How much does a HOLLOW 60cm chocolate rabbit weigh?
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8 times as much as an identical rabbit that is half the size
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First weighing:\nSplit the 27 balls into groups of 9, 9, 9.  Put 9 balls on one side, 9 on the other.  If one side of the scale goes down, the heavy ball is in that group.  If they balance, the heavy ball is in the group you didn't weigh.\n\nSecond weighing\nTake your heavy group of 9 and split it into 3, 3, 3.  Weigh 3 balls against 3 balls.  Again, find the heavy group either on the scales if one side goes down, or in the unused group if they balance.\n\nThird and final weighing.\nSplit the heavy group of 3 into 1, 1, 1.  Weigh 1 ball against 1 ball.  If one side goes down, that is the heavy ball.  If they balance the heavy ball is the one you didn't weigh.
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From rabbits. Rabbits (hares) have "hare-lips"  A split in their front lip.  Jeez.  ...... Yes he does oghma !!  look again!
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You could try ebay, they have all kinds of weird things, or try googling it. www.google.com and put in manuel Model# DWXL 1028 weighing scale, something may come up.
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part A\nfind the limit as t->infinity = 2000\n\npart B\nthe first derivative tells the rate at which the population grows.  you want to know when the rate was highest, i.e use the second derivative.\nfind p"(t)=0\nt=13.25 years\n\npart C\nthe inflection point is at t=13.25 years, which is what we found in the previous problem.  this is the time when the rabbit population grew the fastest.  to find the size of the population, evaluate p(13.25)=1000\n\npart D\nlack of food, lack of genetic variability causing imbreeding, lack of space
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hecka!!  damn.  i miss california.\n\nwhat you have to do is realize that this question is asking about the volume of a rectangular shape that is 1 meter by 1 meter by X meters, where X is the height of the column.\n\nso, you know the density.. density is defined as mass divided by volume.  and you know the weight.. which is mass times acceleration.  here the acceleration is the acceleration of gravity "g" = 9.8 m/s^2.  \n\nso you can do a little algebra to get the equation volume = mass / density \nvolume = weight / (acceleration * density)\n\nyou know the weight (100,000 N), the acceleration (9.8 m/s^2) and the density (1.2 kg/m^3).  plug those numbers in and you get the VOLUME of the atmosphere, and since you know 2 of the dimensions of the box (it is 1 square meter across the bottom face, remember) you can figure out the 3rd pretty easily.\n\nsince this is your homework i wont just tell you the answer, but you should be pretty much able to crank it out from here.
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You have to feed your rabbit three times a day, don't forget.  And give him some warm milk sometimes.\n\nGoats are different....\n\nWait, what was the question?
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A lipstick is small but fairly hefty because it's dense.  Its mass could be measured in grams.\n\nA pingpong ball is hollow and extremely light.  You would probably measure it in milligrams.\n\nA person should be measured in kilograms.
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INGREDIENTS:\n\n    * 1 rabbit, about 3 pounds, cut up\n    * 1/2 cup all-purpose flour\n    * 3 tablespoons butter\n    * 1 cup chopped celery\n    * 2 medium onions, thinly sliced\n    * 1 teaspoon seasoned salt\n    * 1 teaspoon salt\n    * dash pepper\n    * 1 bay leaf\n    * 4 cups water\n    * 4 cups dry red wine\n    * 2 cups diced carrots\n    * 4 medium potatoes, peeled and diced\n    * 4 ounces sliced mushrooms, sauteed\n    * 1/4 cup all-purpose flour\n    * 1/3 cup water\n\nPREPARATION:\nDirections for rabbit stew.\nDredge rabbit pieces with 1/2 cup flour. Melt butter in a Dutch oven over medium heat; brown rabbit pieces on all sides. Add celery, onion, salt, pepper, bay leaf, 4 cups water, and wine; bring to the boil. Reduce heat to a simmer, cover, and simmer rabbit stew for 2 hours. Add carrots, potatoes, and mushrooms; cook for about 25 to 30 minutes longer, or until vegetables are tender. Combine 1/4 cup flour and 1/3 cup water; stir until well blended and smooth. Stir flour mixture into the broth; cook and stir until thickened.\nRabbit stew recipe serves 4.
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Do you have the formula of the cillinder? Use it.\nThe weight (2 lbs.) is not important for areas and volumes.\nThe radius is the diameter divided by two.\n\na. 2 x π x radius x height\nb. π x radius x radius x height\n\nc. The formula for the volume of the cone is π x radius x radius x height / 3\n\nTo get your answer just divide the volume of the cillinder by the volume of the cone.
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ok, so lets calculate this.  a balloon with a foot diameter has a volume of .7854 cubic feet. .5 cubic feet converts into 14.158423356 liters.  The density of helium is .1785 g/L (grams per liter) and the density of air is usually approximately 1.25 g/L.  The difference between these densities is 1.07g/L.  The formula for density is d=m/V (density equals mass over volume)  so we set d=m/V, 1.07=m/14.158423356.  the 1.07 was the difference in density(how much less dense helium is than air) and the V i said(14.158423356) is how many Liters i said was in .5 cubic feet before.  it has to be in liters since the density measurement i gave you was in grams per liters, so for the formula to work we need to work in liters and receive an answer in grams.  ok, so solving for m in that density formula, we get 15.95g.  so each balloon can hold about 16g.  but i looked up the average weight of a regular party balloon and it's 2g, so each balloon can hold 14 more grams.  converting grams to pounds, 14 grams equals .030864717 pounds.  so each balloon can hold .030864717 pounds.  now if we divide your weight by the amount of weight each balloon can hold, we will get the number of balloons you need to support your weight. 160/.030864717 = 5183.9 so 5,184 balloons. \n\nyou would need 5,184 balloons to equal your weight.  this only makes you weightless, so the force of these balloons would basically perfectly counteract the force of gravity, so you would need to jump to push off and you wouldnt be pulled back down. if you wanted the balloons to actually lift you, you would need more, and depending on how many more, you would have a greater acceleration upward.  this is also assuming that each balloon is perfectly one foot in diameter, so the number of balloons may fluctuate a bit.\n\neven so, might i suggest you use a balloon with a larger diameter?\n\nif you want to find out for sure with specific balloons, you can always get like 50 balloons and some weights.  then you can measure how much weight the 50 balloons hold. then you set up a proportion saying that 50 balloons divided by the weight you measure it can hold(in pounds) equals X balloons divided by 160 lbs. then you can solve more precisely for the specific balloons you have.
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Well, if they are the same mass and the same material, and you KNOW this before hand, it would be obvious.  \n\nThe larger ball would be the hollow one because being the same mass they would have to weigh the same.  A hollow ball would have to be bigger to match the mass of the solid ball.
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its look like "rabbit"
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Both are Same Weight , 1 Kg\nbut Volume is different
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Check out http://www.healthchecksystems.com/heightweightchart.htm
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Period is independent of mass, so it doesn't matter how much the kid weighs. The period is\n\nT = 2 * pi *sqrt(L / g)\n\nwhere L = 5m, g = 9.81 and sqrt = square root
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210 pounds \n5'8'-6'1 tall\nbench 250 \nno more then 20% body fat.