in c++, how to overload assignment operator in the derived class?
925250
BOOKS ???\n\nwrite a overload method for the assignment operator in the derived class.... if the same operator is overloaded in the base class then you must use virtual keyword in the base overloading method.
254178
With GCC compiler (used by Dev-++) you can write:\n\nsystem("cls");
256646
I'll put a bit of more information than the previous two answers.. or it'll seem like I'm answering for 2 points ;-)\n\nA for loop in C++ basically has the syntax:\n\nfor([initializations];[condition check];[updates])\n{\n  //statement1;\n  //statement2;\n}\n\nInitializations: Initialize counters, iterators.. any data to be set or reset before the loop starts executing. Multiple initialization statements can be provided in a comma-separated-list.\n\nCondition Check: While the condition is true, keep iterating through the loop. Dont make this a list.\n\nUpdates: Update iterators, indices, counters etc. which need to be updated with every iteration of the loop. Again this can be a comma-separated-list.
464936
Commutative operation.
344651
Hey, email me, LBphan@gmail.com, i might be able to help you out a bit, ive got some stuff for c++ and c# if youre curious, and ill give you whatever youre looking for free of charge.  my name is andy, by the way.
471250
Fairly straight forward. The code below is the skeletal C++ code (since I am not familiar with Java).\n\nclass Complex {\npublic:\nComplex () {a = 0; b = 0;}\nComplex (float x, float y) { a = x; b = y;}\nfloat real () {return a;}\nfloat imaginary () {return b;}\nvoid Add (Complex c, Complex d) { a = c.real() + d.real();\nb = c.imaginary() + d.imaginary();}\nvoid Subtract (Complex c, Complex d) {....}\nvoid Print() { cout << a << "+ i" << b; }\nprivate:\nfloat a;\nfloat b;\n};
930756
#include<iostream>\nusing namespace::std\n\nvoid main(){\ncout<<"Plz enter a number"<<endl;\nint x;\ncin>>x;\nif(x!=4)\n{\ncout<<"Well Done"<<endl;\n}\nelse {\ncout<<"The Number You Entered is 4"<<endl;\n}\n\n};\n\nI GUESS THIS IS WHAT YOU MEAN. YOU DONT NEED A BOOLEAN OPERATOR IN THIS CASE.
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class publication\n{\n   private :\n      char title[20];\n      float price;\n   public :\n      void getdata()\n      {\n          cin>>title;\n          cin>>price;\n      }\n};\nclass books :: public publication\n{\n   private :\n      int pagecount;\n   public :\n      void getdata()\n      {\n          cin>>pagecount;\n      }\n\n};\nclass tape :: public publication\n{\n   private :\n      int playing_time;\n   public :\n      void getdata()\n      {\n          cin>>playing_time;\n      }\n};
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When an iterative calculations with predefined conditions are to be done, the need of loop arises.\n\nThe following are the loop constructs...\n\n1. While Loop:\n\nSyntax: \n\nwhile( x < 100 ) {\n     if( x < 0 )\n       break;\n     cout << x << endl;\n     x++;\n   }   \n\n2. for loop\n\nSyntax: \n\nfor( initialization; test-condition; increment ) {\n  statement-list;\n  }\n\n   for( int i = 0; i < 10; i++ ) {\n     cout << "i is " << i << endl;\n   }\n   int j, k;\n   for( j = 0, k = 10;\n        j < k;\n        j++, k-- ) {\n     cout << "j is " << j << " and k is " << k << endl;\n   }\n   for( ; ; ) {\n     // loop forever!\n   }            \n\n3. do \n\nSyntax: \n  do {\n  statement-list;\n  } while( condition );
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class tree {\npublic:\n int countNodes(){\n    if (root == NULL) { return 0; }\n    return this.countNodes(root);\n }\nprivate:\n int countNodes(Node in){\n    if (in == NULL){ return 0; }\n    else { return countNodes(root->leftSubtree) + countNodes(root->rightSubtree) + 1; }\n }\nNode* root;\n};
423121
are you talking about c++? i have a nice header file that i can give you.. maybe thatll help
142433
you havn't closed "void determinecost (...)" function with curly braces " } "\n\nin c++, you have to close any block of code with } that has been opened with {
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The typical rule is that if your class has at least one virtual function, you should always declare your class destructor as virtual.\n\nClasses with virtual functions are usually designed to be used as base classes for other classes and because you can assign a pointer to a derived class to a base class pointer, a virtual destructor is needed to make sure that the derived classes destructor is called.\n\nSee the section (and code example) entitled "Why are destructors not virtual by default?" in Bjarne Stroustrup's (creator of the C++ language) C++ FAQ at the link below.
