You are confronted with the following formula:A * [(B + C)(D - E) - F(G*H) ] / J = 10?
960274
267835149\n\n2[(6+7)(8-3)-5(1*4)]9=\n2[13*5-20]/9=\n2[65-20]/9=\n2*45/9=10\n--------------------------\nalso: 267953148\n\n2[(6+7)(9-5)-3(1*4)]/8=\n2[13*4-12]/8=\n2[52-12]/8=\n2*40/8=10\n-------------------------\nalso: 678413259\n\n6[(7+8)(4-1)-3(2*5)]/9=\n6[15*3-30]/9=\n6*15/9 =10
974937
please complete the equation
1154468
make a common denominator\n\na/b - c/d = a*d/b*d - c*b/d*b = (a*d-c*b)/b*d
843373
1.a3 times a6 =                 a9\n2.(h2)to the fifth power=    h10                \n3.(m4)to the eighth power=m32\n4.(x3y2)to the 3rd power=  x9y6\n5.(2s4t5)to the fourth power=16s16t20\n6.(-pqr2)to the third power=   -p3q3r6
145213
Since A=4,\nThere are four forms for B+C+D=13:\n9+3+1\n8+3+2\n7+5+1\n6+5+2\n\n\nThere are five forms for G+H+I=17:\n9+5+3 [Not valid 5 and 3 are already used for B+C+D]\n9+6+2  \n9+7+1 \n8+7+2 \n8+6+3\n \n\n\nPosibble values for (the order could vary)\nB+C+D and G+H+I then E+F\n9+3+1 and 8+7+2 then 5+6\n8+3+2 and 9+7+1 then 5+6\n7+5+1 and 9+6+2 then 3+8\n7+5+1 and 8+6+3 then 2+9\n6+5+2 and 9+7+1 then 3+8\n\nFirst conclussion E+F=11\nThen D+G = 6\n4+2 [Not Valid, A=4]\n3+3 [Not Valid...]\nValues of D and G  should be 5 and 1\n\nSumarizing:\n\nA = 4\nB+C+D = 6+5+2\nG+H+I = 1+7+9\nE+F = 3+8\n\nTHEN:\n D=5\n H=1
965349
I believe you meant (2x^2 - 3x - 2 )/ (10 + x - 3x^2) right?\n\nWell we can rearrange the problem to look like (2x^2 - 3x - 2 )/ (- 3x^2+ x +10)\n\nWe now factor out the top and factor out the bottom.\n[(2x +1) (x-2)] / [(-3x-5)(x-2)]\n\nSince this is a fraction, we can cancel out the (x-2) because it is on top and the bottom.\n\nWe are left with:\n(2x +1) / (-3x-5)\n\nI think this is what you wanted, good luck and be careful of how you write your notation!
527089
Say a and b\na-b = 10 and a*b = 999\na = b+10 substituting this in another equation\n(b+10)*b = 999\nb^2+10b = 999\nb^2 + 10b - 999 = 0\nb^2 + 37b - 27b - 999 = 0\nb(b+37)-27(b+37) = 0\n(b+37)(b-27) = 0\nSo,\nb = -37 or b = 27\nand as a = b + 10\na = -27 or a = 37
483906
if you want a quick guess, use the rule of thumb, F=2*C+32\n\nif you want it exact, use the formula which is, F=1.8*C+32
235893
(15y^3 + 12y^2)+ (5y+4)\nGCF 3y^2(5y+4)+1(5y+4)\n\n(5y+4)(3y^2+1)
743513
it's A\n\n4st+6t -10s-15\n2t(2s+3) -5(2s+3)    \n(I factored out the negative for both numbers in the -10s-15)\n\n(2t-5)(2s+3) or (2s+3)(2t-5)
757374
Hello again darling \n\n3(m-2)-(m=4)=8\n\n● Step 1 \n3(m-2) = \n(3 * m) + (3 * -2 ) =\n3m - 6\n\n● Step 2\n-(m - 4)= \n-m + 4 \n\n● Step 3\n3m - 6 - m + 4 = 8\n( 3m - m ) = 8 +6 - 4\n2m = 10\nm = 10 / 2\nm = + 5\n\nGood Luck Sweetheart ♣
853859
g(x) = x^5+5x^4+10x^3+10x^2+5x+1 = (x+1)^5\n`
25946
=3fg*(f^2g)+3fg*5f-3fg*4\n=3(f^(1+2g))*g+15(f^2)g-12fg
1161844
use this formula:\n\n[ g(h)  -  g(0)  ]    /   [ h  -  0 ]\n\ni.e.\n\n [  2/(h+1)   -   2/(0+1)  ]  / [ h  -  0  ]  =  [ 2/(h+1)   -  2]   /h\n\n=  [( 2 -2h  -2) / (h+1) ]  / h   =  -2/(h+1)\n\nTry it for f(t)
84658
i got it!\n\nit's 3(2c+7)(c-4d)(c+d)!!!!\n\n6c^3 + 21c^2 - 18dc^2 - 63cd - 24cd^2 - 84d^2\nfirst we take out factor 3:\n3(2c^3 + 7c^2 - 6dc^2 - 21cd - 8cd^2 - 28d^2)\nthen we take out (2c+7) from each pain inside the parenthesses:\n3[(2c+7)c^2 - (2c+7)3cd - (2c+7)4d^2)]\nwe take (2c+7) out:\n3(2c+7)[c^2 - 3cd - 4d^2]\nwe factor [c^2 - 3cd - 4d^2] trinomially:\nc^2 - 3cd - 4d^2 = (c-4d)(c+d)\nthen we get:\n3(2c+7)(c-4d)(c+d)\n\nam i right??\n\n:) yeah i didn't believe myself...\nbut if u really write down all your factors, it's much more easier to take them out. and it WAS fun :))
1181427
ABC+ABD+C'D\n=ABC+ABD(C+C')+C'D\n=ABC+ABCD+ABC'D+C'D\n=ABC(1+D)+C'D(AB+1)\n=1ABC+1C'D\n=ABC+C'D
703485
1) 9 * (t + 1)\n2) 8 * (v + 7)\n3) 25 * (5 - h)