Please Help Me with the following Math problem?
345803
D is # of dimes (each worth 10 cents)\nQ is # of quarters (worth 25 cents)\n\n10D + 25Q = 255 (equation about value)\n\nD = Q + 8 (equation about number of each coin)\n\nSubstitute Q + 8 for D in the first equation and solve for Q. Use that answer to solve for D.
780025
x ≤ 5\n\n-- - - - - - -s-
957682
half it then times it by 2! that will give u the answer
646947
1. A & B cross  -  2\n2. A returns    -  1\n3. C & D cross  -  10\n4. B returns    -  2\n5. A & B cross  -  2\n\nTotal minutes: 17\n:)
1102373
i wont answer.... log onto www.mathguru.com and discover solutions with explanations.
750664
Let,the number be x\nkTherefore according to the problem\n10-2x=x+3\n=>-2x-x=3-10\n=>-3x=-7\nx=-7/-3=7/3=2 1/3\nTherefore the number is 2 1/3
1132233
this question will require calcs using logarithm.\nhence will take time
898860
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
912865
bring the a's to one side... u then get 9a = 27 ... divide and answer is a = 3
154380
I posted these sources earlier to someone else who was looking for math help.\n\nGood Luck!!
208376
6+8+10=24 ........................................................................
113980
Use a calculator - numerator divided by denominator will give you the answer.
840649
1.\nn | n + 20\n------------\n0 | 20\n1 | 21\n2 | 22\n3 | 23\n4 | 24\n\nn | 3n - 35\n-------------\n1 | -32 \n2 | -29 \n3 | -26 \n4 | -23
1074417
The answer is 10. \n\nIf you don't believe me, do the problem yourself and compare that with my answer.
813994
the first one is (x+10)(x+8)\nand the second one is your second answer
821450
go to a math website off yahoo. it should help.