please give exact number. i would thank you so much if you could give me answer ASAP. \nin detail, on Epcot Globe, you know how there are so many sides that are covering the sphere? i want to know how many sides are in ALL.
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Spaceship Earth is a geodesic sphere, standing at 180 feet tall & 165 feet in diameter, & weighing an estimated 16 million pounds. There are 11,324 silvered facets on 954 triangular panels covering the globe. The exterior tiles are made of Alucobond material, a composite of ethylene plastic which has been chemically bonded between two aluminum panels. This material can withstand the Florida climate and is self - cleaning. Rainwater is channeled through the structure and sent to underground drains, where it replenishes the World Showcase Lagoon. It has an outside surface of 150,000 square feet.
362393
By Most Accounts, 193 is the Correct Answer\nA very frequent geographical question is "How many countries are in the world?." Different numbers pop up when one inquires or reads about the number of countries in the world. Each source you use often yields a different answer.
490248
1) Don't know\n2) what the hell is a "25-gon"?\n\n3)360/8(360 deg. in an octogon. divided by the # of sides. And voila. you get your answer)\n4) 360/24(same as above)
519962
I am only using visual techniques and not math theorems here:\n\nThe first plane will divide space into 2 parts.\n\nIf totally random the second plane will probably not be parallel with the first.  This will divide the 2 parts into 4.  If it did happen to be parallel with the first, then the space is divided into 3 parts.\n\nThe third plane will most likely not be parallel with either of the other two.  It would divide the space into 8ths.  If it was parallel to either of the other two then the minimum parts is 4 and the maximum is 6 parts.\n\nThe fourth plane will most likely not be parallel with any of the first 3, and can divide the space into maximum of 15 parts.  The fifth will make that 26.  Parallel planes will reduce this number.\n\nThe space will be divided into a minimum of 6 and a maximum of 26 parts with 5 planes.\n\nI just found a great description at the site below:
324495
number of sides, congurency?, size of angles, distinguishing characteristics
114528
I will put together a demo and update this answer when it is done, in about 12 hours.\n\nUPDATE, 3/21/06: I have finally posted the answer to my blog and my demo site:\n\nhttp://blog.360.yahoo.com/blog-NVb99sQ4RK5BVgIbxdcQdcRtfT8-?cq=1&p=25
84253
There is a delightful article by the late Dr. John Kenny on that, back a few years ago, looking at the formulae for surface area and volumes of spheres; I'll see if I can find it for you--it's in my files SOMEWHERE--and give you the reference, and the formulae he generated. It turns out that they're not precisely the same as what you've got--but not terribly far from it.\n\nAs I said, I'll see if I can find it, and I'll get you the reference and the formulae.\n\nAbout 9pm CST...\n\nOK, here is the formulae, done the best I can on this thing...\n\n\nFor a sphere of dimension 2*k, radius R\n\nVolume: (pi^k)*(R^(2*k))/k!\n\nFor a sphere of dimension 2*k + 1 and radius R\n\nVolume:\n(2^(2*k+1))*k!*(pi^k)* (R^(2*k+1))/(2*k+1)!\n\n\nTo get the surface areas for each of these, all you do is differentiate with respect to R...\n\nAs I said, it was a little more complex than you thought--the surface areas come out a little bit differently for odd and even numbered dimensions.  I do not recall why, frankly.
99914
im a geo student, but i havent done proofs for a long time sorry. ok\n2. false, because squares are parallelograms with 4 congruent sides and 4 right angles, while kites have 2 pairs of congruent sides and only 1 pair of congruent angles that are NOT right angles\n3. false, because a rhombus is a parallelogram with 4 congruent sides, while a kite is any thing BUT a parallelogram. enuff said\n4. false, because kites are quadrilaterals with only two pairs of congruent sides, while the quadrilateral mentioned has 3 congruent sides\n5. false, for example- do trapezoids have 4 congruent sides, and 4 right angles, and is a parallelogram (characteristic of squares)? i think NOT\n6. read above- trapezoids are not parallelograms.
