What is a example of electric force and electric current?
208393
Try these links\n\nhttp://en.wikipedia.org/wiki/Electric_force#The_electromagnetic_force\n\nhttp://en.wikipedia.org/wiki/Electrical_current\n\nMay the Electric Force be with you... always.
257041
Newton's First Law of Motion:\n 1. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.  \n\nNewton's Second Law of Motion:\n 2. The relationship between an object's mass m, its acceleration a, and the applied force F is F = ma. Acceleration and force are vectors (as indicated by their symbols being displayed in slant bold font); in this law the direction of the force vector is the same as the direction of the acceleration vector.  \n\nNewton's Third Law of Motion:\n 3. For every action there is an equal and opposite reaction.
318978
Basically photons (or light) are the particles that is exchanged in communicating the electromagnetic force. To understand the essence of electric charge then you must understand light, or EM fields. This is independent of the atom.
36399
Gravity and electromagnetic forces.  Gravity is an odvious answer.  Most other forces, including frictional forces, fall under electromagnetic forces.  The strong and weak force mentioned earlier can not be experienced directly.  They come into play when dealing with radiation and sub-atomic physics.
63301
Electricity is made up of electrons.  It is the flow of electrons that causes electricity to do work.\n600 B.C. Thales of Miletus writes about amber becoming charged by rubbing - he was describing what we now call static electricity.\nFirst electric motor 1821 First electric motor (Faraday).
93455
In physics, a magnetic field is an entity produced by moving electric charges (electric currents) that exerts a force on other moving charges. (The quantum-mechanical spin of a particle produces magnetic fields and is acted on by them as though it were a current; this accounts for the fields produced by "permanent" ferromagnets.) A magnetic field is a vector field: it associates with every point in space a (pseudo-)vector that may vary in time. The direction of the field is the equilibrium direction of a compass needle placed in the field.
474920
electricity is either made by chemical reactions, or by moving a magnetnic field over a copper wire, as i am sure you allready know, so the problem is geting a force that can move the magnet, to give inductance in the wire. causing a current to flow.\nwater turns the blades of a fan, or tubine whitch is conected to a magnet witch turns inside a copper coil.\nso any natural way that can generate enough force to move the magnet, can be used.\nwith nuclear the heat is made in a chamber called a reactor whitch turns the water to steam the steam turns the turbine whitch is conected to the magnet.\nif you have a propella connected to a magnet that is moved by wind that is driven by the sun, inside a copper coil you get some electricity\nin water fall the downward force of the water turns the blades, withch turn the magnet, inside a coil,\nall diffrent ways of doing the same thing.\nnot sure about forrest though, unless you burn the wood to make steam, to guess what turn the magnet inside the copper coil. or maybe you could cover the tree in magnets, and buld a copper coil next to it, then wait for the wind to sway the tree
504733
To both of our surprise there is a direct analogy between electrical components and mechanical systems. Mercedes has presented a simulation of their suspension system that performed million simulation routines by using coils capacitors and resistances. \nYes my friend a capacitor an inductor and a coil can be directly related to a dumping or suspension or oscillating system in mechanical system where potential and kinetic energy and losses of course can be correlated with capacitance (electrical and magnetic energy), inductance and resistance. \nI am not sure 100% of what you are trying to say and what you have in mind but I am sure that you can make something of it. Or at least simulate it and represent it right.\nThe reason we ended in this is because the analogy was more than obvious and because it is easier to simulate circuits and get reading (multiple set) than to perform test with mechanical sensors etc.\n\nNice question\nKeep thinking \n\n\n(do not get your mind wasted though mate.!)
383706
Net force is required to change the motion of an object, or accelerate the object. Often forces are balanced, so net force = 0, so motion does not change.\n\nWork is in the same units as energy, not force. Work is related to force by \nW = F*d*cos(theta) where F is the applied force, d is the distance through which the force has been applied, and theta is the angle (if any) between the force and the distance. \n\nFor example if a 100 Newton vertical force is applied to lift an object to a table 5 meters above the starting point, 500 Newton*meters, or 500 joules, of work have been done.
467188
can you give examples (such as the witches equation)
111520
electric fields are energy fields that exist around charged particles. now if you bring another charged particle into an electric field, it experiences a force. it can be either repulsion, for similar charges or attraction for opposite charges.\n\nThis force called the electrostatic force is what causes pieces of paper to stick to your sweater, and is the same force that drives electric motors.\n\nNow if you bring two charged sheets close, like described in the given problem, they attract or repulse each other. You are simply being asked to find the force.\n\nIf you consider two small pieces of sheets, the math for calculating the actual force is quite complex, especially at the edges. So for toy problems, like the ones used for teach basic principles, the charges are always "point charges" where the charged body does not occupy any volume or "infinitely large" like the sheets above. The only reason to consider something hypotheical like that is to keep the math simpler.\n\nNow when you have an infinitely large sheet, how do you measure the charge on it? if a small area of the sheet holds x Coloumbs of charge, the total charge is infinity. so again for the math, we use the charge per unit area. It turns out the forces *are* dependant on the charge per unit area and not the entire charge.\n\nNow the forces calculated also end up having the units Newtons per unit area.\n\nDoes that answer your question? Or do you want me to work out the problem too ? :) Let me know\n\n===========================================================\nI am not able to send you a message.. send me your email address\n===========================================================
141757
Force is a vector quantity as it has both magnitude (size) and direction.
