how much power does a tungsten bulb of zero watts 230 vots consume ?
214306
Apparently it's a 12 watt bulb, sold as a "zero watt bulb" (ref.). Go figure.
642321
V=IR\n\nWire 1:\n50 = 2 * R1 => R1 is 25 ohms\nCurrent = 2 amps\npower = V*I = 2*50 = 100 watts\n\nWire 2: \n100= 2* R2 => R2 = 50 ohms\nCurrent=2amps\npower = V*I = 100*2 = 200 watts\n\nare you looking for ratios when you say "compare" ?\nif yes: ratio of resistances is  1:2\nratio of currents is 1:1\nand ratio of power is 1:2
441362
Volts times amps = watts.
413758
It's several million, but it is the lens and reflector that do all the work.\n\nLight is measured in lux or illumination is, candle power is the equivalent of Mega  Tonnes when measuring nuclear yield.\n\nYou may find something here\nhttp://hypertextbook.com/facts/2005/DariaZainullina.shtml\n\nSome have 1000Watt bulbs which is only 10 times more than my bathroom light bulb.
312010
Hey, Benni.  When I was interning in the power industry I had to review some electric bills for a rather large office in downtown Chicago.  They were on the order of tens of thousands of dollars per month.  And this was not anywhere near what a stadium would use.\n\nI'll try to find some figures for you and will edit this post with sources when I find them.  Note that, for indoor stadiums, the cost will be much higher because of heating/cooling.\n\nUpdate: Below is the site of a stadium that says its bulbs are 1500W each.  Each pole looks to have about 12 bulbs.  There looks like there are at least 8 poles.  That's 144kW in lighting.  Assuming they're on for 5 hours a night, that's 720 kWh just in the lights every night that they're turned on.  At $0.05/kWh (they probably get a better rate than that), that comes to $36,000 per night.  Note that that doesn't include ANY other power sources, but is still a highly speculative number.  I'll let you know if I can find anything more definitive.\n\n2nd Update:  The Baltimore Ravens' stadium has two jumbo screens that can consume up to 80 kW.\n\nFinal Update:  The New York Giants' stadium consumes enough power to run 4,000 homes on gameday.  Assuming a typical home uses 800 kWh / month, that is about 1 kW at any given time, which means their stadium uses about 4 MW on gameday.  Assuming this lasts for 5 hours, that's 2000 kWh in one day.  Not a bad number with the above lighting (for a smaller stadium) listed at 720 kWh...  At $0.05/kWh, that's $100,000 every game.  I also came across a site which said Penn State university's electric bill is over $1 million each month.\n\nUpdate on your question:  My above calculation is incorrect.  If a stadium uses 4 MW on gameday for 5 hours, it uses 20,000 kWh on that day, which is then $1,000 at $0.05/kWh.  I think the number is conservative, though.  Sorry for the misunderstanding!
134949
Its impossible to tell how many watts the computer is consuming by a program, but there are ones out there that can tell you the voltage.  this is what you need to know.  as far as if you power supply is powerful enough, anything of 450 should be more than enough unless you have some kind of huge amazing rig setup.  Mine is 500 and Im powering 3 hard drives with it.
155854
No.  This is an old "urban myth."  The amount of energy used by the bulb is the rated watts.  So, for an equal number of lumens [the "brightness" of the bulb] fluourescent lamps use fewer watts.  And if you're buying a new fixture, check to see the different color ratings of fluouresecent bulbs, too.  They don't have to make you look like a corpse anymore.\n\nAnother way to look at it is that incandescent lamps use resistance to overheat a solid chunk of metal until it glows.  That takes a lot of energy. Fluourescents send an electrical charge through a cloud of gas to excite individual molecules.  I'm not a physicist, but that sounds a bit easier to do.
219095
1.80 or 120\n2.bcuz u need 1 to hold the lightbulb, and 99 the rotate the house. lol im a blonde! =-)\n3.One says "cockadoodledoo" and the other says "any cock'll do"
360713
I kept reading anyway.\n\nThe heater is already telling you the power consumption.\n900W = 0.9 kW\nTherefore running the heater for one hour uses 0.9 kWH.\n\nYour formula is wrong. Watt/1000  * cost/kWH = cost per hour\n\nFor heaters, it is true that Volts * Amps = Watts.\nTherefore if you know the supply is 120V and the power is 900W, you can calculate that the current load is 7.5 A.
418476
1500 Watts / 170 Watts per panel = 8.8 panels.\n\nFigure on 9 panels.  The next issue is whether to wire them in series for higher voltage or parallel for higher current.  But that depends on the rest of the system.
398368
P = FD/t = 300*9.8*5/8 = 1837.5 Nm/sec = 1.8375 kw
75109
Correction to Ra.Ge's answer. 220 vac is the rms value; the peak is sqrt(2) * 220. (See ref.) But the power factor information is correct. Assuming the guess of a 0.9 PF is good, the power is 7920 watts and the total consumption is 6083 Kwh. I hope this beast isn't really drawing that power all the time. If you have the fan set to continuous running, the compressor might be running only intermittently which brings down the net consumption.
152800
I heard of a way of producing an electric courant by heating on side of a PN jonction made of two different type of metal. \nI also saw a alcool lamp with a collier all around that was producing enough electricity for a radio, that was realy long time ago ( may be 60 years ), that collier was made with near an hundred piece of two metal in alternance, and each jonction was a thermal diode.
183588
Electricity is charged by the kilowatt (1000 watts) hour.  A 60 watt bulb uses 60/1000 hr. That's .06 times price per KWH.
375347
Of course.  But before doing that check the currents that are required for the load.  Usually, appliances running at 12 VAC are also low power, and those that run at 230 VAC are high power.
469637
An average TV runs about 60 watts... your average light bulb. Your computer burns about 1/2 of that... now, that can depend on what you have running in it, and if your monitor is LCD or CRT (projection). Laptops take very little power at all.
270066
Hmm, I knew that one horsepower was equal to 746 watts, but I didn't know the original definition.  From Howstuffworks, 1 horsepower is equal to 33,000 ft-lbs of work in one minute (or as the example in the link says, lifting 330lb of coal 100ft in a minute).  Interesting.\n\nAnyway, a motor's power output rating on the nameplate should be equivalent regardless of the voltage it uses.  The only difference will be that the 110 volt motor will draw more current than the 550 volt motor given the same loading (edit: and motor efficiency).