identify the effect upon temperature, pressure, density with changing altitude....need graphs and tables too
131522
ISA = Instrument Society of America
92784
This is a lengthy question.\nIt may be an assignment for your weite up.\n\nThere are innumberable factors to affect technology.\n\nThe density and pressure have helped in developing chemistry towards production of new chemicals, mettelery in terms of alloying and joining through various techniques including bolts, aerodynamics in terms of pressure, density and weight, and many more.\n\nYou need to study various books so that you can get the answer. This media is perhaps very small.
373414
So lets roll...\n\nmathematically, set it up as follows:\n\nLet x = the number of kg of water @ 82degC that must be added\n\nEnergy = m * c * T\n(m = mass, c = specific heat of water, T = tempearature)\n\nNeglecting convective and radiation heat losses:\n\n (x kg)*c*(82 C) + (0.2kg)*c*(14 C) = (x + 0.2 kg) *c*(36 C)\n\ndividing by c and re-arranging:\n\n82x + 2.8 = 36x + 7.2\n\nx = 0.096 kg
485681
Try a histogram and use a range of temperatures.
181125
The following link is a pdf slide show that gives examples of buoyancy calculations and theory of floating objects.\n\nhttp://www.colorado.edu/physics/phys1010/phys1010_fa05/lectures/class12-09-29.pdf
184833
R is the gas constant (= 8.31 J/mol*K).  The value should be with the list of constants in your book.\n\nOk Nic, you seem to be a bit confused on this issue so lets go back and start from scratch.\n\nFirst you obtained you values for T and K (experimentally or otherwise).  MAKE SURE YOU CONVERT YOUR TEMP VALUES TO KELVIN.  It's important for the units of the constant (R) are in Kelvin.  So then you calculate 1/T and lnK and plot the values for each set to generate your graph.\n\nYou calculate slope by taking two of your points (x1,y1) and (x2,y2).  From the data you added, let's say we'll use your first (0.002976, -3.079) and last points (0.003165, -4.225).\n\nslope= [-4.225- (-3.079)]/[0.003165-0.002976]= -6063.49 kelvin\n\nSince slope = -delta H/R\nThen -delta H = slope * R\nSo -delta H = -6063.49kelvin * 8.31 J/molkelvin\nAnd -delta H= -50387.62 J/mol\nRemoving the negatives from both sides\nDelta H= 50387.62 J/mol\n\nFor the second part of the question, use one (x,y) experimental point to find the y-intercept.  They don't want you to determine it from your plot, they want you to calculate the exact value.\n\nThe equation of a line is y=mx+b where "m" is the slope and "b" is the intercept.  So take another experimental point from readings (ie 0.003012, -3.751) and calculate the intercept by using the slope value calculated above.\n\nIf y=mx+b, then b= y-mx\nPlugging in the values\nb= -3.751 - (-6063.49kelvin * 0.003012/kelvin)\nb= -3.751 - (-18.26)\nb= 14.51\n\nTo calculate delta S for that same point (for that's what is requested), first you have to calculate delta G for that point.  Use the  following equation;\n\ndelta G = -RTlnK\n\nYou know the value for R (8.31 J/molkelvin), and you have the temp value and lnK value for that point for it was expermientally determined\n\n1/T= 0.003012/kelvin so T=332.01 kelvin\nlnK= -3.751\n\nSo delta G= -8.31 J/molkelvin * 332.01 kelvin * -3.751\nand delta G = 10349.02 J/mol\n\nYou can then calculate delta S for\nintercept = delta S/ delta G (given in your original data)\n\nTherefore delta S = intercept * delta G\nSo delta S = 14.51 * 10349.02 J/mol = 150164.28 J/mol\n\nHope this clarifies things.
249323
PV=nRT\n\nas the air is heated the average kinetic energy of the molecules increases. ie P increases.But V is constant. so some gas molecules escape through the bottom. Hence the density decreases and becomes lesss than that of surrounding air.Thus the balloon rises.
350653
Multiple NASA web sites have the info that you seek.\nGood luck with your project and let me know how it turns out?
166112
This website does all the work.  Just put in the values!  Good luck.  http://www.onlineconversion.com/temperature.htm
467770
You will find all details with calculation and experiment on:\nhttp://www.jgp.org/cgi/reprint/1/4/387.pdf
110180
for every 167 meter increase in the first layer of the atmosphere there is one degree Celsius decrease in temperature.If you get the temperature of the gas,in this case atmosphere, you can calculate the pressure by using the ideal gas law equation.
359737
I am assuming that the values of H° and G° are the standard enthalpy and Gibbs free energy changes for the formation of phsogene from CO(g) and Cl2(g).\n\nFor part (a), you should already know that:\n\ndelta-G = delta-H - T*delta-S\n\nSo, for the values you are given for 298 K,\n\n-206 kJ/mol = -220 kJ/mol - 298 K * delta-S°\n-46.98 J/(mol*K) = delta-S°\n\nFor part (b), we now have (assuming delta-H and delta-S are independent of temperature) that \n\ndelta-G_601K = -220kJ/mol - 601 K * (-4.698*10^-02 kJ/mol*K)\ndelta-G_601K = -191.8 kJ/mol
459739
weight (second order effects), roughness, types of materials, speed (second order effects), moisture content (humidity. affects materials such as wood), temperature (ie hot rubber sticks). if the object is moving fast, then aerodynamics can actually effect it by forcing air into the area of contact for example (eg hydroplaning on wet road where water gets between rubber and the road).
62777
Here is a tutorial...you can change any of the parameters that you mentioned and look at the graph as it is made and changed...really cool if you ask me.\nhttp://www.analyzemath.com/logfunction/logfunction.html
230305
The approximate variation in pressure with altitude is given by:\n\nP(h) = 10^(5-h/15500), where h is given in meters, and the pressure is expressed in Pascals.  (1 atm = 1.013 x 10^5 pascals).\n\nTo find the fractional change in pressure, calculate:\n\n[P(35) - P(0)]/P(0) = -5.19*10^-3.  The pressure would decrease by ~0.52%
539294
1 expansion\n2 contraction\n3 boiling point\n4 melting\n5 compression\n6 vaporisation...;
381910
Just use the formula\n\nE = m*Cp*(Delta T)\n\nE=energy\nm=mass\nCp= Specific Heat\nDelta T = change in temperature\n\nCp= 0.51998 J/(C*g)\n\nGood Luck with the test!