To get the best view of the statue of liberty, you should be at the position where angle theta is a maximum?
952205
You are missing a constraint in your problem.  If your only constraints are \n- theta must be less than or equal to pi/2 \n- you want to maximize theta\nthen theta = pi/2.\n\nSo how far should you be?  0 meters.
831103
I would change cos 2 theta to 2 cos squared theta -1.\n\nYou then have a quadratic in cos theta.
367687
an angle that is inside a circle or any other figure
62428
You want to strike it in the geometric center of the clubface, the best place would be on the fourth groove up from the bottom.
962720
Lots of unnecessary complications here.\n\nAirspeed is the hypotenuse. 20.4 is the side opposite the angle we are looking for.\n\nThe heading, east of north, must be at angle sin^-1(20.4/241).\n\nSpeed relative to the ground is the third side of the triangle, and is \n\nsqrt(241^2 - 20.4^2)\n\nZidane has got the angles all wrong. The wind is from the east. We want to fly due north. That's where the right angle is. 241 is the hypotenuse of the triangle. The wind serves to make the ground speed less than 241, not greater.
728290
The method is entirely dependent on what you know about the triangle in the first place.  If you know the 3 sides, you can use Steve's law for the altitude; ex: (alt to side c) = sqrt(4a^2b^2-(a^2+b^2-c^2)^2) / 2c\n\nIn general, the altitudes of a triangle intersect at a point called the orthocenter, whose location is described in detail at\nhttp://www.cut-the-knot.org/triangle/altitudes.shtml
1133705
If you are given the arc length of s,\n\nThe angle may be found by\n\ns/(2*PI*r) * 360 degrees.
59005
Due south if you're north of the 22nd degree latitude, the tropic of cancer.\n\nBetween the tropics, the highest point of the sun can be directly overhead, or move north or south.
436114
well, you could be an architect and be using a 30-60-90 triangle and you needed to know a particular side of it. you can use x times the square root of 3, x being the shorter leg, to find the length of the longer leg.
715400
Angle of line from horizontal position.
37762
Obtuse angle is an angle more than 90 degrees.
37743
no.... everyone sees about 180 degrees. stretch your arms out from your sides and wiggle your fingers. pull them back until its right on the border of your sight (remain looking forward the whole time). do this to both sides. now look at where your arms are. Its like this for everyone
928764
You would just do 180-56 to equal 124 degrees\n\nsupplementary angles add up together to equal 180 degres or a straight line
735957
Well. You can keep drawing tangents until one which you find is the steepest. From your info, i have the idea that the curve is in the shape of a bell. So perhaps you can try drawing tangents at the mid-range of the curve.\n\nHope this helps=)
975601
consider this eqn,\n\ndsin(theta) = n (wavelength)\nd = slit separation\nn = no. of order\n\nthe max angle is 90, and sin90 = 1\n\ntherefore, d = n (wavelength)\nwhen d is reduced n is reduced too.\nwhen less fringes appear on the screen, then distance between them increases
50853
I think you would find a Mercator projection of the map. It shows true direction even if the shape of the land mass is distorted.
1187062
a) the 90 degree angle