I need to know how to construct angles and triangles using a compass. Please tell me. URGENT!!! I have mathematics exam tomorrow.
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Your question is a little bit generic. You can draw a lot of "angles and triangles" with a compass.\nThe simplest procedure that comes to my mind is this:\n1) Trace an horizontal segment from a point A to another point B.\n2) Now point your compass in A, with radius equal to AB and trace an arc over the segment.\n3) Then point in B with the same radius and trace another arc. The two arcs will intersect in a third point C.\n4) If now you join A with C and C with B, you have a triangle with all segments and angles equal.\nBe more specific if you need more help.
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Check Out This Website!! \n\nGives You Examples And Everything!! \n\nhttp://www.mathleague.com/help/geometry/geometry.htm
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WTF IS THE TRIANGLE AND THE U FOR AND HOW DO U MAKE THE TRIANGLE... THERE ISNT A KEY OR ANYTHING...
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Lots of unnecessary complications here.\n\nAirspeed is the hypotenuse. 20.4 is the side opposite the angle we are looking for.\n\nThe heading, east of north, must be at angle sin^-1(20.4/241).\n\nSpeed relative to the ground is the third side of the triangle, and is \n\nsqrt(241^2 - 20.4^2)\n\nZidane has got the angles all wrong. The wind is from the east. We want to fly due north. That's where the right angle is. 241 is the hypotenuse of the triangle. The wind serves to make the ground speed less than 241, not greater.
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Don't panic ok? Math is something that's dead. It can't kill you so don't worry, we'll get through this =D\n\nLet the sign (>)= angle\n\nLets start off with what you know:\n\n1) Isosceles Triangle means that the bottom 2 angles (in this case >B and >C) is the SAME THING. >B = >C!!!! Remember that.\n\n2) >A is 20 degrees more than 3 times >B. Now how the hell do you write that? Well, I'll show you:\n                                     >A= (3)>B + 20 \nNow look at what I've wrote. I wrote that >A is 3 times the >B plus 20. Yay.\n\n3) All the angles of a Triangle adds up to how many degrees? If you say 180, you are RIGHT! So it makes sense to write:\n                                (>A) + (>B) + (>C) = 180\n                                                 Yay.\n\nNow all you have to do is substitute what we already know. We know that [>A= (3)>B + 20] , and that [>B = >C] \n                                 \n                                  (>A) + (>B) + (>C) = 180\n                                           which becomes\n                            [(3)>B + 20] + [>B] + [>B] = 180\n\nYou see, towards the end I substituted >C with another >B because they are the same damn thing. =D Yay.\n\nNow we add Like-terms.\n\n                            [(3)>B + 20] + [>B] + [>B] = 180\n                                               becomes\n                                         (5)>B + 20 = 180\n\nSee how I got that? I just added the 2 angle Bs in the end with the 3 we started out with.  >B  + >B + (3) >B = (5)>B Yay!\n\nNow we subtract 20 on both sides of the equation. Giving you:\n\n                                          (5)>B = 160\n\nNow lets divide the 5 on both sides so we can get >B alone by itself. Giving you:\n\n                                            >B= 32 degrees!\n                                            which means that \n                                            >C= 32 degrees!\n\nWe stated before that >B is the same as >C so there is your answer:  >C= 32 degrees!!!!!!!!!!!!!!! YEA BABY WE DID IT! WOOOO We solved it YES!!!\n------------------------------------------------------------------------------------\nNow lets check! If we did this correctly, >A + >B +>C should equal 180 right? Damn straight. Lets first find what >A is equal to.\n                                 \n                                         >A= (3)>B + 20 \n                                        Substitute 32 for B...\n                                        >A= (3)(32) + 20\n                                         which means that \n                                          >A=116 !!!!!!!\n\nNow lets plug all the angles in. >A= 116, >B= 32, and >C=32\n\n                               Does 116 + 32 + 32 give you 180?\n\n     OMG IT DOES IT DOES IT DOES!!!! YES!!!! HAHA\n\n                                   Answer to your question:\n                                           >C= 32 degrees.\n\nHope I helped you ALOT hahahaha You're welcome. =D
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a compass tells you which way is north. once you know where north is you can tell in which directions south, east, and west is.
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Circles. You can inscribe an angle in a circle. Choose any point on the circle and let that be the vertex of your angle. Have the sides of the angle be chords of the circle. The degrees of arc subtended by the angle will be twice the number of degrees in the angle.\n\nAn inscribed angle of 90 degrees subtends a semi-circle.
