My friend and I have this little quarrel about this problem, and we need an answer. Someone sold 50 tickets for a baseball game, each adult ticket going for $5, and each student ticket going for $3. He earns $180 dollars from this. How many adult tickets and how many student tickets have been sold? Please list both separately, and write down the mathematical expression you used to solve this. We're trying to see if this might have multiple answers.
123098
35 Student tickets\n15 Adult tickets\n\n5a+3s=$180\na+s=50\na=50-s  solve for a\n\n5(50-s)+3s=180  substitute the value of a into the equation\n250-2s=180\n2s=75  solve for s\n\ns=35\na=50-s=50-35=15
442944
OK.\n\nThe problem specifies that x is the amount John gets a week, so we need to express everything in terms of how much John gets.\n\n"Peter gets twice as much pocket money as John"\n\nP = 2x\n\n"George gets $3 less than Peter"\n\nG = P - 3 = 2x - 3\n\n"Altogether the three boys get $17"\n\nx + P + G = 17\nx + 2x + 2x - 3 = 17\n\nYou can solve from there.
463372
Tickets go on sale to students through a lottery system and alumni before they are available to the public. Therefore, most of the good games are sold out before they are even posted to the public. Trust me i know. I had to pay $1400 for unc vs. duke tickets off ebay...a christmas present for my bf. Ebay and stubhub.com are the only ways i know how to get tickets to any decent games. Unless you want to go during christmas break...notice how those are the only games not sold out because students are gone.
622487
First you need to write down the equations:\nLet x be number of $5 tickets and let y be the number of $2 tickets. Then,\n(1)   x +   y =   56\n(2) 5x + 2y = 208\n\nThen here are the steps to solve them:\n1)   x +   y  =   56   ===>  x  =  56 - y\n2) 5x + 2y  = 208   ===> 5 (56 - y)  +  2y =  208\n3)                                     280 - 5y   +  2y  = 208\n4)                                                     -   3y  = 208 - 280 =  - 72\n5)                                                           y  =  72 / 3      =     24\n\n6)  x  +  y  =   56   ===>  x + 24 =  56\n7)                                     x         =  56 - 24 = 32\n\nProof:\n1)   x +   y  =  56   ===>  32 + 24  =  56\n2)                                             56  =  56 \n\n3) 5x + 2y  =  208 ===>  5 (32) + 2 (24) = 208\n4)                                     160    +  48      = 208\n5)                                     208                  = 208\n\nSo, the number of $5 tickets are 32, and the number of $2 tickets are 24.
355214
A few questions - unless I'm missing somethiing here.\n\n1.  Each team has to play 19 games in order for all to play each other?   That means 190 games in that time frame?\n\n2. Not familiar with the term 'pitches'.  Is this another word for 'playing fields' ?  \n\n3. If it's youth football - is there a time limit to the game?\n\n4. Do you have to schedule a playoff at the end?\n\n---------\nOK -  You obviously sustained a moment of insanity when you volunteered for this.  \nYou have your hands full on this one. \nI'm still trying to digest it all. \nWill let you know if I come up with something.\nGood luck Mom!
246633
So where's that starting point?  Either we start (yesterday) with Mary having $785.63 we subtract $57. and $125. for 603.63.  Then we add $57.25 for a total of 660.88 (B) \nOR\nwe start we $785.63 (today) anb subtract $57. and $125 for $603.63 (C).  The $57.25 doesn't matter cause Mary did that yesterday....
386281
Ticketmaster is tricky, I and several people I know have tried to make sense of how their allocating of seats works but there doesn't seem to be any reason behind it. It càn pay off to check seats a few times.
421819
Each ticket "t" is worth $3, or 3t in dollars for all tickets sold.\n\nOn Friday, you sold 100 tickets, so 3(100) = 300.\n\nOn Saturday, you will sell t tickets for a total revenue of 3t for that night.\n\nTotal revenue is 300 for Friday and 3t for Saturday, 3t+300, which is e, and factoring out 3, you get 3(t+100) which is a, so answer is:\n\na and e.
