In very simple terms, what's a general rule for determining which atom is the central one in a binary compound
915341
The largest atom in the compound is GENERALLY SPEAKING the more dominant (or central) atom in a binary molecular compound.
231898
There are a few isomers possible.\n\nEssentially there are two C's double-bonded, with either 2H's off one C and 2Br's off the other C.\nOr 1H and 1Br off each C
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A pure substance has a formula or symbol so we know exactly what atoms are in it in what proportion. \n\nIn a mixture there can be any material in any proportion.\n\nIn a solution, a type of mixture, there is one substance dissolved in another so that they are all mixed and anywhere we take a sample it will be the same.
80472
I'm trying to work with this info:\n\nOctet Rule - atoms want to have eight electrons in their valence shell (two for H) (most will form octets, some will not)\n\nMultiple Bonds\nSingle bond - a covalent bond in which a single pair of electrons is shared by two atoms\ndouble bond - two pairs of electrons are shared by two atoms\ntriple bond  - three pairs of electrons are shared by two atoms\n-generally form with C, N, O, S\n-------\nOkay, oxygen might attach easily to one of the Cls, leaving no spaces, but I'm not sure if there is a doule bond or something weird like that. Same with C.\nIf I remember correctly, CO2 looks like this:\nO=C=O\n------\nWait, check this out- I found the following (and no further info) somewhere on the net.\n\nE) COCl2\n      (C is the \n       central atom)\n\n----------\nWait. No.\n_______\nCl- C -Cl\n___O___\nI'm going to try that...\nI don't know. It lacks the symmetry that you normally see and it's kinda weird looking. What do you think of what I got?\n__________\nI found a pic: http://www.chem.ox.ac.uk/inorganicchemistry3/C/COCl2.html\nLooks kinda like yours.\n______\nHoly Mother of God - http://www.chem.ox.ac.uk/inorganicchemistry3/C/COCl2.html\nI found the name of the compound- phosgene- and did an image search. *exclamation of glee*\n___\nLol, better be right. Later.
872688
C2H3O2 = acetete, also called OAc\n\nMolecular:\nPb(OAc)2 + 2KI --> PbI2 (s) + 2KOAc\n\nIonic:\nPb(2+) + 2OAc(-) + 2K(+) + 2I(-) --> PbI2 (s) + 2K(+) + 2OAc(-)\n\nNet Ionic:\nPb(2+) + 2I(-) --> PbI2 (s)
819588
number of atoms (of each element) on one side equals the other side.
917127
Here's the how you do it.\n\nBalance the equation.  Element by element.\n\nThat gives you the mole ratios of  the various compounds.\n\nConvert the moles to mass using the molecular weight of each of the compounds.\n\nThat gives you the mass ratios of the various items.\n\nDivide both sides of the equation by the largest mass on the left side of the equation,    Then  you will have the mass of products per Kg of the at least one of the reactants.  Remember  you are starting with 1.0 kg of one item and 0.98 of the other.\n\nso you must check to see which reactant will limit the production.\n\nShould be a simple matter of working out the ratios.
360394
A more generic term for the components of an atom is "sub-atomic particles."  I think that's the answer you're looking for.
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mono = 1\ndi = 2\ntri = 3\ntetra = 4\npent = 5\nhex = 6\nhept = 7\noct = 8\nnon = 9\n\nnonmetals:\nif there is no prefix for the first element, it is assumes to be one.\nTHe ening of the anion (the second one listed) is changed to -ide.\n\ncarbon - 1 \noxygen - 2\nCO2  <---The number is a subscript, but you cant do that on here\n\nPhosphorous - 1\nIodine - 3\nPI3\n\nHydrogen - 2\nOxygen - 1  (it should be monoxide)\nH2O\n\nHope that helps you.  Don't feel bad; you can't know what you haven't learned.
930759
There is a basic equation to calculate the number of isomers for an organic compound with chiral centers.  This equation is 2^n where n is the number of chiral centers.  Chiral centers are located at any carbon that is bonded to four different groups like a hydrogen, a methyl group, a chlorine and an ethyl group,
54928
Lithium nitride\nGallium oxide\nRubidium chloride\nBarium sulfide\nFor binary ionic compounds, you just write the name of the first element, then take the second element and just change the ending to -ide.
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you would also use one of the following equations typically depending on the other information your given, but for sure, you need to look up its chemical composition. (ex: water is H2O)\n\nif youre given concentration:\nconcentration=moles/volume\nmoles=mass/molar mass\nmass=moles*molar mass\nmass=(concentration*volume)(molar mass)\nkeep in mind molar mass can be found by adding and multimplying as necessary the atomic masses of each element in the compound.\n\nif youre given density (which i bet you can easily look up on google or something if youre not given that information):\ndensity=mass/volume\nmass=density*volume
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2 KBrO3 + 3 N2H4 -> 2 KBr + 3 N2 + 6 H2O\n\nYou can check by finding out the total number of atoms of both sides:\n 2 Potassium\n 2 Bromine\n 6 Oxygen\n 6 Nitrogen\n12 Hydrogen
253611
Li+\nBe2+\nB3+\nN3-\nO2-\nF-
171003
in chemistry, u calculate coefficients based upon the subscripts of each element in the individual compounds which are involved in a chemical reaction
789565
a) 4 "things" attached to central atom and no lone pairs then: sp3-> tetrahedral e- arrangement, tetrahedral shape, 109.5°\nb) 4 "things" attached to central atom one lone pair then: sp3 -> tetrahedral e- arrangement, trigonal pyramidal shape, < 109.5° (about 107°)\nc) 3 "things" attached to central atom one lone pair then: sp2 -> trigonal planar e- arrangement, bent shape, < 120° (guess about 115°?). This is most challanging, try to figure out how many e- in total you have (18), then arrange them around the central atom using usual valances.
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Synthesis - a compound forms from simpler reactants