what common household liquid can be combined with water in equal porportions with out increasing the volumeof the original comtainer of water?
125209
Since you are referring to the volume of the water container and not the volume of the water itself...then the container should have at least twice the volume of the water, so that if another liquid having the same volume of the water will be added to the water in the same container, no spilling will happen. And there are many other liquids that can be added...\n\nHowever, if you made a mistake and you are referring to the volume of water after all, and the original volume of water will not change even if another liquid with the same volume will be added, then that other liquid can be LPG (liquified petroleum gas?!?). The volume of water will not change since, at ordinary temperature, the LPG when poured(?) to the water container will instantaneously change to gas, and therefore, no liquid will be effectively transferred to the water container. Therefore. no change in volume will take place!
129004
Drink plenty of water.
535728
just drink it all and then you wont have to worry about having to store it. duhhh!!
183013
Thats simple! Boil some water
623169
1 liter water, 5 tsp salt, 3 tsp sugar== voila! an oral rehydrating solution. Drink as much as you can!
365559
Without introducing a 3rd substance, there are only 2 methods to accomplish what you're asking.  \n\n1/  increase the density of the substance you want to submerge, but without knowing the physical properties it's impossible to propose anything\n\n2/  decrease the density of the water:\n\nput whatever you want to submerge in a pressure vessel and pour in water.  make sure that the combined volume of the water and the substance is less than one or two percent of the total volume of the vessel.  place the lid on and heat until the temperature reaches 120 to 130 degrees C.  your substance is now submerged in water.\n\nYou'll want your teacher to assist to prevent an explosion.
215270
I love this.\n\nFill the 7 liter pail.\n\nPour into 5 liter pail.\n\nLeft with 2 liters in 7 liter pail.\n\nEmpty 5 liter pail.\n\nPour the 2 liters from the 7 liter pail into the 5 liter pail.\n\nFill 7 liter pail.\n\nPour into the 5 liter pail til full.\n\nLeft with 4 liters in 7 liter pail.\n\n:)
552083
assuming what you're adding to water is 1:80, then it'll be\n3000mL / 80 = 37.5 mL
448049
Yes, it is true that the density of a solution is different of solvant but tjis difference is small ; So , i propose to dissove 40g of amyl acetate in a liter of water if that acetate is a solid. If that acetate is aliquid the total volume will be 1.04 l and you must use 47 cc tp water
310063
It would make water (H2O).
270778
It would depend on the size of the jar you was puting it into... If you only have a pint jar that is what will be in it at the end of the year the rest will be spilled. IF by chance your jar did hold all the pints you added it would be 16198 gallons or 64792 pints
660840
It depends on the density of the liquids... think about this... 1 liter of water weights less than 1q liter of quicksilver or one liter of maple syrup... the density changes the weght of the liquid by volume.
258433
I assume this is based on the principle of Osmosis. I would like a bit more data before answering further.
650484
Able to be dissolved by water.
541934
If you want to make 1 Liter of this final solution, you would need to take 721 mL of your 52% formaldehyde solution, add 120 mL of methanol to it and bring the final volume up to 1 Liter with water.  You should be able to scale this up or down to make any particular volume you need.\n\nWhat isn't coming out right in your calculations?
586722
WATER. It's that simple.
474182
OK, I think I have this one pegged:\nThe original mixture is 10% acid and 90% water and the final mixture is 60% acid and 40% water after pouring some amount of the original mixture into 5 liters of pure 100% acid. Set up two equations:\nfor the acid: x (10) + 5 (100) = y (60) where x = original mixture volume and y = volume of resulting mixture.\nfor the water: x (90) + 0 (100) = y (40)\nthen these can be reduced to:\n10x + 500 = 60 y     and  90x = 40y\nsolve the simultaneous equations to find x and y\nThe volume of water in the final mix is equal to y times .40\nGood luck