What is a formula for measuring the mass of a liquid such as water?
928824
If we consider the volume of water is known.(If not known then use graduated cylinder and find the volume)\nMass of water can be calculated using following formula:\n\nDensity(ρ)=mass(m)/volume(V) , where\nρ is the object's density (measured in kilograms per cubic meter) \nm is the object's total mass (measured in kilograms) \nV is the object's total volume (measured in cubic meters) \n(Temp (°C)/ Density (g/cm3) \n30/ 0.9957 \n20 /0.9982 \n10 /0.9997 \n0 /0.9998 \n−10/ 0.9982 \n−20 /0.9935 \n−30/ 0.9839 )
208900
Specific gravity.\n\nPure water has a density of 1 (the mass of 1 cubic centimetre of pure water is precisely 1 gramme), if something was twice as heavy as water (i.e. it has twice the mass) it would have a specific gravity of 2, 6 times as heavy and the SG would be 6.  If something was half as light as water it's SG would be 0.5 and so on.
860910
Pour the liquid in the graduated cylinder and there will usually be mL markings along the side.  This measurement is volume
86157
"water has the molecular formula H2O, indicating that there are two atoms of hydrogen and one atom of oxygen in a molecule of water. Rounded to three decimal places, the atomic weight of hydrogen is 1.008 amu and that of oxygen is 15.999 amu. The molecular weight of water is thus (2×1.008)+(1×15.999)=2.016+15.999=18.015 amu. Since atomic weights are average values, molecular weights are also average values. On the average, a molecule of ordinary water weighs 18.015 amu."
578713
U can a measure the mass of an object accurately using a Physical Balance.\nUnit of mass is kg in SI unit ysstem.\nMore accurate ways of measuring mass is done now.\n\nU can calculate it's weight by a formulae:\nW=mg.\nW-Wieght\nm-mass\ng-aceleration due to gravity (9.8 ms^-2)
470314
the specific gravity of water is 1.
804845
yes u r correct , u need vapour pressure of H2O. From vapour pressure calculate vapour density of H2O\n  Now, u can easily calculate molecular mass of the unknown as it  is twice the vapour density
343969
you would also use one of the following equations typically depending on the other information your given, but for sure, you need to look up its chemical composition. (ex: water is H2O)\n\nif youre given concentration:\nconcentration=moles/volume\nmoles=mass/molar mass\nmass=moles*molar mass\nmass=(concentration*volume)(molar mass)\nkeep in mind molar mass can be found by adding and multimplying as necessary the atomic masses of each element in the compound.\n\nif youre given density (which i bet you can easily look up on google or something if youre not given that information):\ndensity=mass/volume\nmass=density*volume
127092
It would depend on the fluid that you are weighing.  Water for example is 1 g/mL at 20 degree Celcius. Other fluids with different densities will convert differently.
426581
A mol in chemistry is equal to 6.02 x 10 to the 23rd power atoms of an element.  This is equivalent to the atomic weight of a substance in grams...for example, carbon has an atomic weight of 12, so a mol of carbon (6.02 x 10 to the 23rd atoms of carbon) weighs 12 grams.  If you are weighing a compound, the atomic weight of the component atoms in the molecule are added together, so water would have an atomic weight of around 18 (1 for each hydrogen and 16 for the oxygen) so a mol of water is about 18 grams of water.  Ultimately a mol is 6.02 x 10 to the 23rd power units of whatever it is you are measuring.
569202
Scientists use it today to calculate the amount of a substance, number of particles, that they have.  The molecular mass of something times the number of moles of the substance equals the mass in grams of the substance.  For example 1 mol of H2O equals 18g, and equals 6.02810^23 particles of water.
