Find the slope and y-intercept of the line: x+4y=12?
927388
y=mx+b\n\njust rearrange it so you get b as your intercept..\n\nin this case y=-1/4x +3, so the slope is -1/4, and the intercept is 3
564627
change the equation to slope intercept form\nsolve the equations for y\nx+2y=3\n2y= 3- x\ny= -x/2 + 3/2\nDo the same thing for the other formula\nthe form is\ny = mx + b\nAfter that just plug in numbers for x to get y
305322
First you need to solve for y... y = 4/3x-4\nThen by using the Y = MX+B formula you will see M = 4/3 which is your slope. B = -4 which is your Y-Intercept. Plot your Y-Intercept at (0,-4) and then plot the next according to your slope, which is Rise/Run. so from (0,-4) you will go up 4 and over 3. you should end up at (3,0). after that all you have to do is connect the dots....
781563
y>(12-3x)/4\n\nSteps:\n\nmultiply the 12 on both sides\n3x+4y>12\n\nminus the 3x isolating the y variable\n4y>12-3x\n\ndivide by 4 on both sides to get y by itself\ny>(12-3x)/4 or...\n\nsimplified 3-(3x/4)
813674
To find the y intercept make x equal 0 then solve the equation. You can then work out the x intercept by making y equal 0. This will allow you to plot the line and work out the gradient/slope by using rise divided by run. Alternatively, rearrange the equation to make y the subject. I believe the slope would be -1/4. This would be y=-1/4x+8.
94805
If you know how to find the slope of a line in the form y = mx + b, just write the equations of two lines with different slopes.  They will have to cross.  Graph each line and find the crossing point.  That's the answer.  Hint:  make the slope of one line be the y-intercept of the other line and vice versa.  Then they will cross at an exact point on the graph.
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
97021
Using the points you can work out the slope. That is 0.\nThen use one set of points and the slope to work out the equation of a line formula which is:   \n         y-y1=m(x-x1)\nm is the slope \n       y+4=0(x-11)\n       y+4=0\n       y=-4
957268
The slope should be 3 over 1 or +3(rise over run)and the x and y intercepts would both be 0  (0,0). \n\nThis can be found by using the equation y=mx+b or by using a graphing calculator. The graph of the line in this case crosses exactly where the x-axis and y-axis cross (0,0).
213186
4x + 2y = 12\n\n\n2y = 12 - 4x\n\ny = -2x + 6\n\nm = -2
105029
slope: 1; intercept: 2\n\nslope: -1; intercept: -3\n\nslope: -5/4; intercept: 20\n\ny = mx + b, where m, the coefficient of "x" is the slope and "b" is the y-intercept.  If you solve the equations for y it's pretty easy to figure out both.\n\nHope that helps.
1013948
Standard form for a slope intercept equation is:\n\ny = mx + b\n\nwhere m is the slope and b is the y-intercept.  So, transforming:\n7x + 4y = 20\n4y = 20 - 7x\ny = (20 - 7x) / 4\ny = 5 - 7/4 x\ny = -7/4 x + 5\n\nAnd\n5x + 6y = 19\n6y = 19 - 5x\ny = (19-5x) / 6\ny = 19/6 - 5/6 x\ny = -5/6 x + 19/6
1134427
12x + 4y = 8\n(d/dx) * (12x + 4y = 8)\n12 + 4dy/dx = 0\ndy/dx = -12/4\ndy/dx = - 3
653148
All equations for a line will have the form:\n\ny = mx + b,\n\nwhere x & y are coordinates, m is your slope, and b is your y-intercept.\n\nTherefore, substituting in your slope and y intercept, you get:\n\ny = -2/3x + 4\n\nThis equation can then be used to graph the line, since given any x, the corresponding y can be found. :)
700599
1)   y=3x^2+5x-12\n      0=3x^2+5x-12                  (to find the x-intercepts)\n      0=(3x-4)(x+3)                  (Factorised)\n      3x-4=0  or  x+3=0\n      the x-intercepts are x=4/3  and  x=(-3)
746165
Remember the fomula...\n\ny = mx + b\n\nm = Slope\n\nb = Y-intercept\n\nx and y = points\n\nSo plug everything in...\n\n1 = 4(2) + b\nMulitply\n1 = 8 + b\nSubtract 8 on each side\n-7 = b\n\ny = 4x - 7
885928
Find the X intercept by setting Y = 0\n\nx-2 = 0\nx = 2\n\nFind the Y intercept by setting X = 0\n\ny = 0-2\ny = -2\n\nSo the two points to plot are (0,-2) and (2,0) \nThen connect those points with a line