what is the answer to the problem 2y - 4x = 4?
955089
y-2x=2\ny=2(x+1)\nx intercept(-1,0)\ny intercept(0,2)
1152335
Solve,\n\n3x = 2y - 5 ... (1)\n\ny - 5x = -1 ... (2)\n\nRearrange (2), we get,\n\ny = 5x - 1 ... (3)\n\nSubstitute (3) into (1)\n\n3x = 2(5x - 1) - 5\n\n3x = 10x - 2 - 5\n\n3x = 10x - 7\n\n10x - 3x = 7\n\n7x = 7\n\nx = 1 ... (4)\n\nSubstitute (4) into (3)\n\ny = 5(1) - 1\n\ny = 4 \n\nTherefore x = 1 and y = 4.
77049
first you have to tell us what you're solving for.(either x or y).\nIf you want to combine like terms u have to add 2y+2y you get 4y,then you try 4y+4x = ?.\nBut you forgot what is equal to if you're solving \nfor the letter x or y
767931
4x+2y=8\n\nSubtract the 4x to the other side to get\n\n2y= -4x + 8\n\nDivide the 2 on all sides to get:\n\n2y(/2)= -4x(/2) + 8 ( /2)\n\nYour final answer will be:\n\ny= -2x + 4\n\n4= y intercept and -2 equals the slope.
701963
2x - 4y = 24 Divide both sides by 2\n-x + 5y = -24\n\nx - 2y = 12 (1)\n-x + 5y = -24 (2)\n\nAdd (1) and (2) together\n(x-2y) + (-x + 5y) = 12 - 24 <=> 3y = -12 <=> y = -4\n\nSubstitute y = -4 in (1) => x -2.(-4)= 12 <=> x + 8 = 12 <=> x = 12 - 8 =4\n\nx = 4\ny = -4\n\nWhat do you mean by graphical solution? You can draw the two lines and see the co-ordinate of the intersection, I guess. (?)
720107
4x -12y =5...........(1)\n-x +3y = -1..........(2)\n\nMultiplying eq.(2) by 4 and add with eq.(1)\n(4x -12y =5) + (-4x +12y = -4)=\n0 = 1\nwhich is invalid.
714041
10x+4y+4\n\nor can be written as y= -2.5x-1
984033
2x+3y=4\n4x+3y=-36\nsubtracting\n-2x=40\ndividing by -2\nx=-20\nsobstituting\n-40+3y=4\nadding 40\n3y=44\ny=44/3
1134427
12x + 4y = 8\n(d/dx) * (12x + 4y = 8)\n12 + 4dy/dx = 0\ndy/dx = -12/4\ndy/dx = - 3
222015
5x - 2y = 4  (1)\n2x + 3y = 13 (2)\nmul. eq.(1) by 2: 2 (5x - 2y = 4)\n                    10x - 4y = 8\n\nmul. eq.(2) by 5: 5 (2x +  3y = 13)\n                    10x + 15y = 65\n\nsubtract: 10x -  4y =  8\n      (-) 10x + 15y =  65\n          ________________\n               -19y =  -57 \n                  y =  -57/-19\n                  y =  3\n\nsubstitute value of y to any of the eqs.\n\nSubstituting to eq. (1):\n\n    5x - 2y   = 4   \n    5x - 2(3) = 4\n    5x - 6    = 4\n    5x              = 4 + 6\n    5x              = 10\n     x              = 10/5\n     x              = 2\n\nso, x = 2\n    y = 3\n\nto check, substitute values of x and y to any of the two equations:\n    for eq. (1),\n\n    5x   - 2y   = 4   \n    5(2) - 2(3) = 4\n      10 - 6    = 4\n\n    for eq. (2),\n\n    2x   + 3y   = 13\n    2(2) + 3(3) = 13\n      4  + 9    = 13
758567
2(2x-4)= x+4\n4x-8 = x+4\n4x-x = 8+4\n3x = 12\nx=4\n\n&\n\n4(x+3)+3= 5(x-4) + 5\n4x+12+3 = 5x-20+5\n4x+15 = 5x-15\n4x-5x = -15-15\n-x= -30\nx = 30\n\n&\n\nx+2= 4(5x-2)\nx+2 = 20x-8\n2+8=20x-x\n10 = 19x\n19x= 10\nx=10/19\n\n&\n\n21-3x = 4x+7\n21-7 = 4x+3x\n14=7x\n7x = 14\nx=14/7\nx=2
