I have to solve and explain carefully step by step as if I was teaching it to a sixth grader.?
964703
I would start by asking the kids questions.\n\nHow many days are in a year?\n\nSo, if we have 80,000 people how could we estimate how many people will be at each party? At least 1 kid will be smart enough to tell you to divide it. Be sure that write it on the board as you go.\n\nWhen you come up with 219 then ask the kids if they really think that the birthdays will be divided equally. If that is true, then if there are 24 kids in your class... there should be 2 birthdays in each month. (Maybe as a starter for the lesson you could have some sort of birthday poster and could quickly write the names of the kids under each month that their birthday falls. You may have some months with 5 birthdays, and others with 1 or none). If they say that they think that the birthdays will be evenly then use your birthday chart and explain that their birthdays are random; that it does not work out to exactly 2 birthdays in each month.\n\nThen you can explain to them that with 80,000 people there are likely to be a few birthdays on more days than others. They will get it; especially when you use their own data to help explain it.\n\nIf time allows you could do another problem that is similar, but maybe using something like the day they got their first pet (I don't know; something...) anyway, because some people may have never had a pet you could ask if it is possible that some people never come to celebrate. Or maybe use vet patients for the problem because then we could assume that all patients would qualify.
548408
The way I explain percentages to my sixth grade students, I say I use the "Mom" method.  My mother taught me how to find 10% of something and if you can find 10% you can find any percent.  \n\nFirst, take the number you have and move the decimal over ONE place to the LEFT.  That new number is 10%, if you need to find 20%, you double it...etc.  Now to find say 5%, you do the same for 10% but take that same number and cut it in half.  \n\nEasy percentages are 25%, 50%, and 75%.  50% you just cut your number in half.  For 25% and 75%, you cut your number either 1)in half and then in half again. each part is 25%, 2 parts=50%, 3 parts=75%, 4 parts=100%.  2) cut each part into 4 and now you have the same 4 parts.  \n\nI'll be happy to give you extra tips if you need them.
127894
I can probably help u with it....I am in grade 10, skipped grades 9...reasonably good at Algebra and Trig, Geomerticaly retarded though T,T"\ndamnedatheist@gmail.com can help u
931883
Ummm...\nThe equation of algebra, eh?\nWhat on earth are teachers teaching kids these days?!
104581
It takes practice!  And its like a puzzle.  Just use the main trig identities as reference and a good math tutor.  Unfortunately, this place isn't the best place to ask that kind of question because we are limited by text explainations and trig identities need a lot more than that!
156840
Look up "Algebra Solved 2005" or "algebrator", these two programs not only solve problems, but they give step by step solutions for understanding. they have tutorials and practice test. I went from knowing none to fairly advanced in a few weeks.
802374
Much like the others said, it is hard to explain without being able to show you. I also don't know how your teacher has been teaching it. I would say the first step is to memorize the sentence patterns. This goes through the 5 basic sentence patterns: http://college.hmco.com/devenglish/broughton/focus_florida/1e/students/diagramming_basic.html. \nI would, however, as someone else advised, ask your teacher for extra help.
914726
You should probably go see your tutor at school for help.  You never know what kind of answer someone is going to give you...or if they are just messing with you.
915953
Please, learn arithmetic.\n\n12
232907
I would reword it as this:\n\nHowever, I am not good at math.\n\nHope this helps!
114498
Well, if this must have something to do with Math, or abacus calculation, I suggest that you have these slips of paper having equations, like one slip will contain the "question" and the other will contain the "answer".\n\nFor example,\n"3 x 72" and "216"\n\nMake up a few different equations with such slips. Then, in your class, hand out these slips to the children. If they have the "question" slip, their task would be to find the person holding the correct "answer" slip and vice versa.\n\nThis will allow them to interact with one another in some sense. Hope this idea isn't too dull!
531494
Ask your teacher.\n\nBut usually, you are supposed to simplify.
865538
i would guess this is 3rd or 4th grade?\n\nyou could use a calculator of course . . .\n\nto show your work, you need to do it on paper\n\ngood luck!
752879
ok re arranged the second question so that the 6 is factored out so its x= such and such then sub the x equals such and such into the first equation and solve then do the same thing to Y in the second equation
716584
www.math.com has really simple demonstrations. It teaches the student how to do the certain problems, then it goes further into detail. You can then try it online! It covers everything from addition and subtraction to algebra. Hope this helps!
843341
Division and multiplication. Just like I learned in Grade 3.
15032
you might have learning differents. You could be tested to see if you are then you could find help.  You could get a tutor or ask a teacher for help with math.