an observer measures the velocities of 2 particles,he got m1 & m2.?
338257
a) vcenter = (m1*v1+m2+m2)/(m1+m2)\n\nb) v1 rel = v1 - v center\nv2 rel = v2 - v center\n\nremember velocity is a vector so you must keep track of magnitude and direction
893701
v(m/s) = Q(m3/s) / Nozzle Area(m2)
723976
Question is: why on earth would you want to make that calculation?  m/s^2 is the standard form for acceleration.
748491
E = mc2 is an important and well-known equation, which states an equivalence between energy (E) and mass (m), in direct proportion to the square of the speed of light in a vacuum (c2).
947891
E = mc2 states an equivalence between energy (E) and mass (m), in direct proportion to the square of the speed of light in a vacuum (c2). \n\nhttp://www.drphysics.com/syllabus/energy/energy.html\n\nEinstein reasoned that the center of mass of an isolated system doesn't just move on its own. So, the motion of the cylinder must be compensated by the motion of some other mass. Let's assume the light has mass m. Then, Mx=mL, since the cylinder moves x to the left and the light moves L to the right. Substituting the expression for x given above, the equation can be simplified to E=mc2.
680534
Use the equation from the link below.  You will find that \nv/c = 0.14365, or\nv = 0.14365 c\nor\nv = 43,100 km/s\n\nThe object is moving away from the observer at this rate.\n\nBy the way, you probably won't get credit unless you can work out the math steps I left out.
544447
c represents the speed of light in a vacuum.\n\nc = exactly 299,792,458 m/s
447577
enery equals mass times the speed of light squared
848082
The M-M experiment was an optical interferometer. An interferometer is a device that splits a beam of monochromatic light in two, sends each along different paths, and then recombines them. Each time the interfering beams pass from constructive to destructive interference means that one path has increased the number of wavelengths traveled relative to the other by 1. M-M made the different paths orthogonal and rotated the whole interferometer by 90 degrees and observed that the number of wavelengths in each path remained equal to each other. This implies that the speed of light does not depend on direction. Since the earth is known to rotate and move around the sun, the result implies that the speed of light relative to the interferometer does not depend on this motion, as would be the case if there were a fixed medium that light propagates in at constant velocity, and through which the earth moves (a popular hypothesis of the time).
306574
The important principle in this theory is:\n\nThe speed of light is not affected by the speed of the source emitting this light.\n \nThat is: “Once light is emitted from a source it moves in vacuum with a constant speed.\n\nSpeed of a matter and the speed of light are measured by measuring length and time.   But light is energy; whereas the source is a matter.\n\nIf both observers; one at rest and another moving; says that light’s speed is same for both, there are only two possibilities; 1. Both must be at rest or 2. Time and length must be different for the two observers. \n\nBut one observer sees that the other is moving with a speed relative to him. Therefore, time and length must be different for the two observers.\nThe other consequence is that mass is also affected by its speed. \n\nThe one at rest will observe that time and the length are shortened for a moving object such that the speed of light is the same for both frames of reference. \n\nSince the moving observer observes that the other one is moving and he is at rest he will say in the other man’s reference frame time and length are shortened such that the speed of light is the same for both frames of reference. \n\nThis is the theory of relativity.
