how many neutrons are in bromine?
960169
Indeed, the number of neutrons in Bromine (79.904 amu) is 45.\n\nThe AMU is given as a decimal because it is the average AMU of a mole of Bromine atoms(a really lot of atoms). On the Periodic Table round the given AMU and you will have the most commonly occurring isotope (atoms of the same elements with different numbers of neutrons).\n\nGet an "A".
842680
2 KBrO3 + 3 N2H4 -> 2 KBr + 3 N2 + 6 H2O\n\nYou can check by finding out the total number of atoms of both sides:\n 2 Potassium\n 2 Bromine\n 6 Oxygen\n 6 Nitrogen\n12 Hydrogen
381600
Five (5). \n\nMore details:\n\nName: Boron\nSymbol: B\nAtomic Number: 5\nAtomic Mass: 10.811 amu\nMelting Point: 2300.0 °C (2573.15 K, 4172.0 °F)\nBoiling Point: 2550.0 °C (2823.15 K, 4622.0 °F)\nNumber of Protons/Electrons: 5\nNumber of Neutrons: 6\nClassification: Metalloid\nCrystal Structure: Rhombohedral\nDensity @ 293 K: 2.34 g/cm3\nColor: brownish
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Same number of protons\n\ndifferent number of neutrons
209259
26 protons and 30 neutrons
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Mg2+ < Na+ < Br-\n\nIon size depends first on the main quantum number. Na and Mg both strip down to the Ne configuration, while Br takes up the Xe configuration, two main quantum numbers higher.\n\nMg2+ is smaller than Na1+ because the remaining electrons are subject to a stronger electrostatic field.\n\nThe above is true for ions in crystal lattices.\n\nNote that in watery solutions ion size has to be calculated differently when you take the hydrate shell into account. Na+ becomes Na(H2O)6(1+), and Mg2+ becomes Mg(H2O)6(2+). Bromide won't take up a regular hydrate shell.
62040
Two.  "Normal helium has 2 protons and 2 neutrons in its nucleus, giving it an atomic weight of 4."
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Electron Proton neutrons
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You may already know the answer, but I'll give you credit for wording it precisely.\n\nThe answer is more than one (on average), because neutron losses mean it would be impossible to sustain a critical nuclear reaction (that is, a constant rate of nuclear reactions) if you had one or less than one (on average) per reaction, since it takes at least one neutron to cause a nuclear reaction.\n\nThe exact reaction that occurs and the byproducts produced will determine exactly how many you get per individual reaction, but *on average* you need to net >1.0 neutrons per reaction.  The more losses you have (due to poor shielding, absorbant material, etc.), the higher the number needs to be, but something like 1.2-1.5 should be fine.
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You take the difference between the mass number and the atomic number to determine your neutron count.. at least that is what is stated in my Chemistry book.  Hope this info helped!
45574
a) Sr, Mg, Be \nRationale: they are all in the same group (II), but because Sr has the most energy levels, it has greater shielding and lower effective nuclear force, so it is easiest for it to give up an electron.  Be has the lowest number of energy levels, so it has less shielding and greater effective nuclear force, so it clings to its electrons more, requiring greater force to take away an electron.  \nb) Cs, Ba, Bi\nRationale: They are all in the same period, so shielding and effective nuclear force are not variables.  Instead, we look at stability.  Cs is in group one, meaning that it only needs to lose one electron to reach a stable octet.  The electron configuration of Bi gives exactly 1 electron per p orbital (try writing it out), so it's somewhat stable already; taking away an electron would mess with that stability.  Ba is somewhere in between.  \nc) Na, Al, S\nRationale: group I elements always have lower ionization energies in the same period because they only have to lose one electron, so sodium goes first.  Next is aluminum, which only has to lose one electron to be totally rid of electrons in its p orbitals.  Last is sulfur, which will lose one electron to have one electron in each of its p orbitals, which is less stable than the other two.
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Neutron, proton, and electron... though there are other sub-atomic particles making up these basic three.
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Alpha, Beta, Gamma and Neutron
223672
Could the bromine react with the iron to form FeBr3?  If I remember right, the Febr3 should make it easier to react with toluene (hence the iron catalyst).  I'm not sure about the math, but it seems like toluene was the excess reagent so FeBr3 shouldnt be leftover...\n\nDo you know if either of the distillation products are a bromotoluene?  From what you said, dibromotoluene could have come out.  Also, the methyl group has activating properties, so there will likely be more than one substitution, possibly even 3
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Lithium has four neutrons and three protons. The number of protons is determined by the Atomic Number, which is the number at the upper left of the periodic table. Using the nearest whole number of the atomic weight, which is the numerical average of the relative proportions of the isotopes, and subtracting the atomic number, the number of neutrons is determined. For lithium with an atomic weight of 6.941, or about 7, the number of neutrons is 7 - 3 = 4. P. S. I referred to my Periodic Table of the Elements, not the web for my answer. I do not normally search the web for my answers.
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They're constantly adding new ones.  The new ones are synthetically created by bombarding already existing elements with neutrons.  Apparently, they're up to atomic no. 118, now:\n\nhttp://www.webelements.com/webelements/scholar/
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Francium and cesium are about 0.5.\nFluorine is highest at 3.9-4.0 (by Pauling's estimate)