Please solve this problem and show us the steps. Thanks.7c + 3d= -16   and 7c + 5d = -8?
925685
7c + 3d= -16 .. (1)\n7c + 5d = -8 ... (2)\n\n(2) - (1) 2d = 8\nd = 4\nBy substitution\nc = -4
776052
3*5b= 15b      \n3*-7= -21\n 15b-21=-7+b\n15b-b-21=-7\n15-b=-7+21\n14b=14\nb=14/14\nb=1
1177436
-5 - 8 • (71-43)= -364.\n\n71-43=28, then,\n-5 - 8= -13, then,\n-13 • 28 = -364
706243
-2y+3=7y-42\n-2y+3-3=7y-42-3\n-2y=7y-45\n-2y-7y=7y-7y-45\n-9y=-45\n-9y/-9=-45/-9\ny=5
981955
3a-7a= -4a\n-2xy+5xy=3xy\n\ntherefore you get...\n\n3xy-4a
407918
(3,-7)(6,15)\nm = (y2 - y1)/(x2 - x1)\n\nm = (15 - (-7))/(6 - 3)\nm = (15 + 7)/3\nm = (22/3)\n\nANS : (22/3)
429835
ok, u have to use distance formula\n\nsqrt[(-4-(-7))^2+(c-7)^2]=5   \nsquare both sides\n[(-4-(-7))^2+(c-7)^2]=25      \nadd the stuff in the parentesies\n[(-3)^2+(c-7)^2]=25           \nexponents\n9+(c-7)^2=25                  \nsubtract from both sides\n(c-7)^2=16                    \nsquare root both sides\nc-7= +/-4                     \nadd to both sides\nc=11 or c=3
770383
-4(3a+4b)= -12\n3(4a-5b)= -16\n\n-12a-16b= 48\n12a-15b= -48\n\n-b=0\nb=0\n\n3a+4(0)= -12\n3a= -12\na= -4\n\ncheck: 3(-4)+4(0)= -12
1106166
I used the quadratic formula\n\na = 5\nb = -7\nc= = -1\n\n-(-7) +- sqrt[ (-7^2 - 4(5)(-1)]\n----------------------------------------\n             2(5)\n\n7 +- sqrt [ 49 - (-20)]\n---------------------------\n             10\n\n7 +- sqrt [69]\n------------------\n         10\n\n\nFor your second problem, one of the solutions is -1/3.  The other is also 4\n\nfrom (11+13) / 6 = 4 or yours (11-13) / 6 = -1/3
995498
5 - y = 6y - [4 + (1/7)(21y -14)]\nDistribute the 1/7\n5 - y = 6y - [4 + 3y - 2]\n5 - y = 6y - [3y + 2]\n5 - y = 3y - 2\n-4y = -7\ny = 7/4
168190
If you were to have the equations just as they are then 5x-3y would equal 7 not 13.  And 4x-3y would equal 5 not 11.  So try putting in -1 as y, then it will work out as you have it originally written.
1075528
(7.3-.5-2.5)/-.9 = b\n\nb = -4.8
969498
You need to find a common denominator for each one.\n(7x+3)/x\n\n(40c+18z)/(15cz)\n\n(8+21)/6y = 29/6y
1008519
Solve the first one for x:  x = 3\nSolve the second one for y:\n7x - 5y = 8\n7(3) - 5y = 8\n21 - 5y = 8\n-5y = -13\ny = 13/5\n\nCheck it:\n3-3 = 0 ---> OK\n7(3) - 5(13/5) = 21 - 13 = 8 --->OK\n\nDone.  Hope this helps!
915728
1.4u+ut-6t=-13\nu(4+t)-6t=-13\nu(4+t)=-13+6t\nu=(-13+6t)/(4+t)\n\n2.c(a+3)+(c+7)=5a\nc(a+3+1)=5a-7\nc(a+4)=5a-7\nc=(5a-7)/(a+4)\n\n3.you haven't completed the question.solve interms of what?\nif it is w\n4uw-3w=v(v-1)\nw(4u-3)=v(v-1)\nw=v(v-1)/4u-3)
412752
This looks like it's been rotated 90 degrees counterclockwise.\n\nSo, I guess it would be as follows:\n\nx = -(9/25)(y-3)^2 + 7
296060
5x-2y=7\n3x+4y=2\n\n5x-2y=7 (multiply this by 3)\n3x+4y=2 (multiply this by 5)\n\n15x-6y=21  (now subtract the bottom from\n15x+20y=10  the top)\n\n-26y-11 (y=.42 then substitute y in the problem)\n\n15x -6*.42=21 (then solve from there)