Can you please show me how to do this problem?
917018
1. Find the reciprocal\nSo...IT'd be\n2b/-7 x 9/7=\n2b(9) / (7)(-7)=\n18b / -49\n\n49x divided by 7/2. Multiply by the reciprocal\n49x(2/7)\n98x/7=\n14x\n\n54x^2  divided by -9/5. Multiply by the reciprocal\n54x^2  times 5/-9   =\n270x^2/-9 =\n-30x^2
263286
the problem you presented above can be represented as,\n\n(8x^8/2x^2) + (16x^6/2x^2) - (12x^3/2x^2)\n\nthen you can simply divide each of the term\nyou'll get\n\n4x^6 + 8x^4 - 6x
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
101541
This is kinda wierd without drawing it out, but I'll try to explain and you can come up with the picture.\n\n1)  Start Program\n2)  Accept Input\n3)  Add 1 to counter\n4)  If counter is not equal to 3; go to #2\n5)  If N2 > N3, do #6-8; if not, go to #9\n6)  Move N3 to a hold field\n7)  Move N2 to N3\n8)  Move the hold field to N2\n9)  if N1 > N2, do #6-8 with the N1 & N2 replacing each other\n10) if N2 > N3, do #6-8\n11) print them
1056171
Try www.purplemath.com it shows you how to work out problems step by step
1166133
Multiply both sides by R+r\nI(R+r) = E\nDistribute the I\nIR + Rr = E\nSubtract IR form each side\nRr = E - IR\nDivide both sides by R\nr = (E-IR)/R
429835
ok, u have to use distance formula\n\nsqrt[(-4-(-7))^2+(c-7)^2]=5   \nsquare both sides\n[(-4-(-7))^2+(c-7)^2]=25      \nadd the stuff in the parentesies\n[(-3)^2+(c-7)^2]=25           \nexponents\n9+(c-7)^2=25                  \nsubtract from both sides\n(c-7)^2=16                    \nsquare root both sides\nc-7= +/-4                     \nadd to both sides\nc=11 or c=3
309995
do this\n9x-3/4y=1  move 9x to other side\n3/4y=-9x+1 get rid of 3/4, by7 multiplying everything by 4/3\ny=-9x*4/3 +1*4/3\ny=-12x+4/3
336716
Try this tutorial below...
137681
Ok...\nI see what you are doing...\nYou merely substitute the number in for x...\nso the problem becomes 6-2*(-1)\n6+2\n8
1127430
try this one http://www.algebrahelp.com/
1094108
Use a calculator and raise it to the 1/3 power.\nDon't try to do it by hand...
796133
Try this. It's a tutorial on how to do one (below).
981023
Problem: 4(3c + 1) = -(5-c)\n\nFirst step is to distribute.\n     4(3c) and 4(1) = 12c + 4\n     -(5) and -(-c) = -5 + c (negative times a negative is a positive)\n\nStep #2: Write out the new problem.\n     12c + 4 = -5 +c\n\nStep#3: Get the variables to one side.\n      12c +4 = -5 + c\n         -c                   - c\n--------------------------------\n      11c +4= -5\n              -4      -4\n----------------------------\n       11c = -9\n\nStep#4: Divide:\n       11c = -9\n      -------   ------\n        11       11\n         c = -9\n               -----\n                11
836789
All this problems are solved using the equation:\n\nHeat = M * Cp * DeltaT\n\nPlug the numbers, check wich one is OK.  Oh, and watch the units.
1020883
i am sure you can find a math tutor that will be happy to help you when you explain what the problem is.\n\nso what IS the problem, anyway?
1889
I have included several links that show how to do this.  The first one is the most helpful, I think. The others are just to give you a little more background info or other examples.