1)  [8] in Z(17)\n2)  [11] in Z(54)
126347
1) 15\nbecause 15*8 = 120\n120 in Z(17) = 1\n2) 5\nbecause 5*11 = 55\n55 in Z(54) = 1
362367
1) 21\n2) 52\n3) 40\n4) 80\n5) 104\nIn each pattern you are adding a number to the one before it.\nEx: 1 + 0 = 1, 1 + 1= 2, 2 + 1 = 3, 3 + 2 =5, 5 + 3 = 8, etc.
664297
2[w+ {2w+8}]= 64\n3w+8 = 32\nw= 8 \nyour are right
420160
Let us call the first 2 "2 sub 1", the second "2 sub 2" ... same thing for the 6's.\n\nLet us say that "2 sub 1" is distinct from "2 sub 2", and so on.\n\nWe have 8 choices for the first number, seven choices for the second number, etc. This means that there are 8*7*6*5*4*3*2*1 choices, or 8!. \n\nNow if you look at any number, take all of the 2's out. You see that you can rearrange the 2's in 3! different ways (including the original arrangement) using the procedure in the paragraph above. If we take out the 2's rearrange them, and put them back in we have created the a new arrangement. So for each arrangement of numbers, we have counted it 3! times. So we divide by 3!. The same thing for the sixes, we divide by 2!.\n\nThe result it (8!)/((3!)(2!)) = 3360 choices.
493072
1) b)\n\n2) [H2O]^2 / 2[H2] [O2]\n  \n   [NO]^2 / [N2] [O2]\n\n3) b)\n\n4) b)
115224
1:C\n2:A\n3:D\n4:D\n5:A\n6:D
171622
THE POSSIBILITIES:\n\n1.1:1→1*1=1\n2.1:2→1*2=2\n3.1:3→1*3=3\n4.1:4→1*4=4\n5.1:5→1*5=5 √\n6.1:6→1*6=6\n\n7.2:1→2*1=2\n8.2:2→2*2=2\n9.2:3→2*3=5\n10.2:4→2*4=8\n11.2:5→2*5=10 √\n12.2:6→2*6=12\n\n13.3:1→3*1=3\n14.3:2→3*2=6\n15.3:3→3*3=9\n16.3:4→3*4=12\n17.3:5→3*5=15 √\n18.3:6→3*6=18\n\n19.4:1→4*1=4\n20.4:2→4*2=8\n21.4:3→4*3=12\n22.4:4→4*4=16\n23.4:5→4*5=20 √\n24.4:6→4*6=24\n\n25.5:1→5*1=5    √\n26.5:2→5*2=10   √ \n27.5:3→5*3=15   √\n28.5:4→5*4=20   √\n29.5:5→5*5=25   √\n30.5:6→5*6=30   √\n\n31.6:1→6*1=6\n32.6:2→6*2=12\n33.6:3→6*3=18\n34.6:4→6*4=24\n35.6:5→6*5=30   √\n36.6:6→6*6=36\n\nProbability = No. of required possibilities/No. of total possible events =11/36\nSo the right answer is D
313313
1.D\n2.B\n3.B\n4.A\nright?
88032
2, 3, 5, 7, 11, 13, 17, 19\n1 is NOT prime
37185
11.\nthe =3\nalphabet =8
47572
1) 4\n2) 15241578750190521
414878
1 -> b\n2 -> e\n3 -> c\n4 -> d\n5 -> a\n6 -> f
165661
1st list of elements=\n\n{X u Y}n Z\n{2,4,6,8,10} n {3,6,10,12}\n= {6,10}\n\n2nd list of elements=\n\n{Y n Z}' /X\n{6,10} / X\n{6,10} / {2,4,6,8}\n={10}
182273
Let 1 2 3 4 5 6 7 8 9 A B C D be the dots, with D in the middle. (You say 1 in the middle)\n\n1 2 3 4\n5 -- -- 6\n-- -D- --\n7 -- -- 8\n9 A B C\n\nIT CAN BE DONE WITH 5 LINE SEGMENTS AND DOESN'T NEED 6.\n\nConnect 7-5-1-2-3-4-D-9-A-B-C-8-6 in a Z-shape\n\nSo I think if it needs six lines, your question was meant to be regarding 16 dots, 4 of them in the middle. It would then be similar to your other question with 9 dots.\n\n1 2 3 4\n5 6 7 8\n9 A B C\nD E F G\n? -- -- !\n\nConnect 1-2-3-4-8-C-G-! and then proceed as for 9=dot problem, F-A-5-6-7-8-B-E-?-D-9. Six lines needed.\n\nGeneralising, an n x n square of n^2 dots will require 2n-2 lines. (for n>2)\n\nImagine a further 9 dots wrapped around the 16-dots as follows\n\nH I- J K L\n1 2 3 4 M\n5 6 7 8 N\n9 A B C 0\nD E F G P\n\nConnect G-F-E-D-0-5-1-H-I-J-K-L-  M-N-O-P and then proceed as for the 9-dot problem:\n\nC-7-2-3-4-M-8-B-E-A-6\n\nwhich is 8 lines.
52115
#1: no clue\n#2: 36, 16 (1*9,1*4,2*9,2*4,3*9,3*4,4*9,4*4)\n#3: 5/252, 2/2016 (100/2/3/4/5/6/7/8)
654356
The first one is (-5, 3). I don't remember how to do the others.
409968
Use the FOIL method; First, Outer, Inner, Last.\n\nFirst, n * n\n\nOuter, n * 5\n\nInner, n * 7\n\nLast 7 * 5.\n\nThen add them all together.\n\n22 NOV 06, 0420 hrs, GMT.