how many bytes are required to encode 2000 bits of data?
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__________ bytes are required to encode 2000 bits of data. Explanation: Two bytes are required to encode 2000 (actually with 2 bytes you can encode up to and including 65,535.
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One byte character sets can contain 256 characters. The current standard, though, is Unicode which uses two bytes to represent all characters in all writing systems in the world in a single set.
112938
1 byte = 8 bits. 1 kilobyte (K / Kb) = 2^10 bytes = 1,024 bytes. 1 megabyte (M / MB) = 2^20 bytes = 1,048,576 bytes. 1 gigabyte (G / GB) = 2^30 bytes = 1,073,741,824 bytes.
490199
UTF-16 (16-bit Unicode Transformation Format) is a character encoding capable of encoding all 1,112,064 valid code points of Unicode (in fact this number of code points is dictated by the design of UTF-16). The encoding is variable-length, as code points are encoded with one or two 16-bit code units.
13867
The maximum capacity for a standard QR code (according to Wikipedia) is 2,953 bytes or 23,624 bits. Each bit has two states, so the number of possible permutations is 2^23624 or about 3.4*10^7111. For now, data storage has a finite density and is limited by the size of the medium.
522984
If there is a 1 in each position, then there are 0 zeros in 1GB. If there is a 0 in each position, then there are (1 0/bit)*(8 bits/byte)*(10^9 bytes/1GB) = 8E9 0's in 1 GB.
90041
3 Answers. Yes, a byte is always 8 bits in modern computing. In the book, the word and the size of the word is explicitly mentioned, while there is not a word (haha) about bytes. Look at the phrase ..is represented in RAM by 32 consecutive 16-bit words. .
1089360
A 16-bit integer can store 216 (or 65,536) distinct values. In an unsigned representation, these values are the integers between 0 and 65,535; using two's complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.
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One byte = 1 character. 1 kilobyte = 1024 bytes = 1024 characters. 1 megabyte = 1024 kilobytes = 1,048,576 bytes = 1,048,576 characters.
94800
The right answer is "20MB", or 3064x2282 pixels, which at 8 bits/channel, works out at 20MB. It comes to the same thing.
1134197
At 9600 baud, the bit time is about 104 microseconds which makes each character sent take 1.04 milliseconds. This corresponds to a transfer rate of about 960 bytes per second. Before sending a byte, you should check that the UART transmitter is ready to accept the byte.
638672
A yottabyte is 1,208,925,819,614,629,174,706,176 (280) bytes, 1,024 zettabytes, 1,048,576 exabytes, 1,073,741,824 petabytes, 1,099,511,627,776 terabytes, 1,125,899,910,000,000 gigabytes, or 1,152,921,500,000,000,000 megabytes.
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Kilobyte: A Kilobyte is approximately 1,000 Bytes, actually 1,024 Bytes depending on which definition is used. 1 Kilobyte would be equal to this paragraph you are reading, whereas 100 Kilobytes would equal an entire page.
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['Bit is an eighth of a byte* ... ', 'Byte: 1 Byte. ... ', 'Kilobyte: 1 thousand or, 1,000 bytes. ... ', 'Megabyte: 1 million, or 1,000,000 bytes. ... ', 'Gigabyte: 1 billion, or 1,000,000,000 bytes. ... ', 'Terabyte: 1 trillion, or 1,000,000,000,0000 bytes. ... ', 'Petabye: 1 quadrillion, or 1,000,000,000,000,000 bytes.']
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One byte = 1 character. 1 kilobyte = 1024 bytes = 1024 characters. 1 megabyte = 1024 kilobytes = 1,048,576 bytes = 1,048,576 characters. 2 megabytes = 2×1,048,576 bytes = 2,097,152 bytes = 2,097,152 characters.
1109621
99 megabytes to bytes. This conversion of 99 megabytes to bytes has been calculated by multiplying 99 megabytes by 1,048,576 and the result is 103,809,024 bytes.
387220
NOTE: The lowercase "b" in Kbps is significant. It stands for "bits," not bytes (which is represented by a capital "B"). Since there are eight bits in one byte, 400 Kbps is equal to 400 ÷ 8, or 50 KBps. Because data transfer speeds have traditionally been measured in bps, Kbps is more commonly used than KBps.