What happens during the TCP synchronization process?
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http://www.eurosmartz.com/help/manual/pro/index.html?chapter=Synchronization&section=n
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http://computer.howstuffworks.com/bytes.htm if u goto that. \nit will explain it all.
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go here http://www.lvllord.de/?lang=en&url=downloads&PHPSESSID=1a8caa8f75ad9de0476e3dbc0dbdca97#4226patch\n\ndownload this file an run it, it will update your tcp.sis file, to 50 half open connections like previous versions of windows. \n\nwhen you install it, it will askik if your are sure, press y to continue, after it has updated, a windows message will appera, asking if your wish to restore the file, if you say no, and restart your machine it will open your half open tcpip connections to 50
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the client connects to the server and gets all the info it needs...\n\nthe client is the users machine
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Yeah, it depends on internet traffic and the hop counts.  If  you want to goof around to see how a packet is routed from one destination to another open a command prompt (Start-->Run-->Type cmd-->click ok) type tracert <destination>, for example, do a tracert yahoo.com and see how many hop counts you get.  Have fun!
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Well, all Messneger applications do the following:\nthey use\n- TCP Protocol for authentication (LOGIN), etc\n- UDP Protocol for chatting\n\nThe difference between the 2 is that TCP guarantees the delivery of data while UDP doesn't, and thats why, in some cases, while text messaging or Voice chatting, some text &/or portions of voice conversation is omitted...\n\nHope this answers your question...
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http://www.rfc-editor.org/rfc/rfc3961.txt\n\n i dont really  know about it but what the hellthats everything i found
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It's software on a PC, or a handheld device that listens to the network traffic and displays the network traffic.  It usually knows about a large number of different protocols and can show the meaning of the different packets.\n\nFor example, the software listed below understands ethernet, TCP and http.  If you view a web page while the software is capturing, it will show the TCP SYN/ACK, the http get and the http response.
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You're probably thinking of TCP-IP and wikipedia has an interesting article on its history, and comparisons between the two. http://en.wikipedia.org/wiki/TCPIP  \n(It's far better than me boring you with explanations of models and standards)
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TCP-F: TCP Feedback [55] is a feedback based approach to handle route failures in MANETs. This approach\nallows the TCP sender to distinguish between losses due to routes failure and those due to network congestion.\nThis is done as follows. When routing agent of a node detects the disruption of a route, it explicitly sends a Route\nFailure Notification (RFN) packet to the source. On receiving the RFN, the source goes into a snooze state. TCP\nsender in snooze state will stop sending packets, and will freeze all its variables, such as timers and congestion\nwindow size. The TCP sender remains in this snooze state until it is notified of the restoration of the route through\nRoute Re-establishment Notification (RRN) packet. On receiving the RRN, the TCP sender will leave the snooze\nstate and will resume transmission based on the previous sender window and timeout values. To avoid blocking\nscenario in the snooze state, the TCP sender, on receiving RFN, triggers a route failure timer. When this timer\nexpires the congestion control algorithm is invoked normally.\n\n\nRoute reconstruction (RR) detection) RRN packet resumes TCP to normal state\n---------\nObject RRN \n(Transaction) The relative record number of the record involved in the conflict\n-----------\n1. TCP-F\nIn the mobile ad hoc networks, topology may change rapidly due to\nthe movement of mobile hosts (MH). The frequent topology changes\nresult in sudden packet losses and delays. TCP misinterprets such\nlosses as congestion and invokes congestion, leading to unnecessary\nretransmission and loss of throughput. To overcome this problem,\nTCP-F (TCP-Feedback) [20] was proposed so that the sender can distinguish\nbetween route failure and network congestion. In this scheme,\nthe sender is forced to stop transmission without reducing window size\nupon route failure. As soon as the connection is reestablished, fast retransmission\nis enabled.\nTCP-F relies on the network layer at an intermediate node to detect\nthe route failure due to the mobility of its downstream neighbor along\nthe route. A sender can be in an active state or a snooze state. In the\nactive state, transport layer is controlled by the normal TCP. As soon\nas an intermediate node detects a broken route, it explicitly sends a\nroute failure notification (RFN) packet to the sender and records this\nevent. Upon reception of the RFN, the sender goes into the snooze\nstate, in which the sender completely stops sending further packets,\nand freezes all of its timers and the values of state variables such as\nRTO and congestion window size. Meanwhile, all upstream intermediate\nnodes that receive the RFN invalidate the particular route to avoid\nfurther packet losses. The sender remains in the snooze state until it is\nnotified of the restoration of the route through a route reestablishment\nnotification (RRN) packet from an intermediate node. Then it resumes\nthe transmission from the frozen state. The state machine of TCP-F
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There is a program called Tcpview. Sometimes it will show the IP. But not always.
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you can use tcp optimizer ?\n\nhttp://www.speedguide.net/downloads.php
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First I want to say,\nAs far as I know you can do both Input and output operation within same socket. But I think this is not the problem.\nIn first loof I haven't found any problem but you can do some simple work to find out where it hangs.\nAfter every line put a \nSystem.out.println("line-X");\nwhere x is the line number. then you will be able to find in wich line of server and client it hangs around.\nThe most probable cause may be when it hangs, both server and client are waitin for input.\nGood Luck.
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I can't address the issue of the problems it causes in\na Service Oriented Architecture, but an RPC is a remote\nprocedure call.\n\nThe idea is that your program can make what *appears* to\nbe a typical function call, but what will happen "under\nthe covers" is:\n\n- the function arguments will be "marshalled" in some\nway in preparation for network transmission.  This may\nbe as simple as re-ordering the bytes of the arguments\nto account for machine "endianness" or it might involve\nserializing objects.\n- a server will be contacted on the remote machine which\nwill accept and unpack the arguments and then call the\nfunction on the remote machine to do the work.\n- whatever return value is generated will be packaged\nup and transmitted back to the calling machine, which\nwill unpack the value and allow the original "call" to\nretrieve the value.\n\nIt allows the source to make remote functions calls\nwhich appear to be local.
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just go to advance properties in TCP/IP add the IP there  then you no needs to change your IP where ever you are just conect I start using
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In TCP/IP network stack it uses TCP(Transmission Control Protocol) for Connection Orient service. Ex: HTTP (port 80)\n\nFor connection less UDP(User Datagram Protocol) is used.
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Why don't you do your own homework?  This is clearly a question that was written by a teacher.  Besides, you have already asked a TCP/IP question a few minutes ago.