find the factor s of 15 with a difference of 2?
343717
Let the factors be x and y, then\nxy = 15\nand x-y = 2\nSolve for x in x-y = 2 by adding y to both sides\nx = y+2\nSubstitute into xy = 15\n(y+2)y = 15\ny^2 + 2y - 15 = 0\nFactor\n(y-3)(y+5) = 0\ny equals 3 or -5.\nWe usually only talk about positive factors.\nAnswer: 3 and 5
246336
r = 20+t\nf = 6+y\ns = 15-g+u\ng = 15-s+u\nu = s+g-15
976886
It is a difference of two squares, in the form a^2-b^2\n\n\nTake the square root of both terms, which will be 3k and 5b.  Then write them in the form\n\n(a-b)(a+b)\n\nYour factored form will be \n\n(3k+5b)(3k-5b)
8473
7t+15 > 3t-13\n4t > -28\nt > -7
210100
Factor them out. \n2 = 2\n3 = 3\n4 = 2*2\n5 = 5\n6 = 3*2\nLowest common multiple = 2*2*3*5 = 60\nYou have 1 left over, so 60+1\n61.\n(2*30)+1, (3*20)+1, (4*15)+1, (5*12)+1, (6*10)+1
23893
There IS a solution:\n\n1x - .15x = 680\n\n.85x = 680\n\n.85x/.85 = 680/.85\n\nx = 800\n\nThere you go!!!
1089449
It's as simple as plugging in numbers.  The number 15 becomes the letter "a", the number 7 is "b", and the number 55 is "c".  Just substitute the number for the letter in the formula and solve.
701956
15(s-3)=12s-43\nfirst you distribute the 15 to the s and the 3 so you get 15s-45=12s-43\nThen you subtract 12s from both sides leaving you with 3s-45= -43\nthen you add 45 to both sides and you have 3s=2\nthen you divide both sides by 3 and your answer is 2/3.\n\nHope I helped!!
147408
(15-5) divided [ (12 divided by 2 *2) -2]\n\n= (15-5)/[12/(2*2) - 2]\n= 10/[12/(2*2) - 2]\n= 10/[12/4 - 2]\n= 10/[3 - 2]\n= 10/1\n= 10
117018
the first one all you do is simplify. since both the top and bottom have 5x, both would cancel eachother out. \n5x+2y/5x+14y = 2y/14y\nto simplify that further, both have factors of 2 so divide both numbers by two and you end up with\n2y/14y = y/7y\nif you need to simplify further you could divide y out of the equation and end up with 1/7\n\nthe second question you have to find the factors of each complex equation. x^2-5x-14 has factors of (x-7)(x+2)\n2x^2-x-10 has factors of (2x-5)(x+2)\nsince both share a factor of (x+2) they cancel eachother out. so you are left with x-7/2x-5.
681111
let me solve ur example first, then i will explain it to u.\n-5-(-15)\n-5+15\n10 is the answer. \n\nIf there r two negative together, make it positive.\nUse the following formula:\n- -= +\n- += -\n+ += +\n+ -= -
771836
Simple substitution.\n\n5(3) - 2(2) + 4(4)\n15 - 4 + 16\n27
572119
Well the correct is both 15 and 95.\nTaking 15 :\n(1)^2 + (5)^2 = 26 which is 11 more to 15\n2(1)(5) = 10 which is  5 less than 15\n\nTaking 95 : \n(9)^2 + (5)^2 = 106 which is 11 more to 95\n2(9)(5) = 90 which is 5 less than 95
281150
Next time just type your math equation into Google and it will do the math for you.\n\n15
517819
start pulling out common factors\n\n2 (x^3 + 27)\n\n2(x^3 + 3^3)
17162
Actually, the product of "it's" factors, is "it"!\n\nThe factors of "the number" are two numbers that you can multiply together to get "the number".\n\nFor example, if "the number" = 15,  two factors are 3 and 5 (because 3 x 5 = 15).  Since the product means the answer to a multiplication problem, to find "the product of the factors" would mean to take the factors, 3 and 5, and multiply them together!\n\nSo the product of two factors of 15 is 15!\n\nIf you want to know the product of ALL it's factors that's a different question.  All the factors of 15 are 1,3,5 & 15.  The product of ALL the factors of 15 is 1x3x5x15=  225.   Got it!?
903426
multiply 12 and -15 that is -180\nfactor -180 into 2 numbers such that sum is 11, (20 , -9) by trial and error. 15 , -12 sum is 3 so try >15 18,-10 no 20 -9 yesy\n\nso 12a^2+11a-15\n= 12a^2+20a -9a - 15\n= 4a(3a+5) -3(3a+5)\n=  (3a+5)(4a-3)