If you were in a submarine at 300 meters, how would the temperature, light, pressure, salinity, and oxygen compare to that at ten meters?
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The pressure would be higher, the temperature would be lower, the light would be less.
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The density is different - sea water being more dense than fresh.\n\nFreezing point (lower for sea water) and boiling point (higher for sea water) would be slightly different.\n\nElectrical conductivity would be different (higher for sea water).\n\nAll these things are different - but the differences are also all due to the salinity difference that you mentioned.
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The question is:  What should I set on the sub-scale of my altimeter so that the instrument would indicate my elevation if I were on the ground at your station?\n\nANSWER:  QNH
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The penetration depth depends to a great degree on if and for how long the projectile remains intact.\n\nSuffice it to say, high velocity (~3000fps) rifle bullets, even with full copper jackets, disentegrate very quickly upon impact with water.  I've seen this effect in person.\n\nI doubt you could achieve any significant penetration at 1 meter, much less 10.\n\nI suspect that variations in dynamic pressures caused by fluid flow and cavitation across the bullet's surface literally rip the projectile apart.  It's quite probable that a high-velocity rifle bullet could penetrate farther through many solid materials than through water.
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depends on the transit time to thermal transfer rate ratio.\n1) Adiabatic if the transit time is much less than the thermal equalization time. \n2) PV = nRT if the transit time is much greater than the thermal equalization time. \n\nSo for the sake of simplicity, for option 2\nV = nRT/P\nV1/V2 = T1P2/T2P1\n\nT1/T2 = (273 + 7)/(273 + 20) = 0.9556\nP2/P1 = 33/49 =0.6735 [33 ft depth is +1 atmospheres]\n\nV1/V2 = 0.9556 * 0.6735 = 0.6436\n\nV2 = V1/0.6436 = 3.12 cm3\n\nAs the transit time becomes less than the thermal equilibrium time, the air bubble is cooler so the volume is less than the calculated value.
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As the guy above me said, your temperature range would be in the range of -33.7 degrees Celsius and -75 degrees Celsius for liquid ammonia seas. However, the ammonia would most likely not be pure, and could contain trace compounds. Odds are that there won't be an ozone layer, as such a world probably wouldn't have much oxygen in its atmosphere, though methane may be common in a gaseous form. It is also likely that the planet may have 'dirty' ice caps at the poles, depending upon the axial tilt, composed of a mixture of ammonia, water, and carbon dioxide ice. Life as we know it on this hypothetical world is debateable, but certainly not impossible. \nMost of these details depend on specific parameters for your planet: what is its atmospheric composition? atmospheric pressure? is it Earth's distance from the sun? what kind of sun? any moons? how old of a planet is it? continental drift? please e-mail me and I will try to help you in any way I can:  paleoboy1291@yahoo.com
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At sea level, the pressure the air exerts downward is at 1 atmosphere (normally).  If you decend 32 feet below water, the water pressure acting on you is 1 atmosphere as well, even greater as you go deeper.\n\nWhen you try to suck air down underwater, the water is trying to push it back up.  At some point, you just wont have enough "sucking power" to over come the weight of the water.
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1745 meters below water\n\njust guessing i know im wrong the person would die
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How can I answer that?  If I didn't know then how could I tell you what I didn't know?\n\nHowever, the ten thing that I do know that I think are interesting are:\n\nThe speed of light is constant no matter the respective velocities of the source and the observer.\n\nThe rate of time passage is not constant.\n\nHot water will freeze faster than cool water.\n\ne=mc^2\n\nWhen you stand still, you are moving in 8 different directions.\n\nL’ = L sqrt(1-v^2/c^2)\n\nM’ = M/sqrt(1-v^2/c^2)\n\nAbsolute Zero (not my physics grade, but close)\n\nClarke's Orbit\n\nAvagadro'w number\n\nPlanket's Constant\n\nThe Big Bang\n\nBlack Holes\n\nString Theory\n\nGravity Bends Light (not really, but the effect is the same)\n\nNeutrinos\n\nGirls (Ok, that's biology not physics, but I am listing more than 10 anyway)\n\nThe expanding universe\n\nrefraction of light\n\nSpectrograms\n\nAnd, I could go on and on.  When you look deep enough to understand things, it is all interesting.
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The deepest ocean depth to be sounded is in the Challenger Deep of the Mariana Trench at a depth of 10,911 m (35,798 ft) below sea level.\n\nThat's about 6 and three quarter miles deep
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skin and organs which are adapted to face damn high pressure\nsome bacteria to produce artificial light\nuses fluorescent tentacles to lure prey.\n\nThe deep sea is also an extremely hostile environment, with pressures between 20 and 1,000 atmospheres (between 2 and 100 megapascals), temperatures between 3 and 10 degrees Celsius, and a lack of carbon dioxide.\n\nIt has also been found that the deeper a fish lives, the more jelly-like its flesh and the more minimal its bone structure. This makes them slower and less agile than surface fish.
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the answer is a, mercury is much heavier than water and would require a heavier pressure tto reach the same altitude...i think..lol
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1) 31.750 degrees\n2) 30.964 degrees\n3) 23.629 degrees\n4) 7.765 feet
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32 degrees farenheit\n0 degrees celcuis\n\nFor pure water, that is....\nThe reason they salt roads is to introduce impurities that will interfere with the H2O (106 degree bond angle?) from fitting together in the proper configuration to form crystals
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Latitude, Ocean currents, Winds, Elevation, Relief and Nearness to water.
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Self-Contained Underwater Breathing Apparatus
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Yes, it's harder because of the water pressure from the outside water increases as depth increases.\n\nEvery 33 feet of water is another atmosphere of pressure.