What does the slope of an acceleration vs. force graph represent?
962881
if acceleration is on the x axis, the slope represents 1/mass\n\nas\n\nslope = x/y = acc/force\nand\nforce=mass x acc\nso\nacc/force=1/mass\n\nif force is on the x axis, the slope represents mass\n\nas\n\nslope = x/y = force/acc\nand\nforce=mass x acc\nso\nforce/acc=mass
819742
The first derivative is the slope of the line that is tangent to the graph.  If there is a maximum or minimum, the tangent line at that point will be horizontal, so its slope is 0.  \n\nThe second derivative is 0 when there is an inflection point. An inflection point is a place on the graph where it changes the direction of the concavity. \n\nIn the two cases above, the converse is not necessarily true.  That is, just because the first derivative is 0 doesn't mean there has to be a max/min there.\n\n If the second derivative is positive, the graph is concave upward which means like a regular "U".  If it's negative, it's concave downward like an upside-down "U".
1171507
Acceleration (A) is a vector. In addition to a value, it also has a direction. As does force (F).\nWhen an object is pushed uphill, A and F have values and the direction is upward (appropriately defined depending on the co-ordinate system used).\nSimilarly, when an object is pushed downhill, F and A point downward.\nSo, yes. It works for objects being pushed uphill and downhill.
113710
Well, the y-intercept would be acceleration when the force on the object is zero.  You'd better hope it's zero!  If it's not, you might want to fix the point in your analysis (this can be done in Excel) or redo the experiment.\n\nEdit: If you're plotting acceleration vs. force, the intercept really should be zero.  Those values appear small enough to be within the error of the experiment.  They could be indicative of the effect of a systematic error, but are more likely the result of random noise.  Try fixing the intercepts at zero in Exel (right-click on the regression line and open up the options for it; there should be a checkbox for "fix intercept").  An intercept value that is not equal to zero indicates that there was acceleration when there was no force!
547413
On a graph, a line can have a slope. The slope is defined as how many spaces the line moves up or down divided by how many spaces the line moves left or right from any two given points. You may see it written as\n\nrise\n----\nrun\n\nOR\n\nchange in Y\n-----------\nchange in X\n\nOR\n\n{for the line through points (X1, Y1) and (X2, Y2)}\n\nY1-Y2\n-----\nX1-X2\n\n\nA line from upper right to lower left will have a positive slope.\nFrom upper left to lower right will have a negative slope.\nStraight up and down will have an undefined slope.\nLeft to right will have a slope of 0.\n\nHope this helped! Good luck!
668559
when a body is in limiting equilibrium on an inclined plane then the inclination of the plane with the horizontal is called the angle of repose.it is denoted by greek letter alpha.tangent of alpha=mu<greek letter meaning coefficient of static friction.\n u might hav got it now tht its a term related to friction
454697
Which graph du you use? velocity verses time or velocity versus distance?
787000
slope is equivalent to dy/dx = y'\n y = x -1\ndy/dx = dx/dx -0\n dy/dx = 1\n   y' = 1\nTherefore the slope of the given equation is 1.
898061
No.\n\nIt means that the slope of the curve y = x^2 at a given point is equal to twice the value of x at that point.\n\nThe change in y for an infinitesimally small change in the value of x is equal to twice the value of x at that point.\n\nYour interpretation, "for every change in x there is a change of 2 [in y]", would correspond to a derivative (or slope) of 2, not of 2*x.  The function, y = 2*x + constant would have a derivative dy/dx = 2.
281933
what is on the axes?\n\nthis is the best i could find for you...\nIf a graph shows time on the horizontal axis and speed on the vertical\naxis, a straight horizontal line across the graph would indicate?\n\na. no motion\nb. constant speed\nc. steady acceleration\nd. maximum speed\n\nANSWER:\nb. constant speed.\n\n\nIn effect, the horizontal line in the graph indicates that for every\nvalue of the horizontal axis (time) corresponds the same value on the\nvertical axis (speed), i.e. the same speed for every time, that is a\nconstant speed.
