crash test on motor cycle with stationary object or moving object
120408
your gonna regret it...there has to be a better project than that?
291020
upside down\nwhile driving
5497
(a) it's an inelastic collision.  An inelastic collision is when they stick together, and an elastic collision is when they bounce off of each other\n(b) p=mv  momentum= mass x velocity.  p= 30 m/s x 500kg = 15,000 kg*m/s\n(c) well, momentum is conserved, so the we would use the formula from before and the momentum(p) from before, except that now the mass is different because it is the combined masses of the two vehicles (300+500=800) , so you can solve for the new velocity.\np=mv  15000 = 800 x v\n\ndivide both sides by 800 to get  v=15000/800 = 18.57 m/s
408612
Between 30 and 40 mph.
20932
car, windmill, bicycle, propeller, anything with gears, hope this helps
344783
ok biker bike, here we go.\n\nacc.= g = 9.8 m/s2, (any object moving in air will have this acc. or retardation)\n\nb) we apply formula\ns=ut + 1/2at^2\nu=20\nt=4\ns=20*4 + 1/2 *9.8 *4*4\n  =158.4 m\n\nc) v=u + at\n  therefore, t= v-u/a\n                   =50-20/9.8\n                   =3 seconds (approx)
329291
It's 220mph, near enough, so you're looking at perhaps a bullet, or a jet. It might be worth dropping it to 49 m/s (110mph) or even 24.5 m/s (55mph) to bring it within the range of a sports car or ordinary motor.
407951
This is a momentum question.  If the end result is comming to a halt, then then each vehicles' momentum was equal and opposite.  Momentun (M) = mass (m) * velocity (v),  therefore you are left needing to solve the equation m1*v1 = m2*v2...you can do the rest I hope....
511051
The given final speed doesn't seem to compute. I get 14.8 m/s. \nMa*Va + Mb*Vb = (Ma+Mb)*Vf \nis the formula that applies to show conservation of momentum in a completely inelastic collision, which is what you have. The only explanation I could suspect is some cargo was spilled. \n\nTo continue the assignment - kinetic energy is given by\n(1/2)*m*v^2\nThere is no requirement that all the original kinetic energy be measurable as kinetic energy after a completely inelastic collision. But you should be able to point to where the missing energy went. Some of the energy probably went into cart damage. Perhaps the cargo slid around.
28758
Engine = Gas\nMotor = Electric
385413
check the jumpers \nand check that you did not break a pin off
459691
The braking force was enough to dissipate the kinetic energy.\n\nForce x distance = work = kinetic energy\n\nma x 160 = mv^2/2 , notice that m cancels out\n\n160a = v^2/2, solve for v...
542631
if they are both going at the same speed, then the mass,size of the wheel and other considerations have already been take in account, so they both should arrive at the same time.\nGod bless,\ngabe
148343
The motorcycle. I think this is something that should have never been invented. I feel it is very unsafe. I hate to meet one on the road. People have lost their lives needlessly on these things. They don't make any sense. Who wants to go down the road on two wheels in storms and pouring down rain. They have very little protection against oncoming traffic.
510894
The condition for max v is\n\ng = v^2/r\n\nSo vmax = sqrt(gr) = sqrt(42.1*9.81) = 20.4 m/s.\n\nThat's the speed at which accelaration due to gravity is just enough for the wheels to stay in contact with the road (and the reaction force from the road is zero).\nTo see why, read my answer to your earlier related question.
330827
Design Failure Modes and Effects Analysis (DFMEA)\n\n\nhttp://www.sasltd.net/dfmea.htm
504733
To both of our surprise there is a direct analogy between electrical components and mechanical systems. Mercedes has presented a simulation of their suspension system that performed million simulation routines by using coils capacitors and resistances. \nYes my friend a capacitor an inductor and a coil can be directly related to a dumping or suspension or oscillating system in mechanical system where potential and kinetic energy and losses of course can be correlated with capacitance (electrical and magnetic energy), inductance and resistance. \nI am not sure 100% of what you are trying to say and what you have in mind but I am sure that you can make something of it. Or at least simulate it and represent it right.\nThe reason we ended in this is because the analogy was more than obvious and because it is easier to simulate circuits and get reading (multiple set) than to perform test with mechanical sensors etc.\n\nNice question\nKeep thinking \n\n\n(do not get your mind wasted though mate.!)