I know the answer, so you guys are guessing to get the 10 points.\nWhat walks on four legs by day, two legs in the afternoon, and 3 legs at night?\nThis is an old riddle by the way, supposedly is was the riddle that the Sphinx used to keep people out of a city, I think Thebes.  Anyone who didn't answer or who did and was wrong was destroyed. (Yikes!)
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a human walks on 4 as a baby walks on 2 as a man walks on 3 because of cane as an old person
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man\n\nIn the morning, or childhood, humans crawl on their hands and knees.  In the afternoon, or adulthood, humans walk on their own two feet, and at night, which represents old age, many humans rely on the aid of a walking stick, which represents a third leg.
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Regarding chambers beneath the Sphinx - yes, ground penetrating radar studies have revealed several anomalies, none very big, that are probably chambers. It is not clear how many of these reflect natural fissures in the limestone or how many are actual deliberate constructions. It is known that some of these chambers are of fairly recent date - the 1800s, made by explorers and/or in the course of restoration efforts. It is extraordinarily unlikely that there is either a "Chamber of Lost Records" as predicted by Edgar Cayce, nor a "machine" of Atlantean provenance associated with the Sphinx.\nIt is not entirely beyond possibility that there is an ancient chamber dating to the period of the carving/construction of the Sphinx or to later restoration efforts by Tutmose IV and later kings. Such a chamber(s) would likely be a foundation deposit - quite common for constructions of a religious nature in ancient Egypt.\n\n\nSee the following and links therein for a decent summary:\nhttp://www.catchpenny.org/chamber.html...
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That's the trouble with answers that give no explanation. Who can you believe?\n\nSince we go in each direction once, the ORDER of the moves doesn't matter. \n\nDraw a grid. Start at 0,0\n10 North means 0,10 You are due north 10 miles. Then we come back south 6 miles, so we're 4 miles north of where we started. \n4 miles east and then 7 west means we're 3 miles west of the starting point. \n\nDraw a right triangle 4 miles up and then 3 miles to the left of the starting point. We want the hypotenuse of the triangle whose sides are 3 and 4. \nTime for Pythagoras: a^2 + b^2 = c^2 \n3^2 + 4^2 = c^2 \n9 + 16 = 25 Take the square root of that for your final distance. Direction: NW
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1)One leg of a right triangle is 12 cm long. The diference between the other two sides is 2 cm.\nFind the sides of the triangle. (Pythagorean Theorem)\n\nWhat we can take from this problem is that one LEG is 12 cm long, while the other LEG is unknown (we will call it X) and the HYPOTENUSE -- the longest side of a right triangle -- is also unknown (we will designate it X+2, since it differs 2 cm from the unknown leg).\n\nSetting up Pythagorean Theorem as always:\n\n "Leg squared" + "Leg squared" = "Hypotenuse squared"\n\n  12^2 + x^2 = (x+2)^2\n\nExpanding:\n\n  144 + x^2 = x^2 + 4x + 4\n\nCollecting like terms:\n\n  4x = 140\n\nDivide by 4:\n\n   x = 35\n\nThe unknown leg is 35 cm, while the hypotenuse is 37.  Thus, we can also call the triplet (12,35,37) a "Pythagorean Triple" (of which there are infinitely many!).\n\n\n2) The hypotenuse of a right triangle is 58 cm long. The diference between the other two sides\nis 2 cm. Find the sides of the triangle. (Pythagorean Theorem\n\nIn this case, we know the hypotenuse, but do not know the lengths of the legs.  For convenience, we will again use the expressions X and (X+2) for each side's length.\n\nBy P.T.:\n\n x^2 + (x+2)^2 = 58^2\n\nExpanding:\n\n x^2 + x^2 + 4x + 4 = 3364\n\nCollect like terms:\n\n 2 x^2 + 4x - 3360 = 0\n\nDivide by the GCF (2):\n\n  x^2 + 2x - 1680 = 0\n\nCan we factor this trinomial easily?  We could, if we knew integer factors of -1680 (one positive, one negative) that combine to make 2.\n\nLuckily, -1680 can be factored into -2*2*2*2*3*5*7, and these can be grouped into two sets:\n      2*3*7 = 42\n -2*2*2*5 = -40\n\nFactor:\n\n (x+42) (x-40) = 0\n\nAlthough two solutions come from these factors (-42 and 40), we may only consider the positive answer, since lengths of triangle's legs are always positive!\n\n Therefore, x=40 (Leg 1), and Leg 2 is 42 cm.
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Does night actually move faster than day?\n\nThat doesn't really make sense, because while it may be night in one place, it will be day on the other side of the world. So they must both be moving at the same pace to be happening simultaneously, right?\nSorry I can't be more help, but I believe they both move at the same pace.
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what do you get when you combine an agnostic, an insomniac, and a dyslexic?\n\ngive up yet?----- someone who stays up all night wondering if there really is a dog.
