I would like to know what is the relationship between capacity & cost so I can chose 1 or 2 equipments with lower cost for example if I want to get an electrical generator of 2MW shall I get 2 electrical generators with 1MW or One electrical generator with 2 MW
212923
for generators , we choose like this , if the load is 1 MW , then we choose two of 60-75% each , according to budget and power failure problems , also the life time for a machine to be considered for 12 yrs , 8-10% depreciation yearly
148901
This question is a little tricky. Work is the product of FORCE X DISTANCE. Work is energy that has been used or transferred. Work is accomplished when force acts through distance. For example, when a force of 1 pound acts through a distance of 1 foot, 1 foot pound of work is accomplished. \n\nI will have to go with Answer D,  it would be a better chose if the question was about something like motor efficiency. The efficiency of any type of machine is the ratio of the output power to the input power. This ratio is commonly expressed as a percent. Because all machines have some losses, the efficiency will never be 100 percent. \n\nEfficiency = (output/input) X 100\n\nEfficiency = [output / (output + losses)] X 100\n\nor\n\nEfficiency = [(input - losses)/ input] X 100
616061
Im sorry but you have not supplied enough information for me to answer this question properly. You need to be more specific as to where your measuring the 70 MW from....\n\n Heres a good reliable motor set up anyways....\nThe FT4C-3F Twin Pac generating unit consists of two Pratt & Whitney C-3F engines. The Mitsubishi generator is rated at 70 MVA at ISO. The base load power output is 58 MW at ISO conditions or 48.5 MW at 90 degrees F. \n\n..
113979
if you produce more, it costs less to produce each item... take a look at answers.com and type in: "economy of scale", it explains it well there.
294936
Most generators are rated in watts. If you have a 50 amp circuit, then 110 volts x 50 amps = 5500 watts. You do not want to run the generator past 80% of its duty cycle, so a 6000 watt gen should be the best.\nHope the formula helps\nYou can also figure out how many watts a microwave will need. I it takes 10 amps at start up then 10 x 110 = 1100 watts.\nThus a 60 watt light bulb would take 60/110= .54 amps
176518
If there is demand, there will be supply. They work side by side. One cannot exist without the other. As one increases or decreases, so will the other. Not always at the same rate of increase or decrease. This rule determines cost of production & selling price. On a simple grid, using a X & Y axis; where they cross is the selling price.
572706
Power = work done per unit of time.\n\nP=W/T
377973
The fuel should increase to take the load. My experience is on turbine generators, one was 9 mega. WATS.
343186
Depends on how much each costs and how many people are going to be living there.  For me, smaller house with extras, but I don't need a big house.  Also, smaller house usually means smaller utility bill, and I'm all about that.
330497
The deciding factor here would be the Utility Company Service Entrance. THAT cannot be rewired by you! The other two points ( Low side of transformer and Motor Windings) can easily be configured either way by simply rewiring the 3 windings on the motor, and the 3 windings on the output of the transformer.\n\nOptimum efficiency will be DELTA-DELTA-DELTA or STAR-STAR-STAR...Either way no 'ground loops' to cause loss.
94238
a compound machine would involve multiple mechanical devices.  For example a pulley connected to a lever which is connected to a gear system would be a good example.  This would be used possible to mechanically lift a load.
384294
kilo is the prefix meaning 1,000, thus one kilowatt would equal one thousand watts.... if this is for a class you will probably run into some more numerical prefixes so ill give u a few more...\n\nassuming the standard unit is 1:\ncenti-100th\nmilli-1000th\nmicro-1,000,000th\nnano1,000,000,000th
291327
There is not enough wind power being generated for everyone who might want to buy it. And I would be suspicious too. How do you really KNOW that all your electricity comes from wind? Just because the electric company says it does? And you believe them? Wind power is just put on the power grid with all the other electricity, so it is all mixed up. You are depending on accountants at your power company to correctly calculate, second by second, that all the power from wind entering the network equals or exceeds all the power being used by customers paying extra to get wind power. I am not sure I trust them to do that.
472705
Most electric companies are monopolies - they have no reason to spend money on puttng together something that will require an initial investment on their part.  You are going to pay your bill because you don't have a choice, so they have no motivation to upgrade anything.
172042
i am assuming you are trying to minimize losses in a utility distribution system...when i was a system engineer at a utility..the quickest payback items were 1)correcting power factor as close to unity as possible with switched capacitor banks 2)have a policy of sizing distribution transfomers properly in relation to the load (i.e not oversized) to miminimize NL (no load) losses and not undersized too much either to minimize LL (load losses).\n3)size distribution feeder conductors to miminize both NL and LL losses.  The correct point at which you achieve max savings has a good bit to do with your %rate of capital as well as your cost of power both KW and KWH rates.
360713
I kept reading anyway.\n\nThe heater is already telling you the power consumption.\n900W = 0.9 kW\nTherefore running the heater for one hour uses 0.9 kWH.\n\nYour formula is wrong. Watt/1000  * cost/kWH = cost per hour\n\nFor heaters, it is true that Volts * Amps = Watts.\nTherefore if you know the supply is 120V and the power is 900W, you can calculate that the current load is 7.5 A.
557293
First, to the basics...\n\nAC is Alternating Current.  This means that the current moves in one direction and then the other, changing at a frequency of 60 time per second, its unit of measurement being Hertz (Hz).  The generator produces this current at very high voltages which are sent down the transmission wires to local substations, where the voltages are reduced to the familiar 110 volts which appears in your electrical panel.   At the transformer of the substation, the transmission lines to your house are isolated from the ground and "float".  This means that there is no path for the current to flow from either wire to the ground or to each other.  Now, in order to use the power (which is a product of the voltage times the current)  the current must flow through a load, which is any energy using device from a light-bulb to a toaster to the pump on you washing machine.  Since both sides of the wire (both the black (hot) wire and the white (neutral) wire) are isolated from ground to begin with, attaching the neutral to the ground does not provide a path for current flow.  Only if a path is made from the black to the white wire will there be current flow.   If we connect a lightbulb between the black and white wires, we will complete this circuit.  Remember that power (measured in Watts) is the product of Voltage (measured in Volts) and current (measured in Amps).  If we know the amount of Voltage (110V) and the power used (say 100W in a light bulb), we can figure that the amps used are 100W / 110V = ~.91 Amps.  If the circuit breaker is rated for 15 amps, it would require at least 17 of those bulbs to exceed the capacity of the breaker and cause it to trip.  I hope this clears things up for you...