shelly ran 2 1/4 miles  lynne ran 3 1/8 miles who ran farther\nany by how much\n\na) shelly by 7/8\nb) shelly by 3/4\nc) lynne 7/8\nd) lynne 3/4
202962
c is the answer\n\nput it as 9/4 miles for shelly and 25/8 miles for lynne\nmultiply 9/4 by 2 to get a common denominator of 8 for both fractions\n25/8 - 18/8 = 7/8
137884
Let t be the time it takes for Denise to catch Gloria expressed in hours.\n\nGloria will have been walking for (t + 1/2) hours, at 3 mph\nso she will have gone (t+1/2) * 3 miles.\n\nDenise will have been jogging t hours at 5 mph, so she will have gone 5t milse.\n\nSince they are at the same place, the distances will have to be the same: 3(t+1/2) = 5t\n\nSolve for t:\n3t + 3/2 = 5t\n\n3/2 = 2t\n\n3/4t = t\n\nCheck Denise goes 3/4 * 5 = 15/4 miles\n\nGloria goes (3/4 + 1/2) * 3 = (5/4) * 3 = 15/4 miles\n\n\n\nIf you have a square, and you triple the length of the side,  the resulting square has an area that is 9 times that of the original square.  The same thing works for all figures in the plane. If you enlarge them by a factor of 3, the area grows by a factor of 9.   \n\nIf you were to break the star down into a collection of triangles, and analyzed the area of each one, you would see that you were multiplying the base and altitude of each triangle by a factor of three, so you are multiplying the area of every one of the pieces by 9. So 90 is your correct answer.
441184
Answer: 4PM\n\nSouth<=======Start======>North\n4PM===3PM===1PM==3PM===4PM\n120 M==60 M===0 M==110 M==165 M\n\n120 Miles +165 Miles = 285 Miles
344410
I think the easiest to look at this one is:\n\nAt 48mph, the Smiths cover 4 miles in 5 minutes.\n\nAt 60mph, the Garcias cover 5 miles in 5 minutes. \n\nSo, every 5 minutes, the Garcias get 1 mile closer to the Smiths.\n\nThe Smiths started 20 minutes before the Garcias, so they were 16 miles down the road when the Garcias started.  Therefore, the Garcias needs 16 * 5 = 80 minutes to catch the Smiths.
428707
Distance = Speed * Time.\nWe don't know the "distance" variable for either. We need to find the "time" at which the "distance" will be the same. Let distance = d\n\nWe want to find Thomas's time, so let Thomas's time = t.\nAlexis left 3 hours earlier, so her time is t + 3.\n\nThomas speed is 30, Alexis is 20. So lets fill this in.\nThomas:\nD = 30t\nAlexis:\nD = 20(t+3)\n\nThe distance will be the same, so the D in both equations is the same variable. A basic principle is that if a = b and b = c, then a = c.  Therefore, we can combine the equations for the two people as follows:\n30t = 20(t+3)\n30t = 20t + 60\n10t = 60\nt = 6 hrs\n\n\nThe same applies to the second.\nTimothy:\nD = 58t\nSavanah:\nD = 47(t+2)\n\n58t = 47(t+2)\n58t = 47t + 94\n11t = 94\nt = 8 6/11 OR 8.5454545454545\nt = 8 hours, 32 minutes, 43 seconds\n\n\n\nThe last one is slightly different.\nJet 1 Distance = 331t\nJet 2 Distance = 333t\nThe two distances aren't equal this time, but the two distances added up will equal 1,705, SO:\n331t + 333t = 1705\n664t = 1705\nt = 1705/664 = 2 377/664 = 2.56777108\nt = 2 hrs, 34 minutes, 4 seconds
41156
Heather leaves a town at 2 p.m., going 56 mph, traveling east. Erin leaves the same town at the same time going 64 mph, traveling in the same direction. What time of day will it be when Erin is 72 miles ahead of Heather?\n============================================================\n\nHeather's distance = 56x\nErin's distance = 64x\nx = hours traveled\n\nThe distance between them at any time can be expressed as a simple equation:\n\nd = 64x - 56x\nd = 8x\n\nYou want to find "x" when d = 72 miles:\n\n8x = 72\nx = 9 hours\n\n2:00 p.m. + 9 hours = 11:00 p.m.
