options\n1)20*25\n2)50*21\n3)20*50
199816
The dimensions of an Olympic pool are required to be 25 metres by 50 metres.\n\nAccording to the rules of FINA.org, an Olympic pool should be 50 m long by 8 times 2.5 meter lanes with 2.5m outside lanes 1 and 8 (so 10*2.5 = 25m) - minimum depth 2m.
620211
Or is it this:\n300+20+4\n400+60+7\n100+10+1\n800+90\n60+8\n1000+600+50+4
439972
a) 4 is in the tens place, so it is worth 4 * 10 = 40\nb) 6 is in the ones place, so it is worth 6 * 1 = 6\nc) 3 is in the thousands place, so it is worth 3 * 1000 = 3000\nd) first 2 is in the hundreds place, so it is worth 2 * 100 = 200\ne) 7 is in the hundreds place, so it is worth 7 * 100 = 700\n\nOr you can just say the numbers and see what you say when you are on the underlined number...\n\n42 = "forty two" so 4 is "forty"\n176 = "one hundred seventy six" so 6 is "six"\n3049 = "three thousand forty nine" so 3 is "three thousand"\n1223 = "one thousand two hundred twenty three" so first 2 is "two hundred"\n10731 = "ten thousand seven hundred thirty one" so 7 is "seven hundred"
5259
$1.20, $1.25, $1.50, and $3.16.
187382
I know it has already been answered but I"ll take a chance with something different. Ok 3 to the third power plus two would be 3 to the fifth power which is 243.\n :)
495526
35-55\n\n13-30\n\n12-28\n\n25-22\n\n32-5
544230
1. 1s2 2s2 2p6 3s1\n2. 1s2 2s2 2p6 \n3. 1s2 2s2 2p4\n4. 1s2 2s2 2p6\n5. 1s2 2s2 2p6 3s2 3p6 3d7 4s2
499024
1. (3/51 * 2/50 * 1/49) * (3/47 * 2/46) * 7!\n2. (3/51 * 2/50) * (3/48) * (3/46) * 45/47 * 7!\n3. (3/51 * 2/50 * 1/49) * (3/47) * 44/46 * 7!\n4. (3/51 * 2/50) * (3/48 * 2/47) * 45/46 * 7!\n5. (3/51) * (48/50 * 3/49) * (44/48 * 3/47) * 40/46 * 7!\n\nNote: As I read it, #2-#4 exclude the possibility of #1.  If you think #1 is a special case of the others, then add the value of #1 to the other three.  Likewise, as I read it, #5 excludes #2.
581645
1. 65\n2. 16\n3. 243\n4. 12\n5. 3\n6. 24\n7. 108\n8. 31\n9. 14\n10. $5\n11. 5\n12. 6\n\nI better get best answer for this
629207
a) 25pi\nb) 50pi\nc) 100pi
373868
1, 2, 4, 8, 16, or 32
550944
1.) if I am understanding this correctly that is an easy one: just start with 2 and go up by 10\n\n2, 12, 22, 32, 42...\n\n2.) the pattern for this is adding 8 more to the previous add \n\n15-3 = 12\n35-15=20\n63-35=28\n\nsee how its adding 8\n\nso the 17th number would be: 1155 and the 37th number would be: 5607
27051
1) yes, this is correct as written.  Not sure what else you need? \n2) 10/14?\n3) 2 (1 is not a factor)\n4) -6(x+1)\n5) 5 1/4 or 21/4 (same thing)\n6) 1 4/9
222447
1) Assuming an aritmetic sequence\n\nbn = b1 + (n-1)d \nletting b3=a1 = 20, then b7=a5 = 32, and b25 = b23\na5 = a1 + (5-1)d\n32 = 20 + (5-1)d\n32 = 20 + 4d\n12 = 4d\n3 = d\n\nb25 = a23 = 20 + (23-1)*3\nb25 = 20 + 22*3\nb25 = 20 + 66\nb25 = 86\n=====================================================\n2)\na75 = a1 + (75-1)d; d=-3\n\na75 = 5 + (75-1)*-3\na75 = 5 + 74*-3\na75 = 5 + -222\na75 = -217\n\nSn = n/2(a1+an)\nS75 = 75/2(5 + -217)\nS75 = 75/2(-212)\nS75 = -7950\n===================================================\n3) ????\n\na5 = 5*5 - 4 = 21\na15 = 5*15 - 4 = 71\na25 = 5*25 - 4 = 121\n\nOR MAYBE\n\na1 = 5*1 - 4\na1 = 5 - 4\na1 = 1\na30 = 5*30 - 4\na30 = 150 - 4\na30 = 146\n\nSn = n/2(a1+an)\nS30 = 30/2(1 + 146)\nS30 = 30/2(147)\nS30 = 2205\n================================================\n4)\n\nrth term is nCr-1m^n-(r-1)k^r-1\n\n5th term =\n4C4m^4-(5-1)k^5-1\n4C4 = 1\n\n5th term = k^4
425327
1     $58.50\n\n2     $23.20\n\n3     $38.25\n\n4     $75.60
345604
1) 9 * (t + 1)\n2) 8 * (v + 7)\n3) 25 * (5 - h)
234640
1: x<12\n2: x>257\n3: x>42\n4: x>84\n5: x>25\n6: x>179\n7: x<8\n8: x>577\n9: x<113