Serious question about the dewey dot decimal?
109674
Dewey decimal system is a system of classifying books, used in most\nof the libraries.\nThis was developed by the american librarian Melvil Dewey(b.1851, d. \n 1931).\nThis has 10 major classes viz.\n \n\n000 Generalities  \n100 Philosophy and Psychology \n200 Religion \n300 Social Science \n400 Language \n500 Natural Science and Mathematics \n600 Technology (Applied Sciences) \n700 Arts \n800 Literature \n900 Geography and History \n\nThese classes have ten divisions each which are are further divided.\nThe divisions become more and more specific.\n\nThis is a copyrighted system which is frequenty updated.\nThe homepage is:\nhttp://www.oclc.org/dewey/\n\nYou can visit any of the following sites to get a general idea:\nhttp://www.mtsu.edu/~vvesper/dewey.html\nhttp://en.wikipedia.org/wiki/Dewey_Decimal_Classification\n\n(BTW This has nothing to do with Mathematics. The right people\nto address this question are the librarians.)
903533
ignore the decimals when u originally do the problem, then however many deciams there are in both of the decimals you're multiplying is how many there will b in the answer. i.e. if you multiply 6.78x4.234 together the answer will have 5 numbers behidnthe dceimal point
798085
Your instructor is an idiot.\nThere is no commonly accepted notation in math which puts a dot over a natural number.\nI'm really sorry that you have a numbskull for a Calculus teacher.
1042171
Answer from Wikipedia - Dot and Dash\n\nThis answer satisfies the NBC treasure hunter's challenge.\nhttp://www.nbc.com/Treasure_Hunters/playwin/register.shtml
766854
28! I just did it on paper putting 8 dots and connecting each one with the rest. There is a math formula for it but I don't remember it!
761270
it is quite an inexact calculation, here are a few attempts\n\nhttp://hypertextbook.com/facts/2006/KristineMcPherson.shtml
550093
OK, CREATIVE, here's how it works:\n\nFirst let's think of what we mean by writing a number as follows:  "4321". \n\nWe mean the number is [(4X1000) + (3x100) + (2X10) + 1X1)]. \n\nIn other words, the number is the sum of four thousands, three hundreds, two tens, and one ones.\n\nWe'll call your word sequence of directions the "sequence", for short. What I intend to do is derive the number 1755 or 1756, as appropriate, because that is the key to how the sequence works. The multiplication that the sequence calls out just serves to positions numbers in the columns so that the last three digits of the answer become, in order, the chocolate number, the first age digit, and the second age digit.\n\nAlso To help simplify things, let's name the numbers 1755 & 1756, the "adjuster", because they "adjust" the sequence so that when we subtact our birth year, we arrive at the desired three-digit answer!\n\nNow let's write the sequence of steps you outlined as an equation, where n = the number of times we eat chocolate, and 19xy represents the year of birth (YOB).\n\n(By the way, the sequence doesn't work if you were born before 1901 or after 1999, but we when finish here, you'll have the tools to fix it to work for either the 19th or 21st centuries! YEAH!) :-)\n\nSo here's the sequence written as an equation:\n\n\n{[100(n) + 250] + 1756} - 19xy = nTO\n\nWhere we've assigned "T" as in "T"ens column, as the first digit in the age, and "O" as in "O"nes column, as the second digit. So the answer to the equation is properly "nTO".\n  \ndouble check the equation by going back and reading what the sequence spells-out.\n\nNotice that whatever (n) is, the first term of the equation, 100(n), will always create, in the hundreds (third) column, the number we chose for (n)!!!\n\nAHAW! - we've already cracked part of the trick!  We know we have to choose our "adjuster" such that it cancels-out any other numbers appearing in the hundreds column! The "n" gets preserved because its the first digit of the answer!