There is one junior, one freshman, one senior and two sophomores in a group, what percentage of this group is NOT juniors\n20%\n40%\n60%\n80%
210304
80%. There is 1 junion, 1 senior, 1 freshman, and 2 sophomores. 1 + 1 + 1 + 2 = 5, and 1/5 are juniors = .2 - 1 (or 100%) = 80% of them are not juniors.
495872
Answers:\n\n2 168\n2  5\n4  15%\n4  23.1%\n3  70
505114
If 4/7 are male, then 3/7 are female.\n\nLet x be the total number of students:\n(3/7)x = 3,600\n\nMultiply both sides by 7/3:\nx = 3,600 * 7/3\n\nSimplify:\nx = 1,200 * 7\nx = 8,400 students total
208010
You need to know the total number of boys.\nThen take 4 divided by the total number of boys.\nThis will give you the probability.\nMultiply by 100 to get the percent.
28773
Here in Slovakia, we use a simple formula to calculate percentages.  And yes, there are 3 kinds of percentage problems, but the formula applies to all of them, you just have to play with it a little bit.\nOkay, problem no. 1: there are 35 kids (total = T) in a class, 40% (P as in percentage) of which are boys.  How many (value = V) boys are there?\nHere's the formula:\nV = T/100*P\n(V = 35/100*40 = 14)\n\nProblem no. 2: there are 14 boys and 21 girls (T = 14 + 21)in the class.  What's the percentage(P) of boys (V)?\nSame formula as before, really:\nP = V/(T/100)\n(P = 14/(35/100) = 40%)\n\nProblem no. 3: how much did your shoes originally cost (T) if your 10% discount (P) meant $2 (V) off?\nSame formula:\nT = V*100/P\n(T = 2*100/10 = $20)\n\nOnce you know which is P, V, and T, you're fine.  You don't necessarily have to remember the formulas.
298048
I belive it is just a percent of the total graduating class, so...\n\n5% = 28 or lower\n10% = 57 or lower\n25% = 144 or lower\n33.3% = 193 or lower\n50% = 289 or lower\n\n*****\noops!, lower, not greater... da!\n\n*****\nand everyone else (for the most part) is right, you are sitting at about 23%... and to get that, you do indeed take (136/579)*100 = % the same formula can be applied to find anyone's position... n/579*100=% (where "n" equals that persons "rank")...\n\nby the way, congradulations, welcome to the real world, my suggestion would be to move on, get a college degree, and at that point, high school will seem insignifigant... I graduate college in about 2 weeks, yay!!!... for my area of study, I am about one of five people graduating... my class started with almost 40 people, and I will be either #2, or #3!!! sweet!
515535
If you don't know the answer to this, I'm guessing you are not in the 22% category.\n\nIf 22% passed, that's .22(68) or 14.96.  I'll give that last student the benefit of the doubt, and assume s/he is a whole person.  So that's 15 students that passed.\n\nIf there were 68 students, and only 15 passed, that leaves 53 that failed.  68 - 15 = 53.\n\nAnd she or he is a damn tough teacher.
291634
Freshman(9th grade), Sophmore(10th grade), Junior(11th Grade) Senior(12th grade)
541604
First the probability that a family of 4 is all girls is:\n1/16 (and the chance that they are not is 15/16).\n\nRather than figuring the chance of at least one family having this arrangement, figure the probability that *none* of the families do.  Then subtract from 1.\n\nThe answer will be 1 - (15/16)^10\nor about 47.6%\n\nIt's not a simple multiplication by n... if it were, then with 16 families you should have a 100% chance.  And with 32 families you would have a 200% chance.  That logic would be correct if you couldn't repeat a combination, but you can.  Just because family A has four boys, for example, doesn't mean family B can't also have four boys.\n\nLabel the 10 families as A, B, C, D, ... , I, J.  The probability that A has four girls is 1/16.  The probability that B has four girls is 1/16, etc.\n\nThe chance that *none* of them have four girls is 15/16 x 15/16 x 15/16 x ... x 15/16.  This is (15/16)^10 or about 52.4%.  Therefore the chance that at least one of them has four girls is 100 - 52.4 or 47.6%
166713
* How many people are there?\nA> Total seating capacity of the cars is 3200x4 + 4000x6 = 36800.\nIf, by (80% of the cars are full" you mean 80% of all cars, as an average, then total number of people = 80% of 36800 = 29440.\n\n* How many 4 seaters are there?\nA> 3200 (as mentioned in the question itself)\n\n* What is the combined driving time of all the cars?\nA> Total time is as follows:\n38% of all people live to 53 => 11187.2 live to 53 => lifetime = 11187.2x53 = 592921.6 years\nSimilarly, the numbers in the other cases are 31795.2, 194304, 296755.2 & 503424 years respectively. Adding, we get 1619200 years.\n\n* How many people are there of each age group?\nA> 53 : 38% of 29440 = 11187 and so on.
