I know straight is recessive, cury is dominate and wavey is a mix of the two.
138371
Two people with straight hair cannot have a child with curly hair, assuming there are no other genetic factors.\n\nSince straight hair is recessive, both parents are homozygous recessive.  Neither one can pass the dominant curly gene to their children.\n\nss X ss = ss\n\nHmm... some totally clueless folks on here.  The guy above me is right -- they can have a curly haired child only if they have a curly haired mailman  :D
271026
Well... completele dominance means that if the allele shows up at all in the gene, it totally dominates.\n\nA completely made up example: Let's say that a long tail is COMPLETE dominance...  T = Long Tail t = short tail.  So if the gene goes: TT or Tt, the cat has a long tail.  It only has a short tail if the gene goes: tt.\n\nIncomplete dominance is when neither allele takes full control.  So the same example with the cat would be very different.  TT would still mean a long tail.  But Tt would equal a medium-length tail as a blend between the long tail (T) and the short tail (t).  \n\nI'm not sure if that explains it very well... another good way to look at it is with colors...  If a flower's color is determined by incomplete dominance and it has a red allele and a white allele, the flower will be pink, or a MIXTURE of the red and white.  \n\nI hope that helps.
349639
Well if they ensure that the mate a homozygous dominant with a homozygous recessive (eg B/B x b/b, as is the case in monohybrid crosses, you can make sure the parents have this genetics by watching them over generations, mating only dominant with dominant and recessive with recessive) then you'd know that for a diploid plant/animal, as all offspring get one gene from one parent and one from the other, all of the F1 would have to be B/b - so heterozygous for that trait. So they'd all be the same genetically for that particular trait! But then if you crossed the F1 with one-another they wouldn't all be the same... crossing heterozygotes youd get some B/B, some B/b and some b/b...
132349
All three of these answers above me are correct.  Your biological mother would have to be BO and your biological father would be AO and the O allele in each would be recessive, or not showing its trait because of the dominant a/b allele.  A Punnett Square would look something like this:  \nMOM    \n       ||||||||||  B |||  O  |\n       ------------\nD||     A| AB |  AO |\nA||     -------------\nD||     O| BO |  OO | <- That's you with type O blood.  If you had three siblings it would be likely that one would have AB blood, one type A blood, and one type B blood. \n       ------------
43860
I believe that I was taught it is genetic... your mother or your father have the gene and pass it to you... they don't have to be a lefty... only have the gene
489392
the result of fl is barr(if it is dominant) or else white.one main ground rule of inheritance is that it may be white or barr but one can be dominant only for 2 generations it's not the matter but in  the third gen.the recessive will take the turn
220124
a punnets square allows you to graphicially understand all possible offspring created by two parents. the phenotype is the outward expression of the gene you are studying like a rabbit being brown or white. the gene is usually coded by the first letter of the dominant phenotype. suppose brown was thought to be dominant and white was recessive. brown would be called BB if it was homozygous or Bb if if was heterozygous. white would be called bb. the heterozygous organism is always the dominant phenotype. (except in codominance etc.) punnet squares can be used to answer questions like is it possible for two blondes to have a brunette baby? or is it possible for two purple plants to produce seeds that would make white flowers? your book or your notes will show you how to set up a punnet square properly.
452267
Its actually more complex than a typical simple black and white mix (referring to color)\n\nAlbinism is a genetic disorder that is quite recessive.  The possibility of the resulting child having the color of black, white or "blended" would depend if the child inherits the albinism. \n\nInheriting the afican parent's albinism depends on the caucasion's popsibilty of passing along albanism as well. \n\nTaking the albinism factor out of the equation and it is safe to say that the offspring of a person with black skin and a person with white skin will result in a blending of the skin colors. \n\nIt is also safe to assume that the offspring will appear to have more of an african-american (black) look as opposed to a caucasion (white) look and would appear to be a child of mixed heritage.
532895
To start with, You need more information as to the Parental genotype for each question, \nFor example in question (a) since you have only mentioned full dominance, we can either assume both parents will be A/A x A/A. However this cross is useless because you know there will not be variation in the F1 progeny because both are dominant. thus the ratio is 100% all dominant A/A.\nThe second assumption is to cross a dominant parent A/A with a recessive parent a/a. If that's the case then you choose one gamete from each parent to form the F1 as follow\n\nParental Genotype        A/A    x    a/a\nGametes                          A     x    a\n\nF1                                         A/a\n\nfrom here, if you need to get genotype and phenotype ratio for your F2, you need information as to what kind of cross you want do. You can self the F1 or you can testcross with a recessive parent. In either case the ratio is different\n\nSelf-cross                  A/a    x      A/a\nGametes              1/2 A , 1/2 a    x   1/2 A , 1/2 a\n\nF2  punnet square\n..............1/2  A..........1/2 a\n\n1/2 A......1/4 A/A........1/4 A/a\n\n1/2 a.......1/4 A/a........1/4 a/a\n\nPhenotypic ratio of F2:  1/4 A/A; 2/4 A/a; 1/4 a/a = 1:2:1\nGenotypic ratio of F2:  (1/4 A/A + 2/4 A/a); 1/4 a/a = 3:1\n\n\n\nTest-cross                  A/a    x      a/a\nGametes              1/2 A , 1/2 a    x   1/2 a , 1/2 a\n\nF2  punnet square\n..............1/2  A..........1/2 a\n\n1/2 a......1/4 A/a........1/4 a/a\n\n1/2 a.......1/4 A/a.......1/4 a/a\n\nPhenotypic ratio of F2:  1/2 A/a; 1/2 a/a = 1:1\nGenotypic ratio of F2: same as genotypic ratio\n\nquestion (a) is not formulated in a clear way. for example. question (a) should have mentioned something like this:\n\na) The F2 of monohybrid cross with both parents full dominance, or 1 parent full dominance, 1 parent recessive.\n\nIs hard to work in genetics problems when the problem lacks crucial information. let me know if there is more information that you did not write down on your question.
