I kinda get it, but the best i can get is y=x+2\nand i understand simple equations like that
122868
A graphing calculator has very few pixels, so all the graphing calculator has to do is plug in a finite amount of values into the equation and illuminate a finite amount of pixels. The fast custom processor and memory banks make this seem almost instantaneous.\nSimple home computer software graphs curves by evaluating the equation at some finite amount of points, and connecting those points with lines (or simple polygons for surfaces). Professional software such as Mathematica uses more advanced algorithms to render curves and surfaces.
440299
Using the third equation, you can see that z = x + y + 1.\n\nSubstituting into the first two equations:\n\n4x + 2y - (x + y + 1) = 4\n2x - 3y + 2(x + y + 1) = 4\n\nSimplifying:\n\n3x + y = 5\n4x - y = 2\n\nAdding the two equations:\n\n7x = 7\nx = 1\n\nSubstituting x into the first of the two equations that I have containing only x's and y's:\n\n3(1) + y = 5\ny = 2\n\nSubstituting x and y into the original equation that I derived:\n\nz = (1) + (2) + 1\nz = 4\n\n(x, y, z) = (1, 2, 4)\n\nYou can verify that this is a solution by substituting values into the original 3 x 3 system.
622534
X+Y=5\n\nHence Y=(5-X)\n\nHence Y/4 = 5/4 - X/4\n\nHence your first equation is\n\n(X^2)/6-(5/4-X/4)=1\n\nX^2+3X/2-27/2=0\n\n2x^2+3x-27=0\n\nx= (-3 +/- 15)/4\n\nx= 3 or x= -9/2\ny= 2 or y= 19/2\n\nSo either x=3, y=2 or x= -9/2, y= 19/2.\n\nP.S. I assumed that x^2/6 means (x^2)/6 and not x^(2/6) which would be much more difficult.\n\nGood luck.
632441
from equ 1\nx=2(3+y)=6+2y\n\nputting in equ2\n6+2y+2=0\n2y=-8\ny=-4\n\nputting y in modifiyed equ1\nx=6+2y\nx=6-8\nx=-2
368613
just plug the numbers in.  if y=8, and x=2, \nits 8=a(2^2)\nso 8=a(4)\nso a=2.\nhope that helps!
345366
Rearranging equation 2:  x = y + z + 1\n\nSubstitute this in for x in each of the other two equations:\n\ny + z + 1 + y + z = 1   simplifies to  y + z = 0\n\n2y + 2z + 2 + 2y - z = -4  simplifies to 4y + z = -6\n\nSubtracting these simplified equations gives 3y = -6\n\ntherefore y = -2\n\nNow substitute this into y + z = 0, giving z = 2\n\nNow substitute these values of y and z into x = y + z + 1, to get x = 1\n\nSo the solution is:\n\nx = 1\ny = -2\nz = 2
527951
y= (x^2 - 1)^2\nx^2-1=+/-√y\nx^2=1+/-√y\nx=+/-√(1+/-√y)
343885
4x +y = 16   ;2x + 3y = 24      Multiply the 2nd with -2, that gives -4x -6y = -48    Add the two:   0x - 5y = -32  \nDivision by -5 gives  y = 6,4\nInsert this value into the first equation:   4x + 6,4 = 16\n4x = 9,6 ;    x = 2,4\n\nNumber 2 is even easier:\nMultiply the first equation by 2 and add the equations.\n24x + 2y = 50    plus   8x - 2y = 14  gives  32x = 64; x = 2\nYou can now choose:  24 + y = 25  or  16 - 2y = 14\n(That you get when you replace in the original equations \nx by 2)  Anyhow you'll find   y = 1
187835
y-y^1=m(x-x^2)\ny-8=2(x-(-2)\ny-8=2(x+2)\n A is the correct answer.\ny-8=2x+4\ny=2x+4+8\ny=2x+12 >> y form\n(transpose)\n-2x+y=12\n(if the variable x is negative make it positive)\n-(-2x+y=12) \n2x-y=-12 >> standard form
164508
I did this pretty fast so you may want to check my basic arithmetic\ny^2+2y+12x+25=0\n(y^2+2y+1)+24+12x=0\n(y+1)^2+24=-12x\n(y+1)^2=-12x-24\n(y+1)^2=-12(x+2)\n-1/12*(y+1)^2=x+2\n-1/12*(y- -1)^2=x- -2, k=-1and h=-2\ni hope this helps
333130
if x + y = 12 and y = 2x, then in the original equation, you can substitute 2x for y.\n\nx + 2x = 12\n\ncombine like terms\n\n3x = 12\n\ndivide both sides by 3\n\nx = 4\n\nbecause y = 2x, substitute x for 4.\n\ny = 2(4)\n\ny = 8
70870
y^2 + 3y + 6 -4y^2 - 6y simplifies to:\n\n-3y^2 - 3y + 6\n\nIt's a second-degree trinomial expression.
