The Formula of the cylinder is V=1 over 3 or 1 over 3 times 3.14 times the radius to the second power. Plz help me out i need this by tommorrow
203675
Volume of a cylinder, V = pi * r^2 * h\n\nV = pi * 18^2 * 8\nV = pi * 324 * 8\nV = pi * 2592\nV = 8143 cubic inches OR 4.71 cubic feet
616592
The amount of air is the difference in volumes.\nA = V(r+1) - V(r) = (4/3)pi (r+1)^3 - (4/3)pi r^3\nA = (4/3)pi((r+1)^3 - r^3)
547788
volume of a cylinder is pi x r^2 x h\nr= radius of the top and h is height\nso volume is 3.142 x 2.5^2 x 10 = 196.35 cubic inches\n\nso this is the amount of jelly it can hold
147876
The formula is as follows:\n\nC\n- = pi\nd\n\nC=the circumference\nd=the diameter\nand pi=3.14\n\nThe next step is to put all the known information into the equation:\n\nC\n- = 3.14\n14\n\nOnce you have that, you can multiply 14 by both sides to get C alone. Like this:\n\n14( C/14) = (3.14)14\n\n14 is canceled on the side with C, and the you take 3.14 and multiply it by 14 to get 43.96. So now the equation looks like this:\n\nC = 43.96\n\nAnd there you have your answer. The circumference of the circle with a diameter of 14 is 43.96\n\nHope this helped.
407635
Great "How fast is the car moving" formula.  \nd = vt + 1/2 at^2\n1/2 at^2 = d - vt\nat^2 = 2d-2vt\na= (2d - 2vt) / t^2
466349
The basic formula that we know in circular motion is:\n\nF=mv^2/r, \n\nwhere F is the centripetal force, m the mass, v is the linear velocity, and r is the radius.\n\nWe also know that v=wr\n\nwhere v is the linear speed, w (supposed to be omega) is the angular velocity, and r is the radius.\n\nSubstitute the value of v in our first formula:\n\nF=m(wr)^2/r\n F =mw^2r      Formula 1)\n\nIn this problem, we also know that w which is the angular velocity is the same for m1 as for m2 because they are located along the same line which is rotating about one end of the rod.\n\nWe are also given the value of the tension in the inner section as 3x that of the outer section. Let's draw a simple free body diagram:\n                  \nT1=3F2<----0-->T2=F2<---0\n\nThe first 0 is m1 and the second 0 is m2.\n\nThe diagram might get distorted when I send it, but let's just cross our fingers it comes out clear enough.\n\nThe net force acting on m1 is (3F2-T2). But T2=F2. \nTherefore, net force on m1 =3F2-F2=2F2. Let's call\nthis net force as F1. Thus F1=2F2. Now we also know\nthat \n\nF1=m1w^2r    \nbased on formula 1) above.  Now substitute the value of F1=2F2, and we get:\n\n2F2=m1w^2r   Equation 1)\n\nAnd based on the same formula F=mw^2r:\n\nF2=m2w^2(2r)    Equation 2)\n\nRemember that for m2 the radius is twice that of m1, which is a given condition in this problem.\n\nNow divide equation 2 by equation 1:\n\nF2=m2w^2(2r)\n------------------\n2F2=m1w^2r\n\nF2,w^2, and r will cancel out leaving:\n\n1/2=2m2/m1\n\nDivide both sides by 2:\n\n1/4=m2/m1\n\nm2/m1=1/4\n          =0.25
543198
Your basic equation for volume is \nV = Pi * R^2 * H        (this is the answer to part B)\nIf you put the values for radius and hight into that equation you have\nV = Pi * 4 * 6\nWe know Pi is 3.14159, so the equation solves\nV = 75.39822369\nI think you mistyped the 6 when aiming at the 9.\n\nYour constant is Pi.\n\nPutting the values for R=3 and H = 5 into that equation will get \nV = Pi * 3^2 * 5\nV = 3.14159 * 9 * 5\nV = 141.372
54546
OK, I love a good math problem, here goes...\n\nVolume of cylinder is PI r^2 h.\n\nHeight of cylinder is h.\n\nRadius of cylinder if sqrt (R^2 - h^2).\n\nThus volume of cylinder = PI (R^2 - h^2) h. This is equal to PI R^2 h - PI h^3.\n\nTo find maximum, find derivative and set equal to zero, or\nPI R^2 = 3 PI h^2.\n\nThis in turn simplifies to h = R / sqrt (3).
