i.e. Miles per hour(MPH)...Time is governed by one complete revolution of the Earth(24 hours)..In Space, would these same principles apply since the body in motion is no longer in Earths' Sphere of influence? Is time relevent in Space?
209350
yes, space and time are forever linked into spacetime. please read the pages to which the following link leads. i hope they answer your question.
12201
Approximately one rotation every 24 hours [grin].\nBut, seriously though, the Earth's radius (at the equator) is\n6380 km so the equatorial circumference is about 4 x 10^4 km,\nso the speed of the earth's surface (at the equator) due to the earth's\nrotation is 4 x 10^4 / 24 = 1700 km/hr.\nAs an exercise for the reader, compute the speed for your particular\nlatitude.\n\n1. What is the Sun's rotation speed around center of the galaxy? \n\nThe disk of our galaxy is flattened by rotation (just as the planet Saturn is flattened, and protostellar disks are flattened.) Individual stars in the disk are on nearly circular orbits in the plane of the disk, all revolving in the same direction around the center of our galaxy. (By contrast, stars in the halo are on elongated orbits, at random orientations, some traveling clockwise, and others counterclockwise.) \nThe Sun, for instance, a fairly typical disk star, is orbiting with a speed\nv = 220 km/sec = 0.000225 parsecs/year.\nThe radius of the Sun's orbit around the galactic center is\na = 8000 parsecs.\nThe circumference of the Sun's orbit is then\n2 pi a = 50,300 parsecs.\nThe orbital period of the Sun thus turns out to be\nP = 2 pi a / v = (50,300)/(0.000225) = 220,000,000 years. \n\n2. What is the speed of center of our galaxy?\nThe sun is about 26,000 light years from the centre of the milky way
92036
His definition is a little odd, and does not seem to follow from his example (which is more about motion than position on the earth).  Technically, his motion relative to stationary students would make time pass at a different rate according to all that Einstein stuff (though there's no way he could ever notice the tiny difference).  But that would be true without any reference to the earth and the sun.  Is he trying to make a different point -- that his days would be longer because the sun would set later for him because he is walking toward the west where the sun sets?  If so, he's right that his days (defined as revolving around the Earth's axis) would be longer, but that would not mean time was moving at a different speed for him; it would only mean that the sun would set a little later from his visual perspective -- just like you can gain or lose hours when you cross time zones in an airplane; you reset your watch, but that has nothing to do with the passage of time.  Unless you are defining time only by calendars and clocks and common agreement.
20887
The Earth rotates on its axis at 1000 miles per hour (1600 kph). It orbits around the Sun at an average speed of around 67,250 miles per hour (107,600 kph). The Sun, in turn, is orbiting around the centre of the galaxy at a speed of 540,000 miles per hour. So the combined speed through space of the Earth and the Sun is 607,250 miles per hour. But there´s more - our Galaxy is also hurtling through space at a speed of 360,000 miles per hour. The combined motion of the Earth, Sun and Galaxy means that we are about twenty three and a quarter million miles away from where we were in space this time yesterday.\n\n  The Solar Sytem is believed to be about 4.5 billion years old but it's constituent parts were undoubtedly moving even before that. It is predicted\nthat our Milky Way galaxy will collide with the Andromeda galaxy in, roughly, 5 billion years.
210034
First "time" is relative.  \n\nAs you should know time as we know it is based on the rotation of the Earth, 24 hrs to make one revolution and 365.4 days to go around the Sun.  \n\nMaking the assumption that time is based on the revolutions of the planet you hypothetically happen to be on, time would be different on each planet because the day/night revolutions and the time to go around the Sun are different than on Earth.\n\nIf you were on Mars the Martian year is much longer that the Earth year, as it the day.  If you took you watch to mars and went by it, it would not make much sense on Mars because it is set to Earth time.  \n\nIt  sort of be like if you traveled to Sidney Australia but you were still on New York time and you tried to live like you were still in NY.  It wouldn't work very well.
