solve the system: 2y=x+16  and 5x+10y=0?
952983
2y = x + 16 - - - - -Equation 1\n5x + 10y = 0- - - - Equation 2\n- - - - - - - - - - - -\n\nRearrange equation 1\n\n2y = x + 16\n\n-x + 2y = x + 16 - x\n\n-x + 2y = 16 - - - -equation 1 rearranged\n- - - - - - - - - - - -\n\nMultiply equation 1 rearranged by 5\n\n5(-x) + 5(2y) = 5(16)\n\n- 5x + 10y = 80- - - - New equation 1\n\n- - - - - - - - - - - -\n\nElimination of x new equation 1 and equation 2\n\n- 5x + 10y = 80\n5x + 10y = 0\n- - - - - - - - - -\n20y = 80\n\n20y/20 = 80/20\n\ny = 4\n\nThe answer is y = 4\n\nInsert the y value into equation 1 \n\n- - - - - - - - - - - - - - - - - - - - - - - -\n\nSolving for x\n\n2y = x + 16\n\n2(4) = x + 16\n\n8 = x + 16\n\n8 - 16 = x + 16 - 16\n\n-8 = x\n\nThe answer is x = - 8\n\nInsert the x value into equation 1\n\n- - - - - - - - - - - - - - - - - - - - - -\n\nCheck for equation 1\n\n2y = x + 16\n\n2(4) = -8 + 16\n\n8 = 8\n\n- - - - - - - - - -\n\nCheck for equation 2\n\n5x + 10y = 0\n\n5(- 8) + 10(4) = 0\n\n-40 + 40 = 0\n\n0 = 0\n\n- - - - - - - - -\n\nThe solution set is { -8, 4 }\n\n- - - - - -s-
1174662
2(x-4y+1)+3(-2+y-2)\n2x-8y+2-6+3y-6\n2x-8y+3y-6-6\n2x-5y-12\n\n2x-5y-12= answer\n\nHope this helps you.
931393
GIVEN:\n\n0.4x - 0.1y = 5 \n6.4x + 0.4y = 60\n\nSTEP 1:  Multiply the first equation by 4 to get the following:  (because notice that 0.1 * 4 = 0.4, and we will be able to cancel our y's out and solve for x)\n\n1.6x - 0.4y = 20\n6.4x + 0.4y = 60\n\nSTEP 2:  Add the two equations together, to get one equation with our x variable only:\n\n1.6x - 0.4y = 20\n6.4x + 0.4y = 60\n-----------------------\n8.0x + 0y = 80\n\nSTEP 3:  Divide both sides by 8 to solve for x:\n\nx = 10\n\nSTEP 4:  Substitute this value for x into either one of your original 2 equations to solve for y:\n\n0.4x - 0.1y = 5\n0.4(10) - 0.1y = 5\n4 - 0.1y = 5\n-0.1y = 1\n0.1y = -1\ny = -10\n\nFINAL STEP:  Your answers are x = 10, y = -10\n\nHope that helped!\n\n~ ♥ ~
95804
You know that\n              1)3x+4y=12y\n              2)-2x+10=12y\nSo you can substitute 3x+4y for 12y in equation 2. Hence:\n              3)3x+4y=-2x+10\n                   5x=10-4y\n                    x=2-4y/5\nSubstitute this value for x into equation 1 and it becomes:\n              1)8y/5+6=12y\n                     y=15/26\nPlug this back into 3 and you get\n              3)x=2-(4/5)*(15/26)\n                x=20/13\nTherefore the answer to the system is (x,y)=(20/13,15/26)
159612
Multiple the first equation by two\n-10x-8y = -22\n10x +y = -6  (second equation)\n\neliminate x\n\n-7y = -28\ny = 4\n\n10x + 4 = -6\n10x = -10\nx = -1
1031270
x^2 + 5 + 5x + x y +5y\n\nx^2 + xy + 5x + 5y + 5\n\nx(x+y) + 5(x+y) + 5\n\nx(x+y) + 5(x+y+1)       OR     (x+5)(x+y)+5\n\nCynthia
810055
x^2 - 2x + y^2 + 2y + 2 = 16\n\nx^2 - 2x + 1  + y^2 + 2y + 1 = 16\n(x - 1)^2 + (y+1)^2 = 16\n\nCenter = (1, -1)\nRadius = sqrt(16) = 4
1066425
A system of linear equation has a unique solution if and only if the determinate of the coefficients matrix is not equal to zero. Therefore, for your system\n\nx+5y=10\n-2x-10y= -20\n\nThe determinate is\n|   1     5    |\n|  -2   -10  |\n\ndet= 1*(-10) – 5*(-2) = 0\n\nThen the system is linear dependency and has infinite number of solutions.
