what is the area of any oval?
921006
Area = πab where a and b are the semi-major and semi-minor axis length
501756
length x width = area\n3 x 6 = 18
460116
It depends what it looks like.\nWithout seeing the actual picture I cannot find the area.
174683
The simple way to find the area of any shape is to break it up in to trangles and squares.  \n\n\nOr use integration... but i do not think that is what you are looking for
327427
Each side would have length sqrt(3), so the area would be 3 m^2.
610865
The oval tracks around football fields are usually 440 yards in length. One yard = 3 feet and one lap around the track equals 1,320 feet.
224253
You know that the area of a circle is given by:\nA = (pi)(r²)\n\nYou also know that the radius is half the diameter, so\nr = d/2\n\nYou may substitute this to the area formula:\nA = pi * (d/2)²\nA = pi * d²/4\nA = (pi)(d²)/4\n\n^_^
644034
nope footbal feild is rectangular cricket field is circular or elliptical(oval in shape)
941539
A square is a quaderlateral. All of it's sides are the same length. If you want to find the area you multiply the side by it's other side. In this case it would be 5 X 5. This would equal 25. So your square's area is 25 square units.
568696
rare gem's answer is right..given the radius you'll just need to compute for the area using the formula right?\n\nArea=(radius^2)(pi)\n    = (5)(5)(pi)
426495
It depends on what shape you want to know the area.\n\nSimple shapes have formulas. (such as a circle's area is Pi*r*r)\n\nComplex shapes which have pattern.(you know the equation of lines that form the shape), calculus is used to find the area.\n\nIf a shape is not ordinary. You should draw lines to grid it and count the area square by square.\n\n-Hope this would help-
975485
H*W= area\nheight times width\n\none side has a height of 8 and its width is 9 thus the area would be 72
826650
area =\n\nx^2 + 2x\n\ncost ($) =\n \n( x^2 + 2x ) * 20\n\n_
660555
The shape closest to a circle gives the most area.  With 4 posts you can make half a hexagon.  The 2 at the canyon wall will be 200 feet apart.  The 2 away from the wall will be 100 feet apart and 100*sqrt(3)/2 (86.6) feet from the wall.  This give a center rectangle of 10K*sqrt(3)/2 area and a triangle on each side adding to 5K*sqrt(3)/2.  The sum is 15K*sqrt(3)/2  =  12990 sq ft.\n\nA rigorous analysis proving this is a maximum is a bit more than I can come up with at this hour, but it's the highest # so far, and I feel the truth of my reasoning for it in my gut.
1109203
Playing field is 105 x 68 m.\n\nGrass area is 120 x 80 m.
289202
If you know the side length of the octagon (regular octagon)\nand let call it (a) then the area will be :\nArea=2 a2 cot PI/8 \n    =2(1+square root of 2)*a2\n    it is about 4.82843 a2\n\nExample if the side length of an octagon is 100 ft the are \nwill be :\nArea = 2(1+ 1.41421)* 100*100\n     = 48284.271  ft2.
1075072
The maximum area would be a circle. If it has to be a rectangle a square would be the highest area. So divide 50 by 4 and you get 12.5 and that will be the largest. It is a square 12.5 feet per side.