Is a bulb with a resistance of 95 ohms labeled "150 W"used in a 120-V or a 220-V circuit?
100752
There are two relavent formulas,\nOhms Law: V = R*I\nwhere V is the voltage, R is the resistance, and I is the current.  Also,\nPower = V*I\n\nIf we know that power is 150 watts, then,\n150 = V * I,\nbut what is the current (I)?\n\nWe know the resistance is 95 ohms,\nV = 95*I --> I = V / 95\nSo plugging back into the power equation,\nP = V^2 / R \n150 = V^2 / 95 --> V = sqrt(150 * 95)\nso V = 119.4 volts --> 120 volts
518406
equivalent to 4   100 Watt  Bulbs
114097
casey's last sentence is wrong:\nthe more resistance the slower the flow rate \npressure is determined by voltage\n\njdub says:\n"for example...the higher the voltage, the greater the resistance, and the higher the current, the lower the resistance...etc.."\nshould say_ that a a higher voltage will need a greater resistance to oppose flow in order to keep the current the same, or if you want to raise current you would either raise voltage across given resistance, or lower the resistance at a given voltage.\n\nbrmick says:\nthat air is a better conductor than concrete,\nThis largely depends on the frequency of the source, gases are not generally considered conductive, while concrete which is largely water is a moderate conductor especially if wet or wetted.\nDO this take two light bulbs and wire one of each lamps leads to the other then tie it to its intended source (series) using the remaining leads. check the voltage across the source and between the lamps. Assuming you have two equal size lamps you have {nearly-ignoring impedance} doubled the resistance. and so the current and wattage are cut.
1079575
By Ohm's Law, current = voltage / resistance\n\nTherefore the current is 120 / 2 = 60 amps (answer b)
738167
Unless you are playing with low voltage, please find some other project. 120 Volt or 220 volt is very dangerous.\n\nAny way you will need all the components in same voltage I say get every thing in under 9 volts to make things easy, they must operate in 6 to 8 volt range so you will have voltage to spare. You may not be able to find them readily.\n\nThis is how it works.\n\nClapping sound is picked up by micro phone.\n\nThis produces a signal, that will close an open circuit on a lamp(or any thing that you need to turn on like a bell).\n\nTo make a package, like the one you buy in the store, it took quite a few years to perfect it, and they had experts working on it.. \n\n1.  9 volt battery. few to operate the systems.\n2.  red and black wire.\n3.  9 volt lamp.\n4.   6 volt Micro phone.\n5.   Sound activated switch, 6 volt \n6.   Tapes electrical.\n7.    cardboard to mount every thing.\n8.    cutting tool to make connections.\n9.    Solder iron and silver solder wire.\n10.   Different types of connectors.\n11.   Glue to put components on the board. \n\nEdmund-scientific.com may have a kit, it is on Internet.\n\nBuy the kit and assemble it.
921578
120W would be brighter, and here is why:\n120W light bulb would have higher temperature (rough argument: dQ/dt= c*m-sigma*T^4, at equalibrium c*m = sigma*T^4 =P =V*I, where c= heat capacity per mass), and by Planck's law of black-body radiation will emitt more visible light than Infra Red light, so it's more efficient in producing visble light for the same energy than 2x 60W light bulbs. Great question.
927371
Voltage is analogous to the PRESSURE forcing water through a pipe, and electric current is analogous to the liquid FLOWRATE.  220 volts is twice the "electrical pressure" of 110 volts, so it would force twice as much electrical current (amperes) through an appliance as 110 volts would.\n\nAs other answerers have noted, the appliance plugs are usually designed so that you cannot do this by accident.
910320
There is something funny about your question as resistance and reactance is measured in Ohms.  However I believe that the answer that you are looking for is because the resistance part is dissipating 15 kW and the reactance part is drawing 10 kW so since the two are 90 degrees in phase apart the total power drawn would be sqrt( 15^2 + 10^2)  = 18 kW
533465
V=IR so R=V/I so R=120/2.5 = 48 ohms
749151
If the voltmeter is connected across the bulb, it measures the voltage drop (potential difference) across the bulb.. ie.. the voltage the bulb gets from the battery..\n\nIf theres only the light bulb in your circuit, then the entire voltage of the battery drops across the bulb... so the voltmeter will read 12V\n\nIf there is some other bulb or other appliance connected in series with this bulb, then voltage of the battery gets divided according to their resistances..\n\nIf there is a bulb in parallal with the bulb.. then both bulbs get 12V each because in parallel, the voltage remains the same\n\nGot It?
228080
Assuming a DC circuit: use Ohm's law, I=E/R and P=I*E or I=150 Volts /11 Ohms = 13.64 Amps and Watts = 13.64 Amps * 150 Volts * 24 hours or 49,090.9 Watthours or 49.091 kWh.
1073127
A lightbulb is a very cheap effective producer of heat!  Use something like a 15 to 25 watt bulb and make sure it holds the temperature steady at the correct level so you don't fry your eggs or they don't get cold.\n\nBTW a 100W lightbulb gives off 2% of the energy in light and guess what the other 98 watts are?  HEAT!
368541
Probably yes.\n\nFor general purposes, any voltage from 110V-130V can be considered the same thing.  Same for any voltage from 208V-240V.  The variations are due to many factors including distance from the outlet to the nearest transformer, capacity of the circuit, other attached devices, etc.\n\nMost devices today are capable of handling the seemingly wide variance in voltages. (e.g. a device rated for 220V can handle any voltage from 208V-240V.)
616652
Most generators are rated in watts. If you have a 50 amp circuit, then 110 volts x 50 amps = 5500 watts. You do not want to run the generator past 80% of its duty cycle, so a 6000 watt gen should be the best.\nHope the formula helps\nYou can also figure out how many watts a microwave will need. I it takes 10 amps at start up then 10 x 110 = 1100 watts.\nThus a 60 watt light bulb would take 60/110= .54 amps
579320
Turn it off.\nA watt measures power, not energy. Power is the rate of using energy.\nEnergy is measured in joules.\nOne watt is one joule per second. \nA 100 watt light bulb uses 100 joules per second, or 6,000 joules per minute or 360,000 joules per hour.\n\nNow how much energy do you think it takes to turn on that bulb? An hour's usage? And how fast does it use it? All in the first second? If it really did used 3600,000 joules in the first 1 second, that would be 360,000 watts. That would definitely blow your circuit breaker. Does the bulb use one minute of power in the first second after you turn it on? If so, that would be 6,000 watts, which still blows your breaker. Most household circuit breakers trip at 15 to 30 amps, which is 1,800 or 3,600 watts on a 120 volt circuit.\n\nSo turn off the light.
713107
range/amount\n\nrange = 120 mV (90mv - (-30mV))\namount = 2^16 = 64*1024\n\nplug-n-chug
932209
Basic-   15 amp circuuit should not hold more than 1440.00watts, or 12 amps ( 1440watts / 120v= 12 amp).  you should load the circuit for lighting or continual use more than 75%.  the same for 20 amp circuits. (1800 watts/120v=15amps).   Check the back of the space heater. It should the watts listed.