write lewis structure that obey the octet rule for the following species?
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http://www.stolaf.edu/depts/chemistry/courses/toolkits/123/js/lewis/\n\nI agree it is too hard for us to draw lewis structures in a forum like this. What helped me learn lewis structures is by practicing them on sites like these. If you follow each step you can do lewis structures for anything.
317042
www.chemfinder.com might help
771965
I can't tell you the name because i can't remember that stuff but the product will be K(NO3) PbI2\nif you're writing it in the long form it will be\n2KI + Pb(NO3)2 yeilds (arrow) 2K(NO3) + PbI2
855087
Ca2+=[Ar]\nMg2+=[Ne]\nI-=[Xe]\nF-=[Ne]
749646
Try doing a Google search under the Hall or the Hall-Heroult process.    That or check out a General or an Inorganic Chemistry book from the library.  That's a good launch point.
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Look up the site chemfinder.com.  its a good website if you have not heard of it already.
910312
okay. i just took the test on this and passed with a B. so i promise i know what im doing.\n\nK, look at your elements. then look them up on the periodic table. lets pick, oh say the compout Cl(subscript)2O. that is 2 chlorines, and 1 oxygen. well, chlorine is in group 17, which means that each have 7 valence electrons, and oxygen is in group 16, which means that it has 6 valence electrons. following me so far? okay, take those valence electrons, and add them up. that equals 20 valence electrons. now, position the lewis dot diagram so that the oxygen is between the two chlorines. now, distribute the 20 electrons amongst the three letters, so that each has eight. now each letter should be surrounded by exactly eight dots. keep in mind that it should look like this -- :Cl:O:Cl:, but dots on the tops and bottoms. that is the lewis dot. luckily, this one did NOT have double or triple bondage. but in the event of double bondage, it might look like this -- :Cl::O:Cl, without dots all the way around each letter.\n\nand the VSEPR theoryis quite simple. it is just talking about the potential shapes that chemicals can make. for example, there is linear, or trigonal planar, or tetrahedral. this is vital. i promise that, if you contact me, i can give you a simple cheat sheet (not really for cheating, but it helps your memorization) to remember VSEPR. it gives you the shapes, lewis dot examples for the shapes, and angle measurements.\n\nhope this helps!\n~ally
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just a few of the web resources available for lewis dot structures, although I personally can vouch for none of them. Lewis dot structures (aka electron dot diagrams) are best explained in person by another student who has a good solid grasp of the concept, a tutor, or your instructor. The only way to really get the hang of them is to draw a lot of them. :-)
760405
well family 13 has B and Al.  they are metaloids that are great lewis acids.  they have interesting bonding strategies that defy the normal octet rule.
381120
look it up on any periodic table - like the one linked below... good luck!
85238
Step 1: Draw the Lewis structure.\nStep 2: count the number of double bonds.\nStep 3: count the number of triple bonds.\nStep 4: total up number of pi bonds from steps 2 and 3.\n\nThere is 1 pi bond for every double bond and 2 pi bonds for every triple bond.
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First you should draw the Lewis structure.\n\nBr\n|\nC=O\n|\nBr\n\nThere are 3 lone pairs of electrons on each bromine and two lone pairs on the oxygen.\n\nVSEPR tells us that the molecule is trigonal planar and the oxygen is a bit more electronegative than the bromine, therefore this molecule is polar.\n\nTake care,\nDavid Roth
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Tetrahedral arrangement at the methyl carbon. (4 bonding pairs, no lone pairs)\nTrigonal planar arrangement at the carbonyl carbon. (3 bonding pairs, no lone pairs)\nBent arrangement at the single-bonded oxygen. (2 bonding pairs, 2 lone pairs)
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Four as a stable compound, up to 5 or 6 for a polyatomic ion.
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The formula in the above answer is incorrect since it omits the aromatic ring and the 9 subsequent repeating units (it's not 9 repeating -OH groups, that makes no sense).\n\nThe empirical formula by my calculations seems to be: C33 H60 O10
401509
I don't know that question.\n\nI can tell you that it's an octahedral complex. The two isomers would be CIS (Both chlorides adjacent to each other) and TRANS (both chlorines opposite each other)
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go to\nwww.chemistry.com