Each of the square tiles that a tile company plans to manufacture has an area of 3 square feet. To the nearest hundredth of a foot, what should be the length of each side of one of these tiles?
122684
1.73\n\nproof\n3 squared = 1.73205080756887729....\nrounded\n1.73
447193
its a square with 13 feet sde.\n\nIf a proof is to be sumbitted ask her her to find are at different side lenghts,\n\n1,12\n2,11\n......\n......\n.......\n13,13\n\n14,2 etc and hence conclude.\n\nI i dont know a better proof for fifth grader. otherwise i will nedd to use maxima minima or a quadratic equation atleast to prove that\n\n\nsorry i cant help much\n\n\n\nbythe way you dont adjust anything  like  13.00001 or 12.9999999\n\nsquare is a special case of rectangle with length=breadth
341494
"Square feet" are used to measure area and "cubic feet" are used to measure volume. These are quite different concepts and there is no way to change one into the other. You can convert cubic feet to gallons, (one gallon is approximately 0.1336 cubic feet) or square feet to acres (one acre is 43,560 square feet) but not square feet to cubic feet.\n\nIf you were covering an area with a depth, then we can convert.  see below:\n\nhow many cubic yards of soil is needed to cover 750 square feet at a height of 3 inches?\n--------------------------------------------------------------------------------\nSince you want the volume in cubic yards I would first convert all the measurements to yards. There are 3 feet in a yard and hence 32 = 9 square feet in a square yard. Thus\n\n750 square feet is 750/9  = 83.33 square yards.\n\nThere are 36 inches in a yard so\n\n3 inches is 3/36  = 0.0833 yards.\n\nThus the volume of soil needed is\n\n83.33  0.0833 = 6.9 cubic yards.
287960
Assume that the length is y cm.  Then the width is (y-3) cm.\nTo find the area, multiply length by width : y x (y-3).  But this is equal to 54 cm^2.\n\nSo, y x (y-3) = 54\n    y^2 - 3y  = 54\n    y^2 - 3y - 54 = 0\n\nSolving for y (using any method at your disposal (formula, completing the square, factoring), y = 9 or -6.  Obviously, -6 cannot be a side.  That leaves us with the length being 9 cm.  If the width is 3 cm less, that will be 6 cm.\n\nYou did ask for it to be explained.
532569
You can do all these in google. For the first one, type in "4 square metres in square cm", and it tells you the exact answer. Do the same for the others. \nYou can then work out any others by yourself without needing to ask :)
163593
THE PRICE OF CERAMIC ROOFING TILES CAN RANGE ANYWERE FROM 80 TO 200 DOLLARS PER SQUARE DEPENDING ON QUALITY AND THAT IS RETAIL PRICE FROM SUPPLIERS. A SQUARE IS EQUAL TO A 10 FT. BY 10 FT AREA = 100 SQUARE FEET OR 1 SQUARE. AND I BELIEVE THAT TILES PER SQUARE DEPENDING ON MEASUREMENTS CAN RANGE FROM 90 PIECES OF TILE TO 100 PIECES OF TILE.BUT AS YOU ALREADY KNOW YOU NEED AN NOA# OR PRODUCTIC APPROVAL NUMBER. IF YOU HAVE ANY QUESTIONS OR IF THAT HELPED LET ME KNOW. THANKS
399807
I would think that the area is proportional to the *square* of their corresponding sides.\n\nIf you had a rectangle that was 3 x 4 and the corresponding rectangle was 6 x 8, the ratio of their sides is 1 : 2.  But their areas are 1 : 4 (2²).
41657
Ya the number 1s 320\nBut who in the world has a perfecr floor???\nPlus you dont know how the room is \nWhen doing a floor you want a reveal the same on all 4 side if you can to make it look right. \nYou would not want a tile 4inch on this end and 8 on the other.\nSo then is you do the math its\n320+16+20=356total\nthis will make sure that the floor looks correct and your not short\nI have been in the field 20yrs+ and trust me you never buy just what you need.\nIf you did that and you need 10 more pc and you went back the tiles would be from a differnt batch and not match up right.\nGoodluck
154430
It is a problem in long division with a remainder. You need to simply divide the whole integers (everything before the decimal point) and keep the remainder as the inches.  Thus your problem becomes 20 feet and 6 inches, you can check your answer by reversing the problem.  In 20 feet there are 20 times 12 inches, or 240 inches with 6.138 inches left over.  Thus the answer is 20 feet and 6 inches (rounding to whole inches as in your example). \n\n-LOVE YOUR NIEGHBOR AS YOURSELF
448503
From the Question, it should be a triangle....\nso take take 28 X 25 / 2 should be the answer\n350 ft!
451635
you might try addition and subtraction this is not complicated just add table-space-table till you reach the room dimensions ( in each direction )\n\nno matter what shape the tables are in the formula they are effectively square or rectangular ( actual dimension plus the 3' of clearance )
517072
Let the length be x ft and the width be y ft\n\n2x + 2y = 300\nie x + y = 150\nThus y = 150 - x\n\nArea = xy\n=x(150 - x)\n= 150x - x²\n\nVertex of this parabola occurs when x = -b/2a and at this point Area is maximum as the parabola is concave down. (a < 0)\n\nie x = (-150)/(-2)\n= 75\n\nWhen x = 75 y = 75 so it should be square with sides 75 ft\n\nWhen x = 75, Area = 150*75 - 75² = 5625 sq ft\n\nSo the maximum area occurs when the length (and width) are 75 ft and it equals 5625 sq ft
213978
There are 12 inches in a foot.\n\nSo divide by 12.
397826
Let the length of side "b" be x ft.\nTherefore side a=2x and side c=2x+3\nAccording to the problem,\nx+2x+2x+3=93\n=>5x+3=93\n=>5x=93-3=90\n=>x=90/5=18\nTherefore.side a=2X18=36 and side c=36+3=39\nAnswer a=36ft. b=18 ft and c=39 ft
252597
That all depends on the shape of the room, the units the measurements are in, etc.  If is it a rectangular room, it is length times width.  Other rooms are just the formula for the are of that shape.  Ex. Circular room would be the formula for are of a circle.  If the room is not just one even, easy shape, break it up into smaller parts and find the area of each then add them together.\n\nIf the units are not in feet, convert them to feet before you find the area of the shape, will make it easier in the end. Ex.  If in inches, divide length by 12 and you have the number of feet.\n\nHope that helps, enjoy.
100505
Maybe I'm not understanding the problem correctly, but if "There is only space for the pature 2 be @ most 100ft" means that no side can be longer than 100 feet then I think you may have written the question down incorrectly.\n\nIf each side has to be less than or equal to 100 feet, then let's say that each side *is* 100 feet in length. There are 4 sides, so the perimeter is 4 times 100 feet = 400 feet. You say you have 500 feet of fencing. This is more than enough to surround the maximum-sized pasture allowed. So what's the problem?\n\nThe only two linear equations you need to worry about in this case are:\nwidth <= 100\nlength <= 100\n\nChoose any values for the width and length that satisfy these constraints,\nsay the width = 75 and the length = 50 or the width = 2 and the length = 89\nand you have solutions to your question.\n\nOften these questions ask for the maximum area that it is possible to enclose. In this case there is only one solution: width = 100, length = 100 therefore the area enclosed = 10,000 square feet and the amount of fencing used is 400 feet.
55367
Since a square yard means a square with sides one yard long, and one yard = three feet, the same square would be three feet long on each side, or 9 square feet.  So you were right to divide by 9.