is 12 divisible by 2?
152628
Examples of numbers that are even and therefore pass this divisibility test. Since the last digit is a 2, the entire number, 12, is an even numberand therefore divisible by 2. Since the last digit is an 8, this is an an even number and therefore divisible by 2.
958420
there are (100/3) or 33 numbers between 1 and 100 which will be divisible by 3. Since the problem deals with numbers "between 1 and 100", I feel we should exclude both 1 and 100. Therefore, there are (99/2) or 49 numbers divisible by 2 between 1 and 100.
676892
For the number to be divisible by 12, it should be multiple of 12. ... So, x is a multiple of 27, like 27, 54, 81, 108 etc… We can see that, 27,54,81 are not multiples of 12 but 108 is. So, it is insufficient.
462052
A number is divisible by 7 if it has a remainder of zero when divided by 7. Examples of numbers which are divisible by 7 are 28, 42, 56, 63, and 98.
819096
A number is divisible by 5 if the number's last digit is either 0 or 5. Divisibility by 5 - examples: The numbers 105, 275, 315, 420, 945, 760 can be divided by 5 evenly.
267080
We need to answer if m is divisible by 6. The answer has to be a definitive YES or a NO. The test of divisibility for 6 is that the number should be divisible by both 3 and 2.
199820
The Solution is 14. 7,14,21,28,35,42,49,56,63,70,77,84,91,98, so a brute force answer of 14? How many numbers between 1 and 100 are divisible by 2?
1143521
The set of whole numbers between 1 and 100 that are not divisible by 3 or 11 is {2,4,5,7,8,10,13,14,16,17,19,20,23,25,26,28,29,31,32,34,35,37,38,40,41,43,46,47,49,50,52,53,56,58,59,61,62,64,65,67,68,70,71,73,74,76,79,80,82,83,85,86,89,91,92,94,95,97,98}. So there would be 59 such numbers.
291044
The numbers that 29 is divisible by are 1 and 29 and 29. You may also be interested to know that all the numbers that 29 is divisible by are also known as the factors of 29. Not only that, but all the numbers that are divisible by 29 are the divisors of 29.
257699
This means that the number is ODD and 2 will not divide into it evenly. ... The Rule for 4 : If the last two digits of a whole number are divisible by 4, then the entire number is divisible by 4. Example: 456,791,824. For this rule, we will look at the last two digits: 456,791,824.
377085
any number divisible by 2 and 3 is divisible by 6 (since 2 and 3 are prime numbers and 6 is the lowest common multiple). therefore there are 16 numbers between 1 and 100 divisible by 2 and 3.
730450
All numbers except the ones below are divisible by 2 or 3. 66 numbers between 1 and 100 inclusive are either divisible by 2 or 3. 1 is not include in the count. 99÷3=33 , 99÷2=49 .
318160
12 is divisible by all of these numbers. The factors for 16 are 1, 2, 4, 8, 16. The two numbers (12 and 16) share common factors (1, 2, 4). The greatest of these is 4 and that is the greatest common factor.
308391
A number is divisible by 6 if it is divisible by 2 and 3 both. Consider the following numbers which are divisible by 6, using the test of divisibility by 6: 42, 144, 180, 258, 156. [We know the rules of divisibility by 2, if the unit's place of the number is either 0 or multiple of 2]. 42 is divisible by 2.
1295854
Now, you have 100 divided by 3 = 33 + 1 remainder. This means that there are 33 numbers from 1 to 100 divisible by 3, but you have to pick only the odd ones, since you;ve already eliminated the even ones. The number off odd multiples of 3 between 1 and 100 will be 33/2 = 16 remainder 1.
1364004
So, the number of numbers between 1 and 100 which are divisible by both 2 and 3 is (33+49-16) or 66. Therefore, the required number is (98-66) or 32.
508121
A number is divisible by 2 if the last digit is 0, 2, 4, 6 or 8. 168 is divisible by 2 since the last digit is 8. A number is divisible by 3 if the sum of the digits is divisible by 3. 168 is divisible by 3 since the sum of the digits is 15 (1+6+8=15), and 15 is divisible by 3.