Height and widthe of a trapezoid?
100993
how do you din the height of a trapezoid if one of the non parallel sides is straight, and the other is slanted. Which makes the two parallel sides different lengths? Also, how would you find the width of a trapezoid in this situation?\n\nIf the length of the shorter parallel side is A and the length of the longer parallel side is B and the length of the straight side is C and the length of the slanted side is D then:\n\nthe height is:\nh = C (the length of the straight side.\n\nThe width depends on where you measure the width.\n\nI am imagining that your trapezoid looks like this:\n.__\n/__|
1046488
length x width (in inches)\n\ndivide by 12 ( feet)
622265
a trapezoid ia a quadrilateral with only two parallell sides.\n\nas to figuring out what CD is, i'd need to know what MA and HT are (are they lengths of sides? measurements of angles?)  so, if you post those, then i'll see what i can do
486266
the formula for volume of a cylinder is V = h * pi * r^2.\nAlternatively, the surface area is A = h * pi * r * 2.\n\nSo, if you have either the surface area or the volume, you can calculate for the height.\n\nH = Volume / pi * r^2\nH = Area / pi * r * 2
836045
The area of the trapezoid is the average of the bases times the height.\n\nThe average of the bases (2x + 4x)/2 = 3x, which is also the height.  So:\n3x * 3x = 324\n9x² = 324\nx² = 36\nx = 6\n\nSo the bases are 12 and 24 and the height is 18.
720499
7.3m (width) by 2.4m (height)
348844
It sounds to me like you are talking about a trapezoid. Go to the website I have listed under my sources and see if what you are describing looks like the trapezoid on there. If it is a trapezoid, the area formula is  Area = 1/2h(b1 + b2). h=height, b1=base 1, b2=base 2
819602
If the bases are in the ratio of k:1, then we can say they have lengths of kx and x (kx and x have ratio k:1). Let's say the trapezoid has height h.\n\nThe mid-segment of the trapezoid cuts the trapezoid into two similar trapezoids, and has length (1/2)(kx + x)\n\nThe area of a trapezoid is (1/2)(height)(b1 + b2).\n\nThe top trapezoid has height h/2, and bases kx and (1/2)(kx + x).  It has an area \nA1 = (1/2)(h/2)(kx + (1/2)(kx + x))\n     = (h/4)(kx + kx/2 + x/2)\n     = (h/4)(3kx/2 + x/2)\n     = (hx/8)(3k + 1)\n\nThe bottom trapezoid has height h/2 and bases (1/2)(kx + x) and x.  It has an area\nA2 = (1/2)(h/2)((1/2)(kx + x) + x)\n     = (h/4)(kx/2 + x/2 + x)\n     = (h/4)(kx/2 + 3x/2)\n     = (hx/8)(k + 3)\n\nIf A1:A2 = 5:2, then \n[(hx/8)(3k + 1)]/[(hx/8)(k + 3)] = 5/2\n(3k+1)/(k+3) = 5/2\n2(3k+1) = 5(k+3)\n6k + 2 = 5k + 15\nk = 13\n(C)
489663
Reviewing the facts:\n\n1.  You're constructing a pentagon and two trapezoids by using the center of the square.  Since the sides are 1, the short parallel side of the trapezoid is 1/2.\n\n2.  Since the two trapezoids are congruent, the short parallel side is midway in the square.  So the height of each trapezoid is 1/2.\n\n3.  Since there are three areas now, and each area is equal, the area of the trapezoid is 1/3.\n\nThe area of a trapezoid is A = (1/2)h(b1 + b2).  We have everything we need now to solve for b2, the longer parallel side:\n\nA = (1/2)h(b1 + b2)\n1/3 = (1/2)(1/2)(1/2 + b2)\n1/3 = (1/4)(1/2 + b2)\n4/3 = (1/2 + b2)\nb2 = 5/6
584072
