how to measure mass using electronic top balance.\n how to measure mass using manual top balance?
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Volume is defined as the amount of space occupied by an object. Density is defined as the amount of mass per unit volume.In other words If there are two objects of volume one litre, And the mass of the first is greater, then the density is also greater.\nDensity=mass/volume. Hope that cleared your concept.
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It's called an inclinometer - here are some ideas:\n\nhttp://www.exploratorium.edu/math_explorer/tfl_howHigh_inclinometer.html\n\nHope this helps!
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The last poster needs to have his dynamic physics retaught, or stop trying to sound like an engineer.\n\nThe first mistake, is identifying newtons = force x distance.  This is actually a measure of work or energy and measured in joules.  The second mistake identifying force as being measured in joules.  Force is measured in Newtons.  Since it was Isaac Newton in the second law of motion that defined Force.\n\nYour question cannot really be answered without more information.  What is the direction of motion, horizontally or vertically?  \n\nVerically?  Then 150 lbs of force.  Pounds were once used to measure force.  If you want to use metric, convert the 150 lbs to kilograms, multiply by 9.8 and then you must exert at least this much force in Newtons to overcome the force of gravity.  150 lbs is 68.04 kg.\n\nHorizontally, what type of surface?  Determine the coefficient of friction, and multiply it by the mass in kilograms.  Then this is the amount of force you need to exert to overcome the force of friction.  There are two types of friction, static and dynamic.  In other words it takes more force to move an object at rest, but once the object is in motion it takes less force to keep it move (opposing the dynamic force of friction).\n\nWatts by the way is a measurement of power, which is energy derived by time, Power = dE/dt.  Joules per second.
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Oh good grief.  If it's anything like what I've just done it'll include velocity, centrepetal forces, magnetic fields, friction, gravity, forces generally, working out the mass of something and the speed at which it will fall, balances with pivot points, static electricity, AC & DC electricity, transformers, vectors and so on and so on.  It's quite hard but it's maths based so if you like maths, you should be ok.  I wish you luck.
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It usually helps with these kinds of problems if you start by drawing a little sketch. It doesn't have to be accurately scaled, its purpose is to help you recognize the physical relationships and to keep your signs correct.\n\nYou are dealing here with rotational motion. You should be familiar with the relation: (alpha) * J = T, where (alpha) means the rotational acceleration, J is the rotational moment of inertia, and T is applied net torque.\n\nYour bicycle wheel has inertia. In general the rotational inertia of an object is (integral)[r^2 dm] where r is measured with respect to the axis of rotation. That's very simple in your case since all your mass is distributed in a thin ring - so r is constant, and you get J = r^2 m. This works out to 0.1941 kg m^2.for your problem.\n\nTorque due to a force applied at a distance from the center of rotation is T = r * F. Now here's where the sketch starts to become useful. The problem tells you that you have one force (123 N) applied at the rim and a second force applied to a sprocket 8.92 cm in diameter, and the net result is acceleration of 4.49 rad/s^2. And the problem tells you that the 123 N force is resisting the motion. So you get:\n\n(alpha) J = T1 + T2\nwhere\nT1 = what we seek\nT2 = -123 N * .3205  m  The (-) sign is because it opposes T1.\n\nSolve this to find T1 = 39.6 N-m\ntherefore the force required is T1/r1 = 39.6 / .0446 = 888 N.\n\nIf you have followed this you should be able to do the second part easily.
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Trick question! You can figure the VOLUME of dirt you dig up, but without the density of the dirt, you cannot calculate the mass or weight.
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That's easy! You measure it with a tape-measure and a stopwatch! Next question.
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Kinesiology II\n Physics of Motion\nI.  Force \nA.  Definition\n1.  Force = mass * acceleration\n2.  Mass is a fundamental dimension, units g, kg\n3.  Acceleration is change in velocity, units m/sec/sec or m/s2\n4.  “Weight” is a force, units pounds or Newtons\n- Pounds = mass * acceleration of gravity\n- Why your weight, but not your mass, is different on the moon\n- Gravity on Earth = 9.8 m/sec2 \n5.  Example:  A person with a mass of 70 kg weighs:\n                        70*9.8 = 686 kg*m/sec2 or 686 N\n \nB.  Aspects\n1.  Force has a point of application or origin\nExample:  location where muscle attaches to bone\n2.  Force has a line of application\nFollows the tendon\n3.  A rotational force is called torque\n4.  Force has direction\nCan be indicated in two (x,y) or three (x,y,z) dimensional space\n5.  Force has magnitude\nMagnitude is measured in Newtons\n \nII.  Rotational Force \n1.  Force (mass*acceleration) may cause rotation about an axis\n2.  Moment of force (=Torque) is equal to the force times the lever arm – the perpendicular, straight line distance between the axis of rotation and the force\n3.  Moment of force (torque) = force* perpendicular distance \nUnits:  N*m\n4.  Sign convention:  \nClockwise moment = negative\nCounterclockwise moment = positive\n \nIII.  Levers – Location of effort force, load or resistance force, and rotational axis\nA.  Three types of levers\n1.  First class\n2.  Second class\n3.  Third class\n4.  Differences between the three have to do with the relative locations of the effort, load, and the axis of rotation\n \nB.  First Class Lever\n1.  “EOR”\nO = axis or pivot point\nE = effort force (as applied by muscle/tendon)\nR = resistance (load) force (outside force such as barbell)\n2.  The effort force and the load force are located on opposite sides of the axis of rotation\n3.  Example:  seesaw\n4.  Anatomical example:  Triceps muscle – elbow extensor\nInsertion:  Olecranon process of ulna\n5.  First class levers are rare in human body\n \nC.  Second Class Lever\n1.  “ORE”\n2.  The resistance (load) force and the effort force are on the same side of the axis of rotation\n3.  The effort lever arm is GREATER than the resistance lever arm\n4.  