How many pieces would come out of a 4'x10' sheet?
347717
well, i'm going to assume that you mean a sheet of glass.\n\nNow if we drop this sheet of glass just right on the concrete we can make approximately a mole of glass pieces.  A mole is 6.022 x 10^23 pieces. \n \nIf we don't drop the sheet just right can end up with significantly more or less pieces.\n\nIf you mean anything other than a sheet of glass and random pieces you need to tell us the size of the pieces you need and other information.
844185
square-ish in shape\ncome in different sizes\nmany varieties
880272
Total Gobz = 20\nOne fourth of these are red\nSo, number of red Gobz = (1/4) * 20 = 5\nThe rest are blue\nSo,number of Blue Gobz = 20 - 5 = 15\n\nWhat do you mean by into how many parts was the group divided?\n\n1) If you want to know the percentage share, then the question itself gives the answer\n\nRed gobz take 1/4 parts = 25%\nSo Blue gobz take (1 - 1/4)parts = 3/4 parts = 75%\n\n(or)\n\n2) If you mean to say that the 20 Gobz should be split into various parts such that each part is same as the other,\n\nThe number of parts = 5\neach part will have 1 red gobz and 3 blue gobz
791300
Use the FOIL method; First, Outer, Inner, Last.\n\nFirst, n * n\n\nOuter, n * 5\n\nInner, n * 7\n\nLast 7 * 5.\n\nThen add them all together.\n\n22 NOV 06, 0420 hrs, GMT.
306739
4 times the length of one side
880678
Area = length times width\nA = L time W\nReplace L with 32 and W with 22\nA = 32 times 22\nA = 704 square feet
1111648
200 x 200\n\nor\n\n40, 000 colors
706198
5*4*3 = 60\n\nExample:\nNow let's suppose we have 10 letters and want to make groupings of 4 letters. It's harder to list all those permutations. To find the number of four-letter permutations that we can make from 10 letters without repeated letters (10_P_4), we'd like to have a formula because there are 5040 such permutations and we don't want to write them all out! \n\nFor four-letter permutations, there are 10 possibilities for the first letter, 9 for the second, 8 for the third, and 7 for the last letter. We can find the total number of different four-letter permutations by multiplying 10 x 9 x 8 x 7 = 5040. This is part of a factorial \nhttp://mathforum.org/dr.math/faq/faq.comb.perm.html
784389
4 x 11 = 44 square inches
905726
three sizes\nthree crusts\nten toppings\n\nLook in your math text under "combinations and permutations." You can do this!
776007
If your two figures have a ratio of similarity of 2:5, then each side of the smaller one is the side of the larger one times 2 and divided by 5.  This might lead you to believe that your area would be 100 times 2 and divided by 5 = 40.  This is, however, not the case.  If each side is times 2 and divided by 5, the total area is times 2 times 2 divided by 5 divided by 5. = 16\nThe best way to imagine this problem is by assuming your shape is a square.  How large is each side of the square if the area is 100 square units?  Each side must be 10 units, since 10 times 10 is 100 square units.  Now shrink each side by multiplying by 2 and dividing by 5.  Each side is now 4 units long.  How much area is your square?  4 times 4 is 16 square units!
93641
Okay, 2 + 4= Look at 2 now look at 4, 4 is 4 pieces and 2 is 2 pieces. add the 4th piece and the second piece = 6! Duh!
875596
you count the legs and divide by 4
882047
I can't draw a diagram, but that would help.  So, picture the box and the corners.  Label the amount cut off (like the size) from each side x.  The new length on each side is going to be 11-2x or 14-2x (as there are two squares on each side).  These multiplied together (like a rectangle) form the area of 80.  Let's solve.\n\n(11-2x)(14-2x)=80\n\nExpand.\n\n154-50x+4x^2=80\n\nBring the 80 over\n\n4x^2-50x+74=0\n\nBring out the two\n\n2(x^2-25x+37)=0\n\nx is about 1.715 solving this equation.\n\nThere is actually another solution, somewhere around 10.8.  However, this is an unnecessary solution:  10.8*2 is obviously larger than both 11 and 14.  We can throw it out.  \n\nCheck that:\n\n(11-2(1.715))(14-2(1.715))=80\n\nThat's your answer.\n\nHope this helps.
862464
Your responders are telling you how to solve the problem with three pieces. But the problem calls for TWO pieces.\n\nHere's how to do it in two pieces.\n\nBegin your cut on the left side, 3 squares from the top. \nCut from the left side a distance of 2 squares into the rectangle (i.e., half-way across).\nFrom that point, cut downward (down the middle) 3 squares.\nFinally start cutting to the right again, and complete your cut at the right side, 3 squares from the bottom. \n\nThen just move the top piece over to the right and down, and it will fit with the other piece to form a 6x6 square.\n\nHere's a diagram:\n\na a a a\na a a a\na a a a\nb b a a\nb b a a\nb b a a\nb b b b\nb b b b\nb b b b\n\nJust cut between the a's and the b's and you'll have your two pieces.
72734
Cut up little squares and stack them up until you get to a quarter inch or some measurable amount.  Then count the number of sheets and do some basic division to determine a single sheet thickness.
379186
One width is 1/4 the length:\nRectangle: a 4-sided figure with 2 sets of equal-length sides.\nside a = 1/4 side b.\nside a + corresponding side a = 1/2 side b.\n4a = 1 long side.\n8a = 2 corresponding long sides.\n2a + 8a = 130'\n10a = 130'\ntherefore a= 13'\n4a = 4x13 = 52'\n2 short side @ 13' each = 26'\n2 long sides @ 52' each = 104'\n104' + 26' = 130'\nNot trying to do your homework for you, but helping you see how to think it through.  Hope this helps.