What is the range of wavelength fo visible light?
957910
The visible light region is from 0.7 µm to 0.4µm of the spectrum. The color of an object that we see is the color or wavelength of light reflected from the visible spectrum. All other colors or wavelength are absorbed. the following chemicals are different in terms of wavelength because of their different nature's regarding reflection of particular wavelength or the absorption of other.
975005
All light (or more technically, electromagnetic radiation) is waves.  Light waves have different frequencies.  Ultraviolet light waves have a frequency higher than light waves in the visible spectrum (the frequencies humans can see).  Infrared light waves have a freqency lower than light waves.  The terms come from the fact that violet has the highest frequency in the visible spectrum, and red the lowest.
290359
The energy of a photon is given by E = h*f where h is planck's constant and f is the frequency.  Since photons travel at the speed of light, c, the wavelength is just:\nlambda = c / f.\n\nThe spectrum of light goes from red to violet, where red has the lowest frequency (longest wavelength) and violet has the highest frequency (shortest wavelength).  This means that violet light has more energy per photon than red light.\n\nIn radiation heat transfer, a black body is an object that absorbs all incoming radiation and reflects none (stars are nearly black).  Also, a black body emits a spectrum of radiation based on its temperature.  A plot of monochromatic emissive power vs. wavelength shows the relative "concentration" of different wavelengths of radiation in the total output.  This plot has a characteristic shape given by Planck's Law of blackbody radiation, and it has a maximum at:\n\nlambda_max * T = 2898 micrometers * K = constant\n\nwhere T is the temperature in Kelvin\n\nThus lambda_max is inversely proportional to Temperature.  This means, as the temperature of the emitting body increases, the wavelength at which more of the energy is radiated at decreases (the frequency increases).\n\nI wish I could show you the loglog plot of monochromatic emissive power vs wavelength in Mills page 453.  It shows how low temperature bodies emit in the infrared and negligibly in the visible range and as the temperature increases, the maximum moves toward the visible range.  The sun, at 5800 K has a nice plateau maximum in the visible range which explains why being able to see light is so useful for us.  Another cool thing to see in the plot is that the curve is steeper on the low wavelength side than it is on the high wavelength side: this means that as you increase the temperature of an object, it will glow red and then white because anything hot enough to have its maximum in the violet range also has a large emissive power for everything colder than violet, so all colors of light will be present.\n\nSince a hotter body radiates at higher frequencies, in a sense violet light is "hotter" than red light.\n\nTake a look at the book (or another heat transfer engineering text).  I can't explain very well with only text.
374484
Since the UV light has particular wavelength and energy, the atoms in the florescent material absorbs that energy and goes to excited state from ground state. but it nomore stable in the excited state. so it emits an energy with is in the range of visible region with some particular wavelength and returns to ground state. the wavelength corresponding colour is visible to us....
210020
Monochromatic light is light that is all the same wavelength like light from a laser.
626191
I did find 0.47 for the refraction index "http://www.robinwood.com/Catalog/Technical/Gen3DTuts/Gen3DPages/RefractionIndexList.html" but I I do not know at what wave lenght that I am not seeing probably for green or blue. I found another values has well following:\nhttp://engr.smu.edu/ee/smuphotonics/Modeig/pages/MISC/RNCRIM.DOC\nn=0.18+i*5.72 for 900nm (near infrared)\nn=0.08+i*4.98 for 827nm (red)\n\nI do think it changes a lot with the wavelenght that you input\n\nI do not now if you know what the i means but is the imaginary part of the refraction index it reflects the absorption that light will suffer in the metal. Gold has a metal behaves to the the light much has it behaves  the plasma ones it has free electrons. This explines 2 things the imaginary part and second the value that is minus then 1. the imaginary part is due to the current that are induced when the light incidates in the metals it creates a current that consequently creates an energy lost. (ohm`s theorem) second the efect that is minus then one reflects that the phase velocity seams to propagate at a velocity larger then the velocity of light in vacuum ( its a rouder normal stuff in plasmas if you want to know more tell me I can inform you). Atention this does not mean that the energy travels faster then c it just means the phase does. \n\nif you want me to tell you why is it faster then light it is a litle bit more complicated but if you insist tell me
302610
The electromagnetic spectrum is the range of all possible electromagnetic radiation.\n\ngo to the site below, it has the chart
972525
Calculate it yourself, using the equation: c = f x w\nc = velocity of light in vacuum = 3 x 10^8 m/s\nf = frequency of the light\nw = wavelength (convert 4000 A to meters; 1 A = 10^-10 m)
834583
You can use the Rydberg formula, which relates the reciprocal of the wavelength of the photon absorbed or emitted to the squares of the reciprocals of the principal quantum numbers.\n\n1/wavelength = R(1/n_l^2 - 1/n_u^2)\n\nSo, for the listed values of n, \n\nA.  1/w = R(1/ 2^2 - 1/4^2) = 0.1875R\nB.  1/w = -0.75R\nC.  1/w = 0.21R\nD.  1/w = -0.04861R\n\nSince energy and frequency are proportional to 1/wavelength,\nlooks like the order is D, A, C, B.
