Does anybody hv a maths puzzle that I can use for a tie breaker between two teams of sch kids.?
912698
Do the game when the students can make one, two or three tally marks.  The object of the game is to make the last mark without going over.    The team gets a choice of going first, or choosing the number the game will go to.  \n\nThere is a pattern to the madness, but I want you to figure it out.
11697
b-a, at least if it is mathematics
1094028
Most of them got it right.\n\nThis is another way to think about the result.\n\nFirst player = T or H doesn't matter\n\nSecond Player = Must be that same as the First Player\n                        =  only 2 possibility (H or T)\n                        = 1/2\nThird Player = Must be the same as First Player\n                    = again, only 2 possibility ( H or T )\n                    = 1/2\n\nIn order for the Second Player and Third Player to have the same result as First Plaer = 1/2 x 1/2\n                                 = 1/4.
733595
you can't, but Y! can....email them requesting one of these options....these are the only options avail...\n\nWeek 15 and 16    4 teams\nWeek 16 and 17    4 teams\nWeek 14, 15 and 16  6 teams \nWeek 15, 16 and 17  6 teams\nWeek 14, 15 and 16  8 teams \nWeek 15, 16 and 17  8 teams\n-nny
993326
If two team are tied by points the first tiebreaker will be the goal differencial wich wil be for example: USA is tied up with Germany... they both have equal points in total ex: 4\n  USA   srored  3 goals and took 1--> goal diferencial is +2 : 3-1=2\n         \n       Germany scored 5 and took 4-->goal diferencial is +1 : 5-4= 1\nTherefore Usa advances to next round.
328609
Try this site:\n\nhttp://puzzlemaker.school.discovery.com/
894091
None. Two odds make an even
798663
Francopit was by far the closest yet.  Since there are only 2 kids, an exhaustive solution really makes sense.  With 2 kids, there are 4 possibilities of male/female combinations.  Listing the older one first they are:\n\nMM\nMF\nFM\nFF\n\nSince we know there is at least one male, the problem reduces to three possibilities:\n\nMM\nMF\nFM\n\nNow for each case there are two choices depending on which one is the king/queen.  Using caps for the king/queen:\n\nMm\nmM\nMf\nmF\nFm\nfM\n\nThe problem list a king not a queen so all the 'F' cases are discarded.  Francopit said, mM is not possible since the oldest male is king.  This leaves:\n\nMm\nMf\nfM\n\nBased on the problem statement, these are all the possible configurations.  In one, the king has a brother, in the other 2 he has a sister so the probability of a sister is 2/3.
942547
Can you please check you haven't made a mistake somewhere? I have just calculated (with 99% certainty) that there are no solutions to those equations with those restrictions.\n\nEdit - OK, I assumed you made exactly one mistake. By removing each possible word and trying to solve it, I discovered that removing 'SIGH' was the only option that gave an answer.\nt 1\nh 8\na 3\nn 7\nk 6\ns 5\ng 9\ni 4\nv 2\nwhere SIGH = 26, not 25. Then THANKSGIVING = 65.\n\nThat was actually a cooler puzzle that the original, assuming you made one mistake :)
576112
Your tie breaking rules should be stated before the tournament begins.  One team is going to feel screwed.  I'd suggest that your first tie breaker is points scored, then points allowed, and then a coin flip.\n\nIf you didn't have a tie breaker set up before the tourney, I think you should explain that to both teams.  Explain that anything you do would be viewed as picking one team over the other, and propose a coin flip.  You screwed up and the team that doesn't get in will be unhappy with you, but it's the only fair way you can do it.  But be honest that there wasn't a tie breaker set up ahead of time.
391420
These are some ideas aimed for pre-k, 1st and 2nd grade:\n*you can provide different geometrical shapes and have them sort them according to color, size, shape, etc.\n*with the same shapes have them complete a pattern you start for them ex. red circle, yellow square, red circle, yellow square, etc.\n*try looking for a game called "Tangram", I don't know if you can buy one already done or you can make your own in this site:http://www.tangram.i-p.com/\n*give students play money and have them solve problems using it.
