wirte equation in slope-intercept form contains (3,-5) is parallel to 5x-2y=10?
928485
First solve for y to find the slope.\n5x - 2y = 10\nSubtract 5x from each side\n-2y = -5x + 10\nDivide everything by -2\ny = (5/2)x - 5\nThe slope is m = 5/2\nSince you want a line that is parallel, that means the slope of the new line will be the same as the slope of the old line.\nUse your point to find the equation.\ny - (-5) = (5/2)(x -3)\ny + 5 = (5/2)x - 15/2\ny = (5/2)x -15/2 - 5\ny = (5/2)x - 25/2
796832
5(2^2)+5(2)+2y=2\n2y=-28\ny=-14\n10x+5+y+x(dy/dx)=0\nx(dy/dx)=-10x-5-y\ndy/dx=(-10x-5-y)/x\n(-10*2-5-(-14))/2\n-11/2\ni hope thats right
346120
The equation of a line in slope-intercept form is given by \ny=mx+b where m is the slope and b is the y-intercept.\nAll you have to do is plug the numbers in.\nso the equation is y=9x-3
172343
the easiest way to find a y-intercept is to just plug in 0 for x.\n\nSo, you get:\ny-3=2(0-5)\ny-3=2(-5)\ny-3=-10\ny=-7
806897
First equation:\n4x + 2y = 10\n\nRearrange to get the y-term alone:\n2y = 10 - 4x\n\nDivide both sides by 2 to get it in slope-intercept form (y = mx + b):\ny = -2x + 5\n\nNow you can graph it by drawing a line through (0,5) as the y-intercept and have it go down at a slope of -2 through points (1,3), (2,1), (3,-1), etc.\n\nFor the second equation, draw a horizontal line for y = 4\n\nYou'll see they intersect at the point (½, 4).  I've attached a graph of the two lines...\n\nSo your solution is:\nx = 0.5 (or ½)\ny = 4
218561
A parallel line must have the same slope.\nSo you just need to find slopes of the lines that  you have.\n1) 5y= -4x - 11\ny = -4/5x -11/5\nthe slope m = -4/5\n\n2) 4y= 5x-7\ny= 5/4x -7/4\nthe slope m = 5/4
92961
The slope intercept form is y=mx+b. Basically, you solve for y. For your formula, you would do the following.\n\n6x + 9y = 27   (Simplify by dividing by 3)\n2x + 3y = 9    (Move x to right side of equation)\n2x - 2x + 3y = -2x + 9 (Simplify)\n3y = -2x + 9   ( Divide by 3 to solve for y)\n3y/3 = (-2/3)x + 9/3 (Simplify)\ny = (-2/3)x + 3\n\nThe (-2/3) is a negative two thirds. I just couldn't put that in this little box.
197787
y = 3/5x+q (q is free to choose) is parallel to y = 3/5x-5\nEach has the same slope: 3/5\ny = -5/3x+r (r is free to choose) is perpendicular to it,\nso its slope is -5/3
143646
LET US SEE:\n\n1. y = (1/2)x + 5. This is an equation in standard form.\nIt is called slope-intercept form. If you mean general form\nthen:\n\ny = (1/2)x + 5\n\nMultiply by 2:\n2y = x + 10\n\n0 = x - 2y + 10\n\nx - 2y + 10 = 0  ANSWER\n\n=======================\n2. Line parallel to y = (1/4)x + 2:\n\nAny line parallel to y = (1/4)x + 2 has the equation:\ny = mx + b  ===> Equation of line\nwhere:\nm = slope = same as slope of given parallel line = 1/4\n\ny = (1/4)x + b ANSWER (equation of parallel lines)\n\nex:\na) y = (1/4)x + 0\nb) y = (1/4)x + 1\nc) y = (1/4)x + 3\nd) y = (1/4)x + 4\nd) y = (1/4)x - 1\ne) y = (1/4)x - 2\n.\n.\n.\n\n=======================\n\n3. y varies directly as x ; y = 2/3 and x = 1/2.\n\ny = kx (direct variation equation) where:\nk = constant of variation\n\nif y = 2/3 and x = 1/2:\n\ny = kx\n2/3 = k(1/2)\nk = (2/3)/(1/2)\nk = (2/3)(2/1)\nk = 4/3\n\nTherefore:\n\ny = (4/3)x ANSWER\n\n=======================\n4. Line passing thru (0,2) and perpendicular to \ny = (1/4)x + 2\n\nLet m = slope = -4 = negative reciprocal to slope\nof perpendicular line.