what is the BTU or therm content of food grade corn oil when burned?
958967
A bushel of corn yields ethanol that can be burned for about 200,000 BTU.  Food grade corn oil is not typically burned as fuel, so there isn't any readily available information about it in that respect.
791019
Straight chain hydrocarbons (e.g., methane, butane, propane, gasoline, deisel) run about 20,000 BTU/lb.  High explosives typically are 2,000 BTU/lb because they must include the heavy oxidizer.  Most other combustibles (wood, paper, methanol, ethanol) are in the range of 5000-10000 BTU/lb.\n\nIt is interesting that high explosives have less energy than firewood.  For explosives, its not the energy, its how fast it is relaesed.
978594
Acetone       2.13kJ/kg K or  0.51  btu/lb F\nWater, fresh 4.19kJ/kg K or  1.0   btu/lb F\n\nsee also http://www.engineeringtoolbox.com/specific-heat-fluids-d_151.html
677677
One BTU is 252 calories.\n\nThe origin of the BTU is suggested by its name--British Thermal Unit.  It's just like the calorie, but in English units: one BTU is the amount of heat necessary to raise one pound of water by one degree Fahrenheit.
756094
ANSWER: -5645kJ/mol \n\nSHOWING WORK:\nqrxn = - qcalorimeter = - (Ccal . t)calorimeter \nqrxn = - (4.68 kJ/(oC)) . (11.23 oC) = -52.56 kJ\n\n1.397g thymol (1mol thymol/150.14 g thymol) = 0.009305 mol thymol.\n\nHeat of Comb. Thymol =-52.56 kJ / 0.009305mol = -5645 kJ/mol\n\n\n____________________________________________________\n\nEXPLAINATION  (If you care...) :\nWhen measuring the heat flow in a reaction, it is typically carried out in a device known as a calorimeter. The device contains water or other materials of known heat capacity. The walls of the calorimeter are insulated in order to eliminate any exchange of heat with air outside of the device. This means that there is only heat flow between the reaction system and the calorimeter (surroundings). The magnitude of this heat flow must be equal but opposite in sign meaning \n\nqrxn = - qcalorimeter = - (m . c . t)calorimeter                  (1)\n\nHowever, a special device known as a bomb calorimeter is used when gases or high temperatures are involved. Use of a bomb calorimeter involves a different equation because it can be calibrated for the amount of heat absorbed by the water and the metal parts of the calorimeter per oC change. Equation 1 can be rewritten to the following:\n\nqrxn = - qcalorimeter = - (Ccal . t)calorimeter                  (2)\n\nIn your problem we are using a bomb calorimeter; therefore, we will be using equation 2. Plugging in the values for this problem we obtain\n\nqrxn = - (4.68 kJ/(oC)) . (11.23 oC) = -52.56 kJ\n\nThis is the amount of heat for 1.397g of Thymol.  To determine the heat of combustion expressed in kJ/mol of thymol, you have to convert the this mass into mols, then divide the qrxn found above by the mol of thymol.\n\nThus, 1.397g thymol (1mol thymol/150.14 g thymol) = 0.009305 mol thymol.\n\nHeat of Comb. Thymol =-52.56 kJ / 0.009305mol = -5645 kJ/mol
1160164
Depends on the oil :\n\nAs a broad indicator :\n\nLight oil (100SUS / 20 cSt @ 40C)  about 0.820kg/lt\nMedium Oil (500SUS / 300 cSt @ 40C) about 0.850kg/lt\nHeavy Oil (BRIGHTSTOCK / 1000 cSt @ 40C) about 0.900kg/lt\n\nWater around 1kg/lt
152561
All cooking oils (vegetable, coconut, etc) are roughly the same density : ~900 kg/m^3.\n\nFor example, coconut oil is about 925 kg/m^3, olive 920, vegetable b/w 900 and 930. Also, coconut oil viscosity is 28.58 mm^2/s.
1019845
somebody on yahoo answers once asked wt will be the result wen a i month old infant is cooked in bbq sauce
774630
Commercial grade (98 to 99 percent) Tetraphenylcyclopentadienone (or 2,3,4,5-tetraphenylcyclopenta -2,4-dien-1-one) has a melting point of 217 to 220 drgrees C.  The pure recrystalized specimen will usually melt at about 222 degrees using a vacuum melting point tube.
1148552
It can be estimated but without a detailed analysis, an accurate determination can not be made. \n\nNatural gas for instance can contain various contaminates that will lower the heating value and some heavier hydrocarbons that may raise the heating value. \n\nDiesel or gasoline can also have variations depending on the exact composition. Both are multi-component fuels with varying amounts of certain hydrocarbons and as a result the heating value can vary.\n\nLPG (ie. propane, butane or propane/butane mixutures) can vary in composition.  As an example not only is the amount of propane in a propane product different from tank to tank but also the amount of ethane and butane. depending on the degree to which these vary there can be some variation in the heating value. \n\nThe real question is how accurate do you have to be with your answer.
98572
Since vegetable oils are not pure materials, they will have varying molecular weights depending on the specific mixture of a sample of the oil.  I would recommend using Chemfinder.com and free MSDS resources on the internet to gather data.\n\nFor example, Chemfinder.com lists lauric acid as the primary ingredient of coconut oil.  Lauric acid has a molecular weight of 200.  This may be good enough for your purposes.
765230
EER = Q in (BTU/hr) divided by W in (watts)\n\n600/500= 1.2
663598
Food coloring and vegtable oil
418645
heat of combustion = -(enthalpy change for reaction )\n          \n = -(heats of formation of products - reactants)\n \n1 mole of ethanol, when burnt completely, produces 2 moles of CO2 and 3H2O i.e delta H = 2(heat of formation of CO2) + 3(heat of formation of H2O ) \n\n= 2(-394 kJ/mol ) + 3(-286 kJ/mol)\n\n= -1646 kJ/mol\n\nheat of formation of ethanol = -277 kJ/mol\n\nso\n\nheat of combustion = - (-1646 - (-277) )\n                   \n                   = - (-1646 + 277 )\n\n                   = 1369 kJ mol
501191
There is a formula...but this is much easier\n\nhttp://www.onlineconversion.com/temperature.htm
198902
1 ton of diesel fuel contains 39,312,123 BTUs  or, in other words,   \n\ndiesel fuel  is 39,312,123 BTU/ton
1048755
the quality of rapeseed oil used in europe to produce biodiesel is the one with low Erucic acid content