The rules states that der must be at least one man and one woman on the committee.In how many different ways can the committee be chosen?\nSubsequently one of the men and one of the women get married to each other.The rules also state that a married couple may not both serve on the committee.In how many ways can the committee be chosen now?
125073
Querier's answer to the first part was excellent.  Here's the second part, which is even simpler.  Suppose you've chosen the married couple.  That gets you 1 man and 1 women.  Then there are 7 ways to choose the 3rd person.  So 7 of the 70 committees from part one include the married couple, leaving 63 that do not.
134384
First think of a situation involving 4 seats for 4 people:\n\nIn the first chair any of the 4 can sit, in the second, any of the remaining 3, in the third either of the remaining 2 and the last person gets the 4th seat\n\nthe number of combinations is 4*3*2*1= 24\n\nThis is the same for 4 couples since each couple sits together.\nNext, each couple can be in one of two positions because the members of a couple may switch seats and still be sitting together.\n\nthis multiplies the original number of combinations by 2^4 or 16\n\n24*16=384
53670
I think there should be a seperation of Rev Trask and Yahoo Answers.  But to answer your question, yes.  It would allow people to get married to whoever they want, however they want.
421405
Three married couples?
502559
I think you missed out a word...  holding oneself out to BE the.......\n\nIt would be my understanding that they are saying "You do not have to be married to someone to be classed as co-habiting"\n\nIn th family code it then gors on to say that you need not be of the opposite sex either - which to my mind is basically further suggesting that the bit you are unsure of is simply saying "you don't need to be married to be classed as cohabiting"\n\nHorrible wording I grant you.
382563
I understand people's confusion over AA, but what about this scenario?  It happens all the time:  18 qualified people apply for a job.  One, however, is extremely qualified, heads above the rest.  She is the only woman applicant.  The man hiring her convinces himself that because she is a woman, she'll likely not work as hard because she probably will want kids and be a mom some day.  OR this scenario.  Of the 18 applicants, the one who stands way over the rest is an African American.  The man hiring decides that his clients would be uncomfortable working with a minority, so he gives the job to a white man.\n\nDiscrimination does exist.  Maybe AA doesn't solve these problems, but how do you make it fair for women and minorities if it's not a law to have fair hiring practices?
276543
1) the pdf is actually a binomial.\nIf you consider only 1 man, what is the probability that he will be paired to his wife out of the 10 women? \nIt is 1/10\n\nLet X be the number of paired couples, paired meaning they are paired to their own spouse.\nTherefore X~B(10,1/10)\n\nSo if we want to find the probability that there is only 1 pair, using the formula of a binomial dist,\n\nP(X=1)= [10 choose 1] (1/10) (9/10)^9\n= 0.3874\n--------------------\n\n2) To find the mean and variance, using the Binomial parameters formula, we compare what we got in part 1 with the general formula,\nX~B(n,p)\nX~B(10,1/10)\n\nSo our mean = (n) multiply (p)\n= 10 x (1/10)\n= 1\n\nVariance = (n) multiply (p) multiply (1-p)\n= 10 x (1/10) x (9/10)\n9/10\n----------------------\n3) P(X >= 3) = 1 - P(X <= 3) \n= 1 - [ P(X=0) + P(X=1) + P(X=2) + P(X=3) ]\nreferring to the above eg in part 1, its easy to derive\n= 1 - [ 0.0349 + 0.3874 + 0.1937 + 0.0574]\n= 0.3266
516885
C is at the end, so its just the other 8 positions to play with.\n\nCount how many permutations of those 8 there are.\n\nThen count how many there are where A and B stand side by side.\n\nThen subtract those out.\n\nEdit:  Poster below me is way off.  without any restrictions, 9 men could be arranged in over 360000 ways.   Not 81.\n\nBasically, you can take 'C' out of it.  There are 8 spots left, and 8 men.  Spot 1 can hold any of the 8.  spot 2 any of the remaining 7 and so on, giving 8X7X6X5X4X3X2 which is 8! possibilities.\n\nThat's 40320.\n\nOf those 40320, some involve A and B being side by side.  How many?  Well, they could be in slot 1&2, 2& 3 .... up to 7&8.  And they could be A-B or B-A.  That's 14 possibles.  For each of those 14, the other 6 spots could be filled 6! ways.\n\nSo there are 14 X 6! = 14 X 720 = 10800 combos with C in the 9 spot and A & B side by side.\n\nTherefor, of the 40320 with C in the 9 spot, 40320-10800 = 30240 possible arrangements have C at the end, but A and B NOT side by side.
