Using Synthetic division?
339712
If 3 is a zero then P(3) = 0.\nP(3) = 27 + 36 - 21 - 10 = 32 \nThus 3 is not a zero.\nSince 3 is not a zero, then x-3 cannot be a factor.\nPossible rational factors are the positive and negative factors of 10\n1,2,5,10\nP(5) = 180\nP(10) = 1320\nThere are no rational factors greater than 3.\nAlso, there is not a zero between 3 and 4.\nC.\nThe zeros are -5, -1, and 2\nP(x) = (x+5)(x+1)(x-2)
1050751
I think you're referring to synthetic division - maybe this wasn't clear to the previous responders.\n\nThe remainder when f(z) is divided by z^2+1 is some first degree polynomial in z, az+b:\n\nf(z) = Q(z)(z^2+1) + (az + b)\n\nSince z^2=(z+i)(z-i), the first term is divisible by both, and the remainders for division by (z-i) and (z+i) respectively are the same as the remainders of az+b divided by z-i and z+i:\n\naz+b = a(z-i) + (b+ia) --> b+ia=1-i\naz+b = a(z+i) + (b-ia) --> b-ia=1+i\n-->\nb = 1 , a = -1\n\nIn other words, the answer is:\n\n-z + 1
437452
the right answer is 3 because the order of operations is this: first u divide 2 by 2, and that get's 1; after that, add 1 at 2 and u get 3.\n\nAlways the division or * is the first operation u make. After that u make the + or -.
412721
First, change any mixed number into improper fraction.\n\nThen, I will show you how to divide fractions.\nThink of a, c as the numerators and b and d as denominators. Then you want to divide a/b by c/d. It will be written like this:\n(a/b)/(c/d)\n\nGet the reciprocal of(invert) the divisor, and multiply it to the dividend\n\nthe reciprocal of c/d is d/c, so\n(a/b)/(c/d) = a/b x d/c\n\nmultiply them now\n(a x d)/(b x c)\n\n^_^
180224
Not necessarily.  If the answer to a division problem is 7.5, then the answer is 7 and a half (half of what you're dividnig by).\n\nExample- 15 divided by 2 is 7.5, but the remainder in this problem is 1, not 5 (1 is half of 2).
438371
same thing as (8x^2+2x-2)^(3/2), right?\nso add one to the power\nmultiply by the inverse of that power\nand divide by the derivative of what's in the parenthesis on the left\ngot it?
894899
Horners' method of synthetic division is used to find the roots of polynomials. \nwe have to know one of the roots to proceed with this. we can check if 1or -1 are roots of the polynomial using some easy tricks. \n1) if the sum of all the coefficients is equal to 0, then 1 is a root\n2) if the sum of coefficients of even terms is equal to the sum of the coefficients of the odd terms, then -1 is a root.\nnow, for the first equation, we already know that -2 is a root, because the question is to find the quotient when the polynomial is divided by x+2. \nin synthetic division, u first put down a 0 beneath the first coefficient, ie., 3. now add these two. the result is 3. \nnow multiply 3 with the root, ie., -2. the result is -6. write this beneath the second coefficient, ie., 2. the result is -4 after addition. \nrepeat the same steps until u reach the last coefficient.\nnow next we write 8 below -1. result is 7.\nnext we write 7*-2 ie., -14 below 5. the result is -9.\nlastly, we write -9*-2=18 below . the result is 12, but the result should be zero.\nso, the given equation is not divisible by x+2.\n\ncoming to the second equation, follow the same procedure as above and u will get the resultant coefficients at each stage to be 2,6,22,61 respectively. so it is not divisible by 3
889816
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
258044
divide the exponent by two
354324
To divide decimal numbers:\n\n1.If the divisor is not a whole number:\n      *Move the decimal point in the divisor all the way to the right (to make it a whole number).\n      *Move the decimal point in the dividend the same number of places.\n\n   2.Divide as usual. If the divisor doesn't go into the dividend evenly, add zeroes to the right of the last digit in the dividend and keep dividing until it comes out evenly or a repeating pattern shows up.\n\n   3. Position the decimal point in the result directly above the decimal point in the dividend. \n\n   4. Check your answer: Use the calculator and multiply the quotient by the divisor.
95584
I rember doing something like this: you had to take the int you store the input in, and divide it by ten with the mod operator (%), and store it in a new int.  Since the mod operator divides the two numbers, and then returns the remainder, that will separate your last number.  For example:\n\nSay the input is 4321, and you have it stored in int input;\n\nint first_num = input % 10;\n\nthis takes your value in input, divides it by 10, then takes the remainder and stores it in first_num.  In this case, first_num should now equal 1.  \n\nAfter that, you have to shorten your input from 4321 to 432 by dividing (regular dividing this time) it by ten, and storing it in another new int.  (Since int can't have any decimals, dividing by ten just shortens it by the first number).  Then you do the whole thing over until you have all four numbers in separate ints, and then output them to separate lines.  \n\nHope that's clear enough--it's hard to explain this stuff so it's easy to understand.  Good Luck!
1148035
Division, if you do not know how to divide can be done easily.\n\nTake the problem 32 divided by 8.  You would divide this out the long way.  The easiest way might be to subtract 8 until you get to zero.   You notice it take you 4 times of subtracting 8 to get to zero.  So your answer would be 4.
985294
you just keep on deriving.\n\nI find it easier to split things into exponents.\n\nI am assuming your question goes\n\n(1/(2x))  - 4 = g(x)\nor\n\n(1/2)*x^-1     - 4 = g(x)\n\ndifferentiate once\n\ng'(x) = -(1/2) * x^-2 \ng''(x) = -2 * (-1/2) * x^-3  = x^-3\ng'''(x) = -3 * x^-4  =  -3/(x^-4)  **ans**\n\nPlug 3 into this... bah\n\nFor reference please use parenthesis to make your problem clearer for us. I just solved the whole thing using the wrong g(x).\n\n\n===!using the correct g(x) which should be g(x) =1 / (2x -4)===\n\ng(x) = 1 / (2x -4) = (2x - 4)^-1  don't forget the chain rule\n\ng'(x) = -1*2*(2x - 4)^-2 = -2 * (2x -4)^-2    chain rule again\n\ng''(x) = -2*-2*2*(2x -4)^-3 = 8*(2x -4)^-3    chain rule again\n\ng'''(x) = -3*2*8(2x - 4)^-4 = -48 * (2x -4)^-4\n\ng'''(x) = -48/[(2x -4)^4]\ng'''(3) = -48 * (6 -4)^-4 = -48/ (2^4) = -48/16   = ***real ans***\n\ng'''(3) = -3
66583
Polynomials are expressions involving x raised to a whole number power (exponent). Some examples are: \n\n\n\nIn this lesson we consider division of polynomials such as: \n and . \nThere are two ways to calculate a division of polynomials. One is long division and a second method is called synthetic division. Synthetic division can be used when the polynomial divisor such as x-2 has the highest power of x as 1 and the coefficient of x is also 1. Otherwise, such as , a long division process must be used. Both methods will be demonstrated. \n\nWe will now look at some examples showing how these two procedures are done
125119
add them together and divide by 3
622069
Above answer is ok except for not using the -- operator:\nNeed to start at 10 and to decrement i use the statement:\n\ni--;\n\nThis changes the problem somewhat.  Another problem in the first answer is that fact is not initialized, so it will always equal zero resulting in a division by zero error.
113980
Use a calculator - numerator divided by denominator will give you the answer.