A= (top) 1,2 (bottom)4,3  and plug in to solve 2A\n\nany help would be greatly appreciated thnx
138467
If A is a 2x2 matrix, then 2A means to multiply each of the numbers \n[12\n43]\nby 2 (this is called scalar multiplication)\nand you would get\n[24\n86]\n\nI hope this helps.\n:o)
284982
you have to solve the ones in the brackets first. so in this instance, 4(-1) = -4.\n\nand then, you solve -4 - 3 = -7
554928
2(x+2) +8=6\n2x +4 + 8=6\n2x +12=6\n2x= -6\nx= -3
497062
Plug in each of the four answers.  The only one that works is (2), because you get\n\n | 3 (-2/3) - 3 | = 5\n | -2 - 3 | = 5\n | -5 | = 5\n 5 = 5
516827
-8t+tw-2w+4t\n=-8t+4t+tw-2w\n=4t+tw-2w
385676
2(2x-4)= x+4\n4x-8 = x+4\n4x-x = 8+4\n3x = 12\nx=4\n\n&\n\n4(x+3)+3= 5(x-4) + 5\n4x+12+3 = 5x-20+5\n4x+15 = 5x-15\n4x-5x = -15-15\n-x= -30\nx = 30\n\n&\n\nx+2= 4(5x-2)\nx+2 = 20x-8\n2+8=20x-x\n10 = 19x\n19x= 10\nx=10/19\n\n&\n\n21-3x = 4x+7\n21-7 = 4x+3x\n14=7x\n7x = 14\nx=14/7\nx=2
345973
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
52787
the solutions is 7,8,3,2 or 7,6,5,2. The problem works with both sets of numbers.
231359
1+1+1+1=4\n2+2=4\n4x1=4\n2x2=4\n3+1=4\n1+3=4\n1x4=4\nHope that answer your question, and u could count by your fingers or u can get objects to help u
541278
Take each number, multiply by two, and then subract two.\n\n3*2 - 2 = 4\n4*2 - 2 = 6\n6*2 - 2 = 10\n10*2 - 2 = 18\n\nedit: I'm sure that the two possible answers are related.  I would also get 34, then 66, then 130 as the next numbers in the sequence.  It has to do with the fact that it started with three.  If we had started at 2, then my system would always yield 2 every time, but you guys wouldn't.  I think both are acceptable, although I will admit that the other method is more interesting.
222447
1) Assuming an aritmetic sequence\n\nbn = b1 + (n-1)d \nletting b3=a1 = 20, then b7=a5 = 32, and b25 = b23\na5 = a1 + (5-1)d\n32 = 20 + (5-1)d\n32 = 20 + 4d\n12 = 4d\n3 = d\n\nb25 = a23 = 20 + (23-1)*3\nb25 = 20 + 22*3\nb25 = 20 + 66\nb25 = 86\n=====================================================\n2)\na75 = a1 + (75-1)d; d=-3\n\na75 = 5 + (75-1)*-3\na75 = 5 + 74*-3\na75 = 5 + -222\na75 = -217\n\nSn = n/2(a1+an)\nS75 = 75/2(5 + -217)\nS75 = 75/2(-212)\nS75 = -7950\n===================================================\n3) ????\n\na5 = 5*5 - 4 = 21\na15 = 5*15 - 4 = 71\na25 = 5*25 - 4 = 121\n\nOR MAYBE\n\na1 = 5*1 - 4\na1 = 5 - 4\na1 = 1\na30 = 5*30 - 4\na30 = 150 - 4\na30 = 146\n\nSn = n/2(a1+an)\nS30 = 30/2(1 + 146)\nS30 = 30/2(147)\nS30 = 2205\n================================================\n4)\n\nrth term is nCr-1m^n-(r-1)k^r-1\n\n5th term =\n4C4m^4-(5-1)k^5-1\n4C4 = 1\n\n5th term = k^4
551877
Well dear\n\n-If the first root is " α " and the second roots is " α + 3"  so have  \n▪x ² - (α + β) + α β = 0 \n▪( x - α )(x - β ) = 0 \n-b/a = α+ β  \n&\nc/a = α β\nso we have ; \nc/a = m/4  \n-b/a = - ( -16) / 4 = 4 \nα + α + 3 = 4 , 2α + 3 = 4 \nα = 1/2  ,  β = 3 1/2 \n2 /a = α β  =>  m/4 =  1/2 * 7/2  , m = 7\n\nGood Luck dear
658759
7 apple\nfirst one 3 1/2 + 1/2           =4\nsecond one 1 1/2 + 1/2     =2\nlast one will be 1/2 + 1/2   =1
500424
bring the a's to one side... u then get 9a = 27 ... divide and answer is a = 3
519512
(-2ab^2)^2(-ab)^3 = (4 a^2 b^4) * (-1 * a^3 b^3)\n = -4 (a^2 * a^3) * (b^4 * b^3)\n = -4 (a^5) (b^7)
342519
Just plug in the numbers and solve for s...\ns=6^2-4^2\n    -----------\n       2(2)\ns=36-16\n     -------\n         4\n\ns=20/4\ns=5
460869
1) 4-3x<_8+x\n4+8<_x+3x\n12<_4x\n3<_x or x in the interval [3,plus infinity)\n\n2) 3x-3>-x+1\n3x+x>1+3\n4x>4\nx>1 or x in the interval (1, plus infinity)\n\n3) 3(x-1)_<4x\n3x-3<_4x\n-3<_x or x in the interval [-3, plus infinity)\n\n4)1/2x<x+1\n-1<x/2\n-2<x or x in the interval (-2, plus infinity)\n\n5)-1/2x>1-x\nx/2>1\nx>2 or x in the interval (2, plus infinity)