How much additional string, to the nearest 100th of an inch is needed?
348932
It's just 2 * pi, or 6.28 inches because it's the difference of the diameter by 2 inches.
515359
1/1000th of an ampere
358099
0.43 & 0.0062\n\nDivide by 100
1101854
i don't really think there is a limit. so long as you can get your string length between the " " quotes, and on the same line, it should accept it. there's rumours of it being 65000 characters, however someone wrote a javascript and got it well over 2,000,000 characters.
784078
The optimum thickness is infinity. You need to factor in the cost for various thicknesses and weigh that against how much heat you are willing to lose.
572231
My dear friend you need two more dimensions ie., length and breadth to calculate that.
49759
A comparable question: How long is a piece of string?
832125
gonna need a little more than that to go on....
568941
You can't do it without repeating a number. If you put a number in a box, 200/that number must go next to it and below it.
133989
probably 2-5 grams.  it depends on the dimensions of the ballon.  you might as well ask a question like "how long is a piece of string?"
323833
The long way to do this is much simpler:\n\n1) convert everything into inches and re-write the problem.\n2) do the easy math\n3) see how many times 12 goes into your new answer (that'll be the number of feet in your answer)\n4) then add on the remainder (that'll be the number of feet in your answer)
355080
The easist way is to just type it into a Google search and it will do it for you.  So if you type: 4ft into inches  then it will give you this answer: http://www.google.com/search?hs=mUM&hl=en&lr=&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&q=4ft+to+inches&btnG=Search\n\nNeat huh?
684908
About 1/30" of an inch, or 0.8 mm
245127
Maybe I'm not understanding the problem correctly, but if "There is only space for the pature 2 be @ most 100ft" means that no side can be longer than 100 feet then I think you may have written the question down incorrectly.\n\nIf each side has to be less than or equal to 100 feet, then let's say that each side *is* 100 feet in length. There are 4 sides, so the perimeter is 4 times 100 feet = 400 feet. You say you have 500 feet of fencing. This is more than enough to surround the maximum-sized pasture allowed. So what's the problem?\n\nThe only two linear equations you need to worry about in this case are:\nwidth <= 100\nlength <= 100\n\nChoose any values for the width and length that satisfy these constraints,\nsay the width = 75 and the length = 50 or the width = 2 and the length = 89\nand you have solutions to your question.\n\nOften these questions ask for the maximum area that it is possible to enclose. In this case there is only one solution: width = 100, length = 100 therefore the area enclosed = 10,000 square feet and the amount of fencing used is 400 feet.
130506
I believe you are correct. See if you go down the line it is 100,000 centimeters and then 1,000,000. So seeing your question, You are certainly correct
973110
This an excellent site for you :-\n\nhttp://www.onlinearchery.org.uk/advice/tune/string_making.html
845900
Do to the increased weight (volume) I'd say 1/100th of 33 feet.