Help me what the difference between solving this |2b + 9|, why this one requiers simple and this one......?
954759
The || signs represent absolute value. This is a term that means the distance of a number on a number line to zero. Absolute value is thus always positive. For example, |2| = 2 and |-2| = 2.\n\nFor equations where you are solving for a variable and one side is absolute value, you must solve the variable so it can equal both the negative and positive values. Using the example above, this means we have to set the equation so that x+3 equals both 4 and -4. This is because regardless of the negative or positive part, it will change into 4 because it is absolute value. Here is how you do it:\n     |x+3| = 4\nx+3=4\nx=1\nThats the normal way, as if there were no absolute value marks.\nBut we have to account for the negative part too:\nx+3=-4\nx=-7\n\nNow to prove this is true:\n         |x+3|=4\n|(1)+3|=4\n|4|=4\nThe negative too:\n|(-7)+3|=4\n|-4|=4\n\nI don't know how the second equation would work, partially because I don't know the full equation. Perhaps you meant |2b+9|=0 ? Otherwise, you can't do anything further. I hope I explained it well.
965967
The twos being subscripts simply means you are using binary notation. In binary computation it is only necessary (for addition) to remember that 0 + 0 = 0,------0 + 1 = 1---------and 1 + 1= 10.\n\n                                    10011\n                                  +  1110\n                                  ________\n\n                                   100001\n\n\nIn the right column, 1 + 0 = 1\nIn the next column1 + 1 = 10. Put the zero down, carry the 1\nIn the next column1 + 1 = 10. Put the zero down, carry the 1\nIn the next column 1 + 1 = 10Put the zero down carry the one\nIn the next column 1 + 1 = 10Put down the 10
365207
|b+3|<=4 means\n-(b+3)<=4 and so b=-7 which is smaller than the value b=1\n\nYou have to consider the smaller value when you have 2 options as per the question.\n\nModulus means both + and minus.\n\n|7| means + or - seven.\n|b+3| means + or - (b+3).\nYou gotto consider the smallest of two in the question...and so go for the negative value which givews you b=-7.
976886
It is a difference of two squares, in the form a^2-b^2\n\n\nTake the square root of both terms, which will be 3k and 5b.  Then write them in the form\n\n(a-b)(a+b)\n\nYour factored form will be \n\n(3k+5b)(3k-5b)
373987
of cos!\n\n9*9 + 9 + 9 + 9/9 + (9-9)9
888151
Basic math/algebra. You are taking two known numbers and finding the unknown number. \nE=P/I  solve for I    Think like simple Algebra I is X. So you want to work the problem and get a final answer x=?  or   I=?\nHope this helps.
970698
(a + b)(c + d + e)\n= a(c + d + e) + b(c + d + e)\n= ac + ad + ae + bc + bd + be\n\nOR\n\n(c + d + e)(a + b)\n= c(a + b) + d(a + b) + e(a + b)\n= etc.
535346
I'm not sure if this is the whole question, but I will interpret it as if it ended with a ) in place of the [exp...\n\n9(x^3)N - 12(x^4)(N^2) - 9(x^2)N
134065
Your statement translates to the following algebraic equation.\na+b=a-b=a*b\nSolving a+b=a-b, we get b = 0; \nSubstituting b=0 and solving a+b=a*b, we get a = 0;\nSo the two numbers are zeroes.
340285
-12b + b^3 + 3b = 0 (multiplying the two vectors together)\n\nb(b^2 - 9) = 0\n\nb(b + 3)(b - 3) = 0\n\nso b=0 or b=3 or b=-3
732994
99=3*3*11\nab=a*b\nso 99ab=3^2*11*a*b
750843
you cannot divide by 0 = a-b\n&#92;
777394
factor out 4b\n\n4b(b-2)= 0\n\nb = 2, 0\n\ngoodluck ^_^
658148
given 4a^2-12ab+9b^2\n    =(2a)^2-2(2a)(3b)+(3a)^2\n    =(2a-3b)^2
714877
b)\n\nNote that 314159266 is of the form 4k + 2, where k is an integer.  Since any integer is of the form 2n or 2n +1, this means that all squares of integers are either of the form 4m or 4m + 1.  No matter how we try to do the subtraction of two numbers of the form 4m or 4m + 1, we won't get a number of the form 4k + 2:\n\n4m - 4n = 4k\n4m - (4n + 1) = 4k + 3\n(4m + 1) - 4n = 4k + 1\n(4m + 1) - (4n + 1) = 4k.\n\nCheers!
285967
ANSWER : 459 + 495 = 954\n\n ABC\n+ACB\n ---\n CBA\n\nNotice the second column, C has to be either 0 or 9. But it can't be 0, since CBA is the sum, two three-digit numbers can't add and become a two-digit number. So, C = 9\n\n AB9\n+A9B\n----\n 9BA\n\nNow look at the first column. Obviously, 2A = 9 doesn't have any integer solutions, so there must be a carry there. So, 1 + 2A = 9. Therefore, A = 4.\n\nThen you can solve for B, since 9 + B = 4 doesn't work, there's a carry there as well. So, 9 + B = 14, and therefore B = 5.\n\nEDIT : Flavio, except that the question says that "A B & C stand for 3 different digits" ;)\n\nThere is an easy solution is Base 4 though :\n\n123 + 132 = 321
87985
The expression was not set equal to anything.\n\nIf you're doing simple factoring in algebra class, the \nsimplest factors would be (b+4) (b+3).\n\nIf the expression was set to equal 0, solve for b, then your answer set would include -4 and -3.\n\nHope this helps!