Find length of arc intercepted by a central angle of pi/8 radians on a circle of radius 8 in.?
966696
Arc=r.theta=8*pi/8=pi
1119451
radius = 2.2/2 = 1.1\nA = 1.1*1.1*pi = 3.8
554627
the circumference of a circle can be calculated by using the formula:\n circumference of circle=2*pie*r\n where pie=22/7;it is equal to 3.1415;\n r=radius of the circle.\nThanks.
389433
If you're asking how to do it: Just take the total number of degrees of the angle, divide by two, and there you go, you know the measurements of the 2 equal angles.\nanswered by Fading Away...\n\nAngle bisector Theorem.\n\nIf you are a Geometry student who knows constructions, locate a radi from your vertex and draw an arc. Choose another radii on that new arc that you just drew(That is more than half the arc) from the point where your newly drawn arc intersects the segment. Draw another arc. Repeat process on opposite side. Draw bisectore from vertex through intersection of two arcs.\n\nHope that helps!\nAnswered by Emily\n\n\n\nThis was asked and answered 13 hours ago, click this link.\nhttp://answers.yahoo.com/question/;_ylt=Al6hLACuaPLouhbP7BmwxcIjzKIX?qid=1006041024466
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The 14 foot line is called a secant.  Bisect it, and draw a radius through the point of bisection.  You now have two identical right triangles, with hypotenuses of 12 feet, and known sides of 7 feet.  Use trigonometry to calculate the angle at the center of the circle of either triangle, and then a simple proportion (involving the circle's total circumference) will give you the arc length you want.
237156
Pi * r^2\n\n(Pi R Squared)\n\nwhere R is the radius (which is also equivalent to half the diameter)
183956
Half the diameter, or circumference divided by 2.pi
838513
Sigh - first guy had it right, but didn't explain it all.  \nPi = 3.14- all you need for the problem\nRadius= half the diameter of your circle. You find the midpoint and measure from there to the side of the circle, in any direction. Most problems give you the radius. or at least show you the midpoint on the circle.\n\nSo, it is 3.14 x the amount of the radius x 2= the area of the circle.\n\nYou can do this in reverse as well, if you know the area but not the radius.
506648
use a protractor - thats' the semi circle type thing...\n\nmeasure the angle on a straight line which is 180 degrees in total, the obtuse (larger) angle and the acute (smaller) angle will equal 180 degress so calc the obtuse one and subtract this by 180 leaving the acute angle.
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How to do this problem:\n1. Find the Radius. To do this, take the diameter and divide by two. This gives you a radius of 5.\n2. Because the Area of a circle is equal to Pi times the radius squared, and your teacher wants the answer in terms of pi, square the radius and get 25 pi.
796855
if you mean an ellipse....\n\narea is equal to pi * minor radius * major radius
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let the base of the isosceles triangle be x\nheight of the triangle=h\ngiven the radius of the circle is 4\n(4-h)^2+(x/2)^2=4^2\n16-8h+h^2+x^2/4=16\n4h^2-32h+x^2=0\nx=rt(32-4h^2)\narea=1/2*x*h\n=1/2*h[2rt(8-h^2)]\ndA/dh=0 for max\nafter finding h sub to get x
1167722
areah of a circle=pie times r squared  (r is radius)\ndiameter= 2r\nso r= d/2\n\nso you do 6sqrt(3)  divided by 2\n(you get 3 times sqrt of 3)\nthen do that number sqared....times pie(3.14)\n(18 times pie...more accurate if use calculaterbut answer is 18x3.14......)
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1.60\n\nThe Arc Length Formula:\nS sqrt(1+[f ' (x)]^2)dx from a to b\n\nNote: "S" is the symbol for integration\n\nf(x) = x^4\nf ' (x) = 4x^3\n\nS sqrt(1+[4x^3]^2)dx from a=0 to b=1\n= 1.6002294....\n\n*Note: I checked this answer using the arc length calculator in my TI-92 calculator
850372
SOH CAH TOA...\n\nsin(angle) = O/H\ncos(angle) = A/H\ntan(angle) = O/A\n\nO=opposite length\nA=adjacent length\nH=hypoteneuse length\n\nsooooo...\n\nsin(angle) = O/H = 18/25\n\nso the angle is...\n\nangle = arcsin(18/25)\n\nPlease try to figure this stuff out on your own before resorting to answers... Europe teaches this to their students in like the 6th grade...
385689
You want arc length or straight line?\n\n934.59 nm\n\naccording to the reference below.
93089
This seems like a homework problem, so I'll give a few hints.\n\nThe arclength is radius times the angle subtended.\n\nTo find the angle subtended, consider the isosceles triangle created inside the circle where the chord is the hypotenuse and the radius of the circle is the two other legs. \n\nSince the isosceles triangle created is not a right triangle you need to use a specific formula to find the angle "C" subtended by the chord.