please, please be kind. i am really scared. :(\n\n\n1.)natural numbers or counting numbers\n2.)whole numbers\n3.)integers\n4.)rational number5.)irrational numbers\n6.)decimals\n7.)repeating decimals \n8.)terminating decimals\n9.)solution sets\n10.)finite sets \n11.)infinite sets\n12.)empty or null set \n13.)domain\n14.)open sentence\n15.)equation\n16.)inequalities\n17.)Addition \n18.)Multiplication\n19.)polynomials
217707
1) Natural Numbers are numbers that you count.  They are 1,2,3,4,5,6,7 and so on and so forth starting with one.\n2) Whole numbers are numbers that have no decimals.  They are like -1,0,1,2,3,4,5 and so on towards positive and negative infinty.\n3) Integers are the same as whole numbers.\n4) Rational numbers are numbers that can be expressed in a fraction.  Like 21/7ths.\n5) Irrational numbers are numbers that cannot be expressed in a fraction.  Like the square root of 6.5.\n6) Decimals are pieces of a number like .12 dogs or .75 cups of water.\n7) Repeating decimals are decimals the repeat forever.  Such as 1/3 is .3333333 repeating.\n8)  Terminating decimals do not repeat forever.\n9) Solution sets are sets that solve a problem.\n10) Finite sets are sets that have a final answer.\n11) Infinite sets go on forever.\n12) Empty or null set is a problem with no answer.  It looks like a circle with a line through it.\n13) Domain is what x values the function passes through.\n14) An open sentence is a sentence the doesn't end.\n15) An equation is two things connected by a equals sign.  Such as 4x+y=13-7a\n16) Inequalites are two things connected by a greater then or less then sign.  15>2.\n17) Addition is adding numbers 4+5=9.\n18) Multiplication is timesing numbers like 4x5=20.\n19) Polynomials are numbers with more then one term.  Like 4x+5+6y
116155
Nb2718 and ixat01 have understood the concept well.\n\nYour question has kindled me to refresh my knowledge about numbers.\n\nFirst we shall deal with rational number.\n\nA rational number is in the form P/Q. (P and Q are integers and Q is not equal to zero) \n\nAny rational number is an integer when Q = 1. \n\nDecimals are simply a different way of expressing a rational number.\n\nSquare root of two is an irrational number and hence it cannot be expressed as an irrational number \n\nWhat we can do best is to find a rational number which is more or less equal to that irrational number. \n \nThe number we find can either be written in P/Q form or in decimal form because both represent one and the same.\n\nFor example, the ratio of the circumference of a circle to its radius is an irrational number. \nIf we write 22/7 then it is a rational number.\n If we write 3.1415927, then it is 31415927/10000000. Again it is a rational number. \n\nThen how to represent an irrational number in a simple way? The great mathematicians have guided us.\n\nThe simple way of writing this is Pi. \n\nSimilarly how to write the square root of two?  Write 2^ (1/2).\n\n In fact, the figures 1,2 , 3 etc are all symbols only.\n\nThe multiplication factor 1000000 is written as 10^6 or simply 1M.\n\nIn algebra we use x or y to denote any quantity. Thus there exists many numbers of ways to express any quantity in a simple way.
609593
(1) 1.3\n(4) 4\n(5) Right\n(6) 0\n(7) 0\n(8)0\n(9)12
344970
I'll try to help... \n\nFirst, I'm going to leave out all the x-terms, but just imagine they are there:\n\n.................. ........ ......4/5 56/25 -156/125 -1028/625\n5 ... -4 ... 9 ) 4 ... 8 ... -8 ... 4 ... 1 ... -8\n................... 4 .-16/5 36/5\n...................------------------\n................... ......56/5 -76/5 4\n................... ......56/5 -224/25 504/25\n................... ......-------------- -----------\n................... ............. -156/25 -404/25 1\n................... ............. -156/25 624/125 -1404/125\n................... ............. ------------------- ----------------\n................... ............. ........... -1028/125 1529/125 -8\n................... ............. ........... -1028/125 4112/625 -9252/625\n................... ............. ........... ------------- --------------- --------------\n................... ............. ................. .......... 3553/625 4252/625\n\nIf I did it correctly (which there is no guarantee), I get the answer as:\n\n(4/5)x^3 + (56/25)x^2 - (156/125)x - 1028/625)\nwith a remainder of:\n[ (3553/625)x + 4252/625 ] / (5x^2 -4x+9)\n\nHowever, with all those fractions I probably made a mistake somewhere... your math teacher is a masochist!
