1_1.67^0=\n2_(3/2)^-2=\n3_376.5^0=\n4_3ab^0=\n5_3x^-2/4=\n6_(3x)^-1/4=\n7_(3a)^2b^-3/b^-2=
212765
two hints:\n\n1) anything raised to the 0 power gives 1\n\n2) anything raised to a negative power means 1/the same thing raised to the positive opposite power.\n\nEnjoy your homework.
315845
a)  1/3^-3 = 3^3  = 27\n\nb)  3/5^-1 = 3*5 = 15\n\nc)  4a^-2b^-3 = 4/(a^2*b^3)\n\nd)  x^-2y^-3/z^-1 = z/(x^2*y^3)\n\ne)  x^6/x^2 = x^3  (I think this is what you wanted to ask, you left out the carets)\n\nf)  x^4y^2z/x^2y^4z^2 = x^2/(y^2*z)
664019
2.3x + 1.7x = 24\n(2.3 + 1.7)x = 24\n4x = 24\nx = 6\n\nANS : 6
450438
1. 28x + 30\n\n2. 24y + 30\n\n3. -63 - 36x
472958
1) 1/4, 3/8, 2/5\n2) 5/9, 2/3, 7/8\n3) 9/10, 11/12, 15/16\n4) 5/9, 7/12, 2/3\n\n\nExplanation:\n1/4:\n   ____\n4 )1.0\n\n\n\n\n      .2\n   ____\n4 )1.0\n    -  .8\n_______\n        .2\n\n\n\n\n\n\n\n      .25\n   ____\n4 )1.00\n    -  .80\n_______\n        .20\n    -   .20\n_______\n         0\n\n\n\nI doubt the explanation will work.
573188
(1/(z^2 - 3z - 4)) + ((3z)/(z^2 - 6z - 7))\n(1/((z - 4)(z + 1))) + ((3z)/((z - 7)(z + 1)))\n\nMultiply everything by (z - 4)(z + 1)(z - 7)\n\n((z - 7) + (3z(z - 4)))/((z - 4)(z + 1)(z - 7))\n\n(z - 7 + 3z^2 - 12z)/((z - 4)(z + 1)(z - 7))\n\n(3z^2 - 11z - 7)/((z - 4)(z + 1)(z - 7))\n\nANS : a.) (3z^2 - 11z - 7)/((z - 4)(z + 1)(z - 7))
348928
1.132/3=43\nthe nos are 42,43 and 44\n\n2.76/2=38\nthe consecutive odd nos are 37 and 39\n\n3.x+3.04=6.24+1.2x\nadding -1.2x-6.24\n-0.2x-3.2=0\n-0.2x=3.2\ndividing by -0.2\nx=-16
407833
1.6^2/6^1=6^2 X6^-1=6^(2-1)=6^1=6 ans\n2.11^5/11^3=11^5 X11^-3=11^(5-3)=11^2\n4. 200m^200/100m^100=(200/100)(m^200 Xm^-100=2(m^[200-100]=2m^100\n5.18x^20/36x^12=(18/36)(x^20 Xx^-12)=1/2(x^[20-12]=1/2x^8\n\nIf I have to failed to make you understand any step/s of the above process,please donot hesitate to write to me through Yahoo Answers and I promise you,I shall try to explain the things to the best of my ability.Best of luck
541379
1) 2a^3 - 13a^2b + 11ab^2 + 14b^3\n\n2) (2a-4b) (4a^2+8ab+16b^2)\n\n3)  (b-8)(b-1)=0\n      b=8   or    b=1\n\n4) 4m^3 - 26m^2 - 14m=0\n2m(2m^2 - 13m - 7)=0\n2m=0  or  2m^2 - 13m -7=0\nm=0  or    (2m+1)(m-7)=0\n                  m=-0.5   or  m=7\n\n so the final answer is m=0 and m=-0.5 and m=7
564274
[sqrt(2)]^2 = c^2 - b^2\nLet c = 3/2 and b = 1/2, then\n[sqrt(2)]^2 = (3/2)^2 - (1/2)^2\n2 = 9/4 - 1/4\n2 = 8/4\n2 = 2
285162
