How can we calculate height centimeters to foot.\nfor eg: 154cm then tell me answeer with eg
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http://www.digitaldutch.com/unitconverter/\n\nhas a converter for unit conversion.\n\n1 foot = 30.48 cm\n\n154cm = 5.052feet
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Multiply inches by 2.54 to get centimeters.\nDivide pounds by 2.2 to get kilograms.
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height by width measured in feet
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take calicium supplements to get taller. I should know. I take them and I am only 12 but are 5 feet 7 inches
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1 FT = 12 INCH\n1 INCH = 2.54 CM\n\nTHERE FORE:\n\n5 FT + 6 INCH = 66 INCHES\n66 INCHES = 167.64 CM
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.794cm=.313in\n1.59cm=.626in\n.953cm=.375in\n\nyep, visit my site too
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The safest way to do any unit conversion is to just multiply your initial value by 1 unil the units are what you want. I know this sounds strange. I will explain by doing a more complex conversion.  This technique works for all conversions.\n\nI don't know the direct conversion from miles to km or from cm/sec to mph, but I do know this:\n\n1 inch = 2.54 cm\n100 cm = 1 m\n1000 m = 1 km\n12 inch = 1 foot\n5280 foot = 1 mile\n60 sec = 1 minute\n60 minute = 1 hour\n\nI can take any of the above equations and make the number one by dividing one side by the other ( 1 = (2.54 cm)/(1 inch)).\n\nI will convert 1 mile to km by taking 1 mile and multiplying it by 1 until all the units but km cancel:\n\n1 mile = 1 mile x (5280 ft/1 mile) x (12 inch/1 foot) x (2.54 cm/1 inch) x (1 m/100 cm) x (1 km/1000 m) = 1.609344 km\n\nGo through the above carefully to make sure its clear. Once you get comfortable with the concept of mulitplying by 1 and cancelling out the units properly, you can do any unit conversion.\n\nTake 30 cm/sec to mi/hr:\n\n(30 cm/sec) * (1 in/2.54 cm) * (1 foot/ 12 inch) * (60 sec/min) = 59.055 ft/min\n\nTake it from there.
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All you need to do is know the density of water- not too difficult to find! THe psi necessary to support a column then must match the weight of that column. So, if a column is 1inch in area and Hinches high, if you know D the density of water per cubic inch in pounds, the height of the column in inches times this value is the psi needed.\n\nPressure psi=H*D\n\nThis also works for metric, just use cms and kgs as the base sizes.
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The first thing you need to do is to have the same units. This applies to any measurement question. If it were 20g as a percentage of 30kg, you'd need to have both terms in the same units before moving on.\n\nIT makes the most sense to convert 3 metres to centimetres (so that we aren't dealing with decimal numbers), which is, of course, 300 cm. \n\nSo, now you have 20 cm and 300 cm. This is like having a mark of 20 out of 300. So, you do 20/300 then multiply by 100 to have a percentage mark.\n\n20/300 * 100 =6.67% (or to whatever decimal place you are supposed to give your answer)
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http://www.onlineconversion.com/length_common.htm\n\nthat's for height.\n\nhttp://www.onlineconversion.com/weight.htm\n\nThat's for weight.
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a) km\nb) cm\nc) mm\nd) cm\n\n(height is in cm on my license)
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Remember that you have to do the conversion from cm to km (1m/100cm)*(1km/1000m) and from year to hours (365days/1year)*(1day/24hrs).  Kilometers should end up on top of the fraction and hours on the bottom.
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See previous answer--\n\nGives vertical height as rt27\n\nTherefore 1/2*6*rt27 is area of one side\n\nBase is 6*6 = 36
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5'6 in feet and inches = about 1meter and 65 cm \n\nI got the info on the internet I don't know how credible it is
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This is a simple dimensional question.  There are 2.54 cm in one inch.  For simplicity, you should set up the problem like this:\n\n3.33 cm (1 inch/2.54 cm) = 1.31 inches\n\n(that answer is to the correct number of significant figures, since you have only three in your problem)
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means that the base is 4 cm rite?\nok, u obtained the base, then now u need the height.\nHow to find the height?,\nUse trigo!. U know what izzit, well, i assume u know.\n\nFirst split the triangle in half. \n            /|&#92;\n           / | &#92;\n          /__|__&#92; \ntake one side only,\n            /|\n           / |\n          /__|\n\nthe slant side is 4 cm rite?,\nand to find the height,\n\nsin 60 = opposite/hypotenus\nopposite = (hypotenus)sin 60,\nopposite = 3.46cm.\n(oppossite is the height, hypotenus is one of the side of the triangle)\n\nU have the height!\nUse triangle formula\nArea = 0.5(heigth)(base)\n     = 6.93cm(squared)\n\nOR, for easier way,\nuse trigo formulae for triangle area\n\nArea = 0.5*a*b*sin C\n(C is the angle of any two sides while a and b is both sides making the angle)\n\n     = O.5 (4) (4) (sin 60)\n     = 6.93 cm squared
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Do you already know where the CM of the hemisphere is?  Because I don't and it would take me a while to work it out.  Anyway, it would be on the vertical radius, so the horizontal position of the CM of the composite body is on the radius drawn to the particle, distant 0.2*r/4.2 from the centre.  If the height of the CM of the hemisphere above the centre is h, then the height of the CM of the composite body is\n4*h/4.2