Can someone help me with a ball-stick model for Alumminum Chloride??
922867
Check out that link.  It has a picture that shows how it looks like: the grey Al atom is in the center, and 3 green Cl atoms are around it in a triangular arrangement.
232578
There are many different forms of Alum.\n\nAlum is a double Sulfate salk with a general formula of,\nM+M'3+ (SO4)2 * 12H2O\n\nA very common form of Alum involves Potassium and Aluminum ions as shown below, this would be the standard "Alum",\nKAl(SO4)2 * 12H2O\nThis can be made through a series of chemical reactions.  Start with some Aluminum , react it with a KOH solution to make Al(OH)3 and then slowly add some Sulfuric acid (H2SO4). \n\nIt is a multistep process, there iare certainly more thorough explanations to be found out there on the internet.
824855
if you find it difficult to find alum in powder form gett the crystal form from the chemist and crush it and pulverise it into a powder
816883
First find the moles of Al. The relative atomic mass of Al equals Ar = 27, so\n\nn = m/Ar = 3.845/27 = 0.142 mol (approx)\n\nFrom the chem. equation:\n\n2Al + 6KOH  --> 2K3AlO3 + 3H2\n\n2 mol of Al reacts with 6 mol KOH, so\n0.142 mol Al reacts with 6*0.142/2 = 0.427 mol KOH\n\nAt last find the volume of the KOH solution:\n\nn = C*V, V = n/C, V = 0.427/4, V = 0.107 L or 107 mL (approx)
1175967
If there is nothing else present, neutralize with NaOH and add the ammonium chloride.  You may need to dissolve the ammonium chloride into solution first.  You may try skipping the neutralization.  More details here:\n\nwww.pgi-platinum-tech.com/pdf/V6N7.pdf
1053356
Progress has just been made in designing a murine model of ALZ.\n\nSupport novel transit solutions: http://www.hallisystem.bravehost.com
860022
Here are the formulas:\n\nAluminum Hydroxide = Al(OH)_3\nSulfuric Acid = H_2SO_4\nWater = H_2O\nAluminum Sulfate = Al_2(SO_4)_3\n\nThe correct balanced equation is:\n\n2[Al(OH)_3] + 3[H_2SO_4] + → Al2(SO_4)_3 + 6[H_2O]
770078
alcl3 is trigonal planar (bond angle 120')\nco2, straight (180')\nh20, bent (~105')\nch4 and ch2cl2 are tetrahedral. (~110')
208085
http://www.chemicool.com/
54928
Lithium nitride\nGallium oxide\nRubidium chloride\nBarium sulfide\nFor binary ionic compounds, you just write the name of the first element, then take the second element and just change the ending to -ide.
672813
http://www.psigate.ac.uk/roads/cgi-bin/psisearch.pl?term1=alkyl+halides&limit=0&subject=All\n\nhttp://library.tedankara.k12.tr/carey/ch4-2.html\n\nhope this helps
923134
Use the pastel or whatever the kindergarden kids use.  It is like mud but comes in different colours.  The model should be a representation of the cross-section of your cell.  Use strings and other things to show different structures of the cell.  Some diagrams are drawn in 3D, and that's what your model should look like.  I wish they made us do that in university.  It would be fun.
87280
MBrO3-9H2O where M can be Na,K,Li, other +1 cations\n\nIf M is other than these you have to adjust subscripts
866145
HCl + AgNO3-----> AgCl +HNO3\nPb(OOC-CH3)2  + 2LiCl -------> PbCl2  + 2Li(OOC-CH3)\nNa3PO4 + CrCl3 -------> Cr(PO4) + 3NaCl\nH2SO4 + BaCl2 ----------> BaSO4 + 2HCl\nAl2(SO4)3  + 6NH4OH ------> 2Al(OH)3  + 3(NH4)2SO4\n2AgNO3 + H2S -------> Ag2S  + 2HNO3\nCaCl2   + Pb(NO3)2 -------> Ca(NO3)2  + PbCl2\nCa(NO3)2 + Na2CO3 ------>CaCO3  + 2 NaNO3
791388
the one wch we have this year in science, i learn it like this-\nPoSoCaM AluZIL CoMeSiGo\n\nPo-potassium  \nSo-sodium  \nCa-calcium  \nM-magnesium\nAlu-aluminium  \nZ-zinc  \nI-iron  \nL-lead \nCo-copper  \nMe-mercury  \nSi-silver  \nGo-gold\n\nread posocam aluzil comesigo like a word or a sentence...it works!
517995
67.  AgCl <---> Ag+ + Cl-  Ksp = [Ag+][Cl-] = 1.8 x 10^-10\n[Ag+] = 0.001/2 = 0.0005 M; [Cl-] = 0.0025 M; [Ag+][Cl-] = 1.25 x 10^-6, as this is greater than Ksp, a precipitate will form.\n\n68.  SrCrO4; Ksp = [Sr2+][CrO42-] = 3.5 x 10^-5; molar solubility = [Sr2+] = [CrO42-] = sqrt (3.5 x 10^-5) = 0.0059 M\n\n69.  Total volume = 3L  [Fe2+] = 0.150 * 1/3 = 0.050M; [OH-] = 0.0333 * 2 / 3 = 0.0222 M.  Ksp Fe(OH)2 = 4 x 10^-38.  (0.050) * (0.0222)^ 2 >>> 4 x 10^-38, so a precipitate will form.\n\n73.  Pb3(AsO4)2 <---> 3 Pb2+ + 2 AsO43-.  If solubility = x, then [Pb2+] = 3x, [AsO43-] = 2x.\n4.0 x 10^-36 = [3x]^3[2x]^2 = 108 x^5 ==> x = 3.26 x 10^-8
958410
1.\nMn(s) + SnCl2(aq) --> MnCl2(aq) + Sn(s)\nCr(s) + 2HBr(aq) --> CrBr2(aq) + H2(g)\nCo(s) + CaBr2(aq) --> N.R\n2Al(s) + 3Ni(NO3)2(aq) --> 2Al(NO3)3(aq) + 3Ni(s)\n\n2.\nMg + 2AgNO3 --> Mg(NO3)2 + 2Ag\nmole of Ag = 3.580 / 108 = 0.033 mole\nmole of AgNO3 = 0.033 mole = 33 mmole\nmolarity of AgNO3 = 33 / 50 = 0.66 M\n\n3.\na.soluble\nb.soluble\nc.soluble\nd.insoluble\ne.soluble\nf.soluble\ng.insoluble in water, soluble in acid\nh.soluble\n\n4.\n3NaOH(aq) + Fe(ClO4)3(aq) --> Fe(OH)3(s) + 3NaClO4(aq)\n3Na+ + 3OH- + Fe3+ + 3ClO4- --> Fe(OH)3 + 3Na+ + 3ClO4-\nFe3+ + 3OH- --> Fe(OH)3\n(NH4)2SO4(aq) + Pb(NO3)2(aq) --> PbSO4(s) + 2NH4NO3(aq)\n2NH4+ + SO42- + Pb2+ + 2NO3- --> PbSO4 + 2NH4+ + 2NO3-\nPb2+ + SO42- --> PbSO4\n\nHope it helps\npeace\nvixklen