how many different combinations are there with 4 numbers?
10234
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
195649
For the third digit there are only 2 choices and for the last digit, one choice. Thus if you are not allowed to repeat a digit the number of possible 4 digit numbers you can construct from 1,2,3,4 is 4 3 2 1 = 24.
551730
Berry analyzed passwords from previously released and exposed tables and security breaches, filtering the results to just those that were exactly four digits long [0-9]. There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
52844
Explanation: If we are looking at the number of numbers we can create using the numbers 1, 2, 3, and 4, we can calculate that the following way: for each digit (thousands, hundreds, tens, ones), we have 4 choices of numbers. And so we can create 4×4×4×4=44=256 numbers.
1004049
So there are possible numbers of length 4. It's easy. The first digit can be 1,2,3,4,5 or 6 (6 combinations). We choose the second,third and fourth digit the same way we did it with the first (so it's 6*6*6 combinations) and the final answer is 6*6*6*6=1296 combinations.
414273
With a four digit PIN, there are a possible 10,000 combinations. But with a six digit code, there are 1 million possible combos, making it a lot tougher for someone to crack your security code. If you are currently using a four digit PIN and update your software, you will need to manually opt in for the six digit PIN.
401186
We can get a sum of 4 in two different combinations: (1,3) and (2,2). We can get a sum of 5 in two different combinations also: (1,4) and (2,3).
130300
The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999. You can generalize that: the number of N-digit combinations is 10 N.
643296
Explanation: Since there are no parameters as to use of numerals we have nine numbers that can be inserted into each of four digits of the code. This means there are 6561 possible combinations for the key code.
22327
There are 1 billion 9 digit numbers (000,000,000 through 999,999,999). There are 45 different combinations of two different numerals (10 x 9 divided by 2). There are 512 (2 to the 9th power) different permutations for any two numbers to be used in a 9 digit number.
387357
Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
625856
There are only four combinations (ABC, ABD, ACD, and BCD). Listed below each of those combinations are the six permutations that are equivalent as combinations.
38270
Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated. Now consider the possibilities with 13 as the first two digits.
96505
Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated. Now consider the possibilities with 13 as the first two digits.
948
Answer and Explanation: For any group of 6 numbers and letters, there are a possible 720 different permutations or combinations that can be made.
295474
Given 100, choose 99, there are 100 combinations. Given 100, choose 98, there are 161,700 combinations. The number of combinations gets bigger fast. 100, choose 95, is over 7 million combinations.
683759
For each of these 4 first choices there are 3 second choices. Therefore there are 4 x 3 = 12 possibilities.