what is the perimeter of a square if it has an area of 9cm squares?
338371
sqare root of 9=3\n\n3+3+3+3=12\n\n12 cm
802049
The answer is (D).\n\nThe perimeter is 9x (just add up the 4 sides 2x+3x+3x+x to determine this) -- which eliminates (B) and (C) as a possible answer.\n\nThe area is 6x^2 -- which eliminates (A) as a possible answer, leaving only (D).\n\nLooks like you have a trapezoid, where the base is 2x, the sides are 3x each, and the top is x.  Draw straight lines down from your top to your base, so that your trapezoid is in 3 pieces:  a right triangle with base = x/2 and hypotenuse 3x, a rectangle x by 2x, and another right triangle with base = x/2 and hypotenuse 3x.  The area of the inner rectangle is 3x^2, and you can put the two triangles together to get another x by 2x rectangle for another 3x^2 area, or a total area of 6x^2.\n\nI hope that helped.\n\n~ ♥ ~
915466
Let a and b the lengths of the sides of the rectangle (with a the side with the semi-circle).\nThe perimeter is 2b+a(pi/2+1)=16, and the area ab+pi/8*a^2. Substituting b in the area (from the perimeter equation), the area is 8a-a^2*(1/2+pi/8). \nSetting the derivative to 0, we have a=32/(4+pi). Then b comes from the perimeter constraint as b=8*(1-(2+pi)/(4+pi)).\nNumerically this gives a=4.48, b=2.24 and an area of 17.92
783536
let the length and width be 'x' and 'y' reply.\ngiven xy=512\nso x=512/y\nthe perimeter=2x+y\n=2x+512/x\nfor optimising\ndP/dx=0\n2-512/x^2=0\nmultiplying by x^2\n2x^2-512=0\n2x^2=512\ndividing by 2\nx^2=256\nx=rt256=16\ny=512/x=512/16=32\nso the dimensions for min perimeter\n=16'*32'\nperimeter=2x+y=64'\ncost=64*2=$128
865958
The perimeter is 8.32 Inches\n\nThe answer is 8.32 inch\n\n- - - - - - - s-
650879
Use string, paper, and a ruler.  The string can represent the perimeter, and you can draw a grid on the circle to represent the units of area.  Just don't get too in depth on the origins of pi.
794849
I am not sure if I understand your question correctly, or else your question is not complete.\nFor example, a usual question of this sort is to find the maximum area of a rectangle for a given perimeter, the classical fence problem, as follows:\n\nYou are given a specific length of fence L to make en enclosure of maximum area.  What would be the dimensions of the rectangle.\n\nHere we take the length of one side as x, then the other side will be (L-2x)/2.  The area is thus A(x)=x(L-2x)/2.\n\nTo obtain the value of x for a maximum area, we differentiate A with respect to x, \ndA(x)/dx = d(Lx/2-x^2)=L/2-2x\nfor maximum area, dA(x)/dx=0, so we equate\nL/2-2x=0\nand solving for x gives x=L/4.\n\nThat means that the maximum area rectangle for a given perimeter is a square!\n\nHope that helps with your project.\nPost if you need other information, but please post details, especially how far you are with your project, so we can help you better.
6731
Area & Perimeter of Parallelogram\n\nA Parallelogram is a four-sided quandrilateral with both pairs of opposite sides parrallel.\nA area of parallelogram is calculated using the following formula:\n\nA=(base)*(height)=bh\n\nThe perimeter of a parallelogram is calculated using the following formula:\n\nP=2a+2b               (3-4)\n\nThe area of a parallelogram is always expressed in square units, and the perimeter of a parallelogram is always expressed in the original units.\n\nExample:\n\nCalculate the area and perimeter of a parallelogram with base (b) = 4', height (h) = 3', a = 5' and b = 4'. Be sure to include units in your answer.\n\nSolution:\nA= bh \nA=(4)(3)\nA=12 square feet \n\nP= 2a+2b\nP=2(5)+2(4)\nP=10+8\nP=18 feet
38016
Let No of square is N\nPerimeter = 2xN + 2 \n\nAssumptions:\nThey are arranged in a row.\nThey are of same size.\nThey are of UNIT size.
