Exogenous and endogenous forces
213043
observed phenomenon in economics where the economy experiences booms and slumps. Any force that influences national income would influence the business cycle.\n\nY = C + I + G + NX\n\nNational Income = Consumption + Investment + Government + Net Exports.
133779
This is not Newtons third law. the two forces you mentioned does not form action reaction pair. they act on the same body. Newtons third law in this case is : action : force of gravity exerted by the earth on the book , reaction : force of gravity on earth by the book. and action : normal force on the book by the table , reaction : force exerted by the book on the table in the downward direction
243117
If the forces are both acting in the same direction, add them together. = 65 Newtons
128435
B.  The acceleration is towards the Earth and the force is constant.
407832
To understand this quandary you must look at a much bigger picture. since gravitational force is determined by an objects mass the earth actually exerts a much greater force on the object than the object exerts on the earth. Now this is where you must remember Newton's second law - if an unbalanced force acts on an object the object will accelerate in the direction of the force. The unbalanced force is the force of gravity the larger mass (earth in this case) exerts on the smaller object. The acceleration in the direction of the force is what we call gravity. It is true that the object exerts a reaction force but the maximum force it exerts is only the force of gravity it can generate based on it's mass. Since it weighs less it's force is not strong enough to move the earth.
458576
Glad to see you're thinking, but this is an easily answered question.  \n\nTake for example a magnet.  Regardless of what is in front of your magnet it will still attract an object to a distance equal to its strength.\n\nex:\n\n.....(|)<<<< <[]<<<<<<<[]          \n\n......^..............^...... ......^\nMagnet......Metal..... ..Metal\n.................Object.... Object\n\nThe magnet is going to exert force on both of the objects without interference from first object.  \n\nBased on your definition of propagate...come to your own conclusion...that is the joy of thinking...we all have our own thoughts.
471495
its newtons first law, (objects in rest stay at rest unless a force is acted upon it which causes acceleration) and objects in motion stays in motion\n\naka intertia keeps the smaller peices moving in the same direction
75497
There is no such thing as an unbalanced force in physics because of Newton's Third Law: for every action, there is an equal and opposite reaction. So for every force that exists, there has to be an opposing force that balances it out.
442090
The answer is C. Although B seems to be a possible answer at first, there could still be an n-number of forces acting on the object such that the sum of all the force vectors is zero, thus making C the more complete answer. One of Newton's laws says that F=m*a (force on an object equals its mass times its acceleration), or a force of 1 Newton on a 1kg object will make it accelerate at a rate of 1m/s^2 in the same direction of the force.
396265
try the formulas:\n\nforce = mass * aceleration\n\nwork = force * distance\n\n\n\n\nWell i dont speak english very well, but i hope i help u.\n\nKisses
540929
The gravitotional force F of two masses m1 and m2 separated by a distance r is given by the equation\n\nF = G * m1 * m2 / r^2\n\nwhere G is a physical constant with value 6.67*10^ -11 N*m^2/kg^2\n\nSInce the third object is placed midway then its distance from either m1 or m2 is 0.15 m.\n\nSubstituting we get\nF1=3.9*10^-5 N\nand\nF2=9,5*10^-5 N\n\nSince the two forces have opposite directions then \nFtotal = F1 - F2 = -5.6*10^-5 N having the direction of F2.\n\nIn order for total to be zero we have\nF1=F2 ->\nG*m1*m/x^2=G*m2*m/y^2 ->\nm1/x^2 = m2/y^2 ->\nm1*y^2=m2*x^2 (1)\n\nwhere x and y the diastances of m from m1 and m2 respectively.\n\nsince\n\nx+y=r=0.300 m\n\nit follows that y = 0.3-x (2)\nCombining (1) and (2) we have\n\nm1*(0.3-x)^2=m2*x^2 ->\n215*(0.09-0.6*x+x^2)=515x^2 ->\n300x^2+129x-19,35=0\n\nsolving this we get\n\nx1=0.12m\nand\nx2=-0.55 m which is of course rejected since it represents a point where there can be no equilibrium.
364708
1. friction\n2. W=mg  , he has a mass of 100Kg. Weight is the force=newtons, g=pull of gravity N=100 x 9.8m/sec^\n98Newtons\n3. correct
330307
In all the phenomenon force is the rate of change in momentum.\n\nBut the cause of change in momentum is different for different phenomenon.\n\nThe inertial force is caused by the collision of two objects;\n\nThe gravitational force is caused even when the objects are separated.\n\nThe concept of field of force comes in.\n\nThe electro-static force is caused because of charges and is acting on the masses and acting at distances.\n\nHere again the concept of field of force comes in.\n\nThere is close range attraction of forces and repulsion of forces in nuclei.\n\nThus it is natural to think of a cause which is the origin of force.\n\nYou have understood the uniqueness of force in these entire phenomenons.\n\nBut the cause is not unique.\n\nI don’t know whether it has been found or not.
10081
1.Objects at rest tend to remain at rest, and objects in motion tend to remain in motion in a straight line at constant speed.  2. Force=Mass times Velocity. 3. Every action has an equal and opposite reaction.
475817
In an isolated system (one where there are not external forces) the total momentum will be constant. There is not any exception.\nIf an external force is acting on a mechanical system, second law of Newton is applied:\ntotal external force = (total mass)*(acceleration of center of mass)
369736
Given a rotating hub or wheel all the centrifugal forces are along the radii from every point on the hub to the center. Because of circular symmetry, all the these forces will cancel; one pointing up is cancelled by one pointing down. Therefore the net external force is zero; there is no way the linear motion is influenced.
475725
you need to identify that there're two parts of the force, one acting horizontally, the other acting vertically.\nSo:\n1) the vertical part is:\n70sin30\n2) tje horizontal part is:\n70cos30