OK smart people. Solve this Geometry Question. The winner gets 10 points!!!!?
961710
The boat rises as the water rises. It will never reach the rings. bob h spelled "near" wrong.\nSpud55 Didn't answer.\nTim assumed the boat was already afloat therefor the water might come closer that 7 ft to the ladder.\nWil t said "bob k" instead of "bob h"\niron duke insulted you\nI should get the 10 points ( not to mention that I am your husband)
563121
a right angled isosceles triangle\n\nplease give me 10 points now
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
621583
What type of triangle is it?\nIf it is an equilateral triangle, all sides will be the same length, so p=(1.25 X 3)m\n\nHope this helps
899919
16.72 inches squared.\n\n\nDivide an equilateral triangle into two equal right triangles (meaning, draw the height).  The right triangles will have angles of 30, 60, 90, right (an equilateral triangle has 3 60 degree angles)?\n\nThe ratio of the sides in such a right triangle (the smallest leg being a) is a:a(sq(3)):2a, where 2a is the hypotenuse and a(sq(3)) is the other leg.\n\nThe "other leg" in this case is the height.  So a, half of the length of the side of the whole equilateral triangle, is 5.382/sq(3).\n\nMultiply this by 2 to get the whole length of the side.  We have our base and height.\n\n\nThe area of an equilateral triangle is 1/2bh.  b=2(5.382)/sq(3)\nh=5.382\n\nPlug those in and you get 16.72.
243852
Hope this helps\n\n\nhttp://argyll.epsb.ca/jreed/math9/strand3/triangle_congruent.htm\n\nhttp://mathforum.org/geopow/fullsolutions/102596.solutions.html or www.mathforum.org
787980
i believe this is a continuation of the previous prob.\n\nit can be solved graphically. \ndraw the lines x + y = 2,  y - x = 2 and y = -2 on the cartesian plane. the feasible reason will be the area enclosed by the triangle formed by these 3 lines. the vertices being (0,2) , (4, -2) and (-4, -2). it can be proved that the max value of 2x + 3y will be one of these vertices. \n\nsubstituting, u can see the maximum occurs at (0,2) whence 2x + 3y = 6
902666
This may possibly be the easiest question anyone has ever asked on this forum. If you can't figure this out yourself, you really need to do more homework!! BTW, that is one freakin' tall sheep!!
863713
The only thing I remember about geometry is...a2 + b2 = c2.\n\nSomehow, I doubt that helps you.....sorry.
681882
I can't see your image, but if it is like any of these other pictures (see link), the problem is with the slopes of the triangles.  They may appear the same, but they aren't and that is where you lose a fraction of a square.  These small differences eventually add up to a full square if you rearrange things differently.\n\nThe key is in the slopes.\n\nI wish I could see the picture because I like area paradox puzzles like these.\n\n-----\n\nI'm back and can see your picture now... it is just like the first paradox in my link.\n\nThe answer, as I said is the slopes of the triangles.  One triangle has a rise of 2 for a run of 5 (slope = 0.40) and the other has a rise of 3 for a run of 8 (slope = 0.375).  So despite how it looks in the picture, that is not a straight line along the top.\n\nIn the top case, the slope causes a slight bend inward on that line.  In the bottom case, the slope causes a slight bend outward on that line.  If you take the difference between these two you get 1 sq. unit which accounts for the "missing" square.  The second link shows this visually.
473359
DEepnds on the shape. If it's a quadrilateral then it's 25 m. If it's a triangle, then it's 15 m. But that's only if all the shapes are regular (all sides and angles the same).
140436
First you have to know how to spell the various types of geometry: Euclidean, Non-Euclidean for a start. Then do a search for more informaiton.
703288
Cool geometry im learning this in class 2bad i cant help u cuz im faling -.-
368676
I see someone gave you the answer. Give Al the points! =-)
792610
Try these;\nhttp://www.mathleague.com/help/geometry/geometry.htm\nhttp://www.coolmath.com/home.htm\nhttp://www.ics.uci.edu/~eppstein/geom.html
185652
since your ddoing coordinate geometry you should at least tell what shape you're trying to get.\nI'm assuming it's a parallelogram so u should make it (1,8)
932841
This might help --> http://www.uwm.edu/~ericskey/TANOTES/Geometry/node15.html