i don't get ALGEBRA...so plz sumone help me\nx^+12x+36       \n^ is squared, can sumone help and explain this\n\n* also if possible\n9x^+12xy+4y^\nThanks
131565
The equation is a quadratic, (you know this this because of the x squared) To solve a quadratic you need to factoruse ut, so make two brackets with and x in each, (x   )(x   ).\nNow, you need to look for factor pairs of 36(the constant at the end) that when you add them together or take them away, they equal 12 (the number in front of the x term)  Our options are, 1x36, 2x18, 3x12, 4x9 and 6x6.  Only 6x6 adds to give us 12.  You can now add two sixes to your brackets, so (x   6)(x   6).  Now you need to look at the signs, which signs when multiploed out will give us +36?\n\nIf you are not confident with algebra, try trial and error.  in this case it'll be ++, \n\nSo fully factorised this gives us (x+6)(x+6)\n\nTo solve this we now need to make it equal to 0\n\n(x+6)(x+6)=0\n\nNow put each bracket equal to zero  ( as both brackets are the same we need only look at one of them)..(x+6)=0, so with simple manipulation we can say that x=-6\n\nThe second equation is related to a circle and tricky to explain by message, try looking in a revision book around circle equations and properties
149409
-6-9x=-9x-4\n-6=-4.....\nno solution?? whats so hard to that?
537838
b. is quadratic\nx-4=x^2+4x\n=>x^2+3x+4=0\nc. is quadratic\nx-2x+8=x^2-4x\nx^2-3x-8=0
173944
3*3-12*2*3*2+4x-4\n9-12*12+4x-4 Order of Operations-Multiply first\n9-144+4x-4 Subtract\n-135+4x-4 Subtract\n4x-139 Simplified\n\n3*2-14x+8\n6-14x+8\n-14x+14\n\n6*2+12x\n12x+12
490003
an expression of the form x^-n can be written as \n    1\n_____\n \n   x^n\n\nwhere ^ implies raised to the power of\n\nSo first square the expression you have given. this gives\n\n  4 x^6 y^-6\n__________\n    \n    9 a^12\n\n\ntake reciprocal of this\n\n      9 a^12\n___________\n\n   4 x^6 y^-6\n\nThis is your answer
610445
:)\nOpen by multiplying  you have \n6x + 6=12x – 36\nMove the unknown to the left side and all known values to right. DO NOT forget to change their signs as you do that. Now you have\n6x-12x=-6 – 36 \nOr\n-6x=-42\nx=42/6=7 (remember – divided by – is +)\n\nDoes that help?
482020
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
524594
[(x^2)^2]^2\n\n(x^2 -4x +4)^2\n\nmultiply      x^2  (x^2 -4x +4)^  = x^4 -4x^3 +4x^2\n\nmultiply     -4x (x^2 -4x +4)^    = -4x^3 +16x^2 -16x\n\nmultiply     4  (x^2 -4x +4)^      =  4x^2 -16x +16\n__________________________________________\n\nthe answer should be                 x^4 -8x^3 +24x^2 -32x +16\n\ni hope that helped
435310
I prefer "long" multiplication but it doesn't line up as well...\n\n3x^2 + 7x - 6\n* _____x+12\n--------------------  Multiplying term by term\n_____36x^2 + 84X - 72\n3x^3 + 7x^2 - 6x\n--------------------------------  Add term by term\n3x^3 + 43x^2 + 78x - 72   <--  final answer
309103
Wonderful.\nTHis is some sort of simultaneous equation.\nAccording to the principle of this equation, we try to rationalize one term of the equation so as to get one unknown term. We can either try finding the x term or the y term. For your question as to find the y term.\n\nFirstly, we rationalize the x terms by multipling them by the inverts. then it will result to \n                                    12x + 20y = 32\n                                    12x + 18y = 39\nThe we apply the subtraction rule. ie. we multiply all the terms beneath by the negative (-) sign. This will result to \n                                    12x + 20y = 32\n                                   -12x - 18 = -39\nWe later subtract so as to attain\n                                2y = -7\nWe apply the law of linear equation by dividing both sides by the coefficient which in this case is 2.\n                              2y/2 = -7/2\nThis will eventually cancel the 2 in the first term therby leavin y alone. \n The answer will be in either of the following cases through simplification.  -7/2, -3 1/2 or -3.5
