Chemistry help needed, AGAIn!!?
955362
Violet12.. is right on both questions. Now, about the second question:\n\nFor the 4s orbital: n + l = 4 + 0 = 4.\nFor the 3d orbital: n + l = 3 + 2 = 5\n\n4 < 5, so the 4s orbital has less energy than 3d, so we put electrons first in 4s orbital and then in 3d.
788506
b. electrons\n\nI really hope you are trying to answer these first before you put them on here because although we are all certainly willing to help you, you are not going to gain anything from just having the answers given to you.  You really need to try and learn this stuff.
231663
_KCl3 _KCL + _o2? K2Cl4o2 thats the answer i think.:)
215160
http://www-ec.njit.edu/~skawinsk/chem243/chap11/chap11.htm\nthis may help–near the bottom
696739
The chemicals are not correct\n\n2 (NH4)3PO4+3 Pb(NO3)2-> Pb3(PO4)2+6 NH4NO3?
482555
AgBr-------->Ag+ + Br-\n(a) Ksp=[Ag][Br] solubility=s=[Ag]=[Br]=Ksp^0.5\ns=(6*10^-7)^0.5\n(b) [Br]=0.01 (because all of kBr was dissuciated)\ns=Ksp/[Br]=(6*10^-7)/0.01 mol/lit
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This site should help you.\n\nhttp://sparknotes.com/chemistry\n\nGood luck.
1171989
http://en.wikipedia.org/wiki/Chemistry\n \nthis nust be helpful for you
962694
Tehe answer is:\nAg + HNO3 -> AgNO3 + H\nAgNO3 + KBr -> AgBr + KNO3
2247
And this is chemistry how??
936280
You are so smart - in fact, so smart that no one in THREE DAYS has even tried to answer your question.  Perhaps you can take this question and apply it to another realm:  \n\nhttp://antoine.frostburg.edu/chem/senese/101/index.shtml\n\nThis way you can get your homework done for you by people who know chemistry on a much larger scale... Answers is not here for homework completion
813421
Na2CO3(aq) + MgCl2(aq) --> 2NaCl(aq) + MgCO3(aq)
73319
the earlier equation is not balanced.\nCaO + 2HCl --------> CaCl2 + H2O
1040448
ask your chem prof or tutor ..it's hard to explain over the internet!
136146
The 1st answer is wrong. The reaction is\n\nNa2CO3(aq) + SrCl2 (aq)--> 2NaCl (aq) +SrCO3 (s)
149472
Hey I'm studying physical and chemical equilibrium too, currently.The answer is that it will definitely have units when the concentrations have different powers.Just try and work it out with the units and it will be very clear.
64647
2x (G2 + M2 ---> 2GM)      DH=-280.0*2= -560.0 kJ\n2x (L + 2M2 ---> LM4)      DH=-350.0*2= -700.0 kJ\n   (L2G4 ---> 2L + 2 G2)   DH=122.0*(-1)=-122.0 kJ (change sign when flip over)\n\nAdd them together, we'll have:\n2G2 + 2L + 6M2 + L2G4 ---> 4GM + 2LM4 + 2L + 2G2\nthen cancel 2G2 and 2L on both side, we end up with:\nL2G4 + 6M2 ---> 2LM4 + 4GM\nthe enthalpy of this reaction is, therefore the sum of each enthalpies calculated above.\nDH=(-560.0) + (-700.0) + (-122.0)= -1382.0 kJ (exothermic process)\nhope that'll help!