what  is the perimeter of a  triangle which sides  measure 6,8, and 10 inches?
354025
the perimeter of a figure is the distance around the edge of the figure.  so in this case, the triangle is 6 in + 8 in + 10in = 24in.
609578
definitely 63 square inches. The formula to find the area of a triangle is A=(1/2) x base x height. That is 0.5 times base times height. So, if you plug in the numbers, you get\n0.5 x 14 x 9 square inches\n(0.5 x 14) x 9 square inches\n(7) x 9 square inches\n63 square inches\n\nMake sure that whenever you look for the area of the triangle, the problem tells you that the numbers are the height and base.\n\nYes, 24 is correct.
545831
You give two sides lengths, 10 , 15\nThe length of the other two sides are:\n15*(9/10)= 13.5 \n10 + 6.538348415 = 16.538348415
1068661
Perimeter of the triangle multiplied by the height of the prism.
442228
the side of a decagon is exactly (sqrt(5)-1)/2 times the radius of the external circe.\nIf your circle has a diameter of 6 foot (that is, your 6 foot lenght is the distance between two opposite vertexes), then calculate (sqrt(5)-1)*3/2 and you get the side of the decagon in feet.\n\nIf your value of 6 foot is the distance between two opposite sides (from the middle point of a side to the middle point of another side), then you have a apotheme of 3 feet. \n\nNow, the radius is 2/(sqrt(5)-1) times the side of the decagon = 1/(sqrt(5)-1) the half-side of the decagon.\n\nApplying the Pythagorean theorem you have that the square of the apotheme is worth ((1/(sqrt5 - 1))^2 - 1^2) times the half-side, that is \n\n9 ft = ((1/(sqrt5 - 1))^2 - 1^2)*(X/2)    (X = lenght of the side)\n\nthat is \n\n(X/2) = (9-(1-(5+1-2sqrt5))/(5+1-2sqrt5))\n\nthat is \n\n(X/2) = (9 - (2sqrt5 - 5)/(6-2sqrt5))\n\nX = 2*(54 - 18sqrt5 - 2sqrt5 + 5)/(6-2sqrt5)\n\nTHAT IS:\nX = (59 - 20sqrt5)/(3-sqrt5)  feet
753977
Do you mean the perimeter? To find the perimeter of a rectangle, you will have to add up the lengths of each side.\n\nFor example, a rectangle with sides that are 2 feet and 4 feet long would have a perimeter of 2 + 2 + 4 + 4 = 12 feet
558451
The are of a triangle can be found out by this formula...\nsquare root over s(s-a)(s-b)(s-c)\nwhere s=a+b+c&#92;2...\nWhere a, b and c are the sides..\nso i guess u can find the side and then find the perimeter..\nLolz...\nU calculate it urself
747405
15 inches\nThe side of a regular hexagon inscribed in a circle is the same as the radius of the circle. In fact, if you connect the center of the circle to each vertex of the hexagon (with a straight line segment), then you will have 6 equilateral triangles that all meet at the center of the circle.
937054
let \n\na = Opposite side\n\nb = adjacent side\n\n10 = hypotenuse\n\nsin30 = degrees\n\ncos30 = degrees\n\n- - - - - - - - - - - - - -\n\nSolving for the opposite side\n\nsinθ = a/10\n\nsin30 = a / 10\n\n10sin30 = 10(a/10)\n\n10sin30 = a\n\n10(.5) = a\n\n5 = a\n\nThe answer is a = 5\n\nThe opposite side  = 5\n\n- - - - - - - - - - - - - - - - - -\n\nSolving for the adjacent side\n\ncosθ = b/10\n\ncos30 = b/10\n\n10cos30 = 10(b/10)\n\n10cos30 = b\n\n10(0.866025404) = b\n\n8.660254038 = b\n\nThe answer is b = 8.66 rounded to two decimal places.\n\nThe adjacent side is 8.66\n\n- - - - - - - - - - - - - - - - - -\nThe perimeter is\n\n10 + 5 + 8,66 = 23.66\n\nThe perimeter is 23.66\n\n- - - - - -s-
688339
Let's say w is the width of the rectangle.  Then, the length will be w+5.  We know the perimeter is 58, and we know that the rectangle has two sides of length w, and two sides of length (w+5).  So...\n\n2w + 2(w+5)=58\n2w + 2w + 10 = 58\n4w + 10 = 58\n4w = 58 - 10\nw = (58-10)/4\nw=48/4\nw=12, the width of the rectangle.\n\nSince the length=w+5, the length is 17.
