what is the area of a equalateral triangle with a peremeter of 10 units?
966422
The area of an equilateral triangle is\nA = (1/4)sqrt(3) * a^2, where a is the length of the side.\nSince the triangle is equilateral, you know that the length of each side is 10/3.\nThe area is\nA = (1/4)sqrt(3) (10/3)^2\nA = (1/4)sqrt(3) (100/9)\nA = (25/9)sqrt(3)
323670
measure each diagonal, come up with the area of one triangle X it by 4, then work out the area of the base simple!
92345
Can you complete the question ? \n\nFYI : Perfect triangles are triangles with sides of integer length and having numerically equal integer area and perimeter.\n\nEg. Triangle with sides of length 6,8, and 10 units.
87402
a: width\nb: length\nperimeter = 2 x (a+b)= 420 ---> a+b = 210\nwe need to find max (a x b)\n\na= 210-b ---> area = a x b = b x (210-b) = 210 - b2 = - b2 + 210b = - b2 + 2 x 105 x b - 105squared + 105squared\n= - (b2 - 2 x 105 x b + 105squared) + 105 squared\n= - (b - 105)squared + 11025\n\nSince (b - 105) squared is always >= 0,\n - (b - 105)squared is always <= 0\n  - (b - 105)squared + 11025 is always  <= 11025\n\nthe largest area will be 11025 squared feet. This happens when - (b - 105)squared = 0, which means b = 105.\n\na = 210 - b = 105\n\n\nthe shortest way is to say that a rectangle has the largest area when it's a square, so each side would be 420/4 = 105.
936604
let the equal sides be x\n1/2x^2=area=20 given\nx^2=40\nx=rt40\nusing the pythagoras theorem\nc^2=a^2+b^2\nc=rt(a^2+b^2)\nthird side=rt(40+40)\n=rt80\n=4rt5 cm
779149
you can figure out the hypotenuse using the pythagorean theorem (a^2 + b^2 = c^2), so the hypotenuse is 10.\n\nAfter that, you just add up the areas of all the surfaces - For the triangles, its 6x8 divided by 2 = 24\n\nFor the rectangular faces, you do the following\n4x8 = 32\n4x6 = 24\n10x4 = 40\n\nAdd all these up and you get as surface area of 120.
941539
A square is a quaderlateral. All of it's sides are the same length. If you want to find the area you multiply the side by it's other side. In this case it would be 5 X 5. This would equal 25. So your square's area is 25 square units.
324878
I'm assuming you are asking for a formula to calculate the area when you just know the base (x) and not the height.  But, you need to know the height, even if the triangle is a right triangle.  To see this, imagine you had a right triangle standing on it's shortest side.  That shortest side would be your base, x.  Now stretch the triangle taller and taller.  The base length still stays the same, but the area inside the triangle grows and grows.  (And the triangle is still a right triange.) So, unless you know the height, you can't know the area.\n\nNow, what I'm guessing, is that your triangle might actually be not only a right triangle, but an isosceles triangle too, meaning that 2 of the sides are the same length.  And because it's a right triangle too, that means the two shorter sides (that connect at the right angle) are the same length.  So, your base and your height are the same length.\n\nIf this is true...\n\nlet x = length of base\nsince triangle is isosceles and right, height also = x\n\nSo the traditional formula becomes:\n1/2 BH = 1/2 x*x\n(sorry, can't figure out how to write "x squared" right now)\n\nHope that helps...
975485
H*W= area\nheight times width\n\none side has a height of 8 and its width is 9 thus the area would be 72
609578
definitely 63 square inches. The formula to find the area of a triangle is A=(1/2) x base x height. That is 0.5 times base times height. So, if you plug in the numbers, you get\n0.5 x 14 x 9 square inches\n(0.5 x 14) x 9 square inches\n(7) x 9 square inches\n63 square inches\n\nMake sure that whenever you look for the area of the triangle, the problem tells you that the numbers are the height and base.\n\nYes, 24 is correct.
579191
Area of a triangle:\n\nA = 1/2 (B)(A)\nwhere B = base which could be any of the three sides\nand A = altitude (or height), which is the perpendicular distance to the base B from the opposite vertex.
991928
Assuming you mean a regular hexagon, then with the 30-60-90 relationship, you should get that half the length of a side is 2.\n\nSo, the area of that yellow triangle in the link below is\n.5 * 2 * 2 * sqrt(3) = 2 * sqrt(3)\n\nThere are 12 triangles, so the area is 24 * sqrt (3).
235455
Area = 225 sq. cm = (15)^2\nPerimeter = 4*15 = 60 cm\n\nP*6 = 360 cm = 4x cm\nx = length of side = 90cm\nArea = 90^2 = 8100 sq. cm\n\nArea increased (6)^2 times, or 36 times.\n\n(225 * 36 = 8100)
628701
Area = 1/2 ac Sin B\n\nwhere a,b,c are the sides and A B C are the opposite angles. \nFrom the 10 sided figure you get an internal angle of 360/10 - 36 degrees so the other two angles are 180-36 all divided by 2 = 144/2 = 72 degrees.\n\nand the outside edge is 240/10 = 24\n\nSo using ac = 24 and Sin 36.. plug into the formula above.. this gives you the area of one triangle, then multiply by 10
193691
area = r^2 * pi\narea = 9.8^2 * 3.1415\narea = 96.04 * 3.1415\narea is about 301.71
509644
Formula of area 'A' of any regular 'n'-sided polygon of each side 'a' is\nA = 0.25*n*a^2*cot(pi/n)\n\nPut a=10 and n=6 in this formula.\nA = 0.25*6*10^2*cot(pi/6)\n  = 150*sqrt(3)   [since cot(pi/6) = sqrt(3)]\n  = 259.8 sq units
545831
You give two sides lengths, 10 , 15\nThe length of the other two sides are:\n15*(9/10)= 13.5 \n10 + 6.538348415 = 16.538348415