and so why is this??? x(sqrd)/x+2 - 4/x+2?
952176
Presumably you mean\n(x^2)/(x + 2) - 4(/x + 2)\nSince the denominators are the same, you can add the numerators without modifying them:\n(x^2 - 4)/(x + 2)\nFactor the numerator to get\n(x - 2)(x + 2)/x+2)\n(x + 2)/x+2) = 1 so you are left with\n(x - 2)\n\nIf you post this question under philosophy, you can probably get many different answers to why this is.  Because it works is mine.
714589
x/(x+3) - 2(x-1)/(x+3)(x+2)\n\nx(x+2) - 2 (x-1)\n--------------------\n   (x+3) (x+2)\n\n\nx^2 +2\n----------\n(x+3)(x+2)
1013726
There is no real value for x that satisfies that equation.  It simplifies to (x-3) = (x+1).  In other words, (4(x-3))/4 does not = x+1.
233014
U R RIGHTT..HOW DID YA GET IT..PLZ CAN YA EXPLAIN..I'VE BEEN TRYING THIS PROBLEM FROM A LONGTIME.EVEN DE CALCULATOR SAYS ITZ "4"..I KNOW DE CALCULATORS WRONG TOO..PLZZ DO EXPLAIN IT TO ME ASAP
894400
I'm not sure what you mean by ***, so I'll answer the second part of your question.\n\n-4x/-4x + 12/-4x = 1 - 3/x
1171615
I think this is also the 'trial and error method'\nYou will have an equation where you do not know the value of x.\nKeep on substituting different values of x into the equation until you come up with the right answer.\nIf you are lucky, you may have been told that x lies somewhere between 2 values.\nBest way to do it is to choose a number, get the answer, then choose another number a fair bit larger than the first. If the answer you want is between these 2 values, choose a number about half way between the 2 and so on.
757614
4 (x^2 + 3X -4)\n4(x+4)(X-1)
893013
is it x-3/x+2 or (x-3)/(x+2)?\n\nlets assume the second one\n\n2x(x+2)/(x+2)=x-3\nx+2 cancels out\n\n2x=x-3\nx=-3
294522
COS_STUDYGROUP is COMPLETELY WRONG.  (2-7x)^2 == 4+49x^2, please don't get confused about that!\n\nWhile the first user above me is completely correct. I'd like to go a step further and explain how he arrived at that solution.  See that number in front of the x squared?  It should look familiar, if you take the square root of it you get an even 7.  That is how he got to 2 7x's.  The 4 when square rooted becomes a 2.  So now we have a 2 and a 7x in each set of parentheses.  Since the x squared is negative that means that the signs must mismatch so one + and one -.\n\nSo we arrive at the equation (-7x + 2)(7x + 2) or (2 - 7x)(2 + 7x) .... I was always taught the number with the x goes first.
561262
u jammed the equation together.\ndo u mean\n6x^3 + ( 6/x - 2 * x^2 - x/3x2 - 3x + 3)\nits really hard to see ur question. can u write it out with spaces...\nhurry up i am waiting... lol
852286
if it x - 4x/(x+1) = 4/(x+1)\nthen x(x+1) - 4x = 4\nor x^2-3x + 4 = 0\n\nthis is quadratic and so 2 solutions so Megan is right\n\nyou do not have tro evaluate
672142
it's\n[x(x+2)]/[x*x] -2/3x=\n\n[x+2]/x - 2/3x=\n\n[3[x+2]-2]/3x=\n\n[3x+4]/3x=\n\nx + [4/3]x
753754
I presume you mean\n\n[(6x^2) / (4x^2y-12xy)] * [(x^2+x-12) / (3x^2+12x)]\n\nThere seems to be something wrong. Are you sure about those "y" terms?
415757
I hate to tell you, but I don't think there is an algebraic method for arriving at a value for x. Sometimes, this can be the case, in which case all you can do is find a numeric approximation, here around x=1.0587...\n\nI'll see if another user can prove me wrong, but I'm going to go with there's no way to solve this problem using analytic methods.
670503
The answer is x2+2x-4 with a remainder of 11/(x+1)
321475
*(2x/(x^2-4)) + (5/2-x) - (1/2+x)\n*(2x/(x^2-4)) + (5/2-x)((2+x)/(2+x)) - (1/2+x)((2-x)/(2-x))\n*(2x/(x^2-4)) + (10+5x)/(4-x^2) - (2-x)/(4-x^2)\n*(2x/(x^2-4)) + (8+6x)/(4-x^2)\n\nyou should be able to get it from there
38332
(x-2)/(x^2-2x-15)+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(-2-x)(x+3)/(x-5)(x+3)\n\n[(x-2) + (x+3)(-2-x)] / [(x+3)(x-5)]\n\nANSWER :\n(x^2+4x+8)/((x+3)(5-x))