**(-1)=1/2m+x\n\n**28=3m-7m\n\n**4+5y+11=35\n\n        anyone please help me and show me all the steps to cause i need those to understand them thank you
207622
The goal is to get the term containing x (or other unknown) on one side and the numbers (and other unknowns) on the other.\n\nYou do this by performing the same operation on both sides at once. That way, the equation remains an equality. If you did different operations on the two sides, the two sides would no longer be equal.\n\nHere is an example: -4(2x+8)=32\n\nDivide both sides by -4. The minus four on the left becomes (-4/-4) or 1. It kind of disappears. And dividing the 32 on the right by -4, changes the 32 to -8. However, the left and right sides are still equal because you performed the same operation on both sides.\n\nAnd here is the rest:\n\n2x + 8 = -8\nAdd -8: 2x + 8 - 8 = -8 -8\n2x = -16\nDivide by 2: 2x/2 = -16/2\nx = -8
486249
1.  Here you just divide both sides by 5 to get the x by itself\nand you get :\n5x<35\nx<7\n\n2. Divide both sides by 4\n4y>15\ny>15/4\n\n3.  Divide both sides by 16\n16y<64\ny<4\n\n4.  Divide both sides by a -18. Remember that you have to switch the equality sigh when you divide by a negative:\n-18y>-36\ny<2\n\n5. First, combine like terms (x):\n5x + 6x <-33\n11x<-33\nDivide both sides by 11:\nx<-3\n\n6. Combine like terms (y):\n-12>2y - 6y\n-12>-4y\nDivide by a -4. Remember to switch the equality sigh \n3<y\n\nHope that was helpful!
208785
42\n\n(X-1+3)/4=11\nx+2=44\nx=42
156565
(m-6)(m+7)=0\nm=6 or m=-7\n\n(n-1)(n-7)=0\nn=1 or n=7\n\n(x+1)(x+5)=0\nx=-1 or x=-5\n\n(x-2)(x-7)=0\nx=2 or x=7\n\nas easy as ABC!!!
458962
3x*=11x+4\n\n3x*-11x-4=0\n\n(3x+1)(x-4)\n\nx=-1/3    x=4
234017
3-4(2)+2(2)+1=0\n2(-3)+1-[3-4(-3)]=-20\n3-4[2(1)+1]=-9\n\ng(x)=(x-4)/-5\n3-4[(x-4)/-5]=x\n{[3-4(x)]-4}/-5=x
473886
1.  \n-3 - 11 = -3 + -11= -14\n\n2.  \n-8 - (-6) = -8 + -(-6) = -8 + 6 = -2\n\n3.  \n20 - 55 = 22 + -55 = -33\n\nHope this helps\n~i~
396166
(-3,8) and (-4,-5)\nm=(-5)-(8)       negative plus a negative is -13\n      (-4)-(-3)    a negativewith another negative becomes a positive (-4)+3=1 so your answer to 1 is -13\n\n2.(-4,-1) and (-5,9) \nm=(9)-(-1)   9+1=10\n      (-5)-(-4) -5+4=-1   so your answer is 10
481034
First, I multiplied the first equation by 2 and the second one by -5 in order to make it easy for me to cancel out both x's.\n2(-5x+7y=-40)\n-5(-2x+4y=-16)\n\n-10x+14y=-80\n10x+-20y=80\n\nNow, you can actually cancel out the x's and the constants at the end.\n\n-6y=0\ny=0\n\nNow you plug y=0 into one of the equations to find x.\n\n-5x + 7(0) = -40\n-5x +0 = -40\n-5x = -40\nx = 8\n\n(0,8) is the answer.