184372
goyalnarinder2 is correct.\n\nIf you also want to understand it, not only have the answer, then you should first know how to get rid of those brackets, for instance:\n\n(3x-1)(2x+3)= 3x(2x+3)-1(2x+3) \n\nGot the picture? It's called distributivity, the fact that you can distribute the factor 2x+3 to each of the terms of the first bracket - these would be 3x and -1.\n\nThen u continue distributing:\n3x(2x+3)=3x.2x+3x.3=6x^2+9x \n-1(2x+3)=-2x-3\n\nThat is how u get to:  \n6x^2+9x-2x-3=6x^2+7x-3 and this is just the result of the product of the first 2 brackets.\n\nAre u still w me? :-)\n\nYou now try to do the second product - which is (x-4)(x-1) - by yourself and see if you get this:\n(x-4)(x+1)=x^2-3x-4\n\nThen u add the 2 things (or rather substract...):\n(3x-1)(2x+3)-(x-4)(x+1)=(6x^2+7x-3)-(x^2-3x-4)\nand here u take care of the signs in the second bracket, which u should reverse (because say if I take -3 apples from u what I do is really give u +3 apples, got it?)\nSo u continue w:\nthe above = 6x^2+7x-3-x^2+3x+4=5x^2+10x+1\n\nHope this helped. Good luck!
74761
12 = 3x²\n\nI hope you will know that if a = b, then b = a\nTherefore,\n3x² = 12\n\nYou will observe that 3 times x² is equal to 12.  What will you multiply to 3 to make it 12? The answer is 4. Therefore, x² = 4\nx² = 4\n\nYou will again notice that the square of x is 4. What number/s when squared gives 4? The answers are 2 and -2. Therefore,\nx = 2 or\nx = -2\n\n^_^
308263
To solve this you raise everything inside the first parenthesis to the power of 2 (essentially multiply the exponent by the power it is to be raised to.  Thus (6x^2z^4)^2 becomes (36x^4z^8).  Now we can multiply like terms:  (4*36)(x^4*X^3)(Z^8*Z^2).  When multiplying exponents, simply add the 2 powers.  144x^7z^5\n\n (6x^2z^4)^2(x^3z^2)4=(36x^4z^8)(x^3yz^2)4\n                       =(4*36)(x^4*X^3)(Z^8*Z^2)\n                       =144x^7z^5
382070
I presume you mean\n\n[(6x^2) / (4x^2y-12xy)] * [(x^2+x-12) / (3x^2+12x)]\n\nThere seems to be something wrong. Are you sure about those "y" terms?
475165
x^2 - 8x + 16\n\n\nthe person above me said it is -x^2 but that is incorrect because -x * -x = x^2
200398
if by this you mean\n\n((3x^-2 * y)^-2)/((4xy^-2)^-1)\n\nthis becomes\n\n((3^-2) * x^(-2 * -2) * y^-2)/((4^-1) * x^-1 * y^(-2 * -1))\n\n((1/9)x^4 * y^-2)/((1/4) * x^-1 * y^2)\n\n((1/9)/(1/4)) * x^(4 - (-1)) * y^(-2 - 2)\n\n((1/9)*(4/1)) * x^(4 + 1) * y^(-2 + (-2))\n\n(4/9)x^5y^-4\n\nwithout using negative exponents, the answer would be\n\n(4x^5)/(9y^4)
449256
I'll rewrite the question for you, because we usually denote ^ as "to the power of" for simplicity.\n\nx^2 + y^2 - 4x + 2y = 4\n\nWe have to do a process called completing the square, for both the x and y variables.  So first, let's group all the x terms together and y terms together.\n\nx^2 - 4x + y^2 + 2y = 4\n\nTo complete the square, we have to add 4 to the x terms and 1 to the y terms.  Since we're adding 4 and 1 to the left hand side, we have to do the same to the right hand side.\n\nx^2 - 4x + 4 + y^2 + 2y + 1 = 4 + 4 + 1\n\nNow, we factor those now square polynomials.\n(x-2)^2 + (y+1)^2 = 9\n\nThe center of the circle is given by the values in the brackets, but the negative of them.  In the above case, the center is at (2,-1), since you take the negative of -2 (the value next to the x) and 1 (the value next to the y).\n\nTo get the radius, you take the square root of the right hand side, so the square root of 9 is 3.