What is the formula for converting C degrees into F degrees?
355543
It is to double the C degrees then add 30.  You're right, it's not exact, but pretty close for numbers that could be weather temperatures.
782406
°oO****Oo°°oO****Oo°°oO****Oo°\n\n\n 4 ∫[g(x)] g'(x) dx = 4 x 1/2g(x)² +c = 2g(x)²+c\n\nits the first suggestion that u made but i think you forgot the number 4...\n\n\n°oO~<<_P~'*'_ I~'*'_M~'*'_O~'*'~L _~'*'_A>>~Oo°
964943
(4.7)(9.81)cos 20 degree   ... you do the calculator punching..\n\ncheers
1007444
Used to convert celcius to fahrenheit and reverse.\n\nF = (9/5 *C) + 32\n\nYeah, I know the parentheses are redundant.\n\nAlso \n\nC = 5/9 * (F-32)\n\nJust to assure yourself and me that the equations are correct\n\n20 degrees Celcius is the same temperature as 68 degrees Fahrenheit.
483791
0°C = 32°F\nSo instead of going with 0°C, go with 32°F, so that would be 32 * 2 = 64°F or about 18°C\n\nBut if you are talking about 0°F, which is about -18°C, double that and you get -32°F\n\nSo you either get about 18°C or -32°F
14789
A general form of the equation I beleive you are looking for comes from a basic understanding of thermodynamics.  I am assuming that your ct=(Tfinal-Tinitial)...\n\nSo a general form of the equation would be:\nmCp(Tf-Ti)=Q \n\n"Cp is the specific heat"\n\nWATCH UNITS!!!!!  \n(I am ignoring the conversions in this statement)\n55g*Cp(67degrees UNITS)=343 cal \n\nSolving this equation will give you Cp ... just make sure that you watch units.
944165
F = C * 9/5 + 32\nC = (F - 32) * 5/9\n\nF = 2212 * 9/5 + 32 = 4013.6\n\nHope this helps!
458700
F = 9/5 C + 32\nC = 5/9 (F - 32)\n\nwhere F is degrees Fahrenheit and C is degrees Celcius.
1099854
4.44 ºC\n\nAn easy way to find this out is do do a google search.\n\nGoogle has a buildt in calculator/conversion machine.\n\nhttp://www.google.com/search?q=40+F+in+C&sourceid=mozilla-search&start=0&start=0&ie=utf-8&oe=utf-8&client=firefox-a&rls=org.mozilla:en-US:official
111333
Begin by subtracting 32 from the Fahrenheit number. \nDivide the answer by 9. \nThen multiply that answer by 5.
1151656
C=(5/9)(F - 32)\n\nC = (5/9)(0 - 32)\nC = (5/9)(-32)\nC = -160/9\nC = -17 7/9\n\nDouble that, and you get\n\nC = -35 5/9\n\nF = (9/5)C + 32\n\nF = (9/5)(-35 5/9) + 32\nF = (-320/5) + 32\nF = -64 + 32\nF = -32\n\nANS : -32°F
821224
Degree (C) = (Degree (F) - 32) * (5/9)\nTherefore, 102 F = 38.8888888888... C (round it off to be as accurate as you need).
744550
One way is the reverse of going from celsius to fahrenheit! To find what 10c is in f you would take 10 and multiply by 2, then add 30 to get 50 fahrenheit. Do the reverse to answer your question! Let's say that its 82 f, to get c you would -30 from 82=52,then divide by 2, giving you 26celsius. Hope this helps.
691885
To map [32, 212] onto [0, 100], use Theta(x) = [(100-0)/(212-32)][x-32], or Theta(x)=5/9(x-32).  As you may know, this is the formual to convert Fahrenheit to Celsius.
41963
F=150N\nA=51 degrees\nFh = horizontal\nFv = vertical\n\nsinA=Fh/F => Fh=F*sinA = 116.572N\ncosA=Fv/F => Fv=F*cosA = 94.398N\n\nAlso, F^2=Fh^2 + Fv^2\nlet’s check:\n 22500 = 13589.031184 + 8910.982404\n22500 = 22500.013588   TRUE  (rounding error)\n\nMake sure you understand this (especially if it's your homework) :)
775660
Degrees F = (Degrees C * 9 / 5) + 32\n\nSo,\n\nF = (20 * 9 / 5) +32\nF = 36 + 32\nF = 68\n\n68 Degrees Fahrenheit
69132
F=5/9C+32\nSubtract 32 from each side\nF-32=5/9C+32-32=\nF-32=5/9C\nDivide each side by 5/9 (multiply by 9/5)\n(F-32)/(5/9)=(5/9)/(5/9)C\n=(F-32)/(5/9)=1C=C\nSo\nC=(F-32)/(5/9)\nwhich, as I said before is like multiplying by 9/5,\nso it equals 9/5(F-32)\ndistribut the (9/5) to the F and the 32\nC=(9/5)F+(9/5)32=\nC=(9/5)F+57.6\nconvert to decimal if you want\nC=1.8F+57.6