have swimming pool 16 x 36 with depth of 3 to 6 ft. ? rough estimate of # of gallons of water for pool.
210600
1 cubic foot = 6.23 UK gallons or 7.48 US gallons.\nRocketmans approximation of gallons in a U.S pool is therefore correct.
296374
1st, the volume of the tank is (4/3)π(4.5)^3 = 381.7035 cubic meters.  The part left unfilled is a spherical cap whose volume formula is (π/6)(3r1² + h²)h, where r1 is the radius of the base of the cap, and h is its height.  The height here is 9 - 6.5 = 2.5, and r1² = 4.5² - (6.5-4.5)² = 16.25.  \n\nSo the volume of the unfilled cap is (π/6)(3*16.25 - 2.5²)*2.5 = 55.6324 cubic meters.  We subtract that from the volume of the tank to get 326.0711 cubic meters of water when the tank is filled 6.5 meters deep.  \n\nNow one liter fills a cube 1/10 of a meter on a side (10 cm), so a bucket is 1/100 of a cubic meter.  Multiplying the required volume gives 32,607.11 buckets, which rounds up to 32,608.\n\nMathgirl mistakenly assumed the volume of the tank was proportional to the depth of water, which would be true for a cylinder, but not for a sphere.
345602
Okay.  This can be a little tricky if you dont see how to set it up.\n\nwe don't yet know the length, so lets call that x.  Since we all know there are 4 sides to a rectangle lets set up the equation like this.\n\n36 = Perimiter.  Since the length is 4 ft longer lets write the expression to show that.\n\n36= 2(4+x)+2x\n\nx = the width, and since theres 2 lengths and 2 widths, multiply them by two. now multiply out.\n\n36= 2(4+x)+2x => 36=8+2x+2x => 36=8+4x\n\nnow its simple algebra\n\n36-8=4x\n28=4x\nx=7\n\nsince x=width,         width =7 ft\nsince x+4=length     length = 11 ft\n\nnow find the area. This is the easy part.\n\nArea= length x width\n\nA= 11x7\n\nA=77 ft^2
196401
If it's an ellipse the area is pi*r1*r2, r1 and r2 being the semimajor and semiminor axes. This is 3.14*25*9 ~= 705 sq. ft. You'll have to estimate the average depth. If it's 4 feet you have 4*705 ~= 2820 cu ft. There are ~7.5 gallons in a cu ft, so that's 7.5*2820 ~= 21200 gallons.
144853
American 9ft x 4ft table - allow 6ft around the exterior of the table therefor room required 21ft x 16ft = 336sqft\n\nEnglish 6ft x 3ft table - allow 6ft around the exterior of the table therefor room required 18ft x 15ft = 270sqft
6262
V = πr2h\n1.v = 36 cubic inches = 0.15584410891073416 us galons\n\n2. v = 36 0.15584410891073416 us gallons \n\n3.v = 72 = 0.3116882178214683 us gallons
199109
The formula for the area of a trapezoid is A=(a+b)h/2 so yours would be 20+25+45  45*14=630 630/2= 315 and that would mean you would need 2 gallons to stain
360818
12 x 16, that will equal square feet (192)\njust measure length times width to calculate square footage
274579
i haven't done this in a while.\n\nThe volume of the reservoir is equal to (1/2)*(height)*("base")*length.  the reservoir is a rectangular prism with the "base" being the distance across the surface of the water.  We are given the shape of the full volume so we can scale down to the level of the water to find what the volume in the reservoir at its current level.\n\nif you think about the cross-section of the volume, and use half of that forming a right triangle, we can determine the ratio of the surface (the "base") to the height (water depth).  In this case, it is (40/2)/(20*sqrt(3)) or 1/sqrt(3).  so ("base"/2)/(height) = 1/sqrt(3)  and then "base" = (2*height)/sqrt(3).\n\nsubstitute that into the volume equation so that\nvolume = [(height^2)*length]/sqrt(3) or literally,\nV = [(h^2)*L]/sqrt(3).  differentiate with respect to time,\n(dV/dt) = [2*h*(dh/dt)*L]/sqrt(3) and substitute the numbers in:\ndV/dt = 200 - 50 = 150\nh = 10*sqrt(3)\nL = 450\nand solve for dh/dt which is the rate of change of the water level in yds/hour.  these are odd units, you might want to change to inches/hour.\n\ni did it this way and got 1/60 yds/hr or 0.6 inches/hr.\n\nbut again it has been a long time....
499325
36 quarts = 9 gallons\n\nso we have 18 gallons, 15 gallons, and 9 gallons\n\nIf we fill the 18 gallons, then pour it into the 15 gallon container, this will leave 3 in the 18, and 15 in the 15.\n\nWe now pour from the 15 into the 9 to give us:\n\n3 in the 18\n6 in the 15\n9 in the 9\n\nNow just empty the 9 back into the 18 and it will have 12 gallons!\n\n:) Hope this helps!
27387
We bought one at Walmart...it was 200 (last summer) and lasted all year, with no holes or problems.  We used it tons and had lots of kids jumping in & around it.  Plan on bringing it out again soon!\n\nHappy swimming!
445911
This is what I could find.\n\n160' x 360' = 57600 square feet.\n\n\nThis is NCAA but the same with NFL.
156919
If the tank is a cylinder, the Volume is πr²h.  If you get the volume in cubic feet, multiply by 7.5 to get gallons.
210067
Find the area.\nArea of a rectangle = length*width\n= 15*20\n= 300\n(2/3)(300) = 200\n300-200 = 100 square feet
54255
...Average Depth(in feet)...Maximum Depth(in feet)\nsuperior--------483-----1332\nMichigan-------279-------925\nHuron-----------195--------750\nErie---------------62------210\nOntario---------283-------802
608330
Approx 6 pounds per gallon
311072
4 X 4 =16 square inches.......