anybody know the apparatus needed for this experiment?
917922
Well, if you want to measure their growth in milk you need:\n\nPure culture of the bacteria in question, sterile milk, sterile glass tubes and a spectrophotometer.  This will measure the density of the bacteria in liquid culture.  I don't know what equipment you have access too (pipetts, tubes, a spectrophotometer etc).\n\nIf you've isolated the bacteria from milk and want to just measure their growth in "whatever", you can use any sterile growth medium that supports the growth of the isolated bacteria.  Again, measuring growth is most easily accomplished by use of a spectrophotometer.  \n\nGrowing bacteria on a plate to decide which grows faster is fairly insane, unless they have significant differences in growth.  I mean, are you going to stare at an agar plate for 24 hours just to see that at 14 hours 5 minutes a tiny pinpoint on plate A was visible, but it took 15 hours and 22 minutes for a colony of the same size on plate B?  No, of course you're not, it's not even plausible.\n\nWith liquid culture, you can take readings every hour for 8 hours and at 24 hours or something.\n\nYou can also dilute and spread-plate the bacteria from liquid cultures onto agar plates if you have your heart set on using them and achieving an exact count for bacterial populations.  But use of a spec still allows for comparisons between species, even without an exact population number.
1004079
www.howstuffworks.com\nu may find somethin
130396
Yes. You'll need a lemon, a galvanometer or Vmeter, 2 stiff copper wires, a large paper clip, and scissors.\nStrip the insulation off on the ends of the wires. Untwist the paper clip and twist the end of one of wires around it. Squeeze and roll the lemon to loosen the pulp inside. Make two small cuts in the skin of the lemon an inch or so apart. Insert the bare wire and the paper clip through these cuts into the juicy part. The two wires should be close but not touching. Connect the free ends of the two wires to the terminals of the meter.\n\nNow watch the meter move!\n\nExplanation: Electrochemistry causes the two different metals (the copper wire and the iron clip) in the acid (lemon juice) to draw electrons away from one wire towards the other. They flow out of the lemon through one wire, go through the meter and then enter the lemon by the other wire.\n\nYou can even try to make your own galvanometer (an instrument designed to detect electrical currents) if one isn't available to you. You'll need a compass, 15 feet of bell wire (hardware store), and a small rectangular cardboard tray. Place the compass in the cardboard tray. Scrape off 1/2" of insulation from each end of the bell wire. Starting 6" from one end, wind the wire tightly around the box, circling it at least two dozen times. Leave another 6" of wire free on the other end of the tray. Rest your homemade galvanometer on the table horizontally and turn it until the compass needle is parallel to the coil of wire. Use these bell wire ends to attach to your lemon and paper clip.\nIt's fun!
943693
this question is sooo odd. there is no way someone will no this without actually doing an experiment. you dont deserve to pass the class if you didnt do an experiment to find it.
620413
Do the experiment.  You might learn something.
400534
http://www.lancasterlabs.com/  try that
544143
Experiment w/ what works for you.
731168
just measure how much water they lose to the atmosophere some how and keep track of the amount of water you have added over a period of time. \nThis should be an interseting experiment.
288751
http://www.scioly.org/obb/board.php?FID=35\n\nThis is where I get help for such projects.  If you can't find the information, start a new topic and ask your question.  It is a great science project help site!
42193
http://www.itt.edu/staff/boyter/links/index.html\n\nLook under chemistry equipment.  There are some chemicals you will not be able to get.  Posting what you are looking for would help.
1118096
laboratory apparatus ang its function
394753
what kind of experiment do you mean?
100009
I am not quite sure what the question is. What should the manufacturer do? Did they already do the experiments or do you want to know what sort of experiments to do? Do you want to know how to reduce the data? How to present the data? What statistical tools might be useful?
