Arrange the following in order of increasing mass percent of carbon; A. C8H10N4O2  B. C12H22O11?
912377
A has a higher percent carbon than B.\n\nThe molecular mass of A is 194 g/mol and it contains 96 g/mol of carbon.  96 g/mol carbon /194 g/mol molecule A = 0.495 = 49.5% carbon\n\nThe molecular mass of B is 342 g/mol and it contains 144 g/mol of carbon.  144 g/mol carbon/342 g/mol molecule B = 0.421 = 42.1% carbon.
363082
2Ag+ + CO_33-2 -> Ag_2CO_3
725621
6Rb(s)+N2(g)--->2Rb3N(s)
737487
The mass percentage of carbon in CH2O is 4%.  You can solve this by first calculating the molar mass of CH2O (which is 30.0262 - you obtain this by adding the atomic mass of each element, 12.011 for C since there is only one, 2.0158 for H2 since there are two Hydrogen, and 15.9994 for oxygen since there is only one oxygen).  After you got the molar mass, you divide the amount of Carbon that is in the compound (in this case, it's 12.011 since there is only 1 carbon), and you get approximately 0.4000.  Multiple that by 100 and you get approximately 4%.
954811
C3H8 + 5O2 --> 3CO2 + 4H2O
262916
4 OH-(aq) --->  O2(g) + 2H2O(l) + 4e-
758773
6O2 + C6H12O6 ---> 6CO2 + 6H2O
384517
(12/12+16)*100=42.85\n12---------atomic mass of carbon\n16---------atomic mass of oxygen
744647
C(3)H(8)+5O(2)=>3CO(2)+4H(2)O\nfuel+oxygen=>carbon dioxide+water\ncombustion \nbrackets-subscript
821017
(CH3)2 N2H2+2N2O4-->3N2+4H2O+2CO2
223476
heres an easy one..its nitrogen 79.1%next is oxygen and then 0.03 %is carbondioxide.
900829
H      H       H\n         |        |        |\nH --- C --- C --- C --- H\n         |        |        |\n        H      OH    H\n\nsince the functional group is on the 2nd carbon, the answer is (c)
377149
Nitrogen (N2) 78.084 % by volume\nOxygen(O2)20.9476 % by volume\nArgon(Ar)0.934 % by volume\nCarbon Dioxide(CO2)0.0314 % by volume
943
the number of carbon-12 atoms in 12 grams (0.012 kg) of carbon-12 or 6.02214199 × 10^23
839940
1. 2C6H6 + 15O2 --> 12CO2 + 6HOH\n\n2. C12H22O11 + 12O2 --> 12CO2 + 11HOH\n\n3. CH3COCH3 + 4O2 --> 3CO2 + 3HOH\n\n4. C2H5OC2H5 + 6O2 --> 4CO2 + 5HOH\n\n5. C4H9OH + 6O2 --> 4CO2 + 5HOH
747676
2C12H22O11 +24O2 ---> 24CO2 +22H2O\na)F\nb)F\nc)T\nd)F\ne)T\nf)T
795154
2CO(g) + O2(g) --> 2CO2(g)