if 1=5\n\n\n\n   2= 25\n\n\n\n   3=125\n\n\n\n   4=625\n\n\n\n   then 5= what?\n\nthink before answering........
209421
Think as follows.\n\n1 is 5^1 = 5\n\n2 is 5^2 = 25\n\n3 is 5^3 = 125\n\n4 is 5^4 = 625\n\nSee the pattern?, For the nth row is 5^n.\n\nHence, for what you wanted,\n\n5 is 5^5 = 3125\n\nAnd buddy, I always think before answering... :)\n\nRegards
274714
1. c\n2. c\n3. b\n4. a\nand 5 is a.
410250
D = Q + 5\n\n(N-1)*5 + 25 = (D-1)*10 + 5 = (Q-1)*25 + 10\n\nTake the first equation and the second two of the triple below it:\n\n(Q  + 5 - 1)*10 + 5 = (Q - 1)*25 + 10\n10Q + 45 = 25Q - 15\n15Q = 60\nQ = 4\nD = 9\n\n(N-1)*5 + 25 = (D-1)*10 + 5\n5N + 20 = 85\n5N = 65\nN = 13
95531
4\n\n5+3 = 8\n\n8/2 = 4\n\nEdit: if you're saying it's tricky, maybe you mean (5+3)/2 IS (5+3)/2 or "five plus three all divided by two (is equal to four)"?
465717
Hello dear Asker ;\n\n{ as you know ;\nP(n , r) = n! / ( n –  r )! }...\n\nso ;\n\nP (5 , 3) = 5! / ( 5 – 3)! \n=5! / 2! \n= (5 * 4 * 3 * 2 * 1) / (2 * 1) \n= 120 / 2 \n= 60 \nTotally We cane make 60 words with out any repetition\n\nGood Luck dear
37150
u can do it by trial and error. ok the possible digits for ones are just 1,3,5,7,9 since the statement says it is an odd number. ok then try to add 2 and equate it to 12. if it is = that's is the answer. 7+5= 12. so and 7 is greater than 5 by 2. the answer is 75 degrees.
236991
a=7\n25 squared is 625\n24 squared is 576\nthe difference is 49\n7 times 7 is 49 not 3
526816
Multiply them\n1*3*2 = 6\nAnswer: 6 possibilities
66745
I agree with the previous answers. However, I would like to provide you with some tips so that you can do it yourself next time : )\n\n5 minus 2 5/16: \nfirst : 16 minus 5 = ? --> this number (11) will be placed over 16 in the result fraction\nsecond: 5 minus 1 minus 2 = ? --> result integer\n\nWhy 5 minus 1? Because 1 has been taken from 5 to take part in the decimal minus process.
171649
"We could change the second + to 4 by putting a vertical small line\n\n5 + 5 + 5 = 550\n5 + 5 4 5 = 550"
604740
44\n\nthe cubed root of 125 is 5... this means the cube was 5x5x5. 8 of these are the coners (having 3 sides red) then that leaves 12 edges with 3 cubes no coners (2 sides red). \n\n8 + 12*3 = 44
33744
:D i think the person asking this question is not stupid, as most people here make him out to be, but rather is having fun, and seeing how far ppl will go to be picked :D ... anyways\nHere's my version of the proof, i'm going to do it in a step by step manner\n\nGiven: 5*5\nProof: the value is equvalent to 25\n\nStatement                |         Reason\n1)5*5                    |  1)Given\n2)=25                    |  2)Multiplicative Property of                      \n                         |     Arithmetic
458284
1. 2(n-1) -1= x, where n starts as 10 then n-1 will be equal to 9 and then becomes your answer, or x. 2(9)-1=17, then n is 17 the second time you use this equation....the first 5 numbers are 17, 31, 61, 121, 241. each answer is one less than one less twice the number before it, confirming our equation.\n\n2. 3n+1=x, where n starts as 2. The answers are 7, 22, 67, 202, 607. each number is triple the number before it, plus one.......\n\nsorry if my answers are wrong.......\n\nbut hope this is correct because it is very familiar to me.......it is like an IQ test...
166069
Easy Homework?\n\na=2, b=1, k=2, j=5, n=3.\n2^2=1^2 (mod 3), and 2=5 (mod 3) but 2^5=2 (mod 3) and 1^5=1 (mod 3), so 2^5 is not 1^5 (mod 3).
508996
1.)\nan = a1 * r^(n - 1)\n\na5 = a1 * r^(5 - 1)\n(1/24) = (2/3) * r^4\n(3/24) = 2r^4\n(1/8) = 2r^4\nr^4 = (1/16)\nr = (1/2)\n\nan = (2/3)(1/2)^(n - 1)\n\na1 = (2/3)(1/2)^(1 - 1) = (2/3)(1/2)^0 = (2/3) * 1 = (2/3)\na2 = (2/3)(1/2)^(2 - 1) = (2/3)(1/2)^1 = (2/3)(1/2) = (1/3)\na3 = (2/3)(1/2)^(3 - 1) = (2/3)(1/2)^2 = (2/3)(1/4) = (1/6)\na4 = (2/3)(1/2)^(4 - 1) = (2/3)(1/2)^3 = (2/3)(1/8) = (1/12)\na5 = (2/3)(1/2)^(5 - 1) = (2/3)(1/2)^4 = (2/3)(1/16) = (1/24)\na6 = (2/3)(1/2)^(6 - 1) = (2/3)(1/2)^5 = (2/3)(1/32) = (1/48)\n\na6 = (1/48)\n\n---------------------------------------------\n\n2.)\nan = a1 + (n - 1)d\n\na5 = a1 + (5 - 1)d\n-5 = a1 + 4d\na1 = -4d - 5\n\na7 = a1 + (7 - 1)d\n-2m - 11 = a1 + 6d\na1 = -2m - 11 - 6d\n\n-4d - 5 = -2m - 11 - 6d\n2d = -2m - 6\n2d = 2(-m - 3)\nd = -m - 3\n\na1 = -4(-m - 3) - 5 = 4m + 12 - 5 = 4m + 7\n\na1 = (4m + 7) + (1 - 1)(-m - 3)\na1 = 4m + 7 + 0(-m - 3)\na1 = 4m + 7\n\na2 = 4m + 7 + (2 - 1)(-m - 3)\na2 = 4m + 7 + 1(-m - 3)\na2 = 4m + 7 - m - 3\na2 = 3m + 4\n\na3 = 4m + 7 + (3 - 1)(-m - 3)\na3 = 4m + 7 + 2(-m - 3)\na3 = 4m + 7 - 2m - 6\na3 = 2m + 1\n\na4 = 4m + 7 + 3(-m - 3)\na4 = 4m + 7 - 3m - 9\na4 = m - 2\n\na5 = 4m + 7 + 4(-m - 3)\na5 = 4m + 7 - 4m - 12\na5 = -5\n\na6 = 4m + 7 + 5(-m - 3)\na6 = 4m + 7 - 5m - 15\na6 = -m - 8\n\na7 = 4m + 7 + 6(-m - 3)\na7 = 4m + 7 - 6m - 18\na7 = -2m - 11\n\na8 = 4m + 7 + 7(-m - 3)\na8 = 4m + 7 - 7m - 21\na8 = -3m - 14\n\nANS : a8 = -3m - 14
170230
1 = b\n2 = d\n3 = d\n4 = c\n5 = c\n\n4/5
382985
a 4\nb 5\nc 3\nd 2\ne 3\nf 4\ng 3\nh 5\ni 5\nj 5\nk 3\nl 5\nm 5\nn 5