p(x) = 2x^4 =5x^3 – 3x^2 -2x -6\n\nA. x-3\nb. x +3\nc. 2x^2 –x-2\nd. 2x^3 –x^2 -2\ne. both b,d\nf. b and c
201435
You probably mean\np(x) = 2x^4 +5x^3 – 3x^2 -2x -6\nThe answer is e) Both b,d\nbecause when you multiply the factors you should get the original expression and (x+3)(2x^3 –x^2 -2)= 2x^4 +5x^3 – 3x^2 -2x -6\nThis was quickly seen because you need x^4 which is only obtainable by x multiplied by x^3 in your problem :)\nHope this helps
345628
if you want:\n(6x )^2 (2x)^3\n= 36 x^2 ( 8 x^3)\n= 36(8) x^5\n\nif you, instead, want this: \n(6x^2)(2x)^3\n= 6 x^2 (8 x^3)\n= 48 x^5\n\ns
329344
3x + x - 5 = 2(x-2)\n4x - 5 = 2x - 4\n2x = 1\nx = 1/2\n\n2) 6a^3 b^2 c / [2abc]\n= 3a^2 b\n\n3) 8x^2 y z^3 / [12x y^2 z]\n= 2xz^2/[3y]
339421
1.4x^2-3x-1=0\nx= (3+- sqrt(9-4(4)(-1) ) )/2(4)\nx=(3+- sqrt(25) )/8\nx=(3+- 5)/8\nx= (3+5)/8 =1 or x=(3- 5)/8 = -1/4\nthen \n4x^2-3x-1 = (x-1) (4x+1) =0\n\n2.(x^2-14)/(x-2)(x+2)+3/(x-2) =  4 / (x+2)\n [ (x^2-14)+3(x+2) ]/(x-2)(x+2)= 4 / (x+2)\nmultiply the equation by (x-2)(x+2) then we get:\n(x^2-14)+3(x+2) = 4(x-2)\nx^2 +3x -4x -14 +6 +8 =0\nx^2 -x =0\nx(x-1) =0\nso x =0 or x=1\n.
480807
(px+2)(3x+q) = rx ^2 + x - 2\n\n(3p)*x^2 + (pq+6)*x + 2q =  rx ^2 + x - 2\n\nComparing coefficients on both side: we have\n\n2q = -2 , q = -1\n\npq+6 = 1, p(-1) + 6 =1 , p = 5\n\n3p = r , r = 3*5 = 15\n\nTherefore the solution is p = 5, q = -1 and r = 15\n\nHope it helps!
591559
[2x/(x+3)(x-3)]*[(x-3)/4(x)]\ncancelling 2 and x-3 we will get\n=x/(x+3)2(x)\nsimplify we will get\n=x/(2x^2+6x)
658768
(x+5)(2x^2+4x+2)\nx(2x^2+4x+2)+5(2x^2+4x+2)\n2x^3+4x^2+2x+10x^2+20x+10\n2x^3+14x^2+22x+10
388678
use remainder theorem\nhttp://en.wikipedia.org/wiki/Remainder_theorem\n"When p(x) is divided by (x-a), the remainder is p(a)"\nUR QUESTION:\np(x) = x^3+3x+k\n(x-a) = (x-1)\np(a) = 6\nhence, p(1)=6\nso, (1)^3 + 3(1) + k = 6\nhence, 1+3+k = 6\nso, k = 2\n\nhence, k = 2
625828
gurl am not helping out with ur homework next time.\n f(x) =/x/ +3x +1\n       =x+3x+1\n       = 4x+1\n\n  f(x)=3x+/2x-5/\n       = 3x+2x-5\n       =5x-5\n\n  g(x)= /x/+/x-1/\n        = x+x-1\n        =2x-1\n\n  g(x)=3/x-2/ - /x+1/\n        =3(x-2) - x+1\n        =3x-6-x+1\n        =2x-5
444549
1) -2 x (2/5 -2p)\n    =4/5+4p            after multiplying through by -2\n\n2) 1 x (9/20 -p)\n    =9/20-p              after multiplying through by +1\n\nThis has started you off you should be able to solve now!
