is 11 divisible by 0?
428922
0 is divisible by 11 (11 | 0). Zero is divisible by any number other than zero.
1131171
Now, we are going to check if it is divisible by 3 by adding all the digits, 1 + 3 + 8 = 12. As 12 is divisible by 3, then 138 is also divisible by 3.
621780
Given : 871*45 is divisible by 9 & 534*0 divisible by 18.
746345
Now, we are going to check if it is divisible by 3 by adding all the digits, 1 + 3 + 8 = 12. As 12 is divisible by 3, then 138 is also divisible by 3. Since 138 is divisible by both 3 and 2, 138 it is also divisible by 6.
928550
P(k): 23k – 1 is divisible by 7. ... = 7(8m + 1), which is divisible by 7. Thus, P(k + 1) is true whenever P(k) is true. So, by the principle of mathematical induction P(n) is true for all natural numbers n.
776177
The numbers that 50 is divisible by are 1, 2, 5, 10, 25, and 50 and 50. ... Not only that, but all the numbers that are divisible by 50 are the divisors of 50.
218650
There are 11 numbers divisible by 9 between 1 and 100, and 25 numbers divisible by 4 between 1 and 100. So there are 11 + 25 = 36, so 36 numbers divisible by one or the other, but this also includes every number which is divisible by both 9 and 4 twice.
508121
A number is divisible by 2 if the last digit is 0, 2, 4, 6 or 8. 168 is divisible by 2 since the last digit is 8. A number is divisible by 3 if the sum of the digits is divisible by 3. 168 is divisible by 3 since the sum of the digits is 15 (1+6+8=15), and 15 is divisible by 3.
15626
Now, P( 1): 23 - 1 = 7, which is divisible by 7. ... = 7(8m + 1), which is divisible by 7. Thus, P(k + 1) is true whenever P(k) is true. So, by the principle of mathematical induction P(n) is true for all natural numbers n.
351815
Which of the following numbers is exactly divisible by 99? Description for Correct answer: A number divisible by 99 must be divisible by 9 as well as 11. Clearly, 114345 is divisible by both 9 and 11 i.e. 99.
137062
Assuming multiples of 10 are greater than 10 (meaning we will not consider 1/10, 1/100, etc), then all multiples have a zero in the ones column such as 10, 20, 30, 40, etc. If a number is a factor of 80, then 80 must be divisible by that number with no remainder. ... 80 is not divisible by 3 so we will skip 30.
1469293
3, 6, 9, 12, 15,18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93,96,99 are divisible by 3. 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96 are divisible by 4.
1245922
When a 2 digit number is reversed and added to the original number, the result is divisible by 13. This resultant number has to be divisible by 13. We know that 11 is not divisible by 13, this basically means that (a+b) must then be divisible by 13, because 11(a+b) as a whole must be divisible by 13.
958420
there are (100/3) or 33 numbers between 1 and 100 which will be divisible by 3. Since the problem deals with numbers "between 1 and 100", I feel we should exclude both 1 and 100. Therefore, there are (99/2) or 49 numbers divisible by 2 between 1 and 100.
877871
In other words, is 2 divisible by 6? For 2 to be divisible by 6, both of the following two criteria must be met: First, 2 has to be an even number and second, the sum of its digits must be divisible by 3. ... The sum of the digits in 2 is 2, which is not divisible by 3. Therefore, the second criteria is not met.
1217655
All even numbers are divisible by 2. Therefore, a number is divisible by 2 if it has a 0, 2, 4, 6, or 8 in the ones place. For example, 54 and 2,870 are divisible by 2, but 2,221 is not divisible by 2.
531909
Thank you. n(n^2-1 ) is always divisible by 24 for all odd numbers..