you get $0.50 back from a 420 bill. How much change would you get from a $20 bill if you bought 3 slices of pizza and 5 burgers?
132162
The cost of 7 hamburgers and 3 slices of pizza would be\n20 - 1 = $19\nThe cost of 8 burgers and 2 slices of pizza would be\n20 - 0.5 = $19.50\nLet x = cost of a burger and y = cost of a slice of pizza\nThe first statement implies\n7x + 3y = 19\nThe second statement implies\n8x + 2y = 19.50\nNow solve these two equations either using substitution of elimination.\nAfter you solve for x and y, you will see that\nx = 2.05 for one burger and y = 1.55 for one slice of pizza\nThus, the cost of 5 burgers and 3 slices would be\n5(2.05) + 3(1.55) = $14.90\nYou paid with a $20, so the change would be\n20 - 14.90 = $5.10
612376
each person gets $1 back, so that means  25 + 3 = $28\nand the bellhop keeps $2, and thats $30
653972
It's D because $1.45 is very close to one-and-a-half.\nSo you could estimate by using $1.50 which is one and a  half.\ntimes the 5 cans of oil.  You will be off by only a quarter by doing this.
279453
Alvin pays 40% (4/10)\nBernie pays 33.333% (1/3) "His fair share"\n\nA = 4/10\nB = 1/3\nC = ?\n\nA + B + C = 1\n\n4/10 + 1/3 + C = 1\nC = 1 - 4/10 - 1/3\nC = 30/30 - 12/30 - 10/30\nC = 8/30\nC = 4/15\n\nIf the full price is x then:\n4/15 x = $2.40\nx = $2.40 * 15/4\nx = $0.60 * 15\nx = $9.00\n\nAlvin paid $3.60\nBernie paid $3.00\nCharlie paid $2.40\n\nThe pizza cost $9.00.
188323
This question is old. If the bill is $25 and they each paid $10 but the clerk returns $1 to each and the bellboy gets the $2 tip there is no lost dollar. It's all in the way the question is presented. \n\n$25/3 = $8.33 1/3 Or 2 people paid $8.33 and the final guy paid $8.34\n\nIn the question the cents get dropped making it seem as though they each paid an even $8 with an extra $1 back.\n\n$8 + $1 = $9. You can see the cents were dropped.\n\nThe other dollar is in the till where it belongs. The bill was $25 NOT $24\n\nEDIT: This is all a question of laziness. The clerk knew 3 guys split the bill. He should have sent up $1.67 cents each for 2 guys and $1.66 for the last. \n\n$1.67 + $1.67 + $1.66 = $5.00\n\nInstead he sent up 5 $1 bills. The guys were too lazy to work out who got what out of the final $2 after taking back a $1 bill each so they let the bellboy keep the $2. \n\n0.67 + 0.67 + 0.66 = $2.00 \n\nA cheap tip for the bellboy when you look at what each one tipped.\n\nTo sum this up\n\nGuy 1 paid\n\n$8.33 (room) + 0.67 (tip) + $1 (returned) = $10.00 \n\nGuy 2 paid\n\n$8.33 (room) + 0.67 (tip) + $1 (returned) = $10.00 \n\nGuy 3 paid\n\n$8.34 (room) + 0.66 (tip) + $1 (returned) = $10.00
163201
nothing...the person who wrote that just took the wrong approach to finding the answer.  the math was just done wrong...\n\n10x3=30 each guy pays 10\n30-3=27 each guy get back one dollar\n27-2=25 the bellman pockets two\nthere are $25 left\n\nin the problem when the counter man keeps two they add it rather than subtract it like they should have
62055
you collect 30.00 everyone takes1.00 back  =27.00\nrent is 25.00 ( that leaves 5.00 extra - 3.00 you already took back =  2.00 over
161846
ok. there are 3 guys who go on a road trip. they go into the hotel and its $30.00 even for the room. so each guy pays 10.00. (10 x 3 =30)\nwhile they are in the room the checkin girl realizes its only $25.00 for the room. so she grabs 5 one dollar bills and goes up to the room. she realizes that 5 does not divide by 3 evenly. so she taked $2.00 and puts them in her pocket. as she knocks at the door she feels guilty and pulls the $2.00 out of her pocket. they ended up giving her 2 dollars and kept 3. if each guy gets 1 dollar back then instead of 10 they paid 9 each for the room. ( $9 x 3 = 27)\n27 + 2 (tip they gave lady) = $29.00\n\nWHERES THE LAST DOLLAR??????????????
