Hi I need help with my Homework.. I already did these.. just making sure their correct, thank you:\n\n6) Divide. Simplify if possible:15x^3/y^6/3x^y^6/7\n\n7) Divide. Simplify if possible: 1/-x-5/8x^2-64x/x^2-3x-40
137204
hmmm...\nhave fun with that
14593
(x-2)/(x^2-2x-15)+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(-2-x)(x+3)/(x-5)(x+3)\n\n[(x-2) + (x+3)(-2-x)] / [(x+3)(x-5)]\n\nANSWER :\n(x^2+4x+8)/((x+3)(5-x))
27051
1) yes, this is correct as written.  Not sure what else you need? \n2) 10/14?\n3) 2 (1 is not a factor)\n4) -6(x+1)\n5) 5 1/4 or 21/4 (same thing)\n6) 1 4/9
333654
4 x (7 - 6) / 3 = 4/3\n9 - (38 / (7 + 12)) = 7\n2 5/8 - (3 / (4 - 1)) + 1 / 2 = 2 1/8\n6 + (15 / 3) - (2 x 5) = 1\n18 / (9 - 6) + 8 = 14 \nMath Rulez!!!!
500752
You end up with a remainder, so it's not pretty, but you should be able to do long division and get:\n\n3x^2 - 4x + (16/3) - 23/(3*(3x+2))
479739
1. b^2 -ab -6a^2\n(b-3a)(b+2a)\n\n2. 3(x-2)^2-3(x-2)-6\n3(x^2-4x+4)-3x+6-6\nx^2-4x+4-x\nx^2-5x+4\n(x-4)(x-1)\n\n3. 6x^2 +7x +2\n(2x+1)(3x+2)\n\n4. y^3 -12y^2 +36y\ny(y^2-12y+36)\ny(y-6)^2\n\n5. 9x(x-7y) -6(x-7y)\n9x^2-63xy-6x+42y\n3(3x^2-21xy-2x+14y)\n\n6. 6z^3 -27z^2 +12z\n3z(2z^2-9z+4)\n3z(2z-1)(z-4)\n\n7. 6x^2 - xy -5y^2\n(6x+5y)(x-y)\n\nThe things we go through for our kids!
183477
Use remainder theorem and polynomial division for the first one and then either the quadratic formula or, if you know your maths, logics. Just plot the second one in a graph and you'll see the answer. The next few lines I just don't understand what you are writing, perhaps if you wrote it more clearly. As for the simplify bits, you don't really need help there, it's a matter of seeing how you can create similar terms. The last bit, once again, I do not know what you mean. \n\nEdit: corrected some spelling mistakes (it's quite late over here).
97551
I'd start by pairing them up a bit to simplify common denominators.\n0/1 = 0\n1/2+3/4+7/8 = 4/8+6/8+7/8 = 17/8\n2/3+5/6+8/9 = 12/18+15/18+16/18 = 43/18\n4/5+6/7 = 28/35+30/35 = 58/35\n\nNow there's only 3 fractions, 58/35+43/18+17/8.  Time to find the grand common denominator.  I'm using underscores to indent since spaces get stripped out.\n_35\nx18\n- - -\n280\n35\n- - -\n630\n\n_630\nx__8\n- - - -\n5040\n\nBut since 2 will go into 630 and 8, we can reduce that by half, 2520.\nNow, find the multipliers we want through long division to use against the numerators.\n\n_____72\n35 | 2520\n___245\n___- - -\n____070\n_____70\n_____- -\n______0\n\n\n____140\n18 | 2520\n___18\n___- -\n___072\n____72\n____- -\n____000...\n\nThis is too tedious after all.  Guess I'll keep going, but I'm going to use my calculator a little, now.\n\n2520/35=72\n2520/18=140\n2520/8=315\n\n58/35+43/18+17/8 =\n4176/2520+6020/2520+5355/2520 =\n15551/2520\n\nAnd that's my final answer.  What do I win?
410584
for the first type of problem--60% of ? =45, you take 60% (which is the same as .6) and make the ? an x.  Of always means multiply, so it becomes .6x=45.  simply divide both sides by .6 and x=75. \n\nFor the second type--what % of 90 is 63, you just set it up the same way.  90X=45.  divide by 90 and you get .5 or 50%\n\nThe final type--39% of 1500, you simply multiply .39 by 1500 to get 585\n\nNow that you know how to do each type of problem, simply plug the right numbers into the equations and finish your homework.  Good luck.
