How do you multiply three integers?
926866
it really doesnt matter...\nyou could do a x b then the answer times c\nb x c and then the answer times a\nor c x a and then the answer times c\n\nif you have a calculator just enter it as a x b x c\n\nno matter how you multiply them you will get the same answer
891988
Multiply that by about 0.458
575490
I- + 2e- -------> I2\n\n4P + 3e-  -------------> P4\n\nthere ya go :)
949122
isolate the variable.\n\nfirst subtract 3 from both sides.\n2x=6\n\nisolate the variable further.  Divide each side by 2\nx=3
125119
add them together and divide by 3
674087
The question is how to describe the steps of the multiplication. The asker is not a native English speaker and wants the words that describe the multiplication procedure.\n\nFirst, you multiply 123 by 8 and write the product.\nThen, you multiply 123 by 6 and write the product under the previous product and one place to the left.\nThen, you multiply 123 by 7 and write that product under the previous product and one place to the left.\n\nThen you add the products to get your final answer.
985663
First, if you are just going to have 3 numbers from 0 to 27 inclusively, you have 28 numbers all in all and it is with repitition so you will have just raise the 28 to the 3rd power \n\nso you will get 21,952   \n\nand then , if you will have a correct answer on the first time you will get \n\n1/21952
738083
3√x times 3√x, this means you multiply 3√x to 3√x\n3√x * 3√x = (3*3)*(√x * √x)\n                = (9)*((x^(1/2)) * (x^(1/2)))\n                = (9)*((x^[(1/2)+(1/2)])\n                = (9)*((x^[1])\n                = (9)*x\n                = 9x\nWhich is not 9√x.\n\nI hope this makes clear.
169512
In multiplying you have to multiply the numerators and demoninators and simlify. and in dividing you have to find the resiprocal of the second # by switching the numerators and demoninators and then you multiply the #s. Peace!
199153
I dont know how old you are so you might not have learned this. I will try to explain a good way to multiply stuff if you dont have a calculator. \nYou can split up the multiplication to make it easier for yourself. instead of doing 13 x 375, you can make it \n(10 x 375) + (3 x 375). This is basic factoring. The first one is pretty easy, you just add a 0 on the end.\n3750 + (3*375) is what you have to find now. If this is also too hard, then you can split it up further. \nYou can do (3 x 300) + (3 x 75) and the first one isnt that hard to do. 3 x 300 = 900. then 3 x 75 is 225, but if that is still too hard then just do it again. Pick a number that you can multiply easily (such as 50), and split it up again\n(3 x 50) + (3 x 25) = 150 + 75 = 225.\n\nNow comes the hard part though. (Not that hard). You have to add all the totals up.\n  (10 x 375) + (3 x 300) + (3 x 50) + (3 x 25)\n= 3750 + 900 + 150 + 75\n= 4875
880864
3(4x+6)+7\n\nexpand first (ie multiply what is in the bracket by what is out side the bracket)\n\n= (3 times 4x + 3 times 6) +7\n=12 x + 18 + 7\n\nthen collect like terms (i.e. similar powers of x)\n\n= 12x +25
789393
The same way as you multiply any number! you just have to remember you're in hex. If you can get your mind to work in base 16 then the questions will look a lot simpler...\n\nBut, a slightly long winded but foolproof way would be to convert the numbers you want to multiply into decimal, perform the multiplication, and then convert the answer back into hex. The website below has a converter
576432
multiply straight across 1/2x3/4=3/8
901612
First, you have to distribute the 3 into the 4m and the -6, giving you 12m-18=12. Then, add 18 to each side, giving you 12m=30. Last, divide each side by 12, giving you m=2.5
119559
its (x+2)(3x+1) now thats rite lol
133768
Assuming each digit is used no more than once in any given integer, this one would be fairly simple (and perhaps time-consuming) to draw out on paper:\n\n1. All integers have to end with the 3. For single-digit integers you of course have:\n\n3\n\n2. For two-digit integers, you have:\n\n43\n63\n83\n\n3. Three-digit integers:\n\n403\n603\n803\n463\n643\n483\n843\n683\n863\n\n4. Four-digit integers:\n\n4063\n4083\n4603\n4803\n6043\n6083\n6403\n6803\n8043\n8063\n8403\n8603\n8463\n8643\n4683\n4863\n6483\n6843\n\nI count 31.
1084101
You must cast legs to an integer using parseInt\n\nlegs = parseInt(legs);