how many combinations of numbers and letters are there?
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Since there are 26 letters and 10 digits you have a total of 36 characters to choose from for each position. Starting from the left you can fill in the first position in 36 possible ways. For each of the 36 possibilities for the first character there are 36 possibilities for the second character.
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For any group of 6 numbers and letters, there are a possible 720 different permutations or combinations that can be made.
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Answer and Explanation: The number of combinations possible with 6 numbers between 1 and 59 is 45,057,474.
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There are 60 of them. Using the same argument as above there are 60 60 = 3600 two "digit" combinations and 60 60 60 = 216000 three "digit" combinations.
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If you want to count the number of unique combinations of any number of keys, just notice that each key can be either used or not used, so there are 2^88 combinations exactly. (If you don't count pressing 0 keys, there are 2^88 - 1 possible chords.)
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Since letters can be in any combination or permutation as long as they arent words as your question suggests, any letter can occur in any of the 3 slots thus the answer is simply number of letters in the alphabet to the power of 3, also commonly known as “cubed”. Thus, 26 x 26 x 26 or 26^3 which is 17576.
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The number of combinations that are possible with 20 numbers is 1,048,575.
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Just to estimate this, there are approximately 200,000 words in the English language, and 12 million possible five-letter combinations, so all the words about 1% the number of possible five-letter combinations.
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The number of combinations possible with 5 letters is 65,780.
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Answer and Explanation: Thus, total number of different combination is 35 .
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Letters in the alphabet: The English Alphabet consists of 26 letters: A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z.
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There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times.
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Since there are only 12 notes to our Western musical vocabulary, there is a finite number that my feeble brain can't comprehend. With about ten notes there are at least 82,500,000,000,000,000,000 combinations. Anyone who has a simple college level understanding of algebra can figure it out to a finite number.
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There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
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The answer is 11, because the number of letters in the numbers has the pattern 3, 3, 5, 4, 4. The next number in that pattern would be 4+2, which is 6, and ELEVEN is the next number that has six letters.
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There are 40,475,358 possible 6-number combinations that can be formed from numbers 1-58 . To determine this, the Combination formula is used.
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Dana F Anderson, Just interested in math is all. Kinda a hobby. Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.