I need help with Statics? I have 4 problems to solve as my test, can someone help ASAP? willing to pay?
965059
It's nice to know that someone who may one day be responsible for public safety is upholding the ethics of his profession by CHEATING ON A TEST.  Publicly, no less.\n\nI hate to think of how much of this is going on.  It's depressing.
812688
1*6N right\n2*No Direction\n3*How much force and where\n4*???\n5*???
1079574
what's the boundary conditions?\nself weight problem? \nthen, what's the material of the beam?\n\npls be clear :)
1157643
I took a few TE classes...Exactly what HELP do you need???
617970
I am terribly afraid of the equilibrium problem.. the first one on the free response!!! well, good luck!
858889
QUESTION 1:\n\nAsk yourself: WHICH TRIG FUNCTION IS OPPOSITE OVER ADJACENT?  IT IS THE TANGENT FUNCTION, RIGHT?\n\nThe bottom of the tree is 25 feet away from a point that measures 30 degrees from ground level to the top of the tree.\n\nAnswer: tan30degrees = x/25feet...choice 1.\n\nNotice that they are NOT asking you to solve for x.  Get it?  \n\nQUESTION 2:\n\nYou need to write the given equation 3x - 2y = 12 in the y =mx + b\nform.\n\nLet's do that right now.\n\nWe have:\n\n3x - 2y = 12 \n\nI will subtract -3x from both sides of the equation.\n\nWe get:\n\n-2y = -3x + 12...See what I did?  \n\nNext:\n\nDivide BOTH sides of the equation by -2 to find the value of y.\n\nWe get this:\n\ny = (-3x + 12)/-2\n\nWe can reduce the equation to this:\n\ny = 3/2 (x) - 6\n\nSlope is 3/2 and the y-intercept is -6.\n\nFinal answer: choice 1\n\nGuido
851212
hmm im not quite in college yet, but i hope to be help.\ndo you know the values for f, h, v, and a?\nif you do, id substitute it in.\nthen square both sides. \nand then solve.
49314
Sorry, but with the time you spent typing these questions you could of looked them up in your physics book or googled them.  Sometimes getting others to do your leg work isn't always the best answer to a problem.  Good Luck in your new class!
668063
Why don't you just get all of your homework problems asked now so you can go out and play?\n\nThe answers you received to your previous (and almost identical) question should be enough for even a casual observer to answer the current question. At some point in time you have to start thinking on your own.
390341
As one of the FE takers this Saturday, April 22, I believe that the reference manual would be a great help if you get yourself to be familiar with it. It contains all the equations and formulas that are used to solve all the problems in the FE. \n\nBut, there are some things that you should remember.\n\n1. Sometimes finding a formula for a specific problem may take up a lot of time. Remember you have only 4 hours for 120 questions which is practically 2 mins for one question (only morning exam).\nAssume you would spend 1 min to find the formula and 1 min to solve it. That is good. But, what if you can't find it in 2 mins? Don't try to look for a formula for every problem. \n\n2. The formulas in the reference manual do not have any explanation of how the formula is applied or any example problems. You must have knowledge of the formula you would like to use. If you do not have any idea of how to apply, and try to prove or understand the formula, you will fail.\nSimply, you have no time to do.  \n\nSo, my suggestion to you as well as to myself is to use the reference manual when it is really really necessary.\nTry to use your common sense and the knowledge you already have acquired in the university.\nMy best wishes to all exam takers. ! ! !
917347
It sounds like you know what to do.  From your description, it looks like a basic statically determinate problem.\n\nYou have a known applied force P, and two unknown reaction forces, lets say A and B for the top and bottom reactions respectively.  You also have two equations of static equlibrium, specifically the sum of the forces in the "x" direction, and sum of the moments about any point you wish.\n\n(Ok, really you also have the force of gravity and the normal force, but those are the only forces in the "y" direction so that equation won't help you, especially since the mass or weight isn't given).\n\nAssuming to the right is positive, assume A is to the left and B is to the right (this is intuitive, but if directions are incorrectly assumed the answer will just have a negative sign, thats all).\n\n                    _ ------------> P\n                    |   |\n                    |   |\n                    |   |     10.5 m\n                    |   |\n                    |   |\n                    |   |\n                    |   |<----------A\n                    |   |\n                    |   |       1.5 m\n                    |_|--------------> B\n                    \n                 (FBD!)\n\nSum of forces in "x" gives: P - A + B = 0\nSum of moments about B: A(1.5) - P(12) = 0\n\nI took moments about an unknown reaction, B, to eliminate it.  Also, I assumed counter-clockwise to be positive.\n\nSubbing in the value of P = 5.40 N into the second equation:\n\nA = (5.40*12)/1.5 = 43.2 N\n\nThen, put that into the first equation:\n\nB = A - P = 43.2 - 5.40 = 37.8 N\n\nThat should do it.  Both come out positive because their assumed directions were correct, however on the Free-Body-Diagram they are in opposite directions necessary for equilibrium.\n\nCheers,
706663
The idea is that all forces at the nodes (connecting points) are balanced. Draw the two free body diagrams.\n\nLeft point:\nFx\n0=-T1cos53+T2cos11\nFy\n0=T1sin53-T2sin11-57\nRight point:\nFx\n0=-T2cos11+T3cos42\nFy\n0=T2sin11+T3sin42-W2\n\nBy inspection we see only the first 2 eqns are required. Solve the system:\n0=-T1cos53+T2cos11\n0=T1sin53-T2sin11-57\n\nT1=83.62 N\n{=}8.5 kg
533021
there are some solved physics problems on \nhttp://www.dctech.com/physics/help/\nbut I don't know if it will help you out.
501273
Didn't got the question do you want the solution for all the problems of goodman's Introduction to Fourier optics book? Well I do not think I have them any more if you want a specific problem I can help you. I can even try to get a chapter solution for you. Just tell me each one, I can try to get it for you, I do not garantee but I think I may have a way to got them just send me an email (I have a yahoo email). If you have the solutions and you don't understand tell me each problem I can do it in more detail probably, not garantee at 100% but at a good 90% .
685464
Follow the method from the other 4 problems that you just posted.\nIn order to learn, you have to try things yourself.
930026
wellz why not just help me with that matrix problem? :oP
805064
lol \nYou have homework that you don't know the answer to.  \n\nWhy would someone ask these here out of interest? Like you have these specific parameters and conditions that you are just raring to want to know just out of the blue.\n\n Quit wasting time writing and typing questions out waiting here for answers when you could be the next engineering graduate who actuallly UNDERSTANDS this stuff by doing it yourself.