3x +1      3x + 5\n______   - ______\nx2-16      x2 + 8x+16?? \n\nI can't help my daughter with this math problem. Can any of you guys??
126028
You have to find a common denominator\nFirst, factor each denominator\nx^2 - 16 = (x+4)(x-4)\nx^2 + 8x + 16 = (x+4)(x+4) = (x+4)^2\nThe common denominator would be (x-4)(x+4)^2\nThe first term:\n(3x+1)/{(x+4)(x-4)} is missing an (x+4) so multiply the top and bottom by x+4\n{3x+1)(x+4)/{(x-4)(x+4)^2}\n= (3x^2 + 13x +4)/{(x-4)(x+4)^2}\nThe second term\n(3x+5)/(x+4)^2 is missing an x-4 so multiply the top and bottom by x-4\n(3x+5)(x-4)/{(x-4)(x+4)^2}\n= (3x^2 - 7x - 20)/{(x-4)(x+4)^2}\nNow that there is a common denominator, you can just subtract the numerators\n{3x^2 + 13x +4 - (3x^2 - 7x - 20)}/{(x-4)(x+4)^2}\n= (3x^2 + 13x + 4 - 3x^2 + 7x + 20)/{(x-4)(x+4)^2}\nAnswer: (20x + 24)/{(x-4)(x+4)^2}\nYou can factor a 4 from the numerator but nothing will cancel with it, so this is an acceptable final answer.
406597
4x+3y=19\n-\n (2*(2x-5y))=6\n____________\n3y+10y=19-6\n_____________\n13y=13\n_____________\n      so, y=1.\nnow,\n      2x-5*1=3\ni.e; 2x=8\nor,  x=4\n\nhence, x-4;y=1.................deserve 10 pts..isn't it??
584694
i think you made an arithmetic error in the first step.\n\nstart with: |5x - 3| + 8 = 22\nthen subtract 8 from both sides, and you will get\n|5x-3| +8 - 8 = 22 - 8\n|5x-3|  = 14\nand not |5x - 3| = 24\n\nfrom there:\n|5x-3|  = 14\n5x-3 = 14 or 5x-3= -14\n5x-3+3=14+3  or 5x-3+3= -14+3\n5x = 17 or 5x = -11\nx = 17/5 or -11/5
479185
(3x+5)(2x-3) = 6x^2 +x -15\n\n(x-1)(6x+5) = 6x^2-x-5\n\ntherefore you have \n\n6x^2+x-15 = 6x^2 -x -5\n\nsubtract 6x^2-x from both sides and you get\n\n2x-15 = -5\n\nadd 15 to both sides and you get\n\n2x = 10\ndivide both sides by 2\n\nx = 5
395658
Simple substitution.\n\n5(3) - 2(2) + 4(4)\n15 - 4 + 16\n27
646574
(2x-9)(2x+9)\n\na guess... its been a long time since I did that stuff
188908
(3x^3-7x^2+x-20)/(x-3) = 3x^2+2x+7 with a remainder of 1\n         \n         3x^2+2x+7 \n     _______________\nx-3 | 3x^3-7x^2+ x-20\n      -3x^3+9x^2\n    __________\n          2x^2+ x\n         -2x^2+6x\n         ________\n              7x - 20\n             -7x + 21\n             ________\n                   1\n\nI tried to show what this would look like as a division problem but it keeps jumbling up.