Rewrite the equation as follow:\n(2x+7){(x-7)+(2x-3)} -(2x-1)(3x+1)=-1\n(2x+7)(3x-10)-(2x-1)(3x+1)=-1\n(6x^2+21x-20x-70)-\n(6x^2-3x+2x-1)=-1 =>\n(6x^2+x-70)-(6x^2-x-1)=-1\n(note: x^2 means x to the power of 2)\nRe-group:\n6x^2-6x^2+x+x-70+1=-1\n              2x-69=-1 \n=> 2x=68 => x=34
232425
2^(1/3)=1.26\nif the next term is\n\n2*(-1/3)=-.667\nx=2^(1/3)-2*(-1/3)=1.92\nand\n2*x^3+6*x=25.86\n\nor if you meant\n\n2^(-1/3)=.7937\nx=2^(1/3)-2^(-1/3)=.466\nand\n2x^3+6x=3
590052
1) when you are multiplying them together, just add the exponents.  m^5\n\n2) x^2 / x^5 is the same as (xx) / (xxxxx), so simplify it by removing 2 x's from each side, and you have 1 / (xxx) which equals 1/x^3\n\n3) 0.00317 = 3.17 x 10^-3  to do a problem like this just count how many places you have to move the decimal to get it with only one number on the left.  If you have to move it to the right, then the answer is 10^ negative how many places you counted.  If you move it to the left, it's 10^ positive.\n\n4)\n2.3(10 ^ -2) times 4.1(10^-3)\n(2.3)(4.1)(10^-2)(10^-3)\n(2.3)(4.1)(10^-5)\n(9.43)(10^-5)\n9.43 x 10^-5\n\n5) hmmm,  it's been a really long time, but i believe the degree of the equation is the highest exponent, so 4th degree?\n\n6) first multiply every number inside the first parenthesis together with the numbers in the second set of parenthesis, then simplify. \n(3y^2 - 7y + 4) (2y^2 + 3y - 2)\n\n(3y^2)(2y^2) + (3y^2)(3y) + (3y^2)(-2) + (-7y)(2y^2) + (-7y)(3y) + (-7y)(-2) +(4)(2y^2) + (4)(3y) + (4)(-2)\n\n6y^4 + 9y^3 - 6y^2 - 14y^3 - 21y^2 + 14y + 8y^2 + 12y - 8\n\n(6y^4) + (9y^3 - 14y^3) - (6y^2 - 21y^2 + 8y^2) + (14y + 12y) - 8\n\n6y^4 - 5y^3 - 19y^2 +26y - 8\n\nuse that same principle to do 7 and 8, they are the same line of thought, just easier.\n\nthat's all i've got, i should be working, not doing algebra.
666491
(7/(3x)) / (x/3)\n(7/(3x)) * (3/x)\n21/(3x^2)\n7/x^2\n\nBut if you meant\n\n((7/3)x)/(x/3)\n((7x)/3)*(3/x)\n(21x)/(3x)\nANS : 7\n\n-------------------------------\n\n2 1/3 - 3/4\n2 1/3 = (7/3)\n\n(7/3) - (3/4)\nMultiply everything by 12\n(28 - 9)/12\n(19/12) or 1 (7/12)
138553
For exemple:\n\n1) 5/4 + 2/6 = (5*6)/ (6*4) + (2*4)/(6*4)\n             = 30/24 + 8/24\n             = 38/24\n\n2) 5/4 * 2/6 = (5*2)/(4*6)\n             = 10/24\n\n3) 5/4 / 2/6 = (5*6)/(4*2)\n             = 30/8\n\n4) 5/4 - 2/6 = (5*6)/ (6*4) - (2*4)/(6*4)\n             = 30/24 - 8/24\n             = 38/24
314325
1. 63.75 or 63 3/4\n2. 63\n3. 24.75 or 24 3/4
401528
1. 2.1432 x 10^6\n2. 1.2375 x 10^5\n3. 3.9672 x 10^9\n4. 4.058 x 10^5\n5. 7.317405 x 10^20\n6. 4.776647501 x 10^-7