Aslo how can I covert this to lbs? thanks Clem.
215311
All you need to know to convert N*m to lb*ft is to know that they are both units of torque. Sure, you could say they are both units of length multiplied by force, but that's besides the point. To do a conversion you will need to convert between units, that's just a fact of the matter. Why convert more units then necessary? If you know they are both units of torque, you are already done. Look up the conversion factor and there you go.\n\n1 N*m = 0.737561 lb*ft
151520
Use this...\n\nhttp://www.oanda.com/convert/fxhistory
462473
This is an example on how to convert regular formula in Excel formula\nIf you have this\nLBs = Kg * 2.2\nthen you can do this in Excel\nIn A1 type the amount on Kg you want to convert\nIn B1 paste this\n=A1 * 2.2\nAll we did is made B1 as LBs and A1 as Kg variabls\nand so on all other units\n\nEnjoy my profile, I am the VBAXLMan
616173
Zero out all scales. You start will the scale with the largest ballast (big heavy thing). Move it larger by notches until the scale tips the other way, then move it back one notch. Repeat this on each successively smaller scale. Then your weight is the sum of each scale.\nSo 150 + 10 + 5 + 3 would be 168.
276935
Try the app from the link below. There are a few converters that will do this for you.\n \nhope that helps\nNigel
675195
The basic principle is to use leverage. Here's one way off the top of my head (I wish I could draw a diagram):\n(1) Hang the object from a rope/cable that runs up through a pulley. \n(2) Fix the other end of the rope so that it pulls up on a lever arm. \n(3) Make the other end of the lever arm (beyond the lever's pivot point) push down on the scale. \n(4) Since you want to effectively reduce the weight pushing on the scale, the length LR of the lever arm between the pivot and the rope will be shorter than the end LS between the pivot and the scale. \n(5) The relationship between the weight WO of the object and the weight WS you read on the scale will be: WO = (LS/LR)WS. \n(6) This ignores the effects of mechanical imperfections and friction in this apparatus. \n\nAlso, I can imagine several other mechanical configurations that would achieve the same thing.
414333
These are pretty simple questions ... They are VERY straight forward indeed!!\n\n1. Just do what it tells yoiu to do (divide!) and the answer is in feet /s\n\n2 16 oz = 1 lb so 28 oz =?? so 10 lb 28 oz = ??\n\n3. 1 L = ? qt and 12 L = 12 * 1L\n\n4. Maximum = biggest number and minimum = smallest number ... so away you go and numbers get smaller the further they go into the negative range. (Owing $25 means that you have less money than if you are broke ie have no money at all and if you have $2.35 you have more money still)\n\nThat should be enough to get you out of trouble BUT I am not doing your homework for you
361639
1 pound = 4.4475 newtons
257253
It's all in the instruction manual; I assume you've lost it?  The wheel size numbers are odd, I'm not quite sure what it is that determines them.  For my 26" 1.5" wide tires, the number was 2460 ( I don't know why I remember that either. . .).  Generally it is shown on the left hand side what it is that you're to enter.   I don't know if you have the same one that I do, but here's the setup for mine: C1 is the wheel size number, P2 is the pedometer step meter, ignore that if you want to. Then pick km or mi. Then is the maintenence mile picker -- I've ignored this too. Then you should be set.  Good luck!  I've tried e-mailing and finding the Back Trails website, which is no help, so I help that helped some.
255788
Divide into two equal groups of 4.\nOne will be heavier than the other.  Take that group off the scale.\nDivide the remaining four into two groups of two.\nOne will be heavier than the other.  Take that group off the scale.\nDivide the remaining group into two groups of one.\nThe lighter one is the answer.\n\nEDIT: This can be accomplished in just 2 weighings.\nSplit the 8 into two groups of 6 and 2.\nDivide the group with 6 into two groups of three.\nCase 1: If they weigh the same then the lighter one is in the group of two.  Weigh the two to see which one is lighter.\nCase2: If they don't weigh the same, take the lighter group of three and weigh one on each side.  If they are the same then you know which one is the lighter one.  If they are different then you still know which one is the lighter one.
52954
Its not called a converter its called porting. Also I am not sure of any tools myself that will allow you to do that ( I am not saying there arent tools out there to do it ) but I havent really come across any but saying that I havent really searched :) Do a quick google search :)\n\nShort of that wait for another person to reply :)
406704
It usually helps with these kinds of problems if you start by drawing a little sketch. It doesn't have to be accurately scaled, its purpose is to help you recognize the physical relationships and to keep your signs correct.\n\nYou are dealing here with rotational motion. You should be familiar with the relation: (alpha) * J = T, where (alpha) means the rotational acceleration, J is the rotational moment of inertia, and T is applied net torque.\n\nYour bicycle wheel has inertia. In general the rotational inertia of an object is (integral)[r^2 dm] where r is measured with respect to the axis of rotation. That's very simple in your case since all your mass is distributed in a thin ring - so r is constant, and you get J = r^2 m. This works out to 0.1941 kg m^2.for your problem.\n\nTorque due to a force applied at a distance from the center of rotation is T = r * F. Now here's where the sketch starts to become useful. The problem tells you that you have one force (123 N) applied at the rim and a second force applied to a sprocket 8.92 cm in diameter, and the net result is acceleration of 4.49 rad/s^2. And the problem tells you that the 123 N force is resisting the motion. So you get:\n\n(alpha) J = T1 + T2\nwhere\nT1 = what we seek\nT2 = -123 N * .3205  m  The (-) sign is because it opposes T1.\n\nSolve this to find T1 = 39.6 N-m\ntherefore the force required is T1/r1 = 39.6 / .0446 = 888 N.\n\nIf you have followed this you should be able to do the second part easily.
641427
x + y = 100 lbs\n\n9x + 12y= 100*11.25 = 1125\n\n9x + 9y= 900 (first equation, both sides x 9)\n\n3y = 225 (subtract 3rd from 2nd equation)\n\ny = 75 lbs\nx = 25 lbs\n\n25 + 75 = 100 lbs\n25*9 +75*12 = 225+900 = 1125
578534
Try reading the manual. I know its difficult but it could work, or maybe go to where you got it.
511272
Well, you already have the answer several times (and once with kg and lb mixed up). But, you can ask google these questions and it will answer them directly (ie. won't search the web, will just tell you). See the link below.
205172
I ride a Gravity.  Independent trucks are the way to go. I'm sure they have their own website you can checkout.
366646
Try asking in the recumbent section of Bike Forums on the link below, users of this type of bike may be able to help you:\n\nhttp://www.bikeforums.net/\n\nGood Luck