after a bettery is completely used we generally remove it, but when we again connect it to circuit it shows some transit current for some time. why is it so ?
209840
because the residual current collected over a period of time keep the exhausted battery work for a while.
302167
First there is a correction to your statement.\n\nResistance increases with the length of the wire or conductor; but it decreases with the area of cross section of the wire or conductor. \n\nIt will give a wrong meaning if you use the word breadth instead of area of cross section.\n\nConsider a wire of length L and area of cross section A connected in a circuit. Let n be number of charges flowing through it under a given condition.\n\nNow connect a similar wire side be side with the previous one. (This is called parallel connection)\n\nAs before in the first wire there will be n number of charges flowing through it.\n\nWhat about the second wire. Since the condition is the same as the first one, in the second wire also there will be n number of charges flowing through it. \n\nThus if the area of cross section is doubled current is increased or resistance is decreased.\n\nIn a high way there is a bridge which is very narrow; the flow of vehicles will be less.\nIf the bridge is broadened the flow will increase.\n\nHowever the above is an analogy to make the concept some what to understand. But the charge in a wire is different from the vehicle flow.  \n\n\n\n.
62744
It may be because of the electricity fluctuation. Or their may be a problem with your monitor's picture tube.
510725
The CT will only work on an AC circuit so I don't see where it would make any difference.  The only thing that would is to have another phase too close and the magnetic fields might cancel each other. Since the current being measured is AC the output from the CT will also be AC and shouldn't matter on the leads.
494225
You sure do need help....\nWhen you were cutting the LED off, you created a short circuit, first with the wire cutter (or whatever you were using), and then you most likely allowed the 2 lose wires to touch each other (or both touch a common metallic item).\nYour battery is now kaput !  They don't like short circuits, you know....
161177
you are almost right, electrical ground is allways relative to a higer potential source like a live wire and the current flows toward ground from the higer source, when you ar isolated (you have rubber shoes, you have a high resistance in the way of the current), there still a current flow, but it is so small (nano amperes) that you body cant feel it
234498
Something else in the pocket made contact with both terminals, causing the battery to pass current and generating heat.  I did this once by tossing a 9V that I thought was discharged into my pants pocket where I have my office keys.  The keys completed the circuit from the positive to the negative terminals, and I shortly noticed the heat.
433500
I use an NPN transistor to turn my relays on/off. See pic...\nhttp://img47.imageshack.us/img47/9813/untitled1ut4.png\nR1=(Voutmax)/(Ioutmax)\n\nThe other option is to use open-collector logic. They use a pulup resistor to what ever voltage you want. This gets sketchy because logic cant handel much current: not to mention the current needed for the relay. See pic...\nhttp://img47.imageshack.us/img47/3778/untitled2vf8.png\nI would use the transistor methoid. Its less trouble then the open-collector methoid. If you need more current through the relay: just decrease the bias resistance.\n\nEDIT: Left_Field is right about the diod. Slipped my mind.
609057
Hotwire around it in the circuit.  Cut the lead feeding into the filter after the jumper.\nJust like bypassing a sensor in a burglar alarm system.
160135
Your printer has a memory on it.   The printer remembers the last three cartridges that have been installed, and thus is remembering your cartridge as being empty.\n\nIf you have some empties kicking around or know somebody that does, just install and remove them in sequence with your refilled cartridge being the fourth and final.  \n\nHopefully that will clear it up.  \n\nHowever if you are getting a blinking light and a "please check cartridge" warning then unfortunately the cartridge is done.  The electronics have failed and there is nothing left to do except replace the cartridge.
547857
What you say is true --IF-- all the components are in series. That will not be true in a circuit with parallel paths, because the current that left the voltage source has to divide at any 'T', some electrons going along one branch and the rest the other branch.
527533
Check whether the power cables from the motherbaord to the powerswitch are connected properly. It could behave mad if the connection is not proper !!!!
86847
Voltage across parallel circuts is always the same, so 7V. The current, however will be split (if the lamps are exactly identical, split in half between them).\n\nSeries circuits are the other way. Voltage is different, current is the same.\n\nThis is a consequence of Kirchoff's laws. Kirchoff's law says that all the current going into a node must equal the current going out of the node (conservation of energy, really). And also, the voltage drops around a loop must equal. Common sense really. There can't be any extra (or deficit) current or voltage.
317350
b) and c)\n\nthe transformer works in such a way that electric current flows through the secondary circuit only when the electric current in the primary circuit is changing.\n\nwhen you close the switch the electric current in the primary circuit suddenly rises from 0amp to some value\nwhich causes electric curent to flow through the secondary circuit\n\n.. b) is true\n\nwhen you open the switch the electric curent in the primary circuit changes from the maximum value to 0amps thus electric curent flows through the secondary.\n\n.. c) is true\n\nbut \n..a) is false\n\nsicne a battery is a dc source wich means that as long as the switch is closed it supplies a steady amount of electric current through the primary. thus ther will be no current through the secondary.
213972
a drawbridge or a circuit??
125566
There are very simple way of checking this type of thefts. Switch off the source it self, and check if your energy meter is still working/ revolving. If yes, it means that your doubt is correct. disconnect that load first by calling the experts of the system. and then check further.
10848
In a good conductor, electron flow doesn't really affect physical structure.  When atoms in a conductor bond together, one can think of the atoms' electrons as "free electrons," able to roam hither, thither and yon with little interference.  Without an electric current, you can think of these electrons just roaming about randomly - there's no overall flow.  When one introduces an electric current, these electrons all flow in the same direction.  So you see that the physical structure in the conductor is the same - roaming electrons - the only physical difference is that the electrons flow together in a current, while they do not otherwise.\n\nAs far as changes on a larger-than-atomic level - electric current can heat up a material conducting the current.  This, for example, is how light bulbs work: a current flows through the light bulb and heats the little filament inside.  As the filament heats, it also glows and - voila! - light.  Also, if you stick a thin copper wire between the two poles of a car battery (DON'T try this!) the wire will vaporize due to the heat produced by the massive current running through it.\n\nOne final thing - please note that heating something up (even if it glows) is not a physical change, but rather a transfer of energy.  However, if the conductor vaporizes, like the copper wire, this is a physical change.