A water pipe is to be installed on the diagonal of a lot which is 80 meters by 100 meters.?
920010
Using the Pythagorean theorem, s1²+s2²=d²\n80²+100²=d²\n6400+10000=d²\n164000=d²\nd=128.1 meters
882706
305m long by 33.5m wide
566593
100 m above sea level
524622
Wow, big undertaking ok well the only thing that I can think of is the Friant Kern Canal project that lifts 6, 10 ft. diamiter pipes full of water South just out of Bakersfield Ca. and delivers LA with drinking water. Pumps are used of cource but the lift is huge, maybe 2,500 ft.
520408
Finding the under ground water supply!
334079
Go to a pipe and fitting company and get prices.
816108
dA = ½ (b.dh + h.db)\nSo δA ≈ ½ (b.δh + h.δb)\n= ½ (100 x ±1 + 10 x ±2)\n= ½  * ±120\n= ±60ft²\n\nCheck:\nMin area = ½ * 98 * 9 = 441ft²\nMax area = ½ * 102 * 11 = 561ft²\n\nNow 500±60 ft² = (440 to 560)ft²\n\nSo estimate is pretty close!!!
754418
You can have different sizes of the pool, for example: \n20 ft. wide pool 1800:20=90ft. long \nor 25ft. wide pool 1800:25=72 ft. long\nor 30 ft. wide pool 1800: 30=60 ft. long\nI would clarify with the owner what pool width he or she prefers.\nFor the side decks we add 2x5 ft.=10ft to the chosen width of the pool \nFor the end decks we add 2x10ft.=20 ft.to the length of the pool \n\nthus the pool site should be over\n\n(20 +10) x (90+10)=30'x100'\nor\n(25+10) x (72 + 10)=35' x 82'\nor\n(30 + 10)x (60+10)= 40'x 70'\n\nPlease remember to add the pool clearances from the property line as per local municipal codes. Also, the machines used for digging have to have access from this property, not from the neighbours yards.  The smaller they are the more difficult and expensive the job is. \nIf we add about 10 ft. for access (and clearance) on each side we end up with a poll site: \n(20+20)x(90+20)=40'x110'\n(25+20)x(72+20)=45'x92'\n(30+20) x(60+20)=50'x80'\n \nAn addition of the area needed for the house will give you the minimum lot size required.\nGood luck!
437917
I would recommend a fire hydrant,the water is free.
731199
The first three answers are correct, but confusing. Let me see if I can't simplify this for you. \n\nThe pipe expands in all directions. Assume that the pipe is made of a uniform material, like copper, so we can say that it expands uniformly in all directions.\n\nYou must understand that the metal expands uniformly per unit of measurement. Think of a strip of metal, first. (our piece of tubing cut down the side and unrolled flat.) This means not only that the length, width and thickness expand-- it also means that it will expand so much PER UNIT.\n\nSuppose the copper will expand 1 mm per cm. (We'll use metric, just to keep it simple, because everything will be in tens.) \n\nIf the thickness of the copper strip is 1 cm, \nit will expand to 1.1 cm, or 1 cm plus (1 x 1mm.)\n\nIf the width of the strip is 20 cm, \nit will expand to 22 cm, or 20 cm plus (20 x 1 mm.)\n\nIf the length of the strip is 200 cm, \nit will expand to 220 cm, or 200 cm plus (200 x 1 mm.)\n\nNow, suppose we roll the strip back into a tube again. \n\nThe inner circumference of the tube started out as 20 cm, and the diameter was 20/ pi (which is something less than six cm.)\n\nThe new inner circumference is 22 cm, and the new diameter is 22/pi, which is greater than seven cm. \n\nSo, the metal expands proportionately in all dimensions, and the with of the strip (the circumference of the tube, and thus the diameter) expands MUCH MORE than the thickness of the strip, (which is the same as the tube wall). \n\nIs physics cool, or what?\n\n10 NOV 06, 0419 hrs, GMT.
42092
10,000 square metres as in 100x100 square metres
973746
picture a water pipe that is 1/4 inch in size, and a water pipe that is 5 inches in size.\nWhich one can move more water?\n\nnow invision dial up and the small pipe and broadband as the large pipe.\n\nof course the use it to move more stuff.
33833
two flanges can be bolted together to connect pipes.
719561
it's where you place a T intersection (like for where the shower faucets go) with a riser above it to stop "water hammer" by giving the system some room for the air to pressure to go to.
652480
somewhere with water is a good idea...be a bit more specific with your question!
1011212
Near or on the transom there is an electric pump. It might be filled there or in a reservoir close to the pump.
12926
First, find the area of the circle that is the end of the pipe.  Pi * r squared = 3.1416 * (.25 / 2) = 0.7854 square inches.\n\nThen multiply by the length of the pipe.  BUT, since you want cubic inches, and the pipe is 750 FEET long, convert feet to inches (750 * 12).\n\nSo the answer is 750 * 12 * .7854 = 7068.6 cubic inches\n\nThe prior answer above assumed 750 INCH LONG pipe not 750 FOOT long pipe (750')