what is the mass of mars?
351568
6.4185×1023 kg, or the equivalent of 0.107 Earths.
1117701
the earth does not weigh. It has a mass.\n5.9742×10^24 kg
100886
The equations weren't visible in Ginabean's answer (at least not on my display) and the other answer dealt with Earth, not the fictional planet postulated.  So I'll add some things.\n\nWe worked out the mass of this planet using the density and the radius in your other question.  M = 8.92*10^22 kg.\n\nNow, the force of gravity is given by\n\nF = G M m /r^2  , where M is the mass of the first object, in this case the planet, m is the mass of the other object, in this case something on the surface of the planet, and r is the distance between their centers, in this case the radius of the planet.  (Because the planet is spherical, we can treat the mass of the planet as if it were all located at its center.)\n\nSo, the acceleration caused by gravity on this planet, g, is F/m where F is the force of gravity and m is the mass of the object, \n\ng =F/m = G M /r^2\n\ng = (6.67 * 10^-11 m^3/s^2kg) * 8.92*10^22 kg / (1600000 m)^2\n\ng = 2.32 m/s^2\n\nThis is about a fourth of the values on earth.  That makes sense.  The mass and radius of this imaginary planet are comparable to the Moon (M = 7.36 x 10^22 kg, r = 1738 km) where the acceleration of gravity is about 1/6 of the Earth.
36310
Mars is larger than Mercury in size, but smaller than the Earth. It orbits the Sun at a distance 50% farther away from the Sun than the Earth. Mean density of Mars is 3930 kilogram per cubic meter.
770605
a)\nGravitational force F between two bodies with masses m1 and m2 separated by a distance r is described by the equation\nF=G*m1*m2/r^2, where G is a constant with value 6,67*10^(-11) N*m^2.kg^2.\n\nWe know that F=34.3 N and m2 = 3.5kg and r = 7.4*10^6 m\nSubstituting we get \nm1=8.05*10^24 kg\n\nb)\n\nDensity d = m / V\nSince the planet is a sphere its volume is V=(4/3)*Pi*R^3\n\nSo d = 4740 kg/m^3
631787
The number is less than the mass of the Earth's mantle divided by the average mass of a sand particle. According to http://www.astro.wisc.edu/~ewilcots/astro236/drakeandrichter.pdf, the mass of the Earth's mantle is around 1.4*10^24 grams. According to http://www.ma.iup.edu/~hedonley/drag/drag25.html the mass of a sand particle is around 1.7*10^(-7) grams.\nThus the amount of particles in a mantle made up completely of sand would be around (1.4/1.7)*10^31 = 8.2*10^30. In America, this would be called 8.2 nonillions by the nomenclature-obsessed minority. Since the mantle is not made completely up of sand particles, the number of sand particles is less than this number, and since that number is less than infinity, so is the number of sand particles. It is thus an unknown, but finite, number.\n\nPS: Note that a "zillion" is not a real number. It is a fictitious play on the way we name large numbers and does not correspond to any exact amount. See http://www.google.com/search?hs=Xwl&hl=en&lr=&safe=off&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&q=define%3Azillion&btnG=Search .
948318
309grams.\nThe dry mass is 58grams.
546930
The diameter of Mars at its equator is 6,794 kilometers (4,222 miles), compared to Earth's 12,756 kilometers (7,928 miles).  This is 53% of Earth's size.\n\nIt also has about 30% of Earth's gravity, 11% of Earth's mass, and 1% of Earth's atmospheric pressure.  Oh, and it has 0% of Earth's population, but that statistic is the most likely of any of them to change.
658807
Check the following links to know more about Mars.\n\nFollow links on these pages to have  a better insight on The Universe!
95148
Actually, the mass of a proton is 1.00727664669 atomic mass units.\n\nAn atomic mass unit is defined such that Carbon 12 is exactly 12.  The carbon atom weighs less than 12 times the proton (because of nuclear binding energy).
426189
see for yourself.\n\nhttp://marsrovers.nasa.gov/home/index.html
781013
hope these websites help...\n\n\nhttp://www.seds.org/nineplanets/nineplanets/mars.html\nhttp://www.the-planet-mars.com/
180650
Mars is quite cold as usual, ranging from -120 degrees Celsius to -60 degrees Celsius (-185 to -75 degrees Fahrenheit).  Wind speeds range from near calm to 130 km/h or 80mph.
1183745
Mars is much smaller than Earth.  About 1/2 the diameter (0.53), and 1/10 of the mass (0.107) of the Earth.\n\nHere's a great set of illustrations showing the relative sizes of all the planets, and the sun.\n\nhttp://www.comagz.com/webmagazine/story/proportions_how_small_we_are
1003351
The mass of the planet Earth is 5.97 * 1024 kilograms (from Ask.com)\n\nMass From Wikipedia, the free encyclopedia\nJump to: navigation, search\nFor other uses, see Mass (disambiguation).\nMass is a property of a physical object that quantifies the amount of matter and energy it contains. Unlike weight, the mass of something stays the same regardless of location. In relativity, the quantity invariant mass, which is closest in content to the classical idea of mass, also does not vary between single observers in different reference frames. Mass is a central concept of classical mechanics and related subjects, and also several forms of mass appear in relativistic kinematics (see mass in special relativity).
264256
CALCULATING THE MASS OF THE EARTH\n\n1. F = GmM/r2 = ma, where F is the gravitational force, G is the gravitational constant, M is the mass of the Earth, r is the radius of the Earth, and m is the mass of another object (near the surface of the Earth). \n\n2. GM/r2= a (The m's canceled out.) Now solve for M, the mass of the Earth. \n\n3. M = ar2/G, where a=9.8m/sec2, r=6.4 x 10 6m, and G=6.67 x 10-11m3/(kg sec2). \n\n4. M = 9.8 x (6.7 x 106)2/6.7 x 10-11 = 6.0 x 1024 kg
1047333
A 150lb. person on the planet Mars would weigh 38 lbs. on Mars.\nIf an average 150 lb. person was able to jump 3 feet high on Earth then the same person on Mars should be able to jump\n(150/38) * 3 feet = 11.84 feet high.  If he could jump that high on Earth he would have been drafted 1st by the NBA and be a star player, lol.