well this is a math question...heres the tabel\n \nSKIN FACTS\naverage thickness 2/25 in.\nthickest(upper eyelids) 1/5 in.\nthinnest (eyelids) 1/50 in.\n\n\n\n\nhow many eyelids equal thickness to the skin on the upper back?\n\nwhat is the difference in thickness between the average thickness of the skin and the thickness of the skin on the eyelid?\n\n\n\nexplain how u got ur answers.
204968
I'll assume thickest is Upper back not upper eyelids.\n1/5 = 10/50\nHow many eyelids 1/50 should you stack to equal 10/50? (u need 10 eyelids, gross)\n\nav thickness of skin 2/25 = 4/50\neyelids 1/50\ndifference between the two: 4/50 - 1/50 = 3/50in.
334830
The basic idea for maximum reflectance is that the optical phase thickness, the refractive index times the physical thickness, is equal to one half the wavelength of light.  It could be this minimum thickness for the zero order effect, or some integer multiple of half the wavelength plus one half wavelength.\n\nThe minimum physical thickness of the oil film would be\n\nl = lambda/(2n) = 640/2.5 = 256 nm.\n\nSeems like a low index of refraction for oil, though.  There would also be a maximum reflection for this wavelength for 512, 768, ...\n\nThe condition for zero reflection is that the optical thickness is equal to one quarter wavelength.\n\nl = 512/(4n)= 102.4\n\nAlso, 512/(2n) + 102.4 = 307.4, 512/n + 102.4 = 512, and so forth.\n\nNow, 512 is sort of a blue-green color, but no matter.  Also the refractive index should depend on the wavelength.  But this cooked up problem has a solution for both wavelengths when \n\nl = 512 nm \n\nis the thickness of the oil film.  There are other correct answers, but this is the minimun thickness to meet the requirements of the two wavelengths given.
8407
Cool problem.\n\n6908.9 feet when the diameter is 25".\n\nThe formula is:\nL = (X^2+8*X)*49.26108,  \nwhere L is the length of paper remaining in feet, and X is the measure from the core out in inches\n\n\nIt's not simply a number times the measure because an inch near the core is not the same amount of paper as an inch near the edge.\n\nIt's important to realize that any formula will be an approximation.  You can't be very precise when measuring the size of the roll, and the size of the core is not always going to be exactly the same.  And the paper may be tighter near the core than on the outside.  Also, based on the info given, the thickness of the paper is actually .005314528".\n\n\nThere are a couple ways to approach this.  The easiest way, which happens not to be very intuitive, is to correlate the area of the cross-section with the length of paper.\n\nIf you want to follow this, draw two concentric circles - one representing the core, and the other representing the paper around the core.\n\nThe radius of the larger circle is X+4 inches.\nThe radius of the smaller circle is 4 inches.\n\nThe area of the donut area (representing the paper) is π*(X+4)^2-π*16 = π*((X+4)^2-16) = π*(X^2+8*X) square inches\n(In case the font is not clear in the browser, "π" is pi=3.141593.)\n\nLength x thickness = area of cross section\n(For this purpose, I'm assuming that the area of the cross section for a given amount of paper is the same whether it's rolled around a core, or it's cut into sheets and stacked.)\n\nWhen X=21 inches, Length = 30,000 feet = 360,000 inches\n\n(360,000 inches)*thickness = 3.141593 * (21^2+8*21)\nSo, thickness = .005314528 inches\n\nTo derive the formula:\n(Length in feet)*(12 inches/foot)*thickness=area of cross-section\n\nL*(12 in/ft)*(.005314528 in)=3.141593*(X^2+8*X)\n\nSolve for L:\nL=(X^2+8*X)*49.26108\nL is in feet, X is in inches.\n\n\nThe question asked how many feet when the diameter is 25".  \nX=8.5\nL=(8.5^2+8*8.5)*49.26108 = 6908.9 ft.
340549
You pull your eyelid away from your eye by the lashes. Then you push the part that is between the lashes and your eyeball. Let it go slowly and it should stay folded out....
