can h2s be breackdown by a high ph compound?
218447
H2S in solution is a weak acid and so will react to produce Water plus a sulphide salt with any strong base.
384105
The water isn't involved in the reaction, so take it out.  Then, just put a 2 in front of the Nh2(SO3)H and a 2 in front of HNO3, and you're finished.\n\nNow, go take a nap or go to sleep...
198528
try this site.  if you ever need to look up other chemicals, etc. search for msds b/c that is where all the info on storage, etc will be.\n\nhttp://www.chem.tamu.edu/class/majors/msdsfiles/msdsleadsulfate.htm
139250
I am pretty sure that it is due to polarity.  Since sulfur forms nonpolar S8 molecules, they are nonpolar, where water has a + end and a -end, making it polar (has a dipole moment).  The general rule is like dissolves like.  Molecules that a alike can interact on  the molecular level and form solutions, unlike molecules can not.
553114
H2SO4 will dehydrate and remove water.\n\n\n(CH3)2 CH - CH2-CH=CH-(CH3)2
232765
Write out the balanced reaction which occurs.\n\nSince both NaOH and H2SO4 are strong electrolytes (strong base, strong acid), we can assume both dissassociate completely and the reaction produced Sodium Sulfate and water,\n\n2NaOH + H2SO4 --> 2H2O + Na2SO4\n\nFind limiting reactant in order to find which  will be left over (either NaOH or H2SO4).\nIn order to do this, you need to know both the concentrations of the NaOH and the H2SO4 in order to find the initial number of moles of each.\n\nOnce you know how many moles of either OH- or H+ are left over, you can then find the pH, or pOH like this,\n\npH = -log ([H+])\npOH = -log ([OH-])\n\npH + pOH = 14\n\n*Remember to take into account that the final volume of solution is the sum of the intial volumes of each othe reactant solutions when calculating pH.\n\nEDIT:\nYou know, it just occured to me, I dont know why I even brought up pH, that was not what the question was asking.  but everything I said still stands in order to calculate the molarity...you just dont have to go the one extra step and calculate the pH by taking the negative log of the molarity concentration of H+ ions.\n\nAlso, for all of you out there who are just given answers with not other explanation, it would be nice if you stated what the concentration was of....salt? NaOH?  H2SO4?\nBecause of this ommision, I would highly inclined to disreguard their answers as numerically incorrect as well.
348314
use the molarity x volume = molarity x volume equation, but beware that the H2SO4 shells out 2 protons, not 1.
461016
Sulphuric acid when it ionises in solution, will form 2 H+ ions per molecule of H2SO4 originally present.  Or rather, for each mole of sulphuric acid present, 2 moles of H+ will form.  The strength of an acid obviously depends on the number of H+ present in the solution.\n\nHCl on the other hand will only produce 1 H+ per molecule of H2SO4.\n\nIf you follow the same logic, H3PO4 should have produced 3 H+ per molecule of the acid and hence become the strongest.  Unfortunately it is not as simple.  Although, phosphoric acid can indeed ionise to form 3 H+, it is not energetically profitable.\n\nH3PO4 → H+ + H2PO4–       Ka1= 7.5×10^−3\nH2PO4–  → H+ + HPO42–       Ka2= 6.2×10^−8\nHPO42–  → H+ + PO43–       Ka3= 2.14×10^−13\n\nAs the Ka values decreases, it means that it becomes less easy for the reaction to proceed.  In the case, you can see that it is quite easy for a molecule of phosphoric acid to ionise forming one H+.  But further ionisations are quite difficult due to the smaller values of Ka.
455959
A stabilizer is often necessary when using H2O2, because that compound tends to decompose, especially in the presence of trace amounts of many metallic ions.  In fact, if even a minute amount of, say, Cu++ is present, the decomposition can be violent.
389304
a) neutral\nb) basic\nc) basic\nd) acidic\ne) acidic if in solution\nf) basic.\n\npH is a scale ranging from 0-14.  7 is the intermediate and a pH of 7 means that the solution is neutral.  If the pH is below 7, then there are more H+ than OH- in the solution.  Hence the solution becomes acidic.  If the pH however is greater than 7, then there is less H+ than OH- in the solution and the solution is basic.\n\nFor the acid H2SO4, when in solution, it will dissociate to form H+ and SO4-.  The H+ gives the acid its acidic property.  Similarly when Ca(OH)2 is dissolved, it dissociates into Ca2+ and OH-.  The OH- gives the compound its basic property.
60286
Do not capitalize the spelled-out names of chemical elements and compounds. When using symbols, use capital letters but no periods.\n\ncadmium Cd\niron         Fe\nsulfuric acid H2 SO4
508336
I would say CH2O2 (I'm assuming you mean formic acid, not dioxirane), CH3CO2H, and water.  \n\n"Important" is a tough word here, as all of these compounds can participate in h-bonding to varying degreees, with water being the strongest and CH2F2 being the weakest.  That said, strong hydrogen bonding gives rise to many of the nifty properties of water and in all three cases the h-bonding is powerful enough to raise the boiling points to be significantly higher than what you would expect based on molecular weight.
401379
both of these two above ^ are wrong \n\nthere would be no reaction.\nall you're doing when you heat something is giving it energy which  causes its atoms (if it's an element) to move faster, which will change it to a higher state of matter. The gas state is the highest state of matter and H2 is the gas state of hydrogen. Since it's alreay in the highest state of matter, nothing would happen \n\n\nit would not form 2H because hydrogen is diatomic \nHydrogen only exists as a hydrogen ion (H^1+) in solution.\nand it only exists as a single atom in a compund.\nHowever, If you burned hydrogen in the right proportions of oxygen then it would be explosive, but that is not the case. \nAnd it would not be exothermic because if it was, heat would be on the product side of the equation.
345372
No surprise at all, the transition does not take place at an pH of exactly 7 but already before. Take a look here for a graph:\n\nhttp://antoine.frostburg.edu/chem/senese/101/acidbase/faq/indicating-strong-or-weak.shtml
417166
Yes you can; the reaction is only contingent upon having free H+ ions floating around.
444550
if the reaction involves H2SO4 and heat, it is most likely going to be an elimination meaning the OH group will leave and there will be forming of a double bond between the carbon where the OH group was and an adjacent carbon. where this new double bond is formed is determined by zaitsev's rule which says that the product formed will have the most substituted double bond meaning the double bond with the most carbon substituents attached. understand this and you will find your answer and learn some friggin chemistry at the same time.
99468
Maybe the HCl concentration is too high?  Pepsin is active at pH 2.5.  Also how do you know the 'fish sample' is actually being broken down by pepsin?