find the Croc and then the slope of (6,4) (2,1)...?
968621
This question sounds like a crock.  \n\nCould you clarify what exactly you're asking?
322514
m1*m2=-1\n\nhold for the slope of two intersecting lines
994720
Well, I am going to assume that the function is: d=28+24cos[("pie"/5)(t-6)]. First of all, minus the 28, then divide by 24, then take the inverse cosine (arcosine), then divide by ("pie"/5) then add six, so it should result:\narccos [(d-28)/24] * (5/"pie") + 6= T
1002212
first calculate slopes of each line \nslope of 1st line (1+4)/(3+7)\n                          =5/10\n                          =1/2\nslope of second line (4-2)/(10-6)\n                                 =2/4\n                                 =1/2\nas bothe slopes r equal these lines r parallel...\n..\n\nanywaz..two lines r peripendicular wen product of their slopes   is -1(negative one)
533058
Point slope form:\n\ny-(-3)=(1/2)(x-5)
182913
The slope of the line is 3/4.
518912
Rise over run.\n\n(y2-y1) / (x2-x1)\n\nP1 = (3,7)\nx1 = 3\ny1 = 7\n\nP2 = (-1,4)\nx2 - -1\ny2 = 4\n\n= (4 - 7) / (-1 - 3)\n= -3 / -4\n= 3/4\n\nThe slope is 3/4\nThe x-intercept is (0,4 3/4)\n\nIn the form of a line:\ny = mx + b\ny = 0.75x + 4.75\n\nDouble checking the points:\n(3, 7)\ny = 0.75(3) + 4.75\ny = 2.25 + 4.75\ny = 7\n\n(-1,4)\ny = 0.75(-1) + 4.75\ny = -0.75 + 4.75\ny = 4\n\nTo recap, the slope is 3/4 or 0.75
870460
Use the formula m = (y2-y1) / (x2-x1) to answer this.  (x1,y1) and (x2,y2) are your two points.\n\nm = (4-4) / (7-1) = 0/6 = 0\n\nSo, your slope is 0.\n\n(All lines with a slope of 0 are lines that are parallel to the x-axis)
578147
First, you'll move the 6x to the other side to create the equation y=mx+b.  M=Slope.  Divide by 5 to get Y by itself, then you're left with y=-6/5x+13.  So slope is...\n\n-6/5
888267
2y - 6x = 5\n\n2y - 6x + 6x = 6x + 5\n\n2y = 6x + 5\n\n2y/2 = 6x/2 + 5/2\n\ny = 3x + 2.5\n\nThe slope equals 3\n\n- - - - - - - - - - - - - -\n\n2y - 6x = 5\n\nPoint (k, 6)\n\n2 ( 6 ) - 6k = 5\n\n12 - 6k = 5\n\n12 - 6k - 5 = 5 - 5\n\n7 - 6k = 0\n\n7 - 6k + 6k = 0 + 6k\n\n7 = 6k\n\n7 / 6 = 6k / 6\n\n7 / 6 = k\n\n1 1/6 = k\n\n- - - - - - - -s-
271844
If you need the tangent, take the derivative of the function at the specific point, which will give you the slope. Since you have taken the derivative at some specific point (a,f(a)) you also have a point. Now use the point-slope form to figure out the equation. Then simply get a graph paper and graph it.\n\nExample: f(x)=3tan(2x)\n\nf'(x)=6[sec(2x)]^2 (I assume you can take derivatives.)\n\nYou have a point (a,f(a))\n\nNow use the point-slope form: y-f(a)=f'(x)(x-a)\ny-3tan(2a)=6[sec(2a)]^2*(x-a) is the answer in this case. \n\nOr in function form: y=6[sec(2a)]^2*(x-a)+3tan(2a)\n\nTo graph it, find 2 points on the equation, then draw a straight line between them. That is your tangent.
744864
although Question is little vague, i understand that u want to find slope of a line ???\n\nsay coordinatyes of A and B are (x1,y1) and (x2,y2)\n\nThe Slope of line m= (y1-y2)/(x1-x2)
371794
slope = (-1-2)/(-1-0) = -3/-1 = 3
92968
The slope is 2. (Rise / Run)\n\n(8-2) / (5 - 2) = 6 / 3 = 2
971807
(0,0)\n(3,0)\ndraw the graphs and then find them out!\nif u can't, then mail me!
341837
y=-9\ny=-6\ny=-3\nincrease by 3\nand the slope is 3
554784
x=(1--2)  or (1+2)\ny=(5-3)\n\ny/x=slope\nx=3\ny=2\nslope is 2/3