what is the equation in slope-intercept form of the perpendicular bisector of the given line segment?
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Answer Expert Verified The equation of a line in point-slope form. is the equation of the line containing point (x1, y1) and having slope, m. The given point of the perpendicular bisector is (-1, -2), so in this case, x1 = -1, and y1 = -2.
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The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept. Using the slope-intercept form, the slope is 3 3 . The equation of a perpendicular line to y=3x+2 y = 3 x + 2 must have a slope that is the negative reciprocal of the original slope.
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If you know the slope m , and y -intercept (0,b) of a line (the point where the line crosses the y -axis), you can write the equation of the line in slope-intercept form .
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['The equation of the line in the slope-intercept form is y=2x+5.', 'The slope of the parallel line is the same: m=2.', 'So, the equation of the parallel line is y=2x+a.']
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The equation of a line is in the form y=mx+b form, where m is the slope and b is the y-intercept. Perpendicular lines have negative reciprocal slopes. The slope of the given line is 3. Therefore, the slope of the line that is perpendicular to the given line is -1/3.
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The graph of the equation y = mx + b (where m and b are real numbers) is a line with slope, m, and y-intercept, b. This form of the equation of a line is called the slope-intercept form. The y-intercept of a line (b), is the y-coordinate of the point where the graph of the line crosses the y-axis.
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The form of the equation is Ax + By = C, so subtract Ax from both sides and divide both sides by B. You get : y = -(A/B)x +C/B. This is the slope intercept form.
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Correct answer: Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6.
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Perpendicular Bisector. Definition: A line which cuts a line segment into two equal parts at 90°. Try this Drag one of the orange dots at A or B and note the the line AB always divides the segment PQ into two equal parts. When it is exactly at right angles to PQ it is called the perpendicular bisector.
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We can now use point-slope form to determine the equation of our line. Therefore, the equation of the line that is perpendicular to y=x−1 and that passes through the point (5,4) is y=−x+9 .
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We can use the slope-intercept form (y = mx + b). The x-intercept is found by setting y = 0, because that will give us the x-value at which the line crosses the x-axis.
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Thus, "line segments AC and BD are perpendicular bisectors of each other" means that AC cuts BD into two equal parts at 90° and BD cuts AC into two equal parts at 90°. For (2): AB = BC = CD = AD, means that ABCD is either a rhombus or square (so still a rhombus).
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Start be converting the equation to slope intercept form: y = mx + b. To do this, subtract 5x from both sides and divide both sides by 7: y = -5/7x + 4/7. The slope of this line is -5/7, so the slope of a perpendicular line must be 7/5.
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The product of the slopes of two line segments that are perpendicular is equal to –1. In other words, if we multiply the slope of the line by the slope of AB, we will get –1. We can use the slope formula to find the slope of AB. slope of AB = (10 – (–2))/(–3 – 5) = 12/–8 = –3/2.
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The slope-intercept form is y=mx+b y = m x + b , where m is the slope and b is the y-intercept. Rewrite in slope-intercept form. Subtract 3x 3 x from both sides of the equation. Divide each term by 4 4 and simplify.
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In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis). This useful form of the line equation is sensibly named the "slope-intercept form".
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The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.