If there was a white hole emitting a very strong intense light would it suck in an incomming ray or repel it?
921042
If it has a strong gravitational field, light will bend towards it. No sucking involved.
961817
Above answer is quite to the point.. i would just like to add that, if u consider a light ray entering a open window there is very less chance that it will escape out again. in short it can be assumed to be absorbed.  \n\nIn the black body radiation, we need a perfect radiator n perfect absorber.
988641
Awesome question.  I have no idea.  The first thing you would have to know is what the properites of glass are that could, if at all, slow the speed of light.  As well as at what thickness of glass, which, in a backwards loop hole sortof way, directly relates to my last sentance.  (if a piece of glass were doubly thick as a single piece of glass, would it cut the speed of light in half?--depends on how thick the original piece was and if the original piece did anything to slow light's speed at all--see where i'm goin?).  Please tell me what you find, I'm very curious, I love questions that make me think deep.  Peace out dude, rioedgebravo@yahoo.com
585565
Spectroscopy (splitting the light into its constituent colors) and photometry (counting up how much light there is).  We can measure how far away they are via redshift, and from that and brightness measurements calculate their absolute luminosity (how much energy it puts out per second). The size of the emitting area can have an upper limit placed on it by watching how fast it varies in brightness.  (Approximately the speed of light over the brightness change timescale).  \n\nSo, you are emitting "x" amount of energy in a volume of "y" size.  The number of stars necessary to produce that sort of energy collectively would have a mass large enough that this superdense cluster would be inside of its own Schwarzschild radius (ie be a black hole).  \n\nSo you need some more efficient way to produce energy than fusion in stars.  The only astrophysical phenomenon known to do that is the rapid loss of a large fraction of  gravitational potential of mass (drop something onto something dense enough that it would reach an appreciable fraction of the speed of light. As it interacts with other matter on the way in, it heats up and glows.)  This requires either black hole or neutron star type gravity.\n\nI suppose you could hypothesize a dense cluster of a zillion neutron stars all accreting matter, but that is pretty contrived compared to a single large blackhole.  You can probably show that their accretion disks would result in enough drag as they zipped around one another (and consequently through one another's accretion disks) in this small volume that they would all be coalescing and collapsing into blackholes in a pretty short timescale anyway.\n\nIn short, nothing so small and so bright could be anything BUT an accreting supermassive blackhole.
824779
No surface can be 100% reflective. If you shot, say a laser at the most reflective surface possible, the reflected light would be less than the original beam.\nThere is no material that can allow light in and no light out. If you did create the sphere, you would need a little hole to aim a light source at, then you would have to close it quickly with the light source still shinning at the hole. Theoretically, with a 100% reflective surface and a vacuum inside the sphere, it would bounce around forever, until you broke it. A small flash would be seen, but the light energy would not compound and blow up.
418005
First a black hole is a point of infinite density where gravity is so strong that even light cannot escape. A white hole is a hypothetical point of negative gravitational energy that emits matter from it. By negative gravitational energy i mean this: A planet has positive gravitational energy because it pulls matter towards its center of mass and experiences normal everyday gravity, but a white hole, which has negative gravitational energy is the exact opposite, it repels matter and nothing, not even light can reach the surface of a white hole. A wormhole is a hypothetical shortcut in the fabric of space and time. Think of it like a blanket that you are trying to get across, the simplest way to cross it is to just follow its surface in a straight line. A worm hole on the other hane is like folding the blanket in half and cutting a hole in it and going through that hole which is a much much shorter and quicker way of moving long distances.
655580
no, it is infared light, which is lower energy than regular light. plus it is a very weak, un focused siganl that only transmits for an instant.
704068
Say you shine a flashlight into a mirror. Then put a mirror behind the flashlight and remove the flashlight. Given that the 2 mirrors are exactly parallel, will the light just bounce back and forth forever? No - the light travels in waves and each time it reflects back, some of the light is not hitting the mirror exactly at 90 degrees and is reflected off on an angle. The light will reflect away and eventually dissipate completely. \nIf you try to trap light in a box, as it bounces off the walls inside, it will dissipate into energy (heat). The temperature of the inside of the box will raise - but just infintestimly so.\nRemember all of this will take place at the speed of light.
648382
In the vacuum light can get the high speed.\nAfter that you have gas, liquid an then solid.\nThis is because the density of matter. The more dense the matter is the more athoms there are, making it harder for the light to pass.
490235
Assuming you are standing still relative to the airplane, and the airplane is going at the exact speed of light... yes you would see it, but only as it colides into you.  if you are asking if you would see if before it hits you, then no.  Due to it's speed, all of the light coming off of it would not be able to outrun the plane.
1126630
Theoretically, it'd be trapped inside the sphere forever. In practice, mirrors are not perfect. The material the light bounce off would absorb energy, allow light to "leak" through, etc etc.\n\n\nsomething related.. maybe...\nThis remind me of one thought experiment to determine the position and energy of an electron simultaneously by putting the electron in a box and making the box smaller and smaller. Heisenberg's uncertainty principle said u cannot determine both the momentum and position of the electron infinitely accurately at the same time. The idea is to make the box so small eventually the electron would be confined to a fixed position with 0 velocity and known position. But however, by making the box smaller and smaller, the wall of the box push against the electron, giving it more and more energy and when u thought u have zoom in on its position, the electron would have so much energy it'd simply burst out of the box.
192375
I would suggest trying methods where you do have a hole to confirm results.  For example, light is reflected (and refracted?) at every surface and thickness of a transparent media where there is a change in density or crystal structure.  You may be able to shine a light (at night or under a blanket?) to detect the bottom of the ice and compensate for refraction where the actual thickness may differ from apparent thickness.  Use a ladder to spread your weight if the strength of the ice may be marginal.  Would a laser pointer work better than a flashlight?  Good luck.
464698
stick a black ball in a middle of a usless disc. color the disc yellow because the black hole is very bright!
476594
Would that be refraction?
416072
It depends on the wavelength of the light and its energy.
129373
A small hole can act as a sort of lens, focussing the light rays.  There was something called the camera obscura that used this principle.  It was a dark room with a light colored wall.  On the opposite wall, usually an outside wall, a small hole was placed in the wall.  The sunlight from outside reflected off the objects outside and were focussed on the light colored wall to form an image of what was outside.
1164989
The energy from the light is absorbed into the walls, etc.  If you could create a room that had everything in it 100% reflective, then the light would continue to exist.  But, you wouldn't know this, because you are not 100% reflective, and you would absorb the light.