1096127
Remember few basics!!!!!\n\n1. One Mole of a substance is atomic weight, molecular weight or formula weight of a substance in grames.\n\nMolecular weight of water (H2O) is 18 so 18 gram of water is one mole\n\n2. One mole of any substance contains (Avagadros' number) 6.023 X 10^23 particles (molecules, atoms or ions)\n\n3. for converting mass into no. of particles follow the steps\n\nI. Divide the mass by molecul;ar weight . You get no. of Moles\n\nII. Multiply moles with Avagadro's No.\n\nYou get the number of particles
917775
Do you mean mass or weight?\n\nTo get the mass of 1 cubic meter of water:\n\nA cubic meter is a cube 1m x 1m x 1m \n\nConvert to centimeters this gives 100cm x 100 cm x 100cm\n\nTherefore the volumen of the cube in cubic cm is 1000000 cm3\n\n1 litre = 1000 cm3 therfore :\nvolume in litres is 1000000 / 1000 = 1000 l\n\nrelative density of water is 1kg / l therefore the mass of the water is 1000kg or 1 tonne.\n\nWeight is the gravitational force exerceted on the water by the earths gravitational pull. I'm assuming the water is stationary at ground level and not in orbit or something daft. The effect of gravity at ground level is given by the constant g which is 9.8N/kg.\n\nTherefore the weight of the water is 1000 * 9.8 =  9800N
1145319
Remember few basics!!!!!\n\n1. One Mole of a substance is atomic weight, molecular weight or formula weight of a substance in grames.\n\nMolecular weight of water (H2O) is 18 so 18 gram of water is one mole\n\n2. One mole of any gas at STP occupies 22.4 litre of spspace\n\n3. for converting mass into  volume follow the steps\n\nI. Divide the mass by molecular weight . You get no. of Moles\n\nII. Multiply moles with STP volume i.e. 22.4\n\nYou get the volume at STP
1006390
You need to know the density of whatever it is you want to convert.  1 ml of water at 4 degrees C is has a mass of 1 g or 1000 mg.  To convert any other liquid you must multiply by the specific gravity or density.
970729
Looks like this is your homework. anyway, i'll only answer two of your questions.\n\n1. the density of water is almost 1 g/mL. and 1 liter = 1000 mL. hence the mass of 1 liter of water is 1000 g.\n\n2. since 1 liter of water is 1000 g or 1.00 kg, its weight is 1.00 * 9.8 = 9.80 N
760373
an ore sample weighs 15N (newton) in air. when the sample is suspended by a light cord and totally immersed in water, the tension in the cord is 10.80 N. find the volume and the total density of the sample.. \n\n\nApparent loss in weight=(15 -10.8 )N\nMass of water displaced=(1.50-1.08)kg\n                                        =0.42 kg\nVolume=0.42 l(since cm3= l)\n1 kg= 1 l (litre)\n\nTherefore,volume =0.42 litre\n                             =21/50000 m3\n\n\nsince density equals to mass over volume;\ndensity=0.42 (divide by) 21/50000\n           =100000 kg m-3\n\n\n\n\n\nThis is called Archimedes principle\n\nBelow is a table that will help you to change units from Wikipedia. \n\n\n\nName of unitSymbolDefinitionRelation to SI units\n\ncubic metre (SI unit)\nm³≡ 1 m × 1 m × 1 