greatest commmon factor of these:\n\n36,150, 100\n\n2.  27x4, 18x3\n\n3.  -45y, 150y3\n\n\nfind the greatest monomial:\n\n1.  7y-7\n\n2.  9x+30\n\n3.  54x2-36\n\n\n4.  y2-5y\n\n\n5.  3x2+6x\n\n\nMy roonate and I are torn between these -we both got different answers so if anyone can help, I would appreciate it..
209209
36 = 2*2*3*3\n150 = 2*3*5*5\n100 = 2*2*5*5\n\ntake those that are common amongst all three and multiply them. 2 is the only common so answer is 2\n__________________\n2. 27x4, 18x3\n\n3*3*3*x*x*x*x\n3*3*2*x*x*x\nso 3*3*x*x*x = 9x3\n______________________\n3. -45y, 150y3\n\n3*3*5*y\n2*3*5*5*y*y*y\n\nso 3*5*y = 15y\n____________________\n\n1. 7(y-1)\n2. 3(3x+10)\n3. 6(9x2-6)\n4. y(y-5)\n5. 3x(x+2)\n\n\n\n\nMONOMIAL: An expression that is either a numeral, a variable, or the product of a numeral and\none or more variables.
399305
with n a perfect square  represent n as x^2 + p with prime p = 1 mod 4 and write p = y^2 + z^2. This yields the representation n = x^2 + y^2 + z^2. \n the largest n for wicht this is not possible is 9634\n\nHow serious are you with your questions ?\nsee http://answers.yahoo.com/question/index;_ylt=AvivP2vdn_qSdnT5M_Siyhfsy6IX?qid=20061106081029AAr4yHJ\n\nyour chooses answer is not an answer
162631
yes u can\nt^2(s^4-4)is the factored form\nt^2 is the highest common factor\n\n\n75x^2 - 147y^2\n3 is the common factor\n3(25x^2-49y^2)\n3(5x^2-7y^2)(5x^2+7y^2) is the factored form of 75x^2 - 147y^2
504937
When you multiply a polynomial, the degrees are added\n\nex: x^2 * x^5 = x^7\n\nbut... if they are in parenthesis, you multiply the degrees\n\nex: (x^3)^6 = x^18\n\nanswer #1: 6\n\nbut you also have to take the coefficient into account. That must be multiplied as well...\n\nex: 3x^2 * 2x^4 = 6x^6\n\nanswer #2: x^3 - 41x^2 + 22x + 3\n\nThe only two things that can be combined are 8x and 14x = 22x\n\nI don't know what you need to do with #2, solve for x or just add? The adding rule for polynomials is that monomials with different degrees cannot be combined.
98174
Use the guess and check method.\n\nFirst, find all the factors of the number at the far right (example: in the 1st exercise, it is 25, so...\n\n25=1*25, 5*5\nNext, find those factors that together add up to the number in the middle.(10, in this case) . That would be: 5*5=25 and 5+5=10. So you write...\n(a+5)(a+5). \nDo this with all the rest.However, this sadly doesnt work with trinomials that have its largest exponent be bigger than 2. Also the term with the largest exponent (remember:it has to be 2) cannot have a coefficient.\n\nNote:this method works with the following exercises:1,2,3,4,5,6,and 7. I'm pretty sure. :)
490236
84, without even needing to check. That is 2*2*3*7, which gives 3 prime factors. You can't get 4, since 2*3*5*7 is too big.
138785
It's pol_Y_nomial (polynomial) and try this one:\n\nhttp://www.google.com/u/lamarmathnotes?q=polynomials\n\nor this one:\n\nhttp://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut7_factor.htm
254606
ok\nI am guessing they are two different fractions?\nso you can cancel out with the same method of cross multiplication\nso it would be\nwait is the 14s = 14x is that what you meant?\nthen it would be\n2x/6 *  7a/5y^3\nso then you have\n14xa/30y^3\nwhich simplifies t:\n7xa/15y^3\n\nIf you can, can you make the question clearer so I can verify the answer
333425
find whole (integer) number a,b, and c such that a^3+b^3=c^3.\nDon't remember the answer anymore,but it should be easy - all numbers were less that 10.
353598
f = 30 x 25 x 20 x 15 x 10 x 5 x the other 24 integers. \n\nSo f contains 7 factors of 5 (25 supplies 2 of them) and more than 7 factors of 2. \n\n(The 15 even numbers supply a total of more than 15 such factors as there are three powers of 2 and 3 of the other even numbers (12, 20 & 28) are also divisble by 4 and 24 is divisible by 8)\n\nBut 7 factors of 2 is all we need for our purposes and even if we had a multitude of surplus 2s, they cannot give us another 10\n\ni.e. f contains 7 factors of 10. And ONLY 7 such factors as each 10 can only be made up of a 5 and a 2 \n\nso d = 7 is the only possible answer, given that we are told that d >6\n\nGENERALISING:\n\n50, 75, 100, also supply two 5s to a factorial they are part of, \n\nso for f = 55! and d> 12, d must = 13\nso for f = 80! and d> 18, d must = 19\nso for f = 105! and d> 24, d must = 25\n\nhowever\n\nfor f = 130! and d> 30, d is not 31 but 32\nCAN YOU SEE WHY?
360167
The greatest common factor of two non-zero integers is the largest positive integer that divides both numbers without remainder. To find the GCF of 2 numbers, make a list of their factors (the numbers that they are divisible by)For example:\n\nFactors of 25: 1, 5, 25 \nFactos of 36: 1, 2, 3, 4, 9, 12, 18, 36. \n\nHere you see that 25 and 36 do not have a common factor (other than 1)...maybe you typed the question wrong?\nGood luck anyway...;-)
98554
1^3 = 1^2\n4^3 = 8^2\n9^3 = 27^2\n\nsee the pattern?  cube a perfect square\n\nso 16^3 = 64^2 will work (4096)\n\n25^3 = 125^2  (you found)\n\n36^3 = 216^2  (46656)\n\ntoo high\n\nSo you only missed 4096.
297439
With just ! (Factorial), +, -, * and /, it is impossible to get 150 using only 3 5s without the x^2 (Squared) operation (Which means x*x, in case you are in Fifth Grade), or using a '^2' as you say. If you say there is an alternate way, and there really is, then I give up and admit defeat. (I'm sure most others do.) If you are so sure, why don't you post the answer yourself?
649355
1. 2\n\n2. 2a^2b\n\n3. 6xyz^2(2z-3y)\n\n4. 3a(4a-b+3ab^2)\n\n5.(d+2)(d+3)\n\n6.(x-9)(x-2)\n\n7. (4x-1)(x+3)\n\n8. (4b-9)(4b+9)\n\n9.(y+7)^2\n\n10. (2m+7n)^2
534050
Edited: With the new information.\nLet x be the width and y be the length required. \n\nThen we have the equations  \n                                 xy = 150.................a\n                              x + 2y = 35..............b\nThen,         y = (35-x)/2                 (ans to i)\n\nSubstituting in equation a,\n                              x(35-x)/2 = 150             (ans to ii and iii)\n               or          x^2 -35x +300= 0\n               or      (x-15)(x-20) = 0\nSolving, x = 15 or 20 and correspondingly, y = 10 or 7.5  (iv)\n\nthis is the case when ALL of 35 meters of fencing is used. we can use LESS than 35 meters too.\n\nNow, in this case,      xy = 150\n          and              2y + x < 35\nSubstituting for y,\n            2 * 150 /x + x <  35\nor x^2 - 35x +300 <0\nor   (x - 35/2) ^2   < 25/4............c\n\nnow if x > 35/2, inequation c becomes (on taking square roots)\n                                 x - 35/2 < 5/2\n or   x < 20\n\nif x < 35/2  c becomes    - (x - 35/2) < 5/2\nor                                     x > 15\n\nTherefore the restriction is 15 < x < 20\n and    7.5 < y < 10                (ans to v)
531117
-4t^2+36-72\nFactor-2t+12\n +2t-4t^2+24\n-6+12-72\nIt is (2t-6)(-2t+12)\n\nFirst you put the first trinomial in the upper left corner of the box (-4t^2).\nThen you put the last trinomial in the bottom right corner of the box(-72).\nYou multiple (-4t^2 & -72) then you make a list of factors that will equal that number. In this case they are 12 & 24.\nYou know that one number must be negative because -4t^2. Fill in the info in the box and multiple them out. \nIf you do this you can see that it equals the trinomial.\nAdd down the left side of the box to get the first set of numbers.\nThen add across the box to get the second of numbers.\nYou can see how I did this.\n\nYou can email me if this doesn't make sense.
306199
8x^2y^3+5y^2 when "FACTORED COMPLETELY"=\n\ny^2 (8yx^2+5). \n\nThis should be right. My dad is a complete genius and he did this in like 2 seconds. I double checked it on my calculator too by plugging in numbers, so I can assure you he's right.\n\nHope this helps! Have a nice day :)