what is 2ax+6xc+ba+3bc factored?
339354
(2x + b) * (a + 3c)\n\n\nsteps:\n2ax + 6xc + ba + 3bc \n1) group first two, and last two\n(2ax + 6xc) + (ba + 3bc)\n\n2) factor out 2x from the first, and then b from the second group\n2x*(a + 3c) +  b*(a + 3c)\n\n3) since (a + 3c) is common, combine 2x and b\n(2x + b)*(a + 3c)
1128579
abc=V\n2(ab+ac+bc)=SA
528677
2ab+ 2ab=4ab-ab=3ab   answer is 3ab
402918
I think you wrote 10x*2yz - 22x*3yz.  To factor this oyu must take out like terms by dividing.  You can see that both terms share a 2, y, z, and an x*2.  After the  division you get  2x*2yz( 5 - 11x).  I hope this helps.
975217
Line AC = 6, line BC= 2x+2, line AB=x+1\nSo 2x + 2 = 6\n2x = 4\nx = 2 <-- option C
919174
first multiply the first two factors and multiply the product by the third factor\n\nTo multiply something complicated like (4x + 6)(5x - 3)(15 - x), just do FOIL on two of the binomials and then distribute the answer onto the remaining binomial
534750
1/2 + 1/2b + 2b^2 + 6bc + c^2\n\n(1/4b)(1/4b) + 4bc + (bc)(bc)\n1/2 + 1/4b +1/4b + b^2 +4bc + b^2 + c^2 + 2bc\n1/2 + 1/2 + 2b^2 + 6bc + c^2\n\nI think this is right... email me if I'm wrong?
99842
in a multiplication problem:\n\n2 x 3 = 6\n\n2 & 3 are factors, 6 is the product
1019688
(x - 2)*3 = 6 + x\n\n3x - 6 = 6 + x\n\n2x = 12\n\nx = 6
259003
Use the quadratic formula.  It works everytime!\nx = (-b plus or minus sprt(b^2 - 4ac))/2\nwhere\nax^2 + bx + c = 0\nSome of these will factor, however not all of them will.
550482
-2a(b+2)-6b=\nor\n-2(ab+2a+3b)
898616
abc(-24a^2b+43c)/6abc\n=(1/6)(-24a^2b+43c)
924243
(q - 6h)(g - 6h) \n= q(g - 6h) - 6h(g - 6h)\n= gq - 6hq - 6gh + 36h² (-6h x -6h = +36hh = +36h²)\n\n8q²j - 12g³hj \n= 2 x 2 x 2 x q x q x j - 2 x 2 x 3 x g x g x g x h x j\n= 2 x 2 x j x (2 x q x q - 3 x g x g x g x h)\n= 4j(2q² - 3g³h)  (The common factors in each part are the multiplier, the remaining factors are what are left inside the parentheses ... and always remember that 1 is always a factor of any number .. see example below)\n\n5g²h - 10g³h²\n= 5 x g x g x h - 2 x 5 x g x g x g x h x h\n= 5 x g x g x h x (1 - 2 x g x h)\n= 5g²h(1 - 2gh) (because 5g²h x 1 = 5g²h)
503348
No, the previous answer is wrong.\n\nGroup it like this:\n\n2p + pq -6q -3q^2\n\nthen factor like this:\np(2+q) -3q(2+q)\n\nfactor out the 2+q to get:\n(2+q)(p-3q)\n\nFOIL it out and you will see it is correct.
658148
given 4a^2-12ab+9b^2\n    =(2a)^2-2(2a)(3b)+(3a)^2\n    =(2a-3b)^2
62092
if you mean 3(2ab-x) ... then 6ab-3x
843398
6x(x-3y)-3(6x^2-xy) = 6x^2-18xy-18x^2+3xy=-12x^2-15xy ans.