x+7 square root of x - 18 = 0?
912557
u = SQRT(x)\nThis will make the equation\nu^2 + 7u - 18 = 0\nu = 2\nu = -9 does not give any x real\n\nu = 2 ===> 2 = SQRT(x) ===> x = 4
606423
Here's how to work it out:\n\n(Sorry, because I can't use special symbols, I'm using _/ for the square root symbol and <= for the less than or equal to symbol.)\n\n_/3x + 6 + 4 <= 7\n_/3x + 10 <= 7\n3x + 10 <= 7 x 7\n3x + 10 <= 49\n3x + 10 - 10 <= 49 - 10\n3x <= 39\n3x/3 <= 39/3\nx <= 13
84097
17.\n\ny+7=(8/3)(x-4)\n\ny=(8/3)x - (32/3) - 7\n\nr=(8/3)(-2) -(32/3) - (21/3)\n\nr=(-16-32-21)/3 = -23\n______________________________\n18. y-5 = 5(x-8)\n______________________________\n19. y-7 = 0(x--5) so y-7 = 0 so y=7\n______________________________\n20. y-2 = (1/2)(x-6)
779020
Just a number. Also, the answer is 3, not 37. You just have to substitute -1/3 where there is an x in the original.\n\nf(x) = 18x(squared) - 12x - 3\nf(-1/3) = 18 * (-1/3)^2 - 12 * ( -1/3) - 3\n                    18 * 1/9     + 4            - 3\n                             2 + 4 -3\n                                  3
753567
square both sides\nx+6+1=2x-11\n7+11=2x-\n18=x\n\nx=18
445500
(18)(-3)=(-11)r\n-54=(-11)r\n54/11=r
706596
You'd have to use the chain rule for the square root, then the quotient rule for what's inside.\n\nf ' (x) = (1/2) [(2x³ - 7) / (4x + 1)]^(-1/2) times the derivative of the radicand.\nFor that, the quotient rule gives:\n[6x²(4x + 1) - 4(2x³ - 7)] / (4x + 1)²\n\nThere's most likely some simplifying to be done, but that should get you on the right path.\n\nGood luck!
256504
because 56 is not an even root the best answer is=\n(n-squareroot of 56)(n+squareroot of 56). \nThe square root of 56 is 7.48331477355 if you need the exact number, but that's messy.
597652
The square root of 1 is 1.\nsqrt(6.6) = 2.569\nsqrt(15) = 3.873
790936
x≠０\ncuz if x=0, (x-7)/x^3 is meaningless
17048
= x^2 - 7x + 4x -28\n= x^2 - 3x - 28
621649
(3x-18)  = 7+4x+64\n-18-7-64 = 4x-3x\n-23-64   = x\nx = -89
927172
18 / x = 24 / 100\n18 / x = .24\n18 = .24x\n18/.24 = x\n75 = x
681319
-18=x-9\n+9   +9\n-9=x\n\n27=x-11\n+11   +11\nx=38\n\n15=x-16\n+16  +16\nx=31
801012
inverse square root of a number say"x" is\nx^[-(1/2)]
838099
Yes, you can factor it as follows:\nx² - 22x + 7x \n= (x - 4)(x - 18)
1164377
There are zeros at 2, -3/2 and -6, so\n\nf(x) = (x-2)*(x+3/2)*(x+6)\n\nf(x) = x^3 + 11/2*x^2 - 6*x -18