what is the answer to this equation: 2(x-3)squared=8?
927818
2(x - 3) = 2\n\n2(x - 3) / 2 = 8 / 2\n\n(x - 3)² = 4\n\n√(x - 3)² = √4\n\nx - 3 = ± 2\n\nx - 3 + 3 = 3 ± 2\n\nx = 3 ± 2\n\n- - - - - - - - - \n\nSolving for ( + ) \n\nx = 3 + 2 \n\nX = 5\n\n- - - - - - - - - \n\nSolving for ( - )\n\nx = 3 - 2 \n\nx = 1\n\n- - - - - - - - -s-
602540
x + 3 >  8 ==> x >  8 - 3  ==> x > 5\nx - 4 < -2 ==> x < -2 + 4 ==> x < 2\n\nAnswer... not possible.
574841
-2(x+10)=3(2x-4)\n-2x-20 = 6x-12\n-2x = 6x+8\n-8x = 8\nx = -1
79707
16 - 3(8-3)squared / 2\n\n1. 16-3x(8-3)²÷2\n2. 16-3x(5)²÷2\n3. 16-3x25÷2\n4. 16-37.5\n5. -21.5
220918
2*x^2 - 3*x - 2 = 0 <=> x = -1/2 V x = 2 \n\n==> 2*x^2 - 3*x - 2 <=0 <=> x = [-1/2 , 2]
744241
3/(x + 6) - 1/(x - 2) = -8/(x^2 + 4x -12)\n\nStep 1: Create a common denominator for the left side. This is convenient, because (x + 6) * (x - 2)  = (x^2 + 4x - 12)\n3/(x + 6) * (x - 2) / (x - 2) - 1/(x - 2) * (x + 6) / (x + 6)\n3 (x - 2) / ((x + 6) * (x - 2)) - 1 (x + 6) / ((x + 6) * (x - 2))\n\nFinally:\n(3 (x - 2) - 1 (x + 6)) / (x^2 + 4x -12) = -8/(x^2 + 4x -12)\n\nStep 2: Cancel the x^2 + 4x -12 denominator on both sides, then solve.\n(3 (x - 2) - 1 (x + 6)) / (x^2 + 4x -12) = -8/(x^2 + 4x -12)\n3 (x - 2) - 1 (x + 6) = -8\n3x - 6 - x - 6 + 8 = 0\n2x - 4 = 0\n2x = 4\nx = 2 (solution!)
123892
3(x – 2)^2 – 3(x – 2) – 6\n3((x-2)^2 - (x-2) -2)\n3(x^2-4x+4-x+2-2)\n3(x^2-5x+4)\n\n3(x-4)(x-1)\n\nYay!!
553161
(1+3)*2 = 8\n(3+8)*3 = 33\n(8+33)*4 = 164
959117
1. When you square root both sides you get x - 3 = +4 or - 4\nNow add 3 to bot sides and get x = 7 or -1\n\n3 and 4 are similar.  (x-3)^2 means (x-3)(x-3) which is x^2 - 6x + 9\n\nSo x^2 - 6x + 9 = 16\n\nSubtract 16 from both sides to get x^2 - 6x - 7 = 0\n\nTo use the zero product rule, factor by FOIL:(x-7)(x+1)=0\n\nAnd to use quadratic formula, you can see\n that a= 1, b= -6, and c= -7
982146
Just add and substract terms in both sides.\n\nSince \ny-x^2+8x\nis equal to 7, \nyou can add x^2 and substract 8x to both sides.\n(y-x^2+8x) +x^2-8x = y\n7 +x^2-8x = x^2-8x+7\n\nso y=x^2-8x+7\n\nby the way, if you factorize in terms of x then you'd get\ny=(x-1)(x-7)
852311
3(x+4)^2 -6=8\n3(x+4)^2  = 14\n(x+4)^2 = 14/3\n \nx+ 4 = +- sqrt (14/3)\nx= -4 + sqrt(14/3) or x= -4 - sqrt(14/3) !
588927
easy.. -1 , -2 , 1,2,3.\n\n-1 x -2 =2\n2x2x3 = 12
1019688
(x - 2)*3 = 6 + x\n\n3x - 6 = 6 + x\n\n2x = 12\n\nx = 6
243121
first square two sides\nyou will get 3x+1 =9+6√(x-4)+x-4\n= (x-2)=6√(x-4)  square it \nyou will get x^2 -4x +4=9(x-4)\n=x^2 -13x + 40=0\nfactor  (x-5)(x-8)\nso x=5 or x=8
929178
4(-2)² + 8(-2) + 3(-2) + 6\n= 4(4) - 16 - 6 + 6\n= 16 - 16 + 6 - 6 = 0
140487
3(x-2)^2 - 3(x-2) - 6\n\n= 3[(x-2)^2 - (x-2) - 2]\n\n= 3[(x-2){(x-2) - 1} - 2]\n\n= 3[(x-2)(x-3) - 2]\n\n= 3[x^2 - 5x + 6 - 2]\n\n= 3[x^2 - 5x + 4]\n\n= 3(You should solve the next step as this is ur home work and dont make this a habit.)
120172
y-2 = -2(x-3)\ny-2 = -2x + 6 \ny+ 2x = 6+2 \ny+2x  = 8  ( linear equation)\n\nFINDING SOLUTIONS FOR THIS LINEAR EQUATION :\n\ny+2x = 8\n(a)  Assume, x=2 \n     subtitute the assumed value of x in the equation\n     y+ 2 (2) = 8\n     y+4 = 8\n     y = 8-4\n     y = 4\n     HENCE,  when -->   x= 2 then y= 4\n\n   Similarly you can find more solutions for any\n   given linear equation by assuming the value of any one unknown ( x or y ) and then finding the value of the other by substitution in the same given equation.