(3x-2 y)-2\n----------\n4xy-2)-1 \nThis is dealing with dividing monomials and simplifying expressions with negative exponents.
200398
if by this you mean\n\n((3x^-2 * y)^-2)/((4xy^-2)^-1)\n\nthis becomes\n\n((3^-2) * x^(-2 * -2) * y^-2)/((4^-1) * x^-1 * y^(-2 * -1))\n\n((1/9)x^4 * y^-2)/((1/4) * x^-1 * y^2)\n\n((1/9)/(1/4)) * x^(4 - (-1)) * y^(-2 - 2)\n\n((1/9)*(4/1)) * x^(4 + 1) * y^(-2 + (-2))\n\n(4/9)x^5y^-4\n\nwithout using negative exponents, the answer would be\n\n(4x^5)/(9y^4)
384944
4 (x^2 + 3X -4)\n4(x+4)(X-1)
92892
[(15x^5)-(10x^2)+(20x)]/[5x^5]\n   find a common factor\n(5x)[(3x^4)-(2x)+(4)] / (5x)(x^4)\n   division by self equals 1/1, disregard\n[(3x^4)-(2x)+(4)] / (x^4)\n   invert and multiply (1/x^y = x^-y)\n(x^-4)[(3x^4)-(2x)+(4)]\n   Multiply through, simplify [x^y * x^z = x^(y+z)]\n3x^0 - 2x^(-2) + 4x^(-4)\n   For non-zero x, x^0 = 1\n3 - 2x^(-2) + 4x^(-4)\n\nThree minus Two x to the negative second plus Four x to the negative fourth
487528
Order of operations: Parentheses Exponent Multiplication Division Addition Subtraction.\n\n2 - 2[4-9] ÷ (-5)\n2 - 2[-5] ÷ (-5)\n2 - [-10] ÷ (-5)  ~~ same as 2 + 10 ÷ (-5)\n2 + [-2]  ~~ same as 2 -2\n= 0\n\nI'd double check that if I were you; it's a bit early for me. :*)
514869
y = 3/2 (-4) -2 = -12/2 - 2 = -6 -2 =  -8\n\n(x,y) = (4,-8)
554204
X                      Y1                        Y2\n-2                     -4                          7\n-1                     -1                          6\n0                       2                           5\n2                       8                           3\n5                       17                         0\n\nX is your domain and Y1 is the range for y=3x+2 and Y2 is the range for y=-x+5.\n\nHope this is what you are looking for.
449036
well assuming you just want to break it down...\n1: you put the -2 power on both the 4 and a^3.  then it'd be (4^-2)(a^3^-2).\n2: remember that when it's an exponent to an exponent you multiply the numbers together so it becomes (4^-2)(a^-6)\n3: a negative exponent means it is one over itself so it would be 1/(4^2)(a^6)\n4: just simply from there to make it 1/ (16a^6)\n\nhopefully that was what you were asking!!
417398
x³y - 3x²y - 10xy --- Take x and y out of each term...\nxy(x² -3x - 10) --- Factor the x² - 3x - 10\nxy(x - 5)(x + 2)\n\n*Note: To show exponents, such as x², use the ^ key (such as x^2). This expression looks like you basiclly wrote:\n3xy - 6xy - 10xy
512195
x^2-6xy+8y^2\nx^2-6xy+9y^2-9y^2+8y^2\n(x-3y)^2-y^2\n(x-3y+y)(x-3y-y)\n(x-2y)(x-4y)\n\naliter\nx^2-4xy-2xy+8y^2\nx(x-4y)-2y(x-4y)\n(x-4y)(x-2y)
239169
i. is  pretty easy, just subtract one eq. from the other (2)-(1), leaving you with 2y=6 -> y=3. plugging into the eq. leaves x=2.\n\nii. subtraction again (2)-(1), leaving y=4, substitution yields x=2\n\niii. think of all the integers that have the product 35...done yet? just -1 x -35, -5 x -7, 1 x 35 & 5 x 7. see which works for the other eq.: x=5, y=7\n\niv. if (1) is 2^(x+y)=1 we can conclude x=-y, then there is no solution, since the exponent in (2) will be negative and the answer will always be less than one.\n\nif (1) is 2^(x)+y=1, then 2^x=1-y -> y=1-2^x\nplugging that in the second eq. & simplifying:\n2x(1-2^x)=3\n2^x=(2x-3)/(2x)\n2^x=1-(3/2x)\n\nAfter that, you'd have to use logarithms to solve it, which I'm not too keen on, so I'll leave the rest of the computation up to you. after you find a value for x, plug it into y=1-2^x to find y.
