If a beam of light has a wavelength of 555 x 10^-9m than whats its frequency?
953272
f * w = c\n\nFrequency in Hertz times wavelength in meters equals the speed of light.\n\nTo solve for frequency.\nf = c/w\n\nTo solve for wavelength\nw = c/f
972525
Calculate it yourself, using the equation: c = f x w\nc = velocity of light in vacuum = 3 x 10^8 m/s\nf = frequency of the light\nw = wavelength (convert 4000 A to meters; 1 A = 10^-10 m)
810936
f = c/L, where f is the frequency in Hz, c is the speed of light in m/s, and L is the wavelength in m.\n1 angstrom = 1e-10 m, c = 300e6 m/s, so,\nf = 300e6/4000e-10 = 750e12 Hz = 750e6 MHz...that's 750 million MHz.
819160
em energy radiated is proportional to T^4, so it would be : ((273.15+9627)/ (273.15+5227))^4 =10.5
49259
c = yf\n\nc = speed of light (3 x 10^8 m/s)\ny = wavelength\nf = frequency\n\n==> f = c/y\n\n==> f = 3 x 10^8 m/s / 0.032 m \n\nf = 9.38 x 10^9 Hz\n\n-or-\n\nf = 9.38 GHz\n\n:)
778975
Only if the photons would have their frequencies at about    \nf = 1.83*10^42 which is HUGE. \n  (c^2 / r)=[ K*(h*f / c^2) ] / r^2 Thus  f=(r * c^4)/(K*h)\nh=planks constant K=gravitational constant c=speed of light and f=frequency of the photon
751077
Yes...\n\nThe refraction indecces\n\nn =c/v, but c = wave lenght * frequency
20065
it has a wavelength of about 650 nm. divide the speed of light to the wavelength and obtain the frequency.
124381
You can use the equation c = fλ.\nNow f = c/λ = 3 x 10*8/600 x 10-9 = 5 x 10*14 Hz
738444
You create two waves a second -> frequency = 2 Hz\n\nperiod = 1/f = 1/2 = 0.5 s\n\nThe wave travels 0.18m per 0.5 s, which is .36 m/s
252752
When the lightwave is traveling in a vacuum, there is no change regardless of the wavelength.  All light travels where there is no matter at roughly 300,000 km/sec.\n\nFor other materials, you would have to look at the dispersion relation for that material.  This will tell how the speed of light at different wavelengths is affected by the material.
943929
The frequency of light and its wavelength have an inverse relationship.  As the frequency of light increases, the wavelength decreases.\nThe frequency is the number of 'cycles' per unit time, and the wavelength is how far the wave propagates in that same time.  At a constant speed, the shorter the higher the frequency (very short time durations between cycles), the smaller the wavelength.\n\nThe energy contained within a single photon of light is given by Planck's equation,\nE = hv\nwhere E is the energy, h is Planck's constant, and v is the frequency of light.\nThe equation can be re-written as,\nE = h * c / lambda\nWhere c is the speed of light in a vacuum, and lambda is the wavelength of light.\n\nYou can see that as the frequency of the light increases (or when the wavelength decreases), the energy contained within a photon of light increases.  The higher the frequency of light, the more energy the light carries.  For example, high frequency X-rays carry much more energy than low frequency radio waves.\n\nh = 6.626 E-34 J s
517715
Yes, if L is wavelength, then it is L/2.
706718
The energy contained within a single photon of light can be found using Planck's equations,\nE = hv\nWhere E is the energy, h is Planck's constant, and v is the frequency of the light.\n\nYou can see that the higher the frequency of light, the higher the energy per photon.\nExamining the spectrum of light one can see that green light (roughly a wavelength of 550 nm) has a higher frequency than orange light (roughly a wavelength of 650 nm).\nTherefore, green light photons contain more energy than orange light photons.\n\nPlanck's constant = h = 6.626 E-34 J s
827543
The equations involved are:\na) freq*wavelength = velocity of wave\nb) energy of radiation E = h*freq, where h is Plank's constant.\nYou can work out from these that the choice should be a.
267019
Given:\nh = Planck's constant = 6.626*10^-34\nf = frequency = 7.5*10^14\n\nBinding Energy = h*f = 6.626*10^-34*7.5*10^14 = 4.9695*10^-19 Joules\n\n============================================================\nGiven:\nh = Planck's constant = 6.626*10^-34\nf = frequency = 7.5*10^14\nc = speed of photon = 3*10^-8 m/s\nWavelength of photon = 366 nm = 3.66*10^-7 m\n\nFrequency of photon = c/wavelength of photon = 3.3*10^-8/3.66*10^-7 = 0.090163934 /s\nEnergy of photon = h*f = 6.626*10^-34*0.090163934 = 5.97426*10^-35 Joules\n\n============================================================\nSorry, I'm actually at work. Not being able to concentrate too much on it.\n\nEnergy of photon should have been bigger than the B.E. of electrons. Try to figure out, why its not.\n\nDifference of the two energies would be the energy of the realsed electrons from the surface.\n\nWhen I'm done with work I'll check back and try to finish it up.\n\nHope you understand.
956950
The exact same as all light -- all wavelengths travel the same\n\n3 x 10 ^ 8 m/s or 186,000 miles per second