what is the formula for calculating the efficiency of a heat engine?
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So, for a boiler that produces 210 kW (or 700,000 BTU/h) output for each 300 kW (or 1,000,000 BTU/h) heat-equivalent input, its thermal efficiency is 210/300 = 0.70, or 70%. This means that 30% of the energy is lost to the environment. An electric resistance heater has a thermal efficiency close to 100%.
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Simple Levelized Cost of Energy Calculation. The simple levelized cost of energy is calculated using the following formula: sLCOE = {(overnight capital cost * capital recovery factor + fixed O&M cost )/(8760 * capacity factor)} + (fuel cost * heat rate) + variable O&M cost.
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Electric Horsepower to Kilowatts Since one electric horsepower is equal to 0.746 kilowatts, the formula to find kilowatts is to multiply electric horsepower by 0.746.
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The thermal energy, or heat, of an object is obtained by adding up the kinetic energy of all the molecules within it. Temperature is the average kinetic energy of the molecules.
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['The resistance, R of the conductor. A higher resistance produces more heat.', 'The time, t for which current flows. The longer the time the larger the amount of heat produced.', 'The amount of current, I.']
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The thermal energy produced by burning one gallon of octane using 3.8L with a density of 0.70g/mL is 126, 646kJ. Suppose a car operates so inefficiently that only 16% of the thermal energy from burning fuel is “useful” energy.
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If the motor is fully loaded, it will provide output power of 1 HP = (1 X 0.746) kW = 0.746kW. Electrical Input Power = (Output Power/Efficiency). Assuming 90% efficiency, Input Power = 0.746/0.9 = 0.83kW.
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The formula below shows the reaction in a stoichiometric format: CH4+4O2→CO2+H2O (plus heat!)
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Usually, a new condensing oil-fired boiler will have an efficiency of 92% to 93%, compared with 85% for a new non-condensing boiler and 60% to 70% for older systems. An oil boiler purchased from a well-established company should be just as efficient as a gas powered boiler system, if not more.
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['2H2 + O2 -> 2H2O. This means that for every 2 molecules of Hydrogen gas, one molecule of Oxygen is needed to make 2 molecules of water. ... ', 'Enthalpy of reaction = (Enthalpy of products) - (Enthalpy of reactants) ... ', 'Enthalpy= -285.83-(0+0)', 'This means Enthalpy of formation of water=-285.83kJ/mol.']
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The electrical equivalent of one horsepower is 746 watts in the International System of Units (SI), and the heat equivalent is 2,545 BTU (British Thermal Units) per hour. Another unit of power is the metric horsepower, which equals 4,500 kilogram-metres per minute (32,549 foot-pounds per minute), or 0.9863 horsepower.
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['FORMULAS FOR CALCULATING THE HEATING VALUE OF COAL AND COAL CHAR: DEVELOPMENT, TESTS AND USES. ... ', 'of the United States.', 'Four formulas were selected for test. They are as follows: ... ', 'Q = 145.44 C + 620.28 H + 40.5 S - 77.54 (0)', 'Boie (11) Q = ... ', '9 = [ ~~', '+ 424.621 [C/3 + H -(0)/8 + s/8]', 'Mott and Spooner (1,13)']
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Power converted to heat in a component is always dissipated in an effective resistance in the component, so you can use P = I2R or V2/R to determine the power in watts from the current I through the resistance or the voltage V across it.
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Question: What Is The Formula Used For Calculating Efficiency In Assembly Line Balancing? Production Time Per Day/ Required Output Per Day Sum Of Task Time/(Theoretical Minimum Number Of Workstations*cycle Time) Sum Of Task Times/(Actual Number Of Workstations*cycle Time) Sum Of Task Times/cycle Time.
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Use the formula ∆H = m x s x ∆T to solve. Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.
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['E = emissions;', 'A = activity rate;', 'EF = emission factor, and.', 'ER =overall emission reduction efficiency, %']
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The relationship between the internal energy of a system and its heat and work exchange with the surroundings is: E = q + w (The form of work will be restricted to gaseous, PV-type for this discussion.) Interestingly, both q and w are not state functions.