ad is the median of triangle abc?
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AD is a median of triangle ABC and E is the midpoint of AD. BE produced meets AC in F, Prove that AF 1/3 AC.
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Could triangle ABC be congruent to triangle ADC by SSS? ... No, because AB is not congruent to AC. d.
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Answer. In a parallelogram if two diagonals are equal, then the parallelogram is a rectangle.So, ABCD is a rectangle.It is known that each interior angle of a rectangle is 90 degree. Since ABC is an interior angle of rectangle ABCD, so measure of angle ABC is 90 degree.
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In ABC, if AD is the median, then show that AB2 + AC2 = 2[AD2 + BD2].
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Other properties. The centroid divides each median into parts in the ratio 2:1, with the centroid being twice as close to the midpoint of a side as it is to the opposite vertex. The medians from sides of lengths a and b are perpendicular if and only if.
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Trigonometry. In a figure, ABCD is a rectangle in which AD=43.7 cm, DE=100 cm and EDC =27°, where E is a point above C making a rught angled triangle DEC above the rectangle. ... I assumed AB as the rectangle's base and DC as the triangle's basee i.e the top of the rectangle.
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Given: ABCD is a rectangle in which diagonal AC bisects ∠A as well as ∠C. To Prove: (i) ABCD is a square. (ii) diagonal BD bisects ∠B as well as ∠D. and transversal AC intersects them.
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Abcd is a quadrilateral in which diagonals bd=64 cm alperpendicular bd and cm perpendicular bd such that al =16.8cm and cm =13.2 cm.
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Every triangle has exactly three medians, one from each vertex, and they all intersect each other at the triangle's centroid. In the case of isosceles and equilateral triangles, a median bisects any angle at a vertex whose two adjacent sides are equal in length. The concept of a median extends to tetrahedra.
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"Question 12 ABCD is a trapezium in which AB || CD and AD = BC (see the given figure). Show that (i) ∠A = ∠B (ii) ∠C = ∠D (iii) ΔABC ≅ ΔBAD (iv) diagonal AC = diagonal BD [Hint: Extend AB and draw a line through C parallel to DA intersecting AB produced at E.]
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ABCD is an isosceles trapezoid with diagonals that intersect at point P. If AB || CD , AC = 7y – 30, BD = 4y + 60, and CD = 5y + 14, solve for y A. 124. B.
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The median is the middle value of the group and often it lies around the central value. This gives it a good value as an indicator of central tendency. However, the geometric mean wanders off from the central tendency and is not a good measure of the central tendency.
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In Figure-8, ABCD is a parallelogram. A semicircle with centre O and the diameter AB has been drawn and it passes through D. If. AB = 12 cm and OD 1 AB, then find the area of the shaded region.
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ABCD is a parallelogram whose diagonals AC and BD intersect at O. A line through O intersect AB at P and DC at Q. Prove that: ar( POA) = ar( QOC)
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What is the median of a triangle? If you find the middle of any side of a triangle, you have found its midpoint. From that midpoint, you can construct a line segment to the opposite interior angle. That constructed line from the midpoint of a side to the opposite interior angle is a median.
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Answer Expert Verified Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem, it bisects the third side which in this case is AC at E. Therefore, E is the mid point of AC. Hence, BE is the median of ΔABC.
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A median of a triangle is a segment connecting a vertex to the midpoint of its opposite side. An altitude of a triangle is a segment from a vertex to the line containing its opposite side, and is perpendicular to that line.