Solve:2+7/x=4/x^2\nPlease explain how you would do the problem.\n\nThank you.
128652
Here is what I would do:  multiply each term by x^2 to get rid of the fractions:\n\n2x^2 + 7x = 4\n\nThen move the 4 over to get a quadratic equation in solving form:\n\n2x^2 + 7x - 4 = 0\n\nThen factor by FOIL: (2x - 1)(x + 4) = 0\n\n2x - 1 = 0 means x = 1/2; x + 4 = 0 means x = -4.\n\nCheck these to see that they work.\n\n2x^2 + 7x - 4 = 0
445734
x^2 + 4x + 4 = 7 (subtrat 7 from both sides)\n\nx^2 + 4x -3 = 0 (use the quadratic equation formula)\n\n-b + or - the square root of (b^2 - 4ac) / a^2\n\n-4 + or - the square root of 16 - (4) (1) (-3) / 2\n\n-4 + or - the square root of 28 / 2\n\n-4 + or - (the square root of 4) (the square root of 7) / 2\n\n-4 + or - 2 (the square root of 7) / 2 (simplify by dividing 2 into  the -4 and 2 on the top to get rid of the 2 on the bottom)\n\nthat gives you x = - 2 + or - the square root of 7.
349671
You have to complete the square.\n\ny = a(x^2 + b/a x) + c\ny = a(x^2 +b/a x + b^2/4a^2) + c - b^2/4a\ny = a(x + b/2a)^2 + (4ac - b^2)/4a\n\n[4ay - (4ac - b^2)]/4a = a(x + b/2a)^2\n[4ay - 4ac + b^2]/(4a^2) = (x + b/2a)^2\n\n+/- sqrt(4ay - 4ac + b^2)/2a = x + b/2a\n\nx = (-b +/- sqrt(4ay - 4ac + b^2))/2a
568619
You got it right so far. But next...to multiply by 1/4...is the same thing as dividing by 4. So take 4x^2/4=x^2 and then -4/4=-1...so you get x^2-1...make sense? I hope I helped...God bless.
528970
Add them... 8+7+7+5+3+2+2= 34 and divided by 7\nYyou have 34/7=\nYou know 4x7= 28 so you need 6 more to reach 34\nso you have 4 and 6/7
559180
take the equation x^2 - 7x + 12 and do the following  (x ) (x) now...see that there is a - and a + in the equation....you need to do this ( x -  ) ( x - ) 'cause you put the minus in the first factor in the second factor you take the - and the + and multiply them....So you get (x- ) (x -) the other 2 terms for each equation comes from the 7x and the 12.  What you do is to find 2 numbers that multiplied gives you 12 and added give you 7....The numbers are 3 and 4 ...Then put them into your factors (x-3)(x-4).\n\nFor the other 2 equations you do the same process\n\n(x^2 - 8x + 7) = (x-  ) (x-  ). In this one, you have to find 2 numbers that multiplied give you 7 and added give you 8. They are 1 and 7. Then (x^2 - 8x + 7) = (x- 1 ) (x- 7 ).\n\nw^2 - 8w + 15 = (w - ) (w- ). As you saw in one and two, three is the same....so the factors are 3 and 5. Then, w^2 - 8w + 15 = (w -3 ) (w-5 )\n\nFor the solve...\n1. x^2 - 6x = 0\n2. x^2 - 2x - 3 = 0\n\nTHe 1 is like this...you have to complete your quadratic equation then you do the following x^2 - 6x = 0 --> x^2 - 6x + 9 =0+ 9...The 9 in the right side was added in order to keep the two sides equal...IN the left side you got a perfect quadratic equation, hence it will be (x-3)^2= 9....Now you pass the 9 of right to the left ...then it will be [(x-3)^2]-9=0\n\n\nThe other equation x^2 - 2x - 3 = 0....This one is quite simple, it is the same as the part 1...The difference is that when you find the factors, they will be 2 numbers that multiplied give you 3 but substracted gives you 2.....The #s are 3 and 1....Here is the thing....when you break the equation into factors, you will have the following (x- ) (x+ )...Since you have a -2 that means that it is the -3 and the +1...Hence your factors will be the following (x-3)(x+1)
76705
Please use parentheses to explain the problem more effectively. Assuming the problem as,\n\n(x-1)/2x + x/(x+3)\n\nThe solution can be,\n\n(3x^2+2x-3)/(2x^2+6)
501663
4x+3/2-2x-2=3-x-4/3+2x-5        then you add everthing up\n\n2x-1/2=x-3and2/3           Sorry for the and....i didn't want it to look like 32 divided by 3....it's 3 and 2/3\nmultiply each side by 6...\n12x-3=6x-22\nThen you have to simplify \n6x=19  Divide each side by 6 to get the answer\nx=19/6\nI'm pretty sure but im not absolutly sure....
