Why is it not possible to use the formula D = M/V to calculate the density of gas?
343770
Because gas doesn't have a definable 'volume'.  You can compress it and change it as long as you are willing to deal with changing the pressure.  To compensate, you have to PV = nRT
757137
Volume of the balloon * density of the gas = mass of gas in the balloon
865332
density =mass over volume ( i hate chem)
700450
Letters A, B, D.\nIn not sure about C, its wording is tricky.\nIdeal gas law : PV = nRT\nReal gas law : (P + (a(n / V)^2)) * (v - nb) = nRT\nThe corrected pressure times the corrected volume.
878174
Weight times density yeilds volume. You need it's density before you can compute it's volume.\n\nOnly with materials (like water) where the specific gravity is 1(implying 1ml of water weighs one gram) are you able to convert fluid measurements to/from weight, without explicit multiplication/division.
67284
well the formula is the square root of 3kT/m  where k is the boltzman constant(1.38066 x 10^-23 J/K) T is in Kelvin so you would have to convert(just add 273 to the temp in Celcius) so your T is 290K and m is the mass. the mass can be found using the density of water(1000 kg/m3) the formula for density is d=m/V and V can be found by using the volume of a sphere, 4/3(pi)r^3 oh, and don't forget to convert the nanometers into meters, then cut the diameter in half for radius.\nusing this information to get you started, you should be able to do it yourself. so you should try it first before reading further :) im sure you were familiar with all of those formulas, you just need to remember to think of things all at once so you can put them together.\n\nok, so we start with the rms velocity formula. first problem is that we need mass. ok, lets solve for mass using density. oh right, we need volume, ok, lets solve for volume then:\nwe need to make the diameter into meters, so thats 1.0 x 10^-8 meters. now we cut this in half to get the radius(r) so that's 5.0 x 10^-9.\nV=(4/3)(pi)r^3\nV=(4/3)(3.14159)(5 x 10^-9)^3\nV=5.236 x 10^-25 m^3\nnow we have volume, so using the density of water(1000 kg/m3), we can solve for mass:\nd=m/V\n1000=m/(5.236 x 10^-25)\nm=5.236 x 10^-22 kg\nok, now we have mass, so we can use our original rms velocity formula and solve for velocity. *sigh* finally.\n\nv(rms)= sqrt[3kT/m]\nv(rms)= sqrt[3(1.38066 x 10^-23)(290)/(5.236 x 10^-22)]\nv(rms)= 22.94 m/s\n\ni would check my math if i were you though, i tend to make stupid calculator errors. the concepts are there though :p
33182
We'd need a formula editor to do this...\n\nPressure difference delta-p must equal vapour pressure p(x) in order to get the vacuum on top of a manometer.\n\nPressure is force F divided by area a.\n\nF is mass m times gravity acceleration g\n\nmass m is density rho times volume V\n\nThe column inside the manometer exerts a pressure \n\np(i) = g * rho * V / a\n\ng: gravity acceleration\nrho: density\nV: volume V=h*a\na: area\nh: height  h=V/a\n\nso we get\n\np(i) = g * rho * h
144053
Pay more attention in class! And assuming it is an ideal gas, use PV=nRT. Since there is not change in volume you can basically drop it from the equation and make P=nRT. If you like algebra you can leave it in but it will cancel out eventually. You could solve for 'n' first using initial P and T, and then plug and chug.
149911
Density = Mass / Volume\nIf you know any 2 of the above quantities, you can find the other.
595268
Use the formula: \n\nPV(1)=PV(2) where P is pressure and v is volume.\n\n400(1)=(2000)x(P)\n\nSolving, P =.2atm\n\nPS: If you ever forget the formula, use common sense. When you place any gas under pressure, what happens to its volume? It goes down, because the pressure is forcing the gas into a smaller volume. So when you increase your gas volume by 5 (400x5=2000) you must lower that pressure by the same amount. So the pressure goes down by 5 (1/5=.2).
609831
pv=nrt\nmeasure pressure, volume, and temperature to find the number of moles, n\n\nfind the mass of the gas\n\nmass of gas/ moles of gas= molecular mass (g/mol)
857152
I'll agree that you need help.  Density is mass/vol.  You've given the density, you need another value to calculate the remaining value.
94789
Use Boyle's Law for that. Assuming the temperature is always constant, the product of pressure and volume is always constant.\n\nP * V = k\nor\nP1 * V1 = P2 * V2\n\nIf temperature is included in the equation, you could either use the combined gas law or the ideal gas law.\n\nNote: Elevation plays a significant role in Boyle's Law so it will have a difference in the gauge readings if you relocate it from sea level to the mountaintop.
433864
Use the General Gas Equation:\n\nPV = nRT\n\nwhere\nP = pressure \nV = volume \nn = number of moles\nR = Universal Gas Constant (value depends on units of P,V, n, T eg R = 62.3638 when V is in litres, P is in mmHg, T in Kelvins and n in moles.)\n\nUse the above equation to solve for n. If you want the answer in grams, simply multiply the number of moles by the molar mass of H2.\n\nIf you require a more precise answer, then you should use the Van der Waals equation (a more sophisticated version of the General Gas Equation that takes into account interactions between particles and the volume of those particles).
1167777
D.  Based on the ideal gas law, PV=nRT\n\nSolve for R to get: R = (P*V)/(n*T)\n\nfor two different conditions, then, you would have:\n\n(P1*V1)/(n1*T1) = R = (P2*V2)/(n2*T2)  or,\n\n(P1*V1)/(n1*T1) = (P2*V2)/(n2*T2)\n\nor P1*V1*n2*T2 = P2*V2*n1*T1\n\nNote how V1 and T1 can never be in the numerator together?  \n\nIn order for the ratio to work, one must be the numerator, the other the denominator, because volume is directly proportional to temperature -- the higher the temperature (keeping number of moles and pressure equal), the larger the volume.
859051
water has density 1gm/ml. what ever is the volume in ml for water same is the mass in gms because density = mass/volume\n\n\ni hope it will help you out
691993
density=mass/volume\n5.3=371/v\n0.014cm cubed=v\napproximately