simplify the following?
920734
2xy(-15x^2y^4)+8x^2)-5/-4xy^3\n(-1/2)[-15x^2y^4+8x^2-5)/y^2\n(-1/2y^2)[-15x^2y^4+8x^2-5]
750837
1--d\n2--a\n3--b\n4--a
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
771836
Simple substitution.\n\n5(3) - 2(2) + 4(4)\n15 - 4 + 16\n27
966462
(6x^2)/(4x^2 y-12xy) * (x^2 + x - 12)/ (3x^2 + 12x)\n\nFirst, I would attempt to simplify if possible:\n2x(3x)/x(2xy-6y) * (x^2 + x - 12)/ (3x^2 + 12x )\n(3x) / (2xy - 6y) * (x^2 + x - 12)/ (3x^2 + 12x)\n\nRewrite to see if we can cross cancel:\n\n(3x)           (x^2 + x - 12)\n---------  *   -----------------\n(2xy-6y)    (3x)(x + 4x)\n\n1               (x^2 + x - 12)\n---------- *  -----------------\n(2xy-6y)     (x+4x)\n\nUnfoil the (x^2 + x -12 to see if we can further simplify\n\n(x^2 + x - 12) = (x -3)(x+4) so you will have:\n\n1             (x-3)(x+4)\n-------  *  --------------\n2y(x-3)      (x+4)\n\nBy simplification:\n\n1           (x-3)\n------   * ----------\n2y(x-3)     1\n\nBy Cross Cancel:\n1/2y
1046507
[2x/(x+3)(x-3)]*[(x-3)/4(x)]\ncancelling 2 and x-3 we will get\n=x/(x+3)2(x)\nsimplify we will get\n=x/(2x^2+6x)
372587
I'm not sure what you are looking for.\n(x-3)/(x+2) does not simplify.\nThe domain is all real numbers except -2.\nThe range is all real numbers except 1.
561170
use the 'g' modifier. for example ~/^first.*last$/g
751318
x^2-x-6>0\nor, x^2-3x+2x-6>0\nor, x(x-3)+2(x-3)>0\nor, (x-3)(x+2)>0\nor x>3 and x<2\n\nhope this helps :)
971390
{3XY^2M/1}-{2M/[X^-1Y^-1]^2\n+{[4X^2Y^2]/M^-1}-\n(3X^(3Y)^(3M)^-1/(XYM)^-2
597439
=[(4+3x)/x] + (2/3)[(5+3x)/x]\n=[(4+3x)/x] + [(10+6x)/3x]\n=[(12+9x+10x+6x)/3x]\n=[(15x+22)/3x]
725255
1. (xy^2)^3 (x^2y)^2 + (x^3y^4)(x^2y^2)^2\n(x^3y^6)(x^4y^2) + (x^3y^4)(x^4y^4)\nx^7y^8 + x^7y^8\n2x^7y^8\n\n2. (3x^2)(3y^2)+ 3x^2y - (3xy)^2 - 3xy^2\n9x^2y^2 + 3x^2y - 9x^2y^2 - 3xy^2\n9x^2y^2 - 9x^2y^2 + 3x^2y - 3xy^2\n3x^2y - 3xy^2\n\nSimplifying is fun.\n\nBarjesse37
852547
You need to multiply by the reciprocal\n\nwhich gives you \nnumerator:  (s+t)15\ndenonimator:  5(2(s+t))\nThis will simplify to 15(s+t) over 10(s+t); which is 1.5
110508
(x^2+5) / (x^3+15-2x^2+1)^2\non [0,1]
618071
simplify to f(x)=(sqrt(x-2)(x-3))/(x-4)(x+5)\nthen sub in 1/x\nto get (sqrt(1/x -2)(1/x -3))/(1/x -4)(1/x +5)
971669
1. 1s2 2s2 2p6 3s1\n2. 1s2 2s2 2p6 \n3. 1s2 2s2 2p4\n4. 1s2 2s2 2p6\n5. 1s2 2s2 2p6 3s2 3p6 3d7 4s2
904430
(T-12)/(T-5) - (T-11)/(5-T) = (T-12)/(T-5) + (T-11)/(T-5) = (2T-23)/(T-5)\n\nPerhaps you would consider this simplified further as:\n\n2 - 13/(T-5)