how do you use a transient for elevations in construction?
339392
Websters dictionary says a transit is an instrument used by surveyors to determine angles. It also measures the up and down layout of the ground called topography. I believe you need 2 people, one to move a measuring stick and the other one reads the transit. Surveyors put the transit in a fixed or assigned spot. He looks through a little telescope that has a movable measure on the side called a compass (Maybe you will remember a similar tool from school called a protractor). The protractor measures distances and makes circles. The compass on the side of transit measures angles. By looking and recording the different angles and degrees on the transit compass compared to the assigned mark on the measuring stick the surveyor records the surface of the ground. In this way the surveyor provides information to the contract engineer. The measurements are used in algebra formulas to determine how much additional dirt is needed to make to site level or if the ground needs to be scrapped off to make it level. or the info could be used to determine if the site possibly will flood. I hope this is the info you are looking for. An encyclopedia or science book can probably do a better job of describing the process than I have. I hope you get a lot more responses.
695604
The only way I can see this being done is to have a piston or other way to separate the water and air; otherwise, the air will simply bubble up through the water.\n\nAssuming there is a piston or other separation device and the water will overflow at the top, the initial pressure needed to begin the displacement of the water is the height of the water in inches  times its density in pounds per cubic inch. Taking the density of water as 62.4 pounds per cubic foot and converting to pounds per cubic inch the density becomes .036111. The height is of course 100 ft time 12 inches per foot or 1200 inches. This yields an initial pressure of 1200 time .036111 or 43.33 psi. As the piston moves upward, the required pressure will decrease directly in proportion to its height or .4333 psi per 12 inches of rise.
1077336
there are a few diff ways for this.  the way i do it is with a rotating lazer level. you can rent them at most rental places, another way is with a transit/builders level but if you dont know how...you will be lost cause you wont know how to read it. or the cheap and easy way.   get some clear plastic hose hold the ends up and fill it with water. create a "benchmark". use a post or somthing else you can tie it to and walk away without spilling. on the other end make a leg for you to rest it on roughley as high as the post. now as you move around you can see if it isflat by marking the level in the tube cause water will seek its own level. i prob left out some things in the explanition but im sure you will pick it up.....it was good enough for the romans and it can work for you.
135914
Dear mr./ms. engineer, \n\nProducing ceramics is one thing and managing the busyness is another. You should include in your question what kind of help you need.
959992
depends on which city you are building that that model for ,as different cities have different rules regarding the building heights,but if its just for fun then divide the total height of your model with the number of floors you want ,to get the exact height of each floor.
814300
Some of the techniques are: active and passive damping; minimiization of masonry in tension (such as avoidance of overhangs and use of ring collars); reinforcement of structures at high-stress areas; cross-bracing; deliberately flexible design; base sliders or rollers to accommodate ground motion. See the refs. below.
866685
If the soils removed from the excavation aren't too wet then use the same soils. \n Why do you have post tension cables on a slab on grade design?\n If you are trying to bring the subgrade level across the whole floor area to minimize the purchase of extra concrete ,then sand would prob. be the way to go.
824167
The radius is actually 2/3 of the altitude.  Try that
1097253
i'm not an engineer but i would say that there are more than one methods. i think you have to make each carrier autonomic,which means it can react as an indepenent part of the bridge in forces like wind or earthquake. i don't know if i helped, i hope i'm not beyond the subject of your question? if i'm sorry
824936
a) You have to draw gravity as a straight line down. Then you have to realize that gravity does no work if the block was on a horizontal surface. Work done by gravity is alway M*G*H.  The mass is 4.8 kg and the gravity is 9.81 m/s^2 .  The height will be sin (30) = H/2.  the sin (30 degrees) is 0.5 so .5=H/2.  the height will be .5/2 = .25 m.\n\nsoo you will have 4.8*9.81*0.25\n\nb) the work done by the frictional force will always be the frictional force times the distance.  The frictional force is going to be the normal force times Uk.  The normal force has components to it, so its going to be sin(30)*g*m.  The you need to multiply that by the friction coefficient and then by the distance traveled.  You will have 2*0.436*sin(30)*4.8*9.8\n\nc.  The work done by the normal force is just going to be cos(30) (i think) times 2 ( the distance traveled) times 9.81 (gravity) times 4.8 (the mass)
703199
It is an exercise in elementary calculus to show that (ignoring air resistance) the elevation angle for maximum distance is 45 degrees.  The vertical velocity of the egg will be zero at the peak height, and will increase as v = gt^2/2 until it hits the ground.  Energy is conserved, so the vertical velocity when it strikes the ground will match the vertical velocity with which it was launched, and the horizontal velocity will be constant.   This is enough data to solve the whole thing, but there is a shortcut: in the parabolic path at issue, it is always true that the peak height is 1/4 of the horizontal distance.  Hence, the peak height here is 24.225 meters, and that makes it trivial to compute the time and hence the velocity.
