What is the slope and intercepts of the equation y = 3x ?
957268
The slope should be 3 over 1 or +3(rise over run)and the x and y intercepts would both be 0  (0,0). \n\nThis can be found by using the equation y=mx+b or by using a graphing calculator. The graph of the line in this case crosses exactly where the x-axis and y-axis cross (0,0).
736765
slope=1\ny=x+b\n-3=3+b\nb=-6\ny=x-6
867910
y = m*x + b\n\nwhen x = 0, (the y intercept) you get:\n4 = m*0 + b\n4 = b\n\ny = m*x + 4\n\nwhen y = 0, (the x intercept) you get:\n0 = m*(-3) + 4\n3*m = 4\nm = 4/3\n\nso the equation is:\ny = (4/3)*x + 4
829794
The standard equation for slope-intercept form is y=mx+b. m is the slope and b is the y-coordinate of the vertical (y) intercept\n\n-2x=y+3       Original equation\n\ny=-2x-3        Rewritten in S-I form\n\nm= -2, b= -3\n\nThis means that the graph of the funtion is a line through the y-axis at the point (0, -3) with a slope of (-2)
715413
To find the y-intercept to the line satisfying the equation y = (2/3)x + 3, we set x = 0 to obtain y; that is,\ny = (2/3)(0) + 3 = 3.\n\nSo, the y-intercept is 3. (i.e., The given equation of the line passes through the point (0, 3) in the Cartesian plane. )
760751
a) i)  (0,3)\nThe y-intercept is when x=0, right?  So just plug in zero for x and get:\ny=(0)^2-4(0)+3\nWe get 3 since everything else is zero.\n\nii) (3,0) and (1,0)\nOkay, we have to find when the equation is zero for the x-intercepts.  So, set the equation equal to zero (y=0)\n0=x^2-4x+3\nYou can factor this, which is finding two things that, when multiplied together, form this equation.  The two factors are\n(x-3) and (x-1)  Our factored form is\n(x-3)(x-1)=0\nOne of them MUST equal zero for the whole thing to be zero since they are multiplied, but either one can equal zero.  So we have two possible x values: 3 and 1.  Those are the x-coordinates, the y coordinates are zero.\n\niii) (2,-1)\nThe vertex is halfway in between the roots, which are 3 and 1.  You can take the average of them:  (3+1)/2=4/2=2.  The x-coordinate of the vertex is 2.  Now plug that in:\n\n(2)^2-4(2)+3 = 4-8+3=-4+3=-1\nThe y-coordinate is -1.\n\n\nb) x=2\nThis is just a vertical line with the same value as the x-coordinate of the vertex (the line of symmetry goes through the vertex).  The line is x=2
806897
First equation:\n4x + 2y = 10\n\nRearrange to get the y-term alone:\n2y = 10 - 4x\n\nDivide both sides by 2 to get it in slope-intercept form (y = mx + b):\ny = -2x + 5\n\nNow you can graph it by drawing a line through (0,5) as the y-intercept and have it go down at a slope of -2 through points (1,3), (2,1), (3,-1), etc.\n\nFor the second equation, draw a horizontal line for y = 4\n\nYou'll see they intersect at the point (½, 4).  I've attached a graph of the two lines...\n\nSo your solution is:\nx = 0.5 (or ½)\ny = 4
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
621346
y=mx+b (this is known as the standard form of linear equations)\n\nm=slope\nx=x values\ny=y values\nb= y-intercept\n\nso the answer for you question is:\n\nslope = -1\ny-intercept = -3\n\nEXPLANATION:\n\ny = mx + b\ny = -x-3\n\nm= -1   and    b = -3\n \nslope = m    and   y-intercept = b\n\nthus, the slope is -1 and the y-intercept is -3\n\n\nNote: the slope is rise/run (rise over run) -- to make a graph use the y-intercept and the slope -- once you have the slope and the y-intercept, making this graph should be easy because it's a linear graph -- but if you still don't get it ask your teacher\n\n\nthus, the slope is not a-1 -----there is no "a"
977519
a/x + b/y = 2\nlet 1/x = X and 1/y = Y\nSo aX + bY = 2\nSo slope = -a/b = 3/4 (= 0.75)\n  Y intercept = 2/b = -0.5\nThus b/2 = -2\nb = -4\nSo a = 3
653148
All equations for a line will have the form:\n\ny = mx + b,\n\nwhere x & y are coordinates, m is your slope, and b is your y-intercept.\n\nTherefore, substituting in your slope and y intercept, you get:\n\ny = -2/3x + 4\n\nThis equation can then be used to graph the line, since given any x, the corresponding y can be found. :)
408060
To find the slope, you always have to set the equation as y=mx+b.  That equation is called the slope-intercept form.  "m" is the slope and b is the y-intercept.\nNow, to find the slope, try to get y alone.\n1. Subtract 2x from both sides.  You'll get: -8y=-2x+7\n2. Divide both sides by -8.  You'll get: y=(1/4)x+(-7/8)\nSo, the equation is y=(1/4)x-(7/8) and the slope is (1/4).
308059
slope: -3/4\nx intercept = 0\ny intercept = 0
791058
The slope-intercept form for a line is y=mx+b, wherem is the slope and b is the y-intercept. Comparing this form to y=7x+3, you see that m=7 (the slope) and b=3 (the y-intercept).
964525
Y = mx + b\nWhere  m is the slope of the line ond\nb is the y intercept
615215
sure...here are 2\n\nThe slope-intercept equation for a line\ny = mx + b\ny=the y part of a point given any x value\nm=slope of the line\nx=the x part of the point given y, or just given x to find y\nb=y intercept, the point at which the line crosses teh y axis, or (0,y)\n\nanother equation is\nPythagorean Theorem \na^2 +b^2 = c^2\na, b, c are sides of a triangle, c is the longest side (the hypotenuse)\nthis formula only works in right triangles\n\nhope this helps\nmatttlocke
744326
yes!  \n\n2x-3y=7\n\n-2x from each side of the =\n\n-3y=-2x+7\n\n-3y/-3 and -2x+7/-3\n\ny=2/3x+-2.3\n\nGo to -2.3 on the Y-intercept\nThe slope is 2/3 (up 2, over 3)