Physics question related to energy?
923574
It goes into thermal energy (heat) as the brakes heat up due to friction and perhaps to other, less significant sources of energy loss (e.g. sound of brakes squealing).\n\nNote: The car doesn't really gain energy, it just converts its gravitational potential energy (from being at the top of the hill) into kinetic energy (the energy associated with motion).
624995
Energy = mass x speed of light squared
140934
Energy = mass times the speed of light squared\n\nIt conveys that a very small amount of matter actually represents/can be turned into a very large amount of energy, as in nuclear power, or a nuclear explosion.
1010100
ok, so if we're assuming that it was a head on elastic collision, and all the energy was transferred then there are two possible situations: if the 25lb ball was sliding then the total energy transferred will be equal to the amount it had originally (since we assumed elastic collision) that is equal to 1/2mv^2...where mass would usually be measured using the metric system. \nif the ball was rolling then it has not only translational energy (1/2mv^2) but also rotational energy which is equal to 1/2Iw^2 where I = inertia of a ball...if it is a solid sphere the moment of inertia is equal to 2/5mr^2 (m = mass, r = radius) and w (omega) = rotational speed in radians per second...which is equal to velocity/radius. so the amount of energy transferred would be equal to 1/2Iw^2 + 1/2mv^2.
209055
Potential Energy: Energy due to position.\nKinetic Energy: Energy due to motion.\n\n======================================================\nAs the ball moves up it gains potential energy and loses kinetic energy. It the maximum height, it has all potential energy and no kinetic energy. As it moves down, it loses potental energy and gains kinetic energy. When it hits the floor it's velocity (ideally) remains the same in magnitude but reverses in direction. It starts moving up again.....\n\nWork is the process of conversion of energy from one for to the other. So, work is being done as the ball bounces up and down.
986389
Energy = force * distance\n= 100 N * 6 m = 600 J\n\nAnswer is d
502927
Energy equals mass times the speed of light squared
816057
again ... conservation of (mechanical only here) energy\n\npot energy = kin energy\n\nmgh = 1/2 m V^2\n\nso V = sqrt(2gh) -- see mass irrelevant\n\nV = sqrt(2*9.8*8.53) = 12.9 m/s\n\ng=9.8m/s^2 is the acceleration due to gravity\n\ng=10m/s^2 is not a bad approximation
1085576
F = d/dt(mv) [the time deravitive of the momentum] = dp/dt  where p is the momentum\n\nWork = Energy = F x distance\n\nPower = Energy/time\n\nPower = (F x distance)/time\n\nPower = [(dp/dt) x distance]/t\n\nremember dp/dt = d/dt(mv) = m dv/dt + v dm/dt
631645
Hmmmm......... could it be energy?????
1131325
Maybe this can help...all you have to do is a search in Yahoo or Google...\n\nhttp://www.think-energy.com/ThinkEnergy/11-14/activities/EnergyTrans.aspx\n\nTry searching for "energy" or "kinetic energy"
313762
youre holding a stone on a top of a hill (potential energy here) ---> you drop the stone off the hill (here kinetic energy) ---> the stone is on the ground (here again potential energy)
36280
Assuming it can't be II and III, I would say it's all of the above. The potential energy is converted into kinetic - the velocity increases and the height decreases. The KE + PE remains constant, because there is no work being done because there is no force here (besides gravity). However, the first depends on how you define mechanical energy - if it's kinetic energy, it's true. If not, I really don't know what it is.
298488
Energy Unit = Joule = 1 kg x m^2/s^2 = 1 N x m\n\nHow can work transfer into keinetic energy?\nThink in a pendulum in which these two are constantly tranfered into one another.\n\nWork = Force x Distance \n\nwork = 10N x 2m = 20 N x m\n\nKinetic energy = Mass x Velocity^2 / 2\n\nkinetic energy = 2kg x (4m/s)^2 / 2 = 16 N x m
822266
Conservation of energy:  KE=PE\n1/2*Mb*Vb^2= (Mb+Mw)*g*h\nVb^2=2*(Mb+Mw)*g*h/Mb\nVb^2=2*(0.01+2)*10*0.1/0.01\nVb^2=402\nVb=20.05 m/s
596819
Kinetic Energy = mass x velocity^2 divided by 2\n\nKE = 12 x 12^2 / 2
404136
Calculate the total energy of the system before and after and make an energy balance.\n\nFor example, lets say you have an inelastic collision between two cars of equal mass m:\n\nInitial State:\nCar 1 moves at v1 to the right\nCar 2 moves at v2 to the left\n\nAssume v1 > v2\nThey hit and stick together completely.  Use conservation of momentum to find the total resultant velocity:\n\np1 + p2 = ptotal (p is the momentum of car 1 and car 2 respectively)\n\nm*v1 - m*v2 = (m+m)*vf\n\nvf is the final velocity of the clump\nthe minus sign is because I am choosing the direction "right" as positive (momentum is a vector)\n\nvf = (v1-v2)/2\n\nNow do an energy balance:\n\nEbeforecollision = 1/2*m*(v1^2) + 1/2*m*(v2)^2\nEaftercollision = 1/2*(m+m)*(vf)^2 + Efrictionlosses\n\nEbefore = Eafter (this is conservation of energy, and it is true as long as you account for all forms of energy...it wont be true if you forget about the frictional losses in Eafter)\n\nNow solve for Efrictionlosses\n\nTo get the total fractional energy loss, take the ratio Efrictionlosses/Ebefore