physics problem involving mirrors (not lenses)?
350944
This sounds like a homework question?  Maybe I shouldn't give you the whole answer, so you can learn something on your own.\n\nYou are describing a Cassegrain telescope.  You can use the mirror formula to calculate the image plane for the first optic (the concave mirror) and then use that as the object plane for the second optic (the convex mirror) to get your final focal image plane.\n\nMirror Equation:  (1/So) + (1/Si) = -2/R\n\nSo = object plane (distance from object to mirror)\nSi = image plane (distance from image to mirror)\nR  = radius of curvature of mirror\n\nThe hardest part of these calculations is to use the right sign convention and to remember that the stars (initial object plane) can be treated as at infinity.
89741
A mirror CAN make things look upside down.  Stand in front of a mirror and hold a book up so you're reading the cover.  Now, turn the book so the cover faces the mirror and you can see the book cover in the mirror.  Normally you would rotate the book about a vertical axis, THIS is when the left and right reversal takes place.  You could instead turn the book upside down.  Then the reflection of the cover WOULD be upside down, and not backwards.\n\nOther answers given:\nRefraction does not happen. Only reflection.  Refraction has to do with the bending of light when it goes from one medium (such as air) to another medium (such as water).  It has nothing to do with the question.\n\nBecause our eyes are next to each other.  Close one eye and prove to yourself that that answer is nonsense.\n\nAlthough it seems backwards its really not.  Prove this is wrong by holding a book to a mirror and trying to read it.
596764
Magnification is dimensionless\n\nWhat is the focal length of the concave mirror in b\n\nConvex mirror has wider field of view.
593131
The incident ray is perpendicular to the surface of reflection.\nThen one has the least distance case.
443144
you should try this site http://www.oberlin.edu/physics/dstyer/SolvingProblems.html
774526
On a smooth surface, the angle of reflection will be the same as the angle of incidence.\n\nTherefore, the answer is (B) 40 degrees.
1119730
ahh, good theory problem...\nlet's see, there's energy, friction, force (normal, tension, as well as the other ones mentioned), gravitation, mass, pendulum motion, gotta be more that I've missed, but no doubt someone'll be here to correct me.
217437
Not in the same way that light reflects. This is an important topic in X-Ray telescopes. See below!
941047
The answers are:\na)35deg\nb)50deg\n\nThings to remember: The angle of incidence is the angle between the beam of light and the line drawn perpendicular to the mirror, NOT between the beam of light and the surface of the mirror. Also, angle of incidence = angle of reflection, so, for part a), the beam reflects towards M2 at an angle of 35deg. Form a triangle with the two intersecting mirrors and this reflected beam (internal angles in a triangle add to 180 deg). You will find that the angle of incidence onto M2 is also 35deg.\n\nFor part b): the angle of reflection from M1 is 60deg, and again forming a triangle with the intersection of M1 and M2, you will find that the angle of incidence for M2 is 50deg.
1088876
To verify the laws of reflection, this is what you have to do.\nTake a sheet of paper and place in on a wooden board.\nPlace a mirror, and 2 pins perpendicular to the sheet of paper.\nNow view the reflection of the two pins such that you can see only one pin. (the second pin should be exactly behind the first.)\nNow take two more pins and place them such that, these 2 and the reflection of the other 2 are in the same line.(This means that you will see only one pin and not 4)\nNow remove the pins and draw a st. line through the points were the first set of pins were placed.\nDo the same for the second set.\nBefore removing the mirror make an outline of it so that you know where the reflecting surface was placed.\nThe 2 lines that you obtained are the reflected and incident rays. Draw the normal with the help of a protractor and measure the angle of incidence and reflection. You will find that they are equal(one of the laws proved)\nAnd since you could draw the incident and reflected rays and the normal at the point of incidence in the plain of the paper, it follows that they all lie in the same plane(final law proved)
946998
since its a concave mirror, f = -31.6 cm\nlet object position be u and image position v\n\nmagnifivation m = - v/u = h'/h      h is abject size n h' image size\nresulting image is uprigth so h' is +ve and is 6h\n- v/u = 6 or v = -6u\nby mirror formula 1/v+1/u=1/f\n1/u = 1/f-1/v\n1/u = 1/f + 1/6u\n5/(6u) = 1/f\nu = f * 5/6\nu = 31.6 * 5/6\nu= 26.3 cm(approx)\nits kept at a distance 26.3 cm from the pole of the concave mirror.