544230
1. 1s2 2s2 2p6 3s1\n2. 1s2 2s2 2p6 \n3. 1s2 2s2 2p4\n4. 1s2 2s2 2p6\n5. 1s2 2s2 2p6 3s2 3p6 3d7 4s2
492205
I had a terrible time in algebra in ninth grade. Having a conference with the teacher to find out where I wasn't "getting it" did the trick. I didn't know what "1n" meant! I asked the teacher, and she patiently said, "it's the same as "n." That really opened my eyes. I hadn't figured that out, so it was like a light bulb going on!  For you, it may be something as simple, and so difficult if you aren't thinking mathematically. Math anxiety is a terrible thing.\n\nBy the way, I eventually got an A+ in calculus...me! I'd never have believed it.
21460
hold on let me look at that for a minute....(dya hate math like this as much as i do?)\n\n(1,4) is one for sure\nyea thats' the only one!!!
470169
1. the number before 10 is 9\nmultiply by two\n9 *2 = 18\nsubtract 1\n18 - 1 = 17\n\nthen for 17\n16*2 = 32\n32 - 1 = 31\n\nthen for 31\n30 * 2 = 60\n60-1 = 58\n\nthen for 58\n58 * 2 = 116\n116-1=115\n\nthat is the first five numbers (including 10):\n10, 17, 61, 58, 116\n\n2. multiply two by three\n2 * 3 = 6\nadd one\n6 + 1 = 7\n\nthen for 7\n7*3 = 21\n21+1 = 22\n\nthen for 22\n22*3 = 66\n66+1=67\n\nthen for 67\n67*3 = 201\n201+1=202\n the first 5 numbers are 2, 7, 22, 67, 202
394803
38894 0's between 1-100000\n\nWrite EVERY number (except 100000) as a 5-digit number with leading 0's.  We will subtract out the leading 0's later.\n\nIf the first digit is zero, there are 10*10*10*10=10000 numbers.\nif the second is zero, there are also 10*10*10*10=10000 \nsame with if the third, fourth or fifth is zero.\nSo now, we have 5*10000 or 50000 zeroes.\nNow we subtract out the number of 0's in numbers with leading 0's.\n\nIf the first is 0, there are 10000 numbers, so we added 10000 too many 0's, so subtract 10000\nIf the first two are 0, there are 1000 numbers, so we added 1000 too many more 0's\nIf the first three are 0, we added another 100 too many.\nIf the first four are 0, we added another 10 too many.\nIf all five are zero, we add 1 more too many.\n\nSo N = 50000 - 10000 - 1000 - 100 - 10 - 1 = 38889 for the numbers 1 through 9999.\nThen we add 5 more for the number 100000, so\nN = 38894\n\n*****\nThe equation for the number of 0's between 1 and 10^n inclusive is:\nn10^(n-1) - 10^(n-1) - 10^(n-2) - 10^(n-3) -  ... - 10 - 1 + n\n= (n-10/9)*10^(n-1) + n + 1/9
171622
THE POSSIBILITIES:\n\n1.1:1→1*1=1\n2.1:2→1*2=2\n3.1:3→1*3=3\n4.1:4→1*4=4\n5.1:5→1*5=5 √\n6.1:6→1*6=6\n\n7.2:1→2*1=2\n8.2:2→2*2=2\n9.2:3→2*3=5\n10.2:4→2*4=8\n11.2:5→2*5=10 √\n12.2:6→2*6=12\n\n13.3:1→3*1=3\n14.3:2→3*2=6\n15.3:3→3*3=9\n16.3:4→3*4=12\n17.3:5→3*5=15 √\n18.3:6→3*6=18\n\n19.4:1→4*1=4\n20.4:2→4*2=8\n21.4:3→4*3=12\n22.4:4→4*4=16\n23.4:5→4*5=20 √\n24.4:6→4*6=24\n\n25.5:1→5*1=5    √\n26.5:2→5*2=10   √ \n27.5:3→5*3=15   √\n28.5:4→5*4=20   √\n29.5:5→5*5=25   √\n30.5:6→5*6=30   √\n\n31.6:1→6*1=6\n32.6:2→6*2=12\n33.6:3→6*3=18\n34.6:4→6*4=24\n35.6:5→6*5=30   √\n36.6:6→6*6=36\n\nProbability = No. of required possibilities/No. of total possible events =11/36\nSo the right answer is D
443783
2,3,1 (nothing goes there) ,6\n\nHope it helps :]
