The Actual Mech. Advantage of a machine is 3. if you exert an input force of 5N what output force is exerted -
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5N * 3 = 15N\n\nYour arm is a lever in weight training. The input force is at your shoulder, the output force is on your hand, and the fulcrum is your elbow.
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To lift an object from a ground we must apply a force equal to the weight of the object and move it to the required height.\n\nThus to do a work two things are required, a force and a distance. \n\nWork is the product of these two. \n\nIf a body of weight 32N is to be moved up through a distance of 1m we have to do a work of 32 joule totally. \n\nThat is we apply a force of 32N and move it through 1m.\n\nThe same work can be done by a boy who cannot exert a force more than 16 N.\n\nThis is possible because, the boy has to move 16N force through a distance of 2m instead of usual 1m.\n\nWe can apply 1N force and move it through 32m. \n\nOnly thing is that the product of force and distance must be 32 joule.\n\nAll simple machines are based on this principle. \n\nWhen we reduce the force the distance is increased; when we increase the force the distance is reduced. But the product remains the same. That is the total work done is the same.
991659
the key to the tip is the "movable block".  mechanical advantage refers to the relationship between how far (how hard) you pull the rope versus how much the load moves.  if you have a rope running through a fixed block and down to a load, you can change the direction of force (you pull down, the load goes up), but you have no mechanical advantage.  for every foot you pull the rope, the load goes up one foot.  \n\nif you have a fixed block and a movable block attached to a load and the rope runs through the fixed block (F) once, down to the movable block (M), through M and back up to F, you have two parts through M (one down and one up).  if you attach a load to M and pull, the load goes up 1/2 foot for each foot of rope you pull, so you have a 2:1 mechanical advantage.  remember, the rope running through F at the top isn't giving you any mechanical advantage, its just changing the direction of your pull from up to down.  if you stood above M and pulled up, you'd get the same 1/2 foot up for each foot you pulled and the same 2:1 mechanical advantage.  \n\nso yes, the tip seems to work.  try it on paper for some other blocks, for example, double blocks at F and M.  \n\ngood luck!
1170770
Which one.\nThey range from statical scales to efficient, low friction machines.
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Fnet=M*A \n\nYou know that the only forces are friction and the applied force of the orderly because friction and the normel force cancel out.\n\nso:\nFo-Ff=M*A\n70N - xN=80Kg * .4m/s^2\n70N - xN=32Kg*M/s^2 =32N\n-xN=32N-70N\nx=38N\n\nThe force of friction is 38.0N in the direction opposite of motion.
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In any machine there is a way to put the energy inside and there is a way to take the energy out.The out put energy need not be the same type of  input energy.\nIn any machine as per conservation of energy the input and out put energies  must be equal.\n But what we speak of efficiency of a machine is the ratio of the useful out put energy to the input energy.\nNaturally this will be less than  the total out put energy. It follows efficiency is less than 100%.\nBut we can try our best to reduce the unused energy (not used for our purpose)to be the minimum possible.\n\nFor example in machines due to friction many energy is being lost as the parts are heated. But with out friction no parts will work. So  some minimum amount of energy has to be wasted (wasted according to us and not according to nature). \nA car rolls down the road because of friction and the same friction reduces efficiency. \nThe efficiency of an incandesant bulb is low because the useful  light energy is low compared to the input electical energy and most of the energy is wasted as heat energy.\nThe florescent bulb has high efficiecy compared to the ordinary bulb because less amount of energy is not used for our purpose.
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Check this site out.\n\nhttp://www.usoe.k12.ut.us/curr/science/sciber00/8th/machines/sciber/lever3.htm
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a compound machine would involve multiple mechanical devices.  For example a pulley connected to a lever which is connected to a gear system would be a good example.  This would be used possible to mechanically lift a load.
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advantage:\n\nfriction, resistance offered to the movement of one body past another body with which it is in contact. In certain situations friction is desired. Without friction the wheels of a locomotive could not “grip” the rails nor could power be transmitted by belts. \n\ndisadvantage:\n\nOn the other hand, in the moving parts of machines a minimum of friction is desired; an excess of friction produces heat, which in turn causes expansion, the locking of the moving parts, and a consequent breakdown of the machinery. Lubrication is important in minimizing friction as are also such devices as ball and roller bearings.
