What is the radius of curvature of the human femur?
345631
the average femoral anterior radius of curvature of a human is 124cm (+/-36 cm).
958759
At birth the human body has about 350 bones, but by the time adulthood rolls around, some of our bones have fused together to give us a total of 206 bones in our body!\n\nHere is the breakdown:\n\nThe adult skeleton consists of 206 bones . . . \n\n- 28 skull bones (8 cranial, 14 facial, and 6 ear bones); \n\n- the horseshoe-shaped hyoid bone of the neck; \n\n- 26 vertebrae (7 cervical or neck, 12 thorax, 5 lumbar or loins, the sacrum which is five fused vertebrae, and the coccyx, our vestigial tail, which is four fused vertebrae);\n\n- 24 ribs plus the sternum or breastbone; the shoulder girdle (2 clavicles, the most frequently fractured bone in the body, and 2 scapulae); \n\n- the pelvic girdle (2 fused bones); \n\n- 30 bones in our arms and legs (a total of 120); \n\n- There are also a few partial bones, ranging from 8-18 in number, which are related to joints.
739888
On average, an adult human has 206 bones (according to Gray's Anatomy, but the number can vary slightly from individual to individual), but a baby is born with approximately 300 bones. The difference comes from a number of small bones that fuse together during growth, such as the sacrum and coccyx of the vertebral column.\n\nThe number of bones per area:\nSkull (22) \nChest (25)\nVertebral column (26)  \nFeet (52) \nHands (54)\n\nSo the hands have the most bones.
318501
1.618\n\nit's PHI\n\nThe Divine Proportion.\n\nIt is the number of nature, try measuring this with a tape measure:\n\nThe length from your head to foot then divide it by the length of your navel to foot.\n\nIt is 1.618, although it might not be very accurate as there are many measuring discrepancies, this 1.618 is really the answer if you should just be very accurate.\n\nTry this: from your shoulder to fingertips the divide it by the length if your elbow to the finger tips.\n\nI guess it would be PHI again.\n\nThere are many of these occurring in nature, we are not just seeing it.\n\nAnd as with the Fibonacci Sequence, yeah, it's appears to be PHI either.
569932
the radius of curvature of a plane mirror is infinity( iam dead sure)\n\n\nThe term radius of curvature has specific meaning and sign convention in optical design. A spherical lens or mirror surface has a center of curvature located in (x,y,z) either along or decentered from the system local optical axis. The vertex of the lens surface is located on the local optical axis at a distance equal to the radius of curvature from the center of curvature. The sign convention for the optical radius of curvature is as follows:\n\nIf the vertex lies to the left of the center of curvature, the radius of curvature is positive. \nIf the vertex lies to the right of the center of curvature, the radius of curvature is negative. \nThus when viewing a biconvex lens from the side, the left surface radius of curvature is positive, and the right surface has a negative radius of curvature.\n\nNote however that in some areas of optics other than design, other sign conventions are sometimes used.
686118
THE STRONGEST BONE IN THE BODY IS THE THIGH BONE ALSO KNOWN AS FEMUR\n\n\nThe femur or thigh bone is the longest, most voluminous and strongest bone of the human body (able to withstand over 550 pounds of force). It forms part of the hip and part of the knee.\n\nThe word "femur" is Latin for "thigh". In medical Latin its genitive is always femoris, but in classical Latin its genitive is often feminis, and should not be confused with case forms of femina = "woman".
1067026
consult your doctor.. for curvatures less than 20 exercises may do and the best exercise is swimming others go to a chriopractic practitioner.. >20- 40 some doctors advice to have a brace..  >  40 surgery is adviced
447343
http://www.engin.umich.edu/class/bme456/bonefracture/bonefracture.htm
598614
two rows of four = 8 bones.\n\nscaphoid, lunate, triquretrum, pisiform (my favorite), trapezium, trapezoid, capitate and hamate
917141
the radius is half the diameter.
472888
The normal amount is 206 bones, however, the number varies between people due to sesamoid bones (bones that grow in tendons that experience hight stress).  The patella is a sesmoid bone.  There are also a varied number of bone fragments in the sutures of the skull.
108822
275 bones at birth, 206 as an adult.  I found this out by going to www.ask.com & typing in your question...
346906
http://www.orthojournalhms.org/volume7/manuscripts/ms13.htm
736798
So R=1.6*r; R for body, r for head; and H1=K1*R is the distance from body center to the feet, K1=0.8; and h=k*r is the distance from head center to the neck, k=0.9; Now neck radius p=sqrt(r^2-h^2) and p=sqrt(R^2-H2^2), H2=K2*R is distance from body center to the neck, K2 being unknown.  Find K2;  p^2 = r^2*(1-k^2) = R^2*(1-K2^2), hence (r/R)^2*(1-k^2)=1-K2^2 and K2 = sqrt(1-(1/1.6)^2*(1-0.9^2)) = 0.9622;\nNow head volume v=v0-v1, v0=(4/3)*pi*r^3, v1=(pi/3)*r^3*(2-3h/r+(h/r)^3) is head cut-off part; v = (pi/3)*r^3*(2+3h/r-(h/r)^3) = (pi/3)*r^3*(2+2.7-0.9^3)\nThe same for body volume V=V0-V1-V2, V=(pi/3)*(1.6*r)^3 * (4-{2-3*K1+K1^3} - {2-3*K2+K2^3});\nW=v+V=r^3*C is the whole volume! To plug in numbers to find C, OK?
478313
V = h*pi*r^2\n\nThere h - height\nr - radius of foundation\nV - volume
836396
circumference= 2*r*pi\nwhere r is the radius and pi is approximately 3.14
1010564
Good question. But wouldn't one need to narrow the parameters a bit? Age and height each play a huge role. The difference in the weight the skeleton of a newborn vs. that of a six-footer, when averaged, wouldn't give you a useful representative estimate.\n\nPerhaps the weight of an average-sized adult male or female skeleton? Or, as a percentage of body mass?