the following are the scores earned by 15 college students on a 25 point quiz. ( 0,1,3,14,14,15,16,16,17,17,18,18,19,20)\na) Calculate the, mean, median & mode value.  can someone please help with this question. THANK YOU.
136538
ill help\n\nmean is average.  add all the numbers together and divide by 15.\n\nmedian is the middle number. put them in order from highest to lowest and find the 8th number.\n\nmode is the number that appears most frequently.\n\nim sorry, but i can't calculate it because i can only see 11 scores.\n\nedit: ok, i can see them now.\n\nmean: 206/15 or 13.73333333... (three repeating)\nmedian: 16\nmode: 18\n\nhope this helps you! have a nice day! :)
353976
If you've taken five tests already, the next one will make six. So to find the average after the next one, you will add your six scores and divide by 6. Therefore, you add 100+90+82+96+78, which equals 446. If you want the highest possible, you add 100 to make 546. 546/6=91
516898
I think this is what you are trying to do...\n\nLets say F49 is a test score, and if the test score is less than 21, it's a fail, and if it is less than 31 but more than 21 it's a pass, anything over 31 is Excellent.\n\nYou need to write the formula the other way round.  Remember that computers only work logically, and we make assumptions that don't work in logic.\n\nAn IF statement says, if this is true, do this, and if it's not, do that (where that can be a new question).\n\nSo,\n\nIF(F49<31,"IF(F49<21,"FAIL",\n"PASS")","EXCELLENT")\n\nThis says, is the score less than 31?  If it is, then is it less than 21?  If it is less than 21 enter FAIL, if it's not (and so is between 21 and 31, then enter PASS).  If the score is greater than 31, then enter EXCELLENT.\n\nSorry if this confuses you more, perhaps if you can explain exactly what you are trying to acheive.....\n\nExcel help will shed a little light, but not sure if it gives you embedded examples.
215052
Well if these are scores off an assignment or test and the score is out of 100, then\n\n94 = A (Very Good)\n85 = B (Good)\n85 = B (Good)\n81 = B- (Fairly Good)\n73 = C (Fair)\n\nTotal average out to 83.6 = B. For 6th grade you did very well, so be proud. You are on the right track so far.
80672
GPA is usually calculated on a 4.0 scale.  An "A" is worth 4.0.  A "B" is worth 3.0.  You need to add up all of your scores (e.g. if you had two "B's" and five "A's", then you would add them together to get 26) and divide this number by the total number of scores (e.g. in this example, you would divide 26 by 7, since this was the total number of scores you added up; you get a result of 3.71, which is your cumulative GPA).  The result of this division will be your cumulative GPA.  Keep up the good work!
163150
Sorry your answer was wrong.\nMean can be less than median also as median is not affected by extreme numbers at its both ends while mean is.\n\ne.g. find mean and median of following data.\n     1, 3, 5, 9, 18, 180\n\nhere your answer for mean will come to\n               36\n\nwhile if you find median for it then it will come to\n            7\n\nIn this example mean was greater than median.\n\ne.g. -180, 18, 5, 3, 1, 9\nhere your mean is -24\n\nwhile your median is 4.\n\nSo from both example you can say that\n\nnone of them is always greater than other one nor it is always smaller than other one.
422517
Your data set would look like this:\n\n10 10 10 10 10 10 10 10 10 10 20 20 20 20 20 20 20 20 235 235\n\nThe mean is 730/20 = 36.5.\nThe median is (10+20)/2 = 15.\nThe mode is 10.\n\nSo certainly what was stated by the dean isn't a lie.\n\nNow, if I were to calculate, say, the average number of classmates for each person in the statistics classes, there would be 100 9's, 160 19's, and 470 234's.  So the average number of classmates for people taking these classes is approximately 113,920/730 = 156.05.  The median is 234 and the mode is also 234.  So the newspaper isn't really lying either.\n\nI guess you can say that they are looking at this from two different perspecitves, so in that sense, there are two truths.
281020
Sure you have learned it. It's addition. If the mean (average) must be in the middle (the third number) then the numbers are:\n\n15,16,17,18,19\n\nand sum is 5*17 or 85
446842
The mode is the data point that appears the most often. From the problem statement, there's a single mode, 5. So, since there are 3 cards, then at least 2 of the cards must be 5. (If all 3 cards are different, then there would be 3 modes.)\n\nSo the cards are 5, 5, and x. (x could be 5 without changing the mode). Now, look at the mean. To find the mean, add up all the values, and divide by the number of values. So add 5 + 5 + x to get x + 10, and divide that by 3. That expression must equal 8.\n\nSo, you now have an equation to solve: (x + 10) / 3 = 8. Solve it as you normally would:\n\nmultiply both sides by 3 to get x + 10 = 24\nsubtract 10 from both sides to get x = 14.\n\nSo the 3 cards are 5, 5, and 14. The mode is 5, and the mean is (5 + 5 + 14) / 3 = 24 / 3 = 8.
