how many grams of h2o are produced when 2.50 moles of oxygen are used?
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Thus, when 2.5 mol of oxygen reacted with hydrogen, 2 * 2.5 mol = 5 mol of water is produced. The molar mass of water is 18 g/mol. One mol of water weighs 18 g. 5 mol of water weights 5 * 18 = 90 g.
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64 gram of oxygen means two moles of oxygen so it has 2x 6.3 x10 raise to power 23 molecules.
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A mole of water is about 18 grams. A water molecule contains one oxygen atom and two hydrogen atoms. Considering an oxygen atom is sixteen times heavier than a hydrogen atom, 1 mole of water has roughly 2 grams of hydrogen. This is just an estimate from high school level chemistry.
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per mole of oxygen. From here, the answer is simple. Just multiply 2 by 31.9988 g because there are two moles of oxygen. So, the answer is 63.9976 g ..
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The equation says that for every 1O2 , there are 2H2O produced. Therefore, if you have 2.2O2 , you must have 2.2⋅2H2O , or 4.4 moles of H2O .
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The calculation for oxygen is really similar. Again, there's two oxygens in the compound. So, there would be 31.998 grams per mole of oxygen in hydrogen peroxide. We divide that by the total mass of the compound, multiply it by 100%, and get the mass percent of oxygen in hydrogen peroxide being about 94%.
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Well 1 mole of water is 2 moles of hydrogen + 1 mole of oxygen - that is; 1.008 x 2, + 16, which is 18.016 grams. Multiply that by the number of moles - 5, so that's 90.08 grams, or about 90mL. There are 90 grams in 5 moles of water.
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1 Answer. 4.73 mol O2 must be consumed to produce 68.1 g H2O in the given reaction.
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The SI base unit for amount of substance is the mole. 1 grams Oxygen is equal to 0.062502343837894 mole.
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Water has a molar mass of 18.01528 g/mol≈18 g/mol . Since water has a chemical formula of H2O , there will be 2 moles of hydrogen in every mole of water. In one mole of water, there will exist approximately 6.02⋅1023 water molecules.
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We assume you are converting between moles Oxygen and gram. You can view more details on each measurement unit: molecular weight of Oxygen or grams The molecular formula for Oxygen is O. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Oxygen, or 15.9994 grams.
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Therefore from Avogadro's Law, 2 moles of Mg combine with 1 mole of Oxygen to form 2 moles of MgO. Here, 1.5 moles of Oxygen take part in the reaction, which reacts with 1.5 X 2 = 3 moles of Magnesium. = 24.305 X 3 = 72.915 grams which is the required answer.
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1 mole of water requires 1 mole of hydrogen (H2) and 0.5 moles of oxygen (O2). This requires 100/18 moles of hydrogen. As the molar mass of hydrogen is 2, it requires 200/18 = 100/9 g of hydrogen. It requires 100/9 g of hydrogen gas and 800/9 g of oxygen gas to make 100 g of water.
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Answer and Explanation: 0.133 mole of oxygen gas is required to react to form 0.100 mole of water.
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1 Expert Answer Assuming that only oxygen evaporated, you can figure out the moles by dividing the difference in weight of the mixture by the molecular weight of the oxygen. So the answer would be (23.584-22.347)grams divided by 16.000 g/mol, or 7.7313x10^-2 moles O2.
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Approximately how many grams of oxygen are there in 144 grams of water? Since the ratio, by mass, of hydrogen to oxygen is 2:16, then oxygen is 16/(2+16)=8/9 of mass of water. Therefore there are 144*8/9=128 grams of oxygen in 144 grams of water.
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Electrolytic decomposition of 18 g of water gives 0.5 mole of O2. So 90 g of water will give (0.5/18)×90 = 2.5 moles of O2.