Can someone explain polarization of light simply?
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http://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/light/u12l1e.html
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these guys do it much better than i can:\n\nhttp://hyperphysics.phy-astr.gsu.edu/Hbase/class/phscilab/kundt2.html
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The basics...\n\nBackground:\nLight from the sun, light bulbs, etc. hit objects.  That light is reflected off but as a color which is a specific wavelength of light.  Our eyes get those reflect wavelengths and that's how we see.  Different color objects reflect light as different wavelengths.\n\nMirrors:\nMirrors reflect light off of them just like any other object.  The difference is mirrors reflect the same wavelength that hit them.\n\nSo, images seem to reflect when looking at a mirror.\n\nThere is a lot more too it but that is the basics.
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Light is not bent. I abruptly changes direction as it passes from one substance with one velocity of light into a second substance with a different velocity of light. The amount of change in direction depends on the wavelength of the light.
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In electrodynamics, polarization (also spelled polarisation) is the property of electromagnetic waves such as light, which describes the direction of their transverse electric field. More generally, the polarization of a transverse wave describes the direction of oscillation, in the plane perpendicular to the direction of travel. Longitudinal waves such as sound waves do not exhibit polarization, because for these waves the direction of oscillation is along the direction of travel.
847874
The moving photons in the ray of light can be calculated as a vector because they have a direction and a numerical quantity.
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Basically photons (or light) are the particles that is exchanged in communicating the electromagnetic force. To understand the essence of electric charge then you must understand light, or EM fields. This is independent of the atom.
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Light is a very odd thing to try and understand.  It behaves as a wave and as a stream of particles...we call this a dual nature.  You just have to accept it, really.  Light is like nothing else for it has no mass and behaves in two different ways.
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All light has a velocity of "c."  c is ~ 3*10^8m/s.  With this knowledge you can say that frequency is the inverse of time/distance.  Thus, you can use the formula C(meters/sec) / Freq.(cycles/sec) = Wavelength(meter/cycle) to solve the question.\n\nDo your own work from there.
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The maximum velocity of light is in air (strictly in vacuum).\n\nThe velocity is less in other medium.\n\nThe change in velocity from medium to medium is refraction.\n\nWhen light enters from medium 1 to medium 2, a potion of light is bounced back into the medium 1 and the remaining passes into medium 2 (Refracted). The bouncing back is reflection.\n\nThe proportion of reflection or refraction depends on the angle the ray makes at the point of incidence on the boundary.\n\nWhen light enters from glass (a medium of less velocity; optically denser medium) into air (a medium of more velocity; optically rarer medium) no portion of light is refracted (do not enter into air) at certain angles of incidences. The whole portion of light is bounced back into glass\n\nThey are TOTALLY AND INTERNALLY reflected.\n\nThere is no change in velocity and therefore total ilnternal reflection is not refraction,
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Polarized in a vertical plane
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Light 'dimming' is due to a decrease in the intensity of the light that reaches your eyes. This is different from the waves loosing energy or becoming 'shorter.'\n\nThink of it this way... When you shoot a shotgun, the pellets are very dense, grouped closely together, when the exit the barrel. As they get farther away from the barrel, they get farther away from each other. This is kind of what happens with a decrease in intensity.\n\nHere's another way, one that is more applicable to your question. Think of the surface of a star. It is, roughly, a sphere. To make this simpler, lets just think of the star as a circle. (It may help to draw this out as I'm explaining it) Let's assume that all of the light that is emitted comes straight out of the surface. A way to picture this is to draw straight lines from the center of the circle outwards. Do this for a few lines that start out very close together and are almost going in the same direction. Extend these lines out very far from the center. Do you see how, as they get farther from the center, they get farther away from each other?\n\nYou can also draw a tiny dot some distance away from the circle. This can represent the earth. How many lines that initially start out close together actually intersect this dot? Now can you see why the light gets dimmer? It is because only a small fraction of the light that is sent in our direction actually reaches us.\n\nWhile it is true that light waves do extend forever, they do not exist everywhere. To describe where something is located, you can only talk about how probable it is to be located somewhere. This is a consequence of the Uncertainty Principle.\n\nIf you want to know more, I suggest looking at wikipedia or googling Schroedinger's Equation. There are probably other people who can explain it far better than I could.
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No polarization does not offer UV protection as far as I've been able to find out.  UV protection has to be added to the lens in addition to having them polarized.
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Hi Scarlett,\n\nFirst of all, visible light waves consist of a continuous range of wavelengths or frequencies. When a light wave with a single frequency strikes an object, a number of things could happen. The light wave could be absorbed by the object, in which case its energy is converted to heat; the light wave could be reflected by the object; and the light wave could be transmitted by the object. Rarely however does just a single frequency of light strike an object. While it does happen, it is more usual that light of many frequencies or even all frequencies are incident towards the surface of objects. When this occurs, objects have a tendency to selectively absorb, reflect or transmit light of certain frequencies. That is, one object might reflect green light while absorbing all other frequencies of visible light. Another object might selectively transmit blue light while absorbing all other frequencies of visible light. The manner in which visible light interacts with an object is dependent upon the frequency of the light and the nature of the atoms of the object.\n\n"White" or natural light is made up of different colours (as in a rainbow) and Isaac Newton showed that these could be shown by shining white light through a prism.\n\nWhat "colour" we see an object depends on what wavelength of light it does not absorb and that depends on what the chemistry of the object is. This is because the electrons in a substance will vibrate at a certain frequency depending on what the construction (i.e. what the chemistry) of the atom is. Accordingly this will either absorb (interfere) or coincide with the wavelength of a particular colour.\n\nThus we will always see different chemicals as different colours (ie. wavelengths).
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y dont u do ur homework urself .ok heres abrief intro.\n\n1.see the level of frequency changes when beam of ultra violet light rays enter to one medium from another medium(to glass from air).\n\n2.when light undergoes refraction it frequency changes its speed acc. to the medium such as(glass,air and water)\n\n3.yes there will be,as light enters to one medium from another medium.
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mass, length, time, current, luminous intensity and solid angle steradians r fundamental. Rest all can b expressed by these alone.\n\nDarren G - missed d last 1.\n\nSo ur ans is option D
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No it can come out very different, depending on the materials involved.\n\nThe light can come out a different color. \nThe light can come out a different amplitude. \nThe light can come out in a different direction. \nThe light can come out with a different polarization.\nThe light can come with a phase lag.