how to calculate percent water in hydrate?
37798
Divide the mass of the water lost by the mass of hydrate and multiply by 100. The theoretical (actual) percent hydration (percent water) can be calculated from the formula of the hydrate by dividing the mass of water in one mole of the hydrate by the molar mass of the hydrate and multiplying by 100.
1000291
Hydrates are pure substances, because they contain a specific and reproducible number of waters in their formula. A wet compound is a mixture of two compounds that vary in their percent composition; a sample can be very wet or contain just a bit of extraneous water.
322591
['Take the mass of the hydrate and subtract the mass of the anhydrate to get the mass of water. ... ', 'Divide the mass of water by the molar mass of water to get moles of water. ... ', 'Divide the mass of anhydrate by the molar mass of anhydrate to get moles of anhydrate.']
30265
['Find the molar mass of all the elements in the compound in grams per mole.', 'Find the molecular mass of the entire compound.', "Divide the component's molar mass by the entire molecular mass.", 'You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.']
330769
['If 1 mole of HCl or NaOH gives you 1 mole of H2O , then the number of moles in H2O is: [ 1÷1×1 ] = 1 mole.', 'Now you have to find out the molar mass (M) of water ( H2O ). ... ', 'Therefore the molar mass (M) of H2O is: ... ', 'Last step, find the mass (m) of water.']
1117496
['mass % O = (mass of 1 mol of oxygen/mass of 1 mol of CO2) x 100.', 'mass % O = (32.00 g / 44.01 g) x 100.', 'mass % O = 72.71 %']
232805
The percent composition of water in the given sample is 20.93 %
118290
['A percent v/v solution is calculated by the following formula using the milliliter as the base measure of volume (v):', '% v/v = mL of solute/100 mL of solution.', 'Example:', 'X % = 5.0 mL HCl/100 mL of solution.', 'X/100 = 5.0/100.', '100X = 500.', 'X = 5.0% % v/v.']
742456
['Base Saturation (%) = (Base cations/CEC) x 100.', 'Calcium Saturation (%) = (Calcium cations/CEC) x 100.', 'Cation exchange capacity (CEC) = Base cations + Acid cations =12.4 + 4.8.', 'Base Saturation (%) = (Base cations/CEC) x 100.', '= (12.4/17.2) x 100.', 'Calcium Saturation (%) = (Calcium cations/CEC) x 100.', '= (10/17.2) x 100.']
788880
Answer and Explanation: The percent by mass of water in Na2 SO4. 10H2 O, also written as Na2 SO4 x 10H2 O is 55.91 percent.
70645
['Subtract the accepted value from the experimental value.', 'Take the absolute value of step 1.', 'Divide that answer by the accepted value.', 'Multiply that answer by 100 and add the % symbol to express the answer as a percentage.']
327835
['Either add/subtract the percentage given in the problem from 100% to determine what percentage we have.', 'Find 1% by dividing by percentage found in previous step.', 'Find 100% (original amount) by multiplying your answer in step 2 by 100.']
809606
To calculate percentages you can use the formula described at Libre Office Help: =A1*16% # Displays 16% of the contents of A1.
285165
Water activity is equal to equilibrium relative humidity divided by 100: (a w = ERH/100) where ERH is the equilibrium relative humidity (%). Relative humidity sensors of great variety are available for this purpose, including electric hygrometers, dewpoint cells, psychrometers, and others.
127471
['Method 1.', 'Step 1: Think about the percentages that add or multiply together to make your percentage.', 'Step 2: Find the value of these percentages.', 'Step 3: Add/Subtract/Multiply.', 'Method 2.', "Step 1: Divide the number you're finding the percentage of by 100 to find 1%."]
141819
The molar mass of the hydrate is the molar mass of the CoCl2 plus the mass of water. Calculate the percent by mass of water by dividing the mass of H2O in 1 mole of the hydrate by the molar mass of the hydrate and multiplying by 100%. Step 2: Calculate.
436650
To calculate, divide the amount obtained by the amount which entered the operation, times 100 to express in percent. The molecular weight doesn't change, so units of grams may be used.