multiplication  of alegbraic fraction?
966462
(6x^2)/(4x^2 y-12xy) * (x^2 + x - 12)/ (3x^2 + 12x)\n\nFirst, I would attempt to simplify if possible:\n2x(3x)/x(2xy-6y) * (x^2 + x - 12)/ (3x^2 + 12x )\n(3x) / (2xy - 6y) * (x^2 + x - 12)/ (3x^2 + 12x)\n\nRewrite to see if we can cross cancel:\n\n(3x)           (x^2 + x - 12)\n---------  *   -----------------\n(2xy-6y)    (3x)(x + 4x)\n\n1               (x^2 + x - 12)\n---------- *  -----------------\n(2xy-6y)     (x+4x)\n\nUnfoil the (x^2 + x -12 to see if we can further simplify\n\n(x^2 + x - 12) = (x -3)(x+4) so you will have:\n\n1             (x-3)(x+4)\n-------  *  --------------\n2y(x-3)      (x+4)\n\nBy simplification:\n\n1           (x-3)\n------   * ----------\n2y(x-3)     1\n\nBy Cross Cancel:\n1/2y
789393
The same way as you multiply any number! you just have to remember you're in hex. If you can get your mind to work in base 16 then the questions will look a lot simpler...\n\nBut, a slightly long winded but foolproof way would be to convert the numbers you want to multiply into decimal, perform the multiplication, and then convert the answer back into hex. The website below has a converter
933454
30 over 4x^2\n\nremember the rule with adding fractions with the same denominator is that you keep the denominators as they are, and only add the numerators.
93955
change mixed fractions to proper fractions and then divide,\nwhats so hard?
1034542
The steps for adding two fractions:\n\n1) reduce both fractions  (not strictly necessary, as long as you reduce in the end)\n2) give them both the same demoninator (the bottom number)\n3) add the top numbers (the numerators)\n4) reduce the answer\n\nSo, step one is already done.\n\nStep two is to give them a common (the same) denominator.  So what number should that be?\n\nIt's going to be the product of both denominators.  so 3 * 8 = 24.  So that's our common denominator.\n\nWhat you are going to do is to multiply the top and bottom half of each fraction by the same number (which is okay, it's equivilant to multiplying by 1) so that the bottom number is 24.  So for the left fraction, we will multiply the top and bottom by 3.  So we get (3 *3)/(8 * 3), which is 9/24.\n\nAnd now we multiply the second fraction, top and bottom, by 8.  so (2 * 8)/(3 * 8) = 16/24.  Now that both fractions have the same denominator, we add them by adding the top numbers, and putting that over the common denominator.  So 9 + 16 = 25, so we get 25/24.\n\nThis is technically acceptable, but teachers will probably want you write this as 1 and 1/24th.
636881
Here is a full page multiplication chart. Thanks Yahoo!\n\nhttp://www.gtcocalcomp.com/erc/interwritebackgrounds/multiplication_table_complete.jpg
960799
BIMDAS BIMDAS BIMDAS!\nbrackets, indices, multiplication, division, addition, and then subtraction\n\nHence, do your 6.4 divided by 0.032 first.\nThen, do 3.34 add the answer from above.\n\nShould be 203.34
843077
Who sez?  You need a common denominator to ADD two fractions.  To multiply, just do separate operations on the numerator and denominator.
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
900662
You have to rationalize the denominator by multiplying the fraction by rad15 over rad 15\n\nyou get 2 rad 30 over 3*15  or 2 rad 30 over 45
940700
When we see the word 'is', we can often substitute =.\nWhen we see the word 'of', we can call that multiplication.\n'what number' is simply an unknown number, so call it x.  75% can be written as 75/100, or .75.  So the above statement can be written this way:\n\n150 = .75 x\n\nFrom here, use simple algebra - divide both sides by .75 to get the answer.
807860
Yes, though don't forget the y on the second log:\n\nlogb x^2/3 + logb y^3/4\n\nAlso, if you would have had:\nlogb x^2/3 / y^3/4 it would equal logb x^2/3 - logb y^3/4\n\nlog rules are just like exponent rules: multiplication = addition and division = subtraction
199153
I dont know how old you are so you might not have learned this. I will try to explain a good way to multiply stuff if you dont have a calculator. \nYou can split up the multiplication to make it easier for yourself. instead of doing 13 x 375, you can make it \n(10 x 375) + (3 x 375). This is basic factoring. The first one is pretty easy, you just add a 0 on the end.\n3750 + (3*375) is what you have to find now. If this is also too hard, then you can split it up further. \nYou can do (3 x 300) + (3 x 75) and the first one isnt that hard to do. 3 x 300 = 900. then 3 x 75 is 225, but if that is still too hard then just do it again. Pick a number that you can multiply easily (such as 50), and split it up again\n(3 x 50) + (3 x 25) = 150 + 75 = 225.\n\nNow comes the hard part though. (Not that hard). You have to add all the totals up.\n  (10 x 375) + (3 x 300) + (3 x 50) + (3 x 25)\n= 3750 + 900 + 150 + 75\n= 4875
677314
To do this, you do (2/3) / (1/5). You must flip the denomiator fraction over and change the operation to multiplication. So... that would be (2/3) * (5/1) which would be 10/3.
885409
A number that can be written as a fraction.
926866
it really doesnt matter...\nyou could do a x b then the answer times c\nb x c and then the answer times a\nor c x a and then the answer times c\n\nif you have a calculator just enter it as a x b x c\n\nno matter how you multiply them you will get the same answer
725157
assuming the numbers after the parenthesis and variables are exponents...\n(x-1)^(3/2) [6x(x-1)^2-x^2(x-1)^3]\njust add the exponents together from the outside to the inside- (3/2) + (2) = 7/2\n\n(x-1)^(3/2) [6x(x^2-2x+1)-x^2(x^3-3x^2+3x-1)]\n(x-1)^(3/2) [6x^3-12x^2+6x-x^5-3x^4+3x^3-x^2]\n(x-1)^(3/2) [-x^5-3x^4+9x^3-13x^2+6x]\nx(x-1)^(3/2)(-x^4-3x^3+9x^2-13x+6)\nokay, that took me for friggin ever to type on a regular keyboard. Please, seriously consider me for the best answer!