ALERT\nRead the followinf first then answer:What are the dimensions of the photograph? Hint:Do you want to add to or subtract from each side\nA picture frame containing a photograph is 11 inches wide and 14 inches high. A mat arount the photograph is 1 and 1/2 inches wide on all sides.
216642
8X11\n\nThink about two boxes.  The outer box is 11X14.  The inner box is smaller, so you subtract.  You have to subtract 3 inches in each direction, so 11-3=8, and 14-3=11.
375864
slope should be zero as you say that the mirror image was right in front of it ( parallel in other words )\n\nintercept should be +n as that should be the distance between the centre point and the images.
654319
It works... (see mine!)   Just use any digital camera to capture your image (b&w works best, as it is a smaller file) and make it as small as possible!   Save as a gif or jpg, and voila!
109973
At a Family Dollar Store or a craft store they carry those corner pieces for pictures.  They are two sided tape corners.  Place them on the picture first then peel off the other part and place where you needed it.  Also you could use a glue stick on the back of the pictures, but in time the glue might wear off.
274453
I recommend you use http://www.villagephotos.com instead. I have used them for a long time and whatever pic you upload in it, is the actual size.\n\nIts free too =)
615749
Down loading from where? How big of a file? or are you trying to up load (pic on your computer uploaded to the internet?) If the Pic is on your computer you can use a program from ShowYourPhotos.com. hope it helps
555402
Let: L=length, W=width, P=perimeter\n\nL=5+2W\n\nP=2L+2W, P=112\n2L+2W=112\nSubstituting L into the equation, we get:\n\n2(5+2W) +2W = 112\n10 + 4W + 2W = 112\n6W = 112-10\n6W = 102\nW = 17\n\nL = 5+2W\nL = 5+ (2*17)\nL = 39\n\nSo, the dimensions of the frame is 39 x 17 inches.
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you need a photo software to edit , re-size and organize the pics , you can get a Free software here : http://downint.googlepages.com/photosoftware
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Total area = 120\nArea of picture = 8*10 = 80\nArea of border = 120 - 80 = 40\n\nArea of border\n= Area of both - Area of picture\n= (8+2x)(10+2x) - 80\n-- where x is the border width\n-- 2x because there are borders on both sides of the picture\n\nSo\n(8+2x)(10+2x) - 80 = 40\n80 + 16x + 20x + 4x^2 - 80 - 40 = 0\n4x^2 + 36x - 40 = 0\nx^2 + 9x - 10 = 0 --- div. both sides by 4\n(x+10)(x-1) = 0\nx = -10 or 1\n\nBut as this is length, -10 is not applicable.\n\nSo the width of the border is 1 unit.
495521
The poster is x cm wide, x + 24 cm tall.\n\nThe poster plus border is 20 + x cm wide, 20 + 24 + x cm tall (with the border).  \n\nThe area of the poster is x^2 + 24x.  The total area is (20+x)*(44+x) = x^2 + 64x + 880.  The area of the border is the difference, so \n\nx^2 + 64x + 880 - (x^2 + 24x) = 2400.\n40x + 880 = 2400\n40x = 1520\nx = 38\n\nSo the area of the poster is 38 times (38 + 24) = 2356 cm^2
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Area=width*length=12*9=108 i.e \nC
159288
After the collage was made in Paint, Save it as a JPEG file (use File > Save as and choose JPEG).\n\nNow when you use it, the size is likely to be less than 50K. If it still isnt less than 50K, reduced the size of the collage.
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About the song, that's odd. Are you sure it's working that way for everyone that accesses your page? Maybe you should ask someone else to check it out for you.\n\nOk, to make your photo smaller all you have to do is get on microsoft paint. You open up your picture, you go to the upper bar and you choose Image/Picture. You click and you will choose expand or contract. (These translations may be wrong because my computer's in spanish), then here's where you can play around with your picture. If you want to reduce your picture by half, then on the two first boxes write "50", leave the two boxes on the bottom as they were. Then click accept. You will notice your picture has been shrunk by half, so the size in kbs, of course, has changed as well. You can also put 60, or 70. Depends on how small you want your picture. If you wish to return to the original size, you can Undo changes or you can simply Expand (using the two boxes on the bottom, if you have shrunk your picture by 50, expand by 100, by 60, expand by 120 and so on).\n\nIt's pretty simply. I know I gave a huge explanation but I hope it works, because I always use this method. \n\nThen save changes...you can save as, to keep the 600 kb separate from your new smaller picture.
