4 < 3x < 16 { intergers} How do you get x by itself?
959165
(4/3)<(3/3)x<(16/3)\nboth sides are divided by 3, so you will not change the original\ninequalities. \nso, 1.333<x<5.333,\nx=2,3,4,5, for all integers.
2302
(1) = x\n(2) = / \n(3) = x
225094
Either X with the upper value -4, or 1/x to the fourth power.
789893
x+4(2x+1)=3( x-2)+10x : x=2.5\n\nI like to work with x
846594
I'm not entirely sure if you meant (11-3X) on the top, or 11 - (the rest). I'm going to assume the former - if not, hopefully you'll be able to work it out yourself with the same method.\nWe want to express (11-3X)/((X-1)(X+3)) as A/(X-1) + B/(X+3) for some A and B. There are a couple of ways of doing this.\nThe purely algebraic way would be the following:\nFirst put everything over a common denominator: that gives a numerator of A(X+3) + B(X-1) = AX+BX+3A-B by crossmultiplying. So we want (A+B) = -3 to get the X part working, and 3A-B = 11 for the constant bit. Add those equations to get 4A = 8, so A = 2, and thus B = -5.\nSo its 2/(X-1) - 5/(X+3).\n\nThere is another way that works that you may find easier. 'Cover' the (X-1) part on the denominator with your hand. Now its perfectly fine to substitute X=1, since you can't see the divide-by-0 on the bottom. When you do that, you get 8/4 = 2.\nSimilarly, cover the X+3 part, and substitute X=-3. That gives 20/-4 = -5.\nAnd those two numbers happen to be precisely the same numbers we came up with before. And that always works.
771358
3x + 4 < x + 8\n2x < 4\nx < 2\n\n{x | x < 2}
228750
x xxxxx x\n    x----->\n\n<--x    x x--->\n    x
721099
4a + 3b = 4x4 + 3x(-4) = 16 - 12 = 4
408554
yes. take out an x \nyou answer should be x(x+3)
205373
1. Distribute the 4 on the left of the = sign\n   4(4x) + 4(1)\n2. Distrube the 3 on the right of the = sign\n   3(4x) - 3(5)\n3. Combine like terms and solve\n\n16x + 4 = 12x - 15\nsubtract 4 from each side, then subtract 12x from each side.  Divide each side by the number in front of x to find what x equals to.
811806
If x is 2, then 8x is 16.\n\nIf y is 3, then 4y is 12.\n\n16-12 is 4.  :o)
315839
keep a table of binary 4 bit equivalents 0 1 2 ... F of hexadecimal degits.\nconvert each 4 bits of your binary no. to equivalent hex. no looking the table.\n\nyou got the answer
881943
I see what you did -- you added 3x + x to get 4x, but you knew your answer had to have a square, so you made it 4x².  Then you added 8+5 to get 13, for a final answer of 4x̍ + 13.\n\nThat's not how to do these.  You need to multiply here, not add.\n\nUse a method called FOIL - which stands for First, Outside, Inside, Last.  I will demonstrate it for you with your problem:\n\n(3x+8)(x+5)\n\nF - multiply the FIRST terms of each parentheses:\n\n3x * x = 3x²\n\nO - multiply the OUTSIDE terms of each parentheses:\n\n3x * 5 = 15x\n\nI - multiply the INSIDE terms of each parentheses:\n\n8 * x = 8x\n\nL - multiply the LAST terms of each parentheses:\n\n8 * 5 = 40\n\nNow that you've done the FOIL multiplication, you can add up your terms, as follows:\n\n3x² + 15x + 8x + 40\n\nFinally, combine your like terms (the 15x and 8x) to get your final answer:\n\n3x² + 23x + 40\n\nHope that helped!\n\n~ ♥ ~
1110742
12 simply place the 1 where the x is\n\n(1+3)(1+2)\n4*3\n12
863644
take out 4x first\n4x(x2-6x+8)\n4x(x-4)(x-2)
101082
(x-1)/4 > 3\nx-1 > 12\nx > 13
196269
i took this question to mean as:\n\n[11/ (4-x)] + [2x/ (16-x^2)]\n\nso, what you do first is to multiply addends by (-1/-1), which is still equal to one, and won't make a difference, except to change the signs.\n\nso it would look like\n\n[-11/ (x-4)] + [-2x/ (x^2 - 16 )]\n\nsimplify to:\n\n[-11 / (x-4) ] + [ -2x / (x+4) (x-4) ]\n\ncombine the elements:\n\n[(x+4) + (-2x)]/ [(x+4) (x-4)]\n\nto make \n\n[(x+4-2x)]/ [(x+4) (x-4)]\n[(-x+4)]/ [(x+4) (x-4)]\n[-(x-4)]/ [(x+4) (x-4)]\n\nand the simplest would be:\n\n-1 / (x+4)\n\n hope this helps. :D