i need to find the mean, median,mode, and range for the following set of numbers: 6,9,9,8,3,1?
927294
mean (add all numbers together and divide by the amount of numbers) - 6\nmedian (middle number when ordered from least to greatest) - 7\nmode (the number that appears the most) - 9\nrange (lowest number subtracted from highest number) - 8
308432
Suppose you have a set of numbers:\n\n0, 1, 1, 2, 3, 4, 6, 8, 9, 11, 15\n\nThe median is the middle number when put in least to greatest: 4\n\nThis breaks your list into two halves: 0, 1, 1, 2, 3 and 6, 8, 9, 11, 15.  Your upper quartile is the median of the greater half: 9.  Likewise, your lower quartile is the median of the lower half: 1.\n\nIn the event you have two numbers for a median, take the average of the two and that becomes your median.  In the above example, if you only had 6, 8, 9, 11 for your upper half, your median would be the average of 8 and 9, or 8.5.\n\nAs for your second question (assuming that x belongs in the numerator):\n\n4/5 = (-9/4) - 7x/10\n4/5 + 9/4 = -7x/10\n16/20 + 45/20 = -7x/10\n61/20 = -7x/10\n61/2 = -7x\nx = -61/14
603103
The median is another word for the number that is the middle number. When there is an odd amount of numbers, the one in the middle is the median. When there isn't, you take the mean (average) of the two in the middle. With this set of numbers, since there is 11, the median is 9.\n\nHope that helps!
768633
order the data: 7,9,9,11,12,13,13,13,15,19\n\nfind the Median (middle point, as there are 10 data points it's the average of the 5th and 6th): 12.5\nLower Quartile: 9 (25th percentile, median of lower half, i.e. here 3rd observation)\nUpper Quartile: 13 (75th percentile, median of upper half, i.e. here 8th observation)\nmin. observation: 7\nmax observation: 19\n\nso it's:\n\n    12.5\n9          13\n7          19
789559
Ten numbers per line, add 'em up and divide by 10.\n\nYou should get these means for the four sets:\n\n0.138, 0.172, 0.184, 0.156\n\nBe careful, since not all the numbers may show up on Yahoo unless you put your mouse pointer on the line.
889816
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
343527
Mode is most occuring. I always remember it because like M for most and O for occuring. \n1 3 4 4 4 4 4 5 6 6 6 \n \n4 would be the mode\n\n\nMedian is like middle number. median.. middle. they just kinda go together. you line them up in order then cross the end ones off until there is only one left. if there are two of them left then add them up and divide by two.\n \n2 3 4 5 6 7 8\n \nfive would be the median\n\n\nMean is average. i always remember it by ME Average? haha kind of doesnt make sense but hey it works for me. thats when you add all the numbers up and divide the sum by how many numbers there are \n\n1 2 3 4 5 6 \n\nso 1+2+3+4+5+6 = 21 / 6 =  3.5\n\nso the mean is 3.5
831476
rearrange the numbers from the least to the greastest\n83,85,85,88,89,89,90\n\n88 is the median
902613
I just plugged this into my calculator.\n\n[1, 0, 2, 0, 2, 0 | 0\n0, 1, -3, 0, -2, 0 | 0\n0, 0, 0, 1, -1, 0 | 0\n0, 0, 0, 0, 0, 1 | 0\n0, 0, 0, 0, 0, 0 | 1 ]\n\nTake it however you want.
592312
Sure you have learned it. It's addition. If the mean (average) must be in the middle (the third number) then the numbers are:\n\n15,16,17,18,19\n\nand sum is 5*17 or 85
835896
if you have a set of numbers such as..... 1, 4, 5, 6, 5, 7, 5, 3, 8\n5 is the mode because it appears the most times in the set of numbers
868097
-\naside from 1,\n2,3,4,6,12
786357
The mean is simply the average of the data.  Add them all up and divide by 15.\n\n69.54
1018969
Just google it dear..very simple..calculate mean and average the sum of square of variation of each score from the mean.\nhttp://davidmlane.com/hyperstat/A16252.html
178476
Diameter is two times the radius.\n\nThey may want you to calculate the mean (average), median, or mode of the 12 values.\n\nIt would be best if you would give more details.
617746
sample space {1,2,3,4,5,6}
800575
There are three averages, you need two, the mode+median, the other one is the mean.  \n\nThe median is the middle of the data, so just arrange the data in order from least to greatest and cross out ones from either side one by one, but you're left with two in the middle, just take the average of 9 and 15, you get 12, which is your median.  \n\nThe mode is the value that appears most in a set of data, in the first set 9 appears the most, thrice, so it's the mode.  \n\nIn the second set no number appears more frequently than the others so there is no mode.  \n\nHope this helps!!