x^2 + y^2 -6y = 7\n\nthanks,
136817
x^2 + y^2 -6y = 7\n\nFirst complete the square of the y term\n\nx^2 + y^2 -6y + 9 = 7 + 9\n\nFactor\nx^2 + (y - 3)^2 = 16\n\nThis of the form (x-h)^2 + (y-k)^2 = r^2\n\nSo h = 0, k = 3, r = 4\n\nCenter is at (0,3) with radius 4.
462317
subtract 1st equation from the second:\n  8y^2=32\nso y^2=4, and y = +/- 2\n\nplug back into 1st equation:\n4x^2+4=4\n\n4x^2=0\nx=0
339128
determine the square of 6 - sqrt[(x-2)^2 + y^2]\n\n-->\n\n36 + [(x-2)^2 + y^2] - 12*sqrt[(x-2)^2 + y^2]\n= 40 + x^2 + 2x + y^2 - 12*sqrt[(x-2)^2 + y^2]
300735
6y + 3 = -4y^2\n4y^2 + 6y + 3 = 0\n\na=4, b=6, c=3\n\ny = -b+-SQRT(b2-4ac) / 2a\ny = -6+-SQRT[36-(4)(4)(3)] / [(2)(4)]\ny = -6+-SQRT[-12] / 8\n\nBut SQRT[-12] is not possible, unless we are looking for imaginary values, then:\n\ny = -6/8 +- SQRT[-12]/8\ny = -3/4 +- [2SQRT3]i/ 8\ny = -3/4 + [(SQRT3)/4]i or -3/4 - [(SQRT3)/4]i
480939
Y = 7 X\nX + Y = 72 = 8 X\n\nX = 9\nY = 63
450839
(E): y+2=-3/2(x-6) (=) y=-3/2*x + 7
70870
y^2 + 3y + 6 -4y^2 - 6y simplifies to:\n\n-3y^2 - 3y + 6\n\nIt's a second-degree trinomial expression.
563733
# 1    \n(x+1)*(x+6)=x2 +x+6x+6=x2 +7x +6\n#2\n(y-6)*(y-5)= y2-5y-6y+30= y2-11y+30\n#3\n(a-2) * (a+10)=a2 +10a-2a -20= a2  +8a -20\n#4\n(x-1) *(x+1)= x2 -x+x -1= x2 - 1
236259
x^2 + y^2 = 25\nx - y = 0\n\nx = y\n\nY^2 + Y^2 = 25\n2 Y^2 = 25\n\nY ^2 = 25/2\ny =  (25/2)^1/2 or\ny = Sqrt (12.5)
626430
Y=X^5-X^-3+X^2\nY'=5X^4+3X^-4+2X\nY''=20X^3-12X^-5+2
671467
x^2y^2 + 2x^2y - 3y + 4x^2y + 8x^2 -12\nx^2y^2 + 6x^2y + 8x^2 - 3y - 12
390699
1. x²+y²-4x+6y=12\nSo\nx² - 4x + 4 + y² + 6y + 9=12 + 4 + 9\n(x - 2)² + (y + 3)² = 25 = 5²\n\nCentre ≡(2, -3) radius = 5\n\nOption B\n\n2. M ≡(2 √2,1)\n\nx² = 8, y² = 1\n\nTherfore x² - 4y² = 4\n\nOption A\n------------------------------- ------------------------------- ------------\nDunno about fattest but I was the fastest ... hehehehehehe
67168
The answer is:\n2y^3 - y^2\nOR\n(2y-1)*y^2
439485
Sqrt(2y+7) + 4 = y\n>>\n2y + 7 = (y - 4)^2\n>>\n(y - 4)^2 -2y -7 = 0\n>>\n(y - 4)^2 -2(y - 4) -15 = 0\n\ny - 4 = (2 + sqrt(4 +60))/2 or  (2 - sqrt(4 +60))/2\n>>\ny = 9 or 1\n\nBut if you require the sqrt(2y + 7) be positive, the only acceptable solution is 9.
196843
((x^2-2x)/4y)/((x^2-4)/6)\n=(6x(x-2))/(4y*(x-2)(x+2))\n=3x/(2y(x+2))
627181
3x = 2y + 6\nx = (2y + 6) / 3
537204
SQRT(7 - x) - SQRT(6 + x) = 1\nEverything squared\n(7 - x) + (6 + x) - 2SQRT((7 - x)(6+x)) = 1\n13 -1 = 2 SQRT((7 - x)(6+x))\n6 = SQRT((7 - x)(6+x))\nSquare again.\n36 = (7 - x)(6 + x)\nx1 = 3\nx2 = -2\n\nTest that x1 and/or x2 solve the original equation.