Can n e 1 help me on math?
347428
Yes, this sounds like the knight's tour.\n\nHere's a way to address it, but it may take fairly big sheet of paper.\n\nIn the corner, draw a circle inside of it place A1. This stands for the square in Row A, Column 1. Next to it draw two more circle, and label them B3 and C2. Draw a line from A1 to each of these. Draw all 30 squares as circles with collecting lines. It will look kind of like a map of cities connected by roads. Next. Start at A1 and visit each city once. It will be easier to see this pattern than to imagine the knights.\n\nOnce you're able to see the tour on your map, place the numbers back into the original table as you would have visited them.
425475
Is it 2ln(x) + 1 = 3 or 2ln(x+1) = 3\nIf it is 2ln(x) + 1 = 3, then\nsubtract 1 from each side\n2ln(x) = 2  Divide both sides by 2\nln(x) = 1\nPut these in the exponent of e\ne^[ln(x)] = e^1\nx = e^1, so x = e.\n\nIf it is 2ln(x+1) = 3, then divide by 2 on each side\nln(x+1) = 3/2\nPut these in the exponent of e.\ne^[ln(x+1)] = e^[3/2]\nx+1 = e^[3/2]  Subtract 1 from each side\nx = e^[3/2] - 1
1053953
Divide both sides by 11.\ne^x = 11\nThen take the natural log (ln) of both sides.  Any good scientific calculator can do this.\nln(e^x) = ln(11)\nx = ln(11)
520168
Try this:\n\nhttp://www.algebra.com/
50664
ln(e) = 1 is a basic rule\nwhen you have ln(x^y)\nyou can rewrite it as yln(x)\nso for that specific problem bring the 4 to the front to make 2*4*ln(e)\nthen ln(e)=1\nso 2*4*1 = 8
1178018
This may be useful:\n\nAlt + 160 = á\nAlt + 130 = é\nAlt + 161 = í\nAlt + 162 = ó\nAlt + 163 = ú\nAlt + 164 = ñ\nAlt + 165 = Ñ\nAlt + 129 = ü
956128
Simply multiply\n9 * 8 * 7 * 6\nBecause the first number can be 1-9 but not zero and the second number can be 1-9 but one number has already been used and so on and so forth.\nHope it helps.
390304
THE POSSIBILITIES:\n\n1.1:1→1*1=1\n2.1:2→1*2=2\n3.1:3→1*3=3\n4.1:4→1*4=4\n5.1:5→1*5=5 √\n6.1:6→1*6=6\n\n7.2:1→2*1=2\n8.2:2→2*2=2\n9.2:3→2*3=5\n10.2:4→2*4=8\n11.2:5→2*5=10 √\n12.2:6→2*6=12\n\n13.3:1→3*1=3\n14.3:2→3*2=6\n15.3:3→3*3=9\n16.3:4→3*4=12\n17.3:5→3*5=15 √\n18.3:6→3*6=18\n\n19.4:1→4*1=4\n20.4:2→4*2=8\n21.4:3→4*3=12\n22.4:4→4*4=16\n23.4:5→4*5=20 √\n24.4:6→4*6=24\n\n25.5:1→5*1=5    √\n26.5:2→5*2=10   √ \n27.5:3→5*3=15   √\n28.5:4→5*4=20   √\n29.5:5→5*5=25   √\n30.5:6→5*6=30   √\n\n31.6:1→6*1=6\n32.6:2→6*2=12\n33.6:3→6*3=18\n34.6:4→6*4=24\n35.6:5→6*5=30   √\n36.6:6→6*6=36\n\nProbability = No. of required possibilities/No. of total possible events =11/36\nSo the right answer is D
764334
d=4\na=-1\ntn=a+(n-1)d\n=-1+(n-1)4\n=-1+4n-4\n=4n-5
1089687
Try this calculator, you can answer any question like that
1094108
Use a calculator and raise it to the 1/3 power.\nDon't try to do it by hand...
888151
Basic math/algebra. You are taking two known numbers and finding the unknown number. \nE=P/I  solve for I    Think like simple Algebra I is X. So you want to work the problem and get a final answer x=?  or   I=?\nHope this helps.
1019971
Okay smarty here is a good site www.math2.org\n\ngood luck
1181046
http://homeworkhelp.aol.com/math/?sem=1&ncid=AOLRNL00170000000006
641208
The best place to go for math help online that i found was \nhttp://www.math.com\nI hope its useful to you.  I know people on here can tell you the answers, but if you have a test to take, and want to really learn it, go there.
154380
I posted these sources earlier to someone else who was looking for math help.\n\nGood Luck!!
741999
whats the equation or formula u need help with?