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Power:\nP=dE/dt = dW/dt\n\nForce:\nf=ma\n\nEnergy:\ne=mc^2
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We shall apply logic and find answer.\n\nForce is a push or pull.\nWhen A pushes or pulls B, in Physics, we say A exerts a force on B\nWhen A exerts a force on B, three things may happen. 1. B is accelerated.  2. B is moving with constant velocity. 3. B is in rest.\n\nB is accelerated if no other forces except the one exerted by A acts on B. The other two happens when some other forces also act or not even a single force acts. \n \nWe shall consider the first case in which B is acted on by a force exerted by A.\n\nThere are three things which cannot be ignored when we speak of a force.\n1. “A” the one which exerts a force\n2. ‘The Force’ that acts on B.\n3. “B” the one on which the force acts. When the concept of force is understood “B” can a point.\n\n  The statement, “The force acts on B” implies that A is the cause of the force. \n\nHow can A apply a force? Physics answers, ‘Because it has energy to do so,’\n\nWhat happens to A and B when it exerts a force on B\nWhen there are no other forces except the one exerted by A on B, A looses energy and B gains energy.\n\nAs long as A exerts force on B, B is in motion (accelerated) by the force  \nIn Physics we say when a force acts, the one on which the force acts gains energy and the one that exerts the force looses energy and it is seen the gain and loss are equal.\n\n In cases 2 and 3, if we remove the extra forces acting on them the situation reduces to case 1 and the principle persists.
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Generally, the force is applied at the point of "input force" - that point is determined by what class of lever you're using.\n\nFor example, if you're using scissors (First class lever), the fulcrum is at the pivot between the two handles and blades, the input force is at the handle, and the output force is on the blade.\n\nIf you're using, say, a wheelbarrow (2nd class lever), the fulcrum is at the wheel, the input is on the handle (end), and the output force is in the middle - in the bucket.\n\nFor a baseball bat (third class levers), the input force is in the middle (your hands), fulcrum at one end (you), and the output force is at the other end (the end of the bat).
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Torque is force*distance.\n\nFind the weight of the person (M*g) = 89kg *9.81m/s^2 \nM*g= 873.09 Newtons\n\nthere is a 1:3 lever arm there--> 4cm/12cm\nThe muscle is having to exert a force of 3*873.09N or 2619N\n\nThe torque around the pivot is 2619N @ 4cm (or .04m)\n2619N * .04m = 104.77N*m\n\nYour question says you want to "find the torque" yet you ask for the "forces pushing up".  Make sure you know which one you need.
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assuming that force is applied in the same direction that displacement....\nwork = force * displacement * cos(angle between force and displacement)\nwork = (10N)*(5.0m)*cos(0)\nwork = 50 Joule
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It depends if it is acting as a Force or a Pressure (a distributed Force). If it is a force, it has units of N (Newtons, or kg m/s²) and if it is a pressure it has units of Pa (Pascals, or N/m² which is the same as kg/(m s²))
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Some of the advantages are that a CNC (Computer Numerical Code [a computer controlled variant]) Mill can give incredibly accurate machined surfaces, edges and bolt patterns, and can reproduce that exact piece over and over, with barely a noticeable difference in one piece over another. Most differences come from irregularities in the stock or casting you want to machine. Mills can cut gears, ream key-ways or bore holes, make manifolds ... it goes on and on. There are different kinds of mills; there are the manually operated ones that take much care in setup and production of each piece, to single head mills with a battery of tools to do multiple operations, but only in one axis, to multi head, multi angle mills, which are like a legion on gnomes attacking a piece of metal, doing multiple operations at once, from shaping (all Mills can do this) one surface while another head is drilling and tapping holes, and yet a third is boring on another axis. The main disadvateges are that most mills in my experience are not very good at machineing round or spherical stock to a round or sphereical finished product, you use lathes for that. Another is the size, even a small mill can require about 3 meters square for setup and auxilliary equipment. Another drawback is the cost. These things aren't cheap and they use lots of electricity.
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OK, below is a list of websites that may give you ideas.  Try a couple of ideas and test them at home before taking them into class?\n\nUsing the clothespin as the main source of energy does not necessarily mean that the spring has to be the main driver of the machine?  It might be used more as a trigger release – thus allowing the clothespin to be the main release of the energy.\n\nGood Luck.