Solve     2   x-12 =2048    (x-12 is the power )?
338945
2^(x-12) = 2048\nFirst rewrite 2048 as an exponent with a base of 2.\n2^(x-12) = 2^11\nNow set the powers equal to each other and ignore the 2's.\nx-12 = 11\nNow solve for x by adding 12 to both sides.\nx = 23
1012196
3(x+12)=x+2\n3x+36 =x+2\n2x+36=2\n2x=34\nx= 17
796276
a.)\nx^2 - 12x\nx^2 - 12x + 36 = 36\n(x - 6)^2 = 36\n(x - 6)^2 - 36 = 0\n\nb.)\nx^2 + 22x\nx^2 + 22x + 121 = 121\n(x + 11)^2 = 121\n(x + 11)^2 - 121 = 0\n\nc.)\nx^2 + 13x\nx^2 + 13x + (169/4) = (169/4)\n(x + (13/2))^2 = (169/4)\n(x + (13/2))^2 - (169/4)) = 0
122527
1 - 64x^2 = (1 + 8x)(1 - 8x)\n\ny^2 - 12y + 36 = (y - 6)(y - 6)  or (y - 6)^2
971462
48=2(20+w)\n24=20+w\nw=4
1110742
12 simply place the 1 where the x is\n\n(1+3)(1+2)\n4*3\n12
819891
2(x-6)=3x\n\n1.Distribute the 2 to the X and the 6. \n2x-12=3x\n\n2. Subtract the 2x from the left side and subtract it from 3x\n-12 = 1x\n\n3.flip the problem so it looks pretty!\nx = -12\n\nYour Welcome :D
787487
roots: x= (-12 +/- sqrt(144-4k^2) ) / 2k\n\nset them equal, assume k is not zero and cancel 2k:\n  -12 + sqrt(144-4k^2) ) = -12 - sqrt(144-4k^2) )\nso it mus be that \n  sqrt(144-4k^2) ) =0\nor \n  144=4k^2\n  k=6
560506
that works... so does this:\n\n-2 x -1 x 1 x 2 x 3 = 12\n\n-2*-1=2\n2*1=2\n2*2=4\n4*3=12
909474
You can do this by hand.\nCall your number x.\nWrite the binary digits of x as b_i :\nx = sum_n=0_n=N b_n.2^n\n\nThe algorithm is simple: compare your number x to the largest power of two (2^N), subtract if necessary, and decrease n until finished (n=0).\n\nStart with n=N , the largest integer such that X >=2^n\nIf x >= 2^n, then {\n b_n = 1;\n x = x-2^n;\n n = n-1; \n} else {\n b_n 0;\n}\n\nThe above is pseudocode, you could do it in C, PERL, Python, Java etc.\n\nSo: x= 121 = 64+57=(64+32)+25=(64+32+16)+9\n=(64+32+16+8)+1 =64+32+16+8+0+0+1\n\nThus 121 (base 10) = 1111001 (base 2)
258035
Without more information, it could be any two numbers such that their product is 144.\n12*12 = 144 works and 16*9 = 144 works as well.  \nThere are infinitely many solutions of the form\nbase = b and height = 144/b
922786
For all real numbers x:\n\n\n12 + x = 18\n\n-12 + 12 + x = -12 + 18\n\nx = 6\n\n{6}
731776
simple!!!\nthe answer is : 12x^2\nthe rule of addition intergers with exponents is simple.\nyou just add the whole number (that is 4+8) and then follow the integers (that is x^2)... get my point?\ni hope i have helped you with your assignment....
4959
=8(y^3)z + 12(y^2)(z^2) - 20y^2
749417
-14‹2x-6≤12\n -14+6<2x<=12+6\n -8<2x<=18\n -4<x<=9
830859
64=1,2,4,8,16,32,64\n120=1,2,3,4,5,6,8,10,12,..............
658148
given 4a^2-12ab+9b^2\n    =(2a)^2-2(2a)(3b)+(3a)^2\n    =(2a-3b)^2