Does anybody know how to do well in Add Maths chapter 9 ( differentiation)?
960976
DO NOT study them as a parrot, but try to understand what you are doing!
802534
I'll help set it up\nbut, honesty, it isn't that hard and the only way you'll learn it is to do some on your own so that at test time, you can do it yourself...\nI'll start your homework....you finish....\n\nthe essential idea is to complete the square for each variable\nfirst reorder the terms \nx^2 - 2x +____  - 9y^2 - 18y + ___ = 9\nfactor out where possible\nx^2 - 2x + ___ - 9 (y^2  + 2y + ___) = 9\ncomplete the sq for both terms\nin case you were wondering why I put a "space" for the constant term in the working\nx^2 - 2x + 1  - 9(y^2 +2y + 1) = 9 + 1 + (-9)\nfactor\n(x - 1)^2 - 9(y+1)^2 = 1\n\nOK?????\nyou take it from here...it's almost in standard form
846189
practice xtra hard 4 commerce related topics.nd 4 others like calculus  ur formulae shud alwz b clear nd on ur tips.nd 4 limits reason out nd think.and wat else practice nd practice..and thats da key 2 100% mks in maths.dis is my experince.believe me.
169490
Step 1. Study all the formulas in your textbook. Don't get discouraged if you don't remember them all at first. The more problems you solve, and refer to the formulas while doing so, the better you will remember.\nStep 2. Many formulas are given in the general cases, say for a general n, for a general functiion f(x)...find out for yourself what it means, by reverting to the most particular examples you can find. If you have to integrate x^n, try integrating first, say x itself. The particular examples give you often better understanding.\nStep 3. Learn about the very definition of integral. Calculate a few integrals from the definition, by using sums, as shown in your calculus books. To do so, you would need to review some of your highschool material, such as how to sum n consecutive integers, squares of integers or cubes of integers. This step is harder for many students that the first 2, but once you have completed that step successfully, you will gain a feel for the integral and will understand many of the formulas your textbooks are using, might be even able to prove some yourself.\nThose three steps will make you exceptionally good in all but the most esoteric kind of integration.\nFor understanding about the integral, you may refer to the most thorough calculus book of the 40's, Fundamentals of Mathematical Analysis. It explains both the theory and the practice. It is considered outdated for math majors, but for science major it is still good, in my opinion.\nHope that helps
1128820
You won't find anything on the Internet that it explains things more clearly than your math book.  The only way to get help beyond that would be to ask questions directly to a teacher or tutor.\n\nYou probably should have been asking those questions sooner than the night before the final exam.
575056
The first time I tool Calculus in college I flunked (then again I hardly went to class and tried to do my homework an hour before it was due)\nNeedless to say I had to take the course again.\nNext time around this is what I did:\n1. Go to class everyday and take good notes.\n2. Do your homework as soon as you can and dont limit yourself in time. Take as much time as you need to be able to finish the homework (I would do this while drinking Mountain Dew and music helped me)\n3. If you don't understand something from the homework ask the teacher. Remember they are there to teach you.\n4. Look over your notes to study.
494062
I do hope you are scoring around 80 % now and want to score 100%. If you are at still lower level then lot of efforts is needed,\nPRACTISE MAKES PERFECT .\nYou have to solve all the problems in each chapter . and when ever you get spare time mentally refresh the probelems and answers.\nOnce one chapter is over borrow mathematics books prescribed by  other schools for yourclass and solve problems given there for the same chapter.\nConstant practise would familiarise you to the technique of problem solving and you would find it a childs play to solve any problem in less than half the time others take. \nYou can review your answers too. best of luck
950537
Sumi, I think 9th Std is where you get into your logics.. The platform is build up in that class.\n\nfor my 10th almost 20% of the 9th portion came again. Even it'll be helpful for you in your future classes..\n\nThe integration.. algebra.. alfa.. beta.. and all mess.. \n\nOH god !.. Njoy you studies dude.. dn't miss the little things..
