in a triangle abc ad is the bisector of angle a?
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The angle bisector theorem states that given any triangle ABC with the foot of the angle bisector of angle A at point D (so AD bisects ∠BAC), two specific ratios are the same: AC : CD = AB : BD. Written another way, DB : DC = AB : AC, meaning D splits side BC in the side ratio AB : AC.
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ABCD is a cyclic quadrilateral in which AB and CD when produced meet at E and EA=ED. Prove that AD is parallel to BC and EB=EC.
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ABC is a right triangle right angled at B, such that BC = 6 cm and AB = 8 CM, find the radius of its in circle. ABC is a right triangle right angled at B, such that BC = 6 cm and AB = 8 CM, find the radius of its in circle.
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If one pair of opposite sides of a quadrilateral are congruent and parallel, then the quadrilateral is a parallelogram. If — BC — AD and — BC ≅ — AD , then ABCD is a parallelogram. If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.
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ABCD is an isosceles trapezoid with diagonals that intersect at point P. If AB || CD , AC = 7y – 30, BD = 4y + 60, and CD = 5y + 14, solve for y A. 124. B.
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In figure ABCD is a rhombus whose diagonal AC makes an angle alpha with AB. If cos alpha = 2/3 & OB = 3cm, find the lengths of diagonals AC & BD.
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ABCD is a parallelogram. AB is produced to P, such that AB = BP and PQ is drawn parallel to BC to meet AC produced at Q. Given AB = 8 cm, AD = 5 cm, AC = 10 cm. When triangles are similar, their corresponding angles are equal.
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Thus, "line segments AC and BD are perpendicular bisectors of each other" means that AC cuts BD into two equal parts at 90° and BD cuts AC into two equal parts at 90°. For (2): AB = BC = CD = AD, means that ABCD is either a rhombus or square (so still a rhombus).
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Answer. In a parallelogram if two diagonals are equal, then the parallelogram is a rectangle.So, ABCD is a rectangle.It is known that each interior angle of a rectangle is 90 degree. Since ABC is an interior angle of rectangle ABCD, so measure of angle ABC is 90 degree.
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ABCD is a trapezium in which AB is parallel to CD and AD is equal to BC. show that angle A is equal to angle B. angle C equal to angle D. triangle ABC is congruent to triangle BAD and diagonal AC equal to diagonal BD.
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No, median cannot be equal to the angle bisector (in general) because : Median is a line segment whose end points are the vertex and mid point of the opposite side of a triangle. while; Angular Bisector is a ray whose starting point is the vertex and which cuts the angle into two equal parts.
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Abcd is a rhombus whose diagonal ac makes an angle alpha with ab. if cos alpha is 2/3 and ob =3cm, find the length of its diagonals ac and bd?/
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ABCD is a parallelogram. What kind of quadrilateral is it&#160;if :AC = BD and AC are perpendicular to BD? Answer: quadrilateral is square.
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ABCD is a parallelogram X and Y are the midpoints of BC and CD respectively. Prove that ar(AXY) = 3/8ar(parallelogram ABCD).
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The diagonals are perpendicular to and bisect each other. A square is a special type of parallelogram whose all angles and sides are equal. Also, a parallelogram becomes a square when the diagonals are equal and right bisectors of each other.
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Given ABCD is a square and CDE is a equilateral triangle. we have to find the angles ∠AED, ∠EAB and reflex angle of ∠AEC.
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Median – A line segment joining a vertex of a triangle with the mid-point of the opposite side. Angle Bisector – A line segment joining a vertex of a triangle with the opposite side such that the angle at the vertex is split into two equal parts.