how big an air tank would i need to hold 160,000 cf of air?
915015
You would need a tank about the size of a house (55ft cube) unless you compress the air then it would be much smaller.
925743
This is pretty straightforward.\nFirst you have to write the formula fo rthe cost of the tank as a function of, say, its radius, r:\n\nThe volume of the cylinder is 100 cubic feet.\nIt is also pi*r^2 times the height, h\n\nso let's solve for h\n100=pi*r^2*h\nh = 100/(pi*r^2)\n\nnext, the cost:\nthe rectangle cost is 2.40*(h*2*pi*r),\nor 2.4*100/(pi*r^2)*2*pi*r\nor, simplifying, 480/r\nThe cost of the base and top are:\n1.50*2 pieces * pi*r^2\n\nSo the total cost is\n480/r+3*pi*r^2\n\nNow you need to differentiate this and find the roots, and make sure they are minima, not maxima!
123629
with or with out diving gear? [air tank}  don't know
264523
1 ft^3 = 7.48 gallons.  You will therefore need a box with an internal volume of 2.139 ft^3 (or 3696.257 cubic inches).\n\n12" x 14" x 22" will work.  OR 12" x 12" x 25.67"  OR ....
1005734
That's a bit high...usually want to operate at about 40-45 C or less. Get yourself a better heat sink and cooling fan, and maybe a better cooled case.
569075
well i know with simple instructions!\n\nTo measure how much air your lungs can hold by making a spirometer.\nInstructions: Lung Capacity\n1\nWhat You Need\n• 2 or 3 liter plastic bottle\n• Large, deep bowl or plastic dishpan\n• Water\n• Masking tape\n• Measuring cup\n• 30 cm (1 foot) long piece of flexible tubing (aquarium tubing works well)\nTo Do and Observe\n1. Vertically attach a strip of masking tape to the plastic bottle, from the\nbottom to the top of it. Fill the measuring cup with 60ml of water. Pour\nthe water into the bottle. Mark the water level on the tape. Repeat until\nyou've marked to the top of the bottle.\n2. Fill the dishpan about 10cm (4 inches) high with water.\n3. Fill the plastic bottle to the top with water, and hold your fingers over the\nmouth of the bottle so the mouth is completely covered.\n4. Invert the bottle into the pan of water. Make sure you do not remove your\nfingers until the mouth of the bottle is completely submerged. Insert one\nend of the tubing into the mouth of the bottle.\n5. Take a breath and exhale completely into the open end of the tubing.\n6. Measure how much air is now in the bottle (count the marks). To calculate\nyour lung capacity, multiply the number of marks by 60ml. If your pan is not\ntoo full of water, you can repeat without filling the bottle back up.\nWhat's Going On\n• The amount of air you can hold in your lungs is called lung capacity, and\ncan be measured with a spirometer. Blowing air from your lungs into the\nbottle forces a measurable amount of the water out of the bottle, which\nadds to the volume of water in your pan. This method of measuring uses\ndisplacement – you're displacing a volume of water with a volume of air.\nInstructions: Lung Capacity\n• Displacement is often used when something can't be measured directly. What else could you\nmeasure using displacement?\nTips\n• Check for variations in lung capacity in people of different sizes (older students,\nyou). Ask your class to look for a correlation between body size and lung\ncapacity.\n• Have each participant test for a difference between a "normal" breath of air and\nan "expanded" deeper breath.
570799
I think you talk about a Paintball Marker Tank. They are High Pressure Air Tanks, can shoot paintballs. 3000 psi is near 210 Bar (Atmosphere). It means Its not a toy :D
1052394
144 square feet\nhow many gallons fit in one square foot?
803330
i got the same answer \nusing the equation PV / RT = n, i found the number of moles of the tank, which is 264.  Then using the same equation find the balloon, which i got was .138 moles.  Then divide and i got 1.91*10^3 balloons
29809
It depends...how big are you aiming for?\n10 inches or double that. If its in the 10-20inch range, your heart will have to work overtime to "fill it up," if you catch my drift. Any bigger and you'd need to be an elephant.
174339
Try to compress your lungs.  All that air takes up much needed space.
695589
Solve for the smallest tank, witha volume of 10,000 m^3 \n\nSurface area of the tank would be\n(height of the tank x circumference of the tank) + piR^2 \n\nvolume of the tank = 10000m^3 \nh*piR^2\n\nAs you change the values of H and R to get you volume the surface area will change. Solve for a minimum value.\n\nThe dimensions of the small tank then determines the radius of the hemisphere that it would take to hold that tank.
520946
one gallon per inch of fish is the rule of thumb with fish tanks.  More if you aerate the water.
979901
Between 160 and 170 degrees.
315401
Use PV=nRT ideal gas equation.\nP=0.400 atm\nV=?\nn=3 mol\nR=0.0821 L atm /K/Mol\nT=300K\n\nDo yourself now...
550091
Depends on local airpressure and weight of the man.\nAt 1013 millibar (= 1 atm) the mass of 1m³ of air is 1.29 kg\nand the mass of 1 m³ of helium is 0.178 kg\n\nTo make a mass of 75 kg weightless you'll need 75/(1.29-0.178) = 67 m³ of helium, to lift it a little bit more.
443013
It depends on how far out of the water you wish to be.  Humans are very close to being bouyant-we are more dense than water, but have lungs full of air, thus a lean man with a large lung capacity is bouyant with a deep breath.  Its isnt the pounds of air that matter, its the pounds of water displaced by the air.  If you hold onto a 10 gallon jug full of air, it displaces 10 gallons worth of water, which is about 80 pds-well more than you need to keep your upper body above water.  For a 200 pd man, he would need an water-displacing container of 25 gallons (this could be a boat or anything else that displaces water for air).