a gamma ray has an equation of y = A sin Bt. What is B if the wavelength is 3 x 10^ -10 cm and c = 3 x 10^10?
355213
In y = A sin Bt, B is the frequency in radians/second, or B = 2pi*f, where f is the frequency in cycles/second, or Hertz.\n\nI assume by "c= 3 x 10^10", you're referring to the speed of light, which is 3*10^10 cm/sec.\n\nf = c / wavelength, so f = 3*10^10 cm/sec / (3*10^-10cm) = 3*10^20 cycles/sec or 3*10^20Hz.\n\nSo B = 2*pi*f = 2*pi*3*10^20 = 6*pi*10^20 radians/sec.  That's about 1.885*10^21 radians/sec.\n\nNote that these equations hold for all electromagnetic radiation, including radio waves, microwaves, IR, light, UV, X rays, and gamma rays.
956102
Here is the equation\n\n(246,92)U ---> (4,2)He + (242,90)Th + 2Gamma
886265
gotta put the equation into y=mx+b first\ny= 1/3x - 1\n\nperpendicular would be y = -3x (+ or - any #)
634321
Every time the ray of light goes from one mirror to the other, it goes through a certain distance d along the mirrors axis (in the 20m direction).   The law of reflection says that the angle of incidence is the same angle as the one the ray will leave the mirror surface, so, we can build a right triangle, with the reflected ray of light as the hypotenuse.  So, we have:\n\nr*Sin( theta ) = d    and   r*Cos( theta ) = a\n\nDividing the first over the second:\n\nSin( theta ) / Cos ( theta ) = d / a\n\nOr:    Tan( theta ) = d / a\n\n            --->   d = a*Tan( theta )\n\ntheta being 30 degrees and a being 10cm = 0.1m\n\nNow, just divide 20m over d and you're good to go.\n\nHope I helped.
1123630
1) 10 full wave-length passed by 120 sec so the wave period is 12 sec. f=1/T so f=0.083333 Hz\n2) First of all, light speed=3 x 10^8 m/s.\nSecondly, f=v/lambda\n(where v=light speed and lambda=wave-length)\nso f=3X10^8 / 6.6 x10^(-7)=4.5454 x 10^14 Hz (approx. 4500 GHz = Giga Hertz)
978722
You can't, algebraically.  You have two equations and three variables.  Sorry.  You need one more equation, such as a = b.
46026
Gamma ray frequencies range from 3e18 Hertz to 3e20 Hertz.
269338
The speed of light is 3 x 10^10 cm/sec or 3 x 10^8 m/sec or 3 x 10^5 km/sec.\n\nWavelength = speed of light / frequency\n\nBe sure you use the right units.
912572
sin^3 β + cos^3 β  = (sinβ + cosβ)(sin^2β + cos^2β - sinβcosβ)\n= (sinβ + cosβ)(1 - sinβcosβ)\n\nsin^3 β + cos^3 β / sin β + cos β\n = (sinβ + cosβ)(1 - sinβcosβ)/( sin β + cos β)\n= 1 - sinβcosβ
747451
c) the frequency of incident radiation\nThis is according to the Einsteins photoelectric equation\nKmax = hf - phi\nwhere phi is the work function, h is the planck's constant and f is the frequency
807253
nu = c / lamda\n\nsolve for lamda - you want wavelength.\nc is the speed of light = 3 x 10^8 m/sec\nnu is your frequency = 3.2 e-2\n\nplug into the calculator: 9.375 e9 meters
777234
the wavelength will be speed/frequency=300000/100100000\n=0.002997002997002997002997002997003 kilometers \nin aproximation\n=2.997002997002997002997002997003 in meters\nor 3meters
462416
9. B\n10. B\n11. It's 0.3455\n12. C
833971
use the formula sinA/sinB.\nA is the angle of incidence,B is the angle of refraction.\nso in this case it is sin40/sin25 = 1.52(to 3sig. fig)
164646
You mean a 'frequency of 5.10^12Hz'\n\nCan you work it out yourself?:\n\nRemember that the speed (v) of the wave is 3×10^8 m/s,\nand that the wavelength is given by v/f\n\n[Edit: Darn, Kirchwey - don't do Glow's homework for her! ;-) ]
821495
a) Assume the following:\n\nAngles a= 10 deg, b= 80 Deg, c=90 deg \nHypotenuse length = 2.5 m\nheight = 2.5 * cos 80 Deg= .434 m\nlength = 2.5 * sin 80 Deg= 2.462 m\nacceleration = "g" * Sin 10 Degree
1115976
100 : 10\nx : y\n\nCross Multiply to get equation,\n\n100y = 10x