okay the problem is 2/y^2-16 = 10 y^2+4y can anyone help me?
952496
Wasn't it 2/y^2-16 = 10/y^2+4y?\n\nIf so:\n\n2/y^2 - 16 = 10/y^2 + 4y\n10 (y^2 - 16) = 2 (y^2 + 4y)\n5 (y^2 - 16) = y^2 + 4y\n5y^2 - 80 = y^2 + 4y\n5y^2 - y^2 - 4y = 80\n4y^2 - 4y = 80\n4 (y^2 - y) = 80\ny^2 - y = 80/4\ny^2 - y = 20\ny^2 = 20 + y\n\nso now, we have this:\n\n2/y^2 - 16 = 10/y^2 + 4y (where we can replace y^2 with 20 + y)\n10 (y^2 - 16) = 2 (y^2 + 4y)\n10 (20 + y - 16) = 2 (20 + y + 4y)\n5 (20 + y - 16) = 20 + y + 4y\n100 + 5y - 80 = 20 + 5y\n20 + 5y = 20 + 5y
599677
i know how 2 do this.\n4x+2y=2\n x-2y=8\n---------\n5x   =10\n5x=10\nx=10/5\nx=2.\nsubstitute x=2 in any1 of the equations.\nlet us take x-2y=8.\n  2-2y=8\n  -2y=8-2\n  -2y=6\n    y=6/-2\n    y=-3.\n therefore ur x=2 nd y=-3.
892609
y=2x-8\nx=2y-8\nadding 8\n2y=x+8\ndividing by 2\ny=(x+8)/2
917826
I'm going from memory\n\ntry multiply all terms in top eq by 5\n\ngiving         10x + 20y = 40\n\nthen the bottom by 2\n\ngiving          -10x + 6y = 10\n\nthen add the two gives   26y = 50\n\nwork back  2x + 4(1.923) = 8\nthus               2x + 7.69 = 8\n                                 2x = 8 - 7.69\n                                 2x = 0.31\n                                   x = 0.155\n  \ntherefore y = 1.923  and x =  0.155\n\nyou have to find the lowest common multiple of two of the terms, whether it be x or y.\n\ni hope this helps but it looks wrong to me. did u get the original eq right and what level are they at?\n\ngood luck
731860
x² - y² = 16\nSo 2x - 2ydy/dx = 0\nie dy/dx = x/y\n\nd²y/dx² = (y - xdy/dx)/y² (NOTE: x² - y² = 16  → y² = x² - 16)\n= (y - x.x/y)/(x² - 16)\n= (y² - x²)/(x²y - 16y)\n= -16/(x²y - 16y) (As x² - y² = 16)
631400
Factor out the y:\n\n(a-2) * y = c\n\nThen divide both sides by (a-2):\n\ny = c / (a-2)
907035
You have \n100 +4X^2 -16y -40x\n\nFirst let's factor out a 4, since 4 is a factor of each term, that gives\n\n4*(x^2 -10X +25) -16Y\n\nOf course I rearranged the terms so the highest powers of X are\non the left.  I didn't factor 4 out of -16Y because I want the \nquadratic (X^2-10X+25), which I know I can factor.\n\nsince (X^2-10X+25) = (X-5)*(X-5) = (X-5)^2, we have\n\n4*(X-5)^2 -16Y\n\nThe secret is being able to recognize that \n(x^2 -10X +25) = (X-5)^2
1027604
[(1/y)+4)]/[(1/y^2) -16]\nFirst simplfy the numerator.\n(1/y) +4\n= (1/y) +4y/y\n= (1+4y)/y\nthen simplify the denominator.\n(1/y^2) -16\n= (1/y^2) - 16y^2/y^2\n= (1-16y^2)/y^2 \n= [(1-4y)(1+4y)]/y^2\nNow multiply the numerator by the reciprocal of the denominator.\n(1/y+4)/(1/y*2)-16\n= [(1+4y)/y] * y^2/[(1-4y)(1+4y)]\n(1+4y) and y cancel\nAnswer: y/(1-4y)
90743
Well you must have two equations! If you wanted to say x+4y=16 then just add the two and you'll fing x (4x=10) and then find y from one of them.
1027274
2x^2 - 2y^2 = 2(x^2 -y^2) = 2(x-y)(x+y)\n-2x^2 + 2xy = -2x(x-y)\nx^2 + xy = x(x+y)\n2(x-y)(x+y)/[-2x(x -y)]/[x(x+y)]\n= 2(x-y)(x+y)/[-2x(x-y)(x)(x+y)]\n= -1/x^2
512448
x^2 + y^2 = 25\nx - y = 0\n\nx = y\n\nY^2 + Y^2 = 25\n2 Y^2 = 25\n\nY ^2 = 25/2\ny =  (25/2)^1/2 or\ny = Sqrt (12.5)
873806
y/=-8 = 11\nMultiply both sides by -8\ny = 11(-8)\ny = -88\n\n4/5 = 16  This is simply not true.\nAssuming you left out a variable, then\n(4/5)x = 16\nMultiply both sides by (5/4)\nx = 16(5/4) = 80/4\nx = 20\n\n-x/6 = 9\nMultiply both sides by -6\nx = 9(-6)\nx = -54\n\n1/9 = /2/7  does not make sense
815860
Hello Dear \n\n- Take " √ " of eachsides\n√16y^2 =  √ 25 \n± (4y = 5)\ny = ± 5/4\n\nGood Luck dear.
735754
just plug the numbers in.  if y=8, and x=2, \nits 8=a(2^2)\nso 8=a(4)\nso a=2.\nhope that helps!
159612
Multiple the first equation by two\n-10x-8y = -22\n10x +y = -6  (second equation)\n\neliminate x\n\n-7y = -28\ny = 4\n\n10x + 4 = -6\n10x = -10\nx = -1
800260
4y+3=2y\n      3=-2y\n-1 1/2= y\n\n\nslope- 3
104006
Start with \n\n    4x + 9y = 24\n\nsubstitute the value of y from the second equation:\n\n    4x + 9(-x/3 + 2) = 24\n--> 4x -3x + 18 = 24\n--> x = 24 - 18\n--> x = 6\n\nand now y can be computed,\n\n    y = -6/3 + 2\n--> y = 0