What are the importaant compounds of Alkali metal and their uses?
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Sodium Chloride = Table Salt\nPotasium Chloride = buffering salt used by all animals and plants\nSodium hypochlorate = Bleach\nSodium BiCarbonate =  Baking soda\nSodium Hydroxide = lye   (strongly caustic .. basic solution used in manufacturing and synthesis of many compounds\non, and on, and on
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The word alkali comes from the Arabic word for "ashes," where the oxides of these metals were first found. Alkali is now used as another word for base (see acids and bases); when the ashes containing the oxides of the alkali metals are dissolved in water, a base is formed. For example, sodium oxide dissolved in water yields sodium hydroxide, or lye.
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Ionic compounds (like NaCl) for lattice structures.  These lattice structures make up the crystaline arrangement of the compound.\n\nThe lattice of NaCl looks like a cube,\nhttp://zimmer.csufresno.edu/~davidz/Chem3AF97/ChB/IonicBond.html\nhttp://departments.kings.edu/chemlab/chemlab_v2/nacl.html
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You need to split the ionic compounds apart to find the individual ions you would find in these structures.\n\nMgO would produce Mg^2+ & O^2- ions.\n\nK2S would produce K^+ & S^2- ions.\n\nYou can find the charge values directly from the periodic table trends for the charges atoms assume when they are ionized.
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sodium, potassium, chloride, trace amounts of other metal ions.
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Alkali metals and alkali earth metals tend to form ionic bonds.  They have a +1 or +2 charge.\n\nThe halogens normally form ionic bonds when "joined" with a IA or IIA metal.\n\nTransition metals normally are ionic.\n\nNow for the trick part:  Carbon and nitrogen generally form covalent bonds.  When joined with other elements, they can produce a neutral molecule (CO, CO2).  But they also form polyatomic ions (C03- (carbonate); NO3- (nitrate) ).  \n\nGeneral rule of thumb - IA, IIA, and VIIA atoms will make ionic bonds.  \n\nHope this helps!
201939
a.)ionic b.)covalent c.)covalent d.)metallic
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Alkali earths are the elements of group 2.\nAlkali metals are the elements of group 1.\n\nHere are the properties of group 2\nhttp://en.wikipedia.org/wiki/Alkaline_earth_metal\n\nHere are the properties of group 1\nhttp://en.wikipedia.org/wiki/Alkali_metal\n\nYou can compare them.\n\nHere is the water reaction with elements of group 1 (example K)\n\n2K (s) + 2H2O (l) → 2KOH (aq) + H2 (g)\n\nHere is the water reaction with elements of group 2 (example Mg)\n\nMg + 2H2O → Mg(OH)2 + H2\n\nAs you go to the extremes of the table and down the table the reactivity is higher because the electronegativiy is lower so they have a greater tendency to lose the electron and react.
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potassium can form many compounds. such as KCN KCl KOH et cetera.
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I assume you mean alkaline earth metals and they are all metals in the second column of the periodic table and include beryllium, magnesium, calcium, strontium, barium, and radium.  They oxidize easily in air so most often pure samples are stored in oil.
