Solve the inequality 8x - 9 < 3x - 11.
127336
Ok step by step...\n\n1) You start with 8x - 9 < 3x - 11.\nYou need to get the x's on one side... and the other numbers onto the other.\n\n2) So you'll take the 9 over to the other side... you'll add 9 to both sides (it's the opposite of -9... in essence 8x - 9 = 8x + -9).\n\n8x - 9 + 9 < 3x - 11 + 9\n8x < 3x - 2\n\n3) Now you'll need to get the x's onto the same side. So subtract 3x from both sides).  Make sure that whatever you do to one side you do to the other - this will keep it balanced and in check!\n\n8x < 3x - 2\n8x - 3x < 3x - 3x - 2\n5x < -2\n\n4) Now take it a step further and you'll need to get x by itself.  To do this, you'll need to divide by 5 (again, remembering to divide both sides by 5).\n\n5x < -2\n5x/5 < -2/5\nx < -2/5\n\n5) You can simplify the fraction further since it will be an even decimal point.\nx < -2/5\n-2/5 = -.4\nx < -.4\n\nIf your teacher wants you to keep it in fractions, then don't fret about dividing.  However, if s/he does, then divide and round to the respective amount of digits they would like (generally to the hundredths).\n\nThat's how you would solve this equation.  I hope this helps!
618607
3x + 4(3x+11)=-16 substitute 2 in 1\n3x + 12x +44 = -16\n15x= -16-44\nx=  -60/5\nx= -4\n\nx= -4 substitute in 2\ny= 3(-4)+11\ny= -12+11\ny= -1
440356
1) 1/-4<m/-4\nmultiply both sides by negative 4 and flip the inequality sign\n4>m.\n\n2) -1/8< or equal to n/-32\nmultiply both sides by negative 32 and flip the inequality sign\n4 greater than or equal to n\n\n3) x/-12>1/4\nmultiply both sides by negative 12 and flip the inequality sign\nx<-3\n\n4) -1/2x< or equal to 2\nmultiply both sides by negative 2 and flip the inequality sign\nx> or equal to -4
417750
8k^8/9y^3\n\n1)  Reduce 64/72 => Divide both sides by 8 => 8/9\n2)  Reduce y^2/y^5 => (2-5 = -3) => 1/y^3\n3)  Reduce k^11/k^3 => (11-3 = 8) => y^8\n\nCombine all 3 => 8k^8/9y^3
545139
5x+8-2x+26=0\n3x=-26-8\n3x=-34\n3x/3=-34/3\nx=-34/3 or -11.3\n\n\n2x+5-10x+11=0\n-8x=-11-5\n-8x=-16\n-8x/-8=-16/-8\nx=2
465947
9x^2+18x+8=0\n\n(3x + 2)(3x + 4)=0\n3x+2=0\nx=-2/3\n3x+4=0\nx=-4/3
351175
x - 6 - 3(x - 8) > 0 --- Firstly, multiply the -3 by the x - 8\nx - 6 -3x + 24 > 0 --- Combine like terms...\n-2x + 18 > 0 --- Subtract 18 from both sides...\n-2x > -18 --- Divide both sides by -2 (flip the sign)...\nx < 9\n\nCheck: Pick a number less than 9, I will use 0, and put zero in for x in the original equation.\n(0) - 6 - 3(0 - 8) > 0\n0 - 6 - 0 + 24 > 0\n18 > 0 --- It checks out.
343974
You have to graph each inequality and find the correct shaded area.  You can use substitution of elimination to find your missing point.\nI graphed the inequalities and it looks like it is the intersection of the first and second inequalities.\n-x + 4y = 16\n-10x - 9y = 13\nMultiply the first equation by -10 and add that to the second one.\n10x - 40y = -160\n-10x -9y = 13\n-49y = -147\ny = -147/-49 \ny = 3\nNow go back to the first equation, replace y with 3 and solve for x.\n-x + 4(3) = 16\n-x + 12 = 16\n-x = 4\nx = -4\nThe last point is (-4,3).
467157
xqrt(x-1) = 3\nx-1 = 9\nx = 10\n\n\nx^3 = 8\nx = 2\n\n\n\ngood luck
410726
nope\n\n2+3(x-4) < 3(2x-5)\n\n2+3x-12 < 6x-15\n\n3x-10 < 6x-15\n\n-3x < -5\n\nx < 5/3
348878
- a/b over 9/b = -(a/b) ( b/9) = -a/9 \nand\n(3) - a/b over 9/b = (3b-a)/b (b/9) = (3b-a)/9\n:D
519078
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today
231046
(x+7)(x+3)\n(x-11)(x+2)\nforget this one.  its AC factoring though\nthis ones AC too
259562
Um...\n\n2(-X) + 3(-X) + X + 8\n\n-2X - 3X + X + 8\n\n-5X + X + 8\n\n-4X + 8\n\n8 - 4X
516684
So let's say the problem looks like this\n\n   11\nx 12\n--------\n        <-----the answer from 11*2\n       <------answer from 11*1\n\nfirst hide the 1 from the 12 and work out the problem as 11*2\nthen work on multiplying the 1 with 11 but make sure you start putting your answer down below your first answer and the answer starts in the column that is below the 1 from the 12.\n\nfinally when the two answers are found, you can add them and get your final answer. SOOO here's what it looks like\n\n      11\n   x  12\n--------------\n           22    (this is from 11x2)\n +  11       (this is from 11 x1)\n------------\n     132 = final answer!
467130
let the distance cycled be x\nDan bicycled 12+1/3x<=24
591368
When you multiply (or divide) an inequality by a negative number, you have to reverse the direction of the inequality.\n\nAnother way to approach it is to write the problem as two separate inequalities, simplify then rewrite it.\n\n-4 < 2 - x < 6 \n\n-4 < 2 - x   and 2 - x < 6 \n\n-4 < 2 - x   \n0 < 6 - x    add 4 to both sides\nx < 6 subtract x from both sides\n\n2 - x < 6\n-4 -x < 0   subtract 6 from each side\n\n-4 < x     add x to each side\n\n- 4 < x < 6  restate the two inequalties