what are the prime factors of 721?
352698
7 & 103\n\nYou can go here to find the prime factors for any number:\nhttp://www.acme.com/software/factor/
320622
The question relates to two things:  the first is to determine basically what numbers it takes multiplied together to create the final number in question.\n\nTo do this, you start with the prime numbers, i.e., numbers which are only divisible by 1 and themselves.  Several examples of these would be 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, and so on.\n\nTake 352, for example:\n352/2 = 176\n176/2 = 88\n88/2 = 44\n44/2 = 22\n22/2 = 11\nYou have exhausted the number 2.  Now move on to the next prime number by which 11 is divisible.  As 11 itself IS a prime number, the answer is 11.\n\nThe second part of the question relates to exponential form.  How many times did you divide 352 by 2 until you hit an odd number?  Five times.  So, the exponential expression of the prime factorization of 352 is 2 to the 5 (which is not posible to illustrate here.  Write the number 2 and then write a small 5 to the upper right,) * 11\n\n2(5) * 11 = 352\n\nNow take the other two numbers.  If you look at the list I provided above, you will note that 89 is a prime number.\n\n1 * 89 = 89\n\nFinally, take 156.\n\n156/2 = 78\n78/2 = 39\n39/3 = 13\n\n2(2) * 3 * 13 = 156\n\nHope this helps.\n\nPlease take time to pick the best answer.\n\nI tip the hat to the people who chose to use the "^" key.  I could not think of a way to describe it otherwise.  Their representation is probably more valid than my use of parentheses, which would actually represent something else altogether.  Note well though that I indicated how to write "two to the fifth power" in my paragraph above.
923846
Answer 1:\n59, 61 and 67 are all the primes between 55 and 70\n\nAnswer 2:\nThe Greatest Common Factor of 8 and 3 is 1. It can never be higher than 80. Even if it's the LCM you want, the answer is 24. Maybe you typed the 8 by mistake.\n\nAnswer 3:\nWhile searching for common multiples of two different primes, multiply the two and search for the product's multiple.\n7*5 = 35\nWe need a multiple of 35 between 150?\nOOps! What do you mean between 150?
728630
Prime factor each\n4 = 2 x 2\n7 = 7\n9 = 3 x 3\n\nTake union of all factors, removing duplicates (none here)\nAnswer = 2 x 2 x 3 x 3 x 7 = 252
815927
You just asked this, and I just answered it.  :)\n\nThe answer is 72.\n\nClick link to see this problem solved.
842132
71 is a prime number, so the only factors it has are 1 and 71.
1090956
25, if you're talking about whole, positive numbers.\n\nThey are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89 and 97.\n\nMany people debate whether or not 0 and 1 should also be considered prime.  0 is just weird and 1 is part of the definition of prime, so I don't think they really are prime, personally.
877331
The prime factorization of 90 is 2x3x3x5.  Each number must be a multiple of 3. One or both must have two threes in its prime factorization since the LCM has two threes in its PF; one or both must have a 5 and a 2 in its PF; and none can have more.  This leaves as possibilties:\n\none #: 3x3, 3x3x5, 3x3x2, 3x3x5x2 or 9, 45, 18, 90\n\nFor 9, 6 or 12 are 3 away but neither work.\nFor 45, 48 or 42 are 3 away but neither work.\nFor 18, 15 or 21 are 3 away.  21 doesn't work but 15 does.\n\nSo 15 and 18
804536
1 + 7 + 7(6) + 42(5) + 210(4) + 840(3) + 2520(2) + 5040(1) = 13,700
807869
the prime factorization can be figured out by repeatedly dividing the number by a prime number.\n for example 12\n 12 divided by 2 = 6,   6 divided by 2= 3,  3 divided by 3= 1\n the answer is 1.\ni hope this was helpful.
293052
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97\n\n101 is the next prime number ... \nso 24 prime numbers between 1 - 100
46670
Factor trees are the way to go. Start with any composite number on the top of the page. Then think of any two factors of that number, then draw two branches downward from the first number to the two factors you determined. Then if either of the two numbers you chose are composite, find two factors of that number and draw two branches downward to the next level of factors. Keep doing this until the final row of numbers you get is all prime. Any prime factors that are repeated can be expressed with exponents.\n\nFor example, take the number 90:\nTwo factors of 90 are 9 and 10 (you can choose others if you wish).\nDraw two branches down from 90 to 9 and 10.\nBoth 9 and 10 are composites, so find factors for each of those. Factors of 9 are 3 and 3; factors of 10 are 5 and 2. Now our last line of prime factors is 3 x 3 x 5 x 2 or 3^2 x 5 x 2 (using exponents). And, BAM, there's our answer!\n\nVery crudely, your factor tree should look something like this (drawn without the branches):\n\n  90\n 10 9\n5 2 3 3
679309
this is a quadratic equation. first subtract the 72 to h^2-6h-72, which factors out to (h+6)(h-12). This means that h must be -6 and +12
202585
I am the first to get it\n\n381 654 729\n\nthe proove\n\n38/2=17\n381/3=127\n3816/4=954\n38165/5=7633\n381654/6=63609\n3816547/7=545221\n38165472/8=4770684\n381654729/9=42406081\n\nand without any repetation
1096992
differences between consecutive primes\n\n3-2 = 1\n5-3 = 2\n7-5 = 2\n11-7= 4\n13-11 = 2\n17-13 = 4\n19-17 = 2\n23-19 = 4\netc.
823020
If you mean the common factors, there is only one and it's (1).\nThe factors of 49 are: 1,7,7, and 49\nThe factors of 94 are: 1,2,47, and 94\nThe factors of 48 are: 1,2,3,4,6,8,12,16,24, and 48\nThe factors of 68 are: 1,2,4,17,34, and 68
792528
Do a prime factorization of each number:\n\n18 = 2 x 3 x 3\n30 = 2 x 3 x 5\n42 = 2 x 3 x 7\n\nThe prime factors they have in common are a two (2) and a three (3).\n\n2 x 3 = 6\n\nGCF(18, 30, 42) = 6