Ka=[CH3Co2-] [H+]/ [CH3CO2-+H+]?
967763
Equivalent to [H+]^2/([HCH3CO2] - [H+]).  You can solve for [H+] knowing Ka and [HCH3CO2].
743385
Cl2 + 2 KI → I2 + 2 KCl
1097630
Na2CO3 + 2HCl-> NaCl + H2O + CO2
295951
2 CH3OH + 3 O2 → 2 CO2 + 4 H2O + 726 kJ/mol
363082
2Ag+ + CO_33-2 -> Ag_2CO_3
550972
CO2 + H2O --> CH2O + O2\n read the attached webpage
914156
6 CO2 + 12 NADPH + 12 H+ + 18 ATP → C6H12O6 + 6 H2O + 12 NADP+ + 18 ADP + 18 Pi
811861
KCl(s)  ---->  K+(aq)  +  Cl-(aq)
98695
My answer is,\n \nNH4NO3(ag) + KOH(aq) -> NH4OH(aq) + KNO3(aq)
868179
2Rb + 2 H20 --> 2RbOH + H2
1185900
H2SO4 + 2KOH --> K2SO4 + 2H2O
801550
You have\nmole CH3COOH= Ca*Va= 0.2*0.2=0.04\nmole KOH= Cb*Vb= 0.2*0.2= 0.04\n\nCH3COOH + KOH -> CH3COOK + H2O\n\nThe stoichiometry is 1:1 and you have equal mole of acid and base therefore they will react completely and you will have only CH3COOK in the final solution\nHowever this is the salt of a weak acid with a strong base so it will hydrolyze according to\n\n.. .. .. ..  .. CH3COO- + H2O <=> CH3COOH + OH-\nInitial .. .. .. .. C\nReact .. .. .. ..x\nProduce .. .. .. .. .. .. .. .. .. .. .. .. .. .. .. x .. .. .. .. .. . x\nAt Equil. .. .. C-x .. .. .. .. .. .. .. .. .. .. .. x .. .. .. . .. .. x\n\nKb=[CH3COOH][OH-] / [CH3COO-] = x^2/(C-x)\n\nBut Kb=Kw/Ka= 10^-14/(1.82*10^-5)\nC=moleCH3COOK/Vfinal = Ca*Va/(Va+Vb)=0.04/0.4\nsubstitute Kb,C and find x (you can assume that C>>x and C-x=C. this simplifies the equation to x^2/C=Kb. If you calculate x and it is truly much smaller than C the assumption is valid. Otherwise you have to solve the quadratic equation)\n\npOH=-logx and pH=14-pOH
744647
C(3)H(8)+5O(2)=>3CO(2)+4H(2)O\nfuel+oxygen=>carbon dioxide+water\ncombustion \nbrackets-subscript
250762
2 HCl + CaCO3 ----> CaCl2 + H2O + CO2
746063
CO3^2- + 2H^+ ===> CO2 + H2O
48368
2HC2H3O2 + Ba(OH)2 --> Ba(C2H3O2)2 + 2H2O
839940
1. 2C6H6 + 15O2 --> 12CO2 + 6HOH\n\n2. C12H22O11 + 12O2 --> 12CO2 + 11HOH\n\n3. CH3COCH3 + 4O2 --> 3CO2 + 3HOH\n\n4. C2H5OC2H5 + 6O2 --> 4CO2 + 5HOH\n\n5. C4H9OH + 6O2 --> 4CO2 + 5HOH