280678
Gauge and mil are two names for the same unit, so a 20 gauge liner is the same thickness as a 20 mil liner.  The conversion is 1 gauge=1 mil=.001 inches, so a 20 mil liner is .02 inches thick
319484
the smaller 1 being right u get the hypotenuse as 5..\n\nthe bigger triangle n the smaller 1 are similar...so sides are proportional...(the sides r acually duble of tht of the smaller 1) so the perpendicluar is 6... n the hypotenuse of the biggger triangle is 10..(duble of the smaller 1)...\n\nso perimeter is 8+6+10=24\n\nperimeter of the shaded region is indeed 19..4+6+5=19..got it?
395496
The real answer should be 4.8 inches apart, since there are only 3 gaps with 4 buttons, but of the answers given, 3.6 would be correct (14.4 / 4 = 3.6)\n\nNone of the other answers even makes sense.\n\nHope this helps!
42767
ok, you have 1 inch, the lines are all just fractions of that inch.  The line in the middle is one half of an inch, like 1/2.  The quarter inch line divides that inch into 4 sections therefore it is 1/4 of an inch, there are 8 eighths, 16 sixteenths, etc.  Example, 3/4 of an inch is just 3 of those 1/4 inch lines...  hope this helps...
144991
Brown eyes\n \nBrown eyesThe vast majority of the world's people have dark eyes, ranging from brown to nearly black. Light brown eyes are also present in many people, but to a lesser extent. Most of the original inhabitants of Africa, Asia, and the Americas have brown eyes. Brown eyes are also found in Europe, Oceania and North America, though within European populations they are not predominant to the same extent
476058
Total Gobz = 20\nOne fourth of these are red\nSo, number of red Gobz = (1/4) * 20 = 5\nThe rest are blue\nSo,number of Blue Gobz = 20 - 5 = 15\n\nWhat do you mean by into how many parts was the group divided?\n\n1) If you want to know the percentage share, then the question itself gives the answer\n\nRed gobz take 1/4 parts = 25%\nSo Blue gobz take (1 - 1/4)parts = 3/4 parts = 75%\n\n(or)\n\n2) If you mean to say that the 20 Gobz should be split into various parts such that each part is same as the other,\n\nThe number of parts = 5\neach part will have 1 red gobz and 3 blue gobz
157620
Well, now dummy, let's think this one through.  First, let's divide the sucker by 12 and see what we get.\n\n495.923 / 12 = 41.3296 feet\n\nSo, we see it is 41 feet plus a tad more, almost a third of a foot as a matter of fact.\n\nNow how many inches is .3296 foot?\n\nWell, 1 inch divided by 12 = 0.0833, so each inch is .0833 of a foot.\n\nSo, .3296 / .0833 = 3.95 inches\n\nNow we have it narrowed down to 41 feet, 3.95 inches.\n\nYou should realize that 95/100 of an inch would be 19/20.\n\nSo if you want all fractions it is 41 feet 3 and 19/20 inches.\nThis is the same as 41 feet 3.95 inches\n\nThere is probably an easier way to figure this out but I just go through things logically.  You could figure this out too if you didn't spend so much time playing stupid video games.
118832
Ubergeek is right again, almost.  Half the cards are black, so prob that the first one is is 1/2.  After that, only 25 of the remaining 51 cards are, so prob that the second is black is 25/51, and prob both are is the product, 1/2 * 25/51 = 0.245098, roughly.  I used to teach this stuff.
