If seven different people had seven different conversations with seven different people how many conversations would that total in all?
121637
343 diff conversations
199162
Make a list of 20 spaces on a sheet or how ever many people are in the room. Everyone walks around the room trying to get the name of and some basic information about each person. They get thirty seconds then they switch and find somebody else. You can do this for 5 minutes or how ever long you want. Just a suggestion.
457628
Assuming the first stop can be any of the 10 cities, the next stop can be any one of the remaining 9 cities, then 8, 7, and 6:\n\n10 x 9 x 8 x 7 x 6 = 30240
394929
7.final answer.figured out.
224823
Count the total number of groups:\n9 choose 5 = 9*8*7*6/(4*3*2*1) = 9*2*7 = 126.\n\nb) Count the number of groups where 3 women where chosen and 2 men.\n(4 choose 3) * (5 choose 2) = 4 * 10 = 40.\n\nThe prob that a random committee has exactly 3 women = 40/126\n\nc) If there were no women then the number of ways this can happen is:\n(4 choose 0) * (5 choose 5).  As you could probably already see, there is only 1 way to have a committe of 5 men and 0 women.  The prob = 1/126.\n\nf) >=3 women is the same as saying 3 or 4 women as 4 women is the most you can have.\n\n(4 choose 3)*(5 choose 2) + (4 choose 4) * (5 choose 1)=\n4*10 + 1*5 = 45.  Prob = 45/126.
670502
You asked it wrong. It's "Why is 6 afraid of 7?"\n\nCause 7 ate 9.
169310
There are 8 available seats. In the first seat any of the 8 people can sit there. Then the next seat must be the partner of that person. Then the next seat, there will be 6 remaining people who could sit there, then the partner in the next. And so on down the line. The equation would be: \n\n8x1x6x1x4x1x2x1=384
118235
aproxamately 16438356.164383561643835616438356\n\nassuming an equal occurance of people being born each day of the year and a world population of 6 billion
501001
if there were 12 groups each with 1 cheerleader in....you will have 12 groups
471225
this is like statistic..in one side u have 14 individuals and the other side u have 16 individuals so when you test the difference of 2 population take 14 out of each of population and the sum of that is 28 so,...28 is the answer....lol
432185
once we chose 5 persons for one committe then other committe members get fixed.\n\nThe 5 members can be chosen in 10C5 ways = 10*9*8*7*6/120\nor 6*7*6 or 252 ways
101274
I can't count, so don't blame me if I get this wrong.\nLet n be the number of participants.\nSince it's a close circuit, the people in front of him are in a sense also behind him so there ara (n-1) people both ahead and behind him.\nso (1/5+5/6)(n-1)=n\n31/30*n -31/30=n\n1/30*n=31/30\nthus n=31\n31 total people
309200
69..\n\nand try to paraphrase your friggin homework...
608439
The answer is 10. \n\nIf you don't believe me, do the problem yourself and compare that with my answer.
52787
the solutions is 7,8,3,2 or 7,6,5,2. The problem works with both sets of numbers.
505114
If 4/7 are male, then 3/7 are female.\n\nLet x be the total number of students:\n(3/7)x = 3,600\n\nMultiply both sides by 7/3:\nx = 3,600 * 7/3\n\nSimplify:\nx = 1,200 * 7\nx = 8,400 students total
5936
There are 6 combinations\n3,5,7\n3,7,5\n5,3,7\n5,7,3\n7,5,3\n7,3,5