using slopes and intercepts.  How do I do this?
341565
Well, first, write it in standard form (y=mx+b).\n\ny = -3x + 0\n\nThe m in the equation is the slope of the line, and the b is the y-intercept. \n\nSlope = -3\ny-Intercept = 0\n\nFor another example, y = 5x + 3 would have a slope of 5 and a y-intercept of 3.\n\n\nHope this helped.
955089
y-2x=2\ny=2(x+1)\nx intercept(-1,0)\ny intercept(0,2)
733627
Rewrite the equations as:\ny = -x + 2 and\ny = (x+10)/2 = 1/2*x +5\n\nNow, if you insert x=0 in each equation, you will get a y-value.\nIf you insert y=0 in each equation, you will get an x-value.\nFor each line, you can use those two intercepts to graph the line.
3669
This is for math right? If so:\n\nThe slope-intercept form is:\n\ny = mx + b\n\ny = value on the y-axis\nm = slope\nx = value on the x-axis\nb = y-axis intercept\n\nThe slope-intercept form gives the equation for a straight line.
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
925887
Hopefully you know how to solve one part of it. Slope intercept form is Y= M x+B. First find the slope, using 2 set of coordinates, that formula is Y2-Y1 over X2-X1. that will be your M.  Then find your Y intercept. then plug it in to that formula above. I hope i was of some help. Don't put your life on this i did it in the beginning of the school year.  I may have the M and the B switched.
771990
y = mx + b is the slope intercept form, where m = slope\n\nso 2 is the slope in your example\n\nWith any equation for a line, there are 2 variables, x and y, representing the position on the x and y axis.  Given any line equation, you can manipulate it to get it into slope intercept form (y = mx + b), and m will be your slope.\n\nThe y-intercept is where the line crosses the y-axis (or where x = 0).  As you can see, if you put x = 0 in the equation, you will get:\n\ny = 0x + b\ny = b\n\nso when x = 0, y = b.\n\nHope this helps! :)
306531
First, the slope is (delta y)/(delta X) = (-3)/2) = -3/2\n\nthe y intercept is +6  (interpolating back from \n(6,-3) ,(4,0),(2,3), (0,6)\n\nso the equation is Y=-3/2 X + 6\n\ngo from there and you have your answer.
730934
First you have to find the equation of the line that contains these two points (9,1) and (5,5)\nI believe the easiest way to do that is to use slope and y-intercept form (y=mx+b) m= slope and b= y-intercept\n\nto find slope, m = rise/run\nrise = -4\nrun = 4\nrise / run = -1\n\nTo find y-intercept plug in a coordinate pair and use are found slope.( i used 5,5)\ny=mx+b  x= 5 y=5 m=-1 b =?\n5=(-1)(5) +b\n10 = b\n\nSo this is our equation of the two points\ny=-x +10 \n\nNow we can use this equation to find whether  (10,0) is on  the line: Substitute (10,0) and see if the equation is still valid\n\n 0 = (-1)(10) + 10\n 0 = 0 Yes (10,0) is on the same line as the other points
562373
y = mx + b\n\nm is the slope (rise over run).  You have two coordinates (x1,y1) and (x2,y2).  Rise is y2-y1, Run is x2-x1.  So in your example, Rise = 6, Run = -5.  Slope = Rise/Run or -6/5\n\ny = -6/5x + b\n\nb is the y-intercept.\n\nPlugging in one of your coordinate x=3, y=-5\n-5 = -(6/5)(3) + b\nSolve for b and you have\nb = -5 + 18/5\nb = -25/5 + 18/5\nb = -7/5\n\ny = -6/5x -7/5\n\nTo double check, let's put in the second coordinate of x = -2, y = 1\n\n1 = -6/5(-2) -7/5\n1 = 12/5 - 7/5\n1 = 5/5\n1 = 1\n\nThis is consistent, so there is your answer:\n\ny = -6/5x -7/5
444240
-y=2-x\n\ny=x-2\n\nslope is 1\ny intercept is (0,-2)
665061
have the equation in slope intercept form except with a greater then or equal to sign or less then or equal to sign\nexample:  Y > Mx + B  then solve it like you would a normal slope intercept equation by solving for x... start by adding or subtracting b to Y and then divide the slope which is Mx from both sides and then you will get your x answer the greater or less then sign will change if the answer is negative it will face the opposite way from which it was if postive answer it won't change....... hope this helps......
238720
So we can find the x-intercept(s)
789536
If you are supposed to do it by graph, then it's easy.  Just place the points on the graph (scaled, of course) and see when x=0, namely, when the line crosses the y-axis.  That will be your answer.  If you are looking for the formula way, here you go:\n\nm=(4-0)/(10-(-10)) = 4/20 = 1/5\n\n0 = 1/5(-10) + b\nb= 2\n\ny=x/5+2\n\nYour y-intercept, or f(0), is 2
341751
Using pt. slope equation:\n\nY=mX+B where m=slope = 2/3, b=intercept, in this case = 0,\n\nY = 2/3 * x + 0\n\ny=2x/3.\n\n3y=2x\n3y-2x = 0.\n2x-3y=0
359675
y-intercept occurs when x=0\n\nSo, set x=0, and your equation becomes:\n    2(0) - y = 4\n\nor, because 2*0 = 0,\n    \n    y = -4 is your y-intercept.\n\nThe slope can be found by writing the equation in standard "y = mx + b" form, where "m" is the slope. In your example, that would be:\n\n    y = 2x - 4\n\nSo, the slope ("m") is 2.\n\nDone and done.
698987
Another form of the equation is the point-slope form. If you have two points, find the slope.\n\nm = (a2-b2)/(a1-b1) for points (a1,a2) and (b1,b2)\n\n  Then take one point (a1,a2) and plug it into the following:\n\n(y-a2) = m(x-a1)\n\nIt actually turns out to be the slope intercept form, but if your teacher will accept that form than it is easier since you can just leave it like that.