can anyone explain this amazing mathematical puzzle?
955822
a+b-c=0\nDivision by a+b-c is division by zero, an "illegal" operation.\n\nI think that the "proof" is saying that the only way to make the process true is if a+b=0.  The "proof" stands apart from the assignment of values (a=4000, b=6000).
766854
28! I just did it on paper putting 8 dots and connecting each one with the rest. There is a math formula for it but I don't remember it!
735406
Hint: the three side are equal long.\n\nTh
800132
how does this fit into mathematics?
786886
Why didn't you just ask me?  You could have emailed and saved 5 points.\nMy solution did indeed contain a typographical error omitting the q from the value of m.\nAlso, I had amended the solution with a comment shortly after the question had been resolved.  (There was another small error as well.  It is very difficult sometimes typing and then proof-reading mathematical proofs in these Yahoo boxes, especially when they contain alot of special characters.)\n\nSee:\n\nhttp://answers.yahoo.com/question/index;_ylt=ApZ1XohHNUdL5xkBg8bXQEfsy6IX?qid=20061124162535AAURdJ5
74043
I don't think you have stated the puzzle correctly.\n\nIf each letter is supposed to represent a single digit, (which is the usual way these kinds of problems are stated) and the correct statement of the arithmetic is\n XYZXYZ+ABCD-ABC=EFGHA\nthen there is no solution.\n\nXYZXYZ is a 6 digit number, since ABCD has to be larger than ABC, ABCD-ABC is a positive number.\nWhen you add that to XYZXYZ, the result will have at least 6 digits, but EFGHA only has 5 so the problem is inconsistant.\n\nThere is another problem: The puzzle as you have stated it, uses 11 symbols to represent the 10 digits. If you allow more than one letter to represent a single digit then you can say let all the letter represetn the same value. Then you can get: A=B=C=D=E=F=G=Z=Y=Z=0 and the problem is trivial.
604123
I figured it out... the answer is 1/(13*(2-3x))\nIf you need an explanation tell me
1090404
look at what is added (in parentheses)\n\n2 (+1) 3 (+2) 5 (+0) 5 (+3) 8 (-1) 7 (+4) 11\n\nStarting with the first and taking every other number you have +1 +0 -1.  The other values are +2 +3 +4.  So you have two patterns interwoven.  Following those patterns will yield:\n\n2, 3, 5, 5, 8, 7, 11, 9, 14, 11, 17, 13, 20
748483
The answer is 119\n\nTake 2 at a time end up with 1 (59 times=118 one left)\nTake 3 at a time end up with 2 (39 times=117 two left)\nTake 4 at a time end up with 3 (29times =116 three left)\nTake 5 at a time end up with 4 (23times=115 four left) \nTake 6 at a time end up with 5 (19times=114 five left)\nTake 7 at a time end up with 0 (17times=119 o left)\n\nI am dead sure this time = ]\n\nThe trick is look at 5 at a time. there is 4 left this means the last digit must be 9. So look at all possible answer of 7s that ends with 9 and work it out from that!!!!!!!!!!
403722
1,11,21,1211,111221....\n\n312211,13112221,1113213211\n\n\nBTW i love this riddle, i use it on for my chess team for brain warm-ups
766645
Each row coresponds to coeficients of the binomial expansion.  The first row is the n=0 row with the entry 1, the second row n=1 with the entries 1,1 and so on.  The entries correspond to the coefficients of (a+b)^n.  \n\nAlso you can get relationships between the entries of pascal's triangle and the fibonaci numbers.  There are many other applications and patterns to be found.
528695
x to the n + y to the n = z to the n where n is an integer? ... damn it's been so long I can't remember for sure. Some Brit solved the proof already.
840916
i know how it's done. in the theorm, every number is one higher than stated (ex. 1=2, 2=3, 3=4, etc) since it's 2+2, it's actually 3+3. and if 3+3 =6, and 6=7, then the resulting equation is 2+2=7
908277
* * * * * * * . I have encrypted the answer for you so that only you can see it and the rest of the readers can't solve it yet. This way your question isn't dead but you know I know the answer. Howzzat!?
633099
The triangle shows the coefficients in the expansion of (a+b)^n, for n incrementing by 1 in successive rows of the triangle. \n\nStart top row with single 1\n\nNext row (a + b) records the probabilities when a coin is tossed once (1 chance in 2 of heads, 1 chance in 2 of tails).\n\nNext row (a^2 + 2ab + b^2) records the probabilities when a coin is tossed twice (1 chance in 4 of 2 heads, 2 chances in 4 of one head and one tail, 1 chance in 4 of 2 tails).\n\nNext row (a^3 + 3a^2b + 3ab^2 + b^3) records the probabilities when a coin is tossed three times (1 chance in 8 of 3 heads, 3 chances in 8 of two heads and one tail, 3 chances in 8 of one head and two tails, 1 chance in 8 of 3 tails). etc.\n\nThe mathematical properties of the triangle then strike you and provide an alternative way of constructing it.
467967
this is probably not a perfect answer but this site may give you some clues.\n\nhttp://www.gomath.com/Questions/question.php?question=4751\n\naltrnatively type 'prove v*v = 2gr*r/s+v0*v0-2gr' into a search engine and see what comes up.
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.