why should the string be thin in a flywheel experiment?
957813
Hi Either one of two answers. If the string is pulled and releases from the flywheel it allows more turns (faster wheel motion). If the string stays attached then you want the weight as small as possible.
399579
It would screw up a lot of calculations and other assigned physical values. Since no friction at all is 0 you would be claiming less friction than none. It is set up the way that it is for much the same reason that there are limits to aerodynamic lift and other forces that are nonsensical when allowed to become either negative or larger than one.
701523
Good ? fernando,\n\nI thought about this problem and remembered blowing up balloons long, long ago in my childhood.  (It actually is easier to blow when the balloon gets larger).  \n\nReason: the material stretches in the larger balloon and becomes thinner, so the elastic modulus is inversely proportional to size.  Ergo, when the 2 are connected, air will flow from the smaller to the larger, since the smaller one has more pressure.\n\nI realize this is not a formal proof, but it will have to do for now!
1044991
My answer is somewhat silly.\n\nI think that is friction between the rope and your hands. If there was low friction, the rope would slide out, or you would have to hold it very very tightly, and this would increase the effort.\n\nAs between the pulley and the rope, there is very little friction and exactly this reduces the effort. If the friction was high (e.g. if the pulley was stuck), the required effort would have been higher.\n\nIf you're interested in how the wheel reduces friction, it is simple. Say you need to pull something by many meters. If there was no wheel, you would have many meters of high friction movement. If you have a wheel with a circumference of 1m, and its axis has a circumference of 1cm, then for each rotation of the wheel (1m) only the axis slides against the wheel by 1cm. The slide distance is 100 times lower. That's even not accounting for sleeve bearings (reducing friction of the axis). Or, even better, ball bearings.
1130182
Um... I think maybe pull... if something is rotating/turning it is creating it's own little gravity field (I think!) therefore making it easier to pull.  I'm no scientist but this is an educated guess.
817948
My science class did the same project a few years ago. I suggest suspending the egg within a sphere, try making wings to slow its fall. I dont think whether it is a trianlge or not will really affect its streght to much. Good luck
6374
The second and fourth answers are essentially correct and apply in ideal circumstances, with a fly that is just hovering (not flying forward or backward in the car), and in air that has infinitely low viscosity (is very very thin).\n\nBut this isn't simply a Newton's first law problem [1], since a fly is so small and light, and is effected by the movement of the air it is flying in.  For example, if you open the windows, a stationary hovering fly might get sucked out sideways, even with a constant velocity.\n\nSo when you suddenly accelerate, a ball on a roller might hit the back window, but a small, lightweight fly won't neccessarily hit the back window since the fly is in a fluid (air) that prevents the free movement of the fly through it.
1087038
lets see there are different theroies about the fundamental particles............but answering you qestions i will say the "strings" are the fundamental particles and we physicist now belive that all the fundamental particles which we have establish through some experiments are basically made up of these strings......a string in a perticular mode behaves as a perticular fundamental particle like protron neutron electron or quarka etc
510959
The strands. You know how they twist the strings around each other. Well, if they use 2 strands, of course that's 2 stranded string. If it's 3 strands well... you get the point.
98142
Tightening the string (or making it shorter, or a smaller diameter).
510510
I would have to go with the Planck length on this one, which is a millionth of a billionth of a billionth of a billionth of a centimeter!  \n\nThe reason I say this: According to String Theory, strings are that long, and they are the fundamental building block of all matter.  Therefore, nothing exists that is smaller than that, so it is useless to have a smaller measurement.
348312
as someone pointed out. it could be because of a very large angular rotation decreasing the air resistance.
433102
Since the piece of string is not necessarily straight, it is insufficient to simply measure the distance from one end to the other.  Furthermore, the length of the string depends on the observer - if the string were moving at relativistic speeds (that is v/c is not << 1) compared to the observer, the string would not be nearly as long as an observer that moved with the string.  To measure the proper length of the piece of string, consider an observer that moves with the piece of string and that the entire string itself moves at a constant speed (since if part of the string were spinning very quickly and another were motionless, the observer on the motionless piece would observe the spinning piece to have length contraction as above).\n\nSide note:  My girlfriend is telling me that she wants to kick me in the face for responding like this.. hope you enjoy! (:\n\nAnyhow, the appropriate way to find the length of the string is to move as an observer sitting on the string and integrating over the path at an instant in time.  This will give you the proper length of the string which is the longest possible measurable length for the string.  Any other measurement would find a value that is smaller than this and would vary depending on the speed of the observer compared to the string as well as any relativistic gravitational effects.
317039
Imagine the stretching of the surface of the drum as the stretching of a spring. use hooke's law to do calculation. u will need to know about the strength of material and etc. very very very complicated
324285
The thicker the string the slower the vibrations occuring when plucked. A thin string is light-weight, so it is free to vibrate at a faster frequency, giving the sound a higher pitch. The thicker the wire, the slower the vibrations will be. Guitar strings can be wrapped with copper to add weight to the string, slowing down vibration capacity, giving it a lower pitch.\n\nThe tightness of the string will also affect the pitch. The more lose a string is, the WIDER the vibrations occur, causing the pitch to lower. The tighter the string, the tighter the vibration, causing the pitch to be higher
833617
I'd say the force you use is a combination of friction and gravity. The string you hold doesn't escape from your hand because of friction (think about walking on ice: you can easily slip because there's almost no friction involved between the bottom of your foot and the ground); by pulling the string, you also exert a force greater than the weight of the string (even though you might not feel it because it is very light). This is all I can think about right now, but I hope it helps
834149
The period T is 0.9s\nT = 1/f = 2pi/w so w = 2pi/T\n\nAs the movement is circular, the total of the forces is in this plan and to the centre and the value is mw²R.\n\nSo P + S = mw²R where P is the weight and S the tension of the string and R the radius and a the angle between the string and the vertical\nIn projection, we have :\nmw²R = S sin a\nmg = S cos a\n\nDividing the 2 equations :\ntg a = w²R/g\nand R = L sin a\n\nso w² = g/(Lcos a)\nso cos a = g/Lw² = g T²/(L 4 pi²) \n\nso cos a= 9.8 0.9²/ (0.3 4 3.14²) = 0.6702\n so a = 47.91°  or a =0.83 rad\n\nBut this angle is the angle between the string and the vertical so angle between the string and the horizontal is 90-a = 42.09°