3 Soldiers decide to check into a hotel for the night. Instead of purchasing 3 rooms, the soldiers decide to pitch in $5 a piece and just get one instead.  After paying and walking to the room, the Manager of the Hotel realizes that since they're soldiers, they get a discount and one room is only 10 dollars.  So, the Manager tells the bell boy to return 5 dollars back.  Once the bell boy reaches the hotel door, he realizes that 5 dollars cannot be split into 3 evenly, so he decided to keep 2 and then each soldier will get 1 dollar back...thus 2 to the bell boy...and 3 for the soldiers. So, if each soldier only had to pay 4 dollars instead of 5, that would make 12. 12 dollars that the soldiers paid total, and the 2 that the bell boy kept only equals 14...what happened to the other dollar?  :-)
135128
This is not really a Math question. It's more of a logic question. Think of it this way: The three soldiers had given out 15 dollars. The manager kept 10 dollars, the bell boy kept 2 dollars, and the soldiers got 3 dollars back. Nothing is missing.\n\nThe way in which the question counts the total number of dollars is wrong. Yes, each soldiers only had to pay $4. That's a total of $12. Think about it. These $12 included the $2 that's secretly kept by the bell boy already (Again, $10 to the manager/hotel, $2 to the bell boy). Why count that again? The question is trying to fool you.\n\nThe correct way to count is: 15 dollars were circulating in this whole story. The soldiers paid out $12 and got $3 back. See? There's no missing dollar!\n\nIf you're still a little confused, draw a diagram. It helps.
603554
Your math is cheating.  =0)\n\nThe room didn’t cost 27, it cost 25 – although they paid 27 for it.\nBecause the bell boy took the extra 2.\nSo\n$25 to hotel\n$3 to the guys\n$2 to the bell boy.\n=\n$30\n\n(but I do love to see how people’s minds work.)
264506
The flaw is in adding that 20.\nEach boy spent 90.\n90*3 = 270 of which 20 was pocketed by the son.\nIf you want how 300 was distributed then think like this\nActual cost was Cost of pen + 20 pocketed by son =270\nOf the original 300 only 30 was returned therefore 270+30=300\nThe point is either you do per boy calculation or for the whole group don't mix them and if you do mix then be cautious.\nFinally we conclude\n90+90+90 is the actual sum spent by boys whcih includes that 20 so don't add it again.
198054
Nothing is lost. Their contribution is 47$ (23.5 $ each). This sum includes the 2$ for the cab, so the 2$ should not be added again to get the 49 sum.\n\n25$   25$\n---------\n1.5   1.5.......back\n1     1.........cab\n22.5  22.5......pen cost\n---------\n25$   25$\n\n=>Each paid 23.5$, the shop received 45 (22.5 from each), and the cab received 2$(1 from each).
208325
the other dollar is in your pocket.... you spent $97 dollars and had 3 dollars change... you payed back $2. of the $100.  you spent $97..... no matter how you look at it you had $3. and if you payed back 2 of the $3. the other Dollar is in your pocket.  the equation is 100. - 97 = 3 then 3 - 2 = 1 the dollar is in your pocket
580285
The total cost of the room was not 30 dollars.  Its 25 dollars because they overcharged them (30-5)=25 dollars was the cost of the room.  Since the clerk kept 2 dollars of it the total cost of the room is 27 dollars.  This works out since each man put in 10 and was refunded 1 dollar each paid $9 and all three 9 x 3 = 27 dollars.  So the problem with this brain teaser is that the total cost was not $30 and that extra dollar did not magically disappear.  The actually total cost of the room was $27 (25 + 2 dollar clerk's cut).
