how many combinations with 3 numbers up to 9?
44314
If what you want are all possible three digit numbers with no repetition of the digits then you have 10 choices for the first digit, you have 9 choices for the 2nd digit, and you have 8 choices for the 3rd digit giving you 10x9x8 = 720 in all.
316456
There are about 1,000 combinations possible for a 3-digit number/code. There are 10,000 combinations possible for a 4-digit number/code.
876640
Hi Mike. If order mattered, we would say select the first number (10 choices), then the second (9 choices) then the third (8 choices). So there would be 10 x 9 x 8 = 720 possible choices.
849988
If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
768495
The number of combinations is 8,145,060. This is because there are 45!/(6!
431600
We conclude that there are 35−3×25+3=150 combinations. If there were no restrictions, the number of five digit codes that could be formed with the digits 1, 2, 3 would be 35 since there are three ways to choose each of the five digits.
278994
It's the same as possibilities to a 6 digit code with known numbers and no repeats. With 1 item there are 6 possibilities with 2 you only have 5 choices after the first if you don't repeat the same item. So for 6 items the equation is as follows 6*5*4*3*2= 720 possible combinations of 6 items.
955838
There are 3 numbers. So the number of permutations (arrangements) of three items equals 1 x 2 x 3 = 6. Thus, there are six permutations per combination. The number of combinations therefore is 6480 / 6 = 1080.
17604
With three columns, each with ten possibilities, the number of total combinations is 10 × 10 × 10, or 1000. With three switches, each with two possibilities, the number of total combinations is 2 × 2 × 2, or 8.
1173500
In this case you have all ten digits [0,1,2,3,4,5,6,7,8,9] at your disposal. Assuming repetition is allowed, you can have 7-digit numbers from 1,000,000 to 9,999,999 which is a total of 9,000,000 7-digit numbers. These are all the possible 7-digit numbers. In general, there are 9 × 10^(n-1) possible n-digit numbers.
130300
The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999. You can generalize that: the number of N-digit combinations is 10 N.
107557
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code. Berry analyzed those to find which are the least and most predictable.
219027
See for 11 numbers there can be 9 ways for each number for 1st nine places since 0 can't be the fist number and next two are repeated from 10 numbers hence 10!/2! So 99 combinations have 10!/2! Permutations hence total ways are 99*10!/2!
1160994
As you can see, there are six combinations of the three colors. Table 3. Six Combinations. The formula for the number of combinations is shown below where nCr is the number of combinations for n things taken r at a time.
101010
The number of combinations that are possible with 10 numbers is 1,023.
10234
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
1283597
Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number. Out of these, 104 start with zero (once we start with 0, there are only 4 slots to fill, where we have 10 choices each).