I would use the trapezoid rule myself. For seven vertices:\nV0 = (x(0),y(0))\nV1 = (x(1),y(1))\nV2 = (x(2),y(2))\n...\nV6 = (x(6),y(6))\n\nFor notational convenience, define V7 = V0.\nThat is, x(7) = x(0) and y(7) = y(0).\n\nThen the area is:\n\n 6\nSUM ( x(i+1)*y(1) - x(i)*(y(i+1) ) / 2\ni=0\n\n= ( x(1)*y(0) - x(0)*y(1)\n + x(2)*y(1) - x(1)*y(2)\n + x(3)*y(2) - x(2)*y(3)\n + x(4)*y(3) - x(3)*y(4)\n + x(5)*y(4) - x(4)*y(5)\n + x(6)*y(5) - x(5)*y(6)\n + x(0)*y(6) - x(6)*y(0) ) / 2\n\n\nIf the heptagon is regular, you don't need to know the coordinates of the vertices, just the length of the regular side(s):\n\nA = (7/4) * s^2 * cot(π/7)
893599
You may want to be more specific on this one... are you trying to find the largest possible area? You can inscribe lots of different trapezoids in a circle. \n\nAnd which theta are we talking about? The angle that the base makes with the circle?\n\nTry that one again,\n\nUMRmathmajor
605775
Are you talkin about a trapezium or a trapezoid.\nif its a trapezium,here's how : \nlet the height be "h".\ndrop two perpendiculars equal to h on the base.the lengths b&#92;w the perps.is 6 units.therefore the rest of the length is 10.each individual length to the left of the perp is 5 units.\nin the triangle with the diagonal,the side adjacent to the angle with the base and diagonal is 6+5=11\ntherefore the angle is cos^-1(11/12)=a\ntherefore tan a=h/11\ntherefore h=11tan a\nanswer is height,h=4.795831523
680840
Trapezoidal Rule : area occupied by given curve,y=f(x),\nbetween limits (a,b),divided into various values,x0,x1,x2,...xn,for which corresponding values are y0,y1,y2,y3....yn=f(xn).\n\nHence area =A=integration(y)=integration(f(x))\n\nA=Integration between a and b(f(x))\n\nA=(h/2)[(y0+yn)+2(y1+y2+....yn-1)]\nwhere h=(b-a)/n
710674
I hope by width you mean height.  If so then the answer is πr^2 * h\nso π15^2 * 60 \n\n13500π\n or \naprox.  42411.5
814748
The obtuse angles of the trapezoids will be (in degrees) 90+invtan((57.35-29.27)/(2*27.54)), which is approximately 117 degrees.\n360 degrees minus the sum of two of these angles (126 degrees) is the interior angle of whatever regular polygon you are trying to make.\nThe interior angle of a regular hexagon is 120 degrees.\nThe interior angle of a regular heptagon (7-sided polygon) is approximately 128.57 degrees.\n\nTherefore, you could put 6 of these tables into a circular arrangement and have some extra space between the front edges of the tables, or you could put 7 of these tables into a circular arrangement (a better fit) and have a little bit of extra space between the back edges of the tables.\n\nIt would also look more interesting to have heptagonal arrangements of tables in the room.
430786
The formula for the capacity or volume, V, of a cylinder is:\n\nV = Π(d^2)h/4\nwhere:\nΠ = 3.1416 (value up to 4 decimal places)\nd = diameter of the cylinder\nh = height of the cylinder\n\nSo, merely substitute the values that you have and you will get the capacity or volume of the cylinder. Just make sure to use similar unit of measures both for the diameter and the height.
137325
This is a lot to ask here. Why dont you look it up? \n\nAnd a lot of these are easy to figure out. \n\nSphere surface area is A=4 *pi *R^2 where R is the radius\n\nbecause A={int 0 to 2 pi} {int 0 t0 pi} R^2 sin(a)dadb\n\n\nThe cube surface area is A=6*S^2, where S is the length of an edge because there are 6 sides, each of area A^2.\n\nThe cylinder surface area A=2*pi*(R^2)+2*pi*R*H, where R is radius and H is height, because it has two circular end caps of area pi*(R^2) and a side of dimensions 2*pi*R by H, when it is unrolled. \n\nCone surface areas can be found the same way. Just unroll the side, and you get a triangle with height sqrt(H^2+R^2) and base 2*pi*R. The area of a triangle is .5*base*height. Then add in the area of the round bottom. \n\nAnd so on. I am sure you can do this yourself.