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It would help if you used some parentheses to indicate which terms are being divided into which terms!  I suspect that just using the order of precedence for operations will not result in the problem you are actually trying to solve.
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#include <iostream>\n#include <vector>\nusing namespace std;\n#define rep(i, n) for((i) = 0; (i) < (n); (i)++)\n#define rep2(i, k, n) for((i) = k; (i) < (n); (i)++)\nvoid f21();\nint n;\ndouble mat[100][100];\nint main()\n{\nwhile(true)\n{\ncin >> n;\nif(!n) break;\nmemset(mat, 0, sizeof(mat));\nf21();\n}\nreturn 0;\n}\n\nvoid f21()\n{\ncout << "****************************************" << endl;\ncout << "*          INVERSE OF MATRIX           *" << endl;\ncout << "****************************************" << endl;\n\ncout << "ORDER OF THE MATRIX: " << n << endl;\ncout << "ENTER ELEMENT ROW-WISE" << endl;\nint m = 2*n;\nint i, j, k;\nrep(i, n) {\nrep(j, n) {\ncin >> mat[i][j];\ncout <<"&#92;t";\nprintf("%5.3lf", mat[i][j]);\n}\nrep2(j, n, m) {\nif(i == (j-n)){\nmat[i][j] = 1;\ncontinue;\n}\nmat[i][j] = 0;\n}\ncout << endl;\n}\n\ncout << endl << "INVERSE MATRIX: " << endl;\ndouble pivot, comm;\nrep(i, n) {\npivot = mat[i][i];\nif(mat[i][i] == 0){\ncout << "DIVISION BY ZERO." <<endl;\nreturn;\n}\nrep(j, m) mat[i][j] = mat[i][j]/pivot;\nrep(j, n) {\nif(i == j) continue;\ncomm = mat[j][i];\nrep2(k, i, m) {\nmat[j][k] = mat[j][k] - (comm*mat[i][k]);\n}\n}\n}\n\nrep(i, n) {\nrep2(j, n, m) {\ncout <<"&#92;t";\nprintf("%6.4lf", mat[i][j]);\n}\ncout << endl;\n}\ncout << endl;\n}\n\n/*This is writen in C++ this will output the inverse of a Matrix\ninput:\n4\n1 2 3 4\n2 1 4 2\n2 5 7 12\n1 -1 3 11\n\n5\n1.173 -0.634 0 0 0\n-0.539 1.173 -0.634 0 0\n0 -0.539 1.173 -0.634 0\n0 0 -0.539 1.173 -0.634\n0 0 0 -0.539 1.173\n\n0\n*/
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There's a very explicit algorithm which explains\nhow to handle number, operators (including left\nor right precedence), functions, etc. on the \nWikipedia site for RPN (see reference #1).\n\nMostly, it's very straight-forward.  If it's an operand\n(ie. a number), then push it on the stack.  If it's an\noperator, then pop off as many operands are needed and\nevaluate.\n\nBut do look at the full algorithm for the details.\n\nOh yeah, for a full-blown implementation, see the source\ncode to the Unix "dc" (desk calculator) program.  The\nSolaris source is at reference #2.
1150710
Use a visual C++ compiler to compile the code . you will need to modify some of your code too..