216609
Remember Order of Operations - in this case, Parenthesis, then Add/Subtract.\n\n1.) First, we do the parenthesis:\n3x-5(3x-7)=2(x+9)+45\n3x-(15x-35)=(2x+18)+45\n\n2.) Next, we add/subtract from the parenthesis:\n3x-(15x-35)=(2x+18)+45\n-12x + 35 = 2x + 63\n\n3.) Then, we solve by subtraction and division:\n-12x + 35 = 2x + 63\n-12x - 2x = 63 - 35\n-14x = 28\nx = -2\n\nCheck:\n3(-2) - 5(3(-2)-7) = 2(-2+9)+45\n-6 - 5(-6-7) = 2(7) + 45\n-6 + 65 = 14 + 45\n59 = 59
524185
[(7x^3)(-x^7)]/14x^4\n= (-7x^10)/14x^4\n= -x^6/2
540396
I just typed this all out and then lost it. Here I go again.\n\nfirst I would multiply both sides by -1/3 because i want to get rid of the neg and i know 3 goes into 18 and 3 and I want to work with smaller numbers.Also factor the denominator.\n\ny/(y+2)= 6/(y+2)(y-5)   Now mult. by the LCD (y+2)(y+5)\n\ny(y+5)=6   remove () and sub 6\n\ny^2+5x-6=0  factor\n(y+1)(y-6)=0  set each factor =0\ny+1=0  or  y-6=0  solve\ny=-1  or  y=6\n\nalways remember to check your answers in teh original denominators to make sue you won't get zero.
359788
Are you certain the denominator isn't:\n\nx^6 - 6x^5 + 15x^4 - 20x^3 + 15x^2 - 6x +1 ?\n\nBecause that denominator has a very simple factorization: (x-1)^6. Whereas the polynomial you actually gave for the denominator doesn't have any factors I'd be inclined to call simple, and I'll bet even money that there's no way of expressing them using any finite sequence of elementary operations and nth roots. I think you should double-check your input.\n\nEdit: well, it's a very good thing nobody took me up on that bet - it seems I am completely wrong. See the question at http://answers.yahoo.com/question/index;_ylt=Aqz3W3s3NPcz.j__CQYxK0bsy6IX?qid=20061127003230AA2oHuA\n\nI will give a summary here:\n\nAs mentioned, (x-1)^6 = x^6 - 6x^5 + 15x^4 - 20x^3 + 15x^2 - 6x +1. So logically (assuming that really isn't a typo), your original denominator is (x-1)^6 - 10x^3. We need to find the roots of this equation, so set:\n\n(x-1)^6 - 10x^3 = 0\n(x-1)^6 - 10√x^6 = 0\nSince x=0 is not a solution, we may divide by √x^6. so:\n(√x-1/√x)^6 - 10 = 0\n\nLet t=√x-1/√x. Then this polynomial is:\n\nt^6-10=0\n\nThe solutions of this polynomial are precisely the complex sixth roots of 10, which are:\n\nt=√(∛(10))\nt=√(∛(10)) * (1/2 + i√3/2)\nt=√(∛(10)) * (-1/2 + i√3/2)\nt=-√(∛(10))\nt=√(∛(10)) * (-1/2 - i√3/2)\nt=√(∛(10)) * (-1/2 + i√3/2)\n\nWe now set √x-1/√x equal to each of these roots in turn. In so doing, we find the possible roots of x. Let u=√x. Then:\n\nu-1/u=t\nu²-tu-1=0\nu = (t±√(t²+4))/2\nx = u² = (t² ± t√(t²+4) + 2)/2\n\nx=(∛10 ± √(∛100+4∛10) + 2)/2\n\nx=(∛10 * (-1/2 + i√3/2) ± √(∛(10)) * (1/2 + i√3/2)√(∛10 * (-1/2 + i√3/2) + 4) + 2)/2 \n= (∛10 * (-1/2 + i√3/2) ± √(∛100 * (-1/2 - i√3/2) + 4∛10 * (-1/2 + i√3/2)) + 2)/2 \n= (∛10 * (-1/2 + i√3/2) ± √(-(∛100 + 4∛10)/2 + (4∛10 - ∛100)i√3/2) + 2)/2\n\nx=(∛10 * (-1/2 - i√3/2) ± √(∛(10)) * (-1/2 + i√3/2)√(∛10 * (-1/2 - i√3/2) + 4) + 2)/2 \n= (∛10 * (-1/2 - i√3/2) ± √(∛100 * (-1/2 + i√3/2) + 4∛10 * (-1/2 - i√3/2)) + 2)/2 \n= (∛10 * (-1/2 - i√3/2) ± √(-(∛100 + 4∛10)/2 + (∛100 - 4∛10)i√3/2) + 2)/2\n\nThus the factors of the denominator are:\n\n(x - (∛10 + √(∛100+4∛10) + 2)/2) * (x - (∛10 - √(∛100+4∛10) + 2)/2) * (x - (∛10 * (-1/2 + i√3/2) + √(-(∛100 + 4∛10)/2 + (4∛10 - ∛100)i√3/2) + 2)/2) * (x - (∛10 * (-1/2 + i√3/2) - √(-(∛100 + 4∛10)/2 + (4∛10 - ∛100)i√3/2) + 2)/2) * (x - (∛10 * (-1/2 - i√3/2) + √(-(∛100 + 4∛10)/2 + (∛100 - 4∛10)i√3/2) + 2)/2) * (x - (∛10 * (-1/2 - i√3/2) - √(-(∛100 + 4∛10)/2 + (∛100 - 4∛10)i√3/2) + 2)/2).\n\nAnd yes, that is one ugly polynomial.
263621
u jammed the equation together.\ndo u mean\n6x^3 + ( 6/x - 2 * x^2 - x/3x2 - 3x + 3)\nits really hard to see ur question. can u write it out with spaces...\nhurry up i am waiting... lol
361232
I think it is this:\n\nFirst multiply through the groups..\nso you get:\n6n^7-4n^6-16+4n^6+2n^7+15\n\nThen gather like terms\n\n=8n^7-1\n\n(The -4n^6 and the +4n^6 cancel each other out)\n\nI don't think you can go further than that.\n\nGood luck.
526134
You can do this using "synthetic division"\n....... ______________________\nx - 5 ) x^4 - 0x^3 - 3x^2 + 0x + 6\n\nI'm going to simplify this leaving out the x-terms and only showing the coefficients, but just imagine they are there:\n\n.............. 1 . 5 .22 110\n1 -5 ) 1 . 0 .-3 . 0 . 6\n......... 1. -5\n......... ------\n.............. 5 .-3\n.............. 5 -25\n.............. -------\n................... 22. 0\n....... ........... 22 -110\n....... ............----------\n....... ........ ........ 110  6\n....... ........ ........ 110 -550\n....... ........ ........ ------------\n....... ........ ........ ....... 556\n\nSo if I did it correctly the answer should be:\n1 5 22 110 remainder 556\n\nThis equates to:\n(x^3 + 5x^2 + 22x + 110) + 556/(x-5)
483760
Wow, there is a lot here!  I'll start with some tips for solving algebra problems.  The first thing you should always remember is to play the equal game.  Whenever you add, subtract, multiply, or divide, you should do the same to the other side.  The other tip is to use the order of operations when simplifying.  Remember the sentence: Please excuse my dear Aunt Sally.  The initial letters of each word stands for the order of operations.  Do the Parenthesis first, followed by the Exponents, then Multiplication or Division, and Addition and/or subtraction next.  Finally, you should always simplify first using the order of operations before you start shifting numbers from one side of the = to the other.  \n\nI'm not going to work all of these problems, but I'll show you a few to get you started.\n\n1)\n3x-7 = 2   Add 7 to both sides\n3x = 9   Divide by 3\nx = 3\n\n4)\n6x - 3 = 2x - (4-3)/3   Simplify the stuff inside the parenthesis first\n6x - 3 = 2x - 1/3  Add 3 to both sides\n6x = 2x - 5/3  Subtract 2x from both sides\n4x = -5/3  Multiply both sides by 3\n12x = -5  Divide both sides by 12\nx = -12/5\n\nI hope this helps.  Good luck!