This is a steel frame on a trailer. I had this down pat when in college. My algebra is very rusty at this time. You know use it or lose it.
199508
The ultimate strength of a beam is found by US = max load/CSA.  There's not a lot of math to it, but you do need to measure pretty carefully.\n\nThere comes a problem, however, where some materials "stretch" before actually failing, thus making the measurement of the max load difficult.  As an example, if you've ever pulled plastic wrap apart, it gets easier at a point right before it breaks into two.  The point where after you pull on it and it gets easier is called the yield strength.  After you pass the yield strength, you don't need as much force to cause failure in the material.\n\nNow in steel, the yield and ultimate strengths are pretty close to each other that the above discussion really doesn't affect it if you are trying to break a beam on your own.  But the ultimate strength of steel is probably something you can look up in a table somewhere.  Then you can use the above formula to see how much your beam can take based on the US and the cross sectional area.
414663
I may be going out on a limb here, but as a non-engineer I would guess that a solid core door is solid, and a hollow core door is hollow. However, I could be missing something.
509409
You put a round bracket "()" on the number line when the sequence doesn't include the number where that bracket goes. For example, if the final answer you get is "all the numbers between 2 and 8, excluding 2 and 8" then you use the round brackets. You'll know your answer excludes a number or numbers because it will be "bigger than" or "smaller than" only, not "bigger than or equal to" or "smaller than or equal to", in other words, ther will be no line underneath the inequality sign. \nNow, if you do get something like "x is bigger than or equal to  8 and smaller than or equal to 2" than you know your answer includes 2 and 8, so you use the brick bracket, "[ ]". Good luck.
117013
that's a real vague question, try to be more specific or at least say what king of structure do u want? (steel, conc, ..?)\nanyways this is an exremely simple example.\n\nlets' say u want to design a tension member -carrying tension force = 100 tons, -between 2 supports and this member is a steel member of yield stress= 1.4\nso to get the area u need :\n100/1.4= 71.43 cm square let's say again u want it to be I-shaped steel then u'll need  I number 400 i.e IPE 400
480617
Your description of the problem is not iron-clad, so let me make these assumptions explicit:\n- The axis of the cylinder is horizontal.\n- The block descends because of acceleration due to gravity(g).\n-  There is no air resistance to the motion of the block.\n- The string does not slip on the surface of the cylinder and it is\n  completely inelastic.\n\nAcceleration of the block is  = g\nForce acting on the block is = mg\nThe torque by this force on the cylinder about the axis = mgr\nThis results in accelerating the rotation of the cylinder.\nmgr = I x alpha, where I = moment of inertia of the solid cylinder;\n                         alpha = Angular acceleration of the cylinder.\n\nI = (1/2)mr^2 \n[ M.I of a solid cylinder; Given: Mass of cylinder = block = m ]\n\nalpha = torque/I = mgr/I = 2g/r
504993
You need to clarify some details.  Are they all peeing at the same time?  Is the 35 degree angle from the ground up?  What modifications have been made to the frame to keep this weight off the tires?  And last, but not least...what size tires and how much tread is left?\n\nToo funny!!
279928
I have an idea for you. Go to the site I provided for the source. It's a truss bridge with an arch. The best of both worlds. The most important thing is the arch. That is where all of the strength comes from in a bridge. I hope that helps.
456243
Both the above answers are correct, provided the acceleration is horizontal. If it's not then it's a vectors and trig. question.
92328
Well this mite be a job. The number is on the back of the block where the bell housing for the trans bolts to the block.\nDont know what this number will help you or not, but that is where it is.
571817
If the block is not accelerating, then the net force acting on the back must be zero.\nSince the force of weight in the diagram is acting straight downward, there must be another force of equal magnitude acting in the opposite direction to counter the weight of the object.  This balancing force is known as the "normal force" (F_n) as it acts "normal"/perpendicular to the surface the object rests on.\n\nTo complete the force diagram, you'll need to draw aother force pointing straight upward from the block with an equal magnitude of the weight of the black (mg).  Doing this will balance the forces and keep the black from accelerating through the ground.
179079
Looks like A> Reining
387941
Probably silicone and iron.   It's a friggin big rock.   Hollow it out a bit; near the center the gravity is probably near earths gravity.
477452
pretty sure its a metal.\nhope this helps. :)
346344
The stress in the cable is m*g/A.  The Young's modulus of steel is about 200*10^9 N/m^2 (pascal).  Therefore the strain will be\n\nm*g*/(A*200*10^9).\n\nThe elongation is strain*length.\n\nFor the second part, replace g above with (g+a), where a =2.7m/s^2\n\nFor the last, compute the mass from S = m*(g+a)/A, The elastic limit is Sm, so the max mass is m = Sm*A/(g+a)\n\nNote: keep the units straight.  Use kg, m, sec, N in all calcs then convert to the asked-for units last.
375661
focus on a triangular frame- these frame are the strongest. also try googling for the manufacture of bridges and find out why certain bridges are built.
553574
I think you actually need to use Tangent for this problem. \n\nThe wheelbase of the truck is 1.8m. Assuming it is perfectly balanced, the center of gravity would be directly over the center of that; 0.9m from one wheel. That's the base of the triangle.\n\nThe vertical side rises up to the center of gravity; which is unknown, or X.\n\nA 30 degree tilt causes the truck to roll over. This means that the angle of our triangle is 90 degrees minus 30, or 60deg.\n\nNow we have, Tan60=X/0.9\n1.73(0.9)=X\nX=1.56
83501
ok so for A, the first set has 2 seats. so between the 2 seats, theres 2.5feet of steel. and then from each seat to the end, theres 2 more feet (on each side) so thatz 4 feet + 2.5feet = 6.5 feet for the first set.\nfor the 2nd set, 3 seats so 2*2.5 between the seats (2.5 between seats 1 and 2 and then 2.5 more between seats 2 and 3) + 4 =9feet of steel for the 2nd set.\nfor the 3rd set, theres 4 seats so that means (3*2.5) + 4 = 11.5feet of steel.\n\nso you should get the pattern hopefully. if theres 5 seats, then 4*2.5 + 4. 6 seats is 5*2.5 + 4.\nso then the expression would be [(n-1)*2.5] + 4. i dont really know how to explain why its correct. i guess you could just say  it works and it makez sense. for n seats, theres n-1 gaps between the seats and each gap is 2.5feet long. and then theres alwayz 2 feet on both ends added to it which is the +4. \n\nanywayz hope this helps. let me know if u need mroe help or whatever. laterz