Planck's constant is given as 6.626^minus 34 J s\n\nIs the 's' after 'J' for seconds as in 'Joules per second?'
137963
yup...energy (Joules) multiplied by time (seconds)
428526
a) v^2-u^2=2as\n    v^2-52.4^2=2*(-9.8)*28.5\nv^2= 2745.8-558.6\n     =2187.2\nv=46.76m/s\n\nKinetic Energy=1/2mv^2\n                     =1/2*46.9*46.76^2\n                      =51,290 Joules\n\nb)height=28.5-5.06=23.44m\n\nv^2-u^2=2as\n\nv^2-52.4^2=2*(-9.8)*23.44\nv^2=2745.8-459.42\n     =2286.4\nv=47.8m/s
29841
5*60/40 = J, 7.5\n\nThanks for stimulating my brain for a couple of seconds.
350541
λ = h/m*v\n\nwhere h the Planck's constant, m the mass of the proton and v its velocity
366706
period =t=1/f=1/256=.00391 seconds\n\nv=lf                            l=lambda=wavelength\n\nl=v/f=340/256=1.328meters
371576
T = 1.90 + .12(w)\nT = 1.90 + .12(37)\nT = 6.34
533530
t=2.512 seconds\n\n10.3=0.5(0+8.2)t\nTherefore \n\n1 = 4.1t/10.3\n\n1/t = 4.1/10.3\n\nt = 10.3/4.1 = 2.512 seconds
433143
If the period is 2.60 seconds, the frequency is 2Pi/2.60 = 2.42 radians/sec. The natural frequency is sqrt(k/m) (see the reference).\n\n2.42 = sqrt(k/m) = sqrt(k/7)\n\n5.84 = k/7\n\nSo the spring constant k = 40.88
443913
WL = h/(mv)\n\nh is the planck constant\nm is the mass of the elecron\nLook for them in you book.  Plug the numbers.
341519
E = mc^2 = 1kg * (3*10^8)^2 = 9^10^16 Joules
54045
Bolztmann constant(k) = 1.380 6505(24) × 10−23 joules/kelvin\nRead more about it on the following link.\nhttp://en.wikipedia.org/wiki/Boltzmann_constant
350946
GPE is the gravitional potential energy.\nM is the mass.\nG is the gravitational constant.\nH is the height.\nJ stands for joules.\n\nGPE=(500 + 85 kg)(9.8 s^2)(1000)\nGPE=5733000 J
508880
The wavelength of an electron is given by the de Broglie equation\n\nlambda = h / m / v\n\nHere h is Planck's constant, m is the mass and v is the speed of the electron. Use the above equation only is the velocity is much below the speed of light (3*10^9 m/s), now this is the case.\nPlanck's constant = 6.626068 × 10-34 m2 kg / s\n\n5.59492358 x 10^-12 m = 5.5 picometers\n\nhope I did the division correctly :)
487550
Energy=Mass * (speed of light)^2
376738
I can't get greek symbols so you will have to substitute\n\ntheta = 1/2( omega initial + omega final)t\n\ntheta = 1/2( 15,000 rev/min)3.7 min\ntheta = 28,000 rev
523632
The frequency of light and its wavelength have an inverse relationship.  As the frequency of light increases, the wavelength decreases.\nThe frequency is the number of 'cycles' per unit time, and the wavelength is how far the wave propagates in that same time.  At a constant speed, the shorter the higher the frequency (very short time durations between cycles), the smaller the wavelength.\n\nThe energy contained within a single photon of light is given by Planck's equation,\nE = hv\nwhere E is the energy, h is Planck's constant, and v is the frequency of light.\nThe equation can be re-written as,\nE = h * c / lambda\nWhere c is the speed of light in a vacuum, and lambda is the wavelength of light.\n\nYou can see that as the frequency of the light increases (or when the wavelength decreases), the energy contained within a photon of light increases.  The higher the frequency of light, the more energy the light carries.  For example, high frequency X-rays carry much more energy than low frequency radio waves.\n\nh = 6.626 E-34 J s
213298
E is normally expressed as joules (kilogram-meters per second^2)\n\nSo the mass is in Kg, and the speed of light is in Meters/Sec