430048
1.) (x^2y)/(xy) = ((x)(x)(y))/(x)(y) = (x/x)(y/y)(x) = (1)(1)(x) = x\n\n2.) (3(x-2)^2)/(6(x-2)^4) = ((3)(x-2)(x-2))/((3)(2)(x-2)(x-2)(x-2)^2)\n    *Now what can be "1" \n\n3.) There may be a type-o in the denom having the "+" sign, but if such the case, the expression is at it's simplest form.\n\n4.) Now for this think about factoring out a number and I think you'll see something that can be in its simplest form.
557339
The answer is {2,-1}which is x=2, y= -1.  You have to put the problem in brackets {  3x - 2y=4  }, {2x+ y= 5} and then multiply each formula to cancel one element out. ( 2 )  times {3x - 2y=4}  and ( -3)  times {2x+ y= 5}.  Then you cancel out the { 6x - 4y = 8} and { -6x - 3y + -15}.  You can subtract the second equations X's and add the Y's and you get.  {-7y  = -7}.  You divide both sides by -7 and you get y = 1.  Then you use the original second equation and move the 2x to the =5 side.  YOu get {y= 5 - 2x.}  You substitute 1 for y, and turn the formula to {1 = 5 - 2x}  {subtract 5 from both sides and get {-4 = -2x.}  x=2.  Hope that answered your question.
438615
4x - y\nSo it'd be...\n4 x 3 - - 2\nSince the two minuses are together, it equals a plus, so then it would be 4 x 3 + 2 = 14
396188
x^2 + 3x  = -1\nx^2 + 3x +(3/2)^2 = -1 + (3/2)^2\n(x +(3/2))^2 = (5/4)\nx + 3/2 = sqrt(5)/2 OR x + 3/2 = - sqrt(5)/2\n\n(sqrt means the positive square root) \n\nx = -(3/2) + (1/2)sqrt(5)\nx = -(3/2) - (1/2)sqrt(5)\n\n.......................................................................\n\n2x^2 +4x + 1 = 0\nx^2 + 2x = -(1/2)\nx^2 + 2x + 1 = (1/2)\n(x+1)^2 = (1/2)\n\n(x + 1) = sqrt(1/2) OR (x + 1) = -sqrt(1/2)\n\nx = -1 + sqrt(1/2) OR\nx = -1 - sqrt(1/2)\n....................................\nLW = 783\n\n\n\n(W+2)W = 783\nW^2 + 2W = 783\nW^2 + 2W  + 1 = 784\nW + 1 = sqrt(784)\n\nW = srqt(784) -1\nW + 2 = sqrt(784) + 1\n\n2(W + L) = 2(2) sqrt(784)\n                = 4* 28\n                 =   112
196843
((x^2-2x)/4y)/((x^2-4)/6)\n=(6x(x-2))/(4y*(x-2)(x+2))\n=3x/(2y(x+2))
415329
do you mean 6x([1/2]x^2)?\nif so 3x^3\nor 6x(1/(2x^2))?\nthen its 3x^-1
585647
gemglaze,\nuse - for subtraction not _ . Make sure you put brackets in the right places and use x^2 for x squared etc. and group your powers so they are not confusing. People don't mind helping but make sure your question is unambiguous and properly presented.\n\nDid you mean (1/4x) - y or 1/(4x-y)?\n\n1) if the first then (-1/4*8)+1 = 1-(1/32)= 29/32 \n    if the other then  1/(4(-8)-(-1)) = 1/(-32+1) = -1/31\n\n2) that's properly factored but if you multiply it out you get:\n\n   3*(10x^2 +6xy-15xy-9y^2) = 30x^2 -27xy-27y^2\n\n3) (6^4)y + (9^2)y^5 = 81y(16+y^4)\n\n4)  x^2 +7x +10 = (x+2)(x+5)