Objects with masses of 215 kg and a 515 kg are separated by 0.300 m.?
967250
The gravitotional force F of two masses m1 and m2 separated by a distance r is given by the equation\n\nF = G * m1 * m2 / r^2\n\nwhere G is a physical constant with value 6.67*10^ -11 N*m^2/kg^2\n\nSInce the third object is placed midway then its distance from either m1 or m2 is 0.15 m.\n\nSubstituting we get\nF1=3.9*10^-5 N\nand\nF2=9,5*10^-5 N\n\nSince the two forces have opposite directions then \nFtotal = F1 - F2 = -5.6*10^-5 N having the direction of F2.\n\nIn order for total to be zero we have\nF1=F2 ->\nG*m1*m/x^2=G*m2*m/y^2 ->\nm1/x^2 = m2/y^2 ->\nm1*y^2=m2*x^2 (1)\n\nwhere x and y the diastances of m from m1 and m2 respectively.\n\nsince\n\nx+y=r=0.300 m\n\nit follows that y = 0.3-x (2)\nCombining (1) and (2) we have\n\nm1*(0.3-x)^2=m2*x^2 ->\n215*(0.09-0.6*x+x^2)=515x^2 ->\n300x^2+129x-19,35=0\n\nsolving this we get\n\nx1=0.12m\nand\nx2=-0.55 m which is of course rejected since it represents a point where there can be no equilibrium.
280622
3m = 300cm\n300 - 197 cm = 103 cm = 1.03m
800535
jinde, hi!\n\nwhat an amazing question!  i remember reading about this somewhere, so it took me so long to research it...\n\nsee, when we talk about weight, it varies from spot to spot in the universe.  you may weigh 60kgs on Earth.  but on the moon, you'd be 10kgs.  on Jupiter, you'd be 600000kgs!!!\n\nwhat we need to discuss is the mass of the object, because that would be the only thing that makes sense on the Galactic scale.  are you ready for the answer?  it's gonna be mind-boggling!\n\nThe Earth's mass is approximately 6,000,000,000,000,000,000,000,000 (6E+24) kilograms!!\n\ni know what you're next question will be?\n\n"How did they measure that?"  i have the answer for you!\n\nthe measurement of the planet's weight is derived from the gravitational attraction that the Earth has for objects near it.\n\nit turns out that any two masses have a gravitational attraction for one another. if you put two iron weights near each other, they will attract one another gravitationally. the attraction is extremely slight, but if your instruments are sensitive enough you can measure the gravitational attraction that they have on one another. from that measurement, you could determine the mass of the two objects. the same is true for two marbles too! but the attraction is even slighter because the amount of gravitational force depends on mass of the objects...\n\nNewton showed that, for spherical objects, you can make the simplifying assumption that all of the object's mass is concentrated at the center of the sphere... and the following equation expresses the gravitational attraction that two spherical objects have on one another :\nF = G * M1 * M2 / R2\n\n    * R is the distance separating the two objects.\n    * G is a constant that is 6.67259x10-11m3/s2 kg.\n    * M1 and M2 are the two masses that are attracting each other.\n    * F is the force of attraction between them. \n\nassume that Earth is one of the masses (M1) and a 1-kg sphere is the other (M2).  the force between them is 9.8 kg*m/s2 -- we can calculate this force by dropping the 1-kg sphere and measuring the acceleration that the Earth's gravitational field applies to it (9.8 m/s2)...\n\nthe radius of the Earth is 6,400,000 meters (6,999,125 yards)... if you plug all of these values in and solve for M1, you find that the mass of the Earth is 6,000,000,000,000,000,000,000,000 kilograms (6E+24 kilograms / 1.3E+25 pounds)...\n\nhope this made sense... and if it did, i hope it was useful to you...\n\ndo write me if you need more clarification...\n\nenjoy!
40169
The force on the system is 3.0 kg x g. (the only force is due to gravity acting on the hanging mass) The mass of the system is 3.0 kg + 5.0 kg = 8.0 kg.  The acceleration of the system is a = force/mass = 3.0 kg x g / 8.0 kg   =  3 / 8 g or 0.375 x 9.8 = 3.675 m/sec^2
823430
the buoyancy of the object and its volume.
960920
0.07896 km\n153 mm\n0.578  km
975661
Depending on which reference you go by, it is in the vicinity of 6.0 X 10^24 kilograms.  \n\nSince, 1 kilogram = 0.00110231131 short tons we can say that the earth weighs approximately 6.61386787 x 10^21 short tons.
121693
cmon...dont u know basic physics...just calculate the resultant of these 2 forces\nanswer= [(132)^2 + (181)^2]^1/2\nif this makes sense!!
787981
let al' mass be m\n\nconserving momentum\nm*0.91=(158-m).829\nsolving for m we get\n         m=75.320kg
754188
you divide the mass by the volume\n1.2.14 g/cm^3\n2..82 g/cm^3\ngood luck!
417845
It has no mass. But it has relative mass of ≤ 1. It is a matter.
945010
Equatorial gravity 3.69 m/s2\n(0.376g)
321421
0.215 kL = 215L\n(1kL = 1000L)
255172
Density = mass/volume\nDensity = 615/105 gm/cm3 = 5.86 gm/cm3
57362
Weight is a unit measure of gravitational force.
621321
If the density is 'd' kg/m^3 then the weight is '9.81d' Newton. [remember weight is force]
997326
Use Newton's universal gravitation equation, then sum the forces.\n\nF = G*m1*m2/r^2\n\nF = force (newtons)\nG = gravitational constant (6.6742 x 10^-11)\nm1 = mass of object 1 (kg)\nm2 = mass of object 2 (kg)\nr = distance between objects (meters) ==> don't forget to convert the units\n\nIn this case, you do it twice:\nF1 = G * 390 * 390 / 0.11^2 = 0.84mN to the left\nF2 = G * 390 * 390 / 0.39^2 = 0.067mN to the right \n\nNet Force = 0.84 - 0.067 = 0.772mN to the left