How can i test the specific heat capacity of water and salt-water?
960390
Get an electrical heating element, a DC power supply, a thermometer, a voltmeter and an ammeter.\nPass electricity through the heating element, dipped into a measured volume of water (or salt water) in an insulated cup, and measure the current, the voltage and the time taken. This will give you the heat energy supplied. Measure the temperature rise, and work out how much energy would be required to raise 1g of water (or salt water) by 1 degree Celcius. The answer should be close to 4.2!
773978
Yes.....apply an electric current to salt water...I think this is the actual commercial method.
705010
The specific heat of water is 4.184 J/g C.\n\nSince water's density is 1 g/ mL, 500 mL of water will have a mass of 500 g.\n\nThe equation to calculate the joules of energy required is:\nheat = mass x specific heat x change in temperature\n\nenergy = 500 (4.184)(95-25)\nenergy = 146440 J or 146.44 kJ\n\nHope that helped.
88784
when the salt in in the water, it contribute ions in the water. and ions will conduct the electricity. the salt tester will test the electricity in the water, therefore, the salt compound will be measured
468283
Depends on the quantity of ice in the water, time you measure it at, etc. All depends on the precise details of the experiment.
163823
Q=mc(Tf- Ti)\nWhere Q is the heat added\nm is the mass\nc is the specific heat capacity\nTf is the final temperature\nTi is the initial temperature
75392
You need to check your units.  The specific heat of water is not 4.184 J/g; it is 4.184 J/g*degrees C (or degrees kelvin).  And the heat of solution should not be in J/degree, but in J/g.\n\nTry this equation instead:\n\n[HoS = J/g] = [(Specific Heat = 4.184 J/g*C)*(mass = 100g)*(Temperature change = Initial C - Final C)] / [Mass of CaCl2 = 3 g]\n\nBy subtracting the final from initial you should get the negative value and not need the -1 at the front.\n\nSometimes enthalpy of solution is in J/mol rather than J/g, in which case you modify the above by calculating the mols of CaCl2 in 3 grams and switching that out with the 3g in the above equation:\n\n(3g) / (110.99 g/mol) = 0.027 mol\n\nTheoretically, you should want to know the heat capacity of the CaCl2 because it is also being heated, but this is assumed to be negligible.  Write that into your error analysis and you teacher will love you.  Also, make sure to check your significant figures; i don't know how many sig figs you used in weighing out your 3 grams, but that will be necessary to know how much to round everything.  Good luck.
940410
saltwater  boil faster.
177044
use the fmla.... Q=msT\n\nwhere Q is the quantity of heat required, m is mass, s is specific heat capacity of water, T is the temperature difference. i dont hav a calculator with me now, u do the computations plz...
948401
Energy required to heat 1liter of water:\n\nQ = V(liters) * d(kg/liter) * Cp(kJ/kg/K) * (Tfinal - Tinitial)\nwhere Cp is the specific heat capacity of water, which is temperature dependant but for which you can use an average value for the temperature range.\n\nQ = 1 * 1 * 4.18 * 73\nQ = 305.14 kJ\n\n1 kW.h = 3600 kJ\n\nQ = 305.14 kJ / 3600 (kJ/kW.h)\nQ = 0.085 kW.h\n\nPrice = 0.085 * 10 = 0.85 cents
719242
1) Salt water is more dense.\n\nMeasure out one cup of tap water and one cup of the sample your testing.  Determine their mass by placing them on an accurate scale one at a time.  If the sample has greater mass then the tap water then it has salt in it.\n\n2) Salt does not evaporate.\n\nPut the sample into a pot on the stove and boil it.  If crystals form on the side of the pan then their is salt in the sample.  Be careful not to boil away all the water or you may damage the pan.\n\n3) Humans can taste salt.\n\nOur tounges are very sensitive to salt.  The problem is that some salts are poisonous.  If you know for certain that the type of salt you are testing for is table salt (NaCl) then go ahead and taste it.  Otherwise, try other methods.\n\n4) Osmosis\n\nThere are membranes ( called semi-permeable) that allow water molecules to pass through them but not things like ions ( the things salt breaks down into in water).  Water will flow from one side of a membrane to the other to try and ballance the concentration of salts on either side.  In other words, water will flow through the membrane from the side with less salt to the side with more.  The skin of a grape is a membrane of this type.  Drop it into your sample and if it shrivels up then the sample has salt in it.  This may take a couple days though.\n\nHope this helps.
580603
stick it in a tank of water then measure the water displaced.archemedes law
366921
Q = mc delta T\nHeat = mass times specific heat times change in temperature\nspecific heat for water is 4.186 kJ/kg C\n-41840 J (negative because absorbed) = .200 kg x 4.186 x 10^3 J/ kg C x (Tf - 20)\nTf = final Temp.\nsolving the equation gives you Tf = -30.0 degrees Celsius
380685
1)Remember that a calories is a measure of the heat it takes \n  to raise 1 degree of the water temperature.\n2)A Calorimeter helps you measure among other thing the\nheat of fusion and since we know the heat of fusion of water its easier to calculate the heat of fusion of other things.
753535
Just use the formula\n\nE = m*Cp*(Delta T)\n\nE=energy\nm=mass\nCp= Specific Heat\nDelta T = change in temperature\n\nCp= 0.51998 J/(C*g)\n\nGood Luck with the test!
48939
none water is H2O two parts hydrogen 1 part oxygen any thing else the water is inpure.but in the case of fish do a 1/4 water change every week so not to shock your fish make sure you keep temp about 78 degrees or they can get ick as far as testing you dont have to test fresh water but salt water is where the nitrite cycle is critical and then you also will test ph which is idealy 8 use a hydrometer to the line as it mesures the salt level by the boyency of the device nitites no higer than 14 i belive ask you pet shop owener as it been abuot 10 years since i had my salt water tank but for fresh water, the water change should cover it.
688178
The sources of error will always depend on the way you carry out the experiment. To measure the heat directly wouldn't work well. So you need to monitor the temperature at both ends. Monitoring the temperature at both ends, the errors will be the scale error of your measuring device, the quality of the thermal contact between the sensor and the fluid as well as the effect that the sensor has on the flow of the fluid (I'd use fibre optic sensors as they are non-invasive and don't have the problems asociated with using electrical test equipment in water).