Can any one help me here??
952234
The starting point of Q is the edge of the disk where the radius is parallel to the x axis.\n\nThe disk spins so that an angle of a radial line to Q opens downward at a rate of 6 pi/sec\nLet's call the angle a\n\nThe x value of Q will be located at\nx= 3*cos(a)\nand the y value of Q will be located at\ny=2-3*sin(a)\nIt's translated up by 2 and set negative since the motion is clockwise.\n\nNow, a = 6*pi*t\nso x=3*cos(6*pi*t)\nand y=2-3*sin(6*pi8*t)\n\na       1.884        \nt  0.1\nx  -0.924324094                  \ny  -0.854054129\n\n\n\nj
115848
Sorry wish I could help
603504
Hi, I think this thread will help. See link..
1004799
go on line maybe there will help you
434557
Try these.\n\nHope that helps.\n\nGood Luck.
825335
this might help...   ?
214321
Try the links below. Good luck!!
657309
yea man i would need help with this too. hope you get some help from others, good luck
24770
have you tried chat! thats my best way. Try to pick ya game up a little bit if its costin ya! ;)
851632
hope this helps.  ;-)
973153
Try the one below...:D
633765
Try here.\n\nHope that helps.\n\nGood Luck.
720755
hi\nhere are some links to help u.\ncheers
490771
hi\nhere are some helpful links\ntry to contact them.\ncheers
125925
so u need help well i have afriend who could help ya!!!\nso answer back
18435
Here is a site that you can check out. I don't know how much it will help but I tried. \n\nGood luck
638381
What kind of help?  Can you be a little more vague, please.  LoL..