If you have two points with the slope how do you put it into standard form?
953409
(3,7) (1,5)\n\n5-7/1-3=  -2/-2= 1 so that is your slope (1)\n\ny=mx+b....m= slope, and b= y intercept\n\ny=1x+b then plug in x and y from one of your coordinates\n\n7=1(3)+b\n7=3+b\n4=b\n\ny=1x+4\n\nthen you put it into standard form
1161836
One way to write the equation of a line is\ny - y1 = m(x - x1)\nwhere m is the slope and (x1, y1) is a point on the line.\n\nGiven your information,\ny - 4 = -2(x - 1)\nThat is the point-slope form of the line.  This can be changed to slope-intercept form:\ny - 4 = -2x + 2\ny = 2x + 6
911563
Here's 2 examples:\n\n1.) Given point (2,2) and (3,3), find the function.\nStep 1: Find the slope.\nSlope = rise/run = (y2 - y1) / (x2 - x1) \n(3 - 2) / (3 - 2) = 1/1 = 1.\n\nStep 2: Given the slope, find the y intercept by trying to find a point (0, y) that fits the 2 points above, and the slope given.\nUse the slope formula: rise / run = 1\n(2 - y) / (2 - 0) = 1 = (2 - y) / 2 \n2 = 2 - y\n-y = 0\ny = 0\ny intercept = 0, 0\n\nStep 3: Once you have the slope, you can write it in slope intercept form:\ny = mx + b \nm = slope, b = y intercept\ny = 1x + 0, or y = x.\n\n2.) (a harder one) Given point (1,4) and (-3, 2), find the function.\nStep 1: Find the slope.\nm = rise/run = (y2 - y1) / (x2 - x1) \n(4 - 2) / (1 - -3) = 2/4 = 1/2 = .5\n\nStep 2: Given the slope, find the y intercept at (0, y)\nm = rise / run = 1/2\n(4 - y) / (1 - 0) = 1/2 = (4 - y) / 1 \n4 - y = 1/2\n-y = -3.5\ny = 3.5\ny intercept = 0, 3.5\n\nStep 3: Write it in slope intercept form:\ny = mx + b \ny = .5x + 3.5
872809
If the equation is lineear, or a line like it sounds like, the equation is y=mx+b. m is the slope or ten. and b is the y-int. or -130, and you are done
895612
Standard form? you mean in the form y= ax + c?? \nIn that case:\ny = 2x + 4 + 13 (add 13 to both sides)\n\ny= 2x + 17
849727
Solve for y to get it in y = mx + b form.  Then the slope is m.\n\n1) 2x - y = 14\n\nSubtract 2x from both sides:\n-y = 14 - 2x\n\nDivide by -1:\ny = 2x - 14\n\nSo the slope is 2.\n\n2) 13 = 20x - 5y\nSubtract 20x from both sides:\n13 - 20x = -5y\n\nDivide both sides by -5:\ny = 4x - 13/-5
743347
It all depends on what result you're hoping to get.  For example, if you want to solve a system of equations in two variables, you would try to get the variables on the same side in both equations.  If you want to express the equation in slope intercept form, you would move the y variables to the left side and the x variables and constants to the right side of the equation.  If you're trying to express the equation in standard form, i.e. ax + by + c = 0, you want both variables on the same side.
206717
Slope = 1/4\n\nSlope is the "change in y" divided by the "change in x" (AKA "rise" over "run").\n\n(x1, y1) = (1, 3)\n(x2, y2) = (5, 4)\n\nThus:\n\nm (slope) = "delta y"/"delta x"\nm = (y2 - y1)/(x2 - x1)\nm = (4 - 3)/(5 - 1)\nm = 1/4
903948
find the slopes of both lines and if there answers are opposite recipricals, then they are parrallel\n\nheres adn ex:\nslope = 2 and -1/2\n\nin other workds, if you multiply the two slopes, u should get -1
789216
Try to find a trend in the table.  For example if the table were to tbe like x: 5, 6, 7 for y: 8,10,12, respectively.  Then, go from y to x and try to find some eqation that fits.  For the example, it would be 8 = b + 5m (in which be is some number that gets added to y and m is the constant slope).  The other equation would be 10 = b + 6m, in which b = 10 -6m.  Thus, since the b in the first equation and the second are the same, substitute.  8 = (10 - 6m) + 5m.  8 = 10 - m.  m = 2.\nFind b now by plugging in m.  8 = b + 5(2).  b = -2.\nThus, the equation is y = 2x - b.