897796
Let L be the length\nLet W be the width\nWe know the perimeter is:\n2(L + W) = 300\nSolving for L:\nL + W = 150\nL = 150 - W\n\nNow write a formula for the area:\nArea = L * W\nArea = (150 - W) * W\nArea = -W² + 150W\n\nYou can see this is the formula for a parabola.  I'll simplify things by expressing it in terms of x:\nf(x) = -x² + 150x\n\nBut it isn't in vertex form:\nf(x) = a(x - h) + k\n\nTo get it in that form, first pull out the -1 to get x²:\nf(x) = -1(x² - 150x)\n\nNow take the coefficient on the x term (-150), take half of it (-75) and square it (5625). Add and subtract this:\nf(x) = -1(x² - 150x + 5625 - 5625)\nNow you can write this as a square:\nf(x) = -1[ (x - 75)(x - 75) - 5625)\nSimplify:\nf(x) = -1(x - 75)² + 5625\n\nYou have a downward facing parabola, with a maximum vertex at the point (h, k) or (75, 5625)\n\nSo the maximum is when the width is 75. When you solve for length you get that the length is also 75. So the maximum area for the patio is a square with sides of length 75 feet.  The total area will be 5,625 sq. feet, a maximum.
753977
Do you mean the perimeter? To find the perimeter of a rectangle, you will have to add up the lengths of each side.\n\nFor example, a rectangle with sides that are 2 feet and 4 feet long would have a perimeter of 2 + 2 + 4 + 4 = 12 feet
114649
Here's an idea.  Show them something that's pretty much flat and rectangular, such as piece of stiff carpet or a pad of paper.  Write on the board what the perimeter, area, and volume are.  Have them measure it with a tape measure and come up with the answers that you have.  They'll see that they just have to add for the perimeter but multiply for the area and volume.
860533
long sides are 24ft and short sides are 9ft.\n\nArea = width x lenth\n216 = 24 x 9\n\nDimensions 24+24+9+9 = 66
74729
The formula for the area of a circle is:\nPi*r^2/2\nto translate, "one half of Pi times the suare of the radius"\n\nSo, if you have a 3 cm radius:\n(3 cm)(3 cm) = 9 cm^2\n\nthen divide by two:\n9 cm^2 /2 = 4.5 cm^2\n\nthen multiply by Pi:\n\n4.5(Pi) cm^2\n\nIf you want a decimal number, you can use an estimation of Pi, something like 3.1415, but it's not exact since Pi is an irrational number (a non-ending and non-repeating decimal)
71096
let area be A\nwidth be W\nlength be L\nnow area of rectangle is = length * breadth \n    A = L * B\n  L = A/B\n L = 3x (squared) +14x+8 / x+4\n   = (3x+2)(x+4) / (x+4)\n   = 3x+2
283369
The perimeter of the square is 50 units\n\nThere are 5 rectangles that means the ratio of length to width has to be 5 to 1\nTherefore since each rectangle has a 5 to 1 ratio and a perimeter of 30 they are all 12.5 units by 2.5 units. (12.5 x 2 is 25, 2.5 x 2 is 5, 25 + 5 = 30)\nThe length of each side of the square is 12.5. 12.5 x 4 is 50 units
505748
If the perimeter is 36 and 1 side is 4, then you know by the rules of a rectangle that 2 of the sides are equal.  So if 2 sides are 4 each, that is a total of 8.  to find the length of the other two sides, you subtract 8 from the total perimeter 36 which gives you 28.  So the sum of the remaining two sides is 28 and by definition of a rectangle, they are equal.  So 28/2 is 14.  So 2 sides are 14 in length and 2 sides are 4 in length.  \n\nto find square footage, which is also the AREA of the rectangle, multiply LxW which is 14x4 which gives you 56.