Can you explain how you work it out please
201919
Lisa = L, Jen = J\nL+J=25\nwe know from the question L=4J  \nso L+J=25 becomes\n         \n          4J+J=25\n          5J=25\n           J=25/5\n            J=5  so we get Jen catches 5 frogs \n                           Lisa catches 20 frogs
341563
find out what happens to Y (what it approaches) as:\nx goes to infinity\nx goes to negative infinity\nthen find out what happens to X as:\ny goes to infinity\ny goes to negative infinity\n\nalso find the intercepts (if they exist)
247002
Ask your teacher.\n\nBut usually, you are supposed to simplify.
235659
Start by multiplying both sides by D this gives you\n(D*P) = (2*s*t)\n\nthe divide both sides by 2t which gives you\n(D*P)/(2*t) = s\n\nor\n\ns = (D*P)/(2*t)
405069
The trick is that you can do the same thing to both sides of an equation:\n\n1. Divide both sides by W: L = A/W\n\n2. Subtract 32 and multiply by 5/9: C = (F - 32) * 5 / 9\n\n3. Multiply both sides by 2 and divide by b: h = 2A/b\n\nSimple steps, once you have the hang of it.
321442
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
417229
wow I didnt get the answer I got like something outta this world when I used that formula. But isnt the answer b. cuz when you use the formula f=c9/5+32
178322
let x be the number from A\nlet y be the number from B\nlet z be the number from C\nthey have 500 pounds\nso\n2x+2y+3z=500\nand we have 1000 hours to produce \nso \n4x+5y+5z=1000\nsolve this system with respect to x u will get the following\n-2(2x+2y+3z=500)\n   4x+5y+5z=1000\nadd them u get \ny-z=0\nthen y=z\n5(2x+2y+3z=500)\n-2(4x+5y+5z=1000)\nu add and get\n2x+5z=500\nthen z=(500-2x)/5=100-2x/5\nz=y=100-2x/5\nlet f(x)=500x+600y+1000z=500x+y(1000+600) since y=z\n        =500x+1600y\nsubstitute y and z\nu will get\nf(x)=500x+1600(100-2x/5)=500x+160000-640x\n    =160000-140x\ndifferentiate f(x)\nu get\nf'(x)=-140\nso it is maximal when x=0\nthen y=z=100\nand profit =f(0)=160000$\nf(x)=
629797
3/x  + 1    the way you put it..
494549
Wellll, since the first one is an equality, you multiply the inner factors to equal the outer factors.  Then, you have to divide both sides by N in order to move N to the other side of the equation.  Then, you can solve for P:\n\nN x P = M x Q\nN x P / N = M x Q / N \nThe 2 N's on the left cancel each other out, so now you can solve for P\nP = (M x Q)/N\n\nAnd for the second one, it helps to remember you always do the multiplication and division portions before you do the additions and subtractions.  So, write it in that way and it'll be easier to solve.  Then, you have to add (B/M) to both sides of the equation to solve for Y (essentially, you're moving it from one side of the equation to the other):\n\nY - (B/M) = X\nY - (B/M) + (B/M) = X + (B/M)\nY = X + (B/M)
531869
I think you just take the numbers and plug them in where the letters are and find your result.  Ie.  every time you see an a in the question, write -2 instead and then work it out...
435567
Okay, let's start by finding a value of x in terms of y.  That will be like x=something with a y in it.  That way we can "plug in" the value of x into the other equation and get a result for y.  Then we can find x.  Let's start.  The second equation looks easier to solve for x  because you don't have to divide anything.\n\nx-2y=-3\n\nAdd 2y to both sides\nx=2y-3\n\nNow plug 2y-3 in for x in the first equation, and we get\n\n2x+3y=8\n2(2y-3)+3y=8\n\nUse distributive property, simplify\n4y-6+3y=8\n\nCombine like terms.\n7y-6=8\n\nAdd 6 to both sides\n7y=14\n\nDivide both sides by 7\ny=2\n\nWe now have a value for y.  Let's plug it into one of the equations:\n\nx-2y=-3\nx-2(2)=-3\n\nSimplify and solve\nx-4=-3\nx=-3+4\nx=1\n\n\nx=1\ny=2\nThat is your answer.\n\nHope this helps.
240189
can you elucidate it a little more please?
100538
Use your buffering equation and plug in the numbers you know to get your answer.  You might have to do reverse calulations to find your answer.
183301
You can find the answer here.\n\nhttp://www.swlearning.com/finance/brigham/ffm10e/ffm10e.html\n\nGo to chapter 8 and it will explain how to solve.
45011
Use a calculator - numerator divided by denominator will give you the answer.
204800
can u explain further?