MATH qwestun need help please!!!!!?
931004
You just need all the factors of 86400.  To get the prime factors, you don't even need to divide since you know that the number of seconds in a day is 60 x 60 x 24.  These two numbers are easy to factor: 60 = 2 x 2 x 3 x 5 and 24 = 2 x 2 x 2 x 3.\n\nNow you know that every factor of 86400 is a mulitple of 2, 3, or 5.  You can figure the factors by all the combinations of the above or just by stepping through all the possibilities.  For example:\n\n2 x 43200\n3 x 28800\n4 x 21600\n5 x 17280\n6 x 14400\n\nI don't need to try 7 since I cant make 7 out of the factors avove.  The same is true for 11, 13, 17 and all primes.\n\n8 x 10800\n9 x 9600\n10 x 8640\n12 x 7200\n15 x 5760\n 16 x 5400\n 18 x 4800\n 20 x 4320\n \nEven though 21 is not prime, it cant be a factor because 21 = 7 x 3 and 7 is not a factor of 86400.  The same is true for 22.\n\n24 x 3600\n25 x 3456\n27 x 3200\n30 x 2880\n\nYou can take it from here.  You don't need to go all the way to 86400 because n x m = m x n meaning that you can divide a day into 10 periods of 8640 seconds just as well as 8640 periods of 10 seconds.  You only need to find factors as long as the first number is less than the second or n < sqrt(86400).  So you have another 260 numbers to sort through.  \n\nAlternatively, you can use the list of factors to construct all the possible combinations.   Since:\n\n86400 = 2^7 x 3^3 x 5^2\n\nEach factor will have 0-7 2s, 0-3 3s and 0-2 5s for 8 x 4 x 3 = 96 factors including the pair 1 and 86400.\n\nSo you can pick the factors as:\n\n2, 2^2, 2^3, 2^4, 2^5, 2^6, 2^7, 3*2, 3*2^2, 3*2^3, 3*2^4, 3*2^5, 3*2^6, 3*2^7, 3^2*2, 3^2*2^2 ....... yo get the idea\n\n \n15 x
950045
Correct formula should be as follows:\n\nE = 1/2*I*w^2
396671
try www.quickmath.com and www.calculator.com. I have a lot of others if you want them.
930340
PROBLEM 1:\n\nsqrt(x^3) = 8\n\nSquare both sides:\nx^3 = 64\n\nNow take the cuberoot of both sides:\nx = cuberoot(64)\n\nSolve:\nx = 4\n\nPROBLEM 2:\n\ncuberoot(x^2) =4 \n\nCube both sides:\nx^2 = 4^3\n\nSimplify:\nx^2 = 64\n\nTake the square root of both sides:\nx = ±8
128596
im great with algebra, ive been doing it for the past 4 years now non stop, email me and ill be more than happy to show you how to do it step by step and answer you questions\nzinger_38@yahoo.com
603161
take number of correct answers and divide by total number of question then multiply that by 100\nc/t times 100\nc=correct answers \nt=total num of quest
646947
1. A & B cross  -  2\n2. A returns    -  1\n3. C & D cross  -  10\n4. B returns    -  2\n5. A & B cross  -  2\n\nTotal minutes: 17\n:)
53373
Here are a few sites you can check out:\nhttp://www.freemathhelp.com/\nhttp://www.mathgoodies.com/\n\nHope these sites can help you..
748310
q is mean proportion of p and r\n\nq^2 = pr\n\n(p^3+q^3+r^3)/p^2(q^2)r^2\n= (p^3+q^3+r^3)/p^2(pr)r^2\n= (p^3+q^3+r^3)/p^2(pr)r^2\n=(p^3+q^3+r^3)/(p^3r^3\n= 1/r^3+q^3/(pr)^3 + 1/p^3\n= 1/r^3+q^3/(q^2)^3+ 1/p^3\n= 1/r^3+1/q^3+1/p^3\n= RHS
807922
Here is how to do it:\n\nsqrt 500\nsqrt 100*5\n10 sqrt 5\n\nTherefore, you are correct.
