1. x-intercept:2,y-intercept 1\n2. x-intercept:5, y intercept 5\n3. x-intercept:-4,y-intercept -1 \nexplain please
212298
I'll calculate these, but I'll apologize now to those others who might already be doing this if I post my replies after yours.....\n\n1. x-intercept:2,y-intercept 1\nx-int = 2 at point (2, 0) = (x1, y1)\ny-int = 1 at point (0, 1) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (1-0)/(0-2)\nm = -1/2\n\ny = mx + b (now, b is the y-intercept)\ny = (-1/2)x + 1\n\ny = (-1/2)x + 1 (substitute other point for verification)\n0 = (-1/2)*(2) + 1\n0 = 0\n\ny = (-1/2)x + 1\n\n------------------------------------------------------------\n2. x-intercept:5, y intercept 5\nx-int = 5 at point (5, 0) = (x1, y1)\ny-int = 5 at point (0, 5) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (5-0)/(0-5)\nm = -1\n\ny = mx + b (now, b is the y-intercept)\ny = -x + 5\n\ny = -x + 5 (substitute other point for verification)\n0 = (-1)*(5) + 5\n0 = 0\n\ny = -x + 5\n\n------------------------------------------------------------\n3. x-intercept:-4,y-intercept -1 \nx-int = -4 at point (-4, 0) = (x1, y1)\ny-int = -1 at point (0, -1) = (x2, y2)\n\nslope (m) = (y2-y1)/(x2-x1)\nm = (-1-0)/(0-(-4))\nm = -1/4\n\ny = mx + b (now, b is the y-intercept)\ny = (-1/4)x - 1\n\ny = (-1/4)x - 1 (substitute other point for verification)\n0 = (-1/4)*(-4) - 1\n0 = 0\n\ny = (-1/4)x - 1
400703
1) (a - b)(x - y)\n2) (x^9 + y^3)(x^9 - y^3)\n3) (6x + 5)(x + 8)\n4) (x - 9)(x - 7)
343510
1)   y=3x^2+5x-12\n      0=3x^2+5x-12                  (to find the x-intercepts)\n      0=(3x-4)(x+3)                  (Factorised)\n      3x-4=0  or  x+3=0\n      the x-intercepts are x=4/3  and  x=(-3)
552156
1st one:\n\nadd the 2 equations\n(-4x + 4x) cancels\n(-5y + 4y) = -y\n(-21 + 16) = -5\n\ntherefore y = 5\nsubstitute y = 5 into one of the equation\n\n4x + 4(5) = 16\n4x + 20 = 16\n4x = 16 - 20\n4x = -4\nx = -1\n\n2nd one:\n\nmultiply the first equation by 2 since no addition can cancel x or y\n\n-4x + 2y = 28\nthe other equation remains the same : 4x - 4y = -36\n\nadd the 2 equations cancelling x\n\n2y - 4y = 28 - (-36)\n-2y = 64\ny = - 32\n\nsubstitute y = -32\n\n-2x + (-32) = 14\n-2x = 14 + 32\n2x = -46\nx = -23\n\nThe important step is the first one in which you decide which letter you want to cancel. you have to the find the easiest method. Good luck
155787
y=-5. you stick x=0 into it and get the answer.\n\nThe x intercepts are x=1 and x=-5, that's what makes each bracket equal to zero.
413809
1) x = y\nSubstituting:\n4x - 3x = -3\nx = -3\ny = -3\n\n2) 3x + 2y = 6\nx = 2y - 6\nSubstituting:\n3(2y - 6) + 2y = 6\n6y - 18 + 2y = 6\n8y = 24\ny = 3\nx = 2(3) - 6\nx = 0\ny = 3\n\n3) 2x - 6y = 2\n-3x + 9y = -3\nIf you divide the top by 2 and the bottom by -3 you get:\nx - 3y = 1\nx - 3y = 1\n\nThese are equivalent, so you can't determine a single solution.\n\nThe best you can do is simplify the equation to get a formula for y given x:\n3y = x - 1\ny = (1/3)x + (-1/3)\nBecause you can't isolate a single variable, you essentially have one equation and two unknowns.  The solutions will lie along the line with a slope of 1/3 and a y-intercept of -1/3.
