Help with Pre-Algebra Homework?
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The factor of 8 and 56 is 8.\n8v+56\n=8(v+7)           [This is because when 8v and 56 are divided by 8,\n                         the remainer is v and 7 respectively]
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2) new-old divided by old\n3) find the square root first\n4) i think its 184... not sure\n5) Distribute 3 to 4x and 4 to get 12x+12 and the 2 tho 5x and 9 to get: 12x+12+10x+18-12 Then simplify (I'm not gonna do all ur work 4 u!)
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subtract c from both sides then you'll have\n\nx^2 + Bx = -C\n\nthen you can complete the square\n\nx^2 +Bx +_____=-C +_______\n\nfill in the blank with (b/2)^2\n\ni'm positive this is right...i teach high school math.
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there is a website called www.hotmath.com where they have some books that offer help on homework and explains how to do the problem step by step. \n\ni hope that may help you in geometry! \ndoctor math (google it) might help too
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Go to homeworkhelp.com and get a real live tutor. You chat with them and ask your question and they help you figure it out. Don't get too excited though because they don't give you the answer, straight up.
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http://mathforum.org/dr.math/\n\nThis is Ask Dr. Math, a website that can offer help for general math through Algebra and beyond. There are other good websites for math out online, type in keywords,  homework  math help and see all that you come up with. Eventually you will find one that can walk you through most problems. Good luck.
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http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut35_polyfun.htm\n\nhttp://www.sosmath.com/algebra/algebra.html\n\nI found these to be helpful.
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I am not sure what class you are taking, this question can be important for anything from algebra to calculus, and beyond.\n\n0.) This is kind of cheating, but usually, an exercise in the book uses something from the section that you just did.  So try to make sense of it in terms of that.  Like if you were doing quadratic equations, and the problem has an exponent of 4 or 6, think of how you could change that to a square. Example: you've just learned how to factor the difference of two squares, and the problem they give you is (x^6-25)=0.  You don't need to freak out and say "What do I do with a six?  Think about how to write the problem as something you know. Well, if you just learned how to  factor the difference of two squares, then try to find the difference of two squares.  Notice that x^6=(x^3)^2, so you get (x^3-5)(x^3+5)=0.  The solution is the cubic root of plus or minus 5. \n\nDon't be too quick to start writing stuff.  Read the problem.  Take a deep breath.  Stop and think of what the answer might look like when you are done, and also how you would know you are done.  Now see what steps you can take to get there. \n\n1.) For many expressions there is a standard form to write the expression.  This is helpful in order to see if two expressions that look different are the same.  This is the reason proper fractions are prefer ed to improper fractions, square factors are factored out from radical signs, polynomials are written in descending order.\n\n2.)Parentheses are your Friend.  When in doubt, more is better, you can always take them out later.\n\n3) Remember: My Dear Aunt Sally.  If there are no parentheses, then multiplication is the first operation, followed by division, addition and subtraction.  More complicated operations are done before less complicated, so trig functions and exponents take precedence. \n\nBe careful with trig functions and exponents.  An exponent after the argument means the argument is exponentiated first.  If you are supposed to exponentiate the result, then the exponent goes after the trig function name.\n\n4.) My favorite trick is to underline similar terms,  I will use a different number of lines for each term.  I might use one line for variables with a power of 4, two lines for variables with a power of two, wavy lines, zigzag lines.  This is a shortcut, which allows me to simplify more than one thing at a time.  I also use these underlines to group things, also you can vary your grouping symbols, parentheses, braces, brackets.  These techniques are also useful when there are nested parantheses.\n\n5.)  A quick and easy check for your work is to substitute numbers into your original expression and your final answer.  Pick easy numbers, like zero, -1, 1.  Sometimes larger numbers make more sense.  Like if I have a denominator of 23 I might pick 46 as a substitution.  Be sure to try several numbers, bith positive and negative.\n\n6.) Don't be afraid of baby steps.  The answer may not be immediately obvious, and you might need to try different arrangements of things before you see a simplification.\n\nI hope these steps are helpful, and by the way, I learned calculus before calculators became common.  I think that graphing things by hand and factoring help me see patterns that I would miss when using a calculator.  Also, I just make more mistakes with a calculator.\n\nCould just be because I am a fossil, but use the techniques that are most comfortable for you.
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No problem, i just finished a calc3 course in college.\n\nYour problem is the same as 125 * (6x^2 + 5x + 7)^(-1/3)\nYou have to use the chain rule so you get\n125 * (-1/3) * (12x + 5) * (6x^2 +5x + 7)^(-4/3)\n\nthen you can simplify how you like from there
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I wish you the best of luck, I know how hard algebra is. Here are a couple of websites that will hopefully help:\n\nhttp://www.algebrahelp.com/\nhttp://www.math.com/homeworkhelp/Algebra.html\nhttp://www.purplemath.com/\nhttp://www.helpalgebra.com/\nhttp://www.algebra.com/\nhttp://www.mathleague.com/help/algebra/algebra.htm\nhttp://www.freemathhelp.com/algebra-help.html\nhttp://www.gomath.com/algebra.html\nhttp://archives.math.utk.edu/topics/algebra.html
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all you need to do is go to www.webmath.com, it'll help u there!\n\nI always do my math problems to that site if ever i get stuck on something! It's helpful!