500016
Should not u work that urself?\n\n\nAnyway,\n\nIf 3x+y=3,\n\nmultiply both the sides by 2.\nAs both sdies are being multiplied, the equality is maintained\n\n2* (3x+y) = 2*(3)\n\n=> 2*(3x) + 2*(y) = 6\n\n=> 6x + 2y = 6                                               ----(eqn 1)\n\nNow as it can be seen that the left hand side is 6x+2y+10, therefore we will add 10 to our (eqn 1). To maintain the equality, this addition will have to be done to both the sides.\n\nTherefore,\n6x + 2y +10 = 6 + 10\n\n=> 6x + 2y + 10 = 16\n\ndone!!\n\nThere is another way to look at the problem, and this seems a bit mopre logical, if ur comfortable with equations i.e.\n\nNow look carefully at what is asked.\n\n6x + 2y +10 = ?\n\nfactorize it by taking out 2 common\n\n2*(3x + y) +10 = ?\n\nwe already know the value of (3x+y), which is 3\nso, we substitute it in 2*(3x + y) +10 = ? to get,\n\n2*( 3 ) +10 = ?\ncalculating, 2*3+10=6+10=16
347480
2x+1\n------- =\nx\n\n(2x+1)(x - 2)(4x + 3)\n-------------------------- =\nx(x - 2)(4x + 3)\n\n8x³ - 6x² - 17x - 6\n-------------------------- =\n4x³ - 5x² - 6x\n\n8x³ - 10x² - 12x + 4x² - 5x - 6\n------------------- ----------------- =\n4x³ - 5x² - 6x\n\n...... 4x² - 5x - 6\n2 + ----------------\n..... 4x³ - 5x² - 6x
477252
I see what you did -- you added 3x + x to get 4x, but you knew your answer had to have a square, so you made it 4x².  Then you added 8+5 to get 13, for a final answer of 4x̍ + 13.\n\nThat's not how to do these.  You need to multiply here, not add.\n\nUse a method called FOIL - which stands for First, Outside, Inside, Last.  I will demonstrate it for you with your problem:\n\n(3x+8)(x+5)\n\nF - multiply the FIRST terms of each parentheses:\n\n3x * x = 3x²\n\nO - multiply the OUTSIDE terms of each parentheses:\n\n3x * 5 = 15x\n\nI - multiply the INSIDE terms of each parentheses:\n\n8 * x = 8x\n\nL - multiply the LAST terms of each parentheses:\n\n8 * 5 = 40\n\nNow that you've done the FOIL multiplication, you can add up your terms, as follows:\n\n3x² + 15x + 8x + 40\n\nFinally, combine your like terms (the 15x and 8x) to get your final answer:\n\n3x² + 23x + 40\n\nHope that helped!\n\n~ ♥ ~
373536
Factor out first........\n\n3x(3x-5y)\n\n__________\n\n(3x-5y)(3x+5y)\n\n\nCancel:  the 3x-5y goes away both top and bottom.  That should give you a hint as to what to do next.
429587
just solve it. i think it comes out to -1x=1x\n|x-2| = |x+2| -2\n\n-1x= 3x -2\n-1x= -1x\nsorry if im wrong havent done alegebra in a while :)
526784
-8x+12=-8x+5\n\n16x=-7\n\nx=-7/16
216609
Remember Order of Operations - in this case, Parenthesis, then Add/Subtract.\n\n1.) First, we do the parenthesis:\n3x-5(3x-7)=2(x+9)+45\n3x-(15x-35)=(2x+18)+45\n\n2.) Next, we add/subtract from the parenthesis:\n3x-(15x-35)=(2x+18)+45\n-12x + 35 = 2x + 63\n\n3.) Then, we solve by subtraction and division:\n-12x + 35 = 2x + 63\n-12x - 2x = 63 - 35\n-14x = 28\nx = -2\n\nCheck:\n3(-2) - 5(3(-2)-7) = 2(-2+9)+45\n-6 - 5(-6-7) = 2(7) + 45\n-6 + 65 = 14 + 45\n59 = 59
435671
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
575283
(x - 2)*3 = 6 + x\n\n3x - 6 = 6 + x\n\n2x = 12\n\nx = 6
619928
4 - 8 ( 2 (x-3) - (-2x) ) = 5 ( 9 - 2 (3x+1) ) + 7x\n4 + ( -16 (x-3) + 2x ) = ( 45 - 10 (3x+1) ) + 7x\n4 - 16x + 48 - 16x = 45 - 30x - 10 + 7x\n52 - 32x = 35 - 23x\n17 = 9x\nx = 17/9