find slope of a line that is perpindicular to this line: y=2x-3?
916414
For a line to be perpendicular all you need is the negative inverse slope.\ny=2x-3 has a slope of 2 so the negative inverse would be (-1/2)\n\nSo y=(-1/2)x-3 would cross perpendicular at the y axis at -3
907088
The slope is 1/3 and the point is (-2, -4).
42786
If X=0, then Y=5 (Y-intercept is 5)\nIf Y=0, then X=3\n\nPlot and you get, Slope = rise(y)/run(x) = 5/3
840251
parallel lines have same slope\nperpendicular lines have negative recipricol slopes\nthis is neither.....it is reciprical, but not negative.....\n\ny = mx+b..... in equation y = 3x-3, m = 3,  in equation y = 1/3x+2, m = 1/3......would have to be -1/3 for perpendicular....
910261
Slope = m\n= y2-y1&#92;x2-x1 \n= -4-6/-3-2\n = -10&#92;-5\n=2\n\nnote: / means divided by\n\nthe slope of y= 2&#92;3x-4 is 2&#92;3
724767
This cannot be done since if it's perpendicular to y = -3, which is a horizontal line, it would be a vertical line and vertical lines have no slope.\n\nPS Its equation would be x = 1
954966
First find the slope of the segment connecting the points:\n(9-3)/(-1 - 1) = 6/-2 = -3\n\nThen do its opposite reciprocal since perp. lines have opp. recip. slopes:  1/3\n\nThen find the midpoint: ( (1 + -1)/2, (3 + 9)/2) = (0, 6)\n\nSo you need the equation of a line through (0,6) with slope 1/3\n\nLines are y = mx + b where m is slope (1/3) and b is y-intercept (6)\n\nSo y = 1/3 x + 6\n\nHope that helps explain and not just gives the answer
783146
slope of the second line is  3/2  ( y=3/2 x - 5 )\n\nso slope of the 1st line -2/3\n\ny=-2/3 x + b, plug in ( 2, -1) to solve for b\n\n-1 = -4/3 + b\n\nb=1/3\n\nso eq of the first line is y=-2/3 x + 1/3\n\n or                                  3y=-2x + 1
823070
Get the slopes of the two lines using the formula:\n(y2 - y1)/(x2-x1)\n\nIf the slopes are equal the lines are parallel\nIf the slopes multiply together to give -1 the lines are perpendicular\nIf the slopes do not meet these conditions they are neither\n\nHope this helps!
532403
The slope of y = (1/3)x - 5 is m = 1/3\nA line that is perpendicular to the above line will have slope m = -3.\nIf two lines are perpendicular, then the product of their slopes is -1.  For this case, we have (1/3)(-3) = -1, so -3 must be the slope.\nSince you're not given a point, any equation of the form \ny = -3x+b will work.\nJust pick whatever value of b that you want.\nSome examples, \ny = -3x\ny = -3x + 5\ny = -3x - 7
341837
y=-9\ny=-6\ny=-3\nincrease by 3\nand the slope is 3
1093431
what is d2 here..if its line what is its equation?
497708
to find if a line is paralel to each other, you had to find out it's gradient or slope. If the gradient is the same, then the lines are paralel.\n\nTo find gradient is rather easy.\n\nYou just plug in the points into (y2 - y1)/(x2 - x1)\n\nSo the first line is:\n(3 - - 7) / (1 - - 4)\n= (3 + 7) / (1 + 4)\n= 10/5\n= 2\n\nand the second line is:\n(10 - 6) / (4 - 2)\n= 4 / 2\n= 2\n\nyou see here that 2 = 2, so the two lines are paralel
542210
Solve for y: y=3x\n\nThe slope is 3, and the y-intercept is (0,0). (y=mx+b: m is slope, b is y-intercept)\n\nThe slope is the change of y over the change of x.\n\nStart from (0,0) and go up 3 units, right 1 unit.  Connect the points and continue the line.
1151711
One thing we  know about rhombuses is that their diagonals are perpendicular bisectors of each other. Given that, we can find the slope of BD. \n\nFirst find the slope of AC:  (-2 - 4)/(1 - 5) = -6/(-4) = 3/2\n\nThe slope of BD is the opposite reciprocal of 3/2 so the slope of BD is -2/3.\n\nWe also know that BD passes through the midpoint of AC. The midpoint of AC is (3,1).\n\nUsing point slope form, the equation of the line containing BD is \n\ny - 1 = (-2/3)(x - 3)\n\nIn slope intercept form, it is y = (-2/3)x + 3
753590
Basically, its a straight line going through (1,3), with gradient, m=-3. we have y=mx+c. putting the point (1,3) into here, \n\n3=(-3)(1)+c, so c=6, which is the y-intercept. so the line equation is,\n\ny=-3x + 6, which is a straight line with y-intercept at y=6. the line will be sloping downwards since the gradient (m) is negative. if you plot a few values of x and y which satisfy the equation you can see the line. to check axis intercepts, put y=0 for the x-intercept and x=0 for the y-intercept.
554784
x=(1--2)  or (1+2)\ny=(5-3)\n\ny/x=slope\nx=3\ny=2\nslope is 2/3