how long is a string?
922999
As long as it needs to be
1057756
lets say length= L\nwidth=W\nperimeter=P=22=2L+2W\nL=W+7\n\n22=2(W+7)+2W\n22=4W+14\n8=4W\n2=W\n9=L
300240
LongestPenis x 12 characters\n ************ = 12 asterisks (12 across)
621287
International System of units\n\nfor length its the meter
454208
the diffrent lenghts in strings make diffrent pitches, the diffrent length is the same as pressign down on a fret on a guitar, shorting the string makes it vibrate at a differnt speed creatign a diffret pitch
278945
This is an interesting site which can answer your question!\nhttp://www.gwydir.demon.co.uk/jo/units/length.htm
433102
Since the piece of string is not necessarily straight, it is insufficient to simply measure the distance from one end to the other.  Furthermore, the length of the string depends on the observer - if the string were moving at relativistic speeds (that is v/c is not << 1) compared to the observer, the string would not be nearly as long as an observer that moved with the string.  To measure the proper length of the piece of string, consider an observer that moves with the piece of string and that the entire string itself moves at a constant speed (since if part of the string were spinning very quickly and another were motionless, the observer on the motionless piece would observe the spinning piece to have length contraction as above).\n\nSide note:  My girlfriend is telling me that she wants to kick me in the face for responding like this.. hope you enjoy! (:\n\nAnyhow, the appropriate way to find the length of the string is to move as an observer sitting on the string and integrating over the path at an instant in time.  This will give you the proper length of the string which is the longest possible measurable length for the string.  Any other measurement would find a value that is smaller than this and would vary depending on the speed of the observer compared to the string as well as any relativistic gravitational effects.
607855
2 meters long i think. Or was it 5? i cant remmeber. Im doing a report on the discovery of a giant squid.
986711
maybe its not there anymore. did you take it out somtime earlier? \n\nand isnt there supposed to be a string?
377366
Depends how you measure it. \n\n1, Most people measure the length along the surface of the rope. \n2. Rope can stretch so if you stretch it taunt and measure it from end to end it will be longer,\n3. Rope is made of braid strands, So if you follow the twisted path of a strand, I that gives you the max length.
109636
How long is a piece of string! comes to mind
823010
As I write this, the question has been posted for 3 hours without an answer, so I'll give it a try.  When you suspend a slack (not taut) string between two points, the string, having weight, will naturally form a parabolic shape between the points.\n\nEarlier I did the math, figuring out how long the string would be if strung across the 8-inch diameter and falling parabolically to a depth of 10 inches in the center.  This is a "length of curve" problem that involves some very messy calculus.\n\nThat's not the only problem.  Having done the math for the longest string -- the one that crosses the diameter -- I realized that the same problem would have to be repeated for each of the chords that will have shorter distances between the endpoints and shorter depths.\n\nAs a result, after reading your question again, I decided to take a new tack, focusing on the "how do you make" part of your question.  There's still some math, but not nearly as much as there would've been otherwise.\n\nTo begin, think of a circular tennis racket with loose strings sinking in the center.  That's the kind of net we're going to design.  For orientation, think of the 8-inch circular rim as the face of a clock. with 12:00, 1:00, ... 11:00 positions.\n\nFor the general shape, long strings will connect the 12:00 and 6:00 positions, falling parabolically to a central depth of 10 inches, and also connect the 3:00 and 9:00 positions, falling to the same depth.\n\nThere can be shorter strings connecting 1:00 and 5:00, 11:00 and 7:00, 10:00 and 2:00, and 8:00 and 4:00, and falling to a shallower depth (less than 10 inches).  These four strings will all be the same length.  Another set of four still-shorter strings will connect 2 and 4, 10 and 8, 11 and 1, and 7 and 5, again all of equal length and falling to a still-shorter depth.\n\nAll strings will be parabolic.  The longer and deeper strings will be in the center, and the shorter and shallower strings (the chords) will be toward the sides.  There will be an odd number of both vertical (e.g., 12-6) and horizontal (e.g., 9-3) strings because there's one central string in each direction and an even number of strings on the sides due to symmetry.\n\nTo form the net, the strings will all be woven as they interlace with each other.  I imagine that your net may be constructed with fishing line.\n\nHaving described the general structure of the net, we now have to do some math to figure out the spacing of the strings.  Going back to the tennis racquet idea, let's suppose we want the strings to be equally spaced <when viewed from above.>\n\nFor an example, suppose the strings are a half-inch apart.  Let the 12-6 line be the y-axis and the 9-3 line be the x-axis.  We want vertical strings at x-values of 0, 0.5, 1.0, 1.5, ... 3.5 (plus and minus) for a total of 15 strings.  There'll also be 15 horizontal strings for a total of 30.\n\nWe've already said that the central strings will attach across diameters (plus and minus 4) and descend to a depth of 10.  In three dimensions, suppose the bottom of the net is at (0,0,0), and the top circle is in the plane z = 10.  The equation of the parabola for the center strings is z = ax^2, passing through (4,10), so 10 = 16a, or a = 5/8, and the final equation in the x-z plane is\n\nz = (5/8) x^2  (Equation 1)\n\nLet's look at the placement of the string at x=3.  In the x-y plane, the circle has radius 4, and by the Pythagorean Theorem, the y-value is sqrt(4^2 - 3^2) = sqrt 7.  This string will be attached at (3, sqrt 7, 10) in 3 dimensions, with the other end at negative sqrt 7 in the y-dimension.  The distance between the attachment points is 2 sqrt 7.\n\nHow far down will this string go?  To get that, we evaluate Equation 1 at x=3:\n\nz = (5/8)(3^2) = 45/8 = 5 5/8 = 5.625\n\nThis means the <height of the netting> at x=3 is z= 5.625 inches.  But the top of the netting is at z=10, so the <drop> is 10 -
401109
between 10 and 30. thats not to say it cant be shorter or longer. dont worry about the lenght of time just enjoy the situation!!!
1169146
At least 12 feet.\nI could be wrong though.
473176
100 cm, its a 3:4:5 right triangle.\n\n[lay the cylinder out flat, if you will.  4 times around is 80 cm, and the width is 60 cm.  So the string has to form the hypotenuse of the 60 cm by 80 cm sided triangle.  60 divided by 20 is 3, 80 divided by 20 is 4, and a right triangle is famously 3:4:5, so 5 times 20 is 100 cm]
214408
According to string theory, the strings are the universe's \nelemental material. They vibrate in different ways and can\njoin and break apart to form different elemental particles\nthat make up the universe. The strings exist in 11\ndimensions: time, which physicists consider a dimension, and\n10 spatial dimensions. Four of those dimensions are the ones\nwe are familiar with, three spatial dimensions plus time.\nThe other dimensions may be so small they're invisible to\ncurrent detection equipment and are only known to exist because they leave a "footprint" of where they have been.
928881
how longs a bit of string