Math problem help please?
352673
Make right triangles with the height as one leg, a radius (segment from center of base to one of its vertices) as the other leg, and lateral edge as the hypotenuse.  The radius will equal the length of the base edge as it's a side of an equilateral triangle.  So 10^2 + 15^2 will equal lateral edge squared.\n\nSlant height would be the hypotenuse of a right triangle with legs of the pyramid's height, and the apothem (distance from center of base to midpoint of a side.)  You can get the apothem from Pythagorean theorem from the right triangle formed by half a base edge, a radius, and the apothem.  Then use the apothem in another Pythagorean theorem to get slant height.\n\nLateral area = 6 times the area of any one triangle.  Each triangle's area is 1/2 times 10 times slant height.\n\nVolume = 1/3 (area of base)(height).  The area of the base is 1/2 (apothem)(perimeter).\n\nThose are the steps.  Hope you can figure them out from this typing!
133517
the solutions is 7,8,3,2 or 7,6,5,2. The problem works with both sets of numbers.
912865
bring the a's to one side... u then get 9a = 27 ... divide and answer is a = 3
954300
ok\nso its factoring.this is hella easy.10x+40 is 10(x+4)\nso the answer is 10(x+4)there you go
729930
Time =10/20.which one is it really?Imusing 10.If its 20 then use the same steps and solve that problem.\nP=12000(1+3.5/100x10)\nP=12000x1.0035\nP=12042
501445
Try this website. http://www.webmath.com/index3.html
800717
(1) First one is copied wrongly by you                                            (2) Where is the equal to sign?                                                        (3)This equn. also cannot be solved                                              (4)-p/16+5=9  Multiplying all the terms by 16 ,we get -p+80=144   =>-p=144-80=66 Therefore p=66 YOU SHOULD BE MORE CAREFUL BEFORE SENDING YOUR PROBLEMS TO YAHOO ANSWERS.HOWEVER,YOU MAY SEND THE CORRECTED VERSION OF THE PROBLEMS TO ME IMMEDIATELY THROUGH YAHOO ANSWERS.
250230
You both missed 803 as another answer.\n\nThis problem can be summed up as finding digits a,b, and c where:\n\n   11(a^2+b^2+c^2) = 100a + 10b + c\n\nand where a is non-zero.\n\nOffhand, I can't think of anything other than trial and error.
520168
Try this:\n\nhttp://www.algebra.com/
269746
Make 2 7/15 an improper fraction, flip it over to its reciprical and mulitply the two.\n\nBoy...I hope I got that.  *bits fingernails*
132964
You are solving for k so it you need to rewrite the problem to look like this k=z/(xy) where x=3, y=8, z=6 substitute the letters for numbers so k=6/(3*8) k=6/24 or k=1/4 to check just solve for any other letter such as z by using what you know of k and you should come out with z=6
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
111021
If you are sloving for X then anything greater than 2 will work. basically it is 6 time what (X) will be greater than 12. Well 6x2=12 so that won't work.
892068
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
952904
A= (B*h)/2\nA=(10*15)/2\nA-=75
821450
go to a math website off yahoo. it should help.
787725
To solve a problem like that:\n\n2x-3+4x = 10 (i'm not sure if this is your answer but I'm using it as an example)\n\nFirst combine the x's on the left side to get 6x-3 = 10\n\nThen add 3 to both sides to cancel the 3 on the left side.  You will not have 6x = 10.\n\nDivide both sides by 6 to isolate the x.  You will now have x = 10/6 (or 5/3)