Any Math Wiz here? Help please..?
928416
Aw, come on, it's not that hard...\n\nSince you know that Jerry's age = x, and Tom is three times as old, then Tom's age = 3x.\nNow you can write the first three:\n\ni :  3x (Tom's age in 1994)\nii: x+10  (x is jerry's age in 1994, plus ten years)\niii: 3x+10 (same reasoning)\n\nNow for (b)\n\nOkay, in 2004 Tom is twice as old as Jerry (careful, this one *can* get a bit tricky):\n\ni:  x = J*2  (an equation in x -- tom is twice as old, or 2 times, jerry's age)\nii:  assign a value to J for jerry's age, say 20, and it's:\n     x = 20 * 2\n     x = 40\n\niii:  No way to tell this without some additional information!  You have to know how old one of them was at some point in time...
298555
If it's math you can get some pretty good help at math.com. going to google for extra practice in pretty much anything. edhelper has worksheets you can print.
1168806
Do your own math homework...
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.
491746
If u could give the entire question i could solve it for u and i'm not jokin. its actually quite easy.Its basically\n\n(w+3)/4w * 2w/(w-3).So wat ud have is\n\n1/2( (w+3)/(w-3) )\n\nits xactly like sayin 2/4 = (2/1) / (4/1)
1127430
try this one http://www.algebrahelp.com/
950092
Do a Yahoo search.  Enter "Homework help, math."  There are bunches of web sites.  Good luck.
957682
half it then times it by 2! that will give u the answer
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.
37738
try sosmath.com  they helped me before. if they don't have the answer you are looking for they have a list of links to tons of other math sites.  \n\nand there probably is someone on your campus that can help as well.  One on one help is always best...\n\nGood luck!
821450
go to a math website off yahoo. it should help.
891080
1. Xc = 1/2πfC\nSo 2πfC = 1/Xc\nSo C = 1/2πfXc\n\n2. ib = ibq + √2is\nSo √ = ib - ibq\nSo 2is = (ib - ibq)²\nie is = ½(ib - ibq)²\n\n3. Q = XL/R\nSo XL = QR\n\n4. Lt = L1 + L2 - 2Lm\nSo 2Lm = L1 + L2 - Lt\nie Lm = ½(L1 + L2 - Lt)\n\n5. R1=i2 R2 / i2\n??????? So R1 = R2\n\n6. Es = E1 + E2 + E3\nSo E2 = Es - E1 - E3\n\n7. R1 / Rx = R2 / R3\nSo Rx / R1 = R3 / R2\nSo Rx = R1 * R3/R2\n\n8. y = Mx + b\nSo Mx = y - b\nSo M = (y - b)/x\n\n9. i2=i1 R1 / R2\nSo i1 R1 = i2R2\nie i1 = i2 R2 / R1\n\nI would be extremely concerned about your progress if you find this simple algebra a serious chore!!!!!! (Especially if you are learning the electrical trade)
228388
Actually I had something to help you but x=0 which makes it pretty difficult.\n\nI guess you could try to talk about tomatoes or something.  Say Tom (X) has 1/2 the amount of tomatoes that Jill has, plus four.  Or in other words, if you take Jill's amount of tomatoes, multiply it by two, and take Tom's amount and multiply it by three, there total amount of tomatoes will equal 12.  How many tomatoes does Jill have?  How many does Tom have?
490047
I think a calculator would be great for this one! It sounds perfect for a math wiz to try...Good luck! MayMay
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
1132233
this question will require calcs using logarithm.\nhence will take time