will someone please help with a few math analysis questions?
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For the first one, the zero exponent should not be disregarded.  2x^0 is just one so it just eliminates that second 2x.  For the cubed part, the three needs to be distributed to the 2 and the x.  Is the negative one only on the x or is it on both the 2 and the x?  If it is only on the x, then your answer will be (2^3)(x^-3)=8x^-3 or 8/x^3.  If it is on both then you have (2^-3)(x^-3) which is 1/(8x).\n\nFor the second one, first flip the fraction, you get (4/3)^2 and then distribute the power to both the top and the bottom, youget (16/9).\n\nTHE NEGATIVE IN THE EXPONENT HAS NOTHING TO DO WITH A NEGATIVE IN THE BASE.  So just because there is a negative power, DO NOT put a minus sign in the base.\n\nFor the third one, just solve for y.\ny+2=3/8(x-16)\nget rid of the parenthesis and we have\ny+2=3/8x-6\nand then subtract 2 from both sides\ny=3/8x-2
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#1.)-----------------------------------\n  \n25b^ -20by + 4y^\n\nMultiply 1st and 3rd term together to get 100b^y^.\n\nFactor 100b^y^ into two factors whose sum = the middle term of -20by.\n\n1by   X 100by\n2by   X 50by\n4by   X 25by\n5by   X 20by\n10by X 10 by   ....................BINGO!\n\n-10by + (-10by) = - 20by   &   (-10by)(-10by) = 100by\n\nThis is a really kewl factor by grouping trick, I LOVE it!\n\nBring down the first term of: (25b^)\n\nNext, write the SMALLER of the two factors 1st.  Followed by the LARGER of the two factors.  In this case, they're both the same, so it doesn't matter which one goes first: (-10by)\n\nFinally, bring down the third term of: (+4y^)\n\n25b^ -10by -10by + 4y^\n\nNow, lets factor by grouping! \nFactor out the GCFs.\nGCF#1 = 5b\nGCF#2 = -2y\n\n(25b^ -10by) + (-10by +4y^)\n5b(5b - 2y) -2y(5b - 2y)\n\nGCF#3 = (5b - 2y)\n\n(5b - 2y)(5b - 2y)\n\nSimplifies further as: (5b - 2y)^   ....Whatdayaknow?! \n.......................................................................................................It's a Perfect Square Trinomial.\n\n#2.)------------------------------------------------------------------\n\n100 - 9b^\n\nAh, the difference of two perfect squares.\n\n---------------------------------------------\n\nFORMULA:\na^ - b^ = (a-b)(a+b)\n\n---------------------------------\n\nSOLUTION:\n100 - 9b^\n(10)^ - (3b)^\n\n-----------------------\n\nANSWER:\n(10-3b)(10+3b)
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go to a math website off yahoo. it should help.
414419
http://www.math.niu.edu/~beachy/aaol/frames_index.html
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http://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/\n\nhttp://www.math.armstrong.edu/MathTutorial/
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1. 2\n\n2. 2a^2b\n\n3. 6xyz^2(2z-3y)\n\n4. 3a(4a-b+3ab^2)\n\n5.(d+2)(d+3)\n\n6.(x-9)(x-2)\n\n7. (4x-1)(x+3)\n\n8. (4b-9)(4b+9)\n\n9.(y+7)^2\n\n10. (2m+7n)^2
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http://homeworkhelp.aol.com/math/?sem=1&ncid=AOLRNL00170000000006
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Please state the requirements of the mathematic's work project.\n\n- - - - - - - -s-
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Differential equations.\nLinear algebra.\nNumerical analysis.
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http://www.mathgoodies.com/\nhttp://www.gomath.com/\nhttp://www.mathnerds.com/mathnerds/\n\nhope these sites help you..happy studying!!
503650
Why don't you share with us what you have done so far instead of just asking someone to do your homework?\n\nSorry about the snide remark. Here is your well-deserved step-by-step solution:\nhttp://www.rgetso.com/yahoo/afchica101.pdf
424650
Not really enough information to help, so try this site:\n\nhttp://www.blc.edu/fac/rbuelow/calc/ex4-6.html\n\nit's the second problem down the page
68097
do you mean things as far as max and mins, asymptotes and things like that?\n\nif you are a little more specific i can help you better, or e-mail me, it would be a little easier  matttlocke@yahoo.com
437783
1) 1, 2, 3 and 6\n2) 1, 2, 2m\n3) 1\n4) 1, 3\n\n5) 5/9 (55/99) > (45/99) 5/11\n6) 2/3 (8/12) < (9/12) 3/4\n7) 4/5 (32/40) < (35/40) 7/8\n8) 1/3 (4/12) = (4/12) 4/12
1127430
try this one http://www.algebrahelp.com/
775593
Load the Analysis Toolpak add-in and then use this formula, it's shorter:\n\n=A1/GCD(A1, B1)&":"&B1/GCD(A1, B1)
547907
1) 4 3/4\n\n2) 1356.66\n\n3) 760