670501
21\nLets do this problem in reverse order.\nAfter giving 1/3 to her brother she is left with 6.\nThat means she has 2/3 of what she had.\nthat means she had 3*6/2 = 9 raisins before she gave it to her brother.\nNow add one she ate. So 10.\nNow she gave half to her sister that means she had 20.\nAdd 1 which she ate before that... so 21.
532678
d la mas alta\n\nmaria is____\na shortr than ana (x)\nb the shortest (x) (paula is the shortest)\nc more shorter than paula (x)\nd the tallest\ne more shorter than ___? I assume you meant to put ana, but still no. (x)\nf none of the above
520743
t = d/r\n\nAndrei: t = 50/7.7 = 6.49 sec\nBrother: t = 45/6.5 = 6.92 sec\n\nSo Andrei wins\n\nBrother runs 42.21 m (6.49 x 6.5) so he still had 2.79m to go\n\n(rounded answers ok I hope)
62398
Problem 1:\n\nSITA = 12 WINS\n\nGITA = 20 WINS (SINCE SITA HAS TO GIVE HER 8 CHOCO AT THE  \n       END OF ALL GAMES)\n\nTOTAL = 32 GAMES = 32 DAYS\n\nTHEREFORE, SITA STAYED 32 DAYS AT GITA'S HOUSE.\n\nProblem 2:  \n\nMMMMM...@#$%&*...ZZZZZZZ....SNORE....????\n\nProblem 3\n\nC - is the reference point. He is in third place.\n\nA - he can either be in 1st or 4th place only since he is \n  to be followed by E. If he is in 1st place that would \n  make him a liar which means that he should not be in 1st \n  place. Therefore, he must be in 4th place.\n\nE - follows A, therefore, he is in 5th place.\n\nB -is in 1st place (gold). Liar. So he must be in 2nd place.\n\nD - is not in 1st place (silver). Another liar. So he must be in 1st place. Also, that is the only remaining place.\n\nSo the correct order (From 1st place to 5th place):\n\nD - B - C - A - E
50512
A: 2 PPL HAVE SAME GENDER\nB: 2 PPL HAVE SAME BIRTHDAY\n\n\nP(A) = 90/190\nP(B) = 365/365 X 1/365 = 1/365\n\nP(AnB) = P(A) X P(B) = 90/190 X 1/365 = 0.001
311878
1. A & B cross  -  2\n2. A returns    -  1\n3. C & D cross  -  10\n4. B returns    -  2\n5. A & B cross  -  2\n\nTotal minutes: 17\n:)
153796
M = Martina's distance from home at time t, in hour.\nM = 24t\n\nJ = John's distance from home at time t, in hour.\nJ = 48(t - 2) \n\nWhy (t - 2)? because, John started 2 hours later.\n\nThus, when " john catch up with Martina" means that their distance from home is equal. Thus, \n\n24t = 48(t - 2)\n  t = 2t - 4\nor t = 4.\n\nThis means 4 hours from the time Martina's leaves home, John, would have caught up with her. The time is just 4 hours after 9 am, i.e, 1 pm.\n\nRegards
356397
becareful. I knew a girl that ran 2:15 in the 6th grade... Never got any faster... don't burn her out
142473
Let x = Eloise's time\nChristian's time = x-3\nsince Chistian's time is three hours less than Eloise's time\nNow distance equals rate times time or\nd = r*t\nFor Eloise r = 15, so d = 15x\nFor Christian, r = 30, so d = 30(x-3)\nThese distances are equal so\n15x = 30(x-3) \nDistribute 30\n15x = 30x - 90  \nSubtract 30x from each side\n-15x = -90 \nDivide both sides by -15\nx = 6\nThus, they traveled\nd = 15x\nd = 15(6)\n= 90 miles
59031
1. Second\n2. Depends in what position you are when you lap the last person - you stay in the same position (e.g. if you were first you'd still be first; if you were second you'd still be second, etc\n3. 4100\n4. Mary
229726
Say she was asleep for 20 miles.  She still would have ten miles left, as 10 is half of 20.  So before she fell asleep she still had 30 miles to go.  But that was halfway through the trip, so the trip was 60 miles.  She slept for 20 of the 60 miles, or 20/60 (reduces to 1/3) of the trip.