Which creates force of friction: sliding your physics book across the table on its back cover or along one of?
919106
They all involve friction, but I think you mean which has the most force due to friction, right? :-&#92;  If so, I believe the answer is that they are all the same.\n\nIn simple situations, the frictional force created by sliding two surfaces against eachother is given by:\n\nf = u * N\n\nWhere u (mu) is the frictional coefficient (an experimentally-determined constant) and N is the normal force, which is mg (mass times accelleration of gravity) if the surface isn't tilted.\n\nSo, assuming the frictional coefficient is the same for all sides of the book, there is no reason why changing the sides would make a difference.
909261
basically it is the amount of friction, caused by movement, or no movement. below is a GREAT link to explain. hope this helped!!!!\n\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/frict2.html
757274
READ THIS CAREFULLY\nAs the block just slides on the table the net force just equals the limiting friction acting on the body\n\nhence,\nF=coeff. of friction * Nor,mal rxn\n\nnormal rxn= weight of body on a plane\n\nhence F= 20*9.8*0.4\n              =78.4N\n\nACC \nit is just begg to slide and the given data is just unsufficient 2 find the acc. of the box
834102
1)  I'm not entirely sure.  It may just be the preference of that publisher, or just that the quantities being compared were not measured more accurately than to two places.\n\n2)  The coeffecient of friction is basically a measure of how well two surfaces slide against one another.  Pressing down simply increases the force, it does not necessarily change the structure of the surfaces in contact.\n\n3)  The coefficient of friction has no units because it is a ratio.  If you were to write out the units being compared in a fraction, say 2 Newtons / 4 Newtons, the units would cancel out when divided.
760426
Figure out the centripetal force.  After that, this becomes a sliding problem turned on its side.
975611
is the ques complete is there any friction between the boxes or any other force. can't understand the ques itself do we have a figure somewhere
201866
Circulation of lubricant through the space between a pair of bearing surfaces by their relative motion and the adhesion and viscosity of the lubricant.
65267
It's me again, Dhinesh,your classmate.\nrolling frictin is the friction caused due to rolling. it opposes rolling & it acts on a single point as there is a single pt. which has contact with surface
1130182
Um... I think maybe pull... if something is rotating/turning it is creating it's own little gravity field (I think!) therefore making it easier to pull.  I'm no scientist but this is an educated guess.
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Rolling friction : http://webphysics.davidson.edu/faculty/dmb/PY430/Friction/rolling.html\n\nSliding friction: http://www.mtsu.edu/~phys2010/Lectures/Part_2__L6_-_L11/Lecture_10/Friction/friction.html
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The butter affect the slice of bread's CG (Centre of Gravity) by lowering it, hence, it topples butter-side down.\n\nSame principle (lowering of CG) is used in formula 1 cars and double decker buses. Prevents overturning because the point of CG is less likely to exceed the base of the object.\n\nYou can apply this same principle humourously e.g. how heavy and how large can a ladies' boobs get before she keels forward every time she stands up. =P *wink
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The special case of mechanical equilibrium of a stationary object is static equilibrium. A paperweight on a desk would be in static equilibrium. A child sliding down a slide at constant speed would be in mechanical equilibrium, but not in static equilibrium.\n\nIn static equilibrium there is not only a status quo, but there is no motion at all. In dynamic equilibrium there is motion but the overall situation is unchanging.
198734
The force of friction is dependent on two things, the Normal force between the "object" and the "surface" and the coefficient of friction between the two.\n\nThe normal force on a level surface is equal the weight of the object.  You are given the mass, from this, you can easily calculate the force of weight (and this F_n).\n\nYou are given the coefficient of friction, greek letter mu.\n\nThe force of friction can be found as,\nF_f = F_n * mu\n\nThe force of friction is always in the direction opposite that of the motion.  So if your traveling "forward", the frictional force is pointed "backward".\nWhat are the two components in the formula that affect the magnitude of the frictional force?  Just the normal force (which is dependent on mass and gravity) and the coefficient of friction.  For all intensive purposes, mu is constant, as is the mass and gravity of the object.  Therefore, the force of friction is constant.\n\nYou are given in initial velocity.  You are trying to find how far (change in distance) the car will travel while this constant force is being exerted on it before the car comes to a stop.\nThere are several ways this could be found.  I think the energy method would be the easiest, but I will cover the kinematic method as well....\nThe car has some initial kinetic energy when the problem starts out.  KE = 1/2 mv^2.  After the car comes to a stop, the car has zero KE...therefore some work had to be done on the system to change the energy (we assume a level road).  The change in KE equals the work done.  Work is also equal to the product of the force applied over the distancd applied.\nW = F * d\nSince the frictional force is what is causing this change in energy (which we know, it was calculated earlier), and we also know the change in KE, we can simply solve for the distance, d.\n\nThere is also another possible solution.\nWe know that the frictional force will cause an acceleration.\nF = m*a\nWe know that an acceleration will cause a change in velocity.  We know ,\nv_f^2 = v_i^2 + 2ad\nwhere v is velocity (i is initial, f is final), a is acceration, and d is distance.  Simple solve for d.
863293
In the opposite direction of the applied force or motion
136353
If you consider a model in which both surfaces which cause friction have crusts and troughs, and their interlocking causes the frictional resistance, then it is explained as follows.\n\nThe lubricant molecules fill up the troughs in both surfaces and make them more or less even, and hence there is less interlocking among the two surfaces, and so less friction.
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friction is opposing force which opposes motion of body\naccrding to new studies fiction force exists due 2 the molecular interaction (forces)  b/w surface and body \nu can see here that more the roughness more the interacction b/w 2 bodies \nhence more fri. forc. hence more force is required 2 move body
883840
The force due to friction (whether static or kinetic) is dependent on the appropriate coefficient of friction (static or kinetic), between the materials, and the mass of the object (which defines the NORMAL force between the two surfaces). \n\nBy the way, the coefficient of static friction is ALWAYS greater than for kinetic friction.\n \nNow, no matter what the surface area, the normal force will remain the same, since the mass remains the same. In other words, no matter what side you put the block on, the force due to static friction and the force due to kinetic friction will not change.\n\nHope this helps!