simplifying - more help please?
924962
her's the solution in this link
798195
Don't be scared by all the words.  You just have to remove brackets and parentheses from\n2[x+(x+10)+(x+2(10))] \n\nand then collect the terms -- you should get 6x+60.\n\nThe last part just means do it again with 15 replacing 10.
917224
Simply use correct order of operations\n\nparentheses\nexponents\nmult/division (from left to right)\naddition/subtraction (from left to right)
967368
Just treat all other letters as constants. You can multiply, divide, add and subtract both sides of an equation and maintain the equality.
890645
Wow, there is a lot here!  I'll start with some tips for solving algebra problems.  The first thing you should always remember is to play the equal game.  Whenever you add, subtract, multiply, or divide, you should do the same to the other side.  The other tip is to use the order of operations when simplifying.  Remember the sentence: Please excuse my dear Aunt Sally.  The initial letters of each word stands for the order of operations.  Do the Parenthesis first, followed by the Exponents, then Multiplication or Division, and Addition and/or subtraction next.  Finally, you should always simplify first using the order of operations before you start shifting numbers from one side of the = to the other.  \n\nI'm not going to work all of these problems, but I'll show you a few to get you started.\n\n1)\n3x-7 = 2   Add 7 to both sides\n3x = 9   Divide by 3\nx = 3\n\n4)\n6x - 3 = 2x - (4-3)/3   Simplify the stuff inside the parenthesis first\n6x - 3 = 2x - 1/3  Add 3 to both sides\n6x = 2x - 5/3  Subtract 2x from both sides\n4x = -5/3  Multiply both sides by 3\n12x = -5  Divide both sides by 12\nx = -12/5\n\nI hope this helps.  Good luck!
1099552
x' € S - {x}\nworks fine...\n( replace the € by the usual "is an element of" symbol )
51150
UGH!!!  Thx for the effort (I was the one to post that question, as a part of a solution to another problem I found here on Yahoo! Answers.)  Incidentally, I made a mistake when simplifying the other problem and it should be xln(2)-2ln(x)-ln(86400) = 0\n\nI don't know any way to get rid of the ln(x) unless maybe it's using calculus techniques?  I'm just glad this problem is making other ppl trouble about it as much as I did :-).
98013
make it a more simple question please
833452
INSTEAD of giving you the answer directly -- here are the steps to solve and simplify.\n\nWRITE down the equations on separate lines -- leave about 4 lines between each problem.\n\nNOW -- draw connecting lines between the LIKE TERMS (for example -- in the first problem (4x+6-2x+6) the like terms are those that have the 'x' value with them and the other set of like terms are the constants with NO variables with them) -- I would use two different color pencils to do that)\n\nso add the 4x and 2x together (Answer is _x) -- then add the constants (those numbers without variables together (or +6+6)) together (Answer is __).\n\nNow put these two results together on the 3rd line.\n\n\nFinally, factor out any common terms in the results.\n\nTHAT is your final answer and the simplified expression.\n\n\n\n\nFOLLOW these steps once again for the 2nd problem -- but now instead of the variable being 'x' it is now 't'.\n\nNOW
316383
Reduce it untill the # on the bottom is prime.\n (divide the top AND bottom by 2 untill you get a decimal.)
974937
please complete the equation
557964
Wouldn't it be something like:\n\n2x(8) + 8s     to get rid of the denominator\n\n16x + 8s\n\nThat is as far as I think you could simplify it, because each has different variables and you can't combine something with different variables.
945604
1.adding-2f-7\n-6f-2f+7-7<2f-2f-9-7\n-8f<-16\ndividing by -8\nx>2\n\n2.5/8g-4>2/3g+6\nadding 4\n5/8g>2/3g+10\nmultiplying by 24\n15g>16g+240\nadding -16g\n-g>240\ndividing by -1\ng<-240\n\n3.sum incomplete\n\n4.-2 1/9d+3/5<-3 2/9d-4 2/5\n-19/9d+3/5<-29/9d-22/5\nmultiplying by45\n-95d+27<-145d-198\nadding 145d\n50d+27<-198\nadding -27\n50d<-225\ndividng by 50\nd<-5 1/2
379522
adding more apostrophes..
196269
i took this question to mean as:\n\n[11/ (4-x)] + [2x/ (16-x^2)]\n\nso, what you do first is to multiply addends by (-1/-1), which is still equal to one, and won't make a difference, except to change the signs.\n\nso it would look like\n\n[-11/ (x-4)] + [-2x/ (x^2 - 16 )]\n\nsimplify to:\n\n[-11 / (x-4) ] + [ -2x / (x+4) (x-4) ]\n\ncombine the elements:\n\n[(x+4) + (-2x)]/ [(x+4) (x-4)]\n\nto make \n\n[(x+4-2x)]/ [(x+4) (x-4)]\n[(-x+4)]/ [(x+4) (x-4)]\n[-(x-4)]/ [(x+4) (x-4)]\n\nand the simplest would be:\n\n-1 / (x+4)\n\n hope this helps. :D
1031756
It would help if you used some parentheses to indicate which terms are being divided into which terms!  I suspect that just using the order of precedence for operations will not result in the problem you are actually trying to solve.
550918
Type "=B1-C1+D1*A1" without the quotes inside another cell such as E1.  This is assuming that your equation is the correct algebraic form and solved for one variable.  Your text is a bit jumbled so I didn't parse all of it.