I am having trouble with the symbol in math. On the greater than > or equal to or <less then or equal to symbol
218473
Whole numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, and so on.\nThe whole numbers that are less than 6 (x<6) are\n{0,1,2,3,4,5}
642374
Multiply both sides by 2 to get x>-2. If you multiply both sides of an inequality by a positive number, it does not affect the sign. If you have to multiply by a negative number, the sign gets reversed. Hope that helps.
467735
Just graph it like an equality, and then your answer is everything either above (>) or below (<) the line.  For example, in the last inequality, the answer is everything above the line y = -2, not including the line itself.
623827
x' € S - {x}\nworks fine...\n( replace the € by the usual "is an element of" symbol )
551422
We use the symbol above the number 6 on the keyboard to show exponents.  For example, 2 squared is typed 2^2 = 4.\n\nWhy don't you use the symbol ^ and retype your question correctly?\n\nGuido
528469
Let epsilon greater than zero be given.\n\nchoose delta such that |f(x) - f(y)| < epsilon/2 if |x-y| < delta\n\ndo the same thing with g.\n\nnow |f(x) + g(x) -[f(y) + g(y)]| is less than or equal to\n\n|f(x) - f(y)| + |g(x) - g(y)| < epsilon/2 + epsilon/2 = epsilon
134105
Generally, you break an inequality such as this into two parts and graph each separately.  So you'd be graphing x=-1 and x=3.\n\nThe type of line depends on the sign: if it's a <= or >=, then use solid lines to indicate anything on the line satisfies the original inequality.  If it's just < or >, then use a dashed line.  (This is similar to open and closed circles on a number line.)  Then, you pick points in the different regions that you created with the lines and determine if they satisfy the inequality.  If so, the region gets shaded.\n\nThere is no y dependency, so you basically have two vertical lines for your graph for this problem.  Checking the regions, only the area between the lines satisfies the inequality, so that's the only region that gets shaded.
509409
You put a round bracket "()" on the number line when the sequence doesn't include the number where that bracket goes. For example, if the final answer you get is "all the numbers between 2 and 8, excluding 2 and 8" then you use the round brackets. You'll know your answer excludes a number or numbers because it will be "bigger than" or "smaller than" only, not "bigger than or equal to" or "smaller than or equal to", in other words, ther will be no line underneath the inequality sign. \nNow, if you do get something like "x is bigger than or equal to  8 and smaller than or equal to 2" than you know your answer includes 2 and 8, so you use the brick bracket, "[ ]". Good luck.
146554
hahahah that doesn't make sense in order for two sides of an equation to be equal the numerical value of each side must be the same.  Whats with all the equals signs!
390360
My guess is that you are trying to use this method to find out if  a character is a letter or a digit. The name of the method is wrong. and the wya you are using it might be wrong too. It is Character.isLetter(...) or Character.isDigit(...) Hope that helps\n\n\nChiney
181272
when playing with < and >\nif you multiply all the equation by -1 the sign < changes to >, and the sign > changes to <\nbut if you just switch the number on the other side the sign doesnt change\nin ur case :\n2x-y < 4 \nequals\n-y < -2x + 4\nif you multiply it with -1 it will become\ny > 2x - 4\n\nlike that. hope it helps :)
367210
its between negative one and 0
260676
Santosh is correct, both work...\n\nI want to know how you use the ∫ symbol!! I just copied & pasted from yours..what's the keystroke for it??
342677
(2^x-2^-x) / 3 (the whole thing is divided by 3)\n\nThat is not an equation to be solved.   So I don't know where you are getting an equals sign (=).??\n\nYou may be able to simplify it, but you cannot say x= something unless you were provided with an EQUATION.\n\nI will do some work on it.\n\nAfter further review, try to input your value for x into the statement\n(2^x-2^-x) / 3 and what you get is another question.   Your value then EQUALS what?   Does this answer your question?    All you will get is a value.
368562
First, notice that you need to restrict x to > 0\n\nthen mult by x\n\n1/x>7\n1 > 7x\n1/7>x\n\nIf you have a graphing calculator, it's instructive to see what 1/x looks like.
302273
GIVEN:\n\nA. <1 + <2 =180\n\nB. <1 = <2 + 36\n\nsubstitute\n\n(<2 + 36) + <2 =180\n\n2<2 + 36 =180\n\nsubstract 36 from both sides\n\n2<2 + 36 -36 =180 -36\n\ndivide 2 on both sides\n\n2<2 = 144\n\n(2<2)/2 = 144 /2\n\n<2 =72\n\nsubstitute 72 for <2 in equation B.\n<1 =<2 + 36\n<1 =72 + 36\n\n<1 =108
327609
The previous answerer is correct but this is why....\n\nWith algebra you have to balance each side of the equals sign.  You can only add or subtract like kinds (think of 12x and 11 x as apples and -6 as a pear).  You want to get all the pears on one side and all the apples on the other.  So, to get rid of the -6 from the left side you move it to the right but because you've changed which side it's on you change what you do to it, ie, the six is -6 so moving to the other side makes it +6.  The same for the 11x.  Moving it from right to left means it goes from being a +11x to a -11x.  That leaves you with 12x - 11x = 6.  Thus, 1x = 6. Convention says you don't use the number 1 in front of an x so you have x = 6.\n\nTo check it, go back to your original equation and replace the x with 6 so you have (12 x 6) - 6 = 11 x 6.  Both sides equal 66 so you know that both sides are equal - problem solved.\n\nHope this makes it a little clearer.