What is the square root for 40.5?
966435
square root of 40.5 = 6.363961.\n\nAnd for the future.... http://www.calculator.com/
712870
You only can say\nRoot[x^2 - 25x + 40]\nType for x sq only x^2.\n\nTh
806633
π^40=76912142205157127257.265187923789\nπ^40=7.6912142205157127257265187923789e+19
767712
First you find the square root of both the numerator and the denominator which would end up being √5/√8. This would be a fine answer, but in my math classes teachers have had rules against keeping a radical in the denominator. so, to get rid of that multiply √5/√8 by √8/√8, which gives you √40/√64, or √40/8.
61372
both stetements are true because 40/4 = 10 and the square root of 100 is ten so that is my explanation.
909546
The square root of a number is just the number which when multiplied by itself gives the first number. So 2 is the square root of 4 because 2 * 2 = 4.\n\nStart with the number you want to find the square root of. Let's use 12. There are three steps:\n\n   1. Guess\n   2. Divide\n   3. Average.\n\n      ... and then just keep repeating steps 2 and 3. \n\nFirst, start by guessing a square root value. It helps if your guess is a good one but it will work even if it is a terrible guess. We will guess that 2 is the square root of 12.\n\nIn step two, we divide 12 by our guess of 2 and we get 6.\n\nIn step three, we average 6 and 2: (6+2)/2 = 4\n\nNow we repeat step two with the new guess of 4. So 12/4 = 3\n\nNow average 4 and 3: (4+3)/2 = 3.5\n\nRepeat step two: 12/3.5 = 3.43\n\nAverage: (3.5 + 3.43)/2 = 3.465\n\nWe could keep going forever, getting a better and better approximation but let's stop here to see how we are doing.\n\n    3.465 * 3.465 = 12.006225\n\nThat is quite close to 12.
755615
24 -- I used a calculator\n\nIf you wanted to take a guess, you could do this:\n\nNotice that 20^2 = 400 and 30^2 = 900, so √576 is in between 20 and 30.\n\nThen notice that 576 ends with a 6, and ask yourself what two numbers between 0-9 when multiplied together produce a number ending with 6?  The answer is 4 and 6.\n\nSo, since you know your answer is between 20-30, and ends with a 4 or 6, you could try 24*24 and 26*26 to see what you get. \n\nIn this way you could, using some deductive reasoning and just a little trial and error, find that √576 = 24.\n\nHope that helped!\n\n~ ♥ ~
973521
=5.2*5.2*10^-5\n=27.04^10^-5\n=2.704*10^-4
543808
The square root of 3.14159265 is approximately 1.77245385.
699204
4.3 x 10^5 = 430,000\n\n4.3 x 10^-5 = .000043\n\nYou just move the decimal either left or right, based off of the exponent.  If it's 5, you move it the right 5 spaces.  If it's -5, you move it to the left 5 spaces.  Fill in empty spaces with zeros.\n\nIf you have a specific question, email me, otherwise, that's really all there is to it.
282417
radical is sqrt? i think\n\n10 sqrt(20) / sqrt(64)=\n10 sqrt(4*5) / 8 =\n10 * 2 * sqrt (5) /8 = \n20 * sqrt (5) / 8 =\n5 sqrt(5) /2=\n2.5 radical 5
258864
there is a method of getting the square root of any number!!\n\nfirst, group the digits in two's, starting from the decimal pt.\n\n1'23'45'43'21.00'00\n\nThen, do the ff:\n1.Get the sq.root or the nearest sq.root of the first group of digits (sqrt3=1, sqrt5=2), that is the first digit of your square root.\n2. Square that number and subtract it from the first group of digits. Bring down the first digit of the next pair of digits.\n3. Multiply the digits of your sq.root by 2 and use this as the divisor of the numbers you brought down. this will be the next digit of your sq.root. Put it next to the previous digit.\n4. then, multiply, and subtract, just like in division. Bring down the next digit of the pair.\n5. Square the so far last digit of the sq.root, and subtract this from the brought-down number.\n6. Repeat the steps until the right decimal pt.\n\nThus,\n\nsqrt1'23'45'43'21\n\nsqrt1 = 1 (1st digit)\n1x1 = 1\n1 - 1 = 0\nBring down 2\n\n1x2 = 2\n2/2 = 1 (2nd digit)\n1x2 = 2\n2-2 = 0\nbring down 3\n1² = 1\n3-1 = 2\nBring down 4\n\n11x2 = 22\n24/22 = 1 (3rd digit)\n1x22 = 22\n24-22 = 2\nbring down 5\n1²=1\n25-1=24\nBring down 4\n\n111x2=222\n244/222=1 (4th digit)\n1x222=222\n244-222=22\nBring down 3\n1²=1\n223-1=222\nBring down 2\n\n1111x2=2222\n2222/2222=1 (5th digit)\n1x2222=2222\n2222-2222=0\nBring down 1\n1²=1\n1-1=0 STOP..\n\nThe answer is 11111.^_^
308931
sqrt(160) = sqrt(16*10) = sqrt(16)*sqrt(10) = 4 sqrt(10) ~ 12.6491
383203
Renee, do you know what a square root is? It's a number, which, when multiplied by itself, gives the original number. So the square root of 900 is 30, because 30 * 30 = 900. That is called the "principal" square root.\n\n900 also has a negative square root, -30, because\n\n-30 * -30 = 900 also.
746280
c^2 = 3^2 + 4^2\nc^2 = 9 + 16 = 25\nc = square root (25) = 5
31612
just remember that i equals the square root of -1.  every time you see a negative square root split it up:  square root of -16 = sqare root of 16i = 4i.\n\nif you have 4i x 5i, then you multiply and get 20i^2 and since i is the square root of -1, i^2 = -1.  so 4i x 5i = -20.\n\nhope that helped a bit...
1169888
If you're looking for the exact answer, then I would start by rationalizing the denominator.\n[sqrt(5) - 2]/[sqrt(5) + 2]\n= [(sqrt(5) - 2)(sqrt(5) -2)]/[(sqrt(5) + 2)(sqrt(5) -2)]\n= [5 - 4sqrt(5) + 4]/[5-4]\n= [9 - 4sqrt(5)]/1\n= 9 - 4sqrt(5)\nNow you are looking for [x^3 + 1]/x^3\nx = 9 - 4sqrt(5)\n[x^3 + 1]/x^3\n= [(9 - 4sqrt(5))^3 + 1]/(9 - 4sqrt(5))^3\nYou need to multiply (9 - 4sqrt(5))^3\n(9 - 4sqrt(5))^3 = (9 - 4sqrt(5))(9 - 4sqrt(5))(9 - 4sqrt(5))\n= (81 - 72sqrt(5) + 80)(9 - 4sqrt(5))\n= (161 - 72sqrt(5))(9 - 4sqrt(5))\n= 1449 - 644sqrt(5) - 648sqrt(5) + 1440\n= 2889 - 1292sqrt(5)\n[x^3 + 1]/x^3\n= [2889 - 1292sqrt(5) + 1]/[2889 - 1292sqrt(5)]\n= [2890 - 1292sqrt(5)]/[2889 - 1292sqrt(5)]\nRationalize this to get your final answer.