Coffee is draining from a conical filter into a cylindrical coffeepot at the rate of 10in^3/min.?
966390
Assume the diameter of the cylindrical pot is D in. hence cross section area is pi*D^2/4 = 3.14 /4  * D^2 = 0.785 * D^2\nthe rising speed of coffee level in pot = 10 /(0.785 * D^2) in/min\n  = 12.739 D^(-2) in/min\n\nassume diameter of  base of cone = n at depth of 5 inches.\nhence in general when the liquid is at D diameter the H = 5*D/n\nor D= n*H/5\nVolume of cone = 1/3 * (0.785 D^2) * H = .262 H*D^2\nsubstitute D we get Vol = 0.262 H* (n*H/5)^2 =0.01048 n^2*H^3\nflow rate = d(vol)/dt = 0.01048 n^2*3*H^2 dH/dt\nwhere dH/dt = linear speed of the coffee level in cone\n10 = 0.01048 * n^2*3* 5^2 dH/dt = 0.768*n^2 dH/dt\ndH/dt = 10/(0.768*n^2) = 13.021 n^(-2) in/min  (n= diameter of cone base at coffee level = 5 inches)
929521
V=(4/3)pir^3\ndV/dt=4pir^2*dr/dt\n10=4pir^2*dr/dt\nA=4pir^2\ndA/dt=8pir*dr/dt\n=4pir^2*dr/dt*/r\n=10/r\nwhen r=8 dA/dt\n=10/8cm^2/sec
530518
such methods are filtration and centifugation and decant the liquid\nFiltration either simple or gravity\nduring simple filtration you use filter paper and a funnel\nduring gravity filtration you use either Buchner or Gooch funnel\nduring centifugation you put a test tube in the machine...
386344
1067 gallons/minute, approx.\n\nSee reference
107612
This is potentially a massive and complex task.\nSearch the web for "computational fluid dynamics".  Here's what I found in a couple of minutes:\nThe 1st ref. below has some interesting simulation ideas (but unfortunately for a liquid, not air).\nThe next discusses things you should know before even deciding whether to do this.\nThe last gives links to software downloads.
317090
Yes, it's moving and every now and then (like, millions of years) it reverses direction. The North Pole goes South and viceversa.\nBut I'm sure that has nothing to do with your coffee creamer!!!
1140416
you need to employ th ebournoulli equation and the fanninf (or darcy ) friction factor equation ... \n\nThe Darcy-Weisbach Equation for pressure loss due to friction (in the SI metric system) is:\n\nΔP = 4f(L/D)(ρ v2)/(2 gc)\n\nwhere: \nΔP = pressure loss in Pascals \nf = Fanning friction factor (dimensionless) from Moody's diagram \nL = pipe length in meters \nD = pipe diameter in meters \nρ = fluid density in kilograms per cubic meter \nv = fluid velocity in meters per second \ngc = gravitational conversion constant = 1 (kg-m)/(N-s2) in the SI metric system\n\nAnd for head loss due to friction, the equation is:\n\nΔh = f(L/D)(v2)/(2 g)\n\nwhere: \nΔh = head loss in meters \nf = friction factor (dimensionless) \nL = pipe length in meters \nD = pipe diameter in meters \nv = fluid velocity in meters per second \ng = local gravitational acceleration of 9.807 m/s2
893701
v(m/s) = Q(m3/s) / Nozzle Area(m2)
206838
The beans are soaked in water which disolves the caffeine. It also disolves other compounds which give coffee its flavor. To restore the flavor, the water is filtered through activated charcoal to remove the caffeine, then the water is put back with the beans and the beans are dried.
1043213
That may depend on your application.  The pressure drop will depend on whether you are filtering gas or liquid and whether you are interested in the pressure drop of new filter samples or filters in use as they become clogged.  Flow rate will also increase pressure drop.\n\n\nFor example, if the filter is installed at as joint in a round horizontal pipe, and the flow is liquid (water?), and the pressure is relatively low, you can attach vertical plastic tubes with pipe fittings upstream and downstream of the filter.  If the water rises say one foot higher in the upstream tube than the downstream tube, the pressure drop across the filter is 12 inches w.g. (water gage).  If the pressure is too high for plastic tubes (where about 15 psi would require 34 foot high tubes), you can attach pressure gages to the pipe fittings and compare their readings or install a differential pressure gage across the fittings to directly read the pressure drop.\n\nIf the flow is a gas (air?), flowing through a duct, you can install a clear plastic "U" tube partially filled with water (and food coloring?) across fittings upstream and downstream of the filter to measure the pressure drop in inches w.g. or use a sensitive differential pressure gage.  Hope that helps a little.
477733
You need to integrate part of a circle.  Imagine this cylindrical tank centered at (0,-4) in order to accomodate the 8" depth.  First, you want to find your X values of integration.  Imagine that the liquid in the tank (which is upside down now) makes a horizontal line.  The distance from the center to the end of one of these lines is the radius, or 12".  The distance vertically is 4", or the radius minus the depth.  Therefore, you can find the horizontal distance by using right triangle properties. The answer is the square root of 128, each direction.  So you will be integrating from -(128)^(1/2) to 128^(1/2).\n\nNext, you must set up the integral.  The equation for this circle would be X^2 + (Y+4)^2 = 144.  Solving for Y gives us\n\nY = (144-X^2)^(1/2) - 4\n\nIntegrating this would give us\n\n[1/2(144-x^2) + 72arcsin(x/12)-4x] from the negative square root of 128 to the positive square root of 128.\n\nevaluating this gives us approximately 102.75 in^2\n\nMultiply this area by the length of the tank to get the volume...\n\n102.75 in^2 * 68 in = 6886.89 in^3\n\n1 in^3 = .004329 gal, so...\n\n3437.36 in^3 * .004329 gal/in^3 =30.24 gal.\n\nAs far as I can see, that seems logical.\n\nNote: I had the wrong integral formula to begin, so this has been edited.
602654
Filtered coffee tends to be associated with coffee made with a filter bag of some sort.  This is where you put the coffee in the filter itself and the water in a reservoir.  The water is heated and passed through the coffee/filter to create the drink.\n\nBrewed coffee is generally one which is made from an espresso machine.  It doesn't have any filters at all.  Domestic machines are designed so that the water is in a 'container' at the bottom with a funnel type contraption that sits on the top.  This contains the coffee.  Another containers sits on top of that and when the heat is applied the water turns to steam, travels through the funnel and coffee and into the top container.\n\nThe brewed coffee tends to be stronger, so it is more likely to increase your heart rate.
856026
Use the gas law\nPV=nRT
234909
4.5 Quarts with the filter.
96858
erm the volume of the circle would be the same, the volume of the cylinder would be (pi)r*r*h (r=radius, h=height)
795577
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267078
There is a computer program called "Circumventer" that gets around filters.  That's all I know about it.  I guess you could find it if you searched.