In 458 kcal there are how many joules?    How many kilojoues?
344306
458 kcal converts to 458000 cal\n\nthe k = kilo which = 1000\n\nso when you remove the k you must insert 1000, hence you multiply 458 by 1000 and get 458000 cal\n\nif 1 cal = 4.184 J then 458000 cal need to be multiplied 4.148 and you will get 1916270 J or 1.91 x 10^6 J\n\nIf you divide the 1916270 by 1000 you can insert a k or kilo.\n\nThis gives you 1916.270 kJ
1128546
specific heat Q = mc(t2-t1)\nput everything in SI units..\nthen \n\n40,000= 500/1000 * c(68-20)\n40000=0.5* 48*c \nhence c= 40000/24= 1666.67 joules/kg oC.
1044823
Converting from KJS (kilojoules) to Calories: \n\nMultiply the number of kjs by 0.239 \n\n1 kjs = 0.239 Calories\n320 kjs =76.48 \n\nConverting from Calories to KJS: \n\nMultiply the number of Calories by 4.184 \n\n1 Calorie = 4.184 kjs\n75 Calories = 313.8 kjs
316045
kg m^2\n------- = Joule\ns^2\n\nb = kg m/s
602803
The theoretical physics equation E = mc2 states a relationship between energy (E), in whatever form, and mass (m). In this formula, c², the square of the speed of light in vacuum, is the conversion factor required to formally convert from units of mass to units of energy, i.e. the energy per unit mass. In unit specific terms, E (Joules) = M (kilograms) · (299792458 m/s) 2.
770398
682 J - 485 J = 196 J\n(energy going into a system is positive, energy going out is negative)
978927
You have to be careful about what you mean by calorie, as there are two kinds.  The standard calorie (the energy it takes to raise 1 cc of water 1ºC) is 4.185 joules.  However the calorie used to depict the energy content of food is the "large Calorie", spelled with a capital "C",  and is equal to one kilocalorie and therefore 4.185 kilojoules.
615198
use the formula q=m*s*(t2-t1) where q is energy in heat,m is mass in grams,s is specific heat in joules/gram celsius,t1 is initial temp,t2 is final temp.\nsubstituting in formula,\n42,000=900*4.186*(t2-35)\nt2 works out to be 46.14 celsius.\nhope this helps.
155062
Quantity of heat (Q), measurement = joule (J)\nSpecific heat capacity in liquid, measurement = c/(kJ kg^-1)
827623
F*m = μ*Joules→ m = .25*40000000/1000 = 10000m = 10 km
1074974
its calories multiplied by 4.  65 calories multiplied with 4 = ... kjoules
132617
KVA =Kilo Volt Ampere\nKilo = 1000\nPower = Voltage * Current\nso watts = KVA*1000\nEg. 5KVA = 5*1000 =5000W
1074656
[V]=J/C=W/A=Kg.m^2/(s^3.A)\n\nFor experimental reasons A is the base unit and not C, you can not count electrons one by one, not yet probably soon
66875
Absolute zero refers to 0 degress Kelvin -- a measure of temperature.\n\nA Joule is the "metric" standard measure of energy.\n\nCalories are an older measure of thermal energy.\n\n1 Calorie = 4.18 Joules.
705010
The specific heat of water is 4.184 J/g C.\n\nSince water's density is 1 g/ mL, 500 mL of water will have a mass of 500 g.\n\nThe equation to calculate the joules of energy required is:\nheat = mass x specific heat x change in temperature\n\nenergy = 500 (4.184)(95-25)\nenergy = 146440 J or 146.44 kJ\n\nHope that helped.
186138
For an accurate answer you would need more parameters answered to address the question. The internal combustion of coal and also the units of energy you finally want it answered in Joules?
870267
.4084c(80)+.4084(heat of vaporization)\nc is specific heat of water\nthat will give you J/KG C   si units