How do  you calculate the area of a column in flat plate concrete construction?
965465
It is related to the length.
323670
measure each diagonal, come up with the area of one triangle X it by 4, then work out the area of the base simple!
938684
If you desire the external surface area of the pipe,\n\nA = pi*d*L\n\nMake sure d & L are in the same units and your answer will be in those units squared.\n\nIf you are looking for the internal cross sectional area:\n\nAc = (pi*d^2)/4
396424
The curved surface area of the cylinder would be made up of the circumference times the height.  Figure the circumference then divide the surface area by that to get the height.  it would probably be best to convert M2 into cm2 first.  100 cm=1M so 1 sq m would be 100 x 100 or 10,000sq cm x 4m2 equals 40000 cm2.  The C would be 2(pi)r  which is 2 x 3.14 x 70 = 439.6 cm.  Divide 40,000 by 439.6 = 90.99 cm for the height. volume would be (pi)r2h or 3.14 x 4900 x 90.99 = 1399972 cu cm
520391
Area is given in square ft: Length * Width yields ft*ft=ft^2 =sqft\n\nVolume is given in cubic ft: L*W*Height yields ft*ft*ft=ft^3 =cuft\n\nThe formulas above are for area of a square or rectangle, and volume of these shapes in 3-dimensions.  \nFormulas for Area and Volume are different for circles, spheres, cylinders and such.\n\nArea of a circle = pi*(radius^2)\nVol of a sphere= (4/3)*pi*radius^3\nVol of a cylinder= pi*radius^2*Length
870548
I have two answers depending on whether your patio is free standing and the boards go all around the outside, or if the patio is attached to a house and the boards go around three sides.\n\nPlease clarify.\n\nCASE 1 - maximum area is a square.\nLet L be the length\nLet W be the width\nWe know the perimeter is:\n2(L + W) = 300\nSolving for L:\nL + W = 150\nL = 150 - W\n\nNow write a formula for the area:\nArea = L * W\nArea = (150 - W) * W\nArea = -W² + 150W\n\nThis is the formula for a parabola:\nf(x) = -x² + 150x\n\nBut it isn't in vertex form:\nf(x) = a(x - h) + k\n\nTo get it in that form, first pull out the -1 to get x²:\nf(x) = -1(x² - 150x)\n\nNow take half the coefficient on the x term (-150), take half of it (-75) and square it (5625).  Add and subtract this:\nf(x) = -1(x² - 150x + 5625 - 5625)\nNow you can write this as a square:\nf(x) = -1[ (x - 75)(x - 75) - 5625)\nSimplify:\nf(x) = -1(x - 75)² + 5625\n\nYou have a downward facing parabola, with a maximum vertex at the point (h, k) or (75, 5625)\n\nSo the maximum is when the width is 75.  When you solve for length you get that the length is also 75.  So the maximum area for a free standing patio is a square with sides of length 75 feet.
783613
Area = length x width
182640
I'm not sure if this is what you're asking, but if...\nd = length\nd-3 = width\n\nthen the area is d(d-3), a.k.a. d^2 - 3d .\n\nHope this helps!
1060915
Area can be calculated by using the formula Area = 4 Pir^2 .  You didn't mention radius of the tank, thus a numerical answer is impossible.
405573
you need to use some calculus.\nget an expression for the area \ndifferentiate it\nthen find when it is a maximum.
876382
Area = (1/2) Base x Height.\n\nBase is x, because you can choose any side as base.  All are equal.\n\nThe Height (h), half of Base (0.5x), and one Side(x) form a right angled triangle.\n\nh/x = sin 60 = sqrt (3)/2\n\nh = (sqrt(3)/2)x.\n\nArea = (1/2)x (sqrt(3)/2)x\n=sqrt(3)*x^2/4
572270
triangle area = 1/2(height * width)\n\ncircle area = pi * radius^2
198865
Volume = (area of the base) x (height)
611169
Base area x height of water.
765616
Since the volume is 1000, \npi*(r^2)*h = 1000, and so you can express h in terms of r.\n\nCall the cost per sq cm of the wall 1 unit.  Then the cost of the ends is 2 unit per sq cm.  Apply the areas, and get\ncost of wall = 2*pi*r*h  =  (sub in the expression you got above for h in terms of r)\nCost of ends = 2*pi*(r^2) * 2\n\nWrite f(r) for total cost, and as usual differentiate etc to find minimum value of r.  Obviously r and h must both be positive, and that's the only restriction on the domains.  Hope you can do it yourself from here.  You need the exercise and I don't.
460515
i think the volume must be, ((12*5)/2)*15 \n\nin which (12*5)/2 is the area of the one of the bases and 15 is the height since the volume is the base area times the height
223867
It depends on the object.  You find the area of all the sides and then add them together.