i need help with science variables!!!! pronto!?
964185
I sense that you have no clue what you're doing. Tell me I'm wrong.\n\nFor DC circuits, Ohm's law says: V = I * R, voltage equals current times resistance.\n\nYour circuit will consist of a battery (voltage source) and a load (resistance) plus the wires to connect them and the meter(s).\n\nIdeally you will test one battery at a time. That way the load will be identical (including the small resistance of the wires).\n\nBatteries typically have two ratings: voltage and capacity.\nVoltage is measured in volts and this decreases as the battery discharges. Capacity is measured in amp hours (current multiplied by time) which specifies how long the battery can deliver a current.\n\nAssuming the circuit resistance is constant (reasonable assumption for your purposes), when you connect the battery to the load, the voltage (independent variable) will cause a current (dependent variable) to flow. As the battery discharges, the voltage will decrease, and the current will correspondingly decrease. You will need a watch or timer as well. Time zero will be when you first connect the battery. Measure the battery voltage at that instant and at intervals. Depending on the load and how fast the battery discharges should determine how frequently you take measurements.\n\nmsg me when you have the data if you need help analyzing it.
856026
Use the gas law\nPV=nRT
7127
here's a site with pics that might give you some ideas:\n\n\nhttp://www.physics.usyd.edu.au/competition/comp1998/comp98.html
928663
Are you asking for help or an answer?\n\nTake any 2 equations and multiply all of the terms or one or both by numbers that will make one of the terms in each equation have the same coefficient. Now subtract one from the other and the term will disappear. Now take the resulting equation and do the same with it against the third. Keep doing this until you are down to one term and solve for the variable. Now substitute the variable into the equation and solve for the other variables.
179131
Try this:\nhttp://kr.cs.ait.ac.th/~radok/physics/f3.htm
693418
Well see as though you dont really have much time for a project that involves a control... But here is an awesome listing that has loads of ideas with explicit instructions not to mention material list for a wider variety of projects. Since I have no clue what realm of science you were intrested in... This has a little bit of them all! Good Luck!\n\nhttp://school.discovery.com/sciencefaircentral/scifairstudio/ideas.html
645991
ok...\n\ntry this...do a little research on Newtonian versus non-Newtonian fluids. (see link)  There are several types of fluids (this is a very important topic in Chemical Engineering, so don't be worried if you don't understand all of the mathematics on this link).\n\nSet up a web/video camera above a bowl containing one of each type of fluid in the table. Make sure you have a ruler or some other scale in view of your shot. Then take turns dropping:\n1) Large marble\n2) Small marble\n3) Pencil\n4) die (singular of dice)\n\nwhile you photograph the results.  Discuss General shape differences of the waves generated by the objects.  And discuss wavelength differences (measured using the ruler in your shot and freeze frames of the video) between the different types of fluids.  \n\nThis project will yield some cool photographs and a demonstration will act as an awesome visual aid as well.\n\nHope this is what you were looking for. If not, or if you need any additional information, feel free to contact me. Good luck.
696750
try the following. they are really helpful.\n\nwww.tutor4physics.com\nwww.physicsclassroom.com
1064629
find the surface area first (thats easy). Then given that the emissivity of th sphere is .851, and that the rate of change will be the change of temp/time. Since there is no time involved directly, we need to have the Surface area x emissivity rate / the temperature difference (in relation to the time, which is given within the emissivity rate). This should give u the net rate, depending on the emissivity/time relationship. You do the working out, otherwise you won't learn it.
379801
This website does all the work.  Just put in the values!  Good luck.  http://www.onlineconversion.com/temperature.htm
861788
There is no accurate way to do this because too many variables are involved. You can do like I do though and run a series of tests and then average them.\n\nhttp://www.toast.net/
741999
whats the equation or formula u need help with?
212435
I do not have a scientific calculator at the moment, but maybe i can borrow yours ;)
928401
A variable is something that changes. In a science project, the independent variable is the thing you are changing. For example, if you are experimenting on the growth of plants with different types of liquids (like water, orange juice, whatever), the independent variable would be the liquid you feed the plant. The dependent variable in the same experiment would be the growth of each plant. The dependent variable is always something you can measure (temperature, height, mass, etc.)
547532
Your nearest rainbow? Just kidding!\nTry this site: http://physics.nist.gov/PhysRefData/Elements/legend.html
62664
Kinetic, potential, nuclear, chemical and electrical.
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck