Express the function of the complementary angle, sine 30°15'?
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sine 30° 15'\n\nCos ( 90 - A)\n\n89 60\n30 15\n- - - - -\n\n59 45\n\nThe answer is cos 59° 45'\n\n- - - - - - - -s-
951198
^ Parasite alert LOL! ^\n\n30 s for C to move from A to B, maybe? I'll assume that. Also, x seems to be a length, not an angle. Maybe a) is asking for the rate of change of z (called z')? We know the angular rate of C about O (y') is pi/30 (answer to b)), and triangle CAO is isosceles, so z'=-0.5*pi/30. \nFor c), circumferential velocity is pi*r/30. Angle CAO is, conveniently, 45 deg, so x' = sqrt(0.5)*circumferential velocity.\nFor d), the area of triangle OAC is .5*AO*altitude, and altitude=r*sin(y). This is a maximum when y (not x) =pi/2.\nSorry, I know you wanted  no answers, but I couldn't see how/where to stop short of most of the answers.
132715
Formula for Sine, Cosine and Tangent:\nTangent= opp./adj.\nSine= opp./hyp.\nCosine= adj./hyp
835259
I'll give you a hint and let you try to figure out the rest yourself (unless someone else tells you the exact answer). =)\n\nUse your trig identities:\n\ntan A = sinA/cosA\n\ncot A = 1/tanA or cot A = cosA/sinA
943973
Tangent 25° 56' 30" = cot (90 - A)\n\n89 59 60\n25 56 30\n- - - - - - -\n\n64 3 30\n\nCotangent 64 degrees 3 minutes 30 seconds\n\nThe answer is. The complemenary angle of tangent 25° 56' 30" is cotangent  64° 3' 30 "\n\n- - - - - - - - - - - -s-
367687
an angle that is inside a circle or any other figure
756724
The first quadrant angle x whose sine is 1/2 is 60 degrees.\n\nThis angle has cosine of sqrt(3)/2.\n\nAnother way that we can do this is to remember that:\n[sin(x)]^2 + [cos(x)]^2 = 1 for all x.\n\n(1/2)^2 + [cos(x)]^2 = 1\n[cos(x)]^2 = 3/4\n[cos(x)] = sqrt(3/4) = sqrt(3)/2
507417
r/SinR = s/SinS\nSinS = 24*(Sin(38)/20) = 0.73879....\nAngle S = Sin^-1 (0.73879.... = 47.628 degrees\nAngle T = (180-(38+47.628))94.372\nUse same procedure to find side t.
611398
The ratios of the indices of refraction will be the same as the ratio of the sin of the angles.\n\nsin(32)/sin(27) = x/1.61
299283
first draw a right triangle and label the angles and sides. now angle B cut in half is 15 degrees and angle A is 90 degrees.  lets assign AM a value of x.  so the tangent function is equal to the opposite leg over ajacent leg=> tan(15degrees)=x/(2*sqrt(3)).  take the tan of 15 and then multiply that by 2*sqrt of 3 and that will be your answer for the length of AM which is approx=.9282  to find MC you must first find the length of AC with the same tangent function using 30degrees as your angle so lets assign AC a value of y. so tan(30degrees)=y/(2*sqrt(3)) which is = 2 so MC=AC-AM= 1.0718
765813
There's a pretty good online grapher at http://id.mind.net/~zona/ezGraph/ezGraph.html that you can use.  It works basically like a graphing calculator.\n\nIt appears this function should be an upside-down sign curve with an amplitude of 10 and a vertical shift of 9, which means the center of the graph will be at 9, it will go up to 19 and down to -1.  It's not 100% clear what you mean by what you have written after sin.  If you mean the sine of 2pi/15 times x (since the minus zero is irrelevent), you would have a period of 15, so you'd complete 1 complete cycle at 15 radians; the halfway point would be 7.5 radians.
701201
Since there are four quadrant that make up the 360degrees. Draw the two axis x and y. Assume the top right part as quadrant 1, top left part as quadrant 2, bottom left as 3 and bottom right as 4. Now the calculation of angle starts from quadrant 1 in anticlockwise direction to make an angle of 360degrees. Now use "ASTC" rule i.e. assign 'A' to quadrant 1, 'S' to quadrant 2, 'T' to 3 and 'C to 4. \n\n'A' states that in this quadrant all i.e. sin, cos and tan have positive values.\n\n'S' states that in this quadrant sin have positive value and cos and tan have negative values.\n\n'T' states that in this quadrant tan have positive value and cos and sin have negative values.\n\n'C' states that in this quadrant cos have positive value and sin and tan have negative values.\n\nthat's it simple enough.
509207
Yes. You can use sine or cosine to determine the angle.\n\nSine x = Opposite / Hypotonuse\nSin x=5/13\nSin x=.38\nx=22.6*\n\nCosine x = Adjacent / Hypotonuse\nCos x=12/13\nCos x=.92\nx=22.6*
706305
R^2=A^2+B^2 -2(A*B)cos(180-acute angle)
830426
The crux of this problem is for you to realize that the given angles are "complementary pairs", which add up to 90 degrees.\n\nYou are expected to know that the "co-function" of angle A gives the same value as the "function" of angle A's complement.\n\nSpecifically:\n\n cos(A) = sin(90-A)\n\nA graphical way of looking at this statement is that "cosine and sine are the same function, but offset by 90 degrees!"  We call that "out of phase by pi/2 or 90 degrees."\n\nThe same works for tangent and its co-function:\n\n tan(A) = cot(90-A)\n\nSo the answer to the second problem is 0.\n\nIf one of the fuctions in the first problem had been sin, the quotient would have been 1.  However, that's not the case, and I leave the upper problem as an exercise for another Answerer.\n\n Hope this helps!
1093073
A = 45 degrees or (pi / 4) radians\n\n1/sin^2A-1/cos^2A-1/tan^2A-1/cot^2A-1/sec^2A-1/csc^2A = -3\nIf i understand the way you wrote the problem above, it's 1/ each term, subtract each other right?\n1/ ((sinA)^2) - 1/ ((cosA)^2) - 1/ ((tanA)^2) - 1/ ((cotA)^2) - 1/ ((secA)^2) - 1/ ((cscA)^2) = -3\nI'm going to drop the A part, i assume you know that it will still be officially added in the final version\n\n[1/ (sin^2)] + [(-1)/ (cos^2)] + [-(cot^2)] + [-(tan^2)] + [-(cos^2)] +  [-(sin^2)] = -3\n[1/ (sin^2)] + [(-1)/ (cos^2)] + [-(cos^2) / (sin^2)] + [-(sin^2) / (cos^2)] + [-(cos^2) - (sin^2)] = -3\ncombine denominators\n[( 1 - (cos^2) ) / (sin^2)] + [( (-1) - (sin^2) ) / (cos^2)] + (-1) [(cos^2) + (sin^2)] = -3\n[(sin^2) / (sin^2)] + (-1)[( 1 + (sin^2) ) / (cos^2)] + (-1) [ 1 ] = -3\nTrig identity [(cos^2) + (sin^2)] = 1\n[ 1 ] + (-1)[( 1 + (sin^2) ) / (cos^2)] + [ -1 ] = -3\n(-1)[( 1 + (sin^2) ) / (cos^2)] = -3\n[( 1 + (sin^2) ) / (cos^2)] = +3\n1 + (sin^2) = 3 * (cos^2)\nTrig identity 1 = [(sin^2) + (cos^2)] =\n[(sin^2) + (cos^2)] + (sin^2) = 3 * (cos^2)\n2 * (sin^2) = 2 * (cos^2)\nsin^2 = cos^2\nsinA = cosA\nA= 45 degrees of (pi/4) radians
984494
sine opposite/hypotenuse\ncosine adjacent/hypotenuse\ntangent opposite/adjacent