Please help with equation?
969755
Relax\n\n1)) (5x + 7) + (x - 2) = 5x + 7 + x - 2 = 5x + x + 7 - 2 = 6x + 5\n\n2)) 2 X length + 2 X height = perimeter\n\n  (2 X x) + (2 X (x - 3)) = per = 2x + (2x - 6) = cir = 2x + 2x - 6\n\n  perimeter = 4x - 6,   or 2 ( 2x - 3)\n\n3)) same as # 2;\n\n  2 X (t + 5) + 2 X 2t = 2t + 10 + 4t = 2t + 4t + 10 = 6t + 10 = per\n\n4)) (t - 5) - (3t - 1) = t - 5 - 3t + 1 = t - 3t - 5 + 1 = -2t -4\n\n  or -2 (t + 2)
426775
b = 2g - 10\ng = (b + 10)/2
417188
y=Asin(2x)+Bcos(2x)+(x/4)\n\nNow you get to determine why.
4935
ur second equation is wrong. \n2a is not equal to a-squared (which u symbolized by ab, since a=b).
60599
This is not an equation.  Its garbage.  Both side of the equation have to equal each other.\n-35=.000075 this does not compute
617282
are u sure its x2? shouldn't it be 2x+10x=(a number) usually there is a number at the end of the equation and u have 2 solve for "x". add details to ur question and then i may be able 2 help u.
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
853922
These are the right ones:\n\n2K(s) + 2H2O(l) ---> 2KOH(aq) + H2(g)\nH2SO4(aq) + 2KOH(aq) ---> K2SO4(aq) + 2H2O(l)\nCa(OH)2(aq) + 2HCl(aq) ---> CaCl2(aq) + 2H2O(l)
1155111
xsquare=x+x+x...x terms\nby diff x\n2x=1+1+1...x terms\n2x=x\n2=1
578331
Solution:\n\n2x*2-3x-14=0\n\nAnswer will be: (2x-7)(x+2)\n\nWhen you multiple these two equations together, you'll do the reverse to start out with your answer.
728397
You need to first balance the equation.\n\n2CO + O2 --> 2CO2\n\nUsing this you find the answer to be D.
550918
Type "=B1-C1+D1*A1" without the quotes inside another cell such as E1.  This is assuming that your equation is the correct algebraic form and solved for one variable.  Your text is a bit jumbled so I didn't parse all of it.
250429
the answer for the line eqwuation  is \n\nY= m(x)+c;\ny=(y2-y1)/(x2-x1)(x)+c;\n\nx1,y1 be the first coordinate and \nx2,y2 be the second coordinate.\n\nm is slope of the Equation.\nc is the Constant \n\nx,y  is  first cordinate value s or seconde cordinate values..\n\n\n\nBaalu..?
984409
The goal here is to find the equation with x on one side and everything else on the other.  It's like the equation you have, but instead of y= you want x=.  So you need to "solve for x."  Think of y as just a number, and you need to find what x =.\n\nStep by step:\n\ny=4x+4\n\nSubtract 4 from each side:\n\ny-4=4x\n\nDivide both sides by 4\n\n(y-4)/4=x\n\nx=(y-4)/4\n\nThere's your equation!  Hope this helps.
1017997
The equations are wrongor insufficient. Post the correct data if you want me to help/ Alternately, you could also message me.
893931
m = 2\n\nb = -1\nso just substitute               these values in your equation\n\ny = mx + b\nthen you'll have\n\ny = 2x -1
891679
I assume your x is in the denominator, but the -c is not.\n\nOriginal equation:\na / (bx) - c = 0\n\nAdd c to both sides:\na / (bx) = c\n\nMultiply both sides by bx:\na = cbx\n\nDivide both sides by bc:\na / (bc) = x\n\nx = a / (bc)