789618
a) 24 in.\n\nSince a square has four sides...  You must add six for each side (i.e. 6 + 6 + 6 + 6) to get perimeter.
509644
Formula of area 'A' of any regular 'n'-sided polygon of each side 'a' is\nA = 0.25*n*a^2*cot(pi/n)\n\nPut a=10 and n=6 in this formula.\nA = 0.25*6*10^2*cot(pi/6)\n  = 150*sqrt(3)   [since cot(pi/6) = sqrt(3)]\n  = 259.8 sq units
802049
The answer is (D).\n\nThe perimeter is 9x (just add up the 4 sides 2x+3x+3x+x to determine this) -- which eliminates (B) and (C) as a possible answer.\n\nThe area is 6x^2 -- which eliminates (A) as a possible answer, leaving only (D).\n\nLooks like you have a trapezoid, where the base is 2x, the sides are 3x each, and the top is x.  Draw straight lines down from your top to your base, so that your trapezoid is in 3 pieces:  a right triangle with base = x/2 and hypotenuse 3x, a rectangle x by 2x, and another right triangle with base = x/2 and hypotenuse 3x.  The area of the inner rectangle is 3x^2, and you can put the two triangles together to get another x by 2x rectangle for another 3x^2 area, or a total area of 6x^2.\n\nI hope that helped.\n\n~ ♥ ~
1184743
Heron's formula for triangles:\na = √s(s-a)(s-b)(s-c)\ns is the semiperimeter or 1/2 (4+4+4)\ns = 6\na = √6(2)(2)(2)\na = √3×2²×2²\na = 2×2×√3\na = 4×1.7\na = 6.8\n\n\nJose, you calculated the area of the right triangle, not the entire equilateral triangle you started with.
336458
the sides are 2 units (3-1=2) \nand the ends are 10 units. (6-(-4)=10)\n\narea = side times end = 2*10 = 20\nperimeter = 2 * side + 2 * end = 2*2 + 2*10=4+20=24
505748
If the perimeter is 36 and 1 side is 4, then you know by the rules of a rectangle that 2 of the sides are equal.  So if 2 sides are 4 each, that is a total of 8.  to find the length of the other two sides, you subtract 8 from the total perimeter 36 which gives you 28.  So the sum of the remaining two sides is 28 and by definition of a rectangle, they are equal.  So 28/2 is 14.  So 2 sides are 14 in length and 2 sides are 4 in length.  \n\nto find square footage, which is also the AREA of the rectangle, multiply LxW which is 14x4 which gives you 56.
1021808
Ok, you've got a good one here.\nFor a right triangle, height and base are the short sides; and area of the triange is (bh)/2. Since we know the area, and the length of the sides, we can plug it in to an equation, and find x. So...\nA = (bh)/2\n60 = ((5x)(3x-1))/2\n120 = (5x)(3x-1)\n120 = 15x^2 - 5x\n15x^2 - 5x -120 = 0\nDivide both sides by 5 to get\n3x^2 - x -24 = 0\nOk, there's a number of ways to do this, but the simplest way is to list the combinations of integers that will multiply to get -24 (the constant in the above equation). That gives us the combinations of (1, -24; 2, -12; 3, -8; 4, -6; 6, -4; 8, -3; 12, -2; and 24, -1). Now, we need to figure out the one combination that, when the second number is multiplied by three (the coefficient of x^2), you can add it to the first number to become (-1). It happens to be (8, -3) {-3*3=-9, -9+8 = -1}. There; you've factored the equation, leaving you with...\n(3x+8)(x-3)=0\nSince multiplication rules say that when ab=0, either a=0 or b=0, we can test by setting both numbers equal to zero; giving us...\n3x+8 = 0 ; x-3 = 0\nx = -8/3; x = 3\nSince x is an absolute length, and lengths can't be negative, we can disregard (-8/3) for now. That gives us x=3, and putting that back into the original lengths gives us sides of 15 and 8. To find the hypotenuse, we use Pythagorean Theorum: a^2 + b^2 = c^2, substituting in the known lengths gives us:\n15^2 + 8^2 = c^2\n225 + 64 = 289  = c^2\nc = √289 = 17\nSo, the hypotenuse of your triangle is 17.