y = 3x - 2 how do you do this???
338193
The equation represents a straight line graph whose gradient is 3 , and intercepts the the ordinate axis(i.e y-axis) at the -2 position.\n\nthe easiest way to arrive at this is to draw a table of values. Such that you find the values of y, using values of x from -6 to +6.\n\nYour graph will confirm my story, \nBut from mere looking at the equation I can make a good prognosis, when i compare it with Y=mx + c .where Y represents the value of the equation, X represents the value of x which made y what it is.\nM stands for the gradient of the graph, while c stands for the intercept on the Y-axis.
1011851
2x + y=14 and x - y= 1\nhence x=1+ y now substitute that in the 1st eq 2(1+y)+y=14\n2+3y=14\n3y=12\ny=4 now find out value of x you will get lhs = rhs simillary you can solve the second one...
778162
Step 1: find y '\nStep 2: fill in x=1\nThat gives the right answer 2\n\nTh
791030
3x – 2y = 6\n3x = 6 + 2y\nx = 2 + 2/3y
863140
First, you multiply the top equation by 2, to get:\n\n2x+2y = 8\n2x - y = 2\n\nThen, subtract the top equation with the bottom equation.  That is,\n(2x+2y) - (2x - y) = 8 - 2\n2x + 2y - 2x + y = 6\n3y = 6\ny = 2\n\nNow that you know the value of y, you can now solve for x, using any one of those two equations.  Let's use the second one.\n\n2x - y = 2\n2x - (2) = 2\n2x - 2 = 2\n2x = 4\nx = 2\n\nTherefore, x=2 and y=2 is the solution.
498659
1) y=x+4\n   3x+y=16 (I guess you made a mistake by writing +16)\n--------------\nsubstitute x+4 for y in second equation and you'll get\n\n   3x+x+4=16\n    4x+4=16\n    4x=12\n     x=3\n\nnow y=x+4=3+4=7\n\nsolution (x,y)=(3,7)\n\n2) 4x+5y=48\n    y=3x+2\n--------------\nsubstitute 3x+2 for y in first eq.\n\n4x+5(3x+2)=48\n\n4x+15x+10=48\n\n19x=38\n\nx=2\n\nnow y=3x+2=3*2+2=6+2=8\n\nsolution (x,y)=\n(2,8)\n\n3)3x-y=0\ny=6\nin first equation instead of y write 6\n\n3x-6=0\n3x=6\nx=2\n\nso, the solution is (2,6)\n\n4) x-2y=-10\n3x-y=0\n\nfrom the first equation you have\nx=2y-10\nnow substitute 2y-10 for x in second one\n\n3(2y-10)-y=0\n6y-30-y=0\n\n5y=30\ny=6 \nnow x=2y-10=2*6-10=12-10=2\nso x=2 and y=6
718048
x + y = 3\n\nSolve for a variable.  I chose X.\nx+y = 3\n -y    -y\nx = 3 - y\n\nSubstitute the value of X in the first equation.\n2(3-y) + y = 4\nDistribute.\n6-2y+y = 4\nAdd like terms.\n6-y = 4\n-6    -6\n-y = -2\nmultiply by -1.\ny=2\n\nSince you know Y = 2, substitute that back into the second equation that you solved for X with.\nx + y = 3\nX + 2 = 3\n  -2    -2\nX = 1\n\nX = 1\nY = 2
679397
y = 0.5x-4 \n\nor similarly\n\nx= 2y +8
809908
2(y-3) = y-6\n\nThis is what you are supposed to calculate : a value for the y, such that the equation holds.\n\nfor instance try y = 1\n\n2(1-3) = 1-6\n2 - 6 = 1- 6\nand you see that this is not so, thus y=1 is not a solution.\n\nthe standard way to solve is : move all y''s to the left of the=, and all numbers to the right of the =\n\n2(y-3) = y - 6\n2y - 6 = y - 6\n2y -y - 6 = -6 ( move left y to the right, sign changes )\n2y - y = -6 + 6 moved left -6 to right, change sign\n\ny = 0. ( adding the 2y - y together, and the -6 + 6\n\nso the solution is y = o
293623
(y(1)-y(2))/(x(1)-x(2)) =\n(3-(-2))/(3-8) =\n(5)/(-5) =\n-1
272177
