Identify the phenotype of a rabbit with the genotype Bb, where B= black coat and b= brown coat.?
921345
hey im doing this in class too. the phenotype is black because the the black is dominant. whatever the capital letter is, that is the dominant trait. if the genotypes were: BB or Bb, the phentype is still dominant. The only difference is that BB is a homozygous trait; meaning that homosygous trait is the same trait or identical trait. Bb is heterozygus trait meaning that it is two different traits.
796672
OK, draw yourself up a nice big checkerboard with 16 squares! Down the left hand side, write beside each square the 4 possible gametes produced by 1 parent - for parents with the genotypes you have given above, the gametes produced are: AB, Ab, aB, ab - this is because each egg or sperm produced will have only half the number of genes of the parent (so ONE copy instead of 2) so that when the egg and sperm meet, they will have 2 copies of each and not more!!! So the gametes will have ONE copy of the 'A' gene (which may be either the dominant 'A' allele or recessive 'a' allele - half the gametes will get one type of allele and half the other) and the same goes for the 'B' gene, to produce the possible gamete types above. Then, along the top of your little checkerboard diagram, write above each of the 4 squares the 4 possible gamete types for the SECOND parent - which in your case, are the same as the first!\n\nNow - you want to fuse your eggs and sperm to produce offspring! Do this by combining the gamete genotype of 1 parent with that of the other in the box where they meet up - eg if your very top left-hand square has the genotype 'AB' above it, and 'AB' to the left of it, then the genotype of the offspring produced will be AABB - homozygous for both! And the square 2 down from the top, in most left column, might be combining the gametes 'Ab' with AB - producing offspring AABb, which is homozygous for gene 'A' but not for gene 'B'.... and so on and so forth for the rest of the squares!\nI WOULD RECOMMEND DRAWING UP THIS SQUARE TO SHOW YOUR WORKING - YOUR TEACHER WILL BE WANTING TO SEE THAT!\ndouble homozygotes are AABB, AAbb, aaBB, or aabb...
627126
check out the picture :\nhttp://www.edhelper.com/AnimalReadingComprehension_61_1.html
117941
Go to the Quest Diagnostics site, and type in Bun.\nhttp://www.questdiagnostics.com/kbase/topic/medtest/hw4322/results.htm
901637
Let B mean the genotype for dominant black fur and b mean the genotype for brown fur. \n\nRecall that when a gene is dominant, it is always expressed when  it is present. When a gene is recessive then it is ONLY expressed  when there is no alternative.\n\na) Pure black mice would have B1B2 and brown mice must be b1b2 because it is a recessive gene. (I've put in the numbers to act as subscripts so it makes more sense.) Crossing these, you would get offspring that inherit one gene from each parent.\nB1b1 ==> black\nB1b2 ==> black\nB2b1 ==> black\nB2b2 ==> black\n\nSo false because all the offspring from pure black and brown rats would be black. \n\nb) True. Pure black mice have BB. As both parents have BB then there's not a chance for bb to occur!\n\nc) False. Brown mice are always bb (recessive) so bb x bb can never result in Bb or BB. So offspring of 2 brown mice are always brown.\n\nd) Heterozygous black mice are Bb. So crossed with brown mouse bb (b1b2):\nBb1 ==> black\nbb1 ==> brown\nBb2 ==> black\nbb2 ==> brown\nSo you get equal numbers of black and brown offspring. True.
1029267
doodee?  seriously?\n\nnot sure how this related to biology, since biology is the study of LIVING things.\n\nbut what else could be brown and red?  a robin?
591863
The answer is "b"\n\nAssuming the dwarf characteristic is recessive, since about half of the offspring were dwarf, that means that half the offspring have to by homozygous for the dwarf genotype (tt).  The only way to get that is to cross the Tt and tt.  Thus you get half the offspring being Tt (tall) and half being tt (dwarf).  If you cross a homozygous dominant (TT) with anything else, all the offspring will be tall, because all will carry at least 1 "T" gene.  If you cross "Tt" and Tt" then you get 1/4 TT (tall), 1/2 Tt (tall), and 1/4 tt (dwarf).
95947
A) Both the genotype and phenotype would be roan\nB) 1/2 you would get roan(Rw)and 1/2 white(ww)
272838
1 is false. It is the other way around. Genotype determines phenotype.
696944
It depends on what kind you have.  I used to have 4 different rabbits... The himalayan ones are really nice but really freaky looking! If you want one, that's the one I'd suggest!
36000
The blood types are A, B, AB, and O. Additionally, you can either be Rh+ or Rh-\n\nso in total the blood type possibilities are\nA+\nA-\nB+\nB-\nAB+\nAB-\nO+\nO-\n\nhope that helps.  If you are looking for the genetics codes thats different....be a little more specific in that case...
966795
I remember something like this in biology\n\nI am not going to do your homework for you, but you start by finding the percentages of phenotypes
632744
B- brown (dominant), b- blue (recessive)\n\nChildren's phenotypes: both blue\nChildren's genotypes: both bb\n\nParents phenotypes: both brown\nSo, both parent must be heterozygous for eye colour:\nParents genotypes: both Bb
151482
Try here\nhttp://www.genomesize.com/search.php\nThey have a good searchable database, see the column labeled "Ch" for chromosome diploid number.
673764
first all blood has 3 genes a,b,o.  A and B are both dominant while o is recessive.  A person with A phenotype blood can have a genotype of AA or AO.  Same with the B phenotype blood except only with B.  AB phenotype is the same as the genotype AB and same goes for O.  OO phenotype can only be seen as OO genotype.  When people do the nasty and mate each one type is paired with another.  For example an AO phenotype person and an B0 phenotype person can have a babies as AB,AO,BO,OO.  The punnet square all depends on two peoples blood type and the possibilities of the childs when they mate, you cannot make a square of an individual.
94669
Yes, it is possible. The type B person could be type BO and the B is dominant so they are type B. The type A person could be type AO and the A is dominant so they are type A. If a BO person and an AO person have children, they're children have 25% change of being type O.
543487
Well, being as I've never had a curly wurly long enough to measure it against a rabbit I really can't say, but I would guess at the rabbit being bigger. (Fancy people not knowing what a curly wurly is!)