AS Chemistry equation..?
968007
Multiply 0.7 by the Mr of NaClO to get grams per litre, divide by 10 to get it per 100 cm cubed, and compare the answer with that printed on the bottle.
895751
Al2S3 + 6H2O -> 2Al(OH)3 + 3H2S\n\nP4O10 + 6H2O -> 4H3PO4\n\n\nShould be right.
683249
Oh, come on, it doesn't get any easier than this!\n\nSnO2 + 2H2 --> Sn + 2H2O\n\nAbove is balanced. 1 Sn on both sides, 2 O on both sides and 4 H on both sides.\nYou need to work a little harder on these yourself.
539827
(a) 2 NaClO3 -> 2 NaCl + 3 O2\n\n(b) 3 MnCl2 + 2 Al -> 3 Mn + 2 AlCl3\n\n(c) C4H10 + 13/2 O2 -> 5 H20 + 4 CO2 \n                  or\n(c) 2 C4H10 + 13 O2 -> 10 H20 + 8 CO2\n\nBalancing is quite simple for these simple equations. You just have to see the left hand side pick up an element, see how many atoms of that element are there in it and multiply the R.H.S compound containing that element with a number which will be equal to no. of atoms in the l.h.s. Then again repeat the procedure by picking another element.....see it's quite difficult to explain you with writing aneways i hope it helps u :)
1040448
ask your chem prof or tutor ..it's hard to explain over the internet!
744647
C(3)H(8)+5O(2)=>3CO(2)+4H(2)O\nfuel+oxygen=>carbon dioxide+water\ncombustion \nbrackets-subscript
976540
a) +1\nb) 0   (in molecule state)\nc) 0\nd) -3\ne) 0\nf) +4 of Carbon\ng) +2 of Mg\nh) +1 of Chlorine (interesting!)\ni) +6 of Sulphur
967763
Equivalent to [H+]^2/([HCH3CO2] - [H+]).  You can solve for [H+] knowing Ka and [HCH3CO2].
843441
The answer is c.\nC12H22O11+12O2-->12CO2+11H2O
758773
6O2 + C6H12O6 ---> 6CO2 + 6H2O
657532
Do you mean a reaction?  Some can be tracked by analytical methods.  Chemical equation has no meaning in this context.
866732
do you want to know how to balance chemical equations? It's actually quite simple when you know how\n\nrather than asking for direct answers, it's better if you know how to do it for yourself\n\nI'm not going to answer your questions but show you how to do it for future reference\n\nH2 + O2-->H2O\n\nthe above equation is not balanced because there is only one oxygen atom on the right and two on the left\n\nnow, how do we balance this?\n\nfirst thing we need to do is ensure that there are equal amounts of atoms on the left and on the right\n\nso, to balance that equation\n\nwe will write\n\n2H2+O2-->2H2O\n\nthe equation is now balanced with respect to equal atoms on the left and right\n\nin words\n\n2  molecules of hydrogen  react with 2 oxygen atoms to produce 2 molecules of water\n\nthere are now 4 hydrogen atoms and two oxygen atoms on each side of the equation\n\nthe 2 in front of each compound represents the molecules and the subscripts represent the number of atoms
954811
C3H8 + 5O2 --> 3CO2 + 4H2O
867158
2Mg+O2-->2MgO\n2MgO+2H2o---->2Mg(OH)2
1185900
H2SO4 + 2KOH --> K2SO4 + 2H2O
1049588
I think that you are trying to find the net ionic equation. \nWhich in this case would be \nAg+ (aq) + Br- arrow AgBr (solid)\nif you are trying to find a single replacement reaction?\nthen you need to put Br- instead of NO3- and cancel out the NO3 - on the product side? \nTried my Best.
164045
What do you want a step by step set of instructions or a balanced equation?\n\n2C6H5OH + NaOCL = 2C6H50 + NaCl + H2O