Do you think the sun will form a black hole up like any other star?
343545
It will NOT!\n\nIt'll 'die' by:\nIt starts to fuse helium to heavier elements. Thus, it'll swell up into a red giant (earth will be gone). \nThen, it'll suddenly shrink into a white dwarf.
710830
Not at all.  The sun exploding might make a pretty nebula for a few days.
313861
YES. There are many stars in our galaxy with solar system formed.
406243
very long. this is because the sun is a very large star and will take billions or rather trillions of years. when it does burn out however, it will be big enough to swell so big that it will swallow mercury, venus and possibly earth ^^ good luck
410940
Our Sun's mass isn't great enough to create a black hole, but speaking in a hypothetical situation it would suck everything into including the planets and so forth because its gravitational pull is so great.  However, recent astronomical studies have proven using a spectrometer and examining the data produced by it the stars in almost every single galaxy are moving at a rate which only indicates the presence of a super massive black hole in almost every single galaxy.  The size of the black hole is dependent upon the galaxies size and is directly related to its sigma, but these black holes are present in almost every galaxy we have viewed, including our own and are currently not feeding anymore and are dormant.  They believe that they helped form the galaxy in some way but it is not known yet.  So maybe it is possible if the Sun created a black hole it would feed to the point that it also became dormant, probably not though.
128460
It might be, or it might be a neutron star. We do not really know. \n\nThere are some other objects in the sky which are much more certainly black holes, from their masses and other properties.
438696
the guys talking about our sun in 5 billion years are correct. by then we should figure out a way to move to a new star system.
1152122
A star is a big mass of gas. It originated as a hydrogen cloud  that started contracting because gravity pulled it together. When this happens the interior gets denser and hotter. Dense enough and hot enough for fusion reactions to start. The latter produce heat and light that pushes outwards.\n\nThe result is an equilibrium between gravity and the light radiation. The star stabilizes and stays stable for billions of years. The sun is in this stage.\n\nHowever, when the hydrogen is burnt up, the outward pressure is taken away and gravity takes over again. If the mass of this burnt out star is big enough, then there is nothing to counteract gravity.\n\nThe mass of the star will be more and more concentrated in a smaller and small volume. Gravity at the surface will become so strong that not even light can escape from it. \n\nThat is a black hole.
6001
yes!!\n\nBlack holes are predictions of Albert Einstein's theory of general relativity. In particular, they occur in the Schwarzschild metric, one of the earliest and simplest solutions to Einstein's equations, found by Karl Schwarzschild in 1915. This solution describes the curvature of spacetime in the vicinity of a static and spherically symmetric object, where the metric is\n\n    ds^2 = - c^2 &#92;left( 1 - {2Gm &#92;over c^2 r} &#92;right) dt^2 + &#92;left( 1 - {2Gm &#92;over c^2 r} &#92;right)^{-1} dr^2 + r^2 d&#92;Omega^2,\n\nwhere d&#92;Omega^2 = d&#92;theta^2 + &#92;sin^2&#92;theta&#92;; d&#92;phi^2 is a standard element of solid angle.\n\nAccording to Schwarzschild's solution, a gravitating object will collapse into a black hole if its radius is smaller than a characteristic distance, known as the Schwarzschild radius. Below this radius, spacetime is so strongly curved that any light ray emitted in this region, regardless of the direction in which it is emitted, will travel towards the center of the system. Because relativity forbids anything from travelling faster than light, anything below the Schwarzschild radius – including the constituent particles of the gravitating object – will collapse into the center. A gravitational singularity, a region of theoretically infinite density, forms at this point. Because not even light can escape from within the Schwarzschild radius, a classical black hole would truly appear black.\n\nThe Schwarzschild radius is given by\n\n    r_s = {2&#92;,Gm &#92;over c^2}\n\nwhere G is the gravitational constant, m is the mass of the object, and c is the speed of light. For an object with the mass of the Earth, the Schwarzschild radius is a mere 9 millimeters — about the size of a marble.\n\nThe mean density inside the Schwarzschild radius decreases as the mass of the black hole increases, so while an earth-mass black hole would have a density of 2 × 1030 kg/m3, a supermassive black hole of 109 solar masses has a density of around 20 kg/m3, less than water! The mean density is given by\n\n    &#92;rho=&#92;frac{3&#92;,c^6}{32&#92;pi m^2G^3}\n\nSince the Earth has a mean radius of 6371 km, its volume would have to be reduced 4 × 1026 times to collapse into a black hole. For an object with the mass of the Sun, the Schwarzschild radius is approximately 3 km, much smaller than the Sun's current radius of about 700,000 km. It is also significantly smaller than the radius to which the Sun will ultimately shrink after exhausting its nuclear fuel, which is several thousand kilometers. More massive stars can collapse into black holes at the end of their lifetimes.\n\nMore general black holes are also predicted by other solutions to Einstein's equations, such as the Kerr metric for a rotating black hole, which possesses a ring singularity. Then we have the Reissner-Nordström metric for charged black holes. Last the Kerr-Newman metric is for the case of a charged and rotating black hole.\n\nThere is also the Black Hole Entropy formula:\n\nS = &#92;frac{Akc^3}{4&#92;hbar G}\n\nWhere A is the area of the event horizon of the black hole, &#92;hbar is Dirac's constant (the "reduced Planck constant"), k is the Boltzmann constant, G is the gravitational constant, c is the speed of light and S is the entropy.
