please help, how do u do this equation  2x+3<6x-1?
926616
2x+3<6x-1\n2x-6x<-1-3 \n-4x<-4\nx>1
698536
1. 4x=2x+6\n\nCollect like terms\n4x - 2x = 6\n2x = 6\n2x/2 = 6/2\nx = 3\n\n2. 7x=4x+12\nCollect like terms\n7x - 4x = 12\n3x = 12\n3x/3 = 12/3\nx = 4\n\n3. 2x=x+17\nCollect like terms\n2x - x = 17\nx = 17
705297
6x -2x -6 =5\n6x -2x = 11\n4x = 11\nx = 11/4
790277
ill give it a shot - im not sure , anyways i got 2 answers..\n\n(1st)\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6x = 2-4x\n\nx+4x+6x = 2+1\n\n11x = 3\n\nx = 3/11\n\n\n(2nd possible answer)\n\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6/x = 2-4/x\n\n-5 = -2/x\n\n-5x = -2\n\nx = -2+5\n\nx = 3
290738
12x+3-26=6x+1\n\n=> 6x-24=0 => x = 4
957282
|3(x + 1) + 6| =18\nie |3x + 9| = 18\nwhence |x + 3| = 6\nThere are 2 different methods to solve such an equation\n\nOne is to use the definition that\n|N| = N if N ≥ 0\nand = -N if N < 0\n\nThe other is to use the propety that |N|² = N²\n\nMethod 1\nSo x + 3 = ±6\nWhence x = -9 or 3\n\nMethod 2\n|x + 3|² = 6²\nie x² + 6x + 9 = 36\nx² + 6x - 27 = 0\n(x + 9)(x - 3) = 0\nx = -9 or 3
117592
Multiply the 1st equation by 3\n\n3 [ 2x + y = -4]\nthat gives.. 6x + 3y = -12\n\nsubtract the 2nd equation from this\n\n6x + 3y - (-5x + 3y ) = -12 - (-1)\n\n6x + 3y + 5x - 3y = -12 + 1\n\n11x = -11\n\nx = -1\n\nput this into 1st equation\n\n2(-1) + y = -4\n\n-2 + y = -4\n\ny = -4 + 2\n\ny = -2\n\n\nx = -1 & y = -2\n\nyou can check this with 2nd equation\n\n-5(-1) + 3(-2) = -1\n+5 - 6 = -1 . hence the solution x = -1 & y = -2 is CORRECT
794701
The first thing you have to do is group together like terms, and remember that since this is an equation, what you do to one side you have to do to the other side.  I'll show you this in steps.\n\n4x + 2x = 9x - 6  Group together like-terms on the left hand side to get\n6x = 9x - 6    Subtract 9x from both sides to get\n\n6x - 9x = -6   (at this point, note that the 9x on the right hand side disappeared.  This should happen, since subtract 9x would make 9x on the right hand side equal to zero).\n\nNow, group together like terms on the left hand side, to get\n-3x = -6\nSince our goal is to isolate x, we divide both sides by -3\n\n-3x/-3 = -6/-3\nx = 2
791030
3x – 2y = 6\n3x = 6 + 2y\nx = 2 + 2/3y
268383
2x^2+6x-1x-3\n2x(1x+3)-1(1x+3)=0\n(2x-1)(x+3)=0\nx=1/2 or -3
798514
do you mean 6x([1/2]x^2)?\nif so 3x^3\nor 6x(1/(2x^2))?\nthen its 3x^-1
819891
2(x-6)=3x\n\n1.Distribute the 2 to the X and the 6. \n2x-12=3x\n\n2. Subtract the 2x from the left side and subtract it from 3x\n-12 = 1x\n\n3.flip the problem so it looks pretty!\nx = -12\n\nYour Welcome :D
848564
Substitute 2x-1 for y in the middle part, you get:\nx^2 + x -6(2x-1) = 2x-1\nThis you can reduce to a quadratic equation for x.
822539
first multiple everythingby x, then simplify and solve:\n\n1/x-2 = 3/x+3 =>\n\nx/x - 2x = 3x/x +3x =>\n\n1 - 2x = 3 + 3x =>\n\n-2  = x
1138309
I hope you are trying to say x+2 = (2/3)(2x-1)..if it is correct then\n\n3(x+2) = 2(2x-1) --> 3x+6 = 4x - 2 --> 6+2 = 4x-3x --> 8 = x
264301
I'm assuming you're new to algebra, so I'll do it the long way....\n\nSubtract 3 from both sides:\n\n1/2x + 3 - 3 = 9 - 3\n\n1/2x = 6\n\nMultiply both sides by 2\n\n1/2x * 2 = 6 * 2\n\nx = 3\n\nRemember, whatever you do to one side of the equation you need to do to the other side.
840645
1,2,3\n1+2+3=6\n1x2x3=6