the perimeter of a figure it the "distance around."\n   suppose that-\n    two sides of a triangle are equal \n    the third side is 10cm greater than each of the others\n    the perimeter is 130cm\nfind the length of each side
215494
The permiter of a triange would be a + b + c where a,b,c are the length of the sides. Let a and b be the sides that are queal. Represent this quantity by x. So so far we have x + x. We knoe the third side is 10 cm greater than x. so we let this be represented by x + 10.\nEverything added together = 130 so:\nx+x+x+10 = 130\nconbine like terms\n3x+10=130\nsubtract 10 from both sides\n3x=120\ndivide by 3\nx=40. \nSo, your two sides of equal length are 40 and the third side is 10 greater, so it is 50. Therefore the sides are\n40,40,50
472703
ok so 2 length sides (6x-2) and 2 width sides(x+3), all added together, make the perimeter (100):\n2(6x - 2) + 2(x+3) = 100\nDistribute the 2s through the parenthesis:\n(12x - 4) + (2x + 6) = 100\nCombine like terms:\n14x + 2 = 100\nSubtract 2 from each side:\n14x = 98\nDivide each side by 14:\nx = 7
199189
You can use Heron's formula if you know the length of all three sides. \nHeron's Formula:\nLet s be the semiperimeter (which is half the perimeter) and a,b,c be the length of the sides, then the area is\nA = sqrt[s*(s-a)*(s-b)*(s-c)]\nperimeter = 4+4+6 = 14\ns = 14/2 = 7 (because s is one-half the perimeter)\nA = sqrt[7(7-4)(7-4)(7-6)]\n= sqrt(7*3*3*1)\n= sqrt(63)\n= 3*sqrt(7) which is approximately 7.93725\n\nYou can also use the Pythagorean Theorem to find the height.
106822
Perimeter\ntwo sides are 8 and the other two sides are 16. \n\n8 times 2 is 16 and 16 times 2 is 32. \n\n16+32= 48(unit) \n\n                Area\njust multiply them:) \n\n8 times 16= 128(unit) squared\n\nDoes that help?
364928
Define the lengths of the smallest triangle:\nAP = ½ AC\nAQ = ½ AB\n\nSquare the equations:\nAP^2 = ¼ AC^2\nAQ^2 = ¼ AB^2\n\nPythagorean theorem for smallest triangle:\nAP^2 + AQ^2 = PQ^2\n\nSubstitute:\n ¼ AC^2 + ¼ AB^2= PQ^2\n\nMultiply by 4:\nAB^2 + AC^2 = 4PQ^2\n\nPythagorean theorem for triangles ABP and ACQ:\nAP^2 + AB^2 = BP^2\nAQ^2 + AC^2 = CQ^2\n\nAdd the two equations:\nBP^2 + CQ^2 = AP^2 + AQ^2 + AC^2 + AB^2 \n\nSubstitute:\nBP^2 + CQ^2 = PQ^2 + AC^2 + AB^2\n\nSubstitute:\nBP^2 + CQ^2 = PQ^2 + 4PQ^2\n\nTherefore:\nBP^2 + CQ^2 = 5PQ^2\n\n\nIf you get stumped with this type problem, sometimes it helps to start at the end and work backwards...
33098
The dimensions of the rectangle are 5.5 cm x 16.5 cm\n\nIf the rectangle is 3x longer than it is wide, then there are four units that make up two sides...1 unit width, and 3 units length.  So we have four units (4x) that make up one half of the perimeter.  That means that eight units (8x) will make up the entire perimeter.\n\n8x = 44cm, therefore x = 5.5cm\nWe already said that one side is 3x and the other is 1x, so that gives us dimensions of 5.5cm x 16.5 cm
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We know that the width is 5 yards, and that the length is double that, we can deduce that the length is 5x2=10.  So the rectangle is 5x10.\n\nThis means that the perimeter is 5x2+10x2=30 yards.  Since there are two sides length wise, and two width wise.\n\nThe area is the length times the width, 5x10=50 square yards.\n\nAgain, if you want to grow as a person you need to solve these yourself.  The time it took you to copy all these questions onto Yahoo! you should have been able to answer them yourself.  If you don't know how, you should be asking your teacher to explain them and give you extra tuition.