25444
You could try to make an accurate experimental thermometer by glueing two strips of dissimilar metals together along their lengths. Perhaps try copper and steel or copper and aluminum or steel and aluminum.  Try perhaps one half inch wide by six inch long strips.  Use sheets of metal that are equally thin.  Perhaps cut the strips from aluminum soda cans and steel soup cans, etc.  Use a magnet to check for steel vs aluminum.  Glue the strips together using epoxy or super glue.  Attach one end of the combined strip to a firm base and leave one end free to move in front of a paper scale.  You now have a bimetalic thermometer.  The thermometer can be made to be more sensitive by using greater length strips and bending the strips into a spiral and attaching a pointer to the free end of the spiral to amplify movement.  This is how most oven thermometers are built except the metals are joined without glue.  The principal of operation of a bimetalic thermometer is that one  metal expands or contracts more or less than another metal.  When joined, a temperature change causes the combined strip to bend.  You can calibrate your thermometer by marking its "pointer" position at two or more large temperature changes then calculating the total deflection divided by the total temperature difference to get deflection per degree (either F or C).  Be careful with tin snips and epoxy or super glue.  Good luck.\n\nAs an alternative, you can make a highly accurate experimental thermometer by winding very thin insulated copper wire (like that used in toy motors) around a wooden spool and connecting the scraped   wire ends to an accurate ohmmeter to measure resistance change vs temperature change.  Calibrate as before but remember that calibration temperatures must be steady long enough for any lag to catch up.  This is called a resitance thermometer and accuracy will depend on the length and thinness of wire and sensitivity of your ohmmeter.  Also the ohmmeter should not cause enough current to flow in the wire to heat the wire.  Observe for drift (increase in resistance and temperature) while taking measurements.
748213
Try Edmund Scientific on the web..but if you want to make your own try the link provided.\n\nGood luck!
562654
Okay, I'll try this one -\n\nRun this experiment twice (or more times), each time with a piece of metal having different density.  The metal piece should be of adequate size (a sewing needle isn't going to do it), it needs to be big enough to significantly affect the temperature of the water.  You will need to know the mass of the metal (i.e., weigh it) and have a thermometer capable of reading from room temperature up through boiling or so.  Please note this is not going to give you a highly accurate answer, but can give you a ballpark idea (I'm guessing you're probably not doing this in a 500 million dollar lab).\n\nThe procedure:\n\n1)  Measure and record room temperature as T1.\n\n2)  Weigh the metal, call it M1.\n\n3)  Bring a known quantity of water (weigh it, or measure it and convert to weight, call it M2) to a temperature just short of boiling (say 180F to 200F, use the same temperature for each run of this experiment).  Record the temperature as T2, and remove the heat source (take it off the burner, etc.).\n\n4)  Drop in a metal piece at room temperature.  Allow a couple of minutes for heat to exchange.  Make sure you use \nthe same amount of time for each run of this experiment.\n\n5)  Measure and record the new temperature of the water as T3.\n\n6)  Repeat with your other metal samples.\n\nYou can now estimate the specific heat capacity for each metal.  It will not be super-accurate (heat escapes your system, and temperatures won't have completely equalized), but should give you some idea.  Just assume all temperatures did equalize and that no heat escaped for calculational purposes.\n\nSince (you are assuming) the heat which left the water went into the metal, then the product of mass, specific heat capacity, and temperature change should be the same for both the metal and the water (but in opposite directions).\n\nThis means that:\n\n(M1)(c1)(T3-T1) = (M2)(cw)(T2-T3)\n\nwhere c1 is the specific heat capacity of the metal, and cw is the specific heat capacity of water (look it up on Google to get the units you need).\n\nSolving this, you get:\n\n......(M2)(cw)(T2-T3)\nc1 = -----------------\n........(M1)(T3-T1)\n\n(sorry about the dots, I'm trying to keep everything aligned)\n\nRepeat the calculations for each of the metals.\n\nYou will need to calculate (or look up) the densities of each of the metals.  Then, graph density vs. the specific heat capacities you calculated, and see if your hypothesis is true.\n\nHave fun!
164495
this experiment is called calorimetry