520994
This seems really dumb, because clocks do not change speed because of gravity.  Even if they were, their acceleration would be different at different times, not first constant and then zero like in your question.  But if you really need an answer...\n\nThe hands of the clock that are not affected by gravity will meet between 6:30 and 6:35.  To find when, we have to look at the angles of the hands.\n\nAssume t counts, in minutes, from 6:00.\nh(t) = 180 + t/60*15 degrees, or 180 + t/4\nm(t) = t/60*360 degrees, or 6t\n180 + t/4 = 6t\n(6 - 1/4)t = 180\nt = 180/5.75 = 720/23 = about 31.30 min, or 31:18.  This is when the hands of the clock not affected by gravity will meet.\n\nNow for clock A.  The rate of acceleration is xv(t), so we know that v' = xv.  This is an ordinary linear differential equation.  Rewrite it as v' - xv = 0.  The characteristic equation is λ - x = 0.\nThe zero of the characteristic equation occurrs when λ = x, so the basis for the solution is e^(xt).  So,\nv(t) = ce^(xt)\n\nThe initial velocity is 360º/hour = 6º/min, so v(t = 0) = 6 = ce^0 => c = 6.\n\nFor the minute hand, until time t=15, v(t) = 6e^(xt).  Integrate this to find the position and convert from radians to degrees...\nm(t) = (6/x)e^(xt) * (π/180) = (π / 30x) e^(xt)\n\nSolve for t=15:\nv(15) = 6e^(15x)\nm(15) = (π / 30x) e^(15x)\n\nFor all time t>15, v(t) is constant.  Integrate:\nm(t) = 6t e^(15x) + c\n\nKnowing that m(15) = (π / 30x) e^(15x),\n(π / 30x) e^(15x) = 6*15 e^(15x) + c\nc = (π / 30x - 90) e^(15x)\n\nSo for time t>15 min,\nm(t) = (6t + π / 30x - 90) e^(15x) º\n\nFor the hour hand, the initial velocity is 1/4º per minute.  The acceleration is -yv, which gives v' = -yv.  Rewrite as v' + yv = 0.  The characteristic equation is λ + y = 0.  The zero occurrs when λ = -y.  The basis for the solution is e^(-yt).\nv(t) = ce^(-yt)\nv(0) = 1/4 = ce^0 => c = 1/4\n\nSo for the hour hand, v(t) = 1/4 e^(-yt).  The hands will meet before 9:00, so we do not have to worry about the condition when the hour hand stops decelerating.\n\nIntegrate to find the position:\nh(t) = 1/(-4y) e^(-yt) + c\nh(t = 0) = 180º = -1/(4y) e^0 + c\nc = 180 + 1/(4y)\n\nSo,\nh(t) = 180 + [1 - e^(-yt)]/(4y)\nFrom above,\nm(t) = [6t + π/(30x) - 90]e^(15x)\n\nSet them equal and solve for t.  I think YOU can handle that.\n\n\n\n\nAbout the acceleration being constant:  Yes, the acceleration due  to gravity is a constant, however, it is acting upon the arm's centre of mass, which is rotating about the fixed end.  The constant force due to gravity acts straight down.  However, if you break the gravitational force into orthagonal components parallel and normal to the arm, only the normal component generates torque, and torque is what accelerates the arm.  The normal component varies as the sine of the angle at which the arm is pointing, hence the torque will vary and so will the acceleration of the arm.  I took statics; I know what I am talking about.\n\nIs this a homework problem, or did you make it up?