530688
A current is simply a flow of electrons in a direction.  These electrons collide with the materials in the wire, which in turn vibrate, thus producing heat.  A curving wire re-directs the flow of the electrons, whose inertia resists the change in velocity (direction).  The material must then act upon the electrons normal to the curve, which produces stronger collisions (greater resistivity) and thus more heat.
426656
using KCL (current law), A is corrent.\nusing KVL (voltage law), B is correct\nC doesn't make any sense, and you can support that with the definition of the KCL.
204849
from my knowlege the emf is opposite of the direction of change of flux and the difference between ac, emf is the phase constant. for example if emf is vertical ac is 90degrees-phase constant
267740
Let's see if I can remember...\n\na) Find the current flowing through a DC circuit, from a 12V battery and a 3 ohm resistor.\n\nBy Ohm's Law, V = IR, where\n\nResistance = ohms = R\nCurrent = amperes = I\nVoltage = volts = V\n \nYou want to find the current, in amperes, so we switch the equation around a little: if V = IR, that also means that I = V/R (dividing both sides by the same thing gives the same answer).\n\nNow, plug in our values:\nI = (12 volts/ 3 ohms) = 4 amperes\n\nb) what is the current in an AC circuit, with 120 V and 60 W lightbulb.\nIn this case, Watts is a unit of power, and volts is a unit of resistance, and amperes is a unit of current. Electrical power is amperes times volts, or W = I * V\n\nIn this case, W = 60 and V = 120, so we rearrange it:\nW = I * V or \nI = W/V or \nI = (60 watts/120 volts) = 0.5 A\n\nAs for the atom model problem...hmmm! Si is the symbol for silicon. It has an atomic number of 14 (not 16) and an atomic mass of 28.085. According to the Bohr model of an atom, every atom has electrons (with no mass, and a negative charge), protons (with a mass, and a positive charge) and neutrons (with a mass, and no charge). The number of protons and electrons must be equal in order for the atom to have no charge, if one is greater than the other, it results in an ion (positive ion if protons are greater than electrons, negative ion if electrons are greater than protons). Electrons orbit around a nucleus of protons and neutrons.\n\nNow, an element's atomic number (14 in this case) is the same as the number of protons (and electrons, since the element is not an ion, in this case). So a silicon atom has 14 electrons orbiting around its nucleus, and its nucleus also has 14 protons and a number of neutrons.\n\nThe electrons orbit in shells around the nucleus. In the case of silicon, the inner shell has two electrons, the next shell has the maximum number possible or eight, and the third shell has the other electrons, or four. (To check, 2+8+4 = 14.) \n\nFinally, the number of neutrons in the nucleus can be calculated if we know how much a neutron weighs and how much a proton weighs. If N is the weight of a neutron, and P is the weight of a proton, and the number of neutrons is n1, and the number of protons is n2, and we say that the atomic weight is A, we have:\n\nA = (n1 * N) + (n2 * P)\n\nWe want to find n1, so we rearrange this like:\n(n1 * N) + (n2 * P) = A\n(n1 * N) = A - (n2 * P)\nn1 = (A - (n2 * P))/N\n\nNow all we have to do is plug in the relevant values, and we shall get the number of neutrons in an atom of silicon:\nA = 28.085\nn2 = 14\nP = \nN = \n\nSo, n1 = (A - (n2 * P))/N = \n\nSimple! Or at least, simpler! :)\n\nI know what you're going through...getting back into the swing of things after you've been away from school for a long time can be a pain. But keep on plugging away, it's worth it in the end! Good luck!
32924
Okay, you know the right hand rule. Good.\nFirst consider the effect of only the e-field: The e-field is pointing in the +x direction. Therefore, the force it exerts on the proton will also be in the +x direction.\nSecond, consider the effect of only the magnetic field: The magnetic field is pointing in the +y direction; therefore, the force it exerts on the proton will be in the -x direction (you use the rule you described to figure this part out). It so happens, that in the first scenario, the force exerted on the proton by the magnetic field exactly balances that exerted by the electric field. Therefore, the movement of the proton is unaffected.\n\nHowever, in the second case, the proton is accelerated through a potential difference of 2V. Therefore, it will be moving faster (think about it: a higher potential difference has greater "potential" to pull the proton.  Also, the equation F = qvB where q is the charge of the proton, v is its velocity, and B is the magnetic field strength, states that the faster the proton is moving, the greater will be the force exerted on it.  So, compared to the first case with only a 1V potential difference, the magnetic field here will exert a greater force on the proton. But, the force exerted by the electric field is unchanged. So, the net force on the proton will be in the -x direction.