Simplify. 3 - a/b over a/b?
922233
You start with [3-(a/b)] / (a/b)\n\nTo get a/b out of the denomenator, multiply the top and bottom of the fraction by b/a:\n\n[3-(a/b)] * (b/a) = (3b/a) - (ab/ba) = (3b/a) - 1\n\nNow find common denomenators:\n\n(3b/a) - (a/a) = (3b - a) / a\n\nand there's your answer:\n\n(3b - a) / a
78524
(1-a)+3(a-2)-(2a-3)=1
179535
I believe it simplifies to n - w.\n\nHere's the expression you wrote: (a-y/w+n * w^2-n^2/y-a).\n\nHere's what I think it should look like:\n\n((a-y)/(w+n)) * ((w^2-n^2)/(y-a))\n\nBecause:\n\n((a-y)/(w+n)) * ((w^2-n^2)/(y-a))\n\n= ((a-y)/(w+n)) * ((w+n)(w-n))/(y-a)\n= ((-1)(y-a)/(w+n)) * ((w+n)(w-n))/(y-a)\n\nThe (w+n)'s cancel out, as do the (y-a)'s, so you're left with this:\n\n= (-1)(w-n)\n= (n-w)
351083
In A3, put "=SUM(A1:A2)" or just "=A1+A2"
889713
3|(2x-1)/5| + 3 = 1?\nThats impossible. |anything| >= 0, so the LHS is >= 3. Did you mean something else?
11476
algebraic simplification\n\nx over 4+3 = 2x+3 over 5\nx / (4+3) = (2x+3) / 5\nx/7 = (2x+3)/5\n5x/7 = 2x+3\n9x/7 = -3\n\nx = -7/3
762985
(b-4)/(b-4)(b+4) simplifies to 1/(b+4)\nrestrict denominator...bcannot equal 4 or -4
544625
3 and 23/32nds\nor simply\n119/32
470404
((a^2 - b^2)/8a) X ((4a^3)/(a + b)^2))\n(4a^3(a^2 - b^2))/(8a(a + b)^2)\n((4a^3)/(8a)) * ((a^2 - b^2)/(a + b)^2)\n((a^(3 - 1))/2) * (((a - b)(a + b))/((a + b)(a + b)))\n((a^2)/2) * ((a - b)/(a + b))\n\nANS : ((a^2)(a - b))/(2(a + b))\n\nOn your problem, here is where you went wrong\n\nTo make it easier, you should had kept your problem in\n\n(4a^3(a - b))/(8a(a + b)) form, then had done this\n\n((4a^3)/(8a)) * ((a - b)/(a + b))\n\n(4/8)(a^(3 - 1))((a - b)/(a + b))\n(1/2)(a^2)((a - b)/(a + b))\n((a^2)(a - b))/(a + b)
664470
Since 1/(a+b+x)=1/a+1/b+1/x\nSo 1/(a+b+x) - 1/x =1/a+1/b\nSo (x-a-b-x)/(x(a+b+x)) = (a+b)/ab\nSo -(a+b)/(a+x+b)=(a+b)/ab\nSo -1/(x(a+b+x))= 1/ab\nSo x(a+b+x) = - ab\nSo x^2+ (a+b)*x + ab =0\nAnalyzing :\n(x+a)(x+b)=0\nEither x = -a\nOr     x + -b
514501
It's not really a problem as much as a simplification; there's no = sign.  Anyway, simplified I get 8w^3 + 4w^2.  I got that by multiplying your original problem by \n(-2w-1)/(-2w-1).  That gets rid of the fraction in the denominator and reduces the numerals in the numerator down.
769323
6 - 12x\n-or-\n-12x + 6\n\n-or-\n\n6(1-2x)\n\n...although that depends on whether you want the simplest expanded form or the simplest factored form.
331279
what does a^2ba^3ab^3b =a^6b^5 or a*a*a*a*a*a*b*b*b*b*b
164692
Yes, it goes like this:\n\n\nStatr out with any two numbers.....a & b.\n\nThen set them equal to each other:\n\na = b\n\nThen proceed as follows.\n\na = b\n\n==> a^2 = ab\n==> a^2 - b^2 = ab - b^2\n==>(a + b)(a - b) = b(a - b)\n==> a + b = b\n\nNow....on the left hand side, since a = b as was staed in the beginning you say:\n\n(b) + b = b\n==> 2b = b\n==> 2 = 1\n\n<done>\n\nVery slick, and very cool...and very wrong.....lol.\n\nThe 'error' comes in when you divide by a - b. Since a = b, you are essentially dividing by zero, and that is a mathematical no-no.\n\nHiope that clears things up for you.
924187
= 16ab/20ab^2\n= 4/5b // 16 and 20 can be reduced by 4, and an a and a b cancels out\n\n3*3*3*3*3 = 3^5\n3*3 = 3^2\n3^5/3^2 = 3^3\n= 3*3*3
1139003
(n/(n - 3)) + (5/(2n - 6))\n(n/(n - 3)) + (5/(2(n - 3)))\nMultiply everything by 2(n - 3)\n(2n + 5)/(2n - 6)
8373
(([(4+4+4).(4+4)]+4)/4)*(4+4)\n\n(4+(4*4)).([(4+4+4).(4+4)]+4)