A group of 5 boys and 3 girls are going to sit together in a row of 8 theater seats...?
913301
i think its 15 cause 5x3=15
133197
For area, make the lesson interactive.  Create a row out of four of your students.  Next, create four more rows for a total of five rows.  Ask the remaining students, "If there are five rows of students, and four students in each row, how many students are there?"  Make them count out loud if necessary or make the children in the rows count from one to 20, thus making your point that there are 20 students total....
985649
being seated by their friends,good smelling classroom,and of course the cute boy.
438798
if 4/12 of 315.\n\nso divide 315 into 12 groups and the total number of people in each group r = 26.25 \n\nnow u take 4 groups of 26.25 members. that means u multiply 4*26.25 = 105.\n\nthen u take 105 and subtract it by 315 cuz there r 315 people in the book club right?\nso its 315- 105 = 210 females in the book club!
232956
cos all of those beautiful girls come in the same bus!, and you know how number 69 buses are!, they all come together!
892421
You could divide the sections in colors and let them choose.  I don't think by age and birthdate is the best approach because it seems the latter months would get put in the back.  As a teacher, I usually let them choose a seat and then I move them around if it is a hinder to the learning process.  Of course, special ed. children need to be seated according to their special needs. Some children with glasses need to be up front and there are some that are too small to be placed in the back of the room.  I usually divide my seats and place half of them on the side looking toward the middle of the room and the other half the same way on the opposite side of the room.  Then you have the two halves facing each other.  It works quite well and my students like hoe "different" it is from their other classrooms.
885158
Let's assume there were 'g' girls and 'b' boys at the beginning.\n\nWith the given assumptions we have,\n\ng-15 = 2b ---- (i)\n\nand\n\ng-15 = 5 (b-45) ---- (ii)\n\nfrom (i) & (ii) we get,\n\n2b=5(b-45)\n\nor, 2b=5b-225\nor 2b-5b = -225\nor -3b = -225\nor b = 75\n\nfrom (i) we get\n\ng-15 = 2b = 2X75=150\n\nso, g = 150+15 = 165\n\nSo there were 165 girls and 75 boys initially \n\ncool
25161
she could have 4, 5, 6, or 7 boys. in any of those cases, at least half are boys.
1162527
Because you are looking for the number of girls in relationship to the total class, you have to figure out what proportion of the total are girls. Out of every 9 students, 4 are boys and 5 are girls, so 5/9 of the students are girls.\n\nG/45=5/9\n\nSolve for G.
298927
there are (2/5)*30=12 boys.  Therefore, there are 30-12=18 girls.  The boy-girl ratio is 12:18 or 2:3.
775941
Well, since the school goes Kindergarten through high school, I would assume there are students in the eighth grade. Unless the school is having trouble recruiting...
318418
First think of a situation involving 4 seats for 4 people:\n\nIn the first chair any of the 4 can sit, in the second, any of the remaining 3, in the third either of the remaining 2 and the last person gets the 4th seat\n\nthe number of combinations is 4*3*2*1= 24\n\nThis is the same for 4 couples since each couple sits together.\nNext, each couple can be in one of two positions because the members of a couple may switch seats and still be sitting together.\n\nthis multiplies the original number of combinations by 2^4 or 16\n\n24*16=384
322091
Only if the girl asked the boy out first before the other boy asked the girl who asked the boy who thought about asking the girl but then asked another girl who is friends with the boy who thought about asking the girl who doesn't like the boy who originally asked the girl about the boy with the girl who looks like a boy.
192695
You have the following lists:\nB B B\nB B G\nB G B\nG B B\nB G G\nG B G\nG G B\nG G G\n\nSo you have 8 variations and of those 3 are 2 boys 1 girl so the probability is 3/8.
913636
if there were 12 groups each with 1 cheerleader in....you will have 12 groups
39943
we are talking about boys\nwe can say not less than 4
301740
well if the men are abc and women are def, then  the arrangement is like adbecf  right?  so   man a is "flanked" by d and f, and man a could also be "flanked" by de or ef so theres 3 different ways man a could sit. for each of these, there are 2 positions the other 2 men could sit in. \n\nso basically its 1 of these:\nadbecf\nadcebf\naebdcf\naecdbf\nafbdce\nafcdbe    \nit doesnt matter which seats they sit on, cuz that will make each man be "flanked" with the same women so u cant have that. all that matters is their order.\nthe answer is c. i hope this makes sense.