I have x beans.I eat 1/3 of them. she ate some until 1/5 of the original # of beans remains. fraction she ate?
353312
ok so if you use fractions, the number of beans you start off with is x and if you multiply it by 3/3, you get 3x/3. so now, you ate 1/3 of them so you ate x/3 beans altogether, which means you have (3x-x)/3  = 2x/3 beans left over.\nso now you want to know how much your friend ate if only x/5 beans remain. so first you have to get a common denominator (15), so \n(2x/3 * 5/5) - sometin = (x/5 * 3/3)\n10x/15 - somethin = 3x/15. \nto find the somethin, you can do (10x-3x)/15 = 7x/15.\nso she ate 7/15 of the beans.
887154
You start from the end and work backward.  If Dad ate half the cookies and left two, he must have eaten two so when he got there there were 4.  Ashley had just eaten 1/3 of the cookies, so she had left 2/3 in the jar.  Well, four is two/thirds of six so when she got there there were six cookies.  Charles had eaten 1/4 meaning he had left 3/4 of the cookies.  Well, 6 is 3/4 of 8 so originally there were 8 cookies in the jar.  Good luck, hope that helped.
824389
Say he ate x cookies on the first day. Then he ate x+6 on the second day and x+12 on the third day, etc..\nso:\n\nx+(x+6)+(x+12)+(x+18)+(x+24)= 100\n5x+60=100\n5x=40\nx=8\n\nso he ate 8 on the first day.
279807
A lot depends upon how hungry you are when you start putting them in (in my case it is usually zero) :)\n\nIf it is a serious question and you can't afford to buy enough jellybeans to test it out, then buy a small bag, empty them into a small straight glass, so that the glass is full, and slowly pour some sugar into the glass until the gaps are filled up (gently tap the glass to make the sugar settle).\n\nEmpty all the jellybeans out and put the sugar back into the glass, measure how high the sugar is (ie. 1 inch) put the sugar back in the bag.\n\nNow fill the glass up with water, but less the height you measured (ie. 1 inch).... This gives you the volume of the jellybeens, now count the jellybeans and divide the volume by the number of jellybeans, you now have the volume of 1 jellybean.\n\nNow it is just a matter of finding out how big that jar you mentioned is and dividing it's volume by the volume of 1 jellybean.\n\nPresto you have the number of jelly beans in your jar :)\n\nPS. some jellybean manufacturers might have different sizes, try to find a typical sized bean :)
924480
The common ratio is simply 1.5.\n\nf(t) = 6 * (1.5)^t\n\nDay 0: 6 pellets\nDay 1: 9 pellets\nDay 2: 13.5 pellets\nDay 3: 20.25pellets\nDay 4: 30.375 pellets\nDay 5: 45.5625 pellets\nDay 6: 68.34375 pellets\n\nIf you add it up (not counting day 0), I get that she would eat through a total of 187.03125 pellets by the end of day 6, so she runs out before the end of day 6.
710040
U could do a comparative analysis of the fat content of your cafeteria foods. Using a fixed mass of each food, extract the fat by mixing with petroleum ether, filtering and collecting the filtrate then heating to drive off the solvent. U could then find the mass of fat that remains (of course you would nned to know the weight of the empty beaker etc bofore anything ws added). Do your percentages, graphs etc. and you are good to go.
556524
Set up a ratio:\n\n1.5 = 4\n___  ___\n1_____x      (I put the bar there so it would stay lined up)\n\nCross multiply to get:  1.5x = 4\nDivide both sides by 1.5:  x = 4/1.5 = 2.666667 or \n2 and 2/3 cups
779136
2/3 = $8\n1/3 = $8/2\n$4.\nHence Rosita saved $4.
559447
assuming the one chicken is unique and all other chickens have two legs, 2 1/2.\n\nif all chickens have 1 1/2, then 1 1/2 plus 3/4 would be a total of 2 1/4 legs.\n\nHow does a chicken walk with 1 1/2 legs?
726340
in the first bowl, two people each take 'x' amount.  if you add them up you get x+x=2x.  therefore the amount that remains in the first bowl is 1-2x.\n\nin the second bowl, you have 3 people taking different amounts, taking x% of what remains in the bowl.\nlets assume the first person takes x amount\nthe second person takes x amount of what is left (1-x), or x(1-x) or x-x^2\nthe third person takes x amount of what is now left:\nx * 1-(1-x) or\nx (1-1+x) or \nx-x+x^2    or\nx^2\n\nif you add up what these 3 people had you get:\nx+(x-x^2)+x^2\nx+x-x^2+x^2\n2x\n\n1-2x=2x\n1-2x-2x=0\n1-4x=0\n-4x=-1\n4x=1\nx=1/4  or  .25
605811
As Lauren said, it's 1/x.\n\nMemorize this. It will be very useful.
891913
15 - 3.5 = 11.5\n\n11.5 - 3.5 = 8.0\n\n8 - 3.5 = 4.5\n\n4.5 - 3.5 = 1\n\nso, you get 4 pieces at 3.5 and 1 piece leftover at 1
686296
You mean you use 4/5 as much jam as milk?\nThen take \n3 1/2 times 4/5\n7/2 times 4/5 = 14/5 = 2 4/5
501287
Let x be the number of cookies.\n\n(1/3)*x + (2/9)*x + 4 + 8 = x.\n\n(5/9)*x +12 = x\n12 = x-(5/9)*x\n12 = (4/9)*x\n12*(9/4) = x\n27 = x.
367452
Your information is given in terms of how much Beatrice collected, so let her amount = b.  Then Amy collected four times as much, or 4b and Colin collected half as much, or b/2.  If b=1, then your ratio would be 4:1:1/2 and to get rid of the fraction in the ratio you can multiply them all by 2 and get 8:2:1\n\nNow to solve how much each person got, Amy + Beatrice + Colin = 44 and you need to weight it for how much each collected.  Remember that Amy = 4b and Colin=b/2\n\n4b + b + b/2 = 44 --- again, multiply through by 2 to get rid of the fraction\n8b + 2b + b = 88\n11b = 88\nb = 8\n\nSo Beatrice earned 8.  Amy was 4b, so Amy earned 32; Colin was b/2 so he earned 4.  Check and make sure that 8+32+4=44.
697935
a. 38 + x = 75   Diana has 38 marbles. Her marbles (38) + her brother's (x) = the amount of marbles they have together (75).\n\nb. 5 + x = 23    Ramon's score has to = 23. He needs 5 more to get to 23.\n\nc. x - 8 = 9        Spring spent 8 from the total amound she started with (x). She now has 9 left.
830557
Tom baked 4 batches of fairy cakes. Each batch consisted of x cakes. He put 3 cherries on top of each cake in the first batch, but couldn't resist taking off and eating 5 of them. He did the same again with the second batch, then the third, then the fourth! Meanwhile, Sarah baked 5 batches of fairy cakes, again with x cakes in each batch. She put 2 cherries on each cake and an extra two on the final one. She repeated this procedure with each of the batches. She managed to resist eating any at all! Tom and Sarah discovered that Tom's cakes had exactly the same number of cherries in total as Sarah's. Set up an equation for this.\n\nThen: \n\nNumber of cherries on Tom's cakes = 4(3x-5)\nNumber of cherries on Sarah's cakes=5(2x+4)\n\nBut number of cherries is equal so:\n\n4(3x-5)=5(2x+4)\n\nPhew!! I think that works!! Lol!