math help,how to solve?
969498
You need to find a common denominator for each one.\n(7x+3)/x\n\n(40c+18z)/(15cz)\n\n(8+21)/6y = 29/6y
959479
all you need to do is go to www.webmath.com, it'll help u there!\n\nI always do my math problems to that site if ever i get stuck on something! It's helpful!
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
870123
Problem: 17x=51\n\nsolution:  17x=51 (divide 17x  by 17 which will cancel out and will leave x by itself, then do the same for 51. so 51 divided by 17 is equal to 3.) you are left with x on one side and 3 on the other, therefore x=3
598425
Solving for x in the first equation gives us...\n\nx + 5 - 5 < 4 - 5\nx < -1\n\nSolving for x in the second gives us...\n\n2 - 7x - 2 < 16 - 2\n-7x < 14\n---   ---   Here, don't forget to swap the sign\n -7    -7   since we are dividing by a negative.\nx > -2\n\nSo use that to find your solution set.  We know x must be less than -1 but greater than -2.  \n\nHope this is helpful.
425927
Solve for b and c for a.\nb = 4a/3\nc = 5a/3\nso\na * 4a/3 * 5a/3 = 1620\n\ntimes both by 3\n\n3a * 4a * 5a = 1620 * 3 = 4860\n\n60a^3 = 4860\n\na^3 = 4860/60 = 729\n\na = 9\n\nb = 4* 9/3 = 4 * 3 = 12\nc = 5 * 9/3 = 5 * 3 = 15\n\nB = 12\n\ngood luck!
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
784708
What is there to do to solve this?
760030
okay well pretty much you have to solve for  x\nso inorder to get X by itslef you have to -4 from -8 like so:\n2x + 4-4 = –8-4\n2x=-12\nnow you still have 2X but now you can divide the 2 into -12\nx= \nI won't give you the answer but you should be able to find the answer!!!
934652
So let's say the problem looks like this\n\n   11\nx 12\n--------\n        <-----the answer from 11*2\n       <------answer from 11*1\n\nfirst hide the 1 from the 12 and work out the problem as 11*2\nthen work on multiplying the 1 with 11 but make sure you start putting your answer down below your first answer and the answer starts in the column that is below the 1 from the 12.\n\nfinally when the two answers are found, you can add them and get your final answer. SOOO here's what it looks like\n\n      11\n   x  12\n--------------\n           22    (this is from 11x2)\n +  11       (this is from 11 x1)\n------------\n     132 = final answer!
831674
1. replace x with -3, calculate and see if you get 0\n2. divide by (x+3) and solve the remaining quadratic equation
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.
1160760
what you have is something like\na(b+c)\n\nthe solution is \nab+ac\n\n(x^3)(2x^-2)+(x^3)(4x)\nnow to multiply x^a * x^b you get x^(a+b)\n\n2x^((3+(-2))+4x^(3+1)\n\n2x+4x^4
61956
try to follow\n\nx/2-10=a\na/2-4=b\nb/2-2=6\n\nsolve and substitue\nb=16\na=40\nx=100 --the original amount\n\nhope that helped
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
610726
there is a solution, all x,y that satisfy this equation:\ny = 4 - 2x\n\nwhich is a straight line with intercepts (0,4) & (2,0)\n\nIt has an infinite amount of solutions. To be able to solve for actual numbers, you need as many equations as you have variables.
531205
2 + 2 = 4\n\nthats all I got