Please help!finding wavelength and frequency.?
924047
455 nanometers is 0.455 micrometers, 0.000455 milimeters, and 0.000000455 meters. Is that enough for you to get started, or would you like me to solve it for you...?\n\n16 NOV 06, 0336 hrs, GMT.
734266
Frequency, f = 440 Hz\nAmplitude, A = 2.24 mm or 0.00224 m\n\ny(t) = Asin(2πft), assuming that y(t=0)=0\n\nv(t) = dy(t)/dt = 2πfAcos(2πft)\n\na(t) = dv(t)/dt = -(2πf)²Asin(2πft)\n\nMax velocity: v = 2πfA = 2π(440)(0.00224) = 6.19 m/s\n\nMax acceleration: a = -(2πf)²A = -17120.37 m/s^2
834583
You can use the Rydberg formula, which relates the reciprocal of the wavelength of the photon absorbed or emitted to the squares of the reciprocals of the principal quantum numbers.\n\n1/wavelength = R(1/n_l^2 - 1/n_u^2)\n\nSo, for the listed values of n, \n\nA.  1/w = R(1/ 2^2 - 1/4^2) = 0.1875R\nB.  1/w = -0.75R\nC.  1/w = 0.21R\nD.  1/w = -0.04861R\n\nSince energy and frequency are proportional to 1/wavelength,\nlooks like the order is D, A, C, B.
572734
Frequency is measured in Hertz, or inverse seconds.  So take the inverse of 6, which would be 1/6, which is your frequency.  Tada!
52783
The equation you want to use is \n\nfrequency * wavelength = speed of light\n\nor in order to calculate wavelength\n\nwavelength = speed of light / frequency\nwavelength = (3 x 10^8 m/s) / (100 MHz)\n\nIn the last equation the units don't match so convert in this way:\n100 MHz = 100 x 10^6 Hz = 1 x 10^8 Hz \n\nA Hz is just 1/s so now the units do match.\n\nwavelength = (3 x 10^8 m/s) / (10^8 1/s) = 3 m\n\n3 meters is a radio wave.
894747
Set the string vibrating. Use a variable frequency xenon lamp, and keep changing the rate until the string appears to be a static wave. Then you know the frequency of vibration. At this stage you can also measure the wavelength of the vibration. The velocity is then wavelength*frequency.
939890
well Kc first of all this is physics, not chem.\nsecondly the wavelength cannot be in Hz, frequency is measured in Hz so probably your ques should be \na certain violet light has a frequency of 6.0*10^14 Hz. What is its wavelength?\nif this is correct all you need is the equation\nVelocity  =  frequency X wavelength\n 3.0 * 10^8 = 6.0 * 10 ^14  X W\nW = ( 3.0 * 10 ^8 ) / ( 6.0 * 10 ^14 )\n     = 0.5 * 10 ^ -6 \n     = 5 * 10 ^ -7 meters\n\nI hope this helps.
910705
Hello, here is what you need:\n\nEnergy = Planck Constant * Frequency\n\nE = h * f\n\nh = 66.26 x 10^-34 Joule second
360055
For blue light'\nd Sin th = 2W        W is wave length\nFor a minimum \nd Sin th = (2n+1)W'/2\nSo,  2W=(2n+1)W'/2\nW'=4W/(2n+1)\n  =1440/(2n+1)\nBy putting various values for n , I find that only for the valu n=1, W' is within the vivible range,\nW'=480 nm
910620
wave length = speed / frequency\n\n12 = 550 / f\nf = 550 / 12 = 45.8 Hz
1044821
Frequency 2Hz\n\nTime period = 1/2 s\n\nAmplitude = 10 cm.
854178
Uh, I'm not smart on this, so I'm guessing here, but...\nSince different frequencies and wavelengths are what determines what color is being reflected, there has to be some way to quantify the amount of each in different hues of different colors.  Does that even make sense?  I don't know...
733204
period =t=1/f=1/256=.00391 seconds\n\nv=lf                            l=lambda=wavelength\n\nl=v/f=340/256=1.328meters
556687
2) Use stop wave:\nPlace a speaker of known, variable frequency close to a micro, the micro is connected to a microamperemeter.\nPlace that in the top of a long glass tube, slowly fill the tube with water until the the microamperemeter show a maximum. Continue filling the tube with water to get the next maximum. The distance between the two consecutive maximums is half the wavelength.\nSpeed = wavelength x frequency.\nRepeat the experiment several times and get the averange. That should be close to actual value.
168920
This is ultrasonic, not electromagnetic, so C is irrelevant.  The equation is:\nF=V/L where V=sound velocity in water (~1475 m/s), F=frequency in Hz, L=wavelength (0.0003 m)\nResult is you need 4.9 MHz or higher.
737785
I'll let you do the calculation, but the equation you need is:\n\nE = hc/lambda \n\nwhere h is Planck's constant, c is the speed of light in m/s and lambda is the wavelength of the light (in meters). You can find the rest of the numbers in your text book, I'm sure...
738444
You create two waves a second -> frequency = 2 Hz\n\nperiod = 1/f = 1/2 = 0.5 s\n\nThe wave travels 0.18m per 0.5 s, which is .36 m/s