I have a graph that starts out at (7.5, 235), goes to (15, 460), goes to (22.5, 235), goes to (30, 10), goes to (37.5, 235).  I know that the horizontal stretch is something to do with how wide the period is, but are they the same????  I missed this week of school.
131199
Take the difference between the x values.\nThe period is the horizontal stretch, which is also called the wavelength.  They're all one and the same, from one crest of a wave (or any other part) to the next.\nI'm talking about sine and cosine waves here.
262630
First of all, if you round off, you loose the last significant digit. 1.5 rounds up to 2, not 2.0. \nWhen you write that a measurement is 2.0, you are saying that it lies between 1.95 and 2.05 and it was rounded to 2 significant places.\n\nHere is the convention for rounding:\nWhen round to a whole number, \nn.0 is already rounded.\nn.1, n.2, n.3, n.4 round down to n\nn.6, n.7, n.8, n.9 round up (n+1)\n\nTo avoid an upwards or downwards bias in your rounding, n.5 rounds up half the time, and down half the time, depending on whether n is even or odd. Always round so that n.5 in the direction that gives you an even number.\n\nSo 1.5 rounds to 2 and 2.5 rounds to 2.\n\nSimilarly -.5 rounds to 0, -1.5 and -2.5 round to -2.\n\nThe same rule applys whenever you round down to any number of significant digits.
540837
I can see why no-one has posted an answer yet!\nI expect left-hand sum means you multiply 3.5, 8.2, 9.0 and 7.5 in turn by the interval length, which is 0.5, and add together.  The right-hand sum means you do it with 8.2, 9.0, 7.5, and 5.3\n\nplot these figures on a graph, with t on the horizontal axis and g/hr on the vertical axis and try to work out a commonsense answer to the second part.  I don't know off the cuff.
519563
Isnt there a 2 sides to a ruler and one has centimetres and one has millimetres.......Maybe that is just in Australia......lol....\n\nThere are 2.5cms to an inch and there are 250mm to an inch.
441843
The period T is 0.9s\nT = 1/f = 2pi/w so w = 2pi/T\n\nAs the movement is circular, the total of the forces is in this plan and to the centre and the value is mw²R.\n\nSo P + S = mw²R where P is the weight and S the tension of the string and R the radius and a the angle between the string and the vertical\nIn projection, we have :\nmw²R = S sin a\nmg = S cos a\n\nDividing the 2 equations :\ntg a = w²R/g\nand R = L sin a\n\nso w² = g/(Lcos a)\nso cos a = g/Lw² = g T²/(L 4 pi²) \n\nso cos a= 9.8 0.9²/ (0.3 4 3.14²) = 0.6702\n so a = 47.91°  or a =0.83 rad\n\nBut this angle is the angle between the string and the vertical so angle between the string and the horizontal is 90-a = 42.09°
285300
When graphed, a linear equation will form a straight line while a non linear equation will not be a straight line
352040
I think it's supposed to be symmetrical.  I think the point of the question is to see if you can list the points on the graph as symmetrical pairs.  The 'if' is there so it doesn't give away that it's supposed to be symmetrical for anyone who graphed it wrong
650821
draw a picture of the graph over the specified interval.  divide the graph into vertical rectangles.  the area under the curve will be the sum of the areas of the rectangles.  saying that youve made "n" rectangles, the only way to get the exact area is to find the sum for the limit as n approaches infinity.  work from that concept.  if you already knew that, or need more help or something, email me and i can give you more steps and a much more detailed description.  that would take a really long time though so im gonna see if this helps first.
209822
I am not sure that I follow what you are asking. Are you looking for the above items to be charted as variables on your graph?\n\nPerhaps if you post additional details in your question, it would help us.
391134
There's a pretty good online grapher at http://id.mind.net/~zona/ezGraph/ezGraph.html that you can use.  It works basically like a graphing calculator.\n\nIt appears this function should be an upside-down sign curve with an amplitude of 10 and a vertical shift of 9, which means the center of the graph will be at 9, it will go up to 19 and down to -1.  It's not 100% clear what you mean by what you have written after sin.  If you mean the sine of 2pi/15 times x (since the minus zero is irrelevent), you would have a period of 15, so you'd complete 1 complete cycle at 15 radians; the halfway point would be 7.5 radians.
324253
If the graph of Volume vs Pressure is a diagonal line with a positive slope, you should be able to conclude that the graph of Pressure vs Volume is also a diagonal line with a positive slope!\n\nSince we know that the gas has expanded, the work done by the gas is positive. Hence, W= corresponding area under Pressure vs Volume graph. If you make a sketch of the graph and indicate the intial and final pressures and volumes of the gas, finding W should not be too much of a problem!
313712
You need to start your values at "0", i.e. for your source data, you need to add 0 as the first entry for both Minutes and Grams (I know nothing about Chemistry but I'm trying to make sense..). That way, when you use the Chart Wizard, the starting point will be 0,0 on your chart. \n\nI think this answers your question, however if my answer sounds as vague to you as it does to me, I've uploaded an image for you to have a look at. Go to: http://i4.tinypic.com/10e0w00.png\n\nGood luck and I hope that helps.
504138
out of the statements given 1,4,5,7,9,11 are always right \ni dont know how i can show u the graph but it is a discontinuois graph at x=0 \n\nif u hv any problems feel free to ask
551385
Gopal has the correct answer! \n\nSo... becareful with some other results... and... never use:\n0.833 instead of 5/6... it's a mistake!\n\nFinished Algebra with 19!
656497
Let width = W     and     length = L\nL = 7 + W\n\nPerimeter is two widths plus two lengths, so\n2W + 2(7 + W) = 22\n2W + 14 + 2W = 22\n(subtract 14 from both sides)\n4W = 8\n(divide both sides by 4)\nW = 2\n\nSince L = 7 + W, then\nL = 7 + 2\nL = 9\n\nI can't help with the graphing, as that doesn't make sense to me in this problem.
122247
You should be more specific with your question. A lot of people don't know what a v-t graph is (velocity-time).\n\nAnyway, it's a horizontal line. Velocity remains constant while time keeps moving forward.
431645
Your question is not very clear to me,but what i think you want is to know inequality graphing.\nwell , X>3, means X is greater than 3.So counting numbers greater than 3. Your straight line must be started on top of 3 heading right because numbers right are greater than 3.\nSomething like: (x:x>3>infinity) is the same are the above.Infinity does not end and has no specific value.