Please give me solution.
208375
Since f(x) is a polynomial of degree two in x,\nLet f(x) = ax^2 + bx + c, where a,b,c are constants.\n\nLet's find f(x) first.\n\nf(0) = 1 implies, c = 1.\n\nf(1) = 3 implies, a + b + c = 3\nor  a + b = 2 , or b = 2 - a  ...(1)\n\nf(-1) = 5 implies, a - b + c = 5\nor a - b = 4 ...(2)\n\nSubstituiting (1) into (2), we get,\n\na - [ 2 - a  ] = 4\n2a = 6 or a = 3.\nThus, b = 2 - a = 2 - 3 = -1.\n\nHence, f(x) = 3x^2 - x + 1\n\nNote that by long division or by the identity below,\n\n3x^2 - x + 1 = 3(x + 1)^2 - 7x - 2\n             \nWe get,\n\n[ 3x^2 - x + 1 ] /[1 + x]^2 = 3 - [7x + 2]/ [1 + x]^2   \n\nAnd that together with below,\n\n[7x + 2]/ [1 + x]^2  = 7 /(x + 1) - 5 /(x+1)^2\n\nGives,\n\n[ 3x^2 - x + 1 ] /[1 + x]^2 = 3 - 7 /(x + 1) + 5 /(x+1)^2\n  \nNow, we have an "integratable form".\n\n∫ [f(x) / (1 + x)^2] dx\n\n= ∫ [3x^2 - x + 1] / (1 + x)^2] dx\n\n= ∫ [ 3 - 7 /(x + 1) + 5 /(x+1)^2 ] dx\n \n= 3x - 7 log(x + 1) - (5/[x + 1]) + C\n\nwhere C is any arbitary constant.\n\nNote: Sometimes log(x + 1) can also be written as ln (x + 1)\n\nRemark. It is generally accepted that log and ln are both in base "e", the Euler number. If its in a different base, then usually its said or stated. For example logarithm of x in base 2 can be written as log_2(x).\nJust symbols :)\n\nRegards
246651
Fill a long tube with solids and try to blow air through it.\nPut a flabby piece of rubber at the end.\nYou will get all your answers then.
304926
I've been working on this for a little while now....but you got me scratching my head.  \nso I think the correct answer is  "No, I cannot."
172172
No home works here Please!\nYou should ask conceptual problems
557935
Substitute or plug in the value for x an solve the problem using PEMDAS\n\nParentheses\nExponents\nMultiplication&\nDivision\nAddition&\nSubtraction
551815
Sorry but I dont understand your question.
3353
Let's resolve this overdue question by bringing it to a vote.
287427
Hi, I think this thread will help. See link..
509488
her's the solution in this link
171679
try checking out the links below... you may find the answer to your problem there
436500
Please explain yourself so we can give an answer.
90774
go to parlour\ndont squeeze it urself\ntake the help of proffesional
427991
Sorry, but I don't think there is a way. You can mail this question to danuitti(who has 2180 best answers and appears at the top). He is a genius and he will most certainly find a solution. Good Luck!
119856
cmon dont do this again, give the other equation
459800
Hopefully these links should provide you with possible solutions, have a read of the last two first.
20386
I had a similar problem not long ago. How I solved it was by following the directions at [1]. Hope this helps!
299115
check brilliant tutorials homepage...they have posted the solutions...by the way was there a set A  as well?? anyways good luck!