Algebra 2, If the measure of one angle is five less than two-thirds of the measure of its supplementary angle?
956320
x+y=180\nx=2y/3 - 5\n\ntry to find  the value of x and y
140611
Complementary angles add up to 90 degrees.\nSupplementary angles add up to 180 degrees.\n\nJust think in alphabetical order: C comes before S, and 90 comes before 180.
805124
Read about one's complement addition here --> http://mathforum.org/library/drmath/view/54379.html
356323
Absurd... A triangle cannot have more than 1 obtuse angle, since the sum of all angles of a triangle is 180 degrees.
21860
Let's call these angles A and B.  And let's call C the adjacent angle in the middle of these two angles.\n\nThen we will have:\n\nA + C = 180\nB + C = 180\n\nAs a result, A = B = 180 - C
807541
Let A be the angle\n\nTurn the words into an equation:\n\n"The supplement" --> 180° - A\n"is" --> =\n"thirty less than" ---> - 30°\n"three times" ---> 3 x\n"the complement" --> 90° - A\n\n180° - A = 3(90° - A) - 30°\n\nDistribute the 3 through on the right:\n180° - A = 270° - 3A - 30°\n\nSimplify:\n180° - A = 240° - 3A\n\nAdd 3A to both sides:\n180° + 2A = 240°\n\nSubtract 180 from both sides:\n2A = 60°\n\nDivide both sides by 2:\nA = 30°\n\nSo the angle is 30° (the supplement is 150°, the complement is 60°)
1002935
Its the Pythagorean Theorem. It applies to right angle triangles. \nIt states that a^2 + b^2 = c^2\nWhere a and b represent the lengths of legs of the triangle and c is the Hypotenuse.\nThe Hypotenuse is the side that is opposite the right angle (also the longest side). Whereas the legs are the two sides that meet at the right angle.
274876
by inspection I can understand another point will be...\n\n(0, 5) because if you add 1 to X you must add 2 to Y
968872
Let the shorter leg be 'x'\nLonger leg = 'x + 1'\nHypotenuse = 'x + 2'\nx^2 + (x + 1)^2 = (x + 2)^2\nx^2 + x^2 + 2x + 1 = x^2 + 4x + 4\n2x^2 + 2x + 1 = x^2 + 4x + 4\nx^2 + 2x + 1 = 4x + 4\nx^2 -2x - 3 = 0\nx^2 + x - 3x - 3 = 0\nx(x + 1) -3(x + 1) = 0\n(x - 3)(x + 1) = 0\nEither x - 3 or x + 1 = 0\nIf x + 1 = 0, x = -1 which cannot be true for the triangle\nIf x - 3 = 0, x = 3\nTherefore, the sides are:\nShorter leg = 3cm\nLonger leg = 3 + 1 = 4cm\nHypotenuse = 3 + 2 = 5cm
991856
It is called WRONG. If A is much larger than B, then A+B/A is about A unless you meant (A+B)/A, in which case the result is about 1. In neither case do you get A/B.
930936
Use the fact that the sum of the angles of a triangle add up to 180 degrees. Let A, B, C be the angles of the triangle. The m<A + m<B + m<C =180. If you know m<A and m<B, you can find m<C.\n\nWhen I write m<A, I mean the measure of angle A, not m is less than A.
754610
The answer to your homework question is 5.62
1078035
C-120... Two supplementary angles must equal 180.... 60+120=180\nB-32 feet... 8*4=32
780025
x ≤ 5\n\n-- - - - - - -s-
1028326
1 - A is enough because with the lengths of 2 sides you can use pythagoras' theorem to work out the length of the other
930882
31 / 5\n\nThat's because .2 is 1 / 5, so I just converted the 6 to 30 / 5 and added one more.
533231
By cosines low I guess you mean cosines law,\nwhich is a^2 + b^2 = c^2 -2(ab)cos(C) where C\nis the angle opposite side c. And I don't see any\ncorrelation between that and your equation.