what would 3(2s-3) = - (7 - s) be?
929787
6s-9= -7+s\n6s=s+9-7\n6s-s=2\n5s=2\ns=2/5\n2/5
321226
It's false.\n\nYou have to use order of operations. You do the stuff in the parenthesis first:\n\n(3-3) - 3 = 3- (3-3)\n(0)-3=3-(0)\n\nSo you get:\n-3=3\n\nSince -3 isn't equal to 3, it's not true.
765445
(1) sqrt(7a)Xsqrt3=sqrt(7aX3)=sqrt(21a)\n(2)sqrt(5a)Xsqrt(15a)\n=sqrt(5aX15a)\n=sqrt(75a^2)\n=sqrt(25X3Xa^2)\n=5a)sqrt)3\n(3)sqrt3(sqrt5-sqrt3)\n=sqrt(15)-3\n(4)(sqrt2+3)(sqrt2-7)\n=2+3(sqrt)2-7(sqrt)2-21\n=-19-4(sqrt)2
787381
m = (7-4)/(6-8) = -3/2
773396
x+y-z=2---(1)\n2x-y+z=7-(2)\n-x-y+2z=3---(3)\nadding (1) and (2)\n3x=9\nx=3\nadding 1 and 3\nz=5\nsub x=3,z=5 in 1\n3+y-5=2\ny-2=2\ny=4\nthe solution set{3,4,5}\n\n2.x+2y-z=-3\n2x+y+z=6\nadding\n3x+3y=3\n=>x+y=1\neqn. 1*3\n=3x+6y-3z=-9\n-2x+2y+3z=3\nadding\nx+8y=-6\nx+y=1\nsubtracting 7y=-7\ny=-1\nsub in x+y=1,x=2\nsub in x+2y-z=-3\nz=3\nso solution set {2,-1,3}
286213
a) 1/(3x+3)=-7\n1=-7(3x+3)\n1=-21x-21\n1+21=-21x\n22=-21x\nx= -(22/21)\nx= -1.0476\n\nb)x-3/-1=x-2\nx-3=-1(x-2)\nx-3=-x+2\nx+x=3+2\n2x=5\nx=2.5
609144
7(x-3)=3(x+1/3)\n7x-21=3x+1\n7x-3x=1+21\n4x=22\nx=22/4=5(1/2)
431729
6(8s-3)=48s-18\n\n\nactually, the correct answer is all real numbers. any number you substitute for "s" will work
973910
17.\n5x+7y=-1  (1)\n-2y+3z=9  (2)\n7x-z=27    (3)\n(3)*3\n21x-3z=81\n-2y+3z=9\nadding\n21x-2y=90 *7\n147x-14y=630\n10x+14y=-2\n157x=628\nx=4\nsub in (1)\ny=-3\nsubin (2)\nz=1\n\n\n18.\nr-s+3t=-8    (1)     \n2s-t=15       (2)\n3r+2t=-7      (3)\n\n(2)*2  4s-2t=30\n          3r+2t=-7\nadding\n4s+3r=23\n(2)*3  6s-3t=45\n       r-s-3t=-8\nadding\n5s+r=37\n4s+3r=23\n15s+3r=111\nsubtracting\n11s=88\ns=8\nsub in (2)\n16-t=15\nt=1\nsub in (3)\n3r+2=-7\nr=-3
153400
i believe it would be '-9'\nn=5 \n-3-(5-1)(1.5)\n-3-(4*1.5)\n-3-6\n-9
12533
r/3 + 7 = -4\nr/3 = -11\nr = -33
490567
=-1\n2(0)+3(0)-1=f(x)\n2(0)=0\n3(0)=0\nminus 1\nequals negative 1 or -1
554172
Um...\n\n2(-X) + 3(-X) + X + 8\n\n-2X - 3X + X + 8\n\n-5X + X + 8\n\n-4X + 8\n\n8 - 4X
8794
5t+1>3t-13\n-> 5t-3t>-13-1\n-> 2t>-14\n-> t>-14/2\n-> t>-7\nKeep Asking
763039
x(sqrt)3+4=7+(sqrt)3\n=>x(sqrt)3-(sqrt)3=7-4=3\n(sqrt)3} (x-1)=3\n3(x-1)=3(sqrt)3    [multiplying both sides by (sqrt)3]\nx-1=(sqrt)3      [cancelling or dividing both sides by 3]\nx=1+(sqrt)3  ans
549518
How about...\n\n( 3 + (3/7) ) * 7 = 24\n\nThat would be like (21/7 + 3/7)... which is (24/7)... times 7 = 24.
701956
15(s-3)=12s-43\nfirst you distribute the 15 to the s and the 3 so you get 15s-45=12s-43\nThen you subtract 12s from both sides leaving you with 3s-45= -43\nthen you add 45 to both sides and you have 3s=2\nthen you divide both sides by 3 and your answer is 2/3.\n\nHope I helped!!