what is the empirical formula for a compound that is 7.70 carbon and 92.3 chlorine?
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Question: What Is The Empirical Formula For A Compound That Is 7.70 % Carbon And 92.3 % Chlorine? Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems.
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The chemical formula is CH₃CH₂O. The subscripts indicate the number of atoms of the corresponding atom in each molecule. Then, there are 1 + 1 = 2 atoms of C, 3+ 2 = 5 atoms of H, and 1 atom of O.
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Formula and structure: The chemical formula for hydrochloric acid is HCl, and its molecular weight is 36.47 g/mol. It is the solution of hydrogen chloride in water, and HCl is used synonymously for both the gaseous form and the aqueous solution.
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A molecule of carbon tetrachloride contains one carbon and four chlorine atoms.
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39.2 g Cl2(1 mole of Cl270.9 g Cl2)(6.022⋅1023molecules Cl21 mole Cl2)=3.33⋅1023 molecules Cl2 . Hence, the answer is 3.33⋅1023 molecules of Cl2. Note that 6.022⋅1023 is also known as Avogadro's number, and it can be referred to as the number of molecules in one mole of that substance.
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example: CH2 is the empirical formula for C2H4, C3H6, C5H10, C8H16 etc. example: Vitamin C (molar mass = 176.1 g/mol) is composed of 40.9% C, 4.57% H and 54.5% O by mass. Determine the empirical and molecular formulas of vitamin C. 1.
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117/58.44 = 2.0020533881. Ans * 2 = 4.0041067762 moles of sodium chloride. Therefore moles of chlorine gas = ans/2 = 2.002….
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One molecule of CCl4 has 1 carbon atom and 4 chlorine atoms. The atomic weight of carbon is 12.01 and the atomic weight of chlorine is 35.45. So the molecular weight of CCl4 is 12.01 + 4*35.45 = 153.81 g/mol. The number of molecules in a mole of any given substance is always the same: 6.022 x 10^23.
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Thenwe divide the given mass by this molar mass to get moles: 15.1g/(70.9) = 0.21298 moles. Now we can use the mole-to-mole ratio of hydrogen to chlorine. Notice in the reaction how the coefficient of both H2and Cl2 is 1, so the amount of hydrogen is equal tochlorine, so we have 0.21298 moles of hydrogen as well.
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['Water - Formula: H2O = Hydrogen2 + Oxygen. ... ', 'Hydrogen Peroxide - Formula: H2O2 = Hydrogen2 + Oxygen2 ... ', 'Salt - Formula: NaCl = Sodium + Chlorine. ... ', 'Baking Soda - Formula: NaHCO3 = Sodium + Hydrogen + Carbon + Oxygen3 ... ', 'Octane - Formula: C8H18 = Carbon8 + Hydrogen18']
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For every molecule of C12H22O11, there are 12 carbon atoms, aka 1:12. This means that 0.1 mole C12H22O11 is 12*0.1=1.2 mole carbon. One mole is around 6.022 * 10^23 atoms. All you need is multiple 1.2*6.022*10^23, which is 7.2264*10^23 carbon atoms.
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Answer and Explanation: The empirical formula for magnesium chloride is MgCl2 .
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* The empirical formula would be CO₂ * E What is the empirical formula of a compound that is 25.9% nitrogen and 74.1% oxygen? 74.19 0 x 74.1g ox Imole Togo = 4.63 mo 10/1.85 = 2.5 moles 0x2=5 molest .
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1 Answer. C2H7N is the simplest whole number ratio defining constituent atoms in a species, and is thus the empirical formula.
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The given chemical compound has 2 atoms of hydrogen and one atom of oxygen for each atom of carbon. The mass of CH2O is 12 + 2*1 + 16 = 30. The molecular weight of the compound is 180.18 which is approximately 180. This gives the molecular formula of the chemical compound as C6H12O6.
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You can view more details on each measurement unit: molecular weight of CCl4 or grams This compound is also known as Carbon Tetrachloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CCl4, or 153.8227 grams.
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The empirical formula of a compound is NO2. Its molecular mass is 92 g/mol.