Rationalize the denominator?
914649
multiply by top and bottom by (sqrt(5) + sqrt(14))\n\nbottom = (5 - 14) = -9
912338
Neither, it is undefined, i.e. it has none of the properties of all rational or whole numbers.\n\nI might be wrong, but I think this is one of those trick questions that are so common in math courses.
924404
This one is a candidate for l'Hopital's rule.  Take the derivative of both numerator and denominator, and the resulting fraction (if not of the form 0/0) will give the limit.  If you get 0/0, do it again.
520679
When dividing rational expressions you flip the second one and multiply\n (2x^2 + 5x)/(9x^2 – 16) ÷ (2x^2-7x + 6)/(3x^2 -x -4)\n= (2x^2 + 5x)/(9x^2 – 16)*(3x^2 -x -4)/(2x^2-7x + 6)\nFactor each one, then you can cancel anything on the top with anything that is on the bottom.
866142
The numerator must be a factor of the constant term (12) and the denominator must be a factor of the leading coefficient (6)\n\nSo (many of these will reduce to one also in the list):\nPlus or minus\n12/1, 6/1, 4/1, 3/1, 2/1, 1/1\n12/2, 6/2, 4/2, 3/2, 2/2, 1/2\n12/3, 6/3, 4/3, 3/3, 2/3, 1/3\n12/6, 6/6, 4/6, 3/6, 2/6, 1/6
167162
I do agree with Anniemc46.\nIf the denominator is 1+(tanhx)^2 then it is easy to do.\n\nI have done and uploaded to my web site.\nPlease check the url I provided in the sourse.\n\nThanking U,\nThuvalpakshi.
703752
simply subtract 7 from both sides. This leave you with\n\nx<_3
316383
Reduce it untill the # on the bottom is prime.\n (divide the top AND bottom by 2 untill you get a decimal.)
57974
Not neccessarily. For instance, the square root of two (which is irrational) multiplied by the square root of two is two, which is very rational.\n\nGood Luck!\n\nP.S. Great Screenname. I love the phantom.
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
787164
is there a specific area that you need help with in rational numbers?  I guess you can use a site that i know of.  Here: \nwww.algebra-online.com\n^ after that put a slash and write: rational-numbers-1.htm\nthat might help you (:
818643
You asked about the numerator before, didnt you get an answer?\nWith synthetic substitution, you should find that the roots of the numerator are -1, -1, -2, and 3.\nThis gives (x+1)(x+1)(x+2)(x-3)  see *.\n\nAre you sure you typed the denominator correctly?\nYou typed: \nx^6 - 6x^5 + 15x^4 - 30x^3 + 15x^2 - 6x + 1\n(by the way, you need to insert spaces into long polynomials like this one or Yahoo does not display them after 30 spaces.  You can place the mouse cursor over them and see the complete polynomial, but many people dont know that, including the previous answerer.)\nThis is not factorable (over the rational numbers)\n\nHowever, if one digit is changed, namely if -30x^3 was written \n -20x^3, then the denominator becomes a very common one (and one that you may notice just by looking at it if you stay at this factoring stuff for a long time):\nnamely (x-1)^6 !!\n\n\n*\n1st root (-1):\n\n-1 || ..1... 1 ... -7 .. -13 ... -6\n...............-1 .... 0 ..... 7 ..... 6\n————————————\n..........1....0.....-7.....-6... || 0\n\nso (x+1) is a root\n\n2nd root (-1):\n\n-1 || ...1....0.....-7.....-6\n................-1 .... 1 .... 6\n——————————\n..........1...-1 ... -6 .. || 0\n\nso (x+1) is a root again.\n\nx^2 - x - 6 remains\n= (x-3)(x+2)\n\nInteresting correlative problem:\nhttp://answers.yahoo.com/question/index;_ylt=Aqz3W3s3NPcz.j__CQYxK0bsy6IX?qid=20061127003230AA2oHuA
291495
Rational, because it can be expressed as the quotient of 2 integers:\n-2 5/8 = -21/8\n\n^_^
696212
find the common denominator\nmultipy the top and bottom of the fraction so the denominators are equal and then add the numerator
113980
Use a calculator - numerator divided by denominator will give you the answer.
762985
(b-4)/(b-4)(b+4) simplifies to 1/(b+4)\nrestrict denominator...bcannot equal 4 or -4
896031
Why not?  If you divide top and bottom of this expression by x^7 you get\n(3 + 4/(x^5))/(9 - 1/(x^4) + 2/(x^7))\n\nEvery term except the 3 and the 9 now has a power of x as denominator, and therefore approaches 0 as x goes to infinity,\ntherefore it approaches 3/9.