I can never figure this out, but I know who to the rest...(x,y)?
955256
There are 2 ways.\n1st - Substitution\n In the first equation solve for x.\n x=4y+6\nIn the second equation substitute 4y+6 for x.\n5(4y+6)+3y = -16\n23y=-46\ny=-2 No use -2 for y in either equation and ckeck the other\nwith x and y. Using the first -x+4(-2)=-6\nso x=-2\nChecking  5(-2)+3(-2)=-10-6=-16   OK\n\n2nd  by adding (or subtracting) simultanious equations\n\nMultiply the first thru by 5\n-5x + 20y=-20  and add this equation to the second.\nThis gives 23y=-46 so y=-2 and you can do the rest.\n\nTry the last 2 yourself befor reading on so you get the\nmental exercise of doing. Reading the answer is not\nthe same as doing it\n 2nd pair of equations - Subtract the second equation from the \nfirst to get rid of the y.  -5x+x=23-3 ==>  -4x=20 \nx=-5.   -(-5)+y=3  ==> y=-2\nChecking:  -5(-5)+(-2)=25-2=23  OK\n\n3rd pair\n  Add equations to eliminate x\n-2y+5y=36 ==>  3y=-12 ==> y=-4\nx-2(-4)=12 ==> x=4\nChecking: -4 +5(-4)=-24  OK
781527
y=mx+b\n\ndid you get any actual integers in the question>
741552
You have got it right.\nthe answer is\n\nf(x) = 3x
585937
Rene Descartes (the Cartesian coordinate plane plus many other contributions)\n\nPierre de Fermat\n\nBlaise Pascal\n\nLook them up. That can get you started. Personally, I'm going to bed.
560506
that works... so does this:\n\n-2 x -1 x 1 x 2 x 3 = 12\n\n-2*-1=2\n2*1=2\n2*2=4\n4*3=12
909284
((1/x) + (1/y)) / ((1/x) - (1/y))\n\n((y + x)/xy) / ((y - x)/xy)\n\n((y + x)/xy) * ((xy)/(y - x))\n\n(xy(y + x))/(xy(y - x))\n\n(y + x)/(y - x) = (x + y)/(-x + y) = (x + y)/(-(x - y)) = -(x + y)/(x - y)
239035
Independence....\n\nAnd what =0\n\nBig I
502159
?\n\n(x-coordinate, y-coordinate)\n(0,0)\n(1,3)\n(2,6)\n(3,9)\n\nCos y-coordinate is 3 times of x-coordinate?
846745
Typically you know three out of the four variables and solve for the last variable.\n\nBut sometimes they get tricky by giving you only two but one of the remaining variable is related to one or two of the given variables.
658708
this one isn't possible..wait...i think i got it....\n\nxa+yb+xz+yz\nxa+yb+z(x+y)\n\nif a typo, and a = b then:\nxa+ya+z(x+y)\na(x+y)+z(x+y)\n(a+z)(x+y)\n\notherwise, not possible unless, use the math trick:\nxa+yb+z(x+y)+ya-ya+xb-xb\nxa+xb+ya+yb+z(x+y)-xb-ya\n(x+y)(a+b)+z(x+y)-xb-ya\n(x+y)(a+b+z)-xb-ya
223041
uh..... no. Unless I am missing something, you substitute the 3 for 'x' and the 2 for 'y' and get 3+(3 x 2) = 3 + 6 = 9
1146358
I’m not seeing how this is solvable.  I’m getting two possible answers.\n\nBut here’s how you should work the problem.  \n\nFirst of all, I think you pretty much have to assume that the x,y < 10.\n\nSo we know that Bill can’t tell what his two numbers are just by looking at the product.  As it turns out, there are very few products that allow this to happen: they are 12,16,18,24,36.  So you factor out all the number pairs that would make those products, and the sums are 7,8 (twice), 9, 10(twice), 11(twice), 12, and 13.\n\nSo we know that Albert is seeing one of those sums.  If he sees 7, then he knows that the only way for his numbers to add up to 7, and multiply up to either 12, 16, 18, 24, or 36 is for the numbers to be 3 and 4.  But he says nothing.  Therefore, he isn’t seeing 7.  Neither is he seeing 9, 12 or 13, for the same reason.  So, now we know the sum must be either 8,10, or 11.  And now Bill knows that.\n\nSo, if Bill were seeing 12 as the product, he would know that the numbers were 2 and 6, since they add up to 8.  But he says nothing, so he’s not seeing 12.  Likewise, if he were seeing 18, he would know that the numbers have to be 2 and 9.  But he doesn’t, so he’s not seeing 18, and he can’t be seeing 36 either.  So that means he must be seeing either 16 or 24.\n\nAnd now Albert knows this, so either Albert is seeing a sum of 8, and knows that the numbers are 4 and 4, or he’s seeing 11, and the numbers are 3 and 8.  I just don’t know how to eliminate either of those options.
405561
X  = Nothing \nor X  = 24th letter of the English Alphabet.\n\nAm I too clever or do I get the 10 points for being a smart ass?
738586
Friend, \n            let the number be y\n                        3*y=9\n                            y=9/3\n                            y=3\n           So the number is 3
158047
Pretty slick, RED\n\nYou came on pretending that "someone else" had a problem and even gave out a wrong answer on purpose.  Clever!\n\nI can see through that, you just wanted people to give you the right answer without giving you the whole "Do your own homework" speech.\n\nNice! Score one for you.  Unless, of course, I am giving waaaay too much credit for such an ingenious plan.  In which case, x=2, not 24.
363348
Are we solving for x?
781563
y>(12-3x)/4\n\nSteps:\n\nmultiply the 12 on both sides\n3x+4y>12\n\nminus the 3x isolating the y variable\n4y>12-3x\n\ndivide by 4 on both sides to get y by itself\ny>(12-3x)/4 or...\n\nsimplified 3-(3x/4)