S=vt-16(t*t) what does v equal?
930595
v stands for velocity, or how fast something is speeding up.\n\nfor example, if something is thrown at a velocity of 5ft/sec squared, its speed increases by 5 feet/sec every second it travels
855540
The circuit has a time constant which is calculated as\nT=L/R\n\nThe circuit will have the equation\nfor current of:\n\ni(t)=(Vs/R)*e^(-t/T)\nWhere\nVs is the supply voltage\ne is Euler's constant\n\nj
841789
Assume s=275, v=43, r=0.21 & t is time from start to stop; then v=a*t & s=a*t^2/2, ‘a’ being deceleration. Therefore t=v/a, s=a*(v/a)^2/2; thus 2*s*a=v^2 or a=v^2/(2*s).\nAngular deceleration w’=a/r.\nNow I=0.175, so frictional torque T=I*w’. plug numbers in.
907686
M1V1 = M2V2\n\nso you are starting out with a .1M times V1 is going to be equal to .08M times how ever much you need.  so you need ratios 5:1, 5:2,  5:3, and 5:4.
338257
a) vcenter = (m1*v1+m2+m2)/(m1+m2)\n\nb) v1 rel = v1 - v center\nv2 rel = v2 - v center\n\nremember velocity is a vector so you must keep track of magnitude and direction
924429
The ball\nVt= Vo + at\nVo= 0 hence Vt= at\nF = m * a = 0.350 * a\na= F/0.350\n28 = F/0.350 * t\nF= 28 * 0.350 /t  = 9.8 /t\n\nThe man\nt man = t ball\nF man = F ball ( Newton's law)\nF = 9.8/t\nF = m * a = 65 * a\n9.8/t = 65 * a\na = 9.8/(65*t)\nV=a*t\nV= 9.8/(65*t) * t = 9.8/65 = 0.151 m/sec
207263
63V/sin22 = xV/sin90\n\n63Vsin90/sin22 = xV\n\nx = 168.2 V =)
449048
P1 x V1 / T1 = P2 x V2 / T2\n\nYou have all you need.  Calculate it.
43919
Always remember PV=nRT.  In your case, P=(nRT)/V.
536856
as you know that\na1v1=a2v2 \nso \npi r1 square v1= pi r2 square v2\nv2= 1600 ft/sec\n\ni hope it helps
931347
x =70m, t = 7s, Vf = 15m/s\na.)\nx = 1/2(Vi + Vf)t\nVi = initial velocity\nVf = final velocity\n\n70m = 1/2(Vi + 15m/s)(7s)\n10m/s = 1/2Vi + 7.5m/s\n2.5m/s = 1/2Vi\nVi = 5m/s\nb.)\nVf = Vo + at\n15m/s = 5m/s + 7s(a)\n10m/s = 7s(a)\na = 1.43m/s/s\nbasic kinematics\nyou can't use distance = rate x time because there is acceleration and the speed is not constant.
713107
range/amount\n\nrange = 120 mV (90mv - (-30mV))\namount = 2^16 = 64*1024\n\nplug-n-chug
756080
a=(delta V)/(delta t)\n\ndelta V = V_final - V_initial = 0 - 3.2\ndelta t = 0.01 sec\n\na=3.2/0.01=320 m/s2\n\nforce=mxa=0.084x320=26.88 N
852750
T=I*w’, T=16 torque, w’= angular acceleration, I=1.2/1000; In time t (SECONDS) its angular speed w=w’*t;\nOr w’=w/t or w’=T/I; thus w/t=T/I or I*w=T*t is angular momentum, & w=T*t/I
378804
Vf=Vi+At\n5=12+A*2.3\nA= -3.04348 m/s^2
756774
P=P (momentum before = momentum after)\nmv=mv\n(55kg)(4.6m/s) = (230kg)v\nv= ((55kg)(4.6m/s))230kg\nv=1.1m/s
879746
Ek = 1/2.m.v2   (1/2 mass times velocity squared) - \n\nsorry can't do superscript on this site