Which one of the following chemical equations is balanced?
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The answer is C.\n\nIn order for the equation to be balanced, you have to make sure there are the same number of each element on both sides of the equation.\n\nIn answer C, the number of each element is equal on both sides. \n\nIn answer A, the number of Sodium (Na) and Hydrogen (H) atoms are not equal on both sides of the equation.\n\nIn answer B, the number of Nitrogen (N) and Hydrogen atoms are not equal on both sides of the equation.\n\nIn answer D, the number of Sodium atoms is equal, but there is one more Sulfur (S) atom on the product (right) side of the equation.
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Sodion Hypochlorite and Sodium Thiosulfate?  Ive never heard of Na2(s2o3)2?!  Anyways heres the balanced equation:\n\n2NaOCl + Na2S2O3 ---> Na2S2O3 + 2NaOCl\n\nPretty straight forward I guess.  Double Replacement reaction.
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Acid + base = salt + water.\n\nUnbalanced eqn is: Al(OH)3 + H2CO3 --> Al2(CO3)3 + H2O
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This is very simple\n\nCa+H2O -> Ca(OH)2 + H2\n\nThe reactant has\n1 atom of Ca\n1 atom of H\n2 atoms of O\n\nThe product has\n1 atom of Ca, ok\n2 atoms of H\n2 atoms of O\n\nJust put a coefficient of 2 in the water (H2O)\n\nSo the chem. eqn becomes\n\nCa+2 H2O -> Ca(OH)2 + H2\n\nThat's it.\nThe equation is already balance
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Just remember glucose (C6H12O6). Then using the basics of balancing any chemical equation you can figure out the rest of it.
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What do you want a step by step set of instructions or a balanced equation?\n\n2C6H5OH + NaOCL = 2C6H50 + NaCl + H2O
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the balanced reaction\nC12H22O11 + 12 O2 ---> 12 CO2 + 11 H2O\nso the right answer are:\nc. \nand\ne.
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To understand balancing chemical equations better, it helps to know what it is called. It is called "stoichiometry". Just a quick web search and I found a TON of very accessible web sites on balancing chemical equations. I put a couple of them below. \n\nIt should be noted that in mathematics, there is a very easy way to solve stoichiometry equations, or do chemical balancing. It is much easier than what chemists are usually taught. To look at the mathematical version of the same problem, look for web sites and books on linear algebra. The first linear algebra web site listed below is a simple introduction, but I also included a few links to free books in linear algebra which is probably more detail than you want.\n\nHere is an easy way to start thinking about it, however. It is all about counting how many atoms of each type are on the left side of the equation, and how many are on the right side. You want to adjust the numbers in front of the molecules so that there are as many atoms of each type on the right side as there is on the left side. \n\nSuppose you are considering the burning of carbon C in oxygen O2 to make carbon monoxide, CO. \n\nThere are j C atoms and k O2 molecules that combine to make m CO molecules \n\nSo jC + k O2 ----> m CO\n\nIt is up to you to pick j, k and m so that \n\nthere are the same number of C and O atoms on both sides.\n\nIf m=2, and k=1 and j=2, then \n\n2C+O2----->2CO \n\nand you see there are 2 C atoms on each side, and 2 O atoms on each side, and you are done.\n\nOf course it gets much more complicated than this. That is addressed in the references below.
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balanced is the best answer, although constant would be correct as well....or if you're looking for a numerical answer, it would be 0
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This is an acid base reaction, but the other answer is incorrect about the product. There is no Cl present. Here’s the balanced equation:\n\n2NaOH (s) + H2CO3 (aq) ➔ Na2CO3 + 2H2O\n\nNaOH is the base. H2CO3 is the acid.
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Here are the formulas:\n\nAluminum Hydroxide = Al(OH)_3\nSulfuric Acid = H_2SO_4\nWater = H_2O\nAluminum Sulfate = Al_2(SO_4)_3\n\nThe correct balanced equation is:\n\n2[Al(OH)_3] + 3[H_2SO_4] + → Al2(SO_4)_3 + 6[H_2O]
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Equations are balanced- Hence the equal sign.  More information or a specific equation.
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Providing that the H3C6H5O7 is citric acid, that balanced equation is:\n\nH3C6H5O7 (s) + 3 NaOH (aq) --> Na3C6H5O7 (aq) + 3 H2O (l)\n\nThe net ionic equation is:\n\n3 H+ (aq) + 3 (OH-) (aq) --> 3 H2O (l)
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It should be Fe2+ + 2OH- --> Fe(OH)2 since you not only need to balance the elements but you also need to balance the charges.
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The equation is meant to record the results of an experiment.  The reactants (stuff you started with) are written to the left and the products (the stuff you end up with) is written to the right.\nTo balance an equation, only the coefficients (the numbers in front of the chemicals) may be changed.\nIf you change the symbols, you change the type of atoms used.\nIf you change the formulas or subscripts, you change the chemicals (the molecules) used in the experiment.
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The equilibrium constant of any equation is [C]^c[D]^d/[A]^a[B]^b.\n\nthe equation is already balanced. But you have to know how many moles of each element there are in order to compute the problem
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Within each half-reaction, the charge on each side must be balanced, as well as the number of each element.\n\nFor the overall oxidation-reduction reaction, the charge on each side must be the same, as well as the number of each element, and no free electrons should be in the equation.