366685
There are an infinite quantity of rational numbers between -1 and 1.\n\nFor example all of these are rational numbers in this range:\n-1, -7/8 -3/4, -5/8, -1/2, -3/8, -1/4, -1/8, 0, 1/8, 1/4, 3/8, 1/2, 5/8, 3/4, 7/8, 1\n\nBasically anything in the form a/b where a and b are integers, and the ratio of a/b is between -1 to 1 will satisfy the equation.\n\nGiven integers a and b, where 1 < a < b -- any of these will be valid rational numbers in the range -1 to 1:\n\na/b, 0, -a/b
387919
1.(4x+1)(16x^2-4x+1)\n\n2.(1-5x)(1+5x+25x^2)\n\n3.(2xy^2+3)(4x^2y^4-6xy^2+9)\n\n4.b^3(a^3-b^3)\nb^3(a-b)(a^2+ab+b^2)\n\n5.(3x-2y)(9x^2+6xy+4y^2)
80588
In the future, us ^ for exponents. It's pretty much standard for typed equations. But I digress....\n\n6. 10[(4 + 5).2. - 12)]\n10[9^2 - 12)]\n10[81 - 12]\n10 * 69\n690\n\n-------------\n\n9. 7.0.\n\nAny number raised to the zero will equal 1.\n\n-------------\n\n27. 3(2a + 4) + 2(4a + 2)\n6a + 12 + 8a + 4\n14a + 16\n\n-------------\n\n43. 32 - (-15) \n\nSubtracting a negative is the same as adding so...\n32 - (-15) = 32 + 15 = 47\n\n-------------\n\nX. Evaluate the expessions. b = 6, c = -3.\n2b - c\n\n2(6) - (-3) = 12 + 3 = 15\n\n-------------\n\nXIV. Sequences and tables. look at the table below and awser the questions.\n_____\nn ! t!\n1 ! 4!\n2 ! 8!\n3 !12!\n4 !16!\n5 !20!\n------\n\n67. Write and equation in the for of t = ____ that describes the table above.\n\nt is always 4 times n, therefore t = 4n\n\n-------------\n\nXIV. Sequences and tables continued. Look at the table below.\n_____\nn ! t!\n1 ! 4!\n2 ! 7!\n3 !10!\n4 !13!\n5 !16!\n-----\n69. Write and equation in the form of t = ____\nthat describes the table above.\n\nThis on is trickier but notice that the value of t increases at 3 times the rate of n. At that point, we know the 'slope' is 3. Then, the 'intersection' would have to be 1 to make the equations true. So....\n\nt = 3n+1
320535
Irrational numbers don't have patterns, either.\n\nYou could take pi or e or sqrt(2) out to a hundered digits and stat test it.\n\nI just looked at sqrt(2), sqrt(3), and e.  I couldn't see any pattern to occurances.\n\nAlso, I can't think of any reason there would be more of some number than another.  For years, sqrt(prime) has been used as a source of random numbers.
244026
You see: \n9\n19\n29\n39\n49\n59\n69\n79\n89\n90\n91\n92\n93\n94\n95\n96\n97\n98\n99\n\n\n\nThat counts 20 9s.\n\nI did not see other answers. When I saw your question, I smiled because I know that you did mislead us as 9, 19... for avoiding the nervous nintees.\n\n\n\nThank you for this nice Question.\n\n\n--- LeeeN
543635
OOOOOOOOOh i LUV LUVLUVLUV challenge 24!!!! ok her are some ideas:\n7,2,2,1=(7-1)(2+2)\n6,8,2,1=(8/4)(6*1)              ***All taken from Challenge 24 cards\n3,3,6,2=(3+3)(6-2)                     (single digit)\n9,2,5,1=(9-1)(5-2)\n~* ah what the heck i dont have time to finish this. I'llget back to you later, soon. and for future reference, DO buy challenge 24 cardsand so you can use them often. the only annoying thing is, it doesnt come w/anser key u have to figure it out yourself:(