I NEED SOMETHING TO MAKE LETTER A=10\n\n\nI CAN'T GET THIS FORMULA TO WORK.
213285
The formula would be: =IF(A2="A", 10)\n\nThis would be pasted into another cell, like B2 for example.  Thus, if A2 is A, then B2 would display a 10 - if it is not, it will display FALSE.\n\nIf you don't want FALSE to appear, change the formula to: =IF(A2="A", 10, 0)  You can substitute the value of 0 for whatever you want the cell B2 to display if A2 is not A.
28367
-1 works\n-1*3 + 1 = -2\n-2/2 = -1 (back to where we started)\n\nAddition> Now you say they should be pos! Jeez\n\n0 works though is it technically positive?\n\nWow, try a number like .1  - The numbers get REALLY big before coming back down to 1.  (5.00315450989997E+15)\n\n\n  Function IsOddNum(ByVal intNumber As Double) As Boolean\n    If (intNumber Mod 2 = 0) Then\n      Return False\n    Else\n      Return True\n    End If\n  End Function\n\n  Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click\n    Dim num As Double = Convert.ToDouble(TextBox1.Text)\n    Dim count As Integer = 0\n    Literal1.Text = num.ToString() & "<BR>"\n    While num <> 1 And count <> 1000\n      If IsOddNum(num) Then\n        num = 3 * num + 1\n      Else\n        num = num / 2\n      End If\n      Literal1.Text &= num.ToString() & "<BR>"\n      count += 1\n    End While\n  End Sub\n\n\nAnother Note:  I just plotted the number of iterations for the numbers between 1 and 20,000.  The graph totally shows a pattern!  (Mathematicians love patterns)\n\nAnother Note, Doh, now the numbers have to be integers?  Jeez, there goes my repeating number answer.  Are you going to keep adding rules every time I get it right? LOL
475064
Make a program on your calculator.\nView the snippet in the link for code.
148610
Ok, I got it.  I recommend writing the numbers 1-12 and crossing them out as you use them.\n\nYou've got your 5,6,1,and 8 on the inside.  So on the upper row of four, 5+6=11, so you need 15 more to make 26.  The only numbers that are left where 2 add up to 15 are 12&3 or 11&4.  I tried 11&4 first and will just tell you it didn't work, so it's 12&3.  Now to decide which goes where.  If you put the 3 on the left, it lines up with the 1 making 4, and there's no other numbers that will add up to the required 22 - so 12 must go on the left and 3 on the right.\n\nNow you can see the line  from the bottom point up to the 3.  8+3=11, so you need 15 again, and the only choices left are the 11&4.  Put the 11 at the bottom point and the 4 between the 8&3.\n\nNow looking at the line that goes from 12 down to the 11 you have 12+1+11=24, so you must use the 2 here.  Now you have 7,9 & 10 left.\n\nLooking at the line with the 5&2, that makes 7, so you need 19.  The only way to get that is with the 10 & 9, but you don't know which goes where.  You DO know, though, that the only other point that is left gets the 7.  That's the bottom right point.\n\nThis made a line with 7,6,4 and the very top point.  7+6+4=17, so you need 9 at the top to make 26, which leaves the space for the 10 at the bottom left.\n\nIn order, from top to bottom/left to right you have\n\n9\n12,5,6,3\n2,4\n10,1,8,7\n11
257824
Type "=B1-C1+D1*A1" without the quotes inside another cell such as E1.  This is assuming that your equation is the correct algebraic form and solved for one variable.  Your text is a bit jumbled so I didn't parse all of it.
81496
http://www.aaamath.com/ Try this. Hope it works!!
401028
I believe you mean "abc" to be a 3 digit number! So, the problem is to find digits a, b and c such that\n\n     100a + 10b + c = a + b^c\n\nthat is, b^c + digit = three digit number (not beginning with 1)\n\nThe only possibilities for b^c are\n\n     256, 512; 243, 729; 256; 625; 216; 343; 512; 729\n\nAfter trying these, find that there is only one answer corresponding to 736:\n\n     a = 7, b = 3 and c = 7
394803
38894 0's between 1-100000\n\nWrite EVERY number (except 100000) as a 5-digit number with leading 0's.  We will subtract out the leading 0's later.\n\nIf the first digit is zero, there are 10*10*10*10=10000 numbers.\nif the second is zero, there are also 10*10*10*10=10000 \nsame with if the third, fourth or fifth is zero.\nSo now, we have 5*10000 or 50000 zeroes.\nNow we subtract out the number of 0's in numbers with leading 0's.\n\nIf the first is 0, there are 10000 numbers, so we added 10000 too many 0's, so subtract 10000\nIf the first two are 0, there are 1000 numbers, so we added 1000 too many more 0's\nIf the first three are 0, we added another 100 too many.\nIf the first four are 0, we added another 10 too many.\nIf all five are zero, we add 1 more too many.\n\nSo N = 50000 - 10000 - 1000 - 100 - 10 - 1 = 38889 for the numbers 1 through 9999.\nThen we add 5 more for the number 100000, so\nN = 38894\n\n*****\nThe equation for the number of 0's between 1 and 10^n inclusive is:\nn10^(n-1) - 10^(n-1) - 10^(n-2) - 10^(n-3) -  ... - 10 - 1 + n\n= (n-10/9)*10^(n-1) + n + 1/9
487338
Don't panic, you can do this...\n\nJust start by distributing the numbers through the parentheses:\n5(2x-3)=2(-3x-2)+5\n10x - 15 = -6x -4 + 5\n\nNow group letters on one side and numbers on the other, start by adding 15 to both sides:\n10x = -6x - 4 + 5 + 15\n10x = -6x + 16\n\nNow add 6x to both sides:\n10x + 6x = 16\n16x = 16\n\nNow divide both sides by 16:\nx = 1\n\nIf you did it correctly, you should be able to plug x = 1 back into the equation and get a valid statement:\n\n5(2(1) - 3) = 2(-3(1) - 2) + 5\n5(2 - 3) = 2(-3 - 2) + 5\n5(-1) = 2(-5) + 5\n-5 = -10 + 5\n-5 = -5 <-- check\n\nSo x = 1 is the correct answer.
