Anybody who can answer this 10 points??
343985
need to use the chain rule i.e.\n\nf'(pq) = p'*q + p*q'\n\nwe get:\nae^ax/(sin(bx+c)) - be^ax*cos(bx+c)/[(sin(bx+c))^2]\n\nThis is the correct answer\n\n*edit* srry couldnt see all of it if its on one line so split over two lines the answer is:\n\nae^ax/(sin(bx+c)) \n-be^ax*cos(bx+c) / [(sin(bx+c))^2]\n\n\nand ofcourse if you like, further simplification is possible with cos(bx+c)/sin(bx+c) =1/tan(bx+c)=cot(bx+c), also you can take a factor of e^ax out if you like but the above answer is perfectly accebtable.
954535
Dude, no offense, but you asked this question twice, which equals -10 points....\n\nDon't do that!!!
686844
give me my ten points!!!!!
174738
really dont know thks for 2 points
1048168
dont know?   2 points!!
768969
I dont know the answer but atleast I have seen your question so give me best answer 10 points I am respecting you sir and also I have given you a thumbs up I am apoor guy in level2..
729815
Wait? Did I really just get two points for answering this? Are you serious?\n\nAlright!\n\nHey ---- you can gain 3 points right away if you choose my answer as the best!
1061888
What are you talking about.\n\n2 points for me
727925
to get your 10 points
568775
Great one!!!  10 Points for you. 2 Points for me.
986456
mind givin 10pts 2 me...???\nnoone answered ur q....\nif i didn answer... it would me deleted... and u'll loose 5 pts in vain...
585163
Yes.  Now....can I have my 10 points please?
267836
http://blog.360.yahoo.com/blog-NVb99sQ4RK5BVgIbxdcQdcRtfT8-?cq=1&p=13\n\nI think this is the 10th time I've answered this question today.
812050
just to get more points
606457
I don’t know what are you talking about but …….\nCan you……\nChoose me as a BEST ANSWER.\nI want 10 points.
248233
hi friend i really have no idea  ....but i have a personal request if u will get no answers except mine please choose my answer for the best i really need some points to go to next level. \ni will b really thankful to you
827269
good question. would like 10 points if no-one else answers please.