You learned that S waves are stopped by liquids. Verify this for yourself and give a reason for what you see.\n\nFill up your tub with about 3 inches of water and drop a light object into the water. Watch what happens to the ripples (waves) that form. Describe what you see and try to come up with an explanation of why it happens.\nPlease explain why are S waves stopped by liquids
216259
"S-waves" are shear waves, wheras "P-waves" are sort of push-waves (essentially).  So because fluids are umm... fluids, you can't shear them.  Shearing is when you deform something by applying unequal stresses from three dimensions.  With a fluid, such a stress would make no difference, because fluids cannot be deformed, they meerly move.  This is why an S-wave that hits a fluid will only be propigated as a P-wave!  Weee!
266450
Generally, small angular waves are an indication that something in the water is moving just below the surface and can be attributed to some form of water organism.  This can range from water bugs to minnows to fish or whales.  \n\nEven in very small puddles I have seen very small water beetles.  It usually takes about two to three days for them to begin to appear.\n\nIf you want to perform an experiment to see if the "currents" are created by water based organisms or not try filling a small wading pool with a few inches of water and covering it with a tarpaulin or some other cover for about two weeks.  At the same time fill a second small wading pool with water of a few inches depth and leave it uncovered for the same time period.  After two weeks have gone by you should begin to see the "currents" you asked about.  If you take the cover off the "control" pool and look you should not see these same "currents".  (Just be sure that there are no winds or breezes when you are performing your observations.)\n\nDave Cooke
170261
Tsunamis fall into a wave physics category called long waves, also known as shallow water waves.  This type of wave is characterized by a wavelength that is much larger than the water depth.  In the case of tsunamis, their wavelength might be 500 km versus, for example, a 4 km ocean depth, so even though 4 km is "deep", the waves are technically "shallow water waves".\n\nAccording to the sources I have included below, the velocity of shallow water waves does in fact vary according to the water depth.  According to the NOAA site, "The speed of a shallow-water wave is equal to the square root of the product of the acceleration of gravity (32ft/sec/sec or 980cm/sec/sec) and the depth of the water."  Therefore, the longer the wavelength, the faster the wave.  Since tsunamis have very large wavelengths, their speed is large.\n\nThe ripples on a pond that we're all so familiar with are technically short waves, or deep water waves, because the wavelength of the waves is not substantially larger than the depth of the water.  In this situation, the wave velocity is relatively constant for the wavelengths we typically see on the surface of a pond or bathtub, but according to the sources below, the wave speed does in fact vary according to the wavelength of the waves.\n\nYou are correct that the speed of a wave is constant in a given medium.  However, as you suspected after you lost the bet, tsunamis and ripples are effectively traveling through different media because of the ratio of their wavelengths to the water depth.
664552
Yes water is a highly effective ground which lightening needs to get to the earth. Lightening can strike you even through a window when you are in a house and the window is closed. extremely rare though. The water bed is safer, unless it leaks on you. Don't worry the odds of you being hit is like winning the lottery. I bet you win the lottery.
472533
The bonds between particles in a liquid are pretty weak, so I think its because the energy lost in the liquid by the wave has two components; one parallel to the direction of propagation, one perpendicular to it. The energy is passed from one particle to the next, but at each interaction, energy is lost (as heat, i guess), and so the further away the observer is from the wave, the less energetic the particles are; the wave "fades". Liquid is viscose, and so the bonds between particles have a certain degree of stretch to them. Energy is lost in the transferral of momentum through these bonds. \n\nTransverse waves in air can be produced with radio frequency electromagnetic waves (but they can travel through vacuum too), or a mechanical wave could probably be created using some sort of oscillator; bonds between gas molecules are pretty much non existent, so it'd be hard :-)\n\nBulk movment of particles, like in sound waves, are much easier - just pushing the particles forward repeatedly at the right frequency is audible.
32570
First, you need to find the wavelength of the frequency.\nSpeed=Wavelegth*frequency\nWavelength= 342 m/s / 440 1/s =.78 meters\n\nThe wave traveling into the tube will hit its first resonance frequency one quarter of the way along the wave.  This is the first spot where that wave travels into the tube at such an angle that when it bounces off the water, it can escape the tube again; that is what creates the "resonance" or the louder vibrating sound.  So the first resonance would be @ .78m/4=.19m ; the second @ .19*2=.39m ; and the third at .19*3=.58 meters.
653080
http://www.seafriends.org.nz/oceano/waves.htm\n\nIs a good place to start.\n\nhttp://www.fluidmech.net/tutorials/ocean/w_waves.htm\nIs more advanced\n\nYou will need to go to a libray and get a book to see equations and solutions.
84658
The liquid is transparent if you can see the pencil. The reason the pencil looks that way is refraction. The light travels differently through the water, so it bends and doesn't go in the same straight line that it was. So you see half in the air, straight, and half in the water, at a different angle. Try putting the pencil in slowly. You will see it is only the part that is in the water that looks bent. Other liquids (oil, rubbing alchol) bend the light different amounts so the angle is different. Try it and see.
51985
i would think that the radiation from the freqs listed above should all cause excite the water molecules in the same way but to differing extents. that's a very good question; i think i'll research it.
591243
Electromagnetism and gravity. I have had success divining for water. Try it: Take a steel coat hanger and cut the long side in half. Make a cut on the other 2 sides  that same length. Bend until you have 2  L-shaped pieces. Stroke one side of each  L with a good magnet. Hold both pieces lightly as if you were holding 2 pop cans, tilting slightly away from you. As you walk over a water source, water table, well or buried pipe the two L's will move to point to each other. Use caution, this also works to locate underground live power lines.                        The REASON this works is that everything in our physical environment has an energy level. When there is a difference in density or materials, then resistance is created and this can be electromagnetic resistance. Underground water is electrically conductive and carries a faint electromagnetic charge that the magnetic "L's" tend to align with. I hope that explains it better, I'm glad you were able to find a good spot for your well.
