i need help with this equation how to set everything up and solve it
136872
You havent really provided many details as to how you want to set it up.\n\nQ = m*c*(delta T)\nQ = heat energy\nm = mass\nc = specific heat\ndelta t = change in temperature (= final - initial temp)\n\nRemember, in a closed system, heat gained by one thing equals the heat lost by another.\n\nHeat is a form of energy, meausred in Joules (sometimes calories, but the official SI unit is Joules),\nDepending on the value you use for the specific heat, it is common to use grams or kilograms for the mass measurement.\nAgain, depending on the value of the specific heat, most commonly, you'll use temperature in terms of degrees C (or perhaps K, a change of 1 degree C = change of 1 K).
209883
Your equation would be:\n\n= ((1/p) - (1/q))/(1/pq)\n\n= ((q - p)/pq) * pq\n\n= q - p\n\nHope I am clear.
381414
ok re arranged the second question so that the 6 is factored out so its x= such and such then sub the x equals such and such into the first equation and solve then do the same thing to Y in the second equation
57466
Use cubic equation \ny=ax3+bx2+cx+d\n\nSince you have four points data you can get four linear equations with four variables which is very easy to solve, get variables (a,b,c,d) and plug the values to cross check and see u will get answer. Use guass jordan or elimination method.
192095
ok, u have to use distance formula\n\nsqrt[(-4-(-7))^2+(c-7)^2]=5   \nsquare both sides\n[(-4-(-7))^2+(c-7)^2]=25      \nadd the stuff in the parentesies\n[(-3)^2+(c-7)^2]=25           \nexponents\n9+(c-7)^2=25                  \nsubtract from both sides\n(c-7)^2=16                    \nsquare root both sides\nc-7= +/-4                     \nadd to both sides\nc=11 or c=3
47256
So, usually the best way to do these is to just fiddle with them until you get them right, but for the sake of it, let's go with a systematic approach using algebra.  First we assign a variable in front of each of the terms on the left and right like:\n\nx Pb  +  y H2O  +  z O2  -->  a Pb(OH)2\n\nSo now we'll write down equations to make sure that we have the same numbers of both sides of each *element*.  I'll do this by writing down the variable in front of each compound in your equation (so x, y z and a) and then multiplying those by the number of times an element exists in that compound.  (So when I'm writing the equation for hydrogen, the H20 term will be 2*y, because y is the coefficient in front of H20 and H occurs twice in that compound).\n\nRemember, the number of any element on the reactants (left) side equals the number of that element on the products (right) side.\n\nFor Pb: x = a, because Pb shows up only once on each side with a subscript of 1, those two compounds will have to be present in the same molar amounts.\n\nFor Hydrogen: 2y = 2a\n\nFor Oxygen: y + 2*z = 2 * a\n\nSo now we have three equations:\n\nx = y\ny = a\ny + 2z = 2a\n\nBut four unknowns, which is fine because we'll just solve for them in terms of one of the variables and then simply choose the last variable to make all the numbers nice.  So solving the equations in terms of a:\n\nx = a\ny = a\nz = (2a - y)/2 = (2a - a)/2 = a/2\n\nSo now we have x, y and z in terms of a free parameter, a.  We'll just choose a = 2, for example, to make x, y and z all turn out as integers.  So now we've chosen:\n\nx = 2\ny = 2\nz = 1\na = 2\n\nSo the balanced equation is:\n\n2 Pb + 2 H2O + O2 --> 2 Pb(OH)2\n\nMake sense?
