bond orders which ______ integers indicate molecules with resonance structures. (are/ are not)?
925332
Are not integers. Example: C-C bonds in benzene are bond order 1.5
750269
The shape of the molecule depends on how many electrons and bonds you have in the outer shell of the central atom.\nFor NH3, N is the central atom. It has 3 covalent bonds and a lone pair. Thus the repulsion of the lone pair electrons and the bond electrons will force them to arrange at the corners of a tetrahedral. The molecule will look as a trigonal pyramid (since the lone pair is not "visible" in the structure.\n\nFor BH3, B is the central atom and has no lone pair apart from the three bonds. So the repulsion of the bond electrons will force them to be in a planar trigonal arrangement.
749219
a) Ag2S\nb) SnCl4\nc) Na3N\nd) SrI2\n\nDo us a favor and pay attention during class. That way you'd know how to do these.
908225
Go to this site and it will show you structures of a whole bunch of molecules with Carbon and without, by formula and by name, kind of mess around with it for a while. http://www.chem.purdue.edu/gchelp/molecules/index.html
895488
3. is correct.\n1. is not correct since formaldehyde has 3 sigma and one pi bond\n2. is not correct since H cannot form a pi bond\n4. is not correct since only one pi bond forms
139994
Is its structure a ring with double bonds?
479762
I assume you are talking about the formula and not the structure.\n\nThe molecular formula is C6H5NO5P\n\nStructure (if in case you want it too) is as follows:\n\nDraw a benzene ring (phenyl group) minus 1 hydrogen (C6H5). To the Carbon without the hydrogen, attach a Hydroxyl group (-OH). On the other Carbon positions, whether it is the ortho positions, meta positions, or para position, erase the hydrogen and attach a nitrate group (-NO2). On the Oxygen with the double bond to Nitrogen on the Nitrate group, erase one of the bonds and attach this bond to the phosphate group (-PO3).\n\nI'm not sure if you are talking about a nitro-phospho bond or a hydroxy-phosphate bond, but the difference is only 1 hydrogen.
337603
Here is the answer.. Just remember periodi table...\nElements on left most side are electro positive and elements on right most are electro negative. (The last row is nobel gases..so leave it)\nNow Cl- belongs to right most side... its more electro-ve\nRb, Ca are on left side.... they are electro positive(They will give  electron with out much force)\nSi, S are in middle-- their properties are in between...\n\nThats it!
837515
You need to look at the central atom and determine the number of lone pairs and bonding pairs of electrons (multiple bonds in this case will not count, as the orbitals used in those bonds will be orthogonal to the bonding axis and thus won't be hybridized).  2 is sp, 3 is sp2, 4 is sp3, 5 is sp3d, 6 is sp3d2.
644051
See if this article has a diagram\n\nhttp://jchemed.chem.wisc.edu/Journal/Issues/1999/Apr/abs542.html
130061
Yes, CN- has a triple bond, and N is slightly more EN than C, Remember that electronegativity increases up and to the left in the periodic table!
30363
Yeah, benzene is a resonance structure, which means that there are bonds that are shared, but that's beside the point. Benzene looks like a hexagonal ring of six carbons with a hydrogen bonded to each carbons.  \nhttp://en.wikipedia.org/wiki/Benzene (scroll down a fourth of the way)\nThe sigma bond is the first bond formed between two atoms; the other ones after the first one are called pi bonds.  If you check out the picture on the above link and count the number of first bonds on the diagram, you'll get 12.  I don't know where 18 is coming from.  \nThere are also 3 secondary bonds, or pi bonds.
874456
If they are linear, then it's quite easy. \n\n1. Number the carbon atoms, trying to assign the lower number possible to double and triple bonds.\n2. Check for double or triple bonds an their numbers.\n3. Write a preffix that expresses the number of carbon atoms:\n\nif its 1 , "meth"\nif its 2 , "eth"\nif its 3 , "prop"\nif its 4 , "but"\nif its 5 , "pent"\nif its 6 , "hex" and now you can carry on.\n\n4. Write the number of the double or triple bonds present.\n5. Write a suffix for the type of compund (no double bonds: "ane", double bonds, "ene", triple bonds "yne")\n\nExamples are:\n\nCH3-CH2-CH=CH2     ____   1-butene (or butene)\n\nCH3-CH2-C≡C-CH3     ____    2- butyne\n\nCH3-CH2-CH2-CH=C=CH-C≡CH   ____    octa-3,4-diene-1-yne\n\nIt can be weird for some cases. So practice.
450187
Its a chemistry term to describe resonant bonds between atoms in molecules
5016
O\n                       ^\n                       |\n                      xx\n                  H-O-Br:->O\n                      xx\n                       |\n                       V\n                       O\n\nPlace the xx above and below Br. Br donates electron pairs to three oxygen atoms. There is also one Br-O-H bond in the molecule.
92358
Just count the (sigma) bonds and the lone electron pairs and memorize the cooresponding geometric shapes.  Sorry, but it's the only way.
200262
mono = 1\ndi = 2\ntri = 3\ntetra = 4\npent = 5\nhex = 6\nhept = 7\noct = 8\nnon = 9\n\nnonmetals:\nif there is no prefix for the first element, it is assumes to be one.\nTHe ening of the anion (the second one listed) is changed to -ide.\n\ncarbon - 1 \noxygen - 2\nCO2  <---The number is a subscript, but you cant do that on here\n\nPhosphorous - 1\nIodine - 3\nPI3\n\nHydrogen - 2\nOxygen - 1  (it should be monoxide)\nH2O\n\nHope that helps you.  Don't feel bad; you can't know what you haven't learned.