cd is given by A=P(1+r over n)^nt. you deposit 10,000 for 2 yeats at a rate of 10% what is the return if the bank compound annually(n=1)? if bank compounds quarterly (n=4)? compounds monthly (n=12)? compounds daily (365)?
126098
You seems to mean\nP - sum of initial deposit (10000)\nr - annual rate (10%)\nt - number of years (2)\nn - number of bank compounds per year\nA - finally returned sum of money\n\nWith these definitions, the formula is:\n\nA = P * (1+r/n)^nt\n\nSo, we have:\nn = 1 then A = 10000 * (1+0.1/1)^(1*2) = 12100\nn = 4 then A = 10000 * (1+0.1/4)^(4*2) =~ 12184,03\nn = 12 then A = 10000 * (1+0.1/12)^(12*2) =~ 12203,91\nn = 365 then A = 10000 * (1+0.1/365)^(365*2) =~ 12213,69
214191
You run a bank and a competing bank has a branch across the street.\n\nYou compound your interest annually. So you use the formula: A = P * (1+i)^n.\n\nThe bank across the street says, "We'll compound your interest every month. Their formulate is: A = P * (1+i/12)^(n*12), which gives the customer a little better deal.\n\nOkay, this means war. You start advertising weekly compound interest, or: A = P * (1+i/52)^(n*52), which is a slightly even better deal.\n\nThe other bank compounds daily.\n\nSo you decide to take it as far as you can go. You'll compound continuously. You're formula is:\n\nA = P * (1+i/x)^(n*x) as x approaches infinity. \n\nThe bank across the street can't beat that. Oh, there's no infinity button on your calculator, so how do you calculate savings deposits?\n\nBy running this formula through limit theory, you use the fact that (1+1/x)^x as x approaches infinity is e, and you get the following formula:\n\nA = P*e^(i*n) for continuous compounding.\n\nI don't know of any bank that calculates interest continuously, but there are at least two natural phenomenons that change at a continuous rate.\n\nThe first is population growth, such as the number of humans on the plant, or the number of bacteria in a jar.\n\nThe other is radioactive decay, which is often described as "half-life."\n\nBoth of these natural behaviors are defined by the continuous growth formula, and it cannot be derived without limit theory.\n\nBy the away, we pretty much define calculus using limit theory, but one could argue that calculus isn't part of daily life.
476359
I've got the first part.  I/rt = P\nSo, 93.08/(.065 times 1.33) = 1076.69 dollars\n.\nHere is the second one, I hope. I = Prt .\nSo, 56000times .12 times 1 = 6720\nNow divide 6720 by twelve to find the interest for each month.\nIt's 560 \nSubtract 560 from the monthly payment of 619.36 = 59.36. This is the amount coming off the principal. So after one month the principal is 56000- 59.36 = 55940.64\nHere is the third one.\nI = Prt\nSo 387000 times >147 times 15 = 853335 dollars to be paid back in 15 years. Divide that amount by 180 months(15 years) and you get a monthly payment of 4740.75\nI hope those folks have really good jobs. Ha
471869
OK, here goes nothing.\n\nFor year 1: 25% of 1000000\n= 250000 Depreciation\n\nYear 2= 25% of (1000000 - 250000)\n=187500 Dep. Total Dep =437500\n\nYear 3= 25% of (1000000 - 437500)\n= 140625 Dep. Total Dep= 578125\n\nYear 4= 25% of (1000000 - 578125)\n=105468.75 Total dep= 683593.75\n\nLoss of Rs. 16406.25
6678
use $100\nfv=pv * (1+ I/compounding)^n*compounding \nn = years I = interest\nx = 100 * (1+.0425)^3*1 simple\nx = 100 * (1+.04/2)^3*2 compounded semiannually\nsimple = 113.30\nsemi annual = 112.62\nso simple is better over 3 years
592190
7 cd/9 - cd/9 =\n(7 cd - 1 cd)/9 =\n6 cd/9 =\n(6/3) cd/(9/3) =\n2 cd/3
109088
to be able to solve this, first you have to determine the amount of money in the fund after 30 years of annual deposit. to solve this you'll use the formula for annuity, which is,\n\nP = A [1 - (1+i)^-n] / i\n\nP = is the pricipal, in this case this would be the amount of the fund after 30 years.\n\nA = is the annual withdrawal, which is 50,000\n\ni = is the interest rate, which is 10%\n\nn = is the number of years, in this case it would be 20 years\n\nsubstitute the values of A, i, and n\n\nP = 50,000 [1 - (1 + .1)^-20] / .1\n\nP = 425678.19, this would be the amount of the fund after 30 year\n\nfrom this you can get the annual deposit in the account, you'll be using this formula,\n\nF = A [(1+i)^n - 1] / i\n\nF = is the future amount, in this case it would be the amount of the fund after 30 years, which is 425678.19\n\nA = is the annual deposit, which we are looking for\n\ni = is the interest rate, 10%\n\nn = is the number of years, this time it would be 30 years\n\nsubstituting,\n\n425678.19 = A [(1+.1)^30 - 1] / .1\n\nA = 2587.80
652505
The formula for compound interest calculation is  \nFuture Value = Principal (1 + monthly interest rate*12/100 )^no. of years\nHence $100 would become = 100(1+ 1.67*12/100)^5\n= $ 100(1+20.04/100 )^5\n= $ 100 ( 1.2004)^5\n= $ 100 * 2.4924697\n= $ 249.25 (rounded to two decimals)
101283
Hello,\nI am only in 10th grade. I never heard about nominals or ordinals... percentage is simple, Suppose u want to find the profit%, it will be (profit/Cost price)*100.. Read some lower class maths books. They will help u get ur basics right.\nCumulative frequency can be of two types, less than C.F and Greater than C.F..... Lets use the following data table...\n\n class ....... frequency ....... C.F. (less than)\n 0-10  ........... 3 ............. 3\n 10-20 ........... 5 ............. 5 + 3 = 8\n 20-30 ........... 3 ............. 8 + 3 = 11\n 30-40 ........... 8 ............. 11 + 8 = 19\n\nSo u see, u just have to add the frequencies in less-than C.F... in greater than C.F... U have to add all the frequencies and then subtract the individual frequencies from it...\n Total sum of frequency = 3 + 5 + 3 + 8 = 19\n class ......... frequency ......... C.F.(Greater than)\n 0-10  ............ 3 ............... 19 - 3 = 16\n 10-20 ............ 5 ............... 19 - (5+3) = 11\n 20-30 ............ 3 ............... 19 - (8+3) = 8\n 30-40 ............ 8 ............... 19 - (11+8)= 0...
