Current through component?
913133
your homework would need to be learned by whom?
317786
http://www.electrospec.com/electronic/components-parts/index350.html\n\ntry here!!
186229
Here are some sites that may help.  Both have circuit examples utilizing LVDT's.  Hope this helps.
1015158
initailly it was believed that current flows from+ve to -ve. but actually its electrons moving from -ve to +ve. so it became - current flows from +ve to -ve (thoritically) electrons from -ve to +ve (actually)\n\nhope that answeres
471894
a drawbridge or a circuit??
797208
Not the easiest thing to explain via email but the best way to start is to understand clearly the function of the symbols shown in diagram. Once you understand what each item does find a starting point - usually the power supply and walk through it. ANother way is to get the corresponding termination diagram. I find them much easier to understand.
211231
It depends on both the type of current and the circuit.  For example, AC and DC currents passing through a circuit with reactive elements (capacitors and inductors) will much diffreently from one another.... Ohm's law always applies however...
36631
B. the current will increase
926622
The CT will only work on an AC circuit so I don't see where it would make any difference.  The only thing that would is to have another phase too close and the magnetic fields might cancel each other. Since the current being measured is AC the output from the CT will also be AC and shouldn't matter on the leads.
1186419
That would depend on the voltage. Current = Watts / Volts\nA couple of examples:\n110V - 90.9 Amps\n220V - 45.45 Amps\n240V - 41.67 Amps\n440V - 22.7 Amps\n10,000V - 1 Amp
797986
This is a very simple circuit.\nhttp://www.rason.org/Projects/fmkeyer/fmkeyer.htm
374938
maybe broken wire from internal to external
971534
Well, u can assume that on every section of wire there is an amount of current flowing say i1,i2.... etc. and give any direction to them.\nKirchoff has two laws:\n1st law(current law) : At any junction the incoming current is equal to the outgoing current. So at any junction u can add all the incoming currents and equate it to the addition of all outgoing currents.\n2nd law (voltage law) : it states that the total voltage in a closed loop or mesh is zero. so if u consider first loop on left and the direction of current in both sections of wire clockwise. Then u can write -i1R1-i1R2+Ub1=0. if u r tracing the loop in the direction of current then voltage on resistance is negative(-iR) or u can take the vice versa it doesn't matter.For voltage source if the current is moving from positive to negative plate then voltage is termed as positive and the other way negative.\n\nSo form that many number of equation, that suffice u in finding the unknowns. And then by applying simple mathematics find the current in each segment and then the voltage across each resistor. U need to consider here the concept of voltage drop too.
879048
Resistance = Voltage / Current\n= 1.4/0.8\n= 1.75 ohms.
575172
V=IR, voltage = current times resistance. If you know the current flowing in the circuit, just plug that and the known resistance into the formula to get the voltage. If you don't know the current, you need to measure it. One way to measure it is to measure the voltage across the resistor and plug that and the resistance into the equation and calculate it. But if you are measuring the voltage across the resistor, then you don't need to calculate it, do you?
1079575
By Ohm's Law, current = voltage / resistance\n\nTherefore the current is 120 / 2 = 60 amps (answer b)
293488
use a clamp ammeter to measure the line current. then check the resistance of the cable your using. you can get the voltage drop by multiplying the square of current to resistance reading...