what is the mass of jupiter in yottagrams?
342475
1,900,000\nAnd yes, I had to look up yotta in wikipedia.
26899
go to encarta.msn.com and search for keys mass/solid structure, surface Structure
800535
jinde, hi!\n\nwhat an amazing question!  i remember reading about this somewhere, so it took me so long to research it...\n\nsee, when we talk about weight, it varies from spot to spot in the universe.  you may weigh 60kgs on Earth.  but on the moon, you'd be 10kgs.  on Jupiter, you'd be 600000kgs!!!\n\nwhat we need to discuss is the mass of the object, because that would be the only thing that makes sense on the Galactic scale.  are you ready for the answer?  it's gonna be mind-boggling!\n\nThe Earth's mass is approximately 6,000,000,000,000,000,000,000,000 (6E+24) kilograms!!\n\ni know what you're next question will be?\n\n"How did they measure that?"  i have the answer for you!\n\nthe measurement of the planet's weight is derived from the gravitational attraction that the Earth has for objects near it.\n\nit turns out that any two masses have a gravitational attraction for one another. if you put two iron weights near each other, they will attract one another gravitationally. the attraction is extremely slight, but if your instruments are sensitive enough you can measure the gravitational attraction that they have on one another. from that measurement, you could determine the mass of the two objects. the same is true for two marbles too! but the attraction is even slighter because the amount of gravitational force depends on mass of the objects...\n\nNewton showed that, for spherical objects, you can make the simplifying assumption that all of the object's mass is concentrated at the center of the sphere... and the following equation expresses the gravitational attraction that two spherical objects have on one another :\nF = G * M1 * M2 / R2\n\n    * R is the distance separating the two objects.\n    * G is a constant that is 6.67259x10-11m3/s2 kg.\n    * M1 and M2 are the two masses that are attracting each other.\n    * F is the force of attraction between them. \n\nassume that Earth is one of the masses (M1) and a 1-kg sphere is the other (M2).  the force between them is 9.8 kg*m/s2 -- we can calculate this force by dropping the 1-kg sphere and measuring the acceleration that the Earth's gravitational field applies to it (9.8 m/s2)...\n\nthe radius of the Earth is 6,400,000 meters (6,999,125 yards)... if you plug all of these values in and solve for M1, you find that the mass of the Earth is 6,000,000,000,000,000,000,000,000 kilograms (6E+24 kilograms / 1.3E+25 pounds)...\n\nhope this made sense... and if it did, i hope it was useful to you...\n\ndo write me if you need more clarification...\n\nenjoy!
586639
With over sixty three moons to date and growing, Jupiter has more moons than any other planet in the Solar system*.  In fact, Jupiter and its moons are often referred to as the Jovian system (Jove being an alternate name for Jupiter), and are almost more complex as a planetary system than the Solar system itself is.\n\nThe planet with the second most numerous moons is the planet Saturn.  If you would like more information on either the moons of Jupiter or Saturn, I would highly recommend searching through either nasa.gov, nineplanets.org (which can be a little dry but still has a lot of useful information), or solarviews.com.\n\n\n*By the way, there's only one "Solar system" since the name refers to the star in the center of our star system, which is properly named "Sol", and not "the Sun"... all other systems containing a star and planets would be properly referred to as either a planetary system or a star system, as they do not orbit the star Sol.
1046890
Through the study of other stars 'wobble' within our own galaxy, we have detected planets larger than Jupiter, we believe.  Though, this is through a calculation with the doppler effect.  So to play it safe, as far as we know now it is Jupiter.  But to say that this will always be true would be bold and naive.
