Croissants are produced in the desert by workers with a (free) solar oven. Debbie owns a shop where croissants are produced according to Equation 2:\n\n(Equation 2) minutes of labor= [C x C] x 3.5.\n\nWhy does the MC curve have the slope (positive, flat, or negative) it does?
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Assuming that C is the number of croissants produced, \nand w = wage per minute,\n\nTotal Cost is:\nTC =  w x (3.5xCxC) \n\nSo, Marginal Cost (the slope of the Total Cost curve) is:\nMC = w x 2x(3.5xC) = 7w x C\n\nThe MC has a positive slope equal to 7 times the wage per minute. This is because each croissant takes 7 minutes more than the last one to produce, and so costs more in wages...
33582
Well since you have to plot this on a graph this might be hard to explain only using english - but I'll try.\nQ would be 2 places to the right (from (0,0)) and 3 places up on your graph.  R is 1 place to the left and 1 place down.  S lies 4 places to the left and 2 places up.  Once these are graphed you can see that there is no way they can lay on a single line - so no they don't.\nSlope = rise/run.  R is 3 places below S and 3 places to the right so your rise/run = 3/3 and your slope = -1 (it's negative 1 because the line is sloping doen and not up).  If you were doing the slope from R to Q the slope would be positive.\nI hope this helps, good luck.  Hooray for math!
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You cut at 1/4 of the distance from the center to the edge.  If you want it more exact, it's 0.2649 of the radius.  Steve is wrong, size of the cookie doesn't matter.\n\nIf you want the trig: the cut is a chord parallel to the horizontal diameter.  Draw radii to the ends of the chord, and an altitude from the center of the circle to the (center) of the chord.  For convenience let radius r=1.  Length of altitude = d.  Half the length of the chord = w.  And angle between altitude and radius = x (in radians). \n\nNow area of the sector is 2x/2pi*pi*r^2 = (so nice!) just x.  Area of the triangle is 1/2 base * height = d*w.  And we eventually want the value of d, distance from center to the cut.\n\nSo area of the slice = area of sector - area of triangle=\nx-dw=1/3*area of whole circle = 1/3*pi*r^2=pi/3\nSince d=cos(x) and w=sin(x), \nwe need to solve x-cos(x)*sin(x)=pi/3.\nUsing a graphing calculator, we get x=1.302662837 radians, for which cos(x)=d=0.2649320846.
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I just taught this section today to my calc students.  You start by finding the first and second derivative.  I recommend looking in your book for an example.  Your book probably has something like this towards the front of the section.  It would be too long winded to write everything down here.  If you don't have your book on you, the web page below has problems that you can do and then check your answer.\n\nhttp://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/graphingdirectory/Graphing.html
43684
YOur premise for the first set is wrong.\n\nif c + p + s = 100 \nthen 10c + 3p + .5s  cannot = 100, but rather it would be \nXc + Yp + Zs would equal 100 where X is 10, Y is 3 and Z is .5\n\nBUT, according to your work problem, it couldn't be 10c plus anything since cows are $10 and 10 would eat up the whole $100.
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Solution: According to Sunkist's law of conversion - as you reached terminal velocity and the time portal appeared - Chiquita's banana-form entropy would come into play around France. \n\nAnswer: 2
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I used to have a morning croissant breakfast sandwich from Carl's Jr at least 3 mornings a week. Then I looked up the information on it-580 calories and 69% fat. I stopped eating them, changed my diet, started exercising, drink water instead of soda, and have lost 28 lbs! No, no one forces the food down our throats, but they do make it look tasty and convenient. It's not their fault, though. It's our fault for falling for the marketing. It works.