546854
The faster you travel, the more time slows down for you (the traveller) compared to a person not moving as fast as you.  *At* the speed of light, time slows to be infinitely long -- so your teacher's "example" is actually incorrect, because at the speed of light it would take you an infinitely long time to get to the moon (as mass increases as you approach the speed of light, you'd also be infinitely heavy -- what all that shows is that it's impossible for anything except light to travel at the speed of light).\n\nHis example would have been better if he had said you went to the moon at, say, 75% of the speed of light.  At that speed, time would pass slower for you and faster for the people on earth, so by the time you went there and back nearly everybody on the earth you knew would be dead.  It would only take a few seconds from YOUR point of view to make the trip to the moon, but in those few seconds from your perspective the people on the earth would have passed dozens or hundreds of years.\nThis is the essence of "relativity" : that time is relative to the observer based on his position and speed, and is not absolute.  It's been confirmed experimentally by flying extremely accurate clocks in airplanes and spacecraft at high speeds, and then bringing them back to earth and comparing them with a similarly accurate clock synchronized with the moving clock before takeoff.  It's real, but also can be confusing :)
47775
Yes they'd revolve around their common center of mass (CM), which currently is located only 280 mi from the center of the sun, the sun's mass being 332830 x earth's.  With equal masses the CM would be midway between their centers.  The CM actually moves a bit due to perturbations from other planets that act on both bodies. \nYou can quickly approximate the new period. The new composite mass (in earth units) is 2 instead of the current 332831, and the radius (in earth-to-CM current  distance units) is .5 instead of (almost exactly) 1.  Kepler's 3rd law says T = (2*pi*R^1.5)/sqrt(G*M), so the new duration of a year is .5^1.5*sqrt(332831/2), or 144 current years, for an orbital speed of 15.3 feet/sec.
5263
when u r measuring time from a given inertial time frame every time-frames are relative to it.Standing at that reference frame u can only calculate the precision of individual events but not the absoluteness of the time-frame itself.\n    U don't need to think about the absoluteness ofcourse to describe any property of universe. U do it relative to u.
527581
The land does not move beneath us.  What are you talking about - the revolution of the Earth on its axis?\n\nIf that is the case, please take note, as I have seen nobody answer this frequently asked question correctly.\n\nIf you turn round quickly on the spot, you'll soon get dizzy, even though no part of your body is moving much more than a few miles per hour.\n\nIf you drive around a traffic island at 60 mph, you will throw your passengers all over the place.\n\nIf you drive around the city loop at 60 mph, you will hardly notice any turning forces.\n\nSo, speed is not the critical factor in how turning affects you.  What affects you is the rate at which you are changing direction. \n\nWith the Earth taking 24 hours to turn once, at any point in time you are not changing direction hardly at all, and from minute to minute you are travelling in a straighter line than a draughtsperson could draw.  \n\nTravelling in a straight line at constant speed has no effect on you at all, even if it is 1 million mph.
574679
about 1000 mph.\n\napprox #'s here--earth is 25,000 miles in circuvfrence, 24 hours per day.   this is at equator.\n\ni am thinking, the farther away from equator, the speed can be progressivly slower.
210475
Earth's speed changes from time to time.  The average is 29.783 kilometers/second or 107,218 kilometers/hour.
419320
As matter approaches the speed of light, the properties of change, and since E=MC2, we know that there's a relationship between energy and matter.\n\nEinstein's theory of special relativity dictates that since all motion is relative (for example, you in your chair may be at rest, but the Earth is rotating, the galaxy is moving, and the universe is expanding).  However, the speed of light will be measured by anyone anywhere to be the same.  \n\nIf an object undergoing constant change (like, say a human aging) is accellerated to close to the speed of light, the environment around it, (like say, his family on earth), would experience time at a different rate.  If you go on a 6-month space flight traveling at near the speed of light, you would find that people on Earth had aged several years.\n\nIn this way, it is like that person traveled into the future.  However, I can't think of any plausible way of matter reversing time, since it must be positive, or zero.
