In the reaction 2Mg + o2 -> 2 MgO?
960163
2 Mg + O2  =  MgO\n48 g  + 32 =   80\n50 g + 33.33= 83.33\n (50*80) / 48 = 83.33\n\nit should have been 83.33\n75/83.33=0.90    = 90% ?
502184
5H2O2(aq)+2KMnO4(aq)+\n3H2SO4(aq)-->\n2MnSO4(aq)+K2SO4(aq)+\n8H2O(l)+5O2(g)
797218
I just added 2 everywhere:\n2KMnO4  K2O  2MnO O2\n\nThen took  care of Oxygen like this\n8=1+2+2x, x=5/2\n2KMnO4  == K2O 2MnO 5/2 O2\n\nThen made it whole number all.\n4 KMnO4  ==  2K2O  4MnO  5O2
904363
(NH4)2CO3+MgSO4->(NH4)2SO4+MgCO3
929071
2C18H18 + 45 O2 --->  36 CO2 + 18 H2O\n3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O
957775
Ca(OH)2 + CO2 --> C(OH) + CaO\n\nIs unbalanced..
651011
H2O2 + OC(NH2)2 -> HCOOH + NH4OH -> NH4(HCOO)
295951
2 CH3OH + 3 O2 → 2 CO2 + 4 H2O + 726 kJ/mol
455269
H2SO4 + Mg(OH)2 -> 2H2O + MgSO4
793971
According to the equation:\n\n2NO + O2 --> 2NO2\n\n2 mol of NO reacts with 1 mol O2, so\n0.886 mol NO reacts with 0.886/2 = 0.443 mol O2\n\nWe have 0.503 mol O2 > 0.443 mol. So O2 is in excess and NO is the limiting reactant. It reacts fully and produces 0.886 mol NO2 (because 2 mol NO give 2 mol NO2)
866210
2NO+O2--->2NO2\n\nCaO+H2O--->Ca(OH)2\n\nCaCO3--->CaO+CO2
116069
The balance is :\n\n     H2O2(aq) -> O2(g) + 2H+(ag) + 2e-\n MnO2(s) + 4H+(aq)  +  2e-  ->  Mn2+(aq)  + 2H2O\n \n Combine the two half-reactions and cancel on both sides yield the     complete balance equation.\n\n MnO2(s) + H2O2(aq) + 2H+(aq) -> Mn2+(aq) + O2(g) + 2H2O\n\n this is an oxidation-reduction reaction\ntype  decomposition reaction.
129663
Please do your own home work.\n\nI suspect you are missing a symbol, it probably should be,\nN2O4  <==>  2NO2\n\nThink about how each of the changes will effect the equilibrium of the reaction.
728397
You need to first balance the equation.\n\n2CO + O2 --> 2CO2\n\nUsing this you find the answer to be D.
438725
Magnesium Sulfate\n\nMgSO4\n\nMg(OH)2 + H2SO4 -> MgSO4 + 2HOH\n\nHOH = H20\nJust in case...
673183
MnO4- + 5e- + 8H+ -> Mn2+ + 4H2O\n\nVO+2  + H2O ->  VO2+ + e- + 2H+\n\nMultiplying eqn. below by 5\n\nMnO4- + 5VO+2 + H2O -> Mn2+ + 5VO2+ + 2H+
727458
2. 2 Na + 2 H2O --> H2 + 2 NaOH\n3. 2 HNO3 + Ca(OH)2 --> Ca(NO3)2 + H2O\n4. C5H12 +  8 O2 --> 6 H2O + 5 CO2