which waves travel  a longer distance in equal time-transverse or longitudinal?
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Try this website for information on transverse and longitudinal waves:\n\nhttp://www.kettering.edu/~drussell/Demos/waves/wavemotion.html
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The answer depends upon what sort of wave you are talking about and the medium it is travelling. Say for example if it is a light wave through vacuum, then \n\nWavelength = (2.99875 X 10^8) / Frequency.\n\nIf the same is sound through air at 60% humidity and at sea level, then\n\nWavelength = (340) / Frequency.\n\nIf it is a sound wave through water (4 degrees celsius), then\n\nWavelength = (1440) / Frequency.\n\nThe value inside the bracket is the speed of the wave in the respective medium under respective conditions.
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see the flowing\n\nhttp://www.seismo.unr.edu/ftp/pub/louie/class/100/seismic-waves.html
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Shear Wave: A wave in which the disturbance is an elastic deformation perpendicular to the direction of motion of the wave. (Shear waves are also called 'transverse waves.')\n\nShear-wave splitting due to the alignment of vertical cracks in the crust has been widely observed in a variety of tectonic settings and data gathering experiments, from earthquake recordings to controlled-source seismic data. It has also been recognized that the polarization of the fast split shear wave is usually parallel to the local strike of cracks (or direction of the maximum horizontal stress), and that the time delay between fast and slow shear waves is closely related to the intensity of crack-induced anisotropy in the medium.\n\nif you wanna see an image of ahear wave aplit then click on the link below.\nhttp://www.missouri.edu/~sandvole/split.html
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wave length\n(DOD) The horizontal distance between successive wave crests measured perpendicular to the crest, usually expressed in feet.
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You mean a 'frequency of 5.10^12Hz'\n\nCan you work it out yourself?:\n\nRemember that the speed (v) of the wave is 3×10^8 m/s,\nand that the wavelength is given by v/f\n\n[Edit: Darn, Kirchwey - don't do Glow's homework for her! ;-) ]
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Physics. Tasty, tasty physics.\n\nIt occours for the same reason a car rushing by you seems to change sound. To a stationary observer, the frequency (pitch) of the soundwaves made by the car as it drives away will decrease, so the pitch in your ear gets lower and lower as the car gets further and further from your location.\n\nSounds waves and light waves work much the same way - I used the car example to help with visualization. :3 It's all the Doppler Effect in action.\n\nSo, to answer your questions...\n\nIf space itself were not expanding, but galazies were moving away from each other, yes, redshift would still occour, since it's the light sources that matter, not the size of what they're contained in. If the stars are moving away, you will experience redshift looking at them.\n\nLight does indeed travel at a constant speed, but you've got the second part wrong. Yes, the energy, wavelength, and frequency changes. But all waves in a single medium (IE space) will have the same speed.\n\nTake a look at the equation v = lamba (f), which in words is velocity of the wave equals the wavelength times the frequency. If the wavelength doubles, frequency will halve, and velocity remains the same.
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Energy is directly proportinal to the square of velocity as you know (Kinetic Energy)\nas far as the velocity of a wave is concerned it wavelength * frequency\nso it has to be either frequency or wavelength,the choice is left to you\nif u asked me i had rather choose to go with frequency
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there are basically 2 parallel mediums of propagation. air and the outer liquid hemisphere. i expect to see interference also as there will be addition of waveforms.
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Both are waves. Both have an associated frequency, amplitude, wavelength etc.\n\nSound travels in a medium (air for example) and is made up of compression and rarefaction waves.\n\nLight doesn't travel in a medium (it can travel through a vacuum) and is made up of the fundamental particles photons.
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In longitudinal wave, the compressions (or rarefactions) are taking place parallel to   the direction of the wave motion.\n\nThe compressions and rarefaction of the materials take place about their equilibrium position.\n\nTHEY DO NOT TRAVEL.\n\nThe energy of motion alone is transferred from one place to another place.\n\nIn transverse wave the vibrations take place perpendicular to the motion of the wave. But the vibrations do not move from place to place.\n\nIf one says that the compressions and rarefactions move along the direction of wave,  we can say the vibrations travel along the direction of wave in transverse wave (in any type of wave) also.
