I tried it and got an answer totally different from my friend. So then, today we asked our math teacher who's correct and she said his was. Can you give steps on how to get right answer? My friend told me I had to square root it first. I didn't know what he was talking about. I couldn't ask him since he left. I got 1/9(x+18)(x+18). He got something different. Can you tell me what I did wrong?
199812
It's a perfect square trinomial.  Take the square root of the first term and the square root of the last.  If you multiply them and then double it, and it equals the middle term, then it's a perfect square trinomial.\n\nIn this case, it factors into (x/3 + 6)^2.  Using FOIL, you'll see that it expands into your original expression.
449256
I'll rewrite the question for you, because we usually denote ^ as "to the power of" for simplicity.\n\nx^2 + y^2 - 4x + 2y = 4\n\nWe have to do a process called completing the square, for both the x and y variables.  So first, let's group all the x terms together and y terms together.\n\nx^2 - 4x + y^2 + 2y = 4\n\nTo complete the square, we have to add 4 to the x terms and 1 to the y terms.  Since we're adding 4 and 1 to the left hand side, we have to do the same to the right hand side.\n\nx^2 - 4x + 4 + y^2 + 2y + 1 = 4 + 4 + 1\n\nNow, we factor those now square polynomials.\n(x-2)^2 + (y+1)^2 = 9\n\nThe center of the circle is given by the values in the brackets, but the negative of them.  In the above case, the center is at (2,-1), since you take the negative of -2 (the value next to the x) and 1 (the value next to the y).\n\nTo get the radius, you take the square root of the right hand side, so the square root of 9 is 3.
569661
Hi:\n\nI know of six ways to find a square root of a number:\n\n1) Take the logarithm of number and divided by 2 take the result and take the Antilog \n\n2) Use the School boy method of extracting a square root see this website for how :\n\nwww.nist.gov/dads/HTML/squareR...\n\n3) Use the following method ( example on the bottom of page ):\n\n(N/gn+gn)/2= gn\n\nN= number to be Square root \ngn = Guess number or Square root\n\nrepeat this for about about 5 to 10 times ( see example)\n\n4) Use trail and error by running a number value and Square it\n\n5) Graph and interpolarite it\n\n6) Look it up in a Mathematical hanbook of tables and formulas and look under Square & square roots tables.\n\n------------------------------...\n\n\n\nExample:\n\nThe square root of 27:\n\n(27/5+5)/2= gn\n\n\n(5.4+5)/2 = gn\n\n10.4/2= gn \n\n5.2 =gn \nend of run 01 \n\n(27/5.2 + 5.2)/2= gn\n\n(5 + 5.2)/2 = gn\n\n10.2/2= gn \n\n5.1= gn\n\nend of run 02\n\n((27/5.1)+ 5.1) /2= gn\n\n(5.294117647+5.1)/2 = gn\n\n10.394117647/2 = gn\n\n5.197058823 = gn\n\nEnd of run 03\n\n(27/ 5.197058823) + 5.197058823 )/2 = gn\n\n(5.195246179+ 5.197058823 )/ 2 = gn\n\n10.392305003/2 = gn\n\n5.196152501 = gn\n\nEnd of run 04 \n\n((27/5.196152501)+ 5.196152501)/2 = gn \n\n(5.196152343+5.196152501)/2 = gn\n\n10.392304844/2 = gn\n\n5.196152422= gn \n\nEnd of run 05\n\n((27/ 5.196152422) + 5.196152422 )/2 = gn\n\n(5.196152422 + 5.196152422 ) /2 = gn\n\n5.196152422 = gn \n\nEnd of run 06\n\nSquare root of 27 appoximatily = 5.196152422 ( accurate to 9 decimal places.) \n\nSource(s):\n\nwww.nist.gov/dads/HTML/squareR...\n\nwww.du.edu/~jcalvert/math/sqrt... \n\nmathforum.org/library/drmath/v...
354138
I'm 100% sure you will fail your tests if you dont at least try these yourself.  You should try them, get an answer, and then if YOU'RE not sure, ask the question here with your solutions and maybe someone will show you right or wrong.\nAs it stands now it sounds like you're just lazy and want someone else to do your homework.\nBesides, I see many many WRONG answers in this mathematics category.  Its like you'd just be copying your final exam answers from the class idiot.\n\nBY THE WAY...\nThere are two square roots of EVERY number.  So every answer which gives just one solution (unless the question specifically asks for just the negative square root, as in "the negative square root of of 169/4") is incomplete.  You dont have to specify "what is the negative and positive square root of (a number)...".  Asking for the square root of a number demands two solutions.