\n\nSimple - eh?\n\nFor now, lets assign the adjuster the value ABCD, where the alphabet letters represent the numbers we need to derive. \n\nUsing our terminology and chain, we can re-write the equation as a column of numbers to be added and subtracted as follows:\n   \n             0n00\n             0250\n             ABCD \n             19xy(-)\n            ______\n             0nTO               \n \nNote: The lead zero's in rows one, two, and the answer row are put there to try and line-up the columns correctly when they appear on the yahoo! answer site, which otherwise moves them out of position because it "left justifies" all columns. By the same token, normally the minus sign for the "19xy", which is to be subtracted, would appear in front, instead of behind, but in so doing  the program mis-aligns the columns. Also note that the alphabet letters do not line-up accurately with the numbers. Readers will have to mentally correct for these mis-alignments.  Sorry!\n\n\nHang on!  We're almost there!  The hard part's done, it's all down  hill from here!  :-)\n\nNow let's plug in to the columns the numbers for an easy case, say a ten-year old born in 1996, then work backwords and see what numbers result for the "ABCD".\n\nplugging in age 10, YOB of 1996, then the desired answer is n10. Go back and put in the answer line.\n\n Then see how the columns look. we have:\n    For the ones column,        D-6=0,      so D=6\n    For the tens column,       5+C-9=1,     so C=5          \n    For the hundreds column,  n+2+B-9=n     so B=7\n    For the thousands column,    A-1=0      so A=1\n\nSo  ABCD = 1756  QED  (Quid Erat Demenstradum - what we wanted to demonstrate, as the Romans used to say!)\n\nNow you can have some fun and derive the "1755" adju
85305
This is 8 bit binary system.\nand u know, there are only two possibilities for a switch (on/off or 0/1).\nin binary syatem, as i have to take 10101000, to convert into decimal.\nfrom right to left:\n0*2^0 + 0*2^1 + 0*2^2 + 1*2^3 + 0*2^4 + 1*2^5 + 0*2^6 + 1*2^7 = 168 (it is the decimal form).\n\nsimilarly as we take 10110001\n\nthen its decimal is :\nfrom right to left : and increase pawer of 2 from 0 step 1.\n1*2^0 + 0*2^1 + 0*2^2 + 0*2^3 + 1*2^4 + 1*2^5 + 0*2^6 + 1*2^7 =  177
854439
For those who don't know Math24 (like me)\n\nA standard Math 24 card consists of four digits arranged radially around the center of the card. \n\n(See the 2nd link to see what the cards look like.)\n \nThe number (and color) of dots in the corner of a card indicates the difficulty (and point value) of that particular card. Cards are double-sided, with a different set of numbers on each side.\n\nA card is solved by using all four digits on the card exactly once to form a total of 24, using addition, subtraction, multiplication, and/or division. Digits may be used in any order, and any result from a previous mathematical operation can be used in a future operation for that card. For example, a card with the digits 2, 3, 6, and 9 could be solved by stating that 6-3=3, 3+9=12, and 12x2=24. There is often more than one answer to a card. A second solution could be that 9x3=27, 6/2=3, and 27-3=24.\n\nEach digit on the card must be used exactly once in an answer. The solution to the above card could not be 3+9=12, 12x2=24, as the digit 6 is completely unused. Also, the solution could not be 2x6=12, 12-3=9, 9+9=18, 18+6=24, as the number six is used twice.\n\nCards are divided into three levels of difficulty. One-dot cards (with a single white dot in each corner) are often solved by simple addition, or contain three digits that can make 24, plus a 1 (in which case any other digit could be multiplied or divided by 1 to create the same digit). Two-dot cards (with two red dots) are slightly more difficult, and often require more multiplication and division than one-dot cards. Three-dot cards (with three yellow dots) are the most difficult cards, often having only one solution. In most decks of Math 24 cards, the ratio of one-dot cards to two-dot cards to three-dot cards is 1:2:1.