Did i do this right...7-13i/2i?
914360
You need to put parenthesis around your numerator if you mean that 7-13i is on top of the fraction.  You also are canceling the terms wrong.\n\nI am not sure what the problem is asking you to do.\n(7-13i)/(-2i)\nThat is already in its simplest form; the only thing you could do to it is make it read:\n-3.5/i + 6.5\nand that is more of a personal preference thing than a practical, useful thing.  If you are trying to find the value of i, you have to tell us what (7-13i)/(-2i) is equal to.
784392
Here is what i found.  I'm not sure how right this is, but you can check it out.  Good Luck with your testing.
934849
291.13 L is the correct volume.\n\nCheck your algebra when you are solving for V1.
772712
(9+7i)(9-3i)/(9+3i)(9-3i)\n=(81+21+36i)/(81+9)\n=102/90+(36/90)i\n=(51/45)+(2/5)i
703752
simply subtract 7 from both sides. This leave you with\n\nx<_3
511277
rationalising both numerator nd denominator by the conjugate of the denomenator.\n  2+i/1-3i  mutiplied by 1+3i/1+3i\n =(2+i)(1+3i)/(1-3i)(1+3i)\n =2+6i+i+3(-1)/1-3(-1)\n =2+7i-3/1+3\n =7i-1/4\n =7i/4-1/4......is ur answer.
981364
Gopal has the correct answer! \n\nSo... becareful with some other results... and... never use:\n0.833 instead of 5/6... it's a mistake!\n\nFinished Algebra with 19!
42679
28:  1, 7\n155:  1, 5\n\ni think
950386
Remember that i = sqrt(-1)\n\n(-2+5i)(-6-5i) = 12 - 30i + 10i - 25i^2 = 12 - 20i -25(-1) =\n12 - 20i + 25 = 37 - 20i
584190
Correct.\n\n(1350+99)*1.06
543826
(x+2)*(x-5i) = x^2+(2-5i)x-10i\n\nsomehow, i dont like these complex #'s\n\nyeah, the answer below mine is probably correct.\n\n(x+2)*(x-5i)*(x+5i) = ...
454578
mrniceguy's answer is correct, but he has one little eror in the work.  i^7 = -i
839453
1) 21.69\n2) 14.10\n3) 7.59
78988
I2 + 2NaCl ---> 2NaI + Cl2\n\nSodium Iodide and Chlorine
572398
first multiply i by everything in the first bracket.\nso -8i * i + 3 * i + 2(2-5i)\n\nthen do same with 2nd bracket\nso -8i^2 + 3i + 2*2 - 5i*2\n= -8i^2 + 3i + 4 - 10i\n\nnow collect all the like terms\n-8i^2 + 3i - 10i + 4\n= -8i^2 - 7i + 4\n\nnow if i is the imaginary number i^2 would be -1.\nso it would be 8-7i +4 = 12-7i\n\nhope that helps. laterz
116087
keeping with the same unit fractor harry is correct.\n \n .2 ml
611131
Depends on which 'unit' you're talking about   :P