Need help with Norman Windows Problem (pre-calculus)?
912405
Let x be the radius of the semicircle, then the rectangle has base 2r and height h.  The total perimeter of the window is\n\npi*r + 2r + 2h = 20. \n\nSo h = (20 - pi*r - 2r) / 2\n\nThe area is (pi*r^2)/2 + 2rh.  Replace h with the above so that the area is a function of r.  Differentiate to find the maximum.
87655
From the Pythogorean Theorum, the square of the width plus the  square of the height must equal the square of the diagonal:\n1) w^2 + h^2 = 40^2\n\nBut the ratio of the width to the height must be 16/9:\n2) w/h = 16/9\n\nUse equation 2 to solve for either w or h (I'll solve for w):\n3) w = (16*h)/9\n\nNow substitute the value you got for w in equation 3 back into equation 1 and solve for h:\n4) ((16*h)/9)^2 + h^2 = 40^2\n   ...\n   h = 19.61\n\nOnce you have h, substitute this value into equation 3 to get w:\n5) w = (16*19.61)/9\n   w = 34.86\n\nNow you have your answer. The width of the screen is 34.86" and the height of the screen is 19.61".\n\nYou can check your answer by substituting the values for w and h into equation 1 to make sure the sum of their squares really do equal 40^2 (they won't be exactly 40^2 because of rounding errors, but they will be very close).
622612
Joel, you need some help.  This is one of the easiest questions I have ever heard!  You should know this, man!  You're gonna fail your test if you keep cheating on here and don't actually figure out how it works.  Good luck, brotha'\n\nL = -2 or L(x) = -2
242572
maple, mathematica should do the trick.  but you have to pay for this.  if ur a programmer savy, u can get GNU BigNum package.  otherwise, umm, search for a free product.  there should be a couple out there.  see link.  oh btw did u know windows calculator is arbitrary precision also?  it just doesnt display every digit :)
756805
x<2   (-infinity,2)\nx>3   (3, infinity)\nx<2 see first interval\nx>-2 (-2,infinity)
679965
actualy every version of windows comes with a scientific calculator. load the caluclator click on view scientific.
778162
Step 1: find y '\nStep 2: fill in x=1\nThat gives the right answer 2\n\nTh
920579
use synthetic  divsion method \ni think this link would help\nhttp://www.purplemath.com/modules/synthdiv.htm
932841
This might help --> http://www.uwm.edu/~ericskey/TANOTES/Geometry/node15.html
769460
I think that you want x element of [-6,4)\n\nYou wanted closed on the left and open on the right, is that true?\n\nJust remember that for intervals:\nopen   ( )\nclosed [ ]\n\nAnd you can match them up: [-6,4)
1010902
This is  basic\nslope= m=(y2-y1)/(x2-x1)=(12-7)/(8-6)=5/2\nangle=arctan(5/2)
354245
the answer is 1.442250\n\nthe solution will be rigorous if tried to solve mathematically. The better way is trial and error and the following program does that pretty well. \n\n#include<stdio.h>\n#include<math.h>\n\nint main()\n{\nfloat error = .000001;\nfloat x = 1.0;\nfor (;;)\n{\nfloat y = pow (x,3);\nif ( pow (x,y) < 3 )\n{\nx = x+error;\n}\nelse break;\n}\nprintf ("%f",x);\nreturn 0;\n}
128434
Try the following link:\n\nhttp://www.cs.bham.ac.uk/~axk/EC_tut2.ppt
424650
Not really enough information to help, so try this site:\n\nhttp://www.blc.edu/fac/rbuelow/calc/ex4-6.html\n\nit's the second problem down the page
860398
Let W be the width of the pen (2 fences perpendicular to the barn).\nLet L be the length of the pen (1 fence parallel to the barn).\n\nWe know that 2W + L = 144\nSolve for L:\nL = 144 - 2W\n\nNow create a function for the area:\nArea = W * L\nArea = W (144 - 2W)\nArea = -2W² + 144W\n\nIf you take the first derivative and set it to zero you get:\n-4W + 144 = 0\n4W = 144\nW = 36\n\nThus the area will be maximized when the width is 36 and the length is 72.
725168
Use L'Hospitals rule\nd(sin ax)/d( bx)\na*cos(ax)/b lim x----> 0  = a/b
1142710
Use this formula, you can find millions of them\n\nL x W = 2(L + W)\n\nuse any number for L and solve for W