ok i wanna make sure about one thing period 1 in periodic table is very reactive?
958717
Period 1 is very reactie because it wants to give away the 1 e- in the outer ring. Period 2 is slightly less reactive it has 2 e-(electrons) to give away. Period 3 is slightly less reactive with 3e- to give away. Period 4 kind of shares. Period 18 is inert, no reaction. Period 17 is very reactive, it only takes 1 e- to fill that outer ring. Period 16 is slightly less reactive taking 2 e- to fill the outer ring.Period 15 is slightly less reactive taking 3 electrons to fill the outer ring. All atoms want to get that outer ring full. The metals do it by giving away e- and the nonmetals do it by taking e-.
796961
you need a periodic table... just look for the symbol NA... and the atomic number 15, also look for it on the table.. it shud be under the 2-3 letter symbol of the element.
366349
I love chemistry. =P Though I last did chemistry in 1999...hmm.\n\nAnyway, ignore the group 8 elements (inert gases)..you know why. =P\n\nAlright, Group 1 and Group 2 are the 'metals', and they carry one/2 extra electrons in their orbits, which they 'readily donate' (i.e. they are reduced), hence this makes them oxidising agents in nature! Hence, to answer your question, these Group 1, Group 2 (and some Group 3, e.g. Aluminium) like to be reduced. (reactivity decreases along from left to right of the groups)\n\nElements on the opposite end of the periodic table (group 6, 7, eg. CL, F.. and some group 5 (use the "step ladder" to determine, e.g. Asitine)) are your reducing agents, because they 'need' electrons (i.e. to be oxidised) in order to have a complete stable orbit (1s, 2s, 2d, 3s, 3d, 3f..) ..hence, to answer your question, these like to be oxidised.
240126
Tommy was right as far as Mg & Ca are concerned.  Na is a Group 1 metal and is more reactive than either because it's 3s1 structure is an incomplete atomic orbital, whereas Mg (3s2) and Ca (4s2) have a certain stability from being a complete electron pair.
928366
The first answer is, like, SO wrong. Gold is one of the least active metals. Check out the Activity Series of metals (you can Google it). The ones at the top of the list (lithium, calcuim, and barium, I think) are the most reactive. They'd react readily with air (they oxidize, releasing hydrogen gas from the water vapor in the atmosphere, forming an oxide or hydroxide). They'd definitely cause an explosion when reacted with acids. Even sodium metal (not salt, I'm talking pure sodium) will react with acids violently.\n\nAll metals react with acids to some degree. Even gold, the most unreactive metal, dissolves in selenic acid. Silver reacts best with nitric acid to form silver nitrate. The coinage metals (Au, Ag, Cu) are the most unreactive.
471015
google it and type 'periodic table, first twenty elements'\nn u'll get sumthing, far quicker than lettin sum1 write them up 4 u.
1007912
We did a similar lab in my math class. It will be about half whenever you flip 100 pennies, then half again, ect... This is roughly the same thing as the radioactive element ("half-life").\n\nNow, make sure you do the work so you will know the material, and explain the relationship in words your teacher would like to see.\n\nGood luck.
888694
There are a few ways to approach this problem.\n\nFirst, on the left side of the periodic table, most elements are cationic in nature--that is, they like to form a positively charged ion. Elements on the right side of the periodic table tend to be anionic, or negavitely charged.\n\nSecondly, elements on the left side of the periodic table are predominantly metals. Those on the right side of the periodic table are mainly non-metals.\n\nAnother significant difference between the left and right sides of the periodic table is the atomic radii of the elements. Elements to the right side of the periodic table are larger in radius than the elements to the left side of the periodic table.\n\nFinally, elements on the right side of the periodic table are usually (although not always) more electronegative than those found on the left side of the periodic table.\n\nI hope this is enough information to help you with your problem. Good luck!
