how many grams of oxygen are required for 27 gram of aluminium?
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Answer: 24 gram of oxygen is required for 27 gram of aluminium.
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Oxygen gas is O2 . O2 has a molar mass of 32g/mol . ∴ There are 1.25 moles of O2 in 40g of oxygen gas.
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The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles aluminum oxide, or 101.961276 grams.
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12 md Al2O3) C. How many moles of oxygen are required to react completely with 14.8 mol Al? R 14mot AL ) : 11.1 mol o₂ d.
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per mole of oxygen. From here, the answer is simple. Just multiply 2 by 31.9988 g because there are two moles of oxygen. So, the answer is 63.9976 g ..
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Now, 1 mole of Al2O3 contains 2 moles of Al. The atomic mass of aluminium is given to be 27 u. This means that 1 mole of aluminium atoms ( or aluminium ions ) has mass of 27 grams , and it contains 6.022 × 10^23 aluminium ions.
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Aluminium or aluminum (13Al) has 22 known isotopes from 22Al to 43Al and 4 known isomers. Only 27Al (stable isotope) and 26Al (radioactive isotope, t1/2 = 7.2×105 y) occur naturally, however 27Al comprises nearly all natural aluminium.
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Aluminium is located in period 3, group 13, and has an atomic number equal to 13 . This tells you that the electron configuration of a neutral aluminium atom must account for a total of 13 electrons. Now, when aluminium forms 3+ cations, Al3+ , it loses 3 electrons from its outermost energy shell.
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The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Aluminium, or 26.981538 grams.
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We assume you are converting between moles Oxygen and gram. You can view more details on each measurement unit: molecular weight of Oxygen or grams The molecular formula for Oxygen is O. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Oxygen, or 15.9994 grams.
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Problem: The total numbers of neutrons, protons, and electrons in 27Al3+ are: A. 14 neutrons, 13 protons, 13 electrons B. 35 neutrons, 17 protons, 18 electrons C.
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An average aluminium can (without its contents, of course) weighed 16.55 grams in 1992. By 2001 the aluminium can weighed about 14.9 grams. Aluminium beverage cans come in different shapes and sizes. The standard volume is 375 ml.
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U mentioned element here so one gram atom of an element has 6.022×10^23 atoms :-) in oxygen(molar mass=16g/mol) 1g=1/16mol so it's 1/16 of the avogadro number.
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You need to balance the equation and see the mole ratio between the reactants. For this equation, the mole ratio is 3 moles of O2 : 4 moles of Al. So, you would then multiply: 14.8 moles*(3/4) = 11.1 moles. 11.1 moles O2 are needed to react completely with 14.8 moles of Al.
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For this equation, the mole ratio is 3 moles of O2 : 4 moles of Al. So, you would then multiply: 14.8 moles*(3/4) = 11.1 moles. 11.1 moles O2 are needed to react completely with 14.8 moles of Al.
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11.1 moles O2 are needed to react completely with 14.8 moles of Al.
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Parth Patil, former Intern at Class Sathi by Taghive. so, 0.1 mole will have 20.8 gm of oxygen.