943301
Use the standard equation for a line going through two points.\n\nI.e. for two points (x1,y1), (x2,y2) the equation is : \n   (y2-y1)/(x2-x1) = (y-y1)/(x-x1).\n\nIn this case we have (x1,y1)=(0,-5) and (x2,y2)=(8,9), so\n   (9-(-5))/(8-0) = (y-(-5))/(x-0)\nwhich computes to\n   14/8 = (y+5)/x\nor, in standard format\n   y = (7/4)*x - 5\n\nIf you now check (fill in those two points) you will see it is the correct equation for both.\n\nHope this helps :-)
158205
Base on the Mathematics for STPM, Penerbit Fajar Bakti SDN.BHD. ,written by Ong Beng Sim...From the cphater 5,Coordinate Geometry, the actual standard form is ax/2+y/2=1.\n\nTo change the form:\n\nfind the axis-y & axis-x first,\n\nwhen y=0, x=2/a (axis-x)\nwhen x=0, y=2   (axis-y)\n\nBase on the standard form of linear funtion is x/a+y/b=1, where, a is axis-x and b is axis-y.\n\nso, substitute the axis-x & axis-y into the standard form of linear function...\n\nTherefore, the standard form of the linear funtion for y=-ax+2 is ax/2+y/2=1
952901
since the y intercept is 1, put a mark one tick above the origin, then since the slope is -1, put a mark down one and to the right of that one.  then do that a few times to make a line.
1038364
Formula for linear slope is y=mx+b\n5y=10x-10\nDivide the 10x-10 and 5y  by 5 to get\ny=2x-2\n-21+7y=14\nAdd -21 to both sides to get\n7y=35 Hence y=5\nx=-5 The slope is undefined. IF you graph the line and take two coordinates and use the formulas (y2-y1)/(x2-x1) you get 0 at the bottom. Anything divided by 0 is undefined.\nY-5=2 is add the 5 to both sides to get y=7
850944
You have 2 points, (x1,y1) and (x2,y2) and you want to find the equation of the line that goes through these points.\n\nThe first thing you want to do is find the slope.\nslope is rise/run so m = (y1-y2)/(x1-x2)\n\nFor slope intercept form , y = mx + b\nwhere m is the slope, and b is the y intercept\nnow that you have found the slope, you can solve for b, the y intercept by plugging in your value for m and one of the given points, either (x1,y1) or (x2,y2).\n\nFor point slope form,  y - K = m(x - H)\nm is the slope, and   (H,K) is a point that the line passes through.\nSince you have already calculated the slope, m, for the slope intercept form, you're already almost done. All you have to do is plug in the point (x1,y1) or (x2,y2). In your question, you are asked for the point slope form of just point (6,2).
45255
5 is where you put the first point on the Y axis. Count up 5 in the middle and put a dot.\n\nIf it has X by it it is the slope.\n2x means the slope is 2, or, 2/1, which means move up 2 and to the right one and put another dot.\n\n\n|    /\n|  /\n|/\n|\n|\n|\n|___________
892240
Slope is Y2 -Y1 divided by X2 - X1\n\nIn your example, Y2= 12\n                            Y2= -7\n                             X2= 0\n                            X1=-2\nSo... \n(12-(-7)) / (0-(-2))= 19 / 2 = 9.5\n\nThe slope of the line is 9.5