If a trapezoid is inscribed in a circle with 12 and 16 bases and the radius of the circle is 1, what is Area?
117539
A trapezoid has 4 sides but you talk about 12 and 16 bases - I assume you mean 12 and 16-sided polygons. The question can be answered, as stated, if we assume that the sides of each polygon are the same length - if the sides are not the same length then the question can't be answered until you tell us the lengths of the sides. Polygons with sides that are the same length are called "regular polygons."\n\nAnswer:\n\n1) The area of a 12-sided regular polygon inscribed within a circle with a radius of 1 is 3\n\n2) The area of a 16-sided regular polygon inscribed within a circle with a radius of 1 is 3.0614674589207183
326809
The area of a trapezoid is the height times the average of the bases, or h*(b1+b2)/2.  In your case, your bases are the top and bottom of your figure (parallel to the x-axis), and your height is along the y-axis.  So,\n\nh = a\nb1 = c\nb2 = b\n\nA = a(b+c)/2
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Area increases 4 times. Beacause Area of circle = PiR2.\n\nSo if R doubles then radius will be 2R.\n\nHence area will be Pi(2R)2. which results into\n\n4 Pi R2.
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limit is not specified so we asume whole area\n\nx^2+y^2 = a^2\n\nthis is a circle of radius a\n\nso area = pi*a^2
803161
That's the equation of a circle of radius 12 & the center at (6,4)
539392
I'm thinking of a trapezoid with a base of 9 on top and 17 on the bottom, with the other two sides being 5.  If I were to drop a verticle line from one corner where the 9 base meets one of the legs to the other base, then I have a right triangle.  The hypotenuse would be 5 and the base would be (17-9)/2 = 4.  So the height would be sqrt(5^2-4^2) = 3.  So you have a trapezoid that has bases 9 and 17 and height 3, so the area is\n\nA = (17+9)3/2 = 39 (Area of trapezoid is (b1+b2)h/2, where b1 and b2 are the length of the bases and h is the height.)\n\nedit: Ooh, I just found a formula you can use if you know the length of the sides.  Let a be the length of the longer parallel side, c be the length of the shorter parallel side, and b and d be the legs.  Then\n\nA = (a+c)/(4(a-c))*\nsqrt((a+b-c+d)(a-b-c+d)*\n(a+b-c-d)(-a+b+c+d))\n\nSo in your case a = 17, c = 9, b = d = 5.\n\nA = (17+9)/(4(17-9))*\nsqrt((17+5-9+5)(17-5-9+5)*\n(17+5-9-5)(-17+5+9+5))\n= (26/32)sqrt(18*8*8*2)\n= (26/32)(48)\n= 39\n\nSorry, I have to line break sometimes because Yahoo likes to truncate.\n\nSo either way...
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The center is (-4, 6) and radius sqrt(64) = 8\n\nThis is because the equation of a circle with center (a,b) and radius r is\n\n(x-a)^2 + (y-b)^2 = r^2
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It's a trapezoid.  The base is 9 (11-2) and the top is 3 (8-5).  The height is 4 (5-1).\n\nThe area is the average of the bases x the height.\n\nSo that is (9+3)/2 x 4\n\n= 6 x 4\n= 24 sq. units.
824
Volume of cylinder = area of base * height.\nSince the base is a circle, that part is Pi *r^2\nSo we have Pi * r^2 * height --> \n3.14 * 12^2 * 21 = ?\n\nVolume of square prism = area of base * height\nSince the base is a square, that part is side^2\nSo we have 12 * 12 * 21 = ? \n\nSubtract the results for your final answer.
921006
Area = πab where a and b are the semi-major and semi-minor axis length
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15 inches\nThe side of a regular hexagon inscribed in a circle is the same as the radius of the circle. In fact, if you connect the center of the circle to each vertex of the hexagon (with a straight line segment), then you will have 6 equilateral triangles that all meet at the center of the circle.
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The area of the trapezoid is the average of the bases times the height.\n\nThe average of the bases (2x + 4x)/2 = 3x, which is also the height.  So:\n3x * 3x = 324\n9x² = 324\nx² = 36\nx = 6\n\nSo the bases are 12 and 24 and the height is 18.
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triangle area = 1/2(height * width)\n\ncircle area = pi * radius^2
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well the radius of the inscribed circle is r=S/p, where S is the area of the triangle (b*c/2) and p is the semiperimetre ((a+b+c)/2); so r=bc/(a+b+c), where b,c are the sides of the triangle and a is the hypotenuse.\nif r is an integral, then a+b+c divides bc, so b and c are of integral type.
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The triangle area formula is\n\nA = 1/2 b h\n\nA = 1/2(8)(12)\n\nA = 8/2(12)\n\nA = 96/2\n\nA = 48\n\nThe area of the triangle is 48 inches\n\n- - - - - - -s-
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Ok, If A is a point on the circle and C is the middle of the circle then AC is the RADIUS of the circle.  Which means any point on the circle to C WILL ALWAYS be 12.  So if the excess of the circle to B is 8, then Add the RADIUS to the distance to B, and we arrive at the result of 20. Which is AC + (Distance of circle to B)\n\n20
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A trapezoid is a 4-sided figure with one pair of parallel sides. To find the area of a trapezoid, take the sum of its bases, multiply the sum by the height of the trapezoid, and then divide the result by 2.