what is the area of an uneven rectangle, measuring 30ftx604ftx250ftx427ft ?
348844
It sounds to me like you are talking about a trapezoid. Go to the website I have listed under my sources and see if what you are describing looks like the trapezoid on there. If it is a trapezoid, the area formula is  Area = 1/2h(b1 + b2). h=height, b1=base 1, b2=base 2
608232
Rec first  8 X 4 = 32\n32 X 16 = 512  this is Area of rectangle.\n\nCircles pi X r^2 = Area\n3.14159 X 8 X 8 = 201\n\n512 - (2 X 201) = shaded area\n109.87 = shaded area\n\nOK ?
359093
Square and Rectangle= lenght*height\ntriangle=base*height divided by 2
87402
a: width\nb: length\nperimeter = 2 x (a+b)= 420 ---> a+b = 210\nwe need to find max (a x b)\n\na= 210-b ---> area = a x b = b x (210-b) = 210 - b2 = - b2 + 210b = - b2 + 2 x 105 x b - 105squared + 105squared\n= - (b2 - 2 x 105 x b + 105squared) + 105 squared\n= - (b - 105)squared + 11025\n\nSince (b - 105) squared is always >= 0,\n - (b - 105)squared is always <= 0\n  - (b - 105)squared + 11025 is always  <= 11025\n\nthe largest area will be 11025 squared feet. This happens when - (b - 105)squared = 0, which means b = 105.\n\na = 210 - b = 105\n\n\nthe shortest way is to say that a rectangle has the largest area when it's a square, so each side would be 420/4 = 105.
123707
Let:\n\nL = length of the rectangle\nW = width of the rectangle\nP = perimeter of the rectangle\n\nGiven:\n\nW = x\nL = 2x - 4\nP = 2L + 2W from geometry\n\nSolution:\n\nP = 2L + 2W\n64 = 2[2x - 4] + 2x\n\n2[2x - 4] + 2x = 64\n\n[4x - 8] + 2x = 64\n\n4x - 8 + 2x = 64\n\n4x + 2x = 64 + 8\n\n6x = 72\n\nx  =  72/6\n\nx  =  12 cm.\n\nTherefore:\n\nW = width = x = 12 cm. ANS.\n\nL = length = 2x - 4 = 2(12) - 4 = 24 - 4 = 20 cm. ANS.
897796
Let L be the length\nLet W be the width\nWe know the perimeter is:\n2(L + W) = 300\nSolving for L:\nL + W = 150\nL = 150 - W\n\nNow write a formula for the area:\nArea = L * W\nArea = (150 - W) * W\nArea = -W² + 150W\n\nYou can see this is the formula for a parabola.  I'll simplify things by expressing it in terms of x:\nf(x) = -x² + 150x\n\nBut it isn't in vertex form:\nf(x) = a(x - h) + k\n\nTo get it in that form, first pull out the -1 to get x²:\nf(x) = -1(x² - 150x)\n\nNow take the coefficient on the x term (-150), take half of it (-75) and square it (5625). Add and subtract this:\nf(x) = -1(x² - 150x + 5625 - 5625)\nNow you can write this as a square:\nf(x) = -1[ (x - 75)(x - 75) - 5625)\nSimplify:\nf(x) = -1(x - 75)² + 5625\n\nYou have a downward facing parabola, with a maximum vertex at the point (h, k) or (75, 5625)\n\nSo the maximum is when the width is 75. When you solve for length you get that the length is also 75. So the maximum area for the patio is a square with sides of length 75 feet.  The total area will be 5,625 sq. feet, a maximum.
786144
Multiply through the parentheses:\n\nA(x) = 3000x - 2x²\n\nNow, take the first derivative of this equation,set it equal to zero, and solve for x:\n\nA'(x) = 3000 - 4x = 0\n4x = 3000\nx = 750\n\nSo, the area of the space would be 750 x 1500 = 1,125,000 sq ft.\n\nYou integrate and set = 0 because you are essentially graphing the possible areas based on the length of one of the sides. When the tangent to the graph goes to zero, then the curve is at its maximum location.