370965
x^2-5x-14=0\n=>x^2-7x+2x-14=0\n=>x(x-7)+2(x-7)=0\n=>(x-7)(x+2)=0\nTherefore either x-7=0 or x+2=0\nIf x-7=0,then x=7,and if x+2=0,then x=_2\nThereforex=7 or -2 ans
421924
x^2+1/x^2\n=(x+1/x)^2-2\n=4-2\n=2\naliter\nby reasoning we can say x=1\nso x^2+1/x^8\n=1+1\n=2
612557
I assume the equation is:\n\n4/(x+3) = 6/(4-x)\n\nFirst cross multiply (denominator on left to numerator on right and denominator right to numerator on left) \n\n4(4-x) = 6(x+3)\n16-4x = 6x+18\n\nCombine like terms, x's on one side, numbers on the other\n\n16-18 = 6x+4x\n-2 = 10x\n\nDivide both sides by 10 to isolate the x\n\n-2/10 = 10x/10\n-2/10 = x\n-1/5  = x\n\nThat's it!  Have fun!
369872
y = 2 - 3x\ny = 2x + 4\ny = 4x/3 + 4\ny = 3x - 4\ny = 7x/2 + 5\n\nNot triying to bother the other guy, but i think you did #4 the wrong way. Check the "-" before the "y" in the original equation.
385676
2(2x-4)= x+4\n4x-8 = x+4\n4x-x = 8+4\n3x = 12\nx=4\n\n&\n\n4(x+3)+3= 5(x-4) + 5\n4x+12+3 = 5x-20+5\n4x+15 = 5x-15\n4x-5x = -15-15\n-x= -30\nx = 30\n\n&\n\nx+2= 4(5x-2)\nx+2 = 20x-8\n2+8=20x-x\n10 = 19x\n19x= 10\nx=10/19\n\n&\n\n21-3x = 4x+7\n21-7 = 4x+3x\n14=7x\n7x = 14\nx=14/7\nx=2
188908
(3x^3-7x^2+x-20)/(x-3) = 3x^2+2x+7 with a remainder of 1\n         \n         3x^2+2x+7 \n     _______________\nx-3 | 3x^3-7x^2+ x-20\n      -3x^3+9x^2\n    __________\n          2x^2+ x\n         -2x^2+6x\n         ________\n              7x - 20\n             -7x + 21\n             ________\n                   1\n\nI tried to show what this would look like as a division problem but it keeps jumbling up.
494268
let u = x^2 + 1, then you have du = 2xdx, => dx = 1/2x du,\n\nsubstitute back you are on the way  to solve it
666491
(7/(3x)) / (x/3)\n(7/(3x)) * (3/x)\n21/(3x^2)\n7/x^2\n\nBut if you meant\n\n((7/3)x)/(x/3)\n((7x)/3)*(3/x)\n(21x)/(3x)\nANS : 7\n\n-------------------------------\n\n2 1/3 - 3/4\n2 1/3 = (7/3)\n\n(7/3) - (3/4)\nMultiply everything by 12\n(28 - 9)/12\n(19/12) or 1 (7/12)
260832
(8/x+2) + (8/2) = 5\n\n(8/x+2) + 4 = 5\n\nSubtract 4\n\n(8/x+2)=1\n\nMultiply x+2\n\n8= x+2\n\nSubtract 2\n\nx=6