I know that this is a silly question, but how do I find the wavelength minimum?  the visible spectrum goes from 400nm to 750nm and I can't figure out how to get the wavelength minimum.  I know that the minimum equation is sin(theta)=wavelength/D....Can someone help me I have tried many things?
210442
The equation is just for the angle of a particular wavelength. Not for resolution. Say 250nm,300nm look like 2 lines and not one. \nI think you want to look up diffraction limits. \nSimple experiment is to compare a CD rom and DVD see how they split wavelengths.
522809
This seems to be equivalent to saying what is the maximum frequency of a sine wave with a maximum amplitude of 1.1e-6 metres and  maximum acceleration of about 9.8m/s^2.\n\nLets have a think , the area under 1/2 a cycle of sin is a/2*period/2 and period is 1/f so max v = a/2/2/f  - ha!  similarly max_v/2/2/f= max acceleration = a/2/2/2/2/f/f , that's better.  a/16/f^2 > g  gives max acceleration > g  so \nf^2 > g/16/a  or  f > about 750 Hz.
417255
Let x = distance of object from stronger source. If weaker source has strength S then stronger source has strength 3S.\n\nIllumination due to stronger source is 3S/x².\n\nIllumination due to weaker source is S/(12-x)².\n\nRequired to minimize the total illumination\n 3S/x² + S/(12-x)², or ignoring S, minimize \n\n          t(x) = 3/x² + 1/(12-x)².\n\nDo the usual t '(x) = 0 and check t '' > 0. After simplifying t '(x) = 0 get\n\n          3 (12 - x)³ = x³\n\nTake cube roots and simplify to get\n\n          x = 12 / [ 1 + 1 / 3^(1/3) ]\n\nand on further simplification\n\n          36 / ( 3 + 9^(1/3) ) = 7.086497 feet\n\nYou can check the answer using WIMS Function calculator and selecting "curve"
442788
You need to get your units in a consistent form.  I suggest changing the velocity of the electron to 2.5E6 m/s so when you divide it into c-----------WAIT A MINUTE!-----Yor formula is NOT right, because you're dividing a speed by a speed, which will give a dimensionless answer.  Wavelength is a LENGTH, so the answer must come out that way.  I forget the formula you're refering to, but what you've typed isn't it................
543653
Use the relation wavelength*frequency=velocity of light\nWavelength= velocity of light /frequency\n                 =6*10^4/3*10^8\n                 =2/10^4 meters\nmultiply this by 10^9 to convert into nm\nu get 2*10^5nm
668939
It is correct that the visible wavelengths of electromagnetic radiation  are from 400nm (violet) to 700nm (red); but that is because of the way the eye perceives light, and has nothing to do with the way waves interact with each other.  Also, because of the way the eye sees color (and not due to the nature of the waves) many colors can be produced either by a  single wavelength of a combination of two or more wavelengths.  For additive color reproduction three primaries are selected (red, blue and green) because they produce the widest range of other colors (gamut), probably because of the way the eye works.  Other primaries can be used, but they will result in a more limited range; also more primaries can be added to increase gamut.  How selected primaries are combined to create other colors is shown in the "CIE color chart".
334830
The basic idea for maximum reflectance is that the optical phase thickness, the refractive index times the physical thickness, is equal to one half the wavelength of light.  It could be this minimum thickness for the zero order effect, or some integer multiple of half the wavelength plus one half wavelength.\n\nThe minimum physical thickness of the oil film would be\n\nl = lambda/(2n) = 640/2.5 = 256 nm.\n\nSeems like a low index of refraction for oil, though.  There would also be a maximum reflection for this wavelength for 512, 768, ...\n\nThe condition for zero reflection is that the optical thickness is equal to one quarter wavelength.\n\nl = 512/(4n)= 102.4\n\nAlso, 512/(2n) + 102.4 = 307.4, 512/n + 102.4 = 512, and so forth.\n\nNow, 512 is sort of a blue-green color, but no matter.  Also the refractive index should depend on the wavelength.  But this cooked up problem has a solution for both wavelengths when \n\nl = 512 nm \n\nis the thickness of the oil film.  There are other correct answers, but this is the minimun thickness to meet the requirements of the two wavelengths given.
