how do you determine an ordinary high water line?
347856
Ordinary high water line is where normal vegatation stops and river gravel or stone begins.  You're neighbor needs to be educated, which will be impossible if he's NASCAR fan.
517312
300 meters (or 1000 feet) is about as far as a human being can go without the aid of a vessel. Dive depth records are a little over 300 m.\n\nThe Eiffel Tower is 300 meters tall, which is not very far at all considering how deep the ocean goes. The ruins of the Titanic, for example, are at a depth of 3,800 meters (which is about 2.5 miles). The pressure at that depth is over three tons per square inch - enough to crush you in an instant!
946895
Let the height be h (inches), radius r.\n\nNow by proportion, h = 5r at every level.\n\nHence volume is given by\n\nV = (1/3)pi*r^2*h which is\n       (5/3)*pi*r^3\n\n"Rate at which water is drained" means find dV/dt\n\ndV/dt = 5*pi*r^2*(dr/dt),\n\nand dr/dt = (1/5)*(dh/dt)\n               = -2/5\n\nYou can finish from there.
963866
Cover one end of your garden hose with clear plastic (like Saran Wrap) and wrap rubber bands around it to hold the plastic in place.  Then remove your garden hose from the faucet and cover the faucet end of the garden hose with plastic wrap and use rubber bands to hold that in place as well.  Lay down the garden hose over a relatively flat area of the ground where you wish to determine level elevation.  Then look at each end for air bubbles.  (Make sure the garden hose isn't draped over a hill, or this procedure won't help.)\n\nIf you find air bubbles at one end of the hose, it means that end is at a higher elevation than the other.  Move the bubble end of the garden hose, without moving the other end until the bubbles leave the plastic.  Then check the other end of the garden hose.  If you find bubbles, move that end only until the bubbles leave the plastic.  \n\nRepeat this procedure until you don't see bubbles at either end.  That is when the ground is level along the length of the garden hose.
1062484
if you are asking an instrument to measure a parameter outside of its design range, then it is not possible to state with accuracy how reliable the measured value is.  Your best bet is to look at the equations for flow through an orifice and see if the pressure drop is linear, or not, or what the relation is.  You might be able to extrapolate a resaonable approximation of the true flow if it is not too far away from the 3000 value.  If the meter was reliable below 3000, the manufacturer would have stated so.
927347
Draw lines from the top of the vertical lines in the H to the opposite lower corners. There you go.\n\nIn response to the comment below:\nBTW\nI guess the middle line of the H would have to be not directly centered between the lines.  It has to be a little highter or lower so the 2 lines do not intersect on the center line.  Then you come out with 5 individual triangles and not triangles within triangles.
431380
If the pressure is 0.76m of Hg, it is equivalent to 10.3 m of water. There is a vacuum in the tube above this water height.\n\nHowever, by “vacuum” we mean inside this space, the pressure is low. There will be vapour of water which will have some pressure.\n\nEven in mercury barometer, there will be mercury vapour inside the “Torricelli’s vacuum”.  \n\nThis is the reason that ordinary pump which sucks water from a well or sump is not able to lift water to a height more than 10m from the surface of the water.
613715
First find the volume of the object, i.e metal, by placing it in water and then u know the amount of water displaced.\nIf it displaces half the water than it's weight, then u know that it's specific gravity is twice that of water.
1051954
All you need to do is know the density of water- not too difficult to find! THe psi necessary to support a column then must match the weight of that column. So, if a column is 1inch in area and Hinches high, if you know D the density of water per cubic inch in pounds, the height of the column in inches times this value is the psi needed.\n\nPressure psi=H*D\n\nThis also works for metric, just use cms and kgs as the base sizes.
888281
Contour lines on a map are set at even intervals.  The high points on a hill or mountain are rarely an exact number of feet.  The top would be represented by a point with the elevation next to it.
164771
Very wet!\n\nTry it yourself.  Take a sprinker head and put in on a hose up as high as you can support it.  Place a bucket below.  Turn on the water and adjust it until you get your 1.5 inches per minute in the bucket.  \n\nGo stand in the flow.\n\nVery wet!
191497
It depends how high is it?
412802
p=F/A \n\nSo, you have the pressure of the atmosphere pluss the weight of the water above you.  Which is usually figured as a cylinder.  Hope that helps.
548154
Use a water level:  \nTake a long piece of hosepipe, put a short length of clear tube in each end.  \nFill with water and with a friend lay the pipe along the ground with the open ends (with the clear tube pointing upwards).\nThe water in the clear tubes at each end will be at the same height.
183244
Flowing water does.  I don't know about standing water.
151606
if all the lines are equal in every way (duplicate) then you can put a measurment (dimension) from the existing line to a datum or border whichever you choose and then put a callout like 3@12.00' (3 lines at 12.00 feet)in the dimensionwith a arrow pointing at the line.\n\njeff
835572
Gotta approach this using basic principles.\n\nEnergy is the integral of force applied over a distance.\nTheres two sets of forces working:\nfluid and gravitational.\n\nSo you make your control volume, and look at it.\nYou want to raise the water in it, thats mgh or rho*v*g*h\n\nYou also have to exert a pressure to push against the water ahead of it.  The downward pressure acting on your control volume is f/a so the force you must overcome is p*a and you are traversing distance h so the energy is p*a*h\n\nTherefore to raise the fluid vertically against a down pressure and against gravity the minimum energy (real world is lossy) is \nE = h*(mg+pa)