Help figuring this out?
960995
I'm going to assume that you "forgot" to include parentheses.\n3/(y^2 -3y +2) + 7/(y^2 -1)\nFactor each denominator.\ny^2 - 3y + 2 = (y-2)(y-1)\ny^2 - 1 = (y-1)(y+1)\nYour common denominator (CD) will be (y-2)(y-1)(y+1)\nThe first term is missing the (y+1) part, so you need to multiply the numerator and denominator by (y+1)\n[3/(y^2 -3y +2)] (y+1)/(y+1) = 3(y+1)/[(y-2)(y-1)(y+1)]\n= (3y +3)/[(y-2)(y-1)(y+1)]\nThe second term is missing the (y-2) part.\n7/(y^2 -1) = 7(y-2)/[(y-2)(y-1)(y+1)]\n= (7y-14)/[(y-2)(y-1)(y+1)]\nWe now have a common denominator, so we can add the numerators.\n(3y +3)/[(y-2)(y-1)(y+1)] + (7y-14)/[(y-2)(y-1)(y+1)]\n= (3y + 3 + 7y - 14)/[(y-2)(y-1)(y+1)]\n= (10y -11)/[(y-2)(y-1)(y+1)]
438692
Can't figure this one out.
1158895
not sure, maybe B3 & B4?
469609
very unclear question
233014
U R RIGHTT..HOW DID YA GET IT..PLZ CAN YA EXPLAIN..I'VE BEEN TRYING THIS PROBLEM FROM A LONGTIME.EVEN DE CALCULATOR SAYS ITZ "4"..I KNOW DE CALCULATORS WRONG TOO..PLZZ DO EXPLAIN IT TO ME ASAP
762847
please explain the question.
487526
Sounds like a Math/Science type question to me. Why are you posting it here?\n\nBesides, I have the the slightest idea.
952492
Dont quite get the question?
987044
Sorry, you have to check your question first, bec I understand none. I would help you very much but how? you tell me please. thanks
947638
Your question is not clear - please explain.
1146358
I’m not seeing how this is solvable.  I’m getting two possible answers.\n\nBut here’s how you should work the problem.  \n\nFirst of all, I think you pretty much have to assume that the x,y < 10.\n\nSo we know that Bill can’t tell what his two numbers are just by looking at the product.  As it turns out, there are very few products that allow this to happen: they are 12,16,18,24,36.  So you factor out all the number pairs that would make those products, and the sums are 7,8 (twice), 9, 10(twice), 11(twice), 12, and 13.\n\nSo we know that Albert is seeing one of those sums.  If he sees 7, then he knows that the only way for his numbers to add up to 7, and multiply up to either 12, 16, 18, 24, or 36 is for the numbers to be 3 and 4.  But he says nothing.  Therefore, he isn’t seeing 7.  Neither is he seeing 9, 12 or 13, for the same reason.  So, now we know the sum must be either 8,10, or 11.  And now Bill knows that.\n\nSo, if Bill were seeing 12 as the product, he would know that the numbers were 2 and 6, since they add up to 8.  But he says nothing, so he’s not seeing 12.  Likewise, if he were seeing 18, he would know that the numbers have to be 2 and 9.  But he doesn’t, so he’s not seeing 18, and he can’t be seeing 36 either.  So that means he must be seeing either 16 or 24.\n\nAnd now Albert knows this, so either Albert is seeing a sum of 8, and knows that the numbers are 4 and 4, or he’s seeing 11, and the numbers are 3 and 8.  I just don’t know how to eliminate either of those options.
85739
somebody help me with this! i think i just lost point for trying to understand the question.
541678
soorrry i dont know if i can help you there its either i have no idea or its too confusing.....sorry but good luck trying to find and answer :)
679924
You need to explain this better, I can't figure out what the question is.
489911
Not sure, wish I could help.
761302
no idea, if you come across the answer to it please share it with me
534106
Whats the question???