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When we draw a circle with a compass, we keep the angle between the two legs constant.\n\nA ray from the top most point on the rainbow to our eye makes an angle to the horizontal direction. Theory says this angle is a constant.\n\nImagine the ray as one leg of long compass and the horizontal direction as another leg which points the center. Keeping the angle constant when the compass is rotated an arc is formed. \n\nIf we go high up we can see the whole circle.
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If you are talking about trisecting an angle using a compass and straight edge, then it is not and unsolved problem, it is problem for which there is no solution.\n\nThere is an area of abstract algebra called Galois theory. One of the things that you learn in Galois theory is that there exist certain angles that cannot be trisected using the kind of techniques that you would use to bisect an angle or line. Flat out can't be done. I recall, but don't quote me on this, that 60 degrees is one example.\n\nAnother thing that comes from Galois theory is that there is no formula, that will give you the roots of a 5th degree polynomial. You are probably familiar with the quadratic equation which gives you the roots of a second degree polynomial. There are formulas that you can use to get the roots of 3rd and 4th degree polynomials. But there can't be a formula that will work for a general 5th degree polynomial.\n\nI know more than one high school student who wasted a lot of time trying to devise a method for trisecting angles when he/she heard it was a great unsolved problem. Their teachers neglected to tell them that it was not only a great unsolved problem, but that it was a great unsolvable problem.
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Just draw a right triangle with short sides of 10 and 24.\n\nThe hypotenuse can be calculated by the Pythagorean theorem as the square root of 24^2 + 10^2.  That works out to 576 + 100 or 676.  The square root of 676 is 26.\n\nThe direction is roughly ENE (East North-East).
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Wallstream is correct -- start with a right triangle.\n\nLabel the interior angles a, b and c, with c being the 90-degree angle.\n\nNow notice that a and b are complementary angles that add up to 90-degrees.\n\nLet x = sina.  Since the angles are complementary, we also have that x = cosb.\n\nSo we can rewrite as follows:\n\nIf x = sina, then a = arcsinx\nIf x = cosb, then b = arccosx\n\nBut a+b = 90-degrees (aka pi/2).\n\nSo arcsinx + arccosx = pi/2\n\nHope that helped!
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Ive noticed you were asking quite alot of these geometry questions. I think you should pay more attention in class and you wouldnt need to ask home work questions, and plus, just knowing the answer wont help, youll have to know how to do it, especially if this is for a final exam...
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Yes. These are intriguing geometry problems. What is YOUR question? Be specific. Post ONE question and be specific about where you are stuck. Right now, this just looks like you want someone to DO your homework for you. But you wouldn't cheat on your homework like that, would you?\n\nHere's a hint -- supplemental angles add up to 180\n\nFor example, if one angle is 60 degrees, its supplement is 120
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well you can make a pretend display on a real compass, IE when its pointing north make the paper display say whatever direction you want, compasses work by pointing north  http://science.howstuffworks.com/compass1.htm
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Pick an angale, not the 90 degree angle and call it Theta.  The short side that forms this angle is called the x side of the triangle and the long side that forms this angle is the hypotenuse or 'r'.  The third side is called the opposite side or 'y'.\n\n\n.... /|\n..../.|\n.../..|\n../...|\n./....|\n/___|  Bottom is x, slanting side is r, and right side is \n          the y side.  The angle at the bottom left is Theta.\n\n\nSin(Theta) will = y/r\nCos(Theta) will = x/r\nand\nTan(Theta) will = y/x side.\n\nThis all presumes you don't already know 2 of the sides.  If you know 2 sides already, you use the pythagorean thm.\n\nExampe: Theta = 30 degrees, r = 10 feet, what are the others?\n\nSin(Theta) = y/r  and Sin(30 degrees) happens to be 1/2.\n\nso, 1/2 = y/10.  Solving for y you get y=5.
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If u r saying that u have three sides of a triangle as a,b,c\nAnd u want to determine angle b/w them, u can use the formula\ncosA=(b^2+c^2-a^2)/2bc where A is the angle formed by the sides b and c.similarly if B is the angle formed by a and c, it can be calculated as\ncosB=(a^2+c^2-b^2)/2ac\nonce u have calculated A and B, subtract their sum from 180, u will get third angle.\nRemember u will have to use inverse table for cos to find A and B
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First draw a circle w/ the centerpoint well defined (e.g. use a compass).  Then use a protractor, with the circle center at your protractor center, to create the angle you want.\n\nIf you want to divide the circle equally for 30 people, then you take 360 degree/30.  Then you need 30 angles of 12 degrees.  Create these w/ your protractor and extend to the circumference of the circle.\n\nKeep in mind, that spreadsheet programs like excel will let you form pie-charts, which are basically this same thing only done much easier.