242731
x intercept y=4 (0,4)\n(plug 0 in for x and solve)\ny intercept x=20/3 (20/3,0)\n(plug 0 in for y and solve)
480176
Find the X intercept by setting Y = 0\n\nx-2 = 0\nx = 2\n\nFind the Y intercept by setting X = 0\n\ny = 0-2\ny = -2\n\nSo the two points to plot are (0,-2) and (2,0) \nThen connect those points with a line
183805
x=0,2,3,4 and y=1,-1,0,3
155530
1. 4x+3y=4 solve for y, then find slope and y intercept:\n\n4x + 3y = 4\n3y = -4x + 4\ny= -(4/3)x + (4/3)\nY-intercept is 4/3\nSlope is -4/3\n\n2. Write an equation in the form of y=mx+b of the line that is discribed. y intercept is -4 and the line is parallel to the line whose equation is 2x+y=8\n\nThe line whose equation is 2x + y = 8 is written y = -2x + 8 in slope-intercept form.\n\nThe parallel line with y-intercept 4 is:\n\ny = -2x + 4\n\n3. write the point-slope form of the line of the ordered pairs then use the point-slope form of equation (-2,-5) and (6,-5).\n\nThe slope is 0.\n\nThe point-slope form of the line is:\n\ny = 0x -5 = -5\n\n\n4.  Write an equation for each line in point-slope form of equation and slop-int. passing through (-4,2) and perpendicular to the line whose equation is 3x - 2y + -5 = 0\n\nFirst, rewrite 3x - 2y + -5 = 0 as \ny = (3/2)x -(5/2)\nThe perpendicular line has slope -2/3.\n\nThe point-slope form of the line with slope -2/3 passing trhough (-4,2) is:\n\ny - 2 = -(2/3)(x + 4)\n\nThe slope intercept form of the line with slope -2/3 passing trhough (-4,2) is:\n\ny - 2 = -(2/3)x - 8/3\ny = -(2/3)x - 2/3
208635
Seeing as you've gone to all that trouble writing it out, and I'm bored...\n\n1. 2(-5)-3(1)=-13, so yes it is correct.\n2. It is the origin, so it lies in all quadrants.\n3. Third and fourth quadrant.\n4. Straight lines, as the variables are of only the first degree.\n5. Basic line equation for a straight line, so linear. m is gradient, c is y-intercept.\n6. This depends on the degree of the variable, e.g. x^3 is a cubic function.\n7-10. Do yourself!\n11. m- gradient, x- explanatory variable, b- y-intercept.\n12. y intercept from above logic is 8, as b=8. Also, y intercepts line x=0. Let x=0 and y=8.\n13. Assuming f(x)=y, then again the answer is -2/3.\n\n\nThis really is basic!
370956
1) 3x^5 + 4x - 7, x = 1\nJust replace x with 1\n3(1^5) + 4(1) - 7 \n= 3 + 4 - 7\n= 0\n2) 7x^3 - 2x^2 + 1, x = -1\nJust replace x with -1\n7(-1)^3 - 2(-1)^2 + 1\n= -7 - 2 + 1\n= -8
458574
-1. x+y-20;y\ny=-20-x\n2. pie=c/d;d\npi=c/d\nd=c/pi\n3. a+b/c=d/4;a\na= d/4 - b/c\n4. dx=c;x\nx=c/d
552507
the 1st one is simple\n(x+y) dy/dx + y =0\nor xdy/dx + ydy/dx + y =0\nor (xdy/dx + y)  + ydy/dx = 0\nxdy/dx + y = d/dx(xy)\n\nand d(y^2/2)/dx \n\nso d/dx(xy+y^2/2) = 0\n\nor xy+y^2/2 = c\nor 2xy+y^2 = 2c or C\n\nproved\nfor the second one\n\ndy/dx -(1/x)y = xy^2\n\nlet y/x = t\ny = xt\ndy/dx -y/x = t+ x dt/dx -t = x dt/dx\nso\nx dt/dx = - x (xt)^2\nor dt/dx = x^2t^2\ndt/t^2 = x^2 dx\nyou should be able to proceed
349091
Okay, here we go:\n\n1) -2x-10-7 = 3x+2x-10\n    -2x-17 = 5x - 10\n    -2x -5x = -10+17\n    -7x = 7\n       x = -1\n\n2) 12x+6-6x = 5x-10-5x\n     6x+6 = -10\n     6x = -10 - 6\n     6x = -16\n     x = -8/3\n\n3) 30x-5-10x+5 = 4x+40-4x\n    20x = 40\n    x =2\n\n4) -24+6x+12 = 3x-x+4\n    6x-12 = 2x+4\n    6x-2x = 4+12\n    4x=16\n     x = 4\n\nSee? It's quite easy.
498452
a.x=[-8+/-rt(64-24)]/2\n\nb.x=[-5+/-rt(25-56)]/4\n\nc.x=[-7+/-rt(49-64)]/4\n\nd.x=[-5+/-rt(25-72)]/4
357953
1st one:\n\n5x-2y=-5; flip 2y to other side\n5x=2y-5; divide by 5\nx=2/5y-1; put this into 2nd equation for x\ny-5(2/5y-1)=3\ny-2y+5=3\n-y=3-5\n-y=-2\ny=2\n\nput this into 2nd equation for y\n2-5x=3\n-5x=1\nx=-1/5\n\n2nd one\n8x-4y=16; divide by 4\n2x-y=4; flip 2x to other side\n-y=4-2x; multiply by -1\ny=2x-4; lo and behold this is exactly the same as the 2nd equation - can't be solved with substitution, equations 1 and 2 are the same\n\n3rd one\n4x-12y=5; divide by 4\nx-3y=5/4; flip 3y to other side\nx=5/4+3y; substitute this into x in 2nd equation\n-(5/4+3y)+3y=-1; simplify\n-5/4-3y+3y=-1; cancel out the -3y and + 3y\n-5/4=-1; well, how can you have -5/4 ever equal to -1, equations are not the solvable (unless either of the numbers equals infinity)