does this make sense?Its from pascal s triangle?
951662
well the number to the utmost left gets added by 11 and in every row 1 gets added more than the previous row so if u see the difference between any two consecutive row is always 12 !!\nthts wat i thnk
956637
Sorry tried a lot, searched a lot & surfed a lot but found no solution, I think Pascal is right.\n\nP.s- Saket it is ∫e^sinx dx & not ∫(e^x)*sin x dx, if it was that, it would have been trivial.
217638
simple answer, no.\ncomplex answer, yes.\n\nbut it is not simple, too many hoops, and you dont know if you are over-priting.\n\nbest to find another solution besides user tagging.
940980
So is this sequence based purely on a mathematical function?\n\nOkay, so there's a 52 in there, could this sequence somehow relate to the calendar?\n\nWhat sort of scientist? I'm a computer scientist and nothing's glaringly obvious about those numbers.\n\n** GOT IT *** 68! Er or Erbium, the sequence spells out Brainteaser based on the atomic weights of B, Ra, In, Te, As, and Er.
256487
in here www.thefreecountry.com/compilers/pascal.shtml
150854
i bet your thinking, my god, it has 3 values (x,y,z), how the heck does one attack this\n\nbelieve it or not, its simple\n\njust like you would in R^2\n\nsqrt[ (x-x1)^2 + (y-y1)^2 + (z-z1)^2]\n\nso \n\nsqrt [ (3-1)^2 + (-3- -4)^2 + (2-7)^2]\n\nso\n\nsqrt[ (2)^2 + 1^2 + (-5)^2]\n\nso\n\nsqrt [ 4 +1+25]\n\nso\n\nsqrt [30]\n\nhope that helps
815668
You have not provided adequate information about the quation to find an answer.\n\n\nBTW, it's "Ramanujan"
829946
I'd say that this is open to interpretation. you are best to ask your teacher or tutor, you cant trust our advice, cos none of us would know for sure.
430734
attention everyone shane is my b1tch, that is all... have fun translating this a$$h*les?\n\nIt's written in a substitution cypher called "Al Bhed", which is used in the game Final Fantasy to construct the language of the race of that name.
675348
I agree with chapin4ever's answer.\nand the three digit number is the ASCII equivalent of the symbol.
176413
Great puzzle, took me awhile to make it to f=1, g=4. The letters are from a-i: 9,8,7,2,6,1,4,5,3.\n\nPlugged in this is: (9 * 87 + 2/6) / (14 + 5/3) or (783 + 1/3) / (15 + 2/3) which equals 50.\n\nAnswer logged Sunday, March 12th, 3:20 pm with no other valid answers yet. Sorry to have to write that, but I've seen people change their answers too many times in the past.
1146358
I’m not seeing how this is solvable.  I’m getting two possible answers.\n\nBut here’s how you should work the problem.  \n\nFirst of all, I think you pretty much have to assume that the x,y < 10.\n\nSo we know that Bill can’t tell what his two numbers are just by looking at the product.  As it turns out, there are very few products that allow this to happen: they are 12,16,18,24,36.  So you factor out all the number pairs that would make those products, and the sums are 7,8 (twice), 9, 10(twice), 11(twice), 12, and 13.\n\nSo we know that Albert is seeing one of those sums.  If he sees 7, then he knows that the only way for his numbers to add up to 7, and multiply up to either 12, 16, 18, 24, or 36 is for the numbers to be 3 and 4.  But he says nothing.  Therefore, he isn’t seeing 7.  Neither is he seeing 9, 12 or 13, for the same reason.  So, now we know the sum must be either 8,10, or 11.  And now Bill knows that.\n\nSo, if Bill were seeing 12 as the product, he would know that the numbers were 2 and 6, since they add up to 8.  But he says nothing, so he’s not seeing 12.  Likewise, if he were seeing 18, he would know that the numbers have to be 2 and 9.  But he doesn’t, so he’s not seeing 18, and he can’t be seeing 36 either.  So that means he must be seeing either 16 or 24.\n\nAnd now Albert knows this, so either Albert is seeing a sum of 8, and knows that the numbers are 4 and 4, or he’s seeing 11, and the numbers are 3 and 8.  I just don’t know how to eliminate either of those options.
532980
I'm sorry but did you see this in My_Computer properties?\n\n\n\n--- ► λ ◄ \n\nN.B. I'm still a learner.
582564
In mathematics, Pascal's triangle is a geometric arrangement of the binomial coefficients in a triangle. It is named after Blaise Pascal, even though others studied it centuries before him.\nhttp://en.wikipedia.org/wiki/Pascal_triangle
683962
that is possibel only if your triangle abc is equilateral or isosceles. otherwise, that wouldn't happen:)
460547
This looks close enough to the techniques used to show that the roots are close to the critical line. The actual estimates are difficult, though, and nobody has been able to actually give a proof using these techniques (obviously). Go ahead and try it. Perhaps you can see through to a proof. If so, you will be famous. If not, you will have learned somthing.
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.