78646
780\n\n***To all the people below me who answered something other than 780.  GO BACK TO SCHOOL!
422517
Your data set would look like this:\n\n10 10 10 10 10 10 10 10 10 10 20 20 20 20 20 20 20 20 235 235\n\nThe mean is 730/20 = 36.5.\nThe median is (10+20)/2 = 15.\nThe mode is 10.\n\nSo certainly what was stated by the dean isn't a lie.\n\nNow, if I were to calculate, say, the average number of classmates for each person in the statistics classes, there would be 100 9's, 160 19's, and 470 234's.  So the average number of classmates for people taking these classes is approximately 113,920/730 = 156.05.  The median is 234 and the mode is also 234.  So the newspaper isn't really lying either.\n\nI guess you can say that they are looking at this from two different perspecitves, so in that sense, there are two truths.
121585
several classes (100 students)of 6th graders went on a field trip to the zoo. 1/5 of them went to c the monkeys. 1/2 of them visited the penguins. 1/4 went 2 c the bats. and the rest went to the snack bar. how many students went to the snack bar? if u hav a heart. u will help \n\nwell...i got 5 students went to the snack bar...\n1/5 of 100=20\n1/2 of 100=50\n1/4 of 100=25\nso \n  20+50+25=95\n  100-95=5 students\n~Brendon
563707
About 11-13% \n\n\n\n--- LeeeN
181631
#1)  We know that 80% were not festive (100% total -20% festive).  Use the equation Percent x of = is.\nIn this case .80 x People at fair = 1400. OR:\nPeople at fair = 1400/.80 = 1750\n\n#2) Same as above\nTotal = 160/.4 or 400\nWood nymphs = 400-160 = 240\n\n#3)Last years + 45% of Last years = This years\nLY + .45LY = 140795 or\n1.45LY = 140795 or\nLY = 140795/1.45 or 97100\n\n#4) % killed x Legion = # Killed\n.10 x L = 590 or\nL = 590/.1 or 5900\nLeft = Legion - killed\nLeft = 5900-590 or 5310
151184
The part is of 16% of 3500 is 560!\nThe whole of 400% of 4 is 16!\n\nThe answer to both of the questions is the problem in the question itself.\nEXAMPLE:  PART:  ? of 3500 =560\n               16% of   ?  =560\n               16% of 3500 = ?\n         WHOLE:16% of 3500 =560\nSame with the latter question.  LOOK BEYOND THE QUESTION.
548013
This will be an exercise in factorials.  Generally, if you choose one from the list of 4 senior partners, there are (4 choose 1) ways to do this, which equals 4!/(1!3!) = (4x3x2x1)/(3x2x1) = 4.\n\nIf you choose 1 senior and 1 junior partner, you multiply the two selection numbers together: specifically 4 x 6 = 24.\n\nHere we go:\n\nOne senior partner trio: SJJ : 4!/(1!3!) x 6!/(2!4!) = 4 x 15 = 60.\nTwo senior partner trio : SSJ: 4!(2!2!) x 6!/(1!5!) = 6 x 6 = 36.\nAll senior partner trio: SSS: 4!/(3!1!) = 4.\n\nTotal = 60 + 36 + 4 = 100 different groups.\n\nHaving seen this you can trust me on your other probability question.