which is the highest number you can form by using  four 2s?
917912
Since 2p22>222 then\n\n  2p(2p22)  is the greatest number\n\n\nMy calculator could not handle that high a number.\nSo I figured , using an inductive method, that the result\nis a 1 followed by 1,200,000 zeros.\n\n\nAnyone care to confirm or contradict.\n\nHere's how\n\n2p4,000,000=10p(x)\nx=4mil(log2)= 1.2 mil
737723
For starters, S can only be a 1 or a 2 as any other number would have made the P bigger than 10, and that does not work.\nBut then, since 4 A is a number that ends with S, it cannot be 1, as S needs to be even, so S is 2.\n2oda+2oda+2oda+2oda=pop2\nWe can also look at the "p": it can only be 8 or 9, depending if the 4 "o" create a carry or not.  But we know that 4 "o" create a number that ends with a "o" unless the 4 "d" also create a carry.\nZero do that (without the carry) 3 would create a number ending with 2 but ending with 3 if there is a carry from the sum of "d", 4 would make un number ending by 6, so would need a carry of 8 to get to 24, but then we would have 2 to carry over the toal of "s" and that would make "p" 10 which is not acceptable, so "o" is either zero or 3 with a carry of one from the total of "d". But if there is no carry (if "o" is zero) then "p" has to be 8, and "d" would have to be 2, but 2 is already "s"; so "o" has to be 3, and "p" is 9.\n\n23da+23da+23da+23da=9392.\n\nand "d" has to be 4 and "a" is 8.\n\n2348+2348+2348+2348=9392
565741
the number that can be reachable tha most?
842276
1,2,3,4,6,8,12,16,24,48 \n\nlolz hope this helps :)
1067
ummmm... i cant count that high. let me grab my calculator. i calculate 3 as the answer. ;) lol
104047
yes id say 160 but itz hard to tell with only 3 numbers. it seems that you add 12 to the first, then 13 to the 2nd and then probably 14 to the 3rd number (which would be 160)
439989
42 (or forty two if you want two words instead of two numbers).
720161
Yes, I can:\n4! + 4 \n=\n(4 x 3 x 2 x 1) + 4 = 28\n\n(BTW, 4squared + 4squared = 32)
110716
62 where 2 is a superscript.\n\nthis is pronounced as "six square"
653946
1 4\n2 15\n4 2\n5 100\n6 3\n7 15\n8 10\n9 10\n10 33\n11 -45\n12 2\n13 500\n14 5\n15 200
265791
3\n4\n.5\n1\n-7\n\nThe answer above me describes how.
197475
this one is pretty easy\nafter 46 i will give u the next no.\n\n54,55,62,63,69,70,75,76\n\nc it goes like that 80,81,84,85,....
908957
convert the mixed # to a improper fraction... 2 x 2=4 ,   4+1=5 \n5/2\nthen multiply 5/2 x 26 = 130/2\nreduce 130/2=65
131443
4! + 4! + 4! + 4! + 4
845089
Ok, your question makes absolutely no sense.  Why say we can only use 1 through 16, and then say we can only use 1?\nSome ways, assuming I translated your question correctly, would include 16 + 16 +1 +1, and 16 + 15 + 3.... There are almost an infinite number of ways to add to 34 with the numbers 1-16, so please rephrase your question.
639650
There is no such thing as a highest possible number. No matter what number you have, there is always a larger one. (For example, you could always add 1 to your number to get a larger number). The largest number that has a commonly-known specific name is a "googleplex",
83993
84. so the possible numbers for ones is 0,1,2,3,4,5,6,7,8,9 obviously u can't choose more than 5 or 5 because when u double it it would be 3 digits. so 4,3,2,1 so try 4 if u double it =8 so 8+4=12. and 8 is double of 4.