Can you solve this problem? I can't fiqure it out.\nsolve the system by the linear combination method\n\n4x+y=10\n6x-y=20
124168
4x+y=10\n\n6x-y=20 \n+y   +y\n_______\n6x = 20+y\n-20  -20\n6x-20 = y\n\nreplace 6x-20 in for y with the other equation\n\n4x+(6x-20)=10\n10x-20=10\n+20     +20\n10x=30\nx=3\n\nnow plug in 3 in the equation as x\n\n4x+y=10\n4(3)+y=10\n12+y=10\ny=-2\n\nso x=3 and y=-2\nI think\n_____________________________\nAnother way to do it is get y's alone and set them equal\n6x-20=10-4x\n10x-20=10\n10x=30\nx=3\nand then just plug in like what I did b4
468494
if u mean y + 4x = 1, then\ny+4x = 1\ny=-5x-8\nplug the second equation into the first equation using y\n-5x - 8 + 4x = 1\n-x = 9\nx = - 9\nplug x back into the first equation to solve for y\ny + 4(-9) = 1\ny = 37\n\nANSWER\nx = -9\ny = 37\n\n-------------------------\nbut if you meant\ny = 4x + 1, then\n\ny = 4x+1\ny = -5x - 8\nset the two equations equal to each other\n4x + 1 = -5x - 8\n9x = -9\nx = -1\nplug x back into the first equation\ny = 4(-1) + 1\ny = -3\n\nANSWER\nx = -1\ny = -3
280757
x=3y-8\nx+y=28\n\nsolving:\n3y-8+y=28\n4y=46\ny=9\nx=19
404453
why not, you just plug y in the 1st equation:\n5x + 3y = -19   & y=-2x-8\n5x + 3(- 2x - 8) = -19\nand solve for x\n5x - 6 x - 24 = -19\n-x - 24 = -19\n-x = 24 - 19 = 5\nx = -5\ny = -2x-8\ny = -2(-5) - 8\ny = 10 - 8 = 2\n\nx = -5 , y = 2
646828
2 linear equations\n\n X  + 3Y - 1 = 0\n4X + 7Y + 5 = 0\n\nFROM (1)   4X + 12Y - 4 = 0\nFROM (2)   4X +  7Y + 5 = 0\n\nSUBTRACT\n                          5Y - 9 = 0\n\n                          5Y = 9\n\n                            Y = 1.8\n \n  FROM (1)      X + 5.4 - 1 = 0\n\n                        X + 4.4 =   0\n\n                        X =  -4.4
487162
you do not get specific values, there are infinite number of solutions for each equations\n\n2x + y = 9, y= -2x + 9\n\n-x - y = - 8, y=-x+8\n\n- 3x + 4y = 2, y = 3x/4 - 1/2\n\n- 2x - y = - 3, y= -2x +3\n`
477309
2x+y=15  *6\n12x+6y=90\n5x-6y=-22\nadding\n17x=68\nx=4\nsub\n8+y=15\nadding -8\ny=7\nso x=4,y=7
10918
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
420702
#1\n4x+1+3=0\n4x+4=0\n4x=-4\nx=-1\n\n#2\n2y+7+4=y\n2y+11=y\ny=-11
239424
Solving a system by addition involves simply adding the two equations together. First, however, you have to do a little prep work. Either the x's or the y's must be of the opposite sign. I'll show you how to do the y's first, because it is easier.\n\n5x-3y=13\n4x-3y=11\n\nThe y's need to be opposite. What is the simplest way to do so? Make one of the -3y's into a positive 3y. Thus, multiple one of the equations by -1.\n\n-1(5x-3y=13)\nbecomes\n-5x+3y=-13\n\nNow you have\n-5x+3y=-13\n4x-3y=11\n\n+3y + -3y = 0\n\nYou have just canceled out the y's.\n\nNow you have:\n-5x=-13\n4x=11\n\nAdd these together and you get:\n-x=-2\nThus, x=2\n\nNow you know x. Take either of the original equations, and substitute in your new x.\n\n5(2)-3y=13\n10-3y=13\n-3y=3\ny=-1\n\nThat's it! Hope I helped.
381832
X2   5x - 4y = 1\n10x -8y =2\n-10x + 8y = -3\n-------------------------\n  0=-1                NO SOLUTION
415753
-4x + 10 = 6x - 40\n\n-----------------------------\n\n+4x to each side:\n\n(-4x +4x) +10 = (6x+4x) - 40\n10 = 10x - 40\n\n------------------------------\n\n+40 to each side:\n\n(10 + 40) = 10x (-40 + 40)\n50 = 10x\n\n------------------------------\n\nDivide each side by 10:\n\n50/10 = 10x/10\n5 = x\n\n------------------------------\n\nSo your answer is x = 5
481034
First, I multiplied the first equation by 2 and the second one by -5 in order to make it easy for me to cancel out both x's.\n2(-5x+7y=-40)\n-5(-2x+4y=-16)\n\n-10x+14y=-80\n10x+-20y=80\n\nNow, you can actually cancel out the x's and the constants at the end.\n\n-6y=0\ny=0\n\nNow you plug y=0 into one of the equations to find x.\n\n-5x + 7(0) = -40\n-5x +0 = -40\n-5x = -40\nx = 8\n\n(0,8) is the answer.
521329
2x + 4y = -6\nX - 3y = 7 multiply by two\n\n2x + 4y = -6\n2x - 6y = 14\n{subtract equation 2 from equation 1}\n\n2x - 2x + 4y - (-6y) = -6 - 14\n10 y = -20 divide by 10\ny = -2\n\n\nplug into a equation \n2x - 6(-2)  = 14\n2x + 12 = 14\n2x = 2\nx = 1\n\nx = 1, y = 2
650111
You don't give a feasible region. However, only one of your answers actually satisfies z=6x+10y. That should solve your problem.
500016
Should not u work that urself?\n\n\nAnyway,\n\nIf 3x+y=3,\n\nmultiply both the sides by 2.\nAs both sdies are being multiplied, the equality is maintained\n\n2* (3x+y) = 2*(3)\n\n=> 2*(3x) + 2*(y) = 6\n\n=> 6x + 2y = 6                                               ----(eqn 1)\n\nNow as it can be seen that the left hand side is 6x+2y+10, therefore we will add 10 to our (eqn 1). To maintain the equality, this addition will have to be done to both the sides.\n\nTherefore,\n6x + 2y +10 = 6 + 10\n\n=> 6x + 2y + 10 = 16\n\ndone!!\n\nThere is another way to look at the problem, and this seems a bit mopre logical, if ur comfortable with equations i.e.\n\nNow look carefully at what is asked.\n\n6x + 2y +10 = ?\n\nfactorize it by taking out 2 common\n\n2*(3x + y) +10 = ?\n\nwe already know the value of (3x+y), which is 3\nso, we substitute it in 2*(3x + y) +10 = ? to get,\n\n2*( 3 ) +10 = ?\ncalculating, 2*3+10=6+10=16
529941
x+y=8\nx-y=-4\n______\n2x=4 (because +y and -y cancel out)\nx=2\nthen plug 2 in for x in one of the equations\n2+y=8\nsolve for y\ny=6\nordered pair is (2, 6)