In how many ways can three girls and three boys sit in a row, if the boys and girls are to sit together?
930557
Either we have BBBGGG or GGGBBB. In both cases, there are 3! ways of arranging boys, and 3! ways of arranging girls. So 3!*3!*2 = 72.
613390
i have one girl, would like 1 more girl and then one boy.
1098304
5 brothers and 2 sisters......4 older brothers and 2 older sisters...i am the BABY  GIRL and i have one brother under me....believe it or not, we all have the SAME MOTHER AND FATHER.... that's odd in today's world.......lol
181855
If 2/5 of the students are boys, 3/5 must be girls.\nTherefore the boy to girl ratio is (2/5):(3/5)=2:3.
704913
Suppose there are 13 girls and 11 boys in your class.  Then the ratio of girls to boys is 13 to 11 or 13:11 or 13/11
311693
Permutation is arranging some objects in order.\nIf the objects are arranged in a circle then it is called circular permutation.\n\nExample: There are 6 people in a party and they have a 5-seater table. The remaining person sits in a separate chair. In how many ways they can sit?\nFrom permutation theory it is 6*4! = 144
913636
if there were 12 groups each with 1 cheerleader in....you will have 12 groups
772510
In theory 11 - one for each dimension.\n\nIn practice 3 - One to hold, one to turn, and one to rebuttal the whole time.  :-)
1098869
girls,girls, girls & more girls. there is no order the others don't count
481530
OK -I'll call seating spots  1 2 3 \n                             4 5 6  Joe I put at 5 with  V ball at 4 and C Pres @ 6. that makes 1 the Preacher's kid.  Since Sally likes Vball and aint Preacher's kid, she sits at 3 or 6. Now Frank sits opposite Valdictorian Not Joe-that means  Frank sits at 6 (pres) and Sally at 3 is Valdic-torian .By now we know 2 is cheerleader since Joe cant be-FRank likes cheerleader and this crowd is hetero. Since 2 is cheer.. then Gina sits 1 and Betty is cheer..and that leaves Ron at 4 and Joe the B ball\nSO-preachers kid is Gina @ 1spot-\nBetty @2is cheerleader-\nSally is Valdictorian @ 3 \n-Ron is V ball @4-\n-Joe is B ball @5-\n-and Frank is \nclass president @ 6\nEasier if you start with a seat grid to see it
885158
Let's assume there were 'g' girls and 'b' boys at the beginning.\n\nWith the given assumptions we have,\n\ng-15 = 2b ---- (i)\n\nand\n\ng-15 = 5 (b-45) ---- (ii)\n\nfrom (i) & (ii) we get,\n\n2b=5(b-45)\n\nor, 2b=5b-225\nor 2b-5b = -225\nor -3b = -225\nor b = 75\n\nfrom (i) we get\n\ng-15 = 2b = 2X75=150\n\nso, g = 150+15 = 165\n\nSo there were 165 girls and 75 boys initially \n\ncool
145454
three girls ...............(if it is ok with you that is....)
78487
6 - three for each team
209520
It all depends on the number of children and their sex. If you have two, one boy one girl than you will get a three bedroom. If you have two boys or two girls than you will most likely get a two bedroom.
516371
6 Boys, 2 girls\n(Donna has 6 brothers and 1 sister, Tom has 2 sisters and 5 brothers\n\n(Donna +1, Tom +5)
318418
First think of a situation involving 4 seats for 4 people:\n\nIn the first chair any of the 4 can sit, in the second, any of the remaining 3, in the third either of the remaining 2 and the last person gets the 4th seat\n\nthe number of combinations is 4*3*2*1= 24\n\nThis is the same for 4 couples since each couple sits together.\nNext, each couple can be in one of two positions because the members of a couple may switch seats and still be sitting together.\n\nthis multiplies the original number of combinations by 2^4 or 16\n\n24*16=384
704392
b + g = 27 and g = b + 3\nReplacing g with b+3 in the first equation, we get\nb + b + 3 = 27\nCombine like terms\n2b + 3 = 27\nSubtract 3 from each side\n2b = 24\nDivide both sides by 2\nb = 12 boys\nSince there are 3 more girls than boys, we add 3 to 12.\ng = 12+3 = 15 girls