determine whether x+0=x is sometimen,alwsys,or never true. explain your raesoning?
955603
x+0=x is always true. This is the definition of the identity property of addition.
565951
the answer is zero b'coz at the end, X-X is equal to zero.
200150
for all of those, all u do is set once variable at a time equal to zero. for instance..\n\n-x+0=2\n-x=2  <--- multiply x and 2 by -1\nx=2\n\nthen..\n\n0+y=2\ny=2
112971
There's a problem with equation. Go back and check it.\nAs it stands, no x would satisfy this.\nInfity is an abstraction, not a number.
965748
|x - x²| \n= x - x² for x - x² ≥ 0\n= x² - x for x - x² < 0\n\nx - x² = x(1 - x) = 0 when x = 0 and x = 1\n\nSo x - x² ≥ 0 when 0 ≤ x ≤ 1\nand x - x² < 0 when x < 0 and x > 1\n\nSo  dx under the interval [-1,3]\n\n= ∫(x² - x) dx under the interval [-1, 0] +\n∫(x - x²) dx under the interval [0, 1] +\n∫(x² - x) dx under the interval [1, 3]\n\n=  [⅓x³ - ½x² ] [-1, 0] + [½x² - ⅓x³] [0, 1] + [⅓x³ - ½x² ] [1, 3]\n\n= [(⅓0³ - ½0²) - (⅓ (-1)³ - ½ (-1)²) ] + [(½(1)² - ⅓(1)³) - (½0² - ⅓0³)] + [(⅓ 3³ - ½ 3²) - (⅓1³ - ½1²) ]\n\n= [5/6] + [1/6] + [9/2 + 1/6]\n\n= 5 2/3
1048409
It can be anything.  If you follow the sequence to (x-x) you will get an answer of 0 for the entire equation.
1032037
it is any number smaller then 4, for example 3.99999 or 2, or 0.00001, BUT NOT zero itself!!! (0=0, and not 0<0)\n\nSo x<4 is WRONG, the answer is: \nx<4 AND x is not equal to 0\nBUT x CANNOT be a negative number either, as -1(-1-4)=5!!\n\nSo the final answer is: \nx<4 and x>0 --- any figure will match your condition\n\nThanks for the math!
863581
You have a couple of typos, I think.  As for the "proof", dividing by x - y is dividing by zero.  That is a no-no.  (In other words, a * 0 = b * 0 does not imply a = b.)
468001
x+2 must not be 0\nso x must not be -2\ndomain is \nall real numbers - (-2)\nall real no except -2
238404
thanks 4 voting my answer as best but i didnt understand what u said\no divided by any no is always zero and with exception of zero where i guess it's not defined(aint that also zero iam not sure)
553751
Definition of Absolute Value of x, |x|\nIf x >=0, then |x| = x\nIf x < 0, then |x| = -x
365867
2x - (7 + x) <= x\n2x - 7 - x <= x\nx - 7 <= x\n-7 <= 0\n\nSince we're left with a statement with no variables, and the statement is true, x = all real numbers.
103423
NO !!\nwhere is the double negatives ?\nu just replaced " Behind" with " in front" !!\n\nin Logic,   if X = Y  then   not not X = y  \nbut u cannt say    ( not X =y )
500255
This is called an inequality. First, find the zeros (in this case, -4 and 9). Next, make a number line:\n<------(-4)----------(9)----->\nNow, determine where inside and outside the zeros the inequality will be true or false. Finally, express your answer in terms of the inequality.\nExample: x+12 > 0\nAnswer: x > -12
62352
t can be any from negative infinity to positive infinity.  It doesn't matter because the 0 in the numerator makes this equation zero, ALWAYS.  The only thing t cannot be is 0, since the denominator cannot be zero.  That would make the equation "undefined."\nWas that your question?
918808
wouldnt it be like 3<x<-3 f(x)\nso like x would be 1 so it would be just f if you really want to simply that far done.
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.