to see something light from that object should get reflected and should converg in our eye.if i travel faster than light how can the light reach the mirror.
206382
Remember Einstein, It is all relative to the observer. You and the mirror would be traveling at the same speed so your observational world would be the same. Now if somebody was traveling with you slightly less than the speed of light, they would see a empty mirror. It is a paradoxical question just as if you where to travel the universe for 5 yrs at the speed of light, then return to earth, you would have only aged the 5 years, but all of your friends would have long ago died of old age waiting your return.Interesting, No? Good luck and happy perplexing.
677105
Light always travels at the same speed in a vacuum, the speed changes ever so slightly when it has to go through a different medium (water e.g.) but its so fast to begin with you wouldn't really notice it. 300,000 kilometers per second is beyond human comprehension, I mean you can only imagine how fast that is, you can't experience it or 'know' it.
389530
Light is not an object, therefore it can't stop moving.  It travels is all directions.
45829
do u mean speed? no, the magnitude is stillt he same but the direction is changed if and only if the mirror has a smooth surface. cause if it is not. there would be many angle of reflection
304825
Every time the ray of light goes from one mirror to the other, it goes through a certain distance d along the mirrors axis (in the 20m direction).   The law of reflection says that the angle of incidence is the same angle as the one the ray will leave the mirror surface, so, we can build a right triangle, with the reflected ray of light as the hypotenuse.  So, we have:\n\nr*Sin( theta ) = d    and   r*Cos( theta ) = a\n\nDividing the first over the second:\n\nSin( theta ) / Cos ( theta ) = d / a\n\nOr:    Tan( theta ) = d / a\n\n            --->   d = a*Tan( theta )\n\ntheta being 30 degrees and a being 10cm = 0.1m\n\nNow, just divide 20m over d and you're good to go.\n\nHope I helped.
260719
Is the mirror flat? or it is a curved one? and position is relative to what? Position is always relative to each other. So:\nIf it is flat and relative to the mirror, the reflection is as far as our distance to the mirror.\n\nIf it is flat and relative to us, the reflection is twice as far as ourselves from the mirror OR as far as our distance to the mirrors itself, depending on the context.\n\nIf it is curved, it depends on the formula 1/f = 1/do + 1/di
92939
Some people would argue the logic of a space craft having headlights at all, others might find fault in the fact that, physically, nothing with mass can ever travel at the speed of light.  But lets put that aside.\n\nThe speed of light is constant in any frame of reference, no matter who is "watching" it, it always travels with respect to them at the speed of light (c).\n\nIf you are in a space ship already traveling at the speed of light [with respect to some outside observer], when you turn on the headlights, the light will move away from you at the speed of light.\nIf some outside observer (who you are flying past at the speed of light) watches all this, they would, too, see the light travel at c with respect to them.  But since you and the light are traveling both at the speed of light with respect to the observer, you and the light would be keeping up with eachother.
236767
If the mirror is perfect, it would reflect all the energy. How ever, if the frequency of the laser matches one of the excitation radiations of the material then their ill be absorption hence burn thru. \n\nAbove a re two extreme cases . Reality there would be some absorption depending on the material and the finish. Burn thru would occur when the rate of absorption, which depends on the absorption constant and the intensity, exceed the rate of heat dissipation and the temperature rises high enough for fusing and eventual burning. So higher the absorption the burn through will occur at a lower intensity.\n\nIn short better the mirror higher the intensity it would stand
9685
It depends on the distance of the satellite.\n\nI'll translate "be seen" as uptake of scattered light. The amount of scattered light obviously is dependent on the amount of light falling on the object and the light absorption and reflection of the object.\n\nWavelength plays a role with absorption of light by the media it has to pass - in this case the various layers of atmosphere plus the optical system. \n\n(Of course it has to be scattered or reflected by the object, too - here we get a hard limit of wavelength.)\n\nDistortion by the atmosphere or the optical system creates different focussing points for different wavelengths. Given enough time and receptors, this effect can be corrected.\n\nSignal to noise ratio is critical. It is easier to see a bright speck on dark background than a dark speck on bright background. If your receptor is tuned to low intensity scattered light, direct reflection will noise out any meaningful signal.\n\nFinally, the signal at the receptor must have sufficient intensity to register as a signal. Here we get not only absorption but also aperture of the optical system as a variable. A giant concave mirror would have lots more aperture than a lense system, which is why astronomical observatories use them. Put a real big perfect mirror into orbit, and the amount of detail you can see will increase considerably.\n\nThere is a problem combining "real big" with "perfect", though. The history of the Hubble Telescope probably is the best proof.
502602
The amount of light will not double, since mirrors only reflect about 80% of light that hits them (absorbing 20%).  It would be brighter in the room, though.  However, if you had a room full of mirrors on all surfaces, the room would be much brigher than a room full of black surfaces, since the light rays will be reflected rather than being absorbed by the dark color.
25124
Well, if you're traveling faster than light, then the light can never be in front of you.  There would be just a big nothing, probably drive you crazy if you looked at it.  I know, I come from andromeda.  We travel through space backwards so we can see where we're going.
663703
If you are traveling at light speed (which of course you cannot do) then time stops completely. Thus you cannot see anything at all in the mirror.
144521
On the image. The light works exactly as it would if the object was actually behind the mirror at the distance it appears to be.
67983
a translucent material reflects some of the light that hits it\n\nWhen light strikes a translucent material, it enters the body of the object, scatters and re-emerges from the surface\n\nIf an object is translucent, it will allow some of the light to come through, but most of the light is scattered
183218
1m/s physically you are walking towards a stationary object that is reflecing your image, as such you are walking towards it at the steady 1m/s.\n\nIf not that then you are both approaching a common point at 1 m/s so you combine your velocities to get 2 m/s.  but that's semantic bullcrap\n\nYou could get really technical and add in the fact that the photons are travelling back at you at the speed of light but that's just stupid.
540167
No matter how fast you go or think you are going, light always appears to be going the speed of light.\n\nEven if you are going 0.99999999999 c from the viewpoint of an outside observer, you would still see light traveling at the speed of light around you. Now, light sent by objects moving at 0.9999999999 c towards you (those "ahead" of you) would be severely blue-shifted and light from objects moving away from you at that speed (those "behind" you) would be severely red-shifted.\n\nBut light from any object moving the same speed as you would look perfectly normal. In fact if you covered the windows of your spaceship (it better be a spaceship, since you won't be in any atmosphere for very long), you wouldn't know you were moving at all!
328335
The speed that the reflection is moving at is near light speed (186,000 miles a second). The spot we see the reflected light coming from is different as the plane moves across the earth, regardless of how fast or slow the plane is moving.