P to -1 power minus q to -1 power all over (pq) to -1 power. Show work.
209883
Your equation would be:\n\n= ((1/p) - (1/q))/(1/pq)\n\n= ((q - p)/pq) * pq\n\n= q - p\n\nHope I am clear.
525712
[12(X+21]/ -1 to [-12(X+11]
350574
It is -1.\n\nTo figure this out, follow the pattern of i, as you raise it to various powers:\ni^1 = i\ni^2 = i*i = -1\ni^3 = i^2*i = -1 * i = -i\ni^4 = i^3 * i = -i * i = -(i*i) = -(-1) = 1\ni^5 = i^4 * i = 1 * i\netc.\n\nSo, you can see that the powers of i depend on what it is modulo 4.\n\nYou can see that i^32,530 can be written as i^2, since 32530/4 yields a remainder of 2.  Thus, you know that i^32,530 = i^2 = -1.
169486
2 to the 2079863 power\n2^2079863:1 against
637727
Just plug in 1 for x.\n√(1-1) = √0 = 0
270052
Please write the problem clearly and I will answer Use ^2 to indicate "raised to 2nd power."
88822
The answer is -1\n\nIn Algebra, anytime you subtract a number, you change the number following the minus sign into its inverse (negative to a posotive and positive to a negative) and then add.  Therefore, your problem becomes -12+11, giving an answer of -1.
583499
A X = D\nX = A^(-1) D. (A inverse * D)\n Do it ur self.
172169
2&#92;2=-2&#92;2\n1=-1\ntherefore the answer is -1.
666450
work done 1.078 X 10^5\nheat is -0.292X10^5
351016
I'm sure it isn't correct, though I'm not totally sure what you've done.  It looks to me as if you've raised both sides of \naⁿ + bⁿ= cⁿ\nto the power 1/n.  The trouble is, when you do this the left side is not equal to\n(aⁿ)^(1/n) + (bⁿ)^(1/n)\n\nYou can see this if you consider\n(5^3 + 2^3)^(1/3)= 133^(1/3), which is just slightly over 5, definitely not equal to\n(5^3)^(1/3) + (2^3)^(1/3)\n= 5 + 2\n= 7
654356
The first one is (-5, 3). I don't remember how to do the others.
409484
Your would make your teacher much happier, were you able to handle simple rearrangement of terms in an equation.  You can easily do it by pattern recognition; that 's all that mathematics is.\n\n(a) Start from  V=(P+w^2) / L\n\nThen LV = P + w^2\n\nSo w^2 = LV - P, i.e. w = (LV - P)^(1/2)  \n\n(b) Gee! There IS no G in your formula!  So it's either irrelevant or you made a transcription error.  \n\nIn any case, substituting the given values, the G-less w = (2x8 - 10)^(1/2) = 6^(1/2), or sqrt(6).  \n\nIf you WERE given a G in the original formula, trace its effect for yourself and evaluate the consequence appropriately.\n\nLive long and prosper.
510934
(1+1)-2*3/2^2+2\n\nWithout useing Order of Operations: 2\n\nWith Order of Operations: 2.5
489891
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
480807
(px+2)(3x+q) = rx ^2 + x - 2\n\n(3p)*x^2 + (pq+6)*x + 2q =  rx ^2 + x - 2\n\nComparing coefficients on both side: we have\n\n2q = -2 , q = -1\n\npq+6 = 1, p(-1) + 6 =1 , p = 5\n\n3p = r , r = 3*5 = 15\n\nTherefore the solution is p = 5, q = -1 and r = 15\n\nHope it helps!
620475
Use a calculator and raise it to the 1/3 power.\nDon't try to do it by hand...