I need help with Algebra1?
959978
use pythagorean thereom a^2 + b^2 = c^2. (c being teh longest side or the hypotenuse) the two legs are a and b. so you have the sq rt of 169. (sqrt of 12^2 + 5^2) which is 13
890645
Wow, there is a lot here!  I'll start with some tips for solving algebra problems.  The first thing you should always remember is to play the equal game.  Whenever you add, subtract, multiply, or divide, you should do the same to the other side.  The other tip is to use the order of operations when simplifying.  Remember the sentence: Please excuse my dear Aunt Sally.  The initial letters of each word stands for the order of operations.  Do the Parenthesis first, followed by the Exponents, then Multiplication or Division, and Addition and/or subtraction next.  Finally, you should always simplify first using the order of operations before you start shifting numbers from one side of the = to the other.  \n\nI'm not going to work all of these problems, but I'll show you a few to get you started.\n\n1)\n3x-7 = 2   Add 7 to both sides\n3x = 9   Divide by 3\nx = 3\n\n4)\n6x - 3 = 2x - (4-3)/3   Simplify the stuff inside the parenthesis first\n6x - 3 = 2x - 1/3  Add 3 to both sides\n6x = 2x - 5/3  Subtract 2x from both sides\n4x = -5/3  Multiply both sides by 3\n12x = -5  Divide both sides by 12\nx = -12/5\n\nI hope this helps.  Good luck!
1054627
assuming this is (3a+1)/(a^2-1) - 1/(a+1)\n\nfactorise the (a^2-1) to give (a+1)(a-1)\n\nmultiply the second fraction by (a-1)\n\n-->  (3a+1)/[(a+1)(a-1)] - 1(a-1)/[(a+1)(a-1)]\n\nfactorising this gives [(3a+1)-(a-1)]/[(a+1)(a-1)]\n\nwhich equals (2a+2)/[(a+1)(a-1)]\n\n= [2(a+1)]/[(a+1)(a-1)] \n\nthe (a+1)'s cancel out...\n\ntherefore = 2/(a-1)
926616
2x+3<6x-1\n2x-6x<-1-3 \n-4x<-4\nx>1
837436
Your Algebra teacher is trying to kick your butt, right?  I have the answer:\n\nReorder the terms:\n3+64x+16x^2=0\n\nStart with the 16 - divide all numbers by 16\n\n3/16+64x/16+16x^2/16=0/16\n\nResults are:\n\n.1875+4x+ x^2=0\n\nNot done yet...Next, take out the .1875.\n\n.1875+(-.1875)+4x+x^2=0+.1875\n\nResults from this calculation:\n\n4x+x^2=-.1875\n\nThen, add a 4 into the equation\n\n4+4x+x^2=-.1875+4\n\nAdd like terms:\n\n4+4x+x^2=3.8125\n\nThen, you need to factor the problem out.\n\n(x+2)(x+2)=3.8125\n\nTake the square root of 3.8125\n\n=1.952562419\n\nAfter that, take one of the factors you created above and use the square root to arrive at the answer...one positive, one negative\n\n2 + x = 1.952562419\n\nx = 1.952562419 - 2\n\nx = -.0474437581\n\nand\n\n2 + x = -1.952562419\n\nx = -1.952562419 - 2\n\nx = -3.952562419\n\nx = (-.047437581, -3.952562419)\n\nYou might have to plot that on a graph.  You have just calculated a point of off the x axes...the horizontal line.\n\nHope that helps. Maybe someone can give you fewer steps.
795656
The first thing you should remember is the phrase PEMDAS.  This is shorthand for parenthesis, exponents, multiplication/division, and addition/subtraction.  This is the order of operations in math.  You should solve all equations in this order.  So for the first one, you should first distribute (multiply) -7 with (3-3x).  After that combine like terms, i got 25x -30; you can also factor that to be 5(5x-6).  The same steps apply for the rest of the problems.  I hope it helps.
796585
1.factor\n(2x+1)(x-4)=0\n2.set it to 0\n2x+1=0\nor\nx-4=0\n3.solve\n{x=-1/2 or x=4} <=answer
607013
Another Method.\n\n-1 = -1\n\n-1/1 = 1/-1\n\nSquare root both sides,\n\nSQR(-1/1) = SQR (1/-1)\n\nExpanding,\n\nSQR(-1)/SQR(1) = SQR(1)/SQR(-1)\n\nSQR(-1)/1 = 1/SQR(-1)\n\nCross Multiply,\n\nSQR(-1)*SQR(-1) = 1\n\n(SQR(-1))^2 = 1\n\n-1 = 1\n\nDivide by 2 on both sides,\n\n-1/2 = 1/2\n\nAdd 3/2 to both sides,\n\n-1/2 + 3/2 = 1/2 + 3/2\n\n1 = 2 (ans)
1056171
Try www.purplemath.com it shows you how to work out problems step by step
1169576
Try:\n\nhttp://www.sosmath.com/cyberexam/algebra/q001/1/1.html\n\nhttp://www.math.com/practice/Algebra.html\n\nhttp://www.glencoe.com/sec/math/studytools/prealglblr.shtml \n\nhttp://www.syvum.com/squizzes/algebra/
1089643
http://www.algebra.com
1174364
2(x -1) + 3 = X – 3(x + 1)\n2x-2 +3 = x - 3x-3\n2x + 1 = -2x -3 \n2x + 2x = -3 - 1\n4x = -4 \n4x/4 = -4/4 \nx = -1 \n\nTo check your answer plug -1 in the place of x in the main equation:\n2(-1-1) + 3 = -1-3(-1+1)\n-4 + 3 = -1 \n-1 = -1\nThus x = -1 is the correct answer.
602488
1-x = -(x-1)\nx^3 - 1 = (x-1)(x^2+x+1)\nAnswer: -(x-1)(x^2+x+1)
330568
ask a question! I can help! maybe... yeah, pretty sure I can, I'm in Algebra 2!
655260
2=-1=x\n2+1=x\nthere fore x =3
701654
Instead of memorizing all the equations,understand how they are derived.Try to do it yourself.If you can't go to someone who knows for help.
456792
www.algebra-online.com\nwww.sosmath.com/algebra/algebra.html\nmathworld.wolfram.com/topics/Algebra.html\nmathforum.org/algpow\nhttp://education.yahoo.com/homework_help/math_help/chapter_list?id=minialg1gt\nwww.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra\nmath.about.com/od/collegealgebra\n\nGOOD LUCK!! :) Happy studying!