what is the relationship of speed and acceleartion?
919955
Speed and Acceleration are related in that acceleration is the rate of change of your speed (should be velocity since you can take into account change in direction for accelerations).\n\nThe relationship can be mathematically expressed as:\ndv/dt = a.\n\nThat is, the change in velocity over the change in time.
68332
well speed is units of distance per unit time, lets say meters per second(m/s). now the slope is the velocity per unit time. so that would be meters per second per second(m/s/s). meters per second per second is also known as meters per second squared(m/s^2). look familiar? those are the units for acceleration. this also makes sense because of the formula. a=v/t. so the slope is the y-axis divided by the x-axis so v is the y-axis and t is the x-axis. so v/t, which is acceleration. hope that helps :)
388131
Speed is an indicator of how fast you are going. Velocity is an indicator of how fast you are going and in which direction.\n\nTherefore, when you are travelling in a straight line at 65mph for 1 minute, your speed is not changing. But when you travel at 65mph for 1 minute around a curve / bend, then your velocity is changing primarily because your direction is constantly changing.\n\nTherefore the only difference between speed and velocity is the direction component of velocity.
844762
There are jthree  formulae cncerning velocity.These are v=u+at , V^2=u^2+2as ,and s=ut +(1/2) at^2 ,where u= initial velocity,v=final velocity ,a=accelaration.,s= distance travelled and t= time.Now how to decide which formula is to be used?in the problem,just see what they want you to find out and note down what is are already given in the problem, if they give you u,a and t and ask you to find out v,apply formula no.1.But if they gdonot give you time but give the distance or displacement and asks you to find v,donot hesitate to apply formula no,2 and so on.if you have any difficulty to understand.please do not hesitate to write to me through yahoo answersand i shall be glad to assist you
812333
B. Velocity is a vector, meaning it has magnitude (size) and direction. Speed is a scaler, therefore does not depend on direction.
392981
Is the speed at which it travels.
791525
questions are very easy. You must try them by yourself. I will only give hints-\n1> Instantaneous accl  = dv/dt\nAvg accl = (v2-v1)/(t2-t1)\n\n2> draw the vectors, take the components separately along x and y axes.\nremember accl component along x axis increases velocity along x axis, and accl component along y axis increases velocity along y axis.\n3> use the basic kinematics equations like v^2=u^2+2as etc
488201
Try here:\n\nhttp://en.wikipedia.org/wiki/Accelerometer
634337
Eric L is right. Kinetic energy is proportional to speed SQUARED. It is momentum that is linearly proportional to speed.
546224
Energy = force x distance\n=>  Energy = (mass x acceleration) x Distance\n=>  Energy = mass x acceleration x Distance\n=>  Energy = mass x (speed / time) x Distance\n=>  Energy = mass x speed x (Distance/time)\n=>  Energy = mass x speed x speed\n=>  Energy = mass x (speed)²
431787
Looks to be a subtle omission from the other posts about this.\n\nAcceleration is the rate of change of velocity with respect to time.\n\nThat is not insignificant. There can be relationships between numerous quantities in physics. One must specify which ones are dependet on the otehrs, otherwise a 'definition' is unclear and effectively useless.
399954
SPEED=dy/dt=distance/time.its not exactly something you invent.it was an axiom,a basis of understanding.
769961
Hi, \n\nIn general, the equation describing the position of an object under the influence of a constant force is as follows:\n\nh(t) = at^2 + vot + xo \n\nwhere : \nh(t) = height at any time t\na = acceleration\nvo = initial velocity\nxo = initial height.\n\nSo the answer would be \nF= m*a (mass times accelleration) = (the mass kg)*(1.96m/s^2) \n\nI'm guessing that you want to find out the equation for acceleration, so what you should do is use the values for t, and   h(t) to solve for the constants (xo, vo)\n\nexample: \nat time t=0, height is 0.50m\n\nso h(0) = a(0)^2 + vo (0) + xo = xo\n\nbut that also equals 0.50m;\n\nso:\nxo = 0.50m.\n\nand the equation becomes \nh(t) = at^2 + vot + 0.50m. \n\nThen use the different values of t, and h(t) to do the same thing with the other constant, and you'll have it. \n\nHope that helps, \nMatt
1061816
Hai Shaumik\nBy Einsteins energy mass relation E=mC^2 , but mass is inversely proportional to velocity\nA body with small mass have high velocity compared to a body having greater mass. This implies that a body having zero mass moves fast. There is no such object having zero mass. so no body can move with greater or equal to velocity of light
54242
A change in a objects velocity produces acceleration.\n\nAcceration is a measurement of the rate of change of velocity, and is usually measured in "meters per second squared" or ms^-2.\n\nIf a car is travelling at 5 meters per second, and over a time of 5 seconds, increases its speed to 15 meters per second, it has accelerated at a rate of 10 meters per second over 5 seconds, or 2 ms^-2 (2 meters per second squared)\n\nHope that helps
792153
‘impulse’ or momentum\n=m*(v2-v1)=0.42*(-17-4.1)=-8.862 kg*m/s
823412
Velocity (or speed) defines the time it takes to cover a distance from point a to point b.\n\nV=d/t  >\nV (velocity)\nd (distance in meters)\nt (time in segonds)\nm/s (meters per segonds)\n\nAcceleration is a variation in the velocity, wether it increases OR decreases.\n\nie: gravity on earth has an acceleration of \n-9.98m/s  (notice the minus)  so if an object is falling down on earth it will accelerate towards the ground because the object is subject to that force of gravity, \nif it is thrown up it will slow down as it goes up because the same force of gravity affects the speed of the object, when it has slowed down completely it has reached 0m/s and will start to fall again and accelerate untill it reaches a surface that will stop it from falling further (ground, floor, your hand, etc)\n\nThe formula for acceleration is:\n\na= V1-V2/t \n\nor acceleration = initial velocity-final velocity divided by time.\nif it had an initial velocity that is different from the final velocity there was an acceleration, (or change in velocity).