how many valence electrons does o have?
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Valence electrons. Valence electrons are the electrons in the outermost shell, or energy level, of an atom. For example, oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.
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Total 8 valence electron are present in oxygen in water molecule. The electrons which can be seen above oxygen have not been utilised in bonding with hydrogen hence called lone pairs.
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Valence electron is the number of electrons present in the outermost orbit of an element . Oxygen has the atomic number 8. As the electronic configuration of oxygen 1s2 , 2s2, 2p4, it has 6 electrons in outermost orbit ( which is 2nd orbit) and no of electrons in this orbit is 6 ( 2+4).
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Oxygen is #8 in the periodical table. First electron shell can hold 2 electrons; second, 8. Therefore, out of 8 electrons, 2 go to the first shell and 6 to the second; valence electrons are the ones on the outermost shell (there are some exceptions, but they are much further down the table).
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When this is done, each oxygen atom has a total of seven valence electrons and the carbon atom has a total of six valence electrons. Because none of these atoms have an octet of valence electrons, we combine another electron on each atom to form two more bonds.
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So, two carbon atoms times 4 electrons, plus two oxygen atoms times 6 electrons, plus four hydrogen atoms times 1 valence electron equals 24 valence electrons. 2(4)+2(6)+4(1)=24 valence electrons. Look at the Lewis structure of acetic acid.
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In any event, you must start with Xe and 4 O atoms, and note that there are 8 + 4x6 = 32 total valence electrons. The Xe atom is attached to all four oxygen atoms. Four bonds = 8 electrons, so you have 24 electrons left.
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Carbon has 6 electrons --- 2 in the first shell, and 4 in the second shell (so four valence electrons). Nitrogen has 7 electrons --- 2 in the first shell, and 5 in the second shell (so five valence electrons). Oxygen has 8 electrons --- 2 in the first shell, and 6 in the second shell (so six valence electrons).
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1 Answer. BRIAN M. The octet rule is the understanding that most atoms seek to gain stability in their outer most energy level by filling the s and p orbitals of the highest energy level with eight electrons. Oxygen has an electron configuration of 1s22s22p4 this means that oxygen has six valence electrons 2s22p4 .
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There are 32 valence electrons available for the Lewis structure for SO3. Be sure to check the formal charges for the Lewis structure for SO3.
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The Carbonate (CO2−3) Ion 2. Carbon has 4 valence electrons, each oxygen has 6 valence electrons, and there are 2 more for the −2 charge. This gives 4 + (3 × 6) + 2 = 24 valence electrons.
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Oxygen has 8 electrons --- 2 in the first shell, and 6 in the second shell (so six valence electrons). Fluorine has 9 electrons --- 2 in the first shell, and 7 in the second shell (so seven valence electrons). Neon has 10 electrons --- 2 in the first shell, and 8 in the second shell (so eight valence electrons).
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The Lewis electron dot diagram for NO is as follows: Although the O atom has an octet of electrons, the N atom has only seven electrons in its valence shell. Although NO is a stable compound, it is very chemically reactive, as are most other odd-electron compounds.
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Let's do the SeO2 Lewis structure. Se, on the periodic table, 6 valence electrons. Oxygen 6, we've got two of them, for a total of 18 valence electrons.
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Oxygen has atomic no. 8. Its electronic configuration becomes 2,8,6 i.e it has 6 valence electrons. In O2−, there are two more electrons.
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Usually have 4-8 electrons in their outer shell. Gain or share valence electrons easily. Form oxides that are acidic.
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Thus, hydrogen (H) has 1 valence electron and oxygen (O) has 6 valence electrons. The total valence electron is calculated by using equation (1). The total valance electron count of the H2O2 molecule is equal to 14. The Lewis electron dot structure of the molecule is shown by equation (2).