Any Math Wiz here? Help please..?
952428
Q: A nectarine costs 3p more than a peach. Kamal buys 4 nectarines and 5 peaches. The total costs is £1.47.\n\nLet x pence be the cost of a peach.\n\n(a) Write down in terms of x:\n\ni) The cost of all peaches: 5x\nii) The cost of one nectarine: x + 3 (3p MORE than a peach)\niii) The cost of all the nectarines: 4(x + 3)\n\n(b)\n\ni) Write down a equation for the total cost of the fruit.\n\nTotal cost = 5x + 4(x + 3) = 147\n\nii) Solve the equation to find x.\n\nSo 5x + 4x + 12 = 147\n9x = 135\nx = 15\n\nSo a peach costs 15p\n\niii) What is the cost of a nectarine?\n\nSo a nectarine costs 18p (= x + 3)\n\nCheck: \nCost of 4 nectarines and 5 peaches = 4 x 18 + 5 x 15 \n= 72 + 75\n= 147p\n= £1.47 Yessssssssssssssssssssssssss !!!!!!!
855052
Come on now, what is the formula for this???  :)\n\n(V1 * T1)/P1  =  (V2 *T2)/P2\n\n(69L * 131)/2.85  = (xL * -37)/2.85\n\nNow, solve for 'x'?  Be sure to watch your units!!!!
969084
OMG a math riddle I cant seem to answer!!!! :-)  Awesome. I cant sleep because now i want to knwo the anwer. And so i continue to try and solve it.\n\nBest i can come up with is 113  or 240 or 50-something..\nAlso maybe another number in the 100-n-teens\n\nI did find a 1-3-4 pattern aasuming the next number in 1-3-4-1 was a 3 but was unsure of how to continue it. (its1230 in the moring here)\n\nAnd again another possible patter 1-3-4-8 next number would be 16.\n\nI know some may not even know how I came up with these, but I love math and I love a challenge. I have been trying to find any possible correlation in the numbers that I can. \n\nHope someone figures it out. I know I cant wait to see the answer.
37738
try sosmath.com  they helped me before. if they don't have the answer you are looking for they have a list of links to tons of other math sites.  \n\nand there probably is someone on your campus that can help as well.  One on one help is always best...\n\nGood luck!
849743
This is the third time that this question has been asked!?!?!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nBut someone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
974937
please complete the equation
897429
This is the third time that this question has been asked!?!?!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nThis is as far as I got:\n(2B+1)^(D-E) - F^(3G+G2) = (10J)/A\n\nBut someone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
281150
Next time just type your math equation into Google and it will do the math for you.\n\n15
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
958614
#1.)-----------------------------------\n  \n25b^ -20by + 4y^\n\nMultiply 1st and 3rd term together to get 100b^y^.\n\nFactor 100b^y^ into two factors whose sum = the middle term of -20by.\n\n1by   X 100by\n2by   X 50by\n4by   X 25by\n5by   X 20by\n10by X 10 by   ....................BINGO!\n\n-10by + (-10by) = - 20by   &   (-10by)(-10by) = 100by\n\nThis is a really kewl factor by grouping trick, I LOVE it!\n\nBring down the first term of: (25b^)\n\nNext, write the SMALLER of the two factors 1st.  Followed by the LARGER of the two factors.  In this case, they're both the same, so it doesn't matter which one goes first: (-10by)\n\nFinally, bring down the third term of: (+4y^)\n\n25b^ -10by -10by + 4y^\n\nNow, lets factor by grouping! \nFactor out the GCFs.\nGCF#1 = 5b\nGCF#2 = -2y\n\n(25b^ -10by) + (-10by +4y^)\n5b(5b - 2y) -2y(5b - 2y)\n\nGCF#3 = (5b - 2y)\n\n(5b - 2y)(5b - 2y)\n\nSimplifies further as: (5b - 2y)^   ....Whatdayaknow?! \n.......................................................................................................It's a Perfect Square Trinomial.\n\n#2.)------------------------------------------------------------------\n\n100 - 9b^\n\nAh, the difference of two perfect squares.\n\n---------------------------------------------\n\nFORMULA:\na^ - b^ = (a-b)(a+b)\n\n---------------------------------\n\nSOLUTION:\n100 - 9b^\n(10)^ - (3b)^\n\n-----------------------\n\nANSWER:\n(10-3b)(10+3b)
883460
Please see the answer above and find out the missing factor in your calculation. You are in the right track. All the best!
706993
Try reviewing your class notes and looking through your text book. Im sure that the answer you need is there. It might take a bit of thought to figure out how to do these problems! Take the time to figure it out, it will be worth it in the long run!
618077
go to www.curnaturecalculus.com  They have all the answers.\n\nSplooch!
832646
I'm sorry, but how could you not know this?\nThis is basic elementary math and if you don't know how to round you are in trouble.\nIt's 0.1 by the way
1094108
Use a calculator and raise it to the 1/3 power.\nDon't try to do it by hand...
191038
hmm.. sounds like a homework question.  tsk tsk..
195201
i think u typed the question wrong, can u please correct it and if u have 2 unknowns, please give 2 equations, else u cant get a definite solution