geometry hardest problem..ever.. WORD PROBLEM..help if you can..but its hard!?
952045
The first problem:\nThey would need to win 17 more seats, which would be 17/234, or 7.3%. The minimum whole percent would be 8%.\n\nThe second problem:\nThey would need to win 6 more seats, or 6/16 of the remaining seats, or 37.5%. The minimum whole percent would be 38%.\n\nThe third problem:\n229 is prime; 201 is 3*67; a=229 and b=3. ab=687.\n\nThe fourth problem:\nx could be 4. Then, a=5, b=5. The ratio would be 225 : 205.
787980
i believe this is a continuation of the previous prob.\n\nit can be solved graphically. \ndraw the lines x + y = 2,  y - x = 2 and y = -2 on the cartesian plane. the feasible reason will be the area enclosed by the triangle formed by these 3 lines. the vertices being (0,2) , (4, -2) and (-4, -2). it can be proved that the max value of 2x + 3y will be one of these vertices. \n\nsubstituting, u can see the maximum occurs at (0,2) whence 2x + 3y = 6
985579
Here's my answer:\n\nhttp://mudandmuck.com/str2/triangles.JPG\n\nYou didn't say write them out in English, you said describe.  This picture describes the solution.
1121982
look std 10 th NCERT mathematics text book... its in the part 2 of  mathematics in geometry section.
902666
This may possibly be the easiest question anyone has ever asked on this forum. If you can't figure this out yourself, you really need to do more homework!! BTW, that is one freakin' tall sheep!!
306191
a) cube...final answer
837128
My husband and I just used geometry the other day to estimate how much tile to buy for our 2 bathrooms.  Our bathrooms have a lot of irregular spaces, so we had to measure the entire perimeter of each bathroom.  We then split the bathrooms into different geometric shapes to find the area.  We had to work our formulas for several squares, rectangles, and triangles.   Then we added them all together to come up with the square footage.  After that, we had to estimate how many 12 inch by 12 inch tiles we needed.  It was pretty tricky, but my husband is a math whiz, so it's easy for him.  He's an engineer, go figure...
904256
there are 6 vertices and you form 4 triangles from the first 2, then 3, then 2, then 1 for a total of 14.\n\nNow we form other triangles that overlap and it gets really complex...\n\nI count 18 smaller triangles, for a total of 32 so far...\n\nNow middle triangles...\n\n36, for a running total of 68
863713
The only thing I remember about geometry is...a2 + b2 = c2.\n\nSomehow, I doubt that helps you.....sorry.
959479
all you need to do is go to www.webmath.com, it'll help u there!\n\nI always do my math problems to that site if ever i get stuck on something! It's helpful!
913268
Snow, i am sorry but i have no idea! i have some suggestions for helpful websites, though\n\ntry mathforum.org/dr.math/\n\nsorry i could not be more help ful!!! good luck
609208
hey try to think logically about the problem.. its really easy just too much words and it confuses you. so take a deep breath and then begin. take 25 % off of $375 and it will give you the answer..... im pretty sure about this but you cant trust me on those dog gone word problems, lol \ngood luck
48873
well i would like to pretend its a regular hexagon, in this case you would have to draw a line from one vertex to an opposite one, the line should meet at the center of gravity (the point where all 3 lines intersect)
938368
When u r solving a problem draw the figure first and mark it clearly. Visualization is the most important part in geometry.\nThe chapters r different becoz each chapter is another step 2 the next chapter. Try 2 remember the theorems studied earlier becoz u need them now. If u feel grounded, keep in mind, in ur book there is nothing u can't do with what u already know. If u hav enough time try 2 solve all the end of chapter problems on ur own.
880255
I can just give you a link to help you solve it.\n\nhttp://www.ticalc.org/pub/83plus/basic/math/geometry/
951948
When I do word problems, I break it down into manageable chunks.  After reading the entire problem once to get a sense of what I'm dealing with, I re-read each sentence one at a time and try to write down in mathematical terms what each sentence is saying.  Often each sentence is only a portion of the overall equation, but I find if I tackle it like this, I can piece together the overall equation by looking at all the partial equations I got from each sentence.\n\nHope this helps a little.  Good luck!\n\n~ ♥ ~
735406
Hint: the three side are equal long.\n\nTh