What is the voltage of eletricity when it comes out of an eletric plant?
960740
The voltage can reach levels of over 500,000 volts  when it comes out of an eletric plant.  \n\nThe high voltage electric current travels through transmission lines. A second set of wires is used to carry the current back to the generator. These wires are there because electric current travels in a closed circuit. High-voltage substations are places where very high voltages are reduced to lower levels. High-voltage power lines enter and leave the transformer through large insulators. These insulators are used to keep the high voltages away from the metal tank containing the transformer coils. Oil flows around the coils to keep them cool. \n\nThe electricity now travels from the substations to transformers in your neighborhood. These transformers, called "Step-Down Transformers," lower the voltage still further to make the voltage safe for ordinary use in your home. Inside these transformers are coils of wire which help reduce the voltage to 120/240 volts which then can be used safely in homes. \n\nThere is no energy wasted along the process. Remember that energy cannot be destroyed but can be transformed. There is no transformation of energy on the process thus it is not wasted.☺
99832
i believe it is around 9.5%.\n\nBecause Efficiency = O/p Power / Input power * 100.\n\nOutput is the given one \n= 4 * 104 J/min * 3 * 60 min = 74880 J \nInput is  = 75 * 1076 * 9.8 J ( mgh - mg * 0 = Potential energey) \nthefore, eff. is 9.5%\n\nplease reply at autoprash90@yahoo.co.in
906536
These are a published value.  The actual voltages vary as you can see from this quote from a power plant site \n\n"POWER PLANT CAPABILITY: The two hydroelectric power generators boast a generating capacity of 92,000 kilowatts. The estimated annual energy output is 205 million kilowatt-hours."\n\nAnd none of the values quoted are a multiple of 11.  It appears that the source your using just happened to have values that were multiples of 11.\n\nA quick look on Google listed quite a number of plants that produced values that had 13800kv to 205 million kv.\n\nChance that the ones you looked at were multiples.\n\nBest of luck in your project.
1031895
Quite simple really. All you need is a photodiode detector sensitive in the infrared region and a computer or oscilloscope to measure the voltage difference of your photodiode detector.\n\nYour homebrew device is useful, but only as useful as the components it is constructed of. Lab quality devices cost tens of thousands of dollars and have well conditioned electronics.
368244
V (Voltage) = I (Current) x R (Resistance)\n\nOr (although you probably don't need it):\n\nJ (current density) = sigma (conductivity) x E (electric field)\n\nI always use wikipedia to look up stuff like this, it's very helpful for all kinds of info.
942921
Voltage is the amount of "potential difference" present - an analogy with water would be the pressure of the water\n\nCurrent - measured in Amps - (Coulombs per second) the flow of electrical charge - an analogy with water would be the thickness of the pipe.\n\nVolts x Current = Watts\n\nJust as\n\nWater pressure x pipe thickness = amount of water pumped\n\n\nSo a 12volt bulb taking 2 amps will be 24 Watts\nA mains bulb at 240Volts with 0.5 amp will be 120 Watts
209317
The straight calculation is this:\nVolts X Amps = Watts(power)\n\n4.5 watts would be the answer.
268227
Power is directly related to amperage by the voltage, P=I*V.
512277
At standard state, the cell voltage is:\n\ndeltaE0 = - deltaG0 / (n * F)\n\nwhere deltaG0 is the standard state change in Gibbs free energy, n is the number of electrons involved and F is the Faraday constant.\n\nIf you are not under standard state conditions, you can calculated cell voltage with the Nernst Equation:\n\ndeltaE = deltaE0 - (R * T)/(n * F) ln Q\n\nwhere R is the universal gas constant, T the temperature in K, n the number of electrons involved, F the Faraday constant and Q is the reaction quotient.\n\nThe Nernst equation is how you can calculated cell voltages for any combination of temperature and concentration.\n\nHope this helps!
132617
KVA =Kilo Volt Ampere\nKilo = 1000\nPower = Voltage * Current\nso watts = KVA*1000\nEg. 5KVA = 5*1000 =5000W
1166742
solar cells produce electricity through a process known as photoelectricity.Photoelectricity means a process in which light is shone (fall on) photocells which bring about the release of electrons.i.e.production of electricity .