545067
Put a number in box A1\nPut a number in box A2\nClick in box A3\ntype "=A1-A2"\n(you don't type the question marks, just what is inside them)\nHit enter
591854
I don't think these have a name, and I've never run across them before.  However, so long as you don't mind changing the format around, they look easy to create on the computer or anywhere, really.\n\nletter one: 3+4/2\nletter two: 2x+3 = 51 (hint: that's the letter x, not a multiplication symbol)\nletter three: 1*(5-4)\nletter four: the next prime number after 11\nletter five: add 3 to the answer to letter four\nletter six: 4+4*2\nletter seven: this letter is congruent with letter one\n\nThe answer is:\n\nletter one: 3+4/2 = 5 (remember BEDMAS order of opperations: brackets, exponents, divide, multiply, add, subtract) = e (e is the fifth letter of the alphabet)\n\nletter two: remember x?  Let's solve for x:\n2x+3 = 51\n2x = 51-3 (we changed sides of the equation, so we need to change its sign)\n2x = 48 (we knew all the numbers on the right side of the equals sign, so we can solve it!)\nx = 48/2 (we moved the 2, so we need to change the sign, remember)\nx = 24\nNow, if we think about the alphabet, we know that x is the 24th letter.  so...x = x!  :-)\n\nletter 3: 1*(5-4) = 1*1 = 1 = a(Did you remember about BEDMAS from above?)\n\nletter 4: A prime number is a number who's only factors are 1 and itself, for example 7.  We know that 2*6 = 12.  So, 12 can't be prime.  But 13 is!  The 13th letter of the alphabet is, of course, m.\n\nletter five: 13+3 = 16 = p. (You got letter four correct, right?)\n\nletter six: 4+4*2 = 12  = l (BEDMAS is rather important, you know.)\n\nletter seven: Congruent is a math term we use in geometry.  It means two shapes that are exactly the same.  So, i letter seven is exactly the same as letter one, it must also be...e!  \n\nIf you did everything right, the word you get is: example\n\nWasn't that fun?  Wish I had thought of this.
421609
I POSTED THE FIRST CORRECT ANSWER HERE AND WAS WRONGLY DELETED FOR A BOGUS VIOLATION REPORT\n\nI posted last night around 12pm, here was my (correct) answer:\n\nOk so let the tens digit be x, then the ones digit is (12-x). The value of the number is 10*x+(12-x) = 9x+12 which you are told = 11x 9x+12=11x 12=2x x=6 12-x=6 also So the number is 66. (Check x = 6*11 as claimed.)\n\n(There is some severely dishonest point-gaming going on around here)
277691
First, FUNNYPLAYA12'S answer is a partial of what I got, and my formula looked like this:\n\n-8X^3 + 10X^2 - 2X = 0\n-----------------------------------\nFactor out one X and you get:\n\n-8X^2 + 10X - 2 = 0\n\nFactor this and FOIL-check\n\n(-4X + 1)\n(2X - 2)\n___________\n-8X^2 (8X + 2X) -2\n\n-8X^2 +10X - 2\n\nX = {1/4, 1)\n\n\nTo verify:\n\n-8(1) + 10(1) -2(1) = 0\n\n-8 + 10 -2 = 0; and finally:\n\n10 - 10 = 0, which is very true!\n----------------------------------------\n\n-8(1/4) + 10(1/4) -2(1/4) = 0\n\n-2 + 2.5 - 0.5 = 0\n\n-2.5 + 2.5 = 0, which is also very true!\n\n\nOTBPOC
409498
Hello\nThis is very simple.\n\nPlease follow the steps mentioned below :-\n\n1) for this patter you need to do is type\n   2\n   4\n   6\n2) Now you need to click on the box where you wrote "2"\n3) Press Shift, keep on holding it and then click "6"\n4) Now that the 3 box's will be selected. Now all you have to do is that you will see that at the bottom of your selection to the right side there would be a dot. it would appear somethin like ..\n\n2\n4\n6  .\n\nnow drag this dot downwards and you are done\n\nhope this solves your problem, or you can tell me, i can do it for you.\n\nthanks
219205
Very simple:\n\n\n4a - 10 = 42\n\nYou are trying to isolate the variable. The number by the variable is -10. You want it to become 0 so the variable is alone. So, first you must add ten to both sides of the equation. \n\n-10 + 10 = 0\n42 + 10 = 52\n\n4a = 52\n\nNow you are trying to figure out the value of 1a. To make 4a into 1a, divide it by 4. You must do the same on the other side of the =. \n\n4a / 4 = a\n52 / 4 = 13\n\nNow all you have left is a = 13 \nThere is your answer!\n\nYou can also check your work: \nIf a = 13, then 4 x 13 must = 52\nIt does, so the answer is correct!
492713
I just plugged this into my calculator.\n\n[1, 0, 2, 0, 2, 0 | 0\n0, 1, -3, 0, -2, 0 | 0\n0, 0, 0, 1, -1, 0 | 0\n0, 0, 0, 0, 0, 1 | 0\n0, 0, 0, 0, 0, 0 | 1 ]\n\nTake it however you want.
389844
☺☺☺☺☺☻☻☻☻☻♥♥♥♥♥Alt+1=☺ Alt+2=☻Alt+3=♥♥♥♥\nand you can do a bunch more.