142870
The intensity in a rectangular difraccion pattern is given by: \nI(theta)= I(0) [Sin (beta)/beta]^2\n\nThe minima are located where sin(beta)=0\n\nSo thats why you have to put beta=n*Pi as the condition to find a minimun\n\nMaxima are located at tan(beta)=beta which is a non analytical ecuation but a solution can be found graphically or numerically\n\nMaxima are at theta= 1.4306*pi    2.4590pi  3.4707pi
396344
Sanity check. Ultraviolet light is energetic light, which will break bonds, which is why it can be dangerous. UV light is shorter than about 400 nm. So after throwing around the big exponents, we want an answer less than 400 nm, but probably larger than 100 because then it's x-rays, which is usually overkill for breaking molecules apart. \n941 kJ / mol means 941,000 joules are sufficient to break \n6.02x10^23 molecular bonds. ( 1 mol is Avagadro's number)\ndivide it out and get how much to break just one N2 bond:\n941,000 J / 6.02x10^23 molecules = 1.56 x 10^-18 joules\nWhat wavelength of light corresponds to that amount of energy being packed into one photon? \nE = hc / lambda, where h = 6.63x10^-34 m2 kg/s (Planck), c = 2.228x10^8 m/s (speed of light), and lambda is wavelength in meters (staying in mks units, E will be in joules). Solve for lambda, where E is 1.56 x 10^-18. \nlambda = hc/E = 1.274 x 10^-7 meters\nmultiply by 10^9 to get nm, then lambda = 127.4 nm\nLooks good to me...  There might be a simpler cookbook equation to get this answer, but it's good to know how to do it from the basic constants of nature. \n\nNote: previous answer left out factor of Avagadro's number and did no sanity check...
441714
use the formula sinA/sinB.\nA is the angle of incidence,B is the angle of refraction.\nso in this case it is sin40/sin25 = 1.52(to 3sig. fig)
345141
Fringe width β= λD/d\nIf the wavelength is decreased,  the fringe width also decreases.\nSo, if you consider any order fringe, say 5th order, it would form at a lesser distance from the centre as compared to the previous case(i.e.when red light was used)
452858
The wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength. That number, also known as the frequency, will be larger for a short-wavelength wave than for a long-wavelength wave. \n\nThe equation that relates wavelength and frequency for electromagnetic waves is: λν=c where λ is the wavelength, ν is the frequency and c is the speed of light.
17468
The last answer is correct.  The equation:\n\nA*sin(bx+c)\n\nCan be graphed.  A is the amplitude of the wave (how high along the y axis).  b is the frequency (how fast do you need to complete one wavelength).  c is a wavelength shift, how far away from x=0 do you have to start the wavelength.
50724
E=hc/lamda  (h: Planck constant, h=6.626*10^-34 J.s^-1\n             c: speed of light,  c=3.00*10^8 m/s\n             lamda: wavelength, lamda=478.0nm=0.478*10^-6 m\n\nE= (6.626*10^-34*3.00*10^8)/(0.478*10^-6)\n = 4.157*10^-19 J
512158
KNOWN:\nf = 3.2 x 10^-2 Hz\nc (ie speed of light) = 3.00 * 10 ^8 m/s\n\nFIND L (AKA wavelength)\nL m = c m/s  /  f Hz\n= 3.00 * 10 ^8 m/s  /  3.2 x 10^-2 Hz\n= 9 375 000 kilometers\n\nAre you sure its 10^-2 Hz? That seems unlikely
102158
The limit as sky goes to zero from the positive direction would be ground.\nLim    = ground\nsky-->0+\n\nThe limit as sky goes to zero from the negative direction is space.\nLim    = space\nsky-->0-\n\nSince the limit from the + site does not equal the limit from the - side, the limit does not exist.
455171
The frequency in the number of times the wave vibrates in one second. \nIn your question, you probably have light.  The speed of light is 300,000km/s.  If you multiply the frequency and the wavelength, you get the speed.  That is v=lf\nThat 595nm is actually 595x10e-9m or 0,000000595m\nThe speed of light is 3x10e8m/s\nSo the frequency is\nf=v/l\nf=300000000/0.000000595\nf=504201680672268.91\nf=5.1e14 hertz