__2 \n2x  - 1 = 4x + 15
120022
-> 2x^2 - 1 = 4x + 15\n-> 2x^2 - 1 - 4x - 15 = 0\n-> 2x^2 -4x -16 = 0\n-> 2( x^2 -2x -8 )= 0\n-> x^2 - 2x - 8 = 0\n-> factoring the equation you will come up with\n-> (x - 4)(x + 2) = 0\n-> equate both factors to zero\n-> x - 4 =0 , x + 2 = 0\n-> x = 4, x = -2
375326
Consider the following equations:\n1)   2x + y = 4 \n  \n2)   x − y = −1 \n\nTo solve them simultaneously, first, you need to solve one equation with respect to one variable. Let's solve the first one:\n\n2x + y = 4  Rearranging, you get:\ny = 4 - 2x\nNow you know the value of y, so plug it into the second equation, like this:\n\nx − y = −1 Rearrange using the value for y that you determined above:\n\nx - (4 - 2x) = -1\nNow solve this equation, since it now has only one variable:\n\nx - 4 + 2x = -1\n3x = 4 - 1 = 3\nx = 1 Now that you have the real value for x, go back to the first equation and solve for the real value of y:\n\n2x + y = 4  \ny = 4 - 2x  we know x = 1 so, y = 4 - 2\ny = 2\n\nYou can prove these are the right answers by using them in the equations.
90249
5x - 2y = 4  (1)\n2x + 3y = 13 (2)\nmul. eq.(1) by 2: 2 (5x - 2y = 4)\n                    10x - 4y = 8\n\nmul. eq.(2) by 5: 5 (2x +  3y = 13)\n                    10x + 15y = 65\n\nsubtract: 10x -  4y =  8\n      (-) 10x + 15y =  65\n          ________________\n               -19y =  -57 \n                  y =  -57/-19\n                  y =  3\n\nsubstitute value of y to any of the eqs.\n\nSubstituting to eq. (1):\n\n    5x - 2y   = 4   \n    5x - 2(3) = 4\n    5x - 6    = 4\n    5x              = 4 + 6\n    5x              = 10\n     x              = 10/5\n     x              = 2\n\nso, x = 2\n    y = 3\n\nto check, substitute values of x and y to any of the two equations:\n    for eq. (1),\n\n    5x   - 2y   = 4   \n    5(2) - 2(3) = 4\n      10 - 6    = 4\n\n    for eq. (2),\n\n    2x   + 3y   = 13\n    2(2) + 3(3) = 13\n      4  + 9    = 13
515212
4x + 7 = -7\n4x = 14\nx = 14/4\nx = 7/2
525993
**************\nQuestion 1\n**************\n\n2x - 4y = 8\nx - 2y = 4\n\nx - 2y = 4\nMultiply both sides of this equation by -2\n(-2)(x - 2y) = -2*4\n-2x + 4y = -8\n\nNow we will add this equation to the other\n  2x - 4y =  8\n-2x + 4y = -8\n____________\n0 + 0 = 0\n0 = 0\n\nThere are an infinite number of solutions to this problem because both sides of the equal sign end up the same.\n\n**************\nQuestion 2\n**************\nWe can add these together right away because the x and -x will cancel each other out.\n-x - y =  4\n x - y = -8\n_________\n0 -2y = -4\n\nNow we will solve for y.\n-2y = -4\nDivide each side by -2\ny = 2\nNow we plug that into one of the equations to get x\n x - y = -8\n x - 2 = -8\nAdd 2 to both sides\nx = -6\n\nSo, x = -6 and y = 2
273227
Solution:\n\n2x*2-3x-14=0\n\nAnswer will be: (2x-7)(x+2)\n\nWhen you multiple these two equations together, you'll do the reverse to start out with your answer.
520783
Use factoring.\nx2-2x-8=0\n(x-4)(x+2)=0\nso\nx-4=0 and x+2=0\nsolve\nx=4 and x=-2
54208
2x is the largest possible factor, leaving:\n2x(4x^2-5x-7)
507057
2x=(x+5)+1\n2x=x+6\nx=6\n\nthe numbers are 6 and 11
674210
8x-11=2x+1\n8x-2x=11+1\n6x=12\nx=2
496696
2x(x - 2) = 3(x + 10)\n2x² - 4x = 3x + 30\n2x² - 7x - 30 = 0\n(2x + 5)(x - 6) = 0\nx = -5/2 or 6 ← option d
399667
5x + 10 + 7x - 14 = -2x\n\n12x -4 = -2x\n\n14x = 4\n\nx = 4 / 14 = 2 / 7  (not 2/17)
381517
a.2xy(-15x^2y^4+8x^2-5y^2)/-4xy^3\n(-1/2y^2)(-15x^y^4+8x^2-5y^2)\n\nb.2+160-64\n=98
501183
3x + 2y - 2z\n\n3(5) + 2(2) - 2(1)\n\n15 + 4 - 2\n\n19 - 2\n\n17\n\nThe answer is 17\n\n- - - - - - -s-
349464
Use the quadratic formula.\nx1 = 1\nx2 = -1/2
408944
Have you typed this correctly?\n\nEq 1: 2x² + 4xy - 3\nEq 2: x² - 2xy - 4\n\nSubtraction:\n2x² + 4xy - 3 - (x² - 2xy - 4)\n= 2x² + 4xy - 3 - x² + 2xy + 4\n= (2x² - x²) + (4xy + 2xy) + (-3 + 4)\n= x² + 6xy + 1\n\nI don't see that in your list.\nIf your first equation is 2x² + 4xy *plus* 3, then your answer is:\nD) x² + 6xy + 7
351012
15+12(x-7)\n15+12x-84\n12x-69