What is the net ionic equation for the following?
921488
2ClO4(-) --->  2ClO4(-)\n2H(+) + 2OH(-) ---> 2H2O\n\nwhere sign in brackets are superscripts.
781203
2H3PO4(aq) + 3Mn(OH)2(s)  --> Mn3(PO4)2(s) + 6H2O(l)
803450
MgCl2(aq) + 2NaOH(aq)  --> Mg(OH)2(s) + 2NaCl(aq)\n\nNet ionic equation:\n\nMg2+(aq) + 2OH-(aq) --> Mg(OH)2(s)
377842
Which reaction?  You need a reaction to have a net ionic equation.
327609
If I've understood what you're asking then:\nA\nCd(s) + Ag2+ -> Cd2+ + Ag(s) \n\nCadmium occurs at Anode and the Silver would deposit on the Cathode\n\nB (I hate Manganese equations and the partial above is incorrect)\n\nMnO2 + 4H+ + 2AgBr -> Mn2+ 2Br- + 2Ag + 2H2O\n\nMnO2 @ Anode\nAgBr @ Cathode\n\nC\n\n(PtCl4)2- + 4Ag -> Pt + 4AgCl \nAg @ anode\n(PtCl4)2- @ Cathode
770385
FeCl3+3NaOH>>Fe(OH)3+3NaCl
744922
HClO2 + Ba(OH)2 -> BaClO2 + H2O\n\n2(NH4)3PO4 + 3Ca(NO3)2 -> 6(NH4)(NO3) + Ca3(PO4)2\n\nFinished and balanced.
887064
The main thing you need to know to figure out the ionic equation is whether the product is soluble or not.  In this case, PbSO4 and Mg(NO3)2 are your products, and lead salts are insoluble.  Thus, PbSO4 and any ion that is used to make this molecule is removed from the ionic equation:\n\nPb(+2) + 2(NO3)(-1) + Mg(+2) + (SO4)(-2) -> PbSO4 + Mg(NO3)2 (aq)\n\nbecomes:\n\n2(NO3)(-1) + Mg(+2) -> Mg(NO3)2 (aq)
921837
NaHCO3 --> Na+ + HCO3-\nCa(NO3)2 --> Ca(2+) + 2NO3-\nAl2(CO3)3 --> 2Al(+3) + 3CO3 (-2)
855087
Ca2+=[Ar]\nMg2+=[Ne]\nI-=[Xe]\nF-=[Ne]
519991
1, 1, 2, HNO3, 1, PbSO4.\n\nTechnically, the HNO3 is aqueous and stays in ion form, but it doesn't seem like you're looking for a net ionic.
706351
KCl(aq) + AgNO3(aq)  --> KNO3(aq) + AgCl(s)\n\nNet ionic: Cl-(aq) + Ag+(aq)  --> AgCl(s)\n\nNa2SO4(aq) + Ba(NO3)2  --> 2NaNO3(aq) + BaSO4(s)\n\nnet ionic: SO4(-2)(aq) + Ba(+2)(aq)  --> BaSO4(s)
437730
See http://members.aol.com/logan20/elecspon.html for the equation to use.
869137
2H3PO4 + 3Ba(OH)2 ---> 6H2O + Ba (PO4)2 +  2Ba
634552
an ion with both acidic and basic part
91741
What are the states of each of the substances?\n\n\nammonium chloride(aq)+potassium hydroxide(aq)---->ammonium hydroxide(aq)+potassium chloride(aq)\n\n   Complete ionic equation\nNH4+(aq)+Cl-(aq)+K+(aq)+OH-(aq)------->\nNH4+(aq)+OH-(aq)+K+(aq)+Cl-(aq)\n\n     Net Ionic Equation\nSame as complete ionic equation, every ion is a spectator ion, OR it doesn't exist.\n\nI don't think both substances are in aqueous solution.
353745
Net ionic is\n\nAg+ + Cl- => AgCl\n\nThis is double replacement.