well i have a crossword  puzzle and the riddle is how would you breave if placed between earth and the sky?
968087
you would be normal because you are already placed between the earth and the sky
239105
to use the gravitational pulls of the earth and the moon
820907
Assuming you somehow manage to get the ladder pass the centre and out the other side; could you throw a rope ladder 6,378km towards space?\n\nThen the next hurdle; have you ever tried to walk feet-first up a ladder? Because that's what you'll be doing once you've got past the centre of the Earth.
754405
Let L be the initial rope's length and R be the radius of the equator in metres.  Then \n\nL = 2piR\n\nAdding 1 to the length, we get:\n\nL+1 = 2pi(R+x)\n\nwhere x is the extra radius, i.e. the height at which the rope would float.  Combining these two equalities we get\n\n2piR + 1 = 2pi(R+x)\n2piR + 1 = 2piR + 2pi*x\n1 = 2pi*x\nx = 1/(2pi) = 0.159 or about 16 centimetres.\n\nThe cool part about this is, it's independent of the earth's radius!  The result is the same whether you start with the earth, a basketball or a marble.
349451
sky cannot fly skirt high,\n       skirt can fly sky high.
59499
Assuming you sleep at night, you'd be on the opposite side of the earth as the sun.\n\nYou are here-->x(Earth)..........(Sun)
21030
Assuming you have a tunnel that goes through the earth, take aside the fact you would survive the temperatures and such at the center, assuming there's no resistance (vacumn like environment), you would fall into the hole... accelerate to terminal velocity...pass the center, and slowly decelerating, until you reach back a speed of 0, where you will be at the other end of the hole, whereapart the whole process would start all over again unless you grasp the edge :)\n\nConsidering that the fact there's air, you'll encounter resistence, meaning you will accelerate to the center, start slowing down, but fall short of reaching the other end, then you will fall to the center again, fall even shorter of your original jumping position, and you'll oscillate back and forth until you indeed get stuck in the center of the earth.
753758
the question really should be, 'which direction is the earth spinning if you look at it from (insert place here)?'\n\nit all depends on your frame of reference. and your direction of reference. and your size of reference.
883944
You need radius and distance\n\nEarth radius: 6,372 km\n\nMoon:\nDiameter: 3,472 km\nRadius: 1,736 km\nMean distance: 384,401 km (less radius of Earth = 378029 km)\n\nSun:\n\nDiameter: 1.392×10^6 km\nRadius: 6.96×10^5 km\nMean distance:149.6×10^6 km\n\nBy trigonometry, the angle is twice the inverse tangent of radius divided by the distance.\n\nMoon: 0.009032 radians (0.5175 degrees)\nMoon corrected for radius of Earth:\n0.009184 radians (0.5262 degrees)\nSun: 0.009305 radians (0.5331 degrees)\n\nNote These are mean values.  I calculated from the center of the Earth and the surface by subtracting the radius of Earth.  There are several numbers you can plug in from my sources.  I could not draw a diagram to explain my calculation due to the limits of Y!A.
421902
yes, the teacher is looking at your ability to read and answer a question as it is written.  there is no earth in the hole, but the space it represents as a void would be 24 sq inches.  Present both or these answers with the explaination.
261896
The earths atmosphere\n\n\nMy first thought was not formal. What I thought when I read your question is that nothing is between heaven and earth that "the heavens" come down and touch the earth.
537957
The Earth is between the moon and the Sun.  \n\nSomeone standing on the moon would see a solar eclipse.  \n\nSolar eclipse  Sun   Moon   Earth\n\nLunar eclipse  Sun   Earth  Moon
1051472
Ok, say the earth was all solid and there was a tunnel from one side to the other.  \n\nYou would keep accelerating as you moved toward the center of the earth, until you reached a very high speed.  As you passed through your speed would be at a maximum.  Then you would begin to decelerate as you went toward the other side.  Neglecting friction and air resistance, you would have just enough momentum to make it up to the surface on the other side, but you would have to grab on or else you would fall back into the hole and go the other way.  You'd continue oscillating back and forth forever if you neglect friction.  \n\nBut of course in real life you would slow down a little bit each time.  Your motion would be like a kid on a swing set, or a pendulum, a gradually decreasing swinging motion until finally you come to rest in the center.
737740
Follow ditz's advice (make a diagram) as you read these directions for solving the 4 problems:\n\n1. assuming that the sun is a point source and the earth's surface is flat:\nangle = arctan (6.25/10.1)\n\n2. assuming that the string forms a straight line, and that the end of the string is on the ground:\nsqrt(50^2 - 30^2)\n\n3. arccos (1.75/4)\n\n4. 30 cos (75 degrees)
462650
You wouldn't fall anywhere, you'd be stuck in the middle.  Gravity would be too strong for you to dig away from the center.
85444
Earth rotates. Sun on one side.
357343
Wold, huh? Now how do you know for certain that it is not the sun that goes around the wold? Hah! \n\nHere is how to think about that, and it is the basis for orbital mechanics: Imagine holding a cannonball and dropping it to the ground. It will fall straight down. Now, if you add a bit of horizontal motion, the cannonball will fall a short distance away from you. Imagine now that you can throw the cannonball horizontally with a great deal of force.  It will still eventually fall to the ground, maybe 100 yards away, 200 yards, whatever, depending on how hard you threw it.  Now, if you accept the notion that the earth is a sphere, that means that the surface of the earth is ever so slightly curved and would drop away from your perceived horizontal plane at the horizon.  Now if you could throw the cannonball hard enough, as it sped away horizontally two things would happen: (1) the cannonball would begin dropping to the earth, and (2) the earth would be curving down under the cannonball and away from it.  Now if you could throw this cannonball so hard that it would get away over the horizon, so far in fact that the earth would curve away as fast as the cannonball dropped towards it, then you would be in orbit, and end up circling all the way around back to where it started, and if had been going fast enough it would keep on orbiting. Increase the speed even more so it goes farther horizontally than the earth curves away vertically underneath it and you have reached escape velocity, which would send the cannonball off into space. \n\nSo if you subsitute the sun for the earth and the earth for the cannonball you can see why the earth orbits around the sun, it's the same idea.  If the earth were travelling along its orbit at a slower speed than it is it would fall into the sun; at a higher speed and it would fly off into space.