How can I make an even solution without a vortex?
924829
I have an answer to your question, but its easier shown than explained.\n\nI will now attempt the explanation;\n\nI am right handed BTW.\n\n(1) put tube in left hand\n\n(2) hold tube up to light so you can see manual vortex as you perform it (this is critical, because you need to see the tiny air bubbles swirl around in the mix)\n\n(3) flick BOTTOM of tube with forefinger 30-40 times GENTLY.\n\nThis is such an important technique, but often overlooked in experiments.  It is an important variable in experimental outcome.  \n\nBelieve it or not, poor mixing techniques often account for poor results.  \n\nNot only that, but the VORTEX-ER  is NOT always the best way to mix stuff up.  It can be too harsh, depending on what you have in the tube.\n\nFor example, I work with DNA (which is a very long molecule).\n\nI want it to be in its most native and natural state (which is a very long molecule, as I just mentioned).  If I VORTEX a tube containing DNA, I run the risk of MECHANICALLY breaking up the molecule.\n\nThe method I am describing is the best because it is gentle (no matter what size molecules you are working with) and fool proof.\n\nLet me just add this side note:  The smaller the molecules you are working with the less times you have to flick your tube.  I would not go below 15 times though.  \n\nThis is an important question to Scientists!   And I had fun thinking about the answer.  Please spread the good Karma!
856026
Use the gas law\nPV=nRT
54459
I agree with you. V!\n\nBTW, wrong forum.  Try the math forum under "Science and Math."  And this isn't Jeopardy, so try giving a question to get an answer.
624146
check brilliant tutorials homepage...they have posted the solutions...by the way was there a set A  as well?? anyways good luck!
126044
Stand on your head.\n\n16=8+8 and you haven't even changed the equation...(including what direction it's facing)
710256
You got the CG just right.  Your method might work with enough concentration., but I would look at making the angular momentum come to zero:\nL = Iω = (2.7*.325²  + 1.3*.675²) * 26rpm*2π/60 = 2.389 kg m²/s\n\nTo stop the movement the angular impulse must equal the - of the angular momentum:\n\nT * t = L→ T = L/t = 2.389/5.8 = .4118 Nm (ccw)
712410
limit theta tending to 0 sintheta/theta =1
694807
Use conservation of impulse and conservation of kinetic energy.\n\nmv + 0 = mu + mw\n(1/2)mv2 = (1/2)mu2 + (1/2)mw2\n\nu + w = 1 (consider it as a straight line in a graph)\nu2 + w2 = 1 (consider it as a circle in that graph)\nWhen you solve this set of two equations, you get\nu = 0 and w = 1 (m/s)\n(Find the useful intersection. The other one is is the initial situation.)\n\nTh
52637
I had a similar problem not long ago. How I solved it was by following the directions at [1]. Hope this helps!
188376
I was a rock star in college physics!   Top of the class!  But I can't remember any of it now.  My teacher always said to start each solution by drawing a picture, then making a list of the varriable you know, and writing down the equations you thik you might need to solve.  It worked for me!\n\nPost your problem, maybe I can help.  Traditional physics problems have not changed much in the last 5 years, maybe I can remember.
288780
From the following link, look for "Chapt22, Problem-24".\n\nThis problem is similar, except the speed is 10% instead of 11%. I'm sure you can use the same formulae though.\n\nhttp://www.jca.umbc.edu/~george/html/courses/phys112/2004fall/homework/04fall_phys112_hk8.pdf
941165
Maybe you should try one of those little beanie hats with the propellor on top...If you get it spinning pretty fast, I'd bet you could get a few more inches  on your vertical and a hell of lot more hang time
751049
First find Vo:  Vo^2 = Rg/sin(28)  Where R = range & 8 = theta\n\nUsing your numbers, Vo = 41.523 m/s\n\nImpulse = change in momentum ----> Ft = mVo---> F = mVo/t\n\nSo, F = (.0431kg*41.523m/s)/.00438sec = 408.59 N\n\nVoila!
826674
use conservation of angular momentum in these kind of problems\nNOT energy conservation\nif you dont know how to use the conservation equation, better read up on examples
1166430
Make a Dodecahedron. That's what I did.
247965
infinite values for both,\nits caus u cant solve two variables with just one equation
96716
Turn it any number of degrees!\nMaybe you mean only 0 or 360 degrees, because the 'T' or 't' has no rotation symmetry.