96829
For the first question, that means you want to know about committees with exactly 3 women and committees with exactly 4 women. Since these are independent cases, we consider each separately and add the result. \nFor 3 women, we need to know how many unordered groups of 3 women we can choose from 4 women, so we have 4[Choose]3. The men have 2 people on this committee, so they contribute 4[Choose]2 to the product for a total of (4[Choose]3)*(4[Choose]2) committees with exactly 3 women on board. \nThere is only one way to grab an unordered set of 4 objects from a set of 4 objects, so we go right to the men. There are 4 ways the men can fill the last spot, so this is 1*4=4 different committees with 4 women on board.\nThus the total number of committees with a majority of women on board is (4[Choose]3)*(4[Choose]2) + 4.\nThe second part is very similar to the first.
550540
That's a tough one. The priest that will conduct the ceremony, will have to cheat (in essence), because it is against the rules of the doctrine (as far as I know) so that is why one of the two in the couple usually submits him/herself to the demands of the other's doctrine (he will have to be baptized orthodox Christian, in your case). There are exceptions but always in a personal level, and with the fear to get everybody in trouble. I live in an officially greek orthodox country and I grew up as one too (but I don't consider myself as one anymore) so I've heard many occasions like this. I can recall few marriages like the one you're seeking to have, but they are very rare and the couples said afterwards how kind the priest was (so, you see it gets personalized) that he did not demand anything like being baptized. Good luck
237601
Why is a man allowed to have more than one wife in Islam? i.e. why is polygamy allowed in Islam?\n\nAnswer:\n\nDefinition of Polygamy\n\n1.  Polygamy means a system of marriage whereby one person has more than one spouse. Polygamy can be of two types. One is polygyny where a man marries more than one woman, and the other is polyandry, where a woman marries more than one man. In Islam, limited polygyny is permitted; whereas polyandry is completely prohibited.\n\nNow coming to the original question, why is a man allowed to have more than one wife?\n\n\n2.  The Qur’an is the only religious scripture in the world that says,"marry only one".\n\n\nThe Qur’an is the only religious book, on the face of this earth, that contains the phrase ‘marry only one’. There is no other religious book that instructs men to have only one wife. In none of the other religious scriptures, whether it be the Vedas, the Ramayan, the Mahabharat, the Geeta, the Talmud or the Bible does one find a restriction on the number of wives. According to these scriptures one can marry as many as one wishes. It was only later, that the Hindu priests and the Christian Church restricted the number of wives to one.\n\nMany Hindu religious personalities, according to their scriptures, had multiple wives. King Dashrat, the father of Rama, had more than one wife. Krishna had several wives.\n\nIn earlier times, Christian men were permitted as many wives as they wished, since the Bible puts no restriction on the number of wives. It was only a few centuries ago that the Church restricted the number of wives to one.\n\nPolygyny is permitted in Judaism. According to Talmudic law, Abraham had three wives, and Solomon had hundreds of wives. The practice of polygyny continued till Rabbi Gershom ben Yehudah (95% C.E to 1030 C.E) issued an edict against it. The Jewish Sephardic communities living in Muslim countries continued the practice till as late as 1950, until an Act of the Chief Rabbinate of Israel extended the ban on marrying more than one wife.\n\n\n3.  Hindus are more polygynous than Muslims\n\n\nThe report of the ‘Committee of The Status of Woman in Islam’, published in 1975 mentions on page numbers 66 and 67 that the percentage of polygamous marriages between the years 1951 and 1961 was 5.06% among the Hindus and only 4.31% among the Muslims. According to Indian law only Muslim men are permitted to have more than one wife. It is illegal for any non-Muslim in India to have more than one wife. Despite it being illegal, Hindus have more multiple wives as compared to Muslims. Earlier, there was no restriction even on Hindu men with respect to the number of wives allowed. It was only in 1954, when the Hindu Marriage Act was passed that it became illegal for a Hindu to have more than one wife. At present it is the Indian Law that restricts a Hindu man from having more than one wife and not the Hindu scriptures. \n\nLet us now analyse why Islam allows a man to have more than one wife.