At the end the cyclist decelerates and comes to a stop in 5sec. what is his deceleration.?
958243
You need to know the initial speed.  Then the answer is:\n\n(v - u)/t\n\nwhere u = initial speed\n           v = 0 (final velocity)\n           t = 5 seconds\n\nThe answer will be negative because it is decelerating
864791
A.) 3.02891 seconds\nB.) 290.1 m/s\n\nTrust me... =)
995779
To all those who answered 90 mph - BE MORE CAREFUL!\n\nMath Teacher
733989
Salut,\n\nLe cyclisme. C'est le sport le plus dur physiquement car se sont des succéssions d'effort. Mais grâce à un entraînement intencif, tu peux y remédier.
661447
The difference in rates is 1 km/hr. So if they are moving in the same direction, the faster walker will be 5 km ahead at the end of 5 hours.\n\nThe sum of the distances traveled per hour is 11 km. So at the end of 5 hours of travel in opposite directions, they will be 55 km apart.
535733
no. you would accelerate to the centre then decelerate to almost the other side. then repeat traveling a bit less each time till you finally come to rest in the middle.
992106
It is opposite the direction the bicycle is moving
926411
The stop distance is not an arithmetic progression (ie it is not 40m). It is in fact a geometric progression. The stop distance is a lot lot more. Truthfully, I don't know but if you were travelling at 120 kmh and there was a truck 40m (or even 60m) in front of you when the brakes locked; you'd be dead.
985855
velocity = df(t)/dt = 4π + 4πcos(4πt)\nacceleration = dv(t)/dt = -16π^2sin(4πt)\n\nParticle is at rest when velocity = 0, or 4π+4πcos(4πt) = 0\n1+cos(4πt) = 0\ncos(4πt) = -1   The values for which cosø = -1 are ø=n(odd)π, so when\n4πt=n(odd)*π, t = 1/4*n(odd); thus for t = 1/4, 3/4, 5/4, 7/4, 9/4, 11/4 the velocity is zero\n\nThe maximum velocity occurs when cosø = 1, so the max velocity is 8π
515941
D) a skier traveling down the side of a hill\n\nThink think think. Kinetic= motion. Object has to be moving!
32712
Most regular people can coast on there bike at around 10mph. If they pedal as fast as they can they can probably reach around 20-25mph on flat land. Downhill close to 30mph. Someone like Lance Armstrong can go 30-40mph on flatland and downhill in mountains like the ones in the Tour de France can go close to 70mph. That just shows what kind of athletes are in the Tour de France.
792607
0 km/hr^2 .... because your speed doesn't change with time due to constant as you mentioned
18725
Well, I am a cyclist and this is kind of cliche, but Lance Armstrong.  The man won Tour de France for the seventh time in a row.  A very tough event which covers three weeks, more than two thousand miles, with just two days "off" which are used to travel, and through the Pyrenees and French Alps!  He and other professional cyclists train many tens of thousands of miles each year, burning around about a thousand calories per hour, lots of pain to add.  The longest stage in 2005 was over 140 miles, and mind you, the day before that stage was also over 140 miles as well.  This is with no commercial breaks, time outs, half times, substitutions, or any other sort of break other than a crash if you are unfortunate to get into one.  They even have to eat during the course of the race!  And I could go on...  Lance has this event seven times.
30694
20m/s.\nbecause the total time is 5s. and by defn of average speed it is the ratio of total distance travelled to total time taken i.e 100/5 = 20m/s
1076359
0-60 is around 2 secs, and the braking is almost as fast, so it should be around 4 secs.
160887
The insect is inside the bus, and so is moving 5 mph relative to the bus (that is what you meant right?) so:\n\na. 5 mph\nb. 55 mph, since the insect is moving 5 mph faster than the bus\nc. makes no sense since they are moving relative to each other
1014751
some guy and really far