Please Help SOLVE....?
923840
Here's how I would do it:\n\nTo remove the sqrt, you square both sides:\n\nsqrt(p^2 - 3p + 16) = (p+1)(p+1)\np^2 - 3p + 16 = p^2 + 2p + 1\n\nThen it's basic algebra. The p^2 are out of there, and you are left with\n\n-3p + 16 = 2p + 1\n16-1=2p+3p\n15=5p\np=3\n\nSo, let's check:\nsqrt(3^2 - 3(3) + 16) = 3+1\nsqrt(9-9+16)=4\nsqrt 16 =4\n\nThe person who put -5 as one of the answers... it doesn't work:\n\nsqrt ((-5)^2 -3(-5) + 16) = -5+1\nsqrt (25+15+16)= -4\nsqrt 56= -4 This is false, so -5 is not an answer.
599995
abuse of yahoo! answers. This is very simple and u SHOULD be able to solve it yourself!!!
900562
I'd suggest searching for such problems here on yahoo answers.  You can find out how to do it.
511948
There are an infinite number of ordered pairs that would satisfy this equation. If you want to find a few of them, assign a value to x and then solve for y.
966057
well well..the second time i see the same question!!\nshow some of ur work buddy.. ur a degree student and u dont simply put the questions on others..u wud never pass that way...\nso prove that u have tried ur best to solve this problem..show some coding that u have made!
948937
(-3,-3);(-2,0);(-1,1);\n(0,0);(1,-3)
1133069
i can give you the solution contact me on silentsakky@gmail.com
706993
Try reviewing your class notes and looking through your text book. Im sure that the answer you need is there. It might take a bit of thought to figure out how to do these problems! Take the time to figure it out, it will be worth it in the long run!
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
937047
Well, there may be more solutions here than usual, but the first solution I see is:\n(3 L,5 L,8 L)\n(0/3,0/5,8/8)\n(0/3,5/5,3/8)\n(3/3,2/5,3/8)\n(0/3,2/5,6/8)\n(2/3,0/5,6/8)\n(2/3,5/5,1/8)\n(3/3,4/5,1/8)\n(0/3,4/5,4/8)
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
897429
This is the third time that this question has been asked!?!?!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nThis is as far as I got:\n(2B+1)^(D-E) - F^(3G+G2) = (10J)/A\n\nBut someone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
302292
There's no solution.\n\nIf you're evil, you could argue that 102 - 78 is an answer ;)\n\nEDIT : Confirmed no solution with Telraam (http://members.chello.nl/g.de.blaauw/telraam.html). Allowing square roots gives (8*(2+.10))/.7 as a potential answer.
851212
hmm im not quite in college yet, but i hope to be help.\ndo you know the values for f, h, v, and a?\nif you do, id substitute it in.\nthen square both sides. \nand then solve.
538044
hmmm...very tough one!\n\nill sovle by the formula!\n       _________\n-b +- V (b^2)-4ab\n------------------\n       2a\n       _________\n-10 +-V 100+512\n------------------\n       2\n\n       _________\n-10 +-V 612\n------------------\n       2\n\n-10 +- 24.7\n------------\n     2\n\n14.7/2\n\n34.7/2\n\n(7.35, 17.35)
222284
duh...?  what's your question, Mam?  \n\n=0(
942547
Can you please check you haven't made a mistake somewhere? I have just calculated (with 99% certainty) that there are no solutions to those equations with those restrictions.\n\nEdit - OK, I assumed you made exactly one mistake. By removing each possible word and trying to solve it, I discovered that removing 'SIGH' was the only option that gave an answer.\nt 1\nh 8\na 3\nn 7\nk 6\ns 5\ng 9\ni 4\nv 2\nwhere SIGH = 26, not 25. Then THANKSGIVING = 65.\n\nThat was actually a cooler puzzle that the original, assuming you made one mistake :)