NOEL\nx  L\n----\nLEON  \nEach letter represents a distinct whole number.  N, O, E, and L are four different numbers.
124372
First fact: L times L equal to a number ending with N.\n\nL = 0 1 2 3 4 5 6 7 8 9\nN = 0 1 4 9 6 5 6 9 4 1\n\nSince L is not the same as N, it would eliminate a few from the above and leave only:\n\nL = 2 3 4 7 8 9\nN = 4 9 6 9 4 1\n\nFact 2: L times N is 9 or less; otherwise, the product would be a five-digit number.\n\nThat would narrow the above down to:\n\nL = 2 9\nN = 4 1\n\nHowever, if L = 2 and N = 4, L times N would be 8, much greater than L (in product.)  So that would eliminate that combination.\n\nL = 9\nN = 1\n\nFact 3: look at the "NO" times L part, with N = 1 and L = 9.  If O is 2 or above, it won't work because that would lead to a five-digit product.  So letter O is either zero(0) or 1.  But since N is already 1, letter O = zero(0).\n\nO = 0\n\nEnding: putting things together\n\n10E9\nx  9\n----\n9E01\n\nThe only E making sense here is 8 (9 x 8 + 8 = 80)\n\nSo the answer is\n\n1089 x 9 = 9801
499024
1. (3/51 * 2/50 * 1/49) * (3/47 * 2/46) * 7!\n2. (3/51 * 2/50) * (3/48) * (3/46) * 45/47 * 7!\n3. (3/51 * 2/50 * 1/49) * (3/47) * 44/46 * 7!\n4. (3/51 * 2/50) * (3/48 * 2/47) * 45/46 * 7!\n5. (3/51) * (48/50 * 3/49) * (44/48 * 3/47) * 40/46 * 7!\n\nNote: As I read it, #2-#4 exclude the possibility of #1.  If you think #1 is a special case of the others, then add the value of #1 to the other three.  Likewise, as I read it, #5 excludes #2.
315014
Although E is one of the mostly used letter, you're successfull to white this paragraph without usinfg E.\n\n\n\n\n\n--- ► λ ◄
585196
8100.\n\nIt's scientific notation =)
533947
I never understand how x can stand for Christ. It make no sense. It is not like 2 for to,too,two or 4 for for,four.
179507
X  = Nothing \nor X  = 24th letter of the English Alphabet.\n\nAm I too clever or do I get the 10 points for being a smart ass?
332197
I'm not sure if you mean from the set of {a,b,c,d,e} or all letters:\n\nIf only from the set {a,b,c,d,e}:\n\nIn the first case, you have 5 choices for the first letter, 4 choices for the second letter and 3 choices for the third.  The reason you have less choices is that you have already used a letter or two.\n\nStated as permutations this is:\nP(5,3) = 5 x 4 x 3 = 60 permutations.\n\nFor the second case, this is a simple permutation.  You have 5 choices for the first letter, 5 for the second and 5 for the third.  \n\n5^3 = 5 x 5 x 5 = 125 permutations.\n\nIf you mean for all letters of the alphabet:\n\nIn the first case, you have 26 choices for the first letter, 25 choices for the second letter and 24 choices for the third.\n\nStated as permutations this is:\nP(26,3) = 26 x 25 x 24 = 15,600 permutations.\n\nFor the second case, you have 26 choices for the first letter, 26 for the second and 26 for the third.  \n\n26^3 = 26 x 26 x 26 = 17,576 permutations.
296485
7 will be after five\nand eight will be after six.\n\nReason: The upper numbers in 'numerals' contains straight lines, the lower one contains curves.\nWell...
65342
Q is unclear. \nHow many letters do you want to pick? \nOrder of letters, right?\nDo you mean you can't use same letter twice, even though your word has 3 n's and 2 k's?\n--------------------\nKennebunk. there are 5 different letters - K,e,n,b,u\nyou can have 5! = 5*4*3*2*1 = 120 permuations of them.\n\nThe reason is - for first letter, you have 5 to pick from;\nonce you picked first one, there are 4 left to fill second slot; and so on.
123255
Maybe by alphabete they only count "different" ones. I mean, N and n are basically the same. There's no point going over the same letter twice.
622611
m0= A'B'C'D'\nm1= ABSENT\nm2=A'B'CD'\nm3=ABSENT\nm4=A'BC'D'\nm5= ABSENT\nm6= ABSENT\nm7= A'BCD\nm8=AB'C'D'\nm9= ABSENT\nm10= ABSENT\nm11= AB'CD\nm12=ABC'D'\nm13=ABSENT\nm14=ABCD'\nm15= ABSENT
59386
(a) 111100111101\n(b) 110001011
621872
"E" \n\n(eternity -> eternitE)
274710
one number and one letter.
370754
the number '194'\n\n=)
391621
Lets take the different groups of people as x\nthat means 3x+13x=6816(pixies and leprechauns)\n16x=6816\nx=426\nSo now we've got x\nthe no.of pixies were 3x\nthat means 3 mul by x=1278\nso there were 1278 pixies\nthe same way leprechauns are 13x\nthat means 13 mul by x =5538\ndid u understand?
571514
1) 120 words\n\n2)12345 (these represent teh letters) first make all the words with 1 at teh beginning then 2 then 3 and so on