solve? help me please??
914195
5/4x + 1/x = 3/4\n\nFirst, multiply everything by 4 to get rid of the denominators.\nSo now you have:\n\n5/x + 4/x = 3\nnow multiply everything by x to get:\n5 + 4 = 3x\n \n9 = 3x \n\ndivide each side by 3\nx = 3\n\nnow check your answer by replacing x with 3
469080
1.(b+1)(b+6)=0           2.(m+3)(m+7)=0\n   (b+1)=) or (b+6)=0       (m+3) =0 or (M+7)=0\n    b=-1 or b=-6             m=-3   or  m=-7\n\n3.(n+1)(n-4)=0           4.(a-2)(a+4)=0\n   (n+1)=0 or (n-4)=0       a=2 or a =-4\n    n=-1  or n=4\n\n5.(a-2)(a+5)=0            6.(b-1)(b+8)=0\n   a=2  or a=-5              b=1 or b=-8\n\n7. (y-3)(y+9)=27          8. (m-1)(m-5)=0\n   y=3 or y=-9                m=1 or m=5\n\nnext time I'll give answer for the first three,the rest try it yourself or else you won't learn!!!!\n\nOKAY?
624146
check brilliant tutorials homepage...they have posted the solutions...by the way was there a set A  as well?? anyways good luck!
990365
No solutions my ascii, haven't these people ever heard of complex numbers?\n\nAs has been previously mentioned, for the first part of the equation you can set U=e^x and solve for U. Thus:\nU^2+6U+8=0\n(U+2)(U+4)=0\nU=-2 or -4\ne^x=-2 or -4\n\nNow, here's where we demonstrate that this equation has solutions. Remember Euler's identity: e^(iπ)+1=0. Thus, e^(iπ)=-1. Thus:\ne^x=-2\n(-1)e^x=2\ne^(iπ)e^x=2\ne^(x+iπ)=2\nx+iπ=ln 2\nx=ln 2+πi\n\nAnd from e^x=-4, we get x=ln 4+πi. So x=ln 2+πi or  x=ln 4+πi. And that's your solution.\n\nActually, for the sake of completeness, since e^(2πi)=1, x could also be any of these solutions plus an integral multiple of 2πi. Thus, x=ln 2 + (2K+1)πi or x=ln 4 + (2K+1)πi, where K is an arbitrary integer.
730660
This equation has a solution when x = 0 or y = 0\n\n- - - - - - - - - - - -\n\nx = 0\n\n5x - 28 = 12 + 3y\n\n5(0) - 28 = 12 + 3y\n\n0 - 28 = 12 + 3y\n\n- 28 = 12 + 3y\n\n- 28 - 12 + 12 + 3y - 12\n\n- 30 = 3y\n\n- 30/3 = 3y/3\n\n- 10 = y\n\nThe answer is y = - 10\n\n- - - - - - - - - - - - - - - -\n\ny = 0\n\n5x - 28 = 12 + 3y\n\n5x - 28 = 12 + 3(0)\n\n5x - 28 = 12 + 0\n\n5x - 28 + 28 = 12 + 28\n\n5x = 30\n\n5x/5 = 30/5\n\nx = 6\n\nThe answer is x = 6\n\n- - - - - - - - - \n\nx = 6\n\ny = - 10\n\n- - - - - - - - - -\n\nThe solution set is { 6, - 10 }\n\n- - - - - - - - - - - - -s-
227387
D = 36 - (4)*(-2)*(-3)= 36- 24 = 12\nTwo real solutions.
897429
This is the third time that this question has been asked!?!?!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nThis is as far as I got:\n(2B+1)^(D-E) - F^(3G+G2) = (10J)/A\n\nBut someone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
895454
There is no ordered pair {a,b} which solves both equations\n\nif a+b = a-b , then 2b = 0 or b = 0 and a is anything\n\nBut the second equation is not defined for b=0, no matter what a is (specifically, a/b is not defined for b=0)
538044
hmmm...very tough one!\n\nill sovle by the formula!\n       _________\n-b +- V (b^2)-4ab\n------------------\n       2a\n       _________\n-10 +-V 100+512\n------------------\n       2\n\n       _________\n-10 +-V 612\n------------------\n       2\n\n-10 +- 24.7\n------------\n     2\n\n14.7/2\n\n34.7/2\n\n(7.35, 17.35)
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP
296877
It has a solution, indeed. It actually has two solutions, -3 and 7. To find it out, set each pair of nomials, (e.g. (x + 3)) to zero. So it would be (x+3)=0. Then solve for x. Do the same for the other nomial, and there you have it.
542569
I'd try goin to the websites support you know that ask an solve thing on the website. you gonna let me hear it after u get it recorded ?lol
51473
x+3  This is the right answer, because there is no =s sign in the problem.\n\n3x+9-2x-6\nx+3
232773
This question has multiple solutions:\nWe have 2 equations in three unknowns and some constraints:\n5A + 3B + C/3 = 100 -------------- (1)\nA  +  B + C   =100 -----------------(2)\n\nConstraints:\n------------\nA, B and C are integers\nA, B and C >= 0\n\nso we can express A and B as function of C\n\nA=(4/3)C -100\nB=200-(7/3)C\n\nsince A and B intergrs \nthen\nC must be multiple of 3\n\nsince A>=0\nthen\nC>=75\n\nsince B>=0\nthen\nC<85\n\nso\n\n    85>C>=75\n\nso we have C either 75, 78, 81 and 84\n\nso we have A either 0, 4  , 8, and 12\n\nso we have B either 25,18 , 11 and 4\n\nso the four solutions for A B and C\nare\n0 25 75\n4 18 78\n8 11 81\n12 4 84\n\nrespectivily\n\nBest Regards
695947
D\n\nEither is sufficient.  \n1) will lead to 2 equations,2 unknowns which yield a unique solution for x and y:  x=y+1, x+y=77, therefore x=39, y=38.  xy=1482 \n\n2) If the sum is 77 and x and y have the same tens digit, then there are two solutions for {x,y}, namely {38,39} and {39,38}, however the product xy is the same. xy=1482
268888
I think I can do this one...I'll get right back to you when I figure it out... *grabs a pen and paper...and also tries to figure out why people are answering, saying simply that they can't or won't answer your question*\n\nEDIT...k, here's what I got...not sure if I understood what your question was asking, so I may be mistaken...\n\nm=h(x)-2x\nk=(2-3h(x))/6x
840437
Well, I can see that one possible solution is r = 0, and my calculator says the other answer is r = 0.0809394063, so hopefully that helps...