what would p + 6 + 3p = 1 + 3p + 1 be?
967083
P = -4\n\nEntering the answer into the formula to "prove" it.\n\n-4 + 6 +3(-4) = 1 + 3(-4) +1\n\n-4 + 6 -12 = 1 -12 + 1\n\n-10 = -10
760641
x + 6 + 3x = 1 + 3x + 1\nCombine like terms.  x+3x = 4x and 1+1 = 2\n4x + 6 = 3x + 2\nSubtract 3x from each side\nx + 6 = 2\nSubtract 6 from each side\nx = -4
771200
You are 100% right.\n(4P+11)(4P-11)\n=(4P)^2-(11)^2\n=16P^2-121
1019688
(x - 2)*3 = 6 + x\n\n3x - 6 = 6 + x\n\n2x = 12\n\nx = 6
688567
1 + 2 = 3\n3 + 4 = 7\n7 + 6 = 13\n13+ 8 = 21\n21+ 10= 31\n31+ 12= 43
575490
I- + 2e- -------> I2\n\n4P + 3e-  -------------> P4\n\nthere ya go :)
283463
p divides n+3 and p divides (n+3)+7 ---> necessarily p divides  7 so p=7
774052
LetP(n) denote the statement\n1^2+2^2+3^2+......+n^2=n(n+1)(2n+1)/6\nwhen n=1,P(1)=1(2)(3)/6=1 checks\nlet P(k) be true\ni.e.1^2+2^2+3^2+.......+k^2=k(k+1)(2k+1)/6\nto prove\nP(k+1)=(k+1)(k+2)(2k+3)/6 is true\nP(k+1)=1^2+2^2+3^2+.......+((k+1)^2\n=>[1^2+2^2+3^2+......+k^2]+(k+1)^2\nnow 1^2+2^2+3^2+......+k^2=k(k+1)(2k+1)/6\nsubsttituting\n=k(k+1)(2k+1)/6 +(k+1)^2\n=(k+1)[k(2k+1)+6(k+1)]/6\n=(k+1)(2k^2+7k+6)/6\n=(k+1)(k+2)(2k+3)/6\nhence proved\n\n2.try by your self
537135
6+3 = 9\n5+4 =9\n10-1=9\n9x1=9\n27 divided by 3 =9\n8+1 =9
290738
12x+3-26=6x+1\n\n=> 6x-24=0 => x = 4
159634
well lets seeee.... 1 + 3 = 4 and 4 + 6 = 10, so next would be 10 + 9 = ... well i'll just leave that part to you!!
823306
1 1/3  X  6  =  (1 + 1/3) X 6  =  (1 X 6) + (1/3 X 6)  =  6 + 2
282800
3(4x+1)-26=6x+1\n12x+3-26=6x+1\n6x=26-2\n\nx=24/6=4\n\neasy wasnt it
1068964
simplify expression: -2(y+3)+6(y+1)\n\nsimply distribute then add.
825629
P(1/3)=3(1/3)^4-(1/3)^3-21(1/3)^2-11(1/3)+6\nP(1/3)=3(1/81)-(1/27)-21(1/9)-11(1/3)+6\nP(1/3)=(1/27)-(1/27)-(7/3)-(11/3)+6\nP(1/3)=0\n\nP(-2)=3(-2)^4-(-2)^3-21(-2)^2-11(-2)+6\nP(-2)=3(16)-(-8)-21(4)-11(-2)+6\nP(-2)=48+8-84+22+6\nP(-2)=0\n\nNow factor (x+2) and (x-1/3) out of the original equation (I used synthetic division). That leaves you with:\n3x^2-6x-9=0\n3(x^2-6x-9)=0\n3(x-3)(x+1)=0\n\nSo, the other two zeros are -1 and 3.
694795
11(p-3) = 5(p+3)              Distrubute the 5 and 11\n\n11p-33=5p+15                 Subtract 5p and add 33 to both sides\n\n6p=48                    Divid both sides by 6\n\np=8
146086
2x+y=6 => y=6-2x \n3x+y=1 => 3x+(6-2x)=1 => x+6=1 => x=-5\ny=6-(2*-5) => y=16\n\nx=-5\ny=16