98718
Actually, to correct a previous answer, waves in water travel faster than waves in air because the propagation velocity is proportional to the medium density. \n\nSounds produced by a gas modulating larynx are bubbled out of ones mouth underwater. Acoustic energy is transferred from air to water as they emerge from the mouth. there is an impedance mismatch at this point. Also the shape of the bubble emergence guarantees that this is not a very linear transmission mechanism. The result is nonlinear attenuation and spectral dispersion which results in muffling of the signal.\n\nIf you were to use an underwater transducer (speaker) and send your acoustic signal (using a mic and amplifier above water), the intended receiver would hear it with good fidelity since there is no gas/water boundary to cross in this scenario.\n\nHope this helps
186011
This is very similar to the floating of a (slightly oily) needle on the water. Surface tension acts like a stretched elastic membrane. The water is always trying to minimize its free surface area (that is, surface that is not contacting and wetting some solid).\nWhen you put an unwettable object on the water it stretches the surface which increases the surface tension. This tension holds up the needle. When you push a tube with an unwettable inner surface into the water, the surface tension tries to minimize the unwetted surface area by not rising into the tube. It will reach a level in the tube that balances the bouyancy due to the immersed air with the surface tension.
78977
I pierced a candle with the needle and carefully placed the needle on water surface. It floated well. \n\nThis due to the surface tension effect.\n\nNext I did with another needle without wax coating. This time it floated once in many trials.\n\n\nNext I placed the needle on a piece of blotting paper and placed it on the surface of water. The blotting paper in few seconds went inside leaving the needle floating.
345229
Okay I think the other 2 answers you already had when I started this misunderstood your question so I'll get it right for you.\n\nTwo things happen in the 16 seconds.\n1. rock falls s meters\n2. sound travels back up s meters from water surface to well opening\n\nFirst let's deal with the #1 part, the rock's fall.  For this let's use a variable called t1 for time.\n\nWe need to use this formula: s = (v1)(t) + ½(a)(t)²\ns = displacement, v1 = initial velocity, t=time, a=acceleration\n\nSince the rock is dropped it has no initial velocity.  Let down be positive.\n\ns = (v1)(t1) + ½(a)(t1)²\ns = (0)(t1) + ½(a)(t1)²\ns = ½(a)(t1)²\n\nOkay so we figured out what we can in this step about t1.  Now let's go to step 2 and see what we can figure out about t2.\n\nThe sound travelled from the water up to the well opening (s meters) in some amount of time we don't know yet (t2).  We can describe the sound's movement with this formula:\n\ns = (v)(t) (we use this because the sound is not accelerating)\n\ns = displacement, v = velocity, t = time\n\nNow let's use our variables (t2, our s) and use v2 for the sound's velocity and see what we can put together with the sound.\n\ns = (v2)(t2)\n\nOkay so we know something about the sound and rock now, let's gather what we found and look at it.\n\n1. s = ½(a)(t1)²\n2. s = (v2)(t2)\n\nThere is something else we know too and can write down as an equation.  We know that the time it took for the rock to hit the water and the time it took for the sound of the splash to travel back up to the opening add up to a total of 16 seconds.  So we can write it as:\n\nt1 + t2 = 16s (let's isolate the t2 and call it equation 3)\n3. t2 = 16 - t1\n\nSo all together we have:\n\n1. s = ½(a)(t1)²\n2. s = (v2)(t2)\n3. t2 = 16 - t1\n\nWe have enough equations now to solve for the number of variables we have.  Start by substituting t2 from #3 into #2 to get equation #4.\n\n4. s = (v2)(16 - t1)\n\nNow set 1. and 4. equal to each other (because they are both s so they are equal so we can do that)\n\n(v2)(16 - t1) = ½(a)(t1)²       (expand it out now)\n\n16(v2)-(t1)(v2) = ½(a)(t1²)\n\nNow put in what we know (v2 = 345m/s, a = 9.8m/s)\n\n16(345)-(t1)(345) = 4.9(t1²)   (move it all to one side and it should look familiar)\n\n4.9t1²+345t1-5520=0  (it's a quadratic equation and we can solve those, stick it in your calculator)\n\nt1 solves to\nt1 = 13.436\nor\nt1 = -83.844 (forget this one, the rock didn't hit before you dropped it)\n\nSo t1 = 13.436m (we only know this to 2 significant digits)\n\nNow we can finally solve for s by using equation #1\n1. s = ½(a)(t1)²\ns = ½(9.8)(13.436)²\ns = 884.57m (only to two sig. digits)\n\ns = 880 meters
82223
Distill the water. The WATER comes out of the tubes, not the salt.\n    As for testing, just drink a little of it. Do you *LIKE* it?\nNo? Well you better make sure that you don't put it back in the same cup you used for collection.\nOK the water will still pass an electric current through it if it has any impurities. Completely pure water will not.\nUnless you use more than around one volt, in which case the bubbles you see escaping will be hydrogen and oxygen. That means you've gone too far with the testing part.
571354
it could be something as simple as you just didn't notice it, ever been looking for your keys or something then find them later at a place you already checked?\n\nas for the soap, if it falls in the tub it wont take alot of water over night to dissolve it.\n\njust keep any eye out for anything else strange, also check to see there is no way for someone to get in the house, just to be safe, but I am betting its nothing.
503078
probably gravity. it's the most likely. without gravity there would be no wind, running water or sea waves. think about it for a second it'll make sense