how many combinations with 4 unique numbers?
16574
Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
364980
In your case you have 4 digits. So 4x3x2x1=24 combinations of all 4 digits with none repeating. Without repeating digits 24 four digit numbers can be made .
1031102
Answer and Explanation: The number of possible 16-digit combinations, where repetition is allowed is 10,000,000,000,000,000.
535085
['Answer: There are 9,999 different combinations in a 4-digit lock.', 'Explanation: The 4-digit number on a lock begins from 0000 and ends up to 9999 which are:', 'From 0000 to 0999 there are 999 combinations. ( ... ', 'From 1,000 to 9,999 there are 8,999 combinations (9,000)', 'And now we have 1,000+9,000=10,000 combinations total.']
315001
In any Pick 4 game, there are 4 digit positions, with each position containing a digit from 0 to 9. If one were to list all of the possible combinations of digits in each of the three positions, there would be a total of 10,000 different number combinations.
387357
Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
1036797
Question: How many GUID combinations are there? Answer: There are 122 random bits (128 – 2 for variant – 4 for version) so this calculates to 2^122 or 5,316,911,983,139,663,491,615,228,241,121,400,000 possible combinations.
692591
For 4 digits allowing for repetition there are: 10 x 10 x 10 x 10 = 10^4 = 10,000. To get all combination of numbers the first option is correct. If you allow repeated digits and leading zeroes, the answer is 10^4=10000.
683759
For each of these 4 first choices there are 3 second choices. Therefore there are 4 x 3 = 12 possibilities.
1458010
With respect to that technical meaning, there is only one combination of the four numbers 4, 5, 8, and 7, taken four at a time: All four of them. There are 24 combinations. 4578, 4587, 4758, 4785, 4857, 4875, 5478, 5487, 5748, 5784, 5847, 5874, 7458, 7485, 7548, 7584, 7845, 7854, 8457, 8475, 8547, 8574, 8745, and 8754.
794598
There are 40,475,358 possible 6-number combinations that can be formed from numbers 1-58 . To determine this, the Combination formula is used. n choose k equals the factorial of n (divided by) all over the factorial of k times (or multiplied by) the factorial of n minus k.
1439257
There are 10,000 possible combinations. Start at 0001, then 0002, then 0003...and work your way to 9999. Don't forget to try 0000 as well. You can also start at 9999 and work your way down to 0000 if you'd rather.
1462999
I believe there are 126 combinations with 4 dice. This is equal to (6x7x8x9)/(1x2x3x4). Pattern confirmed.
77076
Assuming no five-digit number can begin with zero, there are 9 possible choices for the first digit. Then there are 10 possible choices for each of the remaining four digits. Therefore, you have 9 x 10 x 10 x 10 x 10 combinations, or 9 x 10^4, which is 90,000 different combinations.
279311
Answer: There are 9,999 different combinations in a 4-digit lock. And now we have 1,000+9,000=10,000 combinations total. But…
151182
If you include 3, 2 and 1 digit numbers then it would be 24 + 24 + 12 + 4 = 64 combinations.
299194
If the letters are distinct and repetition is allowed then 4 * 4 * 4 = 4^3 = 64. If the letters are distinct and repetition is not allowed then 4 * 3 * 2 = 24.