how to calculate electric energy bill and meaning of terms in it?
968169
There are different type of tarrifs for different consumers. so any one calculation would not suffice. You have to obtain schedule applicable to type of connection which you have and calculate your bill accordingly.or post copy of your bill from which schedule followed could be understood and method of calculation followed could be explained.\n\nGenerally charges for domestic connections are based on\n(a) Minimum charges based on load sanctioned. if you have a 6 kW connection and rate per kW is Rs. 50/- per month, minimum charge would be Rs. 300/- per month. Now let us say you have consumed 500 units ( kWh or kilowatthours i,e unit of measurement of electricity consumed) in a particular month and charges are Rs. 4/- per unit for first 200 units and Rs 5/- per unit for next 200 units and Rs. 7/- per unit for remaining units, your energy charges would be 2x200+5x200+7x100=2100. Now energy charges being more than Minimum charges energy charges would be levied.\nTo this following additions are also made depending on tarrif schedule.\n\nMeter Rent\nElectricity Duty.\nSurcharge.\netc.
1023349
Electron flow in the circuit (outside the battery) is from - to +\nHole flow in the circuit (outside the battery) is from + to -\n\nPower in an electric circuit is defined as:\n Watts = Amps x Volts\n\nis equivalent to:\n <power> = <current> x <potential, voltage>\n\nis equivalent to:\n P = I x E\n\nSince one cannot have a non-zero value for power without flow(current), then you could say it comes from both - and + being applied to a load.
956993
And the question about utility bill statements is.....?
866700
electricity produced due to flow of charges/electrons
262235
This is very serious for you. Here is how I interpret the situation. I am taking all the information you gave in your question:\n\n1) one building\n\n2) one electric meter\n \n3) five tenants\n\n4) tenant # 1 lease agreement says the electric is included in rent payment.\n\n5) tenant #2 lease agreement says the electric is divided equally by the five tenants.\n\n6) tenant # 3 (which is you) lease agreement says you will pay 65% of the electric. \n\nYou don't say anything about the other 2 apartments. They must be vacant?\n\nNone of you have received a bill or note from the landlord in at least three months.(Jan. Feb. Mar.). You ask repeatedly and no response from the landlord. THEN you are presented a bill of $2647.00, which you are expected to pay within five days from the date you received it.\n\nYou then called the utility company and they said the bill for $2647.00 was for the entire, total building. You need a copy of the bill showing the specific addresses.\n\nIf I have all this straight it sounds to me like your landlord does not have a clue as to what he does. I will assume all of you have your copy of the leases stating what you signed and agreed to pay, right? Again, if I am correct, you have three choices here.\n1) Go to the landlord and state exactly what you did in your letter above. Ask if he thinks this is a fair deal and why did he do this to you?\n\n2) If you and the other two tenants have the signed leases you really have it made. Here's how: #1 is safe. Take the bill and divide it by five. #2 pays his portion. Since the bill is divided by the five tenants it must be assumed the other four (according to #2s lease) will pay in equal parts the remaining balance of the bill. It is not your fault #1 has his electric included in the rent. It is not your fault that there are two vacant units. SOOOOOOOOOOOO, Divide the$2647.00 by 5 = $529.40 per unit. Right? Now, you do your part and pay 65% of  $529.40= $344.11.  Makes sense, huh?\n\n3) This is the last one, get an attorney.\n\nActually I like my #2 the best. Think about that. I cannot believe I have spent all this time on one answer. I was really angry at the damn landlord. You had better let us know what happens.(me, at least)     MUCH LUCK!!!!
360834
I'm not sure if I understand your question, but I good stater \nhttp://en.wikipedia.org/wiki/Electric_power
469764
did you pay your electricity bill?
897585
It depends on how low low is and how high high is. Kilowatt hours are the standard measurements for power expendature pricing. The bill is calculated by multiplying power (kilowatts) by time (hours). If there is twice as much power for half as long, your bill will not change.
488548
Depends so much!  Are you paying for gas and/or electric?  Do you need to pay to heat your water?  How big is your place?\n\nI am really cheap on the electric-- my bill is usually 25 bucks a month (two bedroom) and gas (to heat) has varied from 10 (summer) to 50 (winter).\n\nI plan on an average of 50 bucks.  \n\nActually, the best way to do this is to find the place you're interested in.  Then you find out what gas and electric companies the prior tenant used.  Then you call and ask them the averages and highs/lows.  They can give out this information to help you plan.
