Perform the indicated operation:the ^ means to the power. Please explain how you did each step. 10 points for the best answer.\n\n\nb) Multiply (p+2) (p^4-2p^3+3
122439
First multiply p times the second polynomial.\np(p^4 - 2p^3 + 3) = p^5 - 2p^4 + 3p\nthen multiply 2 times the second polynomial.\n2(p^4 - 2p^3 + 3) = 2p^4 - 4p^3 + 6\nNow add these two together.\n\n(p^5 - 2p^4 + 3p) + (2p^4 - 4p^3 + 6)\n= p^5 - 4p^3 + 3p + 6
1418
1. It's one multiplied by ten to the twenty-third power.\n  -Otherwise ten to the twenty-third power.\n\n2. It is also an example of multiplicative identity.\n\nSorry if that is not what you are looking for.
415430
(x+3)(x^2+2x+4)\n\nStart by taking the first term in the first parenthesis and multiplying it by each term in the second parenthesis:\n\nx*x^2 + x*2x + x*4 = x^3 + 2x^2 + 4x\n\nNow take the second term and multiply it by each term in the second parenthesis:\n\n3*x^2 + 3*2x + 3*4 = 3x^2 + 6x +12\n\nNow add all of that together\n\nx^3 + 2x^2 + 4x + 3x^2 + 6x +12\n\nand combine terms\n\nx^3 + 5x^2 + 10x +12
66551
You can do it on Google.  Do a search on: 2^900\nThe ^ means "to the power of" and it is the shift of 6.\nIt will only give you an approximate answer because the exact answer has hundreds of digits.  It would take you many hours to "show the work" and you would probably make many mistakes because there are so many digits to copy.
344831
Here's why:\nA^x would be x A's all written out; B^x would be x B's all written out\n\nAAAAAAAABBBBBBBB  (if x is 8)\n\nBut then use commutative property to move the Bs around to get\n\nABABABABABABABAB\n\nYou can see this is (AB)^8\n\nSo the principal holds for any x
359931
Its substitution.\n\nYou are given p=i*v\n\nand you need to express it in terms of one variable using ohms law v=i*r\n\nYou want p, so you need to trade out either the i or the v from p=i*v\n\nif you trade out the v using ohms law as (i*r) then your power equation becomes p=i*(i*r) = i^2 *r\n\nif you trade out the i using ohms law, first you solve for i getting i=v/r then substitute into the p-equation.  \nThe substitution yields p=(v/r)*v  = v^2 /r\n\nThis is straightforward algebra.
447370
A:\n\nA hint for these is that a root of a number raised to the power is the number raised to (power/root)\n\ne.g. cube root of x^4 = x^(4/3)\n\nB(i):\n\nEasy - just replace x with 1, 2, 3, 4 and 5 and work out the answer\n\nB(ii):\n\nSimilar to B(i)
487528
Order of operations: Parentheses Exponent Multiplication Division Addition Subtraction.\n\n2 - 2[4-9] ÷ (-5)\n2 - 2[-5] ÷ (-5)\n2 - [-10] ÷ (-5)  ~~ same as 2 + 10 ÷ (-5)\n2 + [-2]  ~~ same as 2 -2\n= 0\n\nI'd double check that if I were you; it's a bit early for me. :*)
187382
I know it has already been answered but I"ll take a chance with something different. Ok 3 to the third power plus two would be 3 to the fifth power which is 243.\n :)
363149
Here is how you do it (I'll use ^ for the power sign).\n- Divide by P:    (1+r/n)^n = F/P\n- Take the 1/n the power:     (1+r/n) = (F/P) ^ (1/n)\n- Solve for r:   r= n* ((F/P) ^ (1/n) -1 )\n\nIn this case F=20000, P = 12600, n=12 therefore r = 0.47 or 47%\n\nSeeing this answer I wonder if I didn't misinterpret your notation, but with the method given, you can solve the question for yourself.
369020
4a^4b^-1\n\nSubtract exponents when dividing a^5/a = a^(5-1) = a^4;  b/b^2 = b^(1-2) = b^-1
32840
There are a couple of ways to work this out, I will take the easiest to explain.\n\n(x-3)(x^3+3x^2+9x+27) Can be rewritten as:\n\n(x)(x^3+3x^2+9x+27)+(-3)(x^3+3x^2+9x+27) Now, multiply those out.\n\nx^4+3x^3+9x^2+27x-3x^3-9x^2-27x-81 Now, sort by like powers of x\n\nx^4+3x^3-3x^3+9x^2-9x^2+27x-27x-81 Simplify\n\nx^4-81
425141
cross multiplying\n(x-4)(x+4)<x(x-5)\nx^2-16<x^2-5x\nadding 5x-x^2\n5x-16<0\nadding 16\n5x<16\ndividing by 5\nx<16/5\nx<3 1/5
559020
u r probably working on order of operations, this might help:\nPlease (parantheses)\nExcuse (exponents)\nMy  (multiplication)\nDear (division)\nAunt (addition)\nSally (subtraction)\n\n1. 7000 x 400000 = 2800000000\n2.  1/144 = x^2 so x = +/- 1/12\n3.  -3 +/- the square root of 2\n4.  5t^4 - 7t^3 + 6t -2\n5.  4x^4 - 16x^2 +16
142292
Perform operations in this order:\ni)   brackets\nii)  powers\niii) divide\niv)  multiply\nv)   add\nvi)  subtract\n\nSo work it out like this:\n\n2 + 2 (4 - 6 * 7) + 4\n= 2 + 2 (4 - 42) + 4\n          By doing multiplication 6 * 7 in brackets first.\n= 2 + 2 (-38) + 4\n          By doing subtraction 4 - 42 in brackets.\n= 2 + -76 + 4\n          By doing multiplication 2 * -38\n= 2 - 76 + 4\n          Since + and - sign in front of 76 combine into a -\n= -74 + 4\n          By doing subtraction 2 - 76\n= -70\n          By doing addition -74 + 4
308477
I'm guessing you meant 17x^3 - 10x^2 - 6x +4 and 2x^2- 6x +2\nIf that's right, you just add like powers of x and their coefficients to get 17x^3 - 8x^2 -12x +6.
335805
4^2=4^x+1\n2=x+1 (because the two powers must be equal\n2-1=x\nx=1