how many combinations of 3 with 3 numbers?
16468
There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times.
450241
There are 60 of them. Using the same argument as above there are 60 60 = 3600 two "digit" combinations and 60 60 60 = 216000 three "digit" combinations.
137078
Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated.
1134217
For the number 3 there are 33 numbers divisible by 3 from 1 to 100. If you want the number divisible by both 3 and 4 it is 58 .
794598
There are 40,475,358 possible 6-number combinations that can be formed from numbers 1-58 . To determine this, the Combination formula is used. n choose k equals the factorial of n (divided by) all over the factorial of k times (or multiplied by) the factorial of n minus k.
208608
Again there ae 4 choices so the number of possible 3 digit numbers is 4 4 4. Finally there are 4 choices for the last digit so the number of possible 4 digit numbers is 4 4 4 = 256.
475048
Originally Answered: How many different ways can you make combinations of 3 letters out of the five-letter word LEARN? So, 60 different combinations of 3 letters out of 5 given letters can be formed.
130300
The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999. You can generalize that: the number of N-digit combinations is 10 N.
219027
See for 11 numbers there can be 9 ways for each number for 1st nine places since 0 can't be the fist number and next two are repeated from 10 numbers hence 10!/2! So 99 combinations have 10!/2! Permutations hence total ways are 99*10!/2!
44803
In any Pick 3 game, there are 3 digit positions, with each position containing a digit from 0 to 9. If one were to list all of the possible combinations of digits in each of the three positions, there would be a total of 1,000 different number combinations.
1305375
Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6.
1123436
The number of combinations that are possible with 7 numbers is 127. In general, the formula we use to determine the number of combinations possible...
47858
There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6.
279311
Answer: There are 9,999 different combinations in a 4-digit lock. And now we have 1,000+9,000=10,000 combinations total. But…
1059377
If repetition of digits is not allowed then the number of combinations possible is 12P12. That is 12! Combinations. So 479001600 combinations are possible if repetition is not allowed.
683759
For each of these 4 first choices there are 3 second choices. Therefore there are 4 x 3 = 12 possibilities.
905943
The number of combinations that are possible with 20 numbers is 1,048,575.