what is x^2 + 4x = -1 ? i need to solve the equation by completing the square.\n\nthanks a lot!! i suck at math. i could really use and appreciate some help.
120950
x^2 + 4x = -1\nx^2 + 4x +1 = 0\n\nUse this formula X = -b +/- ((-b)^2 - 4ac)^(1/2) / 2a\nwhere:\nb=4\na=2\nc=1\n\nThen you will get two answers:\nFirst is -2.73\nSecond is -0.27
390499
√(4x + 1) +3 = 0\nSo √(4x + 1) = -3 (which means that 4x + 1 cannot be real as √N  ≥ 0)\nSo no solution\n\nIf you want to solve: \n\nFnd an x such that one of the square roots of (4x + 1) is - 3,\n\nthen 4x + 1 = 9\nx = 2
489761
x = 4 ==> (x - 4) = 0\nx = -2 ==> (x + 2) = 0\n(x - 4)(x + 2) = 0\nx^2 - 2x - 8 = 0
149409
-6-9x=-9x-4\n-6=-4.....\nno solution?? whats so hard to that?
167641
You can complete the square, like this:\n\n2x^2-12x+15=0\n2x^2-12x=-15\nx^2-6x=-7.5\nx^2-6x+9=-7.5+9\n(x-3)^2=3/2\n\nx-3=sqrt(3/2)    or x-3=-sqrt(3/2)\nx=3+sqrt(3/2)    or x=3-sqrt(3/2)
378565
x^2 + 4x + 4=7  (first put it in the form ax^2 + bx + c = 0, by subtracting 7 from both sides of the equation)\n\nx^2 + 4x - 3 = 0   (this is called a quadratic equation)\n\nNow substitute a =1, b = 4, c = -3 in the following formula\n\nx equals -b plus or minus the square root of (b^2 - 4ac) all over 2a\n\nBecause you are solving for x^2 you expect to get 2 answers.  The plus or minus in the middle of the formula gets you 2 answers as you solve the formula for both plus and minus the square root of (b^2 minus 4ac).\n\n[If you're going to have to do this in an exam, it's probably worth learning the formula off by heart.  It's boring to have to do so but you'll probably have more confidence in the exam if you see an quadratic equation and already know the formula.]\n\nGood luck for the working out - you can do this bit!
437273
I already answered this in the other thread. Theres no solution: |2x-1| >= 0, so the left hand side is >= 0 + 3 = 3.\nNote that I'm not telling you that you did something wrong - 'no solution' is a perfectly legal answer to 'solve for x'.
384471
Don't you just love the quadratic equation?\n\nThe first thing you got to do is get the given equation into the correct form, and in order to do that you have to combine all like terms. Since there are no like terms yet you have to do some math first.\n\n-2.0^2 = 4.0because neg * neg = pos\n\nNow you have 2 like terms 4.0 and 0.5 combine to get 4.5. Your eqution should look like this:\n\nf(t)=10t + 4.5 since you need at^2 + bt^2 + c just insert t^2. Now your equation will look like this:\n\nf(t)=t^2 + 10t + 4.5\n\nAnd just in case you need the quadratic equation:\n\nt= -b + or - sqr(b^2 - 4ac) / 2a\n\noh yeah and a = 1
396188
x^2 + 3x  = -1\nx^2 + 3x +(3/2)^2 = -1 + (3/2)^2\n(x +(3/2))^2 = (5/4)\nx + 3/2 = sqrt(5)/2 OR x + 3/2 = - sqrt(5)/2\n\n(sqrt means the positive square root) \n\nx = -(3/2) + (1/2)sqrt(5)\nx = -(3/2) - (1/2)sqrt(5)\n\n.......................................................................\n\n2x^2 +4x + 1 = 0\nx^2 + 2x = -(1/2)\nx^2 + 2x + 1 = (1/2)\n(x+1)^2 = (1/2)\n\n(x + 1) = sqrt(1/2) OR (x + 1) = -sqrt(1/2)\n\nx = -1 + sqrt(1/2) OR\nx = -1 - sqrt(1/2)\n....................................\nLW = 783\n\n\n\n(W+2)W = 783\nW^2 + 2W = 783\nW^2 + 2W  + 1 = 784\nW + 1 = sqrt(784)\n\nW = srqt(784) -1\nW + 2 = sqrt(784) + 1\n\n2(W + L) = 2(2) sqrt(784)\n                = 4* 28\n                 =   112
384944
4 (x^2 + 3X -4)\n4(x+4)(X-1)
638643
Vx = -1\nx = -1^2=1\n that's it.
475489
so easy :\nx^2 - Sx + P = 0\n\nwhere, S is the sum of the roots and P is the Product of the Roots :\n\nS = 2+(sqrt)2 + 2-(sqrt)2 = 4\n\nP = [2+(sqrt)2][2-(sqrt)2]= 4-(2) = 2\n\n==> the equation is x^2 - 4x + 2 = 0\n\nhope this helps enjoy !!??!!
42251
How about:\nx ^2/(x^2-4)+1/(x+2) = 0\nx^2/(x^2-4) = -1/(x+2)\nx^2/(x+2)(x-2) = -1/(x+2)\nx^2/(x-2) = -1\nx^2 = -x + 2\nx^2 + x – 2 = 0\n(x+2)(x-1) = 0\ncan you take it from here?
512906
4x^2 - 16 = 0\n4(x^2 - 4) = 0\nx^2 - 4 = 0\n(x - 2)(x + 2) = 0\n\nANS : x = 2 or -2
597777
2(x^2-4x)-1=\n2(x^2-4x+4) -8-1=\n2(x-2)^2-9
379867
you do not even need to complete the square,\nyour equation is the one of an ellipse\n\n9x^2-36x+4y^2=0\n9(x^2-4x+4)+4y^2=0\n9(x-2)^2+4y^2=36\ndividing by 36\n(x-2)^2/4 + (y^2)/9 =  1\n:D
130751
are you trying to solve for x?\n\nFirst, find the factors for the equation.  (x+2)(x+1)\n\nCheck it to see if it's right.  x times x equals x squared. 1x plus 2x equals 3x. 2 times 1 equals 2.\n\nMake one of the parenthesis groups equal to zero.  For example, x+2 = 0   To solve this, x must equal -2.\n\nPut -2 back into the original equation and see if it works.\nNow make the parenthesis group equal to zero.  x+1=0  To solve this, x must equal -1.\n\nTherefore, the answer is using either -1 or -2 will make the equation zero.\n\nHope this helps.  ;)