Maths! How do you find the inner surface area of a piece of  conduit in m squared?
929508
inner surface area of a conduit of inner diameter d and length l = pi*d*h\nherd d = 10mm= 0.01 m\nand h = 5m\nso inner surface area = pi*0.01*5\n= 0.157  m squared
1060915
Area can be calculated by using the formula Area = 4 Pir^2 .  You didn't mention radius of the tank, thus a numerical answer is impossible.
827739
Not quite sure what you are asking for....\n\nThe surface area of a right cone (i.e. a cone with its vertex above the center of its base) is:\npi*R*sqrt(R^2+H^2)\n\nwhere R is the radius of the base and H is the height of the cone.
653555
Not considering the spheric harmonic of high orders I would have to tell you that my physics spirit tell the surface area  is what counts and there you could have k0.2Pi.R=2Pi <=>k0=1/R\nk1=1/(2R), k2=1/(distance of the 3 points more away from each other)........................
976222
Area A = area of two ends  +  Curved surfaces.\n  A  =  2π r²  +  2π r h\n\nVolume V = Area of end  x  Heigh.\n  V  = π r²  *  h\n  V  = π r² h\n  h  =  V / π r²\n Now substitute for h into the area formula.\n\n  A  =  2π r²  +  2π r h\n  A  =  2π r²  +  2π r (V / π r²)\n  A  =  2π r²  +  2V / r\nThe volume of the can is 1000cm^3, so substitue in.\n  A  =  2π r²  +  2πV / r\n  A  =  2π r²  +  2000 / r\n\nTake first derivide and let it equat to zero (zero for max. or min. pt.).\n  A  =  2π r²  +  2000 / r\n  δA/δr  =  4π r  -  2000 / r²\n  4π r  -  2000 / r² = 0\n  4π r  =  2000 / r²\n  4π r^3  =  2000\n  r^3  =  2000/ 4π\n  r  =  (2000/ 4π)^1/3    (that is, cubed root).\n  r  =  5∙419 260 701\n  r  ≈  5∙42 cm.\n\nLet's use the r value to calculate h.\n  V  = π r²  *  h\n  1000  = π (5∙419 260 701)²  *  h\n  h  =  1000 /π (5∙419 260 701)²\n  h  =  10∙838 5214\n  h  ≈  10 51 cm.\n\nFor ratio:\n h/r = 10∙838 5214 / 5∙419 260 701\n h/r = 2/1   That is, a two to one ratio.\n\nFor queation two, follow the same proceedure after you set up your formulas.\nLike wise for question three.\n\nWith question two it's not clear what value you are taken for the length of the side of the square edge.  Because you are still using r, I'm assuming you are taken the largest size of a square that fits into the circle or radius r.  Based on this assumsion, the calculations are are follows:\n\nTo identify the length x of one side of the square of radius r:\nDraw two diameters of the circle at 90º to each other.  Where these diameters make contact with the circumference of the circle will be the corner points of the square.  The area of this square now consists of four triangles.  These triangles will have two sides of length r with the enclosed angle of 90º.  So the length of x will be:\n\n x² = r² + r²\n x² = 2 r²\n x = √(2 r²)   That is, length of one side of the square.\n\nArea A = area of two square ends + parameter of square * heigh.\nA = (2r² * 2) + [(√2)r * 4 * h]\nA =  4r²  +  4√(2)r h\n\nVolume V = square area x heigh.\nV =  2 r² * h\nV =  2 r² h\nh = V / 2 r²\nNow substitute for h into the area formula.\n\nA =  4r²  +  4√(2)r h\nA =  4r²  +  4√(2)r V / 2 r²\nA =  4r²  +  2√(2) V/r\nA =  4r²  +  2000√(2) r^-1     (Volume is 1000cm^3).\n\nTake first derivide and let it equat to zero (zero for max. or min. pt.).\nA =  4r²  +  2000√(2) r^-1\nδA/δr = 8r  -  2000√(2) r^-2\n 8r  -  2000√(2) r^-2  =  0\n 8r  =  2000√(2) r^-2\n 8r  =  [2000√(2)] /r²\n 8r^3  =  2000√(2)\n r^3  =  [2000√(2)]/ 8\n r  =  ([2000√(2)]/ 8)^1/3             (that is, cubed root).\n r  =  (353∙55 33 906...)^1/3\n r  =  7∙071 0678 12\n r  ≈  7∙07 cm.\n\nLet's use the r value to calculate h.\nV = 2r² * h\n1000 = 2r² * h\n1000 = 2 (50) * h\n1000 = 100h\n h = 10 cm.\n\nFor ratio:\nh/r = 10 / 7∙071 0678 12\nh/r = 1∙845 270 149 / 1\n h : r  ≈ 1∙85 : 1\nThese ratios do not take into account the scrap metal from the circle when the square is cut out of it.
