Help with area problem?
931375
Imagine the fence completley surrounding the garden:\nthen 2l+2w = 160  where l=length and w=width\nso w = 80-l\nalso area, a=lw = 80l - l^2\nfor max area da/dl=0\nda/dl = 80 - 2l\nthis is equal to zero when l=40 ft\nso w=40 ft\nand area = 1600 ft^2\n(nb the fence would be 40ft long on 3 sides and 30ft long on one side leaving room for a 10ft gate - using 150ft of fence)
549797
enclose the ireegular shape with a rectangle and find the empty spaces. then subtract that with the area of the enclosed rectangle to get ur answer.
219160
hi,i can not answer your question but i am having the same problem and i can`t find anyone to help,\nwill someone help us????
226304
Area = pi*r^2\n\nSo, plug the numbers into the equation.\n\n118 = 3.14 * r^2\n\nr = 6.13\n\nSo, the answer's B.
114649
Here's an idea.  Show them something that's pretty much flat and rectangular, such as piece of stiff carpet or a pad of paper.  Write on the board what the perimeter, area, and volume are.  Have them measure it with a tape measure and come up with the answers that you have.  They'll see that they just have to add for the perimeter but multiply for the area and volume.
1142827
You don't give a feasible region. However, only one of your answers actually satisfies z=6x+10y. That should solve your problem.
198865
Volume = (area of the base) x (height)
840518
Yvonne Mystic found a shape that produces an area three times the original area. But she did not add the same width on all sides.\n\nIf you assume you are adding x meters to each side, the new shape is (6+2x) by (8 + x), and the area is (6+2x) (8+x) = 144 (i.e., it equals three times the original area, which was 48 sq. ft.).\n\nIf you take the equation from the above paragraph (the equation that ends "= 144"), multiply it out, and rearrange it into standard quadratic form, you will be able to solve for x, which is the width of the strip.
826650
area =\n\nx^2 + 2x\n\ncost ($) =\n \n( x^2 + 2x ) * 20\n\n_
801553
lol.\nfind formula for area of spiral.  subtract smaller from bigger.  sry no more help.
1181750
Try        cd c:&#92;\nMake sure that there is a space between d and c.
551690
T= L + 2B\n\nT is total surface area\nL is Perimeter x Height\nB is base area
174683
The simple way to find the area of any shape is to break it up in to trangles and squares.  \n\n\nOr use integration... but i do not think that is what you are looking for
493708
the formula for the area of any regular shape is \n(pa)/2, so there is no multipling the base by 2 involved.\np=perimeter\na=apothem
801034
Here's the answer: (I'm assuming the top of the box is counted in the area)---------   x = side of square base, h = height, S = surface area, P = perimeter length\n\nS = 2x^2 + 4xh\n\nP = 8x + 4h ---->  h = (P-8x)/4  Substituting,\n\nS = 2x^2 + 4*x*(P-8x)/4 = Px - 6x^2\n\nFor your particular case where P = 120 cm,\n\nS = (120x - 6x^2) cm^2
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.
950600
Let z be the amount to multiply each dimension by:\nLet A be the original area\nLet A' be the new area\n\nA = W * L\nA' = zW * zL\nA' = z²(W * L)\nA' = z²A\n\nWe want the new area (A') to be 4/9 the old area (A).\n\nThat means z² = 4/9\nAnd therefore:\nz = sqrt(4/9)\nz = 2/3\n\nIf the original dimensions are 18 cm * 24 cm.  The new dimensions will each be 2/3 of that (12 cm * 16 cm).\n\nThe old area will be 432 cm², the new are will be 192 cm² which is 4/9 the original.\n\nThus the new dimensions should be 2/3 the old or 12 cm * 16 cm.