An 0.0005 kg feather is dropped in the air n floats to the ground at a constant velocity of 2.0m/s?
918435
If the feather floats at a constant velocity of 2.0m/s, it means that it is in equilibrium, i.e. its weight must be equal to the air resistance. Therefore, \n\nWeight=0.0005*9.8\n           =0.0049N\nAir resistance=0.0049N\n\nAgain since the feather is floating at a constant velocity of 2m/s, you can use the formula:\n\nTime=Distance/velocity\n       =10/2\n       =5s\n\nNote: this formula is not applicable if the feather were accelerating downwards.
870400
One feather at a time.
886536
If only birds really could fly in vacuums, but this is physics class world, not real world, so...\n\nIn the x direction the fish has a velocity of 18 m/s\nThis won't change according to Newton's laws.\n\nWe are interested in knowing how fast the fish is going when it hits the ground....I assume the bird dropped it.\n\nWhen the bird is carrying it it has 0 velocity in the y direction.\n\nWe know the height it falls from and the acceleration so we can use the equation below to find the final velocity in the y direction\n\nv = sqrt[V^2 + 2hg]  where V is the initial velocity in the y direction so\n\nv = sqrt[2*5.4*9.81]\nv = 10.293 m/s\n\nWe use the pythagorean theorem to add the vectors \n\nspeed = sqrt[18^2 + 10.293^2]\nspeed = 20.735 m/s
412533
this is the concept of terminal velocity.  The cat will reach a certain speed and then go no faster because the friction caused by the air will counteract gravity to a certain extent.
998671
Gravity slows down the ball at 9.8m/s/s. After 1s, its velocity is 12-9.8=2.2m/s
588018
a ton is 2000 pounds a 1000kg is 2.14 pounds so it is the feathers
444669
There is a dent, although it is quite small and also short-lived. The air pressure just in front of the falling drop pushes the surface down just before the drop hits.\n\nBuh-bye now.
1103152
Falling objects do not fall at a constant speed, they accelerate (get faster) the longer they fall. In a vacuum (no air resistance) two objects of the same mass (weight) experience the same acceleration. So if they're dropped from the same height, they will hit the ground at the same time. \n\nIn the atmosphere, air resistance will diminish the force of gravity, so two objects of different shape or density would accelerate at different rates because of different air resistance.
860846
Force = 60 N.\nMass = 3 kg\nTime = 10 s\n\nAn object's change in momentum, Δp equals the Impulse, I on the object. I = ∫F dt = Ft. \n\nΔp = I = Ft = (60 N) * 10 s = 600 Ns\n\nAssuming the object started at rest,\np (initial) = mv = (3 kg) (0 m/s) = 0 Ns\nΔp = 600 Ns\np (final) = 600 Ns\n\np (final) = mv = (3 kg) * v(final)\nv(final) = (600 Ns) / (3 kg) = 200 m/s\nΔv = v(final) - v (initial) = 200 m/s - 0 m/s = 200 m/s\n\nThe object's change in momentum was 600 Ns (kg * m/s).\nThe object's change in velocity, assuming it started from rest, was 200 m/s.
978262
Hi!\nIn a very simplified model it would take about 2.833 seconds. In reality it takes a little longer than that because the air exerts some drag, however he falls. The time depends still on it's weight because the drag depends on the air and shape, while G=m*g depends on it's weight, so the mass remains as a variable. Very light objects such as balloons fall very slow (as you probably know).\n100km/h=27.7 m/sec.    time*acceleration= (desired speed) When there is no initial speed. Thus time= v/accel=2.83sec
1120781
do your own homework\n\nits probably 0.26 kg M/s ^2 since its a velocity\n\nyou also probably need to convert it to rad/s whatever that is
2759
A ton. 2,000 pounds.\n\nThe trick to the question is that feathers aren't thought of as heavy. Nevertheless, a ton is a ton, no matter what it's a ton of.
759333
all object fall 4.9m after 1 sec\n\nX=1/2(9.8m/s^2)(2s)^2\nx=19.6m\n\nx=(1/2)(9.8m/s^2)(3s)^2\nx=44.1m
1143368
Change the question to "fall in air" and think about it. A parachute drops slower than a rock. The shape influence the speed due to drag.\n\nSame for water.
793793
the thing this problem is concerned is the vertical component of the projectile.\n\nsince the dart is thrown horizontally, the initial vertical velocity is zero.\n\nthe vertical velocity of the dart just before it hits the dart board is\n\nv^2 = u^2 + 2gs\nv^2 = 0 + 2(9.8)(0.32)\nv^2 = 6.272\nv = 2.50 m/s\n\nthe time it took the dart to hit the dart board is given by\n\nv = u + gt\n2.50 = 0 + 9.8t\nt = 0.255 sec\n\n\nnow, we have the time of travel of the dart, we can use the formula  d = vt  to find the horizontal distance\n(the horizontal velocity remained constant throughout the flight)\n\nd = vt\nd = 12.4m/s * 0.255s\nd = 3.169 m\n\n\ntherefore the dart player is standing  3.169 meters away from the board...\n\nthere ya go...
769928
T = 2pisqrt(l/g)\nl = g(T/(2pi))^2 = 9.80(1.0/(2pi))^2 = 0.25 m\n\n(The object's weight is irrelevant for small oscillations.)
1151411
Objects of different mass do fall at the same speed, but air resistance hinders this fact.  For example, if you drop a bowling ball and a feather at the same time on the Earth, obviously the bowling ball falls faster. \n\nHowever, on the moon, when the astronauts dropped a feather and a bowling ball, they hit the ground at the same time. \n\nIt would seem that the bowling ball should fall faster since gravity is pulling on it with more force. But, with the more mass, comes more inertia, which meas it resists being pulled more than the feather. So, the feather is pulled less, but it resists less as well, so because of that, they will fall at the same time. The relationship between the force of pull and the object's inertial compensates exactly so that all objects fall at the same rate.