Confused on finding the slope and Y intercept from a linear equation.?
930270
Well done, you have already done the hard work. The number in front of the x is the slope ie -2/13 and the other number is the y co ordinate of the y intercept ie (0 , 5/13). Another way to find the y intercept is to substitute zero for x and solve for y, or alternately substitute zero for y to find the x intercept.
953271
if it is parallel the slope is 3 so the equation is\ny = 3x + b\nnow you just solve\n-2 = 3*2 + b\n\nfor b and that is your new y intercept and equation.
285662
to find an equation.......\n\ny=mx+b\n\nm=slope \nb=y-intercept
498526
The value of y at the y-intercept (b), which is the point at which the line intersects the y-axis, is -9, and the slope (m) is -3. Following, the y=mx+b or slope-intercept form, the equation is y=-3x-9.
194328
Slope intercept form means that you have to solve for y.  This will result in an equation where y is equal to a multiple of x plus/minus a constant. The multiple is the slope of your line and the constant is the y intercept (where the line crosses the y axis.)\n\nSee http://id.mind.net/~zona/mmts/functionInstitute/linearFunctions/lsif.html for more info.
89344
Use the two given points:\n(x1=7, y1=5) and (x2=-1, y2=1/5)\nand the "two point equation":\ny-y1 = ((y2-y1) / (x2-x1)) * (x - x1)\nto get started on this problem.\n\ny-[5]=(([1/5]-[5]) / ([-1]-[7])) * (x-[7])\ny-5=((-24/5)/(-8))*(x-7)\ny-5=(3/5)*(x-7)\n\nNow put the equation into the "slope intercept" form of y = mx+b.\n\ny-5=(3/5)*x - (21/5)\ny=(3/5)*x - (46/5)\n\nThe slope = 3/5\nThe intercept = -46/5
715413
To find the y-intercept to the line satisfying the equation y = (2/3)x + 3, we set x = 0 to obtain y; that is,\ny = (2/3)(0) + 3 = 3.\n\nSo, the y-intercept is 3. (i.e., The given equation of the line passes through the point (0, 3) in the Cartesian plane. )
698987
Another form of the equation is the point-slope form. If you have two points, find the slope.\n\nm = (a2-b2)/(a1-b1) for points (a1,a2) and (b1,b2)\n\n  Then take one point (a1,a2) and plug it into the following:\n\n(y-a2) = m(x-a1)\n\nIt actually turns out to be the slope intercept form, but if your teacher will accept that form than it is easier since you can just leave it like that.
665061
have the equation in slope intercept form except with a greater then or equal to sign or less then or equal to sign\nexample:  Y > Mx + B  then solve it like you would a normal slope intercept equation by solving for x... start by adding or subtracting b to Y and then divide the slope which is Mx from both sides and then you will get your x answer the greater or less then sign will change if the answer is negative it will face the opposite way from which it was if postive answer it won't change....... hope this helps......
564627
change the equation to slope intercept form\nsolve the equations for y\nx+2y=3\n2y= 3- x\ny= -x/2 + 3/2\nDo the same thing for the other formula\nthe form is\ny = mx + b\nAfter that just plug in numbers for x to get y
203791
The x-intercept is when the line crosses the x axis. When your equation's graph crosses the x axis, it means that y is zero at that point. right?\n\nSo to find the x-intercept you assume y=0 and solve for x.\n\nNow to find the y-intercept, it is when x=0. If you imagine it graphically, when it touches the Y-axis, X's value is zero.\n\nSo to find the y-intercept you assume x=0 and solve for y.\n\nExample: y= 3x-6\nx-interp: assume y=0\n      0= 3x -6      \n 3x = 6     \n x = 2\n\ny-interp: assume x=0 \n     y= 3*0 -6        \n          y= -6
308059
slope: -3/4\nx intercept = 0\ny intercept = 0
922969
y - y value.\nx - x value.\nm - slope of line.\nc - line intercept.\n\nSlope = -½\n pt(-2,4)\n y = mx + c\n 4 = m(-2) + c\n 4 = -2m + c\n 4 = -2(-½) + c\n 4 = +1 + c\n 3 = + c\n\n y = mx + c\n y = -½x + 3
621346
y=mx+b (this is known as the standard form of linear equations)\n\nm=slope\nx=x values\ny=y values\nb= y-intercept\n\nso the answer for you question is:\n\nslope = -1\ny-intercept = -3\n\nEXPLANATION:\n\ny = mx + b\ny = -x-3\n\nm= -1   and    b = -3\n \nslope = m    and   y-intercept = b\n\nthus, the slope is -1 and the y-intercept is -3\n\n\nNote: the slope is rise/run (rise over run) -- to make a graph use the y-intercept and the slope -- once you have the slope and the y-intercept, making this graph should be easy because it's a linear graph -- but if you still don't get it ask your teacher\n\n\nthus, the slope is not a-1 -----there is no "a"
730934
First you have to find the equation of the line that contains these two points (9,1) and (5,5)\nI believe the easiest way to do that is to use slope and y-intercept form (y=mx+b) m= slope and b= y-intercept\n\nto find slope, m = rise/run\nrise = -4\nrun = 4\nrise / run = -1\n\nTo find y-intercept plug in a coordinate pair and use are found slope.( i used 5,5)\ny=mx+b  x= 5 y=5 m=-1 b =?\n5=(-1)(5) +b\n10 = b\n\nSo this is our equation of the two points\ny=-x +10 \n\nNow we can use this equation to find whether  (10,0) is on  the line: Substitute (10,0) and see if the equation is still valid\n\n 0 = (-1)(10) + 10\n 0 = 0 Yes (10,0) is on the same line as the other points
350403
Equation of a line:  y = mx + b\n\nm = 3 (slope)\ny = -4 (y-intercept)\n\ntherefore:  y = 3x - 4 \n\nCrosses x-axis at y = -4 (0,-4)\nCrosses y-axis at x = 4/3 (4/3,0)
850944
You have 2 points, (x1,y1) and (x2,y2) and you want to find the equation of the line that goes through these points.\n\nThe first thing you want to do is find the slope.\nslope is rise/run so m = (y1-y2)/(x1-x2)\n\nFor slope intercept form , y = mx + b\nwhere m is the slope, and b is the y intercept\nnow that you have found the slope, you can solve for b, the y intercept by plugging in your value for m and one of the given points, either (x1,y1) or (x2,y2).\n\nFor point slope form,  y - K = m(x - H)\nm is the slope, and   (H,K) is a point that the line passes through.\nSince you have already calculated the slope, m, for the slope intercept form, you're already almost done. All you have to do is plug in the point (x1,y1) or (x2,y2). In your question, you are asked for the point slope form of just point (6,2).