Math question on Linear Equations?
913489
Lets take the first 2\n\n120s+150m+174L=36000\n-4(30s+36m+48L=9000)   <---multiply whole thing by -4 to get rid of s\n\n120s+150m+174L=36000\n-120s-144m-192L=-36000  <---now added both together\n\n6m - 18L = 0 solve for m\n6m = 18L\nm = 3L\n\nDo the same for 2nd and third ones but try to get s = L\n30s+36m+48L=9000\n-9(4s+4m+4L=1000) multiply by -9 to get rid of m\n\n30s+36m+48L=9000\n-36s-36m-36L=-9000 <--add together\n\n-6s + 12 L = 0\n-6s = -12L\ns = 2L\n\nNow plug both answer into the last one\n\n4(2L) + 4(3L) + 4L = 1000\n8L + 12L + 4L = 1000\n24L = 1000\nL = 41 2/3 or 125/3\nSo plug this into s = 2L and m = 3L to get answers.\n\nL= 125/3, s= 250/3, m=125 Plug into any of the equations to check your answers.  I'll use the third one\n\n4 (250/3) + 4 (125 ) + 4(125/3) =? 1000\n(1000/3) + 500 + (500/3) =? 1000\n(1500/3) + 500 =? 1000\n500 + 500 =? 1000\n1000 = 1000 CHECK
145305
Use cubic equation \ny=ax3+bx2+cx+d\n\nSince you have four points data you can get four linear equations with four variables which is very easy to solve, get variables (a,b,c,d) and plug the values to cross check and see u will get answer. Use guass jordan or elimination method.
642018
Wonderful.\nTHis is some sort of simultaneous equation.\nAccording to the principle of this equation, we try to rationalize one term of the equation so as to get one unknown term. We can either try finding the x term or the y term. For your question as to find the y term.\n\nFirstly, we rationalize the x terms by multipling them by the inverts. then it will result to \n                                    12x + 20y = 32\n                                    12x + 18y = 39\nThe we apply the subtraction rule. ie. we multiply all the terms beneath by the negative (-) sign. This will result to \n                                    12x + 20y = 32\n                                   -12x - 18 = -39\nWe later subtract so as to attain\n                                2y = -7\nWe apply the law of linear equation by dividing both sides by the coefficient which in this case is 2.\n                              2y/2 = -7/2\nThis will eventually cancel the 2 in the first term therby leavin y alone. \n The answer will be in either of the following cases through simplification.  -7/2, -3 1/2 or -3.5
187542
Answer:\ny=-1.25x + 3\n\nProof:\nWe are given two points to work with:\nPoint 1: (x1=0, y1=3)\nPoint 2: (x2=4, y2=-2)\n\nSo, use the "two point equation" to solve this problem.\ny-y1 = (y2-y1)/(x2-x1) * (x-x1)\n\ny-3 = (-2-3)/(4-0) * (x-0)\ny-3 = -5/4 * x\ny = -5/4 * x + 3\n\ny=-1.25x + 3
744692
Consider the following equations:\n1)   2x + y = 4 \n  \n2)   x − y = −1 \n\nTo solve them simultaneously, first, you need to solve one equation with respect to one variable. Let's solve the first one:\n\n2x + y = 4  Rearranging, you get:\ny = 4 - 2x\nNow you know the value of y, so plug it into the second equation, like this:\n\nx − y = −1 Rearrange using the value for y that you determined above:\n\nx - (4 - 2x) = -1\nNow solve this equation, since it now has only one variable:\n\nx - 4 + 2x = -1\n3x = 4 - 1 = 3\nx = 1 Now that you have the real value for x, go back to the first equation and solve for the real value of y:\n\n2x + y = 4  \ny = 4 - 2x  we know x = 1 so, y = 4 - 2\ny = 2\n\nYou can prove these are the right answers by using them in the equations.
123571
add the two equations on left hand side and right hand side\n\n3x - y + 5x + y = 4 + 4\n\n8x = 8\n\nx = 1\n\nput this into the first equation\n3(1) - y = 4\n-y = 4 - 3 = 1\ny = -1\n\nHence x= 1 y = -1\nconfirm it by checking the 2nd equation \n5(1) + (-1) = 4 \nCORRECT!
570575
In a diagram where x denotes the horizontal axis and y the vertical axis, linear equations with only one variable (x or y) is either a horizontal or vertical line.\n\nexample 1:\n\ny = 3 is a horizontal line that connects all points in the diagram which have the y-value 3.\n\nexample 2:\n\nx = 5 is a vertical line that connects all points in the diagram which have the x-value 5.\n\nI hope this is clear?
77431
Any linear combination of x, y and a scalar when is put equal to 0 gives the equation of a line: that is "a term in x + a term in y + a number = 0" is a line.\n\nSo write a line whatsoever's equation:\n\nfor example (but you change it, please)\n\n4x -2y - 5 =0\n\nNow if you multiply all the terms for the same factor, you get an equivalent equation so you get a coincident (= the same) line:\nfor exemple, let's simply change all the signs:\n-4x +2y +5 =0 is always the same line\n\nAnd you can build infinite equations of the same line in this way\n\nP.S. = remember NEVER choose 0 as a multiplicator!
616552
yes...\n\nbecause it is in the form of ax+by=c.\n\nbut if u rearrange the equation to y=(4/5)x-4\nwhich is in the form of y=mx+c, with m is the gradient and c is the y-intercept, it is not a linear equation, but rather a "Cartesian equation".
753426
X2   5x - 4y = 1\n10x -8y =2\n-10x + 8y = -3\n-------------------------\n  0=-1                NO SOLUTION
744496
A row of AB is of the form RB where R is a row of A. Now, if\nR1, R2, ...Rk are linearly dependent, there are constants c1,..ck\nwhere\nc1*R1+c2*R2+..ck*Rk=0.\nNow apply B on the right to get your result.
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
1066425
A system of linear equation has a unique solution if and only if the determinate of the coefficients matrix is not equal to zero. Therefore, for your system\n\nx+5y=10\n-2x-10y= -20\n\nThe determinate is\n|   1     5    |\n|  -2   -10  |\n\ndet= 1*(-10) – 5*(-2) = 0\n\nThen the system is linear dependency and has infinite number of solutions.
1079419
The answer is b, multiple solutions, if you work the problem so that it's in reduced row echelon form you will see that there are many possible solutions to the linear equations.
978722
You can't, algebraically.  You have two equations and three variables.  Sorry.  You need one more equation, such as a = b.
917321
x+y=2\n2x-y=0\n\nx=2-y\n2(2-y)-y=0\n\nX=2-y     \n4-3y=0   \n\nx=2-4/3\ny=4/3
1174662
2(x-4y+1)+3(-2+y-2)\n2x-8y+2-6+3y-6\n2x-8y+3y-6-6\n2x-5y-12\n\n2x-5y-12= answer\n\nHope this helps you.