alright.. I need to know the steps to this.. and discover the rule. because I forgot. :b?
958347
The top 2 terms have a in common; factor it out by Distributive Property: a(a+4)\n\nThe bottom 2 terms have b in common, do the same: b(a+4)\n\nNow as long as a doesn't equal -4, the (a+4) on top cancels the (a+4) on bottom, leaving a/b
614837
I already posted this solution (or how to get it).  Do a search of yahoo answers....
746165
Remember the fomula...\n\ny = mx + b\n\nm = Slope\n\nb = Y-intercept\n\nx and y = points\n\nSo plug everything in...\n\n1 = 4(2) + b\nMulitply\n1 = 8 + b\nSubtract 8 on each side\n-7 = b\n\ny = 4x - 7
357680
I'm trying 2 figure out how 2 chick this question.
1154468
make a common denominator\n\na/b - c/d = a*d/b*d - c*b/d*b = (a*d-c*b)/b*d
1094108
Use a calculator and raise it to the 1/3 power.\nDon't try to do it by hand...
157576
In the textbook you got the question out of. Read it! LOL
605811
As Lauren said, it's 1/x.\n\nMemorize this. It will be very useful.
917250
I'm going off memory here so be sure to check this.  I think the formula is the same, but the structure may be different.  Just trying to point you in the right direction.
1166133
Multiply both sides by R+r\nI(R+r) = E\nDistribute the I\nIR + Rr = E\nSubtract IR form each side\nRr = E - IR\nDivide both sides by R\nr = (E-IR)/R
1069547
I can work the 'dr' bit out but I'm lost on the 'b/c' bit? \nPlease elaborate I'm puzzled!
549149
There is a concept called "Rule of ten", which you can find explained in:\n1) your textbook\n2) this same site, by using the Search Box\n3) many other places
256104
Read Newton's 3rd law of motion.\nAlso, use F=ma to figure out your acceleration.
443025
(tanA + tanB + tanC - tanAtanBtanC) / (1 - tabAtabB - tabBtanC - tanCtanA)\ngets nasty fast, so remember these rules\ntanX = sinX / cosX\nsin(X+Y) = sinXcosY + cosXsinY\ncos(X+Y) = cosXcosY - sinXsinY\n\n(tanA + tanB + tanC - tanAtanBtanC) / (1 - tabAtabB - tabBtanC - tanCtanA)\n=[cosAcosBcosC * (tanA + tanB + tanC - tanAtanBtanC)] / [(1 - tabAtabB - tabBtanC - tanCtanA) * cosAcosBcosC]\n=[sinAcosBcosC + sinBcosAcosC + sinCcosAcosB - sinAsinBsinC] / [cosAcosBcosC - sinAsinBcosC - sinBsinCcosA - sinCsinAcosB]\n=[(sinAcosC + cosAsinC)cosB + sinB(cosAcosC - sinAsinC)] / \n[cosC(cosAcosB - sinAsinB) - sinC(sinAcosB + cosAsinB)]\n=[sin(A+C)cosB + sinBcos(A+C)] / [cosCcos(A+B) - sinCsin(A+B)]\n=sin(A+B+C) / cos(A+B+C)\n=tan(A+B+C)
99006
This link should help walk you through it, step by step....
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
228792
will any answerer plz tell me what exactly is the SIX AND OUT rule is??