help in this math expression?
919910
1/(3 + √5) =\n1/(3 + √5) * (3 - √5)/(3 - √5) (on multiplying the numerator and denominator by the conjugate of (3 + √5) as (x + y)(x - y) = x² - y²)\n= (3 - √5)/(9 - 5) (as 3² = 9 and √5² = 5)\n= (3 - √5)/4
963452
(-5xy + 2xyz) + (xy - 3xyz) \n\nRight, the brackets are a distraction and are not needed, since there is a + in the middle, so remove them:\n\n-5xy + 2xyz+ xy - 3xyz\n\nNow collect like terms...\n\n-5xy + xy = -4xy    and    2xyz - 3xyz = -xyz\n\nPut these answers together and you get:\n\n-4xy - xyz\n\nVoila!\n\n(-5xy + 2xyz) + (xy - 3xyz) = -4xy - xyz
96233
+5,+12, -5, -12, +3.3
885758
2(-x+4)+3x=(-x)+3x\n(-2x + 8) + 3x  = 2x\nx + 8 = 2x\n(x + 8) - x = (2x) - x\n8 = x
909284
((1/x) + (1/y)) / ((1/x) - (1/y))\n\n((y + x)/xy) / ((y - x)/xy)\n\n((y + x)/xy) * ((xy)/(y - x))\n\n(xy(y + x))/(xy(y - x))\n\n(y + x)/(y - x) = (x + y)/(-x + y) = (x + y)/(-(x - y)) = -(x + y)/(x - y)
926880
(1+1)-2*3/2^2+2\n\nWithout useing Order of Operations: 2\n\nWith Order of Operations: 2.5
594239
ok so you have p^2 + p, you can factor out p from both parts of the expression, it will end up like this: p(p + 1).  Hope that works.
749417
-14‹2x-6≤12\n -14+6<2x<=12+6\n -8<2x<=18\n -4<x<=9
857864
=[(-3)^2*12/9-1]/9=[12-1]/9=11/9\nand Brandy is also right (smile)
685531
[(2x^3+2x^2+3x+3)/(x^2-9)]*\n[(x^2+2x-15)/(4x^2+6)]\n\nFactor each expression individually.\n\n(2x^3+2x^2+3x+3) = (x+1)(2x^2+3)\n\n(x^2-9) = (x+3)(x-3)\n\n(x^2+2x-15) = (x+5)(x-3)\n\n(4x^2+6) = 2(2x^2+3)\n\nSubstituting these in, our expression becomes\n{[(x+1)(2x^2+3)]/[(x+3)(x-3)]}\n*{[(x+5)(x-3)]/[2(2x^2+3)]}\n\nCombining these into one larger expression, we get\n[(x+1)(2x^2+3)(x+5)(x-3)]/\n[2(x+3)(x-3)(2x^2+3)]\n\nCancel the quantities common to the numerator and denominator and we get our final answer\n[(x+1)(x+5)]/[2(x+3)]\n\nGood luck.
957836
4x+(-5y)+(-6x)+3y\n4x+(-6x)+(-5y)+3y\n=-2x-2y
38332
(x-2)/(x^2-2x-15)+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(-2-x)(x+3)/(x-5)(x+3)\n\n[(x-2) + (x+3)(-2-x)] / [(x+3)(x-5)]\n\nANSWER :\n(x^2+4x+8)/((x+3)(5-x))
921331
First, find your final value.  This is what your expression equals.  \n\nSo, you can see that the problem states that there are 17 ducks left.  Good start.  We can begin with:\n??? = 17\n\nNow, we tackle each part of the problem.  We see that we started with 28 ducks.  After that, 16 ducks fly in, so we need to incorporate 28 + 16.  So now we have:\n28 + 16 ??? = 17\n\nNow, we need to see what is being asked.  It is being asked how many ducks left.  Since ducks flying in would be addition, then ducks flying out would be subtraction.  We are being asked how many ducks flew out, so this is our unknown (we'll call it x).  Now we can write it as:\n28 + 16 - x = 17\n\nTo find the answer, you solve for x by getting it by itself on the equal sign.  Add 28 and 16 to get 44:\n44 - x = 17\n\nAdd x to each side and subtract 17 from each side:\n44 - 17 - x + x = 17 - 17 + x\n27 = x\n\nSo, 27 ducks flew out.\n\nNote that I added x to both sides above.  This is normally unnecessary, but I didn't know how far along you were.  For future reference, you may want to consider this step:\n44 - x = 17\n\nSubtract 44 from each side:\n44 - 44 - x = 17 - 44\n-x = -27\n\nMultiply each side by -1:\n(-x)(-1) = (-27)(-1)\nx = 27
972642
(A^2+2ab+b^2)/(a+b) + (a^2-b^2)/(a-b) + (a-b)/(a+b)/(a^2-b^2)/a+b)\n(a+b)^2/(a+b)+(a+b)(a-b)/(a-b)+ (a-b)/(a+b)*(a+b)/(a^2-b^2)\na+b+a+b+(a-b)/((a+b)(a-b))\n2a+2b+1/(a-b)\n\nif I got all the ( ) in the right places.
757614
4 (x^2 + 3X -4)\n4(x+4)(X-1)
887284
Subtracting, and adding a negative #, are the same thing. So this equation can also be expressed as:\n(-5x + 6) - (-2x + -7)\nThe negative after the last part of the function, effectively reverses the negatives inside the parenthesis:\n(-5x +6) + (2x + 7)\nFrom there, since this is just addition and subtraction, you can just remove the parenthesis:\n-5x + 6 +2x + 7\nCombine like terms and you've got:\n13 - 3x
1010071
ok its like this...() or parenthesis meant multiplication. Then multiplyin negative by negative is = to +. So now its gonna be +a or simply a