i get 980 Nm in a second! how much is the ampere, volt, watt & ohms?
966388
a Nm (Newton-meters) is a J(oule)\n...\n> Message: I know Nm is joules and joules per\n> second is watts. \n\nCorrect.\n\n> But how do i know the ampere, volt and ohms?\n\namps = Watts/volts\nvolts = Watts/amps\n\nvolts = ohms * amps \n(ohms law)
752320
10 micron.  no need to give long detailed answer to a simple question!!
924435
1 Find the current flowing in the lamp.   P  = VI\n2 Look up the charge on an electron.     q\n\nDivide 1  by 2  which will give you the number of electrons flowing per second.      n  =  I/q
713107
range/amount\n\nrange = 120 mV (90mv - (-30mV))\namount = 2^16 = 64*1024\n\nplug-n-chug
533465
V=IR so R=V/I so R=120/2.5 = 48 ohms
873132
What sort of prints? What sort of current do you want to source? How few milliviolts do you want?
609875
first of all, 120/240 are standard voltages for AC power, not DC.  DC comes in all flavors.\n\nanyway: 2500 kilowatts DC?\n\nthat is 2.5 MEGAwatts.  \n\ni find this somehow hard to swallow.  when i worked at a particle accelerator there was ONE really big DC power supply that put out something like 1.5 megawatts.  it was the size of a small apartment, and required massive amounts of water cooling, was entirely custom built, and probably cost something on the order of a million dollars or more.\n\ni don't think there is any such thing as "usual" for a 2.5 megawatt power supply.  think about it - you're talking about nearly the power consumption of a small town.  anything liek that would have to be custom built.\n\n----\n\nok, having seen your additional details:\n\ni'm quite positive it's AC, not DC.  it also probably depends on what kind of generator it is.  to give you a rough estimate, here's an example of a 11.5MW turbodiesel generator on a cruise ship:\nhttp://www.ship-technology.com/projects/destiny/\nnote the output is at 6.6kV.  that would set the current at the output at around 1.8 amperes.  \n\nhere's some more information.  as you can see there is no real "usual".  \nhttp://www.ship-technology.com/contractors/electrical/abb2/\n\ncheers!
698462
ok, you have the frequency and what you want is hte wavelength. You need this equation. The wavelength multipled by the frequency gives you the speed of light. (2.9979x10^8) \n\nThis will give you the answer and if you want to convert from m to nm, you have to know that the relationship is 10^9. There are 10^9 nm in one meter.
81594
Use ohm's law (I=E/R); 2 AAs are 2.4 to ~3 volts depending on battery type, so 0.4 to 0.5 A.\nHOWEVER, if you measured the bulb's resistance cold, it will be higher when hot, so it will draw less current.
92081
at uniform voltage  \n\nConverting Watts to Amps\n-----------------------------------------\nThe conversion of Watts to Amps is governed by the equation Amps = Watts/Volts\n\nFor example 12 watts/12 volts = 1 amp\n-----------------------------------------\n\nConverting Amps to Watts\n\nThe conversion of Amps to Watts is governed by the equation Watts = Amps x Volts\n\nFor example 1 amp * 115 volts = 115 watts\n--------------------------------------------\n\nfind out how many Amps your monitor needs (see power supply if it has a seperate one.) multiply by 115 or 120 to get the wattage....and that would be how many watt-hrs your monitor uses.
222542
Ignore the guy above the answe ris obviously 37.5 microns
1130014
V=IR\n\nWire 1:\n50 = 2 * R1 => R1 is 25 ohms\nCurrent = 2 amps\npower = V*I = 2*50 = 100 watts\n\nWire 2: \n100= 2* R2 => R2 = 50 ohms\nCurrent=2amps\npower = V*I = 100*2 = 200 watts\n\nare you looking for ratios when you say "compare" ?\nif yes: ratio of resistances is  1:2\nratio of currents is 1:1\nand ratio of power is 1:2
100752
There are two relavent formulas,\nOhms Law: V = R*I\nwhere V is the voltage, R is the resistance, and I is the current.  Also,\nPower = V*I\n\nIf we know that power is 150 watts, then,\n150 = V * I,\nbut what is the current (I)?\n\nWe know the resistance is 95 ohms,\nV = 95*I --> I = V / 95\nSo plugging back into the power equation,\nP = V^2 / R \n150 = V^2 / 95 --> V = sqrt(150 * 95)\nso V = 119.4 volts --> 120 volts
69351
My "amp" has 120 watts
362195
Wavelength= 1/wavenumber\n\nWavelength= 1/1700cm-1\nWavelength= 5.882 x 10^-4 cm\nWavelength= 5882nm
500605
Basically.... it is as simple as (Voltage X (times) amperage = Wattage) example.... \n\na 120volt motor pulling a normal 3 amperes  ....will consume 360 watts of electricity... \n\nThe more amperage the motor requires.... the higher... the horsepower... and also the cost to run or operate it...
272621
v=voltage\no=ohm\nm=milliammeter\n\na tester which test those mentioned aboved. don't use it in measuring resistance(ohms) when the circuit is still connected to a source (voltage)