229463
I used this site when I was studying, its very helpful\n\nhttp://www.bbc.co.uk/schools/gcsebitesize/maths/
62135
Sure.  Let's start with the function\n\nf(x,y,z) = 2x + 3y + 4z + xyz\n\nSo let's say you have to differentiate this function with respect to x, y and z.  In order to do this, we have to differentiate each variable, one at a time.  While we differentiate one, we hold the others constant; in other words, while differentiating x, we will pretend like y and z are numbers or constants, like a, b or c, or 1, 2 or 3.\n\n1. The partial derivative of f with respect to x ("partial f/partial x"):\n\nThis is just like df/dx, if y and z were just regular numbers.  So quit thinking of y and z as variables for a second; x is the only variable we care about.  So then\n\npart(f)/part(x) = 2 + yz\n\nSee what happened?  Taking one element at a time,\n\nd/dx(2x) = 2\n\nd/dx(3y) = 0 (because it's a constant!  and what is the derivative of a constant number?  0!)\n\nd/dx(4z) = 0 (same principle)\n\nd/dx(xyz) = d/dx(yz*x) = yz (because y and z are just constants tacked on to the front of x)\n\nadd them together: partial f/partial x = 2 + yz\n\n2. The derivative of f with respect to y ("partial f/partial) is\n\n3 + xz\n\n3. And, finally, partial f/partial z = 4 + xy\n\nYou can do this with more complex equations, too.  Just remember: only consider one variable at a time.  It's just like normal derivation after that.\n\nf = xyz^2 +5x^5*y + x^2*y^2*z^2\n\npart f/part x = yz^2 +25x^4*y +2x*y^2*z^2\n\npart f/part y = xz^2 + 5x^5 + 2y*x^2*z^2\n\npart f/part z = 2xyz + 2z*x^2*y^2\n\nHope that helps!  See the article below for more explanation, other examples.  Chuck Norris!
533429
well..write them down ...try to derive them (if their derivation is simple enough or else skip it )......\n\ntry to connect each formula with other one with a hint ....a small hint will help u to recollect other one ....\n\ntry to do at least one problem based on each formula
752772
You need to use the chain rule a couple of times.\nHow do you differentiate (something)^2 ? Make it 2*something. Then multiply by (something) differentiated.\nIn this case, (sin 3x)^2 differentiates to 2(sin 3x) * (sin 3x differentiated).\nNow, how do you differentiate sin(something)? Make it cos(something), then multiply by (something) differentiated.\nSo sin 3x differentiates to cos 3x * 3.\nOverall, you get 2 sin 3x cos 3x * 3 = 6 sin 3x cos 3x.
831486
Differentiate both sides, we have \n\ndy =  (1/x)dx + (1 + tan^2(y))/tany dy\n\ntherefore\n(1 - (1 + tan^2(y))/tany)dy=(1/x)dx,\n\ni.e.\n\ndy/dx=tany/(x(tany - tan^2- 1)).
826297
the best way is memorization... some may say otherwise.  It will take a while, but multiplication is KEY to mathematics... if you dont get your mult tables, it will make math more tedious in the long run.  (trust me, I am a math teacher).  Start by writing your times tables over and over again.  Then either make or buy some flashcards.  Also, Get your parents and friends to quiz you.  \n\nGood luck!
595778
Study hard...and do the homework, believe me, I'm not just saying this, it really helps. I could have passed Calc II if I had simply done the homework. Even though it doesn't count toward your grade, it helps you make sure you're really learning the material!
183373
Try the inside cover of your Calculus book - it usually summarizes the rules for derivatives and some key integrals.
986880
Do you want how to derive them or what the derivatives are?\n\nF(x)=a^x  ---> f'(x) = a^x (ln a)\n\nf(x) = sin x ---> f'(x) = cos x\n         cos x      --->           -sin x\n         tan x       ---->           sec^2 (x)\n         sec x      ---->           sec x tan x\n         csc x      ---->           - csc x cot x\n         cot x       ---->            - csc^2 (x)