Everyone in a room writes down a 2-digit number,only 3 people write the same number.how many people at most?
112973
103 people:\n\n00 to 99 is 100 unique two digit plus 3 duplicate\n(zero is a valid digit)
263402
i dont know but that is only 6 numbers!
717704
9999999999999999999999999999999999999999999-9999999999999999999999999999999-9999999999999999999999999999999999-999999999999999999999999999999-999999999999999999999999 people and counting.
771437
There are three types of people in the world.  \nThose who can count and those who can't\n\n\n:-)
603689
add the numbers\n15\n19\n42\n19\nnext number equals 15..... and each has a 2 and a 7 in it\n\ntry 2742 sounds like a good answer for neopets lenny conundrum answer possibility but not fully sure..... lucidlyinsane
571851
Let's simplify the problem.  What if the question was how many people must attend a party to guarantee that a group of 2 people that all know or don't know each other attends.\n\nThis answer is obviously 2.  They either know or don't know each other so you are done.\n\nNow let's try the case with figuring out how many people must attend such that you have 3 people that either know or don't know each other.  You can start with your two people.  Let's say they know each other.  Then...\n\nYou know, I'm going to have to think on this a little longer.  It's not as straightforward as saying it is 5 or 17, but requires some recursive logic...  I'm sure there is a series that explains the relationship.  Let me go look and get back to you.\n\nOkay, I found an article on Wikipedia covering this graph problem.  Let's go back to the case of 3 relationships.  In this case, you can have 5 people you can color the relationship graph with two colors (red = know, blue = don't know).  You can color this without creating a triangle of one color.  However if you try to add one more node to the graph (guest), there is no way to prevent a triangle.  So for 3 relationships (all known or unknown) the answer is 6 guests.\n\nFor 4 people, the answer is 18 guests are required to guarantee this.\n\nHowever for 5 people, the answer is between 43 and 49, but no one has proven the lower bound.  If you had 49, you would definitely guarantee this condition.  But it might be that you could also do it with 48, 47, 46, etc.\n\nSo the answer is somewhere between 43 and 49 people.
68596
1) keep "people" the same; balance "minutes" \noperation: solve this proportion\n\nprevious sheets : NEW SHEETS = previous minutes : new minutes\n\nNEW SHEETS = previous sheets * new minutes / previous minutes\n\nNEW SHEETS = 2 * 10 / 5 = 2*2 = 4\n\nat this point you know that 2 people can work 4 sheets in 10 minutes.\n\nNow keep minutes the same. Balance sheets with a proportion:\n\nNEW PEOPLE : old people = new sheets : old sheets\n\nNEW PEOPLE = old people * new sheets / old sheets\n\nNEW PEOPLE = 2 * 20 / 4 = 2 * 5 = 10\n\n10 is the answer
779216
Each digit is even\nEach digit is different\nThe number has 4 digits\nIt is divisible by 4.\nIt is not divisible by 8.\nIt is a square.\n\nYour answer must be: 6084\nIt is the square of 78.\nAll digits are even and different.\nIt is divisible by 4.\nIt is not divisible by 8
493444
this really only works when its done verbally...when people are looking at the numbers, its much easier to realize that the answer is 4100 instead of 5000, pretty neat one isnt it
752005
42.\n\n    doesn't everybody know that??
741355
There are a few ways to find this, but the answer depends on whether we can repeat numbers in the combination and if the order matters.  \n\nIf we cannot repeat numbers and order matters:\n# combinations = 9*8*7*6*5*4 = 60480\nThere are 9 choices for the first digit, 8 for the second (because one is already taken), and so on.  We multiply the choices for each digit to find the total number of choices.\n\nIf we can repeat numbers and order matters:\n# combinations = 9^6 = 531441\nThere are 9 choices for each of the six digits.\n\nIf we cannot repeat numbers and order does not matter:\n# combinations = 9!/(6!*3!) = 84
927448
A way to write numbers (usualy big numbers)\nImagine number 480,000,000\nIt is 4,8 * 100,000,000\nYou can write it as 4,8*10^8 or simply 4,8E8\n3 452 000 000= 3,452E9\n\nIt is very easy to multiply these numbers
471834
aren't u missing a number there on the last row???\n\nin that case... i would say...\n\n9 11 13 15 17 19....
695512
Answers choices are:\n     1, 4, 3, 2, 2,\n      3, 1, 4, 2, 1,\n      1, 1, 4, 2, 1\n      3, 2, 3, 4, 1\n      3, 4, 1, 2, 4
748483
The answer is 119\n\nTake 2 at a time end up with 1 (59 times=118 one left)\nTake 3 at a time end up with 2 (39 times=117 two left)\nTake 4 at a time end up with 3 (29times =116 three left)\nTake 5 at a time end up with 4 (23times=115 four left) \nTake 6 at a time end up with 5 (19times=114 five left)\nTake 7 at a time end up with 0 (17times=119 o left)\n\nI am dead sure this time = ]\n\nThe trick is look at 5 at a time. there is 4 left this means the last digit must be 9. So look at all possible answer of 7s that ends with 9 and work it out from that!!!!!!!!!!
651368
Answer: 4\n\nPut 30 kids in each room. So, after 10 rooms are filled, you have out (30*10) kids in the 10 rooms. So, you are left with 6. If you put 1 kid in 6 rooms, to make the number of kids in these 6 rooms to 31, you are left with 4 rooms with 30 kids.
657261
isn't it to add pairs of mumbers like (1+100) (2+99) (3+98).......(50+51)\n\nall the answers are 101, and there are 50 answers\n\nso 101 x 50 = 5050