Find the x-coordinate?
957506
k = .7/.25 = 2.8 N/m\n\nT = 2π√(m/k) = 2π√(.25/2.8) = 1.877 sec\n\nergo, t = .71*1.877 = 1.33267 sec\n\nYou haven't told us where the glider is at t = 0\nIf it's at its deflected position, then x = .25cos(2πt/T) = -.062\nIf it's at x = 0 moving left, then x = -.25sin(2πt/T) = +.218
716583
If you know the vertex then you know\n\na (x-xv)^2=y-yv  , use P to find a, the shape \n\nat P:\na(xp-3)^2 =yp-1\na(-1-3)^2 = 3-1\n16a = 2\na=1/8\n\nSo, the parabola is \n\ny = 1/8*(x-3)^2 + 1\n\nCheck: \nat V  y= 1 ok\nat P y = 1/8(-4)^2 + 1 = 16/8+1 = 3 ok
840169
u= x\ndv=cosx dx\n\ndu =dx\nv= sinx\n\n\nintegral of xcosx dx = xsinx - integral of sinx dx\n= xsinx + cosx +C\n`
18379
(XA+XB)/2, (YA+YB)/2\n\n(-7+(-1))/2 = -4 as the X coordinate\n(6+1)/2 = 3.5 as the Y coordinate\n\nThe midpoint is (-4, 3.5)
6838
∫xSec(x²)²dx = .5Sin(x²)/Cos(x²)
939411
Let center point be [0 0] of a rectangular coordinates system.\nAssume the object’s face be initial position on the plane; that is X-axis goes from [0 0] to object’s face, let Y-axis be X-axis rotated through [0 0] by +90 degrees. This way we have defined a rectangular system of coordinates on the plane. \nLet x & y be coordinates of a random point p in our rectangular coordinates system. \nNow lets consider polar coordinates system. Trace vector V from [0 0] to p, then\nx=r*cos(a) & y=r*sin(a), a degrees being angle from X-axis to V, r=sqrt(x^2+y^2). \nAngular position a of p=[x y] should be found as following.  \nAs tan(a)=y/x, (or cotan(a)=x/y), then a=Arctan(y/x) is general solution. Angular position a could be found for any pair of [x y] but [0 0] or when r=0.\nWe do not need general solution in our problem. Our solution must be:\nLet b=arctan(|y/x|) degrees, then a=b for x>0 & y>0, being 0<=a<=90; a=-b for x>0 & y<0, being -90<=a<0; a=180-b for x<0 & y>0, being 90<a<=180; a=-180+b for x<0 & y<0, being –180<a<-90.\nThus the object must be rotated by an angle of abs(a) degrees determined above in the direction of sign(a). \nRotating in opposite direction means to rotate the object by an angle of (360-a) or (–360+a). abs(360-a)=abs(-360+a) is always greater than abs(a).
469175
x-coordinate: Count the horizontal distance from the origin (0,0).  If the point is to the right, then the number is positive.  It the point is to the left, then is is negative.\n\ny-coordinate: Count the vertical distance from the origin (0,0).  If the point is to above, then the number is positive.  It the point is to below, then is is negative.\n\nThen list them as an ordered pair (x,y)
749264
Usually there won't be an answer. \n\nFor planes you have:\nz=ax+by+c\nz=dx+ey+f --->\nax+by+c=dx+ey+f\n(a-d)x+(b-e)y=c-f ---> gives a line for an answer.\n\nHowever if you look at two lines, you will have that the x and y coordinates are dependent on each other:\nI.e.\nz=f(x),y=g(x)\nz=h(x),y=j(x)\nSo --- f(x)=h(x) and g(x)=j(x) ---- which is over determined.
398683
Use log you will find\n\nor put\n\nx=3.597285024\n\nIts done
909143
take out the x\nx(a-b)=6\nx=6/(a-b)
1055471
You need to graph this function. \nIt is a line.\ny = (x^2)^ 1/2 - 16 \ny = x - 16\nx = 0, y = -16, \nx = 16, y = 0
885928
Find the X intercept by setting Y = 0\n\nx-2 = 0\nx = 2\n\nFind the Y intercept by setting X = 0\n\ny = 0-2\ny = -2\n\nSo the two points to plot are (0,-2) and (2,0) \nThen connect those points with a line
790996
if cuts the x axis when p(x) = 0\n\nthat is 2x-3 = or x= 3/2\n\n2nd point x-5 =0 or x = 5\n\n3rd point x+1 = 0 or x = -1
147089
y intercept: (0,4)\nx intercept: (3,0)
317252
to find x-intercept => you have substitute y=0 into the equation and solve for x.\n\nIn this case (0,0) is the x-intercept.
744474
x=2y\n\n-2 -4\n0 0\n1 2\n3 6
3636
X marks the spot. You're right here: at Yahoo Answers.