Which should be more conductive, 1.0 M KCl  solution or deionized water? Explain.?
924596
The KCl, definitely.  Conductivity in water is greatly enhanced by the presence of ions.  Deionized water actually has fewer ions in it than ordivnary tap water, so it's a really terrible conductor.  KCl, on the other hand, dissolves into K+ and Cl- in water, so there are a whole lot of ions in a solution of KCl.
704658
You're not quite right. The dielectric of the solid (ice) is HIGHER than the dielectric of the liquid (water).\n\nAlthough water has a reasonably high dielectric constant (because the water  molecule has a dipole moment and so water can be polarized to virtually eliminate the field's effect), it still can act as a conductor because it always contains ions (OH- and H+ are always there, and also things like Cl- and Na+ are usually present) which are highly mobile.\n\nBeing conducting means that there is a current present whenever you apply an electric field, and the current means you have charge "leaking".  Yes, the reason water conducts well is because it is liquid, so ice is not a good conductor (though ice with a layer of liquid water on the outside would still probably allow quite a bit of current to flow).\n\nIn ice the water molecules have all lined themselves up in a fixed structure where the hydrogen bonds can be maximally satisfied. This means the dielectric relaxation time is higher, and the molecules can't realign themselves to a changing electric field easily. This corresponds to a higher observed dielectric constant.
444550
The difference in solubility of the components allows for separation.  I don't remember the specifics, but that is the reason.  Water will not have a big enough difference.
218353
It depends.\nThe salt has to dissolve in water.\nThe more ions / cm3 in te water (never mind the kind),\nthe better the electric conductivity.
874059
I think that isolating potassium is the wrong approach.  Potassium metal reacts with atmospheric water to form KOH and hydrogen gas.  If you accidentally get water on the metal the reaction is so vigourous that the metal will catch fire, which will be dangerous.  \n\nTry a different approach.  Dissolve KCl in water and add a molar equivalence of Silver iodide, AgI, also dissolved in water..  AgCl is nearly insoluble in water (~0.9 mg/L at 10C)  and will precipitate out, leaving KI in solution.  Filter out the AgCl and evaporate the water, leaving solid KI.  \n\nThe two biggest problems starting with KNO3 are:  It will be nearly impossible to salt out the nitrate because of its high solubility in salt form, and two, many nitrate salts, particularlyof metals, are highly explosive and dangerous.  KCl is cheap and plentiful, so why not just buy some?
1083308
I think water you know that the tap wtaer is hard water i.e it contains excess of Ca++ ions and also the water is made up up of h20 which is ionic in nature and now the the original part when the person touches the switch cause the person is covered all of his body with hard water which is a 98.456% conductor of electricity he gets a svere shock also you should be knowing humanbody is also a conductor of electricity blood is acetic so both media media make good conductors of electricity and no obstruction is observed. In this way the person may also die.\n so always when working with electricity wear rubber slippers which are insulators (dont conduct current).\n GO ON KEEP ASKING
685785
Yep- they're all right.  The salt just carries electricity through the water.  Electrolysis would work by adding any ionic compound like salts or acids to the water.  Interesting- that's why you would never get electricuted in pure water because there's nothing in pure water which carries electricity.  Water in nature or in your house has minerals and salts in it which do conduct.
884983
Salt (or more specifically, Sodium Chloride salt) is a strong electrolyte, meaning that when dissolved in water it will completely break up into ions (Na+ and Cl- ions).\n\nPure water, by itself, does not conduct electricity, but when you dissolve an electrolyte in it, an electric current can pass through the solution.\n\nIn order for a electric current to flow there must be charge carriers which can move.  Pure water does not have these charge carriers, but after a salt is dissolved and ions are present in solution, the solution becomes conductive.
788768
Just the usual stuff.  Use an electrolyte (H2SO4/HNO3), a couple of electrodes, a reduction table of half cell potentials, and some electricity.
