Why is y intercepts variable b?
954269
it is natural to write the equation of st.line as y=ax+b (now common form is y=mx+c; this has its own story!)\n\nso if x=0, y=b
3669
This is for math right? If so:\n\nThe slope-intercept form is:\n\ny = mx + b\n\ny = value on the y-axis\nm = slope\nx = value on the x-axis\nb = y-axis intercept\n\nThe slope-intercept form gives the equation for a straight line.
113710
Well, the y-intercept would be acceleration when the force on the object is zero.  You'd better hope it's zero!  If it's not, you might want to fix the point in your analysis (this can be done in Excel) or redo the experiment.\n\nEdit: If you're plotting acceleration vs. force, the intercept really should be zero.  Those values appear small enough to be within the error of the experiment.  They could be indicative of the effect of a systematic error, but are more likely the result of random noise.  Try fixing the intercepts at zero in Exel (right-click on the regression line and open up the options for it; there should be a checkbox for "fix intercept").  An intercept value that is not equal to zero indicates that there was acceleration when there was no force!
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
173295
It refers to the slope of a line and the y-intercept.
887169
You're getting into logarithm.  If X/D = R^Y, then Y = log(X/D), where log is the logarithm in base R.
849823
set x=0 to get the y intercept and \ny=0 to get the x intercept\nin this case\nsetting x=0\ny-1=9\ny=10\nso y intercept=(0.10)\nsetting y=0\n-1=(x-3)^2\nx-3=rt(-1)\nx imaginary\nso no x intercepts
955089
y-2x=2\ny=2(x+1)\nx intercept(-1,0)\ny intercept(0,2)
887226
x,y intercepts are\n9-y=+/-(x-2)^2\ny intercept bysetting x=0 will be (0,9)\nx intercept by setting y=0\n9=+/-(x-2)^2\nx-2=3x=5\nx-2=-3\nx=-1\nx intercepts(-1,0) and (5,0)\nvertex=(2,9)
782341
Both of your questions refer to equations of lines.\n\n\nSlope intercept form of a line refers to an equation of a line that contains the line's slope and y-intercept. This is normally represented by :    y = mx + b   where m is the slope of the line and the point (0 , b) is the line's y - intercept.\n\n\nStandart form of a line refers to an equation of a line where the coefficients of the variables are integers, and the line is set equal to a constant. This is represented by :  ax + by = c   where a and b  are integers.
543118
No, you must use algebra to plot lines. How else would you explain the variables x and y?\n\nSlope-intercept form looks like this:\n\ny = mx+b\n\nOr, in the case of vertical lines:\n\nx = my+b\n\nWhere m is the slope and b is the x- or y- intercept, depending on which one you are using.
866301
because y- x > 0\n\n|y-x | = y- x (positive value)\n\nx-y < 0\n\nso | x-y| = y-x (as absolute value positive)
943382
If l,w and y are separate variables then\n(lw - lwy)/lw=lw/lw - lwy/lwy = 1 - y\n\nIf lw and lwy are each a vaiable then\n(lw - lwy)/lw= lw/lw - lwy/lw = 1-lwy/lw\n\nIf lw and y are variables then\n(lw - lwy)/lw = lw/lw - lwy/lw = 1 -y
266735
Consider the equation y= a (x^n) / b (x^m) where n and m are the highest powers of the variable x found AFTER factoring and reducing the numerator and denominator to the products of the smallest polynomials posible. The situation may be that n or m may be zero, and that's OK.\nThe y intercept is found when x=0. The x intercept is found when the factors of the numerator are set = to zero; i.e. if y= x^2 + 3x + 2 = (x+2) (x+1), then x=-2 and x=-1 are conditions that yield y=0, and -2 and -1 are the roots of the numerator and are the y intercepts.\nThe vertical asymptotes are when Y becomes infinite, i.e the denominator becomes zero. Take each of the factors in the denominator, set them equal to zero, and solve for the corresponding values of x.  For an equation y = 6 / (x-2) (x+3), set each denominator factor equal to zero, and the conditions are for two vertical asymptotes, one at x=2, and the other at x= -3. \nFor the horizontal asymptotes go back to ,  y= (a (x^n)) / (b (x^m)). If n>m there is no HA. If n<m, such as y= x / ((x^2)+1), the HA is the x axis. If n=m the HA is an/bn, or just a/b.\nTry this. I hope I didn't make any typo mistakes
548747
(x,y) (-x,y)is a refelction over y axis. I think...
836584
The form y = mx + b is called the "slope-intercept" form of an equation describing a straight line.\n\nIn this form, m is the slope (how much the y-value changes for each unit change of the x value) and b is the point along the y-axis where the line crosses it (where x-value is zero).\n\nSo, as m increases, the line bocomes closer to vertical and when m decreases, the line becomes closer to horizontal.\n\nSimilarly, when b increases the line's slope remains the same but the line moves up on the graph, while if b decreases then the line moves down.\n\nHere is a great website for playing with this form of a linear equation in slope-intercept form:
176045
x-intercept\ny-intercept