A math problem has me stumped. If I take 2 apples from 6 apples what do I have?
964376
You have the two apples you took.
482881
Ummmmmmmmm... no, yours is a calculator error ;)  if you divide an apple into 3 parts you can put them back together... you just have a serious logic issue ;)
390719
so you have (1/2)a+a-(6/3)=4+(1/3)a\n\nadding like terms: (3/2)a-2=4+(1/3)a\n\nsubtract (1/3)a from (3/2)a and add two to both sides:\n(3/2-1/3)a=4+2\n(9/6-2/6)a=6\n(7/6)a=6\n\nnow solve and what do you get? :)
954324
0.5 x 0.5\n\nwhen you are dealing with numbers that are less than 1, multiplying them with another number is actually 'TAKING A FRACTION' of the other number.\nhalf of an apple is less apple for breakfast\nhalf of the above is starvation.\n\nSo naturally 0.5 x 0.5 is smaller than 0.5
975217
Line AC = 6, line BC= 2x+2, line AB=x+1\nSo 2x + 2 = 6\n2x = 4\nx = 2 <-- option C
1176888
I would have 2 apples\n\n3 birds  flying in a straight line from front to back\n\n3 socks Only two types of socks, so after getting 3 socks, you would have at least 2 of one type of sock.\n\nNone, there is no dirt in the hole or else it would not be a hole.
909143
take out the x\nx(a-b)=6\nx=6/(a-b)
140472
If I give you three apples three times, you'll have 9 apples.  3x3=9\n\nIf I give you -3 apples  3 times, you'll have -9 apples.  It's like I'm taking 3 apples away from you 3 times.\n  -3x3=-9\n\nIf I give you 3 apples -3 times, It's like you giving me 3 apples 3 times, I'll have 9 apples and you'll have -9 apples.\n3x-3=-9\n\nIf I give you -3 apples -3 times, it's like you're taking away -3 apples from me 3 times, so'll I'll have -9 apples and you'll have 9 apples.\n-3x-3=9
447627
a + 4a where a = 2 ?\n\nif so, then...\n\n2 + (4)2\n\n2 + 8\n\n10\n\nThe answer is 10.
957682
half it then times it by 2! that will give u the answer
501298
1800 is minimum number of apples in the harvest.\n\n(There are larger solutions but I think this is what you had in mind). Give 10 points to whomever you wish; I don't care. \n\nThe key is to use the information given concerning the number of apples that were exhanged between the farmers to set up a system of eqautions which can be solved.\n\nLet a = the no of apples produced by each tree in the 14th\ntree orchard; b = # by the 13th orchard; c the 11th; d the 9th; and e the 7th. \n\nThen, from the problem conditions we have the equation sequence:\n\n11c-1 = 7e+1 = 14a-6 = 13b+3 = 9d+3\n\nwhich implies 13b = 9d so b=9k, d=13k for k>=1\n\nif k=1, then d=13, b=9, and 13x9+3=14a-6 so a=9. \n\nIf a=9 then 14x9-6= 7e+1 and so e=17\n\nIf e=17 then 7x17+1=11c-1 and c= 11\n\nNow, this would imply that the rest of the orchards produced a total of 120 apples each but if this is a solution then the remaining 10 orchards: 1,2,3,4,5,6,8,10,12 and 15 must each produce 120 apples. But since the number of apples produced must be a multiple of the # of the orchard, these 10 numbers must divide into 120 with no remainder and this is the case.\n\nTotal no. of apples produced:\n\n10 orchards produce 120 each for a total of 1200\nThe other 5 must also average 120 so that's 600 more, for a total of 1800 (minimum).\nNote, from the above equation sequence orchards 11,7,14,13 and 9 produce respectively: 121,119,126,117,117 = 5x120 = 600.
863970
let just take the initials of the persons to indicate the no of apples they had,\nj-jeanita 's apple\nc-carl,'s apple\nb-brandon 's apple\nd-denise' s apple\n\n*first    b>j+c\n\n*d+c>b+c    (let d+c>b+c  by x number of apples\n                      then d+c=b+c+x)\n                      \nc+d>b+c  means  d>b\n\n*b+j=c+d\n    \nthat impleies\nb+j=(b+c)+x\n  j=c+x\n \nj>c\n\n*b>j+c\nso\nb>j&c\nj>c\nd>b\n\n\n\nthe order is\ndenise\nbrandon\njeanita\ncarl
674622
The previous answerer is correct but this is why....\n\nWith algebra you have to balance each side of the equals sign.  You can only add or subtract like kinds (think of 12x and 11 x as apples and -6 as a pear).  You want to get all the pears on one side and all the apples on the other.  So, to get rid of the -6 from the left side you move it to the right but because you've changed which side it's on you change what you do to it, ie, the six is -6 so moving to the other side makes it +6.  The same for the 11x.  Moving it from right to left means it goes from being a +11x to a -11x.  That leaves you with 12x - 11x = 6.  Thus, 1x = 6. Convention says you don't use the number 1 in front of an x so you have x = 6.\n\nTo check it, go back to your original equation and replace the x with 6 so you have (12 x 6) - 6 = 11 x 6.  Both sides equal 66 so you know that both sides are equal - problem solved.\n\nHope this makes it a little clearer.
433833
the answer to your question is x=3(4,6)
516552
6 x 1/3 = 2\n2 pieces.
111021
If you are sloving for X then anything greater than 2 will work. basically it is 6 time what (X) will be greater than 12. Well 6x2=12 so that won't work.
659433
1800 Apples\n\nLet Xn be the number of apples produced in each orchard.  You've been told that:\n\nX1 = 2*X2 = 3*X3 = 4*X4 = 5*X5 = 6*X6 = 7*X7+1\n   = 8*X8 = 9*X9+3 = 10*X10 = 11*X11-1 = 12*X12\n   = 13*X13 = 14*X14-6 = 15*X15\n\nIgnoring for a second all those values with minus and plus signs, X1 must be a multiple of 2,3,4,5,6,8,10,12 and 15.  The least common factor of those numbers is 120.  Now check 120 using the other terms (the ones with pluses and minuses).  It checks out, so each farmer contributes 120 apples and 120*15 = 1800