What molarity is physiologically isotonic glucose solution? (show your work)?
107796
Well, now that you know phys saline is 0.85%  YOU do the work.
39876
To answer this question you must look at your given data. 13% of 1.1 = .143 so you have .143g NaCl for every ml solution. Molarity is moles solute/liters solution. You just calculate how many grams NaCl are in a liter and convert to moles, do the division and your done.
952788
A=E*d*C\n\n(d=length of the path of the light through the solution)\n\nIf you have only one value of absorbance then obviously there is no way of determining the concentration without the molar extiction coefficient (E).\n\nIn practice even if you know E, you don't use it to find the unknown concentration. Instead you measure the A of standard solutions and do a standard curve. From the equation of that curve (which you find using linear regression) and the value of A of your sample you calculate the unknown amount. \nThe standard curve doesn't need to be A vs mole/lt. It can be A vs anything e.g. g/ml, mg/ml, ppm or even just g, mole, etc. the only thing that changes is what the slope represents.\nFor example for A vs mole/lt the slope corresponds to E*d, for A vs g/lt the slope corresponds to E*d/MW, etc.\n\nIf you  always have the same volume of sample you can do the curve A vs grams directly. Then if V is the volume of the sample, the slope corresponds to E*d*V/MW\n\nEven if your standard curve is expressed in moles/lt you can convert it to grams. You just need the MW of the compound and the volume, not E...
1168891
The balanced solution is nothing else than a special physiological salt solution.  Near the sodium chloride it generally contains CaCl2, KCl, potassium and sodium-phosphate, Mg-salt(chloride or sulphate), sodium hidrocarbonate.\nAs additional component it may contains some glucose and/or phenol red as a pH indicator.
205076
Since the density is 1.04 grams/mL and there are 410 mL...there is 426.4 grams of solution (Multiply 410mL by 1.04 grams/mL to give you the mass).  Since it contains 9.50% sugar BY WEIGHT, you can simply multiply 426.4 by 9.50%.  This gives you 40.508 grams.\n\nCALCULATIONS:\n1.04 g/mL * 410 mL = 426.4 grams\n426.4 grams of solution * 9.50% sugar = 40.508 grams of sugar
898113
The solute CaBr2 contains 3 ions, which are all separated when it dissolves in water.\nGlucose, although it is a big molecule, is only one particle. Therefore CaBr2 provides three times the lowering of freezing point that glucose does\nBoth substances are freely soluble because the particles have a good attraction to water. But the solution of CaBr2 will not freeze at -5C because it has 6.00M of ions in it (3 x 2.0M).
928965
molarity  = moles / liters\n\nmoles = given mass / molecular mass\n\n10 g H2SO4 / 98 g per mole = about  0.1 moles\n\n0.1 moles / 1 L = 0.1 M solution
622582
As no one else has had a go, i will. \n\nCellulase should produce glucose, so you are needing a method to analyse the amount of glucose formed. \n\nIf you have access to a blood glucose monitor, this would be the simplest way. Otherwise, the reaction between glucose and Benedicts solution is quantitative, and you could weigh the amount of Cu2O formed.
360139
A solution with the same ionic concentration as a cell.  For example, PBS is a isotonic solution with respect to human cells.  Hypertonic is higher ionic concentration, hypotonic is lower ionic concentration.  hyptonic solns will lyse cells because of osmosis, water flows into the cells while solutes flow out of the cell, to reach equilibrium.  Thus cells will lyse in water without signficant amts of solvents.
663838
I agree with Thinkstoomuch's Answers in most part.  \n\nSolid Cu, C will not be soluble in water.  However glucose and  CuBr2 will be soluble in water.  At STP solubility of glucose (C6H12O6) is about 90g/ml.  That eliminates choice 1 and 3.\n\nWhen a compound ionizes in soln it makes electrolyte.  Glucose will not ionize but CuBr2 will ionize to Cu++ and 2Br-, choice 4 can be eliminated.\n\nThe third clue is just there to confirm your answer and CuBr2 being an ionic compound will indeed have a relatively high melting point.  498°C to be exact.  \n\nClearly, Cupric Bromide should be your Answer.\n\nI hope this helps.
122405
erm, high, like really hot. ok, the melting point of α-D-glucose: 146°C\nβ-D-glucose: 150°C [1]\nit probably decomposes before it boils but i found this phase change data [2]\n\nQuantity Value Units Method Reference Comment \nTfus 423. K N/A Kofler and Sitte, 1950 Uncertainty assigned by TRC = 3. K; With "hot stage" \nTfus 420. K N/A Kofler and Sitte, 1950 Uncertainty assigned by TRC = 4. K; By "differntial thermal absorption" \nTfus 414. K N/A Parks and Thomas, 1934 Uncertainty assigned by TRC = 2. K
445032
Click on "Add details," post the problem, and, as SMeghead said, someone might be able to help.\n\n(EDIT: You didn't provide too much information. From what you gave, about all we can say is that 12.5% of the solute - 1% from 8% - evaporated. If you need to know how many grams, milliliters, cubic centimeters, etc. evaporated, we'll need more information.)
5197
More information is needed.  What is the concentration is it a percentage or a molarity.\n\nDo you need to find the concentration or just the amount of alchohal?
842422
Yes, it is true that the density of a solution is different of solvant but tjis difference is small ; So , i propose to dissove 40g of amyl acetate in a liter of water if that acetate is a solid. If that acetate is aliquid the total volume will be 1.04 l and you must use 47 cc tp water
1099901
http://www.amarillomed.com/howto.htm#Glucose:
968320
here, you just use the ideal gas law, PV=nRT.  since molarity is equal to moles of solute per liters of solution, M=n/V, so P=MRT.\ntherefore,\nKp=Pco*Ph2o/(Ph2*Pco2)\n  =[CO]RT*[H2O]RT/ ([H2]RT*[CO2]RT)\nall the RT coefficients end up canceling out, so:\nKp=[CO][H2O]/[H2][CO2]\n  =Kc\nsince there were equal numbers of gas molecules on each side of the equation, Kp was equal to Kc.  as a general rule, Kp=Kc*(RT)^N, where N is the change in the number of gas molecules.
116087
keeping with the same unit fractor harry is correct.\n \n .2 ml