Find the geometric mean between 28 and 18?
965509
Like before.. sqrt(28*18) = sqrt(504) = 22.4499, approx.
261755
Keep in mind that what you're doing when you add the logs is multiplying the ratios.  Then dividing by 3 takes the cube root of that.  So averaging the values is the arithmetic average and averaging the logs is the geometric average.  Which one is fits what you're doing best?  You'll have to figure that out.  I'd guess the geometric average based on the formula you've given.
971574
This is a proportioal problem\n\nMultiply the means\n\nmultiply the extremes\n\n- - - - - - -\n\nx = the amount of men\n\n4 / 7 = x / 28\n\nthe means = 7x\n\nThe extremes = 4 x 28\n\n- - - - - - - - - - - - - - -\n\n7x = 4 x 28\n\n7x = 112\n\n7x / 7 = 112 / 7\n\nx = 16\n\nThe answer there are 16 men\n\n- - - - - - s-
725278
the mean is the same as the average. so just add the three numbers together and divide by 3 (because that's how many numbers there are).\nexample: 12, 45, 63\n12 + 45 + 63 = 120\n120 / 3 = 40\nso the mean is 40
533931
67 * 18 / 6 + 17 - 18 = 200 :)
738486
8w-18 = 12w +14\n    +18           +18    add 18 on both sides\n\n    8w=12w + 32\n-12w   -12w          subtract 12w on both sides\n\n  -4w=32             solve for w\n   /-4    /-4\n\n   w= -8
342139
sqrt(2*18) = sqrt(36) = 6\n\nThe more general formula is found at the web site below.
783113
1)  13/107 is already in the simplest form\n\n2)  Notice that 28 = 7*4.  Therefore multiply 32 by 4 to get the denominator that goes under 28.\n\n3)  Notice that 6 = 1.5 * 4.  Therefore multiply 20 by 1.5 to get the denominator that goes under 6.
873308
OK - I will try and explain it, but forgive me if I get myself confused...  hehehe\n\nFirst step - make a bell curve.  Put a mark in the center and label that "7 hours" - that's your mean.  Next, put three marks on either side of that middle point - those will be your standard deviation points.  For the points on the right, ADD 5.3 to the mean for the first one, then add 5.3 again for the 2nd, etc...  Points on the left side of the mean have the 5.3 SUBTRACTED.  (Am I still making sense?  lol)\n\nNow - the 68-95-99.7 rule says that 68% of the freshmen will fall into the area between the first line on EITHER side of the mean, 95% between the second lines and 99.7% between the third lines on either side of the mean.\n\nI think you should be able to figure it from there - I hope so...  Right now I am so confused I think I gave myself a headache!  lol\n\nGood luck!
786357
The mean is simply the average of the data.  Add them all up and divide by 15.\n\n69.54
815956
An area of 0.99 has a z-szore of 2.33\n\nAll you have to do is to calculate the mean given the value of x, s and z.\n\nz = (x - mean)/s\nmean  = x - sz\nmean = 6 - (0.2)(2.33)\nmean = 5.534 oz.
994720
Well, I am going to assume that the function is: d=28+24cos[("pie"/5)(t-6)]. First of all, minus the 28, then divide by 24, then take the inverse cosine (arcosine), then divide by ("pie"/5) then add six, so it should result:\narccos [(d-28)/24] * (5/"pie") + 6= T
678307
You cannot use the empirical rule for these problems.  None of these numbers are exactly 1, 2, or 3 SD's away from the mean.  You have to use the standard normal table.\n\n1. z = (81-72)/6 = 1.5\nAnswer from tanble = 6.7% a)\n\n2. z = 1.282\n1.282 = (x-72)/6\nx = 80 to the nearest pound a)\n\n3. z = (70-72)/6 = 0.33\nz = (80-72)/6 = 1.33\nArea in table = 0.54 c)
30019
28 - 7*2*2\n\n155 - 5*31
870593
3/8 = 18/48\n2/3 = 32/48\nA number between 18/48 and 32/48 would be\n20/48 = 5/12
74440
The Mean is the average.  You have 22 numbers; add them up and divide by two to get the mean.  In this case, that gives 87.38\n\nThe median is the "middle" value.  Since you have 22 numbers, 11 of them will be below the median, and 11 will be above.  In your case, the 11th biggest number is 87.9 and the 12th biggest number is 88.  The median could be anything in between, but is generally taken to be the average of these two- or 87.95\n\nThe mode is the most common value.  In your case, each value occurs only once, except for 91.7 which occurs twice.  Therfore, 91.7 is the mode\n\nUpper and lower quartiles are similar to the median; The lower quartile is the value below which 1/4 of your values lie, and the upper quartile is the value above which 1/4 of your values lie.  Since you have 22 numbers, the lower quartile is the value between the 5th and 6th largest numbers (82 and 83.6), and the upper quartile is the value between the 17th and 18th largest numbers (92.9 and 94.2).  That makes 82.8 and 93.55\n\nThe range is the minimum value to the maximum value, or {68 to 98.2}\n\nTo get the variance, first subtract the mean from each value.  Then, take the square of each of these new values.  Then, add up all these squares.  Finally, divide this sum by the number of values (22 in your case).  This should give a variance of 51.22 with your numbers.\nNOTE:  The above formula is for "population variance", and is generally used when your numbers represent an entire population.  If your numbers represent a sample of a population, you should use the "Sample Variance", which has the same formula except that you divide by the number of values minus one (21 in your case).  With your numbers, this should give a sample variance of 53.66.\n\nThe standard deviation is just the square root of the variance.  Like the variance, there is a "population standard deviation" (7.16 in your case) and a "sample standard deviation" (7.33 in your case)
766935
The easy way is to note that both numbers have to be equal so 56/2=28\n\n\nthe hard calculus way is to maximize xy given that y=56-x\nx+y=56 implies\nxy=x(56-x)=56x-x^2= to find maximum of 56x-x^2\ndifferentiating with respect to x gives 56-2x. The critical point is when  56-2x=0 so x=28.y=28