How much s-3 asphalt weights per square yard @ 1" thick?
131483
the unit weight of asphalt s-3 is \nabout 1,02-1,04 ton/cubic.metres\n\n1 yard = 3 feet = 38 inches = 0,9144 metres\n\nthe volume asphalts did you meant is \n= 1x1xthick \n= 1x1x(1/38)\n= 0.026316 cubic.yard \n= 0.020119 cubic.metres\n\nSo s-3 asphalt weight per square yard @ 1" thick is about\n(20,52138-20.92376) kilograms
158562
It's difficult to find a plywood any thicker than 3/4", hardwood or softwood. In dimensional lumber measurements, 1" is usually referred to as 5/4...but that's not plywood.  You might try WoodPlanet at www.woodplanet.com ... They have 1" thick sheets of 4'x8' hard maple plywood, A/A grade, good on both sides, which sounds like something you might be looking for.
405964
This question really sound silly but using one's logic and with the aid of the table of conversion I came to this solution...or shall i say my conclusion. 3ft= 1 yard   therefore if i'm going to buy a yard of meat then the butcher will give me three lower limbs or three feet of meat ( pork, beef, or whatever that has feet).
152383
I work in a hardware store, just as an introduction.  So I am cheating because I know the "rule of thumb" that has all the other factors in it like density and stuff.  Quickcrete (TM) says that an 80lb. bag of premixed concrete will do 2/3 of a cubic foot.  There are 27 cubic feet per cubic yard, so it takes about 40 80lb. bags per cubic yard (at a hardware store they just say "yard" and mean cubic yard).  One bag does one two foot deep fence post, not that anyone asked.
162842
(3-3/4" x 2-1/2 x 8)\nstandard (common) red brick = 5 pounds \n(density = 1922kg/m³ or 3,239.64 lb/cubic yard)\n\n(8 by 8 by 16) \nconcrete block = approx 26 lbs\n\n(density of SOLID concrete = \napprox 2200kg/m³ or 3,708.2 lb/cubic yard)
617283
Hope this helps, it's hard to answer without seeing the original question in context. Assuming Pser is a vertical load distributed evenly across a footing:\n\nBearing capacity = maximum force/footing area\n\n330000 Pa = 730000 N / Area\n\nArea = 730000 N / 330000 Pa\n         = 2.12m^2\n\nSo an area of 2.12 square metres would be the minimum acceptable area for a footing. In practice, the load is probably not going to be evenly distributed (the dimensions of the pillar may influence this) and in any case you would probably wish to include a significant factor of safety. Hope this helps.
425681
I get the radial acceleration = ar = V²/r = (325*1000/3600)²/194 = 42.01 m/sec²\nI agree with your value for at = 6.69 m/sec²\n\nThe total acceleration = A = √(42.01² + 6.69²) = 42.539 m/sec²\n\nThe Cf required = A/g = 42.539/9.8 = 4.34\n\nTypical tire/asphalt Cf is around 1.0\n\nAmazing what a little bit of bank angle can do for you!
522009
I think the formula is 3 sq ft per person...but try this link as well
178141
well, I don't know about the testing, but for design, you use 0.4Fy as your shear strength. If you have 36 ksi steel, then you need 14.5 ksi to create a shear failure. Don't know if that works forpunching holes; it's probably less. Good question.
200975
From the ref. (see table 22), Douglas fir at 15% humidity has a weight per foot of 0.233 lb * cross-sectional area in square inches. (Douglas fir happens to be the only wood the ref. lists with a Dense Select Structure rating.)
391776
9000000000 cu. mi.  \n\nAssuming no compaction and identical water content.
634458
Whether your tanks are safe or not depends on the area over which they are imposing a load.  Domestic floors are often constructed to take about 150 kilos per square meter, or about 400 pounds per square yard.  The water in your tanks weighs about 370 kilos, a bit over 800 pounds, so if their area is over two square yards you should be OK.  If they're standing on tables, though, you might want to put some boards under the table legs to spread the load a bit.
203444
1. D. 4000 g. because there are 1000 grams in a kilogram.\n\n2. B. 15 ft. 7 in. because you just have to add the feet and then add the inches (14 ft. 19 inches) and then change twelve of the inches into one foot. \n\n3. C. 10 hr. 20 min. because it is 8 hr. 20 min. from 3:40 AM to noon, and it's 2 more hours to 2:00 PM. \n\n4. A. 8,800 yd. because there are 1,760 yards in one mile, and then you just multiply by 5. \n\nI hope this helps. Don't just copy the answers, but make sure you UNDERSTAND the material. :)
552009
You can't answer this without knowing the tape thickness.  Of course, you can solve it generally for any set of variables.  Call the initial radius (10") D, the hub radius (3") H, the tape thickness b, the rotation rate w (in rpm) and the instantaneous radius r.\n\nThe radius decrease by b after each revolution (call the revolutions x).  The rate of change of the radius with time t is:\n\ndr/dx = -b\n\nThe definition of rotation is: dx/dt = w\n\nBy the chain rule: dr/dt = dr/dx * dx/dt = -bw\n\nAs expected, the radius decreases at a constant rate.  The radius after 1 hour is:   D - bw * (1 hour)\n\nThe amount of tape unwound is just the difference in the area of the roll divided by the tape thickness:\n\nL = pi*(D^2 - (D - bw * (1 hour))^2)/b
323445
yup your answers are correct.\n\nhowever your units are not, length and width are measured in yards not sq yards.
620475
Use a calculator and raise it to the 1/3 power.\nDon't try to do it by hand...
288249
Thats simple. The formula is: Y2-Y1/X2-X1\n\nIt would be: 7-3/6-2 which is 4/4 which is 1. The slops is 1.