Algebraic expression`?
958614
#1.)-----------------------------------\n  \n25b^ -20by + 4y^\n\nMultiply 1st and 3rd term together to get 100b^y^.\n\nFactor 100b^y^ into two factors whose sum = the middle term of -20by.\n\n1by   X 100by\n2by   X 50by\n4by   X 25by\n5by   X 20by\n10by X 10 by   ....................BINGO!\n\n-10by + (-10by) = - 20by   &   (-10by)(-10by) = 100by\n\nThis is a really kewl factor by grouping trick, I LOVE it!\n\nBring down the first term of: (25b^)\n\nNext, write the SMALLER of the two factors 1st.  Followed by the LARGER of the two factors.  In this case, they're both the same, so it doesn't matter which one goes first: (-10by)\n\nFinally, bring down the third term of: (+4y^)\n\n25b^ -10by -10by + 4y^\n\nNow, lets factor by grouping! \nFactor out the GCFs.\nGCF#1 = 5b\nGCF#2 = -2y\n\n(25b^ -10by) + (-10by +4y^)\n5b(5b - 2y) -2y(5b - 2y)\n\nGCF#3 = (5b - 2y)\n\n(5b - 2y)(5b - 2y)\n\nSimplifies further as: (5b - 2y)^   ....Whatdayaknow?! \n.......................................................................................................It's a Perfect Square Trinomial.\n\n#2.)------------------------------------------------------------------\n\n100 - 9b^\n\nAh, the difference of two perfect squares.\n\n---------------------------------------------\n\nFORMULA:\na^ - b^ = (a-b)(a+b)\n\n---------------------------------\n\nSOLUTION:\n100 - 9b^\n(10)^ - (3b)^\n\n-----------------------\n\nANSWER:\n(10-3b)(10+3b)
817461
a^4 - b^4\n\n= (a^2 + b^2)(a^2 - b^2)\n\n= (a^2 + b^2)(a + b)(a - b)
908083
Tried to do it algebraically, that was a booger.\n\nI plugged that into mathematica and it gave me an error normally generated when the inverse of a function is needed to represent a solution and the solution variable occurs in more than one argument of that function.\n\nThat one might not have a solution?
179535
I believe it simplifies to n - w.\n\nHere's the expression you wrote: (a-y/w+n * w^2-n^2/y-a).\n\nHere's what I think it should look like:\n\n((a-y)/(w+n)) * ((w^2-n^2)/(y-a))\n\nBecause:\n\n((a-y)/(w+n)) * ((w^2-n^2)/(y-a))\n\n= ((a-y)/(w+n)) * ((w+n)(w-n))/(y-a)\n= ((-1)(y-a)/(w+n)) * ((w+n)(w-n))/(y-a)\n\nThe (w+n)'s cancel out, as do the (y-a)'s, so you're left with this:\n\n= (-1)(w-n)\n= (n-w)
764329
x(abs[x- (x^2)] (-1=2)\n\n:> peace\n.
268855
we have a^(-b)=1/(a^b), with this rule, the expression will be :\n[m^3/(m.n^5)]^(-3)\n=(m^2/n^5)^(-3)\n=1/(m^2/n^5)^3\n=n^15/m^6\nhope helped ^^
832515
(1) any of the following may be the root of the expression,+1,-1,+2,-2,+3,-3,+6 or -6.\nNow putting the value of x=-1,see ifthe value of the expression becomes zero or not?If it becomes zero,then x=1 is one factor of the expression,if it does not become zero try with =1,then -2.+2 and so on.\nLuckily for us,with x=-1,the value of the expression becomes zero\nTherfore,x+1 is one factor\nx^4++x^3-7x^2-13x-6\n=x^3(x+1)-7x(x+1)-6(x+1)\n=(x+1)(x^3-7x-6)\n=(x+1){x^2(x+1)-x(x+1)-6(x+1)}\n=(x+1)(x+1)(x^2-x-6)\n=(x+1)^2(x-3)(x+2)\n(2)Will you please check up the second one once more and if there is any correction send it to me through Yahoo answers.
883411
lets just simplyfy al of them :)\nThe expression is : -3m -2 + 5m -8 =  2m-10\n\nThe expression is : 4(3a - 5) + 2(-3a + 7) = 12a-20 -6a +14\n                                                                       =6a-6\nThe expression is : 2/3(1/2x + 9) + 3 = x/3 + 6 +3 = x/3 +9\n\nThe expression is : x/4 - 1/8 - x/6 + 1/6 = x/12 + 1/24\n\nThe expression is : 2ab + a - ab - 7 = ab + a -7.\n\nso i would say,, The expression is : 2ab + a - ab - 7 is closest to being in its simplest form than the rest
398761
the product contains the expression (x-x) which = 0 thus the product is 0
926880
(1+1)-2*3/2^2+2\n\nWithout useing Order of Operations: 2\n\nWith Order of Operations: 2.5
752414
An expression is a combination of numbers, operators, grouping symbols (such as brackets and parentheses) and/or free variables and bound variables arranged in a meaningful way which can be evaluated. 5+4 and 1/x+3 are both expressions.\nWhereas an equation is a mathematical statement that sets two expressions equal to each other; 2x-9=3x+17 is an example of an equation.
885758
2(-x+4)+3x=(-x)+3x\n(-2x + 8) + 3x  = 2x\nx + 8 = 2x\n(x + 8) - x = (2x) - x\n8 = x
554172
Um...\n\n2(-X) + 3(-X) + X + 8\n\n-2X - 3X + X + 8\n\n-5X + X + 8\n\n-4X + 8\n\n8 - 4X
896553
4x^2+8x-x-2\n(4x-1)(x+2)
1132938
I can help you with the part of  "Identify the expression that completes the equasion so that it is an identity.\nsin^2x/(1-cosx)"\n\nYou got sin^2x/(1-cosx). Then to complete the equation you multiply[(1+cosx )/(1+cosx)] to the equation.  \n\nThen you get {[(sin^2x)(1+cosx)]/[(1-cosx)(1+cosx)]}...Then by factorization you get that {[(sin^2x)(1+cosx)]/(1-cos^2)]}....The (1-cos^2) is the same as to sin^2x.  \n\nThen you cancel the terms sin^2x/(1-cos^2)...It leaves the equation as following ==> (1+cosx)(1) = (1+cosx)\n\nHope someone helps you with the rest SOrry
8373
(([(4+4+4).(4+4)]+4)/4)*(4+4)\n\n(4+(4*4)).([(4+4+4).(4+4)]+4)
533029
Let's call :\n(a) : x + 2y < 3\n(b) : 2x - 3y < 6\n\nWith the 1st one:\nx + 2y < 3\n<=> 2x + 4y < 6 \n\nThe 2nd one is 2x - 3y < 6\nThat means : \n(a) - (b)\n<=> 4y - (-3y) < 0 \nor 7y < 0 \nor y < 0\n\nWe have also: 2x - 3y < 6 <=> (2/3).2x - (2/3).3y < (2/3).6\n<=> (4/3)x -  2y < 4\nThat means:\n(a) + (b)\n<=> x + (4/3)x < 7\n<=> (7/3)x < 7\n<=> x < 3\n\nSo : x < 3 and y < 0