what is the pushing power when the engine ignites the gas?
927571
Any explosion is a rapid expansion of gas..the volume in the engine cylinder is at a minimum when this occurs,and the only release is the downwards force on the piston, which is the expanding driving force...
1026768
gasoline burning engines
842204
The work done by the engine in lifting the object is m*g*h = 400*3.5 = 1400Joules. This the work output of the engine.\n\nNow, efficiency = (work output)/(input) * 100%\n\nTherefore, 15 = 1400/input * 100\n\ninput is thus = 140000/15 = 9333.33Joules
1129567
You mean:\npetrol in "internal compression engine" - this happened to my parents, it ruined the vehicle.  I'm not sure but I suspect a minor explosion occured in the piston chamber.\n\ndiesel in "internal combustion engine" - I'm not sure anything would happen.  The car might start, or might not.
225260
do you mean petrol?\n\nif so a gas engine works on the spark theory in that you have a closed combustion chamber in which parts of air and fuel are mixed together then ignited by a spark plug. \n\nA Diesel runs on the Pressure Theory in the sense that it requires no spark plug because simply it ignites the fuel by pressure.
269664
One of the basic principles of physics (Newton's Third Law) is that for every action (force) there is an opposite and equal reaction (force). The principle of a rocket motor may be understood by considering the example of a closed container filled with a compressed gas. Within this container the gas exerts equal pressure on every point of its walls. If a hole is punched in the bottom of the container, however, the gas at the bottom escapes and the pressure against the top of the container is no longer equalized. The internal gas pressure then pushes the container upwards in reaction to the jet of air escaping downwards. The amount of thrust developed by a rocket motor depends mainly on two factors, the velocity with which the burning gases leave the combustion chamber, and the mass of the burning gases.\n\nThis website for answer confirmation and more info --> http://uk.encarta.msn.com/encyclopedia_7...\n\nGod is spelled B-I-G B-A-N-G\nPBrax@netscape.com
834512
Torque is not the right question to ask in this problem!\nFirst define the generator output in terms of watts.\nAssume an efficiency of 0.8 for the generator and define the Input of the generator (In = Out / 0.8).\nThis is the output of your motor (assuming some diesel/petrol).\nTorque is expressed as N/m (force x radius) and is part of the electric generator specs.  See there to get the equivalence.\nUsually, the motor power is also 0.8 efficient, so the motor power should be W / (0.8*0.8) and that will give you the right ratio.
42416
Certain automobile engines use superchargers (fans or compressors driven by turbines driven by exhaust gases) to slightly compress intake air and mix it with fuel before delivery into the cylinders of an internal combustion engine.  There should be a practical limit on how much compression can take place outside the cylinder.  For example, if you compress air to half its volume and therefore twice atmospheric pressure the 23% oxygen present is concentrated and behaves as though it were about 46%.  Ignition may occur spontaneously due to high oxygen concentration and compression heat which is exactly what happens within the cylinders of a diesel engine (which does not require spark plugs).  Diesel engines use much higher compression ratios than engines requiring spark plugs.  Hope that helps.
668722
If the graph of Volume vs Pressure is a diagonal line with a positive slope, you should be able to conclude that the graph of Pressure vs Volume is also a diagonal line with a positive slope!\n\nSince we know that the gas has expanded, the work done by the gas is positive. Hence, W= corresponding area under Pressure vs Volume graph. If you make a sketch of the graph and indicate the intial and final pressures and volumes of the gas, finding W should not be too much of a problem!
58808
In order for gasoline to produce power in an engine, it must burn under pressure. What happens is the fuel mixture enters a cylinder then is compressed by a piston to place the fuel under pressure. Once under pressure, the fuel is ignited to burn (explode). This drives the piston back down and the up/down motion of the piston moving is captured to use as power to drive a machine. This process happens over and over again very quickly within an engine.\n\nFour stroke engines work like this:\n1. The fuel mixture enters the cylinder while piston is going down \n2. The mixture is compressed while piston is going up\n3. Fuel is ignited (combustion) forcing piston down (this is the powerstroke)\n4. The spent gas/smoke is pushed out by piston going up\n\n\nTwo stroke engines take a short cut:\n1. The fuel mixture enters the cylinder while piston is being forced down from combustion (powerstroke)\n2. The spent gas/smoke is pushed out by piston going up\n\nSince the two stroke engine combines the intake and exhaust   steps they aren't as efficient. This is because there is still some smoke left in the cylinder during combustion, and some spent fuel being forced out with the smoke.\nThe four stroke engine purges the smoke before taking in new fuel.
206913
petrol or gas engine is internal combustion engine that uses ignition spark to ingnite the fuel air mixture. a diesel engine compresses the fuel air to ignite the mixture. petrol.....spark plugs & diesel....no spark plugs
236163
Okay... If ur serious then I'm game!!  The piston is attached to the piston rod.  When the rod is pulled down by the crackshaft, kinda like bicycle pedals.. the piston draws air into the cylinder.  Then the crankshaft pushes the rod and piston up causing compression.  Then the spark plug ignites and blasts the piston and rod back down creating power.  Then the crankshaft pushes the rod and piston back up expelling the waste.  The piston is the 'plunger' of the system, kina like the black rubber plunger in a hypodermic needle.
551723
Just jam yer foot on the brake, then stomp the gas.  The engine will overpower the brake on the driven wheel.  \n\nYou are already screwing up your car, why not burn up the brakes too?
918434
One of the basic principles of physics (Newton's Third Law) is that for every action (force) there is an opposite and equal reaction (force). The principle of a rocket motor may be understood by considering the example of a closed container filled with a compressed gas. Within this container the gas exerts equal pressure on every point of its walls. If a hole is punched in the bottom of the container, however, the gas at the bottom escapes and the pressure against the top of the container is no longer equalized. The internal gas pressure then pushes the container upwards in reaction to the jet of air escaping downwards. The amount of thrust developed by a rocket motor depends mainly on two factors, the velocity with which the burning gases leave the combustion chamber, and the mass of the burning gases.
424514
The key is internal combustion.  If it has a fire in it, like a car engine or a jet engine, it is just that: an engine.  If its source of power is external, like an electric or hydraulic or compressed air motor, it is a motor.  That's the technical answer.  In practice, ignorance (as in lack of knowledge) causes many people to call engines motors.
1063841
W = PV = RTn, where P = pressure, V = volume, R = gas constant = 8.31 J/mol.K, T = temperature, n = moles of gas involved.\n\n1) Change in P = 4 x 10^5 Pa, then:\n\nChange in W = 4 x 10^5 Pa x 0.250 m^3 = 10^5 Pa.m^3 = 1 x 10^5 Joules.\n\n2) Change in V = 17.00 x 10^(-2), then:\n\nChange in W = 6 x 10^5 Pa x 17.00 x 10^(-2) m^3 = 102.0 x 10^3 Pa.m^3 = 1 x 10^5 Joules (note: there is only one significant number in result)
288771
Gasoline is ignited by the spark plug, which causes a small explosion in the motor. The explosion causes pressure, which moves the piston, which moves the crank, etc.