Answer the question.  Use the commutative/associative laws to rewrite the expression.  List each step.?
343754
This is the shortest solution:\n\n(z9)4\n= z(9*4) = z*36 (associative law)\n= 36z (commutative law)\n\nHope that helps!
1075484
Make a fist with your right hand.\nUncurl your right index finger and point it at this text.\nExtend your right thumb so it points straight up.\nUncurl your right middle finger so that it points to your left.\n\nVector I in the direction of your index finger\nVector M in the direction of your middle finger\nVector T in the direction of your thumb.\n\nI X M = T, that is if you take the vector cross product of I and M the direction of the cross product will be in the direction of T.\n\nIn 3-space,   (1,0,0) X (0,1,0) = (0,0,1)  \nSimplely stated:  (i X j = k).
978671
[i]  = I\n[d]s = does (without the s it would be do)\n[t]  = to or the\n[o] = of\n\nAnyway I think all the [ ] are suppose to be abbreviations and these are the most likely.◘
700951
4x + 6 is not quite right\nwatch the order of operations and distributive properties\n\nrepost your answer and I'll tell you if you got it\n\n(you didn't think I'd just give up the answer, did you ?)
794610
You have to do the equations in the [ ] first.\nThen you have to do multiplication before addition.\nHere's the order of how you should do math like this:\nP - Parenthesis\nE - Exponents (a number to the something power)\nM - Multiplication\nD - Division\nA - Addition\nS - Subtraction\n\nSo you do [2+6(-3)] first\n[2-18]\n[-16]\nNow it's 15-3[-16]\n15+48\nAnswer: 63
973508
Constructing an NFA for this is pretty trivial.  First state loops back to itself on a,b.  Go to the second state on b.  Go to the third state on a.  Go to the fourth state on a or b.  Go to the fifth accepting state on b.  From that you could construct a DFA.\n\nTo do a DFA from scratch, in the first state you'd just keep looping as long as you see a.  Once you see a b, go to the second state.\n\nIn the second state (we got a b), if you get another b, go back to the first state.  If you see an a, go to the third state.\n\nIn the third state (we got a b followed by an a), on a, go to a fourth state.  On b, go to a fifth state.\n\nIn the fourth state (we got baa), if you get a b, you have a match, so go to the sixth accepting state.  If you get an a, you have to start over, so go back to the first state.\n\nIn the fifth state (we got bab), if you get a b, you have a match, so go to the sixth accepting state.  If you get an a (and this part is tricky), you STILL have ba.  So instead of going back to the first state, go to the third.\n\nIn the sixth state, which is accepting, if you get an a or a b, you just go back to the same state (cuz you already found the substring).
1025267
Here is how:\n\n6+6+3\n6+5+4\n5+5+5\n\nnow change the first two around until you have all the possiblities.
954003
it is from a logic work sheet.  directions are find the next item in the pattern.  examples:  12321, 23432, 34543, 45654\na, z, b, y, c, x, d\ntam, tan, rib, rid, rat, raw, hip
794749
This shall work.\nhttp://pubs.logicalexpressions.com/pub0009/LPMArticle.asp?ID=305
1001971
[(16x*2-25) / (24x*2-30x)] / [(8x*2-2x-15) / (6x*2-7x-3)]\n= [(16x*2-25) / (24x*2-30x)] [(6x*2-7x-3) / (8x*2-2x-15)\n= [(16x*2-25) (6x*2-7x-30] / [(24x*2-30x) (8x*2-2x-15)]\n= [(4x-5) (4x+5) (3x+1) (2x-3)] / [(6x) (4x-5) (4x+5) (2x-3)]\n= (3x+1) / 6x
766449
(-x/4+ 5/6) * 12 < (4x/3 +2) * 12 (mulitply both sides by 12)\n\n-3x +10 < 16x + 24\n\n-3x-16x +10-10 < 16x-16x + 24-10 (move all variables and numbers to one side)\n\n-19x< 14 (divide both sides by 19)\n\nx < -14/19\n\n* means times\n\n(-n/5 + 6) * 5 > n *5 (multiply both sides by 5)\n\n-n + 30 > 5n\n\n-n + n +30 > 5n +n (move all varialbes to one side)\n\n30 > 6n (divide both sides by 6)\n\n5>n
917224
Simply use correct order of operations\n\nparentheses\nexponents\nmult/division (from left to right)\naddition/subtraction (from left to right)
459181
Is the symbol "&" just a part of the problem?\n(&2)m\nCommutative law of multiplication says you can switch the order in which things are multiplied.\n&2 = 2&\nThus,\n(&2)m = (2&)m\nThe associative law of multiplication says you can move the parentheses.\n(2&)m = 2(&m)
157474
I do not believe this is always true, only in the case of commuting matrices.\n\nLet A'=A\nLet B'=B\n\nThen (AB)' = B'A' = BA\n\nBut AB is  not always equal to BA unless A and B commute.
887323
1 4 2 5 3\n\nBut it's cyclical, so the sequence is 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 ... and so on.\nYou can start anywhere in the sequence. The first answer you received is correct, but that person chose to start with 3 instead of 1.
885883
for example\na/b\n---- = ad/bc\nc/d\n \n\na/b + c/d = (ad +cb)/ad\n\na/b -c/d =( ad- bc) /ad\n\n(a/b)(c/d)= ac/bd\n\nx
538949
Can you rewrite this- it doesn't make any sense