AP Physics B Free Response Answers?
955493
that's cuz it is guarded like a hawk.  u can't find what is not there.  AP is proprietary which means the board is in complete control of present and past tests and answers.
198521
Well i am taking physics class this semester and we have to use websit to do our home work so please go to\n\n\nwww.masteringphyiscs.com\n\nyou will find all the topic for physics 1, 2 and 3...\nif you need help to search for the any topics than contact me...
966112
u can consult ur physics book
533021
there are some solved physics problems on \nhttp://www.dctech.com/physics/help/\nbut I don't know if it will help you out.
640955
Look in your AP WH book and look for the link that distributes the book. They should have like alot of free response examples and other little things to help you.\n\nAnd if youre taking the AP exams which give you college credit I suggest you buy a booklet that goes over the format and questions that are most likely to be on the exam.
809599
Free online physics tutoring that is available at all times? Hmmm... Yahoo Answer is probably the closest thing to what you're looking for...but there is no guaranteed that your question will get answered, or that the answers are any good. And even if someone does give you the right answer, there is no way for you to tell the right ones from the wrong ones.
1102357
http://www.physicsforums.com/\n\nNothing is more useful than discussing physics with other people.
961153
Ask your physics teacher.  There should be one in the school.  \n\nDon't be too surprised if they're keeping the latest one for the mock!\n\nI'm sure they'll have some old papers for you to work through.\n\nGood luck for the exam!
839721
sorry, if my mother was still alive - chemist/physics major, then she could have helped... try this site:\n\nhttp://chemistry.about.com/
1006142
Here's a great source of free books (audiobooks as well):\n\nhttp://www.gutenberg.org\n\nHere's some other links I've collected over time:\n\nhttp://totallyfreemath.com/math.html\nhttp://spot.colorado.edu/~dubin/bookmarks/b/1240.html\nhttp://www.math.gatech.edu/~cain/textbooks/onlinebooks.html\nhttp://www.physicsforfree.com\nhttp://www.lightandmatter.com/area1book1.html
1166211
I do not know you that well yet...............\n\n\nHow about a physics question or something challenging?
917347
It sounds like you know what to do.  From your description, it looks like a basic statically determinate problem.\n\nYou have a known applied force P, and two unknown reaction forces, lets say A and B for the top and bottom reactions respectively.  You also have two equations of static equlibrium, specifically the sum of the forces in the "x" direction, and sum of the moments about any point you wish.\n\n(Ok, really you also have the force of gravity and the normal force, but those are the only forces in the "y" direction so that equation won't help you, especially since the mass or weight isn't given).\n\nAssuming to the right is positive, assume A is to the left and B is to the right (this is intuitive, but if directions are incorrectly assumed the answer will just have a negative sign, thats all).\n\n                    _ ------------> P\n                    |   |\n                    |   |\n                    |   |     10.5 m\n                    |   |\n                    |   |\n                    |   |\n                    |   |<----------A\n                    |   |\n                    |   |       1.5 m\n                    |_|--------------> B\n                    \n                 (FBD!)\n\nSum of forces in "x" gives: P - A + B = 0\nSum of moments about B: A(1.5) - P(12) = 0\n\nI took moments about an unknown reaction, B, to eliminate it.  Also, I assumed counter-clockwise to be positive.\n\nSubbing in the value of P = 5.40 N into the second equation:\n\nA = (5.40*12)/1.5 = 43.2 N\n\nThen, put that into the first equation:\n\nB = A - P = 43.2 - 5.40 = 37.8 N\n\nThat should do it.  Both come out positive because their assumed directions were correct, however on the Free-Body-Diagram they are in opposite directions necessary for equilibrium.\n\nCheers,
757859
haha, k  Draw a picture and draw a free-body diagram.\n\nI don't feel like busting out a paper/pencil  so I'll try it in my mind\n\nF(sub g) cos Theta  =  Mg cos(20 degrees)\n\nbecause the Normal force is equal to the y-component of gravity.\n\nTwo similar triangles, the incline and one which has the Force of gravity straight down, and the y compentn equal opposite of the normal force, and X component equal opposite to F\n\n\nlots of physics i'm skipping in my explanation tho
871072
since its you science homework the answer your more than likely looking for is Newton meter, now its up to you to find out what you can on it
735831
Did you put your entire homework assignment on here? I noticed you posted a bunch of science questions just now.\nIf you don't have your textbook handy [you really should be looking up these answers so that you can remember and understand them when you have your test/exam], go to the links below and look them up. The 1st is a down loadable physics textbook. The 2nd has animations of physics.
362696
The only link you need:\n\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html\n\nHint:  look under "Mechanics"
898375
I know the answer is in my basic physics book.  I would have to look it up.  You should too.