Find the length x.  Express your answer in simplified radical form.?
922431
Use pythagorean formula to solve:  a^2 + b^2 = c^2, where a and b are the legs of the triangle and c is the hypotenuese.\n\nIt's a little unclear what you mean by "right side is x" -- not sure if you mean it's one of the legs or the hypotenuese.  I will assume you mean hypoteneuse.\n\nSubstitute 51 and 45 for a and b in the formula to solve for c (or x as it's being called in your problem):\n\n51^2 + 45^2 = x^2\n\n2601 + 2025 = x^2\n\nx^2 = 4626\n\nx = √4626 = 3√514\n\n.
616025
Pretend that:\nx= length of base\n\nUsing the information given:\n4x-8= length of one of the legs\n\n\nProcedure:\n2(4x-8) + x = 29 ---> (there are 2 legs- so you x2)\n8x-16 + x= 29\n9x-16= 29\n9x= 29+16\n9x= 45\nx=5\n\nResult:\nSince x=5 and 4x-8 is one of legs of the triangle, by simplying applying the x=5 into 4x-8, you can get your length of one of the equal legs.\n\n4x-8= 4(5)-8= 20-8= 12\n\nANSWER: D) 12 cm
936579
your question seems to be incomplete.\nso far....\nwidth=x\nlength= 2x-1
976501
You mean "one less."\n\nCall the base x.\nThen each leg is 2x-1.\nAnd the perimeter is x + (2x-1) + (2x-1), which equals 18.\n\nJust solve for x and you can calculate the lengths of the sides.
12044
By using the FOIL method, the final answer will be \n\n3x squared - x - 4
825795
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
3037
This is not presented as an equation, so the goal appears to be to combine the rational expression --> x+10 \nThat's all you can do with the question as it is written.
101183
-1<(or equal to)X <(or equal to)6
38332
(x-2)/(x^2-2x-15)+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(-2-x)(x+3)/(x-5)(x+3)\n\n[(x-2) + (x+3)(-2-x)] / [(x+3)(x-5)]\n\nANSWER :\n(x^2+4x+8)/((x+3)(5-x))
825411
first side=x\nsecond side=2*x\nthird side=2*x+3\n1. + 2. + 3. => x+2x+2x+3=33 => x=6 \n\nfirst side: 6cm\nsecond side: 12cm\nthird side: 15cm\ntotal: 33cm
919015
(8X^6/7) * (56/24)\n8X^6/3\n\n(Hint:  X^m/X^n = X^(m-n)
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
134261
Its a scalene traingle. Here x works out to be 10.\n2x+x+40+4X+35= 180. x is nearly 10. Since all the lengths are different its a scalene triangle. The indivudual lengths work out to be 20,50,75.
770190
x² / √(1-x) \n= x² √(1-x)/(1 - x)\n= (-1 + 1 - x²)√(1-x)/(1 - x)\n= (1 - x²)√(1-x)/(1 - x) - √(1-x)/(1 - x)\n= (1 + x)√(1-x) - √(1-x)/(1 - x)\n= x√(1-x) + √(1-x) - 1/√(1-x)\n\nSo ∫x² / √(1-x) . dx\n= ∫[x√(1-x) + √(1-x) - 1/√(1-x)] . dx\n\nNow ∫x√(1-x)dx \n= x * -1 * 2/3 (√(1-x)³ - ∫[-1 * 2/3 (√(1-x)³ . 1)dx\n= -2x/3 * √(1-x)³ + 2/3∫(√(1-x)³ dx\n= -2x/3 * √(1-x)³ + 2/3*2/5 * -1 * √((1-x)^5)\n= -2x/3 * √(1-x)³ - 4/15 * √((1-x)^5)\n\n∫√(1-x) dx = \n\n∫1/√(1-x) dx = -2 *√(1-x)\n\nSo ∫x² / √(1-x) . dx\n= ∫[x√(1-x) + √(1-x) - 1/√(1-x)] . dx\n=  -2x/3 * √(1-x)³ - 4/15 * √((1-x)^5) - 2/3 * √(1-x)³ + 2 *√(1-x) + c\n= - 4/15 * √((1-x)^5) -2/3 (x + 1)√(1-x)³ + 2 *√(1-x)  + c
474388
Okay, first, since the vector given for B is a unit vector, we know that the vector from the origin to B must be given by (some constant)*(2,-2,1)/3.  So, what you want to do is find the value of that constant such that |A-B|=10.  Do this by setting A-B=(6-2x/3, -2+2x/3, -4-x/3).  Then just find the length of that vector in terms of x, set it to 10, and solve for x.
703752
simply subtract 7 from both sides. This leave you with\n\nx<_3
391062
It's an easy equation . The solution is: \nX=(ln (sqrt5-1)/2)/ln(2/3)....sqrt means the radical sign.