any one give me minmax algo for java game connect 4 game?
347782
http://www.google.com/search?q=alpha-beta+OR+minimax+connect-4+java
1092593
try useing Gamecopyworld.com
216910
theres good game called MAX POOL.. u can search for it on google..\n\nthe AKA of it is COOL POOL.. AWESOME 3d POOL
1005750
go to www.java.com, install the latest version of java. It is free. It will help all of the pogo games run smoother.
374477
codes with prefixxes for game
56444
www.koders.com\n\nthese guys have all the code.from c,c++ to java..
282739
sounds like you need too install the lastest java go too this site and install the lastest version http://www.java.com/en/
216650
Just go to the link below and download the latest Java SDK.\nHopefully, that would help you.
59731
Try the Java reference library.  Here is a link to it online:
232131
#include<iostream.h>\nint main() \n{ \n   int stop=false;    \nchar pl='X';    \nchar p; //is used for checking when a game is won  \n  \nint v; //value    \nchar list[]="123456789&#92;0"; //create our array that holds all the values \n\n   do { //start our while loop        //INPUT \n       cin >> v;        //MARKING \n       if (list[v-1]!='X' and list[v-1]!='O')\n {       \n    list[v-1]=pl;       \n }        \nelse\n {  \n     cout << "That place is already taken.&#92;n";   \n      goto skip; //if its already taken skip the turn switch             \n}  \n    if (pl=='X')\n {  \n          pl='O';  \n   }\n   else\n { \n \n          pl='X';  \n      }        skip:;        //win checks   \n     for (int w=0; w<2; w++)\n{    \n        if (w==0)\n{       \n        p='X';   \n         } \n           else{ \n                p='O'; \n           }\n     for (int z=0; z<9; z=z+3)\n {\n     if (list[z]==p and list[z+1]==p and list[z+2]==p) {                 \n  stop=true; \n        goto GAME_END;    \n            } \n           }\n            for (int z=0; z<3; z++) { \n        if (list[z]==p and list[z+3]==p and list[z+6]==p) {\n                   stop=true;            \n       goto GAME_END;        \n        }  \n          }        \n    if (list[0]==p and list[4]==p and list[8]==p or list[2]==p and list[4]==p and list[6]==p)\n{     \n          goto GAME_END;   \n         }   \n     } \n       //PRINTING OF THE VALUES       \n for (int x=0; x<9; x++) {  \n           cout << list[x];   \n          if (x==2 or x==5 or x==8) {  \n              cout << "&#92;n";    \n         }    \n    }   \n     //END PRINTING OF THE VALUES \n       //system("PAUSE");   \n }\n while (stop==false); \n//End the while loop    \nGAME_END:;      \n  cout << p << " wins!&#92;n";      \n  system("PAUSE");\n}
1124769
You need the java applet to play the game.
859174
1.6P4 has no hyper threading.....from what you ask seems like you built an Atari. You cant play these games on an ATARI
974181
go to gamewinners.com
631263
omg YESSSSSSSS... HOLD ON I'LL FIND IT  yes you asses.there a freekin page that will tell you if you can handle games er not  1 sec\n\nfoooook i cant find that page.it was so usefull  but all i coould get is this microjunk 1..load it up in i.e. and hit the scan my puter button on the bottom left\n\n\nok found it 3 hours later...\npick yer game then hit scanit  ------------------->\nhttp://www.systemrequirementslab.com/referrer/gamespy_all
468063
Ive played Chessmaster2000! Belive theres a Plyr. vers.\n Plyr. or set it to play itself...:)
212031
Well, the question doesn't have all the required details, but why not:\n- make sure that you ar eusing the correct type of vaiable (string/number/etc)\n- make a simple if statement that says, IF the number of tries is less than 10 then continue (where number of tries is lets say "x")\nOnce an answer is chosen, if the answer is corret, then thats it, ELSE, if x < 10 then x = x + 1 \n(this makes sure that x is less than 10...and adds 1)\nIF x = 10 THEN MsgBox "HARD LUCK" (like that, if the previous number was 9, by adding 1 it became 10...this line finishes the game up)\n\nAt the end, make sur eto reset the value of "x"\nx = 0
849879
here you go...\n(it'll work with up to 255 different disks, if you need more, you'll have to replace chars with ints)\n\nm1(char *a,b) {memove(b+1,b,strlen(b)+1); *b=*a; memmove(a+1,a, strlen(a);}\nm(char *a,b,c) {if (*a)  {m(a+1,b,c);m1(a,c);m(b,c,a);}