What is an equation (Standard form) for a line if the y intercept is 4 and the x intercept is 2?\n\nWould it be A2 + B4 = C ?
206139
y = mx + b\n0 = 2m + 4\n2m = -4\nm = (-4/2)\nm = -2\n\ny = -2x + 4\n\nStandard form of this would be \n\n2x + y = 4
402488
Get the equations in slope-intercept form (y=mx+b)\n\ny=1/2+1\ny=-2x-3/4\n\ny=-2/3+4\ny=-2/3x+8\n\nNow compare the slopes(m) of each equation\n\nif the slopes of the equations equal -1 (they are oppostite recipricals (example... 2 and -1/2)when multiplied they are perpendicular\n\nif the slopes are the same they are perpendicular \n\nif they are neither they are just intersecting lines
661706
One way to write the equation of a line is\ny - y1 = m(x - x1)\nwhere m is the slope and (x1, y1) is a point on the line.\n\nGiven your information,\ny - 4 = -2(x - 1)\nThat is the point-slope form of the line.  This can be changed to slope-intercept form:\ny - 4 = -2x + 2\ny = 2x + 6
439810
First, put both equations into slope-intercept form (y = mx + b).\n\nL1:\nx - 4y = 12\nx - 12 = 4y\ny = (1/4)x - 3\n\nL2:\n4x + y = 4\ny = -4x + 4\n\nWhen two lines are parallel, they will have the same slope. When two lines are perpendicular, the slopes will be the opposite reciprocals of each other.\n\n-4 and 1/4 are the opposite reciprocals of each other. Therefore, the two lines are perpendicular.
323972
Equation of a straight line: y = mx + b\nSubstitute m=-1 and x=2, y=1 into the equation,\ny = mx + b\n1 = (-1)(2) + b\n1 = -2 + b\n1 + 2 = b\nb = 3\n\nTherefore, equation of the straight line is y = -x + 3\n\nRearranging it into the format: mx + y = b,\nWe have, x + y = 3 (Q.E.D)
169304
The equation of a straight line (linear) is y =mx +c If you consider two variables (positions on a graph etc) y = m times X + a constant. On a graph m is the gradient measured as change in y over change in x and c is the constant (intercept) i.e the value of y when x =0\n\nso you are looking to produce an equation y = mx+c for your problem\n\nyou know that 200 items cost 22000-10000 so your m=12000/200\n\n=60. so if y=mx +c where y is 10000 and m is 60 and x is 100\n\nc= y/mx, c= 4000\n\nno use y =mx +c to check for x =300\n\n300*60 +4000 =2200\n\ny = 60x +4000
532207
Your slope is right, but more simply, -4/2 = -2.\n\nThen if y = -2x + b, 3 = -2(-1) + b, so b (the y intercept) must be +1.
629380
a straight line with x intercept 1 and y  intercept 4
194337
If the equation is y = 4x^2 + 4x - 5, then:\n\nRewrite the equation and complete the sqaure on the right side of the equation...\n\ny = 4(x^2 + x) - 5\n\ny = 4(x^2 + x + 1/4) - 5 -4(1/4)\n\ny = 4(x + 1/2)^2 - 5 - 1\n\ny = 4(x + 1/2)^2 - 6\n\ny - (-6) = 4(x + 1/2)^2\n\ny - (-6) = 4[x - (-1/2)]^2\n\nVertex for standard equation is in the form:\n\ny - k = +/- a(x - h)^2\nwhere:\nh = x-coordinate of the vertex.\nk = y-coordinate of the vertex.\n+ a = the parabola opens upward.\n- a = the parabola opens downward\na = the parabola will have a wide opening if a > 1.\na = the parabola will have a narrow opening if a < 1.\n\nTherefore vertex is at (-1/2, -6) and a wider opening which is upward.
376413
Remember the fomula...\n\ny = mx + b\n\nm = Slope\n\nb = Y-intercept\n\nx and y = points\n\nSo plug everything in...\n\n1 = 4(2) + b\nMulitply\n1 = 8 + b\nSubtract 8 on each side\n-7 = b\n\ny = 4x - 7
11398
say the line is y= ax + b\nsubstitute the (x,y)= (3,-11), (-1,9)\n\n-11= 3a+b......(1)\n9= -a+b.......(2)\nsubtract (2) from (1)\n\n-11-9= (3a+b)-(-a+b)\n-20= 4a\na=-5\nsubstitute this back into (2)\n9=5+b\nb=4\n\nie the original equation is y=-5x+4\n\nThe answer is D. but u left "x" out
662804
If you are given the slope(m) and a point on the line(x1, y1) you can write the equation of the line.\n\nYou take the y-intercept equation\ny =m*x + b and substitute x1 and y1 for x and y and get\ny1 = m*x1 + b    \nnow solve for b\nb = (y1-m*x1)\nsubstite b = (y1-m*x1) into the y-intercept equation\ny =m*x +(y1-m*x1)\nsubtract y1 from both sides of the equation\ny -y1 = m*x -m*x1\nbecomes the point-slope formula\ny -y1 =m*(x-x1)
262197
Remember the y=mx+b form.\n\ncalculate the slope: m= y(1)-y(2)\n                        ---------\n                        x(1)-x(2)\n\nthen calculate the y-intercept (user either [x(1), y(1)] or [x(2), y(2)]\n\n              b = y - m(x)\n\nplug m and b into the y=mx+b form.
263378
Given line is y+5x=-1 or y=-5x-1 [as it must pass through (0,-1)].\nAny line parallel to the given one: y=-5x+c. As y-intercept i.e. 'c' is same so c = -1 and the line is none other than the given line.\nEquation to any line perpendicular to the given one is: y=(1/5)*x+k. As y- intercept is same as the given line so, k=-1. So this line is x-5y=5.
470635
in an equation y = mx + b, m is always the slope and by is always the y-intercept\n\nx + 2y = 3\n2y = 3 - x\ny = (-1/2)x + (3/2)\nthe slope is -1/2 and the y-intercept is 3/2\n\n1/2x - 9 = 0\nwhere's the y?  this isnt an equation\n\ny = 3x - 2\nthe slope is 3 and the y-intercept is -2\n\ny + 4x = 8\ny = -4x + 8\nthe slope is -4 and the y-intercept is 8
380920
Well, let's check if y=4.\nJust replace y with 4\n4(4) + 2(4) = 24\n16 + 8 = 24\n24 = 24 \nThis is equation is true, so you are correct.
71437
The equation of a line is y=mx+c\nHere when x = 6, m = 4/3, y = -2\nTherefore c = y-mx = -2 - (4/3)*6 = -10\n\nHence y = (4/3)x-10\n\nHope this helps!