Find the measure of the supplment of an angle that measures 56 degrees?
928764
You would just do 180-56 to equal 124 degrees\n\nsupplementary angles add up together to equal 180 degres or a straight line
606300
well, think about it- how many degrees are there in ALL triangles? \n\nif you know 2 angles, you only need one more. Let's say 2 angles were 44 and 72. The two angles combined are 44+72. If you know how many degrees there are overall, you would subtract how many you have from what you know needs to be there!
98672
use the tangent ratio ( trig function ) or inverse tangent of (6/ (43/8)) OR iNV TANGENT (1.116) = 48.14 degrees and to get the other angle, just subtract it from 90 degrees or 41.86 degrees. hope it helps how I got it. go over the trig function or cohsahtoa rule
808242
Yes. These are intriguing geometry problems. What is YOUR question? Be specific. Post ONE question and be specific about where you are stuck. Right now, this just looks like you want someone to DO your homework for you. But you wouldn't cheat on your homework like that, would you?\n\nHere's a hint -- supplemental angles add up to 180\n\nFor example, if one angle is 60 degrees, its supplement is 120
471483
Your question is difficult to understand.  From what I make of it, here is my answer (and I could well be wrong)\n\nI assume x and y are angle measures (in degrees)\n\nBC=2(angle A)\n6y=2(2x)\n6y=4x  (eq. 1 to be referenced below)\n\nAB+BC+AC=360 degrees\n6y+6y+4x=360\nUsing (eq. 1)\n6y+6y+6y=360\ny=20\nx=6y/4=30
73727
Angle of deviation, d = i1 + i2 - A\nA= r1 + r2\nIn minimum deviation, µ = {sin(A+D)/2}/(sinA/2)
275762
cos(315)degrees=cos(360-45degrees)\n               =cos 45degrees\n               =1/root2
1128048
Regarding your edit... y = 90º is wrong. All the rest have shown the process, and they are right. With tthat figure, y = 108º
136459
Find the factors of 56 (or all the possible measures of sides that would equal an area of 56). \n2 and 28\n4 and 14\n7 and 8\n\nThen add 2l + 2w to get the perimeters.\n2(2) + 2(28) = 60\n2(4) + 2(14) = 38\n2(7) + 2(8) = 30\n\nSo the least perimeter would be 30 cm.
140611
Complementary angles add up to 90 degrees.\nSupplementary angles add up to 180 degrees.\n\nJust think in alphabetical order: C comes before S, and 90 comes before 180.
760142
multiply the degrees by pi and divide by 180\ndegree*pi/180=radians
110612
2x\nwhen the side opposite the 30 degree angle is x\nand the side opp the 60 degree angle is x(root3)
112740
Actually 56% is 56/100, then if you simplify it you will have 28/50 then 14/25 (each step divided by 2 if you prefer it slower)
816949
Angle measurement, which is the meaurement behind latitude and longitude (the angle being at the center of the earth) are measured in degrees to start with, but to get the measurement more precise, degrees are divided into minutes, and the minutes are divided into seconds.  (Nothing to do with time measurement, except that a degree has 60 minutes, and a minute has sixty seconds).  So 54 35' 45.6" reads 54 degrees, 35 minutes, 45.6 seconds.
633404
ANSWER: \n34 metres\n\nEXPLANATION:\nLet one leg be 'x' units long. \nThen hypotanuse = 2 metres + 2*(length of leg) = (2 + 2x) metres.\nThe other leg is 30 metres.\nIn right angled triangle using Pythagorus' theorem\n(Hypotanuse)^2 = (One leg)^2 + (Another leg)^2\nor (2 + 2x)^2 = x^2 + 30^2\nor 4 + 8x + 4x^2 - x^2 - 30^2 = 0\nor 3x^2 + 8x - 896 = 0\nor 3x^2 + 56x - 48x - 896 = 0\nor x(3x + 56) -16x(3x + 56) = 0\nor (x - 16)(3x + 56) = 0\n\nTherefore x = 16 [as x = -56/3 is inadmissible ('x' being length of a side have to be positive)]\nHence the hypotanuse = 2 + 2*16 = 34 metres
990570
You could use the law of cosines to find the lengths of the diagonals.\n\nThe measure of interior angle B = 128 4/7 degrees.\nAC^2 = AB^2 + BC^2 - 2(AB)(BC)(cos B).\nSince the heptagon is regular, BC = AB, so you can substitute:\nAC^2 = 2AB^2 + - 2(AB)^2(cos B)\nAC^2 = 2AB^2(1 - cos B)\nAC^2 = 2AB^2(1 - cos (128 4/7))\nAC = sqrt [2AB^2(1 - cos (128 4/7))]\n\nThe measure of angle BCD = 128 4/7 degrees.\nThe measure of angle BCA = 25 5/7 degrees because that triangle is isosceles.\nTherefore, the measure of angle DCA is 102 6/7 degrees.\n\nAD^2 = AC^2 + CD^2 - 2(AC)(CD)(cos DCA)\n\nAnd so on...\n\nCheating with a calculator, it's this:\n\nAC = sqrt [2AB^2(1 - (-0.6234898))]\nAC = sqrt [2AB^2(1.6234898)]\nAC = sqrt [AB^2(3.2469796)]\nAC = sqrt [3.2469796](AB)\nAC = 1.8019377358(AB)\n\nThe measure of angle BCD = 128 4/7 degrees.\nThe measure of angle BCA = 25 5/7 degrees because that triangle is isosceles.\nTherefore, the measure of angle DCA is 102 6/7 degrees.\n\nAD^2 = AC^2 + CD^2 - 2(AC)(CD)(cos DCA)\nAgain, CD = AB and you've already found AC, so substitute:\nAD^2 = [1.8019377358(AB)]^2 + AB^2 - 2[1.8019377358(AB)](AB)(cos DCA)\nAD^2 = 3.2469796(AB^2) + AB^2 - 3.60838754716(AB)^2(cos DCA)\nAD^2 = 4.2469796(AB^2) - 3.60838754716(AB)^2(cos DCA)\nAD^2 = 4.2469796(AB^2) - 3.60838754716(AB)^2(cos 102 6/7)\nAD^2 = 4.2469796(AB^2) - 3.60838754716(AB)^2(-0.22252)\nAD^2 = 4.2469796(AB^2) + 0.8019377358(AB)^2\nAD^2 = 4.2469796(AB^2) + 0.8019377358(AB)^2\nAD^2 = 5.04891734(AB)^2\nAD = sqrt [5.04891734(AB)^2]\nAD = 2.2469796(AB)\n\n1/AC + 1/AD = 1/1.8019377358(AB) + 1/2.2469796(AB)\n1/AC + 1/AD = 2.2469796/4.04891734(AB) + 1.8019377358/4.04891734(AB)\n1/AC + 1/AD = 4.04891734/4.04891734(AB)\n1/AC + 1/AD = 1/AB\n\nI like this problem, and I'll give it a shot without a calculator later this afternoon.
1033465
Angle a=159 and the value of y=55.33.\n-\nSimple  supplementary angles  angle a =180-21=159.\n\n159=3y-7\n159+7=3y\n166=3y\ny=166/3\ny=55.33