Please help I have trouble to solve this problem ->simplify: (4-i)(5+i)?
954343
Use FOIL and multiply this out just like you would any other algebraic problem, and recall that i² = -1 when solving:\n\n(4-i)(5+i) = \n\n4*5 + 4i - 5i - i² = \n\n20 + 4i - 5i - (-1) =\n\n21 - i\n\nANSWER:  C. 21-i
137681
Ok...\nI see what you are doing...\nYou merely substitute the number in for x...\nso the problem becomes 6-2*(-1)\n6+2\n8
775644
Duch, there's some confusion over what the problem is.  It could be a/(3+4b) - a/(3+b)  OR  a/3 +4b -a/3 -b\n\nIf the former, then it boils down to -(11ab)/(9 + 15b + 4b²)\n\nIf the later, 3b
545883
(a^2  - 5) * (a^2  - 2)
1174662
2(x-4y+1)+3(-2+y-2)\n2x-8y+2-6+3y-6\n2x-8y+3y-6-6\n2x-5y-12\n\n2x-5y-12= answer\n\nHope this helps you.
528350
(5x + 4)(6x + 4)\n30x^2 + 20x + 24x + 16\n30x^2 + 44x + 16\nANS : 16
1062229
Technically there are only 4 answers that will work, and they all rely on parentheses to modify the natural precedence rules:\n\n(5+5/5)*5\n(5/5+5)*5\n5*(5+5/5)\n5*(5/5+5)\n\nAs you can see they are all variations on (5 + 1) * 5, where you use 5/5 = 1.  So there is really just one answer.\n\nYou can easily solve problems like this yourself using the link below...\n\nFor example, can you make 24 using 3, 3, 8, 8?  Try it before you cheat... also, note that the solver allows % (mod) as an operator, so you may have to filter out those results.
541499
2x(x-5)-3(2x+1)\n2x^2-10x-6x-3\n2x^2-16x-3
572398
first multiply i by everything in the first bracket.\nso -8i * i + 3 * i + 2(2-5i)\n\nthen do same with 2nd bracket\nso -8i^2 + 3i + 2*2 - 5i*2\n= -8i^2 + 3i + 4 - 10i\n\nnow collect all the like terms\n-8i^2 + 3i - 10i + 4\n= -8i^2 - 7i + 4\n\nnow if i is the imaginary number i^2 would be -1.\nso it would be 8-7i +4 = 12-7i\n\nhope that helps. laterz
51216
x = [-(-4) +/- root((-4)^2 - 4x1x(-5))]/2x1\n  = (4 +/- 6)/2\n  = 5 or -1
889891
~..-8,-6,-4,-2,0,2,4,6,8
346216
4p+9+(-7p)+2\n\nGroup the p's and the numbers\n\n(4p - 7p) + (9 + 2)\n\nSimplify\n\n(-3p) + (11)\n\nANSWER : -3p + 11
599219
you have to solve the ones in the brackets first. so in this instance, 4(-1) = -4.\n\nand then, you solve -4 - 3 = -7
788016
5+4=9\n-5+4=-1\n4+(-3)=1\n4-(-3)=4+3=7\nhope that helps!!
123892
3(x – 2)^2 – 3(x – 2) – 6\n3((x-2)^2 - (x-2) -2)\n3(x^2-4x+4-x+2-2)\n3(x^2-5x+4)\n\n3(x-4)(x-1)\n\nYay!!
757614
4 (x^2 + 3X -4)\n4(x+4)(X-1)
804695
If I got it, your problem is.........\n\n4+/- sq root -12\n_______________\n           2\n\n\n\nThen:   4+/- 2i sq root 3\n            _____________\n                  2\n\n\nSimplify to:    2+/-  i sq root 3