Using the equations below?
353265
Hess's law \n\n\n +142KJ  that is all you want "right" is the answer
712820
write them so they can be added top to bottom (i.e. line up the x's, y's, and constants):\n\n4x + 2y = -4\nx - 2y = -3  (we need to rearrange the original equation here to line things up)\n\nnow add top to bottom:\n\n(4x)+(x)  +  (2y)+(-2y)  =  (-4)+(-3)\n5x + 0 = -7\n5x = -7\nx = -7/5\n\nnow plug x in to either equation to solve for y:\n\n2y = -7/5 + 3\n2y = -22/3\ny = -22/6 = -11/3\n\nHope this helps :)
81494
I'm getting some funky answers on these equations\n\nx= -48/7 and y= -156/7
268888
I think I can do this one...I'll get right back to you when I figure it out... *grabs a pen and paper...and also tries to figure out why people are answering, saying simply that they can't or won't answer your question*\n\nEDIT...k, here's what I got...not sure if I understood what your question was asking, so I may be mistaken...\n\nm=h(x)-2x\nk=(2-3h(x))/6x
953940
Hi again \n\nY = √2x – 3 \n2x – 3 = y ²\nX =( y ² + 3 )/ 2\nf –¹ (x)  =( y ² + 3 )/ 2  =>   f –¹ (x)  = (x ² + 3 )/ 2   &  x ≥ 0 \n\nGood Luck \n try to solve them yourslef again if you got wrong , am sure you can solve them correctly , if you just try your best
1046507
[2x/(x+3)(x-3)]*[(x-3)/4(x)]\ncancelling 2 and x-3 we will get\n=x/(x+3)2(x)\nsimplify we will get\n=x/(2x^2+6x)
851212
hmm im not quite in college yet, but i hope to be help.\ndo you know the values for f, h, v, and a?\nif you do, id substitute it in.\nthen square both sides. \nand then solve.
421380
from first equation put the value of b in second and then form a second degree differential equation in "a"...good luck!
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
962403
2M = wx(L-x)\n\n(2M)/w = x(L-x)\n\n2(50N/m) / (5N/m) = x(20m-x)\n\n(100N/m) / (5N/m) =\n\n(20 N/m) = \n\nsorry i couldn't get an answer\nthat is as far as i can get\nit might help a little bit though
240687
4m+H-(4m-h) =\n4m+H-4m+h=\n4m-4m+H+h=\n0+H+h=\nH+h
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
73319
the earlier equation is not balanced.\nCaO + 2HCl --------> CaCl2 + H2O
216060
H2CO3 + 2 NaOH -> Na2CO3 + 2 H2O
761108
p= 2L + 2 W \n2w=p-2l\nw=(p-2l)/2
950045
Correct formula should be as follows:\n\nE = 1/2*I*w^2
586753
1. p1=3.0atm        \n   v1=15mL\n   p2=2.5atm\n   v2=?\n\n(3.0x15)/2.5=18mL\n\n2.t1=(-35+273)=238       \n  v1=75.0mL\n  t2=(25+273)=298\n  v2=?\n\n(298x75.0)/238=93.9mL\n\ni think it's right. i hope it helps.