I have tried this problem every way I know how and keep coming up with x=  -7 but when I put -7 in the original problem it doesn't total out right.  Please help!
216609
Remember Order of Operations - in this case, Parenthesis, then Add/Subtract.\n\n1.) First, we do the parenthesis:\n3x-5(3x-7)=2(x+9)+45\n3x-(15x-35)=(2x+18)+45\n\n2.) Next, we add/subtract from the parenthesis:\n3x-(15x-35)=(2x+18)+45\n-12x + 35 = 2x + 63\n\n3.) Then, we solve by subtraction and division:\n-12x + 35 = 2x + 63\n-12x - 2x = 63 - 35\n-14x = 28\nx = -2\n\nCheck:\n3(-2) - 5(3(-2)-7) = 2(-2+9)+45\n-6 - 5(-6-7) = 2(7) + 45\n-6 + 65 = 14 + 45\n59 = 59
492094
x/(x-8) + 7 = 8/(x-8)\nMultiply everything by (x-8)\nx + 7(x-8) = 8\nDistribute the 7\nx + 7x - 56 = 8\nCombine x and 7x\n8x - 56 = 8\nAdd 56 to each side\n8x = 64\nDivide both sides by 8.\nx = 8\n\nNote that x-8 cannot equal zero, but we just found x to be 8.\nThat means x-8 = 8-8 = 0\nThus, we have no solution.
420182
let the numbers be x and y\nSo x + y = 7\nxy = 25\n\nNow 1/x + 1/y \n= x/xy + y/xy\n= (x + y)/xy\n= 7/25\n\nx + y = 7 So y = 7 - x\nxy = 25\n\nSo x(7 - x) = 25\n\n7x - x² = 25\n x² - 7x + 25 = 0\nx = [-b ± √(b² - 4ac)]/(2a)\n= [7 ± √(7² - 4.1.25)]/(2)\n= [7 ± √(- 51)]/(2)\n\nSo x = [7 - √(- 51)]/(2) and y = [7 + √(- 51)]/(2) \nThus 1/x = 1/[7 - √(- 51)]/(2)\n= 2/[7 - √(- 51)] * [7 + √(- 51)]/[7 + √(- 51)]\n= 2[7 + √(- 51)]/(49 - -51)\n= [7 + √(- 51)]/50\n\n1/y = [7 - √(- 51)]/50\nSo 1/x + 1/y = [7 + √(- 51)]/50 + [7 - √(- 51)]/50\n= 14/50\n= 7/25 (as above but with much more effort!!!!!!!!) (8^O)
395114
This has very little to do with Programming & Design; I think you should post your question in the Education / Homework help section.\n\nBut to help you along: work from the bottom to the top, substituting the value from the lower equation into the one above it.\n\nPS: Come to think of it, there is no solution to this system.\n\ny = -2  \n(-2)-x = 2\n-x = 4\nx = -4\n\nSubstitute x = -4 and y = -2 in the first equation:\n(-4) + (-2) = 2\n-6 = 2\nwhich is clearly not correct...
616457
x-(-2 -7)=-1\nx+2x+14=-1\n3x=-15\n\nx = -5\n\ny=-x-7\ny=-(-5) - 7\ny=5-7\n\ny = -2
431058
Hey, here's the setup for these types of problems.\nYou want the equation in the form of y = mx + b\nsince we know that x = 2, y = -7, and m = -1/5, we can plug these values into that equation to find the equation of the line that passes through the desired point. SO:\n-7 = (-1/5)(2) + b\n-7 = (-2/5) + b\nb = (-7)+(2/5)\nb = -33/5\nso the equation for the line is:\ny = (-1/5)x - (33/5)\n\nhope that helps!!
278802
-13 - (-10) + (-64) = -64\n\nThe Working : \n\n-13 - (-10) + (-64)\n=-13 + 10 - 64 = -67 \n\nNote:\nthe minus and minus in between 13 and 10 changed to a plus b'coz\n\n- and - = +\n\nBest of Luck !!
290759
This is more of a word problem or a riddle than a math problem.\n\nThe answer is 7 (SEVEN).  Remove its first letter and it becomes EVEN!
297938
Above answer is ok except for not using the -- operator:\nNeed to start at 10 and to decrement i use the statement:\n\ni--;\n\nThis changes the problem somewhat.  Another problem in the first answer is that fact is not initialized, so it will always equal zero resulting in a division by zero error.
385623
well....u got 7x-16=-76 \nso.....u add 16 to both sides to get\n7x=-60 so...u divide by 7 to get\nx=-60/7 which is indeed a fraction and there is nothing wrong with that. In higher math course, answers that have fractions will be typical. = )
512835
ok so take the y out, so then the problem will be 3x-6=0, then put the -six over to where the 0 is, so now its 3x=6 so just solve for x, and its x=2
409704
x≠０\ncuz if x=0, (x-7)/x^3 is meaningless
253991
Case 1 : 2x+10<4\n   \n-> 2x+10-4<0\n-> 2x + 6 <0\n-> 2(x+3)<0\n-> x < -3\n\nCase 2 : 2x+10>-4\n\n-> 2x + 14>0\n-> 2(x+7)>0\n-> x > -7\n\nNow we combine the results of the 2 cases\n\ni.e, x<-3 & x>-7\n\nthis will come out to be -7 < x < -3
157160
1)First simplify that in the absolute brackets//\n/13x - x/ = 7\nNext divide by 12.  Note, when we remove the absolute brackets we are basically creating two equations.\n/12x/ = 7\n12x = 7 ; 12x = -7\nSo there are two values of x that satify the question.\nx = 7/12;   x = -7/12\n\n\n2) Take the sqrt of both sides.\n(x+3) = sqrt(13)\nNow subtract three from both sides.\nx = sqrt(13) - 3
20504
x= -1\ny= 3\n\nSimply substitute the x and y values in the equation.\nTherefore\n=(-1)+3*3\n=(-1)+9\n= 8
461240
theres no solution because when you minus the root x from on side, it would be 0=40, which is not true
376501
fistly put the x's on the same side so we weill have the original eqn being 12x - 4 = 7x - 29\n                  12x - 7x - 4 = 7x - 7x - 29\n                 12x - 7x -4 +4 = 4 - 29\n                  12x - 7x = 4 - 29\n                    5x = -25\n         Divide both sides by 5 and we get x = -5