957836
4x+(-5y)+(-6x)+3y\n4x+(-6x)+(-5y)+3y\n=-2x-2y
1009010
y= 40-5x\ny=40-5(6)\ny=10\n10
233924
48x^2y+20xz+20xy+5z\nI switched the position of the two middle terms.\n48x^2y+20xy+20xz+5z\n4xy(12x+5)+5z(4x+1)
639859
its simple..see\n\n2x + 3y = 1 -------- 1st expression\n5x + 3y = 16 ------- 2nd expression\n\nnow..first take 1st expression\n\nStep 1: 2x + 3y = 1\n        2x = 1 - 3y\n        x = (1 - 3y) / 2  -------- this is value of x\n\nnow..take 2nd expression\n\nStep 2: 5x + 3y = 16\n        5(1 - 3y) / 2 + 3y = 16  ---here put the value of x\n        2.5(1 - 3y) + 3y = 16\n        2.5 - 7.5y + 3y = 16\n        2.5 - 16 = 7.5y - 3y\n        -13.5 = 4.5y\n        y = -13.5 / 4.5\n        y = -3 ------ this is value of y\n\nNow again put the value of y in the 1st expression\n\nStep 3: 2x + 3y = 1\n        2x + 3(-3) = 1\n        2x - 9 = 1\n        2x = 1 + 9\n         2x = 10\n         x = 10 / 2\n         x = 5\n\nSo, final value of x = 5 and value of y = -3 \n\nHope ya understand ;-)
863140
First, you multiply the top equation by 2, to get:\n\n2x+2y = 8\n2x - y = 2\n\nThen, subtract the top equation with the bottom equation.  That is,\n(2x+2y) - (2x - y) = 8 - 2\n2x + 2y - 2x + y = 6\n3y = 6\ny = 2\n\nNow that you know the value of y, you can now solve for x, using any one of those two equations.  Let's use the second one.\n\n2x - y = 2\n2x - (2) = 2\n2x - 2 = 2\n2x = 4\nx = 2\n\nTherefore, x=2 and y=2 is the solution.
958973
y=5x+2\ny=5(2)+2\ny=10+2\ny=12
106013
y = -2x + 8\n\nsolve it yourself
704941
The second equation can be rewritten as:\n3x + 2y = -1\nMultiply both sides by 2\n6x + 4y = -2\n6x + 5y = -7 (this is the first equation)\nSubtract the first equation from the second one.\ny = -5\nNow, plug the y = -5 into the second equation:\n3x +2(-5) = -1\n3x - 10 = -1\n3x = 9\nx = 3\nSo your solution is x = 3 and y = -5
408156
OK, let's first align the equations so the variables and the constants are lined up:\n\n2x + 5y = 8\n5x - 2y = 20\n\nLooking at this, we can either solve for x or y. It really doesn't matter in this case; the difficulty of either is the same. For simplicity, let's solve for x.\nAfter multiplying the top by 2 to get 10y, and the bottom by 5 to get -10y:\n\n4x + 10y = 16\n25x - 10y = 100\n\nCombine the two together:\n\n29x = 116\nx=4\n\nSubstitute x back in either of the equations:\n\n2(4) + 5y = 8\n8 + 5y = 8\n5y = 0\ny = 0\n\nor\n\n5(4) - 2y = 20\n20 - 2y = 20\n-2y = 0\ny = 0\n\nSubstitute x (4) and y (0) back in both equations to check:\n\n2(4) + 5(0) = 8\n8 + 0 = 8\n8 = 8\n\n5(4) - 2(0) = 20\n20 - 0 = 20\n20 = 20\n\nDone. The answer is x=4, y=0.