Methanol,   CH3OH,   can be made by combining gaseous carbon monoxide and hydrogen gas.?
961444
We will need to find if there is a limiting material.\n\nCO + 2H2 ------> CH3OH\n\n(1.61 g H2)*(1 mole H2/2.016 g) = 0.7986 mole H2\n\n(0.7986 mole H2)*(0.5 mole CH3OH/mole H2) = 0.3993 mole CH3OH at most\n\n(15.95 g CO)*(1 mole CO/28g) = 0.5696 mole CO\n\n(0.5696 mole CO)*(1 mole CH3OH/1mole CO) = 0.5696 mole CH3OH at most\n\nH2 is the limiting reagent, therefore:\n0.3993 mole CH3OH * (32.032 g/mole CH3OH) = 12.79 g\n\nPlease check for errors, I went by memory on what the atomic and molecular weights were, you may want to check this.
982375
Hydrogen and oxygen, when combined in an appropriate mixture, will burn to form water.  By itself neither pure hydrogen nor pure oxygen will burn (they need an oxidizer and a reductant respectively).  Water is a stable chemical component that does not have the volatile characteristics of the elements that make up its composition (hydrogen and oxygen).
724975
Methane can be produced by the hydrogenation of carbon or carbon oxide, by the action of water on aluminium carbide, or by heating sodium ethanoate with alkali.
7610
Yeah, you can use H2S gas... Hydrogen Sulphid. With just100 parts H2S per a Million parts of Air, it will knock you out in less than a 2 seconds, stop your respiratory functions as it paralyzes your nervous system. It’s made by combining Hydrogen and Sulphur Gases together. \nWell, seeing it comes from crude oil, it is relatively easy to find and make.\nOne short note; if you do not get the person into a breathable atmosphere within 4 minutes and revive them, they will die.
194284
To solve this problem we need to think about limiting reactants.  This one is fairly simple because I already have moles and the ratio is 1:1:1.  If I only have 3 kmols of C, that is the most I can make, because going beyond that, I would be out of C.  Thus, I can only make 3kmols of CO2 with 2 kmols of O2 left unreacted.  These amounts are theoretically find for a combustion reaction.
817151
Water is just a liquid gas isn't it? Hydrogen and Oxygen mixed makes water. That's how.
477055
Oil, coal, and natural gas are all mixtures of various hydrocarbons.  All hydrocarbon molecules contain hydrogen, carbon, and oxygen.  However a pure metal contains none of these, and hence metal may not be made into any hydrocarbon, i.e. cannot be made into oil, coal, or gas.\n  This is more complicated in nature since metals typically do not occur in a pure form, but in various ores.  Ores must be refined to obtain pure metals (gold, silver, copper, iron, zinc, etc.)  Some of these ores may also contain carbon, hydrogen, and oxygen, and in some rare instances refiniing of an ore to produce a particular pure metal may give off a particular hydrocarbon as a by-product.
650823
Carbon, Hydrogen, and Oxygen.
419096
Dihydrogen monoxide means two atoms of hydrogen and one atom of oxygen.  So, the compound is H20, or water, and there is no danger as such by water, but by the modification of its physical and chemical properties.
1127301
I leave the H's:\nC-C-C-C-O butanol-2\nC-C-CO-C  butanol-2\nC-O-C-C-C propyloxy methane\nnot shown: isopropyloxy methane\nC-C-O-C-C ethoxy ethane
1000320
Helium, CO2, Hydrogen and various others.
814744
In the presence of the proper catalyst:\n\nCO + 2 H2  -->  CH3OH\n\n1.40 g of H2 = 1.40 g / 2.016 g/mol = 0.694 moles H2\n\n13.85 g CO = 13.85 g / 28.01 g/mol = 0.4945 moles of CO\n\nIt takes 2 mole of H2 for every 1 mole of CO, so only 0.347 moles of CO will react.  This will give 0.347 moles of CH3OH:\n\n32.04 g/mol * 0.347 moles = 11.12 grams\n\n11.12 is your answer.
748691
CH3COOH, remember the CO2 comes from the sodium carbonate so your question is poorly worded.
822325
a) Find some Acetic Acid (CH3COOH)\nb) Find some Copper (II) Hydroxide (Cu(OH)2)\nc) Add to form Cu(CH3CO2)2 + 2H2O\n\nWithout the volume or the number of moles, preparation of a 0.530M can be done several ways. \n\n2CH3COOH + Cu(OH)2 --> Cu(CH3CO2)2 + 2H2O\n\nUsing 1L:\n0.530 mol of Cu(CH3CO2)2 means 1.060 mol of CH3COOH\n\n1.060 / 0.5L = 2.120M\n\n0.530 mol of Cu(CH3CO2)2 means 0.530 mol of Cu(OH)2\n\n0.530 / 0.5L = 1.060M\n\nSo mix 500mL of 2.120M Acetic Acid with 500mL of 1.060M Copper (II) Hydroxide.\n\nN.B. Being a weak acid, acetic acid will not fully react with copper hydroxide, and hence the actual molarity requiredmay be higher.
777003
CH3COOH + NaOH ---> NaCH3COO + H2O
53184
methanol (rubbing alcohol);\n\none carbon, attached to one oxygen, with hydrogen everywhere else\n\nethanol (drinking alcohol);\n\ntwo carbons attached, one oxygen, with hydrogen everywhere else\n\nethyl ketone (very bad variation on ethanol, which is naturally occuring)\n\ntwo carbons attached, an oxygen attached by double bond, and hydrogen (one less hydrogen) everywhere else
491732
First, commercial production of methanol is accomplished by the catalytic reduction of CO according to the following equation:\n\nCO + 2H2 ---> CH3OH\n\nSo yes, it's very possible to add carbon to your hydrogen to make methanol. In fact, it's constantly being done on the industrial scale. Most catalysts are based on a mixture of Cu, ZnO and alumina, although the precise details of the best catalysts are something of a trade secret.\n\nThere are still a couple of things to keep in mind with your proposal. The first is that H2 is *very* expensive to make by electrolyzing water. If you use an applied potential of 2.5V it will take around around 7.4 kWh of electricity to electrolyze 1 liter of H2O (assuming I did my math right). That's a *lot* of expensive electricity to replace only a liter or so of conventional fuel. Unfortunately, until technology improves there is really isn't any practical way to generate that much electricity by solar or wind power.\n\nWhile I am a big proponent of alternative fuels, it's often not as simple as it seems to replace traditional fossil fuels. It's generally easy to convert energy from one form to another (for example electricity to hydrogen to methanol), but it doesn't solve the basic problem of getting the energy to begin with. Still, it's a problem we need to work on since almost all of our energy comes from non-renewable resources.