Which is better for an emergency kit; an L.E.D flashlight or a Xenon Bulb flashlight?
957566
An L.E.D. light can run 200 hrs on a set of batteries, but isn't terribly bright.\nA Xenon lamp is Extremely bright, but kills batteries fast.\n\nYou can get either one for ten bucks or so. play it safe...\nGet them both.
604975
try looking for a halo bsince they are really good and dont chop paintballs\nif not go with a gravity feed.  the middle electeronic ones will chop up your ammo
547995
This is completely dependant on the atomic structure of the source filament. Once at capacity, the atoms will only give off photonic energy at a specific rate that is inherant to that specific type of atom. Most household filaments are designed to handle standard electrical current,without being at full capacity (atomically).\n\nSo in a standard household bulb, it will release more photonic energy and appear brighter.\n\nIf it is already operating at max capacity (atomically)\nthen there will be no change to the appearance of the bulb, because the atoms are already filled and giving off photons as fast as possible.
986691
Voltage doesn't really matter. This is the only reason people can survive lightening strikes.\n\nIts the Amperage (amps) behind the volts that ultimately decide whether your insides are cooked or not.
441999
That depends on the intensity of the laser, and whether you are aiming it from the earth surface or from a satellite outside the earth's atmosphere. Any beam, laser or flashlight, diverges from its source, and becomes lower in luminence with distance. A laser does not decrease by the inverse square, in the main advantage.
479824
I guess 'moonlight' might be nice for security... tech explaination follows:\n\nThe lux (symbol: lx) is the SI unit of illuminance. It is used in photometry as a measure of the perceived intensity of light. In English, "lux" is used in both singular and plural[1].\nOne lux is equal to one lumen per square metre.\nIlluminance Abbr.   Example\n0.00005 lux or 50 µlx  Starlight\n           1 lux    Moonlight\n400 lux  A brightly lit office\n400 lux  Sunrise or sunset on a clear day.\n1000 lux or 1 klx  Typical TV studio lighting\n1000 lux or 1 klx  Approximate minimum level required to reset the biological clock in humans\n32000 lux or 32 klx  Sunlight on an average day (min.)\n100000 lux or 100 klx  Sunlight on an average day (max.)\n\nLux versus lumen\n\nThe difference between the lux and the lumen is that the lux takes into account the area over which the luminous flux is spread. 1000 lumens, concentrated into an area of one square metre, lights up that square metre with an illuminance of 1000 lux. The same 1000 lumens, spread out over ten square metres, produces a dimmer illuminance of only 100 lux.\nAchieving an illuminance of 500 lux might be possible in a home kitchen with a single fluorescent light fixture with an output of 12000 lumens. To light a factory floor with dozens of times the area of the kitchen would require dozens of such fixtures. Thus, lighting a larger area with the same number of lux requires a larger number of lumens.\n\nRelationship between illuminance and power\n\nIlluminance is not a direct measure of the energy of light, but rather of the illumination it provides as perceived by the human eye. Thus, the conversion factor varies with the wavelength composition or color temperature of light. At 555 nm, the middle of the visible spectrum, one lux is equal to 1.46 mW/m².
928582
A change in color would indicate some sort of reaction.  xenon is a noble gas and is nonreactive, so no.
958515
You can try the following web sites:\n\nhttp://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/light/u12l1e.html\n\nhttp://www.uwgb.edu/dutchs/petrolgy/genlight.htm
883981
If you really want to be technical about this then here you go:\n\nHere are the three main consideration you have to follow when making a flashlight:\n\n1.) Amount of current the bulb will draw:\nI standby this clearly to show that current draw will affect the size of the wire that you will use to power up the bulb.  If your bulb draws lots of current from the source, then you will want to use a bigger wire.\n\n2.) Safe wire colors\nSecondly you have to consider safety standards as well.  You can't simply start to wire up the flash light and put the red wire on the negative end of the battery / power source.   You can possibly confuse someone, if they intend to repair it. \nThus in DC CIRCUITS ONLY\nRed = Positive Voltage w/ respect to GND\nBlack = Ground
932202
Edmunds Scientific\n--> http://scientificsonline.com/search.asp?t=ss&ss=strobe
928685
An electric INCANDSCENT bulb uses a tungstene filament (twisted wire) that is heated by the current passing through to several hundred degrees.  It is this heat that heats the glass.  It is also the proof of inefficiency of the bulb, because it is transforming 80% of the energy it receives into heat, giving only 20% for light!\nIn the FLUORESCENT tubes, the light is produced by the ionisation of the internal gas (neon or argon).  This ionisation is initiated by heating two small filaments at teach end of the tube, that heat up a small drop of mercury.  Once the mercury is vaporised inside the tube, the "starter" opens, creating a high voltage puls across the whole tube, ionising the gas that then becomes conductor: a small current passes through the gas, and the filaments are disconnected.  Since the ionised and conductive gas has nearly no resistance, the current is limited by the "ballast" (an inductor inserted in series).\nSince the CURRENT is limited, there is no "Joule Effect" (heating) and the tube stays pretty cool.\nTheir efficiency is about 100 times more than a bulb... (in terms of power/light ratio).
751079
a light that makes you glow in the dark, buy it at any hardware store\n\n:> peace\n.
971014
It isn't particularly important, except for making neon signs.  Krypton is also sometimes used for filling the space between panes of double-pane glass.  Xenon, which is rarer, is more important because it is used for making flash tubes and the new HID headlights.
56171
1.First of all it is cheaper then the standard  lightbulb. I use it all the time instead of the standard filament bulbs that use the wire to heat up. \n\n2. It uses your power (electricity) to move Mercury vapor in argon or neon.\n\n3.  Did you know that that type of light does not stay on steady? It makes many many  blinks too fast for your eye to catch. I tried experimenting with using  a "fan". Only way to fully see the  blinks very well is when it is reaching end of its life.\n\n4. A modified version you could use to grow  plants. But it is not your standard "flourescent" light.\n\nYou could try (likely) to check howstuffworks because if I would explain would run out of space.\n\nWord of caution as always: Never attempt to open one flourescent up it will explode. It will release  Gas and could be more dangerous if you  break it near yourself then a standard  bulb!\n\nI LOVE IT we have brains on Q /A today!  Now  that could be used on the message boards too.
1059851
The fact that no oxygen is present in a light bulb protects it
921578
120W would be brighter, and here is why:\n120W light bulb would have higher temperature (rough argument: dQ/dt= c*m-sigma*T^4, at equalibrium c*m = sigma*T^4 =P =V*I, where c= heat capacity per mass), and by Planck's law of black-body radiation will emitt more visible light than Infra Red light, so it's more efficient in producing visble light for the same energy than 2x 60W light bulbs. Great question.
975896
Energy is measured in watts, so I assume you mean a voltage source of 200v.\n\n(1)\nThe voltage source of 200v applied to the light bulb (laminar) will be 200v.  Since the light bulb is designed for 130v, the supply voltage will likely blow the bulb.\n\n(2)\nHere you have two possibilities, depending on your circuit.\n(a) If you have a parallel circuit, then each light bulb will have 200v across it, and again the bulbs will likely blow because the voltage is to high.\n(b) If you have a series circuit, the voltage across the light bulbs will be subject to their resistance.  Assuming the resistance is the same, then the voltage will be the same, that is, 100v each.\nThe voltage across each light bulb will be equally proportional to it's resistance ratio.