Possible answers;\na: 1 gram x c2 of energy and 1 gram of matter\nb: 2 grams x c2 of energy and 1 gram of matter\nc: 1 gram x c2 of energy and 2 grams of matter\nd: 4 grams x c2 of energy and 2 grams of matter\ne: 4 grams x c2 of energy and 0 grams of matter
215968
oh, wow, this is a physics question.\n\nto start, we remember E = mc^2\nthe problem gives 4 grams matter and 2 grams antimatter.\nmy solution would be that 2 grams of matter and 2 grams of antimatter annihilate to produce 4c^2 (2 + 2 = 4) energy.\nthe excess 2 grams of matter remains unaffected.\nthe answer is D.
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1. D. 4000 g. because there are 1000 grams in a kilogram.\n\n2. B. 15 ft. 7 in. because you just have to add the feet and then add the inches (14 ft. 19 inches) and then change twelve of the inches into one foot. \n\n3. C. 10 hr. 20 min. because it is 8 hr. 20 min. from 3:40 AM to noon, and it's 2 more hours to 2:00 PM. \n\n4. A. 8,800 yd. because there are 1,760 yards in one mile, and then you just multiply by 5. \n\nI hope this helps. Don't just copy the answers, but make sure you UNDERSTAND the material. :)
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Amount of each element per one mole of the organic compound:\n\n264g (.5455) = 144.0g C / mol\n\n264g (.0909) = 24.00g H / mol\n\n264g (.3636) = 96.00g O / mol\n\nTaking those values to calculate the moles of each substance:\n\n144.0g C * 1 mol C / 12.00g C = 12.00 mol C\n\n24.00g H * 1 mol H / 1.00g H = 24.00 mol H\n\n96.00g O * 1 mol O / 16.00g O = 6.000 mol O\n\nThe moles of each element present in this substance shows it's at a ratio of 2 : 4 : 1\n\nIf the moles are related directly to the molecular formula, the molecule would be C12 H24 O6 (seperated for clarity)\n\nOtherwise it would just be another organic molecule that has an emperical formula of C2H4O\n\nOn a side note: I just took the AP Chemistry Exam today, and this problem is really easy compared to the stuff i saw on that test. It must have been the most difficult test I have ever taken!!
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A) 1\nB)2 moles of gas. ,1 mole of gas takes up 22.4 liters, so 44.8 L
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7. What you have to remember for this one is that even though the masses, volume, and temperatures are the same in each container, this doesn't mean that pressure or moles are the same. You can prove this simply by working out PV = nRT twice to see that pressures are clearly not equal. With that you can eliminate both a and d. You can also eliminate both b and c because...the AVERAGE kinetic energy of two different molecules at the same tempurature is the same!! This leaves you with e, which you would have figured out if you actually did PV = nRT before.\n-----------------\n8. For the simple answer, just memorize this...elements get smaller as you go up and to the right on the periodic table, with few exceptions. This means that Francium (Fr) is the largest element and Fluorine (F) is the smallest. So in a, we have Sodium, Magnesium, Aluminum, and Silicon - these are all right or each other, so these are in order of decreasing atomic size. B is the same. C is Carbon, Sulfur, Selenium, and Tellurium, these elements follow one another down the Carbon column (family), that means they're getting larger as you go down - this is your answer.\n-----------------\n9. Well, you can eliminate a, b, and c because none of them have a 'd' in it. That said, the electron configuration on any transition metal will contain 'd' with an exponent 1 through 10 and a coefficient starting at 3. This leaves us with d or e for choices. Since 4s^2 really comes before 3d^10 on the periodic table, e cannot be the answer because it has more information after 3d^10. But you can check anyway...1s^2 2s^2 2p^6 3s^2 3p^6 leave us at Argon (Ar), 4s^2 is Potassium (K) and Calcium (Ca) and 4s^2 leave you at Nickel (Ni), which is a transition element. The answer is d.
