How many black squares are there on a soccer ball?
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No squares just  octagons!
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32 countrey from all around the world \n\nwww.fifaworldcup.com
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There were 3 yellow cards, 11 corners. Anything else you wana know?
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game1. 1 yellow card\ngame2. 1 yellow card\ngame3 misses match\n\nThat is correct.\n\nIf a player get 2 yelow cards in SAME match, equals a red card.\n\nReferee shows the yellow card for second time (indicating is  not a red card directly), and then, bacuase was secod yellow it will show the red card.\n\nStill, a player can recive a red card without having a yelow card first. Or it can recive a red card after the 1st yellow.\n\nWhen a red card is showed, player will miss at least one match, but can be many more, depending on the FIFA judges.
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1 the goal\n10 midfield\n9 attacker\n3,4,2 defense\n7 or 14 playmaker\nex :\nTores in spain 9\nR.Carlos 3
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Normally 336, but anywhere between 300 and 500 is acceptable. Different balls have different numbers of dimples.
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14 games in 4 world cups  12 goals    (1958)-6 goals; ( 1962)1 goal;(1966)1 goal  ;(1970) 4 goals
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Here you go.....\n\nhttp://www.soccerballworld.com/1930%20Soccer%20Ball.htm \n\n\nhttp://www.sover.net/~spectrum/
73893
For a nine by nine square Sudoku problem (81 total cells), a minimum of 17 numbers must be given to find the unique solution. Graph theorist Gordon Royle has found approximately 10,000 non-equivalent (or unique) Sudoku problems. (Technically, though, Sudoku can be any size, say 16x16). These days, newspaper use Sudoku puzzles which have been created by computer algorithm, deemed inferior to hand-creation. And lastly, the game was not originally Japanese; it was invented in the UK.
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ZERO (O)  NO RECTANGLES..\n\n\nCHESS BOARD HAVE ONLY SQUARES..
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I make it five.  Four in the 1990 World Cup in Italy and one at USA 1994.\n\nMilla did get the ball in the back of the net in Spain in 1982 against Peru but it was ruled out.\n\nFor the goal against Russia in 1994 he holds the record for the oldest goalscorer in the World Cup finals.
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Yes, it is possible.\n\nDenote the number of black dots belonging to a red dot by N.\n\nThe present problem is formulated for N=10.\n\nLet us first solve a simpler problem with N=2.\n\nStep 1. \nTake a square, that is a four-sided regular polygon, with the side equal to R. Put the two red dots at the opposite [i.e., connected by a diagonal] vertices of the square. Put the two black dots at the remaining two vertices. If you draw a circle of radius R around each of the two red dots, you will find exactly 2 black dots lying precisely on the circle line. The problem is almost solved, but the number of red dots (2) is equal to the number of black dots (2).\n\nStep 2. \nTake another square and repeat the above procedure. \nNow we have the two square compounds. In total we have 4 red dots and 4 black dots.\n\nStep 3. \nPut the 5th red dot anywhere in the plane and draw a circle of radius R around it. \nDrag each of the above compounds as a whole closer to this circle. \nPlace one of the black dots belonging to the first compound and one of the black dots belonging to the second compound on the circle line surrounding the 5th red dot.\n\nWhile doing so, make sure that you move and rotate each compound as a whole, keeping all the sides of the squares equal to R. \n\nThe problem with N=2 has been solved: in total we have 5 red dots and 4 black dots satisfying the condition of the problem, 5>4. \n\nLet us solve the same problem for N=3.\n\nIn this case, one has to extend the Step 1.\n\nStep 1a. \nHaving constructed the square compound according to the Step 1 above, draw parallel vectors of length R starting at the vertices of the square. Make sure that the vectors do NOT coincide with the sides of the square. \nIf the vector starts at the red vertex, put the black dot at the end of the vector. If the vector starts at the black vertex, put the red dot at the end of the vector. \n\nNow we have one compound consisting of the two shifted squares containing 4 red dots and 4 black dots. If you draw a circle of R around each of the four red dots, you will find exactly 3 black dots lying precisely on the circle line.\n\nStep 2. Repeat the procedure 1+1a.\nStep 2a. Repeat the procedure 1+1a.\n\nNow that we have 3 compounds with equal numbers of red and black dots (in total 12 red dots and 12 black dots), put the 13th red dot anywhere in the plane and follow the instructions from Step 3 above.\n\nThe problem with N=3 has been solved: in total we have 13 red dots and 12 black dots satisfying the condition of the problem, 13>12. \n\nFor N=4, take the compound constructed for N=3 at Step 1a and translate ALL 8 vertices by a vector of length R.\nAgain, if the vector starts at the red vertex, put the black dot at the end of the vector and vice versa. You will have 8 red dots and 8 black dots, etc.\n\nThe above procedure applies to an arbitrary N, in particular to N=10.\n\n\nAn interesting question is: what is the minimal number of dots needed to solve the problem for a given N.
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Fullerene.  C60.  Picture a soccer ball made of carbon.  For your blank in the question above, I think the answer is 60.
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They use quite a bit.  I don't know how many exactly but on the sideline they have quite a few ballboys, about one every few yards.  Interesting fact:  The World Cup match balls are made in Thailand for the first time ever.  Previously in the World Cup, like 80% of soccer balls manufactured worldwide, they were produced in Pakistan, most of which produced in the city of Sialkot.  FIFA did not want to use balls produced by child labor, so they used balls that were machine-made.
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The best soccer balls have between 1400 and 2000 stitches hand made and need 4 hours of work.\nSource-Sam
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try http://yahoo.com or http://google.com image search for "soccer"
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1. They have all won the international cup.\n2. Norman Whiteside (Northern Ireland, 1982) at the age of 17 years and 41 days.\n3. Spain. He also played for Colombia and Argentina in his career.\n4. Oldest player, Roger Milla ( Cameroon), 42 years and 39 days.\n5. By former Czechoslovakia's Vaclav Masek. The former record was 15 seconds.\n6. The black octopus was Lev Yashin of Russia. Eusebio of portugal was known as the black panther and as the black diamond.