Cost, Income, and Value problem?
956245
372=8(x=4.50) + x\n46.5=x+x+4.50\n42=x+x\n21=x\n\n\nx=apprentice wage \nx+4.50= plumber wage=25.5
683941
Uhm you are vague by saying "at least $30". Hence, it is impossible to figure this out. You did not say "exactly $30".
69556
The problem that you may have, is not taking into account the opportunity costs, which is the money that mike would be making if he wasn’t running a business(70K), and also the money mike's not getting from renting out the building that he has(20K).adding these costs to the costs of running the business results in:\n70K+20K+95K+170K=355K
530853
So where's that starting point?  Either we start (yesterday) with Mary having $785.63 we subtract $57. and $125. for 603.63.  Then we add $57.25 for a total of 660.88 (B) \nOR\nwe start we $785.63 (today) anb subtract $57. and $125 for $603.63 (C).  The $57.25 doesn't matter cause Mary did that yesterday....
192303
An easier way to look at it is to change the "c" to an "l". In other words, "opportunity lost".\n\nOpportunity cost is the price for committing your resources to a project. While they are committed, you can't spend them on other projects. So, you lost your control over your money and, if another project comes up, you lost the ability to invest in it.
146191
Same as above, and there is missing info anyway. How much would 1 unit* of this cost?\n\n*unit, because the question is messed up. <_<
1178729
May be articles from http://www.all-total.com/ helps you!\nSorry if not!
966947
Calculating money, age, time, products that are manufactured, statistics, etc.
665763
Research the cost of the following things:\n1. Facility (including insurance, hydro etc)\n2. Equipment\n3. Personnel\n4. Advertising (very expensive at the beginning)\n\nI can't think of any others right now.
1082116
change problems to challenges.\n\nHigh wages and product cost cause several challenges to our budget costs
1141716
People (mostly young kids) post their whole assignment here...and yes, it does get our ire up sometimes.\n\nIf your question is the accounting question, I asked my wife (an accounting major) and she couldn't think of any reason why you would want to transfer fixed costs to variable. She mentioned that you could sort of "jimmy rig" fixed costs, by considering it as per unit manufactured, so the fixed cost really is determined by units of production. That is all I have...hope it helps.
869572
Assuming\nX = # of units\nR(x)=Income\nC(x)=Cost\n\nNow profit would equal income - cost\nP(x) = R(x)-C(x)\nP(x) = 2x - (0.01x^2 + 0.6x +30)\n        = -0.01x^2 + 1.4x -30\nUsing calculus or some way to find the maximum of the binomial function P(x) or just graph it and find maximum.\n\nProfit is maximized at x = 70 units\nProfit = -0.01*70^2 +1.4*70 - 30 = $19
1162650
pay the 450.  next time figure them out yourself....300 or so is about right.....but you should always get estimate BEFORE you get it done...withthe understanding (in writing) that if it is to cost more---you be notified in advance
187902
Rent is fixed.  If you sell one burger or a million, it won't change the rent.  You'll have to do the math on the other stuff.
609208
hey try to think logically about the problem.. its really easy just too much words and it confuses you. so take a deep breath and then begin. take 25 % off of $375 and it will give you the answer..... im pretty sure about this but you cant trust me on those dog gone word problems, lol \ngood luck
850121
Your question is unclear, but this might help you.\n Total cost of products = No. of products x Price of products.\n\nIf there is more then one produce, say for example three different products then:\n Total cost = (No. of Product 1 x Cost 1) + (No. of Product 2 x Cost 2) + (No. of Product3 x Cost 3)
509660
His profit will actually be found by taking his price minus all of his expenses - you can't just take the derivtive of the price function.  Since the price function given is per widget, multiply it by x to find the total revenue from the selling of x widgets.  The costs given are already given in terms of a total number of widgets, so we can just add those up.  So you're really looking at a profit function\n\nP(x) = x[90 - (x/24)] - (1200 + 60x + x^2/24)\n= 90x - (x^2/24) - 1200 - 60x - x^2/24\n= - 1200 + 30x - x^2/12\n\nTaking this derivative you get\nP'(x) = 30 - x/6\n\nTo find the max profit, set this to 0 and solve for x:\n0 = 30 - x/6\n30 = x/6\nx = 180\n\nSo after selling 180 widgets, you'll maximize profits.  And putting this back into the original per unit price function, you find that you're selling them at\n\nPrice = 90 - x/24\n= 90 - 180/24\n= $82.50 each