Math Word Problems Help?
958710
1) \nSB takes 3 hours to do the job.\n\nfraction of job done by SB in 1 hr = 1/3\n\nSimilarly Fraction of job done by SW in 1 hr = 1/2.5 = 2/5\n\nFraction of job done by both SB and SW in 1 hr = 1/3+2/5 = 11/15\n\nNow Both SB and SW can finish the job together in : 1 / (11/15) = 15/11 = 1.36 hrs.\n\n Shortcut:\n\n1 / (X and Y together) = 1/ X + 1 / Y\n\n2)\n\nNow when Mark and his agent meet they would have covered the 500 Kms together as they \n\ntravel the same road to meet each other.\n\nsuppose after x hrs they meet.\n\n\nMark has travelled : 55x km\nAgent has travelled : 65x km\n\nTotal distance : 55x + 65x = 500\n\n120x = 500 => x = 500/120 = 4.167 hrs\n\n3) Use the same approach as in 1) above.\n\nUse the shortcut too if u need.\n\n1/ ans = 1/12 + 1/9\n\nand find the ans!\n\n4)\n\nLet the cost of the pencil be x.\ncost of pen = 3x\n\n5 * x + 4 * 3x = 4.25\n17x = 4.25\nx = 0.25\n\nSo pencil costs 25 cents!\n\n\nHope the above answers help! Do let me know if they dont! :-)
737022
A "word problem" is actually a math problem stated using actual words (as in english, japanese, etc) instead of mere mathematical symbols (2, -6.25, x, y, + , / , z, etc). More often than not, word problems relate mathematical concepts to real world situations, for example, instead of just saying x - 5, one could phrase this as "my height is 5 inches less than yours". In a word problem, a person's objective is to translate the words into mathematical symbols so that he/she will come up with an equation or inequality or systems of equations or inequalities and then solve these. So, yes, word problems have to do with words AND mathematics. That's what make them sooooo interesting!
821450
go to a math website off yahoo. it should help.
268070
Check out this site. It gives you a few examples. It was helpful for my cousin when she was leaning how to do them.\nhttp://www.purplemath.com/modules/solvelin.htm
760269
"d" is the answer.\n\nGet an "A".
855129
Word problems like this can be hard.  Everybody has problems with them sometimes.\n\nIt does help to draw it out.  So you draw a little rectangle like this:\n ______________\n|                            |\n|                            |\n|______________|\n\n2 of the sides are 120 m and the other 2 are 150 m.  So you take 2 times each of these numbers and add them together:\n2(120) + 2(150)\n\nThat's your perimeter, in meters.  Now if your poles are 2 m apart, you don't need one for every meter you get in your answer, you only need 1 every 2 meters.  So you divide your answer by 2, and that gets your number of poles you need to put around the field.
395445
Your looking for the time they work together so let (x) the time they work together .the rate should be A=15,B=5 then the work should be A=x/15 and B=x/5 since your looking for the time...solve for it cause I'm not giving you all the answers. it should look like this \n\nx/15+x/5= the time they work together...\n\n(Next time listen to your teachers)
299847
Check out the site below.  It has an example in numbers and words.  It's too hard to explain just in words.  Good luck.
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
1013473
1) 120 words\n\n2)12345 (these represent teh letters) first make all the words with 1 at teh beginning then 2 then 3 and so on
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
646947
1. A & B cross  -  2\n2. A returns    -  1\n3. C & D cross  -  10\n4. B returns    -  2\n5. A & B cross  -  2\n\nTotal minutes: 17\n:)
1056171
Try www.purplemath.com it shows you how to work out problems step by step
1127430
try this one http://www.algebrahelp.com/
906875
The trick is turning the word problem into equations.\n(Key: length = l; width = w)\n\nThey tell you the length is 3 feet more than twice the width, so:\nl = 2w + 3\n\nThen they tell you the perimeter (which is twice the width and twice the length) is 36, so:\n2l + 2w = 36\n\nYou should be able to take it from there.
795870
5) W = M + 6, W + M = 30\n\n6) x + (x + 1) + (x + 2) = 153\n\n7) 5x = 3(x + 2) + 14\n\n8) x + (x + 2) + (x + 4) = 54\n\n9) Rate = 356, Distance = 1424\n1424 = 356 * Time
609300
This is more of a word problem or a riddle than a math problem.\n\nThe answer is 7 (SEVEN).  Remove its first letter and it becomes EVEN!