I forget what pairs are in algebra and statistics, what are they?
918264
IF you mean like an ordered pair it is a point on a graph.  An example is:  (x,y)  so you can have (3,5)  or (-7,-88)  Otherwise I'm not sure what you're talking about.
948825
First answerer correct.  \n\nBut the second set is a function, because there are no repeated x values.  If you have a component of the first set corresponding to two different components of the second, then it isn't a function, e.g. in the second set, if the next pair were (15, 5) then it wouldn't be a function because of the double result for 15.  In the first set, if your misprinted pair were (1,2) then it wouldn't be a function, same reason.
395876
Abstract algebra is the field of mathematics concerned with the study of algebraic structures, such as groups, rings, fields, modules, vector spaces, and algebras.\nLinear algebra is the branch of mathematics concerned with the study of vectors, vector spaces (also called linear spaces), linear transformations, and systems of linear equations in finite dimensions.\nIn abstract algebra, a Boolean algebra is an algebraic structure (a collection of elements and operations on them obeying defining axioms) that captures essential properties of both set operations and logic operations. Specifically, it deals with the set operations of intersection, union, complement; and the logic operations of AND, OR, NOT.\n\nCollege algebra covers Algebraic operations, Equations and inequalities, Functions and their properties, Number systems and operations.\nThe easiest one is College Algebra
774817
I can tell that nobody wants to just do this problem.  There's nothing interesting about it.  It's a typical problem that a stat student does to show understanding.  Get out your textbook and study up how to solve it.
324717
what type of statistics?
551184
its simple distributive law.\nwhat has happened is they have taken (a-2) common out of both the terms .\neg: cx-x = x(c-1)\nthe same thing has happened here with x=(a-2) and c=a^2\nso, in step 2, we have: a^2(a-2)-(a-2)\ntaking (a-2) common outside; you end up with (a-2)*((a^2)-1)\nwhihc is [3]\nthen as you know, (a^2)-1 is same as (a^2)-(1^2) and then we apply the algebraic identity (a^2)-(b^2)=(a+b)*(a-b) to get (a-2)(a+1)(a-1) which is [4]
888151
Basic math/algebra. You are taking two known numbers and finding the unknown number. \nE=P/I  solve for I    Think like simple Algebra I is X. So you want to work the problem and get a final answer x=?  or   I=?\nHope this helps.
364344
emmmmmm\n\nd. its not a fuction of x in terms of y explicitly. It needs to be rearranged
1169576
Try:\n\nhttp://www.sosmath.com/cyberexam/algebra/q001/1/1.html\n\nhttp://www.math.com/practice/Algebra.html\n\nhttp://www.glencoe.com/sec/math/studytools/prealglblr.shtml \n\nhttp://www.syvum.com/squizzes/algebra/
895454
There is no ordered pair {a,b} which solves both equations\n\nif a+b = a-b , then 2b = 0 or b = 0 and a is anything\n\nBut the second equation is not defined for b=0, no matter what a is (specifically, a/b is not defined for b=0)
405166
Try this:\nhttp://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut9_bar.htm
680155
i'd love to help but i'm having trouble with it myself\n\nuse ur math textbook it will have it unless ur math book say algebra and is red ( that my alg. book and it doesn't help) \n\nSRY good luck
441742
Assume there is a pair a_i, b_j with a non zero product.\nWrite fg= (a_i x^i + other terms) (b_j x^j + other terms) =\na_i b_j x^(i+j) is non zero.\n\nContradiction.
347066
ok, i think one will be where you have to solve a word problem dealing with alegebra. One with number sentences that have a letter on one side of the problem and letters on both sides of the problem. i could be wrong, but i'm trying to help.
857303
Hmm. It could just be something like forgetting a parenthesis. Let's go through it step by step:\n\nThe quadratic formula is:\n\n[ -b +/- sqrt(b^2-4ac) ] / 2a\n\nBecause of the +/-, we will have two equations:\n\n[ -b + sqrt(b^2-4ac) ] / 2a\nand\n[ -b - sqrt(b^2-4ac) ] / 2a\n\nThe equation is x^2 + 3x - 84 = 0\na = 1\nb = 3\nc = (-84)\n\nSo we have:\n[ -3 + sqrt(3^2-4(1)(-84)) ] / 2(1)\nand\n[ -3 - sqrt(3^2-4(1)(-84)) ] / 2(1)\n\n[ -3 + sqrt(345) ] / 2\nand\n[ -3 - sqrt(345) ] / 2\n\n7.78709\nand\n-10.7871
520168
Try this:\n\nhttp://www.algebra.com/
70409
Go back to math class and figure it out!