how many possible combinations are there for a 3 digit code?
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There are about 1,000 combinations possible for a 3-digit number/code. There are 10,000 combinations possible for a 4-digit number/code.
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There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6.
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With a four digit PIN, there are a possible 10,000 combinations. But with a six digit code, there are 1 million possible combos, making it a lot tougher for someone to crack your security code. If you are currently using a four digit PIN and update your software, you will need to manually opt in for the six digit PIN.
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The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999. You can generalize that: the number of N-digit combinations is 10 N.
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Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
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24. Well you have n choices for the nth digit. In your case you have 4 digits. So 4x3x2x1=24 combinations of all 4 digits with none repeating.
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For the third digit there are only 2 choices and for the last digit, one choice. Thus if you are not allowed to repeat a digit the number of possible 4 digit numbers you can construct from 1,2,3,4 is 4 3 2 1 = 24.
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reto wrote: How many different 4 letter combinations can be created from the letters A,B,C, and D? This is a case of number of arrangements possible with repetition. Thus you have 4 options each for the 1st,2nd,3rd and 4th letter giving you a total of 4*4*4*4 = 256 number of possible combinations.
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For example, a lock with ten numbers would be 10^4 or 10 000 different four digit combinations. Considering the lock only uses number: 10 x 10 x 10 x 10. 10,000 combinations.
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FACT: most master\lock padlocks have around 64,000 possible combinations. ANOTHER FACT: this instructable ( if done properly) will turn 64,000 into 100. so go to step 1 and let's get started.
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Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
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Dana F Anderson, Just interested in math is all. Kinda a hobby. Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
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FACT: most master\lock padlocks have around 64,000 possible combinations. ANOTHER FACT: this instructable ( if done properly) will turn 64,000 into 100.
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There are 10,000 possible combinations that the digits 0-9 can be arranged to form a 4-digit pin code.
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6 x 5 x 4 x 3 = 360 possible combinations. Given a 4 digit integer. each digit can be 1 through 6. No two digits the same.
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It's the same as possibilities to a 6 digit code with known numbers and no repeats. With 1 item there are 6 possibilities with 2 you only have 5 choices after the first if you don't repeat the same item. So for 6 items the equation is as follows 6*5*4*3*2= 720 possible combinations of 6 items.
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Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated. Now consider the possibilities with 13 as the first two digits.