how would you prove that it is a right triangle?
214233
if the toothpicks are of the same length, you'l need a side of 3 t'picks, anther of 4 and the last one of 5.\n\nyou can prove it using the pitagorean theorem\na^2 + b^2 = c^2\n3^2 + 4^2 = 5^2\n9 + 16 = 25\n25 = 25
4491
sorry i made a mistake....this is correct...\ndivide the base by 2.  Now you have a right triangle.  the height is the same, but the base is now 3.  pygathora (spelling, whatever) theorm is A squared + B squared = C squared.  c is the side opposite the right angle, a and b are the other sides.  so 3 squared + 4 squared is 9 + 16 = 25. The square root of 25 is 5, so that is the length of the side.  the volume = area of base times height.  Area of a triangle is 1/2 base times height.  so 3 (one half of 6) times 4 = 12.  times this by height of 8 = 96 cubic units. largest rectangular side is the 6 (the longest side) times 8 = 48 units squared. hope this helped.  the lateral area is the area of the sides added together. so C times 8 = 40 (area of one side)  add the other side of equal area (the C from the second triangle we got when we split the first one) 40 + 40 = 80.  Add the third side of length 6 times 8 = 48.  80 + 48 is 128 (in units squared).  or all sides added up 5 + 5 + 6 = 16 times 8 = 128.
355681
Since the triangle is Isoceles, if you split the triangle down the middle you can turn in into a right triangle. You can use the Pythagorean theorem. (a^2 + b^2 = c^2.)\n\n13 will be the hypotenuse and 5 will be the base. To find the altitude you just fill everything in. \n\n5^2 + b^2= 13^2\n25 + b^2 = 169\nb^2 = 144\nb = 12
642983
Conclusion: If two sides of a triangle are congruent then the third side is also congruent.\nFirst you would state the 2 bottom given statements. then the third will be the conclusion I gave you.\n\nYou could also use the SAS congruency to show that two triangles are congruent. If the triangles are congruent then BC is congruent to DF.\nTHERE IS ALSO THE CPCTC.
389734
Let there be a right-angled triangle.\nnow, \nwe know that, \n(2n^2+2n+1)^2=4n^4 + 4n^2 + 1 + 2(4n^3 + 2n+ 2n^2)\n=>(2n^2+2n+1)^2=4n^4 + 4n^2 + 1 + 8n^3 + 4n+ 4n^2\n=>(2n^2+2n+1)^2=(4n^4 + 4n^2 + 8n^3) + (1 + 4n+ 4n^2)\n=>(2n^2+2n+1)^2=(2n^2 + 2n)^2 + (2n+1)^2\nThis gives solutions\n(3,4,5); (5,12,13); (7,24,25); (9,40,41)........................\nthe above relation is true for all n belonging to natural numbers\nthis way you can find solution for any pair of sides the 3rd side been given.\nput the given side equal to one in equation and find positive n by solving the quadratic and find all the sides.\nEg:If hyputenuse is given as 5\nSolve 2n^2 + 2n + 1= 5\n=>n=1 therefore other sides are 3 and 4\n\nChoose this as best, if correct.
46511
Use the Pythagorean theorem (twice).  The ray from the top light to the observer's eye is a straight line that just grazes the surface of the earth.  One right triangle has the following 3 sides: center of earth (COE) to surface (a known quantity), COE to top light (also known) and distance from tower to graze point (unknown).  The right angle is at the graze point.  Set up the other triangle similarly for the observer's eye, solve for the 2 unknowns, then sum them.
401459
You can write a paragraph proof, or a two-column proof.\n\nWrite an example, on here, and I'll try to help you out. =)
415065
If it's a right triangle, use the Pythagorean Theorem.\n\na^2 + b^2 = c^2\n\n\nA and B are the legs (the ones that touch the right angle), C is the hypotenuse which is opposite the right angle.\n\n10^2 + x^2 = 26\n\n100 + x^2 = 676\n\nx^2 = 576\n\nx = 24
614458
use pythagoras theorm,if left hand side is equal to right hand side then it is a right triangle.\n\nsince 8 is the biggest no here that means the length of hypotenues is 8. \n\nlet side 1 be a=4\nlet side 2 be b=4 sqrt(3)\nlet hypotenuese be c=8\n\naccording to pythagoras theorm,\n\n(a)*(a)+(b)*(b)=(c)*(c)\n\nL.H.S\n\n=4*4+4sqrt(3)*4sqrt(3)\n=16+48\n=64\n\nR.H.S\n=8*8\n=64\n\nsince L.H.S=R.H.S\n\ntherefore, it is a right triangle\n\nhope u understand it\nif u hv any prob u can contact me
532693
If you extend the non parallel sides to form a triangle it is right-angled as the other two angles are 33 and 57 and they sum to 90\n\nSo the requred median is a segment of a line jioning the vertex at the right angle to the midpoint of the hypotenuses of the two triangles so formed with the two parallel sides being these hypotenuses.\nNow in any right angled triangle this is the circumcentre of the triangle \nSo the distance from the lower hypotenuse to the vertex = ½ of 10 \n= 5\nAnd the distance from the upper hypotenuse to the vertex = ½ of 6\n= 3\nSo the length of the required median = 5 - 3 = 2 \n\nI think our friend above has the incorrect median.
