pressure of 745mm Hg equals?
105912
1 atm. = 760.0 mM Hg = 760.0 Torr = 14.70 psi = 1.013 Bars = 1033 cM water = 101.325 kPa.\n\n745 mM Hg = 745/760 = 0.983 or so atmospheres.\n\nA great conversion program can be found at:
290343
The pressure on the surface is roughly 14.7 PSI. Each 10m of depth is equivalent to 1 atmosphere. Therefore, at 120m, it must withhold 12 atmospheres or 176.4 PSI.
180516
Well, P * V = n * R * t\nRight side is equal before and after changin` pressure.\nSo, P1 * V1 = P2 * V2\nP1 = 1.01 kPa ;\nV1 = 458 mL ;\nV2 = 477 mL.\nP2 = (P1 * V1)/V2\nP2 = (1.01 kPa * 458 mL)/477mL\nP2 = 0.97 kPa\n\nP.S. You didn't have to say how much is the temperature, it doesn't mather.
934061
40-65 PSI - that's the standard.
544209
Assuming that the column of Hg is a cylinder with a base with radius 5, and volume unkown, we can use the equation for the volume of a cylinder to determine how high it must be. But remember the high is dependent on the radius of tha base.\n\n760 mmHg = 101,325.024 Pa\n\nPa = [F]/{A] = N/m^2\n\n101,325.024 [Pa] = (1.36x10^4 [kg]/[m^3] * 9.81 [m]/[s^2]\n* [volume][m^3])/(78.53[m^2])\n\nUnits:\n\n[Pa] = [Pa]\n\nvolume = 59.64 m^3\n\nvolume = [pi][r^2][H]\n\n59.64 m^3 = [pi][25m^2][H]\n\nH = 2.3856 m
710153
Usually psi (pounds per square inch).\n\nAloha
652894
the amount of pressure exerted on an object
797227
You have Pressure (being asked) You have the volume (5.43L). You have the number of moles (1.82)You have temperature (69.5C or 342.5K). I assume you know R.\nSo yes it is PV=nRT
1105154
pressure is: \n p(density)gh / gc =y(specific weight)h\nflow of liquid flowing inside the pipeline is:\n use the bernoulli equation:\n [p1/p(density)g  +  v1^2/2g  +  z1]  =  [p2/p(density)g  +  v2^2/2g  +  z2  +  hf]\n\nnote: p(density) is rho and y(specific weight) ir gamma.
372621
Since the speed is constant, the pressure difference is only due to the pressure exerted by the 4m column of liquid.\n\nThe pressure exerted by “h” column of liquid of density‘d’ is hdg.  (g= 9.81 m/s^2). \n\nhdg = 4 x 925 x 9.81 = 36297 pascal.
956075
The maximum "inches of vacuum" would be roughly equal to the barometric pressure outside, around 29.92 inches for a typical day (1 atmosphere here on Earth).  This would be, for example, how far the mercury would rise if you pull air out of the top of a tube whose lower end is in a pool of mercury.\n\nAnother way which is commonly used in science and engineering is to measure in "inches of mercury" or "mm of mercury" (torr).  In this case, you pull a near perfect vacuum inside the tube (by sealing the end, filling it with mercury and flipping it over) and see how high the mercury is when it stops draining out.  A perfect vacuum in this case would be zero inches.  It all depends on whether you're measuring the vacuum inside the tube or outside!
786443
mass * gravity / area\n\n79.5 * 9.81 / (2 * 0.018) = average pressure\n\nunits:\n\nkg * (m/s^2) / (m^2) = N/m^2 = Pa (Pascals)
821966
Not sure where the 600 came from, but it sounds like the question wants the total pressure of all the gases combined.  So you would just add together all the partial pressures, and the total pressure is 330 mm Hg.\n\nDividing the total pressure by the number of gases would give you the average partial pressure, but I don't think that's very useful.
693006
Pressure is force divided by area.You can use various units of pressure. One is Pascals. A pascal is 1 Newton per squared meter (N/meter^2).\n\nSince you have 125 cm-squared you need to convert to squared meters:\n\n125cm^2 x (1m^2/10,000cm^2)= .0125 m^2, area\n\nA Newton is kg x 9.8=75Kgx9.8= 735 Newtons\n\n735N/.0125m^2= 58,800 Pascal
872661
If nitrogen makes up 78% of the air, it will be responsible for 78% of the pressure, namely 760(0.78) = 592.8 mm Hg.
926935
PV = nRT\n\n685 mmHg / 760 = .901 atmospheres\n\n18.6 mmHg / 760 = .0245 atm\n\n.901-.0245 = .8765 atm\n\n21 degrees c = 294 K\n\n.8765 atm x 7.80 L = n x .08206 x 294 K\n\nsolve for n then use the molar mass of H2 (2.016) to convert to grams.\n\nmy calculator's out in the car or else i'd do it for you.
190939
ehm...aren't you suppose to substact 200psi of residual pressure from that 1300psi 1st?  giving you 265.7 minutes left.