urgent/quick antidifferentiation question?
929562
∫ax(2 -x)dx\n= ∫(2ax - ax²)dx\n= 2a * ½x² - a * ⅓x³ + c\n= ax² - ⅓ax³ + c
120885
http://pubs.acs.org/cgi-bin/abstract.cgi/jafcau/1953/1/i03/f-pdf/f_jf60003a008.pdf?sessid=6006l3
504853
/n/r\n\nyou prolly need the correct type of returns.
902349
Hynton has it.  Just remember that you'll be restricted to x > 0 because of the original form of the problem.
818044
Hold ALT and Type 0134.\n\n† Like this right???  †
409149
If you are looking for only the real values,\n\ndifferentiating once,\nd(x³-6x²+12x-4)/dx = 3x^2-12x+12\n\n3x^2-12x+12 = 0\n\nx^2 - 4x + 4 = 0\n\n(x-2)^2 = 0\n\nx = 2\n\nwill be the critical point;\n\ndifferentiating twice,\n\n2x-4=0\nx=2\n\n+ve constant, so that the function will have a minimum at this point.\n\n\nDaneengineer@yahoo.com
201111
You need to measure the distance between the closely spaced lines (J values).  Trans and cis J values will be different
488850
Depress the cubic to eliminate the second order term.\n\nsee\nhttp://www.karlscalculus.org/cubic.html
1139143
Counterclockwise to both questions.
676902
Incomplete question. Are you looking for the anti-derivative of x, a, or b???\n\nput dx, da, or db at the end of the equation so we'll know.
79944
The above is the derivative.\nIntegration gives x + (1/4)x^4 + c (generic constant).
589015
on here? try  & nbsp; (without the space between the ampresand and n, and paste like 5 or 6)\nelsewhere? hit tab\n\n\n       .
802256
this maybe helpful \n\n\n\nwww.springerlink.com/index/R617G25W81437Q01.pdf\n\nhttp://www.springerlink.com/index/R617G25W81437Q01.pdf
657823
disintegration, dispersion, interruption\n\nAny of these will work....
435388
damnt i should have paid attention calculus...\n\nlet pam...pam...breat....dimension......carry the one.....as x approaches zero......carry  the two....hold on...\n\nthis could take a while.
432536
Oops………..!\n\ndac2chari\n\n\n u = 1/(ln t) Then du = t dt ………………..?  How that come …!\n\nIf u = 1/(ln t) then  u = [ ln t ] ^-1 \n\nAnd  du = - [ln t ] ^-2 [ 1/t ] dt = dt / [-t (ln t ) ^2] … please be careful.\n------------------------------------------------------------------------------------\n\nOK… this integral can’t carry out using analytical method; however, the flowing one can be solve\n\n∫ dt / [t ln(t)] \n\nu = ln (t)\ndu =  dt / t  \n\nGives\n\n∫ dt / [t ln(t)]  = ∫ du/ u  ln(u)\n\nSubstitute for u\n\n∫ dt / [t ln(t)]  = ln [ ln (t) ]
712501
take the anti-derivative of the first summation and you get:\n\nln|k| from 1 to infinite\n\nthis is equal to infinite.\n\ntake the anti-derivative of the second summation and you get:\n\n1 / -k from 1 to infinite\n\nthis would be equal to:\n\n(-1/infinite) - (-1/1) = 1\n\n1 is a finite number