how many possible combinations on a 4 digit lock?
107557
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code. Berry analyzed those to find which are the least and most predictable.
921696
However, as we have 4 slots, which need to be all filled at the same time in order to form a 4-digit number, we have to multiply the number of possibilities for each slot together, ie. 2 x 2 x 2 x 2 = = 16. Thus, 16 permutations are made possible.
1427017
Answer: There are 9,999 different combinations in a 4-digit lock.
414273
With a four digit PIN, there are a possible 10,000 combinations. But with a six digit code, there are 1 million possible combos, making it a lot tougher for someone to crack your security code. If you are currently using a four digit PIN and update your software, you will need to manually opt in for the six digit PIN.
151182
If you include 3, 2 and 1 digit numbers then it would be 24 + 24 + 12 + 4 = 64 combinations.
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With respect to that technical meaning, there is only one combination of the four numbers 4, 5, 8, and 7, taken four at a time: All four of them. There are 24 combinations. 4578, 4587, 4758, 4785, 4857, 4875, 5478, 5487, 5748, 5784, 5847, 5874, 7458, 7485, 7548, 7584, 7845, 7854, 8457, 8475, 8547, 8574, 8745, and 8754.
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The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999. You can generalize that: the number of N-digit combinations is 10 N.
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First, we have six possible digits to use to form our number. Assuming we can reuse any of these, the answer is simply 6^4, or 1,296 possible combinations.
77076
Assuming no five-digit number can begin with zero, there are 9 possible choices for the first digit. Then there are 10 possible choices for each of the remaining four digits. Therefore, you have 9 x 10 x 10 x 10 x 10 combinations, or 9 x 10^4, which is 90,000 different combinations.
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There are 10,000 possible combinations. Start at 0001, then 0002, then 0003...and work your way to 9999. Don't forget to try 0000 as well. You can also start at 9999 and work your way down to 0000 if you'd rather.
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In your case you have 4 digits. So 4x3x2x1=24 combinations of all 4 digits with none repeating. Without repeating digits 24 four digit numbers can be made .
387357
Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
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Could it be 10C3? The safe combination could be 433 or 334; the combinations are the same, but their ordering is different. Order is important for the safe combinations, this is a permutation problem. A safe code can be made of any of the numbers {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}.
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The number of combinations is 8,145,060. This is because there are 45!/(6!
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Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
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While this might seem like a small change, it actually makes breaking into your iPhone a lot more difficult. With a four digit PIN, there are a possible 10,000 combinations. But with a six digit code, there are 1 million possible combos, making it a lot tougher for someone to crack your security code.
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Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated.