When your walking or running in the sphere/globe, it rotates and in the video game your walking or running according to the sphere/globe.  The sphere/globe doesn't actually go anywhere, it just rotates in place.  I saw this on TV, I don't remember what channel or what show but I would love to know who creates something like this.
216349
it was on discrovery channel (well on daily planet which is on discovery channel) go to the discovery channel website and go to the daily planet section you should find it. That thing was super cool but 50000 for a goming controler is a little out of my leauge. try buying the ddr dance mats for PS2 and play games not ddr its crazy fun tetris is nutty and crash bandacott or spyro the dragon are just insanely fun.
299998
I wish I could show you how to do it. The best way is to take smaller steps and push downward with a spring in the step. This is a technique used by the Israeli army and you can outrun everyone every time. Kind of a sideways motion.
27115
Initially, the ball is pushed, it slides. There is no rotation, as stated in the problem/question. This means there is no rotation at all. That all the velocity is translational.\n\nFor this scenario think of the ball as a solid block that has been pushed and it sliding across the floor.\n\nAs stared, at some time (t1) the ball begins to roll.\n\nAt this time, the ball's motion is both rotational as well as translational. In other words, it rolls as well as moving forward. This motion is what takes place at the *contact point* of the ball to the floor.\n\nIf the ball rolls, it is not slipping.\n\nIndeed, the friction causes the linear motion to decrease, and eventually stop the ball.\n\nThe rotational motion of the ball is also undergoing friction. A rolling sphere's motion is very subtle and often misunderstood. By virtue of the ball's mass there is a very tiny (tiny is relative to the mass and material) flat spot between the ball and the surface upon which it rolls, whereby a small torque gives rise to a resistance of the motion. This is why a rolling sphere slows. But.....since there is friction, the velocity of translation, is related to that of rotation by the following:\n\nv^2 = 2gh/(1 + I/Mr^2)\n\nWhere M is the mass of the ball and "r" its radius, I its moment of inertia. This is common notation. If there is no rotation, then the moment of inertia term drops out (I = 0) and you are left with a velocity which is strictly that of a translating body......kind of like free-fall.\n\nIf the ball is given one initial push to give it the initial velocity Vo, then unless there is some other forcing function at work, friction will act to decrease the motion of the ball, and all said velocities thereof. None of the velocities will increase.\n\nIf you know of a situation where such a case can exist where the ball increases velocity without doing anything to it.....make sure you mention my name when you pick up the your Nobel Prize.\n\n:)
303227
Remote controlled movable ball amusement device\n\nA remote controlled movable ball amusement device includes a hollow sphere having a propulsion mechanism within the sphere. The propulsion mechanism includes a receiver and a drive unit. The drive unit causes the sphere to move when actuated by the receiver. A remote transmitter sends signals to the receiver for causing the actuation of the drive unit.
460333
I think this could be how it works.. we know all bodies exert a gravitational pull towards the centre of its mass.. Even humans exert a gravitational pull on the earth.. it juz that the force is too feesible to note due to the huge size of the other object (earth). So we dont see the earth moving towards us..\n\nBut in the case of pollen n water particles, pollen is much heavier than the water molecule.. so its gravitational pull is stronger that the pull of the particle..hence the molecules move towards pollen..\n\nThats just a thought..could be true
381693
Think of the wheels as spinning masses or revolving weights, in fact gyroscopes. \nEach wants to turn left or right while spinning but is constrained by it's axis,\nHowever both drift overtime.\nNow add another pair further back and wider apart, and this pair are not on the same line of travel.\nWith four wheels all wanting to drift the resultant direction becomes a straighter line.
284969
Wow...how is that possible.when i move back and foward it starts going in circle...its really cool.
504900
Why would the angular speed of the merry-go-round change when the weight of the person is little over a third of the weight of the machine and the speed at boarding was almost double the rotation speed of the machine? I don't think this would change at all.  Wouldn't the  revolutions per second remain the same?
37042
I think the hardest question ever asked was asked by a scientist.  This was the question, and it literally drove him insane thinking about it:  Two large metallic orbs are traveling towards each other on a collision course.  Both are indestructable, and nothing can divert them from their path in any way.  They can never stop moving on their path for any reason.  What would happen when they collide?  Neither can be moved from the path that they are traveling, they cannot be destroyed, and they can never stop moving.
375906
Your presumption is entirely likely my friend.  Things in the Universe that have mass and hence gravity, tend to rotate around something else.  All plants spin on their axis, all planets orbit around the Sun, the Sun rotates around the center of our Milky Way galaxy, our galaxy rotates around other galaxies in the local cluster of galaxies, the local cluster rotates around other clusters and so on right up to the Universe itself.
469052
There is a weight mounted off-balance on a shaft so that it hangs down. It has a one-way ratchet connected to a reduction gear so that motion in one direction winds the spring. In the other direction the shaft just turns freely.\n\nAs you move about, walking, running, gesturing, whatever, your wrist moves back and forth. As your wrist changes position the weight causes the shaft to turn and the ratchet captures the motion to wind the main spring.
384767
(a) Assuming the base is a half-circle and that there are no other forces acting on the mass (friction, drag, etc), then the kinetic energy at the base is equal to the potential energy at the top. Note that the change in potential energy is not affected by the semi-circular path the mass follows, but rather the net change in height. This net change is simply the radius of the half-circle container:\n\nKE = mgR = (.71 g * 1 kg/1000 g)(9.8 m/s²)(25 cm * 1 m/100 cm)\n\nKE = .00174 J\n\n(b) The kinetic energy associated with rotation is given as:\n\nKER = (1/2) I w², where w is the rotational velocity. Note that since the sphere rolls without slipping, the translational velocity of its cener of mass is simply:\n\nv = w * r\n\nSubstituting this into the expression for the rotational kinetic energy:\n\nKER = (1/2) (I / r²) v²\n\nNote that the expression for the translational kinetic energy is:\n\nKET = (1/2) m v²\n\nThus, the total kinetic energy of the ball at the base of the hemisphere is;\n\nKE = KER + KET = (v²/2)( I/r² + m)\n\nThe fraction of the rotational kinetic energy over the total is:\n\nf = KER / KE = (v²/2)( I/r²) / (v²/2)( I/r² + m)\n\nf = ( I/r²)/( I/r² + m)\n\nFinally, the moment of inertia, I, of a sphere is:\n\nI = (2/5)mr²\n\nSubstituting this into the expression for f:\n\nf = (2/5)m/( (2/5)m + m)\n\nf = (2/5)/( (2/5) + 1)\n\nf = 2/7\n\n(c) At the base of the hemisphere, there are two forces acting on the ball: the force of gravity and the centripetal force. At the base, these forces are coincident (act in the same direction). Thus the normal force, which opposes these two, is simply:\n\nN = Fgrav + Fcent\n\nN = mg + mv²/R\n\nTo find v, recall that KET / KE is 2/7. Using this, we can manipulate the terms to get v:\n\n(1/2) (I / r) v² = (2/7)(mgR)\n\n(1/2) ((2/5)m) v² = (2/7)(mgR)\n\n(1/5) v² = (2/7)(gR)\n\nv = sqrt((10/7)(gR))\n\nv = sqrt((10/7)(9.8 * 25 cm * 1m/100 cm))\n\nv = sqrt((10/7)(9.8 * 25 cm * 1m/100 cm))\n\nv = 1.871 m/s\n\nFinally, the normal force is computed as:\n\nN = mg + mv²/R\n\nN = (.71 g)(9.81 m/s²) + (.71 g)(1.871 m/s)²/(25 cm)\n\nN = (.71 g)(9.81 m/s²) + (.71 g)(1.871 m/s)²/(25 cm)\n\nN = .0169 Newtons\n\n\nGood Luck! :)
464723
It is, by definition, random.  Repitition of a particular sequence of movements in a given timespan (although I don't know how you would measure them accurately in 3 dimensions) is a statistically possible, but highly unlikely, event.
371271
Probablly the most novel one that I've heard of is in the "lensman" series by EE doc smith, and it involves inertialessness. He had a device that would somehow remove the inertia of the object it was hooked to, thus making it unneccesary to accelerate. I thought this was cool; it had some really interesting ramifications. Good series, too!
639405
because the mass of sun is higher than all the other planets ...Moon has a smaller mass compared to earth so it revolves around the earth ...actually it's all 'relative' ...Motion is relative ...if you are driving in the car ...you can say the whole world is moving backwards ....we don't say that ...beacuse of the frame of reference ...we have chosen i.e. "the driver" also the complexity of the motion ....involved when looking at the world the other way....similarly you can say that sun is revolvin the planets but in the frame of reference the motion would be very complex ....so we choose the easier frame of reference ....alo the whole galaxy is rotating ...if you look from the outside frame of reference ....\n\n\nMOTION HAS A DUALITY ....NEVER A SINGULARITY ....
348253
I don't know if it applies to your question or not, but how about the toy called "Newton's Cradle".  It's the one that has either marbles or large steel ball bearings that are strung up and then one is pulled back on one end and the motion is transmitted through the other bearings to the last one that then swings out and returns hitting the bearings once again, this goes on back and forth for awhile.
90783
It is a straight line. You're looking at a map when you should be looking at a globe.  \n\nFind a globe and stretch a string from your North American origin to your overseas destination, and I'll bet it follow the same path you're talking about.