985550
consider the forces on the block:\n\nThe force of gravity\n\nThe frictional force\n\nWhen the forces are translated into the frame of reference of the surface of the slope,\nthe forces parallel to the slope are:\n\nfriction:\n0.60*cos(60)*m*g\nWeight\nsin(60)*m*g\n\nnote that in order for the block to be sliding down the slope, the parallel component of the weight must be greater than the frictional force \nor sin(60) must be greater than .6*cos(60)\nwhich it is\n\nTo compute the acceleration,\nF=m*a\nwhich is\nm*a=sin(60)*m*g-0.60*cos(60)*m*g\ndivide out the mass\na=g*(sin(60)-0.60*cos(60))\na=5.55 m/s^2\n\nb)  For this part, only the force necessary to overcome kinetic friction plus the parallel weight is necessary to keep it moving up the slope.  Since it was given a shove and we don't know how much force was applied in the shove, we can only compute the minimum force necessary to over come kinetic friction and weight\nF>g*m*(sin(60)+0.60*cos(60))\n\nj
368233
N is Newtons, a unit that measures force. For every 1kg of something, if it accelerates at 1 meter per second per second (m/s/s or meters per seconds squared), than there is a force of 1N acting on it.\n\nForce is calculated by multiplying the mass (not weight) with the acceleration. For example, if you are 75kg, than there is a force of 75kg X 9.8 m/s/s (acceleration due to gravity: roughly constant on Earth) = 735N pulling you down. BUT, there is a reaction force, in this case the NORMAL, pushing you back up at the same time and force. Therefore, the force pulling you down, 735N, take away the NORMAL, also 735N, and you will have a NET FORCE of 0N because you are stationary. \n\nSo in order to resist something pulling at 14N (ignoring air resistance, friction, etc), it needs to pull back 14N.
928890
The slope of a line can tell you how to get from one point on the line to another. If the equation is a linear equation, a straight line, then just by knowing one point and the slope you can graph the function because the slope will tell you how to get to the second point you need.\n\nFor instance, if you are told that a line goes through the point (0,2) and has a slope of 1/2 you can plot the second point and connect the dots to draw your line. Since the slope is "rise/run" you have to "rise" one and "run" two to get to another point. "Rising" 1 from 0 gets you to 1, and "running" 2 from 2 gets you to 4. So the next point is (1,4).\n\nIn a more general sense, the slope of a of a graph tells you how quickly the function is increasing or decreasing. For instance, the function f(x) = x^2 has a slope of 2x (trust me on this) where as the function g(x) = 2x^2 has a slope of 4x. What this means is that g(x) increases twice as quickly as f(x). If you look at these two lines on the same graph, it is evident that one increases much more quickly than the other.\n\nIf you progress on into higher mathematics courses, you will see how important the concept of the slope is, especially in Calculus.
45255
5 is where you put the first point on the Y axis. Count up 5 in the middle and put a dot.\n\nIf it has X by it it is the slope.\n2x means the slope is 2, or, 2/1, which means move up 2 and to the right one and put another dot.\n\n\n|    /\n|  /\n|/\n|\n|\n|\n|___________
845136
a good way to describe slope is change in one variable with respect to another.  Thus the rise over run analogy.  Rise is vertical (y-axis) while run is horizontal (x-axis).  In real world applications, the horizontal is oftentimes time, but not necessarily, so slope is often a change in time.
142488
Instantaneous speed, as the name indicates, is measured at a particular instant of time. From a math standpoint, by calculating the first derivative of the displacement function, you can use the result to calculate the speed at any instant of time. In other words, the instantaneous slope of the displacement function is equal to the instantaneous speed.\n\nIf you look at graph of a moving object (displacement vs. time), if you see a steep slope, this means that the object's speed is fast relative to a curve with a moment of shallow slope. How much distance are you moving per unit of time? The more distance you move, the faster your speed. Decrease that unit of time to almost 0, and you'll get instantaneous speed.
948944
The friction force would be the component of the force parallel with the path of the biker.  Friction is usually given as:\n\nForce of Friction=Coefficient of Friction*Normal Force\n\nYou dont even need to worry about that stuff, because friction is the only thing resisting the motion, the biker being on an incline down will be accelerated by gravity, but this is resisted by friction, equally because the rider doesnt accelerate\n\nSo you know that\nFriction=Parallel Component of Gravity=m*g*sin(10)\n\nNow the angle remains the same on the uphill side, so you know that the friction will be the same.  Now however, friction and gravity arent cancelling each other out, they are helping each other fight the biker back down the hill. So now its \n\nFriction+Parallel Component of Gravity=Force required\nFriction=Parallel Component of Gravity\nForce Required=2*Parallel Component of Gravity.