How do you find the X, Y, Z?
955620
2x+2y+3z=-1 .....(1)\n3x-1y-2z=18 .......(2)\n-3x+1y-1z=-9 ......(3)\n\n(1)+(2)x2\n2x+2y+3z=-1\n6x-2y-4z=36\n-------------------+\n8x-z=35 .............(4)\n\n(2)+(3)\n3x-1y-2z=18\n-3x+1y-1z=-9\n---------------------+\n-3z=9\nz=-3\n\nsubstitute this value of z to (4)\n8x-z=35\n8x-(-3)=35\n8x+3=35\n8x=32\nx=4\n\nsubstitute the value of x and z to (1)\n2x+2y+3z=-1\n2(4)+2y+3(-3)=-1\n8+2y-9=-1\n2y-1=-1\n2y=0\ny=0\n\n(x,y,z)=(4,0,-3)\n\nhope this is clear enough
698387
y= -(2/3)x^2 + (2/3)x + 4\n\n\n(P): y = ax^2 + bx + c\n\nPoints (0;4)  (-2;0)  (3;0) are element of (P)\n-->  4 = 0a + 0b + c --> c = 4\n0 = 4a - 2b + c\n0 = 9a + 3b + c\n\n--> 5a + 5b = 0 --> b = -a\n--> 4a + 2a + 4 = 0 --> a = -2/3,  b=2/3
865074
To start off, you are given a simple equation to find x with respect to y and z. \n\nx = 2y - 3z +5\n\nThe next step is to substitute into the other two equations.\n\n3(2y - 3z +5) -3y + z = 9\n6y - 9z + 15 - 3y + z = 9\n3y - 8z = -6\n\n5(2y - 3z + 5) + y - 3z = 3\n10y - 15z + 25 +y - 3z = 3\n11y - 12z = -22\n\nNow what I would do is take the first new equation and solve for y:\ny = (8/3)z - 2\n\nAnd then substitute it into the second equation:\n\n11((8/3)z - 2) - 12z = -22\n(88/3)z - 22 - 12z = -22\nz = 0\n\nInsert this into the previous equation:\ny = (8/3)(0) - 2\ny = -2\n\nAnd then finally into the very first equation:\nx - 2(-2) + 3(0) = 5\nx + 4 = 5\nx = 1\n\nNow, to be sure, we check our answer with the other two equations:\n\n3(1) -3(-2) + 0 = 9\n3 + 6 = 9\n\n5(1) + (-2) - 3(0) = 3\n5 - 2 = 3\n\nEverything checks out, so:\nx = 1\ny = -2\nz = 0
949784
y= (x^2 - 1)^2\nx^2-1=+/-√y\nx^2=1+/-√y\nx=+/-√(1+/-√y)
864314
x2=x1/2, y2=y1+x1/4, z2=z1+x1/4\nx3=x2+4, y3=y2-8, z3=z2+4\nx4=x3+z3/4, y4=y3+z3/4, z4=z3/2\nx4=y4=z4=16\nz3=z4*2=32\nx3=x4-z3/4=8\ny3=y4-z3/4=8\nx2=x3-4=4\ny2=y3+8=16\nz2=z3-4=28\nx1=x2*2=8\ny1=y2-x1/4=14\nz1=z2-x1/4=26\n\nSo the ages are 8, 14 and 26
725388
let them be x and y\n\nxy = 588\nwe need to minimize x+3y\nlet 3y be z\n3xy = xz = 588*3 = 1764\n\nminimize x+z\n(x+z)^2- 4xz = (x-z)^2\n(x+y) is minimum when (x-z)^2 is minimum or x = z\n\nso x=z = 42\nso x= 42 y = 14
549653
Subtract 2x from each side\n-y = 0 - 2x\nMultiply each side by -1\ny = 2x
822825
z-2d=1/2yx^2\n2(z-2d)=yx^2\nx^2=(2/y)(z-2d)\nx=+/-rt[(2/y)(z-2d)]
835073
okay well\n\n1) combine two to figure out the first variable\nx-2y+z=4\n-x+2y+3z=-4\nso 4z=0; z=0\nthen figure out the next variable with a different set of equations\nlike and multiply so the ys will cancel [take Zs out cause zero]\nx-2y+z=4\n2(2x+y)=6\n\ntherefore\nx-2y=4\n4x+2y=6\n5x=10\nx=2\n\nthen substitute for y\n\n-x+2y=-4\n-2+2y=-4\n2y=-2\ny=-1\n\nso y=-1, x=2, z=0\n\n\ncontinue the process with the rest.
1146591
You can't really answer that question the way it was asked.  If you know a value of x or y, you can find the other value though.\n\nFor example, say you want to find the x-intercept (where y=0)\n\ny = 3x + 2\n0 = 3x + 2\n-2 = 3x\n-2/3 = x\n\nThere you go, you can do this for any point you know is on the line.
356024
x + y + z = t\n\nx +x% + y + y% + z + z% =\n[(100 + 1)( x + y + z)]% =\n101t% = t + t%. So\nx +x% + y + y% + z + z% = = t + t% or\nx% + y% + z% = t%
833533
Go for calculator.\npress  number (z), press x^y, press 5 \nthen press x^y then press 0.3\ngotcha, u will get the answer
424288
1. y2+6y+8 = (y+4)(y+2)\n2. x2+7x+12 = (x+4)(x+3)\n3. z2+2z-24 = (z-4)(z+6)\n4. x2+7x+10 = (x+2)(x+5)
695016
4x + 3y =12, find y = 4\n4x+3*4=12\n4x+12=12\n4x=0\nx=0
983933
(x+y+z)(x+y+z) = x^2 + y^2 + z^2 + 2xy + 2xz + 2yz = 1\n\n(1-x^2 - y^2 - z^2) = 2xy + 2xz + 2yz\n\n(1 - x^2 - y^2 - z^2) \n------------------------ = xy + xz + yz\n.............2\n\nClearly the left hand side is less than 1/2
638682
Domain ~ x values\nRange ~ y values\n\nYou have to work the function and figure them out.
405853
y=xz\n\nplug in the numbers tht are given.\n\nyou are given x=3, so x in the equation becomes 3. \ny=(3)z\n\nz=10, so zin the same equation becomes 10.\nNow it's y=(3) x (10)\n\nWhen multiplied, you get 30.