393216
you can use photoshop. just assemble the pics together in there.
544558
1) You need to solve these equations first...\n\nW*L = 192\nL*H = 128\nH*W = 96\n\nLet's multiply the first two equations by each other:\nW*L * L*H = 192 * 128\nH*W * L^2 = 24576\n\nNow divide this by the last equation:\nL^2 = 24576 / 96\nL^2 = 256\nL = 16.\n\nNow you can figure the rest of the dimensions:\nW*L = 192\nW*16 = 192\nW = 192/16\nW = 12\n\nW*H = 96\n(12)*H = 96\nH = 96/12\nH = 8\n\nSo the dimensions are:\n8 inches high, 12 inches wide, 16 inches long.\n\nThat's 2 cubes high (2 x 4" = 8"), 3 cubes wide (3 x 4" = 12"), 4 cubes long (4 x 4" = 16").\n\nAll together that is 24 cubes (2 x 3 x 4 = 24)\n\n2) If you shrink everything by a factor of 2.54 (to get centimeters) the answer doesn't change at all.  Since every dimension changes to cm, the box shrinks and so do the cubes.\n\nYour dimensions will be 8 cm x 12 cm x 16 cm.  With a block that is 4 cm on each side, you still fit 2 blocks x 3 blocks x 4 blocks = 24 blocks.
407016
Let's say   x=width, y=length\nSince length is 6cm longer than width:  y=x+6\nThe area of the painting is therefore:  xy\nThe mat is 2cm wide surrounding the painting, so the dimensions are increased by 4cm each\nThe mat is covered by a piece of glass that is:  352cm squared\nSince the area of the glass equals the area of the mat  + the area of the painting, we have:  (x+4)(y+4) = 352\nSubstituting for y, we get:  (x+4)(x+6+4) = 352\nWhich when multiplied out and simplified, becomes:\nx*2 +14x - 312 = 0\nFactored, this gives us:   (x+26)(x-12)=0\nFor this equation, if either term equals 0 then the equation holds true, therefore:   x = -26 or +12\nSince -26 doesn't make sense for a measurement, then x must equal +12\nSo the dimensions of the painting are:   x=12 and y=12+6=18
397849
OK, first, calculate the amount of wrapping paper used on a single present.  Of course, some extra paper is used in the various folds and such, but I get the feeling that all this question is interested in is the amount of paper needed to cover the surface of the box.  The surface area is equal to the combined area of the sides.  So you have two sides which are 8.5"x2" or 17 in^2.  You have two sides which are 12"x2" or 24 in^2.  And you have the top and bottom, which are each 8.5"x12" or 102 in^2.  So the total surface area is 2(17) + 2(24) + 2(102) = 34 + 48 + 204 = 286 square inches per present.\n\nNext, calculate the amount of wrapping paper used per person.  Since the average person wraps 2.3 gifts, they would need enough wrapping paper for 2.3 boxes.  That's 2.3 * 286 or 657.8 square inches per person.\n\nNext, calculate the amount of paper used by the whole town,  That's 657.8 square inches per person * 26000 people = 17102800 square inches.\n\nFinally, I'd get this into a more manageable form if I were you.  I think a standard roll of wrapping paper is a yard across, so I'll put the result into square yards.  There are 36 inches in a yard, so there are 36^2 or 1296 square inches in a square yard.  So you divide the number of square inches by 1296 to get 13,196.6 square yards.\n\n(I realize that from the wording of the problem, you're probably not American, but if you need it converted into metric, I'm afraid you're on your own.)