algebra help please!!?
955753
1) Plug in some numbers for the Y and X values\n\n5=x/2+3\n\n8=x/2+3 (SOLVE FOR X ON BOTH OF THOSE FIRST)\n========================\n\n5=-2/x-1\n\n8=-2/x-1\n\n(SOLVE FOR X ON BOTH OF THOSE FIRST)\n\nThen draw the chart with those points
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
191567
Please use parentheses to explain the problem more effectively. Assuming the problem as,\n\n(x-1)/2x + x/(x+3)\n\nThe solution can be,\n\n(3x^2+2x-3)/(2x^2+6)
897994
i)\nax=ab+c\nax-ab=c\na(x-b)=c\n       a=c/(x-b)\n\nii)\n3a+ab=6\na(3+b)=6\n         a=6/(3+b)\n\niii)\na(x-6)=3\n        a=3/(x-6)\n\ni hope that this helps
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
607601
I think you set the equation to zero then you have to factor it.  Go to the link below if you wanna know how to do it. OR look your your math book.
520168
Try this:\n\nhttp://www.algebra.com/
747340
-2x-x > -6 + 4\n-3x > -2 \nx < 2/3
927818
2(x - 3) = 2\n\n2(x - 3) / 2 = 8 / 2\n\n(x - 3)² = 4\n\n√(x - 3)² = √4\n\nx - 3 = ± 2\n\nx - 3 + 3 = 3 ± 2\n\nx = 3 ± 2\n\n- - - - - - - - - \n\nSolving for ( + ) \n\nx = 3 + 2 \n\nX = 5\n\n- - - - - - - - - \n\nSolving for ( - )\n\nx = 3 - 2 \n\nx = 1\n\n- - - - - - - - -s-
1089643
http://www.algebra.com
972476
........._______________\nx - 5 ) x³ - 3x² - 13x + 15 ( x²\n......... x³ - 5x²\n......... -------- ....↓\n............... 2x² - 13x ....... ( 2x\n............... 2x² - 10x\n............... ----------- ....↓ \n............... ....... -3x + 15. (-3\n............... ....... -3x + 15\n............... ....... -----------\n............... ....... -----------\n\nSo P(x) = x³ - 3x² - 13x + 15\n= (x - 5)(x² + 2x - 3)
516830
http://www.gateways2learning.com/Algebra/Algebra.htm\n\nAlso try here.......\n\nYou may want to reconsider having it solve the answer for you, always know how to do the breakdown, it will help you to know "how" to go about it when you take a test.\n\nGood luck.....................
714160
x^2+6x+8/x^2-4-21 / x^2-4/x^2-7x\n=x^2 + 6x +(8/x^2) - 4 - (21/x^2) - (4/x^2) - 7x\n=x^2 + 6x -4 -7x +(8/x^2) - (21/x^2) - (4/x^2) \n=x^2 + 6x -4 -7x +[8-21-4]/x^2\n=x^2 + 6x -4 -7x -17/x^2\n=(x^2)*[x^2 - x -4  -17]/x^2\n=(x^2)*(x^2) - (x^2)*(x) -4*(x^2)  -17]/x^2\n=(x^4) - (x^3) - 4(x^2)x -17]/x^2
821450
go to a math website off yahoo. it should help.
571127
Try going to this website. The will explain it step by step and you can ask all the math questions you want. www.algebra.com
390719
so you have (1/2)a+a-(6/3)=4+(1/3)a\n\nadding like terms: (3/2)a-2=4+(1/3)a\n\nsubtract (1/3)a from (3/2)a and add two to both sides:\n(3/2-1/3)a=4+2\n(9/6-2/6)a=6\n(7/6)a=6\n\nnow solve and what do you get? :)
1174662
2(x-4y+1)+3(-2+y-2)\n2x-8y+2-6+3y-6\n2x-8y+3y-6-6\n2x-5y-12\n\n2x-5y-12= answer\n\nHope this helps you.