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1) Calculate the heat needed to melt 100 grams of ice completely: \nMass of ice * Heat of Fusion\n100g * 333J/g = 33300 J\n\n2) Calculate the cooling we can obtain \nMass of water * specific heat of water * temperature loss\n180g * 4.2 J/g K * dT = 33300 J => dT = 44.0 degrees\n\nConclusion we need only to melt 100g * 30/44 = 68.1 gram of ice to cool down the water to zero degree. 31.9 grams of ice remains.\n\n3) 1) Calculate the heat needed to melt 50 grams of ice completely: \nMass of ice * Heat of Fusion\n50g * 333J/g = 16650 J\n\n4) Calculate the cooling we can obtain \nMass of water * specific heat of water * temperature loss\n180g * 4.2 J/g K * dT = 16650 J => dT = 22.0 degrees\n\n5) Calculate the average temperature of the water.\nAfter melting of the ice we have 50 g of water at 0C and 180 g of water at 30-22=8C. This average out to 6.3C
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Fat has roughly twice the energy content per unit.\nFat- 9Kcal/g\nProteins/carbs 4Kcal/g
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1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 7.432 g x (12 / 44) = 2.027 g\nhydrogen: 4.057 g x (2 / 18) = 0.451 g\noxygen: 3.383 - 2.027 - .451 = 0.905 g\n\n2) convert to moles.\ncarbon: 2.027 / 12 = 0.169 mol\nhydrogen: 0.451 / 1 = 0.451 mol\noxygen: 0.905 / 16 = 0.0566 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.169 / 0.0566 = 3\nhydrogen: 0.451  / 0.0566 = 8\noxygen: 0.0566 / 0.0566 = 1\n\nThe empirical formula of the substance is (C3H8O)n\nThe atomic masses add up to 60, which is also the molar mass of the compound. Therefore n=1 and we find C3H8O
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Conservation of energy:  KE=PE\n1/2*Mb*Vb^2= (Mb+Mw)*g*h\nVb^2=2*(Mb+Mw)*g*h/Mb\nVb^2=2*(0.01+2)*10*0.1/0.01\nVb^2=402\nVb=20.05 m/s
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density=mass/volume\n\nd=125.6g/750cm^3=.1674g/cm^3\n\napproximately .167g/cm^3 (dont forget the cubed. if u forget it u'll get it wrong)
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Q (heat energy) = m(mass in gram)*c(specific heat in J/gm/K)*t (change in temp)\nQ = 25 * 1 * (36-24)\nQ = 300 J
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you are confused with the concept of density i think.\nthe closest you could come to say 1 ml = 1g is because of the density of water which is 1 g/ml at 4 C. \n\nin general cm^3 is the volume of a thing gram is its weight. \n\nso you may be saying that something weighs 1 grams and occupies 1 ml of space.\n\n1 ml = 1 cubic cm
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The previous definitions of mass and volume are correct.  As far as cereal goes, have you ever opened a box of cereal and noticed that it looks like the box is only 2/3 full?  It didn't come from the plant that way.  During shipment, the cereal settles, so it takes up less space when you get it home than it did when it left the plant.  It's the same amount (mass) of cereal, just taking up a different amount of space (volume).  If they sold it by volume, what would have been true when the cereal left the plant would be false advertising by the time it got to you.  In general, solids are sold by weight and fluids are sold by volume.\n\nFor the mass of a given volume of water, use the basic formula of 1 kg/L (1 g/mL).
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The terms are similar, but they do differ.\n\nDensity, as usually expressed, is in grams/cubic centimeter-----for example, the element mercury has a density of 13.6 grams per cubic centimeter.Density is non-variable.\n\nSpecific Gravity is a way of relating weights of substances to the weight of water. Therefore, specific gravity, as we measure it, is really specific gravity in the earth's gravitational field at sea level at 0 degrees C.
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According to Google:\n1 ounce = 28.3495231 grams\n\nYou can double check this if you know that there are about 454 grams in a pound.  454/16 ≈ 28+ grams
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LOL.\nFirst you said it was Grams and then at the end it was Gramps.\nGOOD ONE MARV.
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The equipartition theory says that a molecule has 1/2kT energy for each degree of freedom. There are three translational degrees of freedom and three rotational.\n\nDo the math.