744692
Consider the following equations:\n1)   2x + y = 4 \n  \n2)   x − y = −1 \n\nTo solve them simultaneously, first, you need to solve one equation with respect to one variable. Let's solve the first one:\n\n2x + y = 4  Rearranging, you get:\ny = 4 - 2x\nNow you know the value of y, so plug it into the second equation, like this:\n\nx − y = −1 Rearrange using the value for y that you determined above:\n\nx - (4 - 2x) = -1\nNow solve this equation, since it now has only one variable:\n\nx - 4 + 2x = -1\n3x = 4 - 1 = 3\nx = 1 Now that you have the real value for x, go back to the first equation and solve for the real value of y:\n\n2x + y = 4  \ny = 4 - 2x  we know x = 1 so, y = 4 - 2\ny = 2\n\nYou can prove these are the right answers by using them in the equations.
724639
2x-4y = 3.8\n3x - y = 17.7\n\nmultiply second equation by -4 so that when u add them both u will cancel the y's...\n2x-4y = 3.8\n-12x+4y = -70.8\n\nnow add them..\n\n-10x = -67\n     x = 67/10 = 6.7\n\nnow plug this x in for any one of the original equations and solve for y....\n\n2(6.7) - 4y = 3.8\n\n13.4 - 4y = 3.8\n-4y = -9.6\n   y = -9.6/-4 = 2.4\n\nso the solution is (6.7,2.4)
860215
6x - 2y = 8 dividing both sides by 2 we get => 3x - y = 4 -----(1)\n3x + 7y = - 4 -----(2)\n(1) - (2) => 3x - y - 3x - 7y = 4 - (-4)\n-8y = 8 and y= -1\nso x = 1
152532
y = 4x - 3 and y = 5x - 1, so\n4x - 3 = 5x - 1 (I substituted the value of y in the first eq'n to the second eq'n)\n-x = 2\nx = -2\ny = 4(-2) - 3\ny = -8 - 3\ny = -11\n;-)
119155
you're given these two equations:\n\n2x+4y=16\n8y+4x=32\n\nthe second equation can also be:\n\n8y+4x=32\n4x+8y=32\n2x+4y=16, which woah - is the same as the first equation!  in other words, the two equations are the same and, when graphed, are the same lines.  that means any point along the line is a solution.  thus, there are an infinite number of solutions.  one POSSIBLE solution is shown below:\n\n2x+4y=16\nx+2y=8, choose any "x" since this equation will work for all "x"s; say, let x=2.\n2+2y=8\n2y=6\ny=3, therefore x=2,y=3 is A solution.  plugging these back in gives you:\n\n2x+4y=16 ==> 2(2)+4(3)=16 ==> 4+12=16 ==> 16=16\n8y+4x=32 ==> 8(3)+4(2)=32 ==> 24+8=32 ==> 32=32\n\nta-da!
701107
4x +y = 16   ;2x + 3y = 24      Multiply the 2nd with -2, that gives -4x -6y = -48    Add the two:   0x - 5y = -32  \nDivision by -5 gives  y = 6,4\nInsert this value into the first equation:   4x + 6,4 = 16\n4x = 9,6 ;    x = 2,4\n\nNumber 2 is even easier:\nMultiply the first equation by 2 and add the equations.\n24x + 2y = 50    plus   8x - 2y = 14  gives  32x = 64; x = 2\nYou can now choose:  24 + y = 25  or  16 - 2y = 14\n(That you get when you replace in the original equations \nx by 2)  Anyhow you'll find   y = 1