What is the relation between dielectric loss and impedance?
348775
Ummmm...wat' is dis' a trick question? or a challenge? or is dis' a show of ur intell vs sum 1 elses ignorance? Well Sir/Miss lets deal wit' base wordz! impede=to hinder to hold or sum shyt like dat (impedance cain't b far from dat'!) but dielectric is similar huh? jus' more technical?means u cain't conduct an electrostatik' field or break it or sum shyt like dat but relation wud' b they 1 n da' same on the thought of basis!!!! Really i'm like wat' eva...i can go back 2 chem 101 lmao
248482
Ohm's Law is always obeyed.\nIf a conductor is non-linear it has a coefficient of resistance - thermal, pressure, tensile, even voltage-dependent.\nMeasure the current thru it and the voltage across it and you have the instantaneous resistance at the time of measurement.\nThe law stands, but the result may not be static.
219770
Resistance is the physical property of an element that impedes the flow of current.  Here are the basics for a wire:\n\nResistance, R, of a wire is influenced by three main things: (1) the resistivity, p, of the wire, (2) the length, L, of the wire, and (3) the cross-section area, A, of the wire.  The relationship looks like this...\n\nR = (p*L)/A\n\nIncrease the resistivity or length and you increase the resistance.  Increase the cross-sectional area and you decrease the resistance.  Those are the basics anyway.  Hope this helps.
1159791
Sometimes. For instance, in circuit feeding a half-wave rectifier the impedance is much higher in one direction than the other.\n\nBut in general the impedances should closely match. IN fact, the electric system designed to have closely matched impedances.
641823
http://en.wikipedia.org/wiki/Capacitance
542138
The general formula to calculate the heat loss is\n\nQ=m*cv*(t2-t1)\n\nQ is the heat loss\ncv is the specific volume at constant volume(if it is a constant volume process)otherwise use cp(specific heat at constant pressure)\n\nt2 is the external temperature\nt1 is the internal temperature
151570
ohm's law states that current throught a conductor is directly proportional to the voltage applied to it.\n\nso,  i oc V\n=> i = R*V where R is proportionality constant called resistance of the conductor. \n\nResistance of a material is the electrical property which opposes the flow of electrons or current.
70878
Ohm's Law (named after Georg Ohm, a German physicist) states that the electric current I flowing through a given conducting material (conductor means current can flow through it) is equal to the applied voltage V divided by the resistance R:  I=V/R. Ohm's Law deals with the relationship between voltage and current in an ideal conductor.  The resistance R is sometimes called a "lumped element abstraction."\n\nFor general application to alternating-current circuits where inductances and capacitances as well as resistances may be present, the law must be amended to I=V/Z, where Z is impedance.\n\nOhm's Law is a macro-level, aggregate rule as to how current, voltage, and resistance are related.  But it is not a true "law" of nature in that it really is an approximation of behavior that holds true in most circumstances.\n\nOhm's Law may not hold due to:  1) the kind of conducting material the current is flowing through (some conductors do not follow Ohm's Law)  2) how much voltage is applied to the conducting material; as voltage is increased or decreased to extremes, then the linear Ohm's Law relationship breaks down   3) how small the wavelength of a periodically time-varying voltage applied to the conductor is with respect to the conducting circuit\n\nThe deeper reasons behind why Ohm's Law does describe macro behavior in "ohmic" conducting materials requires diving into a little bit of solid state physics and understanding Maxwell's equations.
222936
Consider a conductor of uniform area of crossection A, length L. Let resistivity of conductor be S and resistance of material to current be R.\n\n  Then,  R = SL/A\n\n     Multiply and divide by mass of conductor say m and L\n\n          R = SL*L*m/L*A*m\n\n But L * A  = Volume = V\nAnd m / V   = Density = d\n\n  Hence,  R =  S*L*L*d/m\n          S =  (m*R/L*L)/d\n\nThus, Resistvity (S) is inversely proportional to density(d) when other quantities are kept constant.
