How do i solve for x given: sinx = 6sin2x ??
916168
6 sin 2x != sin 12 x\n\nnow sin x = 6 sin 2x\nor sin x = 6(2 sin x cos x)\nor sin x = 12 sin x cos x\nor 12sin x cos x - sin x = 0\nor sinx(12cos x -1) = 0\nsin x = 0 or cos x = 1/12\n\nsin x =0 => x = npi\ncos x = 1/12 => x = 2npi +/- cos^-1(1/12)
699547
sin[x-(pi/2)]=kcosx\n-sin[(pi/2)-x]=kcosx\n-cosx=kcosx\nk=-1\ncos[x+{pi/2)]=ksinx\n=cos[(pi/2)+x]=ksinx\n=-sinx=ksinx\nk=-1
129827
3.44(sinx)^2 -23.06=25sin2x\nsquare the 2 members u'll have\n11.8336(sinx)^4 -158.6528(sinx)^2+531.7636=\n25*4[(sinx)^2 * (1-(sinx)^2)]\ncoz sin2x=2sinx*cosx &(sin2x)^2= 4(sinx)^2(cosx)^2\nredice this equation :\n111.8336(sinx)^4 -258.6528(sinx)^2 +531.7636=0\nput t=(sinx)^2\n111.8336t^2 -258.6528t+531.7636=0\ndelta=7432.23321088\nt=0.77097759 we cannot take the other solution coz t<1\n=> sin x =+0.87805329 or sinx=-0.87805329\nx=61.408418 or x=-61.408418 or x= 118.59158196 or\nx= -118.59158196\nthere r other ways to solve it but hope this helps
814691
Did you get the question correct?\n\nStart from right-hand side:\n   cos^2x sinx - cos^4x\n= cos^2x [sinx - cos^2x]\n= cos^2x [sinx - (1 - sin^2x)]\n= cos^2x [sin^2x + sinx -1]\n\nYou can't transform (sin^2x + sinx - 1) into sin^3x.
1073595
(cosx)^2 - 2sinx = 2\ncosx^2 = 1 - sinx^2\n(1 - sinx^2) - 2sinx = 2\n1 - sinx^2 - 2sinx = 2\n-sinx^2 - 2sinx + 1 = 2\n-sinx^2 - 2sinx - 1 = 0\n-(sinx^2 + 2sinx + 1) = 0\n-(sinx + 1)(sinx + 1)\n\n-sinx - 1 = 0\n-sinx = 1\nsinx = -1\nx = sin^-1(-1)\nx = 270°\n\n--------------------------------------\n\n1.5^2 = 1.7^2 + 1.8^2 - 2(1.7)(1.8)cosA\n2.25 = 2.89 + 3.24 - 6.12cosA\n2.25 = 6.13 - 6.12cosA\n-6.12cosA = -3.88\ncosA = (388/612)\ncosA = (97/153)\nA = 50.6551127\n\n1.7^2 = 1.5^2 + 1.8^2 - 2(1.5)(1.8)cosB\n2.89 = 2.25 + 3.24 - 5.4cosB\n2.89 = 5.49 - 5.4cosB\n-2.6 = -5.4cosB\ncosB = (13/27)\nB = 61.2177953\n\n1.8^2 = 1.5^2 + 1.7^2 - 2(1.5)(1.7)cos(C)\n3.24 =  2.25 + 2.89 - 5.1cosC\n3.24 = 5.14 - 5.1cosC\n-1.9 = -5.1cosC\ncosC = (19/51)\nC = 68.1270919\n\nAs you can see, the angle opposite of side A, is the smallest angle.\n\nANS : about 51°\n\n----------------------------------------------\n\ncos(A) = 4/7\nx = 4\nr = 7\n\nr = sqrt(x^2 + y^2)\n7 = sqrt(4^2 + y^2)\n49 = 16 + y^2\ny^2 = 33\ny = sqrt(33)\n\nsin(A) = y/r\nsinA = (-sqrt(33))/7\n\ntanA = y/x\ntanA = (-sqrt(33))/4\n\ncscA = r/y\ncscA = -7/(sqrt(33))\ncscA = (-7sqrt(33))/33\n\nsecA = r/x\nsecA = 7/4\n\ncotA = x/y\ncotA = -4/(sqrt(33))\ncotA = (-4sqrt(33))/33
