the track is 3/5 of a mile long if tyrone jogged around it twice how far did he run?
964119
He didn't run at all. He jogged it the whole way.
232038
Distance = rate x time\n\nif you're going 8 feet per second for 4 seconds, you've gone 32 feet...
610865
The oval tracks around football fields are usually 440 yards in length. One yard = 3 feet and one lap around the track equals 1,320 feet.
281019
On a standard outdoor track (like those at most schools around football fields), a full lap is equal to 400 meters or about 440 yards.\n\nSo, figuring your measurements are in yards, you will run one full lap for the 440 and half a lap for the 220.\n\nIndoor tracks are much more size dependent, although those used for most competition are about 60 yards down each straightaway and about 150 yards total ... so you would run about a lap and a half for a 220 and about three laps for a 440.
108141
2.4\n\n75 miles/60 minutes   =   3 miles/X minutes\n\nCross multiply and solve for x:\n\n75X = (60 * 3)\nX = 2.4\n\nThe weight of the car is not relevant.
63833
50 feet or about 2-3 seconds
1083918
100 meters is 109.36+ yds.\n\nIf the runner ran the additional 9+ yds at the same pace, his time would be 10.94. However, the first part of his race is slower than the average pace since he is accelerating out of the blocks. At the end, he would be running faster than the average for the race. \n\n\nI would say that he would be somewhere between 10.80 and 10.89.
1124931
If it is fairly new it is probably 400 meters, but it used to be 1/4 mile. There isn't much difference, but it is a lot if you are training for a mile run.
1014549
About 1/2 mile.  Too far when I was on swimteam!  15 laps on an Olympic sized pool.
253105
well... man is jogging at 10 km/h... and yhe distance between A and B is 25 km.... then the man is jogging for\nt = (25 km)/(10 km/h) = 2.5 h\n-------\nNow the distance that bird makes in that time....\nd = (45 km/h)*(2.5 h) = 112.5 km
696825
Distance = 100\nRate = 180\nTime for the first half = t\n\n100 = 180t\nt = 100/180\nt = 5/9 hours\n\nSecond half:\n100 = 110T\nT = 100/110\nT = 10/11 hours\n\nAdding the time together:\n5/9 + 10/11 = 55/99 + 90/99 = 145/99 hours\n\n145/99 hours ≈ 1 hour 27 minutes 52.72 seconds\n\nAnd if you want the average speed it is:\n200 miles = R * 145/99\nR = 200 * 99 / 145\nR ≈ 136.6 mph\n\nTime = 1 hour 27 minutes 52.72 seconds (*assuming you could instantaneously drop your speed from 180 to 110 at the halfway point)
554051
up the block about 1/2 mile then turn left.. then go up the block about 1/2 mile then turn left.. then go up the block about 1/2 mile then turn left.. then.. You guessed it.. go up the block about 1/2 mile then turn left!
1176347
A football field is 100 yards (300 feet) long. There are 5,280 feet in a mile. Therefore,\n\n300 / 5280 = .057 miles
20687
i ran track in HS...why do u ask? i ran the mile and 800 and 4X800 in outdoor and in indoor i ran the 4X800 and the 600 yard dash
952421
write the fraction you need \n\nhow many feet in two miles......\nmiles on one side of eq ..... feet on other ....\nso use conversion that has feet in numerator\n2 (miles)  *    (5280 feet) / mile  .......  the miles cancel and you're left with 2 * 5280 feet \n\n\nhow many feet in 6 yards .....  ( conversiion has feet in numerator)\n6 yds  =  (3 feet) / yard   .....  yards cancel and you're left w/ \n6 * 3  feet
1169590
The difference in speed is 6.45-5.30 = 1.15 m/s.\n\nThe track is 198 m long - so the faster runner must catch up by this much to lap the slower.\n\nThis will take 198/1.15 seconds.\n\nThe slower one will have run 198 x 5.30/1.15 m.
345628
There are 1760 yards in 1 mile.\n3*1760 = 5280 yards