7 men can finish one job in 54hrs. how fast that job can be done by 9 men?
965979
The job took 7 men * 54 hr = 378 man-hours\nTherefore 9 men takes 42 hours.
119696
In one hour Pol does 1/9 of the job and Jan 1/6 of the job.\nthen in 4 hours Pol has done 4/9 of the job.\nNow both has to work N hours to complete the job:\n1-4/9=N(1/9+1/6)\n5/9 =N(15/54)\n30=15N\nN=2\n\nPol should work 6 hours. (4 alone and 2 with Jan).\nYou can prove it:\nWork done by Pol alone + Work done by Pol with Jan's help + Work done bay Jan =1.\n4/9+2/9+2/6= 1
24167
5\n\nC'mon man make it harder.
222234
All together seven . How many you invented ? ! You can make extra if the drill is OK !!!!!!!
244378
Here's a great formula. One does the work in A days and the other in B days. The number of days they will do the job if they work together being N,\n\nN=AB/A+B\n\nJim and Sue = (30x45)/30+45=18 minutes\n\nAll of them = (18x90)/18+90=15 minutes.... PS. 1 hr and 30 min is 90 minutes.\n\nThey can do the job in 15 minutes!
848957
2 hours\n\nedit: WHY would it be more than 3 hours??? if the brickie does it alone it would be 3 hours max. why say 4.5 hours?? :(
523320
About 10 times a minute\n600 times an hour.\nAbout 14400 times.
339526
60 seconds in minute\n60 minutes in an hour\n\nTherefore, 3600 seconds in an hour
803499
how to gauge??\n\nweekday:\n7 hours zzz(30%)... 9 hours society(40%) ... \n3 hours for himself and the rest frens and family.. (30%)\n\nweekends:\n35% rest, 40% family, remaining others...
573729
An alternative method:\nThe times taken by A, B and C to complete one lap around the track would be 10/7, 10/8 and 10/9 mins, respectively. Now we just need the LCM of these three to find out when they will all catch up with each other. \n\nThis turns out to be 10 mins.
24924
As many as it takes in order to get the job done.
1169800
work done 1.078 X 10^5\nheat is -0.292X10^5
508076
Men: 3 minutes and 26.00 seconds by  Hicham El Guerrouj (MAR). He done it on 14/07/1998.\n\nWomen: 3 minutes and 50.46 seconds by Yunxia Qu (CHN). She make it on 11/09/1993.
1129113
It is 9.8 m/sec , some they have made it 10 :)
217693
There is a difference of 7hours.
205202
each of them has his time
917544
This type of problem is solved by finding the fraction of the job each, then both, can do in an hour.  If t = the hours for the faster person, she can do 1/t of the job in an hour, the slower can do 1/(t+2) of the job, and together they do 1/5 of the job in an hour.\n\nSo 1/t + 1/(t+2) = 1/5