1. The least common multiple of 3, 4, 6, and 8 is \n\nA.8.\nB.24. \nC.72. \nD.96. \n\n2.  You're planning to buy a boat, a motor, and some miscellaneous boating equipment. The boat costs $325, the motor costs $225, and the equipment costs $79. If you've saved $438 toward these purchases, how much more do you need to save? \n\nA.$181 \nB.$191 \nC.$281 \nD.$291 \n\n3.   Write 1,386 as the product of its prime factors. \n\nA. 2x693 \nB. 2 x 3 x 231 \nC. 2 x 3 x 7 x 33 \nD. 2 x 3 x 3 x 7 x 11  \n\nAny boody who makes it thanks. And people who thinks its my homwork please dont respond because your wrong its not my homework. Thanks
218510
Tell you what you post your answers and I'll tell you if you're right!
236531
(a)\nC = mx + b\nC = 10x + 40\n(where fixed cost could be due to the cost of the workers or rental of the factory...)\n(The variable cost is the cost required to make 1 item)\n\n(b)\nR = 50x\n(The revenue, money collected, from selling x items is 50x.\nSo if you were to buy 1 item, you would pay $50\nand if you were to buy 3 items, you would pay $150.)\n\nRevenue = Cost\nR = C\n50x = 10x + 40\n50x - 10x = 40\n40x = 40\nx = 40/40\nx = 1\n\nThe selling of 1 item would result in the break-even point.
552029
1. Bob's favorite ice cream used to cost $1.50.... Then the price was raised to $1.75. Find the percent increase.\n(175/150)-1)*100%=16 2/3% increase\n\n2. Jenny paid $12,000 for her car. Five yrs later she sold it for $8500. What percent decrease was this?\n(8500/12000-1)*100%= -29 1/6% 29 1/6% decrease\n\n3. The Music Box marked up their CD's 75%. If the music box charges $20 for a special cd, how much did it cost before the mark-up? (hint: the answer is not $15)\n$20=1.75x\nx=20/1.75=$11.43\n\n4. Quinn deposits $2000 in a savings account that pays 4% compounded semi-annuallly. HOw much money will Quinn have in her account after two years? Give the expression. (you do not have to simplify) \n\n$2000(1.02)^4=$2164.86
235549
Look for "least common multiple" of 8 and 10 and you get 40.  \n\n8*5=40 and 10*4=40 \n\nso m=5 and n=4. \n\n5+4=9, thus m+n=9.\n\nThis is the only solution since it asked for the LEAST positive integers.  Although 10 and 8 would work as well, they would not be the LEAST positive integers, thus NOT a solution! Also decimals are NOT integers, so you can't use decimals in solution.\n\nHope I explained it well...\n\nGood luck.
532647
Simply multiply\n9 * 8 * 7 * 6\nBecause the first number can be 1-9 but not zero and the second number can be 1-9 but one number has already been used and so on and so forth.\nHope it helps.
485271
8 numbers can be placed  in 8! ways.\nExchange the three two's gives no new numbers, so divide by 3!\nExchange the two six's gives no new numbers, so divide by 2!\n8! / ( 3! x 2! ) = 1680\n\nTh
260349
3 is A $4,187 and 4 is D $6.08
479275
1. 3 of you went with $ 10 each , so you have 10*3 = $ 30.\n2. There is a bill for $ 30 with $ 5 discount, so you have to pay $ 25.\n3. You can not devide 5 in 3 pars so you give away $ 2 at tip.\n4. The amount spent mounts to $ 25 +$ 2 = $ 27.\n5. You are left with $ 3, which you devided in 3 parts. So, all of you have $ 1 each.\n\nNow, if you see the question in perspective of one of the 3 people. The addtional $ 2 are spent in giving away the other 2 frineds their share of $ 3 left. \nSo, in this case the dollar left is with you.\n\nEnjoy the dollar.
