How do parts of an equation effect its graph?
913484
are you talking about a polynomial :\na + bx +cx^2 + dx^3 +...\n\nbecause those a,b,c,d... do not appear any where on the graph... you have to look at the intercepts and the extreama, and the inflection points to get any good idea about the shape of the graph
903787
It allows you to see the relationship between the variables better than you could in a chart.  You can also find the mathematical relationship by calculating the slope of the graph and determining the equation of the line.
796114
Graph equations are of the form y=mx+c\n\nm is the slope or gradient\nc is the y intercept.\n\nSo, for y=-x+1, \nm= -1\nc = 1\n\nAnd for 2y=3x, you have to rearrange it to make it look like y=mx+c.\n\nSo divide by 2.\n\ny=3x/2\n\nm= 3/2 \nc =0\n\nHope you understood my explanation :)
979117
From a table -- see which y-value corresponds to x=0\nFrom a graph -- see where the graph crosses the y-axis\nFrom an equation -- get the equation in y=mx+b form; the y-interecept is b
736099
plot the coordinates then do the vertical line test.  if the vertical line intersects more than two points on the graph then it is not a function.  each set of coordinates you have listed are functions (i free hand it with no graphing paper or calc) so forgive me if im wrong.  also refer to www.coolmath.com. it is a good site for breaking down math
826809
It is probably best to determine the range after you have the graph.  You will need to look at the local maximums, local minimums, and the horizontal asymptotes to determine the range.  (In other words, it is not a fast problem).
883821
There are two types of variables on a graph - independent and dependent.\n\nindependent variables are on the "X" axis.  They are the variables that you change during the experiment.\n\ndependent variables are on the "Y" axis.  They are the ones that change due to your manipulation of the independent variables.
733627
Rewrite the equations as:\ny = -x + 2 and\ny = (x+10)/2 = 1/2*x +5\n\nNow, if you insert x=0 in each equation, you will get a y-value.\nIf you insert y=0 in each equation, you will get an x-value.\nFor each line, you can use those two intercepts to graph the line.
871684
The graph of this equation looks like a V. It's the same as the graph of y=2x, except that the part which should bein quad III is actually in quad II.\nFor this graph, the vertex is when y=0. \nSo the vertex is at (0,0).
152046
y=|x+2| \n this shifts the "v" shaped graph 2 units to the left from the origin.
152511
Which function, Subsitution, Linear COmbination, Graph?
973040
Ok, since you didnt give any equation, i would assume that the graphs are linear in nature\n\nThen for find the points where the graph intersects the Axes,\n\n  Substitute x=0 in the equation to find the point where the point where the graph intersects the Y axis\n\n    Substitute y=0 in the equation to find the point where the point where the graph intersects the X axis\n\nEg.   2x + y = 4\n\nSubstituting y=0,\n\n                          2x=4\n                           x=2\n\nHence the the graph meets the x axis at (x,y) that is (2,0)\n\nSimilarly, substituting for x=0, we get..\n\n                         y=4\n\nTherefore the point where hte graph meets the x axis is (x,y), in this case (0.4)
412953
An equation that is incorrect.
346163
It's curved. Take Newton's second law F=ma, therefore m is proportional to 1/a and therefore the graph will be similar to a y=1/x graph and will be curved.\n\nTake F=ma, so m=F/a, proportionality is about if you double one thing the over doubles, however this is inversely proportional so if you double m you get a half of a, this is assuming that F is a constant.
180174
Confirm, if you insert the values for x and y the equations work out with the solutions.
799272
is it asking you to graph that. otherwise it is not solvable. if it's asking you to graph it then you have to plug into your graphing calculator y=x-9
952896
yes. when you multiply them on the divided sign, it gets rid of them. Example\n\na / b = xc\n\na =(xc)b