what is the effect on the components of f1 and f2 if the angle between the strings is increased?
917179
The question is incomplete.  Which strings?  Components of what?
296265
The inclanation angle doesn't matter. The uk only relates the normal to the frictional force. The angle only changes the normal. So, the amount of force needed to overcome the friction changes as well.
494693
The irregular protrusion of the ear adds directional distortion to the sound that the brain has learned (during infancy) to decode into a direction inkling. When you hear a sound distinctly coming from a certain direction, its because the shape of your ear helped. If you were to drastically change the shape of your ear, your acoustic directionality would be impaired.
740030
f = uN\n198 = u*(55*9.8)\nu = 0.367 for static\n\nf = uN\n175 = u*(55*9.8)\nu = 0.325 for kenetic
788892
OF2 (~104), NF3(~107), CF4 (~109.5),  BF3 (120), BeF2(~180)
872347
The axial F-S-F angles is 173 degrees and the equatorial F-S-F angle is 101.4 degrees.\n\nThe sites below has a good diagrams and additional information:
69843
work = force times distance\nW=Fs
120885
http://pubs.acs.org/cgi-bin/abstract.cgi/jafcau/1953/1/i03/f-pdf/f_jf60003a008.pdf?sessid=6006l3
467452
354246\nfe=3\nfi=5\nfo=4\ntwo=2\nfo=4\nsix=6
310148
D'Addario strings have different coloured ends
425296
Instantaneous rate of change of a function (7 words),\n\nOR,\n\nSlope of the tangent line (5 words). :P
762462
Do you mean the FEA program if so the most important factor and the one that i used to always get wrong is node number and separation. Try a simple shape with fixed point load and pivot. First try with 10000's of nodes then try with 100's then with just 2 or 3 dependent on shape the difference to the results are big. Node choice comes with experience which i am lacking!!
874727
You need to sum the components. Let Fr, Fl, Fu, and Fd be to right, left, upward, and downward directed forces, respectively. Then\n\nFx = Fr - Fl\n\nand\n\nFy = Fu - Fd.\n\nThe right and upward directions are taken as the positive direction so that the minus sign indicates that the forces (Fl and Fd) are directed to the left and downward.\n\nThe magnitude of the resulting force is then computed as\n\nF = sqrt(Fx^2 + Fy^2)\n\nand the direction can be found from\n\ncos(q) = Fx/F\n\nUse some reasoning to be sure that the direction you compute is consistent with the orientation of the force components.
160440
depends on the first angle of refelection.
41963
F=150N\nA=51 degrees\nFh = horizontal\nFv = vertical\n\nsinA=Fh/F => Fh=F*sinA = 116.572N\ncosA=Fv/F => Fv=F*cosA = 94.398N\n\nAlso, F^2=Fh^2 + Fv^2\nlet’s check:\n 22500 = 13589.031184 + 8910.982404\n22500 = 22500.013588   TRUE  (rounding error)\n\nMake sure you understand this (especially if it's your homework) :)
829645
This is half a question! Would you be able to understand this question without more info? Are answerers supposed to be clairvoyant? But... read on.\nHow was the calculated MI calculated? Experimentally?\nYou show a 3.6% error. This could be considered reasonable experimental/measurement error. Could you have ignored (perhaps you were told to ignore) some contributors to error, such as: mass of a connecting string; error in pulley diameter (exactly what length of string per revolution can be difficult to determine because of string thickness); error in effective radius of mass of pulley (if it's the pulley MI you're dealing with) or wheel. Add more information to this Q via the "Additional Details" option and you may get a better answer.
706798
The sound energy is being dissipated uniformly in all directions.\nThe intensity of the sound energy decreases inversely to\nthe distance squared.\n\nSo from a location 78m versus 22m, the decrease in intensity\nis a factor of (22/78)^2.  And teh actual intenisty is then\n\n3x10^-4 x (22/78)^2.