Q: 11) When three times a number, x, is added to a second number, y, the total is 33.The *?
919110
"Q: 11) When three times a number, x, is added to a second number, y, the total is 33. The\nfirst number added to three times the second number is 19.\na)Form two equations connecting x and y.\nb)Find the two numbers."\n\neq 1: 3x + y = 33\neq 2: x + 3y = 19\n\nmultiply eq 2 by 3:\n3x + 9y = 57\nthen, subtr from eq 1:\n-8y = -24\ny = 3\nsolve for x using eq 2:\nx + 9 = 19\nx = 10\n\n"\nQ:11) Ahmed is x years old and his father is x2 years old. The sum of their ages is 56\nyears. Form an equation in x and solve it to find the age of each"\n\nx + 2x = 56\n3x = 56\nx = 18-2/3 years old for Ahmed\n2x = 37-1/3 years old for his father\n\nHope this helps!
432913
Here's a start to help you out.  You should try to finish the rest with a little substitution work,\n\n\nThe sum of three times a first number and twice a second number is 43.\n3x+2y=43\n\nIf the second number is subtracted from twice the first number the result is -4. \n2x-y=-4
959917
You are looking for the number that, when multiplied by itself 3 times will equal 10.\n\nFor example, 2x2x2= 8\nand 3x3x3 = 27\n\nso your answer has to be between 2 and 3, closer to 2.\n\nThe value is actually about 2.15443469, and can be found on most calculators as follows:\n\n1) 10\n\n2) 2nd or Inv\n\n.   .  .  Y\n3) X . .     (X with Y superscripted - may be reversed - or may be ^ symbol)\n\n4) 3\n\n5) =\n\nSome calculators make you put the 10 in last.\n\nGood luck
26400
I don't think it's 49. According to the order in which mathematical operations should be done, multiplication comes before addition. So the answer is 3 + 20 + 2 = 25. \n\nI say the answer is 25!
823174
We'll call the number x.  Let's translate this into equation form so we can solve it algebraically.\nThree times: 3x\nIncreased by 4: +4\nSum is 37: =37\n\nWhat do we have?\n\n3x+4=37\n\nWe can now solve.  It helps to put things into math so the process of finding the answer is really easy to do.\n\n\n3x + 4 = 37\n3x = 33\nx = 11\n\n\nThe number is 11.  Let's check:\n\n3(11) + 4 = 33 + 4=37!\n\nIt's good!\n\nHope this helps.
503803
3p > 21 + 6\n now adD 21+6 on the right hand side\nthis will give u 27\n3p > 27\nnow this will give u 27 divided by (/) 3\np > 27/3\np> 9\nthe answer is : p>9
1158100
adding the number next in sequence. first added 1, then 2, then 3.....
919225
Just multiply 11 by the denomenator (8) and add the numerator (3) and divide the total amount by the original denomenator (8).\n\n11*8=88\n88+3=91\n91/8
119559
its (x+2)(3x+1) now thats rite lol
883290
I understand your confusion, and suggest that you focus on how the two problems are grouped.\n\nIn mathematics, it's customary to group added terms together using parentheses.  Therefore, the first sum is merely 6.\n\nOn to the next problem:  With nine 1's being added, the sum is 9.\n\nNever would you string these together to form a two-digit answer.\n\n\nHowever, as the first Answerer suggests, perhaps your problem was a single multiplication problem.  In that case (and assuming the problem was written all on one line), you would work it out as he/she did:\n\n (6)(9) = 6 * 9 = 54\n\nHope this helps!
759105
False... y has to be 2...\n(3,2) is a solution, but not (3,1).
