i have 2 tricky math questions?
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1) If they shared the delivery equally, then they would each deliver p number of papers but Erin delivered 20 of Jennifer's, so \nGilbert = p\nErin = p + 20\nJennifer = p - 20\n\nTotal = p + (p + 20) + (p - 20) ---- (1)\n\nSince erin's delivery is 1/2 of the total papers, we have that \n\np + 20 = [p + (p + 20) + (p - 20)]/2 ----- (2)\n\nFrom (2) we have that \n2(p + 20) = p + (p + 20) + (p - 20)\n2p + 40 = p + p + 20 + p - 20\n\nCollect like terms\n40 + 20 - 20 = p + p + p - 2p\n40 = 3p - 2p\n40 = p\np = 40\n\nSo Gilbert delivered 40 papers\n\n\n2) Considering the last sentence - one-fourth of those remaining left, leaving only 12 people in the audience. Since 1/4 left leaving 12, it means that 12 is 3/4 of the audience\n\nIf 3/4 = 12\n4/4 = (4/4 X 12)/(3/4)\n= 4/4 X 12 X 4/3\n= 16\n\nRemember that 1/3 left remaining 16, so 16 was the 2/3 of the audience.\n\nIf 2/3 = 26\n3/3 = (3/3 X 16)/(2/3)\n= 3/3 X 16 X 3/2\n= 24 \n\nAlso, remember that this fugure was just 1/2 of the original audience\nIf 1/2 = 24\n2/2 = (2/2 X 24)/1/2\n= 2/2 X 24 X 2/1\n= 48 which is the total audience\n\nCheck ...... working backwards\nAt ther beginning, there were 48 people in the audience;\nAfter a few minutes, 1/2 left remaining 24\n\nFive minutes later 1/3 of the remaining people left;\n1/3 of 24 is 8, so if 8 left, we have 24 - 8 = 16 people left.\n\nTen minutes later 1/4 of the remaining people left;\n1/4 of 16 is 4, so if 4 left, we have 16 - 4 = 12 people left!
843430
1) 45 divided by 9 = 5\n2) 13 times 6 = 78
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Answer 1:\n(4y + 2)/2 = 21\n4y + 2 = 21*2\n4y + 2 = 42\n4y = 42 - 2\n4y = 40\ny = 40/4\ny = 10\n\nAnswer 2:\na + 4 = 3a - 81\na = 3a - 81 - 4\na = 3a - 85\na - 3a = -85\n-2a = -85\n2a = 85 (The minus signs cancel each other out)\na = 85/2 (or) 42.5\n\nAnswer 3:\n146 = (36y + 2)/4 = 236.5?\nThis means that 146 = 236.5 which is never possible\nThis implies that the equation has no solution.
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That is right. Just put them in a calculater to check. 2/9=0.22222222 and 8/36=0.2222222. Either they are wrong or you misinterpred the question and it was asking something else. The best way to solve a problem like that is to cross multiply. 2/9=8/? turns into 2*?=8*9.
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1.  15\n2.   a.  y=(2x-3)^2 + 4\n      b. (3/2;4)
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(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
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#1. (x-5)(x+1)\n#2. (x-3)(x+2)
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Ok, Victoria, if you're going to ask for help you have to write the questions correctly.  Problem 1 cannot be solved using algebra the way you wrote it, I doubt you can use complex integration or any other advanced tool to solve that one.  Unfortunately, I just spent the last half hour manipulating it before I remembered that little fact.\n\nPut parentheses in.  Had you put the parentheses in the problem would have been trivial.  Kudos to the helpers who were smarter than I in figuring out the constants were in the exponent.  It's not that hard Victoria, especially when you're asking for help.\n\nWrite the question correctly.\n\n\nPS. Irma, you forgot to multiply the 2 from 4=2^2 through the whole parenthetical statement.  The answer is x=4.\n.
