without using dataset or datagrid...\npls help... i really need it...\nthanks
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Yes you can. ASP.NET has a lot of library, and one of them is the API to deal with creation/manipulation.\nThis link might help you: http://www.w3schools.com/aspnet/aspnet_xml.asp
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MapInfo Professional will do it, but it's rather expensive.\n\nESRI is even better - but even more expensive.\n\nGood luck...
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hi\ntry this code by putting it into datagrid event\ntextbox txt=new textbox();\ntxt=(textbox)e.item.cell["YourCellNoWhereTextBoxIsPlaced"].controls[0];\n\nthis way u can get the whole textbox binded in the datagrid.\n\nfor any problem you can contact me at vishalsharma556@yahoo.co.in\n\n\nand for your better information this is not the better place to ask this type of questions.go to relatice sites.\n\nregards \nvishal
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U need to call a datagrid.Update after it is deleted out of hte Grid. Or you need to re-fill the grid after u run the sqlcommand.\n\nI presonaly would create the application/webapp using the ADO.NET disconnected feature. I would create an dataset, datatable and fill the datagrid using a SqlDataAdapter. Then all you need to do is call "SqlDataAdapter.Fill" to update the Grid and to delete all you have to do is delete a row (via GUI and programaticly) and call "SqlDataAdapter.Update" to delete out of the database.\n\nEnjoy -
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You can use the GridView control, implement a templatefield column and inside of that have a new SqlDataSource and GridView control.  Note, that SqlDataSource aren't data binding friendly hense the ugly binding w/ old school DataBinder calls. Psuedo code below. (Yahoo answers hates my code blocks, but you should be able to gather a solution from it).\n\n<asp:GridView id="SomeGridView" runat="server" DataSourceId="CustomersDataSource">\n<Columns><asp:TemplateField><ItemTemplate>\n\nCurrent Customer : <%# Eval("CustomerName") %><br>\n\n<asp:GridView id="CustomerProductsGridView" runat="server" DataSourceId="CustomerProductsDataSource"><Columns>(omitted for example)</Columns></asp:GridView">\n\n<asp:SqlDataSource id="CustomerProductsDataSource" SelectCommand='<%# "select * from Products where CustomerId= " + DataBinder.Eval(Container.DataItem, "CustomerId") %>'></asp:SqlDataSource>\n\n</ItemTemplate></asp:TemplateField></Columns>\n</asp:GridView>\n\n<asp:SqlDataSource id="CustomerDataSource" SelectCommand="select * from Customers"></asp:SqlDataSource>
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A data bound list control that displays the items from data source in a table. The DataGrid control allows you to select, sort, and edit these items.\n\nFor a list of all members of this type, see DataGrid Members.\n\nSystem.Object\n   System.Web.UI.Control\n      System.Web.UI.WebControls.WebControl\n         System.Web.UI.WebControls.BaseDataList\n            System.Web.UI.WebControls.DataGrid\n\n[Visual Basic]\nPublic Class DataGrid\n   Inherits BaseDataList\n   Implements INamingContainer\n[C#]\npublic class DataGrid : BaseDataList, INamingContainer\n[C++]\npublic __gc class DataGrid : public BaseDataList, INamingContainer\n[JScript]\npublic class DataGrid extends BaseDataList implements\n   INamingContainer\nThread Safety\nAny public static (Shared in Visual Basic) members of this type are thread safe. Any instance members are not guaranteed to be thread safe.\n\nRemarks\nUse the DataGrid control to display the fields of a data source as columns in a table. Each row in the DataGrid control represents a record in the data source. The DataGrid control supports selection, editing, deleting, paging, and sorting.\n\nDifferent column types determine the behavior of the columns in the control. The following table lists the different column types that can be used.\n\nColumn Type Description \nBoundColumn  Displays a column bound to a field in a data source. It displays each item in the field as text. This is the default column type of the DataGrid control. \nButtonColumn  Displays a command button for each item in the column. This allows you to create a column of custom button controls, such as Add or Remove buttons. \nEditCommandColumn  Displays a column that contains editing commands for each item in the column. \nHyperLinkColumn  Displays the contents of each item in the column as a hyperlink. The contents of the column can be bound to a field in a data source or static text. \nTemplateColumn  Displays each item in the column following a specified template. This allows you to provide custom controls in the column. \n\nBy default, the AutoGenerateColumns property is set to true, which creates a BoundColumn object for each field in the data source. Each field is then rendered as a column in the DataGrid control in the order that each field appears in the data source.