I need to know how to enter the data in each baxes i.e what are input Y range and input X range? and what should be entered ; and how to get the Graph. giving a simple example of A-Z from scratch will greately appreciated. do you any very easy to understoo and simple website on the issue?
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when you know your range of y's and x's, then in excel you click on fx (formula function)key menu to display and insert the formula using the parameters requested.
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It's many years since I did maths but shouldn't there be an = somewhere? And isn't there normally "y" too? I thought it would be fun to stretch my brain for a change but...Am I being obtuse?
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This all right from Excel's Help - pretty clever, huh?\n\nCreate a histogram   \nYou can analyze your data and display it in a histogram with the Histogram tool of the Analysis ToolPak. This data analysis add-in is available in Excel, but may not be automatically loaded. \n\nNote  If you don't see Data Analysis on the Tools menu, you will need to load the add-in. For more information, see Load or unload add-in programs.\n\n\nEnter the data you want to use as input for the Histogram tool in one column. If you want, you can add a label in the first cell of this column.\nNote  You must enter quantitative numeric data (such as item amounts or test scores) in each cell of the input column— the Histogram tool doesn't work with qualitative numeric data (such as identification numbers).\n\nIn another column, enter the bin numbers you want to use for the analysis. The bin numbers need to be entered in ascending order. To quickly generate a set of evenly distributed bin numbers, you can use the Fill Series option. \n-MM
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Start as Jim Valentinojr stated:\n\n-1   0  -2 |  -6\n 1   4  -3 | -31\n 5   1  -1 | -28\n\nNow, do row and column operations as he stated until the first element of each row is a "1" and everything below is a "0."\n\nYou will have something that will look like:\n\n1  0  0 | 4\n0  1  0 | 2\n0  0  1 | 3\n\nThen, look at the columns the "1's" are in.  In the bottom row, 1 is in the z column, so the solution in this example is z = 3, y = 2, x = 4.
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2x is the rise over run there for it would go up two for every one it goes right, and the 1 is the starting point on the y axis\n\n\nIf you need more e-mail me and i'll get back to you, include your yahoo messenger username
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y varies kx\n30 = .... wait a minute this question is impossible to do lol, u need to know two sets of values ( y, x).. either you said the question wrongly or the person who made it is dumb
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In the given qts, the data provided is typical for using an orthodox yet nice method called L.P.P. (Linear programming) which is actually a graph method with the cartesian co-ordinates. I am sorry but i won't be able to provide you with the graph solution. Here is the theory of the required solution.\n\nLet the no of matches per box in the first case be x\nLet the no of matches per box in the second case be (x-y) where y is the number of matches decremented per box.\n\nNumber of matches in first case = 24x\nNumber of matches in second case = 28(x-y)\n\nHowever number of match boxes are equal\nHence, 24x = 28(x-y)\n       24x = 28x - 28y\n       28y = 4x\n        7y = x  ----------- (1)\n\nNote that since the total number of matches is not = 0\n hence,   x > y \n          x > 0\n          y > 0  \n and x,y are integers ----- (2)\n\nHence, x is minimum when y is minimum.\nMinimum integral value of y is 1\nHence minimum value of x = 7y = 7*1 = 7 ----- (3)\n\nFrom (1), (2) and (3), we conclude that...\n\nTotal number of matches required for the given qts should have a minimum value         \n   = 24x \n   = 24*7 \n   = 168   ........ (ANSWER)\n\nThe data provided by you is sufficent for finding minimum no of matches required since that's the limiting case. If you have a more precise condition in the given qts, a unique solution shall be obtained for the same. Graphs would have made the solution more interesting.\n\nI saw someone getting an answer as 672. It's possible if there is a condition in the given qts that "When the number of matches in each box are decremented, number of boxes required are 28. However, the number of matches placed in each box is found to be four less than the intial number of matches placed in each box". Then the solution would be like this :\n\nLet the no of matches per box in the first case be x\nHence, the no of matches per box in the second case be (x-4) \n\nNumber of matches in first case = 24x\nNumber of matches in second case = 28(x-4)\n\nHowever number of match boxes are equal\nHence, 24x = 28(x-4)\n       24x = 28x - 112\n        4x = 112\n         x = 28 \n\nClearly, like in the previous solution, in this case too, \n \n   x > 4\n  and its obvious that x > 0 and x is an integer.\n\nHence, the unique number of matches required in this case is \n         = 24x \n         = 24 * 28 \n         = 672 ... (ANSWER)\n\nI hope that this solution serves its purpose and helps you conquer this question satisfactorily.
