What is the formula for the perimeter and area of a rectangle?
343312
perimeter = 2 (side1 + side2)\narea = side1 * side2
753977
Do you mean the perimeter? To find the perimeter of a rectangle, you will have to add up the lengths of each side.\n\nFor example, a rectangle with sides that are 2 feet and 4 feet long would have a perimeter of 2 + 2 + 4 + 4 = 12 feet
445638
l=2w, and length times width is area, so...\nl*w=A...use l=2w, w=w, A=5000\n2w*w=5000, or\n2w^2=5000...divide by two and solve for w!
300586
Adding. example if the lenght of rectangle is 4 and width is 2 then to work out the perimeter you do this: 4+2+4+2= 12 = perimeter.
548292
Assuming that an area may be dissected into triangles, then the area of each triangle is given by \n\nArea = (s(s-a)(s-b)(s-c))^(1/2)\n\nwhere s = (1/2)(a + b + c)\n\nand a, b, and c are the lengths of sides of each triangle -\n\nThe sought for area is (finally) the sum of all the areas of the triangles.\n\nGiven sufficient patience, any arbitrary area will be found.\n\n(Drawing a diagram while slogging through the exercise and looping around the separate triangles in the same direction can yield a shortcut whereby all of the internal perimeters eliminate each other, leaving only the perimeter of the original figure.)
172067
Perimeter is the distance around a figure. The area is the amount of space inside the shape. Good luck!
724177
B)48\n\nFirst of all, you can quickly eliminate choices A and C because the number of tiles (or area of the rectangle) has to be greater than or equal to the perimeter.  Then just use guess and check to see what dimensions give you a perimeter of 38 and an area of 48 or 52.  You'll come up with 3 x 16.
443635
You can use Heron's formula if you know the length of all three sides. \nHeron's Formula:\nLet s be the semiperimeter (which is half the perimeter) and a,b,c be the length of the sides, then the area is\nA = sqrt[s*(s-a)*(s-b)*(s-c)]\nperimeter = 4+4+6 = 14\ns = 14/2 = 7 (because s is one-half the perimeter)\nA = sqrt[7(7-4)(7-4)(7-6)]\n= sqrt(7*3*3*1)\n= sqrt(63)\n= 3*sqrt(7) which is approximately 7.93725\n\nYou can also use the Pythagorean Theorem to find the height.
241144
to calculate the area of a 2-dimensional space you always multiply length x width, or in this case height\n\nC
182640
I'm not sure if this is what you're asking, but if...\nd = length\nd-3 = width\n\nthen the area is d(d-3), a.k.a. d^2 - 3d .\n\nHope this helps!
650879
Use string, paper, and a ruler.  The string can represent the perimeter, and you can draw a grid on the circle to represent the units of area.  Just don't get too in depth on the origins of pi.
528659
This is simple algebra. I'll use P for perimeter, and L and W for length and width.\n\nWe know that 2L + 2W = P = 94. Also, 2W + 3 = L.\n\nSo, put these equations together and solve.\n\nL - 2W = 3\n2L + 2W = 94\n\nAfter solving, you get L = 97/3 and W = 44/3.
6341
Area of a Rectangle\nA rectangle is a good, simple shape to begin with. The area of a rectangle is equal to the product of the length of its base and the length of its height. The height is a segment that is perpendicular to the base. For a rectangle, the base and height are often called the "length" and the "width", and sometimes the height is referred to as the "altitude." \n\nArea of a Parallelogram\nTo find the area of a parallelogram, we can use the same formula that we used for the area of a rectangle, multiplying the length of the base times the length of the height. \n\n\n\nLet's find the area of a parallelogram that has a base of 23 cm and a height of 7 cm. If we substitute the values into the formula, we find that the parallelogram has an area of 161 square centimeters\n\n&...
83837
The dimensions of the rectangle are 5.5 cm x 16.5 cm\n\nIf the rectangle is 3x longer than it is wide, then there are four units that make up two sides...1 unit width, and 3 units length.  So we have four units (4x) that make up one half of the perimeter.  That means that eight units (8x) will make up the entire perimeter.\n\n8x = 44cm, therefore x = 5.5cm\nWe already said that one side is 3x and the other is 1x, so that gives us dimensions of 5.5cm x 16.5 cm
775763
Let the sides of the rectangle be x and y.\n\nWe have xy = 1000.\n\nThe perimeter of the rectangle is 2x + 2y.\n\nUsing the area equations, solve for y in terms of x:\n\ny = 1000/x\n\nThis gives a perimeter equation P(x):\n\nP(x) = 2x + 2000/x.\nP(x) = 2x + 2000x^(-1)\n\nTake P'(x) and set it equal to 0:\n\nP'(x) = 2 - 2000x^(-2) = 0\n\n2 - 2000x^(-2) = 0\n2 = 2000x^(-2)\n2x^2 = 2000\nx^2 = 1000\nx = sqrt(1000)\nx = 31.622 m.\n\nThe rectangle is a square having side length 31.622 m. The perimeter is 124.491 m
906875
The trick is turning the word problem into equations.\n(Key: length = l; width = w)\n\nThey tell you the length is 3 feet more than twice the width, so:\nl = 2w + 3\n\nThen they tell you the perimeter (which is twice the width and twice the length) is 36, so:\n2l + 2w = 36\n\nYou should be able to take it from there.
71096
let area be A\nwidth be W\nlength be L\nnow area of rectangle is = length * breadth \n    A = L * B\n  L = A/B\n L = 3x (squared) +14x+8 / x+4\n   = (3x+2)(x+4) / (x+4)\n   = 3x+2