the smallest of all the exterior angles measures?\na.5* b.20* c.70* d.85*\n*=degrees
216964
The interior and exterior angle add up to 180 degrees; so far the smallest would be 180 - 110 = 70 degrees.  But since there are 5 angles in a pentagon, we have to first make sure that the unknown angle of the pentagon is not larger than 110 (making it's supplement, the exterior angle, smaller than 70 degrees.\n\nDraw a pentagon on your scratch paper (it doesn't have to be perfect) and pick one of the vertices (the "corners" where the sides meet).  If you draw a line from that vertex to all of the other vertices, you see that you've divided the pentagon into 3 triangles.  Since each triangle has 180 degrees, the whole pentagon has angles that add up to 3 x 180 or 540 degrees.  From the four angles you've been told (85 + 90 + 95 + 110 = 380) you can figure out that the fifth angle has to be 160 degrees (540 - 380 = 160).  So the exterior angle that matches up with that angle is 180 - 160 = 20 degrees and choice B. is correct!
485689
The sum of external angles of a regular polygon ( a regular polygon mens all the sides of the polygon are equal) is always 360 degrees. Therefore,the table being a 7-sided polygon or regular heptagon,each of its external angle would be 360/7=51.43 degrees.Therefore the measure of each internal angle would be (180-51.43)=128.47 or 128.5 degrees (apprax) ans
465977
at the vortex, the degree measure would be 45. at a cube's vertex, the degree measure is 90. so if it passes it (between the middle, of course) you have half of 90 degrees one each side.\n\n45
90046
Divide the world into 4 quadrants (NE, NW, SE, SW), according to the middle of the Earth (0 degrees lat. by 0 degrees long.) \nThe True North would equal 0 degrees (or 360), East equals 90 degrees, South equals 180, and West equals 270 degrees (this is not long. and lat. measurements). \nWork out which quadrant the Vessel Movement is in and then use a protractor to work out the degrees. Then you have the bearing.
391204
Yeah, you described it very poorly.  I don't even know where X should be.  But from what I've read, you're probably dealing with a transversal.  That should be easy.\nSupplements, interior angles, corresponding angles, exterior angles, supplementary/complementary angles  - ring a bell?
490663
16.72 inches squared.\n\n\nDivide an equilateral triangle into two equal right triangles (meaning, draw the height).  The right triangles will have angles of 30, 60, 90, right (an equilateral triangle has 3 60 degree angles)?\n\nThe ratio of the sides in such a right triangle (the smallest leg being a) is a:a(sq(3)):2a, where 2a is the hypotenuse and a(sq(3)) is the other leg.\n\nThe "other leg" in this case is the height.  So a, half of the length of the side of the whole equilateral triangle, is 5.382/sq(3).\n\nMultiply this by 2 to get the whole length of the side.  We have our base and height.\n\n\nThe area of an equilateral triangle is 1/2bh.  b=2(5.382)/sq(3)\nh=5.382\n\nPlug those in and you get 16.72.
429116
Angle measurement, which is the meaurement behind latitude and longitude (the angle being at the center of the earth) are measured in degrees to start with, but to get the measurement more precise, degrees are divided into minutes, and the minutes are divided into seconds.  (Nothing to do with time measurement, except that a degree has 60 minutes, and a minute has sixty seconds).  So 54 35' 45.6" reads 54 degrees, 35 minutes, 45.6 seconds.
29505
actually its not\n the answer would be (sin(30degrees)*200)+5\nsin(30degrees) is .5\n.5*200 = 100 +5 = 105 feet in elevation\n\ndraw a picture and label everything as much as possible, you eralize that you have the length of a hypotenuse, so you take teh sin of the angle then multiply by the length of the hypotenuse to get the length of the opposite side, that gives you teh height from eye level, you now must add the level you are looking from (5ft)\n\nhope this helps!!
626746
The angles in a triangle add up to 180, so the answer is b. 40 degrees.
432460
a) Assume the following:\n\nAngles a= 10 deg, b= 80 Deg, c=90 deg \nHypotenuse length = 2.5 m\nheight = 2.5 * cos 80 Deg= .434 m\nlength = 2.5 * sin 80 Deg= 2.462 m\nacceleration = "g" * Sin 10 Degree
188932
Let A be the largest angle, B be the middle angle, and C be the smallest angle.  From the question:\n\n1) A = 2C\n2) A + C = 2B\n3) and since it's a triangle, A + B + C = 180 degrees.\n\nYou can add B to both sides of equation 2, and get.\n2-rev) A + B + C = 3B\nCompare to equation 3, and you discover\n3B = 180.\nSo B = 60.  Substitute B into equation 2.\n\n2) A + C = 2B = 120\nAnd you know from equation 1 that A = 2C, so substitute\n2C + C = 120\n3C = 120\nC = 40\n\nSubstitute B and C into equation 3, and\n3) A + B + C = A + 60 + 40 = 180\nA must be 80.
239498
If they're tangent to each other that means they all touch at one point. That means you're given the lengths: 85 cm, 100 cm and 115 cm.\n\nFrom here, you can use the cosine law to figure out what each angle is.\n\na^2 = b^2 + c^2 - 2bc cosine A.
581748
a=c*sin(30)=.5c since it is apposite the 30 degree angle\nb=sqrt(c^2-a^2)= .866c\nor b=c*cos(30)=.866c\n\na=b=c*sin(45)=.707c=
492918
Trigonal planar.\n\n120 degrees.
459431
Without a picture or more information, your question isn't answerable, but I'm guessing that angles x and a are parts of a right angle, in which case the answer would be 41 degrees (49 + x = 90).
195617
If the shape is a quadrilateral, the measures of its opposite angles WOULD add up to 180 degrees.  This is because the measure of an inscribed angle (an angle with vertex on the circle) is half the measure of its intercepted arc.  Between the two opposite angles, their combined arc is the whole circle which measures 360 degrees.  So the sum of the inscribed angles is half of that, or 180.
543173
The average was (90-50)/20 = 2 lower than it should have been; thus 76.\n\nSide length = sqrt(625) = 25, so 4*25 = 100 inches.\n\n2/18 * 360 = 40.