836187
yes.\nI would solve first the square root of 1+sin2x\nsince (sinx)^2+(cosx)^2=1,so we can write\n1+sin2x=(sinx)^2+(cosx)^2+sin2x\n             =(sinx)^2+(cosx)^2+2sinx cosx             ( because we have the formula  sin2x=2sinx cosx )\n              =(sinx +cosx )^2\nso sq. root of 1+sin2x=  sinx +cosx \nnow integral of sinx+cosx is -cosx+sinx
6838
∫xSec(x²)²dx = .5Sin(x²)/Cos(x²)
1028428
well..\n\nI'll give you one:\n\ntanx + cotx = 1/(sinx cosx)\n\ntanx = sinx/cosx\ncotx = cosx/sinx\n\nsubstituting:\n\nsinx/cosx + cosx/sinx\n\nmultiply each term to get a common denominator:\n\nsinx/cosx *(sinx/sinx) + cosx/sinx *(cosx/cosx)\n\nsin^2 x / (cosx*sinx) + cos^2x/(cosx*sinx)\n\nsince sin^2x + cos^2 x = 1, and you can add the two terms together because they have a common denominator, the entire expression equals:\n\n1/(sinxcosx)
738333
(1+sin^2x)dx/\n(1+sin^2x)(1-sin^2x)\n=dx/(1-sin^2x)\ndx/cos^2x\nsec^2xdx\ntanx+C
898033
cos2x = 1 - 2 (sin x) ^2 = sin x\n\nthen 2 ( sin x)^2 + sin x  - 1 = 0\n or (2sin x - 1 )(sin x + 1) = 0\nsin x = 1/2 , - 1\nx = 30 deg, or - 90 deg
806885
dy/dx of xsinx = x(d/dx sinx) + sinx(d/dx x) = xcosx + sinx(1) = xcosx + sinx\n\nHope that helps - it's the first thing multiplied by the differential of the second, plus the second multiplied by the differential of the first. :)
368536
2cosx(2sinx-1)+2sinx-1=0\n(2sinx-1)(2cox+1)=0\nsinx=1/2\ncosx=-1/2\nx= π/6 + 2πk, where k is a member of the set of integers\nx= 2π/3 + 2πk, where k is a member of the set of integers\nx= 5π/6 + 2πk, where k is a member of the set of integers\nx= 4π/3 + 2πk, where k is a member of the set of integers
998890
If you mean to solve it, it would be this:\nF:xtimesx=x^2\nO:xtime6.5\nI:xtimes-4.5\nL:-4.5times6.5\nEquals:x^2+2x-29.25
245398
sinx = a with a Є [-1;1] or -1 </= a </= 1\n\na^2 - 2a - 3 = 0\nwe have 2 roots: a = -1 (accept) & a = 3 (reject) because a Є [-1;1]\n=>  sinx = -1\n<=>  x = -∏/2 + k2∏ with k Є Z
911476
5sin² x +13sin x - 6 = 0 This is a quadratic in sinx. Solve by factoring (if possible)\n\n(5sinx - 2)(sin x + 3) = 0\n\nOnly possibility is sin x = 0.4 as |sinx| ≤ 1 in real numbers. So sin x = -3 is disallowed.\n\nThus x ≈ 0.4115, π - 0.4115\n≈ 0.4115, 2.730
847590
sin (2x ) = 2.sinx.cosx so;\n6- 6(2.sinx.cosx) = 6-12sinxcosx;\n6(1 - 2sin2x) is the simplified form.
1015891
Isn't it sinx divided by 6?\nSimple just cancel 'n' from the numerator and the denominator.\nU will be left with six=6