ie force acting on a unit north pole\nforce on a unit positive charge?\nbut then isolated poles do not exist whereas isolated charges do
124721
Electric field causes a force on all charges whereas magnetic field only causes a force on moving charges. The Lorentz equation can be used to define both electic field strength E and magnetic field strength B. The equation is:\n\nF = q(E + vxB)\n\nThis is a vector equation: q is the charge and vxB is the vector product of velocity and magnetic flux density.
287564
The following refers to Coulomb force between two charges in a single uniform medium, not the two-medium situation described in  the question.\nAnswer 1 is helpful but the lack of exponent signs makes it misleading. The force is inversely proportional to the square of the distance, so the simplified formula is \nF = k * q1 * q2 / r^2 \nk is a constant = 8.99*10^9 N m^2 / C^2 (C is charge in Coulombs). Thus if q1 = q2 = 1 Coulomb, and q1 is separated from q2 by r = 1 meter, the force is 8.99*10^9 N or 2.01 billion pounds! \nThe above simplified formula is a contraction of the full formula (see ref.),\nF = q1 * q2 / (4 * pi * epsilon * r^2)\nin which k is replaced by 1/(4 * pi * epsilon), where epsilon is the product of epsilon0, the electrical permittivity of the vacuum (= 8.85 * 10^-12 c^2/(N m^2)), and kappa, the dielectric constant which = 1 for vacuum and is assumed in the simplified formula.\nFor two segments of distance as you specify, first solve for F1 and F2, each as a function of a particular distance (r or d - r) and dielectric constant. Then my inclination would be to try the sum-of-inverse square root solution which works for a similar situation, gravitational force F at distance R, computed from F1 and F2 at partial distances R1 and R2, where R = R1 + R2, \n1/SQRT(F) = 1/SQRT(F1) + 1/SQRT(F2)\nSorry I can't be more definite than that.
39273
Einstein alluded about forces saying that they are fictitious.This make sense because forces do not exist unless there is an interaction between two entities.\nThe magnetudes of interaction depends on the densities of the masses and their volume.The greater the densities the greater the interaction.Thus we can categorize them.\nHowever ;the mechanisms involved is the same in all interactions!Einstein Related this mechanism to a curvature.\nHe had discovered when a force comes into being it comes  from a common  mechanism(.A force is a force ). Force only come into being only as pairs.A force cannot exist by itself no more than a magnet having a single pole.\nUnfortunately ,He had the basis for a Unified Theory and did not realize it.\nAs far what has been measured in the interaction of micromasses or micromasses,I  dont believe there is anything exact.Only approximtions.\nThe phenomena of gravity apply to both micromasses as well as Macromasses.This is the only thing that is Realistic.\nIn other words Electrical phenomena as well Gavity are all one and the same Phenomena.\nYou may not agree with it but its a more realistic answer than resorting to the aphabetic soup of forces that the Physists have concocted as saying that they are different Phenomenae.\nIf you dont understand about their description of weak,strong nuclear forces, dont feel bad. I doubt that they fully understand it themselves!
367753
A force at its most simplistic is a push or a pull. According to Newton's laws of motion, when something is at rest or travelling at constant velocity, there is NO force acting on it. \n\nNewton's second law states that Force = mass x acceleration which means that a force causes a _change_ in velocity (acceleration). So for continuing motion, there is only a force when there is acceleration.
400000
Magnitude of net force would be sqrt(2) times magnitude of F  and it will act along a line bisecting the angle between AB and CB produced. [ By Parallelogram law of forces]
153311
Gee .. been a while.  If I remember correctly the magnetic field is perpendicular to the electrical field.  Thus around the two wires the magnetic fields move in the same direction and combine, producing a net attractive force.\n\nIf the currents go the opposite direction, the forces repel.\n\nSee the link below for a more detailed explanation and pictures:
633670
No, the electron's charge is not its energy content, the charge is the charge which is a fundamental quantity (and the same for all electrons.) The volt is not a unit of force, it is a unit of electrical potential, with units of J/C (joules/coulomb). A volt represents a potential difference that will impart one joule of energy to one coulomb of charge passing through it. An electron volt is a unit of energy, defined as the amount of energy imparted to one electron passing through a potential difference of one volt. Since the electron's charge is −1.60217653*10^-19 C, the energy so imparted is equal to 1.60217653*10^-19 J.
658301
The alpha particles have a positive charge. A magnet  would deflect them away from the others.
