xMATH HELPx?! = ]~[ =?
913544
In school they used to teach us to read the words...\n\nIf the words said "minus a minus"\n. . . that meant plus\n\nSo your example 9X- (-2x)\n\nis 9X minus a minus 2x\n\nWhich means\n\n9X plus 2X\n\nWhich is 11X\n\nGood luck,\nZah
587091
Xn = (Xn-1 + Xn-2)/2\nThen X2 = (X1 + X0)/2 = (a+b)/2.\nX3 = (X2 + X1)/2 = [(a+b)/2 + b]/2 = (a+3b)/4\nX4 = (X3 + X2)/2 = [(a+3b)/4 + (a+b)/2]/2 = (3a+5b)/8
1146893
x^2+mx+1/x^2+x+1<3\n\ncase 1 : for x>0\n=> (x+1/x)^2 +(m+1)x <4\n=> (m+1)x < 4- (x+1/x)^2\n\nNow, we find the maximum value of the RHS:\nthe minimum value of (x+1/x)^2 is 2 when x=1 and for all other values of x it is >2 \nThis makes max(RHS)=0 or m+1 <0 \nor m<-1\n\ncase 2: x<0\nthe same argument as above(but x=-1)  leads us to m+1 >0 \nor m>-1\n\ncase 3: x=0\nThe given expression is undefined \n\nI guess its a home work problem, which indeed makes you lazy!
771358
3x + 4 < x + 8\n2x < 4\nx < 2\n\n{x | x < 2}
733649
(4)/(x+7) + (x+3)/(x+7)\n=(4 + (x+3))/(x+7)\n=(4 + x + 3)/(x+7)\n=( x +7)/(x+7)\n=1
942085
u can do alt + 3 = ♥\nor <3\n\nxox <3 <3 ♥♥♥♥ <3 <3
1099552
x' € S - {x}\nworks fine...\n( replace the € by the usual "is an element of" symbol )
554172
Um...\n\n2(-X) + 3(-X) + X + 8\n\n-2X - 3X + X + 8\n\n-5X + X + 8\n\n-4X + 8\n\n8 - 4X
560506
that works... so does this:\n\n-2 x -1 x 1 x 2 x 3 = 12\n\n-2*-1=2\n2*1=2\n2*2=4\n4*3=12
978426
for example:\n\n-1 < 2\nthen\n1 > -2\n\nanother:\n x < -5\nthen\n-x > 5\n\n-2 x > 9\nx< -9/2\n\ns
101183
-1<(or equal to)X <(or equal to)6
825795
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
936579
your question seems to be incomplete.\nso far....\nwidth=x\nlength= 2x-1
1110742
12 simply place the 1 where the x is\n\n(1+3)(1+2)\n4*3\n12
926616
2x+3<6x-1\n2x-6x<-1-3 \n-4x<-4\nx>1
872873
There is only one value that works: \nx=1\n\nj
196269
i took this question to mean as:\n\n[11/ (4-x)] + [2x/ (16-x^2)]\n\nso, what you do first is to multiply addends by (-1/-1), which is still equal to one, and won't make a difference, except to change the signs.\n\nso it would look like\n\n[-11/ (x-4)] + [-2x/ (x^2 - 16 )]\n\nsimplify to:\n\n[-11 / (x-4) ] + [ -2x / (x+4) (x-4) ]\n\ncombine the elements:\n\n[(x+4) + (-2x)]/ [(x+4) (x-4)]\n\nto make \n\n[(x+4-2x)]/ [(x+4) (x-4)]\n[(-x+4)]/ [(x+4) (x-4)]\n[-(x-4)]/ [(x+4) (x-4)]\n\nand the simplest would be:\n\n-1 / (x+4)\n\n hope this helps. :D