Calculate the mass of oxygen-16 ions with a charge magnitude of 3.20*10da-19C, accelerated into a?
959062
The ions are acceerated through the potential difference V. The kinetic energy they achieve going through that potential is\n\n0.5*m*v^2 = Q*V\n\nwhere m is the mass, v is the speed, Q is the charge, and V is the potential difference.\n\nThe moving charge in the applied magnetic field will result in a force that is at right angles to the motion. The ion will traverse a curved path, and as a result will experience centripetal acceleration. The force of the applied magnetic field (Q*v*B) is balanced by the centrifugal force.\n\nQ*v*B = m*v^2/r\n\nQ*B = m*v/r\n\nUsing v derived from the energy balance above\n\nv = sqrt(2*Q*V/m)\n\nso that\n\nQ*B = (m/r)*sqrt(2*Q*V/m) = sqrt(2*m*Q*V)/r\n\nSolving for the mass m\n\nm = (Q*B*r)^2/(2*Q*V)\n\nsimplifying\n\nm = (0.5*Q/V)*(B*r)^2
728397
You need to first balance the equation.\n\n2CO + O2 --> 2CO2\n\nUsing this you find the answer to be D.
694411
IAnd for your other request, I would request you to send a seperate mail to me through yahoo Answer so that I am able to send it part by part.These are long subjects and would take some time,The balanced equation would be                                           H3PO4+3KOH=K3PO4+3H2O
775039
For the groups on the table, the ion charges are\n\n          1       +1\n          2       +2\n         13      +3\n         14    +4/-4\n         15       -3\n         16       -2\n         17       -1\n\nThe ion charge equals the number of electrons gained (-) or \nlost (+) by the atom to form the ion.
235216
mass P = 283.9 * .4365 = 123.92g P\n\n  moles of P =  123.92/30.97 = 4\n\n so = P4\n\nunknown molecular mass = 283.9 - 123.92 = 160g\n\n P has a charge of 5+ times 4 = total charge of 20+\n\n    \n20 can divide into 1-,2-,4-,5-,10-,20- evenly \n   \n the trial and error method\n   \n   160g /10 =16\n\nthe unknown F.W. is 16g which is Oxygen that has an anion charge  Of 2-\n  \n so (5+ * 4 ) + ( 2- *10) = 0\n \n    oxygen moles = 160 / 16  = 10\n\n     O  =  O10\n\n the molecular formula is:\n\n\n P4O10
561926
XeF  + e-  ============> Xe  + F-      E°/V = 3.4 with reference to the standard hydrogen electrode
699905
mass initial = Mi\nmass final = Mf\n\nMass growth = Mf - Mi\nPercent growth = Mf/Mi * 100
287378
Mass spectrometers are only able to record the total weight on an atom that passes through. Since oxygen isotopes are measured by reacting calcium carbonate with acid to form carbon dioxide, the mass spectrometer reveals the molecular weight of each carbon dioxide molecule. Assuming carbon-12, there are then 6 possible combinations of carbon dioxide that the mass spectrometer will record.\n\nThe oxygen combinations can be O-16 and O-18; O-16 and O-17; O-16 and O-16; O-17 and O-17, O-17 and O-18, and O-18 and O-18. The mass spectrometer will then record masses of 46, 45, 44, 46, 47, and 48 for these. So you can see that you will not be able to tell the difference between O-16/O-18 and O-17/O-17 because they both come to 46. That is why you have to independently determine how much O-17 is in the sample and correct for the ambiguity.
820473
Carbon dioxide is not weightless\nIn fact is has \n\n12g in carbon, and in oxygen it has 12, but as there is 2 carbon atoms there is 16g in oxygen\n\nSo 12+16*2 = 44g.\n\nHow do i know this? Look at the periodic table.
697475
1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 7.849 g x (12 / 44) = 2.141 g\nhydrogen: 3.213 g x (2 / 18) = 0.357 g\noxygen: 3.215 - 2.141 - .357 = 0.717 g\n\n2) convert to moles.\ncarbon: 2.141 / 12 = 0.178 mol\nhydrogen: 0.357 / 1 = 0.357 mol\noxygen: 0.717 / 16 = 0.0448 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.178 / 0.0448 = 4\nhydrogen: 0.357  / 0.0448 = 8\noxygen: 0.0448 / 0.0448 = 1\n\nThe empirical formula of the substance is (C4H8O)n\nThe atomic masses add up to 72, which is also the molar mass of the compound. Therefore n=1 and we find C4H8O
753355
125.6\n\nhttp://www.webelements.com/webelements/elements/text/Ag/ionz.html
707973
You have to start with a balanced equation.  The subscripts will give you the correct charge and a prefix will give you the right amount of atoms on each side of the equation.  Some elements, like O, F, and I are diatomic and come in pairs.
843441
The answer is c.\nC12H22O11+12O2-->12CO2+11H2O
736571
there are .833 moles. divide the mass by 18 (2 hydrogens + 1 oxygen) oxygen= 16g/mole Hydrogen = 1 g/mole
776335
2C8H18 + 2502 ---> 16CO2 + 18H20\nit sometimes helps to first solve H then C then O in that order.
111480
it appears to be the name of the CO-2 ion. (-2 is the charge).
251863
At 20 degrees C, it's 0.6g/100mL. You can convert that to a Ksp.