In the compound KClO3 the total negative valence is?
955815
In this compound (potassium chlorate),  the net charge is zero. The potassium ion has a charge of +1, and the chlorate ion (ClO3-) has a charge of -1.\nSo, the total negative charge is -1.
87280
MBrO3-9H2O where M can be Na,K,Li, other +1 cations\n\nIf M is other than these you have to adjust subscripts
837199
K+; its a CATION because it carries a positive charge\nions that have a negative charge are called anions\n\nCa(+2): cation\nGa(+3):  cation\nN(-3): anion\nBr(-):  anion
752218
2KOH + Cl2 ----> KCl + KClO + H2O\n6KOH + 3Cl2 ----> 5KCl + KClO3 + 3H2O
846516
Yes, it actually is that simple. Potassium bonds very well to both chloride and bicarbonate. Potassium has a +1 charge, while both chloride and bicarbonate have a -1 charge.\n\nCheck out this site for a detailed description of these three electrolytes and their effect on the body:\n\nhttp://www.medicinenet.com/electrolytes/article.htm
851182
Yes.  The easiest trick for determining polarity is to evaluate the electronegativity of the atoms.  Oxygen is more negative, while hydrogen is more positive.  If you write the partial charges on the atoms, you see that the charge balance is not equal.  If you had a molecule such as BCl4 (not real, just an example) the B is surrounded evenly by Cl atoms, so there is no polarirty
98695
My answer is,\n \nNH4NO3(ag) + KOH(aq) -> NH4OH(aq) + KNO3(aq)
921419
First of all let's find how many moles of KClO3 you have and how many moles of O2 are produced\n\nmole KClO3=mass/MW =0.261/122.5 =2.13*10^-3\n\n2KClO3(s) → 2KCl(s) + 3O2(g) \nthus 2mole KClO3 produce 3 mole O2\n2.13*10^-3 mole KClO3 produce x mole O2\n\n=> 2x=3*2.13*10^-3 => x=3.19*10^-3 mole O2\n\nIn order to find the volume you use PV=nRT, but how much is P?\nYou know that the total pressure is 722.7 mm Hg and the pressure comming from water is 17.5 mm Hg. Thus the pressure coming from O2 is 722.7-17.5= 705.2 mm Hg.\nYou have to convert into atm.\n1 atm is 760.0 mm Hg\nThus 705.2 mm Hg is 705.2/760.0 = 0.928 atm. This value of P will go in the equation\n\nPV=nRT=> V=nRT/P= (3.19*10^-3)*0.082*293/0.928= 0.08259 L= 82.59ml
863192
Cl2 is going to go to Cl- ; it goes from an oxidation state of 0 to -1.\nBr- is going to go to Br2, or from -1 to 0\n\nWhen an oxidation state goes more negative, you are gaining e-\nVice versa, when the ox. state gets more positive, you lose e-\n\nYou can figure out the rest from there and turn in  your homework.
833725
The group 3A elements have three valence electrons and typically assume +3 oxidation state when forming compounds.\n\nThe group 7A elements are called halogens and have seven valence electrons.  They take -1 oxidation state when forming compounds and are the most electronegative group of elements in the periodic table.
791152
The chemical formula of potassium alum is KAl(SO4)2.\nThe bonding type is mixed. The K+ and Al3+ ions are bonded ionically to the (SO4)2- ions. But in the latter the bonds are rather covalent as the S atom retains hold on its electrons at least part of the time.
231663
_KCl3 _KCL + _o2? K2Cl4o2 thats the answer i think.:)
811861
KCl(s)  ---->  K+(aq)  +  Cl-(aq)
284634
3K4Fe(CN)6 + 4FeCl3 -> 12KCl + Fe4[Fe(CN)6]3
596849
2 - Potassium Chloride\n\nIt has, by far, the weakest covalency of all those listed, and therefore breaks apart most readily.
853340
KCl + Cu(Cr2O7)\n\nDichromate has 2 Chromium +6s to counter the 7 oxygen -2s.  +2 + -2 = 0\n\nPotassium Chlorite and Copper Dichromate
830712
The MW of KClO3 is 122.55 (ref.), so 0.274 g KClO3 is .0022358 M. This will evolve 3/2 * .0022358 = .0033537 M O2 * 22.4 L/M = .075124 L O2 at STP. Correcting for temperature, pressure and partial pressure H2O, multiply by 295/273 * 760 / (726.2 -19.8) and volume at given temp. and press. = 0.087337 L.