g*g-8g-36 factor trinomial?
346867
it doesn't factor out...are you sure you typed it correctly?\n\nif it is correct, then use the quadratic formula to get the answer...but its pretty complicated (negative b plus or minus the square root of b squared minus 4ac)...
1079532
2xy^2(3y^2)^(1/3)\n\ndivide the exponents by three, leave the remainder in the root.\nfind the lowest cubic factor in 24 (8=2^3) and take it out, leave the 3 in.
1099108
I think its 8a^4b^3+6a^3b^5-2a^3b^4
945958
(2n-1) * (2n-2) * (2n-3) * (2n-4)... * 3 * 2 * 1\n\nJust like any other factorial.
889891
~..-8,-6,-4,-2,0,2,4,6,8
792528
Do a prime factorization of each number:\n\n18 = 2 x 3 x 3\n30 = 2 x 3 x 5\n42 = 2 x 3 x 7\n\nThe prime factors they have in common are a two (2) and a three (3).\n\n2 x 3 = 6\n\nGCF(18, 30, 42) = 6
25946
=3fg*(f^2g)+3fg*5f-3fg*4\n=3(f^(1+2g))*g+15(f^2)g-12fg
766790
1. 5m^2 - 15mp - 2mr - 6pr <-- Impossible to factor by grouping. It needs to be either, exactly one of the signs needs to be reversed.\n\n2. 6-3x-2y+xy\n(6 - 3x) - (2y - xy)\n3(2 - x) - y(2 - x)\n(3 - y)(2 - x)
68296
To find the greatest common FACTOR, here is an example:\n\nFind the GCF of 36 and 54.\n\n    The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36.\n\n    The factors of 54 are 1, 2, 3, 6, 9, 18, 27, and 54.\n\n    The common factors of 36 and 54 are 1, 2, 3, 6, 9, 18\n\nAlthough the numbers in bold are all common factors of both 36 and 54, 18 is the greatest common factor.\n\nThe second method for finding the greatest common factor is to list the prime factors, then multiply the common prime factors. \n\n**************************************\nTo find the least common denominator:\n**************************************\n\nTo find the least common denominator, simply  list the multiples of each denominator (multiply by 2, 3, 4, etc.) then look for the  smallest number that appears in each list.\n\n    Example: Suppose we wanted to add 1/5 + 1/6 + 1/15. We would find the least common denominator as follows...\n\n        *\n\n          First we list the multiples of each denominator. \n\n        Multiples of 5 are 10, 15, 20, 25, 30, 35, 40,...\n\n        Multiples of 6 are 12, 18, 24, 30, 36, 42, 48,...\n\n        Multiples of 15 are 30, 45, 60, 75, 90,.... \n\n        *\n\n          Now, when you look at the list of multiples, you can see that 30 is the smallest number that appears in each list.\n\n        *\n\n          Therefore, the least common denominator of 1/5, 1/6 and 1/15 is 30.\n\nThis method works pretty good. But, adding fractions with larger numbers in the denominators it can get pretty messy.\n\nSo hold that thought for a moment, as we look at another way to find a least common denominator for adding these same fractions.
382213
A perfect square trinomial is in the form\nm² + 2am + a²\n\nSince you know 2a is -8, a must be -4\nSince n = a², n = (-4)² = 16
1002101
factor 9x^2y^2-9y^2\n9y^2(x^2-1)\n9y^2(x+1)(x-1)
1070097
(x+3) (5x-3) (7x-1)\n\nYou can do this manually by figuring out the factors of 35 and 9.\n\nFor 35:  {1, 5, 7, 35, -1, -5, -7, -35)\nFor 9: {1, 3, 9, -1, -3, -9)\n\nI started assuming that (x + n) would be a factor.  I tried (x + 1), (x - 1), then (x + 3).\n\nIf you do long division, you get:\n(x + 3) ( 35x^2 - 26x^2 + 3)\n\nThen you just repeat the process for ( 35x^2 - 26x^2 + 3)... you need factors of 35 and factors of 3 that will add up to -26.  \n-3 x 7 = -21 and -1 x 5 = -5, so (5x - 3)(7x - 1) works.\n\nThat gives the final answer of: \n(x+3) (5x-3) (7x-1)
483173
((6p - 18)/(9p)) / ((3p - 9)/(p^2 + 2p))\n((6(p - 3))/3(3p)) / ((3(p - 3))/(p(p + 2)))\n((2(p - 3))/(3p)) / ((3(p - 3))/(p(p + 2)))\n((2(p - 3))/(3p)) * ((p(p + 2))/(3(p - 3))\n(2p(p - 3)(p + 2))/((9p)(p - 3))\n(2p(p + 2))/(9p)\n(2(p + 2))/9\n(2p + 4)/9
457089
G=uys\nF=***\nE=verthing
930308
x=[2+/-rt(4+60)]/2\n=[2+/-8]/2\n=-3 or 5\nso the factors are\n(x+3)(x-5)
677061
i think this formula works.\nfactorial of A-4A\nso.using this formula the correct answer is 5012
408031
First, factor the polynomial using the Rational Roots Theorem. All possible factors of -36 are (+or-) 1, 2, 3, 4, 6, 9, 12, 18, 36.  Use synthetic division for each, until you find one root.  In my solution I got x - 4 as a root and the other x^3 + x^2 + 9x + 9.  Continue with the factoring.  Here I got x + 1 as a factor and the other x² + 9. Therefore, the factorization is:\nP(x) = (x - 4)(x + 1)(x² + 9)\n\nThe zeroes are all the roots when P(x) = 0\nTherefore,\n(x - 4)(x + 1)(x² + 9) = 0\nx = 4\nx = -1\nx² = -9 or \nx = 3i or -3i\n\n^_^