759134
I'm afraid its "Goodnight Vienna" for us. As this is unlikely to happen for another 5 billion years or so though, there is a fair chance that we will have blown ourselves up or evolved into something a little more intelligent and cleared off elsewhere by the time it happens.\n\nAlthough the Sun uses up around 5 million tons of hydrogen every second, it still has enough left in its core to last for another 5 billion years or so. When it finally does run out of fuel, though, it will swell up to many times its present size and become what is known as a red giant. \n \nThe outer layers of the Sun will grow to swallow up the planets Mercury and Venus and they may even reach out as far as Earth. Way before the Earth is swallowed the surface of our planet will be scorched, its oceans boiled dry and most of the atmosphere will be stripped away.\n\nAs a red giant, the Sun might be able to exist for a few more million years. During this time it will shed matter quite quickly. The solar wind will strengthen to a solar gale. Finally, the Sun may cast off most of its outer layers as a bright shell of gas called a planetary nebula.\n\nAll that will be left behind is a very hot, dense core. The Sun, in fact, will have become a white dwarf - a star no bigger than the Earth. Gradually, over many millions of years, even this small star will cool. The Sun will end its days quietly as a dimming ember in space.\n\nThe attached link shows a photo of a star similar to the Sun in its death throes.
145689
*Poking lordfarhad.rahimi* Please only post a question once...\n\nFar as the universe being unsteady, yes of course it is. That is the nature of the universe, it is not a steady, static thing. It changes and is chaotic. That is part of the beauty of our universe.\n\nNow, as to stars collapsing. Yes indeed they do, that is part of the life cycle.\n\nStars are born in nebulae. Huge clouds of dust and gas collapse under gravitational forces, forming protostars. These young stars undergo further collapse, forming main sequence stars.\n\nStars expand as they grow old. As the core runs out of hydrogen and then helium, the core contacts and the outer layers expand, cool, and become less bright. This is a red giant or a red super giant (depending on the initial mass of the star). It will eventually collapse and explode. Its fate is determined by the original mass of the star; it will become either a black dwarf, neutron star, or black hole.\n\nOur own sun will become a black dwarf in a few billion years...\n\nOn a side note, the universe itself is not collapsing, never fear. It is expanding and getting larger all the time.\n\nI've added some links that have great diagrams of this fascinating topic below.
311448
Theoretically yes.  One type of supernova is due to a massive star ending it's life.  The star literally blows itself apart.  You need a star of about 8 times the mass of the sun for this to happen.  As such the sun won't have this form of supernova.\n\nHowever, the sun will end it's life as a white-dwarf.  As such it will drift through the galaxy and cool off for a long long time.  If at some time in the future the "dead" white dwarf sun runs into s sufficient source of mass it may be able to exceed 1.4 solar masses of matterial.\n\nWhen a white dwarf accumilates that much mass it will spontaniously undergo a rapid, and destructive fusion cycle that will blow the white dwarf completely apart.  This event is also a type of supernova.  Since the sun does not have a likely source of this extra mass, this fate is very unlikely, but since white dwarfs last for exceedingly long times it is possible (but unlikely) for this to happen.\n\nIt is an extreamly small chance though.
388947
ya every star has a time to explode but dont worry when the sun explodes they will be no earth.....
905154
I think if nothing unbelievable happens (EG: Mass nuclear war, a new deadly air-borne virus, etc) I think the world will end when the sun goes supernova. All stars (I think ) go supernova, basically imploding in on itself but releasing a massive amount of energy. The world will get toasted and even though this will supposedly happen thousands upon thousands of years ahead of today, I doubt technology will be so good as to prevent this.\n\nWikipedia says this isn't possible because the Sun is too small but some notable sources disagree. Well, I'll be long dead so I'm not too bothered.
685277
A black hole will only form for stars that have a mass greater than or equal to approximately 25x the mass of our sun.\n\nLet me back up a little.\n\nStars are basically a huge ball of gas that is burning at astronomically high temperatures.  The only thing holding this giant bomb together is its own gravity: it is so massive that it holds itself together.\n\nEventually, though, enough of the star has burned up so that its mass drops enough so that the explosive force of the nuclear reactions push it outward - this is a supernova.\n\nWhen stars are 25x more massive than our sun (or more), there is so much mass that all the mass collapses back in on itself, forming a black hole.\n\nA dying star will never collapse back into a black hole; that is the essential difference.
1047786
Yes, in a couple of billion years, the Sun will exhaust most of its hydrogen and enter the Red Giant Phase, its radius will be equal to that of the orbit of Mars. \n\nAstronomical calculations are proof.
1151473
No, because a black hole is a collapsed star, and the closest star to us, besides the sun, is thousands of light years away. They also suck in EVERYTHING including light and destroys it.