what is the force generated by the piston?
967963
Either air pressure, or fluid pressure on a fluid present in the cylinder.
806769
Since mechanical advantage is the factor by which a mechanism multiplies the force put into it, a mech. ad. of 3 means that whatever force is put into it, the output force will be 3 times that. For your problem:\n\noutput force = 3 * input force = 3*5 = 15 N\n\nI'm sorry, but I don't have an answer for the second part of your question. You might want to submit it as a separate question though, it will probably get some answers that way.\n\nI hope this helps!
762826
Hydraulic machines work on Pascals principle.\nAccording to it the pressure exerted on a confined fluid is tranmitted equally and undiminshed in all directions.\nSo we can apply a small force on a large area and that pressure is transmitted throughout the fluid.\nThis pressure can be used to lift relatively large load(or force) by making it act on a small area of cross-section on the platform of the machine.\nPascals Principle is : P1=P2\nor\nF1/A1=F2/A2
1070754
First, the spring constant (I suppose g=10m/sec^2):\nf=k.d\n0.3 x 10=k x 0.02  so  k = 150 N/m\nNow, the problem is like that we have a 2 Kg block hung from the spring and pull it down 2 cm then release it. The total force applied to block would be:\nf=Mg-kx=20-150x (x = distance of block from its final point, 2 cm above its first place) so the acceleration 'a' is:\na=10-75x   so applying the second law:\nx''=10-75x  so the movement equation is  x''+75x-10=0\nSolving this differential equation gives sin function for x as the general form x=a.Cos(w.t+c). By substitution we get:\nw^2=75 so w=5.sqrt(3)  rad/sec\n(divide it by 2*pi if you like to have the frequency in Hz)\nT=2*pi/w ~ 0.73 sec
269311
assuming that force is applied in the same direction that displacement....\nwork = force * displacement * cos(angle between force and displacement)\nwork = (10N)*(5.0m)*cos(0)\nwork = 50 Joule
805281
OK, first we need a formula for the motion, which, if it's simple harmonic motion is\nf(x) = Asin(kx)\nwhere A is 1.8*10^-4\nand k = 2000*2*pi\nSo f(x) = 1.8*10^-4*sin(4000*pi*x)\n\nTo compute the maximum force, we need the accelleration f''(x)\nf'(x) = 1.8*10^-4*(cos(4000*pi*x))*4000*pi, or \n1.8*4*pi*10^-1*cos(4000*pi*x)\n\nf''(x) = 1.8*4*pi/10*(-sin(4000*pi*x))*4000*pi\nor\n1.8*16*pi^2*100*(-sin(4000*pi*x))\nthe MAXIMUM acceleration is then 1.8*16*pi^2*100.\nThis is because you can find a value for x where -sin(4000*pi*x) is 1.\n\nUsing F=ma, the maximum force is 50 *1.8*16*pi^2*100 KG m/s^2, or approximately 1.42*10^6 KG m/s^2
205454
well i have no clue what your units are. but torque is force x distance. and if the drum is 12 inches in diameter, its 6 in radius. so the distance from pivot point is 6 inches. and the force would be um 200lbs? i guess. if that could be considered a force. and then multiply. \n\ni can do it in SI units for you though. 1 in = 2.54 cm = 0.0254m. and 1lb = 2.2kg. \nso 6 in = 15.24cm = 0.1524m. and 200lb = 440kg. F = 9.8*440 which is around 4180N. so 4180N * 0.1524m
770512
The total force on the block is mg sin (theta). The mg cos (theta) and force normal cancel out. Since there is no friction, the only force, again, is only mg sin (theta). \n\nThis is obvious if you consider that there is a force mg, and break it down into components, the solution should seem obvious.
121693
cmon...dont u know basic physics...just calculate the resultant of these 2 forces\nanswer= [(132)^2 + (181)^2]^1/2\nif this makes sense!!
