find the mean of the set of numbers?
957340
The answer is C.\n\nHowever, do you know how to get the answer?\n\nThe mean is the average of all of the numbers. Add the four numbers you gave me and divide by 4. That is how you get your number. This is what teachers use to find your average for your school grade.\n\nSorry, im studying to be a teacher, I wanted to make sure you understood.
252318
If I understand correctly, your 8 numbers are:\n12, 24, 36, 38, 45, 69, X, and X.\nThe last two are the same number as the mode by definition.\n\nSince the mode times two equals the mean, then\n\n2X = (224+2X)/8\n16x=224+2x\n14x=224\nx=224/14=16\n\nSo, your numbers were 12,16,16,24,36,38,45,and 69\nTotal 256\nAverage (Mean) 32\nMode 16
973127
Since the mean is 10, what does that mean the total is? 24.3*10 = 243.\nNow, how much has the total gone down by? (31-18) and (28-19) make 22. So the new total is 223. So the new mean is 22.3.\n\nLets list the numbers in order:\na b c 13 d e f.\nWe want to make the last one as big as possible, so lets make the others as small as possible:\n1 2 3 13 14 15 f\nNow we just have to find f which makes the total 13*7; which gives 43.\n\nAgain, this just comes down to working out totals. Boy total = 123*178.4. Girl total is 237*168.3. Total total = 61830.3.\nSo we divide that by the total number of people (360) to get 171.75, approx.
617746
sample space {1,2,3,4,5,6}
927294
mean (add all numbers together and divide by the amount of numbers) - 6\nmedian (middle number when ordered from least to greatest) - 7\nmode (the number that appears the most) - 9\nrange (lowest number subtracted from highest number) - 8
999718
what was the question?\n\n\nDo you want to know terms like mean, average, mode, standard deviation, etc.?
1030368
(a1* ... *aN)^(1/N)\n\nAs soon as you find the geometric sequence\n\n(a1 * a2 * a3 * a4 * a5 * a6)^(1/6)\nwould be an example of geometric meant, assuming you know a1 through a6\n\nLets say you had\n\n1, 2, 4, 8, 16, 32\n\nThe pattern would be 2^(n - 1)\n\nThe geometric mean would be done like this\n\n(1 * 2 * 4 * 8 * 16 * 32)^(1/6) = 32768^(1/6) = 5.6568542...
842178
Start with the whole array as set Q.\nUse algorithm X to get the median M of Q.\nSet a = [size of Q]/2.\nIf a = k, stop; M is your answer.\nIf a > k, set Q = the values less than M, otherwise set Q = the values greater than M.\nRepeat.\n\nThis algorithm is a bit off because when [a > k], the comparison [a <=> k] is subsequently invalid.  But you get the gist of it.  Use X in a binary search mode.
305208
oh puke, what a pain in the rear.  i don't envy you.  like the other dude said use excel, but if you have to do it on paper, here's the formula:\n \nIn other words, the standard deviation of a discrete uniform random variable X can be calculated as follows:\n\n1.  find the mean of the set of numbers\n2.  subtract the mean from the first number\n3.  square the difference between that number and the mean\n4.  repeat steps 2 and 3 for all numbers\n5.  add all of the differences from step 3\n6.  dvide this number by the number of numbers you had in the set\n7.  take the square root of this\n\n\nthat's the standard deviation.
773196
Mean: 113\nMedian: 108-116\nMode: 108-116\n\nThe mean was the hard one, I actually took the middle score from each range (eg 90-98=94) and multipled it by the number of times it occured (eg 94x6=564) and added all 5 (564+2266+4816+3388+1170= 12204). Then divided it by the frequency (6+22+43+28+9=108). Total (12204/108= 113). It's impossible to find a mean of a set of ranges, you need exact figures.\n\nThe mode is the most commonly occuring range, the median is the central range. These figures can't be accurate without the full actual IQ scores. But based on the figures provided, the mean, median and mode are as I stated above. If you provide the exact figures I'll work out the exact mean, mode and median.
387360
The problem is incompletely or improperly described.\n\nEach member of the population has some characteristic value.  The mean is the average of this value taken over the entire population, which, assuming each member is an equal contributor, is M = sum(values)/N, where N is the population.  If each member has the same value, say 515, then mean would be 515 and the standard deviation would be zero.  If each even-numbered member has value 1030, and each odd-number member has value 0, the mean is 515 and the standard deviation is (approximately) 515.\n\nSo, you have provided enough information to solve the problem satisfactorily.
196956
7\n\nThe median is the number that in the exact middle of all the rest of the numbers.
892527
Take the average of each of the coordinates.\n\nx-mid = (0 - 0)/2 = 0\ny-mid = (4 - 0)/2 = 2\nz-mid = (0 - 4)/2 = -2\n\nmid (0, 2, -2)
919154
It depends on whether you want the mean number of heads, the total number of heads, etc.\nIf you want the total, multiply the standard deviation by sqrt(n), where you have n tosses.\nIf you want the average, divide by sqrt(n).\n\n(Note, the formula talked about below is for the *margin* of error, not the standard error. And thats only for means.)
603103
The median is another word for the number that is the middle number. When there is an odd amount of numbers, the one in the middle is the median. When there isn't, you take the mean (average) of the two in the middle. With this set of numbers, since there is 11, the median is 9.\n\nHope that helps!
1118574
Find the midpoint of each interval.\nFor 1-3, the midpoint is (3+1)/2 = 4/2 = 2\nFor 4-6, the midpoint is (6+4)/2 = 10/2 = 5\nFor 7-9, the midpoint is (9+7)/2 = 16/2 = 8\n2(1) + 5(6) + 8(3)\n= 2+30+24\n= 56\nn = number of data points = 1+6+3 = 10\nvariance = [1/(10-1)][((2^2)(1) +(5^2)(6) +(8^2)(3)) - (56^2)/10]\n= (1/9)((4+150+192) - 3136/10)\n= (1/9)(346 - 313.6)\n= (1/9)(32.4)\n= 3.6\nstandard deviation = sqrt(variance)\n= sqrt(3.6) \n= 1.9
677379
If the population has a mean of 58 and a sd of 8, then the sample means of size 100 will have a mean of 58 and a sd of 8/sqrt(100) = 0.8\n\na) Within 3 of 58 means that the sample mean will be between 58-3 = 55 and 58+3 = 61\n\nz = (55-58)/0.8 = -3.75\nz = (61-58)/0.8 = 3.75\n\nFrom the table, the area between the two is almost 1.\n\nb) The mean weight is less than 2.5 of 58 or more means less than 58-2.5 = 55.5\n\nz = (55.5-58)/0.8 = -3.13\n\nFrom the table, the are greater than that is almost 0.\n\nc) z = (57.5-58)/0.8 = -0.63\nz = (58.7-58)/0.8 = 0.88\n\nFrom the table, the area between is 0.811 - 0.264 = 0.547.\n\nd) 56 +- (1.96)(0.8)\n56 +- 1.568\n(54.432,57.568)