HELP! FORMULA OF COMPOUNDS!! ANY SMARt PERSON? (HARD ONES!)?
913568
Zn(NO2)2; Co(HSO3)3; HgF; Al2(CO3)3; Cs2C2O4; Ba(ClO)2; SnBr2; Mg(HSO3)2.
775000
2 MnO4-(aq ) + 5 H2C2O4(aq ) + 6 H3O+(aq ) --> 2Mn2+(aq ) + 10 CO2(aq ) + 14 H2O
363162
When you ask about the formula that is a pretty broad question.  The only formula I know is the balanced compound formula which is Ga2(SO4)3, direct combination formula which is 2Ga + 3S04 --> Ga2(SO4)3, or the decomposition formula which is, Ga2(SO4)3 --> 2Ga + 3S04.  If this isn't what you wanted I'm sorry, if you want you can email me and be more specific.
167270
I'll tell you where to find the answer - I won't do it for you...\n\nhttp://mathworld.wolfram.com/Tetrahedron6-Compound.html\n\nhttp://www-history.mcs.st-and.ac.uk/~john/geometry/Lectures/L10.html
859471
1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 9.630 g x (12 / 44) = 2.626 g\nhydrogen: 4.928 g x (2 / 18) = 0.548 g\noxygen: 4.055 - 2.626 - .548 = 0.881 g\n\n2) convert to moles.\ncarbon: 2.626 / 12 = 0.219 mol\nhydrogen: 0.548 / 1 = 0.548 mol\noxygen: 0.881 / 16 = 0.0551 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.219 / 0.0551 = 4\nhydrogen: 0.548  / 0.0551 = 10\noxygen: 0.0551 / 0.0551 = 1\n\nThe empirical formula of the substance is (C4H10O)n\nThe atomic masses add up to 74, which is also the molar mass of the compound. Therefore n=1 and we find C4H10O
727004
(NH4)2Cr2O7 -> Cr2O3 + 4*(H2O) + N2\n\n(NH4)2SO4 + 2*(NaOH) -> 2*(NH3) + 2*(H2O) + Na2SO4\n\nFe2(SO4)3 + 6*(NH3) + 6*(H2O) -> 2*(Fe(OH)3) + 3*((NH4)2SO4)
683249
Oh, come on, it doesn't get any easier than this!\n\nSnO2 + 2H2 --> Sn + 2H2O\n\nAbove is balanced. 1 Sn on both sides, 2 O on both sides and 4 H on both sides.\nYou need to work a little harder on these yourself.
813421
Na2CO3(aq) + MgCl2(aq) --> 2NaCl(aq) + MgCO3(aq)
796215
1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 9.270 g x (12 / 44) = 2.528 g\nhydrogen: 3.795 g x (2 / 18) = 0.422 g\noxygen: 3.797 - 2.528 - .422 = 0.850 g\n\n2) convert to moles.\ncarbon: 2.528 / 12 = 0.211 mol\nhydrogen: 0.422 / 1 = 0.422 mol\noxygen: 0.850 / 16 = 0.0531 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.211 / 0.0531 = 4\nhydrogen: 0.422  / 0.0531 = 8\noxygen: 0.0531 / 0.0531 = 1\n\nThe empirical formula of the substance is (C4H8O)n\nThe atomic masses add up to 72.1, which is also the molar mass of the compound. Therefore n=1 and we find C4H8O
799504
FeS + 2HBr --> FeBr2 + H2S\nFe2+ + S2- + 2H+ + 2Br- --> Fe2+ + 2Br- + H2S\n2H+ + S2- --> H2S\n\nK2CO3 + CuCl2 --> 2KCl + CuCO3\n2K+ + CO32- + Cu2+ + 2Cl- --> 2K+ + 2Cl- + CuCO3\nCu2+ + CO32- --> CuCO3\n\npeace\nvixklen
801118
CuCl2 + 2NH4OH --> Cu(OH)2 + 2NH4Cl\n\nCu(OH)2 (s) + 4NH3 (aq)     ----->     Cu(NH3)4^2+
87280
MBrO3-9H2O where M can be Na,K,Li, other +1 cations\n\nIf M is other than these you have to adjust subscripts
1040448
ask your chem prof or tutor ..it's hard to explain over the internet!
850606
Mg       2+\nPb       4+\nCrO4  2-\nNO2    1-\nI           1-\nClO3   1-\nOH      1-\nFe       2+\nNH4    1+\nCu      1+
813911
HBr ---> H(+) + Br(-)\nH2SO3 ---> H(+) + HSO3(-)\nCH3-COOH ---> H(+) + CH3-COO(-)
828480
1 mol of the compound has a mass of 146.1 gram.\n1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 146.1 g x 49.31% = 72.04 g\nhydrogen: 146.1 g x 6.9% = 10.08  g\noxygen: 146.1 g x 43.79% = 63.98 g\n\n2) convert to moles.\ncarbon: 72.04 / 12.01 = 5.998 mol\nhydrogen: 10.08 / 1.008 = 10.00 mol\noxygen: 63.98 / 16.00 = 3.999 mol\n\n3) divide each molar amount by the lowest value o obtain small integers \ncarbon:  6\nhydrogen: 10\noxygen: 4\n\nThe empirical formula of the substance is (C6H10O4)n\nThe atomic masses add up to 146.1, which is also the molar mass of the compound. Therefore n=1 and we find C6H10O4
933142
Yep, all you have to do is to make sure that the atoms shown in the left hand part of the equation appear on the left hand side.  Nothing is created or lost, you just make new compounds.  Dead easy, if only languages were so easy!!!