Multiply. (4m - 3n)(4m + 3n)?
921629
You can easily solve this by realizing (4m - 3n)(4m + 3n) has a pattern (a + b)(a - b), which equals to a^2 - b^2\n\nSo,\n(4m - 3n)(4m + 3n) = (4m)^2 - (3n)^2\n= 16m^2 - 9n^2
240687
4m+H-(4m-h) =\n4m+H-4m+h=\n4m-4m+H+h=\n0+H+h=\nH+h
421777
3x + 4y = 12\n\n(0,3)\n(3,(3/4))\n(4,0)\n((8/3),1)
395559
im guessing you made a mistake typing that out\nit shud've been (4n2+6n-3)+(6n2-3n+1)\n\nthats 10n2 + 3n -2\n\nif you did actually type it right, it is\n\n10n2 + 6n - 5
25946
=3fg*(f^2g)+3fg*5f-3fg*4\n=3(f^(1+2g))*g+15(f^2)g-12fg
681236
Multiply each term in the first () by each term in the second ():\n\n2x times 2x = 4x^2\n2x times 1 = 2x\n-3 times 2x = -6x\n-3 times 1 = -3\n\nThen combine 2x and -6x\nAnswer: 4x^2 - 4x - 3
107302
If you mean N=(mn)/(m-n)\nThen m=[mn/N]+n\n\nIf you mean N=[mn/m]-n\nThen m=(mn)/(N+n)
702805
B...multiply each number by 4 in the matrix
863644
take out 4x first\n4x(x2-6x+8)\n4x(x-4)(x-2)
793289
Replace m with 2n in the second equation\n2(2n) + 2n = 12\n4n + 2n = 12\n6n = 12\nn = 12/6 = 2\n\nm = 2n = 2(2) = 4\n\nAnswer: m = 4 and n = 2
1160760
what you have is something like\na(b+c)\n\nthe solution is \nab+ac\n\n(x^3)(2x^-2)+(x^3)(4x)\nnow to multiply x^a * x^b you get x^(a+b)\n\n2x^((3+(-2))+4x^(3+1)\n\n2x+4x^4
771836
Simple substitution.\n\n5(3) - 2(2) + 4(4)\n15 - 4 + 16\n27
685997
u should write it like\n7.52*10^-4
309995
do this\n9x-3/4y=1  move 9x to other side\n3/4y=-9x+1 get rid of 3/4, by7 multiplying everything by 4/3\ny=-9x*4/3 +1*4/3\ny=-12x+4/3
575490
I- + 2e- -------> I2\n\n4P + 3e-  -------------> P4\n\nthere ya go :)
971390
{3XY^2M/1}-{2M/[X^-1Y^-1]^2\n+{[4X^2Y^2]/M^-1}-\n(3X^(3Y)^(3M)^-1/(XYM)^-2
789893
x+4(2x+1)=3( x-2)+10x : x=2.5\n\nI like to work with x