What is the formula for working out the area of wing needed as in proportion to weight etc?, thanks.?
969868
What parameters do you already have?  I guess you have an a/c weight? The CL equation is a standard with CL= L/(1/2 density*V^2*S)  where S is the Area.
250763
you split it into 2 ,a cone and a cylinder. first u need the slanting height of the cone and you find this by pythagorus theory for triangles ie L2 = h2 + r2, so height=6(found by subtracting the 15 from 21) radius=10 (20/2)therefore L2=6x6+10x10=136 therefore L =sqr root of 136 =11.6 surface area is A=pi*r*L\npi=3.142 so 3.142*10*11.6 = 364.5sq ft now the cylinder the surface area of a cylinder is circumference × h, or 2πr × h\nso 2*3.142*10*15 =942.6 so 942.6+364.5=1307.1 sq ft to find quantity of tins 1307.1/250=5.2 so they need 6 full tins you must check the formulas and calculations as I may have made a mistake ok
140062
L x W = Area\n\nCheater
917981
The pressure P(in pounds per square foot) from wind blowing at S miles per hour is given by P=.00256e^2.\n\nDon't you think the formula ought to have S in it?
847510
Several ways. The first that comes to mind is to figure the area with Heron's formula (area = sqrt(s(s - a)(s - b)(s - c)), where s = (a + b + c)/2). The area can also be figured as 1/2 base times altitude, so you know the altitudes of the triangle. The altitudes give you right triangles where you know the hypotenuse (a side of the triangle), and a leg, so you can compute the trig functions of all the angles. Then the angles can be computed as arcsin or arccos of the angle (arcsin(altitude/side))
891617
The triangle area formula is\n\nA = 1/2 b h\n\na = 1/2(5)(2)\n\nA = 5/2(2)\n\nA = 10/2\n\nA = 5\n\nThe area of the triangle is 5 feet\n\nThe answer is " a "\n\n- - - - - - - - - - - -s-
681731
Hello Friend, in order to calculate one's Body Mass Index(BMI), Take your weight (in kilograms),  and divide by your height (in meters) squared..   If I remember correctly..  Please check it out if I am correct or not!!\n\nAnd Ideal Body Weight Percentage Calculation Process: \n(Weight x 100) / (Height x 2.54 / 100) x (Height x 2.54 / 100) x 21.5 x 2.2\n\n*Put Weight in Pounds and Height in Inches..\n\nHopefully this will prove to be helpful but please confirm the correctness of the formulae from other sources..
772638
try the formulas:\n\nforce = mass * aceleration\n\nwork = force * distance\n\n\n\n\nWell i dont speak english very well, but i hope i help u.\n\nKisses
194515
Look at the Eifel Tower or a local steel bridge. A model airplane shop could help with the wood and look at an airplane body frame. \nTo calculate, look for a statics book. Engineers need to know how much force each piece has to hold.
410854
Wierd question, but i guess size of cargo area, strength of area (weight). Shape of cargo and cargo area.
816108
dA = ½ (b.dh + h.db)\nSo δA ≈ ½ (b.δh + h.δb)\n= ½ (100 x ±1 + 10 x ±2)\n= ½  * ±120\n= ±60ft²\n\nCheck:\nMin area = ½ * 98 * 9 = 441ft²\nMax area = ½ * 102 * 11 = 561ft²\n\nNow 500±60 ft² = (440 to 560)ft²\n\nSo estimate is pretty close!!!
975485
H*W= area\nheight times width\n\none side has a height of 8 and its width is 9 thus the area would be 72
880678
Area = length times width\nA = L time W\nReplace L with 32 and W with 22\nA = 32 times 22\nA = 704 square feet
783277
let the height be x\nthe cross section will be (40-2x)*x\ndA/dx=40-4x\nsetting this to 0\nx=10\nso the length of the sides will be 10 cm each for max area of x section
182640
I'm not sure if this is what you're asking, but if...\nd = length\nd-3 = width\n\nthen the area is d(d-3), a.k.a. d^2 - 3d .\n\nHope this helps!
776007
If your two figures have a ratio of similarity of 2:5, then each side of the smaller one is the side of the larger one times 2 and divided by 5.  This might lead you to believe that your area would be 100 times 2 and divided by 5 = 40.  This is, however, not the case.  If each side is times 2 and divided by 5, the total area is times 2 times 2 divided by 5 divided by 5. = 16\nThe best way to imagine this problem is by assuming your shape is a square.  How large is each side of the square if the area is 100 square units?  Each side must be 10 units, since 10 times 10 is 100 square units.  Now shrink each side by multiplying by 2 and dividing by 5.  Each side is now 4 units long.  How much area is your square?  4 times 4 is 16 square units!
332070
Partition this into parts of known sizes ,then calculate weights  of each part and its cent of gravity. Then take a point outside the assy. The moment of each part about this point equals the total weight times  the dist of the CG from this point. Repeat this process to find the vert and horiz position of the CG.Consider a letter L shape.,height l1,cross secton a1,b1 inches.weight=w1=l1*a1*b1*0.284 (steel) lbs.Bottom of L  , length l2, cross sectio a2,b2. weight=w2=l2*a2*b2*0.284 lbs.Then dist of CG from corner of L is w2*l2/(2*(w1+w2)), and dist up from corner is \nw1*l1/(2*(w1+w2)).- I hope ?