MATH HELP please...not easy alg questions?
922959
____2x^2_+x_-15_____________\nx-2)  2x^3-3x^2-17x+30     \n       \n         2x^3-4x^2\n                  \n                 x^2-17x+30\n                 \n                 x^2 - 2x\n                        -15x + 30\n\nAbove tries to show the working\n\ndivides (2x^3-3x^2-17x+30) by (x-2)\n(same idea as ordinary division except the base is x , not 10)\n\nanswer is (2x^2+x-15) which = (x+3)(2x-5)\nworking:\nif 2x^2+x-15=0\nx = (-1 +/- sqrt(121))/4  "(-b+/-sqrt(b^2-4ac))/(2a) formula"\nx= -3 or x = 5/2\ntry it : (x+3)(2x-5) = 2x^2+x-15\n\nso the zeroes of (2x^3-3x^2-17x+30) =0 are\n2,-3,(5/2)\n\nthe zeroes of  (2x^2+x-15) = 0 are\n-3 and (5/2)\n\nif (2x^2+x-15) is graphed, it crosses \ny=0 (x axis) at x = -3 and x=(5/2)\n\nif the cubic is graphed, it has the \nzeroes 2,-3,(5/2)\n\nthe zeroes of\n(2x^3-3x^2-17x+30)/(x-2) are -3,(5/2)\nbut i think\n(2x^3-3x^2-17x+30)/(x-2) is \nundefined at x = 2
263286
the problem you presented above can be represented as,\n\n(8x^8/2x^2) + (16x^6/2x^2) - (12x^3/2x^2)\n\nthen you can simply divide each of the term\nyou'll get\n\n4x^6 + 8x^4 - 6x
756921
the answer is\n2Al + N2 ----> 2AlN
808003
Do you know your log identities?  That would help you here a lot!\n\nUse these log identities to solve your problems:\n\n. log(a) + log(b) = log(ab)\n. log(a) - log(b) = log(a/b)\n. c*log(a) = log(a^c)\n\nSo, for problem 1 (I'm assuming the "a" means that "a" is your base) we get the following:\n\nlog a(y+5)+2log a (x+1) =\nloga(y+5) + loga((x+1)²) =\nloga((y+5)(x+1)²)  \n\nProblem 2:\n\nIn(x+5)-In(3)=In(x-3)\nln((x+5)/3) = ln(x-3)\n(x+5) / 3 = x-3\nx + 5 = 3x - 9\n2x = 14\nx = 7\n\nProblem 3:\n\n3^x+5=9^x\n\nIs 3 raised to the power of x only, or to the power of x+5?  It's hard to tell, and it does matter to the solution.\n\n~ ♥ ~
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
531417
(a+b)(b^6-ab^5+a^2b^4-a^3b^3+a^4b^2-a^5b+a^6)\nGood Night, and Good Luck!
1039099
This is the answer i got when i worked out the problem\n1. You have to distribute the (x + 2) & (x + 1)....you do the by using the FOIL method....Firsts Outsides Insides Last and you get: x + 2 = x^2 + 3x + 2\n\n2. Get rid of the 2 on the left side by subtracting it on the right side and you end up with : x = x^2 + 3x\n\n3. Now you can move the x on the left to the right side too so you have: 0 = x^2 + 2x\n\n4. Pull out and x leaving you with 0= x (x+2)\n\n5. x = 0 and x = -2\n\nMy algebra is rusty but I think this is how it's done.
863644
take out 4x first\n4x(x2-6x+8)\n4x(x-4)(x-2)
437832
Homework.\n\nSuppose a1*x+a2*Tx+..+am*T^(m-1)x=0.\n\nApply T^(m-1) to get a1=0.\nApply T^(m-2) to get a2=0, etc.
778763
1) (a - b)(x - y)\n2) (x^9 + y^3)(x^9 - y^3)\n3) (6x + 5)(x + 8)\n4) (x - 9)(x - 7)
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
1132233
this question will require calcs using logarithm.\nhence will take time
858552
Have you tried these?  Surely you've been told that division by 0 isn't possible, so there's your answer for 7.  I'm not doing any others on Yahoo answers (too many at once), but if you really need help and are willing to do as much as possible for yourself I'll help you if you email h_chalker@yahoo.com.au, but nasty Maths teachers like me won't just hand you 7 answers on a plate!
966048
(3ab^2)(3ab)^2\n(3ab^2)(9a^2b^2)\n27a^3b^4
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
842934
Ok, first you must get the -8 and the x/-2 out of parentheses, so u just multiply them both by one. So then is -8 * x / -2. First, you do -8 * x, which is -8x. The problem then becomes -8x / 2. In this step, just don't mind the negative or the x and just put them back in at the end. So you're really just doing 8 / 2, which is 4. You must put the - and the x back in, so the answer is -4x. Ta Da!
314590
Since this is college algebra, it should be tough, but I'm having reading errors on the problem.\n\nCan't you just simply it down?\n\n8.5 = log (B/10^-16)\n\n10^8.5 = B/10^-16\n\nB = 10^-7.5