How do I solve this problem?(deals with angles)?
960242
Think about it this way.  A circle has how many degrees?  360.  This is 17% of the total number of degrees.  Therefore you multiply 360 times 17% (or 17/100 or .17).\n360(.17)=61.2\nTherefore the circle is going to have a section for peanuts of 61.2 degrees.  Just multiply the percentage times 360 for the size in degrees!
623818
We can find angle B by subtracting the others from 180:\n\nB = 180 - 32 - 44\n= 104\n\nThe length of the sides can be found using the law of sines:\n\n(sin A)/a = (sin B)/b = (sin C)/c\n\nSo,\n\n(sin B)/b = (sin C)/c\n(sin 104)/b = (sin 44)/20\nb = 20(sin 104)/(sin 44)\n~ 27.94\n\n(sin A)/a = (sin C)/c\n(sin 32)/a = (sin 44)/20\na = 20(sin 32)/(sin 44)\n~ 15.26
718520
D.  The angles have to add up to 180.  If 2 of the angles are the same, then the 3rd has the same.  You have to get an enclosed side to be the same for the triangles to be congruent.
367687
an angle that is inside a circle or any other figure
1108873
Here's the process you would use to solve the problem.\n\nFirst, you need to know that an isosceles triangle has two equal sides.\n\nTherefore, you have two variables in the problem\n                    x = length of leg (there are two of these)\n                    y = length of base\n\nWe know that "the length of one of the equal lengths of an isosceles triangle is 8 cm les than 4 times the length of the base."  Therefore, we can write "x" in terms of "y":\n\n                    x = 4y - 8\n\nFurthermore, we know that the perimeter is 29 cm.  Now we can set up an algebraic expression to solve for "x."\n\n2x + y = 29   (initial equation)\n2(4y-8) + y = 29 (substitution)\ny = 5 (solved)\n\nWe have the length of the base ("y").  Now we can solve for the length of one of the equal legs.  Remember from above that\n\nx = 4y - 8\nx = 4(5) - 8\nx = 12\n\nSolved!\n\nIf you are still confused, draw an isosceles triangle to visualize the problem.  Label the base "y" and the two legs "x."
733210
You basically have 2 options. Use a protractor and measure them (The internal angles total 180 degrees).\n\nThe other option is using the trig functions (Sin, cos and tan), however you must have some info on the triangle eg. length of sides to apply any of these.
1020883
i am sure you can find a math tutor that will be happy to help you when you explain what the problem is.\n\nso what IS the problem, anyway?
367886
x = 75 degrees\n\nSince all the angles must add to 360 degrees\n\n4x + 15 + 45 = 360\n\n4x = 300\n\nx = 75
962823
Can you give angle measures ?  Cant do much without those or some relationship between the other sides.
997132
Draw a picture of the two congruent sections, which are connected at B. The exact angle between them doesn't matter so long as it's not greater than 90 degrees. You will see that if AD=CD, then angles A and C are equal. So what happens as angle A gets larger and angle C gets smaller? You should be able to see the answer for yourself.
607716
If the circles are all tangent to each other, then you can draw lines from center to center to center.  Thus, you'd have a triangle with sides 8, 12, and 10 (each side is formed by adding two radii).  So you can find the angles using the law of cosines:\n\nc^2 = a^2 + b^2 - 2abcos(c)\n8^2 = 12^2 + 10^2 - 2(12)(10)cos(c)\n64 = 144 + 100 - 240cos(c)\n240cos(c) = 180\ncos(c) = 3/4\nc ~ 41 deg\n\nAnd then just change up numbers to find the other angles:\n\nb^2 = a^2 + c^2 - 2accos(b)\n10^2 = 12^2 + 8^2 - 2(12)(8)cos(b)\n100 = 144 + 64 - 192cos(b)\n192cos(b) = 108\ncos(b) = 9/16\nb ~ 56 deg\n\na^2 = b^2 + c^2 - 2bccos(a)\n12^2 = 10^2 + 8^2 - 2(10)(8)cos(a)\n144 = 100 + 64 - 160cos(a)\n160cos(a) = 20\ncos(a) = 1/8\na ~ 83 deg\n\nAnd this checks out since 41 + 56 + 83 = 180.
747766
Yes, use conservation of momentum.  The angle comes into the problem by determining how much of the total momentum is in the x and y directions.  Really, you'll be solving two different equations:\n\nm1*v1x+m2*v2x=m3*v3x\nand\nm1*v1y+m2*v2y=m3*v3y\n\nSo, find each player's initial momentum in the x and y directions, and then solve these equations to find the final x and y velocities of the group.  \n\nGood luck!
284409
Ex:\nA man stands 60 feet away from a building and sees the top of the building at a 60 degree angle. How tall is the bulding?\n \n1)Choosing an equation: (sin, cosine or tan)\nGoing to those three equations which one do we use?\nWell, we want to find the hight of the bulding (opposite b/c it is opposite the angle), so lets use tan.\n \n2)Setting the equation:\n \ntan 60 (the measure of the angle is θ) = (x) (opposite) / 60 (side adjacent to angle is adjacent)\n \n3)Press on Calculator: tan 60\n \nU should get: 1.732050...\n \n4) Multiply by 60. (b/c ur solving for x , see original equation),  \n5)Answer:  about 103.9230485\n \n6)Using 30-60-90 Triangle tricks we check our answer and find the height is 60 X (sqrt 3) which is aproximately 103.9230485 so we are right.
606300
well, think about it- how many degrees are there in ALL triangles? \n\nif you know 2 angles, you only need one more. Let's say 2 angles were 44 and 72. The two angles combined are 44+72. If you know how many degrees there are overall, you would subtract how many you have from what you know needs to be there!
812943
Let the three angles be X,Y Z with Y = 30 \n\nSince the sum is 180 we have:\nX + 30 + Z = 180 ......(1)\n\nand we are given\n X = 2( 30 + Z).........(2)  \n\nSubstituting we have (60 +2Z) + 30 +Z = 180\n\nSolving for Z we get  Z = 30 degree \naccordingly X = 180 -30 - 30 =120  \n\nAns: X= 120, Y =30 (given) Z= 30
846631
Construct meaning with a compass and straightedge? And by "adjacent" they're already at right angles? Just measure each side with the compass, move it so one leg is at the other corner, and draw a small arc approximately where the other leg extends. Do this for both sides, then the point of intersection is your missing point, and you can draw out the rectangle with the straightedge.\n\nIf the sides are not at 90 degrees, just turn one of them (measure one with the compass, draw a circle based on it, then take the two points of intersection and construct the perpendicular bisector, then take the point where that intersects....)
715400
Angle of line from horizontal position.