if two fair dice are thrown what is the probability of getting a double six?
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Thanks for the A2A. Hint: A double of 6 is obtained when both dice throws result in 6. The probability for such an event is 1/36.
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If you were asking about the probability of rolling TWO dice, with the resultant sum being less than 5, there are 6 ways to do so in 36 possible outcomes. The answer is 6/36, or 1/6, or 16.67%.
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The Dice Combinations Provided that you use two dice, you can roll eleven different numbers, namely 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12. It follows that the number of possible combinations is equal to 6 x 6 = 36 as each of the two dice used in craps has six sides.
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So to get a 6 when rolling a six-sided die, probability = 1 ÷ 6 = 0.167, or 16.7 percent chance. So to get two 6s when rolling two dice, probability = 1/6 × 1/6 = 1/36 = 1 ÷ 36 = 0.0278, or 2.78 percent.
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Rolling Two Dice. Note that there are 36 possibilities for (a,b). This total number of possibilities can be obtained from the multiplication principle: there are 6 possibilities for a, and for each outcome for a, there are 6 possibilities for b. So, the total number of joint outcomes (a,b) is 6 times 6 which is 36.
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There are six faces for each of two dice, giving 36 possible outcomes. If the two dice are fair, each of 36 outcomes is equally likely. Three outcomes sum to 4: (1+3), (2+2) and (3+1). Probability of getting a sum of 4 on one toss of two dice is 3/36, or 1/12.
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Rolling Two Dice. Note that there are 36 possibilities for (a,b). This total number of possibilities can be obtained from the multiplication principle: there are 6 possibilities for a, and for each outcome for a, there are 6 possibilities for b.
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Since there are 6 possible outcomes (1, 2, 3, 4, 5 and 6) on each of the dice, of which 3 are even (2, 4 and 6) and 3 are odd (1, 3 and 5), the probability of obtaining an even number on either dice is 3/6 = 1/2, and the probability of obtaining an odd number on either dice is also 3/6 = 1/2.
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Question: What is the probability of getting at least one six in a single throw of three unbiased dice? Answer: The probability of getting either 1 or 2 or 3 or 4 or 5 when one dice is thrown is 5/6 x 5/6 x 5/6 for 3 dices = 125/216. This is the probability of getting at lease one 6 when 3 dices are thrown.
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What is the probability of getting a sum 9 from two throws of a dice? Explanation: In two throws of a dice, n(S) = (6 x 6) = 36.
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When you roll two dice, you have a 30.5 % chance at least one 6 will appear. This figure can also be figured out mathematically, without the use of the graphic.
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There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice. So you have a 16.7% probability of rolling doubles with 2 fair six-sided dice.
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To get a even doublet, you have only three possibilities (2,2), (4,4) and (6,6) out of a total of 36. Since all 36 possibilities are equally likely the chance of a even doublet is 3/36 = 1/12.
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There a four possible rolls with a single die less than 5 (1, 2, 3, and 4). If you were asking about the probability of rolling TWO dice, with the resultant sum being less than 5, there are 6 ways to do so in 36 possible outcomes. The answer is 6/36, or 1/6, or 16.67%.
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What is the probability of getting two numbers whose product is even? Explanation: In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36. n(E) = 27.
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As long as the numbers are all present, the die would still be fair and proper, and the probability of rolling any particular number would be constant - 1/6. ... The average of this seriously-deformed dice is: 1 * 1/3 + 2 * 1/12 + 3 * 1/12 + 4 * 1/12 + 5 * 1/12 + 6 * 1/3 = 3.5, the same as a normal dice.
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If the two dice are fair and independent , each possibility (a,b) is equally likely. Because there are 36 possibilities in all, and the sum of their probabilities must equal 1, each singleton event {(a,b)} is assigned probability equal to 1/36.