find the area of the traingle whose altitude is 15 meters and whose base is 10 meters.?
952904
A= (B*h)/2\nA=(10*15)/2\nA-=75
611169
Base area x height of water.
959978
use pythagorean thereom a^2 + b^2 = c^2. (c being teh longest side or the hypotenuse) the two legs are a and b. so you have the sq rt of 169. (sqrt of 12^2 + 5^2) which is 13
976772
15 / 3.5 = 4 with remainder of 1\n\nTherefore the leftover piece is 1 meter long
1135263
The height of the trajectory is 1 m (3.05-2.05)\n\nThe horizontal distance is 6.02 m\n\nNow you have ucos(25)t = 6.02\n\nand usin(25)t-0.5*9.8*t^2 = 1\n\nSubstitute t = 6.02/ucos(25) in the 2nd eqn and solv.
53126
area = 1/2 x base x height
543583
Use the pythagorean theorum.  Train One is the left leg, train 2 is the right leg, and the distance between them is the hypotenuse.  Since they only traveled an hour, their speed is irrelevant.  That triangle gives the formula of (x+10)^2 + x^2 = 71^2\n\nWork it out from there.  X will equal the distance that the second train traveled, and since they traveled for an hour, that is the magnitude of its speed as well.
619584
Do you mean inside area of triangle ?\n\nArea= 1/2 (base)(height)
977845
Put on a number plane with B initially at O (0. 0)\nTherefore A is initially at (-150, 0)\n\nNow A's position, t hours after midday, is (-150 + 35t, 0) and B's position is (0, 25t)\n\nSo t hours after midday \n\n|AB| = √[((-150 + 35t) - 0)² + (0 - 25t)²]\n= √[(22500 - 10500t + 1225t² + 625t²)\n= √(22500 - 10500t + 1850t²) \n\nVelocity of change = d(|AB|)/dt\n= 0.5 * (3700t - 10500) / √(22500 - 10500t + 1850t²)\n= 0.5 * (3700 * 4 - 10500) / √(22500 - 10500 * 4 + 1850 * 4²)\n= 0.5 * 4300 / √(10100)\n≈ 21.4 km/h
1091583
The altitude of the triangle is 5 times the square root of  3, or 5 times 1.7.\nArea of a triangle = 1/2 bh, so Area = 1/2 times (10)  times (5 times 1.7) = 42.5 or more accurately 43.30127019 using the correct value of the square root of 3.
102628
x= -15/16     m=-3       z=153       y=157\n\n\nYou need to learn this stuff, so you dont get caught cheating.
422511
if u kno the base and height.. then area= (base x height)/2\n\nif the triangle is scalar,\nthen :\n\nfirst find s, using hero's formula\n\ns= (a+b+c)/2   .... where a,b,c are the sides of triangle.\n\nthen , area = squareroot(s x (s-a) x (s-b) x (s-c)
66895
I think  you mean ,you have:\nBase x height = 1x 1/2 \nthan by comparaison base =1\n                    height =1/2
897915
500 miles\n\nthink of it as a triangle with the hypp. being the 1000miles and the distance east being the opp. side.\n\nuse sin.\n\nsin(degrees)=opp./hypp.\nsin(30)=opp./1000\n(1000)(sin(30))=opp.\n500=opp.\n\n500 miles east
722101
Surface Temperature = 5500ºC\n\nCore Temperature = about 15,000,000ºC
640092
450 cm\n1/2 base x height = area of triangle\n\n15 x 30=450 cm
545831
You give two sides lengths, 10 , 15\nThe length of the other two sides are:\n15*(9/10)= 13.5 \n10 + 6.538348415 = 16.538348415