table of values x=4-y   x-2y=10?
351633
4-y-2y=10\n4-3y=10\n-3y=6\ny=-2\n\nx=4-(-2)\nx=6
855878
you have to set up two equations....x+y=24 and .10x+.25y=3.00\n\nnow you can do to things...one way is to solve the first equation for x or y then    x=24-y.... sub this into x in the second equation    \n.10(24-y)+.25y=3.00\n2.4-.1y+.25y=3.00  combine terms\n2.4+.15y=3.00\nsubtract 2.4 from both sides\n.15y=.6 divide both sides by .15\ny=4  x=20
1062625
There is no single value for x or y. Still, we can solve for both.\n\n10x+8y=100 <-lets get rid of the multiplier of x, divide by 10\nx+0.8y=10 <-now lets get x alone, subtract 0.8y\nx=10-0.8y <-this equation defines x\n\n10x+8y=100 <-lets get a single y, divide by 8\n1.25x+y=12.5 <-again, get y alone, subtract 1.25x\ny=12.5-1.25x <-this equasion defines y\n\nSince x and y are not single values but instead equasions, this is the best you can do. Plug in whatever values you want for y in order to come up with what x will have to be to fit your original equasion, and vice versa.
378781
-1*100\n-2*50\n-4*25\n-5*20\n-10*10\n~or~\n1*-100\n2*-50\n4*-25\n5*-20\n10*-10
561594
i think you wrote it down wrong, maybe it should just be 3x+4y=12 and then you solve for y.\n\nalso, i don't know what an in and out table is
225766
Given, x = 1/2y + 4 ............(i)\n and   2y +3 x = 12 ............(ii)\nSoln.: Multiply both side by 2 in eqn. (i)\n      2x = y + 8\ni.e.  2x - y = 8\ni. e. 4x - 2y = 16....(iii), multiplying both the side by 2\nNow, add eqn. (ii) and (iii) above,\n (2y+3x)+ (4x-2y)= 12 + 16\ni.e. 7x = 28\ni.e. x = 28/7 = 4.Ans.\nNow putting the value of x = 4 in either of the eqn. above, find out the value of y. Say, put value of 'x' in eqn.(ii),\n2y + 3x = 12\n2y + 3x4 = 12\n2y + 12 = 12\n2y = 12-12 = 0\nSo, y = 0/2 = 0 Ans.
913982
Replace x with -2:\n4(-2)+y=10\n-8+y=10\n\nAdd 8 to both sides:\ny=18\n\nThe ordered pair is (-2,18)\n\nThe ordered pair means to find the x and y values.\n\nCheck:\n4(-2)+18=10\n-8+18=10\n10=10
338519
If you remove x completely (because you already know it's equal to 9), you have:\n\n4y = 9\n \nor 9/4 which is 2.25
90743
Well you must have two equations! If you wanted to say x+4y=16 then just add the two and you'll fing x (4x=10) and then find y from one of them.
337327
assign value for your x-variable...say -10, -5, 0, 5, 10 and repesent it in a graph form...
735754
just plug the numbers in.  if y=8, and x=2, \nits 8=a(2^2)\nso 8=a(4)\nso a=2.\nhope that helps!
925662
12y=2y+40  subtract 2y from each side\n10y=40  divide by 10\ny=4
705155
10 + 6x = 4x - 4\n2x = -14\nx = -7
424681
substituiting your values you get (the values you gave are not very clear, can't make out whether positive or negative.\nAssuming all values are positive...)\ny-2 = 2(x-5)\ny-2 = 2x -10\n2x -y - 8 =0  is of the form ax + by + c =0
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
985975
take - common\n -(y^2-9y+20)\n-(y^2-5y-4y+20)\n-(y(y-5)-4(y-5))\n-(y-4)(y-5)
885850
y'=-10x+2\nsetting itto 0\nx=1/5\ny''=-10 negative so a max at x=1/5\nthe maximum value=-5(1/5)^2+2/5-4\n=-1/5+2/5-4\n=-19/5