ab is the diameter of a circle and c is any point?
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AB is a diameter of a circle and C is any point on the circle. Show that the area of △ABC is maximum, when it is isosceles. ... For value of area to be maximum,as per calculus should be zero.
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Let C be the circumference of the circle. Let d be the diameter of the circle. Then C/d = pi. So d = C/pi = 5 inches/pi, which is approximately equal to 1.5915494309189533576888376337251 inches.
410917
The two formulas that are useful for finding the radius of a circle are C=2*pi*r and A=pi*r^2. We use algebra skills in solving for our variable r. We know that the constant pi is always 3.14.
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["If you have any two points [let,(a1,b1)&(a2,b2)] on circle's diameter,expect the two points on circumference you should find the equation of diameter with-", '(x-a1)*(a1-a2)=(y-b1)*(b1-b2)', 'and then there will be two equations -', '(1)E. of circle : (x-h)^2+(y-k)^2=r^2 [let]', '(2)E. of diameter : ax+by+c=0 [let]', 'find the (x,y).']
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In Fig. 10.42,AB is a diameter of the circle,CD is a chord equal to the radius of the circle.AC and BD when extended intersect at point at E. Prove that ∠AEB = 60 degree . In Fig.
1289457
The distance from the center to a point on the circle is called a radius. Every circle has an infinite number of possible diameters. The formula for finding the diameter of a circle is two times the radius (2 * radius).
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The diameter, like in a normal circle, is just twice the radius. If given the perimeter: The perimeter of a semicircle will be one half the circumference of its original circle, πd , plus its diameter d .
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Explanation: It is given that AB is tangent to circle O at B, AB = 5 unit and AO = 9.8 unit. According to the tangent perpendicular to radius theorem the tangent line and radius are perpendicular to the point of tangency.
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['Radius: The distance from the center of the circle to its outer rim.', 'Chord: A line segment whose endpoints are on a circle.', 'Diameter: A chord that passes through the center of the circle. ... ', 'Secant: A line that intersects a circle in two points.']
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The area of a circle is given by the formula A = π r2, where A is the area and r is the radius. The circumference of a circle is C = 2 π r. If we "solve for r" in the second equation, we have r = C / (2 π ).
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Given : A circle with centre O, an external point P and two tangents PA and PB to the circle, where A and B are points of contact (Fig. 10.36A). Hence, ∠APB = 2 ∠OAB. ... Since, the tangent at any point of a circle is perpendicular to the radius through the point of contact.
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AB is any chord of the circle x2+y2-6x-8y-11=0 which subtends an angle π2 at (1,2). If locus of midpoint of AB is a circle x2+y2-2ax-2by-c=0; then find the value of (a+b+c). a+b+c=3+4-17=-10.
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Diameter is the length of a line touching two points on a circle that passes through the center. Diameter exists only for circular, or for circle-based objects like a sphere or cylinder, thus the width and length should always be the same.
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The two formulas that are useful for finding the radius of a circle are C=2*pi*r and A=pi*r^2. We use algebra skills in solving for our variable r.
1178359
In a circle with centre O, AB is a diameter and CD is a chord which is equal to the radius OC. AC and BD are extended in such a way that they intersect each other at a point P, exterior to the circle. The measure of ∠ABC is. 4).
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Solve the equation for the diameter of the circle, d= C/π. In this example, "d = 12 / 3.14." or "The diameter is equal to twelve divided by 3.14." Divide the circumference by pi to get the answer.
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In the given figure AB is a chord of a circle, with centre O, such that AB=16cm and radius of circle is 10 cm. Tangent at A and B intersect each order at P. Find the length of PA. AL2+OL2=OA2 So we get, OL=6cm Hence,tan(θ)=OAPA=OLAL (PA)=(OA)⋅ALOL Therefore, PA=80/6=40/3.