How do you find the periphery of a quarter circle with a radius of 14?
349504
A periphery is synonymous to the perimeter...For a circle it is also called circumference. It is the measurement of the length of the boundary of any object...in this case part of a circle.\n\nFormula for the circumference of a circle, C = 2πr\nwhere:\nπ = 3.1416 (up to 4 decimal places)\nr = radius of the circle\n\nTherefore, for a quarter of a circle, the formula becomes:\n\nQuarter circle formula, C/4 = 2πr/4 \n\nSolution:\n\nC/4 = 2πr/4 = 2π(14)/4 = 28π/4 = 7π = 21.9912 units
312528
The radius of a circle is the distance from the center of the circle to the edge of the circle.
1174230
I think you have to know how many degrees the segment is.  Then, calculate the area of the entire circle:\n\nPI x radius ^ 2 (squared)\n\nThen, divide the degrees in the segment by 360, so if your segment is 54 degrees, it's:\n\n54/360 = .15\n\nThen, multiply the result of the 2nd calculation (.15 in the example) by the area of the circle you calculated in step 1, and there's your answer.\n\nThere's probably a more elegant way, but it's been 25 years since I took a trigonometry or algebra course.
914363
Find the center-radious form of the equation of the circle with center = (2,-6) and the tangent to the y-axis.\n\nIf tangent to the y - axis then the point (0, -6) is the point of contact (as tangent to circle _|_ radius at point of contact)\n\nTherefore radius = 2\n\nTherefore required circle is\n\n(x - 2)² + (y + 6)² = 2²
40239
A= pi x Radius(squared)\nA= 3.14 x 10 (squared)\nA= 3.14 x 100\nA= 314\n\n*2piR is the formula to find the CIRCUMFERENCE of a circle. (the second answer is wrong.)
797386
Consider a regular n-gon in a circle of radius r with side length l\nDraw in all radii from vertices to centre.\nThis forms n isosceles triangles with the sides of the n-gon as their bases\n\nThen angle at centre = 360/n° and each angle at base = (90 - 180/n)°\n\nBy sine rule: sin(90 - 180/n)° /r = sin(360/n)° / l \nWhence l = r * sin(360/n)°/ sin(90 - 180/n)°\n= r * sin(2 * 180/n)°/ cos(180/n)°\n= r * 2 sin(180/n)°cos(180/n)°/cos(180/n)°\n=2rsin(180/n)°\n\nSo the perimeter of the polygon is 2nrsin(180/n)°\n\nNote: As n →∞ Perimeter  → circumference of circle\nie lim  n →∞ 2nrsin(180/n)° = 2πr\nSo lim  n →∞ nsin(180/n)° = π\nOr for large n, sin(180/n)° ≈ π/n; which makes sense given that for small x (in radians) sinx ≈ x\n\nGiven area of a triangle = ½absinC\nthen area of 1 isosceles triangle = ½r²sin(360/n)°\nSo the area of the polygon is ½nr²sin(360/n)°\n\nThus for n = 9 and r = 10;\nl = 2rsin(180/n)° \n= 20 sin 20°\n≈ 6.84 in
692007
its quite simple the radius is half way threw the circle so its the radius 3 squared which equals 9 and 9 times pi or 3.14 equals 88.7364 but u mite have to round it so if u round to a whole number it would be 89 but to the nearest tenth it would be 88.7
1056342
Hint, try to work out the radius!  Do your homework yourself.
970313
r=radius\nd=diameter\n\n1 C=2r(pi)\n2 C=d(pi)\n\n(Same thing because 2r=d)
350225
C=2*π*r\n\nC-circumference\nr-radius\n\nd=7=2*r\n\nr=7/2\n\nC=2*π*(7/2)\n\nC=7π=7*3.14=22
392733
Divide the circumference of a circle its diameter.
1033875
What "ChinNa90" gave was a very general form of a conic section equation - it does not have to be only circle, but also a parobola or ellipse or hyperbola. \n\nThe standard and easily understandable form of a circle in 2D Cartesian (x and y) coordinates is given by:\n\n(x - a)^2 + (y - b)^2 = r^2\n\nwhere:\nPoint (a,b) is the Centre of the circle\nr is the Radius\n\nTherefore, if you wanted the equation of a circle whose centre is (3,4) and radius is 7 units, then it's equation would be:\n\n(x - 3)^2 + (y - 4)^2 = 7^2\n\nx^2 + y^2 - 6x - 8y + 25 = 49\n\nx^2 + y^2 - 6x - 8y - 24 = 0
4324
well the radius of the inscribed circle is r=S/p, where S is the area of the triangle (b*c/2) and p is the semiperimetre ((a+b+c)/2); so r=bc/(a+b+c), where b,c are the sides of the triangle and a is the hypotenuse.\nif r is an integral, then a+b+c divides bc, so b and c are of integral type.
168080
Any circle that is tangent to two adjacent sides of a polygon has to have it's center on the bisector of the angle between them. Construct the bisectors of two of the angles and put the center where the lines cross.\n\nIf you construct a line from the center that is perpendicular to any of the sides, that gives you the radius of the circle.
991890
Try the 2-2 pattern. it's the best way. The 3 is done with that criss-cross pattern, but the 2-2 allows you to continue the circle, just make it have a big radius
622311
Simple ratio where C is the full circumference\n24/360 = 16pi feet/C\n24C = 360*16pi\nC = 15*16pi\nC = 240pi\n\nFrom the circumference you can easily derive the radius:\nC = 2pi r\n240pi = 2pi r\n240 = 2r\nr = 240/2\nr = 120\n\nThe radius is 120 feet
496924
Well, you know that each corner of the octagon lies on the circle (by definition). So, if A and B are the names of two adjacent corners, and C the center of the circle, you also know that AC=14.15, and BC=14.15. \n\nAnd you also know that a regular octagon will have its corners equally spaced around the circle. Since a circle is 360 degrees, the AC/BC angle is 360/8 = 45 degrees.\n\nFrom there you can easily calculate the length of AB using simple trigonometry, which is probably the goal of the exercise :-)