376413
Remember the fomula...\n\ny = mx + b\n\nm = Slope\n\nb = Y-intercept\n\nx and y = points\n\nSo plug everything in...\n\n1 = 4(2) + b\nMulitply\n1 = 8 + b\nSubtract 8 on each side\n-7 = b\n\ny = 4x - 7
466854
Just plug 0 in the function whenever you see y.\n\n4x + 3(0) + 24 = 0\n4x + 0 + 24 = 0  \n\nThen solve for x.\n\n4x = -24\nx = -6
490218
I would first simplify each by multiplying by the lowest common denominator.\n\nMultiply the following by 6:\n(1/3)x - (1/6)y = 1/3 \n2x - y = 2\n\nMultiply the following by 12:\n(1/6)x + (1/4)y = 0\n2x + 3y = 0\n\nTo add the equations, you need to make one of the terms the opposite, so I would multiply the top equation by -1:\n-2x + y = -2\n\nNow add them:\n2x + 3y = 0 \n-2x + y = -2\n----------------\n2x -2x + 3y + y = 0 + -2\n\nThe x terms cancel out.\n4y = -2\n\nDivide both sides by 4:\ny = -2/4\ny = -1/2\n\nNow solve for x:\n2x + 3y = 0\n2x + 3(-1/2) = 0\n2x -3/2 = 0\n2x = 3/2\nx = 3/4\n\nNote: If you got to a point where you had something like n = n (e.g. 10 = 10), that would mean any value of x or y would work.  This would mean your system is dependent.  On the other hand if you got to an untrue statement (e.g. 10 = 3), that would tell you that the system is inconsistent.\n\nSince you got to a solution (x = 3/4, y = -1/2), the system is *independent*.
482020
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
370469
you need to set up a matrix equation.  \nthe rows should look like this:\n\n1      ,   -2    ,     1    ,      / -8\n3      ,   -3    ,    -2    ,     /-5\n-2     ,   -3     ,    3      ,    /5\n\nOnce you set this up follow the rules of matrices to get this to a unit matrix.  Once you have done this the three numbers on the right will become your answers for x, y and z.  x being which ever row has the 1 in the first column.  y being which ever row has the 1 in the second column.  z being which ever row has the 1 in the third column.
305905
1) Let y = 2x^2 - 4\n2) Switch x and y\nx = 2y^2 - 4\n3) Solve for y\nx = 2y^2 - 4\nAdd 4 to each side\nx+4 = 2y^2\nDivide each side by 2\n(x+4)/2 = y^2\n(1/2)x + 2 = y^2\nTake the square root of each side\ny = sqrt((1/2)x + 2)\n4) Answer: f-1(x) = sqrt((1/2)x + 2)
360179
Sure...\n\nfirst we want to combine like terms on each side of the equals sign.  Think of the equals like the balance point on a scale... you can do anything on one side as long as you match it (keep it balanced) on the other!\n\nso we want to combine the variables and the constants...\n\n8a - 3a + 4 = -a -4 + 2\n5a + 4 = -a - 2\n\nnow we want all the variables on one side, and constants on the other:\n\n5a -(-a) + 4 - 4 = -a-(-a) - 2 - 4\n5a + a = -2 - 4\n6a = -6\n\nnow we just divide by 6 to get a alone:\n\n6a/6 = -6/6\na = -1\n\nHope this helps! :)
428773
You need to do two things:\n1. set your window\n2. program the equations.\n\n1. At the top there's a 'Window' button.  You can set window parameters there.  However, I'd recommend using the 'Zoon' button and chosing option 6: ZStandard.  This will give you a good window.   You can change it later.\n\n2. The top left button says 'Y='.  Press this and program equation 1 then 'enter'.  This put you down one line so that you can program equation 2.\n\nTo run press the upper right hand button 'Graph'.\n\nAlso, go to the Texas Instruments website for help and to download an users manual.
501285
I will suggest that first you write the equation in a compact mode, balance it and then add all the bells and whistles.\n\nCuSO4 +K3PO4 ---> Cu3(PO4)2 + K2SO4\n\n3CuSO4 +2K3PO4 ---> Cu3(PO4)2 + 3K2SO4\n\n3CuSO4(aq) +2K3PO4(s) ---> Cu3(PO4)2(s) + 3K2SO4(aq)\n\nNow that it is balanced it is easier to break down:\n\n3Cu(+2) + 3SO4(-2) + 2K3PO4(s) --->  Cu3(PO4)2(s) + 6K(+) + 3SO4(-2)
416563
First, not all of the things you typed showed up, put spaces in and we'll be able to see it all.\n\nSecond, I don't know what you need help with. You just have a bunch of algebra, but no equations.\n\nPlease clarify your question!
239807
Multiply the first equation by 2.\n\nSubtract the second equation from the new first equation.\n\nSolve for y.\n\nTake your value for y and substitute it into the original first equation.\n\nSolve for x.