the two beses of a trapezoid are 3 in. and 11 in. and the altitude is 8 in. whta is the area of the trapezoid?
344325
Area of a trapezoid = (1/2)*(base1 + base2)*altitude\nHence area of the trapezoid in question = (1/2)(3+11)(8) = 56 square inches
317924
See previous answer--\n\nGives vertical height as rt27\n\nTherefore 1/2*6*rt27 is area of one side\n\nBase is 6*6 = 36
802843
Area of a trapezoid = 1/2 Height (Base1 + Base 2)\n224 sqm = 1/2 (16)(20 + x)\nmultiply both sides of the equation by 2 to remove fractions\n448 = 16 (20 + x)\n448 = 320 + 16x\ncombine\n16x = 128\nx = 8 m
110565
>>>> what is the altitude of a right triangle?\n\nI have several here, and I am at 12 metres above sea level.\nSeriously, you haven’t provided enough information. You need at minimum the length of 2 sides or a side and an angle as well as the orientation to be able to calculate height (altitude).\n\n>>>>>>if the equation is d=2r what is the d and the r what exectly \n>>>>>>>am I finding with this equation \n\nd = diameter. r= radius. You are finding either how far it is from one side of a circle to another (d), or how far it is form the edge of a circle to the centre (r).
101549
V=1/2(b1+b2)*h*w  where b1 and b2 are the two parallel sides of the trapezoid and h is the height and w is the width.
226304
Area = pi*r^2\n\nSo, plug the numbers into the equation.\n\n118 = 3.14 * r^2\n\nr = 6.13\n\nSo, the answer's B.
862584
area of a regular hexagon=3rt3/2 *a^2\n=3rt3/2*24^2\n=72*12rt3\n=864rt3 cm^2
1017799
V = area of base times height\nheight = 14\nbase = 3*3*pi = 9pi\nV = 14*9pi\nV = 126pi\nV = 395.8
327427
Each side would have length sqrt(3), so the area would be 3 m^2.
326809
The area of a trapezoid is the height times the average of the bases, or h*(b1+b2)/2.  In your case, your bases are the top and bottom of your figure (parallel to the x-axis), and your height is along the y-axis.  So,\n\nh = a\nb1 = c\nb2 = b\n\nA = a(b+c)/2
941173
area = 1/2 base times height\nBase times height = 88  (44*2)\nLenght of the legs are 11 and 8
404470
a) AX = 2.25 cm.\n\nb) area AXY upon area ABC = 0.5625\n\nc) area AXY upon area trapezium XYCB = 0.4375
605775
Are you talkin about a trapezium or a trapezoid.\nif its a trapezium,here's how : \nlet the height be "h".\ndrop two perpendiculars equal to h on the base.the lengths b&#92;w the perps.is 6 units.therefore the rest of the length is 10.each individual length to the left of the perp is 5 units.\nin the triangle with the diagonal,the side adjacent to the angle with the base and diagonal is 6+5=11\ntherefore the angle is cos^-1(11/12)=a\ntherefore tan a=h/11\ntherefore h=11tan a\nanswer is height,h=4.795831523
1087013
To find the area of a trapezoid, take the sum of its bases, multiply the sum by the height of the trapezoid, and then divide the result by 2.  Then, multiply by the depth (here, .5 for 1/2 foot deep) to get the volume.
494278
a trapezoid.\n   __\n  /__&#92;
1085744
A = 1/2 x (a + b) x h\n90 = 1/2 x (6.5 + 5.5) x h\n90 = 1/2 x (12) x h\n90 = 6h\n90 / 6 = h\n15 = h\n\nThe height is 15.  The 'x' should be used as a multiplier.\n\nThe formula for the area of a trapezoid is also:\n\nArea = (height * (side 1 + side 2)) / 2\n\nHope that helps! =)
586130
surface area = 3bh, where b is length of side, and h is the height dropped normally from center to any of the sides\n\nvolume = 6 times volumeof each triamgle, formed by all 3 diagonals