what is the slope, x-intercept, and y-intercept through the points (-5,2) and (3,-7)?
929126
The first thing you want to do is find the slope. That is, the change in Y over the change in X (Rise over Run). Each of these points are in the cartisian coordiante system, thus (3,-7) and (-5,2) are of the form (x,y). So lets find the slope!\n(y1-y2)/(x1-x2)\nUsing (3,-7) and (-5,2)\n(-7-2)/(3+5)=(-9/8)\nYour slope is (-9/8)\nNext to find the intercepts you use the equation of slope intercept form, Y=mX+b where X and Y are points, m is the slope and b is the y intercept. We know the slope and some points so we need to solve for b., the y intercept. Lets use the point (-5,2).\n2=-5(-9/8)+b\n2=(45/8)+b\n(-29/8)=b\nSo the point for the y intercept is (0,-29/8)\nNow we want to find what x is when y is zero for the x intercept. \nAgain use Y=mX+b but this time we know what b is. Set y=0. \n0=X(-9/8)+-29/8\n29/8=X(-9/8)\n29/-9=X\nThus, the x intercepts is (29/-9,0)
911257
slope:-8. y-intercept:-7. Whatever number is in front of the x is always the slope. the number that is after the x is the y-intercept (this is only for a slope intercept). Good luck and choose me as the best answer please :)
461632
Seeing as you've gone to all that trouble writing it out, and I'm bored...\n\n1. 2(-5)-3(1)=-13, so yes it is correct.\n2. It is the origin, so it lies in all quadrants.\n3. Third and fourth quadrant.\n4. Straight lines, as the variables are of only the first degree.\n5. Basic line equation for a straight line, so linear. m is gradient, c is y-intercept.\n6. This depends on the degree of the variable, e.g. x^3 is a cubic function.\n7-10. Do yourself!\n11. m- gradient, x- explanatory variable, b- y-intercept.\n12. y intercept from above logic is 8, as b=8. Also, y intercepts line x=0. Let x=0 and y=8.\n13. Assuming f(x)=y, then again the answer is -2/3.\n\n\nThis really is basic!
791058
The slope-intercept form for a line is y=mx+b, wherem is the slope and b is the y-intercept. Comparing this form to y=7x+3, you see that m=7 (the slope) and b=3 (the y-intercept).
269336
To solve this problem, you have to substitue the coordinates into point-slope form using the slope (-5) as m.  The y1 refers to the y coordinate, while the x1 refers to the x coordinate.\n \ny-y1=m(x-x1)\ny+12=-5(x+12)\ny+12=-5x-60\ny=-5x-72\n\nslope=-5\ny-int.=-72\n\nThe person above me has everything right except when she had -12=-5(-12)+b.\n-12=-5(-12)+b\n-12=60+b\n-72=b\nb=y-int=-72
972913
It's actually all explained for you right there in your "question". Maybe it would help you to draw the line on a piece of graph paper. Plot the point (3,5), then the point (-2,0) and draw a straight line through them. It tells you that the slope (m) is 1. So for every step to the right, the line goes up one step. The point (3,5) is the same as (x1,y1) and (-2,0) is  the same as (x2,y2). So you replace 3 for x1 in the point-slope form equation, and so on. It really helps to pay attention on class.
