by using 1 to 25 numbers without repeat we get same answer for 5 rows and columns  have  same total?
920549
3   7    14 16  25\n11 20  23  2   9\n22  4    6    15 18\n10 13  17  24 1\n19  21  5    8   12
527322
1+1-21+30-5\n2-21+30-5\n-19+30-5\n11-5\n6
981844
2 +28 -65 +48 +99,002,456,486 +1 -87 -998\n= 99,002,455,415\nNote to other answerers:  If you hold your mouse over the string of characters, it will show everything.
1033860
4096 - all answers are 4 times the previous number.\n1457 - all answers are 3 times the previous number plus 2
131932
it cant but .99 repeating is equal 2 one!!!! o unless u do a number 2 the 0th power \nex. (5^0)+(2+2)
1156254
the correct answer is 34592.\n\nthe first time i used MS excel.  then i wrote a database query to confirm it.\n\nhere's my SQL query:\n\ndeclare @pRunningTotal as integer\n\ndeclare @pMyNumber as integer\n\n\nselect @pMyNumber = 5\nselect @pRunningTotal = 0\n\nWHILE @pMyNumber < 372\nBEGIN\n   select @pRunningTotal = @pRunningTotal + @pMyNumber\n   SELECT @pMyNumber = @pMyNumber + 2\n      CONTINUE\nEND\nPRINT @pRunningTotal
301670
here are some examples\n\n5,6,2,3\n\nMedian - Put in accending order (2,3,5,6) Find the middle number, or in this case the middle two (3 & 5) and divide by two. 3/5\n\nMode - Does not exist here. What ever number or numbers is repeated the most.\n\nMean - 5+6+2+3=16  16/4(amount of numbers) = 4\n\nTry to do it in the order i did. I always get confused with the Mean and Mode. Just remember that Median sounds like Middle. Mode reminds you of functions and stuff. So just think of repetition. and Mean is left over.
632041
The number of elements in the sample space are all the possibilities that could happen after spinning the wheel twice.\nImagine two empty boxes which you will fill out with the numbers the wheel gives. _  _\nIn the first one there are five possibilities,\nin the second one also five possibilities, therefore a total of 5*5=25.
628648
None. The two numbers have no common factors, bar -1. You mean exactly (with no remainder) not evenly.
315772
You simply type: \n=rand(25,25) and then enter.
568941
You can't do it without repeating a number. If you put a number in a box, 200/that number must go next to it and below it.
523621
(10+15+23+37+45) / 5 = 26
198636
The number of combinations is given by\nnCr  =  n! / ( (n-r)! r! )\n\nThis formula works by calculating the number of possible permutations of r=5 choices from n=38 objects then dividing it by the number of ways the 5 objects can be arranged leaving just the number of possible combinations without worrying about their order.\n\nn!/(n-r)! = 38 * 37 * 36 * 35 * 34 = 60233040\n\nThis is the number of different possible permutations.\n\nr! = 5 * 4 * 3 * 2 * 1 = 120\n\nThis is the number of ways you can rearrange 5 objects. Each different possible combination of 5 from 38 objects can be arranged in 120 different permutations. Thus taking the total number of permutations and dividing by 120 will tell you the number of unique combinations.\n\n501942
826611
If the information in schools.xls is in more than one column (if the info includes the school name in one column, # of students in another, etc...) choose one value that doesn't have repeats.  School name would be a good choice.\n\nIsolate that information in one column, copy and paste if needed.\n\nIn the column directly to the right of your schools info, in the top cell, enter the follwing:\n\n=rand()\n\nThat will put a rand number between zero and one in that cell.  Double click on the box at the bottom right of the higlight to copy the formula down all of your data.  Then, choose the data menu, and sort...\n\nsort by the columnwith your rand om numbers, either ascending or descending.  Then take the first 30, 50, or 70.  In order to preserve randomness, after each set, hit f9 to refresh the random numbers and sort again.\n\nHope that's clear.\n\nTo be fair, the answer below this one is a bit simpler.  At the bottom of the tools menu, select Data Analysis.  Scroll down until you see sampling. Drag a box over the schools info, select random, and put n in for the number of samples.\n\nCan't win 'em all.  :)
513855
CLXXVI \n\nC = 100\nL = 50\nXX = 20\nV = 5 \nI = 1\n\nto have 176 just add those ones...
592397
b)two, but only if you are looking for specific Numbers to complete the table.\nThe two would have to be in different row\nYou have 6 blank spaces on the table. \nIf you have one more number given you can find the other column by subtraction.\nIf you have two more numbers given you can find the other row and Column by subtraction.\n\nI can complete the table right now you take 36/64=.5625\nso I use the equations  \n.5625C2+C2=53 1.5625C2=53 53/1.5625=C2=33.92\n.5625C2+C2=26 1.5625C2=26 26/1.5625=C2=16.64\n.5625C2+C2=21 1.5625C2=21 21/1.5625=C2=13.44\nC1=53-C2=19.08\nC1=26-C2=9.36\nC1=21-C2=7.56
674697
For five consecutive, there are 34 possibilities because you could start with 1, 2, 3,..., or 34\nYou can't start with 35 because then you would have\n35, 36, 37, 38 which is only four numbers.\nI'm not sure about the other two.\nNote: The answer to the other two are not 35 and 36.