How do I determine what 2 numbers will sum to 50 and give the largest possible product?
928789
numbers are 25, taken twice.\n\nway to prove it is to write x*(50-x), take a derivative and set it to zero.
274779
25 + 25 is equal to 50
44918
Okay. First of all, we have 3 sets. We can split them into 3 in this format:\nStep 1:\nMultiply 3000 * 854. You should get the following:\n2562000.\nOur next step is to multiply 2562000 * 9.\nStep 2:\nMultiply 2562000 * 9. You should get the following:\n23058000.\nFinal Answer:\n23058000 is the product of 3000, 854 and 9.
605852
multiply n-m by 0.737562
543957
The answer is 480. You can go to Progams, then Accessories, and then calculator.\n\nOr, you can multiply 24 times 2 which is 48 and add a zero to the end so it becomes 480
762401
50 grinches plus 2?\n\n52?
1178350
P=x^2+5x-50\nP=(x-5)*(x+10)\n\nif x=5 then \n\nP=(5-5)*(5+10)\nP=0*15\nP=0\n\nso x has to be greater than 5\nx = >5
648976
yes it's correct\nu can use the arithmetic series formula \nor do this\n\n1 + 100 = 101\n2 + 99 = 101\n......\n50 + 51  = 101\n\nSince there are 50 pairs of these numbers and their sum is always 101\nIt's 50 x 101 = 5050
635110
For doing squares of numbbers ending with 5, here it is\n\ntake the numbers before 5 and multiply it by its next number and write product followed by 25 e.g.\n65*65 = (6*(6+1)) and 25 = 6*7 and 25 = 4225
378781
-1*100\n-2*50\n-4*25\n-5*20\n-10*10\n~or~\n1*-100\n2*-50\n4*-25\n5*-20\n10*-10
754767
Assuming that the two numbers are positive, the best you can do is take double and triple 850.  Both numbers will be divisible by 850, and since neither can be divisible by the other they need each to be multiplied by numbers which are not divisible by the other.  The smallest numbers that work are 2 and 3, so 850 * 2 and 850 * 3 are the smallest solutions to your problem.
553854
I came up with eight possible answers.  I'm assuming what you are saying is that each digit must be a prime number (e.g. in the set {2,3,5,7}) It's pretty obvious that the product will end in 5, and neither of the multipliers can end in 2.\n\nUsing an Excel spreadsheet I came up with the following answers:\n325 x 73 = 23725\n337 x 75 = 25275\n355 x 77 = 27335\n375 x 73 = 27375\n575 x 57 = 32775\n735 x 35 = 25725\n737 x 75 = 55275\n775 x 33 = 25575
274854
The difficult thing here is reading and writing the numbers. They must be transformed from ASCII and then the result transformed back to ASCII.I found a program that calculates the sum of 2 numbers.I hope it helps.
1025788
do you mean 18 times the sq rt of 50, that would be 127.3\nthen subtract 21 times sq rt 40 divided by 3 times sq rt 2\nOr, is all of the subtraction part above the line\nSee if you can rewrite the problem
1105884
Say x is the first number, y is the second number.\n\nThus, x+2y = 11 and 2x + 3y = 50.\nSolve for x in the first equation: x = 11 - 2y\nSubstitute this in for x in the second equation: 2(11-2y)+3y = 50\nDistribute the 2: 22 - 4y + 3y = 50\nSimplify: 22 - y = 50\nSolve for y: y = 22 - 50 = -28\nSo y is -28. Because x = 11 - 2y, we can plug in 67 for y and get x: x = 11 - 2(-28) = 67.\n\nThe answer: the first number is 67, the second number is -28.
253073
Each answer is 4 more than the sum of the previous two terms.  The 49 is a misprint and should be 59.\n\n(5+11) + 4 = 20\n(11+20) + 4 = 35\n(20+35) + 4 = 59\n\nso,\n\n(35+59) + 4 = 98\n(59+98) + 4 = 161
971892
no of customers=-50(0.25n)+1000\nwhere n is element of natural numbers