How can you identify the frequency of a wave?
339135
first one is quite correct but frequency is in per second\n\n47 waves/min = (47/60)Hz   (1 Hz= 1wave/sec)
738444
You create two waves a second -> frequency = 2 Hz\n\nperiod = 1/f = 1/2 = 0.5 s\n\nThe wave travels 0.18m per 0.5 s, which is .36 m/s
833592
measure the size of bowl(better if rectagular or square) and time how long it takes for waves to hit the sides for one minutes. about 10 waves. multiply by 60 to get speed/hr
729264
The fundamental frequency = the first harmonic.\nThe first overtone = the second harmonic.\nThe second overtone = the third harmonic.\nand so on...\n\nSee http://en.wikipedia.org/wiki/Harmonic for lots more surrounding detail.
445689
Radio shack has a book (about $20) that has every freq you could ever need in it , even your local #'s
311539
Radio Shack sells FM frequency detector.  Since most listening devices work on FM frequencies, it should be pretty simple to locate.  You can also use a Near Radio Field Meter.
584010
E = 1/2 M x v^2 x F x H \n \nWhere v is the velocity of the load hitting the surface and H is the time period in which the frequency continues.
119936
You need to know the mass of the earth and it's natural freqeuncy. The answer is usually about 10 Hz. It goes "dong" at about ten times per second, as opposed to the human ear, which can start to detect "dong"s at 2000 Hz.
45092
You first have to represent your wave as a function. Let's say your wave has maximum and minimum aplitudes of 2 and -2 respectively, and a period of 10 seconds. The square of your function would be \nx^2 (t)= 2^2.\n\nMathematically, the squared signal is x^2 (t) and the "mean squared" signal is the integral of s^2(t) over an entire period, divided by the period. Finally, the "root mean squared" is the square root of this final result. \n\nIt's hard to put in the integrals and square roots in this text only format, so check out the website.
792662
Frequency = velocity of propagation / wavelength.\n\nFor light, we assume it is moving in a vacuum, so vp is 3e8 m/s.  The wavelength of 310nm is 310e-9 meters.  Then we plug the numbers in, and we get (3e8 m/s) / (310e-9 m) = 967.742e12 Hz because 1/s is the same as cycles/sec, which is a Hertz.
505284
Sure, I have a scanner and the website I use to find frequencys is http://www.radioreference.com/modules.php?name=RR&stid=17 . \n\nHope that Helps :)
957687
you would hear the resultant of the two frequencies both in frequencie and amplitude.
437661
This requires the use of doppler shift formula for a moving source and stationary observer:\n\nf = f0 ( v / ( v + u ) )\n\nf0 = actual frequency = 5\nv = speed of wave = 20\nu = relative velocity of source away from observer = -10\n(since travelling toward)\n\nf = observed frequency = 10 Hz\n\nNow velocity = v = fl = frequency * wavelength\n\nso wavlength l = v / f = 20 / 10 = 2m
1097080
a)\n\n(change in frequency)/(recorded frequency) = (Speed of emitter)/(wave speed).\n\nChange in frequency = 22 Hz\nRecorded frequency = 820 Hz\nSpeed of emitter = what you are trying to find.\nWave speed = speed of sound = 340 m/s\n\n(22 / 820) x 340 = 9.12 m/s\n\nb)\n\nThe frequency of the echo is (I'm guessing for this one sorry) double the regular frequency, which is 1684 Hz.\n\nc) \n\nThe frequency heard by the man is 820 Hz by definition isn't it? Thats the frequency as the boy passes anyway.\n\n[EDIT] Wait I just realised your whole question makes no sense. Due to the limited info in the question I was assuming you meant it falls to 820 Hz from the emission frequency at the point where the boy passes the man. But why would the frequency fall? The point where the boy passes the man is the point where the frequency experienced by the man is highest.\n\nOh well I hope my answer helped a bit anyway.
953272
f * w = c\n\nFrequency in Hertz times wavelength in meters equals the speed of light.\n\nTo solve for frequency.\nf = c/w\n\nTo solve for wavelength\nw = c/f
774563
The amplitude should not have anything to do with the frequency of the wave.  \n\nAssumption:\n1.) 12 microseconds is the time\n\nEquation:\nFrequency = 1 / time\nFrequency = 1 /.0000012 \nFrequency = 83333.333\n\nFinal Answer: 83.33 KHZ
476058
Don't know about calculations, but I know the frequency of the vibrations will tell you what is making the noise.