is there any site, online book or journal mentioning the molecular weight of dapoxetine, its cas number is 119356-77-3? or somebody can tell you about this? thanks alot!
137554
molecular weight's 305.4188 g/mol
494255
CH3CH2C(CH3)3.\nI guess you forgot to type the C before the parenthesis. If you didn't forget, then none of the answers is correct (you would be missing a carbon atom).\n\nChem-man I would have contacted you in private about this but you do not give us the option to e-mail you. I have seen several of your answers prompting askers to verify your answer through echemistryhelp. I checked the website and it is not a free one; you post a question and pay for the answer. I'd say that this is a form of indirect advertisement  which is against the community guidelines. Please refrain from doing that or I will have to report you.
465061
I was on zyprexa, I think 10 milligrams once, some higher dosage. Zyprexa and i had a love, mostly hate, relationship. Zyprexa made me gain 80 pounds by slowing down my metabolism. it also caused me to sleep through my freshman year of highschool and part of my sophmore year- greatly affecting my grades. On the flipside though, I was pretty psychotic and the drug may have been what it took to permanently tame me. Now I am on topimax and lexapro, which i find to be my personal ideal combination. I have on rare even taken a zyprexa as a PRN- as needed. I use it for the effect that is similar to valium, very calming if I am very manic. I haven't needed it in several years though. As for zoloft, that didn't work for me. \n\nI had a very bad experience with taking medication that was "thrown" at me. The only time I ever found a combination that worked for me was when I did my own research, advocated myself, and said "this doesn't work for me" and "i would like to try this combination." If you make realistic suggestions, your psychiatrist will probably listen. drugs alone are never enough to be the answer to emotional problems, unfortunately. the best they can do for anyone is regulate their moods and keep them from aweful feelings. anti-depressants do just that, work against depression- not cause happiness. be careful not to confuse the two. good luck.
549949
204.23g of Tryptophan is one mole.  Hence by proportion you can find how many moles is made with 15400mg or 15.4g by: 15.4/204.23.\n\nThis number of moles of Tryptophan produced is also equal to the number of moles of serotonin produced.  As one mole of serotonin is contained in 176.22g, you can find the mass of serotonin formed by: 176.22*number of moles of serotonin.
157428
the small round one that says 377 is valium.(diazepam)\n44-385 is generic-viagra
125867
I'm guessing you mean Xanax (alprazolam).\n\nIn initial studies, it caused weight gain in almost the same number of patients that it caused weight LOSS.\n\nFor other drugs, it depends on the individual medication.
603851
Yes, weight gain is a side effect from diovan hct.  Unfortunately, it is usually not a reason that the doctor will discontinue the drug since the gain usually stabilizes (as yours obviously did at 30 pounds).\n\nIf you contact me with your email address, I will gladly give you a diet based on Jenny Craig and Nutrisystem (unfortunately, yahoo answer's email system doesn't have enough  "characters" to allow me to send the diet through them).  You can do it yourself at home. You won't need to measure anything or count calories. It is all already proportioned. It involves all food groups and is based on 1250 calories. Very healthy.  I have shared it with many askers on yahoo answers.  Hopefully, it will be enough of a calorie change that it will help you shed those extra pounds.
403350
Hi i've been on and off it for 2 years,\nFirstly what form is it in,is it modified release or is it a small white tablet.\nWhat strenght is it in mgs.\nCan you add some more details please.\n\nFor me 37.5 mgs [little white one] made me a sick as a dog,I'd feel sick-Nauseous and extremely tired.\n\n75 mgs modified release is the capsule.\nIt gives you the 'jitters' but they wear off after a few week.Do not drive within the first week-They make you grind your teeth and you can't sleep.\nAfter 4 weeks,you will feel better and gain some energy and strength.They are brill after a few weeks.\n\nA word of advice-Never ever stop suddenly taling Venlaflaxine.You will be ill,sick and almost delireous.You will have the worst 72 hours ever with severe depression.You have to be weaned off it slowley by your GP reducing the dose.\n\nGood luck.
