this question relates to physics
124783
no more gravity thus it and you will float out into space.
157307
The only link you need:\n\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html\n\nHint:  look under "Mechanics"
71932
Interesting question and one asked in various forms for several centuries.  The answer, of course, is "yes" because the logic in the way the question is framed is specious.  The act of traveling does not divide into discrete units but is an on-going process tht will eventually terminate at the wall
395434
The problem is about conservation of angular momentum.  The tricky part is (b). To solve this use this definition of angular momentum and draw a picture to find out the value of r sin θ\n\nThe angular momentum of a particle of mass m with respect to a chosen origin is given by vector product L = r x p= mvr sin θ
68736
check www.howstuffworks.com
19029
Sorry, but with the time you spent typing these questions you could of looked them up in your physics book or googled them.  Sometimes getting others to do your leg work isn't always the best answer to a problem.  Good Luck in your new class!
442090
The answer is C. Although B seems to be a possible answer at first, there could still be an n-number of forces acting on the object such that the sum of all the force vectors is zero, thus making C the more complete answer. One of Newton's laws says that F=m*a (force on an object equals its mass times its acceleration), or a force of 1 Newton on a 1kg object will make it accelerate at a rate of 1m/s^2 in the same direction of the force.
2621
here's a site with pics that might give you some ideas:\n\n\nhttp://www.physics.usyd.edu.au/competition/comp1998/comp98.html
21796
Check http://www.howstuffworks.com\nUltimate guide!
118895
Please, watch these examples below to solve your problem it take a lot of explanation so take you to some good websites for the purpose.\n\nhttp://360.yahoo.com/jcbroogley
154830
When V(t)=0 the particle stops.\nIt can have a(t)=0, but still moving (constant speed)
491970
Someone posted the exact same set of questions a few days back, either here or on the physics page - you ought to be able to find the methods in the responses. Have a look.\n\n\nBest of Luck - Mike
540072
u can consult ur physics book
448831
Answer d is true.\n\nCheck out the website below for information on circular motion.
513562
Try looking at the equation for the Laws of Strings... If they are directly proportional, meaning, they are on the opposite sides of the equation, then an decrease of 1% is also an decrease of 1% to the other. \n\nTry looking it up in Resonance too... But I am more confident of my first answer... Studey the equation!
387747
I've found this question with no answers after three days.  I cannot answer it; only someone with a very specialised  background could.\n\nYou will have to place it again - at peak time for prospective Answerers with the requisite background.
4545
The rotational energy you impart to the object when spinning overcomes the force of gravity that would topple a stationary object.  \n\nA total layman's explanation:\n\nA perfect stationary top perfectly balanced will not fall over.  In real life though,it's impossible to perfectly balance a top.  It's shape practically guarantees that its center of gravity will not be directly over the balance point for any practical length of time.  Imperfections in the material will cause a slightly uneven weight distribution, air currents will introduce a small force, and mechanical vibrations will be transmitted through the medium the top rests on.  The upshot of all this is that as soon as the center of mass is no longer over the resting point, gravity is going to pull the top over.  \n\nNow gravity has an acceleration of 32 feet per second squared (if I remember my ancient high school course correctly).  It can only topple the top at a specific speed.  If you spin the top fast enough, any side that gravity tries to "pull down" will translate around so quickly that it literally has no time to fall.  If you were standing on a planet with a much higher gravity, you'd have to spin the top far faster to achieve stability, and if you were on the moon, it would spin for a much longer time. Eventually, however, the top starts to slow and the tip will inscribe little circles.  That action is called "precession".  And of course, eventually the thing drops to the table and the game is all up once it slows enough.\n\nAgain, that's a layman's view of how it works.  Some college physics major is probably going to come in here and make my answer look really foolish.