is the equation satisfied by the given value of the varible? 3c+7=24;c=6   yes or no?
338536
3(6) + 7 = 24\n18 + 7 = 24\n\n25 = 24\n\nNo.
909020
Recall the distributive property: a(b+c) = ab +ac\nUse this on the second part of your equation where a = -2, b = p and c = 1.\n-2(p+1) = -2p + (-2)(1) = -2p -2\n\nSo 3p - 2(p+1) = 3p - 2p - 2 = p - 2
565039
For this you are asked to take the the equation y = 2n + 3 and substitute the rest of the values in for n and solve the equation. The implied operation between 2 and n is multiplication.\n\nSo you take the n out of the equation and put in the values that you have listed.\n\nFirst Value:\ny = 2(2) + 3  Do the multiplication first then add the 3\ny = 4 + 3\ny = 7\n\nSecond Value:\ny = 2(1/2) + 3\ny = 1 + 3\ny = 4\n\nThird Value:\ny = 2(0) + 3\ny = 3
407918
(3,-7)(6,15)\nm = (y2 - y1)/(x2 - x1)\n\nm = (15 - (-7))/(6 - 3)\nm = (15 + 7)/3\nm = (22/3)\n\nANS : (22/3)
867879
Just plug 0 in the function whenever you see y.\n\n4x + 3(0) + 24 = 0\n4x + 0 + 24 = 0  \n\nThen solve for x.\n\n4x = -24\nx = -6
777051
6=3*2\n7=7*1\n12=2*2*3\nso the LCM=2*3*7*2=84
838286
well Honestly dear Megan i don't think its correct , coz equation should have ONE " = " \n\nit must be something like this \n-4r ² ± 21r=r+13\n\nGood Luck
978722
You can't, algebraically.  You have two equations and three variables.  Sorry.  You need one more equation, such as a = b.
956578
x^2+3x-y=c\n2x +3 -y'=0\ny'= 2x +3\n\n(remember y^0=1)!
804813
(y+1)(y-7)\n=y^2-6y-7
882001
Your equation f=wl/c is wrong. It should be f*wl = c. In that case\nf'*wl' =  f(1 + (v cos theta/c)) *  wl(1- (v cos theta/c)) = \nf * wl * (1 - (v cos theta/c)^2) = f * wl = c\nas long as v/c is much smaller than 1
928623
Hi Kenima ;\n\n-if u = 6   & t = 3  & v = (u -t )/ 3 \n-just fill the value of " u " & " t " in to Formula of v \n\nv = ( 6 - 3 ) / 3 \nv = 3 / 3\nv =1 \n\nGood Luck ♣
439071
a) log3(x-24) is valid for all x but x = 24\nb) log3(x) is valid for all x but x = 0\nc) x-24  = 3^4 solve for x :)\n\nRival
969498
You need to find a common denominator for each one.\n(7x+3)/x\n\n(40c+18z)/(15cz)\n\n(8+21)/6y = 29/6y
1151963
Yes it is\nX+7=11\n  -7    -7\nX=4
1114001
c = 108 degrees\nyou can find this since A + B + c = 180\nA=B+C+72\nThensubstitute to get A + A + A + 72 = 180\n3A + 72 = 180\nA = 36 so then C= 108
335533
Well, you know C<4 to start with.\n\nAlso, since the total sum is odd, either B or C must be odd, but not both.  Since C has the fewest possible values, I'd start with that.\n\nIf C=3, 5C = 15 and there is no combination of 2A + 3B (where A and B must be 1 or more) that could equal 4.  So C must be 1 or 2.\n\nIf C=2, 2A + 3B must equal 9.  So B must be 3 or less.  If B = 3, A = 0, which is not acceptable.  B must be odd (see above paragraph), so B must be 1 (yielding A = 3).\n\nIf C = 1, 2A + 3B must equal 14.  So B must be 1, 2, 3 or 4.  As in the paragraph above, if C is odd, B must be even.  So if B = 4, 2A + 12 + 5 = 19, so A = 1.  If B = 2, 2A + 6 + 5 = 19, so A = 4.\n\nWe now have 3 solutions:\nI) A = 3, B = 1, C = 2\nII) A = 1, B = 4, C = 1\nIII) A = 4, B = 2, C = 1