3.435 kg/mm^3 to g/cm^3
119905
the way i do conversions is this. you know that 1kg = 1000g right? and 10mm = 1cm. so that means 1kg/1000g = 1 = 10mm/1cm. so you multiply the equation by 1 repeatedly until you get the units you want. \n\n3.435kg/mm^3 * 1000g/1kg * 10mm/1cm * 10mm/1cm * 10mm/1cm\n\nyou have to make sure the units you dont need all cancel out. in this case, the kg gets taken out and the mm should get taken out too. i dont know if u get this but ya. \nso the answer is 3435000g/cm^3\nlet me know if u needm roe help or whatever. laterz
596270
me=[ (Vx2)/450240] x W in grains = .2 ftlbs
260709
Depends on what they are filled with.  If it is saline, salt water then a cc of water has a mass of 1 gram.  To convert 1 kilogram to pounds, multiply by 2.2
57922
Multiply inches by 2.54 to get centimeters.\nDivide pounds by 2.2 to get kilograms.
363289
acceleration can be found using\na=(m1-m2)g/(m1+m2) = 3*9.8/5 = 5.88 m/s^2
331891
If you mean ml (milliliters), mg (milligrams) and cm^3 (cubic cm), I can help you.\n\n1 cubic cm = 1 millileter = 1 gram (1000 mg) of water.\n\nThe following flows are all equivalent:\n7000 ml/hr\n7000 cu cm/hr\n7000 grams/hr\n7000000 mg/hr\n\nI think I've answered your question, but if you have more details, please add them to your question.
439603
w = mg\n(w is weight, m is mass, g is acceleration due to gravity (9.8m/s^2))\n :. m = w/g\n        = 300 / 9.8\n        = 30.6 kg
467433
Use dimensional analysis: (/ is fraction bar, * is multiply)\n\n25euros/500gr  *  1000g/1kg  *  $1/1.14euros \n\nResult: $25000/570kg  or  $43.86/kg
606689
assume 0.1mm3\n6.02e22 mm3\n6.02e19 cm3 \n6.02e13 m3\n6.02e5 km3\nroughly 602,000 km3
491580
There are several wrong answers in the preceding.\nThese are correct:\n\n(lbf) = (lbm) * (acceleration in g)\n(lbf) = (slugs) * (acceleration in ft/sec^2)\n\n1 g = 32.174 ft/sec^2\ncorrespondingly\n1 slug = 32.174 lbm\n\nIf you know acceleration in in/sec^2, the corresponding unit mass would be 12 slugs or 386.09 lbm. This unit does not have a popular name that I am aware of.\n\n1 lbm = .45359 kg\nAll conversions are approximate
392663
Since 50 grams is .05 kg, at sea level the weight is .05 * 9.80665 = .4903325 N.\n\nAssuming a sea level radius of 6400 km, at 6401.5 km the reduction in gravitational force is (6401.5^2) / (6400^2) = 1.000469\n\nAnd the weight would be .490103 Newtons.
133184
kg m^2\n------- = Joule\ns^2\n\nb = kg m/s
471169
53 kgs = 116.8438 pounds\n\nIf you want to convert stuff in the future, here's an easy way to do it:\nhttp://www.strengthcats.com/kilopoundconverter.htm
482136
density=__g/ml   that means density equals __grams per millileter
413776
length = 3.5m (appr)\n\nn=6\n\n(hint: find GCF of frequencies)
662895
Set m1 = 0.145 kg, v1i = 0.720 m/s\nand m2 = 0.295 kg, v2i = 2.22 m/s\n\nConservation of linear momentum:\nm1v1i + m2v2i = m1v1f  + m2v2f\nSimplified\nm1(v1i-v1f) = -m2(v2i-v2f)\n\nConservation of energy (kinetic only):\n(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2\nSimplified:\nm1(v1i - v1f)(v1i + v1f) = -m2(v2i - v2f)(v2i + v2f) \n\nSolving the two simplified equations:\nv1f =((m1-m2)/(m1+m2))v1i + ((2m2)/(m1+m2))v2i\nand\nv2f =((m2-m1)/(m1+m2))v2i + ((2m1)/(m1+m2))v1i\n\nTherefore,\nv1f = 3.315 m/s\nv2f = 1.23 m/s
417135
For quick answers to conversion problems:\nhttp://www.onlineconversion.com/\n\n1) 16 yr = 832 wk\n2) 172 oz = 4.88 kg\n3) 1020 kg = 1.02*10^9 mg\n4) 1.936 L = 1.936*10^6 μL