Two circular, similar coaxial loops carry equal currents in the same direction. If the loops are brought near\na. Current will increase in each loop\nb. Current will decrease in each loop\nc. Current will remain same in each loop\nd. Current will increase in one and decrease in the other
130684
The answer is B.  Its Faraday's law of magnetic induction.  As the loops are brought closer to each other, the magnetic field from one loop to another increases, increasing the flux.  The loops will want to counter this increase in flux, creating a back EMF that will oppose the original current.  This reduces the current in each loop.
539501
The resistance (ohms) is zero in a superconducting circuit.  Such a circuit will not create a current but will maintain indefinetly a current made in it. Approaching a steady magnet near a superconducting material will induce a current in it. There are projects for accumulating electricity in superconducting loops of many kilometers diameter for peak hours of electricity consommation.
521494
If you consider 2 nodes in a circuit, node A and node B, and you consider that node A has a higher potential than node B, then the current between A and B is 0.30 A, but the current between Node B and Node A is -0.30 A. See Kirchoff's laws.
395865
By me Ampere's Law states that:\n\nThe magnetic field in space around an electric current is \nproportional to the electric current which serves as its source, just as the electric field in space is proportional to the charge which serves as its source. Ampere's Law states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop.
608967
Certain materials allow electric currents to pass more freely than others.  We all know about copper, iron, silver and gold being conductors of this type.  However, even the best natural conductors offer some resistance to the passage of that current.  This resistance results in power loss due to heat.  It has been found that some materials, metals, metal alloys, and some ceramics, when cooled sufficiently, will pass those same currents without any loss due to heat.  This is very important for items like electromagnets which require huge amounts of current to create the kinds of magnetic fields that are useful, and still be efficient.  Since power is the square of the current (measured in amps) and resistance (measured in ohms), if the resistance is zero, no power is used to create the magnetic field.
390927
power=VI ,even though the voltage and current are variables,the total power for a fixed circuit with constant resistances,power is also constant .it is not variable.\nwe know ohm's law i.e V=IR,and this law is valid at constant resistance only.so,at constant resistance V is proportional to current.as constant resistance is maintained through out the operation of the circuit ,power is constant.and if both voltage and current are varied,power also varies.and this is the main reason for getting low and high voltages.\nand we are getting constant results during our power supply or in experiments bcoz we are maintaining constant resistances.\nI hope u understood the reason.thanq for innovative doubt.
444295
PROBLEM ONE\nThe electric resistance R of a wire varies directly as its length L and inversely as the square of its diameter.  So you mean R=cte*L/d2 where the constant depends on the metal used.\nfor that alloy, C=Rd2/L=36*0.6*0.6/20=0.648\nIn the second wire, you use the same constant\nR=0.648*60/(1.2*1.2)=27 ohms\n\nPROBLEM TWO\nhere, period=T=cte*sqrt(L)\ncte=T/sqrt(L)=2/sqrt 6=0.816\nL=(T/cte)2=(1/0.816)2=1.22*1.22=1.5
661211
An antenna with thick elements has a lower Q, and hence wider bandwidth, than one with thin elements.\n\nThere are also other techniques which can increase bandwdth.  I suggest you search on Google.
339622
The resistance of the filament of the lamp varies with temperature. When the filament is at room temperature the resistance is much lower than when it is white hot. \n\nCurrent = V/R. If the voltage is constant and the resistance increases, the current decreases.
302167
First there is a correction to your statement.\n\nResistance increases with the length of the wire or conductor; but it decreases with the area of cross section of the wire or conductor. \n\nIt will give a wrong meaning if you use the word breadth instead of area of cross section.\n\nConsider a wire of length L and area of cross section A connected in a circuit. Let n be number of charges flowing through it under a given condition.\n\nNow connect a similar wire side be side with the previous one. (This is called parallel connection)\n\nAs before in the first wire there will be n number of charges flowing through it.\n\nWhat about the second wire. Since the condition is the same as the first one, in the second wire also there will be n number of charges flowing through it. \n\nThus if the area of cross section is doubled current is increased or resistance is decreased.\n\nIn a high way there is a bridge which is very narrow; the flow of vehicles will be less.\nIf the bridge is broadened the flow will increase.\n\nHowever the above is an analogy to make the concept some what to understand. But the charge in a wire is different from the vehicle flow.  \n\n\n\n.
404290
YOU ARE ASKING A QUESTION THAT IS ANSWERED BY SOLVING THE EQUATION (E=IR) OR OHMS LAW. IF YOU GIVE ME TWO OF THE  UNKNOWNS THE EQUATION CAN BE SOLVED FOR A NUMERIC ANSWER.   LETS ASSUME THE VOLTAGE(E) IS 100VOLTS.  THEN THE CURRENT(IR1) WOULD BE (100VOLTS/110 OHMS) E1/R1 OR 0.909 AMPS.\nTHE SITE BELOW GIVE A LENGTHY DESCRIPTION OF THE SIMPLE CONCEPT AND JUST SEARCHING "OHMS LAW" WILL YIELD DOZENS MORE. YOU WILL FIND THAT THE VOLTAGE APPLIED TO EACH RESISTOR IS THE SAME AND THE AMPERES THROUGH EACH RESISTOR IS INVERSELY PROPORTIONAL TO THE RESISTANCE.
564435
It sounds like you are creating a basic electrical circuit. with the batteries, wires, bulbs and paper clip you can make either a series or parallel circuit. The light bulbs will light up when you have a complete single loop for series. When you measure the current it should be the same anywhere on the circuit. In a parallel circuit you are splitting the circuits into three or more branches, with one bulb on each side. When measured each branch should be using half the current. You shouldn't have any problem finding a site online that shows this experiment. use keywords, including science experiments for kids. I found the experiment in Reader's Digest,"How Science Works"
544604
If the resistors are in parallel, then the voltage is the same across all of them - that's pretty much the definition of parallel.  If they are the only circuit elements, then that voltage will be the voltage of the circuit.  Since you didn't tell us what that voltage is, there's no way for us to figure the rest of the problem.  If you know the voltage, though, then Ohm's Law will give you the currents.
202011
If a gets one coil, there are four ways.\n\na(1), b(3), c(0)\na(1), b(2), c(1)\na(1), b(1), c(2)\na(1), b(0), c(3)
348087
It doesn't VIOLATE ohms law in any sense at all. The formula V=IR is independently applicable to the 2 coils (Primary and secondary) where R is the resistance of the coil. The resistance of the 2 coils is different as in this case due to the soft iron core and winding, a electromagnetic resistance (inductance) is introduced in the circuit, taking that into account every thing falls in place.
104836
The only things that remain the same between the series and parallel circuit are the individual resistances themselves. You can derive an equation relating the two total resistances; it would just be a lot of messy math and lots of substitution. For example, if there were only two resistors:\n\n1/(Rparallel) = 1/(R1) + 1/(R2)\n1/(Rparallel) = R2/(R1*R2) + R1/(R1*R2)\n1/(Rparallel) = (R2 + R1) / (R1*R2)\nRparallel = (R1*R2) / (R2 + R1)\nRparallel = (R1*R2) / (Rseries)
197003
Standard copper coaxial CABLE TV wires use a drip-loop to compensate.\n\nThe drip loop is approximately 12 inches long, so the wire probably doesn't move more than six inches.