i need some more help with math please.?
922907
Only if it's the highest common denominator.  12/36 divided by 2 is 6/18.  But the highest common denominator would be 12, that would leave you with 1/3.
1019971
Okay smarty here is a good site www.math2.org\n\ngood luck
520168
Try this:\n\nhttp://www.algebra.com/
128596
im great with algebra, ive been doing it for the past 4 years now non stop, email me and ill be more than happy to show you how to do it step by step and answer you questions\nzinger_38@yahoo.com
771776
http://mathforum.org/dr.math/\n\nThis is Ask Dr. Math, a website that can offer help for general math through Algebra and beyond. There are other good websites for math out online, type in keywords,  homework  math help and see all that you come up with. Eventually you will find one that can walk you through most problems. Good luck.
281150
Next time just type your math equation into Google and it will do the math for you.\n\n15
708585
What sort of help do you need with fractions? It depends. Or you can try math.com\n\nYou have to look a little to actually find what youre looking for, but mostly its good \n\nHope this helps!  :)
825795
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
858552
Have you tried these?  Surely you've been told that division by 0 isn't possible, so there's your answer for 7.  I'm not doing any others on Yahoo answers (too many at once), but if you really need help and are willing to do as much as possible for yourself I'll help you if you email h_chalker@yahoo.com.au, but nasty Maths teachers like me won't just hand you 7 answers on a plate!
311655
There are a lot of great sites out there that can help you along. \nAlso, you may want to check into some English help as well.\n\nhttp://www.math.com/
272295
There's lots of help online. Try these web sites:\n\nhttp://www.algebrahelp.com/\nhttp://www.purplemath.com/\nhttp://www.sosmath.com/algebra/algebra.html\nhttp://www.helpalgebra.com/\n\nThere's even more. So start with these, and good luck!
111021
If you are sloving for X then anything greater than 2 will work. basically it is 6 time what (X) will be greater than 12. Well 6x2=12 so that won't work.
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
151115
Would you please type your entire math question the way it is presented in your book? Your description is not enough for anyone to answer you correctly. Thanks!
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
680155
i'd love to help but i'm having trouble with it myself\n\nuse ur math textbook it will have it unless ur math book say algebra and is red ( that my alg. book and it doesn't help) \n\nSRY good luck