you have 3 houses on top in a row. then you have h20, gas and electricity in a row underneath the houses. all 3 houses have to have h20, gas and electricity w/o crossing paths w/ any other lines. and no lines can connect w/ eachother. how do you solve this brainteaser? I have fried my brain trying to figure this one out
122477
Build the houses on a planet shaped like a giant doughnut.
620429
Most of them got it right.\n\nThis is another way to think about the result.\n\nFirst player = T or H doesn't matter\n\nSecond Player = Must be that same as the First Player\n                        =  only 2 possibility (H or T)\n                        = 1/2\nThird Player = Must be the same as First Player\n                    = again, only 2 possibility ( H or T )\n                    = 1/2\n\nIn order for the Second Player and Third Player to have the same result as First Plaer = 1/2 x 1/2\n                                 = 1/4.
512161
You haven't given me any information with which to solve this problem.  How big are the blocks?  How much do the blocks weigh?  How far apart are they?  How much resistance is there when I push the first block?   How fast is the first block going when it is pushed?  Without all this I cannot figure out how much momentum is lost between the time the first block is pushed and when it hits the second block or if the second block will have enough momentum to move at all or make the third block move if it contacts it.\n\n\nBy the way, you cannot solve this without knowing how much each block weighs, how much momentum it has to begin with, how much friction there is (to reduce momentum), and how far each block has to travel before it contacts the next one.    You need to have the variables to create a formula. \n\nGeeze, don't you hate it when idiots try to act smart????
33882
How about this? Straight multiplying gives you the following:\n\n18b^3/b^2\n\nb^3 = bxbxb\nb^2 = bxb\n\nYou have 3 bs on top and 2 on bottom. Whenever you have the same number on top and bottom, it cancels out. Since there are 2 bs on bottom, 2 of the ones on the top cancel out as well. This leaves you with 18b.\n\nDid that help at all?
646154
Storage_ I corrected a miscount.\n\nThe answer is 12+24 = 36\n\nPlanes that include 4 vertices = 12\n\nobviously the six faces = 6\nPlanes that pass through the two parallel diagonals of opposing faces. There are two of these for each face but since they join two opposing faces there are 2*3 = 6\n\n24 planes that include only 3 vertices\nFor each face of the cube there are two diagonals and each digonal belongs to two planes that pass through the two vertices which are kitty corner to the end-points of the diagonals. this gives 2*2*6 =24
299618
Mkay, I will explain how to play MASH. First, get out a piece of paper. Write M.A.S.H at the top of the paper. (Mansion, Apartment, Shack, House) and pretend you have a friend with you because this is just practice so you get the hang of it. Make 6 columns with 5 lines in each and title the first column Girl/boy, title the 2nd column cars, 3rd is colors, 4th is job, 5th is number of kids, and 6th column is State. You must pick 5 girls/boys, cars, etc. At the top of the page your friend will keep drawing straight lines until you say "STOP!" and then when you do say stop, your friend will count the number of lines. (Hint: it's best not to have so many lines!) Lets say you have 8 lines. Your friend will keep going down the list and every 8th thing she comes to (car/house/etc) she will cross out the kind of car/house/etc you put there then she will keep going until you have one choice let out of the five. Once you're left with one choice under each of the categories you will say "I live in a (M/A/S/H) with my husband/wife insertnamehere who is a typeofjobhere and we drive a *color* carname with our #ofkids in statename" If you want to play it online you can! Go to the site I provided under my sources. Have fun!
205
That's the trouble with answers that give no explanation. Who can you believe?\n\nSince we go in each direction once, the ORDER of the moves doesn't matter. \n\nDraw a grid. Start at 0,0\n10 North means 0,10 You are due north 10 miles. Then we come back south 6 miles, so we're 4 miles north of where we started. \n4 miles east and then 7 west means we're 3 miles west of the starting point. \n\nDraw a right triangle 4 miles up and then 3 miles to the left of the starting point. We want the hypotenuse of the triangle whose sides are 3 and 4. \nTime for Pythagoras: a^2 + b^2 = c^2 \n3^2 + 4^2 = c^2 \n9 + 16 = 25 Take the square root of that for your final distance. Direction: NW
603235
To get your answers, imagine what has to happen.  \n\na) First, you have to pick 1 of the 4 white balls out of the 12 balls there.\n\n2nd, you have to pick 1 of the 3 white balls left out of the 11 balls there.\n\nSo, in order to get a red and then a red, you need to get 4 out of 12 followed by 3 out of 11 or 4/12 times 3/11 or 12/132 = 1/22.\n\nb) First, how many ways can 5 people line up?  5!.  How many ways are correct (assuming they all have different names, only 1).  So, the prob is 1/5! or 1/120.
519962
I am only using visual techniques and not math theorems here:\n\nThe first plane will divide space into 2 parts.\n\nIf totally random the second plane will probably not be parallel with the first.  This will divide the 2 parts into 4.  If it did happen to be parallel with the first, then the space is divided into 3 parts.\n\nThe third plane will most likely not be parallel with either of the other two.  It would divide the space into 8ths.  If it was parallel to either of the other two then the minimum parts is 4 and the maximum is 6 parts.\n\nThe fourth plane will most likely not be parallel with any of the first 3, and can divide the space into maximum of 15 parts.  The fifth will make that 26.  Parallel planes will reduce this number.\n\nThe space will be divided into a minimum of 6 and a maximum of 26 parts with 5 planes.\n\nI just found a great description at the site below:
180457
Consider the point with the smallest number of neighbors, say k.  You can disconnect this point from the graph in k moves by choosing each of its neighbors in turn.\n\nIn a graph of n points and 100 edges, the point with the smallest number of neighbors can have no more than:\n\nk = Floor(200 / n)\n\nneighbors.
