Please solve, show your work, and if possible give a brief explantion of how to do the problem.\n\nThanks
138075
You need to first find 2 numbers that multiplies to give you a -4 and adds to give you a negative 3.  -4 and 1 work.\n(p^2 -4) (p^2+1) = 0\n\nThen, set them both = to 0.\np^2-4 = 0\np^2 = 4\np = 2\n\nand P^2 +1 = o\nP^2 = -1\nP = the square root of -1, also known as i\n\nFINAL ANSWER: P = 2, and i
400650
I believe you will find the solution to your problem here:\n\nhttp://www.engineeringtoolbox.com/bernouilli-equation-d_183.html
128237
Basically this question is one of trial and error. You have to think of the many possibilities and try eliminating some to get the desired results. It would be mind-boggling to finish these questions off in half an hour.
235734
I think there is something wrong with the problem.The given details are not sufficient.Any how if you find the answer for it please email me.Lemme make use of it.
391172
I'm unclear with the way you stated the problem. Am I looking for a implicit derivative. I'll check back to solve it.
247484
Please see the method explained by me as an answer tothis question..\nhttp://in.answers.yahoo.com/question/index;_ylt=AiNJtRa.xTUMUTdP29hR7sSQHQx.?qid=1006051102360\n\nThis will help u solve cubic as well as other equations.. :-)
283199
This is very straightforward. Which step are you having trouble with? The same goes for your other question.
490217
I could not understand head and tail of this problem.Please send the proper problem immediately so that it may be solved.
446355
r = 0 is one solution.\nThe other one is impossible to find exactly; the best you can do is a numerical approximation, which gives r = 0.0809394, approx.
80080
Sorry, but I think you need to do this yourself.  Here are some guidelines though; give them a try.\n1.  Make a line drawing so you can see the info you're given and the path to the required answer.\n2.  Make a list of ALL the related formulae you were given.  Check each one against the given data; if you find one in which you have all the variables EXCEPT one, substitute and solve for the unknown.\n3.  Sometimes, you may have to use one formula to find a variable and THEN use that in ANOTHER formula to arrive at your ansver.\n\nGood luck!!
625630
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
645627
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
90027
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
527006
I won't show in details since it's hard to type out the work, but you'll get the rest, here it goes:\n\na)\nWork = mgd  *d=change in height\nW = (10kg) (9.8m/ss) (sin15) (-7.5m) = -190J\n\nb)\nW=(friction coef)(natural force)(distance traveled)\nnatural force = (cos15)(10kg)(9.8m/ss)\nW= (0.4) (cos15) (10kg) (9.8m/ss) (-7.5m) = -280J\n\nc) \nW=Force x distance\nW=(100N)(7.5m)=750J\n\nd)\n(initial KE)+ (puller work)=(gravity work) + (frictional work) + (final KE)\n(final KE) - (initial KE) = 750J - 280J - 190J = 280J\n\ne)\n(final KE) - (initial KE) = 280J\n*solve for final v\nv = squareroot (2 x [280j+ (1/2)(10kg)(1.5squared)] / 10kg) =7.63m/s
270754
hey dude i hav d same problem blive me n still havnt figured out d solution for dis so can any1 one help me......\nif u get d solution den email me at arein1986@yahoo.co.in
482020
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
519078
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today