E.g. i want to represent 101325 as 1.01e5. similarly 1013250 as 10.13e5. E5 should be constant.
213124
Microsoft Excel supports both scientific notation and the engineering notation variant.\n\nEnter a number such as 12,345,678 in a cell\nSelect the cell\nSelect menu bar "Format > Cells ... > Number".\nFor scientific notation, select "Scientific" and select the number of digits of precision (say 3) and the number will reformat as 1.23E+07.\n\nFor engineering notation, select "Custom" and find the format that looks like ##0.00E+00.  The number will reformat to 12.34E+06. Engineering notation traditionally formats numbers with exponents that are multiples of 3 corresponding to thousands, millions, billions, etc.\n\nI don't know of a way to select an arbitrary constant for the exponent.  Try reading the Microsoft help.
464358
♪ALT 13♫\nalt 14\nHold down the ALT button and push 13 or 14 on the numpad
501998
= 12.543 (3 decimal places)
423211
I would assume that one of your .01s in column A is something like 0.012.\n\nChange your number  format to General and see what happens.
483147
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
510378
You look as though you could benefit from a 'u' substitution of the following type:\nu = (0.0172(t-80))\ndu = 0.0172 dt\nTherefore, dt = (du / 0.0172)
512581
Hi. 0.754 x 1.0 would be obvious.  0.754 x .1 would involve moving the decimal point one place to the left.  0.754 x 0.8 would involve solving for the last value and adding 8 times.
633940
just divide both sides by 0.015...\n\nand you will get...\n\n566.66 \n\nwith a repeating six.
276533
Correct.\n\n(1350+99)*1.06
355619
0.009 \n\n0.018 \n\n0.027\n\n0.036
374338
Working above is good until this step:\n\n2 + 0.8x >0.9(x + 6)\n2 + 0.8x >0.9x + 5.4)\n0.1x > -3.4 ← Symbol error in this line\n\nShould read 0.1x < -3.4\nie x < -34
462710
10.1\n0.569\n1,400,000 or 1.4 million
515293
4.4.........the zeros cancel themselves otherwise the answer would be 8 but because of decimal point locations, its just 4.4.....\n\n\nhow did u come up with the answer?
659996
How does this work?  Is it okay to have a decimal in the middle?\n\nType 1   (Screen says 1)\n/ 3          (Screen says 0.3333333)\nx 3         (Screen says 0.9999999)\n+ 9        (Screen says 9.9999999)\n\n- Jack
450835
if you are using a "while" or "do while" loop\n\nwhile ((x1 - x0) > 0.001)\n{\n//your code here\n}\n\nor you can do this\n\ndo\n{\n//your code here\n}\nwhile ((x1 - x0) > 0.001);
443025
-0.070, -0.001, 0.000
333332
SQL has got a convert(datatype(size,precision),value) method\n eg:convert(decimal(18,2),12345.6789) as no_with_10.2_precisoin\n\nu should be able to use it to convert ur string to small int too. but make sure u validate the entry before sending to sql (avoid a typecaste error)