My prescreption is:\n\n     SPH       CYL    Axis\nOD  -5.50    -4.00     010\nOS  -4.00    -4.75     168
138027
It's higher than average, but I don't think I'd call it severe.  Average is about 1.00D of astigmatism (the second number), but I wouldn't call it severe until it gets over 6.00D.  You were probably born with that much astigmatism, so I wouldn't expect it to get worse, although your overall nearsigtedness (the first number) may increase.
245245
r= SQRT(V/(H*pie))\n\nmines the only right one haha
285646
....|&#92;\n....|a&#92; 15\n....|...&#92;\n....|___&#92;\n......8\n\nFirst, use SOH CAH TOA.\n\nSoh - sin=opp\n................---\n................hyp\n\nCah - cos=adj\n................---\n................hyp\n\nToa - tan=opp\n................---\n................adj\n\nIn this case, you know the hyp and the opp, so you would use sin.\n\nYou then want to substitute in the values\n\nsin <a=8\n...........-\n...........15\n\nDividing, you get\n\nsin <a=.5333\n\nIf you have the Texas Instruments TI-30XIIS calculator or similar, you will want to find the sin-1 key and hit it, filling in the parenthesis with .5333\n\nClick enter, and you get 32.2309 degrees, which rounds to 32 degrees
553236
the answer I got was 844093.44N\n\nhere is how I did it\nhttp://img.photobucket.com/albums/v628/kerahna/physyahoo2.jpg\n\nI hope its right XD
453886
SOH CAH TOA...\n\nsin(angle) = O/H\ncos(angle) = A/H\ntan(angle) = O/A\n\nO=opposite length\nA=adjacent length\nH=hypoteneuse length\n\nsooooo...\n\nsin(angle) = O/H = 18/25\n\nso the angle is...\n\nangle = arcsin(18/25)\n\nPlease try to figure this stuff out on your own before resorting to answers... Europe teaches this to their students in like the 6th grade...
101049
h= (C*I/A+T/k)*z*log(.7*y)
137715
Found a good diagram here\nhttp://www.laynetworks.com/Block%20diagram%20of%20the%20Pentium.htm
337262
i like having the lines in my @ss read. i think it is more accurate than a plain old palm reading! try a rump reading, you'll be suprised to see how accurate they are.
403988
I left school a while ago, but isn't it (0,2).  2 on the y axis.
381736
|t - 78.3| ≤ 38.3\n\nSo either t -78.3 ≤ 38.3 whence t ≤ 116.6\nOR - (t - 78.3) ≤ 38.3\nwhence - t ≤ - 40 ie 40 ≤ t\n\nSo 40 ≤ t ≤ 116.6
405901
h = 4tanθ\nVh = dh/dt = (dh/dθ)(dθ/dt)\ndh/dθ = 4/cos^2θ\ncos^2θ = 4^2/(4^2 + 19^2)\nVh = (16 + 361)/4)(5/361)\nVh = (5/4)(16/361 + 1)\nVh = 1.3054 km/sec
158882
I think all you have to do is plug in a few values for C to get a graph.  For example, try 0, 5, 10, 15, 20.  It's continuous so you can connect the dots.\n\n(0,0), (5,87.5), (10,350), (15,787.5), (20,1400)\n\nTotal labor for 20 is 1400.
380037
Im not sure if it would look right all on the same graph, why dont you try doing two graphs one for the stature with the 3 groups of people and then one with nirtogen isotope, if you were to combine them it would seem very confusing to the eye - hope this helps and good luck
486499
4.25 = (((2.1 rev/s) /  3.1s) * (360degrees/rev)) / 57.3 rad/degree
29887
In order to use the standard normal prob. chart, you need to subtract the mean and then divide by the std dev.\nP(X>125) = P( Z > (125-110)/15 ) = P(Z>1) \nDon't forget that the tables tell you the area to the left (i.e. <), but you can look up the area to the left and then subtract that value from 1 to get the area to the right.  In other words:\nP(Z>1) = 1 - P(Z<1) \nP(Z>1) = 1 - 0.841345 = .158655\nAlmost 16% of infants have birthweights above 125 oz.
550549
ok, im going to assume that you know (rho)(g)(h) = pressure\n\nlets label 4 points:\nA is at the bottom of the 1.28cm mark\nB is at the top of the 1.28cm mark\nC is at the bottom of the hl mark\nD is at the top of the hl mark\n\nNotice 2 things:\n1. the pressures at A on the right and the left must be the same\n2.if you removed the same amount of blue from both sides, hl would still be the same measurement (so lets remove it for calulations)\n\nnow the blue on the left side is of a height of 1.28+hl and the green on the right is 1.28\n\nat the top they are equal, so:\n2.25*g*(1.28+hl)=8.41*g*(1.28)\n2.25(1.28+hl)=8.41*1.28         g cancels from both sides\n2.25*1.28+2.25*hl=8.41*1.28\n2.88 + 2.25hl = 10.765\n2.25hl = 10.765 - 2.88=7.885\nhl = 7.885/2.25 = 3.50435.....cm
115222
SEC stands for secant, which is the ratio of the hypotenuse to the leg adjacent to the acute angle X.  So here, \n\nsec(x)= (sqrt 41)/4