How many watts are there in one volt?
928079
There are no watts in one volt.\n\nWatts is a measure of the rate of energy transfer. If you only have voltage, you have no energy transfer. Your wall outlet has voltage, but no electricity is actually flowing through it (until you plug something in), so there is no wattage.\n\nVoltage is the 'pressure' of the electricity - how hard it pushes to get through the circuit. Amperage is the actual quantity of electricity moving through the wire. Multiply the two of them together, and you get your wattage.
132617
KVA =Kilo Volt Ampere\nKilo = 1000\nPower = Voltage * Current\nso watts = KVA*1000\nEg. 5KVA = 5*1000 =5000W
362045
markey watts = volts x amps , only for a Direct Current device. For AC, which we use in our wall outlets, there is another quantity called the power factor which is the cosine of the phase lag between the voltage and the current:\n\nwatts = volts x amps x powerfactor
784102
16. C 150 Ohms not Watts\n\n17. A\n\n18. D Current Divider Rule in a parallel Circuit\n\n19. C\n\n20. A  6V time 0.04A = 0.24 Watts
211994
V = Er = 3E6 x 0,30 = 9E5 volt = 900 kV
767776
The Power, P = VI, hence\n\nThe current at 120V is I = P/V = 65000/120 = 541.667 A\nThe current at 1200V is = 54.1667 A\n\nHowever, here the power is carried by TWO parallel lines, each with 0.1 ohms of resistance. That means the effective resistance is given by:\n\n1/Reff = (1/R1) + (1/R2) = 20 or Reff = 0.05 ohms\n\nTherefore, the Power Loss at 120V is\n\nP = I^2R = (541.667)^2(0.05) = 14670.15 watts\n\nThe Power Loss at 1200V is = 146.7 watts\n\nHence the power saving by stepping up to 1200V is\n\n= 14670.15 - 146.7 = 14523.45 watts
313707
Assuming you are using US household electricity (120VAC)\nP=V^2/R   R=V^2/P = (120)^2/1875= 7.68 ohms which is really small.
656857
if you live in the US\n110V for most appliances\n220v/110v for bigger ones\nif you live over in Europe \n220V
1105249
8.5x1000=8500 watts.  415 volts.  W=V*A A=W/V\n\nso 8500watts/415 volts =20.48... Amps\n\nthis is the basic relationship between watts volts and amps.  I dont know if the 3 phase motor part would change that answer.
261103
10 amps if the voltage difference is 120 volt as usual
148878
1power0 = 1\n1power1 = 1\nso that 0=1
1050051
Technically, you don't convert mA into VA in any AC circuit!  One is a measure of current flow, the other is a measure of power.\n\nNow if you want to figure out the power of the transformer, simply multiply the amperage by the voltage.\n\nP = 12V X 800mA = 12V X 0.8A = 9.6 VA or 9.6 watts.\n\nNow you can think of the power in terms of VARs (volt amp reactive), but those are typically used in where you have either a(an) inductive and/or capacitive load and use imaginary numbers to solve such problems.
500605
Basically.... it is as simple as (Voltage X (times) amperage = Wattage) example.... \n\na 120volt motor pulling a normal 3 amperes  ....will consume 360 watts of electricity... \n\nThe more amperage the motor requires.... the higher... the horsepower... and also the cost to run or operate it...
36069
My guess is no\ni thnk volts is more
210547
power=voltage^2/resistance\nhigher power means lower resistance.
663172
700V x 2.5A = 1750VA\n\n1750VA / 240V = 7.291666A\n\nWatts (Voltamps) Input = Watts (Voltamps) Output\n\nThe answer is 7.3 Amps @ 240V
1130014
V=IR\n\nWire 1:\n50 = 2 * R1 => R1 is 25 ohms\nCurrent = 2 amps\npower = V*I = 2*50 = 100 watts\n\nWire 2: \n100= 2* R2 => R2 = 50 ohms\nCurrent=2amps\npower = V*I = 100*2 = 200 watts\n\nare you looking for ratios when you say "compare" ?\nif yes: ratio of resistances is  1:2\nratio of currents is 1:1\nand ratio of power is 1:2