Find the expected value of X?
955894
x1*p(x1) + x2*p(x2)\n\nx1 = 1 for  event dots> 3,\nx2 = 4 for event  dots<=3.  \nThese are equally probable because there are 6 dots on the die.  \n\n1*(1/2) + 4*(1/2)
353406
You will want to isolate the variable (many times it is 'x'). First you will add or subtract from each side. Then divide. For example:\n5x+4=19, subtract 4 from each side giving 5x=15. Then divide by 5 giving x=3. I hope this helps.
101082
(x-1)/4 > 3\nx-1 > 12\nx > 13
217977
f(E) = 1/(exp{(E-Ef)/kT}+1)
914435
x > 5\n\n- - - - - -s-
612882
You first need the probablity function of the basic variable... Lets call it P(x) where x is the variable... Then to get the epectation take the integral of x*P(x). The limits of integration should be the min and max values that x can be.
764329
x(abs[x- (x^2)] (-1=2)\n\n:> peace\n.
1047777
first x outside x inside x last\n(2x*5x) + (2x * -2) + (-5 * 5x) + (-5 * -2)=\n10x^2 + -4x + -25x + 10=\n10x^2 - 29x + 10
954164
grab a calculator and try 1.1 x = = = = =  until you get a number >2.\nthe first time you hit = is ^2, next is ^3 etc.  count.\n\nN=7
872873
There is only one value that works: \nx=1\n\nj
308163
x can be any value.\n\ntan x = sin x / cos x\n\ncot x = cos x / sin x\n\nso tan x * cot x = sin x/cos x * cos x/sin x\n\nsin x's cross out each other\n\ncos x's cross out each other\n\nso you're left with 1.
1053953
Divide both sides by 11.\ne^x = 11\nThen take the natural log (ln) of both sides.  Any good scientific calculator can do this.\nln(e^x) = ln(11)\nx = ln(11)
711149
Is it lim (x approaches 0)?
1110742
12 simply place the 1 where the x is\n\n(1+3)(1+2)\n4*3\n12
935707
x<0\nso for all values of x, x will be a negative. when you absolute x, the positive absolute will always be bigger than the negative x
565951
the answer is zero b'coz at the end, X-X is equal to zero.
859504
(x-7)(x-5)\nso x= +7, or +5