1123152
let 1st no. be x\n......2nd.....be x+2 <--becuz its even no.\n......3rd......be x+4 <-- same reason\n\n2((x+2)+(x+4)) = 3x + 34\n2(2x + 6) = 3x + 34\n4x + 12 = 3x + 34\nx = 34 - 12\ntherefore, \nx = 22\n\nso 1st number is 22,\n2nd is 22 + 2 = 24\n3rd is 22 + 4 = 26\n\n=)
1108542
actually, i think it's 15 because however much you add or subtract in the first two, it always adds up to 6.\nAND\nyou always add once and subtract once\nTHUS\nyou have to subtract 3 from 18
345220
Let x = first integer, then x+1 = second integer.\n(We use x and x+1 because consecutive integers always differ by one.)\nThree times the smaller means 3(x) = 3x\nThree times the smaller is added to four times the larger means add 4(x+1) to 3x\nThe result is 60 means to set it equal to 60.\n3x + 4(x+1) = 60\nDistribute the 4.\n3x + 4x + 4 = 60\nCombine 3x and 4x\n7x + 4 = 60\nSubtract 4 from each side.\n7x = 56 \nDivide both sides by 7\nx = 8\nThus, the integers are 8 and 9.
593943
1) The sum of the positive 3-digit odd integers = 101 + 103 + 105 + ... + 995 + 997 + 999.  Adding the first of these to the last, we get 101 + 999 = 1100.  Adding the second of these to the next to last, we get 103 + 997 = 1100.  This pattern keeps repeating until 549 + 551 = 1100.  The question then becomes, how many of these 1100's do we have?  We have one for 101, 103, 105, ..., 549 (the later numbers share their 1100's with these).  How many numbers are in the set 101, 103, 105, ..., 549?  Well, there are 449 numbers in 101, 102, 103, ..., 549.  Since there is one more odd number than even number, we must have 225 odd numbers and 224 even numbers.  Thus, there are 225 odd numbers in the set 101, 103, 105, ..., 549.  Thus, we have 225 1100's to add together.\n\n225 * 1100 = 247500.\n\n\n\n2) This time we wish to add the numbers of the set 10, 11, 13, 14, ..., 94, 95, 97, 98.  Adding the first to the last we get 10 + 98 = 108.  Adding the second to the second to last we get 11 + 97 = 108.  The pattern keeps repeating until we get 53 + 55 = 108.  How many 108's do we have?  Well, we have one for 10, 11, 13, 14, 16, 17, ..., 52, 53 (again, the later numbers share their 108's with these).  How many numbers are in this set?  In the set 10, 11, 12, 13, ..., 52, 53, there are 44 numbers.  The multiples of three range from 12 to 51--from 3*4 to 3*17.  Thus, there are 14 multiples of three in this range.  This means that there are 30 numbers in the set 10, 11, 13, 14, 16, 17, ..., 52, 53.  Thus, we have 30 108's to add together.\n\n30 * 108 = 3240.\n\n\n\n3) Here, I am assuming that the raise of 10% also applies to the previous year's raise and not just to the "principal" of $18000.  Thus, I am assuming a compound raise instead of 5 simple raises.\n\nDuring the first year, you make $18000.  During the second year, you make 18000 * 1.1 = $19800.  During the third year, you make 19800 * 1.1 = $21780.  During the fourth year, you make 21780 * 1.1 = $23958.  Finally, during the fifth year, you make 23958 * 1.1 = $26353.80.\n\nGood luck.
9842
These numbers seem to be defined as : x,x+2,x+3 for every triplet. \nTherefore, 1,3,4,5,7,8,9,11,12,13,15,16,...
161410
Okay.  I'm explaining this to one of the people above me, too.\n\n1/3 = .33\n2/3 = .66\n\nTherefore, if logic persists, 3/3 = .99.  However, this is not true because math is dumb like that.  \n\nIf that concept was true, odd things would happen in the math world.  Basically, if the numbers keep continuing forever, you're never going to have the next number, so you never could have even began.  You would be stuck in NUMBER LIMBO.  There would BE NO NUMBERS.  And everything would be pretty much screwed.\n\nThis is why 3/3 = 1.  But also, 4/3 is obviously more than one.  It's all very confusing, and there are loopholes everywhere.  This is why people round and I am not in charge of math books.