what chemical reaction takes place to form a compound with this odor?
202316
It's an acid catalysed hydrolysis. The oxygen attached to the 2-carbon is protonated, then acetic acid is displaced from the ring by water, which is deprotonated to give salicylic acid. The vinegar smell is acetic acid. Note that the reaction cannot occur without water.
19409
This is an acid base reaction, but the other answer is incorrect about the product. There is no Cl present. Here’s the balanced equation:\n\n2NaOH (s) + H2CO3 (aq) ➔ Na2CO3 + 2H2O\n\nNaOH is the base. H2CO3 is the acid.
391420
CO2\nCarbon Dioxide\nHere is the reaction:\nHC2H3O2(aq) + NaHCO3(aq) ----> NaC2H3O2(aq) + H2O(l) + CO2(g)
576945
Ozone is created anytime there is a high amount of energy supplied to oxygen.  The smell after a lightning strike, for instance, is pure ozone odor\n\nAs for the ozone layer I am not sure how you could set that up in lab, but I am betting just a box of ozone will behave in a similar way.  be sure to recreate the temperature and pressure conditions and you might want to get a UV lamp too
537551
Tehe answer is:\nAg + HNO3 -> AgNO3 + H\nAgNO3 + KBr -> AgBr + KNO3
379517
You're almost right, except you need to add water to the reaction:\n\nWater + acetylsalicylic acid ---> acetic acid + salicylic acid\n\nAspirin is the acetate ester of salicylic acid.  Over time, this reacts with moisture from the air to hydrolyze the ester, generating acetic acid and salicylic acid.  Acetic acid is the principal odor and flavor component of vinegar.
516360
2\nthe reaction is\nCa(OH)2+2HNO3=2H2O+Ca(NO3)2
380262
Perhaps there is also a H atom at C*\n\nThen final product is\n\n(CH3)2CH-CH=CH-CH2-CH(CH3)2\n\nA dehydration reaction occurs.
288883
Cu(s) + 4HNO3 (aq)--> Cu(NO3)2(aq) + 2H2O(l) +2NO2(g)
31785
I'd expect oxidation to form the carboxylic acid. The aldehyde will form a primary carboxylic acid and CO2 gas. The ketone will form 2 secondary carboxylic acids.
498527
The answer is c)\n\nProtonation of the double bond gives the more stable secondary carbonium ion, this reacts with Br- to give the product.\n\nIn the presence of peroxide the reaction goes through a radical mechanism to give the reverse selectivity
287968
Carbon itself doesn't do anything at room temperature up to boiling point with sulfuric acid. Might just swim on it and adsorb a little of it (this being a process which gives out a little heat).\n\nIn case your carbon contains impurities, these might react with sulfuric acid and give out some smell and also colour and sediments, depending what the impurities are.\n\n(But the creation of CS2 as mentioned in GforGenius' answer in my opinion is just a joke against people who want to escape from doing their homework from their books and go the easy way on yahoo. If stinks something, the odour mostly comes from H2S (=rotten egg), because impure carbon depending on its origin might contain metallsulfides).
123069
2 CH3OH + 3 O2 → 2 CO2 + 4 H2O + 726 kJ/mol
161835
CH3-CH=CH2 has an electrohilic addition of bromine.  The bromine adds to the double bond via an intermediate known as a bromonium ion.  This is essentially a polarised bromine molecule, with a small dipole.\n\n\n....Brd-\n....Brd+\n../....&#92;\nCH2-CH-CH3 (ignore the dots, only there for spacing).\n\n---->\n\n............+\nBr-CH2-CH-CH3   secondary carbocation is formed\n\nThe Br-Br bond then breaks the bromonium ion formally forms a single covalent bond with the terminal carbon, and creates a secondary carbocation.  The Br- formed from the breaking of the Br-Br bond then attacks the carbocation to form 1,2-dibromopropane.\n\nBecause you are doing the reaction in the presence of NaCl and H2O, then Cl- (from the NaCl) or -OH, from the water can also attack the formed carbocation, giving 1-bromo-2-chloropropane and 1-bromopropan-2-ol as a result.  \n\nThe reason for not generating any 2-bromo-1-chloropropane for example is that this would require the preparation of a primary carbocation.  This is far less stable than a secondary carbocation, so the three products described by far predominate in the reaction mixture
188596
In the first reaction, the base is NH2-, and the conjugate acid is NH3 (ammonia).\n\nIn the second reaction, the acid is HClO4 (perchloric acid) and the conjugate base is ClO4- (perchlorate).\n\nIn the third reaction, the acid is HSO4- (hydrogen sulfate) and the base is CO3-2 (carbonate). The conjugate base of HSO4- is SO4-2 (sulfate) and the conjugate acid of CO3-2 is HCO3- (hydrogen carbonate).
355448
Concept: An element and a compound can react to form another element and another compound. \n\nMaterials: 200 mL of 0.1M copper(II) chloride (CuC12), 5 cm. square piece of aluminum foil (Al), 400-mL beaker, safety goggles. \n\nProcedure: 1. Place the beaker of copper(II) chloride in front of the class. 2. Crumple the aluminum foil and throw it in the beaker. 3. Soon the solution starts to bubble as hydrogen gas is produced. 4. A red brown precipitate of copper falls to the bottom of the beaker, and the aluminum foil dissolves completely. 5. Aluminum would react spontaneously with water without its protective oxide coating. The aluminum-copper(II) chloride reaction removes this protection. Caution: Copper(II) chloride is an irritant. \n3CuCl2 + 2Al --> 2AlCl3 + 3Cu\n\nInput = 3CuCl2 + 2Al \nOutput = 2AlCl3 + 3Cu
360686
The answer is Cu + Cu(NO3)2 -> Cu + Cu(NO3)2\n\nThere is no reaction.