how to find the equation of a perpendicular line without points?
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First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.
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['The equation of the line in the slope-intercept form is y=2x+5.', 'The slope of the parallel line is the same: m=2.', 'So, the equation of the parallel line is y=2x+a.']
103494
To find the slope of this line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y:. The slope of the line –6x – 9y = 4 is m = –2/3. Therefore, the slope of every line perpendicular to this line would have to be m = 3/2 because (–2/3)(3/2) = –1.
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Find the distance from point to the line . Explanation: Draw a line that connects the point and intersects the line at a perpendicular angle. The vertical distance from the point to the line will be the difference of the 2 y-values.
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Explanation: Find the slope of the given line. The perpendicular slope will be the opposite reciprocal of the original slope. Use the slope-intercept form (y = mx + b) and substitute in the given point and the new slope to find the intercept, b.
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Step 1: Find the slope of the line. To find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: The slope of the line 4x – 5y = –10 is m = 4/5. Therefore, the slope of the line perpendicular to this line would have to be m = –5/4.
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The distance between two points (x_1, y_1) and (x_2, y_2) can be defined as d= \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. Perpendicular lines are lines that intersect at a 90^{\circ} angle. The product of the slopes of two perpendicular lines is -1.
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What is the slope of line k? To find the slope of a line perpendicular to a given line, we must take the negative reciprocal of the slope of the given line. Thus the slope of line k is the negative reciprocal of 2/5 (slope of line m), which is -5/2.
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Perpendicular Lines and Slopes. Perpendicular lines are lines that intersect at right angles. If you multiply the slopes of two perpendicular lines in the plane, you get −1 . That is, the slopes of perpendicular lines are opposite reciprocals .
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['Calculate the slope of the original line. ... ', 'Take the reciprocal of the original slope. ... ', 'Calculate b, the y intercept of the new line using the new slope and the point given along that line.', 'Put all of the information together in point slope form.']
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Correct answer: Explanation: The question puts the line in point-slope form y – y1 = m(x – x1), where m is the slope. Therefore, the slope of the original line is 1/2. A line perpendicular to another has a slope that is the negative reciprocal of the slope of the other line.
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Answer Expert Verified The perpendicular equation is y = -1/3x + 10.
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Find the slope of the given line. The perpendicular slope will be the opposite reciprocal of the original slope. Use the slope-intercept form (y = mx + b) and substitute in the given point and the new slope to find the intercept, b. Convert back to standard form of an equation: ax + by = c.
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Hence, the equation of a line perpendicular to x axis is x = c. Note : If the line is passing through some other value on x axis, we have to replace "c" by that value.
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['Step One: Identify two points on the line. In this example we are given two points, (15, 8) and (10, 7), on a straight line.', "Step Two: Select one to be (x1, y1) and the other to be (x2, y2). It doesn't matter which we choose, so let's take (15, 8) to be (x2, y2). ... ", 'Step Three: Use the equation to calculate slope.']
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Correct answer: Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6.
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Write an equation into point-slope form, y - k = m(x - h), since the slope of the perpendicular bisector and a point (h, k) the bisector goes through is known. Solve the point-slope equation for y to get y = mx + b.