a. all sifes equal?\nb. all angels equal? \nc. all sides equal but not all angels equal? \nd. all angles equal but not all sides equal? \ne. exactley 3 congruent sides? \nf. excatley 4 congruent sides? \ng. exctley 2 right angels ? \nh. exctley 3 right angels ? \ni. exctley 4 right angels ? \n\nIf you can't answer all of it or just part that would help alot. Thank you!
120690
1st of all: "angles". \n\nAnd then, let's work on the questions\n\n- first, remember that any pentagon has the sum of the internal angles equal to 3*180° \n(n-2)*180° is the general rule for an n-agone\nso:\n\ni) none: otherwise you would have a degenerating pentagon (the last angle would be 180° so the polygon would be a rectangle)\n\nh) infinite: if you only fix the angles and you can choose the sides lenght, you can get infinite similar polygons.\n\ng) infinite: you have even more choices on the other three angles\n\nf) infinite: take a square and "open" it by one vertex, to make room for another side: you have infinite chances to choose the fifth side's lenght.\n\ne) infinite: even more generical than f\n\nd) infinite: cut a regular pentagon with a line parallele to one side and intersecting two adiacent sides\n\nc)this is possible for shapes which are symmetrical with respect to some of their diagonals; for the pentagon, it is impossible: you should "stretch" one side in order to change the angles of a regular pentagon\n\nb) infinite: see answer d)\n\na) one: the regular pentagon
402985
Since the question is relative to whether it is good or not:\nYes, it is.\nWould you like us to work it out as well? I appreciate that it must come right out of a quesiton from, perhaps, your homework? Otherwise, why the last sentence? "One hint is that it is related to chapter- 'CIRCLES'" Can you attach that entire chapter for us as well?\n\nThanks!
553694
sine opposite/hypotenuse\ncosine adjacent/hypotenuse\ntangent opposite/adjacent
398270
1) x= 2\n2) correct\n3)correct\n4)correct, u got the rest right!
589358
1.Two\n2.non-collinear\n3.non-planer\n4.collinear\n5.Parallel\n\nthere can be another word for (3) but it is also correct
10635
90\n\nA pair of angles are complementary if the sum of their measures is 90 degrees.\n\nIf the two complementary angles are adjacent (i.e. have a common vertex and share a side, but do not have any interior points in common) their non-shared sides form a right angle.
237120
Question 1 used if three or more things to distinguish. Question 2 used if only 2 things to distinguish
115224
1:C\n2:A\n3:D\n4:D\n5:A\n6:D
176895
since each one gives you a *-----* i would say all of them are line segments.\n\nHowever since D. is the only one with an indefinite beginning and end and not a possible end or beginning, i would definately have to go with \n\nD.) -5 <= x <= 5\n\nThat is the only one that has a defined beginning and end and not a undefined end and/or beginning.
274349
Question 1: No.\nBecause they are irregular and so there would be gaps.\n\nQuestion 2: I can't draw it here.\nIt is often just translation or rotation of 180 degrees followed by translation.\n\nQuestion 3:\na) 4\n\nXX\nXX\n\nX\nXX\nX\n\nXXX\nX\n\nX\nXX\n_X\n\nb) Yes, they all do.
467756
1.(c) 2.(d) 3.(b) 4.(a)
277777
Quadrilateral..........D is the correct answer.....
441271
Let the triangle be ABC\n\nAB = BC\n\nso angle C = angle A (opposite angle of equal sides)\n\nAB = CA\nso angle C = angle B\n\nso all angles are same\nso equiangular
559127
1. yes.\n\n2. one\n\n3. 2 equal segments (this one's a theorem)
501654
Let the trianglas be ABC & BCD\nAD forms 2 triangles, ABD & ACD\nAB=AC since ABC is isisceles\nBC+BD since BCD is isosceles.\nangle ABC=angle ACB\nangle DBC=angls DCB so angls ABD=angle ACD so ABD is congruent to ACD by SAS\n\ncall the point where AD crosses BC E\n\nso both vertex angles are bisected.\nlook at ABC.\nAE bisects BAC & AE is a commin side for BAE & CAE.\nsince AB=AC, the triangles are congruent by SAS\ntherefore BE=CE\n& angle AEB= angle AEC which are supplements so they must be right angles.\nQED
265018
A: God is all, not just one sex.\n\nB: Lillith was created in God's image, Eve was created from Adam's rib.\n\nC: Those that created the Bible didn't want you asking questions like that.\n\nD: If this is just one universe in a higherarchy of multiverses, then: God could have got the prototype for woman from another universe with a female God.\n\nE: What part of man was created in God's inmage? The tangable, easily worn out body? Or, the eternal spirit?\n\nAnd if none of these thought do it for ya, please keep searching. The journey is as inportant as the destination.
568668
SSA\n\nWe can immediately exclude AAS and ASA because to fit those criteria, two angles have to be congruent to begin with. SAS will also ensure that two angles are congruent because the two sides are opposite to the two angles that you know nothing about, and by the law of sines assure you know their proportion. Knowing A/B, C, and A+B+C (which is always 180 degrees) gives you enough information to uniquely determine the remaining angles, thereby ensuring congruence. Thus the only option given that doesn't ensure that two angles are congruent is SSA.