i have a math question on angles.?
914527
This is easy.\nComplementary angles add up to 90.\nSupplementary angles add up to 180.\n\nSo if two angles are complementary and one is 40, the other is 50.\n\n40 + x = 90\nx = 90 - 40\nx = 50\n\nIf two angles are supplementary and one is 40, the other is 140.\n\n40 + x = 180\nx = 180 - 40\nx = 140\n\nIf an angle has a measure of 'x':\nThe complementary angle is 90 - x\nThe supplementary angle is 180 - x\n\nDoes that make sense?  If not I can try to explain it another way...
832160
The angles formed by crossing lines are supplementary (add to 180º).\n\nSo it is a simple matter of subtracting:\n180º - 145º = 35º\n\nThe acute angles will each be 35º.
356323
Absurd... A triangle cannot have more than 1 obtuse angle, since the sum of all angles of a triangle is 180 degrees.
1159510
the four angles add up to 360 degrees
21860
Let's call these angles A and B.  And let's call C the adjacent angle in the middle of these two angles.\n\nThen we will have:\n\nA + C = 180\nB + C = 180\n\nAs a result, A = B = 180 - C
43253
Depending on what you need to solve, you need two angles and a side, or two sides and an angle. Hit me with an E-Mail if you are stuck with something.\n\nkeptcompany@yahoo.com
771231
let one angle be x and the other y\nso x= 20+2y\nx+y= 180\nso x= 180-y\nsubstitute in \nx=20+2y\n180-y=20+2y\n3y=160\nso y=160/3\nx= 180-160/3\n  =(540-160)/3\n  =380/3
367687
an angle that is inside a circle or any other figure
262981
All sides and angles are equal to a side and angle on another figure
914296
Use properties of dot product to get angles.\n\nv1*v2 = |v1|*|v2|*cos(theta)\n\nIf you first normalize your vectors then |v| = 1 it makes the calculations easier.
1023518
Use the Law of Sines.\n\nsin A/a = sin B/b\n(sin 36)/24 = sin B/47\nsin B = (47 sin 36)/24\nsin B = 1.151079452\nAt this point you have a problem--it is impossible for the sine of an angle to have a value greater than 1.\n\nSo either you copied the problem wrong, or you are being asked to recognize that a triangle cannot be formed with these dimensions.
975643
are you sure that the question is correct? because when you add 4 angles of a quad, it's 360 degrees, not 180.
811153
Hi, \n\nThe answer lies in the pythagorean theorem. \n\nFor any right (one of the angles is 90 degrees) triangle with sides a,b and c where c is the side opposite the 90 degree angle:\n\na^2 + b^2 = c^2\n\nso for your first excercise:\n\na = 4\nb = 4 Sqrt(3)\nc = ?\n\na^2 + b^2 = c^2\n4^2 + {4 Sqrt(3)}^2 = c^2\n16 + 4^2 * 3 = c^2\n16 + 16 * 3 = c^2\n64 = c^2 \nc = +- 8 (since we're dealing with a triangle, -8 doesn't make sense, so just ignore it.)\n\nc = 8. \n\nFollow that same pattern, and you should be all set. \n\nHope that helps, \nMatt
962823
Can you give angle measures ?  Cant do much without those or some relationship between the other sides.
715400
Angle of line from horizontal position.
471483
Your question is difficult to understand.  From what I make of it, here is my answer (and I could well be wrong)\n\nI assume x and y are angle measures (in degrees)\n\nBC=2(angle A)\n6y=2(2x)\n6y=4x  (eq. 1 to be referenced below)\n\nAB+BC+AC=360 degrees\n6y+6y+4x=360\nUsing (eq. 1)\n6y+6y+6y=360\ny=20\nx=6y/4=30
392786
you may be dealing with "right" triangles, but you don't identify the angle that is 90, so your question is bout impossible to answer. this type of question usually involves  \na squared + b squared = c squared (a^2 + b^2 = c^2) where a and b are the 'legs' of the triangle in question. (the two 'legs' of a right triangle make the 90 degree corner) :)