given that T = RV find R if T =4 and V = 8?
336054
T=RV \nT=4\nV=8\n 4=8R\n\nR = 4/8 = 0.5 = R
364905
Use Charles' Law\n\nLet V initial = V\nLet T initial = T\n\nLet V final = V'\nLet T final = T'\n\n\nV/T = V'/T'\n\nSolve for V' you might have to convert from mL to L though.
761125
It depends on if the equation is S=A-((RT)/(1-R)),  S=A-((RT)/(1))-R or any other variation.  Either way, T must be isolated by itself.  Assuming it is S=A-((RT)/(1-R)) you would first you would subtract A from both sides so you would have (S-A)=(A-A)-(RT)/(1-R) in which you get (S-A)=-(RT)/(1-R).  Divide each side by a -1 and get -(S-A)=(RT)/(1-R).  Multiply each side by (1-R) to eliminate from the right side to get -(S-A)(1-R)=RT.  Divide each side by R to eliminate R on the right side and get -(S-A)(1-R)/(R)=T.  Multiply out left side and get -(S-A-RS+RA)/R=T.  Simplify to get (-S+A+RS-RA)/R=T.  T=(-S+A+RS-RA)/R
860625
(10x+8) - (5x+4)\n= 10x - 5x +8 -4\n= 5x + 4
449048
P1 x V1 / T1 = P2 x V2 / T2\n\nYou have all you need.  Calculate it.
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
840437
Well, I can see that one possible solution is r = 0, and my calculator says the other answer is r = 0.0809394063, so hopefully that helps...
43919
Always remember PV=nRT.  In your case, P=(nRT)/V.
864795
8(t-2sqrt(a))(t+2sqrt(a))
615562
I assume these are vectors.\nv-w = <3-(-5),4-12> = <8,-8>\nu*(v-w) = <-2,1>*<8,-8> = -2(8) + 1(-8)\n= -16 - 8\n= -24
930308
x=[2+/-rt(4+60)]/2\n=[2+/-8]/2\n=-3 or 5\nso the factors are\n(x+3)(x-5)
886898
Find next closest square to 80 that is also a factor: 16\n\nSince 4*4 is 16, you can bring the 4 outside the radical and leave the product of the other factors underneath the radical: 4rt(5)
1119164
3x-4y-1=0\n\ndistance=4.8
928623
Hi Kenima ;\n\n-if u = 6   & t = 3  & v = (u -t )/ 3 \n-just fill the value of " u " & " t " in to Formula of v \n\nv = ( 6 - 3 ) / 3 \nv = 3 / 3\nv =1 \n\nGood Luck ♣
46701
v=u+at\nv^2-u^2=2as\ns=ut+1/2at^2\ns=disance traveled\nu=initial vel.\nv=final vel.\na=accelaration\nt=time
735754
just plug the numbers in.  if y=8, and x=2, \nits 8=a(2^2)\nso 8=a(4)\nso a=2.\nhope that helps!
170974
Prove that for  u,v, and w, p1=s(u)+t(v)+r(w), i.e that you can create a linear combination of vectors such that v=a1v1+a2v2+...+anvn.