16-9x² (Factorise Fully) Helpppppp!!!?
953913
It's a difference of squares...\nIf you have (a² - b²) that is equal to (a + b)(a - b)\n\nSo in your example:\n16 - 9x²\n\n16 = 4² = a²\na = 4\n\n9x² = (3x)² = b²\nb = 3x\n\n(a + b)(a - b)\n= (4 + 3x)(4 - 3x)
398507
since the aspect ratio is 16:9, then the length and width are in proportion. Let width=9*x and length=16*x. Then area=length*width= (9*x)*(16*x)= 144*x^2=190000\n\nx^2=190000/144=1319.44444\nx=sqrt(1319.4444)=36.324\n\nwidth=9*x=9*36.324=326.917\nlength=16*x=16*36.324=581.187\n\nCHECK: 326.324*581.187 =190000
783870
7x^2+16x over (x-2)(x+2)(x+3)
35955
like this???            \n              \n                x x x x x \n                x x x x x \n                x x x x x \n                x x x x x \n               (4x5/5x4)
911592
Factorize!\n4x (x^2-9) = 0\n4x (x+3) (x-3)\n\nyour solution is \nX = 0\nx= -3\nx= 3
990505
See my answer in your next question, Rajesh. \nYour answer only works for powers of 2. (2ⁿ)\n\nAnd I agree with the other guy.  (9/2)² does not yield a perfect square.  What you're doing is taking 2^5 = 9^2 - 7^2 and dividing everything by 2^2 and saying you have a "new solution" to 2^3 = c²-b².
539053
4.43x10(at the power of -4)
713027
Just try out small numbers. 1, 2, 3, 4, 6, 8 all work. Once you start doing anything higher, the second factor becomes smaller again, so the others are 96/8, 96/6, 96/4, 96/3, 96/2, 96/1.\nIn all: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96.
1001971
[(16x*2-25) / (24x*2-30x)] / [(8x*2-2x-15) / (6x*2-7x-3)]\n= [(16x*2-25) / (24x*2-30x)] [(6x*2-7x-3) / (8x*2-2x-15)\n= [(16x*2-25) (6x*2-7x-30] / [(24x*2-30x) (8x*2-2x-15)]\n= [(4x-5) (4x+5) (3x+1) (2x-3)] / [(6x) (4x-5) (4x+5) (2x-3)]\n= (3x+1) / 6x
954300
ok\nso its factoring.this is hella easy.10x+40 is 10(x+4)\nso the answer is 10(x+4)there you go
92952
(8x+3)(4x+3)\n32x2+24x+24x+9\n32x2+48x+9
969030
Original equation:\n16c . 44c\n----- / ----\np²n² . pn\n\nWhen you have a division, invert and multiply:\n16c . pn\n----- * ----\np²n² . 44c\n\nNow you can cancel P, N and C:\n16  . 1\n---- * ---\npn . 44\n\nAlso cancel a 4 from 16 and 44:\n4 ... 1\n-- * ---\npn .11\n\nNow just multiply across:\n4\n---\n11pn\n\nThere's your answer:\n4 / 11pn
801730
8k^8/9y^3\n\n1)  Reduce 64/72 => Divide both sides by 8 => 8/9\n2)  Reduce y^2/y^5 => (2-5 = -3) => 1/y^3\n3)  Reduce k^11/k^3 => (11-3 = 8) => y^8\n\nCombine all 3 => 8k^8/9y^3
607601
I think you set the equation to zero then you have to factor it.  Go to the link below if you wanna know how to do it. OR look your your math book.
981364
Gopal has the correct answer! \n\nSo... becareful with some other results... and... never use:\n0.833 instead of 5/6... it's a mistake!\n\nFinished Algebra with 19!
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
868538
the sides are 9 and 12 units long.  Here is the algebra:\narea: a=xy=108\nperimiter:p=2x+2y=42\n                     -2y   -2y\n               =(2x=42-2y)/2\n               =x=(-y+21)\nsubstitute that back into the area formula:\n(-y+21)(y)=108\n0=-y^2+21y-108\nuse the quadratic formulat to get the roots 9,12