what are the formulas of finding the areas of 1. Right triangles 2. parallelograms 3. trapezoids  Thanks a ton
350617
Actually trapezoids are Bottom Edge + Top Edge X Height /2.  Or:\n\nH(B+T)\n------\n  2
422511
if u kno the base and height.. then area= (base x height)/2\n\nif the triangle is scalar,\nthen :\n\nfirst find s, using hero's formula\n\ns= (a+b+c)/2   .... where a,b,c are the sides of triangle.\n\nthen , area = squareroot(s x (s-a) x (s-b) x (s-c)
87971
The area of a parallelogram is area = base x height. Now, drawing a diagonal of the parallelogram splits the shape into two congruent triangles. Therefore, each triangle will have an area equal to (1/2)base x height.\n\nThis is true for any triangle; that is, any triangle has a corresponding parallelogram associated with it, which can be cut in half.
440894
go to this website and try to understand how to get the area of the shade region \n\nhttp://www.algebralab.org/lessons/lesson.aspx?file=Geometry_AreaPerCricle.xml\n\ngood luck
464335
I normally hate referring people to wikipedia articles, since it is so often inaccurate, but this one is quite good (link is below).  If you scroll down, there is a table that gives just what you're looking for.\n\n2x2 grid: 288 possible solutions\n3x3 grid: 6.7*10^21 possible solutions!
609578
definitely 63 square inches. The formula to find the area of a triangle is A=(1/2) x base x height. That is 0.5 times base times height. So, if you plug in the numbers, you get\n0.5 x 14 x 9 square inches\n(0.5 x 14) x 9 square inches\n(7) x 9 square inches\n63 square inches\n\nMake sure that whenever you look for the area of the triangle, the problem tells you that the numbers are the height and base.\n\nYes, 24 is correct.
276388
If an object is a parallelogram, we define its area to be its length multiplied by its height. Rectangles and squares are common parallelograms.\nIf you cut a parallelogram in half along its diagonal, you get a triangle with the same width and height, but half the area. Thus the formula for the area of a triangle is (1/2)*base*height where the name "base" has replaced the now meaningless label of "length".\nUsing these two formulas, you should be able to find the area of any polygon (a closed shape with straight sides) by cutting it up into these shapes of known area. For example, a trapezoid can be cut up into a rectangle and two triangles.\nThe perimeter of a polygon is the easiest measure. Just add up the lengths of all the sides.
117539
A trapezoid has 4 sides but you talk about 12 and 16 bases - I assume you mean 12 and 16-sided polygons. The question can be answered, as stated, if we assume that the sides of each polygon are the same length - if the sides are not the same length then the question can't be answered until you tell us the lengths of the sides. Polygons with sides that are the same length are called "regular polygons."\n\nAnswer:\n\n1) The area of a 12-sided regular polygon inscribed within a circle with a radius of 1 is 3\n\n2) The area of a 16-sided regular polygon inscribed within a circle with a radius of 1 is 3.0614674589207183
348844
It sounds to me like you are talking about a trapezoid. Go to the website I have listed under my sources and see if what you are describing looks like the trapezoid on there. If it is a trapezoid, the area formula is  Area = 1/2h(b1 + b2). h=height, b1=base 1, b2=base 2
802049
The answer is (D).\n\nThe perimeter is 9x (just add up the 4 sides 2x+3x+3x+x to determine this) -- which eliminates (B) and (C) as a possible answer.\n\nThe area is 6x^2 -- which eliminates (A) as a possible answer, leaving only (D).\n\nLooks like you have a trapezoid, where the base is 2x, the sides are 3x each, and the top is x.  Draw straight lines down from your top to your base, so that your trapezoid is in 3 pieces:  a right triangle with base = x/2 and hypotenuse 3x, a rectangle x by 2x, and another right triangle with base = x/2 and hypotenuse 3x.  The area of the inner rectangle is 3x^2, and you can put the two triangles together to get another x by 2x rectangle for another 3x^2 area, or a total area of 6x^2.\n\nI hope that helped.\n\n~ ♥ ~
809433
1.rectangle\n\n2.trapezoid
890633
1. total area of a box of sides a,b,c is 2(ab+bc+ca)\na=4,b=3,c=6 => surface area = 108 sq.ft\n..\n2.Lateral area = pi*radius*slant ht\npi=3.1415,radius=2m(4m/2), slant ht=15m\nans is 188.49sq.metres\n..\n3.   volume of pyramid = (1/3)* height * base area\n= (1/3)* (6) * (6*6)\n= 72 cu.metre\n..\n4. lateral area of cylinder = 2*pi* radius* height\n=2*3.1415*12*60\n=4523.76cu. mm\n..\n5. total surface area = outer surface + inner surface + top surface + bottom surface\n= 2*pi*8*height + 2*pi*5*height + 2 times ( pi*(8-5)^2)\n[the last term is the sum of top and bottom surfaces which are circular rings]\nheight is not given :(
991928
Assuming you mean a regular hexagon, then with the 30-60-90 relationship, you should get that half the length of a side is 2.\n\nSo, the area of that yellow triangle in the link below is\n.5 * 2 * 2 * sqrt(3) = 2 * sqrt(3)\n\nThere are 12 triangles, so the area is 24 * sqrt (3).
324878
I'm assuming you are asking for a formula to calculate the area when you just know the base (x) and not the height.  But, you need to know the height, even if the triangle is a right triangle.  To see this, imagine you had a right triangle standing on it's shortest side.  That shortest side would be your base, x.  Now stretch the triangle taller and taller.  The base length still stays the same, but the area inside the triangle grows and grows.  (And the triangle is still a right triange.) So, unless you know the height, you can't know the area.\n\nNow, what I'm guessing, is that your triangle might actually be not only a right triangle, but an isosceles triangle too, meaning that 2 of the sides are the same length.  And because it's a right triangle too, that means the two shorter sides (that connect at the right angle) are the same length.  So, your base and your height are the same length.\n\nIf this is true...\n\nlet x = length of base\nsince triangle is isosceles and right, height also = x\n\nSo the traditional formula becomes:\n1/2 BH = 1/2 x*x\n(sorry, can't figure out how to write "x squared" right now)\n\nHope that helps...
583176
A trapezoid is a 4-sided figure with one pair of parallel sides. To find the area of a trapezoid, take the sum of its bases, multiply the sum by the height of the trapezoid, and then divide the result by 2.
326809
The area of a trapezoid is the height times the average of the bases, or h*(b1+b2)/2.  In your case, your bases are the top and bottom of your figure (parallel to the x-axis), and your height is along the y-axis.  So,\n\nh = a\nb1 = c\nb2 = b\n\nA = a(b+c)/2
893599
You may want to be more specific on this one... are you trying to find the largest possible area? You can inscribe lots of different trapezoids in a circle. \n\nAnd which theta are we talking about? The angle that the base makes with the circle?\n\nTry that one again,\n\nUMRmathmajor