I have cards and I put them in order from 0-12. No number should be next to a number that is 1 less, 1 more or
920768
One solution is\n0, 2, 4, 6, 8, 10, 12, 1, 3, 5, 7, 9, 11\nBut there is a huge variety of solutions\n\nSorry Chris I did not copy so here is another\n\n0, 11, 5, 2, 9, 3, 1, 4, 10, 7, 12, 6, 8
697965
every number from 0 to 10\n\nplus placed in alphabetical order
810881
Arrange your sequence of numbers from the smallest to largest...\n\nthen the middle number in your sequence is your median\n\nit's simple as that.\n\nfor example\n\nA.   6, 7, 10, 4, 9\n\nRearrange to\n\n4, 6, 7, 9, 10\n\nThe middle number in the sequence is 7 as you can see\n\nSimple :D\n\nhope it helps
401032
If your asking number mine is 10
391186
13!/(13-4)! = 17160 if order matters\n\n13!/(4!*(13-4)!) = 715 if order does not matter\n\nI give up after this one ...\n\nNow that I think of it, if you're allowed to reuse numbers, you would have\n\n13^4 = 28561
285643
12 yellow cards and 2 red cards
1145815
6\n\nYou are putting the single digit numbers in alphebetical order:\neight, five, four, nine, one, seven, six, three, two, zero
568941
You can't do it without repeating a number. If you put a number in a box, 200/that number must go next to it and below it.
471834
aren't u missing a number there on the last row???\n\nin that case... i would say...\n\n9 11 13 15 17 19....
9961
0,1,1,2,3\n\nto get the next number add the previous 2 numbers
1051900
1 2 3 4 5 6 10 12 15 20 30 60\n-1 -2 -3 -4 -5 -6 -10 -12 -15 -20 -30 -60
946903
Numbers 1 - 9 are spelled out, once you get to10 and above, you can just use the numerals. Here's a web site to prove my point...\n\nhttp://www.grammarbook.com/numbers/numbers.asp
532000
How about 9! 51, 52, 55, 56, 57, 58, 59, 60, 61
779807
Yiu would first decide how many decimal places you are going to consider.  The usual is 3.  Then work it from there...;
1006179
111221, 312211, 13112221, 1113213211, ...\nOR\n1231, 131221, 132231, 232221, 134211, ...\nOR\n3112, 211213, 312213, 212223, 114213, ...\n\nEach is based on the digit makeup of the previous term, but I need one more term in the sequence to be sure of the rule.
771506
It could be any number between 0000 and 9999. If you need a list, start by writing down 0001, then 0002, then 0003, until you get to 9999. There's your list.
668533
There are 3 pairs:\n\n1. 0 and 0\n2. 2 and 2\n3. 9 and 9\n\nThere won't be any more as the number values get larger. This is because when the no.s are multiplied, there would be more digits than when the no.s are added. So they can't be opposite if they have diff. no. of digits.