(a^2 - 2ab b^2)/a + b?
913473
Are you missing a plus sign and parentheses around a+b?  If so, then\n(a^2 -2ab + b^2) = (a-b)(a-b) = (a-b)^2\nYou cannot cancel anything, so \n(a^2 -2ab + b^2)/(a+b) does not simplify.\nYou may wish to write it as (a-b)^2 /(a+b)\n\nIf you are not missing a plus sign or parentheses, then\na^2 - 2ab b^2 = a^2 - 2ab^3\nYou can factor out an a.\n= a(a-b^3)  This does not factor, so you cannot simplify.\nDivide this by a and you get a - b^3\nNow add b\nAnswer: a - 2b^3 + b
741426
If z=a+ib, then we have:\n2a=a²+b²\na²-2a+b²=0\nThis is a quadratic equation in a, with solutions:\n\na=(2±√(4-4b²)/2\na=1±√(1-b²)\n\nNote that since both a and b are real numbers, this implies that 0≤a≤2 and -1≤b≤1.
798164
A = 3ax + 4by - 2ay - 6bx\n= 3x.(a - 2b) - 2y.(a - 2b)\n= (3x - 2y).(a - 2b)\n\nB = 2ax - 2by + ay - 4bx\n= 2x.(a - 2b) + y.(a - 2b)\n= (2x + y).(a - 2b)\n\nA/B = (3x - 2y).(a-2b) / [(2x + y).(a - 2b)]\n= (3x - 2y) / (2x + y)
321475
*(2x/(x^2-4)) + (5/2-x) - (1/2+x)\n*(2x/(x^2-4)) + (5/2-x)((2+x)/(2+x)) - (1/2+x)((2-x)/(2-x))\n*(2x/(x^2-4)) + (10+5x)/(4-x^2) - (2-x)/(4-x^2)\n*(2x/(x^2-4)) + (8+6x)/(4-x^2)\n\nyou should be able to get it from there
543300
Use the quadratic formula. a^2 + b^2 = c^2. 65^2 + 75^2 = c^2. You get 99.247166206396039345852328631456.
470404
((a^2 - b^2)/8a) X ((4a^3)/(a + b)^2))\n(4a^3(a^2 - b^2))/(8a(a + b)^2)\n((4a^3)/(8a)) * ((a^2 - b^2)/(a + b)^2)\n((a^(3 - 1))/2) * (((a - b)(a + b))/((a + b)(a + b)))\n((a^2)/2) * ((a - b)/(a + b))\n\nANS : ((a^2)(a - b))/(2(a + b))\n\nOn your problem, here is where you went wrong\n\nTo make it easier, you should had kept your problem in\n\n(4a^3(a - b))/(8a(a + b)) form, then had done this\n\n((4a^3)/(8a)) * ((a - b)/(a + b))\n\n(4/8)(a^(3 - 1))((a - b)/(a + b))\n(1/2)(a^2)((a - b)/(a + b))\n((a^2)(a - b))/(a + b)
965349
I believe you meant (2x^2 - 3x - 2 )/ (10 + x - 3x^2) right?\n\nWell we can rearrange the problem to look like (2x^2 - 3x - 2 )/ (- 3x^2+ x +10)\n\nWe now factor out the top and factor out the bottom.\n[(2x +1) (x-2)] / [(-3x-5)(x-2)]\n\nSince this is a fraction, we can cancel out the (x-2) because it is on top and the bottom.\n\nWe are left with:\n(2x +1) / (-3x-5)\n\nI think this is what you wanted, good luck and be careful of how you write your notation!
825318
(a^2 -2ab + b^2) = (a-b)(a-b) = (a-b)^2\nYou cannot cancel anything, so \n(a^2 -2ab + b^2)/(a+b) does not simplify.\n\nYou may wish to write it as (a-b)^2 /(a+b)
908544
sin 2a / (1 + cos 2a)\n\n(2 sin a cos a) / (1 + (2 cos ^2 a - 1) )\n\n2 sin a cos a / (2 cos ^2 a)\n\nsin a / cos a\n\ntan a
777394
factor out 4b\n\n4b(b-2)= 0\n\nb = 2, 0\n\ngoodluck ^_^
817461
a^4 - b^4\n\n= (a^2 + b^2)(a^2 - b^2)\n\n= (a^2 + b^2)(a + b)(a - b)
893957
well darling ;\nimagine this like that\n\ny^2 + ( a+b)y + ab \nyou need to find " a+b " & " ab" \nin our function \na+b = 16 & ab = 64 \n( y + a)( y + b) \n( y + 8 ) ( y + 8)\n{ ' 8 + 8 = 16 '   &  ' 8 * 8 = 64 ' }\nso\n( y + 8)^2\n\nGood Luck sweetheart.
1027362
(1+2)/2=3/2\n1+(2/2)=2
16153
this is a mathematical trick that is done as a teaching method on commonf fallacies of math.\n\nLet a=b\n\na^2=a*a\n\nsince a=b, a^2=ab\n\na^2+a^2=a^2+a^2\n\nsince a^2=ab, a^2+a^2=a^2+ab or 2a^2=a^2+ab\n\nsubtract 2ab from each side to get 2a^2-2ab=a^2+ab-2ab or 2a^2-2ab=a^2-ab\n\nthis can be rewritten as 2(a^2-ab)=1(a^2-ab)\n\ndivide both sides by a^2-ab to get 2=1\n\n\ncheck it over, mathematically its sound.. except for one thing... from what we already described, a^2=ab! therefore a^2-ab=0!  and if you all remember, you can not divide a number by 0!  \n\n2(a^2-ab)=1(a^2-ab) is actually saying that 2*0=1*0 which is a correct statement!\n\nthus no issues
775644
Duch, there's some confusion over what the problem is.  It could be a/(3+4b) - a/(3+b)  OR  a/3 +4b -a/3 -b\n\nIf the former, then it boils down to -(11ab)/(9 + 15b + 4b²)\n\nIf the later, 3b
489740
let 0=0\n   then a^2-a^2=(a-a)(a+a)\n  then a(a-a)=(a-a)(a+a)\nthen a=2a\nthen 1=2\nthen 2=3
300657
let a = b  \nMultiply both sides by a \na² = ab  \n Add (a² - 2ab) to both sides \na² + a² - 2ab = ab + a² - 2ab  \n Factor the left, and collect like terms on the right \n2(a² - ab) = a² - ab  \n Divide both sides by (a² - ab)\n2 = 1\n(The place where the proof goes wrong is the very last step.  If a² - ab = 0, then you would be dividing by zero, which is undefined.)