abcd is a parallelogram whose diagonals intersect at e?
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ABCD is a parallelogram whose diagonals intersect each other at O with 90°. so it's a rhombus as diagonals of rhombus interest each other at right angles.
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The diagonals of a parallelogram bisect each other. ... In any parallelogram, the diagonals (lines linking opposite corners) bisect each other. That is, each diagonal cuts the other into two equal parts.
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ABCD is a trapezium in which AB||DC and its diagonals intersect each other at the point O. Show that `(A O)/(B O)=(C O)/(D O)` .
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The slopes of are the same so the segments are parallel. Use the Distance Formula to find AB and DC. Thus, AB = DC and . Therefore, ABCD is a parallelogram because if one pair of opposite sides of a quadrilateral are both parallel and congruent, then the quadrilateral is a parallelogram.
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Yes if diagonals of a parallelogram are equal then it is a rectangle.
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['All the properties of a parallelogram apply (the ones that matter here are parallel sides, opposite angles are congruent, and consecutive angles are supplementary).', 'All sides are congruent by definition.', 'The diagonals bisect the angles.']
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Explanation: In a parallelogram, the diagonals bisect one another, so you can set the labeled segments equal to each other and then solve for . \displaystyle x + 14 = 5x - 10 \rightarrow 24 = 4x \rightarrow 6 = x.
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Yes if diagonals of a parallelogram are equal then it is a rectangle. Let PQRS be a parallelogram. To show that PQRS is a rectangle, we have to prove that one of its interior angles is 90º.
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The diagonals of a parallelogram are represented by vector R1 = 3i + 2j- 7k and vector R2 = 5i +6j -3k. ... In a parallelogram, the longer diagonal corresponds to A + B, and the shorter diagonal corresponds to A - B. Let us find | R¹| and | R²|, where R¹ and R² are the two diagonals of the parallelogram.
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THEOREM: If a quadrilateral is a parallelogram, it has diagonals which bisect each other. THEOREM: If a quadrilateral is a parallelogram, it has diagonals which form 2 congruent triangles. DEFINITION: A parallelogram is a quadrilateral with both pairs of opposite sides parallel.
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Definition. A quadrilateral ABCD is a parallelogram if AB is parallel to CD and BC is parallel to DA.
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If both pairs of opposite sides of a quadrilateral are congruent, then the quadrilateral is a parallelogram. If — AB ≅ — CD and — BC ≅ — DA , then ABCD is a parallelogram.
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If a parallelogram is a rectangle, then the diagonals are congruent. SOLUTION: A rectangle is a parallelogram with four right angles, opposite sides parallel, opposite sides congruent, opposite angles congruent, consecutive angles are supplementary, and the diagonals bisect each other. The statement is true.
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Opposite sides of a parallelogram are parallel (by definition) and so will never intersect. The area of a parallelogram is twice the area of a triangle created by one of its diagonals.
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The opposite sides of a parallelogram are equal. ABCD is a parallelogram. To prove that AB = CD and AD = BC.
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In the Following Figure, Abcd is a Cyclic Quadrilateral in Which Ad is Parallel to Bc. If the Bisector of Angle a Meets Bc at Point E and the Given Circle at Point F, Prove That: (I) Ef = Fc (Ii) Bf - Mathematics.
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In a parallelogram if two diagonals are equal, then the parallelogram is a rectangle.So, ABCD is a rectangle.It is known that each interior angle of a rectangle is 90 degree. Since ABC is an interior angle of rectangle ABCD, so measure of angle ABC is 90 degree.