a cube made of sturdy material with a total volume of 1.0 Liters?
349692
10cm on a side. I think this is what you want.
98651
With the dimentions of the container, calculate its volume. One cubic foot = 7.48 gallons.
306191
a) cube...final answer
797243
there are different formulas for volume.
401376
1 liter is 10 cm x 10 cm x 10 cm. this is 1/1000 of a cubic meter.
166652
For a specific kind of solid, yes.  In general, no.\n\nFor example, a cube with a side length of s will have a volume of s^3 and a surface area of 6s^2.  So, for any cube, the volume and surface area will be in the ratio of s/6.\n\nFor a right cylinder, the volume is (pi)r^2*h, while the surface area is given by 2(pi)r^2 + 2(pi)r*h, which through some algebraic manipulation can be reduced to 2(r+h)(pi*r).  So the ratio of volume to surface area for a cylinder will be r*h to 2(r+h)... \n\nFor other solids, you could observe similar relationships, but in general, the relationship depends on the shape of the solid, so you could not make a definitive statement about the surface area enclosing a certain volume unless you also knew what shape that volume was in.
74771
hecka!!  damn.  i miss california.\n\nwhat you have to do is realize that this question is asking about the volume of a rectangular shape that is 1 meter by 1 meter by X meters, where X is the height of the column.\n\nso, you know the density.. density is defined as mass divided by volume.  and you know the weight.. which is mass times acceleration.  here the acceleration is the acceleration of gravity "g" = 9.8 m/s^2.  \n\nso you can do a little algebra to get the equation volume = mass / density \nvolume = weight / (acceleration * density)\n\nyou know the weight (100,000 N), the acceleration (9.8 m/s^2) and the density (1.2 kg/m^3).  plug those numbers in and you get the VOLUME of the atmosphere, and since you know 2 of the dimensions of the box (it is 1 square meter across the bottom face, remember) you can figure out the 3rd pretty easily.\n\nsince this is your homework i wont just tell you the answer, but you should be pretty much able to crank it out from here.
16584
You can find the volume using a triple integral
645515
hahahah, really i must say one thing about thsi question , this question relly confused all the guys so far answered it. \nok listne, the dimention is not fixed. when u try to minimize a surface area while keeping the volume constant u tend to form a sphere, think of a ball which can be inflated, when the ball is fully inflated, its totally perfect sphere and then it cant be deformed to anyother shape with ur hands.ths is just tru with sphere and not with cube or anyother shape, other shapes can always be deformed\nso a shape which has its surface area and volume same is never a sphere can thus it can be deformed to any shape keeping its surface area and volume same.\nso the ans to this question is : NO DEFINITE SHAPE
408620
an extremely low value of 1.1 × 10-6 Ω·m but the interesting thing is it almost never varies with changes in physical conditions(actully only but higly small amounts) and so it is used to make standard resistance boxes.
93491
shape it into a brick divide its mass by its volume
1081095
Consider an animal weighing 100 kg. If all his dimensions suddenly are multiplied by two, than it's volume and weight will be multiplied by 2x2x2 = 2^3. This argument results already in L(W) scaling as W^0.333. Close enough.
524937
look here\nhttp://education.yahoo.com/reference/weights_and_measures/index?p=volume
425258
volume = height X width x depth\nv = h x w x d\nv= 11 x 16 x 24\nv= 4224 inches^3 ( inches cubed )
45100
To get the greatest surface area to volume the boxes would be spheres.\n\nWhy not?\n\n1) Spherical boxes would be hard to make\n\n2) They would roll off the sheleves in the stores\n\n3) People would slip on them, fall, and then sue the cereal companies and the grocery stores.\n\n:)
1080952
mass, volume and temperature.
329557
Try this....\n\nhttp://www.efunda.com/formulae/solid_mechanics/mat_mechanics/pressure_vessel.cfm