any matheatical equations that will give me an answer of 27
137843
27 + 0 = x\n26 + 1 = x\n25 + 2 = x\n24 + 3 = x\n23 + 4 = x\n22 + 5 = x\n21 + 6 = x\n20 + 7 = x\n19 + 8 = x\n18 + 9 = x\n17 + 10 = x\n16 + 11 = x\n15 + 12 = x \n14 + 13 = x\n3 = cube root of x\n3^3 = x\n3 = log(x)\n3 * 9 = x\n27 - 0 = x\n28 - 1 = x\n29 - 2 = x\n...(you get the point)...\n2 * 14 - 1 = x\n27 * x^0 = x\n27 = x\n3.14159265*8.59436693 = x
232425
2^(1/3)=1.26\nif the next term is\n\n2*(-1/3)=-.667\nx=2^(1/3)-2*(-1/3)=1.92\nand\n2*x^3+6*x=25.86\n\nor if you meant\n\n2^(-1/3)=.7937\nx=2^(1/3)-2^(-1/3)=.466\nand\n2x^3+6x=3
416563
First, not all of the things you typed showed up, put spaces in and we'll be able to see it all.\n\nSecond, I don't know what you need help with. You just have a bunch of algebra, but no equations.\n\nPlease clarify your question!
444927
well Honestly dear Megan i don't think its correct , coz equation should have ONE " = " \n\nit must be something like this \n-4r ² ± 21r=r+13\n\nGood Luck
567069
42 - 7 * 2^2 + 3 * sqrt(25)\n= 42 - 7*4 + 3*5\n= 42 - 28 + 15\n= 29
45011
Use a calculator - numerator divided by denominator will give you the answer.
549069
y = 8\n\n2 + 3y\n\n2 + 3(8)\n\n2 + 24\n\n26\n\nThe answer is 26\n\n-- - - - - - - - - - - s-
415169
27=3x3x3\n189=3x3x3x7\nto calculate lcm, just cancel out (one each of the pair of) the numbers that appear twice; you're left with 3x3x3x7, or 189.\nApparently your other respondent thinks if he can't do it it can't be done...
467309
the truth about this is find the right formula for this equasion, then set it with ur need of what space you put it in to example : =sum(a1:a28)
540549
All of them can be written:\nA. 6 + 24 = 30\nB. 10 x 3 = 30\nC. 126 - 54 = 72\nD. 126 -63 = 63
482116
Divide 840 by the answer from this equation (0.08 - 1), then you can solve for "y".\n\nGood luck!
260334
here are the answers:\n-17x-19 for the first one \n22x+1 for the second one\n-6x^2+3x+15 for the third one, which can also be written as -3(2x^2-x-5)
459698
1. 14x^2 +21x\n\na good way to start would be to factor out any common terms:\n\n7(2x^2 + 3x)\n\n7x(2x + 3)
101971
That problem is written somewhat wrong.  You can re-write that problem as \nx - .3x = 1925 \nsubtract .3x from 1 x and you bet\n.7x=1925\ndivide both sides by .7 and you get\nx = 2750
155497
Mathomatic version 12.5.10 (www.mathomatic.org)\nCopyright (C) 1987-2006 George Gesslein II.\n50 equation spaces available, 960000 bytes per equation space.\n\n1-> 49x^4-14x^3-28x\n\n#1: (49*(x^4)) - (14*(x^3)) - (28*x)\n\n1-> factor\n\n#1: x*(((x^2)*((49*x) - 14)) - 28)\n\n1-> quit\n\n\nsteve@saturn /usr/home
343549
Yes you're correct - just plug in -2 for x to get: \n \n20 - -6 + 1 = 27
222220
just pick any number and substitute it for x. lets try 10.\n\nw=4(10)-1   w=39\nx=7(10)+3   x=73\ny=3(10)-4   y=26\n\n\nso the answer is   x, w, y\n\nedit::\n\nmaybe next time you could ask the right question? you asked for the lengths of the SIDES, not the ANGLES. >:(