The water depth d (in feet) at which a wave breaks varies directly with the height h (in feet) of the wave...?
930657
So they told you the relation is:\nd=kh\n(Since they said "varies directly", there is no offset: d=kh+d0)\nThen: 8.45=6.5k\ntherefore k=1.3 (unitless, ft/ft)\n\nThen you want to find:\nd=5.2 = kh=1.3h\nTherefore:\nh = d/k = 5.2/1.3 = 4 ft
869579
let the height of cliff be h\nthen \ndistance of first ship =x\ndistance of first ship =x+500\nnow \n1.h/x=tan 24\n2.h/(x+500)=tan 15\nfrom 1\nx=hcot24\nfrom 2\nx=hcot15-500\ntherefore\nh(cot15-cot24)=500\nh=336.47
601391
Depends on the height.\n\nV=pi*r^2*h\n\n1 ft^3 = 7.48 gallons (U.S.)
832830
Your head loss is going to be the the total weight of the water columns (height X area X density) between the inlet and the outlet.\n\nThe height of the current point at freefall is the head required by the pump beyond the inlet pressure supply to provide the required pressure at the outlet. It is the pressure expressed as weight of the water column divided by the outlet area.\n\nE-mail me more specifics.
281732
frequency of a wave NEVER changes, whether you change the medium or the temperature of the medium. The speed changes and the wavelenght changes, but the frequency NEVER does.\n\nIf the temperature decreases, the speed of the wave decreases (due to decreased kinetic energy), so the wavelength decreases as well.
277032
I assume you are talking about any wave equation, not just a QM probability density function.\n\nIn any case, what do you mean that you have a "different x for every instant t"?  That is not the case.  I suspect you are thinking of travelling along with the crest or trough of a wave.  As t changes, the location of the crest and trough changes, but that is not the only location on the wave.\n\nWhat the wave equation specifies is the magnitude of the wave at *any* location x, at any time t.  So, if you are at a constant location x', the magnitude of the wave will vary periodically in time at that location. If you were a cork on the water, you would bob up and down at your location as the waves passed you. But similarly, if we were to somehow freeze time, and travel up and down our x axis, the magnitude of the wave would vary periodically in space as well.  So now, rather than a cork bobbing on the water, imagine you're on a jet ski that is going across the water so fast, compared to the speed of the waves, that it's almost like the waves aren't moving.  Yet you bob up and down as you cross the waves that lie in your path in space.\n\nHence, the wave varies both in x and t, independently.
70735
The upthrust force equals the weight of the water displaced.\n\nIf d = density of the water,\nV = volume displaced,\ng = acceleration due to gravity,\n\nThe force of upthrust is,\nF = d*V*g
9692
An earthquake under a body of water often lifts or collapses the land under the water.  This sudden move of a large body of land displaces the water above it, creating a massive wave.  The wave is unlike waves you see at the beach, which are caused by wind.  This wave is very long and can travel at hundreds of miles per hour.  Once the wave reaches shallow water, the wave is compressed, lifting the water very high, causeing a tsunami, or tidal wave.
835975
This question can be answered with both calculus and standard constant acceleration equations.  In constant accelaration, velocity equals acceleration multiplied by time (v = at). Taking the integral of this gives us popular phyics equation d = v0t + (1/2)at^2, or distance equals initial velocity multiplied by time plus half the acceleration multiplied by the time squared.  Using these equations we have:\n\nAt peak of the dive:\nv = v0 - at\n0 = 12 - 9.8t\n9.8t = 12\nt = 1.22 (time in the air at peak)\n\nHeight at peak:\nd = vot + (1/2)at^2\nd = 12(1.22) + (1/2)(-9.8)(1.22)^2\nd = 7.34684 feet\n7.34684+10 feet (height of board) = 17.34684 feet above water\nSo, the answer to A is 17.347 feet\n\nWhen she will hit water:\nd = (1/2)at^2\n17.34684 = (1/2)(9.8)(t^2)\nt^2 = 3.54017\nt = 1.8815 (falling) + 1.22 (to reach peak) = 3.1015 seconds\nSo B is 3.1 seconds\n\nShe was falling for 1.8815 seconds at 9.8 m/s, so using v = at we have:\nv = 9.8(1.8815)\nv = 18.4387 m/s\nSo C is 18.4387 meters per second.
265293
It is due to a change in the mass as the volume of water changes.
137078
...Average Depth(in feet)...Maximum Depth(in feet)\nsuperior--------483-----1332\nMichigan-------279-------925\nHuron-----------195--------750\nErie---------------62------210\nOntario---------283-------802
529872
Easy H*D*W    H=Height D=Depth W=Width *= times\n\nUse the units cubed, if it is meters use m^3 as the unit of measurement
1110962
Mu,\n\ni.e. The question is incomplete, part of the ship will be above water, part below, depending on the exact nature of the ship and the position of the ladder a differing amount of steps will be visible when it is floating.
836671
At an atmosheric pressure of 101.3 KPa (14.7 psi), the usual pressure at sea-level (it DOES vary a bit with the weather), water boils at 212 deg.F or 100 deg.C.  However, the boiling point goes down as the atmospheric pressure goes down, which is what happens when you go up in elevation.  Where I live, the elevation is about 4600 ft.  In a physics lab I took here, one of the experiments was to measure the B.P. of water.  It turned out to be 92 deg.C.
168920
This is ultrasonic, not electromagnetic, so C is irrelevant.  The equation is:\nF=V/L where V=sound velocity in water (~1475 m/s), F=frequency in Hz, L=wavelength (0.0003 m)\nResult is you need 4.9 MHz or higher.
277776
when looking into a bowl of water. Air has a refractive index of about 1.0003, and water has a refractive index of about 1.33. If a person looks at a straight object, such as a pencil, which is placed at a slant, partially in the water, the object appears to bend at the water's surface. This is due to the bending of light rays as they move from the water to the air. Once the rays reach the eye, the eye traces them back as straight lines (lines of sight). The lines of sight intersect at a higher position than where the actual rays originated. This causes the pencil to appear higher and the water to appear shallower than it really is. The depth that the water appears to be when viewed from above is known as the apparent depth.
1149367
None of the above.\n\nThe "most" true statement would be that it "transfers" its energy from its winds to the shallower water creating waves, but it's not entirely true.  Huge waves are also present in very deep water during a hurricane; it doesn't require shallow water to create large waves.\n\nOh, and contrary to some posts here, it doesn't gather most of its power from warm air, it gathers it from warm water.  That's why it never gains strength once it hits land.  Lord knows Florida's hot, and if it were the air that was the defining factor, these things wouldn't lose strength the moment they hit land.