How many moles of CaCl2 are in 250 mL of a 3.0 M of CaCl2 solution?
919031
to find Moles use the equation:\nMolarity = moles/Litres\nmolarity = 3.0M\nmoles = ?\nLitres = 0.25L\nso rearrange the equation to get\nMolarity X Litres = moles\n3.0M     X  0.25L = moles\n                           = 0.75\nTherefore there are 0.75 moles of CaCl2 in the solution
165367
molality = moles of solute / kg of solvent.\n\n200 grams of water  = .2 kg of solvent.\n\n.3 molality = x moles / .2 kg\nsolve for the number of moles (x).\n\nThen multiply the number of moles by the Molar mess of Silver Nitrate and that is your answer.
736794
I'll teach you how to do these.  The answer may seem long at first, but just try it, and you'll see it's not as bad as it first appears.  For mass/mass problems, you only have to use the first section of this answer:\n\nToo solve these types of problems, use the following general steps:\n\n[I will use the general word equation: calcium hydroxide reacts with lithium bromide to produce     calcium bromide and lithium hydroxide; as an example, throughout each step, to aid in your learning]\n\n(1)  Write the correct chemical formula for each substance in the reaction.  Be certain each chemical equation is correct!   (ex:  calcium hydroxide:    correct formula  = Ca(OH)2;   NOT CaOH.)\n\n(2)  Write out the chemical equation;   ex:  Ca(OH)2  +     LiBr   gives      CaBr2    +       LiOH    \n\n(3)  Balance this chemical equation;    ex:   Ca(OH)2  +  2LiBr   gives   CaBr2   +   2LiOH\n\n       Note:  this balanced equation is TELLING you that one mole of calcium hydroxide is reacting with 2 moles of lithium bromide to produce (gives) one mole of calcium bromide and 2 moles of lithium hydroxide.  It is TELLING you the relative number of moles of each substance.  \n\n(4)  Determine the MOLE RATIO of the substances involved;  ex:  if the question says you have 1.0 moles of calcium hydroxide and it reacts with an excess of lithium bromide, and asks how many moles of lithium hydroxide are produced,  the answer would be 2.0 moles of lithium hydroxide.  In other words, the MOLE RATIO of calcium hydroxide to lithium hydroxide is 1 to 2, also written as a “1:2 ratio“.    ex:  same question but suppose you have 3 moles calcium hydroxide.  Because the mole ratio  is 1:2, you would produce 6 moles of lithium hydroxide.   A ratio of 3:6  =  a ratio of 1:2;  (you just reduced it to simpler terms).  \n\nStop here if you  are simply given the number of moles of product you have, and asking how many moles of some different substance are produced in a chemical reaction.  \n\n\nSame type of problems, but working with grams instead of moles:\n\nyou simply have to do a couple of extra steps:\n\nI will use the same reaction as above, but will change the question to this:  \n\n“If you have  255 grams of calcium hydroxide, how many grams of lithium hydroxide will be produced, (assuming you have an excess of lithium bromide)”.  \n\n [Note:  unless the question states otherwise, assume you have an excess of the other reactant, thus giving the maximum yield of product; see “Limiting Reagents” below to solve those types of problems]. \n\nTo solve, complete the first 4 steps above (we’ve just done that):\n\n(5)  Convert grams of substance into moles of substance!!!   This is essential in solving these types of problems.  THE KEY STEP FOR ALL PROBLEMS OF THIS TYPE IS TO ALWAYS CONVERT EVERYTHING INTO MOLES FIRST!!!  The general formula’s are as follows:  \n\n                        Moles  =  grams / molecule weight\n\nOr you can use basic algebra and say the following:  \n\n                    Grams  =  Moles   X   molecular weight\n\n[Note:  “molecular weight” is used to describe molecules; “formula weight” is used to describe ionic compounds; and “atomic weight” is used to describe elements;  ALL of them are the sum of all the atomic weights of the elements in the substance. In the case of a single element, alone by itself, this refers to the atomic weight of that element.  Note that the 7 elements:  hydrogen, nitrogen, oxygen, fluorine, chlorine, bromine and iodine only exist as “diatomic” elements, when they are ALONE by themselves (not combined with any other element(s)).  Thus H2, is the correct way to write the chemical formula for hydrogen when it is all alone, by itself.  And it is a molecule, and it’s molecular weight would be equal to 2.0.  This is the same for the all diatomic molecules:  the molecular weight will equal double the atomic weight for that particular diatomic element (because there are TWO a
800121
3.0% m/v = 3g/100mL of solution. so 25ml/100ml=.25; .25 X 3g= .75g or 750mg, whatever units you want
984571
1 litre (1000 ml) of 1 M solution of NaCL contains 23 + 35.5 gms =58.5 gms (ie 1 molecular wt of sodium chloride in gms dissolved in 1 lit of solution)\n\nHence 1 lit of 0.360 M solution  will contain 0.360 X 58.5 gms or 21.06 NaCl (Sodium Chloride) \n\nTo find out exact vole in ml which contain 21.14 find volume by this formula 2.14 divide by 21.06 multiply 1000 , (ie 2.14/21.06 * 1000 ) 101.6 ml\n\nPS\nbasic assumption is 0.360 M indicates .360 Molar solution. \n(ie: M stands for Molar)
726441
4.74 / 300 = 0.0158 g/ml\nin 35 ml\n0.0158 * 35 = 0.553 g\nDividing by 40 g/mol (MW) we get\n0.553 / 40 = 0.0138 mol in 100 ml\nSo in 1000 ml the number of moles will be 0.138\nThe molarity is then 0.138 M.
