work function and maximum wavelength?
922532
E = 423.6 kJ / mol ; the amount of energy needed, but this is per mole, you want it per atom, so you use Avagadro's number:\nE = 423,600 J/ mol / (6.02E23 atoms/mol) = 7.036 E-19 J/atom\n\nh is planck's constant; 6.626068 × 10-34 J * s\nc is the velocity of light in a vacuum 3.00 E8 m / s\n\nThe E__ is a shorthand way of writing * 10^__, so E8 means * 100,000,000 and E-34 means * 0.0000 0000 0000 0000 0000 0000 0000 0000 1 (which makes it a very small number)\n\nYou can rearrange the equation like this:\nE = hc/λ\nλ * E = h * c\nλ = h*c / E\n\nλ = 6.626068 E-34 J * s * 3.00 E8 m/s / (7.036 E-19 J/atom * 1 atom)\n\nλ = 2.825 E-7 m = 28.25 E-6 m = 28.25 μm
49259
c = yf\n\nc = speed of light (3 x 10^8 m/s)\ny = wavelength\nf = frequency\n\n==> f = c/y\n\n==> f = 3 x 10^8 m/s / 0.032 m \n\nf = 9.38 x 10^9 Hz\n\n-or-\n\nf = 9.38 GHz\n\n:)
710202
You are right! Atomic structure has everything to do with what wavelengths are absorbed, and which ones are reflected. I works with light, and it works with radio waves... Thats how they make stealth aircraft. Funny thing about copper... when powdered and burned, it makes a pretty green color!
687349
The basic idea for maximum reflectance is that the optical phase thickness, the refractive index times the physical thickness, is equal to one half the wavelength of light.  It could be this minimum thickness for the zero order effect, or some integer multiple of half the wavelength plus one half wavelength.\n\nThe minimum physical thickness of the oil film would be\n\nl = lambda/(2n) = 640/2.5 = 256 nm.\n\nSeems like a low index of refraction for oil, though.  There would also be a maximum reflection for this wavelength for 512, 768, ...\n\nThe condition for zero reflection is that the optical thickness is equal to one quarter wavelength.\n\nl = 512/(4n)= 102.4\n\nAlso, 512/(2n) + 102.4 = 307.4, 512/n + 102.4 = 512, and so forth.\n\nNow, 512 is sort of a blue-green color, but no matter.  Also the refractive index should depend on the wavelength.  But this cooked up problem has a solution for both wavelengths when \n\nl = 512 nm \n\nis the thickness of the oil film.  There are other correct answers, but this is the minimun thickness to meet the requirements of the two wavelengths given.
725972
You mean the graph of the function?  The second term is a sine wave with frequency 2x, meaning it goes through a full cycle in pi radians instead of 2*pi radians.  The max amplitude of the second term is +/- 1/2, since the max of the sine is +/- 1.  That's the second term.  Now, offset that by 4 units down at every point.  Got it?  Okay, your turn.
27455
wavelength = speed of light/frequency\n\nwavelength = (299792458[m/s] / 100000000[1/s])\nwavelength = 2.99792458m
876805
Work = F * d\nWork = Force of the spring * distance mass moves\n\nWork refers to an activity involving a force and movement in the directon of the force. A force of 20 newtons pushing an object 5 meters in the direction of the force does 100 joules of work.\n\nThe max KE is the work put into moving the object.
524846
B'coz wavelength decides the power gain that transmitting antenna should have .\n& distance that can be covered by signal also depends on wavelength.
684422
I know EM can go up to 100,000x (maybe beyond?), and light can go up to 1000x.  I'm not sure what the limit on EM is, but i think it's less than 800,000x.  So #4 looks right.
470121
Try these answers:\n\nFor the first one, shortest is 0.0086 m, longest is 8.6 m.\nFor the second one, it should be 2.95 Hz
617450
Some molecules absorb visible light, e.g. due to conjugation and pi to pi antibonding transitions, with the highest intensity at a particular wavelength.  One can prepare standard solutions, with accurately devised known concentrations, the measured intensities of these solutions are correlated with these standard solutions, covering a particular dynamic range.  Assuming Beer's Law, the plot will resemble a linear curve, and a least fit regression line and its equation can be obtained; also by correcting for the blank if this is has not bee accounted for by the spectrometer.  The unknown pure solution, or a matrix derived alternative method if the solution is not pure that there are significant impurities in the unknown solution, will also be measured at this wavelength and it's intensity, often the y value, will be plugged into the regression equation to estimate the concentration.
376222
As the wavelength goes up, the energy goes down. So blue is most energetic and red is least.\n\nHomework?
984947
W=F*L – work done by F=145N on distance L=7.2m,\nU=k*m*g*cos(a)*L, work wasted on friction, where k*m*g*cos(a) is force of friction, while\nk=0.31, a=11.7deg, g=9.8m/s^2, m=10.3kg.\nY=m*g*L*sin(a) work done to hoist m to height of L*sin(a) meters.\nE0=m*v0^2/2 initial kinetic energy of m, v0=1.3m/s \nNow energy balance: E0+W=U+Y+E1, E1 is final kinetic energy of m E1=m*V^2/2, V is final speed of m. Thus kinetic energy change dE=E1-E0=W-U-Y.\nAs E1=E0+W-U-Y=m*V^2/2, then V=sqrt[2*(E0+W-U-Y)/m], \nI hope you cope with numeric calculations, all are SI units
750681
A photon with a wavelength of about 650 nm
416072
It depends on the wavelength of the light and its energy.
702843
Fringe width β= λD/d\nIf the wavelength is decreased,  the fringe width also decreases.\nSo, if you consider any order fringe, say 5th order, it would form at a lesser distance from the centre as compared to the previous case(i.e.when red light was used)
747451
c) the frequency of incident radiation\nThis is according to the Einsteins photoelectric equation\nKmax = hf - phi\nwhere phi is the work function, h is the planck's constant and f is the frequency