How do you find the slope of any line parallel to the line (15,1) and (4,2)?
930136
Use the slope formula to get the slope.  All parallel lines will have the same slope.\n\nm = (y2-y1) / (x2-x1)\n\nSo, for your points you have the following:\n\nm = (2-1) / (4-15) = 1/(-11) = -1/11\n\nTherefore all lines parallel to this line will also have a slope of -1/11.\n\nHope that helped!\n\n~ ♥ ~
35268
slope = (-4-(-6))/(-2-0)\nslope = -1
161144
equation of slope is (y2-y1)/(x2-x1)\n\n(8,-2) means x1=8 and y1=-2\n(3,5) means x2=3 and y2=5\n\nso slope= (5-(-2))/(3-8)\n=7/-5\n\nso slope= -7/5
744864
although Question is little vague, i understand that u want to find slope of a line ???\n\nsay coordinatyes of A and B are (x1,y1) and (x2,y2)\n\nThe Slope of line m= (y1-y2)/(x1-x2)
554784
x=(1--2)  or (1+2)\ny=(5-3)\n\ny/x=slope\nx=3\ny=2\nslope is 2/3
870460
Use the formula m = (y2-y1) / (x2-x1) to answer this.  (x1,y1) and (x2,y2) are your two points.\n\nm = (4-4) / (7-1) = 0/6 = 0\n\nSo, your slope is 0.\n\n(All lines with a slope of 0 are lines that are parallel to the x-axis)
978234
A parralel line has the same slope, so you know in the form y=mx  + b, m is your slope.  In your case, it is 1 (1x +4)\n\nSo you know your equation now is y = x + b.  x=-2 and y=0\n\n0= -2(1) + b\n\nSolve for b, which equals 2\n\nSo your parralel line equation is y = x + 2
143646
LET US SEE:\n\n1. y = (1/2)x + 5. This is an equation in standard form.\nIt is called slope-intercept form. If you mean general form\nthen:\n\ny = (1/2)x + 5\n\nMultiply by 2:\n2y = x + 10\n\n0 = x - 2y + 10\n\nx - 2y + 10 = 0  ANSWER\n\n=======================\n2. Line parallel to y = (1/4)x + 2:\n\nAny line parallel to y = (1/4)x + 2 has the equation:\ny = mx + b  ===> Equation of line\nwhere:\nm = slope = same as slope of given parallel line = 1/4\n\ny = (1/4)x + b ANSWER (equation of parallel lines)\n\nex:\na) y = (1/4)x + 0\nb) y = (1/4)x + 1\nc) y = (1/4)x + 3\nd) y = (1/4)x + 4\nd) y = (1/4)x - 1\ne) y = (1/4)x - 2\n.\n.\n.\n\n=======================\n\n3. y varies directly as x ; y = 2/3 and x = 1/2.\n\ny = kx (direct variation equation) where:\nk = constant of variation\n\nif y = 2/3 and x = 1/2:\n\ny = kx\n2/3 = k(1/2)\nk = (2/3)/(1/2)\nk = (2/3)(2/1)\nk = 4/3\n\nTherefore:\n\ny = (4/3)x ANSWER\n\n=======================\n4. Line passing thru (0,2) and perpendicular to \ny = (1/4)x + 2\n\nLet m = slope = -4 = negative reciprocal to slope\nof perpendicular line.\n\ny = mx + b  ==> slope-intercept form, where:\n\nm = slope\nb = y-intercept\n\nSolving for b, use point (0,2)\n\ny = mx + b\n2 = -4(0) + b\n2 = 0 + b\nb = 2\n\nTherefore, equation is:\n\ny = -4x + 2 ANSWER\n\n=======================\n\n5) Point(s) that lie on the graph of the equation \n\n3x + 6y = 27.\n\nThese are points that will make the left side of \nthe equation equal to 27.\n\nEX. ...;(-5,7)(-3,6)(-1,5);(1,4);(3,3);(5,2);(7,1);...\n\n=============================\n6. Equation of the line that contains (2,4) and undefined slope.\n\nA line that has an undefined slope is a vertical line. So,\na vertical line that contains (2,4) has the equation:\n\nx = 2  same as the x-coordinate of the given point.\n\n===========================\n\n7. Equation of the line that passes thru the x-axis \nat x = -1 and y-axis at y = 3.\n\nFrom the given intercepts, the two points are (-1,0)\nand (0,3)\n\nTherefore:\n\ny = mx + b ===> equation in slope intercept form.\nwhere:\nm = slope = (3-0)/(0--1) = 3/1 = 3\nb = y-intercept from point (0,3) = 3\n\nTherefore:\n\ny = mx + b\n\ny = 3x + 3 ANSWER.
875002
slope is a fraction found by subtracting the two y-coordinates and putting this on top, then subtracting the two x-coordinates (in the same order as you did for y) and putting this on bottom.  So, either\n\n(4-2)/(1- -6) = 2/7\n\nor\n\n(2-4)/(-6 - 1) = -2/-7 which is also 2/7 since a negative divided by a negative is positive
460260
First you need to know that the slope of two perpendicular lines are negative reciprocals of each other.\n\nSo given your first line of -1/3x - 4y = 2, find the slope of this line by changing to the slope/intercept form.\n\ny = -1/12x + 2\n\nThe slope is -1/12, so the slope of a line perpendicular to this line has a slope of 12.\n\nNext it's easiest to use the point slope form of a line to write the new equation.  Given a point and the slope, the formula allows you to write the equation for the line.\n\ny - y1 = m(x - x1)\n\nwhere m is the slope and (x1, y1) are the coordinates you are given.\n\nIn this case\ny - (-4) = 12(x - 2)\n\nor y + 4 = 12(x - 2)
442472
If the line is parallel then it must have an equal slope. Therefore the parallel line would also have a slope of 0.
958631
The slope is 1.\n\nThink about it this way.  All lines have the same formula:\n\ny = mx + b\n\nm = slope\nb = y intercept\n\nSince there is nothing in front of the x, the slope is 1 because \n1*x = x
775556
*Note that when the line is vertical the slope is undefined.\nVertical lines have the form x = c.\nTherefore, since this line passes through (2, -3), the x value is 2, and the equation for this line is simply x = 2.\n\nhttp://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut15_slope.htm\n\nhttp://math.about.com/library/weekly/aa120502a.htm
743965
If you can find the slope, you use the formula\n\ny - y1 = m(x-x1) where y and x are in general and y1 and x1 are the x and y values from ONE point. Pick either, it doesn't matter. So...\n\nThe slope is -2.\n\ny - 8 = -2 (x - - 2)\n\ny-8 = -2x - 4\n\ny = -2x + 4
706345
slope = -5-1 / -2-(-3) = -6/1 = -6\ny-1=-6(x+3)\n.
371794
slope = (-1-2)/(-1-0) = -3/-1 = 3
887097
y=1 is a straight line parallel to x axis\nx=(-1/4) is a straight line parallel to y axis