I am trying to find out the average temperature drop per foot underground below the freeze line?
912336
it heats up if  you go down for a long way,\nwith water it sinks to 4 degrees then if it gets colder it rises ,dont ask me why ,it is just that way.\nWater does not always follow the rule \n\nground temperature is the coldest at the surface ,in cold weather,\nthan below it is constant for a long way \nafter a few miles it will heat up.
62689
specific heat of steam is 2.02 J/g*K\n\nU steam= 215000J - 75.0g*2.02J/g*K(25K)= 211213J\n\nU liquified = 211213 - 40,700J/mol*mol/18g*75g = 41629J\n\nU water @ 0 C = 41629J - (4.18J/g*K)*75g*100K = 10279J\n\nU freezing = 10279J - 6000J/mol * mol/18g * 75g = -14721\n\nso you have some water and some ice, or liquid and solid phases.
991327
All depends where you are. For instance, way up north or on the antarctic where you have permafrost (frozen ground all year round) the temperature is going to be below zero up to 3 below ground, though, probably at 3 m you're looking at the maximum depth.. I'm not exactly sure about that, but if you can find mamoth you can dig it up and eat it as the meat is supposed to be fresh.\nHowever, at this depth the average temp is going to be around 15 deg C higher than the ambient ground level temp. \nIn hot places, the reverse is true and temperatures around 3 m below ground level are going to be around 15deg Cooler. \nThe main factor working here is the specific heat of dirt.. Not easy to work out exactly but has a general average which works.\nSeasonal changes do vary but if we go back to the permafrost situation we can see that the ground is frozen constantly to this depth, even though on the surface we may get a bit of thaw and things get damp and sticky.\nThe same is true for warmer places.. Ground temperatures as with sea temperatures at depth, do not change that much from season to season, and with the ocean we can talk about from decade to decade.
807771
go to the national weather service web site in the source part of my reply and go to montana and research this information.  you should have no problem finding this info, but you may have to look for a while
722101
Surface Temperature = 5500ºC\n\nCore Temperature = about 15,000,000ºC
812469
I'll give you some data and you can work out the details.  Total mass of the atmosphere, 5.136E18 kg.  Assumed average temperature of the atmosphere, 15 C. Enthalpy of vaporization of water at 15 C, 44.4 kilojoules per mole (by interpolation).  That should be enough data to do the trick -- except that I have no idea how much electricity Ottawa uses.  Call the power company and ask..\n\nPostscript: I tried to reply to your private note, but you have to do an address verification protocol with Yahoo before it will accept e-mails posted through your avatar.\n\nPost-postcript (11/21):  Yahoo is still claiming that your e-mail address is unconfirmed.  A pox on them!
519157
Freezing point depression constant for water: \n1.86 degrees C/m\ndepression = (1.86 degrees C/m)(.81 m)= 1.5 degrees C to correct significant figures.  \n0 degrees C is the normal freezing point.  \n0-1.5= -1.5 degrees C, the new freezing point.
196969
its 0 degrees c\nand 32 degree F\n\nBut this is assuming it normal tap water without to much sediment like rust.  I don't know what temp sea water freezes at.
1031939
temperature decreases with increase in altitude
771897
This is a direct quote (copy and paste):\n"Mean annual temperatures range from 64° F in the extreme southeast to 40° F or lower in high mountains and valleys of the north; elevation is a greater factor in determining the temperature of any specific locality than its latitude.  This is shown by only a 3° F difference in mean temperature between stations at similar elevations, one in the extreme northeast and the other in the extreme southwest; however, at two stations only 15 miles apart, but differing in elevation by 4,700 feet, the mean annual temperature are 61° and 45° F – a difference of 16° F or a little more than 3° decrease in temperature for each 1,000-foot increase in elevation."
291269
Cold water has more dissolved gases in it than hot water.  Any dissolved solutes cause the freezing point of water to be lower than pure water with nothing dissolved in it.\n\nThis means if your power goes out in the wintertime and it is about 32 degrees F outside, the water in your hot water pipes is more likely to freeze than the water in your cold water pipes.  This is because the freezing point of the water in your hot water pipes is higher than the freezing point of the water in your cold water pipes.\n\nSpeed isn't being considered here.  The cooling process is assumed to be slow so that the pipes are in thermal equilibrium with surroundings.\n\nAlso check out this link.  It is from the Alaska Science Forum.  They can explain the water pipes problem more correctly than me and they have more personal experience with the phenomenon.\nhttp://www.gi.alaska.edu/ScienceForum/ASF4/440.html
40654
Too many factors, not enough info. First, you have to know which way is up. Then you have to know how deep the snow is.\n\nRoughly somewhere between 4 and 4 googlizillion.
1120766
close to absolute zero or -273.15 deg C\nst\nIn 1994 the NIST achieved a record cold temperature of 700 nK (billionths of a kelvin).  In 2003, researchers at MIT established a new record of 0.5 nK.
975304
Your wording of the question is going to throw many for a loop. I had to scratch my head for a second to figure out what you wanted.\n Everybody's cold tolerance is different and every dive is different as well. For example, mid summer diving in Tobermory Ontario on the Niagara II, outside the wreck a 5mm would be fine. Inside you need a 7mm or turn blue. That applies everywhere in the world. You never know about thermoclines, currents etc.\n I'd be asking at a dive shop that is local to the area you want to dive. They know the average water temps for that area for the time of year you're thinking of diving.\n Sorry, but the way the question stands, you really can't expect an accurate answer other than 3mm to 7mm two piece with hood.
411850
this site has the last 30 yrs average temps....\nhttp://www.ncdc.noaa.gov/oa/climate/online/ccd/meantemp.html\n\nhope that helps...
934498
This is a three step problem.  Since you're losing heat temp is going down.  First calculate the amount of heat needed to go from 25.0 C to 0.00 C.\n\nq1 =  1 g X 4.18 J/gC X -25 = -104.5 J\n\nNow you have water at 0 C which needs to freeze.  You need to remove the heat of fusion to make ice.  deltaHf is -335.5 J/g.\n\nSo q = m X deltaHf = 1.0 g X 335.5 J/g = -335.5 J.\n\nNow we've used up 440 J so far, and the remaining 24 J will lower the temperature of our 1.0 gram of ice.\n\nThe heat capacity of ice is 2.1 J/gC and we'll need to solve for delta T.\n\n-24 J = 1.0 g X 2.1 J/gC X delta T\n\ndelta T = -24 J/ 2.1 JC= -11.4 C.\n\nSo the final state and temperature would be ice at - 11.4 C.\n\nSo the answer of -12 C should be correct with more care paid to significant figures and proper rounding.
752365
Not very well. \n\nIf the ambient temperatures will be in the 30 degree range and below then a heat pump does best with a heat sink such as a underground well to provide heat at high enough level to be economic.