600993
well, lets think about this\n\navagodro's number is the number of atoms in a mole and =\n6.02 x 10^23\n\nso, if we divide the number of atoms in the problem by the number of atoms in a mole, we will get moles of the atom\n\nI think you get .0027 moles.\na quick glance at the periodic table of the elements will give you the molecular weight for silicon\n28.0855 grams/mole\n\nmultiply and you get .076 or in sci notation, 7.6 x 10^-2\n\nassuming I punched the calculator correctly, it looks like "E".
147088
http://www.parpharm.com/pdf/product/tramadol_po.pdf#search='tramadol%20hydrochloride'\nread this
531535
It seems that you have problems with moles and Avagadro's number. You will need to refer to your periodic table to get the molecular weights that your teacher wants you to use.\n\nSo get the molecular weights of the elements you are working with from your periodic table and substitute in the formula.\n\nI am using round numbers to show the substitution you should know how many decimal points you need to work to.\n\nHG atomic weight 200\nO atmic weight 16\n\nSubstitute in the formula to get the masses involved\n\n2 HgO(s) - 2 Hg(l) + O2(g) Hrxn = 181.6 kJ\n 2 (200g + 16g)   =  2(200g) + 2(16g) = 181.6 kj  \n\n432g oxide decomposes releasing 181.6Kj\n\nQuestion a)\nStraightforward ratio. X = the no of KJ required\n\n572g/432g = xkj/181.6kj\n\nYou'll need to calculate the molecular mass from you periodic table substitute it for the 432 and then refine the equation.\n\nQuestion b) Straightforward ratio. X = the no of KJ required\n\nYou'll need to calculate the molecular mass from you periodic table substitute it for the 432 and then refine the equation.\n\n289/181.6 = xg/432\n\nA mole is the amount of pure substance containing the same number of chemical units as there are atoms in exactly 12 grams of carbon-12 (i.e., 6.023 X 1023). This involves the acceptance of two dictates -- the scale of atomic masses and the magnitude of the gram. Both have been established by international agreement. Formerly, the connotation of "mole" was "gram molecular weight." Current usage tends to apply the term "mole" to an amount containing Avogadro's number of whatever units are being considered. Thus, it is possible to have a mole of atoms, ions, radicals, electrons, or quanta. This usage makes unnecessary such terms as "gram-atom," "gram-formula weight," etc.
53048
cyclghst is an idiot! That does not answer the question.\n\nStrattera contains the active ingredient atomoxetine hydrochloride, which is a type of medicine called a selective norepinephrine re-uptake inhibitor. It is a non-stimulant medicine.  The reason it is classified as a non-stimulant is that it does not increase activity of the sympathetic nervous system.\n\nAtomoxetine works in the brain, where it increases the levels of a natural chemical called norepinephrine. norepinephrine is involved in passing messages between brain cells.
482478
Imprint:  COR116\nDescription:  Tab, White, Oval\nIngredient & Strength:  Acetaminophen 650 mg\nBrand (or equiv.):  Tylenol Ex Strength\nFirm:  CorePharma\nClass;Sch:  Analgesic
498762
so you plot the proton number on the y-axis, and the different melting points of the elements across the x- axis.. actually are sure it has to be a bar graph.. i think a line/scatter graph would be more accurate maybe?
340356
51.9961 is the _atomic_ weight.  Molecular weight would be the overall weight of a mole of some molecule of which one or more chromium atoms is a part.
398757
I think these are the correct answers.  I won't show you how I got my answers, but I will tell you one integral piece of information:  remember that the atomic weight is the # of grams in one mole of the element of interest.  (I would like to see what you worked out.)\n\n1)  1.663 g of Pb(NO3)2 in 0.005 mol\n     0.211 g of K2CrO in 0.005 mol\n\n2)  417.210g of CO2 can be removed.\n\nPlease keep in mind that I could be wrong...it's been a bit since I've regularly done chemistry.  Again, I want to know what you did, if you don't mind.
510982
http://www.etfrc.com/benzos1.htm