231099
sounds like a candidate for queer eye for a straight guy.
122093
Your friend is correct. I just studied this in school. Dark hair always dominates light hair. And the allele for green eyes overpowers the allele for blue eyes.
447711
Mendel's laws predict that a monohybrid cross between any two heterozygotes would produce offspring in a 3:1 phenotypic ratio.  That is:\nAa  X  Aa = \n1 AA - Dominant Phenotype\n2 Aa - Dominant Phenotype\n1 aa - Recessive Phenotype\n\nSo, 3 Dominant : 1 Recessive\n\nNow for your two instances:\n\nA.\nIn the case of codominance we have two different dominant alleles and one recessive allele.  When both dominant alleles are present, the phenotype is different from that seen when either of the alleles is present alone (homozygous or heterozygous).  A classic example of codominance is that of blood types.  Type A and type B are both dominant phenotypes, type O is the recessive phenotype, and type AB is the codominant phenotype.\n\nBack to your question, lets say:\nA = dominant allele 1\nA* = dominant allele 2\na = recessive allele\n\nCrossing two heterozygotes: Aa X A*a results in\n1 AA* - codominant phenotype\n1 Aa - dominant allele 1 phenotype\n1 A*a - dominant allele 2 phenotype\n1 aa - recessive phenotype\n\nSo we have a 1:1:1:1 phenotype ratio, not Mendelian expected 3:1\n\nB.\nRecessive lethal alleles are a situation where the homozygous recessive genotype is lethal to the organism.  So if we cross two heterozygotes:\n\nAa X Aa \n\nWe get:\n\n1 AA - dominant phenotype\n2 Aa - dominant phenotype\n1 aa - lethal, so this offspring is never seen\n\nSo here all the offspring seen are of the dominant phenotype, again defying Mendel's predicted 3:1 ratio.\n\nHope this helps!
314466
a punnett square is a genetic tool designed by reginald punnett that biologists continue to use in order to determine the probability of an offspring expressing a particular genotype.\n\ncertain facial features are dominant such as curly hair, free ear lobes and dimples. the curly hair trait will be used as an example: a homozygous curly-haired male with genotype CC, meaning he carries both dominant alleles and has curly hair, is crossed with a homozygous straight-haired female with genotype cc, meaning she carries both recessive alleles and has straight hair. typically, the dominant trait is denoted by capital letters and the recessive by small letters. \n\nhomozygous means that both alleles are the same, while heterozygous means both alleles are different. so, if one of them were heterozygous then its genotype would be Cc, meaning it has one gene for curly hair and the other for straight hair.\n\nusing the given genotypes, a table is made putting one of the genotypes on the top row and the other genotype down the left column. as a rule, the male's (m) genotype is usually written down the side of the square, while the female's (f) is listed on the top. we'll go down starting at the first column to put both genotype letters in the blank, remembering that in a genotype the dominant gene is written first. \n\nm&#92;f c  c\nC  Cc  Cc \nC  Cc  Cc\n----------\nresult: 4 Cc (curly hair)\n\nwhen the genotype paired up results in Cc, the dominant allele is shown in the phenotype, meaning the offsprings with genotype Bb will have curly hair. all of the offsprings from this cross demonstrate the phenotype for the dominant allele, though they are all heterozygous.\n\nnow let's try to cross a homozygous curly-haired male (CC)with a heterozygous curly-haired female (Cc).\n\nm&#92;f C  c\nC  CC  Cc\nC  CC  cc\n---------\nresult: 2 CC : 1 Cc : 1 cc\n3 C_ (curly hair) : 1 cc (straight hair)
379773
I like your straight hair.  I would love to see your curlies.
68119
if it is a complete dominance situation, then it's what the dominant color is. if it's imcomplete dominance, then it's a mixture of W and w. for example red and white would make pink.
544571
Sheesh.  Do you mean dominant, or dominated?  The difference is important.
381195
B\nwhen the white and purple were bred, they were all purple so it must be dominant. those plants would then be Pp, and when bred with pp half the plants were purple (Pp) and half were white (pp)