find square root in radical form?
964858
That just means that keep it in the square root instead of simplifying it.\nEx: Keep it as square root of 2 instead of 1.414\n\nSo if you're finding the square root of 27, for example.  You can split up 27 into 9*3.  Square root of 9 is 3, but 3 is not a perfect square.  So your answer would be : 3 square root of 3.  Instead of 5.196
1010349
Hi:\n\nI know of six ways to find a square root of a number:\n\n1) Take the logarithm of number and divided by 2 take the result and take the Antilog \n\n2) Use the School boy method of extracting a square root see this website for how :\n\nwww.nist.gov/dads/HTML/squareR...\n\n3) Use the following method ( example on the bottom of page ):\n\n(N/gn+gn)/2= gn\n\nN= number to be Square root \ngn = Guess number or Square root\n\nrepeat this for about about 5 to 10 times ( see example)\n\n4) Use trail and error by running a number value and Square it\n\n5) Graph and interpolarite it\n\n6) Look it up in a Mathematical hanbook of tables and formulas and look under Square & square roots tables.\n\n------------------------------...\n\n\n\nExample:\n\nThe square root of 27:\n\n(27/5+5)/2= gn\n\n\n(5.4+5)/2 = gn\n\n10.4/2= gn \n\n5.2 =gn \nend of run 01 \n\n(27/5.2 + 5.2)/2= gn\n\n(5 + 5.2)/2 = gn\n\n10.2/2= gn \n\n5.1= gn\n\nend of run 02\n\n((27/5.1)+ 5.1) /2= gn\n\n(5.294117647+5.1)/2 = gn\n\n10.394117647/2 = gn\n\n5.197058823 = gn\n\nEnd of run 03\n\n(27/ 5.197058823) + 5.197058823 )/2 = gn\n\n(5.195246179+ 5.197058823 )/ 2 = gn\n\n10.392305003/2 = gn\n\n5.196152501 = gn\n\nEnd of run 04 \n\n((27/5.196152501)+ 5.196152501)/2 = gn \n\n(5.196152343+5.196152501)/2 = gn\n\n10.392304844/2 = gn\n\n5.196152422= gn \n\nEnd of run 05\n\n((27/ 5.196152422) + 5.196152422 )/2 = gn\n\n(5.196152422 + 5.196152422 ) /2 = gn\n\n5.196152422 = gn \n\nEnd of run 06\n\nSquare root of 27 appoximatily = 5.196152422 ( accurate to 9 decimal places.) \n\nSource(s):\n\nwww.nist.gov/dads/HTML/squareR...\n\nwww.du.edu/~jcalvert/math/sqrt... \n\nmathforum.org/library/drmath/v...
923840
Here's how I would do it:\n\nTo remove the sqrt, you square both sides:\n\nsqrt(p^2 - 3p + 16) = (p+1)(p+1)\np^2 - 3p + 16 = p^2 + 2p + 1\n\nThen it's basic algebra. The p^2 are out of there, and you are left with\n\n-3p + 16 = 2p + 1\n16-1=2p+3p\n15=5p\np=3\n\nSo, let's check:\nsqrt(3^2 - 3(3) + 16) = 3+1\nsqrt(9-9+16)=4\nsqrt 16 =4\n\nThe person who put -5 as one of the answers... it doesn't work:\n\nsqrt ((-5)^2 -3(-5) + 16) = -5+1\nsqrt (25+15+16)= -4\nsqrt 56= -4 This is false, so -5 is not an answer.
225517
Well... if I understand your question, it isn't a square root any more. If you have what looks to be a square root sign:\n√¯\nwith (for example) a three over the first little squiggly part, then it would be called a cube root. Any number under the radical sign (root sign) would then have it's cube taken. \n\nFor example, the number 8 under a cube root would be 2, because 2*2*2=8, or 2^3=8.\n\nIf you simply mean that there is a number in front of the square root:\n9√¯\nthis just means that you take the square root and then multiply it by 9. So the number 4 under a square root with a nine in front would be:\n2(the square root of 4)*9=18
597652
The square root of 1 is 1.\nsqrt(6.6) = 2.569\nsqrt(15) = 3.873
857476
When working with the simplification of radicals you must remember some basic information about perfect square numbers. \n\nYou need to remember:  \n\nPerfect Squares \n4 = 2 x 2 \n9 = 3 x 3 \n16 = 4 x 4 \n25 = 5 x 5 \n36 = 6 x 6 \n49 = 7 x 7 \n64 = 8 x 8  \n81 = 9 x 9  \n100 = 10 x 10 \n \n Radicals (square roots) \n = 2 \n = 3 \n = 4 \n = 5 \n = 6 \n = 7 \n = 8 \n = 9 \n = 10 \n \n \n\nWhile there are certainly many more perfect squares, the ones appearing in the charts above are the ones most commonly used. \n\n \n\nTo simplify means to find another expression with the same value.  It does not mean to find a decimal approximation.\n \n\n \n\nTo simplify (or reduce) a radical: \n\n1.  find the largest perfect square which will divide evenly into the number under your radical sign.  This means that when you divide, you get no remainders, no decimals, no fractions.\n\nReduce:  the largest perfect square that divides evenly into 48 is 16. \nIf the number under your radical cannot be divided evenly by any of the perfect squares, your radical is already in simplest form and cannot be reduced further.\n\nwrite the number appearing under your radical as the product (multiplication) of the perfect square and your answer from dividing.\n\n\n \n\n3.  give each number in the product its own radical sign.\n\n\n \n\n4.  reduce the "perfect" radical which you have now created.\n\n\n\n5.  you now have your answer.
