how do i find the product and simplify to lowest terms?
915212
To find the product of anything just means to multiply, for eg, the product of 5 and 3 is 15.  When it comes to fractions you have to multiply the top numbers together then multiply the bottom numbers together eg. \n half X half = a quarter  Write it out on paper to help you understand\nThis doesn't need simplifying but the next one does!\ntwo thirds X half = two sixths, simplified that is the same as one third because you are able to divide top and bottom numbers by 2.  So really to simplify fractions you have to look for a number that both top and bottom are able to be divided by.  Hope that helps.
316383
Reduce it untill the # on the bottom is prime.\n (divide the top AND bottom by 2 untill you get a decimal.)
398761
the product contains the expression (x-x) which = 0 thus the product is 0
1053403
Write it as:\n2x^2-4x+3x-6\n=2x[x-2]+3[x-2]\n=[2x+3][x-2]\nSimple middle-term factorisation!!!
943546
LCM of 2, x+1, x+2 is the product of the terms.  Express everything fractions with the LCM as the denominator.  Then solve.\n\n4(x+2) / 2(x+1)(x+2) + 6(x+1) / 2(x+1)(x+2) = 7(x+1)(x+2) / 2(x+1)(x+2)\n\nThen multiply everything by the denominator (LCM):\n4(x+2) + 6(x+1) = 7(x+1)(x + 2)\n\nMultiply out:\n4x + 8 + 6x + 6 = 7(x+1)(x+2)\n10x + 14 = 7(x+1)(x+2)\n10x + 14 = 7(x² + 3x + 2)\n10x + 14 = 7x² + 21x + 14\nPut it all on one side:\n7x² + 11x = 0\nx(7x + 11) = 0\n\nx = 0\nor\n7x + 11 = 0\n7x = -11\nx = -11/7\n\nSo x = 0 or x = -11/7
215144
Multiply the numerators together.  Then multiply the denominators together.  Just go straight across.  If you want, you can simplify the fractions in the beginning so that it's a bit easier.  Then if your answer isn't in lowest terms, I'd simplify that too.  Hope I helped!
971390
{3XY^2M/1}-{2M/[X^-1Y^-1]^2\n+{[4X^2Y^2]/M^-1}-\n(3X^(3Y)^(3M)^-1/(XYM)^-2
617264
Since each term has at least x in it, divide out the x by distributive property:\n\nx(x^2 - 4xy + 4y^2)\n\nThen factor the rest by FOIL:\n\nx(x-2y)(x-2y)
850884
using chain rule and product rule\n\ny'= 3x^(2)*tan(4x)\n         +4x^(3)*sec^(2)(4x)\n  = x^2(3tan(4x)+4x*sec^(2)(4x) \n\ni hope that this helps
947283
You can do this using "synthetic division"\n....... ______________________\nx - 5 ) x^4 - 0x^3 - 3x^2 + 0x + 6\n\nI'm going to simplify this leaving out the x-terms and only showing the coefficients, but just imagine they are there:\n\n.............. 1 . 5 .22 110\n1 -5 ) 1 . 0 .-3 . 0 . 6\n......... 1. -5\n......... ------\n.............. 5 .-3\n.............. 5 -25\n.............. -------\n................... 22. 0\n....... ........... 22 -110\n....... ............----------\n....... ........ ........ 110  6\n....... ........ ........ 110 -550\n....... ........ ........ ------------\n....... ........ ........ ....... 556\n\nSo if I did it correctly the answer should be:\n1 5 22 110 remainder 556\n\nThis equates to:\n(x^3 + 5x^2 + 22x + 110) + 556/(x-5)
930497
find the standerd formula, rearrange it, and plug in the numbers
147771
You have to write as a product of two terms.\nThis is always possible, as a consequence of an important theorem. \nIn general, if you have the expresion a*x^2 + b*x + c, where a,b,c are constants and x is a variable, here is the way you can put this expression in a product form.\nFirst calculate b^2-4*a*c (the so-called determinant). If this number is negative the expression can't be put in the product form (well at this stage).\nThen calculate x1=(2*a-sqrt(determinant))/2 and x2=(2*a+sqrt(determinant))/2. The result will be:\na*x^2 + b*x + c= (x-x1)*(x-x2).\nIn your case the determinant is 256 and sqrt(256)=16. then x1=-7 and x2=9 and that's it.
1001167
The solution to your question is a bit lengthy and it wont be easy typing that here. However I can tell you the guidelines to arrive at that.\n(1)Write down the equation\n(2) take differentiation wrt x on both sides.RHS will be 1 here.LHS will have to be diff..you must know how to diff e^(y/x).Use the diff rule for products.\n(3) take diff.again of the above obtained equation.you will get alot of terms then.try getting from that the form you want.
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
221721
Product rule:\n\n(fg)' = (f ')g + f(g ')\n\nSo,\n\n(-2x^2 * ln(x))' = (-4x * ln(x)) + (-2x^2 * 1/x)\n\nMultiply and clean up:\n\n-4xln(x) - 2x
76419
4 08 [12] 16 18 22\n6 [12] 18 24 30 36\n\nyou keep adding the number until you find the lowest one they both have.
235893
(15y^3 + 12y^2)+ (5y+4)\nGCF 3y^2(5y+4)+1(5y+4)\n\n(5y+4)(3y^2+1)