How do you do Point Slope, i need explanation bad!!?
963751
find the first derivative for the curve, and then substitute the x coordinate for the slope at that point.\n\nfor example, for the graph y = x^2, the first derivative is 2x. to find the slope at where x = 1, sub x = 1 into 2x and the slope at that point is 2.\n\nalternatively, draw a tangent to the point where u want to find the point slope and the slope of the tangent is the point slope. note that this method's accuracy depends on how accurately you draw your tangent
927388
y=mx+b\n\njust rearrange it so you get b as your intercept..\n\nin this case y=-1/4x +3, so the slope is -1/4, and the intercept is 3
155791
Here is a good page describing slope.\n\nhttp://mathforum.org/cgraph/cslope/slope.html
1121252
slope = m\nperpendicular slope = (-1)/m\n\nslope = (y2-y1)/(x2-x1)\nslope = (2-5)/(4-2)\nslope = -3/2\n\nperpendicular slope = 2/3
892240
Slope is Y2 -Y1 divided by X2 - X1\n\nIn your example, Y2= 12\n                            Y2= -7\n                             X2= 0\n                            X1=-2\nSo... \n(12-(-7)) / (0-(-2))= 19 / 2 = 9.5\n\nThe slope of the line is 9.5
1038364
Formula for linear slope is y=mx+b\n5y=10x-10\nDivide the 10x-10 and 5y  by 5 to get\ny=2x-2\n-21+7y=14\nAdd -21 to both sides to get\n7y=35 Hence y=5\nx=-5 The slope is undefined. IF you graph the line and take two coordinates and use the formulas (y2-y1)/(x2-x1) you get 0 at the bottom. Anything divided by 0 is undefined.\nY-5=2 is add the 5 to both sides to get y=7
911563
Here's 2 examples:\n\n1.) Given point (2,2) and (3,3), find the function.\nStep 1: Find the slope.\nSlope = rise/run = (y2 - y1) / (x2 - x1) \n(3 - 2) / (3 - 2) = 1/1 = 1.\n\nStep 2: Given the slope, find the y intercept by trying to find a point (0, y) that fits the 2 points above, and the slope given.\nUse the slope formula: rise / run = 1\n(2 - y) / (2 - 0) = 1 = (2 - y) / 2 \n2 = 2 - y\n-y = 0\ny = 0\ny intercept = 0, 0\n\nStep 3: Once you have the slope, you can write it in slope intercept form:\ny = mx + b \nm = slope, b = y intercept\ny = 1x + 0, or y = x.\n\n2.) (a harder one) Given point (1,4) and (-3, 2), find the function.\nStep 1: Find the slope.\nm = rise/run = (y2 - y1) / (x2 - x1) \n(4 - 2) / (1 - -3) = 2/4 = 1/2 = .5\n\nStep 2: Given the slope, find the y intercept at (0, y)\nm = rise / run = 1/2\n(4 - y) / (1 - 0) = 1/2 = (4 - y) / 1 \n4 - y = 1/2\n-y = -3.5\ny = 3.5\ny intercept = 0, 3.5\n\nStep 3: Write it in slope intercept form:\ny = mx + b \ny = .5x + 3.5
305322
First you need to solve for y... y = 4/3x-4\nThen by using the Y = MX+B formula you will see M = 4/3 which is your slope. B = -4 which is your Y-Intercept. Plot your Y-Intercept at (0,-4) and then plot the next according to your slope, which is Rise/Run. so from (0,-4) you will go up 4 and over 3. you should end up at (3,0). after that all you have to do is connect the dots....
930136
Use the slope formula to get the slope.  All parallel lines will have the same slope.\n\nm = (y2-y1) / (x2-x1)\n\nSo, for your points you have the following:\n\nm = (2-1) / (4-15) = 1/(-11) = -1/11\n\nTherefore all lines parallel to this line will also have a slope of -1/11.\n\nHope that helped!\n\n~ ♥ ~
533058
Point slope form:\n\ny-(-3)=(1/2)(x-5)
952901
since the y intercept is 1, put a mark one tick above the origin, then since the slope is -1, put a mark down one and to the right of that one.  then do that a few times to make a line.
779591
well, you have to set up two questions in point slope form. (ie. equation for the line)\nso for your first question:\n\ny-9 = 2(x-5)\ny-3 = 2(x-r)\n\nso simpliy to be\n\ny = 2x - 10 + 9\ny = 2x - 2r + 3\n\nand simplify again to be\n\ny = 2x - 1\ny = 2x - 2r + 3\n\nand from here.. i'm drawing a blank. but that should help.. maybe?
509875
We use point slope to find the equation for the line:\n\ny - y1 = m(x - x1)         Initial Equation\ny - 7 = 3(x - 2)           substitute\ny - 7 = 3x - 6             distribute\ny = 3x + 1                 Add 7 to each side to solve for y\n\nNow that we have the equation for the line, we want to know where the line crosses the x axis.  That means we put 0 in for y and solve for x.\n\n0 = 3x + 1      Initial equation with 0 substituted for y\n-1 = 3x         Subtract one from each side\n-1/3 = x        Divide each side by 3.\n\nDone - the answer is (d) -1/3
1066076
ok first set up the problem according to y=mx+b:\n3y+2x+6=0\n- you want to get y by itself so you subtract 2x+6 from both sides (or add -2x-6)\n- you should get 3y= -2x-6\n-then divide by 3(or multiply by 1/3)on both sides\n- you should get y=-2/3x-2 and since m = your slope then the slope is -2/3\n:D\nI LOVE MATH!!!!!!!!
819957
Start with a graph of:\nf(x) = x\n\nThat's a straight line going through the origin with a slope of 1.  It should look like a 45 degree angle if you draw it correctly.\n\nNow to transform this to:\nf(x) = | x |\n\nYou have to think of each value smaller than 0.  Rather than -1, for example, you'll have 1.  Rather than -2, you'll have 2, etc.  This is like "mirroring" the graph that is below the x-axis so that it is above the x-axis.\n\nThis results in a "V" shape.  A slope of -1 down to the origin, then a slope of 1 from the origin.\n\nFinally:\nf(x) = | x | - 2\n\nFor every value that results, you now subtract 2.  For example, x = 0, gives -2, rather than 0.  This is true for every point x, making every point y smaller by 2.  It would look like you shifted the whole graph down 2 units.\n\nSo it would be "V" like before, but it would go down at a slope of -1, cross the x-axis at -2, and continue to (0, -2).  Then it would slope up (m=1) through the x-axis at 2 and continue upward.\n\nYou can go to the first link and type 'abs(x) - 2' in the box.  The resulting graph is shown as the 2nd link.
843812
slope= 1   y-int=0\nThis is an equation. You can cancel the -7 and you'll have y=x. If you remember from the equation y=mx+b, then you'll see that here your m=1 and your b=0
450157
slope = (y2-y1)/(x2-x1)\n5= (k-4)/(2-3)\n5= (k-4)/(-1)\nk-4= (-1)*5\nk-4= -5\nk= 4-5\nso k= -1.\ni hope you understand they way I worked it out. If you have any more questions, pls feel free to ask me on: pinkieflava@yahoo.co.uk