551690
T= L + 2B\n\nT is total surface area\nL is Perimeter x Height\nB is base area
396424
The curved surface area of the cylinder would be made up of the circumference times the height.  Figure the circumference then divide the surface area by that to get the height.  it would probably be best to convert M2 into cm2 first.  100 cm=1M so 1 sq m would be 100 x 100 or 10,000sq cm x 4m2 equals 40000 cm2.  The C would be 2(pi)r  which is 2 x 3.14 x 70 = 439.6 cm.  Divide 40,000 by 439.6 = 90.99 cm for the height. volume would be (pi)r2h or 3.14 x 4900 x 90.99 = 1399972 cu cm
140062
L x W = Area\n\nCheater
287728
Surface Area = [Base Area] +\n1/2 × Perimeter × [Side Length]\n\nVolume = 1/3 × [Base Area] × Height\n\nThe Surface Area has two parts: the area of the sides (the Lateral Area) and the area of the base (the Base Area). \n\nThe Base Area depends on the shape, there are different formulas for triangle, square, etc. \n\nBut the Lateral Area is surprisingly simple. Just multiply the perimeter by the side length and divide by 2. This is because the sides are always triangles and the triangle formula is base times height divided by 2
802377
Assume that the sphere is centered at (0,0,0)\nStart out by slicing the sphere through its center and looking at the cross section of the sphere and the cylinder. You will have a rectangle inscribed inside a circle.\n\n\nDraw a line from the center of the rectangle to the corner of the rectangle that is in the first quadrant. It will have length r since it is a radius of the sphere.  Let t be the angle the radius makes with the positive x axis. \n\nThe height of the cylinder is   r*sin(t).\nThe radius of the cylinder is r*cos(t)\n\nThe surface area is 2*pi*r^2cos^2(t) + 2*pi*rcos(t)rsin(t)\n\nTake the derivative and find the max.
378913
Do you mean like an object that has a semi-circle on one end?\n\nIf yes, you can find the area of the semi-circle by figuring the area of the entire circle and dividing by half. Then you just find the area of the rectangular portion and add the two answers.
827251
V = πr²h\nA (top & bottom) = πr²\nEnd Area = 2πr²\nLateral Area = 2πrh\nCost of tube = 2πrhC, C being cost per unit area\nCost of ends = 2πr²C*1.2\nTotal cost, P = 2πC(1.2r² + rh)\nh = V/πr², so\nP = 2πC(1.2r² + rV/πr²)\nP = 2πC(1.2r² + V/πr)\ndP/dr = 2πC(2.4r - V/πr²) = 0 for max or min, so\n2.4r = V/πr²\nr³ = V/2.4π\nr³ = 5/2.4π\nr = 0.872"\nh = 5/π0.872²\nh = 2.093"\n\nCheck:\nC(2.4*π0.872² + 10/0.872) = 17.201050C\nC(2.4*π0.87² + 10/0.87) = 17.201444C (+0.000394)\nC(2.4*π0.874² + 10/0.874) = 17.201137C (+0.000087)
250763
you split it into 2 ,a cone and a cylinder. first u need the slanting height of the cone and you find this by pythagorus theory for triangles ie L2 = h2 + r2, so height=6(found by subtracting the 15 from 21) radius=10 (20/2)therefore L2=6x6+10x10=136 therefore L =sqr root of 136 =11.6 surface area is A=pi*r*L\npi=3.142 so 3.142*10*11.6 = 364.5sq ft now the cylinder the surface area of a cylinder is circumference × h, or 2πr × h\nso 2*3.142*10*15 =942.6 so 942.6+364.5=1307.1 sq ft to find quantity of tins 1307.1/250=5.2 so they need 6 full tins you must check the formulas and calculations as I may have made a mistake ok
863802
area=(1/2)d1*d2\n=(1/2)*28*13\n=14*13\n=182 sft
691057
Imagine cutting the tube down its length and opening it up into a long, narrow rectangle.  The outside area would be the length times the width.  The width of the rectangle is really the circumference of the circular cross section of the tube.  Thus, since you know the diameter, you have this:\n\nsurface area = length * pi * diameter\n\nwhere pi is approximately 3.14159265358979.\n\nNote, if the tube is not flexible, you have to be careful measuring the length of the bent tube.  it is the length of an imaginary line through the center of the tube, but as the other answerer pointed out, you can get this by taking the average of the "inside the curve" length and the "outside the curve" length.  Of course, if the tube is flexible, just straighten it out and measure it.\n\n\nNote--straightening, cutting and opening up, etc., will change the area slightly as it stretches part of the tube and compresses another part--this is a very small effect (unless you tie the tube into a tight knot or something) and probably can't easily be measured well anyway--should be too small to matter in most applications.
657525
If you have the equation of the curve then integrate it on the lower and upper limits of the variable. In some cases you can find devide the identical parts and find out area of a single identical part and multiply by the number of parts made (sine wave).\n\nIf shape is a simple square circle etc you can find area by simple formula.
953741
Just break the pentagon up into 5 triangles.  You can then add together the area of the 5 triangles to get the total area.