please help with math?
958043
Edited: With the new information.\nLet x be the width and y be the length required. \n\nThen we have the equations  \n                                 xy = 150.................a\n                              x + 2y = 35..............b\nThen,         y = (35-x)/2                 (ans to i)\n\nSubstituting in equation a,\n                              x(35-x)/2 = 150             (ans to ii and iii)\n               or          x^2 -35x +300= 0\n               or      (x-15)(x-20) = 0\nSolving, x = 15 or 20 and correspondingly, y = 10 or 7.5  (iv)\n\nthis is the case when ALL of 35 meters of fencing is used. we can use LESS than 35 meters too.\n\nNow, in this case,      xy = 150\n          and              2y + x < 35\nSubstituting for y,\n            2 * 150 /x + x <  35\nor x^2 - 35x +300 <0\nor   (x - 35/2) ^2   < 25/4............c\n\nnow if x > 35/2, inequation c becomes (on taking square roots)\n                                 x - 35/2 < 5/2\n or   x < 20\n\nif x < 35/2  c becomes    - (x - 35/2) < 5/2\nor                                     x > 15\n\nTherefore the restriction is 15 < x < 20\n and    7.5 < y < 10                (ans to v)
1162372
120\nx.25\n------\n3000\n\n~~move decemal point over two places so the answer is 30.00 or can be written 30~~
851464
that is a really simple question, so if you have a calculator you should be able to get it, otherwise, it is your homework and I refuse to give you an answer to your homework. I would actually HELP you to get the answer if you asked for HELP doing it.\n\n-EA
474972
I agree with Mike, do your math homework.  Everyone would love to hang around someone who knows how to do math.
873100
Here you go!\n\nhttp://www.math.com/homeworkhelp/Algebra.html
107813
Is this really a math question???\nP.S. I don't know.
323178
What would you like to know?\n\nTry here for whatever it is...\nhttp://www.math.com/homeworkhelp/HotSubjects_decimals.html
777951
Tackling the problem bit-by-bit:\n\nFirst, let x = the larger number\nlet y = the smaller number\n\nYou can write out an equation to show their relationship of "difference" by:\nx - y = 68\n\nNext, you write out the equation to show their quotient relationship by:\nx/y = 5\nwhich gives:\nx = 5y\n\nNow plug x = 5y into the "difference" equation:\n(5y) - y = 68\nwhich gives\n4y = 68\nwhich gives \ny = 17\n\nNow plug y = 17 into the "difference" equation:\nx - 17 = 68\nx = 85
896136
try http://www.webmath.com/\nit gives you help on math on almost any time of math.
520168
Try this:\n\nhttp://www.algebra.com/
286845
don't know the answer,\nbut GOOD LUCK :)
515516
goto purple math.com it will hopefully help you
950092
Do a Yahoo search.  Enter "Homework help, math."  There are bunches of web sites.  Good luck.
959479
all you need to do is go to www.webmath.com, it'll help u there!\n\nI always do my math problems to that site if ever i get stuck on something! It's helpful!
538653
Just put each number in for x and see what the answer is.  Example : -11/2 + 75 = -5.5 + 75 = $69.50 a unit.
398683
Use log you will find\n\nor put\n\nx=3.597285024\n\nIts done
1168806
Do your own math homework...