863394
3M it has 3 times the molarity of 1M, the 3M has 3 mols of hcl for every liter and the 1 has 1 mol for every liter and since 3 is a bigger number then one im sure u can take it from there.
461143
Well, look at each species. NaCl dissociates into two ions, giving a strength of 0.20M. In 400 mL, that'd be 0.08 moles.\n\nFeCl3 dissociates into four ions, giving a strength of 0.40M. In 200 mL, that'd also be 0.08 moles.\n\nCaCl2 dissociates into three ions, giving a strength of 0.30M. In 300 mL, that'd be 0.09 moles.\n\nKBr dissociates into two ions, giving a strength of 0.20M. In 200 mL, that'd be 0.04 moles.\n\nSo, the calcium chloride (CaCl2) solution contains the greatest number of ions.\n\n\nHope this helped.
361205
1,000,000 millimoles= 1 mole \ntherefore u'd need 50/1,000,000 * 147kg of calcium chloride \nie. 0.00735kg and since 1000g=1kg u multiply this by 1000 and that gives u 7.35 grams.\nhope this helps... cheers
775430
25% citric acid will have a concentration of 250 g/l.\n\nDividing by 192.1 g/mol we will get:\n\n(250 g/l) / (192.1 g/mol) = 1.3 mol/l = 1.3 M.
728109
Number of moles = mass/formula mass for a pure acid.\n\nBut acids in solution have a different equation:\n\nmoles = volume x molarity/1000\n\nThe volume in the above equation is in cm3.
519052
Na2CO3 + CaCl2 -> __2NaCl + CaCO3
733075
Two moles of HCl are rquired for every mole of X2CO3.\n\n27 cm3 is 27/1000 dm3 = 0.027 dm3 of HCl\n\n0.027 dm3 * 0.100 mol/dm3 = 0.0027 moles of HCl\n\nThis means that there were 0.0027/2 = 0.00135 moles of X2CO3\n\nIf 1.86 g of X2CO3 were in 250 cm3 of solution, then 25 cm3 would contain:\n\n25 cm3/250 cm3 * 1.86 g = 0.186 grams of X2CO3.\n\nFrom this we know that 0.00135 moles = 0.186 g\n\n0.186g/0.00135 mol = 137.8 g/mole.\n\n(by the way, this would mean that the atomic mass of the metal = 39 or so.  The metal is Potassium).
861217
molarity = moles/L\nso just plug in what you have!  6.3M= mol/0.216 L   just multiple 6.3 by 0.216 and you will get the moles of the acid (i dnt have a calculator on me right now, but just do the calc out and theres ur answer! ) :)
979643
Assuming you meant the MASS or the number of moles of Calicum, and assuming your asking the ratio of Ca+2 to CN-  it would be 1/2 the molar mass of CN-, or equal to the number of moles of substance.\n\nFor example, if you had 1 mole of CaCN2, you would have 1 mole of Ca+2 and 2 moles of CN-.  If you know the number of moles you can find mass, and if you know the mass you can find number of moles.\n\nI'm not sure what your looking for here, but if you maybe re word it some I will be able to help.
159316
[Ca(NO3)2]=n/V  ---> n=[]*V= 0.390M * 0.044L=0.01716 mol\nn=m/M ---> m=n*M= 0.01716mol * 164 g/mol=2.81424 g
341279
125mL of 0.251 M HCl gives 0.125 * 0.251 mols of HCl\n\nThen 250 + 125 mL is 375 mL = 0.375 L\n\nSo 0.125 * 0.251 mols in 0.375 L gives 0.125 * 0.251/0.375 M\n\nThat is 0.084 M