how can you show work for this math problem?
915778
1) 6.4/100\n2) 100|6.400..since 100 cannot divide into 6, nor 64, you have to move the decimal point over until you reach a whole number that is divisible by the denominator (100). \n3) 0.0640\n\nI hope this clarified the problem for you!
538044
hmmm...very tough one!\n\nill sovle by the formula!\n       _________\n-b +- V (b^2)-4ab\n------------------\n       2a\n       _________\n-10 +-V 100+512\n------------------\n       2\n\n       _________\n-10 +-V 612\n------------------\n       2\n\n-10 +- 24.7\n------------\n     2\n\n14.7/2\n\n34.7/2\n\n(7.35, 17.35)
838481
Well hey, you need help, ask the teacher! I know how to do this, with help from my nerdy Calculus BC friend, but it's really not that hard once you think about it...
517819
start pulling out common factors\n\n2 (x^3 + 27)\n\n2(x^3 + 3^3)
1110742
12 simply place the 1 where the x is\n\n(1+3)(1+2)\n4*3\n12
727014
start with the O... they are always -2\nsince there are 2, and the compound must balance...\nPb must be +4\n\nso you get +4 -2
572318
1) Let x:the length , y:the width of the picture.Note:x,y>0\nThe first equation we have is : x=y+4 (1)\nThe combined area has the length is x+4,the width is y+4       \nso the second equation we have is: (x+4)*(y+4)=140 (2)\nReplace (1) in (2)-->(x+4)x=140--> x^2+4x-140=0 -->x=10 or x=-14 .since x>0 then x=10(cm)-->y=6(cm).\n2)  Let x: the length,y:the width.Note:x,y>0\n    The first equation we have is x=y+3 (1)\n    The second is: the area=x*y=550 (2)\n    Replace (1) in (2)--> (y+3)y=550--> y^2+3Y-550=0 --> y=22 or y=-25.Since y>0 then y=22(cm)-->x=25(cm)\n3)  Let x,y:two positive integers.Supposed that x>y>0 \n    we have two equation:x*y=240(1) and x=y+8(2)\n    Replace (2) in (1)-->y(y+8)=240--> y^2+8y-240=0 -->y=12 or y=-20.Since y>0 then y=12-->x=20.
1169010
Find d?\n\nWhere are a, b, and c?\n\nwhy don't you write out the entire problem if you want help?
54243
DO YOUR OWN HOMEWORK. I'll expect you to show YOUR work when you hand it in.
132964
You are solving for k so it you need to rewrite the problem to look like this k=z/(xy) where x=3, y=8, z=6 substitute the letters for numbers so k=6/(3*8) k=6/24 or k=1/4 to check just solve for any other letter such as z by using what you know of k and you should come out with z=6
777951
Tackling the problem bit-by-bit:\n\nFirst, let x = the larger number\nlet y = the smaller number\n\nYou can write out an equation to show their relationship of "difference" by:\nx - y = 68\n\nNext, you write out the equation to show their quotient relationship by:\nx/y = 5\nwhich gives:\nx = 5y\n\nNow plug x = 5y into the "difference" equation:\n(5y) - y = 68\nwhich gives\n4y = 68\nwhich gives \ny = 17\n\nNow plug y = 17 into the "difference" equation:\nx - 17 = 68\nx = 85
231014
Here's a great formula. One does the work in A days and the other in B days. The number of days they will do the job if they work together being N,\n\nN=(AB)/A+B\n\nSo, if the first do the job together: N=24/10=2.4\n\nAnd if the three of them do it: N=(2.4x2)/(2.4+2)=1.09 days approximately.
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
268070
Check out this site. It gives you a few examples. It was helpful for my cousin when she was leaning how to do them.\nhttp://www.purplemath.com/modules/solvelin.htm
70409
Go back to math class and figure it out!
936579
your question seems to be incomplete.\nso far....\nwidth=x\nlength= 2x-1
1169800
work done 1.078 X 10^5\nheat is -0.292X10^5