We sold 240 tickets to our school water carnival. Tickets cost $1.00 or $2.00. We sold $3oo worth of tickets. How many $2.oo tckets did we sell?\n(Please tell me the answer and explain how you got it.)
200013
There is not enough information.  You are leaving something out.  Did they sell twice as many $1 tickets than $2 tickets, or what?
350576
If x is the ticket price increase from $6, the number of tickets is 70000 - 10000x ; the ticket price is 6+x; and the concession revenue is 1.5(70000 - 10000x)\n\nThe ticket revenue is (6+x)(70000 - 10000x) \n\n1.5(70000 - 10000x) + (6+x)(70000 - 10000x) = total revenue\n\nThese combine to be (7.5 + x)(70000 - 10000x) which multiplies out to be\n\n525000 - 5000x - 10000x^2\n\nThis has a maximum value when x = 5000/ -20000 = -1/4  [x = -b/(2a)]\n\nso technically it means they should drop their price by 25 cents to get the maximum profit, if that is possible\n\nPlug it in to get your other answers
316750
a) the number of possible tickets is C(42,6) = 5245786\n1/5245786 = .000000190629\nb) the number of tickets with exactly 4 is \nC(6,4)C(36,2)\n= 15*630 = 9450\n9450/5245786 = .00180\nc) You don't win if you have less than 3 winning numbers, so either you can have 0, 1, or 2 winning numbers and not win\nP(0 numbers) = C(36,6)/5245786 = .37130\nP(1 number) = C(6,1)C(36,5)/5245786 = .43119\nP(2 numbers) = C(6,2)C(36,4)/5245786 = .16843\nP(no prize) = .37130 + .43119 + .16843\n= .97092
380370
I agree w/ you. I don't think a legitimate fundraiser would be selling a pack of m@m's for $3.00. I've never seen anything around where I live. If I've ever bought from someone outside a store it was usually our local highschool band/ cheeleaders or the boy or girlscouts selling for no more that a dollar or two for a box of cookies or candy bars. I know my son's candy that he has sold has never been more than a dollar.
552029
1. Bob's favorite ice cream used to cost $1.50.... Then the price was raised to $1.75. Find the percent increase.\n(175/150)-1)*100%=16 2/3% increase\n\n2. Jenny paid $12,000 for her car. Five yrs later she sold it for $8500. What percent decrease was this?\n(8500/12000-1)*100%= -29 1/6% 29 1/6% decrease\n\n3. The Music Box marked up their CD's 75%. If the music box charges $20 for a special cd, how much did it cost before the mark-up? (hint: the answer is not $15)\n$20=1.75x\nx=20/1.75=$11.43\n\n4. Quinn deposits $2000 in a savings account that pays 4% compounded semi-annuallly. HOw much money will Quinn have in her account after two years? Give the expression. (you do not have to simplify) \n\n$2000(1.02)^4=$2164.86
656384
Write them as a ratio of integers (cents) first:\n1250 / 875\n\nRemove a common factor of 5 from top and bottom:\n250 / 175\n\nRepeat for another 5:\n50 / 35\n\nOops, we can do it again:\n10 / 7\n\n(Note: this is equivalent to 1.428571... in decimal, so the previous answer was right about this, but the problem asked to do it as a ratio of whole numbers.)\n\nSo the ratio of the prices is 10 / 7.
94580
to complete the problem:\n7.5o + 3.5b = 4375  Eq.#1\no + b = 650  Eq.#2\n\nSolve Eq.#2 for o:\no = 650 - b  Eq.#3\n\nSubstitute Eq.#3 into Eq.#1:\n7.5(650-b) + 3.5b = 4375\n4875 - 7.5b + 3.5b = 4375\n\nSolve for 'b':\n4875 - 4375 = 7.5b - 3.5b\n500 = 4b\nb = 125\n\nSubstitute b = 125 into Eq. #2:\no + 125 = 650\no = 600-125\no = 525\n\nTherefore, there were 125 balcony seats sold, and 525 orchestra seats sold.
358100
Look here in the completed items. The items with a green price were sold. The items with a red price did not sell or did not have their reserve price met.\n\nGood luck!
618206
actually tickets are from 20 to 75 bucks. they go on sale today(july6) so you all should go. i for sure will be there. heres a link to the ticketmaster site
246633
So where's that starting point?  Either we start (yesterday) with Mary having $785.63 we subtract $57. and $125. for 603.63.  Then we add $57.25 for a total of 660.88 (B) \nOR\nwe start we $785.63 (today) anb subtract $57. and $125 for $603.63 (C).  The $57.25 doesn't matter cause Mary did that yesterday....
546795
It looks like the price is $85.  I did not see a special "student" price.  However, I'm assuming student tickets were sold as season packages and individual tickets will be hard to find.
445883
Sell "Holiday Grams", it would be a short note that the sender writes and xmas lollipop sent to someone in their class (say like 2nd period on Dec 15th). Charge two or three dollars. My school used to do this to raise money during each major holiday
115959
For a more expensive event, excluding the ticket, I would spend around 50 ir 60 bucks.  At a local event maybe 30 or 40 depending on what it was.  I'm pretty cheap though.\n\nThe most I would spend on a ticket (assuming you mean rides at a fair) would be a dollar.  It depends on how many tickets you need to get into a ride.  No more than a dollar on a ticket though.  If the fair is general admission I would say 10 dollars.
625528
Okay, I think this is what you're asking: suppose merchant A sells 2 bananas for $5 and merchant B sells 3 bananas for $5. Then one of the merchants gets sick and the other switches to selling 5 bananas for $10, will the other mechant make more or less oney than if he had sold at his original price?\n\nIf merchant A sells at 5 for $10, he will lose money.\nIf merchant B sells at 5 for $10, he will gain money.\n\nJust compute the amount each merchant makes per banana - Merchant A makes $2.50/banana and merchant B makes $1.67/banana (rounded to nearest cent). If they sell 5 for $10, they would make $2/banana.
417196
These kinds of questions always follow the same pattern.\n\nOne equation will always be, how many tickets were sold of each type?\n\nIf s = # of student tickets and a = # of adult tickets, then:\n\ns + a = 267\n\nThe other equation will always be, how much of the money collected was from student tickets, and how much from adult tickets?\n\nThe amount of money collected from student tickets is 2.50 x s.\nThe amount of money collected from adult tickets is 4 x a.\nThe total amount collected is $1042.50.\n\n2.5s + 4a = 1042.50\n\nSolve for a.
158269
One could buy eight horses and chariot sets and then sell them as suggested in the multiple choice to see how it works or one could set up two sets of equations and solve:\n\n-10%*(Horse Price) + 20%*(Chariot Price) = 0 (no profit)\n 10%*(Horse Price) + -5%*(Chariot Price) = 15 (profit)\n\nCombine the equations to get:\n                     -15%*(Chariot Price) = 15\n\nSolve for Chariot Price... 100\n\nPlug back into either equation to get Horse Price... 200\n\nThe answer is c
425327
1     $58.50\n\n2     $23.20\n\n3     $38.25\n\n4     $75.60