How do you find the base length of a trapezoid?
966614
It is a median of a trapezoid, not a midsegment because a midsegment is used for triangles.\n\nThe formula for getting the measurement of the median would be m=1/2(b1+b2)\n\nm is the median\nb1 is base 1\nb2 is base 2\n\nm=1/2(b1+b2)\n8=1/2(6+x)         [multiply both sides by 2]\n16=6+x\nx=10\n\nYou could use the formula of a median of a trapezoid to get the measurement of any of the bases with a median as one of the given.
458187
find the area of the base and multiply it by the height\n\n(1/2)*b*h1*h2  for a triangular prism h1 is height of the triangle, h2 is the height of the prism\n\npi*(r^2)*h for cylinder, h is height, r is radius of the base
167445
The integral is defined over 6 units so 6/3 = 2 units.  Use your calculator to calculate f(0)=sin(0/3), f(2)=sin(2/3), f(4)=sin(4/3) and f(6)=sin(6/3).  Make sure your calculator is on "radians" not degrees when you do this.  The area of a trapezoid is the average of the heights times the base.\n\nWhen you use this method, the endpoints only get use once whereas the interior points get used twice.  You can now write:\n\nA = {[f(0)+f(2)]/2}2 + {[f(2)+f(4)]/2}2 +{[f(4)+f(6)]/2}2\n\nThe 2's cancel out, so you have f(0)+2f(2)+2f(4)+f(6).\n\nNow, put in your calculator values and add.
554282
A = base * height\n\nbase = 8\n\nslant height = 6\nto get the actuall height, we use trig\n\nthink of 6 as the hypotenuse\n\nsin 30 = height / slant height\n\nor height = sin30 * 6\n\nheight = 3\n\ntherefore area = 8 * 3 = 24
567965
means that the base is 4 cm rite?\nok, u obtained the base, then now u need the height.\nHow to find the height?,\nUse trigo!. U know what izzit, well, i assume u know.\n\nFirst split the triangle in half. \n            /|&#92;\n           / | &#92;\n          /__|__&#92; \ntake one side only,\n            /|\n           / |\n          /__|\n\nthe slant side is 4 cm rite?,\nand to find the height,\n\nsin 60 = opposite/hypotenus\nopposite = (hypotenus)sin 60,\nopposite = 3.46cm.\n(oppossite is the height, hypotenus is one of the side of the triangle)\n\nU have the height!\nUse triangle formula\nArea = 0.5(heigth)(base)\n     = 6.93cm(squared)\n\nOR, for easier way,\nuse trigo formulae for triangle area\n\nArea = 0.5*a*b*sin C\n(C is the angle of any two sides while a and b is both sides making the angle)\n\n     = O.5 (4) (4) (sin 60)\n     = 6.93 cm squared
583176
A trapezoid is a 4-sided figure with one pair of parallel sides. To find the area of a trapezoid, take the sum of its bases, multiply the sum by the height of the trapezoid, and then divide the result by 2.
884235
Base is the dimension along the bottom of the object.\n\nHowever, your equation only applies to parallelograms.
684619
Draw a horizontal staight line to be the base of the trapezoid.\nMark a point to be a corner of the trapezoid. Label it A.\nSet your compass to the length of the base.\nMeasure that distance from the first mark and make a second mark on the line. Lable it B\n\nWithout changing the width of the compass, put the point at A and swing an arc above the line. Move the point of the compass to B and swing and arc. Lable the point where the arcs cross C.\n\nDraw the lines AC and BC. You now have an equilateral triangle. The angles are all 60 degress.\n\nSet your compass to the distance of the leg length.\nPut the point at A and swing an arc across AC. Label the intersection D.\nMove the point to B and swing an arc across BC. Label the intersection E.\nDraw the line DE.\nDone.
101549
V=1/2(b1+b2)*h*w  where b1 and b2 are the two parallel sides of the trapezoid and h is the height and w is the width.
326809
The area of a trapezoid is the height times the average of the bases, or h*(b1+b2)/2.  In your case, your bases are the top and bottom of your figure (parallel to the x-axis), and your height is along the y-axis.  So,\n\nh = a\nb1 = c\nb2 = b\n\nA = a(b+c)/2
93089
This seems like a homework problem, so I'll give a few hints.\n\nThe arclength is radius times the angle subtended.\n\nTo find the angle subtended, consider the isosceles triangle created inside the circle where the chord is the hypotenuse and the radius of the circle is the two other legs. \n\nSince the isosceles triangle created is not a right triangle you need to use a specific formula to find the angle "C" subtended by the chord.
893599
You may want to be more specific on this one... are you trying to find the largest possible area? You can inscribe lots of different trapezoids in a circle. \n\nAnd which theta are we talking about? The angle that the base makes with the circle?\n\nTry that one again,\n\nUMRmathmajor
478941
69.0948, 69.0948, 41.8104\n\nMore precisely, one of the base angles is equal to\n\narccos( 0.5 * sin(36) * ( 4 - sec(18)^2 )^0.5 / ( 1 + sin(36)^2 + sin(36) * sec(18) )^0.5 )
523203
a trapazoid has 2 parallel sides and two non parallel sides.\n\nArea=( 1/2 sum of the parallel sides) * height\n\nremember the height must be the perpendicular height.\ni.e the height perpendicular to the parallel sides
551690
T= L + 2B\n\nT is total surface area\nL is Perimeter x Height\nB is base area
863154
First find the length of the of z. Call the length L.\n\nL^2 = (sqrt(3))^2 + 1^2\nL^2 = 3 + 1 = 4\n\nL = 2.\n\nNow find the angle that x makes with the x axis. Call the angle t\n\ntan(t) = 1/sqrt(3)\nt = 30 degrees.\n\nSo in polar form, z = 2(angle sign)30 degrees
489663
Reviewing the facts:\n\n1.  You're constructing a pentagon and two trapezoids by using the center of the square.  Since the sides are 1, the short parallel side of the trapezoid is 1/2.\n\n2.  Since the two trapezoids are congruent, the short parallel side is midway in the square.  So the height of each trapezoid is 1/2.\n\n3.  Since there are three areas now, and each area is equal, the area of the trapezoid is 1/3.\n\nThe area of a trapezoid is A = (1/2)h(b1 + b2).  We have everything we need now to solve for b2, the longer parallel side:\n\nA = (1/2)h(b1 + b2)\n1/3 = (1/2)(1/2)(1/2 + b2)\n1/3 = (1/4)(1/2 + b2)\n4/3 = (1/2 + b2)\nb2 = 5/6