lim as X->0 of xcosx?
930650
cos(0) = 1. so you can plug in x = 0 to get the limit as 0*1 = 0
324244
sinx + xcosx  (product rule)
918808
wouldnt it be like 3<x<-3 f(x)\nso like x would be 1 so it would be just f if you really want to simply that far done.
1023164
Limit ( n to infinity) (n + i/n)^ n
846187
if you are using a "while" or "do while" loop\n\nwhile ((x1 - x0) > 0.001)\n{\n//your code here\n}\n\nor you can do this\n\ndo\n{\n//your code here\n}\nwhile ((x1 - x0) > 0.001);
101082
(x-1)/4 > 3\nx-1 > 12\nx > 13
147502
log x goes to negative infinity\nbut with the squared it becomes positive.\nSo the limit is +infinity
867867
Ignore the relative maximum from -2<x<3. The horizontal asymtote is defined to be the limit as x approaches infinity of the function. Which as you have calculated is 3.
346514
Do you mean the limit of ln(cos x)/(x^2) as x goes to 0?\n\nIf so, substituting 0 in for x gives 0/0, which means you can use L'Hopital's rule.\n\nTo do so, take the derivative of the numerator and denominator, which are respectively -sinx/cosx=-tanx and 2x.\n\nThat still gives 0/0, so we can apply L'Hopital's rule again.  This time, we get -1/(cosx)^2 for the derivative of the numerator, and 2 for the derivative of the denominator.\n\nPlugging x=0 into -1/(cosx)^2 / 2 gives -1/2.\n\nSo the limit of ln(cos x)/(x^2) as x goes to 0 is -1/2.
1070381
It will be a zero because of the x-x term
712410
limit theta tending to 0 sintheta/theta =1
780025
x ≤ 5\n\n-- - - - - - -s-
104840
Actually, as what I have learned, this equation is limitless because the numbers itself are limitless. The incredible fact about this is that in every number you substitute in "x", the answer is always "0".
248915
The limit as sky goes to zero from the positive direction would be ground.\nLim    = ground\nsky-->0+\n\nThe limit as sky goes to zero from the negative direction is space.\nLim    = space\nsky-->0-\n\nSince the limit from the + site does not equal the limit from the - side, the limit does not exist.
879179
There is no limit.\n\nYou can see this by approaching from two different directions, along the x-axis and along the y-axis.If x is zero and y->0, then the formula becomes:\n\n   (siny)^2/y^2\n\nSince sin y/y -> 1 as y->0, this also approaches 1 as y approaches zero.\n\nOn the other hand, if y=0, and x->0, then the formula becomes:\n\n    x^2/(2x^2)\n\nwhich has a limit of 1/2 as x->0.
1066492
x = -4\n10points thank u!
790936
x≠０\ncuz if x=0, (x-7)/x^3 is meaningless