54478
There are plenty of good websites that answer this question, for any knowledge level. The concept is complex enough that you won’t get a meaningful answer here.\n\nIn horribly oversimplified terms Relativity simply states two things.\n\nOne that there is no universal ‘at rest point’, it all depends on how you choose to define it. You sit in a car doing 100mph and I stand beside the road. Normally we assume that you are in motion and I am at rest. Relativity states that we can just as accurately say that you and the car are at rest and I am moving at 100mph. Alternatively, we normally believe that the Earth orbits the sun and the Moon orbits the Earth. Relativity states that it is just as accurate to say that the Earth orbits the moon and the sun orbits the Earth, or we could say that we all orbit some imaginary point in between all three. It is all a matter of choice what we define as being the fixed point.\n\nThe second is that the speed of light is constant regardless of whether you are at rest or moving, and regardless of how fast you move. If you are sitting in a car doing 9/10 of lightspeed and are going past me standing still beside the road and we both look at exactly the same light beam shining down the road we will both see that light beam travelling away from us at exactly the speed of light relative to both of us. You don’t see it slowed down just because you are travelling almost as fast as it is. It will move away form me just as fast as it moves away form you.\n\nThose are the basics, and they aren’t all that hard to understand, even if they don’t seem to make much sense. What Einstein did was sit down and think really hard about the logical consequences of those two points.\n\n\n>>>>>>also is it true gravity on sun is greater than earth?\n\nYes.\n\n>>>>>if it is so ,sun would have had sucken all planets\n>>>> in it!!\n\n\nNo. Just as the Earth doesn't suck the moon in despite having much higher gravity.\n\nThe planets orbitthe Sun. In simple terms that means they are constantly falling around the sun in a ciruclar pattern.\n\nThe best way I have heard this described for the layman  is to imagine yourself throwing a heavy weight like a shotput. You could only throw it a few metres. Now imagine standingon the roof of a house and throwing that same shotput. This time it will go much further before it hits the gorund. Now go to the top of a rally high cliff and throw it. This time the shotput will travel for 20 or 30 metres before it hits the ground.\n\nThe higher you go the further somehting thrown will travel before it hits the ground. And if you go high enough the object will travel right around the world and back to where it starts before it hits the ground. It will continue falling forever. \n\nThe planets are doing exactly that WRT the sun. We are constantly flaling aorund the sun, but we can't be sucked in because we are falling from such a great height.
539547
Travelling back in time is not allowed by einstein's theory of relativity...however if you can instantly teleport youself to some faraway star,say a 101 light years away, you might be able to catch einstein receiving his nobel prize!! as stated earlier, there is no master grandfather clock that is regularly ticking away the seconds..rather that rate is adjustable...but one may zip into the future..consider an example where you are on a space-ship at a speed of 0.99990 c that is going away from the earth and coming back..in your time frame say,it takes about twenty years..using lorentz transformations, the time for your to and fro motion is close to 450 years!!
557180
hey this is a very good question. \nthe circumference divided by 24 (i.e. hours) = angular velocity travelled in one hour. \nif the rotation changes suddenly or  it stops rotating suddenly then due to the inertia that every moving object carries will suddenly travel in the direction of rotation at exactly the angular speed of the earth. so ocean water will move all over the earth and the plates beneath the earth will shift causing severe earthquakes and the volcano will erupt from the gaps due the internal pressure. so all the movable objects will shoot. these objects will move in the direction perpendicular to the centre of the globe in the direction of the motion respectively. there after stopping , there would be more gravitational force exerting on the objects cause the earth while in motion , objects have centrifugal force that is why the weight is different at the time when earth stops rotating and due to the absence of the centrifugal force weight would be more. there day will be 6 months and the night would also be 6 months longer like the north/south pole.
415817
You can't move through something that doesn't exist! Time is not a NATURAL feature of the universe but simply a concept invented by our species to separate events into past, present and future. There is no Cosmic Master Clock that keeps track of absolute, universal time. There is no physical "past" trailing along behind the "present," nor any physical "future" waiting up ahead for us to get there.