w^2=16w      solve this equation?
928253
w² = 16w\nSo w² - 16w = 0\nSo w(w - 16) = 0\nSo either w = 0 or w - 16 = 0\nTherefore w = 0, 16
838263
so\n\n2l+2w=230\n\nl=2w-5\n\n2(2w-5)+2w=230\n\n4w-10+2w=230\n\n6w-10=230\n6w=240\nw=40\nplug and find\n\n80+2l=230\n\nl=75
810055
x^2 - 2x + y^2 + 2y + 2 = 16\n\nx^2 - 2x + 1  + y^2 + 2y + 1 = 16\n(x - 1)^2 + (y+1)^2 = 16\n\nCenter = (1, -1)\nRadius = sqrt(16) = 4
287893
l = 4w + 15\n\nArea = l * w\nArea = (4w + 15) * w,  then\n\nArea = 4w2 + 15w
897198
6w+60=124-10w\n16w=64\nw=4\n\n4weeks
190781
A perfect square for this question is in the form of (a-b)^2 which is the same as a^2-2ab+b^2\n\nConsider u^2-16u+c = a^2-2ab+b^2\nSo 'u' equals 'a' and -16 equals -2b. Therefore, b=8 and since C=b^2, the answer is 8^2 or 64.
1073032
Urs is wrong.Here is the correct answer.------>\nGiven equation, 16 x^2 +25 y^2= 100\n\n=>  x^2/(100/16) +y^2/(100/25)=1\nWe know,\ne= square root over[ 1-b^2/a^2]\n\nso, here b=100/25 and a=100/16\nTherefore, e=sq root over[ 1-(16/25)]\n after simplification e=3/5 or 0.6.
1080496
lwh = 162\nl = 2w\nh = 3w\n\n2*3*w*w*w = 162\n6(w^3) = 162\nw^3 = 27\nw = 3\n\ntherefore, w = 3, l = 6 and h = 9
815860
Hello Dear \n\n- Take " √ " of eachsides\n√16y^2 =  √ 25 \n± (4y = 5)\ny = ± 5/4\n\nGood Luck dear.
740569
1) L = 4W\nA = LW = 20\nSubstitute L = 4W to get 20 = 4W x W\n20 = 4W^2, divide both sides by 4 to get\n5 = W^2, take square root of both sides to get W\nW = √5\n\n20 = L x W\n20 = L x √5, divide both sides by √5 to get L\nL = 20/√5 or, when rationalized, 4√5\nFinal answer:\nL = 4√5 and W = √5\n\n----\n\n2) L = W + 4\nA = 6 = L x W, substitute L = W + 4 to get\n6 = (W + 4) x W\n6 = W^2 + 4W, substract 6 from both sides to get\n0 = W^2 + 4W - 6\nThis is not easily factored, so you'd have to use the quadratic equation to solve for W. Once you have W, just plug that in to L = W +4 to get the L value. Good luck!
1187393
SA = 2lw + 2lh + 2wh\n= 2(lw+lh+wh)\n= 2(8*6 + 8*2 + 6*2)\n= 2(48+16+12)\n= 2(76)\n= 152 centimeters squared
882001
Your equation f=wl/c is wrong. It should be f*wl = c. In that case\nf'*wl' =  f(1 + (v cos theta/c)) *  wl(1- (v cos theta/c)) = \nf * wl * (1 - (v cos theta/c)^2) = f * wl = c\nas long as v/c is much smaller than 1
963947
assuming you meant:\nP=2(L-W)\nthen\nP/2 = L-W\nand so\nL= W+ P/2\n[
757630
h=w+7\nl=3w-5\n\nh+w+l = w+7+w+3w-5 = 5w+2\n\nSo the correct answer is C.
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
952983
2y = x + 16 - - - - -Equation 1\n5x + 10y = 0- - - - Equation 2\n- - - - - - - - - - - -\n\nRearrange equation 1\n\n2y = x + 16\n\n-x + 2y = x + 16 - x\n\n-x + 2y = 16 - - - -equation 1 rearranged\n- - - - - - - - - - - -\n\nMultiply equation 1 rearranged by 5\n\n5(-x) + 5(2y) = 5(16)\n\n- 5x + 10y = 80- - - - New equation 1\n\n- - - - - - - - - - - -\n\nElimination of x new equation 1 and equation 2\n\n- 5x + 10y = 80\n5x + 10y = 0\n- - - - - - - - - -\n20y = 80\n\n20y/20 = 80/20\n\ny = 4\n\nThe answer is y = 4\n\nInsert the y value into equation 1 \n\n- - - - - - - - - - - - - - - - - - - - - - - -\n\nSolving for x\n\n2y = x + 16\n\n2(4) = x + 16\n\n8 = x + 16\n\n8 - 16 = x + 16 - 16\n\n-8 = x\n\nThe answer is x = - 8\n\nInsert the x value into equation 1\n\n- - - - - - - - - - - - - - - - - - - - - -\n\nCheck for equation 1\n\n2y = x + 16\n\n2(4) = -8 + 16\n\n8 = 8\n\n- - - - - - - - - -\n\nCheck for equation 2\n\n5x + 10y = 0\n\n5(- 8) + 10(4) = 0\n\n-40 + 40 = 0\n\n0 = 0\n\n- - - - - - - - -\n\nThe solution set is { -8, 4 }\n\n- - - - - -s-
285238
you can take 9v^2 out and then it becomes a simple quadratic equation\ni can give u d ans \nit will be\n\n9v^2(v+2)(v+1)\ni hope u understood