I first thought it was grep -v " " samplefile > samplefile2\nbut it didnt work.
203831
grep -v "^$" filename > newfilename\n\nThe ^$ within the quotes is a regular expression: ^=beginning of line, $=end of line, with no characters between.
194164
At the shell prompt '$ ' use the commands:\n\n$ # save the original file\n$ mv mydocument mydocument.bak\n$ # censor the naughty words\n$ # the following should be all on one line\n$ gawk -v WORDLIST=wordlistpathname ... mydocument.bak > mydocument\n\nwhere ... (just type it on the command line) is the multiline gawk (GNU awk) or awk script shown below:\n\n'\nBEGIN {\n  while ((getline word < WORDLIST) > 0)\n  {\n    naughty[word] = 1\n  }\n}\n\n{\n  # no leading space before\n  # first output word on line\n  sep = ""\n  for (i = 1 ; i <= NF ; ++i)\n  {\n    if (naughty[$i] == 1)\n    {\n      printf "%s%s", sep, $i\n      # leading space before next\n      # output word on line (if any)\n      sep = " "\n    }\n    else\n    {\n      # do not leave in the null\n      # table entry just added\n      delete naughty[$i]\n    }\n  }\n  printf "&#92;n"\n}\n'\n\n1. My pretty indentation is going to be completely removed by the time you read this.  I don't know how to prevent that on Yahoo Answers.\n\n2. The top and bottom single quote characters are part of the command line!\n\n3. The word list file is assumed to have one word per line.\n\n4. White space in the original document is not preserved -- leading and trailing white space is remove and between word whitespace is collapsed to a single space.\n\n5. No stemming, case folding, regex matching is done in comparing a word in the document to a word in the naught word list -- only an exact match is suppressed.
356293
ok if you go srart-run you don't type the name what it looks like the file has different name which it runs. so go to property of the main icon of the program and you will see the name just type that name and it will run
432594
May be ur stored the file in a different package name , in that case u need to execute the java command as\n\n                      java pkgname.filename\n\n\n  or if it is in a different folder thn change the current directory to that folder and execute from there
51252
var fileName =\nlocation.pathname.substring (location.pathname.lastIndexOf ('/')+1)\nalert(fileName);
104730
try terminating "exeplorer.exe" and deleting the file using DOS commands. That worked for me.
188665
#include <stdio.h>\n#include <stdlib.h>\n\nint\nmain(int argc, char* argv[])\n{\n  int count = argc>1 ? atoi(argv[1]) : 10;\n  FILE *f = fopen("numfile", "w+");\n  if (!f)\n    perror("fopen"), exit(-1);\n  for (int i=0; i<count; i++)\n    fprintf(f, "%d&#92;n", rand());\n  fclose(f);\n  return 0;\n}
204550
find it in your diectory. C:disc
201578
If you aren't sure of this file. DELETE it. Could be a virus.\n\nIf file name make some sense to you, extract and see the contents.
315213
You can use a combination of the find command along with wc.\n\nThe format for find to recursively list all filenames in a folder is:\n\nfind (directory) -type f\n\nThe wc command with the -l switch (that's a dash and lowercase L) will count the number of lines.\n\nIf you pipe the output of the find command to wc it will give you the number you're looking for.  An example with a real directory name would be:\n\nfind /home/martin/docs -type f | wc -l\n\nThis insures you will only get files.  If you use something like ls -R your count will include folders.
300313
Here's one way:\n\n#!perl\n\nwhile(<>) {\nif($_ =~ m/abxy$/) {\nchop;\nprintf("$_ -- $.&#92;n");\n}\n}\n\nTurn this into a perl file (say findinline.pl) then run\nPerl findinline.pl somefile\n\nAny qualifying line will print out followed by the line number.
138239
Try this\n\nusing System.Diagnostics;\n\n\nstring Path_of_PDFFile;\nPath_of_PDFFile = <PATH>; //Remember to use // instead of / when setting path.\n\nProcess.Start(Path_of_PDFFile);
491572
Best bet is to use \n\nbc filename >outfile\n\nIt won't give you exactly what you want but will be close
635240
Try putting the name in quotes.  If that doesn't work, you might need to use an escape sequence for the -, like "&#92;-o".  If neither of those work, you might be able to delete it by doing "rm ?o"; of course, you'll lose the file this way, and you can't have any other files that are 2 letters long with the 2nd letter an o.\n\nIf you need to preserve the file, you can write a program to rename it.  Since from within a program, it won't try to use the -o as a parameter, you can open a file with any name.\n\nI'm surprised Unix even allowed you to create a file with a - in the name; I thought that was one of the restricted characters.
114802
Try the following:\nchar str [255];\nchar s_wrd1[80];\nchar s_wrd2[80];\nchar s_wrd3[80];\n\nfscanf(tFile, "%s", str);\nsscanf(str, "%s %s %s", s_wrd1, s_wrd2, s_wrd3);\n\nThe first 3 words will be stored in s_wrd1, s_wrd2 and s_wrd3 variables.\n\nAbout the hard return, it doesn't matter whether you have it or not.
220399
A text file with the .BAT extention. \n\nIt will then be executable, and run the commands listed in the file in order via DOS prompt.
675475
What do you mean with "invisible file"? Before using sed, you have to get a list of the files, correct? So, if you are you refering to files in your list starting with a dot . mask the first . using a slash (like this:  &#92;. )