How do you solve for L in the equation P=2(L=W)?
963947
assuming you meant:\nP=2(L-W)\nthen\nP/2 = L-W\nand so\nL= W+ P/2\n[
164837
Perimeter = (2*L) + (2*W)\nArea = L*W\n\nFor example, if P=30 and A=50, L could be 5 and W could be 10.\n\nBut this might also work...\n\n((2*L) + (2*W))/Perimeter = 1 = (L*W)/Area\n\nFrom there, you can multiply both sides by the area (and/)or the perimeter to eliminate one of the fractions.  Just massage the numbers around a bit until the answer jumps out at you.
778162
Step 1: find y '\nStep 2: fill in x=1\nThat gives the right answer 2\n\nTh
928253
w² = 16w\nSo w² - 16w = 0\nSo w(w - 16) = 0\nSo either w = 0 or w - 16 = 0\nTherefore w = 0, 16
757630
h=w+7\nl=3w-5\n\nh+w+l = w+7+w+3w-5 = 5w+2\n\nSo the correct answer is C.
826268
2l + 2w = 300\n2l = 300 - 2w\nl = 150 - w\n\nMaximize length times width:\n\nA(w) = w(150 - w) = 150w - w²\n\nTo maximize, take derivative, set = 0, and solve for w.\n\n150 - 2w = 0\n2w = 150\nw = 75\n\nand then l = 150 - 75 = 75.
1080496
lwh = 162\nl = 2w\nh = 3w\n\n2*3*w*w*w = 162\n6(w^3) = 162\nw^3 = 27\nw = 3\n\ntherefore, w = 3, l = 6 and h = 9
909202
a= r * w^2 = .12 * 2^2 = .12 *4 = .48 m/s^2
1057756
lets say length= L\nwidth=W\nperimeter=P=22=2L+2W\nL=W+7\n\n22=2(W+7)+2W\n22=4W+14\n8=4W\n2=W\n9=L
688339
Let's say w is the width of the rectangle.  Then, the length will be w+5.  We know the perimeter is 58, and we know that the rectangle has two sides of length w, and two sides of length (w+5).  So...\n\n2w + 2(w+5)=58\n2w + 2w + 10 = 58\n4w + 10 = 58\n4w = 58 - 10\nw = (58-10)/4\nw=48/4\nw=12, the width of the rectangle.\n\nSince the length=w+5, the length is 17.
510279
Jimbo, you gave up too soon......\n\nV = L*W*H = L*W*x in this problem\n\nV = (6-2x)*(4-2x)*x\n\nV  oila!
50664
ln(e) = 1 is a basic rule\nwhen you have ln(x^y)\nyou can rewrite it as yln(x)\nso for that specific problem bring the 4 to the front to make 2*4*ln(e)\nthen ln(e)=1\nso 2*4*1 = 8
1187393
SA = 2lw + 2lh + 2wh\n= 2(lw+lh+wh)\n= 2(8*6 + 8*2 + 6*2)\n= 2(48+16+12)\n= 2(76)\n= 152 centimeters squared
898070
ln(x) + 2ln(4) = ln(7) - ln(x)\nln(x) + ln(4^2) = ln(7) - ln(x)\nln(x*4^2) = ln(7/x)\nln(16x) = ln(7/x)\n16x = 7/x\n16x^2 = 7\nx^2 = 7/16\nx = sqrt(7/16)\nx = sqrt(7)/4
868234
P = 2W + 2L\nReplace W with 10 and L with 19\nP = 2(10) + 2(19)\nP = 20 + 38\nP = 58 in
738486
8w-18 = 12w +14\n    +18           +18    add 18 on both sides\n\n    8w=12w + 32\n-12w   -12w          subtract 12w on both sides\n\n  -4w=32             solve for w\n   /-4    /-4\n\n   w= -8
816989
2 * (l + w) = perimeter of rectangle\nl * w       = area of rectangle\nPerimeter of rectangle = Area in sqr units\n=> 2 * (l +w) = l * w\n=> 2*l + 2*w = l*w\n=> 18 + 2 * (x+1) = 9 * ( x +1 ) since l = 9 and w = x + 1\n=> 18 + 2x + 2 = 9x +9\n=>  11 = 7x\nHence x = 11/7