117654
1) First we move all the factors with x to one side, and the ones without x to the other.  Result will be:\n\n4x/3 - 2x + x = 3/2 + 1/5\n\n2)  Then, we factor out an x from the left side and get:\n\nx(4/3 - 2 + 1) = 3/2 + 1/5\n\n3)  Calculate the actual numbers on both sides\n\nx(4/3 - 6/3 + 3/3) = 15/10 + 2/10\nx(1/3) = 17/10\n\n4)  Divide both sides by 1/3 and get a final result of...\n\nx = (17/10)/(1/3)\nx = (10/17)*(3/1)\nx = 30/17\n\n5)  Comform that I PWN n00bs.  And... I'm pretty sure I pwn n00bs.  Therefor, we are done!  ^-^
138480
ok well you know that, since P(3)=0, that (x-3) HAS to be a factor of it. so you divide the whole equation by x-3. \n\n''''________________________\nx-3 ) 4x^3 - 9x^2 - 10x + 3\n\nfirst step is to divide 4x^3 by x, andyou get 4x^2. then you take this and multiply it by x-3 and you get 4x^2-12x^2\nwrite the 4x^2 in the answer section, and the other thing under the polynomial and subtract.\n\n\n''''_________4x^2___________\nx-3 ) 4x^3 - 9x^2 - 10x + 3\n''''''4x^3 -12x^2\n''''''''''''''3x^2 - 10x\n\nnow divide 3x^2 - 10x by x-3 and do the same thing.\n\n''''_________4x^2 + 3x - 1_\nx-3 ) 4x^3 - 9x^2 - 10x + 3\n''''''4x^3 -12x^2\n''''''''''''''3x^2 - 10x\n''''''''''''''3x^2 - 9x\n'''''''''''''''''''''-x + 3\n'''''''''''''''''''''-x + 3\n''''''''''''''''''''''''''0\n\nso after you divide, you get 4x^2 + 3x - 1 and you can factor this easily. \n4x^2 + 4x - x - 1\n4x(x+1) - (x+1)\n(4x-1)(x+1)\n\nso the final factored form of 4x^3-9x^2-10x+3 is \n(x-3)(x+1)(4x-1). so then the factors of P(x) are x=3, x=-1,\nand x=1/4.\n\nhope that helps. laterz
79723
1. x^+6x-5=0\n\n2. 3x^+10x+8=17x-2\n(x-6)(x+1)\n\n3. x^+3x-40=0\n(x-5)(x+8)\n\n4. x^=10x-24\n(x-6)(x-4)\n\n5. p^+15p+25=6p+5\n(p+5)(p+4)
276292
Try factoring each one.\n5x^3 - 15x^2 = 0\n5x^2(x-3) = 0 means\n5x^2 = 0 or x-3 = 0\nx = 0 or x = 3\n\nx^3 + 2x^2 - x = 2\nx^3 + 2x^2 - x - 2 = 0\nFactor by grouping.\n(x^3 + 2x^2) + (-x - 2) = 0\nx^2(x+2) + (-1)(x+2) = 0\n(x^2-1)(x+2) = 0\n(x-1)(x+1)(x+2) = 0\nx = 1, -1, or -2\nNow try the others on your own.
12790
x^6-3x^4-4x^2 = 0\nx^2(x^3-3x^2-4)= 0\nx^3-3x^2-4 = 0\n(x^2-4)(x+1)\n(x-2)(x+2)(x+1)\nSO, x = 2,-2, or -1\n\nI don't think ur "correct answer" is correct, sorry\n\nhope this helps!
415430
(x+3)(x^2+2x+4)\n\nStart by taking the first term in the first parenthesis and multiplying it by each term in the second parenthesis:\n\nx*x^2 + x*2x + x*4 = x^3 + 2x^2 + 4x\n\nNow take the second term and multiply it by each term in the second parenthesis:\n\n3*x^2 + 3*2x + 3*4 = 3x^2 + 6x +12\n\nNow add all of that together\n\nx^3 + 2x^2 + 4x + 3x^2 + 6x +12\n\nand combine terms\n\nx^3 + 5x^2 + 10x +12
363551
a.xa+xb\nb.21x^3+24x^2y\nc.3x(8x+5)+2(8x+5)\n=24x^2+15x+16x+10\n=24x^2+31x+10\nd.4x(2x+1)-6(2x+1)\n=8x^2+4x-12x-6\n=8x^2-8x-6\ne.8x(5x^2+7x+3)+2(5x^2+7x+3)\n=40x^3+56x^2+24x+10x^2+14x+6\n=40x^3+66x^2+38x+6\nf.x^2-1\ng.x(x^2+2x+4)-2(x^2+2x+4)\n=x^3+2x^2+4x-2x^2-4x-8\n=x^3-8