What are the answers for the 2006 Abacus Math competition November problems?(grades 7-8)?
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553.    343434, 686868\n\n554  42\n\n555  642, yes\n\n556  210\n\n557  42\n\n558  Sorry, you have to do proofs yourself\n\n559  987987^30
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http://www.maa.org/mathland/mathtrek_11_27_00.html
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Well, the second question is kinda fun... the fifth term has to be 2, so that the fourth term + the fifth term = the sixth term.  That means the seventh term is 2 + 6 = 8, and the eighth term is 6 + 8 + 14.\n\n* * * * \n\nOK, on the first one: Make a diagram so that you can visualize this.  You should see that the area of the square is the same as two right triangles, while the area of the trapezoid is the same as three right triangles.  So, the area of the trapezoid is 3/2 the area of the square, or 3/2 * 2800 = 4200.
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Solve for y\nSubtract 2x from each side\n-8y = -2x + 7\nDivide everything by -8\n-8y/(-8) = -2x/(-8) + 7/(-8)\ny = (1/4)x - 7/8\nFor the equation y = mx + b, the slope is m.\nAnswer: slope = 1/4
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http://www.aaamath.com\n\nThis site has been helpful for my daughter.
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Try www.artofproblemsolving.com\nIt's the world's largest online math community and kids can learn here in lots of different ways. Its math forum is used by everyone, from beginners to the world's smartest math students.
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m = (7-4)/(6-8) = -3/2
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12s - 5s + 6 = 55                     \n\n7s + 6 = 55\n\n7s + 6 - 6 = 55 - 6\n\n7s + 0 = 49\n\n7s = 49\n\n7s / 7  = 49 / 7\n\ns = 7\n\n\nCHECK:   Let  s = 7\n\n12s - 5s + 6 = 55\n \n12(7) - 5(7) + 6 = 55\n\n84 - 35 + 6 = 55\n\n49 + 6 = 55\n\n55 = 55  TRUE\n\nTherefore,   s = 7    is the solution.
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try http://www.webmath.com/\nit gives you help on math on almost any time of math.
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http://thesaurus.maths.org/mmkb/entry.html?action=entryById&id=3206\n\nhttp://mathforum.org/library/drmath/view/51899.html\n\nhttp://www-staff.mcs.uts.edu.au/~don/pubs/solving.html\n\nhttp://thesaurus.maths.org/mmkb/entry.html?action=entryById&id=3206
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www.aaamath.com i hope I helped
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Example Questions\n\n1. Which symbol in the Answer Figure completes the sequence in the Problem Figure ?\n\n2. Which of the Answer Figures belongs in neither group?\n\n3. Which of the Answer Figures belongs in neither group?\n\n4. Which of the Answer Figures fits the missing space in the Question Figure? \n\ngo to this site\nhttps://www.careers.ox.ac.uk/homepage/registration/regform
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Let 1 2 3 4 5 6 7 8 9 A B C D be the dots, with D in the middle. (You say 1 in the middle)\n\n1 2 3 4\n5 -- -- 6\n-- -D- --\n7 -- -- 8\n9 A B C\n\nIT CAN BE DONE WITH 5 LINE SEGMENTS AND DOESN'T NEED 6.\n\nConnect 7-5-1-2-3-4-D-9-A-B-C-8-6 in a Z-shape\n\nSo I think if it needs six lines, your question was meant to be regarding 16 dots, 4 of them in the middle. It would then be similar to your other question with 9 dots.\n\n1 2 3 4\n5 6 7 8\n9 A B C\nD E F G\n? -- -- !\n\nConnect 1-2-3-4-8-C-G-! and then proceed as for 9=dot problem, F-A-5-6-7-8-B-E-?-D-9. Six lines needed.\n\nGeneralising, an n x n square of n^2 dots will require 2n-2 lines. (for n>2)\n\nImagine a further 9 dots wrapped around the 16-dots as follows\n\nH I- J K L\n1 2 3 4 M\n5 6 7 8 N\n9 A B C 0\nD E F G P\n\nConnect G-F-E-D-0-5-1-H-I-J-K-L-  M-N-O-P and then proceed as for the 9-dot problem:\n\nC-7-2-3-4-M-8-B-E-A-6\n\nwhich is 8 lines.
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for these types of problems. all u have to do is change around the words to symbols, and then u got ur equation\n\njust remember "is" is the same thing as =\njust remember "of" is the same thing as * or times (multiplication)\n\n0.06 is what percent of 250\n0.06 = n% times 250\n (divide 0.06 by 250)\nsolve\n\ndo the same thing for the other problem
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It's multiple choice, so all you really need to do is start plugging numbers in and see if they work:\ng(7) = 2(343) -11(49) + 8(7) + 21\ng(7) = 686 - 539 + 56 + 21 =/= 0\n\ng(1) = 2(1) - 11(1) + 8(1) + 21\ng(1) = 2 - 11 + 8 + 21 =/= 0\n\ng(7/2) = 2(343/8) - 11(49/4) + 8(7/2) + 21\ng(7/2) = 343/4 - 539/4 + 112/4 + 84/4 = 0\n\nThus, d is the right answer.
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http://mathcentral.uregina.ca/RR/database/RR.09.00/treptau1/ u'll get everything abt the games.
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http://www.aaamath.com/ There you go!! Hope that helps.