preparing for upcoming exams, these samples above from practice will give me some kind of idea,after studying them over & over. rounding 38.90952 to nearest 1000th
199631
Yes, and don't forget, when rounding raise to next highest if following digit is 5 or more...38.90952 = 38.910 if rounded to 1000ths.
401484
Yiu would first decide how many decimal places you are going to consider.  The usual is 3.  Then work it from there...;
630759
11.111111111111111111111111111111111111111\n\n\n5/.45
579175
Ten is a good round number.
674315
depends on what place value you are supposed to be rounding to.
67815
5000                  AHHHHHHHHHHHHHH!\nIt is 4100!\nGreat Question!
612255
1113213211\n\nAfter starting the sequence with 1, each term in the sequence consists of groups of two numbers based on the previous term - the first being the quantity and the second specifying which digit.
111500
Make 2 7/15 an improper fraction, flip it over to its reciprical and mulitply the two.\n\nBoy...I hope I got that.  *bits fingernails*
244627
1.41421356237 further add 30950488016887242097
419835
42*10=420   42*100=4200\nnow u do it
103665
I thought it was 3.142857...Anyway, nice of u to sacrifice ur 5 points to give us 2 points. Three cheers for you. Thanx for the 2 points.
142595
Are you sure you want them *completely* random? Is it acceptable to have, say, 941 + 1 + 1 +... ?\n\nIf so, do something like (in pseudolanguage, my c++ is rusty ;-) :\n\n\nint sum = 1000; //or whatever\nArray allNumbers = EMPTY;\n\nfor (int i = 59; i > 0; i++) {\n  number = Random-between(1, sum - i);\n  push allNumbers, number;\n  sum -= number;\n}\n\n\nSo the first time it gets a result between 1 and 941, say 100.\nNext round, a number between 1 and 842...\nUntil it gets a number between 1 and at-least-1 minus 0.\n\nIf it picked 941 on the first round, say, (sum - i) would be (59 - 58), so a number between 1 and 1 all the way.\n\nThat should do the trick.
439607
36. >\n38. =\n40. >\n42. <\n44. <
398271
40, 15. Every other number sequence, +5, -3. LSAT practice.
219512
Without resorting to a search of the web I have memorized the following digits. (I hope I don't mistype any):\n\n3.1415926535897932384626433832\n795028841971693993751058209749\n445923078164062862089986280348\n253421170679821480865132823066\n470938446095505822317253594081\n284811174502841027019385211055\n5964462294895493038196
459255
If this is for a statistics course, chances are you are allowed to run out 22.8 times.  If you must round, 23 would be more correct, but as answers never come out to integers in statistics, my guess is that you are to put the decimals.
288430
72201,02,03,04,05,06,07,09,10,11,12,14,15,16,17,19,21,22,23,25,27,31,60,95\n\n72213,14,15,16,17,18,19,20,24,90,98,99