Is there a theoretical (or practical) limit to the frequency (in Hz) a laser can output?
353533
If you could find a transition between an inverted state and a ground state of 1 joule, you could probably make a laser of that frequency. At this point, hard gamma rays are the limit we have done.
283860
Frequency = speed of light/wavelength.\n\nMake sure you keep the units straight when performing the calculations or it may not make sense.\n\nSo for your problem its (3 x 10^17 )/200 = 1.5 x 10^15 Hz
742095
Since the impedance of a coil at the 400Hz is higher than it is at 60Hz you can build smaller inductive devices for 400Hz. Weight counts on an airplane. An electric motor or a generator or transformer that produces the same power at a fraction of the weight is a winner when you have to fly it around.\n\nWhy did they pick the exact number 400 I don't know but lately fluorescent lamps are being operated at much higher frequencies so maybe 400 is getting obsolete and will be replaced by a higher frequency too.
913461
"Near Infra-Red" starts at 750nm wavelength (a fixed, accepted value).\nIn theory, and by definition, we CAN'T see it.\nHowever, we are all different: we are not machines built on a standard.\nTo find out if you can see NIR, you have to go to a laboratory, ask for a calibrated source of light and check from say, 650nm to 900nm wavelength radiations.  You will then be able to find exactly your limit for "your" visible.  If it is above 750nm, then you see NIR... officially!\nYou can compare this to your auditive perception: the AF (audio frequencies range, by definition, from 16Hz to 16000 Hz).\nMany of us cannot hear 16kHz, many of us can hear much higher than that!\nIt is all relative.
1104023
Not likely.  Most modern pc's have built in protection against external frequencies.
844258
um, basically, there is no connection between resistance and frequency. there are however some circuits that output a frequency based on a time constant that can be set by a resistor though. if that is what you mean, then we need to know what circuit you are talking about.
159866
The extremes that people can hear are 20 Hz to 20 kHz.  The upper limit for most people is closer to 15 kHz.  For comparison, 60 Hz is the low-pitched hum you frequently hear from AC wall power.  320 Hz is middle C.  440 Hz is the "A"that you hear when an orchestra is tuning.  Each octave is double.  So, high "C" is 640 Hz and the "A" above is 880.  Two octaves above middle "C" is 1280 Hz, and so on. Many, though more females than males, can detect a high pitched noise from the scan rate of the TV video.  This, is at 15.734 kHz.\n\nA and B are on the order of the vibrations you might feel from an earthquake -- more felt than heard.  100 kHz is well beyond the range of human hearing.  Dogs don't even hear that high!  That leaves "C" as the correct answer.
99168
Need more detail.  Analog or digital?  Cutoff frequency?  Out of band rejection?  Is there a constraint on number of orders?  Matlab has built in functions to do filter design.  \n\nSomething a simple as a suitable capacitor will block low frequency.
243391
Yes. The Op Amp data sheet will have a Ft or Unity Gain Badwidth and you want it to be several times higher than the frequencies you want to use.\n\nFor example, an OPA695 has a Bw of 450Mhz. The slew rate is the limiting factor, and as frequency goes up, the open loop gain may suffer.\n\nLook at http://www.analog.com and this paper from TI:\nhttp://www.eetasia.com/ARTICLES/2005JUN/A/2005JUN13_RFD_AN.PDF
123099
I still trying to figure out it's voltage, sorry. ;-) I try to look.  5.5x10 to the 14th power Hz   http://www.cs.williams.edu/~cs105/f01/text/ch3/DigitalTrans_14.html    Then scroll down until you find Prism.
548925
Well in the 808 to 908 nm you are working in the range of photon emission of water.  I have not heard of a H2O laser yet; but, you never know...  I have seen some Noble gas lasers work near this frequency range however, most generate much higher power then the mw range you are querying about.\n\nAs to the range of a laser it really depends on the divergence of the beam.  The greater the beam spreads out from the end of the laser the less likely it will go far with any appreciable energy.  And example might be a Helium Neon at 6.15 um and 5 mw with a beam divergence of 1.5 radians.  Though visible at the target up to 1 mile away\nthe amount of energy is very small and can only be observed as a distant red dot.  That you have chosen a laser with a higher energy density (by a factor of about 10,000) you might be able to detect it at a distance of 100 miles as a small bluish dot regardless of the power level.  All the power level at this distance will do is determine the relative intensity of the blue dot, (IE faint, barely visible, clearly visible in a dark night sky.)  However, you would not be able to see the ends on the surface of the planet as the curvature of the earth limits the distance between two points at about 6 feet above the ground to around 14-15 miles.)\n\nThe other issue you have is how much interference there is between the laser and the target.  Indoors you can simulate long distances using fiber optic cables; however, most are tuned for higher frequencies.  Though Corning makes a 50nm single mode fiber that might be used to simulate a long distance; however as a general rule Bell Labs discovered the greatest distance they could send a high frequency signal through the fiber with a loss of less then one third the signal strength is around 160 miles.  In free air emissions there are a number of variables, dust or aerosols, rain, water vapor even the nitrogen in the air can attenuate the power of the laser.  Again Bell Labs did a number of experiments using laser to attempt to form a very tight communications channel between ground stations and satellites, they found it was possible; however, the interference was so great that even with 100 watts of a blue laser the signal would not allow a reliable signal.\n\nBut, I digress, if you want to calculate the db loss you have to know the signal loss of the medium the laser light will pass.  There are a number of tables that will help you estimate this data; but, you have to pay attention to the test conditions.  As a general rule you need to know the initial power, the attenuation of the medium and the minimum detection power required of the detector.  You have the initial power in your choices above, the minimum power of the detector will generally be around 10mw at this frequency.  So you only need to know the db loss of the medium.  The general rule of thumb is as you double the distance you reduce the energy level by the square root of the initial power.  So if you start with 100 mw at 1 meter you would be at 10 mw at 100 meters.  If you start with 1 watt you would normally reach 10 mw at 1000 meters.  If you start with 10 watts you would normally reach 10 mw at 10,000 meters.  All providing you do not have much interference.\nIf the medium has a db loss of 3db that means in addition to the squares rule you would have half the power or distance capability.  If you have 9db loss you would have about 1/8th the power level.  \n\nI don't know how much this will help you; but, these are general rules of thumb that should at least help you determine for yourself the type of data you might need to either do more research or guide you in your research.  \n\nGood Luck,\nDave Cooke
314821
It would be 622.5 Hz.\n\nThe second harmonic is twice the fundamental frequency, and the third harmonic is three times the fundamental frequency, so it would be 3/2 times the frequency of the second harmonic.
952318
there will stretching to the string, and the amplitude and frequency will be tranmitted....but the cycles wont be at light speed...so they wont allow for instantaneous communication.  Now if the cable was fiberoptic...and pulses were transmitted...hmm
173113
Below are some links with some cool diagrams.  I'm not sure if it's specifically what you wanted though.  The second link has some really cool information about spectral transitions in a LASER.
572734
Frequency is measured in Hertz, or inverse seconds.  So take the inverse of 6, which would be 1/6, which is your frequency.  Tada!
683354
b. 93,300,000 Hz\n\nFM stations measure their frequencies in Megahertz (MHz)
538754
hi dude!\ni'll give u only the unworked answers\nwavelength of light i the cornea is 193/1.376 nm\nand the frequency would be 3*10^8*1.376/(193*10^-9) hz\ni hope i'm not too late!!