What is Porter's five forces?
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Four forces -- the bargaining power of customers, the bargaining power of suppliers, the threat of new entrants, and the threat of substitute products -- combine with other variables to influence a fifth force, the level of competition in an industry. Each of these forces has several determinants:\n\nThe bargaining power of customers \nbuyer concentration to firm concentration ratio \nbargaining leverage \nbuyer volume \nbuyer switching costs relative to firm switching costs \nbuyer information availability \nability to backward integrate \navailability of existing substitute products \nbuyer price sensitivity \nprice of total purchase \nThe bargaining power of suppliers \nsupplier switching costs relative to firm switching costs \ndegree of differentiation of inputs \npresence of substitute inputs \nsupplier concentration to firm concentration ratio \nthreat of forward integration by suppliers relative to the threat of backward integration by firms \ncost of inputs relative to selling price of the product \nimportance of volume to supplier \nThe threat of new entrants \nthe existence of barriers to entry \neconomies of product differences \nbrand equity \nswitching costs \ncapital requirements \naccess to distribution \nabsolute cost advantages \nlearning curve advantages \nexpected retaliation \ngovernment policies \nThe threat of substitute products \nbuyer propensity to substitute \nrelative price performance of substitutes \nbuyer switching costs \nperceived level of product differentiation \nThe intensity of competitive rivalry \npower of buyers \npower of suppliers \nthreat of new entrants \nthreat of substitute products \nnumber of competitors \nrate of industry growth \nindustry overcapacity \nexit barriers \ndiversity of competitors \ninformational complexity and asymmetry \nbrand equity \nfixed cost allocation per value added
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Two\n\nWeigh ABC against DEF\n\nIf the balance tilts, take the lighter group and weigh one ball against a second one. If it tilts take the lighter ball, If it doesn't tilt, it must be the third ball of that group of 3 balls.\n\nIf ABC weigh the same as DEF, weigh G against H, take the lighter one if it tilts. take I if G and H weigh the same as one another.\n\nTwo weighings suffice.
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depends on the direction of the force
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gravitation, electromagnetic force, nuclear force
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We know of four types of fources, gravitational, electromagnetic, strong and weak forces. gravitational force will be there whereever massive bodies are present. If electrically charged bodies are present then electromagnetic force will also be there. Strong nuclear and weak forces are also likely to be there between subnuclear particles. So I guess all four forces will be present at the planets you mention.
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force = constant * distance\nF=kx\nforce = mass* acceleration\nF=ma\n\nx=F/k\nx=m*a/k = 4.0*9.8/800= about .05m, or 5cm
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The net force needed is zero.  Force is mass * acceleration, and acceleration suggests a change in velocity.  For constant speed and direction, the acceleration is zero, and hence the net force is zero.  When moving at constant velocity, the frictional and drag forces (which work to slow the car) and the drive force of the engine are exactly equal and opposite.  The net force is the sum of these two opposite forces, and hence the net force is Zero.
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1. potential\n2. kinetic\n3. it left at 0\n4. friction\n5. the greater the mass, the less  distance\n\nYour source of errors and improvements must come from your lab
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The net force is the volume of the balloon times the density difference between air and hydrogen (∆d) times g. From archimedes principle: the bouyant force is dair*V*g, the weight of hydrogen is dhyd*V*g, so the net force is the difference, or (dair - dhyd)*V*g =∆d*V*g.   The volume of the baloon is (4/3)πr^3.\n\nr = cuberoot[3*F/(4π * ∆d * g)]\n\nThis comes out 4.89 m
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The net force is F2 - F1 = 25 - 19 = 6N.\n\nFrom F = ma, a = F/m = 6/5 = 1.2 m/s^2, toward the west because F2 > F1.  Also, we're ignoring friction.
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first you must know that where are you use this information ? \nif calculate of force per leg is very important , you must make a static model which is include all dimensions et. and you can calculate forces  with use most useful static rules. \nexample rules \ntotal moment = always zero (every point)  \ntotal forces any direction (x,y,z) = always zero \netc. \n\nif solution not important you can accept 25 N per leg
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gravity, strong force, weak force, and electromagnetivity
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Newtons is the unit for measure of force
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The net force is zero.  Remember the equation F=MA:  force equals mass times acceleration.  If something is at rest, A is zero, so F must be zero.\n\nThe gravitational force on the brick is exactly balanced by the force of the table holding the brick up.  Net force is zero.
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Force - Newtons\nMass - Kilograms\nAcceleration - metres per second
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force=mass*acceleration\nforce/area=pressure (usually measured in p.s.i. [pounds per square inch])
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Flexibility, balance, agility, and force