667845
In 1881 Michelson using his interferometer measured the speed of light when moving toward a light beam and when moving away from a light beam. \n\nThe experiment was repeated many times and it was found that the speed of light is constant irrespective of the speed of the source of light.\n\nIn a moving train if a ball is thrown in the direction of motion of the train with a speed u’ and if the train is moving with a speed of v, we generally conclude that for an observer outside the train who is at rest the speed is u’ + v. \n\nThis is the formula which we applied to find the speed of light and we expected the speed of light to be equal to c+v. ‘v’ is the speed of train in which we measured the speed of light.\n\nHow did we measure the speed of light in the moving train? We marked two points in the train and measured the distance and found the time for the light to travel this distance.\n\nIf the measured distance and time are not shortened, we will measure the speed of light as c+ v. But the speed of light is actually measured to be c. We conclude as the train is moving with a speed v, the distances and times measured within the moving train are shortened such a way the measurement of light yields the value c.\n\nIf x’ and t’ are the distance and time measured in the moving train, we expect that \nthe distance x for an observer at rest must be x’ + v t’ ( Of course we also assume that x = x’ and t = t’)\n\nLorentz formed the equation to accommodate the constancy of speed of light by modifying the equation as follows. \n\nx = x’ + v t’/ B and t = [t’ + vx’/ c^2] / B where B = square root of {1- (v/c) ^2}\n\nIf the velocity of any object in a moving train is u’, then according to the observer at rest the velocity\n u = u’ +v / 1 + u’v/ c^2 and not u’ +v alone.\n\nIf the train is moving with the speed c and the speed of any object is c in the train, then for the observer at rest it will be viewed as \nu= c +c / 1 + cc/ c^2= c.\n\n If the train is moving with the speed c and the speed of any object is 2c in the train, then for the observer at rest it will be viewed as \nu = 2c +c / 1 + 2cc/ c^2 = c\n\nThus for the observer at rest no object can exceed the speed light.\n\n\nFor ordinary speeds the above equations reduces to our usual equations.
953783
did he? \nhe talked about attraction force (F) between bodies (m1, m2, staying d distance apart) though\nF = G (m1. m2) / d^2
727746
Well we have\n\nwavelength = h/momentum = h/mv = h/m(.0131c)\n\nwhere h is plank's constant and c is speed of light.\nso substitute and calculate.
75525
a) 72.072 cm/sec^2\n\nb) 82.63 cm/sec^2
936755
Momentum is defined as mass x velocity.  When two objects, m1 and m2 collide with velocities v1 and v2 the equations is:\n\nm1 x v1 = m2 x v2 showing that like energy momentum is conserved.  Use this equation to solve your porblem and go to the head of the class.
40471
E=mc^2 \nEnergy = mass * (speed of light)^2, c = the speed of light (approx. 186,000 miles per second).
38506
yikes, everyone is giving you the wrong formula. it's not e=mc^2. that would be converting energy into mass and back which is done like when subatomic particles crash into each other really fast and such... the mass dialation formula you are looking for is \nm'= m/sqrt(1-v^2/c^2)\nwhere m' is the mass you would be not moving at the high velocities, m is the mass moving at the high velocities, v is the velocity you're traveling at, c is the speed of light, sqrt means we're square rooting everything in those parenthesis, and ^2 means squared. if you were to plug numbers in for velocity, you can see that this effect is absolutely neglagible unless you are moving very very close to the speed of light. and it is impossible to actually move at the speed of light, because then v^2/c^2 would be 1, and 1-1=0 so you would have a 0 in the denominator of that equation, which is impossible.  that equation is actually very interesting in that it is part of the lorentz factor which also effects time and length. in fact, as you increase speeds close to the speed of light, not only does mass increase, but time moves slower for you and length shrinks.  I've had to derive these equations in physics class, it's very interesting to do it yourself and come up with the equation proving that things like velocity, mass, and length are affected by velocity.  but again, you need to be going very very close to the speed of light for the velocity to have any effect on these things.\n\nas far as practicality, instances of the lorentz factor have been proven. there are these particles that have a certain lifespan before they disintigrate.  so now, we know how fast they are going and we know how long before they disintegrate, so theoretically, we should easily be able to figure out how much distance they cover before they disintigrate, right? but somehow, the particles go a lot farther than they should... if we plug their velocity into the lorentz transformation formula however, and put in how far they should travel (but don't), they we come up with how far they actually do travel.  this proves the validity of the lorentz factor.\n\nthere is no practical application of the mass increase since objects of great mass would require way too much energy to accelerate to speeds great enough to see this effect, so therefore it can't really happen.. if ever it did though, the only thing this mass expansion would serve to do would be to limit time travel. i mean, if time is slowing down for us at high speeds, technically we could make it slow down so much so that it would be going slower for you than everyone else and so you could basically travel forward in time. but if your mass was expanding and length shrinking, then either the pressure would kill you, or your blood would get so dense it couldnt carry oxygen to your cells and that would kill you, so there goes the time travel thing.