i want to make a model (framed structure) of a high rise building.how to decide the height of building.(floor)
959992
depends on which city you are building that that model for ,as different cities have different rules regarding the building heights,but if its just for fun then divide the total height of your model with the number of floors you want ,to get the exact height of each floor.
149750
If you have to actually build this thing then a castle-style drawbridge would probably be the easiest thing I can think of. \n\nBuild a tower out of boxes, wood or whatever. If you’re real lazy simply stand a shoebox on its end and paint an archway on what was the bottom.\n\nCut a piece of cardboard slightly narrower than the base of the box and about 8 inches long. That piece of cardboard is your span.  Bend the first couple of inches of the cardboard up at right angles. Push thumbtacks through that bent up section and into the tower a few inches above the tabletop. That way when the span is lowered it will slope downwards on to the table.\n\nPass a piece of wire through a cotton spool and bend both ends around to make a U shape. Bend the ends of the “U’ shape into tight circles. You can now put a screw through those circles and into a piece of light wood/heavy card that you can glue to the tower somewhere near the top.\n\nPoke a hole in the free end of the span. Tie some thread through it. Pass the thread around the cotton spool a few times. \n\nYippee, finished in one afternoon.\n\nWhen you turn the spool the span will lift. The spool is both a wheel and a pulley system. The span itself functions as a lever. Because the span slopes downwards onto the table top it is an inclined plane/ramp.\n\nAttaching a couple of parts using screws and a couple more using nails/tacks gives you your screw and wedge.\n\nSimple. Next time don't procrastinate.
352673
Make right triangles with the height as one leg, a radius (segment from center of base to one of its vertices) as the other leg, and lateral edge as the hypotenuse.  The radius will equal the length of the base edge as it's a side of an equilateral triangle.  So 10^2 + 15^2 will equal lateral edge squared.\n\nSlant height would be the hypotenuse of a right triangle with legs of the pyramid's height, and the apothem (distance from center of base to midpoint of a side.)  You can get the apothem from Pythagorean theorem from the right triangle formed by half a base edge, a radius, and the apothem.  Then use the apothem in another Pythagorean theorem to get slant height.\n\nLateral area = 6 times the area of any one triangle.  Each triangle's area is 1/2 times 10 times slant height.\n\nVolume = 1/3 (area of base)(height).  The area of the base is 1/2 (apothem)(perimeter).\n\nThose are the steps.  Hope you can figure them out from this typing!
284409
Ex:\nA man stands 60 feet away from a building and sees the top of the building at a 60 degree angle. How tall is the bulding?\n \n1)Choosing an equation: (sin, cosine or tan)\nGoing to those three equations which one do we use?\nWell, we want to find the hight of the bulding (opposite b/c it is opposite the angle), so lets use tan.\n \n2)Setting the equation:\n \ntan 60 (the measure of the angle is θ) = (x) (opposite) / 60 (side adjacent to angle is adjacent)\n \n3)Press on Calculator: tan 60\n \nU should get: 1.732050...\n \n4) Multiply by 60. (b/c ur solving for x , see original equation),  \n5)Answer:  about 103.9230485\n \n6)Using 30-60-90 Triangle tricks we check our answer and find the height is 60 X (sqrt 3) which is aproximately 103.9230485 so we are right.
1180346
Unfortuantely the pictures do not show up, but here is how the math works...\n\nThe following drawing shows 3 views of a Hip Roof. TOP \n\n\nWith the information above we find the information needed to make each of the following: Ridge, Normal Rafters, End Rafters, Hip Rafters, and Jack Rafters. ( see the following figure ) We also find the squares of shingles and # sheets of plywood to cover the roof.
466401
Trigonometry is hard to do in you head, so start out by making a drawing. You have two buildings A (tall) and B (short) - Draw them far apart, not like this:\n\nA         B\n|         \n|         \n|    \n|         |\n|         |\n|         |\n|         |\n\nNow draw one line from the top of A to the top of B - this is the angle of depression of the top and it is 46 degrees. That is, if you drew a straight, horizontal line across the top of building A, the angle between that line and the line joining the top of A to the top of B is 46 degress.\n\nSimilarly, draw a line from the top of A to the *bottom* of B - this is the angle of depression of the bottom and it is 77 degrees. That is, the angle between the horizontal line across the top of A, and the line between top of A and bottom of B is 77 degrees.\n\nNow can you find out the angle between the line from A-top to B-top, and the line from A-top to B-bottom? (It's very important for you to draw this!) Let's put this value aside for a minute. \n\nLooking at your drawing, can you see that you know the value for *part* of the angle between the horizontal line across A's top and length of building A? What is that part you know? Now, see how the line across A's top and length of A make a right angle? So how many degrees in a right angle? So if you know the total of that angle, and part of that angle, how do you get the other part? **Notice that this part we're trying to get is actually the angle between the line A-top to *B*-bottom, and the line A-top to *A*-bottom. \n\nYou should also notice that now we have two triangles:\nTriangle 1: A-top to B-bottom to A-bottom. Solve this triangle for line A-bottom to B-bottom for distance between the two buildings.\nTriangle 2: A-top to B-top to B-bottom. Solve this triangle for line B-top to B-bottom for height of building. \n\nDon't forget, we have two important angles that will help solve these two triangles!