481119
1. fourteen minus the product of 3 and a number is 26\n14 - (3n) = 26\n14 - 26 = 3n\n-12 = 3n\nn = -4\n\n2. negative seven minus the product of 5 and number is 28\n -7 - (5n) = 28\n -7 - 28 = 5n\n -35 = 5n\nn = -7\n\n3. eleven minus the quotient of a number and 8 is 15\n11 - (n/8) = 15\n11-15 = (n/8)\n-4 = n/8\nn = -32\n\n4. negative sixteen plus the quotient of a number and 2 is 35\n-16 + (n/2) = 35\nn/2 = 35 + 16\nn/2 = 51\nn = 102
294689
1.  .35 x 400 = 140\n2.  .22 x 400 = 88\n3.  .16 x 400 = 64\n4.  .32 x 50 = 16\n5.  .25 x 50 = 12.5\n6.  .1 x 50 = 5
420160
Let us call the first 2 "2 sub 1", the second "2 sub 2" ... same thing for the 6's.\n\nLet us say that "2 sub 1" is distinct from "2 sub 2", and so on.\n\nWe have 8 choices for the first number, seven choices for the second number, etc. This means that there are 8*7*6*5*4*3*2*1 choices, or 8!. \n\nNow if you look at any number, take all of the 2's out. You see that you can rearrange the 2's in 3! different ways (including the original arrangement) using the procedure in the paragraph above. If we take out the 2's rearrange them, and put them back in we have created the a new arrangement. So for each arrangement of numbers, we have counted it 3! times. So we divide by 3!. The same thing for the sixes, we divide by 2!.\n\nThe result it (8!)/((3!)(2!)) = 3360 choices.
281068
b)two, but only if you are looking for specific Numbers to complete the table.\nThe two would have to be in different row\nYou have 6 blank spaces on the table. \nIf you have one more number given you can find the other column by subtraction.\nIf you have two more numbers given you can find the other row and Column by subtraction.\n\nI can complete the table right now you take 36/64=.5625\nso I use the equations  \n.5625C2+C2=53 1.5625C2=53 53/1.5625=C2=33.92\n.5625C2+C2=26 1.5625C2=26 26/1.5625=C2=16.64\n.5625C2+C2=21 1.5625C2=21 21/1.5625=C2=13.44\nC1=53-C2=19.08\nC1=26-C2=9.36\nC1=21-C2=7.56
446734
1.\nn | n + 20\n------------\n0 | 20\n1 | 21\n2 | 22\n3 | 23\n4 | 24\n\nn | 3n - 35\n-------------\n1 | -32 \n2 | -29 \n3 | -26 \n4 | -23
345241
Mode: $3\nReason: There are 2 threes and 1 six. The most frequent is three. (2>1) So your answer is $3\n\nMead? Do you mean Mean?\n\nMean: $4\nReason: 3+3+6=12 For the total\nThen you divide by how many you coupouns you have to find the average, or AKA mean. That would be 12/3=4\nSo $4 is your answer
435671
OK,as the first one is already done,I am doing the rest for you\n4(2x-6)=x+2 =>8x-24=x+2  =>8x-x=2+24  =>7x=26  =>x=26/3=8 2/3  (3) 2(x+5)+1=3(x-1)+4   =>2x+10+1=3x-3+4 =>2x-3x=-3+4-10-1  => -x=-4  =>x=1  (5)x+6=4(4x-1)   =>x+6=16x-4  =>x-16x=-4-6  => -15x=-10  =>x=-10/-15=2/3 [after reducing]
415285
Answer 1:\n8y+6=3\n8y = 3-6\n8y = -3\ny = -3/8\n\nAnswer 2:\n3b+14=5b\n3b = 5b -14\n3b - 5b = -14\n-2b = -14\n2b = 14 (Minus signs cancel each other out)\nb = 14/2\nb = 7\n\nAnswer 3:\n4.5m-3=2m-0.5\n4.5m = 2m -0.5 + 3\n4.5m - 2m = 2.5\n2.5m = 2.5\nm = 2.5/2.5\nm = 1\n\nAnswer 4:\n7.3m-16=m+0.38\n7.3m = m + 0.38 + 16\n7.3m - m = 16.38\n6.3m = 16.38\nm = 16.38/6.3\nm = 2.6\n\nAnswer 5:\n18n+2n=6n+11.2\n20n = 6n + 11.2\n20n-6n = 11.2\n14n = 11.2\nn = 11.2/14\nn = 1.6/2\nn = 0.8
189302
Problem #1:  Four consecutive integers have sum of -34.  Let the first integer be x.  The next three must be x+1, x+2, and x+3.  This gives you the equation\n\n-34 = x + x+1 + x+2 + x+3\n-34 = 4x + 6\n-40 = 4x\nx = -10\n\nSo, the 4 consecutive integers are -10, -9, -8, and -7.\n\nProblem #2:  Again, four consecutive integers can be written as x, x+1, x+2, and x+3.  This time the equation is:\n\n4(x + x+3) = 24 + 6(x+2)\n4(2x + 3) = 24 + 6x + 12\n8x + 12 = 6x + 36\n2x = 24\nx = 12\n\nSo, the 4 integers are 12, 13, 14, and 15.  \n\nIt pays to check your answers:  The sum of the first and fourth is 12+15=27.  Four times this sum is 108.  6 times the third integer is 6*14=84.  108 is 24 greater than 84.