x^2+3x-10=\nx to the second power + 3x - 10=
213925
Depends on the value of x.\n\nIf you are solving and equation (=0) you can factor\n\n(x+5)(x-2) = 0 \n\nand solve for x (x = -5 or +2)\n\nBut if it doesn't equal something, there's nothing to solve unless you know what x equals.
482020
You need to give some directions.  What is the problem asking you to do?\nNote: The person below is incorrect.  (4+3x)^5 does NOT equal\n4^5 + (3x)^5
504529
a)10x^2=40\nx^2=4\nx= + or - 2\n\nb) 4x^2-3x-1=0\n(4x+1)(x-1)
410157
(2asinx*cosx)^2 + a^2(cos^2x - sin^2x)^2\n=4a^2 sin^2xCos^2x + a^2(cos^4x+sin^4x -2sin^2xCos^2x )\n=2a^2 sin^2xCos^2x + a^2cos^4x+a^2sin^4x\n=a^2(cos^2x + sin^2x)^2\n=a^2
238161
(5x)^3=5^3*x^3=125x^3\n\n(10s)^2=10^2*s^2=100s^2\n\n(-x)^4=-1^4*x^4=1*x^4=x^4\n\n(-3y)^3=(-3)^3*y^3=-27y^3
342677
(2^x-2^-x) / 3 (the whole thing is divided by 3)\n\nThat is not an equation to be solved.   So I don't know where you are getting an equals sign (=).??\n\nYou may be able to simplify it, but you cannot say x= something unless you were provided with an EQUATION.\n\nI will do some work on it.\n\nAfter further review, try to input your value for x into the statement\n(2^x-2^-x) / 3 and what you get is another question.   Your value then EQUALS what?   Does this answer your question?    All you will get is a value.
397246
2^3+2*2^2-3(2)-10=8+8- 6 -10 =0\nTherefore x-2 is a factor of the given polynomial
541825
(2x sqrt(2x)) (3 sqrt(5x))\n= (2x*3) (sqrt(2x*5x))\n= (6x) (sqrt(10x^2))\n= (6x) sqrt(x^2) sqrt(10)\n= (6x)(x) sqrt(10)\n= (6x^2) sqrt(10)
529747
(x+3)(x^2 + x + 2)\n= x(x^2 + x + 2) + 3(x^2 + x + 2)\n= x^3 + x^2 + 2x + 3x^2 + 3x + 6\n= x^3 + 4x^2 + 5x + 6
487385
2x^2-8x+3x-12\n2x(x-4)+3(x-4)\n2x+3 = 0 or x-4= 0\nx = -3/2 or x = 4\n\n2x^2+10x-72\n2x^2+18x-8x-72\n2x(x+9)-8(x+9)\nx = 4 or x = -9\n\nx^2+6x-x-6\nx-1 = 0 or x+6 = 0\nx = 1 or x = -6
599479
x^2(3x+1) = 3x^3 + x^2. Use the distributive property.
561602
8100\n\n10 to the power 3 = 10 cubed = 10*10*10 = 1000
484537
a^2+a^3+2a^2\n\n3a^2 + a^3\n\n= a^2(3 + a) \n\nUntil here is finished.... but...\n..If you want the results for a ...do:\n\na^2(3 + a) = 0\n\na^2 = 0,            3 + a = 0;\na= 0          and     a = -3.\n\nPS: You can'tt get 4a^7 because you have to separate the a's that have exponencial 2 from the one with exponencial 3 in order to sum them in the ecuation. You can only add the exponencials if they are multiplying like this for example:\n\na^3 * a^2 = a^3+2 = a^5
540238
The second option is right.\n3x^(-2) = 1/3x^2
182934
One answer is:  ( 6x^3-10x^2+5x-4) / x\n\nProof : replace both equations by 10 ang you will get the same result, that is : 504.6\n\nmichelplafter@videotron.ca\n\nSORRY I made a mistake. Forget the previous answer. The new answer is: it appears that there is no simplification to this equation.
270052
Please write the problem clearly and I will answer Use ^2 to indicate "raised to 2nd power."
212590
3x^2 = 12\n\nFirst, divide by three.\n\nx^2 = 4\n\nTake the square root.\n\nx = +2, -2