Find the equation of the line that passes through the point (2,2) and is perpendicular to the line y = 3x -5?
920764
Perpendicular lines have slopes whose product is -1.\n\nIf the original line has slope 3, the line that is perpendicular has slope -(1/3)\n\nNow use the point slope form of the line.\n\ny - y1 = m(x - x1)\n\nIf (x1,y1) = (2,2) - your point, then:\n\ny - 2 = (-1/3)(x - 2)\n\nWe can convert this into slope-intercept form.\n\ny - 2 = (-1/3)x + (2/3)\ny = (-1/3)x +(8/3)\n\nBoth equations represent the same line.
849182
2x-3y=6 is the same as y=2/3x-2\n\nso in order to be perpendicular to this line, you must have slope -3/2\n\ntherefore L has slope -3/2 and has y-intercept of (0,2).  so plug that into slope-intercept form\n\ny=(-3/2)x+2
753792
You can find the slope of 2x - 3y = 12, call it m.  The line perpendicular to it will have slope -1/m.  Since you know the slope (-1/m) of your line and a point on it (2,8) you can solve to find the equation.\n\nSTEP 1 -- Find -1/m\n\n2x - 3y = 12\n-3y = -2x - 12\ny = 2/3 x - 4  << so m=2/3, and -1/m = -3/2\n\nSTEP 2 -- Use slope -3/2 and point (2,8) to find the equation\n\nRecall that (y-y0)=m(x-x0), so we get the following:\n\ny - 8 = -3/2 (x - 2)\ny - 8 = -3/2 x + 3\ny = -3/2 x + 11\n\nSo, the equation you are looking for is y = -3/2 x + 11\n\n~ ♥ ~
77842
the equation of a line that is perpendicular to another line will have a slope that is an opposite reciprocal to the other line (ex: if the slope of a line is 1/2, the perpendicular line will have a slope of -2).
232592
2x = 3y - 4y + 5 - 2\n2x = -y + 3\n2x + y = 3
876684
y = -x + 6 is in slope intercept form, y = mx + b, where m is the slope.\nSo, you know that the slope of this line is -1. A perpendicular line has the opposite converse slope, so since this slope is -1/1, the slope of the new line will be positive 1/1, or 1.\n\nNow that you have the slope of the new line, you can use that and the point-slope form of a line to find the equation. The general form of a point slope line is y - Y = m(x-X), where m is the slop, Y is the y coordinate of a point on the line, and X is the x coordinate of the same point.\nSo plug in the point and slope to this form and you have:\n\ny - (-4) = 1(x - (-2))\nor\ny + 4 = x + 2\n\nYou can leave the equation in this form, or you can rearrange it so that it is in slope intercept form again.\n\ny = x - 2\n\nI hope this helped!
730934
First you have to find the equation of the line that contains these two points (9,1) and (5,5)\nI believe the easiest way to do that is to use slope and y-intercept form (y=mx+b) m= slope and b= y-intercept\n\nto find slope, m = rise/run\nrise = -4\nrun = 4\nrise / run = -1\n\nTo find y-intercept plug in a coordinate pair and use are found slope.( i used 5,5)\ny=mx+b  x= 5 y=5 m=-1 b =?\n5=(-1)(5) +b\n10 = b\n\nSo this is our equation of the two points\ny=-x +10 \n\nNow we can use this equation to find whether  (10,0) is on  the line: Substitute (10,0) and see if the equation is still valid\n\n 0 = (-1)(10) + 10\n 0 = 0 Yes (10,0) is on the same line as the other points
176995
The equation should be in the form y=mx+b where m = gradient or slope and b = y-intercept.  So you already know the equation is y = 2x + something since 2 is given to be the gradient.\n\nPut the x coordinate of your point (-3,5) in for x and put the y-coordinate in for y.  \nNow you have 5 = 2(-3) + something\n\nSimplify: 5 = -6 + something\n\nYou can find out what "something" is by adding 6 to both sides\n\n11 = something\n\nPut it all together and you get y = 2x + 11\n\nI hope you can learn what to do from this explanation so if you have any other problems you can do them yourself.
1102848
Slope of k = (2 - 4) / (4 - 1) = -2 / 3\n\nSlope of perpendicular = -1 / (-2 / 3) = 3 / 2\n\n(To find the slope of any line perpendicular to any other line you divide -1 by the slope of the first line).
832720
let line 1 make an angle x with the x-axis\nso the line perpendicular toit will make an\nangle of 90*+x with the xaxis\nm1=tanx\nm2=tan(90+x)\n=-cotx\nm1m2=tanx*(-cotx)=-1\nhence proved
908381
Note that I am using properties of standard form of an equation of a line (Ax+By=C) below.\n\nslope of a line from an equation in standard form is -(A/B);\n\nso the slope of your original line is -3/2.  Slope of a line perpendicular is the opposite reciprocal of the slope, so 2/3. \n\nUsing -(A/B), the left side of the equation will be:\n\n2x-3y; to find the right side, plug the point in:\n\n2(3)-2(2) = 6-4 = 2\n\nSo, an equation is 2x - 3y = 2
71640
you find to points on the line \nexample (2,5) and (1,6)\naight m= slope\nput the points in this simple equation\ny2-y1 (over) \nx2-x1\n\n6-5 over\n1-2\nwhich Equals  \n M= 1/ -1\nHoped it helped\nor try asking the teacher for help after school or at lunch
757381
to determine whether two lines are parallel or perpendicular or neither, we need to have their slopes.\nthe slope of a line passing through (x1,y1) and (x2,y2) is given by m=(y2-y1)/(x2-x1)\ntwo lines are parallel, if their slopes are equal\ntwo lines are perpendicular if the product of their slopes is -1\nfirst find the slopes of both the lines\nslope of first line is m1=(-3-2)/(9-5)=(-5/4)\nslope of the second line is m2=(1-6)/(8-4)=(-5/4)\nsince m1=m2, the lines are parallel, but not perpendicular
196300
wow i got confused by the answers. i will try to explain it simply in case anyone else got confused too. the equation   -7x-4y = 25 is an equation of a line. if you rearrange it to the y=mx+b form u get y = -7x/4 - 25/4 so the slope (m) of this line is -7/4. to get a line thatz perpendicular, u have to get the negative reciprocal. which is basically flipping the denominator and numerator and changing the sign. so the slope is 4/7. so now you use (x,y) = (2,-8) and m=4/7. and you solve for b in the y=mx+b equation. and once u get b, you have your equation for a line y = 4/7x + b.
766938
Use the forumula     delta Y/ deltaX to find the slope of the given points\n\n4-2/ 0-4   = -2/4 =  -1/2\n\n\nSince the perpendicular line is the equation  y = -1/2x; the other equation has the slope of the negative reciprocal of -1/2x so the equation would be \n\ny= 2x+b\n\nthen plugin x and y in this equation and you get\n\nb= -4\n\nso the final equation would be y=2x-4\n\n   Thats it
199440
find the tangent of the equation x+y=5
961745
the slope of the line perpendicular to that line would be the inverse negative of the slope of x-3y = 8\n\n(x-8)/3 = y\n\nthe slope = x/3, so the perpendicular line has a slope of -3x\n\ny = mx + b\n\nm = -3\n\nx = 5\n\ny = -4\n\n-4 = -15 + b\n\nb = 11 \n\ny = -3x + 11