Ok, science homework so all you smartypants please help!?
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There is also friction caused by the turning of the gears.  The pendulum need enough mass to overcome this.
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6 CO2 + 6 H2O + light → C6H12O6 + 6 O2\n\ncarbon dioxide + water + light energy → glucose + oxygen + water
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Hello,\n\nIn this link you will have what you need:\n\nhttp://www.bsu.edu/web/fseec/pie/Lessons2/Physics/Potato%20Battery.doc\n\nI believe now will be OK.
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SCIENCTISTS:  Make an HYPOTHESIS (an educated guess...)/ then do EXPERIMENTS/ then formulate a THEORY!! (From a Science Professor!)  GLAD to help you with your Homework!
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http://www.uq.edu.au/_School_Science_Lessons/UNPh32.5.html#32.5.9.3
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here's a site with pics that might give you some ideas:\n\n\nhttp://www.physics.usyd.edu.au/competition/comp1998/comp98.html
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How about visiting this site:\n\nhttp://www.all-science-fair-projects.com/category0.html
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Here it is again folks, our educational system failure on parade!  This is 4th grade science. 24 hours is the answer.  Please donate your tax money to me rather than your local school system.
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X2O\n\nExamples:\nH2O => Water
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Here is a great site, made specially for teachers, that has many tutorials, plus links to others\n\nGood luck\nhttp://sciencepage.org/chem.htm
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1) this one is already balanced for you!!\n\n2)Count the number of Mg and O on the right side, and count the number of Mg and O on the right side.  On the left, you have 2 O and 1 Mg, and on the right you have 1 Mg and 1 O.  To make the oxygen on both sides equal, you need to double the MgO.  Now on the left, you have 2 O and 1 Mg, and on the right, you have 2Mg and 2 O.  Now you need to multiply the Mg by two so the Mg on both sides is equal.  and you're done!!!! \n2Mg + 02 --> 2MgO\n\n3) On the left, you have 1 Zn, 1H, and 1 Cl.  on the right you have 1 Zn, 2Cl and 2H.  the Zn are balanced and you just need to multply the HCl on the left to balance the whole equ.\nZn + 2HCl --->ZnCl2 + H2\n\n4) On the left, you have 1 P and 2O, and on the left you have 4 P and 10 O. If you multiply the P on the right by 4, and the O on the right by 10, you have 4P and 10 O on both sides\n4P + 5O2 ---->P4O10\n\n5)  On the left, you have 1 Fe 2 Cl, and pn the left, you have 1 Fe and 3 Cl.  The easiest way to balance this is multiply the Cl on the right by the amount of the left one and vice versa. when you do that, you have 1 Fe and 6Cl on the right, and you have 2Fe and 6Cl on the left. To finish the equation, multiply the Fe by two.\n2Fe + 3Cl2---->2FeCl3\n\nVoila!  You have balanced 5 equations!\n\ni hope this was helpful!
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This is too much work for my lazy buns.  Sorry but please just go find a science book or look it up in a library book section under tools.
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Check the Michaelis-Menten equation.It's too long to write it all down for you ;)
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After a simple google search I found a good website with all the info you need.\n\nFrom now on do your own homework!
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Interesting question for the science section
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I hope, the site "www.sciencedirect.com" will b much more helpful\n\ngud luck n tek care
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nitrogen, phosphorus, and potassium \n\nGood Luck :)