What is the  four VB data type other than numeric data type?
966072
This link gives all the data types.\nAs you already know the numeric ones I suggest you remove them from the list so that you are left with the four you require.
362816
You could try and make a public const in the general declartions area ( I think its still called that ) , something like so\n\nPublic const convert = 2.54\n\nIm not sure if it will require quotes around it or not and you may have to also assign it afterwards ( Not sure on that either, I havent really used vb.net much.\n\nSo it may be \n\nPublic const convert\n\nconvert = 2.54\n\nor it could just be a simple matter of putting quotes around it ie\n\nPublic const convert = "2.54"\n\nLet me know what works :)
383056
what kind of program are you doing?? all i know is visual basic stuff
751189
If you are under Windows you can turn on NumLock, and use Alt plus codes on the number pad to do some of them (Alt-253 = ², Alt-171 = ½, Alt-251 = √, etc.) \n\nAlternatively, you can use Character Map utility under Start > All Programs > Accessories > System Tools.  Then you can get lots of others:\n°±²³ΦΘΠⁿ⅓⅔⅛⅜⅝⅞∆∏∑√∞∫≈≠≤≥\n\nFeel free to copy these from here too...
923765
Public Function FindDelimitedString(ByVal s As String, ByVal startDelimiter As String, ByVal EndDelimiter As String) As String\n        Dim beginPosition As Integer\n        Dim endPosition As Integer\n\n        If (s.Length > startDelimiter.Length + EndDelimiter.Length) Then\n            beginPosition = s.IndexOf(startDelimiter)\n\n            If (beginPosition >= 0) Then\n                beginPosition = beginPosition + startDelimiter.Length\n                endPosition = s.IndexOf(EndDelimiter, beginPosition)\n                If (endPosition >= 0) Then\n                    Return s.Substring(beginPosition, endPosition - beginPosition)\n                End If\n            End If\n        End If\n\n        Return String.Empty\n    End Function
873325
Put this in the form code where txtQuantity is the name of the text box. This will only allow the keys listed by Ascii value. Everything else produces a beep. This is made for text boxes, but you can use on any form control just change the form name. Text boxes are easier to work with than input boxes anyways.\n\n8 = backaspace\n9 = tab \n46 = decimal\n48-57 are number values\n\nPrivate Sub txtQuantity_KeyPress(KeyAscii As Integer)\n    Call NumbersOnly(txtQuantity, KeyAscii)\nEnd Sub\n\nPut this in a module so you can call it from any form.\n\nPublic Sub NumbersOnly(TextBox As TextBox, KeyAscii As Integer)\n    Select Case KeyAscii\n        Case 8, 9, 46\n        Case 48 To 57\n        Case Else\n            KeyAscii = 0\n    End Select\nEnd Sub
65676
VB.Net code uses .Net library classes where as VB code dont.\nalthough you can use a convertor to convert your old vb project int vb.net but reverse is not possible.
728764
Kindly go to www.allexperts.com\nChoose computing category. then Programming--Basic--Visual Basic\nYou can post your query there with one of the experts.\nThey will reply you free of charge
330673
Well for an official and thorough comparison between Visual Basic 6.0 and Visual Basic .net refer http://www.microsoft.com/learning/syllabi/en-us/2562bfinal.mspx\n\nCoz let me tell you will find wat you are looking for and which we all also won't be able to tell you.
273902
Here are functions to go both ways from my Calculator program in VB6. You'll have to convert it into C++, but that shouldn't be too hard. E-mail me later if you can'c figure out how to convert it to C++...\n\n' sRomanStr = GetDecRomanStr( 234 )\nPublic Function GetDecRomanStr(ByVal xDecimal As Double) As String\n    Dim iThousands, iHundreds, iTens, iOnes As Integer\n    Dim sReturnStr As String\n    Dim sHunds(9) As String\n    Dim sTens(9) As String\n    Dim sOnes(9) As String\n    \n    sHunds(1) = "C"\n    sHunds(2) = "CC"\n    sHunds(3) = "CCC"\n    sHunds(4) = "CD"\n    sHunds(5) = "D"\n    sHunds(6) = "DC"\n    sHunds(7) = "DCC"\n    sHunds(8) = "DCCC"\n    sHunds(9) = "CM"\n    sTens(1) = "X"\n    sTens(2) = "XX"\n    sTens(3) = "XXX"\n    sTens(4) = "XL"\n    sTens(5) = "L"\n    sTens(6) = "LX"\n    sTens(7) = "LXX"\n    sTens(8) = "LXXX"\n    sTens(9) = "XC"\n    sOnes(1) = "I"\n    sOnes(2) = "II"\n    sOnes(3) = "III"\n    sOnes(4) = "IV"\n    sOnes(5) = "V"\n    sOnes(6) = "VI"\n    sOnes(7) = "VII"\n    