5 days are 432000 seconds 4+3+2+0+0+0=9?\n13 days are 18720 minutes 1+8+7+2+0=18=1+8=9?\n55 weeks are 554400 minutes 5+5+4+4+0+0=18=9?\n68 years are 596088 hours 5+9+6+0+8+8=36=3+6=9?\ndoesnt metter witch day year or week calculate,but why is at end always 9? can someone me explain that?
207777
Yes, you manipulate the question to get the answer you want.\n\nWhy 5 or 13 days? What about 1 day, or 7 days?\nWhy 55 weeks? Why not 1 or 52?\nWhy 68 years?\nEtc.
618935
1) 3/4=9/12 and 1/3=4/12\n\n 9/12-4/12=5/12                                         \n\n7:25-7:05=5/12\n20=5/12\n\n5/12=15/36=20 minutes               \n1/3=12/36= 16 minutes      \n\n 7:05\n-   16                                          \n6:49         \n\nAnswer is 6:49!!!
10473
n^2 days = 7.46x10^9*n^2 seconds, so the question is asking to find the smallest value of n such that \n7.46x10^9*n^2 < 2^n.  For the first approximation, find\n2^n > 7.46x10^9\nln(2^n) > ln(7.46x10^9)\nn > ln(7.46x10^9)/ln(2) = 33.\nBut n^2 = 33^2 = 1089, which is about 2^10, so second \napproximation is 33+10 = 43.\n7.46x10^9*(43)^2 = 1.38 x 10^13\n2^43 = 8.8 x 10^12, the second algorithm is still faster.\nTry 44,\n7.46x10^9*(44)^2 = 1.44 x 10^13 sec\n2^44 = 1.76 x 10^13 sec.\nSo the answer is 44, and the time is 44^2 = 1936 days
306921
start with the easy ones... all of 2007 and 2008 (a leap year), so that is 365 + 366 = 731\n\nnow for 2009, 31 + 28 + 3 = 62\n\nfor this year, if you include the 20th you have 12 + 30 + 31 + 31 + 30 + 31 + 30 + 31 = 226\n\n731 + 226 + 62 = 1019 (take off one day if you dont count the 20th)
51771
last digit of 3^17=3 because 3^1=3,3^2=9,3^3=27,3^4=81.Then the last no.repeats four times.so 17/4=4&remainder 1.therefore 3^1=3 =last number.\nlast digit of  7^13=7 because 7^1=7,7^2=49,7^3=243,7^4=1701.Then the last no.repeats four times.so 13/4=3&remainder 1.therefore 7^1=7 =last number.\nTherfore last number=7+3=10.So last number =0
609282
a)7:30 + 3:42 =  11:12    Just add minutes it gives 72 but sixty minutes is an hour so 72 = 1 hour and 12 minutes keep the 12 in minutes section and carry 1 hour to hour section.7+3 =10\nAdd carry 1 you get 11.\n\nb) 18:30-3:42 =   14:48  ...Proceed similarly this time you need to borrow 1 from hours section that becomes sixty minutes subtract 42 from 60+30\n\nc)3+42/60 = 3.7 hrs\n\nd)370/3.7= 100 km/hr
480105
The easiest way is to figure the number of minutes (to get them the same), then figure the number of hours (to get them the same).\n\nFor example, you need to move from 10:30 to 11:15...\n\nMentally move the hand forward from 10:30 to 10:35, then 10:40, then 10:45, etc.  You'll see that to get to 11:15 you have to move *9* five minute increments.  (9 x 5 minutes = 45 minutes).  So now you have made the minutes the same :15 and :15.\n\nNext you need to go from 11:15 to 1:15.  You can ignore the minutes now... you should count two spots from 11 to 12 to 1.  That's 2 hours.\n\nSo your final answer is 2 hours and 45 minutes.
27573
According to my Excel Spreadsheet.\n\n03-20-08 minus 01-11-06 equals 799 Days\n\nIt is very easy. You must configure the first two cells as dates.\n\nBut then you have to format the resulting cell as a number
395097
Yes there is a better way than counting.\nBecause you have a leap year every four years, you can say that there are 365.25 days per year, as long as you deal in years that are multiples of four (which I will be doing). \n\nSo,  that means there are 52 + (1.25/7) weeks per year. \nThis is the same as 52 + (5/28) weeks per year. \nAs a top heavy fraction, this is 1461/28 weeks per year, and therefore there are 1461 weeks in 28 years. This is relevant because it is an exact number of weeks, the actual number 1461 doesn’t matter. This means that exactly 28 years ago, on 6 November, it was a Monday like it is today.\nSo, 6 November 1978 was a Monday.\n6 November 1950 was a Monday.\n6 November 1922 was a Monday.\n6 November 1894 was a Monday.\n\nWe have slightly overshot now, so we need to add on years. (I did this because it is easier to add than subtract, plus 1894 is closer to 1907 than 1922.)\nIn 4 years there are 208 weeks and 5 days (I found this by multiplying 52 + (1.25/7) by 4 to get 208 + (5/7) which is equivalent to 208 weeks and 5 days.)\n\nSo, 208 weeks after 6 November 1894, the date is 1 November 1898, also a Monday (because it’s an exact number of weeks later). 5 days later, it is a Saturday, on 6 November 1898.\nYou use the same process to find that it is a Thursday on 6 November 1902, and that it was a Tuesday on 6 November 1906.\n\nSince neither 1907 nor 1907 was a leap year (1904 and 1908 were), 365 days later it will be 6 November 1907.\n365 days is 52 weeks and 1 day. So, 52 weeks later, it is a Tuesday and the date is 5 November 1907, and the next day is 6 November 1907, and it’s a Wednesday.\n\nSo on 6 November 1907, it was a Wednesday.\n\nActually there is a slight problem with this method, because 1900 was not actually a leap year, but in this case it did not matter because the date is after 1900. You would have to adjust it very slightly for dates before 1900.
