I need help with these algebra problems, not just the answers but how to solve them?
912362
5 -(- 4)² / 9 - 4(- 5 + 12)\n\n5 - (16) / 9 + 20 - 48\n\n5 - 16 / 29 - 48\n\n- 11 / - 19\n\n- - - - - - - - - - - - - -\n\n7/8 - x/64 = 0\n\n7/8 - x/64 + x/64 = 0 + x/64\n\n7/8 = x/64\n\n8x = 7(64)\n\n8x = 448\n\n8x/8 =448/64\n\nx = 56\n\nThe answer is x = 56\n\n- - - - - - - - - -\n\n-(40 + 72x) = 56x - 8(5 - x)\n\n- 40 - 72x = 56x -  40 + 8x\n\n- 40 - 72x = 64x  - 40\n\n- 40 - 72x + 72x = 64x - 40 + 72x\n\n- 40 = 136x - 40\n\n- 40 + 40 = 136x - 40 + 40\n\n0 = 136x \n\n0/136 = 136x/ 136\n\n0/136 = x\n\n0 = x\n\n--- - - - - -- -s-
790308
1.  5x + 7= 3x + 21\n     -3x       -3x\n     2x + 7 = 21\n           -7    -7\n     2x = 14\n     /2     /2\n        x = 7\n\n2.  3x - 2 (5-x) = -3(x-10) + 3x\n     3x - 10 - 2x = -3x + 30 + 3x\n     x - 10=30\n     x=40\n\n3.  5( x+1) = 3(2x +3) + 5\n     5x + 5 = 6x+9 + 5\n    5x+5=6x+14\n    5=x+14\n    x=-19
504285
It has been a long time, here are suggestions:\n1. 5x^3 + 11x^2 + 3x + 1  \n2. 4x^3 - 13x^2 - 8x + 7 \n3. 2x^4 - x^3\n4. 21x^2 + 26 x + 8
833452
INSTEAD of giving you the answer directly -- here are the steps to solve and simplify.\n\nWRITE down the equations on separate lines -- leave about 4 lines between each problem.\n\nNOW -- draw connecting lines between the LIKE TERMS (for example -- in the first problem (4x+6-2x+6) the like terms are those that have the 'x' value with them and the other set of like terms are the constants with NO variables with them) -- I would use two different color pencils to do that)\n\nso add the 4x and 2x together (Answer is _x) -- then add the constants (those numbers without variables together (or +6+6)) together (Answer is __).\n\nNow put these two results together on the 3rd line.\n\n\nFinally, factor out any common terms in the results.\n\nTHAT is your final answer and the simplified expression.\n\n\n\n\nFOLLOW these steps once again for the 2nd problem -- but now instead of the variable being 'x' it is now 't'.\n\nNOW
953801
Get a tutor, get your parents to help you, read through the chapter in your Algebra book that you're currently doing, if your school has extra help with teachers go to the help sessions, study with your friends, form a study group, and do the extra practice problems for the current chapter in the back of your book for learning how to do the equations and stuff. I am also in your same grade doing Algebra 1 Honors. Hehe, I should take my own advice!
362703
Free Video lessons!   \nForum/Help Center  Ask for help and help others \nand much more\nhttp://www.algebra.com/
396545
http://www.math.com/ or http://www.gomath.com/algebra.html are good places to start.
651993
Here's the best I can do to help with the first one.\n   __x_+9___\nx-2)X^2+7x-2\n    x^2-2x\n    ------\n        9x-2\n        9x-18\n        -----\n           16\nFollow the example for the rest
775488
Ok, Victoria, if you're going to ask for help you have to write the questions correctly.  Problem 1 cannot be solved using algebra the way you wrote it, I doubt you can use complex integration or any other advanced tool to solve that one.  Unfortunately, I just spent the last half hour manipulating it before I remembered that little fact.\n\nPut parentheses in.  Had you put the parentheses in the problem would have been trivial.  Kudos to the helpers who were smarter than I in figuring out the constants were in the exponent.  It's not that hard Victoria, especially when you're asking for help.\n\nWrite the question correctly.\n\n\nPS. Irma, you forgot to multiply the 2 from 4=2^2 through the whole parenthetical statement.  The answer is x=4.\n.
1162328
1) -  Y-2x-8 = 0 - so Y=-2x-8\n2) -  Y^2 +8x=0 - (-2x-8)^2+8x=0 \n\n\n4x^2+32x+64+8x=0\n\n4x^2+40x+64=0 - so (4x+8)(x+8)=0 so x=-8 or 4x=-8, x=-2\n\nWhen x=-8, Y-2(-8)-8=0 so Y=-8    A=(-8,-8)\nWhen x=-2, Y-2(-2)-8=0 so Y=4     B=(-2,4)
102673
If you can't get an answer here, try asking your Algebra teacher for extra help after school tomorrow.  It's sure to add to your grade that you asked for the help.
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
516830
http://www.gateways2learning.com/Algebra/Algebra.htm\n\nAlso try here.......\n\nYou may want to reconsider having it solve the answer for you, always know how to do the breakdown, it will help you to know "how" to go about it when you take a test.\n\nGood luck.....................
890645
Wow, there is a lot here!  I'll start with some tips for solving algebra problems.  The first thing you should always remember is to play the equal game.  Whenever you add, subtract, multiply, or divide, you should do the same to the other side.  The other tip is to use the order of operations when simplifying.  Remember the sentence: Please excuse my dear Aunt Sally.  The initial letters of each word stands for the order of operations.  Do the Parenthesis first, followed by the Exponents, then Multiplication or Division, and Addition and/or subtraction next.  Finally, you should always simplify first using the order of operations before you start shifting numbers from one side of the = to the other.  \n\nI'm not going to work all of these problems, but I'll show you a few to get you started.\n\n1)\n3x-7 = 2   Add 7 to both sides\n3x = 9   Divide by 3\nx = 3\n\n4)\n6x - 3 = 2x - (4-3)/3   Simplify the stuff inside the parenthesis first\n6x - 3 = 2x - 1/3  Add 3 to both sides\n6x = 2x - 5/3  Subtract 2x from both sides\n4x = -5/3  Multiply both sides by 3\n12x = -5  Divide both sides by 12\nx = -12/5\n\nI hope this helps.  Good luck!
1106533
1) 6(x-4)(x-2)\n= 6(x^2 - 2x - 4x +8)\n= 6(x^2 - 6x + 8)\n= 6x^2 - 36x + 48\n\n2) (x+7)(x+4)-(x+3)(x+2)\n= (x^2 + 4x + 7x + 28) - (x^2 + 2x + 3x + 6)\n= (x^2 + 11x + 28) - (x^2 + 5x + 6)\n= x^2 + 11x + 28 - x^2 - 5x - 6\n= 6x + 22
768805
Factor out the 3:\n3(x^2+3x+2)\nUnfoil:\n3(x+1)(x+2)\nTake the roots:\nx=-1 or -2
953940
Hi again \n\nY = √2x – 3 \n2x – 3 = y ²\nX =( y ² + 3 )/ 2\nf –¹ (x)  =( y ² + 3 )/ 2  =>   f –¹ (x)  = (x ² + 3 )/ 2   &  x ≥ 0 \n\nGood Luck \n try to solve them yourslef again if you got wrong , am sure you can solve them correctly , if you just try your best