332621
It's easy.\nYou have 2 linear equation:\n3x - y = -7  -> equation  1\nx + y = -9   -> equation  2\n\nNote that in equation 2 you can rewrite as follow:\n  x = -9 - y \nBy simply moving the y to the other side.\nSo you know what x is in terms of y.\n\nIn equation 1 you have:\n      3x - y = -7  \nBut you know x now in terms of y and you can SUBSTITUTE to equation 1.\n\n    3(-9 - y) - y = -7\nSolving and expanding the multiplication you have\n    3*(-9) -3*y - y = -7\n    -27 - 4*y = -7\n         -4y  = -7 + 27\n           y  = -5\nSo you know y.\n\nIf you want to know x, you SUBSITUTE back to equation 2, since there you know x in terms of y.\nSo:\n    x = -9 - y \n    x = -9 - (-5)\n    x = -4\n\nChecking the answers by SUBSTITUTING back: \n    x = -4\n    y  = -5\n\n3x - y = -7  -> equation  1\n3(-4) - (-5) = -7  \n-12  + 5 = -7   (correct)\n\nx + y = -9   -> equation  2\n-4 + (-5) = -9 (correct)\n\nHope you understand the process :)
348618
x = (y^2 + 2y -1) / 2\ndx=ydy+dy\n1=(y + 1 )dy/dx\ndy/dx=1/(y+1)\nd2y/dx2 = -1 / (y+1)^2
660532
xy + x + y = x^2y^2\n\nxy' + y + 1 + y' = (x^2)(2yy') + (y^2)(2x)\n\nGrouping y' terms on the left,\n\n(x + 1 - 2x^2y)y' = 2xy^2 - y -1\n\ny' = (2xy^2 - y - 1) / (x + 1 - 2x^2y)\n\nHope that's clear. :-)
25852
from the first, bringing y to the other side of the equation, you get x= j-y (you must change the sign of y)\nThe second relation tells that you can write k instead of j-y, and hence you get x=k
517059
Okay, same principle as last time.\n\nSolve for y in the easier equation (x-2y=1)\nx-2y=1\nx=1+2y\n\nNow we have a value that we can plug into the other equation.\nx^2+y^2=10\n\nPlug in x\n(1+2y)^2+y^2=10\n\nExpand\n1+4y+4y^2+y^2=10\n\nCombine like terms (in this case y^2)\n5y^2+4y+1=10\n\nNow bring the 10 over by subtracting 10 on both sides\n5y^2+4y-9=0\n\nFactor this equation\n(5y+9)(y-1)=0\n\nSince one of these factors must be zero for the whole thing to equal 0, \ny=1 and -9/5\n\n\nPlug each one into the other equation:\nx-2y=1\nx-2(1)=1\n\nSimplify and solve\nx-2=1\nx=3\n\nBUT, we have the other solution so you need to plug that one in as well.\n\nx-2y=1\nx-2(-9/5)=1\nx+18/5=1\n\nSubtract 18/5 from both sides\nx=1-18/5\nx=5/5-18/5\nx=-13/5=-2.6\n\n\nx=3 and -2.6 or -13/5\ny=1 or -9/5\n\nThose are your two answers.\n\nHope this helps. \n\nNote:  the y=1 is paired with the x=3 (3,1) and the y=-9/5 is paired with the x=-13/5 (-9/5, -13/5)