help, please? pretty please?
925148
Hi Alyssa...\n\nSlope equation for a line is y = mx + b where m is the slope. The perpendicular slope is (-1/m).  So, first we need to change your equation to this form.\n\n2x-5y=8\n2x-8=5y\n\nnow, divide by 5\n\n(2/5)x-8/5 = y or y = 2/5 x - 8/5\n\nso the slope of the original line is m=2/5\nthe perpendicular slope for a lin is -1/m = -5/2\n\nNow, let's create a new line using the "Point-Slope" formula:\ny-y1 = m(x-x1) where m is the slope and (x1, y1) is a known point.\n\nWe calculated the slope aready above at m = -5/2\nYou have been given the point as (4, -4)\nNow, just plug the numbers into our Point-Slope equation.\n\ny-(-4) = (-5/2) (x-4)\ny + 4 = (-5/2)x + (-5/2) * (-4)\n\nmultiply by 2\n\n2y + 2*4 = 2*(-5/2)x + 2*(-5/2) * (-4)\n2y + 8 = -5x + 20\n\nor\n\n2y + 5x = 12\n\nNow, check that this line does in fact pass through the point (4, -4) by plugging the numbers and verifying that the equation is true!
747381
Try these...sorry, I'm not really sure how much help you need, but these have decent explanations
694063
Is anyone has a? Does anyone could help?
1015739
nope, sorry cant help ya
84992
What do you need help with, grammer?
64787
Ask nicely. Say "Pretty Please"
670773
see the link:\nhope it helps you
592574
YES!!!!! May I help you?????
531870
Can't help you, wish I could. Good luck
869404
wish i could help!\n\ngood luck
495715
What kind of help you need ?
285788
call someone smart and ask them for help on it
516392
What? xplain ur qstn well somebody may able 2 help u
231414
okaaaaaaaaay, but i need more info than the fact that you need help
68651
I could help you, but I´d have to charge....wasn´t that a song or something?\n\nTry your question in jokes and riddles!!
938620
Go ahead and ask!  You helped him, so he should help you.\n\nGood luck.
749787
srry can't help ya there!