How do i find the equation of Line through (-1,5) parallel to the Y axis? "  " " " "....X axis?
345972
If you're parallel to the y axis, you have a vertical line. The equation is x = -1\n\n\nIf you're parallel to the x axis, you have a horizontal line The equation is y = 5
431677
If you're dealing with a straight line (and a few other types of line I think), the equation will be of the form\ny=mx+c\nThe c part will give you the y-intercept i.e. where the line crosses the y-axis.
283524
For the benefit of all the folks who answered, question a), since (2,-1,0) is not ON the x-axis, a line through it can be parallel to the x-axis.  Equations of lines in 3-space are VECTOR equations with a simple form (kind of like slope and intercept): we need a point the line passes through -- (2,-1,0) -- and a direction to go -- parallel to the x-axis.  So any point on this line, P(x,y,z)= (2,-1,0)+m(1,0,0).\n\nFor b), you need dot product divided by product of magnitudes equal to cosine of angle.  So\n(x,2,4) dot (1,0,1)/[sqrt(x^2+2^2+4^2)*sqrt(1^2+0^2+1^2)=sqrt(2)/2\n(x+4)/[sqrt(x^2+20)*sqrt(2)=sqrt(2)/2....cross multiply\n2(x+4)=2*sqrt(x^2+20)\n(x+4)=sqrt(x^2+20)............square both sides\nx^2+8x+16=x^2+20\n8x=4\nx=1/2
759458
parallel means the slopes will be the same, so our new line can me found using the point-slope formula:\n\ny - y1 = m(x - x1)\ny - (-4) = (1/2)(x - 2)\ny + 4 = (1/2)x - 1\ny = (1/2)x - 5
416338
As halibori says, you can use a graphing calculator and see where the lines cross.   I use a different machine, the one between my ears.   \n\nIf you add the two equations, the +3y in the first cancels the -3y in the second, leaving the equation  4x + x = -8 - 17, or 5x = -25.   This one's easy since the only unknown is x, and we see that x = -5.   Now\nwe can go back to the first equation, plug in the value -5 instead of x, and it becomes\n-20 -3y = -8, or -3y = 12, so we have that y = -4.
63789
A line's equation is y=mx+b where m is the slope of the line and b is where it crosses the y-axis.  In this case, you need to simplify the equation down to make it into the y=mx+b format.  If you do this, you get y=10x-13.  So in this instance, the slope of the line is 10.
876684
y = -x + 6 is in slope intercept form, y = mx + b, where m is the slope.\nSo, you know that the slope of this line is -1. A perpendicular line has the opposite converse slope, so since this slope is -1/1, the slope of the new line will be positive 1/1, or 1.\n\nNow that you have the slope of the new line, you can use that and the point-slope form of a line to find the equation. The general form of a point slope line is y - Y = m(x-X), where m is the slop, Y is the y coordinate of a point on the line, and X is the x coordinate of the same point.\nSo plug in the point and slope to this form and you have:\n\ny - (-4) = 1(x - (-2))\nor\ny + 4 = x + 2\n\nYou can leave the equation in this form, or you can rearrange it so that it is in slope intercept form again.\n\ny = x - 2\n\nI hope this helped!
130487
it's delta-y divided by delta-x\n\n(5 - (-1))/((-1) - (-3))
850944
You have 2 points, (x1,y1) and (x2,y2) and you want to find the equation of the line that goes through these points.\n\nThe first thing you want to do is find the slope.\nslope is rise/run so m = (y1-y2)/(x1-x2)\n\nFor slope intercept form , y = mx + b\nwhere m is the slope, and b is the y intercept\nnow that you have found the slope, you can solve for b, the y intercept by plugging in your value for m and one of the given points, either (x1,y1) or (x2,y2).\n\nFor point slope form,  y - K = m(x - H)\nm is the slope, and   (H,K) is a point that the line passes through.\nSince you have already calculated the slope, m, for the slope intercept form, you're already almost done. All you have to do is plug in the point (x1,y1) or (x2,y2). In your question, you are asked for the point slope form of just point (6,2).
695994
The eqaution of the line is\ny-y1 =m(x-x1)\ny-0 = -3[x-(-4)]\ny-0 = -3(x+4)\ny= -3x-12
668279
Equation of a straight line: y = mx + b\nSubstitute m=-1 and x=2, y=1 into the equation,\ny = mx + b\n1 = (-1)(2) + b\n1 = -2 + b\n1 + 2 = b\nb = 3\n\nTherefore, equation of the straight line is y = -x + 3\n\nRearranging it into the format: mx + y = b,\nWe have, x + y = 3 (Q.E.D)
839656
Graph the line y = x - 5 (slope=1, y-intecept=-5)\nNow graph the line y = x.  You'll see if you shade everything above this second line (y > x), it doesn't intersect with your first line.\n\nSo the answer is the null set (no graph)\n\nAnother way to see this is to solve for x:\nx = y + 5\n\nNow plut this into your second equation:\ny > y + 5\n\nThere is no solution for this...\n\nEdit:  I reread your question and realized your [ x ] notation was intended to mean absolute value.  I would have written it | x |.  However, it doesn't make a difference.  \n\nFor negative x values, you have x < 0.  This makes lines with negative slopes, but even when they flip slopes, the y > -x line will be above the y = -x - 5 line.\n\nFor the negative values of x (x < 0), you have:\ny = -x - 5\ny > -x\n\nThe first line has a slope of -1 and an intercept of -5.  \nAgain if you solve for x:\nx = -y -5\n-x = y + 5\n\nPlug it into the inequality:\ny > y + 5\n\nAgain, no solution.\n\nSo the correct answer is an empty graph...
934552
Rearrange the equation so that you get it in the form of the equation of a straight line, that is in the form y = ax +b.\n\nYou get 2y = -x -2\n\nDivide through by 2 anf you get:\n\ny = -x/2 -1\n\nthe -x/2 term is -1/2 times x, so compare this with the equation of a straight line and you see that a = -1/2.  b is -1.\n\na is the slope or gradient of the line so the answer is -1/2.  Not that it has aminus sign so that tells you it slopes upwards from RIGHT to Left.\n\nb is the intercept on th y axis.  So the line crosses the y axis at y = -1.
110363
If you put an equation in the form:\n\ny = m*x + b\n\nthen, \n\nm = the slope\nb = the y-intercept.\n\nIf you look for a parallel line that passes through a given point, then you keep the slope the same, and solve for the slope:\n\n5x-4y = 1   -->  y = 5/4x - 1/4\nthe family of all parallel lines is\ny = 5/4x + b  (for any value of b).\n\nFor a line passing through (-8, 2), plug the numbers in and solve for b:\n2 = 5/4*(-8) + b\nb = 12\n\nSo y = 5/4x+12 is a line with slope 5/4, passing through the point (-8,2).
954269
it is natural to write the equation of st.line as y=ax+b (now common form is y=mx+c; this has its own story!)\n\nso if x=0, y=b
549653
Subtract 2x from each side\n-y = 0 - 2x\nMultiply each side by -1\ny = 2x
338193
The equation represents a straight line graph whose gradient is 3 , and intercepts the the ordinate axis(i.e y-axis) at the -2 position.\n\nthe easiest way to arrive at this is to draw a table of values. Such that you find the values of y, using values of x from -6 to +6.\n\nYour graph will confirm my story, \nBut from mere looking at the equation I can make a good prognosis, when i compare it with Y=mx + c .where Y represents the value of the equation, X represents the value of x which made y what it is.\nM stands for the gradient of the graph, while c stands for the intercept on the Y-axis.