How much is the investment worth after 36 years, after 60 years?\nHOw would i model the value of this investment with an exponential function?
123470
After 12 years, it's worth $4000.\nAfter 24 years, it's worth $8000.\nAfter 36 years, it's worth $16,000.\nAfter 48 years, it's worth $32,000.\nAfter 60 years, it's worth $64,000.\n\nDo you see a pattern here?
218136
worthless but you may keep it for collection purpose.\nYou may get a good deal in 10-20 years, you never know.\n:)
336291
may be this will work,\n\nLets say all the years are 365 days each (skiping leap yrs for now)\nassume interest on daily basis.\n\nFor Nth dollar the interest would be;\n\n1+(An*7/100)\n\nwhere A is time left in years, and that would be,\nAn = (3650-n)/365\n\nyour series will start from 0 to 3649.\n\nnow on expanding (3650-n) we find that it turns out to be a simple arithmetic progression,\n\n3650, 3649.....2, 1 with n= 3650\n\nSimplifying we get \n\nTotal Amount = 3650*1 + ( 7/365*100 * sum of the above progression)\n\nusing arithmetic progression formula I get sum (n) = 3650*3649/2\n\nPutting all of it together,\n\nTotal Amount = 3650 + ( 7/365*100 * 3650*3649/2)\n\n= 3650 + 1277.15 \n= 4927.15
433421
If the question is for COMPOUND interest\nWhat you're looking for is \n1.075^n=2\nTake logarithms on both sides, and noting that the power is multiplied to the logarithm\nnlog(1.075)=log(2)\nn=log(2)/log(1.075)=9.584 years\nNote: To check results for compound interest, the rule of 72 says that an approximation to the number of years to double the principle is 72/(interest rate in percent).\nIn the present case, an approx. value is 72/7.5=9.6 years, which is very close to the exact value of 9.584 years.\n\n\nThe question is for simple interest, where the interest does not make interest, so\nN=(2-1)/(1.075-1)=13.333 years
106733
The formula for future value of an annuity is\nFV = pymt((1+i)^n - 1)/i\nwhere FV is the future value, pymt is the payment, i is the periodic interest rate, and n is the number of payments made.\npymnt = 4600\ni = .0873/4 = .021825 because it is quarterly\nn = 6(4) = 24 because you're making 4 payments a year for 6 years\nFV = 4600((1+.021825)^24 - 1)/.021825\n= 143099.60
271244
first, start with how much money you have, then find the rate, and the time\n\nfor example:\nI have $20,000, at a rate of 12% for 36 months. The interest would be $20,000 times .12 times 36.
94488
In total the dude made 9000, which is not quite a lot to be honest for me. (I spend too much). Anyway!\n\nSay the amount he invested at 7% is X, this would naturally make the rest 9000-X, right? Good.\n\nSo hee is the math!\n\n0.07*X + 0.1(9000-X)=720 ....... clear! Now for simplicity, multiply all by 100 and you will get:\n\n7X + 10(9000-X) = 72000 ... and after distribution:\n7X + 90,000-10X = 72000\n-3X = 72,000-90,000 = -18,000  \nX = -18,000/-3= 6,000\n\nSo this is the amount he invested at 7% and the rest, as we shwed earlier, is 9,000-X = 9,000-6000 = 3,000\n\nSo he invested $3,000 at 10%.\n\nOf course you know this is true if the interest was made in one year and without talking taxes, which would be anouther story.
557726
If you spend it wisely, yes.\n\nLet's say you're 20 years old. one million would last you 60 years at about 16,500 a year so it would be like having a job making about $10 an hour
161981
straight line = 150,000 (200,000 * 1/12 *3 years)\ndouble-declining = 115,740.75 (1/12 * 200% = 16.66%)\n\n200,000*16.66% = 33,333.33\n166,666*16.66% = 27,777.77\n138,888*16.66% = 23,148.15\n\nAccumulated depreciation after 3 years = 84259.25\n200,000-84259.25=115,740.75\n\nAny more homework you need done, ha!
