Velocity for SHM oscillator...?
912968
Your formula give the displacement, just put in the value of t.  The velocity is the derivative of the displacement,  Take the derivative dx/dt and put in the value of t.  The acceleration is the second derivative of displacement, or the first derivative of velocity.  Same method.  The period is given by ∆t when the argument of cosine goes from 0 to 2π, and the frequency is 1/period.
756774
P=P (momentum before = momentum after)\nmv=mv\n(55kg)(4.6m/s) = (230kg)v\nv= ((55kg)(4.6m/s))230kg\nv=1.1m/s
888452
f=ma\n\na=change in velocity/change in time = (5.53-2.25)/1 \n\nm= 57\n\nf = 57 (5.53-2.25)\n\npunch the numbers in to your calculator, and there it is!
107382
v^2-u^2 = 2gh\nHere, v=1, g=-10m/s/s, h=0.6m\nHence, u^2 = 1+12=13\n=> u = 3.606 m/s
697157
False.  m/s (meters per second?) is not a measure of rotary speed.  Until you get that straightened out, no answer can be calculated for a) or b)\n\nBefore posting a ?, do a search here.  This same ? came up yesterday.........!
1035497
(v - v0) / (t - t0)\n\nv - final velocity\nv0 - initial velocity\n\nt - final time\nt0 - initial time
587882
FORMULA: speed = frequency * wavelenght (sorry cant get symbols to work on yahoo)\n\n(1) 0.2= 1/0.5 * w   ...(as f=1/T)\n=> 0.2=2w\n=> w=0.1\n\n(2) s= 25*(10^8) * 0.12    ...(12cm= 0.12m)\n=> s= 3*10^8\n=> s= 300000000 m/s\n\n(3) 2= f * 0.5\n=> f= 2/0.5\n=> f= 8\n\n8 waves strike dock each second.\n\npretty easy questions.
821401
yes, it's a sine wave, and velocity is integral of that, ie a cosine\n(this is considering only fist order effects)
820873
I can't understand this question. Is the tuning fork totally immersed in the water? Then its frequency will be radically changed and the oscillation highly damped due to the water's inertia, relative incompressibility and resistance to motion. There's no way to compute its frequency without having a lot more information (at a minimum, details about the mass, size & shape of the tuning fork) and the calculation would be complex and difficult. \nOK, so let's suppose its vibration is coupled to the water without beng immersed. Then it oscillates at 400 Hz, and this is the frequency of the sound in the water. The wavelength is then a trivial calculation.\nSurely I'm missing something. I think you should provide the answer (via the "add details" option) and see what people think then.\nEDIT: Since you added the answers, there's no disagreement on the frequency. The wavelength in any medium is the speed divided by the frequency, so there's no disagreement on the wavelength in air. However, the speed of sound in water is a parameter that many physicists have attempted to formulate. The generally agreed value at 0C is about 1430 m/s. Using the web page given below and the Marszak interactive calculator available there, I get 1402.385 m/s, which yields a wavelength of 1402.385/400 = 3.505963 m. (The other calculators on that page all agreed on the speed within 0.003 m/s.) The textbook's answer of 3.83 m implies a speed of 1532 m/s, which the Marszak calculator equates to a temperature of 42C! I think the textbook's author(s) have some explaining to do.
45821
are you sure that you want acceleration instead of velocity??\n\nwell, the acceleration is going to be 0.  since the speed is going to be the same the whole time, there won't be any acceleration.
759319
acceleration=rate of change of velocity\n=80*5280/3600*6ft/sec^2\n=19.6 ft/sec^2\n\n2.0=(70*5280/3600)^2-2f(157)\n314s=67.1ft/s^2
15926
.6 m/s.  and here's why:\nthe distance between two crests is the wavelength, and the "one wave goes by every 5 sec" is it's period.  The formula is v=fw where w(which is normally lambda, but i cant put greek letters on here) is wavelength, f is frequency, and v is velocity. you don't have frequency, but f=1/T where T is the period, so f would just be 1/5.  So then you go back to the first formula and multiply 3x(1/5) and you get 3/5 which is .6 m/s.\n\nAnd FYI, this formula does NOT include index if refraction and therefore it doesn't matter what medium the wave is traveling through.  Yes, velocity get's slower with a more dense medium, but the different medium would also make the frequency and period change, so therefore, the period you were given corresponds to whatever medium the wave is in.  There can only be one wave speed for that period/frequency with that wavelenth.  I mean, the 1/5 that we got for frequency means that 1/5 of a wave passes per second.  Now if each wave is 3 meters long, that means that we have to find 1/5 of 3 meters to fnd out how many meters of this particular wave passes per second.  1/5 of 3m (or 1/5 x 3) is 3/5(which is the answer, .6)  Meaning that the wave is passing by at a speed of 3/5(.6) meters per second.  I hope this helped you to understand the concept behind that formula :)
676957
E = 1/2 M V^2 where V is the velocity.  Either we need to know the distance of travel of the load or the speed of the vibrating load.\n\nA load  hitting the surface 3 times a second going back and forth 1 ft each way will exert greater energy than a load traveling only 1 inch 3 times a second.\n\nTherefore, if the distance of travel is "d"\nE= 1/2 [M (df)^2]
544479
The speed of sound: 340.29 m / s
835410
You need to get your units in a consistent form.  I suggest changing the velocity of the electron to 2.5E6 m/s so when you divide it into c-----------WAIT A MINUTE!-----Yor formula is NOT right, because you're dividing a speed by a speed, which will give a dimensionless answer.  Wavelength is a LENGTH, so the answer must come out that way.  I forget the formula you're refering to, but what you've typed isn't it................
851042
Weight of the bullet..IE. grain  how far it'll travel @ what velocity
887961
Use the general equation for Doppler effect from here( http://en.wikipedia.org/wiki/Doppler_effect ). f'/f = .86 and v0 =0 for you since the observer isn't moving. Note that since the frequency is lower that it must be moving away from you.