Does anyone know what the standard potential is for [Ag(NH3)2]?
913031
Standard electrode potential for Ag(NH3)2 = 0.37V
308551
Xavier is dead wrong. NH4+ is tetrahedral. Most of his answer applies to NH3, which is trigonal pyramidal, and not the same thing as NH4+.\n\nPolar molecules have a large net electrical dipole moment. In a sense, the dipole moment tells you how close you are to becoming an ionic compound. If there is no net dipole moment, the compound is completely non-polar. On the other extreme, if it's an ionic compound, it's completely polar.\n\nLook carefully at your question. NH4+ is an ion, not a molecule, and the terms "polar" and "non-polar" don't really apply to ions. The reason is that ions must be part of an ionic compound, and the ionic compound would be considered polar by definition. For example, (NH4)Cl is an ionic compound and therefore very polar, but asking whether NH4+ is polar is no different than asking whether Cl- is polar.\n\nA couple of good textbooks for further information and examples would be "Organic Chemistry" by Solomons and "Organic Chemistry" by Peter Vollhardt.
903130
Na2SO4(aq)+ 2 AgNO3(aq)-->Ag2SO4(s)+ 2 NaNO3(aq).
383259
go to\nwww.chemistry.com
712728
choose the noble gas that comes before the element.   in Mn(2+)'s case, that's Ar\n\nwrite the noble gas down in brackets, and continue on with the electron config. as normal\n\n[Ar}4s23d3\n\nFor O(2-), it turns into Neon so it would just be [Ne]
613727
try:\nhttp://lb.chemie.uni-hamburg.de/static/data/50_zzk46n8n.html
962694
Tehe answer is:\nAg + HNO3 -> AgNO3 + H\nAgNO3 + KBr -> AgBr + KNO3
36586
Ag+ + SO4(2-) ---> Ag2SO4\nYeah, it's double replacement, and according to my solubility rules, AgSO4 is insoluble.
904363
(NH4)2CO3+MgSO4->(NH4)2SO4+MgCO3
438289
Co(NH3)4 would be more likely
937526
If the reaction would "go" it is written: 3H2 + N2 = 2 (NH3)\nFill in the atomic masses of H = 1.00797 and N = 14.0067:\n[3 x 2 x (1.00797)] +[ 2 x (14.0067)]  = 2 x (14.0067) x 3 x (1.00797) = 34.06122\nThis is the stochiometric ratio of elements needed. You have 2.04 gm of H2, so multiply each term by 2.04 / 6.04782 to get:\n2.04 + 9.4492 = 11.4892. In other words, all of the H2 combines with about 9.45 gm of N2 to yield about 11.49 gm of ammonia with about 1.9 gm of N2 left over.
787375
1. AgCl(s) + NaNO3\n\n2. AgOH(s) + NaNO3\n\n3. They would not react as both are nitrates already
176528
http://www.chem1.com/CQ/ionbunk.html\n\nskim this article.
857220
NH4 if the compound is not usually charged but people will tell you NH3 because that is what wikipedia says because the people who say that are too lazy to work out the problem and see that Nitrogen can also have a -4 charge. NH3 has a neutral charge and NH4 has no charge also but can also have a -1 charge. \n\nAs I said some idiot with wikipedia right above me\nIt depends on what kind of ammonia you are talking about.
138848
Here is one example ,\n\nAgNO3(aq) + NaCl(aq)-> AgCl(s)white precipitate + NaNO3(aq)
150155
Carbon bound to Nitrogen by a triple bond.
496847
N2- has a bond order of 3.\n\nhttp://www.meta-synthesis.com/webbook/39_diatomics/diatomics.html