empirical formula for a compound which contains 67.1 zinc and the rest is oxygen?
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4. What is the empirical formula for a compound which contains 67.1% zinc and the rest is oxygen? 45.53 g of nitrogen.
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Zinc has an HCP crystal structure, a c/a ratio of 1.856, and a density of 7.13 g/cm3. Compute the atomic radius for Zn. Express the theoretical density . Here, is number of atoms associated with each unit cell, is atomic weight, is volume of unit cell, and is Avogadro's number.
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The electron configuration of Zn2+ is 1s22s22p63s23p63d10 .
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Iodine is the limiting reactant. The extra shiny, silver-colored zinc will be removed from the reaction; its mass will not be included in the calculation of the empirical formula. We need the molecular formula of zinc iodide.
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There are 4.517⋅1023 atoms of Zn in 0.750 mols of Zn.
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There is 1 mol of Mg for 1 mol of O . The empirical formula of magnesium oxide is MgO .
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Thus if the molecular formula of the compound is C_6H_{18}O_3, the simplest ratio of 6:18:3 is 2:6:1. Thus the empirical formula of of the compound is C_2H_6O.
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Since we know that there are 6.022⋅1023 atoms in every mole of a substance (Avogadro's Number), there are 6.022E23⋅0.750 atoms of Zn in 0.750 mols of Zn.
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Zn + HCl = ZnCl2 + H2 - Chemical Equation Balancer.
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Chemical reactivity Zinc exhibits only the +2 oxidation state. It can give up two electrons to form an electrovalent compound; e.g., zinc carbonate ZnCO3. It may also share those electrons, as in zinc chloride, ZnCl2, a compound in which the bonds are partly ionic and partly covalent.
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So then we will have 63.52g of iron and 36.48g of sulphur. So the empirical formula of the compound is FeS. Usually FeS is also a frequent compound between Fe and S. So the chemical formula of the compound can also be FeS.
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Answer and Explanation: The empirical formula of H2 O2 is HO. H2 O2 is the molecular formula for hydrogen peroxide.
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Answer and Explanation: The empirical formula for P4 O6 is P2 O3. The given formula is a molecular formula because the subscripts can be reduced.
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So then we will have 63.52g of iron and 36.48g of sulphur. So the empirical formula of the compound is FeS.
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The empirical formula is the smallest whole number ratio of copper to oxygen atoms. To obtain the empirical formula divide the number of moles of both copper and oxygen by the smaller of the two numbers. 5. After dividing by the smaller of the two numbers round each to the nearest whole number.
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1 Answer. Faizan B. There are 4.517⋅1023 atoms of Zn in 0.750 mols of Zn.
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What is the empirical formula of a compound that is 14 g calcium, 11 g oxygen, and 0.7 g hydrogen? A. Ca2OH2.