how to solve this equation 2x/x^2 - 16 = 2/x^2 - 16 - 1/x+4 ?
916369
2x/(x+4)(x-4)=2/(x+4)(x-4)-1/(x+4)\n\nMultiply (x+4)(x-4) on both sides:\n2x=2-(x-4)\n\nDistributive property:\n2x=2-x+4\n\nCombine like terms:\n2x=-x+6\n\nAdd 1x to both sides:\n3x=6\nx=2\n\nCheck:\n2(2)/(2)^2-16=2/(2)^2-16-1/2+4\n-1/3=-2/12-1/6\n-1/3=-1/6-1/6\n-1/3=-2/6\n-1/3=-1/3\n\nI hope this helps!
707304
1/(x - 1) = (x + 2)/4\ncross multiply\n4*1= (x-1)*(x+2)\n4 = x^2 +2x - 1x -2\n4 = x^2 + x -2\n0 = x^2 +x -6\n0 = (x+3)(x-2)\n\nso x= either -3 or +2\npositive = +2
731860
x² - y² = 16\nSo 2x - 2ydy/dx = 0\nie dy/dx = x/y\n\nd²y/dx² = (y - xdy/dx)/y² (NOTE: x² - y² = 16  → y² = x² - 16)\n= (y - x.x/y)/(x² - 16)\n= (y² - x²)/(x²y - 16y)\n= -16/(x²y - 16y) (As x² - y² = 16)
832845
you need to add +1\nso that the equation can be represented as a perfect square\nx^2 - 2x + 1 = (x - 1) (x - 1) = (x - 1)^2\n\nthis is called solving by perfecting the square\nto do this, make sure that the coefficient of the first term is 1.\nThen, divide the coefficient of the middle term by 2,\nthen square the whole thing.\n\nIn this case, the coefficient of the middle term is -2\n-2 / 2 = -1\n(-1)^2 = +1
939593
(x^2-x^(3/2))/2x^2 = 1/2-sqrt(x)/2\n        =1/2(1-x^(-1/2))\n\nd(1/2(1-x^(-1/2)))/dx\n=1/2(-(-1/2x^(-3/2))\n= 1/4x^(-3/2)\n\ni hope that this helps
954896
x^2 + -2x = 5   Isolate the x^2 and x terms.\n\nx^2 + -2x = 5   Divide both sides of the equation by 1, which is the a-coefficient.\n\nx^2 + -2x + (-2/2)^2 = 5 + (-2/2)^2   Add half of the b-coefficient squared. In this equation that value is (-2/2)^2, and can be simplified to 1.\n\n(x + -2/2)^2 = 5 + (-2/2)^2   Write the x^2 and x terms side as a perfect square binomial.\n\n(x + -2/2)^2 = 5 + 1   Simplify the other side (simplify fractions).\n\n(x + -2/2)^2 = 6   Simplify the other side (combine numbers/fractions).\n\nSQRT[(x + -2/2)^2] = {+,-}SQRT[6]   Find the square root of both sides.\n\nWhen you combine and solve you'll get\n\nx = -1 plus or minus SQRT[6]
287526
x+5/16x divided by 3X-2/4x^2 \n=x+5/16x multiply 4x^2/3x-2\n=X^2 +5x/ 12x-8\n\nunless the mathemathical equation u give above equals to a figure or another matn equation...it is impossible to determine the correct value of x
796530
x/16 = 40/64\nmultiply both sides by 16\nx = 40/4\nx = 10
810055
x^2 - 2x + y^2 + 2y + 2 = 16\n\nx^2 - 2x + 1  + y^2 + 2y + 1 = 16\n(x - 1)^2 + (y+1)^2 = 16\n\nCenter = (1, -1)\nRadius = sqrt(16) = 4
103674
2x^2 - x = 0  { by adding 1 to both sides }\nx^2 - (1/2)x = 0  { by dividing both sides by 2 }\nx (x - 1/2) = 0 { by factoring }\n\nsolves when either x = 0 or x = 1/2 . QED
216863
((4 * 4) / 4) - 4 + 4 = 4
784622
16x^2 - 4x - 2\n= (4x)^2 -(4x)- 2\n= {(4x)^2 - 1} - (4x+1)\n={(4x+1)(4x-1)} - (4x+1)\n=(4x+1)(4x-2)\n= 2*(4x+1)(2x-1)
898442
You just factor\n(2x-1)(x-2)=0\nx=2, 1/2
635930
x+2/x-2 \n= (x^2 - 2x + 2)/x [BODMAS rule]\nSo Eric is correct.
449301
4/Q=2\n4/Q * Q/1 = 2*Q/1\n4 = 2Q \n4/2 = 2Q/2\n2=Q\n\nYou first multiply each side of the equation by the same figure, in this case by Q/1.  The result is 4 = 2Q.  Next, divid each side of the equation by the same figure, in this case by 2.  The result is 2=Q.
786976
16x^2 + 12x\n\nIn order to solve, you would need an equal sign.  I think maybe you mean finding the zeros?\n\nFirst we would need to factor it.  We could pull an x and a 4 out of each.\n\n4x(4x + 3)\n\nWe get two factors.\n4x\n4x + 3\n\nThen we set each factor equal to 0 to find the zeros of the equation.\n\n4x = 0\nx = 0\n\n4x + 3 = 0\n4x = -3\nx = -3/4\n\nOur zeros are 0 and -3/4.\n\nI hope I helped. :)
302160
You have to find a common denominator\nFirst, factor each denominator\nx^2 - 16 = (x+4)(x-4)\nx^2 + 8x + 16 = (x+4)(x+4) = (x+4)^2\nThe common denominator would be (x-4)(x+4)^2\nThe first term:\n(3x+1)/{(x+4)(x-4)} is missing an (x+4) so multiply the top and bottom by x+4\n{3x+1)(x+4)/{(x-4)(x+4)^2}\n= (3x^2 + 13x +4)/{(x-4)(x+4)^2}\nThe second term\n(3x+5)/(x+4)^2 is missing an x-4 so multiply the top and bottom by x-4\n(3x+5)(x-4)/{(x-4)(x+4)^2}\n= (3x^2 - 7x - 20)/{(x-4)(x+4)^2}\nNow that there is a common denominator, you can just subtract the numerators\n{3x^2 + 13x +4 - (3x^2 - 7x - 20)}/{(x-4)(x+4)^2}\n= (3x^2 + 13x + 4 - 3x^2 + 7x + 20)/{(x-4)(x+4)^2}\nAnswer: (20x + 24)/{(x-4)(x+4)^2}\nYou can factor a 4 from the numerator but nothing will cancel with it, so this is an acceptable final answer.