i need to find what the variable q is
132250
Given 0.5q + 3 = 10.5 + q\nRearranging the terms,\n-q + 0.5q = 10.5 -3\nThat is \n-0.5q = 7.5\nOr q = - 7.5/0.5 = -15
553112
Q = 25000 - 5000p\nSubtract 25000 from each side\nQ - 25000 = -5000p\nDivide everything by -5000\n(Q-25000)/-5000 = p\nAnswer: p = (25000-p)/5000\nor you could write it as p = 5 - (p/5000)
557821
isolate the variable\n\n-7x+1+8x=x+1\n-7x+8x=x\nx=x\nx=1\n\nthe answer is c) 1\nnow give me 10 points please!!!
41102
you have to solve p such that S=D=Q.\n\nfrom S, p=Q/10 -70\n\nput that instead of p into D equation, solve for Q\n\nthen use that Q to compute p=Q/10 -70
119747
Copy this and paste it into your code:\n\nOriginal = "Hello"\nLower = LCase(Original)\nUpper = UCase(Original)\nReverse = ""\nFor i = 1 To Len(Original)\n   If Mid(Original, i, 1) < Mid(Lower, i, 1) Then\n      Reverse = Reverse + Mid(Lower, i, 1)\n   Else\n      Reverse = Reverse + Mid(Upper, i, 1)\n   End If\nNext
162729
f=m*a=E*q\na=Eq/m\n\nv^2=v0^2+2ax\n\nv=sqrt(v0^2+2ax)=sqrt(v0^2+2Eqx/m)\n\nv0=2.74e4\nE=2.58e3\nq=1.6e-19\nx=.00185\nm=1.67e-27
314403
I think you're missing a variable...in order to find x, you have to know what the end result is.
433710
Q( thermal equilibrium/heat  )= Mass *specific heat capacity * (Temperature final - temperature initial) This is the formula.
183119
x = -b +(or)- sqrt(b^2 - 4ac)\n    -------------------------\n               2a
598281
lets say length= L\nwidth=W\nperimeter=P=22=2L+2W\nL=W+7\n\n22=2(W+7)+2W\n22=4W+14\n8=4W\n2=W\n9=L
447879
Start with the whole array as set Q.\nUse algorithm X to get the median M of Q.\nSet a = [size of Q]/2.\nIf a = k, stop; M is your answer.\nIf a > k, set Q = the values less than M, otherwise set Q = the values greater than M.\nRepeat.\n\nThis algorithm is a bit off because when [a > k], the comparison [a <=> k] is subsequently invalid.  But you get the gist of it.  Use X in a binary search mode.
226564
if u meant {4/(q^2+2q+1)}- {q/7(q+1)}\nthe answer is\n\n(28-q^2-q)/{7*(1+q)^2}
602672
Q (heat energy) = m(mass in gram)*c(specific heat in J/gm/K)*t (change in temp)\nQ = 25 * 1 * (36-24)\nQ = 300 J
670979
1) q^3/(5p^8)\n\n2) 1/(-2y)^4 = 1/[(-2)^4(y)^4]\n= 1/(16y^4)
490767
a Q1 since it is between 0 and 67\nb Q2 since it is between 67 and 88\nc Q3 since it is between 88 and 105
613871
q=2/25\nx=28/3 and x=7/6\nx=(-4)\nx=(-7.5)\ny=13*3=39
628820
x^3 + px^2 + qx + r = 0\n\np = -3\nq = -2\nr = -1\n\n3 solutions, one real, and a complex conjugate pair\n\nx1 = 3.62736508471183\nx2 = -0.31368254235592 + i0.421052806987577\nx3 = -0.31368254235592 - i0.421052806987577\n\nSee calculation:\nhttp://www.geocities.com/derekcowley/public/cubic.xls\nYou will need the "Analysis ToolPak" and "Analysis ToolPak -VBA" add-ins in Excel to properly see this file. \n\nbased on cubic depression:\nhttp://www.karlscalculus.org/cubic.html