Can anyone good at math solve ANOTHER question?
969305
This initial value problem is surprisingly simple, since niether y nor any derivatives other than the second appear in the equation, so all that is necessary is to integrate twice:\n∫∫d²y/dx² dx dx = ∫∫6x dx dx\n∫dy/dx dx = ∫3x² + C dx\ny=x³+Cx+K\n\nNow we need merely find the constants C and K. We know that y'(0)=3(0)² + C = 0, so C=0. Further, we know that y(0) = K = 1, so K=1.\n\nThus y=x³+1\n\nb: There is exactly one such function. All antiderivatives of a function are the same up to addition of an arbitrary constant, and as we showed when solving the problem, there is only one consistent set of values for the two constants of integration introduced in this problem.
1132201
So what is the question if you already solved it?
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
937830
T=m1*-9.8+m1*a\nT=m2*a--m2*-9.8\n\nset them equal and solve for a\n\ntrust me, i had a test on this today
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
966470
answer four does not appear to be correct
741999
whats the equation or formula u need help with?
856711
because this has 2 unknowns it cannot be solved.\n\nbut I can write  x in terms of b\n\n2x = 13-b\nor x =(13-b)/2
969084
OMG a math riddle I cant seem to answer!!!! :-)  Awesome. I cant sleep because now i want to knwo the anwer. And so i continue to try and solve it.\n\nBest i can come up with is 113  or 240 or 50-something..\nAlso maybe another number in the 100-n-teens\n\nI did find a 1-3-4 pattern aasuming the next number in 1-3-4-1 was a 3 but was unsure of how to continue it. (its1230 in the moring here)\n\nAnd again another possible patter 1-3-4-8 next number would be 16.\n\nI know some may not even know how I came up with these, but I love math and I love a challenge. I have been trying to find any possible correlation in the numbers that I can. \n\nHope someone figures it out. I know I cant wait to see the answer.
396330
Another homework question.
769971
This is solvable, and you wrote it very well!\n\nThe key to setting this up is knowing that for any 2-digit number, you can write it as 10a + b.\n\nSo your problem states that a+b=9 (the sum of the tens digit and ones digit is 9), and it states that a=3b+1 (the tens digit is 1 more than 3 times the ones digit).\n\nSo now you have 2 equations in 2 unknowns, which you can easily solve for:\n\na + b = 9\na = 3b + 1\n\nSubstitute a = 3b + 1 into the first equation to get:\n\na + b = 9\n(3b + 1) + b = 9\n4b + 1 = 9\n4b = 8\nb = 2\n\nNow you can easily solve for a, which equals 7 since a+b=9.\n\nSo your 2-digit number is 72.\n\nCheck: 7+2=9\n7 = 1 + 3*2\n\nIt checks out, so our answer is correct!\n\n~ ♥ ~
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.
531205
2 + 2 = 4\n\nthats all I got
541116
3=2 did get a correct answer...maybe you need to review your rules of square roots.
1017997
The equations are wrongor insufficient. Post the correct data if you want me to help/ Alternately, you could also message me.