Is this a polynomial in x? X^pi +3X^2+2X+1?
342135
Ill try this. Yes. Its a poly because its in 4 terms. Example\nx^4+3x^3+7x^2-x+2 you could solve (i think) using the P/Q form.
904672
let u = x^2 + 1, then you have du = 2xdx, => dx = 1/2x du,\n\nsubstitute back you are on the way  to solve it
865971
p(x)=-3x^2 (x-1) (x+1/3) (x+2)^3\n\n1) what are the roots and multiplicities? \nroots - multiplicity\n0 .............2\n1..............1\n-1/3 .........1\n-2 ............3\nbasically the multiplicity of a root A is the exponent of the factor (x-A)\n.
703053
so the Q is basically asking for two binomials which, if multiplied will end up as a polinomial...\nAs a matter of fact any two binomials can form a polynomial.\n(2X+3) (x-7)...this is an e.g.
26326
A procedure for finding the quadratic factors for the complex conjugate roots  of a polynomial P(x) with real coefficients.\n\n[x-(a+ib)][x-(a-ib)]=\nx^2+2ax+(a^2+b^2)=\nx^2+Bx+C.
219026
x^3+4x+1\n\n(3x^4+2x^3+12x^2+11x+2)=\n=(3x+2)*(x^3+4x+1)
931584
Is parabola(rational funtion) a polynomial?\n\nok, you know that a parabola is not a rational function. a parabola is the graph of a quadratic function that looks like:\n\nf(x) = y = ax^2 + bx + c. \n\na polynomial is a sum of finite monomials in which coefficients of terms are real numbers and exponents of variables are whole numbers.\n\nthus, a quadratic is a polynomial.\n============================================\n\n\nnow, is hyperbola a polynomial?\n\nwhat does a hyperbolic function look like?\n\n(x-h)^2/a^2 - (y-k)^2/b^2 = 1\n\nif you solve for y, we do not have a polynomial.
562954
You simply divide each term in the polynomial by that integer.. For your example here it goes..\n\n(3x^2+8x-2) divided by 2 \n\n> {3(x^2)/2} + {8x/2} - {2/2}\n\n>> Answer: 1.5 x^2 + 4x -1    or   (3/2)x^2 + 4x -1
201685
If y is a root of this and b is in F_p, then (y+b)^p -(y+b)=y^p +b^p -y-b=a, so y+b is another root. Hence the complete list of roots is y, y+1, ....y+p-1.\n\nThus we have two cases, the first where the polynomial splits in F_p (a=0) and the other where we get a degree p extension, so F_(p^2).\n\nNotice that we are using the algebra student's dream (x+y)^p=x^p +y^p which is justified because we are working over a field of characteristic p.
853619
There is a theorem related to polynomial divisions called the remainder theorem. Let p(x) be a polynomial of any degree. When it is divided by a linear polynomial of the form x - a, the remainder is p(a).\nAnswer 1:\nLet p(x) = x^5 - 3x^3 + x^2 - 3\nDivisor = x - 2\nHere, a = 2\np(2) = 2^5 - 3(2)^3 + 2^2 - 3\n= 32 - 24 + 4 - 3\n= 32 - 24 + 1\n= 8 + 1   \n= 9\n\nAnswer 2:\np(x) = x^5 - 3x^3 + x^2 - 3\nDivisor = x + 1\na = -1\np(-1) = (-1)^5 -3(-1)^3 + (-1)^2 - 3\n= -1 + 3 + 1 - 3\n= 0\n\nYou can check with actual division if you like. Looks like some of us have it wrong.
593998
When you have a polynomial, the coefficients are integers.  For example:\n\nax^2 + bx + c = 0\n\nThis is the general formula for a second degree polynomial (x is to the 2, hence second degree).  In this case, a, b, and c are the integers.\n\nAlso, if you add other terms, such as x^3, they would also be multiplied by integers.
695176
6x^2-3x-4x+2\n3x(2x-1)-2(2x-1)\n(2x-1)(3x-2)
913484
are you talking about a polynomial :\na + bx +cx^2 + dx^3 +...\n\nbecause those a,b,c,d... do not appear any where on the graph... you have to look at the intercepts and the extreama, and the inflection points to get any good idea about the shape of the graph
902478
wow its been a long time.. i use a calculator to do that now.. but here goes one thing i remember...\n\nlets say we have a polynomial like this\n\nx^2 -3x-10  and we need to factor it..\n\nwe take a look at what factors of -10 we could use that would add up to -3  in this case there are two way to get -10 (-2*5) or (2*-5)  if we add the two sets together one gives us -3 and the other gives us 3 so we can throw out the -2*5 terms.\n\nSo now we lay out the factors.... we need two x's to get x^2 so we need two x's in the first terms (remember FOIL?)\n\nlay the terms out so they give us the correct values\n\n(x+2)(x-5)  now we can use FOIL (firs, outer, inner, last) to check ourselves...\nX*X = x^2\nX*-5 = -5X\n2*x =2x\n2*-5=-10\n\nso we get [x^2] +[-5x] +[2x] +[-10]\nor x^2 -5x+2x-10\ncombine like terms now\n-5x+2x =-3x\n\nwhich gives us\nx^2-3x-10\n\nhope that helps
774014
2^3+2*2^2-3(2)-10=8+8- 6 -10 =0\nTherefore x-2 is a factor of the given polynomial
783870
7x^2+16x over (x-2)(x+2)(x+3)
879052
x^2 - 8x + 16\n\n\nthe person above me said it is -x^2 but that is incorrect because -x * -x = x^2