ihave this math problem thatr says\nquantitative comparison:\n         column A                  column B\n         180(.5)^2                20(1.5)^2\n\nand i have no clue what it wants cause i missed four days of school coming back from spring break \nsomeone please explain what i am suppose to be doing i don't actualy want the answer just an explanation
130132
Google is my friend is it urs???
484842
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
41102
you have to solve p such that S=D=Q.\n\nfrom S, p=Q/10 -70\n\nput that instead of p into D equation, solve for Q\n\nthen use that Q to compute p=Q/10 -70
483905
Gary, that's a good one, but one mistake...\nyou said that a=b, thus you cannot divide by (a-b) b/c that equals zero, and you cant divide by zero.
357063
ya, that one has the same dimension as that of time.see how that eqn is derived.you find distance covered by 'n' seconds then distance covered by (n-1) seconds.subtract.and you get the eqn.... but see wat is the difference b/w the time n and n-1. it is one second..this is the one that appeared in the eqn and confused you.is it clear?
482309
I hope you appreciate this since it is a bit of work. Hopefully it will help you solve similar problems. There are problems with the data you presented but you will get the idea of how to solve these problems.\n\n1) the cost function C(x) is:\n \nC(x) = (-x^2+165x+136)/120\n\nYou need to determine a,b,c from 3 independent equations of the form ax^2+bx+c = specified value.You can choose any 3 of the 5 data points to determine a,b,c. I chose the first 3 and determined a,b,c. However, though the above function works for x =1,4,5 it does not work for x=7 or 10. So the data is inconsistent. Also, this is not a realistic cost function since if x>165.82 the cost becomes negative.\n\nIf x =1....  a+b+c=2.5\nIf x=4...16a+4b+c=6.5\nTaking the difference between these equations gives:\n15a+3b=4 \nb = (4-15a)/3 = (4/3)-5a\n\nIf x= 5....25a+5b+c = 7.8\nor using the value of b above\n25a+5(4/3 -5a)+c =7.8\n25a+20/3-25a+c = 7.8\nc=7.8-20/3 = 39/5 - 20/3 = (117-100)/15 = 17/15 = 136/120\n\na+b+c=2.5\nSo a+4/3-5a+17/15 = 2.5\n-4a = 2.5-17/15-4/3 = (37.5 -17-20)/15 = 0.5/15\na= -0.5/60 = -1/120\n\nb=(4/3)-5a = 4/3-5(-1/120) = 4/3+5/120 = 165/120\n\n2) The average cost per unit x is:\n\n C(x)/x = -x/120 + 165/120 + 136/120x\n\nd/dx C(x)/x = -1/120 - 136/120x^2 \n\nWhen the average cost is a minimum this must = 0\n\nSo 0=1+136/x^2 but this would make x^2 = -136 which is impossible. It would still not make since if it was the Total cost which you were trying to minimize, snce, as mentioned, for large enough x this becomes negative and increasingly so.\n\n3) The total cost is given by the the function C(x). The elasicity E is the sensitivity of the total cost to a change in production.\n\nSo E = d C(x)/dx = C' (x) = (-2x+165)/120\n\nthe average cost per unit x is:\n\n C(x)/x = -x/120 + 165/120 + 136/120x\n\nThe elasticity is again given by the derivative of this funcion:\n\n= d/dx C(x)/x = -1/120 - 136/120x^2\n= (-1/120)(1+136/x^2)\n\nWe see that this elasticity is negative.
506075
The answer is:  4.47, and that's all there is to it!\n\nOk Vanessa, all you have to do is pull up your calculator (Start>Accessories).\nI am not suggesting you don't work it out in your head first: it's just basic. Check the answer on the calc, or, if you get stuck....go back.... to POWERS OF HIGH HOLY ROOTISM   SQUARE YOU KNOW, 1x1+(2x2)+2+(10-5)/1=       Simple:\n1+4+2+5/1=12
146554
hahahah that doesn't make sense in order for two sides of an equation to be equal the numerical value of each side must be the same.  Whats with all the equals signs!
514432
Problem 1:\nColumn A: Slope of 2y=3\nColumn B: Slope of y+2x=3\n\nAnswers:\nThe quantity in A is greater\n\n\nProblem 2:\nColumn A: 3x(squared)+4x=15\nColumn B: x(squared)-7x+12=0\n\nAnswers:\nCannot be determined\n`
532408
That simplifies to 3[2x-1]>12\n\n[2x-1]>4\n\n2x-1>4    2x-1<-4\n\nx>5/2  or x<-3/2\n\nWhen you have absolute values, you have to look at both ends of the spectrum
457402
Come on now, what is the formula for this???  :)\n\n(V1 * T1)/P1  =  (V2 *T2)/P2\n\n(69L * 131)/2.85  = (xL * -37)/2.85\n\nNow, solve for 'x'?  Be sure to watch your units!!!!
174505
haha, but this does not work. you cannot mathematically divide by (a-b) because this quantity is equal to 0. (1-1)=0. Dividing by zero yields an indeterminate answer.
473261
something is wrong in the way the problem is stated\nboth the answers are wrong, according to me.\nif you differentiate -19800-50.01x  you will get -50.01 and that cannot be equated to zero
406683
Why didn't you just ask me?  You could have emailed and saved 5 points.\nMy solution did indeed contain a typographical error omitting the q from the value of m.\nAlso, I had amended the solution with a comment shortly after the question had been resolved.  (There was another small error as well.  It is very difficult sometimes typing and then proof-reading mathematical proofs in these Yahoo boxes, especially when they contain alot of special characters.)\n\nSee:\n\nhttp://answers.yahoo.com/question/index;_ylt=ApZ1XohHNUdL5xkBg8bXQEfsy6IX?qid=20061124162535AAURdJ5
519078
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today
414726
Do out col. A and get 6x - 2 = 13; 6x = 15; x = 15/6; x = 2.5\n\nDo out col. B and get 36 = 9x + 36; 0 = 9x, 0 = x\nSo col A is greater\n(assuming they put an x over the 2 columns)
448459
+SEE\n+YOU\n-----------\nSOON\n\nS must be 1, so\n\n+1EE\n+YOU\n-----------\n1OON\n\nTens column is E+O=O.  If 1 is retained from units column then E=9.  If not, E=0 - impossible since this would mean U=N.  So E=9.\n\n+199\n+YOU\n-----------\n1OON\n\nWe must have Y=8 in order for 1+Y+retainer being at least 10.  This also means O=0.\n\n+199\n+80U\n-----------\n100N\n\nThere are many possibilities for U and N resulting in the following solutions:\n\n199+803=1002\n199+804=1003\n199+805=1004\n199+806=1005\n199+807=1006.