equation in slope...?
961745
the slope of the line perpendicular to that line would be the inverse negative of the slope of x-3y = 8\n\n(x-8)/3 = y\n\nthe slope = x/3, so the perpendicular line has a slope of -3x\n\ny = mx + b\n\nm = -3\n\nx = 5\n\ny = -4\n\n-4 = -15 + b\n\nb = 11 \n\ny = -3x + 11
892240
Slope is Y2 -Y1 divided by X2 - X1\n\nIn your example, Y2= 12\n                            Y2= -7\n                             X2= 0\n                            X1=-2\nSo... \n(12-(-7)) / (0-(-2))= 19 / 2 = 9.5\n\nThe slope of the line is 9.5
450157
slope = (y2-y1)/(x2-x1)\n5= (k-4)/(2-3)\n5= (k-4)/(-1)\nk-4= (-1)*5\nk-4= -5\nk= 4-5\nso k= -1.\ni hope you understand they way I worked it out. If you have any more questions, pls feel free to ask me on: pinkieflava@yahoo.co.uk
285662
to find an equation.......\n\ny=mx+b\n\nm=slope \nb=y-intercept
850944
You have 2 points, (x1,y1) and (x2,y2) and you want to find the equation of the line that goes through these points.\n\nThe first thing you want to do is find the slope.\nslope is rise/run so m = (y1-y2)/(x1-x2)\n\nFor slope intercept form , y = mx + b\nwhere m is the slope, and b is the y intercept\nnow that you have found the slope, you can solve for b, the y intercept by plugging in your value for m and one of the given points, either (x1,y1) or (x2,y2).\n\nFor point slope form,  y - K = m(x - H)\nm is the slope, and   (H,K) is a point that the line passes through.\nSince you have already calculated the slope, m, for the slope intercept form, you're already almost done. All you have to do is plug in the point (x1,y1) or (x2,y2). In your question, you are asked for the point slope form of just point (6,2).
35268
slope = (-4-(-6))/(-2-0)\nslope = -1
890222
for (0,2),(4,0) the slope is -1/2\nfor (-2,0),(4,0) the slope is 0
706345
slope = -5-1 / -2-(-3) = -6/1 = -6\ny-1=-6(x+3)\n.
777827
y=-4x+k is the first line slope =-4= m\n \nsecond line has a slope-1/m=-1/-4=1/4\n\nsecond line : y=(1/4)*x+C , but C=0 because line passes through the origin\n\nline  is thus y=x/4\n\n\nsubstitute v+1 for y and v for x in this equation\n\nv+1=v/4\n\nv=-4/3
626863
To find slope you start by choosing two points Ex: (1,2) and (5,6). You us the equation m(slope)=(y2-y1)/(x2-x1) Ex:(6-2)/(5-1)=4/4=1 The slope is one. To find the x-intercept you plug in Y=0 (zero) into the equation, and to find the y-intercept you plug in X=0 into the equation.
247082
Yes because to find slope you need change in y and change in x (or whatever coordinate system you use).\n\nSince you have both two x's and two y's then you're set.\n\nUse this formula: Δy/Δx where Δ stands for "change in" or (y1 - y2)/(x1 - x2)\n\nUsing the coordinates listed:\n(-2 - -2)/(6 - -8)=\n(-2 + 2)/(6 + 8)=\n(0)/(14)\n\nSince '0' divided by anything is zero, your slope is zero.\n\nThis would be a line that is parallel to the x axis 2 units below the axis.
771990
y = mx + b is the slope intercept form, where m = slope\n\nso 2 is the slope in your example\n\nWith any equation for a line, there are 2 variables, x and y, representing the position on the x and y axis.  Given any line equation, you can manipulate it to get it into slope intercept form (y = mx + b), and m will be your slope.\n\nThe y-intercept is where the line crosses the y-axis (or where x = 0).  As you can see, if you put x = 0 in the equation, you will get:\n\ny = 0x + b\ny = b\n\nso when x = 0, y = b.\n\nHope this helps! :)
623659
Lines with undefined slope are always in the form x = a, where a  is any real number. This is a vertical line, where the the value of x is constant, not dependent on y.\n\n\nSince an ordered pair is in the form (x,y)....in the ordered pair (4,-2), x = 4\n\nSo your equation is x = 4
787000
slope is equivalent to dy/dx = y'\n y = x -1\ndy/dx = dx/dx -0\n dy/dx = 1\n   y' = 1\nTherefore the slope of the given equation is 1.
953083
let your given point be P(a,b,c...) and your slope be a direction given by a vector V(v,w,x,....).  I'm assuming you want a vector equation of a line?  You can get to any point on the line by starting at P and moving some distance m (maybe negative) in the direction V.  So any point R(r,s,t,...) on the line is given by\n\nR = P + mV, where m is some real number.\n\nFor example, in 2 dimensions, the line y = (2/3)x + 1 has a y-intercept at (0,1).  Let that be P.  The slope 2/3 is the vector (3,2).  The point (2, 7/3) is on the line, and the equation\n\n(2, 7/3) = (0,1) + m(3,2) works when m = 2/3.  m/√13 is the distance you go along the line from P to R.
155791
Here is a good page describing slope.\n\nhttp://mathforum.org/cgraph/cslope/slope.html
725779
when you multiply the 2 through on the right side of the equation you get:\ny = 2x-2+3\ny = 2x+1\nthe slope of this line is the number in front of the x.