Solve using the multiplication principle: 5 b < -10?
347304
I'll show you a slightly different way.\nI am assuming you know basic algebra.\n\nSee,       5b < -10\n      5b + 10 < -10 + 10    ( by adding 10 both sides )\n     5b + 10  < 0\n    5*( b + 2 ) < 0         ( Factorize out 5 )   \n\nNow, just think for a second. The two numbers "5" and \n"(b +2) " when multiplied, we require a negative ( i.e < 0 )\nresult. Since 5 is positive, we must have that ( b + 2 ) must be negative. Why? because by convention only a positive number multiplied by a negative number yields a negative number and vice versa.\n\nThus, ( b + 2 ) negative means that \n      b + 2 < 0  \n   b + 2 -2 < 0 - 2   ( by substracting 2 both sides )\n          b < -2
550724
I'm not 100% sure what it's asking, but I'm thinking that it's this:\n\nThe simple way of looking at it...\n\nIf you look at it like a basic multiplication with Roman Numerals representing the actual numbers.\n\n((10)(50)(1)(5))*(10) = (100)(500)(10)(50)\n\nYou either distribute the last X (or 10) in left side of the equation to the other numbers on the left side or divide both sides by X (or 10) to come up with\n\n(100)(50)(10)(50) = (100)(500)(10)(50)\n2,500,000 = 2,500,000\nor\n(10)(5)(1)(5) = (10)(5)(1)(5)\n250 = 250\noh, and after re-reading the question, im more positive about the answer because of the 'There are two solutions'
96233
+5,+12, -5, -12, +3.3
261181
assuming that 2x+5=0, then I deny that solution. The Pair(3,-5) workes for 6y-8=-54 only.
914435
x > 5\n\n- - - - - -s-
928231
8x-10x > -11-1\n\n-2x > -12\n\nx < 6
30589
2(5)-5(5)+2(5)=\n10-25+10\n20-25\n-5
804510
3x^2+6x+5x+10\n(3x+5)(x+2)
153400
i believe it would be '-9'\nn=5 \n-3-(5-1)(1.5)\n-3-(4*1.5)\n-3-6\n-9
538824
2 + 2 = 5 for moderately large values of 2
836780
Its 5=2n-6 \n\nwell done!
604216
In an ordered pair, the first number stands for the x value and the second number stands for the y value.  \n\nTaking the first ordered pair you have (5,?), you know that the x value is 5.  So you plug 5 into the equation where it says x.  \n\n2(5)+y=10.  Now solve as a regular algebraic equation\n10+y=10  \ny=0\n\nNext one: (?,10).  This time you know the y value, so you plug the 10 into the y value and you have \n\n2x+10=10   Solve algebraically. \n2x=0, \nx=0.\n\nI will leave the last two for you to figure out, although I'm sure others will be posting it.\n\nI hope this helped you to understand HOW to do it...\n\nGood Luck.
980081
That isn't an algebra 'problem'. Perhaps you were asked to expand it?\nIn which case, (8-√10)(5-√10) = 8*5 - 5√10 - 8√10 + √10*√10 = 40 - 13√10 + 10 = 50 - 13√10.
973521
=5.2*5.2*10^-5\n=27.04^10^-5\n=2.704*10^-4
462416
9. B\n10. B\n11. It's 0.3455\n12. C
144204
-10\n\nand to prove it -10 x -10 x -10 = -1000
600095
You can factor out 15bc^2\n15bc^2(5b + 4c^4)