the dimensions are 45 by 30 by 20 cm.  im guessing the height is 20? HELPP!!!!!!!!!!!!!!
203954
45*30+30*20+20*45= 5700
525950
I hope you made a start.  Since you're asked the original side measure, let that equal x ft.  Then read the question again and notice that the length of the increased garden is x + 3, and the width is ...?  [I'm sure you know].\nArea = length * width, and we're told area is 72, so you have an equation in the form\n(x + 3)(x + ...) = 72\n\nExpand the left side to get 3 terms, then subtract 72 from both sides and get \n\nx^2 +  ...x - ..... = 0, which I hope you can solve, but I really don't think I should do it for you.  If you need more help, email the bloke who answered your previous question.\n\n-- or me at h_chalker@yahoo.com.au
310693
if x is width, then 30-x is length \n(so that 2* (width_length)=60),\nand area is indeed 30x-x^2, which is maximized at x=15.\n\nGenerally, a rectangle with a given perimeter will have max area if it is square.
333284
Question 20906\nSubmitted on 5/28/2002\n\nFind the area of a nonagon inscribed in a circle of radius 24cm.\n\nSolution 20906\n\nThe nonagon can be divided into nine congruent isosceles triangles. \nThe lengths of the sides are 24 cm and the vertex angle is 360/9 = 40.\nThe base of one triangle is\nB = 2 * 24 * sin (20)\nThe height of the triangle is\nh = 24 * cos (20)\nSo the area of one triangle is\nA = (1/2) * 2 * 24 * sin (20) * 24 * cos (20)\nA = 24^2 sin(20) cos(20)\nAnd the area of the nonagon is\n9 * 24^2 sin (20) cos (20)\n= 1666.1\n\n\nSubstitute in your 1 meter for the 24 centimeters and you'll get your answer.  I believe the answer should come out to somewhere around 3.353 m^2
345602
Okay.  This can be a little tricky if you dont see how to set it up.\n\nwe don't yet know the length, so lets call that x.  Since we all know there are 4 sides to a rectangle lets set up the equation like this.\n\n36 = Perimiter.  Since the length is 4 ft longer lets write the expression to show that.\n\n36= 2(4+x)+2x\n\nx = the width, and since theres 2 lengths and 2 widths, multiply them by two. now multiply out.\n\n36= 2(4+x)+2x => 36=8+2x+2x => 36=8+4x\n\nnow its simple algebra\n\n36-8=4x\n28=4x\nx=7\n\nsince x=width,         width =7 ft\nsince x+4=length     length = 11 ft\n\nnow find the area. This is the easy part.\n\nArea= length x width\n\nA= 11x7\n\nA=77 ft^2
120837
The height is 30 yd.  Just plug in what the problem gives you into the formula, and solve for the variable or the missing information.  \n\nArea = 1/2(Base.1 + Base.2)h\n\n450 = 0.5(20+10)*h\n450/0.5 = (30)*h\n900 = 30*h\n900/30 = h\n30 = h\n\n100% possitive
76784
r u sure its not 40 m less, if it is here:\nLet w=width\n    w+40=length\nw(w+40)=21^2\nw^2+40w=441\nw^2+40w-441=0\n(w+49)(w-9)=0\nw=-49 or w=9\nthe width is 9 m and the length is 13 m
4491
sorry i made a mistake....this is correct...\ndivide the base by 2.  Now you have a right triangle.  the height is the same, but the base is now 3.  pygathora (spelling, whatever) theorm is A squared + B squared = C squared.  c is the side opposite the right angle, a and b are the other sides.  so 3 squared + 4 squared is 9 + 16 = 25. The square root of 25 is 5, so that is the length of the side.  the volume = area of base times height.  Area of a triangle is 1/2 base times height.  so 3 (one half of 6) times 4 = 12.  times this by height of 8 = 96 cubic units. largest rectangular side is the 6 (the longest side) times 8 = 48 units squared. hope this helped.  the lateral area is the area of the sides added together. so C times 8 = 40 (area of one side)  add the other side of equal area (the C from the second triangle we got when we split the first one) 40 + 40 = 80.  Add the third side of length 6 times 8 = 48.  80 + 48 is 128 (in units squared).  or all sides added up 5 + 5 + 6 = 16 times 8 = 128.
241510
the length is 6 inches. the width is 3 inches. Am I right?
620852
Why it's still 20 feet tall silly.  hehehehe
56825
i have no idea about dimensions but be sure that,it'll be equal buying a new model.i mean this modifying will cost so much...
551717
How much space would 19.3 g of gold take up?\n\nthen it is 318.97/19.3 times that much space!
263203
30.48 cm per foot.  So divide.  \n= 182 / 30.48\n= 5.97 feet\n\n.97 x 12 inches\n11.6535433 \nSo the answer is about 5 feet 11 21/32 inches.
448503
From the Question, it should be a triangle....\nso take take 28 X 25 / 2 should be the answer\n350 ft!
141257
The dimesnions of the rectangle are 14 feet by 34 feet.\n\nYou know that the perimeter is 96 feet and that each long side is 20 feet more than the short sides.\n\nAs there are 2 long sides the total length of both these sides must be 40 feet more than the total length of the 2 short sides (20 x 2 = 40).\n\nIf all the sides were the same length as the short sides then the rectangle would have a perimeter of 56 feet (we know it's 96 feet to start with and that the additional length on the two long sides is 40 feet and 96 - 40 = 56).\n\nEach side would therefore be 14 feet long since 56 divided by 4 = 14.\n\nNow that we know the length of the short sides all we need to do is add 20 to get the length of the long sides, 14 + 20 = 34.\n\nTo check it you can add 14 + 14 (the two short sides) + 34 + 34 (the two long sides) = 96.\n\nI hope that makes sense, it's 1:25AM here and I'm getting tired.
259620
A = base * height\n\nbase = 8\n\nslant height = 6\nto get the actuall height, we use trig\n\nthink of 6 as the hypotenuse\n\nsin 30 = height / slant height\n\nor height = sin30 * 6\n\nheight = 3\n\ntherefore area = 8 * 3 = 24
503035
The first thing you need to do is to have the same units. This applies to any measurement question. If it were 20g as a percentage of 30kg, you'd need to have both terms in the same units before moving on.\n\nIT makes the most sense to convert 3 metres to centimetres (so that we aren't dealing with decimal numbers), which is, of course, 300 cm. \n\nSo, now you have 20 cm and 300 cm. This is like having a mark of 20 out of 300. So, you do 20/300 then multiply by 100 to have a percentage mark.\n\n20/300 * 100 =6.67% (or to whatever decimal place you are supposed to give your answer)