Directly from the AC line cord\n\nIndirectly from a switch contact\n\nFrom a tap on field coil\n\nFrom a brush holder contact
203183
every electrical diagram has a rout\nand a disrout from ground\ntherefore any bulb or luminare device\nhas its own route on the map\nnextime, challenge me
96771
Mineral oil is used in AC power line step down transformers.\nLow frequency though.
104113
Try this place: http://www.tradekey.com/ks-Galvanized-Steel-Coil
466916
use an acetylene torch aluminum rod & flux.
189097
first connect all grounds then take the  neutral on the transformer to your  receptacle neutral then  take one live wire from the receptacle to the switch and from the switch to the transformer being that it is two pole you will take a wire from each pole and take each "hot leg" wire to a separate "live" connection point on the transformer, provided that it is a two phase connection
573385
Call the manufacturer.
308127
I doubt that you have any ground on that outlet (screw or otherwise). Surge protectors shunt to ground, so no, no help with that.\n\nHowever, you could put a hole-house protector in at the service panel. These aren't as effective, b/c you house wiring is a nice antenna for transforming lightening fields into surges on your lines.
100463
look on the top of the controler, near the wire or sensor.
89284
!WARNING!\nFirst before I even answer your question.  I just like to warn you that if your actually attempting a stunt like this be very careful.  Connecting 100 AA Batteries(1.25V) in series will produce 125 Volts.  Be very careful with it!\n\nAnswer:\nThe SI units of the electric field are volts per meter.\nThe equation for an electric field is: (E=V/r)\nWhere E=Electric Field, V=Voltage, r=distance from point.\nSo a higher electric field means two things: Higher voltage, or less distance. In order for you to get the highest voltage connect the batteries in series as follows:\n\nConnection: \nYou would need to connect the battery in series as follows to get the highest voltage. \n Bat1  Bat2  Bat3  Bat4  Bat5  Bat6      Bat100\n[- +]o[- +]o[- +]o[- +]o[- +]o[- +]o....[- +]o\n\n\nWhy:\nThe electric field is dependent on the voltage and distance. Increasing voltage will directly increase the electric field.  Decreasing distance will increase the electric field. Look at the equation above. E=V/r\n\nAnother way to think of it:\nThink of Voltage as pressure. And a ball as an point charge(electron).  Suppose you have a water hose and a ball.  You have to use the water hose to move the ball around.  If your too far away from the ball, the water will not reach the ball and the ball won't move.  The same thing happens in electric field.  The electric field is too far from the electron to make it move.  Now suppose you increase the pressure on the water hose.  Because of the increased pressure(Voltage) the water will shoot further and hit the ball, thus moving it.  If your very close to the ball you can use the water pressure(Voltage) to move the ball faster.
675647
this is so easy... the answer is furnace...\n\n\nFURNACE
269623
AC - is easy.  Go to the library and read up on the subject.. You will figure it out, its easy....\n\nIf you buy a split system, the condensing unit will come fully charge with mostly all the gas you need. You'll have to silver solder the system together and then bring the air handling unit down into a vacuum before you can release the gas into it... Soldering is easy, but you'll have to get your hands on a vacuum pump. They can be costly.   I'd say buy the unit, install it, solder it up, and then have a service guy come out to pump it down and charge it with the little gas you may need.
210111
Don't try this one yourself! Use a pet rat or something!\n...\nActually, don't! Or i'll get hunted by Animal Rights Activists!!\n\nAll you need is a battery, two wires and a large capacitor.\nCharge the capacitor by connecting the battery across it with the two wires.\nThen disconnect the wires.\nThe capacitor has now been charged - if you put your hands across the terminals, you'll get a nasty shock.
276889
A generator produces a current by moving a wire through a magnetic field.  If you had an infinitely large magnetic field, you could move in one direction forever and produce a dc current.  However, it isn't practical to do that.\n\nInstead, you put a ball of wire inside a much smaller magnetic field and you spin it.  The ends of the wire have to be touching something to complete the circuit so electrons can flow.  At one part of the circle, the wire is moving left to right across the magnetic field and causes electrons to flow in one direction in the wire, in another part of the circle, the wire is moving from right to left and the electrons flow in the opposite direction.  This is what causes the current to alternate.\n\nSo, when converting motive energy into electricity, ac current is the easiest to produce.  This is like what is produced by a car's alternator or a hydro-electric plant.
340887
the is rotated in the magnet with the help of the wheels which are turned by the driver. this induces electricity to flow through the wire. this electricity is used to light the bulb.\nlook up electro magnetic induction.
317350
b) and c)\n\nthe transformer works in such a way that electric current flows through the secondary circuit only when the electric current in the primary circuit is changing.\n\nwhen you close the switch the electric current in the primary circuit suddenly rises from 0amp to some value\nwhich causes electric curent to flow through the secondary circuit\n\n.. b) is true\n\nwhen you open the switch the electric curent in the primary circuit changes from the maximum value to 0amps thus electric curent flows through the secondary.\n\n.. c) is true\n\nbut \n..a) is false\n\nsicne a battery is a dc source wich means that as long as the switch is closed it supplies a steady amount of electric current through the primary. thus ther will be no current through the secondary.
211417
You'll need, as the name may suggest, a voltmeter.  Also applicable is a multimeter - which you'd then set to voltmeter mode.\n\nAt which point you'd just put one contact on one one end of the battery, and one on the other, and see what the equipment reads.\n\nMy money's on 1.5V :)
433887
light duty is the problem - would be very easy to make one using any push on connector in the circuit ( you need a spring loaded connector with the pin being non conductive - a 'blade' shaped pin would be the easiest to rig )\n\nanother possibility is to use a switch of any type ( a - b ) that shunts the circuit to a open   circuit  ( this can be activated by a pull - and switched back manually )