for what positive numbers will the cube of a # exceed 4 times its square?
338855
You are looking for values of x such that\nx^3 > 4x^2  Solve for x by bringing everything to one side.\nSo subtract 4x^2 from both sides\nx^3 - 4x^2 > 0\nFactor x^2 out\nx^2(x-4) > 0\nx^2(x-4) = 0 when x = 0 or x = 4\nSince you're looking for positive numbers, you only have to test a number between 0 and 4, and then another number greater than 4\nAny number between 0 and 4 will result in a negative value.\nAny nummber greater than 4 will result in a positive value.  You are looking for the positive values because  the expression is greater than zero.\nThus, any number that is greater than 4 will give you the result that the cube of a number is greater than 4 times its square.
215797
To 'square' a number means to multiply it by itself.\nexample: 4 squared = 4 X 4\n\nTo 'cube' a number is to multiply it by itself again after squaring it.\nexample: 4 cubed = 4 X 4 X 4
799963
If you are asking if the negative cubed root of 64 is 8, then no it is wrong.  The cubed root of 64 is 4, so your answer should be negative 4.   4*4*4 is equal 64, so taking the cubed root would be 4.     Taking the square root is like multiplying to the (1/2) power, so taking the cubed root is like multiplying to the (1/3) power.  So 64^(1/3) is equal to 4.  then the negative of that answer is -4.
4519
(4/3)*pi*r^3\n\n[four thirds pi r cubed]\n\ngood luck!
297409
This doesn't make any sense. You need to put down the numbers you're working with. If you're talking about finding cube roots, that's one thing; taking any number to the third power (x, for instance), is just: x*x*x.
306191
a) cube...final answer
475059
4\ncubed root of 8 is 2. squared is 4. \nOr 8 squared is 64, cubed root of that is 4.
413500
2.8284271. For that to equal 8, x would have to be 2. 2 cubed is eight and the square root of that is 2.8284271. Another way to express that is 2^(3/2) = 2.8284271, or the "square root of two cubed".
836453
a^24b^24\njust multiply the exponents\n\nhope thie helps!!!
723712
One way to solve this is to draw it on graph paper and count up the squares.  Howevr, I think I have a solution that doesn't resort to graphing:\n\nThe units 15 and 42 have a common divisor of 3.  So, if the diagonal starts at (0,0), it will also intersect (5,14) and (10,28).  Therefore, we can reduce this problem to testing a 5 by 14 rectangle and multplying by 3.\n\nFor the 5 by 14 rectangle, since this diagonal won't hit any vertices of the unit squares, just figure you will pass through 14 squares as you make your way across, and you will move up 4 squares.  So, 4 + 14 = 18 squares.  \n\nMultiple by 3 to get your answer for the 15 by 42 rectangle: 18 * 3 = 54.
504201
Actually, none of the above are correct. To factor anything in the form of a cubed - b cubed, where a and b are real numbers, the formula is (a - b)(a^2 + ab + b^2). In this case, the a would be 1 and the b would be 4. So, the answer would be (x-4)(x^2 + 4x + 16i)\n\nand paul is incorrect also, try to multiple it out, it's wrong
539053
4.43x10(at the power of -4)
540085
(a-2)(a+2)  \n(difference of squares)
87438
cubed = power of 3\n\ny cubed = y raised to 3 or y^3 = y x y x y\n\n2 cubed = 2 ^ 3 = 2 x 2 x 2 = 8
41284
Wait, all the answers are wrong\n\nx^2+4>4\nThen x^2-4x+4>0\nthen (x-2)^2>0\nBut hey, (x-2)^>0 is always true expect when x=2 which equals zero. An square is always positive or 0.\nSo the answer will be any value but 2 or R-{2}\nthese are the evidence:\nPut them in original non equation\nx=0 then 4>0 which is true\nx=-1 then 1+4>-4 so 5>-4 which is true\nx=3 then 9+4>12 so 13>12\n but at x=2 then 8>8 which is incorrect
671808
4 sides and corners in a square
805518
These numbers are cubes. 1 cubed (1 x 1 x 1) is 1, 2 cubed (2 x 2 x 2) is 8, 3 cubed (3 x 3 x 3) is 27, and 4 (4 x 4 x 4) cubed is 64. Therefore, the next number is 125 or 5 cubed (5 x 5 x 5). This pattern continues with 6 cubed, 7 cubed, etc.