How do you work this problem? x(x+5)-2(x+5)?
342762
x2+5x-2x-10\n\n*answer*\n\nx2+3x-10
888367
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
198477
x^2-6x+5=\n\nx^2-5x-x+5=  [presenting -6x as -5x-x]\n\nx(x-5)-1(x-5)= [getting out common factor]\n\n(x-1)(x-5)\n\nTo see that it was done correct put any small number in the original expression and the result and compare them. If you did right, you should get two numbers which are equal to each other.\n\nPutting x=1 on the left side(the original expression):\n\n1^2-6*1+5=1-6+5=-5+5= 0.\n\nPutting x=1 on the right side(the result):\n\n(1-1)(1-5)=0*(-4) = 0.\n\nWe got on both sides the number 0, as expected, which probably means we did it right.\nTher final answer is:\n\n(x-1)(x-5)\n\nHope that helps.
1000586
# 1    \n(x+1)*(x+6)=x2 +x+6x+6=x2 +7x +6\n#2\n(y-6)*(y-5)= y2-5y-6y+30= y2-11y+30\n#3\n(a-2) * (a+10)=a2 +10a-2a -20= a2  +8a -20\n#4\n(x-1) *(x+1)= x2 -x+x -1= x2 - 1
726744
x/ -4 + 5 = 1\nsubtract 5 from both sides\nx/ -4 = -4\nthen multiply both sides by -4\nx = 16
921411
(x+2)(x-5)=(x-1)(x-3)\nx^2-3x-10=x^2-4x+3\n-3x-10=-4x+3 [x^2's cancel]\n+3x       +3x\n-10=-x+3\n-3        -3\n-13=-x\nx=13
747439
(5)(5)-2(5)(-4)+(-4)(-4)\n=25-(-40)+(16)\n=25+40+16\n=81\n\nDon't forget that (-)(-)=(+) and (-)(+)=(-).\n\nGood luck!
594458
The steps in substituting "2" for "x" are:\n\n3(2)+ y = 5\nwhich results in:\n6 + y = 5\nthen you isolate "y" by subtracting "6" from each side of the equation:\n6 - 6 + y = 5 - 6\nwhich results in the answer:\ny = -1\n\nI hope that helps.
775457
multiplying by x\nx^2-5=4x\nx^2-4x-5=0\n(x-5)(x+1)=0\nx=5 or -1
38332
(x-2)/(x^2-2x-15)+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(-2-x)(x+3)/(x-5)(x+3)\n\n[(x-2) + (x+3)(-2-x)] / [(x+3)(x-5)]\n\nANSWER :\n(x^2+4x+8)/((x+3)(5-x))
888483
First question:\nTake the sq. root of both sides:  x+2=+/-(sqrt5)\nThen subtract 2:  \n                               x = -2 +/-(sqrt 5)\n\nSecond prob:  subtract 5 first:\n\n(a+2)^2 = -3\nTake the square root of both sides:  (a+2) = +/-(sqrt(-3)\n    \nsqrt (-3) = i*sqrt 3\n\na+2 = +/-(i*sqrt 3)\n\nThen subtract 2: final answer:  -2 +/-(i*sqrt3)
655260
2=-1=x\n2+1=x\nthere fore x =3
1097866
(x + 5)^2 + 1 = 37\n(x + 5)^2 = 37 - 1 = 36\nx + 5 = +- 6\nHere you have two solutions:\nx = -11\nand\nx = 1
954896
x^2 + -2x = 5   Isolate the x^2 and x terms.\n\nx^2 + -2x = 5   Divide both sides of the equation by 1, which is the a-coefficient.\n\nx^2 + -2x + (-2/2)^2 = 5 + (-2/2)^2   Add half of the b-coefficient squared. In this equation that value is (-2/2)^2, and can be simplified to 1.\n\n(x + -2/2)^2 = 5 + (-2/2)^2   Write the x^2 and x terms side as a perfect square binomial.\n\n(x + -2/2)^2 = 5 + 1   Simplify the other side (simplify fractions).\n\n(x + -2/2)^2 = 6   Simplify the other side (combine numbers/fractions).\n\nSQRT[(x + -2/2)^2] = {+,-}SQRT[6]   Find the square root of both sides.\n\nWhen you combine and solve you'll get\n\nx = -1 plus or minus SQRT[6]
493796
You have to do the Trick, meaning you take out the 5 and reapply it to the number without the variable (2). This leaves you with: 5(xsquared-3x-10)=0\n\nFactor what is inside the parenthesis and get: (x+2)(x-5)\n\nThen reapply the 3 into the equations (but only into the variables, because your doing the trick) and you get:\n(5x+2)(5x-5)=0\n\nThen, set both equations to 0 and solve.\nThe first equation:5x+2=0\nSubtract the 2 from both sides to get: 5x=-2\n\nNext, divide the 5 out of both sides to get: x=-2/5\n\nThe second equation: 5x-5=0\nAdd 5 to both sides to get: 5x=5\n\nNext, divide the 5 out of both sides to get: x=5/5 or x=1\n\nFINAL ANSWERS:\nx=-2/5\nx=1\n\nIf it's a word problem and you can only have one answer, elimate the one that doesn't make sense. For example, if they are asking for the height of something, you wouldn't pick the negative number.
558121
i=i+2 (i=4)\ni++ (i=5)\ni=5
838051
5(x – 2)^2 = 3\n(x – 2)^2 =3/5\nx -2 =+- sqrt(3/5)\nx=2+- sqrt(3/5)