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The starting point of Q is the edge of the disk where the radius is parallel to the x axis.\n\nThe disk spins so that an angle of a radial line to Q opens downward at a rate of 6 pi/sec\nLet's call the angle a\n\nThe x value of Q will be located at\nx= 3*cos(a)\nand the y value of Q will be located at\ny=2-3*sin(a)\nIt's translated up by 2 and set negative since the motion is clockwise.\n\nNow, a = 6*pi*t\nso x=3*cos(6*pi*t)\nand y=2-3*sin(6*pi8*t)\n\na       1.884        \nt  0.1\nx  -0.924324094                  \ny  -0.854054129\n\n\n\nj
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That's a tough 8th grade question; I've seen similar ones in algebra 2.  You have to figure the amount of the job that gets done in one hour. If x is the total time for the faster machine, 2x is the total time for the slower machine.  Together it takes 3 hours, so together they can do 1/3 of the job in one hour.  The slow machine can do 1/x of the job in an hour; the faster, 1/(2x).  This gives the equation:\n\n1/x + 1/(2x) = 1/3\n\nmultiply both sides of this equation by the LCD (6x) as if it were a giant distributive property example and get:\n\n6 + 3 = 2x       (the denominators all cancel out)\n\nso 9 = 2x (the slower machine takes 9 hrs)\n4.5 = x (the faster one takes 4 1/2 hours)
222717
I think that what you really want here is the tangent ratio. You know the slope of the line, right (hint, it is right there in the equation)? You know that the tangent ratio is a over b (where a and b are the non-hypotenuse sides of the triangle), right? You should be able to use that to figure out the tangent of the angle made by the line. Now all you have to do is figure out the angle that has that number as a tangent. That would be the "tan -1" (inverse tangent) function on your calculator.\n\nIf you are working from trig tables rather than a calculator, find the number in the second column of the tangent table that is closest to your tangent number then look in the first column for the angle.\n\nIf you are required to use sin and cosine remember your Pythagorean theorem and use it to find the hypotenuse.\n\nASIDE TO Drakestone: Your solution only finds the sine of the angle, not the angle itself. You need to apply "sin -1" to your answer to get the final answer.\n\n\nASIDE TO eternal...: You are wrong too. graph y=5x+3 and you will see that it is way too steep to be an 11 degree angle. You mixed up your opposite and adjacent values in calculating your tangent.
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There's a pretty good online grapher at http://id.mind.net/~zona/ezGraph/ezGraph.html that you can use.  It works basically like a graphing calculator.\n\nIt appears this function should be an upside-down sign curve with an amplitude of 10 and a vertical shift of 9, which means the center of the graph will be at 9, it will go up to 19 and down to -1.  It's not 100% clear what you mean by what you have written after sin.  If you mean the sine of 2pi/15 times x (since the minus zero is irrelevent), you would have a period of 15, so you'd complete 1 complete cycle at 15 radians; the halfway point would be 7.5 radians.
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let the amount of pizzas equal x\nron makes x/30 pizzas per minute and jess makes x/40 pizzas per minute \ntogether they make:    x/40+x/30 pizzas per minute\n                                   =7x/120 pizzas per minute\ntherefore to make x pizzas they will take 17.14 (=120/7) minutes\nThey make 7 times the amount needed in 120 minutes therefore we must divide the 120 by 7.
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y' = [(x-1) - x] / (x-1)^2 = -1/(x-1)^2, so no critical points.  y' < 0 for all x where y is defined, so it's always decreasing.\n\ny'' = 2/(x-1)^3, which is positive when x>1, and negative for x<1.  Therefore the curve is concave up for x>1, and concave down when x<1.\n\nThere is a vertical asymptote at x=1, and lim x->inf x/(x-1) = \nlim x->inf 1/(1-1/x) = 1 (same for x -> -inf) so there is a horizontal asymptote at y=1.
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sidharth has solved the problem correctly and given you the two values for x that satisfy the conditions of the problem.\n\nHowever, he didn't specify the POINTS on the curve.\nThey are (0,0) and (-2,-2).
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Thw formular to use here is Q = mcT where Q = quantity of heat, m = mass, c = specific heat capacity, and T is the change in the temperature, thus here Q = 2.0g*(30-25)*0.90 = 9J. Notice that I sed Joules as the unit.\n\n2.For this one, a law which i cant remember the name right now is nedeed. Here we have C(s)+O2(g)=CO2 Enthalphy -390KJ\nand also Mn(s)+O2(g)=MnO2(s) Enthalphy = -520KJ\nFor this law to be appplied, we have to write the second equation the other way to become MnO2= Mn+O2 Enthalphy = 520KJ. Notice that i changed the sign when i reversed the equation. Then O2 could be canceled out on the left side of the first equation and on the right side of the second equation. This was we are adding. Finally adding, we get MnO2(s)+C(s) = Mn + CO2 Enthalphy = -390KJ+520KJ = 130KJ.\nand thats the correct answer
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Q=100,000 – 1.25P\n\nPQ = P(100,000 – 1.25P)\n\n= 100,000P - 1.25 P^2\n\nVertex of curve occurs at derivative = 0 or when\n\n2.5P = 100,000 or P = $40,000\n\nThis maximizes revenue at $2,000,000,000
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Actually you should right the reaction of salad and croutons. You need to balance it too. It should look like this:\n\n38 Lettuce (s) + 16 Tomato (s) + 7 Carrots (s) + Dressing (l) + X Croutons (s) => Salad (solidish-liquidish) \n\nNow you need to consider the moles of everything and solve for X and you are done...