7 WOTW................    8LOAO............. ??   Can you break the codes (two answers)?
340160
7 wonders of the world\n8 lines on an octogon
791407
u got PWND!!! n00b! lolololololol!!!!!!!11
645425
try googling it first. i do have the code, but dont want to give it away like candy. (everybody can see it and use it)
324992
it = 5667766776600000, is this for you enjoy ment? :)
889816
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
342459
Since there are seven ones, it will count up to 7 and then back down - 1234567654321.\n\n 1111111\nx1111111\n-------------\n0000001111111\n0000011111110\n0000111111100\n0001111111000\n0011111110000\n0111111100000\n1111111000000\n-------------\n1234567654321
176504
WHICH CODE YOU ARE ASKING......PLZ CLEARIFY.......
919497
Simply.  The answer is\n\nU89sjn33hHYkPM0iL
747650
1.7.9\n\n2.18.132\n\n3.7.818
966057
well well..the second time i see the same question!!\nshow some of ur work buddy.. ur a degree student and u dont simply put the questions on others..u wud never pass that way...\nso prove that u have tried ur best to solve this problem..show some coding that u have made!
160575
if it 2 numbers... you multiply msb by 10D and add to your answer the lsb... and youl get the number in hex!
470294
Press Alt and the numbers 164 = ñ\n\nPress Alt and the numbers 165 = Ñ
457195
the simple program given above if fine.. in terms of the conncept.. but there's a bug... \nthe problem is with looping.. coz when u enter a number such as 80301  or 55302 ( a no. having 0 in between), the loop breaks at the point when zero is encountered.\n\n so the output in the first eg. is  8 0 ,sum= 8 (instead of correct 8 0 3 0 1 , sum=12\n\n\nso the logic of handling the number is absolutely correct but the looping is a comparatively difficult job in this case!
845925
If you problem, or part of it, is:\n\nHow many 8 digit numbers can be formed from this list of digits?\n8! / (3! * 2!)\nThe number combinations of digits has tobe reduced by 2! because of the 2 "6"s.\nThe number combinations of digits has tobe reduced by 3! because of the 3 "2"s\n.\nBut since the number cannot exceed 65,500; all larger numbers must be eliminated. Subtract the number of 8 digit numbers that can be produced from the list that start with "9". Likewise "7". Likewise "69", "67", "66", "659", ""657", and "656".\n\n\n\n(Try to state your problem clearly and completely.)
248038
I will give your in binary :\n0000\n0001\n0010\n0011\n0100\n0101\n0110\n0111\n1000\n1001\n1010\n1011\n1100\n1101\n1110\n1111
1033178
64 bits set in code unfortunately
448118
Oh jeeze, are you serious LOL.......ok lets say: 999,349,843,928,999,344,576,345,768,324,999 gazilliontrillionbazillion........