Can u tell me easiest method for conversion (i.e Decimal to Binary and Hexa to Decimal)?
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in case of conversaions on multiplication and division r possible(remember)\nthink of decimal value of any no as highest(remeber)....than binary,octal and hexadecimal..\ndecimal 2 binary=higher 2smaller..which mean u have 2 carry out division by 2....(division makes result smaller)\nhexadecimal2decimal=smaller 2 higher...which means u have 2 carry out multiplication by 16.....(multiplication makes result bigger)
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u can't get a remainder only a decimal
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Binary is base two. The decimal system we use is base 10.\nThe earliest computers used base two because there are only two states - on or off, (1 or 0).\n\nIn our system we have 1s place, 10s place, 100s place etc.\nin base two, there is 2^0, 2^1, 2^2, 2^3  or 1's, 2's, 4's, 8's place.\n\nthe number 5 is written 1 in 1s place and 1 in 4s place\nso 5 is 101 in base 2.
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There are built-in functions in a programming language to perform that task.For instance in C++ we have: cint("string value") for converting the string value into integer.And in Visual Basic we have the val() function to do the same thing.
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Change 1/2 to a decimal and add it to 11.\n\nChange 1/5 to a decimal and add it to 2.\n\nSubtract the second decimal number from the first.
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A decimal number is one made out the normal digits 1234567890. A binary number is made out 1's and 0's for example in binary 1=1 10=2 11=3 100=4 101=5 etc
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binary 11 is 3 decimal
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I can do all that, but except for small numbers I wold never bother.\n\nThe "easy" way, such as it is, is to always go through binary on your way from decimal to hex. \nFor the others, list the bits and add/partition.
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0.01 is already decimal..\nif you want 0.01%, it should be 0.01/100=0.0001
49715
use bitwise operators. something like:\n\nnum_bits = 0;\nfor(i = 0; i < 32; i++) {\nif number & (1<<i) num_bits++;\n}\n\nnow num_bits holds the number of bits that were set in number. The "<<" operator does bit shifting. So "1<<i" equals a number that's all 0's except for a 1 at position i. If you bitwise and that with something, that tells you if that bit is set in the number. So we do this for each of the bits and add up the results.\n\nThis is assuming 32-bit integers. Adjust accordingly for 64-bit integers.
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download converter free from www.download.com \nxlnt site no ads or spam , safe downloads and user  reviews.
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Depends what Base you are using.\n\nIn decimal it is 1234602335680234\n\nIn Hexadecimal it is 0x123463677ABD69AC\n\nI'll leave other bases as an exercise for the student...
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use a hex editor \n\ngo to download.com then search for a hex editor software
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I use http://www.convert-me.com ... it's much easier!
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The best I've found is a free converter - \nhttp://joshmadison.net/software/
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I suggest http://www.oanda.com/convert/classic\nI've tried this many times, very easy and very helpful too.
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you line up the decimal points and subtract from right to left.\nExample:\n\n  2.10\n- 1.25\n_____\n   .85