261593
Aahhh, subtle. You're obviously careful with your parentheses, so the difference between x=(-b±√(b^2-4ac))/2a and x=(-b±√(b^2-4ac))/(2a) (the correct quadratic formula) could not have escaped your attention - technically, the first could be interpreted as x=((-b±√(b^2-4ac))/2)a, in which case a=1/a and a=±1.\n\nThat's clever.
452249
When you added x to the right side, you should have gotten:\n\n4 = x^2\n\nThen take the square root of both sides to get\n\nx = 2, -2
212680
When you say "x2", I assume you mean "x^2" - that's how you say x-squared.\n\nYou have to factor, so use reverse FOIL. Set up:\n\n(__ +/- __) (__ +/- __)\n\nYou know what needs to go in the first blank in each parenth to get x^2 (don't you?), so start there, then addends for -14, then see what happens when you square those addends.\n\nYou can do this.
420210
I'm Ioana and I think I can help because I have  been doing this since the fift grade here in Romainia.So , because that in your equation the number below the fraction line is the same you can say 4/x.In other case you have to amplify to get the same number below the fraction line.Now you take 2 and put it at the other side of  the equal so  4/x=7-2 from were results that 4/x=5.Now 5 is a natural number so if you want to write it as a fraction (in this case u need)you say 5/1.Now try writing it like this  4 =5\n        -    -\n       x    1\nit is the same thing.Now yo multiply on the diagonaly.So u get \n5x=4  .Remember what I said earlier.When you change the position of a number to one side or other of the equal ,the mark changes too exactly the oposite.So for - you have + and for / u have multiplication.Get it ?So the final form is x=4/5.Tell me if it works out .My adress is janne1992@yahoo.com.\n\nIoana
581497
D\n\nSeriously, what class are you in? Algebra? Geometry? You chould know this!! It's the pythagorean theorm- [a2 +b2 =c2] (2's = squared).  You have a and b, the two adjacent sides of the triangle.  Therefore, it is the square root of 50, or approx. 7.07.  Thats SUPER important, make sure you remember it!
636318
when you switch -x to x, you are multipling by -1.  This needs to be done to both sides of the equation.  One of the rules of algebra is that when ever you multiple or divide both sides of the equation by a negative number, you must flip the > to a <, or the < to a >.  So...\n\n-x > -2/3\n-x * -1 < -2/3 * -1\nx < 2/3\n\ni hope that helps!
530970
The square root of a fraction is the square root of the numerator over the square root of the denominator.\n\nSo if you have sqrt(9/25) that is equal to sqrt(9) / sqrt(25) = 3/5.\n\nThat's the easy case where everything works out cleanly.\n\nLet's try another example of sqrt(7/100).  This is equal to sqrt(7)/sqrt(100).  The bottom works out nicely to give you sqrt(7)/10.\n\nThat's about as far as you can go to simplify it, so your answer is\nsqrt(7)/10.\n\nNow the other case is where you get a sqrt in the denominator.\n\nsqrt(4/7) = sqrt(4)/sqrt(7) = 2/sqrt(7).\n\nHere we don't like to leave sqrt(7) in the denominator, so multiply top and bottom by another sqrt(7).  Notice how this is equal to 1 so you aren't changing the value.\n\n2/sqrt(7) = 2sqrt(7) / sqrt(7)sqrt(7).  And what happens if you multiply sqrt(7) * sqrt(7)?  You just need to remember that sqrt(a) * sqrt(a) = a.  In our case we have sqrt(7) * sqrt(7) = sqrt(49) which is simply 7.  So the final answer is:\n2 sqrt(7) / 7.\n\nFrom the website:\nsqrt(1/2) = sqrt(1) / sqrt(2) = 1 / sqrt(2).\n\nMultiply top and bottom by sqrt(2):\nsqrt(2) / sqrt(2) * sqrt(2)\n= sqrt(2) / 2
123410
-3 + sqrt(2) or -(3 - sqrt(2))\nthats like saying\n\n-1x, 0x, 1x\n\nthe answer is problem found like this\n\n2x, 3x, 4x\n\nso i believe the answer is \n\n6 - 2sqrt(2), 9 - 3sqrt(2), 12 - 4sqrt(2)
430373
