plzzzzzz.............volume of cube Q?
961118
Yes if you add cubic centimeters W*H*L
778715
increments of radius is 0.001 in/min\nincrement of area is 3.14(1.801^2-1.8^2)=0.0113 sq in\nhence increment of volume is 6*0.0113=0.0678 cu in/min\n\nMore scientific solution\nassume radius increments = dx\nthen volume increment V will be Height*area increment\nV = 6*3.14{(R+dx)^2-R^2} = 18.84(R^2+2Rdx+dx^2-R^2)\nV=18.84 (2Rdx)  when dx close to 0 then dx^2 can be omitted\nthen dV/dt = 37.68 R dx/dt = 37.68 * 1.8 * 0.001 =0.0678 cu in/min
322239
Try Cube: http://www.cubeengine.com
738861
If you are talking about a 3-D rectangle,\n\nThe volume of a rectangle is height times width times depth.  \n\nYou can also use base times height if its easier.\n\nhope this helps!
16584
You can find the volume using a triple integral
934849
291.13 L is the correct volume.\n\nCheck your algebra when you are solving for V1.
85173
at the command prompt. type "FORMAT D: /q |y" \n(without the double quote and assuming your 8gb is on drive d)
306191
a) cube...final answer
984888
it would be 2/3 of the original surface area\n\nOriginal Cube Surface Area:\n6 sides.....one side = Length * Width\n6*L*W\n\nIf you cut it exactly in half, you have 2 sides that are still Length * Width, and 4 sides that are HALF Length * width....so u can combine those 4 halves to make 2 wholes and ur surface area will be 4 (Length*Width)'s\n\nmaking it 4/6th of the original surface area\nsimplifying gives u 2/3
730124
1. volume = h*2*pi*r^2 =1000 so r^2= 1000/2/pi/h\n\nsurface area = 2*pi*(h+2*r^2)\nsurface area / volume = (h+2*r^2)/h/r^2 \n=1/r^2+2/h  = 2*pi*h/1000+2/h  which is a minimum when h is about 17.84  [(1000/pi)^0.5]
173051
area is .001 X .001 = .00001 (the area per cube face) X 6 ( the number of faces on a cube)=.00006 cm squared.\nVolume is length times width times height, or .001 X .001 X .001 = .0000001 cm cubed\n\nso, .00006/.0000001 = 6/.001 = 6000.
924127
just multiply the side of the cube 3 times
854049
You don't. Feet are a length measurement, and cubic feet measure volume. If I had a cube 2 feet on a side, the volume would be (2)(2)(2) = 8 cubic feet.\n\nWhen you multiply feet by feet by feet, you get cubic feet. Funny how that works :)\n\nHope that helped.\n\nUMRmathmajor
635866
I might be missing something, but the cubic space something occupies is also referred to as it volume, where:\n\nfor a six sides regular box shape volume = heightxbreadthx depth\n\n( make sure all your measurements are in feet eg 1 foot 5 inches is 1 and 5/12 feet. \n\nHowever this formula is not true for a sphere or a trapezoidal box or a pyramid.  For whcih I'd recommend wikipedia or the old maths textbook as its hmmm, err 18 years since I last did all that stuff.
729521
Here's what we know so far:\n1. Let x = the length of one of the sides of the cube in inches.\n2. The volume of the cube is x^3.\n3. The rate of change of volume is d(x^3)/dt = 3.\n4. The surface area of one of the sides is x^2.\n5. The surface area of the entire cube (six sides) is 6*x^2.\n6. The rate of change of surface area is d(6*x^2)/dt. (This is what you're trying to solve for.)\nHere's the solution:\n7. Use the chain rule on (3): d(x^3)/dt = d(x^3)/dx*dx/dt = 3*x^2*dx/dt = 3; or x^2*dx/dt = 1.\n8. Evaluate (7) with x = 12: 12^2*dx/dt = 1 or dx/dt = 1/144.\n9. Use the chain rule on 6: d(6*x^2)/dt = d(6*x^2)/dx * dx/dt = 12*x * dx/dt.\n10. Substitue (8) into (9): d(6*x^2)/dt = 12*x * 1/144 = x/12.\n11. Evaluate (10) with x = 12: d(6*x^2)/dt = 12/12 = 1. Units are inches^2/minute. Answer is 1 sq. inch per minute.
18353
There are many possibilities, but the one using whole numbers is a pyramid with a square base that is 3cm. on each side and has a height of 10cm.\n\nVolume = (length x width x height)/3
982484
i think the volume is constant, so\nV= pi r^2 h, so\nh = V/(pi r^2)\nthen\n dh/dt = V/pi * (-2)/r^3 * dr/dt =\n- 128*2/(1,8)^3 * 0.05 which i think is a) \nBtw it's pi not pie....lol