-OR and 2-chloro-3-methylpentane?
961812
According to Zaitzev rule your answer is correct. I don't know if they expected you to say that still you'll get some 3-methyl-1-pentene as a by-product, or if they also wanted you to note that the E (trans) stereoisomer of 3-methyl-2-pentene is the main product.\n\nBy the way, the way you wrote the question people mistake the alkoxy base (RO-) with "dash or"
515166
Hmmm, since you're only getting one product, and I assume you have an excess of NaCN, I would suspect that you have a double displacement reaction, and you're getting pentanedinitrile, NC-(CH2)3-CN
453727
trans-2-hexene\n\ncis-2-hexene\n\ntrans-3-hexene\n\ncis-3-hexene\n\npictures in link :)
688017
2-hexanol. Look at the link, I think this is what you want.
539827
(a) 2 NaClO3 -> 2 NaCl + 3 O2\n\n(b) 3 MnCl2 + 2 Al -> 3 Mn + 2 AlCl3\n\n(c) C4H10 + 13/2 O2 -> 5 H20 + 4 CO2 \n                  or\n(c) 2 C4H10 + 13 O2 -> 10 H20 + 8 CO2\n\nBalancing is quite simple for these simple equations. You just have to see the left hand side pick up an element, see how many atoms of that element are there in it and multiply the R.H.S compound containing that element with a number which will be equal to no. of atoms in the l.h.s. Then again repeat the procedure by picking another element.....see it's quite difficult to explain you with writing aneways i hope it helps u :)
1032656
C4H10\n\nCH3-CH2-CH2-CH3
702840
Of the choices you listed above, then Alkane is the answer.  There are other compounds which fit this description, for example the cycloalkanes which is a sub-group of alkanes.\n\nThese are also called aliphatic compounds and saturated hydrocarbons.
651011
H2O2 + OC(NH2)2 -> HCOOH + NH4OH -> NH4(HCOO)
72715
CH3CH2Cl is an example.  An alkyl group (R) with at least (an usually) one halogen (X), so R-X
225634
None. They are two different compounds.\n\nIt looks like you want to compare a specific property of the alcohols. Please specify!
589750
SO4 2-\nCO3 2-\nOH -\nPO4 3-
813421
Na2CO3(aq) + MgCl2(aq) --> 2NaCl(aq) + MgCO3(aq)
712605
#10.\n\n3,4 - dimethylhept - 3 - ene\n\nI cant really draw the other ones.\nJust look up your reaction mechanisms.\n\nGood Luck!
405453
If you do the above reaction, you can get the following compounds: (chloromethyl)benzene, (dichloromethyl)benzene, and (trichloromethyl)benzene.
802465
carboxylic acid, as represented by -(C=O)-OH. For more info, check the source.
821017
(CH3)2 N2H2+2N2O4-->3N2+4H2O+2CO2
957221
The naming is correct. But the molecule can't exist as described. The Chlor-atom must be attached to the methyl-particle, which is attached to the 3-chloro pentane molecule at the 3rd Carbon-atom.