a woodencrate has length 80*60*80.if thepriceof woodenplank is rs50per meter sq.what's price of wood in crate?
924989
Surface Area - converted cm to meters:\n\n2 x .8 x .8 = .64 square meters\n2 x .6 x .8 = .48 square meters\n2 x .6 x .8 = .48 square meters\n\nTotal Surface Area = 3.2 square meters\n\nTotal Cost = 3.2 x Rs 50 = Rs 160
320176
You know that you waste 15 points on this question, seeing that you have to spend only 5.\n\nThe answer is 2.540106951871 cubic ft.
865940
I will try, but it would have been easier if you had copied the problem from your homework exactly - this version is confusing.\n\nThe side of the shed to be used is 20m long, correct?  If this is not the case, substitute the correct value into the work below marked by an asterisk (*).\n\na) The width of the sheep pen is 20m*.  This means two sides of the rectangle total 40m, and the other two sides must be a total of 160-40+20* = 140 m.  So the pen is 20m(wide) by 70m (high).  \nGoing back to check, you get 70+70+20 = 160 (the fourth side is the 20m shed wall) and this is correct.\n\nb) If I remember my geometry correctly, the maximum area would come from a square.  You have a total of 180m for all four sides (160m of fence plus 20m* of shed).  To make a square, each side must be 180/4 or 45m.  This area would be 2025 sq m, vs. 1400 in a).
683941
Uhm you are vague by saying "at least $30". Hence, it is impossible to figure this out. You did not say "exactly $30".
544478
Length = 24 ft\nWidth = (1/2)*24 = 12 ft\n\nPerimeter = (24 + 12)*2 = 72 ft\n\nNumber of boxes = 72/25 = 2.88 boxes.\n\nSo Kara has to buy 3 boxes.
23547
78.75\n\ntimes .035 x 750 x 3
811932
1     $58.50\n\n2     $23.20\n\n3     $38.25\n\n4     $75.60
124171
Three men rent a room for $30.00. ($10.00 each)  When they got to the room there was no heat.  They called the man at the front desk who sent up a $5.00 refund.  They couldn't evenly split the five so they each took a dollar and gave the bellhop a $2.00 tip. Now the three men ended up paying $9.00 each because they all took a dollar back from the five. (9 x 3 = 27) Plus the $2.00 tip to the bellhop. (27 + 2 = 29)  What happened to the last dollar?\nI LIKE THIS ONE TOO !!
190690
Dr. Int. on Notes Payable...800\nCr. Outstanding Interest....800\n\n320,000 * 3% * 1/12 = 800\n\nAssuming the value in the trimber tract as its cost i.e. $100,000\n\nDepreciation per board feet \n= (Cost - Salvage Value)/(Productive Capacity)\n= ($100,000 - $40,000)/500,000\n= $60,000/500,000\n= $0.12\n\nAssuming that the quantity sold is quantity produced\nDepreciation to be charged \n= Quantity produced * Depreciation per board feet \n= 20,000 board feet * $0.12/board feet\n= $2,400\n\n\nDr. Depreciation on Timber Tract a/c 2,400\nCr. Timber Tract a/c... ... .... ... 2,400\n\nDr. Profit & Loss a/c ... ... ... .. 2,400\nCr. Depreciation on Timber Tract a/c 2,400\n\n\nhttp://www.futureaccountant.com/accounting-process/
731411
67inches. \n\n5ft x 12in = 60in + 7in = 67in
294284
multiply 70x60 to find out
941832
How about:\n\n186 X 39 = 7254
827251
V = πr²h\nA (top & bottom) = πr²\nEnd Area = 2πr²\nLateral Area = 2πrh\nCost of tube = 2πrhC, C being cost per unit area\nCost of ends = 2πr²C*1.2\nTotal cost, P = 2πC(1.2r² + rh)\nh = V/πr², so\nP = 2πC(1.2r² + rV/πr²)\nP = 2πC(1.2r² + V/πr)\ndP/dr = 2πC(2.4r - V/πr²) = 0 for max or min, so\n2.4r = V/πr²\nr³ = V/2.4π\nr³ = 5/2.4π\nr = 0.872"\nh = 5/π0.872²\nh = 2.093"\n\nCheck:\nC(2.4*π0.872² + 10/0.872) = 17.201050C\nC(2.4*π0.87² + 10/0.87) = 17.201444C (+0.000394)\nC(2.4*π0.874² + 10/0.874) = 17.201137C (+0.000087)
881092
You can get it for $9.99 a square board foot my friend.\nGood Q\nGood luck
829871
Plant A: 18/3=6windows*$5=$30 profit on windows\n             18/2=9doors*$3=$27 profit on doors\n\nPlant B: 7.5/1.5=5windows*$5=$25 Profit on windows\n             7.5/.75=10doors*$3=$30 profit on doors\n\nthey will profit most by producing windows in Plant A and doors in Plant B
51368
A cord of wood is 4 feet high, 4 feet wide, and 8 feet long, stacked tightly. That is 128 cubic feet. A typical full size pickup, bed level, will hold about 1/2 a cord. Be cautious about what you buy, because it is easy to stack a cord so that it contains as much as ten percent less when restacked. \n\nThere is also a measurement called a face cord, that is 4 feet high, 8 feet long, and some variable width. Obviously, not a full cord. Buying wood by weight is also somewhat dubious because moisture content and wood density varies greatly depending on the species of tree and amount of seasoning (drying) given the wood. \n\nCosts vary dramatically depending on your location. There's a guy selling it on eBay for $150 per cord. I find prices range from less than $100 a cord to several hundred dollars. It depends on how close you are to forested areas and how much demand there is in your area from suburban consumers. It might also depend on how cheaply the teenager next door wants to work. Cutting and splitting  a cord it is easily one or two days work even if the trees are already down.
817821
It is my understanding that you would multiply the given costs by the surface area of those pieces to get total cost (C). Your equation would be as follows:\n2[(πr^2)(.027)] x πrh(.015)=C\nThe constraint equation is the volume:\n(πhr^2) = 16\nsolve your constraint equation for one of the variables.\nThen take the derivative of the cost equation and solve for your variable at "0." This will give you r (where r is radius) or h (where h is height of can) depending on what you solved for.