how many grams of sodium hydroxide are in 0.500 L of a 1.00N NaOH solution?
929350
Do you mean M instead of N?\nIf you mean M, then\n1,00M/L*0,500 L= 0,500M\n0,500 moles NaOH*(40g NaOH/1 mol NaOH)= 20,0g of NaOH\nIt is c).
913013
0.9% NaCl means 0.9 g NaCl in 100 mL SOLUTION, so you need 9 g NaCl for 1000 mL (1L)\n\nTake a volumetric cylinder, putsome water in it, dissolve the salt and add water to a final volume of 1L and mix. If you just add 9 g of NaCl in 1L of water the final volume of the solution will be different than 1L and thus your concentration will deviate from 0.9%.
434032
1N NaOH means a solution of 1 N concentration\n\nNormality = (disolved substance mass)/[(Equivalent-gram of substance)*(solution volume (liters))]\n\nWhere Equivalent-gram (Eg) is Atomic mass/valence
527028
This time i ans ur question but next time plz do ur homewrk ur self.\n\n1.\nWeight of NaOH = (4*.05) = .2 grams\nMoles of HCl =  Moles of NaOH = (.2/40) = .005\nVol. of HCl = .005*22.4 = .112 l = 112 ml\n\n2.\nWell let the grams be x\n1000x = 74.5*2.25*(75+x)\n(1000-167.25)x = 167.25*75\nx = 14.98 grams
608403
NaOH (aq) + HCl (aq) --> NaCl (aq) + H2O (l)
295875
for each one you are given a ratio i am assuming you are combining them both, make sure you write out a balanced equation for each one to make sure, some may not be a 1 to 1 ratio, next Molarity=mol/L therfore 1M = 1 mol per liter, use your periodic table to figure out the molecular weight for each one, each one of these is a strong acid, strong base reaction, therefore they will create water as a product and a salt, in the first one you are given 1.0 mol of HCl which is reacting w/ NaOH 1 to 1, therefore you only need to convert to # of moles of NaOH i am assuming you can do this hopefully this helps
475375
There are 1000 mg in 1 gram, so 500 grams is 500,000 mg. Therefore 500g > 5000 mg.
685497
Molarity = moles/volume, so volume = moles/molarity\n\n18.5 grams NaOH /40.0 g/mol = 0.4625 moles\n\nVolume = 0.4625/0.750 = 0.6167 L = 616.7 ml
745017
Your question isn't really complete - the NaOH needs someting to react with.\n\nFor example:\n\nNaOH is used with lipids to make soap.\n\nNaOH + HCl -> H2O + NaCl
272450
The density must be 1.09 g/mL, not g/mol\nM = mol solute/ L sol'n\n\n8.50% sol'n NaC2H3O2 = 8.50 g NaC2H3O2/100 g sol'n\n\nTherefore, \nM = (8.50 g NaC2H3O2)/(100g sol'n) x (1 mol/82.0 g)\nx (1.09 g/1 mL) x (1000 mL/1 L)\nM = 1.1298780 M = 1.13 M ^_^
164045
What do you want a step by step set of instructions or a balanced equation?\n\n2C6H5OH + NaOCL = 2C6H50 + NaCl + H2O
927975
15%(m/v) means 15grams of NaOH in 100ml of solution.\nHence 120*100/15= 800ml will contain 120 g of NaOH
558772
the correct answer is 1.30.  the answer would be two if the concentration was 0.01M.  you just take the negative log of the concentration of hydronium ion.
897932
1.60L contains 0.230mol*1.60mol/L ions of sodium sulphate\n2moles of Na+ exist per mol sodium sulphate, then:\n0.23*1.6*2= 0.736 moles of Na+.
907209
Na2CO3 + NaHCO3  \n\nmoles Na2CO3 = 0.070L * 5.5 mol/L = 0.385 mol\nmoles of Na+ from Na2CO3 = 0.77 mol\nmoles NaHCO3 = 0.030L * 1.0 mol/L = 0.030 mol\nmoles of Na+ from NaHCO3 = 0.03 mol\ntotal moles of Na+ in the solution = 0.80 mol\nsodium ion (Na+) concentration = 0.80 mol/0.1L = 8.0M
912770
Conversion Factors\n1L=.001 cubic meters, 1 cubic meter =10 dm cube so\nConverting to Liters of solution\n4dm=.4 cubic meters=400L\nUsing ratio to find mols/Liter (which is M)\n2M=2mol/1L=x/400L\n\nx=800mol of iodomethanel in 4dm cube of 2M aqueos solution\n\nnext question\n500cm=5meters cubed=5000L\n1M=1mol/1L=5000mol/5000L\n5000mols of Sodium Hydroxide\n\nThe next question is not a complete question, I'm not getting it.
741771
0.5M = 500mM\nv x c=v'xc'\nv x 500 = 50 x 1\n0.1mL of the 0.5M solution diluted to 50mL will be 1mM