the distance between two wave crests in the water is 3 meters.?
915373
Each crest travels 3m in 6 s, so the wave's speed is 3/6 = 1/2 m/s.
593131
The incident ray is perpendicular to the surface of reflection.\nThen one has the least distance case.
501508
3853 feet (1175 meters)?
580754
i haven't done this in a while.\n\nThe volume of the reservoir is equal to (1/2)*(height)*("base")*length.  the reservoir is a rectangular prism with the "base" being the distance across the surface of the water.  We are given the shape of the full volume so we can scale down to the level of the water to find what the volume in the reservoir at its current level.\n\nif you think about the cross-section of the volume, and use half of that forming a right triangle, we can determine the ratio of the surface (the "base") to the height (water depth).  In this case, it is (40/2)/(20*sqrt(3)) or 1/sqrt(3).  so ("base"/2)/(height) = 1/sqrt(3)  and then "base" = (2*height)/sqrt(3).\n\nsubstitute that into the volume equation so that\nvolume = [(height^2)*length]/sqrt(3) or literally,\nV = [(h^2)*L]/sqrt(3).  differentiate with respect to time,\n(dV/dt) = [2*h*(dh/dt)*L]/sqrt(3) and substitute the numbers in:\ndV/dt = 200 - 50 = 150\nh = 10*sqrt(3)\nL = 450\nand solve for dh/dt which is the rate of change of the water level in yds/hour.  these are odd units, you might want to change to inches/hour.\n\ni did it this way and got 1/60 yds/hr or 0.6 inches/hr.\n\nbut again it has been a long time....
20069
It depends a lot on how high above the water your eyes are and how tall the distant object is.\n\nThe radius of the Earth at the equator is 6378135 meters.  Assume your eyes are 2 meters above sea-level, and the distant object is at sea-level.\n\nYou have a right triangle, where the longer leg is the radius of the Earth, and the hypotenuse is 6378315 + 2.  The shorter leg is the distance to the horizon.\n\nThe distance to the horizon = √(6378317^2 - 6378315^2) = 5051 meters, or about 3 miles.\n\n\nIf the distant object is 2 meters above sea-level, then it'll disappear when it's another 3 miles past the horizon, or 6 miles from you.
678647
The water starts from one end and reaches the other end in 30 minutes\n\nThe distance traveled is 1700 meter. Time taken 30 minutes = 1800 second.\n\nThe velocity is distance traveled per second. Therefore, it is 1700 /1800 m/s =0.94m/s
698513
The boats path as viewed from an observer on the bank will be a the hypotenuse of a right triange.  It moves along that hypotenuse at a speed of 4.5 m/s and has traveled 27 m on that path.  therefore the time it took to get across was 27/4.5 seconds.  In that time, it travelled downstream 11m.  The river current is what was carrying it downstream and moved the boat 11m in 27/4.5 second.  Velocity is distance/time so the river current is 11 / (27/4.5) m/sec
326563
Zero.\n\nThere are just over 3 feet (3') in a meter, though.\n\nFYI...\n\n1 Yard = 3 Feet\n\n1 meter is CLOSE in size to 1 Yard.\n\nMeter is just barely larger.\n\n1 foot = 0.304 800 609 6012 meter\n1 yard = 0.9144 meter
315486
200cm < 200dm \n\n200cm = 2m\n200dm= 20m
164646
You mean a 'frequency of 5.10^12Hz'\n\nCan you work it out yourself?:\n\nRemember that the speed (v) of the wave is 3×10^8 m/s,\nand that the wavelength is given by v/f\n\n[Edit: Darn, Kirchwey - don't do Glow's homework for her! ;-) ]
639920
its simple.\nwhen boat travels downstream the two velocities add up to give the answer 15+3=18km/hr.\nwhen boat travels upstream the velocity of river gets subtracted from velocity of boat which gives the result as 15-3=12km/hr.
75525
a) 72.072 cm/sec^2\n\nb) 82.63 cm/sec^2
889524
The sound waves bounce of the whale and come back. Now the waves have travelled for 0.4 seconds more or 2000 feet more. so the further microphone is 1000 feet further from the whale.
277745
Answering...\n\nBasic Equation:\n\nSine:.. y = a sin bx\nCosine: y = a cos bx\nwhere:\namplitude = absolute value of a (always positive)\nPeriod = 360 degrees/absolute value of b or 2pi/abs b\n\nEX: y = sin 4x\namplitude = abs a = 1\nPeriod = 360 deg./abs. b = 360/4 = 90 deg.\n\nEXPLANATION:\n\nSine Function\n1. The graph looks like a regular sea wave.\n2. For positive function, along the y-axis, the graph starts at the origin and then it goes up like a wave until it reaches the peak (called crest).\n3. Then it goes down until it reaches its lowest part (called trough).\n4. Then the cycle is repeated.\n5. For a negative sine function, from the origin, the graph goes down to its trough and then up again.\n\nCosine Function:\n1. The graph also looks like a regular sea wave.\n2. For a positive function, the graph (along the y-axis) starts at the its crest.\n3. Then it goes down until it reaches its trough.\n4. Then it goes up again until it reaches its crest again.\n5. The cycle is repeated.\n6. If the function is negative, along the y-axis, the graph starts at its trough first. Then it goes up.
637941
3 feet and 2 1/2 inches
966711
The volume of the water in the cup at any moment is:\n\nV = (1/3) pi [ (Rw)^2 + (1)Rw + (1)^2 ] \n   = (1/3) pi [ (Rw)^2 + Rw + 1 ] h\n\nRw = Radius of upper part of water\nh = height of water\n\nRw / h = 2 / 6\n\n6 Rw = 2 h\n\nRw = 1/3 h\n\nSubstitute in to the volume equation\n\nV = (1/3) pi [ (1/9) h^2 + (1/3) h + 1] h\n = (1/3) pi [ (1/9) h^3 + (1/3) h^2 + h ]\n\ndV / dt  = (1/3) pi [ (1/3) h^2 + (2/3) h + 1] (dh / dt)\n\nSolve for dh /dt  and plug in the values h=4 and dV/dt = 3
862702
1 meter = 3.2808399 feet = 3 feet, 3.36 inches\n\nI hope this helps!