(x + 3y)² = 4\n\nThanks^_^
203984
Multiply it out: (x + 3y)^2 = x^2 + 6xy + 9y^2 = 4 implies (x^2)/4 + y^2/(4/9) + 6xy = 1.\nA well aligned ellipse has the equation ax^2 + by^2 = 1, \nequivalent to the matrix equation [x, y][1/a, 0; 0, 1/b][x; y] = 1. If we replace the scaled standard axes by a set of axes rotated by r, we get [x, y][(1/a)cos(r), (1/b)sin(r); -(1/a)sin(r), (1/b)cos(r)][x; y] \n= (cos(r)/a)x^2 + (cos(r)/b)*y^2 + sin(r)(1/a - 1/b)xy = 1. Thus, the graph of your equation is an ellipse rotated by r.
238685
y= -x+4 is x=4 y=3.87
376210
C is correct but not complete... only the 3 is factored out... the real answer would be:\n\n3(x-1)(x+4)
183119
x = -b +(or)- sqrt(b^2 - 4ac)\n    -------------------------\n               2a
532981
x^2+3x-y=c\n2x +3 -y'=0\ny'= 2x +3\n\n(remember y^0=1)!
439489
c)\n\n= x^3 + x^2 + x - x^2 - x -1\n= x^3 -1
58185
y intercept: (0,4)\nx intercept: (3,0)
67168
The answer is:\n2y^3 - y^2\nOR\n(2y-1)*y^2
549339
subtrac 3y and 4 from boside\ny^2-3y-4\nfactor\n(y-4)(y+1)\ny= 4 and -1
527951
y= (x^2 - 1)^2\nx^2-1=+/-√y\nx^2=1+/-√y\nx=+/-√(1+/-√y)
384944
4 (x^2 + 3X -4)\n4(x+4)(X-1)
429437
y=(x^2-3x)^2\ny=x^4-9x^2\nAnd then I'm confused.
409328
y = M(n+1)\n   = ½(n+1)²\n   = ½(n²+2n+1)\n\nI think that's the furthest you can go. \nHope this helps=)\napl
300735
6y + 3 = -4y^2\n4y^2 + 6y + 3 = 0\n\na=4, b=6, c=3\n\ny = -b+-SQRT(b2-4ac) / 2a\ny = -6+-SQRT[36-(4)(4)(3)] / [(2)(4)]\ny = -6+-SQRT[-12] / 8\n\nBut SQRT[-12] is not possible, unless we are looking for imaginary values, then:\n\ny = -6/8 +- SQRT[-12]/8\ny = -3/4 +- [2SQRT3]i/ 8\ny = -3/4 + [(SQRT3)/4]i or -3/4 - [(SQRT3)/4]i
444927
well Honestly dear Megan i don't think its correct , coz equation should have ONE " = " \n\nit must be something like this \n-4r ² ± 21r=r+13\n\nGood Luck
330893
actually, you only found where y=x, but since x and y are squared, x=-y is also valid\n\nsolve\n3 +4/x =y\nx=+-y\n\nx=y\n3y+4-y^2=0\n(y-1)(y-4)=0\ny=1,4\n\nx=-y\n3y-4-y^2=0\nsolve using quadratic formula - will give you two more answers\n(y+)(y-)=0
384935
[(x^3)/(2 - x)]^4/3 \ndy/dx = (4/3)[(x^3)/(2 - x)]^1/3[3x^2(2 - x) + (x^3)]/(2-x)^2\ndy/dx = (4)[(x^3)/(2 - x)]^1/3[6x^2 - 3x^3 + (x^3)]/(3(2-x)^2)\ndy/dx = 8x^3(3 - x)/(3(2-x)^7/3)