501273
Didn't got the question do you want the solution for all the problems of goodman's Introduction to Fourier optics book? Well I do not think I have them any more if you want a specific problem I can help you. I can even try to get a chapter solution for you. Just tell me each one, I can try to get it for you, I do not garantee but I think I may have a way to got them just send me an email (I have a yahoo email). If you have the solutions and you don't understand tell me each problem I can do it in more detail probably, not garantee at 100% but at a good 90% .
575249
If there is 10 degrees between them and both strike the mirror at 5 degrees then they will both make the same angle reflecting. !0 degrees between them.\n\nIf one ray strikes the mirror at 0 degrees and reflects straight back, the other will reflect at 10 degrees, same answer.\n\nIf one ray strikes the mirror at 10 degrees then the other ray will strike at 20 degrees. Reflected angles are 10 and 20 so it's still 10 degrees between them.\n\nYou need to subtract instead of add the angles.
704068
Say you shine a flashlight into a mirror. Then put a mirror behind the flashlight and remove the flashlight. Given that the 2 mirrors are exactly parallel, will the light just bounce back and forth forever? No - the light travels in waves and each time it reflects back, some of the light is not hitting the mirror exactly at 90 degrees and is reflected off on an angle. The light will reflect away and eventually dissipate completely. \nIf you try to trap light in a box, as it bounces off the walls inside, it will dissipate into energy (heat). The temperature of the inside of the box will raise - but just infintestimly so.\nRemember all of this will take place at the speed of light.
524755
You are measuring the distances from the mirror.\n\nThe focus is behind the mirror. Therefore take that as - 53cm.\n\nThe object is at + 25cm.\n\nWe have to find v.\n\n1/f = 1/u + 1/v. \n\n-1/53 = 1/25 + + 1/v..\n\n+ 1/v = -1/53 - 1/25 = - 17 cm.\n\n17cm to the back of the mirror.\n\nA convex mirror focus distant objects at the focus.  If the object is brought nearer and nearer, the image moves from the focus toward the mirror.\n In your problem the object is very near to the mirror.  The image must be nearer to the mirror. \n Your answer -47 cm implies it is very near to the focus (-53cm) and it cannot be the correct answer.
590082
1) Let's think about this problem two-dimensionally.  A cross-section of the parabolic mirror would simply be a parabola.  Let's translate this onto a Cartesian coordinate system with (0,0) as the center.  Then (0,35) would be the focus, y=-35 would be the directrix, and one of the upper points would be (27,y).  If we find y, we find the depth of the mirror.  Since the points on a parabola are those points that are equidistant from the focus and directrix, let's set these distances equal to one another.  The distance between the focus--(0,35)--and the top point--(27,y)--is given by sqrt((35-y)^2 + 27^2).  The (shortest) distance between the directrix--y=-35--and the top point--(27,y)--is simply y+35.  Setting these two distance equal, we solve for y:\n\nsqrt((35-y)^2 + 27^2) = y+35\n(35-y)^2 +729 = (y=35)^2     (square both sides)\n1225 - 70y + y^2 + 729 = y^2 + 70y + 1225       (simplify)\n729 = 140y    (simplify)\ny = 729/140\n\nThus, the depth of the mirror is 729/140 ft.\n\n\n\n2) We must assume this 6% is an annual interest rate.  Then, the problem is simple.  A = P * (1 + r/n)^(nt), where A is the ending amount, P is the principal, r is the annual percentage rate as a decimal or fraction, n is the number of times compounded per year, and t is the number of years.\n\nIn this example, P = 6000, r = 0.06, n = 4, and t = 10.  Plugging these numbers into the above formula, we find that A = 10884.11.\n\nThus, after ten years, there is $10884.11 in the account.\n\nGood luck!
745196
What you are describing is a result of light reflecting off a concave surface.  The best way to explain this is like this:\n\nDraw a big T on a piece of paper.\nNow draw a line from the lower right side to the vertex of the T (that's the intersect).  This represents light coming in.\nNow draw another line from the vertex to a point at the same location as the origin of the other line, but on the lower left.  That is the light leaving.  The angles of both lines converging on the crossing of the T should be the same.  Same with any beam of light.  It is reflected at the same angle as it is received.\n\nA spoon is a reflecting concave mirror.  If you could get close enough to the spoon you could see your image right side up.  But when you are further out than the focal distance the image inverts because the beams cross over each other.