Assuming each earphone required 1mW that is.
128137
Picture your transmitter at the center of an outward growing sphere where part of the sphere enters the ground and is lost.  You transmitted signal races away from you (at the speed of light) as though growing a bubble where the bubble (signal strength) gets thinner and weaker as the bubble grows.  Your listeners must be above ground and likely on the ground forming a circle around your transmitter.  If they are close enough to detect your signal (using crystal radios) they will hear it.  Even more people could be close enough to hear if in the air above ground but with their crystal radio sets grounded using ground wires.  The effective listening area would be like an grapefruit half facing down with you at the center.  No one would be in the grapefruit flesh (inside your house or on your lot?) but would be within the grapefruit skin that would be as thick as your signal supported, given sensitivity of their receivers.  Hope that helps a little.
382675
From 50 to over 100 µm (microns), where 1 µm = one millionth of a metre = one thousanth of a millimetre.
606891
roughly 11 meters per second, or 24 miles an hour.\n;o)
249758
it's called tinnitus.
441362
Volts times amps = watts.
98973
8 Kilowatt-Hours mean you used an average of 8 KW for 1 hour.
77287
You need a separate line for the audio.
307312
very carefully from the sound of them.
453891
Here is a somewhat accurate quick way to determine this.\n\nTake your resting hear rate x height (inches) and divide by your weight (pounds) and finally multiply by 1.75%.
221888
If one wave equals one cycle, then the answer is:\n\nA. 6 Hz
16125
To explain this, I would have to use many words, so here's a website to sum it up for you:\nhttp://electronics.howstuffworks.com/speaker.htm
479033
You would have to amplify them which would use more energy than what you derived. Less than unity gain.
217711
It would be 1 meter divided by 2pi, or 0.159 m (159 mm) approximately.
247137
after connecting your headphone socket goto START>ACCESSORIES>ENTERTAINMENT>sound recorder. \n\nYou can find your requirement here.
212712
in opinion like 1 mth
642788
Most likely NOT.  1000Watts equates to 8.33amps at 120Vac.\nEach band member's amp draws about 2 -3amps plus the mic.\n\nYou should double this, 2000 - 2500watts to properly handle the load.\nThe last thing you want is to hit a power surge only to shut down the band. You'll probably get booed off the stage.
471302
Note that it also depends on frequency.\n\nhttp://en.wikipedia.org/wiki/Loudness