How to convert to hours and minutes in Visual C#?
919463
//D = dictance value assume alrady exist\n\nint H,min,TM;          //TM =total Minutes\nint speed =55;\n\nTM=Math.Round((D*60)/speed);                                   \n\nH=TM/60;\nmin=TM%60;\n\nlabel1.text= H.toString() + " hours and  " + min.ToString() + " Minutes";
34052
I do not know a preprogrammed utility to do this, but can point you in the direction that you might need to go.  See the reference below for the math and an on-line converter:
1162831
hh:mm:ss\n4:00:40 or\n8:00:20
142487
Try the following link:\n\nhttp://custom.programming-in.net\n\nIt has info about the API along with how to access it from C#, VB.NET & VB6
186354
Easy - \n\nDim someDate As DateTime = DateTime.Parse(yourString)
999494
9 PM.  You can alwasy do the conversion by taking 12 from the military time. For example:\n21-12=9
1118192
I don't use vb.net myself (C# I use).\n\nIf you want to keep the 0's in the front though, it has to be a string, not an integer.\n\nYou convert it over to integer, add the next number, then cast it back to string, and pad the length to the desired number of 0's\n\nPseudo code:\n\nLicenseNoNum = CastToInt(LicenseNostr)\nLicenseNoNum = LicenseNoNum + 1\nLicenseNoStr = CastToStr(LicenseNoNum)\nWhile LicenseNoStr(Length) < 8\nLicenseNoStr = '0' + LicenseNoStr.\n\nYou could also just store it as an integer, and perform the cast for printing, which might be all you were looking for.
1081056
Menu>settings>Time&Date
711827
Java may be returning the 12-hr format of the time. That would be 12:03:00 AM. You would need to format it for 24-hr, that would return 00:03:00
1070309
1. Place a Timer control on your form.\n2. Set its Interval property to 1000(for 1 sec., 1000 millisec.), so the Timer(or Tick) event will be called every n\nmilliseconds, determined by the Interval property.\n3. Put this code into the Timer(or Tick) event(first define an Integer variable at the top of the form's code):\n\nIf seconds = <secondstoanswer> Then \nMsgBox("Times up!")\nExit Sub\nEnd If\nseconds = seconds + 1\n\nDiring design, you can set the Timer's Enabled property to False to disable the Timer. To change states(enabled/disabled), use:\n<timername>.Enabled = Not <timername>.Enabled\n\n:)
44336
One solutions is:\n\nGet the formula from the user then parse it. You have to write a parser.\n\nAt run time, todays languages won't be able to get forumula and input from those variable.\n\nI am a Software Engineer and I know you can't do it with C, C++, Java, any .Net...\n\nGood Luck
691740
Try this:\n\nHold MODE and SET for 2 seconds. Then use MODE and SET to adjust hours and minutes. Hold them again to exit adjust mode.
800542
You could use GetTickCount\n\n'Put this in a module\nDeclare Function GetTickCount Lib "kernel32" () As Long\n\n'Use something like this in a form\nDim starttime As Long\nDim endtime As Long\n\nPrivate Sub CommandButton1_Click()\n\nstarttime = GetTickCount()\nEnd Sub\n\nPrivate Sub CommandButton2_Click()\nendtime = GetTickCount()\n\nMsgBox (endtime - starttime) / 1000 & " secs"\n\nEnd Sub
411262
You need a special made function:\nTry this\nput start time in A1\nput end time in B1\nput this fumction in C1\n=HOUR(B1) -HOUR(A1)&":"&MINUTE (B1)-MINUTE(A1)\nThis will work if both time are in the same day\n\nI had to put spaces for you to read, remove them.\ne-mail me for further info\n\nXLMan
813501
Set cell A1 to 5:34:55 and some other cell to:\n\n=(HOUR(A1))*60+MINUTE(A1)+ IF(SECOND(A1)>30, INT(1+ SECOND(A1)/60), SECOND(A1)/60)
197427
Sub Main()\n        Console.WriteLine(2 ^ 5)\n        Console.ReadLine()\nEnd Sub
1121045
If you want to use the time right now:\n\nthis.txtMyFormElementName.Text = System.DateTime.Now\n\nIf you want to use your own time, use the System.DateTime object to create an instance around whatever time you want by passing it day/month/year... etc.