47500
gym english science any thing but math lol
12336
Try the BBC's Maths series and MathsFile as well as Math.com (see links below)
698606
Hmm, interesting question, actually, and a practical application of math.  Hey, all you folks who ask what this stuff is good for, here is a real-life situation where you can use it!\n\nGetting to the problem.  Obviously, the contestant to go last spins again if his score is lower than the best score.  If tied, there is a spin-off where his winning chance is 50%; so, if there is a tie, he should respin if he has 45 or less (giving him at least 11 out of 20 good numbers), not spin if he has 55 or more (giving him at most 9 out of 20 good numbers - better to go to the spin-off, where he has a 50% chance), while 50 is a "push".   \n\nNow, for the contestant to go 2nd to last: First, let's assume the first player busts (of course, the second player respins if his score is lower than the first player), which essentially makes this a two-player game.  Based on what number the second player stops on, this is the winnning percentage I calculate for the last player:\n\n100 - 4.875%\n95 - 14.375%\n90 - 23.375%\n85 - 31.875%\n80 - 39.875%\n75 - 47.375%\n70 - 54.375%\n65 - 60.875%  \n60 - 66.875%\n55 - 72.375%\n50 - 77.375%\n\nSo, you may think the second player should respin whenever his odds are under 50%, but that is actually incorrect.  For example, if the second player has 70, giving him a 45.625% chance of winning, respinning would give him a 70% chance of going bust - he is better off stopping with the 45.625% chance.  To determine whether or not respinning improves the second player's chances, a second calculation is needed that considers each of the 20 scores after the second spin - some of them bust the player but the others improve his chance of winning.  Based on that, here is a new table, giving the last player's chance of winning if the second player respins with the score given:   \n\n95 - 95.24375%\n90 - 90.9625%\n85 - 87.13125%\n80 - 83.725%\n75 - 80.71875%\n70 - 78.0875%\n65 - 75.80625%  \n60 - 73.85%\n55 - 72.19375%\n50 - 70.3125%\n45 - 69.68125%\n\nSo, comparing the two tables, the critical points are 55 and 60.  If the second player has 60, he should stop - the last player's chance of winning improves if the second player spins.  At 55, however, the second player should spin, improving his odds by about 0.2%.\n\n\nMoving on to the three player game... now it gets really messy.  The player to go first needs a score that can beat the other two players.  Does he stop on 55 again, hoping the other two players both bust?  He'll need a better score than that to have a 50% chance of winning, but, as was noted in the two-player analysis, stopping with a 30% chance can be better than making a second spin.  As for how to do a complete analysis, uh, beats me.  This may require a computer to do all the math.\n\n* * * * * *\n\nThinking about the three-player game, maybe it isn't as messy as I initially thought - the only additional consideration for the first player, as opposed to the second player, is that either player will stop if the first player's score is beaten.  This can be calculated from the first table.  For this table, listed is the chance of the first player losing (i.e. either player beats him) if he stands on the score given:\n\n100 - 9.51% \n95 - 26.68%\n90 - 41.29%\n85 - 53.59%\n80 - 63.85%\n75 - 72.31%\n70 - 79.18%\n65 - 84.69%\n\nSimilar to the two-player game, I can now calculate the odds if the first player decides to respin.  Since I’m getting a little tired crunching these numbers, for this last table I’ll only list the critical ones:\n\n70 - 83.4%\n65 - 82.3%\n\nIn other words, the first contestant should respin on 65, stop on 70.\n\nIn conclusion, I think the optimum strategies are.....\n\nFirst player: spin on 65, stop on 70\n\nSecond player: spin on 55, stop on 60 (assuming his score at least matches the first player)
709282
Quick Math-Mind Games
86553
http://www.kidzone.ws/math/
959000
Have a look here http://www.google.co.uk/doodle4google/winners.html