\n\nIn all versions, the loop of the digit 9 is filled in with red, so that it is distinguished from the digit 6.\n\n==\n\n2 2 2 2: [(2 x 2) + 2 - 2] ! = 24\n3 3 3 3: [(3 x 3) x 3] - 3 = 24\n4 4 4 4: (4 x 4) + 4 + 4 = 24\n5 5 5 5: (5 x 5) - (5/5) = 24\n6 6 6 6: (6 x 6) - (6 + 6) = 24\n8 8 8 8: [8/ {(8 + 8)/8}] ! = 24\n9 9 9 9: (9 + 9) + sqrt 9 + sqrt 9 = 24\n\n(I do not know if the square root sign or the factorial sign are allowed, Teachers may say "too difficult for this age-group")\n\nSomebody asked about 3 3 8 8 recently and I came up with the following answers:\n\n3 3 8 8: [8 / (8 - 3 - 3)] ! = 24\n3 3 8 8: [8 / (3 - 8/3)]  = 24\n\nand if other base maths than base 10 are allowed: how about:\n\nbase 9: 3 + 3 + 8 + 8 = 2 (9s) + 4 units = 24\nbase 11: 3^3 - 8/8 = 2 (11s) + 4 units = 24\nbase 12: 3^3 + 8/8 = 2 (12s) + 4 units = 24\n\nBut some easy examples with 2 solutions would be:\n\n1 1 4 7: (4 - 1) x (7 + 1) = 24  OR (7 - 1) x (4 x 1 = 24\n1 3 4 5: (4 - 1) x (5 + 3) = 24  OR (3 + 1) + (4 x 5) = 24\n1 3 4 7: (7 x 3) + (4 - 1) = 24 OR (7 x 4) - (3 + 1) = 24\n2 3 5 7: (5 x 3) + (7 + 2) = 24 OR (3 x 7) + (5 - 2) = 24 \n2 6 8 9: (2 x 8) x (9 / 6) = 24 OR (2 x 9) x (8 / 6) = 24 or if factorials are allowed: 6 + 2 x (9! / 8!) = 24
175757
I can get you started. \n\nThe digit A can't be very large if ABCD * 4 is a 4 digit number. In fact 4  3 = 12 so if A = 3 then ABCD x 4 is at least five digits. \n\nA is either 1 or 2. If A is 1 then 1BCD x 4 = DCB1 But this is not possible since the left side is even and the right side is odd. Thus A = 2. \n\nso, we have the first number!\n\n2BCD x 4 = DCB2 \n\nLook at D on the right side. What can it be? 4 x 2 = 8 so D might be 8 or, if there is a carry, D might be 9. But if D on the left side is 9 we get 4 x 9 = 36 which doesn't work with the units digit of 2 on the right side. So, D = 8 and we get:\n\n2BC8 x 4 = 8CB2 \n\nThis should be enough to get you started
929737
the first three questions are answered as follows\n~ = means repeating decimal\n#1     $75 - (75 x .333~) = $50\n#2     $150 - (150 x .5) = $75\n#3     $750 x .1 = $75\n\nthe easiest way to the the additional problems you have add is as follows\n\n#1    80 x .2 = 16\n#2    50 x .5 = 25\n#3    40 x .1 = 4\n#4    68 x .25 = 17
323178
What would you like to know?\n\nTry here for whatever it is...\nhttp://www.math.com/homeworkhelp/HotSubjects_decimals.html
80562
Relatively easy way\n\n0.008895478\n0.012222453\n\nmultiply both by 100 (ie, move decimal point two spaces to the right):\n\n0.8895478\n1.2222453\n\nObviously first one is less.
854222
Those are the right numbers. As you suspected they have too many decimal places, however. To have them correct to 6 decimal places, look at the 7th decimal place. If this is 5 or more, round the 6th decimal up one, otherwise leave it the same and just drop all the numbers after it.\n\nSo for a) the answer would be 1.499975 and for b) it would be 1.499997.
139403
in decimal its 2\nin binary its  0\nin other like octal hexa etc its 2\nin logical or its 1\nnow wat do u want????
1151942
Metric system?????\n\nWe BARELY know the system we're using now!!! Anyone who knows their Multiplication Table is considered a Mathematical GENIUS!!!
499912
So far you have been given the easy conversion(a\nnon repeating decimal). Now let's go to the next\nlevel. Suppose your decimal repeats. For example,\n.3... , the ellipsis(...) means the 3 goes on forever.\nPut the 3 in the numerator and a number in the\ndenominator with as many 9's as there are digits in the\nrepeating part of the decimal. In this case. just one 9.\nSo the answer is 3/9 which equals 1/3 as you would\nexpect. How about .45...  , which means the "45" repeats.\nThe answer is 45/99 which is reduced to 5/11.