any link on how to construct a pythagorean spiral on a graphical calculator?? its very urgent!!!?
926476
You could start here and write a program:\nhttp://www.math.nmsu.edu/~breakingaway/Lessons/spiral_K_1/spiral_K.html
894799
Use a cyclical function, like a sine function, but add a third dimension, z, and have the value of z oscillate with the same wave length at which y oscillates.  Like y=sin x, and z=cos x.  This will produce a spiral around the x axis.
589334
http://aleph0.clarku.edu/~djoyce/mathhist/mathhist.html
458048
Or you can do this:\n\nhttp://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabolaTangents.png\n\nto form a parabola out of many straight lines.
459338
Go to http://mathworld.wolfram.com/Cosine.html
104581
It takes practice!  And its like a puzzle.  Just use the main trig identities as reference and a good math tutor.  Unfortunately, this place isn't the best place to ask that kind of question because we are limited by text explainations and trig identities need a lot more than that!
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There's a pretty good online grapher at http://id.mind.net/~zona/ezGraph/ezGraph.html that you can use.  It works basically like a graphing calculator.\n\nIt appears this function should be an upside-down sign curve with an amplitude of 10 and a vertical shift of 9, which means the center of the graph will be at 9, it will go up to 19 and down to -1.  It's not 100% clear what you mean by what you have written after sin.  If you mean the sine of 2pi/15 times x (since the minus zero is irrelevent), you would have a period of 15, so you'd complete 1 complete cycle at 15 radians; the halfway point would be 7.5 radians.
148719
You just draw a graph yourself.\n\n! ain't gonna graph for you. Rather ! love calculus.
878923
Make a program on your calculator.\nView the snippet in the link for code.
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Build an abacus.  \nArrange 10 beads on a piece of piano wire.  Every fifth bead should be a different collor.\n--oo--oo0-oooo0--\nMake a few more strings and mount them together in parallel or inline with each other.\n------ooooxoooox\nooo----oxoooox--\n--ooooxoo----ooo\n\nA really cool math based model would be a display of geometric shapes.\n\nYou could go to the matherworld site and print out some patterns for the platonic solids.  Then cut them out and fold them together.  The collection can be displayed in a couple of ways.  The easiest would be to mount them on straws poking out from a block of styrofoam.  The most dramatic would be to arrange them to hang in a mobile.  If you want instructions on making a mobile, send an email to samphelps at yahoo.\n\nPlatonic solids are the 3 dimensional shapes where all the sides are the same.  The most familiar is a cube where each side is a square.  Another is the tetrahedron where each side is a triangle.
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What are you trying to do?\nPlease ask your question again with a few details that would help us help you.\nWhat format is the 'math page' in?\nWhere is the website?\nWhy do you need to upload it? (If it's for university or similar it's different than if it's a just a 'standard' website).
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http://www.bymath.com\n\nand this is my weblog it is new but it will been good in future http://bymath.blogfa.conm\nDont forget comment!!!
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I posted these sources earlier to someone else who was looking for math help.\n\nGood Luck!!
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I'm a fan of MathWorld: http://mathworld.wolfram.com/\nIt's affiliated with the software package Mathematica.  Also at the same site is ScienceWorld: http://scienceworld.wolfram.com/
900535
This type of problem will eventually seem EASY for you, so hang in there.  Let's begin by stressing that "a circle with radius 5" is simple to draw -- I recommend marking the 4 points that are "5 units" above, below, right and left of the center point.\n\nThat is, mark (-6,7) on your graph paper, then sketch four more points at (-1,7), (-11,7), (-6, 2) and (-6,12).  "Connect the dots" by drawing all 4 quarter-circle arcs between the points.\n\nThe equation for any circle -- in "rectangular coordinates" (which means (x,y)) -- is normally:  (x-a)^2 + (y-b)^2 = r^2, where (a,b) is the center point and r is the radius.\n\nBut what you're hoping to find is the equation of a circle in "polar coordinates" (which means (r,theta)).\n\nThe reason a sample triangle was drawn inside the given circle (I'm assuming you're looking at a textbook) is to illustrate the relationships among x, y, theta and r.  Let's inspect, using rules from trignometry:\n\nx = r cos (theta) + a\ny = r sin (theta) + b\nr = sqrt ((x-a)^2 + (y-b)^2)\ntheta = Arctan ((y-b)/(x-a))\n\nwhere (x,y) is any point on the circle, (a,b) is the circle's center, and r is the radius.\n\nThe formula for theta that I just provided may be precisely what you are looking for.  It works simply by first finding the "slope" of the line connection (x,y) and (a,b), then taking the inverse tangent of that slope, which 'converts' it to an "angle."\n\nHope this helps!
920579
use synthetic  divsion method \ni think this link would help\nhttp://www.purplemath.com/modules/synthdiv.htm
88080
there is one you can use for A LITTLE BIT of math/algebra. it's www.algebrasolutions.com