what is the value of x? (x-5)squared=4?
921129
x = 7 or 3\n\nTake the square root of each side of your equation, to get the following:\n\n| x-5 | = 2\n\nNotice I used absolute value signs, because either 2 or -2 squared will give us 4.\n\nSo, x-5 = 2 or x-5 = -2\n\nx-5 = 2 → x = 2+5 = 7\n\nx-5 = -2 → x = -2+5 = 3\n\nSo x=7 and x=3 are both solutions to your equation.\n\nHope that helped!\n\n~ ♥ ~
1013726
There is no real value for x that satisfies that equation.  It simplifies to (x-3) = (x+1).  In other words, (4(x-3))/4 does not = x+1.
775585
-5+-sqr(25-4(2)(-9))/4\n-5+-sqr(97)/4\n1.21 and -3.71
1066492
x = -4\n10points thank u!
198477
x^2-6x+5=\n\nx^2-5x-x+5=  [presenting -6x as -5x-x]\n\nx(x-5)-1(x-5)= [getting out common factor]\n\n(x-1)(x-5)\n\nTo see that it was done correct put any small number in the original expression and the result and compare them. If you did right, you should get two numbers which are equal to each other.\n\nPutting x=1 on the left side(the original expression):\n\n1^2-6*1+5=1-6+5=-5+5= 0.\n\nPutting x=1 on the right side(the result):\n\n(1-1)(1-5)=0*(-4) = 0.\n\nWe got on both sides the number 0, as expected, which probably means we did it right.\nTher final answer is:\n\n(x-1)(x-5)\n\nHope that helps.
602540
x + 3 >  8 ==> x >  8 - 3  ==> x > 5\nx - 4 < -2 ==> x < -2 + 4 ==> x < 2\n\nAnswer... not possible.
1009002
y = x² - 4x - 5\n\nSimplify -5 = 4 - 9 to complete the square\ny = x² - 4x + 4 - 9\n\nSimplify the square\ny = (x - 2)² - 9\n\n^_^
41284
Wait, all the answers are wrong\n\nx^2+4>4\nThen x^2-4x+4>0\nthen (x-2)^2>0\nBut hey, (x-2)^>0 is always true expect when x=2 which equals zero. An square is always positive or 0.\nSo the answer will be any value but 2 or R-{2}\nthese are the evidence:\nPut them in original non equation\nx=0 then 4>0 which is true\nx=-1 then 1+4>-4 so 5>-4 which is true\nx=3 then 9+4>12 so 13>12\n but at x=2 then 8>8 which is incorrect
216656
(x^4 - 25) = (x^2 - 5)(x^2 + 5) = (x - 5)(x + 5)(x^2 + 5)\n\n(x^4 - 25)/(x - 5) = [(x - 5)(x + 5)(x^2 + 5)]/(x - 5)\n(x^4 - 25)/(x - 5) = [(x + 5)(x^2 + 5)]\n(x^4 - 25)/(x - 5) = x^3 + 5x^2 + 5x + 25\n\nBut remember that division by 0 is a no-no, so looking at the original expression, a graph of this will have a vertical asymptote at x = 5.
636051
x=4\n\nplease solve...\n\n8-(1) :-) ;-(
775656
2(x - 5)^2 = 3\nSo (x - 5)^2 = 3/2\nThus x - 5 = ± √(3/2)\n= ± √6 / 4\n\nThus x = 5 ± √6 / 4
741230
x = 6\n\n8x + 5 = 4x + 29   (subtract 5 from both sides)\n8x = 4x + 24         (subract 4x from both sies\n4x = 24                 (divide both sides by 4)\nx = 6
117989
do it like grade 5 - 1 see - \n[X-(1/5X)^2] sqrt\n    (1/5X)^2 \n     1/25 (2X) \n[X-1/25(2X)]sqrt\nX=4 , understand
321475
*(2x/(x^2-4)) + (5/2-x) - (1/2+x)\n*(2x/(x^2-4)) + (5/2-x)((2+x)/(2+x)) - (1/2+x)((2-x)/(2-x))\n*(2x/(x^2-4)) + (10+5x)/(4-x^2) - (2-x)/(4-x^2)\n*(2x/(x^2-4)) + (8+6x)/(4-x^2)\n\nyou should be able to get it from there
338855
You are looking for values of x such that\nx^3 > 4x^2  Solve for x by bringing everything to one side.\nSo subtract 4x^2 from both sides\nx^3 - 4x^2 > 0\nFactor x^2 out\nx^2(x-4) > 0\nx^2(x-4) = 0 when x = 0 or x = 4\nSince you're looking for positive numbers, you only have to test a number between 0 and 4, and then another number greater than 4\nAny number between 0 and 4 will result in a negative value.\nAny nummber greater than 4 will result in a positive value.  You are looking for the positive values because  the expression is greater than zero.\nThus, any number that is greater than 4 will give you the result that the cube of a number is greater than 4 times its square.
893470
x^2-4x-5 = (x+1)(x-5) if that helps any.  I just factored the trinomial into two binomials.  A graphing calculator would help you solve this in no time.  I have my own homework to do, so I'm not gonna do this for you, but I hope that that will get you started.  Good luck.
630233
(4/x+2)+3-4/x = (2/x-3)+3-4/x\n5 = 2/x-4/x\nx(5) = x(2/x-4/x)\n5x = 2-4 = -2\n(5x)/5 = (-2)/5 = -0.4\nx = -2/5 = -0.4