What number represents the sum of the x's for y=1.488x-30.27?
966181
This equation is plainly the result of a least squares regression in the form y = ax + b.  The formula is exactly correct for the mean values of X and Y, so if xbar = sum(x)/n and ybar = sum(y)/n, then\n\nybar = a xbar + b\n\nxbar = (ybar - b) / a\n\nsum(x) / n = [sum(y) / n - b] / a\n\nsum(x) = [sum(y) - nb] / a\n\nSo to get the sum of the x's, you need to know n and the sum of the y's.  That's as close as you can get.
765005
s = sqrt(1/n*sum from 1 to n (x - xbar)^2)\n\nn = 5\nmean or xbar = 50.8\n\n(21 - 50.8)^2 = 888.04\n(34 - 50.8)^2=282.24\n(56 - 50.8)^2=27.04\n(67 - 50.8)^2=262.44\n(76-50.8)^2=635.04.\n\nsum/5 = 418.9600\n \ns = 20.46851
678134
0.207+0.093+0.031+0.020 = 0.561\n\nor\n\n1-0.439 = 0.561
929737
the first three questions are answered as follows\n~ = means repeating decimal\n#1     $75 - (75 x .333~) = $50\n#2     $150 - (150 x .5) = $75\n#3     $750 x .1 = $75\n\nthe easiest way to the the additional problems you have add is as follows\n\n#1    80 x .2 = 16\n#2    50 x .5 = 25\n#3    40 x .1 = 4\n#4    68 x .25 = 17
199621
that would be .72 * 162 = 478.24
268593
x=3.921341315270809\n y=1.4240793774891456
1166602
Set it up: x=1/y which simplifies to x/y. So if y=30 when x=2, then 2/30=0.066667 When y=600, then x/600=0.066667; multiply 0.066667 by 600 for your answer of x=40. Good luck!
953140
4000(1 + .06/4)^4*x\n4000(1 +.06/4)^20 = $21227.27\n\n4000(1 + .08/4)^4*x \n4000(1 + .08/4)^20 = $21648.64
1186783
You can't really solve it - all you can get is x+y=31.54875
652953
I got:\n1. 6x^2 - 36x +48\n2. 6x + 22
538653
Just put each number in for x and see what the answer is.  Example : -11/2 + 75 = -5.5 + 75 = $69.50 a unit.
831094
36. >\n38. =\n40. >\n42. <\n44. <
836116
Let x and y be your numbers.  Your equations, therefore, are the following:\n\nx+y = 72\nx-y = 12\n\nDo you need to actually solve for x and y as well, or just set up the equations?  If you also need to solve, then write your two equations one on top of the other, then subtract to get an equation in one term only:\n\nx + y = 72\nx - y = 12\n----------------\n0x + 2y = 60\n\nSo, 2y = 60, which means y = 30\n\nNow substitute y=30 into one of the original equations to solve for x:\n\nx + y = 72\nx + 30 = 72\nx = 72  30 = 42\n\nSo your two numbers are 30 and 42\n\n~ ♥ ~
61276
100101111\nThat is:\n256+32+8+4+2+1
765455
Given y=.55x+12.when x units produced\nkTherefore,y=.55X20+12\n=11+12\n=$23 (when 20 units produced)
695947
D\n\nEither is sufficient.  \n1) will lead to 2 equations,2 unknowns which yield a unique solution for x and y:  x=y+1, x+y=77, therefore x=39, y=38.  xy=1482 \n\n2) If the sum is 77 and x and y have the same tens digit, then there are two solutions for {x,y}, namely {38,39} and {39,38}, however the product xy is the same. xy=1482
525953
X = 24/Y  Just start plugging in Y and getting X, there are lots of possibilities, unless you restrict it to just whole numbers.