\n\nYou can also manually control which columns appear in the DataGrid control by setting the AutoGenerateColumns property to false and then listing the columns that you want to include between the opening and closing <Columns> tags. The columns specified are added to the Columns collection in the order listed. This allows you to programmatically control the columns in the DataGrid control.\n\nNote   The order that the columns are displayed in the DataGrid control is controlled by the order that the columns appear in the Columns collection. Although you can programmatically change the order of the columns by manipulating the Columns collection, it is easier to list the columns in the desired display order.\nExplicitly declared columns can be displayed in conjunction with automatically generated columns. When using both, explicitly declared columns will be rendered first, followed by the automatically generated columns.\n\nNote   Automatically generated columns are not added to the Columns collection.\nThe appearance of the DataGrid control may be customized by setting the style properties for the different parts of the control. The following table lists the different style properties.\n\nStyle Property Description \nAlternatingItemStyle  Specifies the style for alternating items in the DataGrid control. \nEditItemStyle  Specifies the style for the item being edited in the DataGrid control. \nFooterStyle  Specifies the style for the footer section in the DataGrid control. \nHeaderStyle  Specifies the style for the header section in the DataGrid control. \nItemStyle  Specifies the style for the items in the DataGrid control. \nPagerStyle  Specifies the style for
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http://www.smartcomputing.com/Editorial/article.asp?article=articles/2004/w1510/12w02/12w02.asp&guid
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Use a flat database file format. One unique value in one column and the rest is employee data. All the data in a contiguous range. This way you can use pivot tables, auto filters, etc. to analyze data.\n\nI would suggest you use the latest version of Excel. Excel 2000 has a limit of 65,536 rows and 256 columns but Excel 2006 (out later this year...MAYBE) has 1,000,000 rows and 16,0000 columns.
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check out http://www.pscode.com for examples.  You would need to use ADO.NET in addition to VB.NET in order to obtain the required data.
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Try this link\n\nhttp://www.google.co.uk/search?hl=en&q=flexgrid+control+in+asp.net.+If+i+use+rows+property+for+flexgrid+control+%2C+it+is+giving+error.+Why&btnG=Search&meta=
188138
UML is suited and u can effectively use microsoft visio.net for it :)
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try\nreformelections.org
378167
Try using the chart wizard.  Under Insert, select chart.
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If you need to persist data across several different applications, I would suggest persisting the information to the database in the form of a profile. I believe that 2.0 offers this type of functionality almost out of the box.\n\nYou might want to google for .net profiles:\nhttp://www.google.com/search?hl=en&q=.net+2.0+profiles
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that can be done with dreamweaver, but there's also another alternative, maybe you can try visiting this site\n\nwww.dynamicdrive.com
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Your probably would have to have SQL, but even that would not be enough. You'd need a log viewer as well.
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I'm not exactly clear on what you're trying to do with the second button, but if you're binding the datagrid from a query, you should be able to set the DataKeyField property of the datagrid to the primary key of your query.  It will then automatically be stored for each row when the datagrid is bound.\n\nYou can then retrieve it by using a line like:\n\n            Dim PID As Integer = Val(source.datakeys(e.Item.ItemIndex))\n\nIf this doesn't help, contact me with the exact error message you're receiving and with more info about what you are using the second button for, and I'll try to help.\n\n- Rich\nhttp://www.IMAgolfer.com