m\nlitre\nL≡ 1 dm³\nlambda\nλ≡ 1 mm³= 1 μL\ndrop (metric)\n ≡ 1/20 mL= 0.05 mL\nminim (Imperial)\nmin≡ 1/480 fl oz (Imp) = 1/60 fl dr (Imp)≈ 0.059 193 880 208 333 mL\nminim (U.S.)min≡ 1/480 US fl oz = 1/60 US fl dr= 0.061 611 519 921 875 mL\ndrop (U.S.) (alt)gtt≡ 1/456 US fl oz≈ 0.064 854 231 mL\ndrop (Imperial) (alt)gtt≡ 1/1824 gi (Imp)≈ 0.077 886 684 mL\ndrop (U.S.)gtt≡ 1/360 US fl oz= 0.082 148 693 229 1(6) mL\ndrop (medical) ≡ 1/12 mL= 0.08(3) mL\ndrop (Imperial)gtt≡ 1/288 fl oz (Imp)= 0.098 656 467 013 (8) mL\ndash (U.S.) ≡ 1/96 US fl oz = ½ US pinch= 0.308 057 599 609 375 mL\ndash (Imperial) ≡ 1/384 gi (Imp) = ½ pinch (Imp)= 0.369 961 751 302 08(3) mL\npinch (U.S.) ≡ 1/48 US fl oz = 1/8 US tsp= 0.616 115 199 218 75 mL\npinch (Imperial) ≡ 1/192 gi (Imp) = 1/8 tsp (Imp)= 0.739 923 502 604 1(6) mL\nfluid scruple (Imperial)\nfl s≡ 1/24 fl oz (Imp)= 1.183 877 604 1(6) mL\nfluid drachm (Imperial)\nfl dr≡ 1/8 fl oz (Imp)= 3.551 632 812 5 mL\nfluid dram (U.S.); U.S. fluidramfl dr≡ 1/8 US fl oz= 3.696 691 195 312 5 mL\nteaspoon (Canadian)\ntsp≡ 1/6 fl oz (Imp)≈ 4.735 510 416 667 mL\nteaspoon (U.S.)tsp≡ 1/6 US fl oz= 4.928 921 595 mL\nteaspoon (metric) ≡ 5 mL\nteaspoon (Imperial)tsp≡ 1/24 gi (Imp)= 5.919 388 020 8(3) mL\ndessertspoon (Imperial)\n ≡ 1/12 gi (Imp)= 11.838 776 041 (6) mL\ntablespoon (Canadian)\ntbsp≡ ½ fl oz (Imp)= 14.206 531 25 mL\ntablespoon (U.S.)tbsp≡ ½ US fl oz= 14.786 764 782 5 mL\ntablespoon (metric) ≡ 15 mL\ncubic inch\ncu in≡ 1 in³= 16.387 064 mL\ntablespoon (Imperial)tbsp≡ 5/8 fl oz (Imp)= 17.758 164 062 5 mL\npony ≡ 3/4 US fl oz= 22.180 147 171 875 mL\nfluid ounce (Imperial)\nfl oz (Imp)≡ 1/160 gal (Imp)= 28.413 062 5 mL\nfluid ounce (U.S.)fl oz (US)≡ 1/128 gal (US)= 29.573 529 562 5 mL\nshot ≡ 1 US fl oz= 29.573 529 562 5 mL\njigger ≡ 1 ½ US fl oz= 44.360 294 343 75 mL\ngill (U.S.)\ngi (US)≡ 4 US fl oz= 118.294 118 25 mL\ngill (Imperial); Noggingi (Imp); nog≡ 5 fl oz (Imp)= 142.065 312 5 mL\ncup (Canadian)\nc (CA)≡ 8 fl oz (Imp)= 227.3045 mL\ncup (U.S.)c (US)≡8 US fl oz ≡ 1/16 gal (US)= 236.588 236 5 mL\ncup (metric)c≡ 250 mL\nbreakfast cup ≡ 10 fl oz (Imp)= 284.130 625 mL\npint (U.S. fluid)\npt (US fl)≡ 1/8 gal (US)= 473.176 473 mL\npint (U.S. dry)pt (US dry)≡ 1/4 bu (US lvl)= 0.550 610 471 357 5 L\npint (Imperial)pt (Imp)≡ 1/8 gal (Imp)= 0.568 261 25 L\nfifth ≡ 1/5 US gal= 0.757 082 356 8 L\nquart (U.S. fluid)\nqt (US)≡ 1/4 gal (US fl)= 0.946 352 946 L\nquart (U.S. dry)qt (US)≡ 1/32 bu (US lvl) = ¼ gal (US dry)= 1.101 220 942 715 L\nquart (Imperial)qt (Imp)≡ ¼ gal (Imp)= 1.136 522 5 L\npottle; quartern ≡ ½ gal (Imp) = 80 fl oz (Imp)= 2.273 045 L\nboard-foot\nfbm≡ 144 cu in= 2.359 737 216 L\ngallon (U.S. fluid; Wine)\ngal (US)≡ 231 cu in= 3.785 411 784 L\ngallon (U.S. dry)gal (US)≡ 1/8 bu (US lvl)= 4.404 883 770 86 L\ngallon (Imperial)gal (Imp)≡= 4.546 09 L\nbeer gallonbeer gal≡ 282 cu in= 4.621 152 048 L\npeck (U.S. dry)\npk≡ ¼ US lvl bu= 8.809 767 541 72 L\npeck (Imperial)\npk≡ 2 gal (Imp)= 9.092 18 L\nbucket (Imperial)\nbkt≡ 4 gal (Imp)= 18.184 36 L\ntimber foot\n ≡ 1 cu ft= 28.316 846 592