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Oh my goodness gracious. I can not believe someone had the nerve to ask this riddle. This is like riddle me this & riddle me that. I know the answer to this one, I can't believe the men didn't. \n\nShaking her head at the men: This is the correct answer!!\nIf that day should come to pass, I'd make a sailboat out of my a*s, I'd turn my d*ck into an oar & I'd paddle that pu**y back to shoar!!!!\n\nNow women make a note of this one. If you have a man & he can't answer. oh nevermind on that I might get reported just for answering this question. I only answered because my mom told me the joke when I was 9. Wish I had never heard of it. ;)
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That is good of you to share this information with us.  I Really had to try hard to find all six it was only when you continued with the bit about the word 'of' that I found another two but still missed the last one.  However I am old, so that may have something to do with it.\n\nIt kept me amused for a while so 10/10.  I demand more of this sort of thing;)\n\nI am going to try it with my listeners next time I do a show
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The answer is man (or woman to be PC here).  Four legs is a baby, two legs is grown man walking upright and the three legs are man in his later years walking with a cane.
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You can find this passage in Joshua 10 : 12,13.\n\nAs you rightly stated, it was JOSHUA who asked God to stop the sun and the moon. Note that the sun "stood still" and the moon "stayed".  It could well be that Joshua was speaking JUST like we do today when we say that the sun "rises in the East and sets in the West" even though WE KNOW that the SUN does nothing of the sort!!!\n\nNow, let me make it quite clear the I have never read the Bible and neither have the majority of Christians; what we have read are various TRANSLATIONS of the Bible (because most of us cannot read Hebrew, Aramaic and ancient Greek). Hebrew scholars say that the expression "stand still" as used here means "stop acting". Scientifically, what causes the earth to spin on its axis resulting in day and night?  If the GRAVITY that the sun AND the moon exert on the earth were to DECREASE OR STOP ACTING OR STAND STILL, wouldn't that lenghten the day?
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Heard this before.. it is not a riddle .. it is a joke...\n\nanswer is ... They are still thiking... (pointing to those who try to answer you!).. I am the last pig!!
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First.\n"the sequence of cities is relevant for a tour"\nmeans order is important. Thus, a permutation reflects each different tour.\n\nThere are 3 possibilities for the number of cities included for the tour, namely, 3,4, or 5 cities. We consider each case separately.\n\nCase 1. ( 3 cities )\n\nDelhi is included. The remaining 2 cities can be chosen from the remaining 4 cities in 4C2 ways = 6 ways.\n\nAfter the 3 cities are selected, they can be permutated in \n3P3 ways = 3! ways. Each representing a tour.\n\nHence, Total number of tours in case 1 = 6 x 3! ways.\n\n\nCase 2. ( 4 cities )\n\nDelhi is included. The remaining 3 cities can be chosen from the remaining 4 cities in 4C3 ways = 4 ways.\n\nAfter the 4 cities are selected, they can be permutated in \n4P4 ways = 4! ways. Each representing a tour.\n\nHence, Total number of tours in case 2 = 4 x 4! ways.\n\nCase 3. ( 5 cities )\n\nDelhi is included. The remaining 4 cities can be chosen from the remaining 4 cities in 4C4 ways = 1 way.\n\nAfter the 5 cities are selected, they can be permutated in \n5P5 ways = 5! ways. Each representing a tour.\n\nHence, Total number of tours in case 3 = 1 x 5! ways.\n\nThus,\n\nTotal number of \n"major city tour is" \n\n= "no.tour in case 1,2 and 3."\n\n= 6 x 3! + 4 x 4! + 5!\n\n= 5!+4*4!+6*3! ways.\n\nThe answer is (b)\n\nRegards
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***********************Spoiler Alert***********************\n\nThe puzzle is solvable. I spent about 4 mind-racking hours on it. Click the link to see the puzzle together. :-)
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"and this whole The Bible is a myth garbage... Did you ever know that archaeologists have found countless cities, names,etc. mentioned in the bible that they didn't think existed?"\n\nThe Da Vinci Code mentions Paris and a Louvre museum and they happen to exist. Does that mean the whole Da Vinci Code is true? According to your "logic", it seems so.\n\nTroy has been found. Does that mean the greek gods exist?\n\nChichen Itza was found too, should we offer maidens to Kukulkan? When is Kukulkan second coming? It was predicted he'd do so.\n\nYou can't prove the miracles happened.
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Humans.  The morning is birth, when we crawl as babies.  The afternoon is when we are young and mid-adults, when we walk.  The evening is when we are older and use a cane.  The one voice is always our own.  Ah, the Riddle of the Sphinx.  ;)
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The reason you haven't gotten an answer yet for this question is that there is no translation.  \n\nHow many "tile walkers" do you think there were before the 1900's? LOL  There were no drain pipes or "inspectors" I wouldn't think.\n\nBimose - S/he is walking\nOgimaa - Chief or Boss