how many 4 digit combinations with 10 numbers?
317090
Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
208608
Again there ae 4 choices so the number of possible 3 digit numbers is 4 4 4. Finally there are 4 choices for the last digit so the number of possible 4 digit numbers is 4 4 4 = 256.
102661
A standard 3-digit lock has 999 possible combinations, which is why the 4- digit locks cost a bit of a step more money, as they have 9999 possibles.
450241
There are 60 of them. Using the same argument as above there are 60 60 = 3600 two "digit" combinations and 60 60 60 = 216000 three "digit" combinations.
178666
There are one million of them (999999 + 1). If repetition is not allowed (which is probably what you are referring to in your last sentence), you can pick any of ten digits for the first number, any of the nine remaining for the second, and so forth. This is 10 times 9 times 8 times 7 times 6 times 5 or 151,200.
411390
Well, this could turn out to be a simple permutation problem: you have ten number choices (0-9) for each digit of a phone number and repetitions are allowed. Technically, there could be as many as \begin{align*}10^{10} = 10,000,000,000\end{align*}, or 10 billion possible phone numbers in the U.S.
107557
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code. Berry analyzed those to find which are the least and most predictable.
849988
If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
284335
How do I know this? 10 10 = 100 two digit combinations.
279311
Answer: There are 9,999 different combinations in a 4-digit lock. And now we have 1,000+9,000=10,000 combinations total. But…
966160
Hence, in this case there are 4 3 = 12 possible two digit numbers. For the third digit there are only 2 choices and for the last digit, one choice. Thus if you are not allowed to repeat a digit the number of possible 4 digit numbers you can construct from 1,2,3,4 is 4 3 2 1 = 24.
414282
Well you have n choices for the nth digit. In your case you have 4 digits. So 4x3x2x1=24 combinations of all 4 digits with none repeating. Without repeating digits 24 four digit numbers can be made .
315001
In any Pick 4 game, there are 4 digit positions, with each position containing a digit from 0 to 9. If one were to list all of the possible combinations of digits in each of the three positions, there would be a total of 10,000 different number combinations.
1109952
The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999.
362961
There are 6 = 3x2x1 ways to order 3 digits in a row. Thus the number of combinations of 3 of the 10 digits is 720/6 = 120 combinations.
1440137
There are about 1,000 combinations possible for a 3-digit number/code. There are 10,000 combinations possible for a 4-digit number/code. You are much better off choosing the 4-digit code lock because anyone can easily brute-force the combination in between 20 minutes and an hour.
1173500
In this case you have all ten digits [0,1,2,3,4,5,6,7,8,9] at your disposal. Assuming repetition is allowed, you can have 7-digit numbers from 1,000,000 to 9,999,999 which is a total of 9,000,000 7-digit numbers. These are all the possible 7-digit numbers. In general, there are 9 × 10^(n-1) possible n-digit numbers.