What is the diffrence when do you know when to change the sign and subtract or add instead off doing what the problem is told
208907
When you add a positive number and a negative number, you actually subtract the two numbers, then choose the sign of the larger number for your answer.\n\nWhen you subtract a negative number from a positive number, the negative number becomes positive and you add the 2 numbers.\n\nWhen you subtract a positive number from a negative number, it becomes negative and you add the 2 numbers.
37563
thats not a big issue.....u can rearrange the letters to numbers...for example if the problems lists the coordinates as a,b,c,d etc....mark a=1, b=2, c=3 atc....\nhope this helps
65067
i suggest you should start any activity with fixing "out comes" not the "input".Unless you reach that outcomes you shoud not revise anything. if you use this principle of fixing outcomes you will never need to make any revision.
169799
They are correct.  Observe the order of operations or PEMDAS\n\nParenthesis\nExponents\nMultiplication-Division\nAddition-Subtraction\n\nso first multiply   -89 * 658 =   -58562\nThen add 2   =                    -58560\nThen add 6   =                    -58554\nThen subtract 89 (or add -89) =   -58643
620580
well  the answer is 3  however  when using mathematics it is better to use an asterisk (*)  to remove any possibility of confusion between multiplying or a variable  \nbut you do multiplication or division and then addition or subtraction reading left to right\n\nso you have 1*2=2\nthen 1+2=3\n\nhave a nice day  check ya later ♥
302160
When you figure it out tell me
272968
I think people naturally want to improve their efforts, and that is what is being done to serve the clients better. However, there are those who have a hard time with change. It sounds as though you do. Actually, I have used both formats and find them equally well-done, although if I had to choose, I would choose the original.
630026
toss a coin and then see if the answer feels right --- if it doesnt than choose the other option \n\nmake a choice and move on
646202
subtracting a negative is the same as adding a positive\n\nmultiplying/dividing like signs (+,+ ; -,-) will give a positive product/quotient\n\nmultiplying/dividing opposite signs will give a negative answers
70081
A main difference would be the intent, if the obstacle/challenge were deliberately placed before you.  The intent of an obstacle is to block you.  The intent of a challenge is to test you.\n\nIf it were not intentionally placed, and just something that you came upon in your life, then the difference might be in your perspective.  Do you think "oh, crap!" and ponder whether it is worth the trouble (perhaps selecting another path)?  Or, do you embrace it as exciting and a path to self-improvement -- a chance to show yourself and others your capabilities or dedication?  \n\nIt is important to select the correct word to properly communicate.  They say different things, about the situation and about you.
409863
if(help_you_out == do_it_for_you){Answer=NO;}\n\nOn the other hand, try looking at the tutorials and other resources on the URL below for a quick refresher on some stuff.
185678
at college level we have different method one of these is this \nwhen solving problem you feel that u required some quantity let them (these are called Unknowns )the no of unknown = no of conditions using these conditions remove all unknowns you will get your answer definitely if it worked ask me for the next \nthanks
486143
well...both answers that were given arnt wrong...but not entirely right\n\nok...so you are given some equation you find its derivitive\n\nim going to assume you now have solved for dy/dx ...in other words you have an equation\n\ndy/dx = mess of an equation...most likely a fraction\n\nok, so now you need the second derivitive...if your dy/dx has some y's involved on the right of the equal sign your probably panicking...dont\n\ntake your derivitive..probably involving the quotient rule, and when you take derivitives of things with a y in them remember to put the dy/dx\n\nso your final equation will be\n\nd2y/dx2 = some x terms, some xy terms...maybe a fraction and probably some stuff with dy/dx's attached\n\nand you say...now what do i do...well you already know what dy/dx is..you solved for it initially...its the first derivative with respect to x\n\nyou now can substitute your dy/dx equation anywhere you see a dy/dx...and some cancelling will ensue...and life will be good\n\nhope this helped\n\nmatttlocke
290678
The first one is correct.\nThe second one fails in the first line.\nYou can't move the 2 inside the sqrt sign.\n(i)^2 = (sqrt(-1))^2\n(sqrt(-1))^2 = sqrt((-1)^2)\nThis only works for positive numbers.
602858
looks like you have change it--What is the problem? You can't put up with inconvenience and wait?
378355
yes the signs have just been changed\ntake -x+y=-2 and multiply by -1 on both sides\n \nyou get x-y=2 and since the same thing was done to both sides the equation is equivalent
20425
shift or change\nfixed or immobile\nvector