This is a tough math question for me: How many zeros does 5000! (5,000 factorial) END WITH?
131604
It is important to remember that fives, when multiplied by an even number, will give zero. There will always be more even numbers than multiples of five so we can use all factors of five. 5000 divided by 5 is 1000. There are 1000 zeros right now. 5000 divided by 25 is 200. There are 200 more zeros. 5000 divided by 125 is 40. 5000 divided by 625 is 8. 5000 divided by 3125 only is 1 whole number. There are 1249zeros coming from fives. \n\nThere are 1249 zeros at the end of 5,000!
225599
this really only works when its done verbally...when people are looking at the numbers, its much easier to realize that the answer is 4100 instead of 5000, pretty neat one isnt it
638158
7249\n\ntake 0.0659 x 110,000 = answer (7249)
595151
The trivial zeros are at (-2K+0i), where K is a positive integer. The nontrivial zeros are all the others. It has been shown that the nontrivial zeroes must have a real part between 0 and 1.
513403
yes because any number ending in zero is even but is divisable by five
153407
You have to find the highest factor of 5 that divides n! to find the number of zeros in n!\nThere is a formula for this:\nfloor(n/5) + floor(n/25) + floor(n/125) + ... \nthe series clearly ends since some power of 5 will exceed n.\n\nGet it?
337063
3)4320\n(4!/2!)*(6!/2!)
441192
so far, so good\n\nn!/(n-4)! = 56 [n!/(n-2)!] \n\nmultiply both sides by (n-2)!/n!\n\n[n!(n-2)!] / [n!(n-4)!] = 56\n\n(n-2)! / (n-4)! = 56\n\n(n-2)(n-3) = 56\n\nYou could multiply this out and solve the quadratic, in which case you will get one positive and one negative root, or if you remember that 56 = 8*7, then that quickly leads to n = 10
313569
4) n is even.\nStarting with an even number (0) and ending with an even number, means you have an odd number off roots.
436382
2 zeroes, one in the range -3<z<-1, and the other in the range 1<z<3.\n\nSteve
525133
(2n-1) * (2n-2) * (2n-3) * (2n-4)... * 3 * 2 * 1\n\nJust like any other factorial.
457503
Hold up eight fingers.  Now put down three of them.  That leaves five of them.\n\nThe answer is 5.\n\nIt is also equivalent to the number of points you lost asking this question... but I guess you are just having fun with Yahoo! Answers coming up with silly questions, aren't you.  Enjoy!
335395
Last few digits are zeros. For any positive integer 'n', factorial n i.e. n! has last digit equal to zero if n > 4. One question is how many zeros are there in 1000!? But you have not asked this question and so I am not going to give the answer.
506844
0.00056 = 0.056%, and by the way, \n0.056     = 5.6 % and\n5.6         = 560%
423126
500007 is divisible by 3!\n\n166669 / 3333333
320239
(0! + 0! + 0! + 0!)!\n=(1+1+1+1)!\n=(4)!\n=24
49025
4000 ones plus 2000 minus twos =0