436020
she had with her $165.74\nshe spent $16.59+$63.99\nbakance she had=$165.74-(16.59+63.99)\nno of jeans she bought @ $21.29\n=165.74-(16.59+63.99)/21.29\n=4
245759
let us take each lobe as 3kgs(assumption) then they will have 24kgs of lobe. that is each get 8 kgs...so the person with  3 lobes will have 9kgs and other 15kgs. so 3 lobe will give 1 kg to the hunter and 5 lobe fellow will give 7kg to the hunter. so if each kg costs 1 bronze coin.they will divide 1:7. Are you clear?\n\nBut i missed all your other questions gal!!!!!!!! waht you have done...explaining this i missed all other questions.\n\nis the previous one right?\n\nBut i wont be the first to answer them.....
596942
There's nothing left over.\n\nIf they each paid $10, then that's $30 all together.\nThe room costs $25, so they get $5 back.\nThey give the bell hop $2, which leaves them with $3, and when each of them gets $1, the remainder is 0.
389053
1st Problem:\n\nLet's see, if we sell 198 thousand candy bars, we are giving them away, which is terrific for volume, but bad for profit.    \n\nRevenue = x P(x), = 9x-(x^2/22)  differentiate to get 9-(2x/22) so x/11=9 x=99\n\nPrice would be  4.50
242636
It didn't go anywhere.  \n\nThey each paid $10 to begin with- that's $30\n\n$25 to the hotel\n\n$2 to the bellhop\n\nthat's $27- which leaves $3 left over as a refund to the original three.\n\nThe questions is misleading becuase you add the $2 instead of substracting it.
625528
Okay, I think this is what you're asking: suppose merchant A sells 2 bananas for $5 and merchant B sells 3 bananas for $5. Then one of the merchants gets sick and the other switches to selling 5 bananas for $10, will the other mechant make more or less oney than if he had sold at his original price?\n\nIf merchant A sells at 5 for $10, he will lose money.\nIf merchant B sells at 5 for $10, he will gain money.\n\nJust compute the amount each merchant makes per banana - Merchant A makes $2.50/banana and merchant B makes $1.67/banana (rounded to nearest cent). If they sell 5 for $10, they would make $2/banana.
439972
a) 4 is in the tens place, so it is worth 4 * 10 = 40\nb) 6 is in the ones place, so it is worth 6 * 1 = 6\nc) 3 is in the thousands place, so it is worth 3 * 1000 = 3000\nd) first 2 is in the hundreds place, so it is worth 2 * 100 = 200\ne) 7 is in the hundreds place, so it is worth 7 * 100 = 700\n\nOr you can just say the numbers and see what you say when you are on the underlined number...\n\n42 = "forty two" so 4 is "forty"\n176 = "one hundred seventy six" so 6 is "six"\n3049 = "three thousand forty nine" so 3 is "three thousand"\n1223 = "one thousand two hundred twenty three" so first 2 is "two hundred"\n10731 = "ten thousand seven hundred thirty one" so 7 is "seven hundred"
356880
Well you got a quarter and a nickel.  Because one of the coins is not a nickel, it is a quarter.  So the other one is a nickel.  Hehehe.... Good one.
130659
it doesnt matter how much a b and c "spent". they all gave d ten dollars. that equals 30 dollars. person d spends 25 dollars. then he gives 1 dollar back to a b and c. a b and c all have 1 dollar, which equalls 3 total $. person d has $25, plus the 2 he has left=$27, plus the three owned by a b and c=$30.
669740
she took the deal at 196,000.  \n\nthen Howie asked her which case would she have opened next, she picked 21, which had 400.00, so the money would have went up to 296,000.  \n\nthen she picked 13, which had 1.00 so the money would have went up to 419,000.  \n\nthen that left the last case and hers.  Hers had the 750,000. and the last one, on stage had 1 penny. \n\nBut, she walked away with a lot more money than she had at the start. \n\nWhat a good game!!  \n\n:-)
646660
You are adding the bellboy when he should be subtracted.  $27 -$2 = $25, which is what the room cost.  Since the room cost only $25, each man should get ~$1.66 back, but the bellboy robs them of $.33 each.  The total should be the cost of the room, which is $25, not $30.\n\nYes it is a riddle.  The trick is in telling the person that it adds to $29.  Without that, most people would probably just figure out that they had to subtract the $2, not add.