(x^2-3x-18) / (x^2-4x-32) divided by (x^2-2x-24) / (x^2-x-20)\ncan u solve?
217152
Factor each one.\n(x^2-3x-18) / (x^2-4x-32) divided by (x^2-2x-24) / (x^2-x-20)\n= (x^2-3x-18) / (x^2-4x-32) times (x^2-x-20)/(x^2-2x-24)\n= [(x-6)(x+3)]/[(x-8)(x+4)] times [(x-5)(x+4)/(x-6)(x+4)]\n= [(x-6)(x+3)(x-5)(x+4)] / [(x-8)(x+4)(x-6)(x+4)]\nYou can now cancel anything on top with anything on bottom\nx-6 and x+4 cancels\n= [(x+3)(x-5)]/[(x-8)(x+4)]
135967
*(2x/(x^2-4)) + (5/2-x) - (1/2+x)\n*(2x/(x^2-4)) + (5/2-x)((2+x)/(2+x)) - (1/2+x)((2-x)/(2-x))\n*(2x/(x^2-4)) + (10+5x)/(4-x^2) - (2-x)/(4-x^2)\n*(2x/(x^2-4)) + (8+6x)/(4-x^2)\n\nyou should be able to get it from there
448429
Ok, first you must get the -8 and the x/-2 out of parentheses, so u just multiply them both by one. So then is -8 * x / -2. First, you do -8 * x, which is -8x. The problem then becomes -8x / 2. In this step, just don't mind the negative or the x and just put them back in at the end. So you're really just doing 8 / 2, which is 4. You must put the - and the x back in, so the answer is -4x. Ta Da!
183984
(x/2)-4=8\n(x/2)=12\nx=24
375185
You have \nx^3 = x^2\nSubtract x^2 from each side\nx^3 - x^2 = 0\nFactor out x^2\nx^2 (x-1) = 0\nx^2 = 0 or x-1 = 0\nx = 0 or x = 1\n\nYou do not want to divide both sides by x^2 because then you will lose a solution.  Suppose I tried solving it this way:\nx^3 = x^2\nDivide both sides by x^2\nx^3/x^2 = x^2/x^2\nx = 1\nI only have one solution if I solve it this way.  The solution x=0 was lost when I divided by x^2\n\nNote that x^2 divided by x^3 is 1/x
466854
Just plug 0 in the function whenever you see y.\n\n4x + 3(0) + 24 = 0\n4x + 0 + 24 = 0  \n\nThen solve for x.\n\n4x = -24\nx = -6
364400
x = (-b +/- sqrt(b^2 - 4ac))/2a\n\nwhere a= 1, b= -6 , c=8\n\nx1 = (6 + sqrt(36 - 32))/2 = 4\nx2 = (6 - sqrt4)/2 = 2
451218
-x + 2y = 18\n x + 8y = -38\n\nadd up these two lines\n\n0x+ 10y = -20\ny= -20/10 = -2\n\nx + 8(-2) = -38\nx - 16 = -38\n\n\nx=-22\ny=-2
409893
(6x^2)/4x^2y-12xy(x^2+x-12)/3x^2+12x\n3/(2y)-4y/x(x^2+x-12)+12x\n=(3/2y)-(4x^2y-4xy+48y)/x+12x\n=[3x-2y(4x^2y-4xy+48y)+24x^2y]\n/2xy\n=[3x-8x^2y^2+8xy^2-96y^2\n+24x^2y]/2xy
498452
a.x=[-8+/-rt(64-24)]/2\n\nb.x=[-5+/-rt(25-56)]/4\n\nc.x=[-7+/-rt(49-64)]/4\n\nd.x=[-5+/-rt(25-72)]/4
514239
(-0.242+2.18-1.94)*10^-18\n=(-0.002)*10^-18