819211
Only 70% of the power flux reaches the surface ot the earth.\nThe electric field is defined a Newton per unit charge..\nThe power flux from the sun is really radiation power its Usually measured in Joules per second per meter^2. \nVolt per meter is = to force per unit distance. Its resulting units are kg /sec^2. which is not equal to joules/sec/meter^2.
1187482
Kilowatt\nCost depends on method of generation and location
157293
well the voltage is dc,so +ve and -ve potential comes in picture.the potential of c will be differnce of potential at the two end.\nso if both +ve ends are connected at the c ends the potential of c =10 v.\nif +20v and 0v(-ve 10 v wire) is connected pot c=20v\nif 0 and +10v is conncted pot c=10v\ndir of current is from +ve to -ve\nhere in 1st case current varies from 20 to 10.\nthis is only in case of transmission and distribution. so u plz explain if it is related to the same and is externally connected. if not then current will be vector sum as in the 3 cases i said. u may refer to power system by j. b. gupta\nthis is engg book for 5th sem eee stud.
989966
First, to the basics...\n\nAC is Alternating Current.  This means that the current moves in one direction and then the other, changing at a frequency of 60 time per second, its unit of measurement being Hertz (Hz).  The generator produces this current at very high voltages which are sent down the transmission wires to local substations, where the voltages are reduced to the familiar 110 volts which appears in your electrical panel.   At the transformer of the substation, the transmission lines to your house are isolated from the ground and "float".  This means that there is no path for the current to flow from either wire to the ground or to each other.  Now, in order to use the power (which is a product of the voltage times the current)  the current must flow through a load, which is any energy using device from a light-bulb to a toaster to the pump on you washing machine.  Since both sides of the wire (both the black (hot) wire and the white (neutral) wire) are isolated from ground to begin with, attaching the neutral to the ground does not provide a path for current flow.  Only if a path is made from the black to the white wire will there be current flow.   If we connect a lightbulb between the black and white wires, we will complete this circuit.  Remember that power (measured in Watts) is the product of Voltage (measured in Volts) and current (measured in Amps).  If we know the amount of Voltage (110V) and the power used (say 100W in a light bulb), we can figure that the amps used are 100W / 110V = ~.91 Amps.  If the circuit breaker is rated for 15 amps, it would require at least 17 of those bulbs to exceed the capacity of the breaker and cause it to trip.  I hope this clears things up for you...
602903
You don't, any more than you convert between volts and watts.  You can read about dBm in the article below, but simply put, it is a measure of power.
87578
P = EI (Power equals voltage E times current I)\n\nMany electrical properties can be explained as analogous to water flow.  For example, a transformer "transforms" high voltage and low current into low voltage and high current, keeping the power constant (except for minor losses) at full load.\n\nThis would be equivalent to a high pressure water pump supplying low water flow to the primary winding and taking out high water flow at low pressure from the secondary winding to drive a low pressure water turbine.\n\nYou could represent the transformer core as a hollow square of wood or even thick cardboard.  On one side wrap say ten turns of thin clear plastic tube around the core to represent the primary (first) winding.  On the other side wrap say five turns of larger diameter plastic tube around the core to represent the secondary (second) winding.  Fill the primary tubing with water and red food coloring to represent "hot" high voltage and the secondary tubing with water and blue food coloring to represent "cooler" low voltage.\n\nThe explanation of course is that the high voltage primary winding will have more windings of thin tube (similar to more thinner copper wire windings) because the current will be less than in the secondary winding.\n\nThere will be less windings for the secondary coil using larger tubing because the current will be higher at low pressure.\n\nSupply the secondary tube with a shut off valve (or clip) to represent the fact that there will be no current unless the circuit is open.  In the formula, if current is zero power is also zero (on both sides of the transformer).\n\nYou can represent the pump and turbine with pictures (or drawings) of same but it would not be impossible to rig an actual pump and turbine, just not necessary to "see" what is happening.\n\nThe turbine can use up more and more power until the maximum power of the primary winding is reached but not more.  The magnet of the core will be "saturated at full power."\n\nThe rest is explaining magnetic flux in the core and how it is produced by the primary winding and cuts through the wires of the secondary to produce voltage and current if there is a load.  Each winding of a coil adds to the effect.  A transformer with equal primary and secondary windings would have the same voltage and current under load.  I believe that the phase would shift 180 degrees because of lead/lag.   Good luck.