could i factor a2- 81 like (a-9)2 ?
344768
Nooooooooooo\n\na^2-81=\na^2-9^2=\n(a-9)(a+9)\n\n(if you don't believe\n multiply (a-9)(a+9)=a^2-9a+9a-81=a^2-81)\n\nthe formula is a^2-b^2=(a-b)(a+b)\n\n(a-9)^2=\na^2-18a+81\n\nhere the formula is (a-b)^2=a^2-2ab+b^2\n\n(you can simply check it by multiplying\n(a-9)^=(a-9)(a-9)=a^2-9a-9a+81=a^2-18a+81)\n\nand you must see the difference between \na^2-81 and a^2-18a+81, it's quite obvious.
545883
(a^2  - 5) * (a^2  - 2)
783756
in standard form yes, but thats not the whole answer, the answer would be x to the 2 power and -1
1123652
#1 - 8100\n#2 - 45%\n#3 - 1/40\n#4 - 36a^6\n#5 - 7x^6\n#6 - 60\n\nAnd for the love of god, please learn to spell.
631080
You can noy factor it out... it makes it easier to figure out when you put it into lowest terms... so it would be \n\n   x^2+7x-25..... so you cant factor it.
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
122942
Any answer with B>90 is acceptable satisfying:\nA=2B-180\nand C=180-B-A\n\nfor example: (A,B,C)=(20,60,100) or (40,30,110)\n\nNote that ABC and DBC are similiar.
678104
Are you trying to factor?\n\n2^(x+1) * 8^(-x)\n\nYou can solve this by remembering that a negative exponent term in the numerator should go into the denominator as a positive exponent term. Remember also that y^(x+1) = y*y^(x)\nand that 2^(x+1) with 8^x means that for any number, x, there is one more "2" than there are "8"\n\nThis is easily a homework question. You'll have to complete it from here.
912271
(495/98)-((159*√2)/2)\nor\n.462041705769\n\nDepending on which form u need it in.
614283
the first step is basically to factor 120175.  the obvious factor to do first is 5.  this gives us 5*24035.  then factoring another 5 gives us 5*5*4807.  since 4807 obviously isn't divisible by 5 or 2, try 3.  doesn't work - so keep on trying the next biggest prime number (1,2,3,5,7,11,13,17...)  turns out that 4807 is divisible by 11.  this gives us 5*5*11*437.  keep on going and you get 5*5*11*19*23.  just checking, yes - 5*5*11*19*23=120175.\n\nnow converting these factors into letters, you get the available letters EEKSW.  this can be rearranged to be WEEKS.  however, remember that 5*5*11*19*23 can also be written as 25*11*19*23, since this also equals 120175.  this means the word could also have KSWY.  but i don't think you can rearrange those letters to make a word.\n\nso therefore the english word encoded as 120175 is WEEKS.  basically, you factored the number, converted them into letters, and solved the anagram.\n\n[[edit]]\n\ninuyasha's right - there could be an infinite number of "a"s in there too since 5*5*11*19*23 = 5*5*11*19*23*1*1*1*...\n\nhowever, this gives us WEEKS+AAA... so using the online anagram solver, found at http://wordsmith.org/anagram/ , there are no words that have "WEEKS" in them and "A"s.  therefore, the answer is still WEEKS.
800533
Well dear Kristi \n\nthe answer is \n( 9r - 2s )^2 \n{ as you know ( a - b )^2 = a^2 -2ab+ b^2 \n81r^2 - 36rs + 4s^2\na = 9r , b = 2s , so \na^2 = (9r)^2 = 81r^2 \nb^2 = (2s)^2 = 4s^2 \n-2ab = (-2)(9r)(2s) = -36rs  } \n\nGood Luck Darling
402918
I think you wrote 10x*2yz - 22x*3yz.  To factor this oyu must take out like terms by dividing.  You can see that both terms share a 2, y, z, and an x*2.  After the  division you get  2x*2yz( 5 - 11x).  I hope this helps.
768731
1 x 80 = 2 x 40 = 4 x 20 = 5 x 16 = 8 x 10\n80 has 2 x 5 = 10 factors.\n\nTh
775644
Duch, there's some confusion over what the problem is.  It could be a/(3+4b) - a/(3+b)  OR  a/3 +4b -a/3 -b\n\nIf the former, then it boils down to -(11ab)/(9 + 15b + 4b²)\n\nIf the later, 3b
945505
{(x^2+5x+4)/(x+3)^2}/(x+1/(x^2 -9))\nFactor everything that you can factor.\nx^2 + 5x + 4 = (x+1)(x+4)\nx^2 - 9 = (x+3)(x-3)\nYou have\n{(x+1)(x+4)/(x+3)^2} * {(x+3)(x-3)/(x+1)}\nYou can cancel the (x+3)'s and the (x+1)'s leaving you with\n(x+4)(x-3)/(x+3)
769323
6 - 12x\n-or-\n-12x + 6\n\n-or-\n\n6(1-2x)\n\n...although that depends on whether you want the simplest expanded form or the simplest factored form.
713027
Just try out small numbers. 1, 2, 3, 4, 6, 8 all work. Once you start doing anything higher, the second factor becomes smaller again, so the others are 96/8, 96/6, 96/4, 96/3, 96/2, 96/1.\nIn all: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96.