i dont understand = (?
964772
so if you love him, give him the time and the space he asked for
1036177
sory i didnt get ur Q\ndo u mean 2x-6>x ?\nthen x is greater than 6
782057
look at a few examples and it will make sense\n\nfor example \n\n02 (where the 2 is small)   -> _ O    (the _ is where a number goes)  (2)
5376
first line is "a=b", therefore a-b = 0\nso when it says "divide both sides by a-b", it really means "divide both sides by 0, which results in some probably invalid, and definitely not finite, values on each side"
901449
It's a smiley face.  I wish someone would trell me what this means: \n( . )( . )\n\nor this:\n(_|_)
357409
There is no such thing as OR,AND operator. There are boolean operators OR, AND, NOT, XOR.\nOR is maximizing function and AND is minimizing one.\nLet's observe two integers: 7 and 11.\n(In binary form 7 is 0111 and 11 is 1011): \n7 & 11 == 3\n7 | 11 == 15.
667791
Do you mean "not equal to"?\n<>\nThat's also still supported in some newer languages, although != is more common nowadays.
2302
(1) = x\n(2) = / \n(3) = x
390031
what????????? i cant understand
440005
Pseudocode, I'm not up on my Java syntax:\n\nint sum=0;\nfor(int i=0;i<array.size;i++)\n  sum+=array[i];
790936
x≠０\ncuz if x=0, (x-7)/x^3 is meaningless
763483
If u're asking about boolean "v", then it represents the "OR" function. (And the "reversed v" i.e. "^" represents the "AND" function);\n\n0 v 0 = 0\n0 v 1 = 1\n1 v 0 = 1\n1 v 1 = 1
942085
u can do alt + 3 = ♥\nor <3\n\nxox <3 <3 ♥♥♥♥ <3 <3
365867
2x - (7 + x) <= x\n2x - 7 - x <= x\nx - 7 <= x\n-7 <= 0\n\nSince we're left with a statement with no variables, and the statement is true, x = all real numbers.
339889
You will get a error because you need a loop condition it cant be just 1. for example to print god 5 times make loop condition like for(i=0; i <=5;i++) then it will print "god" five times.
1072291
for the first one it's '1'. this is because of the AB'+1. since anything or'ed with 1 gives u 1. the whole thing turns out to be 1. same thing happens in the other bracket. so when 1 n 1 are ANDed u get 1.\n\nfor the second one remember ther are two terms. one is DE' other is (A+F) in the second bracket the (A+F) term has been complemented. when DE' is ANDed by itself u get DE' again. When DE' is Anded with (A+F) and it's complement u are able to actually factorize it so u can take DE' out and u get the or'ing of a term an it's complement inside. that is 1. therfore it evaluates to DE'. then (A+F) and it's complement gives a 0 when anded. oring everything left u get ED' as the final answer. if u need the working pls msg me
533029
Let's call :\n(a) : x + 2y < 3\n(b) : 2x - 3y < 6\n\nWith the 1st one:\nx + 2y < 3\n<=> 2x + 4y < 6 \n\nThe 2nd one is 2x - 3y < 6\nThat means : \n(a) - (b)\n<=> 4y - (-3y) < 0 \nor 7y < 0 \nor y < 0\n\nWe have also: 2x - 3y < 6 <=> (2/3).2x - (2/3).3y < (2/3).6\n<=> (4/3)x -  2y < 4\nThat means:\n(a) + (b)\n<=> x + (4/3)x < 7\n<=> (7/3)x < 7\n<=> x < 3\n\nSo : x < 3 and y < 0