766787
If this is a problem in a math class, the answer provided by abcde12345 is correct. He shows you the technique to simplify it, which is to multiply numerator and denominator by the "conjugate" of the denominator (which just means you change the sign of the square root part, so you get (3 - sqrt(5)).\n\nIf this is a problem in physics or some other class, and all you need is a value, then follow the suggestion of some others who recommend using a calculator.
981873
-7 and -sqrt49\n\nYou can not take a square root of a negative number. Well, you can, but it's called an imaginary number because it can't actually exist.
1029855
D\n\nSeriously, what class are you in? Algebra? Geometry? You chould know this!! It's the pythagorean theorm- [a2 +b2 =c2] (2's = squared).  You have a and b, the two adjacent sides of the triangle.  Therefore, it is the square root of 50, or approx. 7.07.  Thats SUPER important, make sure you remember it!
879678
The first thing to do is to find the factors of the number you're taking the root of.\nFor example, teh factors of 24 include 2*12, 3*8, and 4*6.\nSince four is a perfect square (2^2), we'll use that set of factors.\nSo:\nsqrt(24)= sqrt(4*6)= sqrt(4)*sqrt(6)= 2sqrt(6)\n\nSame with sqrt(18):\n18=9*2\n9=3^2\nsqrt(18)= sqrt(9)*sqrt(2)= 3sqrt(2)\n\nsqrt(3) +sqrt(3) can only be reduced by realizing that it's\n2*sqrt(3), which could be the sqrt(12). THis is because you can take the two under the radical by squaring it. so  you get sqrt (2^2+3)= sqrt(12), but technically 2sqrt(3) is more reduced.\n\nsqrt(27)=3 sqrt(3)\nsqrt(12)= 2 sqrt(3)\nso 3sqrt(3) + 2sqrt(3) = 5sqrt(3)\nin this case, you're treating the sqrt(3) sort of like it was a variable. think of 3x +2x = 5x
966435
square root of 40.5 = 6.363961.\n\nAnd for the future.... http://www.calculator.com/
78107
what is the square root of orange?
832801
Completing the square involves adding constants to both sides of your equation so you have a form:\n\n(x - a)^2 = b\n\nOnce you get this form, you can take the square root of both sides:\n\nx - a = sqrt(b)\n\nx = a + sqrt(b) \n\nSince a square root can be either positive or negative, it is just as correct to write:\n\nx = a - sqrt(b)\n\nNow, back to the original "perfect square"\n\n(x - a)^2 = b\n\nExpanding this out:\n\nx^2 - 2*a + a^2 = b\n\nMoving b to the other side:\n\nx^2 - 2*a + a^2 - b = 0\n\nYour equation is 2*x^2 - x - 2 = 0\n\nForst thing is to get plain x^2, so divide by 2:\n\nx^2 - (1/2) * x - 1 = 0\n\nNow from the form above, a = 1/.4 because 2*a = (1/2)*x\nNext, look at the constant term: \n \n-1 = a^2 - b\n-1 = (1/4)^2 - b\n\nSolving for b: b = 17/16\n\nSo your perfect square equation is:\n\n(x - 1/4)^2 = 17/16\n\nSolving for x:\n\nx - 1/4 = sqrt(17/16)\n\nx = 1/4 + sqrt(17/16)\nx = 1/4 - sqrt(17/16)\n\nSimplifying slightly:\n\nx = (1 + sqrt(17))/4\nx = (1 - sqrt(17))/4
535859
all radicals can be expressed as rational exponents. the roots of all radicals be expressed as denominators of exponents. a regular exponent will be the numerator of the exponent.\n\na regular x has an exponent of 1,  x = x^1\n\nso, for example, the square-root of x (√x) can be rewritten as:\nx^(1/2)\n\nthe cube-root of x (3√x) can be rewritten as:\nx^(1/3)\n\nthe cube-root of x^2 (3√(x^2)) can be rewritten as:\nx^(2/3)\n\nand so on\n\nthis is why the square-root of x^2 = x, becuase\n= x^(2/2) = x^1 = x
1012665
if the multiplication involves the same radical, (squarel root, cube root, etc.) then that is equal to the product of the radicals\nie sqrt(5) * sqrt (2) = sqrt(10).\n\nif they are different radicals, then it is more difficult. the only way is to change the radical to the same radical through manipulation of the number/radical.\n\nfor example 4 * sqrt (2) = sqrt (4^2) * sqrt (2) = sqrt (16) * sqrt (2) = sqrt(32).
546400
D=square root ((x1-x2)^2 + (y1-y2)^2)
974343
√50 + √72 - √8\n√(25*2) + √(36*2) - √(4*2)\n√25√2 + √36√2 - √4√2\n5√2 + 6√2 - 2√2\n9√2