440430
Let x = number of ride tickets.\n60 = 3x + 12\nSubtract 12 from each side\n48 = 3x\nDivide both sides by 3\n16 = x\nAnswer: 16 ride tickets.\n\nCheck.\n16 tickets at $3 each would cost\n16*3 = $48\nplus the $12 in refreshments\n48+12 = $60
38865
is there more than one answer?  it seems like it since with the information you get, you can only make two equations, but with three variables.  anyways, here's one possible answer (i must say it wasn't much of a brain teaser):\n\n56 mice, 41 cats, 3 dogs\n\n[[edit]]\n\nah yes, the guy below me got it.  never realized to make those two equations equal :)
198054
Nothing is lost. Their contribution is 47$ (23.5 $ each). This sum includes the 2$ for the cab, so the 2$ should not be added again to get the 49 sum.\n\n25$   25$\n---------\n1.5   1.5.......back\n1     1.........cab\n22.5  22.5......pen cost\n---------\n25$   25$\n\n=>Each paid 23.5$, the shop received 45 (22.5 from each), and the cab received 2$(1 from each).
83501
ok so for A, the first set has 2 seats. so between the 2 seats, theres 2.5feet of steel. and then from each seat to the end, theres 2 more feet (on each side) so thatz 4 feet + 2.5feet = 6.5 feet for the first set.\nfor the 2nd set, 3 seats so 2*2.5 between the seats (2.5 between seats 1 and 2 and then 2.5 more between seats 2 and 3) + 4 =9feet of steel for the 2nd set.\nfor the 3rd set, theres 4 seats so that means (3*2.5) + 4 = 11.5feet of steel.\n\nso you should get the pattern hopefully. if theres 5 seats, then 4*2.5 + 4. 6 seats is 5*2.5 + 4.\nso then the expression would be [(n-1)*2.5] + 4. i dont really know how to explain why its correct. i guess you could just say  it works and it makez sense. for n seats, theres n-1 gaps between the seats and each gap is 2.5feet long. and then theres alwayz 2 feet on both ends added to it which is the +4. \n\nanywayz hope this helps. let me know if u need mroe help or whatever. laterz
625535
I may be barking completely up the wrong tree here. Are you comparing one ratio with another?\n\nIn the first, there are 45 parts, in the second there are 19.\n\nMost math problems have a glimmer of sense about them, in that when you hit upon the right way to solve them or what they are really asking, the calculation is quite easy.  I was expecting the number of total parts in each expression to be an easy multiple of each other, which they are not.\n\nIf you are expected to apply the first ratio to the 18 side of the second, that looks a little more reasonable (45 and 18 are both multiples of 9.)\n\nDoes that help without seeming to? (Also I understand you to mean 'factor' and 'easy')
546795
It looks like the price is $85.  I did not see a special "student" price.  However, I'm assuming student tickets were sold as season packages and individual tickets will be hard to find.
211063
The waitress calculation is wrong...\n\nYou me and Sally gave the waitress $10 each for a total of $30.\n\nThe waitress gave back $5\n\nWe gave the waitress back $2.\n\nTherefore, the waitress has $30 - $5 + $2 = $27
200013
There is not enough information.  You are leaving something out.  Did they sell twice as many $1 tickets than $2 tickets, or what?
108465
First of all, you know that the total money collected was 57444 * 2, which is 114888.\n\nNext, you know that you have only 202 prizes.  Of those, three of them were valued: 2000, 1500 and 1000.  Keep in mind that after those three prizes, there are 199 prizes left, I'll get to that later.\n\nThe first three prizes will take a total of 4500 from the initial pot of 114888.\n\nNow, since each following prize is 5 less than the one before it, it is a summation of the next 199 prizes starting at an initial prize value of 1000 minus 5.  (Remember, each following was 5 less than the one before it.)\n\nSo, the summation is the sum of each value of the equation: (1000 - (5 * x)) where x starts at the value of 1 and increases to 199.  So this is the sum of: 995 + 990 + 985 + ... + 5.  The result of which is 99500.\n\nSo, 99500 + 4500 is the total amount paid out in prizes, being 104000.  Subtracting that from the initial intake of funds on $2 tickets leaves a total pure profit of 10888.\n\nNot a bad profit, it was almost like asking about one out of six of those people to just 'give' you one dollar. :)