Please subtract, show your work.If possible please give a brief explantion of how to do the problem.\n\nThank you.
207055
you subtract like terms.  \n5x^2 - 9x^2 = -4x^2\n-3x - (-5x) = -3x+5x = 2x\n6 - (-3) = 6+3 = 9\n\nTherefore, the final answer is -4x^2 +2x +9
71311
try working with BODMAS (BRACKETS Of Multiplication Division Addition Subtraction) and of course equalising the denominator. Hope that helps
399731
Subtract 8 from each side of the = sign and you have your answer\n\nx equals -11
199005
1.) A - 0.6666666\n2.) C - $12.26\n3.) B - 0.308\n4.) C - 19.87\n5.) A - $.65
126391
Probably easier to show by example.\n4x2+8-:-4-1 (-:- = divide)\nmultiply any numbers first, then divide, then add and subtract.\n\nYou could add brackets in if that helps you.\n(4x2)+(8-:-4)-1 = 9
81537
add 2 pi to each, then subtract 2 pi from each.\ndo it just like you do fractions, and carry along the 'pi'
114438
Goto this site and look at problem #24 and you will see the solution to this problem...in the end the answer sec x.\n\nhttp://noether.uoregon.edu/~montgome/math251/homework/Section3.8.pdf\n\nI hope this helps...\n\nDon
612505
[ (50000 x 2.4)+(25000 x .8) ] / (50000+250000)=1.8\n\nThe remainder of the info in the problem is not necessary.
454505
hmm im not quite in college yet, but i hope to be help.\ndo you know the values for f, h, v, and a?\nif you do, id substitute it in.\nthen square both sides. \nand then solve.
534929
I have factored it please refer to.\n\nFrom this solution can be found
484842
Well, you got me stumped!\n\n-------------------------------------\n\nI started working it out and got pretty far.\n\nThe above given information might be incorrect.  Maybe?  I don't know.\n\nI tried it several times.  I even double and triple checked my work!\n\n---------------------------------------------\n\nThis is as far as I got and then I got stumped:\n(D-E) (B+C) = (10J + AFGH) / A\n\n------------------------------------------------------\n\nGreat question!\n\nI look forward to the continuing discussion.\n\nI love the way you worded your question.  Right on!!!\n\nKeep those challenge questions coming!  ;o}
446456
Make sure the order is maintained:\n\nAdd 1 to x: x + 1\n\nThen multiply by 6: (x + 1) * 6\n\nFor the other equation, divide by 6: x / 6\n\nThen subtact 1: (x / 6) - 1\n\nThe trick is to take your time and read the problem statement throroughly. Good luck.
78362
i think u typed the question wrong, can u please correct it and if u have 2 unknowns, please give 2 equations, else u cant get a definite solution
447345
When you retry the problem remember to move only yout z^-2 up don't move the 4 that is a constant in the denominator. \n\nyou should get this . (12x^5z^3/30x^7y^7) * (15x^2z^10/4y^3)\n\nremember to simplify as best you can prior to multiplying.\n\ntry from here and let me know what you get.
6802
firt you work the problem in the parentheses. that would be (2*-5)+ 4. that would make it -10+4. that equals -6. then you take that and multiply it by -5. that gives you a positive 30
606002
Mutiply $28 by 0.30, then subrtact 28 again, and that should tell you how much it is. ($19.60. It will come up as -19.60 though, just ignore the negative)
239169
i. is  pretty easy, just subtract one eq. from the other (2)-(1), leaving you with 2y=6 -> y=3. plugging into the eq. leaves x=2.\n\nii. subtraction again (2)-(1), leaving y=4, substitution yields x=2\n\niii. think of all the integers that have the product 35...done yet? just -1 x -35, -5 x -7, 1 x 35 & 5 x 7. see which works for the other eq.: x=5, y=7\n\niv. if (1) is 2^(x+y)=1 we can conclude x=-y, then there is no solution, since the exponent in (2) will be negative and the answer will always be less than one.\n\nif (1) is 2^(x)+y=1, then 2^x=1-y -> y=1-2^x\nplugging that in the second eq. & simplifying:\n2x(1-2^x)=3\n2^x=(2x-3)/(2x)\n2^x=1-(3/2x)\n\nAfter that, you'd have to use logarithms to solve it, which I'm not too keen on, so I'll leave the rest of the computation up to you. after you find a value for x, plug it into y=1-2^x to find y.