given a line containing the points (1,3), (2,4), (3,5) determine the slope-intercept form of the equation,?
925887
Hopefully you know how to solve one part of it. Slope intercept form is Y= M x+B. First find the slope, using 2 set of coordinates, that formula is Y2-Y1 over X2-X1. that will be your M.  Then find your Y intercept. then plug it in to that formula above. I hope i was of some help. Don't put your life on this i did it in the beginning of the school year.  I may have the M and the B switched.
143646
LET US SEE:\n\n1. y = (1/2)x + 5. This is an equation in standard form.\nIt is called slope-intercept form. If you mean general form\nthen:\n\ny = (1/2)x + 5\n\nMultiply by 2:\n2y = x + 10\n\n0 = x - 2y + 10\n\nx - 2y + 10 = 0  ANSWER\n\n=======================\n2. Line parallel to y = (1/4)x + 2:\n\nAny line parallel to y = (1/4)x + 2 has the equation:\ny = mx + b  ===> Equation of line\nwhere:\nm = slope = same as slope of given parallel line = 1/4\n\ny = (1/4)x + b ANSWER (equation of parallel lines)\n\nex:\na) y = (1/4)x + 0\nb) y = (1/4)x + 1\nc) y = (1/4)x + 3\nd) y = (1/4)x + 4\nd) y = (1/4)x - 1\ne) y = (1/4)x - 2\n.\n.\n.\n\n=======================\n\n3. y varies directly as x ; y = 2/3 and x = 1/2.\n\ny = kx (direct variation equation) where:\nk = constant of variation\n\nif y = 2/3 and x = 1/2:\n\ny = kx\n2/3 = k(1/2)\nk = (2/3)/(1/2)\nk = (2/3)(2/1)\nk = 4/3\n\nTherefore:\n\ny = (4/3)x ANSWER\n\n=======================\n4. Line passing thru (0,2) and perpendicular to \ny = (1/4)x + 2\n\nLet m = slope = -4 = negative reciprocal to slope\nof perpendicular line.\n\ny = mx + b  ==> slope-intercept form, where:\n\nm = slope\nb = y-intercept\n\nSolving for b, use point (0,2)\n\ny = mx + b\n2 = -4(0) + b\n2 = 0 + b\nb = 2\n\nTherefore, equation is:\n\ny = -4x + 2 ANSWER\n\n=======================\n\n5) Point(s) that lie on the graph of the equation \n\n3x + 6y = 27.\n\nThese are points that will make the left side of \nthe equation equal to 27.\n\nEX. ...;(-5,7)(-3,6)(-1,5);(1,4);(3,3);(5,2);(7,1);...\n\n=============================\n6. Equation of the line that contains (2,4) and undefined slope.\n\nA line that has an undefined slope is a vertical line. So,\na vertical line that contains (2,4) has the equation:\n\nx = 2  same as the x-coordinate of the given point.\n\n===========================\n\n7. Equation of the line that passes thru the x-axis \nat x = -1 and y-axis at y = 3.\n\nFrom the given intercepts, the two points are (-1,0)\nand (0,3)\n\nTherefore:\n\ny = mx + b ===> equation in slope intercept form.\nwhere:\nm = slope = (3-0)/(0--1) = 3/1 = 3\nb = y-intercept from point (0,3) = 3\n\nTherefore:\n\ny = mx + b\n\ny = 3x + 3 ANSWER.
850944
You have 2 points, (x1,y1) and (x2,y2) and you want to find the equation of the line that goes through these points.\n\nThe first thing you want to do is find the slope.\nslope is rise/run so m = (y1-y2)/(x1-x2)\n\nFor slope intercept form , y = mx + b\nwhere m is the slope, and b is the y intercept\nnow that you have found the slope, you can solve for b, the y intercept by plugging in your value for m and one of the given points, either (x1,y1) or (x2,y2).\n\nFor point slope form,  y - K = m(x - H)\nm is the slope, and   (H,K) is a point that the line passes through.\nSince you have already calculated the slope, m, for the slope intercept form, you're already almost done. All you have to do is plug in the point (x1,y1) or (x2,y2). In your question, you are asked for the point slope form of just point (6,2).
104788
Remember the slope-intercept form?\n\ny = mx + b.\n\ny = the y coordinate.\nx = the x coordinate.\nm = the slope.\nb = the y - intercept.\n\nyour equation is already in slope-intercept form. so all you need to do is match up your numbers with the y = mx + b.\n\nThe slope is -5.\nThe y - intercept is -17.\n\nHope that helps :)
89344
Use the two given points:\n(x1=7, y1=5) and (x2=-1, y2=1/5)\nand the "two point equation":\ny-y1 = ((y2-y1) / (x2-x1)) * (x - x1)\nto get started on this problem.\n\ny-[5]=(([1/5]-[5]) / ([-1]-[7])) * (x-[7])\ny-5=((-24/5)/(-8))*(x-7)\ny-5=(3/5)*(x-7)\n\nNow put the equation into the "slope intercept" form of y = mx+b.\n\ny-5=(3/5)*x - (21/5)\ny=(3/5)*x - (46/5)\n\nThe slope = 3/5\nThe intercept = -46/5
3669
This is for math right? If so:\n\nThe slope-intercept form is:\n\ny = mx + b\n\ny = value on the y-axis\nm = slope\nx = value on the x-axis\nb = y-axis intercept\n\nThe slope-intercept form gives the equation for a straight line.
