What is the wavelength of electromagnetic radiation if its frquency is 3.2 x 10^-2 Hz?
928544
KNOWN:\nf = 3.2 x 10^-2 Hz\nc (ie speed of light) = 3.00 * 10 ^8 m/s\n\nFIND L (AKA wavelength)\nL m = c m/s  /  f Hz\n= 3.00 * 10 ^8 m/s  /  3.2 x 10^-2 Hz\n= 9 375 000 kilometers\n\nAre you sure its 10^-2 Hz? That seems unlikely
854524
Radio frequency, or RF, refers to that portion of the electromagnetic spectrum in which electromagnetic waves can be generated by alternating current fed to an antenna
422440
the wavelength is half...\n\nvavelength and frequency are inversely proportional
769972
DeltaE=(6.626x10^-34) (3.0x10^8)/ lamda\n\nlamda = (6.626x10^-34) (3.0x10^8)/ DeltaE\n\n-------- = 1.978x10^-25 / 5 x 10^-8\n\n= 3.98 x 10^ -18m\n\nYour answer for wavelength is correct.\n\nFor frequency, it is equal to  c / lamda\n\n= 3 x 10 ^8 m/s  / 3.98 x 10^ -18m = 7.54 x 10 ^ 25 Hz.\n\nChecking.\n\n10^ 8 divided by 10^ -18 is  10^ 26 and 3 divided by 3.98 is approximately ¾ = 0.75.\n\nHence the answer is near 0.75 x 10^26 or 7.5 x 10^25.
910724
In electromagnetic radiation, the lower the frequency, the lower the energy (per photon).  So, radio frequencies have the lowest energy photons.
1031384
f=1/period=1x10^9 hz= 1 GHz\n\n1 GHz- microwave/radio frequency (rf)
708133
The frequency is irrelevant -- all radio waves travel at the speed of light.\n\nSo 8.00x10exp7 divided by 313,000 km/sec would be 255.6 seconds, or about 4.25 minutes.
164646
You mean a 'frequency of 5.10^12Hz'\n\nCan you work it out yourself?:\n\nRemember that the speed (v) of the wave is 3×10^8 m/s,\nand that the wavelength is given by v/f\n\n[Edit: Darn, Kirchwey - don't do Glow's homework for her! ;-) ]
939439
The frequency is irrelevant, just divide the distance by the speed of light, which is 3 x 10^8 meters per second.\n\nIf the distance between the two planets is approximately 8.00 x 10^7 km, that is 8.00 x 10^10 meters, so:\n\n8.00 x 10^10\n----------------\n3.00 x 10 ^8\n\n= 8/3 x 10^2\n\n= 2.667 x 10^2\n\n= 266.7 seconds
479233
The energy of the incoming photons is given by Planck's relationship:  energy = Planck's constant * frequency.\n\nYou are given the wavelength, not the frequency, so you need to know that for any wave, the wavespeed = frequency * wavelength, so frequency = wavespeed/wavelength.  For photons, wavespeed = c.\n\nh = 6.626068 × 10^-34 34 m^2 kg / s (Planck's constant)\nc = 2.998 × 10^8 m / s (speed of light)\nwavelength = 48.2 x 10^-9 m (given in problem)\n\nPutting this together, the energy of each incoming photon is:\n\nE_photon = h*c/(48.2 x 10^-9 m) = 4.121 x 10^-18 J\n\nThe outgoing electron has kinetic energy = 1/2 * m * v^2.  You are given both m and v:\n\nE_electron = 1/2 * 9.109 x 10^-31 kg * (2.371 x 10^6 m/s)^2 \nE_electron = 2.56 x 10^-18 J\n\nThe ionization energy is the difference in energy between the incoming photon and the kinetic energy of the outgoing electron.  Because the question asks for the energy in joules per mole, we must multiply the energy difference for a single photon/electron pair by Avagadro's number:\n\nE_ionization = (E_photon - E_electron)* N_A\n\nE_ionization = (4.121 x 10^-18 J -2.56 x 10^-18 J)*6.022 x 10^23 mol^-1\n\nE_ionization = 9.4 x 10^5 J/mol = 940 kJ/mol
777234
the wavelength will be speed/frequency=300000/100100000\n=0.002997002997002997002997002997003 kilometers \nin aproximation\n=2.997002997002997002997002997003 in meters\nor 3meters
283860
Frequency = speed of light/wavelength.\n\nMake sure you keep the units straight when performing the calculations or it may not make sense.\n\nSo for your problem its (3 x 10^17 )/200 = 1.5 x 10^15 Hz
219596
visible light has wavelengths from 400 to 700 nm. Frequency is inversely proportional to wavelength. The longer the wavelength (lower frequency), up to 700nm, the closer the color will be to red. As wavelength decreases, the color will shift through orange, yellow, green, blue, to violet at 400 nm. See; the color spectrum (more info in linked wikipedia article)
852104
The frequency in the number of times the wave vibrates in one second. \nIn your question, you probably have light.  The speed of light is 300,000km/s.  If you multiply the frequency and the wavelength, you get the speed.  That is v=lf\nThat 595nm is actually 595x10e-9m or 0,000000595m\nThe speed of light is 3x10e8m/s\nSo the frequency is\nf=v/l\nf=300000000/0.000000595\nf=504201680672268.91\nf=5.1e14 hertz
953272
f * w = c\n\nFrequency in Hertz times wavelength in meters equals the speed of light.\n\nTo solve for frequency.\nf = c/w\n\nTo solve for wavelength\nw = c/f
437661
This requires the use of doppler shift formula for a moving source and stationary observer:\n\nf = f0 ( v / ( v + u ) )\n\nf0 = actual frequency = 5\nv = speed of wave = 20\nu = relative velocity of source away from observer = -10\n(since travelling toward)\n\nf = observed frequency = 10 Hz\n\nNow velocity = v = fl = frequency * wavelength\n\nso wavlength l = v / f = 20 / 10 = 2m
168920
This is ultrasonic, not electromagnetic, so C is irrelevant.  The equation is:\nF=V/L where V=sound velocity in water (~1475 m/s), F=frequency in Hz, L=wavelength (0.0003 m)\nResult is you need 4.9 MHz or higher.