941539
A square is a quaderlateral. All of it's sides are the same length. If you want to find the area you multiply the side by it's other side. In this case it would be 5 X 5. This would equal 25. So your square's area is 25 square units.
331831
The dimesnions of the rectangle are 14 feet by 34 feet.\n\nYou know that the perimeter is 96 feet and that each long side is 20 feet more than the short sides.\n\nAs there are 2 long sides the total length of both these sides must be 40 feet more than the total length of the 2 short sides (20 x 2 = 40).\n\nIf all the sides were the same length as the short sides then the rectangle would have a perimeter of 56 feet (we know it's 96 feet to start with and that the additional length on the two long sides is 40 feet and 96 - 40 = 56).\n\nEach side would therefore be 14 feet long since 56 divided by 4 = 14.\n\nNow that we know the length of the short sides all we need to do is add 20 to get the length of the long sides, 14 + 20 = 34.\n\nTo check it you can add 14 + 14 (the two short sides) + 34 + 34 (the two long sides) = 96.\n\nI hope that makes sense, it's 1:25AM here and I'm getting tired.
549797
enclose the ireegular shape with a rectangle and find the empty spaces. then subtract that with the area of the enclosed rectangle to get ur answer.
860533
long sides are 24ft and short sides are 9ft.\n\nArea = width x lenth\n216 = 24 x 9\n\nDimensions 24+24+9+9 = 66
76067
The answer is 13.5 in.\n\nFirst we have that the total area is 178 in^2, and we have the lenght and width, so we just need to write the formula for the area of each side and sum them. We would have an unknown variable: height.\n\n178 = (2*4) + (2*4) + (4*X) + (4*X) + (2*X) + (2*X)\n\n178 = 16 + 8X + 4X\n\n(178-16)/12 = X\n\nX = 13.5
360732
Right.  I'm not sure what the question is, but let's assume that the space we are talking about is a rectangle, and you have to figure out what the dimensions are.  Well, the perimeter, 26, is the distance around the space which has the area of 36, which for the sake of argument, we will assume is square feet.  What times what equals 36?  9 x 4, right?  So, it's possible, but not certain that we are looking at a rectangle whose dimensions are 9 feet by 4 feet.  To prove this, remember that a rectangle has four sides.  If our assumptions are correct, it has two sides of 9 feet and two of 4 feet, right? So then,  9 + 9 + 4 + 4 = 26.  It would seem that this is the right answer.  \n\nOf course 12 times 3 also equals 36.  But this time, if we substitute the 12 and the 3 as the dimensions, we would get a perimeter of 30 feet, obviously the wrong answer.  Looks like you have a rectangular space that is 9 by 4 feet.\n\nI hope this helps and that I haven't just muddied the water further.
235455
Area = 225 sq. cm = (15)^2\nPerimeter = 4*15 = 60 cm\n\nP*6 = 360 cm = 4x cm\nx = length of side = 90cm\nArea = 90^2 = 8100 sq. cm\n\nArea increased (6)^2 times, or 36 times.\n\n(225 * 36 = 8100)
783277
let the height be x\nthe cross section will be (40-2x)*x\ndA/dx=40-4x\nsetting this to 0\nx=10\nso the length of the sides will be 10 cm each for max area of x section
117044
Area equals half the base times the height.  \nA=1/2bh.  Plug in and solve!
896075
Do you mean what is the area of a square with sides (width and length) of 6 meters?\n\nIf so it is just 6m x 6m = 36 sq. meters.  (Remember area is sq. units and is given by the formula width times length.)\n\nOn the other hand, if you are asking for the dimensions of a rectangle with an area of 6 sq. meters, there is no single answer.  It could be 1 x 6, 2 x 3, 1½ x 4, ½ x 12, etc.