Find The prime factorization of -160?
341037
-5 x 2 x 2 x 2 x 2 x 2 (or, I guess you could say -1 x 5 x 2 x 2 x 2 x 2 x 2)
108730
268=(6-(6+6)/6) * (66+6/6)\n\n\n\n 264 =(666 - 66*6 -6 )\nAt leas t i tried
807869
the prime factorization can be figured out by repeatedly dividing the number by a prime number.\n for example 12\n 12 divided by 2 = 6,   6 divided by 2= 3,  3 divided by 3= 1\n the answer is 1.\ni hope this was helpful.
780131
1224=2*2*3*3*17\n4000=2*2*2*2*2*5*5*5\n6336=2*2*2*2*2*2*2*11\n3125=5*5*5*5*5\n\nNone. There is no prime # that is a factor of all; therefore, there is no #, prime/composite, that goes into all of them.
750586
One way is to write down what prime factors are required. For each prime find the most number of times that prime divides one of the number and include that number as a factor of the least number.\n\n2 divides 2, 4, and 8, and it divides 8 three times: 8 = 2*2*2. So the least number has a factor of 8.\n3 divides 3 and 9. 9 is 3*3, so the least number has a factor of 9.\n5 divides 5 and 10, but only once in each. So the least number has a 5.\n7, 11, and higher primes don't divide these numbers.\n\nSo the number you want is 8*9*5 = 360. \n\nIf you include 7, then we must account for that prime number. It occurs once in itself. So the least number must have 7 as a factor. So the number you want is 8*9*5*7 = 2520.
713090
Actually, it's quite simple.  To get á, hold alt, and press 160 on your num pad.  Do that with 161 to get í, 162 for ó, 163 for ú, 164 for ñ, and 130 for é.  Holding alt and pressing 165 will get you Ñ, but I'm not sure that it's very necessary.  I've never had to use it.
1121426
I don't know if this is what you are looking for but simplified this fraction would be 24/43 (divided by 3). And you cannot simplify it any further because 43 is a prime number, as far as I remember...
199030
2\n\n228 -> 234\n\nprime numbers are 229 & 233\n\nIf you want how as well, this is the simplest...\n\n1617 / 7 = 231, go either side by 3.\nThen look up the prime numbers
980553
The following is a link to a calculator which will generated large prime numbers as well as multiply huge numbers together:\nhttp://world.std.com/~reinhold/BigNumCalc.html\n\n716111958663682417342303150142 608858901789417310093684696588 037024637209566331209352948311 017575749961619319828641955426 693304570465688762892415366806 836017495077860594429200032782\n63334056542642264651\n\nX\n\n580216645856397911811840259504 402483982261360695169382324936 875058224718365368242988227337 103422506977399968259382326419 406708576245141031259861340509 976971601273015479957884681378\n87651823707102007839\n\n=\n\n415500078713497281558905442483 784251718409580288016708180261 624957845916174034681385215800 377996269949769240101176290536 233429600607265291665503850867 426580947888398820550079218757 303625094649132652959885439006 834654658500398125929731018350 466670499118257135230989594968 432239652495895326959857212205 024845334097138922197109779294 150585092298147887850145072541 456311267636214499699970863002\n4114599189\n\n********************* **************************\nYou can also use this site if you just want the prime numbers:\nhttp://primes.utm.edu/lists/small/small2.html#200\nYou would want to pick two that are 200 digits long and such that the product of the first two digits is 2 digits long.
813960
To get a factor tree, start with picking a couple factors of 1200 (say 30 and 40).  Draw them as two branches under 1200.  Now continue doing that for each number (30 = 5 x 6, 40 = 4 x 10).  Keep branching until you get to a prime number.  When you read all the "leaves" you'll have your prime factorization.\n\n... 1200\n..../ .... &#92;\n.30 .....40\n./ .&#92; .... /. &#92;\n5  6... 4 10\n.. / &#92; ../ &#92; . / &#92;\n..2 3 2 2 2 5\n\n1,200 = 2 x 2 x 2 x 2 x 3 x 5 x 5\n\nNote: it doesn't matter how you pick your factors, since you'll still get to the same leaves.  The example above is just one way to create a factor tree for 1,200.  You could have started with 12 x 100, for example.  Just pick whatever first comes to mind.
1051900
1 2 3 4 5 6 10 12 15 20 30 60\n-1 -2 -3 -4 -5 -6 -10 -12 -15 -20 -30 -60
231634
well i am trying to find out myself\n\n31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.\n\nthat makes 15\n\n2, 3, 5, 7, 11, 13, 17, 19, 23, 29.\n\nthats 10\n\nU have all 25 prime less than 100 !\n\nAlways remember 1 is not a prime number ! cuz its divisible only by 1 and not any other number. and prime number requires divisibility by 1 and the number itself. i hope u got everything !\n\nmodified....i messed up somewhat. i wrote 65 and forgot 71. its clear now im sure watever i've writeen is 100% correct.
865396
Prime factorization is basically simplifying a number into its prime factors.  A numerical example would help.\n\nHere's how you would simplify 100 into a prime factorization:\n\n100 = \n4*25 (these aren't prime numbers yet, thus factor again)\n2*2*5*5\n\nSince 2 and 5 are prime numbers, this is the prime factorization.  \n\n----------\n\nHope this helps
90213
it isn't prime: it's divisible by 7 (which is one of my favourite numbers).\nIf you add it to 668^2 you get 669^2 (but that's a trick you can do with every odd number).
890978
To get prime factors, keep dividing by numbers and divide those until you can't divide them no more!  For example,\n\n34 \n17 * 2\n\n(Can't divide 17 any more and can't divide 2 -- both of these are prime numbers)\n\nAnother example,\n\n120\n12 * 10\n2 * 6 * 2 * 5\n2 * 2 * 3 * 2 * 5 (<-- all prime numbers here)\n\nTry to get the rest yourself and post the answers, we'll tell you if you got them right!  ;-)
877331
The prime factorization of 90 is 2x3x3x5.  Each number must be a multiple of 3. One or both must have two threes in its prime factorization since the LCM has two threes in its PF; one or both must have a 5 and a 2 in its PF; and none can have more.  This leaves as possibilties:\n\none #: 3x3, 3x3x5, 3x3x2, 3x3x5x2 or 9, 45, 18, 90\n\nFor 9, 6 or 12 are 3 away but neither work.\nFor 45, 48 or 42 are 3 away but neither work.\nFor 18, 15 or 21 are 3 away.  21 doesn't work but 15 does.\n\nSo 15 and 18
875190
Perform a prime factorization of each number:\n16 = 2 x 2 x 2 x 2\n36 = 2 x 2 x 3 x 3\n\nTo find the lowest common multiple, you need to take each prime factor, enough to cover both numbers.  In other words you need four of the 2s and two of the 3s.\n\nLCM(16, 36) = 2 x 2 x 2 x 2 x 3 x 3\nLCM(16, 36) = 144\n\nThe other people might be thinking greatest common factor, but even that answer is wrong since the GCF(16, 36) is 4, not 2.