answers: \n\na.) 3(3x + 3y)\nb.) 3(6x+y)\nc.) 3(3x+y)\nd.) 12xy
136188
the answer is letter "C". coz 3(3x+y)=9x+3y.use the distributive property.now do your homework lazy kid!!! j/k!!! lmao!!! =D haha! kidding! hope i helped you somehow!
503745
10-3x=2x-8x+40\n10-3x=-6x+40\n10+3x=40\n3x=30\nx=10\n:)
70870
y^2 + 3y + 6 -4y^2 - 6y simplifies to:\n\n-3y^2 - 3y + 6\n\nIt's a second-degree trinomial expression.
584311
(3x-2)(12x^2-2) + (4x^3-x^2+1)(3)\n\nThat is the un-simplified answer
500016
Should not u work that urself?\n\n\nAnyway,\n\nIf 3x+y=3,\n\nmultiply both the sides by 2.\nAs both sdies are being multiplied, the equality is maintained\n\n2* (3x+y) = 2*(3)\n\n=> 2*(3x) + 2*(y) = 6\n\n=> 6x + 2y = 6                                               ----(eqn 1)\n\nNow as it can be seen that the left hand side is 6x+2y+10, therefore we will add 10 to our (eqn 1). To maintain the equality, this addition will have to be done to both the sides.\n\nTherefore,\n6x + 2y +10 = 6 + 10\n\n=> 6x + 2y + 10 = 16\n\ndone!!\n\nThere is another way to look at the problem, and this seems a bit mopre logical, if ur comfortable with equations i.e.\n\nNow look carefully at what is asked.\n\n6x + 2y +10 = ?\n\nfactorize it by taking out 2 common\n\n2*(3x + y) +10 = ?\n\nwe already know the value of (3x+y), which is 3\nso, we substitute it in 2*(3x + y) +10 = ? to get,\n\n2*( 3 ) +10 = ?\ncalculating, 2*3+10=6+10=16
339768
a) (x+4y)(x+y)=0    x=-y or -4y\n\nb) (2x+y)(x-3y)=0   x=-y/2 or 37\n\nc) (2x-y)(2x-y)=0  x=y/2\n\nd) 4x^2+7xy-2y^2=0\n    (4x-y)(x+2y)=0    x=y/4 or -2y\n\ne) x(5x+y)=0   x=0 or -y/5\n\nf) x(3x-7y)=0   x=0 or 7y/3
575283
(x - 2)*3 = 6 + x\n\n3x - 6 = 6 + x\n\n2x = 12\n\nx = 6
470893
1.  (x + 9)(x - 9)\n2.  (t + 2)(t - 2)\n3.  (b + 12)(b - 12)
450438
1. 28x + 30\n\n2. 24y + 30\n\n3. -63 - 36x
224961
x=\n3x-3+2x=5x-6-x\n3x+2x-5x+x=-6+3\n1x=-3\nx=-3&#92;1\nx=-3
90864
3x*(x^2-8xy+16y^2) Same factor\n3x*(x-4y)^2 Perfect squares.
400703
1) (a - b)(x - y)\n2) (x^9 + y^3)(x^9 - y^3)\n3) (6x + 5)(x + 8)\n4) (x - 9)(x - 7)
460869
1) 4-3x<_8+x\n4+8<_x+3x\n12<_4x\n3<_x or x in the interval [3,plus infinity)\n\n2) 3x-3>-x+1\n3x+x>1+3\n4x>4\nx>1 or x in the interval (1, plus infinity)\n\n3) 3(x-1)_<4x\n3x-3<_4x\n-3<_x or x in the interval [-3, plus infinity)\n\n4)1/2x<x+1\n-1<x/2\n-2<x or x in the interval (-2, plus infinity)\n\n5)-1/2x>1-x\nx/2>1\nx>2 or x in the interval (2, plus infinity)
193701
Here's a start to help you out.  You should try to finish the rest with a little substitution work,\n\n\nThe sum of three times a first number and twice a second number is 43.\n3x+2y=43\n\nIf the second number is subtracted from twice the first number the result is -4. \n2x-y=-4
494194
ok sorry, i'll work it out this time\n\n3x-6y=-30\n-8x+20y=104\n\n(8)(3x-6y)=-30(8)\n(3)(-8x+20y=104(3)\n\n24x-48y=-240\n-24x+60y=312\n\n12y=72\n\ny=6\n\n3x-6(6)=-30\n\n3x-36=-30\n\n3x=6\n\nx=2\n\ndoes that help?
669375
2(x-4y+1)+3(-2+y-2)\n2x-8y+2-6+3y-6\n2x-8y+3y-6-6\n2x-5y-12\n\n2x-5y-12= answer\n\nHope this helps you.
227237
I hope this isn't homework!\nx+y=94 \n2x-y=26 \n3x=120\nx=40\ny=54