482392
It is the range of frequencies from about .7-.4 micrometres.\nWhite light is not a frequency it is the combination of all frequencies in the visible spectrum. The cones in our retina are sensitive to these frequency differences while the rods are sensitive only to the intensity (black & white). The pupil does not respond to light outside of the visible frequencies, therefore infrared and ultraviolet light can easily damage our retinas.
58422
A typical human eye will respond to wavelengths between 400 and 700 nm.  Some may be able to perceive from 380 to 780 nm.
943929
The frequency of light and its wavelength have an inverse relationship.  As the frequency of light increases, the wavelength decreases.\nThe frequency is the number of 'cycles' per unit time, and the wavelength is how far the wave propagates in that same time.  At a constant speed, the shorter the higher the frequency (very short time durations between cycles), the smaller the wavelength.\n\nThe energy contained within a single photon of light is given by Planck's equation,\nE = hv\nwhere E is the energy, h is Planck's constant, and v is the frequency of light.\nThe equation can be re-written as,\nE = h * c / lambda\nWhere c is the speed of light in a vacuum, and lambda is the wavelength of light.\n\nYou can see that as the frequency of the light increases (or when the wavelength decreases), the energy contained within a photon of light increases.  The higher the frequency of light, the more energy the light carries.  For example, high frequency X-rays carry much more energy than low frequency radio waves.\n\nh = 6.626 E-34 J s
937514
wavelength = speed of light / frequency\nfrequency = speed of light / wavelength\nf = (3*10^8 m/s) / (615*10^-9 m)\nf = 4.878*10^14 Hz\n\nwavelength = planck's constant * speed of light / energy\nenergy = planck's constant * speed of light / wavelength\nE = (6.626*10^-34 J*s) * (3*10^8 m/s) / (615*10^-9 m)\nE = 3.232*10^-19 J
1146629
Visible light is within the electromagnetic spectrum.  This spectrum consists of different frequencies such as microwaves, visible light, gamma rays, laser, etc.  Visible light is just a band width within the electromagnetic spectrum that humans can detect with thier senses.  ROYGBIV- red, orange, yellow, green, blue, indigo, and violet.  These are the colors that are detectable by humans within the electromagnetic spectrum and make up the visible light that we see.
1065631
To convert between wavelength and frequency, recall the following equation, converting all units to meters:\n\nspeed = frequency * wavelength\n\nspeed of light is 3*10^8\nwavelength is 1150 = 1150 * (10^-9)\n\nso just divide and you shall conquer !\n\nHope this helps,\n\nJ
164646
You mean a 'frequency of 5.10^12Hz'\n\nCan you work it out yourself?:\n\nRemember that the speed (v) of the wave is 3×10^8 m/s,\nand that the wavelength is given by v/f\n\n[Edit: Darn, Kirchwey - don't do Glow's homework for her! ;-) ]
442820
The wavelength of visible light is approximately 400 to 800 nm.  In a crystal, such as table salt (NaCl) the spacing between the Cl atoms is 0.563 nm, with the Na atoms half way in between.  The numbers are similar for other solids.  So, atoms are spaced about 500 times the wavelength of light, but that is a rough number.