374150
join AC\nnow youhavetwo triangles ABC and ADC\nin triangle ABC <CAB+<B+<ACB=180*.............(1)<s of a triangle\nin triangle ADC <CAD+<D+<ACD=180*............(2)--------do--------\nadding (1) and (2)\n<ABC+<ADC+<B+<D+ACB+<ACD=360*\n=><DAB+<B+<BCD+<D=360*\nhence proved
238702
I'm not giving you the answer, but Cos is adjacent over hypotenuse.  Also, if you wanted the question answered correctly, us answering people might want to know where all of the letters are in relation to the triangle.
526041
Yes, graph this. (0,0),(1,0),(1,1),(0,2)\nThere are two right angles and two sides of length 1, but the figure is not a parallelogram. It is only a trapezoid.
436234
multiply the tangent of the given angle by the known side as long as it's not the sloping side (i.e. the hypotenuse). You will need a scientific calculator to do this. I am assuming of course that you are dealing with a right triangle. This will give you the other side of the triangle. Example:\n\nlets say you have side A of a right triangle and an angle of 30 degrees and A = 10. Take your scientific calculator press 30 and then the tan button depending on the type of caculator you have. Now multiply that result by 10 and you will get side B.\n\nSide C is found by A^2 + B^2 = C^2. take the square root for your answer.\n\nNow if the given angle is opposite the given side. Just calculate the angle of the given side by adding the given angle to 90 degrees and subtract the result from 180, and then multiply the tangent of the new new angle by the given side.\n\nTheoretically you can check the answer by multiplying the new side by the tangent of the new angle. You should in theory get the given side. But my trig is so rusty I may have forgotten more than  you will ever know. good luck.
382135
ACD is a right triangle, CD = 2, AD = 4, so AC = 2 sqrt [5]\n\nABD is a right triangle, BD = 3, AD = 4, so AB = 5.\n\nBC = BD + CD = 5\n\nABC is an isosceles triangle, so BH bisects AC.\n\nAH = 1/2 AC = sqrt[5]
255052
A right angled triangle with short sides of 7cm and 11cm would have a long side (hypotenuse) of √(7²+11²)\nSo the square of the length of the longest side would be \n49 + 121 = 170 \n16² = 256, so this side is too long to make a right-angled triangle - the two short sides would have to open up a bit - making an angle greater than 90°...\n\nI have heard of a right angled triangle, but acute and obtuse are used to describe angles, in my experience...\nAs the internal angles in a triangle sum to 180°, clearly if one angle is obtuse or 90°, the other two must be acute.\nThe question may be referring to one specific angle in the triangle - so the answer is here, anyway!
401587
1. cosθ=A*B / (|A|*|B|)=(1*5+0*2+3*6) / 5√ 26\n            =81.171\n\n2. assume the angle of vectors of a and b is "m"  \n   so cos m= a*b/(|a|*|b|)=0   because cos90=0\n   m=90...so it is a right triangle...\n   |a| and |b| are representing the right-angled sides of the triangle.\n   |a|=√17; |b|=√26\n   S=|a|*|b| / 2 =10.5\n\n3. P(1,3,5) to cylindrical coordinates.......\n                         r=√1+9 =√10....\n                         θ= tan^(-1)3=71.6\n                         z= 5 \n       In terms  of x , y , and z\n                         x= r.cosθ =√10*71.6 =226\n                         y= r.sinθ = 0.95*√10= 3\n                         z=5\n                        so its (226,3,5)\n            ditto, T 's doesn't have cylindrical coordinates \n                     S 's cylindrical coordinates is (0.6, -0.8, -10)\n  ......................(that's all i know..)