if it is possible to graph then help me out!
134105
Generally, you break an inequality such as this into two parts and graph each separately.  So you'd be graphing x=-1 and x=3.\n\nThe type of line depends on the sign: if it's a <= or >=, then use solid lines to indicate anything on the line satisfies the original inequality.  If it's just < or >, then use a dashed line.  (This is similar to open and closed circles on a number line.)  Then, you pick points in the different regions that you created with the lines and determine if they satisfy the inequality.  If so, the region gets shaded.\n\nThere is no y dependency, so you basically have two vertical lines for your graph for this problem.  Checking the regions, only the area between the lines satisfies the inequality, so that's the only region that gets shaded.
290410
i think it's a parabola.. im not sure. u should try plotting it on a graph.. substitute  the x and y values and see what form comes out..
44707
Sure.  Start with this link.  And please don't cry. :-)\n\nAdded:  First of all, all an org chart is a a visual representation of the information supplied in the link I gave you.  You could create one yourself.  Secondly, I found no such organizational chart on the Internet.\n\nBe creative and make your own, for goodness sake!
451391
Sorry no one will be able to help you as we do not the data in #3.\n\nYou will need to figure this one out yourself...
526041
Yes, graph this. (0,0),(1,0),(1,1),(0,2)\nThere are two right angles and two sides of length 1, but the figure is not a parallelogram. It is only a trapezoid.
152949
Take a look at this webpage:\n\nhttp://www.walterzorn.com/grapher/grapher_e.htm\n\nType: \nx min = 0\nx max = 20\ny min = 0\ny max = 10000\n\nFunction f(x):\n1000*exp(0.1x)\n\nThen click plot graph.\n\nVoila!
656430
I dont know how a Grapher works, but your can first draw 12 edges and then fill them\nAssume one vertice to be the origin and then start drawing the edges in X Y Z co-ordinate axis.\nPlot the following points and join for a solid with sides 3,4,5.\n0,0,0\n3,0,0\n0,4,0\n0,0,5\n0,4,5\n3,4,0\n3,0,5\n3,4,5\n\nYou have 8 vertices. Join to get 12 edges. Your solid is ready.\nYou can substitute your required lengths instead of 3,4,5
650821
draw a picture of the graph over the specified interval.  divide the graph into vertical rectangles.  the area under the curve will be the sum of the areas of the rectangles.  saying that youve made "n" rectangles, the only way to get the exact area is to find the sum for the limit as n approaches infinity.  work from that concept.  if you already knew that, or need more help or something, email me and i can give you more steps and a much more detailed description.  that would take a really long time though so im gonna see if this helps first.
272156
Searching/Sorting/If there's some statistical information, A special part for designing some graphs would be great I think/History(Which saves all the actions during the week or more)/Back up part(Which allows the administrator to make some back-ups) etc...\nGood luck;)
483599
go here- http://people.hofstra.edu/staff/steven_r_costenoble/Graf/Graf.html\n\nand enter     2x^2   in the big blank field and a graph will pop up!
103646
Well, if you're using Microsoft Office, Excel provides many chart and graphic options.\nStatistical software also provide those functions, but they're really expensive.\nHere's a link for some software. Some are free, and others are shareware or have free demos that might serve you:\nhttp://dmoz.org/Science/Math/Software/Graphing/
515345
This might help --> http://www.uwm.edu/~ericskey/TANOTES/Geometry/node15.html
497179
http://www.usps.com/news/online/0907_3.htm\n\nThere is no chart but from this info, you should be able to make a chart.
58840
You just draw a graph yourself.\n\n! ain't gonna graph for you. Rather ! love calculus.
432448
graph both the graphs as though they were of equality and not inequality and after wards shade the relevant portion
366327
Start here and good luck:\nhttp://www.vertex42.com/ExcelArticles/mc/Histogram.html
548074
c=9\ns=28/15\nr=10\ny=-7/4\nfor the rest, i'd assume you're supposed to graph them need two points to graph lines so\n(-1,13)and(0,61,3)\n(0,-14)(14,0)\ndon't know what you mean by 7+1/4m...doesn't tell enough\n(0,5)(2.5,0)\n(0,5)(5/2,0)\n(1,22/6)(22/6,1)\n(0,7)(-21,0)