A guy was dying, he had a herd of 17 camels, he said that after he dies the camels shall be divided as follows:\nthe first kid - takes 1/2 of the herd\nthe second kid - takes 1/3 of the herd\nthe third kid - takes 1/9 of the herd\nSo the town judge came on his camel to help them split it up correctly ... how will he do it ?
214063
Include the town judge's camel into the number... it gives you 18. then do the proper math to get the numbers\n1/2 of 18 = 9\n1/3 of 18 = 6\n1/9 of 18 = 2\n\n9+6+2 = 17... the judge trots off on his own camel...
185784
How many ways to pick 5 from 20 if order isn't important?\nAnd, how many ways to pick 2 from 7 if order isn't important?\n\nFor the second question, you have... 1,2 1,3...1,7 or 6 that include 1. Then 2,3 2,4... 2,7 which is 5 more. Then 3,4 3,5...3,7 which is 4 more. Keep doing this and you will see the answer is 6+5+4+3+2+1 = 21\n\nFor the first part 5 out of 20, note that the total number of arrangements of 20 things is 20! which is 20 x 19 x 18 x17 ..... x 2 x 1. But for every arrangement that you take the first 5 of, there will be 15! ways to arrange the rest.\nAnd for those first 5, you can get them in any order which means that 1 2 4 3 5 is the same for you as 2 3 1 4 5. So, you need to divide the 20! by both 15! and 5! which looks like this-  20!/(15! x 5!) and equals 15,504.\n\nNow for each pick from the cable houses (15,504 possible) you have 21 different ways to pick a no cable set. Therefore, multiply 15,504 by 21 to get your final answer. 325,584
290586
Come on now...35,000?  450ft long?  75ft wide?  That's a football stadium.  Zippy chance there was a vessel that large and zippy chance 35,000 animals were on it.  It's just a story...as for the fabled crap on the boat, the animals just ate it and the food...makes for a better story.  One more thing.  No way anyone made it to 600+...I mean what eventually kills a guy who has lived 600 years?  Ahh, he probably ate the same crap the animals did.
121585
several classes (100 students)of 6th graders went on a field trip to the zoo. 1/5 of them went to c the monkeys. 1/2 of them visited the penguins. 1/4 went 2 c the bats. and the rest went to the snack bar. how many students went to the snack bar? if u hav a heart. u will help \n\nwell...i got 5 students went to the snack bar...\n1/5 of 100=20\n1/2 of 100=50\n1/4 of 100=25\nso \n  20+50+25=95\n  100-95=5 students\n~Brendon
603235
To get your answers, imagine what has to happen.  \n\na) First, you have to pick 1 of the 4 white balls out of the 12 balls there.\n\n2nd, you have to pick 1 of the 3 white balls left out of the 11 balls there.\n\nSo, in order to get a red and then a red, you need to get 4 out of 12 followed by 3 out of 11 or 4/12 times 3/11 or 12/132 = 1/22.\n\nb) First, how many ways can 5 people line up?  5!.  How many ways are correct (assuming they all have different names, only 1).  So, the prob is 1/5! or 1/120.
86405
7 men with 2 legs each = 14\n7 cats with 4 legs each = 28*7=196\n7 kittens with 4 legs each = 28*7*7=1372\nso, as long as each animal has all there legs\nthe answer is 1582\n\nI originally thought that only 1 sack had 7 cats with 7 kittens, not each sack with 7 cats with 7 kittens, sorry.
588784
What if there is only one child and one adult?\nWhat if there is at least two adults and only adults?
292766
The scene was a tiny mountain village in a remote section of West Virginia. An old mountaineer and his young wife were getting a divorce in the local court. But custody of the children was a problem.\n\nThe mother jumped to her feet and protested to the judge that since she had brought the children into this world, she should retain custody of them.\n\nThe old mountaineer also wanted custody of the children. The judge asked for his side of the story and, after a long moment of silence, the mountaineer slowly rose from his chair and replied, "Judge, when I put a dollar in a candy machine and a candy bar comes out, does it belong tome or the machine?"