543388
Hmm, kinda hard to help you here, since we can't see all your options for the first two.  The ellipses (. . .) indicate that you have more in your message than is being displayed.  Perhaps if you retyped them, it would be easier for us to help.\n\nHere's what I *can* help with:\n\nHalogens:Reactive as Noble Gas:STABLE\n(the halogens are very reactive gases, while the noble gases are extremely stable, almost to the point of being inert)\n\nOxygen:molecule as chloride:ION\nOxygen gas is a molecule, while chloride is the ionic form of chlorine\n\nRatio:subscript as oxidation number:CHARGE\nthe ratio of components in a mixture is denoted by the subscripts, as the oxidation number of an atom is denoted by its ionic charge
796417
Noble gases are inactive\nhalogens are very active\nLast one, ionization energy decreases\nlanthanide and actinide are the bottom 2 periods
732503
U CAN MAKE A PROJ ON REACTIONS ON THE FOLLOWING PTS  .\n INTRO OF REACTIONS\nDEFINITION OF A REACTION\n TYPES OF REACTIONS\n THEN, DESCRIBE THEM SEPARATELY
121386
http://www.chemistrycoach.com/periodic_tables.htm#Periodic%20Table%20Songs\n I hope it helps you
905961
Nobody knows the answer to this exept for Mendeleev himself, and he isn't talking. The first periodic table had 64 elements, although 3 or 4 of those were still purely theoretical. Since there were more than 50 in the first periodic table, you can't really discuss the first 50 added very well. Several models of organization were proposed, but there were around 60 known elements before it was deemed necessary to organize them. Only Mendeleev's used periodicity, and it is the closest to our modern periodic table.\n\nThe only 2 elements in my periodic table are:\n\nWOMANIUM (XX)\nPhysical properties: Generally soft and round in form. Boils at nothing and may freeze any time. Very bitter if not used well.\nChemical properties: Very active and highly unstable. Possesses strong affinity with gold, silver, platinum, and precious stones. Violent when left alone. Turns slightly green when placed next to a better specimen.\nUsage: An extremely good catalyst for dispersion of wealth.\nCaution: Highly explosive in inexperienced hands!\n\nMANIUM (XY)\nPhysical properties: Solid at room temperature but gets bent out of shape easily. Difficult to find a pure sample. Due to rust, aging samples are unable to conduct electricity as easily as young samples.\nChemical properties: Attempts to bond with XX any chance it can get. Also tends to form strong bonds with itself. Becomes explosive when mixed with Childrium for prolonged period of time.\nUsage: Possibly good methane source.\nCaution: In the absence of XX, this element rapidly decomposes and begins to smell.
892172
44 A) 2AgO --> 4Ag + O2\n     B)NiCO3 --> NiO + CO2\n     C)NH4NO3 --> N2O + 2H2O\n48)A)2HCl + Ca(OH)2 --> CaCl2 + 2H2O\n     B)3Ag2SO4 + 2AlCl3--> 6AgCl + Al2(SO4)3\n     C)&D) I've no idea, sry\n50)A)C4H8 + 6O2 --> 4CO2 + 4H2O\n     B)2C8H18 + 25O2 --> 16CO2 + 18H2O\n     C)2C3H8O3 + 7O2 --> 6CO2 + 8H2O\n     D)2C3H6O + 5O2 --> 6CO2 + 6H2O\n52)A)2Al + 3H2SO4 --> Al2(SO4)3 + 3H2\n     B)2HCl + Ba(OH)2--> BaCl2 + 2H2O\n     C)Au + HCl--> No Reaction(gold is below hydrogen in the metal reactivity series)\n54)A)2Cl2 + 2NaI --> 2NaCl2 + I2\n     B)2NH3--> N2 + 3H2\n     C)4Na + O2--> 2Na2O\n     D)Mg + H2SO4--> MgSO4 + H2\n     E)MgCl2 + Ca(OH)2--> Mg(OH)2 + CaCl2\n     F)H2 + Cl2--> 2HCl
608949
cant answer secifically, but you should be able to back calculte taking elements present today and using the half lives as your main variable.
464799
I assume that you have an equation such as A and B react together to give C. Work out the molar ratios of each, i.e. is it 1 equivalent of A reacted with 1 equivalent of B to give 1 equivalent of C?\nAssuming it is a 1:1:1 ratio, then look at the amounts you actually reacted - chances are that you did not use 1 mole of each of the reactants. Work out the molar quantities of each reactant. (mass used/molecular weight of compound)\n\nIf you used 0.5 moles of each, then you would get 0.5moles of product and just convert this to a mass.\n\nIf one of the reactants is in excess, e.g. 0.5 moles of A and 0.8moles of B was used, ignore B because as there is only 0.5 moles of A you would only make a maximum of 0.5 moles of C.\n\nHope this helps
761935
when in a chemical reaction