PLEASE...PLEASE...PLEASE someone help me with these math problems!!!?
964521
1. I think there's more information needed here.  There are several functions of x such that an x value of 4 will produce a function value of -5 (f(x) = x -9, f(x) = 2x -13, f(x) = x^2 - 5x -1, etc.).\n\n2. I assume that your original function is f(x) = 1/(x^2 - 2x - 8), not f(x) = (1/x^2) - 2x - 8.  If that assumption is incorrect, my answer will be wrong.\n\nThe only way 1/(x^2 - 2x - 8) can be negative is if (x^2 - 2x - 8) is negative.  Thus, you should set up a new inequality like this:\nx^2 - 2x - 8 > 0\n\nFactor:\n(x - 4)(x + 2) < 0\n\nNow, we know that when two numbers are multiplied together, the only way you end up with a negative is if one of the numbers is negative and the other is positive.  Thus, you need to figure out where that will be true in this case\n(x - 4) is positive for all numbers > 4 and negative for all numbers < 4\n(x + 2) is positive for all numbers > -2 and negative for all numbers < -2\n\nThe easiest way to figure out your interval would be to draw this out on a number line, but the answer is -2 < x < 4.\n\n3. 2^2 = 4.  Therefore, 4^(2x + 1) = 2^2^(2x + 1) = 2^(4x +2)\n2^(4x + 2) = 2^(3x + 6)\n4x + 2 = 3x + 6\nx = 4
800717
(1) First one is copied wrongly by you                                            (2) Where is the equal to sign?                                                        (3)This equn. also cannot be solved                                              (4)-p/16+5=9  Multiplying all the terms by 16 ,we get -p+80=144   =>-p=144-80=66 Therefore p=66 YOU SHOULD BE MORE CAREFUL BEFORE SENDING YOUR PROBLEMS TO YAHOO ANSWERS.HOWEVER,YOU MAY SEND THE CORRECTED VERSION OF THE PROBLEMS TO ME IMMEDIATELY THROUGH YAHOO ANSWERS.
965314
Not sure why u can't do these yourself but 1) = -360 \n2) -12\n3)-56.8\n4)-45\n5)1328\n6)-144\n7)-.5\n8)25\n9)11\n Those should be right
437783
1) 1, 2, 3 and 6\n2) 1, 2, 2m\n3) 1\n4) 1, 3\n\n5) 5/9 (55/99) > (45/99) 5/11\n6) 2/3 (8/12) < (9/12) 3/4\n7) 4/5 (32/40) < (35/40) 7/8\n8) 1/3 (4/12) = (4/12) 4/12
937250
PROBLEM 1:\nBobby is 3 years old.  His sister Nancy is four more than six times as old as Bobby.  How old is Nancy?\n\nPROBLEM 2:\nThe pizza parlor cuts large pizzas into 6 slices and small pizzas into 4 slices.  If Ryan buys 3 large pizzas and a small pizza, how many total slices will he have?\n\nPROBLEM 3:\nThere are 3 hexagons and a square drawn on a piece of paper.  How many total sides are there?\n\nPROBLEM 4:\nWhat is the base-10 equivalent of 34 base-6?\n\nPROBLEM 5:\nAdult tickets are $6 each and child tickets are $4 each.  How much will it cost for a family of 3 adults and 1 child?
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
806420
Go to their website and you might be able to get the answers. Or if you have the book, they have all of the odd answers in the back of the book.  (Or if you have an older sibling who's really good at math, they can help a lot!)
117522
1. x=1.25\nSol'n.\n1/3x+1/2=11/12\n1/3x=11/12-1/2\n1/3x=5/12\nx=15/12\nx=1.25\n\n2. x=-3\nSol'n.\n1.5x+9=4.5\n1.5x=4.5-9\n1.5x=-4.5\nx=-3\n\n3. x=28\nSol'n.\n2(x+2)=3(x-8)\n2x+4=3x-24\n24+4=3x-2x\nx=28\n\n4. x=-12\nSol'n.\nx+5=-7\nx=-7-5\nx=-12\n\n5. x=-10.5\nSol'n.\n-4/7x=6\nx=-42/4\nx=-10.5\n\n6. x=261\nSol'n.\nx/3+2=89\nx/3=89-2\nx/3=87\nx=261\n\n7. a=3.5\nSol'n.\n3a+13=9a-8\n13+8=9a-3a\n21=6a\na=21/6\na=3.5\n\n8. n=0.8\nSol'n.\n15n+9=21\n15n=21-9\n15n=12\nn=12/15\nn=0.8\n\n9. x=-1\nSol'n.\n2(x+6)=-2(x+-4)\n2x+12=-2x+8\n2x+2x=8-12\n4x=-4\nx=-1\n\n10.x=0\nSol'n.\n-(x+2)-2x=-2(x+1)\n-x-2-2x=-2x-2\n-3x+2x=-2+2\n-x=0\nx=0
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
275079
1) m= (2-4)/(2-5) = -2/-3 = 2/3\n2) m= (1-1)/ (-8+9) = 0/1 = 0
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
1129355
Question 1:\n\n\n(-2)^2=(-2)(-2)=4\n4 * 4=16\n\n8(-2)=-16\n\n16-16=0\n\n3(-2)=-6\n0-6+6=0\n\nanswer:  zero\n\nQuestion 2:\n1/3* 3^6=3^5=243\n\nQuestion 3:\n30+825*30/1000+30*15/100\n=30+8,25 *3+4,5\n=59,25\n\n\nQuestion 4:\n598/100*100/26=23\n\nQuestion 5:\n4/5+3/4=16/20+15/20=31/20= 1,55
260828
Go to homeworkhelp.com and get a real live tutor. You chat with them and ask your question and they help you figure it out. Don't get too excited though because they don't give you the answer, straight up.
