How do you calculate the percentage increase in value per year of something $350 to $800 in 7 years?
121809
apolitical and hayharbor avoided the compounding issue, and ws's formula is for an annuity where you ADD another 350 each year.  subwoofer has it right but gives you an old fashioned lesson in logarithms.  but it takes only 2 steps of algebra to get a calculator-ready equation.\n\n350*r^7=800\nr^7=800/350\nr=(800/350)^(1/7)\n\nand even a $12 calculator, say a TI-30, will give you\n\nr=1.125353197; which makes the annual percent of increase 12.54%
160945
Value = Dividends one year from now / (required rate - growth rate)\n= 4.8 / (.05)\n= 96
533079
Increase = 11877 - 3752 / 3752\n\n216%\n\nThink of a simpler example.  Say something happened 2 times today and 3 times tomorrow.  That would be 50% more tomorrow or (3-2)/2 = 1/2\n\nSome people will tell you it is 3/2, that is wrong.  The increase is not 150% in this simple case.
433421
If the question is for COMPOUND interest\nWhat you're looking for is \n1.075^n=2\nTake logarithms on both sides, and noting that the power is multiplied to the logarithm\nnlog(1.075)=log(2)\nn=log(2)/log(1.075)=9.584 years\nNote: To check results for compound interest, the rule of 72 says that an approximation to the number of years to double the principle is 72/(interest rate in percent).\nIn the present case, an approx. value is 72/7.5=9.6 years, which is very close to the exact value of 9.584 years.\n\n\nThe question is for simple interest, where the interest does not make interest, so\nN=(2-1)/(1.075-1)=13.333 years
162180
For a 5% increase the growth factor is 1.05; for 8.75%, it's 1.0875; for 15%, 1.15.\n\n$30 at 4.5% compound interest (compounded how often?) for 2 years is 30*(1.045)^2 = 32.76
542169
The shorter the interest term the faster it grows as the principal grows more quickly so you get more interest on your interest\n\nFor example lets look at the interest gained over 1 year on an interest rate of 12% per annum\n\nYearly: Well at the end of the year A = 1.12*P\nSo interest gained = 1.12*P - P = 0.12*P\n\nHalf Yearly: Well at the end of the year A = (1.06)*(1.06)*P (because the interest is applied each 6 months\n= (1.06)² * P\n= 1.1236*P\nSo interest gained = 1.1236*P - P = 0.1236*P > 0.12P\n\nQuarterly: Well at the end of the year A = (1.03)*(1.03)*(1.03)*(1.03)*P \n= (1.03)^4 * P\n≈ 1.1255P\nSo interest gained = 1.1255*P - P = 0.1255*P > 0.1236P\n\nMonthly: Well at the end of the year A = (1.01)*(1.01)* ... *(1.01)*(1.01)*P \n= (1.01)^12 * P\n≈ 1.1268P\nSo interest gained = 1.1268*P - P = 0.1268*P > 0.1255P\n\nDaily: Well at the end of the year A = (1.0003288)*(1.0003288)* ... *(1.0003288)*P \n= (1.0003288)^365 * P\n≈ 1.1275P\nSo interest gained = 1.1275*P - P = 0.1275*P > 0.1288P\n\nNow while it may not sound like much over 1 year over 20 years it can become significant\n\nJust quickly over 20 years\n\nYearly: Interest = ((1.12)^20 -1)*P = 8.6463*P\nHalf Yearly: Interest = ((1.06)^40 - 1)*P = 9.2857*P\nQuarterly: Interest = ((1.03)^80 - 1)*P = 9.6409*P\nMonthly: Interest = ((1.01)^240 - 1)*P = 9.8926*P\nDaily: Interest (using 365.25 days per year to account for leap years)= ((1.0003285)^365.25*20 - 1)*P = 10.0154*P
28301
It depends on how much you owe at which rates, and how fast you're paying them off.  If it costs you $700 to drop 5%, you would be ahead after just a year if you owed $700 / 0.05 = $700 * 20 = $14,000.
381713
300000*8%=?\nthen subtract that amount from the 300000
164357
Try this:\n\n778+785+158+162=1883\n\n(778/1883)*100=41.317% or 41.32% or 41%\n(785/1883)*100=41.688% or 41.69% or 42%\n(158/1883)*100=8.390% or 8.39% or 8%\n(162/1883)*100=8.603% or 8.60% or 9%\n\n41%+42%+8%+9%=100% to confirm totals
449773
I = Prt, \nwhere  I = interest, P = principal, r = interest rate and t = number of years\nP = 770, r = 3% = .03 and t = 9\nI = 770(.03)(9)\nI = 207.90
526102
One year ago,   sales were    25990510/1.30 = 19992700.\nTwo years ago, sales were    19992700/1.30 = 15379000.\nThree years ago, sales were 15379000/1.30 = 11830000.\nFour years ago, sales were    11830000/1.30 =  9100000.\nFive years ago, sales were       9100000/1.30 =  7000000.\nSix years ago, sales were         7000000/1.30 = 5384615.38\n\nHope this helps :-)
313635
If the tax rate is 8.25%:\n\nPrice*1.0825=total\n\nYou add 1 to the tax amount (.0825) so the original value will be added in as well.\n\nIf you just multiply by .0825 then your answer will just be the tax and not the cost.
537832
you just multiply your price for .07 and you get the sales tax then you add this amount to the price of whatever that you buying. For example      $55.00\n                       X.07\n                   _______\n                      $3.85\nThen    $55.00 + $3.85 = $58.85
381079
i=r/k  (Divide by 100 to change from percent to decimal.)\nn=kt
472141
Problem 1: If a piece of real estate purchased for $75,000 in 1998 appreciates at the rate of 6% per year, then its value t years after the purchase will be f(t)=75,000(1.06^t). According to this model, by how much will the value of this piece of property increase between the years of 2005 and 2008? \n\nf=75000*1.06^3=89326.20\nincrease=89326.20-75000=$14,326.20\n\nProblem 2: The amount A in an account after t years of an initial principle P invested at an annual rate r compounded continuously is given by A=Pe^rt where r is expressed as a decimal. What is the amount in the account if $500 is invested for 10 years at the annual rate of 5% compounded continuously?\n\n500*e^.05*10=500*e^.5=$824.36\n\n\n\nProblem 3: Find the number log5(1/5). \n-1
273337
percentage change is your difference over the original number multiplied by 100
667993
A.\n\nIn 19 years, it went up by a factor of 31.948.\n\n31.948^(1/19) = 1.20 = 20% increase every year.\nIn another 20 years, that's 31948 * (1.2^20) = 1224810