1. 15c4 (to the 4th)-26c2 (to the 2nd)-21\n2. 12h4 (to the 4th) -29h2 (to the 2nd)-8\n3. 2x2( to the 2nd)+7x+6 \nall it says in the instructions is to factor it out... so i have to factor it out if that helps at all...
138670
1.) \n15c^4 - 26c^2 - 21 = (3c^2 - 7)(5c^2 + 3)\n\n2.) \n12h^4 - 29h^2 - 8 = (3h^2 - 8)(4h^2 + 1)\n\n3.) \n2x^2 + 7x + 6 = (x + 2)(2x + 3)
475242
Multiply (2x+1)/(3x-4) by 7/7 to give 7(2x+1)/7(3x-4)\nMultiply 5/7 by (3x-4)/(3x-4) to give 5(3x-4)/7(3x-4)\n\nNow they have a common denominator you can just add the fractions\n\n(7(2x+1) + 5(3x-4))/7(3x-4)\n\n(14x + 7 + 15x -20)/7(3x-4)\n\n(29x - 13)/7(3x-4)
384567
1. (x-5)(x-3)\n2.(x+10)(x+2)\n3. (x+8)(x-4)\n4.(a-8)(a-7)\n5. ? your writing is confusing\n6. (a+6b)(a+5b)\n7.(-a+10)(a+5)\n8. I don't think this is factorable, 19 is a prime number\n9. (-x-7)(x-3)\n\nAlright, they key to factoring is pretty simple, once you get the hang of it it becomes second nature. The thing about factoring is you have to understand the multipliers of the 3rd number. \ni.e. #1: 15 has a couple factors, 1&15, and 3&5. Next, you must look at the factors it has, and see which add up or subract in any combination to form the second term. In this case, 5 and 3 combine to make 8. When the last term is positive and the middle term is negative, the two factors must both be subraction. Therfore the answer is (x-5)(x-3)= x2-3x-5x+15=x2-8x+15.\n\nHope I was able to help kid, I was you only a few years back secretly cussing about having to do this. Good luck in Algebra.
349091
Okay, here we go:\n\n1) -2x-10-7 = 3x+2x-10\n    -2x-17 = 5x - 10\n    -2x -5x = -10+17\n    -7x = 7\n       x = -1\n\n2) 12x+6-6x = 5x-10-5x\n     6x+6 = -10\n     6x = -10 - 6\n     6x = -16\n     x = -8/3\n\n3) 30x-5-10x+5 = 4x+40-4x\n    20x = 40\n    x =2\n\n4) -24+6x+12 = 3x-x+4\n    6x-12 = 2x+4\n    6x-2x = 4+12\n    4x=16\n     x = 4\n\nSee? It's quite easy.
419025
(4 root 5)[2 root 10 - 3 root 5)\n(4 root 5)[(root 5)(2 root 2 - 3)   I took out a root 5 from the subtraction part\n(4 root 5 root 5)( 2 root 2 - 3) Multiply the first two parentheses together\n(4X5)(2 root 2 - 3)  Root 5 times root 5 is 5\n20(2 root 2 - 3)\n40 root 2 - 3
418697
First question:  we just simplify and group together like terms.  Let's move the "x" terms to the left hand side, and the numbers to the right hand side.\n\n-0.7x + 1.15 = -0.4x + 3.85\n-0.7x + 0.4x = 3.85 - 1.15\n-0.3x = 2.70 (at this point, divide both sides by -0.3x) to get\nx = -9\n\nThus, the answer is b.\n\nFor the second question, you first expand each side the best way you can.\n\n0.10(70) + 0.50x = 0.30 (70+x)\n7 + 0.5x = 21 + 0.3x\n0.5x - 0.3x = 21 - 7\n0.2x = 14\nx = 70\n\nSo the answer is b.