457242
(3x - a)(x - 2)(x - 7) = \n(3x - a)(x^2 - 7x - 2x + 14) = \n(3x - a)(x^2 - 9x + 14) = \n3x^3 - 27x^2 + 42x - ax^2 + 18ax - 14a\n3x^3 + (-27 - a)x^2 + (42 + 18a)x - 14a\n\n3x^3 - 32x^2 + 81\n\nso\n\n(-27 - a)x^2 + (42 + 18a)x - 14a = -32x^2 + 81\n(-27 + 32 - a)x^2 + (42 + 18a)x + (-14a - 81) = 0\n(5 - a)x^2 + (42 + 18a)x - (14a + 81) = 0\n(-a + 5)x^2 + (18a + 42)x - (14a + 81) = 0\n-(a - 5)x^2 + (18a + 42)x - (14a + 81) = 0\n\nx = (-b ± sqrt(b^2 - 4ac))/(2a)\n\nx = (-(18a + 42) ± sqrt((18a + 42)^2 - 4(-(a - 5)(-(14a + 81)))/(2(-(a - 5))\n\nx = (-(18a + 42) ± sqrt(((18a + 42)(18a + 42)) - 4(a - 5)(14a + 81)))/(-2(a - 5))\n\nx = (-(18a + 42) ± sqrt((324a^2 + 756a + 756a + 1764) - 4(14a^2 + 81a - 70a - 405))) / (-2(a - 5))\n\nx = (-(18a + 42) ± sqrt(324a^2 + 1512a + 1764 - 4(14a^2 + 9a - 405))) / (-2(a - 5))\n\nx = (-(18a + 42) ± sqrt(324a^2 + 1512a + 1764 - 56a^2 - 36a + 1620))) / (-2(a - 5))\n\nx = (-(18a + 42) ± sqrt(268a^2 + 1476a + 3384)) / (-2(a - 5))\n\nx = (-6(3a + 14) ± sqrt(4(67a^2 + 369a + 846)))/(-2(a - 5))\n\nx = (-6(3a + 14) ± 2sqrt(67a^2 + 369a + 846)) / (-2(a - 5))\n\nx = (3(3a + 14) ± sqrt(67a^2 + 369a + 846))/(a - 5)\n\nUnless you mistyped something, 3x^3 - 32x^2 + 81 does not factor into (3x - a)(x - 2)(x - 7)\n\n--------------------------------------------------------------------------------\n\nx^3 - x^2 + 16x - 16\n(x^3 - x^2) + (16x - 16)\nx^2(x - 1) + 16(x - 1)\n(x^2 + 16)(x - 1)\n\nif you were to take this further, then\n\n(x - 4i)(x + 4i)(x - 1)
441944
If you mean:\n(x+8)/(x-3) + (x-14)/(x-3), then \n(x+8+x-14)/(x-3)\n(2x-6)/(x-3)\n2(x-3)/(x-3)= 2
514107
-4(x+3)>=20    &     x-5< -2\n-4x-12  >= 20    &     x < 5-2\n-4x  >=  20+12   &    x < 3\n-4x >=  32      &    x < 3\nx >= -8   &  x< 3\n-8  <=  x  <  3\n(x lies between -8 and 3)
435671
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
363551
a.xa+xb\nb.21x^3+24x^2y\nc.3x(8x+5)+2(8x+5)\n=24x^2+15x+16x+10\n=24x^2+31x+10\nd.4x(2x+1)-6(2x+1)\n=8x^2+4x-12x-6\n=8x^2-8x-6\ne.8x(5x^2+7x+3)+2(5x^2+7x+3)\n=40x^3+56x^2+24x+10x^2+14x+6\n=40x^3+66x^2+38x+6\nf.x^2-1\ng.x(x^2+2x+4)-2(x^2+2x+4)\n=x^3+2x^2+4x-2x^2-4x-8\n=x^3-8
433224
first multiple everythingby x, then simplify and solve:\n\n1/x-2 = 3/x+3 =>\n\nx/x - 2x = 3x/x +3x =>\n\n1 - 2x = 3 + 3x =>\n\n-2  = x