53767
Inductance is the "definite answer" that I was given 30 years ago. I don't suppose that my confirmation is any better than yours, but it's a vote anyway.
837447
PROBLEM ONE\nThe electric resistance R of a wire varies directly as its length L and inversely as the square of its diameter.  So you mean R=cte*L/d2 where the constant depends on the metal used.\nfor that alloy, C=Rd2/L=36*0.6*0.6/20=0.648\nIn the second wire, you use the same constant\nR=0.648*60/(1.2*1.2)=27 ohms\n\nPROBLEM TWO\nhere, period=T=cte*sqrt(L)\ncte=T/sqrt(L)=2/sqrt 6=0.816\nL=(T/cte)2=(1/0.816)2=1.22*1.22=1.5
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www.acoustics.hut.fi/asf/publicat/ akup05/johansson_saine_viitala_johansson.pdf \n\nwww.thermaflex.net/docs/thermaflexcatalog.pdf \n\nhttp://mrtmag.com/mag/radio_measuring_insertion_loss/index.html
74610
if we apply voltage across an insulator, charges pass through it.\nif we apply voltage(there is limit in the value of voltage) across an dielectric it will keep the positive and negative charges separate on the opposite surfaces of the dielectric material. those materials are used in making capacitor.
783633
YOU ARE ASKING A QUESTION THAT IS ANSWERED BY SOLVING THE EQUATION (E=IR) OR OHMS LAW. IF YOU GIVE ME TWO OF THE  UNKNOWNS THE EQUATION CAN BE SOLVED FOR A NUMERIC ANSWER.   LETS ASSUME THE VOLTAGE(E) IS 100VOLTS.  THEN THE CURRENT(IR1) WOULD BE (100VOLTS/110 OHMS) E1/R1 OR 0.909 AMPS.\nTHE SITE BELOW GIVE A LENGTHY DESCRIPTION OF THE SIMPLE CONCEPT AND JUST SEARCHING "OHMS LAW" WILL YIELD DOZENS MORE. YOU WILL FIND THAT THE VOLTAGE APPLIED TO EACH RESISTOR IS THE SAME AND THE AMPERES THROUGH EACH RESISTOR IS INVERSELY PROPORTIONAL TO THE RESISTANCE.
748559
The dielectric constant of a material can be found by a variety of static electrical measurements. The complex permittivity is evaluated over a wide range of frequencies by using different variants of dielectric spectroscopy, covering nearly 21 orders of magnitude from 10−6 to 1015 Hz. Also, by using cryostats and ovens, the dielectric properties of a medium can be characterized over an array of temperatures. In order to study systems for such diverse exciting fields, a number of measurement setups are used, each adequate for a special frequency range.\n\n    * Low-frequency time domain measurements (10−6−103 Hz)\n    * Low-frequency frequency domain measurements (10−5−106 Hz)\n    * Reflective coaxial methods (106−1010 Hz)\n    * Transmission coaxial method (108−1011 Hz)\n    * Quasi-optical methods (109−1010 Hz)\n    * Fourier-transform methods (1011−1015 Hz)
1100598
voltage = current x resistance\nE = I x R  It IS Ohm's law. An easy way to remember the formula and it's configurations is to draw a circle and divide it in half horizontally. Above the line write "E". In the lower half divide the semicircle vertically and write "I" on the left, "R" on the right. It should look something like this:\n                                                     E\n                                                   I    R\nNow just cover up the one you need. and either divide, or multiply.
695323
Hi. From the web, they use the constant 'k' :    http://answers.yahoo.com/question/;_ylt=Aku8q5AETPeTKbquDgodzrYezKIX?link=answer&.crumb=xa6shFEtoH4&qid=20061103074030AA2hrrt&.done=http%253A%252F%252Fanswers.yahoo.com%252Fquestion%252Findex%253Fqid%253D20061103074030AA2hrrt\nThermal conductivity = heat flow rate × distance / (area × temperature difference).