345973
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
394372
3ax+4by-2ay-6bx\n=3ax-6bx-2ay+4by\n=3x(a-2b)-2y(a-2b)\n=(3x-2y)(a-2b)\n2ax-2by+ay-4bx\n=2ax-4bx+ay-2by\n=2x(a-2b)+y(a-2b)\n=(2x+y)(a-2b)\nso 3ax+4by-2ay-6bx over2ax-2by+ay-4bx\n=3ax+4by-2ay-6bx /2ax-2by+ay-4bx\n=(3x-2y)(a-2b)/(2x+y)(a-2b)\n= (3x-2y)/(2x+y)
433163
1.  = 1cm\n2.  = 2cm\n3.  = 4cm\n4.  = 7cm\n5.  = 11cm\n6.  = 16cm\n7.  = 22cm\n8.  = 29cm\n\ntotal length = 92cm\neach step adds more to the next length.  \nbetween the first and second step, add 1\nbetween the second and third step, add 2\nbetween the third and fourth step, add 3\nbetween the fourth and fifth step, add 4....\n\nand so on.
285479
You can factor out 15bc^2\n15bc^2(5b + 4c^4)
435671
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
497886
1) \n76>40+4c\n36>4c\nc<9\n\n2) 1500>100+17.5p\n1400>17.5p\np<80
564578
[(16x*2-25) / (24x*2-30x)] / [(8x*2-2x-15) / (6x*2-7x-3)]\n= [(16x*2-25) / (24x*2-30x)] [(6x*2-7x-3) / (8x*2-2x-15)\n= [(16x*2-25) (6x*2-7x-30] / [(24x*2-30x) (8x*2-2x-15)]\n= [(4x-5) (4x+5) (3x+1) (2x-3)] / [(6x) (4x-5) (4x+5) (2x-3)]\n= (3x+1) / 6x
369888
Even though somebody told you the answer, I'm going to explain how to do it so you know on other problems. \n\n\n4(3y+2m+1)=\n\nYou have to take the number outside of the parenthesis, and multiply it to all the other numbers.\n\nFirst you do 4 x 3y, because 3y is the first term. \nThat comes out to 12y. \n\nThe next one is 2m, so 4 x 2m= 8m\n\nThe last term is 1, so 4 x 1=4.\n\nAdd up all the numbers and the answer comes out to 12y+8m+3\n\nApply the same method to the 2nd problem\nHope this helps!
442605
.more kids homework... factoring?\n1. rewrite the middle term as the sum of two terms and then factor completely 15x^2 -21x +6\n\n3(5x^2-7x+2)\n3(5x^2-5x-2x+2)\n3(5x-2)(x-1)\n\n2. rewrite the middle term as the sum of two terms and then facto by grouping. x^2 - 14x +45 \n\nx^2-9x-5x+45\n(x-9)(x-5)\n\n3. rerewrite the middle term as the sum of two terms and then facto by grouping x^2 + 19x +90\n\nx^2-10x+9x+90\n(x+10)(x+9)\n\n4. rewrite the middle term as the sum of two terms and then facto by grouping x^2 -2x -63\n\nx^2-9x+7x-63\n(x-9)(x+7)\n\n5.solve x^2 = -6x\n\nx=-6
366124
Factor out 2 in the numerator.\n\n2(3x - 5)/5 - 3x\n\nMultiply the denominator by -1 and then rearrange the denominator.\n\nWe have:\n\n-1 TIMES each term inside the parentheses (5-3x).\n\nDoing this we get:\n\n-5 + 3x\n\nNOTICE: +3x = 3x.\n\nWe rerrange the denominator.\n\nWe NOW have this in the denominator: 3x - 5.\n\nLet's go back to the top.\n\n2(3x-5)/3x-5\n\nWe can CANCEL 3x-5 in the numerator and denominator.\n\nDoing that we get 2 as the answer.\n\nGuido
548956
expand it\n\n24=6r-6+4r\n\nbring 6 to the left\n\n30 = 10r\n\ndivide them\n\n3=r