598257
I don't think height alone makes much difference.  Construction style and materials is a much bigger issue.  But between two buildings which are identical in every way except height, I would the taller one is more succeptible to collapse because its center of mass is higher.
427221
At around half the height of the Eiffel Tower, the Great Pyramid in Egypt was the world’s tallest building for over 4,000 years. An engineering feat of magnificent scale and astonishing precision, its four triangular sides rise at an angle of 51.5 degrees. By each side of the pyramid meets at the apex – 146.5m above its perfectly level base – they deviate by just half a metre.\n\n An amazing 2.3 million blocks, weighing between two and 70 tons, were all hand-carved to create the structure.
266818
you have to put yourself into situations involving height that are comepletely safe first. face the fear, and conquer it. I would personally start by going up to second stories of houses, and looking out the closed window at the ground. Then move on to taller buildings looking out the window, and you will gain confidence that you wont fall.
685732
Technically this is divided into risers and treads. A riser is vertical distance u travel in a single step. Generally it is kept ranging from 150mm to 180 mm. And if u take a story height to be approximately 3m i.e. 9'9", you have to add 230mm for the floor slab and floor finishes, so you have to climb a total of 3230mm in a story. Now divide this by a suitable factor between 150mm to 180mm to get a full number. 23 steps of a riser 153.8mm or 18 riser of 179.44mm. For a building of 50 stories, first u have to make sure that the floor heights are kept equal otherwise sum up the total elevation distance and divide. For a 3m nominal floor to ceiling height it comes out to be 161500mm and no of steps ranging from 1076 having 150mm risers and 897 having 180mm riser.\nIm an architect so u can believe me.
525431
Visual CAD or any full CAD program is the standard for designers until something better comes along. They can be used for visual layouts or even blue prints. Training for one of these programs is pretty intensive. Most learn these programs to land jobs with design or architect firms.\n\nA good architect can work of even a pencil sketch of your own. You're not going to find an "easy to us" inexpensive program to help you with a floor plan layout. You should really be using an architect anyways. They are familiar with building codes in your area and will see plumbing electrical and HVAC needs that you will not. I would suggest using an architect for any project you're serious about.\n\nBrandon O'Dell\nO'Dell Consulting\nRestaurants/Retail/Bars\n(316) 361-0675\nbodell1@cox.net\nhttp://www.bodellconsulting.com\n\nFree initial consultations
1017637
I will assume you want to find the sq ft of a house or building. You just multiply the length by the width. If the build has several different dimentions you will have to figure each area seperately and then add up the totals.
923401
Been there and done it.\nBut in 48 ft high racking?\nAs an engineer I was responsible for the team that built a 1,200,000 sq ft Parts Warehouse and have been manager of 3 Parts Warehouses.\nSo, ignoring the height thing for a moment, you need an interface between Shipping and Receiving and the final stock location.\nYou also need computer controlled stocking keeping and location.\nEnough of this for this media so contact me direct and we will start from there.
841370
Good Grief! I was thinking the exact opposite - RAISE it. And while we are at it since we have a floor, how about a ceiling? Say...75?
849810
Here's the start of the answer and here is the link to the rest.\nA skyscraper is a very tall, continuously habitable building. Although there is no official definition, a minimum height of approximately 150 meters or 492.12 feet is often used as a criterion for a building to qualify as a skyscraper. Other criteria like shape and appearance may also affect whether or not a building is considered a skyscraper. The city of Chicago is credited as being the birth place of the skyscraper.\n\n\nhttp://en.wikipedia.org/wiki/Skyscraper
73982
Same as the foundation of a house, except bigger.\n\nThere are several ways to build the foundation depending on the soil structure and the estimated weight of the skyscraper.
973902
Generally there are several areas that engineers usually have to decide, but this depends on what the engineer is trying to do.\n\nFor instance if something is safety critical (i.e. a crane or bridge or tower), then they will choose to make something much stronger than it needs to be.\n\nSay a crane expected to see a max load of 10,000lbs.  The design might actually be able to support a load of 15,000, but you tell the public that 10,000 is the safe limit.  This is called factor of safety and engineers almost always want to be conservative.\n\nNow an engineer could design it to support 100,000 lbs, but this would make the crane much more expensive than it needs to be.  So what happens is they compromise with 15,000 pounds because it is safe enough and not as expensive.\n\n\nAnother topic would be tolerances.  For instance, you want a rod 1 foot long.  I the real world, it's impossible to get something exactly 1 foot long.  We can get close, 1.001 is easy to do, but why do you need such precision if something that is 1.2 feet long will do.  \n\nSo in many cases you see tolerancing on dimensions, 1 +/- .003. That means something from 0.997 to 1.003 is acceptable.  If you want something much closer, say 1.0001, then it'll be much more expensive because it's more difficult to make.\n\n\nHope this helps.