square root question?
923612
1) 24 is the product of 4*6 , we can take the square root of 4 which is 2,but we can't simplify the 6 any more\nso square root of 24 is 2square root of 3.\n2)a^3 = a^2 * a^1  ,so we can take the square root of a^2 which is = a\nso square root of a^3 =a square root of a.\n3) b^6 = b^2 * b^2 * b^2 , now we can take the square root of each b^2  , so the answer for this part will be b^3,but we have to put this b^3 inside an absolute value ( check the algebra II textbook ).\n4) c will stay inside the square root.\n\nso the final answer is : 2aIb^3I square root of 6ac.\n                               or: 2a absolute value of b^3 times square root \n                                       of 6ac  .\n\nI hope this would help
946285
square root of 2x+3=6\n<=> 2x+3 = 36\n<=> x = 33/2
762368
NB! sqrt(x)=x^½ \n2*(2+1)^½ / -5*(2+3)^½<=>\n( 2*(3)^½*(5)^½ )/(-5*5)<=>\n( -2*(3*5)^½ )/25<=>\n( -2(15)^½ )/25<=>\n-2( 3*5/5*5*5*5)^½<=>\n-2(3/5*5*5)^½= -sqrt(3/5)*2/5\n=========================
805274
1) 3 * sqrt(-8)\n= 3 * sqrt(4) * sqrt(-2)\n= 6 * sqrt(2) * i\n\n2) sqrt(1/6)\n= sqrt(6/36)\n= sqrt(6) / sqrt(36)\n= sqrt(6) / 6
716502
CLUE 1: The number squared < 1200\nTake square roots: the number < 34.64...\nIt is an integer, so the number ≤ 34.\n\nCLUE 2: The number cubed > 29000\nTake cube roots: the number > 30.72...\nIt is an integer, so the number ≥ 31.\n\nCLUE 3: The fourth power of the number < 930000\nTake fourth root: the number < 31.05...\nIt is an integer, so the number ≤ 31.\n\nFrom CLUE 2 and CLUE 3 the number must be 31 (which is consistent with CLUE 1).
546400
D=square root ((x1-x2)^2 + (y1-y2)^2)
296703
-3 + sqrt(2) or -(3 - sqrt(2))\nthats like saying\n\n-1x, 0x, 1x\n\nthe answer is problem found like this\n\n2x, 3x, 4x\n\nso i believe the answer is \n\n6 - 2sqrt(2), 9 - 3sqrt(2), 12 - 4sqrt(2)
1010349
Hi:\n\nI know of six ways to find a square root of a number:\n\n1) Take the logarithm of number and divided by 2 take the result and take the Antilog \n\n2) Use the School boy method of extracting a square root see this website for how :\n\nwww.nist.gov/dads/HTML/squareR...\n\n3) Use the following method ( example on the bottom of page ):\n\n(N/gn+gn)/2= gn\n\nN= number to be Square root \ngn = Guess number or Square root\n\nrepeat this for about about 5 to 10 times ( see example)\n\n4) Use trail and error by running a number value and Square it\n\n5) Graph and interpolarite it\n\n6) Look it up in a Mathematical hanbook of tables and formulas and look under Square & square roots tables.\n\n------------------------------...\n\n\n\nExample:\n\nThe square root of 27:\n\n(27/5+5)/2= gn\n\n\n(5.4+5)/2 = gn\n\n10.4/2= gn \n\n5.2 =gn \nend of run 01 \n\n(27/5.2 + 5.2)/2= gn\n\n(5 + 5.2)/2 = gn\n\n10.2/2= gn \n\n5.1= gn\n\nend of run 02\n\n((27/5.1)+ 5.1) /2= gn\n\n(5.294117647+5.1)/2 = gn\n\n10.394117647/2 = gn\n\n5.197058823 = gn\n\nEnd of run 03\n\n(27/ 5.197058823) + 5.197058823 )/2 = gn\n\n(5.195246179+ 5.197058823 )/ 2 = gn\n\n10.392305003/2 = gn\n\n5.196152501 = gn\n\nEnd of run 04 \n\n((27/5.196152501)+ 5.196152501)/2 = gn \n\n(5.196152343+5.196152501)/2 = gn\n\n10.392304844/2 = gn\n\n5.196152422= gn \n\nEnd of run 05\n\n((27/ 5.196152422) + 5.196152422 )/2 = gn\n\n(5.196152422 + 5.196152422 ) /2 = gn\n\n5.196152422 = gn \n\nEnd of run 06\n\nSquare root of 27 appoximatily = 5.196152422 ( accurate to 9 decimal places.) \n\nSource(s):\n\nwww.nist.gov/dads/HTML/squareR...\n\nwww.du.edu/~jcalvert/math/sqrt... \n\nmathforum.org/library/drmath/v...
1001448
[sqrt(2)]^2 = c^2 - b^2\nLet c = 3/2 and b = 1/2, then\n[sqrt(2)]^2 = (3/2)^2 - (1/2)^2\n2 = 9/4 - 1/4\n2 = 8/4\n2 = 2
544837
I squared the 7 to start with and got 49.  I am also only showing the addition version, you can do the subtraction later yourself.\n\n(-7 + sqrt(49 - 4(9)(-1)))/2(9)\n(-7 + sqrt(49 - -36))/18\n(-7 + sqrt(49 + 36))/18\n(-7 + sqrt(85))/18\n\nand I think that that is it.  You cannot simplify the square root.
773471
√2 . √6 \n---- x ----- =\n. 3 .... 22\n\n√12\n------- =\n66\n\n\n√(2² x 3)\n------------- =\n66\n\n2√3\n------ =\n66\n\n√3\n-----\n33
693929
Your first question with the V's is unclear.\n\n√(10 - 6) / -5 √(10 + 7)\n√(4) / -5 √(17)\n√(4) / -5 √(4 * 4∙25)\n√(4) / -5 √(4) √(4∙25)\n 1 / -5 √(4∙25)
832245
square root by x both sides\n\nso\n\n5 - 3 = X Root 2\n2= xroot 2\nso x = 1.
193948
The sq rt of x is x to the 1/2 power; 1 over sqrt x is x to the -1/2 power\n\nThen use your normal rule for exponents : d/dx (x^n) = n x^(n-1)\n\nd/dx x^-1/2 = -1/2 x^(-3/2)\n\n(This equals -1 over the square root of x cubed if you need to write it that way.)
1147786
x - sqrt(x) = 0\nx = sqrt(x)\nx^2 = x\nx(x-1) = 0\nx = 0,1\n\nBoth check.
875144
you have to take the square root of each side, then just simplyfy\n\nx = 1.2472191289247
964858
That just means that keep it in the square root instead of simplifying it.\nEx: Keep it as square root of 2 instead of 1.414\n\nSo if you're finding the square root of 27, for example.  You can split up 27 into 9*3.  Square root of 9 is 3, but 3 is not a perfect square.  So your answer would be : 3 square root of 3.  Instead of 5.196