You asked about the numerator before, didnt you get an answer?\nWith synthetic substitution, you should find that the roots of the numerator are -1, -1, -2, and 3.\nThis gives (x+1)(x+1)(x+2)(x-3)  see *.\n\nAre you sure you typed the denominator correctly?\nYou typed: \nx^6 - 6x^5 + 15x^4 - 30x^3 + 15x^2 - 6x + 1\n(by the way, you need to insert spaces into long polynomials like this one or Yahoo does not display them after 30 spaces.  You can place the mouse cursor over them and see the complete polynomial, but many people dont know that, including the previous answerer.)\nThis is not factorable (over the rational numbers)\n\nHowever, if one digit is changed, namely if -30x^3 was written \n -20x^3, then the denominator becomes a very common one (and one that you may notice just by looking at it if you stay at this factoring stuff for a long time):\nnamely (x-1)^6 !!\n\n\n*\n1st root (-1):\n\n-1 || ..1... 1 ... -7 .. -13 ... -6\n...............-1 .... 0 ..... 7 ..... 6\n————————————\n..........1....0.....-7.....-6... || 0\n\nso (x+1) is a root\n\n2nd root (-1):\n\n-1 || ...1....0.....-7.....-6\n................-1 .... 1 .... 6\n——————————\n..........1...-1 ... -6 .. || 0\n\nso (x+1) is a root again.\n\nx^2 - x - 6 remains\n= (x-3)(x+2)\n\nInteresting correlative problem:\nhttp://answers.yahoo.com/question/index;_ylt=Aqz3W3s3NPcz.j__CQYxK0bsy6IX?qid=20061127003230AA2oHuA
371717
Many mathematical operations have an inverse, or opposite, operation. Subtraction is the opposite of addition, division is the inverse of multiplication, and so on. Squaring, lesson (exponents), has an inverse too, called "finding the square root." Remember, the square of a number is that number times itself. The perfect squares are the squares of the whole numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 … \nThe square root of a number, n, written \nsquare root of n\nis the number that gives n when multiplied by itself. For example,\nsquare root of 100 =10\nbecause 10 x 10 = 100\nFinding square roots of of numbers that aren't perfect squares without a calculator.\n1. Estimate - first, get as close as you can by finding two perfect square roots your number is between.\n2. Divide - divide your number by one of those square roots.\n3. Average - take the average of the result of step 2 and the root.\n4. Use the result of step 3 to repeat steps 2 and 3 until you have a number that is accurate enough for you.\nExample: Calculate the square root of 10 to 2 decimal places.\n1. Find the two perfect square numbers it lies between.\nSolution:\n3 squared = 9 and 42 = 16, so the square root of 10  lies between 3 and 4.\n2. Divide 10 by 3. 10/3 = 3.33 (you can round off your answer)\n3. Average 3.33 and 3. (3.33 + 3)/2 = 3.1667\nRepeat step 2: 10/3.1667 = 3.1579\nRepeat step 3: Average 3.1579 and 3.1667. (3.1579 + 3.1667)/2 = 3.1623\nTry the answer --> Is 3.1623 squared equal to 10? 3.1623 x 3.1623 = 10.0001\nIf this is accurate enough for you, you can stop! Otherwise, you can repeat steps 2 and 3.\nNote: There are a number of ways to calculate square roots without a calculator. This is only one of them.
533569
if it is square root of (x-2) then\naccording to the question x must be >\nwe have \n3 square root (x-2) > 0\n5x > 10\n=> 5x + 3 square root x-2 > 12 >0\nso this equation has no real root\n\nor\n\nlet t be square root of x , t here must be > 0\nwe have : 5t^2 + 3t -2 =0\n=> t = -1( <0 not acceptable ) or t = 2/5 ( acceptable )\n=> square root of x = 2/5 => x = 4/25
506075
The answer is:  4.47, and that's all there is to it!\n\nOk Vanessa, all you have to do is pull up your calculator (Start>Accessories).\nI am not suggesting you don't work it out in your head first: it's just basic. Check the answer on the calc, or, if you get stuck....go back.... to POWERS OF HIGH HOLY ROOTISM   SQUARE YOU KNOW, 1x1+(2x2)+2+(10-5)/1=       Simple:\n1+4+2+5/1=12
262401
are u sure its not supposed to be the other way around. Cuz that would make a little more sense.\n\nBut if not, then it would probably be:\n1 + ((4s squared - 11) / (s to the 4 - 3s squared -11))\n1 the quotient. the rest the remainder.