498526
The value of y at the y-intercept (b), which is the point at which the line intersects the y-axis, is -9, and the slope (m) is -3. Following, the y=mx+b or slope-intercept form, the equation is y=-3x-9.
502566
it's the slope-intercept form of the equation for a line.
653148
All equations for a line will have the form:\n\ny = mx + b,\n\nwhere x & y are coordinates, m is your slope, and b is your y-intercept.\n\nTherefore, substituting in your slope and y intercept, you get:\n\ny = -2/3x + 4\n\nThis equation can then be used to graph the line, since given any x, the corresponding y can be found. :)
621346
y=mx+b (this is known as the standard form of linear equations)\n\nm=slope\nx=x values\ny=y values\nb= y-intercept\n\nso the answer for you question is:\n\nslope = -1\ny-intercept = -3\n\nEXPLANATION:\n\ny = mx + b\ny = -x-3\n\nm= -1   and    b = -3\n \nslope = m    and   y-intercept = b\n\nthus, the slope is -1 and the y-intercept is -3\n\n\nNote: the slope is rise/run (rise over run) -- to make a graph use the y-intercept and the slope -- once you have the slope and the y-intercept, making this graph should be easy because it's a linear graph -- but if you still don't get it ask your teacher\n\n\nthus, the slope is not a-1 -----there is no "a"
101123
(3, -3)\n\n-3 ?>= -2(3) + 5\n-3 ?>= -6 + 5\n-3 ?>= -1 (not true)\n\nIf you don't want to "plug and chug" all the points individually into the equation, you could draw up a graph and plot each point, and then draw the line for the equation. The solution set for the equation will be the shaded area to the right of the line, including the line itself.
317632
slope = 1/5\ny-intercept = 2\nx intercept = -10
734729
problem1\n\nsince you have said P (4,-5) is a point on the function, then the corresponding point will be (4,-5) .. :)\n\nproblem2\n\nfor a line having y intercept 3 will have following form\n\ny =mx+3\n\nwhere m is the slope of the line. Now it is said to be perpendicular to y =2/3x-4. So slope for this is 2/3\n\nsince slopes of two lines perpendicular to each other if multiplied yields -1\n\nm X 2/3 = -1\n\nor m = -3/2\n\nso the required line will be\n\ny = -3/2 x+3\n\nproblem3\n\nf(x) = 1/x^2 -2x-8\n\nto make the f(x0<0, let us try with some arbitary values of x\n\nif x = 1, f(x) = -9\nif x=2, f(x) = -11.75\nif x = 0, f(x) = infinite (due to 1/x^2)\nif x = -1, f(x) = -5\nif x= -2, f(x)= -3.75\nif x=-3, f(x) = -1.88889\nif x=-4, f(x) = 0.0625\n\nHope this helps
1124994
you can use the y=mx+b formula for a line.  \n\ny is the y-coordinate of a point\n\nm is the slope, x is the x-coordinate of a point\n\nb is the y-intercept (where the line touches or intercepts the y-axes).  \n\nsince you know the y intercept of the line (passes through origin, so it's 0), the value of b would be 0 and  you also know the slope of the line, which is two, the equation for the line would look like this.\n\ny=2x + 0 or y=2x\n\na point on the line would have coordinates that would fit the equation ---- y has to be two times x; x has to be 1/2 of y.\n\nhere are some points on this line: (0,0), (1,2), (-1,-2), (2,4), (-2,-4).\n\nhope that helped :)
350403
Equation of a line:  y = mx + b\n\nm = 3 (slope)\ny = -4 (y-intercept)\n\ntherefore:  y = 3x - 4 \n\nCrosses x-axis at y = -4 (0,-4)\nCrosses y-axis at x = 4/3 (4/3,0)
910261
Slope = m\n= y2-y1&#92;x2-x1 \n= -4-6/-3-2\n = -10&#92;-5\n=2\n\nnote: / means divided by\n\nthe slope of y= 2&#92;3x-4 is 2&#92;3
972913
It's actually all explained for you right there in your "question". Maybe it would help you to draw the line on a piece of graph paper. Plot the point (3,5), then the point (-2,0) and draw a straight line through them. It tells you that the slope (m) is 1. So for every step to the right, the line goes up one step. The point (3,5) is the same as (x1,y1) and (-2,0) is  the same as (x2,y2). So you replace 3 for x1 in the point-slope form equation, and so on. It really helps to pay attention on class.