Solving something with two variables?
959758
( -1 -y) / (x + 4y) = -1/3\n=> (1 + y) = (x + 4y)/3\n=> 3 + 3y = x + 4y\n=> x + y = 3 => x = 3 - y = k  =>\nx = k\ny = 3 - k\n\nit means,for infinite number of k,x = k and y = 3 - k
747036
0.12 \nP(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B) - P(A)P(B|A) = 0.1 + 0.1 - 0.1(0.8)
826575
Use one equation to substitute into the other,then solve for a one variable problem.  Use your new information (the solved variable) to solve for the second variable.\n\nFor the first set:\n\n-3x - y = 2 rearranged becomes:\ny = -3x -2\n\nUsing this "definition" of y, substitute it into the second equation as such:\n\n-6x + 2(-3x -2) = -2\n-6x - 6x - 4 = -2\n-12x = 2\nx = -1/6\n\nSubstitute -(1/6) for x in either equation to solve for y:\n\n-3(-1/6) - y = 2\ny = -3/2\n\nDo the same for the second pair of equations to make sure you got it (the answers for x and y are x=9/7, y = 1/7).
429488
If you have two unknowns (i.e. x, y) then you must have two equations to solve for x and y. You only have one equation, unless I missed something.
195201
i think u typed the question wrong, can u please correct it and if u have 2 unknowns, please give 2 equations, else u cant get a definite solution
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
697874
Multiply or divide all components in one question to set the variables in the opposite questions to cancel out if you added the two problems together by combining like terms. For example:\n2x + 3y = -13  and 4x + y = -1\n\nTo keep this simple I will multiply all the components of the 2x + 3y = -13 equation by negative 2, resulting in:\n\n-4x - 6y = 26\n\nThen add the new equation to the other equation 4x + y = -1\n\n-4x -6y = 26\n4x + y = -1\n----------------\n0x -5y = 25  which simplifies to y = -5\n\nInsert the value found for y back into one of the original eqations and solve for x\n\n2x + 3(-5) = -13\n\n2x + -15 = -13\n\n2x = 2\n\nx = 1\n\nYour end result is x =1 and y = -5
539943
x+y........e=mc2..........2+2
589722
Step 1: Solve one equation for one variable in terms of the other.\nStep 2: Plug that into the other equation and solve for the second variable.\nStep 3: Plug the second variable into the first equation and solve for the first variable.
408462
to solve such a system in general, what you do is this: take the first equation, solve it for x treating y as you would a constant. In your case, this is x = 4 + y.\n\nThen, take your expression for x and substitute it everywhere you see x in the second equation; in your case you get 3 *(4+y) + 2y = 7.\n\nSolve this now 1-variable equation for y, once you find y (in this case, -1).\n\nSubstitute the value of y into either equation, and you get the value of x (3 in this case).
897159
x + y = 2- - - - - - -Equation 1\ny - x = 2- - - - - - -Equation 2\n- - - - - - - -\n\nRearrange equation 2 to read\n\n-x + y = 2\n\n- - - - - - - -\n\nx + y = 2\n-x + y = 2\n- - - - - - - -\n\n2y = 4\n\n2y/2 = 4/2\n\ny = 2\n\nThe answer is y = 2\n\nInsert the y value into equation \n\n- - - - - - - - - - - - - - - - - - - - - \n\nx + y = 2\n\nx + 2 = 2\n\nx + 2 - 2 = 2 - 2\n\nx = 0\n\nThe answer is x = 0\n\nInsert the x value into equation 1\n\n- - - - - - - - - - - - - - - - - - - - - -\n\nCheck for equation 1\n\nx + y = 2\n\n0 + 2 = 2\n\n2 = 2\n\n- - - - - - - - -\n\nCheck for equation 2\n\ny - x = 2\n\n2 - 0 = 2\n\n2 = 2\n- - - - - - -\n\nThe solution set is { 0 , 2 }\n\n- - - - - - -  -s-
1076564
What do you want to solve for? x? y? or do you want an ordered pair (x,y) that works (integers maybe?)
518727
Multiply the first equation by 2.\n\nSubtract the second equation from the new first equation.\n\nSolve for y.\n\nTake your value for y and substitute it into the original first equation.\n\nSolve for x.
201432
x=2 and y =2,\n\n2^2=2^2 and 2*2 = 2 + 2 =4
515169
u r surely missing some information\nlet us put this in the form of an equation\nlet y=A&B, x=A,B&C\nthen we have,\n275-x=120+110+100-20-30-y+x\nnow we have two variables and one equation\nby the way what dou want to know?\nwhat is the question exactly?
27685
You have two equasions 2x=3y and y=2x+4\nYou're going to plug one equasion into the other; plug the y= into the  first equasion because the y is already by itself.\n2x=3(2x+4) (I plugged what y equaled into the y in the first equasion.\nThen you solve for x\n2x=3(2x+4)\n2x=6x+12\n-4x=12\nx=-3\nNow that you have solved for x, plug x back into the y='s equasion\ny=2x+4\ny=2(-3)+4\ny=-6+4\ny=-2
878962
first you get one variable on one side by its self (lets say x), solve for that variable (x), then you put the answer in for "x" and solve for the second variable, Just like you would if you only had one variable to begin with.