how to calculate the time difference in oracle sql?
192027
select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss') as run_time from some_table; It displays time in more human readable form, like: 00:01:34. If you need also days you may simply add DD to last formatting string.
1425922
['Add over 24 hours: Start time + (N/24)', 'Add over 60 minutes: Start time + (N/1440)', 'Add over 60 seconds: Start time + (N/86400)', 'Subtract over 24 hours: Start time - (N/24)', 'Subtract over 60 minutes: Start time - (N/1440)', 'Subtract over 60 seconds:']
71678
['Type 9:15:00 AM into cell B1, and type 4:50:15 PM into cell B2.', "To subtract time, type in =B2-B1, and it'll return the elapsed time. The answer is displayed as an AM time, so to change that, right click and select Format Cells and change it to h:mm."]
1421254
select 24 * (to_date(sysdate, 'YYYY-MM-DD hh24:mi') - to_date('2012-02-28 15:20', 'YYYY-MM-DD hh24:mi')) diff_hours from dual; But that did not work.
526851
Method 1: Using strtotime() function $timestamp1 = strtotime ( $date1 ); $timestamp2 = strtotime ( $date2 ); echo "Difference between two dates is " . $hour = abs ( $timestamp2 - $timestamp1 )/(60*60) .
655466
To calculate the minutes between two times, multiply the time difference by 1440, which is the number of minutes in one day (24 hours * 60 minutes = 1440).
233200
['Add 30 days to a date SELECT DATEADD(DD,30,@Date)', 'Add 3 hours to a date SELECT DATEADD(HOUR,-3,@Date)', 'Subtract 90 minutes from date SELECT DATEADD(MINUTE,-90,@Date)', 'Check out the chart to get a list of all options.']
992381
Explanation: To subtract time, subtract the minutes then subtract the hours. Since we can't have negative minutes, add 60 to the minutes and subtract 1 from the hours (60 minutes = 1 hour).
1452477
['add 60 to Minutes: −5+60 = 60−5 = 55 Minutes.', 'and subtract 1 from Hours: −2−1 = −3 Hours.']
679275
['Calculate difference between two timestamps :', 'Calculate difference between two Dates : difference between two dates can be calculated using. date(exp) - date(exp1) OR date(exp) -exp1 OR exp-date(exp1) , where exp, exp1 are date or valid string representation of date.']
809538
Finding the number of hours or the time between two times / dates is simple, just subtract the start date/time from the end date/time and multiply the result by 24 hours.
764317
When you subtract two dates in Oracle, you get the number of days between the two values. So you just have to multiply to get the result in minutes instead: SELECT (date2 - date1) * 24 * 60 AS minutesBetween FROM ...
931654
["$time1 = new DateTime('2017-01-23 18:16:25');", "$time2 = new DateTime('2019-01-23 11:36:28');", '$timediff = $time1->diff($time2);', 'echo $timediff->format(\'%y year %m month %d days %h hour %i minute %s second\'). "<br/>";']
506395
To subtract time, type in =B2-B1, and it'll return the elapsed time. The answer is displayed as an AM time, so to change that, right click and select Format Cells and change it to h:mm. It'll return the answer in time format (7:35, or 7 hours and 35 minutes).
630852
getTime() – date1. getTime(); Calculate the no. of days between two dates, divide the time difference of both the dates by no.
1252066
['You simply subtract both columns and display it as column like below query.', 'SELECT col1,col2,(col1-col2) as col3 FROM table;', 'This will display the difference in third column.']
1245194
['Subtract the hours.', 'Subtract the minutes.', 'If the minutes are negative, add 60 to the minutes and subtract 1 from hours.']