Math Help Needed here please?
958006
in order to solve the system of equations you can do one of two things.  The easiest thing to do is to set the two equations to be equal. i.e. \n\nsince y=2x and y = -3x+5, then 2x=-3x+5.  In solving for x you will find that 5x=5 or x=1.  Then you can plug your resulting x back into the equation to get y=2(1) =2.  The main thing you are trying to do is get one of your variables to be equal to some combination of your other variables.  For example, if you are trying to solve 3y+2x-1=5x+3 and 6y=2x+7.  The first thing you want to do is to get a single variable by itself on one side of an equation.\nLet's start with the first equation, 3y+2x-1=5x+3. You would try to group the y terms by themselves on one side of the equation, an group the x terms and constants on the other side of the equation.  In this example, in order to group the terms correctly, you would have 3y=3x+4.  Then solve for y by itself by dividing both sides by 3.  The result is y=x+4/3.  You take this result and substitute for y in the second equation, 6y=2x+7.   You will get 6(x+4/3)=2x+7.  Then you solve for x by itself.  6x+8=2x+7\n4x=-1;  x=-1/4.  Then you can substitute this result back into either of your original equations to produce your solution for this system.  6y=2(-1/4)+7 => 6y=13/2 =>y=13/12.  In order to check your answer, you can graph the two linear equations.  Where the two lines intersect is the solution to your system.\n\n\nIf you are looking for a more advanced way to solve a system of equations, then you may want to consider using an augmented matrix.  Rearrange your equations so that you have only variables on one side of your equations, and only constants on the other side of your equations, then sole the system of Ax=b.  The matrix A is the coefficients of your variables, and b is a vector of your constants.  x is a vector of your variables.  Augment the matrix of your coefficients with your constant vector and do Gaussian Elimination until the matrix is in reduced row echelon form.  This will provide the exact solution to the system of equations.
1053054
Use the binomial.  I've already shown you how in a previous question.  And you already know that you need to use it.
945604
1.adding-2f-7\n-6f-2f+7-7<2f-2f-9-7\n-8f<-16\ndividing by -8\nx>2\n\n2.5/8g-4>2/3g+6\nadding 4\n5/8g>2/3g+10\nmultiplying by 24\n15g>16g+240\nadding -16g\n-g>240\ndividing by -1\ng<-240\n\n3.sum incomplete\n\n4.-2 1/9d+3/5<-3 2/9d-4 2/5\n-19/9d+3/5<-29/9d-22/5\nmultiplying by45\n-95d+27<-145d-198\nadding 145d\n50d+27<-198\nadding -27\n50d<-225\ndividng by 50\nd<-5 1/2
61956
try to follow\n\nx/2-10=a\na/2-4=b\nb/2-2=6\n\nsolve and substitue\nb=16\na=40\nx=100 --the original amount\n\nhope that helped
821450
go to a math website off yahoo. it should help.
958757
So lets start with the first one. Make a division problem with 9.0 on the outside and 0.9 on the inside. 9.0 does not go into 0 but does go into nine. Raise the decimal and the answer is ten. It's a bit difficult to explain but here's your answers and when you go in next time ask your teacher for help::\n1. 10 \n2. 8\n3. 4.7\n4. 3.2\nOkay theres a few for you and you should be able to figure out the rest. For the next part you take what x is equal to and divide it by 1.2. So for\n13. 40.8/1.2=34\nAnd do the same for the rest!!\nGood luck!
538044
hmmm...very tough one!\n\nill sovle by the formula!\n       _________\n-b +- V (b^2)-4ab\n------------------\n       2a\n       _________\n-10 +-V 100+512\n------------------\n       2\n\n       _________\n-10 +-V 612\n------------------\n       2\n\n-10 +- 24.7\n------------\n     2\n\n14.7/2\n\n34.7/2\n\n(7.35, 17.35)
942916
your question has a problem...............\nif the sum is 13, then the other number has to be -35, which will not meet your other condition
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
538111
yeah.....!!!! just calculate it!!! lol
298505
7.7460824293385895341052207744781\n\nFollowing Correct order of operations:\n\n2 + (2x24.546/8.54356)+10*0\n\n2 + (5.7460824293385895341052207744781) + 0\n\n7.7460824293385895341052207744781
111021
If you are sloving for X then anything greater than 2 will work. basically it is 6 time what (X) will be greater than 12. Well 6x2=12 so that won't work.
1168806
Do your own math homework...
800717
(1) First one is copied wrongly by you                                            (2) Where is the equal to sign?                                                        (3)This equn. also cannot be solved                                              (4)-p/16+5=9  Multiplying all the terms by 16 ,we get -p+80=144   =>-p=144-80=66 Therefore p=66 YOU SHOULD BE MORE CAREFUL BEFORE SENDING YOUR PROBLEMS TO YAHOO ANSWERS.HOWEVER,YOU MAY SEND THE CORRECTED VERSION OF THE PROBLEMS TO ME IMMEDIATELY THROUGH YAHOO ANSWERS.
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
107813
Is this really a math question???\nP.S. I don't know.
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.