Are there any equations for calculating the amplitude, the frequency, etc.?
133672
Imagine the stretching of the surface of the drum as the stretching of a spring. use hooke's law to do calculation. u will need to know about the strength of material and etc. very very very complicated
321442
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
73250
Assuming you mean over R, solve the equation s*t + r*sin(t) = 0 for r and s for all t that is not the trivial solution (r,s)=(0,0). \nIn other words, if f(t)=sin(t) and g(t)=t were linearly dependent, then there is some non-zero slope s, s*g(t) = s*t and some non-zero amplitude r, r*f(t) = r*sin(t) such that the graphs of these functions completely coincide for all t. Since f is non-linear and g is, this is nonsense and the functions are linearly independent.
297281
The best way to work this out would be to plot a speed time graph for the information.\n\nOr you could express it as a simultaneous equation.
522809
This seems to be equivalent to saying what is the maximum frequency of a sine wave with a maximum amplitude of 1.1e-6 metres and  maximum acceleration of about 9.8m/s^2.\n\nLets have a think , the area under 1/2 a cycle of sin is a/2*period/2 and period is 1/f so max v = a/2/2/f  - ha!  similarly max_v/2/2/f= max acceleration = a/2/2/2/2/f/f , that's better.  a/16/f^2 > g  gives max acceleration > g  so \nf^2 > g/16/a  or  f > about 750 Hz.
352252
Simple harmonic motion can be described by a sinusoidal function\n\nX(t) = X0*sin(w*t)\n\nwhere X0 is the amplitude of the motion, w is the angular frequency, and t is time. Given this expression for the time dependence of the displacement, the velocity is expressed as\n\nV(t) = X0*w*cos(w*t)\n\nand the acceleration can be written as\n\nA(t) = -X0*w^2*sin(w*t).\n\nBased on these expressions, the maximum velocity is\n\nVm = X0*w\n\nand the maximum acceleration is\n\nAm = X0*w^2\n\nThe angular frequency w is\n\nw = 2*pi*f\n\nwhere the linear frequency for this problem is f = 4940 /min. Be sure to convert to the proper units to get the answers in the form you need.
395556
Try Google or Yahoo.  You'll find worked examples there.  I think it needs diagrams to understand; they and the accompanying explanations are too complex to attempt to reproduce here.
380789
L+ e = C/4N\n\nL is the resonance length.\n\ne is the end correction \n\nC is the speed of sound in air\n\nN is the frequency of the fork.\n\nThe above equation can be written as \n\n4NL + 4Ne = C.\n\n\nFor first fork, 4N = 1024.\n\n\n1024 x 0.32 + 1024 e = C --------------- (1)\n\nFor the next fork, 4N = 1536\n\n1536 x 0.208 + 1536 e = C----------------- (2).\n\nEquating (2) and (1) \n\n1536 x 0.208 + 1536 e = 1024 x 0.32 + 1024 e \n\n512 e = 327.68 - 319.49 = 8.19 \n\ne = 0.016 m = 1.6 cm.
433168
Listening to music always helps!\nw=w’*t, w=500rpm=500/60 rps=2pi*25/3 rad/s, t=2.6s, then \nw’=w/t=2*pi*25/3/2.6=20.14 rad/s^2;\nu=w’*t^2/2=w*t/2=25/3*2.6/2=10.83=~10 full revs
380048
Yes...\n\nThe refraction indecces\n\nn =c/v, but c = wave lenght * frequency
188316
the wavelength is half...\n\nvavelength and frequency are inversely proportional
512158
KNOWN:\nf = 3.2 x 10^-2 Hz\nc (ie speed of light) = 3.00 * 10 ^8 m/s\n\nFIND L (AKA wavelength)\nL m = c m/s  /  f Hz\n= 3.00 * 10 ^8 m/s  /  3.2 x 10^-2 Hz\n= 9 375 000 kilometers\n\nAre you sure its 10^-2 Hz? That seems unlikely
487983
a^2+b^2=c^2\n2ada/dt+2bdb/dt=2cdc/dt\n2*-4+2b.dbdb/dt=0\nb=rt225-144=rt81=9\n-8+18db/dt=0\ndb/dt=8/18=4/9'/sec
240076
Another person had the same basic question. This is called the Doppler Effect, which follows the equation:\nf = f0 [(S +/- So)/(S -/+ Ss)]\nWhere f is the observed frequency, f0 is the frequency of the source, S is the speed of sound, So is the speed of the observer (+ if moving towards, - if away), and Ss is the speed of the source (- if moving towards, + if away).\nIn this case, just set f = 1.05f0
549967
You can easily calculate the speed of the transverse wave with the given information for distance travelled and time elapsed, with the formula s=vat where s is the distance va is the magnitude of velocity and t is the time.  Rearange that to get your speed.\n\nTHe speed in strings is dependent on the tension and the linear density of the string.  The formula is Vstring= square root (Tstring/linear density of the string)  Rearange this formula to calculate your tension.  Note:  the linear desnity can be calculated with the given information of the mass of the string and its distance...I think.
453548
I understand your frustration in receiving no Answer yet to this question, but since I do not have any direct knowledge of how to perform the calculation(s) you need ... I hope the link below serves you well.  It appears to explain the mathematics behind all the concepts you mention.
196156
See http://members.aol.com/logan20/elecspon.html for the equation to use.