Anyone familiar w/ the math game called math 24.?
970878
OOOOOOOOOh i LUV LUVLUVLUV challenge 24!!!! ok her are some ideas:\n7,2,2,1=(7-1)(2+2)\n6,8,2,1=(8/4)(6*1)              ***All taken from Challenge 24 cards\n3,3,6,2=(3+3)(6-2)                     (single digit)\n9,2,5,1=(9-1)(5-2)\n~* ah what the heck i dont have time to finish this. I'llget back to you later, soon. and for future reference, DO buy challenge 24 cardsand so you can use them often. the only annoying thing is, it doesnt come w/anser key u have to figure it out yourself:(
741881
i do indeed, the same thing is at mysticball.com - i answered the following to that question and it applies to this one also:\n\nit doesn't, the answer is predetermined before you even think of one, all you're doing is using the mathematical equation it tells you to to arrive at a certain number containing the predetermined symbol.\n\nalthough each time you play the symbol sheet to the left is different, you will see that every number on that sheet that is a multiple of 9 is the same symbol - 9, 18, 27, etc etc.\n\nbecause the result of the equation you do will ALWAYS be a multiple of 9 the symbol you 'picked' will be the same regardless of which number you choose at the start because every number on there that is a multiple of 9 has that symbol.\n\nit's just basic math, nothing exciting.
725561
Oh Dear! lots of dodgy maths out there!\nWelcome to Mr Cantor's infinity paradise hotel!\nWe got infinite rooms, but they're all full just now.\nDon't worry!.. we'll squeeze you in!..I'll just get every guest to move one room along\nNow you can get in room1\nHey there's an infinite stretch limo arrived with an infinite number of guests..no probs just get all our guests to move from room n to 2n!\nYes infinity is an uncountable number, but you can still do mathematical ops with it\nHope that helps, you can work out the rest foor yourselves. PS always agree with your wife- she's right even when she's wrong-now that's a true paradox
987992
mathworld \n\n\n\n--- LeeeN
916534
21, 34  Yes it's called the Fibonacci series.  Each number is the sum of the previous two.\n\nWhat I don't understand is as a result of asking a valid question to expand your knowledge, so many people gave you such rude replys.\n\nI hope this helps, have a good day.
806909
I POSTED THE FIRST CORRECT ANSWER HERE AND WAS WRONGLY DELETED FOR A BOGUS VIOLATION REPORT\n\nI posted last night around 12pm, here was my (correct) answer:\n\nOk so let the tens digit be x, then the ones digit is (12-x). The value of the number is 10*x+(12-x) = 9x+12 which you are told = 11x 9x+12=11x 12=2x x=6 12-x=6 also So the number is 66. (Check x = 6*11 as claimed.)\n\n(There is some severely dishonest point-gaming going on around here)
243446
It's called the Fibonacci sequence, but there's actually a couple more terms at the front: 0,1,1,2,3,5,8,13...  You take the last 2 terms and add them together to get the next term.  So 8+13 = 21; 21+13 = 34, etc.\n\nHere is a good start if you're interested in learning more about it:\n\nhttp://www.mcs.surrey.ac.uk/Personal/R.Knott/Fibonacci/
648450