586753
1. p1=3.0atm        \n   v1=15mL\n   p2=2.5atm\n   v2=?\n\n(3.0x15)/2.5=18mL\n\n2.t1=(-35+273)=238       \n  v1=75.0mL\n  t2=(25+273)=298\n  v2=?\n\n(298x75.0)/238=93.9mL\n\ni think it's right. i hope it helps.
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go to a math website off yahoo. it should help.
556019
thats 2 questions & i dont understand either of them
120457
1) 4\n2) 15241578750190521
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1.) A - 0.6666666\n2.) C - $12.26\n3.) B - 0.308\n4.) C - 19.87\n5.) A - $.65
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Problem #1:\n2^(3x) = 4\n\nSince you have powers of 2, I would take the log base 2 of both sides:\nlog[2](2^(3x)) = log[2](2²)\n3x = log[2](2²)\n3x = 2\nx = 2/3\n\nProblem #2:\n5/6x = 10\n\nMultiply both sides by x\n5/6 = 10x\n\nDivide both sides by 10:\n5/60 = x\n\nReduce:\nx = 1/12\n\nYour answers are:\n2/3 and 1/12
839453
1) 21.69\n2) 14.10\n3) 7.59
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Problem 1: Find an exponential function of the form f(x)=ba^x+c with y-intercept 2, horizontal asymptote y=-2, that passes through the point P(1,4). \n\nYou find the y-intercept by replacing x with zero, which gives f(x) [which is y on the graph] = 2, so b + c = 2 (since a^0 = 1)\n\nThe horizontal asymptote is y = c, so c = -2.  That means b must be [you figure it out]\nNow it is y = 4a^x - 2.  This must be true when x=1 and y=4.\nSo 4 = [you figure it out; answer deleted due to complaint from below]\n\n\nProb. 3.  What is the amount in the account if $500 is invested for 10 years at the annual rate of 5% compounded continuously? \n  Just plug in the values.\nA = 500 e^(.05 x 10)\n\n[answer deleted]
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1(A) 1 L = 1000 cm^3 therefore 2L = 2000 cm^3\n1(B) 1 L = 1 Kg therefore 2L = 2Kg\n\n*******************\n\n2)\nTwo thirds less than half of what number is five sixths\n(1/2)X - (2/3) = (5/6)\n\nmultiply every term by 6\n3x - 4 = 5\n\nadd 4 to both sides\n3x = 9\nx = 3\n\n*******************\n\n3)\nvolume of a cube = side^3 = 12^3 = 1728 cubic inches\nvolume of square pyramid = (1/3)(b^2)(h)\n where b = 12 and h = 8 (because the total height = 20)\n\n v = (1/3)(144)(8) = 384 cubic inches\n\n total volume = 2112 cubic inches\n\n*******************\n\n4)\nwe do not know the relation ship between the segments, if they form a line, if they form a right triangle, or if they lie on top of each other....\n\nif they form a line segment, where "b" is between "a" and d", then the total meximum length is 12 + c. if they lie on top of each, then they have a minimum distance of |12 - c| (absolute value of 12 - "c")\n\n*******************\n\n5)\nyou would need (1 x 10^3 or 1000) to form 1 meter multiplied by 1000 to form 1 KM\n1000 x 1000 = 1,000,000 or 1 x 10^ 6\n\n*****************\n6)\nx^2 + x  : GCF = x\nx(x + 1)\n\n\n12m^2n^3 + 18mn^2 - 24m^2n^3 \n12m^2n^3 and 24m^2n^3 are like terms\ntherefore\n\n= -12m^2n^3 + 18mn^2\n\nGCF = 6mn^2\n\n6mn^2(-2mn + 3) or 6mn^2(3 - 2mn)\n\n*****************\n\n7)\n-2 2/3w - 1 1/3 = 4 \n\nadd 1 1/3 to both sides\n\n-2 2/3w = 5 1/3\n\n= -(8/3)w = (16/3)\n\nmultiply both sides by -(3/8)\n\nw = -2