Like the square root \nof 18 is 6. But what is the square root of 72? How would you solve it?
208009
The square root of 18 is not 6 it's 4.24264069\n\nThe square root of 36 is 6.
484022
if s+2 = 38, s is equal to 38 -2 which is 36\n\nThe square root of 36 is 6\n\n6 / 6 is 1\n\n1 + 4167 is 4168\n\n 4168\n-  612\n-------\n3556\n\n3556 divided by 50 si the same as 355.6 divided by 5\n\n355.6 / 5 = 71.12\n\nSimple :-)
665102
6√2\n\nRemember it's a square so the sides are all the same length, and the area is s^2\n\nso s^2=36==>s^2-36=(s-6)(s+6)=0 so s is either 6 or -6.  -6 makes no sense here, so it is obviously 6.\n\nNow, since we have a square we can "draw" (imagine) a line at the diagonal, and that makes a right triangle (since the corners of a square are all 90º) with legs 6 and 6.  using the Pythagorean relation, we have d^2=s^2+s^2=6^2+6^2=72.  Thus d^2-72=(d-6√2)(d+6√2)=0.  Thus d is either 6√2 or -6√2, and again is obviously the positive one :)
372450
true\n\nbecuase you know that the square root of 38 is between 6 and 7, because there squares are 36 and 42
51335
72 = 70 + 2\nwhen we cancel 7 to 6 this mean 70 = 60 + 10\nthis 10 when you add to 2 make 12\n72 = 60 + 12\n48 = 40 + 8\n72-48 = 20 + 4\n72 - 48 =24
418544
If a is 1/2 of c, and c is 22, and a^2 + b^2 = c^2, what is b?\n\nc = 22..... 22^2 = 484\n1/2 of 22 = 11 = a...... 11^2 = 121\n484 - 121 = b^2\n363 = b^2\nsquare root 363 = about 19.\nWhat's strange about this is that b is not a whole number, and usually they make it a whole number for prealg. sure that's right above? This answer is true for your problem.
544084
48=2(20+w)\n24=20+w\nw=4
30173
a=8\nb=-6\nc=-9\n\nx= -b + or - square root of {b^2-4(ac)} all over 2a\n\nx= 6 + or - square root of {36 - 4(8)(-9)} all over 16\n\n = 6 + or - square root of 324 all over 16\n\n (6+18) divided by 16= 3/2\n (6-18) divided by 16= -3/4\n\nso, x= 3/2 or -3/4\n\nthere you go. hope this helps
554575
86 divided by 24.\ntake it from there?
521268
-6[4-3(9-12)]+7(18-7)\n=-6[4-3(-3)]+7X11\n=-6[4+9]+77\n=-6X13+77\n=-78+77\n=-1 ans\nParenthesises are never used in answers excepting in algebra,when it is used to denote factors of multiplication of two or more expressions containing  two or more terms
526176
a) 72*60*24*30=3110400\nb) 3110400*12 = 37324800\nc) 37324800*72=...................................... :))
355848
Let x = sqrt(6*sqrt(6*sqrt(6*....\nthen x = sqrt(6*x)\nthen x^2 = 6x\nthen x^2 - 6x = 0\nthen x(x-6) = 0\nthen x =0, 6\nthere is no scope of x being zero, hence x = 6.\n\nThis problem can also be solved in another way.\nx = 6^(1/2+1/4+1/8+1/16+....)\nThen find the sum of the series 1/2+1/2^2+...+1/2^n\nThis is a geometric progression\nTherefore sum of this series is (1/2)[1-(1/2)^n]/[1-1/2]\n= 1-(1/2)^n\nBut, here n tends to infinity.  There fore (1/2)^n tends to zero.  There fore the sum of this series is 1.\nHence x = 6
638158
7249\n\ntake 0.0659 x 110,000 = answer (7249)
451381
LCM \n\n48a^2b^2. 72aDivide 48 and 72 and  by the lowest factor possible, so that when you multiply them, you get 48 and 72 again. \n\nSo 48 and 72 are factorized side by side\n   |  \n2 |_48, 72_______\n2 |_24, 36_______\n2 |_12, 18_______\n2 |_06, 09_______\n2 |_03, 09<here, only 6 can be divided by 2, so 9 remains the same>\n3 |_01, 03_______\n3 |_01, 01_______\n\nNow take all the factors, and multiply them together...\n==> 2*2*2*2*3*3 = 144. That is your least common multiple. Try the same with the a's and b's, I think you'll get a^3 b^3.\n\nHCF is similar. But factorize them seperately.\n48 = 2*2*2*2*3*a*a*b*b*b\n72= 2*2*2*3*3*a*a*a*b*b\n\nTake ONLY the common digits (only the ones that are present in both, write it down below, ONCE)\n\nHCF=2*2*2*3*a*a*b*b = 24a^2b^2. This is your highest common factor.\nAnymore help, mail me. \nGoodLuck!
388177
560 = N / (1- u/ 340) --------------- [1]\n\n480 = N *(1+ u/ 340) --------------- [2]\n\n[2] Divided by [1] gives \n\n480 / 560 = (1 + u/ 340) *(1 - u/ 340)\n\n 0.8571 = 1- (u/ 340) ^2.\n\n(u/ 340) ^2 = 0.1429\n\nu = 128.5 m/s.
540325
square root of 40.5 = 6.363961.\n\nAnd for the future.... http://www.calculator.com/
511884
a^6-3=61\na^6=64\na^6=64\na=6th rt of 64\na can be  or -2\nchoice i and ii