issue with force problem?
917347
It sounds like you know what to do.  From your description, it looks like a basic statically determinate problem.\n\nYou have a known applied force P, and two unknown reaction forces, lets say A and B for the top and bottom reactions respectively.  You also have two equations of static equlibrium, specifically the sum of the forces in the "x" direction, and sum of the moments about any point you wish.\n\n(Ok, really you also have the force of gravity and the normal force, but those are the only forces in the "y" direction so that equation won't help you, especially since the mass or weight isn't given).\n\nAssuming to the right is positive, assume A is to the left and B is to the right (this is intuitive, but if directions are incorrectly assumed the answer will just have a negative sign, thats all).\n\n                    _ ------------> P\n                    |   |\n                    |   |\n                    |   |     10.5 m\n                    |   |\n                    |   |\n                    |   |\n                    |   |<----------A\n                    |   |\n                    |   |       1.5 m\n                    |_|--------------> B\n                    \n                 (FBD!)\n\nSum of forces in "x" gives: P - A + B = 0\nSum of moments about B: A(1.5) - P(12) = 0\n\nI took moments about an unknown reaction, B, to eliminate it.  Also, I assumed counter-clockwise to be positive.\n\nSubbing in the value of P = 5.40 N into the second equation:\n\nA = (5.40*12)/1.5 = 43.2 N\n\nThen, put that into the first equation:\n\nB = A - P = 43.2 - 5.40 = 37.8 N\n\nThat should do it.  Both come out positive because their assumed directions were correct, however on the Free-Body-Diagram they are in opposite directions necessary for equilibrium.\n\nCheers,
545558
Force = mass * acceleration\nForce = 1300 kg * 2.6 m/s2\nForce = 3380 Newtons
352168
What seems to be the problem?  Need more info.
328695
you can delete your program that uses that. Then re download it to see if it works correctly. There might have been a problem when you first downloaded the program :D
790286
I've never had that happen to me.  You should have mentioned the application that happened on.\n\nMy guess is... it's a software bug.  You might need to reload the application.  Try that.
1153380
they seem to be having problems for the last 24 hrs, give it awhile then try again. i installed the new beta version, had some problems and had to reinstall the older version 7 before i could get things going.\nonce you get your up maybe you can holler ;)
617970
I am terribly afraid of the equilibrium problem.. the first one on the free response!!! well, good luck!
556017
try just clicking once or left click on whatever it is your clicking on,then right click & see what it says on the drop menu.\nI sometimes have provlems with this & if I just right click on an icon instead of double clicking,it seems to work.
958288
Could be.\n\nTry rebooting the system. That might help.
618210
Not due to gravitational pull?!
319601
Hello\n\nGo to the source link, this problem is taking care of.\n\nneed more help email me.
211731
If all forces are in equilibrium then the object won't move even if there are several forces acting on it.
772638
try the formulas:\n\nforce = mass * aceleration\n\nwork = force * distance\n\n\n\n\nWell i dont speak english very well, but i hope i help u.\n\nKisses
476666
contact the software manufacturer.  they should be able to help you resolve the issues
695419
Im pretty sure this is one of teh bugs to the beta version, contact Microsoft...;
984662
You could try installing it again and then try uninstalling it again. Sometimes that works.
812295
Er, gravity really has nothing to do with this question. Fk = coefficient*Fn.  Fn = mg.  -19.6 is your Normal Force.  But yea, the answer is correct.