multiply both sides by 3 and you'll get\n3x-3*4=-2*(y-9)\n\n3x-12=-2y+18\n-2y+18=3x-12\n-2y=3x-12-18\n-2y=3x-30  divide both sides by -2\n\ny = (-3/2)x + 15
781563
y>(12-3x)/4\n\nSteps:\n\nmultiply the 12 on both sides\n3x+4y>12\n\nminus the 3x isolating the y variable\n4y>12-3x\n\ndivide by 4 on both sides to get y by itself\ny>(12-3x)/4 or...\n\nsimplified 3-(3x/4)
942101
start by seperating y, u then have y=3x/2+3 then plug in the domain, or the numbers u are givin\nu'll have 0, 1.5, 3, 6, 7.5
225505
First manipulate a little to get everything lined up\n\n3x - 2y = -8\n9x - 3y = -21\n\nNow to cancel out one of the variables.  It's easiest to cancel out x, since 9 is a multiple of 3.  Multiply the 1st equation by -3\n\n-9x + 6y = 24\n9x -3y = -21\n\nNow add the 2 equations together.  The -9x and 9x cancel eachother out and you are left with\n\n6y - 3y = 24 - 21\n3y = 3\n\nFinish solving for y, and then plug that number in for y in either one of the equations above and solve for x. Good luck!
1119268
okay first take x/5 + y/5 = 3 and times everything by 3 so you have 3x/5 + 3y/5=9 now times everything by 5 so you have 3x + 3y = 45 (notice the 5's on left side cancel when u mulitiply) now take \n3x + 3y = 45 and subtract the other equation from it which is 3x + y = 13 so it looks like this \n  3x + 3y = 45\n -3x -   y  =-13 which gives you \n  2y = 32 divide by 2 to get \n y=16 substitute this value of y in second equation ( 3x + y = 13)\nso you have 3x + 16 = 13 subtract 16 from both sides and you will have 3x = -3 divide by there and it gives you x = -1 now plug in both of you values x and y into one of the equations i say the second one because it's much easier but anyways when you plug it in the second one you get 3(-1) + 16 = 13 is this true and the answer is yes therefore it is solved correctly\n\nEDIT: Doin it again with a little more detail for my own sake lol\nEquation 1=  x/5 + y/5 = 3\nEquation 2=  3x + y = 13\n\n(x/5 + y/5 = 3) mulitiply everything in the ( ) by 3\n(3x/5 + 3y/5 = 9) multiply everything in the ( ) by 5\n3x + 3y = 45 notice the fives on the left side cancel\nNow subtract Equation 2 from 3x + 3y = 45\n   3x + 3y = 45\n   -3x - y= -13 so this will give you\n 0x + 2y = 32 divide by 2\n          y = 16 Substitute your y value into equation 2\n3x + y = 13 so you have instead 3x + 16 = 13 subtract 16 from both sides 3x = -3 divide both sides by 3 so you have x = -1 now plug in your x and y values into equation 2\n3(-1) + 16 = 13; -3 + 16 = 13; 16 - 3 = 13 which is correct therefore the solutions are correct
796461
1) x = y\nSubstituting:\n4x - 3x = -3\nx = -3\ny = -3\n\n2) 3x + 2y = 6\nx = 2y - 6\nSubstituting:\n3(2y - 6) + 2y = 6\n6y - 18 + 2y = 6\n8y = 24\ny = 3\nx = 2(3) - 6\nx = 0\ny = 3\n\n3) 2x - 6y = 2\n-3x + 9y = -3\nIf you divide the top by 2 and the bottom by -3 you get:\nx - 3y = 1\nx - 3y = 1\n\nThese are equivalent, so you can't determine a single solution.\n\nThe best you can do is simplify the equation to get a formula for y given x:\n3y = x - 1\ny = (1/3)x + (-1/3)\nBecause you can't isolate a single variable, you essentially have one equation and two unknowns.  The solutions will lie along the line with a slope of 1/3 and a y-intercept of -1/3.
461929
6x=2y\ndivide both sides by 2\n3x=y\nrewrite\ny=3x