multiply X^2-5x+4/X^2-9  times X^2+7x+12/X^2+3x-28?
346785
(x^2-5x+4)/(x^2-9) * \n(x^2+7x+12)/(x^2+3x-28)=\n\n[(x^2-5x+4)*(x^2+7x+12)]/\n[(x^2-9)*(x^2+3x-28)]=\n\n[(x^2-4x-x+4)*(x^2+4x+3x+12)]/\n[(x-3)(x+3)*(x^2+7x-4x-28)]=\n\n[(x(x-4)-(x-4))*(x(x+4+3(x+4)]/\n[(x-3)(x+3)*(x(x+7)-4(x+7)]=\n\n[(x-4)(x-1)*(x+4)(x+3)]/\n[(x-3)(x+3)*(x+7)*(x-4)]=\n\n[(x-1)(x+4)]/[(x-3)(x+7)]
896553
4x^2+8x-x-2\n(4x-1)(x+2)
913334
x^2 + 2x + 7 Remainder 10\n\ni can add the steps if you don't think i did it by hand
1174116
8x^2 -5 -3x^2 + 7\n8x^2 - 3x^2 -5 + 7\n5x^2 + 2
901268
Multiply the 7 out on the left side to both terms and the 5 out on the right side.\n7x +7*2 = 5x + 5*4\n7x + 14 = 5x + 20\n\nGet the variable on one side by subtracting 5x from both sides (one way to do it).\n7x-5x +14 = 5x-5x + 20\n2x + 14 = 20\n\nSubtract the 14 from both sides.\n2x = 6\n\nDivide both sides by two.\nx = 3
762880
5 + 4 - 7 = 4x + 3 - x\n 9 - 7 = 3x + 3\n2 = 3x + 3\n2 - 3 = 3x + 3 - 3\n -1 = 3x\n-1/3 = 3x/3\n-1/3 = x
600301
x^3+x^2+2 = x^5+2\n\n(x^2+2)^2 = x^4+4\n\n(x^3+x^2+2)/[(x^2+2)^2] = (x^5+2)/(x^4+4) = (x+2)/4 = (x+1)/2
219026
x^3+4x+1\n\n(3x^4+2x^3+12x^2+11x+2)=\n=(3x+2)*(x^3+4x+1)
945218
[(x^2)^2]^2\n\n(x^2 -4x +4)^2\n\nmultiply      x^2  (x^2 -4x +4)^  = x^4 -4x^3 +4x^2\n\nmultiply     -4x (x^2 -4x +4)^    = -4x^3 +16x^2 -16x\n\nmultiply     4  (x^2 -4x +4)^      =  4x^2 -16x +16\n__________________________________________\n\nthe answer should be                 x^4 -8x^3 +24x^2 -32x +16\n\ni hope that helped
838764
- 7 - 4x < 13\n\n-7 - 4x + 7 < 13 + 7\n\n- 4x < 20\n\n- 4x/- 4 > 20 /- 4\n\nx > - 5\n\nThe answer is x > - 5\n\n- - - - -s-
19519
=3(5+4x)-3x(5+4x)\n=15+12x-15x-12x^2\n=15-3x-12x^2
912242
2-10x=3x^2+3x-7x-7\n2-10x=3x^2-4x-7\n0=3x^2+6x-9\n0=3(x^2+2x-3)\n0=(x+3)(x-1)\nx=-3 and 1
911039
12x^2-10x-8\n=2(6x^2-5x-4)\nsplitting the middle term -5 into\n-8 and +3 so that the sum is -5 and\nthe product is -24\n=2(6x^2-8x+3x-4)\n=2(2x+1)(3x-4)
714160
x^2+6x+8/x^2-4-21 / x^2-4/x^2-7x\n=x^2 + 6x +(8/x^2) - 4 - (21/x^2) - (4/x^2) - 7x\n=x^2 + 6x -4 -7x +(8/x^2) - (21/x^2) - (4/x^2) \n=x^2 + 6x -4 -7x +[8-21-4]/x^2\n=x^2 + 6x -4 -7x -17/x^2\n=(x^2)*[x^2 - x -4  -17]/x^2\n=(x^2)*(x^2) - (x^2)*(x) -4*(x^2)  -17]/x^2\n=(x^4) - (x^3) - 4(x^2)x -17]/x^2
771896
expand x^2-6x+9 = 5\nor x^2-6x+4 =0
712395
9x+5/(x-4)+(-7x)/(x-4)\n=9x+5-7x/(x-4)\n=(2x+5)/(x-4)
142543
Polynomial= multiple terms, i.e. 3x^2+7x-3\nSo I suppose addition of them would be like\n(4x^2+7x-5)+(9x^2+9x+7+y)\n=4x^2+7x-5+9x^2+9x+7+y\n=13x^2+16x+2+y\nor\n(4x^2+7x-5)-(9x^2+9x+7+y)=\n(4x^2+7x-5)-1(9x^2+9x+7+y)=\n(4x^2+7x-5)+ (-1*(9x^2+9x+7+y))=\n(4x^2+7x-5)+(-9x^2-9x-7-y)=\n4x^2+7x-5-9x^2-9x-7-y=\n-5x^2-2x-12-y.\n\nMaybe now you can do your own.\nNote that these methods only work with adding/subtracting.