If additional cards bearing the same number are requested for family members, what is the responsibility of?
957892
They are responsible for all of the cards issued on their account.  If they don't want to be responsible for the other cards, then the other family members must fill out an application and get their own account number and card.
848851
You may get your answer from Beckett. www.beckett.com they have a lot of cards on there. Just type the name (company) of the card and the year1999, you cand then type the person on the card and the no. 201 and click search.and you should be able to find it there.Good Luck.
431487
Columbia House allowed me to do that during the xmas holiday.  I had not planned on it, but I ordered several on the phone and then she asked me if I would prefer to be billed.  They may only do that if you are a member in good standing, I'm just not sure what the reqs are.
955592
you have to wait till you get the card before you can use it\nduh
1137758
1) Let's first consider not the combination but the permutations without repetition (considering the order).\n\nSuppose to have 39 numbered cards in your hands and shuffle them well. \nIf you get one card and you drop it on the table you have 39 different possibilities, obviously.\n\nNow, from the remaining 38 cards in your hands, If you drop another card on the right side of the previous card, you'll have 38 different possibilities for just that second choose, but If you consider the order of both cards you'll have exactly 39*38 = 1482 different possibilities that the 2 card will be ordered and choosen in that way.\n\nIf you get a 3rd card from the remaining 37 in your hand you'll have on the table in the right side of previous exraction, a group of 3 ordered cards choosen by 39*38*37 = 54834 different ways will be on the table.\n\nRecursively go to choose until 6 ordered cards will be the table and you'll have 39*38*37*36*35*36 = 2349088560 possibile ways if you consider the order. \n\n2) Now let's see what happend when the order of the selection matters as you asked in your question. \nSo let's make this consideration:\n\na) If you have one card (A) you don't mind about ordering problems:  {A} = (A)\n\nb) if you have two cards (A, B) you have to consider the couple (A, B) = (B, A) so we write {A, B} are commutative;\n\nc) if you have three cards "A", "B" and "C" you can group (A, B) as one element {A, B} because order doesn't matter (point b).\n\nSo we can consider the 3 cards (A, B, C) as:\n ( {A, B}, C ) = ( C, {A, B} ) as we made in the point b.\nYou could also group (A, {B, C}) = ( {B, C}, A)  or {A, C} and then swapping with B.\n\nSo with 3 elements we have 3 different ways to create couple to swap so we can create 3*2 = 6 different combination.\n\nIf we have 4 cards we know it's possible to choose 4 different ways to create list of 3 cards. Let's stop one each time with your finger and you can see that you can group easily the remaining other 3's.\nSo the possible combination with 4 cards is 4 times the possible combination I have with 3 cards. So it's  4 * (3 * 2).\n\nWith 5 cards you'll have 5 times the number of combinations we found with 4 cards, so it's  5 * (4 * 3 * 2).\n\nFinally, with 6 cards in a table arrange in 6 * 5 * 4 * 3 * 2 = 720 different ordered ways.\n\nNow, your question was how to do if the order of selection matters and in the previous example we find that the number of possibilities we have when we select 6 cards ordered is this number 39*38*37*36*35*34 = 2349088560. And we know now that this number is 720 times greater than the possibilities wether the order of selection doesn't matter. (720 = 6 * 5 * 4 * 3 * 2).\n\nIn other words, 39 * 38 * 37 * 36 * 35 * 34 is the number of permutations without repetition of 39 elements grouped by a list of 6 elements considering the order.\n\nAnd now we know with 6 elements you can have 6*5*4*3*2 possible different positions of those elements. \n\nSo Just divide 39*38*37*36*35*34  by 6*5*4*3*2 and you'll have the result of the combinations.\n\nSo to see how many combination of 6 cards bye a set of 39 just divide 39*38*37*36*35*34 / 6*5*4*3*2 = 3262623.\n\nthe number 6*5*4*3*2 could be wrote "6!" using the the factorial function.\n\nThe factorial function of positive integer n, is defined as the product of first n numbers:\n\nn! = 1 * 2 * 3 * ... * n\n\nand is a convention that the product of no numbers at all is 1.\n\n0! = 1\n\n\nThe factorial is also defined recursively by the follow definition:\n\n(n+1)! = (n+1) * n!\n\n\nSo if you have n object and you want to know how many permutation (the order matters) without repetition (each object can be chosen only once) the objects makes with a number k of selection the formula is:\n \n  n! / (n-k)!\n\nso it's the product of k terms starting from n and descending until reached (n-k+1).\n\nn*(n-1)*(n-2)*.
85962
have you contacted the greeting card companies? that seems like a good place to start.
54003
call and ask tell them you are related
783765
A card offering your services for for somthing personal, like cleaning ,or babysitting,etc.
189389
I don't know if you can but you can try the second website below. I suggest locating and contacting the nearest ID card facility and get their opinion.
115062
Send him an electronic card.
51087
I think that it is ok, but please remember that what you would see in the cards for a stranger, you will see something different for your family member with the same cards.  Another thing too, be very careful, because a family member will take far more to heart than a stranger.
310935
call the number on the back of the card.  trust me, they'll give you more info then you ever cared to know.
910099
I've got the same problem. What I do is I send my friends Christmas cards with my name only. Unless my mother knows them then I put her and my name on the card. I put both our names on the family cards unless it's my father and his family then it just my name.
1128635
it means you have to provide  two copies.
232731
You can just put his name and the address. As long as the address is correct the Mail Carrier will deliver the card. My Dad works for the Post Office as a Mail Carrier and said they deliver to the address not the person's name.\n\nA.H.
302849
I would say totally appropriate, probably 99% of weddings I've been to in the last 5 years have had some type of drop-box system for the cards.  Keeps from other people stealing them!
4125
it depends. From what I know, a store credit card is considered the same as a bank card (for your credit history). At any point it is good to have around 2-3 such cards open. any more or less, and you risk being considered as not such a good credit risk