I want to have 3 DropDownlist Control A B C\nwhen I chose something from A then B showing the content and when I choose something from A & B then I choose content of C.\nC depend on B and B depend on A. What should I do.
207171
Write code in index changed event of A and B drop downs.
416002
My biology teacher taught it as the Independent variable being the thing I control. The I in independent with the I in I helps me remember.\n\nAnd then the dependent variable depends on the independent. It's the thing you're looking for the change in.
584354
Hey.\nIf you want to really get your page really layed out the way you want, you will have to use tables.\n\nDraw the entire layout using tables (probably in dreamweaver) and then drag and drop controls where you want.\n\nAs for the login control, you will need to set up a database in the backend and let asp.Net 2 create the necessary tables it needs.\nWe use SQL Server for this.\n\nYou can do it with access I guess, but I wouldn't recommend it.\nTo set up asp properly (make it create the tables and stuff for membership), run this command from the Visual Studio 2005 command prompt : \naspnet_regsql
654069
A data bound list control that displays the items from data source in a table. The DataGrid control allows you to select, sort, and edit these items.\n\nFor a list of all members of this type, see DataGrid Members.\n\nSystem.Object\n   System.Web.UI.Control\n      System.Web.UI.WebControls.WebControl\n         System.Web.UI.WebControls.BaseDataList\n            System.Web.UI.WebControls.DataGrid\n\n[Visual Basic]\nPublic Class DataGrid\n   Inherits BaseDataList\n   Implements INamingContainer\n[C#]\npublic class DataGrid : BaseDataList, INamingContainer\n[C++]\npublic __gc class DataGrid : public BaseDataList, INamingContainer\n[JScript]\npublic class DataGrid extends BaseDataList implements\n   INamingContainer\nThread Safety\nAny public static (Shared in Visual Basic) members of this type are thread safe. Any instance members are not guaranteed to be thread safe.\n\nRemarks\nUse the DataGrid control to display the fields of a data source as columns in a table. Each row in the DataGrid control represents a record in the data source. The DataGrid control supports selection, editing, deleting, paging, and sorting.\n\nDifferent column types determine the behavior of the columns in the control. The following table lists the different column types that can be used.\n\nColumn Type Description \nBoundColumn  Displays a column bound to a field in a data source. It displays each item in the field as text. This is the default column type of the DataGrid control. \nButtonColumn  Displays a command button for each item in the column. This allows you to create a column of custom button controls, such as Add or Remove buttons. \nEditCommandColumn  Displays a column that contains editing commands for each item in the column. \nHyperLinkColumn  Displays the contents of each item in the column as a hyperlink. The contents of the column can be bound to a field in a data source or static text. \nTemplateColumn  Displays each item in the column following a specified template. This allows you to provide custom controls in the column. \n\nBy default, the AutoGenerateColumns property is set to true, which creates a BoundColumn object for each field in the data source. Each field is then rendered as a column in the DataGrid control in the order that each field appears in the data source.\n\nYou can also manually control which columns appear in the DataGrid control by setting the AutoGenerateColumns property to false and then listing the columns that you want to include between the opening and closing <Columns> tags. The columns specified are added to the Columns collection in the order listed. This allows you to programmatically control the columns in the DataGrid control.\n\nNote   The order that the columns are displayed in the DataGrid control is controlled by the order that the columns appear in the Columns collection. Although you can programmatically change the order of the columns by manipulating the Columns collection, it is easier to list the columns in the desired display order.\nExplicitly declared columns can be displayed in conjunction with automatically generated columns. When using both, explicitly declared columns will be rendered first, followed by the automatically generated columns.\n\nNote   Automatically generated columns are not added to the Columns collection.\nThe appearance of the DataGrid control may be customized by setting the style properties for the different parts of the control. The following table lists the different style properties.\n\nStyle Property Description \nAlternatingItemStyle  Specifies the style for alternating items in the DataGrid control. \nEditItemStyle  Specifies the style for the item being edited in the DataGrid control. \nFooterStyle  Specifies the style for the footer section in the DataGrid control. \nHeaderStyle  Specifies the style for the header section in the DataGrid control. \nItemStyle  Specifies the style for the items in the DataGrid control. \nPagerStyle  Specifies the style for
199782
You do it like this:\n\nDim objItem As New ListItem()\n\nobjItem.Text = "Text To Appear"\nobjItem.Value = "Value of Selection"\nMe.uiNameListBox.Items.Add(objItem)\n\nobjItem.Text = "Second Text"\nobjItem.Value = "Second Value"\nMe.uiNameListBox.Items.Add(objItem)\n\nand so on, and so on.
63444
For firefox and IE you may need to develop 2 seperate toolbars. For firefox, check http://developer.mozilla.org/en/docs/Building_an_Extension\n\nand for IE check\nhttp://msdn.microsoft.com/library/default.asp?url=/workshop/browser/ext/tutorials/button.asp
261637
if you want to create content that is dynamic in nature (pulling from a database), then you will need to code in php, asp, asp.net, etc...\n\nyou should buy a book.  it will make it easier to learn.  i recommend the Sams Teach yourself in 24 hours/21 days series.  They are great for beginners.
304023
You would need a RichTextField Control instead of a normal one unless you are willing to build it from scratch
131105
Yes you can. ASP.NET has a lot of library, and one of them is the API to deal with creation/manipulation.\nThis link might help you: http://www.w3schools.com/aspnet/aspnet_xml.asp
388282
no there is no other way but to write code for each lines. because each form will open by its own place and its target place. all form are not going open by one button, so you have to write codes therefor every single form. and another thing is you cant not setup property all at a time.
285930
The following site not only explains to you the use of Multiple Design Templates but also has a presentation on the process.  Good luck! \n\nhttp://www.webmayfair.com/easilyexpandyourdesignoption.htm
8988
What you're looking for is something called a Browser Helper Object (BHO) ...  The process is rather elegantly explained on the Microsoft web site.  See the attached source.\n\nedit - I also should mention that the easiest and most straightforward way to use the Toolbar control is through the ASP.NET forms designer in Visual Studio .NET.  To use a Toolbar on a web form, drag it onto the form as you would any other control.
431490
You nailed it. They're called drop down boxes: Heres a sample code:\n\n<form id="color" name="color" method="post" action="yourform.php">\n<label>Color\n<select name="select">\n<option>Red</option>\n<option>Blue</option>\n<option>Green</option>\n<option>White</option>\n<option>Black</option>\n<option>Orange</option>\n</select>\n</label>\n</form>
356299
you need to access that control and get the relevant check box. if you are using a checkboxlist you can access it by using\n\ncheckboxlist.selectedValue.Text should give you what you selected.
204413
Controllers are classes in ASP and VB, so u kan just make classes in PHP and u will get the result...
452691
For your listbox control selections try the SelectedItem property instead of text.\n\nIntsum = intsum + Val( me.listbox1.SelectedItem ) * Val( me.listbox2.SelectedItem )\n\nAlso, the argument for the While method should be:\nintx <= listbox1.Items.Count
70722
If I understand you correctly...You have 3 frames.  One of the frames is a sidebar.  One is where the content is.  When you select a link on the sidebar, you want the page to pop up on the content frame...Ok, here's what you do:\n\nWhen you declare your frames, use the name attribute:\n<frame src="PAGE HERE" name="display"> (Where display can be any name you want)\n\nOn your sidebar links, add the target attribute:\n\n<a href="PAGE HERE" target="display">....</a>\n\nI hope that's what you're looking for.