891480
Calculate the k value for the spring.  The stone exerts a force of 8*9.8 = 78.4 N and a compression of 9 cm is\n78.4/.09 = 871 N/m. (Keep it in the MKS system ☺)\n\nWhen the spring is pushed down another 30 cm its total deflection is 39 cm and it's total potential energy is \nkx²/2 = 871(.39)²/2 = 132.5 J\n\nThe stone acquires 132.5 J of gravitational potential energy when released.\n\nSince gravitational potential is mgh, then\n8*9.8*h = 132.5 or h = 1.69meters\n\n\nDoug
964900
If i understand your scenario, the force is pushing downward on the block.  The horizontal component of the force is 15 N times cosine of 40 degrees.  The vertical component of the force is 15 N times sine of 40 degrees.  However, there is also the force of gravity, which is (3.5 kg * 9.8 m/s2)  (units are N, like the other forces).  So if you add the force of gravity to the vertical component, you have the total downward force.  Multiply this by the coeficient of friction, and you have the force of friction.  \n\nThe force of friction is directed against the direction of motion.  Subtract the frictional force from the horizontal component, and you have the total horizontal force.  Divide the horizontal force by the mass and you should get the acceleration.\n\nfriction force = [(15*sine 40)+(3.5*9.8)]*.25\nacceleration = [(15*cosine 40)-friction force]/3.5
658774
I would think you would use the force created by compressing the spring.\n\nThis force is given by the equation:\n\nF = k(Li - Lc)\n\nWhere:\nF = force\nk = spring constant\nLi = uncompressed spring length\nLc = compressed spring length\n\nThe below link is for a calculator for this force.\n\nhttp://www.efunda.com/DesignStandards/springs/calc_comp_Fstress.cfm
627120
a)\ncross-sectional of the small piston: A1 = 25 cm²\ncross-sectional of the large piston: A2 = 400 cm²\nMass on the small piston: m1 = ?\nMass on the large piston: m2 = 1200 kg\n\nby Pascal's Principle:\nF1/A1 = F2/A2\nm1*g/A1 = m2*g/A2\nm1 = m2*(A1/A2)\nm1 = 1200 kg (25 cm²/400 cm²) = 75 kg\n\n\nb)\nwhen a person enter into the car, the person on the small piston will be elevated a heigh h1 over initial level and the car is going down a lenght h2, and height difference in the fluid levels in the pistons is H = h1 + h2.\nMass on the small piston: m1 = 75 kg\nMass on the large piston: m2 = 1290 kg\n\npressure by 75 kg person + hydrostatic pressure by column of fluid = pressure by (90 kg person and 1200 kg car)\nm1*g*A1 + d*g*H = m2*g*A2\nH = (m2*A2 - m1*A1)/d\nH = {(1290 kg * 0.04 m²) - (75 kg * 0.0025 m²)}/(720 kg/m³)\nH = 0.0714 m = 7.14 cm\n\n\nc)\nvolume displaces is the same in both pistons:\nA1*h1 = A2*h2\nA1*(H - h2) = A2*h2\nA1*H = h2*(A1 + A2)\nh2 = H*{A1/(A1+A2)}\nh2 = 7.14 cm (25 cm²/425 cm²)\nh2 = 0.42 cm = 4.2 mm
643953
depends on the direction of the force
505249
no.its the force produced due to the movement of other particles(electrons).so..
543978
Frictional force, f = uR\n\nwhere u - frictional constant\n(it is actually "miu", but I can't typr it out.)\n\nand R - the normal/reaction force (which is the reaction caused by the action of the object's weight.)
963774
Use the fact that PV/T = a constant, we find the constant by pluging in the values we have, T = 20C, but we must convert that to K first so 20C = (273 + 20) = 293K.  And 1 atm should be converted to physicall units of Nt/m^2 for an easier solution.  1 Atm = 101325 Nt/m^2.    So our constant is (101325)(4.5)/293 = 1.336 x 10^7 so now you have one equation as\n\nPV/T = 1.336 x 10^7 setting T = 260C or 533K gives\n1)  PV = 7.121 x 10^10\n\nThe next equation that we need is the force on the cylinder end given the pressure, which would be\n\n2)  .01P = F\n\nThe spring will stretch a distance 3)  d = F / (2.00 x 10^3)  \n\nThe volume changes by  4)  V = 4.5 + d * .010   \n\nThis gives you 4 equations which you can now solve to find the solution for V, d, P and F