x-10x > -11-1\n\n-2x > -12\n\nx < 6
457868
It's possible to get 100 using even THREE eights!\nAnd this is in DECIMAL, not binary base!\n\n100 = -log_8 (log_8 (sqrt(sqrt(...sqrt(8))))),\n\nwhere log_8 is logarithm in base 8\nand the number of square roots is 300.\n\nLet's prove it.\n\nA = sqrt(sqrt(...sqrt(8))) {300 roots} =\n= ((8^(1/2))^(1/2))...^(1/2) {300 powers} =\n= 8^(1/2 * 1/2 * ... * 1/2) {300 multiples} = \n= 8^(1/8 * 1/8 * ... * 1/8) {100 multiples} = \n= 8^(1/(8^100)) =\n= 8^(8^(-100)).\n\nlog_8 (A) =\n= log_8 8^(8^(-100)) =\n= 8^(-100).\n\nlog_8 (log_8 (A)) =\n= log_8 8^(-100) =\n= -100.\n\nHence, -log_8 (log_8 (sqrt(sqrt(...sqrt(8))))) = 100.\n\nQED\n\nYou can use forth eigth, for example, to change every one 8 in that formula to sqrt(8*8).
966925
There are 3 solutions for ABCDEFGHJ -\n\n2 6 7 8 3 5 1 4 9\n2 6 7 9 5 3 1 4 8\n6 7 8 4 1 3 2 5 9
940725
64/x=8/100\n8x=6400\nx=800
864795
8(t-2sqrt(a))(t+2sqrt(a))
865514
12 and 7/8ths\n\nconvert the 1/2 to 4/8, the 3/4 to 6/8, add the fractions to get 15/8 which is 1 and 7/8, then add the whole numbers
901509
2, i think....8*6 = 48\n9*7 = 63\n7*2+1 = 15\n9*3+1 = 28