a.  changing gravitational force toward Earth\nb.  net gravitational force toward Earth\nc.  changing acceleration away from Earth\nd.  net acceleration away from Earth
128435
B.  The acceleration is towards the Earth and the force is constant.
327992
Every atom has gravitational forces, also known as the "VanderWaal force". This force is linearly related to the mass of the particle. As the mass grows (a cluster of particles, an object, a planet) the gravitational force gets larger, being the sum of all individual gravitational forces. The gravitational force only influences objects that have a mass of there own. So a ball is attracted by the Earth and the ball attracts the Earth.
439811
it is the force of gravity it's simply 9.8 m/s/s or 32ft/s/s     \nacceleration of gravity is -9.8m/s/s or 32ft/s/s\ng force is just the absolute value
210095
Gravitational potential = G *Mass of the earth/radius of the earth.\nIn other words its equal to Gravitational energy per unit mass.
71275
Besides the intense heat and pressure, gravity would be the major force acting on you (say if we lived in a world with no air resistance.) As you would get closer to the center of the earth you speed would be increasing, but once you start pulling away from the center you speed would be slowing down due to gravity pulling on you from the opposite direction. At the opposite side of the earth you find yourself to come to a standstill for a brief second until you get pulled back inward toward the center and emerge on the same side of the earth in which you started. You would be stuck in this cycle going from either side of the earth until someone threw you a rope and are able to pull yourself to the surface.
522615
zero, \n\nno acceraltion = no net force\n\nmathematically  Net F = ma\n\nif the right side is 0, left side is too
3392
ok, well the formula you need is:\n\nFg=Gm1m2/r^2\n\nwhere Fg is the force of gravitation, G is the universal gravitational constant(just a constant, you dont have to worry about it) m1 and m2 are the masses of the 2 objects, and r^2 is the distance between the two objects squared.\n(a) ok, so if r increases by 10 times, since r is squared, the denominator would actually increase by 100 times.  Since the denominator increases by 100 times, and the numerator stays the same, you're basically multiplying it by (1/100) so that means that you have to do the same thing to both sides, so you just multiply Fg by 1/100 so thats 500/100 so the answer is 5 newtons.  This makes sense because the farther objects get from each other, the less each other's gravity will affect them.\n\n(b) ok, now one of the m's, lets say m1 doubles.  The rest stays the same again, and this time its in the numerator, so you're just multipying the whole thing by 2, so the new force would be 1000 newtons.  This makes sense, because something with more mass would experience more gravitational force, for example, a person with more mass experiences a greater gravitational force with the earth, and therefore weighs more.
76842
2 masses dropped from a given height are subject to air resitance (assumed: only phy resistance)...thus earth's pull on either is same & ofcourse insignificant. On the contrary two masses rolled from the top of a slope are subject to the earth's terrain & friction. Also it is believed that the earth's gravitational pull could slightly vary  from point A to B. These "could" cause a variance in their acc.\n\nI believe we're looking at objects of the same mass here.
61676
*is a center-directed force\n\n\nnot "*acts as an unbalanced force on the satellite" because, it is balanced by centrifugal force. \n\nnot "*changes the direction of the satellite" because direction is changed by only tangential forces and not the force acting towards center.
115713
gravity.\n\nany shape of mass that is not spherical is gravitationally unstable
407832
To understand this quandary you must look at a much bigger picture. since gravitational force is determined by an objects mass the earth actually exerts a much greater force on the object than the object exerts on the earth. Now this is where you must remember Newton's second law - if an unbalanced force acts on an object the object will accelerate in the direction of the force. The unbalanced force is the force of gravity the larger mass (earth in this case) exerts on the smaller object. The acceleration in the direction of the force is what we call gravity. It is true that the object exerts a reaction force but the maximum force it exerts is only the force of gravity it can generate based on it's mass. Since it weighs less it's force is not strong enough to move the earth.
500476
1D\n2D (acceleration can be negative in which case you mihgt call it deceleration)\n3B
207059
1. Diferentiation\n\n2. Outgassing\n\n3. Spring (vernal) equinox\n\n4. This is just presession, the natual motion of a spinning body in a graviational field. not sure what "forces" you are looking for.\n\n5. It marks the equinoxes, the days of the year of even amounts of sun and dark, and we start several of our coordinate systems from the point of the spring equinox.
248448
gravitational pull is different in different places on earth. but it is fixed. we cannot change it locally or globally. bcoz it depends on earth's mass, which we cant change.
148446
Gravity is also like another force. it follows Newton's 3rd law. Earth attracts us and we attract Earth.\n\nBut a = f/m. Since our mass is less, we move with greater acceleration. For earth, mass is huge and the effect is negligible.
515342
forces are opposite and equal, otherwise you would change speed/direction.
356458
All objects are pulled by earth with constant acceleration\n\nAcceleration is change in velocity per unit time = change in velocity / time\n\nIn one second the velocity changes by g unit.\nIn t seconds it velocity reduces by gt.\nIf u is the initial velocity and if in t seconds it is reduced to zero then u = gt.\n\nOr t = u/g.\n\nThe time to go up is u/g.\n\nThe height it has gone up is given by average speed x time. = u/2 x t = u/2 x u/g = uu/ 2g.\n\nWhen it falls down it starts with zero speed, but falls with the same acceleration g.\n\nWhen it reaches the ground let its speed is v and time of fall is t2.\n\nv= gt2.\n\nSince the distance is = average velocity x time = v/2 x t2 = gt2/2 x t2= gt2t2/2  \n\ngt1t2/2 = uu/ 2g. or t2t2 = uu/ gg  ot t2 = u/g .\n\nThus time of fall is equal to time of up.