422093
ok first you have to distribute on each side, remember to watch the (-) (+) signs.\n\n- 4 (x + 2) - 11 = 2 (- 2x -3) - 13\n_________________________\n  -8x + (-8) - 11= - 4x -6 - 13\n\nnow that you are done distributing the 4 and 2, you must start isolating the X's, I like the x on the left, and so will work it that way. it makes no difference though....if you like it on the right, that is fine too. so I will start with the 4, and remember whatever you do to one side you must do to the other. \n\n    -8x + (- 8) - 11 = -4x - 6 - 13\n    +4x                     +4x\n__________________________\n     -4x + (-8) -11= - 6 -13\n\nremembering you cannot subtract with positive and negative numbers  so be careful of the signs and change/change the subtraction to plus signs. so let's do that next.\n\n  -4x + (-8)  + (-11)= -6 + (-13 )\n\nnow that you have changed the signs as above, do the operations on both sides.\n\n   -4x + (-19) = (-19)\n\nnow yo umust further isolate the X, so move the (-19) from left to right, again what you do to one side you must do to the other.\n\n    -4x + (-19) = (-19)\n             +19     + 19\n________________\n              -4x  = 0\n\nnow divide out the  -4, which into zero is zero, therefore x= 0, thus any number plugged in for the x would result in an "x=0" answer. \n\nhope this helped, for more help ask yahoo answers, or try www.purplemath.com, it is a great math site!
425728
2.5 m= - 25.. are you trying to solve for M.... \nand -3.25t=-3.11 i am assuming you are trying to solve for T?\n\nfor the first one... 2.5m/2.5=-25/2.5 so m = 10\n\n2nd one .. -3.25t/-3.25= -3.11/-3.25\n\ni don't know if this is what u looking for
196178
1) 1, 2, 3 and 6\n2) 1, 2, 2m\n3) 1\n4) 1, 3\n\n5) 5/9 (55/99) > (45/99) 5/11\n6) 2/3 (8/12) < (9/12) 3/4\n7) 4/5 (32/40) < (35/40) 7/8\n8) 1/3 (4/12) = (4/12) 4/12
552156
1st one:\n\nadd the 2 equations\n(-4x + 4x) cancels\n(-5y + 4y) = -y\n(-21 + 16) = -5\n\ntherefore y = 5\nsubstitute y = 5 into one of the equation\n\n4x + 4(5) = 16\n4x + 20 = 16\n4x = 16 - 20\n4x = -4\nx = -1\n\n2nd one:\n\nmultiply the first equation by 2 since no addition can cancel x or y\n\n-4x + 2y = 28\nthe other equation remains the same : 4x - 4y = -36\n\nadd the 2 equations cancelling x\n\n2y - 4y = 28 - (-36)\n-2y = 64\ny = - 32\n\nsubstitute y = -32\n\n-2x + (-32) = 14\n-2x = 14 + 32\n2x = -46\nx = -23\n\nThe important step is the first one in which you decide which letter you want to cancel. you have to the find the easiest method. Good luck
226564
if u meant {4/(q^2+2q+1)}- {q/7(q+1)}\nthe answer is\n\n(28-q^2-q)/{7*(1+q)^2}
656547
=(x+3)(x-1) - (x-2)(x+4)  /  (x+4)(x-1)\n=(x^2 +2x - 3) - (x^2 + 2x - 8) / (x^2 + 3x - 4)\n=(5) / (x^2 + 3x - 4)
82469
[(5x^2-5x-30)/(45-15x)]*\n[(4x-12)/(6+x-x^2)]=\n\n[5(x-3)(x+2)/(5*(9-3x)]*\n[4(x-3)/(3-x)(x+2)]=\n\n[(x-3)(x+2)/3(3-x)]*\n[-4(3-x)/(3-x)(x+2)]=\n\n[(x+2)/-3]*[-4/(x+2)]=\n\n[-(x+2)/3]*[-4/(x+2)]=\n\n[-4(x+2)]/[-3(x+2)]=\n4/3
456864
Do you mean:\n(8 + sqrt(28)) / 2?\n\n1) [8 + sqrt(4)sqrt(7)] / 2\n= 4 + sqrt(7)\n\n2) sqrt(7) * (9 * sqrt(5) - 3 * sqrt(7) )\n= 9 * sqrt(5) * sqrt(7) - 3 * sqrt(7) * sqrt(7)\n= 9 * sqrt(35) - 3 * 7\n= 9 * sqrt(35) - 21\n= 3 ( 3 sqrt(35) - 7 )