i want to print a (c program)triangle pattern as follows:?
966909
I am assuming that all you want is that simple pattern drawn.\n\nFor a predefined size of the triangle LINELIMIT:\n\nint main() {\n  int head = 1. prev; line = 0, col = 0;\n\n  for (line = 0; line < LINELIMIT; line++) {\n    prev = head;\n    for (col = 0; col < line; col++) {\n      printf("%d ", prev);\n      prev *= 2;\n    }\n\n    printf("&#92;n");\n    head *= 2;\n  }\n\n  return 0;\n};
608853
Code written in C and it works in C++\n\n#include <stdio.h>\n#include <conio.h>\n\nvoid main() {\n     float f[5];\n     int   i[5];\n     int j;\n     clrscr();\n     printf("Please, enter five float numbers: &#92;n");\n     for (j=0;j<5;j++){\n scanf("%f",&f[j]);\n i[j]=(int) f[j];\n     }\n     printf("Float value&#92;n");\n     for (j=0;j<4;j++)\n printf("%2.2f&#92;n",f[j]);\n     printf("&#92;nInteger value&#92;n");\n     for (j=0;j<4;j++)\n printf("%d&#92;n",i[j]);\n\n     getch();\n}
1079280
go to start>programs>accessories>system tools>character map...here you will see All types of those symbols
359046
#include <ctype.h>\n#include <stdio.h>\n#include <stdlib.h>\n\nstatic char *article[] = { "the","a", "one", "some", "any" };\nstatic char *noun   [] = { "boy","girl", "dog", "town", "car" };\nstatic char *verb   [] = { "drove","jumped", "ran", "walked", "skipped" };\nstatic char *prep   [] = { "to", "from", "over", "under", "on" };\n\nint\nmain()\n{\n  int asize = sizeof(article)/sizeof(article[0]);\n  int nsize = sizeof(noun)/sizeof(noun[0]);\n  int vsize = sizeof(verb)/sizeof(verb[0]);\n  int psize = sizeof(prep)/sizeof(prep[0]);\n\n  char buff[100];\n  for (int i=0; i<20; i++) {\n    (void)sprintf(buff, "%s %s %s %s %s %s.",\n      article[rand()%asize],\n      noun[rand()%nsize],\n      verb[rand()%vsize],\n      prep[rand()%psize],\n      article[rand()%asize],\n      noun[rand()%nsize]);\n    *buff = toupper(*buff);\n    (void)printf("%s&#92;n", buff);\n  }\n  return 0;\n}\n\n\n$ a.out\nSome town walked to a dog.\nThe car ran from any dog.\nAny boy drove under any town.\nOne girl jumped under the girl.\nOne car jumped to one girl.\nAny boy skipped over a dog.\nAny town jumped from some town.\nThe town ran from the town.\nOne car walked to any town.\nOne town ran over one boy.\nAny town jumped on the car.\nSome dog skipped from a boy.\nSome girl skipped over a boy.\nA car walked over some girl.\nThe car jumped from a girl.\nThe boy skipped on the town.\nAny car walked from one girl.\nAny dog ran to a town.\nA car jumped under some car.\nSome boy walked to the car.
328129
just draw a triangle has right angle which dimensions 1,sqrt(3),and hypothenus 2. if you want it, i can send to you
750295
check out http://www.planet-source-code.com for examples.  I don't do C, but I use that site all the time.
747560
http://www.cplusplus.happycodings.com/Computer_Graphics/code22.html\nhttp://www.wol.net.pk/mtshome/cppComputerGraphics.html#Area%20Filling\n\nThis is C, but close enough:\nhttp://www.programmersheaven.com/download/15200/download.aspx
423103
#include <stdio.h>\n#include <stdlib.h>\n\nint\nmain(int argc, char* argv[])\n{\n  int count = argc>1 ? atoi(argv[1]) : 10;\n  FILE *f = fopen("numfile", "w+");\n  if (!f)\n    perror("fopen"), exit(-1);\n  for (int i=0; i<count; i++)\n    fprintf(f, "%d&#92;n", rand());\n  fclose(f);\n  return 0;\n}
648070
http://www.anagramgenius.com/archive/algebr.html\n\nedit: sorry didn't answer your real question. I don't know of a program that does what you want, but it shouldn't be too hard to write it. \n\nEdit: Contact me at algebra@envisagecapital.com if you would like the solution. I wrote a quick program to do what you wanted.
1186498
In a hexagram shape, like so...\n\n----o----\no-o-o-o\n--o---o-\no-o-o-o\n----o----
764538
For any given triangle ABC with sides a, b and c.\n\nCos C = (a^2 + b^2 - c^2)/2ab  This is the cosine rule.\n\nSin C =sqrt(1 - Cos^2 C). You may need to adjust the sign of the sign to match the triangle.
408935
Hey,\nthe code in JAVA would look like this ::\n\nclass test {\npublic static void main(String a[]) {\nfor(int i=1;i<100;i++) {\nSystem.out.print("&#92;t"+i+"&#92;n");\n}\n}\n}
396589
Here's the pattern:\nhttp://knitty.com/ISSUEfall05/PATTbits.html
81883
Details of the algorithm for conversion along with\nsource program written in C can be found at.\nhttp://www.codepedia.com/1/Art_Expressions_p1\n\nA good short article on this topic.\nhttp://www.cs.man.ac.uk/~pjj/cs2121/fix.html
33544
Here you go:\n\nhttp://home.att.net/~dexter.a.hansen/pattern/pat7.htm
195373
Try this:\n\n#include <stdio.h>\n\nmain()\n{\nint size,array[50],n,m,border,max,buf,step;\nint i, j, temp;\n\nprintf("Input number of elements in array:");\nscanf("%d",&size);\n\nfor(n=0;n<size;n++) {\n  printf("input %d. element of array:",n+1);\n  scanf("%d",&array[n]);\n  }\n\n for (i=(size-1);i>=0; i--)\n  {\n   for(j=1;j<=i;j++)\n    {\n     if(array[j-1]>array[j])\n      {\n       temp=array[j-1];\n       array[j-1]=array[j];\n       array[j]=temp;\n      }\n     }\n   }\n\nfor(n=0;n<size;n++)\n   printf("%d. element: %d&#92;n",n+1,array[n]);\n\n}\n\n\n\nHERE IS MY OUTPUT:\n\nInput number of elements in array:8\ninput 1. element of array:6\ninput 2. element of array:2\ninput 3. element of array:3\ninput 4. element of array:5\ninput 5. element of array:1\ninput 6. element of array:4\ninput 7. element of array:5\ninput 8. element of array:7\n1. element: 1\n2. element: 2\n3. element: 3\n4. element: 4\n5. element: 5\n6. element: 5\n7. element: 6\n8. element: 7
937186
WTF IS THE TRIANGLE AND THE U FOR AND HOW DO U MAKE THE TRIANGLE... THERE ISNT A KEY OR ANYTHING...