help factor     1.     x^3-125                  -------                2.       x^3+8y^3?
912595
Here are the formulas you will need to use:\nx^3 - y^3 = (x-y)(x^2 +xy +y^2)\nx^3 + y^3 = (x+y)(x^2 -xy +y^2)\n\n1) x^3 - 125 is a difference of two cubes.\nx^3 - 125 = x^3 - 5^3 = (x-5)(x^2 + 5x + 25)\n\n2) x^3 + 8y^3 is a sum of two cubes\nx^3 + 8y^3 = x^3 + (2y)^3 = (x+2y)(x^2 - 2xy + 4y^2)
958614
#1.)-----------------------------------\n  \n25b^ -20by + 4y^\n\nMultiply 1st and 3rd term together to get 100b^y^.\n\nFactor 100b^y^ into two factors whose sum = the middle term of -20by.\n\n1by   X 100by\n2by   X 50by\n4by   X 25by\n5by   X 20by\n10by X 10 by   ....................BINGO!\n\n-10by + (-10by) = - 20by   &   (-10by)(-10by) = 100by\n\nThis is a really kewl factor by grouping trick, I LOVE it!\n\nBring down the first term of: (25b^)\n\nNext, write the SMALLER of the two factors 1st.  Followed by the LARGER of the two factors.  In this case, they're both the same, so it doesn't matter which one goes first: (-10by)\n\nFinally, bring down the third term of: (+4y^)\n\n25b^ -10by -10by + 4y^\n\nNow, lets factor by grouping! \nFactor out the GCFs.\nGCF#1 = 5b\nGCF#2 = -2y\n\n(25b^ -10by) + (-10by +4y^)\n5b(5b - 2y) -2y(5b - 2y)\n\nGCF#3 = (5b - 2y)\n\n(5b - 2y)(5b - 2y)\n\nSimplifies further as: (5b - 2y)^   ....Whatdayaknow?! \n.......................................................................................................It's a Perfect Square Trinomial.\n\n#2.)------------------------------------------------------------------\n\n100 - 9b^\n\nAh, the difference of two perfect squares.\n\n---------------------------------------------\n\nFORMULA:\na^ - b^ = (a-b)(a+b)\n\n---------------------------------\n\nSOLUTION:\n100 - 9b^\n(10)^ - (3b)^\n\n-----------------------\n\nANSWER:\n(10-3b)(10+3b)
658148
given 4a^2-12ab+9b^2\n    =(2a)^2-2(2a)(3b)+(3a)^2\n    =(2a-3b)^2
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
79707
16 - 3(8-3)squared / 2\n\n1. 16-3x(8-3)²÷2\n2. 16-3x(5)²÷2\n3. 16-3x25÷2\n4. 16-37.5\n5. -21.5
617827
3x^3y^2z^4\n\nbecause you divide the exponents by 4, but do the fourth root of the coefficient 81
764068
2x - 2 = x^2 - 4x + 3\nSet one side equal to 0\n0 = x^2 - 6x + 5\nFactor\n0 = (x - 5)(x - 1)\nSet each factor equal to 0\n0 = x - 5              0 = x - 1\nSolve\n5 = x                  1 = x
102099
(128x)^(1/3)^(5y)^(13)=\n\nMultiply all the power\n\n(128x)^[1/3*5y*13]=\n(128x)^(65/3 y)
402918
I think you wrote 10x*2yz - 22x*3yz.  To factor this oyu must take out like terms by dividing.  You can see that both terms share a 2, y, z, and an x*2.  After the  division you get  2x*2yz( 5 - 11x).  I hope this helps.
930643
factor:\n\n(2x^2+x-6)/(2x+4)=\n\n(2x-3)(x+2) / 2(x+2)\n\nthe (x+2)s cancel out leaving\n\n(2x-3)/2
397605
12-13b+b^2=(12-b)-(12b-b^2)\n  = (12-b)-(12-b)b\n  =(12-b)(1-b)\n\nThis might not be easy to see, so here is the general approach:\n  Cb^2 + Db + E = (b-B1)(b-B2)\nwhere B1 = (-D + sqr(D^2-4CE) ) /(2C)\n and B2 = (-D - sqr(...) ) /(2C)\n\nIf (D^2-4CE)<0, you cannot factor it.\n\nsqr is square root. In your case C=1, D=-13, E=12, so you get B1=12 and B2=1
503153
(x+7)(x+3)\n(x-11)(x+2)\nforget this one.  its AC factoring though\nthis ones AC too
636732
8x^2y^3+5y^2 when "FACTORED COMPLETELY"=\n\ny^2 (8yx^2+5). \n\nThis should be right. My dad is a complete genius and he did this in like 2 seconds. I double checked it on my calculator too by plugging in numbers, so I can assure you he's right.\n\nHope this helps! Have a nice day :)
772026
1.\n7x^6y^4 + (x^3y^2)^2\n7x^6y^4 + x^6y^4\n8x^6y^4\n\n2.\nx^2(xy^3)^2 + y^2(x^2y^2)^2\nx^2(x^2y^6) + y^2(x^4y^4)\nx^4y^6 + x^4y^6\n2x^4y^6\n\n3.\n7x^2+3x-x^2\n6x^2+3x\n3x(2x+1)\n\nYou sure you posted #3 correctly?
791576
I'm going to assume the placement of parenthesis.\n(x^2 – 3x + 2)/(8x - 8) ÷ (x^2 – 4)/(5x +10)\n\nStep 1: Flip the second fraction, so that you have multiplication instead of division.\n(x^2 – 3x + 2)/(8x - 8) * (5x +10)/(x^2 – 4)\n\nStep 2: Factor.\nx^2 – 3x + 2 = (x - 2)(x - 1)\n8x - 8 = 8(x-1)\n5x +10 = 5(x + 2)\nx^2 – 4 = for a^2 - b^2, the factors are (a + b)(a - b). So: (x + 2)(x -2)\n\n(x - 2)(x - 1) / 8(x-1) * 5(x + 2) / (x + 2)(x -2)\n\nStep 3: Cancel out, multiply\n(x - 2) / 8 * 5 / (x -2)\n5 / 8 (solution!)
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
1174662
2(x-4y+1)+3(-2+y-2)\n2x-8y+2-6+3y-6\n2x-8y+3y-6-6\n2x-5y-12\n\n2x-5y-12= answer\n\nHope this helps you.