how many possible combinations in hexadecimal?
314488
One hexadecimal digit can represent one of 16 values (0x0 to 0xF, or 0 to 15 if you prefer), so 16^7 = 268,435,456 and that's how many different values you can achieve if you use all the bits.
231966
Answer and Explanation: There are 325 possible combinations with two letters. To determine this number of combinations, we use the fact that the alphabet has 26 letters....
393576
All Possible 6/42 Number Combinations. Total Combinations - 5,245,786. 50K-1M number combinations per file. View in any word processor or Excel.
1440137
There are about 1,000 combinations possible for a 3-digit number/code. There are 10,000 combinations possible for a 4-digit number/code. You are much better off choosing the 4-digit code lock because anyone can easily brute-force the combination in between 20 minutes and an hour.
317090
Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
943591
First, we have six possible digits to use to form our number. Assuming we can reuse any of these, the answer is simply 6^4, or 1,296 possible combinations.
275875
-- we're in a position to answer your original question. With 8 items on your menu, the number of possible combinations will be 28 = 256. And if you bought all 8 items, and tried to arrange them in different orders on your tray, the number of arrangements ('permutations') would be 8! = 40320.
1166886
I.e. there are 4 objects, so the total number of possible combinations that they can be arranged in is 4! = 4 x 3 x 2 x 1 = 24.
1116347
Dana F Anderson, Just interested in math is all. Kinda a hobby. Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
841444
All Possible 4/1-24 Number Combinations. Total Combinations: 10,626.
274188
There are two possible states in a bit, usually expressed as 0 and 1. A series of eight bits strung together makes a byte, much as 12 makes a dozen. With 8 bits, or 8 binary digits, there exist 2^8=256 possible combinations. The following table shows some of these combinations.
127783
With a four digit PIN, there are a possible 10,000 combinations. But with a six digit code, there are 1 million possible combos, making it a lot tougher for someone to crack your security code.
650553
Each character can be a digit 0 through 9, or letter a through f. 32 hexadecimals x log2(16) bits/hexadecimal = 128 bits in a UUID. In the version 4, variant 1 type of UUID, 6 bits are fixed and the remaining 122 bits are randomly generated, for a total of 2¹²² possible UUIDs. We'll refer to this value as n.
934195
With 1 item there are 6 possibilities with 2 you only have 5 choices after the first if you don't repeat the same item. So for 6 items the equation is as follows 6*5*4*3*2= 720 possible combinations of 6 items.
1352732
The 5-button Simplex Lock has only 1,082 possible combinations. By comparison, this 3-dial lock (three wheels, each with digits 0-9) has 10   10   10 = 1, 000 possible combinations.
16574
Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
17604
With three columns, each with ten possibilities, the number of total combinations is 10 × 10 × 10, or 1000. With three switches, each with two possibilities, the number of total combinations is 2 × 2 × 2, or 8.