166350
Triangles can be classified in two ways:\n\nBy the relative lengths of their sides:\n\n1.  Equilateral:  all sides are of equal length\n2.  Isosceles:  at least two sides are equal\n3.  Scalene:  all sides have different lengths \n   \nBy the size of their largest internal angle:\n\n1.  Right:  has one 90°internal angle\n2.  Obtuse:  has one internal angle larger than 90° \n3.  Acute:  all internal angles are smaller than 90°
165812
One width is 1/4 the length:\nRectangle: a 4-sided figure with 2 sets of equal-length sides.\nside a = 1/4 side b.\nside a + corresponding side a = 1/2 side b.\n4a = 1 long side.\n8a = 2 corresponding long sides.\n2a + 8a = 130'\n10a = 130'\ntherefore a= 13'\n4a = 4x13 = 52'\n2 short side @ 13' each = 26'\n2 long sides @ 52' each = 104'\n104' + 26' = 130'\nNot trying to do your homework for you, but helping you see how to think it through.  Hope this helps.
506944
The area of a triangle is half base times height.\n\nCould you properly define the length of the base, height and hypotenuse?
436988
just add the sides -- that is the definition of a perimeter\n\n2x - 5 + 3x + 1 + 4x +2 \n= 9x - 2\n\nhope this helps !!!
499177
1st way:  \nP= Perimeter\nL = Length of square or rectangle.\nW = Width of square or rectangle.\n\nP = 2L + 2W\n\n-----------------------------------------------------------------\n2nd way:  \nP = Perimeter\ns = side length of square.\n\nP = 4s\n\n-----------------------------------------------------------------------\n3rd way:\nP = Perimeter\ns = side length of square.\n\nP = s + s + s + s\n\n--------------------------------------------------------------------\n4th way: \nWritten out in words.......\n \nPerimeter = (Add all sides of shape together)
332234
perimeter is the length of a line that surrounds a geometric shape.. so you see a aquare is made of 4 lines.. so its perimiter is those lines added together, the formula of a circle is a bit more complicated but the same idea..
258336
The answer is C\nwell, one side's length of a triangle should be shorter than the other 2's plus (2 sides plus should be longer than one side)\nthen: 3x+4+8x+2>6x-1\n      8x+2+6x-1>3x-4\n      6x-1+3x+4>8x+2\n--> x>-7/5\n    x>3/11\n    x>-1\nThus, the answer should be x>3/11\n:)
441152
Area = 5 square meters\nBase = 2x\nArea of any triangle = (Base*Height)/2\n5 = (2x*Height)/2\n5 = x*Height (The 2's cancel each other out)\nx*Height = 5\nHeight = 5/x(Divide both sides by 'x')\n\nI hope that helped
35787
I´m guessing you want to know the difference in meaning, since you already have the values.\n\nThe radius is the distance measured from the center to the edge of a circle. Imagin Earth as an orange cut in half and put back together. The cut line would be the Equator. Now open the orange and face the inside of the orange and you´ll see a white circle. The distance from the center of the orange to the edge (or white stuff) is the radius.\nThe circumference (or perimeter) is the length of one full lap around that circle.
534556
width = x\nlength = 2x +2\nperimeter = 52\n\nperimeter = 2(length) + 2(width)\n\n52 = 2(2x + 2) + 2(x)\n52 = 4x +4 +2x\n52 = 6x +4\n48 = 6x\n8 = x\n\nbecause x = 8 then:\n\nwidth = 8\nlength = 2(8) + 2 \nlength = 16 + 2\nlength = 18\n\nlength = 18, width = 8\n\nto check it add up the numbers to see if they equal the perimeter of 52\n\n18 + 18 + 8 + 8 = 52 True.  answer is correct