What is the specific heat of glass?
338498
There are different types of glass, with different specific heat values.  Specific Heat is also called Heat Capacity.\n\nFlint Glass   0.503 Joules / gram Kelvin\nPyrex Glass   0.753 Joules / gram Kelvin
299604
Aqueous humor\ndensity:                   1000 kg/m3\nThermal Conductivity:0.578 N/(oC ∙ sec)\nSpecific Heat:             4180 N∙m/(kg oC)
949133
OMG!\ni have the same question!\nmine is:\nA piece of an unknown metal has a mass of 20.0 g and at 100.0 C is placed in a styrofoam cup calorimeter containing 50.7 g of water at 22 C. If the final temp is 27.2 C, calculate the specific heat capacity of the metal. Assume that all the energy lost by the metal is gained by the water.\n\nok, haha fine, not the SAME question, but close enough. But, i'm uber confused. ><
116361
It depends on the temperature at which you are talking about. At room temp glass is a solid. However, at a high enough temperature, glass can be in liquid form, much the same way that ice melts into liquid. It just takes a lot more heat. To clarify from one of the other responses, it is liquid as long as it is in it's liquid phase. Steel is still called steel, even when it is molten enough that it's flow properties are similar to that of water. However, as we interact with steel and glass it is in it's solid phase.
988791
First off, nothing is perfectly smooth or anywhere near 100 % flat.  I work with what we call 'atomically' flat surfaces every day and they are actually quite rough. \n\nFor the system you're talking about I'd extimate somewhere between 1 and 50 microns of space between the sheets of glass depending on how much force you apply. \n\nAlso, remember that glass is not technically a 'solid' so if you're really looking for a good seal you may want to use a different material.
869909
Specific heat capacity, also known simply as specific heat (Symbol: C or c) is the measure of the heat energy required to raise the temperature of a specific quantity of a substance (thus, the name “specific” heat) by certain amount, usually one kelvin. A kelvin is a unit increment of thermodynamic temperature and is precisely equal to an increment of one degree Celsius. Virtually any substance may have its specific heat capacity measured, including pure chemical elements, compounds, alloys, solutions, and composites.
1128546
specific heat Q = mc(t2-t1)\nput everything in SI units..\nthen \n\n40,000= 500/1000 * c(68-20)\n40000=0.5* 48*c \nhence c= 40000/24= 1666.67 joules/kg oC.
885641
Assuming that they have equal masses, it would be whichever material has the highest specific heat, because that defines how much heat energy is required to increase a unit mass of material by a unit temperature.  Water is known for having a very high specific heat, so it could be that, but you should really look up the specific heat (or "specific heat capacity") for all of these materials in your text book.
1098900
The specific heat at constant volume for solid KCl as a function of temperature between 298 and 900 K is given by  (see 1st source):\n\nCp° (J/mol/K) = A + B*t + C*t^2 + D*t^3 + E/t^2\n\nwhere \n\nA = 35.41597 \nB = 70.03472 \nC = -91.38233 \nD = 52.52426 \nE = 0.153460 \nF = -449.1357 \nG = 108.9982 \nH = -436.6841\nand\nt = Temperature in K/1000\n\ndelta-H of formation of KCl at 298.15 = -436.68 kJ/mol (1st source)\n\ndelta-H of formation of KCl at 298.15 = -436.47 kJ/mol (2nd source\n\ndelta-H of formation of K+ (aq) at 298.15 = -252.17 kJ/mol (2nd source)\n\ndelta-H of formation of Cl- (aq) at 298.15 = -167.08 kJ/mol (2nd source)\n\ndelta-H of solution (using data from second source for KCl(s)):\n\n-252.17 +(-167.08) -(--436.47) = +17.22 kJ/mol\n\ni.e., this is the enthalpy change for the reaction:\n\nKCl (s) -> K+ (aq) + Cl- (aq)\n\nCan't help you with the value for Cv, but if you happen to know the molar volume, molar expansivity, and isothermal compressibility of solid KCl, at the temperature of interest, you can calculate Cv from the thermodynamic relationship:\n\nCp - Cv = T*V*a^2/K\n\nwhere T is the absolute temperature, V is the molar volume, a is the isobaric expansivity, and K is the isothermal compressibility.
753535
Just use the formula\n\nE = m*Cp*(Delta T)\n\nE=energy\nm=mass\nCp= Specific Heat\nDelta T = change in temperature\n\nCp= 0.51998 J/(C*g)\n\nGood Luck with the test!
849685
Water has a very high " specific heat ".  Specific heat is a measurement of how much energy is needed to raise the temperature of a substance. \nHere is a table of a few specific heats:\nhttp://hyperphysics.phy-astr.gsu.edu/hbase/tables/sphtt.html\n\nIf you notice, water is much higher than anything else on that list.\nFor comparison, it would take you 5 times more energy to increase the temperature of water by 1 degree than it would take to increase the temperature of solid granite by 1 degree.  \n\nWater has some very strange properties, but because it is so common, we think nothing of it!
358448
specific heat? that would be represented by Cp.\nHowever if you are using delta H then it would either be: delta H (fus) which is the enthalpy of fusion, used in problems concerning melting point (indicating a state change from solid to liquid)\nOr it could be delta H (vap) which is the enthalpy of vaporization, used in problems concerning a boiling point (indicating a state change from liquid to gas)\n\nHeat calculations are done using the formulas:\nq=m x (delta T) Cp <-- Used when there is a temperature change, but no state change\ng= m x (delta H fus) <-- Used for state changes from solid to liquid\nq= m x (delta h vap) <-- Used for state changes from liquid to gas
1032149
Q=MC (delta) T....(5000 G)(.377 J/G degree C)(200 Degree C) which should be.....i get 377 J, which isn't your answer....i just had an exam on this last week, so i thought for sure i am right....the only thing i am not sure about for certain is the specific heat of coal, i got it from a website.....need more info if i am able to help, surely they provided the specific heat of coal....also if latent heat of fusion of vaporization has a part, the answer above is going to be different....sorry dude
332731
It doesn't always have to be.  The values for the heat of fusion of ice that you are using were probably found using equipment sensitive to only two significant figures.  I have seen heats of fusion values that have had more than two sig figs, but they were probably found with more sensitive equipment.
783249
Change it to 1.27 × 10^4\n\nYour value for Specific Heat of Zn is only 3 sigfigs, thus, your answer can only be up to 3 sigfigs.
810276
Well, probably easier to explain empirically -- I know that one of the equations that you would be looking for is Planck's law of black-body radiation.  That, along with other equations involved in transport phenomena could be used to model the system and let you know how much heat you lose from the glass.\n\nOff the top of my head, I can't remember every equation that one would want to use.  Good luck!\n\nThe link is to Wiki's entry for Transport Phenomena -- the first reference there would be an excellent -- if very heavy on the math -- reference for solving this problem.
48432
Well, I work with glass for a living, and for me, two different types of glass are Moretti and Boroscilicate. Boro glass is commonly referred to as Pyrex; it has a higher melting temperature and, when annealed (cooled) properly, is very resistant to breaking. Moretti is a softer, soda-lime glass, with a lower melting temperature (this is the kind I typically work with.) in my sources i've put some links to some glass sellers who could tell you more about different types of glass.