How far will a car travel in 15 min at 20 m/s?
959780
Well, the car travels 20 m in 1 sec. There are 60 seconds in one minute, so multiply 20 m by 60 to find out how far the car travels in one minute.\n\n20 x 60 = 1200\n\nSo the car travels 1200 m in one minute. Multiply that by 15 to find out how far it travels in 15 minutes.\n\n1200 x 15 = 18000 m
841492
a)The acceleration a = Force / mass = -6070 / 2600 = -2.33 m/s^2\nInitial velocity u = 34.9 m/s\nThe velocity at any time is given by v = u+a*t = 34.9 - (2.33*1.76) = 30.8 m/s\nb) v^2 - u^2 = 2*a*s, where s is the distance travelled in that time. \ns = ( v^2 -u^2)/2a = 57.8 m\nc) The car stops when u + a*t = 0.\nt = 34.9/2.33 = 15 s
859010
The average veocity of the car from 0 to 25 m/s is 12.5 m/s.\n\nThe total amount of time it takes is 200 m / (12.5 m/s) = 16 seconds.\n\nThe change is speed in 16 seconds is from 0 to 25 m/s.  Therefore, the acceleration is (25 m/s)/ (16 s) = 1.5625 m/s^2\n\nThe force = mass * acceleration = 1600 kg * 1.5625 m/s^2 = 2500 N\n\nAnswer is d.
684454
Let's consider the case when the Car is right in front.\n\nAt that instance, the car is travelling tangentially to a circle of radius 132ft, where the Camera is the centre of the circle.\n\nCircumference of the Circle = 2*(pi)*R\n= 2 * pi * 132 = 264*(pi) ft.\n\nTime taken to travel the entire circumference by the car\nT = circumference/velocity = 264*(pi)/264 = pi seconds\n\nHence the car would require pi s to cover 360 degrees of the circle.360 degrees = 2(pi) radians.\n\nW = angular velocity = 2(pi)/pi = 2 radians/sec.\n\ncan't help about half a sec later now
325281
OK, this is a simple unit conversion problem, buddy. First, get your measurements into similar units: in this case, change your minutes into hours (1 hr/60 min). You'll end up with.\n\n(40 km/h * .5 h) + (60 km/h * .25 h)\n\nThe hours will cancel out, and you'll be left with the kilometers.\n\n20 km + 15 km = 35 km\n\nIn this instance, the direction of travel doesn't matter: the question asks the distance traveled, not how far away from the point of origin you are.
443173
This problem can be solved using v^2=2ax, where v is the velocity, a is the acceleration due to gravity, and x is the distance (this is a simplified version of a more complex equation, but this equation will work for this scenario).\n\na=32.15 ft/ s^2\nx= 30 ft\n\nSo, v^2=2(32.15ft/s^2)(30ft)\n\nOnce you solve and convert to miles per hour, you get approximately 29.9 mph.
228164
Speed is distance/time.\n\nSo for examle if a car went 120 miles in an hour their speed would be 120 miles/per hour.
824387
The ball goes from 0 to 9/s in .15 secs\n\nSo:    9meters           1\n        ------------  x    ------                  =9 /.15 m/sec2\n           second          .15secs\n\n                                                      =60 m/sec 2
960583
plz find car position and after \nincrement in car position and car is moving
696298
1st way :-\ndistance = speed x time = 55 mph x 3 h = 165 m\n\n2nd way :-\ngiven that d = 55t , so on putting t = 3hrs , we get d = 165 m
1106658
About 18.5 miles per second. 66600 Mph
1175600
They will meet when:\n\n4mph x Time = 3miles - 5mph x Time\n\nSo the answer is 0.33333 hours \n\nOr just 20 minutes.\n\n(not 27)
1170380
You have mass of car = 1500 kg.\nand speed = V = 25 meters per second.\n\nYou will recall the equation \nE = (1/2) * m * v^2\n\nKinetic Energy = 0.5 * mass * speed *speed.\n\nPunch these numbers into your calculator and you will get a numerical answer with units kilogram meters meters per second per second.\n\n\nThis is the kinetic energy of the car, which is removed by the brakes.\n\nI'm not going to do all your homework for you.  Just the first part to get you rolling.\nHave a great day.
1005028
if \na=(v-u)/t\nthen\na*t=v-u\nthen\nt=(v-u)/a\nor\nt=(15-0)/0.75 \n\nSo as the previous poster says the answer really is 20
782101
East bound speed=x, in 5 hours 5x\nWest                     =x+6,             5x+30\n10x+30=240\nx=21 miles per hour.\nEast=21\nwest=27\nVR
30694
20m/s.\nbecause the total time is 5s. and by defn of average speed it is the ratio of total distance travelled to total time taken i.e 100/5 = 20m/s
995779
To all those who answered 90 mph - BE MORE CAREFUL!\n\nMath Teacher