1. When electric current is flowing in a circuit, if the voltage applied to the circuit is increased, \n \n   A. the resistance will increase. \n    B. the current will increase. \n    C. the resistance will decrease. \n    D. the current will decrease. \n        \n     \n 2. Which of the following information sources will not be directly affected by the Telecommunications Act of 1996? \n \n   A. Telephone services \n    B. The Internet \n    C. Newspaper publishing \n    D. Cable television \n        \n     \n 3. Porcelain, paper, glass, and rubber are all examples of electrical \n \n   A. conductors. \n    B. batteries. \n    C. insulators. \n    D. grounds. \n        \n     \n 4. A testing instrument that an electronics technician will connect to selected points inside a piece of electronic equipment and measure electrical values such as ohms, volts, and amperes is called \n \n   A. a signal generator. \n    B. a power supply. \n    C. an oscilloscope. \n    D. a multimeter.
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1 - b\n2 - c\n3 - c\n4 - d
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DC means that you have a constant voltage.  A battery is a great example of DC.  I used to like to think of electricity as water- voltage is how high up the water tank is (the higher up it is, the harder it pushes the water down), resistance is how thick the downpipe is, and current is the volume of water that flows down.  All three are connected, eg a narrower pipe gives less current \n\nAC is as if your source pushes, then pulls, then pushes, etc, the electricity.  This is what you get in your power socket.  It looks a bit like a kid jumping up and down on a trampoline... he pushes as he hits the trampoline, and pulls as he flies up.  To use our water example: imagine a pump that pushes the water, then sucks it back, then pushes...\n\nNo idea how this relates to Venn diagrams, sorry
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If you could pulse the electricity in the wire, it may change the velocity of the wire.  Look up something called Magneto-hydrodynamics
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4. The current does not change.  I=E/R so multiplying the numerator and denominator by 0.50 results in the same answer, does it not?
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http://science.howstuffworks.com/electricity.htm
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Very simple circuit, the two power supplies are used to maintain an electric equilibrium.\nThe potentiometer is used to adjust the sensibility.\nThe transistor amplifies the signal when the person lies, he or she reduces her or his resistance, and the transistor amplifies the signal, the meter instrument shows the result.
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A resistor reduced the voltage in an electrical curcuit at the same time as is applied some load it increases the amps.\nThe formualr volt = amp x ohms can be used to calculate the required resistance.\nA resistor had a measurement unit of ohms.\nVolts = I x R\nResistance = V/I\nI(Amps) = V/R\n\nSo if you had a simple circuit with a battery and a lamp, if you wanted to make the lamp dull you would put a resistor in the curcuit you then could change the value of the resistor to make the lamp brighter or duller.
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if you have a series circuit with 2 resistors, then the current through the resistors will be the same as the total current. if you have a parallel circuit, then the current through the resistors will be lesser than the total current, but may or may not be higher than the current in the series circuit. follow the definition of electricity, and figure it out.
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For academic related materials Wikepedia is the best in the business Go to http://en.wikepdia.org \nFor your quetion answer is already there on Wiki\nhttp://en.wikipedia.org/wiki/Electrical_insulators
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1. volts\n2. (b) negatively charged.\n3.  short.  Could also be "conductor," but the lack of control seems to indicate an unwanted short.\n4.  watt-hours.\n5.  \n6.  (a) The formula is P=V*V/R.  Where V is the voltage and R is the resistance.  So P=45*45/15=135 watts.  Actually the object is consumming the power, not producing it.\n    (b)  135*10 = 1350 watt-hours, or 1.35 kw-hr.\n    (c) 0.08*1.35 = $1.08\n7.  (a)  V=IR, so if the voltage is increased while the resistance is kept constant, then the current will also increase. (I=V/R)\n    (b)  If the resistance is increased and the voltage is kept constant, then the current has to decrease. (I=V/R)
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If you change voltage say from 100 Volts to 200 Volts (perhaps by changing a switch position), the nearly instantaneous change will be a step change (like the steps on a stairs).  If you change the voltage from 100 to 200 Volts uniformly over a period of time (perhaps 10 seconds) for example by rotating a rheostat, the voltage will increase more like the ramp provided for wheelchairs than steps and will be a ramp change.  The terms are often used to describe the graphs or stripchart recorded traces of electrical signals relative to time.\n\nIn electric circuits, selecting various resistors with a switch may produce step changes and charging or discharging capacitors may produce ramp changes.
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Three  terms you need to know are:\n\nVoltage- This is the "potential" to make current flow through \n                a wire.  (measured in volts)\nCurrent- This is the actual electrons or "electricity"  which \n               "flows" through the wire. (measured in amperes or amps)\nResistance- This is the quality of a substance which tends to \n                      allow or inhibit the flow of electricity.\n\nOne more term is power. This is measured in Watts and is \n given as 1 Watt=(1 volt)(1 amp)\n\nHere's how it works.  You put a voltage across a wire.\nYou decide the voltage.  It does not change.  The wire and bulb has "resistance" and only lets a certain amount or current flow.  The current flows through the bulb and lights the bulb.\n So both 100 watt bulbs and 40 watt bulbs have the same \n120v "voltage".  The difference  is that less current flows through the 40 watt bulb, so it is dimmer.\nRemember that power or "Watts" is current  times voltage.\nso lower wattage means lower current.\nThe question should be how much current does each bulb use.\nThe answer is: 100 watt-5/6 amp\n60 watt- 1/2 amp\n40 watt- 1/3 amp
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The CT will only work on an AC circuit so I don't see where it would make any difference.  The only thing that would is to have another phase too close and the magnetic fields might cancel each other. Since the current being measured is AC the output from the CT will also be AC and shouldn't matter on the leads.
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Hmmm... good question... exactly what are you trying to do?\n\nMaximum current would depend on the gauge, type, and quality of wire used to make the cable.  Not all cables are made the same... some are higher quality and provide better transmission distances while others are generic, cheap, and won't handle the same load.\n\nIf you're an electronics person... it's kinda like comparing copper to aluminum... so the answer would be... it really depends on your cable...\n\nLater!
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It appears you are speaking of apparent power. \nTransformers are rated in VA (volt X amps) called apparent power. \nIn a DC circuit power is determined by multiplying voltage X current (E X I = P). In an AC circuit power is determined the same way only when voltage and current are in phase with each other which means they are rising and falling falling at the same time. \nWhen they rise and fall at slightlly different times the time difference is known as a phase angle and the cosine of this angle is also applied to the E X I =P formula making it E X I X the cosine of the angle. This formula is used to determines the TRUE POWER of the AC circuit or any transformer circuit. \nTo sum it up, the APPAREMT POWER is always volts X amps. The TRUE POWER is always VOLTS X AMPS X the cosine of the angle. \nThe angle becomes larger when inductors, motors and capacitance are part of the load circuit.
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Think of the analogy between the flow of electricity and water where voltage is pressure and current is water flow.  It take voltage (pressure) to cause current (water flow).  Therefore, current (water flow) will occur in the direction under greatest voltage differential (pressure).  Because you may be working with more than one voltage source (two transformers or ttwo battery cells?) one of the sources may be adversely affected.  Are you working with AC or DC?  You may need to avoid connecting a circuit for example that would be like charging a car battery with the leads reversed.  Good luck.
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http://en.wikipedia.org/wiki/National_Information_Infrastructure\nhttp://en.wikipedia.org/wiki/Section_230_of_the_Communications_Decency_Act