hint: AB, AP, BP are line segments.\nplease show me every steps of your work.
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Since angle in a semicircle is right, angle (APB) = 90 \n\n=> APB is right angle triangle with hypotenuse as AB = 10 cm and other side AP = 6 cm,\n\napplying Pythagoras theorem,\n\nBP^2 = AB^2 - AP^2 = 100-36 = 64 => BP = 8 cm
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1) b)\n\n2) [H2O]^2 / 2[H2] [O2]\n  \n   [NO]^2 / [N2] [O2]\n\n3) b)\n\n4) b)
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You need to start off with a six-pointed star (constructed with two equilateral triangles).\n\ntriangle AEC and triangle FBD\n\nNow connect A to D, then connect B to E, and finally C to F. If you \ndrew everything correctly, those three segments should meet at a point \nin the center of the star.  \n\nThe 3 line segments you just drew plus the six sides of the star make \n9 lines. There are 5 points of intersection on each line, and the \ntotal number of intersections is 19.
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(0,0)\n(3,0)\ndraw the graphs and then find them out!\nif u can't, then mail me!
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See if this article has a diagram\n\nhttp://jchemed.chem.wisc.edu/Journal/Issues/1999/Apr/abs542.html
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cool! I'll think about it\n\n---\n\nhere I am.\nUse the two perpenducular segments as a coordinate system with O on their intersection.\n\nSay: the 4-3 segment defines the x axis, and the 2-6 segment defines the y axis.\nYou know four points belonging to the circle: (-4;0),(0;-2),(3;0) and (0,6)\nThe center of the circle has the mean value between -4 and 3 as its x and the mean value between -2 and 6 as its y (property of chords: the center is on the chord's axis)\n\nso the center's coordinates are C(-1/2;2)\n\nNow you can easily calculate the distance between C and anyone of the four points you know to get the radius.\n\nThen finish finding the diameter\n\n----
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Try using graph paper.  Draw a line segment from the origin to a point 3.5 units straight down.  Starting at the bottom of this segment draw a line that is 8.2 units that makes a 30 degree angle with the horizontal. \nThe third segment starts at the end of the second segment and goes 15 units to the left.  Connect the end of the third segment to the origin, this is the deplacement vector (make it red or something so you can really see it).  You can measure its length and the angle that it makes with the horizontal to describe it.
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1 -> b\n2 -> e\n3 -> c\n4 -> d\n5 -> a\n6 -> f
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circular segment\n\nhttp://en.wikipedia.org/wiki/Circular_segment
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your question is not clear. describe positions of the objects.
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the first thing is to parametrize the segment:\nx= 1 + t(0)\ny = 2+ t(3)\nz=1+ t(4),\nnow when t=0, then x=1,y=2 and z=1, and when t=1: x=1,y=5 and z=5,\nso\nnow\nthe line integral is:\nintegral from 0 to 1 (3x dx+y dy+(x^2z–y^3)dz) \n=integral form 0 to 1 3(1) (0) + (2+3t)3dt - (1(1+4t)- (2+3t)^3 )(4)dt\n= integral form 0 to 1 (6 +9t -4 - 16t +4(2+3t)^3 ) dt\n= integral from 0 to 1 (2 - 7t + 4(2+3t)^3 ) dt\n= 2t - 7t^2 + 4 (2+3t)^4 (1/4) (1/3) evalutated at 1 and 0\n= 2 -7 + (1/3) (5)^4 - ( 0 -0 + (1/3) 2^4 )\n'
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Slope of the given line AB= [2-3]/[-2-2]= 1/4\n\nSlope of the required line= -1/4.\n\nThe required equation y= (-1/4)*x + constant.\n\nInfact this is the equation for family of lines which met the above condition.
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What are the co-ordinates of the other point? just use the midppint formula for a segment. All the best!\n\nLife's Lovely! Love & Live Life!
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It comes from the fact that the "hypotenuse" of the two "triangles" is not a straight line segment.  It is actually two segments of similar, but not equal, slope.
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1.  Find the midpoint, then the negative slope, that will give you an equation for a line that is a bisector.\n\nThe midpoint is halfway between A and B.  The midpoint is the average of the x-coords and the average of the y-coords.\n\nx(mid) = [ x(A) - x(B) ] / 2\nx(mid) = [ 7 - (-1) ] / 2\nx(mid) = 8 / 2\nx(mid) = 4\n\ny(mid) = [ y(A) - y(B) ] / 2\ny(mid) = [ 3 - 4 ] / 2\ny(mid) = -1 / 2\ny(mid) = -1/2\n\nSo your midpoint is (4, -1/2)\n\nNow the slope of the line AB is given by the formula (y2 - y1) / (x2 - x1).\n\nm = (4-3) / (7 -(-1) ) \nm = 1 / 8\nm = 1/8\n\nThat means the perpendicular line must have a slope equal to the negative reciprocal:\n\nm' = -1/m\nm' = -1/(1/8)\nm' = -8\n\nSo you have a point (4, -1/2) and a slope (-8).\n\nUsing the point slope form, you can get an equation of the line:\ny - y(mid) = slope (x - x(mid))\ny - (-1/2) = (-8)(x - 4)\ny + 1/2 = -8x + 32\ny = -8x + 31.5\n\n2. For each vertex, you can connect to (n-3) other vertices.  For example with ten vertices, you can connect to 7 other vertices.  This excludes the point itself and the two adjacent vertices that would make up the outside of the polygon.\n\nSince there are 10 vertices and 7 ways for each to connect that would be 70 connections.  But connecting A to B is the same as connecting B to A, so we have actually counted everything twice.  Therefore divide by 2 to get 70/2 = 35 diagonals.\n\nIn general, for an n-sided polygon there are n(n-3)/2 diagonals.  For n = 10, there are 35 diagonals.
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Directions how to do this can be found in the text book.\n\nDo your own homework!
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This is pretty simple. Take each row to be a line. There is a theorem:\nTwo lines parallel to the same line are parallel to each other.\nThe first row is parallel to the second row. So, the second row is parallel to the first row. The second row ia also parallel to the third row(Each row is parallel to the row immediately next to it.). So, the first row is parallel to the third row.\nSimilarly,you can go on proving this true for each row till you get the result that the first row is parallel to the last row.