p*p-16p+38 factor trinomial?
355476
here's a tip. p*p = p^2\n\nnow do your own homework. How do you expect to pass the test?! Y!A won't be there for you then.
420710
I know it has already been answered but I"ll take a chance with something different. Ok 3 to the third power plus two would be 3 to the fifth power which is 243.\n :)
950667
This is a mathematics question, but fine. \nThe factors are 1, 2, 3, 4, 6, 8, 12, 16, 24.\nThe prime factors are 2^4,3.\n\nJust trial and error.
743513
it's A\n\n4st+6t -10s-15\n2t(2s+3) -5(2s+3)    \n(I factored out the negative for both numbers in the -10s-15)\n\n(2t-5)(2s+3) or (2s+3)(2t-5)
120086
(b-3a)(b+2a)\n\nk skippy you should be able to do your own homework now :)
898616
abc(-24a^2b+43c)/6abc\n=(1/6)(-24a^2b+43c)
854026
Step 1: Calculate the "grouping" number: 10 × 6 = 60\n\nStep 2: Find 2 numbers whose product is 60 and whose sum is 19. Writing 60 = 1 × 60 = 2 × 30 = 3 × 20 = 4 × 15 = 5 × 12 = 6 × 10, we see that 4 + 15 = 19, so the two required numbers are 4 and 15 (or 15 and 4).\n\nStep 3: Write 19 x = 4 x + 15 x\n\nStep 4: Rewrite the whole trinomial, and factor by grouping:\n\n10 x² + 19 x + 6\n= 10 x² + ( 4 x + 15 x ) + 6\n= ( 10 x² + 4 x ) + ( 15 x + 6 )\n= 2 x ( 5 x + 2 ) + 3 ( 5 x + 2 )\n= ( 2 x + 3 ) ( 5 x + 2 )\n\nAlternatively, you can use 19 = 15 + 4:\n\n10 x² + 19 x + 6 \n= 10 x² + 15 x + 4x + 6\n= 5 x ( 2 x + 3 ) + 2 ( x + 3 )\n= ( 5 x + 2 ) ( 2 x + 3 )
956461
factors of 24\n1, 2, 3, 4, 6, 8, 12, 24
954300
ok\nso its factoring.this is hella easy.10x+40 is 10(x+4)\nso the answer is 10(x+4)there you go
965295
6 + 4(m+13) -9m\n6 + (4m + 52) - 9m\n58 - 5m
320291
6p^6 + 24p^5 + 18p^3 = 6p^3(p^3 + 4p^2 + 3)\n\nIt doesn't break down any farther than that.
1027973
the 3rd one is correct, but I get -(3+b)/b+2 and 2 for the first 2
136651
7c\n\n\n2*7*c*c\n\n5*7*c\n\ncommon factors:  7 and c\n\ntherefore, it's 7c
838062
24x+29xy-19y\n-16x+9xy+ 23y\n-----------------------\n8x+38xy+4y\n------------------------
916165
Sorry, there isn't one.  If you meant "3x + 9" instead of 3x, then x + 3 is a common factor.
67300
it depends on the alphabeth you use.\nIf you use the 26 charachter anglo-saxon alphabeth as I suppose, you'll get 27 terms in your polynomial, starting from a*b*c*...*z and ending with +x^26\nAll the powers of x form 1 to 26 will be present; the terms where the exponent of x is even will be positive in sign, and the terms where the exponent of x is odd will be negative.\nThe coefficient of the k-th factor will be the algebraic sum of all the combinations of k different elements picked among the 26 alphabeth's letters; such terms will be in number of C(26,k), the same Newton coefficient for the k-th term of the 26-th power of (x+1).\nThere are simple algorythms to calculate that numbers, such as the so-called Tartaglia's triangle, which gives in their right sequence all the numbers of different terms to add to obtain the developement of the n-th power of a binomial:\n\n1          (power 0)\n11         (power 1) \n121        (power 2)\n1331       (power 3)\n....         ....\nYou can obtain the next row from the one above putting 1 as the first, and calculating the next ones as sums of the numbers they have on their top and on their top-left; then add a new 1 to finish.\nYou can also do it on an Excel sheet\n\nIf instead you used Italian alphabeth which has only 21 letters, the last term would be -x^21 (negative as 21 is odd), and in all the reasoning you should substitute 26 with 21.
287407
3(16 y_squared - 24xy + 9 x_squared)