how many combinations on a pair of dice?
235688
Rolling Two Dice. Note that there are 36 possibilities for (a,b). This total number of possibilities can be obtained from the multiplication principle: there are 6 possibilities for a, and for each outcome for a, there are 6 possibilities for b.
1174880
When 2 dice are thrown, the probability of the sum being 9 is 1/9.
994152
The total number of possibilities is 6 for the first die and 6 for the second. Since each throw on the first die could be paired with any of the six on the second, the total ways the dice could fall is 6 × 6 = 36. So the probability of getting 11 or more is 3/36 = 1/12.
1004288
There a four possible rolls with a single die less than 5 (1, 2, 3, and 4). If you were asking about the probability of rolling TWO dice, with the resultant sum being less than 5, there are 6 ways to do so in 36 possible outcomes. The answer is 6/36, or 1/6, or 16.67%.
319401
Thanks for the A2A. Hint: A double of 6 is obtained when both dice throws result in 6. The probability for such an event is 1/36.
929310
The total number of outcomes equals the number of different ways we can roll two six-sided dice. We find this number by multiplying 6 x 6. ... Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12 (E).
135457
For example, 1234. Each combination of this type has 24 different box combinations, so your odds of winning by playing one "single" box combination would be approximately 1 in 417. Double (12-way): Two of the four positions have the same digit, and the third and fourth digits are different.
1006450
When two fair dice is thrown, The possibilities are as below. So, For getting 6 in both dices, The probability is 1/36. And, For getting sum of 8, It can be (2,6),(3,5),(4,4),(5,3),(6,2) and It is 5/36.
183203
What is the probability of getting two numbers whose product is even? Explanation: In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
1383571
Originally Answered: Two different dice are tossed together. ... two dice rolled once has 6x6= 36 possible outcomes. There 6 ways of having a doublet. Thus p(doublet) = 6/36 = 1/6.
1053463
Let's consider two players are playing the game, so there are 3 possibilities for the first person( Rock/Paper/Scissor). Again, for the second person, there are 3 same possibilities. Now on combining both we get: 3*3 = 9. So, there are 9 possible combinations in all.
154599
Since there are 6 possible outcomes (1, 2, 3, 4, 5 and 6) on each of the dice, of which 3 are even (2, 4 and 6) and 3 are odd (1, 3 and 5), the probability of obtaining an even number on either dice is 3/6 = 1/2, and the probability of obtaining an odd number on either dice is also 3/6 = 1/2.
879426
A total of 30. So the probability of getting the sum of two dice to be less than 10 is 30/36 or 5/6.
625546
To get 6 with two dice, 1,2,3,4,5 are possible on on die, so 5,4,3,2,1 are needed on the other to make 6. Each die has 1 chance of being 1–6, out of 6, but 6 is excluded as there is no pairing that sums to 6 if either die is 6.
1028399
The probability of getting a total of 10 or 11 with two die thrown simultaneously is %13.89. This breaks down as: Getting a total of 10 is possible with a 4+6, 5+5 or a 6+4 for 3 of 36 possible combinations. ... Two dice are rolled.
710584
Probabilities for the two dice. The colors of the body of the table illustrate the number of ways to throw each total. The probability of throwing any given total is the number of ways to throw that total divided by the total number of combinations (36).
1133468
Two dice are thrown once. ... The probability of getting an even number on the first die is 18/36 or 1/2. The probability of getting a sum of 8 is 5/36, as there are 36 possible outcomes and five of them -- 26, 35, 44, 53, and 62 -- have a sum of 8.