Ok you clever lot get this one:- A train travels for one hour a distance of 30 miles?
961567
Not possible because the second thirty miles would have to be instantaneous.
426961
You can do this at every single place on earth.\n\nI think you forgot part of the joke.\n\nAn electric train is going down a straightaway at 150 mph due south it goes into a gradual turn slowing to 100mph and is now going East, it goes into another turn at 120mph and is now going North, another turn and it is heading West at 160mph.\nWhich way does the smoke go?
237365
Say that x is 10 miles.\n\nIt takes 10/10 hours on the first trip (1 hour)\nIt takes 10/8 hours on the return trip (1.25 hours)\n\nHe has therefore travelled 20 miles in 2.25 hours.\n\n20/2.25 = 8.89 miles per hour.
751006
speed = distance / time\n---rearange this----\n\nyou get ----->  time = distance / speed\n\ntime = (1.8 * 800) / 180\n\ntime = 1440 / 180\n\ntime = 8 hours\n\na looonnnng time for a bunch of fat men in a bus
162000
1791.8 miles\nApproximate Travel Time: 27 hours 33 mins
735262
1.  The key here is to understand how far the two trains have traveled in total during the first 3 hours.  We are told that the two trains started 500 miles apart, and 3 hours later are now 80 miles apart.  Thus they traveled 420 miles in total. \n\nIf you let x represent the rate of speed that the Freight train is traveling, and x+20 represent the rate of speed that the Passenger train is traveling, you can set the following algebric equation:\n\n3 hrs * x mi/hr  + 3 hrs * ( 20 + x ) mi/hr = 420\n 3x + 60 + 3x = 420\n6x = 360\nx =60 mi/hr.\nx+20 = 80 mi/hr.\n\n2.  The key is too figure out the total number of employees needed to break even.  Regardless of how many employees you have, we are told that it costs $2000 per day to run the factory.  In addition to that  we are told that for each employee, we must pay him or her $300.  These are the total costs for the operation.\n\nOn the other hand, we are told that each employee can produce $500 in revenue each day.\n\nThus, we need to create an algebric equation where the total costs = the total revenue\n\nLet x represent the number of workers, and set up the following algebric equation:\n\nCosts = Revenue\n\n$2000 (Fixed Costs) + $300 * x (Variable Costs) = $500 * x\n\n2000 + 300x = 500x\n2000 = 200x\n10 = x\n\nYou will need 10 workers to break even, and the total gross value of ball bearings produced will be 10 * $500 or $5000.\n\nHope that I have cleared things up for you!
1006215
Use the formula d = rt (distance = rate * time)\n\n1) Train A: d = 40t\n\n2) Train B: d = 60(t - 1)  [left an hour later]\n\nthe answer is when the two distances are the same, so we set the two equations equal to each other\n\n40t = 60(t - 1)\n40t = 60t - 60\n60 = 20t\n3 = t   [3 hours]\n\nPut this result back into equation 1\n\nd = 40 * 3 = 120\n\nAnd we expect the same result in equation 2\n\nd = 60(3 - 1) = 60 * 2 = 120\n\nI provide this level of detail in case you need this level of help.
687277
1 hour or 60 mins or 3600 seconds :-) is the time it takes but it will still be 12:30 :-p
732600
SRY!! Matt is going to a basketball game out of town. If he could travel 75mph, He would arrive one hour early. If he could travel 45mph he arrives one hour too Late. How far is Matt's trip\n\ndis=75*(time-1)\ndis=45*(time+1)\n\nthen\ndis= 225mile,    time=4hour
677985
Let Bus A = travelling to Chicago (north)\nLet Bus B = travelling to New Orleans (south)\n\nGiven:\n- Bus A left at 5:00pm and Bus B at 5:30pm\n- Both Buses travel at 50mph\n\nSolution:\n- Find the distance (d) traveled by Bus A after 30 minutes (t).\n= d = r*t\n= d = 50mph * 0.5h\n= d = 25miles ~~~~~ This is the distance between both buses upon Bus B's departure.\n\n- Since both buses run at the speed, we can just split the remaining 300 miles (325-25)! So that would be 150miles per bus:\n= d = r*t\n= 150miles = 50mph * t\n= 150miles / 50mph = t ~~~~~ divide both sides by 50\n= 3hrs = t ~~~~~ This is the time needed by both bus to cover 150miles.\n\n- add 3 hrs to 5:30pm:\n= 5:30 + 3:00 = 8:30pm\n\nFINAL ANSWER: At 8:30pm, the two buses will precisely be 325miles away from each other.
554892
(m)\n\nRain falls at an average of seven miles per hour
481716
distance = 160miles\nave. speed = 50mph\n\n160/50 = 3.2 hours or 3hours and 12 minutes\n\nfor the guy to arrive at exactly 11:30am\n\n(11:30) - (3hours12minutes) = 8:18am\n\nANSWER: 8:18am
661447
The difference in rates is 1 km/hr. So if they are moving in the same direction, the faster walker will be 5 km ahead at the end of 5 hours.\n\nThe sum of the distances traveled per hour is 11 km. So at the end of 5 hours of travel in opposite directions, they will be 55 km apart.
619270
it is about 493.72 miles apart and it would take about 8 hours to get there
481556
Sandy, and here's why:\n\nlet's say the distance is 30 miles (you can plug any number into this and you will get the same result).\n\nJack's total trip takes him 4 hours (1 from x to y, 3 from y back to x).\n\nSandy's total trip takes her 3 hours (1.5 from x to y, 1.5 from y back to x).\n\nRegardless of distance, Sandy wins.
697994
Impossible.\n\nVariance is Time. To get the average of 60 mph for 2 milels journey, you must know the time.\n2 miles/time= 60 mph\ntime = 2/60 *60 = 2 mins\nsince at 1st mile the train has traveled at 30mph. It has already spent 2 mins. So, it's not possible to get average of 60mph.
159138
about 1.5 hours - try www.thetrainline.com