how do equations help you?
920401
usually when you solve equations you get a solution.\nthe solution solves your problem.\n!
741999
whats the equation or formula u need help with?
110265
The equation is meant to record the results of an experiment.  The reactants (stuff you started with) are written to the left and the products (the stuff you end up with) is written to the right.\nTo balance an equation, only the coefficients (the numbers in front of the chemicals) may be changed.\nIf you change the symbols, you change the type of atoms used.\nIf you change the formulas or subscripts, you change the chemicals (the molecules) used in the experiment.
474440
The key to math is understanding the definitions. Make sure you understand them first and then start on examples of problems.  You need to ask yourself two questions when approaching math problems.  1. What is the questions asking me? 2. What does the answer look like?  For example:\n\nFind the roots for the function y=x^2 + 7x + 12\n\nYou know that your answer needs to be where y=0.  Now you need to know what the answer looks like. It can take varying forms but these would be reasonable:\n\n(-3,0) and (-4,0) or x=-3 and x=-4\n\nRemember to always understand what is being asked of you and to have an idea of what it should look like.  The biggest problem students have is relying on the calculator.  The calculator can only tell you what you tell it.  So if you don't understand what it should look like then it may come out wrong.
665050
You use algebra every day, believe it or not.\n\nWhen you buy something in a store, you usually estimate how much it will cost with tax.  That's algebra.  If x is final cost; the item costs $10, and sales tax is 5%, then the equation is:  x = 10(1.05).  \n\nAnytime you have an unknown, you can use algebra to form an equation and get an answer, or find that you don't have all the information you need to get an answer.\n\nRather than looking at algebra as learning how to solve esoteric equations, think of it as a way of learning how to manipulate quantitative information to find what initially may seem to be unknowable quantitative information.\n\nSo, when you have to figure out what percentage of aid a client is entitled to from various agencies, you will have to manipulate information algebraically.\n\nGranted, you may never need the more complex equations, but it will be a great help when you look at a bunch of complex information and you realize that you can find the answers you need by formulating simple equations.
789077
in excel all you have to do is to put = before any equation you want to solve and then press ok \nyou can use squares instead of the no.s
878962
first you get one variable on one side by its self (lets say x), solve for that variable (x), then you put the answer in for "x" and solve for the second variable, Just like you would if you only had one variable to begin with.
514202
All you have to do is combine like terms and then solve for x or y.  Then for the solving and graphing, refer to your textbook.  I don't feel like telling you HOW to graph it.
931883
Ummm...\nThe equation of algebra, eh?\nWhat on earth are teachers teaching kids these days?!
76405
In solving equations, the first step is always classifying them:\nin this case you have a square of x and an x as exponent: the exponent wins and the equation is an exponential one.\nAs there are non-exponential terms involving x, you have to follow this procedure to find a solution:\n\n1) Graphical study\nGraphical study helps making an idea of HOW MANY solutions there are and APPROXIMATELY WHERE they are\n\nWrite the equation isolating the exponential from the polynomial terms:\n8^x = 16 - x^2\nThis equation tells that you are trying to "balance" an exponential (y=8^x) with a parabola (y= 16 - x^2)\nThat is, you are looking for the ascissa of any intersection point of the two graphs.\nIn this case there should be two intersection points, one for some negative x and one for some positive x: try and find them making the graphs.\n\n2) After finding an integer interval which contains the solution (at a glance: -4<x<-3 for the negative solution; 0<x<1 for the positive one), you can choose any iteration formula (Newton or others) to find the solution. A computer is needed for this, or you can also do by hand, but it's a hard and teasing job
577117
It depends...If you are working on a simple equation then you simply move all of the variables to one side and solve.  If you are working with a set of equations, ex....\neq 1. 3x+48=4(y+11)\neq 2. y=4+x\nYou wouls simplify the first equation to get one variable by it's self, and then you would plug the secone equation in... like this...\nsimplify the first equation... (3/4)x+1=y\nthen plug in the 4=x for the y in the first variable, giving you (3/4)x+1=4+x, and then simplify.  that will allow you to find the value of X, and then you plug x back into one of the equations, 2 is easier here, and then solve for y.  of yo uwant more help, try this website...http://www.algebrahelp.com/
1112132
Microsoft Office has an equations editor.  It may not be installed by default.\nIf you have Office, click [Insert] / [Object], then see if MS Equation Object is available.  If not, use the CD to add the equation feature.
518727
Multiply the first equation by 2.\n\nSubtract the second equation from the new first equation.\n\nSolve for y.\n\nTake your value for y and substitute it into the original first equation.\n\nSolve for x.
327077
generally, you combine like terms and then subtract the same thing from both sides and/or divide both sides by the same thing.  but that may b 2 vague to help much.  i need a specific question.
285662
to find an equation.......\n\ny=mx+b\n\nm=slope \nb=y-intercept
533429
well..write them down ...try to derive them (if their derivation is simple enough or else skip it )......\n\ntry to connect each formula with other one with a hint ....a small hint will help u to recollect other one ....\n\ntry to do at least one problem based on each formula
589722
Step 1: Solve one equation for one variable in terms of the other.\nStep 2: Plug that into the other equation and solve for the second variable.\nStep 3: Plug the second variable into the first equation and solve for the first variable.