for physics people, pliz help?
354034
Forget the 6000N horizontal for for a second...\n\nYou have 5000N acting downward (negative) and 7000N acting upward (positive). The total net force acting vertically to the A/C is 7000-5000= +2000N so upward. We know that the horizontal force of 6000N is acting at a 90 degree angle to the upward force so the resulting forces make a right triangle. Use Pathagorean theorem.\n\n2000^2 + 6000^2 = x^2\n\nx is your MAGNITUDE.\n\nNow find the angle:\n\nUse trigonometry: \n\nTan(Angle) = opposite/adjacent\nwe know the opposite is 2000 and the adjacent is 6000 so,\ninverse Tan(2000/6000) = 18.4 degrees, upward and forward.
823034
You can find a good summary here:\n\nhttp://www.sparknotes.com/testprep/books/sat2/physics/chapter12section2.rhtml
918781
Where is your freebody diagram? There are other forces acting on the block than just gravity...\n\nGood Luck
210676
Use free body diagram to balance the forces and u can derive the equation of motion \nIf u want i can give u full derivation.\n"::
799487
Alright... physics is fun if you get the right problems :) .  \n\nThe collision is elastic... your book should have a conservation of momentum equation.  It states that p1+p2 = Ptotal\n\nYou have to use component vectors for the velocity after the collision.  A good thing to do would be to draw the problem.  It would make it a lot easier.  So use conservation of momentum.\n\nAnd there are two equations that would really help you:\n\nFinal velocity of block A= ((MB-MA)/(MA+MB))*VAinitial\n\nFinal velocity of block B= ((2MA)/(MA+MB))*VAinitial\n\nHelp with physics:\n\nALWAYS draw pictures epecially on your exams.  Get on the good side of the professor, go to a tutoring center if you have one, do many problems and memorize how to do the basic ones if you want an A on the test.
611013
Oh good grief.  If it's anything like what I've just done it'll include velocity, centrepetal forces, magnetic fields, friction, gravity, forces generally, working out the mass of something and the speed at which it will fall, balances with pivot points, static electricity, AC & DC electricity, transformers, vectors and so on and so on.  It's quite hard but it's maths based so if you like maths, you should be ok.  I wish you luck.
341507
You mean find "g" as if you didn't know the constant? Okay.\n\nPretty simply really. Have the height measured that you're going to drop it from to where it's going to land (this will be your "h"). Make it a high one (one meter is enough). Measure the mass of the object (that's the "w"). Then when you do the experiment, time it. Start it at the instant you let it drop and stop it once it touches where ever it lands. That's enough information to find "g." Just solve for "g" then that would be the answer.\n\nActually, for an experiment, you should solve for "g" as a formula before you start doing anything else. So the formula would be like this:\n\ng = (2h)/[(t^2)(w)]\n\n(t^2 is "t squared")\n\nSo just have that formula then do the experiment: measure height of the drop, the mass of the object, then time it when you drop it (you need good reflexes when you drop it, as it falls fast).\n\nPS Penguins!!!
700795
physics ?\n- jindajind ?
288780
From the following link, look for "Chapt22, Problem-24".\n\nThis problem is similar, except the speed is 10% instead of 11%. I'm sure you can use the same formulae though.\n\nhttp://www.jca.umbc.edu/~george/html/courses/phys112/2004fall/homework/04fall_phys112_hk8.pdf
677540
A lot of physics (especially beginning physics) is just finding the right equation and plugging in what numbers you are given.\nEquations usefull for your problem:\nKE = 1/2*m*v^2 (KE = kinetic energy, m = mass, v = velocity)\nAND\nWork = Force * distance     This is a very important equation\nit's easy to memorize so do it!
771568
Basically you have the right idea. Use momentum (mass x velocity) for the motion and the sudden change in speed and/or direction (acceleration) and you get force x time = kinetic energy trying to rip you apart or squash you like a bug.
966112
u can consult ur physics book
653943
gravity and inertia\n\nread more below. It is really fascinating.
765480
Physics.\nhttp://www.colorado.edu/physics/2000/index.pl
1152255
www.physicsclassroom.com
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http://scienceworld.wolfram.com/physics/YoungsModulus.html\n\nhttp://physics.uwstout.edu/Univphys1/labs/ymodul.htm\n\nTry them..
170255
It is much easier to just give you a link instead of explaining it:\n\nhttp://www.shef.ac.uk/physics/teaching/phy107/solvegray.html