Find the y and x-intercepts for the function f(x)=-3x^2+6x-2?
959079
For the y-intercept, set x to zero and solve:\n\nf(0)=-3(0)^2+6(0)-2\nf(0)=-2\n\nFor the x-intercepts, use the quadratic formula since this equation can't be factored. The x-intercepts come out to be 0.42264973 and 1.5773503
918456
domain\nall real x\nx intercept\nputting y=0\n0=x+rt{x]\n-x=rtx\nx^2=x\nx(x-1)=0\nx=0 or 1\nx intercept=(0,0) and (1,0)\ny intercept\nsetting x=0\ny=0\ny intercept=(0,0)\nno symmetry exhibited
91777
y=-6\n4x+y=2\n\nsubstitute -6 for Y\n\n4x-6=2\nadd 6 to both sides\n\n4x=8\nDivide both sides by 4\n\n\nx=2\ny=-6 (taken from above)
266141
when x=0  f(x)=2(1)+3=5\n\n(0,5) y intercept\n\nwhen y=0 2(x+1)^2+3=0\nso 2(x+1)^2=-3 and this is not possible in the field of real numbers (number squared cannot be negative).\n\nno x intercepts
704179
An equation in slope-intercept form is y = mx + b\nIn the equation, m = slope and b = y-intercept\n\nUsing the equation given\ny=-3/2x+6\ny = mx + b\n\nWe know that the slope is -3/2.  That would be m.\nWe know the y-intercept is 6.  That would be b.\n\nNow we have to find the x-intercept.\n\nTo get the x-intercept, we will set y = 0 and solve the equation for x.\ny=-3/2x+6\nSubstitute 0 for y\n0=-3/2x+6\nAdd 3/2x to both sides\n3/2x = 6\nMultiply both sides by 2/3\n2/3*3/2x = 6*2/3\nx = 4\nThe x-intercept is 4.\n\nSlope =  -3/2. \ny-intercept = 6.\nx-intercept = 4.
819736
x intercept is when y=0\n\nso this would be x=3\n\n3^2 - 3 -6=0\n9-3-6=0\nso x intercept is 3\n\nproof:\n0= x^2 - x - 6\n6 = x ( x-1)\n6 = 3 (3-1)\n6 = 3 * 2\n6=6
732775
y = -16x^2 +80x +3\n\nFirst of all, it is a negative quadratic function, so, you expect this quadratic function to open downwards. Now that you know the general shape, you need a few points on the graph in order to help you graph it. So, let's find the x and y intercept. \n\nTo find the y intercept, you sub x = 0 into the above equation, which leads to 3. Now, you know one point (0,3).\n\nTo find the x intercept, the easiest way is to use the quadratic formula:\n\nFor an equation y = Ax^2 + Bx + C\nx = [- B ± sqrt(B^2 - 4AC)] / (2A)\n\nIn your equation, A = -16, B = 80, C = 3. Sub these information into the quadratic formula, you get\n\nx = [- 80 ± sqrt(6592)]/(-32)\n\nFurther simplify this expression, you get\n\nx = [80 ± 8*sqrt(103)]/32\nx = [10 ± sqrt(103)]/4\nThis leads to two answers, x ~ 5.04 and x ~ -0.037. So, the two x intercepts are (5.04, 0) and (-0.037, 0).\n\nNow you have three points: (0,3), (5.04, 0), and (-0.037, 0). Put these on a coordinate, with the general shape in mind (quadratic facing downwards), it should be very obvious how the function should look like. Hope that helps.
143223
a) (6x-7y)(6x+7y)\nb) y(4xy-7)\nc) (x-8)(x+3)
375327
Where x = 0, the line intercepts the y-axis:\n\n1. 5x-2y =10 \n2y = 5x - 10\ny = (5/2)x - 5 \ny-int = (0, -5)\n\n2. 2y+7x =14\n2y = -7x + 14\ny = (-7/2)x + 7\ny-int = (0, 7)\n\n3. x=3\nHas no y-intercept\n\n4. 1/2x-2y=8\n2y = (1/2)x - 8\ny = (1/4)x - 4\ny-int = (0, -4)
304476
y = x^2-5x\n0 = x^2-5x\n\nx^2-5x = 0\n\nx(x-5) = 0\n\nx = 0 or x = 5\n\nx-intercepts : (0,0) and (5,0)\n\nANSWER : two
885928
Find the X intercept by setting Y = 0\n\nx-2 = 0\nx = 2\n\nFind the Y intercept by setting X = 0\n\ny = 0-2\ny = -2\n\nSo the two points to plot are (0,-2) and (2,0) \nThen connect those points with a line
700599
1)   y=3x^2+5x-12\n      0=3x^2+5x-12                  (to find the x-intercepts)\n      0=(3x-4)(x+3)                  (Factorised)\n      3x-4=0  or  x+3=0\n      the x-intercepts are x=4/3  and  x=(-3)
735529
f(x)=-2x^4+6x+7\nf(-x)=-2(-x)^4+6(-x)+7\n=-2x^4-6x+7\nnether odd nor even
216211
when x=0 \ny=f(x)=\n(-1/15)(-5)(3)^2(-1)^3=\n(-1/15)(-5)(9)(-1)=\n(5/15) *(-9)=\n(1/3)*(-9)=\n-9/3=-3\n\n(0,-3) y-intercept\n\n\nWhen y=0\n\n-1/15(x-5)(x+3)^2(x-1)^3=0 multiply by -15\n(x-5)(x+3)^2(x-1)^3=0\n\nso x-5=0 and x=5  or\n   x+3=0 and x=-3 or\n   x-1=0 and x=1\n\nso (5,0) (-3,0) and (1,0) are x intercepts.
937981
Your goal here is to solve for a, b, and c.  We can easily do this with the facts that we're given.\n\ny-intercept is 2: This means that when x=0, f(0) = 2\n\nso f(0) = b * a^(0) + c = 2\nb + c = 2 (since a^0 = 1)\n\nHorizontal asymptote is y = -2.  Remember that for exponential functions, the horizontal asymptote is always the horizontal shift, which is the constant next to the term containing the expontential.  Thus, in our case, c is the horizontal shift, so \n\nc = -2\n\nCombining this with b+c=2 (which is what we solved for earlier), substituting c=-2 in there yields:\n\nb+(-2) = 2, so b=4.\n\nb=4 and c = -2, so if we plug it back into f(x), we get\n\nf(x) = 4*a^x - 2\n\nPasses through the point (1,4) means we plug in 1 for x and 4 for f(x), to get:\n\n4 = 4*a^(1) - 2, or\n4 = 4a - 2\n6 = 4a\n3/2 = a\n\nNow we have a, b, and c.  The final answer is then:\n\nf(x) = 4*(3/2)^x - 2
672055
To get x intercept set x = 0 and solve for y\ny = -2*0 + 9\ny = 9\nx intecept (0,9)\n\nTo get y intercept set y = 0 and solve for x\n0=-2x+9\n-9 = -2x\n9/2 = x\n\ny intecept (9/2, 0)
751318
x^2-x-6>0\nor, x^2-3x+2x-6>0\nor, x(x-3)+2(x-3)>0\nor, (x-3)(x+2)>0\nor x>3 and x<2\n\nhope this helps :)