only to expert (god mode )?
957722
Fermat's Last Theorem states that \nx^n + y^n = z^n \n\nhas no non-zero integer solutions for x, y and z when n > 2. \n\nHis proposition was about an equation which is closely related to Pythagoras' equation. Pythagoras' equation gives you:\n\nx^2 + y^2 = z^2\n\nYou can ask, what are the whole number solutions to this equation, and you can see that:\n3^2 + 4^2 = 5^2\nand\n5^2 + 12^2 = 13^2\n\nAnd if you go on looking then you find more and more such solutions. Fermat then considered the cubed version of this equation:\nx^3 + y^3 = z^3\n\nHe raised the question: can you find solutions to the cubed equation? He claimed that there were none. In fact, he claimed that for the general family of equations:\nx^n + y^n = z^n where n is bigger than 2\n\nit is impossible to find a solution. That's Fermat's Last Theorem.\n\n\nProof : \n\nn = 3\n\nx^3 + y^3 = z^3 has integer solutions -> xyz = 0\n\n(1) Let's assume that we have solutions x,y,z to the above equation.\n\n(2) We can assume that x,y,z are coprime. \n\n(3) First, we observe that there must exist p,q such that \n\n(a) gcd(p,q)=1\n(b) p,q have opposite parities (one is odd; one is even)\n(c) p,q are positive.\n(d) 2p*(p2 + 3q2) is a cube.\n\n(4) Second, we know that gcd(2p,p2+3q2) is either 1 or 3. \n\n(5) If gcd(2p,p2+3q2)=1, then there must be a smaller solution to Fermat's Last Theorem n=3. \n\n(6) Likewise, if gcd(2p,p2+3q2)=3, then there must be a smaller solution to Fermat's Last Theorem n=3.\n\n(7) But then there is necessarily a smaller solution and we could use the same argument on this smaller solution to show the existence of an even smaller solution. We have thus shown a condition of infinite descent.\n\n\nI can not have much explaination about in general n. Anyways, that was a real nice question.\n\nI read this somewhere, its not my creation. \n\nAll the best and have nice time
490351
Anytime Anywhere press F1 for help.\n\n(it works for all softwares)
760258
Hello Fred,\nWhy not pray to God yourself? \nGet to know him - his name & purposes & plans for the earth & mankind & the future. His requirements. In this way, you will be able to form your own relationship with the Creator of the universe & ask prayers for yourself.\n\nYou should not rely on other people in this way:- PSALM 146:3\n\nPlease have a look at :\nhttp://www.watchtower.org/library/w/1996/7/15/article_02.htm\n\nhttp://www.watchtower.org/library/w/1996/7/15/article_01.htm\n\nHope that helps :-)\n\n\n\n.
796286
Well Mr Perfect , if you are that good then you should be able to answer your own question. Dontcha think?
1069433
if noone answers you can i get best answer?
1000168
can't fail with this answer 'Only God knows'
1135585
HAY IT WILL B UR GREATNESS IF U TEACH ME THE SAME.I REALLY NEED IT VERY BADLY...PLZ DNT TAKE IT AS A JOKE
1001638
not sure if it is on this site but worth to check it out\n\nhttp://expertfootball.com/training/tricks.php
744788
Try Guru.com (http://www.guru.com/)
14663
You might try Beliefnet.
689576
YES YOU CAN.\n\nBut like Gadget, I haven't figured it out yet.
86556
You have two options.. Both are extreme.. Become very God-based and spiritual.. Or... D-I-V-O-R-C-E..
960966
TRY ARES IT KICKS MAJOR A(S(S
721772
TRUST GOD.\n\nMAKE A SELF-EXPERIMENT.\n\nSEEK EXPERTS ADVICE.\n\nDONT BELIEVE ANYTHING WITH EYES SHUT.\nANALYSE EVERYTHING.CONSIDER THE POSSIBLITIES OF BOTH SIDE.
204319
wot a stupid question
621608
according to me it is not possible still take advise of some expert
330602
See Amit Wikid. What more is there to say.\n\n    And Zen