If three times the smaller of two consecutive integers is added to four times the larger, the result is 60.?
345220
Let x = first integer, then x+1 = second integer.\n(We use x and x+1 because consecutive integers always differ by one.)\nThree times the smaller means 3(x) = 3x\nThree times the smaller is added to four times the larger means add 4(x+1) to 3x\nThe result is 60 means to set it equal to 60.\n3x + 4(x+1) = 60\nDistribute the 4.\n3x + 4x + 4 = 60\nCombine 3x and 4x\n7x + 4 = 60\nSubtract 4 from each side.\n7x = 56 \nDivide both sides by 7\nx = 8\nThus, the integers are 8 and 9.
45380
its simple ... 80*70*60 ... 10*0 = 0 !!\n\nright isnt it ??? :D
400630
Answer : 64\n\nExplanation : \n2+3=5\n5+5=10\n10+7=17\n17+9=26\n26+11=37\n37+13=50\n50+15=65\n\nSo the next number in the line should be 65, not 64.
823097
Can't prove it as n cannot = + or -1 and k be an interger.\nIt appears to work with other odd integers. Change your question then it may be possible to prove it.
853291
4 is the answer. Here's how:\n4 appears after a break of two numbers, so the number that follows 40 must be 4
306730
well we know the 3 space must be even, in order to avoid the last space resulting in another 5\n\nhmmm... i'l work on it, provided you're working as well!\n\n..and #3 mustn't be 0, to avoid another 0\n..lol i'd have had it if i had been home...i made a program to do it, and then left before i finished/ran it lol\n\nbut that, is of course, the correct asnwer, 396*45=17820\n\nhaha thanx for the challenge!
136789
That's an extremely good question. \n\nThe answer is simple. Before that, i will explain what your question means to those who don't get. Well, it means that we must get 24 using 1,3,4 and 6 any number of times however involving operations +,-,* and / only once. \n\n  Then, the answer is very simple :\n\n  {[(6*6)/(3-1)]+[6]}  =  24\n\n---------------------------------------------------------\nWOKRING :\n\n {[(6*6)/(3-1)]+[6]}   =  {[(36)/(2)]+[6]}\n                       =  18 + 6\n                       =  24\n\n----------------------------------------------------------\n\nI hope you post more questions like these. They evoke a lot of thought. I hope the solution serves th purpose.
819558
Theres 7 choices for the first digit, 6 more for the second .. 2 for the sixth. So 7*6*5*4*3*2 = 5040.
1024279
34, 35, 36. 105/3=35. They are consecutive integers so subtract 1 and add 1.
925101
The number is 4(x+3), or 4x+12
205892
n! =n*n-1*n-2...until you get to zero.\n\nso 4! equals 4*3*2*1\nwhich is 24
684946
find whole (integer) number a,b, and c such that a^3+b^3=c^3.\nDon't remember the answer anymore,but it should be easy - all numbers were less that 10.
932821
adding 2x+3\n8x=24\ndividing by 8\nx=3
720986
answer is 9\n\n(3/4)*(x+1)-(1/2)*x=3\n\nx is the integer and x+1 is the next consecutive integer\nsolve the equation, you get x=9 and hence ans:9,10
433833
the answer to your question is x=3(4,6)
535646
I think you mean 36 not 38 since\n\n4 = 4*3^0\n12 = 4*3^1\n36 = 4*3^2\n108 = 4*3^3\n324 = 4*3^4\n\nSo, if that's the case, it's 324.\n\nUPDATE: Kemmy, 1^3+1 = 2, not 4.
678736
the sum of the two smallest numbers must be higher than the third one so your answer is d)