Can you help me find a z score?
967643
z score= (n-mean)/standard deviation\nstandard deviation = square root of variance\n\nz score = (50-24)/ 5\n            = 26/5\n            = 5.2\n\nThe z score of the data is 5.2, meaning n is 5.2 standard deviations from the mean.
367593
best bet is to go for the highest mark. It does depend on the test though. my A+ said it was 80% but after i passed on my pass sheet is said 75% so my ACPT and ACDT both said 80 and were 80 my ACHDS said 70 and was 65 so i would assume the full 87% and hope your lucky and its lower
793773
10% > is z score of 1.281551\n7% < is z score of -1.475791\n\nz = (x - μ) / σ\n\n1.281551 = (16.3 - μ) / σ\n\n-1.475791 = 15.5 - μ) / σ\n\nMulitply by σ:\n\n1.281551σ = 16.3 - μ\n-1.475791σ = 15.5 - μ\n\nSubtract one from the other:\n1.281551σ + 1.475791σ = .8\n\n2.757342σ = .8\nσ = 0.29013448\n\nPlug that back into the equation:\n1.281551 (0.29013448) = 16.3 - μ\nμ = 15.9281779\n\nstandard deviation is ~.29 oz. and mean is ~15.93 oz.\n\nIf you go back and do that common sense check, you will see this fits in the bell curve between the percentages stated.  Only 10% is more than 16.3 oz and only 7% is less than 15.5 oz.  Since this is a normal distribution, the number has to be between these two, and should be closer to the 16.3 than the 15.5, which it is.  Clearly, the first answer submitted was wrong.  Brian made both z scores negative...
790960
Try Zaba Search - I am sure it will help you...
1146357
No. You can read about what drives your score here: http://www.myfico.com/
967537
lol...if you have to ask, you must not be too concerned with the results of the test. BTW, 2400 is a perfect score.
123406
Try Chi square testing, it starts out complicated but once you understand it, it is way faster than punnett squares! You can find all kinds of stuff about it on the internet, it's a statistical analysis.
45503
It appears to be an IQ score. Here is the mapping of scores to percentile
828638
Assuming the population is normal, to calculate the percentage of subjects obtaining 65 or below, we find the Z score that corresponds to 65:\n\nZ score \n= ( score - mean ) / standard deviation\n= (65 - 80) / 6\n= -2.5\n\nLooking up a Z-score of -2.5 in a 'table of standard normal probabilities' (or using statistical software), gives 0.0062 which is 0.62%. \n\nAs for the confidence interval.. it is 'estimate' +/- 'margin of error'\n80 +/- 1.95 * 6 / sqrt(100)\n80 +/- 1.176\nThe 95% confidence interval (78.824,81.176)\n\n(I.e we can be 95% confident that the true population mean lies between 78.824 and 81.176, and this is based our the sample of 100 subjects which had a mean of 80)
502903
4.0\n1600\n\ngood luck, mate.
666462
ZOTTF (0 1 2 3 4)\n\nNEXT:\n\nFSSENT... (5 6 7 8 9 10...)
861788
There is no accurate way to do this because too many variables are involved. You can do like I do though and run a series of tests and then average them.\n\nhttp://www.toast.net/
468763
Enjoy: I hope I only had a quick look might help?\n\nhttp://www.free-scores.com/index_uk.php3
842271
My rule of thumb is that the skewness should be less than 2 in absolute value.  Other people might have different rules of thumb.\n\nYou may find the Jarque-Bera test of interest.  It is a test for normally that uses both the sample skewness and sample kurtosis.  I have posted a link about it below.
768633
order the data: 7,9,9,11,12,13,13,13,15,19\n\nfind the Median (middle point, as there are 10 data points it's the average of the 5th and 6th): 12.5\nLower Quartile: 9 (25th percentile, median of lower half, i.e. here 3rd observation)\nUpper Quartile: 13 (75th percentile, median of upper half, i.e. here 8th observation)\nmin. observation: 7\nmax observation: 19\n\nso it's:\n\n    12.5\n9          13\n7          19
432417
LOL, are u taking data management too with z scores
366404
It all comes down to averages my friend and you would have a 2.9.  Sorry....your D hurt you.  Better do some extra credit work.  The scale is as follows for your future reference (oh, and there's really no such thing as an A+):\n\nA = 4.0\nA- = 3.7\nB+ = 3.3\nB = 3.0\nB- = 2.7\nC+ = 2.3\nC = 2.0\nC- = 1.7\nD+ = 1.3\nD = 1.0\nD- = .7\nF+ = .3\nF = 0