Can anybody explain to me or an example what a constant (mathematical) is?
952227
Constant is a number that will stay the same unless acted upon by PEMDAS or a variable.\n\nexample: 3-5x=y, the 3 is the constant.
991696
To define an equation, you can use the syntax\nf := x -> (k*x*(1-x));\nWhich is creating a function defined on a variable x.\nThen, you can set the value of k by saying \nk := 2;\nIf you then say\nf(.1);\nit will give you the value of f(.1).  You can repeat this with the value you get from this.
341988
Yes, the coefficient is usually a constant factor, any factor that does not contain a variable.
39584
If you derive a constant, you always get 0
936497
To a mathematician 1 + 1=2 right. If I were using that equation in another context it could be interpreted differently. In a nutshell the quote is saying that people sometimes interpet the same one thing differently.
800132
how does this fit into mathematics?
161780
There is a simple mistake in your logic.\nYou want to say you will add x , x times. As you want to add it x time you are making it constant.( Because when you are diffrentiating, x can't change)\nwhen you diffrentiating const, all will be 0.\nso you have proved 0=0.
945362
An exponential function diverges from a base value by a factor of e (or converges to a base or asymptote value, reducing the difference by a factor of 1/e) for each time interval known as a "time constant". In the equation you provided, the time constant is T, the base value is 'a', b is a scale factor for the rate of increase, and the time variable is t. This equation represents an asymptotic or converging function since the power of e is negative. In each successive interval of T, the function's difference from 'a' decreases by a factor of 1/e. For an example of a real-world application of this equation, consider a capacitor of C farads being charged from 0 volts by a 5-volt source through a resistor of R ohms. The time constant of charging is R*C seconds. The equation for the voltage V on the capacitor is V = 5 - 5 * e^(-t/(R*C)). When T = 0, e^(-t/(R*C)) = 1 and V = 0; when T is large, e^(-t/(R*C)) approaches 0 and V approaches 5.
81081
g(x)=(x-a)(x+a)/(x-a)\n= x+a\nSince g(x) =4\ntherefore, x+a = 4 \nbut, x=a so substituting the value of x\na+a=4\n2a=4\na=2\nThe constant a = 2.
81560
balanced is the best answer, although constant would be correct as well....or if you're looking for a numerical answer, it would be 0
307829
A term is a variable, a constant, or the product of a constant and variable(s).  So:\n12y\n-12z\n13\n\nThose are the 3 terms in this trinomial.
357903
When V(t)=0 the particle stops.\nIt can have a(t)=0, but still moving (constant speed)
238404
thanks 4 voting my answer as best but i didnt understand what u said\no divided by any no is always zero and with exception of zero where i guess it's not defined(aint that also zero iam not sure)
1052664
Not changing or subject to change; constant.
84903
In C++, const is used to declare a constant. A constant is similar to a variable in the sense that it represents a memory location. It differs, as I sure you can guess, in that cannot be reassigned a new value after initialization. In general, constants are a useful feature that can prevent program bugs and logic errors. Unintended modifications are prevented from occurring. The compiler will catch attempts to reassign constants new values
727467
It can be a constant or a variable.  It asks what is the behavior of the function as x approaches the "a" variable or constant.  Thus,\nlim x->a [(x - a)²]/[1 + cos (π/a x)]\n\nLet me show you.  We first get the limit:\n_______________________________________\n| Since it is the indeterminate form 0/0, we can use the \n| L'Hopital's rule.\n| lim x->a [2x - 2a]/[- π/a sin (π/a x)]\n|\n| Again, it is 0/0, so use L'Hopital's Rule,\n| lim x->a 2/(-π²/a² cos (π/a x)]\n|\n| We can now substitute x\n| = 2/(-π²/a² cos π)\n| = 2/[-π²/a² (-1)]\n| = 2/(π²/a²)\n| = 2a²/π²\n|__________________________________\n\nWe now have the limit\n= 2a²/π²\n\nNow, you can interpret this limit in 2 ways.\n\nIf "a" is a constant, then the limit of that function (of only 1 variable, x) when the variable x approaches an unstated constant "a" is the limit that we have acquired (which, in this case, is a constant).\n\nNow, if "a" is a variable, then the limit of that function (of 2 variables, a and x) when the variable x approaches the value of the variable a, is a function of a single variable, which is the limit we have acquired (which, in this case, is a function).\n\n^_^
133024
y = 0.\n\nETA: That's if we're to assume that the value of x is constant between the equations.