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Rather than tackle all these topics where no one else can see, I will briefly summarize some thoughts here for you.  Of course, you'll get much more from checking out a good Beginning Calculus study aid (like "Schaum's Outline" series) at your local bookstore.\n\nINTERVAL NOTATION\n\nWe can use brackets [ ] and parentheses ( ) to denote portions of the x-axis or any other continuous set of numbers.\n\nExamples are probably best to learn from.  I'll say it in English, then write the interval using notation.\n\n"All the numbers from 0 to 5, but not including 5 itself."  [0,5)\n\nSee how the parenthesis ) means "not including this number"?  And the [ means "include the zero" on the left-hand side of the interval.\n\n"Numbers greater than 6 but less than 11."\n(6,11)\nHere, neither of the interval's endpoints is included in the set, but everything in between is.\n\nIf I could write the symbol for "infinity" I could come up with open-ended intervals:\n"All the numbers smaller than -3" would be the interval (-inf,-3)\n\nIMPORTANT:  When infinity is one of the 'endpoints', a parenthesis is ALWAYS used.  Because you can never 'include' infinity.\n\nLIMITS\n\nThis is normally a lengthy topic, and limits can seem complicated because there are so many different occasions where limits apply.  Even the notation is funny-looking (like an arrow --> that means 'approaches') and takes a while to get used to.\n\nBut the simplest way to think of a limit is as "a possible value that is being approached somehow."  We could speak of x values becoming closer and closer to, say, 15 -- and 15 might turn out to be "the limit" in the problem, in which case x might eventually EQUAL 15 and stop there (or x might just get arbitrarily CLOSE to 15 and something stops it from BEING 15).\n\nIf we choose simple functions like y=3x and then ask "What will be the limit of this function as x approaches 7?" ... the answer is very straightforward.  21!  Because there's nothing to stop x from being 7, and it doesn't frankly matter whether it 'got there' after being 7.1 or 6.9.  The function has no holes (discontinuities) or breaks (asymptotes) or restrictions (such as x<5) ... so life was really easy with y=3x!\n\nBut for functions that are more "interesting" or have funky graphs right around a particular x-value, it pays to be aware how the limit (the y-value) may be a challenge to discover.  The limit may even CHANGE as we let x approach from the 'left' (below) or the 'right' (above).\n\nHere's the last example:\n\nf(x)=(x-1)/(x+5)\nBeing a rational function, f is defined only for values of x that are permitted ... and, like any fraction, the denominator may NEVER be 0.  That eliminates x=-5.  In interval notation, we'd say that the permissible values of x come from the set (-inf,-5) U (-5,inf).  As you can see, sometimes 'interval notation' is not so brief!\nIn those cases, we often simply write x / -5 (where the 'equal sign' has a slash drawn through it).\nNevertheless, f(x) has values we can calculate for every other possible value of x besides -5!  If you graph f(x), you will see that the function behaves 'strangely' right around x=-5.  Those are asymptotes ... a break in the graph that cannot be "fixed" simply by filling in a missing hole!  You could say the function f(x) "increases without limit" or "decreases without limit" on either side of x=-5 ... some teachers prefer "f has infinite limits."\n\nMAXIMA and MINIMA\nThese are merely the greatest and least values that a function might attain over a given interval.  Sometimes a function's least or greatest value occurs at the interval's endpoint(s).  But just as often, the 'lowest' (valley) or 'highest' (peak) might occur somewher
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The easiest thing to do is plug in a number for x and get y and then graph it for example:\n\nplug 0 for x and you get 5-0=5\nthere you have a pint on your graph (0,5)\n\nthen plug 1 for x and you get 5-1=4\nthere you have a pint on your graph (1,4)\n\nthen plug 3 for x and you get 5-3=2\nthere you have a pint on your graph (3,2)\n\nthen maybe plug in some negative like -1 for x and you get 5--1=6\nthere you have a pint on your graph (-1,6)\n\nthen maybe plug in another negative like -3 for x and you get 5--3=8\nthere you have a pint on your graph (-3,8)\n\nI hope this helps
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plot the coordinates then do the vertical line test.  if the vertical line intersects more than two points on the graph then it is not a function.  each set of coordinates you have listed are functions (i free hand it with no graphing paper or calc) so forgive me if im wrong.  also refer to www.coolmath.com. it is a good site for breaking down math
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you dont need to enter data into L1 you can use any of the lists, as longs as you specify which one when you are setting up plots in 2nd y= you then type in what lists you are using and make sure you turn on the plot!
