how to solve for y 4y=x=9?
338519
If you remove x completely (because you already know it's equal to 9), you have:\n\n4y = 9\n \nor 9/4 which is 2.25
1137447
2 linear equations\n\n X  + 3Y - 1 = 0\n4X + 7Y + 5 = 0\n\nFROM (1)   4X + 12Y - 4 = 0\nFROM (2)   4X +  7Y + 5 = 0\n\nSUBTRACT\n                          5Y - 9 = 0\n\n                          5Y = 9\n\n                            Y = 1.8\n \n  FROM (1)      X + 5.4 - 1 = 0\n\n                        X + 4.4 =   0\n\n                        X =  -4.4
985362
x-4y+4=12\n\nyou want to get it in y= mx + b form \n\nso switch the 4y and the 12 \n\nx + 4 -12 = 4y\nx - 8 = 4y\n\nnow divide by 4\n\n(1/4)x -2 = y\n\nso the slope is 1/4 and it crosses the y axis at -2\n\nsome points are \n(0, -2)\n(-4, -3)\n(-8, -4)\n(4, -1)\n(8, 0)\n(12, 1)\n\nhope this helped\nbest of luck
775275
2y^3 + 2x^3 - 9xy = x^5\n\nBy implicit differentiation\n\n6y² dy/dx + 6x² - 9y - 9x dy/dx = 5x^4\nSo 3y(2y - 3) dy/dx = 5x^4 - 6x² + 9y\n\nSo dy/dx = (5x^4 - 6x² + 9y)/[3y(2y - 3)]
867879
Just plug 0 in the function whenever you see y.\n\n4x + 3(0) + 24 = 0\n4x + 0 + 24 = 0  \n\nThen solve for x.\n\n4x = -24\nx = -6
122878
1. Move -36 to the other side by adding it.\n\n4y=2y+42+36\n\nnow the equation is...\n\n4y=2y+78\n\n2. Now move the 2y to the other side by subtracting it. This is called isolating the variable (y)\n\n4y-2y=78\n\nNow the equation looks like...\n\n2y=78\n\n3.Now divide both sides by 2 to get y by itself.\n\nYou finally get...\n\ny=39
897443
2x + y = - 9\n\n2x + y - y = - 9 - y\n\n2x = - 9 - y\n\n2x/2 = - 9/2 - y/2\n\nx = - 9/2 - y/2\n\n- - - - - - - -\n\ny values\n\n2x + y = - 9\n\n2x + y - 2x = - 9 - 2x\n\ny = - 9 - 2x\n\n- - - - - - - - - - - - -\n\n2).\n\nx values\n\n-x - y = - 8\n\n- x - y + y = - 8 + y\n\n- x = - 8 - y\n\n- 1(- x) = - 1(- 8) + (- 1)(y)\n\nx = 8 - y\n\n- - - - - - - - - - - -\n\ny values\n\n- x - y = - 8\n\n- x - y + x = - 8 + x\n\n- y = - 8 + y\n\n- 1(- y) = -1(- 8) + (- 1)(x)\n\ny = 8 - x\n\n- - - - - - - - - - - -\n\n3).\n\nx values\n\n- 3x + 4y = 2\n\n- 3x + 4y - 4y = 2 - 4y\n\n- 3x = 2 - 4y\n\n- 3x/ - 3 = 2/- 3 - 4/- 3\n\nx = - 2/3 + 4/3\n\n- - - - - - - -\n\ny values\n\n- 3x + 4y = 2\n\n- 3x + 4y + 3x = 2 + 3x\n\n4y = 2 + 3x\n\n4y/4 = 2/4 + 3x/4\n\ny = 1/2 + 3x/4\n\n- - - - - - - - - -\n\n4).\n\nx values\n\n- 2x - y = - 3\n\n- 2x - y + y = - 3 - y\n\n- 2x = - 3 - y\n\n- 2x/ -2 = - 3/- 2 - y/-2\n\nx = 3/2 + y/2\n\n- - - - - - - - - \n\ny values\n\n- 2x - y = - 3\n\n- 2x - y + 2x = - 3 + 2x\n\n- y = - 3 + 2x\n\n- 1(- y) = -1 (- 3) + (- 1) (2x)\n\ny = 3 - 2x\n\n- - - - - - - -s-
90743
Well you must have two equations! If you wanted to say x+4y=16 then just add the two and you'll fing x (4x=10) and then find y from one of them.
955998
so easy. 9y-11=7. add the 11 to the 7 so 9y=18. Divide by 9 so y=2.  20+4m=42. same thing. subtract 20 so 4m=62. divide by 4 so m=15.5
287408
y = 0\n4x^2 + 9 = 0\nget the discriminant\nb^2 - 4ac\n=0^2 - 4(4)(9)\n= -144\n\nTherefore, it has no real  x-intercepts but generally has 2 irreal (imaginary) x-intercepts^_^
695016
4x + 3y =12, find y = 4\n4x+3*4=12\n4x+12=12\n4x=0\nx=0
754976
It's true.\nThe answer is indeed y = 0.\nYou can find this by dividing each side by -4.\n-4y = 0\n-4y/-4 = 0/-4\ny = 0\nRemember that zero divided by any nonzero number is always zero.
225505
First manipulate a little to get everything lined up\n\n3x - 2y = -8\n9x - 3y = -21\n\nNow to cancel out one of the variables.  It's easiest to cancel out x, since 9 is a multiple of 3.  Multiply the 1st equation by -3\n\n-9x + 6y = 24\n9x -3y = -21\n\nNow add the 2 equations together.  The -9x and 9x cancel eachother out and you are left with\n\n6y - 3y = 24 - 21\n3y = 3\n\nFinish solving for y, and then plug that number in for y in either one of the equations above and solve for x. Good luck!
895237
you do not get specific values, there are infinite number of solutions for each equations\n\n2x + y = 9, y= -2x + 9\n\n-x - y = - 8, y=-x+8\n\n- 3x + 4y = 2, y = 3x/4 - 1/2\n\n- 2x - y = - 3, y= -2x +3\n`
701107
4x +y = 16   ;2x + 3y = 24      Multiply the 2nd with -2, that gives -4x -6y = -48    Add the two:   0x - 5y = -32  \nDivision by -5 gives  y = 6,4\nInsert this value into the first equation:   4x + 6,4 = 16\n4x = 9,6 ;    x = 2,4\n\nNumber 2 is even easier:\nMultiply the first equation by 2 and add the equations.\n24x + 2y = 50    plus   8x - 2y = 14  gives  32x = 64; x = 2\nYou can now choose:  24 + y = 25  or  16 - 2y = 14\n(That you get when you replace in the original equations \nx by 2)  Anyhow you'll find   y = 1
1144396
you would take the 2x-4y=3 and solve for a variable, such as x=(3-4y)/3   you now have what x equals and you sub that into the other equation so you now have 2[(3-4y)/3]-3y=0 and you should be able to solve that equation
305313
4x^3y^2-16y^3-9y=\ny(4x^3y-16y^2-9)