N*(N-1/2) Project Managment  Formula Question?
916854
Susan, seems pretty straightforward mathematically. N * (N - 1) / 2\n\nOriginal communication channels with N = 4 + 1 = 5\n5 * 4 / 2 = 20 / 2 = 10\n\nNew communication channels with N = 5 + 3 = 8\n8 * 7 / 2 = 56 / 2 = 28\n\nIncremental communication channels is the difference or\n28 - 10 = 18\n\nMake sense?
894151
I think the way to approach this is to minimize the number of remaining (that is, unused) hours to zero.\n\nJob B jobs must be multiple of 10, e.g. 10 jobs = 7 hours exactly (no remainder). \n\nJob C jobs must be multiple of 5, e.g. 5 jobs = 127 hours exactly (no remainder).\n\nUsing this approach, if you did 60 jobs B and 10 jobs C, the hours = 60 * .7 = 42 hours + 10 * 25.4 = 254 hours, total = 296 hours exactly (no remainder).\n\nThis would yield a revenue of $10,465.24 \n\nWrong!\n\nHmmm - (I'm doing this in Excel with columns labeled:\n# of B jobs, # of C jobs, B hours, C hours, total hours, $B/hr, $C/hr, $B, $C, $total; then keeping total hours <= 296, what is max $total)\n\nBest answers using Excel:\n# of B jobs, # of C jobs, B hours, C hours, total exact hours, $B/hr, $C/hr, $B, $C, $total\n\n0,11,0.000,279.4,279.400,$35.51 $35.33 $0.00 $9,871.20 $9,871.20 all C\n\n422,0,295.400,0,295.400,$35.51 $35.33 $10,489.65 $0.00 $10,489.65 all B\n\n386,1,270.200,25.4,295.600,$35.51 $35.33 $9,594.80 $897.38 $10,492.18 \n\n23,11,16.100,279.4,295.500,$35.51 $35.33 $571.71 $9,871.20 $10,442.91 \n\n350,2,245.000,50.8,295.800,$35.51 $35.33 $8,699.95 $1,794.76 $10,494.71 \n\n314,3,219.800,76.2,296.000,$35.51 $35.33 $7,805.10 $2,692.15 $10,497.24 optimum\n\n277,4,193.900,101.6,295.500,$35.51 $35.33 $6,885.39 $3,589.53 $10,474.92 \n\n241,5,168.700,127,295.700,$35.51 $35.33 $5,990.54 $4,486.91 $10,477.45 \n\n60,10,42.000,254,296.000,$35.51 $35.33 $1,491.42 $8,973.82 $10,465.24 \n\nLooks like 314 B jobs and 3 C jobs win!\n\nI'm not sure how to put this in an optimization formula...\n\nHope this helps!
1053054
Use the binomial.  I've already shown you how in a previous question.  And you already know that you need to use it.
375635
Kp=Kc(RT)n\na.Kp=Kc(RT)-1/2\nb.Kp=KcRT\nc.Kp=KcRT\nd.Kp=Kc(RT)2
313772
the answer is 5/p.\nhere is how it go.\n 1 page ----->  p min.\n x page ----->  5 min.\nsince it is direct relationship i.e. more page more time.\nw'll do cross product i.e. 5 * 1 = p * x\nso it comes out to be  x = 5/p.
1139003
(n/(n - 3)) + (5/(2n - 6))\n(n/(n - 3)) + (5/(2(n - 3)))\nMultiply everything by 2(n - 3)\n(2n + 5)/(2n - 6)
1081631
T = 8239\nE = 1/2\nA = 1\nM = 1/3
847480
Q = m * Cp * DeltaT.\n\nPlug the numbers in.  Get Cp from your book.
403252
let x be the number from A\nlet y be the number from B\nlet z be the number from C\nthey have 500 pounds\nso\n2x+2y+3z=500\nand we have 1000 hours to produce \nso \n4x+5y+5z=1000\nsolve this system with respect to x u will get the following\n-2(2x+2y+3z=500)\n   4x+5y+5z=1000\nadd them u get \ny-z=0\nthen y=z\n5(2x+2y+3z=500)\n-2(4x+5y+5z=1000)\nu add and get\n2x+5z=500\nthen z=(500-2x)/5=100-2x/5\nz=y=100-2x/5\nlet f(x)=500x+600y+1000z=500x+y(1000+600) since y=z\n        =500x+1600y\nsubstitute y and z\nu will get\nf(x)=500x+1600(100-2x/5)=500x+160000-640x\n    =160000-140x\ndifferentiate f(x)\nu get\nf'(x)=-140\nso it is maximal when x=0\nthen y=z=100\nand profit =f(0)=160000$\nf(x)=
864388
some formulas that can help :\nhttp://www.eskridgeinc.com/support/formulas.html
242452
This is a typical combination problem.\n\nformula for combination is n!/r!(n-r)!\n\n= 9! / 5!(9-5)!\n= 9! / 5!4!\n= 126 (ANS.)\n\nfactorial ex. 5! = 5 x 4 x 3 x 2 x 1\n\nDONT FORGET TO RATE THIS AS BEST ANSWER
1169800
work done 1.078 X 10^5\nheat is -0.292X10^5
604983
Thats simple. The formula is: Y2-Y1/X2-X1\n\nIt would be: 7-3/6-2 which is 4/4 which is 1. The slops is 1.
704007
use arithmatic progression formula n(2a+(n-1)d)/2\nwhere n=no. of terms. a=value of first term and d=common difference between each consecutive term\nsay fro your first eg. no. of black ball = 1+3+5+...\nn=10 a=1 d=2\nso sum = 10(2+9*2)/2 = 100\nsolve the rest by changing values of n, a and other variables respectively
929018
mn=20!\nmn= 20*19*18*17*......*2=20!\nif m=20; n=19!\nif m=20*19; n=18!\nand so on.\nso m=20!/n; n=i! .... i 20 to 1\n\n0<m/n<1 means that m Not eq 0; and m < n\nby solving the above,\nm will remain < n only till iteration 8\n\nSo the ordered pairs are:\nm=20!/20!; n= 20!\nm=20!/19!; n=19!\nm=20!/18!; n=18!\nm=20!/17!; n=17!\nm=20!/16!; n=16!\nm=20!/15!; n=15!\nm=20!/14!; n=14!\nm=20!/13!; n=13!
603804
apply formula for it\nits easy
737278
In general, the formula is (n - 1)!, but notice that an arrangement is the same when you reverse the order of the guests, so the formula will be (n - 1)!/2.  In your case, 9!/2 = 181440 arrangements.\n\n^_^