Express the following measurements as a number word preceded by a 1.\n\n100 liters...help
203966
100 liters equals one what?\n\nKangaroos Hop Down Under drinking chocolate milk - KHDUdcm\n\n\nK Kilo\nH Hecto\nD Deca\nU base unit (liters in this case)\nd deci\nc centi\nm milli\n\n\nHow many places do you need to move the decimal to make 1?  2 to the left.  So start with liters (the U) and move to the left 2.  It's H, which stands for hecto so 100 liters = 1 hectoliter.\n\nNow you try to do the rest of them, or you won't make a good grade on the test :)
283518
Just "m" (always lower case)\n\n1 km = 1000 m
104086
l = length\nw = width\n\nl = 8w\n\nlw = 128\n(8w)(w) = 128\n8w² = 128\nw² = 16\nw = 4\nl = 8(4)\nl = 32\n\nWidth is 4 feet.
521877
The Specific Gravity of water is 1
539366
Here's how to think about it.  In the end you will be mixing so many liters of 30% mixture and so many liters of 100% mixture.\n\nLet a be the amount of 30% mixture.\nLet b be the amount of 100% mixture.\n\nAdded together these must equal 16 liters:\na + b = 16\n\nAlso, you want the mixture to equal 50%.\n30% x a + 100% x b = 50% x 16\n\nYou have two equations and two unknowns, so this should be solvable.\n\nLet's solve for a:\na = 16 - b\n\nSubstitute this into the second equation:\n30% x (16 - b) + 100% x b = 50% x 16\n\nYou could do this all with decimal amounts (30% = 0.30, 50% = 0.50) etc.  But it is easier to just do them as whole amounts (30, 100, 50).  The answer will work out either way.\n\nDistribute through:\n30 x 16 - 30b + 100b = 50 x 16\n\nSimplify:\n480 - 30b + 100b = 800\n\nCombine like terms:\n480 + 70b = 800\n\nSubtract 480 from both sides:\n70b = 800 - 480\n70b = 320\n\nDivide both sides by 70:\nb = 320 / 70\nb = 32 / 7\nb = 4 4/7 liters\n\nSo you will need to drain 4 4/7 liters of the 30% mixture, then add 4 4/7 liters of the 100% mixture.\n\nAs a double check:\na = 11 3/7\nb = 4 4/7\n\n30% x 11 3/7 + 100% x 4 4/7 =? 50% x 16\n30% x 80/7 + 32/7 =? 8\n24/7 + 32/7 =? 8\n56/7 = 8 <-- check\n\nSo the correct answer is you must drain 32/7 liters, or 4 4/7 liters (as a mixed fraction).\n\nAs a decimal, the answer is approximately 4.571 liters.
272713
1 cc = 1 ml\n1000 ml = 1 liter\n3.8 liters = 1 gal = 4 qts\n4/3.8 = 1.05 qt per liter\n1.05 * .800 = .8421 qt per 800 cc\n.8421 * 32 oz per qt = 26.95 oz per 800 cc\n26.95/8 = 3.37 cups per 800 cc
463851
http://www.translatum.gr/converter/measurements.php\n\nhttp://www.easysurf.cc/cnver7.htm
516840
291.13 L is the correct volume.\n\nCheck your algebra when you are solving for V1.
314939
It will be \n1, \n3, \n9 and \n27. \n\nAnd you can easily get all the measurement from it. I ve counted all that.
186964
volume = 3x2x2 = 12 cubic feet\n\n1 litre = 100 cubic centimetres\n\n30 centremetres = 1 ft\n\nwork the rest out, come you can do it
670883
multiply by 100 and divide by the other amount of water
481319
If L = Length\nW = width\nPerimeter = P = L + L + W + W\nP = 2L + 2W ... (1)\n\nBut in this question \nL - 5 = 3W\nL = 3W + 5 ... (2)\n\nSubstitute this value of L in (1)\nP = 2(3W + 5) + 2W\n\nP = 46\n46 = 2(3W + 5) + 2W\n46 = 6W + 10 + 2W\n46 - 10 = 6W + 2W\n36 = 8W\nW = 36/8\nW = 4.5 cm\n\nSubstitute this value of W in (2)\nL = 3W + 5\nL = 3(4.5) + 5\nL = 13.5 + 5\nL = 18.5cm\n\nCheck ...1\nP = 2L + 2W\n46 = 2(18.5) + 2(4.5)\n46 = 37 + 9\n46 = 46!\n\nCheck ... 2\nL - 5 = 3W\n18.5 - 5 = 3(4.5)\n13.5 = 13.5!
91557
1cm3=1mL\n1000mL=1L\n.16L=160cm3\nYes you can use the jar
73812
Get the dimensions of the rectangular tank into the same units, then get the volume. the unit could be in^3, cm^3, m^3, ft^3, mi^3, mm^3, km^3, etc. Have them be converted to cm^3 using the ff. conversion units:\n\n1 mi = 5280 ft\n1 ft = 12 in\n1 in = 2.54 cm\n1 m = 10 dm = 100 cm = 1000mm = .1 dam = .01 hm = .001 km\n\nNow, 1 cm^3 = 1 mL. Have it converted into liters using 1000 mL = 1 L. To get gallons, use the ff. conversion unit:\n3.8 L = 1 gal\n\nHope this helps ^_^
150737
Use the formula PV=rnT\n\np= pressure in atm\nV= volume in L or dm^3\nr=number of moles\nn= constant: 0.0821 atm x L/ moles x K (This constant is used to balance out units)\nt= temperature in K\n\nSo for your problem:\n2.3 atm x 120 L = r x (0.0821 atm x L/ moles x K) x 340 K\n\nthe constant should allow you to be left with moles as your unit\nusing algebra, r is left, which also stands for the number of moles (meaning the problem coordinates with your question)\n\nusing this setup, i got 9.89 moles
606689
assume 0.1mm3\n6.02e22 mm3\n6.02e19 cm3 \n6.02e13 m3\n6.02e5 km3\nroughly 602,000 km3
536076
Volume of water\n=volume of flask\n=mass/density\n=183.07/.99754\n=183.52g\n=.18352 kg\n1000gm\n=1kg\n=1lit.\n.18352kg\n=.18352lit