It is 7th grade math (combinations)
212916
10 * 9 * 8 * 7 * 6 = 30240 combinations
521216
Im assuming that by using the word 'groups', (plural) you are not allowed all four in one group as a solution.\nSo, if the counters are the same, then 2 ways:\n1, 1, 1, 1 \nand\n2, 2\n\nIf the counters are different, then 4 ways.  (If the counters are:\na, b, c, d then:\nab,cd\nac,bd\nad, bc\na, b, c, d. )\n\nIf this is for a 3rd grader then the former is probably what they are looking for, but I can't really know that.  The latter seems a little complicated for the average 3rd grader.
368733
add 4, divide by 4\nadd 3, divide by 3\nadd 2, divide by 2\nthe answer is 3
460710
(x-7)(x-5)\nso x= +7, or +5
287293
this is possible to figure out.  What it is a combination of numbers   i will do examples to keep it simple.   If your number was 00  or 000  then the answer was 9.  well its a pattern    if your number is 001 then the answer he came up with was 8.  well then if you had 002  then it was 7.  but also on the note if your number was 011 or some combination of this number then it was 8 also  because when you take 011 and add 0+1+1 you get 2 so it was 8.   the way it works is the numbers you type in it adds them together so there is a correlating number that goes with the answer that was added together.  so... if the numer added together was 0 then it was 9.  and the number added together was 1 then he came up with 8.  added together you got 2 then he said 7.  and just keep going ... 3 is 6,   4 is 5.    also on the same account    5 is 4,  6 is 3,   7 is 2,   8 is 1,  and 9 is 0.
72899
No. of alphabets = 22  [{a, b, .. z) - {i, o, q, z)]\n==> n = 22\nNo. of letters taken at a time = 3 \n==> r = 3\n\nNo. of combinations of "n" different things taking "r" at a time is given by n_C_r or C(n,r) \n= (n)(n-1)..r times/(r) * (r-1) * ...(1)\n\nTherefore, the number of combinations that can be formed \n= C(22,3)\n= 22 * 21 * 20/3 * 2 * 1\n= 1,540\n\nIf you are looking for the number of words that can be formed using the letters,.. then you have to look out for permutations..\n[No. of permutations of "n" different things taking "r" at a time given by n_P_r or P(n,r) = (n) * (n -1) * ... r times.\n\nThe number of words that can be formed \n= P(22,3)\n= 22 * 21 * 20\n= 9,240\n\nIf the same letter can be used then the number of words that can be formed is given by (n)^r\nThe number words that can be formed \n= 22^3\n= 22 * 22 * 22\n= 10,648\n\n\nhttp://www.futureaccountant.com/probability/\n\nhttp://www.schoolingkids.com/
400996
7 th grade! im doing the same thing in the 10th
419806
1 + 7 + 7(6) + 42(5) + 210(4) + 840(3) + 2520(2) + 5040(1) = 13,700
294890
Ah, but it is only 14 if you do math correctly.\n\n;-)
674280
7x+27 over (x+9)(x-9)
448736
Division and multiplication. Just like I learned in Grade 3.
269993
Definetly it is 35/15 because it is teachers which is 35 over students which is 15. So then you simplify it to 7/3 after you divide the top and the bottom number by 5. Hope I helped you understand!
222758
Eleven: 1 3 7, 3 8, 3 3 5 = 3 ways\nTwelve; 1 3 3 5, 5 7, 1 3 8, 3 9 = 4 ways\nThirteen: 3 3 7, 1 3 9, 5 8, 1 5 7 = 4 ways\nFourteen: 3 3 8, 1 3 3 7, 5 9, 1 5 8 = 4 ways\nFifteen: 3 3 9, 1 3 3 8, 3 5 7, 1 5 9, 7 8 = 5 ways \nSixteen: 1 3 3 9, 1 3 5 7, 1 7 8, 7 9, 3 5 8 = 5 ways\nSeventeen: 8 9, 1 7 9, 3 5 9, 1 3 5 8 = 4 ways\nEighteen: 1 8 9, 1 3 5 9, 3 7 8, 3 3 5 7 = 4 ways\nNineteen: 1 3 7 8, 3 7 9, 3 3 5 8, 1 3 3 5 7 = 4 ways\nTwenty: 1 3 7 9, 3 8 9, 3 3 5 9, 5 7 8, 1 3 3 5 8 = 5 ways\nTwenty-one: 1 5 7 8, 5 7 9, 1 3 3 5 9, 1 3 8 9, 3 3 7 8 = 5 ways\nTwenty-two: 1 5 7 9, 3 3 7 9, 1 3 3 7 8, 5 8 9 = 4 ways\nTwenty-three: 3 3 8 9, 1 3 3 7 9, 3 5 7 8, 1 5 8 9 = 4 ways\nTwenty-four: 1 3 3 8 9, 7 8 9, 3 5 7 9, 1 3 5 7 8 = 4 ways\nTwenty-five: 1 7 8 9, 1 3 5 7 9 = 2 ways\nTwenty-six: 3 3 5 7 8, 1 3 5 8 9 = 2 ways\nTwenty-seven: 3 7 8 9, 3 3 5 7 9, 1 3 3 5 7 8 = 3 ways\nTwenty-eighr: 1 3 3 5 7 9, 1 3 7 8 9, 3 3 5 8 9 = 3 ways\nTwenty-nine: 1 3 3 5 8 9, 5 7 8 9 = 2 ways\nThirty: 3 3 7 8 9, 1 5 7 8 9 = 2 ways\nThirty-one: 1 3 3 7 8 9 = 1 way\nThirty-two: 3 5 7 8 9 = 1 way\nThirty-three: 1 3 5 7 8 9 = 1 way\nThirty-four: cannot be done = 0 ways\nThirty-five: 3 3 5 7 8 9 = 1 way\nThirty-six: 1 3 3 5 7 8 9 = 1 way\n\n78 ways in all\nSystematic searching is the only way I could find.
631055
okay here is what I think....still a little unclear\nx=9th grade\nx+8=8th grade\n3/4(x+8)=11th grade\n\nso...\nx+ x+8+ 3/4(x+8)=96\n\nx+x+8+3/4x+6=96\ncombine terms\n2 3/4x + 14=96\nsubtract 14 from both sides\n2 3/4x=82\ndivide each side by 2 3/4\nx=29 9/11\nthen round up\n9th grade =30\n8th grade =38\n11th grade=28 (actually it is28 1/2 but bc you can't have 1/2 of a person it is 28)
111500
Make 2 7/15 an improper fraction, flip it over to its reciprical and mulitply the two.\n\nBoy...I hope I got that.  *bits fingernails*
465138
i would guess this is 3rd or 4th grade?\n\nyou could use a calculator of course . . .\n\nto show your work, you need to do it on paper\n\ngood luck!
500424
bring the a's to one side... u then get 9a = 27 ... divide and answer is a = 3