Algebra Problem that I cannot solve?
930527
Writer = x\nActuary = 3x\n3x + x = 4x\nBrother = 3x/2 = 4x - 40000\n3x/2 = 4x - 40000\n3x = 8x - 80000\n3x - 8x = -80000\n-5x = -80000\n5x = 80000\nx = 80000/5\nx = 16000\nActuary = 3x\n             = 3*16000\n             = $48000
873100
Here you go!\n\nhttp://www.math.com/homeworkhelp/Algebra.html
1075828
Try http://www.edhelper.com/number_puzzle.htm.  I don't know what your subject matter is, so this is the best I can do.  Toward the bottom of the page are puzzles on algebra, polynomials, systems of linear equations and inequalities.
1023759
There is a site where you can ask questions, see the answers of previously solved questions and see the lessons on specific topics about Mathematics; ALL FOR FREE. The site is http://www.algebra.com. There are presently about 359 unpaid-tutors in this site solving problems posted by students. I am also a tutor, giving free service, in that site with the same id "psbhowmick". Hope you have got your answer.
604013
there is no answer becuase it is impossible to divide by 0
1022192
i have  a book about algebra..... and some website...see if they could help u
362703
Free Video lessons!   \nForum/Help Center  Ask for help and help others \nand much more\nhttp://www.algebra.com/
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
961595
umm..are you missing an equals sign somewhere or am i really dumb? how do you figure out what x is unless you have both sides of the equation?
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
759105
False... y has to be 2...\n(3,2) is a solution, but not (3,1).
924033
Well, in order to solve it, you have to set it equal to something, because as of right now, it's just a random algebraic expression that means nothing.\n\nIf you set it equal to zero however...\n\n14c/15 + 7/17 = 0\n14c/15 = -7/17\n14c = -105/17\nc= -15/34
368125
if this is the problem:\n((x+3)/2)*((x^2-x)/(x+3))=21\nthen you solve by\ncancelling out (x+3)\n(1/2)*(x^2-x)=21\nmultiplying by 2\nx^2-x=42\nmaking it quadratic\nx^2-x-42=0\nand using x=(-b(+-)srt(b^2-4ac))/2a\nx=(1(+-)srt(1-4*1*(-42)))/2\nx=(1(+-)srt(169))/2\nx=(1+13)/2  or x=(1-13)/2\nx=7   or x= -6
611167
You can't factor that equation.
924405
Is it possible to have 2 equal signs in a problem?\nI am only in algebra but I haven't seen one like that before.\nSorry I couldn't help.
1039099
This is the answer i got when i worked out the problem\n1. You have to distribute the (x + 2) & (x + 1)....you do the by using the FOIL method....Firsts Outsides Insides Last and you get: x + 2 = x^2 + 3x + 2\n\n2. Get rid of the 2 on the left side by subtracting it on the right side and you end up with : x = x^2 + 3x\n\n3. Now you can move the x on the left to the right side too so you have: 0 = x^2 + 2x\n\n4. Pull out and x leaving you with 0= x (x+2)\n\n5. x = 0 and x = -2\n\nMy algebra is rusty but I think this is how it's done.
636051
x=4\n\nplease solve...\n\n8-(1) :-) ;-(