What direction is the pilot flying and what is the speed relative to the ground?
962720
Lots of unnecessary complications here.\n\nAirspeed is the hypotenuse. 20.4 is the side opposite the angle we are looking for.\n\nThe heading, east of north, must be at angle sin^-1(20.4/241).\n\nSpeed relative to the ground is the third side of the triangle, and is \n\nsqrt(241^2 - 20.4^2)\n\nZidane has got the angles all wrong. The wind is from the east. We want to fly due north. That's where the right angle is. 241 is the hypotenuse of the triangle. The wind serves to make the ground speed less than 241, not greater.
817165
Very simply:\n\nIf he keeps flying at the same speed, he will be moving at his flight speed plus the speed of the bus.\n\nIf he stops flying, he will fall to the floor (or perhaps land a bit more gracefully than that), and be moving only at the speed of the bus (his flight speed has gone to zero).\n\nIf you jump in a bus, you continue to move forward at the same rate as when you were standing, so you land in the same spot on the floor.  Of course, if the bus changes velocity while you are in midair, your motion will be different from its and you will not be in the same spot when you land.\n\nThe same goes for the rotation of the earth... the circumference of the earth is about 24,000 miles at the equator.  Hence, at the equator, it is moving at about 1467 ft/sec.  If you jumped and stayed in midair for 1 second, the earth would travel 1467', but you are travelling at the same rate and you would land in the same spot you jumped from.
1163276
The angle the vehicle was traveling
728806
flying faster than the gravitational pull that is pulling you back
149116
Since the plane is horizontal normal force cancel weight so no force in vertical direction. No friction so no extra force in the horizontal direction.\nF = ma System: wagon\nFn + Fg + F1 + F2 = ma   \n(these are all vectors, except the m, but I can't type the arrow)\nF1 + F2 = ma (Fn + Fg = 0) (again, vectors)\nChoose the 45N as positive direction\n45 - 30 = 8a\n15 = 8a\na = 1.875 m/s^2 in the 45N force direction
627683
fly as the sky and rain
403944
the answer is blowing in the wind
446591
1)X=V1t+1/2gt^2\nat the interval between getting to the highest point and being dropped back to the first place is half of the full time = 2 seconds\nV1 at the highest point = 0\nX=displacement\nX=0+1/2*9.8*4=19.6 m \n2)V2=V1+gt\nV2 = velocity of landing\nV1 = velocity at highest point\nV2 = 0 + 9.8 * 2 = 19.6 m/sec
1147435
(tangent 30 degrees= 1km/x) - (tangent 60 degrees= 1km/y)\n\nSolve for the two variables, then subtract y from x.  That is how far the plane traveled in 10 seconds.
441442
you have your units wrong, do you mean 5m/s or 5m/s^2 and you mean 20m from the ground?\nIf acc=5 when height=20 speed= 14.14 in upwards direction (using 2ax=v^2-u^2)\nIf initial speed is therefore -14.14m/s then at t=1 speed=-4.34m/s so it is still going upwards\nt=2 speed= 5.45m/s it is now going down. Both last results worked out using v=u + at\n(Sorry I assumed you meant 5m/s^2 straight up, you need the angle at which it accelerates aswell)
38384
720 mph = 12 miles/min = 1 mile every 5 seconds.\n\nSo the jet is traveling at the speed of sound. The plane meets the sound half way 4 1/4 miles.\n\nNote: If he were flying away from the lightning, the sound would never catch him.
359184
There is no wind.  The conveyor belt isn't moving air to cause lift.  Just because the conveyor belt is moving the plane's wheels doesn't mean it will fly..   Point the plane the other way and it will.
401679
Lift. The shape of airplane wings (curved on top, flat on bottom) allows air to pass over them at different speeds, creating a pressure gradient. Higher pressure is built up underneath the wing, allowing for lift to carry it off the ground. For this to work, the airplane must maintain a minimum rotation speed to get off the ground (in a Cessna 150, that speed is about 90mph). Once in the air, the plane can reduce its speed and often glide, however when an aircraft looses too much speed, it looses lift and stalls out.
11427
With a small amount of gas and a light pilot they can do that distance in about 2.7 seconds.  With a normal fuel load and 160 lb pilot they can do it in anout 2.9-3.0 seconds.
1046911
it will fall straight down , but appear to fall at an angle if observed from the plane
836862
distancetravelled by the bird=2000m\ntime taken=187 1/2 sec\n                 =375/2 sec\nspeed is in the ratio of 1:2\ndividing the time in the ratio of 1:2\ntime to=375/2(2/3)=125 sec\nspeed=distane/time=1000/125=8 m/sec\nspeed in thefro direction=16m/sec\ncheck\n1000/8+1000/16=3000/16\n=187.5 sec checks
1170153
hahaha, good one. An airplane isn't moving as fast as time is.