72 in. = _ cm and 7 L=_ qt.?
353885
162.88 cm.\n75.02 qt.
683260
A length of a single wire:\nL^2 = 72*72 + 54*54 (from a right triangle)\nso L = 90 ft\nFour sets of wires -> he needs 360 ft
841638
4.00751601 × 10^9 centimeters
826268
2l + 2w = 300\n2l = 300 - 2w\nl = 150 - w\n\nMaximize length times width:\n\nA(w) = w(150 - w) = 150w - w²\n\nTo maximize, take derivative, set = 0, and solve for w.\n\n150 - 2w = 0\n2w = 150\nw = 75\n\nand then l = 150 - 75 = 75.
908586
GB >= 0.6*(CS + GB)\n\n"cushion" variable U introduced : \n\nU >= 0 \nGB + U = 0.6 * (CS + GB)
907964
let l be the length and w be the width\n lw=111\n\nbut it has a margin so Area= (l-11cm)(w-4)\ndifferntiate\nbut we have 3 unknowns so we use the first ea lw=111\nl=111/w\n\nA=(111/w-11)(w-4)\n\ndA/dw= (111/w-11)+(w-4)(-111/w^2)=0\n\n111/w-444/w^2= 111/w-11\ncancel 111/w\n-444/w^2=-11\ncrossmultiply\nw^2=-444/-11\nw=6.4 cm\nl=111/6.4=17.3
761047
1m 73cm=173cm\n1in=2.54cm\n173cm/2.54cm/in=68.1in=5' 8.1"
1118220
Perimeter = 60 = 2L + 2w\nw = (60 - 2L)/2 = 30 - L\n\nArea = 216 = Lw\n216 = L (30-L)\n216 = 30L - L^2\nL^2 - 30L + 216 = 0\n(L + 6) (L - 36) = 0\nL = -6, 36\nLength cannot be negative\nTotal Length = 36\neach length = 36/2 = 18\n\n60 = 2(18) + 2w\n60-36 = 2w\n24= 2w\nw = 12\n\nTo check:\nA = LW\nA = (12)(18) =216\n\nSo, 12ft x 18 ft
1187393
SA = 2lw + 2lh + 2wh\n= 2(lw+lh+wh)\n= 2(8*6 + 8*2 + 6*2)\n= 2(48+16+12)\n= 2(76)\n= 152 centimeters squared
853272
Use this online converter\nhttp://www.kt.rim.or.jp/~tyamamot/pt.htm\n\nPut in size then choose unit as mm\nConversion standard is American Standards Association 1933\nNumerical format is "real"\nClick "CALC"\nThen scroll down to "results" & look for the result for the 1/72 inch point system\nCross check: 1pt  (1/72inch point system) = .35277777777777775mm....or 1mm = 2.8346456692913384 pt (1/72 inch point system)
810050
area = lxb = 600 or l=600/b\nperimeter = 2l + 2b\ncost = 2.4l + 2.4b +0.5b\n c= 1440/b + 2.9b\ndc/db = -1440/b^2 +2.9\nfor minima dc/db=0\nso b = 22.283\nto check minima d2c/db2 = 2880/b^3 greater than 0 so minima\nl/600/22.283 = 26.926\ncost is = 1440/22.283 + 2.9 x 22.283 = 129.24
1009332
Convert everything to inches, then multiply.  LxHxW.  They need to be the same units, though.
309380
5280 ft\n63360 in\n160934.4 cm
923548
x + 2x + x +2x = 72\n6x=72\nx=12\n\nTherefore the rectange is 12 by 24 units.
979599
L = length\nW = width\n\nLW = Area\n1) LW = 35\n\n2L + 2W = Perimeter\n2) 2L + 2W = 27\n\nSolve equation 1 for L and substitute into equation 2\n\nLW = 35\nL = 35/W\n\n2L + 2W = 27\n2(35/W) + 2W = 27\n70/W + 2W = 27\n70 + 2W^2 = 27W\n2W^2 - 27W + 70 = 0\n(2W - 7)(W - 10) = 0\nW = 7/2, 10\n\nL = 35/W\n\nIf W = 3.5, L = 10 and if W = 10, L = 3.5\n\nAssume L is longer than W: L = 10, W = 3.5
779325
1 Inch  = 2.54 centimeters\n\n- - - - - - - - - - - - - - - - - -\n\nFirst convert feet to inches\n\n12 x 6 = 72\n\n72 + 2 = 74 inches\n\n6 feet 2 inches = 74 inches\n\n- - - - - - - - - - - - - -\n\n2.54 x 74 = 187.96 cintimeters\n\nThe answer is: there are 187.96 cintimeters in 6' 2"\n\n- - - - - - - s-
96647
M(1000)CM(900)L(50)V(5)I(1)\nMCMLVI