507695
define i = apr/12\nP = quantity (principle)\nn = time (months in this case)\n\nThe calculation formula for payments is\n\np = iP/(1-1/((1+i)^n))\n\nplugging in the numbers,\n\np = (0.01/12)(17,500)/(1 - 1/((1+0.01/12)^72))\n\nOh, if you just want future amount at compound interest, \n\nA(i,n) = A(1+i)^n\n\nA = 17,500(1+0.01/12)^72
450211
The formula for continuously compounded interest is\nA = P e^(rt) where A = final amount, P = principal (initial amount), r = interest rate as a decimal, and t = time in years.  e is a mathematical constant.\n\nFor your equation, A = 4634 e^(0.08X4) = 4634e^0.32 = 6381.61\n\nSo the interest earned is 6381.61- 4634.00 = 1747.61\n\n\nTo find the effective rate, choose an arbitrary amount, say $100, that you can easily find 16% of.  Then find the actual interest.  The formula for quarterly compounding is\n\nA = P(1 + r/n)^(nt)  where all are as above and n = number of compoundings per year; here n = 4\n\nA = 100(1 + 0.16/4)^(4X1) = 116.98\n\nSo you actually earned 16.98 in interest which would be 16.98% of 100 so 16.98 is the effective yield.
52856
http://www.aea-bank.com/calc/CompoundSavings.html
299886
The formula is\nA = Pe^(rt), where A is the amount returned, P is the original amount, r is the interest rate, and t is the number of years.\nP = 2000\nr = 2% = .02\nA = 2000e^(.02t)\n"How long will it take?" means you are looking for t.\nIn order to find t, you will need to know A.
450705
The math depends slightly depending on what 10% annual return indicates (specifically, if you want the return to be compounded).\n\nHowever, the principle here is that if you're looking at a zero coupon bond, there are no interest payments, so the return is going to be exclusively realized in getting the principal back.  Also, since we're talking about returns, we won't include factors such as the riskless rate, etc.\n\nBasically, you have the following:\n\nToday:  Pay $X to receive bond\n5 Years Later:  Receive $2000\nDesired return:  10%\n\nUsing the more simple example of an uncompounded bond, the formula is:\n\nFuture = Today * (1 + rate) ^ time\n\n$2000 = $X * (1.10) ^ 5\n\nBacking it out, $X = $1241.82\n\nIn this case, having a zero coupon bond makes the math easy.  Had it paid a coupon, it would have been a tad more complicated.
94488
In total the dude made 9000, which is not quite a lot to be honest for me. (I spend too much). Anyway!\n\nSay the amount he invested at 7% is X, this would naturally make the rest 9000-X, right? Good.\n\nSo hee is the math!\n\n0.07*X + 0.1(9000-X)=720 ....... clear! Now for simplicity, multiply all by 100 and you will get:\n\n7X + 10(9000-X) = 72000 ... and after distribution:\n7X + 90,000-10X = 72000\n-3X = 72,000-90,000 = -18,000  \nX = -18,000/-3= 6,000\n\nSo this is the amount he invested at 7% and the rest, as we shwed earlier, is 9,000-X = 9,000-6000 = 3,000\n\nSo he invested $3,000 at 10%.\n\nOf course you know this is true if the interest was made in one year and without talking taxes, which would be anouther story.
665464
Goose is right. The formula is:\n\nFV = P x e^(r x y) \n\nwhere FV = Future Value; P is your principal, r is the annual interest rate and y is the number of years of continuous compounding and e = lim(n-->inf) of (1+1/n)^n\n= 2.7182818.(about)\nHere's link which explains it quite well and also has a periodic/continuous calculator to fool around with.\n\nhttp://www.moneychimp.com/articles/finworks/continuous_compounding.htm
392184
Assuming you start at the beginning of a month\n\nFirst investment = $350\nAfter the 1st half month amount saved =  $(350(1 + r) + 350)\nAfter 2nd half month amount saved = $((350(1 + r) + 350)(1 + r) + 350)\n=$(350(1 + r)² + 350(1 + r) + 350)\nAfter 3rd half month amount = $350((1 + r)² + (1 + r) + 1)(1 + r) + 350)\n= $350((1 + r)³ + (1 + r)² + (1 + r) + 1)\nThat will mean that, at maturity,\nAmount = $350((1 + r)^20 + ...  + (1 + r)³ + (1 + r)² + (1 + r) + 1)\n= $350 ((1 + r)^21 - 1)/((1 + r) - 1)\n= $100000\nSo [(1 + r)^21 - 1] / r = 100000/350\nSo r/[(1 + r)^21 - 1] = 0.0035\nUsing Excel r = 0.2185\nie 21.85% per half year\nor 43.7% pa ... a rather ambitious interest rate!!\n\nAnd it would need to be high considering you are only investing 20 * $350 ie $7000 to mature at $100000 in 10 years