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http://www.algebra.com
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If you're talking about algebra I, you are probably dealing with quadratic expressions like the following:\n\nx^2 + 7x + 6\n\nThese are a bit like a puzzle.  If the number in front of the x^2 term is 1 (as in the above example) then the puzzle is like this:\n\nLook at the 7 and the 6.  What two numbers multiply to 6 and ad to 7?\n\nConsider all the pairs of numbers that multiply to 6\n\n1,6 or 2,3.  Which pair adds to 7? The 1 and 6.\n\nSo the above equation factors to (x + 6)(x + 1)\n\nAnother example is x^2 - 6x - 16\n\nThe ques ion becomes what two numbers multiply to -16 and add to -6.\n\nThe pairs of factors of -16 are \n+ or - 1 and 16\n+ or - 2 and 8\n+ or - 4 and 4\n\nWhich pair of these factors add to -6?  With a little checking you can see the pair is -8 and +2\n\nSo this equation factors to\n(x - 8)(x + 2)\n\n\nThis even works for equations like the following:\nx^2 - 16\n\nWhat you have to remember is that this can be re-written as\n\nx^2 + 0x -16\n\nSo, what multiplies to -16 and add to zero.  Use the last example and you should see this one for yourself.\n\nGood luck.
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i are in class avansed of algebra i have algebra2 if you traslate this to english is that i don't speak much english please my homework is for tomorrow or have a F : yo habia olvidado limpiar los muebles de mi casa y me enferme yo y mi hermanito es por eso que no voy a dejar ni una sola cosa sin limpiar
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Use the following four steps to solve a quadratic equation, in this order:\n\nStep 1: Guess the answer\n\nIf x^2=0, can you guess the answer?\nIf x^2=1, you can guess, but remember that there may be two answers. (1 and -1)\n\nYou can tell if you are guessing right by plugging back into the original equation. If it worked, you're done.\n\nIf you can't guess in 30 seconds, you are done with Step 1. Go to Step 2.\n\n\nStep 2: Try factoring\n\nx^2 + 4x + 4 = (x+2)(x+2)\n\nRemember that the constant term of your factors has to multiply to the constant term of the quadratic. \n\nFor example, if you have x squared plus something plus 6, remember that your constant terms must be multiples of 6. \n\nTry:\n\n(x + 1)(x + 6)\n(x - 1)(x - 6)\n(x + 2)(x + 3)\n(x - 2)(x - 3)\n\nYou just ran out of factors of 6. If this didn't work, go to step 3.\n\n\nStep 3 -- Complete the Square\n\nOne important thing to remember about completing the square is that it does exactly the same thing as the quadratic equation. Pick either Step 3 or Step 4 as your last step. Guessing and factoring don't always work because you can't always guess and you can't always factor. But completing the square and using the quadratic formula will always find the answer if there is one.\n\nSuppose you have \n\nx^2 - 6x - 16 = 0\n\nHere's how to complete the square:\n\n#1. Move the constant (whatever it is) to the right side\n\nx^2 - 6x = 16\n\n#2. Find half of the coeficient of the x term and add the square of that number to both sides of the equation:\n\nThe x term here is -6x\nThe coefficient is -6\nHalf of -6 is -3 (Remember this number -3)\n-3 sqared is 9. Add 9 to both sides of the equation:\n\nx^2 - 6x + 9 = 16 + 9\n\n#3. If you did #2 correctly, then the left side is a perfect square and the constant term is -3 (remember -3?)\n\n(x - 3)^2 = 25\n\n(If you're not sure, multiply it out and see if you get what you had before.)\n\n#4. Take the square root of both sides. Remember, it could be negative or positive.\n\nx - 3 = 5\nx - 3 = -5\n\n#5. Solve your two equations\n\nx = 8\nx = -2\n\n#6. Put your answers back into the original equation and see if you got the right answer. \n\n\nStep 4. \n\nIf you did Step 3, you already have the answer, and you're already done. If you didn't do Step 3, use the quadratic formula to get the answer. You can find the quadratic formula here:\n\nhttp://en.wikipedia.org/wiki/Quadratic_formula\n\nMemorize the quadratic formula and never forget it.  Write it on your forhead until you have it memorized.
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http://www.aaamath.com/ There you go!! Hope that helps.
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im taking Trig. try finding a homework helper web page. or go to the book that ur learning from web page because the majority of the times they have practice help on there.