Find the interest that will be earned if 10,000 is invested for 3 years at 9% compounded monthly.
211625
$10,000 * (1 + .09/12)^36 - $10,000 = $3,086.45\n\nDo I get 10 points?\n\nRaizon used the wrong interest rate.  The rate is 9%
665464
Goose is right. The formula is:\n\nFV = P x e^(r x y) \n\nwhere FV = Future Value; P is your principal, r is the annual interest rate and y is the number of years of continuous compounding and e = lim(n-->inf) of (1+1/n)^n\n= 2.7182818.(about)\nHere's link which explains it quite well and also has a periodic/continuous calculator to fool around with.\n\nhttp://www.moneychimp.com/articles/finworks/continuous_compounding.htm
509745
the formula for compound interest yearly is\n\nA=P(1+r/n)^(rn)\n\nwhere\nA=final amount\nP=Initial amount\nr=rate in deciamals\nn=number of times coumponded yearly \nMontly=12,quartely=4,daily=365.....
527452
Invest it in a high interest acount over 10 years...its safer than investing in busines...;
659812
Say the bond is a 10 yr bond issued on on 12-31-03 for 9,700 and the face value is 10,000.  You would amortized the discount over over ten years.  (10,000-9,700)/10 yrs = 30 amortization of 2004.
45688
Considering annual coupon payment, it works out to be 6%.\nFormula is    Rate of Interest = (Interest X 10) / (Principal X No. of years)  = 6000/1000 = 6\n\nReal rate of return = Nominal return - inflation rate\nwork out ... results will be 4,2,0,-2
193507
The Accumulate amount, A, = Pe^(in) where P is the investment, i is the interest rate and n is the time.  e is a mathmatical number and is on your calculator.\n\nTo find the present value of an investment n years ago you would use this formula PV = P(1+i)^n  with P the initial investment, i your interest, and n your time.\n\nyou will have to look at when your interest is compounded, if it is monthly or semi-annual make sure to adjust your interest and time accordingly
496161
Okay, I would figure this out one year at a time:\n\nThe first year, the account would have:\n\n1.08(2500 + x) = 2700 + 1.08x\n\nwith x equaling the end of the year deposits. I multiplied by 1.08 to get the amount after the 8% interest was added.\n\nThe second year would be the above amount plus another x and multiplied by 1.08 for the 8% interest:\n\n1.08((2700 + 1.08x) + x) = 2916 + 1.1664x + 1.08x\n\nThe third year would be this amount plus another x and multiplied by 1.08 for the 8% interest:\n\n1.08((2916 + 1.1664x + 1.08x) + x) = 1.08(2916 + 1.1664x + 1.08x) + 1.08 x\n\nThe above equation represents the amount in the savings account after 3 years. Set that equal to 10,000 and solve for x:\n\n1.08(2916 + 1.1664x + 1.08x) + 1.08 x = 10000\nx = 1953.94\n\nSo the couple will have to deposit $1953.94 at the end of each year.
507695
define i = apr/12\nP = quantity (principle)\nn = time (months in this case)\n\nThe calculation formula for payments is\n\np = iP/(1-1/((1+i)^n))\n\nplugging in the numbers,\n\np = (0.01/12)(17,500)/(1 - 1/((1+0.01/12)^72))\n\nOh, if you just want future amount at compound interest, \n\nA(i,n) = A(1+i)^n\n\nA = 17,500(1+0.01/12)^72
57926
$5000 saved in an account earning 4.75% yearly, compounded daily, will yield $243 in one year. If it's compounded daily, your monthly return will vary, but it averages out to $20.25 a month.\n\nDinkytown has the best free calculators anywhere, below:
311203
$13,455. x 9% = $1210.95 Interest\n$13455.00 + $1210.95 = $14,665.95\nUnless the interest was 9% per annum\nThen you only use 1/2 of the total interest amount and the previous answers are correct (or $605.48 + $13455.).
475992
The lower rate times investment A will be part of the 760.\nThe higher rate times investment B will be the other part.\nA and B are parts of $10,000.\nSo A + B = 10,000\n\n6% interest * A plus 8% interest times B = 760.\nSo .06 * A + .08 * B = 760.\n\nLets return to A + B = 10,000.\nYou can "define" B by solving for B\nA + B - A = 10,000 - A\nB = 10,000 - A.\n\nYou can now substitute the definition of B for its occurance in the interest equation .06 * A + .08 * B = 760.  Therefor\n.06 * A + .08 * (10,000 - A) = 760.\n\nNow that A is the only variable, you can solve for A.\n.06 * A + .08 * (10,000 - A) = 760.\n.06 * A + 800 - .08 * A = 760\n800 = 760 - .06A + .08A\n40 = .02A\n40 / 0.02 = A\n2,000 = A\n\nB will then be 10,000 - A.  B = 8,000\n\nNow let's check the answer\n$2,000 * 6% = $120\n$8,000 * 8% = $640\n$120 + $640 = $760 \nQED
183301
You can find the answer here.\n\nhttp://www.swlearning.com/finance/brigham/ffm10e/ffm10e.html\n\nGo to chapter 8 and it will explain how to solve.
74647
This may seem tricky, but it's not that hard.  The formula to calculate the monthly interest needs APR (Annual Percentage Rate), and you have the APY (Annual Percentage Yield).  We can approximate the APR from the APY, so, again it's not a big deal.\n\nThe formula is monthly_interest = APR/365 * days_in_month * monthly_balance.  As you know, leaving the monthly interest in your savings account will increase your balance, giving you more interest the next month.  An APY or 4.8% is likely based on an APR of 4.7%.  An APR of 4.7% actually gives an APY of 4.8026%  Confirm the actual APR with your bank.  \n\nUsing 4.7% as the APR and your current balance of $113.94, we get the first month's interest of .047/365*30*113.94 = $0.440152 or 44 cents.  Notice that I assumed the month has 30 days.  Longer months will get you a few more cents of interest.\n\nBest of Luck.
478500
To keep it very simple, the answer is: it grows exponentially by compounding interest.  With that said, over time the 10% is added to the previous years value so after each year the base value is greater.  Like I said keep it very simple after two years the interest gained is not 10%+10%=20%, but rather (1.10*1.10)-1=21.0%...this happens every year and gains momentum.  See time value of money.  Basically add 10% to each value:\n\nEnd of:\nYear 1= 11000\nYear 2= 12100\nYear 3= 12100*1.1=13310\nYear 4= 13310*1.1=14641\n....\nYear 25=98947*1.1=108347\n...\nYear 40=411447*1.1=452952
213434
Let's see, A million in three months\nis 1 million a month.\nInvest 10 million dollars, and get a net\nreturn of 10% in a month.\nI think that comes to 1 million a month.\nDo that three times. Surely a day trader can net\nyou 10% over a month.
271244
first, start with how much money you have, then find the rate, and the time\n\nfor example:\nI have $20,000, at a rate of 12% for 36 months. The interest would be $20,000 times .12 times 36.