what is thermal expansion of 90 durometer urethane?
953550
see this website :\nhttp://www.hydraulicspneumatics.com/200/FPE/Accessories/Article/True/6443/Accessories
85318
Heat is equal to the change in enthalpy, dH, which is equal to the enthalpy of the products minus the enthalpy of the reactants.\n\ndH=H(products)-H(reactants)\n\n2B + 3F(2) --> 2BF(3)\n\nGet the heat of formation values for each specimen from a chemical thermodynamics table. I don't have a table in front of me so I'm just going to make up values so you'll know how to solve the problem. Let H=100 for B, H=150 for F(2), and H=400 for BF(3).\n\ndH= 2(400)-[2(100)+3(150)]\ndH=800-650=150 kj/mol\n\nI do know that elements alone have a heat of formation of 0, but I don't remember if the element has to be in a certain state or not.
422875
U have not mentioned the gas gravity to determone deviation factor to have an exact answer...generally..taking z=1\npsia ( absolute value) will also be used \nPsc*Vsc/Tsc=PV/T\n\nso: Vsc/V=PTsc/PscT=53.1/T \n\nThis is the simplest correct answer.... make is easier but worse that the process is isothermal so\n\nVsc/V=102 --> 1cu ft at TVD= 102 SCF\n\nThe most exact solution can be provided if u want..with taking temperatire and deviation,composition in account
198092
Use:\n\npressure = density x height x g\nwhere g = 980 cm/s^2\n\nfor each liquid.  the answer (in dynes) will be the sum of the two pressures.
855038
increasing steel volume would increase ammount spilled. the steel ball becomes bigger and there is less volume left for mercury=> more spilling. so it should be +ve: \nChange in Volume = mercury(B*V*changeT) "+" steel(B*V*changeT) - brass(B*V*changeT)\n\nActually, contrary to what I thought before, you don't need to convert B_brass to per-area beacuse when solid sphere expands it's surface expands in the same ammoun as hollow sphere (i did derivation to prove it, but it's long so im not gonna post it).\nanswer= 1.1736 x10^-6 m^3\nif you have questions email.
774630
Commercial grade (98 to 99 percent) Tetraphenylcyclopentadienone (or 2,3,4,5-tetraphenylcyclopenta -2,4-dien-1-one) has a melting point of 217 to 220 drgrees C.  The pure recrystalized specimen will usually melt at about 222 degrees using a vacuum melting point tube.
21920
Cr - 51.995g/mol\n49048gCr / 51.995gCr/mol = 943.32mol Cr\nStoichiometrically 2Cr to 3Cu so 943.32 x 3/2 = 1415mol Cu.\n\nPlease correct me if I'm wrong but that makes sense to me.\nOh and please award me best answer...\n\noh and part b:\n200ml x 0,75mmol/ml = 0.15mol\n0.15mol x 2/3 = 0.1molCr\n0.1molCr x 51.995g/mol =5.2g Cr.\n\nAgain correct me if I'm wrong...
1137013
Thermal Properties Conditions \nTemp. (K) Pressure (Pa) \nMelting Temperature  1357.77 K   101325  \nBoiling Temperature  2835.15 K   101325  \nCritical Temperature  8280 K     \nFusion Enthalpy  208.7 J/g 0  101325  \nHeat Capacity  385 J/kg-K 298.15 more...  100000  \nThermal Conductivity 401 W/m-K 300 more...  101325
427727
Material objects (solid, liquid or gas) are made up of particles called molecules.   (Molecules are in turn made up of atoms, with one or more atoms per molecule).  These molecules are in constant motion, vibrating, rotating and translating (moving in a straight line).  Temperature is the mean kinetic energy (energy of motion) of the molecules making up an object.  Molecules don't all have the same kinetic energy, it's distributed randomly among them.\n\nWhen molecules collide (as they do constantly) they transfer kinetic energy.  When two systems of molecules come into contact, the molecules of the two systems collide and exchange kinetic energy.  The mean kinetic energies of the two systems even out: if one is colder than the other (lower mean kinetic energy) it becomes warmer (higher mean kinetic energy); if one is warmer it becomes colder.  \n\nWhen a clinical thermometer (or any thermometer) comes into contact with a warm object (a patient) the kinetic energy of the molecules of the thermometer warm up to match those of the warm object (since the patient is quite large & generates its own heat, the decrease in the patient's temperature is very small).  The thermometer typically has some liquid subsance (mercury, alcohol, ...) that expands when it warms, as molecules moving faster take up more space (bounce into each other harder, push each other further away).  So the "reading" of the thermometer goes up as the liquid within the thermometer expands.
659692
Semtex H  \nPETN         49.8 %  \nRDX          50.2 %  \nDye          Sudan I (red-orange)  \nAntioxidant  N-phenyl-2-naphthylamine  \nPlasticizer  di-n-octyl phthalate, tri-n-butyl citrate  \nBinder       styrene-butadiene rubber\n  \n        Semtex A \nPETN         94.3 % \nRDX          5.7 % \nDye          Sudan IV \nAntioxidant  N-phenyl-2-naphthylamine  \nPlasticizer  di-n-octyl phthalate, tri-n-butyl citrate  \nBinder       styrene-butadiene rubber
1122922
Density of LOX is 1140 kg/m3 at -183 C, 1 atm\nDensity of GOX is 1.29 kg/m3 at 0 C, 1 atm (same as air, ideal gas)\n\nTherefore 1 m3 LOX = 884 m3 GOX\n\nDense fluid expander would work for LOX to GOX however this would probably be too heavy for a spaceship.  \n\nNote of caution, if to do use pure gaseous oxygen, it is a major fire risk.  Do not get hurt screwing around.
775136
when ever two dissimilar metals are joined  they produce a specific millivoltage at each degree of temperature\nif you graft the changes you will find a bell curve \nunique to each type \nthis is how you determine which is proper one for your use\ntype K alumel and cromel  is used at medium temperature ranges 90 to 1600 degrees F
432258
Since it is at thermal equilibrium, the energy (q) of the water must equal the energy (q) of the metal.\n\nTherefore: mcAT = mcAT\n\n(90)(4.18)(0.9) = (11)(87.2)(c)\n\nSolving for c, the specific heat of the metal would be 0.353 J/g*oC
871220
The second one:\nAF + H --> AFM + TM\n\nActivation E: +10KJ/mol is moderate\nHeat of Rx= +5.2 KJ/mol is positive, making this an endothermic reaction (requires the input of heat or energy to accomplish).\n\nSee the site below:
755934
If any site would have this, I would think the Army Corps of Engineers ERDC Cold Regions Research Lab website, listed below, would have this. It's got to be there somewhere!\n\nGood Luck!
324916
1,2,3,4-Tetramethyl-1,3-cyclopentadiene \n85% (26.5 USD/gr)\n\nC9H14 \nF.W. 122.21 \n[4249-10-9] \n\nDensity 0.80g/mL \nBoiling Point 142°C \nFlash Point 42.00°C \n\nn n20D 1.47 \n\nRecommended storage: Refrigerator +4°C
214548
You should use DOD Specification 5200.28-M, for the degaussing and destruction of high-density media.\n\nhttp://all.net/books/standards/remnants/standards.html