please help.  use then substitution method.?
923416
Sometimes I like math.  What you need to do is add 1 to both sides of the equation for x=3y-1\nyou will be left with (x+1)=3y you should then divide the 3 from both sides... afterwards you will have (x+1)divided by 3 equals y or (X+1)/3=y\nFor the other part x+2y=9 you should substitute (x+1)/3 for the "y"\nNow solve x + 2((x+1)/3)=9\nx+(2x/3) +(1/3)=9\ntake from there
573927
single replacement, double replacement, decomposition, synthesis
1165079
Create a user-defined function: (make sure to paste this in a module for the workbook, not in a sheet)\n\nFunction CountChars(Txt As String, Char As String) As Integer\n    CountChars = Len(Txt) - Len(Replace(Txt, Char, ""))\nEnd Function\n\nThen use the new function:\n=countchars(lower(A1),"a")&" "&countchars(lower(A1),"e")&" "&countchars(lower(A1),"i")&" "&countchars(lower(A1),"o")&" "&countchars(lower(A1),"u")\n\nAs written, it will return an answer of 1 2 0 0 0 for the string "statement." One "a", two "e" and 0 for the other three vowels.\n\nYou should be able to come up with a better formula to use it.
695856
I'll try and help you with this one and give you details on how to solve others.\n\nTo solve by substitution you must first solve for a single variable.  Take the first equation, for example and solve for x.\nx - y = 3\n\nAdd y to both sides:\nx = y + 3\n\nNow substitute this equation for x into the second equation:\n3x - 2y = 3\n3 (y+3) - 2y = 3\n\nMultiply the 3 through:\n3y + 9 - 2y = 3\n\nCombine like terms:\n(3y - 2y) + 9 = 3\ny + 9 = 3\n\nSubtract 9 from both sides:\ny = 3 - 9\ny = -6\n\nNow solve for x by substituting this back into your original equation:\nx - y = 3\nx - (-6) = 3\nx + 6 = 3\nx = 3 - 6\nx = -3\n\nSo your solution is x = -3, y = -6.\n\nIt's a good idea to double check your answer:\nx - y =? 3\n-3 - (-6) =? 3\n-3 + 6 =? 3\n3 = 3 <-- check\n\n3x - 2y = 3\n3(-3) - 2(-6) =? 3\n-9 - (-12) =? 3\n-9 + 12 =? 3\n3 = 3 <-- check\n\nNow to answer the second part of your question.\n\nIf you get to a solution with actual values (like we did) then you have an *independent* system of equations.\n\nIf you get to a solution like y = y or x = x or n = n, then you have a *dependent* system of equations.  An example of this would be:\nx = y + 1\n2x = 2y + 2\n\nHere you can see that the second equation is just double the first, so it doesn't give you any more information.  If you substitute x = y + 1 into the second equation you get:\n2(y + 1) = 2y + 2\n2y + 2 = 2y + 2\n2 = 2 <-- dependent system (x or y can be anything and the system is true)\n\nThe last case would be an *inconsistent* system.  This is when you get to an answer like 2 = 7.\nx = y + 1\n2x = 2y - 7\n\nHere when you substitute in x = y + 1, you get:\n2(y+1) = 2y - 7\n2y + 2 = 2y - 7\n2 = -7 <-- inconsistent system (x or y can be anything and the system will never be true).\n\nSo in summary, with your example:\nx = -3 \ny = -6\nAnd since you have a result, the system is independent.
245176
u*(u-2)+v*(u-2)\n(u+v)*(u-2)
784164
sure you can use that syntax and it's correct this way:\nwrite(arraylist[x]);\nusualy this is used with a for clause\nfor i:=0 to n do\n write(arraylist[i]);\nbut if you put a pice of code when ur using this i can help you fix your errors.
770678
Try to substitute something in its place.
392646
You usually do this by using a programming language and comparing the input to a regular expression.\n\nLook up "regular expression tutorial" in Yahoo search and you'll find more information that you probably want  :)
1174987
If I get your question right, this is what you want.\nYour perl file is actually some kind of a template where there are placeholder variables whose values will be known at run time from another file, and you need some way to replace the correct values in their correct places.\n\nI once had a similar requirement and I resolved it by writing another program (you can write this one in perl, I chose java) that takes the template you have and create a new perl script with the placeholder variables replaced with those in the other file.\n\nYou need to execute this newly generated file now.
76546
How about using the char array that is the input string, converting to uppercase, then using the chars as indexes into your substitution array of chars? Use the ASCII table to help you.\n\nchar subst_array[] = {'Z', 'Y', 'X', ...};\n\nconversion to uppercase: if (char > 90) char -= 32;\n\nfor (i = 0; i < strlen(input_string); i++)\n  input_string[i] = subst_array[input_string[i] - 65];\n\ncout << input_string;
814204
To quote the wikipedia:\n\n"Replace x by (x + y) / 2 and y by (x – y) / 2 in the product-to-sum formulae."
281772
You need 2 equals signs:\n\nif (toBeRemoved.left = null || toBeRemoved.right = null)\n\nshould be\n\nif (toBeRemoved.left == null || toBeRemoved.right == null)\n\nOne equals is for assignment, 2 for comparison.
878923
Make a program on your calculator.\nView the snippet in the link for code.
906761
Try this:\n\nvoid addIt(int* begin, int* end, int x)\n{\nint* p;\nfor (p=begin; p!=end; ++p) {\n*p = *p + x;\n}
92611
Use the following syntaxis:\n\nLike *[#]*
830317
f1>f3>f2>f5>f4\nJust replace the variable n in  Excel's function and compare the result.
538319
A -> B\nB -> C\n...\nT -> U\nYou (U) -> V\nV -> W\n\nSo, You -> V