what is the calculation to find composite r-value?
919629
I'm supposing that by R-value you mean resistance value.\n\nIf so, there are two separate formulas. \nFirst for R-values in series, meaning, materials which are layered: \n\nRtotal =R1 + R2 +...+ Rn\n\nFor R-values in parallel, meaning two or more materials side by side:\n\n(1/Rtotal) = 1/R1 + 1/R2 +...+ 1/Rn
648512
r^2 + 16r + 64 = r^2 + 784\n16r = 720\nr = 45
871386
∫udv = uv - ∫vdu\n∫x^2dx/√(1-x)\nlet u = x^2, dv = dx/√(1-x)\ndu = 2xdx, v = -2√(1-x)\n∫x^2dx/√(1-x) = -2x^2√(1-x) + ∫(4x√(1-x))dx\nu = 4x, dv = √(1-x))dx\ndu = 4dx, v = -(2/3)(1-x)^(3/2)\n∫x^2dx/√(1-x) = -2x^2√(1-x) - (8x/3)(1-x)^(3/2) + ∫(8/3)(1-x)^(3/2)dx\n∫x^2dx/√(1-x) = -2x^2√(1-x) - (8x/3)(1-x)^(3/2) - (16/15)(1-x)^(5/2)\n∫x^2dx/√(1-x) = √(1-x)(2x^2 - (8x/3)(1 - x) - (16/15)(1-x)^2)\n∫x^2dx/√(1-x) = √(1-x)(2x^2 - 8x/3 - 8x^2/3 - (16/15)(1 - 2x + x^2)\n∫x^2dx/√(1-x) = (1/15)√(1-x)(30x^2 - 40x - 40x^2 - 16 + 32x + 16x^2)\n∫x^2dx/√(1-x) = -2√(1 - x)(x(3x + 4) + 8)/15
1116823
Isolate your variable by dividing by -3 to get -5 for y.\n\nsubtract 8 and divide by -1 to get -4 for r.
605453
The (r+1)st term of (x+y)^n is\nC(n,r)x^(n-r)y^r, where C(n,r) is n choose r\n\na) n = 4, r = 2, x = a, and y = 5b\nC(4,2)a^(4-2)(5b)^2\n=6*a^2*25b^2\n= 150a^2b^2\n\nb) n = 9, r = 4, x = 2m, y = -k\nC(9,4)(2m)^(9-4)(-k)^4\n= 126*2^5m^5*(-k^4)\n= 126*32m^5(-k^4)\n= -4032m^5k^4\n\nc) n = 8, r = 5, x = 3x, y = -2y\nC(8,5)(3x)^(8-5)(-2y)^5\n= 56*(3^3)x^3(-2)^5y^5\n= 56*27*(-32)x^3y^5\n= -48384x^3y^5\n\nNow try the other two using the above formula.
770136
P = Ae^rt\nP = 100e^(.2*52)\nP = 100 * 32824.21\nP = 3282421
744496
A row of AB is of the form RB where R is a row of A. Now, if\nR1, R2, ...Rk are linearly dependent, there are constants c1,..ck\nwhere\nc1*R1+c2*R2+..ck*Rk=0.\nNow apply B on the right to get your result.
92762
A = P + Prt\n\n==> P(1 + rt)\n\n==> P = A/(1 + rt)\n\n<done>
734014
AIR, WOOD,  stone, (insulation)\n\nR-value\nThe R-value of a material is its resistance to heat flow and is an indication of its ability to insulate. It is used as a standard way of telling how good a material will insulate.The higher the R-value, the better the insulation.\n\nDefinition\nThe R-value is the reciprocal of the amount of heat energy per area of material per degree difference between the outside and inside. Its units of measurement for R-value are:\n\n(square feet x hour x degree F)/BTU in the English system and\n\n(square meters x degrees C)/watts in the metric system\n\n\n\nMaterial\n R-value\n \nHardwood siding (1 in. thick)\n 0.91\n \nWood shingles (lapped)\n 0.87\n \nBrick (4 in. thick)\n 4.00\n \nConcrete block (filled cores)\n 1.93\n \nFiberglass batting (3.5 in. thick)\n 10.90\n \nFiberglass batting (6 in. thick)\n 18.80\n \nFiberglass board (1 in. thick)\n 4.35\n \nCellulose fiber (1 in. thick)\n 3.70\n \nFlat glass (0.125 in thick)\n 0.89\n \nInsulating glass (0.25 in space)\n 1.54\n \nAir space (3.5 in. thick)\n 1.01\n \nFree stagnant air layer\n 0.17\n \nDrywall (0.5 in. thick)\n 0.45\n \nSheathing (0.5 in. thick)\n 1.32
193438
the 6^2 will divide out, and then you have to multiply the 2 with all the exponents on the inside....oh and r^0 is just one....so i think the answer would be t^-10 \nPS i just changed this answer, realized i made some stupid mistkae :-)
659812
r^2 + 16r + 64 = r^2 + 256\n16r + 64 = 256\n16r = 192\nr=192/16 = 12
791344
R = [ a^2 + b^2 -2*a*b* cos(theta), where  theta is the angle between a and b.\nIf a and b are fixed,\nR is max when  cos(theta) is min.   \nMin value of cos(thete) = -1  at  thete = 180 degree
496307
Tf = 9/5 Tc + 32\n\nor \n\nTf = (1.8)Tc + 32
435632
and the formula is:\n\ndB = k I dl sin theta / r^2\n\nwhere k = mu0/4pi
889826
Hi, \n\nI think you are referring to the r-squared value of an equation that models a set of data. Often times when we plot a set of data, we want to find a relationship between the points that reveals an underlying relationship. In some cases, that relationship is linear, that is all the points lie roughly on a line.\n\nThe R-squared value tells you how well your line fits the points that you've plotted. It's simply a way of judging how good your approximation is.
724685
r-s = t\nadd s to both sides\nr = t+s
958486
Rs=Im*Rm/Is\n\nRs*Is = Im*Rm\nRm= (Rs*Is)/Im\n\nc=(8.85*10^-12)(K)(A/d)\nc*d = (8.85*10^-12)(K)(A)\nd= [8.85*10^-12)(K)(A)]/c\n\ny=mx+b\nb=y/(mx)\n\nx= (y-b)/m\n\nLm=(Lt-L1-L2)/2\n\nE=Q/C\n\n1/Rt - 1/R2 = 1/R1