963947
assuming you meant:\nP=2(L-W)\nthen\nP/2 = L-W\nand so\nL= W+ P/2\n[
1181046
http://homeworkhelp.aol.com/math/?sem=1&ncid=AOLRNL00170000000006
904822
Hello Dear Blue \n\n2x^3+8x^2 - 5x + 5 ÷ x-2\n\n▪ Step1\n( 2x^2 ) ( x-2 ) = 2x^3 - 4x^2 ; { let Q1 = 2x^2 }\n2x^3+8x^2 - 5x + 5 - ( 2x^3 - 4x^2 ) = \n2x^3+8x^2 - 5x + 5 - 2x^3 + 4x^2 = +12x^2 - 5x + 5 {remainder} \n\n▪ Step 2\n+12x^2 - 5x + 5 ÷ x - 2 \n(x - 2) (12x) = 12x^2 - 24x ; { let Q2 = +12x }\n+12x^2 - 5x + 5 - ( 12x^2 - 24x  ) =\n+12x^2 - 5x + 5 - 12x^2 + 24x = +19x +5 {remainder}\n\n▪ Step 3 \n19x +5 ÷ x -2\n(x -2) (+19) = +19x - 38; { let Q3 = +19}\n19x +5  - (+19x - 38) =\n19x +5  -19x + 38 = +43 {remainder}\n\n▪ Step 4\nSum Q1, Q2, Q3\nQ1 + Q2 + Q3\n2x^2 +12x +19\n\nSo;\n(2x^3+8x^2-5x+5) ÷ (x - 2)    = >\n\nQ(x) OR quotient = 2x^2 +12x +19 \nR(x) OR Remainder is + 43 \n\nGood Luck dear.
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
778361
x=\n\n -b +/- SQRT (bSQ-4ac\n-------------------------------\n              2a\n\nwhereas: a(x)SQ+b(x)+c=number\n\nproblem: xSQ+2x+3=6\n\na=1\nb=2\nc=3\n\n-2 +/- SQRT (2SQ+4*1*3)\n-----------------------------------\n                 2*1\n\n2SQ=4\n4*1*3=12\n2*1=2\n4+12=16\nSQRT16=4\n\n-2+4\n------\n   2\n\n-2+4=2\n\n2/2=1\n\n-2-4\n------\n  2\n\n-2-4= -6\n\n-6/2= -3\n\nx= 1 AND -3
449301
4/Q=2\n4/Q * Q/1 = 2*Q/1\n4 = 2Q \n4/2 = 2Q/2\n2=Q\n\nYou first multiply each side of the equation by the same figure, in this case by Q/1.  The result is 4 = 2Q.  Next, divid each side of the equation by the same figure, in this case by 2.  The result is 2=Q.
891080
1. Xc = 1/2πfC\nSo 2πfC = 1/Xc\nSo C = 1/2πfXc\n\n2. ib = ibq + √2is\nSo √ = ib - ibq\nSo 2is = (ib - ibq)²\nie is = ½(ib - ibq)²\n\n3. Q = XL/R\nSo XL = QR\n\n4. Lt = L1 + L2 - 2Lm\nSo 2Lm = L1 + L2 - Lt\nie Lm = ½(L1 + L2 - Lt)\n\n5. R1=i2 R2 / i2\n??????? So R1 = R2\n\n6. Es = E1 + E2 + E3\nSo E2 = Es - E1 - E3\n\n7. R1 / Rx = R2 / R3\nSo Rx / R1 = R3 / R2\nSo Rx = R1 * R3/R2\n\n8. y = Mx + b\nSo Mx = y - b\nSo M = (y - b)/x\n\n9. i2=i1 R1 / R2\nSo i1 R1 = i2R2\nie i1 = i2 R2 / R1\n\nI would be extremely concerned about your progress if you find this simple algebra a serious chore!!!!!! (Especially if you are learning the electrical trade)