Converting right ascension with latitude and declination with longitude.?
922469
I found this very easily on the Internet.  You could have done the same thing.\n\nhttp://liftoff.msfc.nasa.gov/academy/universe/RADEC.HTML
360089
949,04\n\nYou can type the following as a search in g**gle:\n\n$1689 in gbp\n\nIt does all sorts of computations and conversions for you. Curency conversions, miles to kilometers, plain arithmatic, etc.
199351
I haven't worked with this in a long time and I'm not sure this will work, but try starting w/ this:\n1) Define an equation that describes the " ∞ " with polar coordinates (something like r = C1 - C2*theta);\n2) If L is lengh, delta.L = delta.theta / (2 pi) * r\nand dL = r/(2 pi) dtheta  ;\n3) substitute for r and integrate from 0 to 2pi (or the necessary for one complete " ∞ ".\n \nProbably you'll find more than one mistakes here, but I think the general idea is correct.
728902
This can be done easily using a scientific calculator or there are many angular / decimal tables in Trig text books or many machinists handbooks or machinists guides.\n\nwww.industrialpress.com/en/tabid/63/Default.aspx
443897
longitude 20 00 N and latitude 77 00 E
80562
Relatively easy way\n\n0.008895478\n0.012222453\n\nmultiply both by 100 (ie, move decimal point two spaces to the right):\n\n0.8895478\n1.2222453\n\nObviously first one is less.
1183908
There is no such equation. \n\nThe post office keeps a database with the latitude and longitude of each post office -- each zip code. You can look up the latitudes and longitudes of the zip codes and use them to compute the distance. For a spherical earth:\n\nLet Lat1 and Lon1 be the latitude and longitude of the first post office. Let Lat2 and Lon2 be the latitude and longitude of the second post office. Then compute the angles:\n\ndLon = | Lon1 - Lon2 |   (make sure to account for any difference in the east- or west- of Greenwich longitudes)\n\nD = 2 arcsin[ sqroot{ sin^2((Lat2 - Lat1)/ 2)+ cos(Lat1) cos(Lat2) sin^2(dLon/2) } ]\n\nIf you computed D in radians, convert D from an angle to a distance (in miles) using the equation: \n\nMiles = D * 12450 / pi\n\nIf you computed D in degrees, use the equation:\n\nMiles = D * 69.167
756719
D.C. = Latitude:  38° 53' North \n            Longitude:  77° 02' West  \n\nHawaii = Longitude: 154° 40' W to 162° W \n               Latitude: 16° 55' N to 23° N\n\nLondon = Longitude: 51° 32' N\n                Latitude: 0°  5' W \n\nParis =  Longitude: 02.20E\n              Latitude: 48.50N
353272
Any language can be used. The basic arithmetic operation is to multiply the decimal by 60 every time, until such time there is no decimal portion left. The C code for the same would look like;\n\ndouble longitude = ...;\nint long = (int)longitude;\nint min;\ndouble minutes = longitude - long;\ndouble seconds;\nint sec;\nmin = minutes * 60;\nseconds = (minutes * 60) - min;\nsec = seconds * 60;\n\nDo not know Java syntax, so cant help you with that...
601534
To convert from polar to cartesian co-ordinates, yousimply use:\n\nx = r cos (theta)\n\nand:\n\ny = r sin (theta)\n\nYou have radians - so make sure your calculator is set to radians.  This gives:\n\nx = 15 × cos (2.75) = -13.864...\ny = 15 × sin (2.75) = 5.7249...
1173388
longitude and latitude
142836
Sorry dude I can't able to arrive at a answer.\n\nThis conversion tool looks good check it.
468833
Latitude: 42.12 N, Longitude: 71.18 W
127882
Where are you, Say to me so that I can tell you.\nIf you are in Riyahd or Kuwait in The Arabic Gulf it will be the time their minus three to give you the answer. If you are in Cario or Alexandria in Egypt you will sbtract the time their by two. To know the number you will subtract the time your country are in by, you need to count how many longitude lines are there after The Prime Meridian which, runs along Greenwich City near London in U.K, Every line to east +1, and every line to west -1. So see on a map The Prime Meridian, then count the longitude lines till you reach your city or country. USE THE RULE EXPLIANED IN THIS ANSWER! \nN.B: READ THE WHOLE ANSWER TO KNOW THE RULE!!!
1116036
that is the date? what is its longitude and latitude? this will be required to compute the suns position in the sky
549504
Search http://www.download.com for converteors\n\nXLMan
939515
There is possibly something wrong with your GPS data.  The interpretation of the points may be your error source as it is hard to locate certain items with Google Earth.\nI first ran the Longitude points with a Geodetic Program that can run the Inverse of two geodetic points on an ellipsoid.  I used the WGS84 datum. I noticed that you did not include the latitude and the elevation of the point pair in question.  That is ok.  The program kicked back an Ellipsoidal distance of 1, 040.528 meters and a Mark-to-Mark distance of the same value, 1,040.528 meters.\nI then did a check on this value by using the Mean Radius of the Earth and converting the difference in the Longitude values to radians and ran it through my Geodesy equation and came up with a value of 1039.36 meters.  Pretty close to my program's value.\nYou can always do a check by pacing, pulling a tape, or using some survey techniques to get a fix on the distance.\nRemember, that GPS is referenced to a mathematical Ellipsoid and there are complex equations that determine fixed locations on Earth and the precision and accuracy of the points defined.\nGood night and good luck.