1. What are the oxidation numbers of phosphorus in its most common compounds?\n2. What is the physical state of phosphorus at room temperature; what is its color, density, melting point and boiling point?\n3. List four important compounds of phosphorus and use for each.\n4. List two uses of phosphorus as an element (not in a compound).
210282
go here and you'll find all your answers and more\n\nhttp://en.wikipedia.org/wiki/Phosphorus
208605
C                    1s2 2s2 2p2\nSi                   1s2 2s2 2p6 3s2 3p2\nGe                   (Ar) 4s2 3d10 4p2\nSn                   (Kr) 5s2 4d10 5p2\nPb                   (Xe) 6s2 4f14 5d10 6p2\n\nConsult a good chemistry book.
378635
a) Ag2S\nb) SnCl4\nc) Na3N\nd) SrI2\n\nDo us a favor and pay attention during class. That way you'd know how to do these.
471336
i know that H2PO4 is phosphoric acid. i hope that helps.
438164
AB + CD ---> AD + CB\nlogic doesn't work here as Si doesn't react/bond with Ca or Phosphorus.and Ca(PO) should be Ca3(PO4)2\nand SiO should be in the form of SiO2. \nso unless you want hypothetical compounds SiO2 won't form with either of the two other reactants.\nbased on the forumlae from an SI data book, the above reaction would not balance.\ngood luck solving this one. :-)
334714
Okay, this is trivial stuff here.\n\nThe trick is to have enough + and - to add up to zero.  so, for example:\n\na) Cu2+ and NO3-;  you have two + and one -, thus to make a neutral compound you will need twice as much -, so the formula for the salt is: Cu(NO3)2\n\nYour problem in d) is a little trickier, but it is the same process:\n\nd) Mg2+ and PO4(3-): how can you get an equal number of + and - here?  use three Mg and two PO4!  Mg3(PO4)2\n\nI will leave the rest for you to do by yourself so you understand the process.
490423
Ba(NO3)2 and sodium phosphate\n\n1.  Ba(NO3)2 + Na3PO4 --> NaNO3 + Ba3(PO4)2\n\n2.  Ba(+2) + NO3(-1) + Na(+1) + PO4(-3) --> Na(+1) + NO3(-1) + Ba(+2) + PO4(-3)\n\n3.  No reaction (All spectator ions cancel out)\n\nBa(NO3)2 and sodium carbonate\n\n1.  Ba(NO3)2 + Na2CO3 --> BaCO3 + NaNO3\n\n2.  Ba(+2) + NO3(-1) + Na(+1) + CO3(-2) --> BaCO3 + Na(+1) + NO3(-1)\n\n3.  Forms BaCO3 (Barium Carbonate)\n\n\nBa(NO3)2 and pottasium iodide\n\n1.  Ba(NO3)2 + KI --> BaI2 + KNO3 \n\n2.  Ba(+2) + NO3(-1) + K(+1) + I(-1) --> Ba(+2) + I(-1) + K(+1) + NO3(-1)\n\n3.  No reaction (All spectator ions cancel out)\n\nBa(NO3)2 and sodium sulfate\n\n1.  Ba(NO3)2 + Na2SO4 --> NaNO3 + BaSO4\n\n2.  Ba(+2) + NO3(-1) + Na(+1) + SO4(-2) --> Na(+1) + NO3(-1) + BaSO4\n\n3.  Forms BaSO4 (Barium Sulfate)\n\nHopes this helps you!
550947
b,\n\nall the others are ionic compounds.
338927
IAnd for your other request, I would request you to send a seperate mail to me through yahoo Answer so that I am able to send it part by part.These are long subjects and would take some time,The balanced equation would be                                           H3PO4+3KOH=K3PO4+3H2O
444067
Hmmm.. The one affecting the boiling point is the intermolecular force..\nAs you can see, most of the compound here is polar. \n\nTherefore all you have to do is if the compound is consisted only of 2 elements (Group 17), you'll have to calculate the electronegativity difference. The more difference between them, the boiling will increase as well.\n\nIf there is more than 2 atoms in a molecule, you'll have to see the dipole moment magnitude (a.k.a polarity). The higher the magnitude, the higher the boiling point will be.\n\n\npeace\nvixklen
467733
2H3PO4 + 3Ba(OH)2 ---> 6H2O + Ba (PO4)2 +  2Ba
376143
s and p are orbitals. They also stand for the diffirenet blocks of the periodic table\nIts how you would show where an element is on the table and the electrons in its shells. for example:\nNitrogen\n1s^2 2s^2 2p^3\nthe first number says which period it is in, the letter is the block, and the power is how many elements into the block that is\n\nThis is a bit confusing hard to teach with just words
349316
a=oxygen diflouride\nb=dichlorine octoxide\nc= sulfur trioxide\nd=phosphorus pentoxide
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d. \n\nIt's a double replacement (acid/base) reaction.  The Sr and the H are both positive and they switch.  Since Sr has a 2+ charge and the PO4 has a 3- charge, you use a common multiple of 6.  The other product would be H(OH) or water.
550783
1) MgCO3\n2) AlF3\n3) BF3\n4) NH4F\n5) SnO2\n6) HCL\n7) Ca(OH)2\n8) Na2S\n9) K2SO3\n\n1) do yo mean PbCl2? then Lead (II) Chloride\n2) Lithium Bromide\n3) Potassium Sulfate\n4) Megnesium Hydroxide\n5) don't know\n6) Hydrogen Nitrate\n7) Barium Phosphate\n8) Carbon Monoxide\n9) Copper Brimide\n10) Ammonium Chloride\n11) Tin (II) Hydroxide\n12) Calcium Nitrogide\n13) Strontium Oxide\n14) Tetraiodide prefix for 9 and oxide\n\nFe^+2\nNi^2\nAg^+1
460682
Elements are Carbon, Nitrogen, Phosphate, Oxygen
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answer can be a or c, but i'd go with answer c.\n\nthe melting point (which solid becomes liquid) varies by each molecules & substances.  What happen is when temp. rises, it translates into more energy put into the soild or heat absored by the solid.\n\nHowever, you can melt solid by chaning pressure, and leaving temp constant.\n\nSo best answer would be C, by heat absorption.