Example:  wheel barrow\n5.  Anatomical example:  brachioradialis – elbow flexor\nInsertion:  Styloid process of radius (distal – past the center of mass)\n6.  Second class levers are rare in the human body\n \nD.  Third Class Lever\n1.  “OER”\n2.  Effort and resistance (load) forces are on the same side of the axis of rotation\n3.  The effort lever arm is SMALLER than the resistance lever arm\n4.  Anatomical example:  Biceps brachii – elbow flexor\nInsertion:  Tuberosity of radius (proximal)\n5.  Anatomical example 2:  Quadriceps group – knee extensors\nInsertion:  Patella, tibia \n6.  Third class levers are common in the human body\n \nIV.  Mechanical Advantage\n     A.  Mechanical Advantage defined as:\nEffort Lever Arm/Resistance Lever Arm\n1.  A second class lever will always have a mechanical advantage greater than one because the effort lever arm is always GREATER than the resistance lever arm\n2.  A third class lever will always have a mechanical advantage less than one because the effort lever arm is always LESS than the resistance lever arm\n3.  A first class lever can have a mechanical advantage less than, equal to, OR greater than one, depending on the locations of the effort force and resistance force versus the axis of rotation\n \nB.  Mechanical Advantage VS. Speed\n1.  The mechanical advantage of a third class lever – common in the body – is poor – always less than one\n2.  However, the SPEED of rotation created by a third class lever is high\n \n\n3.  Because the origin of the resistance force is located farther from the axis than the origin of the effort force, it must travel a greater distance in the same time\n4.  Greater distance per unit time = greater speed\n5.  Good for throwing objects, kic
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Currently, the scientific community uses the MKS system for most engineering, and beginning physics:\n\n      M = Meters (Length)\n      K = Kilograms (Mass)\n      S = Seconds (Time)\n\n...the answer is KILOGRAMS.
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The net force is the difference between the two weights.\n\nHowever, there is not enough information in the question to answer without making some assumptions.\n\nYou are not given the mass of the man and/or the bricks. One can calculate the mass if given the force of gravity, however you aren't given that either.\n\nOne method of solving is:\n\nASSUMING that this system is on the surface of the Earth, you can find the two masses, using F=mg with g=9.8N/kg. Once you've got that you can find the acceleration using F=ma since you know the net force and the mass of the system.\n\nMake sure you indicate which direction the acceleration is in (in this case, which object is falling, and which is being raised.
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I'm not positive, but I think a platform balance is weighing device with a flat plate mounted above a balanced beam.  A triple beam balance works by sliding the bars until you get the scale level (like the scale at a doctor's office)\n\nIt depends on the scale, but usually a platform balance will weigh up to 0.1 of a gram while the triple beam balance will read up to 0.01 of a gram.\n\nIt's been a while since I had a lab, but I hope that helps.
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This is Measured in MTBF or Mean Time Before Failiure. Noramlly if you know the manufacturer you can get information on that through thier website.
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The answer hippoterr... gave you was OK till the last step. It's always is wise to check the units and see if they make sense. His result is in sec/rev.\n\n2 x Pi x11.5 / 30 = 2.4 He left out the units in the math part, but if you include them you see that the result is in sec/rev.\n\nUnit conversion can be confusing. A better way - you know you want it to be something per sec so start with:\n\n30 meter/sec. Then to convert to rev/sec multiply by 1, in a special form.\n\nIn the form 1 rev/(2 x Pi x11.5 meters). This = 1, right? The top and bottom are equivalent. So back to \n\n30 meter/sec * 1 rev/(2 x Pi x11.5 meters) = .415 rev/sec\n\nYou understand why weight/mass wasn't needed? It's the acceleration that results from the rotation,  and  a = F/m.
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same mass, same weight
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find the force of her weight. \nthat should be the answer
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(m)\n\n blood pressure can be measured either by using a machine called a sphygmomanometer (spig-mom-an-om-eter) or by using an automatic machine.\n\n\nA sphygmomanometer is the older kind of equipment that measures blood pressure using a column of mercury. The person taking your blood pressure will put a cuff around the top of your arm, pump up this cuff and then listen for sounds through a stethoscope placed on your arm. The sounds heard through the stethoscope will start and then finish at certain points on the mercury column, and this will give the reading for your blood pressure.\n\n There are also automatic digital machines that can measure blood pressure. They also use a cuff around your arm and will give a readout of your blood pressure.\n\n\n\n\nWhat do the numbers mean?\n\nWhen you have your blood pressure measured, it is written down as two numbers, one over the other like a fraction. \n\nFor example:\n\n140/90mmHg\n\nIt is said as "140 over 90," for example. The top number, which is called the systolic pressure, shows the pressure in your arteries when your heart is forcing blood through them. The bottom number, called the diastolic pressure, shows the pressure in your arteries when your heart relaxes. The top number can be anywhere from 90 to 240 and the bottom number can be anywhere from 60 to 140. Blood pressure is measured in millimetres of mercury, which is written down as: mmHg\n\nEveryone has a different blood pressure and it can change in the same person during the day and night. Your blood pressure varies by large amounts, depending on what you are doing. The lowest blood pressures occur when you are asleep or if you relax all your muscles. Standing up, exercising or anxiety all cause an increase in blood pressure. In a single day your blood pressure may vary by 30 to 40 mmHg systolic with similar proportionate changes in diastolic pressure. This is why when you have your blood pressure level assessed it is so important to have it measured under the same conditions every time.
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Measure them with an accurate measuring device.