553842
The moment of inertia of a solid cylinder is 1/2 mr ^2..\nTorque is the product of moment of inertia and angular acceleration.  It can also be expressed as the product of the force applied to the edge of the disk and the radius.  Set the two products equal to each other and solve for m.\n\nT = I α = r F\n\n1/2 m r ^2 α = r F\n\nm = (r F) / (1/2 r ^2 α)  = 2 F / r α\nm = 2 (40) / 0.16 (90)\n\nm = 5.56 kg
505366
Imagine the center of the triangle. Draw a line segment from it to a vertex, and then one from the center to a midpoint of a side. This makes a 30-60-90 triangle, so the line segment is (p/2) sqrt(3). This is a radius of the cylinder, so we multiply it by 2 to get the diameter.\n\nd = p sqrt(3)\n\nor, as the question wants it\np = d/sqrt(3) = d sqrt(3)/3
429675
The translational energy is equal to 0.5 * mass * (velocity)^2, or\n\n0.5 * 12 * 12^2 = 864 J\n\nThe rotational kinetic energy is equal to 0.5 * (moment of inertia) * (angular velocity)^2.\n\nThe moment of inertia for a cylinder is 0.5 * (mass)*(radius)^2\n\nThe angular velocity is the (velocity)/(radius).\n\nso substituting in gives:\n\n0.5 (0.5 * mass * radius^2) * (velocity/radius)^2\n\nthe radius^2 factor will cancel leaving\n\n0.25 * mass * velocity^2 or\n\n0.25 * 12 * 12^2 = 432 J\n\nTotal energy is the sum = 432 + 864 = 1296 J.
472041
V cone = ⅓πr²h\nh/r = 50/30 so h = 5r/3 and r = 3h/5 so when h = x, r = 3x/5\nThus V = ⅓π(3x/5)²x\n= 3/25 * πx³\nWhen h = x, dx/dt = (50 - x)\nSo dV/dt = dV/dx * dx/dt\n= 9/25 * πx² * (50 - x)\n\nFor the rectangular tank\n\nV = Ah\n= 400h\ndV/dt = dV/dh * dh/dt\n9/25 * πx² * (50 - x) = 400 * dh/dt\n\nSo dh/dt = 9/10000 * πx² * (50 - x) \nwhen x = 10\ndh/dt = 9/10000 * π * 10² * (50 - 10) \n= 9/10000 * π *100 * 40\n= 18π/5 in/min
350472
Vt is the source with R1 and R2 in series\n\nIt=Vt/(R1+R2)\n(OHMS LAW)\n\nIt=12/(120)\n---------------\nIt=0.1 A\n-------------\n\n\nVr2=Ir2 *R2\n     = It *R2\n     =0.1 * 100=10v\n\n------------------\nVr2=10 v\n------------------\n(So,Vr1=Vt(total)-Vr2=12-10=2 V)
504558
use the formulas your given\nto find the volume of the cylinder\nthen pretend the semi hemi on  the top is a sphere find the volume and multiply by 1/2\n\nadd two totals to find volume
673698
The volume of the sphere is 4/3*pi*r^3\n\nThe volume of the cylinder is pi*r^2*h\n\nSince the cylinder's h is the same as 2r, then the volume becomes pi*r^2*2r which is the same as 2*pi*r^3.\n\nThe fraction of the space taken up by the sphere is the same as:\n\n4/3*pi*r^3\n-------------\n2*pi*r^3\n\nwhich is the same as:\n\n4/3\n----\n2\n\nwhich reduces down to 2/3
324
Volume of cylinder = area of base * height.\nSince the base is a circle, that part is Pi *r^2\nSo we have Pi * r^2 * height --> \n3.14 * 12^2 * 21 = ?\n\nVolume of square prism = area of base * height\nSince the base is a square, that part is side^2\nSo we have 12 * 12 * 21 = ? \n\nSubtract the results for your final answer.
542845
Let the radius of the sphere be R.\nLet x be the radius of the cylinder.\nThen height of half of the cylinder= sqrt(R^2-x^2)\n\nTotal surface area of cylinder = 2*pi*x^2 +2*pi*h, so\nS=2*pi*x^2 +2*pi*2*(R^2-x^2)^.5  [Eq I]\ndS/dx=4*pi*x + 4*pi*.5*(-2x)(R^2-x^2)^-.5\n=4*pi*x - 4*pi*x/(R^2-x^2)^.5\n=4*pi*x(R^2-x^2)-4*pi*x =0\nR^2-x^2-1=0\nx^2=R^2-1\nx=+ or - sqrt (R2-1)\nPlug these values of x into [EQ I] to get answer.