Solve this calculus equation (for 10 points)?
959197
I have factored it please refer to.\n\nFrom this solution can be found
838481
Well hey, you need help, ask the teacher! I know how to do this, with help from my nerdy Calculus BC friend, but it's really not that hard once you think about it...
1105592
y+dy=5(x+dx)^2 +1\n  y+dy=5(x² +2xdx +dx²) +1\n    y+dy=5x²+1 +5(2xdx+dx²)\n       dy=10 xdx as dx² is very small\n          dy/dx= 10x
813994
the first one is (x+10)(x+8)\nand the second one is your second answer
106013
y = -2x + 8\n\nsolve it yourself
782406
°oO****Oo°°oO****Oo°°oO****Oo°\n\n\n 4 ∫[g(x)] g'(x) dx = 4 x 1/2g(x)² +c = 2g(x)²+c\n\nits the first suggestion that u made but i think you forgot the number 4...\n\n\n°oO~<<_P~'*'_ I~'*'_M~'*'_O~'*'~L _~'*'_A>>~Oo°
464039
Your equation would be:\n\n= ((1/p) - (1/q))/(1/pq)\n\n= ((q - p)/pq) * pq\n\n= q - p\n\nHope I am clear.
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
932135
x=0.66666666666.........................................\n10x=6.666666666.........................................\nsubtracting 1 from 2\n9x=6\nx=6/9=>2/3\n\n2.0.35\n=35/100\n7/20\n\n3.0.37506\n=37506/100000\n=18753/50000
217134
Hi there,\nThis is a linear differential equation and can be solved using a certain list of steps (check any calculus text book). To avoid finding an integrating factor etc, we note that by dividing by x^2 we get:\nf'(x)/x - f(x)/ x^2 = 1/x\nThe left side is the same as (f(x)/x)' [product rule].\nThus we have, (f(x)/x)' = 1/x\nIntegrating gives f(x)/x = ln|x|+C\nSo, f(x)=x ln|x|+Cx\nSubstituting f(-1)=1 gives C=-1\nThus, f(e^-1)=(e^-1) ln|e^-1| - e^-1=-2e^-1.\n\nCheerios,\nMike
918737
The equation for the tangent is:\ny = f'(a) * (x-a) + f(a)\n\nYou need to calculate the derivative h'(t) for t=3s and plug that into the equation, adapted to your problem:\n\ny = h'(3) * (t-3) + h(3)\n\nI'll let you do the maths...
797737
Ok, take your equation \nf(x) = 2x^2 - 10\n\nreplace f(x) with y\n\ny = 2x^2 - 10\n\nswap y and x\n\nx = 2y^2 - 10\n\nsolve for y\nto do this first add 10 to both sides\n\nx + 10 = 2y^2\n\ndivide both sides by 2\n\n(1/2)x + 5 = y^2\n\ntake the sqaure root of both sides\n\nsqrt((1/2)x + 5) = y\n\nchange y to f(x)^-1 [the inverse function notation]\n\nf(x)^-1 = sqrt((1/2)x + 5)\n\nhope this helps
796832
5(2^2)+5(2)+2y=2\n2y=-28\ny=-14\n10x+5+y+x(dy/dx)=0\nx(dy/dx)=-10x-5-y\ndy/dx=(-10x-5-y)/x\n(-10*2-5-(-14))/2\n-11/2\ni hope thats right
3037
This is not presented as an equation, so the goal appears to be to combine the rational expression --> x+10 \nThat's all you can do with the question as it is written.
996406
solve for x for the eq. of x+ky=10, and you would get x=-ky+10. plug that eq. to the x^2+y^2=10. and solve for x or k. after you get that, plug it back into the x+ky=10.
832686
Take the integral of this function, like this:\n\n∫ (10 + x²) / x³ =\n\n∫ (10 / x³) + ∫ (x² / x³) =\n\n10 ∫ (1 / x³) + ∫ (1 / x) =\n\n10 (-1 / 2x²) + ln(x) + C = \n\n-5 / x² + ln(x) + C\n\n~ ♥ ~
741999
whats the equation or formula u need help with?