what is the interval of the scale in the graph?
922643
It depends on the graph. If the values of each notch differ by x, then the interval is x.\n\nJust look at two numbers on adjacent notches, and subtract.
1153957
The website below seems to be what you're looking for.  The spreadsheet you can download uses the NORMDIST function to do the graph.  Check out the help feature for the function to see its equation.\n\nI assume you know how to calculate the mean and standard deviation for your data.  The AVERAGE and STDEV Excel functions are good for this.
778580
Go to this link:\n\nhttp://www.coolmath.com/graphit/index.html\n\nYou can enter your equation and graph it.
100190
plot these coordinates:\n(0,0),(22.5,-1),(45,0),(67.5,1),(360,0), etc., etc.\n\nconnect them together in a curve and you'll have it.\n\nsine graphs are a series of curved lines. they start at zero, go up to one, go down to zero, go down to -1, and go up to 0 again.\n\nthe negative in front of the sine means that the graph is reflected along the x-axis. so that the 0, 1, 0, -1, 0 sequence is switched to 0, -1, 0, 1, 0.\n\nthe 4 in front of the x means that the normal period for the graph to make a complete curve is divided by for. so instead of the graph following the sequence every 90 degrees, it is done every 22.5 degrees.
921732
If you look at a picture (aka a graph) of the function, it will all become clear...\n\nhttp://upload.wikimedia.org/wikipedia/en/3/3e/1-over-x.png
923293
1. If you pass a vertical line down the graph, and it only passes through the function once, then ya, it is function.  If it passes through more than once, then it is not a function.\n\n2. Isolate x
978117
The graph of f(x) is a line, which means it can't have an asymptote.\n\ng(x) = log5(2x) should have a vertical asymptote x = 0.
1132263
Some relationships in mathematics and in real world are more complex and cannot be easily represented by a line graph (for example, the growth of bacteria is exponential, therefore you need a parabola to represent that relationship. A line graph just wouldn't do in this case).
1059314
because "h" moves the graph left and right and "k" moves it up and down. so you take the origanal graph "y=x^2" then move it -h L or R and k up or down.
332981
Depends:\n\nYou can have as many as needed.  As an example I can have a horizontal axis with time variable in increments of years, a variable T.\nThen I can have 1 or 43 or whatever number of bar graphs coming out of each year as x1, x2, x3, etc. to represent maybe toy sales of x1=# cars, x2=# dolls, x3=# balloons, etc. as different colored bars.\n\nAs for a line graph if it is a single line like the number line it usually will have only one variable represented.
463925
I am not sure that I follow what you are asking. Are you looking for the above items to be charted as variables on your graph?\n\nPerhaps if you post additional details in your question, it would help us.
831435
The graph of sin x goes up to 1 when x = pi/2. When you graph y = sin (2x), it shrinks the x-values by half - so it will be 1 when x = pi/4.
612991
the y axis depend on the x axis so if u were doing a graph the x axis would be at the bottom
857286
Im not sure don't right this at your Homework.........\nwhere f(x) > 0. a. (–3, 1) b . (–3, 0) ∪ (1, ∞) c . (1, 3) d . (0, 1) ∪ (3, ∞) If f(x) = x(x – 1)(x – 4)2, use interval ..............??????\n\n\nSORRY I DON'T HELP TOO MUCH I TRY MY BEST......
763094
Here's a tip... why use a linear scale?  If the purpose of your plot is that you want to actually LOOK at the data, try using a log plot.\n\nInstead of:  plot(f,<quantity>);\nUse:  semilogx(f,<quantity>);\n\nIf you want better percision readout just do 'format long'.
614293
Hertzsprung-Russell  Diagram.  See the wikipedia article for more info.
1015745
here goes again .. seems like im gona do the whole hw for u ;) to find the limit of the area that ur gona revolve around the x=-2 axis u have to draw the two equations again and the area enclosed is basicly the shape of a circle (not a perfect circle though) and its located right above the x-axis touching it from below and the center of it is on the y-axis .. now the limit is the intersection of these two euations y=x^2 and y=2-x^2 that is x^2= 2- x^2 ==> 2*x^2 = 2 ==> x^2=1 ==> | x | = 1 ==> x = +1 or x = -1 .. and thats ur interval limits