MATH QUESTION THAT i NEED HELP ON!?
918525
1) "Kilo" means 1000, so in 1 kilogram, there are 1000 grams, so to find how many grams are in 1.93 kilograms, you simply multiply by 1000, or move the decimal place over 3 places. So the answer is 1930 grams.\n\n2) In 1 centimetre, there are 1/100 meters. So to find how many meters are in 840 centimetres, you can multiply 840 by 1/100, which is the same as dividing it by 100. So the answer is 8.40 meters.\n\n3) In 1 litre, there are 1000 millilitres. So multiply. 7.5 L x 1000 mL = 7500 mL
520168
Try this:\n\nhttp://www.algebra.com/
192062
Maybe this link will help:\nhttp://www.mathinvestigations.com/
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
934925
6! / 2! = 6x5x4x3x2x1 / 2x1\n= 6x5x4x3\n[
467967
this is probably not a perfect answer but this site may give you some clues.\n\nhttp://www.gomath.com/Questions/question.php?question=4751\n\naltrnatively type 'prove v*v = 2gr*r/s+v0*v0-2gr' into a search engine and see what comes up.
833246
More than one answer.\n\n(a) (8/ [8-3-3]) ! = 4! = 24\n\n(b) 8 / (3 - [8/3]) = 24 \n\n(c) In base-9 maths:\n8 + 8 + 3 + 3 = 2 (9s) + 4 units = 24\n\n(d) In base-11 maths:\n3^3 - 8/8 = 2 (11s) + 4 units = 24\n\n(e) In base-12 maths:\n3^3 + 8/8 = 2 (12s) + 4 units = 24\n\n(f) In base-26 maths:\n8! / (8-3)! x 3! = (8 x 7 x 6) / 6 = 8 x 7 = 2 (26s) + 4 units = 24
285246
hey this is the math section\nthere is an another section for this type of question\nu had better post it their 4 a better response
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
849743
This is the third time that this question has been asked!?!?!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nBut someone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
909352
This question has been asked so many times!?!?!\n\nGood challenge question!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nSomeone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
320882
1 2 3 4 5 6 7 8\n<---[======)--->
886428
____________________________________________________\n| \nBecause the bottom number is the same- X, so u add the top number-1+2, and u get 3. let me show you-- 1/x+2/x=3/x\nArent i right???!!!!!!!!!!
609300
This is more of a word problem or a riddle than a math problem.\n\nThe answer is 7 (SEVEN).  Remove its first letter and it becomes EVEN!
897429
This is the third time that this question has been asked!?!?!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nThis is as far as I got:\n(2B+1)^(D-E) - F^(3G+G2) = (10J)/A\n\nBut someone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
777951
Tackling the problem bit-by-bit:\n\nFirst, let x = the larger number\nlet y = the smaller number\n\nYou can write out an equation to show their relationship of "difference" by:\nx - y = 68\n\nNext, you write out the equation to show their quotient relationship by:\nx/y = 5\nwhich gives:\nx = 5y\n\nNow plug x = 5y into the "difference" equation:\n(5y) - y = 68\nwhich gives\n4y = 68\nwhich gives \ny = 17\n\nNow plug y = 17 into the "difference" equation:\nx - 17 = 68\nx = 85
136789
That's an extremely good question. \n\nThe answer is simple. Before that, i will explain what your question means to those who don't get. Well, it means that we must get 24 using 1,3,4 and 6 any number of times however involving operations +,-,* and / only once. \n\n  Then, the answer is very simple :\n\n  {[(6*6)/(3-1)]+[6]}  =  24\n\n---------------------------------------------------------\nWOKRING :\n\n {[(6*6)/(3-1)]+[6]}   =  {[(36)/(2)]+[6]}\n                       =  18 + 6\n                       =  24\n\n----------------------------------------------------------\n\nI hope you post more questions like these. They evoke a lot of thought. I hope the solution serves th purpose.