Math.Tell me whether ea number is divisible by 2,4,5,6,9 and or/ 10.?
913443
Test for divisible by 2 - last digit is 0, 2, 4, 6, 8\nTest for divisible by 4 - last *two* digits are divisible by 4\nTest for divisible by 5 - last digit is 0 or 5\nTest for divisible by 6 - divisible by 2 and sum of digits is a multiple of 3).\nTest for divisible by 9 - sum of digits is a multiple of 9\nTest for divisible by 10 - last digit is 0.\n\nIf you check 1800, you'll see that it passes ALL tests.
726226
It is based on powers of 2.\n\ni.e. 2 ^ 10 = 1024
410550
5(2a+2) - 9a = 12\n10a + 10 - 9a = 12\n10 + 10a - 9a = 12\n10 + a = 12\n10 + a - 10 = 12 - 10\na = 2\n\n\nb = 2(2)+2\nb = 4+2\nb = 6
681251
1. If any number has an even number at its end, it is divisible by two. So 23000 is divisible.\n\n2. If the sum of digits of a number equal a number divisible by three, then the first number is divisible by three. In 23000, 2+3+0+0+0=5, which is not divisible by three. So 23000 is not divisible.\n\n3. Sorry, but I dont remember the divisiblity test for 4.\n\n4. If any number has 5 or 0 as its last digit, it is divisible by 5. So 23000 is.
951310
9+6         6+69          69+60\n9-6          6-9             69-6\n9+69       6-69           60-9\n9-69        6+60          60-6\n9-60        6-60           \n\n60/6\n\ncan you go so far as to do (60+6)/6\nif so... its a very long list... \nbut 9*6 is the only outright multiplication one\n\ncan you have negative #s as well thatare 2-digit?
628552
Use order ie\nParenthesis, Exponents, Division, Multiplication, Addition, Subtraction.\nThus, \n(4*5)+9-6 = (20)+9-6 = 29-6 = 23
803653
2x>-10\ndividing by 2\nx>-10/2\n=x>-5
858552
Have you tried these?  Surely you've been told that division by 0 isn't possible, so there's your answer for 7.  I'm not doing any others on Yahoo answers (too many at once), but if you really need help and are willing to do as much as possible for yourself I'll help you if you email h_chalker@yahoo.com.au, but nasty Maths teachers like me won't just hand you 7 answers on a plate!
876876
6 * [6*(5/6 - 1/6)]\n6 * [6*(4/6)]\n6 * 4\nTough.
788759
To find if a number is divivsible by...\n2-The dividend must be even\n3-Add all of the numbers together. If the number comesout to a number divisible by three it's divisble by that number[the larger one]\n5-dividend ends in a 0 or a 5\n10-dividend ends in a 0\n11-same digits al along...22,33,44,55, etc. etc\n\n\nHope this was useful information!
597439
=[(4+3x)/x] + (2/3)[(5+3x)/x]\n=[(4+3x)/x] + [(10+6x)/3x]\n=[(12+9x+10x+6x)/3x]\n=[(15x+22)/3x]
146728
no, it is divisible by 1, 3, 23, 29, and itself (with the numbers being reduced as far as possible)
1120506
No, it cannot be disproven, because it is true.  Actually, you could even remove the exponents:\n10 base n = n base 10\nHere is the reason.  In any numbering system, the value 10 (in that base) is equal to the value of the base you are using.  In binary, 10 = 2 base 10.  In a base three system, 10 = 3 base 10, and so forth.  So 10 base n will always equal n base 10.\n\nBecause that is true, you can raise them to any exponent value x you want--you are dealing with the same values on both sides of the equation.
382118
(10^2-10^2)/10(10-10)\n= (10+10)10-10)/10(10-10)\n= 20/10 = 2
766678
Since ABC divided by 5 and by 6 are both integers and that 5 and 6 are relatively prime, it follows that ABC is divisible by 30, so C is 0.\n\nBy the division, DE and ED are integers with DE the larger and divisible by 6 and ED the smaller and divisible by 5.  Also we can deduce that DE = (6/5)*ED.\n\nSince ED is divisible by 5, then D is either 0 or 5, but if it were 0, then DE would be a one digit number and less than ED.  So D must be 5.\n\nSo we are looking for a single digit E so that 5E = (6/5)*E5, and that 5E > E5.  Since we only have 1, 2, 3, and 4 as our candidates (0 is right out by a similar one digit number argument as above).  We can check each case to find that E=4.\n\nSo ABC = 6*ED = 6*45 = 270.  Thus the numbers are\n\nA = 2\nB = 7\nC = 0\nD = 5\nE = 4.\n\nCheers!
215800
only divisable by 1 and itself\n\nsee prime number pooping bear for examples\n\nhttp://members.surfeu.fi/kklaine/tpnsb/poopbear.html
68882
1) yes, this is correct as written.  Not sure what else you need? \n2) 10/14?\n3) 2 (1 is not a factor)\n4) -6(x+1)\n5) 5 1/4 or 21/4 (same thing)\n6) 1 4/9