A) 20b - 4ab -15c +3ac\nB) (5-a) (4b +3c)\nC) 12bc (5-a)\nd) (5-a) (4b-3c)
201717
4b(5 - a) - 3c(5 - a)\n= (5 - a)(4b - 3c)\n\nThe answer is D. Since both have the factor (5 - a), you factor it out, and what's left is (4b - 3c).
669375
2(x-4y+1)+3(-2+y-2)\n2x-8y+2-6+3y-6\n2x-8y+3y-6-6\n2x-5y-12\n\n2x-5y-12= answer\n\nHope this helps you.
564578
[(16x*2-25) / (24x*2-30x)] / [(8x*2-2x-15) / (6x*2-7x-3)]\n= [(16x*2-25) / (24x*2-30x)] [(6x*2-7x-3) / (8x*2-2x-15)\n= [(16x*2-25) (6x*2-7x-30] / [(24x*2-30x) (8x*2-2x-15)]\n= [(4x-5) (4x+5) (3x+1) (2x-3)] / [(6x) (4x-5) (4x+5) (2x-3)]\n= (3x+1) / 6x
456876
S=(c-b)/(b-a)\nSb-Sa-c+b=0\nc=Sb-Sa+b\nc=S(b-a)+b\nHowever you like it.
632569
c = 108 degrees\nyou can find this since A + B + c = 180\nA=B+C+72\nThensubstitute to get A + A + A + 72 = 180\n3A + 72 = 180\nA = 36 so then C= 108
448805
The answer is c.\nC12H22O11+12O2-->12CO2+11H2O
73195
20x +  4y = 32    the first line *4\n-20x - 20y = -80   the second line *5\n________________   add lines \n       -16y = -48 => y=3 =>x=1
183151
B-2A-3C = log a(3/(2^2*5^3) = loga0.006\n\nso, answer is D
390165
This is an impossible figure as by your own figures ΔABC is equilateral with AB = 2AL = 10\nBC = 2BD = 10 and\nAC = 2AE = 10\nso AT = 2/3 * BT = 2/3* 5√3\n= (10√3)/3\n≠10
542487
4(x+5)=12x\n4x+20=12x\nadding -4x\n20=8x\ndividing by 8\nx=2.5cm
459235
9c^2 - 64\n(3c+8)(3c-8)\n\n9c^2-24c+24c-64\n9c^2-64
501183
3x + 2y - 2z\n\n3(5) + 2(2) - 2(1)\n\n15 + 4 - 2\n\n19 - 2\n\n17\n\nThe answer is 17\n\n- - - - - - -s-
673383
ABC+ABD+C'D\n=ABC+ABD(C+C')+C'D\n=ABC+ABCD+ABC'D+C'D\n=ABC(1+D)+C'D(AB+1)\n=1ABC+1C'D\n=ABC+C'D
391531
4(4)+2x7-(5x4-15)\n4x4\n16+2x7-(5x4-15)\n2x7\n16+14-(5x4-15)\n5x4-15\n16+14-5\n16+14\n30-5\n25=answer\n\n(b)-2bc+c(c)\n-2b^2c^3=answer\n\n2x-2-5x4/4+3x-1\n-4-20/4+-3\n-4-5+-3\n-2=answer
114123
qw\n 12a-43b-22c = 3a-69b+22c\n   .........+22c........... .... -22c\n  12a-43b = 3a-69b
177377
(4x + 5y)(2y^2)\n8y^3 + 10y^3\n\na.)\n(4x + 2y^2)(5y)\n20xy + 10y^3\n\nb.)\n(4x) + (5y)(2y^2)\n4x + 10y^3\n\nc.)\n4x + (5y + 2y^2)\n4x + 5y + 2y^2\n\nd.)\n(2y^2)(4x + 5y)\n8xy^2 + 10y^3\n\nSo the answer is d.) (2y^2)(4x + 5y)\n\nI just did the math out.
534479
#1.)-----------------------------------\n  \n25b^ -20by + 4y^\n\nMultiply 1st and 3rd term together to get 100b^y^.\n\nFactor 100b^y^ into two factors whose sum = the middle term of -20by.\n\n1by   X 100by\n2by   X 50by\n4by   X 25by\n5by   X 20by\n10by X 10 by   ....................BINGO!\n\n-10by + (-10by) = - 20by   &   (-10by)(-10by) = 100by\n\nThis is a really kewl factor by grouping trick, I LOVE it!\n\nBring down the first term of: (25b^)\n\nNext, write the SMALLER of the two factors 1st.  Followed by the LARGER of the two factors.  In this case, they're both the same, so it doesn't matter which one goes first: (-10by)\n\nFinally, bring down the third term of: (+4y^)\n\n25b^ -10by -10by + 4y^\n\nNow, lets factor by grouping! \nFactor out the GCFs.\nGCF#1 = 5b\nGCF#2 = -2y\n\n(25b^ -10by) + (-10by +4y^)\n5b(5b - 2y) -2y(5b - 2y)\n\nGCF#3 = (5b - 2y)\n\n(5b - 2y)(5b - 2y)\n\nSimplifies further as: (5b - 2y)^   ....Whatdayaknow?! \n.......................................................................................................It's a Perfect Square Trinomial.\n\n#2.)------------------------------------------------------------------\n\n100 - 9b^\n\nAh, the difference of two perfect squares.\n\n---------------------------------------------\n\nFORMULA:\na^ - b^ = (a-b)(a+b)\n\n---------------------------------\n\nSOLUTION:\n100 - 9b^\n(10)^ - (3b)^\n\n-----------------------\n\nANSWER:\n(10-3b)(10+3b)