Another equation help needed.?
928231
8x-10x > -11-1\n\n-2x > -12\n\nx < 6
156051
first let T =X^2\nthan we get a second degree equation\n2T^2-7T-4=0\nso you can solv it easyer
893931
m = 2\n\nb = -1\nso just substitute               these values in your equation\n\ny = mx + b\nthen you'll have\n\ny = 2x -1
838286
well Honestly dear Megan i don't think its correct , coz equation should have ONE " = " \n\nit must be something like this \n-4r ² ± 21r=r+13\n\nGood Luck
822981
i)Just substitute in the values to get F\nx = 1.1.  Other values are given.  Hence F.\n\nii) Rearrrange the equation\nx = [cosh^-1(QCK/2F-1)]/k\nF = 2.9.  Other values are given, hence x.
417188
y=Asin(2x)+Bcos(2x)+(x/4)\n\nNow you get to determine why.
765864
I'm unclear with the way you stated the problem. Am I looking for a implicit derivative. I'll check back to solve it.
550918
Type "=B1-C1+D1*A1" without the quotes inside another cell such as E1.  This is assuming that your equation is the correct algebraic form and solved for one variable.  Your text is a bit jumbled so I didn't parse all of it.
60599
This is not an equation.  Its garbage.  Both side of the equation have to equal each other.\n-35=.000075 this does not compute
268888
I think I can do this one...I'll get right back to you when I figure it out... *grabs a pen and paper...and also tries to figure out why people are answering, saying simply that they can't or won't answer your question*\n\nEDIT...k, here's what I got...not sure if I understood what your question was asking, so I may be mistaken...\n\nm=h(x)-2x\nk=(2-3h(x))/6x
35745
I think your equation got cut off because of the word-length limit.  Try putting spaces between the expressions (and put the equation in the 'more details section' and post again).  All I got was 550=2.297904*(L^0.38)*(M^0.41)... The answer to this snippet of equation at least is:\nM = 1.0596x10^58 / L^.926829
518727
Multiply the first equation by 2.\n\nSubtract the second equation from the new first equation.\n\nSolve for y.\n\nTake your value for y and substitute it into the original first equation.\n\nSolve for x.
565612
Take all the terms that include H to one side.\n\nS - 2LW = 2LH + 2WH.\n\nNow, factor out the H from the right side to get:\n\nS - 2LW = (2L + 2W)*H.\n\nNow, divide both sides by what it takes to leave H by itself.  In this case, get rid of the (2L + 2W)\n\n(S - 2LW)/(2L + 2W) = H
850884
using chain rule and product rule\n\ny'= 3x^(2)*tan(4x)\n         +4x^(3)*sec^(2)(4x)\n  = x^2(3tan(4x)+4x*sec^(2)(4x) \n\ni hope that this helps
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
953940
Hi again \n\nY = √2x – 3 \n2x – 3 = y ²\nX =( y ² + 3 )/ 2\nf –¹ (x)  =( y ² + 3 )/ 2  =>   f –¹ (x)  = (x ² + 3 )/ 2   &  x ≥ 0 \n\nGood Luck \n try to solve them yourslef again if you got wrong , am sure you can solve them correctly , if you just try your best
896553
4x^2+8x-x-2\n(4x-1)(x+2)