edge on, what is the mass of the system?
128972
I got a combined mass of ~11 solar masses.  The masses of the individual components of course, would be impossible to tell from the information given alone.
454667
MASS / VOLUME\n that's way you measure it in g/mL
522027
The point to note is that the mass of the water in the cylinder is continuously varying.\nMass of can = M (constant)\nMass of water = M*(x/H)   -- because it is proportional to the height of the water column.\nCentre of mass of can alone (from the bottom)  = H/2\nCentre of mass of water = x/2\na) Centre of mass of the system = (Mass of can * cm of can+Mass of water * cm of water) / (Mass of can+Mass of water) \n = {(M*H/2) + (M*x/H)*x/2} / (M+M*x/H)\n = 1/2 (H^2+x^2)/(H+x)\n \nb) The value of x for the minimum height of the cm can be found out by putting d(cm)/dx = 0\n This gives, x = H*(sqrt2 - 1). \n At this value of x, the cm turns out to be:\n cm = H*(sqrt2 - 1).
386383
Hi, \n\nYou want to calculate the total kinetic energy of the system which is:\n\nKE= 1/2 Iw^2 \n\nso I = I(stool,and person) + I(masses)\n\nThe moment of the person and chair is listed in the question.\n\nI(masses) = mr^2 = 1.49 * (0.759)^2 = 1.73 Kg m^2\n\nSo the total Moment is \n\nI(total) = 1.73 Kg m^2 + 4.83 Kg m^2 = 6.56 Kg m^2\n\nSo the kinetic energy is \nKE = 1/2 6.56 Kg m^2 (3.10 rev/sec)^2 = 31.52 Kg(m^2/s^2) = 31.52 J\n\nThen for the final, just change the numbers to reflect the changes in the question, and you're all set.\n\nHope that helps, \nMatt
448562
good start.\n\ntotal inital momentum = 480-397.5\n\nthis is an inelasitc collision, and aferwards you have \nboth masses travelling at velocity v:\n\n(75+120)v = 480-397.5\n\nsolve for v.  This is the velocity at which they both slide.\nThe inital energy now is 1/2(75+120)v^2\n\nThis energy is converted to frictional energy:\n\ninital kinetic energy = total work of friction = Fr(distance)\n\nFr = uN = u(120+75)g = .3(195)(9.8)\n\nso we have\n\n.3(195)(9.8)(distance slided) = 1/2(195)v^2 \n\nYou know v form above.  So find distance slided.
613028
There are too many formulas to calculate that answer. You have to take in account for example, position of object to find potential energy, mass and the weight due to the gravitational force, also Force that is going to be exerted the object and the amount of that energy that will be lost. SO it is a lot to  find that out. But their is not one formula for it. Sorry, But if you do find out Let me know.
59664
On Earth, at surface level, the acceleration due to gravity is approximately 9.81 m/s^2. Weight = mass*acceleration, and so mass of flea = 5.097*10^-7 kg
642480
I think the equation W = m x g (W = weight; m = mass; g = acceleration due to gravity) might address your question.\n\nStating they are interchangeable might be misleading if the statement is not qualified by your textbook. The qualification is that when we are measuring objects from an earth reference point, for all intents and purposes, the weight of an object is proportional to its content (i.e., mass). In mathematical terms, the assumption would be, W = m * 1. \n\nHowever, if we are measuring objects in places other than from an earth reference point, then weight and mass are not interchangeable. For example, the force of gravity on the moon is less than on earth. So as an example, the equation for weight on the moon could be, W = m * .5. With this equation, the weight of an object on the moon is less than its weight on the earth. Here is a math example to illustrate:\n\nObject (Mass) = 100 Kg\ng(Earth) =  1 \ng(Moon) = .5\n\nW(Earth) = 100 x 1\n              = 100 Kg (Object's weight on earth)\n\nW(Moon) = 100 x .5\n              = 50 Kg (Object's weight on moon)\n\nWikipedia might explain the notion of interchange between weight and mass better:\n\nhttp://en.wikipedia.org/wiki/Weight#Weight_and_mass
306791
n * MW / V = density\n\nTherefore, MW = density * V/n = density * RT/P\n\ndensity = 0.480 g/L\nR =0.08205746 L · atm · K-1 · mol-1\nT= 533.15 K \nP=0.140 atm \n\nMW = 0.480 * 0.08205746 * 533.15 / 0.140  = 149.996 g/mol\n\nIf your teacher is a stickler about significant figures, then the answer is 150. g/mol (don't forget the period)
445026
Take the mass 3M on the ramp.  The weight of the mass 3Mg will have a component 3Mg(cos(theta)) along the ramp; (theta is the angle the ramp makes with the vertical).\n\nThis will be the force acting on it along the ramp, downward.\n\nThe upward, along the ramp force on it will be Mg, the weight of the hanging mass.\n\nIf Mg > 3Mg cos(theta) the block will move up.  If Mg < 3Mg cos(theta), it will move down.  if the two are equal, it remains stationary.\n\nOr,\ncos(theta) < 1/3 , moves up\ncos(theta) = 1/3 , stationary\ncos(theta) > 1/3, moves down.