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Domain is the X coordinates, and range is the y coordinates.\n\nWhen a problem says "what is the domain?"\nThey want to know if for any x value you put in, if there will be a real answer.\n\nRange, yeah, thats just the Y values. :D
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yep, here they are, are you doing a pri=oject? i might be doing the same one.\n\nhttp://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=mathcom&s1=graphs&s2=equations&s3=basic\n\nhttp://www.webgraphing.com/plotting_advanced.jsp
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it is from a logic work sheet.  directions are find the next item in the pattern.  examples:  12321, 23432, 34543, 45654\na, z, b, y, c, x, d\ntam, tan, rib, rid, rat, raw, hip
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0.1(6) ---> point one six - the six repeating\n\n0.(16) ---> point one six - one and six repeating\n\nNotice:\n1) the parenthesys notation is a standard, and it works well even when you don't have special characters, as on Y!Answers...\n2) when things get ambiguous, like in this case, it is a duty to spend a little more words to make things comprehensible; so you could well say "one point six repeating" for the two, as you noticed: it's not wrong for any of the two, but you yourself felt the need to specify better, so you can spend words and specify what you exactly mean. Otherwise, use standard notation
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That's a great link from Jose on the direct answer; however, here are two easy ways to do it yourself and not be reliant on a calculator:\n\n***FIRST WAY***\n\nFirst draw the x and y axes, tick marks and all.\n\nNext, remember that all the points on this graph involve a value for x and a value for y.  The points that form the line are going to be the values for x and y where multiplying by x and adding y gives 9.  For a linear graph (like this one), you can choose any point in the universe for x or y and come up with the corresponding value for the other variable.\n\nLike this:\n\nI'm going to make my life easy and see what y will be when x is zero.  I do this by plugging the value of 0 in for x:\n\n3*0 + y = 9\n\nThree times zero is just zero, so I am left with:\n\n0 + y = 9\n\nor just\n\ny = 9.\n\nThis means that if x = 0, then y = 9 (the converse is true as well:  if y = 9, then x = 0).  In other words, that means that the point (0,9) is on the line that we are trying to draw.\n\nNow, it takes two points to draw a line, so let's pick another value.  I'm going to make my life easy again and ask what the value of x will be when y is zero:\n\n3*x + 0 = 9\n\nor \n\n3*x = 9\n\nIn this case, by dividing both sides of the equation by 3, we get that x = 3.  This means that when x = 3, then y = 0.  In other words, (3,0) is also on the graph.\n\nIf I draw both points on my graph, then I can draw a straight line between them.  Now, simply extend your line past the two points in the same direction that you are already going, and you have your answer!\n\n***SECOND WAY***\n\nThe first way is called the two-intercept method because, by setting x and y to zero in the equation, we were finding the x-intercept and the y-intercept.\n\nThe second way is similar in that it involves the y-intercept (the point on the line when x = 0), but it involves another concept as well called the 'slope'.\n\nTake your equation, 3x + y = 9, and rearrange it so that the 'y' is by itself.  We can do this by subtracting the 3x from both sides to get:\n\ny = -3x + 9\n\nNow, writing it this way is convenient because a couple of things are already done for us.  The '9' is what is called the 'y-intercept' and the '-3' is what is called the slope.  The y-intercept is the point along the y-axis where your line and the y-axis meet.  The slope is  how steep or shallow the line moves from the y-intercept.\n\nSo, with that defined, it's really easy.  Draw a point on the y-axis at (0,9).\n\nFor the slope, remember 'rise-over-run'.  A slope tells us how far to 'rise' up or down and how far to 'run' right or left from the point that we have just drawn.  Any slope can be written as a fraction, and the top of the fraction (the numerator) is the 'rise' and the bottom of the fraction (the denominator) is the 'run', thus 'rise over run'.\n\nIn this case, -3 can be written as -3/1.  So, the 'rise' is -3 and the run is 1.  This means that from the point that we drew on the y-axis, you can count *down* three (since it is negative) and count right 1, and that new point is a point on the graph as well.  This means that (0,9) - the point that we originally drew - and (1, 6) - the point that is 3 down and 1 right from the first point - are both on the graph.\n\nNow, just draw a line between the two points and extend it in the same direction past the point, and you're done!\n\nI prefer the first way, but there are times when either is a little easier.  Mostly, if the equation is like this:\n\nax + by = c\n\nUse the first way.  If the equation is like this:\n\ny = mx + b\n\nUse the second way.
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the rise is -4 the run is -1 first put a dot on the negative 1 for the x axis i think and go 4 down and 1 back (rise and run is always the same just change the x axis for the other numbers)