Solve the following equation for x?
958049
[Log(11)3 - 7]/0.35 = x\n\nRead: Log base 11 of 3 minus 7 all divided by 0.35 equals x
998890
If you mean to solve it, it would be this:\nF:xtimesx=x^2\nO:xtime6.5\nI:xtimes-4.5\nL:-4.5times6.5\nEquals:x^2+2x-29.25
758848
let y = x^x\nw = ln y = xlnx\nthen y = e^w\ndy/dx = e^w * dw/dx\ndw/dx = x(1/x) + lnx = 1+lnx\ndy/dx = (1+lnx)*x^x
725566
The other way is to balance out the equation so only x is left on one side. So here we go.\nFirst, add 6 to both sides\n3x=6\nThen, divide by three on both sides and get\nx=2\nGood Luck
572493
=x(x^3-2)\n--> x=0 or x=2^(1/3) or -2^(1/3)
366751
make x the width, and solve the two equations (the one given, and the one assumed about the rectangle where l*w=A)
939696
there is no x in the equation
141310
to solve for X, you have to separate X from everything else. in that problem 2X+3X=5, you would combine the 2X and 3X to get 5X. so the equation end up as 5X=5. from there, divide both side by 5. 5X/5=X and 5/5=1 so X=1.
1046507
[2x/(x+3)(x-3)]*[(x-3)/4(x)]\ncancelling 2 and x-3 we will get\n=x/(x+3)2(x)\nsimplify we will get\n=x/(2x^2+6x)
936579
your question seems to be incomplete.\nso far....\nwidth=x\nlength= 2x-1
1144396
you would take the 2x-4y=3 and solve for a variable, such as x=(3-4y)/3   you now have what x equals and you sub that into the other equation so you now have 2[(3-4y)/3]-3y=0 and you should be able to solve that equation
429058
x==(-b+/-sqrt(b^2-4ac))/(2a).
846663
(x+3)(x-1)\n\n x= -3\nx=1
904672
let u = x^2 + 1, then you have du = 2xdx, => dx = 1/2x du,\n\nsubstitute back you are on the way  to solve it
1177677
shouldn't it be x^2??? if it IS x-squared, then sure, you could use the factorization method. \n\nit goes like this:  (6x + 1) (x - 1) = 0\n\ntherefore, x = -1/6 , 1
856711
because this has 2 unknowns it cannot be solved.\n\nbut I can write  x in terms of b\n\n2x = 13-b\nor x =(13-b)/2
764329
x(abs[x- (x^2)] (-1=2)\n\n:> peace\n.