350954
1.Let the no.of boys in the family be x+1\nTherefore,each boy has x brothers(excluding the boy himself)  and x sisters\nSo the number of girls in the family is x\nTherefore each girl has x-1 sisters(excluding herslef,of course) and as assumed x+1 brothers\nBut by the problem,\n(x-1)=(x+1)/2\n+.2x-2=x+1\n2x-x=1+2\n+.x=3\nTherefore there are 3 sosters amd 4 boys in the family and the no. of children is 7.\nso A is correct\n2>Let the no. of children who lost 1 teddybear each be x\nTherefore,the no of children who lost two teddy bears each is 32-x\nAccording to the problem\nx+2(32-x)56\n=>x+64-2x=56 \nor x=8\nTherefore,8 children lost one teddy bear each\nA is correct
422488
A Sardarjee reported for his University final examination which consists of\n"yes/no" type questions. he takes his seat in the examination hall, stares at\nthe question paper for five minutes, and then in a fit of inspiration takes\nhis wallet out, removes a coin and starts tossing the coin and marking the\nanswer sheet - Yes for Heads and No for Tails. Within half an hour he is all\ndone whereas the rest of the class is sweating it out. During the last few\nminutes, he is seen desperately throwing the coin, swearing and sweating. The\nmoderator, alarmed, approaches him and asks what is going on. "I finished the\nexam in half and hour. But, I am rechecking my answers
666809
QUESTION: Wasn’t it irresponsible for the Buddha to walk out on his wife and child?\n\nANSWER: It couldn’t have been an easy thing for the Buddha to leave his family. He must have worried and hesitated for a long time before finally leaving. But he had a choice, dedicating himself to his family or dedicating himself to the whole world. In the end, his great compassion made him give himself to the whole world. And the whole world still benefits from his sacrifice. This was not irresponsible. It was perhaps the most significant sacrifice ever made.\n\n-------------\n\ni also heard that it is her wife who ask Siddharta to give birth for her so she can remember him, she agree with Siddharta's search for truth.\nlater, i heard that his wife and his son and many family members also follows him.. (but you might want to validate it)
283507
The task can be accomplished in exactly 11 bags (and no fewer). Divide the money into 11 bags (7+1+3) as follows:\n\n1,2,4,8,16,32,64,\n8,\n132,266,532\n\nThe first 7 bags clearly cover any amount from 1 through 127.\n\nThe 8th bag extends the range from 127 to 135 as follows:\n\n128 = 64+32+16+8+8\n129 = 64+32+16+8+8+1\n130 = 64+32+16+8+8+2\n131 = 64+32+16+8+8+2+1\n132 = 64+32+16+8+8+4\n133 = 64+32+16+8+8+4+1\n134 = 64+32+16+8+8+4+2\n135 = 64+32+16+8+8+4+2+1\n\nThe 9th bag extends the range through 132+135 = 267\nThe 10th bag extends the range through 266+267 = 533\nThe 11th bag extends the range through 532+533 = 1065\n\nThe total number of amounts which can be formed by including or excluding each of n bags cannot exceed 2^n. Since 1065 distinct amounts must be formed it's clearly impossible for n to be less than 11.
330310
Have a cow, then murder it.  Then murder the director, all the producers, and anyone affiliated with the infidels.  The world will finally understand, you can't be nice to hard-line fanatics OF ANY RELIGION!
44401
Ok there's a picture. And the picture shows a bull in a field. Now a bomb falls in the field, and the bull swallows the bomb. How do you describe this picture?\nAnswer: Abominable\n\nHow do you describe the bull?\nAnswer: Noble
280943
Imagine coloring the seats in a checkerboard pattern, alternating red and blue.  Since 35 is an odd number you will have 18 seats of one color (red) and 17 of the other (blue).\n\nHave everyone sit down.  Now when everyone moves (up, down, left or right) notice that they must all switch chair colors.  (No diagonal moves allowed).  Everyone on a blue chair must switch to a red chair and vice versa.\n\nYou can see that there is no way to accomplish this.  Everyone on a blue chair could find a red chair, since there are more.  But everyone on a red chair *could not* find a blue chair because there are less, no matter how you arrange the movement, one person will be left out.\n\nIt is not possible with an odd number of chairs.  Try it yourself with a 3 x 3 set of chairs... can't do it, can you?\n\nIn the simplest case you could have everyone switch with their neighbors.  But again, because there are an odd number of chairs, one person has nobody to switch with.  They'd have to stay where they were.  Since they *must* move, you can't accomplish the task.\n\nFor the person that suggested the 'snake' move, the start of the snake would not meet up with the end of the snake, so the person in the last seat couldn't move to the seat vacated by the first person.\n\nThis *will* work if you have an even number of chairs for the total.  You could have 5 x 8 (40 chairs) or 6 x 7 (42) chairs, for example and then people could easily swap around.  But if both the rows and the columns are odd, then the product is odd and you can't do it.
492838
told them to switch  camels
39954
coasterfreak has the best question for you. Not all of these are reasonable questions, so be careful. \n\nSome more:\n\nWhat fraction of the boys in the class are blonde ? \n\n6 of the 50 boys in the class have red hair, 20 have brown hair, 3 have black hair, 2 have shaved their hair bald, and only one dyed his hair (blue). The rest are blonde. \n\n\nIf 3 sheep of the flock of 72 sheep are black, what fraction of the flock is not black?