what is the battery capacity and weight of Tesla motors sports car?
970178
The weight is about 1140 kg, curb weight that is.  The battery capacity, I don't know if you want to know miles of driving, which I've heard is arround 250 per charge, or this.  6,831 Lithium ion battery cells, about 450 kg, full-charge time of three and a half hours, ~50 kWh capacity.  \n\nAlso, coming in at arround 100,000 dollars, made by Lotus.
202078
A power supply will provide as much amperage as possible depending on the resistance of the circuit.  The formula is voltage=Amps (current) times Ohms (resistance).  Or E=IR\nIt is possible that the resistance of your race car is too much for a small power supply.  The power supply can't overcome the resistance of the car.  \nMost little converters are built for electronics running very little resistance.  An electric motor has higher power demands.
105796
top speed 185MPH \nhttp://sportcars.4mg.com/gts.html
743723
The Nikola Tesla Museum offers you a possibility to make purchases of photographs related to Tesla's inventing activity, video cassettes, CD ROMs and books published by the Museum's Library, as well as three-dimensional models of Tesla's patents in their real size. \nNikola Tesla Museum    \nKrunska 51 \n11000 Belgrade \nSerbia\nTel: +381 11 24 33 886\nFax: +381 11 24 36 408\ne-mail: info@tesla-museum.org
216149
Depending on which vehicle the 350 is in. About 225 to 305 hp. Teacher should learn how to spell.
886660
Battery capacity is rated in ampere-hours, which is the number of hours for which the battery can produce a current of one ampere of current before the battery is exhausted.\n\nNormally there is some cut-off voltage, which varies depending on the type of battery.  For typical alkaline cells it is normally 0.8 volts per cell.\n\nA battery which is rated for 2000 milli-ampere-hours (mAh) could theoretically then produce a current of 2000 milliamperes for 1 hour before it reached this "depleted" level of 0.8 volts per cell.  In practice however, the peak current rating of the battery may be well below 2 amperes.  So lets say the peak current rating is 500 milliamperes (mA) -- the battery would be able to supply a current of 500 mA for a period of 4 hours before it was depleted.  500 mA * 4 hours = 2000 mAh.\n\nIf only life were so simple, though...  As it turns out, batteries have certain characteristics due to their chemistry and construction that cause them to have different apparent capacities depending on how much current you are trying to get out of them.  Take a look at this data sheet for a fairly standard Energizer AA Alkaline battery:\nhttp://data.energizer.com/PDFs/E91.pdf\n\nOn the first page you will see a bar chart of "milliamp hours capacity" and as you can see, the more current you try to draw from the battery, the less apparent capacity (in mAh) it has.  So if you are only drawing 25 mA from it, it has an apparent capacity of about 2750 mAh (it will handle that load for about 110 hours).  But if you were trying to pull 500 mA for it, it only has an apparent capacity of about 1500 mAh (it will only handle that load for about 3 hours).
250746
This is the best answer you'll get -\nhttp://electronics.howstuffworks.com/battery.html
756949
Answer to your question is 'No' if we neglect slight weight loss due to evaporation of water due to the heat generated while the charging is going on.\n\nThe lead-acid battery is recharged, meaning the chemical reactions are made from discharged to charged, from flat by way of transferring molecule between the positive and negative plates in reverse order then when it got discharged while in use. Therefore, the total weight remains the same at charge and discharge condition, assuming the weight of added electrolyte is negligible.\n\nHowever, one of the problems with the plates in a lead-acid battery is that the plates change size as the battery charges and discharges, the plates increasing in size as the active material absorbs sulphate from the acid during discharge, and decreasing as they give up the sulphate during charging. This causes the plates to gradually shed the paste during their life. It is important that there is plenty of room underneath the plates to catch this shed material. If this material reaches the plates a shorted cell will occur\n\nPS. Lead-acid car batteries for a 12 volt system consist of six cells of 2.1 V nominal voltage. Each cell contains (in the charged state) electrodes of lead metal (Pb) and lead oxide (PbO2) in an electrolyte of about 37% (or 6-12M) w/w sulfuric acid (H2SO4). In the discharged state both electrodes turn into lead sulfate (PbSO4) and the electrolyte loses its dissolved sulfuric acid and becomes primarily water.
362726
my dear, hope u r big enough to under stand my answer.\nok i appreciate ur idea to conserve all the mechanical energy produced in a car, but the problem is c if the battery can run a car which requires 100w power that means the power delivered by the battery is 100w now that power is exactly sufficient to run the car but if u want to recharge the battery again u need 100w of more power which will increase the load on the same battery which is to be recharged. which is absurd. so my dear it is practically IMPOSSIBLE to manufacture a car of ur kind. hope u got my answer if u dint understand u go through it once again then also if u face problems do not hesitate to write to me ok bye.
1029495
It is impossible to tell from the information given.  YOu need to know the power factor and efficiency too.  \n\nAt full load of a motor that big it is likely to be 95% efficiency and have power factor of probably 0.8.  \n\nIF (!!) that is true, then the current is (75 hp * 746 W/hp)/(480  V *sqrt(3))/0.95/0.8 Amps (rms)\n\nNotice I've considered a wye-connected motor too - that's where the sqrt(3) comes from.  I also get 90 A (like the previous guy)!
434080
I dont own one but this dude in my town does. 94 supra single turbine. i dont know how much he is boosting but rumors got to me at 900hp maximum. thats all i got to say.
165131
The Bugatti Veyron 16.4 (known as the EB 16/4 Veyron in concept stages) is the most powerful and expensive production car in the world, as well as the fastest street legal production car with a proven top speed of over 400km/h. It reached full production in September 2005. The car is built by Volkswagen AG subsidiary, Bugatti Automobiles SAS, and is sold under the legendary Bugatti marque. It is named for famed Bugatti racing driver, Pierre Veyron who won the 24 hours of Le Mans in 1939.  It has a 1,001 BHP Quad-turbo engine.
1029524
It's a Saleen 750 hp S7.  See link below.
255015
The SRT-4 has Fun factor written all over it! Fast from the factory and insanly fast when modded.Simple to mod,easy to maintain and fun to drive.\n\nThe Gt , big motor, V-8... nuff said.\nthrow a supercharger on that bad boy and call it a day!\n400HP!
195932
82X5.6X100/Body weight in gm.\nThanks.
865403
Alright Alright...I'll calculate this for you! Whatever! Ok...What 4x4 are we talking about here?\n\nAssumption:\n4x4 = JK Jeep Wrangler.  Here are the specs from Wikipedia:\nA 3.8 L OHV V6 producing 205 hp (153 kW) and 240 ft·lbf (325 N·m) will be the base engine, replacing the venerable AMC Straight-6 engine. \n\n205hp=153kW!!!!!  I can tell you straight up that to produce this amount of power from solar panels would be ridiculous!  If you go up to Home Depot and ask them for a 153kW System for your house, they will tell you to get lost! The average solar panel at PEAK Efficieny can produce roughly between 60 - 110 Watts! \n\nThus lets take the best case scenario.  At peak efficiency:\n153,000 Watts/110 = 1,390 Solar Panels!!\n\nSo...to power up your 4x4(Of course that 205hp to the crank and not to the wheels!) you would need around 1,390 solar panels.  Not that bad though!
424529
Try SPEEDWAY MOTORS.com