1108709
Safe to drink... or safe to be around in the presence of an electrical current?\n\nWell zero conductivity would be ideal, because it would be evidence of zero ion presence in the water.\n\nHowever the water could be very conductive and still be "safe" to consume. Salt (Na-Cl) for instance mixed into the water would make turn the water into an ionic solution. It is therefore now has conductivity. But as we all know... we can consume salt water "safely" if it is consumed at appropriate amounts.
961365
ch3cooh is Ethel alcohol.\n\nNa cl is salt.\n\nSalt is the better conductor, and the higher concentration of .2 moles is the better conductor.\n\nWilliam
919591
You need to know a lot more about it before you can answer the question.  Potassium chloride, KCl, is a salt.  It is very similar to table salt, NaCl, in behavior and properties.  If you dissolved a little bit of it in water, you'd have an unsaturated solution.  If you dissolved so much of it in water that any more KCl you added would fall to the bottom without dissolving, you'd have a saturated solution.  If you then heated it up and dissolved the remaining KCl (because the solubility of KCl in water increases with temperature), and then cooled it back to room temperature, you'd have a supersaturated solution.  But without knowing the concentration of the solution, as well as the solubility of KCl in water, you can't answer this question.
706351
KCl(aq) + AgNO3(aq)  --> KNO3(aq) + AgCl(s)\n\nNet ionic: Cl-(aq) + Ag+(aq)  --> AgCl(s)\n\nNa2SO4(aq) + Ba(NO3)2  --> 2NaNO3(aq) + BaSO4(s)\n\nnet ionic: SO4(-2)(aq) + Ba(+2)(aq)  --> BaSO4(s)
1001225
"gods_my_ruler" obviously has NO IDEA what he is talking about.\nOf course you can, easily split H2O into H2 and O2 gas through a process known as "electrolysis".  Actually, 12 volts is way over the minimum voltage required to electrolysize water.\nYou will also, of course, need to use some form of electrolyte (commonly, "salt", or Na/K Hydroxide are popular choices) in order to help the water conduct electricity since pure water does will not conduct at all.\n\nBut you question was about controlling the current flow.\nI assume you are having problems with the current getting too high and overloading your power supply?\nFor starters, I would downgrade your power source to something with a little less voltage if possible.\nYou can also use combinations of small (on the order or just a few ohms or less) resistors wired in series/parallel in order to give you just the right resistance you are looking for in order to decrease the current through the cell.\n\nWithout more specifics about the problem you are having, that is about all the advice I can give for now.\n\nRemember, it is not the voltage that controls the H2 production rate, it is the current.\nAccording to Ohm's Law,\nV = R*I\nso a higher voltage (with a given resistance) does mean a higher current, but the same goal could be achieved with a lower voltage and much lower resistance.\n\n\nEDIT:\nIn reply to "kurticus1024",\n\nUsing a reostat or variable resistor would work to dynamically control the resistance in the circuit, and thus the current through the cell, however, most reostat which I am aware of have a high minimum resistance (i.e.  even when turned all the way to the minimum setting, they are far from zero ohms) so by doing this, you will be DRAMATICALLY increasing the resistance through the cell and intern virctually cutting your cuttent to just a few miliamps.  A few miliamps is fine for many common electrical components whcih the reostat was designed for but if you intend on produce Hydrogen, you are going to have to wait a VERY long time to get any sizeable amount.
1110280
Depending on quality of the distilling process. The conductivity should be very near 0. Pure water does not conduct electricity, it is the impurities such as iron that conduct.
360112
Why dont you just try going to google search and just type "NaCl Electrodialization". You should get more info. than you think you'ld get.
815817
You must have the CELL CONSTANT to do this properly.\nResistance and Conductance are reciprocals.   But to go from\nConductance to ConductIVITY, you need the Cell Constant.\nIt's different for each probe, and should be easy to find on the probe you're using.   Find that and get back to me.