If you combine AgNO3 and Cu, what will be the products? Will it be Cu(NO3)2 and Ag? or CuNO3 and Ag?
953082
Okay, it's been a looooooong time since I had to use my chemistry skills, so lets see what I have:\n\nCopper is more magnetic with electrons than silver is because it's electrons (with fewer of them) are close to the nucleus (or whatever you call it) of the element.  Silver is more apt to lose its electrons with them being so far away.  \n\nCopper is more often found in a +2 state.  So I'd say that's a safe bet to go with.  I'd only assume a +1 state if your teacher said so.\n\nSo therefore:  2AgNO3 + Cu -> Cu(NO3)2 + 2 Ag would probably be your best bet.\n\nBut once again, it's been a long time since I used this so I don't know how right I might be.
612968
I hope you mean this...\n\n8Cu + 2AgNO3 -> 2Ag + CU(NO3)2 + 7Cu
625286
Cu is more active than Silver or to put it in more technical terms, its reduction potential is higher. Thus this particular reaction is spontaneous i.e. happens on its own. \n\nThe reverse is also possible but only if you supply the energy required which is usually in the form of electricity.
122259
wow open question here...what is the end result and use. if it is say for automobiles it would be copper, nickle and chrome for cheep jewerlery sure gold last...many possible answers
98695
My answer is,\n \nNH4NO3(ag) + KOH(aq) -> NH4OH(aq) + KNO3(aq)
1169923
It cann't be copper 3 oxide.  It simply does not exist.  The charges don't balance!
791597
You will get Silver Chromate as the precipitate.  It is red in color.\n2AgNO3(aqueous) + K2CrO4(aqueous) -> Ag2CrO4(solid) + 2KNO3(aqueous)
1018313
Silver is being oxidized, nitrogen from the nitrate is being reduced.\n\nOxidation half reaction:\nAg --> Ag+  +  e\n\nReduction half reaction:\nNO3- +  4H+ + 3e  -->  NO + 2H2O\n\nNet balanced and reduced equation:\n3Ag +  NO3- +  4H+ --> 3Ag+ + NO + 2H2O
418443
Copper can react with nitric acid on two different ways based on the concentration of nitric acid.\n\nIf cold and dilute nitric acid is used, then the reaction yields copper(II) nitrate, nitrous oxide(N2O) and water.\n\nCu + HNO3 ----- Cu(NO3)2 + N2O + H2O\n\nIf hot and conc. nitric acid(a stronger oxidising agent) is used, the reaction yields copper(II) nitrate, nitrogen dioxide(NO2) and water.\n\nCu + HNO3 ----- Cu(NO3)2 + NO2 + H2O\n\nP.S. - Balance the equations yourself(might take some time but use the oxidation no. method)
847934
You should recognize that, when they combine with nonmetals, metals tend to LOSE electrons and form POSITIVE ions. Nonmetals, on the other hand, tend to GAIN electrons and form NEGATIVE ions.\n\nGet an "A".
894420
Here you are:\n\nCu2S + 12HNO3 => Cu(NO3)2 + CuSO4 + 10NO2 + 6H2O
742926
Cu(s) + 2HNO3(aq) = Cu(NO3)2(aq) + H2(g)\n\nCu + 2H+ + 2NO3- = Cu+2 + 2NO3- + H2 (leaving off the s,aq,g)\n\nCu + 2H+ = Cu+2 + H2 (net ionic equation, the NO3-'s just cancel out, they don't change in the reaction).
865869
Your question is hard to interpret.  Are you saying you have a solution of sodium nitrate (NaNO3) and lead (II) sulfate?  The combination looks like the result of an ionic recombination (double replacement) reaction between sodium sulfate and lead nitrate.  The lead sulfate is a solid (low solubility in water) and precipitates out.  The sodium and nitrate are spectator ions.
184549
The first website explains *how* to make a\nmirror using "nitrate of silver", water, and ammonia.\n\nThe second website offers "nitrate of silver" for sale.
197904
based on the net inoic equation:\n\n\nCu2+(aq)---> Cu(s)\n\nAg+(aq)---> Ag(s) --- zero grams\n\nexcess Cu(s) or Cu(aq)\n\nif, Cu(s) then it is  3.78 grams of Ag
706351
KCl(aq) + AgNO3(aq)  --> KNO3(aq) + AgCl(s)\n\nNet ionic: Cl-(aq) + Ag+(aq)  --> AgCl(s)\n\nNa2SO4(aq) + Ba(NO3)2  --> 2NaNO3(aq) + BaSO4(s)\n\nnet ionic: SO4(-2)(aq) + Ba(+2)(aq)  --> BaSO4(s)
888667
Cu2S + 12HNO3 -> Cu(NO3)2 + CuSO4 + 10NO2 + 6H2O\n\nThere you go.