531264
The Energy Information Adminstration is a great resource for this.  Information can be organized and sorted many differnt way over many years.\nhttp://www.eia.doe.gov/\n\nhttp://tonto.eia.doe.gov/dnav/pet/hist/mg_tt_usw.htm\nIncidently, all prices are in cents.  I was confused for a minute or so until I figured that out.
945879
The first method would be to compare you utility bills to see if there is a drastic change (or any) between last year at this time and the most recent bill with the insulation on.  \n\nFor an exact calculation, you need the following:\n\nThe R value of the insulation\nLength of pipe insulated\nTemperature of the water inside the pipe\n\nThen plug them into this equation:\n\nQ=UA(Tinside - Toutside)\nwhere Q is the amout of Btus \nU is the thermal insulation (or lack there of) expressed as =1/R\nTinside = water temperature\nToutside = air temperature (average) where the pipe is installed\nA = the surface area of the pipe\n\nOnce you get that for the insulation, do it once with out the insulation.  For the second R value without the insulation, use a R-value of 0.5.  The two different Q's you get will be the amount of Btu's you saved.  \n\nTo convert that to $, you need to convert the Btu's (Q) to kW.  Divide the Btu's by 3.412 to get watts.  That will be the amount watts you saved at your hot water heater/boiler or whatever is heating the water (assuming it is electric).  You then look at your electric bill to determine the cost $/W or $/kWh.  Take the number you got for watts and convert to kilo Watts by dividing by 1000.  Then multiply it by the cost off of you utility bill for $/kWh.  \n\nThis is all for a one hour period.  You need to calculate that for a month, day, or year (720, 24, 8765 hours respectively).  You now have what your savings for this project was.
739842
To work this out you must find out the power rating (in watts). Most of the time this information is written on the appliance. For example a standard electric kettle may use 1300 watts. \n\nElectricity is sold in units of 1000 watts per hour. For example if you use 10 100w light bulbs for an hour it will cost you 1000watts or 1 unit of Electricity\n\nYou will have to find your power rating on your appliance then compare an hour of usage of that appliance with the price of 1 unit of power (1 Kilowatt per hour)
381406
Define power.\nElectricity is the flow of electrons through a substance.\nIn the United States, electricity can be generated through coal/fossil fuel burning plants, nuclear power plants, wind(mills), and solar energy collection.\n\nIn fossil fuel and nuclear plants, they use the furnace and nuclear reactor to heat up water in order to turn a turbine, which spins around an electromagnet to generate electricity. There is much loss of energy through this process because much of the energy used to heat the water is lost through convection.  In windmills, the wind directly turns the turbine, so there is not as much loss, plus, it is a renewable resource.
1088769
P = d * Q * g * H * efficiency\nWhere,\np= power in KW\nd= density of fluid used\nQ= discharge\nH = head\nefficiency= given for a turbine
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to run a house about $5,000.  to add everything else to because it produces DC power (like a battery) and a house used AC power: $50,000 and another $10,000 for engineering, and $5,000 for somebody to install it all for a total of about $70,000 given that the average house power bill is about $100-200 it would take about 30-60 years to break even (not including maintainence costs and its an unreliable power source).  Moral of the story...just buy power from the utility!
970880
Power requirements for a room are determined by the total heat load. This heat load consists of solar load (if the room has an exterior window), people load (how many people use the room at a time, and how active are they), appliance loads (lights, equipment, etc.) and the ambient conditions surrounding the room and insulation (r-value for walls separating room from hot and cold areas).\n\nIf you need more specific help for a commercial project - e-mail me.
204153
You should distinguish between power and engergy. A watt or kilowatt is a unit of power. It does not make sense to associate a cost with a unit of power, as you also need to know how much time was spent absorbing this power.\n\nEnergy on the other hand (with units like the kilowatt-hour or the joule) does incorporate information about time. A kilowatt-hour of energy, for example, would be enough energy to provide 1 kilowatt of power over a period of 1 hour. Energy costs about 5-8 cents per kilowatt-hour.