I have to solve for distance on the TI83 calculator. I need to know how to solve this equation on the calculator. \n\n- I don’t just want the answers. I would only like to know how to solve these equations on the TI83 or by hand.\n\nHere is the equation.\n\nDistance problem:\n\nFind the distance between the points (2, -1) and (-3, 8); show your answer in simplified form.\n\nIf someone can show me how to do this, it will be much appreciated. Thank you!
120961
Mizz Britz Im sorry Ive never used a TI 83, so im not going to be of any help on this one. Still I was wondering How´s your Macroeconomics project going. . . ?\n\nif you´re still in a jam, e-mail me \n\nT.
450544
let x=distance to go to\nreach inn when first question \nis asked\nlet y =distance travelled from inn\nwhen second question is asked\n\nx+y=2\ndistance travelled to inn=4x\ndistance travelled from inn=4y\ntotal distance travelled\n=4x+4y\n=4(x+y)=4*2=8 miles  \n\ni hope that this helps
285646
....|&#92;\n....|a&#92; 15\n....|...&#92;\n....|___&#92;\n......8\n\nFirst, use SOH CAH TOA.\n\nSoh - sin=opp\n................---\n................hyp\n\nCah - cos=adj\n................---\n................hyp\n\nToa - tan=opp\n................---\n................adj\n\nIn this case, you know the hyp and the opp, so you would use sin.\n\nYou then want to substitute in the values\n\nsin <a=8\n...........-\n...........15\n\nDividing, you get\n\nsin <a=.5333\n\nIf you have the Texas Instruments TI-30XIIS calculator or similar, you will want to find the sin-1 key and hit it, filling in the parenthesis with .5333\n\nClick enter, and you get 32.2309 degrees, which rounds to 32 degrees
31420
If it is anything like the TI-83 plus, you need to turn on DiagnosticOn. For the 83 hit [2nd][0] which is the catalog of all commands and scroll down to DiagnosticOn hit enter twice and then run the linear regression. I assuming they didn't change the calculator that much and that this wont work for the TI-84 plus.
492811
In addition to what “Spoonish1” told you I suggest you to write a program calculating minimal distance between 2 straight lines in 3D. Be this distance =0, then and only then you may state that 2 lines intersect. A classic line equation in 3D looks like:\n(y-y1)/(y2-y1)=(x-x1)/(x2-x1)=(z-z1)/(z2-z1) – just as a matter of fact. Has your desire faded? Or more help?
532456
You need the software: TI-Connect. I think it is a free download from education.ti.com.
506757
I just taught this section today to my calc students.  You start by finding the first and second derivative.  I recommend looking in your book for an example.  Your book probably has something like this towards the front of the section.  It would be too long winded to write everything down here.  If you don't have your book on you, the web page below has problems that you can do and then check your answer.\n\nhttp://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/graphingdirectory/Graphing.html
127996
(4,3) and (-4,-3)\nI think.\n\nCan't blame ya for asking about that one.  Trying to do that equation without a calculator before Calc III can be a pain since you don't get a shortcut in differentiating that type of  problem until late into Calc III.  It can be a pain even with a calculator without that shortcut due to the fact is doesn't balance easily either into a y=f(x) form.
485956
1. if you have a TI83/84, then put \n    y1=3^x+4^x\n    y2=25\nwhere they intersect is the answer\n\n2. do the same thing, put one side of the equation as y1 and the other side as y2\n\n\nthis is much faster than using logs!
577956
It does work.\n(3x+1)ln2=(x-2)ln3 \nDistribute ln2 on the left side and ln3 on the right side.\n3x*ln2 + ln2 = x*ln3 - 2ln3\nSubtract x*ln3 from each side\n3x*ln2 - x*ln3 + ln2 = -2ln3\nSubtract ln2 from each side\n3x*ln2 - x*ln3 = -2ln3 - ln2\nFactor an x from the left side\nx(3ln2 - ln3) = -2ln3 - ln2\nDivide both sides by 3ln2 - ln3\nx = (-2ln3 -ln2)/(3ln2 -ln3)\nx = -2.9469
42839
The length is 10 miles and the width is 8 miles.\n\nOkay... this is what you do:\n\nLet w = width\nLet w + 2 = length, because the length is 2 miles larger than the width.\n\nArea = (Length)(Width)\n80 = (w+2)(w)\n80 = w^2 + 2w\n0 = w^2 + 2w - 80\n0 = (w+10)(w-8)\nw = - 10 miles or 8 miles. Since there is no such thing as a negative distance, it's 8 miles.\nw + 2 = length, so...\n8 + 2 = length\n10 = length
428707
Distance = Speed * Time.\nWe don't know the "distance" variable for either. We need to find the "time" at which the "distance" will be the same. Let distance = d\n\nWe want to find Thomas's time, so let Thomas's time = t.\nAlexis left 3 hours earlier, so her time is t + 3.\n\nThomas speed is 30, Alexis is 20. So lets fill this in.\nThomas:\nD = 30t\nAlexis:\nD = 20(t+3)\n\nThe distance will be the same, so the D in both equations is the same variable. A basic principle is that if a = b and b = c, then a = c.  Therefore, we can combine the equations for the two people as follows:\n30t = 20(t+3)\n30t = 20t + 60\n10t = 60\nt = 6 hrs\n\n\nThe same applies to the second.\nTimothy:\nD = 58t\nSavanah:\nD = 47(t+2)\n\n58t = 47(t+2)\n58t = 47t + 94\n11t = 94\nt = 8 6/11 OR 8.5454545454545\nt = 8 hours, 32 minutes, 43 seconds\n\n\n\nThe last one is slightly different.\nJet 1 Distance = 331t\nJet 2 Distance = 333t\nThe two distances aren't equal this time, but the two distances added up will equal 1,705, SO:\n331t + 333t = 1705\n664t = 1705\nt = 1705/664 = 2 377/664 = 2.56777108\nt = 2 hrs, 34 minutes, 4 seconds
464417
y = 3/(1 - x)²\n\n1, (1 - x)² ≥ 0 for all x and therefore 3/(1 - x)² ≥ 0 for all x\n\n2. 3/(1 - x)² is undefined when x = 0. Therefore 3/(1 - x)² (ie y) → +∞ when x → 1 from the left of 1 and when x → 1 from the right of 1\n\n3. As x → ±∞, 3/(1 - x)² (ie y) → 0\n\n4. Plot a few other points and Bob's your uncle!!
467505
hmm use a calculator...i am sure a ti-83 can show you how to do it, and/or this problem is impossible..but i am sure you can do it..or am i...man now you confused me you have this in the tennis section???
472382
Very understandable....I just posted a question about my pre-calculus homework and i didnt ask for the answer, i just need help finding how to get it....i'd like to know how to do it myself, i dont just want someone to tell me the answer....does me no good @ all!
355170
Of three points, A,B,C\n Check the slope of A-B,  B-C, A-C.  If any of the slopes are the same, you have parallel lines and thus no triangle.  So, to do (2), do (4) first.\n  If you know the distance between A-B, B-C, A-C, you can calculate the area with the formula, so (5) also depends on (4).\n\n You write your own code.  yA isn't a site to do your homework, since if you don't do it yourself, you don't pass the class!
629721
I do a lot of graphics calculator programming so could give you tips if you want. In any case you could write a program on the ti-83 + or 84+ by pressing prgm right right enter typing in a name then writing the equation which can be viewed from edit. You can also store them in the GDB I think it's called by going second prgm and across to store GDB. or You can write a program\n:Clrhome\n:Output(1,1,"Your info"\n:Pause\n:Clrhome\n:Output(1,1,"More info"