and then moving on to balls/clubs? My books by Dave Finnigan stop at 4 scarves.
199238
I'm not sure about scarfs, but for something way cool and differant in juggling check out this site..........\n\nhttp://video.google.com/videoplay?docid=4776181634656145640
367738
First, find out how many ways you can arrange 20 different books with exactly two books on each shelf.  Then, find how many ways you can arrange the remaining 10 books on the 5 shelves.  Multiply these two answers together to find the total number of arrangements.  \n\nFor the first, consider each spot on each shelf as a different position.  How many choices are there for the left-most spot on the top shelf?  How many choices for the second spot on the top shelf?  Continue for each shelf and multiply them together - you should get 20!/10!\n\nFor the second, you have 10 books and 5 shelves where each book can go.  A shelf can have no books at all or it might have all 10 books.  If you start at the top shelf, they can either place a book or move to the next shelf.  You have 10 books and will move to the next shelf a total of 4 times.  Pretend you are putting the books in a row and using a marker to indicate when you move to the next shelf - you have 14 spots to place either a book or a marker and the markers all look alike.  (This is similar to arranging the letters AAAABCDEFGHIJK)  The number of ways you can arrange them is 14! / 4!\n\nThus, the total number of ways to arrange the books is 20!14! / 10!4!
539186
I quess as many as she want's to have.
341476
They are selling the paper garlands that you stretch out. It's by Todd Oldham. I think that's how you spell his name. Look back in the Christmas section.
402310
Well since you don't provide a list of "every book you want", that's a pretty broad request.\n\nThere is a project (Gutenberg) that's taking all the freely available books (passed their copyright dates) and digitizing them (http://www.gutenberg.org/wiki/Main_Page). There are 19,000 free books available there.\n\nIf you hit Usenet, you should be able to find lots of the books there too. You'll have to search them out though.\n\nI can't guarentee safe since you don't list what books you want.
637487
Stuff that not everyone else has, like stuff that's been sitting in your grandma's attic for years.  I sold a bunch of old matchbooks...yes, matchbooks...on ebay and bought myself one of those new composite hockey sticks ($130).  Pretty cool, eh?
429762
3) ~ whatever is handy! \n\nThough scarves and ties are nice ;)
545420
well im sure you know it is a penalty, but funny anyway. Even with a club foot if you had 14 clubs in your bag allready it was still a penalty.\n\nLeon
119914
Bookfinder has your book.
142869
Someone once gave me one of his books. Two years on, I still cannot go beyond page 1. Maybe it is just me...
639879
OMG. This is a riot!! Thanks for all the tips. Maybe I should print them out and slip them in my purse for emergencies???
573612
Oh was that a book name???????? Never heard b4 :)\n  Nops!
486620
Depends how much the books are worth.
245270
Good luck with your book proposals. If you happened to have stashed away some cash over those 7 years, you may want to self-publish your book (ex., "What Color Is Your Parachute?" was self-published).\nYou can try such publishers as "Cafepress.com","Lulu.com", and "Luniverse.com".
544182
3 books: "Running With Scissors," "Dry," & "Magical Thinking," all by Augusten Burroughs =]
54439
Since the book just was released today (2/13), I don't think the list will be readily floating around online (Then nobody would have to buy it).  I would say to go check it out at Borders or Barnes & Noble.\n\nI hope to buy it within a week or so, and will let you know if anyone from GA is in there.
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There are 8! different arrangements (permutations) of the 8 friends.\n\nThere are 4! different arrangements of the 4 boys.\n\nThere are 5 different locations where the leftmost boy can sit when the 4 boys sit together.\n\nTherefore, there are 5*4! (or 5!) arrangements of the boys where all the boys sit together.  But there are also 4! arrangements of the 4 girls in the remaining slots.  So there are 5!*4! arrangements where the 4 boys sit together.\n\nSince there are 8! arrangements overall, the probability of all boys sitting together is (5!*4!)/8!.\n\nSimilarly, if the boys sit to the left and the girls sit to the right, then the probability is (4!*4!)/8!.\n\nInterestingly, this last answer is also the same probability as boy-girl-boy-girl-boy-girl-boy-girl and also the probability of girl-boy-girl-boy-girl-boy-girl-boy.  Therefore, the probability of alternating seats is (2*4!*4!)/8!.\n\nRecall that n! (read n-factorial) is n*(n-1)*(n-2)*...*3*2*1.