Please explain and show work.
213654
in 1mol of NH3, there will be 6.023 E 23 molecules will be present\nIn 0.7 mols 6.023 X 0.7 =4.21 E23 molecules will be there\n\nIs it clear?
297281
The best way to work this out would be to plot a speed time graph for the information.\n\nOr you could express it as a simultaneous equation.
25094
I'm not sure I understand the question.  Add some detail?
433876
Your ratio is 1:8.15          You fid this out by starting at 13:106 and work yoiur way down to 1. \n\nyou divide both sides by 13 to get your answer.
490217
I could not understand head and tail of this problem.Please send the proper problem immediately so that it may be solved.
420217
lol \nYou have homework that you don't know the answer to.  \n\nWhy would someone ask these here out of interest? Like you have these specific parameters and conditions that you are just raring to want to know just out of the blue.\n\n Quit wasting time writing and typing questions out waiting here for answers when you could be the next engineering graduate who actuallly UNDERSTANDS this stuff by doing it yourself.
541499
I gues the question wrong or has printing mistakes.... please confirm in the first equation is it U= U+ GT or.... that woud make GT= 0;\n\nNext in the second equation is it 1 by twice GT or is it half GT.
2854
Trying to get someone to do your homework for you?  Why don't you take a first stab at it and post the results... \nIf you then still can;t get it, I'm sure we can help!\n\nBut you'll learn a LOT more by trying it yourself FIRST!
51587
Give me a better example and I may be able to help.:)
413210
Your answer key is wrong, or you are not reading the right answer.\nFrom the data you presented above y = x^3 is OK.
60578
check those equations out at wikipedia
25002
ok, all you have to do is figure out how much work it should have been doing, then compare it to the amount of work it actually did by using a percentage. so first of all, W=Fx(work equals Force times distance) that means that W=(12)(.3)=3.6 J of work.  Ok, so since it only did 3.2 J, that means .4J were lost somewhere.  the efficiency is calculating the efficiency in terms of what percentage of the work that was actually applied was translated into the work energy that was done on the lid.  the way you do this is just divide the amount of work it did by the amount of work it should have done(in an ideal solution) and then multiply by 100 in order to find the percentage of work it actually did in relation to the work it should have done.  3.2/3.6= .88889(x 100) = 88.89%.  \n\nso basically, in cases with efficiency, you divide the number you solved for by the number they gave you. a good way to figure out which you divide by which is just to randomly try dividing and if the answer is above 1(100%), that's impossible so you switch them ; )
247563
go to this site, its very good,\n\nit gives clear explanations and statistics
453548
I understand your frustration in receiving no Answer yet to this question, but since I do not have any direct knowledge of how to perform the calculation(s) you need ... I hope the link below serves you well.  It appears to explain the mathematics behind all the concepts you mention.
535546
Everyone is working at the same time so add their work together like this:\n\n20pg/40m + 20pg/30m + 20pg/24m.\n\nReduce these down so you can get a common denominator and add them together:\n\n1pg/2m+ 2pg/3m + 5pg/6m = \n\n3pg/6m + 4pg/6m + 5pg/6m = 12pg/6m.\n\nThat's 2 pages a minute, or 20 pages in 10 minutes working together.
174304
Your looking for the time they work together so let (x) the time they work together .the rate should be A=15,B=5 then the work should be A=x/15 and B=x/5 since your looking for the time...solve for it cause I'm not giving you all the answers. it should look like this \n\nx/15+x/5= the time they work together...\n\n(Next time listen to your teachers)
382050
Looks as though this is some kind of assignment. No? Maybe you ought to think it all through and provide your own answers. You can do it!!\n\nChow!!