What is the force of gravity on a spacecraft given the following?
916991
The force of gravity is indeed given by Newton's equation:\n\nF = G*M*m/r²\n\nwhere G is the gfravitational constant, M is the mass of the Earth, m is the mass of the space ship and r is the distance between their centers of mass.\n\nThus, if the space ship is 5 Earth radii above the surface of the planet, then it is 6 Earth radii from the planet's center:\n\nr = (6/5) * (32000 km * 1000 m/km) = 38400000 m\n\nThe mass of the Earth is about 5.9742×10^24 kg. Finally, the value of G, the gravitational constant is about 6.6742x10^-11. Substituting these values into Newton's equation provides:\n\nF = (6.6742x10^-11)(5.9742×10^24 kg)(1500 kg) / (38400000 m\n)²\n\nF = 405.61 N
351440
well ok. for part a, the acceleration is in the horizontal direction, because its moving horizontally. so the force is just mass x acceleration which is 70*6=420N. but thatz only in the horizontal direction.\n\nfor part b, you have to account for gravity. so gravity is pulling down at 9.45m/s^2, but youre accelerating upwards at 6m/s^2. so that means that youre overcoming the gravity and accelerating at 6m/s^2 MORE than the gravitational acceleration.\nso 9.45+6 = 15.45. this is your actual acceleration.\nso now you just do F=ma again and you get 70*15.45=1081.5N. \n\nhope this helps. let me know if you need more help. and this isnt thermodynamics.
40169
The force on the system is 3.0 kg x g. (the only force is due to gravity acting on the hanging mass) The mass of the system is 3.0 kg + 5.0 kg = 8.0 kg.  The acceleration of the system is a = force/mass = 3.0 kg x g / 8.0 kg   =  3 / 8 g or 0.375 x 9.8 = 3.675 m/sec^2
768444
Plane upwards force > then Earth gravitational pull + mass of the plane+how fare it want to be escape.
408862
the force between the object and the earth is dependant on mass, but the acceleration of the object towards the earth is 9.81 meters&#92;second. (ignoring air resistance)\n\nforce = mass x acceleration
965597
you convert mass into force by multiplying with 9.8m/sec^2 which is the acceleration due to gravity
966128
use the universal law of gravitation to find the force of gravity at the inner radius.  Use 1kg as your second mass (mass is irrelevent in this next part anyways), and use this force to find the accel of gravity.  Using the force and accel of gravity, you can find the kinetic energy needed in order to overcome the potential gravity of the planet (m cancels).  with kinetic energy you can find velocity, and with velocity and radius, period.  Hope that helps.\n\nfor the second part, repeat, except with the outer radius as D.
51910
Weight is a force, but when something is weighed you actually measure it's mass assuming you are in an environment in which the force of gravity is constant (i.e., you're at a fixed location <radius from the center> on a planet or massive planetary mass).\n\nof course, one's mass can be approximated by W=mg at fixed radii from such planetary masses (like the earth, a massive asteroid, a superdense star, whatever...) if the force of gravity, g, is known at that radius.\n\nThere are 2 possible variables here - mass and the force of gravity.  Which one do you know?  usually an approximation for g is given.  Which one do you measure, then...that would be mass.
611971
Mass is a constant; weight varies by gravitational pull.
953154
Acceleration\n    a = w^2 r\n    w = 2pi / T\n    w = 2 x 3.14 / (365.25x24x60x60)\n    w = 1.99 x10^ - 7\n    a = (1.99 x10^ - 7) ^2 x 1.5 x 10 ^11\n    a = 5.95 x 10 ^ -3 m/s^2\n\nForce\n\n    F = mw^2r\n    F = 6.02 x 10^24 x (1.99 x10^ - 7) ^2 x 1.5x10^11\n    F = 3.58 x 10^ - 22 N\n\nSource of this force:\n    It is the gravitational force of attraction between the sun and the\n    Earth. It is given by Newton's law of gravitation.
152239
AIR RESISTANCE CANCELS OUT THE FORCE DUE TO GRAVITY , THERE IS NO ACCELERATION BECAUSE THE OPPOISTE FORCE IN THE SAME.\nSO YOU CAN SAY 0
1159027
...mass of the planet it is "escaping" from, and the mass of the rocket.\n\nIf there are other large objects close enough to exert a gravitational influence on the rocket, these may need to be factored in as well.
912569
I think F is the answer. Taking acceleration due to gravity is constant at 9.81ms^-2, but this assumes that air resistance is neglected, and g is a constant.\n\nIf air resistance is NOT neglected, and acceleration due to gravity is not taken to be constant, H is the correct answer. The rest of the options are wrong.
632008
Gravity, its weight, friction\nThat's about it.
306816
B.  The acceleration is towards the Earth and the force is constant.
466570
Mass.\n\nF=ma\n\nF is the force\nm is the mass\na is acceleration
935341
1 sum the forces and set equal to zero. 2 forces, gravity and electric.\n\n2. conservation of energy. initially all kinetic, finally all potential. KE1=U2. U2 is electric potential. solve.\n\ngood luck