Explain why the decimals 0.16,0.1666667,0.1616161616 are  not equal to the same number.\n__>__>__
130925
.16 has a zero in the thousandths place, but .1666667 has a six in the thousandths place. .1616161616 has a 1 in the thousandths place.
621470
T=.00139x^2+.0304x=1.25 \n\nmaybe you meant\n\nT=.00139x^2+.0304x-1.25 \nor\nT=.00139x^2+.0304x+1.25 \n\n?????
197849
Because a double can represent a much wider range of magnitudes that a float, the cast/conversion can produce some enexpected results.\n\nTo understand the conversion fully, you must format the number being converted into binary format. That is when you see how the bits are altered when converting from long (64 bits) to float (32 bits).
506844
0.00056 = 0.056%, and by the way, \n0.056     = 5.6 % and\n5.6         = 560%
103665
I thought it was 3.142857...Anyway, nice of u to sacrifice ur 5 points to give us 2 points. Three cheers for you. Thanx for the 2 points.
546845
The previous responders have given you the answer for a terminating decimal. (That means a decimal that has a certain number of decimal places, and then all the rest of it is zeroes. For example, .9187 is a terminating decimal, which could be extended with zeroes as .918700000000000000000....)\n\nBut you may be asking about repeating decimals. These are more interesting. Here's how you convert them to fractions.\n\nIf there is only a single digit that repeats (such as .3333333333....), you take that digit and put it over 9:\n.3333333333.... = 3/9 = 1/3. (Note that you should put the fraction in lowest terms (1/3, in this case) after you put the digit over 9.)\n\nIf there are 2 digits that repeat, you put them over 99. For example, .636363636363636363.... = 63/99 = 7/11.\n\nAnd if there are lots of digits that repeat, you put them over the same number of 9's. For example, .71237123712371237123.... = 7123/9999.\n\nThere are other tricks, such as a decimal that doesn't repeat until after the first few decimal places (e.g., .7633333...), but the above rules should handle most of the situations you encounter.
443122
There's a better way of looking at it.\n\nFor every real number x in [0,1) you define D(x, n) as the nth decimal of x.  This is defined for every natural number n.\n\nFor x=1/3, we have D(1/3, n) = 3 for every n.  The number 0.3333... (the dots are important, they indicate that the nth decimal is a 3 for every n) is not "very close" to 1/3, it does not "tend toward" 1/3.  It is EXACTLY the number 1/3.  Show me a number other than 1/3 and I will show you that its decimal representation is not 0.33333...\n\nFor 0, we have D(0,n) = 0 for every n.  There is never a '1' decimal.  If you give me an arbitrarily small number 0.00000...1, the digit 1 is at a finite position p.  I can then reply with a number such that D(x,n)=0 for all n<=p, and D(x,p+1) = 1.  That number is greater than zero and smaller than the number that you gave me.  \n\nThe 0.5 = 0.49999... thing is just a quirk of decimal notation.  We can formally prove the equality as follows:\n\nLet a = 0.5, i.e. D(a, 1) = 5 and D(a,n) = 0 for all n>2.\nLet b = 0.4999..., i.e. D(b, 1) = 4 and D(b,n) = 9 for all n>2.\n\nProof by contradiction that a=b: Let's suppose on the contrary that a > b.  This means there must be a number x between a and b.\n\nLet's figure out the digits of x.  Since x is less that a=0.5, its first decimal must be a 4.  D(x,1) = 4.\n\nThe second decimal of x must be 9 since x > b `> 0.49.\nThe third decimal of x must be 9 since x > b >0.499.\nAnd so on, the nth decimal of x must be a 9 because x > b > the number y such that D(y,1)=4, D(y,i)=9 for i=2 to n and D(y,i) = 0 for i>n.\n\nTherefore x has exactly the same digits as b=0.499999... (I just showed that for every n, the nth digit of x is the same as the nth digit of b), and so x=b.  Contradiction, ergo a = b.\n\nThat's the difference between 0.499999... vs. 0.5 and 0.0000...1 vs. 0.  In the latter case, it is possible to find a number that is between the two.
388300
they are similar because they have '435' , they are lower than 1\nthey are dfferent from each other because : -453 is an negative integer , 0.453 is a positive real number
33394
if x is the original price\n216=x-.1x\n216=.9x\ndivide 216 by .9 this gives you x
551385
Gopal has the correct answer! \n\nSo... becareful with some other results... and... never use:\n0.833 instead of 5/6... it's a mistake!\n\nFinished Algebra with 19!
412833
though there is only 16 0's, you have to count the place where the decimal is at also. for example: \n45,000,000=4.5x10^7 becasue you move the decimal over 7 places to get 45,000,000.\n\n220,000,000,000=2.2x10^11 because of the decimal placement also
504933
Look for some math help live chatrooms.  Do you have anyone's phone number from school who could help?  Don't sweat it too much.  You can just divide as with any other numbers just remember to put the same number of decimal places in your answer that you began with.  Look at the examples in your textbook.  Good luck.
117261
The quick way: Move the decimal point to the right the same number of places as the exponent.  Eg: 3.2 x 10^16 is 32,000,000,000,000,000\n\nIf the exponent is negative, move the decimal point that number of places to the left.  Eg:  3.4 x 10^-4 is 0.00034.\n\nIf the exponent is zero, the decimal point stays put.
226492
When you are rounding a number to two significant figures first simply write the first digit (5) and then look at the third digit. If it is above or equal to 5 then incrase the second digit. If the third digit is below 5 then keep the second digit is kept the same.\n\nThe remaining digits are then just replaced by '0'\n\nIn this case O is below 5 so the second digit is kept the same. The remaining digits are then replaced by zeros. Thus we get 5200\n\nThis is a rather an irrational approach to it. Rather when rounding to two significant figures the want you to choose between two values of which one is closer to the given one. In this case they essentially want you to determine whether or not 5206 is closer to 5200 or 5300. Thus if you had to 'simplify' the number, which would give less error!
119262
to change a decimal into a fraction take the decimal lets say .56 and put to over 1 with as many zeros that there is in the decimal so it becomes 56/100 then reduce to its simplest terms....56/100=14/25  and viola!\n\nto turn it into a decimal just divid it so it would be 14 divided by 25 ...and you get .56! \n\nhope this helps :)
504431
what it means is this 4 plus negative .01 and with the other it's 5 plus negative .04 its simple. if you know what it means and if you took notes look at them. it may help a little
184615
nope... 01 (in binary) = 1 (in decimal)\n\nand \n\n10 (on binary) = 2 (in decimal)