\n\n\n4.   Qur’an permits limited polygyny\n\n\nAs I mentioned earlier, Qur’an is the only religious book on the face of the earth that says ‘marry only one’. The context of this phrase is the following verse from Surah Nisa of the Glorious Qur’an: \n\n"Marry women of your choice, two, or three, or four; but if ye fear that ye shall not be able to deal justly (with them), then only one."\n\n                                  [Al-Qur’an 4:3]\n\nBefore the Qur’an was revealed, there was no upper limit for polygyny and many men had scores of wives, some even hundreds. Islam put an upper limit of four wives. Islam gives a man permission to marry two, three or four women, only on the condition that he deals justly with them. \n\nIn the same chapter i.e. Surah Nisa verse 129 says:\n\n"Ye are never able to be fair and just as between women...."\n\n                                 [Al-Qur’an 4:129]\n\nTherefore polygyny is not a rule but an exception
358276
Makes me wonder if the guys who are in favor of it would be in favor of sharing their Wives with other men as well.\n\nAfterall it should go both ways.\nSomehow I am doubting the guys would be in favor of that :)
646741
Paul writes to Timothy about overseers and deacons that, among other things, they should be the husbands of one wife. (I Timothy 3:2, 12) These are people who are supposed to be an example to the flock, so it is especially important that they really do things by the Book.\n\nFor that matter, while back in Old Testament times the patriarchs did often have more than one wife, God instructed the kings of Israel (whether they obeyed Him is another matter, but still...) that they were not to have multiple wives. This is so their hearts would not be led astray. (Deuteronomy 17:17)\n\nBut as far as we 'ordinary people' are concerned, in Matthew 19:3-6, Jesus takes a very strict view of Genesis 2:24, basically indicating that we should live strictly by the following: leave father and mother, cleave to wife, become one flesh. In this instance, He interprets that to mean no divorce (because that is the matter under discussion). Using the same kind of thinking, it would also mean having only one spouse of the opposite sex.
225006
women cant do nothing back as muslin can have more than one wife, being the case there is no infidelity...\nthe husband in this case gets away with it, how dam convenient.
58361
4. A younger one every 8 years. There are man living such that they marry a younger women at least every 10 years. I think this is disgusting. \nMonogamy is a must. (i think marrried man with girlfriends are also disgusting). sorry.\nOne husband is enough for me.
77842
In the experiment of choosing a committee of 6 from a group of 8 women and 7 men,\n\nTotal no. of possible choices \n= no. of ways in which the 6 members of the committee can be chosen from the total 15\n==> n = C(15,6)\n==> n = 15*14*13*12*11*10/6*5*4*3*2*1\n==> n = 7*13*11*5\n==> n = 5005\n\nLet "A" be the event of choosing the committee with 3 women and 3 men\n\nFor Event "A"\n\n---------- Men----Women---Total\nAvailable---8-------7------15\nTo Choose---3-------3-------6\nChoices----C(8,3)-C(7,3)--C(15,6)\n\nNo. of favorable choices\n= (no. of ways in which the 3 men can be chosen from the total 8) * (no. of ways in which the 3 wommen can be chosen from the total 7) \n==> m(a) = C(8,3) * C(7,3)\n==> m(a) = 8*7*6/3*2*1 * 7*6*5/3*2*1\n==> m(a) = 8*7 * 7*5\n==> m(a) = 1960\n\nProbabilty of choosing the committe with 3 women and 3 men \n==> Probability of occurance of event "A" = m(a)/n\n==> P(A) = 1960/5005\n==> P(A) = 392/1001\n\n\nhttp://www.futureaccountant.com/probability/study-notes/\n\nhttp://www.schoolingkids.com/
1829
The entire thing is recorded... depending on the event yes someone can participte in only one stretch... each event will have its own set of officals rules...