sOnes(8) = "VIII"\n    sOnes(9) = "IX"\n    \n    iThousands = (xDecimal - (xDecimal Mod 1000)) / 1000\n    xDecimal = xDecimal Mod 1000\n    iHundreds = (xDecimal - (xDecimal Mod 100)) / 100\n    xDecimal = xDecimal Mod 100\n    iTens = (xDecimal - (xDecimal Mod 10)) / 10\n    xDecimal = xDecimal Mod 10\n    iOnes = xDecimal\n    \n    sReturnStr = ""\n    For iCount = 1 To iThousands\n        sReturnStr = sReturnStr + "M"\n    Next\n    If iHundreds > 0 Then\n        sReturnStr = sReturnStr + sHunds(iHundreds)\n    End If\n    If iTens > 0 Then\n        sReturnStr = sReturnStr + sTens(iTens)\n    End If\n    If iOnes > 0 Then\n        sReturnStr = sReturnStr + sOnes(iOnes)\n    End If\n    GetDecRomanStr = sReturnStr\nEnd Function\n\n' xDecimal = GetRomanDecNum( sRomanStr )\nPublic Function GetRomanDecNum(ByVal sRomanStr As String) As Double\n    Dim xDecimal As Double\n    Dim sStr As String\n        \n    sStr = Left(sRomanStr, 1)\n    While sStr = "M"\n        xDecimal = xDecimal + 1000\n        sRomanStr = Right(sRomanStr, Len(sRomanStr) - 1)\n        sStr = Left(sRomanStr, 1)\n    Wend\n    \n    iHunds = 0\n    If Left(sRomanStr, 2) = "CM" Then\n        iHunds = 9\n        sRomanStr = Right(sRomanStr, Len(sRomanStr) - 2)\n    Else\n        If Left(sRomanStr, 1) = "D" Then\n            iHunds = 5\n            sRomanStr = Right(sRomanStr, Len(sRomanStr) - 1)\n        Else\n            If Left(sRomanStr, 2) = "CD" Then\n                iHunds = 4\n                sRomanStr = Right(sRomanStr, Len(sRomanStr) - 2)\n            End If\n        End If\n    End If\n    If iHunds = 0 Or iHunds = 5 Then\n        sStr = Left(sRomanStr, 1)\n        While sStr = "C"\n            iHunds = iHunds + 1\n            sRomanStr = Right(sRomanStr, Len(sRomanStr) - 1)\n            sStr = Left(sRomanStr, 1)\n        Wend\n    End If\n    xDecimal = xDecimal + iHunds * 100\n    \n    iTens = 0\n    If Left(sRomanStr, 2) = "XC" Then\n        iTens = 9\n        sRomanStr = Right(sRomanStr, Len(sRomanStr) - 2)\n    Else\n        If Left(sRomanStr, 1) = "L" Then\n            iTens = 5\n            sRomanStr = Right(sRomanStr, Len(sRomanStr) - 1)\n        Else\n            If Left(sRomanStr, 2) = "XL" Then\n                iTens = 4\n                sRomanStr = Right(sRomanStr, Len(sRomanStr) - 2)\n            End If\n        End If\n    End If\n    If iTens = 0 Or iTens = 5 Then\n        sStr = Left(sRomanStr, 1)\n        While sStr = "X"\n            iTens = iTens + 1\n            sRomanStr = Right(sRomanStr, Len(sRomanStr) - 1)\n
908927
Go for Black Book for VB.\nComplete Reference for C++ is good.\nC++, Java and .Net are valued.
870390
Hold down ALT and put in a few numbers in in the number pad, eg:\n\nALT + 0178 = ²\n\nAlternatively you can go Start > All Programs > Accessories > System Tools > Character Map for a big list of them all
966661
check out http://www.pscode.com for examples.  You would need to use ADO.NET in addition to VB.NET in order to obtain the required data.
1118192
I don't use vb.net myself (C# I use).\n\nIf you want to keep the 0's in the front though, it has to be a string, not an integer.\n\nYou convert it over to integer, add the next number, then cast it back to string, and pad the length to the desired number of 0's\n\nPseudo code:\n\nLicenseNoNum = CastToInt(LicenseNostr)\nLicenseNoNum = LicenseNoNum + 1\nLicenseNoStr = CastToStr(LicenseNoNum)\nWhile LicenseNoStr(Length) < 8\nLicenseNoStr = '0' + LicenseNoStr.\n\nYou could also just store it as an integer, and perform the cast for printing, which might be all you were looking for.
623675
I think you can find such a program, try to search on the internet.\nif you did not find, the conversion should be simple if you know VB6 in a good way, ASP is a technology that use scripting(VB script for example) language in addition to set of objects, what is needed is to add the suitable interface using HTML to your code of VB.
673564
It appears to be a string function, one that looks at the character at the position indicateded.  Don't quote me on VB syntax, but something like this \n\nvar string mystring = "Hello";\nmystring.IndexOf('e');  <-- this would give you a value of "1" (one), assuming the indexing starts at zero.
670568
Try Planet Source Code:\n\nhttp://www.planetsourcecode.com/vb/scripts/ShowCode.asp?txtCodeId=3270&lngWId=3\n\nThis one's in C++. You should be able to convert it back to C...