447367
Here are the results of a couple of studies. I trust the second study more than the first. To help you better understand what all these numbers really mean, please read all my post. \n\nBy age, the averages found were:\n\n\nFirst Study\nAge....... Size \n12....... 4.1" (104 mm)\n13....... 5.1" (130 mm)\n14....... 6.0" (152 mm)\n15....... 6.1" (155 mm)\n16....... 6.3" (160 mm)\n17....... 6.5" (165 mm)\n18....... 6.4" (163 mm)\n19....... 6.2" (157 mm)\n20....... 6.2" (157 mm)\n\nSecond Study\nAge....... **Erect Length (inches & centimeters)\n11....... 3.0" (3 and 0/16ths") 7.5 cm\n12....... 3.8" (3 and 13/16ths") 9.6 cm\n13....... 4.8" (4 and 13/16ths") 12.3 cm\n14....... 5.4" (5 and 6/16ths") 13.6 cm\n15....... 5.6" (5 and 10/16ths") 14.3 cm\n16....... 5.7" (5 and 11/16ths") 14.5 cm\n17....... 5.8" (5 and 13/16ths") 14.8 cm\n18....... 5.8" (5 and 13/16ths") 14.8 cm\n19+....... 5.9" (5 and 14/16ths") 14.9 cm\n\nConclusions: \nThe average adult penis size is about 6.2 inches or (157mm). It is interesting that in this study, penis size 'peaks' at age 17. Since penises do not get smaller as a male approaches age 21, it can be concluded that boys aged 16, 17, and 18 are most likely to exaggerate the size of their penises.\n\nPenis growth among teens differs widely. For a young male, trying to interpret a table of averages is not necessarily easy nor beneficial. Young men who read this may try to make comparisons with themselves and this table. I advise any concerned teen (or concerned parent) to use this table only as "average reference". Remember, when an "average measurement" is listed, that means approximately 50% of all young men are shorter than this number (and about 50% are larger). Less than 1% of males are exactly average. That means less than 1 out of 100 men will match the average number exactly. Beware that averages are actually known as "statistical means" and they are typically used in the context of medicine and statistical sciences rather than personal counseling. Nevertheless, the table can still be used as a good reference for average penis growth over time.\n\nThe table above is a collection of measurements from doctors and pediatric physicians. They do not measure the boys' penises while they have erections. The length of the erect penis can be determined by stretching the flaccid penis from the tip as far out as it will comfortably extend. It is then measured from the tip to the base while flaccid (and still extended). The measurement is then taken for the medical records of boys who have had developmental concerns, urogenital diseases, or penis injuries. It does not take long for a group of physicians to determine averages and normal variations when they see hundreds of patients per year.
168251
98 is correct because 50/25=2. 49*2=98\n\ntry setting up a proportion: \n\n25   50\n----   ----\n49    n\n\nit may help!!
356753
If it's a small piece and isn't embedded in the eyeball then you can lift your upper eyelid and tuck the bottom eyelid underneath after removing any loose eyelashes. Sweep the inside of the upper lid with the lower lid. The lashes should remove any grit caught under the top lid. This also works in reverse. If the object still doesn't come out after trying everything else then go immediatly to your doctor. It's not worth losing your sight for the sake of a few bucks!
53264
2.5 Centimetres is 1 Inch and one foot is 12 Inches and 1 Meter is 100 Centimetres so 170m is 17,000 Centimetres divide by 2.5 is 8,500 - 50% 0.5 = 25% = 8,500 - 2,125 = 6,375 Inches divide by 10 = 637.5 divide by 50% = 318.75 Feet! 3/4 of 12 = 9 so its 318 Feet and 9 inches.\nDo you mean 1.7 Metres? (I will have to study another hour.)So 3 feet = 1 Meter so Its 5 Feet 7 inches to work it out simply use My Logical Theroem so its 1.7 Meters or 170 Centimetres So half biggest so its 5 foot and then divide the 7 by 10! Blindingly simple!\nP.S I spent 3 Hours trying to work out a theroem, please give me a best answer and that will be much appreciated.
606080
Soak them with hot compresses for 5 minutes and then make a dilute mixture of 1/2 cup warm water and 5 drops of baby shampoo. Using a qtip, gently scrub the edge of your lids-where the lashes meet the lids- for 30 seconds each lid. Rinse with cool water and dry with a towel. Repeat this nightly for 2 weeks and then you can cut it to about 2-3 times a week. If this doesn't help, go to your local Ophthalmologist.