Evaluate x² – 1/x² given that x = √2 + 1/√2 – 1?
912271
(495/98)-((159*√2)/2)\nor\n.462041705769\n\nDepending on which form u need it in.
707304
1/(x - 1) = (x + 2)/4\ncross multiply\n4*1= (x-1)*(x+2)\n4 = x^2 +2x - 1x -2\n4 = x^2 + x -2\n0 = x^2 +x -6\n0 = (x+3)(x-2)\n\nso x= either -3 or +2\npositive = +2
736337
2/x + 3 = 2\n2/x = -1\n-x = 2\nx = -2
902917
y=1/x^2-3 => y+3 = 1/x^2 => x= +/-sqrt(1/(y+3))
670503
The answer is x2+2x-4 with a remainder of 11/(x+1)
618071
simplify to f(x)=(sqrt(x-2)(x-3))/(x-4)(x+5)\nthen sub in 1/x\nto get (sqrt(1/x -2)(1/x -3))/(1/x -4)(1/x +5)
887664
let u = x^2\ndu = 2x dx\n\nThis turns the function in to:\n1 / (u^2 + 1) - which you can work from.
607013
Another Method.\n\n-1 = -1\n\n-1/1 = 1/-1\n\nSquare root both sides,\n\nSQR(-1/1) = SQR (1/-1)\n\nExpanding,\n\nSQR(-1)/SQR(1) = SQR(1)/SQR(-1)\n\nSQR(-1)/1 = 1/SQR(-1)\n\nCross Multiply,\n\nSQR(-1)*SQR(-1) = 1\n\n(SQR(-1))^2 = 1\n\n-1 = 1\n\nDivide by 2 on both sides,\n\n-1/2 = 1/2\n\nAdd 3/2 to both sides,\n\n-1/2 + 3/2 = 1/2 + 3/2\n\n1 = 2 (ans)
586893
If its differentiate x * sqrt 1 + x^2 , the answer is\n  1 + 2x ( since sqrt 1 is a constant and d x^2/dx = 2x)\n\n \nIf your question is sqrt1 + x^2 answer is 0 + 2x = 2x
185700
It's bringing the √2 out from the brackets. \n\nMultiply 1+(3/2) by 2... what do you get? 2+(3)\nMultiply 1+(√3/2) by √2.. what do you get √2+(√3)
46351
Sy   = |x| - x^2 + 2   \n     = (x^2/2) - (X^3/3) + 2X
756563
1/2-x<3\nadding x-1/2\n0<x+5/2\nadding -/2\n-5/2<x\n-1/2+x<3\nadding -x+1/2\n0<-x+7/2\n-7/2<-x\n7/2>x\nx<7/2\nso answer is\n-5/2<x<7/2\ninteger values are -2,-1,0,1,2,3
435571
Given: f(x) = 2x - 1 and 1/2*f(√(t)) = 4. \n\nThen f(√(t)) = 8 where f(√(t)) = 2*√(t) - 1. \n\nSo, we must solve the equation 2*√(t) - 1 = 8 as follows\n\n2*√(t) - 1 = 8\n2*√(t) = 9\n√(t) = 9/2\nt = 81/4.
949784
y= (x^2 - 1)^2\nx^2-1=+/-√y\nx^2=1+/-√y\nx=+/-√(1+/-√y)
714589
x/(x+3) - 2(x-1)/(x+3)(x+2)\n\nx(x+2) - 2 (x-1)\n--------------------\n   (x+3) (x+2)\n\n\nx^2 +2\n----------\n(x+3)(x+2)
927818
2(x - 3) = 2\n\n2(x - 3) / 2 = 8 / 2\n\n(x - 3)² = 4\n\n√(x - 3)² = √4\n\nx - 3 = ± 2\n\nx - 3 + 3 = 3 ± 2\n\nx = 3 ± 2\n\n- - - - - - - - - \n\nSolving for ( + ) \n\nx = 3 + 2 \n\nX = 5\n\n- - - - - - - - - \n\nSolving for ( - )\n\nx = 3 - 2 \n\nx = 1\n\n- - - - - - - - -s-
1147786
x - sqrt(x) = 0\nx = sqrt(x)\nx^2 = x\nx(x-1) = 0\nx = 0,1\n\nBoth check.