197381
Since a = 9-t,\nThen 4(9-t) = 8t-12.\nThen 36-4t = 8t-12.\nThen 12t = 48.\nSo t = 4.\n\nThus a = 9-t = 9-4 = 5.
535126
Try this online calculator-\n\nhttp://www.timeanddate.com/date/duration.html?ti=on\n\nFrom and including: Tuesday, June 30, 1998\nTo and including: Wednesday, February 14, 2007\n\nIt is 3152 days from the start date to the end date, end date included\n\nOr 8 years, 7 months, 16 days including the end date\nAlternative time units\n3152 days can be converted to one of these units:\n\n    * 272,332,800 seconds\n    * 4,538,880 minutes\n    * 75,648 hours\n    * 450 weeks (rounded down)
151200
it just has to do with our calender, there is always going to be the same days in november and march, bcause it is a constant. there are always the exact same number of days between mar and nov, and its devisible by 7, no weird things, just math, if we made weeks 6 or 8 days long, some other month would logicaly have the same days.
651149
Number of cells on the first and subsequent days:\n\nCulture X\n-----------\nStart              .                                 = 1200\nAfter 1 day        1200x 1.0125 exp1   =1215\n         2 days      1200x 1.0125 exp2   =1230\n         3 days       1200x 1.0125 exp3  =1245\n             and similarly for subsequent days\n\nCulture Y\n-------------\nNote that here we have a decay constant so we have to divide the values\n\nStart                                              = 1600\nAfter 1 day         1600/ 1.18 exp1    =1356\n         2 days       1600/ 1.18 exp 2   =1149\n        3 days         1600/ 1.18 exp3   =974\n        and similarly for subsequent days.\n\nIf you plot  these two sets of results on the same graph, putting the day on the horizontal axis and the daily counts on the vertical axis, the point of intersection is where they are equal.\n\nA brief  look at these results will show you that the answer will be "After about 1.5 days"  (the exact result is 1.62 days)
542616
Yes there is a formula for working it out. They do not actually remember every date and day. I have it in one of my books, I'll find it and add it here later.\n\nHere's a link to site that does the calculations.\nhttp://216.109.124.98/search/cache?p=how+do+i+work+out+what+a+day+of+the+week+was&prssweb=Search&ei=UTF-8&meta=vc%3D&fl=0&fr=ush-ans&u=www.nightmare-relm.co.uk/guest/birth.php&w=work+day+week&d=VgBk9JIFNyTS&icp=1&.intl=uk\n\nI'm still checking my books for the formula\n\nRight I'm back. I've found the answer. I\nYou have to memorise a lot of codes for different days and  months. It's too complicated to write here and I'm not sure that so-called "mindreaders" would be too happy if I gave away the secret.\n\nYou can by a CD with instructions on how to do it.\nhttp://www.world-of-magic.co.uk/magic.asp?id=16568\n\nSorry I couldn't be more help
514517
1000*365.25 = 365250 days\n\nbecause in i year it is 365 days and 6 hrs.\n\nso in 4 yrs we usually add one day and write 366 days \nit is known as leap yr.\n\nso practically in 1 yr  it is 365.25 days\n\nso in 1000 years it is 365250 days
231700
52x \n\nthere are 52 weeks in 1 year.  so you multiply 52 (the # of weeks by X the # of years
91785
TWO WAYS TO REMEMBER HOW MANY DAYS IN A MONTH\n\nA RHYME:\n30 days has September, APRIL, June and November.\nAll the rest have 31 except February alone which has 28 or 29 on a leap year.\n\nA STRANGE COINCIDENCE\nClench your fists and put your knuckles together side my side. The first knuckle on the left of your left hand is January, then moving to the right there is a dip, this is February, then there is the next knuckle, March, etc. until you get to December on the middle of your right hand. All the knuckles are 31 days and all the dips are 30 (except February, which is an exception, as above)