149678
Their are two types of planets:\n\n    * Terrestrial planets\n          o low mass (£ 1 MÅ )\n          o high density (rocky, metallic)\n          o slow rotators (P ³ 24 hours)\n          o few satellites\n          o close to Sun (a £ 1.6 AU)\n          o Thin atmospheres\n          o Weak or no mag field\n                   \n            &\n\n     * Jovian planets\n          o high mass (³ 15 MÅ )\n          o low density (gaseous, but some gas is solid)\n          o rapid rotators (P £ 18 hours)\n          o many satellites\n          o far from Sun (a ³ 5 AU)\n          o Thick atmospheres\n          o Strong magnetic field\n\n\n\n\nThe Jovian Planets\n\n    * Jupiter, Saturn, Uranus, and Neptune have all been visited by the Voyager space probes.\n          o Galileo is now studying Jupiter\n          o Cassini is on its way to Saturn\n    * Jupiter, Saturn, Uranus, and Neptune are all massive bodies\n          o formed in outer part of pre-solar nebula where ices condense\n          o growth by accretion and coalescence\n          o Massive enough that gravity probably played an important role as well\n    * Jovian planets are gaseous/fluid bodies\n          o supported by balance between pressure and gravity: Hydrostatic equilibrium\n\n\nIf you want to see pictures and a more indepth explanation goto this url below.\n\n\nI hope this helps...\n\nDon
770605
a)\nGravitational force F between two bodies with masses m1 and m2 separated by a distance r is described by the equation\nF=G*m1*m2/r^2, where G is a constant with value 6,67*10^(-11) N*m^2.kg^2.\n\nWe know that F=34.3 N and m2 = 3.5kg and r = 7.4*10^6 m\nSubstituting we get \nm1=8.05*10^24 kg\n\nb)\n\nDensity d = m / V\nSince the planet is a sphere its volume is V=(4/3)*Pi*R^3\n\nSo d = 4740 kg/m^3
934797
Jupiter has a diameter equal to 11.2 times the diameter of Earth.  In terms of volume, the ratio is 11.2^3 = 1405.
627250
All the solar system models you can buy are not to scale, which is OK if all you want to do is show the planets in the right order. But I much prefer a scale model. Only trouble is, it is WAY to big to make indoors. Jupiter is 10 times bigger than Earth and the Sun is 10 times bigger than Jupiter, so if Earth is a 1 inch ball, you need a 10 inch ball to be Jupiter (a basketball is 10 inches) and a 100 inch ball (8 feet 4 inch) for the Sun. Maybe a weather balloon would do. What I did instead was say that the basketball was the Sun, a one inch ball was Jupiter and a 1/10 inch pinhead was Earth. The other planet sizes can be calculated with the first link in the sources below. If the Sun is 10 inches, then Mercury is 34 feet away, Earth is 89 feet away and Pluto is about 2/3 of a mile away. What I did was take the class for a walk outside. We walked 2/3 of a mile from the school, setting up planets as we went. Or you could just set them in a row on the table and have the correct distances written on an information sheet. The whole point is that the planets are really small and really far apart. The models where the sun is only twice as big as Earth just are not convincing.
1020680
Divide 57 N by 9.81 m/s/s to get the mass in kilograms.\nThe mass will be the same on the surface of Io as it is on the earth.\nTo find the weight on Io multply the mass by 1.81 m/s/s and that will be in Newtons.
18543
The relative size of Earth, Jupiter, Sun = 1 : 10 : 100
952581
http://planetmath.org/?op=getobj&from=objects&id=3808
310199
1 x Star ("Sol"/"The Sun")\n9 x planets\n140 x satellites (moons) [approx.]\nasteroids [1,000s]\ncomets [by guest appearance only]
108382
As of right now we don't know sizes of other planets outside our solar system.\n\n But, Jupiter is the largest planet in the Solar System. With an equatorial diameter of 143,884 km, (89,405 miles), it is as wide as more than 11 Earths stacked side by side. The planet also has the shortest period of rotation - Jupiter days last just under ten hours.
265928
1.27 X 1022 KG (0.0021 Earths)
248549
Mean Equatorial Radius\n71,492 km\n(11.209 of Earth's radius)\n\n142,984 km diam *3.14\n\n\n448,969.76 km is the cirumference\n\nif you search for astronomy pic of the day then search jupiter everyting is there.  Plus some relly awesome pictures
90717
Europa is the smallest of the four Galilean moons, but it is still the 6th largest satellite in the solar system. With a diameter of 3,138 km, Europa is slightly smaller than our own Moon. \nEuropa Quick-Look Statistics\n \nDiscovery:                             Jan 7, 1610 by Galileo Galilei\nDiameter (km):                         3,138           \nMass (kg):                             4.8e22 kg \nMass (Earth = 1)                       0.0083021\nSurface Gravity (Earth = 1):           0.135 \nMean Distance from Jupiter (km):       670,900 \nMean Distance From Jupiter (Rj):       9.5 \nMean Distance from Sun (AU):           5.203\nOrbital period (days):                 3.551181 \nRotational period  (days):             3.551181 \nDensity (gm/cm³)                       3.01 \nOrbit Eccentricity:                    0.009\nOrbit Inclination (degrees):           0.470\nOrbit Speed (km/sec):                  13.74\nEscape velocity (km/sec):              2.02 \nVisual Albedo:                         0.64\nSurface Composition:                   Water Ice