HOW! do u solve this? \n\n 3       \n---- +\nx-5   \n\n\n 2\n----\n5-x
205259
Is it an equation? then it goes like:\n3/(x-5)=2/(5-x)\n3*(5-x)=2*(x-5)\n15-5x=2x-10\n15+10= 2x+5x\n7x=25\nx=25/7=3 4/7 \n\nOt it's an expression to simplify?\n3/(x-5)+2/(5-x) = 3/(x-5) - 2/(x-5)\n = 1/(x-5)
348816
3x = 17 - 2(x+1)\n3x = 17 - 2x -2\n5x = 15\nx   = 15/5\nx = 3
410726
nope\n\n2+3(x-4) < 3(2x-5)\n\n2+3x-12 < 6x-15\n\n3x-10 < 6x-15\n\n-3x < -5\n\nx < 5/3
283964
=[(4+3x)/x] + (2/3)[(5+3x)/x]\n=[(4+3x)/x] + [(10+6x)/3x]\n=[(12+9x+10x+6x)/3x]\n=[(15x+22)/3x]
563733
# 1    \n(x+1)*(x+6)=x2 +x+6x+6=x2 +7x +6\n#2\n(y-6)*(y-5)= y2-5y-6y+30= y2-11y+30\n#3\n(a-2) * (a+10)=a2 +10a-2a -20= a2  +8a -20\n#4\n(x-1) *(x+1)= x2 -x+x -1= x2 - 1
135967
*(2x/(x^2-4)) + (5/2-x) - (1/2+x)\n*(2x/(x^2-4)) + (5/2-x)((2+x)/(2+x)) - (1/2+x)((2-x)/(2-x))\n*(2x/(x^2-4)) + (10+5x)/(4-x^2) - (2-x)/(4-x^2)\n*(2x/(x^2-4)) + (8+6x)/(4-x^2)\n\nyou should be able to get it from there
357953
1st one:\n\n5x-2y=-5; flip 2y to other side\n5x=2y-5; divide by 5\nx=2/5y-1; put this into 2nd equation for x\ny-5(2/5y-1)=3\ny-2y+5=3\n-y=3-5\n-y=-2\ny=2\n\nput this into 2nd equation for y\n2-5x=3\n-5x=1\nx=-1/5\n\n2nd one\n8x-4y=16; divide by 4\n2x-y=4; flip 2x to other side\n-y=4-2x; multiply by -1\ny=2x-4; lo and behold this is exactly the same as the 2nd equation - can't be solved with substitution, equations 1 and 2 are the same\n\n3rd one\n4x-12y=5; divide by 4\nx-3y=5/4; flip 3y to other side\nx=5/4+3y; substitute this into x in 2nd equation\n-(5/4+3y)+3y=-1; simplify\n-5/4-3y+3y=-1; cancel out the -3y and + 3y\n-5/4=-1; well, how can you have -5/4 ever equal to -1, equations are not the solvable (unless either of the numbers equals infinity)
140648
5/X+1<-2\n-1\n5/X<-3\n*X\n5<-3X\n/-3\n-5/3<X
564366
a) - Just substitute the numbers, so the problem becomes:-\n\n5+ 3(4-2) - (Do the sum in brackets first then multiply the answer by 3 then add the 5)\n\nb) - Y=3(x-5)(x-2) - Lose the brackets first by multiplyiny what's inside by eachother - (x-5)(x-2) - First multiply the xs, then the x in the first bracket by the 2 in the 2nd, then the minus 5 in the first bracket by the x in the 2nd, then the minus 5 in the 1st by the minus 2 in the 2nd. Add together the 4 terms and multiply by the 3 outside the brackets, and you should get to one of the options given.\n\n\n3) - Should be fairly obvious from the options given - Y = x+5 so Y is 5 greater than X \n\nHope this helps
501183
3x + 2y - 2z\n\n3(5) + 2(2) - 2(1)\n\n15 + 4 - 2\n\n19 - 2\n\n17\n\nThe answer is 17\n\n- - - - - - -s-
677040
well start by multiplying things out\n\n-8x+12=-8x+5\n-8x+8x+12=5\n0+12=5\nno solution?\n\n2x+3y=6\n2x=6-3y\nx=6/2-3y/2\nx=3-(3/2)y
409231
1.  5x + 7= 3x + 21\n     -3x       -3x\n     2x + 7 = 21\n           -7    -7\n     2x = 14\n     /2     /2\n        x = 7\n\n2.  3x - 2 (5-x) = -3(x-10) + 3x\n     3x - 10 - 2x = -3x + 30 + 3x\n     x - 10=30\n     x=40\n\n3.  5( x+1) = 3(2x +3) + 5\n     5x + 5 = 6x+9 + 5\n    5x+5=6x+14\n    5=x+14\n    x=-19
506653
5x - 15\n3x -  9 \n\n5 ( x - 3 )\n3 ( x - 3 )  = 5/3\n\nx^2+7x+10\nx^2+11x+30\n\n( x + 5 ) ( x + 2 )\n( x + 5 ) ( x + 6 )   =   (x+2)/(x+6)
216609
Remember Order of Operations - in this case, Parenthesis, then Add/Subtract.\n\n1.) First, we do the parenthesis:\n3x-5(3x-7)=2(x+9)+45\n3x-(15x-35)=(2x+18)+45\n\n2.) Next, we add/subtract from the parenthesis:\n3x-(15x-35)=(2x+18)+45\n-12x + 35 = 2x + 63\n\n3.) Then, we solve by subtraction and division:\n-12x + 35 = 2x + 63\n-12x - 2x = 63 - 35\n-14x = 28\nx = -2\n\nCheck:\n3(-2) - 5(3(-2)-7) = 2(-2+9)+45\n-6 - 5(-6-7) = 2(7) + 45\n-6 + 65 = 14 + 45\n59 = 59
345973
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
259562
Um...\n\n2(-X) + 3(-X) + X + 8\n\n-2X - 3X + X + 8\n\n-5X + X + 8\n\n-4X + 8\n\n8 - 4X
465806
Let one side be 'x', second will be 'x + 5 ' third will be  ( x+5) - 3\nx  + x + 5 + ( x + 5 ) - 3 = 16