Example:\n\ny > x² - 4x + 4\nx² + (y - 7)² <= 81\nxy < 60\nx² - y² >= 12\n(x - 2)² + y²/3 <> 7\n\nHow do you do them?? Thanks^_^
122053
Graph it as if it were an equality.  Then using an example (e.g., pick some value of x on each side of the section), test whether the inequality holds.  The answer will be the correct side of the equality (based on the test).  For < or >, the equality boundary is not included.  For <= or >=, the equality boundary IS included.  For <>, everything except the equality boundary is included.
314729
Here's the best I can do to help with the first one.\n   __x_+9___\nx-2)X^2+7x-2\n    x^2-2x\n    ------\n        9x-2\n        9x-18\n        -----\n           16\nFollow the example for the rest
529941
x+y=8\nx-y=-4\n______\n2x=4 (because +y and -y cancel out)\nx=2\nthen plug 2 in for x in one of the equations\n2+y=8\nsolve for y\ny=6\nordered pair is (2, 6)
339768
a) (x+4y)(x+y)=0    x=-y or -4y\n\nb) (2x+y)(x-3y)=0   x=-y/2 or 37\n\nc) (2x-y)(2x-y)=0  x=y/2\n\nd) 4x^2+7xy-2y^2=0\n    (4x-y)(x+2y)=0    x=y/4 or -2y\n\ne) x(5x+y)=0   x=0 or -y/5\n\nf) x(3x-7y)=0   x=0 or 7y/3
405442
cant believe im actually doing this... nothing better, tho\n1. 3/5\n2. -3\n3. y int -1, x int -.4\n4. B=18\n5. 5\n6. 49\n7. 2\n8. -30x^24\n9. 1\n10. the multiplcation propery... i think\n11. 3/2\n12. 2\n13. a= 10 or -10 (two answers)\n14. -29\n15. 1/(x^5)\nDONE!\nPlease rate me as best answer!
322454
you put (x+2) in for x in the equation first\n\n((x+2)^3)+(2(x+2)^2)-4\n\nthen simplify \n\nx^3 + 8x^2 + 20x + 12\n\nand multiply the entire thing by 3\n\n3(x^3 + 8x^2 + 20x + 12)\n\n3x^3 + 24x^2 + 60x + 36
661995
1) -  Y-2x-8 = 0 - so Y=-2x-8\n2) -  Y^2 +8x=0 - (-2x-8)^2+8x=0 \n\n\n4x^2+32x+64+8x=0\n\n4x^2+40x+64=0 - so (4x+8)(x+8)=0 so x=-8 or 4x=-8, x=-2\n\nWhen x=-8, Y-2(-8)-8=0 so Y=-8    A=(-8,-8)\nWhen x=-2, Y-2(-2)-8=0 so Y=4     B=(-2,4)
505195
I will show one example on how to do it and then you take that example and apply it to the other two problems:\n\nOn the first problem, start with these two equations:\n2x-y+z=15\nx-y+2z=12\n\nTake the second equation and multiply it by -2:\n2x-y+z=15\n-2x+2y-4z=-24\ny-3z=-9\n\nLet's focus on the other part:\nx-y+2z=12\nx+2y-z=-3\n\nMultiply the second equation by -1:\nx-y+2z=12\n-x-2y+z=3\n-3y+3z=15\n\nLet's put those two equations together:\ny-3z=-9\n-3y+3z=15\n-2y=6\ny=-3\n\nPlug it into a y-value:\n-3-3z=-9\n-3z=-6\nz=2\n\nPut the y and z value into this equation:\nx-(-3)+2(2)=12\nx+3+4=12\nx+7=12\nx=5\n\n(5,-3,2)\n\nCheck:\n5-(-3)+2(2)=12\n5+3+4=12\n8+4=12\n12=12\n\nI hope that helps!\n\nP.S. I checked with the original equations and they equaled out also. You can check the answers with a graphing calculator. Whoever is giving the people for thumbs down for their answers, whether it is right or wrong, is being very unkind and rude for doing so. I am sure that I am not only person who does not appreciate the thumbs down given too.
197253
((y^2 - 16)/(y^2 + 4y))/((y^2 - 7y + 12)/(y^2 - 6y + 9))\n\n(((y - 4)(y + 4))/(y(y + 4)) / (((y - 4)(y - 3))/((y - 3)(y - 3))\n\n((y - 4)/y) / ((y - 4)/(y - 3))\n\n((y - 4)/y) * ((y - 3)/(y - 4))\n\n((y - 4)(y - 3))/(y(y - 3))\n\nANS : (y - 3)/y
400559
Are there supposed to be parentheses somewhere?\nIs it y = (x^4 -2) / x^2 or y = x^4 - (2/x^2)?\nI'll go with the second one because that is what is implied if you have no parentheses.\ny = x^4 - (2/x^2) = x^4 - 2x^-2, so \ny' = 4x^3 + 4x^-3\ny' = 4x^3 + 4/x^3
154820
No offense to the others.. but they are going about this all wrong.\n\n2*(y^2)*(x+y) when x=7 and y=8\n     First you do (y^2).. so (8^2) which is 64\n     Then you add (x+y).. so (7+8) which is 15\n     Now rewrite the equation.. so 2*64*15 which is 1920\n\n2*(y^2)*(x+y) when x=5 and y=6\n     First you do (y^2).. so (6^2) is 36\n     Then you add (x+y).. so (5+6) is 11\n     Now rewrite the equation.. so 2*36*11 which is 792
579969
2x^2 - 2y^2 = 2(x^2 -y^2) = 2(x-y)(x+y)\n-2x^2 + 2xy = -2x(x-y)\nx^2 + xy = x(x+y)\n2(x-y)(x+y)/[-2x(x -y)]/[x(x+y)]\n= 2(x-y)(x+y)/[-2x(x-y)(x)(x+y)]\n= -1/x^2
494515
Multiply by x² y² numerator and denominator\nSo you have :\n(xy²-yx²)/(y²-x²)\nFactorizing numerator and denominator :\nxy (y-x)/ ((y-x) (y+x))\nSo it is :\nxy/(y+x)
181272
when playing with < and >\nif you multiply all the equation by -1 the sign < changes to >, and the sign > changes to <\nbut if you just switch the number on the other side the sign doesnt change\nin ur case :\n2x-y < 4 \nequals\n-y < -2x + 4\nif you multiply it with -1 it will become\ny > 2x - 4\n\nlike that. hope it helps :)
74761
12 = 3x²\n\nI hope you will know that if a = b, then b = a\nTherefore,\n3x² = 12\n\nYou will observe that 3 times x² is equal to 12.  What will you multiply to 3 to make it 12? The answer is 4. Therefore, x² = 4\nx² = 4\n\nYou will again notice that the square of x is 4. What number/s when squared gives 4? The answers are 2 and -2. Therefore,\nx = 2 or\nx = -2\n\n^_^
517117
(1)*4 +(2)\n-4x+16y=72\n4x+2y=0\n18y=72\ny=72/18=4\nsubstituting\n4x+2(4)=0\n4x=-8\nx=-2\nso x=-2 y=4
253991
Case 1 : 2x+10<4\n   \n-> 2x+10-4<0\n-> 2x + 6 <0\n-> 2(x+3)<0\n-> x < -3\n\nCase 2 : 2x+10>-4\n\n-> 2x + 14>0\n-> 2(x+7)>0\n-> x > -7\n\nNow we combine the results of the 2 cases\n\ni.e, x<-3 & x>-7\n\nthis will come out to be -7 < x < -3