FFT code in C language
217580
You can use FFTW. Its even optimized for performance.
140757
http://en.wikipedia.org/wiki/Pascal_programming_language#Syntax\nhttp://www.allegro.com/papers/htpp.html\n\nThey will help
257889
http://abstractvb.com/code.asp?F=1&P=1&A=1032
532292
va sur le site de la fft.
67034
int\nmain (void)\n{\nfor(i=0;i<10;i++){\nprintf("some thing output here %d", i)\n}\n}
257748
I have heard this question so many times that I decided to look it up on the net and I found a very good site that explains it very well, step by step.\nSo I will simply link that one here. This is the C equivalent, you can modify it for c++!\n\nhttp://www.iwebthereforeiam.com/programming/selfWrite.asp\n\nEnjoy!
87727
I think you're talking RF not audio and the given C value sounds just fine. We pretty much agree except for the decimal point, unless you are using a comma for the d.p.\nI get f = v/lambda = 299792458/5.7 = 5.259517E+07 Hz, \nw = 2*pi*f = 3.304652E+08 rad/s, and \nL = 1/(w^2*C) = 1/(1.092072E+17*1.9E-12) = 4.819422E-06 H or 4.819 uH.
409626
main () {char *s, b[100]; while(s=gets(b)) printf (atoi(s)%2 ? "nope&#92;n" : "yep&#92;n");}
279542
#include <iccclkeh.hpp> \n\nclass \n{\n       IccClock(UpdateMode update = manual);\n       IccAbsTime& ansTime();\n       void cancelAlarm(const IccRequestId* reqId= 0);\n       const char* date (DateFormat format= defaultFormat;\n            char dateSeparator='&#92;0');\n       unsigned long dayOfMonth(); \n       DayOfWeek dayOfWeek();\n       unsigned long daysSince1900();\n       long double milliSeconds();\n       MonthOfYear monthOfYear();\n       const IccAlarmRequestId& setAlarm (const IccTime& time,\n            const IccRequestId* reqId= 0);\n        const char* time(char timeSeparator= '&#92;0');\n        void update();\n        unsigned long year();\n        typedef enum{\n              defaultFormat,\n              DDMMYY,\n              MMDDYY,\n              YYDDD,\n              YYDDMM,\n              YYMMDD,\n              DDMMYYYY,\n              MMDDYYYY,\n              YYYYDDD,\n              YYYYDDMM,\n              YYYYMMDD,\n       } DateFormat;\n       typedef enum {\n              Sunday,\n              Monday,\n              Tuesday,\n              Wednesday,\n              Thursday,\n              Friday,\n              Saturday,\n       } DayOfWeek;\n       typedef enum {\n              January,\n              February,\n              March,\n              April,\n              May,\n              June,\n              July,\n              August,\n              September,\n              October,\n              November,\n              December,\n       } MonthOfYear;\n       typedef enum {\n              manual,\n              automatic,\n       } UpdateMode;\n };
619707
Think of it as attempting to approach an impulse in the frequency domain.  The fourier transform of an impulse is a constant.  Try this:\n\nb = fir1(100,0.000001);\nstem(b)\n\nAll of the filter coefficients are positive.  Your result will look almost like a Gaussian distribution. That's the result of convolution.  Your filter coefficients are trying to "knock down" anything that is periodic.
562029
==================\n#include <iostream.h>\n\nint main(void)\n{\n\n   int count; // holds the count\n   float sum, number, avg;\n\n   sum = 0.0;\n   count = 0;\n\n   cout << endl << endl   //  Make some space\n        << endl << "Enter a number.  Enter a zero (0) when you have"\n        << endl << "finished entering numbers and want to compute the"\n        << endl << "average of the inputted numbers." ;\n\n   do {\n         cout << endl << endl << "Data element #" << count + 1\n              << ": ";\n\n         cin >> number;\n\n         if (number != 0.)\n           sum = sum + number;\n           count = count + 1;\n\n      } while (number != 0.0);\n\n      averg = sum / (count-1);\n      cout << endl << "The average is: " << avg\n           << endl << endl ;\n      return 0;\n}\n\n\n==================\n\nThis program computes the average of a set of data values. Commented a bit for you to understand\n\nEnjoy
188813
here...I'll tell you what to write and you write it...\n\n/* outline the program */\n\n// void main()...etc..\n\n/* define your variables */\n/* you'll need a pair of char pointers */\n/* and some numbers to hold converted values */\n\n\n/* input the first binary as a string */\n\n/* input the second binary as a string */\n\n/* convert them to decimal */\n\n/* add them */\n\n/* fprintf them */\n\n/* end program */\n\n\nthat's all.\nI write all my programs in commented logic first then fill in the blanks so that it does what I meant.  When I'm done, the program follows the flow and is already commented for the next person to follow.
225506
FFMPEG is a video and audio encoding / decoding open source program. To use it, you need to download the source, compile it (which will also compile the required libraries) and then run the generated binaries on the audio / video files to do what you want to do.\n\nUnder Windows, you need to have MinGW Tools installed to be able to compile FFMPEG. Read http://ffmpeg.sourceforge.net/faq.html#SEC21\n\nUnder Linux, of course you use the "make" command to compile.\n\nIf you are an experienced C++ developer, compiling and installing should not be such a problem. If not, then I would recommend using MPlayer at the URL given below. It comes with an inbuilt media player and encoder. It is also open source runs on the command line. But it is an amazing tool. Try it when you get the time. Click on the second link below.
493094
Try Bloodshed Software's version of C/C++ instead.  It's free just like Turbo C from Borland.\n\nhttp://www.bloodshed.net/devcpp.html
70669
just try this out:\n\nfor(couter=n; counter>=0; counter--)\n{\n   printf("&#92;n %d", counter);\n   sleep(1000); //or might be Sleep(1000) \n   //check out delay() also in place of sleep()\n   //sleep(1) suggests a delay of 1 millisecond\n}\nprintf("&#92;n That is..!");\n\n\n----------\nI think tht shud be simple n sweet. :-)\n\nI think the answerer below really needs to refer back to his expert programming.. as sleep takes milliseconds only.
45233
I have the answer.\n\nYou should change the numbers to be "400.0" instead of "400". This is your primary problem.\n\nThe deeper reason that this is happening is that 400*400/400 is an INTEGER expression. It will be evaluated as an integer, and only assigned to a floating point result.\n\nI believe that your compiler is a 16 bit compiler, this is the only answer that makes sense.\n\nNow let's just see what the compiler is doing. Its first step is to evaluate 400*400. Now if you get out your calculator, you will get the answer 160,000. NOT SO FAST!!!! An integer in your compiler is only 16 bits long, and can only express numbers between -32768 and 32767. The answer that it comes up with is 28,928 (160,000 - 2*65,536). It will next divide 28,928 by 400 to give 72 (again it drops the fractional result because it is integer).\n\nIn both C and C++, the result of an integer expression is an integer. It does not matter if it gets assigned to a float or not. If you want float accuracy, then the numbers in the expression must be floats.
589693
A monumental task!\nHope yur not the sole programmer.\nI recommend staying with standard C or Cobol\nA comprehensive telecom billing system will atke you years to write.