466247
A curious result is that if you put a charged object anywhere inside a spherically symmetric charged hollow sphere, the net force on that object is zero.  It doesn't have to be in the centre.  This is a consequence of Gauss' Law.
171258
Well that book must have a misprint or something because q=CV is not accurate. Actually if the potential of a outside conductor depends on the size, then this is a variable dependent, (and therefore mutable) in structure, shape, and amount of conduction based on the charge of q. For if C=q/v, then the isolated conductor's potential to change will be hinder and therefore not fully capable of allowing a full transformation for V due to the charge (power) of q.
905
I'm assuming this is an electric dipole.\n\nSince a dipole can be modeled as a pair of opposite charges +_q separated by a small displacement, you can use the method of images and assume the field produced by the conductor is the same as the original dipole reflected across the plane with the signs of the charges reversed. That means the image dipole is in the same orientation as the original dipole and is at a distance r = 2I from it. The force is attractive (towards the plane). The energy between two dipoles having the same moment p parallel to their separation vector is:\n\nW = -2p^2/r^3\n\nwhere r is the separation distance. The force between two such real dipoles would be (i.e. this is the force on either one):\n\nF = dW/dr = -6p^2/r^4\n\nThis should be the same force experienced by the one dipole in the field produced by the conducting plane. Since r = 2I, this is:\n\nF = (3/8)p^2/I^4
230704
A dipole (Greek: di(s) = double and polos = pivot) is a pair of electric charges or magnetic poles of equal magnitude but opposite polarity (opposite electronic charges), separated by some, usually small, distance. Dipoles can be characterized by their dipole moment, a vector quantity with a magnitude equal to the product of the charge or magnetic strength of one of the poles and the distance separating the two poles. The direction of the dipole moment corresponds, for electric dipoles, to the direction from the negative to the positive charge. For magnetic dipoles, the dipole moment points from the magnetic south to the magnetic north pole — confusingly, the "north" and "south" convention for magnetic dipoles is the opposite of that used to describe the Earth's geographic and magnetic poles, so that the Earth's geomagnetic north pole is the south pole of its dipole moment. Because of the absence of magnetic monopoles, magnetic dipoles are actually created by current loops or by quantum-mechanical spin.\n\nSince the direction of an electric field is defined as the direction of the force on a positive charge, electric field lines point away from a positive charge and toward a negative charge.\n\nWhen placed in an electric or magnetic field, equal but opposite forces arise on each side of the dipole creating a torque τ:\n\n \nfor an electric dipole moment p (in coulomb-meters), or\nfor a magnetic dipole moment m (in ampere-square meters).\n\nThe resulting torque will tend to align the dipole with the applied field
440886
d)\notherwise some of work transforms to heat which is potential energy not kinetic.\nfor example when you kick the wall, acting forces are not elastic and do not rise kinetic energy of your feet or wall.
619672
I had the same problem when I learned about both of them. \nBut now think of it in a different way. You are assuming that the magnetic FORCE that magnets have on certain metals. But if you think about it carefully they don't create or destroy energy. \nIf you don't beleive me consider a piece of iron with only gravity working on. But its height is 0 so it has no Potential or Kinetic energy. But now let's say you bring in a magnet. Now naturally that will make the iron bar rise and stick to the magnet. Now a natural assumption would be that you just created potential energy because the height of the iron bar just increased. But now you have to consider the fact that magnet is still putting some force on the Iron bar. So no change in potential energy occured. No change in Kinetic energy occured once the bar stuck to it. and the Energy needed to bring the bar up could be accounted by the energy needed to bring iron bar in. This shows that there was no energy created.  \nI think that you are trying to overthink the problem. I think this should help good luck.
61676
*is a center-directed force\n\n\nnot "*acts as an unbalanced force on the satellite" because, it is balanced by centrifugal force. \n\nnot "*changes the direction of the satellite" because direction is changed by only tangential forces and not the force acting towards center.
266513
the rate of change of charge density is constant along the cylinder. So if we consider two nearby points along the cylinder the charge difference between the two points would be the same aslong as the distance between them was the same(no matter where in the cylinder those two points were).\n\nSince the electric field is dependent on this difference then it will be the same all along the cylinder. (This assumes that all the other charges can be ignored because they either cancel with other charges or they are very small  (electric field is proportional to 1/r^2))
534100
Putting it simply:\nEffort force, is force that must be applied to do something,eg, to push a block.\nResistance force, is the force which restricts the movement,eg, the friction of the block with the ground.