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I was able to draw 16 different forms (8 with their symmetrical reversed forms).  There may be more but I don't have the time to work on it.\n\nI took another look at the problem and realized that in addition to the left-right symmetry there is also a top-bottom symmetry that adds at least another 14 answers to the 16 that I came up with earlier.  So there are at least 30.\n\nCould be more, but it is my bed time.
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The Cube has 43,252,003,274,489,856,000 different possible configurations.\n\nI cheated and looked up the answer, but to figure it out you'll want to use combinatorics.  I'll have to work on that part of it...\n\nIf you're taking the cube apart and counting how many different ways you can put it back together, this is a relatively simple problem (although it doesn't match the above answer).\n\nThe center cubes don't move at all, so there is only one possible configuration of them.\n\nThere are 12 edge cubes, which each have 2 outside edges and therefore two orientations for each location.  The number of possible combinations of these edges is (2*12)*(2*11)*...*(2*2)*(2*1) = (2^12)*12!\n\nThere are 8 corner cubes, which each have 3 outside edges and therefore three orientations for each location.  The number of possible combinations of these corners is (3*8)*(3*7)*...*(3*2)*(3*1) = (3^8)*8!\n\nMultiply the number of possible combinations of edge cubes by the number of possible combinations of corner cubes and you end up with 519,024,039,293,878,300,000 combinations.  \n\nThis is different than the answer I looked up because there are possible combinations when you take the cube apart that cause it to no longer be solvable.  I can't think of an easy way to find the number of combinations that keep solvability.
19596
do you mean : 31 planes of existence? i have a pdf file describing the sensuous world, form realms & formless realms, with the table of 31 realms. you can email me @ ashnertan@yahoo.com for it.
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UH-UHH!   It's  28.  \n\nThe first one  we count has 7 distinct ribbons. One each to every other diver. The second one has 6 since the one to the first has already been counted. The next one has 5 since the ribbons to the previous 2 have already been counted and so on. \n  So the answer is 7+6+5+4+3+2+1= 28.  Notice that we only\naccount for 7 sky divers. That's because the 8th one's ribbons have all been accounted for by the others.
69754
Your question is too complicated to appreciate the math in it, which is supposed to be the real beauty in the first place. Anyway, I have tried figuring it out and come with equations. I do not even want to try and begin substitution and end up with more complications. I just thought once you saw the relation, you would throw those 10 points my way.\n\nAssuming a to be sides of the squares of the prism and b to be the length of the rectangles, we know that the sum of all dimensions is 14a+5b. Now I do not even want to get started why you brought it the story of the equilateral triangle. You can just say the sum  of the dimensions is 61. Anyway, since any side of the trianle, as it is equiangular hence equilateral, is twice 14a+5b and 122, the sum of the dimensions will be 61. So your first equation is 14a+5b=61\n\nYou know the volume of the prism is the length X width X heiht = a x a x b = (a^2)b This is equal to the surface area. The surface area is the sum of all the areas on the prism and that is a^2+4ab. (How about you calculate how that came up?)\n\nSo there is your second equation, (a^2)b = a^2+4ab So then from 14a+5b=61, express a in terms of b or the other way around and plug it into the second equation and experience brutal complications and figure out what the variables are. I think you know it is too easy to calculate each dimension and area after that.
282620
one... but I can see how you're confused... it's kind of like those old transformer toys, where you could put three transformers together to make one big transformer... they all three are one God, but are also independent... it's odd
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12,000,198 microscopical creatures\n\nit's 7 x 7 x 7 x 7 x 17 x 7 x 6 x 7 = 12,000,198\n\nBy the way, why is this in Words and Wordplay not Math?\nAm I missing something?
77175
No way to know.  What is the shape of "everything"?  I think it is round and that if you go to one end, you'll end up back at the same point if you keep going the same direction.\n\nGood question.
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From what we understand right now, it seems to be infinite. However, a year or two ago, there were some scientists that claimed evidence that it is actually a large icosahedron that repeats. Their evidnece has not withstood more tests, though.