make up a Word problem for 4(3x - 5) = 5(2x + 4)?  ~again~?
952102
two times of 'x' if increaed by four is equal to 4/5th of three times of 'x' after lowering by 5
681236
Multiply each term in the first () by each term in the second ():\n\n2x times 2x = 4x^2\n2x times 1 = 2x\n-3 times 2x = -6x\n-3 times 1 = -3\n\nThen combine 2x and -6x\nAnswer: 4x^2 - 4x - 3
889666
5(x-1)=2(x+3)\n5x-5=2x+6\nadding -2x+5\n3x=11\nx=11/3 or 3 2/3\notherwise\n5(x-1)=2x+3\n5x-5=2x+3\n3x=8\nx=8/3\n=2 2/3
968026
I got   3(x² - 5x + 4) or 3( x - 4 )( x - 1 )\n\nLet me show you my work...\n\n3( x - 2 )² - 3(x - 2) - 6\n\nSimplify\n\n3( x -2 )( x - 2 ) - 3( x- 2 ) - 6\n\nDistribute\n\n3( x² - 4x + 4) - 3x + 6 - 6\n\nDistribute and Simplify\n\n3x² - 12x + 12 - 3x\n\nSimplify\n\n3x² - 15x + 12\n\nYou can now simplify by factoring out 3\n\n3(x² - 5x + 4)\nor\n3( x - 4 )( x - 1 )
981023
Problem: 4(3c + 1) = -(5-c)\n\nFirst step is to distribute.\n     4(3c) and 4(1) = 12c + 4\n     -(5) and -(-c) = -5 + c (negative times a negative is a positive)\n\nStep #2: Write out the new problem.\n     12c + 4 = -5 +c\n\nStep#3: Get the variables to one side.\n      12c +4 = -5 + c\n         -c                   - c\n--------------------------------\n      11c +4= -5\n              -4      -4\n----------------------------\n       11c = -9\n\nStep#4: Divide:\n       11c = -9\n      -------   ------\n        11       11\n         c = -9\n               -----\n                11
458594
you subtract like terms.  \n5x^2 - 9x^2 = -4x^2\n-3x - (-5x) = -3x+5x = 2x\n6 - (-3) = 6+3 = 9\n\nTherefore, the final answer is -4x^2 +2x +9
859187
I'll do one for u.\nIn the first,\nMultiplying both sides by x*,we get\nx+3x+2x*=7x*\n4x+2x*=7x*\nMoving 4x and 2x* to the R.H.S.\n5x*-4x+0=0\nThus 5x*-4x=0\nAttempt the others in the same manner.
19519
=3(5+4x)-3x(5+4x)\n=15+12x-15x-12x^2\n=15-3x-12x^2
227193
∫[(2x^4) - (4/x^5)]dx=\n\n∫(2x^4)dx - ∫(4/x^5)dx=\n\n2∫x^4dx - 4∫[x^(-5)]dx=\n\n2*[x^5/5] - 4*[x^-4/-4]=\n\n(2/5)x^5 + x^-4 + C=\n\n(2/5)x^5 + 1/x^4 + C
895464
Don't panic, you can do this...\n\nJust start by distributing the numbers through the parentheses:\n5(2x-3)=2(-3x-2)+5\n10x - 15 = -6x -4 + 5\n\nNow group letters on one side and numbers on the other, start by adding 15 to both sides:\n10x = -6x - 4 + 5 + 15\n10x = -6x + 16\n\nNow add 6x to both sides:\n10x + 6x = 16\n16x = 16\n\nNow divide both sides by 16:\nx = 1\n\nIf you did it correctly, you should be able to plug x = 1 back into the equation and get a valid statement:\n\n5(2(1) - 3) = 2(-3(1) - 2) + 5\n5(2 - 3) = 2(-3 - 2) + 5\n5(-1) = 2(-5) + 5\n-5 = -10 + 5\n-5 = -5 <-- check\n\nSo x = 1 is the correct answer.
608409
x=34\n\n5[x-4{1-2x]-6}-3{x+10}=40x-12\n5[x-4+8x]-6-3x-30=40x-12\n5x-20+40x-6-3x-30=40x-12\n42x-80=40x-12\n2x=68\nx=34
607838
where is the rest of the equation?\n\n2x+5-x+3x+2-2x+5x-3x+8-4x+2+1x\n\nCollect like terms:\n\n2x-x+3x-2x+5x-3x-4x+1x+5+2+8+2\n\nRelocate the terms:\n\n1x+2x+3x+5x-x-2x-3x-4x+5+2+8+2 = 37\n\nAdd like terms:\n\n11x - 10x + 17 = 37\n\nNow, subtract all terms and solve from there.\n\nx + 17 = 37\nx = 20
1006262
Rearrange the equation so that the variable (in this case x) appear on one side and rest on the other.\n3x + 4 = 9 - 2x\n3x+2x +4 = 9-2x+2x  [adding 2x to both sides]\n5x + 4 = 9\n5x +4-4 = 9-4 [subtracting 4 from both sides]\n5x = 5 \n5x /5 = 5/5 [deviding both sides by 5]\nx = 1
766358
4(4)+2x7-(5x4-15)\n4x4\n16+2x7-(5x4-15)\n2x7\n16+14-(5x4-15)\n5x4-15\n16+14-5\n16+14\n30-5\n25=answer\n\n(b)-2bc+c(c)\n-2b^2c^3=answer\n\n2x-2-5x4/4+3x-1\n-4-20/4+-3\n-4-5+-3\n-2=answer
733063
5x^2-35x+3x-21\n5x^2-32x-21
488956
Similar to your other question, add them up and divide by the number of expressions.  The shortcut is to take the average of the x-terms and the average of the numbers.\n\nx-terms:\n(5x + 3x + 2x -2x)/4 = 8x/4 = 2x\n\nnumbers:\n(-2 + 1 + 0 + 5)/4 = 4/4 = 1\n\nSo the answer is:\n2x + 1\n\nP.S. Don't forget to add 0 for the 2x equation... and don't accidentally divide by 3... you must divide by 4.
316989
2x-5=3x+6\n2x=3x+6+5\n2x=3x=11\n-x=11\n\nx=-11