slove this nuclear equation Uranium 246 producing two gamma rays by alpha particle production.?
956102
Here is the equation\n\n(246,92)U ---> (4,2)He + (242,90)Th + 2Gamma
167143
Start with formula for total energy (the derivation of this is pretty awful and requires lots of diagrams to explain it)\n\nSo total energy is g*m*c^2 [g is gamma factor 1/sqrt(1 - V^2/c^2)]\n\nThe kinetic energy is total energy minus internal energy of particle = g*m*c^2 - m*c^2 (1)\n\nNow expand the gamma factor as a binomial series:\n\ng = 1/sqrt(1 - V^2/c^2) = 1 + (v^2/2*c^2) + ...\n\nsubstitute this into the above equation (1) and you get\n\nkinetic energy = m*c^2(1 + v^2/2*c^2) - m*c^2\n\n= 1/2*m*v^2\n\n(This is an approximation - so this only applies for low velocities. For relativistic velocities use formula (1) or expand the binomial expression to higher degrees of 'v')
199003
a proton has a weight of approximately 1836.15 electrons
101213
You may already know the answer, but I'll give you credit for wording it precisely.\n\nThe answer is more than one (on average), because neutron losses mean it would be impossible to sustain a critical nuclear reaction (that is, a constant rate of nuclear reactions) if you had one or less than one (on average) per reaction, since it takes at least one neutron to cause a nuclear reaction.\n\nThe exact reaction that occurs and the byproducts produced will determine exactly how many you get per individual reaction, but *on average* you need to net >1.0 neutrons per reaction.  The more losses you have (due to poor shielding, absorbant material, etc.), the higher the number needs to be, but something like 1.2-1.5 should be fine.
987522
The equation was a result of the mathematics involved in explaining the Special Theory of Relativity.  \n\nAfter the theory was published, a mother and son team of physicists (sorry but I forget their names), were performing fission experiments.  Fermi was the first to have performed a sustained chain reaction.  When this team split an atomic nucleus, they found that the parts left over after the split did not add up mass or matter-wise to the mass of the original atomic nucleus.  Where did this mass go?  It was converted into energy.  Energy and matter are transmutable.  At what rate does matter convert into energy in a fission  reaction?  c^2\nEnergy [E] is equal to mass [m] * the speed of light [c] squared.
608949
cant answer secifically, but you should be able to back calculte taking elements present today and using the half lives as your main variable.
546696
Ok, So you know the Time, the Starting mass we'll say Ao, and the Half life.  So by the equation:\nA/Ao = (1/2)^n,\n\nwhere A is the amount remaining, Ao is the starting amount and n is an integer, which needs to be determined.\n\nn = T/(t)\n\nWhere t is the half life and T is the time elapsed.  \n\nSo you first solve for n, and then derive the expression for A.  you should get the equation,\n\nA = ((1/2)^n)*(Ao)\n\nThat'll give you the new mass and from the mass you can use Avogadros number to determine the particles emitted.
651178
14C --> 14N + e ( = beta particle)
756921
the answer is\n2Al + N2 ----> 2AlN
724861
For the first question, , I think C is the least correct.  Alpha and beta emissions are particles, not rays.  B is also suspect, because not all radioactive emiissions are both particulate and energy.\n\nFor your true/false question, the answer is FALSE.  An alpha emission reduces the atomic number by 2, and reduces the atomic weight by 4.
903111
The answer is 2\n\nWe see it happening all the time when beta plus (positrons) come in contact with electrons, which are their anti-particles. The result is annihilation and two gamma rays. The gammas share (somewhat unevenly) the rest-mass energy of the electron-positron pair (2 times 0.511 MeV = 1.022 MeV). \n\nIf a proton and an anti-proton annihilate (this can happen in accelerators) the energy would be about 2000 times greater.
798483
Here it is:\n\n(98,42)Mo + (1,0)n ---> (99,42)Mo
470230
Many people have, in every single nuclear reaction, whether in power plants or detonated nuclear weapons. Nuclear binding energy is generated by mass converted to energy which holds nucleons together. In nuclear reactions differences in binding energy between the reactants and products in atoms is released as light, thought not necessarily visible light.\n\nLight is also produced in particle-antiparticle annihialition. If an electron and positron collide, they annihialate each other and release 2 photon's of equal energy and momentum as the 2 original particles.\n\nIt is also possible to create particle-antiparticle pairs from photons fired into strong magnetic fields.
220685
They are alike in that they are all high energy emissions fron the sun. All are dangerous if you are exposed to them.\n\nThey are different in that gamma rays are high energy photons with zero rest mass, and alpha & beta particles are actual particles with non-zero rest mass. Alpha particles are helium4 nuclei with no electrons attached. Beta particles are high energy electrons emitted from a nucleus as it decays.
176876
The gas in the balloon is helium. These helium atoms were once the alpha particles of radioactive decay trapped with other particles beneath the ground in natural gas deposits. For each uranium atom that decays to lead, 8 alpha particles are emitted. An alpha particle with 2 electrons is a helium atom.
821096
Because being so dense, Uranium is higly unstable. A normal atom simply shouldn't contain that many protons, neutrons, and electrons, so every once in a while, protons start popping out, which is what causes the radiation output. Over time, Uranium gradually changes into lighter and lighter elements through the loss of its electrons. This process is called radioactive decay.\n\nBTW, I don't mean to show off, but I'm only 14.
858334
Thorium-234 and Protactinium-234