\n\ny = mx + b  ==> slope-intercept form, where:\n\nm = slope\nb = y-intercept\n\nSolving for b, use point (0,2)\n\ny = mx + b\n2 = -4(0) + b\n2 = 0 + b\nb = 2\n\nTherefore, equation is:\n\ny = -4x + 2 ANSWER\n\n=======================\n\n5) Point(s) that lie on the graph of the equation \n\n3x + 6y = 27.\n\nThese are points that will make the left side of \nthe equation equal to 27.\n\nEX. ...;(-5,7)(-3,6)(-1,5);(1,4);(3,3);(5,2);(7,1);...\n\n=============================\n6. Equation of the line that contains (2,4) and undefined slope.\n\nA line that has an undefined slope is a vertical line. So,\na vertical line that contains (2,4) has the equation:\n\nx = 2  same as the x-coordinate of the given point.\n\n===========================\n\n7. Equation of the line that passes thru the x-axis \nat x = -1 and y-axis at y = 3.\n\nFrom the given intercepts, the two points are (-1,0)\nand (0,3)\n\nTherefore:\n\ny = mx + b ===> equation in slope intercept form.\nwhere:\nm = slope = (3-0)/(0--1) = 3/1 = 3\nb = y-intercept from point (0,3) = 3\n\nTherefore:\n\ny = mx + b\n\ny = 3x + 3 ANSWER.
114816
-3+5=5-3y+4y       \n   2=5+y\n  2-5=y \n   -3=y\n because...          2=5-3(-3)+4(-3)\n                     2=5+9-12 \n                     2= 14-12         \n                     2=2
892026
The slope intercept form is y=mx+b\n\nSo we rewrite the equation of the line as so:\n\nx - 2y = 5  , subtract x from both sides\nx - x -2y = 5 - x\n-2y = 5 - x  , now divide both sides by -2\n-2y/-2 = (5 -x)/-2\ny = -5/2 + x/2  , rearrange the left side\ny = x/2 - 5/2\n\nSo the slope (m) is 1/2.  Now we use the point given and the general equation.  From the point we know that x=2 and y=-4.  Sustitute these into the general equation.\n\ny = mx +b\n-4 = (1/2)2 + b  , do the math\n-4 = 2 + b ,subtract 2 from both sides\n-4 - 2 = 2 - 2 +b\n-6 = b\n\nSo the equation of the required line is:\n\ny = x/2 - 6
779591
well, you have to set up two questions in point slope form. (ie. equation for the line)\nso for your first question:\n\ny-9 = 2(x-5)\ny-3 = 2(x-r)\n\nso simpliy to be\n\ny = 2x - 10 + 9\ny = 2x - 2r + 3\n\nand simplify again to be\n\ny = 2x - 1\ny = 2x - 2r + 3\n\nand from here.. i'm drawing a blank. but that should help.. maybe?
197692
y-5-y-5=7y\n-10=7y\ny=-10/7
829794
The standard equation for slope-intercept form is y=mx+b. m is the slope and b is the y-coordinate of the vertical (y) intercept\n\n-2x=y+3       Original equation\n\ny=-2x-3        Rewritten in S-I form\n\nm= -2, b= -3\n\nThis means that the graph of the funtion is a line through the y-axis at the point (0, -3) with a slope of (-2)
1092839
y=0 is the x-intercept\n\nso 5(0)-3x+4=0\n\n-3x=-4\n\nx = 4/3\n\nx-int = (4/3 , 0)
826923
The easiest way to do this would be to put the equations into slope-intercept form and compare the slopes.  If the slopes are the same, the lines are parallel.  If the slopes are the negative reciprocals of each other (like 2/3 and -3/2), they are perpendicular.  If neither, then neither.\n\n3x + 6y = 30\nx + 2y = 10\n2y = -x + 10\ny = (-1/2)x + 5\n\nSlope:  -1/2\n\n4y + 2x = 9\n4y = -2x + 9\ny = (-1/2)x + 9/4\n\nSlope:  -1/2\n\nYour call here.
949123
2x + 5y = 15\n\nSo 5y = 15 - 2x\n\nSo y = 3 - 0.4x\n\n3 is the intercept. -0.4 is the slope