solve for the variable...?
965376
z=w+whx\nz=w(1+hx)\nz/(1+hx) = w &#92;
869887
If you have 2 equations, just solve for one variable for one of the equations. Take that equation and plug it into the same variable for the other equation. You will solve for that variable, and plug in that number to any of the 2 equations to solve for the other variable.
1084156
The answer to that is a line.  If you want a unique solution to a two-variable problem, you need two equations.
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
830587
y'=-x^(-1/2)\ny"=(-1/2)x^(-3/2)\n2x^2[(-1/2)x^(-3/2)]+3x[x^(-1/2)]-x^(-1)=0\n-x^(1/2)+3x^(1/2)-1/x=0\n2x^(1/2)-1/x=0\n2x(x^(1/2))-1=0\nx^(3/2)=-1/2\nx=(-1/2)^(2/3)\n\n\ni think thats correct... but who knows...>.<;;;\nis there an answer key???
741999
whats the equation or formula u need help with?
949122
isolate the variable.\n\nfirst subtract 3 from both sides.\n2x=6\n\nisolate the variable further.  Divide each side by 2\nx=3
369017
Set one equation equal to one of the variables, then insert it into the other equation and solve for the second variable.  then insert that variable into the original equation.\n\nx+y=5 or x=5-y\nx+2y=6\n\nput x=5-y into the second equation\n\n5-y+2y=6 \n\nnow solve for y\n\ny=1\n\nput this back into one of the original equations\n\nx+1=5\n\nx=4
1076564
What do you want to solve for? x? y? or do you want an ordered pair (x,y) that works (integers maybe?)
122775
same method i used to answer your previous homework question: isolate the variable.  right now, "n" is being multiplied by 36.  to cancel this out, divide it by 36.  thus, divide both sides by 36:\n\nn x 36 = 360\n36n = 360\n(36/36)n = 360/36\nn=\n\nand you can solve the answer from there hopefully :)
872873
There is only one value that works: \nx=1\n\nj
928663
Are you asking for help or an answer?\n\nTake any 2 equations and multiply all of the terms or one or both by numbers that will make one of the terms in each equation have the same coefficient. Now subtract one from the other and the term will disappear. Now take the resulting equation and do the same with it against the third. Keep doing this until you are down to one term and solve for the variable. Now substitute the variable into the equation and solve for the other variables.
846745
Typically you know three out of the four variables and solve for the last variable.\n\nBut sometimes they get tricky by giving you only two but one of the remaining variable is related to one or two of the given variables.
886222
Solve for one variable and plug it into the second equation...\n\nSo, let's solve the first equation for y:\n-x + y = -4\ny = x - 4\n\nNow plug this into the second equation:\n4x - 3(x - 4) = 13\n\nDistribute through the parentheses:\n4x - 3x + 12 = 13\n\nSubtract 12 from both sides:\n4x - 3x = 1\n\nSimplify:\nx = 1\n\nNow plug this back into your original substitution:\ny = x - 4\ny = (1) - 4\ny = -3\n\nSo your answer is x = 1 and y = -3.\n\nYou should double-check your answer....\n-x + y = -4,\n-(1) + (-3) =? -4  \n-4 = -4 <-- check\n\n4x - 3y = 13\n4(1) - 3(-3) =? 13\n4 + 9 = 13 <-- check\n\nSo your answer is:\nx = 1\ny = -3
867879
Just plug 0 in the function whenever you see y.\n\n4x + 3(0) + 24 = 0\n4x + 0 + 24 = 0  \n\nThen solve for x.\n\n4x = -24\nx = -6
122445
Just replace x with -3 and y with 4 in each equation and then solve for the remaining variable.\n5x + 7y = b\n5(-3) + 7(4) = b\n-15 + 28 = b\nb = 13\n\nmx + y = 22\nm(-3) + 4 = 22  Subtract 4 from both sides\n-3m = 18  Divide both sides by -3\nm = 18/-3\nm = -6
363348
Are we solving for x?