a concrete ix requires 3 parts sand and 5 parts cement.how many pounds of cement are needed for 75 pounds of?
963883
Cement : sand = 5 : 3\nSo 3 parts = 75 pounds\nSo 1 part = 25 pounds\nThus cement needed = 5 parts = 125 pounds
1107204
You are looking for cubic yards. If you have your length and width in feet take those dimensions and divide each by 3 that will make them yards. If your depth is in inches divide it by 36 and that will give you your yards. After you get those figures multiply the 3 together l * w * d = cubic yards. If you are ordering concrete and I'm assuming you are, that is how many yards you need plus some extra.
353215
I work in a hardware store, just as an introduction.  So I am cheating because I know the "rule of thumb" that has all the other factors in it like density and stuff.  Quickcrete (TM) says that an 80lb. bag of premixed concrete will do 2/3 of a cubic foot.  There are 27 cubic feet per cubic yard, so it takes about 40 80lb. bags per cubic yard (at a hardware store they just say "yard" and mean cubic yard).  One bag does one two foot deep fence post, not that anyone asked.
708143
add the parts together 4 + 1 = 5\ndivide the 100 by 5 = 20\ntherefore one part = 20\nyou need one part of cement = 20kg\ni hope that helps
95602
2:3:1/2 cement sand water\n2:1:2:1/2  cement gravel sand water
312260
It's about 10 lbs per square foot. (Multiply the density of steel, about 490 pounds per cubic foot, times the thickness of the plate in feet, 1/4 in. = .02 ft.) I'm assuming you mean 1/4 in. plate.
855352
I make it that 636" x 97" x 100" is roughly 16 meters by 2.5 meters each way, only 100 cubic meters, so you need 7 more trailers.
856161
By unit volume, probably dry cement is heavier. Why? Because rocks are heavier than water.
767488
Divide the 1000 pounds by the 7 inches.\n\nThis will tell you how many pounds is required for each inch of compression.  Now multiply that by the additional 5 inches.  This will tell you how many more pounds of compression is required for the extra 5 inches of spring.\n                                              \nEdit:  I see this as being 714.285714
488838
75 Kilograms = 165.3467 pounds\n\n75 Kilograms = 200.9422 pounds(troy)
978750
You need to buy nine yards to cover 231 square feet to 4 inches depth: Volume = depth x area = 4/12 x pi x 42^(2) / 8 = 231 cubic feet, assuming the semi circular driveway is half of a circle with diameter of 42 feet. There are 27 cubic feet in a cubic yard (3x3x3) so 231 cubic feet is about 8.55 cubic yards, which I rounded up to nine. More or less about ten pickup trucks full of topsoil.\n\nA bag of grass seed that covers 1000 square feet will allow you to seed the patch (231 square feet) three times with some left over.
899361
4 pieces.\n\n12 * 2 is 24\nand 24/6 is 4
787203
first find the area of Mr.brown's lawn by the equation A=lw\nit will be A=25 x 50 = 1250 square feet.\nNow,some fraction 4/500=x/1250 where x is your answer.\ncross multiplication will give you x =10 pounds\nso you need 10 pounds of fertilizer.
863404
The gravel chips have density about 2.9 to 3.0 gm/cc.  The problem is estimating their packing factor.  Using 0.55, we have say 1.62 gm/cc therefore 1.62 tonne per cubic metre.  The actual chip size doesn't come into the calculation, so sand ought to be the same, except that if the grain size varies a lot then the packing factor could maybe go up to 0.65 as small grains fill the spaces between larger grains, but still just under 2 tonne/m3.
708751
Material - Portland Cement\n Bulk Density- 1,2-1,36\n Max Angle of Inclination - 20\n Repose Angle - 39
1027487
Not enough info to answer correctly.\n\nDo you mean and 18" diameter circular pool\n\nOr an eighteen inch deep pool of undertermined dimensions\n\nfurther what is the weight and mass of the sand.\n\nWhat I can tell you is that will will take 2 cubic inches for every square inch of pool\n\nan 18" square pool has an area of 324" therefore 648 cubic inches  for example
124675
75 times 3 = 225 so its $225.00