734729
problem1\n\nsince you have said P (4,-5) is a point on the function, then the corresponding point will be (4,-5) .. :)\n\nproblem2\n\nfor a line having y intercept 3 will have following form\n\ny =mx+3\n\nwhere m is the slope of the line. Now it is said to be perpendicular to y =2/3x-4. So slope for this is 2/3\n\nsince slopes of two lines perpendicular to each other if multiplied yields -1\n\nm X 2/3 = -1\n\nor m = -3/2\n\nso the required line will be\n\ny = -3/2 x+3\n\nproblem3\n\nf(x) = 1/x^2 -2x-8\n\nto make the f(x0<0, let us try with some arbitary values of x\n\nif x = 1, f(x) = -9\nif x=2, f(x) = -11.75\nif x = 0, f(x) = infinite (due to 1/x^2)\nif x = -1, f(x) = -5\nif x= -2, f(x)= -3.75\nif x=-3, f(x) = -1.88889\nif x=-4, f(x) = 0.0625\n\nHope this helps
911563
Here's 2 examples:\n\n1.) Given point (2,2) and (3,3), find the function.\nStep 1: Find the slope.\nSlope = rise/run = (y2 - y1) / (x2 - x1) \n(3 - 2) / (3 - 2) = 1/1 = 1.\n\nStep 2: Given the slope, find the y intercept by trying to find a point (0, y) that fits the 2 points above, and the slope given.\nUse the slope formula: rise / run = 1\n(2 - y) / (2 - 0) = 1 = (2 - y) / 2 \n2 = 2 - y\n-y = 0\ny = 0\ny intercept = 0, 0\n\nStep 3: Once you have the slope, you can write it in slope intercept form:\ny = mx + b \nm = slope, b = y intercept\ny = 1x + 0, or y = x.\n\n2.) (a harder one) Given point (1,4) and (-3, 2), find the function.\nStep 1: Find the slope.\nm = rise/run = (y2 - y1) / (x2 - x1) \n(4 - 2) / (1 - -3) = 2/4 = 1/2 = .5\n\nStep 2: Given the slope, find the y intercept at (0, y)\nm = rise / run = 1/2\n(4 - y) / (1 - 0) = 1/2 = (4 - y) / 1 \n4 - y = 1/2\n-y = -3.5\ny = 3.5\ny intercept = 0, 3.5\n\nStep 3: Write it in slope intercept form:\ny = mx + b \ny = .5x + 3.5
829794
The standard equation for slope-intercept form is y=mx+b. m is the slope and b is the y-coordinate of the vertical (y) intercept\n\n-2x=y+3       Original equation\n\ny=-2x-3        Rewritten in S-I form\n\nm= -2, b= -3\n\nThis means that the graph of the funtion is a line through the y-axis at the point (0, -3) with a slope of (-2)
375327
Where x = 0, the line intercepts the y-axis:\n\n1. 5x-2y =10 \n2y = 5x - 10\ny = (5/2)x - 5 \ny-int = (0, -5)\n\n2. 2y+7x =14\n2y = -7x + 14\ny = (-7/2)x + 7\ny-int = (0, 7)\n\n3. x=3\nHas no y-intercept\n\n4. 1/2x-2y=8\n2y = (1/2)x - 8\ny = (1/4)x - 4\ny-int = (0, -4)
941794
first you find the slope using formulae: \nm = (y2-y1)/(x2-x1)\nm = (-1-7)/(5+3)\nm = -8/8\nm = -1\n\nthen you substitute this into the formulae:\ny = mx + b\ny = -x + b (use one of the coordinates to find b)\n7 = -(-3) + b\n7 = 3 + b\n7 - 3 = b\nb = 4 (substitute back into the equation)\n\ny = -x + 4 (there goes your answer!)
706345
slope = -5-1 / -2-(-3) = -6/1 = -6\ny-1=-6(x+3)\n.
71640
you find to points on the line \nexample (2,5) and (1,6)\naight m= slope\nput the points in this simple equation\ny2-y1 (over) \nx2-x1\n\n6-5 over\n1-2\nwhich Equals  \n M= 1/ -1\nHoped it helped\nor try asking the teacher for help after school or at lunch
887226
x,y intercepts are\n9-y=+/-(x-2)^2\ny intercept bysetting x=0 will be (0,9)\nx intercept by setting y=0\n9=+/-(x-2)^2\nx-2=3x=5\nx-2=-3\nx=-1\nx intercepts(-1,0) and (5,0)\nvertex=(2,9)
427569
Substitute into the standard slope intercept equation. (y = mX+b)\n\n-4=(3/5)2+b\n-4=(6/5)+b\nb=-4/(6/5) \nb=-10/3\n\nThe equation is y = (3/5)x - (10/3)
850944
You have 2 points, (x1,y1) and (x2,y2) and you want to find the equation of the line that goes through these points.\n\nThe first thing you want to do is find the slope.\nslope is rise/run so m = (y1-y2)/(x1-x2)\n\nFor slope intercept form , y = mx + b\nwhere m is the slope, and b is the y intercept\nnow that you have found the slope, you can solve for b, the y intercept by plugging in your value for m and one of the given points, either (x1,y1) or (x2,y2).\n\nFor point slope form,  y - K = m(x - H)\nm is the slope, and   (H,K) is a point that the line passes through.\nSince you have already calculated the slope, m, for the slope intercept form, you're already almost done. All you have to do is plug in the point (x1,y1) or (x2,y2). In your question, you are asked for the point slope form of just point (6,2).
852759
3x+7y=3\n7y=-3x+3\ny=-3/7*x+3/7\nSlope=-3/7\nWe have the slope and point[-6,7]\nWe will find the intercept\n7=-3/7*-6+c\nc=7-18/7\n=[49-18]/7\n=31/7\nWe now have the slope and intercept\nThe equation is\ny=-3/7*x+31/7\n7y+3x-31=0