Name the addition property used in this equation-(9+1)+3=9+(1+3)?
964689
That is the associative property.  In addition, it doesn't matter what order you add things in, so you can "associate" any grouping of additions and get the same result:\n\n(a+b)+c = a+(b+c)\n\nNote that this is true for multiplication as well:\n\n(a*b)*c = a*(b*c)
904649
6-(b+1)=9\n-(b+1)=3\n-b+(-1)=3\n-b=4\nb= -4
970698
(a + b)(c + d + e)\n= a(c + d + e) + b(c + d + e)\n= ac + ad + ae + bc + bd + be\n\nOR\n\n(c + d + e)(a + b)\n= c(a + b) + d(a + b) + e(a + b)\n= etc.
389044
I believe it is 9599...because the digits of the right side add up to the left side.\n\n3+9+8+3 = 23\n9+5+9+9 = 32
503153
(x+7)(x+3)\n(x-11)(x+2)\nforget this one.  its AC factoring though\nthis ones AC too
304206
the clue would be to simplify the equation  to \nlim {x +[-(x+1)+1]}/(x+1)\n x-->0 \nlim [x + 1 -x]/(x+1)\nx-->\nlim (1/(x+1)) =1\nx-->0
1042004
nine times a single digit number always ends up in two numbers that add to nine and the first number is risen each number higher multiplied and the second number is lowered each number higher multiplied. For example\n                                       \n                                       1x9 is  09\n                                       2x9 is 18\n                                       3x9 is 27\n                                       4x9 is 36\n                       \nthe first number of the product increases each time and the second number of the product decreases each time.
1124767
9a*a+6a-4b*b+1\n= (9a^2+6a+1)-4b^2\n=(3a+1)^2-(2b)^2\n=(3a+2b+1)(3a-2b+1)
957282
|3(x + 1) + 6| =18\nie |3x + 9| = 18\nwhence |x + 3| = 6\nThere are 2 different methods to solve such an equation\n\nOne is to use the definition that\n|N| = N if N ≥ 0\nand = -N if N < 0\n\nThe other is to use the propety that |N|² = N²\n\nMethod 1\nSo x + 3 = ±6\nWhence x = -9 or 3\n\nMethod 2\n|x + 3|² = 6²\nie x² + 6x + 9 = 36\nx² + 6x - 27 = 0\n(x + 9)(x - 3) = 0\nx = -9 or 3
760641
x + 6 + 3x = 1 + 3x + 1\nCombine like terms.  x+3x = 4x and 1+1 = 2\n4x + 6 = 3x + 2\nSubtract 3x from each side\nx + 6 = 2\nSubtract 6 from each side\nx = -4
83153
There are a couple of ways to work this out, I will take the easiest to explain.\n\n(x-3)(x^3+3x^2+9x+27) Can be rewritten as:\n\n(x)(x^3+3x^2+9x+27)+(-3)(x^3+3x^2+9x+27) Now, multiply those out.\n\nx^4+3x^3+9x^2+27x-3x^3-9x^2-27x-81 Now, sort by like powers of x\n\nx^4+3x^3-3x^3+9x^2-9x^2+27x-27x-81 Simplify\n\nx^4-81
500151
The distributive property (of multiplication over addition) is an axiom that states that for any numbers a, b, and c, the equality a*(b + c) = a*b + a*c is true. This can be used to distribute or factor (read the equation from right to left. Remember that if a=b, then b=a).\nFor example, 3*1.99 = 3*(2.00 + (-0.01)) = 6.00 + (-0.03) = 6.97.\nLikewise, x^2 + x = x*(x + 1).
115335
4.\n\nThink about it... 1+1+1+1= 4\n1+1=2\n1+1+1= 3\n1+1+1+1=....4\nHence:\n\n1+1+1+1= 4\n\nor:\n\n3+1= 4\nand\n4+0= 4
748322
The numbers for this particular answer are 9 and 10.\n\n9 + 10*3\n9 + 30\n=39
650616
These three sequntal clock wise numbers \n2+3+4 --> 9+4 --> 1 (adding the last no.(4)\nBut not works for all
356024
x + y + z = t\n\nx +x% + y + y% + z + z% =\n[(100 + 1)( x + y + z)]% =\n101t% = t + t%. So\nx +x% + y + y% + z + z% = = t + t% or\nx% + y% + z% = t%
206636
for (i=1,t=1,cosx=1;i<=n;++i)\n{\n  t=(-1)*(t*x*x)/((2*i)*(2*i-1);\n  cosx += t;\n}