Homework help, algebra 2, please help! one word problem :-/?
956295
We need a certain amount of each kind of candy.\n\nCall the amount (in pounds) of the 50 cent candy X. Call the amount (in pounds) of the 75 cent candy Y.\n\nTo get 80 pounds of the mixture, X + Y = 80.\n\nThe candy mixture has a total value of:\n\n80 pounds * (55 cents per pound) = $44.\n\nThe value of the 50 cent candy used is 0.50X. The value of the 75 cent candy used is 0.75Y.\n\nTo have the values add up, 0.50X + 0.75Y = 44.\n\nHere is the system of equations:\n\nX + Y = 80\n0.50X + 0.75Y = 44\n\nThere are many ways to solve systems. I'll use substitution here:\n\nX + Y = 80\nY = 80 - X\n\n0.50X + 0.75Y = 44\n0.50X + 0.75(80 - X) = 44\n0.50X + 60 - 0.75X = 44\n-0.25X = -16\nX = 64\nY = 80 - X\nY = 16\n\nUse 64 pounds of the 50 cent candy, and 16 pounds of the 75 cent candy.\n\nCheck:\n\nClearly, 64 + 16 = 80 pounds.\n\nThe 64 pounds of 50 cent candy costs 32 dollars. The 16 pounds of 75 cent candy costs 12 dollars.\n\nThe total value of the 80 pounds of candy is 44 dollars.\n\n44 dollars/80 pounds = 55 cents per pound\n\nIt works!
757452
x=-54\nthis one is incorrect.\ny=-2/3\nx=1\ny=54/2.7\ny=-2 ~
610821
Easy...\n0 = 0\n\nadding -2 on both sides\n\n-2 = -2\n-> -3 + 1 = -6 + 4\n-> -2*3/2 + 1 = -4*3/2 + 4\n\nadding 9/4 on both sides..\n\n-> 9/4 -2*3/2 + 1 =9/4 -4*3/2 + 4\n->\n(3/2 - 1)^2 = (3/2 - 2)^2\n\ntaking +ve sqr root\n3/2 - 1 = 3/2 - 2\n\n-> 1= 2\nadding 1 on both sides\n2 = 3\n-> 1 + 1 =3
516830
http://www.gateways2learning.com/Algebra/Algebra.htm\n\nAlso try here.......\n\nYou may want to reconsider having it solve the answer for you, always know how to do the breakdown, it will help you to know "how" to go about it when you take a test.\n\nGood luck.....................
491455
(x^2+4x+1)/(x-2) = x+2+3/(x-2)\n\nx  : x^2+4x+1-x^2-2x =2x+1\n2  : 2x+1 -2x-4 =3
768805
Factor out the 3:\n3(x^2+3x+2)\nUnfoil:\n3(x+1)(x+2)\nTake the roots:\nx=-1 or -2
200519
+/- 1\n\nThe answer is not 1, because -1 * -1 = 1 also.
512145
subtract c from both sides then you'll have\n\nx^2 + Bx = -C\n\nthen you can complete the square\n\nx^2 +Bx +_____=-C +_______\n\nfill in the blank with (b/2)^2\n\ni'm positive this is right...i teach high school math.
825795
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
945604
1.adding-2f-7\n-6f-2f+7-7<2f-2f-9-7\n-8f<-16\ndividing by -8\nx>2\n\n2.5/8g-4>2/3g+6\nadding 4\n5/8g>2/3g+10\nmultiplying by 24\n15g>16g+240\nadding -16g\n-g>240\ndividing by -1\ng<-240\n\n3.sum incomplete\n\n4.-2 1/9d+3/5<-3 2/9d-4 2/5\n-19/9d+3/5<-29/9d-22/5\nmultiplying by45\n-95d+27<-145d-198\nadding 145d\n50d+27<-198\nadding -27\n50d<-225\ndividng by 50\nd<-5 1/2
467924
Assuming I've read the problems right (writing math problems on a single line is tough without using a lot of brackets, so I assume for 9 that the space indicates two expressions, for 10 that 1/x+2 is 1/(x+2) and not (1/x)+2, and that the polynomial in 11 is all under 17 instead of (17/x^2)+3x... )\n\n09) Given: 7/(x+3) - 3/(x^2-9)\nFactor Denominator: 7/(x+3) - 3/(x+3)(x-3)\nRewrite with LCD: 7(x-3)/(x+3)(x-3) - 3/(x+3)(x-3)\nMultiply and Rewrite: 7x-21/(x^2-9) - 3/(x^2-9)\nSubtract: (7x-24)/(x^2-9)\n\n10) Given: (1/x+2)+9\nRewrite with LCD: (1/(x+2))+[(9x+18)/(x+2)]\nAdd fraction w/same denom.: (1+9x+18)/(x+2)\nSimplify: (9x+19)/(x+2)\n\n11) Given: [17/(x^2+3x-28)] - [2/(x-4)]\nFactor first denom: [17/(x+7)(x-4)] - [2/(x-4)]\nRewrite with LCD: [17/(x+7)(x-4)] - [2(x+7)/(x+7)(x-4)]\nSimplify numerator: [17/(x+7)(x-4)] - [(2x+14)/(x+7)(x-4)]\nSubtract fraction w/like denom: [17-(2x+14)]/[(x+7)(x-4)]\nSubtraction rule for polynomial: [17-2x-14]/[(x+7)(x-4)]\nSimplify: (3-2x)/(x^2+3x-28)
540085
(a-2)(a+2)  \n(difference of squares)
912865
bring the a's to one side... u then get 9a = 27 ... divide and answer is a = 3
1127430
try this one http://www.algebrahelp.com/
272295
There's lots of help online. Try these web sites:\n\nhttp://www.algebrahelp.com/\nhttp://www.purplemath.com/\nhttp://www.sosmath.com/algebra/algebra.html\nhttp://www.helpalgebra.com/\n\nThere's even more. So start with these, and good luck!
450981
I'm guessing that second term was to be -11x.\n\nSadly, this is trial and error.  as the last term (+24) you know the terms are both like signed (both x+something or X-something).  The second term being negative (-11x), we know that they are both x-something.  so we are looking for two factors:  (x-a) and (x-b), where:\n\n1.  a+b=11, and\n2.  axb=24\n\nOur factors of 24 are:\n1x24\n2x12\n3x8\n4x6\n\nas 3x8 fits, we try it:\n\n(x-3) (x-8)\n\nthis equals:\n\nx^2-11x+24\n\nso we are right with these two factors\n\nHope this helps....I do these things instinctually, so I have trouble explaining them.
909284
((1/x) + (1/y)) / ((1/x) - (1/y))\n\n((y + x)/xy) / ((y - x)/xy)\n\n((y + x)/xy) * ((xy)/(y - x))\n\n(xy(y + x))/(xy(y - x))\n\n(y + x)/(y - x) = (x + y)/(-x + y) = (x + y)/(-(x - y)) = -(x + y)/(x - y)