How do I solve 3x^3-6x^2-9x=0?
923617
First, factor out 3x from the equation, so 0= 3x(x^2-2x-3).\n\nThen, factor the polynomial in the parenthesis, so 0= 3x(x-3)(x+1)\n\nAfter that, use the zero product property to set each part of the the equation to zero, so 0=3x, 0=x-3, and 0=x+1.\n\nSolve these three to get x=0, x=3, and x=-1, respectively.
774101
6+4x=3x+2\n4x-3x=2-6\n1x=-4\nx= -4
834770
3x^2-x-4=0\n=> 3x^2-4x+3x-4=0\n=> x(3x-4)+1(3x-4)=0\n=>(3x-4)(x+1)=0\nTherefore,either 3x-4=0 or x+1=0\nIf 3x-4=0,then x=4/3,and \nif x+1=0,then x=-1\nTherefore, x=4/3 or -1 ans
1161859
3x^2 - x - 24 = 0\n(3x + 8)(x - 3) = 0\n\n3x + 8 = 0 and x - 3 = 0\nx  = -8/3 and x = 3
786976
16x^2 + 12x\n\nIn order to solve, you would need an equal sign.  I think maybe you mean finding the zeros?\n\nFirst we would need to factor it.  We could pull an x and a 4 out of each.\n\n4x(4x + 3)\n\nWe get two factors.\n4x\n4x + 3\n\nThen we set each factor equal to 0 to find the zeros of the equation.\n\n4x = 0\nx = 0\n\n4x + 3 = 0\n4x = -3\nx = -3/4\n\nOur zeros are 0 and -3/4.\n\nI hope I helped. :)
336950
3x = 6x^2 if rearranged becomes\n\n0 = 6x^2 - 3x\n6x^2 - 3x = 0\n\nsince the highest common factor for both terms is 3x, then\n6x^2 - 3x = 0\n3x(2x - 1) = 0\n\nremember that a x 0 = 0 x a = 0\n\nso either 3x = 0    or    (2x - 1) = 0\n\nif 3x = 0, then x = 0\nif 2x - 1 = 0, then 2x = 1 and x = 1/2
843398
6x(x-3y)-3(6x^2-xy) = 6x^2-18xy-18x^2+3xy=-12x^2-15xy ans.
786382
x^2-6x+9=3+9\n(x-3)^2=+/-rt12\nx-3=+/-2rt3\nx=3+/-2rt3\n\n2.2(x^2+5x)=-11\n2(x^2+5x+25/4-25/4)=-11\n2(x+5/2)^2-25/2=-22/2\n2(x+5/2)^2=3/2\n(x+5/2)^2=3/4\nx+5/2=+/-(rt3)/2\nx=-5/2+/-(rt3)/2\n=1/2[-5+/-rt3]
774020
3x^2(5x^2 – 2x + 6) – 2x(x^2 + 3x + 9)\n15x^4-6x^3+18x^2-2x^3-6x^2-18x\n15x^4-8x^3+12x^2-18x\nx(15x^3-8x^2+12x-18)
825419
x^3 - 6x^2 - 3x + 18 \n= x^2 (x -6) - 3(x-6) \n= (x^2 - 3)(x - 6)
896236
First expand the brackets, collect like terms and simplify.\n\n(-2x^2 + 5x - 1) - (3x^2 - 4x - 6)\n= -2x^2 + 5x - 1 - 3x^2 + 4x + 6\n= (-2 - 3)x^2 + (5 + 4)x + (-1 + 6)\n= -5x^2 + 9x + 5
957282
|3(x + 1) + 6| =18\nie |3x + 9| = 18\nwhence |x + 3| = 6\nThere are 2 different methods to solve such an equation\n\nOne is to use the definition that\n|N| = N if N ≥ 0\nand = -N if N < 0\n\nThe other is to use the propety that |N|² = N²\n\nMethod 1\nSo x + 3 = ±6\nWhence x = -9 or 3\n\nMethod 2\n|x + 3|² = 6²\nie x² + 6x + 9 = 36\nx² + 6x - 27 = 0\n(x + 9)(x - 3) = 0\nx = -9 or 3
198676
We can solve it directly\n(12x^2+18x-54)=0\n(6x+18)(2x-3)=0\n6x+18=0   OR 2x-3=0\nx=-18/6=-3  Or x=3/2\nX={3/2 , -3}\n\nBut we can simplify it first\n(12x^2+18x-54)=0         [divide by 6 both sides]\n(2x^2+3x-9)=0\n(x+3)(2x-3)=0\nx+3=0  Or 2x-3=0\nx=-3  Or x=3/2\nX={3/2 , -3}\n\nThe same answer
761754
UW+WZ+UZ\n3x+6+4-x=8x+6\n-6x=-4\nx=2/3
895342
x^2-9x-x+9=0\n(x-9)(x-1)=0\nx=9 or x=1
833469
6x -9 = -9 + 6x\nsubtract 6x...........-9 = -9\ntherefore it is true.
895527
2x^2-8x+3x-12\n2x(x-4)+3(x-4)\n2x+3 = 0 or x-4= 0\nx = -3/2 or x = 4\n\n2x^2+10x-72\n2x^2+18x-8x-72\n2x(x+9)-8(x+9)\nx = 4 or x = -9\n\nx^2+6x-x-6\nx-1 = 0 or x+6 = 0\nx = 1 or x = -6