jamie will definietly try out for either basketball or baseball, but not both.  The probability that Jamie will try out for baseball and try out for catcher is 42%.  What is the probability that Jamie wil try out for basketball????\n\nA. 40%\nB. 60%\nC. 80%\nD. 90%
213154
P(A or B) = P(A) + P(B) - P(A and B)\n\nP(A) = probability of trying out for basketball\nP(B) = probability of trying out for baseball\n\nNow, P (A and B) = 0, since Jamie will not try out for basketball and baseball\n\nP(A or B) = 1 (or 100%), since Jamie will definitely try out for basketball or baseball\n\nSo, P(A) + P(B) = 100%\nP(B) is more than 42% or more (since you have to consider that Jamie will try out for other positions for baseball).\n\n100% - 42% = 58%\nP(A) has to be 58% or lesser. The only answer that is less than 58% is option A (40)
575337
Excellent catcher and hitter with a great future ahead of him in baseball!!\n\nGood luck!!
312238
check on yahoo sports. but ill tell you in hitting.\n\n1.Games Played Jeff Kent and Rafael Furcal 36 Games\n2.At Bats Rafael Furcal 149 At Bats\n3.Runs Rafael Furcal 29 Runs\n4.Hits J.D Drew 37 Hits\n5.Doubles Nomar Garciapara 9 Doubles\n6.Triples Kenny Lofton 4 Triples\n7.Homeruns J.D Drew 7 Homeruns\n8.RBI J.D Drew 27 RBI\n9.Walked Jose Cruz and Rafael Furcal 23 Walks\n10.Strucken Out Rafael Furcal and J.D Drew struck out 23 times\n11.Stolen Bases Rafael Furcal and Kenny Lofton 9 Stolen Bases\n12.Caught Stealing Rafael Furcal Caught Stealing 4 times\n13.Batting Average Nomar Garciapara 354. Batting AVG cody ross and willie aybar have better batting averages but they played very little games but if you want theyre batting averages willie aybar 375. cody ross 500. batting average.\n12.On base percentage once again cody ross and willie aybar have the highest on base percentage and it is 500. but i think they played to little games so the next to highest on base percentage is nomar garciapara 416. on base percentage\n13. slugging percentage one again cody ross has the highest 1,143. slugging percentage but i think he played to little games so the next to highiest is nomar garciapara 684. slugging percentage.\n\nThat was batting. id say the three best players on the dodgers are 1. rafael furcal 2. nomar garciapara 3. J.D Drew and if you would count cody ross even though i think he played to little games i would put him on the list instead of J.D Drew\n\nNow if you want info about pitching write another question tonight to say about pitching and ill tell you info about pitching
336130
Oh yes, softball is pretty much my life!  I play catcher about 99% of the time... I can play anywhere, though.  I have been playing for 5 years now, and it is certainly addictive!  Make sure to check out the Women's College World Series... it should be coming up on ESPN U or ESPN 2.
303664
a. first draw doesnt matter since it's replaced; you're back at 3 in 10 chance\n\nb. two ways this could happen: first, 3/10 chance first ball is red, leaving you 2/9 chance then of second ball being red on second draw.  second, 7/10 chance you draw a white ball, leaving you with 3/9 chance of second ball being red.  (3/10*2/9)+(7/10*3/9) which leaves you with 3/10 chance. again.\n\n\nEDIT:\n\nsurprises me how many people can't do math.\n\nfor A), the second draw is completely independent from the first.  Doesn't matter if I took a dump in the bowl in the first draw; as long i fished it out, you're left again with the same start on the second draw-3 reds and 7 whites.  your probability doesn't change because of what happened in the first draw as the conditions are RESET.\n\nfor B), let's run through allll possible scenarios\nNumber the Balls\n\n1 - red\n2 - red\n3 - red\n4 - white\n5 - white\n6 - white\n7 - white\n8 - white\n9 - white\n10- white\n\nPossible draws (X denotes red second ball outcome)\n1,2 - X\n1,3 - X\n1,4\n1,5\n1,6\n1,7\n1,8\n1,9\n1,10\n(2 fav outcomes if ball 1 is drawn first)\n\n2,1 - X\n2,3 - X\n2,4 \n...\n2,10 \n(2 fav outcomes if ball 1 is drawn second)\n\n3,1 - X\n3,2 - X\n3,4 \n...\n3,10 \n(2 fav outcomes if ball 1 is drawn second)\n\n4,1 - X\n4,2 - X\n4,3 - X\n4,5 \n...\n4,10\n(3 fav outcomes if ball 4 is drawn first)\n\n...\n\n10,1 - X\n10,2 - X\n10,3 - X\n...\n10,8\n10,9\n(3 fav outcomes if balls 5-10 are drawn first)\n\n\nthere are 90 outcomes\nof which there are 2+2+2+3+3+3+3+3+3+3 favorable outcomes = 27.\n\n27/90 = 3/10\n\n\nSecond edit: guy below, 2*3 + 7*3 = 6 + 21 = 27, not 28
341455
I'm assuming that each parent is Bb which would in fact give you the 1/4 probability. \n\nSo, for 3 kids in a row, the probability is 1/4 x 1/4 x 1/4 which is 1/64.
