im having trouble with this math problem?
931130
-4(x+3)>=20    &     x-5< -2\n-4x-12  >= 20    &     x < 5-2\n-4x  >=  20+12   &    x < 3\n-4x >=  32      &    x < 3\nx >= -8   &  x< 3\n-8  <=  x  <  3\n(x lies between -8 and 3)
1020883
i am sure you can find a math tutor that will be happy to help you when you explain what the problem is.\n\nso what IS the problem, anyway?
137681
Ok...\nI see what you are doing...\nYou merely substitute the number in for x...\nso the problem becomes 6-2*(-1)\n6+2\n8
448711
51,336\n\nNext time just type your math problem into at google search and it will do the math for you!\n\nLink below.
662213
Anyone can give you the answer, but try here next time you need help with conversion or any other kind of math: \n\n\nhttp://www.gateways2learning.com/BasicMath/BasicMath.htm\n\nGood luck..................
156773
when x=3\na) 9\nb) 38\nc) 23\nd) 9\ne) 4 and 2/3\n\nwhen x=2\na) 7\nb) 30\nc) 17\nd) 7\ne) 6\n\nwhen x=1\na) 5\nb) 22\nc) 11\nd) 5\ne) 10\n\nwhen x=0\n\na) 3\nb) 14\nc) 5\nd) 3\ne) ERROR, can not divide by zero
780025
x ≤ 5\n\n-- - - - - - -s-
813994
the first one is (x+10)(x+8)\nand the second one is your second answer
974937
please complete the equation
841476
When you retry the problem remember to move only yout z^-2 up don't move the 4 that is a constant in the denominator. \n\nyou should get this . (12x^5z^3/30x^7y^7) * (15x^2z^10/4y^3)\n\nremember to simplify as best you can prior to multiplying.\n\ntry from here and let me know what you get.
859744
(x + 4y)(x - 4y)\nI answered 2 of your questions. Do the rest of the questions yourself.
908965
the answer is pi 3.14. use the pythagoran therom with x= pi(r2) then compensate for the remainder and it'll work itself out. If that doesn't work, try FOIL. first, outside, inside, last.
55565
Your computer has a calculator built in.  Failing that, try long division.  You're gonna have to learn how to do it anyway.\n\nSheesh.
851464
that is a really simple question, so if you have a calculator you should be able to get it, otherwise, it is your homework and I refuse to give you an answer to your homework. I would actually HELP you to get the answer if you asked for HELP doing it.\n\n-EA
893957
well darling ;\nimagine this like that\n\ny^2 + ( a+b)y + ab \nyou need to find " a+b " & " ab" \nin our function \na+b = 16 & ab = 64 \n( y + a)( y + b) \n( y + 8 ) ( y + 8)\n{ ' 8 + 8 = 16 '   &  ' 8 * 8 = 64 ' }\nso\n( y + 8)^2\n\nGood Luck sweetheart.
800717
(1) First one is copied wrongly by you                                            (2) Where is the equal to sign?                                                        (3)This equn. also cannot be solved                                              (4)-p/16+5=9  Multiplying all the terms by 16 ,we get -p+80=144   =>-p=144-80=66 Therefore p=66 YOU SHOULD BE MORE CAREFUL BEFORE SENDING YOUR PROBLEMS TO YAHOO ANSWERS.HOWEVER,YOU MAY SEND THE CORRECTED VERSION OF THE PROBLEMS TO ME IMMEDIATELY THROUGH YAHOO ANSWERS.
859713
You should go to www.AAAMath.com  good luck