207889
You can use the Dividend Growth Model to value your investment based on the current dividend, estimated growth in the dividend and your required return.\n\nThe current dividend is 1.75 and based on 3 yr history (assuming this growth will continue) your dividend is growing at 9.04%. Your required return is 12%. \n\nThe stock will return 12% if you were to buy it at no greater than $64.37.\n\nValue = (Current Dividend x (1+ dividend growth)) / (Required Return - Dividend Growth)\n\nBut this value is only loosely in line with the concept of "intrinsic value". Instead of explaining the concept of "intrinsic value" here, let me point you to the definitive source on intrinsic value - Warren Buffett.\n\nsee pp 77-78 of the attached link
494853
A withdrawal of $w equivalent to $1.12w next year.\nThis $w is equivalent to w.(1.12)^y after y years.\n\nw remains withdrawn  for 11 years, \nanother w amount remains withdrawn for 10 years,\nand so on...\n\nTotal effective withdrawn amount at the end of 12 years,\nw (1.12^11+ 1.12^10+ 1.12^9 + .....   + 1) \n\n= w (1.12^12 -1)/(1.12 -1) \n= 24.133 w\n\nTotal value of $9500 in 12 years \n= P(1+r/100)^N\n= 9500(1.12)^12\n=9500*3.896\n\nNet future value after 12 years \n=  9500(1.12)^12  - 800*(1.12^12)/0.12\n= 9500*3.896 - 800*24.133\n= $17,705.4
228703
I would take it over the 30 year period. You get more and you know you'll be set for at least 30 years...so you don't go crazy and spend everything within the first year. \n\nFirst, I would get a layer, financial advisor, a very nice house and a car. Then give some to my parents and grandparents, charitable causes and invest the rest. \n\nThen I would travel to the United Kingdom, Europe, Austalia and make my own archaeology excavation in Egypt. Well, that's what I would do.
548750
Rs 2000 in T years is worth Rs 2000/(1+r)^T today, where r is the required return. \nWith r=0.1 and T=5 we find Rs 1241.84
207251
Based on the rule of 72 your asset will double in 11.1 years.  \nHere is how the rule of 72 works;\n\n\nThis teaches you how to determine the number of years it will take for your investment or debt to double in value.\n\nDivide the number 72 by the percentage rate you are paying on your debt, or earning on your investment. Here are two examples...\n\nYou borrowed $1,000 from your friend, who is charging you 6% interest. 72 divided by 6 is 12. That makes 12 the number of years it would take for your debt to your friend to double to $2,000 if you did not make any payments.\n\nYou have a savings account with $500 deposited in it. It earns 4% interest from the bank. 72 divided by 4 is 18. It will take 18 years for your $500 to double to $1,000 if you don't make any deposits.\n\nRemember: 72 divided by the Interest Percentage is the number of years it takes to double.\n\n\n\n\nFor a calculator that you can use to determine how long it will take to double your money based on interest rates check this out.....
40870
Under straight line method,\nAnnual Depreciation = (Cost - Salvage Value)/Life time\nHere \nAnnual Depreciation = (30,000 - 2,000)/4\n                    = 28,000/4\n                    = $ 7,000 \n\n\nhttp://www.futureaccountant.com/\nhttp://www.schoolingkids.com/
665464
Goose is right. The formula is:\n\nFV = P x e^(r x y) \n\nwhere FV = Future Value; P is your principal, r is the annual interest rate and y is the number of years of continuous compounding and e = lim(n-->inf) of (1+1/n)^n\n= 2.7182818.(about)\nHere's link which explains it quite well and also has a periodic/continuous calculator to fool around with.\n\nhttp://www.moneychimp.com/articles/finworks/continuous_compounding.htm
46057
For those of you not familiar with the rule of 70, it goes something like this:  If you invest your money at X percent, it will take 70/x years to double.\n\nHere is why it works. Suppose that x = X/100 (10% is really .10 = 10/100)\n\nIf you start with a principle amount of P and invest it at rate X, after n years you have P(1+x)^n\n\nYou want to solve for P(1+x)^n = 2P or  (1+x)^n = 2.\n\nTake ln of both sides you get ln((1+x)^n) = ln2\n\nnln(1+x) = ln2\n\nln(1+x) = ln2/n\n\nThe Taylor series for ln(1+x) is x - x^2/2 + x^3/3 - x^4/4 + ...\nFor small values of x, ln(1+x ~ x\n\nso x ~ ln2/n, and X ~ 100ln2/n.\n\nln2 = .6931... so  X ~ 69/n and n ~ 69/X\n\nTo see how accurate it is, you have to look at the size of - x^2/2 + x^3/3 - ... which is relatively small since you are generally talking about values of x < .1\n\nI think the reason for Rule of 72 is that 72 is divisible by 2,3,4,6,8, and 12.