Graphing using Basic Shapes and Shifting?
958822
well, a square root function looks like...half of a bridge or an arc. it starts at (0,0) and gradually rises for infinity. there's your basic shape.  now i am not exactly sure on your equation, but if the +3 is INSIDE the squareroot, then you would shift the graph to the LEFT 3. (yes, the opposite) but if it is OUTSIDE the squareroot, then you would shift it UP 3.
918897
Note 6G • Graphing Inequalities\nGraphing an inequality is like graphing an equation except you select a graph style to shade above or below the boundary line. The calculator always graphs a solid line for the boundary regardless of the type of inequality.\na. Enter the boundary line equation into the Y= Editor screen and\npress [Enter].\nb. Highlight the boundary line equation, then press [2nd] [F6] (Style). (On a TI-92 Plus or a Voyage 200, press [F6].)\nc. Select 7:Above to shade above the boundary line, or select 8:Below to shade below the boundary line.\nd. Set an appropriate window and then display the graph.
531033
Draw it your self on x-y plane, then determine the coordinates
731311
I use GrafEq for my graphs, you could give it a try at http://www.peda.com/grafeq/
402025
In order to do this you need to set the stroke of your Graphics2D object something like this:\n\ng2D.setStroke(new BasicStroke(5.0f, BasicStroke.CAP_ROUND, BasicStroke.JOIN_ROUND)); \n\nTo learn more about creating a stroke check out the javadoc of the BasicStroke class here (JDK 1.5): http://java.sun.com/j2se/1.5.0/docs/api/index.html\n\n\nIf you only have a Graphics object then you can usually just cast it to a Graphics2D object like this:\n\ng2D = (Graphics2D)yourGraphicsObject;\n\nand then use this Graphics2D object to set up the stroke and draw the line.
403308
It is correct, but there's no way to paste diagrams here. Just draw the intersecting circles (i.e. 7 regions) and then shade the appropriate areas.
442406
Make a table of values.  Then plot the points.  Your graph should be a "V" shape (not a parabola which is U shaped)---whether upright, sideways, or downwards.
163337
Word wouldnt be the right software to be using for that... You should try EXCEL\n\nDepending on the task you might want to get something like d-plot.\n\nDPlot is a general purpose plotting program designed for scientists, engineers, and students. It features multiple scaling types, including linear, logarithmic, and probability scales, as well as several special purpose XY graphs and contour plots of 3D data. Manipulation functions include FFT, filtering, smoothing. Data can be input via file, copied from the clipboard, or sent to DPlot from another program via dynamic data exchange
727314
From y = x2 to y = x2 - 6 is: shift the graph 6 units 'down'.\nFrom y = x2 to (x + 5)^2 is: shift the graph 5 units 'to the left'.\n\nTh
363795
Well, if you think about it, you shouldn't have to copy. To make any shape 3D from 2D, just give it DEPTH. Draw lines slightly up and tilted from each corner, then connect them accordingly. It's super easy once you get the concept.\n\nFor pictures, go to www.mathworld.com and search for cubes, prisms, etc.
557940
google diagrams and draw it out
321282
GIMP (GNU Image Manipulation Program) will let you do that quite nicely. You can find it at http://www.gimp.org
819957
Start with a graph of:\nf(x) = x\n\nThat's a straight line going through the origin with a slope of 1.  It should look like a 45 degree angle if you draw it correctly.\n\nNow to transform this to:\nf(x) = | x |\n\nYou have to think of each value smaller than 0.  Rather than -1, for example, you'll have 1.  Rather than -2, you'll have 2, etc.  This is like "mirroring" the graph that is below the x-axis so that it is above the x-axis.\n\nThis results in a "V" shape.  A slope of -1 down to the origin, then a slope of 1 from the origin.\n\nFinally:\nf(x) = | x | - 2\n\nFor every value that results, you now subtract 2.  For example, x = 0, gives -2, rather than 0.  This is true for every point x, making every point y smaller by 2.  It would look like you shifted the whole graph down 2 units.\n\nSo it would be "V" like before, but it would go down at a slope of -1, cross the x-axis at -2, and continue to (0, -2).  Then it would slope up (m=1) through the x-axis at 2 and continue upward.\n\nYou can go to the first link and type 'abs(x) - 2' in the box.  The resulting graph is shown as the 2nd link.
731189
Yes. Shifting the binary point one position right doubles both the top and bottom.
933904
Yes, it is possible, and not too difficult.  You can use 2D drawing commands to create simple or complex shapes using the GDI+ library for .NET 1.1 (Studio 2003).\n\n  Research more about GDI, and build some simple applications.  There are many examples on the web.  You could easily draw colored boxes like a bar chart with heights relative to the histogram of data you've collected from SQLServer.\n\n Graphics can seem overwhelming at first (with scaling and other tricks), but start with the simplest example of just drawing a box with Graphics class.  Good luck!
7772
You can.  Use the mapping (x, y, z) -> x.  Of course, that is a many-to-one mapping, and kind of useless.
1027994
if you are asking .. how to sketch an eclipse ... take two verticies (two spots some distance apart left to right on a page) ... and using a compass play with intersecting the radius' of different lengths ... you will find that if you pick the one of equal length as the distance from the vertices ... you will get an intersection of the two radius' from the original vertices ... then playing with the new found radius' ... you will be able to place arcs on the ajoining vertices to creat the other two arcs and blend them together creating an approximate elipse ... a french curve help too