pls tell me how to solve this question √45x^6y^7?
917114
√45x^6y^7=√(3x^3y^3)^2*5y=3x^3y^3√5y
928591
x^2-6xy+8y^2\nx^2-6xy+9y^2-9y^2+8y^2\n(x-3y)^2-y^2\n(x-3y+y)(x-3y-y)\n(x-2y)(x-4y)\n\naliter\nx^2-4xy-2xy+8y^2\nx(x-4y)-2y(x-4y)\n(x-4y)(x-2y)
204269
isolate one of the radicals, then square both sides.\nhere you get 2x+3=5x-6.......3x=9.......x=3\n\nworst case is sqrt(something) + something = sqrt(something)\n\nhere you'd isolate a radical, square both sides, clean up the equation, isolate the remaining radical, square both sides, and finish.  AND CHECK YOUR ANSWERS.  when you square both sides, "extraneous" solutions sneak in that might have you, back in the original equation, taking the square root of something negative.\n\nexample:  sqrt(3x+3) + 1 = sqrt(5x+6)\n....... (3x+3)+2*sqrt(3x+3)+1=(5x+6) ..... left side is a binomial\n.........2*sqrt(3x+3) = 2x+2\n...........sqrt(3x+3) = x+1\n...............(3x+3) = x^2+2x+1 ....... right side is a binomial\n....................0 = x^2-x-2 ......... and it factors!\n....................0 = (x-2)(x+1)\n....................0 = (x-2) so x=2\nor .................0 = (x+1) so x=-1\n\nnow check: sqrt(3*2+3)+1 =? sqrt(5*2+6)\n.............sqrt(9) + 1 =? sqrt(16)\n...................3 + 1 = 4.............yes.\n\n..........sqrt(3*-1+3)+1 = sqrt(5*-1+6)\n...............sqrt(0)+1 = sqrt(1)\n.......................1 = 1 ............yes\n\nsigh.  when I wrote it the equal signs lined up.
835686
4x^2 + 3y^2 = 4\n8x x' + 6y y' = 0\n8 x '' + 6 y'' = 0\n6y'' = -8x ''\ny '' = -4x / 3
1187142
maybe something like 7^(1/3) over 7^(1/2)\n\nthat's the same as the cube root of 7 over the square root of 7.\nTo solve it, you would just subtract the exponents and you'd get 1 over 7^(1/6)\n\nI hope that is what you are looking for.
17048
= x^2 - 7x + 4x -28\n= x^2 - 3x - 28
352749
By the chain rule:\n[e^(3x^(2)-7x)]*(6x-7)
532062
If the question is to simplify:\n\nSqrt(144(x^10)(y^12)(z^18)) then the first answer is correct:\n    \n12(x^5)(y^6)(z^9)
974343
√50 + √72 - √8\n√(25*2) + √(36*2) - √(4*2)\n√25√2 + √36√2 - √4√2\n5√2 + 6√2 - 2√2\n9√2
934867
(√3x²z³) * (√15x²z )\n\n(√3x²z) (√z²)  * (√3x²z) (√5z)\n\n3x²z (√5z³ )\n   \n3(√5) x²z²  <--answer\n\nor\n\n√3x²z³ * √15x²z \n\n(√45x^4z^4)\n\n(√[9*5]x^4z^4)\n\n3(√5)x²z²  <--answer
772026
1.\n7x^6y^4 + (x^3y^2)^2\n7x^6y^4 + x^6y^4\n8x^6y^4\n\n2.\nx^2(xy^3)^2 + y^2(x^2y^2)^2\nx^2(x^2y^6) + y^2(x^4y^4)\nx^4y^6 + x^4y^6\n2x^4y^6\n\n3.\n7x^2+3x-x^2\n6x^2+3x\n3x(2x+1)\n\nYou sure you posted #3 correctly?
919015
(8X^6/7) * (56/24)\n8X^6/3\n\n(Hint:  X^m/X^n = X^(m-n)
811519
sqrt(250y^6)\n=sqrt[25X10(y^6)]\n=5y^3 (sqrt)10
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
652953
I got:\n1. 6x^2 - 36x +48\n2. 6x + 22
694690
determine the square of 6 - sqrt[(x-2)^2 + y^2]\n\n-->\n\n36 + [(x-2)^2 + y^2] - 12*sqrt[(x-2)^2 + y^2]\n= 40 + x^2 + 2x + y^2 - 12*sqrt[(x-2)^2 + y^2]
787855
6 = 5y - 44\n-5y + 6 = -44\n-5y = -50\ny = -50/-5\ny = 10\n\nso y is equal to 10