The below reaction results in one mole of a single ionic compound as a product.?
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2Cu + O2 ---> 2CuO,          \nThis is copper oxide or cupric oxide or copper( II )oxide\n\n4 Cu + )2---> 2Cu2O\nCopper also combines with oxygen as Cu2O, cuprous oxide , or copper(I) oxide
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An ionic compound.\nA covalent compound.
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my question is:\n\nNaHCO3(s) + NaOH(aq) -> Na2CO3(aq) + H2O(l)\n\n3.25 moles of Na2CO3 is produces.
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MgSO4(s) + 2HCL(aq) ---> H2SO4(aq) + MgCl2 (aq)
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K2Cr2O7 + 2Pb(C2H3O2)2 + H2O --> 2PbCrO4 + 2HC2H3O2 + 2KC2H3O2
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2 HNO3(aq) + Sr(OH)2(aq) --> Sr(NO3)2 (aq) + 2 H2O\n\n2 H3PO4(aq) + 3 Ba(OH)2(aq) --> Ba3(PO4)2 (cr)* + 6 H2O\n\n* Barium Phosphate will precipiate out of an aqueous solution in this reaction
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NaOH (aq) + HCl (aq) --> NaCl (aq) + H2O (l)
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Na2CO3 + 2HCl = CO2 + H20 + 2NaCl (aq)\n\nThis reaction is a double displacement reaction because oxygen from the sodium carbonate combines with the hydrogen in the hydrochloric acid to form water, and the sodium goes with chlorine to form sodium chloride, making carbon dioxide in the process.
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The REAGENT is an ylide. The PRODUCT is an ALKENE (and triphenylphosphine oxide). The reaction is:\naldehyde/ketone + triphenylphosphonium ylide ----> (Z)-alkene + triphenylphosphine oxide.
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K2IC4H6 + HNO3 ---  K2HI + NO3C4H6
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NaClO + 2FeSO4 + H2O -> NaCl + 2 Fe(3+) + 2 (SO4)(2-) + 2 OH(1-)
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CH3COOH + NaOH ---> NaCH3COO + H2O
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2Ca(s) + O2(g) -> 2CaO(s)
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Cr2(SO4)3 + 6KOH  --> 2Cr(OH)3 + 3K2SO4
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Na2CO3 + 2HCl-> NaCl + H2O + CO2
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Based on what you have given us, there are no coefficients in front of any of the compounds/elements, so the ratio would be 1:1:1.\n\nI'm guessing that you didn't provide all the information need, though.\n\nGenerally these questions give you a reaction that you must first balance to determine the mole ratios.
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2Rb(s)+Cl2(g)--2RbCl(s)