115728
This is always so much fun, isn't it.  This is probably why the previous answerer is now looking for satisfying employment in the food-service sector.\n\nBy the way, you forgot to mention if they have to specifically be in that order or in any order, though.  It's a very different answer.\n\nOkay, what's the probability of drawing one green marble each time you draw, if you put the marbles back each time?  It's the partial over the sum, or in other words 4 out of 6, or 2/3.  Similarly the probability of drawing a red marble is 2 of 6, or 1/3.\n\nSo if you specifically want the order to be green, green, red, then you just multiply the probabilites each time.  2/3 * 2/3 * 1/3 is  4/27.\n\nHowever, suppose it can be in any order?  Here's where it gets tricky.  First we figure how many ways there are to draw two greens and a red -- we can draw (g,g,r) or (g,r,g) or (r,g,g) -- so three ways.  The probability is the same for each time so we add them together, essentially 3 * 4/27 is 12/27, or a little less than 50%.\n\nPart b) is harder, since the probabilities change with each draw.  The first time we draw it's a 2/3 chance of getting green, but after that there are only 3 green marbles out of 5, so it's now 3/5 instead of 4/6.  So if we want to draw two green and one red IN THAT ORDER it's 2/3 * 3/5 * 1/2 = 1/5.\n\nIf you don't care the order, then figure out each of the ways to draw 2 greens and one red (same as above) and add the probabilities from each time.  I'll leave it to you for the answer.\n\nActually there are very few interesting people in the world who like statistics.  But even the boring ones can usually find very good jobs.  Also it's been a while since my stats classes so if I'm wrong, please don't come after me with a baseball bat, thanks  :)
542087
trick question cause in jersey or idaho gays can get married so you dont no the probability to men to wemon but that aside then the answer is \n\nWhat is the probability a married couple wins the prizes? 1/6\n\nWhat is the probability one prize goes to a man and one to a woman? 1/2\n\n\nIf John's wife Mary wins a prize, what is the probability that John will also win a prize?  1/11\n\nIf Mary does not win a prize, then what is the probability that John will? 1/12
334586
As it is certain that the first one is red and the second one is blue, we can ignore the fact that they were even mentioned. (It would be different if you phrased it as find the probability of the first ball being red, the second being blue and the third being yellow...)\n\nP(Yellow) = 1/5
66394
Is this a baseball question?
569098
it doesnt matter what inning it is.  you have an undefined percentage of scoring in any inning against any team and any pitcher.  and just because the yankees scored 3 in the first once doesnt mean anything.  whoever said that should stay out of these forums cause you dont know anything.
620429
Most of them got it right.\n\nThis is another way to think about the result.\n\nFirst player = T or H doesn't matter\n\nSecond Player = Must be that same as the First Player\n                        =  only 2 possibility (H or T)\n                        = 1/2\nThird Player = Must be the same as First Player\n                    = again, only 2 possibility ( H or T )\n                    = 1/2\n\nIn order for the Second Player and Third Player to have the same result as First Plaer = 1/2 x 1/2\n                                 = 1/4.
244155
dude, i asked the same question about a week ago. I saw the second base monster from another question that involved it. The answers i got from most of the people was that it was an hypothetical question, an analogy of sorts. It can basically be anything that could happen when you are rounding 2nd base, but there are certainly no monster at 2nd base.
404379
Between 1/3 and 2/3 chance\nChance of him on his first step 1/3.\nChance if he first steps back,=  2/27 -  2/3 x 1/3 x 1/3 (ie he has to take 1 step back, then two forward to fall off cliff).\nChance if first two steps back then three \nsteps forward =  4/243\n\nSo its1/3+2/27+4/243 etc etc\n\nThe other options just keep adding up. \n\nThe increments get smaller, but they keep adding on to the probability.
426271
I couldn't quite infer from your question if you're the one that's African American who's thinking of trying out?  If its you, I'd say give it a shot regardless of who is on the team.  Hopefully they'd give you a fair shot, and from what you've said about your hitting, I'd think they'd be crazy not to find a spot for you.\n\nSpecifically regarding the racial disparity of women's softball, I've never known that there was a disparity.  I'm not a huge fan of it, so maybe I just haven't noticed.  Regardless, I don't think it would be awkward so long as your comfortable with yourself and you're able to focus on the game without dwelling on it.  I actually just got back from a hockey game tonight with the San Jose Sharks, and they have an African American on their team (Grier) that has had to deal with the same thing his whole life.  Although I remember him being a lot better than what he showed tonight, he's always been very good and fit right in over the course of his career.\n\nI say "go for it!"  Good Luck!
181266
Baseball or basketball.....because I understand the game, hahahaha!!!!
178452
try this site for help on probability\n\nhttp://www.futureaccountant.com/probability/