(3ab^2)(3ab)^2    simplify?
966048
(3ab^2)(3ab)^2\n(3ab^2)(9a^2b^2)\n27a^3b^4
937737
3a2(a-b) -6a(a-b) +21(a-b)\n(a-b)(3a^2-6a+21)\n3(a-b)(a^2-2a+7)
817461
a^4 - b^4\n\n= (a^2 + b^2)(a^2 - b^2)\n\n= (a^2 + b^2)(a + b)(a - b)
194716
x^2 + 13x + 52 + 160/(x-3)
944695
12 * (3-e^-3x)^3 *  e^-3x
1027973
the 3rd one is correct, but I get -(3+b)/b+2 and 2 for the first 2
966462
(6x^2)/(4x^2 y-12xy) * (x^2 + x - 12)/ (3x^2 + 12x)\n\nFirst, I would attempt to simplify if possible:\n2x(3x)/x(2xy-6y) * (x^2 + x - 12)/ (3x^2 + 12x )\n(3x) / (2xy - 6y) * (x^2 + x - 12)/ (3x^2 + 12x)\n\nRewrite to see if we can cross cancel:\n\n(3x)           (x^2 + x - 12)\n---------  *   -----------------\n(2xy-6y)    (3x)(x + 4x)\n\n1               (x^2 + x - 12)\n---------- *  -----------------\n(2xy-6y)     (x+4x)\n\nUnfoil the (x^2 + x -12 to see if we can further simplify\n\n(x^2 + x - 12) = (x -3)(x+4) so you will have:\n\n1             (x-3)(x+4)\n-------  *  --------------\n2y(x-3)      (x+4)\n\nBy simplification:\n\n1           (x-3)\n------   * ----------\n2y(x-3)     1\n\nBy Cross Cancel:\n1/2y
747277
5a+6b-3a+b=?\nSimplified= (2a+7b=?)  or (2a = -7b) or (7b = -2a)\nThey are all the same\n\n15x-3y-7x-4y=?\nSimplified = (8x-7y=?)  or (8x = 7y) or (-8x = -7y)\n\n15m-17n-23m+25n=?\nSimplified -8m+8n=? or (8n=8m) or (n=m)
1121270
This one can't be simplified further uness you just write\nsqrt{5+3sqrt{3}}.\n\nOn the other hand, sqrt{7+4sqrt{3}} can be rewritten as 2+sqrt{3}. Making such simplifications is not easy in general.
725255
1. (xy^2)^3 (x^2y)^2 + (x^3y^4)(x^2y^2)^2\n(x^3y^6)(x^4y^2) + (x^3y^4)(x^4y^4)\nx^7y^8 + x^7y^8\n2x^7y^8\n\n2. (3x^2)(3y^2)+ 3x^2y - (3xy)^2 - 3xy^2\n9x^2y^2 + 3x^2y - 9x^2y^2 - 3xy^2\n9x^2y^2 - 9x^2y^2 + 3x^2y - 3xy^2\n3x^2y - 3xy^2\n\nSimplifying is fun.\n\nBarjesse37
888747
I think you meant 3^0 + 3^1 + 3^2 + ... + 3^(n-1)\nNote the parenthese.\nIt reduces to (3^n - 1) / 2\n\na^0 + a^1 + a^2 + ... + a^(n-1) reduces to (a^n - 1) / (a - 1)
723313
Yes\n\n(1-2)^2 = (3-2)^2\n\n3 is not equal to one\n\na and c do not have to be equal since the terms are squared. On removing the squares, you have to account for both +ve and -ve roots.
658148
given 4a^2-12ab+9b^2\n    =(2a)^2-2(2a)(3b)+(3a)^2\n    =(2a-3b)^2
652728
a=b=i^(1/3)\ni=-1\nab+a^2b+ab^2 = [i^(1/3)*i^(1/3)] + [i^(2/3)*i^(1/3)] + [i^(1/3)*i^(2/3)]\n= [i^(2/3)] + i + i\n= -2+(-1)^(2/3)
211814
2x^2 +3x-6 well that is as simple as it can get unless you have a number for the variable x
641733
[-b +/-  sqrt(b^2-4ac)]/(2a)
123892
3(x – 2)^2 – 3(x – 2) – 6\n3((x-2)^2 - (x-2) -2)\n3(x^2-4x+4-x+2-2)\n3(x^2-5x+4)\n\n3(x-4)(x-1)\n\nYay!!