651993
Here's the best I can do to help with the first one.\n   __x_+9___\nx-2)X^2+7x-2\n    x^2-2x\n    ------\n        9x-2\n        9x-18\n        -----\n           16\nFollow the example for the rest
824758
Question 1 : 4^x - 2 * 5^(2x) < 10^x\n\nFactorise :\n2^(2x) - 2 * 5^(2x) < 2^x * 5^x\n\nDivide through by 2^(2x) :\n1 - 2 * (5/2)^(2x) < (5/2)^x\n\nLet y = (5/2)^x\n\nTherefore, 1 - 2y^2 < y\nor, 2y^2 + y - 1 > 0\nor, (y + 1)(2y - 1) > 0\nThus, y < -1 or y > 1/2\n\nThat is, (5/2)^x < - 1 or (5/2)^x > 1/2\n\nBut (5/2)^x is always > 0, so the only\nsolution occurs when (5/2)^x > 1/2.\n\nTake the reciprocal of both sides :\n(2/5)^x < 2\n\nTake logarithm of both sides :\nx(log2 - log5) < log2\n\nTherefore, x < log2 / (log2 - log5)\nor x < -0.7565 approximately.\n----------------------------------------------------------------------\nQuestion 2 : 7 * 3^(x + 1) - 5^(x + 2) = 3^(x + 4) - 5^(x + 3)\n\nDivide through by 3^(x + 1) :\n7 - 5 * (5/3)^(x + 1) = 27 - 25 * (5/3)^(x + 1)\n\nRearrange :\n20 * (5/3)^(x + 1) = 20\n\nTherefore, (5/3)^(x + 1) = 1 = (5/3)^0\nThus, x + 1 = 0, so, x = -1\n----------------------------------------------------------------------\nQuestion 3 : 6 * 9^(1/x) - 13 * 6^(1/x) + 6 * 4^(1/x) = 0\n\nFactorise for ease of viewing :\n6 * 3^(2/x) -13 * 2^(1/x) * 3^(1/x) + 6 * 2^(2/x) = 0\n\nDivide through by 6^(1/x), which equals 2^(1/x) * 3^(1/x) :\n6 * (3/2)^(1/x) - 13 + 6 * (2/3)^(1/x) = 0\n\nThe latter term, (2/3)^(1/x) = 1 / [ (3/2)^(1/x) ]\n\nSo now we have : 6 * (3/2)^(1/x) - 13 + 6 / [ (3/2)^(1/x) ] = 0\n\nLet y = (3/2)^(1/x)\n\nTherefore, 6y - 13 + 6 / y = 0\n\nMultiply through by y :\n6y^2 - 13y + 6 = 0\nor, (3y - 2)(2y - 3) = 0\nor, y = 2/3 or 3/2\n\nThat is, (3/2)^(1/x) = 2/3 or (3/2)^(1/x) = 3/2\n\nFirst, trying (3/2)^(1/x) = 2/3 = 1 / (3/2) = (3/2)^(-1)\nTherefore, 1 / x = -1, so x = -1.\n\nSecond, trying (3/2)^(1/x) = 3/2 = (3/2)^1\nTherefore, 1 / x = 1, so x = 1.\n\nSo there are 2 solutions, x = -1 or 1.
662213
Anyone can give you the answer, but try here next time you need help with conversion or any other kind of math: \n\n\nhttp://www.gateways2learning.com/BasicMath/BasicMath.htm\n\nGood luck..................
326501
For exemple:\n\n1) 5/4 + 2/6 = (5*6)/ (6*4) + (2*4)/(6*4)\n             = 30/24 + 8/24\n             = 38/24\n\n2) 5/4 * 2/6 = (5*2)/(4*6)\n             = 10/24\n\n3) 5/4 / 2/6 = (5*6)/(4*2)\n             = 30/8\n\n4) 5/4 - 2/6 = (5*6)/ (6*4) - (2*4)/(6*4)\n             = 30/24 - 8/24\n             = 38/24