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Figure 21: Heteropolymolybdate structures. (A) The structure of [Mo< ...  \n  \nchemical compound\n\nCrystal field, ligand field, and molecular orbital theories \n\nConsiderable success in understanding certain coordination compounds also has been achieved by treating them as examples of simple ionic or electrostatic bonding. The German theoretical physicist Walther Kossel's ionic model of 1916 was revitalized and developed by the American physicists Hans Bethe and John H. Van Vleck into the crystal field theory (CFT) of coordination, used by physicists as early as the 1930s but not generally accepted by chemists until the 1950s. This view attributes the bonding in coordination compounds to electrostatic forces between the positively charged metal ions and negatively charged ligands--or, in the case of neutral ligands (e.g., water and ammonia), to charge separations (dipoles) that appear within the molecules. Although this approach meets with considerable success for complexes of metal ions with small electronegative ligands, such as fluoride or chloride ions or water molecules, it breaks down for ligands of low polarity (charge separation), such as carbon monoxide. It also requires modification to explain why the spectral (light-absorption) and magnetic properties of coordinated metal ions generally differ from those of the free ions and why, for a given metal ion, these properties depend on the nature of the ligands. Thus, the complex ion hexafluoroferrate(III) (FeF63-) has magnetic properties to be expected from a substance with five unpaired electrons, as does the free iron(III) ion (Fe3+), whereas the magnetic properties of the closely related hexacyanoferrate(III) ([Fe(CN)6]3-) correspond to only one unpaired electron.\n\nSince 1950 it has been apparent that a more complete theory, which incorporates contributions from both ionic and covalent bonding, is necessary to give an adequate account of the properties of coordination compounds. Such a theory is the so-called ligand field theory (LFT), which has its origin in the more general, but more complicated, theory of chemical bonding called the molecular orbital (MO) theory. (Molecular orbitals describe the spatial distributions of electrons in molecules, just as atomic orbitals describe the distributions in atoms.) This theory accounts with remarkable success for most properties of coordination compounds.\n\nAn important conclusion from LFT is that two types of bonds, called sigma () bonds and pi () bonds, occur in coordination compounds just as they do in ordinary covalent (organic) compounds. The more usual of the two are  bonds, and they are symmetrical about the axis of the bond;  bonds, which are less common, are unsymmetrical with regard to the bond axis. In coordination compounds,  bonding may result from donation of electrons from ligands, such as fluorine or oxygen atoms, to empty d orbitals of the metal atoms (the designation d merely being a way of indicating the particular orbitals involved). An example of this type of bonding is the chromate ion, (CrO4)2-, in which the oxygen atoms donate electrons to the central chromium ion (Cr6+). Alternatively, electrons from d orbitals of the metal atom may be donated to empty orbitals of the ligand. This is the case in the compound tetracarbonylnickel, Ni(CO)4, in which empty  orbitals in the carbon monoxide molecules accept d-orbital electrons from the nickel atom.
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http://www.chem1.com/CQ/ionbunk.html\n\nskim this article.
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This compund has an octahedral geometry and is coordinated with 3 bidentate oxalate (C2O4) ligands.\nReaction of potassium oxalate hydrate and ferric chloride\n\n3K2C2O4ˇH2O + FeCl3 --> K3[Fe(C2O4)3]ˇ3H2O + 3KCl\n\nWater molekules do not act as ligands and potassium ions act as counter-ions
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1) MgCO3\n2) AlF3\n3) BF3\n4) NH4F\n5) SnO2\n6) HCL\n7) Ca(OH)2\n8) Na2S\n9) K2SO3\n\n1) do yo mean PbCl2? then Lead (II) Chloride\n2) Lithium Bromide\n3) Potassium Sulfate\n4) Megnesium Hydroxide\n5) don't know\n6) Hydrogen Nitrate\n7) Barium Phosphate\n8) Carbon Monoxide\n9) Copper Brimide\n10) Ammonium Chloride\n11) Tin (II) Hydroxide\n12) Calcium Nitrogide\n13) Strontium Oxide\n14) Tetraiodide prefix for 9 and oxide\n\nFe^+2\nNi^2\nAg^+1
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Lithium nitride\nGallium oxide\nRubidium chloride\nBarium sulfide\nFor binary ionic compounds, you just write the name of the first element, then take the second element and just change the ending to -ide.
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Generally Group I and Group II elements form ionic compounds with non-metals. Hence for all of the metals above, they should form ionic compounds with oxygen.\nSodium - Na+; oxide - O2-\nHence you need 2 sodium ions to calcen out the -2 charge on the oxide ion, and the formula of sodium oxide is Na2O.\nSimilarly for potassium oxide, K2O.\nCalcium - Ca2+, oxide - O2-\n1 of each is needed to cancel out the charges, hence the formula CaO.\nSimilarly for MgO.\nAns: Na2O, K2O, MgO and CaO\n\nHope this helps :)
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Magnesium is used in sparklers\nCalcium is use as calcuim carbonate (limestone)