Simplify x^2+3x/x^2+3x+2 * x^2-4x+3/x^3-9x?
920830
i like chicken burgarz....and pizza too...\n\n\n....
92952
(8x+3)(4x+3)\n32x2+24x+24x+9\n32x2+48x+9
829339
x^2-6x+9 = (x-3)(x-3)\nx^2-9 = (x-3)(x+3)\n\nMultiple everything by (x-3)(x-3)(x+3)\n\n(x+3)(x+3) - (x+2)(x-3) - 5(x-3)(x+3)\n\nx^2+6x+9 - (x^2-x-6) - (5x^2-45)\n\nx^2+6x+9-x^2+x+6-5x^2+45\n\n-5x^2 + 7x + 60
110508
(x^2+5) / (x^3+15-2x^2+1)^2\non [0,1]
722836
I think you are asking to simplify the rational expression:\n[(x^3+27)/(9x+27)]/\n[(3x^2-9x+27)/(4x)]\n\nIf this is what you are asking, here's what you do.\n\nWe are dividing by a fraction, so we must flip the second fraction and multiply.  Our problem now becomes:\n[(x^3+27)/(9x+27)]*\n[(4x)/(3x^2-9x+27)]\n\nNow we must factor each expression individually.\n\nThe first expression--x^3+27--is a sum of two cubes and factors as:\n(x+3)(x^2-3x+9)\n\nThe second expression--9x+27--has 9 as a common factor and factors as:\n9(x+3)\n\nThe third expression--4x--cannot be factored, so we leave it alone.\n\nThe fourth expression--3x^2-9x+27--has 3 as a common factor and factors as:\n3(x^2-3x+9)\n\nUsing substitution, our expression:\n[(x^3+27)/(9x+27)]*\n[(4x)/(3x^2-9x+27)]\nbecomes:\n{[(x+3)(x^2-3x+9)]/[9(x+3)]}*\n{(4x)/[3(x^2-3x+9)]}\n\nMultiplying these expressions into one large expression, we get:\n[(x+3)*(x^2-3x+9)*(4x)]/\n[27*(x+3)*(x^2-3x+9)]\n\nCancelling the (x+3)'s and the (x^2-3x+9)'s that are common to the numerator and denominator leaves us with our final answer:\n\n(4x)/27\n\nGood luck.
52440
[x+1]/x^2+10x+5=2x/x^2+x-2\n9x+7=[x+1]/x^2\n9x^3+7x^2=x+1\n9x^3+7x^2-x=1
913334
x^2 + 2x + 7 Remainder 10\n\ni can add the steps if you don't think i did it by hand
599364
x^2 + x = x(x+1)\n\nIt can be simplified to x(x+1).
423594
(3x^3-7x^2+x-20)/(x-3) = 3x^2+2x+7 with a remainder of 1\n         \n         3x^2+2x+7 \n     _______________\nx-3 | 3x^3-7x^2+ x-20\n      -3x^3+9x^2\n    __________\n          2x^2+ x\n         -2x^2+6x\n         ________\n              7x - 20\n             -7x + 21\n             ________\n                   1\n\nI tried to show what this would look like as a division problem but it keeps jumbling up.
404885
1 - x + x^2/2 - x^3/6 + x^4/24
783870
7x^2+16x over (x-2)(x+2)(x+3)
699742
-(3x+y)(3x-y)\n-(9x^2-y^2)\ny^2-9x^2
924177
FOIL out the first part of the expression and simplify:\n\n(x+3)^2 = x^2+6x+9\n\nTherefore, (x+3)^2-6 = x^2+6x+9-6 = x^2+6x+3\n\nTherefore using the general form, ax^2+bx+c, you can conclude that,\n\na=1, b=6, c=3\n\n----------------\n\nHope this helps
790277
ill give it a shot - im not sure , anyways i got 2 answers..\n\n(1st)\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6x = 2-4x\n\nx+4x+6x = 2+1\n\n11x = 3\n\nx = 3/11\n\n\n(2nd possible answer)\n\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6/x = 2-4/x\n\n-5 = -2/x\n\n-5x = -2\n\nx = -2+5\n\nx = 3
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
198742
28x^6 - 14x^4 + 35x\n(7x)*(4x^5 - 2x^3 + 5)
817835
x^3-x^2+3x-1\nx+4&#92;x^4+3x^3-x^2+11x-4\n      -(x^4+4x^3)\n              -x^3-x^2\n            -(-x^3-4x^2)\n                       3x^2+11x\n                     -(3x^2+12x)\n                                   -x-4\n                                 -(-x-4)\n                                         0\nx^4+3x^3-x^2+11x-4=(x+4)(x^3-x^2+3x-1)