487655
Oh dear.  You should be able to do this one.  You simply need to calculate the mass of the core and divide by the total mass.  You have a density and a radius.\n\nMultiply the density of the core by the volume of the core (be sure you use the same units!)  I will leave it to you to look up/remember the equation for the volume of a sphere.\n\nTake the result and divide by the total mass. Are you sure that is the density, btw?  It seems awfully light for iron at the center of the Earth.  Even water has a mass of 1000 kg/m^3.
193261
*copied from previous post\n\nYour question is unclear about what set of assumptions you want to use. You seem to imply a perfectly constructed stool, with a perfectly centered force, using incompressible material. You want the stool to have no mass, and you imply that you want to use statics to solve this problem. Strictly applying statics, this system is indeterminate, NOT the ridiculous answer of 0 [N] in two legs and W/2 [N] in the others. There are only 3 equations of equilibrium here, 1 for vertical forces and 2 for moments. Since you have four legs, this system cannot be solved by statics alone. Treating the stool as a deformable structure, you can use geometric compatibility to get a fourth equation. I challenge you to find a competently built stool that has 0 [N] in any leg (a physical stool built of real materials), or an incompetently built stool with 0 [N] in any two legs (unstable system that is obviously not static). The answer indicated as "correct" requires an incorrect application of statics. A large part of studying physics is learning when to use a particular tool, and the physical limits of that tool.
382378
you divide the mass by the volume\n1.2.14 g/cm^3\n2..82 g/cm^3\ngood luck!
473517
If you're using m to indicate the mass, the differential equation should be:\ndm/dt = km\nIf you're using y, then:\ndy/dt = ky\n\nThe error in your answer is that you are alternately using two variables, y and m, to indicate the mass. Pick one and stick with it.
404563
Consider a mass m on the surface of \nEarth. The equation governing this mass\ncan be written as\nmg=G*m*M/R^2\nm=mass of the object=kg\ng=acceleration due to gravity=9.81m/sec^2\nM=mass of Earth kg ?\nR=radius of Earth=6.4*10^6m[given]\nG=universal constant of Gravitation\n=[6.6742+-.0010]*10^-11Nm^2kg^-2\nCanceling m we can write\nM=g*R^2/G\nYou have all the values\nSubstitute and get Mass of Earth.
15320
The force on the system is 3.0 kg x g. (the only force is due to gravity acting on the hanging mass) The mass of the system is 3.0 kg + 5.0 kg = 8.0 kg.  The acceleration of the system is a = force/mass = 3.0 kg x g / 8.0 kg   =  3 / 8 g or 0.375 x 9.8 = 3.675 m/sec^2
373006
I won't do all the sums, but here's the idea:\n\n- You know the radius of the circle, and the angle, and thus the pendulum's height off the ground.\n- Thus, GPE = mass x g x height (all of which you know).\n- Energy is conserved, so when at the bottom, all the GPE has been transferred into Kinetic Energy = 0.5 x m x v^2.\n- As you know the total energy and the mass, just solve the equation to obtain v.