You have been given the equation\n        \n\n        \n\n        \n b = a / e^2 \n\n        \n\n        \n\n        If a is measured in joules and e is measured in m s−1,\n        what are the SI base units of b?
133184
kg m^2\n------- = Joule\ns^2\n\nb = kg m/s
407823
I worked this up, but Jess beat me to it.\n\nFollow her very clear explanation...excellent presentation.\nBut correct her math...\n10 mols x 0.928 = 9.28 mols SO3 produced\nMW of SO3 is 80.06\nSo, 9.28 x 80.06 = 743 g SO3 produced\n\nDon't be harsh...it's easy to transpose digits.  :-))
239341
Well E=mc^2 that give us\n\nm = E/c^2\n\nm = 9.6/16 *  10^ 15-14\nm = 0.6 * 10 = 6.0
430547
Es = L*r*w (w=2piN) , N=600 rpm=10rps , L=9 \nEs = L*r*2pi*N) , N=10, L=9 \nEs = 9*0.18*2*3.14*10\nEs (Shaft Energy)= 101.734 Newton/second which is not a unit of power.\n\nPlease specify the units of r,Es,L=95 or 9 ?\nWhat is the unit of Ee? HP or KW?\nfurther you have given following data which are contradictory.\nPump Shaft Speed =1200 ?\nEe (Electrical Energy) = 67.2\nT = 1.62\nw (Rotational Speed)= 62.8
553260
the units for joules are N*m...  so if you divide the volume of the water m^3, then your pressure units are N/m^2....  simply divide 25000/30 = 833.333N/m^2
18538
F = ma    \nNewton's second law.
428526
a) v^2-u^2=2as\n    v^2-52.4^2=2*(-9.8)*28.5\nv^2= 2745.8-558.6\n     =2187.2\nv=46.76m/s\n\nKinetic Energy=1/2mv^2\n                     =1/2*46.9*46.76^2\n                      =51,290 Joules\n\nb)height=28.5-5.06=23.44m\n\nv^2-u^2=2as\n\nv^2-52.4^2=2*(-9.8)*23.44\nv^2=2745.8-459.42\n     =2286.4\nv=47.8m/s
213298
E is normally expressed as joules (kilogram-meters per second^2)\n\nSo the mass is in Kg, and the speed of light is in Meters/Sec
1814
ur second equation is wrong. \n2a is not equal to a-squared (which u symbolized by ab, since a=b).
391001
C=2(Pi)r or diameter times Pi\nI don't know how to solve the problem cause not enough info is given. Does it say what C equals?\n\nv = lwh . H stands for the height. Does it say what v equals?\n\na= 1/2h(b1+b2) b1 is base 1. Does it say waht the area is?\n\nProvide more info please. :)
413370
1. b\nBecause \n'1/s' is inversly related to 's'\n\n2. c\nBecause\n1/s AKA Hertz\n\n3. d\nBecause\nN.P,As,Bi are all in the same chemical group\n\n4. b\nBecause\n(3*10^8)m/s /  (2.50 * 10^13)Hz = 1.20 x 10^-5 m\n\n5. b\n\n(I am 100% sure for every question accept the last one. I am only 50% sure on 5)
31994
A*B=(3i+5j)*(2i+4j)=2k
531660
51kg x 25 m = energy used\n\ndivide the energy used by 0.30 to get the second answer
663471
base times the hieght divided by 2\n\nthe base is the bottom or the triangle and the high it the top of the triangle to the middle of the base
344344
Resistance, R, is converted to conductance, G, by inversion. \nG = 1/R. The unit was called mho (ohm spelled backwards) when I went to school. But the unit name was changed to Siemens (the symbol is S) when the SI unit changes were made. \n\nSo just take all your readings and do a 1/x calculation with your calculator. And put an S after each result for the unit.\n\nIncidentally, ohmmeters are not very accurate with measurements of such low resistance. The test leads probably have resistance of something like .3 ohms.
41875
Use these equations:\nEnergy of a photon = 1240 eV * nm / lambda.\nlambda is your wavelength and you can leave it in nanometers.\nIn other words, 1240 eV nm / 482 nm = __ eV.\nThen use the conversion factor\n1 ev = 1.602 E-19 Joules to put your answer in Joules.\n:-)
414960
well, I didnt go through ur calculation, but I think numerically you are right, but you didnt give units of E, so I really cant tell the answer is right or not without units.