303072
If everything but the final is complete and you have an 87% then... \n\n.85*(87) + .15*Final = 80\n\nFinal score = (80 - .85(87))/.15 = 40.333%\n\n\nBut try your best
320950
Usually to judge a student's grade, we use mean (or average) to make comparison. Average mark for A is \n\n(50 + 100 + 90 + 60 + 120 + 140 + 60 + 120) / 8\n= 92.5\n\nwhile average mark for B is\n(20 + 140 + 160 + 100 + 100 + 40 + 120 + 80) / 8\n=95\n\nIf the average score is used to judge their intelligence, then, B is more intelligent because B has more score than A.\n\n\nConsistency can be test using standard deviation. Standard deviation is a measurement of how spread out the values in a data set are. More precisely, it is a measure of the average difference between the values of the data in the set. If the data points are all similar, then the standard deviation will be low (closer to zero). If the data points are highly variable, then the standard variation is high (further from zero)\n\nTo calculate standard deviation for A, we sum up the square of each data difference from mean value,\n\n(50-92.5)^2 + (100-92.5)^2 + (90-92.5)^2 + (60-92.5)^2 + \n(120-92.5)^2 + (140-92.5)^2 + (60-92.5)^2 + (120-92.5)^2\n= 7750\n\nThen the sum is divided by number of scores, 8\n7750/8 = 968.75\n\nFinally, standard deviation for A is the square root of value 968.75, \nSD = ��68.75 = 31.12\n\nSame procedure is also used to calculate SD for B, and you will find the value of SD is 44.44. Lower the value (closer to zero), higher the persistency of the data. Thus, A is more persistent.
319704
The mean and the mode of a normal curve are the same.  In your example this would be 400.  80% of your scores are within 10 of the mode.  Typically 68% of tests are within 1 standard deviation and 95% are within 2 standard deviations.  But a deviation of only 10 just seems too low compared to the total range of +/-200 from the mean.\n\nLooking up 80% in a table, that equates to 1.28 standard deviations, or about 7 points of standard deviation.  In a normal distribution of test scores, I would expect the bell to be neither too flat or too steep, but this distribution seems to be rather tall in the middle.  It would look more like the first drawing in the attached link.
348019
1.  Using your Normal Distribution table (sorry, mine is buried under my dirty laundry), find the Std Devs that represents .18 (.50 - .32).  Multiply by 30 (Std Dev).  This number represents the number of pages short of 150 (the mean).  It's probably around 140.\n\n2.  The second group (.18 below 150 pages + .25 above 150).  Repeat the process for 1 above. (about 140 to 165)\n\n3.  The third group is from .25 to .49 above the mean (about 165 to 240)\n\nGood luck.
274193
1,3,5,8,8\n\nUsing these numbers, the mean is 5 (1+3+5+8+8=25  25/5=5), the median (middle number) is 5.  The mode is 8 since it appears the most.  \n\nTherefore, the difference between the largest and smallest number is 8-1=7.
534941
1)math 13,,and math 14,,\ni didnt get what did u mean by that,,\nbut i think,,the number of quizzes in math 13 and math 14,,may not be the same,,\n\nfor eg,,\nif there r 5 quizzes in math 13,,\nthe total score is,,60 into 5 = 300,,\nand if there r 4 questions in math 14,,\nthe total score is,,70 into 4 = 280,,\nthus,,\n(280+300)divided by (5+4)\nthats total average,,and is not necessarily be 65,, \n\n2)theres one possibility,,\nthat all students got the same scores,,that is the mean score of the class,,
29308
The Mean is the average.  You have 22 numbers; add them up and divide by two to get the mean.  In this case, that gives 87.38\n\nThe median is the "middle" value.  Since you have 22 numbers, 11 of them will be below the median, and 11 will be above.  In your case, the 11th biggest number is 87.9 and the 12th biggest number is 88.  The median could be anything in between, but is generally taken to be the average of these two- or 87.95\n\nThe mode is the most common value.  In your case, each value occurs only once, except for 91.7 which occurs twice.  Therfore, 91.7 is the mode\n\nUpper and lower quartiles are similar to the median; The lower quartile is the value below which 1/4 of your values lie, and the upper quartile is the value above which 1/4 of your values lie.  Since you have 22 numbers, the lower quartile is the value between the 5th and 6th largest numbers (82 and 83.6), and the upper quartile is the value between the 17th and 18th largest numbers (92.9 and 94.2).  That makes 82.8 and 93.55\n\nThe range is the minimum value to the maximum value, or {68 to 98.2}\n\nTo get the variance, first subtract the mean from each value.  Then, take the square of each of these new values.  Then, add up all these squares.  Finally, divide this sum by the number of values (22 in your case).  This should give a variance of 51.22 with your numbers.\nNOTE:  The above formula is for "population variance", and is generally used when your numbers represent an entire population.  If your numbers represent a sample of a population, you should use the "Sample Variance", which has the same formula except that you divide by the number of values minus one (21 in your case).  With your numbers, this should give a sample variance of 53.66.\n\nThe standard deviation is just the square root of the variance.  Like the variance, there is a "population standard deviation" (7.16 in your case) and a "sample standard deviation" (7.33 in your case)
428033
1) two make-ups get 40 and 70\n2) make-ups get 68 (current mode)\n3) denote the score of one make-up student as x, write out the mean, set it equal to 58 and solve the equation (it is your homework, remember?)