how to find the distance between two corners of a rectangle?
320173
Use the Pythagorean Theorem (a^2 + b^2 = c^2). A and B are the lengths of the two sides of the rectangle. To get the length of the hypotenuse, you would need to solve for C. C is the square root of (A squared plus B squared).
69994
You can use the Pythagorean theorem to estimate the diagonal of a rectangle, which can be expressed with the following formula: d² = l² + w² , and now you should know how to find the diagonal of a rectangle explicit formula - just take a square root: d = √(l² + w²) .
321585
Set it up! Find the perimeter of the following rectangle by using the formula P=2L+2W, where L represents the legth and W represents the width of the rectangle. To find the perimeter, let L=2x+3 (the legth) and W=x+1 (the width) and plug these values into the formula P=2L+2W.
509976
To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. x is in this case the length of the rectangle while y is the width of the rectangle. The area is measurement of the surface of a shape.
56485
A rectangle has two diagonals, and each is the same length. If you know side lengths of the rectangle, you can easily find the length of the diagonal using the Pythagorean Theorem, since a diagonal divides a rectangle into two right triangles.
15982
To find the perimeter of a shape, measure each of the sides and add them all together. To find the area of a square, rectangle, or other parallelograms, multiply the length by the width.
284022
Here is the complete answer. Length = distance between (1,3) and (3,1) = √[(3-1)^2 + (1-3)^2)] = √8 = 2√2. So the area of the rectangle is 4√2 • 2√2 = 16.
706807
['When we need to find length of a rectangle we need to divide area by breadth.', 'Length of a rectangle = Area ÷ breadth.', 'ℓ = A ÷ b.', 'Similarly, when we need to find breadth of a rectangle we need to divide area by length.', 'Breadth of a rectangle = Area ÷ length.', 'b = A ÷ ℓ']
207290
A simple way to calculate the distance between numbers on a number line is to count every number between them. A faster way is to find the distance by taking the absolute value of the difference of those numbers. For example, the absolute values of 4 and -4, or |4| and |-4|, are both 4.
1367560
['If the curves are intersecting, then obviously the shortest distance between them is zero.', 'If they do not intersect at any point then:', 'Equate the slopes of the two curves and find the points where the slopes match.', 'Then find the distance between those points.']
920017
Width. Divide the area by the length if you are given these two figures but not the width. For example, if a rectangle has an area of 20 square feet and a length of 10 feet, divide 20 by 10 to get a width of 2 feet. Multiply the length times 2 and subtract this figure from the perimeter, if you're given these values.
986752
A rectangle has four edges. A rectangle is a two-dimensional shape that has four straight sides that meet in four 90 degree angles.
723887
Add l + l + w + w. Instead of adding two sides of your rectangle and multiplying by two, you can simply add all four sides together directly to find the perimeter of your rectangle.
1452394
Given a rectangle with length l and width w, the formula for the area is: A = lw (rectangle). That is, the area of the rectangle is the length multiplied by the width. As a special case, as l = w in the case of a square, the area of a square with side length s is given by the formula: A = s2 (square).
1056225
Find the dimensions of the rectangle using the perimeter. For this example, suppose the perimeter is 22 feet and the length is 5 feet. Write down the perimeter equation for a rectangle: P = 2L + 2W where "P" stands for perimeter, "L" stands for the length and "W" stands for the width. Fill in the perimeter equation.
873495
['The side length of the square is the distance between the points A and B. (Or any two adjacent vertices). Here, this is 22.', 'Area is the side length times itself, or 22 x 22 = 484.', 'Perimeter is four times the side length or 4 x 22 = 88.']
970019
['public class Main.', '{', 'public static void main (String args[])', '{ float a ,b, c, d, perimeter;', 'a=c= 5;', 'b=d=4;', 'perimeter = 2*(a+b);', 'System.out.println("Perimeter of Rectangle is: "+perimeter);']