# Problem 1
# If we list all the natural numbers below 10 that are multiples of 3 or 5,
# we get 3, 5, 6 and 9. The sum of these multiples is 23.
# Find the sum of all the multiples of 3 or 5 below 1000.

multiple_3_5(x) = ((x % 3) == 0) || ((x % 5) == 0)

∑ = 0
for i in 1:1000-1
    global ∑ += multiple_3_5(i) ? i : 0
end
print(∑)