387764
Let # of students be s\n\nTherefore s = 2*(4/3*4* 15) = 160\n\nDetailed answer:\n\n15 = ¼ of students who bought pizza\nSo # of students who bought pizza = 4* 15 = 60\n60 = ¾ of students who bought lunch\nSo # of students who bought lunch = 60/¾ = 80\n80 = ½ of students in cafeteria\nSo # of students in cafeteria = 80/½ = 160
166913
there was total $30 in which you gave $3 and kept $2 to your self.so,the remaining $25 has to be split beetween the three so each dude gets $8.33.\nso the total would be\n9.33*3+2=30 dollars
154498
QUESTION 1) JOE'S INCOME\n\nJoe's income increased by 2,500\n\nYou can find the percentage change by using this sum ;\n\n(2,500 / 30,000) * 100\n\nANSWER = 8.33 %\n\n__________________________________________________________\n\n\nQUESTION 2) DISCOUNT\n\nThe amount of discount can be found using the following sum ;\n\n(5 / 100) * 205.5\n\nAMOUNT OF DISCOUNT = $10.275 = $10.28 (rounded to the nearest cent)\n\nSo, AMOUNT PAID AFTER DISCOUNT = ($205.50 - $10.28) = $195.22\n\n__________________________________________________________
399497
1) Percentage change = [(new price - old price) / old price] x 100\nso: \n[($58.56 - $48) / $48] x 100 = 22%\n\n2) \na + b = 73 \nwhere a = number of dimes\nwhere b = number of quarters\n[ie. some number of dimes plus some number of quarters equals 73 coins]\n\nFirst, write it in terms of dollar value.\n($0.10 x a) + ($0.25 x b) = $13\n[this means: some number of dimes multiplied by their dollar value, plus some number of quarters multiplied by their dollar value, equals $13]\n\nRemember that "a + b = 73"?\nIt can be written as "a = 73 - b"\n\nPut this relationship into: ($0.10 x a) + ($0.25 x b) = $13\n($0.10 x [73 - b]) + ($0.25 x b) = $13\n\nWhich gives:\n$7.3 - 0.1b + 0.25b = $13\n\nOrganise the "b"s into one side, the integers into the other:\n0.15b = 5.7\nb = 38\n\nThis means you need 38 quarters.\n\nSince you had a total of 73 coins to play with, and 38 are already known to be quarters, 35 must be dimes.
542656
B -- it;s the only one that adds up to $3 and fits the criteria of the problem \nWork backwards to solve it\na = $3.50\nb = $3.00 - 9 is is more than 3 and 3 is 1/2 of 6\nc = $2.50
138677
The trick is how the question is asked. However if you look at it objectively, the three men spent a total of Rs. 270 which includes the Rs. 20 that the waiter kept for himself. So the total is 250 (restaurant bill) + 20 (waiter) + 30 (money that they got back). \nThe question has been asked in such a way so as to trick the reader. You don't have to add the 20 to 270 because the 20 is already included in 270.
673179
The only problem with the math is that you don't ADD the two dollar tip to the $27; it's already included.  Remember, the $25 room charge plus the $2 tip gives the $27 total payment; the $3 change makes up the rest of the original $30.
246193
Ok so let's try this:\n\nGuy 1, Guy 2, Guy 3 each pay $15 so:\nGuy 1 = $15\nGuy 2 = $15\nGuy 3 = $15\n\nManager says "$5 too much" and sends the change back ($5) but neither 40 nor 5 divides by 3 into a integer so with an honest waitress the money situation could go like this:\n\nGuy 1 gets back $1, Guy 2 gets back $2, Guy 3 gets $2 and all three get an explanation that $5 doesn't split evenly, sorry. So prior to our waitress taking the $2 you have:\n\nGuy 1 = $15 - $1 = $14\nGuy 2 = $15 - $2 = $13\nGuy 3 = $15 - $2 = $13\ntherefore: $14 + $13 + $13 = $40\n\nOur waitress reasons that our guys want to have spent the same amount of money so she takes a $ each from Guy 2 and Guy 3 to even it out and she takes an extra dollar otherwise she gives back Guy 1 his whole $15 back and Guys 2 and 3 are upset:\n\nGuy 1 = $14\nGuy 2 = $13 + $1 = $14\nGuy 3 = $13 + $1 = $14\ntherefore all three guys have paid $14 each = 3 x $14 = $42\nShe keeps the extra $1 to keep it fair (all guys paid $14)
418407
You have to bear in mind that the drinks were not actually $27 dollars, it was $25.  Just because you gave them a dollar each back, they ASSUMED it was $27.\nEven though they had paid $27, you still had to pay their bill of $25 which would leave you the $2.....\nthe missing $1, is therefore, not a missing dollar....!