m+(m+3)=(m-2)-(m-1)                PLEASE HELP!!!?
962594
you sure you have this problem right ???????\n\nhere's what i came up with\n\nm + ( m + 3 ) = ( m - 2 ) - ( m - 1 ) \nthis is wrong \n\nm + ( m + 3 ) = 2m + 3\n\n( m - 2 ) - ( m - 1 ) \n\n= ( m - 2 ) ( m + 12 ) \n\n= m^2  + 1m - 2m  + 2 \n\n= m^2 - 1m + 2
972642
(A^2+2ab+b^2)/(a+b) + (a^2-b^2)/(a-b) + (a-b)/(a+b)/(a^2-b^2)/a+b)\n(a+b)^2/(a+b)+(a+b)(a-b)/(a-b)+ (a-b)/(a+b)*(a+b)/(a^2-b^2)\na+b+a+b+(a-b)/((a+b)(a-b))\n2a+2b+1/(a-b)\n\nif I got all the ( ) in the right places.
955620
2x+2y+3z=-1 .....(1)\n3x-1y-2z=18 .......(2)\n-3x+1y-1z=-9 ......(3)\n\n(1)+(2)x2\n2x+2y+3z=-1\n6x-2y-4z=36\n-------------------+\n8x-z=35 .............(4)\n\n(2)+(3)\n3x-1y-2z=18\n-3x+1y-1z=-9\n---------------------+\n-3z=9\nz=-3\n\nsubstitute this value of z to (4)\n8x-z=35\n8x-(-3)=35\n8x+3=35\n8x=32\nx=4\n\nsubstitute the value of x and z to (1)\n2x+2y+3z=-1\n2(4)+2y+3(-3)=-1\n8+2y-9=-1\n2y-1=-1\n2y=0\ny=0\n\n(x,y,z)=(4,0,-3)\n\nhope this is clear enough
1072878
m=3/5\ny=3/5x+b\norigion (0,0)\n0=(3/5)(0)+b\n0=0+b b=0\n\ny=(3/5)x
469080
1.(b+1)(b+6)=0           2.(m+3)(m+7)=0\n   (b+1)=) or (b+6)=0       (m+3) =0 or (M+7)=0\n    b=-1 or b=-6             m=-3   or  m=-7\n\n3.(n+1)(n-4)=0           4.(a-2)(a+4)=0\n   (n+1)=0 or (n-4)=0       a=2 or a =-4\n    n=-1  or n=4\n\n5.(a-2)(a+5)=0            6.(b-1)(b+8)=0\n   a=2  or a=-5              b=1 or b=-8\n\n7. (y-3)(y+9)=27          8. (m-1)(m-5)=0\n   y=3 or y=-9                m=1 or m=5\n\nnext time I'll give answer for the first three,the rest try it yourself or else you won't learn!!!!\n\nOKAY?
747340
-2x-x > -6 + 4\n-3x > -2 \nx < 2/3
38332
(x-2)/(x^2-2x-15)+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(-2-x)(x+3)/(x-5)(x+3)\n\n[(x-2) + (x+3)(-2-x)] / [(x+3)(x-5)]\n\nANSWER :\n(x^2+4x+8)/((x+3)(5-x))
858135
m = (9-(-1))/(-2-3) = 10/-5 = -2\n\n-1 = -2(3) + b\nb = -1 + 6\nb = 5\n\n\nf(x)= -2x + 5\n\n\nYou got the slope sign reversed.  Be careful about that.  Otherwise, it's correct!
854360
S=(c-b)/(b-a)\nSb-Sa-c+b=0\nc=Sb-Sa+b\nc=S(b-a)+b\nHowever you like it.
1019688
(x - 2)*3 = 6 + x\n\n3x - 6 = 6 + x\n\n2x = 12\n\nx = 6
554172
Um...\n\n2(-X) + 3(-X) + X + 8\n\n-2X - 3X + X + 8\n\n-5X + X + 8\n\n-4X + 8\n\n8 - 4X
1054627
assuming this is (3a+1)/(a^2-1) - 1/(a+1)\n\nfactorise the (a^2-1) to give (a+1)(a-1)\n\nmultiply the second fraction by (a-1)\n\n-->  (3a+1)/[(a+1)(a-1)] - 1(a-1)/[(a+1)(a-1)]\n\nfactorising this gives [(3a+1)-(a-1)]/[(a+1)(a-1)]\n\nwhich equals (2a+2)/[(a+1)(a-1)]\n\n= [2(a+1)]/[(a+1)(a-1)] \n\nthe (a+1)'s cancel out...\n\ntherefore = 2/(a-1)
818236
m= -2\ny=mx+b\n5= -2(2)+b\n5= -4+b\nb=9\ny= -2x+9
928756
m^6-n^6=(m^3+n^3)(m^3-n^3)\n(m^2-n^2)(m^4+m^2n^2+n^4)\nm^4-n^4=(m^2+n^2)(m^2-n^2)\nplugging in\nm^6-n^6/m^4-n^4\n=(m^4+m^2n^2+n^4)/(m^2+n^2)
119559
its (x+2)(3x+1) now thats rite lol
705864
Alright, don't listen to the above post...\n\nGrade 12 here, answering questions all day for mere fun.\n\n12)\ny - 3 = -1/3 (x + 4)\n\nEXPLAINED\n\nadd 3 to both sides\ny = -1/3 (x + 4) + 3\n\nexpand 1/3(x + 4) \n= x * 1/3 + 4 * -1/3\n= x/3 + 4/3\ny = -1/3x - 4/3 + 3\n\nTo add -4/3 and 3, use 3 = 9/3\ny = -1/3x - 4/3 + 9/3\ny = -1/3x + 5/3\n\nTrue, my bad. I originally added 4/3 instread of -4/3\n\n\n16)\n(-2, -1) (4, -4)\n\nm = Dy / Dx\nm = ((-1) - (-4)) / ((-2) - (4))\nm = 3 / -6\nm = -1/2\n\ny = mx + b\n(-1) = -1/2(-2) + b\n-1 = 1 + b\n-1 - 1 = b\n-2 = b\n\ny = -1/2x - 2\n\nCHECK\ny = -1/2(4) - 2\ny = -2 - 2\ny = -4\nTherefore it works.\n\n18)\n(0, 0) (2, 3)\n\nm = Dy / Dx\nm = ((3) - (0)) / ((2) - (0))\nm = 3/2\n\nb = 0\n\ny = mx + b\ny = (3/2)x + 0\ny = (3/2)x\n\nNote, the lower post copied my answers
733649
(4)/(x+7) + (x+3)/(x+7)\n=(4 + (x+3))/(x+7)\n=(4 + x + 3)/(x+7)\n=( x +7)/(x+7)\n=1