250306
Well you could multiply 16.5*12*14 and get the answer, but how will you get the second car to where the first car runs out of gas. Also most cars don't suck gas clear to the bottom of the tank.
44515
the riddle really goes like this: There are 3 lights and 3 light switches. The lights are in a room and the switches are in the basement. How do I see what switch goes to what bulb with only one trip up and down the stairs? \n\nAnswer: turn on switch 1 for 20 minutes and turn it off, turn on light 2 for 5 minutes and turn it off, turn on light 3 and leave it on. go upstairs and feel the bulbs. the really hot one is the 1st switch, the warm one is the 2nd switch. and the one that is on is the 3rd switch
131739
First of all you need to realized that there are the following information:\n5 people: Vic, Hal, Tim, Lon and Winnie\n5 colors: Yellow, Blue, Red, Ivory and Green\n5 Pets: Fox, Horse, Snail, Dog and Hamster\n5 Drinks: Gin, Water, Tea, Pepsi, Coffee\n5 Cars: Bike, Cadillac, Truck, Ford, and MGB\n\nDraw a 5 by 5 grid and fill in the following information.\nThese are the steps:\n1. VIC lives in the first house\n2. 2nd house is BLUE\n3. 3rd house drinks TEA\n4. This is where you need to make a decision.  The 3rd and 4th house can be IVORY and GREEN OR the 4th and 5th house can be IVORY and GREEN.  Choose the 4th and 5th house as IVORY and GREEN respectively.\n5. From Step #4 3rd house is RED and TIM lives there.\n6. 5th house drinks COFFEE\n7. 1st house is YELLOW and has a BIKE\n8. The house with bike is next to the house with a pet horse so 2nd house has HORSE\n9. Since Hal drinks water and Winnie drives MGB and Pepsi and Ford are bundled together it must be that Lon who owns a dog drinks Pepsi and drives a Ford.  There's only one house that can fit these criteria: Ivory house.  So 4th house is Ivory and LON with a DOG and a FORD drinks PEPSI\n10. HAL and WATER can only fit into 2nd house\n11. WINNIE and MGB fit into 5th house\n12. SNAIL and TRUCK fit into 3rd house\n13. House with fox is next to house with Cadillac so only spot is FOX in 1st house and CADILLAC in 2nd house\n14. GIN is drank by VIC <-- Answer\n15. HAMSTER is owned by WINNIE <-- Answer
559964
You place all 9 squares. There are 9! ways to place the pieces(without being concerned about each pieces orientation)\nFor each of the 9!, each piece can be rotated into 9 positions. So there are going to be 4^9 possiblities.\n\nOnce you find the correct solution, you can rotate the entire puzzle 90 degrees 4 times.\n\nso the correct number is 9!* 4^9 /4\n9!*4^8\n= 23,781,703,680\n\nNOTE--To the people who are answering 9!*4^9\nWhat would the possible solutions be if there was only one piece?\nWould it be 1!*4^1 =4\nNo, it would be 1/4 of that.\n\nIf there is a similar puzzle of NxN size\nthe solution would be (N^2)! *4^(N^2 -1)
159182
I love this riddle, haven't seen it a while... quite simple :) okay its takes a while: $25 to hotel, $2 for bellboy in transit, $3 returned to the GUYS = $30. Each guy DID spend $27, plus the $2 bellman pocketed (tricky part is do not add but SUBTRACT!) they had no idea they're supposed to spend $25! should've stayed home, lol
315572
The best method to solve these type of problems is to sove them through VENN Diagrams. First draw a rectangle which is the sample space, then draw three circles intersecting each other wjich are E, F AND G. The common region between E & F is P[E n F] and so on. It is quite difficult to explain this in writing but I hope you have understood. Now by drawing Venn diagram I have tried to solve ur questions.\n\nPr[EuF'] = P[E] + P[F'] - P[E n F']\n         = 0.35 + (1 - 0.5) - (0.35 - 0.1)\n         = 0.6\n\nPr[F'nG']= 1 - P[F u G]\n         = 1 - ( P[F] + P[G] - P[F n G])\n         = 1 - ( 0.5 + 0.45 - 0.3)\n         = 0.35\n\nPr[E'nG] = P[G] - P[E n G] = 0.45 - 0.2 = 0.25\n\nI think above answers are correct and hope they help you!!
230456
well chinaren got it started but I believe his explianation is weird.\nLets assume x=3^t\nthen log3(x)+log2(x+1)=3\n=>log3(3^t)+log2(3^t+1)=3\n=>tlog3(3)+log2(3^t+1)=3\n=>log2(3^t+1)=3-t\n=>3^t+1=2^(3-t)\n=>3^t+1=2^3/2^t\n=>(3^t+1)*2^t=2^3\n=>3^t*2^t+2^t=8\n=>6^t+2^t=8\nfrom here there is one one solution possible as t=1\nso x=3^1=3