Anyone know the unit for k in PV=K? Like.. is it just... k?
916556
If I understand the units (and your question)right...this relates to pressure and volume.  Go straight to the base units.   A pascal is a N/m^2 (newton per meter squared).  A liter is volume so meter^3.  This leaves you (N/m^2)*(m^3) = N*m.  This is force times distance aka WORK which is represented as a Joule (J).
992153
the listing is here:\n  http://en.wikipedia.org/wiki/Conversion_of_units\nhere is a calculator\nhttp://www.onlineconversion.com/
867789
Try starting with a proportion. Let K be the cost we are looking for.\n\nb / x = K / y\n\nNow solve for K.\n\nK = by / x
894614
PV=nRT\nP= (nRT)/V  (1st eq)\n\nn,R,T u know.\n\nV >>>\nDensity = mass/ volume\n2.3 = .00446 *10^3/Volume\n\nrearrange and ull get volume.............and then put that into the first equation.............and voila
716901
You can use polynomial long division to find the value of k. Be very careful! For the first expression, after dividing the numerator by the denominator a remainder of  8 - 4k  is obtained. Set this equal to zero to find the desired value of k.\n\nTo review polynomial long division, see:\n\nhttp://en.wikipedia.org/wiki/Polynomial_long_division
1071773
PV=nRT\n\nV=nRT/P\n\nR=.08206\nT=373 K\nP= 1 atm.\n\nYou will have to figure out n, the number of moles in one gallon of water.  The answer will be in liters, convert it to gallons
375635
Kp=Kc(RT)n\na.Kp=Kc(RT)-1/2\nb.Kp=KcRT\nc.Kp=KcRT\nd.Kp=Kc(RT)2
929836
v = b - u/k\nv - b = u/k\nk(v-b) = u
144053
Pay more attention in class! And assuming it is an ideal gas, use PV=nRT. Since there is not change in volume you can basically drop it from the equation and make P=nRT. If you like algebra you can leave it in but it will cancel out eventually. You could solve for 'n' first using initial P and T, and then plug and chug.
26218
fv = pv (1 + I/compound)^years*compounding\n\nfv = 6000 (1 + .06/2)^3*2\nfv = 7164.3138
789203
Well, if you convert grams to kilograms, then you have\n\ne [=] kg*(m^2/s^2) [=] kg*(m/s^2)*m [=] N*m [=] J\n\nHowever, the units of E are determined by the units of mass, distance, and time that you use, and consequently could by in any of the units of energy.\n\nI'm not sure what english units you mean, but                               1 J = .73 feet*pound_force.\n\nFor unit conversions, consider using google or download a more comprehensive freeware unit converter, like Uconeer. I use Uconeer for the more obscure unit transformations, and tabulated values for more common conversions.  Google it.
231663
_KCl3 _KCL + _o2? K2Cl4o2 thats the answer i think.:)
711363
The volume will be 549.5 mL.  Let me know if you want to see the work.   Use this equation PV/T=P*V*/T*.    P,V, and T are just the pressure, volume, and temperature for the initial system (they are usually represented as P1,V1, and T1 but I left out the numbers which should be subscripts for simpliofication because yahoo does not have many text options.)  P*,V*, AND T* are the pressure, volume, and temperature after the system has been changed.  You could use any units pretty much for the pressure and volume as long as you keep the units consistent.  However always use Kelvin for the temperature.  Kelvin = 273 + Celcius Temp.
655434
K2S\n\nPotassium is K.  Sufide is S2-, so you need 2 K's.
1106975
41F\nI dont' remember a "k" is that in calvins?\nsorry kelvins\n\nthe right answer would be c 278k\n\n Temperature conversions between the three temperature scales:\nkelvin / degree Celsius conversions (exact):\n\n    * kelvin = degree Celsius + 273.15\n    * degree Celsius = kelvin - 273.15 \n\ndegree Fahrenheit / degree Celsius conversions (exact):\n\n    * degree F = degree C x 1.8 + 32.\n    * degree C = (degree F - 32.) / 1.8
879746
Ek = 1/2.m.v2   (1/2 mass times velocity squared) - \n\nsorry can't do superscript on this site
463421
KE = mv\nWrong: energy <> momentum\n\n2y = (2 m)cos(kx)\nRight: a lenght =  lenghth x a number between -1 and +1\n\nvf = vi + ax\nWrong: x should be t\n\ndensity = volume/mass\nWrong: fraction should be inverse