find the slope of a line that is perpendicular to this line y=5x+10?
930285
Given a line with slope m, a perpendicular line has slope -1/m, so the slope of the perpendicular line in this case is -1/5.
496285
slope m = (2-5)/(5--2) = -3/7\n5=-3/7*2+b\n5+6/7 = b = 35/7+6/7=41/7\n\ny =-3/7x+41/7
961745
the slope of the line perpendicular to that line would be the inverse negative of the slope of x-3y = 8\n\n(x-8)/3 = y\n\nthe slope = x/3, so the perpendicular line has a slope of -3x\n\ny = mx + b\n\nm = -3\n\nx = 5\n\ny = -4\n\n-4 = -15 + b\n\nb = 11 \n\ny = -3x + 11
1101023
First you must find the slope of the line with the points (6,3) and (7,7).  Slope equals Y1-Y2 / X1-X2.  So that equation with the numbers substituted is Slope equals 3-7 Divided by 6-7 or -4/-1 or 4.  That is a slope of four.  \n\nA perpendicular line's slope is the opposite reciprocal or -1/4.
196300
wow i got confused by the answers. i will try to explain it simply in case anyone else got confused too. the equation   -7x-4y = 25 is an equation of a line. if you rearrange it to the y=mx+b form u get y = -7x/4 - 25/4 so the slope (m) of this line is -7/4. to get a line thatz perpendicular, u have to get the negative reciprocal. which is basically flipping the denominator and numerator and changing the sign. so the slope is 4/7. so now you use (x,y) = (2,-8) and m=4/7. and you solve for b in the y=mx+b equation. and once u get b, you have your equation for a line y = 4/7x + b.
96323
2 lines are parallel if their slopes are equal. 2 lines are perpendicular if the product of their slopes is -1 (or if the slope of one line is the negative reciprocal of the other)\nFrom your given, the slope of the first equation is 3/5\nusing y = mx + b (m is the slope)\nThe slope of the second equation is -5/3. Notice that their product is -1, so the lines are perpendicular.
941588
Identify the slope of each line and compare the values.\nIf the slopes are the same then they are parallel.\nIf the slopes give a value of -1 when multiplied together, then they are perpendicular.\nIf the slopes differ from that about, then they are neither.\n\nBring the y value to a unit value of one.\n(1) Slope 6∙4 and 6∙4, so it's parallel.\n(2) Slope ½ and ? , second equation is unclear.\nThe slopes are probably 3/2 and -3/2, if so, then they are perpendicular.\n(3) Slope -1/3 and 1/3, so the lines are perpendicular.
766938
Use the forumula     delta Y/ deltaX to find the slope of the given points\n\n4-2/ 0-4   = -2/4 =  -1/2\n\n\nSince the perpendicular line is the equation  y = -1/2x; the other equation has the slope of the negative reciprocal of -1/2x so the equation would be \n\ny= 2x+b\n\nthen plugin x and y in this equation and you get\n\nb= -4\n\nso the final equation would be y=2x-4\n\n   Thats it
910261
Slope = m\n= y2-y1&#92;x2-x1 \n= -4-6/-3-2\n = -10&#92;-5\n=2\n\nnote: / means divided by\n\nthe slope of y= 2&#92;3x-4 is 2&#92;3
626863
To find slope you start by choosing two points Ex: (1,2) and (5,6). You us the equation m(slope)=(y2-y1)/(x2-x1) Ex:(6-2)/(5-1)=4/4=1 The slope is one. To find the x-intercept you plug in Y=0 (zero) into the equation, and to find the y-intercept you plug in X=0 into the equation.
1142461
1. x-y=5; y= x - 5\nAdd y to each side x - y + y = 5 + y, becomes x = 5 + y. Subtract 5 from each side, x - 5 = 5 - 5 + y, becomes x - 5 = y\n\nSolve the rest on your own
751258
y' = 2x + 4\ny'(1) = 6 this is the slope.\ntangent: yt = 6x + b\n\ny(1) = 1 + 4 + 10 = 15\nyt(1) = y(1) = 15 = 6 + b ===> b = 9\n\nyt = 6x + 9
532403
The slope of y = (1/3)x - 5 is m = 1/3\nA line that is perpendicular to the above line will have slope m = -3.\nIf two lines are perpendicular, then the product of their slopes is -1.  For this case, we have (1/3)(-3) = -1, so -3 must be the slope.\nSince you're not given a point, any equation of the form \ny = -3x+b will work.\nJust pick whatever value of b that you want.\nSome examples, \ny = -3x\ny = -3x + 5\ny = -3x - 7
276594
Perpendicular lines have slopes with a product of -1. Your line (y=3x-5) has a slope of 3, so any line with a slope of -1/3 would be perpendicular to it. \n\nThus, any line with a slope *not equal to* -1/3 would not be perpendicular to it.
450157
slope = (y2-y1)/(x2-x1)\n5= (k-4)/(2-3)\n5= (k-4)/(-1)\nk-4= (-1)*5\nk-4= -5\nk= 4-5\nso k= -1.\ni hope you understand they way I worked it out. If you have any more questions, pls feel free to ask me on: pinkieflava@yahoo.co.uk
754086
the slope will be (0 + 9) / (-8 +7) = 9/-1 = -9 --> m = -9\n\nnow take a point and plug it in to the formula y = mx + b.\n0 = -9(-8) + b ---> b = -72\n\nnow your done. y = -9x - 72
1023988
1) Find the line that is perpendicular to the line 3x -4y = 18 and passes through the point (3,4)\n2) Find the point where the two lines intersect.\n3) Find the distance between that point and the point (3,4).