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Polarisation of Transverse Waves \nWe can classify waves into 2 types:\n\n1. Longitudinal: the thing that is waving is in the same direction as the velocity of the wave. Examples include sound waves and a wave traveling down a slinky. A Flash animation of a sound wave -- - the thing that is waving, the air molecules, are oscillating in the same direction as the wave velocity.  \n2. Transverse: the thing that is waving is perpendicular to the velocity of the wave. Examples include water waves and waves on a string. It turns out that light is a transverse wave of electric and magnetic fields. A Flash animation of a light wave  -- - that the electric and magnetic fields are perpendicular to each other and to the direction of motion of the wave.   \nA moment's reflection will convince you that a transverse wave can have the plane of the oscillation at different orientations. The plane is called the polarisation of the wave   Polaroid filters are capable of selecting a particular polarisation state from an incident light wave. By convention the polarisation of a light wave is specified by the orientation of the electric field. \nEdwin Land, a Harvard dropout, invented the polaroid filters, in 1926. Before then the main way of producing a polarised beam of light was using a property of reflected light.   \n\nThe electric and magnetic fields are always at right angles to each other in an electromagnetic wave. By convention, the direction of polarisation of the light is taken to be the direction of the electric field vector.\nAt a single point in space, the electric field vector can only point in one direction at a time. If it maintains the same orientation along the wave, the wave is plane polarised. If the field vector rotates along the wave, then the wave is circularly (or elliptically) polarised.\nVR
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Cirric is always right.  Thought he was a robot did you?\n   On this site put sonic wave included in your question.\n  Or put the equivalence should equal gravity interactive with\n   magnesiums.
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sound travels at an avg speed of .78999342 mps or 2843.9763 MPH in seawater depending on water temperature salinity and depth of the source/receiver.\n\nlight averages 186,282 mps or 11,176,920 mph\n\nthe other answers AREN'T WRONG but you should have specified through what medium they are traveling. also you need to specify temperature humidity pressure altitude/depth salinity and or a myriad of other factors\n\nLight has a different speed when passing through our atmosphere than it does through space just as sound through air and water or a solid. the more dense the material the faster the sound transmission. oddly the opposite is true for light.\n\nthis question has been asked several times before.  if you do a search for previous questions you will doubtless find MANY other answers for these very questions with more precise speeds through different mediums.
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The wave length is the distance between two  consecutive points which are in same phase.\n\nThe wave pattern repeats itself after one wavelength.\n\nThus we can consider this as one cycle of operation. \n\nOne cycle corresponds to 2pi radian or 360 degree.\n\nThus a wave length ( Lambda) corresponds to 2pi radian\n\nAny orbitrary length l corresponds to( 2 pi/ lambda ) x l\n\nThe path differnce l is equivalent to a phase difference of  ( 2 pi/ lambda ) x l\n\nA phase difference of Theta corresponds to a path difference of  ( Lambda/2pi ) x theta.
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This is due to the doppler radar effect.  The wavelength of the reflected sound waves from an object travelling toward you is short (blueshift) whereas the wavelength from a receding object is long (redshift)
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I don't quite understand your notation, but here is how I would do this:\nThe general equation is y(x,t) = A sin 2 pi (t/T - x/L), where\nA = amplitude = 0.12 m\nL = wavelength = 0.3 m\nT = period\nThe latter is not given, but you can get it from the wavespeed v, via the formula v=L/T. Hence T = L/V = 0.3/6.4 = 0.0469 s.\nPlug A, L and T in the general equation and compare the result to the expression given in the problem.\nLooking at your expression, I would guess \na = A = 0.12 m \nb = 1/T = 21.3 s^-1\nc = 1/L = 3.33  m^-1