979265
Sand falls onto a conical pile at rate of 10 ft^3/min. The radius of the base of the pile is always equal to 1/2 of its altitude. How fast is the altitude of the pile increasing when it is 5 ft deep?\n\nLet radius = r and altitude = h\nThen r = ½h\n\nV = ⅓πr²h\n= ⅓π(½h)²h\n= πh³/12\n\nNow dV/dt = dV/dh * dh/dt\nSo 10 = πh²/4 * dh/dt\nWhen h = 5\ndh/dt = 10/(π*5²/4)\n= 8/5π ft/min\n≈ 0.51 ft/min\n(≈ 6.1 inches/min)
901287
Your answer is off, but how to fix it depends on what units of measure you want the result to be.\n\nSo, I assume that the elevations are in feet.  The difference and conversion look OK.  \n\nBut then, you divide 4432m by 160km.  The result should be 27.7 m/km.  \n\nIt looks like you tried to convert the one of the measurements so that the units were the same (i.e., 4.432km/160km or 4432m/160,000m ).  That would be OK, and would give you the result of 0.0277, but the units would be m/m or km/km.
622351
to get the foundations over water, there are several ways to get the foundation for the bridge set up over the water.  one way is to float out a platform that is not unlike an oil derrick.  from there 'piles'(columns made out of concrete or steel)are driven down into the ocean floor and a foundation is rested and secured and built on it until you get to the top.  \n\nthe other way is (in shallower water) to build a 'coffer dam'  this is a temporary structure that you would build around the place that you want the foudmnation for the bridge in the water.  you put the dam around the area, pump out the water, and then build a foundation as you normally would, or even place piles like the example from above.
168445
first find a vicinity plan. \nget a straw(in sodas) and a triangle\nstand on a specific location with the distance of X from the building.\nmake sure to know your height.\ncreate a transit by putting the straw along the hypoteneous of your 45x45 triangle.\nlook through the straw (try to see the zenith of the building) and measure the angle of depression.\nthen, simply apply the law of sines and cosines etc etc.\nthis will not give you exact building height but an instant approximation. this can also be used in finding approximate height of towers, canyons, mountains, and volcanoes.
142488
Instantaneous speed, as the name indicates, is measured at a particular instant of time. From a math standpoint, by calculating the first derivative of the displacement function, you can use the result to calculate the speed at any instant of time. In other words, the instantaneous slope of the displacement function is equal to the instantaneous speed.\n\nIf you look at graph of a moving object (displacement vs. time), if you see a steep slope, this means that the object's speed is fast relative to a curve with a moment of shallow slope. How much distance are you moving per unit of time? The more distance you move, the faster your speed. Decrease that unit of time to almost 0, and you'll get instantaneous speed.
90453
First question, yes.   GPS provides a location in three dimensional space, therefore your receiver can determine your elevation in relation to sea level if equipped (most are).  For best accuracy, you will need at least a 4 satellite position fix...with good satellite geometry (i.e. all the satellites are not lined up in a row in the sky).\n\nSecond question, in theory yes.   Technically, the answer is likely no.  The reason is that GPS signals are very weak by their nature and it requires a sensitive receiver to "hear" them.  While most receivers on the market today will be able to receive signals through tree leaves and other minor obstructions of the sky, the vast majority cannot not receive signals through concrete.  To demonstrate this, just take a walk with your GPS unit underneath an overpass and watch what happens to the signal strength.  \n\nIf you were measuring altitude inside, a barometric altimeter might be a better choice, though be wary of the building's ventilation system, as most are slightly pressurized and would affect this instrument as well.