i need some help with solving eqations.?
921244
Yeah, what Crazy Horse said...  She's (He's?) on the money with this one.
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
646051
mail me bjpumpindogg@yahoo.com i have the answers
152712
get GATE 2006 Solutions here .\nRate my answer
1127430
try this one http://www.algebrahelp.com/
821835
Problem 1.\nu = sin x\nu^2 + 3u + 2 = 0\nu = -3/2 +/- 1/2\nu = -1, -2\nsin x = -1  [because the sine is never -2]\nx = 270 degrees\n\nProblem 2.\nu = cos x\nu^2 + 2 u + 1 = 0\n(u+1)(u+1) = 0\nu = -1\ncos x = -1\nx = 180 degrees
851212
hmm im not quite in college yet, but i hope to be help.\ndo you know the values for f, h, v, and a?\nif you do, id substitute it in.\nthen square both sides. \nand then solve.
533021
there are some solved physics problems on \nhttp://www.dctech.com/physics/help/\nbut I don't know if it will help you out.
52637
I had a similar problem not long ago. How I solved it was by following the directions at [1]. Hope this helps!
953940
Hi again \n\nY = √2x – 3 \n2x – 3 = y ²\nX =( y ² + 3 )/ 2\nf –¹ (x)  =( y ² + 3 )/ 2  =>   f –¹ (x)  = (x ² + 3 )/ 2   &  x ≥ 0 \n\nGood Luck \n try to solve them yourslef again if you got wrong , am sure you can solve them correctly , if you just try your best
702095
it would be easy for me to help you more if you can provide more details abt ur problem.\n\nwaiting for ur reply
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
245193
Use your buffering equation and plug in the numbers you know to get your answer.  You might have to do reverse calulations to find your answer.
27685
You have two equasions 2x=3y and y=2x+4\nYou're going to plug one equasion into the other; plug the y= into the  first equasion because the y is already by itself.\n2x=3(2x+4) (I plugged what y equaled into the y in the first equasion.\nThen you solve for x\n2x=3(2x+4)\n2x=6x+12\n-4x=12\nx=-3\nNow that you have solved for x, plug x back into the y='s equasion\ny=2x+4\ny=2(-3)+4\ny=-6+4\ny=-2
815405
Sorry, but I don't think there is a way. You can mail this question to danuitti(who has 2180 best answers and appears at the top). He is a genius and he will most certainly find a solution. Good Luck!
741999
whats the equation or formula u need help with?