Why would you use percent change in mass rather than just change in mass to compare different solutions of?
964798
This is a chem, not bio question
1151400
simply put: the higher the concentration the faster the reaction rate. in equilibrium the higher concentration shifts the reaction t o the other side.
487220
Changing the subscripts will all together alterate the chemical.  It will be a completely different chemical.  The coefficients only define how much of that chemical is being used, but changing it won't change what type of chemical it is.
659445
well first, you need the actual value, then use the %error formula\n\n(actual-experimental) / actual X 100% = (just change the sign if it is negative)\n\nyou should probably use the averages of the 2 methods you used, but without the actual value, i can't get you the answer
429006
Do you mean in relative terms (percent change) or absolute terms (mm Hg)?  In % terms, the pCO2 changes the most.  In absolute terms, the pO2 changes the most.  See my source for a table of the typical numbers.
593819
It appears that the constants are calculated at one condition (dry,wet,etc) whereas the effective is closer to reality.  See\n\nhttp://www.pnas.org/cgi/content/full/102/45/16293
578520
percentage change is your difference over the original number multiplied by 100
312896
The 2 are unrelated ... if you have a weight for the product per m2 then you would multiply that by the m2 to get a weight.
580895
This is a typical sort of problem found in real life laboratories- You have differences in concentrations because, in the real world, there are errors introduced at every step of the quantitation process..tiny differences in how much stays in the tube, in the pippette tip, the accuracy of the pippette itself, etc.  However, figuring out which is more accurate is fairly easy.  First, any value that actually falls *on* your standard curve is best-that way you don't have to extrapolate. Second, in general, the more you dilute, the less accurate the reading.  The first consideration is the more important.  In sample 1, your 1:50 dilution is too low to get an accurate reading, in unknown 2, your first dilution is too high to get an accurate reading.
390991
its a good idea to standardize your solutions everyday.  Depending on the accuracy you are trying to achieve this is the procedure i would follow.
904975
Because the real mass of atoms are too small or to complicated to be written in regular mass unit (like grams). It just standard constant to make the calculation and writing easier.\nIt's like using light year to measure distance in space instead of miles or kilometers.
73838
Its' probably a rounding error. It would depend on which masses for the elements you use, how precise you want to be.
774877
The equation doesn't differ for different springs, only the value of spring stiffness k does. A different value of k means the deflection x resulting from a given force Fm will differ also since Fm = k*x.
280819
The two main sources of error I would think would be inaccuracies in the measurement of the initial reactants or impurities in the final product.\n\nIf you initially had more reactants than what you thought, you would be making more products than expected, causing a yeild of over 100%.\nWhen determining the amount of products in the yield, if the products contain impurities, that too would offset the calculations.  For example, if you were measuring a specific product of a reaction which produced two or more products and you did not seperate everything completely, you would be measuring some "Extra" stuff.  Also, if you did not dry your products throughouly or the products are hygroscoptic, that would increase your yeild.
621304
If you are dealing with a reaction involving ammonium carbonate in solution, and are then measuring the temperature rise, you need the heat capacity of water, not ammonium carbonate!\n\nPlease post the whole problem if that is not enough to get you started.
712534
used to change colligative properties of solutions
93142
Why not try it?\nYou will have to come up with a way of using small amounts of each to keep it fair; perhaps a toy spoon from a doll's set.\nYou'll need to use the same amount of water for each test.\nAfter each addition, the solutions should be stirred by the same amount.