First get it straight. Algebra and probability are 2 very different things! Now:\n\n1. There are 12 marbels, so,\na) purple then red = (1/12)*(3/12)=1/48\nb) red then green = (3/12)*(3/12) = 1/16\nc) 2 greens = (3/12)*(3/12) = 1/16\nd) 2 reds = (3/12)*(3/12) = 1/16\ne) purple then green = (1/12)*(3/12)=1/48\nf) red then yellow = (3/12)*(5/12) = 5/48\n\n2. There are 9 total marbles, so:\na) purple then white = (3/9)*(1/8) = 1/24\nb) white then green = ((1/9)*(1/8) = 1/72\nc) 2 purples = (3/9)*(2/8) = 1/12\nd) 2 yellow = (4/9)*(3/8) = 1/6\ne) yellow then purple = (4/9)*(3/8) = 1/6\nf)yellow then purple = (4/9)*(3/8) = 1/6\ng) green then white = (1/9)*(1/8) = 1/72\n\n13. Red card is 1/2 and club is 1/4, add them = 3/4\n14. Dimond is 1/4 ans spade is 1/4, add them = 1/2\n15. face card is 12/52 and a 2 is 4/52, add them = 16/52\n16. A 7 is 4/52 and a 9 is 4/52, add them = 8/52\n17. Red card is 26/52 and a king of spades is 1/52 = 27/52\n18. Heart is 13/52 and quuen od diamonds is 1/52 = 14/52
333726
Perform operations in this order:\ni)   brackets\nii)  powers\niii) divide\niv)  multiply\nv)   add\nvi)  subtract\n\nSo work it out like this:\n\n2 + 2 (4 - 6 * 7) + 4\n= 2 + 2 (4 - 42) + 4\n          By doing multiplication 6 * 7 in brackets first.\n= 2 + 2 (-38) + 4\n          By doing subtraction 4 - 42 in brackets.\n= 2 + -76 + 4\n          By doing multiplication 2 * -38\n= 2 - 76 + 4\n          Since + and - sign in front of 76 combine into a -\n= -74 + 4\n          By doing subtraction 2 - 76\n= -70\n          By doing addition -74 + 4
766711
Use this little jingle that my Uncle Ed taught me:\n\n5 times six is thirty-six!\n8 time eleven is a twenty-two!\n4 times pi is a fist in the eye!\n3 times 3 is ze-e-e-e-ro!\n\nThere is a second verse, but I can't remember it.\n\nEmail me if you need help with division.\n\nJohn Z
280927
let the first 3 digits of your number be x = abc and the last four digits be y =defg\n\nwhere a-g are the digits\n\nThe sequence of operations can be rewritten as:\n\n((x*80 + 1) * 250 + 2 * y - 250)/2\n\nIf you distribute the first 250 you get\n\n(20000x + 250 + 2y - 250)/2\n\nCancel the 250's\n\n(20000x+2y)/2\n\nDivide both elements of the numerator by two (distribute the 2)\n\n10000x + y\n\nSince x is a three digit number abc, abc * 10000 = abc0000\n\nSince y is a four digit number defg, 10000x + y = abcdefg.  \nThus we see using algebra that you end up with the same 7 digit number you started out with.
358699
Please visit http://mathforum.org/library/drmath/view/52240.html
1090524
it would be 22 choose 4 =22!/(4!18!) minus the ways in which Mr and Mrs Math can be together = 20 choose 2 = 20!/(2!18!)\n=(22.21.20.19)/(4.3.2)-...\n...(20.19)/(2)\n=((20.19)/2).((22.21/4.3)-1)\n=190.75/2\n=7125\nSorry had to two line one bit due to Yahoos dodgy cutting off of things
338536
3(6) + 7 = 24\n18 + 7 = 24\n\n25 = 24\n\nNo.
986330
It's multiple choice, so all you really need to do is start plugging numbers in and see if they work:\ng(7) = 2(343) -11(49) + 8(7) + 21\ng(7) = 686 - 539 + 56 + 21 =/= 0\n\ng(1) = 2(1) - 11(1) + 8(1) + 21\ng(1) = 2 - 11 + 8 + 21 =/= 0\n\ng(7/2) = 2(343/8) - 11(49/4) + 8(7/2) + 21\ng(7/2) = 343/4 - 539/4 + 112/4 + 84/4 = 0\n\nThus, d is the right answer.
419019
here's are some good websites\n\nhttp://www.funbrain.com\n\nhttp://www.coolmath4kids.com \n\nhttp://www.primarygames.com\n\nhttp://www.kidsdomain.com/games/math2.html \n\nhttp://www.google.com/search?hl=en&lr=&q=math+games+for+children+&btnG=Search
928493
Hmm... 370 and 371 both seem to work.\n\n* * * * * * \n\nI wrote a little program to test all the numbers from 100 to 999.  There are actually four answers:\n\n153\n370\n371\n407\n\nAlso, by "the cube of the sum of the digits", you mean each individual digit is cubed, then you add the sum of the cubes, correct?  For example, 153 is one of the answers because 1^3 + 5^3 + 3^3 = 153.  (It seems like a trivial question if you interpret it the way Dan did, since there are only five numbers to test.)