why six ball for the over cant be five or more.?
341447
YES. IT CAN BE DUE TO UMPIRES MISTAKE.
206747
If, as you say, you're not concerned about the 6th ball:\n\nOn the first ball, there are 49 total balls, and 5 of them are the in the winning combination.\n\nOn the second, there are 48 balls, 4 winners.\n\nEtc.\n...\n\n(49/5) * (48/4) * (47/3) * (46/2) * (45/1) = 1,906,884 possible cominbations\n\nYou would need 1,906,884 tickets.
188381
Same reason Flintoff or Pietersen can't open an innings.  There has always been a case for someone to open up a lead and then the big hitters come in to push the score up.  Especially when the ball is new and it can swing, bounce extra which is more of a liability to these type of players.
998697
there's a difference between "hand ball" and "ball to hand". u cant help the latter. so maybe thats why.
246092
I wouldn't think so. That game is played with only one ball so if another ball happened to be on the field I imagine game play would stop or the 2nd ball would be ignored until game play could be stopped.
445899
you have to be insane nuts\nplay without abandon\nthe box belongs to you\nno one is allowed inside the six\nremember, an object in motion will always break an object sitting still.  \nYou have to be crazy\nnothing can stop you from getting to the ball and securing it
1005646
No to one, no to two, no to three, there should just be one head ref it simplifies things, no to four, no to five, on 6 do you mean he cant come back in, or he just has to leave the field for a few minutes, with his side playing with 10, and then he can come back in? if so, yes, if not, no, no to seven, no to eight, that would be awful, they could carry it down, and drop kick it into the net from a couple yards away, no to 9, and sort of to ten, i think this should be the point system:  four for a win, two for a tie, none for a loss in regulation.  In the group stage, ties at the end of regulation should go to two ten-minute halfs of extra time, silver goal style.  If still tied after extra time, the match would then be a tie, it would NOT go to penalties.  If there was a winner in extra time, that team would receive three points, and the loser in extra time one.
750078
Subsequently, some countries experimented with eight balls an over. In 1922, the number of balls per over was changed from six to eight in Australia only. In 1924 the eight ball over was extended to New Zealand and in 1937 to South Africa. In England, the eight ball over was adopted experimentally for the 1939 season; the intention was to continue the experiment in 1940, but first-class cricket was suspended for the Second World War and when it resumed, English cricket reverted to the six ball over. The 1947 Laws of Cricket allowed six or eight balls depending on the conditions of play. Since the 1979/80 Australian and New Zealand seasons, the six ball over has been used worldwide and the most recent version of the Laws in 2000 only permits six ball overs.
468680
many players have hit four in a row, some have hit five.\ni don't know of any that have hit six in a row.
50506
That sounds like a question for a magic eight ball.\n\nOr a coin.
764918
A bowler can bowl only 20% of the quota of his team. Normally if the match goes full distance when his team is fielding, the team bowls 50 overs and he can bowl 20% of 50 overs, which is 10 overs.\nHowever, if overs are reduced on account of rain or calmity and the overs are reduced to 25 overs, each bowler can not bowl more than 5 overs. However, if the number of overs are not exactly divisible by 5 and you get fraction, i.e. if overs are 28 overs, than 3 bowlers can bowl 6 overs and rest two can bowl 5 overs each.\n\nIn short it can not exceed 20% in a full game and in case of reduced game match it could exceed 20% , but only by that fraction as explained above.
993357
5 BOWLERS\n\nELSE THEY CAN'T OUT WESTINDIES TWO TIMES
1065918
To get your answers, imagine what has to happen.  \n\na) First, you have to pick 1 of the 4 white balls out of the 12 balls there.\n\n2nd, you have to pick 1 of the 3 white balls left out of the 11 balls there.\n\nSo, in order to get a red and then a red, you need to get 4 out of 12 followed by 3 out of 11 or 4/12 times 3/11 or 12/132 = 1/22.\n\nb) First, how many ways can 5 people line up?  5!.  How many ways are correct (assuming they all have different names, only 1).  So, the prob is 1/5! or 1/120.
419587
TO MAKE THE GAME FURTHER INTERESTING..\nTO MAKE THE GAME A RUN-FEAST..\nTHATS WHY NOW A DAYS TEAMS CROSSING 300 RUNS EASILY.
1024463
the home team supplies 12 dozen per game, now all 144 may not be used, but that's what is ready to be used at any given time. the guy that said 20 is obviously a moron, 20 balls could easily be used on 1 or 2 batters. think....homers, foul balls, scuffed or damaged balls, not to mention the simple fact that a pitcher can request a new ball at ANY TIME, regardless of the fact that the one he's holding may be brand new itself.
156224
Hey this isn't a magic 8-ball!
345437
Wait, I'm confused. Are we saying: 90 Red Balls, 90 Blue Balls, 90 White Balls, 10 Multicolored Balls? If that is the case, and you are asking how many must be taken to guarantee that there will be at least 10 of one variety, then the answer is 37. It is possible to pick 9 of each of the four varieties. The next ball would therefore guarantee at least 10 of the same type.\n\nADDED:\nSo then, it's 30 Red, 30 Blue, 30 White, and 10 Multicolor? Then the answer is still 37, for the reason I described before. Unless...are those 10 other balls all the same? Do you mean 10 balls with mixed colors on them, or 10 balls, each a different, random color, but not red, blue, or white? Because if that's the case, it's 38. It is possible to pick 9 of each of the three colors, and all 10 balls of different colors, and you would then have 37. The next ball (38th) would have to be the 10th of either red, blue or white.